message stringlengths 2 433k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 113 108k | cluster float64 12 12 | __index_level_0__ int64 226 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a sequence of integers of length n and integer number k. You should print any integer number x in the range of [1; 10^9] (i.e. 1 β€ x β€ 10^9) such that exactly k elements of given sequence are less than or equal to x.
Note that the sequence can contain equal elements.
If there is no such x, print "-1" (without quotes).
Input
The first line of the input contains integer numbers n and k (1 β€ n β€ 2 β
10^5, 0 β€ k β€ n). The second line of the input contains n integer numbers a_1, a_2, ..., a_n (1 β€ a_i β€ 10^9) β the sequence itself.
Output
Print any integer number x from range [1; 10^9] such that exactly k elements of given sequence is less or equal to x.
If there is no such x, print "-1" (without quotes).
Examples
Input
7 4
3 7 5 1 10 3 20
Output
6
Input
7 2
3 7 5 1 10 3 20
Output
-1
Note
In the first example 5 is also a valid answer because the elements with indices [1, 3, 4, 6] is less than or equal to 5 and obviously less than or equal to 6.
In the second example you cannot choose any number that only 2 elements of the given sequence will be less than or equal to this number because 3 elements of the given sequence will be also less than or equal to this number. | instruction | 0 | 3,066 | 12 | 6,132 |
Tags: sortings
Correct Solution:
```
n,k=map(int,input().split())
t=list(map(int,input().split()))
t.sort()
t=t[::-1]
d={}
for i in t:
if d.get(i)==None:
d[i]=1
else:
d[i]+=1
s=0
a=0
while d!={} and s<k:
l=d.popitem()
s+=l[1]
a=l[0]
if k==0 and t[-1]!=1:
print(1)
elif s==k and k!=0:
print(a)
else:
print(-1)
``` | output | 1 | 3,066 | 12 | 6,133 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a sequence of integers of length n and integer number k. You should print any integer number x in the range of [1; 10^9] (i.e. 1 β€ x β€ 10^9) such that exactly k elements of given sequence are less than or equal to x.
Note that the sequence can contain equal elements.
If there is no such x, print "-1" (without quotes).
Input
The first line of the input contains integer numbers n and k (1 β€ n β€ 2 β
10^5, 0 β€ k β€ n). The second line of the input contains n integer numbers a_1, a_2, ..., a_n (1 β€ a_i β€ 10^9) β the sequence itself.
Output
Print any integer number x from range [1; 10^9] such that exactly k elements of given sequence is less or equal to x.
If there is no such x, print "-1" (without quotes).
Examples
Input
7 4
3 7 5 1 10 3 20
Output
6
Input
7 2
3 7 5 1 10 3 20
Output
-1
Note
In the first example 5 is also a valid answer because the elements with indices [1, 3, 4, 6] is less than or equal to 5 and obviously less than or equal to 6.
In the second example you cannot choose any number that only 2 elements of the given sequence will be less than or equal to this number because 3 elements of the given sequence will be also less than or equal to this number. | instruction | 0 | 3,067 | 12 | 6,134 |
Tags: sortings
Correct Solution:
```
import sys
input = sys.stdin.readline
n, k = map(int, input().split())
a = list(map(int, input().split()))
a.sort()
if k==0:
if a[0]==1:
print(-1)
else:
print(1)
elif k<=n-1 and a[k-1]==a[k]:
print(-1)
else:
print(a[k-1])
``` | output | 1 | 3,067 | 12 | 6,135 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence of integers of length n and integer number k. You should print any integer number x in the range of [1; 10^9] (i.e. 1 β€ x β€ 10^9) such that exactly k elements of given sequence are less than or equal to x.
Note that the sequence can contain equal elements.
If there is no such x, print "-1" (without quotes).
Input
The first line of the input contains integer numbers n and k (1 β€ n β€ 2 β
10^5, 0 β€ k β€ n). The second line of the input contains n integer numbers a_1, a_2, ..., a_n (1 β€ a_i β€ 10^9) β the sequence itself.
Output
Print any integer number x from range [1; 10^9] such that exactly k elements of given sequence is less or equal to x.
If there is no such x, print "-1" (without quotes).
Examples
Input
7 4
3 7 5 1 10 3 20
Output
6
Input
7 2
3 7 5 1 10 3 20
Output
-1
Note
In the first example 5 is also a valid answer because the elements with indices [1, 3, 4, 6] is less than or equal to 5 and obviously less than or equal to 6.
In the second example you cannot choose any number that only 2 elements of the given sequence will be less than or equal to this number because 3 elements of the given sequence will be also less than or equal to this number.
Submitted Solution:
```
def quickSort(alist):
quickSortHelper(alist,0,len(alist)-1)
def quickSortHelper(alist,first,last):
if first<last:
splitpoint = partition(alist,first,last)
quickSortHelper(alist,first,splitpoint-1)
quickSortHelper(alist,splitpoint+1,last)
def partition(alist,first,last):
pivotvalue = alist[int((first+last)/2)]
leftmark = first+1
rightmark = last
done = False
while not done:
while leftmark <= rightmark and alist[leftmark] <= pivotvalue:
leftmark = leftmark + 1
while alist[rightmark] >= pivotvalue and rightmark >= leftmark:
rightmark = rightmark -1
if rightmark < leftmark:
done = True
else:
temp = alist[leftmark]
alist[leftmark] = alist[rightmark]
alist[rightmark] = temp
temp = alist[first]
alist[first] = alist[rightmark]
alist[rightmark] = temp
return rightmark
n,k = map(int,input().split())
alist = [int(x) for x in input().split()]
alist.sort()
if k==0:
if alist[0]==1:
print(-1)
else:
print(alist[0]-1)
else:
if k==n:
print(alist[n-1])
else:
if alist[k-1]==alist[k]:
print(-1)
else:
print(alist[k-1])
``` | instruction | 0 | 3,068 | 12 | 6,136 |
Yes | output | 1 | 3,068 | 12 | 6,137 |
Provide a correct Python 3 solution for this coding contest problem.
In this problem, we consider a simple programming language that has only declarations of one- dimensional integer arrays and assignment statements. The problem is to find a bug in the given program.
The syntax of this language is given in BNF as follows:
<image>
where <new line> denotes a new line character (LF).
Characters used in a program are alphabetical letters, decimal digits, =, [, ] and new line characters. No other characters appear in a program.
A declaration declares an array and specifies its length. Valid indices of an array of length n are integers between 0 and n - 1, inclusive. Note that the array names are case sensitive, i.e. array a and array A are different arrays. The initial value of each element in the declared array is undefined.
For example, array a of length 10 and array b of length 5 are declared respectively as follows.
a[10]
b[5]
An expression evaluates to a non-negative integer. A <number> is interpreted as a decimal integer. An <array_name> [<expression>] evaluates to the value of the <expression> -th element of the array. An assignment assigns the value denoted by the right hand side to the array element specified by the left hand side.
Examples of assignments are as follows.
a[0]=3
a[1]=0
a[2]=a[a[1]]
a[a[0]]=a[1]
A program is executed from the first line, line by line. You can assume that an array is declared once and only once before any of its element is assigned or referred to.
Given a program, you are requested to find the following bugs.
* An index of an array is invalid.
* An array element that has not been assigned before is referred to in an assignment as an index of array or as the value to be assigned.
You can assume that other bugs, such as syntax errors, do not appear. You can also assume that integers represented by <number>s are between 0 and 231 - 1 (= 2147483647), inclusive.
Input
The input consists of multiple datasets followed by a line which contains only a single '.' (period). Each dataset consists of a program also followed by a line which contains only a single '.' (period). A program does not exceed 1000 lines. Any line does not exceed 80 characters excluding a new line character.
Output
For each program in the input, you should answer the line number of the assignment in which the first bug appears. The line numbers start with 1 for each program. If the program does not have a bug, you should answer zero. The output should not contain extra characters such as spaces.
Example
Input
a[3]
a[0]=a[1]
.
x[1]
x[0]=x[0]
.
a[0]
a[0]=1
.
b[2]
b[0]=2
b[1]=b[b[0]]
b[0]=b[1]
.
g[2]
G[10]
g[0]=0
g[1]=G[0]
.
a[2147483647]
a[0]=1
B[2]
B[a[0]]=2
a[B[a[0]]]=3
a[2147483646]=a[2]
.
.
Output
2
2
2
3
4
0 | instruction | 0 | 3,273 | 12 | 6,546 |
"Correct Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**13
mod = 10**9+7
dd = [(-1,0),(0,1),(1,0),(0,-1)]
ddn = [(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)]
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)
def main():
rr = []
def f(n):
_a = [n]
while 1:
s = S()
if s == '.':
break
_a.append(s)
_ks = {}
_d = {}
for _i in range(len(_a)):
_s = _a[_i]
if '=' in _s:
try:
exec(_s,_d)
for _k in _ks.keys():
# print('_k',_k)
_kl = _d[_k].keys()
# print('_kl',_kl)
if _kl and max(_kl) >= _ks[_k]:
# print('mk', _s, _k,_kl)
return _i + 1
except:
# print('except', _s)
# print('_d',_d.keys(),_d['z'])
return _i + 1
else:
_k = _s.split('[')[0]
_n = int(_s.split('[')[1].split(']')[0])
_ks[_k] = _n
# print('tg', _k + ' = {}', _n)
if _n < 1:
continue
exec(_k+"={}",_d)
return 0
while 1:
n = S()
if n == '.':
break
rr.append(f(n))
return '\n'.join(map(str,rr))
print(main())
``` | output | 1 | 3,273 | 12 | 6,547 |
Provide a correct Python 3 solution for this coding contest problem.
In this problem, we consider a simple programming language that has only declarations of one- dimensional integer arrays and assignment statements. The problem is to find a bug in the given program.
The syntax of this language is given in BNF as follows:
<image>
where <new line> denotes a new line character (LF).
Characters used in a program are alphabetical letters, decimal digits, =, [, ] and new line characters. No other characters appear in a program.
A declaration declares an array and specifies its length. Valid indices of an array of length n are integers between 0 and n - 1, inclusive. Note that the array names are case sensitive, i.e. array a and array A are different arrays. The initial value of each element in the declared array is undefined.
For example, array a of length 10 and array b of length 5 are declared respectively as follows.
a[10]
b[5]
An expression evaluates to a non-negative integer. A <number> is interpreted as a decimal integer. An <array_name> [<expression>] evaluates to the value of the <expression> -th element of the array. An assignment assigns the value denoted by the right hand side to the array element specified by the left hand side.
Examples of assignments are as follows.
a[0]=3
a[1]=0
a[2]=a[a[1]]
a[a[0]]=a[1]
A program is executed from the first line, line by line. You can assume that an array is declared once and only once before any of its element is assigned or referred to.
Given a program, you are requested to find the following bugs.
* An index of an array is invalid.
* An array element that has not been assigned before is referred to in an assignment as an index of array or as the value to be assigned.
You can assume that other bugs, such as syntax errors, do not appear. You can also assume that integers represented by <number>s are between 0 and 231 - 1 (= 2147483647), inclusive.
Input
The input consists of multiple datasets followed by a line which contains only a single '.' (period). Each dataset consists of a program also followed by a line which contains only a single '.' (period). A program does not exceed 1000 lines. Any line does not exceed 80 characters excluding a new line character.
Output
For each program in the input, you should answer the line number of the assignment in which the first bug appears. The line numbers start with 1 for each program. If the program does not have a bug, you should answer zero. The output should not contain extra characters such as spaces.
Example
Input
a[3]
a[0]=a[1]
.
x[1]
x[0]=x[0]
.
a[0]
a[0]=1
.
b[2]
b[0]=2
b[1]=b[b[0]]
b[0]=b[1]
.
g[2]
G[10]
g[0]=0
g[1]=G[0]
.
a[2147483647]
a[0]=1
B[2]
B[a[0]]=2
a[B[a[0]]]=3
a[2147483646]=a[2]
.
.
Output
2
2
2
3
4
0 | instruction | 0 | 3,274 | 12 | 6,548 |
"Correct Solution:
```
import re
def get_value(expr, array_size, array):
seq = expr.replace(']', '').split('[')
seq[-1] = int(seq[-1])
while len(seq) > 1:
ind = seq.pop()
arr = seq.pop()
if arr not in array or ind not in array[arr]:
raise KeyError
seq.append(array[arr][ind])
return seq[0]
def testcase_ends():
array_size = {}
array = {}
decl_prog = re.compile(r'(\w)\[(\d+)\]')
line = input().strip()
if line == '.':
return True
i = 1
while True:
if line == '.':
print(0)
return False
if '=' in line:
# assignment
lhs, rhs = line.split('=')
name = lhs[0]
try:
ind = get_value(lhs[2:-1], array_size, array)
value = get_value(rhs, array_size, array)
if name not in array or ind >= array_size[name]:
raise KeyError
array[name][ind] = value
except KeyError:
print(i)
break
else:
# declaration
m = decl_prog.fullmatch(line)
assert m is not None
name = m.group(1)
size = int(m.group(2))
array_size[name] = size
array[name] = {}
line = input().strip()
i += 1
line = input().strip()
while line != '.':
line = input().strip()
return False
while not testcase_ends():
pass
``` | output | 1 | 3,274 | 12 | 6,549 |
Provide a correct Python 3 solution for this coding contest problem.
In this problem, we consider a simple programming language that has only declarations of one- dimensional integer arrays and assignment statements. The problem is to find a bug in the given program.
The syntax of this language is given in BNF as follows:
<image>
where <new line> denotes a new line character (LF).
Characters used in a program are alphabetical letters, decimal digits, =, [, ] and new line characters. No other characters appear in a program.
A declaration declares an array and specifies its length. Valid indices of an array of length n are integers between 0 and n - 1, inclusive. Note that the array names are case sensitive, i.e. array a and array A are different arrays. The initial value of each element in the declared array is undefined.
For example, array a of length 10 and array b of length 5 are declared respectively as follows.
a[10]
b[5]
An expression evaluates to a non-negative integer. A <number> is interpreted as a decimal integer. An <array_name> [<expression>] evaluates to the value of the <expression> -th element of the array. An assignment assigns the value denoted by the right hand side to the array element specified by the left hand side.
Examples of assignments are as follows.
a[0]=3
a[1]=0
a[2]=a[a[1]]
a[a[0]]=a[1]
A program is executed from the first line, line by line. You can assume that an array is declared once and only once before any of its element is assigned or referred to.
Given a program, you are requested to find the following bugs.
* An index of an array is invalid.
* An array element that has not been assigned before is referred to in an assignment as an index of array or as the value to be assigned.
You can assume that other bugs, such as syntax errors, do not appear. You can also assume that integers represented by <number>s are between 0 and 231 - 1 (= 2147483647), inclusive.
Input
The input consists of multiple datasets followed by a line which contains only a single '.' (period). Each dataset consists of a program also followed by a line which contains only a single '.' (period). A program does not exceed 1000 lines. Any line does not exceed 80 characters excluding a new line character.
Output
For each program in the input, you should answer the line number of the assignment in which the first bug appears. The line numbers start with 1 for each program. If the program does not have a bug, you should answer zero. The output should not contain extra characters such as spaces.
Example
Input
a[3]
a[0]=a[1]
.
x[1]
x[0]=x[0]
.
a[0]
a[0]=1
.
b[2]
b[0]=2
b[1]=b[b[0]]
b[0]=b[1]
.
g[2]
G[10]
g[0]=0
g[1]=G[0]
.
a[2147483647]
a[0]=1
B[2]
B[a[0]]=2
a[B[a[0]]]=3
a[2147483646]=a[2]
.
.
Output
2
2
2
3
4
0 | instruction | 0 | 3,275 | 12 | 6,550 |
"Correct Solution:
```
class CustomArray:
def __init__(self, sz):
self.sz = sz
self.vals = {}
def size(self):
return self.sz
def assign(self, idx, val):
if idx == None or val == None:
return False
if idx >= self.sz:
return False
self.vals[idx] = val
return True
def get(self, idx):
if idx == None:
return None
if idx >= self.sz:
return None
if idx not in self.vals:
return None
return self.vals[idx]
class Arrays:
def __init__(self):
self.arrays = {}
def declare(self, arrName, sz):
if sz == None:
return False
if arrName in self.arrays:
return False
self.arrays[arrName] = CustomArray(sz)
return True
def assign(self, arrName, idx, val):
if arrName not in self.arrays:
return False
return self.arrays[arrName].assign(idx, val)
def get(self, arrName, idx):
if arrName not in self.arrays:
return None
return self.arrays[arrName].get(idx)
def resolve(expression):
global arrays
if "[" not in expression:
return int(expression)
arrName = expression[0]
idx = resolve(expression[2:-1])
return arrays.get(arrName, idx)
def processAssignment(command):
global arrays
equalIdx = command.find("=")
leftStr = command[:equalIdx]
rightStr = command[equalIdx + 1:]
leftArrName = leftStr[0]
leftIdx = resolve(leftStr[2:-1])
rhs = resolve(rightStr)
return arrays.assign(leftArrName, leftIdx, rhs)
def processDeclaration(arrStr):
global arrays
arrName = arrStr[0]
sz = int(arrStr[2:-1])
return arrays.declare(arrName, sz)
if __name__ == '__main__':
while True:
commands = []
while True:
line = input().strip()
if line == '.':
break
commands.append(line)
if len(commands) == 0:
break
errLine = 0
arrays = Arrays()
for i in range(len(commands)):
command = commands[i]
if "=" in command:
result = processAssignment(command)
else:
result = processDeclaration(command)
if not result:
errLine = i + 1
break
print(errLine)
``` | output | 1 | 3,275 | 12 | 6,551 |
Provide a correct Python 3 solution for this coding contest problem.
In this problem, we consider a simple programming language that has only declarations of one- dimensional integer arrays and assignment statements. The problem is to find a bug in the given program.
The syntax of this language is given in BNF as follows:
<image>
where <new line> denotes a new line character (LF).
Characters used in a program are alphabetical letters, decimal digits, =, [, ] and new line characters. No other characters appear in a program.
A declaration declares an array and specifies its length. Valid indices of an array of length n are integers between 0 and n - 1, inclusive. Note that the array names are case sensitive, i.e. array a and array A are different arrays. The initial value of each element in the declared array is undefined.
For example, array a of length 10 and array b of length 5 are declared respectively as follows.
a[10]
b[5]
An expression evaluates to a non-negative integer. A <number> is interpreted as a decimal integer. An <array_name> [<expression>] evaluates to the value of the <expression> -th element of the array. An assignment assigns the value denoted by the right hand side to the array element specified by the left hand side.
