input stringlengths 1 8.57k | output stringlengths 2 5.65k |
|---|---|
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
It is important to use strong passwords to make the Internet more secure. At the same time, it is very important not to reuse the same password. No matter how strong your password is, if the plaintext is leaked in one place, it will be very easy to break. Of course, if all applications hash passwords and use SALT properly, such damage will not occur even if leaked, but there are still applications that store passwords in clear text.
Well, the contest is about to begin. I have to register a team account ...
problem
A string representing the password is given. Check if the character string meets all of the following conditions, and if it meets all of the following conditions, output "VALID", and if there is an item that does not meet even one, output "INVALID".
* String length is 6 or more
* Contains one or more numbers
* Contains one or more uppercase letters
* Contains one or more lowercase letters
input
A string representing the password is given on one line.
output
Print "VALID" if the password string meets all the conditions in question, and "INVALID" if there are conditions that do not.
Constraint
* The password string must be between 1 and 20 characters.
* Password string contains only uppercase letters, lowercase letters, and numbers
Input / output example
Input 1
password
Output 1
INVALID
It is a password that is widely used all over the world.
Input 2
AizuCamp2013
Output 2
VALID
Great password.
Input 3
1234
Output 3
INVALID
Widely used as a PIN.
Input 4
NaBiO3
Output 4
VALID
It is barely 6 characters or more.
Example
Input
password
Output
INVALID
Submitted Solution:
```
num = list("0123456789")
large = list("ABCDEFGHIJKLMNOPQRSTUVWXYZ")
small = list("abcdefghijklmnopqrstuvwxyz")
S = input()
if len(S) < 6:
print("INVALID")
exit()
flag_n, flag_l, flag_s = False, False, False
for s in S:
if s in num:
flag_n = True
elif s in large:
flag_l = True
elif s in small:
flag_s = True
if flag_n and flag_l and flag_s:
print("VALID")
else:
print("INVALID")
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
It is important to use strong passwords to make the Internet more secure. At the same time, it is very important not to reuse the same password. No matter how strong your password is, if the plaintext is leaked in one place, it will be very easy to break. Of course, if all applications hash passwords and use SALT properly, such damage will not occur even if leaked, but there are still applications that store passwords in clear text.
Well, the contest is about to begin. I have to register a team account ...
problem
A string representing the password is given. Check if the character string meets all of the following conditions, and if it meets all of the following conditions, output "VALID", and if there is an item that does not meet even one, output "INVALID".
* String length is 6 or more
* Contains one or more numbers
* Contains one or more uppercase letters
* Contains one or more lowercase letters
input
A string representing the password is given on one line.
output
Print "VALID" if the password string meets all the conditions in question, and "INVALID" if there are conditions that do not.
Constraint
* The password string must be between 1 and 20 characters.
* Password string contains only uppercase letters, lowercase letters, and numbers
Input / output example
Input 1
password
Output 1
INVALID
It is a password that is widely used all over the world.
Input 2
AizuCamp2013
Output 2
VALID
Great password.
Input 3
1234
Output 3
INVALID
Widely used as a PIN.
Input 4
NaBiO3
Output 4
VALID
It is barely 6 characters or more.
Example
Input
password
Output
INVALID
Submitted Solution:
```
s=input()
print('INVALID' if s.isdigit() and s.islower() and s.isupper() or len(s)<6 else 'VALID')
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
It is important to use strong passwords to make the Internet more secure. At the same time, it is very important not to reuse the same password. No matter how strong your password is, if the plaintext is leaked in one place, it will be very easy to break. Of course, if all applications hash passwords and use SALT properly, such damage will not occur even if leaked, but there are still applications that store passwords in clear text.
Well, the contest is about to begin. I have to register a team account ...
problem
A string representing the password is given. Check if the character string meets all of the following conditions, and if it meets all of the following conditions, output "VALID", and if there is an item that does not meet even one, output "INVALID".
* String length is 6 or more
* Contains one or more numbers
* Contains one or more uppercase letters
* Contains one or more lowercase letters
input
A string representing the password is given on one line.
output
Print "VALID" if the password string meets all the conditions in question, and "INVALID" if there are conditions that do not.
Constraint
* The password string must be between 1 and 20 characters.
* Password string contains only uppercase letters, lowercase letters, and numbers
Input / output example
Input 1
password
Output 1
INVALID
It is a password that is widely used all over the world.
Input 2
AizuCamp2013
Output 2
VALID
Great password.
Input 3
1234
Output 3
INVALID
Widely used as a PIN.
Input 4
NaBiO3
Output 4
VALID
It is barely 6 characters or more.
Example
Input
password
Output
INVALID
Submitted Solution:
```
s=input()
print('INVALID' if s.isdigit() or s.islower() or s.isupper() or len(s)<6 else 'VALID')
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
It is important to use strong passwords to make the Internet more secure. At the same time, it is very important not to reuse the same password. No matter how strong your password is, if the plaintext is leaked in one place, it will be very easy to break. Of course, if all applications hash passwords and use SALT properly, such damage will not occur even if leaked, but there are still applications that store passwords in clear text.
Well, the contest is about to begin. I have to register a team account ...
problem
A string representing the password is given. Check if the character string meets all of the following conditions, and if it meets all of the following conditions, output "VALID", and if there is an item that does not meet even one, output "INVALID".
* String length is 6 or more
* Contains one or more numbers
* Contains one or more uppercase letters
* Contains one or more lowercase letters
input
A string representing the password is given on one line.
output
Print "VALID" if the password string meets all the conditions in question, and "INVALID" if there are conditions that do not.
Constraint
* The password string must be between 1 and 20 characters.
* Password string contains only uppercase letters, lowercase letters, and numbers
Input / output example
Input 1
password
Output 1
INVALID
It is a password that is widely used all over the world.
Input 2
AizuCamp2013
Output 2
VALID
Great password.
Input 3
1234
Output 3
INVALID
Widely used as a PIN.
Input 4
NaBiO3
Output 4
VALID
It is barely 6 characters or more.
Example
Input
password
Output
INVALID
Submitted Solution:
```
s=input()
print('VALID' if s.isdigit() and s.islower() and s.isupper() and len(s)>5 else 'INVALID')
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Jabber ID on the national Berland service «Babber» has a form <username>@<hostname>[/resource], where
* <username> — is a sequence of Latin letters (lowercase or uppercase), digits or underscores characters «_», the length of <username> is between 1 and 16, inclusive.
* <hostname> — is a sequence of word separated by periods (characters «.»), where each word should contain only characters allowed for <username>, the length of each word is between 1 and 16, inclusive. The length of <hostname> is between 1 and 32, inclusive.
* <resource> — is a sequence of Latin letters (lowercase or uppercase), digits or underscores characters «_», the length of <resource> is between 1 and 16, inclusive.
The content of square brackets is optional — it can be present or can be absent.
There are the samples of correct Jabber IDs: mike@codeforces.com, 007@en.codeforces.com/contest.
Your task is to write program which checks if given string is a correct Jabber ID.
Input
The input contains of a single line. The line has the length between 1 and 100 characters, inclusive. Each characters has ASCII-code between 33 and 127, inclusive.
Output
Print YES or NO.
Examples
Input
mike@codeforces.com
Output
YES
Input
john.smith@codeforces.ru/contest.icpc/12
Output
NO
Submitted Solution:
```
def bhaago():
print('NO')
exit(0)
def type1(s):
if not (len(s) >= 1 and len(s) <=16):
bhaago()
for i in s:
if not (i.isalpha() or i.isdigit() or i == '_'):
bhaago()
s = input()
if not(s[0].isalpha() or s[0].isdigit() or s[0] == '_'):
bhaago()
t1 = s.split('@')
if len(t1) != 2:
bhaago()
username = t1[0]
type1(username)
t2 = t1[1].split('/')
if len(t2) > 2:
bhaago()
hostname = t2[0]
if not (len(hostname) >= 1 and len(hostname) <=32):
bhaago()
for sep in hostname.split('.'):
type1(sep)
if len(t2) == 1:
print('YES')
exit(0)
resource = t2[1]
type1(resource)
print('YES')
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Jabber ID on the national Berland service «Babber» has a form <username>@<hostname>[/resource], where
* <username> — is a sequence of Latin letters (lowercase or uppercase), digits or underscores characters «_», the length of <username> is between 1 and 16, inclusive.
* <hostname> — is a sequence of word separated by periods (characters «.»), where each word should contain only characters allowed for <username>, the length of each word is between 1 and 16, inclusive. The length of <hostname> is between 1 and 32, inclusive.
* <resource> — is a sequence of Latin letters (lowercase or uppercase), digits or underscores characters «_», the length of <resource> is between 1 and 16, inclusive.
The content of square brackets is optional — it can be present or can be absent.
There are the samples of correct Jabber IDs: mike@codeforces.com, 007@en.codeforces.com/contest.
Your task is to write program which checks if given string is a correct Jabber ID.
Input
The input contains of a single line. The line has the length between 1 and 100 characters, inclusive. Each characters has ASCII-code between 33 and 127, inclusive.
Output
Print YES or NO.
