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Provide tags and a correct Python 3 solution for this coding contest problem. A sequence a_1, a_2, ..., a_n is called good if, for each element a_i, there exists an element a_j (i ≠ j) such that a_i+a_j is a power of two (that is, 2^d for some non-negative integer d). For example, the following sequences are good: ...
instruction
0
99,462
12
198,924
Tags: brute force, greedy, implementation Correct Solution: ``` import sys input = lambda: sys.stdin.readline().rstrip("\r\n") ak=[] i=0 while 2**i <=2000000000: ak.append(2**i) i+=1 n=int(input()) a=list(map(int,input().split())) d=dict() for i,v in enumerate(a): d[v]=d.get(v,set()) d[v].add(i) ans=...
output
1
99,462
12
198,925
Provide tags and a correct Python 3 solution for this coding contest problem. A sequence a_1, a_2, ..., a_n is called good if, for each element a_i, there exists an element a_j (i ≠ j) such that a_i+a_j is a power of two (that is, 2^d for some non-negative integer d). For example, the following sequences are good: ...
instruction
0
99,463
12
198,926
Tags: brute force, greedy, implementation Correct Solution: ``` input("") output = 0 array = dict() for element in list(map(int, input('').split(" "))): array[element] = array.get(element, 0) + 1 for element in array: flag = False for j in range(31): if ((pow(2, j) - element) in array.keys()) and ((...
output
1
99,463
12
198,927
Provide tags and a correct Python 3 solution for this coding contest problem. A sequence a_1, a_2, ..., a_n is called good if, for each element a_i, there exists an element a_j (i ≠ j) such that a_i+a_j is a power of two (that is, 2^d for some non-negative integer d). For example, the following sequences are good: ...
instruction
0
99,464
12
198,928
Tags: brute force, greedy, implementation Correct Solution: ``` import sys input = sys.stdin.readline n = int(input()) a = list(map(int,input().split())) r = set(2**i for i in range(31)) c = {} for i in range(n): t = c.get(a[i], 0) + 1 c[a[i]] = t ans = 0 for i in range(n): f = False for k in r: ...
output
1
99,464
12
198,929
Provide tags and a correct Python 3 solution for this coding contest problem. A sequence a_1, a_2, ..., a_n is called good if, for each element a_i, there exists an element a_j (i ≠ j) such that a_i+a_j is a power of two (that is, 2^d for some non-negative integer d). For example, the following sequences are good: ...
instruction
0
99,465
12
198,930
Tags: brute force, greedy, implementation Correct Solution: ``` n=int(input()) l=list(map(int,input().split())) d={} ans=0 for i in l: d[i]=d.get(i,0)+1 for i in range(n): flag=0 for j in range(32): p=1<<j x=p-l[i] m=d.get(x,0) if (m>=2 or ( m==1 and p-l[i]!=l[i])): ...
output
1
99,465
12
198,931
Provide tags and a correct Python 3 solution for this coding contest problem. A sequence a_1, a_2, ..., a_n is called good if, for each element a_i, there exists an element a_j (i ≠ j) such that a_i+a_j is a power of two (that is, 2^d for some non-negative integer d). For example, the following sequences are good: ...
instruction
0
99,466
12
198,932
Tags: brute force, greedy, implementation Correct Solution: ``` b = [] l = 2 t = 0 while t<=30: b.append(l) l=l*2 t+=1 n = int(input()) a = list(map(int,input().split())) from collections import defaultdict c = defaultdict(int) d = set() for i in a: c[i]+=1 for i in c: if i in d: continue ...
output
1
99,466
12
198,933
Provide tags and a correct Python 3 solution for this coding contest problem. A sequence a_1, a_2, ..., a_n is called good if, for each element a_i, there exists an element a_j (i ≠ j) such that a_i+a_j is a power of two (that is, 2^d for some non-negative integer d). For example, the following sequences are good: ...