Examples of assignments are as follows.
a[0]=3
a[1]=0
a[2]=a[a[1]]
a[a[0]]=a[1]
A program is executed from the first line, line by line. You can assume that an array is declared once and only once before any of its element is assigned or referred to.
Given a program, you are requested to find the following bugs.
* An index of an array is invalid.
* An array element that has not been assigned before is referred to in an assignment as an index of array or as the value to be assigned.
You can assume that other bugs, such as syntax errors, do not appear. You can also assume that integers represented by <number>s are between 0 and 231 - 1 (= 2147483647), inclusive.
Input
The input consists of multiple datasets followed by a line which contains only a single '.' (period). Each dataset consists of a program also followed by a line which contains only a single '.' (period). A program does not exceed 1000 lines. Any line does not exceed 80 characters excluding a new line character.
Output
For each program in the input, you should answer the line number of the assignment in which the first bug appears. The line numbers start with 1 for each program. If the program does not have a bug, you should answer zero. The output should not contain extra characters such as spaces.
Example
Input
a[3]
a[0]=a[1]
.
x[1]
x[0]=x[0]
.
a[0]
a[0]=1
.
b[2]
b[0]=2
b[1]=b[b[0]]
b[0]=b[1]
.
g[2]
G[10]
g[0]=0
g[1]=G[0]
.
a[2147483647]
a[0]=1
B[2]
B[a[0]]=2
a[B[a[0]]]=3
a[2147483646]=a[2]
.
.
Output
2
2
2
3
4
0 | instruction | 0 | 3,276 | 12 | 6,552 |
"Correct Solution:
```
import re
def deref(d, expr):
expr = expr.replace(']', '')
symb = expr.split('[')
symb[-1] = symb[-1]
while len(symb) > 1:
name, index = symb[-2:]
if index not in d[name]:
return None
symb.pop()
symb.pop()
symb.append(d[name][index])
return symb[0]
def check(s):
d = {}
dd = {}
for i, stmt in enumerate(s, 1):
if '=' not in stmt:
name = stmt[0]
index = stmt[2:-1]
d[name] = {}
dd[name] = int(index)
continue
lhs, rhs = stmt.split('=')
name = lhs[0]
index = lhs[2:-1]
index = deref(d, index)
value = deref(d, rhs)
if index is None or value is None or int(index) >= dd[name]:
print(i)
return
d[name][index] = value
print(0)
def main():
list_ = []
with open(0) as fin:
for line in fin:
line = line.strip()
if line == '.':
if not list_:
return 0
check(list_)
list_ = []
continue
list_.append(line)
if __name__ == '__main__':
main()
``` | output | 1 | 3,276 | 12 | 6,553 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recently, on the course of algorithms and data structures, Valeriy learned how to use a deque. He built a deque filled with n elements. The i-th element is a_i (i = 1, 2, β¦, n). He gradually takes the first two leftmost elements from the deque (let's call them A and B, respectively), and then does the following: if A > B, he writes A to the beginning and writes B to the end of the deque, otherwise, he writes to the beginning B, and A writes to the end of the deque. We call this sequence of actions an operation.
For example, if deque was [2, 3, 4, 5, 1], on the operation he will write B=3 to the beginning and A=2 to the end, so he will get [3, 4, 5, 1, 2].
The teacher of the course, seeing Valeriy, who was passionate about his work, approached him and gave him q queries. Each query consists of the singular number m_j (j = 1, 2, β¦, q). It is required for each query to answer which two elements he will pull out on the m_j-th operation.
Note that the queries are independent and for each query the numbers A and B should be printed in the order in which they will be pulled out of the deque.
Deque is a data structure representing a list of elements where insertion of new elements or deletion of existing elements can be made from both sides.
Input
The first line contains two integers n and q (2 β€ n β€ 10^5, 0 β€ q β€ 3 β
10^5) β the number of elements in the deque and the number of queries. The second line contains n integers a_1, a_2, ..., a_n, where a_i (0 β€ a_i β€ 10^9) β the deque element in i-th position. The next q lines contain one number each, meaning m_j (1 β€ m_j β€ 10^{18}).
Output
For each teacher's query, output two numbers A and B β the numbers that Valeriy pulls out of the deque for the m_j-th operation.
Examples
Input
5 3
1 2 3 4 5
1
2
10
Output
1 2
2 3
5 2
Input
2 0
0 0
Output
Note
Consider all 10 steps for the first test in detail:
1. [1, 2, 3, 4, 5] β on the first operation, A and B are 1 and 2, respectively.
So, 2 we write to the beginning of the deque, and 1 β to the end.
We get the following status of the deque: [2, 3, 4, 5, 1].
2. [2, 3, 4, 5, 1] β A = 2, B = 3.
3. [3, 4, 5, 1, 2]
4. [4, 5, 1, 2, 3]
5. [5, 1, 2, 3, 4]
6. [5, 2, 3, 4, 1]
7. [5, 3, 4, 1, 2]
8. [5, 4, 1, 2, 3]
9. [5, 1, 2, 3, 4]
10. [5, 2, 3, 4, 1] β A = 5, B = 2. | instruction | 0 | 3,392 | 12 | 6,784 |
Tags: data structures, implementation
Correct Solution:
```
def getN():
return int(input())
def getList():
return list(map(int, input().split()))
from collections import deque
n, m = getList()
nums = getList()
mxnum = max(nums)
d = deque(nums)
qr = []
for i in range(m):
qr.append(getN())
log = []
rot = 0
while(True):
# print(d)
a = d.popleft()
b = d.popleft()
log.append((a, b))
if a > b:
a, b = b, a
d.append(a)
d.appendleft(b)
rot += 1
if b == mxnum:
break
for q in qr:
if q <= rot:
print(log[q - 1][0], log[q - 1][1])
else:
res = q - rot - 1
print(b, d[res % (n-1) + 1 ])
# print(d)
"""
5 10
1 2 5 4 3
1
2
3
4
5
6
7
8
9
10
"""
``` | output | 1 | 3,392 | 12 | 6,785 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recently, on the course of algorithms and data structures, Valeriy learned how to use a deque. He built a deque filled with n elements. The i-th element is a_i (i = 1, 2, β¦, n). He gradually takes the first two leftmost elements from the deque (let's call them A and B, respectively), and then does the following: if A > B, he writes A to the beginning and writes B to the end of the deque, otherwise, he writes to the beginning B, and A writes to the end of the deque. We call this sequence of actions an operation.
For example, if deque was [2, 3, 4, 5, 1], on the operation he will write B=3 to the beginning and A=2 to the end, so he will get [3, 4, 5, 1, 2].
The teacher of the course, seeing Valeriy, who was passionate about his work, approached him and gave him q queries. Each query consists of the singular number m_j (j = 1, 2, β¦, q). It is required for each query to answer which two elements he will pull out on the m_j-th operation.
Note that the queries are independent and for each query the numbers A and B should be printed in the order in which they will be pulled out of the deque.
Deque is a data structure representing a list of elements where insertion of new elements or deletion of existing elements can be made from both sides.
Input
The first line contains two integers n and q (2 β€ n β€ 10^5, 0 β€ q β€ 3 β
10^5) β the number of elements in the deque and the number of queries. The second line contains n integers a_1, a_2, ..., a_n, where a_i (0 β€ a_i β€ 10^9) β the deque element in i-th position. The next q lines contain one number each, meaning m_j (1 β€ m_j β€ 10^{18}).
Output
For each teacher's query, output two numbers A and B β the numbers that Valeriy pulls out of the deque for the m_j-th operation.
Examples
Input
5 3
1 2 3 4 5
1
2
10
Output
1 2
2 3
5 2
Input
2 0
0 0
Output
Note
Consider all 10 steps for the first test in detail:
1. [1, 2, 3, 4, 5] β on the first operation, A and B are 1 and 2, respectively.
So, 2 we write to the beginning of the deque, and 1 β to the end.
We get the following status of the deque: [2, 3, 4, 5, 1].
2. [2, 3, 4, 5, 1] β A = 2, B = 3.
3. [3, 4, 5, 1, 2]
4. [4, 5, 1, 2, 3]
5. [5, 1, 2, 3, 4]
6. [5, 2, 3, 4, 1]
7. [5, 3, 4, 1, 2]
8. [5, 4, 1, 2, 3]
9. [5, 1, 2, 3, 4]
10. [5, 2, 3, 4, 1] β A = 5, B = 2. | instruction | 0 | 3,393 | 12 | 6,786 |
Tags: data structures, implementation
Correct Solution:
```
import sys
input=sys.stdin.readline
from collections import defaultdict as dc
from collections import Counter
from bisect import bisect_right, bisect_left
import math
from operator import itemgetter
from heapq import heapify, heappop, heappush
n,q=map(int,input().split())
l=list(map(int,input().split()))
p=[]
t=[]
x=l[0]
for i in range(1,n):
p.append([x,l[i]])
if l[i]>=x:
t.append(x)
x=l[i]
else:
t.append(l[i])
t.insert(0,x)
#print(x,t,p)
for _ in range(q):
a=int(input())
if a<=n-1:
print(*p[a-1])
else:
y=a-n+1
j=y%(n-1)
if j==0:
j=-1
print(t[0],t[j])
``` | output | 1 | 3,393 | 12 | 6,787 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recently, on the course of algorithms and data structures, Valeriy learned how to use a deque. He built a deque filled with n elements. The i-th element is a_i (i = 1, 2, β¦, n). He gradually takes the first two leftmost elements from the deque (let's call them A and B, respectively), and then does the following: if A > B, he writes A to the beginning and writes B to the end of the deque, otherwise, he writes to the beginning B, and A writes to the end of the deque. We call this sequence of actions an operation.
For example, if deque was [2, 3, 4, 5, 1], on the operation he will write B=3 to the beginning and A=2 to the end, so he will get [3, 4, 5, 1, 2].
The teacher of the course, seeing Valeriy, who was passionate about his work, approached him and gave him q queries. Each query consists of the singular number m_j (j = 1, 2, β¦, q). It is required for each query to answer which two elements he will pull out on the m_j-th operation.
Note that the queries are independent and for each query the numbers A and B should be printed in the order in which they will be pulled out of the deque.
Deque is a data structure representing a list of elements where insertion of new elements or deletion of existing elements can be made from both sides.
Input
The first line contains two integers n and q (2 β€ n β€ 10^5, 0 β€ q β€ 3 β
10^5) β the number of elements in the deque and the number of queries. The second line contains n integers a_1, a_2, ..., a_n, where a_i (0 β€ a_i β€ 10^9) β the deque element in i-th position. The next q lines contain one number each, meaning m_j (1 β€ m_j β€ 10^{18}).
Output
For each teacher's query, output two numbers A and B β the numbers that Valeriy pulls out of the deque for the m_j-th operation.
Examples
Input
5 3
1 2 3 4 5
1
2
10
Output
1 2
2 3
5 2
Input
2 0
0 0
Output
Note
Consider all 10 steps for the first test in detail:
1. [1, 2, 3, 4, 5] β on the first operation, A and B are 1 and 2, respectively.
So, 2 we write to the beginning of the deque, and 1 β to the end.
We get the following status of the deque: [2, 3, 4, 5, 1].
2. [2, 3, 4, 5, 1] β A = 2, B = 3.
3. [3, 4, 5, 1, 2]
4. [4, 5, 1, 2, 3]
5. [5, 1, 2, 3, 4]
6. [5, 2, 3, 4, 1]
7. [5, 3, 4, 1, 2]
8. [5, 4, 1, 2, 3]
9. [5, 1, 2, 3, 4]
10. [5, 2, 3, 4, 1] β A = 5, B = 2. | instruction | 0 | 3,394 | 12 | 6,788 |
Tags: data structures, implementation
Correct Solution:
```
def op(arr,num):
for i in range(0,num-1):
if arr[0]>arr[1]:
z=arr.pop(1)
arr.append(z)
else:
z=arr.pop(0)
arr.append(z)
print (arr[0],arr[1])
def opmod(arr,num):
count=0
while arr[0]!=num:
if arr[0]>arr[1]:
z=arr.pop(1)
arr.append(z)
else:
z=arr.pop(0)
arr.append(z)
count=count+1
return count
a=input()
a=a.split()
p,q=int(a[0]),int(a[1])
a=input()
arr1=a.split()
for i in range(0,p):
arr1[i]=int(arr1[i])
s=max(arr1)
arr2=[]
for i in range(0,q):
a=int(input())
arr2.append(a)
arr3=[]
for j in range(0,p):
arr3.append(arr1[j])
rounds=opmod(arr3,s)+1
for i in range(0,q):
if arr2[i]<rounds:
arr4=[]
for j in range(0,p):
arr4.append(arr1[j])
op(arr4,arr2[i])
else:
rec=(arr2[i]-rounds)%(p-1)
print (arr3[0],arr3[1+rec])
``` | output | 1 | 3,394 | 12 | 6,789 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recently, on the course of algorithms and data structures, Valeriy learned how to use a deque. He built a deque filled with n elements. The i-th element is a_i (i = 1, 2, β¦, n). He gradually takes the first two leftmost elements from the deque (let's call them A and B, respectively), and then does the following: if A > B, he writes A to the beginning and writes B to the end of the deque, otherwise, he writes to the beginning B, and A writes to the end of the deque. We call this sequence of actions an operation.
For example, if deque was [2, 3, 4, 5, 1], on the operation he will write B=3 to the beginning and A=2 to the end, so he will get [3, 4, 5, 1, 2].
The teacher of the course, seeing Valeriy, who was passionate about his work, approached him and gave him q queries. Each query consists of the singular number m_j (j = 1, 2, β¦, q). It is required for each query to answer which two elements he will pull out on the m_j-th operation.
Note that the queries are independent and for each query the numbers A and B should be printed in the order in which they will be pulled out of the deque.
Deque is a data structure representing a list of elements where insertion of new elements or deletion of existing elements can be made from both sides.
Input
The first line contains two integers n and q (2 β€ n β€ 10^5, 0 β€ q β€ 3 β
10^5) β the number of elements in the deque and the number of queries. The second line contains n integers a_1, a_2, ..., a_n, where a_i (0 β€ a_i β€ 10^9) β the deque element in i-th position. The next q lines contain one number each, meaning m_j (1 β€ m_j β€ 10^{18}).
Output
For each teacher's query, output two numbers A and B β the numbers that Valeriy pulls out of the deque for the m_j-th operation.
Examples
Input
5 3
1 2 3 4 5
1
2
10
Output
1 2
2 3
5 2
Input
2 0
0 0
Output
Note
Consider all 10 steps for the first test in detail:
1. [1, 2, 3, 4, 5] β on the first operation, A and B are 1 and 2, respectively.
So, 2 we write to the beginning of the deque, and 1 β to the end.
We get the following status of the deque: [2, 3, 4, 5, 1].
2. [2, 3, 4, 5, 1] β A = 2, B = 3.
3. [3, 4, 5, 1, 2]
4. [4, 5, 1, 2, 3]
5. [5, 1, 2, 3, 4]
6. [5, 2, 3, 4, 1]
7. [5, 3, 4, 1, 2]
8. [5, 4, 1, 2, 3]
9. [5, 1, 2, 3, 4]
10. [5, 2, 3, 4, 1] β A = 5, B = 2. | instruction | 0 | 3,395 | 12 | 6,790 |
Tags: data structures, implementation
Correct Solution:
```
n,k=map(int,input().split())
a=list(map(int,input().split()))
mx=max(a)
ind=a.index(mx)
f=0
s=1
ans=[[] for i in range(ind)]
for i in range(ind):
ans[i].append(a[f])
ans[i].append(a[s])
if(a[f]>=a[s]):
a.append(a[s])
s+=1
else:
a.append(a[f])
f=s
s+=1
a=a[ind:]
#print(a)
for i in range(k):
m=int(input())
if(m<=ind):
print(ans[m-1][0],ans[m-1][1])
else:
m-=ind
m-=1
m%=(n-1)
print(a[0],a[1+m])
``` | output | 1 | 3,395 | 12 | 6,791 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recently, on the course of algorithms and data structures, Valeriy learned how to use a deque. He built a deque filled with n elements. The i-th element is a_i (i = 1, 2, β¦, n). He gradually takes the first two leftmost elements from the deque (let's call them A and B, respectively), and then does the following: if A > B, he writes A to the beginning and writes B to the end of the deque, otherwise, he writes to the beginning B, and A writes to the end of the deque. We call this sequence of actions an operation.
For example, if deque was [2, 3, 4, 5, 1], on the operation he will write B=3 to the beginning and A=2 to the end, so he will get [3, 4, 5, 1, 2].
The teacher of the course, seeing Valeriy, who was passionate about his work, approached him and gave him q queries. Each query consists of the singular number m_j (j = 1, 2, β¦, q). It is required for each query to answer which two elements he will pull out on the m_j-th operation.
Note that the queries are independent and for each query the numbers A and B should be printed in the order in which they will be pulled out of the deque.
Deque is a data structure representing a list of elements where insertion of new elements or deletion of existing elements can be made from both sides.
Input
The first line contains two integers n and q (2 β€ n β€ 10^5, 0 β€ q β€ 3 β
10^5) β the number of elements in the deque and the number of queries. The second line contains n integers a_1, a_2, ..., a_n, where a_i (0 β€ a_i β€ 10^9) β the deque element in i-th position. The next q lines contain one number each, meaning m_j (1 β€ m_j β€ 10^{18}).
Output
For each teacher's query, output two numbers A and B β the numbers that Valeriy pulls out of the deque for the m_j-th operation.
Examples
Input
5 3
1 2 3 4 5
1
2
10
Output
1 2
2 3
5 2
Input
2 0
0 0
Output
Note
Consider all 10 steps for the first test in detail:
1. [1, 2, 3, 4, 5] β on the first operation, A and B are 1 and 2, respectively.
So, 2 we write to the beginning of the deque, and 1 β to the end.
We get the following status of the deque: [2, 3, 4, 5, 1].
2. [2, 3, 4, 5, 1] β A = 2, B = 3.
3. [3, 4, 5, 1, 2]
4. [4, 5, 1, 2, 3]
5. [5, 1, 2, 3, 4]
6. [5, 2, 3, 4, 1]
7. [5, 3, 4, 1, 2]
8. [5, 4, 1, 2, 3]
9. [5, 1, 2, 3, 4]
10. [5, 2, 3, 4, 1] β A = 5, B = 2. | instruction | 0 | 3,396 | 12 | 6,792 |
Tags: data structures, implementation
Correct Solution:
```
a, b = map(int, input().split())
A = list(map(int, input().split()))
A.append(-1)
B = []
Z = []
AN = []
x, y = A[0], A[1]
for i in range(a - 1):
Z.append((x, y))
if x > y:
B.append(y)
y = A[i + 2]
else:
B.append(x)
x, y = y, A[i + 2]
for i in range(b):
w = int(input())
if w <= len(Z):
AN.append(Z[w - 1])
else:
w = w % len(B)
AN.append((x, B[w - 1]))
for W in AN:
print(*W)
``` | output | 1 | 3,396 | 12 | 6,793 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recently, on the course of algorithms and data structures, Valeriy learned how to use a deque. He built a deque filled with n elements. The i-th element is a_i (i = 1, 2, β¦, n). He gradually takes the first two leftmost elements from the deque (let's call them A and B, respectively), and then does the following: if A > B, he writes A to the beginning and writes B to the end of the deque, otherwise, he writes to the beginning B, and A writes to the end of the deque. We call this sequence of actions an operation.
