message stringlengths 2 433k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 113 108k | cluster float64 12 12 | __index_level_0__ int64 226 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
For the given sequence with n different elements find the number of increasing subsequences with k + 1 elements. It is guaranteed that the answer is not greater than 8·1018.
Input
First line contain two integer values n and k (1 ≤ n ≤ 105, 0 ≤ k ≤ 10) — the length of sequence and the number of elements in increasing subsequences.
Next n lines contains one integer ai (1 ≤ ai ≤ n) each — elements of sequence. All values ai are different.
Output
Print one integer — the answer to the problem.
Examples
Input
5 2
1
2
3
5
4
Output
7 | instruction | 0 | 21,622 | 12 | 43,244 |
Tags: data structures, dp
Correct Solution:
```
import os
from io import BytesIO
input = BytesIO(os.read(0, os.fstat(0).st_size)).readline
n, k = map(int, input().split())
a = [int(input()) for i in range(n)]
dp = [[0] * (n + 1) for i in range(k + 1)]
def query(f, i):
r = 0
while i > 0:
r += f[i - 1]
i &= i - 1
return r
def update(f, i, r):
while i < len(f):
f[i] += r
i |= i + 1
res = [1] * n
for i in range(n):
update(dp[0], a[i], 1)
for j in range(1, k + 1):
res[i] = query(dp[j - 1], a[i])
update(dp[j], a[i], res[i])
print(sum(res))
``` | output | 1 | 21,622 | 12 | 43,245 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For the given sequence with n different elements find the number of increasing subsequences with k + 1 elements. It is guaranteed that the answer is not greater than 8·1018.
Input
First line contain two integer values n and k (1 ≤ n ≤ 105, 0 ≤ k ≤ 10) — the length of sequence and the number of elements in increasing subsequences.
Next n lines contains one integer ai (1 ≤ ai ≤ n) each — elements of sequence. All values ai are different.
Output
Print one integer — the answer to the problem.
Examples
Input
5 2
1
2
3
5
4
Output
7 | instruction | 0 | 21,623 | 12 | 43,246 |
Tags: data structures, dp
Correct Solution:
```
"""
NTC here
"""
optimize = 1
#!/usr/bin/env pypy
if optimize:
import os
from io import BytesIO
input = BytesIO(os.read(0, os.fstat(0).st_size)).readline
def iin(): return int(input())
def lin(): return list(map(int, input().split()))
n, k = lin()
a = [iin() for _ in range(n)]
k1 = k+1
mx = n+1
b = [ [0 for i in range(mx+1)] for j in range(k1)]
def sum_b(a, i):
ans = 0
while(a > 0):
ans += b[i][a]
a -= a & (-a)
return ans
def sm_i(a, i):
return sum_b(mx-1, i)-sum_b(a, i)
def set_b(a, i, val):
while(a < mx):
b[i][a] += val
a += a & (-a)
a = a[::-1]
sol = 0
a1 = [1]*(k+1)
for i in a:
# print(*b, sep='\n')
for j in range(1, k1):
a1[j] = sm_i(i, j-1)
# print(i, a1)
for j in range(k1):
set_b(i, j, a1[j])
# b[j][i] += a1[j]
sol += a1[k]
print(sol)
``` | output | 1 | 21,623 | 12 | 43,247 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For the given sequence with n different elements find the number of increasing subsequences with k + 1 elements. It is guaranteed that the answer is not greater than 8·1018.
Input
First line contain two integer values n and k (1 ≤ n ≤ 105, 0 ≤ k ≤ 10) — the length of sequence and the number of elements in increasing subsequences.
Next n lines contains one integer ai (1 ≤ ai ≤ n) each — elements of sequence. All values ai are different.
Output
Print one integer — the answer to the problem.
Examples
Input
5 2
1
2
3
5
4
Output
7 | instruction | 0 | 21,624 | 12 | 43,248 |
Tags: data structures, dp
Correct Solution:
```
from bisect import bisect_right
from collections import defaultdict
import os
import sys
from io import BytesIO, IOBase
from collections import defaultdict
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
def sum(BIT, i):
s = 0
while i > 0:
s += BIT[i]
i -= i & (-i)
return s
def update(BIT, i, v):
while i < len(BIT):
BIT[i] += v
i += i & (-i)
def find(fen, k):
curr = 0
ans = 0
prevsum = 0
for i in range(19, -1, -1):
if ((curr + (1 << i) < n) and fen[curr + (1 << i)] + prevsum < k):
ans = curr + (1 << i)
curr = ans
prevsum += fen[curr]
return ans + 1
def Rank(x,BIT) :
return sum(BIT,x)
def least_significant_bit(i):
return ((i) & -(i))
def prefix_sum(index,BIT):
# 1-indexed
i = index + 1
result = 0
while i > 0:
result += BIT[i]
i -= least_significant_bit(i)
return result
def range_sum(start, end,BIT):
return (prefix_sum(end,BIT) - prefix_sum(start - 1,BIT))
n,k=map(int,input().split())
dp=[[0]*(n+1) for i in range(k+1)]
b=[]
for j in range(n):
b.append(int(input()))
ans=0
for i in range(n):
update(dp[0], b[i], 1)
p=1
for j in range(1,k+1):
p= sum(dp[j-1],b[i]-1)
update(dp[j],b[i],p)
ans+=p
print(ans)
``` | output | 1 | 21,624 | 12 | 43,249 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For the given sequence with n different elements find the number of increasing subsequences with k + 1 elements. It is guaranteed that the answer is not greater than 8·1018.
Input
First line contain two integer values n and k (1 ≤ n ≤ 105, 0 ≤ k ≤ 10) — the length of sequence and the number of elements in increasing subsequences.
Next n lines contains one integer ai (1 ≤ ai ≤ n) each — elements of sequence. All values ai are different.
Output
Print one integer — the answer to the problem.
Examples
Input
5 2
1
2
3
5
4
Output
7 | instruction | 0 | 21,625 | 12 | 43,250 |
Tags: data structures, dp
Correct Solution:
```
# by the authority of GOD author: manhar singh sachdev #
import os,sys
from io import BytesIO, IOBase
def update(tree,pos,diff,si):
pos += si-1
while pos:
tree[pos] += diff
pos >>= 1
def query(tree,l,r,si):
ans,l,r = 0,l+si-1,r+si-1
while l < r:
if l&1:
ans += tree[l]
l += 1
if not r&1:
ans += tree[r]
r -= 1
l,r = l>>1,r>>1
return ans+(0 if l!=r else tree[l])
def main():
n,k = map(int,input().split())
arr = [int(input()) for _ in range(n)]
si = 1<<(n.bit_length()-(not n&n-1))
dp = [[0]*n for _ in range(k+1)]
dp[0] = [1]*n
for i in range(1,k+1):
tree = [0]*(si<<1)
for j in range(n):
dp[i][j] = query(tree,1,arr[j],si)
update(tree,arr[j],dp[i-1][j],si)
print(sum(dp[-1]))
#Fast IO Region
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
if __name__ == '__main__':
main()
``` | output | 1 | 21,625 | 12 | 43,251 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For the given sequence with n different elements find the number of increasing subsequences with k + 1 elements. It is guaranteed that the answer is not greater than 8·1018.
Input
First line contain two integer values n and k (1 ≤ n ≤ 105, 0 ≤ k ≤ 10) — the length of sequence and the number of elements in increasing subsequences.
Next n lines contains one integer ai (1 ≤ ai ≤ n) each — elements of sequence. All values ai are different.
Output
Print one integer — the answer to the problem.
Examples
Input
5 2
1
2
3
5
4
Output
7
Submitted Solution:
```
#
# http://codeforces.com/contest/597/problem/C
#
from typing import List
class Solution:
def read(self, fenwickTree: List[int], index: int) -> int:
sum = 0
while index > 0:
sum += fenwickTree[index]
index -= index & (-index)
return sum
def update(self, fenwickTree: List[int], index: int, delta: int) -> None:
n = len(fenwickTree)
while index < n:
fenwickTree[index] += delta
index += index & (-index)
def numSubsequences(self) -> int:
n, k = map(int, input().strip().split())
fenwickTree = [0 for i in range(n + 1)]
combinations = [[0 for j in range(k + 1)] for i in range(n + 1)]
for i in range(n + 1):
combinations[i][0] = 1
for j in range(1, k + 1):
for i in range(j, n + 1):
combinations[i][j] = combinations[i - 1][j - 1] + combinations[i - 1][j]
result = 0
for i in range(n):
item = int(input().strip())
numLess = self.read(fenwickTree, item)
result += combinations[numLess][k]
self.update(fenwickTree, item, 1)
return result
if __name__ == "__main__":
s = Solution()
print(s.numSubsequences())
``` | instruction | 0 | 21,628 | 12 | 43,256 |
No | output | 1 | 21,628 | 12 | 43,257 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Where do odds begin, and where do they end? Where does hope emerge, and will they ever break?
Given an integer sequence a1, a2, ..., an of length n. Decide whether it is possible to divide it into an odd number of non-empty subsegments, the each of which has an odd length and begins and ends with odd numbers.
A subsegment is a contiguous slice of the whole sequence. For example, {3, 4, 5} and {1} are subsegments of sequence {1, 2, 3, 4, 5, 6}, while {1, 2, 4} and {7} are not.
Input
The first line of input contains a non-negative integer n (1 ≤ n ≤ 100) — the length of the sequence.
The second line contains n space-separated non-negative integers a1, a2, ..., an (0 ≤ ai ≤ 100) — the elements of the sequence.
Output
Output "Yes" if it's possible to fulfill the requirements, and "No" otherwise.
You can output each letter in any case (upper or lower).
Examples
Input
3
1 3 5
Output
Yes
Input
5
1 0 1 5 1
Output
Yes
Input
3
4 3 1
Output
No
Input
4
3 9 9 3
Output
No
Note
In the first example, divide the sequence into 1 subsegment: {1, 3, 5} and the requirements will be met.
In the second example, divide the sequence into 3 subsegments: {1, 0, 1}, {5}, {1}.
In the third example, one of the subsegments must start with 4 which is an even number, thus the requirements cannot be met.
In the fourth example, the sequence can be divided into 2 subsegments: {3, 9, 9}, {3}, but this is not a valid solution because 2 is an even number. | instruction | 0 | 21,685 | 12 | 43,370 |
Tags: implementation
Correct Solution:
```
_, nums =input(), [int(x) for x in input().split()]
def is_odd(num): return num % 2 != 0
from pdb import set_trace
group_len = 0
group_counter = 0
summ = 0
if not is_odd(nums[-1]) or not is_odd(nums[0]):
print("No")
exit()
for x in range(len(nums)):
group_len += 1
if is_odd(nums[x]):
if len(nums)-1 != x:
if not is_odd(nums[x+1]):
continue
if is_odd(group_len):
group_counter += 1
summ += group_len
group_len = 0
summ += group_len
if summ == len(nums) and is_odd(group_counter):
print("Yes")
else:
print("No")
``` | output | 1 | 21,685 | 12 | 43,371 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Where do odds begin, and where do they end? Where does hope emerge, and will they ever break?
Given an integer sequence a1, a2, ..., an of length n. Decide whether it is possible to divide it into an odd number of non-empty subsegments, the each of which has an odd length and begins and ends with odd numbers.
A subsegment is a contiguous slice of the whole sequence. For example, {3, 4, 5} and {1} are subsegments of sequence {1, 2, 3, 4, 5, 6}, while {1, 2, 4} and {7} are not.
Input
The first line of input contains a non-negative integer n (1 ≤ n ≤ 100) — the length of the sequence.
The second line contains n space-separated non-negative integers a1, a2, ..., an (0 ≤ ai ≤ 100) — the elements of the sequence.
Output
Output "Yes" if it's possible to fulfill the requirements, and "No" otherwise.
You can output each letter in any case (upper or lower).
Examples
Input
3
1 3 5
Output
Yes
Input
5
1 0 1 5 1
Output
Yes
Input
3
4 3 1
Output
No
Input
4
3 9 9 3
Output
No
Note
In the first example, divide the sequence into 1 subsegment: {1, 3, 5} and the requirements will be met.
In the second example, divide the sequence into 3 subsegments: {1, 0, 1}, {5}, {1}.
In the third example, one of the subsegments must start with 4 which is an even number, thus the requirements cannot be met.
In the fourth example, the sequence can be divided into 2 subsegments: {3, 9, 9}, {3}, but this is not a valid solution because 2 is an even number. | instruction | 0 | 21,686 | 12 | 43,372 |
Tags: implementation
Correct Solution:
```
def main():
n = int(input())
aa = list(map(int, input().split()))
print(('No', 'Yes')[n & 1 and aa[0] & 1 and aa[-1] & 1])
if __name__ == '__main__':
main()
``` | output | 1 | 21,686 | 12 | 43,373 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Where do odds begin, and where do they end? Where does hope emerge, and will they ever break?
Given an integer sequence a1, a2, ..., an of length n. Decide whether it is possible to divide it into an odd number of non-empty subsegments, the each of which has an odd length and begins and ends with odd numbers.
A subsegment is a contiguous slice of the whole sequence. For example, {3, 4, 5} and {1} are subsegments of sequence {1, 2, 3, 4, 5, 6}, while {1, 2, 4} and {7} are not.
Input
The first line of input contains a non-negative integer n (1 ≤ n ≤ 100) — the length of the sequence.
The second line contains n space-separated non-negative integers a1, a2, ..., an (0 ≤ ai ≤ 100) — the elements of the sequence.
Output
Output "Yes" if it's possible to fulfill the requirements, and "No" otherwise.
You can output each letter in any case (upper or lower).
Examples
Input
3
1 3 5
Output
Yes
Input
5
1 0 1 5 1
Output
Yes
Input
3
4 3 1
Output
No
Input
4
3 9 9 3
Output
No
Note
In the first example, divide the sequence into 1 subsegment: {1, 3, 5} and the requirements will be met.
In the second example, divide the sequence into 3 subsegments: {1, 0, 1}, {5}, {1}.
In the third example, one of the subsegments must start with 4 which is an even number, thus the requirements cannot be met.
In the fourth example, the sequence can be divided into 2 subsegments: {3, 9, 9}, {3}, but this is not a valid solution because 2 is an even number. | instruction | 0 | 21,687 | 12 | 43,374 |
Tags: implementation
Correct Solution:
```
n=int(input())
l=[]
f=False
l=list(map(int,(input().split())))
if n%2==1 and l[0]%2==1 and l[-1]%2==1:
print("yes")
else:
print('no')
``` | output | 1 | 21,687 | 12 | 43,375 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Where do odds begin, and where do they end? Where does hope emerge, and will they ever break?
Given an integer sequence a1, a2, ..., an of length n. Decide whether it is possible to divide it into an odd number of non-empty subsegments, the each of which has an odd length and begins and ends with odd numbers.
A subsegment is a contiguous slice of the whole sequence. For example, {3, 4, 5} and {1} are subsegments of sequence {1, 2, 3, 4, 5, 6}, while {1, 2, 4} and {7} are not.
Input
The first line of input contains a non-negative integer n (1 ≤ n ≤ 100) — the length of the sequence.
The second line contains n space-separated non-negative integers a1, a2, ..., an (0 ≤ ai ≤ 100) — the elements of the sequence.
Output
Output "Yes" if it's possible to fulfill the requirements, and "No" otherwise.
You can output each letter in any case (upper or lower).
Examples
Input
3
1 3 5
Output
Yes
Input
5
1 0 1 5 1
Output
Yes
Input
3
4 3 1
Output
No
Input
4
3 9 9 3
Output
No
Note
In the first example, divide the sequence into 1 subsegment: {1, 3, 5} and the requirements will be met.