instruction
0
99,467
12
198,934
Tags: brute force, greedy, implementation Correct Solution: ``` n=int(input()) a=list(map(int,input().split())) s=set() d={} for i in range(n): if a[i] in s: d[a[i]]=1 s.add(a[i]) cnt=0 for i in range(n): temp=1 flag=False for j in range(32): if temp-a[i] in s: if 2*a[i]=...
output
1
99,467
12
198,935
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A sequence a_1, a_2, ..., a_n is called good if, for each element a_i, there exists an element a_j (i ≠ j) such that a_i+a_j is a power of two (that is, 2^d for some non-negative integer d). Fo...
instruction
0
99,468
12
198,936
Yes
output
1
99,468
12
198,937
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A sequence a_1, a_2, ..., a_n is called good if, for each element a_i, there exists an element a_j (i ≠ j) such that a_i+a_j is a power of two (that is, 2^d for some non-negative integer d). Fo...
instruction
0
99,469
12
198,938
Yes
output
1
99,469
12
198,939
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A sequence a_1, a_2, ..., a_n is called good if, for each element a_i, there exists an element a_j (i ≠ j) such that a_i+a_j is a power of two (that is, 2^d for some non-negative integer d). Fo...
instruction
0
99,470
12
198,940
Yes
output
1
99,470
12
198,941
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A sequence a_1, a_2, ..., a_n is called good if, for each element a_i, there exists an element a_j (i ≠ j) such that a_i+a_j is a power of two (that is, 2^d for some non-negative integer d). Fo...
instruction
0
99,471
12
198,942
Yes
output
1
99,471
12
198,943
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A sequence a_1, a_2, ..., a_n is called good if, for each element a_i, there exists an element a_j (i ≠ j) such that a_i+a_j is a power of two (that is, 2^d for some non-negative integer d). Fo...
instruction
0
99,472
12
198,944
No
output
1
99,472
12
198,945
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A sequence a_1, a_2, ..., a_n is called good if, for each element a_i, there exists an element a_j (i ≠ j) such that a_i+a_j is a power of two (that is, 2^d for some non-negative integer d). Fo...
instruction
0
99,473
12
198,946
No
output
1
99,473
12
198,947
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A sequence a_1, a_2, ..., a_n is called good if, for each element a_i, there exists an element a_j (i ≠ j) such that a_i+a_j is a power of two (that is, 2^d for some non-negative integer d). Fo...
instruction
0
99,474
12
198,948
No
output
1
99,474
12
198,949
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A sequence a_1, a_2, ..., a_n is called good if, for each element a_i, there exists an element a_j (i ≠ j) such that a_i+a_j is a power of two (that is, 2^d for some non-negative integer d). Fo...
instruction
0
99,475
12
198,950
No
output
1
99,475
12
198,951
Provide tags and a correct Python 3 solution for this coding contest problem. Mishka is trying really hard to avoid being kicked out of the university. In particular, he was doing absolutely nothing for the whole semester, miraculously passed some exams so that just one is left. There were n classes of that subject d...
instruction
0
99,503
12
199,006
Tags: greedy Correct Solution: ``` n = int(input()) v = list(map(int, input().split())) new_v = [0] * (n) new_v[-1] = v[0] for i in range(1, len(v)): if v[i] > v[i - 1]: new_v[i] = new_v[i - 1] + v[i] - v[i - 1] else: new_v[i] = new_v[i - 1] new_v[-i - 1] = v[i] - new_v[i] print(*new_v) ...
output
1
99,503
12
199,007
Provide tags and a correct Python 3 solution for this coding contest problem. Mishka is trying really hard to avoid being kicked out of the university. In particular, he was doing absolutely nothing for the whole semester, miraculously passed some exams so that just one is left. There were n classes of that subject d...
instruction
0
99,504
12
199,008
Tags: greedy Correct Solution: ``` n = int(input()) arr = list(map(int,input().split())) ans=[0]*(n) l = 0 h = float('inf') for i in range(n//2): ans[i] = max(l,arr[i]-h) ans[n-1-i] = arr[i]-ans[i] l = ans[i] h = ans[n-1-i] print(*ans) ```
output
1
99,504
12
199,009
Provide tags and a correct Python 3 solution for this coding contest problem. Mishka is trying really hard to avoid being kicked out of the university. In particular, he was doing absolutely nothing for the whole semester, miraculously passed some exams so that just one is left. There were n classes of that subject d...
