message stringlengths 2 433k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 113 108k | cluster float64 12 12 | __index_level_0__ int64 226 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has the sequence consisting of n integers. Vasya consider the pair of integers x and y k-interesting, if their binary representation differs from each other exactly in k bits. For example, if k = 2, the pair of integers x = 5 and y = 3 is k-interesting, because their binary representation x=101 and y=011 differs exactly in two bits.
Vasya wants to know how many pairs of indexes (i, j) are in his sequence so that i < j and the pair of integers ai and aj is k-interesting. Your task is to help Vasya and determine this number.
Input
The first line contains two integers n and k (2 β€ n β€ 105, 0 β€ k β€ 14) β the number of integers in Vasya's sequence and the number of bits in which integers in k-interesting pair should differ.
The second line contains the sequence a1, a2, ..., an (0 β€ ai β€ 104), which Vasya has.
Output
Print the number of pairs (i, j) so that i < j and the pair of integers ai and aj is k-interesting.
Examples
Input
4 1
0 3 2 1
Output
4
Input
6 0
200 100 100 100 200 200
Output
6
Note
In the first test there are 4 k-interesting pairs:
* (1, 3),
* (1, 4),
* (2, 3),
* (2, 4).
In the second test k = 0. Consequently, integers in any k-interesting pair should be equal to themselves. Thus, for the second test there are 6 k-interesting pairs:
* (1, 5),
* (1, 6),
* (2, 3),
* (2, 4),
* (3, 4),
* (5, 6).
Submitted Solution:
```
n,k=map(int, input().split())
a_list=list(map(lambda x: '{0:06b}'.format(int(x)), input().split()))
def looping():
counter=0
for x in range(n):
for y in range(x+1,n):
if sum(1 for a, b in zip(a_list[x],a_list[y]) if a != b) == k: counter+=1
return counter
print(looping())
``` | instruction | 0 | 33,910 | 12 | 67,820 |
No | output | 1 | 33,910 | 12 | 67,821 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has the sequence consisting of n integers. Vasya consider the pair of integers x and y k-interesting, if their binary representation differs from each other exactly in k bits. For example, if k = 2, the pair of integers x = 5 and y = 3 is k-interesting, because their binary representation x=101 and y=011 differs exactly in two bits.
Vasya wants to know how many pairs of indexes (i, j) are in his sequence so that i < j and the pair of integers ai and aj is k-interesting. Your task is to help Vasya and determine this number.
Input
The first line contains two integers n and k (2 β€ n β€ 105, 0 β€ k β€ 14) β the number of integers in Vasya's sequence and the number of bits in which integers in k-interesting pair should differ.
The second line contains the sequence a1, a2, ..., an (0 β€ ai β€ 104), which Vasya has.
Output
Print the number of pairs (i, j) so that i < j and the pair of integers ai and aj is k-interesting.
Examples
Input
4 1
0 3 2 1
Output
4
Input
6 0
200 100 100 100 200 200
Output
6
Note
In the first test there are 4 k-interesting pairs:
* (1, 3),
* (1, 4),
* (2, 3),
* (2, 4).
In the second test k = 0. Consequently, integers in any k-interesting pair should be equal to themselves. Thus, for the second test there are 6 k-interesting pairs:
* (1, 5),
* (1, 6),
* (2, 3),
* (2, 4),
* (3, 4),
* (5, 6).
Submitted Solution:
```
'''
ΠΡΠΎΡ ΠΊΠΎΠ΄ ΠΏΠΎΡΠ²ΡΡΠ°Π΅ΡΡΡ ΡΠ°ΠΌΠΎΠΉ ΠΊΡΠ°ΡΠΈΠ²ΠΎΠΉ Π΄Π΅Π²ΡΡΠΊΠ΅,
Π‘ΠΈΠ½ΠΈΡΡΠ½ΠΎΠΉ ΠΠ»Π΅
'''
n,k=list(map(int,input().split()))
line=list(map(int,input().split()))
d={}
a=0
l=0
for num in line:
d[num]=d.get(bin(num),0)+1
avaliable=list(d.keys())
l=len(avaliable)
for i in range(l-1):
for j in range(i+1,l):
if bin(avaliable[i]^avaliable[j]).count('1')==k:
a+=(d[avaliable[i]]*d[avaliable[j]])
print(a)
``` | instruction | 0 | 33,911 | 12 | 67,822 |
No | output | 1 | 33,911 | 12 | 67,823 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has the sequence consisting of n integers. Vasya consider the pair of integers x and y k-interesting, if their binary representation differs from each other exactly in k bits. For example, if k = 2, the pair of integers x = 5 and y = 3 is k-interesting, because their binary representation x=101 and y=011 differs exactly in two bits.
Vasya wants to know how many pairs of indexes (i, j) are in his sequence so that i < j and the pair of integers ai and aj is k-interesting. Your task is to help Vasya and determine this number.
Input
The first line contains two integers n and k (2 β€ n β€ 105, 0 β€ k β€ 14) β the number of integers in Vasya's sequence and the number of bits in which integers in k-interesting pair should differ.
The second line contains the sequence a1, a2, ..., an (0 β€ ai β€ 104), which Vasya has.
Output
Print the number of pairs (i, j) so that i < j and the pair of integers ai and aj is k-interesting.
Examples
Input
4 1
0 3 2 1
Output
4
Input
6 0
200 100 100 100 200 200
Output
6
Note
In the first test there are 4 k-interesting pairs:
* (1, 3),
* (1, 4),
* (2, 3),
* (2, 4).
In the second test k = 0. Consequently, integers in any k-interesting pair should be equal to themselves. Thus, for the second test there are 6 k-interesting pairs:
* (1, 5),
* (1, 6),
* (2, 3),
* (2, 4),
* (3, 4),
* (5, 6).
Submitted Solution:
```
n, k = (int(i) for i in input().split())
lst = [int(i) for i in input().split()]
lst = [bin(i).lstrip('0b') for i in lst]
lst = [i[::-1] for i in lst]
if '' in lst:
for i in range(n):
if lst[i] == '':
lst[i] = '0'
dif, capacity = 0, 0
for i in range(n):
for j in range(i + 1, n):
dif = abs(len(lst[i]) - len(lst[j]))
cap_dif = dif
if len(lst[i]) > len(lst[j]):
for l in range(len(lst[i]) - dif, len(lst[i])):
if lst[i][l] == '0':
cap_dif -= 1
if len(lst[i]) < len(lst[j]):
for l in range(len(lst[j]) - dif, len(lst[j])):
if lst[j][l] == '0':
cap_dif -= 1
for l in range(min(len(lst[i]), len(lst[j]))):
if lst[i][l] != lst[j][l]:
cap_dif += 1
if cap_dif <= k:
capacity += 1
print(capacity)
``` | instruction | 0 | 33,912 | 12 | 67,824 |
No | output | 1 | 33,912 | 12 | 67,825 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For an array b of length m we define the function f as
f(b) = \begin{cases} b[1] & if m = 1 \\\ f(b[1] β b[2],b[2] β b[3],...,b[m-1] β b[m]) & otherwise, \end{cases}
where β is [bitwise exclusive OR](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
For example, f(1,2,4,8)=f(1β2,2β4,4β8)=f(3,6,12)=f(3β6,6β12)=f(5,10)=f(5β10)=f(15)=15
You are given an array a and a few queries. Each query is represented as two integers l and r. The answer is the maximum value of f on all continuous subsegments of the array a_l, a_{l+1}, β¦, a_r.
Input
The first line contains a single integer n (1 β€ n β€ 5000) β the length of a.
The second line contains n integers a_1, a_2, ..., a_n (0 β€ a_i β€ 2^{30}-1) β the elements of the array.
The third line contains a single integer q (1 β€ q β€ 100 000) β the number of queries.
Each of the next q lines contains a query represented as two integers l, r (1 β€ l β€ r β€ n).
Output
Print q lines β the answers for the queries.
Examples
Input
3
8 4 1
2
2 3
1 2
Output
5
12
Input
6
1 2 4 8 16 32
4
1 6
2 5
3 4
1 2
Output
60
30
12
3
Note
In first sample in both queries the maximum value of the function is reached on the subsegment that is equal to the whole segment.
In second sample, optimal segment for first query are [3,6], for second query β [2,5], for third β [3,4], for fourth β [1,2]. | instruction | 0 | 33,986 | 12 | 67,972 |
Tags: dp
Correct Solution:
```
n = int(input())
a = list(map(int, input().split(' ')))
list_a = [a]
for i in range(n - 1):
temp = []
for j in range(1, len(list_a[-1])):
temp.append(list_a[-1][j-1] ^ list_a[-1][j])
list_a.append(temp)
for j in range(1, len(list_a)):
for k in range(len(list_a[j])):
list_a[j][k] = max(list_a[j][k], list_a[j-1][k], list_a[j - 1][k + 1])
q = int(input())
for i in range(q):
l, r = map(int, input().split(' '))
print(str(list_a[r - l][l - 1]) + "\n")
``` | output | 1 | 33,986 | 12 | 67,973 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For an array b of length m we define the function f as
f(b) = \begin{cases} b[1] & if m = 1 \\\ f(b[1] β b[2],b[2] β b[3],...,b[m-1] β b[m]) & otherwise, \end{cases}
where β is [bitwise exclusive OR](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
For example, f(1,2,4,8)=f(1β2,2β4,4β8)=f(3,6,12)=f(3β6,6β12)=f(5,10)=f(5β10)=f(15)=15
You are given an array a and a few queries. Each query is represented as two integers l and r. The answer is the maximum value of f on all continuous subsegments of the array a_l, a_{l+1}, β¦, a_r.
Input
The first line contains a single integer n (1 β€ n β€ 5000) β the length of a.
The second line contains n integers a_1, a_2, ..., a_n (0 β€ a_i β€ 2^{30}-1) β the elements of the array.
The third line contains a single integer q (1 β€ q β€ 100 000) β the number of queries.
Each of the next q lines contains a query represented as two integers l, r (1 β€ l β€ r β€ n).
Output
Print q lines β the answers for the queries.
Examples
Input
3
8 4 1
2
2 3
1 2
Output
5
12
Input
6
1 2 4 8 16 32
4
1 6
2 5
3 4
1 2
Output
60
30
12
3
Note
In first sample in both queries the maximum value of the function is reached on the subsegment that is equal to the whole segment.
In second sample, optimal segment for first query are [3,6], for second query β [2,5], for third β [3,4], for fourth β [1,2]. | instruction | 0 | 33,987 | 12 | 67,974 |
Tags: dp
Correct Solution:
```
n = int(input())
A = list(map(int, input().split()))
dp = [[0]*n for i in range(n)]
for i in range(n):
dp[0][i] = A[i]
for i in range(1, n):
for j in range(n-i):
dp[i][j] = dp[i-1][j]^dp[i-1][j+1]
for i in range(1, n):
for j in range(n-i):
dp[i][j] = max(dp[i][j], dp[i-1][j], dp[i-1][j+1])
q = int(input())
for i in range(q):
l, r = map(int, input().split())
l, r = l-1, r-1
print(dp[r-l][l])
``` | output | 1 | 33,987 | 12 | 67,975 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For an array b of length m we define the function f as
f(b) = \begin{cases} b[1] & if m = 1 \\\ f(b[1] β b[2],b[2] β b[3],...,b[m-1] β b[m]) & otherwise, \end{cases}
where β is [bitwise exclusive OR](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
For example, f(1,2,4,8)=f(1β2,2β4,4β8)=f(3,6,12)=f(3β6,6β12)=f(5,10)=f(5β10)=f(15)=15
You are given an array a and a few queries. Each query is represented as two integers l and r. The answer is the maximum value of f on all continuous subsegments of the array a_l, a_{l+1}, β¦, a_r.
Input
The first line contains a single integer n (1 β€ n β€ 5000) β the length of a.
The second line contains n integers a_1, a_2, ..., a_n (0 β€ a_i β€ 2^{30}-1) β the elements of the array.
The third line contains a single integer q (1 β€ q β€ 100 000) β the number of queries.
Each of the next q lines contains a query represented as two integers l, r (1 β€ l β€ r β€ n).
Output
Print q lines β the answers for the queries.
Examples
Input
3
8 4 1
2
2 3
1 2
Output
5
12
Input
6
1 2 4 8 16 32
4
1 6
2 5
3 4
1 2
Output
60
30
12
3
Note
In first sample in both queries the maximum value of the function is reached on the subsegment that is equal to the whole segment.
In second sample, optimal segment for first query are [3,6], for second query β [2,5], for third β [3,4], for fourth β [1,2]. | instruction | 0 | 33,988 | 12 | 67,976 |
Tags: dp
Correct Solution:
```
lenght = int(input())
elem = [int(x) for x in input().split()]
num = int(input())
vector = [[int(x) for x in input().split()] for i in range(0, num)]
aux = [[0 for j in range(0, lenght - i)] for i in range(0, lenght)]
for i in range(0, lenght):
aux[0][i] = elem[i]
for i in range(1, lenght):
for j in range(0, lenght - i):
aux[i][j] = aux[i - 1][j] ^ aux[i - 1][j + 1]
for i in range(1, lenght):
for j in range(0, lenght - i):
aux[i][j] = max(max(aux[i][j],aux[i - 1][j]),aux[i - 1][j + 1])
for i in range(0, num):
print (aux[vector[i][1] - vector[i][0]][vector[i][0] - 1])
``` | output | 1 | 33,988 | 12 | 67,977 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For an array b of length m we define the function f as
f(b) = \begin{cases} b[1] & if m = 1 \\\ f(b[1] β b[2],b[2] β b[3],...,b[m-1] β b[m]) & otherwise, \end{cases}
where β is [bitwise exclusive OR](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
For example, f(1,2,4,8)=f(1β2,2β4,4β8)=f(3,6,12)=f(3β6,6β12)=f(5,10)=f(5β10)=f(15)=15
You are given an array a and a few queries. Each query is represented as two integers l and r. The answer is the maximum value of f on all continuous subsegments of the array a_l, a_{l+1}, β¦, a_r.