In the second example, divide the sequence into 3 subsegments: {1, 0, 1}, {5}, {1}.
In the third example, one of the subsegments must start with 4 which is an even number, thus the requirements cannot be met.
In the fourth example, the sequence can be divided into 2 subsegments: {3, 9, 9}, {3}, but this is not a valid solution because 2 is an even number. | instruction | 0 | 21,688 | 12 | 43,376 |
Tags: implementation
Correct Solution:
```
n = int(input())
a = [int(x) for x in input().split()]
if a[0] % 2 == 0 or a[n-1] % 2 == 0 or n % 2 == 0:
print("No")
else:
print("Yes")
``` | output | 1 | 21,688 | 12 | 43,377 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Where do odds begin, and where do they end? Where does hope emerge, and will they ever break?
Given an integer sequence a1, a2, ..., an of length n. Decide whether it is possible to divide it into an odd number of non-empty subsegments, the each of which has an odd length and begins and ends with odd numbers.
A subsegment is a contiguous slice of the whole sequence. For example, {3, 4, 5} and {1} are subsegments of sequence {1, 2, 3, 4, 5, 6}, while {1, 2, 4} and {7} are not.
Input
The first line of input contains a non-negative integer n (1 ≤ n ≤ 100) — the length of the sequence.
The second line contains n space-separated non-negative integers a1, a2, ..., an (0 ≤ ai ≤ 100) — the elements of the sequence.
Output
Output "Yes" if it's possible to fulfill the requirements, and "No" otherwise.
You can output each letter in any case (upper or lower).
Examples
Input
3
1 3 5
Output
Yes
Input
5
1 0 1 5 1
Output
Yes
Input
3
4 3 1
Output
No
Input
4
3 9 9 3
Output
No
Note
In the first example, divide the sequence into 1 subsegment: {1, 3, 5} and the requirements will be met.
In the second example, divide the sequence into 3 subsegments: {1, 0, 1}, {5}, {1}.
In the third example, one of the subsegments must start with 4 which is an even number, thus the requirements cannot be met.
In the fourth example, the sequence can be divided into 2 subsegments: {3, 9, 9}, {3}, but this is not a valid solution because 2 is an even number. | instruction | 0 | 21,689 | 12 | 43,378 |
Tags: implementation
Correct Solution:
```
n = int(input())
a = list(map(int, input().split()))
if(n % 2 and a[n - 1] % 2 and a[0] % 2):
print("Yes")
else:
print("No")
``` | output | 1 | 21,689 | 12 | 43,379 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Where do odds begin, and where do they end? Where does hope emerge, and will they ever break?
Given an integer sequence a1, a2, ..., an of length n. Decide whether it is possible to divide it into an odd number of non-empty subsegments, the each of which has an odd length and begins and ends with odd numbers.
A subsegment is a contiguous slice of the whole sequence. For example, {3, 4, 5} and {1} are subsegments of sequence {1, 2, 3, 4, 5, 6}, while {1, 2, 4} and {7} are not.
Input
The first line of input contains a non-negative integer n (1 ≤ n ≤ 100) — the length of the sequence.
The second line contains n space-separated non-negative integers a1, a2, ..., an (0 ≤ ai ≤ 100) — the elements of the sequence.
Output
Output "Yes" if it's possible to fulfill the requirements, and "No" otherwise.
You can output each letter in any case (upper or lower).
Examples
Input
3
1 3 5
Output
Yes
Input
5
1 0 1 5 1
Output
Yes
Input
3
4 3 1
Output
No
Input
4
3 9 9 3
Output
No
Note
In the first example, divide the sequence into 1 subsegment: {1, 3, 5} and the requirements will be met.
In the second example, divide the sequence into 3 subsegments: {1, 0, 1}, {5}, {1}.
In the third example, one of the subsegments must start with 4 which is an even number, thus the requirements cannot be met.
In the fourth example, the sequence can be divided into 2 subsegments: {3, 9, 9}, {3}, but this is not a valid solution because 2 is an even number. | instruction | 0 | 21,690 | 12 | 43,380 |
Tags: implementation
Correct Solution:
```
n=int(input())
arr=list(map(int,input().split()))
if n==1:
if arr[0]%2==0:
print("No")
else:
print("Yes")
elif len(arr)%2==0:
print("No")
elif arr[0]%2==0 or arr[len(arr)-1]%2==0:
print("No")
else:
print("Yes")
``` | output | 1 | 21,690 | 12 | 43,381 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Where do odds begin, and where do they end? Where does hope emerge, and will they ever break?
Given an integer sequence a1, a2, ..., an of length n. Decide whether it is possible to divide it into an odd number of non-empty subsegments, the each of which has an odd length and begins and ends with odd numbers.
A subsegment is a contiguous slice of the whole sequence. For example, {3, 4, 5} and {1} are subsegments of sequence {1, 2, 3, 4, 5, 6}, while {1, 2, 4} and {7} are not.
Input
The first line of input contains a non-negative integer n (1 ≤ n ≤ 100) — the length of the sequence.
The second line contains n space-separated non-negative integers a1, a2, ..., an (0 ≤ ai ≤ 100) — the elements of the sequence.
Output
Output "Yes" if it's possible to fulfill the requirements, and "No" otherwise.
You can output each letter in any case (upper or lower).
Examples
Input
3
1 3 5
Output
Yes
Input
5
1 0 1 5 1
Output
Yes
Input
3
4 3 1
Output
No
Input
4
3 9 9 3
Output
No
Note
In the first example, divide the sequence into 1 subsegment: {1, 3, 5} and the requirements will be met.
In the second example, divide the sequence into 3 subsegments: {1, 0, 1}, {5}, {1}.
In the third example, one of the subsegments must start with 4 which is an even number, thus the requirements cannot be met.
In the fourth example, the sequence can be divided into 2 subsegments: {3, 9, 9}, {3}, but this is not a valid solution because 2 is an even number. | instruction | 0 | 21,691 | 12 | 43,382 |
Tags: implementation
Correct Solution:
```
n = int(input())
k = list(map(int, input().split()))
if n % 2 == 0:
print('No')
elif k[0] % 2 ==0 or k[-1] % 2 == 0:
print ('No')
else:
print('Yes')
``` | output | 1 | 21,691 | 12 | 43,383 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Where do odds begin, and where do they end? Where does hope emerge, and will they ever break?
Given an integer sequence a1, a2, ..., an of length n. Decide whether it is possible to divide it into an odd number of non-empty subsegments, the each of which has an odd length and begins and ends with odd numbers.
A subsegment is a contiguous slice of the whole sequence. For example, {3, 4, 5} and {1} are subsegments of sequence {1, 2, 3, 4, 5, 6}, while {1, 2, 4} and {7} are not.
Input
The first line of input contains a non-negative integer n (1 ≤ n ≤ 100) — the length of the sequence.
The second line contains n space-separated non-negative integers a1, a2, ..., an (0 ≤ ai ≤ 100) — the elements of the sequence.
Output
Output "Yes" if it's possible to fulfill the requirements, and "No" otherwise.
You can output each letter in any case (upper or lower).
Examples
Input
3
1 3 5
Output
Yes
Input
5
1 0 1 5 1
Output
Yes
Input
3
4 3 1
Output
No
Input
4
3 9 9 3
Output
No
Note
In the first example, divide the sequence into 1 subsegment: {1, 3, 5} and the requirements will be met.
In the second example, divide the sequence into 3 subsegments: {1, 0, 1}, {5}, {1}.
In the third example, one of the subsegments must start with 4 which is an even number, thus the requirements cannot be met.
In the fourth example, the sequence can be divided into 2 subsegments: {3, 9, 9}, {3}, but this is not a valid solution because 2 is an even number. | instruction | 0 | 21,692 | 12 | 43,384 |
Tags: implementation
Correct Solution:
```
'''
# Contest Question 1
ans = False
l,r,x,y,k = input().split()
l,r,x,y,k = [int(l), int(r), int(x), int(y), int(k)]
# k = exp/cost
# exp from (l,r) and cost from (x,y)
for i in range(x,y+1):
if(l <= i*k and i*k<= r):
ans = True
#ans = [i for i in range(x,y+1) if(l<=i*k <= r)]
if not ans:
print("NO")
else:
print("YES")
#print(list(ans))
'''
n=int(input())
arr=[int(x) for x in input().strip().split(' ')]
if(n%2 ==0): print("No")
else:
if(arr[0]%2 != 0 and arr[n-1]%2 != 0):
print("Yes")
else:
print("No")
``` | output | 1 | 21,692 | 12 | 43,385 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an interactive problem.
Jury has hidden a permutation p of integers from 0 to n - 1. You know only the length n. Remind that in permutation all integers are distinct.
Let b be the inverse permutation for p, i.e. pbi = i for all i. The only thing you can do is to ask xor of elements pi and bj, printing two indices i and j (not necessarily distinct). As a result of the query with indices i and j you'll get the value <image>, where <image> denotes the xor operation. You can find the description of xor operation in notes.
Note that some permutations can remain indistinguishable from the hidden one, even if you make all possible n2 queries. You have to compute the number of permutations indistinguishable from the hidden one, and print one of such permutations, making no more than 2n queries.
The hidden permutation does not depend on your queries.
Input
The first line contains single integer n (1 ≤ n ≤ 5000) — the length of the hidden permutation. You should read this integer first.
Output
When your program is ready to print the answer, print three lines.
In the first line print "!".
In the second line print single integer answers_cnt — the number of permutations indistinguishable from the hidden one, including the hidden one.
In the third line print n integers p0, p1, ..., pn - 1 (0 ≤ pi < n, all pi should be distinct) — one of the permutations indistinguishable from the hidden one.
Your program should terminate after printing the answer.
Interaction
To ask about xor of two elements, print a string "? i j", where i and j — are integers from 0 to n - 1 — the index of the permutation element and the index of the inverse permutation element you want to know the xor-sum for. After that print a line break and make flush operation.
After printing the query your program should read single integer — the value of <image>.
For a permutation of length n your program should make no more than 2n queries about xor-sum. Note that printing answer doesn't count as a query. Note that you can't ask more than 2n questions. If you ask more than 2n questions or at least one incorrect question, your solution will get "Wrong answer".
If at some moment your program reads -1 as an answer, it should immediately exit (for example, by calling exit(0)). You will get "Wrong answer" in this case, it means that you asked more than 2n questions, or asked an invalid question. If you ignore this, you can get other verdicts since your program will continue to read from a closed stream.
Your solution will get "Idleness Limit Exceeded", if you don't print anything or forget to flush the output, including for the final answer .
To flush you can use (just after printing line break):
* fflush(stdout) in C++;
* System.out.flush() in Java;
* stdout.flush() in Python;
* flush(output) in Pascal;
* For other languages see the documentation.
Hacking
For hacking use the following format:
n
p0 p1 ... pn - 1
Contestant programs will not be able to see this input.
Examples
Input
3
0
0
3
2
3
2
Output
? 0 0
? 1 1
? 1 2
? 0 2
? 2 1
? 2 0
!
1
0 1 2
Input
4
2
3
2
0
2
3
2
0
Output
? 0 1
? 1 2
? 2 3
? 3 3
? 3 2
? 2 1
? 1 0
? 0 0
!
2
3 1 2 0
Note
xor operation, or bitwise exclusive OR, is an operation performed over two integers, in which the i-th digit in binary representation of the result is equal to 1 if and only if exactly one of the two integers has the i-th digit in binary representation equal to 1. For more information, see [here](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
In the first example p = [0, 1, 2], thus b = [0, 1, 2], the values <image> are correct for the given i, j. There are no other permutations that give the same answers for the given queries.
The answers for the queries are:
* <image>,
* <image>,
* <image>,
* <image>,
* <image>,
* <image>.
In the second example p = [3, 1, 2, 0], and b = [3, 1, 2, 0], the values <image> match for all pairs i, j. But there is one more suitable permutation p = [0, 2, 1, 3], b = [0, 2, 1, 3] that matches all n2 possible queries as well. All other permutations do not match even the shown queries.
Submitted Solution:
```
def fact(x):
if x == 1:
return 1
return x * fact(x - 1)
n = int(input())
print("!")
print(fact(n))
s = ""
for i in range(n):
s += str(i)
s += " "
print(s)
``` | instruction | 0 | 21,701 | 12 | 43,402 |
No | output | 1 | 21,701 | 12 | 43,403 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an interactive problem.
Jury has hidden a permutation p of integers from 0 to n - 1. You know only the length n. Remind that in permutation all integers are distinct.
Let b be the inverse permutation for p, i.e. pbi = i for all i. The only thing you can do is to ask xor of elements pi and bj, printing two indices i and j (not necessarily distinct). As a result of the query with indices i and j you'll get the value <image>, where <image> denotes the xor operation. You can find the description of xor operation in notes.
Note that some permutations can remain indistinguishable from the hidden one, even if you make all possible n2 queries. You have to compute the number of permutations indistinguishable from the hidden one, and print one of such permutations, making no more than 2n queries.
The hidden permutation does not depend on your queries.
Input
The first line contains single integer n (1 ≤ n ≤ 5000) — the length of the hidden permutation. You should read this integer first.
Output
When your program is ready to print the answer, print three lines.
In the first line print "!".
In the second line print single integer answers_cnt — the number of permutations indistinguishable from the hidden one, including the hidden one.
In the third line print n integers p0, p1, ..., pn - 1 (0 ≤ pi < n, all pi should be distinct) — one of the permutations indistinguishable from the hidden one.
Your program should terminate after printing the answer.
Interaction
To ask about xor of two elements, print a string "? i j", where i and j — are integers from 0 to n - 1 — the index of the permutation element and the index of the inverse permutation element you want to know the xor-sum for. After that print a line break and make flush operation.
After printing the query your program should read single integer — the value of <image>.
For a permutation of length n your program should make no more than 2n queries about xor-sum. Note that printing answer doesn't count as a query. Note that you can't ask more than 2n questions. If you ask more than 2n questions or at least one incorrect question, your solution will get "Wrong answer".
If at some moment your program reads -1 as an answer, it should immediately exit (for example, by calling exit(0)). You will get "Wrong answer" in this case, it means that you asked more than 2n questions, or asked an invalid question. If you ignore this, you can get other verdicts since your program will continue to read from a closed stream.
Your solution will get "Idleness Limit Exceeded", if you don't print anything or forget to flush the output, including for the final answer .
To flush you can use (just after printing line break):
* fflush(stdout) in C++;
* System.out.flush() in Java;
* stdout.flush() in Python;
* flush(output) in Pascal;
* For other languages see the documentation.
Hacking
For hacking use the following format:
n
p0 p1 ... pn - 1
Contestant programs will not be able to see this input.
Examples
Input
3
0
0
3
2
3
2
Output
? 0 0
? 1 1
? 1 2
? 0 2
? 2 1
? 2 0
!
1
0 1 2
Input
4
2
3
2
0
2
3
2
0
Output
? 0 1
? 1 2
? 2 3
? 3 3
? 3 2
? 2 1
? 1 0
? 0 0
!
2
3 1 2 0
Note
xor operation, or bitwise exclusive OR, is an operation performed over two integers, in which the i-th digit in binary representation of the result is equal to 1 if and only if exactly one of the two integers has the i-th digit in binary representation equal to 1. For more information, see [here](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
In the first example p = [0, 1, 2], thus b = [0, 1, 2], the values <image> are correct for the given i, j. There are no other permutations that give the same answers for the given queries.
The answers for the queries are:
* <image>,
* <image>,
* <image>,
* <image>,
* <image>,
* <image>.
In the second example p = [3, 1, 2, 0], and b = [3, 1, 2, 0], the values <image> match for all pairs i, j. But there is one more suitable permutation p = [0, 2, 1, 3], b = [0, 2, 1, 3] that matches all n2 possible queries as well. All other permutations do not match even the shown queries.
