message stringlengths 2 19.9k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 322 108k | cluster float64 15 15 | __index_level_0__ int64 644 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected.
The pasture is a rectangle consisting of R × C cells. Each cell is either empty, contains a sheep, a wolf or a dog. Sheep and dogs always stay in place, but wolves can roam freely around the pasture, by repeatedly moving to the left, right, up or down to a neighboring cell. When a wolf enters a cell with a sheep, it consumes it. However, no wolf can enter a cell with a dog.
Initially there are no dogs. Place dogs onto the pasture in such a way that no wolf can reach any sheep, or determine that it is impossible. Note that since you have many dogs, you do not need to minimize their number.
Input
First line contains two integers R (1 ≤ R ≤ 500) and C (1 ≤ C ≤ 500), denoting the number of rows and the numbers of columns respectively.
Each of the following R lines is a string consisting of exactly C characters, representing one row of the pasture. Here, 'S' means a sheep, 'W' a wolf and '.' an empty cell.
Output
If it is impossible to protect all sheep, output a single line with the word "No".
Otherwise, output a line with the word "Yes". Then print R lines, representing the pasture after placing dogs. Again, 'S' means a sheep, 'W' a wolf, 'D' is a dog and '.' an empty space. You are not allowed to move, remove or add a sheep or a wolf.
If there are multiple solutions, you may print any of them. You don't have to minimize the number of dogs.
Examples
Input
6 6
..S...
..S.W.
.S....
..W...
...W..
......
Output
Yes
..SD..
..SDW.
.SD...
.DW...
DD.W..
......
Input
1 2
SW
Output
No
Input
5 5
.S...
...S.
S....
...S.
.S...
Output
Yes
.S...
...S.
S.D..
...S.
.S...
Note
In the first example, we can split the pasture into two halves, one containing wolves and one containing sheep. Note that the sheep at (2,1) is safe, as wolves cannot move diagonally.
In the second example, there are no empty spots to put dogs that would guard the lone sheep.
In the third example, there are no wolves, so the task is very easy. We put a dog in the center to observe the peacefulness of the meadow, but the solution would be correct even without him. | instruction | 0 | 13,872 | 15 | 27,744 |
Tags: brute force, dfs and similar, graphs, implementation
Correct Solution:
```
n, m = [int(x) for x in input().split()]
a = [[x for x in input()] for _ in range(n)]
def set(i, j):
if a[i][j] == "S":
return False
elif a[i][j] == ".":
a[i][j] = "D"
return True
flag = True
for i in range(n):
for j in range(m):
if a[i][j] != 'W': continue
if i>0 and not set(i-1, j):
flag = False
if j>0 and not set(i, j-1):
flag = False
if i<n-1 and not set(i+1, j):
flag = False
if j<m-1 and not set(i, j+1):
flag = False
if flag == False:
break
if flag:
print("Yes")
for s in a:
print("".join(s))
else:
print("No")
``` | output | 1 | 13,872 | 15 | 27,745 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected.
The pasture is a rectangle consisting of R × C cells. Each cell is either empty, contains a sheep, a wolf or a dog. Sheep and dogs always stay in place, but wolves can roam freely around the pasture, by repeatedly moving to the left, right, up or down to a neighboring cell. When a wolf enters a cell with a sheep, it consumes it. However, no wolf can enter a cell with a dog.
Initially there are no dogs. Place dogs onto the pasture in such a way that no wolf can reach any sheep, or determine that it is impossible. Note that since you have many dogs, you do not need to minimize their number.
Input
First line contains two integers R (1 ≤ R ≤ 500) and C (1 ≤ C ≤ 500), denoting the number of rows and the numbers of columns respectively.
Each of the following R lines is a string consisting of exactly C characters, representing one row of the pasture. Here, 'S' means a sheep, 'W' a wolf and '.' an empty cell.
Output
If it is impossible to protect all sheep, output a single line with the word "No".
Otherwise, output a line with the word "Yes". Then print R lines, representing the pasture after placing dogs. Again, 'S' means a sheep, 'W' a wolf, 'D' is a dog and '.' an empty space. You are not allowed to move, remove or add a sheep or a wolf.
If there are multiple solutions, you may print any of them. You don't have to minimize the number of dogs.
Examples
Input
6 6
..S...
..S.W.
.S....
..W...
...W..
......
Output
Yes
..SD..
..SDW.
.SD...
.DW...
DD.W..
......
Input
1 2
SW
Output
No
Input
5 5
.S...
...S.
S....
...S.
.S...
Output
Yes
.S...
...S.
S.D..
...S.
.S...
Note
In the first example, we can split the pasture into two halves, one containing wolves and one containing sheep. Note that the sheep at (2,1) is safe, as wolves cannot move diagonally.
In the second example, there are no empty spots to put dogs that would guard the lone sheep.
In the third example, there are no wolves, so the task is very easy. We put a dog in the center to observe the peacefulness of the meadow, but the solution would be correct even without him. | instruction | 0 | 13,873 | 15 | 27,746 |
Tags: brute force, dfs and similar, graphs, implementation
Correct Solution:
```
def main():
r,c = list(map(int,input().split()))
field = [[x for x in input()] for _ in range(r)]
good = True
for i in range(r):
for j in range(c):
if field[i][j] == 'S':
if i>0 and field[i-1][j] == 'W':
good = False
break
if i<r-1 and field[i+1][j] == 'W':
good = False
break
if j>0 and field[i][j-1] == 'W':
good = False
if j<c-1 and field[i][j+1] == 'W':
good = False
break
if not good:
print('NO')
return
for i in range(r):
for j in range(c):
if field[i][j] == '.':
field[i][j] = 'D'
print('YES')
for i in range(r):
print(''.join(field[i]))
if __name__ == '__main__':
main()
``` | output | 1 | 13,873 | 15 | 27,747 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected.
The pasture is a rectangle consisting of R × C cells. Each cell is either empty, contains a sheep, a wolf or a dog. Sheep and dogs always stay in place, but wolves can roam freely around the pasture, by repeatedly moving to the left, right, up or down to a neighboring cell. When a wolf enters a cell with a sheep, it consumes it. However, no wolf can enter a cell with a dog.
Initially there are no dogs. Place dogs onto the pasture in such a way that no wolf can reach any sheep, or determine that it is impossible. Note that since you have many dogs, you do not need to minimize their number.
Input
First line contains two integers R (1 ≤ R ≤ 500) and C (1 ≤ C ≤ 500), denoting the number of rows and the numbers of columns respectively.
Each of the following R lines is a string consisting of exactly C characters, representing one row of the pasture. Here, 'S' means a sheep, 'W' a wolf and '.' an empty cell.
Output
If it is impossible to protect all sheep, output a single line with the word "No".
Otherwise, output a line with the word "Yes". Then print R lines, representing the pasture after placing dogs. Again, 'S' means a sheep, 'W' a wolf, 'D' is a dog and '.' an empty space. You are not allowed to move, remove or add a sheep or a wolf.
If there are multiple solutions, you may print any of them. You don't have to minimize the number of dogs.
Examples
Input
6 6
..S...
..S.W.
.S....
..W...
...W..
......
Output
Yes
..SD..
..SDW.
.SD...
.DW...
DD.W..
......
Input
1 2
SW
Output
No
Input
5 5
.S...
...S.
S....
...S.
.S...
Output
Yes
.S...
...S.
S.D..
...S.
.S...
Note
In the first example, we can split the pasture into two halves, one containing wolves and one containing sheep. Note that the sheep at (2,1) is safe, as wolves cannot move diagonally.
In the second example, there are no empty spots to put dogs that would guard the lone sheep.
In the third example, there are no wolves, so the task is very easy. We put a dog in the center to observe the peacefulness of the meadow, but the solution would be correct even without him. | instruction | 0 | 13,874 | 15 | 27,748 |
Tags: brute force, dfs and similar, graphs, implementation
Correct Solution:
```
def Fill(A,x,y,n,m):
Bool = False
if x>0:
if A[x-1][y] == '.':
A[x-1][y]= 'D'
if A[x-1][y] == 'W':
Bool=True
if y>0:
if A[x][y-1] == '.':
A[x][y-1]= 'D'
if A[x][y-1] == 'W':
Bool=True
if y<m-1:
if A[x][y+1] == '.':
A[x][y+1]= 'D'
if A[x][y+1] == 'W':
Bool=True
if x<n-1:
if A[x+1][y] == '.':
A[x+1][y]= 'D'
if A[x+1][y] == 'W':
Bool=True
return Bool
n,m=list(map(int,input().split()))
A=[]
for _ in range(n):
S=list(input())
A.append(S)
Ans=False
for n1 in range(n):
for n2 in range(m):
if A[n1][n2] == 'S':
Temp = Fill(A,n1,n2,n,m)
if Temp == True:
Ans = True
break
if Ans == True:
break
if Ans == False:
print("Yes")
for val in A:
print(''.join(val))
else:
print("No")
``` | output | 1 | 13,874 | 15 | 27,749 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected.
The pasture is a rectangle consisting of R × C cells. Each cell is either empty, contains a sheep, a wolf or a dog. Sheep and dogs always stay in place, but wolves can roam freely around the pasture, by repeatedly moving to the left, right, up or down to a neighboring cell. When a wolf enters a cell with a sheep, it consumes it. However, no wolf can enter a cell with a dog.
Initially there are no dogs. Place dogs onto the pasture in such a way that no wolf can reach any sheep, or determine that it is impossible. Note that since you have many dogs, you do not need to minimize their number.
Input
First line contains two integers R (1 ≤ R ≤ 500) and C (1 ≤ C ≤ 500), denoting the number of rows and the numbers of columns respectively.
Each of the following R lines is a string consisting of exactly C characters, representing one row of the pasture. Here, 'S' means a sheep, 'W' a wolf and '.' an empty cell.
Output
If it is impossible to protect all sheep, output a single line with the word "No".
Otherwise, output a line with the word "Yes". Then print R lines, representing the pasture after placing dogs. Again, 'S' means a sheep, 'W' a wolf, 'D' is a dog and '.' an empty space. You are not allowed to move, remove or add a sheep or a wolf.
If there are multiple solutions, you may print any of them. You don't have to minimize the number of dogs.
Examples
Input
6 6
..S...
..S.W.
.S....
..W...
...W..
......
Output
Yes
..SD..
..SDW.
.SD...
.DW...
DD.W..
......
Input
1 2
SW
Output
No
Input
5 5
.S...
...S.
S....
...S.
.S...
Output
Yes
.S...
...S.
S.D..
...S.
.S...
Note
In the first example, we can split the pasture into two halves, one containing wolves and one containing sheep. Note that the sheep at (2,1) is safe, as wolves cannot move diagonally.
In the second example, there are no empty spots to put dogs that would guard the lone sheep.
In the third example, there are no wolves, so the task is very easy. We put a dog in the center to observe the peacefulness of the meadow, but the solution would be correct even without him. | instruction | 0 | 13,875 | 15 | 27,750 |
Tags: brute force, dfs and similar, graphs, implementation
Correct Solution:
```
x,y=map(int,input().split())
lol=[]
f=0
for _ in range(x):
a=input()
a=a.replace(".","D")
#print(a)
for i in range(1,y):
if (a[i]=="S" and a[i-1]=="W") or (a[i-1]=="S" and a[i]=="W"):
f=1
break
if f==1:
break
lol.append(a)
if not f and len(lol)>1:
for i in range(x):
for j in range(y):
if i==0:
yo=[lol[i][j],lol[i+1][j]]
elif i==x-1:
yo=[lol[i][j],lol[i-1][j]]
else:
yo=[lol[i][j],lol[i-1][j],lol[i+1][j]]
if "W" in yo and "S" in yo and lol[i][j]!="D":
f=1
#print(yo,i,j,lol[i],lol[i-1],lol[i+1])
break
if f:
break
if f:
print("NO")
else:
print("YES")
for i in lol:
print(i)
``` | output | 1 | 13,875 | 15 | 27,751 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected.
The pasture is a rectangle consisting of R × C cells. Each cell is either empty, contains a sheep, a wolf or a dog. Sheep and dogs always stay in place, but wolves can roam freely around the pasture, by repeatedly moving to the left, right, up or down to a neighboring cell. When a wolf enters a cell with a sheep, it consumes it. However, no wolf can enter a cell with a dog.
Initially there are no dogs. Place dogs onto the pasture in such a way that no wolf can reach any sheep, or determine that it is impossible. Note that since you have many dogs, you do not need to minimize their number.
Input
First line contains two integers R (1 ≤ R ≤ 500) and C (1 ≤ C ≤ 500), denoting the number of rows and the numbers of columns respectively.
Each of the following R lines is a string consisting of exactly C characters, representing one row of the pasture. Here, 'S' means a sheep, 'W' a wolf and '.' an empty cell.
Output
If it is impossible to protect all sheep, output a single line with the word "No".
Otherwise, output a line with the word "Yes". Then print R lines, representing the pasture after placing dogs. Again, 'S' means a sheep, 'W' a wolf, 'D' is a dog and '.' an empty space. You are not allowed to move, remove or add a sheep or a wolf.
If there are multiple solutions, you may print any of them. You don't have to minimize the number of dogs.
Examples
Input
6 6
..S...
..S.W.
.S....
..W...
...W..
......
Output
Yes
..SD..
..SDW.
.SD...
.DW...
DD.W..
......
Input
1 2
SW
Output
No
Input
5 5
.S...
...S.
S....
...S.
.S...
Output
Yes
.S...
...S.
S.D..
...S.
.S...
Note
In the first example, we can split the pasture into two halves, one containing wolves and one containing sheep. Note that the sheep at (2,1) is safe, as wolves cannot move diagonally.
In the second example, there are no empty spots to put dogs that would guard the lone sheep.
In the third example, there are no wolves, so the task is very easy. We put a dog in the center to observe the peacefulness of the meadow, but the solution would be correct even without him. | instruction | 0 | 13,876 | 15 | 27,752 |
Tags: brute force, dfs and similar, graphs, implementation
Correct Solution:
```
R,C=map(int, input().split())
m=[[str(j) for j in input()] for i in range(R)]
row=0
for i in range(R):
if row == 1:
break
for j in range(C):
if m[i][j] == ".":
m[i][j] = "D"
elif m[i][j] == "S":
if j > 0 and m[i][j-1] == "W":
row=1
break
elif j < C-1 and m[i][j+1] == "W":
row=1
break
elif i < R-1 and m[i+1][j] == "W":
row=1
break
elif i > 0 and m[i-1][j] == "W":
row=1
break
if row == 1:
print("NO")
else:
print("YES")
for i in m:
print("".join(i))
``` | output | 1 | 13,876 | 15 | 27,753 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected.
The pasture is a rectangle consisting of R × C cells. Each cell is either empty, contains a sheep, a wolf or a dog. Sheep and dogs always stay in place, but wolves can roam freely around the pasture, by repeatedly moving to the left, right, up or down to a neighboring cell. When a wolf enters a cell with a sheep, it consumes it. However, no wolf can enter a cell with a dog.
Initially there are no dogs. Place dogs onto the pasture in such a way that no wolf can reach any sheep, or determine that it is impossible. Note that since you have many dogs, you do not need to minimize their number.
Input
First line contains two integers R (1 ≤ R ≤ 500) and C (1 ≤ C ≤ 500), denoting the number of rows and the numbers of columns respectively.
Each of the following R lines is a string consisting of exactly C characters, representing one row of the pasture. Here, 'S' means a sheep, 'W' a wolf and '.' an empty cell.
Output
If it is impossible to protect all sheep, output a single line with the word "No".
Otherwise, output a line with the word "Yes". Then print R lines, representing the pasture after placing dogs. Again, 'S' means a sheep, 'W' a wolf, 'D' is a dog and '.' an empty space. You are not allowed to move, remove or add a sheep or a wolf.
If there are multiple solutions, you may print any of them. You don't have to minimize the number of dogs.
Examples
Input
6 6
..S...
..S.W.
.S....
..W...
...W..
......
Output
Yes
..SD..
..SDW.
.SD...
.DW...
DD.W..
......
Input
1 2
SW
Output
No
Input
5 5
.S...
...S.
S....
...S.
.S...
Output
Yes
.S...
...S.
S.D..
...S.
.S...
Note
In the first example, we can split the pasture into two halves, one containing wolves and one containing sheep. Note that the sheep at (2,1) is safe, as wolves cannot move diagonally.
In the second example, there are no empty spots to put dogs that would guard the lone sheep.