instruction
0
99,505
12
199,010
Tags: greedy Correct Solution: ``` n, b = int(input()), list(map(int, input().split())) a = [0 for _ in range(n)] a[n - 1], a[0] = b[0], 0 for i in range(1, n // 2): if a[n - i] < b[i] and b[i] - a[n - i] >= a[i - 1]: a[n - 1 - i], a[i] = a[n - i], b[i] - a[n - i] else: a[n - 1 - i], a[i] = b[i] - a[i - 1], a...
output
1
99,505
12
199,011
Provide tags and a correct Python 3 solution for this coding contest problem. Mishka is trying really hard to avoid being kicked out of the university. In particular, he was doing absolutely nothing for the whole semester, miraculously passed some exams so that just one is left. There were n classes of that subject d...
instruction
0
99,506
12
199,012
Tags: greedy Correct Solution: ``` import sys import os from math import* input=sys.stdin.buffer.readline n=int(input()) arr=list(map(int,input().split())) ans=[0]*n c=0 d=arr[0] ans[0]=c ans[n-1]=d for i in range(1,n//2): if arr[i]<=d: d=arr[i]-c else: c=max(c,arr[i]-d) d=arr[i]-c ans[i]=c ans[n-i-1]=d for ...
output
1
99,506
12
199,013
Provide tags and a correct Python 3 solution for this coding contest problem. Mishka is trying really hard to avoid being kicked out of the university. In particular, he was doing absolutely nothing for the whole semester, miraculously passed some exams so that just one is left. There were n classes of that subject d...
instruction
0
99,507
12
199,014
Tags: greedy Correct Solution: ``` from bisect import bisect_right as br from bisect import bisect_left as bl from collections import defaultdict from itertools import combinations import sys import math MAX = sys.maxsize MAXN = 10**6+10 MOD = 10**9+7 def isprime(n): n = abs(int(n)) if n < 2: return Fal...
output
1
99,507
12
199,015
Provide tags and a correct Python 3 solution for this coding contest problem. Mishka is trying really hard to avoid being kicked out of the university. In particular, he was doing absolutely nothing for the whole semester, miraculously passed some exams so that just one is left. There were n classes of that subject d...
instruction
0
99,508
12
199,016
Tags: greedy Correct Solution: ``` n = int(input()) arr = list(map(int, input().split())) left = list() right = list() for v in arr: if len(left) == 0: left.append(0) right.append(v) else: rvalue = min(v, right[-1]) lvalue = v - rvalue if lvalue < left[-1]: ...
output
1
99,508
12
199,017
Provide tags and a correct Python 3 solution for this coding contest problem. Mishka is trying really hard to avoid being kicked out of the university. In particular, he was doing absolutely nothing for the whole semester, miraculously passed some exams so that just one is left. There were n classes of that subject d...
instruction
0
99,509
12
199,018
Tags: greedy Correct Solution: ``` n = int(input()) b = [int(x) for x in input().split()] lh=[0] rh=[b[0]] for x in b[1:]: if x>=rh[-1]: y=x-rh[-1] if y>=lh[-1]: lh.append(y) rh.append(rh[-1]) else: lh.append(lh[-1]) rh.append(x-lh[-1]) els...
output
1
99,509
12
199,019
Provide tags and a correct Python 3 solution for this coding contest problem. Mishka is trying really hard to avoid being kicked out of the university. In particular, he was doing absolutely nothing for the whole semester, miraculously passed some exams so that just one is left. There were n classes of that subject d...