For example, if deque was [2, 3, 4, 5, 1], on the operation he will write B=3 to the beginning and A=2 to the end, so he will get [3, 4, 5, 1, 2].
The teacher of the course, seeing Valeriy, who was passionate about his work, approached him and gave him q queries. Each query consists of the singular number m_j (j = 1, 2, β¦, q). It is required for each query to answer which two elements he will pull out on the m_j-th operation.
Note that the queries are independent and for each query the numbers A and B should be printed in the order in which they will be pulled out of the deque.
Deque is a data structure representing a list of elements where insertion of new elements or deletion of existing elements can be made from both sides.
Input
The first line contains two integers n and q (2 β€ n β€ 10^5, 0 β€ q β€ 3 β
10^5) β the number of elements in the deque and the number of queries. The second line contains n integers a_1, a_2, ..., a_n, where a_i (0 β€ a_i β€ 10^9) β the deque element in i-th position. The next q lines contain one number each, meaning m_j (1 β€ m_j β€ 10^{18}).
Output
For each teacher's query, output two numbers A and B β the numbers that Valeriy pulls out of the deque for the m_j-th operation.
Examples
Input
5 3
1 2 3 4 5
1
2
10
Output
1 2
2 3
5 2
Input
2 0
0 0
Output
Note
Consider all 10 steps for the first test in detail:
1. [1, 2, 3, 4, 5] β on the first operation, A and B are 1 and 2, respectively.
So, 2 we write to the beginning of the deque, and 1 β to the end.
We get the following status of the deque: [2, 3, 4, 5, 1].
2. [2, 3, 4, 5, 1] β A = 2, B = 3.
3. [3, 4, 5, 1, 2]
4. [4, 5, 1, 2, 3]
5. [5, 1, 2, 3, 4]
6. [5, 2, 3, 4, 1]
7. [5, 3, 4, 1, 2]
8. [5, 4, 1, 2, 3]
9. [5, 1, 2, 3, 4]
10. [5, 2, 3, 4, 1] β A = 5, B = 2. | instruction | 0 | 3,397 | 12 | 6,794 |
Tags: data structures, implementation
Correct Solution:
```
n, t = map(int, input().split())
a = list(map(int, input().split()))
b, c = [], []
u = a[0]
for v in a[1:]:
b.append(u)
if v > u:
u, v = v, u
c.append(v)
for _ in range(t):
x = int(input())
if x < n:
print(b[x-1], a[x])
else:
print(u, c[(x-1) % (n-1)])
``` | output | 1 | 3,397 | 12 | 6,795 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recently, on the course of algorithms and data structures, Valeriy learned how to use a deque. He built a deque filled with n elements. The i-th element is a_i (i = 1, 2, β¦, n). He gradually takes the first two leftmost elements from the deque (let's call them A and B, respectively), and then does the following: if A > B, he writes A to the beginning and writes B to the end of the deque, otherwise, he writes to the beginning B, and A writes to the end of the deque. We call this sequence of actions an operation.
For example, if deque was [2, 3, 4, 5, 1], on the operation he will write B=3 to the beginning and A=2 to the end, so he will get [3, 4, 5, 1, 2].
The teacher of the course, seeing Valeriy, who was passionate about his work, approached him and gave him q queries. Each query consists of the singular number m_j (j = 1, 2, β¦, q). It is required for each query to answer which two elements he will pull out on the m_j-th operation.
Note that the queries are independent and for each query the numbers A and B should be printed in the order in which they will be pulled out of the deque.
Deque is a data structure representing a list of elements where insertion of new elements or deletion of existing elements can be made from both sides.
Input
The first line contains two integers n and q (2 β€ n β€ 10^5, 0 β€ q β€ 3 β
10^5) β the number of elements in the deque and the number of queries. The second line contains n integers a_1, a_2, ..., a_n, where a_i (0 β€ a_i β€ 10^9) β the deque element in i-th position. The next q lines contain one number each, meaning m_j (1 β€ m_j β€ 10^{18}).
Output
For each teacher's query, output two numbers A and B β the numbers that Valeriy pulls out of the deque for the m_j-th operation.
Examples
Input
5 3
1 2 3 4 5
1
2
10
Output
1 2
2 3
5 2
Input
2 0
0 0
Output
Note
Consider all 10 steps for the first test in detail:
1. [1, 2, 3, 4, 5] β on the first operation, A and B are 1 and 2, respectively.
So, 2 we write to the beginning of the deque, and 1 β to the end.
We get the following status of the deque: [2, 3, 4, 5, 1].
2. [2, 3, 4, 5, 1] β A = 2, B = 3.
3. [3, 4, 5, 1, 2]
4. [4, 5, 1, 2, 3]
5. [5, 1, 2, 3, 4]
6. [5, 2, 3, 4, 1]
7. [5, 3, 4, 1, 2]
8. [5, 4, 1, 2, 3]
9. [5, 1, 2, 3, 4]
10. [5, 2, 3, 4, 1] β A = 5, B = 2. | instruction | 0 | 3,398 | 12 | 6,796 |
Tags: data structures, implementation
Correct Solution:
```
n, q = map(int,input().split())
l = list(map(int,input().split()))
m = max(l)
tab = [0] * 2*n
for i in range(n):
tab[i] = l[i]
odp = [[0,0]] * n
pocz = 0
kon = n - 1
for j in range(n):
A = tab[pocz]
B = tab[pocz + 1]
odp[j] = [A, B]
pocz += 1
kon += 1
tab[pocz] = max(A,B)
tab[kon] = min(A,B)
for i in range(q):
query = int(input())
if query <= n:
print(odp[query - 1][0], odp[query - 1][1])
else:
print(m, tab[(query-2)%(n-1)+n+1])
``` | output | 1 | 3,398 | 12 | 6,797 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recently, on the course of algorithms and data structures, Valeriy learned how to use a deque. He built a deque filled with n elements. The i-th element is a_i (i = 1, 2, β¦, n). He gradually takes the first two leftmost elements from the deque (let's call them A and B, respectively), and then does the following: if A > B, he writes A to the beginning and writes B to the end of the deque, otherwise, he writes to the beginning B, and A writes to the end of the deque. We call this sequence of actions an operation.
For example, if deque was [2, 3, 4, 5, 1], on the operation he will write B=3 to the beginning and A=2 to the end, so he will get [3, 4, 5, 1, 2].
The teacher of the course, seeing Valeriy, who was passionate about his work, approached him and gave him q queries. Each query consists of the singular number m_j (j = 1, 2, β¦, q). It is required for each query to answer which two elements he will pull out on the m_j-th operation.
Note that the queries are independent and for each query the numbers A and B should be printed in the order in which they will be pulled out of the deque.
Deque is a data structure representing a list of elements where insertion of new elements or deletion of existing elements can be made from both sides.
Input
The first line contains two integers n and q (2 β€ n β€ 10^5, 0 β€ q β€ 3 β
10^5) β the number of elements in the deque and the number of queries. The second line contains n integers a_1, a_2, ..., a_n, where a_i (0 β€ a_i β€ 10^9) β the deque element in i-th position. The next q lines contain one number each, meaning m_j (1 β€ m_j β€ 10^{18}).
Output
For each teacher's query, output two numbers A and B β the numbers that Valeriy pulls out of the deque for the m_j-th operation.
Examples
Input
5 3
1 2 3 4 5
1
2
10
Output
1 2
2 3
5 2
Input
2 0
0 0
Output
Note
Consider all 10 steps for the first test in detail:
1. [1, 2, 3, 4, 5] β on the first operation, A and B are 1 and 2, respectively.
So, 2 we write to the beginning of the deque, and 1 β to the end.
We get the following status of the deque: [2, 3, 4, 5, 1].
2. [2, 3, 4, 5, 1] β A = 2, B = 3.
3. [3, 4, 5, 1, 2]
4. [4, 5, 1, 2, 3]
5. [5, 1, 2, 3, 4]
6. [5, 2, 3, 4, 1]
7. [5, 3, 4, 1, 2]
8. [5, 4, 1, 2, 3]
9. [5, 1, 2, 3, 4]
10. [5, 2, 3, 4, 1] β A = 5, B = 2. | instruction | 0 | 3,399 | 12 | 6,798 |
Tags: data structures, implementation
Correct Solution:
```
# import sys
# input = sys.stdin.readline
n,queries = list(map(int,input().split()))
l = list(map(int,input().split()))
if(queries==0):
exit()
maxval = max(l)
pairs = []
count = 0
f = l[0]
secix = 1
while(f!=maxval):
# print(l)
count+=1
f = l[0]
s = l[secix]
pairs.append([f,s])
f,s= max(f,s), min(f,s)
l[0] = f
l.append(s)
secix+=1
# print(secix)
l = [l[0]]+l[secix:]
# print(l)
for i in range(n-1):
pairs.append([maxval,l[1+i]])
# print(pairs)
for m in range(queries):
q = int(input())
if(q<=count):
print(str(pairs[q-1][0]),str(pairs[q-1][1]))
else:
q-=(count+1)
pos = count+(q%(n-1))
print(str(pairs[pos][0]),str(pairs[pos][1]))
``` | output | 1 | 3,399 | 12 | 6,799 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Recently, on the course of algorithms and data structures, Valeriy learned how to use a deque. He built a deque filled with n elements. The i-th element is a_i (i = 1, 2, β¦, n). He gradually takes the first two leftmost elements from the deque (let's call them A and B, respectively), and then does the following: if A > B, he writes A to the beginning and writes B to the end of the deque, otherwise, he writes to the beginning B, and A writes to the end of the deque. We call this sequence of actions an operation.
For example, if deque was [2, 3, 4, 5, 1], on the operation he will write B=3 to the beginning and A=2 to the end, so he will get [3, 4, 5, 1, 2].
The teacher of the course, seeing Valeriy, who was passionate about his work, approached him and gave him q queries. Each query consists of the singular number m_j (j = 1, 2, β¦, q). It is required for each query to answer which two elements he will pull out on the m_j-th operation.
Note that the queries are independent and for each query the numbers A and B should be printed in the order in which they will be pulled out of the deque.
Deque is a data structure representing a list of elements where insertion of new elements or deletion of existing elements can be made from both sides.
Input
The first line contains two integers n and q (2 β€ n β€ 10^5, 0 β€ q β€ 3 β
10^5) β the number of elements in the deque and the number of queries. The second line contains n integers a_1, a_2, ..., a_n, where a_i (0 β€ a_i β€ 10^9) β the deque element in i-th position. The next q lines contain one number each, meaning m_j (1 β€ m_j β€ 10^{18}).
Output
For each teacher's query, output two numbers A and B β the numbers that Valeriy pulls out of the deque for the m_j-th operation.
Examples
Input
5 3
1 2 3 4 5
1
2
10
Output
1 2
2 3
5 2
Input
2 0
0 0
Output
Note
Consider all 10 steps for the first test in detail:
1. [1, 2, 3, 4, 5] β on the first operation, A and B are 1 and 2, respectively.
So, 2 we write to the beginning of the deque, and 1 β to the end.
We get the following status of the deque: [2, 3, 4, 5, 1].
2. [2, 3, 4, 5, 1] β A = 2, B = 3.
3. [3, 4, 5, 1, 2]
4. [4, 5, 1, 2, 3]
5. [5, 1, 2, 3, 4]
6. [5, 2, 3, 4, 1]
7. [5, 3, 4, 1, 2]
8. [5, 4, 1, 2, 3]
9. [5, 1, 2, 3, 4]
10. [5, 2, 3, 4, 1] β A = 5, B = 2.
Submitted Solution:
```
# !/usr/bin/env python3
# encoding: UTF-8
# Modified: <22/Jun/2019 12:28:28 AM>
# βͺ H4WK3yEδΉ‘
# Mohd. Farhan Tahir
# Indian Institute Of Information Technology (IIIT), Gwalior
import sys
import os
from io import IOBase, BytesIO
def main():
from collections import deque
n, tc = get_ints()
arr = get_array()
mx = max(arr)
q = deque()
for i in range(n):
q.append(arr[i])
query = 1
dp = [0] * 10**6
while q[0] != mx:
f = q.popleft()
s = q.popleft()
if (f > s):
q.appendleft(f)
q.append(s)
else:
q.appendleft(s)
q.append(f)
dp[query] = (f, s)
query += 1
curr = 0
c2 = query
while curr != n - 1:
#print(q, c2)
f = q.popleft()
s = q.popleft()
q.appendleft(f)
q.append(s)
dp[c2] = (f, s)
curr += 1
c2 += 1
curr = 0
cycle = c2 - query
while curr != n - 1:
#print(q, c2)
f = q.popleft()
s = q.popleft()
q.appendleft(f)
q.append(s)
dp[c2] = (f, s)
curr += 1
c2 += 1
# print(dp[:10])
#print(cycle, query, c2)
# print(dp[:10])
# print(c2)
for _ in range(tc):
j = int(input())
if j < c2:
print(*dp[j])
else:
j %= cycle
j += cycle
#print(j, "j")
print(*dp[j])
# print(dp)
def get_array(): return list(map(int, sys.stdin.readline().split()))
def get_ints(): return map(int, sys.stdin.readline().split())
def input(): return sys.stdin.readline().strip()
if __name__ == "__main__":
main()
``` | instruction | 0 | 3,400 | 12 | 6,800 |
Yes | output | 1 | 3,400 | 12 | 6,801 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Recently, on the course of algorithms and data structures, Valeriy learned how to use a deque. He built a deque filled with n elements. The i-th element is a_i (i = 1, 2, β¦, n). He gradually takes the first two leftmost elements from the deque (let's call them A and B, respectively), and then does the following: if A > B, he writes A to the beginning and writes B to the end of the deque, otherwise, he writes to the beginning B, and A writes to the end of the deque. We call this sequence of actions an operation.
For example, if deque was [2, 3, 4, 5, 1], on the operation he will write B=3 to the beginning and A=2 to the end, so he will get [3, 4, 5, 1, 2].
The teacher of the course, seeing Valeriy, who was passionate about his work, approached him and gave him q queries. Each query consists of the singular number m_j (j = 1, 2, β¦, q). It is required for each query to answer which two elements he will pull out on the m_j-th operation.
Note that the queries are independent and for each query the numbers A and B should be printed in the order in which they will be pulled out of the deque.
Deque is a data structure representing a list of elements where insertion of new elements or deletion of existing elements can be made from both sides.
Input
The first line contains two integers n and q (2 β€ n β€ 10^5, 0 β€ q β€ 3 β
10^5) β the number of elements in the deque and the number of queries. The second line contains n integers a_1, a_2, ..., a_n, where a_i (0 β€ a_i β€ 10^9) β the deque element in i-th position. The next q lines contain one number each, meaning m_j (1 β€ m_j β€ 10^{18}).
Output
For each teacher's query, output two numbers A and B β the numbers that Valeriy pulls out of the deque for the m_j-th operation.
Examples
Input
5 3
1 2 3 4 5
1
2
10
Output
1 2
2 3
5 2
Input
2 0
0 0
Output
Note
Consider all 10 steps for the first test in detail:
1. [1, 2, 3, 4, 5] β on the first operation, A and B are 1 and 2, respectively.
So, 2 we write to the beginning of the deque, and 1 β to the end.
We get the following status of the deque: [2, 3, 4, 5, 1].
2. [2, 3, 4, 5, 1] β A = 2, B = 3.
3. [3, 4, 5, 1, 2]
4. [4, 5, 1, 2, 3]
5. [5, 1, 2, 3, 4]
6. [5, 2, 3, 4, 1]
7. [5, 3, 4, 1, 2]
8. [5, 4, 1, 2, 3]
9. [5, 1, 2, 3, 4]
10. [5, 2, 3, 4, 1] β A = 5, B = 2.
Submitted Solution:
```
from collections import deque
n,q=list(map(int,input().split()))
a=list(map(int,input().rstrip().split()))
a=deque(a)
c=[]
maxi=max(a)
k=a[0]
j=0
while(a[0]!=maxi):
j+=1
k=a.popleft()
h=a.popleft()
if k>h:
a.appendleft(k)
a.append(h)
else:
a.appendleft(h)
a.append(k)
c.append((k,h))
for i in range(q):
h=int(input())-1
if h<j:
print(*c[h])
else:
print(maxi,a[(h-j)%(n-1) + 1])
``` | instruction | 0 | 3,401 | 12 | 6,802 |
Yes | output | 1 | 3,401 | 12 | 6,803 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Recently, on the course of algorithms and data structures, Valeriy learned how to use a deque. He built a deque filled with n elements. The i-th element is a_i (i = 1, 2, β¦, n). He gradually takes the first two leftmost elements from the deque (let's call them A and B, respectively), and then does the following: if A > B, he writes A to the beginning and writes B to the end of the deque, otherwise, he writes to the beginning B, and A writes to the end of the deque. We call this sequence of actions an operation.
For example, if deque was [2, 3, 4, 5, 1], on the operation he will write B=3 to the beginning and A=2 to the end, so he will get [3, 4, 5, 1, 2].
The teacher of the course, seeing Valeriy, who was passionate about his work, approached him and gave him q queries. Each query consists of the singular number m_j (j = 1, 2, β¦, q). It is required for each query to answer which two elements he will pull out on the m_j-th operation.
Note that the queries are independent and for each query the numbers A and B should be printed in the order in which they will be pulled out of the deque.
Deque is a data structure representing a list of elements where insertion of new elements or deletion of existing elements can be made from both sides.
Input
The first line contains two integers n and q (2 β€ n β€ 10^5, 0 β€ q β€ 3 β
10^5) β the number of elements in the deque and the number of queries. The second line contains n integers a_1, a_2, ..., a_n, where a_i (0 β€ a_i β€ 10^9) β the deque element in i-th position. The next q lines contain one number each, meaning m_j (1 β€ m_j β€ 10^{18}).
Output
For each teacher's query, output two numbers A and B β the numbers that Valeriy pulls out of the deque for the m_j-th operation.