Examples
Input
mike@codeforces.com
Output
YES
Input
john.smith@codeforces.ru/contest.icpc/12
Output
NO
Submitted Solution:
```
def res():
s=list(input().split("@"))
if(len(s)>2):
print("NO")
return
if(len(s[0])>16 or len(s[0])<1):
print("NO")
return
for i in s[0]:
#print(i)
if(97<=ord(i)<=122 or 65<=ord(i)<=91 or ord(i)==95 or 48<=ord(i)<=57):
continue
else:
print("NO")
return
#print("hi")
a=list(s[1].split("/"))
if(len(a[0])>32 or len(a[0])<1):
print("NO")
return
k=a[0].split(".")
for i in range(len(k)):
if(len(k[i])>16 or len(k[i])<1):
print("NO")
return
for i in a[0]:
if(97<=ord(i)<=122 or 65<=ord(i)<=91 or ord(i)==46 or ord(i)==95 or 48<=ord(i)<=57):
continue
else:
print("NO")
return
for i in range(1,len(a)):
m=a[i]
if(len(m)>16 or len(m)<1):
print("NO")
return
for i in m:
if(97<=ord(i)<=122 or 65<=ord(i)<=91 or ord(i)==95 or 48<=ord(i)<=57):
continue
else:
print("NO")
return
print("YES")
res()
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Jabber ID on the national Berland service «Babber» has a form <username>@<hostname>[/resource], where
* <username> — is a sequence of Latin letters (lowercase or uppercase), digits or underscores characters «_», the length of <username> is between 1 and 16, inclusive.
* <hostname> — is a sequence of word separated by periods (characters «.»), where each word should contain only characters allowed for <username>, the length of each word is between 1 and 16, inclusive. The length of <hostname> is between 1 and 32, inclusive.
* <resource> — is a sequence of Latin letters (lowercase or uppercase), digits or underscores characters «_», the length of <resource> is between 1 and 16, inclusive.
The content of square brackets is optional — it can be present or can be absent.
There are the samples of correct Jabber IDs: mike@codeforces.com, 007@en.codeforces.com/contest.
Your task is to write program which checks if given string is a correct Jabber ID.
Input
The input contains of a single line. The line has the length between 1 and 100 characters, inclusive. Each characters has ASCII-code between 33 and 127, inclusive.
Output
Print YES or NO.
Examples
Input
mike@codeforces.com
Output
YES
Input
john.smith@codeforces.ru/contest.icpc/12
Output
NO
Submitted Solution:
```
import string
def main(a):
allowed = string.ascii_letters + string.digits + '_'
limit = 0
limit_2 = 0
flag = 0
for character in a:
if flag == 0:
if character == '@':
if limit == 0:
return 'NO'
flag = 1
limit = 0
else:
if character not in allowed:
return 'NO'
limit += 1
if limit == 17:
return 'NO'
else:
if flag == 1:
if character == '/':
if limit == 0:
return 'NO'
if limit_2 == 0:
return 'NO'
flag = 2
limit = 0
limit_2 = 0
else:
if character == '.':
if limit == 0:
return 'NO'
limit = 0
limit_2 += 1
if limit_2 == 33:
return 'NO'
else:
if character not in allowed:
return 'NO'
limit += 1
if limit == 17:
return 'NO'
limit_2 += 1
if limit_2 == 33:
return 'NO'
else:
if character not in allowed:
return 'NO'
limit += 1
if limit == 17:
return 'NO'
if flag == 0:
return 'NO'
if a[len(a) - 1] == '.':
return 'NO'
if a[len(a) - 1] == '/':
return 'NO'
if a[len(a) - 1] == '@':
return 'NO'
return 'YES'
a = input()
print(main(a))
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Jabber ID on the national Berland service «Babber» has a form <username>@<hostname>[/resource], where
* <username> — is a sequence of Latin letters (lowercase or uppercase), digits or underscores characters «_», the length of <username> is between 1 and 16, inclusive.
* <hostname> — is a sequence of word separated by periods (characters «.»), where each word should contain only characters allowed for <username>, the length of each word is between 1 and 16, inclusive. The length of <hostname> is between 1 and 32, inclusive.
* <resource> — is a sequence of Latin letters (lowercase or uppercase), digits or underscores characters «_», the length of <resource> is between 1 and 16, inclusive.
The content of square brackets is optional — it can be present or can be absent.
There are the samples of correct Jabber IDs: mike@codeforces.com, 007@en.codeforces.com/contest.
Your task is to write program which checks if given string is a correct Jabber ID.
Input
The input contains of a single line. The line has the length between 1 and 100 characters, inclusive. Each characters has ASCII-code between 33 and 127, inclusive.
Output
Print YES or NO.
Examples
Input
mike@codeforces.com
Output
YES
Input
john.smith@codeforces.ru/contest.icpc/12
Output
NO
Submitted Solution:
```
line = input()
valid = True
status = -1
username = []
hostname = []
resources = []
hasResource = False
ant = 'a'
for e in line:
if not valid:
break
if status == -1:
if e.isalpha() or e.isdigit() or e == '_':
username.append(e)
elif e == '@':
status = 0
else:
valid = False
elif status == 0:
if e.isalpha() or e.isdigit() or e == '_' or e == '.':
if e =='.' and ant == '.':
valid = False
else:
hostname.append(e)
elif e == '/':
hasResource = True
status = 1
else:
valid = False
else:
if e.isalpha() or e.isdigit() or e == '_':
resources.append(e)
else:
valid = False
ant = e
#print(username)
#print(hostname)
#print(resources)
if len(username) < 1 or len(username) > 16:
valid = False
if len(hostname) < 1 or len(hostname) > 32 or hostname[0] == '.' or hostname[-1] == '.':
valid = False
else:
word = (''.join(hostname)).split('.')
for e in word:
if len(e) > 16:
valid = False
if len(resources) > 16:
valid = False
if hasResource and len(resources) < 1:
valid = False
if valid:
print('YES')
else:
print('NO')
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Jabber ID on the national Berland service «Babber» has a form <username>@<hostname>[/resource], where
* <username> — is a sequence of Latin letters (lowercase or uppercase), digits or underscores characters «_», the length of <username> is between 1 and 16, inclusive.
* <hostname> — is a sequence of word separated by periods (characters «.»), where each word should contain only characters allowed for <username>, the length of each word is between 1 and 16, inclusive. The length of <hostname> is between 1 and 32, inclusive.
* <resource> — is a sequence of Latin letters (lowercase or uppercase), digits or underscores characters «_», the length of <resource> is between 1 and 16, inclusive.
The content of square brackets is optional — it can be present or can be absent.
There are the samples of correct Jabber IDs: mike@codeforces.com, 007@en.codeforces.com/contest.
Your task is to write program which checks if given string is a correct Jabber ID.
Input
The input contains of a single line. The line has the length between 1 and 100 characters, inclusive. Each characters has ASCII-code between 33 and 127, inclusive.
Output
Print YES or NO.
Examples
Input
mike@codeforces.com
Output
YES
Input
john.smith@codeforces.ru/contest.icpc/12
Output
NO
Submitted Solution:
```
A = {'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z','a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z','_','1','2','3','4','5','6','7','8','9','0'}
s = input()
k=0
i = s.find('@')
s1 = s[:i]
j = s.find('/')
if j!=-1:
s2 = s[i+1:j]
else:
s2=s[i+1:]
z=0
s3=''
if j!=-1:
s3 = s[j+1:-1]
cnt=0
if len(s1)<=16 and len(s1)>=1:
for i in range(len(s1)):
if s1[i] not in A:
k+=1
else:
k+=1
p = 0
if len(s2)<=32 and len(s2)>=1:
for i in range(len(s2)):
if s2[i] not in A and s2[i]!='.':
k+=1
else:
if s2[i]!='.':
p+=1
if p>16:
k+=1
else:
p=0
if p==0:
k+=1
else:
k+=1
if len(s3)<=16:
for i in range(len(s3)):
if s3[i] not in A:
k+=1
else:
k+=1
if k==0:
print('YES')
else:
print('NO')
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Jabber ID on the national Berland service «Babber» has a form <username>@<hostname>[/resource], where
* <username> — is a sequence of Latin letters (lowercase or uppercase), digits or underscores characters «_», the length of <username> is between 1 and 16, inclusive.
* <hostname> — is a sequence of word separated by periods (characters «.»), where each word should contain only characters allowed for <username>, the length of each word is between 1 and 16, inclusive. The length of <hostname> is between 1 and 32, inclusive.
* <resource> — is a sequence of Latin letters (lowercase or uppercase), digits or underscores characters «_», the length of <resource> is between 1 and 16, inclusive.
The content of square brackets is optional — it can be present or can be absent.
There are the samples of correct Jabber IDs: mike@codeforces.com, 007@en.codeforces.com/contest.
Your task is to write program which checks if given string is a correct Jabber ID.
Input
The input contains of a single line. The line has the length between 1 and 100 characters, inclusive. Each characters has ASCII-code between 33 and 127, inclusive.
Output
Print YES or NO.
Examples
Input
mike@codeforces.com
Output
YES
Input
john.smith@codeforces.ru/contest.icpc/12
Output
NO
Submitted Solution:
```
def f():
x = input()
if len(x) < 1 or len(x) > 100:
return 'No'
for i in x:
if ord(i) < 33 or ord(i) > 127:
return 'No'
if len(x[:x.find('@')]) < 1 or len(x[:x.find('@')]) > 16:
return 'No'
for i in x[x.find('@')+1:x.find('/')].split('.'):
if len(i) < 1 or len(i) > 16:
return 'No'
if '/' in x:
for i in x[x.find('/')+1:].split('/'):
if len(i) < 1 or len(i) > 16:
return 'No'
if len(x[x.find('@')+1:]) < 1 or len(x[x.find('@')+1:]) > 16:
return 'No'
return 'Yes'
print(f())
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Jabber ID on the national Berland service «Babber» has a form <username>@<hostname>[/resource], where
* <username> — is a sequence of Latin letters (lowercase or uppercase), digits or underscores characters «_», the length of <username> is between 1 and 16, inclusive.