instruction
0
99,510
12
199,020
Tags: greedy Correct Solution: ``` n = int(input()) A = list(map(int,input().split())) res = [0]*n res[0] = 0 res[n-1] = A[0] for i in range(1,n//2): res[i] = max(res[i-1],A[i]-A[i-1] + res[i-1]) res[n-i-1] = A[i]-res[i] print(*res) ```
output
1
99,510
12
199,021
Provide tags and a correct Python 3 solution for this coding contest problem. Sasha likes programming. Once, during a very long contest, Sasha decided that he was a bit tired and needed to relax. So he did. But since Sasha isn't an ordinary guy, he prefers to relax unusually. During leisure time Sasha likes to upsolve...
instruction
0
99,519
12
199,038
Tags: dp, implementation Correct Solution: ``` #!/usr/bin/python3.6 ''' .__ .__ _______ _______ _________ ______| |__ |__| ____ ____ _______ _____ \ _ \ \ _ \\______ \ / ___/| | \ | | / \ / _ \\_ __ \\__ \ / /_\ \ / /_\ \ / / \___ \ ...
output
1
99,519
12
199,039
Provide tags and a correct Python 3 solution for this coding contest problem. Sasha likes programming. Once, during a very long contest, Sasha decided that he was a bit tired and needed to relax. So he did. But since Sasha isn't an ordinary guy, he prefers to relax unusually. During leisure time Sasha likes to upsolve...
instruction
0
99,520
12
199,040
Tags: dp, implementation Correct Solution: ``` n=int(input()) a=list(map(int,input().split())) ans=[[0]*(2**20+5) for i in range(2)] ans[1][0]=1 x,an=0,0 for i in range(n): x^=a[i] an+=ans[i%2][x] ans[i%2][x]+=1 print(an) ```
output
1
99,520
12
199,041
Provide tags and a correct Python 3 solution for this coding contest problem. Sasha likes programming. Once, during a very long contest, Sasha decided that he was a bit tired and needed to relax. So he did. But since Sasha isn't an ordinary guy, he prefers to relax unusually. During leisure time Sasha likes to upsolve...
instruction
0
99,521
12
199,042
Tags: dp, implementation Correct Solution: ``` list_int_input = lambda inp: list(map(int, inp.split())) int_input = lambda inp: int(inp) string_to_list_input = lambda inp: list(inp) n=int(input()) a=list_int_input(input()) a=[0]+a xl=[] for ind,val in enumerate(a): if ind>0: val=xl[-1]^val xl.append(va...
output
1
99,521
12
199,043
Provide tags and a correct Python 3 solution for this coding contest problem. Sasha likes programming. Once, during a very long contest, Sasha decided that he was a bit tired and needed to relax. So he did. But since Sasha isn't an ordinary guy, he prefers to relax unusually. During leisure time Sasha likes to upsolve...
instruction
0
99,522
12
199,044
Tags: dp, implementation Correct Solution: ``` input() N=1<<20 d=[1]+[0]*N,[0]*N r=s=i=0 for x in map(int,input().split()):s^=x;i^=1;r+=d[i][s];d[i][s]+=1 print(r) ```
output
1
99,522
12
199,045
Provide tags and a correct Python 3 solution for this coding contest problem. Sasha likes programming. Once, during a very long contest, Sasha decided that he was a bit tired and needed to relax. So he did. But since Sasha isn't an ordinary guy, he prefers to relax unusually. During leisure time Sasha likes to upsolve...
instruction
0
99,523
12
199,046
Tags: dp, implementation Correct Solution: ``` n = int(input()) a = list(map(int, input().split())) cnt = [[0 for i in range(int(2 << 20)+10)], [0 for i in range(int(2 << 20)+10)]] cnt[1][0] =1 x = 0 ans = 0 for i in range(n): x ^= a[i] ans += cnt[i % 2][x] cnt[i % 2][x] += 1 print(ans) ```
output
1
99,523
12
199,047
Provide tags and a correct Python 3 solution for this coding contest problem. Sasha likes programming. Once, during a very long contest, Sasha decided that he was a bit tired and needed to relax. So he did. But since Sasha isn't an ordinary guy, he prefers to relax unusually. During leisure time Sasha likes to upsolve...