Input
The first line contains a single integer n (1 β€ n β€ 5000) β the length of a.
The second line contains n integers a_1, a_2, ..., a_n (0 β€ a_i β€ 2^{30}-1) β the elements of the array.
The third line contains a single integer q (1 β€ q β€ 100 000) β the number of queries.
Each of the next q lines contains a query represented as two integers l, r (1 β€ l β€ r β€ n).
Output
Print q lines β the answers for the queries.
Examples
Input
3
8 4 1
2
2 3
1 2
Output
5
12
Input
6
1 2 4 8 16 32
4
1 6
2 5
3 4
1 2
Output
60
30
12
3
Note
In first sample in both queries the maximum value of the function is reached on the subsegment that is equal to the whole segment.
In second sample, optimal segment for first query are [3,6], for second query β [2,5], for third β [3,4], for fourth β [1,2]. | instruction | 0 | 33,989 | 12 | 67,978 |
Tags: dp
Correct Solution:
```
tamanho = int(input())
elementos = list(map(int, input().split()))
matriz = [[0] * tamanho for i in range(tamanho)]
for i in range(tamanho):
matriz[0][i] = elementos[i]
for i in range(1, tamanho):
for j in range(tamanho-i):
matriz[i][j] = matriz[i-1][j] ^ matriz[i-1][j+1]
for i in range(1, tamanho):
for j in range(tamanho-i):
matriz[i][j] = max(matriz[i][j], matriz[i-1][j], matriz[i-1][j+1])
num_buscas = int(input())
for i in range(num_buscas):
busca_l, busca_r = map(int, input().split())
busca_l, busca_r = busca_l-1, busca_r-1
print(matriz[busca_r-busca_l][busca_l])
``` | output | 1 | 33,989 | 12 | 67,979 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For an array b of length m we define the function f as
f(b) = \begin{cases} b[1] & if m = 1 \\\ f(b[1] β b[2],b[2] β b[3],...,b[m-1] β b[m]) & otherwise, \end{cases}
where β is [bitwise exclusive OR](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
For example, f(1,2,4,8)=f(1β2,2β4,4β8)=f(3,6,12)=f(3β6,6β12)=f(5,10)=f(5β10)=f(15)=15
You are given an array a and a few queries. Each query is represented as two integers l and r. The answer is the maximum value of f on all continuous subsegments of the array a_l, a_{l+1}, β¦, a_r.
Input
The first line contains a single integer n (1 β€ n β€ 5000) β the length of a.
The second line contains n integers a_1, a_2, ..., a_n (0 β€ a_i β€ 2^{30}-1) β the elements of the array.
The third line contains a single integer q (1 β€ q β€ 100 000) β the number of queries.
Each of the next q lines contains a query represented as two integers l, r (1 β€ l β€ r β€ n).
Output
Print q lines β the answers for the queries.
Examples
Input
3
8 4 1
2
2 3
1 2
Output
5
12
Input
6
1 2 4 8 16 32
4
1 6
2 5
3 4
1 2
Output
60
30
12
3
Note
In first sample in both queries the maximum value of the function is reached on the subsegment that is equal to the whole segment.
In second sample, optimal segment for first query are [3,6], for second query β [2,5], for third β [3,4], for fourth β [1,2]. | instruction | 0 | 33,990 | 12 | 67,980 |
Tags: dp
Correct Solution:
```
from sys import stdin, stdout
n = int(stdin.readline())
a = list(map(int, stdin.readline().split(' ')))
list_a = [a]
for _ in range(n - 1):
temp = []
for j in range(1, len(list_a[-1])):
temp.append(list_a[-1][j-1] ^ list_a[-1][j])
list_a.append(temp)
for j in range(1, len(list_a)):
for k in range(len(list_a[j])):
list_a[j][k] = max(list_a[j][k], list_a[j-1][k], list_a[j - 1][k + 1])
q = int(stdin.readline())
for _ in range(q):
l, r = map(int, stdin.readline().split(' '))
stdout.write(str(list_a[r - l][l - 1]) + "\n")
``` | output | 1 | 33,990 | 12 | 67,981 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For an array b of length m we define the function f as
f(b) = \begin{cases} b[1] & if m = 1 \\\ f(b[1] β b[2],b[2] β b[3],...,b[m-1] β b[m]) & otherwise, \end{cases}
where β is [bitwise exclusive OR](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
For example, f(1,2,4,8)=f(1β2,2β4,4β8)=f(3,6,12)=f(3β6,6β12)=f(5,10)=f(5β10)=f(15)=15
You are given an array a and a few queries. Each query is represented as two integers l and r. The answer is the maximum value of f on all continuous subsegments of the array a_l, a_{l+1}, β¦, a_r.
Input
The first line contains a single integer n (1 β€ n β€ 5000) β the length of a.
The second line contains n integers a_1, a_2, ..., a_n (0 β€ a_i β€ 2^{30}-1) β the elements of the array.
The third line contains a single integer q (1 β€ q β€ 100 000) β the number of queries.
Each of the next q lines contains a query represented as two integers l, r (1 β€ l β€ r β€ n).
Output
Print q lines β the answers for the queries.
Examples
Input
3
8 4 1
2
2 3
1 2
Output
5
12
Input
6
1 2 4 8 16 32
4
1 6
2 5
3 4
1 2
Output
60
30
12
3
Note
In first sample in both queries the maximum value of the function is reached on the subsegment that is equal to the whole segment.
In second sample, optimal segment for first query are [3,6], for second query β [2,5], for third β [3,4], for fourth β [1,2]. | instruction | 0 | 33,991 | 12 | 67,982 |
Tags: dp
Correct Solution:
```
import sys
import io, os
input = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
n = int(input())
A = list(map(int, input().split()))
dp = [[0]*n for i in range(n)]
for i in range(n):
dp[0][i] = A[i]
for i in range(1, n):
for j in range(n-i):
dp[i][j] = dp[i-1][j]^dp[i-1][j+1]
#print(dp)
for i in range(1, n):
for j in range(n-i):
dp[i][j] = max(dp[i][j], dp[i-1][j], dp[i-1][j+1])
q = int(input())
for i in range(q):
l, r = map(int, input().split())
l, r = l-1, r-1
print(dp[r-l][l])
``` | output | 1 | 33,991 | 12 | 67,983 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For an array b of length m we define the function f as
f(b) = \begin{cases} b[1] & if m = 1 \\\ f(b[1] β b[2],b[2] β b[3],...,b[m-1] β b[m]) & otherwise, \end{cases}
where β is [bitwise exclusive OR](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
For example, f(1,2,4,8)=f(1β2,2β4,4β8)=f(3,6,12)=f(3β6,6β12)=f(5,10)=f(5β10)=f(15)=15
You are given an array a and a few queries. Each query is represented as two integers l and r. The answer is the maximum value of f on all continuous subsegments of the array a_l, a_{l+1}, β¦, a_r.
Input
The first line contains a single integer n (1 β€ n β€ 5000) β the length of a.
The second line contains n integers a_1, a_2, ..., a_n (0 β€ a_i β€ 2^{30}-1) β the elements of the array.
The third line contains a single integer q (1 β€ q β€ 100 000) β the number of queries.
Each of the next q lines contains a query represented as two integers l, r (1 β€ l β€ r β€ n).
Output
Print q lines β the answers for the queries.
Examples
Input
3
8 4 1
2
2 3
1 2
Output
5
12
Input
6
1 2 4 8 16 32
4
1 6
2 5
3 4
1 2
Output
60
30
12
3
Note
In first sample in both queries the maximum value of the function is reached on the subsegment that is equal to the whole segment.
In second sample, optimal segment for first query are [3,6], for second query β [2,5], for third β [3,4], for fourth β [1,2]. | instruction | 0 | 33,992 | 12 | 67,984 |
Tags: dp
Correct Solution:
```
def pyramid(arr, n):
mtx = [[0] * n for _ in range(n)]
for i in range(n):
mtx[0][i] = arr[i]
for i in range(1, n):
for j in range(n - i):
mtx[i][j] = mtx[i-1][j] ^ mtx[i-1][j+1]
for i in range(1, n):
for j in range(n - i):
mtx[i][j] = max(mtx[i][j], mtx[i-1][j], mtx[i-1][j+1])
q = int(input())
for _ in range(q):
l, r = list(map(int, input().split()))
l -= 1
r -= 1
print(mtx[r - l][l])
n = int(input())
arr = list(map(int, input().split()))
pyramid(arr, n)
``` | output | 1 | 33,992 | 12 | 67,985 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For an array b of length m we define the function f as
f(b) = \begin{cases} b[1] & if m = 1 \\\ f(b[1] β b[2],b[2] β b[3],...,b[m-1] β b[m]) & otherwise, \end{cases}
where β is [bitwise exclusive OR](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
For example, f(1,2,4,8)=f(1β2,2β4,4β8)=f(3,6,12)=f(3β6,6β12)=f(5,10)=f(5β10)=f(15)=15
You are given an array a and a few queries. Each query is represented as two integers l and r. The answer is the maximum value of f on all continuous subsegments of the array a_l, a_{l+1}, β¦, a_r.
Input
The first line contains a single integer n (1 β€ n β€ 5000) β the length of a.
The second line contains n integers a_1, a_2, ..., a_n (0 β€ a_i β€ 2^{30}-1) β the elements of the array.
The third line contains a single integer q (1 β€ q β€ 100 000) β the number of queries.
Each of the next q lines contains a query represented as two integers l, r (1 β€ l β€ r β€ n).
Output
Print q lines β the answers for the queries.
Examples
Input
3
8 4 1
2
2 3
1 2
Output
5
12
Input
6
1 2 4 8 16 32
4
1 6
2 5
3 4
1 2
Output
60
30
12
3
Note
In first sample in both queries the maximum value of the function is reached on the subsegment that is equal to the whole segment.
In second sample, optimal segment for first query are [3,6], for second query β [2,5], for third β [3,4], for fourth β [1,2]. | instruction | 0 | 33,993 | 12 | 67,986 |
Tags: dp
Correct Solution:
```
n = int(input())
a = list(map(int, input().split(' ')))
array_a = [a]
for _ in range(n - 1):
aux = []
for i in range(1, len(array_a[-1])):
aux.append(array_a[-1][i-1] ^ array_a[-1][i])
array_a.append(aux)
for i in range(1, len(array_a)):
for j in range(len(array_a[i])):
array_a[i][j] = max(array_a[i][j], array_a[i-1][j], array_a[i - 1][j + 1])
k = int(input())
for _ in range(k):
l, r = map(int, input().split(' '))
print(str(array_a[r - l][l - 1]) + "\n")
``` | output | 1 | 33,993 | 12 | 67,987 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given array a_1, a_2, ..., a_n. Find the subsegment a_l, a_{l+1}, ..., a_r (1 β€ l β€ r β€ n) with maximum arithmetic mean (1)/(r - l + 1)β_{i=l}^{r}{a_i} (in floating-point numbers, i.e. without any rounding).
If there are many such subsegments find the longest one.
Input
The first line contains single integer n (1 β€ n β€ 10^5) β length of the array a.
The second line contains n integers a_1, a_2, ..., a_n (0 β€ a_i β€ 10^9) β the array a.
Output
Print the single integer β the length of the longest subsegment with maximum possible arithmetic mean.
Example
Input
5
6 1 6 6 0
Output
2
Note
The subsegment [3, 4] is the longest among all subsegments with maximum arithmetic mean. | instruction | 0 | 34,285 | 12 | 68,570 |
Tags: implementation, math
Correct Solution:
```
n = int(input())
A = [int(x) for x in input().split()]
mx = max(A)
streak = 0
cur = 0
for a in A:
if a == mx:
cur += 1
streak = max(streak, cur)
else:
cur = 0
print(streak)
``` | output | 1 | 34,285 | 12 | 68,571 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given array a_1, a_2, ..., a_n. Find the subsegment a_l, a_{l+1}, ..., a_r (1 β€ l β€ r β€ n) with maximum arithmetic mean (1)/(r - l + 1)β_{i=l}^{r}{a_i} (in floating-point numbers, i.e. without any rounding).
If there are many such subsegments find the longest one.
Input
The first line contains single integer n (1 β€ n β€ 10^5) β length of the array a.
The second line contains n integers a_1, a_2, ..., a_n (0 β€ a_i β€ 10^9) β the array a.
Output
Print the single integer β the length of the longest subsegment with maximum possible arithmetic mean.