* <hostname> — is a sequence of word separated by periods (characters «.»), where each word should contain only characters allowed for <username>, the length of each word is between 1 and 16, inclusive. The length of <hostname> is between 1 and 32, inclusive.
* <resource> — is a sequence of Latin letters (lowercase or uppercase), digits or underscores characters «_», the length of <resource> is between 1 and 16, inclusive.
The content of square brackets is optional — it can be present or can be absent.
There are the samples of correct Jabber IDs: mike@codeforces.com, 007@en.codeforces.com/contest.
Your task is to write program which checks if given string is a correct Jabber ID.
Input
The input contains of a single line. The line has the length between 1 and 100 characters, inclusive. Each characters has ASCII-code between 33 and 127, inclusive.
Output
Print YES or NO.
Examples
Input
mike@codeforces.com
Output
YES
Input
john.smith@codeforces.ru/contest.icpc/12
Output
NO
Submitted Solution:
```
word=input()
asdf=[95]
for i in range(48,58):
asdf.append(i)
for i in range(65,91):
asdf.append(i)
for i in range(97,123):
asdf.append(i)
def f(word):
if len(x) < 1 or len(x) > 100:
return 'NO'
for i in x:
if ord(i) < 33 or ord(i) > 127:
return 'NO'
if len(x[:x.find('@')]) < 1 or len(x[:x.find('@')]) > 16:
return 'NO'
for i in x[:x.find('@')]:
if i not in asdf:
return 'NO'
for i in x[x.find('@')+1:x.find('/')].split('.'):
if len(i) < 1 or len(i) > 16:
return 'NO'
if '/' in x:
for i in x[x.find('/')+1:].split('/'):
if len(i) < 1 or len(i) > 16:
return 'NO'
if len(x[x.find('@')+1:]) < 1 or len(x[x.find('@')+1:x.find('/')]) > 32:
return 'NO'
return 'YES'
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Jabber ID on the national Berland service «Babber» has a form <username>@<hostname>[/resource], where
* <username> — is a sequence of Latin letters (lowercase or uppercase), digits or underscores characters «_», the length of <username> is between 1 and 16, inclusive.
* <hostname> — is a sequence of word separated by periods (characters «.»), where each word should contain only characters allowed for <username>, the length of each word is between 1 and 16, inclusive. The length of <hostname> is between 1 and 32, inclusive.
* <resource> — is a sequence of Latin letters (lowercase or uppercase), digits or underscores characters «_», the length of <resource> is between 1 and 16, inclusive.
The content of square brackets is optional — it can be present or can be absent.
There are the samples of correct Jabber IDs: mike@codeforces.com, 007@en.codeforces.com/contest.
Your task is to write program which checks if given string is a correct Jabber ID.
Input
The input contains of a single line. The line has the length between 1 and 100 characters, inclusive. Each characters has ASCII-code between 33 and 127, inclusive.
Output
Print YES or NO.
Examples
Input
mike@codeforces.com
Output
YES
Input
john.smith@codeforces.ru/contest.icpc/12
Output
NO
Submitted Solution:
```
import re
if re.compile('(\w){1,16}@(\w{1,16}\.)*\w{1,16}(/\w)*').match(input()) != None:
print("YES")
else:
print("NO")
```
### Response:
| No |
### Instruction:
Provide a correct Python 3 solution for this coding contest problem.
You drew lottery N times. In the i-th draw, you got an item of the kind represented by a string S_i.
How many kinds of items did you get?
Constraints
* 1 \leq N \leq 2\times 10^5
* S_i consists of lowercase English letters and has a length between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
N
S_1
:
S_N
Output
Print the number of kinds of items you got.
Examples
Input
3
apple
orange
apple
Output
2
Input
5
grape
grape
grape
grape
grape
Output
1
Input
4
aaaa
a
aaa
aa
Output
4
### Response:
| "Correct Solution:
```
N = int(input())
X = set([input() for _ in range(N)])
print(len(X))
``` |
### Instruction:
Provide a correct Python 3 solution for this coding contest problem.
You drew lottery N times. In the i-th draw, you got an item of the kind represented by a string S_i.
How many kinds of items did you get?
Constraints
* 1 \leq N \leq 2\times 10^5
* S_i consists of lowercase English letters and has a length between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
N
S_1
:
S_N
Output
Print the number of kinds of items you got.
Examples
Input
3
apple
orange
apple
Output
2
Input
5
grape
grape
grape
grape
grape
Output
1
Input
4
aaaa
a
aaa
aa
Output
4
### Response:
| "Correct Solution:
```
N=int(input())
S=[input() for i in range(N)]
T=set(S)
print(len(T))
``` |
### Instruction:
Provide a correct Python 3 solution for this coding contest problem.
You drew lottery N times. In the i-th draw, you got an item of the kind represented by a string S_i.
How many kinds of items did you get?
Constraints
* 1 \leq N \leq 2\times 10^5
* S_i consists of lowercase English letters and has a length between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
N
S_1
:
S_N
Output
Print the number of kinds of items you got.
Examples
Input
3
apple
orange
apple
Output
2
Input
5
grape
grape
grape
grape
grape
Output
1
Input
4
aaaa
a
aaa
aa
Output
4
### Response:
| "Correct Solution:
```
n = int(input())
S = set(input() for i in range(n))
print(len(S))
``` |
### Instruction:
Provide a correct Python 3 solution for this coding contest problem.
You drew lottery N times. In the i-th draw, you got an item of the kind represented by a string S_i.
How many kinds of items did you get?
Constraints
* 1 \leq N \leq 2\times 10^5
* S_i consists of lowercase English letters and has a length between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
N
S_1
:
S_N
Output
Print the number of kinds of items you got.
Examples
Input
3
apple
orange
apple
Output
2
Input
5
grape
grape
grape
grape
grape
Output
1
Input
4
aaaa
a
aaa
aa
Output
4
### Response:
| "Correct Solution:
```
N = int(input())
print(len({ input() for i in range(N) }))
``` |
### Instruction:
Provide a correct Python 3 solution for this coding contest problem.
You drew lottery N times. In the i-th draw, you got an item of the kind represented by a string S_i.
How many kinds of items did you get?
Constraints
* 1 \leq N \leq 2\times 10^5
* S_i consists of lowercase English letters and has a length between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
N
S_1
:
S_N
Output
Print the number of kinds of items you got.
Examples
Input
3
apple
orange
apple
Output
2
Input
5
grape
grape
grape
grape
grape
Output
1
Input
4
aaaa
a
aaa
aa
Output
4
### Response:
| "Correct Solution:
```
n=int(input())
l=[input() for i in range(n)]
s=set(l)
print(len(s))
``` |
### Instruction:
Provide a correct Python 3 solution for this coding contest problem.
You drew lottery N times. In the i-th draw, you got an item of the kind represented by a string S_i.
How many kinds of items did you get?
Constraints
* 1 \leq N \leq 2\times 10^5
* S_i consists of lowercase English letters and has a length between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
N
S_1
:
S_N
Output
Print the number of kinds of items you got.
Examples
Input
3
apple
orange
apple
Output
2
Input
5
grape
grape
grape
grape
grape
Output
1
Input
4
aaaa
a
aaa
aa
Output
4
### Response:
| "Correct Solution:
```
n = int(input())
a = set([input() for _ in range(n)])
print(len(a))
``` |
### Instruction:
Provide a correct Python 3 solution for this coding contest problem.
You drew lottery N times. In the i-th draw, you got an item of the kind represented by a string S_i.
How many kinds of items did you get?
Constraints
* 1 \leq N \leq 2\times 10^5
* S_i consists of lowercase English letters and has a length between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
N
S_1
:
S_N
Output
Print the number of kinds of items you got.
Examples
Input
3
apple
orange
apple
Output
2
Input
5
grape
grape
grape
grape
grape
Output
1
Input
4
aaaa
a
aaa
aa
Output
4
### Response:
| "Correct Solution:
```
print(len({input().strip() for _ in range(int(input().strip()))}))
``` |
### Instruction:
Provide a correct Python 3 solution for this coding contest problem.
You drew lottery N times. In the i-th draw, you got an item of the kind represented by a string S_i.
How many kinds of items did you get?
Constraints
* 1 \leq N \leq 2\times 10^5
* S_i consists of lowercase English letters and has a length between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
N
S_1
:
S_N
Output
Print the number of kinds of items you got.
Examples
Input
3
apple
orange
apple
Output
2
Input
5
grape
grape
grape
grape
grape
Output
1
Input
4
aaaa
a
aaa
aa
Output
4
### Response:
| "Correct Solution:
```
N=int(input())
d={}
for _ in range(N):
d[input()]=1
print(len(d))
``` |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You drew lottery N times. In the i-th draw, you got an item of the kind represented by a string S_i.
How many kinds of items did you get?
Constraints
* 1 \leq N \leq 2\times 10^5
* S_i consists of lowercase English letters and has a length between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
N
S_1
:
S_N
Output
Print the number of kinds of items you got.
Examples
Input
3
apple
orange
apple
Output
2
Input
5
grape
grape
grape
grape
grape
Output
1
Input
4
aaaa
a
aaa
aa
Output
4
Submitted Solution:
```
N=int(input())
S=[input() for s in range(N)]
print(len(set(S)))
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You drew lottery N times. In the i-th draw, you got an item of the kind represented by a string S_i.
How many kinds of items did you get?