instruction
0
99,524
12
199,048
Tags: dp, implementation Correct Solution: ``` import sys import math def getAndParseInt(num=1): string = (sys.stdin.readline()).strip() if num==1: return int(string) else: return [int(part) for part in string.split()] def getAndParseString(num=1,delim=" "): string = (sys.stdin.readline...
output
1
99,524
12
199,049
Provide tags and a correct Python 3 solution for this coding contest problem. Sasha likes programming. Once, during a very long contest, Sasha decided that he was a bit tired and needed to relax. So he did. But since Sasha isn't an ordinary guy, he prefers to relax unusually. During leisure time Sasha likes to upsolve...
instruction
0
99,525
12
199,050
Tags: dp, implementation Correct Solution: ``` def inpl(): return list(map(int, input().split())) from operator import xor from itertools import accumulate, chain from collections import Counter N = int(input()) A = list(accumulate([0] + inpl(), xor)) B = [a for i, a in enumerate(A) if i%2] A = [a for i, a in enumerat...
output
1
99,525
12
199,051
Provide tags and a correct Python 3 solution for this coding contest problem. Sasha likes programming. Once, during a very long contest, Sasha decided that he was a bit tired and needed to relax. So he did. But since Sasha isn't an ordinary guy, he prefers to relax unusually. During leisure time Sasha likes to upsolve...
instruction
0
99,526
12
199,052
Tags: dp, implementation Correct Solution: ``` import sys input = sys.stdin.readline n=int(input()) A=list(map(int,input().split())) AX=[0,A[0]] for i in range(1,n): AX.append(AX[i]^A[i]) LIST=sorted(set(AX)) DICT=dict() for i in range(len(LIST)): DICT[LIST[i]]=i NUMLIST=[[] for i in range(len(LIST))] f...
output
1
99,526
12
199,053
Provide tags and a correct Python 3 solution for this coding contest problem. This problem is given in two editions, which differ exclusively in the constraints on the number n. You are given an array of integers a[1], a[2], ..., a[n]. A block is a sequence of contiguous (consecutive) elements a[l], a[l+1], ..., a[r]...
instruction
0
99,535
12
199,070
Tags: greedy Correct Solution: ``` n = int(input()) a = list(map(int, input().split())) if n == 1: print(1) print('1 1') else: d = [[]]*(n-1) d[0] = a for i in range(1,n-1): d[i] = [d[i-1][j]+a[j+i] for j in range(0,n-i)] d2 = {} for i,d_ in enumerate(d): for j,x in enumerate...
output
1
99,535
12
199,071
Provide tags and a correct Python 3 solution for this coding contest problem. This problem is given in two editions, which differ exclusively in the constraints on the number n. You are given an array of integers a[1], a[2], ..., a[n]. A block is a sequence of contiguous (consecutive) elements a[l], a[l+1], ..., a[r]...
instruction
0
99,536
12
199,072
Tags: greedy Correct Solution: ``` from collections import defaultdict n = int(input()) arr = [int(i) for i in input().split()] prefix = [0 for i in range(n)] segments = defaultdict(list) prefix[0] = arr[0] for i in range(1,n): prefix[i] = prefix[i - 1] + arr[i] long = 0 long_i = 0 for i in range(n): for j...
output
1
99,536
12
199,073
Provide tags and a correct Python 3 solution for this coding contest problem. This problem is given in two editions, which differ exclusively in the constraints on the number n. You are given an array of integers a[1], a[2], ..., a[n]. A block is a sequence of contiguous (consecutive) elements a[l], a[l+1], ..., a[r]...
instruction
0
99,537
12
199,074
Tags: greedy Correct Solution: ``` n = int(input()) lst = list(map(int,input().split())) d,res,summa = {},{},0 for i,y in enumerate(lst): summa+=y s=summa for j in range(i+1): if d.get(s)==None: d[s]=[0,-1] res[s]=[] if d[s][1]<j: d[s][0]+=1 d[...