In the third example, there are no wolves, so the task is very easy. We put a dog in the center to observe the peacefulness of the meadow, but the solution would be correct even without him. | instruction | 0 | 13,877 | 15 | 27,754 |
Tags: brute force, dfs and similar, graphs, implementation
Correct Solution:
```
import sys
import math
import bisect
import itertools
import random
import re
def solve(A):
n = len(A)
m = len(A[0])
for i in range(n):
for j in range(m):
if A[i][j] == 'S':
if i - 1 >= 0:
if A[i-1][j] == 'W':
return False
if i + 1 < n:
if A[i+1][j] == 'W':
return False
if j - 1 >= 0:
if A[i][j-1] == 'W':
return False
if j + 1 < m:
if A[i][j+1] == 'W':
return False
return True
def main():
n, m = map(int, input().split())
A = []
for i in range(n):
A.append(input())
if solve(A) == False:
print('No')
else:
print('Yes')
for i in range(n):
A[i] = re.sub(r'[.]', 'D', A[i])
print(''.join(A[i]))
if __name__ == "__main__":
main()
``` | output | 1 | 13,877 | 15 | 27,755 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected.
The pasture is a rectangle consisting of R × C cells. Each cell is either empty, contains a sheep, a wolf or a dog. Sheep and dogs always stay in place, but wolves can roam freely around the pasture, by repeatedly moving to the left, right, up or down to a neighboring cell. When a wolf enters a cell with a sheep, it consumes it. However, no wolf can enter a cell with a dog.
Initially there are no dogs. Place dogs onto the pasture in such a way that no wolf can reach any sheep, or determine that it is impossible. Note that since you have many dogs, you do not need to minimize their number.
Input
First line contains two integers R (1 ≤ R ≤ 500) and C (1 ≤ C ≤ 500), denoting the number of rows and the numbers of columns respectively.
Each of the following R lines is a string consisting of exactly C characters, representing one row of the pasture. Here, 'S' means a sheep, 'W' a wolf and '.' an empty cell.
Output
If it is impossible to protect all sheep, output a single line with the word "No".
Otherwise, output a line with the word "Yes". Then print R lines, representing the pasture after placing dogs. Again, 'S' means a sheep, 'W' a wolf, 'D' is a dog and '.' an empty space. You are not allowed to move, remove or add a sheep or a wolf.
If there are multiple solutions, you may print any of them. You don't have to minimize the number of dogs.
Examples
Input
6 6
..S...
..S.W.
.S....
..W...
...W..
......
Output
Yes
..SD..
..SDW.
.SD...
.DW...
DD.W..
......
Input
1 2
SW
Output
No
Input
5 5
.S...
...S.
S....
...S.
.S...
Output
Yes
.S...
...S.
S.D..
...S.
.S...
Note
In the first example, we can split the pasture into two halves, one containing wolves and one containing sheep. Note that the sheep at (2,1) is safe, as wolves cannot move diagonally.
In the second example, there are no empty spots to put dogs that would guard the lone sheep.
In the third example, there are no wolves, so the task is very easy. We put a dog in the center to observe the peacefulness of the meadow, but the solution would be correct even without him. | instruction | 0 | 13,878 | 15 | 27,756 |
Tags: brute force, dfs and similar, graphs, implementation
Correct Solution:
```
def okay(sl,r,c):
rv = [sl[i][j] for i in range(r) for j in range(c)]
cv = [sl[i][j] for j in range(c) for i in range(r)]
for i in range(1,r*c):
if i%c>0 and ((rv[i-1]=='S' and rv[i]=='W') or (rv[i-1]=='W' and rv[i]=='S')):
return False
if i%r>0 and ((cv[i-1]=='S' and cv[i]=='W') or (cv[i-1]=='W' and cv[i]=='S')):
return False
return True
r,c = list(map(int,input().split())) #500,500
sl = [input() for i in range(r)]
if okay(sl,r,c):
print('YES')
for s in sl:
print(s.replace('.','D'))
else:
print('NO')
``` | output | 1 | 13,878 | 15 | 27,757 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected.
The pasture is a rectangle consisting of R × C cells. Each cell is either empty, contains a sheep, a wolf or a dog. Sheep and dogs always stay in place, but wolves can roam freely around the pasture, by repeatedly moving to the left, right, up or down to a neighboring cell. When a wolf enters a cell with a sheep, it consumes it. However, no wolf can enter a cell with a dog.
Initially there are no dogs. Place dogs onto the pasture in such a way that no wolf can reach any sheep, or determine that it is impossible. Note that since you have many dogs, you do not need to minimize their number.
Input
First line contains two integers R (1 ≤ R ≤ 500) and C (1 ≤ C ≤ 500), denoting the number of rows and the numbers of columns respectively.
Each of the following R lines is a string consisting of exactly C characters, representing one row of the pasture. Here, 'S' means a sheep, 'W' a wolf and '.' an empty cell.
Output
If it is impossible to protect all sheep, output a single line with the word "No".
Otherwise, output a line with the word "Yes". Then print R lines, representing the pasture after placing dogs. Again, 'S' means a sheep, 'W' a wolf, 'D' is a dog and '.' an empty space. You are not allowed to move, remove or add a sheep or a wolf.
If there are multiple solutions, you may print any of them. You don't have to minimize the number of dogs.
Examples
Input
6 6
..S...
..S.W.
.S....
..W...
...W..
......
Output
Yes
..SD..
..SDW.
.SD...
.DW...
DD.W..
......
Input
1 2
SW
Output
No
Input
5 5
.S...
...S.
S....
...S.
.S...
Output
Yes
.S...
...S.
S.D..
...S.
.S...
Note
In the first example, we can split the pasture into two halves, one containing wolves and one containing sheep. Note that the sheep at (2,1) is safe, as wolves cannot move diagonally.
In the second example, there are no empty spots to put dogs that would guard the lone sheep.
In the third example, there are no wolves, so the task is very easy. We put a dog in the center to observe the peacefulness of the meadow, but the solution would be correct even without him. | instruction | 0 | 13,879 | 15 | 27,758 |
Tags: brute force, dfs and similar, graphs, implementation
Correct Solution:
```
# cf 948 A 1000
r, c = map(int, input().split())
ans = True
M = []
for _ in range(r):
s = input()
if 'SW' in s or 'WS' in s:
ans = False
if len(M) > 0:
for i in range(len(s)):
if s[i] == 'W' and M[-1][i] == 'S':
ans = False
if s[i] == 'S' and M[-1][i] == 'W':
ans = False
M.append(s.replace('.', 'D'))
print("Yes" if ans else "No")
if ans:
for m in M:
print(m)
``` | output | 1 | 13,879 | 15 | 27,759 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected.
The pasture is a rectangle consisting of R × C cells. Each cell is either empty, contains a sheep, a wolf or a dog. Sheep and dogs always stay in place, but wolves can roam freely around the pasture, by repeatedly moving to the left, right, up or down to a neighboring cell. When a wolf enters a cell with a sheep, it consumes it. However, no wolf can enter a cell with a dog.
Initially there are no dogs. Place dogs onto the pasture in such a way that no wolf can reach any sheep, or determine that it is impossible. Note that since you have many dogs, you do not need to minimize their number.
Input
First line contains two integers R (1 ≤ R ≤ 500) and C (1 ≤ C ≤ 500), denoting the number of rows and the numbers of columns respectively.
Each of the following R lines is a string consisting of exactly C characters, representing one row of the pasture. Here, 'S' means a sheep, 'W' a wolf and '.' an empty cell.
Output
If it is impossible to protect all sheep, output a single line with the word "No".
Otherwise, output a line with the word "Yes". Then print R lines, representing the pasture after placing dogs. Again, 'S' means a sheep, 'W' a wolf, 'D' is a dog and '.' an empty space. You are not allowed to move, remove or add a sheep or a wolf.
If there are multiple solutions, you may print any of them. You don't have to minimize the number of dogs.
Examples
Input
6 6
..S...
..S.W.
.S....
..W...
...W..
......
Output
Yes
..SD..
..SDW.
.SD...
.DW...
DD.W..
......
Input
1 2
SW
Output
No
Input
5 5
.S...
...S.
S....
...S.
.S...
Output
Yes
.S...
...S.
S.D..
...S.
.S...
Note
In the first example, we can split the pasture into two halves, one containing wolves and one containing sheep. Note that the sheep at (2,1) is safe, as wolves cannot move diagonally.
In the second example, there are no empty spots to put dogs that would guard the lone sheep.
In the third example, there are no wolves, so the task is very easy. We put a dog in the center to observe the peacefulness of the meadow, but the solution would be correct even without him.
Submitted Solution:
```
r,c = list(map(int,input().split()))
grid = []
for i in range(r):
grid.append([x for x in input()])
for i in range(r):
for j in range(c):
if grid[i][j] == "." : grid[i][j] = "D"
ans = "Yes"
def valid(i,j):
return i >=0 and j >=0 and i < r and j < c
masks = [(1,0),(-1,0),(0,1),(0,-1)]
for i in range(r):
for j in range(c):
if grid[i][j] != "W" : continue
for a,b in masks:
if valid(i+a,j+b) and grid[i+a][j+b]=="S": ans = "No"
print(ans)
if ans == "Yes":
for x in grid:
print("".join(x))
``` | instruction | 0 | 13,880 | 15 | 27,760 |
Yes | output | 1 | 13,880 | 15 | 27,761 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected.
The pasture is a rectangle consisting of R × C cells. Each cell is either empty, contains a sheep, a wolf or a dog. Sheep and dogs always stay in place, but wolves can roam freely around the pasture, by repeatedly moving to the left, right, up or down to a neighboring cell. When a wolf enters a cell with a sheep, it consumes it. However, no wolf can enter a cell with a dog.
Initially there are no dogs. Place dogs onto the pasture in such a way that no wolf can reach any sheep, or determine that it is impossible. Note that since you have many dogs, you do not need to minimize their number.
Input
First line contains two integers R (1 ≤ R ≤ 500) and C (1 ≤ C ≤ 500), denoting the number of rows and the numbers of columns respectively.
Each of the following R lines is a string consisting of exactly C characters, representing one row of the pasture. Here, 'S' means a sheep, 'W' a wolf and '.' an empty cell.
Output
If it is impossible to protect all sheep, output a single line with the word "No".
Otherwise, output a line with the word "Yes". Then print R lines, representing the pasture after placing dogs. Again, 'S' means a sheep, 'W' a wolf, 'D' is a dog and '.' an empty space. You are not allowed to move, remove or add a sheep or a wolf.
If there are multiple solutions, you may print any of them. You don't have to minimize the number of dogs.
Examples
Input
6 6
..S...
..S.W.
.S....
..W...
...W..
......
Output
Yes
..SD..
..SDW.
.SD...
.DW...
DD.W..
......
Input
1 2
SW
Output
No
Input
5 5
.S...
...S.
S....
...S.
.S...
Output
Yes
.S...
...S.
S.D..
...S.
.S...
Note
In the first example, we can split the pasture into two halves, one containing wolves and one containing sheep. Note that the sheep at (2,1) is safe, as wolves cannot move diagonally.
In the second example, there are no empty spots to put dogs that would guard the lone sheep.
In the third example, there are no wolves, so the task is very easy. We put a dog in the center to observe the peacefulness of the meadow, but the solution would be correct even without him.
Submitted Solution:
```
n,m = [int(x) for x in input().split()]
mat = []
for i in range(n):
mat.append(input())
ok = True
dx = [0,0,1,-1]
dy = [1,-1,0,0]
f = lambda x,y,c,d : x >= 0 and y >= 0 and x < c and y < d
for i in range(n):
for j in range(m):
if mat[i][j] == 'S':
for k in range(4):
tx = i + dx[k]
ty = j + dy[k]
if f(tx,ty,n,m) == False: continue
if mat[tx][ty] == 'W': ok = False
if ok:
print("Yes")
for i in range(n):
mat[i] = mat[i].replace('.','D')
for x in mat: print(x)
else:
print("No")
``` | instruction | 0 | 13,881 | 15 | 27,762 |
Yes | output | 1 | 13,881 | 15 | 27,763 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected.
The pasture is a rectangle consisting of R × C cells. Each cell is either empty, contains a sheep, a wolf or a dog. Sheep and dogs always stay in place, but wolves can roam freely around the pasture, by repeatedly moving to the left, right, up or down to a neighboring cell. When a wolf enters a cell with a sheep, it consumes it. However, no wolf can enter a cell with a dog.
Initially there are no dogs. Place dogs onto the pasture in such a way that no wolf can reach any sheep, or determine that it is impossible. Note that since you have many dogs, you do not need to minimize their number.
Input
First line contains two integers R (1 ≤ R ≤ 500) and C (1 ≤ C ≤ 500), denoting the number of rows and the numbers of columns respectively.
Each of the following R lines is a string consisting of exactly C characters, representing one row of the pasture. Here, 'S' means a sheep, 'W' a wolf and '.' an empty cell.
Output
If it is impossible to protect all sheep, output a single line with the word "No".
Otherwise, output a line with the word "Yes". Then print R lines, representing the pasture after placing dogs. Again, 'S' means a sheep, 'W' a wolf, 'D' is a dog and '.' an empty space. You are not allowed to move, remove or add a sheep or a wolf.
If there are multiple solutions, you may print any of them. You don't have to minimize the number of dogs.
Examples
Input
6 6
..S...
..S.W.
.S....
..W...
...W..
......
Output
Yes
..SD..
..SDW.
.SD...
.DW...
DD.W..
......
Input
1 2
SW
Output
No
Input
5 5
.S...
...S.
S....
...S.
.S...
Output
Yes
.S...
...S.
S.D..
...S.
.S...
Note
In the first example, we can split the pasture into two halves, one containing wolves and one containing sheep. Note that the sheep at (2,1) is safe, as wolves cannot move diagonally.
In the second example, there are no empty spots to put dogs that would guard the lone sheep.
In the third example, there are no wolves, so the task is very easy. We put a dog in the center to observe the peacefulness of the meadow, but the solution would be correct even without him.
Submitted Solution:
```
import math as mt
import sys,string
input=sys.stdin.readline
L=lambda : list(map(int,input().split()))
Ls=lambda : list(input().split())
M=lambda : map(int,input().split())
I=lambda :int(input())
from collections import defaultdict
def dfs(n,dx):
vis[n]=1
dis[n]=dx
for i in adj[n]:
if(vis[i]==0):
dfs(i,dx+1)
r,c=M()
l=[]
x=[]
for i in range(r):
s=input().strip()
s=list(s)
for j in range(c):
if(s[j]=='.'):
s[j]='D'
if(s[j]=='W'):
x.append((i,j))
l.append(s)
for i in range(len(x)):
if(x[i][0]-1>=0):
if(l[x[i][0]-1][x[i][1]]=='S'):
print("No")
exit()
if(x[i][0]+1<r):
if(l[x[i][0]+1][x[i][1]]=='S'):
print("No")
exit()
if(x[i][1]-1>=0):
if(l[x[i][0]][x[i][1]-1]=='S'):
print("No")
exit()
if(x[i][1]+1<c):
if(l[x[i][0]][x[i][1]+1]=='S'):
print("No")
exit()
print("Yes")
for i in range(len(l)):
for j in l[i]:
print(j,end="")
print()
``` | instruction | 0 | 13,882 | 15 | 27,764 |
Yes | output | 1 | 13,882 | 15 | 27,765 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected.
The pasture is a rectangle consisting of R × C cells. Each cell is either empty, contains a sheep, a wolf or a dog. Sheep and dogs always stay in place, but wolves can roam freely around the pasture, by repeatedly moving to the left, right, up or down to a neighboring cell. When a wolf enters a cell with a sheep, it consumes it. However, no wolf can enter a cell with a dog.
Initially there are no dogs. Place dogs onto the pasture in such a way that no wolf can reach any sheep, or determine that it is impossible. Note that since you have many dogs, you do not need to minimize their number.
Input
First line contains two integers R (1 ≤ R ≤ 500) and C (1 ≤ C ≤ 500), denoting the number of rows and the numbers of columns respectively.
Each of the following R lines is a string consisting of exactly C characters, representing one row of the pasture. Here, 'S' means a sheep, 'W' a wolf and '.' an empty cell.
Output
If it is impossible to protect all sheep, output a single line with the word "No".
Otherwise, output a line with the word "Yes". Then print R lines, representing the pasture after placing dogs. Again, 'S' means a sheep, 'W' a wolf, 'D' is a dog and '.' an empty space. You are not allowed to move, remove or add a sheep or a wolf.
If there are multiple solutions, you may print any of them. You don't have to minimize the number of dogs.
Examples
Input
6 6
..S...
..S.W.
.S....
..W...
...W..
......
Output
Yes
..SD..
..SDW.
.SD...
.DW...
DD.W..
......
Input
1 2
SW
Output
No
Input
5 5
.S...
...S.
S....
...S.
.S...
Output
Yes
.S...
...S.
S.D..
...S.
.S...