Constraints
* 1 \leq N \leq 2\times 10^5
* S_i consists of lowercase English letters and has a length between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
N
S_1
:
S_N
Output
Print the number of kinds of items you got.
Examples
Input
3
apple
orange
apple
Output
2
Input
5
grape
grape
grape
grape
grape
Output
1
Input
4
aaaa
a
aaa
aa
Output
4
Submitted Solution:
```
N=int(input())
kuji=[input() for i in range(N)]
print(len(set(kuji)))
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You drew lottery N times. In the i-th draw, you got an item of the kind represented by a string S_i.
How many kinds of items did you get?
Constraints
* 1 \leq N \leq 2\times 10^5
* S_i consists of lowercase English letters and has a length between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
N
S_1
:
S_N
Output
Print the number of kinds of items you got.
Examples
Input
3
apple
orange
apple
Output
2
Input
5
grape
grape
grape
grape
grape
Output
1
Input
4
aaaa
a
aaa
aa
Output
4
Submitted Solution:
```
n=int(input())
s=[str(input()) for _ in range(n)]
print(len(set(s)))
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You drew lottery N times. In the i-th draw, you got an item of the kind represented by a string S_i.
How many kinds of items did you get?
Constraints
* 1 \leq N \leq 2\times 10^5
* S_i consists of lowercase English letters and has a length between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
N
S_1
:
S_N
Output
Print the number of kinds of items you got.
Examples
Input
3
apple
orange
apple
Output
2
Input
5
grape
grape
grape
grape
grape
Output
1
Input
4
aaaa
a
aaa
aa
Output
4
Submitted Solution:
```
n=int(input())
print(len(set([input() for _ in range(n)])))
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You drew lottery N times. In the i-th draw, you got an item of the kind represented by a string S_i.
How many kinds of items did you get?
Constraints
* 1 \leq N \leq 2\times 10^5
* S_i consists of lowercase English letters and has a length between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
N
S_1
:
S_N
Output
Print the number of kinds of items you got.
Examples
Input
3
apple
orange
apple
Output
2
Input
5
grape
grape
grape
grape
grape
Output
1
Input
4
aaaa
a
aaa
aa
Output
4
Submitted Solution:
```
n=int(input())
a=[]
a.append(str(input()))
for i in range(n-1):
flag = 1
tmp = str(input())
for j in range(len(a)):
if a[j] == tmp:
flag = 0
if flag == 1:
a.append(tmp)
print(len(a))
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You drew lottery N times. In the i-th draw, you got an item of the kind represented by a string S_i.
How many kinds of items did you get?
Constraints
* 1 \leq N \leq 2\times 10^5
* S_i consists of lowercase English letters and has a length between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
N
S_1
:
S_N
Output
Print the number of kinds of items you got.
Examples
Input
3
apple
orange
apple
Output
2
Input
5
grape
grape
grape
grape
grape
Output
1
Input
4
aaaa
a
aaa
aa
Output
4
Submitted Solution:
```
import sys
input = sys.stdin.readline
N = int(input())
S = [input() for _ in range(N)]
count = 0
while len(S) >0:
S.remove(S[0])
count += 1
print(count)
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You drew lottery N times. In the i-th draw, you got an item of the kind represented by a string S_i.
How many kinds of items did you get?
Constraints
* 1 \leq N \leq 2\times 10^5
* S_i consists of lowercase English letters and has a length between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
N
S_1
:
S_N
Output
Print the number of kinds of items you got.
Examples
Input
3
apple
orange
apple
Output
2
Input
5
grape
grape
grape
grape
grape
Output
1
Input
4
aaaa
a
aaa
aa
Output
4
Submitted Solution:
```
import sys
n = int(input().strip())
items = set()
for _ in range(n):
items |= {sys.readline().strip()}
print(len(items))
```
### Response:
| No |
### Instruction:
Provide a correct Python 3 solution for this coding contest problem.
Given are strings s and t of length N each, both consisting of lowercase English letters.
Let us form a new string by alternating the characters of S and the characters of T, as follows: the first character of S, the first character of T, the second character of S, the second character of T, ..., the N-th character of S, the N-th character of T. Print this new string.
Constraints
* 1 \leq N \leq 100
* |S| = |T| = N
* S and T are strings consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S T
Output
Print the string formed.
Examples
Input
2
ip cc
Output
icpc
Input
8
hmhmnknk uuuuuuuu
Output
humuhumunukunuku
Input
5
aaaaa aaaaa
Output
aaaaaaaaaa
### Response:
| "Correct Solution:
```
n=int(input())
s,t=(input().split())
a=""
for s,t in zip(s,t):
a+=s+t
print(a)
``` |
### Instruction:
Provide a correct Python 3 solution for this coding contest problem.
Given are strings s and t of length N each, both consisting of lowercase English letters.
Let us form a new string by alternating the characters of S and the characters of T, as follows: the first character of S, the first character of T, the second character of S, the second character of T, ..., the N-th character of S, the N-th character of T. Print this new string.
Constraints
* 1 \leq N \leq 100
* |S| = |T| = N
* S and T are strings consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S T
Output
Print the string formed.
Examples
Input
2
ip cc
Output
icpc
Input
8
hmhmnknk uuuuuuuu
Output
humuhumunukunuku
Input
5
aaaaa aaaaa
Output
aaaaaaaaaa
### Response:
| "Correct Solution:
```
n=int(input())
s,t=input().split()
print("".join(i+j for i,j in zip(s,t)))
``` |
### Instruction:
Provide a correct Python 3 solution for this coding contest problem.
Given are strings s and t of length N each, both consisting of lowercase English letters.
Let us form a new string by alternating the characters of S and the characters of T, as follows: the first character of S, the first character of T, the second character of S, the second character of T, ..., the N-th character of S, the N-th character of T. Print this new string.
Constraints
* 1 \leq N \leq 100
* |S| = |T| = N
* S and T are strings consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S T
Output
Print the string formed.
Examples
Input
2
ip cc
Output
icpc
Input
8
hmhmnknk uuuuuuuu
Output
humuhumunukunuku
Input
5
aaaaa aaaaa
Output
aaaaaaaaaa
### Response:
| "Correct Solution:
```
_, S, T = open(0).read().split()
print(''.join([s + t for s, t in zip(S, T)]))
``` |
### Instruction:
Provide a correct Python 3 solution for this coding contest problem.
Given are strings s and t of length N each, both consisting of lowercase English letters.
Let us form a new string by alternating the characters of S and the characters of T, as follows: the first character of S, the first character of T, the second character of S, the second character of T, ..., the N-th character of S, the N-th character of T. Print this new string.
Constraints
* 1 \leq N \leq 100
* |S| = |T| = N
* S and T are strings consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S T
Output
Print the string formed.
Examples
Input
2
ip cc
Output
icpc
Input
8
hmhmnknk uuuuuuuu
Output
humuhumunukunuku
Input
5
aaaaa aaaaa
Output
aaaaaaaaaa
### Response:
| "Correct Solution:
```
N=int(input())
S,T=input().split()
for i in range(N):
print(S[i],T[i],sep="",end="")
``` |
### Instruction:
Provide a correct Python 3 solution for this coding contest problem.
Given are strings s and t of length N each, both consisting of lowercase English letters.
Let us form a new string by alternating the characters of S and the characters of T, as follows: the first character of S, the first character of T, the second character of S, the second character of T, ..., the N-th character of S, the N-th character of T. Print this new string.
Constraints
* 1 \leq N \leq 100
* |S| = |T| = N
* S and T are strings consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S T
Output
Print the string formed.
Examples
Input
2
ip cc
Output
icpc
Input
8
hmhmnknk uuuuuuuu
Output
humuhumunukunuku
Input
5
aaaaa aaaaa
Output
aaaaaaaaaa
### Response:
| "Correct Solution:
```
n=int(input())
s,t=input().split()
print(*[s[i]+t[i] for i in range(n)],sep='')
``` |
### Instruction:
Provide a correct Python 3 solution for this coding contest problem.
Given are strings s and t of length N each, both consisting of lowercase English letters.
Let us form a new string by alternating the characters of S and the characters of T, as follows: the first character of S, the first character of T, the second character of S, the second character of T, ..., the N-th character of S, the N-th character of T. Print this new string.
Constraints
* 1 \leq N \leq 100
* |S| = |T| = N
* S and T are strings consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S T
Output
Print the string formed.
Examples
Input
2
ip cc
Output
icpc
Input
8
hmhmnknk uuuuuuuu
Output
humuhumunukunuku
Input
5
aaaaa aaaaa
Output
aaaaaaaaaa
### Response:
| "Correct Solution:
```
input()
s, t = input().split()
print(''.join(a+b for a,b in zip(s,t)))
``` |
### Instruction:
Provide a correct Python 3 solution for this coding contest problem.
Given are strings s and t of length N each, both consisting of lowercase English letters.
Let us form a new string by alternating the characters of S and the characters of T, as follows: the first character of S, the first character of T, the second character of S, the second character of T, ..., the N-th character of S, the N-th character of T. Print this new string.
Constraints
* 1 \leq N \leq 100
* |S| = |T| = N
* S and T are strings consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S T
Output
Print the string formed.
Examples
Input
2
ip cc
Output
icpc
Input
8
hmhmnknk uuuuuuuu
Output
humuhumunukunuku
Input
5
aaaaa aaaaa
Output
aaaaaaaaaa
### Response:
| "Correct Solution:
```
input()
s,t=input().split()
print("".join([a+b for a,b in zip(s,t)]))
``` |
### Instruction:
Provide a correct Python 3 solution for this coding contest problem.