Examples
Input
5 3
1 2 3 4 5
1
2
10
Output
1 2
2 3
5 2
Input
2 0
0 0
Output
Note
Consider all 10 steps for the first test in detail:
1. [1, 2, 3, 4, 5] β on the first operation, A and B are 1 and 2, respectively.
So, 2 we write to the beginning of the deque, and 1 β to the end.
We get the following status of the deque: [2, 3, 4, 5, 1].
2. [2, 3, 4, 5, 1] β A = 2, B = 3.
3. [3, 4, 5, 1, 2]
4. [4, 5, 1, 2, 3]
5. [5, 1, 2, 3, 4]
6. [5, 2, 3, 4, 1]
7. [5, 3, 4, 1, 2]
8. [5, 4, 1, 2, 3]
9. [5, 1, 2, 3, 4]
10. [5, 2, 3, 4, 1] β A = 5, B = 2.
Submitted Solution:
```
# @author
import sys
class CValeriyAndDeque:
def solve(self):
from collections import deque
n, q = [int(item) for item in input().split()]
a = [int(item) for item in input().split()]
mi = a.index(max(a))
b = deque(a)
ans = [(-1, -1)] * mi
for i in range(mi):
u, v = b.popleft(), b.popleft()
ans[i] = (u, v)
if u < v:
u, v = v, u
b.appendleft(u)
b.append(v)
b = list(b)
# print(b)
for _ in range(q):
m = int(input())
m -= 1
if m >= mi:
m -= mi
print(b[0], b[1 + m % (n - 1)])
else:
print(*ans[m])
solver = CValeriyAndDeque()
input = sys.stdin.readline
solver.solve()
``` | instruction | 0 | 3,402 | 12 | 6,804 |
Yes | output | 1 | 3,402 | 12 | 6,805 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Recently, on the course of algorithms and data structures, Valeriy learned how to use a deque. He built a deque filled with n elements. The i-th element is a_i (i = 1, 2, β¦, n). He gradually takes the first two leftmost elements from the deque (let's call them A and B, respectively), and then does the following: if A > B, he writes A to the beginning and writes B to the end of the deque, otherwise, he writes to the beginning B, and A writes to the end of the deque. We call this sequence of actions an operation.
For example, if deque was [2, 3, 4, 5, 1], on the operation he will write B=3 to the beginning and A=2 to the end, so he will get [3, 4, 5, 1, 2].
The teacher of the course, seeing Valeriy, who was passionate about his work, approached him and gave him q queries. Each query consists of the singular number m_j (j = 1, 2, β¦, q). It is required for each query to answer which two elements he will pull out on the m_j-th operation.
Note that the queries are independent and for each query the numbers A and B should be printed in the order in which they will be pulled out of the deque.
Deque is a data structure representing a list of elements where insertion of new elements or deletion of existing elements can be made from both sides.
Input
The first line contains two integers n and q (2 β€ n β€ 10^5, 0 β€ q β€ 3 β
10^5) β the number of elements in the deque and the number of queries. The second line contains n integers a_1, a_2, ..., a_n, where a_i (0 β€ a_i β€ 10^9) β the deque element in i-th position. The next q lines contain one number each, meaning m_j (1 β€ m_j β€ 10^{18}).
Output
For each teacher's query, output two numbers A and B β the numbers that Valeriy pulls out of the deque for the m_j-th operation.
Examples
Input
5 3
1 2 3 4 5
1
2
10
Output
1 2
2 3
5 2
Input
2 0
0 0
Output
Note
Consider all 10 steps for the first test in detail:
1. [1, 2, 3, 4, 5] β on the first operation, A and B are 1 and 2, respectively.
So, 2 we write to the beginning of the deque, and 1 β to the end.
We get the following status of the deque: [2, 3, 4, 5, 1].
2. [2, 3, 4, 5, 1] β A = 2, B = 3.
3. [3, 4, 5, 1, 2]
4. [4, 5, 1, 2, 3]
5. [5, 1, 2, 3, 4]
6. [5, 2, 3, 4, 1]
7. [5, 3, 4, 1, 2]
8. [5, 4, 1, 2, 3]
9. [5, 1, 2, 3, 4]
10. [5, 2, 3, 4, 1] β A = 5, B = 2.
Submitted Solution:
```
from collections import deque
n, qs = tuple(map(int, input().split()))
d = deque(list(map(int, input().split())))
m = max(d)
if qs == 0:
exit()
q = []
for i in range(qs):
v = int(input())
q.append([v, i, 'a', 'b'])
# print(q)
q.sort()
# print(q)
# print(q[0][0])
i = 0
curv = q[i][0]
j = 1
while(d[0] != m):
a = d[0]
b = d[1]
if a > b:
d.popleft()
d.popleft()
d.append(b)
d.appendleft(a)
else:
d.popleft()
d.append(a)
if curv == j:
# print(curv)
q[i][2] = a
q[i][3] = b
i += 1
while i < qs and (q[i][0] == curv):
q[i][2] = a
q[i][3] = b
i += 1
if i == qs:
break
curv = q[i][0]
# print(curv)
j += 1
# print(j-1, d)
while(i<qs):
curv = q[i][0]
q[i][2] = m
q[i][3] = d[1 + (curv - j)%(n-1)]
i += 1
q.sort(key=lambda x: x[1])
for f in range(qs):
print(str(q[f][2]) + ' ' +str(q[f][3]))
``` | instruction | 0 | 3,403 | 12 | 6,806 |
Yes | output | 1 | 3,403 | 12 | 6,807 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Recently, on the course of algorithms and data structures, Valeriy learned how to use a deque. He built a deque filled with n elements. The i-th element is a_i (i = 1, 2, β¦, n). He gradually takes the first two leftmost elements from the deque (let's call them A and B, respectively), and then does the following: if A > B, he writes A to the beginning and writes B to the end of the deque, otherwise, he writes to the beginning B, and A writes to the end of the deque. We call this sequence of actions an operation.
For example, if deque was [2, 3, 4, 5, 1], on the operation he will write B=3 to the beginning and A=2 to the end, so he will get [3, 4, 5, 1, 2].
The teacher of the course, seeing Valeriy, who was passionate about his work, approached him and gave him q queries. Each query consists of the singular number m_j (j = 1, 2, β¦, q). It is required for each query to answer which two elements he will pull out on the m_j-th operation.
Note that the queries are independent and for each query the numbers A and B should be printed in the order in which they will be pulled out of the deque.
Deque is a data structure representing a list of elements where insertion of new elements or deletion of existing elements can be made from both sides.
Input
The first line contains two integers n and q (2 β€ n β€ 10^5, 0 β€ q β€ 3 β
10^5) β the number of elements in the deque and the number of queries. The second line contains n integers a_1, a_2, ..., a_n, where a_i (0 β€ a_i β€ 10^9) β the deque element in i-th position. The next q lines contain one number each, meaning m_j (1 β€ m_j β€ 10^{18}).
Output
For each teacher's query, output two numbers A and B β the numbers that Valeriy pulls out of the deque for the m_j-th operation.
Examples
Input
5 3
1 2 3 4 5
1
2
10
Output
1 2
2 3
5 2
Input
2 0
0 0
Output
Note
Consider all 10 steps for the first test in detail:
1. [1, 2, 3, 4, 5] β on the first operation, A and B are 1 and 2, respectively.
So, 2 we write to the beginning of the deque, and 1 β to the end.
We get the following status of the deque: [2, 3, 4, 5, 1].
2. [2, 3, 4, 5, 1] β A = 2, B = 3.
3. [3, 4, 5, 1, 2]
4. [4, 5, 1, 2, 3]
5. [5, 1, 2, 3, 4]
6. [5, 2, 3, 4, 1]
7. [5, 3, 4, 1, 2]
8. [5, 4, 1, 2, 3]
9. [5, 1, 2, 3, 4]
10. [5, 2, 3, 4, 1] β A = 5, B = 2.
Submitted Solution:
```
n,x = map(int, input().split())
m = list(map(int, input().split()))
ind = 0
for i in range(n):
if(m[ind]<m[i]):
ind = i
z = m[ind]
r = m[0]
ans = []
l = []
for i in range(ind):
ans.append([r,m[i+1]])
l.append(r)
r = m[i+1]
for i in range(ind+1, n):
l.append(m[i])
#l.reverse()
for i in range(x):
q = int(input())
if(q<=ind):
print(ans[q-1][0], ans[q-1][1])
elif(q>=n):
print(z, l[(q-ind-1)%(n-1)])
else:
print(z, m[q])
``` | instruction | 0 | 3,404 | 12 | 6,808 |
No | output | 1 | 3,404 | 12 | 6,809 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Recently, on the course of algorithms and data structures, Valeriy learned how to use a deque. He built a deque filled with n elements. The i-th element is a_i (i = 1, 2, β¦, n). He gradually takes the first two leftmost elements from the deque (let's call them A and B, respectively), and then does the following: if A > B, he writes A to the beginning and writes B to the end of the deque, otherwise, he writes to the beginning B, and A writes to the end of the deque. We call this sequence of actions an operation.
For example, if deque was [2, 3, 4, 5, 1], on the operation he will write B=3 to the beginning and A=2 to the end, so he will get [3, 4, 5, 1, 2].
The teacher of the course, seeing Valeriy, who was passionate about his work, approached him and gave him q queries. Each query consists of the singular number m_j (j = 1, 2, β¦, q). It is required for each query to answer which two elements he will pull out on the m_j-th operation.
Note that the queries are independent and for each query the numbers A and B should be printed in the order in which they will be pulled out of the deque.
Deque is a data structure representing a list of elements where insertion of new elements or deletion of existing elements can be made from both sides.
Input
The first line contains two integers n and q (2 β€ n β€ 10^5, 0 β€ q β€ 3 β
10^5) β the number of elements in the deque and the number of queries. The second line contains n integers a_1, a_2, ..., a_n, where a_i (0 β€ a_i β€ 10^9) β the deque element in i-th position. The next q lines contain one number each, meaning m_j (1 β€ m_j β€ 10^{18}).
Output
For each teacher's query, output two numbers A and B β the numbers that Valeriy pulls out of the deque for the m_j-th operation.
Examples
Input
5 3
1 2 3 4 5
1
2
10
Output
1 2
2 3
5 2
Input
2 0
0 0
Output
Note
Consider all 10 steps for the first test in detail:
1. [1, 2, 3, 4, 5] β on the first operation, A and B are 1 and 2, respectively.
So, 2 we write to the beginning of the deque, and 1 β to the end.
We get the following status of the deque: [2, 3, 4, 5, 1].
2. [2, 3, 4, 5, 1] β A = 2, B = 3.
3. [3, 4, 5, 1, 2]
4. [4, 5, 1, 2, 3]
5. [5, 1, 2, 3, 4]
6. [5, 2, 3, 4, 1]
7. [5, 3, 4, 1, 2]
8. [5, 4, 1, 2, 3]
9. [5, 1, 2, 3, 4]
10. [5, 2, 3, 4, 1] β A = 5, B = 2.
Submitted Solution:
```
class Dek:
def __init__(self):
self.items = []
def isEmpty(self):
return self.items == []
def addFront(self, item):
self.items.append(item)
def addRear(self, item):
self.items.insert(0,item)
def removeFront(self):
return self.items.pop()
def removeRear(self):
return self.items.pop(0)
def size(self):
return len(self.items)
def op(self):
a = self.removeRear()
b = self.removeRear()
if a > b:
self.addRear(a)
self.addFront(b)
else:
self.addRear(b)
self.addFront(a)
return (a, b)
dek = Dek()
n, q = map(int, input().split())
arr = list(map(int, input().split()))
for i in range(n):
dek.addFront(arr[i])
qs = []
ans = [()]*q
for i in range(q):
qs.append(int(input()))
i = 0
while dek.items[0] != max(dek.items):
a, b = dek.op()
if i + 1 in qs:
for k in range(len(qs)):
if qs[k] == i + 1:
ans[k] = (a, b)
i += 1
for j in qs:
if j > i:
j -= i
num_el = j % (n - 1)
if num_el == 0:
num_el = n - 1
ans[qs.index(j + i)] = (dek.items[0], dek.items[num_el])
for an in ans:
print(*an)
``` | instruction | 0 | 3,405 | 12 | 6,810 |
No | output | 1 | 3,405 | 12 | 6,811 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Recently, on the course of algorithms and data structures, Valeriy learned how to use a deque. He built a deque filled with n elements. The i-th element is a_i (i = 1, 2, β¦, n). He gradually takes the first two leftmost elements from the deque (let's call them A and B, respectively), and then does the following: if A > B, he writes A to the beginning and writes B to the end of the deque, otherwise, he writes to the beginning B, and A writes to the end of the deque. We call this sequence of actions an operation.
For example, if deque was [2, 3, 4, 5, 1], on the operation he will write B=3 to the beginning and A=2 to the end, so he will get [3, 4, 5, 1, 2].
The teacher of the course, seeing Valeriy, who was passionate about his work, approached him and gave him q queries. Each query consists of the singular number m_j (j = 1, 2, β¦, q). It is required for each query to answer which two elements he will pull out on the m_j-th operation.
Note that the queries are independent and for each query the numbers A and B should be printed in the order in which they will be pulled out of the deque.
Deque is a data structure representing a list of elements where insertion of new elements or deletion of existing elements can be made from both sides.
Input
The first line contains two integers n and q (2 β€ n β€ 10^5, 0 β€ q β€ 3 β
10^5) β the number of elements in the deque and the number of queries. The second line contains n integers a_1, a_2, ..., a_n, where a_i (0 β€ a_i β€ 10^9) β the deque element in i-th position. The next q lines contain one number each, meaning m_j (1 β€ m_j β€ 10^{18}).
Output
For each teacher's query, output two numbers A and B β the numbers that Valeriy pulls out of the deque for the m_j-th operation.
Examples
Input
5 3
1 2 3 4 5
1
2
10
Output
1 2
2 3
5 2
Input
2 0
0 0
Output
Note
Consider all 10 steps for the first test in detail:
1. [1, 2, 3, 4, 5] β on the first operation, A and B are 1 and 2, respectively.
So, 2 we write to the beginning of the deque, and 1 β to the end.
We get the following status of the deque: [2, 3, 4, 5, 1].
2. [2, 3, 4, 5, 1] β A = 2, B = 3.
3. [3, 4, 5, 1, 2]
4. [4, 5, 1, 2, 3]
5. [5, 1, 2, 3, 4]
6. [5, 2, 3, 4, 1]
7. [5, 3, 4, 1, 2]
8. [5, 4, 1, 2, 3]
9. [5, 1, 2, 3, 4]
10. [5, 2, 3, 4, 1] β A = 5, B = 2.
Submitted Solution:
```
import collections
if __name__ == "__main__":
n, q = list(map(int, input().split()))
a = collections.deque(map(int, input().split()))
maxn = max(a)
res = list(range(n))
cnt = 1
while True:
if a[0] == maxn:
break
res[cnt] = [a[0], a[1]]
cnt += 1
A = a.popleft()
B = a.popleft()
if A > B:
a.appendleft(A)
a.append(B)
else:
a.appendleft(B)
a.append(A)
for i in range(q):
m = int(input())
if m < cnt:
print(res[m][0], res[m][1])
else:
print(maxn, int((m - cnt) % (n - 1) + 1))
``` | instruction | 0 | 3,406 | 12 | 6,812 |
No | output | 1 | 3,406 | 12 | 6,813 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Recently, on the course of algorithms and data structures, Valeriy learned how to use a deque. He built a deque filled with n elements. The i-th element is a_i (i = 1, 2, β¦, n). He gradually takes the first two leftmost elements from the deque (let's call them A and B, respectively), and then does the following: if A > B, he writes A to the beginning and writes B to the end of the deque, otherwise, he writes to the beginning B, and A writes to the end of the deque. We call this sequence of actions an operation.
For example, if deque was [2, 3, 4, 5, 1], on the operation he will write B=3 to the beginning and A=2 to the end, so he will get [3, 4, 5, 1, 2].
The teacher of the course, seeing Valeriy, who was passionate about his work, approached him and gave him q queries. Each query consists of the singular number m_j (j = 1, 2, β¦, q). It is required for each query to answer which two elements he will pull out on the m_j-th operation.
Note that the queries are independent and for each query the numbers A and B should be printed in the order in which they will be pulled out of the deque.
Deque is a data structure representing a list of elements where insertion of new elements or deletion of existing elements can be made from both sides.
Input
The first line contains two integers n and q (2 β€ n β€ 10^5, 0 β€ q β€ 3 β
10^5) β the number of elements in the deque and the number of queries. The second line contains n integers a_1, a_2, ..., a_n, where a_i (0 β€ a_i β€ 10^9) β the deque element in i-th position. The next q lines contain one number each, meaning m_j (1 β€ m_j β€ 10^{18}).
Output
For each teacher's query, output two numbers A and B β the numbers that Valeriy pulls out of the deque for the m_j-th operation.
Examples
Input
5 3
1 2 3 4 5
1
2
10
Output
1 2
2 3
5 2
Input
2 0
0 0
Output
Note
Consider all 10 steps for the first test in detail:
1. [1, 2, 3, 4, 5] β on the first operation, A and B are 1 and 2, respectively.
So, 2 we write to the beginning of the deque, and 1 β to the end.
We get the following status of the deque: [2, 3, 4, 5, 1].
2. [2, 3, 4, 5, 1] β A = 2, B = 3.
3. [3, 4, 5, 1, 2]
4. [4, 5, 1, 2, 3]
5. [5, 1, 2, 3, 4]
6. [5, 2, 3, 4, 1]
7. [5, 3, 4, 1, 2]
8. [5, 4, 1, 2, 3]
9. [5, 1, 2, 3, 4]
10. [5, 2, 3, 4, 1] β A = 5, B = 2.
Submitted Solution:
```
import sys
from collections import deque
input = sys.stdin.readline
n, q = map(int, input().split())
a = list(map(int, input().split()))
query = [int(input()) for i in range(q)]
max_a = max(a)
for i in range(n):
if a[i] == max_a:
max_ind = i
break
ans = [0]*(n+1)
tmp_max = -1
for i in range(n-1):
tmp_max = max(tmp_max, a[i])
ans[i] = [tmp_max, a[i+1]]
if a[i+1] == max_a:
break
a = a[i+1:] + sorted(a[0:i+1])
for j in query:
if j - 1 <= i:
print(" ".join(map(str, ans[j-1])))
else:
print(max_a, a[(j - 2 - i) % (n - 1)+1] )
``` | instruction | 0 | 3,407 | 12 | 6,814 |
No | output | 1 | 3,407 | 12 | 6,815 |
Provide tags and a correct Python 3 solution for this coding contest problem.
One common way of digitalizing sound is to record sound intensity at particular time moments. For each time moment intensity is recorded as a non-negative integer. Thus we can represent a sound file as an array of n non-negative integers.