Note
In the first example, we can split the pasture into two halves, one containing wolves and one containing sheep. Note that the sheep at (2,1) is safe, as wolves cannot move diagonally.
In the second example, there are no empty spots to put dogs that would guard the lone sheep.
In the third example, there are no wolves, so the task is very easy. We put a dog in the center to observe the peacefulness of the meadow, but the solution would be correct even without him.
Submitted Solution:
```
import re
r,c=input().split()
s='\n'.join(input().replace('.','D')for _ in[0]*int(r))
print('No'if re.search('(?s)(S(.{'+c+'})?W)|(W(.{'+c+'})?S)',s)else'Yes\n'+s)
``` | instruction | 0 | 13,883 | 15 | 27,766 |
Yes | output | 1 | 13,883 | 15 | 27,767 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected.
The pasture is a rectangle consisting of R × C cells. Each cell is either empty, contains a sheep, a wolf or a dog. Sheep and dogs always stay in place, but wolves can roam freely around the pasture, by repeatedly moving to the left, right, up or down to a neighboring cell. When a wolf enters a cell with a sheep, it consumes it. However, no wolf can enter a cell with a dog.
Initially there are no dogs. Place dogs onto the pasture in such a way that no wolf can reach any sheep, or determine that it is impossible. Note that since you have many dogs, you do not need to minimize their number.
Input
First line contains two integers R (1 ≤ R ≤ 500) and C (1 ≤ C ≤ 500), denoting the number of rows and the numbers of columns respectively.
Each of the following R lines is a string consisting of exactly C characters, representing one row of the pasture. Here, 'S' means a sheep, 'W' a wolf and '.' an empty cell.
Output
If it is impossible to protect all sheep, output a single line with the word "No".
Otherwise, output a line with the word "Yes". Then print R lines, representing the pasture after placing dogs. Again, 'S' means a sheep, 'W' a wolf, 'D' is a dog and '.' an empty space. You are not allowed to move, remove or add a sheep or a wolf.
If there are multiple solutions, you may print any of them. You don't have to minimize the number of dogs.
Examples
Input
6 6
..S...
..S.W.
.S....
..W...
...W..
......
Output
Yes
..SD..
..SDW.
.SD...
.DW...
DD.W..
......
Input
1 2
SW
Output
No
Input
5 5
.S...
...S.
S....
...S.
.S...
Output
Yes
.S...
...S.
S.D..
...S.
.S...
Note
In the first example, we can split the pasture into two halves, one containing wolves and one containing sheep. Note that the sheep at (2,1) is safe, as wolves cannot move diagonally.
In the second example, there are no empty spots to put dogs that would guard the lone sheep.
In the third example, there are no wolves, so the task is very easy. We put a dog in the center to observe the peacefulness of the meadow, but the solution would be correct even without him.
Submitted Solution:
```
import sys, math, os.path
FILE_INPUT = "A.in"
DEBUG = os.path.isfile(FILE_INPUT)
if DEBUG:
sys.stdin = open(FILE_INPUT)
def ni():
return map(int, input().split(" "))
def nia():
return list(map(int,input().split()))
def log(x):
if (DEBUG):
print(x)
r, c = ni()
a = []
print(r, c)
def check():
for i in range(r):
for j in range(c):
if a[i][j] == 'W':
# print(i,j)
if i > 0 and a[i-1][j]=='S':
return False
if (i < r-1) and a[i+1][j]=='S':
return False
if j > 0 and a[i][j-1]=='S':
return False
if (j < c-1) and a[i][j+1]=='S':
return False
return True
for i in range(r):
s = input()
a.append(s)
if check():
print("Yes")
for i in range(r):
print(''.join('D' if x == '.' else x for x in a[i]))
else:
print("No")
``` | instruction | 0 | 13,884 | 15 | 27,768 |
No | output | 1 | 13,884 | 15 | 27,769 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected.
The pasture is a rectangle consisting of R × C cells. Each cell is either empty, contains a sheep, a wolf or a dog. Sheep and dogs always stay in place, but wolves can roam freely around the pasture, by repeatedly moving to the left, right, up or down to a neighboring cell. When a wolf enters a cell with a sheep, it consumes it. However, no wolf can enter a cell with a dog.
Initially there are no dogs. Place dogs onto the pasture in such a way that no wolf can reach any sheep, or determine that it is impossible. Note that since you have many dogs, you do not need to minimize their number.
Input
First line contains two integers R (1 ≤ R ≤ 500) and C (1 ≤ C ≤ 500), denoting the number of rows and the numbers of columns respectively.
Each of the following R lines is a string consisting of exactly C characters, representing one row of the pasture. Here, 'S' means a sheep, 'W' a wolf and '.' an empty cell.
Output
If it is impossible to protect all sheep, output a single line with the word "No".
Otherwise, output a line with the word "Yes". Then print R lines, representing the pasture after placing dogs. Again, 'S' means a sheep, 'W' a wolf, 'D' is a dog and '.' an empty space. You are not allowed to move, remove or add a sheep or a wolf.
If there are multiple solutions, you may print any of them. You don't have to minimize the number of dogs.
Examples
Input
6 6
..S...
..S.W.
.S....
..W...
...W..
......
Output
Yes
..SD..
..SDW.
.SD...
.DW...
DD.W..
......
Input
1 2
SW
Output
No
Input
5 5
.S...
...S.
S....
...S.
.S...
Output
Yes
.S...
...S.
S.D..
...S.
.S...
Note
In the first example, we can split the pasture into two halves, one containing wolves and one containing sheep. Note that the sheep at (2,1) is safe, as wolves cannot move diagonally.
In the second example, there are no empty spots to put dogs that would guard the lone sheep.
In the third example, there are no wolves, so the task is very easy. We put a dog in the center to observe the peacefulness of the meadow, but the solution would be correct even without him.
Submitted Solution:
```
row, strings = map(int, input().split())
# ..S...
# ..S.W.
# .S....
# ..W...
# ...W..
# ......
all_past = []
for i in range(row):
all_past.append([])
array = input()
all_past[i].append(array)
# if row==1:
# if ('SW' or 'WS') in str(all_past[0]):
# print('NO')
flag = False
for i in range(0, row):
first = str(all_past[i])
if i != row-1:
second = str(all_past[i+1])
if ('SW' or 'WS') in (first or second):
print('No')
flag = True
break
for i in range(strings):
if (first[i] == 'S' and second[i] == 'W') or (first[i] == 'W' and second[i] == 'S'):
print('No')
flag = True
break
if not flag:
print('Yes')
for i in all_past:
new_mini = ''
for j in str(i):
if j == '.':
new_mini += 'D'
else:
new_mini += j
print(new_mini[2:-2])
``` | instruction | 0 | 13,885 | 15 | 27,770 |
No | output | 1 | 13,885 | 15 | 27,771 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected.
The pasture is a rectangle consisting of R × C cells. Each cell is either empty, contains a sheep, a wolf or a dog. Sheep and dogs always stay in place, but wolves can roam freely around the pasture, by repeatedly moving to the left, right, up or down to a neighboring cell. When a wolf enters a cell with a sheep, it consumes it. However, no wolf can enter a cell with a dog.
Initially there are no dogs. Place dogs onto the pasture in such a way that no wolf can reach any sheep, or determine that it is impossible. Note that since you have many dogs, you do not need to minimize their number.
Input
First line contains two integers R (1 ≤ R ≤ 500) and C (1 ≤ C ≤ 500), denoting the number of rows and the numbers of columns respectively.
Each of the following R lines is a string consisting of exactly C characters, representing one row of the pasture. Here, 'S' means a sheep, 'W' a wolf and '.' an empty cell.
Output
If it is impossible to protect all sheep, output a single line with the word "No".
Otherwise, output a line with the word "Yes". Then print R lines, representing the pasture after placing dogs. Again, 'S' means a sheep, 'W' a wolf, 'D' is a dog and '.' an empty space. You are not allowed to move, remove or add a sheep or a wolf.
If there are multiple solutions, you may print any of them. You don't have to minimize the number of dogs.
Examples
Input
6 6
..S...
..S.W.
.S....
..W...
...W..
......
Output
Yes
..SD..
..SDW.
.SD...
.DW...
DD.W..
......
Input
1 2
SW
Output
No
Input
5 5
.S...
...S.
S....
...S.
.S...
Output
Yes
.S...
...S.
S.D..
...S.
.S...
Note
In the first example, we can split the pasture into two halves, one containing wolves and one containing sheep. Note that the sheep at (2,1) is safe, as wolves cannot move diagonally.
In the second example, there are no empty spots to put dogs that would guard the lone sheep.
In the third example, there are no wolves, so the task is very easy. We put a dog in the center to observe the peacefulness of the meadow, but the solution would be correct even without him.
Submitted Solution:
```
def test_2():
# B - Protect Sheep
import math
r, c = list(map(int, input().split(" ")))
aa = []
aa.append(list('.' * (c + 2)))
for i in range(r):
c_1 = list('.'+input()+'.')
# print(c_1)
aa.append(c_1)
aa.append(list('.' * (c + 2)))
# print(aa)
for i in range(1, r+1):
for j in range(1, c+1):
# print(aa[i][j])
if aa[i][j]=='S':
bb = [aa[i][j+1], aa[i][j-1], aa[i+1][j], aa[i-1][j]]
# print('b:', bb)
if 'W' in bb:
print('No')
return 0
else:
cc = ''.join([aa[i][j+1], aa[i][j-1], aa[i+1][j], aa[i-1][j]])
# print(cc)
cc = cc.replace('.', 'D')
cc = list(cc)
# print('cc:', cc)
aa[i][j + 1], aa[i][j - 1], aa[i + 1][j], aa[i - 1][j] = cc
# print(aa)
print('Yes')
cc = aa[1:-1]
dd = []
for c in cc:
c = c[1: -1]
dd.append(c)
# print(len(cc[1]))
print(dd)
test_2()
``` | instruction | 0 | 13,886 | 15 | 27,772 |
No | output | 1 | 13,886 | 15 | 27,773 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected.
The pasture is a rectangle consisting of R × C cells. Each cell is either empty, contains a sheep, a wolf or a dog. Sheep and dogs always stay in place, but wolves can roam freely around the pasture, by repeatedly moving to the left, right, up or down to a neighboring cell. When a wolf enters a cell with a sheep, it consumes it. However, no wolf can enter a cell with a dog.
Initially there are no dogs. Place dogs onto the pasture in such a way that no wolf can reach any sheep, or determine that it is impossible. Note that since you have many dogs, you do not need to minimize their number.
Input
First line contains two integers R (1 ≤ R ≤ 500) and C (1 ≤ C ≤ 500), denoting the number of rows and the numbers of columns respectively.
Each of the following R lines is a string consisting of exactly C characters, representing one row of the pasture. Here, 'S' means a sheep, 'W' a wolf and '.' an empty cell.
Output
If it is impossible to protect all sheep, output a single line with the word "No".
Otherwise, output a line with the word "Yes". Then print R lines, representing the pasture after placing dogs. Again, 'S' means a sheep, 'W' a wolf, 'D' is a dog and '.' an empty space. You are not allowed to move, remove or add a sheep or a wolf.
If there are multiple solutions, you may print any of them. You don't have to minimize the number of dogs.
Examples
Input
6 6
..S...
..S.W.
.S....
..W...
...W..
......
Output
Yes
..SD..
..SDW.
.SD...
.DW...
DD.W..
......
Input
1 2
SW
Output
No
Input
5 5
.S...
...S.
S....
...S.
.S...
Output
Yes
.S...
...S.
S.D..
...S.
.S...
Note
In the first example, we can split the pasture into two halves, one containing wolves and one containing sheep. Note that the sheep at (2,1) is safe, as wolves cannot move diagonally.
In the second example, there are no empty spots to put dogs that would guard the lone sheep.
In the third example, there are no wolves, so the task is very easy. We put a dog in the center to observe the peacefulness of the meadow, but the solution would be correct even without him.
Submitted Solution:
```
r,c = map(int, input().split())
arr = []
for i in range(r):
arr.append(list(input()))
for i in range(r):
for j in range(c):
if j<c-1:
if arr[i][j] == 'S' and arr[i][j+1] == 'W' or arr[i][j] == 'W' and arr[i][j+1] == 'S':
print('No')
exit()
if arr[i][j] =='.':
arr[i][j] = 'D'
print('Yes ')
for i in range(c):
print(''.join(arr[i]))
``` | instruction | 0 | 13,887 | 15 | 27,774 |
No | output | 1 | 13,887 | 15 | 27,775 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi and Aoki will play a game with a number line and some segments. Takahashi is standing on the number line and he is initially at coordinate 0. Aoki has N segments. The i-th segment is [L_i,R_i], that is, a segment consisting of points with coordinates between L_i and R_i (inclusive).
The game has N steps. The i-th step proceeds as follows:
* First, Aoki chooses a segment that is still not chosen yet from the N segments and tells it to Takahashi.
* Then, Takahashi walks along the number line to some point within the segment chosen by Aoki this time.
After N steps are performed, Takahashi will return to coordinate 0 and the game ends.
Let K be the total distance traveled by Takahashi throughout the game. Aoki will choose segments so that K will be as large as possible, and Takahashi walks along the line so that K will be as small as possible. What will be the value of K in the end?
Constraints
* 1 ≤ N ≤ 10^5
* -10^5 ≤ L_i < R_i ≤ 10^5
* L_i and R_i are integers.
Input
Input is given from Standard Input in the following format:
N
L_1 R_1
:
L_N R_N
Output
Print the total distance traveled by Takahashi throughout the game when Takahashi and Aoki acts as above. It is guaranteed that K is always an integer when L_i,R_i are integers.
Examples
Input
3
-5 1
3 7
-4 -2
Output
10
Input
3
1 2
3 4
5 6
Output
12
Input
5
-2 0
-2 0
7 8
9 10
-2 -1
Output
34 | instruction | 0 | 13,985 | 15 | 27,970 |
"Correct Solution:
```
from itertools import accumulate
N = int(input())
L, R = [0], [0]
for i in range(N):
li, ri = map(int, input().split())
L.append(li)
R.append(ri)
L.sort(reverse=True)
R.sort()
L = list(accumulate(L))
R = list(accumulate(R))
ans = 0
for k in range(N+1):
ans = max(ans, 2*(L[k]-R[k]))
print(ans)
``` | output | 1 | 13,985 | 15 | 27,971 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi and Aoki will play a game with a number line and some segments. Takahashi is standing on the number line and he is initially at coordinate 0. Aoki has N segments. The i-th segment is [L_i,R_i], that is, a segment consisting of points with coordinates between L_i and R_i (inclusive).
The game has N steps. The i-th step proceeds as follows:
* First, Aoki chooses a segment that is still not chosen yet from the N segments and tells it to Takahashi.
* Then, Takahashi walks along the number line to some point within the segment chosen by Aoki this time.
After N steps are performed, Takahashi will return to coordinate 0 and the game ends.
Let K be the total distance traveled by Takahashi throughout the game. Aoki will choose segments so that K will be as large as possible, and Takahashi walks along the line so that K will be as small as possible. What will be the value of K in the end?
Constraints
* 1 ≤ N ≤ 10^5
* -10^5 ≤ L_i < R_i ≤ 10^5
* L_i and R_i are integers.
Input
Input is given from Standard Input in the following format:
N
L_1 R_1
:
L_N R_N
Output
Print the total distance traveled by Takahashi throughout the game when Takahashi and Aoki acts as above. It is guaranteed that K is always an integer when L_i,R_i are integers.
Examples
Input
3
-5 1
3 7
-4 -2
Output
10
Input
3
1 2
3 4
5 6
Output
12
Input
5
-2 0
-2 0
7 8
9 10
-2 -1
Output
34 | instruction | 0 | 13,986 | 15 | 27,972 |
"Correct Solution:
```
N = int(input())
L,R = [],[]
for i in range(N):
l,r = map(int,input().split())
L.append(l)
R.append(r)
# 原点を追加
L.append(0)
R.append(0)
# 左端点は降順に、右端点は昇順にソート
L.sort(reverse=True)
R.sort()
Ans = 0
for i in range(N+1):
if L[i] > R[i]:
Ans += (L[i] - R[i])*2
print(Ans)
``` | output | 1 | 13,986 | 15 | 27,973 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi and Aoki will play a game with a number line and some segments. Takahashi is standing on the number line and he is initially at coordinate 0. Aoki has N segments. The i-th segment is [L_i,R_i], that is, a segment consisting of points with coordinates between L_i and R_i (inclusive).
The game has N steps. The i-th step proceeds as follows:
* First, Aoki chooses a segment that is still not chosen yet from the N segments and tells it to Takahashi.
* Then, Takahashi walks along the number line to some point within the segment chosen by Aoki this time.
After N steps are performed, Takahashi will return to coordinate 0 and the game ends.