Given are strings s and t of length N each, both consisting of lowercase English letters.
Let us form a new string by alternating the characters of S and the characters of T, as follows: the first character of S, the first character of T, the second character of S, the second character of T, ..., the N-th character of S, the N-th character of T. Print this new string.
Constraints
* 1 \leq N \leq 100
* |S| = |T| = N
* S and T are strings consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S T
Output
Print the string formed.
Examples
Input
2
ip cc
Output
icpc
Input
8
hmhmnknk uuuuuuuu
Output
humuhumunukunuku
Input
5
aaaaa aaaaa
Output
aaaaaaaaaa
### Response:
| "Correct Solution:
```
n=int(input())
a,b=input().split()
for i in range(n):
print(end=a[i])
print(end=b[i])
``` |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are strings s and t of length N each, both consisting of lowercase English letters.
Let us form a new string by alternating the characters of S and the characters of T, as follows: the first character of S, the first character of T, the second character of S, the second character of T, ..., the N-th character of S, the N-th character of T. Print this new string.
Constraints
* 1 \leq N \leq 100
* |S| = |T| = N
* S and T are strings consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S T
Output
Print the string formed.
Examples
Input
2
ip cc
Output
icpc
Input
8
hmhmnknk uuuuuuuu
Output
humuhumunukunuku
Input
5
aaaaa aaaaa
Output
aaaaaaaaaa
Submitted Solution:
```
N = int(input())
S, T = input().split()
print(
"".join(S[i]+T[i] for i in range(N))
)
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are strings s and t of length N each, both consisting of lowercase English letters.
Let us form a new string by alternating the characters of S and the characters of T, as follows: the first character of S, the first character of T, the second character of S, the second character of T, ..., the N-th character of S, the N-th character of T. Print this new string.
Constraints
* 1 \leq N \leq 100
* |S| = |T| = N
* S and T are strings consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S T
Output
Print the string formed.
Examples
Input
2
ip cc
Output
icpc
Input
8
hmhmnknk uuuuuuuu
Output
humuhumunukunuku
Input
5
aaaaa aaaaa
Output
aaaaaaaaaa
Submitted Solution:
```
input()
print(''.join(sum(list(map(list, zip(*input().split()))), [])))
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are strings s and t of length N each, both consisting of lowercase English letters.
Let us form a new string by alternating the characters of S and the characters of T, as follows: the first character of S, the first character of T, the second character of S, the second character of T, ..., the N-th character of S, the N-th character of T. Print this new string.
Constraints
* 1 \leq N \leq 100
* |S| = |T| = N
* S and T are strings consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S T
Output
Print the string formed.
Examples
Input
2
ip cc
Output
icpc
Input
8
hmhmnknk uuuuuuuu
Output
humuhumunukunuku
Input
5
aaaaa aaaaa
Output
aaaaaaaaaa
Submitted Solution:
```
N=int(input())
S,T=input().split()
for i in range(0,N):
print(S[i],T[i],end="",sep="")
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are strings s and t of length N each, both consisting of lowercase English letters.
Let us form a new string by alternating the characters of S and the characters of T, as follows: the first character of S, the first character of T, the second character of S, the second character of T, ..., the N-th character of S, the N-th character of T. Print this new string.
Constraints
* 1 \leq N \leq 100
* |S| = |T| = N
* S and T are strings consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S T
Output
Print the string formed.
Examples
Input
2
ip cc
Output
icpc
Input
8
hmhmnknk uuuuuuuu
Output
humuhumunukunuku
Input
5
aaaaa aaaaa
Output
aaaaaaaaaa
Submitted Solution:
```
N=input()
S,T=input().split()
msg=""
for s,t in zip(S,T):
msg+=s
msg+=t
print(msg)
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are strings s and t of length N each, both consisting of lowercase English letters.
Let us form a new string by alternating the characters of S and the characters of T, as follows: the first character of S, the first character of T, the second character of S, the second character of T, ..., the N-th character of S, the N-th character of T. Print this new string.
Constraints
* 1 \leq N \leq 100
* |S| = |T| = N
* S and T are strings consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S T
Output
Print the string formed.
Examples
Input
2
ip cc
Output
icpc
Input
8
hmhmnknk uuuuuuuu
Output
humuhumunukunuku
Input
5
aaaaa aaaaa
Output
aaaaaaaaaa
Submitted Solution:
```
#b strings with the same length
n=int(input())
sentence=input().split()
ans=sentence[0]+sentence[1]
print(ans)
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are strings s and t of length N each, both consisting of lowercase English letters.
Let us form a new string by alternating the characters of S and the characters of T, as follows: the first character of S, the first character of T, the second character of S, the second character of T, ..., the N-th character of S, the N-th character of T. Print this new string.
Constraints
* 1 \leq N \leq 100
* |S| = |T| = N
* S and T are strings consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S T
Output
Print the string formed.
Examples
Input
2
ip cc
Output
icpc
Input
8
hmhmnknk uuuuuuuu
Output
humuhumunukunuku
Input
5
aaaaa aaaaa
Output
aaaaaaaaaa
Submitted Solution:
```
a=int(input())
char_list1,char_list2 = list(input().split())
for n in range(a):
print(char_list1[n+1:1]+char_list2[n+1:1])
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are strings s and t of length N each, both consisting of lowercase English letters.
Let us form a new string by alternating the characters of S and the characters of T, as follows: the first character of S, the first character of T, the second character of S, the second character of T, ..., the N-th character of S, the N-th character of T. Print this new string.
Constraints
* 1 \leq N \leq 100
* |S| = |T| = N
* S and T are strings consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S T
Output
Print the string formed.
Examples
Input
2
ip cc
Output
icpc
Input
8
hmhmnknk uuuuuuuu
Output
humuhumunukunuku
Input
5
aaaaa aaaaa
Output
aaaaaaaaaa
Submitted Solution:
```
n = input()
s,t = input().split()
for i in range(n):
print(s[i]+t[i],end='')
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are strings s and t of length N each, both consisting of lowercase English letters.
Let us form a new string by alternating the characters of S and the characters of T, as follows: the first character of S, the first character of T, the second character of S, the second character of T, ..., the N-th character of S, the N-th character of T. Print this new string.
Constraints
* 1 \leq N \leq 100
* |S| = |T| = N
* S and T are strings consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S T
Output
Print the string formed.
Examples
Input
2
ip cc
Output
icpc
Input
8
hmhmnknk uuuuuuuu
Output
humuhumunukunuku
Input
5
aaaaa aaaaa
Output
aaaaaaaaaa
Submitted Solution:
```
def p_b():
n = int(input())
s, t = input().split()
ans = ""
for i in range(n):
ans += s[i]
ans += t[i]
print(ans)
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Iroha has a sequence of N strings s_1, s_2, ..., s_N.
She will choose some (possibly all) strings from the sequence, then concatenate those strings retaining the relative order, to produce a long string.
Among all strings of length K that she can produce in this way, find the lexicographically smallest one.
Constraints
* 1 ≦ N ≦ 2000
* 1 ≦ K ≦ 10^4
* For each i, 1 ≦ |s_i| ≦ K.
* |s_1| + |s_2| + ... + |s_N| ≦ 10^6
* For each i, s_i consists of lowercase letters.
* There exists at least one string of length K that Iroha can produce.
Input
The input is given from Standard Input in the following format:
N K
s_1
s_2
:
s_N
Output
Print the lexicographically smallest string of length K that Iroha can produce.
Examples
Input
3 7
at
coder
codar
Output
atcodar
Input
3 7
coder
codar
at
Output
codarat
Input
4 13
kyuri
namida
zzzzzzz
aaaaaa
Output
namidazzzzzzz
Submitted Solution:
```
from collections import defaultdict, deque, Counter
from heapq import heappush, heappop, heapify
import math
import bisect
import random
from itertools import permutations, accumulate, combinations
import sys
import string
from bisect import bisect_left, bisect_right
from math import factorial, ceil, floor
INF = float('inf')
def LI(): return list(map(int, sys.stdin.readline().split()))
def I(): return int(sys.stdin.readline())
def LS(): return sys.stdin.readline().split()
def S(): return sys.stdin.readline().strip()
def IR(n): return [I() for i in range(n)]
def LIR(n): return [LI() for i in range(n)]
def SR(n): return [S() for i in range(n)]
def LSR(n): return [LS() for i in range(n)]
def SRL(n): return [list(S()) for i in range(n)]
def MSRL(n): return [[int(j) for j in list(S())] for i in range(n)]
mod = 1000000007
n, k = LI()
L = SR(n)
dp = ['{' * l for l in range(k+1)]
for i in range(n):
for j in range(k, len(L[i]) - 1, -1):
dp[j] = min(dp[j-len(L[i])] + L[i], dp[j])
print(dp[k])
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Iroha has a sequence of N strings s_1, s_2, ..., s_N.
She will choose some (possibly all) strings from the sequence, then concatenate those strings retaining the relative order, to produce a long string.
Among all strings of length K that she can produce in this way, find the lexicographically smallest one.
Constraints
* 1 ≦ N ≦ 2000
* 1 ≦ K ≦ 10^4
* For each i, 1 ≦ |s_i| ≦ K.
* |s_1| + |s_2| + ... + |s_N| ≦ 10^6
* For each i, s_i consists of lowercase letters.
* There exists at least one string of length K that Iroha can produce.