Example
Input
5
6 1 6 6 0
Output
2
Note
The subsegment [3, 4] is the longest among all subsegments with maximum arithmetic mean. | instruction | 0 | 34,286 | 12 | 68,572 |
Tags: implementation, math
Correct Solution:
```
n = int(input())
arr_str = input().split()
arr = [int(x) for x in arr_str]
max_el = arr[0]
cnt = 1
max_cnt = 1
for i in range(1, len(arr)):
if arr[i] > max_el:
max_el = arr[i]
max_cnt = 1
cnt = 1
elif arr[i] == max_el:
cnt += 1
else:
if cnt > max_cnt:
max_cnt = cnt
cnt = 0
if cnt > max_cnt:
max_cnt = cnt
print(max_cnt)
``` | output | 1 | 34,286 | 12 | 68,573 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given array a_1, a_2, ..., a_n. Find the subsegment a_l, a_{l+1}, ..., a_r (1 β€ l β€ r β€ n) with maximum arithmetic mean (1)/(r - l + 1)β_{i=l}^{r}{a_i} (in floating-point numbers, i.e. without any rounding).
If there are many such subsegments find the longest one.
Input
The first line contains single integer n (1 β€ n β€ 10^5) β length of the array a.
The second line contains n integers a_1, a_2, ..., a_n (0 β€ a_i β€ 10^9) β the array a.
Output
Print the single integer β the length of the longest subsegment with maximum possible arithmetic mean.
Example
Input
5
6 1 6 6 0
Output
2
Note
The subsegment [3, 4] is the longest among all subsegments with maximum arithmetic mean. | instruction | 0 | 34,287 | 12 | 68,574 |
Tags: implementation, math
Correct Solution:
```
n = int(input())
arr = [int(x) for x in input().split()]
ans = l = 0
max_ = max(arr)
for i in arr:
if i<max_:
ans = 0
else:
ans+=1;
l = max(ans,l)
print(l)
``` | output | 1 | 34,287 | 12 | 68,575 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given array a_1, a_2, ..., a_n. Find the subsegment a_l, a_{l+1}, ..., a_r (1 β€ l β€ r β€ n) with maximum arithmetic mean (1)/(r - l + 1)β_{i=l}^{r}{a_i} (in floating-point numbers, i.e. without any rounding).
If there are many such subsegments find the longest one.
Input
The first line contains single integer n (1 β€ n β€ 10^5) β length of the array a.
The second line contains n integers a_1, a_2, ..., a_n (0 β€ a_i β€ 10^9) β the array a.
Output
Print the single integer β the length of the longest subsegment with maximum possible arithmetic mean.
Example
Input
5
6 1 6 6 0
Output
2
Note
The subsegment [3, 4] is the longest among all subsegments with maximum arithmetic mean. | instruction | 0 | 34,288 | 12 | 68,576 |
Tags: implementation, math
Correct Solution:
```
n=int(input())
a=list(map(int,input().split()))
m=max(a)
mcnt=0
cnt=0
for i in range(0,n):
if(a[i]!=m):
cnt=0
else:
cnt+=1
mcnt=max(cnt,mcnt)
print(mcnt)
``` | output | 1 | 34,288 | 12 | 68,577 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given array a_1, a_2, ..., a_n. Find the subsegment a_l, a_{l+1}, ..., a_r (1 β€ l β€ r β€ n) with maximum arithmetic mean (1)/(r - l + 1)β_{i=l}^{r}{a_i} (in floating-point numbers, i.e. without any rounding).
If there are many such subsegments find the longest one.
Input
The first line contains single integer n (1 β€ n β€ 10^5) β length of the array a.
The second line contains n integers a_1, a_2, ..., a_n (0 β€ a_i β€ 10^9) β the array a.
Output
Print the single integer β the length of the longest subsegment with maximum possible arithmetic mean.
Example
Input
5
6 1 6 6 0
Output
2
Note
The subsegment [3, 4] is the longest among all subsegments with maximum arithmetic mean. | instruction | 0 | 34,289 | 12 | 68,578 |
Tags: implementation, math
Correct Solution:
```
a,b,c,d=0,0,input(),0
for w in map(int,input().split()):
if w!=c:c,d=w,0
d+=1;a,b=max((a,b),(c,d))
print(b)
``` | output | 1 | 34,289 | 12 | 68,579 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given array a_1, a_2, ..., a_n. Find the subsegment a_l, a_{l+1}, ..., a_r (1 β€ l β€ r β€ n) with maximum arithmetic mean (1)/(r - l + 1)β_{i=l}^{r}{a_i} (in floating-point numbers, i.e. without any rounding).
If there are many such subsegments find the longest one.
Input
The first line contains single integer n (1 β€ n β€ 10^5) β length of the array a.
The second line contains n integers a_1, a_2, ..., a_n (0 β€ a_i β€ 10^9) β the array a.
Output
Print the single integer β the length of the longest subsegment with maximum possible arithmetic mean.
Example
Input
5
6 1 6 6 0
Output
2
Note
The subsegment [3, 4] is the longest among all subsegments with maximum arithmetic mean. | instruction | 0 | 34,290 | 12 | 68,580 |
Tags: implementation, math
Correct Solution:
```
n=int(input())
a=[int(i) for i in input().split()]
p = max(a)
ct=0
ans=1
for i in range(len(a)):
if(a[i]==p):
ct+=1
ans = max(ans,ct)
if(a[i]!=p):
ct=0
print(ans)
``` | output | 1 | 34,290 | 12 | 68,581 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given array a_1, a_2, ..., a_n. Find the subsegment a_l, a_{l+1}, ..., a_r (1 β€ l β€ r β€ n) with maximum arithmetic mean (1)/(r - l + 1)β_{i=l}^{r}{a_i} (in floating-point numbers, i.e. without any rounding).
If there are many such subsegments find the longest one.
Input
The first line contains single integer n (1 β€ n β€ 10^5) β length of the array a.
The second line contains n integers a_1, a_2, ..., a_n (0 β€ a_i β€ 10^9) β the array a.
Output
Print the single integer β the length of the longest subsegment with maximum possible arithmetic mean.
Example
Input
5
6 1 6 6 0
Output
2
Note
The subsegment [3, 4] is the longest among all subsegments with maximum arithmetic mean. | instruction | 0 | 34,291 | 12 | 68,582 |
Tags: implementation, math
Correct Solution:
```
def main():
n = int(input())
L = [int(x) for x in input().split()]
print(solver(L))
def solver(L):
n = len(L)
#i = 1
maxLength = 1
length = 1
prev = L[0]
maxNum = L[0]
#while i < n:
for i in range(1, n):
cur = L[i]
if prev == cur:
length += 1
else:
if prev > maxNum:
maxLength = length
maxNum = prev
elif prev == maxNum and length > maxLength:
maxLength = length
length = 1
prev = cur
#i += 1
if prev > maxNum:
maxLength = length
maxNum = prev
elif prev == maxNum and length > maxLength:
maxLength = length
return maxLength
# print(solver([6, 1, 6, 6, 0]))
# print(solver([5, 5, 1, 5, 5, 5, 0]))
# print(solver([5, 5, 1, 7, 7, 0, 8]))
# print(solver([5, 5, 1, 5, 5, 0, 5, 5, 5]))
# print(solver([5, 2, 4, 4, 4]))
# print(solver([7, 4, 4]))
main()
``` | output | 1 | 34,291 | 12 | 68,583 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given array a_1, a_2, ..., a_n. Find the subsegment a_l, a_{l+1}, ..., a_r (1 β€ l β€ r β€ n) with maximum arithmetic mean (1)/(r - l + 1)β_{i=l}^{r}{a_i} (in floating-point numbers, i.e. without any rounding).
If there are many such subsegments find the longest one.
Input
The first line contains single integer n (1 β€ n β€ 10^5) β length of the array a.
The second line contains n integers a_1, a_2, ..., a_n (0 β€ a_i β€ 10^9) β the array a.
Output
Print the single integer β the length of the longest subsegment with maximum possible arithmetic mean.
Example
Input
5
6 1 6 6 0
Output
2
Note
The subsegment [3, 4] is the longest among all subsegments with maximum arithmetic mean. | instruction | 0 | 34,292 | 12 | 68,584 |
Tags: implementation, math
Correct Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,copy,functools
import random
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 10**9+7
dd = [(-1,0),(0,1),(1,0),(0,-1)]
ddn = [(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)]
def LI(): return list(map(int, sys.stdin.readline().split()))
def LLI(): return [list(map(int, l.split())) for l in sys.stdin.readlines()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)
def pe(s): return print(str(s), file=sys.stderr)
def main():
n = I()
a = LI() + [-1]
m = max(a)
t = 0
r = 1
for c in a:
if c == m:
t += 1
else:
if r < t:
r = t
t = 0
return r
print(main())
``` | output | 1 | 34,292 | 12 | 68,585 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A sequence (b_1, b_2, β¦, b_k) is called strange, if the absolute difference between any pair of its elements is greater than or equal to the maximum element in the sequence. Formally speaking, it's strange if for every pair (i, j) with 1 β€ i<j β€ k, we have |a_i-a_j|β₯ MAX, where MAX is the largest element of the sequence. In particular, any sequence of length at most 1 is strange.
For example, the sequences (-2021, -1, -1, -1) and (-1, 0, 1) are strange, but (3, 0, 1) is not, because |0 - 1| < 3.
Sifid has an array a of n integers. Sifid likes everything big, so among all the strange subsequences of a, he wants to find the length of the longest one. Can you help him?
A sequence c is a subsequence of an array d if c can be obtained from d by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 10^4) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 10^5) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (-10^9β€ a_i β€ 10^9) β the elements of the array a.
It is guaranteed that the sum of n over all test cases doesn't exceed 10^5.
Output
For each test case output a single integer β the length of the longest strange subsequence of a.
Example
Input
6
4
-1 -2 0 0
7
-3 4 -2 0 -4 6 1
5
0 5 -3 2 -5
3
2 3 1
4
-3 0 2 0
6
-3 -2 -1 1 1 1
Output
4
5
4
1
3
4
Note
In the first test case, one of the longest strange subsequences is (a_1, a_2, a_3, a_4)
In the second test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5, a_7).
In the third test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5).
In the fourth test case, one of the longest strange subsequences is (a_2).
In the fifth test case, one of the longest strange subsequences is (a_1, a_2, a_4). | instruction | 0 | 34,524 | 12 | 69,048 |
Tags: greedy, math, sortings
Correct Solution:
```
for _ in range(int(input())):
n=int(input())
a=list(map(int,input().split()))
a.sort()
p,q=float('-inf'),float('inf')
i=1
while i<n:
p=max(p,a[i])
q=min(abs(a[i]-a[i-1]),q)
if p>q:
break
i+=1
print(i)
``` | output | 1 | 34,524 | 12 | 69,049 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A sequence (b_1, b_2, β¦, b_k) is called strange, if the absolute difference between any pair of its elements is greater than or equal to the maximum element in the sequence. Formally speaking, it's strange if for every pair (i, j) with 1 β€ i<j β€ k, we have |a_i-a_j|β₯ MAX, where MAX is the largest element of the sequence. In particular, any sequence of length at most 1 is strange.
For example, the sequences (-2021, -1, -1, -1) and (-1, 0, 1) are strange, but (3, 0, 1) is not, because |0 - 1| < 3.
Sifid has an array a of n integers. Sifid likes everything big, so among all the strange subsequences of a, he wants to find the length of the longest one. Can you help him?
A sequence c is a subsequence of an array d if c can be obtained from d by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 10^4) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 10^5) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (-10^9β€ a_i β€ 10^9) β the elements of the array a.
It is guaranteed that the sum of n over all test cases doesn't exceed 10^5.
Output
For each test case output a single integer β the length of the longest strange subsequence of a.
Example
Input
6
4
-1 -2 0 0
7
-3 4 -2 0 -4 6 1
5
0 5 -3 2 -5
3
2 3 1
4
-3 0 2 0
6
-3 -2 -1 1 1 1
Output
4
5
4
1
3
4
Note
In the first test case, one of the longest strange subsequences is (a_1, a_2, a_3, a_4)
In the second test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5, a_7).
In the third test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5).
In the fourth test case, one of the longest strange subsequences is (a_2).
In the fifth test case, one of the longest strange subsequences is (a_1, a_2, a_4). | instruction | 0 | 34,525 | 12 | 69,050 |
Tags: greedy, math, sortings
Correct Solution:
```
from sys import stdin
input = stdin.readline
t = int(input())
for _ in range(t):
n = int(input())
a = [int(x) for x in input().split()]
a.sort()
c = 0
d = float("inf")
f = False
for i in range(n):
if a[i] > 0:
if a[i] <= d:
f = True
break
else:
c += 1
if i == 0:
continue
d = min(d, abs(a[i] - a[i-1]))
ans = c + f
print(ans)
``` | output | 1 | 34,525 | 12 | 69,051 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A sequence (b_1, b_2, β¦, b_k) is called strange, if the absolute difference between any pair of its elements is greater than or equal to the maximum element in the sequence. Formally speaking, it's strange if for every pair (i, j) with 1 β€ i<j β€ k, we have |a_i-a_j|β₯ MAX, where MAX is the largest element of the sequence. In particular, any sequence of length at most 1 is strange.
For example, the sequences (-2021, -1, -1, -1) and (-1, 0, 1) are strange, but (3, 0, 1) is not, because |0 - 1| < 3.
Sifid has an array a of n integers. Sifid likes everything big, so among all the strange subsequences of a, he wants to find the length of the longest one. Can you help him?