Let K be the total distance traveled by Takahashi throughout the game. Aoki will choose segments so that K will be as large as possible, and Takahashi walks along the line so that K will be as small as possible. What will be the value of K in the end?
Constraints
* 1 ≤ N ≤ 10^5
* -10^5 ≤ L_i < R_i ≤ 10^5
* L_i and R_i are integers.
Input
Input is given from Standard Input in the following format:
N
L_1 R_1
:
L_N R_N
Output
Print the total distance traveled by Takahashi throughout the game when Takahashi and Aoki acts as above. It is guaranteed that K is always an integer when L_i,R_i are integers.
Examples
Input
3
-5 1
3 7
-4 -2
Output
10
Input
3
1 2
3 4
5 6
Output
12
Input
5
-2 0
-2 0
7 8
9 10
-2 -1
Output
34 | instruction | 0 | 13,987 | 15 | 27,974 |
"Correct Solution:
```
def main():
import heapq
n = int(input())
ab = [tuple(map(int, input().split())) for _ in [0]*n]
# 1周目
d = dict()
for a, b in ab:
d[(a, b)] = d.get((a, b), 0)+1
left, right = [(b, a) for a, b in ab], [(-a, b) for a, b in ab]
heapq.heapify(left)
heapq.heapify(right)
ans1 = 0
now = 0
for i in range(n):
while left:
a, b = heapq.heappop(left)
a, b = b, a
if d[(a, b)] > 0:
d[(a, b)] -= 1
if b < now:
ans1 += now-b
now = b
elif now < a:
ans1 += a-now
now = a
break
while right:
a, b = heapq.heappop(right)
a, b = -a, b
if d[(a, b)] > 0:
d[(a, b)] -= 1
if now < a:
ans1 += a-now
now = a
elif b < now:
ans1 += now-b
now = b
break
ans1 += abs(now)
# 2周目
d = dict()
for a, b in ab:
d[(a, b)] = d.get((a, b), 0)+1
left, right = [(b, a) for a, b in ab], [(-a, b) for a, b in ab]
heapq.heapify(left)
heapq.heapify(right)
ans2 = 0
now = 0
for i in range(n):
while right:
a, b = heapq.heappop(right)
a, b = -a, b
if d[(a, b)] > 0:
d[(a, b)] -= 1
if now < a:
ans2 += a-now
now = a
elif b < now:
ans2 += now-b
now = b
break
while left:
a, b = heapq.heappop(left)
a, b = b, a
if d[(a, b)] > 0:
d[(a, b)] -= 1
if b < now:
ans2 += now-b
now = b
elif now < a:
ans2 += a-now
now = a
break
ans2 += abs(now)
print(max(ans1, ans2))
main()
``` | output | 1 | 13,987 | 15 | 27,975 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi and Aoki will play a game with a number line and some segments. Takahashi is standing on the number line and he is initially at coordinate 0. Aoki has N segments. The i-th segment is [L_i,R_i], that is, a segment consisting of points with coordinates between L_i and R_i (inclusive).
The game has N steps. The i-th step proceeds as follows:
* First, Aoki chooses a segment that is still not chosen yet from the N segments and tells it to Takahashi.
* Then, Takahashi walks along the number line to some point within the segment chosen by Aoki this time.
After N steps are performed, Takahashi will return to coordinate 0 and the game ends.
Let K be the total distance traveled by Takahashi throughout the game. Aoki will choose segments so that K will be as large as possible, and Takahashi walks along the line so that K will be as small as possible. What will be the value of K in the end?
Constraints
* 1 ≤ N ≤ 10^5
* -10^5 ≤ L_i < R_i ≤ 10^5
* L_i and R_i are integers.
Input
Input is given from Standard Input in the following format:
N
L_1 R_1
:
L_N R_N
Output
Print the total distance traveled by Takahashi throughout the game when Takahashi and Aoki acts as above. It is guaranteed that K is always an integer when L_i,R_i are integers.
Examples
Input
3
-5 1
3 7
-4 -2
Output
10
Input
3
1 2
3 4
5 6
Output
12
Input
5
-2 0
-2 0
7 8
9 10
-2 -1
Output
34 | instruction | 0 | 13,988 | 15 | 27,976 |
"Correct Solution:
```
from heapq import heappop, heappush
N = int(input())
QL = []
QR = []
for i in range(N):
L, R = map(int, input().split())
heappush(QL, (-L, i))
heappush(QR, (R, i))
QL1 = QL[:]
QR1 = QR[:]
deta = set()
x = 0
ans = 0
for i in range(N):
if i % 2 == 0:
for _ in range(N):
if QL1[0][1] not in deta:
break
heappop(QL1)
L, i = heappop(QL1)
deta.add(i)
L = -L
if x < L:
ans += L - x
x = L
else:
for _ in range(N):
if QR1[0][1] not in deta:
break
heappop(QR1)
R, i = heappop(QR1)
deta.add(i)
if x > R:
ans += x - R
x = R
ans += abs(x)
x = 0
ans1 = 0
deta = set()
for i in range(N):
if i % 2:
for _ in range(N):
if QL[0][1] not in deta:
break
heappop(QL)
L, i = heappop(QL)
deta.add(i)
L = -L
if x < L:
ans1 += L - x
x = L
else:
for _ in range(N):
if QR[0][1] not in deta:
break
heappop(QR)
R, i = heappop(QR)
deta.add(i)
if x > R:
ans1 += x - R
x = R
ans1 += abs(x)
print(max(ans1, ans))
``` | output | 1 | 13,988 | 15 | 27,977 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi and Aoki will play a game with a number line and some segments. Takahashi is standing on the number line and he is initially at coordinate 0. Aoki has N segments. The i-th segment is [L_i,R_i], that is, a segment consisting of points with coordinates between L_i and R_i (inclusive).
The game has N steps. The i-th step proceeds as follows:
* First, Aoki chooses a segment that is still not chosen yet from the N segments and tells it to Takahashi.
* Then, Takahashi walks along the number line to some point within the segment chosen by Aoki this time.
After N steps are performed, Takahashi will return to coordinate 0 and the game ends.
Let K be the total distance traveled by Takahashi throughout the game. Aoki will choose segments so that K will be as large as possible, and Takahashi walks along the line so that K will be as small as possible. What will be the value of K in the end?
Constraints
* 1 ≤ N ≤ 10^5
* -10^5 ≤ L_i < R_i ≤ 10^5
* L_i and R_i are integers.
Input
Input is given from Standard Input in the following format:
N
L_1 R_1
:
L_N R_N
Output
Print the total distance traveled by Takahashi throughout the game when Takahashi and Aoki acts as above. It is guaranteed that K is always an integer when L_i,R_i are integers.
Examples
Input
3
-5 1
3 7
-4 -2
Output
10
Input
3
1 2
3 4
5 6
Output
12
Input
5
-2 0
-2 0
7 8
9 10
-2 -1
Output
34 | instruction | 0 | 13,989 | 15 | 27,978 |
"Correct Solution:
```
N = int(input())
L = [0]*N
R = [0]*N
for i in range(N):
L[i],R[i] = map(int,input().split(" "))
L.sort(reverse=True)
R.sort()
ans = 0
acc = 0
for i in range(N):
ans = max(ans,acc+2*L[i])
acc += (2*(L[i]-R[i]))
ans = max(ans,acc)
acc = 0
for i in range(N):
ans = max(ans,acc+2*(-R[i]))
acc += (2*(L[i]-R[i]))
ans = max(ans,acc)
print(ans)
``` | output | 1 | 13,989 | 15 | 27,979 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi and Aoki will play a game with a number line and some segments. Takahashi is standing on the number line and he is initially at coordinate 0. Aoki has N segments. The i-th segment is [L_i,R_i], that is, a segment consisting of points with coordinates between L_i and R_i (inclusive).
The game has N steps. The i-th step proceeds as follows:
* First, Aoki chooses a segment that is still not chosen yet from the N segments and tells it to Takahashi.
* Then, Takahashi walks along the number line to some point within the segment chosen by Aoki this time.
After N steps are performed, Takahashi will return to coordinate 0 and the game ends.
Let K be the total distance traveled by Takahashi throughout the game. Aoki will choose segments so that K will be as large as possible, and Takahashi walks along the line so that K will be as small as possible. What will be the value of K in the end?
Constraints
* 1 ≤ N ≤ 10^5
* -10^5 ≤ L_i < R_i ≤ 10^5
* L_i and R_i are integers.
Input
Input is given from Standard Input in the following format:
N
L_1 R_1
:
L_N R_N
Output
Print the total distance traveled by Takahashi throughout the game when Takahashi and Aoki acts as above. It is guaranteed that K is always an integer when L_i,R_i are integers.
Examples
Input
3
-5 1
3 7
-4 -2
Output
10
Input
3
1 2
3 4
5 6
Output
12
Input
5
-2 0
-2 0
7 8
9 10
-2 -1
Output
34 | instruction | 0 | 13,990 | 15 | 27,980 |
"Correct Solution:
```
import sys
input = sys.stdin.readline
N = int(input())
Ls = []
Rs = []
l0 = 0
r0 = 0
for i in range(N):
l, r = map(int, input().split())
Ls.append((l, i))
Rs.append((r, i))
if l > 0:
l0 += 1
if r < 0:
r0 += 1
Ls.sort(reverse=True)
Rs.sort()
used = [False]*N
if l0 > r0:
toright = True
else:
toright = False
l = 0
r = 0
ans = 0
now = 0
for _ in range(N):
if toright:
while True:
nl, ind = Ls[l]
if used[ind]:
l += 1
else:
used[ind] = True
break
if nl-now > 0:
ans += nl - now
now = nl
toright = False
else:
while True:
nr, ind = Rs[r]
if used[ind]:
r += 1
else:
used[ind] = True
break
if now-nr > 0:
ans += now-nr
now = nr
toright = True
ans += abs(now)
print(ans)
``` | output | 1 | 13,990 | 15 | 27,981 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi and Aoki will play a game with a number line and some segments. Takahashi is standing on the number line and he is initially at coordinate 0. Aoki has N segments. The i-th segment is [L_i,R_i], that is, a segment consisting of points with coordinates between L_i and R_i (inclusive).
The game has N steps. The i-th step proceeds as follows:
* First, Aoki chooses a segment that is still not chosen yet from the N segments and tells it to Takahashi.
* Then, Takahashi walks along the number line to some point within the segment chosen by Aoki this time.
After N steps are performed, Takahashi will return to coordinate 0 and the game ends.
Let K be the total distance traveled by Takahashi throughout the game. Aoki will choose segments so that K will be as large as possible, and Takahashi walks along the line so that K will be as small as possible. What will be the value of K in the end?
Constraints
* 1 ≤ N ≤ 10^5
* -10^5 ≤ L_i < R_i ≤ 10^5
* L_i and R_i are integers.
Input
Input is given from Standard Input in the following format:
N
L_1 R_1
:
L_N R_N
Output
Print the total distance traveled by Takahashi throughout the game when Takahashi and Aoki acts as above. It is guaranteed that K is always an integer when L_i,R_i are integers.
Examples
Input
3
-5 1
3 7
-4 -2
Output
10
Input
3
1 2
3 4
5 6
Output
12
Input
5
-2 0
-2 0
7 8
9 10
-2 -1
Output
34 | instruction | 0 | 13,991 | 15 | 27,982 |
"Correct Solution:
```
from collections import deque
N=int(input())
Sec=[]
Left1,Right1=[],[]
for i in range(N):
l,r=map(int,input().split())
Sec.append((l,r))
Left1.append((l,i))
Right1.append((r,i))
Left1.sort()
Right1.sort(reverse=True)
Left2=Left1[:]
Right2=Right1[:]
Used=[False]*N
pos=0
n=0
ans1=0
f_l,f_r=0,0
while Left1 or Right1:
if n%2==0:
if not Left1:
n+=1
continue
l,i=Left1[-1]
if Used[i]:
Left1.pop()
continue
if pos<l:
ans1+=l-pos
pos=l
Used[i]=True
Left1.pop()
f_l=0
else:
if f_l==1:
Left1.pop()
f_l=0
else:
f_l=1
n+=1
elif n%2==1:
if not Right1:
n+=1
continue
r,i=Right1[-1]
if Used[i]:
Right1.pop()
continue
if r<pos:
ans1+=pos-r
pos=r
Used[i]=True
Right1.pop()
f_r=0
else:
if f_r==1:
Right1.pop()
f_r=0
else:
f_r=1
n+=1
ans1+=abs(pos)
n=0
ans2=0
Used=[False]*N
f_l,f_r=0,9
pos=0
while Left2 or Right2:
if n%2==1:
if not Left2:
n+=1
continue
l,i=Left2[-1]
if Used[i]:
Left2.pop()
continue
if pos<l:
ans2+=l-pos
pos=l
Used[i]=True
Left2.pop()
f_l=0
else:
if f_l==1:
Left2.pop()
f_l=0
else:
f_l=1
n+=1
elif n%2==0:
if not Right2:
n+=1
continue
r,i=Right2[-1]
if Used[i]:
Right2.pop()
continue
if r<pos:
ans2+=pos-r
pos=r
Used[i]=True
Right2.pop()
f_r=0
else:
if f_r==1:
Right2.pop()
f_r=0
else:
f_r=1
n+=1
ans2+=abs(pos)
print(max(ans1,ans2))
``` | output | 1 | 13,991 | 15 | 27,983 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi and Aoki will play a game with a number line and some segments. Takahashi is standing on the number line and he is initially at coordinate 0. Aoki has N segments. The i-th segment is [L_i,R_i], that is, a segment consisting of points with coordinates between L_i and R_i (inclusive).
The game has N steps. The i-th step proceeds as follows:
* First, Aoki chooses a segment that is still not chosen yet from the N segments and tells it to Takahashi.
* Then, Takahashi walks along the number line to some point within the segment chosen by Aoki this time.
After N steps are performed, Takahashi will return to coordinate 0 and the game ends.
Let K be the total distance traveled by Takahashi throughout the game. Aoki will choose segments so that K will be as large as possible, and Takahashi walks along the line so that K will be as small as possible. What will be the value of K in the end?
Constraints
* 1 ≤ N ≤ 10^5
* -10^5 ≤ L_i < R_i ≤ 10^5
* L_i and R_i are integers.
Input
Input is given from Standard Input in the following format:
N
L_1 R_1
:
L_N R_N
Output
Print the total distance traveled by Takahashi throughout the game when Takahashi and Aoki acts as above. It is guaranteed that K is always an integer when L_i,R_i are integers.
Examples
Input
3
-5 1
3 7
-4 -2
Output
10
Input
3
1 2
3 4
5 6
Output
12
Input
5
-2 0
-2 0
7 8
9 10
-2 -1
Output
34 | instruction | 0 | 13,992 | 15 | 27,984 |
"Correct Solution:
```
N = int(input())
sect = []
sect_l = []
sect_r = []
for i in range(N):
l,r = map(int,input().split())
sect_l.append((l,r,i))
sect_r.append((r,l,i))
sect.append((l,r))
sect_l.sort()
sect_r.sort()
sect_r.reverse()
ans_l,ans_r = 0,0
if sect_r[N-1][0] < 0:
used = [False for i in range(N)]
L = [x for x in sect_l]
R = [x for x in sect_r]
next = 'L'
cur = 0
cnt = 0
while cnt < N:
if next == 'R':
while True:
l,r,i = L.pop()
if not used[i]:
used[i] = True
break
if not (l <= cur and cur <= r):
ans_l += abs(cur - l)
cur = l
next = 'L'
cnt += 1
else:
while True:
r,l,i = R.pop()
if not used[i]:
used[i] = True
break
if not (l <= cur and cur <= r):
ans_l += abs(cur - r)
cur = r
next = 'R'
cnt += 1
ans_l += abs(cur)
if sect_l[N-1][0] > 0:
used = [False for i in range(N)]
L = [x for x in sect_l]
R = [x for x in sect_r]
next = 'R'
cur = 0
cnt = 0
while cnt < N:
if next == 'R':
while True:
l,r,i = L.pop()
if not used[i]:
used[i] = True
break
if not (l <= cur and cur <= r):
ans_r += abs(cur - l)
cur = l
next = 'L'
cnt += 1
else:
while True:
r,l,i = R.pop()
if not used[i]:
used[i] = True
break
if not (l <= cur and cur <= r):
ans_r += abs(cur - r)
cur = r
next = 'R'
cnt += 1
ans_r += abs(cur)
print(max(ans_l,ans_r))
``` | output | 1 | 13,992 | 15 | 27,985 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi and Aoki will play a game with a number line and some segments. Takahashi is standing on the number line and he is initially at coordinate 0. Aoki has N segments. The i-th segment is [L_i,R_i], that is, a segment consisting of points with coordinates between L_i and R_i (inclusive).