output
1
99,537
12
199,075
Provide tags and a correct Python 3 solution for this coding contest problem. This problem is given in two editions, which differ exclusively in the constraints on the number n. You are given an array of integers a[1], a[2], ..., a[n]. A block is a sequence of contiguous (consecutive) elements a[l], a[l+1], ..., a[r]...
instruction
0
99,538
12
199,076
Tags: greedy Correct Solution: ``` from collections import defaultdict def main(): n = int(input()) values = list(map(int, input().split(' '))) # print(values) ans = defaultdict(list) for i in range(n): s = 0 # print("---------- i = {} ----------".format(i)) for j in range(i,...
output
1
99,538
12
199,077
Provide tags and a correct Python 3 solution for this coding contest problem. This problem is given in two editions, which differ exclusively in the constraints on the number n. You are given an array of integers a[1], a[2], ..., a[n]. A block is a sequence of contiguous (consecutive) elements a[l], a[l+1], ..., a[r]...
instruction
0
99,539
12
199,078
Tags: greedy Correct Solution: ``` from itertools import accumulate def main(): n = int(input()) arr = list(map(int, input().split())) arr_sums = [0] + list(accumulate(arr)) blocks = {} for i in range(1, n+1): for j in range(i): total = arr_sums[i] - arr_sums[j] if...
output
1
99,539
12
199,079
Provide tags and a correct Python 3 solution for this coding contest problem. This problem is given in two editions, which differ exclusively in the constraints on the number n. You are given an array of integers a[1], a[2], ..., a[n]. A block is a sequence of contiguous (consecutive) elements a[l], a[l+1], ..., a[r]...
instruction
0
99,540
12
199,080
Tags: greedy Correct Solution: ``` n=int(input()) a=list(map(int,input().split())) dic={} for i in range(n): sm=0 for j in range(i,n): sm+=a[j] if sm in dic: dic[sm].append((i,j)) else: dic[sm]=[(i,j)] ans=0 anskey=-1 for key in dic: cnt=0 last=-1 for ...
output
1
99,540
12
199,081
Provide tags and a correct Python 3 solution for this coding contest problem. This problem is given in two editions, which differ exclusively in the constraints on the number n. You are given an array of integers a[1], a[2], ..., a[n]. A block is a sequence of contiguous (consecutive) elements a[l], a[l+1], ..., a[r]...
instruction
0
99,541
12
199,082
Tags: greedy Correct Solution: ``` n = int(input()) arr= list(map(int, input().split())) sums = {0: []} for i in range(n): sum = 0 for j in range(i, -1, -1): sum += arr[j] if sum not in sums.keys(): sums[sum] = [] sums[sum].append((j,i)) #print(sums) ans = (0, []) for k in s...
output
1
99,541
12
199,083
Provide tags and a correct Python 3 solution for this coding contest problem. This problem is given in two editions, which differ exclusively in the constraints on the number n. You are given an array of integers a[1], a[2], ..., a[n]. A block is a sequence of contiguous (consecutive) elements a[l], a[l+1], ..., a[r]...
instruction
0
99,542
12
199,084
Tags: greedy Correct Solution: ``` n=int(input()) arr=list(map(int,input().split())) dict1={} for i in range(n): val=0 for j in range(i,n): val+=arr[j] try: dict1[val].append((i,j)) except: KeyError dict1[val]=[(i,j)] ans=0 ansarr=[] for i in dict1.keys(): if(len(dict1[i])>ans): arr2=[] for j in r...
output
1
99,542
12
199,085
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. This problem is given in two editions, which differ exclusively in the constraints on the number n. You are given an array of integers a[1], a[2], ..., a[n]. A block is a sequence of contiguous...
instruction
0
99,543
12
199,086
Yes
output
1
99,543
12
199,087
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. This problem is given in two editions, which differ exclusively in the constraints on the number n. You are given an array of integers a[1], a[2], ..., a[n]. A block is a sequence of contiguous...