Submitted Solution:
```
import sys
n = int(input())
for i in range(n):
print("?", 0, i)
sys.stdout.flush()
a = int(input())
if a == 0:
first = i
break
A = [first]
for i in range(1, n):
print("?", i, first)
sys.stdout.flush()
a = int(input())^first
A.append(a)
B = A[::-1]
l = len(A)
a = [0]*l
b = [0]*l
for i in range(l):
a[A[i]] = i
b[B[i]] = i
# print(A)
# print(a)
# print(B)
# print(b)
flag = True
for i in range(l):
for j in range(l):
if((A[i]^a[j]) != (B[i]^b[j])):
flag = False
break
print("!")
if flag:
print(2)
else:
print(1)
for i in A:
print(i, end=' ')
``` | instruction | 0 | 21,702 | 12 | 43,404 |
No | output | 1 | 21,702 | 12 | 43,405 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an interactive problem.
Jury has hidden a permutation p of integers from 0 to n - 1. You know only the length n. Remind that in permutation all integers are distinct.
Let b be the inverse permutation for p, i.e. pbi = i for all i. The only thing you can do is to ask xor of elements pi and bj, printing two indices i and j (not necessarily distinct). As a result of the query with indices i and j you'll get the value <image>, where <image> denotes the xor operation. You can find the description of xor operation in notes.
Note that some permutations can remain indistinguishable from the hidden one, even if you make all possible n2 queries. You have to compute the number of permutations indistinguishable from the hidden one, and print one of such permutations, making no more than 2n queries.
The hidden permutation does not depend on your queries.
Input
The first line contains single integer n (1 ≤ n ≤ 5000) — the length of the hidden permutation. You should read this integer first.
Output
When your program is ready to print the answer, print three lines.
In the first line print "!".
In the second line print single integer answers_cnt — the number of permutations indistinguishable from the hidden one, including the hidden one.
In the third line print n integers p0, p1, ..., pn - 1 (0 ≤ pi < n, all pi should be distinct) — one of the permutations indistinguishable from the hidden one.
Your program should terminate after printing the answer.
Interaction
To ask about xor of two elements, print a string "? i j", where i and j — are integers from 0 to n - 1 — the index of the permutation element and the index of the inverse permutation element you want to know the xor-sum for. After that print a line break and make flush operation.
After printing the query your program should read single integer — the value of <image>.
For a permutation of length n your program should make no more than 2n queries about xor-sum. Note that printing answer doesn't count as a query. Note that you can't ask more than 2n questions. If you ask more than 2n questions or at least one incorrect question, your solution will get "Wrong answer".
If at some moment your program reads -1 as an answer, it should immediately exit (for example, by calling exit(0)). You will get "Wrong answer" in this case, it means that you asked more than 2n questions, or asked an invalid question. If you ignore this, you can get other verdicts since your program will continue to read from a closed stream.
Your solution will get "Idleness Limit Exceeded", if you don't print anything or forget to flush the output, including for the final answer .
To flush you can use (just after printing line break):
* fflush(stdout) in C++;
* System.out.flush() in Java;
* stdout.flush() in Python;
* flush(output) in Pascal;
* For other languages see the documentation.
Hacking
For hacking use the following format:
n
p0 p1 ... pn - 1
Contestant programs will not be able to see this input.
Examples
Input
3
0
0
3
2
3
2
Output
? 0 0
? 1 1
? 1 2
? 0 2
? 2 1
? 2 0
!
1
0 1 2
Input
4
2
3
2
0
2
3
2
0
Output
? 0 1
? 1 2
? 2 3
? 3 3
? 3 2
? 2 1
? 1 0
? 0 0
!
2
3 1 2 0
Note
xor operation, or bitwise exclusive OR, is an operation performed over two integers, in which the i-th digit in binary representation of the result is equal to 1 if and only if exactly one of the two integers has the i-th digit in binary representation equal to 1. For more information, see [here](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
In the first example p = [0, 1, 2], thus b = [0, 1, 2], the values <image> are correct for the given i, j. There are no other permutations that give the same answers for the given queries.
The answers for the queries are:
* <image>,
* <image>,
* <image>,
* <image>,
* <image>,
* <image>.
In the second example p = [3, 1, 2, 0], and b = [3, 1, 2, 0], the values <image> match for all pairs i, j. But there is one more suitable permutation p = [0, 2, 1, 3], b = [0, 2, 1, 3] that matches all n2 possible queries as well. All other permutations do not match even the shown queries.
Submitted Solution:
```
import sys
n = int(input())
for i in range(n):
print("?", 0, i)
sys.stdout.flush()
a = int(input())
if a == 0:
first = i
break
A = [first]
for i in range(1, n):
print("?", i, first)
sys.stdout.flush()
a = int(input())^first
A.append(a)
B = A[::-1]
l = len(A)
a = [0]*l
b = [0]*l
for i in range(l):
a[A[i]] = i
b[B[i]] = i
flag = True
for i in range(l):
if(A[i]^a[i] != B[i]^b[i]):
flag = False
break
print("!")
if flag:
print(2)
else:
print(1)
for i in A:
print(i, end=' ')
``` | instruction | 0 | 21,703 | 12 | 43,406 |
No | output | 1 | 21,703 | 12 | 43,407 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an interactive problem.
Jury has hidden a permutation p of integers from 0 to n - 1. You know only the length n. Remind that in permutation all integers are distinct.
Let b be the inverse permutation for p, i.e. pbi = i for all i. The only thing you can do is to ask xor of elements pi and bj, printing two indices i and j (not necessarily distinct). As a result of the query with indices i and j you'll get the value <image>, where <image> denotes the xor operation. You can find the description of xor operation in notes.
Note that some permutations can remain indistinguishable from the hidden one, even if you make all possible n2 queries. You have to compute the number of permutations indistinguishable from the hidden one, and print one of such permutations, making no more than 2n queries.
The hidden permutation does not depend on your queries.
Input
The first line contains single integer n (1 ≤ n ≤ 5000) — the length of the hidden permutation. You should read this integer first.
Output
When your program is ready to print the answer, print three lines.
In the first line print "!".
In the second line print single integer answers_cnt — the number of permutations indistinguishable from the hidden one, including the hidden one.
In the third line print n integers p0, p1, ..., pn - 1 (0 ≤ pi < n, all pi should be distinct) — one of the permutations indistinguishable from the hidden one.
Your program should terminate after printing the answer.
Interaction
To ask about xor of two elements, print a string "? i j", where i and j — are integers from 0 to n - 1 — the index of the permutation element and the index of the inverse permutation element you want to know the xor-sum for. After that print a line break and make flush operation.
After printing the query your program should read single integer — the value of <image>.
For a permutation of length n your program should make no more than 2n queries about xor-sum. Note that printing answer doesn't count as a query. Note that you can't ask more than 2n questions. If you ask more than 2n questions or at least one incorrect question, your solution will get "Wrong answer".
If at some moment your program reads -1 as an answer, it should immediately exit (for example, by calling exit(0)). You will get "Wrong answer" in this case, it means that you asked more than 2n questions, or asked an invalid question. If you ignore this, you can get other verdicts since your program will continue to read from a closed stream.
Your solution will get "Idleness Limit Exceeded", if you don't print anything or forget to flush the output, including for the final answer .
To flush you can use (just after printing line break):
* fflush(stdout) in C++;
* System.out.flush() in Java;
* stdout.flush() in Python;
* flush(output) in Pascal;
* For other languages see the documentation.
Hacking
For hacking use the following format:
n
p0 p1 ... pn - 1
Contestant programs will not be able to see this input.
Examples
Input
3
0
0
3
2
3
2
Output
? 0 0
? 1 1
? 1 2
? 0 2
? 2 1
? 2 0
!
1
0 1 2
Input
4
2
3
2
0
2
3
2
0
Output
? 0 1
? 1 2
? 2 3
? 3 3
? 3 2
? 2 1
? 1 0
? 0 0
!
2
3 1 2 0
Note
xor operation, or bitwise exclusive OR, is an operation performed over two integers, in which the i-th digit in binary representation of the result is equal to 1 if and only if exactly one of the two integers has the i-th digit in binary representation equal to 1. For more information, see [here](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
In the first example p = [0, 1, 2], thus b = [0, 1, 2], the values <image> are correct for the given i, j. There are no other permutations that give the same answers for the given queries.
The answers for the queries are:
* <image>,
* <image>,
* <image>,
* <image>,
* <image>,
* <image>.
In the second example p = [3, 1, 2, 0], and b = [3, 1, 2, 0], the values <image> match for all pairs i, j. But there is one more suitable permutation p = [0, 2, 1, 3], b = [0, 2, 1, 3] that matches all n2 possible queries as well. All other permutations do not match even the shown queries.
Submitted Solution:
```
def fact(x):
if x == 1:
return 1
return x * fact(x - 1)
n = int(input())
print("!")
print(fact(n))
s = ""
for i in range(n):
s += str(i + 1)
s += " "
print(s)
``` | instruction | 0 | 21,704 | 12 | 43,408 |
No | output | 1 | 21,704 | 12 | 43,409 |
Provide tags and a correct Python 3 solution for this coding contest problem.
"We've tried solitary confinement, waterboarding and listening to Just In Beaver, to no avail. We need something extreme."
"Little Alena got an array as a birthday present..."
The array b of length n is obtained from the array a of length n and two integers l and r (l ≤ r) using the following procedure:
b1 = b2 = b3 = b4 = 0.
For all 5 ≤ i ≤ n:
* bi = 0 if ai, ai - 1, ai - 2, ai - 3, ai - 4 > r and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 1
* bi = 1 if ai, ai - 1, ai - 2, ai - 3, ai - 4 < l and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 0
* bi = bi - 1 otherwise
You are given arrays a and b' of the same length. Find two integers l and r (l ≤ r), such that applying the algorithm described above will yield an array b equal to b'.
It's guaranteed that the answer exists.
Input
The first line of input contains a single integer n (5 ≤ n ≤ 105) — the length of a and b'.
The second line of input contains n space separated integers a1, ..., an ( - 109 ≤ ai ≤ 109) — the elements of a.
The third line of input contains a string of n characters, consisting of 0 and 1 — the elements of b'. Note that they are not separated by spaces.
Output
Output two integers l and r ( - 109 ≤ l ≤ r ≤ 109), conforming to the requirements described above.
If there are multiple solutions, output any of them.
It's guaranteed that the answer exists.
Examples
Input
5
1 2 3 4 5
00001
Output
6 15
Input
10
-10 -9 -8 -7 -6 6 7 8 9 10
0000111110
Output
-5 5
Note
In the first test case any pair of l and r pair is valid, if 6 ≤ l ≤ r ≤ 109, in that case b5 = 1, because a1, ..., a5 < l. | instruction | 0 | 21,724 | 12 | 43,448 |
Tags: binary search, implementation
Correct Solution:
```
n = int(input());
arr = [];
inf = 2000000000;
def mini(idx):
return min(arr[idx],min(arr[idx-1],min(arr[idx-2],min(arr[idx-3],arr[idx-4]))));
def maxi(idx):
return max(arr[idx],max(arr[idx-1],max(arr[idx-2],max(arr[idx-3],arr[idx-4]))));
arr = [int(x) for x in input().split()]
str = input();
zero = 4;
one = 0;
l = -inf;
r = inf;
for i in range(4,n):
if(zero == 4 and str[i] == '1'):
l = max(l,maxi(i));
if(one == 4 and str[i] == '0'):
r = min(r,mini(i));
if(str[i-4] == '1'):
one = one - 1;
else:
zero = zero-1;
if(str[i] == '0'):
zero = zero+1;
else:
one = one + 1;
if(l != -inf):
l = l + 1;
if(r != inf):
r = r - 1;
elif(l != -inf and r == inf):
r = l;
for i in range (4,n):
r = max(r,mini(i));
elif(l == -inf and r == inf):
l = inf;
for i in range(4,n):
l = min(l,maxi(i));
r = l;
print(l,r);
``` | output | 1 | 21,724 | 12 | 43,449 |
Provide tags and a correct Python 3 solution for this coding contest problem.
"We've tried solitary confinement, waterboarding and listening to Just In Beaver, to no avail. We need something extreme."
"Little Alena got an array as a birthday present..."
The array b of length n is obtained from the array a of length n and two integers l and r (l ≤ r) using the following procedure:
b1 = b2 = b3 = b4 = 0.
For all 5 ≤ i ≤ n:
* bi = 0 if ai, ai - 1, ai - 2, ai - 3, ai - 4 > r and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 1
* bi = 1 if ai, ai - 1, ai - 2, ai - 3, ai - 4 < l and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 0
* bi = bi - 1 otherwise
You are given arrays a and b' of the same length. Find two integers l and r (l ≤ r), such that applying the algorithm described above will yield an array b equal to b'.
It's guaranteed that the answer exists.
Input
The first line of input contains a single integer n (5 ≤ n ≤ 105) — the length of a and b'.
The second line of input contains n space separated integers a1, ..., an ( - 109 ≤ ai ≤ 109) — the elements of a.
The third line of input contains a string of n characters, consisting of 0 and 1 — the elements of b'. Note that they are not separated by spaces.
Output
Output two integers l and r ( - 109 ≤ l ≤ r ≤ 109), conforming to the requirements described above.
If there are multiple solutions, output any of them.
It's guaranteed that the answer exists.
Examples
Input
5
1 2 3 4 5
00001
Output
6 15
Input
10
-10 -9 -8 -7 -6 6 7 8 9 10
0000111110
Output
-5 5
Note
In the first test case any pair of l and r pair is valid, if 6 ≤ l ≤ r ≤ 109, in that case b5 = 1, because a1, ..., a5 < l. | instruction | 0 | 21,725 | 12 | 43,450 |
Tags: binary search, implementation
Correct Solution:
```
import sys
#from io import StringIO
#sys.stdin = StringIO(open(__file__.replace('.py', '.in')).read())
n = int(input())
a = list(map(int, input().split()))
b = list(map(int, input()))
l = -10 ** 9
r = 10 ** 9
p = a[0:5]
for i in range(4, n):
if b[i] == 1 and sum(b[i-4:i]) == 0:
l = max(l, max(a[i-4:i+1]))
elif b[i] == 0 and sum(b[i-4:i]) == 4:
r = min(r, min(a[i-4:i+1]))
print(l+1, r-1)
``` | output | 1 | 21,725 | 12 | 43,451 |
Provide tags and a correct Python 3 solution for this coding contest problem.
"We've tried solitary confinement, waterboarding and listening to Just In Beaver, to no avail. We need something extreme."
"Little Alena got an array as a birthday present..."
The array b of length n is obtained from the array a of length n and two integers l and r (l ≤ r) using the following procedure:
b1 = b2 = b3 = b4 = 0.
For all 5 ≤ i ≤ n:
* bi = 0 if ai, ai - 1, ai - 2, ai - 3, ai - 4 > r and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 1
* bi = 1 if ai, ai - 1, ai - 2, ai - 3, ai - 4 < l and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 0
* bi = bi - 1 otherwise
You are given arrays a and b' of the same length. Find two integers l and r (l ≤ r), such that applying the algorithm described above will yield an array b equal to b'.
It's guaranteed that the answer exists.
Input
The first line of input contains a single integer n (5 ≤ n ≤ 105) — the length of a and b'.
The second line of input contains n space separated integers a1, ..., an ( - 109 ≤ ai ≤ 109) — the elements of a.
The third line of input contains a string of n characters, consisting of 0 and 1 — the elements of b'. Note that they are not separated by spaces.