The game has N steps. The i-th step proceeds as follows:
* First, Aoki chooses a segment that is still not chosen yet from the N segments and tells it to Takahashi.
* Then, Takahashi walks along the number line to some point within the segment chosen by Aoki this time.
After N steps are performed, Takahashi will return to coordinate 0 and the game ends.
Let K be the total distance traveled by Takahashi throughout the game. Aoki will choose segments so that K will be as large as possible, and Takahashi walks along the line so that K will be as small as possible. What will be the value of K in the end?
Constraints
* 1 ≤ N ≤ 10^5
* -10^5 ≤ L_i < R_i ≤ 10^5
* L_i and R_i are integers.
Input
Input is given from Standard Input in the following format:
N
L_1 R_1
:
L_N R_N
Output
Print the total distance traveled by Takahashi throughout the game when Takahashi and Aoki acts as above. It is guaranteed that K is always an integer when L_i,R_i are integers.
Examples
Input
3
-5 1
3 7
-4 -2
Output
10
Input
3
1 2
3 4
5 6
Output
12
Input
5
-2 0
-2 0
7 8
9 10
-2 -1
Output
34
Submitted Solution:
```
from itertools import accumulate
N = int(input())
L, R = [0], [0]
for i in range(N):
li, ri = map(int, input().split())
L.append(li)
R.append(ri)
L = list(accumulate(sorted(L, reverse=True)))
R = list(accumulate(sorted(R)))
ans = 0
for k in range(N):
ans = max(ans, 2*(L[k] - R[k]))
print(ans)
``` | instruction | 0 | 13,993 | 15 | 27,986 |
Yes | output | 1 | 13,993 | 15 | 27,987 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi and Aoki will play a game with a number line and some segments. Takahashi is standing on the number line and he is initially at coordinate 0. Aoki has N segments. The i-th segment is [L_i,R_i], that is, a segment consisting of points with coordinates between L_i and R_i (inclusive).
The game has N steps. The i-th step proceeds as follows:
* First, Aoki chooses a segment that is still not chosen yet from the N segments and tells it to Takahashi.
* Then, Takahashi walks along the number line to some point within the segment chosen by Aoki this time.
After N steps are performed, Takahashi will return to coordinate 0 and the game ends.
Let K be the total distance traveled by Takahashi throughout the game. Aoki will choose segments so that K will be as large as possible, and Takahashi walks along the line so that K will be as small as possible. What will be the value of K in the end?
Constraints
* 1 ≤ N ≤ 10^5
* -10^5 ≤ L_i < R_i ≤ 10^5
* L_i and R_i are integers.
Input
Input is given from Standard Input in the following format:
N
L_1 R_1
:
L_N R_N
Output
Print the total distance traveled by Takahashi throughout the game when Takahashi and Aoki acts as above. It is guaranteed that K is always an integer when L_i,R_i are integers.
Examples
Input
3
-5 1
3 7
-4 -2
Output
10
Input
3
1 2
3 4
5 6
Output
12
Input
5
-2 0
-2 0
7 8
9 10
-2 -1
Output
34
Submitted Solution:
```
from operator import itemgetter
from collections import deque
N = int(input())
L = [[0,0]]
for i in range(N):
l,r = map(int,input().split())
L.append([l,r])
Q = sorted(L)
R = sorted(L,key=itemgetter(1))
ans = 0
suma=0
for i in range(N//2+1):
suma +=2*(Q[-i-1][0]-R[i][1])
if suma>ans:
ans = suma
print(ans)
``` | instruction | 0 | 13,994 | 15 | 27,988 |
Yes | output | 1 | 13,994 | 15 | 27,989 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi and Aoki will play a game with a number line and some segments. Takahashi is standing on the number line and he is initially at coordinate 0. Aoki has N segments. The i-th segment is [L_i,R_i], that is, a segment consisting of points with coordinates between L_i and R_i (inclusive).
The game has N steps. The i-th step proceeds as follows:
* First, Aoki chooses a segment that is still not chosen yet from the N segments and tells it to Takahashi.
* Then, Takahashi walks along the number line to some point within the segment chosen by Aoki this time.
After N steps are performed, Takahashi will return to coordinate 0 and the game ends.
Let K be the total distance traveled by Takahashi throughout the game. Aoki will choose segments so that K will be as large as possible, and Takahashi walks along the line so that K will be as small as possible. What will be the value of K in the end?
Constraints
* 1 ≤ N ≤ 10^5
* -10^5 ≤ L_i < R_i ≤ 10^5
* L_i and R_i are integers.
Input
Input is given from Standard Input in the following format:
N
L_1 R_1
:
L_N R_N
Output
Print the total distance traveled by Takahashi throughout the game when Takahashi and Aoki acts as above. It is guaranteed that K is always an integer when L_i,R_i are integers.
Examples
Input
3
-5 1
3 7
-4 -2
Output
10
Input
3
1 2
3 4
5 6
Output
12
Input
5
-2 0
-2 0
7 8
9 10
-2 -1
Output
34
Submitted Solution:
```
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
from heapq import heappop,heappush
from copy import deepcopy
n = int(readline())
lr = list(map(int,read().split()))
hq_left = []
hq_right = []
for i in range(n):
l,r = lr[i*2:i*2+2]
heappush(hq_left,(-1*l,i))
heappush(hq_right,(r,i))
hq_left_origin = deepcopy(hq_left)
hq_right_origin = deepcopy(hq_right)
done = [0] * n
ans = -1*10**5
now = 10**5
while(len(hq_left)>0)&(len(hq_right)>0):
while(hq_left):
l,ind_l = hq_left[0]
l *= -1
if(done[ind_l] == 1):
heappop(hq_left)
else:
break
else:
break
while(hq_right):
r,ind_r = hq_right[0]
if(done[ind_r] == 1):
heappop(hq_right)
else:
break
else:
break
if( l-now > now-r):
if(l > now):
ans += l-now
now = l
done[ind_l] = 1
heappop(hq_left)
else:
if(now > r):
ans += now-r
now = r
done[ind_r] = 1
heappop(hq_right)
ans += abs(now)
ans2 = -1*10**5
now = -1 * 10**5
hq_left = deepcopy(hq_left_origin)
hq_right = deepcopy(hq_right_origin)
done = [0] * n
while(len(hq_left)>0)&(len(hq_right)>0):
while(hq_left):
l,ind_l = hq_left[0]
l *= -1
if(done[ind_l] == 1):
heappop(hq_left)
else:
break
else:
break
while(hq_right):
r,ind_r = hq_right[0]
if(done[ind_r] == 1):
heappop(hq_right)
else:
break
else:
break
if( l-now > now-r):
if(l > now):
ans2 += l-now
now = l
done[ind_l] = 1
heappop(hq_left)
else:
if(now > r):
ans2 += now-r
now = r
done[ind_r] = 1
heappop(hq_right)
ans2 += abs(now)
print(max(ans,ans2))
``` | instruction | 0 | 13,995 | 15 | 27,990 |
Yes | output | 1 | 13,995 | 15 | 27,991 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi and Aoki will play a game with a number line and some segments. Takahashi is standing on the number line and he is initially at coordinate 0. Aoki has N segments. The i-th segment is [L_i,R_i], that is, a segment consisting of points with coordinates between L_i and R_i (inclusive).
The game has N steps. The i-th step proceeds as follows:
* First, Aoki chooses a segment that is still not chosen yet from the N segments and tells it to Takahashi.
* Then, Takahashi walks along the number line to some point within the segment chosen by Aoki this time.
After N steps are performed, Takahashi will return to coordinate 0 and the game ends.
Let K be the total distance traveled by Takahashi throughout the game. Aoki will choose segments so that K will be as large as possible, and Takahashi walks along the line so that K will be as small as possible. What will be the value of K in the end?
Constraints
* 1 ≤ N ≤ 10^5
* -10^5 ≤ L_i < R_i ≤ 10^5
* L_i and R_i are integers.
Input
Input is given from Standard Input in the following format:
N
L_1 R_1
:
L_N R_N
Output
Print the total distance traveled by Takahashi throughout the game when Takahashi and Aoki acts as above. It is guaranteed that K is always an integer when L_i,R_i are integers.
Examples
Input
3
-5 1
3 7
-4 -2
Output
10
Input
3
1 2
3 4
5 6
Output
12
Input
5
-2 0
-2 0
7 8
9 10
-2 -1
Output
34
Submitted Solution:
```
from operator import itemgetter
n = int(input())
lr = [list(map(int, input().split())) for i in range(n)] + [[0, 0]]
l_sort = sorted(lr, key=itemgetter(0), reverse=True)
r_sort = sorted(lr, key=itemgetter(1))
ans = 0
sigma = 0
for i in range(n // 2 + 1):
sigma += 2 * (l_sort[i][0] - r_sort[i][1])
if sigma > ans:
ans = sigma
print(ans)
``` | instruction | 0 | 13,996 | 15 | 27,992 |
Yes | output | 1 | 13,996 | 15 | 27,993 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi and Aoki will play a game with a number line and some segments. Takahashi is standing on the number line and he is initially at coordinate 0. Aoki has N segments. The i-th segment is [L_i,R_i], that is, a segment consisting of points with coordinates between L_i and R_i (inclusive).
The game has N steps. The i-th step proceeds as follows:
* First, Aoki chooses a segment that is still not chosen yet from the N segments and tells it to Takahashi.
* Then, Takahashi walks along the number line to some point within the segment chosen by Aoki this time.
After N steps are performed, Takahashi will return to coordinate 0 and the game ends.
Let K be the total distance traveled by Takahashi throughout the game. Aoki will choose segments so that K will be as large as possible, and Takahashi walks along the line so that K will be as small as possible. What will be the value of K in the end?
Constraints
* 1 ≤ N ≤ 10^5
* -10^5 ≤ L_i < R_i ≤ 10^5
* L_i and R_i are integers.
Input
Input is given from Standard Input in the following format:
N
L_1 R_1
:
L_N R_N
Output
Print the total distance traveled by Takahashi throughout the game when Takahashi and Aoki acts as above. It is guaranteed that K is always an integer when L_i,R_i are integers.
Examples
Input
3
-5 1
3 7
-4 -2
Output
10
Input
3
1 2
3 4
5 6
Output
12
Input
5
-2 0
-2 0
7 8
9 10
-2 -1
Output
34
Submitted Solution:
```
#!usr/bin/env python3
from collections import defaultdict,deque
from heapq import heappush, heappop
import sys
import math
import bisect
import random
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def I(): return int(sys.stdin.readline())
def LS():return [list(x) for x in sys.stdin.readline().split()]
def S():
res = list(sys.stdin.readline())
if res[-1] == "\n":
return res[:-1]
return res
def IR(n):
return [I() for i in range(n)]
def LIR(n):
return [LI() for i in range(n)]
def SR(n):
return [S() for i in range(n)]
def LSR(n):
return [LS() for i in range(n)]
sys.setrecursionlimit(1000000)
mod = 1000000007
def solve():
n = I()
p = LIR(n)
p.sort(key = lambda x : max(x[0],min(0,x[1])))
x = 0
ans = 0
l = 0
r = n-1
while l <= r:
a,b = p[l]
l += 1
if x < a:
ans += a-x
x = a
elif b < x:
ans += x-b
x = b
if l > r:
break
a,b = p[r]
r -= 1
if x < a:
ans += a-x
x = a
elif b < x:
ans += x-b
x = b
m = ans+abs(x)
x = 0
ans = 0
l = 0
r = n-1
while l <= r:
a,b = p[r]
r -= 1
if x < a:
ans += a-x
x = a
elif b < x:
ans += x-b
x = b
a,b = p[l]
l += 1
if x < a:
ans += a-x
x = a
elif b < x:
ans += x-b
x = b
if l > r:
break
ans += abs(x)
print(max(m,ans))
return
#Solve
if __name__ == "__main__":
solve()
``` | instruction | 0 | 13,997 | 15 | 27,994 |
No | output | 1 | 13,997 | 15 | 27,995 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi and Aoki will play a game with a number line and some segments. Takahashi is standing on the number line and he is initially at coordinate 0. Aoki has N segments. The i-th segment is [L_i,R_i], that is, a segment consisting of points with coordinates between L_i and R_i (inclusive).
The game has N steps. The i-th step proceeds as follows:
* First, Aoki chooses a segment that is still not chosen yet from the N segments and tells it to Takahashi.
* Then, Takahashi walks along the number line to some point within the segment chosen by Aoki this time.
After N steps are performed, Takahashi will return to coordinate 0 and the game ends.
Let K be the total distance traveled by Takahashi throughout the game. Aoki will choose segments so that K will be as large as possible, and Takahashi walks along the line so that K will be as small as possible. What will be the value of K in the end?
Constraints
* 1 ≤ N ≤ 10^5
* -10^5 ≤ L_i < R_i ≤ 10^5
* L_i and R_i are integers.
Input
Input is given from Standard Input in the following format:
N
L_1 R_1
:
L_N R_N
Output
Print the total distance traveled by Takahashi throughout the game when Takahashi and Aoki acts as above. It is guaranteed that K is always an integer when L_i,R_i are integers.
Examples
Input
3
-5 1
3 7
-4 -2
Output
10
Input
3
1 2
3 4
5 6
Output
12
Input
5
-2 0
-2 0
7 8
9 10
-2 -1
Output
34
Submitted Solution:
```
# coding: utf-8
import sys
import math
import fractions
import heapq
import collections
import re
import array
import bisect
from collections import Counter, defaultdict
def array2d(dim1, dim2, init=None):
return [[init for _ in range(dim2)] for _ in range(dim1)]
def move(p, l, r):
if p < l:
p = l
elif p > r:
p = r
return p
def main():
N = int(input())
hl = []
hr = []
md = (0, 0, 0, 0)
for i in range(N):
l, r = map(int, input().split())
heapq.heappush(hl, (l, r, i))
heapq.heappush(hr, (-r, l, i))
d = abs(move(0, l, r))
# sys.stderr.write("{} -> {}\n".format(str((l, r)), d))
if d > md[0]:
md = (d, i, l, r)
# sys.stderr.write(str(md) + "\n")
used = [False] * N
ans = md[0]
used[md[1]] = True
p = move(0, md[2], md[3])
if p > 0:
mode = 1 # right
else:
mode = 0 # left / center?
while hr and hl:
# sys.stderr.write("pos: {}\n".format(p))
if mode == 0:
if len(hr) == 0:
mode = 1
continue
r, l, i = heapq.heappop(hr)
# sys.stderr.write("r: {}\n".format(str((l, -r, i))))
# sys.stderr.write(" used: {}\n".format(used[i]))
if not used[i]:
used[i] = True
r = -r
np = move(p, l, r)
ans += abs(p-np)
p = np
mode = 1
else:
if len(hl) == 0:
mode = 0
continue
l, r, i = heapq.heappop(hl)
# sys.stderr.write("l: {}\n".format(str((l, r, i))))
# sys.stderr.write(" used: {}\n".format(used[i]))
if not used[i]:
used[i] = True
np = move(p, l, r)
ans += abs(p-np)
p = np
mode = 0
ans += abs(p)
return ans
if __name__ == "__main__":
print(main())
``` | instruction | 0 | 13,998 | 15 | 27,996 |
No | output | 1 | 13,998 | 15 | 27,997 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi and Aoki will play a game with a number line and some segments. Takahashi is standing on the number line and he is initially at coordinate 0. Aoki has N segments. The i-th segment is [L_i,R_i], that is, a segment consisting of points with coordinates between L_i and R_i (inclusive).
The game has N steps. The i-th step proceeds as follows:
* First, Aoki chooses a segment that is still not chosen yet from the N segments and tells it to Takahashi.
* Then, Takahashi walks along the number line to some point within the segment chosen by Aoki this time.
After N steps are performed, Takahashi will return to coordinate 0 and the game ends.
Let K be the total distance traveled by Takahashi throughout the game. Aoki will choose segments so that K will be as large as possible, and Takahashi walks along the line so that K will be as small as possible. What will be the value of K in the end?
Constraints
* 1 ≤ N ≤ 10^5
* -10^5 ≤ L_i < R_i ≤ 10^5
* L_i and R_i are integers.
Input
Input is given from Standard Input in the following format:
N
L_1 R_1
:
L_N R_N
Output
Print the total distance traveled by Takahashi throughout the game when Takahashi and Aoki acts as above. It is guaranteed that K is always an integer when L_i,R_i are integers.