If there are exactly K distinct values in the array, then we need k = β log_{2} K β bits to store each value. It then takes nk bits to store the whole file.
To reduce the memory consumption we need to apply some compression. One common way is to reduce the number of possible intensity values. We choose two integers l β€ r, and after that all intensity values are changed in the following way: if the intensity value is within the range [l;r], we don't change it. If it is less than l, we change it to l; if it is greater than r, we change it to r. You can see that we lose some low and some high intensities.
Your task is to apply this compression in such a way that the file fits onto a disk of size I bytes, and the number of changed elements in the array is minimal possible.
We remind you that 1 byte contains 8 bits.
k = β log_{2} K β is the smallest integer such that K β€ 2^{k}. In particular, if K = 1, then k = 0.
Input
The first line contains two integers n and I (1 β€ n β€ 4 β
10^{5}, 1 β€ I β€ 10^{8}) β the length of the array and the size of the disk in bytes, respectively.
The next line contains n integers a_{i} (0 β€ a_{i} β€ 10^{9}) β the array denoting the sound file.
Output
Print a single integer β the minimal possible number of changed elements.
Examples
Input
6 1
2 1 2 3 4 3
Output
2
Input
6 2
2 1 2 3 4 3
Output
0
Input
6 1
1 1 2 2 3 3
Output
2
Note
In the first example we can choose l=2, r=3. The array becomes 2 2 2 3 3 3, the number of distinct elements is K=2, and the sound file fits onto the disk. Only two values are changed.
In the second example the disk is larger, so the initial file fits it and no changes are required.
In the third example we have to change both 1s or both 3s. | instruction | 0 | 3,408 | 12 | 6,816 |
Tags: sortings, two pointers
Correct Solution:
```
import math;
n,I = map(int,input().split());
arr = list(map(int,input().split()));
k = 8*I//n;
K = 2**k;
arr.sort();
nd = 1;
le = arr[0];
b = [0];
for i in range(1,n):
if(arr[i]!=le):
le=arr[i];
b.append(i);
nd+=1;
b.append(n)
#print(b);
#print(nd);
if(K>=nd):
print(0);
else:
maxn = 0;
for i in range(K,nd):
maxn = max(maxn,(b[i]-b[i-K]));
print(n-maxn)
``` | output | 1 | 3,408 | 12 | 6,817 |
Provide tags and a correct Python 3 solution for this coding contest problem.
One common way of digitalizing sound is to record sound intensity at particular time moments. For each time moment intensity is recorded as a non-negative integer. Thus we can represent a sound file as an array of n non-negative integers.
If there are exactly K distinct values in the array, then we need k = β log_{2} K β bits to store each value. It then takes nk bits to store the whole file.
To reduce the memory consumption we need to apply some compression. One common way is to reduce the number of possible intensity values. We choose two integers l β€ r, and after that all intensity values are changed in the following way: if the intensity value is within the range [l;r], we don't change it. If it is less than l, we change it to l; if it is greater than r, we change it to r. You can see that we lose some low and some high intensities.
Your task is to apply this compression in such a way that the file fits onto a disk of size I bytes, and the number of changed elements in the array is minimal possible.
We remind you that 1 byte contains 8 bits.
k = β log_{2} K β is the smallest integer such that K β€ 2^{k}. In particular, if K = 1, then k = 0.
Input
The first line contains two integers n and I (1 β€ n β€ 4 β
10^{5}, 1 β€ I β€ 10^{8}) β the length of the array and the size of the disk in bytes, respectively.
The next line contains n integers a_{i} (0 β€ a_{i} β€ 10^{9}) β the array denoting the sound file.
Output
Print a single integer β the minimal possible number of changed elements.
Examples
Input
6 1
2 1 2 3 4 3
Output
2
Input
6 2
2 1 2 3 4 3
Output
0
Input
6 1
1 1 2 2 3 3
Output
2
Note
In the first example we can choose l=2, r=3. The array becomes 2 2 2 3 3 3, the number of distinct elements is K=2, and the sound file fits onto the disk. Only two values are changed.
In the second example the disk is larger, so the initial file fits it and no changes are required.
In the third example we have to change both 1s or both 3s. | instruction | 0 | 3,409 | 12 | 6,818 |
Tags: sortings, two pointers
Correct Solution:
```
n,l=[int(x) for x in input().split()]
a=sorted([int(x) for x in input().split()])
num=len(set(a))
arr=2**((8*l)//n)
a.append(10**100)
b=[]
counter=1
for i in range(1,n+1):
if a[i]==a[i-1]:
counter+=1
else:
b.append(counter)
counter=1
pref=[0]
for item in b:
pref.append(pref[-1]+item)
c=max(num-arr,0)
lena=len(pref)
answer=10**100
for i in range(c+1):
answer=min(answer,pref[i]+pref[lena-1]-pref[lena-c+i-1])
print(answer)
``` | output | 1 | 3,409 | 12 | 6,819 |
Provide tags and a correct Python 3 solution for this coding contest problem.
One common way of digitalizing sound is to record sound intensity at particular time moments. For each time moment intensity is recorded as a non-negative integer. Thus we can represent a sound file as an array of n non-negative integers.
If there are exactly K distinct values in the array, then we need k = β log_{2} K β bits to store each value. It then takes nk bits to store the whole file.
To reduce the memory consumption we need to apply some compression. One common way is to reduce the number of possible intensity values. We choose two integers l β€ r, and after that all intensity values are changed in the following way: if the intensity value is within the range [l;r], we don't change it. If it is less than l, we change it to l; if it is greater than r, we change it to r. You can see that we lose some low and some high intensities.
Your task is to apply this compression in such a way that the file fits onto a disk of size I bytes, and the number of changed elements in the array is minimal possible.
We remind you that 1 byte contains 8 bits.
k = β log_{2} K β is the smallest integer such that K β€ 2^{k}. In particular, if K = 1, then k = 0.
Input
The first line contains two integers n and I (1 β€ n β€ 4 β
10^{5}, 1 β€ I β€ 10^{8}) β the length of the array and the size of the disk in bytes, respectively.
The next line contains n integers a_{i} (0 β€ a_{i} β€ 10^{9}) β the array denoting the sound file.
Output
Print a single integer β the minimal possible number of changed elements.
Examples
Input
6 1
2 1 2 3 4 3
Output
2
Input
6 2
2 1 2 3 4 3
Output
0
Input
6 1
1 1 2 2 3 3
Output
2
Note
In the first example we can choose l=2, r=3. The array becomes 2 2 2 3 3 3, the number of distinct elements is K=2, and the sound file fits onto the disk. Only two values are changed.
In the second example the disk is larger, so the initial file fits it and no changes are required.
In the third example we have to change both 1s or both 3s. | instruction | 0 | 3,410 | 12 | 6,820 |
Tags: sortings, two pointers
Correct Solution:
```
n, m = map(int, input().split())
a = sorted(map(int, input().split()))
b = [0]
a += [1 << 30]
for i in range(n):
if a[i] < a[i+1]:
b += [i+1]
print(n-max((y-x for x,y in zip(b,b[1<<8*m//n:])),default=n))
``` | output | 1 | 3,410 | 12 | 6,821 |
Provide tags and a correct Python 3 solution for this coding contest problem.
One common way of digitalizing sound is to record sound intensity at particular time moments. For each time moment intensity is recorded as a non-negative integer. Thus we can represent a sound file as an array of n non-negative integers.
If there are exactly K distinct values in the array, then we need k = β log_{2} K β bits to store each value. It then takes nk bits to store the whole file.
To reduce the memory consumption we need to apply some compression. One common way is to reduce the number of possible intensity values. We choose two integers l β€ r, and after that all intensity values are changed in the following way: if the intensity value is within the range [l;r], we don't change it. If it is less than l, we change it to l; if it is greater than r, we change it to r. You can see that we lose some low and some high intensities.
Your task is to apply this compression in such a way that the file fits onto a disk of size I bytes, and the number of changed elements in the array is minimal possible.
We remind you that 1 byte contains 8 bits.
k = β log_{2} K β is the smallest integer such that K β€ 2^{k}. In particular, if K = 1, then k = 0.
Input
The first line contains two integers n and I (1 β€ n β€ 4 β
10^{5}, 1 β€ I β€ 10^{8}) β the length of the array and the size of the disk in bytes, respectively.
The next line contains n integers a_{i} (0 β€ a_{i} β€ 10^{9}) β the array denoting the sound file.
Output
Print a single integer β the minimal possible number of changed elements.
Examples
Input
6 1
2 1 2 3 4 3
Output
2
Input
6 2
2 1 2 3 4 3
Output
0
Input
6 1
1 1 2 2 3 3
Output
2
Note
In the first example we can choose l=2, r=3. The array becomes 2 2 2 3 3 3, the number of distinct elements is K=2, and the sound file fits onto the disk. Only two values are changed.
In the second example the disk is larger, so the initial file fits it and no changes are required.
In the third example we have to change both 1s or both 3s. | instruction | 0 | 3,411 | 12 | 6,822 |
Tags: sortings, two pointers
Correct Solution:
```
from math import log2, ceil
n, k = map(int, input().split())
k *= 8
a = sorted(list(map(int, input().split())))
q1, dif = 0, 1
ans = float('inf')
for q in range(n):
while n*ceil(log2(dif)) <= k and q1 < n:
if q1 == n-1 or a[q1] != a[q1+1]:
dif += 1
q1 += 1
ans = min(ans, q+n-q1)
if q != n-1 and a[q] != a[q+1]:
dif -= 1
print(ans)
``` | output | 1 | 3,411 | 12 | 6,823 |
Provide tags and a correct Python 3 solution for this coding contest problem.
One common way of digitalizing sound is to record sound intensity at particular time moments. For each time moment intensity is recorded as a non-negative integer. Thus we can represent a sound file as an array of n non-negative integers.
If there are exactly K distinct values in the array, then we need k = β log_{2} K β bits to store each value. It then takes nk bits to store the whole file.
To reduce the memory consumption we need to apply some compression. One common way is to reduce the number of possible intensity values. We choose two integers l β€ r, and after that all intensity values are changed in the following way: if the intensity value is within the range [l;r], we don't change it. If it is less than l, we change it to l; if it is greater than r, we change it to r. You can see that we lose some low and some high intensities.
Your task is to apply this compression in such a way that the file fits onto a disk of size I bytes, and the number of changed elements in the array is minimal possible.
We remind you that 1 byte contains 8 bits.
k = β log_{2} K β is the smallest integer such that K β€ 2^{k}. In particular, if K = 1, then k = 0.
Input
The first line contains two integers n and I (1 β€ n β€ 4 β
10^{5}, 1 β€ I β€ 10^{8}) β the length of the array and the size of the disk in bytes, respectively.
The next line contains n integers a_{i} (0 β€ a_{i} β€ 10^{9}) β the array denoting the sound file.
Output
Print a single integer β the minimal possible number of changed elements.
Examples
Input
6 1
2 1 2 3 4 3
Output
2
Input
6 2
2 1 2 3 4 3
Output
0
Input
6 1
1 1 2 2 3 3
Output
2
Note
In the first example we can choose l=2, r=3. The array becomes 2 2 2 3 3 3, the number of distinct elements is K=2, and the sound file fits onto the disk. Only two values are changed.
In the second example the disk is larger, so the initial file fits it and no changes are required.
In the third example we have to change both 1s or both 3s. | instruction | 0 | 3,412 | 12 | 6,824 |
Tags: sortings, two pointers
Correct Solution:
```
n,I=map(int,input().split())
I*=8
I //= n
arr=list(map(int,input().split()))
arr.sort()
smen = [0]
typs = 1
for i in range(1,n):
if arr[i] != arr[i-1]:
typs+=1
smen.append(i)
smen.append(n)
deg = 1
lg = 0
while deg < typs:
lg += 1
deg *= 2
if lg == 0 or I >= lg:
print(0)
else:
degi = 2 ** I
mon = typs - degi
ans = 400001
for x in range(mon+1):
now = smen[x] + n - smen[typs-mon+x]
if now<ans:
ans=now
print(ans)
``` | output | 1 | 3,412 | 12 | 6,825 |
Provide tags and a correct Python 3 solution for this coding contest problem.
One common way of digitalizing sound is to record sound intensity at particular time moments. For each time moment intensity is recorded as a non-negative integer. Thus we can represent a sound file as an array of n non-negative integers.
If there are exactly K distinct values in the array, then we need k = β log_{2} K β bits to store each value. It then takes nk bits to store the whole file.
To reduce the memory consumption we need to apply some compression. One common way is to reduce the number of possible intensity values. We choose two integers l β€ r, and after that all intensity values are changed in the following way: if the intensity value is within the range [l;r], we don't change it. If it is less than l, we change it to l; if it is greater than r, we change it to r. You can see that we lose some low and some high intensities.
Your task is to apply this compression in such a way that the file fits onto a disk of size I bytes, and the number of changed elements in the array is minimal possible.
We remind you that 1 byte contains 8 bits.
k = β log_{2} K β is the smallest integer such that K β€ 2^{k}. In particular, if K = 1, then k = 0.
Input
The first line contains two integers n and I (1 β€ n β€ 4 β
10^{5}, 1 β€ I β€ 10^{8}) β the length of the array and the size of the disk in bytes, respectively.
The next line contains n integers a_{i} (0 β€ a_{i} β€ 10^{9}) β the array denoting the sound file.
Output
Print a single integer β the minimal possible number of changed elements.
Examples
Input
6 1
2 1 2 3 4 3
Output
2
Input
6 2
2 1 2 3 4 3
Output
0
Input
6 1
1 1 2 2 3 3
Output
2
Note
In the first example we can choose l=2, r=3. The array becomes 2 2 2 3 3 3, the number of distinct elements is K=2, and the sound file fits onto the disk. Only two values are changed.
In the second example the disk is larger, so the initial file fits it and no changes are required.
In the third example we have to change both 1s or both 3s. | instruction | 0 | 3,413 | 12 | 6,826 |
Tags: sortings, two pointers
Correct Solution:
```
n,I=list(map(int, input().split()))
l=list(map(int, input().split()))
k=2**(I*8//n)
dd={}
for x in l:
if x in dd:
dd[x]+=1
else:
dd[x]=1
# print(dd)
l=[dd[x] for x in sorted(dd)]
# print(l)
n=len(l)
if k>=n:
print(0)
else:
ss=sum(l[:k])
mxm=ss
for i in range(1,n-k+1):
ss+=l[i+k-1]-l[i-1]
if mxm<ss:
mxm=ss
print(sum(l)-mxm)
``` | output | 1 | 3,413 | 12 | 6,827 |
Provide tags and a correct Python 3 solution for this coding contest problem.
One common way of digitalizing sound is to record sound intensity at particular time moments. For each time moment intensity is recorded as a non-negative integer. Thus we can represent a sound file as an array of n non-negative integers.
If there are exactly K distinct values in the array, then we need k = β log_{2} K β bits to store each value. It then takes nk bits to store the whole file.
To reduce the memory consumption we need to apply some compression. One common way is to reduce the number of possible intensity values. We choose two integers l β€ r, and after that all intensity values are changed in the following way: if the intensity value is within the range [l;r], we don't change it. If it is less than l, we change it to l; if it is greater than r, we change it to r. You can see that we lose some low and some high intensities.
Your task is to apply this compression in such a way that the file fits onto a disk of size I bytes, and the number of changed elements in the array is minimal possible.
We remind you that 1 byte contains 8 bits.
k = β log_{2} K β is the smallest integer such that K β€ 2^{k}. In particular, if K = 1, then k = 0.
Input
The first line contains two integers n and I (1 β€ n β€ 4 β
10^{5}, 1 β€ I β€ 10^{8}) β the length of the array and the size of the disk in bytes, respectively.
The next line contains n integers a_{i} (0 β€ a_{i} β€ 10^{9}) β the array denoting the sound file.
Output
Print a single integer β the minimal possible number of changed elements.
Examples
Input
6 1
2 1 2 3 4 3
Output
2
Input
6 2
2 1 2 3 4 3
Output
0
Input
6 1
1 1 2 2 3 3
Output
2
Note
In the first example we can choose l=2, r=3. The array becomes 2 2 2 3 3 3, the number of distinct elements is K=2, and the sound file fits onto the disk. Only two values are changed.
In the second example the disk is larger, so the initial file fits it and no changes are required.
In the third example we have to change both 1s or both 3s. | instruction | 0 | 3,414 | 12 | 6,828 |
Tags: sortings, two pointers
Correct Solution:
```
from sys import stdin
input = stdin.readline
from math import floor
n, I = [int(i) for i in input().split()]
a = [int(i) for i in input().split()]
K = 2**(floor(8*I/n))
num_occ = dict()
for i in range(n):
num_occ[a[i]] = num_occ.get(a[i], 0) + 1
if K >= len(num_occ):
print(0)
else:
sort_keys = sorted(num_occ.keys())
sum_K = [0]*(len(sort_keys)-K+1)
acc_K = 0
for i in range(K):
acc_K += num_occ[sort_keys[i]]
sum_K[0] = acc_K
for i in range(K, len(sort_keys)):
acc_K += num_occ[sort_keys[i]]-num_occ[sort_keys[i-K]]
sum_K[i-K+1] = acc_K
print(n-max(sum_K))
``` | output | 1 | 3,414 | 12 | 6,829 |
Provide tags and a correct Python 3 solution for this coding contest problem.
One common way of digitalizing sound is to record sound intensity at particular time moments. For each time moment intensity is recorded as a non-negative integer. Thus we can represent a sound file as an array of n non-negative integers.
If there are exactly K distinct values in the array, then we need k = β log_{2} K β bits to store each value. It then takes nk bits to store the whole file.
To reduce the memory consumption we need to apply some compression. One common way is to reduce the number of possible intensity values. We choose two integers l β€ r, and after that all intensity values are changed in the following way: if the intensity value is within the range [l;r], we don't change it. If it is less than l, we change it to l; if it is greater than r, we change it to r. You can see that we lose some low and some high intensities.
Your task is to apply this compression in such a way that the file fits onto a disk of size I bytes, and the number of changed elements in the array is minimal possible.
We remind you that 1 byte contains 8 bits.
k = β log_{2} K β is the smallest integer such that K β€ 2^{k}. In particular, if K = 1, then k = 0.
Input
The first line contains two integers n and I (1 β€ n β€ 4 β
10^{5}, 1 β€ I β€ 10^{8}) β the length of the array and the size of the disk in bytes, respectively.
The next line contains n integers a_{i} (0 β€ a_{i} β€ 10^{9}) β the array denoting the sound file.
Output
Print a single integer β the minimal possible number of changed elements.