Output
Output two integers l and r ( - 109 ≤ l ≤ r ≤ 109), conforming to the requirements described above.
If there are multiple solutions, output any of them.
It's guaranteed that the answer exists.
Examples
Input
5
1 2 3 4 5
00001
Output
6 15
Input
10
-10 -9 -8 -7 -6 6 7 8 9 10
0000111110
Output
-5 5
Note
In the first test case any pair of l and r pair is valid, if 6 ≤ l ≤ r ≤ 109, in that case b5 = 1, because a1, ..., a5 < l. | instruction | 0 | 21,726 | 12 | 43,452 |
Tags: binary search, implementation
Correct Solution:
```
n, a, b, l, r = int(input()), list(map(int, input().split())), input(), -10**9, 10**9
for i in range(4, n):
if b[i-4:i+1]=="00001": l = max(l, max(a[i-4:i+1])+1)
if b[i-4:i+1]=="11110": r = min(r, min(a[i-4:i+1])-1)
print(l, r)
``` | output | 1 | 21,726 | 12 | 43,453 |
Provide tags and a correct Python 3 solution for this coding contest problem.
"We've tried solitary confinement, waterboarding and listening to Just In Beaver, to no avail. We need something extreme."
"Little Alena got an array as a birthday present..."
The array b of length n is obtained from the array a of length n and two integers l and r (l ≤ r) using the following procedure:
b1 = b2 = b3 = b4 = 0.
For all 5 ≤ i ≤ n:
* bi = 0 if ai, ai - 1, ai - 2, ai - 3, ai - 4 > r and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 1
* bi = 1 if ai, ai - 1, ai - 2, ai - 3, ai - 4 < l and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 0
* bi = bi - 1 otherwise
You are given arrays a and b' of the same length. Find two integers l and r (l ≤ r), such that applying the algorithm described above will yield an array b equal to b'.
It's guaranteed that the answer exists.
Input
The first line of input contains a single integer n (5 ≤ n ≤ 105) — the length of a and b'.
The second line of input contains n space separated integers a1, ..., an ( - 109 ≤ ai ≤ 109) — the elements of a.
The third line of input contains a string of n characters, consisting of 0 and 1 — the elements of b'. Note that they are not separated by spaces.
Output
Output two integers l and r ( - 109 ≤ l ≤ r ≤ 109), conforming to the requirements described above.
If there are multiple solutions, output any of them.
It's guaranteed that the answer exists.
Examples
Input
5
1 2 3 4 5
00001
Output
6 15
Input
10
-10 -9 -8 -7 -6 6 7 8 9 10
0000111110
Output
-5 5
Note
In the first test case any pair of l and r pair is valid, if 6 ≤ l ≤ r ≤ 109, in that case b5 = 1, because a1, ..., a5 < l. | instruction | 0 | 21,727 | 12 | 43,454 |
Tags: binary search, implementation
Correct Solution:
```
from sys import stdin as cin
def main():
n = int(input())
a = list(map(int, input().split()))
b = input()
l, r = '?', '?'
for i in range(1, n):
if b[i] == '1' and b[i-1] == '0':
if l == '?':
l = 1 + max(a[i], a[i-1], a[i-2], a[i-3], a[i-4])
else:
l = max(l, 1 + max(a[i], a[i-1], a[i-2], a[i-3], a[i-4]))
if b[i] == '0' and b[i-1] == '1':
if r == '?':
r = min(a[i], a[i-1], a[i-2], a[i-3], a[i-4]) - 1
else:
r = min(r, min(a[i], a[i-1], a[i-2], a[i-3], a[i-4]) - 1)
if l == '?':
l = -1000000000
if r == '?':
r = 1000000000
print(l, r)
main()
``` | output | 1 | 21,727 | 12 | 43,455 |
Provide tags and a correct Python 3 solution for this coding contest problem.
"We've tried solitary confinement, waterboarding and listening to Just In Beaver, to no avail. We need something extreme."
"Little Alena got an array as a birthday present..."
The array b of length n is obtained from the array a of length n and two integers l and r (l ≤ r) using the following procedure:
b1 = b2 = b3 = b4 = 0.
For all 5 ≤ i ≤ n:
* bi = 0 if ai, ai - 1, ai - 2, ai - 3, ai - 4 > r and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 1
* bi = 1 if ai, ai - 1, ai - 2, ai - 3, ai - 4 < l and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 0
* bi = bi - 1 otherwise
You are given arrays a and b' of the same length. Find two integers l and r (l ≤ r), such that applying the algorithm described above will yield an array b equal to b'.
It's guaranteed that the answer exists.
Input
The first line of input contains a single integer n (5 ≤ n ≤ 105) — the length of a and b'.
The second line of input contains n space separated integers a1, ..., an ( - 109 ≤ ai ≤ 109) — the elements of a.
The third line of input contains a string of n characters, consisting of 0 and 1 — the elements of b'. Note that they are not separated by spaces.
Output
Output two integers l and r ( - 109 ≤ l ≤ r ≤ 109), conforming to the requirements described above.
If there are multiple solutions, output any of them.
It's guaranteed that the answer exists.
Examples
Input
5
1 2 3 4 5
00001
Output
6 15
Input
10
-10 -9 -8 -7 -6 6 7 8 9 10
0000111110
Output
-5 5
Note
In the first test case any pair of l and r pair is valid, if 6 ≤ l ≤ r ≤ 109, in that case b5 = 1, because a1, ..., a5 < l. | instruction | 0 | 21,728 | 12 | 43,456 |
Tags: binary search, implementation
Correct Solution:
```
def main():
n, aa, s = int(input()), list(map(float, input().split())), input()
l, r, abuf, bbuf = -1000000001., 1000000001., aa[:5], [False] * 4
for i in range(4, n):
abuf[i % 5], b = aa[i], s[i] == '1'
if b:
if not any(bbuf) and l < max(abuf):
l = max(abuf)
else:
if all(bbuf) and r > min(abuf):
r = min(abuf)
bbuf[i % 4] = b
print(int(l) + 1, int(r) - 1)
if __name__ == "__main__":
main()
``` | output | 1 | 21,728 | 12 | 43,457 |
Provide tags and a correct Python 3 solution for this coding contest problem.
"We've tried solitary confinement, waterboarding and listening to Just In Beaver, to no avail. We need something extreme."
"Little Alena got an array as a birthday present..."
The array b of length n is obtained from the array a of length n and two integers l and r (l ≤ r) using the following procedure:
b1 = b2 = b3 = b4 = 0.
For all 5 ≤ i ≤ n:
* bi = 0 if ai, ai - 1, ai - 2, ai - 3, ai - 4 > r and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 1
* bi = 1 if ai, ai - 1, ai - 2, ai - 3, ai - 4 < l and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 0
* bi = bi - 1 otherwise
You are given arrays a and b' of the same length. Find two integers l and r (l ≤ r), such that applying the algorithm described above will yield an array b equal to b'.
It's guaranteed that the answer exists.
Input
The first line of input contains a single integer n (5 ≤ n ≤ 105) — the length of a and b'.
The second line of input contains n space separated integers a1, ..., an ( - 109 ≤ ai ≤ 109) — the elements of a.
The third line of input contains a string of n characters, consisting of 0 and 1 — the elements of b'. Note that they are not separated by spaces.
Output
Output two integers l and r ( - 109 ≤ l ≤ r ≤ 109), conforming to the requirements described above.
If there are multiple solutions, output any of them.
It's guaranteed that the answer exists.
Examples
Input
5
1 2 3 4 5
00001
Output
6 15
Input
10
-10 -9 -8 -7 -6 6 7 8 9 10
0000111110
Output
-5 5
Note
In the first test case any pair of l and r pair is valid, if 6 ≤ l ≤ r ≤ 109, in that case b5 = 1, because a1, ..., a5 < l. | instruction | 0 | 21,729 | 12 | 43,458 |
Tags: binary search, implementation
Correct Solution:
```
import time
import math
debug = False
nDayQuant = int(input())
Temps = list(map(int, input().split(' ')))
Status = input()
nMaxTemp = 1000000000
nMinTemp = -1000000000
nLowTempMin = nMinTemp
nLowTempMax = nMaxTemp
nHighTempMin = nMinTemp
nHighTempMax = nMaxTemp
if debug : print("---")
begin = time.time()
def max5(nDay):
global Temps
nRet = Temps[nDay]
for i in range (nDay-4, nDay):
if Temps[i] > nRet:
nRet = Temps[i]
return nRet
def min5(nDay):
global Temps
nRet = Temps[nDay]
for i in range (nDay-4, nDay):
if Temps[i] < nRet:
nRet = Temps[i]
return nRet
nLastStatus = "0"
nOffCount = 4
nOnCount = 0
for i in range(4, nDayQuant):
if debug : print("i: ", i)
if Status[i] == "1":
nOnCount += 1
nOffCount = 0
else:
nOnCount = 0
nOffCount += 1
if (Status[i] != nLastStatus):
if debug : print("Status[i]: ", Status[i])
if Status[i] == "1":
nCurrTemp = max5(i)
if debug : print("nCurrTemp: ", nCurrTemp)
if nCurrTemp >= nLowTempMin:
nLowTempMin = nCurrTemp+1
if debug : print("(Change) nLowTempMin: ", nLowTempMin)
else:
nCurrTemp = min5(i)
if debug : print("nCurrTemp: ", nCurrTemp)
if nCurrTemp <= nHighTempMax:
nHighTempMax = nCurrTemp-1
if debug : print("(Change) nHighTempMax: ", nHighTempMax)
nLastStatus = Status[i]
else:
if nOnCount > 4:
nCurrTemp = min5(i)
if debug : print("nCurrTemp: ", nCurrTemp)
if nCurrTemp > nHighTempMin:
nHighTempMin = nCurrTemp
if debug : print("(Save) nHighTempMin: ", nHighTempMin)
if nOffCount > 4:
nCurrTemp = max5(i)
if debug : print("nCurrTemp: ", nCurrTemp)
if nCurrTemp < nLowTempMax:
nLowTempMax = nCurrTemp
if debug : print("(Save) nLowTempMax: ", nLowTempMax)
if debug : print(nLowTempMin, nLowTempMax, nHighTempMin, nHighTempMax)
if nHighTempMin < nLowTempMin:
nHighTempMin = nLowTempMin
if nLowTempMax > nHighTempMax:
nLowTempMax = nHighTempMax
if debug : print(nLowTempMin, nLowTempMax, nHighTempMin, nHighTempMax)
if nLowTempMax <= nHighTempMin:
print(nLowTempMax, nHighTempMin)
elif nHighTempMin != nMinTemp:
print(nHighTempMin, nHighTempMin)
else:
print(nLowTempMax, nLowTempMax)
if debug : print(time.time() - begin)
if debug : print("---")
#print(nLowTemp, nHighTemp)
``` | output | 1 | 21,729 | 12 | 43,459 |
Provide tags and a correct Python 3 solution for this coding contest problem.
"We've tried solitary confinement, waterboarding and listening to Just In Beaver, to no avail. We need something extreme."
"Little Alena got an array as a birthday present..."
The array b of length n is obtained from the array a of length n and two integers l and r (l ≤ r) using the following procedure:
b1 = b2 = b3 = b4 = 0.
For all 5 ≤ i ≤ n:
* bi = 0 if ai, ai - 1, ai - 2, ai - 3, ai - 4 > r and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 1
* bi = 1 if ai, ai - 1, ai - 2, ai - 3, ai - 4 < l and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 0
* bi = bi - 1 otherwise
You are given arrays a and b' of the same length. Find two integers l and r (l ≤ r), such that applying the algorithm described above will yield an array b equal to b'.
It's guaranteed that the answer exists.
Input
The first line of input contains a single integer n (5 ≤ n ≤ 105) — the length of a and b'.
The second line of input contains n space separated integers a1, ..., an ( - 109 ≤ ai ≤ 109) — the elements of a.
The third line of input contains a string of n characters, consisting of 0 and 1 — the elements of b'. Note that they are not separated by spaces.
Output
Output two integers l and r ( - 109 ≤ l ≤ r ≤ 109), conforming to the requirements described above.
If there are multiple solutions, output any of them.
It's guaranteed that the answer exists.
Examples
Input
5
1 2 3 4 5
00001
Output
6 15
Input
10
-10 -9 -8 -7 -6 6 7 8 9 10
0000111110
Output
-5 5
Note
In the first test case any pair of l and r pair is valid, if 6 ≤ l ≤ r ≤ 109, in that case b5 = 1, because a1, ..., a5 < l. | instruction | 0 | 21,730 | 12 | 43,460 |
Tags: binary search, implementation
Correct Solution:
```
n = int(input())
a = list(map(int, input().split()))
b = input()
r = 1000000000
l = -r
for i in range(4, n):
if b[i - 1] != b[i]:
if b[i] == '0':
r = min(r, min(a[i - 4: i + 1]) - 1)
else:
l = max(l, max(a[i - 4: i + 1]) + 1)
print(l, r)
``` | output | 1 | 21,730 | 12 | 43,461 |
Provide tags and a correct Python 3 solution for this coding contest problem.
"We've tried solitary confinement, waterboarding and listening to Just In Beaver, to no avail. We need something extreme."
"Little Alena got an array as a birthday present..."
The array b of length n is obtained from the array a of length n and two integers l and r (l ≤ r) using the following procedure:
b1 = b2 = b3 = b4 = 0.
For all 5 ≤ i ≤ n:
* bi = 0 if ai, ai - 1, ai - 2, ai - 3, ai - 4 > r and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 1
* bi = 1 if ai, ai - 1, ai - 2, ai - 3, ai - 4 < l and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 0
* bi = bi - 1 otherwise
You are given arrays a and b' of the same length. Find two integers l and r (l ≤ r), such that applying the algorithm described above will yield an array b equal to b'.
It's guaranteed that the answer exists.
Input
The first line of input contains a single integer n (5 ≤ n ≤ 105) — the length of a and b'.
The second line of input contains n space separated integers a1, ..., an ( - 109 ≤ ai ≤ 109) — the elements of a.
The third line of input contains a string of n characters, consisting of 0 and 1 — the elements of b'. Note that they are not separated by spaces.
Output
Output two integers l and r ( - 109 ≤ l ≤ r ≤ 109), conforming to the requirements described above.
If there are multiple solutions, output any of them.
It's guaranteed that the answer exists.
Examples
Input
5
1 2 3 4 5
00001
Output
6 15
Input
10
-10 -9 -8 -7 -6 6 7 8 9 10
0000111110
Output
-5 5
Note
In the first test case any pair of l and r pair is valid, if 6 ≤ l ≤ r ≤ 109, in that case b5 = 1, because a1, ..., a5 < l. | instruction | 0 | 21,731 | 12 | 43,462 |
Tags: binary search, implementation
Correct Solution:
```
import sys
input = sys.stdin.readline
n = int(input())
a = list(map(int, input().split()))
b = list(map(int, list(input()[:-1])))
l, r = -10**9, 10**9
for i in range(4, n):
s = b[i-1]+b[i-2]+b[i-3]+b[i-4]
if s==0 and b[i]==1:
l = max(l, max(a[i], a[i-1], a[i-2], a[i-3], a[i-4])+1)
elif s==4 and b[i]==0:
r = min(r, min(a[i], a[i-1], a[i-2], a[i-3], a[i-4])-1)
print(l, r)
``` | output | 1 | 21,731 | 12 | 43,463 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
"We've tried solitary confinement, waterboarding and listening to Just In Beaver, to no avail. We need something extreme."
"Little Alena got an array as a birthday present..."
The array b of length n is obtained from the array a of length n and two integers l and r (l ≤ r) using the following procedure:
b1 = b2 = b3 = b4 = 0.