A sequence c is a subsequence of an array d if c can be obtained from d by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 10^4) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 10^5) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (-10^9β€ a_i β€ 10^9) β the elements of the array a.
It is guaranteed that the sum of n over all test cases doesn't exceed 10^5.
Output
For each test case output a single integer β the length of the longest strange subsequence of a.
Example
Input
6
4
-1 -2 0 0
7
-3 4 -2 0 -4 6 1
5
0 5 -3 2 -5
3
2 3 1
4
-3 0 2 0
6
-3 -2 -1 1 1 1
Output
4
5
4
1
3
4
Note
In the first test case, one of the longest strange subsequences is (a_1, a_2, a_3, a_4)
In the second test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5, a_7).
In the third test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5).
In the fourth test case, one of the longest strange subsequences is (a_2).
In the fifth test case, one of the longest strange subsequences is (a_1, a_2, a_4). | instruction | 0 | 34,526 | 12 | 69,052 |
Tags: greedy, math, sortings
Correct Solution:
```
from sys import stdin
from math import inf
t = int(stdin.readline())
for _ in range(t):
n = int(stdin.readline())
a = list(map(int, stdin.readline().split()))
cp = cz = cn = 0
for ele in a:
if ele == 0: cz += 1
elif ele > 0: cp += 1
else: cn += 1
ak = 0
a = list(set(a))
a.sort()
p = a[0]
fp = a[0]
md = inf
cc = (p <= 0)
for ele in a[1:]:
if ele > 0:
fp = ele
break
cc += 1
md = min(md, ele - p)
p = ele
if md >= fp and fp > 0:
ak = cc + 1
print(max(cz + cn, ak, 1))
``` | output | 1 | 34,526 | 12 | 69,053 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A sequence (b_1, b_2, β¦, b_k) is called strange, if the absolute difference between any pair of its elements is greater than or equal to the maximum element in the sequence. Formally speaking, it's strange if for every pair (i, j) with 1 β€ i<j β€ k, we have |a_i-a_j|β₯ MAX, where MAX is the largest element of the sequence. In particular, any sequence of length at most 1 is strange.
For example, the sequences (-2021, -1, -1, -1) and (-1, 0, 1) are strange, but (3, 0, 1) is not, because |0 - 1| < 3.
Sifid has an array a of n integers. Sifid likes everything big, so among all the strange subsequences of a, he wants to find the length of the longest one. Can you help him?
A sequence c is a subsequence of an array d if c can be obtained from d by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 10^4) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 10^5) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (-10^9β€ a_i β€ 10^9) β the elements of the array a.
It is guaranteed that the sum of n over all test cases doesn't exceed 10^5.
Output
For each test case output a single integer β the length of the longest strange subsequence of a.
Example
Input
6
4
-1 -2 0 0
7
-3 4 -2 0 -4 6 1
5
0 5 -3 2 -5
3
2 3 1
4
-3 0 2 0
6
-3 -2 -1 1 1 1
Output
4
5
4
1
3
4
Note
In the first test case, one of the longest strange subsequences is (a_1, a_2, a_3, a_4)
In the second test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5, a_7).
In the third test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5).
In the fourth test case, one of the longest strange subsequences is (a_2).
In the fifth test case, one of the longest strange subsequences is (a_1, a_2, a_4). | instruction | 0 | 34,527 | 12 | 69,054 |
Tags: greedy, math, sortings
Correct Solution:
```
t = int(input())
while t:
n = int(input())
l = [int(i) for i in input().split()]
pos= []
neg = []
zero = []
for i in l:
if(i<0):
neg.append(i)
elif(i==0):
zero.append(i)
else:
pos.append(i)
if(len(zero)>=2):
print(len(neg)+len(zero))
else:
if(len(pos)>=1):
neg.sort()
mini = float('inf')
for i in range(len(neg)-1):
mini = min(mini,abs(neg[i]-neg[i+1]))
if(len(zero)==1 and len(neg)>0):
negi = neg[-1]
mini = min(mini,abs(0-negi))
pos.sort()
if(mini>=pos[0]):
print(len(neg)+len(zero)+1)
else:
print(len(neg)+len(zero))
else:
print(len(neg)+len(zero))
t-=1
``` | output | 1 | 34,527 | 12 | 69,055 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A sequence (b_1, b_2, β¦, b_k) is called strange, if the absolute difference between any pair of its elements is greater than or equal to the maximum element in the sequence. Formally speaking, it's strange if for every pair (i, j) with 1 β€ i<j β€ k, we have |a_i-a_j|β₯ MAX, where MAX is the largest element of the sequence. In particular, any sequence of length at most 1 is strange.
For example, the sequences (-2021, -1, -1, -1) and (-1, 0, 1) are strange, but (3, 0, 1) is not, because |0 - 1| < 3.
Sifid has an array a of n integers. Sifid likes everything big, so among all the strange subsequences of a, he wants to find the length of the longest one. Can you help him?
A sequence c is a subsequence of an array d if c can be obtained from d by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 10^4) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 10^5) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (-10^9β€ a_i β€ 10^9) β the elements of the array a.
It is guaranteed that the sum of n over all test cases doesn't exceed 10^5.
Output
For each test case output a single integer β the length of the longest strange subsequence of a.
Example
Input
6
4
-1 -2 0 0
7
-3 4 -2 0 -4 6 1
5
0 5 -3 2 -5
3
2 3 1
4
-3 0 2 0
6
-3 -2 -1 1 1 1
Output
4
5
4
1
3
4
Note
In the first test case, one of the longest strange subsequences is (a_1, a_2, a_3, a_4)
In the second test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5, a_7).
In the third test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5).
In the fourth test case, one of the longest strange subsequences is (a_2).
In the fifth test case, one of the longest strange subsequences is (a_1, a_2, a_4). | instruction | 0 | 34,528 | 12 | 69,056 |
Tags: greedy, math, sortings
Correct Solution:
```
def solve():
n=int(input())
l=list(map(int,input().split()))
if n==1:
print(1)
return
l.sort()
count=1
ans = l[1]-l[0]
key=l[0]
j=-1
for i in range(1,n):
if l[i]>0:
key=l[i-1]
j=i
break
count+=1
ans=min(ans,l[i]-l[i-1])
if j!=-1:
flag=True
while j<n:
if flag:
flag=False
if l[j]<=ans:
count+=1
key=l[j]
if flag and l[j]<=ans and l[j]-key<=ans:
count+=1
ans=min(ans,l[j]-key)
key=l[j]
else:
break
j+=1
print(count)
for _ in range(int(input())):
solve()
``` | output | 1 | 34,528 | 12 | 69,057 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A sequence (b_1, b_2, β¦, b_k) is called strange, if the absolute difference between any pair of its elements is greater than or equal to the maximum element in the sequence. Formally speaking, it's strange if for every pair (i, j) with 1 β€ i<j β€ k, we have |a_i-a_j|β₯ MAX, where MAX is the largest element of the sequence. In particular, any sequence of length at most 1 is strange.
For example, the sequences (-2021, -1, -1, -1) and (-1, 0, 1) are strange, but (3, 0, 1) is not, because |0 - 1| < 3.
Sifid has an array a of n integers. Sifid likes everything big, so among all the strange subsequences of a, he wants to find the length of the longest one. Can you help him?
A sequence c is a subsequence of an array d if c can be obtained from d by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 10^4) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 10^5) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (-10^9β€ a_i β€ 10^9) β the elements of the array a.
It is guaranteed that the sum of n over all test cases doesn't exceed 10^5.
Output
For each test case output a single integer β the length of the longest strange subsequence of a.
Example
Input
6
4
-1 -2 0 0
7
-3 4 -2 0 -4 6 1
5
0 5 -3 2 -5
3
2 3 1
4
-3 0 2 0
6
-3 -2 -1 1 1 1
Output
4
5
4
1
3
4
Note
In the first test case, one of the longest strange subsequences is (a_1, a_2, a_3, a_4)
In the second test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5, a_7).
In the third test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5).
In the fourth test case, one of the longest strange subsequences is (a_2).
In the fifth test case, one of the longest strange subsequences is (a_1, a_2, a_4). | instruction | 0 | 34,529 | 12 | 69,058 |
Tags: greedy, math, sortings
Correct Solution:
```
import math
t = int(input())
for _ in range(t):
n = int(input())
arr = list(map(int,input().split()))
count = 0
arr.sort()
min = arr[0]
i = 0
flag = False
for i in range(n):
if(arr[i] > 0):
flag = True
break
count+=1
if(flag):
flag2 = False
max = i
max2 = arr[max]
for i in range(1,max+1,1):
if(arr[i] - arr[i-1] < max2):
flag2 = True
break
if(flag2):
print(count)
else:
print(count+1)
else:
print(count)
``` | output | 1 | 34,529 | 12 | 69,059 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A sequence (b_1, b_2, β¦, b_k) is called strange, if the absolute difference between any pair of its elements is greater than or equal to the maximum element in the sequence. Formally speaking, it's strange if for every pair (i, j) with 1 β€ i<j β€ k, we have |a_i-a_j|β₯ MAX, where MAX is the largest element of the sequence. In particular, any sequence of length at most 1 is strange.
For example, the sequences (-2021, -1, -1, -1) and (-1, 0, 1) are strange, but (3, 0, 1) is not, because |0 - 1| < 3.
Sifid has an array a of n integers. Sifid likes everything big, so among all the strange subsequences of a, he wants to find the length of the longest one. Can you help him?
A sequence c is a subsequence of an array d if c can be obtained from d by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 10^4) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 10^5) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (-10^9β€ a_i β€ 10^9) β the elements of the array a.
It is guaranteed that the sum of n over all test cases doesn't exceed 10^5.
Output
For each test case output a single integer β the length of the longest strange subsequence of a.
Example
Input
6
4
-1 -2 0 0
7
-3 4 -2 0 -4 6 1
5
0 5 -3 2 -5
3
2 3 1
4
-3 0 2 0
6
-3 -2 -1 1 1 1
Output
4
5
4
1
3
4
Note
In the first test case, one of the longest strange subsequences is (a_1, a_2, a_3, a_4)
In the second test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5, a_7).
In the third test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5).
In the fourth test case, one of the longest strange subsequences is (a_2).
In the fifth test case, one of the longest strange subsequences is (a_1, a_2, a_4). | instruction | 0 | 34,530 | 12 | 69,060 |
Tags: greedy, math, sortings
Correct Solution:
```
import sys,os,io
from sys import stdin,stdout
from math import log, gcd, ceil
from collections import defaultdict, deque, Counter
from heapq import heappush, heappop
from bisect import bisect_left , bisect_right
import math
MOD = 1000000000 + 7
# input = stdin.readline
alphabets = list('abcdefghijklmnopqrstuvwxyz')
def isPrime(x):
for i in range(2,x):
if i*i>x:
break
if (x%i==0):
return False
return True
def ncr(n, r, p):
num = den = 1
for i in range(r):
num = (num * (n - i)) % p
den = (den * (i + 1)) % p
return (num * pow(den,
p - 2, p)) % p
def primeFactors(n):
l = []
while n % 2 == 0:
l.append(2)
n = n / 2
for i in range(3,int(math.sqrt(n))+1,2):
while n % i== 0:
l.append(int(i))
n = n / i
if n > 2:
l.append(n)
return list(set(l))
def power(x, y, p) :
res = 1
x = x % p
if (x == 0) :
return 0
while (y > 0) :
if ((y & 1) == 1) :
res = (res * x) % p
y = y >> 1 # y = y/2
x = (x * x) % p
return res
def SieveOfEratosthenes(n):
prime = [True for i in range(n+1)]
p = 2
while (p * p <= n):
if (prime[p] == True):
for i in range(p * p, n+1, p):
prime[i] = False
p += 1
return prime
def countdig(n):
c = 0
while (n > 0):
n //= 10
c += 1
return c
def si():
return input()
def prefix_sum(arr):
r = [0] * (len(arr)+1)
for i, el in enumerate(arr):
r[i+1] = r[i] + el
return r
def divideCeil(n,x):
if (n%x==0):
return n//x
return n//x+1
def ii():
return int(input())
def li():
return list(map(int,input().split()))
def ws(s): sys.stdout.write(s + '\n')
def wi(n): sys.stdout.write(str(n) + '\n')
def wia(a): sys.stdout.write(' '.join([str(x) for x in a]) + '\n')
def power_set(L):
cardinality=len(L)
n=2 ** cardinality
powerset = []
for i in range(n):
a=bin(i)[2:]
subset=[]
for j in range(len(a)):
if a[-j-1]=='1':
subset.append(L[j])
powerset.append(subset)
powerset_orderred=[]
for k in range(cardinality+1):
for w in powerset:
if len(w)==k:
powerset_orderred.append(w)
return powerset_orderred
def fastPlrintNextLines(a):
# 12
# 3
# 1
#like this
#a is list of strings
print('\n'.join(map(str,a)))
def sortByFirstAndSecond(A):
A = sorted(A,key = lambda x:x[0])
A = sorted(A,key = lambda x:x[1])
return list(A)
#__________________________TEMPLATE__________________OVER_______________________________________________________
if(os.path.exists('input.txt')):
sys.stdin = open("input.txt","r") ; sys.stdout = open("output.txt","w")
# else:
# input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
for _ in range(int(input())):
# n,m = map(int,input().split())
n = int(input())
li = list(map(int,input().split()))
zc = pc = nc = 0
pl = []
nl = []
for i in range(n):
if(li[i] <= 0):
nc+=1
nl.append(li[i])
else:
pc+=1
pl.append(li[i])
nl.sort()
pl.sort()
ans = nc
if(pc == 0):
print(nc)
elif(nc == 1):
print(2)
elif(nc == 0):
print(1)
else:
pv = pl[0]
flag = 0
for i in range(nc-1):
if(abs(nl[i] - nl[i+1]) < pv):
flag = 1
break
if(flag == 0):
print(nc+1)
else:
print(nc)
``` | output | 1 | 34,530 | 12 | 69,061 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A sequence (b_1, b_2, β¦, b_k) is called strange, if the absolute difference between any pair of its elements is greater than or equal to the maximum element in the sequence. Formally speaking, it's strange if for every pair (i, j) with 1 β€ i<j β€ k, we have |a_i-a_j|β₯ MAX, where MAX is the largest element of the sequence. In particular, any sequence of length at most 1 is strange.