Input
The input is given from Standard Input in the following format:
N K
s_1
s_2
:
s_N
Output
Print the lexicographically smallest string of length K that Iroha can produce.
Examples
Input
3 7
at
coder
codar
Output
atcodar
Input
3 7
coder
codar
at
Output
codarat
Input
4 13
kyuri
namida
zzzzzzz
aaaaaa
Output
namidazzzzzzz
Submitted Solution:
```
N, K = [int(x) for x in input().split()]
Kp1 = K+1
ss = [input() for _ in range(N)]
ds = ["~" * n for n in range(Kp1)]
for s in ss:
len_s = len(s)
for i in range(Kp1-len_s):
t = ds[i] + s
if t < ds[i+len_s]:
ds[i+len_s] = t
print(ds[K])
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Iroha has a sequence of N strings s_1, s_2, ..., s_N.
She will choose some (possibly all) strings from the sequence, then concatenate those strings retaining the relative order, to produce a long string.
Among all strings of length K that she can produce in this way, find the lexicographically smallest one.
Constraints
* 1 ≦ N ≦ 2000
* 1 ≦ K ≦ 10^4
* For each i, 1 ≦ |s_i| ≦ K.
* |s_1| + |s_2| + ... + |s_N| ≦ 10^6
* For each i, s_i consists of lowercase letters.
* There exists at least one string of length K that Iroha can produce.
Input
The input is given from Standard Input in the following format:
N K
s_1
s_2
:
s_N
Output
Print the lexicographically smallest string of length K that Iroha can produce.
Examples
Input
3 7
at
coder
codar
Output
atcodar
Input
3 7
coder
codar
at
Output
codarat
Input
4 13
kyuri
namida
zzzzzzz
aaaaaa
Output
namidazzzzzzz
Submitted Solution:
```
#!/usr/bin/env python3
import sys
sys.setrecursionlimit(2020)
def make_best(s, best, path):
candidate = ''.join([s[i] for i in path])
if best is None or candidate < best:
return candidate
return best
def dfs(n, k, s, l, i, path, t, best):
path.append(i)
t += l[i]
if t == k:
best = make_best(s, best, path)
path.pop()
return best
elif k < t:
path.pop()
return best
for j in range(i + 1, n):
best = dfs(n, k, s, l, j, path, t, best)
path.pop()
return best
def solve(n, k, s):
l = [len(si) for si in s]
dp = [[0] * (k + 1) for _ in range(n + 1)]
dp[n][0] = 1
for i in range(n - 1, -1, -1):
li = l[i]
lk = k - li
for j in range(k + 1):
if dp[i + 1][j]:
dp[i][j] = 1
if j <= lk:
dp[i][j + li] = 1
order = [i for i in range(n)]
order.sort(key = lambda i: s[i])
order2 = []
i = 0
while i < n:
j = order[i]
a = [j]
order2.append(a)
sj = s[j]
lj = l[j]
ni = i + 1
while ni < n:
nj = order[ni]
if lj <= l[nj]:
snj = s[nj]
if snj[:lj] == sj:
a.append(nj)
ni += 1
else:
break
else:
break
a.sort(reverse = True)
i = ni
best = None
for a in order2:
for i in a:
if dp[i][k - l[i]]:
path = []
best = dfs(n, k, s, l, i, path, 0, best)
if best is not None:
break
return best
def main():
n, k = input().split()
n = int(n)
k = int(k)
s = []
for _ in range(n):
si = input()
s.append(si)
print(solve(n, k, s))
if __name__ == '__main__':
main()
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Iroha has a sequence of N strings s_1, s_2, ..., s_N.
She will choose some (possibly all) strings from the sequence, then concatenate those strings retaining the relative order, to produce a long string.
Among all strings of length K that she can produce in this way, find the lexicographically smallest one.
Constraints
* 1 ≦ N ≦ 2000
* 1 ≦ K ≦ 10^4
* For each i, 1 ≦ |s_i| ≦ K.
* |s_1| + |s_2| + ... + |s_N| ≦ 10^6
* For each i, s_i consists of lowercase letters.
* There exists at least one string of length K that Iroha can produce.
Input
The input is given from Standard Input in the following format:
N K
s_1
s_2
:
s_N
Output
Print the lexicographically smallest string of length K that Iroha can produce.
Examples
Input
3 7
at
coder
codar
Output
atcodar
Input
3 7
coder
codar
at
Output
codarat
Input
4 13
kyuri
namida
zzzzzzz
aaaaaa
Output
namidazzzzzzz
Submitted Solution:
```
N,K=map(int,input().strip().split())
s=[]
kazu=[]
for i in range(N):
s.append(input())
kazu.append(len(s[i]))
for z in range(N):
for x in range(N):
if z==x:
break
if kazu[x]+kazu[z]==K:
print(s[x]+s[z])
exit()
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You want to perform the combo on your opponent in one popular fighting game. The combo is the string s consisting of n lowercase Latin letters. To perform the combo, you have to press all buttons in the order they appear in s. I.e. if s="abca" then you have to press 'a', then 'b', 'c' and 'a' again.
You know that you will spend m wrong tries to perform the combo and during the i-th try you will make a mistake right after p_i-th button (1 ≤ p_i < n) (i.e. you will press first p_i buttons right and start performing the combo from the beginning). It is guaranteed that during the m+1-th try you press all buttons right and finally perform the combo.
I.e. if s="abca", m=2 and p = [1, 3] then the sequence of pressed buttons will be 'a' (here you're making a mistake and start performing the combo from the beginning), 'a', 'b', 'c', (here you're making a mistake and start performing the combo from the beginning), 'a' (note that at this point you will not perform the combo because of the mistake), 'b', 'c', 'a'.
Your task is to calculate for each button (letter) the number of times you'll press it.
You have to answer t independent test cases.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases.
Then t test cases follow.
The first line of each test case contains two integers n and m (2 ≤ n ≤ 2 ⋅ 10^5, 1 ≤ m ≤ 2 ⋅ 10^5) — the length of s and the number of tries correspondingly.
The second line of each test case contains the string s consisting of n lowercase Latin letters.
The third line of each test case contains m integers p_1, p_2, ..., p_m (1 ≤ p_i < n) — the number of characters pressed right during the i-th try.
It is guaranteed that the sum of n and the sum of m both does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5, ∑ m ≤ 2 ⋅ 10^5).
It is guaranteed that the answer for each letter does not exceed 2 ⋅ 10^9.
Output
For each test case, print the answer — 26 integers: the number of times you press the button 'a', the number of times you press the button 'b', ..., the number of times you press the button 'z'.
Example
Input
3
4 2
abca
1 3
10 5
codeforces
2 8 3 2 9
26 10
qwertyuioplkjhgfdsazxcvbnm
20 10 1 2 3 5 10 5 9 4
Output
4 2 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 9 4 5 3 0 0 0 0 0 0 0 0 9 0 0 3 1 0 0 0 0 0 0 0
2 1 1 2 9 2 2 2 5 2 2 2 1 1 5 4 11 8 2 7 5 1 10 1 5 2
Note
The first test case is described in the problem statement. Wrong tries are "a", "abc" and the final try is "abca". The number of times you press 'a' is 4, 'b' is 2 and 'c' is 2.
In the second test case, there are five wrong tries: "co", "codeforc", "cod", "co", "codeforce" and the final try is "codeforces". The number of times you press 'c' is 9, 'd' is 4, 'e' is 5, 'f' is 3, 'o' is 9, 'r' is 3 and 's' is 1.
Submitted Solution:
```
def main():
t = int(input())
for _ in range(t):
n, m = list(map(int, input().strip().split()))
s = input()
p = list(map(int, input().strip().split()))
p.append(n)
cnt = [[0 for _ in range(26)] for _ in range(n)]
cnt[0][ord(s[0])-97] = 1
for i in range(1, n):
for j in range(26): cnt[i][j] = cnt[i-1][j]
cnt[i][ord(s[i])-97] += 1
ret = [0 for _ in range(26)]
for pos in p:
for i in range(26): ret[i] += cnt[pos-1][i]
print(" ".join(list(map(str, ret))))
if __name__ == "__main__": main()
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You want to perform the combo on your opponent in one popular fighting game. The combo is the string s consisting of n lowercase Latin letters. To perform the combo, you have to press all buttons in the order they appear in s. I.e. if s="abca" then you have to press 'a', then 'b', 'c' and 'a' again.
You know that you will spend m wrong tries to perform the combo and during the i-th try you will make a mistake right after p_i-th button (1 ≤ p_i < n) (i.e. you will press first p_i buttons right and start performing the combo from the beginning). It is guaranteed that during the m+1-th try you press all buttons right and finally perform the combo.
I.e. if s="abca", m=2 and p = [1, 3] then the sequence of pressed buttons will be 'a' (here you're making a mistake and start performing the combo from the beginning), 'a', 'b', 'c', (here you're making a mistake and start performing the combo from the beginning), 'a' (note that at this point you will not perform the combo because of the mistake), 'b', 'c', 'a'.
Your task is to calculate for each button (letter) the number of times you'll press it.
You have to answer t independent test cases.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases.
Then t test cases follow.
The first line of each test case contains two integers n and m (2 ≤ n ≤ 2 ⋅ 10^5, 1 ≤ m ≤ 2 ⋅ 10^5) — the length of s and the number of tries correspondingly.
The second line of each test case contains the string s consisting of n lowercase Latin letters.
The third line of each test case contains m integers p_1, p_2, ..., p_m (1 ≤ p_i < n) — the number of characters pressed right during the i-th try.