For all 5 ≤ i ≤ n:
* bi = 0 if ai, ai - 1, ai - 2, ai - 3, ai - 4 > r and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 1
* bi = 1 if ai, ai - 1, ai - 2, ai - 3, ai - 4 < l and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 0
* bi = bi - 1 otherwise
You are given arrays a and b' of the same length. Find two integers l and r (l ≤ r), such that applying the algorithm described above will yield an array b equal to b'.
It's guaranteed that the answer exists.
Input
The first line of input contains a single integer n (5 ≤ n ≤ 105) — the length of a and b'.
The second line of input contains n space separated integers a1, ..., an ( - 109 ≤ ai ≤ 109) — the elements of a.
The third line of input contains a string of n characters, consisting of 0 and 1 — the elements of b'. Note that they are not separated by spaces.
Output
Output two integers l and r ( - 109 ≤ l ≤ r ≤ 109), conforming to the requirements described above.
If there are multiple solutions, output any of them.
It's guaranteed that the answer exists.
Examples
Input
5
1 2 3 4 5
00001
Output
6 15
Input
10
-10 -9 -8 -7 -6 6 7 8 9 10
0000111110
Output
-5 5
Note
In the first test case any pair of l and r pair is valid, if 6 ≤ l ≤ r ≤ 109, in that case b5 = 1, because a1, ..., a5 < l.
Submitted Solution:
```
def check(lst, val):
return (lst[1:] == lst[:-1]) and (lst[0] == val)
n = int(input())
a= [int(s) for s in input().split(" ")]
b_= [int(s) for s in list(input())]
l = -10**9
r = 10**9
list_=b_[:4]
for i in range(4, len(b_)):
if check(list_,0):
if b_[i] == 1:
l = max(max(a[i-4:i+1]) + 1,l)
elif check(list_,1):
if b_[i] == 0:
r = min(r,min(a[i-4:i+1]) - 1)
list_.pop(0)
list_.insert(len(list_),b_[i])
print(str(l)+ " " + str(r))
``` | instruction | 0 | 21,732 | 12 | 43,464 |
Yes | output | 1 | 21,732 | 12 | 43,465 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
"We've tried solitary confinement, waterboarding and listening to Just In Beaver, to no avail. We need something extreme."
"Little Alena got an array as a birthday present..."
The array b of length n is obtained from the array a of length n and two integers l and r (l ≤ r) using the following procedure:
b1 = b2 = b3 = b4 = 0.
For all 5 ≤ i ≤ n:
* bi = 0 if ai, ai - 1, ai - 2, ai - 3, ai - 4 > r and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 1
* bi = 1 if ai, ai - 1, ai - 2, ai - 3, ai - 4 < l and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 0
* bi = bi - 1 otherwise
You are given arrays a and b' of the same length. Find two integers l and r (l ≤ r), such that applying the algorithm described above will yield an array b equal to b'.
It's guaranteed that the answer exists.
Input
The first line of input contains a single integer n (5 ≤ n ≤ 105) — the length of a and b'.
The second line of input contains n space separated integers a1, ..., an ( - 109 ≤ ai ≤ 109) — the elements of a.
The third line of input contains a string of n characters, consisting of 0 and 1 — the elements of b'. Note that they are not separated by spaces.
Output
Output two integers l and r ( - 109 ≤ l ≤ r ≤ 109), conforming to the requirements described above.
If there are multiple solutions, output any of them.
It's guaranteed that the answer exists.
Examples
Input
5
1 2 3 4 5
00001
Output
6 15
Input
10
-10 -9 -8 -7 -6 6 7 8 9 10
0000111110
Output
-5 5
Note
In the first test case any pair of l and r pair is valid, if 6 ≤ l ≤ r ≤ 109, in that case b5 = 1, because a1, ..., a5 < l.
Submitted Solution:
```
inf = int(1e9)
M = mod = 1000000007
mod2inv = 500000004
pt = lambda *a, **k: print(*a, **k, flush=True)
rd = lambda: map(int, input().split())
n = int(input())
a = list(rd())
b = input()
l1 = -inf
l2 = inf
r1 = -inf
r2 = inf
f = 4
for i in range(4, n):
x = b[i]
if f == 4 and x == '1':
l1 = max(l1, max(a[i - 4: i + 1]) + 1)
f = 0
if f == 4 and x == '0':
l2 = min(l2, max(a[i - 4: i + 1]))
if f == -4 and x == '1':
r1 = max(r1, min(a[i - 4: i + 1]))
if f == -4 and x == '0':
r2 = min(r2, min(a[i - 4: i + 1]) - 1)
f = 0
if -4 < f < 4:
if x == '0':
f += 1
if x == '1':
f -= 1
print(min(l1, l2), max(r1, r2))
``` | instruction | 0 | 21,733 | 12 | 43,466 |
Yes | output | 1 | 21,733 | 12 | 43,467 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
"We've tried solitary confinement, waterboarding and listening to Just In Beaver, to no avail. We need something extreme."
"Little Alena got an array as a birthday present..."
The array b of length n is obtained from the array a of length n and two integers l and r (l ≤ r) using the following procedure:
b1 = b2 = b3 = b4 = 0.
For all 5 ≤ i ≤ n:
* bi = 0 if ai, ai - 1, ai - 2, ai - 3, ai - 4 > r and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 1
* bi = 1 if ai, ai - 1, ai - 2, ai - 3, ai - 4 < l and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 0
* bi = bi - 1 otherwise
You are given arrays a and b' of the same length. Find two integers l and r (l ≤ r), such that applying the algorithm described above will yield an array b equal to b'.
It's guaranteed that the answer exists.
Input
The first line of input contains a single integer n (5 ≤ n ≤ 105) — the length of a and b'.
The second line of input contains n space separated integers a1, ..., an ( - 109 ≤ ai ≤ 109) — the elements of a.
The third line of input contains a string of n characters, consisting of 0 and 1 — the elements of b'. Note that they are not separated by spaces.
Output
Output two integers l and r ( - 109 ≤ l ≤ r ≤ 109), conforming to the requirements described above.
If there are multiple solutions, output any of them.
It's guaranteed that the answer exists.
Examples
Input
5
1 2 3 4 5
00001
Output
6 15
Input
10
-10 -9 -8 -7 -6 6 7 8 9 10
0000111110
Output
-5 5
Note
In the first test case any pair of l and r pair is valid, if 6 ≤ l ≤ r ≤ 109, in that case b5 = 1, because a1, ..., a5 < l.
Submitted Solution:
```
n = int(input())
a = list(map(int, input().split()))
b = input()
r = 1e+9
l = -1e+9
for i in range(4, n):
if b[i - 4: i] == "1111" and b[i] == "0":
r = min(r, min(a[i - 4: i + 1]) - 1)
if b[i - 4: i] == "0000" and b[i] == "1":
l = max(l, max(a[i - 4: i + 1]) + 1)
print(int(l), int(r))
``` | instruction | 0 | 21,734 | 12 | 43,468 |
Yes | output | 1 | 21,734 | 12 | 43,469 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
"We've tried solitary confinement, waterboarding and listening to Just In Beaver, to no avail. We need something extreme."
"Little Alena got an array as a birthday present..."
The array b of length n is obtained from the array a of length n and two integers l and r (l ≤ r) using the following procedure:
b1 = b2 = b3 = b4 = 0.
For all 5 ≤ i ≤ n:
* bi = 0 if ai, ai - 1, ai - 2, ai - 3, ai - 4 > r and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 1
* bi = 1 if ai, ai - 1, ai - 2, ai - 3, ai - 4 < l and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 0
* bi = bi - 1 otherwise
You are given arrays a and b' of the same length. Find two integers l and r (l ≤ r), such that applying the algorithm described above will yield an array b equal to b'.
It's guaranteed that the answer exists.
Input
The first line of input contains a single integer n (5 ≤ n ≤ 105) — the length of a and b'.
The second line of input contains n space separated integers a1, ..., an ( - 109 ≤ ai ≤ 109) — the elements of a.
The third line of input contains a string of n characters, consisting of 0 and 1 — the elements of b'. Note that they are not separated by spaces.
Output
Output two integers l and r ( - 109 ≤ l ≤ r ≤ 109), conforming to the requirements described above.
If there are multiple solutions, output any of them.
It's guaranteed that the answer exists.
Examples
Input
5
1 2 3 4 5
00001
Output
6 15
Input
10
-10 -9 -8 -7 -6 6 7 8 9 10
0000111110
Output
-5 5
Note
In the first test case any pair of l and r pair is valid, if 6 ≤ l ≤ r ≤ 109, in that case b5 = 1, because a1, ..., a5 < l.
Submitted Solution:
```
def findIntersection(intervals,N):
if N==0:
return [0,0]
l = intervals[0][0]
r = intervals[0][1]
# Check rest of the intervals
# and find the intersection
for i in range(1,N):
# If no intersection exists
if (intervals[i][0] > r or intervals[i][1] < l):
print(-1)
# Else update the intersection
else:
l = max(l, intervals[i][0])
r = min(r, intervals[i][1])
return ([l,r])
n=int(int(input()))
a=list(map(int,input().split()))
r=input()
inter=[]
for i in range(4,n):
if int(r[i])-int(r[i-1])==-1:
inter.append([-10**9,min(a[i-1],a[i-2],a[i-3],a[i-4],a[i])-1])
elif int(r[i])-int(r[i-1])==1:
inter.append([max(a[i-1],a[i-2],a[i-3],a[i-4],a[i])+1,10**9])
print(*findIntersection(inter,len(inter)))
``` | instruction | 0 | 21,736 | 12 | 43,472 |
No | output | 1 | 21,736 | 12 | 43,473 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
"We've tried solitary confinement, waterboarding and listening to Just In Beaver, to no avail. We need something extreme."
"Little Alena got an array as a birthday present..."
The array b of length n is obtained from the array a of length n and two integers l and r (l ≤ r) using the following procedure:
b1 = b2 = b3 = b4 = 0.
For all 5 ≤ i ≤ n:
* bi = 0 if ai, ai - 1, ai - 2, ai - 3, ai - 4 > r and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 1
* bi = 1 if ai, ai - 1, ai - 2, ai - 3, ai - 4 < l and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 0
* bi = bi - 1 otherwise
You are given arrays a and b' of the same length. Find two integers l and r (l ≤ r), such that applying the algorithm described above will yield an array b equal to b'.
It's guaranteed that the answer exists.
Input
The first line of input contains a single integer n (5 ≤ n ≤ 105) — the length of a and b'.
The second line of input contains n space separated integers a1, ..., an ( - 109 ≤ ai ≤ 109) — the elements of a.
The third line of input contains a string of n characters, consisting of 0 and 1 — the elements of b'. Note that they are not separated by spaces.
Output
Output two integers l and r ( - 109 ≤ l ≤ r ≤ 109), conforming to the requirements described above.
If there are multiple solutions, output any of them.
It's guaranteed that the answer exists.
Examples
Input
5
1 2 3 4 5
00001
Output
6 15
Input
10
-10 -9 -8 -7 -6 6 7 8 9 10
0000111110
Output
-5 5
Note
In the first test case any pair of l and r pair is valid, if 6 ≤ l ≤ r ≤ 109, in that case b5 = 1, because a1, ..., a5 < l.
Submitted Solution:
```
r,l = [[],[]],[[],[]]
n = int(input())
a = list(map(int,input().split()))
b = input()
s = '0'
t = 4
for i,j in enumerate(b[4:]):
if j == s:
if t >= 4:
if j == '1':
r[0].append(min(a[i],a[i+1],a[i+2],a[i+3],a[i+4]))
else:
l[0].append(max(a[i],a[i+1],a[i+2],a[i+3],a[i+4]))
t += 1
else:
if j == '0':
r[1].append(min(a[i],a[i+1],a[i+2],a[i+3],a[i+4]))
s = '0'
else:
l[1].append(max(a[i],a[i+1],a[i+2],a[i+3],a[i+4]))
s = '1'
t = 1
print(r,l)
if r[1] != []:
r = min(r[1])-1
else:
r = 10**9
if l[1] != []:
l = max(l[1]) +1
else:
l = -10**9
print(' '.join((str(l),str(r))))
``` | instruction | 0 | 21,737 | 12 | 43,474 |
No | output | 1 | 21,737 | 12 | 43,475 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
"We've tried solitary confinement, waterboarding and listening to Just In Beaver, to no avail. We need something extreme."
"Little Alena got an array as a birthday present..."
The array b of length n is obtained from the array a of length n and two integers l and r (l ≤ r) using the following procedure:
b1 = b2 = b3 = b4 = 0.
For all 5 ≤ i ≤ n:
* bi = 0 if ai, ai - 1, ai - 2, ai - 3, ai - 4 > r and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 1
* bi = 1 if ai, ai - 1, ai - 2, ai - 3, ai - 4 < l and bi - 1 = bi - 2 = bi - 3 = bi - 4 = 0
* bi = bi - 1 otherwise
You are given arrays a and b' of the same length. Find two integers l and r (l ≤ r), such that applying the algorithm described above will yield an array b equal to b'.
It's guaranteed that the answer exists.
Input
The first line of input contains a single integer n (5 ≤ n ≤ 105) — the length of a and b'.
The second line of input contains n space separated integers a1, ..., an ( - 109 ≤ ai ≤ 109) — the elements of a.
The third line of input contains a string of n characters, consisting of 0 and 1 — the elements of b'. Note that they are not separated by spaces.
Output
Output two integers l and r ( - 109 ≤ l ≤ r ≤ 109), conforming to the requirements described above.
If there are multiple solutions, output any of them.
It's guaranteed that the answer exists.
Examples
Input
5
1 2 3 4 5
00001
Output
6 15
Input
10
-10 -9 -8 -7 -6 6 7 8 9 10
0000111110
Output
-5 5
Note
In the first test case any pair of l and r pair is valid, if 6 ≤ l ≤ r ≤ 109, in that case b5 = 1, because a1, ..., a5 < l.
Submitted Solution:
```
n = int(input())
a = list(map(int, input().split()))
b = input()
r = 1000000000
l = -r
for i in range(4, n):
if b[i - 1] == b[i - 2] == b[i - 3] == b[i - 4] != b[i]:
if b[i] == 1:
r = min(r, min(a[i - 4: i + 1]) - 1)
else:
l = max(l, max(a[i - 4: i + 1]) + 1)
print(l, r)
``` | instruction | 0 | 21,739 | 12 | 43,478 |
No | output | 1 | 21,739 | 12 | 43,479 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little girl Margarita is a big fan of competitive programming. She especially loves problems about arrays and queries on them.
Recently, she was presented with an array a of the size of 10^9 elements that is filled as follows:
* a_1 = -1
* a_2 = 2
* a_3 = -3
* a_4 = 4
* a_5 = -5
* And so on ...
That is, the value of the i-th element of the array a is calculated using the formula a_i = i ⋅ (-1)^i.
She immediately came up with q queries on this array. Each query is described with two numbers: l and r. The answer to a query is the sum of all the elements of the array at positions from l to r inclusive.
Margarita really wants to know the answer to each of the requests. She doesn't want to count all this manually, but unfortunately, she couldn't write the program that solves the problem either. She has turned to you — the best programmer.
Help her find the answers!
Input
The first line contains a single integer q (1 ≤ q ≤ 10^3) — the number of the queries.
Each of the next q lines contains two integers l and r (1 ≤ l ≤ r ≤ 10^9) — the descriptions of the queries.
Output
Print q lines, each containing one number — the answer to the query.
Example
Input
5
1 3
2 5
5 5
4 4
2 3
Output
-2
-2
-5
4
-1
Note
In the first query, you need to find the sum of the elements of the array from position 1 to position 3. The sum is equal to a_1 + a_2 + a_3 = -1 + 2 -3 = -2.