For example, the sequences (-2021, -1, -1, -1) and (-1, 0, 1) are strange, but (3, 0, 1) is not, because |0 - 1| < 3.
Sifid has an array a of n integers. Sifid likes everything big, so among all the strange subsequences of a, he wants to find the length of the longest one. Can you help him?
A sequence c is a subsequence of an array d if c can be obtained from d by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 10^4) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 10^5) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (-10^9β€ a_i β€ 10^9) β the elements of the array a.
It is guaranteed that the sum of n over all test cases doesn't exceed 10^5.
Output
For each test case output a single integer β the length of the longest strange subsequence of a.
Example
Input
6
4
-1 -2 0 0
7
-3 4 -2 0 -4 6 1
5
0 5 -3 2 -5
3
2 3 1
4
-3 0 2 0
6
-3 -2 -1 1 1 1
Output
4
5
4
1
3
4
Note
In the first test case, one of the longest strange subsequences is (a_1, a_2, a_3, a_4)
In the second test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5, a_7).
In the third test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5).
In the fourth test case, one of the longest strange subsequences is (a_2).
In the fifth test case, one of the longest strange subsequences is (a_1, a_2, a_4). | instruction | 0 | 34,531 | 12 | 69,062 |
Tags: greedy, math, sortings
Correct Solution:
```
import sys
for _ in range(int(input())):
n=int(input())
a=list(map(int,input().split()))
a.sort()
c=1
m=sys.maxsize
for i in range(1,n):
m=min(m,abs(a[i]-a[i-1]))
if(m<a[i]):
break
c+=1
print(c)
``` | output | 1 | 34,531 | 12 | 69,063 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A sequence (b_1, b_2, β¦, b_k) is called strange, if the absolute difference between any pair of its elements is greater than or equal to the maximum element in the sequence. Formally speaking, it's strange if for every pair (i, j) with 1 β€ i<j β€ k, we have |a_i-a_j|β₯ MAX, where MAX is the largest element of the sequence. In particular, any sequence of length at most 1 is strange.
For example, the sequences (-2021, -1, -1, -1) and (-1, 0, 1) are strange, but (3, 0, 1) is not, because |0 - 1| < 3.
Sifid has an array a of n integers. Sifid likes everything big, so among all the strange subsequences of a, he wants to find the length of the longest one. Can you help him?
A sequence c is a subsequence of an array d if c can be obtained from d by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 10^4) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 10^5) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (-10^9β€ a_i β€ 10^9) β the elements of the array a.
It is guaranteed that the sum of n over all test cases doesn't exceed 10^5.
Output
For each test case output a single integer β the length of the longest strange subsequence of a.
Example
Input
6
4
-1 -2 0 0
7
-3 4 -2 0 -4 6 1
5
0 5 -3 2 -5
3
2 3 1
4
-3 0 2 0
6
-3 -2 -1 1 1 1
Output
4
5
4
1
3
4
Note
In the first test case, one of the longest strange subsequences is (a_1, a_2, a_3, a_4)
In the second test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5, a_7).
In the third test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5).
In the fourth test case, one of the longest strange subsequences is (a_2).
In the fifth test case, one of the longest strange subsequences is (a_1, a_2, a_4).
Submitted Solution:
```
import math
t = int(input())
def solve(a):
a.sort()
L = len(a)
if a[0] > 0 or L == 1:
return 1
min_diff = math.inf
idx = 1
while idx < L and a[idx] <= 0:
curr = a[idx] - a[idx - 1]
if min_diff > curr:
min_diff = curr
idx += 1
if idx < L:
return idx if min_diff < a[idx] else idx + 1
return idx
for test in range(t):
n = int(input())
a = [int(x) for x in input().split()]
print(solve(a))
``` | instruction | 0 | 34,532 | 12 | 69,064 |
Yes | output | 1 | 34,532 | 12 | 69,065 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A sequence (b_1, b_2, β¦, b_k) is called strange, if the absolute difference between any pair of its elements is greater than or equal to the maximum element in the sequence. Formally speaking, it's strange if for every pair (i, j) with 1 β€ i<j β€ k, we have |a_i-a_j|β₯ MAX, where MAX is the largest element of the sequence. In particular, any sequence of length at most 1 is strange.
For example, the sequences (-2021, -1, -1, -1) and (-1, 0, 1) are strange, but (3, 0, 1) is not, because |0 - 1| < 3.
Sifid has an array a of n integers. Sifid likes everything big, so among all the strange subsequences of a, he wants to find the length of the longest one. Can you help him?
A sequence c is a subsequence of an array d if c can be obtained from d by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 10^4) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 10^5) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (-10^9β€ a_i β€ 10^9) β the elements of the array a.
It is guaranteed that the sum of n over all test cases doesn't exceed 10^5.
Output
For each test case output a single integer β the length of the longest strange subsequence of a.
Example
Input
6
4
-1 -2 0 0
7
-3 4 -2 0 -4 6 1
5
0 5 -3 2 -5
3
2 3 1
4
-3 0 2 0
6
-3 -2 -1 1 1 1
Output
4
5
4
1
3
4
Note
In the first test case, one of the longest strange subsequences is (a_1, a_2, a_3, a_4)
In the second test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5, a_7).
In the third test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5).
In the fourth test case, one of the longest strange subsequences is (a_2).
In the fifth test case, one of the longest strange subsequences is (a_1, a_2, a_4).
Submitted Solution:
```
import collections
import functools
import math
import sys
def In():
return map(int, sys.stdin.readline().split())
input = sys.stdin.readline
import functools
import math
import sys
def In():
return map(int, sys.stdin.readline().split())
input = sys.stdin.readline
def strange():
for _ in range(int(input())):
n = int(input())
last = -float('inf')
mindiff = float("inf")
c = 0
for i in sorted(In()):
if last == -float('inf'):
last = i
else:
mindiff = min(i-last,mindiff)
last = i
if i > 0:
if mindiff < i:
break
c += 1
print(c)
strange()
``` | instruction | 0 | 34,533 | 12 | 69,066 |
Yes | output | 1 | 34,533 | 12 | 69,067 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A sequence (b_1, b_2, β¦, b_k) is called strange, if the absolute difference between any pair of its elements is greater than or equal to the maximum element in the sequence. Formally speaking, it's strange if for every pair (i, j) with 1 β€ i<j β€ k, we have |a_i-a_j|β₯ MAX, where MAX is the largest element of the sequence. In particular, any sequence of length at most 1 is strange.
For example, the sequences (-2021, -1, -1, -1) and (-1, 0, 1) are strange, but (3, 0, 1) is not, because |0 - 1| < 3.
Sifid has an array a of n integers. Sifid likes everything big, so among all the strange subsequences of a, he wants to find the length of the longest one. Can you help him?
A sequence c is a subsequence of an array d if c can be obtained from d by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 10^4) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 10^5) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (-10^9β€ a_i β€ 10^9) β the elements of the array a.
It is guaranteed that the sum of n over all test cases doesn't exceed 10^5.
Output
For each test case output a single integer β the length of the longest strange subsequence of a.
Example
Input
6
4
-1 -2 0 0
7
-3 4 -2 0 -4 6 1
5
0 5 -3 2 -5
3
2 3 1
4
-3 0 2 0
6
-3 -2 -1 1 1 1
Output
4
5
4
1
3
4
Note
In the first test case, one of the longest strange subsequences is (a_1, a_2, a_3, a_4)
In the second test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5, a_7).
In the third test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5).
In the fourth test case, one of the longest strange subsequences is (a_2).
In the fifth test case, one of the longest strange subsequences is (a_1, a_2, a_4).
Submitted Solution:
```
from __future__ import division, print_function
import bisect
import math
import heapq
import itertools
import sys
from collections import deque
from atexit import register
from collections import Counter
from functools import reduce
if sys.version_info[0] < 3:
from io import BytesIO as stream
else:
from io import StringIO as stream
def sync_with_stdio(sync=True):
"""Set whether the standard Python streams are allowed to buffer their I/O.
Args:
sync (bool, optional): The new synchronization setting.
"""
global input, flush
if sync:
flush = sys.stdout.flush
else:
sys.stdin = stream(sys.stdin.read())
input = lambda: sys.stdin.readline().rstrip('\r\n')
sys.stdout = stream()
register(lambda: sys.__stdout__.write(sys.stdout.getvalue()))
for _ in range(int(input())):
n = int(input())
a = list(map(int, input().split()))
if max(a) <= 0 or (max(a) == 0 and min(a) == 0):
print(n)
elif max(a) > 0 and min(a) > 0:
print(1)
elif n == 2 and min(a) <= 0:
print(2)
else:
c = 0
neg = []
pos = []
for i in a:
if i <= 0:
c += 1
neg.append(i)
else:
pos.append(i)
neg.sort()
# print(neg, pos)
q = min(pos)
flag = 0
for i in range(len(neg) - 1):
if q > abs(neg[i] - neg[i + 1]):
flag = 1
break
if flag == 0:
print(c + 1)
else:
print(c)
``` | instruction | 0 | 34,534 | 12 | 69,068 |
Yes | output | 1 | 34,534 | 12 | 69,069 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A sequence (b_1, b_2, β¦, b_k) is called strange, if the absolute difference between any pair of its elements is greater than or equal to the maximum element in the sequence. Formally speaking, it's strange if for every pair (i, j) with 1 β€ i<j β€ k, we have |a_i-a_j|β₯ MAX, where MAX is the largest element of the sequence. In particular, any sequence of length at most 1 is strange.
For example, the sequences (-2021, -1, -1, -1) and (-1, 0, 1) are strange, but (3, 0, 1) is not, because |0 - 1| < 3.
Sifid has an array a of n integers. Sifid likes everything big, so among all the strange subsequences of a, he wants to find the length of the longest one. Can you help him?
A sequence c is a subsequence of an array d if c can be obtained from d by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 10^4) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 10^5) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (-10^9β€ a_i β€ 10^9) β the elements of the array a.
It is guaranteed that the sum of n over all test cases doesn't exceed 10^5.
Output
For each test case output a single integer β the length of the longest strange subsequence of a.
Example
Input
6
4
-1 -2 0 0
7
-3 4 -2 0 -4 6 1
5
0 5 -3 2 -5
3
2 3 1
4
-3 0 2 0
6
-3 -2 -1 1 1 1
Output
4
5
4
1
3
4
Note
In the first test case, one of the longest strange subsequences is (a_1, a_2, a_3, a_4)
In the second test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5, a_7).
In the third test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5).
In the fourth test case, one of the longest strange subsequences is (a_2).
In the fifth test case, one of the longest strange subsequences is (a_1, a_2, a_4).
Submitted Solution:
```
for _ in range(int(input())):
n=int(input())
a=list(map(int,input().split()))
cnt=[]
flag=[]
for i in range(n):
if a[i]<=0:
cnt.append(a[i])
else:
flag.append(a[i])
if len(cnt)==0:
print(1)
elif len(flag)==0:
print(len(cnt))
else:
if cnt.count(0)>1:
print(len(cnt))
else:
flag.sort()
cnt.sort()
mark=0
for k in range(len(cnt)):
if abs(cnt[k]-flag[0])<flag[0]:
mark+=1
for j in range(len(cnt) - 1):
if abs(cnt[j] - cnt[j+1]) < flag[0]:
mark += 1
if mark == 0:
print(len(cnt) + 1)
else:
print(len(cnt))
``` | instruction | 0 | 34,535 | 12 | 69,070 |
Yes | output | 1 | 34,535 | 12 | 69,071 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A sequence (b_1, b_2, β¦, b_k) is called strange, if the absolute difference between any pair of its elements is greater than or equal to the maximum element in the sequence. Formally speaking, it's strange if for every pair (i, j) with 1 β€ i<j β€ k, we have |a_i-a_j|β₯ MAX, where MAX is the largest element of the sequence. In particular, any sequence of length at most 1 is strange.
For example, the sequences (-2021, -1, -1, -1) and (-1, 0, 1) are strange, but (3, 0, 1) is not, because |0 - 1| < 3.
Sifid has an array a of n integers. Sifid likes everything big, so among all the strange subsequences of a, he wants to find the length of the longest one. Can you help him?
A sequence c is a subsequence of an array d if c can be obtained from d by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 10^4) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 10^5) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (-10^9β€ a_i β€ 10^9) β the elements of the array a.
It is guaranteed that the sum of n over all test cases doesn't exceed 10^5.
Output
For each test case output a single integer β the length of the longest strange subsequence of a.