It is guaranteed that the sum of n and the sum of m both does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5, ∑ m ≤ 2 ⋅ 10^5).
It is guaranteed that the answer for each letter does not exceed 2 ⋅ 10^9.
Output
For each test case, print the answer — 26 integers: the number of times you press the button 'a', the number of times you press the button 'b', ..., the number of times you press the button 'z'.
Example
Input
3
4 2
abca
1 3
10 5
codeforces
2 8 3 2 9
26 10
qwertyuioplkjhgfdsazxcvbnm
20 10 1 2 3 5 10 5 9 4
Output
4 2 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 9 4 5 3 0 0 0 0 0 0 0 0 9 0 0 3 1 0 0 0 0 0 0 0
2 1 1 2 9 2 2 2 5 2 2 2 1 1 5 4 11 8 2 7 5 1 10 1 5 2
Note
The first test case is described in the problem statement. Wrong tries are "a", "abc" and the final try is "abca". The number of times you press 'a' is 4, 'b' is 2 and 'c' is 2.
In the second test case, there are five wrong tries: "co", "codeforc", "cod", "co", "codeforce" and the final try is "codeforces". The number of times you press 'c' is 9, 'd' is 4, 'e' is 5, 'f' is 3, 'o' is 9, 'r' is 3 and 's' is 1.
Submitted Solution:
```
import sys;input=sys.stdin.readline
# from decimal import *
# import math
# getcontext().prec = 50
# input().strip()
# int(input())
# list(map(int,input().split()))
# map(int,input().split())
# def solve():
# for _ in range(int(input())):
# solve()
# print()
def update(res,h):
for i in h.keys():
res[ord(i)-97]+=h[i]
def solve():
n,m = map(int,input().split())
s = input().strip()
q = sorted(list(map(int,input().split())),reverse = True)
h = {}
for i in s:
if i not in h:
h[i] = 1
else:
h[i] = h[i]+1
res = [0 for _ in range(26)]
last = len(s)
update(res,h)
for qu in q:
for x in range(qu,last):
h[s[x]]-=1
update(res,h)
last = qu
print(*res)
# solve()
for _ in range(int(input())):
solve()
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You want to perform the combo on your opponent in one popular fighting game. The combo is the string s consisting of n lowercase Latin letters. To perform the combo, you have to press all buttons in the order they appear in s. I.e. if s="abca" then you have to press 'a', then 'b', 'c' and 'a' again.
You know that you will spend m wrong tries to perform the combo and during the i-th try you will make a mistake right after p_i-th button (1 ≤ p_i < n) (i.e. you will press first p_i buttons right and start performing the combo from the beginning). It is guaranteed that during the m+1-th try you press all buttons right and finally perform the combo.
I.e. if s="abca", m=2 and p = [1, 3] then the sequence of pressed buttons will be 'a' (here you're making a mistake and start performing the combo from the beginning), 'a', 'b', 'c', (here you're making a mistake and start performing the combo from the beginning), 'a' (note that at this point you will not perform the combo because of the mistake), 'b', 'c', 'a'.
Your task is to calculate for each button (letter) the number of times you'll press it.
You have to answer t independent test cases.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases.
Then t test cases follow.
The first line of each test case contains two integers n and m (2 ≤ n ≤ 2 ⋅ 10^5, 1 ≤ m ≤ 2 ⋅ 10^5) — the length of s and the number of tries correspondingly.
The second line of each test case contains the string s consisting of n lowercase Latin letters.
The third line of each test case contains m integers p_1, p_2, ..., p_m (1 ≤ p_i < n) — the number of characters pressed right during the i-th try.
It is guaranteed that the sum of n and the sum of m both does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5, ∑ m ≤ 2 ⋅ 10^5).
It is guaranteed that the answer for each letter does not exceed 2 ⋅ 10^9.
Output
For each test case, print the answer — 26 integers: the number of times you press the button 'a', the number of times you press the button 'b', ..., the number of times you press the button 'z'.
Example
Input
3
4 2
abca
1 3
10 5
codeforces
2 8 3 2 9
26 10
qwertyuioplkjhgfdsazxcvbnm
20 10 1 2 3 5 10 5 9 4
Output
4 2 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 9 4 5 3 0 0 0 0 0 0 0 0 9 0 0 3 1 0 0 0 0 0 0 0
2 1 1 2 9 2 2 2 5 2 2 2 1 1 5 4 11 8 2 7 5 1 10 1 5 2
Note
The first test case is described in the problem statement. Wrong tries are "a", "abc" and the final try is "abca". The number of times you press 'a' is 4, 'b' is 2 and 'c' is 2.
In the second test case, there are five wrong tries: "co", "codeforc", "cod", "co", "codeforce" and the final try is "codeforces". The number of times you press 'c' is 9, 'd' is 4, 'e' is 5, 'f' is 3, 'o' is 9, 'r' is 3 and 's' is 1.
Submitted Solution:
```
#!/usr/bin/python3
# Codeforces - Round 624
# Problem C - Perform the Combo
from collections import Counter
letters = "abcdefghijklmnopqrstuvwxyz"
def combo(m, s, p):
cnt = Counter(s)
ind = 0
p.sort()
l = len(p)
for i in range(l):
if p[i] == ind:
continue
presses = s[ind:p[i]]
for press in presses:
cnt[press] += l - i
ind = p[i]
sol = [str(cnt[l]) for l in letters]
return " ".join(sol)
# Main
t = int(input())
for case in range(t):
nm = [int(x) for x in input().split(" ")]
n = nm[0]
m = nm[1]
s = input()
p = [int(x) for x in input().split(" ")]
sol = combo(m, s, p)
print (sol)
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You want to perform the combo on your opponent in one popular fighting game. The combo is the string s consisting of n lowercase Latin letters. To perform the combo, you have to press all buttons in the order they appear in s. I.e. if s="abca" then you have to press 'a', then 'b', 'c' and 'a' again.
You know that you will spend m wrong tries to perform the combo and during the i-th try you will make a mistake right after p_i-th button (1 ≤ p_i < n) (i.e. you will press first p_i buttons right and start performing the combo from the beginning). It is guaranteed that during the m+1-th try you press all buttons right and finally perform the combo.
I.e. if s="abca", m=2 and p = [1, 3] then the sequence of pressed buttons will be 'a' (here you're making a mistake and start performing the combo from the beginning), 'a', 'b', 'c', (here you're making a mistake and start performing the combo from the beginning), 'a' (note that at this point you will not perform the combo because of the mistake), 'b', 'c', 'a'.
Your task is to calculate for each button (letter) the number of times you'll press it.
You have to answer t independent test cases.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases.
Then t test cases follow.
The first line of each test case contains two integers n and m (2 ≤ n ≤ 2 ⋅ 10^5, 1 ≤ m ≤ 2 ⋅ 10^5) — the length of s and the number of tries correspondingly.
The second line of each test case contains the string s consisting of n lowercase Latin letters.
The third line of each test case contains m integers p_1, p_2, ..., p_m (1 ≤ p_i < n) — the number of characters pressed right during the i-th try.
It is guaranteed that the sum of n and the sum of m both does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5, ∑ m ≤ 2 ⋅ 10^5).
It is guaranteed that the answer for each letter does not exceed 2 ⋅ 10^9.
Output
For each test case, print the answer — 26 integers: the number of times you press the button 'a', the number of times you press the button 'b', ..., the number of times you press the button 'z'.
Example
Input
3
4 2
abca
1 3
10 5
codeforces
2 8 3 2 9
26 10
qwertyuioplkjhgfdsazxcvbnm
20 10 1 2 3 5 10 5 9 4
Output
4 2 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 9 4 5 3 0 0 0 0 0 0 0 0 9 0 0 3 1 0 0 0 0 0 0 0
2 1 1 2 9 2 2 2 5 2 2 2 1 1 5 4 11 8 2 7 5 1 10 1 5 2
Note
The first test case is described in the problem statement. Wrong tries are "a", "abc" and the final try is "abca". The number of times you press 'a' is 4, 'b' is 2 and 'c' is 2.
In the second test case, there are five wrong tries: "co", "codeforc", "cod", "co", "codeforce" and the final try is "codeforces". The number of times you press 'c' is 9, 'd' is 4, 'e' is 5, 'f' is 3, 'o' is 9, 'r' is 3 and 's' is 1.
Submitted Solution:
```
t = int(input())
for _ in range(t):
n, m = map(int, input().split())
s = input()
p = list(map(int, input().split()))
d = dict()
k = ord(s[0]) - ord('a')
q = [0 for i in range(26)]
q[k] += 1
d[0] = q
for i in range(1,n):
k = ord(s[i]) - ord('a')
add = [j for j in d[i-1]]
add[k] += 1
d[i] = add
ans = [0 for _ in range(26)]
for i in range(m):
for j in range(26):
ans[j] += d[p[i] - 1][j]
for j in range(26):
ans[j] += d[n - 1][j]
for i in range(26):
print("{} ".format(ans[i]), end="")
print()
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You want to perform the combo on your opponent in one popular fighting game. The combo is the string s consisting of n lowercase Latin letters. To perform the combo, you have to press all buttons in the order they appear in s. I.e. if s="abca" then you have to press 'a', then 'b', 'c' and 'a' again.
You know that you will spend m wrong tries to perform the combo and during the i-th try you will make a mistake right after p_i-th button (1 ≤ p_i < n) (i.e. you will press first p_i buttons right and start performing the combo from the beginning). It is guaranteed that during the m+1-th try you press all buttons right and finally perform the combo.