In the second query, you need to find the sum of the elements of the array from position 2 to position 5. The sum is equal to a_2 + a_3 + a_4 + a_5 = 2 -3 + 4 - 5 = -2.
In the third query, you need to find the sum of the elements of the array from position 5 to position 5. The sum is equal to a_5 = -5.
In the fourth query, you need to find the sum of the elements of the array from position 4 to position 4. The sum is equal to a_4 = 4.
In the fifth query, you need to find the sum of the elements of the array from position 2 to position 3. The sum is equal to a_2 + a_3 = 2 - 3 = -1. | instruction | 0 | 22,035 | 12 | 44,070 |
Tags: math
Correct Solution:
```
'''
When we have sequence of number with length n & we want to
calculate the sum of sub sequence from i to n (inclusive),
actually we could just use following formula:
sum(i, n) = sum(1, n) - sum(1, i-1)
This problem would be straight-forward if we are given
small sequence of input, however we are not! We are given
sequence of number with 10^9 elements on it ._. (duh!).
If we just precalculate the sum from element 1 to 10^9 then
we will most likely get TLE or maybe the memory limit.
So how do we solve this problem?
Let's take a look at our sequence:
-1, 2, -3, 4, -5, ...
If we break down our sequence into odd & even number only,
we would get two sequences:
Odd only:
-1, -3, -5
Even only:
2, 4
Notice that both of these sequences are arithmetic sequences,
so we could know the sum of each of these sequences up until
certain index by using following formula:
sum_n = (n / 2) * (2a + (n - 1) * b)
Where a = first number in sequence, b = difference in sequence
In odd-only sequence, from above formula we could derives
following formula:
sum_odd(1, n) = (n / 2) * (2 * -1 + (n - 1) * -2)
= n * (-1 + 1 - n)
= -n^2
As for even-only sequence, from the base formula we could derives
following formula:
sum_even(1, n) = (n / 2) * (2 * 2 + (n - 1) * 2)
= n * (1 + n)
= n^2 + n
So if we just combine these formula, we could get the sum of
our initial sequence. For example let's count the sum up until
index 5:
-1, 2, -3, 4, -5
sum_odd(1, 3) = -3^2 = -9
sum_even(1, 2) = 2^2 + 2 = 6
So the sum of our sequence is:
sum(1, 5) = sum_odd(1, 3) + sum_even(1, 2)
= -9 + 6
= 3
Notice that in sum_odd we pass 3 as parameter there & in
sum_even we pass 2 as parameter. Why? Yes, because when we
count up until index 5, we meet with 3 odd numbers & 2 even
numbers. This is the reason why we put 3 & 2 as parameter.
So the complete formula for getting the sum is following:
sum(1, n) = -(math.ceil(n / 2) ^ 2) + (math.floor(n / 2) ^ 2)
+ math.floor(n / 2)
By using this formula, we could now count sum(i, n) which is:
sum(i, n) = sum(1, n) - sum(1, i-1)
'''
import math
def get_sum(n):
return -(math.ceil(n / 2) ** 2) + math.floor(n / 2) ** 2 + math.floor(n / 2)
q = int(input())
for i in range(0, q):
l, r = tuple(map(int, input().split()))
print(get_sum(r) - get_sum(l-1))
``` | output | 1 | 22,035 | 12 | 44,071 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little girl Margarita is a big fan of competitive programming. She especially loves problems about arrays and queries on them.
Recently, she was presented with an array a of the size of 10^9 elements that is filled as follows:
* a_1 = -1
* a_2 = 2
* a_3 = -3
* a_4 = 4
* a_5 = -5
* And so on ...
That is, the value of the i-th element of the array a is calculated using the formula a_i = i ⋅ (-1)^i.
She immediately came up with q queries on this array. Each query is described with two numbers: l and r. The answer to a query is the sum of all the elements of the array at positions from l to r inclusive.
Margarita really wants to know the answer to each of the requests. She doesn't want to count all this manually, but unfortunately, she couldn't write the program that solves the problem either. She has turned to you — the best programmer.
Help her find the answers!
Input
The first line contains a single integer q (1 ≤ q ≤ 10^3) — the number of the queries.
Each of the next q lines contains two integers l and r (1 ≤ l ≤ r ≤ 10^9) — the descriptions of the queries.
Output
Print q lines, each containing one number — the answer to the query.
Example
Input
5
1 3
2 5
5 5
4 4
2 3
Output
-2
-2
-5
4
-1
Note
In the first query, you need to find the sum of the elements of the array from position 1 to position 3. The sum is equal to a_1 + a_2 + a_3 = -1 + 2 -3 = -2.
In the second query, you need to find the sum of the elements of the array from position 2 to position 5. The sum is equal to a_2 + a_3 + a_4 + a_5 = 2 -3 + 4 - 5 = -2.
In the third query, you need to find the sum of the elements of the array from position 5 to position 5. The sum is equal to a_5 = -5.
In the fourth query, you need to find the sum of the elements of the array from position 4 to position 4. The sum is equal to a_4 = 4.
In the fifth query, you need to find the sum of the elements of the array from position 2 to position 3. The sum is equal to a_2 + a_3 = 2 - 3 = -1. | instruction | 0 | 22,036 | 12 | 44,072 |
Tags: math
Correct Solution:
```
q,m=int(input()),[]
for i in range(q):
s=input().split()
a,b=int(s[0]),int(s[1])
a,b=a*(-1)**a,b*(-1)**b
m+=[(b+a)/2 if (a+b)%2==0 else ((abs(b)-1)*(-1)**(abs(b)-1)+a)/2+b]
for i in m:
print(int(i))
``` | output | 1 | 22,036 | 12 | 44,073 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little girl Margarita is a big fan of competitive programming. She especially loves problems about arrays and queries on them.
Recently, she was presented with an array a of the size of 10^9 elements that is filled as follows:
* a_1 = -1
* a_2 = 2
* a_3 = -3
* a_4 = 4
* a_5 = -5
* And so on ...
That is, the value of the i-th element of the array a is calculated using the formula a_i = i ⋅ (-1)^i.
She immediately came up with q queries on this array. Each query is described with two numbers: l and r. The answer to a query is the sum of all the elements of the array at positions from l to r inclusive.
Margarita really wants to know the answer to each of the requests. She doesn't want to count all this manually, but unfortunately, she couldn't write the program that solves the problem either. She has turned to you — the best programmer.
Help her find the answers!
Input
The first line contains a single integer q (1 ≤ q ≤ 10^3) — the number of the queries.
Each of the next q lines contains two integers l and r (1 ≤ l ≤ r ≤ 10^9) — the descriptions of the queries.
Output
Print q lines, each containing one number — the answer to the query.
Example
Input
5
1 3
2 5
5 5
4 4
2 3
Output
-2
-2
-5
4
-1
Note
In the first query, you need to find the sum of the elements of the array from position 1 to position 3. The sum is equal to a_1 + a_2 + a_3 = -1 + 2 -3 = -2.
In the second query, you need to find the sum of the elements of the array from position 2 to position 5. The sum is equal to a_2 + a_3 + a_4 + a_5 = 2 -3 + 4 - 5 = -2.
In the third query, you need to find the sum of the elements of the array from position 5 to position 5. The sum is equal to a_5 = -5.
In the fourth query, you need to find the sum of the elements of the array from position 4 to position 4. The sum is equal to a_4 = 4.
In the fifth query, you need to find the sum of the elements of the array from position 2 to position 3. The sum is equal to a_2 + a_3 = 2 - 3 = -1. | instruction | 0 | 22,037 | 12 | 44,074 |
Tags: math
Correct Solution:
```
for i in range(int(input())):
l,r=list(map(int,input().split()))
if r%2==0:
p=r//2
else:
p=-r+((r-1)//2)
if (l-1)%2==0:
q=(l-1)//2
else:
q=-(l-1)+((l-2)//2)
print(p-q)
``` | output | 1 | 22,037 | 12 | 44,075 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little girl Margarita is a big fan of competitive programming. She especially loves problems about arrays and queries on them.
Recently, she was presented with an array a of the size of 10^9 elements that is filled as follows:
* a_1 = -1
* a_2 = 2
* a_3 = -3
* a_4 = 4
* a_5 = -5
* And so on ...
That is, the value of the i-th element of the array a is calculated using the formula a_i = i ⋅ (-1)^i.
She immediately came up with q queries on this array. Each query is described with two numbers: l and r. The answer to a query is the sum of all the elements of the array at positions from l to r inclusive.
Margarita really wants to know the answer to each of the requests. She doesn't want to count all this manually, but unfortunately, she couldn't write the program that solves the problem either. She has turned to you — the best programmer.
Help her find the answers!
Input
The first line contains a single integer q (1 ≤ q ≤ 10^3) — the number of the queries.
Each of the next q lines contains two integers l and r (1 ≤ l ≤ r ≤ 10^9) — the descriptions of the queries.
Output
Print q lines, each containing one number — the answer to the query.
Example
Input
5
1 3
2 5
5 5
4 4
2 3
Output
-2
-2
-5
4
-1
Note
In the first query, you need to find the sum of the elements of the array from position 1 to position 3. The sum is equal to a_1 + a_2 + a_3 = -1 + 2 -3 = -2.
In the second query, you need to find the sum of the elements of the array from position 2 to position 5. The sum is equal to a_2 + a_3 + a_4 + a_5 = 2 -3 + 4 - 5 = -2.
In the third query, you need to find the sum of the elements of the array from position 5 to position 5. The sum is equal to a_5 = -5.
In the fourth query, you need to find the sum of the elements of the array from position 4 to position 4. The sum is equal to a_4 = 4.
In the fifth query, you need to find the sum of the elements of the array from position 2 to position 3. The sum is equal to a_2 + a_3 = 2 - 3 = -1. | instruction | 0 | 22,038 | 12 | 44,076 |
Tags: math
Correct Solution:
```
q = int(input())
for query in range(q):
x, y = map(int, input().split(' '))
sol = 0
if x % 2:
if y % 2:
sol -= y
sol += (y - x + 1) // 2
else:
if (y % 2) == 0:
sol += y
sol -= (y - x + 1) // 2
print (sol)
``` | output | 1 | 22,038 | 12 | 44,077 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little girl Margarita is a big fan of competitive programming. She especially loves problems about arrays and queries on them.
Recently, she was presented with an array a of the size of 10^9 elements that is filled as follows:
* a_1 = -1
* a_2 = 2
* a_3 = -3
* a_4 = 4
* a_5 = -5
* And so on ...
That is, the value of the i-th element of the array a is calculated using the formula a_i = i ⋅ (-1)^i.
She immediately came up with q queries on this array. Each query is described with two numbers: l and r. The answer to a query is the sum of all the elements of the array at positions from l to r inclusive.
Margarita really wants to know the answer to each of the requests. She doesn't want to count all this manually, but unfortunately, she couldn't write the program that solves the problem either. She has turned to you — the best programmer.
Help her find the answers!
Input
The first line contains a single integer q (1 ≤ q ≤ 10^3) — the number of the queries.
Each of the next q lines contains two integers l and r (1 ≤ l ≤ r ≤ 10^9) — the descriptions of the queries.
Output
Print q lines, each containing one number — the answer to the query.
Example
Input
5
1 3
2 5
5 5
4 4
2 3
Output
-2
-2
-5
4
-1
Note
In the first query, you need to find the sum of the elements of the array from position 1 to position 3. The sum is equal to a_1 + a_2 + a_3 = -1 + 2 -3 = -2.
In the second query, you need to find the sum of the elements of the array from position 2 to position 5. The sum is equal to a_2 + a_3 + a_4 + a_5 = 2 -3 + 4 - 5 = -2.
In the third query, you need to find the sum of the elements of the array from position 5 to position 5. The sum is equal to a_5 = -5.
In the fourth query, you need to find the sum of the elements of the array from position 4 to position 4. The sum is equal to a_4 = 4.
In the fifth query, you need to find the sum of the elements of the array from position 2 to position 3. The sum is equal to a_2 + a_3 = 2 - 3 = -1. | instruction | 0 | 22,039 | 12 | 44,078 |
Tags: math
Correct Solution:
```
for _ in range(int(input())) :
l,r = map(int,input().split())
if l%2 == 0 :
se = l
so = l + 1
else :
so = l
se = l + 1
if r%2 == 0 :
ee = r
eo = r - 1
else :
eo = r
ee = r - 1
#print(se,so,ee,eo)
n1 = (ee-se + 2)//2
a = ((n1)*(se+ee))//2
#print(n1,a)
n2 = (eo-so + 2)//2
b = ((n2)*(so+eo))//2
#print(n2,b)
print(a-b)
``` | output | 1 | 22,039 | 12 | 44,079 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little girl Margarita is a big fan of competitive programming. She especially loves problems about arrays and queries on them.
Recently, she was presented with an array a of the size of 10^9 elements that is filled as follows:
* a_1 = -1
* a_2 = 2
* a_3 = -3
* a_4 = 4
* a_5 = -5
* And so on ...
That is, the value of the i-th element of the array a is calculated using the formula a_i = i ⋅ (-1)^i.
She immediately came up with q queries on this array. Each query is described with two numbers: l and r. The answer to a query is the sum of all the elements of the array at positions from l to r inclusive.
Margarita really wants to know the answer to each of the requests. She doesn't want to count all this manually, but unfortunately, she couldn't write the program that solves the problem either. She has turned to you — the best programmer.
Help her find the answers!
Input
The first line contains a single integer q (1 ≤ q ≤ 10^3) — the number of the queries.
Each of the next q lines contains two integers l and r (1 ≤ l ≤ r ≤ 10^9) — the descriptions of the queries.
Output
Print q lines, each containing one number — the answer to the query.
Example
Input
5
1 3
2 5
5 5
4 4
2 3
Output
-2
-2
-5
4
-1
Note
In the first query, you need to find the sum of the elements of the array from position 1 to position 3. The sum is equal to a_1 + a_2 + a_3 = -1 + 2 -3 = -2.
In the second query, you need to find the sum of the elements of the array from position 2 to position 5. The sum is equal to a_2 + a_3 + a_4 + a_5 = 2 -3 + 4 - 5 = -2.
In the third query, you need to find the sum of the elements of the array from position 5 to position 5. The sum is equal to a_5 = -5.
In the fourth query, you need to find the sum of the elements of the array from position 4 to position 4. The sum is equal to a_4 = 4.
In the fifth query, you need to find the sum of the elements of the array from position 2 to position 3. The sum is equal to a_2 + a_3 = 2 - 3 = -1. | instruction | 0 | 22,040 | 12 | 44,080 |
Tags: math
Correct Solution:
```
def sumNatural(n):
sum = (n * (n + 1))
return int(sum)
def sum_even(l, r):
return (sumNatural(int(r / 2)) -
sumNatural(int((l - 1) / 2)))
def sumOdd(n):
terms = (n + 1)//2
sum1 = terms * terms
return sum1
def sum_odd(l, r):
return sumOdd(r) - sumOdd(l - 1)
q = int(input())
entrada = []
for i in range(q):
entrada.append(input())
for i in range(q):
l, r = entrada[i].split(" ")
if l == r:
if int(r)%2 == 0:
print(r)
else:
print(int(r)*-1)
else:
suma = (sum_even(int(l), int(r))) - (sum_odd(int(l), int(r)))
print(suma)
``` | output | 1 | 22,040 | 12 | 44,081 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little girl Margarita is a big fan of competitive programming. She especially loves problems about arrays and queries on them.
Recently, she was presented with an array a of the size of 10^9 elements that is filled as follows:
* a_1 = -1
* a_2 = 2
* a_3 = -3
* a_4 = 4
* a_5 = -5
* And so on ...