Example
Input
6
4
-1 -2 0 0
7
-3 4 -2 0 -4 6 1
5
0 5 -3 2 -5
3
2 3 1
4
-3 0 2 0
6
-3 -2 -1 1 1 1
Output
4
5
4
1
3
4
Note
In the first test case, one of the longest strange subsequences is (a_1, a_2, a_3, a_4)
In the second test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5, a_7).
In the third test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5).
In the fourth test case, one of the longest strange subsequences is (a_2).
In the fifth test case, one of the longest strange subsequences is (a_1, a_2, a_4).
Submitted Solution:
```
from sys import stdin,stdout
stdin.readline
def mp(): return list(map(int, stdin.readline().strip().split()))
def it():return int(stdin.readline().strip())
from collections import defaultdict as dd,Counter as C,deque
from math import ceil,gcd,sqrt,factorial,log2,floor
from bisect import bisect_right as br,bisect_left as bl
for _ in range(it()):
n = it()
l = sorted(mp())
stack = [l[0]]
ans = 1
for i in range(1,n):
if abs(stack[-1] - l[i]) < l[i] or (stack[-1] == l[i] and l[-1] != 0):
continue
else:
stack.append(l[i])
ans += 1
print(ans)
``` | instruction | 0 | 34,536 | 12 | 69,072 |
No | output | 1 | 34,536 | 12 | 69,073 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A sequence (b_1, b_2, β¦, b_k) is called strange, if the absolute difference between any pair of its elements is greater than or equal to the maximum element in the sequence. Formally speaking, it's strange if for every pair (i, j) with 1 β€ i<j β€ k, we have |a_i-a_j|β₯ MAX, where MAX is the largest element of the sequence. In particular, any sequence of length at most 1 is strange.
For example, the sequences (-2021, -1, -1, -1) and (-1, 0, 1) are strange, but (3, 0, 1) is not, because |0 - 1| < 3.
Sifid has an array a of n integers. Sifid likes everything big, so among all the strange subsequences of a, he wants to find the length of the longest one. Can you help him?
A sequence c is a subsequence of an array d if c can be obtained from d by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 10^4) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 10^5) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (-10^9β€ a_i β€ 10^9) β the elements of the array a.
It is guaranteed that the sum of n over all test cases doesn't exceed 10^5.
Output
For each test case output a single integer β the length of the longest strange subsequence of a.
Example
Input
6
4
-1 -2 0 0
7
-3 4 -2 0 -4 6 1
5
0 5 -3 2 -5
3
2 3 1
4
-3 0 2 0
6
-3 -2 -1 1 1 1
Output
4
5
4
1
3
4
Note
In the first test case, one of the longest strange subsequences is (a_1, a_2, a_3, a_4)
In the second test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5, a_7).
In the third test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5).
In the fourth test case, one of the longest strange subsequences is (a_2).
In the fifth test case, one of the longest strange subsequences is (a_1, a_2, a_4).
Submitted Solution:
```
#Fast I/O
import sys,os
import math
# To enable the file I/O i the below 2 lines are uncommented.
# read from in.txt if uncommented
if os.path.exists('in.txt'): sys.stdin=open('in.txt','r')
# will print on Console if file I/O is not activated
#if os.path.exists('out.txt'): sys.stdout=open('out.txt', 'w')
# inputs template
from io import BytesIO, IOBase
def main():
for _ in range(int(input())):
n=int(input())
arr=list(MI())
c=0
for i in arr:
if i<=0:
c+=1
if arr.count(0)<=1:
c+=1
print(min(c,n))
# Sample Inputs/Output
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
#for array of integers
def MI():return (map(int,input().split()))
# endregion
#for fast output, always take string
def outP(var): sys.stdout.write(str(var)+'\n')
# end of any user-defined functions
MOD=10**9+7
# main functions for execution of the program.
if __name__ == '__main__':
#This doesn't works here but works wonders when submitted on CodeChef or CodeForces
main()
``` | instruction | 0 | 34,537 | 12 | 69,074 |
No | output | 1 | 34,537 | 12 | 69,075 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A sequence (b_1, b_2, β¦, b_k) is called strange, if the absolute difference between any pair of its elements is greater than or equal to the maximum element in the sequence. Formally speaking, it's strange if for every pair (i, j) with 1 β€ i<j β€ k, we have |a_i-a_j|β₯ MAX, where MAX is the largest element of the sequence. In particular, any sequence of length at most 1 is strange.
For example, the sequences (-2021, -1, -1, -1) and (-1, 0, 1) are strange, but (3, 0, 1) is not, because |0 - 1| < 3.
Sifid has an array a of n integers. Sifid likes everything big, so among all the strange subsequences of a, he wants to find the length of the longest one. Can you help him?
A sequence c is a subsequence of an array d if c can be obtained from d by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 10^4) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 10^5) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (-10^9β€ a_i β€ 10^9) β the elements of the array a.
It is guaranteed that the sum of n over all test cases doesn't exceed 10^5.
Output
For each test case output a single integer β the length of the longest strange subsequence of a.
Example
Input
6
4
-1 -2 0 0
7
-3 4 -2 0 -4 6 1
5
0 5 -3 2 -5
3
2 3 1
4
-3 0 2 0
6
-3 -2 -1 1 1 1
Output
4
5
4
1
3
4
Note
In the first test case, one of the longest strange subsequences is (a_1, a_2, a_3, a_4)
In the second test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5, a_7).
In the third test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5).
In the fourth test case, one of the longest strange subsequences is (a_2).
In the fifth test case, one of the longest strange subsequences is (a_1, a_2, a_4).
Submitted Solution:
```
# import sys
# sys.stdin=open('input.txt','r')
# sys.stdout=open('output.txt','w')
import sys
import math
import heapq
def input(): return sys.stdin.readline().strip("\n")
def I(): return (input())
def II(): return (int(input()))
def MI(): return (map(int,input().split()))
def LI(): return (list(map(int,input().split())))
def isPerfectSquare(x): return (int(math.sqrt(x))**2 == x)
from collections import Counter
for _ in range(II()):
n = II()
a = LI()
count = 0
a.sort()
for i in range(n-1):
for j in range(i+1,n):
if a[j] > a[i]:
# print(a[j],a[i])
a[j] = 0
count += 1
break;
print(count)
``` | instruction | 0 | 34,538 | 12 | 69,076 |
No | output | 1 | 34,538 | 12 | 69,077 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A sequence (b_1, b_2, β¦, b_k) is called strange, if the absolute difference between any pair of its elements is greater than or equal to the maximum element in the sequence. Formally speaking, it's strange if for every pair (i, j) with 1 β€ i<j β€ k, we have |a_i-a_j|β₯ MAX, where MAX is the largest element of the sequence. In particular, any sequence of length at most 1 is strange.
For example, the sequences (-2021, -1, -1, -1) and (-1, 0, 1) are strange, but (3, 0, 1) is not, because |0 - 1| < 3.
Sifid has an array a of n integers. Sifid likes everything big, so among all the strange subsequences of a, he wants to find the length of the longest one. Can you help him?
A sequence c is a subsequence of an array d if c can be obtained from d by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 10^4) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 10^5) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (-10^9β€ a_i β€ 10^9) β the elements of the array a.
It is guaranteed that the sum of n over all test cases doesn't exceed 10^5.
Output
For each test case output a single integer β the length of the longest strange subsequence of a.
Example
Input
6
4
-1 -2 0 0
7
-3 4 -2 0 -4 6 1
5
0 5 -3 2 -5
3
2 3 1
4
-3 0 2 0
6
-3 -2 -1 1 1 1
Output
4
5
4
1
3
4
Note
In the first test case, one of the longest strange subsequences is (a_1, a_2, a_3, a_4)
In the second test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5, a_7).
In the third test case, one of the longest strange subsequences is (a_1, a_3, a_4, a_5).
In the fourth test case, one of the longest strange subsequences is (a_2).
In the fifth test case, one of the longest strange subsequences is (a_1, a_2, a_4).
Submitted Solution:
```
for i in range(int(input())):
n=int(input())
a=list(map(int,input().split()))
if(max(a)<=0):
print(n)
elif(min(a)>0):
print(1)
else:
ans=0
a1 = sorted(a)
diff = 10**20
j=0
b=[]
while(a1[j]<=0):
ans+=1
j+=1
b.append(a1[j])
x=a1[j]
for j in range(len(b)-1):
if b[j+1] - b[j] < diff:
diff = b[j+1] - b[j]
if(diff<0):
diff=-diff
if(x-b[len(b)-1]<=diff):
diff=x-b[len(b)-1]
if(x<=diff):
ans+=1
print(ans)
``` | instruction | 0 | 34,539 | 12 | 69,078 |
No | output | 1 | 34,539 | 12 | 69,079 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The little girl loves the problems on array queries very much.
One day she came across a rather well-known problem: you've got an array of n elements (the elements of the array are indexed starting from 1); also, there are q queries, each one is defined by a pair of integers l_i, r_i (1 β€ l_i β€ r_i β€ n). You need to find for each query the sum of elements of the array with indexes from l_i to r_i, inclusive.
The little girl found the problem rather boring. She decided to reorder the array elements before replying to the queries in a way that makes the sum of query replies maximum possible. Your task is to find the value of this maximum sum.
Input
The first line contains two space-separated integers n (1 β€ n β€ 2β
10^5) and q (1 β€ q β€ 2β
10^5) β the number of elements in the array and the number of queries, correspondingly.
The next line contains n space-separated integers a_i (1 β€ a_i β€ 2β
10^5) β the array elements.
Each of the following q lines contains two space-separated integers l_i and r_i (1 β€ l_i β€ r_i β€ n) β the i-th query.
Output
In a single line print, a single integer β the maximum sum of query replies after the array elements are reordered.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
3 3
5 3 2
1 2
2 3
1 3
Output
25
Input
5 3
5 2 4 1 3
1 5
2 3
2 3
Output
33 | instruction | 0 | 34,568 | 12 | 69,136 |
Tags: data structures, greedy, implementation, sortings
Correct Solution:
```
from sys import *
def input():
return stdin.readline()[:-1]
def initailze(a):
n=len(a);d=[0]*(n+1);d[0]=a[0];d[n]=0;
for i in range(1,n):
d[i]=a[i]-a[i-1]
return d
def update(d,l,r,x):
d[l]+=x;d[r+1]-=x
def printarray(a,d):
l=[]
for i in range(0,len(a)):
if i==0:
a[i]=d[i]
else:
a[i]=d[i]+a[i-1]
l.append(a[i])
return l
n,q=map(int,input().split())
orig=[int(i) for i in input().split()]
a=[0]*n;d=initailze(a);sm=0
for _ in range(q):
x,y=map(int,input().split())
x-=1;y-=1;update(d,x,y,1)
fin=printarray(a,d);orig.sort(reverse=True);fin.sort(reverse=True)
for i in range(n):
sm+=(fin[i]*orig[i])
print(sm)
``` | output | 1 | 34,568 | 12 | 69,137 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The little girl loves the problems on array queries very much.
One day she came across a rather well-known problem: you've got an array of n elements (the elements of the array are indexed starting from 1); also, there are q queries, each one is defined by a pair of integers l_i, r_i (1 β€ l_i β€ r_i β€ n). You need to find for each query the sum of elements of the array with indexes from l_i to r_i, inclusive.
The little girl found the problem rather boring. She decided to reorder the array elements before replying to the queries in a way that makes the sum of query replies maximum possible. Your task is to find the value of this maximum sum.
Input
The first line contains two space-separated integers n (1 β€ n β€ 2β
10^5) and q (1 β€ q β€ 2β
10^5) β the number of elements in the array and the number of queries, correspondingly.
The next line contains n space-separated integers a_i (1 β€ a_i β€ 2β
10^5) β the array elements.
Each of the following q lines contains two space-separated integers l_i and r_i (1 β€ l_i β€ r_i β€ n) β the i-th query.
Output
In a single line print, a single integer β the maximum sum of query replies after the array elements are reordered.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
3 3
5 3 2
1 2
2 3
1 3
Output
25
Input
5 3
5 2 4 1 3
1 5
2 3
2 3
Output
33 | instruction | 0 | 34,569 | 12 | 69,138 |
Tags: data structures, greedy, implementation, sortings
Correct Solution:
```
N, Q = map(int, input().split())
array = list(map(int, input().split()))
array.sort()
count = [0 for i in range(N+1)]
for q in range(Q):
l, r = map(int, input().split())
count[l-1] += 1
count[r] -= 1
for i in range(1, N):
count[i] += count[i-1]
count.sort()
res = 0
for i in range(N):
res += count[i+1] * array[i]
print(res)
``` | output | 1 | 34,569 | 12 | 69,139 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The little girl loves the problems on array queries very much.
One day she came across a rather well-known problem: you've got an array of n elements (the elements of the array are indexed starting from 1); also, there are q queries, each one is defined by a pair of integers l_i, r_i (1 β€ l_i β€ r_i β€ n). You need to find for each query the sum of elements of the array with indexes from l_i to r_i, inclusive.
The little girl found the problem rather boring. She decided to reorder the array elements before replying to the queries in a way that makes the sum of query replies maximum possible. Your task is to find the value of this maximum sum.
Input
The first line contains two space-separated integers n (1 β€ n β€ 2β
10^5) and q (1 β€ q β€ 2β
10^5) β the number of elements in the array and the number of queries, correspondingly.