Examples
Input
6 1
2 1 2 3 4 3
Output
2
Input
6 2
2 1 2 3 4 3
Output
0
Input
6 1
1 1 2 2 3 3
Output
2
Note
In the first example we can choose l=2, r=3. The array becomes 2 2 2 3 3 3, the number of distinct elements is K=2, and the sound file fits onto the disk. Only two values are changed.
In the second example the disk is larger, so the initial file fits it and no changes are required.
In the third example we have to change both 1s or both 3s. | instruction | 0 | 3,415 | 12 | 6,830 |
Tags: sortings, two pointers
Correct Solution:
```
from itertools import accumulate
# python template for atcoder1
import sys
sys.setrecursionlimit(10**9)
input = sys.stdin.readline
N, K = map(int, input().split())
A = list(map(int, input().split()))
A = sorted(A)
L = []
prev = -1
for a in A:
if a == prev:
L[-1] += 1
else:
L.append(1)
prev = a
max_types = int(2**((8*K)//N))
all_types = len(L)
del_types = all_types-max_types
if del_types <= 0:
ans = 0
else:
ans = float('inf')
sum_L = N
L_acc = [0]+list(accumulate(L))
for i in range(len(L)-max_types):
s = L_acc[i+max_types]-L_acc[i]
ans = min(ans, sum_L-s)
print(ans)
``` | output | 1 | 3,415 | 12 | 6,831 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ayush, Ashish and Vivek are busy preparing a new problem for the next Codeforces round and need help checking if their test cases are valid.
Each test case consists of an integer n and two arrays a and b, of size n. If after some (possibly zero) operations described below, array a can be transformed into array b, the input is said to be valid. Otherwise, it is invalid.
An operation on array a is:
* select an integer k (1 β€ k β€ βn/2β)
* swap the prefix of length k with the suffix of length k
For example, if array a initially is \{1, 2, 3, 4, 5, 6\}, after performing an operation with k = 2, it is transformed into \{5, 6, 3, 4, 1, 2\}.
Given the set of test cases, help them determine if each one is valid or invalid.
Input
The first line contains one integer t (1 β€ t β€ 500) β the number of test cases. The description of each test case is as follows.
The first line of each test case contains a single integer n (1 β€ n β€ 500) β the size of the arrays.
The second line of each test case contains n integers a_1, a_2, ..., a_n (1 β€ a_i β€ 10^9) β elements of array a.
The third line of each test case contains n integers b_1, b_2, ..., b_n (1 β€ b_i β€ 10^9) β elements of array b.
Output
For each test case, print "Yes" if the given input is valid. Otherwise print "No".
You may print the answer in any case.
Example
Input
5
2
1 2
2 1
3
1 2 3
1 2 3
3
1 2 4
1 3 4
4
1 2 3 2
3 1 2 2
3
1 2 3
1 3 2
Output
yes
yes
No
yes
No
Note
For the first test case, we can swap prefix a[1:1] with suffix a[2:2] to get a=[2, 1].
For the second test case, a is already equal to b.
For the third test case, it is impossible since we cannot obtain 3 in a.
For the fourth test case, we can first swap prefix a[1:1] with suffix a[4:4] to obtain a=[2, 2, 3, 1]. Now we can swap prefix a[1:2] with suffix a[3:4] to obtain a=[3, 1, 2, 2].
For the fifth test case, it is impossible to convert a to b. | instruction | 0 | 3,515 | 12 | 7,030 |
Tags: constructive algorithms, implementation, sortings
Correct Solution:
```
t = int(input())
for i in range(t):
l = int(input())
if l <= 1:
g = int(input())
f = int(input())
if g == f:
print('Yes')
else:
print('No')
else:
a = []
b = []
a = list(map(int, input().split()))
b = list(map(int, input().split()))
m = [[min(a[0], a[-1]), max(a[0], a[-1])]]
flag = 1
for i in range(1, l // 2):
m.append([min(a[i], a[l - i - 1]), max(a[i], a[l - i - 1])])
for i in range(l // 2):
test = [min(b[i], b[l - i - 1]), max(b[i], b[l - i - 1])]
flag = 0
for j in range(len(m)):
if test == m[j]:
flag = 1
del (m[j])
break
if flag == 0:
break
if flag:
if l % 2:
if a[l // 2] == b[l // 2]:
print('Yes')
else:
print('No')
else:
print('Yes')
else:
print('No')
``` | output | 1 | 3,515 | 12 | 7,031 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ayush, Ashish and Vivek are busy preparing a new problem for the next Codeforces round and need help checking if their test cases are valid.
Each test case consists of an integer n and two arrays a and b, of size n. If after some (possibly zero) operations described below, array a can be transformed into array b, the input is said to be valid. Otherwise, it is invalid.
An operation on array a is:
* select an integer k (1 β€ k β€ βn/2β)
* swap the prefix of length k with the suffix of length k
For example, if array a initially is \{1, 2, 3, 4, 5, 6\}, after performing an operation with k = 2, it is transformed into \{5, 6, 3, 4, 1, 2\}.
Given the set of test cases, help them determine if each one is valid or invalid.
Input
The first line contains one integer t (1 β€ t β€ 500) β the number of test cases. The description of each test case is as follows.
The first line of each test case contains a single integer n (1 β€ n β€ 500) β the size of the arrays.
The second line of each test case contains n integers a_1, a_2, ..., a_n (1 β€ a_i β€ 10^9) β elements of array a.
The third line of each test case contains n integers b_1, b_2, ..., b_n (1 β€ b_i β€ 10^9) β elements of array b.
Output
For each test case, print "Yes" if the given input is valid. Otherwise print "No".
You may print the answer in any case.
Example
Input
5
2
1 2
2 1
3
1 2 3
1 2 3
3
1 2 4
1 3 4
4
1 2 3 2
3 1 2 2
3
1 2 3
1 3 2
Output
yes
yes
No
yes
No
Note
For the first test case, we can swap prefix a[1:1] with suffix a[2:2] to get a=[2, 1].
For the second test case, a is already equal to b.
For the third test case, it is impossible since we cannot obtain 3 in a.
For the fourth test case, we can first swap prefix a[1:1] with suffix a[4:4] to obtain a=[2, 2, 3, 1]. Now we can swap prefix a[1:2] with suffix a[3:4] to obtain a=[3, 1, 2, 2].
For the fifth test case, it is impossible to convert a to b. | instruction | 0 | 3,516 | 12 | 7,032 |
Tags: constructive algorithms, implementation, sortings
Correct Solution:
```
t = int(input())
for _ in range(t):
n = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
works = True
if n % 2:
if a[n//2] != b[n//2]:
works = False
pairsA = []
for i in range(n//2):
f = a[i]
s = a[n - i - 1]
if f > s:
f, s = s, f
pairsA.append((f,s))
pairsB = []
for i in range(n//2):
f = b[i]
s = b[n - i - 1]
if f > s:
f, s = s, f
pairsB.append((f,s))
pairsA.sort()
pairsB.sort()
if works and pairsA == pairsB:
print('Yes')
else:
print('No')
``` | output | 1 | 3,516 | 12 | 7,033 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ayush, Ashish and Vivek are busy preparing a new problem for the next Codeforces round and need help checking if their test cases are valid.
Each test case consists of an integer n and two arrays a and b, of size n. If after some (possibly zero) operations described below, array a can be transformed into array b, the input is said to be valid. Otherwise, it is invalid.
An operation on array a is:
* select an integer k (1 β€ k β€ βn/2β)
* swap the prefix of length k with the suffix of length k
For example, if array a initially is \{1, 2, 3, 4, 5, 6\}, after performing an operation with k = 2, it is transformed into \{5, 6, 3, 4, 1, 2\}.
Given the set of test cases, help them determine if each one is valid or invalid.
Input
The first line contains one integer t (1 β€ t β€ 500) β the number of test cases. The description of each test case is as follows.
The first line of each test case contains a single integer n (1 β€ n β€ 500) β the size of the arrays.
The second line of each test case contains n integers a_1, a_2, ..., a_n (1 β€ a_i β€ 10^9) β elements of array a.
The third line of each test case contains n integers b_1, b_2, ..., b_n (1 β€ b_i β€ 10^9) β elements of array b.
Output
For each test case, print "Yes" if the given input is valid. Otherwise print "No".
You may print the answer in any case.
Example
Input
5
2
1 2
2 1
3
1 2 3
1 2 3
3
1 2 4
1 3 4
4
1 2 3 2
3 1 2 2
3
1 2 3
1 3 2
Output
yes
yes
No
yes
No
Note
For the first test case, we can swap prefix a[1:1] with suffix a[2:2] to get a=[2, 1].
For the second test case, a is already equal to b.
For the third test case, it is impossible since we cannot obtain 3 in a.
For the fourth test case, we can first swap prefix a[1:1] with suffix a[4:4] to obtain a=[2, 2, 3, 1]. Now we can swap prefix a[1:2] with suffix a[3:4] to obtain a=[3, 1, 2, 2].
For the fifth test case, it is impossible to convert a to b. | instruction | 0 | 3,517 | 12 | 7,034 |
Tags: constructive algorithms, implementation, sortings
Correct Solution:
```
import sys
input=sys.stdin.readline
t=int(input())
for _ in range(t):
n=int(input())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
x=sorted(zip(a,reversed(a)))
y=sorted(zip(b,reversed(b)))
if x==y:
print("Yes")
else:
print("No")
``` | output | 1 | 3,517 | 12 | 7,035 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ayush, Ashish and Vivek are busy preparing a new problem for the next Codeforces round and need help checking if their test cases are valid.
Each test case consists of an integer n and two arrays a and b, of size n. If after some (possibly zero) operations described below, array a can be transformed into array b, the input is said to be valid. Otherwise, it is invalid.
An operation on array a is:
* select an integer k (1 β€ k β€ βn/2β)
* swap the prefix of length k with the suffix of length k
For example, if array a initially is \{1, 2, 3, 4, 5, 6\}, after performing an operation with k = 2, it is transformed into \{5, 6, 3, 4, 1, 2\}.
Given the set of test cases, help them determine if each one is valid or invalid.
Input
The first line contains one integer t (1 β€ t β€ 500) β the number of test cases. The description of each test case is as follows.
The first line of each test case contains a single integer n (1 β€ n β€ 500) β the size of the arrays.
The second line of each test case contains n integers a_1, a_2, ..., a_n (1 β€ a_i β€ 10^9) β elements of array a.
The third line of each test case contains n integers b_1, b_2, ..., b_n (1 β€ b_i β€ 10^9) β elements of array b.
Output
For each test case, print "Yes" if the given input is valid. Otherwise print "No".
You may print the answer in any case.
Example
Input
5
2
1 2
2 1
3
1 2 3
1 2 3
3
1 2 4
1 3 4
4
1 2 3 2
3 1 2 2
3
1 2 3
1 3 2
Output
yes
yes
No
yes
No
Note
For the first test case, we can swap prefix a[1:1] with suffix a[2:2] to get a=[2, 1].
For the second test case, a is already equal to b.
For the third test case, it is impossible since we cannot obtain 3 in a.
For the fourth test case, we can first swap prefix a[1:1] with suffix a[4:4] to obtain a=[2, 2, 3, 1]. Now we can swap prefix a[1:2] with suffix a[3:4] to obtain a=[3, 1, 2, 2].
For the fifth test case, it is impossible to convert a to b. | instruction | 0 | 3,518 | 12 | 7,036 |
Tags: constructive algorithms, implementation, sortings
Correct Solution:
```
def solve(n,a,b,i):
if a[n//2]!=b[n//2] and n%2!=0:return 'NO'
seta=sorted([[a[i],a[n-1-i]] for i in range(n)]);setb=sorted([[b[i],b[n-i-1]] for i in range(n)])
for i in range(n):
if seta[i]!=setb[i]:return 'NO'
return 'YES'
for _ in range(int(input())):print(solve(int(input()),list(map(int,input().split())),list(map(int,input().split())),0))
``` | output | 1 | 3,518 | 12 | 7,037 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ayush, Ashish and Vivek are busy preparing a new problem for the next Codeforces round and need help checking if their test cases are valid.
Each test case consists of an integer n and two arrays a and b, of size n. If after some (possibly zero) operations described below, array a can be transformed into array b, the input is said to be valid. Otherwise, it is invalid.
An operation on array a is:
* select an integer k (1 β€ k β€ βn/2β)
* swap the prefix of length k with the suffix of length k
For example, if array a initially is \{1, 2, 3, 4, 5, 6\}, after performing an operation with k = 2, it is transformed into \{5, 6, 3, 4, 1, 2\}.
Given the set of test cases, help them determine if each one is valid or invalid.
Input
The first line contains one integer t (1 β€ t β€ 500) β the number of test cases. The description of each test case is as follows.
The first line of each test case contains a single integer n (1 β€ n β€ 500) β the size of the arrays.
The second line of each test case contains n integers a_1, a_2, ..., a_n (1 β€ a_i β€ 10^9) β elements of array a.
The third line of each test case contains n integers b_1, b_2, ..., b_n (1 β€ b_i β€ 10^9) β elements of array b.
Output
For each test case, print "Yes" if the given input is valid. Otherwise print "No".
You may print the answer in any case.
Example
Input
5
2
1 2
2 1
3
1 2 3
1 2 3
3
1 2 4
1 3 4
4
1 2 3 2
3 1 2 2
3
1 2 3
1 3 2
Output
yes
yes
No
yes
No
Note
For the first test case, we can swap prefix a[1:1] with suffix a[2:2] to get a=[2, 1].
For the second test case, a is already equal to b.
For the third test case, it is impossible since we cannot obtain 3 in a.
For the fourth test case, we can first swap prefix a[1:1] with suffix a[4:4] to obtain a=[2, 2, 3, 1]. Now we can swap prefix a[1:2] with suffix a[3:4] to obtain a=[3, 1, 2, 2].
For the fifth test case, it is impossible to convert a to b. | instruction | 0 | 3,519 | 12 | 7,038 |
Tags: constructive algorithms, implementation, sortings
Correct Solution:
```
import sys
input = sys.stdin.readline
import math
from collections import defaultdict
t=int(input())
for i in range(t):
n=int(input())
a=[int(i) for i in input().split() if i!='\n']
b=[int(i) for i in input().split() if i!='\n']
dict1,dict2=defaultdict(int),defaultdict(int)
freq1,freq2=defaultdict(int),defaultdict(int)
for j in range(math.ceil(n/2)):
dict1[(min(a[j],a[-j-1]),max(a[-j-1],a[j]))]+=1
dict2[(min(b[-j-1],b[j]),max(b[j],b[-j-1]))]+=1
for j in range(n):
freq1[a[j]]+=1
freq2[b[j]]+=1
#print(freq1,freq2)
ok=True
for j in dict1:
for k in j:
if freq1[k]!=freq2[k]:
ok=False
if j not in dict2:
ok=False
break
else:
if dict1[j]!=dict2[j]:
ok=False
break
if ok==True:
print('Yes')
else:
print('No')
``` | output | 1 | 3,519 | 12 | 7,039 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ayush, Ashish and Vivek are busy preparing a new problem for the next Codeforces round and need help checking if their test cases are valid.
Each test case consists of an integer n and two arrays a and b, of size n. If after some (possibly zero) operations described below, array a can be transformed into array b, the input is said to be valid. Otherwise, it is invalid.
An operation on array a is:
* select an integer k (1 β€ k β€ βn/2β)
* swap the prefix of length k with the suffix of length k
For example, if array a initially is \{1, 2, 3, 4, 5, 6\}, after performing an operation with k = 2, it is transformed into \{5, 6, 3, 4, 1, 2\}.
Given the set of test cases, help them determine if each one is valid or invalid.
Input
The first line contains one integer t (1 β€ t β€ 500) β the number of test cases. The description of each test case is as follows.
The first line of each test case contains a single integer n (1 β€ n β€ 500) β the size of the arrays.
The second line of each test case contains n integers a_1, a_2, ..., a_n (1 β€ a_i β€ 10^9) β elements of array a.
The third line of each test case contains n integers b_1, b_2, ..., b_n (1 β€ b_i β€ 10^9) β elements of array b.
Output
For each test case, print "Yes" if the given input is valid. Otherwise print "No".
You may print the answer in any case.
Example
Input
5
2
1 2
2 1
3
1 2 3
1 2 3
3
1 2 4
1 3 4
4
1 2 3 2
3 1 2 2
3
1 2 3
1 3 2
Output
yes
yes
No
yes
No
Note
For the first test case, we can swap prefix a[1:1] with suffix a[2:2] to get a=[2, 1].
For the second test case, a is already equal to b.
For the third test case, it is impossible since we cannot obtain 3 in a.
For the fourth test case, we can first swap prefix a[1:1] with suffix a[4:4] to obtain a=[2, 2, 3, 1]. Now we can swap prefix a[1:2] with suffix a[3:4] to obtain a=[3, 1, 2, 2].
For the fifth test case, it is impossible to convert a to b. | instruction | 0 | 3,520 | 12 | 7,040 |
Tags: constructive algorithms, implementation, sortings
Correct Solution:
```
t=int(input())
for _ in range(t):
q,f=lambda:list(map(int,input().split())),lambda x:sorted(zip(x,x[::-1]))
q(),print(['no','yes'][f(q())==f(q())])
``` | output | 1 | 3,520 | 12 | 7,041 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ayush, Ashish and Vivek are busy preparing a new problem for the next Codeforces round and need help checking if their test cases are valid.
Each test case consists of an integer n and two arrays a and b, of size n. If after some (possibly zero) operations described below, array a can be transformed into array b, the input is said to be valid. Otherwise, it is invalid.
An operation on array a is:
* select an integer k (1 β€ k β€ βn/2β)
* swap the prefix of length k with the suffix of length k
For example, if array a initially is \{1, 2, 3, 4, 5, 6\}, after performing an operation with k = 2, it is transformed into \{5, 6, 3, 4, 1, 2\}.
Given the set of test cases, help them determine if each one is valid or invalid.
Input
The first line contains one integer t (1 β€ t β€ 500) β the number of test cases. The description of each test case is as follows.
The first line of each test case contains a single integer n (1 β€ n β€ 500) β the size of the arrays.
The second line of each test case contains n integers a_1, a_2, ..., a_n (1 β€ a_i β€ 10^9) β elements of array a.
The third line of each test case contains n integers b_1, b_2, ..., b_n (1 β€ b_i β€ 10^9) β elements of array b.
Output
For each test case, print "Yes" if the given input is valid. Otherwise print "No".
You may print the answer in any case.
Example
Input
5
2
1 2
2 1
3
1 2 3
1 2 3
3
1 2 4
1 3 4
4
1 2 3 2
3 1 2 2
3
1 2 3
1 3 2
Output
yes
yes
No
yes
No
Note
For the first test case, we can swap prefix a[1:1] with suffix a[2:2] to get a=[2, 1].