That is, the value of the i-th element of the array a is calculated using the formula a_i = i ⋅ (-1)^i.
She immediately came up with q queries on this array. Each query is described with two numbers: l and r. The answer to a query is the sum of all the elements of the array at positions from l to r inclusive.
Margarita really wants to know the answer to each of the requests. She doesn't want to count all this manually, but unfortunately, she couldn't write the program that solves the problem either. She has turned to you — the best programmer.
Help her find the answers!
Input
The first line contains a single integer q (1 ≤ q ≤ 10^3) — the number of the queries.
Each of the next q lines contains two integers l and r (1 ≤ l ≤ r ≤ 10^9) — the descriptions of the queries.
Output
Print q lines, each containing one number — the answer to the query.
Example
Input
5
1 3
2 5
5 5
4 4
2 3
Output
-2
-2
-5
4
-1
Note
In the first query, you need to find the sum of the elements of the array from position 1 to position 3. The sum is equal to a_1 + a_2 + a_3 = -1 + 2 -3 = -2.
In the second query, you need to find the sum of the elements of the array from position 2 to position 5. The sum is equal to a_2 + a_3 + a_4 + a_5 = 2 -3 + 4 - 5 = -2.
In the third query, you need to find the sum of the elements of the array from position 5 to position 5. The sum is equal to a_5 = -5.
In the fourth query, you need to find the sum of the elements of the array from position 4 to position 4. The sum is equal to a_4 = 4.
In the fifth query, you need to find the sum of the elements of the array from position 2 to position 3. The sum is equal to a_2 + a_3 = 2 - 3 = -1. | instruction | 0 | 22,041 | 12 | 44,082 |
Tags: math
Correct Solution:
```
def my_fun(number):
if number % 2 == 0:
return number // 2
return - number + my_fun(number - 1)
def result(lst):
a = list()
for elem in lst:
a.append(my_fun(elem[1]) - my_fun(elem[0] - 1))
return a
q = int(input())
b = list()
for i in range(q):
s, t = [int(i) for i in input().split()]
b.append([s, t])
print(*result(b), sep='\n')
``` | output | 1 | 22,041 | 12 | 44,083 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little girl Margarita is a big fan of competitive programming. She especially loves problems about arrays and queries on them.
Recently, she was presented with an array a of the size of 10^9 elements that is filled as follows:
* a_1 = -1
* a_2 = 2
* a_3 = -3
* a_4 = 4
* a_5 = -5
* And so on ...
That is, the value of the i-th element of the array a is calculated using the formula a_i = i ⋅ (-1)^i.
She immediately came up with q queries on this array. Each query is described with two numbers: l and r. The answer to a query is the sum of all the elements of the array at positions from l to r inclusive.
Margarita really wants to know the answer to each of the requests. She doesn't want to count all this manually, but unfortunately, she couldn't write the program that solves the problem either. She has turned to you — the best programmer.
Help her find the answers!
Input
The first line contains a single integer q (1 ≤ q ≤ 10^3) — the number of the queries.
Each of the next q lines contains two integers l and r (1 ≤ l ≤ r ≤ 10^9) — the descriptions of the queries.
Output
Print q lines, each containing one number — the answer to the query.
Example
Input
5
1 3
2 5
5 5
4 4
2 3
Output
-2
-2
-5
4
-1
Note
In the first query, you need to find the sum of the elements of the array from position 1 to position 3. The sum is equal to a_1 + a_2 + a_3 = -1 + 2 -3 = -2.
In the second query, you need to find the sum of the elements of the array from position 2 to position 5. The sum is equal to a_2 + a_3 + a_4 + a_5 = 2 -3 + 4 - 5 = -2.
In the third query, you need to find the sum of the elements of the array from position 5 to position 5. The sum is equal to a_5 = -5.
In the fourth query, you need to find the sum of the elements of the array from position 4 to position 4. The sum is equal to a_4 = 4.
In the fifth query, you need to find the sum of the elements of the array from position 2 to position 3. The sum is equal to a_2 + a_3 = 2 - 3 = -1. | instruction | 0 | 22,042 | 12 | 44,084 |
Tags: math
Correct Solution:
```
from math import ceil
def ps(l):
v = ceil(l/2)
v *= -1 if l % 2 == 1 else 1
return v
def solve():
return ps(r) - ps(l-1)
def main():
global l, r
for _ in range(int(input())):
l, r = list(map(int, input().split()))
print(solve())
main()
``` | output | 1 | 22,042 | 12 | 44,085 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two arrays a and b both consisting of n positive (greater than zero) integers. You are also given an integer k.
In one move, you can choose two indices i and j (1 ≤ i, j ≤ n) and swap a_i and b_j (i.e. a_i becomes b_j and vice versa). Note that i and j can be equal or different (in particular, swap a_2 with b_2 or swap a_3 and b_9 both are acceptable moves).
Your task is to find the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k such moves (swaps).
You have to answer t independent test cases.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 200) — the number of test cases. Then t test cases follow.
The first line of the test case contains two integers n and k (1 ≤ n ≤ 30; 0 ≤ k ≤ n) — the number of elements in a and b and the maximum number of moves you can do. The second line of the test case contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 30), where a_i is the i-th element of a. The third line of the test case contains n integers b_1, b_2, ..., b_n (1 ≤ b_i ≤ 30), where b_i is the i-th element of b.
Output
For each test case, print the answer — the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k swaps.
Example
Input
5
2 1
1 2
3 4
5 5
5 5 6 6 5
1 2 5 4 3
5 3
1 2 3 4 5
10 9 10 10 9
4 0
2 2 4 3
2 4 2 3
4 4
1 2 2 1
4 4 5 4
Output
6
27
39
11
17
Note
In the first test case of the example, you can swap a_1 = 1 and b_2 = 4, so a=[4, 2] and b=[3, 1].
In the second test case of the example, you don't need to swap anything.
In the third test case of the example, you can swap a_1 = 1 and b_1 = 10, a_3 = 3 and b_3 = 10 and a_2 = 2 and b_4 = 10, so a=[10, 10, 10, 4, 5] and b=[1, 9, 3, 2, 9].
In the fourth test case of the example, you cannot swap anything.
In the fifth test case of the example, you can swap arrays a and b, so a=[4, 4, 5, 4] and b=[1, 2, 2, 1]. | instruction | 0 | 22,181 | 12 | 44,362 |
Tags: greedy, sortings
Correct Solution:
```
# import sys
# sys.setrecursionlimit(50000)
# from typing import List
t = int(input())
for _ in range(t):
n, k = list(map(int, input().split()))
A = list(map(int, input().split()))
B = list(map(int, input().split()))
A.sort()
B.sort()
res = 0
for i in range(n):
if A[-1] >= B[-1] or k == 0:
res += A.pop()
else:
res += B.pop()
k -= 1
print(res)
``` | output | 1 | 22,181 | 12 | 44,363 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two arrays a and b both consisting of n positive (greater than zero) integers. You are also given an integer k.
In one move, you can choose two indices i and j (1 ≤ i, j ≤ n) and swap a_i and b_j (i.e. a_i becomes b_j and vice versa). Note that i and j can be equal or different (in particular, swap a_2 with b_2 or swap a_3 and b_9 both are acceptable moves).
Your task is to find the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k such moves (swaps).
You have to answer t independent test cases.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 200) — the number of test cases. Then t test cases follow.
The first line of the test case contains two integers n and k (1 ≤ n ≤ 30; 0 ≤ k ≤ n) — the number of elements in a and b and the maximum number of moves you can do. The second line of the test case contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 30), where a_i is the i-th element of a. The third line of the test case contains n integers b_1, b_2, ..., b_n (1 ≤ b_i ≤ 30), where b_i is the i-th element of b.
Output
For each test case, print the answer — the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k swaps.
Example
Input
5
2 1
1 2
3 4
5 5
5 5 6 6 5
1 2 5 4 3
5 3
1 2 3 4 5
10 9 10 10 9
4 0
2 2 4 3
2 4 2 3
4 4
1 2 2 1
4 4 5 4
Output
6
27
39
11
17
Note
In the first test case of the example, you can swap a_1 = 1 and b_2 = 4, so a=[4, 2] and b=[3, 1].
In the second test case of the example, you don't need to swap anything.
In the third test case of the example, you can swap a_1 = 1 and b_1 = 10, a_3 = 3 and b_3 = 10 and a_2 = 2 and b_4 = 10, so a=[10, 10, 10, 4, 5] and b=[1, 9, 3, 2, 9].
In the fourth test case of the example, you cannot swap anything.
In the fifth test case of the example, you can swap arrays a and b, so a=[4, 4, 5, 4] and b=[1, 2, 2, 1]. | instruction | 0 | 22,182 | 12 | 44,364 |
Tags: greedy, sortings
Correct Solution:
```
for _ in range(int(input())):
n,k = [int(i) for i in input().split()]
a = sorted([int(i) for i in input().split()])
b = sorted([int(i) for i in input().split()])
ans = sum(a)
for i in range(1,k+1):
ans = max((ans, sum(a[i:]+b[n-i:])))
print(ans)
``` | output | 1 | 22,182 | 12 | 44,365 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two arrays a and b both consisting of n positive (greater than zero) integers. You are also given an integer k.
In one move, you can choose two indices i and j (1 ≤ i, j ≤ n) and swap a_i and b_j (i.e. a_i becomes b_j and vice versa). Note that i and j can be equal or different (in particular, swap a_2 with b_2 or swap a_3 and b_9 both are acceptable moves).
Your task is to find the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k such moves (swaps).
You have to answer t independent test cases.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 200) — the number of test cases. Then t test cases follow.
The first line of the test case contains two integers n and k (1 ≤ n ≤ 30; 0 ≤ k ≤ n) — the number of elements in a and b and the maximum number of moves you can do. The second line of the test case contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 30), where a_i is the i-th element of a. The third line of the test case contains n integers b_1, b_2, ..., b_n (1 ≤ b_i ≤ 30), where b_i is the i-th element of b.
Output
For each test case, print the answer — the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k swaps.
Example
Input
5
2 1
1 2
3 4
5 5
5 5 6 6 5
1 2 5 4 3
5 3
1 2 3 4 5
10 9 10 10 9
4 0
2 2 4 3
2 4 2 3
4 4
1 2 2 1
4 4 5 4
Output
6
27
39
11
17
Note
In the first test case of the example, you can swap a_1 = 1 and b_2 = 4, so a=[4, 2] and b=[3, 1].
In the second test case of the example, you don't need to swap anything.
In the third test case of the example, you can swap a_1 = 1 and b_1 = 10, a_3 = 3 and b_3 = 10 and a_2 = 2 and b_4 = 10, so a=[10, 10, 10, 4, 5] and b=[1, 9, 3, 2, 9].
In the fourth test case of the example, you cannot swap anything.
In the fifth test case of the example, you can swap arrays a and b, so a=[4, 4, 5, 4] and b=[1, 2, 2, 1]. | instruction | 0 | 22,183 | 12 | 44,366 |
Tags: greedy, sortings
Correct Solution:
```
import math
import functools
def s():
n,k = list(map(int,input().split(" ")))
a = [int(x) for x in input().split(" ")]
b = [int(x) for x in input().split(" ")]
a.sort()
b.sort(reverse=True)
ans = sum(a)
for i in range(k):
if b[i] > a[i]:
ans = ans - a[i] + b[i]
else:
break
print(ans)
t = int(input())
for i in range(t):
s()
``` | output | 1 | 22,183 | 12 | 44,367 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two arrays a and b both consisting of n positive (greater than zero) integers. You are also given an integer k.
In one move, you can choose two indices i and j (1 ≤ i, j ≤ n) and swap a_i and b_j (i.e. a_i becomes b_j and vice versa). Note that i and j can be equal or different (in particular, swap a_2 with b_2 or swap a_3 and b_9 both are acceptable moves).
Your task is to find the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k such moves (swaps).
You have to answer t independent test cases.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 200) — the number of test cases. Then t test cases follow.
The first line of the test case contains two integers n and k (1 ≤ n ≤ 30; 0 ≤ k ≤ n) — the number of elements in a and b and the maximum number of moves you can do. The second line of the test case contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 30), where a_i is the i-th element of a. The third line of the test case contains n integers b_1, b_2, ..., b_n (1 ≤ b_i ≤ 30), where b_i is the i-th element of b.
Output
For each test case, print the answer — the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k swaps.
Example
Input
5
2 1
1 2
3 4
5 5
5 5 6 6 5
1 2 5 4 3
5 3
1 2 3 4 5
10 9 10 10 9
4 0
2 2 4 3
2 4 2 3
4 4
1 2 2 1
4 4 5 4
Output
6
27
39
11
17
Note
In the first test case of the example, you can swap a_1 = 1 and b_2 = 4, so a=[4, 2] and b=[3, 1].
In the second test case of the example, you don't need to swap anything.
In the third test case of the example, you can swap a_1 = 1 and b_1 = 10, a_3 = 3 and b_3 = 10 and a_2 = 2 and b_4 = 10, so a=[10, 10, 10, 4, 5] and b=[1, 9, 3, 2, 9].
In the fourth test case of the example, you cannot swap anything.
In the fifth test case of the example, you can swap arrays a and b, so a=[4, 4, 5, 4] and b=[1, 2, 2, 1]. | instruction | 0 | 22,184 | 12 | 44,368 |
Tags: greedy, sortings
Correct Solution:
```
# import sys
# sys.stdin = open('input.txt', 'r')
# sys.stdout = open('output.txt', 'w')
# import re
# import math
gg="abcdefghijklmnopqrstuvwxyz"
# def negmod(a, m):
# return (a%m + m) % m
# for C in range(int(input())):
# rawstr = ''.join([int(x) * '(' + x + ')' * int(x) for x in str(input())])
# for _ in range(9):
# rawstr = rawstr.replace(')(', '')
# print("Case #{}: {}".format(C+1, rawstr))
# def f(n):
# if(n<=1):
# return 1
# elif(n==2):
# return 2
# else:
# return((f(n-1)*2)-1)
# dic={}
# def recur(n, count):
# m = n
# remain = []
# while(n>10):
# if n%10 != 0:
# remain.append(n%10)
# n = n//10
# remain.append(n%10)
# if m in dic:
# # print("OK")
# return dic[m]
# if m==20:
# return 4+count
# elif m==10:
# return 2+count
# elif m<10:
# return 1+count
# elif m<20:
# return 3+count
# else:
# count=recur(m-max(remain),count+1)
# dic[m]=count
# print(dic)
# return count
# # for i in remain:
# # count = min(recur(m-i, count)+1, count)
# k=int(input())
# if(k==0):
# print(0)
# else:
# print(recur(k,0))
t=int(input())
while(t):
t-=1
n,k=map(int,input().split())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
a.sort()
b.sort(reverse=True)
for i in range (0,k):
if(a[i]<b[i]):
a[i]=b[i]
print(sum(a))
``` | output | 1 | 22,184 | 12 | 44,369 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two arrays a and b both consisting of n positive (greater than zero) integers. You are also given an integer k.
In one move, you can choose two indices i and j (1 ≤ i, j ≤ n) and swap a_i and b_j (i.e. a_i becomes b_j and vice versa). Note that i and j can be equal or different (in particular, swap a_2 with b_2 or swap a_3 and b_9 both are acceptable moves).
Your task is to find the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k such moves (swaps).
You have to answer t independent test cases.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 200) — the number of test cases. Then t test cases follow.
The first line of the test case contains two integers n and k (1 ≤ n ≤ 30; 0 ≤ k ≤ n) — the number of elements in a and b and the maximum number of moves you can do. The second line of the test case contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 30), where a_i is the i-th element of a. The third line of the test case contains n integers b_1, b_2, ..., b_n (1 ≤ b_i ≤ 30), where b_i is the i-th element of b.