instruction
0
99,544
12
199,088
Yes
output
1
99,544
12
199,089
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. This problem is given in two editions, which differ exclusively in the constraints on the number n. You are given an array of integers a[1], a[2], ..., a[n]. A block is a sequence of contiguous...
instruction
0
99,545
12
199,090
Yes
output
1
99,545
12
199,091
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. This problem is given in two editions, which differ exclusively in the constraints on the number n. You are given an array of integers a[1], a[2], ..., a[n]. A block is a sequence of contiguous...
instruction
0
99,546
12
199,092
Yes
output
1
99,546
12
199,093
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. This problem is given in two editions, which differ exclusively in the constraints on the number n. You are given an array of integers a[1], a[2], ..., a[n]. A block is a sequence of contiguous...
instruction
0
99,547
12
199,094
No
output
1
99,547
12
199,095
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. This problem is given in two editions, which differ exclusively in the constraints on the number n. You are given an array of integers a[1], a[2], ..., a[n]. A block is a sequence of contiguous...
instruction
0
99,548
12
199,096
No
output
1
99,548
12
199,097
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. This problem is given in two editions, which differ exclusively in the constraints on the number n. You are given an array of integers a[1], a[2], ..., a[n]. A block is a sequence of contiguous...
instruction
0
99,549
12
199,098
No
output
1
99,549
12
199,099
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. This problem is given in two editions, which differ exclusively in the constraints on the number n. You are given an array of integers a[1], a[2], ..., a[n]. A block is a sequence of contiguous...
instruction
0
99,550
12
199,100
No
output
1
99,550
12
199,101
Provide tags and a correct Python 3 solution for this coding contest problem. We have a secret array. You don't know this array and you have to restore it. However, you know some facts about this array: * The array consists of n distinct positive (greater than 0) integers. * The array contains two elements x and...
instruction
0
99,614
12
199,228
Tags: brute force, math, number theory Correct Solution: ``` #!/usr/bin/env python3 # encoding: utf-8 #---------- # Constants #---------- #---------- # Functions #---------- # The function that solves the task def calc(n, x, y): best_maximum, best_k = 1000000001, 0 for m in range(1, n): k = (y -...
output
1
99,614
12
199,229
Provide tags and a correct Python 3 solution for this coding contest problem. We have a secret array. You don't know this array and you have to restore it. However, you know some facts about this array: * The array consists of n distinct positive (greater than 0) integers. * The array contains two elements x and...
instruction
0
99,615
12
199,230
Tags: brute force, math, number theory Correct Solution: ``` # -*- coding: utf-8 -*- """ Created on Mon Aug 3 21:10:40 2020 @author: dennis """ import atexit import io import sys _INPUT_LINES = sys.stdin.read().splitlines() input = iter(_INPUT_LINES).__next__ _OUTPUT_BUFFER = io.StringIO() sys.stdout = _OUTPUT_BUF...
output
1
99,615
12
199,231
Provide tags and a correct Python 3 solution for this coding contest problem. We have a secret array. You don't know this array and you have to restore it. However, you know some facts about this array: * The array consists of n distinct positive (greater than 0) integers. * The array contains two elements x and...
instruction
0
99,616
12
199,232
Tags: brute force, math, number theory Correct Solution: ``` def answer(n,x,y): diff=y-x d=-1 for i in range(n-1,0,-1): if diff%i==0: d=diff//i break l=[y] q=y-d while len(l)<n and q>0: l.append(q) q=q-d q=y+d while l...
output
1
99,616
12
199,233
Provide tags and a correct Python 3 solution for this coding contest problem. We have a secret array. You don't know this array and you have to restore it. However, you know some facts about this array: * The array consists of n distinct positive (greater than 0) integers. * The array contains two elements x and...
instruction
0
99,617
12
199,234
Tags: brute force, math, number theory Correct Solution: ``` t=int(input()) w=[] def func(t,h): i=1 boo=True while boo: if t % i==0: if t< i * h: boo=False return i else: i=i+1 else: i=i+1 for i in range(t):...
output
1
99,617
12
199,235