For the second test case, a is already equal to b.
For the third test case, it is impossible since we cannot obtain 3 in a.
For the fourth test case, we can first swap prefix a[1:1] with suffix a[4:4] to obtain a=[2, 2, 3, 1]. Now we can swap prefix a[1:2] with suffix a[3:4] to obtain a=[3, 1, 2, 2].
For the fifth test case, it is impossible to convert a to b. | instruction | 0 | 3,521 | 12 | 7,042 |
Tags: constructive algorithms, implementation, sortings
Correct Solution:
```
for _ in range(int(input())):
n = int(input())
a = tuple(map(int, input().split()))
b = tuple(map(int, input().split()))
if sorted(zip(a, reversed(a))) == sorted(zip(b, reversed(b))):
print("Yes")
else:
print("No")
``` | output | 1 | 3,521 | 12 | 7,043 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ayush, Ashish and Vivek are busy preparing a new problem for the next Codeforces round and need help checking if their test cases are valid.
Each test case consists of an integer n and two arrays a and b, of size n. If after some (possibly zero) operations described below, array a can be transformed into array b, the input is said to be valid. Otherwise, it is invalid.
An operation on array a is:
* select an integer k (1 β€ k β€ βn/2β)
* swap the prefix of length k with the suffix of length k
For example, if array a initially is \{1, 2, 3, 4, 5, 6\}, after performing an operation with k = 2, it is transformed into \{5, 6, 3, 4, 1, 2\}.
Given the set of test cases, help them determine if each one is valid or invalid.
Input
The first line contains one integer t (1 β€ t β€ 500) β the number of test cases. The description of each test case is as follows.
The first line of each test case contains a single integer n (1 β€ n β€ 500) β the size of the arrays.
The second line of each test case contains n integers a_1, a_2, ..., a_n (1 β€ a_i β€ 10^9) β elements of array a.
The third line of each test case contains n integers b_1, b_2, ..., b_n (1 β€ b_i β€ 10^9) β elements of array b.
Output
For each test case, print "Yes" if the given input is valid. Otherwise print "No".
You may print the answer in any case.
Example
Input
5
2
1 2
2 1
3
1 2 3
1 2 3
3
1 2 4
1 3 4
4
1 2 3 2
3 1 2 2
3
1 2 3
1 3 2
Output
yes
yes
No
yes
No
Note
For the first test case, we can swap prefix a[1:1] with suffix a[2:2] to get a=[2, 1].
For the second test case, a is already equal to b.
For the third test case, it is impossible since we cannot obtain 3 in a.
For the fourth test case, we can first swap prefix a[1:1] with suffix a[4:4] to obtain a=[2, 2, 3, 1]. Now we can swap prefix a[1:2] with suffix a[3:4] to obtain a=[3, 1, 2, 2].
For the fifth test case, it is impossible to convert a to b. | instruction | 0 | 3,522 | 12 | 7,044 |
Tags: constructive algorithms, implementation, sortings
Correct Solution:
```
# by the authority of GOD author: manhar singh sachdev #
import os,sys
from io import BytesIO, IOBase
def solve(n,a,b):
if n%2:
if a[n//2]!=b[n//2]:
return 'NO'
ar1,ar2 = [],[]
for i in range(n//2):
ar1.append(sorted([a[i],a[-1-i]]))
ar2.append(sorted([b[i],b[-1-i]]))
if sorted(ar1) == sorted(ar2):
return 'YES'
else:
return 'NO'
def main():
for _ in range(int(input())):
n = int(input())
a = list(map(int,input().split()))
b = list(map(int,input().split()))
print(solve(n,a,b))
#Fast IO Region
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
if __name__ == '__main__':
main()
``` | output | 1 | 3,522 | 12 | 7,045 |
Provide tags and a correct Python 2 solution for this coding contest problem.
Ayush, Ashish and Vivek are busy preparing a new problem for the next Codeforces round and need help checking if their test cases are valid.
Each test case consists of an integer n and two arrays a and b, of size n. If after some (possibly zero) operations described below, array a can be transformed into array b, the input is said to be valid. Otherwise, it is invalid.
An operation on array a is:
* select an integer k (1 β€ k β€ βn/2β)
* swap the prefix of length k with the suffix of length k
For example, if array a initially is \{1, 2, 3, 4, 5, 6\}, after performing an operation with k = 2, it is transformed into \{5, 6, 3, 4, 1, 2\}.
Given the set of test cases, help them determine if each one is valid or invalid.
Input
The first line contains one integer t (1 β€ t β€ 500) β the number of test cases. The description of each test case is as follows.
The first line of each test case contains a single integer n (1 β€ n β€ 500) β the size of the arrays.
The second line of each test case contains n integers a_1, a_2, ..., a_n (1 β€ a_i β€ 10^9) β elements of array a.
The third line of each test case contains n integers b_1, b_2, ..., b_n (1 β€ b_i β€ 10^9) β elements of array b.
Output
For each test case, print "Yes" if the given input is valid. Otherwise print "No".
You may print the answer in any case.
Example
Input
5
2
1 2
2 1
3
1 2 3
1 2 3
3
1 2 4
1 3 4
4
1 2 3 2
3 1 2 2
3
1 2 3
1 3 2
Output
yes
yes
No
yes
No
Note
For the first test case, we can swap prefix a[1:1] with suffix a[2:2] to get a=[2, 1].
For the second test case, a is already equal to b.
For the third test case, it is impossible since we cannot obtain 3 in a.
For the fourth test case, we can first swap prefix a[1:1] with suffix a[4:4] to obtain a=[2, 2, 3, 1]. Now we can swap prefix a[1:2] with suffix a[3:4] to obtain a=[3, 1, 2, 2].
For the fifth test case, it is impossible to convert a to b. | instruction | 0 | 3,523 | 12 | 7,046 |
Tags: constructive algorithms, implementation, sortings
Correct Solution:
```
from sys import stdin, stdout
from collections import Counter, defaultdict
def ni():
return int(raw_input())
def li():
return list(map(int,raw_input().split()))
def pn(n):
stdout.write(str(n)+'\n')
def pa(arr):
pr(' '.join(map(str,arr))+'\n')
# fast read function for total integer input
def inp():
# this function returns whole input of
# space/line seperated integers
# Use Ctrl+D to flush stdin.
return (map(int,stdin.read().split()))
range = xrange # not for python 3.0+
"""
def fun(l):
ans=0
for i in l:
ans|=i
return ans
"""
# main code
for t in range(ni()):
n=ni()
l1=li()
l2=li()
a1=[]
a2=[]
for i in range(n/2):
a1.append((min(l1[i],l1[n-1-i]),max(l1[i],l1[n-1-i])))
a2.append((min(l2[i],l2[n-1-i]),max(l2[i],l2[n-1-i])))
a1.sort()
a2.sort()
f=0
if n%2 and (l1[n/2]!=l2[n/2]):
f=1
if f or a1!=a2:
stdout.write('No\n')
else:
stdout.write('Yes\n')
``` | output | 1 | 3,523 | 12 | 7,047 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ayush, Ashish and Vivek are busy preparing a new problem for the next Codeforces round and need help checking if their test cases are valid.
Each test case consists of an integer n and two arrays a and b, of size n. If after some (possibly zero) operations described below, array a can be transformed into array b, the input is said to be valid. Otherwise, it is invalid.
An operation on array a is:
* select an integer k (1 β€ k β€ βn/2β)
* swap the prefix of length k with the suffix of length k
For example, if array a initially is \{1, 2, 3, 4, 5, 6\}, after performing an operation with k = 2, it is transformed into \{5, 6, 3, 4, 1, 2\}.
Given the set of test cases, help them determine if each one is valid or invalid.
Input
The first line contains one integer t (1 β€ t β€ 500) β the number of test cases. The description of each test case is as follows.
The first line of each test case contains a single integer n (1 β€ n β€ 500) β the size of the arrays.
The second line of each test case contains n integers a_1, a_2, ..., a_n (1 β€ a_i β€ 10^9) β elements of array a.
The third line of each test case contains n integers b_1, b_2, ..., b_n (1 β€ b_i β€ 10^9) β elements of array b.
Output
For each test case, print "Yes" if the given input is valid. Otherwise print "No".
You may print the answer in any case.
Example
Input
5
2
1 2
2 1
3
1 2 3
1 2 3
3
1 2 4
1 3 4
4
1 2 3 2
3 1 2 2
3
1 2 3
1 3 2
Output
yes
yes
No
yes
No
Note
For the first test case, we can swap prefix a[1:1] with suffix a[2:2] to get a=[2, 1].
For the second test case, a is already equal to b.
For the third test case, it is impossible since we cannot obtain 3 in a.
For the fourth test case, we can first swap prefix a[1:1] with suffix a[4:4] to obtain a=[2, 2, 3, 1]. Now we can swap prefix a[1:2] with suffix a[3:4] to obtain a=[3, 1, 2, 2].
For the fifth test case, it is impossible to convert a to b.
Submitted Solution:
```
import os
import sys
from io import BytesIO, IOBase
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
# ------------------------------
from math import factorial, ceil
from collections import Counter, defaultdict, deque
from heapq import heapify, heappop, heappush
def RL(): return map(int, sys.stdin.readline().rstrip().split())
def RLL(): return list(map(int, sys.stdin.readline().rstrip().split()))
def N(): return int(input())
def comb(n, m): return factorial(n) / (factorial(m) * factorial(n - m)) if n >= m else 0
def perm(n, m): return factorial(n) // (factorial(n - m)) if n >= m else 0
def mdis(x1, y1, x2, y2): return abs(x1 - x2) + abs(y1 - y2)
mod = 998244353
INF = float('inf')
# ------------------------------
def main():
for _ in range(N()):
n = N()
arra = RLL()
arrb = RLL()
ca = Counter(arra)
cb = Counter(arrb)
if (n%2==1 and arra[n//2]!=arrb[n//2]) or ca!=cb:
print("No")
else:
reca = []
recb = []
for i in range(ceil(n/2)):
pa = sorted([arra[i], arra[n-1-i]])
pb = sorted([arrb[i], arrb[n-1-i]])
reca.append(pa)
recb.append(pb)
# print(reca)
# print(recb)
print('yes' if sorted(reca)==sorted(recb) else 'No')
if __name__ == "__main__":
main()
``` | instruction | 0 | 3,524 | 12 | 7,048 |
Yes | output | 1 | 3,524 | 12 | 7,049 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ayush, Ashish and Vivek are busy preparing a new problem for the next Codeforces round and need help checking if their test cases are valid.
Each test case consists of an integer n and two arrays a and b, of size n. If after some (possibly zero) operations described below, array a can be transformed into array b, the input is said to be valid. Otherwise, it is invalid.
An operation on array a is:
* select an integer k (1 β€ k β€ βn/2β)
* swap the prefix of length k with the suffix of length k
For example, if array a initially is \{1, 2, 3, 4, 5, 6\}, after performing an operation with k = 2, it is transformed into \{5, 6, 3, 4, 1, 2\}.
Given the set of test cases, help them determine if each one is valid or invalid.
Input
The first line contains one integer t (1 β€ t β€ 500) β the number of test cases. The description of each test case is as follows.
The first line of each test case contains a single integer n (1 β€ n β€ 500) β the size of the arrays.
The second line of each test case contains n integers a_1, a_2, ..., a_n (1 β€ a_i β€ 10^9) β elements of array a.
The third line of each test case contains n integers b_1, b_2, ..., b_n (1 β€ b_i β€ 10^9) β elements of array b.
Output
For each test case, print "Yes" if the given input is valid. Otherwise print "No".
You may print the answer in any case.
Example
Input
5
2
1 2
2 1
3
1 2 3
1 2 3
3
1 2 4
1 3 4
4
1 2 3 2
3 1 2 2
3
1 2 3
1 3 2
Output
yes
yes
No
yes
No
Note
For the first test case, we can swap prefix a[1:1] with suffix a[2:2] to get a=[2, 1].
For the second test case, a is already equal to b.
For the third test case, it is impossible since we cannot obtain 3 in a.
For the fourth test case, we can first swap prefix a[1:1] with suffix a[4:4] to obtain a=[2, 2, 3, 1]. Now we can swap prefix a[1:2] with suffix a[3:4] to obtain a=[3, 1, 2, 2].
For the fifth test case, it is impossible to convert a to b.
Submitted Solution:
```
import sys
INF = 10**20
MOD = 10**9 + 7
I = lambda:list(map(int,input().split()))
from math import gcd
from math import ceil
from collections import defaultdict as dd, Counter
from bisect import bisect_left as bl, bisect_right as br
def solve():
n, = I()
a = I()
b = I()
if n % 2 and a[n // 2] != b[n // 2]:
print('No')
return
pairs = dd(int)
bpair = dd(int)
for i in range(n // 2):
x, y = a[i], a[n - i - 1]
if x > y:
x, y = y, x
pairs[(x, y)] += 1
x, y = b[i], b[n - i - 1]
if x > y:
x, y = y, x
bpair[(x, y)] += 1
for i in pairs:
if pairs[i] != bpair[i]:
print('No')
return
print('Yes')
t, = I()
while t:
t -= 1
solve()
``` | instruction | 0 | 3,525 | 12 | 7,050 |
Yes | output | 1 | 3,525 | 12 | 7,051 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ayush, Ashish and Vivek are busy preparing a new problem for the next Codeforces round and need help checking if their test cases are valid.
Each test case consists of an integer n and two arrays a and b, of size n. If after some (possibly zero) operations described below, array a can be transformed into array b, the input is said to be valid. Otherwise, it is invalid.
An operation on array a is:
* select an integer k (1 β€ k β€ βn/2β)
* swap the prefix of length k with the suffix of length k
For example, if array a initially is \{1, 2, 3, 4, 5, 6\}, after performing an operation with k = 2, it is transformed into \{5, 6, 3, 4, 1, 2\}.
Given the set of test cases, help them determine if each one is valid or invalid.
Input
The first line contains one integer t (1 β€ t β€ 500) β the number of test cases. The description of each test case is as follows.
The first line of each test case contains a single integer n (1 β€ n β€ 500) β the size of the arrays.
The second line of each test case contains n integers a_1, a_2, ..., a_n (1 β€ a_i β€ 10^9) β elements of array a.
The third line of each test case contains n integers b_1, b_2, ..., b_n (1 β€ b_i β€ 10^9) β elements of array b.
Output
For each test case, print "Yes" if the given input is valid. Otherwise print "No".
You may print the answer in any case.
Example
Input
5
2
1 2
2 1
3
1 2 3
1 2 3
3
1 2 4
1 3 4
4
1 2 3 2
3 1 2 2
3
1 2 3
1 3 2
Output
yes
yes
No
yes
No
Note
For the first test case, we can swap prefix a[1:1] with suffix a[2:2] to get a=[2, 1].
For the second test case, a is already equal to b.
For the third test case, it is impossible since we cannot obtain 3 in a.
For the fourth test case, we can first swap prefix a[1:1] with suffix a[4:4] to obtain a=[2, 2, 3, 1]. Now we can swap prefix a[1:2] with suffix a[3:4] to obtain a=[3, 1, 2, 2].
For the fifth test case, it is impossible to convert a to b.
Submitted Solution:
```
t = int(input())
for _ in range(t):
n = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
paira = []
for i in range((n+1)//2):
paira.append(tuple(sorted([a[i], a[~i]])))
pairb = []
for i in range((n+1)//2):
pairb.append(tuple(sorted([b[i], b[~i]])))
paira.sort()
pairb.sort()
if paira == pairb:
print("Yes")
else:
print("No")
``` | instruction | 0 | 3,526 | 12 | 7,052 |
Yes | output | 1 | 3,526 | 12 | 7,053 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ayush, Ashish and Vivek are busy preparing a new problem for the next Codeforces round and need help checking if their test cases are valid.
Each test case consists of an integer n and two arrays a and b, of size n. If after some (possibly zero) operations described below, array a can be transformed into array b, the input is said to be valid. Otherwise, it is invalid.
An operation on array a is:
* select an integer k (1 β€ k β€ βn/2β)
* swap the prefix of length k with the suffix of length k
For example, if array a initially is \{1, 2, 3, 4, 5, 6\}, after performing an operation with k = 2, it is transformed into \{5, 6, 3, 4, 1, 2\}.
Given the set of test cases, help them determine if each one is valid or invalid.
Input
The first line contains one integer t (1 β€ t β€ 500) β the number of test cases. The description of each test case is as follows.
The first line of each test case contains a single integer n (1 β€ n β€ 500) β the size of the arrays.
The second line of each test case contains n integers a_1, a_2, ..., a_n (1 β€ a_i β€ 10^9) β elements of array a.
The third line of each test case contains n integers b_1, b_2, ..., b_n (1 β€ b_i β€ 10^9) β elements of array b.
Output
For each test case, print "Yes" if the given input is valid. Otherwise print "No".
You may print the answer in any case.
Example
Input
5
2
1 2
2 1
3
1 2 3
1 2 3
3
1 2 4
1 3 4
4
1 2 3 2
3 1 2 2
3
1 2 3
1 3 2
Output
yes
yes
No
yes
No
Note
For the first test case, we can swap prefix a[1:1] with suffix a[2:2] to get a=[2, 1].
For the second test case, a is already equal to b.
For the third test case, it is impossible since we cannot obtain 3 in a.
For the fourth test case, we can first swap prefix a[1:1] with suffix a[4:4] to obtain a=[2, 2, 3, 1]. Now we can swap prefix a[1:2] with suffix a[3:4] to obtain a=[3, 1, 2, 2].
For the fifth test case, it is impossible to convert a to b.