Output
For each test case, print the answer — the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k swaps.
Example
Input
5
2 1
1 2
3 4
5 5
5 5 6 6 5
1 2 5 4 3
5 3
1 2 3 4 5
10 9 10 10 9
4 0
2 2 4 3
2 4 2 3
4 4
1 2 2 1
4 4 5 4
Output
6
27
39
11
17
Note
In the first test case of the example, you can swap a_1 = 1 and b_2 = 4, so a=[4, 2] and b=[3, 1].
In the second test case of the example, you don't need to swap anything.
In the third test case of the example, you can swap a_1 = 1 and b_1 = 10, a_3 = 3 and b_3 = 10 and a_2 = 2 and b_4 = 10, so a=[10, 10, 10, 4, 5] and b=[1, 9, 3, 2, 9].
In the fourth test case of the example, you cannot swap anything.
In the fifth test case of the example, you can swap arrays a and b, so a=[4, 4, 5, 4] and b=[1, 2, 2, 1]. | instruction | 0 | 22,185 | 12 | 44,370 |
Tags: greedy, sortings
Correct Solution:
```
t=int(input())
for i in range(t):
n,k=input().split()
a=list(map(int,input().split()))
b=list(map(int,input().split()))
a.sort()
b.sort()
b=b[::-1]
for j in range(int(k)):
if b[j]>a[j] :
a[j]=b[j]
print(sum(a))
``` | output | 1 | 22,185 | 12 | 44,371 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two arrays a and b both consisting of n positive (greater than zero) integers. You are also given an integer k.
In one move, you can choose two indices i and j (1 ≤ i, j ≤ n) and swap a_i and b_j (i.e. a_i becomes b_j and vice versa). Note that i and j can be equal or different (in particular, swap a_2 with b_2 or swap a_3 and b_9 both are acceptable moves).
Your task is to find the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k such moves (swaps).
You have to answer t independent test cases.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 200) — the number of test cases. Then t test cases follow.
The first line of the test case contains two integers n and k (1 ≤ n ≤ 30; 0 ≤ k ≤ n) — the number of elements in a and b and the maximum number of moves you can do. The second line of the test case contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 30), where a_i is the i-th element of a. The third line of the test case contains n integers b_1, b_2, ..., b_n (1 ≤ b_i ≤ 30), where b_i is the i-th element of b.
Output
For each test case, print the answer — the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k swaps.
Example
Input
5
2 1
1 2
3 4
5 5
5 5 6 6 5
1 2 5 4 3
5 3
1 2 3 4 5
10 9 10 10 9
4 0
2 2 4 3
2 4 2 3
4 4
1 2 2 1
4 4 5 4
Output
6
27
39
11
17
Note
In the first test case of the example, you can swap a_1 = 1 and b_2 = 4, so a=[4, 2] and b=[3, 1].
In the second test case of the example, you don't need to swap anything.
In the third test case of the example, you can swap a_1 = 1 and b_1 = 10, a_3 = 3 and b_3 = 10 and a_2 = 2 and b_4 = 10, so a=[10, 10, 10, 4, 5] and b=[1, 9, 3, 2, 9].
In the fourth test case of the example, you cannot swap anything.
In the fifth test case of the example, you can swap arrays a and b, so a=[4, 4, 5, 4] and b=[1, 2, 2, 1]. | instruction | 0 | 22,186 | 12 | 44,372 |
Tags: greedy, sortings
Correct Solution:
```
def solve(a1, a2, k, n):
a1 = sorted(a1)
a2 = sorted(a2)
p1, p2 = 0, n-1
for i in range(k):
if p1 < n and p2>=0 and a1[p1] <a2[p2]:
a1[p1], a2[p2] = a2[p2], a1[p1]
p1 += 1
p2 -=1
else:
return sum(a1)
return sum(a1)
t = int(input())
for i in range(t):
n, k = list(map(int, input().split()))
a1 = list(map(int, input().split()))
a2 = list(map(int, input().split()))
print(solve(a1, a2, k, n))
``` | output | 1 | 22,186 | 12 | 44,373 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two arrays a and b both consisting of n positive (greater than zero) integers. You are also given an integer k.
In one move, you can choose two indices i and j (1 ≤ i, j ≤ n) and swap a_i and b_j (i.e. a_i becomes b_j and vice versa). Note that i and j can be equal or different (in particular, swap a_2 with b_2 or swap a_3 and b_9 both are acceptable moves).
Your task is to find the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k such moves (swaps).
You have to answer t independent test cases.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 200) — the number of test cases. Then t test cases follow.
The first line of the test case contains two integers n and k (1 ≤ n ≤ 30; 0 ≤ k ≤ n) — the number of elements in a and b and the maximum number of moves you can do. The second line of the test case contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 30), where a_i is the i-th element of a. The third line of the test case contains n integers b_1, b_2, ..., b_n (1 ≤ b_i ≤ 30), where b_i is the i-th element of b.
Output
For each test case, print the answer — the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k swaps.
Example
Input
5
2 1
1 2
3 4
5 5
5 5 6 6 5
1 2 5 4 3
5 3
1 2 3 4 5
10 9 10 10 9
4 0
2 2 4 3
2 4 2 3
4 4
1 2 2 1
4 4 5 4
Output
6
27
39
11
17
Note
In the first test case of the example, you can swap a_1 = 1 and b_2 = 4, so a=[4, 2] and b=[3, 1].
In the second test case of the example, you don't need to swap anything.
In the third test case of the example, you can swap a_1 = 1 and b_1 = 10, a_3 = 3 and b_3 = 10 and a_2 = 2 and b_4 = 10, so a=[10, 10, 10, 4, 5] and b=[1, 9, 3, 2, 9].
In the fourth test case of the example, you cannot swap anything.
In the fifth test case of the example, you can swap arrays a and b, so a=[4, 4, 5, 4] and b=[1, 2, 2, 1]. | instruction | 0 | 22,187 | 12 | 44,374 |
Tags: greedy, sortings
Correct Solution:
```
t=int(input())
while t>0:
n,k=map(int ,input().split())
a=list(map(int ,input().split()))
b=list(map(int ,input().split()))
a.sort()
b.sort(reverse=True)
x=[]
count=0
for i in range(0,n):
if count>=k:
break
if b[i]>a[i]:
a[i]=b[i]
count=count+1
else:
a[i]=a[i]
#print(a)
print(sum(a[0:n]))
t=t-1
``` | output | 1 | 22,187 | 12 | 44,375 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two arrays a and b both consisting of n positive (greater than zero) integers. You are also given an integer k.
In one move, you can choose two indices i and j (1 ≤ i, j ≤ n) and swap a_i and b_j (i.e. a_i becomes b_j and vice versa). Note that i and j can be equal or different (in particular, swap a_2 with b_2 or swap a_3 and b_9 both are acceptable moves).
Your task is to find the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k such moves (swaps).
You have to answer t independent test cases.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 200) — the number of test cases. Then t test cases follow.
The first line of the test case contains two integers n and k (1 ≤ n ≤ 30; 0 ≤ k ≤ n) — the number of elements in a and b and the maximum number of moves you can do. The second line of the test case contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 30), where a_i is the i-th element of a. The third line of the test case contains n integers b_1, b_2, ..., b_n (1 ≤ b_i ≤ 30), where b_i is the i-th element of b.
Output
For each test case, print the answer — the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k swaps.
Example
Input
5
2 1
1 2
3 4
5 5
5 5 6 6 5
1 2 5 4 3
5 3
1 2 3 4 5
10 9 10 10 9
4 0
2 2 4 3
2 4 2 3
4 4
1 2 2 1
4 4 5 4
Output
6
27
39
11
17
Note
In the first test case of the example, you can swap a_1 = 1 and b_2 = 4, so a=[4, 2] and b=[3, 1].
In the second test case of the example, you don't need to swap anything.
In the third test case of the example, you can swap a_1 = 1 and b_1 = 10, a_3 = 3 and b_3 = 10 and a_2 = 2 and b_4 = 10, so a=[10, 10, 10, 4, 5] and b=[1, 9, 3, 2, 9].
In the fourth test case of the example, you cannot swap anything.
In the fifth test case of the example, you can swap arrays a and b, so a=[4, 4, 5, 4] and b=[1, 2, 2, 1]. | instruction | 0 | 22,188 | 12 | 44,376 |
Tags: greedy, sortings
Correct Solution:
```
a=int(input())
for _ in range(a):
n,k=map(int,input().split())
b=list(map(int,input().split()))
c=list(map(int,input().split()))
c.sort(reverse=True)
sum=0
j=0
for i in range(k):
b.append(c[i])
b.sort(reverse=True)
for i in range(n):
sum+=b[i]
print(sum)
``` | output | 1 | 22,188 | 12 | 44,377 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two arrays a and b both consisting of n positive (greater than zero) integers. You are also given an integer k.
In one move, you can choose two indices i and j (1 ≤ i, j ≤ n) and swap a_i and b_j (i.e. a_i becomes b_j and vice versa). Note that i and j can be equal or different (in particular, swap a_2 with b_2 or swap a_3 and b_9 both are acceptable moves).
Your task is to find the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k such moves (swaps).
You have to answer t independent test cases.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 200) — the number of test cases. Then t test cases follow.
The first line of the test case contains two integers n and k (1 ≤ n ≤ 30; 0 ≤ k ≤ n) — the number of elements in a and b and the maximum number of moves you can do. The second line of the test case contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 30), where a_i is the i-th element of a. The third line of the test case contains n integers b_1, b_2, ..., b_n (1 ≤ b_i ≤ 30), where b_i is the i-th element of b.
Output
For each test case, print the answer — the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k swaps.
Example
Input
5
2 1
1 2
3 4
5 5
5 5 6 6 5
1 2 5 4 3
5 3
1 2 3 4 5
10 9 10 10 9
4 0
2 2 4 3
2 4 2 3
4 4
1 2 2 1
4 4 5 4
Output
6
27
39
11
17
Note
In the first test case of the example, you can swap a_1 = 1 and b_2 = 4, so a=[4, 2] and b=[3, 1].
In the second test case of the example, you don't need to swap anything.
In the third test case of the example, you can swap a_1 = 1 and b_1 = 10, a_3 = 3 and b_3 = 10 and a_2 = 2 and b_4 = 10, so a=[10, 10, 10, 4, 5] and b=[1, 9, 3, 2, 9].
In the fourth test case of the example, you cannot swap anything.
In the fifth test case of the example, you can swap arrays a and b, so a=[4, 4, 5, 4] and b=[1, 2, 2, 1].
Submitted Solution:
```
t = int(input())
for _ in range(t):
n, k = [int(s) for s in input().split(' ')]
a = sorted([int(s) for s in input().split(' ')])
b = sorted([int(s) for s in input().split(' ')], reverse = True)
i = 0
while k > 0 and i < n and a[i] < b[i]:
a[i] = b[i]
i += 1
k -= 1
print(sum(a))
``` | instruction | 0 | 22,189 | 12 | 44,378 |
Yes | output | 1 | 22,189 | 12 | 44,379 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two arrays a and b both consisting of n positive (greater than zero) integers. You are also given an integer k.
In one move, you can choose two indices i and j (1 ≤ i, j ≤ n) and swap a_i and b_j (i.e. a_i becomes b_j and vice versa). Note that i and j can be equal or different (in particular, swap a_2 with b_2 or swap a_3 and b_9 both are acceptable moves).
Your task is to find the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k such moves (swaps).
You have to answer t independent test cases.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 200) — the number of test cases. Then t test cases follow.
The first line of the test case contains two integers n and k (1 ≤ n ≤ 30; 0 ≤ k ≤ n) — the number of elements in a and b and the maximum number of moves you can do. The second line of the test case contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 30), where a_i is the i-th element of a. The third line of the test case contains n integers b_1, b_2, ..., b_n (1 ≤ b_i ≤ 30), where b_i is the i-th element of b.
Output
For each test case, print the answer — the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k swaps.
Example
Input
5
2 1
1 2
3 4
5 5
5 5 6 6 5
1 2 5 4 3
5 3
1 2 3 4 5
10 9 10 10 9
4 0
2 2 4 3
2 4 2 3
4 4
1 2 2 1
4 4 5 4
Output
6
27
39
11
17
Note
In the first test case of the example, you can swap a_1 = 1 and b_2 = 4, so a=[4, 2] and b=[3, 1].
In the second test case of the example, you don't need to swap anything.
In the third test case of the example, you can swap a_1 = 1 and b_1 = 10, a_3 = 3 and b_3 = 10 and a_2 = 2 and b_4 = 10, so a=[10, 10, 10, 4, 5] and b=[1, 9, 3, 2, 9].
In the fourth test case of the example, you cannot swap anything.
In the fifth test case of the example, you can swap arrays a and b, so a=[4, 4, 5, 4] and b=[1, 2, 2, 1].
Submitted Solution:
```
t = int(input())
for _ in range(t):
n, k = map(int, input().split())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
a.sort(reverse=True)
b.sort(reverse=True)
a_sum = sum(a)
b_sum = sum(b)
h = 0
t = n - 1
while h < k and a[t] < b[h]:
a_sum += b[h] - a[t]
h += 1
t -= 1
print(a_sum)
``` | instruction | 0 | 22,190 | 12 | 44,380 |
Yes | output | 1 | 22,190 | 12 | 44,381 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two arrays a and b both consisting of n positive (greater than zero) integers. You are also given an integer k.
In one move, you can choose two indices i and j (1 ≤ i, j ≤ n) and swap a_i and b_j (i.e. a_i becomes b_j and vice versa). Note that i and j can be equal or different (in particular, swap a_2 with b_2 or swap a_3 and b_9 both are acceptable moves).
Your task is to find the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k such moves (swaps).
You have to answer t independent test cases.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 200) — the number of test cases. Then t test cases follow.
The first line of the test case contains two integers n and k (1 ≤ n ≤ 30; 0 ≤ k ≤ n) — the number of elements in a and b and the maximum number of moves you can do. The second line of the test case contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 30), where a_i is the i-th element of a. The third line of the test case contains n integers b_1, b_2, ..., b_n (1 ≤ b_i ≤ 30), where b_i is the i-th element of b.
Output
For each test case, print the answer — the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k swaps.
Example
Input
5
2 1
1 2
3 4
5 5
5 5 6 6 5
1 2 5 4 3
5 3
1 2 3 4 5
10 9 10 10 9
4 0
2 2 4 3
2 4 2 3
4 4
1 2 2 1
4 4 5 4
Output
6
27
39
11
17
Note
In the first test case of the example, you can swap a_1 = 1 and b_2 = 4, so a=[4, 2] and b=[3, 1].
In the second test case of the example, you don't need to swap anything.
In the third test case of the example, you can swap a_1 = 1 and b_1 = 10, a_3 = 3 and b_3 = 10 and a_2 = 2 and b_4 = 10, so a=[10, 10, 10, 4, 5] and b=[1, 9, 3, 2, 9].
In the fourth test case of the example, you cannot swap anything.
In the fifth test case of the example, you can swap arrays a and b, so a=[4, 4, 5, 4] and b=[1, 2, 2, 1].
Submitted Solution:
```
T = int(input())
for _ in range(T):
n,k = map(int,input().split())
a = list(map(int,input().split()))
b = list(map(int,input().split()))
a.sort()
b.sort()
for i in range(k):
if a[i]<b[n-1-i]:
a[i] = b[n-1-i]
else:
break
print(sum(a))
``` | instruction | 0 | 22,191 | 12 | 44,382 |
Yes | output | 1 | 22,191 | 12 | 44,383 |
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