The next line contains n space-separated integers a_i (1 β€ a_i β€ 2β
10^5) β the array elements.
Each of the following q lines contains two space-separated integers l_i and r_i (1 β€ l_i β€ r_i β€ n) β the i-th query.
Output
In a single line print, a single integer β the maximum sum of query replies after the array elements are reordered.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
3 3
5 3 2
1 2
2 3
1 3
Output
25
Input
5 3
5 2 4 1 3
1 5
2 3
2 3
Output
33 | instruction | 0 | 34,570 | 12 | 69,140 |
Tags: data structures, greedy, implementation, sortings
Correct Solution:
```
from collections import Counter,defaultdict,deque
import heapq as hq
#alph = 'abcdefghijklmnopqrstuvwxyz'
#from math import factorial as fact
#nl = '\n'
#import sys
#input=sys.stdin.readline
#print=sys.stdout.write
#tt = int(input())
#total=0
#n = int(input())
#n,m,k = [int(x) for x in input().split()]
#n = int(input())
#l,r = [int(x) for x in input().split()]
n,q = [int(x) for x in input().split()]
arr = [int(x) for x in input().split()]
c = [0]*(n+1)
for i in range(q):
l,r = [int(x)-1 for x in input().split()]
c[l]+=1
c[r+1]-=1
for i in range(len(c)-1):
c[i+1]+=c[i]
c.pop()
c.sort()
arr.sort()
total = 0
for i in range(n):
total+=c[i]*arr[i]
print(total)
``` | output | 1 | 34,570 | 12 | 69,141 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The little girl loves the problems on array queries very much.
One day she came across a rather well-known problem: you've got an array of n elements (the elements of the array are indexed starting from 1); also, there are q queries, each one is defined by a pair of integers l_i, r_i (1 β€ l_i β€ r_i β€ n). You need to find for each query the sum of elements of the array with indexes from l_i to r_i, inclusive.
The little girl found the problem rather boring. She decided to reorder the array elements before replying to the queries in a way that makes the sum of query replies maximum possible. Your task is to find the value of this maximum sum.
Input
The first line contains two space-separated integers n (1 β€ n β€ 2β
10^5) and q (1 β€ q β€ 2β
10^5) β the number of elements in the array and the number of queries, correspondingly.
The next line contains n space-separated integers a_i (1 β€ a_i β€ 2β
10^5) β the array elements.
Each of the following q lines contains two space-separated integers l_i and r_i (1 β€ l_i β€ r_i β€ n) β the i-th query.
Output
In a single line print, a single integer β the maximum sum of query replies after the array elements are reordered.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
3 3
5 3 2
1 2
2 3
1 3
Output
25
Input
5 3
5 2 4 1 3
1 5
2 3
2 3
Output
33 | instruction | 0 | 34,571 | 12 | 69,142 |
Tags: data structures, greedy, implementation, sortings
Correct Solution:
```
from sys import stdin
n, q = map(int, stdin.readline().split())
a = list(map(int, stdin.readline().split()))
queries = [tuple(map(lambda x: int(x) - 1, stdin.readline().split())) for _ in range(q)]
def sumRange(left, right):
return psums[right + 1] - psums[left]
add = [0] * (n + 1)
for left, right in queries:
add[left] += 1
add[right + 1] -= 1
freq = []
curSum = 0
for i in range(n):
curSum += add[i]
freq.append((i, curSum))
freq.sort(key=lambda x: -x[1])
a.sort(reverse=True)
best = [0] * n
for i, (pos, _) in enumerate(freq):
best[pos] = a[i]
psums = [0]
for val in best:
psums.append(psums[-1] + val)
ret = 0
for left, right in queries:
ret += sumRange(left, right)
print(ret)
``` | output | 1 | 34,571 | 12 | 69,143 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The little girl loves the problems on array queries very much.
One day she came across a rather well-known problem: you've got an array of n elements (the elements of the array are indexed starting from 1); also, there are q queries, each one is defined by a pair of integers l_i, r_i (1 β€ l_i β€ r_i β€ n). You need to find for each query the sum of elements of the array with indexes from l_i to r_i, inclusive.
The little girl found the problem rather boring. She decided to reorder the array elements before replying to the queries in a way that makes the sum of query replies maximum possible. Your task is to find the value of this maximum sum.
Input
The first line contains two space-separated integers n (1 β€ n β€ 2β
10^5) and q (1 β€ q β€ 2β
10^5) β the number of elements in the array and the number of queries, correspondingly.
The next line contains n space-separated integers a_i (1 β€ a_i β€ 2β
10^5) β the array elements.
Each of the following q lines contains two space-separated integers l_i and r_i (1 β€ l_i β€ r_i β€ n) β the i-th query.
Output
In a single line print, a single integer β the maximum sum of query replies after the array elements are reordered.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
3 3
5 3 2
1 2
2 3
1 3
Output
25
Input
5 3
5 2 4 1 3
1 5
2 3
2 3
Output
33 | instruction | 0 | 34,572 | 12 | 69,144 |
Tags: data structures, greedy, implementation, sortings
Correct Solution:
```
class BIT:
def __init__(self,l):
self._freq = [0]*l
def add_region(self,l,r):
self._freq[l] += 1
try:
self._freq[r+1] -= 1
except IndexError:
pass
def get_freq(self):
ans = []
cur_sum = 0
for i in range(len(self._freq)):
cur_sum += self._freq[i]
ans.append(cur_sum)
return ans
n,q = map(int,input().split())
iniarr = [int(x) for x in input().split()]
freq = BIT(n)
for i in range(q):
l,r = map(int,input().split())
freq.add_region(l-1,r-1)
ansfreq = sorted(freq.get_freq(),reverse = True)
iniarr.sort(reverse = True)
ans = 0
for i in range(n):
ans += ansfreq[i]*iniarr[i]
print(ans)
``` | output | 1 | 34,572 | 12 | 69,145 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The little girl loves the problems on array queries very much.
One day she came across a rather well-known problem: you've got an array of n elements (the elements of the array are indexed starting from 1); also, there are q queries, each one is defined by a pair of integers l_i, r_i (1 β€ l_i β€ r_i β€ n). You need to find for each query the sum of elements of the array with indexes from l_i to r_i, inclusive.
The little girl found the problem rather boring. She decided to reorder the array elements before replying to the queries in a way that makes the sum of query replies maximum possible. Your task is to find the value of this maximum sum.
Input
The first line contains two space-separated integers n (1 β€ n β€ 2β
10^5) and q (1 β€ q β€ 2β
10^5) β the number of elements in the array and the number of queries, correspondingly.
The next line contains n space-separated integers a_i (1 β€ a_i β€ 2β
10^5) β the array elements.
Each of the following q lines contains two space-separated integers l_i and r_i (1 β€ l_i β€ r_i β€ n) β the i-th query.
Output
In a single line print, a single integer β the maximum sum of query replies after the array elements are reordered.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
3 3
5 3 2
1 2
2 3
1 3
Output
25
Input
5 3
5 2 4 1 3
1 5
2 3
2 3
Output
33 | instruction | 0 | 34,573 | 12 | 69,146 |
Tags: data structures, greedy, implementation, sortings
Correct Solution:
```
import sys
input=sys.stdin.readline
n,q=map(int,input().split())
b=list(map(int,input().split()))
a=[0]*(n)
for i in range(q):
l,r=map(int,input().split())
a[l-1]+=1
if(r<n):
a[r]-=1
for i in range(1,n):
a[i]+=a[i-1]
a.sort(reverse=True)
b.sort(reverse=True)
res=0
for i in range(n):
res+=(a[i]*b[i])
print(res)
``` | output | 1 | 34,573 | 12 | 69,147 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The little girl loves the problems on array queries very much.
One day she came across a rather well-known problem: you've got an array of n elements (the elements of the array are indexed starting from 1); also, there are q queries, each one is defined by a pair of integers l_i, r_i (1 β€ l_i β€ r_i β€ n). You need to find for each query the sum of elements of the array with indexes from l_i to r_i, inclusive.
The little girl found the problem rather boring. She decided to reorder the array elements before replying to the queries in a way that makes the sum of query replies maximum possible. Your task is to find the value of this maximum sum.
Input
The first line contains two space-separated integers n (1 β€ n β€ 2β
10^5) and q (1 β€ q β€ 2β
10^5) β the number of elements in the array and the number of queries, correspondingly.
The next line contains n space-separated integers a_i (1 β€ a_i β€ 2β
10^5) β the array elements.
Each of the following q lines contains two space-separated integers l_i and r_i (1 β€ l_i β€ r_i β€ n) β the i-th query.
Output
In a single line print, a single integer β the maximum sum of query replies after the array elements are reordered.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
3 3
5 3 2
1 2
2 3
1 3
Output
25
Input
5 3
5 2 4 1 3
1 5
2 3
2 3
Output
33 | instruction | 0 | 34,574 | 12 | 69,148 |
Tags: data structures, greedy, implementation, sortings
Correct Solution:
```
n,q = map(int,input().strip().split())
A = list(map(int,input().strip().split()))
A.sort()
M = [0]*n
for i in range(q):
l,r = map(int,input().strip().split())
l = l-1
M[l]=M[l]+1
if r<n:
M[r] = M[r]-1
for i in range(1,n):
M[i]=M[i-1]+M[i]
M.sort()
s = 0
for i in range(n):
s+=M[i]*A[i]
print(s)
``` | output | 1 | 34,574 | 12 | 69,149 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The little girl loves the problems on array queries very much.
One day she came across a rather well-known problem: you've got an array of n elements (the elements of the array are indexed starting from 1); also, there are q queries, each one is defined by a pair of integers l_i, r_i (1 β€ l_i β€ r_i β€ n). You need to find for each query the sum of elements of the array with indexes from l_i to r_i, inclusive.
The little girl found the problem rather boring. She decided to reorder the array elements before replying to the queries in a way that makes the sum of query replies maximum possible. Your task is to find the value of this maximum sum.
Input
The first line contains two space-separated integers n (1 β€ n β€ 2β
10^5) and q (1 β€ q β€ 2β
10^5) β the number of elements in the array and the number of queries, correspondingly.
The next line contains n space-separated integers a_i (1 β€ a_i β€ 2β
10^5) β the array elements.
Each of the following q lines contains two space-separated integers l_i and r_i (1 β€ l_i β€ r_i β€ n) β the i-th query.
Output
In a single line print, a single integer β the maximum sum of query replies after the array elements are reordered.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
3 3
5 3 2
1 2
2 3
1 3
Output
25
Input
5 3
5 2 4 1 3
1 5
2 3
2 3
Output
33 | instruction | 0 | 34,575 | 12 | 69,150 |
Tags: data structures, greedy, implementation, sortings
Correct Solution:
```
fast=lambda:stdin.readline().strip()
zzz=lambda:[int(i) for i in fast().split()]
z,zz=input,lambda:list(map(int,z().split()))
szz,graph,mod,szzz=lambda:sorted(zz()),{},10**9+7,lambda:sorted(zzz())
from re import *
from sys import *
from math import *
from heapq import *
from queue import *
from bisect import *
from string import *
from itertools import *
from collections import *
from math import factorial as f
from bisect import bisect as bs
from bisect import bisect_left as bsl
from collections import Counter as cc
from itertools import accumulate as ac
def lcd(xnum1,xnum2):return (xnum1*xnum2//gcd(xnum1,xnum2))
def output(answer):stdout.write(str(answer))
###########################---Test-Case---#################################
"""
If you think,You Know me , Then you probably don't know me !
"""
###########################---START-CODING---##############################
n,q=zzz()
arr=szzz()
lst=[0]*n
for _ in range(q):
l,r=zzz()
lst[l-1]+=1
try:
lst[r]-=1
except:pass
for i in range(1,n):
lst[i]+=lst[i-1]
lst.sort()
print(sum(arr[i]*lst[i] for i in range(n)))
``` | output | 1 | 34,575 | 12 | 69,151 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The little girl loves the problems on array queries very much.
One day she came across a rather well-known problem: you've got an array of n elements (the elements of the array are indexed starting from 1); also, there are q queries, each one is defined by a pair of integers l_i, r_i (1 β€ l_i β€ r_i β€ n). You need to find for each query the sum of elements of the array with indexes from l_i to r_i, inclusive.
The little girl found the problem rather boring. She decided to reorder the array elements before replying to the queries in a way that makes the sum of query replies maximum possible. Your task is to find the value of this maximum sum.
Input
The first line contains two space-separated integers n (1 β€ n β€ 2β
10^5) and q (1 β€ q β€ 2β
10^5) β the number of elements in the array and the number of queries, correspondingly.
The next line contains n space-separated integers a_i (1 β€ a_i β€ 2β
10^5) β the array elements.
Each of the following q lines contains two space-separated integers l_i and r_i (1 β€ l_i β€ r_i β€ n) β the i-th query.