Examples
Input
3
-5 1
3 7
-4 -2
Output
10
Input
3
1 2
3 4
5 6
Output
12
Input
5
-2 0
-2 0
7 8
9 10
-2 -1
Output
34
Submitted Solution:
```
#!usr/bin/env python3
from collections import defaultdict,deque
from heapq import heappush, heappop
import sys
import math
import bisect
import random
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def I(): return int(sys.stdin.readline())
def LS():return [list(x) for x in sys.stdin.readline().split()]
def S():
res = list(sys.stdin.readline())
if res[-1] == "\n":
return res[:-1]
return res
def IR(n):
return [I() for i in range(n)]
def LIR(n):
return [LI() for i in range(n)]
def SR(n):
return [S() for i in range(n)]
def LSR(n):
return [LS() for i in range(n)]
sys.setrecursionlimit(1000000)
mod = 1000000007
def solve():
n = I()
p = LIR(n)
p.sort(key = lambda x : max(x[0],min(0,x[1])))
if p[0][1] < p[-1][0]:
p = p[::-1]
x = 0
ans = 0
l = 0
r = n-1
while l <= r:
a,b = p[l]
l += 1
if x < a:
ans += a-x
x = a
elif b < x:
ans += x-b
x = b
if l > r:
break
a,b = p[r]
r -= 1
if x < a:
ans += a-x
x = a
elif b < x:
ans += x-b
x = b
ans += abs(x)
print(ans)
return
#Solve
if __name__ == "__main__":
solve()
``` | instruction | 0 | 13,999 | 15 | 27,998 |
No | output | 1 | 13,999 | 15 | 27,999 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi and Aoki will play a game with a number line and some segments. Takahashi is standing on the number line and he is initially at coordinate 0. Aoki has N segments. The i-th segment is [L_i,R_i], that is, a segment consisting of points with coordinates between L_i and R_i (inclusive).
The game has N steps. The i-th step proceeds as follows:
* First, Aoki chooses a segment that is still not chosen yet from the N segments and tells it to Takahashi.
* Then, Takahashi walks along the number line to some point within the segment chosen by Aoki this time.
After N steps are performed, Takahashi will return to coordinate 0 and the game ends.
Let K be the total distance traveled by Takahashi throughout the game. Aoki will choose segments so that K will be as large as possible, and Takahashi walks along the line so that K will be as small as possible. What will be the value of K in the end?
Constraints
* 1 ≤ N ≤ 10^5
* -10^5 ≤ L_i < R_i ≤ 10^5
* L_i and R_i are integers.
Input
Input is given from Standard Input in the following format:
N
L_1 R_1
:
L_N R_N
Output
Print the total distance traveled by Takahashi throughout the game when Takahashi and Aoki acts as above. It is guaranteed that K is always an integer when L_i,R_i are integers.
Examples
Input
3
-5 1
3 7
-4 -2
Output
10
Input
3
1 2
3 4
5 6
Output
12
Input
5
-2 0
-2 0
7 8
9 10
-2 -1
Output
34
Submitted Solution:
```
import heapq as hq
N = int(input())
ispush = []
L,R = [],[]
LR = []
for i in range(N):
l,r = map(int,input().split())
hq.heappush(L,(l*(-1),i)) #取り出す時は-1を掛け直すことに注意
hq.heappush(R,(r,i))
LR.append([l,r])
ispush.append(False)
side = True #Trueで右(Lを追う側に行く)
sl = min(L)[0]*(-1) #実質max
sr = min(R)[0]
if sl*sr>0: #同符号
if sl>0: side = True
else: side = False
else: #異符号
if abs(sr)>abs(sl): side = False
ans = 0
now = 0
for i in range(N):
#選ぶ
mov = 0
if side: #L追う
while(True):
if len(L)==0:break
mov = hq.heappop(L)
if not ispush[mov[1]]: break
else:
while(True):
if len(R)==0:break
mov = hq.heappop(R)
if not ispush[mov[1]]: break
ispush[mov[1]] = True
#移動する
if now < LR[mov[1]][0] or LR[mov[1]][1] < now:
if side:
ans += abs((mov[0]*(-1))-now)
now = mov[0]*(-1)
else:
ans += abs(mov[0]-now)
now = mov[0]
if side: side=False
else: side=True
#print(now)
print(ans+abs(now))
``` | instruction | 0 | 14,000 | 15 | 28,000 |
No | output | 1 | 14,000 | 15 | 28,001 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Happy Farm 5 creators decided to invent the mechanism of cow grazing. The cows in the game are very slow and they move very slowly, it can even be considered that they stand still. However, carnivores should always be chased off them.
For that a young player Vasya decided to make the shepherd run round the cows along one and the same closed path. It is very important that the cows stayed strictly inside the area limited by the path, as otherwise some cows will sooner or later be eaten. To be absolutely sure in the cows' safety, Vasya wants the path completion time to be minimum.
The new game is launched for different devices, including mobile phones. That's why the developers decided to quit using the arithmetics with the floating decimal point and use only the arithmetics of integers. The cows and the shepherd in the game are represented as points on the plane with integer coordinates. The playing time is modeled by the turns. During every turn the shepherd can either stay where he stands or step in one of eight directions: horizontally, vertically, or diagonally. As the coordinates should always remain integer, then the length of a horizontal and vertical step is equal to 1, and the length of a diagonal step is equal to <image>. The cows do not move. You have to minimize the number of moves the shepherd needs to run round the whole herd.
Input
The first line contains an integer N which represents the number of cows in the herd (1 ≤ N ≤ 105). Each of the next N lines contains two integers Xi and Yi which represent the coordinates of one cow of (|Xi|, |Yi| ≤ 106). Several cows can stand on one point.
Output
Print the single number — the minimum number of moves in the sought path.
Examples
Input
4
1 1
5 1
5 3
1 3
Output
16
Note
Picture for the example test: The coordinate grid is painted grey, the coordinates axes are painted black, the cows are painted red and the sought route is painted green.
<image> | instruction | 0 | 15,457 | 15 | 30,914 |
Tags: geometry
Correct Solution:
```
def O3():
n = int(input())
maxh = maxw = -10 ** 6
minh = minw = 10**6
for _ in range(n):
x, y = [int(x) for x in input().split()]
h, w = x + y, x-y
maxh= max(maxh, h)
minh = min(minh, h)
maxw = max(maxw, w)
minw = min(minw, w)
print(maxh-minh + maxw - minw + 4)
if __name__ == '__main__':
O3()
``` | output | 1 | 15,457 | 15 | 30,915 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Happy Farm 5 creators decided to invent the mechanism of cow grazing. The cows in the game are very slow and they move very slowly, it can even be considered that they stand still. However, carnivores should always be chased off them.
For that a young player Vasya decided to make the shepherd run round the cows along one and the same closed path. It is very important that the cows stayed strictly inside the area limited by the path, as otherwise some cows will sooner or later be eaten. To be absolutely sure in the cows' safety, Vasya wants the path completion time to be minimum.
The new game is launched for different devices, including mobile phones. That's why the developers decided to quit using the arithmetics with the floating decimal point and use only the arithmetics of integers. The cows and the shepherd in the game are represented as points on the plane with integer coordinates. The playing time is modeled by the turns. During every turn the shepherd can either stay where he stands or step in one of eight directions: horizontally, vertically, or diagonally. As the coordinates should always remain integer, then the length of a horizontal and vertical step is equal to 1, and the length of a diagonal step is equal to <image>. The cows do not move. You have to minimize the number of moves the shepherd needs to run round the whole herd.
Input
The first line contains an integer N which represents the number of cows in the herd (1 ≤ N ≤ 105). Each of the next N lines contains two integers Xi and Yi which represent the coordinates of one cow of (|Xi|, |Yi| ≤ 106). Several cows can stand on one point.
Output
Print the single number — the minimum number of moves in the sought path.
Examples
Input
4
1 1
5 1
5 3
1 3
Output
16
Note
Picture for the example test: The coordinate grid is painted grey, the coordinates axes are painted black, the cows are painted red and the sought route is painted green.
<image> | instruction | 0 | 15,458 | 15 | 30,916 |
Tags: geometry
Correct Solution:
```
n = int(input())
# Each of the next N lines contains two integers Xi and Yi which represent the coordinates of one cow of (|Xi|, |Yi| ≤ 106). Several cows can stand on one point.
x1 = y1 = -(10**7)
x2 = y2 = 10**7
for i in range(1, n+1):
mylist = list(map(int, input().split()))
x1 = max(x1, mylist[0]+mylist[1])
y1 = max(y1, mylist[0]-mylist[1])
x2 = min(x2, mylist[0]+mylist[1])
y2 = min(y2, mylist[0]-mylist[1])
# plus 1 for diagonal case (on point +1) => 4 points => +4
total = x1 + y1 - x2 - y2 + 4
print(total)
``` | output | 1 | 15,458 | 15 | 30,917 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Happy Farm 5 creators decided to invent the mechanism of cow grazing. The cows in the game are very slow and they move very slowly, it can even be considered that they stand still. However, carnivores should always be chased off them.
For that a young player Vasya decided to make the shepherd run round the cows along one and the same closed path. It is very important that the cows stayed strictly inside the area limited by the path, as otherwise some cows will sooner or later be eaten. To be absolutely sure in the cows' safety, Vasya wants the path completion time to be minimum.
The new game is launched for different devices, including mobile phones. That's why the developers decided to quit using the arithmetics with the floating decimal point and use only the arithmetics of integers. The cows and the shepherd in the game are represented as points on the plane with integer coordinates. The playing time is modeled by the turns. During every turn the shepherd can either stay where he stands or step in one of eight directions: horizontally, vertically, or diagonally. As the coordinates should always remain integer, then the length of a horizontal and vertical step is equal to 1, and the length of a diagonal step is equal to <image>. The cows do not move. You have to minimize the number of moves the shepherd needs to run round the whole herd.
Input
The first line contains an integer N which represents the number of cows in the herd (1 ≤ N ≤ 105). Each of the next N lines contains two integers Xi and Yi which represent the coordinates of one cow of (|Xi|, |Yi| ≤ 106). Several cows can stand on one point.
Output
Print the single number — the minimum number of moves in the sought path.
Examples
Input
4
1 1
5 1
5 3
1 3
Output
16
Note
Picture for the example test: The coordinate grid is painted grey, the coordinates axes are painted black, the cows are painted red and the sought route is painted green.
<image> | instruction | 0 | 15,459 | 15 | 30,918 |
Tags: geometry
Correct Solution:
```
import math
n = int(input())
l = []
for i in range(n):
l.append(tuple(list(map(int, input().split(" ")))))
l = list(set(l))
n = len(l)
pmin = 0
for i in range(1, n):
if(l[i][1] < l[pmin][1] or (l[i][1] == l[pmin][1] and l[i][0] < l[pmin][0])):
pmin = i
l[pmin], l[0] = l[0], l[pmin]
def orientation(p0, p1, p2):
x = (p1[1] - p0[1]) * (p2[0] - p1[0]) - (p1[0] - p0[0]) * (p2[1] - p1[1])
if(x < 0):
return -1
if(x > 0):
return 1
return 0
l = [(p[0] - l[0][0], p[1] - l[0][1]) for p in l[1:]]
l.sort(key = lambda p: (-p[0]/p[1] if(p[1] != 0) else -10e14, p[0] ** 2 + p[1] ** 2))
l = [(0, 0)] + l
t = [l[0]]
i = 1
n = len(l)
while(1):
while(i < n - 1 and orientation(l[0], l[i], l[i + 1]) == 0):
i += 1
if(i >= n - 1):
break
t.append(l[i])
i += 1
t.append(l[-1])
if(len(t) == 1):
print(4)
elif(len(t) == 2):
print(max(abs(t[1][1] - t[0][1]), abs(t[1][0] - t[0][0])) * 2 + 4)
else:
stack = [t[0], t[1], t[2]]
for i in range(3, len(t)):
while(orientation(stack[-2], stack[-1], t[i]) == 1):
stack.pop()
stack.append(t[i])
n = len(stack)
s = 4
for i in range(n - 1):
s += max(abs(stack[i + 1][1] - stack[i][1]), abs(stack[i + 1][0] - stack[i][0]))
s += max(abs(stack[0][1] - stack[n - 1][1]), abs(stack[0][0] - stack[n - 1][0]))
print(s)
``` | output | 1 | 15,459 | 15 | 30,919 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Happy Farm 5 creators decided to invent the mechanism of cow grazing. The cows in the game are very slow and they move very slowly, it can even be considered that they stand still. However, carnivores should always be chased off them.
For that a young player Vasya decided to make the shepherd run round the cows along one and the same closed path. It is very important that the cows stayed strictly inside the area limited by the path, as otherwise some cows will sooner or later be eaten. To be absolutely sure in the cows' safety, Vasya wants the path completion time to be minimum.
The new game is launched for different devices, including mobile phones. That's why the developers decided to quit using the arithmetics with the floating decimal point and use only the arithmetics of integers. The cows and the shepherd in the game are represented as points on the plane with integer coordinates. The playing time is modeled by the turns. During every turn the shepherd can either stay where he stands or step in one of eight directions: horizontally, vertically, or diagonally. As the coordinates should always remain integer, then the length of a horizontal and vertical step is equal to 1, and the length of a diagonal step is equal to <image>. The cows do not move. You have to minimize the number of moves the shepherd needs to run round the whole herd.
Input
The first line contains an integer N which represents the number of cows in the herd (1 ≤ N ≤ 105). Each of the next N lines contains two integers Xi and Yi which represent the coordinates of one cow of (|Xi|, |Yi| ≤ 106). Several cows can stand on one point.
Output
Print the single number — the minimum number of moves in the sought path.
Examples
Input
4
1 1
5 1
5 3
1 3
Output
16
Note
Picture for the example test: The coordinate grid is painted grey, the coordinates axes are painted black, the cows are painted red and the sought route is painted green.
<image> | instruction | 0 | 15,460 | 15 | 30,920 |
Tags: geometry
Correct Solution:
```
n = int(input())
x, y = map(int, input().split())
max_x = min_x = x
max_y = min_y = y
sum_pp = x + y
sum_pn = x - y
sum_np = -x + y
sum_nn = -x - y
for i in range(1, n):
x, y = map(int, input().split())
max_x = max(max_x, x)
min_x = min(min_x, x)
max_y = max(max_y, y)
min_y = min(min_y, y)
if x + y > sum_pp:
sum_pp = x + y
if x - y > sum_pn:
sum_pn = x - y
if -x + y > sum_np:
sum_np = -x + y
if -x - y > sum_nn:
sum_nn = -x - y
box = 2 * (max_x - min_x + max_y - min_y)
box -= max_x + max_y - sum_pp
box -= max_x - min_y - sum_pn
box -= -min_x + max_y - sum_np
box -= -min_x - min_y - sum_nn
box += 4
print(box)
``` | output | 1 | 15,460 | 15 | 30,921 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Happy Farm 5 creators decided to invent the mechanism of cow grazing. The cows in the game are very slow and they move very slowly, it can even be considered that they stand still. However, carnivores should always be chased off them.
For that a young player Vasya decided to make the shepherd run round the cows along one and the same closed path. It is very important that the cows stayed strictly inside the area limited by the path, as otherwise some cows will sooner or later be eaten. To be absolutely sure in the cows' safety, Vasya wants the path completion time to be minimum.
The new game is launched for different devices, including mobile phones. That's why the developers decided to quit using the arithmetics with the floating decimal point and use only the arithmetics of integers. The cows and the shepherd in the game are represented as points on the plane with integer coordinates. The playing time is modeled by the turns. During every turn the shepherd can either stay where he stands or step in one of eight directions: horizontally, vertically, or diagonally. As the coordinates should always remain integer, then the length of a horizontal and vertical step is equal to 1, and the length of a diagonal step is equal to <image>. The cows do not move. You have to minimize the number of moves the shepherd needs to run round the whole herd.
Input
The first line contains an integer N which represents the number of cows in the herd (1 ≤ N ≤ 105). Each of the next N lines contains two integers Xi and Yi which represent the coordinates of one cow of (|Xi|, |Yi| ≤ 106). Several cows can stand on one point.
Output
Print the single number — the minimum number of moves in the sought path.
Examples
Input
4
1 1
5 1
5 3
1 3
Output
16
Note
Picture for the example test: The coordinate grid is painted grey, the coordinates axes are painted black, the cows are painted red and the sought route is painted green.
<image> | instruction | 0 | 15,461 | 15 | 30,922 |
Tags: geometry
Correct Solution:
```
n=int(input())
mh=sh=-10**7
ml=sl=10**7
for i in range(n):
a,b=map(int,input().split())
m,s=a+b,a-b
mh=max(mh,m)
ml=min(ml,m)
sh=max(sh,s)
sl=min(sl,s)
print(mh-ml+sh-sl+4)
``` | output | 1 | 15,461 | 15 | 30,923 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Happy Farm 5 creators decided to invent the mechanism of cow grazing. The cows in the game are very slow and they move very slowly, it can even be considered that they stand still. However, carnivores should always be chased off them.