Submitted Solution:
```
# from math import factorial as fac
from collections import defaultdict
# from copy import deepcopy
import sys, math
f = None
try:
f = open('q1.input', 'r')
except IOError:
f = sys.stdin
if 'xrange' in dir(__builtins__):
range = xrange
# print(f.readline())
sys.setrecursionlimit(10**2)
def print_case_iterable(case_num, iterable):
print("Case #{}: {}".format(case_num," ".join(map(str,iterable))))
def print_case_number(case_num, iterable):
print("Case #{}: {}".format(case_num,iterable))
def print_iterable(A):
print (' '.join(A))
def read_int():
return int(f.readline().strip())
def read_int_array():
return [int(x) for x in f.readline().strip().split(" ")]
def rns():
a = [x for x in f.readline().split(" ")]
return int(a[0]), a[1].strip()
def read_string():
return list(f.readline().strip())
def ri():
return int(f.readline().strip())
def ria():
return [int(x) for x in f.readline().strip().split(" ")]
def rns():
a = [x for x in f.readline().split(" ")]
return int(a[0]), a[1].strip()
def rs():
return list(f.readline().strip())
def bi(x):
return bin(x)[2:]
from collections import deque
import math
NUMBER = 10**9 + 7
# NUMBER = 998244353
def factorial(n) :
M = NUMBER
f = 1
for i in range(1, n + 1):
f = (f * i) % M # Now f never can
# exceed 10^9+7
return f
def mult(a,b):
return (a * b) % NUMBER
def minus(a , b):
return (a - b) % NUMBER
def plus(a , b):
return (a + b) % NUMBER
def egcd(a, b):
if a == 0:
return (b, 0, 1)
else:
g, y, x = egcd(b % a, a)
return (g, x - (b // a) * y, y)
def modinv(a):
m = NUMBER
g, x, y = egcd(a, m)
if g != 1:
raise Exception('modular inverse does not exist')
else:
return x % m
def choose(n,k):
if n < k:
assert false
return mult(factorial(n), modinv(mult(factorial(k),factorial(n-k))))
from collections import deque, defaultdict
import heapq
def solution(a,b,n):
da = defaultdict(int)
db = defaultdict(int)
for i in range(n//2):
da[frozenset([a[i], a[n-1-i]])]+=1
db[frozenset([b[i], b[n-1-i]])]+=1
if n % 2:
if a[n//2] != b[n//2]:
return "No"
for x in da:
if db[x] != da[x]:
return "No"
return "Yes"
def main():
T = ri()
for i in range(T):
n = ri()
a = ria()
b = ria()
x = solution(a,b,n)
if 'xrange' not in dir(__builtins__):
print(x)
else:
print >>output,str(x)# "Case #"+str(i+1)+':',
if 'xrange' in dir(__builtins__):
print(output.getvalue())
output.close()
if 'xrange' in dir(__builtins__):
import cStringIO
output = cStringIO.StringIO()
#example usage:
# for l in res:
# print >>output, str(len(l)) + ' ' + ' '.join(l)
if __name__ == '__main__':
main()
``` | instruction | 0 | 3,527 | 12 | 7,054 |
Yes | output | 1 | 3,527 | 12 | 7,055 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ayush, Ashish and Vivek are busy preparing a new problem for the next Codeforces round and need help checking if their test cases are valid.
Each test case consists of an integer n and two arrays a and b, of size n. If after some (possibly zero) operations described below, array a can be transformed into array b, the input is said to be valid. Otherwise, it is invalid.
An operation on array a is:
* select an integer k (1 β€ k β€ βn/2β)
* swap the prefix of length k with the suffix of length k
For example, if array a initially is \{1, 2, 3, 4, 5, 6\}, after performing an operation with k = 2, it is transformed into \{5, 6, 3, 4, 1, 2\}.
Given the set of test cases, help them determine if each one is valid or invalid.
Input
The first line contains one integer t (1 β€ t β€ 500) β the number of test cases. The description of each test case is as follows.
The first line of each test case contains a single integer n (1 β€ n β€ 500) β the size of the arrays.
The second line of each test case contains n integers a_1, a_2, ..., a_n (1 β€ a_i β€ 10^9) β elements of array a.
The third line of each test case contains n integers b_1, b_2, ..., b_n (1 β€ b_i β€ 10^9) β elements of array b.
Output
For each test case, print "Yes" if the given input is valid. Otherwise print "No".
You may print the answer in any case.
Example
Input
5
2
1 2
2 1
3
1 2 3
1 2 3
3
1 2 4
1 3 4
4
1 2 3 2
3 1 2 2
3
1 2 3
1 3 2
Output
yes
yes
No
yes
No
Note
For the first test case, we can swap prefix a[1:1] with suffix a[2:2] to get a=[2, 1].
For the second test case, a is already equal to b.
For the third test case, it is impossible since we cannot obtain 3 in a.
For the fourth test case, we can first swap prefix a[1:1] with suffix a[4:4] to obtain a=[2, 2, 3, 1]. Now we can swap prefix a[1:2] with suffix a[3:4] to obtain a=[3, 1, 2, 2].
For the fifth test case, it is impossible to convert a to b.
Submitted Solution:
```
# your code goes here
from collections import defaultdict
t = int(input())
for _ in range(t):
n = int(input())
a = list(map(int,input().split()))
b = list(map(int,input().split()))
possible = 1
pairs = defaultdict(int)
if n%2 == 1 and a[n//2] != b[n//2]:
possible = 0
for i in range(n//2):
x,y = min(a[i],a[n-i-1]),max(a[i],a[n-i-1])
pairs[(x,y)] += 1
for j in range(n//2):
x,y = min(a[j],a[n-j-1]),max(a[j],a[n-j-1])
if pairs[(x,y)] <= 0:
possible = 0
pairs[(x,y)] -= 1
print("yes") if possible else print("No")
``` | instruction | 0 | 3,528 | 12 | 7,056 |
No | output | 1 | 3,528 | 12 | 7,057 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ayush, Ashish and Vivek are busy preparing a new problem for the next Codeforces round and need help checking if their test cases are valid.
Each test case consists of an integer n and two arrays a and b, of size n. If after some (possibly zero) operations described below, array a can be transformed into array b, the input is said to be valid. Otherwise, it is invalid.
An operation on array a is:
* select an integer k (1 β€ k β€ βn/2β)
* swap the prefix of length k with the suffix of length k
For example, if array a initially is \{1, 2, 3, 4, 5, 6\}, after performing an operation with k = 2, it is transformed into \{5, 6, 3, 4, 1, 2\}.
Given the set of test cases, help them determine if each one is valid or invalid.
Input
The first line contains one integer t (1 β€ t β€ 500) β the number of test cases. The description of each test case is as follows.
The first line of each test case contains a single integer n (1 β€ n β€ 500) β the size of the arrays.
The second line of each test case contains n integers a_1, a_2, ..., a_n (1 β€ a_i β€ 10^9) β elements of array a.
The third line of each test case contains n integers b_1, b_2, ..., b_n (1 β€ b_i β€ 10^9) β elements of array b.
Output
For each test case, print "Yes" if the given input is valid. Otherwise print "No".
You may print the answer in any case.
Example
Input
5
2
1 2
2 1
3
1 2 3
1 2 3
3
1 2 4
1 3 4
4
1 2 3 2
3 1 2 2
3
1 2 3
1 3 2
Output
yes
yes
No
yes
No
Note
For the first test case, we can swap prefix a[1:1] with suffix a[2:2] to get a=[2, 1].
For the second test case, a is already equal to b.
For the third test case, it is impossible since we cannot obtain 3 in a.
For the fourth test case, we can first swap prefix a[1:1] with suffix a[4:4] to obtain a=[2, 2, 3, 1]. Now we can swap prefix a[1:2] with suffix a[3:4] to obtain a=[3, 1, 2, 2].
For the fifth test case, it is impossible to convert a to b.
Submitted Solution:
```
import sys, os, io
def rs(): return sys.stdin.readline().rstrip()
def ri(): return int(sys.stdin.readline())
def ria(): return list(map(int, sys.stdin.readline().split()))
def ws(s): sys.stdout.write(s + '\n')
def wi(n): sys.stdout.write(str(n) + '\n')
def wia(a): sys.stdout.write(' '.join([str(x) for x in a]) + '\n')
from collections import Counter
def solve(n, a, b):
ca = Counter(a)
cb = Counter(b)
return ca == cb and (n % 2 == 0 or n % 2 == 1 and a[n//2] == b[n//2])
def main():
for _ in range(ri()):
n = ri()
a = ria()
b = ria()
ws('Yes' if solve(n, a, b) else 'No')
if __name__ == '__main__':
main()
``` | instruction | 0 | 3,529 | 12 | 7,058 |
No | output | 1 | 3,529 | 12 | 7,059 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ayush, Ashish and Vivek are busy preparing a new problem for the next Codeforces round and need help checking if their test cases are valid.
Each test case consists of an integer n and two arrays a and b, of size n. If after some (possibly zero) operations described below, array a can be transformed into array b, the input is said to be valid. Otherwise, it is invalid.
An operation on array a is:
* select an integer k (1 β€ k β€ βn/2β)
* swap the prefix of length k with the suffix of length k
For example, if array a initially is \{1, 2, 3, 4, 5, 6\}, after performing an operation with k = 2, it is transformed into \{5, 6, 3, 4, 1, 2\}.
Given the set of test cases, help them determine if each one is valid or invalid.
Input
The first line contains one integer t (1 β€ t β€ 500) β the number of test cases. The description of each test case is as follows.
The first line of each test case contains a single integer n (1 β€ n β€ 500) β the size of the arrays.
The second line of each test case contains n integers a_1, a_2, ..., a_n (1 β€ a_i β€ 10^9) β elements of array a.
The third line of each test case contains n integers b_1, b_2, ..., b_n (1 β€ b_i β€ 10^9) β elements of array b.
Output
For each test case, print "Yes" if the given input is valid. Otherwise print "No".
You may print the answer in any case.
Example
Input
5
2
1 2
2 1
3
1 2 3
1 2 3
3
1 2 4
1 3 4
4
1 2 3 2
3 1 2 2
3
1 2 3
1 3 2
Output
yes
yes
No
yes
No
Note
For the first test case, we can swap prefix a[1:1] with suffix a[2:2] to get a=[2, 1].
For the second test case, a is already equal to b.
For the third test case, it is impossible since we cannot obtain 3 in a.
For the fourth test case, we can first swap prefix a[1:1] with suffix a[4:4] to obtain a=[2, 2, 3, 1]. Now we can swap prefix a[1:2] with suffix a[3:4] to obtain a=[3, 1, 2, 2].
For the fifth test case, it is impossible to convert a to b.
Submitted Solution:
```
for _ in range(int(input())):
n = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
if sorted(a) != sorted(b):
print('NO')
continue
c = {}
for i in range(n):
if a[i] not in c:
c[a[i]] = [a[n - i - 1]]
else:
c[a[i]] += [a[n - i - 1]]
if a[n - i - 1] not in c:
c[a[n - i - 1]] = [a[i]]
else:
c[a[n - i - 1]] += [a[i]]
for i in range(n):
if b[n - i - 1] not in c[b[i]]:
print('NO')
break
else:
print('YES')
``` | instruction | 0 | 3,530 | 12 | 7,060 |
No | output | 1 | 3,530 | 12 | 7,061 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ayush, Ashish and Vivek are busy preparing a new problem for the next Codeforces round and need help checking if their test cases are valid.
Each test case consists of an integer n and two arrays a and b, of size n. If after some (possibly zero) operations described below, array a can be transformed into array b, the input is said to be valid. Otherwise, it is invalid.
An operation on array a is:
* select an integer k (1 β€ k β€ βn/2β)
* swap the prefix of length k with the suffix of length k
For example, if array a initially is \{1, 2, 3, 4, 5, 6\}, after performing an operation with k = 2, it is transformed into \{5, 6, 3, 4, 1, 2\}.
Given the set of test cases, help them determine if each one is valid or invalid.
Input
The first line contains one integer t (1 β€ t β€ 500) β the number of test cases. The description of each test case is as follows.
The first line of each test case contains a single integer n (1 β€ n β€ 500) β the size of the arrays.
The second line of each test case contains n integers a_1, a_2, ..., a_n (1 β€ a_i β€ 10^9) β elements of array a.
The third line of each test case contains n integers b_1, b_2, ..., b_n (1 β€ b_i β€ 10^9) β elements of array b.
Output
For each test case, print "Yes" if the given input is valid. Otherwise print "No".
You may print the answer in any case.
Example
Input
5
2
1 2
2 1
3
1 2 3
1 2 3
3
1 2 4
1 3 4
4
1 2 3 2
3 1 2 2
3
1 2 3
1 3 2
Output
yes
yes
No
yes
No
Note
For the first test case, we can swap prefix a[1:1] with suffix a[2:2] to get a=[2, 1].
For the second test case, a is already equal to b.
For the third test case, it is impossible since we cannot obtain 3 in a.
For the fourth test case, we can first swap prefix a[1:1] with suffix a[4:4] to obtain a=[2, 2, 3, 1]. Now we can swap prefix a[1:2] with suffix a[3:4] to obtain a=[3, 1, 2, 2].
For the fifth test case, it is impossible to convert a to b.
Submitted Solution:
```
import sys
import string
import math
import bisect as bi
from collections import defaultdict as dd
input=sys.stdin.readline
def cin():
return map(int,sin().split())
def ain():
return list(map(int,sin().split()))
def sin():
return input()
def inin():
return int(input())
def pref(a,n):
pre=[0]*n
pre[0]=a[0]
for i in range(1,n):
pre[i]=a[i]+pre[i-1]
return pre
##dp1=[1]*100
##dp1[0]=2
##for i in range(1,100):
## dp1[i]=dp1[i-1]*2
##pre=pref(dp1,100)
for i in range(inin()):
n=inin()
a=ain()
b=ain()
if(a==b):
print('yes')
elif(sorted(a)==sorted(b)):
if(n%2==1 and a[n//2]!=b[n//2]):
print('no')
else:
l=[]
l1=[]
for i in range(n//2):
l+=(max(a[i],a[n-i-1]),min(a[i],a[n-i-1]))
l1+=(max(b[i],b[n-i-1]),min(b[i],b[n-i-1]))
l.sort()
l1.sort()
if(l==l1):
print('yes')
else:
print('no')
else:
print('no')
``` | instruction | 0 | 3,531 | 12 | 7,062 |
No | output | 1 | 3,531 | 12 | 7,063 |
Evaluate the correctness of the submitted Python 2 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ayush, Ashish and Vivek are busy preparing a new problem for the next Codeforces round and need help checking if their test cases are valid.
Each test case consists of an integer n and two arrays a and b, of size n. If after some (possibly zero) operations described below, array a can be transformed into array b, the input is said to be valid. Otherwise, it is invalid.
An operation on array a is:
* select an integer k (1 β€ k β€ βn/2β)
* swap the prefix of length k with the suffix of length k
For example, if array a initially is \{1, 2, 3, 4, 5, 6\}, after performing an operation with k = 2, it is transformed into \{5, 6, 3, 4, 1, 2\}.
Given the set of test cases, help them determine if each one is valid or invalid.
Input
The first line contains one integer t (1 β€ t β€ 500) β the number of test cases. The description of each test case is as follows.
The first line of each test case contains a single integer n (1 β€ n β€ 500) β the size of the arrays.
The second line of each test case contains n integers a_1, a_2, ..., a_n (1 β€ a_i β€ 10^9) β elements of array a.
The third line of each test case contains n integers b_1, b_2, ..., b_n (1 β€ b_i β€ 10^9) β elements of array b.
Output
For each test case, print "Yes" if the given input is valid. Otherwise print "No".
You may print the answer in any case.
Example
Input
5
2
1 2
2 1
3
1 2 3
1 2 3
3
1 2 4
1 3 4
4
1 2 3 2
3 1 2 2
3
1 2 3
1 3 2
Output
yes
yes
No
yes
No
Note
For the first test case, we can swap prefix a[1:1] with suffix a[2:2] to get a=[2, 1].
For the second test case, a is already equal to b.
For the third test case, it is impossible since we cannot obtain 3 in a.
For the fourth test case, we can first swap prefix a[1:1] with suffix a[4:4] to obtain a=[2, 2, 3, 1]. Now we can swap prefix a[1:2] with suffix a[3:4] to obtain a=[3, 1, 2, 2].
For the fifth test case, it is impossible to convert a to b.
Submitted Solution:
```
from sys import stdin, stdout
from collections import Counter, defaultdict
def ni():
return int(raw_input())
def li():
return list(map(int,raw_input().split()))
def pn(n):
stdout.write(str(n)+'\n')
def pa(arr):
pr(' '.join(map(str,arr))+'\n')
# fast read function for total integer input
def inp():
# this function returns whole input of
# space/line seperated integers
# Use Ctrl+D to flush stdin.
return (map(int,stdin.read().split()))
range = xrange # not for python 3.0+
"""
def fun(l):
ans=0
for i in l:
ans|=i
return ans
"""
# main code
for t in range(ni()):
n=ni()
l1=li()
l2=li()
d=Counter()
for i in range(n/2):
d[l1[i]]=l1[n-1-i]
d[l1[n-1-i]]=l1[i]
f=0
for i in range(n/2):
if d[l2[i]]!=l2[n-1-i] or d[l2[n-1-i]]!=l2[i]:
f=1
break
if n%2:
if l1[(n/2)]!=l2[(n/2)]:
f=1
if f:
stdout.write('No\n')
else:
stdout.write('Yes\n')
``` | instruction | 0 | 3,532 | 12 | 7,064 |
No | output | 1 | 3,532 | 12 | 7,065 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a permutation a consisting of n numbers 1, 2, ..., n (a permutation is an array in which each element from 1 to n occurs exactly once).
You can perform the following operation: choose some subarray (contiguous subsegment) of a and rearrange the elements in it in any way you want. But this operation cannot be applied to the whole array.
For example, if a = [2, 1, 4, 5, 3] and we want to apply the operation to the subarray a[2, 4] (the subarray containing all elements from the 2-nd to the 4-th), then after the operation, the array can become a = [2, 5, 1, 4, 3] or, for example, a = [2, 1, 5, 4, 3].
Your task is to calculate the minimum number of operations described above to sort the permutation a in ascending order.
Input
The first line contains a single integer t (1 β€ t β€ 2000) β the number of test cases.
The first line of the test case contains a single integer n (3 β€ n β€ 50) β the number of elements in the permutation.
The second line of the test case contains n distinct integers from 1 to n β the given permutation a.
Output
For each test case, output a single integer β the minimum number of operations described above to sort the array a in ascending order.
Example
Input
3
4
1 3 2 4
3
1 2 3
5
2 1 4 5 3
Output
1
0
2
Note
In the explanations, a[i, j] defines the subarray of a that starts from the i-th element and ends with the j-th element.
In the first test case of the example, you can select the subarray a[2, 3] and swap the elements in it.
In the second test case of the example, the permutation is already sorted, so you don't need to apply any operations.
In the third test case of the example, you can select the subarray a[3, 5] and reorder the elements in it so a becomes [2, 1, 3, 4, 5], and then select the subarray a[1, 2] and swap the elements in it, so a becomes [1, 2, 3, 4, 5]. | instruction | 0 | 3,619 | 12 | 7,238 |
Tags: constructive algorithms, greedy
Correct Solution:
```
for t in range(int(input())):
N = int(input())
arr = list(map(int,input().split()))
if arr == sorted(arr):
print(0)
elif arr[0] == 1 or arr[-1] == N:
print(1)
elif arr[0] == N and arr[-1] == 1:
print(3)
else:
print(2)
``` | output | 1 | 3,619 | 12 | 7,239 |
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