Output
In a single line print, a single integer β the maximum sum of query replies after the array elements are reordered.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
3 3
5 3 2
1 2
2 3
1 3
Output
25
Input
5 3
5 2 4 1 3
1 5
2 3
2 3
Output
33
Submitted Solution:
```
#b=b[2:].zfill(32)
#for deque append(),pop(),appendleft(),popleft(),count()
import math,sys
from collections import Counter, defaultdict, deque
from sys import stdin, stdout
input = stdin.readline
lili=lambda:list(map(int,sys.stdin.readlines()))
li = lambda:list(map(int,input().split()))
I=lambda:int(input())
S=lambda:input().strip()
mod = 1000000007
def initializeDiffArray( A):
n = len(A)
D = [0 for i in range(0 , n + 1)]
D[0] = A[0]; D[n] = 0
for i in range(1, n ):
D[i] = A[i] - A[i - 1]
return D
def update(D, l, r, x):
D[l] += x
D[r + 1] -= x
def printArray(A, D):
for i in range(0 , len(A)):
if (i == 0):
A[i] = D[i]
else:
A[i] = D[i] + A[i - 1]
n,q=list(map(int,input().split()))
a=list(map(int,input().split()))
A=[]
for i in range(n):
A.append(0)
D=initializeDiffArray(A)
for i in range(q):
l,r=list(map(int,input().split()))
update(D,l-1,r-1,1)
printArray(A,D)
A.sort()
a.sort()
s=0
for i in range(n):
s+=a[i]*A[i]
print(s)
``` | instruction | 0 | 34,576 | 12 | 69,152 |
Yes | output | 1 | 34,576 | 12 | 69,153 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The little girl loves the problems on array queries very much.
One day she came across a rather well-known problem: you've got an array of n elements (the elements of the array are indexed starting from 1); also, there are q queries, each one is defined by a pair of integers l_i, r_i (1 β€ l_i β€ r_i β€ n). You need to find for each query the sum of elements of the array with indexes from l_i to r_i, inclusive.
The little girl found the problem rather boring. She decided to reorder the array elements before replying to the queries in a way that makes the sum of query replies maximum possible. Your task is to find the value of this maximum sum.
Input
The first line contains two space-separated integers n (1 β€ n β€ 2β
10^5) and q (1 β€ q β€ 2β
10^5) β the number of elements in the array and the number of queries, correspondingly.
The next line contains n space-separated integers a_i (1 β€ a_i β€ 2β
10^5) β the array elements.
Each of the following q lines contains two space-separated integers l_i and r_i (1 β€ l_i β€ r_i β€ n) β the i-th query.
Output
In a single line print, a single integer β the maximum sum of query replies after the array elements are reordered.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
3 3
5 3 2
1 2
2 3
1 3
Output
25
Input
5 3
5 2 4 1 3
1 5
2 3
2 3
Output
33
Submitted Solution:
```
def fastio():
import sys
from io import StringIO
from atexit import register
global input
sys.stdin = StringIO(sys.stdin.read())
input = lambda : sys.stdin.readline().rstrip('\r\n')
sys.stdout = StringIO()
register(lambda : sys.__stdout__.write(sys.stdout.getvalue()))
fastio()
MOD = 10**9 + 7
I = lambda:list(map(int,input().split()))
n, q = I()
l = I()
l.sort(reverse = True)
a = []
c = [0]*(200005)
for i in range(q):
x, y = I()
x -= 1
y -= 1
a.append([x, y])
c[x] += 1
c[y+1] -= 1
for i in range(200005):
c[i] += c[i-1]
c.sort(reverse = True)
ans = 0
for i in range(n):
ans += c[i]*l[i]
print(ans)
``` | instruction | 0 | 34,577 | 12 | 69,154 |
Yes | output | 1 | 34,577 | 12 | 69,155 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The little girl loves the problems on array queries very much.
One day she came across a rather well-known problem: you've got an array of n elements (the elements of the array are indexed starting from 1); also, there are q queries, each one is defined by a pair of integers l_i, r_i (1 β€ l_i β€ r_i β€ n). You need to find for each query the sum of elements of the array with indexes from l_i to r_i, inclusive.
The little girl found the problem rather boring. She decided to reorder the array elements before replying to the queries in a way that makes the sum of query replies maximum possible. Your task is to find the value of this maximum sum.
Input
The first line contains two space-separated integers n (1 β€ n β€ 2β
10^5) and q (1 β€ q β€ 2β
10^5) β the number of elements in the array and the number of queries, correspondingly.
The next line contains n space-separated integers a_i (1 β€ a_i β€ 2β
10^5) β the array elements.
Each of the following q lines contains two space-separated integers l_i and r_i (1 β€ l_i β€ r_i β€ n) β the i-th query.
Output
In a single line print, a single integer β the maximum sum of query replies after the array elements are reordered.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
3 3
5 3 2
1 2
2 3
1 3
Output
25
Input
5 3
5 2 4 1 3
1 5
2 3
2 3
Output
33
Submitted Solution:
```
n,q= map(int,input().split())
l = list(map(int,input().split()))
arr= [0]*n
for i in range(q):
a,b= map(int,input().split())
arr[a-1] +=1
if(b<n):
arr[b] -=1
val= 0
for i in range(n):
val =val+arr[i]
arr[i]= val
arr.sort()
l.sort()
ans =0
for i in range(n):
ans +=arr[i]*l[i]
print(ans)
``` | instruction | 0 | 34,578 | 12 | 69,156 |
Yes | output | 1 | 34,578 | 12 | 69,157 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The little girl loves the problems on array queries very much.
One day she came across a rather well-known problem: you've got an array of n elements (the elements of the array are indexed starting from 1); also, there are q queries, each one is defined by a pair of integers l_i, r_i (1 β€ l_i β€ r_i β€ n). You need to find for each query the sum of elements of the array with indexes from l_i to r_i, inclusive.
The little girl found the problem rather boring. She decided to reorder the array elements before replying to the queries in a way that makes the sum of query replies maximum possible. Your task is to find the value of this maximum sum.
Input
The first line contains two space-separated integers n (1 β€ n β€ 2β
10^5) and q (1 β€ q β€ 2β
10^5) β the number of elements in the array and the number of queries, correspondingly.
The next line contains n space-separated integers a_i (1 β€ a_i β€ 2β
10^5) β the array elements.
Each of the following q lines contains two space-separated integers l_i and r_i (1 β€ l_i β€ r_i β€ n) β the i-th query.
Output
In a single line print, a single integer β the maximum sum of query replies after the array elements are reordered.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
3 3
5 3 2
1 2
2 3
1 3
Output
25
Input
5 3
5 2 4 1 3
1 5
2 3
2 3
Output
33
Submitted Solution:
```
inp = lambda: map(int, input().rstrip().split())
n, q = inp()
li = sorted(inp())
a = [0] * (n + 1)
for _ in range(q):
x, y = inp()
a[x - 1] += 1
a[y] -= 1
for i in range(n):
a[i + 1] += a[i]
# a.sort(reverse=True)
# li.sort()
# t = 0
# for i in range(n):
# t += a[i] * li[i]
print(sum(map(lambda x: x[0] * x[1], zip(li, sorted(a[:-1])))))
``` | instruction | 0 | 34,579 | 12 | 69,158 |
Yes | output | 1 | 34,579 | 12 | 69,159 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The little girl loves the problems on array queries very much.
One day she came across a rather well-known problem: you've got an array of n elements (the elements of the array are indexed starting from 1); also, there are q queries, each one is defined by a pair of integers l_i, r_i (1 β€ l_i β€ r_i β€ n). You need to find for each query the sum of elements of the array with indexes from l_i to r_i, inclusive.
The little girl found the problem rather boring. She decided to reorder the array elements before replying to the queries in a way that makes the sum of query replies maximum possible. Your task is to find the value of this maximum sum.
Input
The first line contains two space-separated integers n (1 β€ n β€ 2β
10^5) and q (1 β€ q β€ 2β
10^5) β the number of elements in the array and the number of queries, correspondingly.
The next line contains n space-separated integers a_i (1 β€ a_i β€ 2β
10^5) β the array elements.
Each of the following q lines contains two space-separated integers l_i and r_i (1 β€ l_i β€ r_i β€ n) β the i-th query.
Output
In a single line print, a single integer β the maximum sum of query replies after the array elements are reordered.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
3 3
5 3 2
1 2
2 3
1 3
Output
25
Input
5 3
5 2 4 1 3
1 5
2 3
2 3
Output
33
Submitted Solution:
```
# from debug import debug
# from math import ceil, log2
n, m = map(int, input().split())
lis = sorted(list(map(int, input().split())), reverse=True)
s = [0]*n
e = [0]*n
for i in range(m):
a, b = map(int, input().split())
s[a-1] += 1
e[b-1] += 1
store = []
last = 0
start = 0
end = 0
d = 0
for i in range(n):
if s[i] and not e[i]:
store.append(((start-end)*d,start-end, d))
start+=s[i]
d = 1
elif not s[i] and e[i]:
d+=1
store.append(((start-end)*d,start-end, d))
end+=e[i]
d = 0
elif s[i] and e[i]:
store.append(((start-end)*d,start-end, d))
store.append((s[i]+start-end,s[i]+start-end, 1))
start+=s[i]
end += e[i]
d=0
else:
d+=1
l = 0
ans = 0
store.sort(reverse=True)
for i in range(len(store)-1):
_,b,c = store[i]
ans += sum(lis[l:c+l])*b
l += c
print(ans)
``` | instruction | 0 | 34,580 | 12 | 69,160 |
No | output | 1 | 34,580 | 12 | 69,161 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The little girl loves the problems on array queries very much.
One day she came across a rather well-known problem: you've got an array of n elements (the elements of the array are indexed starting from 1); also, there are q queries, each one is defined by a pair of integers l_i, r_i (1 β€ l_i β€ r_i β€ n). You need to find for each query the sum of elements of the array with indexes from l_i to r_i, inclusive.
The little girl found the problem rather boring. She decided to reorder the array elements before replying to the queries in a way that makes the sum of query replies maximum possible. Your task is to find the value of this maximum sum.
Input
The first line contains two space-separated integers n (1 β€ n β€ 2β
10^5) and q (1 β€ q β€ 2β
10^5) β the number of elements in the array and the number of queries, correspondingly.
The next line contains n space-separated integers a_i (1 β€ a_i β€ 2β
10^5) β the array elements.
Each of the following q lines contains two space-separated integers l_i and r_i (1 β€ l_i β€ r_i β€ n) β the i-th query.
Output
In a single line print, a single integer β the maximum sum of query replies after the array elements are reordered.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
3 3
5 3 2
1 2
2 3
1 3
Output
25
Input
5 3
5 2 4 1 3
1 5
2 3
2 3
Output
33
Submitted Solution:
```
# n = int(input())
# l = list(map(int, input().split()))
# n, m, k = [int(x) for x in input().split()]
import collections
n, q = [int(x) for x in input().split()]
a = list(map(int, input().split()))
ind = [0] * (n + 1)
chh = []
while q:
q -= 1
l, r = [int(x) for x in input().split()]
chh.append([l, r])
ind[l - 1] += 1
ind[r] -= 1
for i in range(1, n):
ind[i] = ind[i - 1] + ind[i]
# print("ind ", ind)
a.sort(reverse = True)
i = 0
b = [0] * n
for i in range(n):
tem = ind.index(max(ind))
b[tem] = a[i]
i += 1
ind[tem] = 0
# print("b ", b)
for i in range(1, n):
b[i] = b[i - 1] + b[i]
# print("cum b ", b)
# print("chh ", chh)
finan = 0
for i in chh:
if i[0] != 1: finan += b[i[1] - 1] - b[i[0] - 1 - 1]
elif i[0] == 1: finan += b[i[1] - 1]
print(finan)
``` | instruction | 0 | 34,581 | 12 | 69,162 |
No | output | 1 | 34,581 | 12 | 69,163 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The little girl loves the problems on array queries very much.
One day she came across a rather well-known problem: you've got an array of n elements (the elements of the array are indexed starting from 1); also, there are q queries, each one is defined by a pair of integers l_i, r_i (1 β€ l_i β€ r_i β€ n). You need to find for each query the sum of elements of the array with indexes from l_i to r_i, inclusive.
The little girl found the problem rather boring. She decided to reorder the array elements before replying to the queries in a way that makes the sum of query replies maximum possible. Your task is to find the value of this maximum sum.
Input
The first line contains two space-separated integers n (1 β€ n β€ 2β
10^5) and q (1 β€ q β€ 2β
10^5) β the number of elements in the array and the number of queries, correspondingly.
The next line contains n space-separated integers a_i (1 β€ a_i β€ 2β
10^5) β the array elements.
Each of the following q lines contains two space-separated integers l_i and r_i (1 β€ l_i β€ r_i β€ n) β the i-th query.
Output
In a single line print, a single integer β the maximum sum of query replies after the array elements are reordered.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
3 3
5 3 2
1 2
2 3
1 3
Output
25
Input
5 3
5 2 4 1 3
1 5
2 3
2 3
Output
33
Submitted Solution:
```
n,q = map(int, input().split())
array = [int(i)for i in input().split()]
array.sort(key=lambda x: -x)
print(array)
arr = []
for i in range(q):
a,b = map(int, input().split())
arr.append([a, True])
arr.append([b+1, False])
arr.sort(key = lambda x: x[0])
count = 0
index = 0
prev = 1
l = []
length = 0
for i in range(2*q):
v = arr[i][0]
left = arr[i][1]
if v != prev:
l += [count] * (v-prev)
length += v-prev
prev = v
count += (1 if left else -1)
l.sort(key = lambda x: -x)
print(l)
ans = 0
for i in range(length):
ans += array[i] * l[i]
print(ans)
``` | instruction | 0 | 34,582 | 12 | 69,164 |
No | output | 1 | 34,582 | 12 | 69,165 |
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