For that a young player Vasya decided to make the shepherd run round the cows along one and the same closed path. It is very important that the cows stayed strictly inside the area limited by the path, as otherwise some cows will sooner or later be eaten. To be absolutely sure in the cows' safety, Vasya wants the path completion time to be minimum.
The new game is launched for different devices, including mobile phones. That's why the developers decided to quit using the arithmetics with the floating decimal point and use only the arithmetics of integers. The cows and the shepherd in the game are represented as points on the plane with integer coordinates. The playing time is modeled by the turns. During every turn the shepherd can either stay where he stands or step in one of eight directions: horizontally, vertically, or diagonally. As the coordinates should always remain integer, then the length of a horizontal and vertical step is equal to 1, and the length of a diagonal step is equal to <image>. The cows do not move. You have to minimize the number of moves the shepherd needs to run round the whole herd.
Input
The first line contains an integer N which represents the number of cows in the herd (1 ≤ N ≤ 105). Each of the next N lines contains two integers Xi and Yi which represent the coordinates of one cow of (|Xi|, |Yi| ≤ 106). Several cows can stand on one point.
Output
Print the single number — the minimum number of moves in the sought path.
Examples
Input
4
1 1
5 1
5 3
1 3
Output
16
Note
Picture for the example test: The coordinate grid is painted grey, the coordinates axes are painted black, the cows are painted red and the sought route is painted green.
<image>
Submitted Solution:
```
a=int(input())
x=[]
y=[]
for i in range (a):
b=input().split()
x.append(b[0])
y.append(b[1])
xm=x[0]
ym=y[0]
for i in x:
if int(i)>=int(xm):
xm=int(i)
else:
continue
for i in y:
if int(i)>=int(ym):
ym=int(i)
else:
continue
print(2*(xm+ym))
``` | instruction | 0 | 15,462 | 15 | 30,924 |
No | output | 1 | 15,462 | 15 | 30,925 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Happy Farm 5 creators decided to invent the mechanism of cow grazing. The cows in the game are very slow and they move very slowly, it can even be considered that they stand still. However, carnivores should always be chased off them.
For that a young player Vasya decided to make the shepherd run round the cows along one and the same closed path. It is very important that the cows stayed strictly inside the area limited by the path, as otherwise some cows will sooner or later be eaten. To be absolutely sure in the cows' safety, Vasya wants the path completion time to be minimum.
The new game is launched for different devices, including mobile phones. That's why the developers decided to quit using the arithmetics with the floating decimal point and use only the arithmetics of integers. The cows and the shepherd in the game are represented as points on the plane with integer coordinates. The playing time is modeled by the turns. During every turn the shepherd can either stay where he stands or step in one of eight directions: horizontally, vertically, or diagonally. As the coordinates should always remain integer, then the length of a horizontal and vertical step is equal to 1, and the length of a diagonal step is equal to <image>. The cows do not move. You have to minimize the number of moves the shepherd needs to run round the whole herd.
Input
The first line contains an integer N which represents the number of cows in the herd (1 ≤ N ≤ 105). Each of the next N lines contains two integers Xi and Yi which represent the coordinates of one cow of (|Xi|, |Yi| ≤ 106). Several cows can stand on one point.
Output
Print the single number — the minimum number of moves in the sought path.
Examples
Input
4
1 1
5 1
5 3
1 3
Output
16
Note
Picture for the example test: The coordinate grid is painted grey, the coordinates axes are painted black, the cows are painted red and the sought route is painted green.
<image>
Submitted Solution:
```
import math
n = int(input())
l = []
for i in range(n):
l.append(tuple(list(map(int, input().split(" ")))))
l = list(set(l))
n = len(l)
pmin = 0
for i in range(1, n):
if(l[i][1] < l[pmin][1] or (l[i][1] == l[pmin][1] and l[i][0] < l[pmin][0])):
pmin = i
l[pmin], l[0] = l[0], l[pmin]
def orientation(p0, p1, p2):
x = (p1[1] - p0[1]) * (p2[0] - p1[0]) - (p1[0] - p0[0]) * (p2[1] - p1[1])
if(x < 0):
return -1
if(x > 0):
return 1
return 0
l = [(p[0] - l[0][0], p[1] - l[0][1]) for p in l[1:]]
def custom1(p):
if(p[0] < 0):
return abs(p[0]/p[1])
if(p[0] > 0):
return -abs(p[1]/p[0])
return 0
def custom2(p):
return p[0] ** 2 + p[1] ** 2
l.sort(key = lambda p: (custom1(p), custom2(p)))
l = [(0, 0)] + l
t = [l[0]]
i = 1
n = len(l)
while(1):
while(i < n - 1 and orientation(l[0], l[i], l[i + 1]) == 0):
i += 1
if(i >= n - 1):
break
t.append(l[i])
i += 1
t.append(l[-1])
if(len(t) == 1):
print(4)
elif(len(t) == 2):
print(max(abs(t[1][1] - t[0][1]), abs(t[1][0] - t[0][0])) * 2 + 4)
else:
stack = [t[0], t[1], t[2]]
for i in range(3, len(t)):
while(orientation(stack[-2], stack[-1], t[i]) == 1):
stack.pop()
stack.append(t[i])
n = len(stack)
s = 4
for i in range(n - 1):
s += max(abs(stack[i + 1][1] - stack[i][1]), abs(stack[i + 1][0] - stack[i][0]))
s += max(abs(stack[0][1] - stack[n - 1][1]), abs(stack[0][0] - stack[n - 1][0]))
print(s)
``` | instruction | 0 | 15,463 | 15 | 30,926 |
No | output | 1 | 15,463 | 15 | 30,927 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Happy Farm 5 creators decided to invent the mechanism of cow grazing. The cows in the game are very slow and they move very slowly, it can even be considered that they stand still. However, carnivores should always be chased off them.
For that a young player Vasya decided to make the shepherd run round the cows along one and the same closed path. It is very important that the cows stayed strictly inside the area limited by the path, as otherwise some cows will sooner or later be eaten. To be absolutely sure in the cows' safety, Vasya wants the path completion time to be minimum.
The new game is launched for different devices, including mobile phones. That's why the developers decided to quit using the arithmetics with the floating decimal point and use only the arithmetics of integers. The cows and the shepherd in the game are represented as points on the plane with integer coordinates. The playing time is modeled by the turns. During every turn the shepherd can either stay where he stands or step in one of eight directions: horizontally, vertically, or diagonally. As the coordinates should always remain integer, then the length of a horizontal and vertical step is equal to 1, and the length of a diagonal step is equal to <image>. The cows do not move. You have to minimize the number of moves the shepherd needs to run round the whole herd.
Input
The first line contains an integer N which represents the number of cows in the herd (1 ≤ N ≤ 105). Each of the next N lines contains two integers Xi and Yi which represent the coordinates of one cow of (|Xi|, |Yi| ≤ 106). Several cows can stand on one point.
Output
Print the single number — the minimum number of moves in the sought path.
Examples
Input
4
1 1
5 1
5 3
1 3
Output
16
Note
Picture for the example test: The coordinate grid is painted grey, the coordinates axes are painted black, the cows are painted red and the sought route is painted green.
<image>
Submitted Solution:
```
a=int(input())
x=[]
y=[]
for i in range (a):
b=input().split()
x.append(b[0])
y.append(b[1])
xm=x[0]
ym=y[0]
for i in x:
if int(i)>=int(x[0]):
xm=int(i)
else:
continue
for i in y:
if int(i)>=int(y[0]):
ym=int(i)
else:
continue
print(2*(xm+ym))
``` | instruction | 0 | 15,464 | 15 | 30,928 |
No | output | 1 | 15,464 | 15 | 30,929 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Happy Farm 5 creators decided to invent the mechanism of cow grazing. The cows in the game are very slow and they move very slowly, it can even be considered that they stand still. However, carnivores should always be chased off them.
For that a young player Vasya decided to make the shepherd run round the cows along one and the same closed path. It is very important that the cows stayed strictly inside the area limited by the path, as otherwise some cows will sooner or later be eaten. To be absolutely sure in the cows' safety, Vasya wants the path completion time to be minimum.
The new game is launched for different devices, including mobile phones. That's why the developers decided to quit using the arithmetics with the floating decimal point and use only the arithmetics of integers. The cows and the shepherd in the game are represented as points on the plane with integer coordinates. The playing time is modeled by the turns. During every turn the shepherd can either stay where he stands or step in one of eight directions: horizontally, vertically, or diagonally. As the coordinates should always remain integer, then the length of a horizontal and vertical step is equal to 1, and the length of a diagonal step is equal to <image>. The cows do not move. You have to minimize the number of moves the shepherd needs to run round the whole herd.
Input
The first line contains an integer N which represents the number of cows in the herd (1 ≤ N ≤ 105). Each of the next N lines contains two integers Xi and Yi which represent the coordinates of one cow of (|Xi|, |Yi| ≤ 106). Several cows can stand on one point.
Output
Print the single number — the minimum number of moves in the sought path.
Examples
Input
4
1 1
5 1
5 3
1 3
Output
16
Note
Picture for the example test: The coordinate grid is painted grey, the coordinates axes are painted black, the cows are painted red and the sought route is painted green.
<image>
Submitted Solution:
```
import functools
n = int(input())
l = []
for i in range(n):
l.append(tuple(list(map(int, input().split(" ")))))
l = list(set(l))
n = len(l)
pmin = 0
for i in range(1, n):
if(l[i][1] < l[pmin][1] or (l[i][1] == l[pmin][1] and l[i][0] < l[pmin][0])):
pmin = i
l[pmin], l[0] = l[0], l[pmin]
def orientation(p0, p1, p2):
x = (p1[1] - p0[1]) * (p2[0] - p1[0]) - (p1[0] - p0[0]) * (p2[1] - p1[1])
if(x < 0):
return -1
if(x > 0):
return 1
return 0
def construct(p0):
def compare(p1, p2):
ox = orientation(p0, p1, p2)
if(ox == 0):
d1 = (p1[0] - p0[0]) ** 2 + (p1[1] - p0[1]) ** 2
d2 = (p2[0] - p0[0]) ** 2 + (p2[1] - p0[1]) ** 2
if(d1 < d2):
return -1
return 1
return ox
return compare
l[1:] = sorted(l[1:], key = functools.cmp_to_key(construct(l[0])))
t = [l[0]]
i = 1
n = len(l)
while(1):
while(i < n - 1 and orientation(l[0], l[i], l[i + 1]) == 0):
i += 1
t.append(l[i])
i += 1
if(i >= n - 1):
break
t.append(l[-1])
if(len(t) == 1):
print(4)
elif(len(t) == 2):
print(max(abs(t[1][1] - t[0][1]), abs(t[1][0] - t[0][0])) * 2 + 4)
else:
stack = [t[0], t[1], t[2]]
for i in range(3, len(t)):
while(orientation(stack[-2], stack[-1], t[i]) == 1):
stack.pop()
stack.append(t[i])
n = len(stack)
s = 4
for i in range(n - 1):
s += max(abs(t[i + 1][1] - t[i][1]), abs(t[i + 1][0] - t[i][0]))
s += max(abs(t[0][1] - t[n - 1][1]), abs(t[0][0] - t[n - 1][0]))
print(s)
``` | instruction | 0 | 15,465 | 15 | 30,930 |
No | output | 1 | 15,465 | 15 | 30,931 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In the spirit of the holidays, Saitama has given Genos two grid paths of length n (a weird gift even by Saitama's standards). A grid path is an ordered sequence of neighbouring squares in an infinite grid. Two squares are neighbouring if they share a side.
One example of a grid path is (0, 0) → (0, 1) → (0, 2) → (1, 2) → (1, 1) → (0, 1) → ( - 1, 1). Note that squares in this sequence might be repeated, i.e. path has self intersections.
Movement within a grid path is restricted to adjacent squares within the sequence. That is, from the i-th square, one can only move to the (i - 1)-th or (i + 1)-th squares of this path. Note that there is only a single valid move from the first and last squares of a grid path. Also note, that even if there is some j-th square of the path that coincides with the i-th square, only moves to (i - 1)-th and (i + 1)-th squares are available. For example, from the second square in the above sequence, one can only move to either the first or third squares.
To ensure that movement is not ambiguous, the two grid paths will not have an alternating sequence of three squares. For example, a contiguous subsequence (0, 0) → (0, 1) → (0, 0) cannot occur in a valid grid path.
One marble is placed on the first square of each grid path. Genos wants to get both marbles to the last square of each grid path. However, there is a catch. Whenever he moves one marble, the other marble will copy its movement if possible. For instance, if one marble moves east, then the other marble will try and move east as well. By try, we mean if moving east is a valid move, then the marble will move east.
Moving north increases the second coordinate by 1, while moving south decreases it by 1. Similarly, moving east increases first coordinate by 1, while moving west decreases it.
Given these two valid grid paths, Genos wants to know if it is possible to move both marbles to the ends of their respective paths. That is, if it is possible to move the marbles such that both marbles rest on the last square of their respective paths.
Input
The first line of the input contains a single integer n (2 ≤ n ≤ 1 000 000) — the length of the paths.
The second line of the input contains a string consisting of n - 1 characters (each of which is either 'N', 'E', 'S', or 'W') — the first grid path. The characters can be thought of as the sequence of moves needed to traverse the grid path. For example, the example path in the problem statement can be expressed by the string "NNESWW".
The third line of the input contains a string of n - 1 characters (each of which is either 'N', 'E', 'S', or 'W') — the second grid path.
Output
Print "YES" (without quotes) if it is possible for both marbles to be at the end position at the same time. Print "NO" (without quotes) otherwise. In both cases, the answer is case-insensitive.
Examples
Input
7
NNESWW
SWSWSW
Output
YES
Input
3
NN
SS
Output
NO
Note
In the first sample, the first grid path is the one described in the statement. Moreover, the following sequence of moves will get both marbles to the end: NNESWWSWSW.
In the second sample, no sequence of moves can get both marbles to the end. | instruction | 0 | 15,490 | 15 | 30,980 |
Tags: hashing, strings
Correct Solution:
```
from time import time
opposite = {
'N': 'S',
'S': 'N',
'E': 'W',
'W': 'E'
}
otr = str.maketrans(opposite)
bits = {
'N': 0,
'S': 1,
'E': 2,
'W': 3,
}
Q = 4294967291
def combine(h, v, q):
return (h<<2 | v) % q
def combinel(h, v, q, s):
return (v*s + h) % q
def flip(s):
return ''.join(reversed(s.translate(otr)))
def solvable(p1, p2):
h1 = 0
h2 = 0
s = 1
for i in reversed(range(len(p1))):
n1 = bits[p1[i]]
n2 = bits[opposite[p2[i]]]
h1 = combine(h1, n1, Q)
h2 = combinel(h2, n2, Q, s)
if h1 == h2 and p1[i:] == flip(p2[i:]):
return False
s = (s<<2) % Q
return True
if __name__ == '__main__':
n = int(input())
p1 = input()
p2 = input()
print('YES' if solvable(p1, p2) else 'NO')
# Made By Mostafa_Khaled
``` | output | 1 | 15,490 | 15 | 30,981 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In the spirit of the holidays, Saitama has given Genos two grid paths of length n (a weird gift even by Saitama's standards). A grid path is an ordered sequence of neighbouring squares in an infinite grid. Two squares are neighbouring if they share a side.
One example of a grid path is (0, 0) → (0, 1) → (0, 2) → (1, 2) → (1, 1) → (0, 1) → ( - 1, 1). Note that squares in this sequence might be repeated, i.e. path has self intersections.
Movement within a grid path is restricted to adjacent squares within the sequence. That is, from the i-th square, one can only move to the (i - 1)-th or (i + 1)-th squares of this path. Note that there is only a single valid move from the first and last squares of a grid path. Also note, that even if there is some j-th square of the path that coincides with the i-th square, only moves to (i - 1)-th and (i + 1)-th squares are available. For example, from the second square in the above sequence, one can only move to either the first or third squares.
To ensure that movement is not ambiguous, the two grid paths will not have an alternating sequence of three squares. For example, a contiguous subsequence (0, 0) → (0, 1) → (0, 0) cannot occur in a valid grid path.
One marble is placed on the first square of each grid path. Genos wants to get both marbles to the last square of each grid path. However, there is a catch. Whenever he moves one marble, the other marble will copy its movement if possible. For instance, if one marble moves east, then the other marble will try and move east as well. By try, we mean if moving east is a valid move, then the marble will move east.
Moving north increases the second coordinate by 1, while moving south decreases it by 1. Similarly, moving east increases first coordinate by 1, while moving west decreases it.
Given these two valid grid paths, Genos wants to know if it is possible to move both marbles to the ends of their respective paths. That is, if it is possible to move the marbles such that both marbles rest on the last square of their respective paths.
Input
The first line of the input contains a single integer n (2 ≤ n ≤ 1 000 000) — the length of the paths.
The second line of the input contains a string consisting of n - 1 characters (each of which is either 'N', 'E', 'S', or 'W') — the first grid path. The characters can be thought of as the sequence of moves needed to traverse the grid path. For example, the example path in the problem statement can be expressed by the string "NNESWW".
The third line of the input contains a string of n - 1 characters (each of which is either 'N', 'E', 'S', or 'W') — the second grid path.
Output
Print "YES" (without quotes) if it is possible for both marbles to be at the end position at the same time. Print "NO" (without quotes) otherwise. In both cases, the answer is case-insensitive.
Examples
Input
7
NNESWW
SWSWSW
Output
YES
Input
3
NN
SS
Output
NO
Note
In the first sample, the first grid path is the one described in the statement. Moreover, the following sequence of moves will get both marbles to the end: NNESWWSWSW.
In the second sample, no sequence of moves can get both marbles to the end.
Submitted Solution:
```
import heapq
opposite = {
'N': 'S',
'S': 'N',
'E': 'W',
'W': 'E'
}
def move(m, i, p):
if i < len(p) and m == p[i]:
return i+1
elif i > 0 and opposite[m] == p[i-1]:
return i-1
else:
return i
def solvable(p1, p2):
n = len(p1)
pq = [(n, (0, 0))]
seen = {(0, 0)}
while pq:
_, (i, j) = heapq.heappop(pq)
print(p1[:i]+"|"+p1[i:])
print(p2[:j]+"|"+p2[j:])
print()
if i == j == n:
return True
for m in 'NEWS':
i_ = move(m, i, p1)
j_ = move(m, j, p2)
ij_ = i_, j_
if ij_ not in seen:
seen.add(ij_)
heapq.heappush(pq, (n-min(i_, j_), ij_))
return False
if __name__ == '__main__':
n = int(input())
p1 = input()
p2 = input()
print('YES' if solvable(p1, p2) else 'NO')
``` | instruction | 0 | 15,491 | 15 | 30,982 |
No | output | 1 | 15,491 | 15 | 30,983 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In the spirit of the holidays, Saitama has given Genos two grid paths of length n (a weird gift even by Saitama's standards). A grid path is an ordered sequence of neighbouring squares in an infinite grid. Two squares are neighbouring if they share a side.
One example of a grid path is (0, 0) → (0, 1) → (0, 2) → (1, 2) → (1, 1) → (0, 1) → ( - 1, 1). Note that squares in this sequence might be repeated, i.e. path has self intersections.
Movement within a grid path is restricted to adjacent squares within the sequence. That is, from the i-th square, one can only move to the (i - 1)-th or (i + 1)-th squares of this path. Note that there is only a single valid move from the first and last squares of a grid path. Also note, that even if there is some j-th square of the path that coincides with the i-th square, only moves to (i - 1)-th and (i + 1)-th squares are available. For example, from the second square in the above sequence, one can only move to either the first or third squares.
To ensure that movement is not ambiguous, the two grid paths will not have an alternating sequence of three squares. For example, a contiguous subsequence (0, 0) → (0, 1) → (0, 0) cannot occur in a valid grid path.
One marble is placed on the first square of each grid path. Genos wants to get both marbles to the last square of each grid path. However, there is a catch. Whenever he moves one marble, the other marble will copy its movement if possible. For instance, if one marble moves east, then the other marble will try and move east as well. By try, we mean if moving east is a valid move, then the marble will move east.
Moving north increases the second coordinate by 1, while moving south decreases it by 1. Similarly, moving east increases first coordinate by 1, while moving west decreases it.
Given these two valid grid paths, Genos wants to know if it is possible to move both marbles to the ends of their respective paths. That is, if it is possible to move the marbles such that both marbles rest on the last square of their respective paths.
Input
The first line of the input contains a single integer n (2 ≤ n ≤ 1 000 000) — the length of the paths.
The second line of the input contains a string consisting of n - 1 characters (each of which is either 'N', 'E', 'S', or 'W') — the first grid path. The characters can be thought of as the sequence of moves needed to traverse the grid path. For example, the example path in the problem statement can be expressed by the string "NNESWW".
The third line of the input contains a string of n - 1 characters (each of which is either 'N', 'E', 'S', or 'W') — the second grid path.
Output
Print "YES" (without quotes) if it is possible for both marbles to be at the end position at the same time. Print "NO" (without quotes) otherwise. In both cases, the answer is case-insensitive.
Examples
Input
7
NNESWW
SWSWSW
Output
YES
Input
3
NN
SS
Output
NO
Note
In the first sample, the first grid path is the one described in the statement. Moreover, the following sequence of moves will get both marbles to the end: NNESWWSWSW.
In the second sample, no sequence of moves can get both marbles to the end.
Submitted Solution:
```
from time import time
opposite = {
'N': 'S',
'S': 'N',
'E': 'W',
'W': 'E'
}
otr = str.maketrans(opposite)
bits = {
'N': 0,
'S': 1,
'E': 2,
'W': 3,
}
Q = 4294967291
def combine(h, v, q):
return (h<<2 | v) % q
def combinel(h, v, q, s):
return (v*s + h) % q
def flip(s):
return ''.join(reversed(s.translate(otr)))
def solvable(p1, p2):
h1 = 0
h2 = 0
s = 0
for i in reversed(range(len(p1))):
n1 = bits[p1[i]]
n2 = bits[opposite[p2[i]]]
h1 = combine(h1, n1, Q)
h2 = combinel(h2, n2, Q, s)
if h1 == h2 and p1[i:] == flip(p2[i:]):
return False
s = (s<<2) % Q
return True
if __name__ == '__main__':
n = int(input())
p1 = input()
p2 = input()
print('YES' if solvable(p1, p2) else 'NO')
``` | instruction | 0 | 15,492 | 15 | 30,984 |
No | output | 1 | 15,492 | 15 | 30,985 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has the square chessboard of size n × n and m rooks. Initially the chessboard is empty. Vasya will consequently put the rooks on the board one after another.
The cell of the field is under rook's attack, if there is at least one rook located in the same row or in the same column with this cell. If there is a rook located in the cell, this cell is also under attack.
You are given the positions of the board where Vasya will put rooks. For each rook you have to determine the number of cells which are not under attack after Vasya puts it on the board.
Input
The first line of the input contains two integers n and m (1 ≤ n ≤ 100 000, 1 ≤ m ≤ min(100 000, n2)) — the size of the board and the number of rooks.
Each of the next m lines contains integers xi and yi (1 ≤ xi, yi ≤ n) — the number of the row and the number of the column where Vasya will put the i-th rook. Vasya puts rooks on the board in the order they appear in the input. It is guaranteed that any cell will contain no more than one rook.
Output
Print m integer, the i-th of them should be equal to the number of cells that are not under attack after first i rooks are put.
Examples
Input
3 3
1 1
3 1
2 2
Output
4 2 0
Input
5 2
1 5
5 1
Output
16 9
Input
100000 1
300 400
Output
9999800001
Note
On the picture below show the state of the board after put each of the three rooks. The cells which painted with grey color is not under the attack.
<image> | instruction | 0 | 15,541 | 15 | 31,082 |
Tags: data structures, math
Correct Solution:
```
n,m=map(int,input().split())
k=n**2
ki=[]
cx=set();cy=set()
a=[False]*n
b=[False]*n
x1=y1=-1
d=0
for i in range(m):
d=0
x,y=map(int,input().split())
x-=1;y-=1
if a[x]==True and b[y]==True:
ki.append(k)
continue
if a[x]==False:
a[x]=True
x1+=1
if b[y]==False:
b[y]=True
y1+=1
k-=(2*n-1-x1-y1)
else:
k-=(n-1-y1)
else:
b[y]=True
y1+=1
d+=1
k-=(n-1-x1)
ki.append(k)
print(*ki)
``` | output | 1 | 15,541 | 15 | 31,083 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has the square chessboard of size n × n and m rooks. Initially the chessboard is empty. Vasya will consequently put the rooks on the board one after another.
The cell of the field is under rook's attack, if there is at least one rook located in the same row or in the same column with this cell. If there is a rook located in the cell, this cell is also under attack.
You are given the positions of the board where Vasya will put rooks. For each rook you have to determine the number of cells which are not under attack after Vasya puts it on the board.
Input
The first line of the input contains two integers n and m (1 ≤ n ≤ 100 000, 1 ≤ m ≤ min(100 000, n2)) — the size of the board and the number of rooks.
Each of the next m lines contains integers xi and yi (1 ≤ xi, yi ≤ n) — the number of the row and the number of the column where Vasya will put the i-th rook. Vasya puts rooks on the board in the order they appear in the input. It is guaranteed that any cell will contain no more than one rook.
Output
Print m integer, the i-th of them should be equal to the number of cells that are not under attack after first i rooks are put.
Examples
Input
3 3
1 1
3 1
2 2
Output
4 2 0
Input
5 2
1 5
5 1
Output
16 9
Input
100000 1
300 400
Output
9999800001
Note
On the picture below show the state of the board after put each of the three rooks. The cells which painted with grey color is not under the attack.
<image> | instruction | 0 | 15,542 | 15 | 31,084 |
Tags: data structures, math
Correct Solution:
```
x = input()
n, m = list(map(int, x.strip().split()))
vseh_polj = n**2
vrstice = set()
stolpci = set()
vrni = []
for _ in range(m):
u = input()
x, y = list(map(int, u.strip().split()))
x, y = x - 1, y - 1
vrstice.add(x)
stolpci.add(y)
vrni.append(str(vseh_polj - n*len(vrstice) - len(stolpci)*(n - len(vrstice))))
print(' '.join(vrni))
``` | output | 1 | 15,542 | 15 | 31,085 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has the square chessboard of size n × n and m rooks. Initially the chessboard is empty. Vasya will consequently put the rooks on the board one after another.
The cell of the field is under rook's attack, if there is at least one rook located in the same row or in the same column with this cell. If there is a rook located in the cell, this cell is also under attack.
You are given the positions of the board where Vasya will put rooks. For each rook you have to determine the number of cells which are not under attack after Vasya puts it on the board.
Input
The first line of the input contains two integers n and m (1 ≤ n ≤ 100 000, 1 ≤ m ≤ min(100 000, n2)) — the size of the board and the number of rooks.
Each of the next m lines contains integers xi and yi (1 ≤ xi, yi ≤ n) — the number of the row and the number of the column where Vasya will put the i-th rook. Vasya puts rooks on the board in the order they appear in the input. It is guaranteed that any cell will contain no more than one rook.
Output
Print m integer, the i-th of them should be equal to the number of cells that are not under attack after first i rooks are put.
Examples
Input
3 3
1 1
3 1
2 2
Output
4 2 0
Input
5 2
1 5
5 1
Output
16 9
Input
100000 1
300 400
Output
9999800001
Note
On the picture below show the state of the board after put each of the three rooks. The cells which painted with grey color is not under the attack.
<image> | instruction | 0 | 15,543 | 15 | 31,086 |
Tags: data structures, math
Correct Solution:
```
import sys
def main():
size, n_rooks = [int(x) for x in sys.stdin.readline().split()]
rows_akd = set()
cols_akd = set()
for line in sys.stdin.readlines():
(x,y) = line.split()
rows_akd.add(x)
cols_akd.add(y)
# print(rows_akd, cols_akd)
safe = size ** 2
safe -= len(rows_akd) * size
safe -= len(cols_akd) * (size - len(rows_akd))
print(safe, end=' ')
print()
if __name__ == '__main__':
main()
``` | output | 1 | 15,543 | 15 | 31,087 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has the square chessboard of size n × n and m rooks. Initially the chessboard is empty. Vasya will consequently put the rooks on the board one after another.
The cell of the field is under rook's attack, if there is at least one rook located in the same row or in the same column with this cell. If there is a rook located in the cell, this cell is also under attack.
You are given the positions of the board where Vasya will put rooks. For each rook you have to determine the number of cells which are not under attack after Vasya puts it on the board.
Input
The first line of the input contains two integers n and m (1 ≤ n ≤ 100 000, 1 ≤ m ≤ min(100 000, n2)) — the size of the board and the number of rooks.
Each of the next m lines contains integers xi and yi (1 ≤ xi, yi ≤ n) — the number of the row and the number of the column where Vasya will put the i-th rook. Vasya puts rooks on the board in the order they appear in the input. It is guaranteed that any cell will contain no more than one rook.
Output
Print m integer, the i-th of them should be equal to the number of cells that are not under attack after first i rooks are put.
Examples
Input
3 3
1 1
3 1
2 2
Output
4 2 0
Input
5 2
1 5
5 1
Output
16 9
Input
100000 1
300 400
Output
9999800001
Note
On the picture below show the state of the board after put each of the three rooks. The cells which painted with grey color is not under the attack.
<image> | instruction | 0 | 15,544 | 15 | 31,088 |
Tags: data structures, math
Correct Solution:
```
I = lambda :map(int, input().split())
n,m=I()
R=[True]*100001
C=[True]*100001
c=n
r=n
for i in range(m):
x,y=I()
r-=R[x]
c-=C[y]
C[y]=False
R[x]=False
print(r*c, end=' ')
``` | output | 1 | 15,544 | 15 | 31,089 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has the square chessboard of size n × n and m rooks. Initially the chessboard is empty. Vasya will consequently put the rooks on the board one after another.
The cell of the field is under rook's attack, if there is at least one rook located in the same row or in the same column with this cell. If there is a rook located in the cell, this cell is also under attack.
You are given the positions of the board where Vasya will put rooks. For each rook you have to determine the number of cells which are not under attack after Vasya puts it on the board.
Input
The first line of the input contains two integers n and m (1 ≤ n ≤ 100 000, 1 ≤ m ≤ min(100 000, n2)) — the size of the board and the number of rooks.
Each of the next m lines contains integers xi and yi (1 ≤ xi, yi ≤ n) — the number of the row and the number of the column where Vasya will put the i-th rook. Vasya puts rooks on the board in the order they appear in the input. It is guaranteed that any cell will contain no more than one rook.
Output
Print m integer, the i-th of them should be equal to the number of cells that are not under attack after first i rooks are put.
Examples
Input
3 3
1 1
3 1
2 2
Output
4 2 0
Input
5 2
1 5
5 1
Output
16 9
Input
100000 1
300 400
Output
9999800001
Note
On the picture below show the state of the board after put each of the three rooks. The cells which painted with grey color is not under the attack.
<image> | instruction | 0 | 15,545 | 15 | 31,090 |
Tags: data structures, math
Correct Solution:
```
n, m = map(int, input().split())
rows = set(range(1, n+1))
columns = set(range(1, n+1))
for i in range(m):
x, y = map(int, input().split())
rows.discard(x)
columns.discard(y)
print(len(rows) * len(columns), end=' ')
print()
``` | output | 1 | 15,545 | 15 | 31,091 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has the square chessboard of size n × n and m rooks. Initially the chessboard is empty. Vasya will consequently put the rooks on the board one after another.
The cell of the field is under rook's attack, if there is at least one rook located in the same row or in the same column with this cell. If there is a rook located in the cell, this cell is also under attack.
You are given the positions of the board where Vasya will put rooks. For each rook you have to determine the number of cells which are not under attack after Vasya puts it on the board.
Input
The first line of the input contains two integers n and m (1 ≤ n ≤ 100 000, 1 ≤ m ≤ min(100 000, n2)) — the size of the board and the number of rooks.
Each of the next m lines contains integers xi and yi (1 ≤ xi, yi ≤ n) — the number of the row and the number of the column where Vasya will put the i-th rook. Vasya puts rooks on the board in the order they appear in the input. It is guaranteed that any cell will contain no more than one rook.
Output
Print m integer, the i-th of them should be equal to the number of cells that are not under attack after first i rooks are put.
Examples
Input
3 3
1 1
3 1
2 2
Output
4 2 0
Input
5 2
1 5
5 1
Output
16 9
Input
100000 1
300 400
Output
9999800001
Note
On the picture below show the state of the board after put each of the three rooks. The cells which painted with grey color is not under the attack.
<image> | instruction | 0 | 15,546 | 15 | 31,092 |
Tags: data structures, math
Correct Solution:
```
base1,base2=map(int,input().split(' '))
row=['F' for i in range(base1)]
col=['F' for i in range(base1)]
nx=ny=base1
for i in range(base2):
xx,yy= map(int,input().split(' '))
if row[xx-1]=='F':
nx-=1
if col[yy-1]=='F':
ny-=1
row[xx-1]='B'
col[yy-1]='B'
print (nx*ny)
``` | output | 1 | 15,546 | 15 | 31,093 |
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