I.e. if s="abca", m=2 and p = [1, 3] then the sequence of pressed buttons will be 'a' (here you're making a mistake and start performing the combo from the beginning), 'a', 'b', 'c', (here you're making a mistake and start performing the combo from the beginning), 'a' (note that at this point you will not perform the combo because of the mistake), 'b', 'c', 'a'.
Your task is to calculate for each button (letter) the number of times you'll press it.
You have to answer t independent test cases.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases.
Then t test cases follow.
The first line of each test case contains two integers n and m (2 ≤ n ≤ 2 ⋅ 10^5, 1 ≤ m ≤ 2 ⋅ 10^5) — the length of s and the number of tries correspondingly.
The second line of each test case contains the string s consisting of n lowercase Latin letters.
The third line of each test case contains m integers p_1, p_2, ..., p_m (1 ≤ p_i < n) — the number of characters pressed right during the i-th try.
It is guaranteed that the sum of n and the sum of m both does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5, ∑ m ≤ 2 ⋅ 10^5).
It is guaranteed that the answer for each letter does not exceed 2 ⋅ 10^9.
Output
For each test case, print the answer — 26 integers: the number of times you press the button 'a', the number of times you press the button 'b', ..., the number of times you press the button 'z'.
Example
Input
3
4 2
abca
1 3
10 5
codeforces
2 8 3 2 9
26 10
qwertyuioplkjhgfdsazxcvbnm
20 10 1 2 3 5 10 5 9 4
Output
4 2 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 9 4 5 3 0 0 0 0 0 0 0 0 9 0 0 3 1 0 0 0 0 0 0 0
2 1 1 2 9 2 2 2 5 2 2 2 1 1 5 4 11 8 2 7 5 1 10 1 5 2
Note
The first test case is described in the problem statement. Wrong tries are "a", "abc" and the final try is "abca". The number of times you press 'a' is 4, 'b' is 2 and 'c' is 2.
In the second test case, there are five wrong tries: "co", "codeforc", "cod", "co", "codeforce" and the final try is "codeforces". The number of times you press 'c' is 9, 'd' is 4, 'e' is 5, 'f' is 3, 'o' is 9, 'r' is 3 and 's' is 1.
Submitted Solution:
```
numbertests=int(input())
lengths=[]
mistakes=[]
map=[]
for x in range(26):
map.append(0)
for i in range(numbertests):
lengths=[int (i) for i in input().split()]
word=input()
mistakes=[int (i) for i in input().split()]
split=[char for char in word]
for c in mistakes:
for e in range(c):
map[ord(split[e])-97]=map[ord(split[e])-97]+1
for d in range(len(word)):
map[ord(split[d])-97]=map[ord(split[d])-97]+1
for g in range(len(map)):
print(map[g], end=" ")
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You want to perform the combo on your opponent in one popular fighting game. The combo is the string s consisting of n lowercase Latin letters. To perform the combo, you have to press all buttons in the order they appear in s. I.e. if s="abca" then you have to press 'a', then 'b', 'c' and 'a' again.
You know that you will spend m wrong tries to perform the combo and during the i-th try you will make a mistake right after p_i-th button (1 ≤ p_i < n) (i.e. you will press first p_i buttons right and start performing the combo from the beginning). It is guaranteed that during the m+1-th try you press all buttons right and finally perform the combo.
I.e. if s="abca", m=2 and p = [1, 3] then the sequence of pressed buttons will be 'a' (here you're making a mistake and start performing the combo from the beginning), 'a', 'b', 'c', (here you're making a mistake and start performing the combo from the beginning), 'a' (note that at this point you will not perform the combo because of the mistake), 'b', 'c', 'a'.
Your task is to calculate for each button (letter) the number of times you'll press it.
You have to answer t independent test cases.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases.
Then t test cases follow.
The first line of each test case contains two integers n and m (2 ≤ n ≤ 2 ⋅ 10^5, 1 ≤ m ≤ 2 ⋅ 10^5) — the length of s and the number of tries correspondingly.
The second line of each test case contains the string s consisting of n lowercase Latin letters.
The third line of each test case contains m integers p_1, p_2, ..., p_m (1 ≤ p_i < n) — the number of characters pressed right during the i-th try.
It is guaranteed that the sum of n and the sum of m both does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5, ∑ m ≤ 2 ⋅ 10^5).
It is guaranteed that the answer for each letter does not exceed 2 ⋅ 10^9.
Output
For each test case, print the answer — 26 integers: the number of times you press the button 'a', the number of times you press the button 'b', ..., the number of times you press the button 'z'.
Example
Input
3
4 2
abca
1 3
10 5
codeforces
2 8 3 2 9
26 10
qwertyuioplkjhgfdsazxcvbnm
20 10 1 2 3 5 10 5 9 4
Output
4 2 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 9 4 5 3 0 0 0 0 0 0 0 0 9 0 0 3 1 0 0 0 0 0 0 0
2 1 1 2 9 2 2 2 5 2 2 2 1 1 5 4 11 8 2 7 5 1 10 1 5 2
Note
The first test case is described in the problem statement. Wrong tries are "a", "abc" and the final try is "abca". The number of times you press 'a' is 4, 'b' is 2 and 'c' is 2.
In the second test case, there are five wrong tries: "co", "codeforc", "cod", "co", "codeforce" and the final try is "codeforces". The number of times you press 'c' is 9, 'd' is 4, 'e' is 5, 'f' is 3, 'o' is 9, 'r' is 3 and 's' is 1.
Submitted Solution:
```
for _ in " "*int(input()):
a,b=map(int,input().split())
z=input()
s=sorted(map(int,input().split()))
ans=[0]*26;p=0;i=0;co=0
while i<b:
k=[0]*26
for j in range(p,s[i]):
o=ord(z[j])-97
k[o]+=1
r=z[i]
while i<b and r==z[i]:i+=1
for t in range(26):ans[t]+=(k[t]*(b-co+1))
p=s[i-1];co+=1
for i in range(s[-1],a):ans[ord(z[i])-97]+=1
print(*ans)
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You want to perform the combo on your opponent in one popular fighting game. The combo is the string s consisting of n lowercase Latin letters. To perform the combo, you have to press all buttons in the order they appear in s. I.e. if s="abca" then you have to press 'a', then 'b', 'c' and 'a' again.
You know that you will spend m wrong tries to perform the combo and during the i-th try you will make a mistake right after p_i-th button (1 ≤ p_i < n) (i.e. you will press first p_i buttons right and start performing the combo from the beginning). It is guaranteed that during the m+1-th try you press all buttons right and finally perform the combo.
I.e. if s="abca", m=2 and p = [1, 3] then the sequence of pressed buttons will be 'a' (here you're making a mistake and start performing the combo from the beginning), 'a', 'b', 'c', (here you're making a mistake and start performing the combo from the beginning), 'a' (note that at this point you will not perform the combo because of the mistake), 'b', 'c', 'a'.
Your task is to calculate for each button (letter) the number of times you'll press it.
You have to answer t independent test cases.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases.
Then t test cases follow.
The first line of each test case contains two integers n and m (2 ≤ n ≤ 2 ⋅ 10^5, 1 ≤ m ≤ 2 ⋅ 10^5) — the length of s and the number of tries correspondingly.
The second line of each test case contains the string s consisting of n lowercase Latin letters.
The third line of each test case contains m integers p_1, p_2, ..., p_m (1 ≤ p_i < n) — the number of characters pressed right during the i-th try.
It is guaranteed that the sum of n and the sum of m both does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5, ∑ m ≤ 2 ⋅ 10^5).
It is guaranteed that the answer for each letter does not exceed 2 ⋅ 10^9.
Output
For each test case, print the answer — 26 integers: the number of times you press the button 'a', the number of times you press the button 'b', ..., the number of times you press the button 'z'.
Example
Input
3
4 2
abca
1 3
10 5
codeforces
2 8 3 2 9
26 10
qwertyuioplkjhgfdsazxcvbnm
20 10 1 2 3 5 10 5 9 4
Output
4 2 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 9 4 5 3 0 0 0 0 0 0 0 0 9 0 0 3 1 0 0 0 0 0 0 0
2 1 1 2 9 2 2 2 5 2 2 2 1 1 5 4 11 8 2 7 5 1 10 1 5 2
Note
The first test case is described in the problem statement. Wrong tries are "a", "abc" and the final try is "abca". The number of times you press 'a' is 4, 'b' is 2 and 'c' is 2.
In the second test case, there are five wrong tries: "co", "codeforc", "cod", "co", "codeforce" and the final try is "codeforces". The number of times you press 'c' is 9, 'd' is 4, 'e' is 5, 'f' is 3, 'o' is 9, 'r' is 3 and 's' is 1.
Submitted Solution:
```
from sys import *
from collections import Counter
input = lambda:stdin.readline()
int_arr = lambda : list(map(int,stdin.readline().strip().split()))
str_arr = lambda :list(map(str,stdin.readline().split()))
get_str = lambda : map(str,stdin.readline().strip().split())
get_int = lambda: map(int,stdin.readline().strip().split())
get_float = lambda : map(float,stdin.readline().strip().split())
mod = 1000000007
setrecursionlimit(1000)
for _ in range(int(input())):
n,m = get_int()
s = str(input())[:-1]
arr = int_arr()
lst = [0] * 26
for ele,ct in Counter(s).items():
lst[ord(ele) - 97] = ct
dic = {}
for i in range(n):
ls = []
for j in range(i+1):
ls += [ord(s[j]) - 97]
dic[i] = ls
ls = []
for i in range(m):
ls += dic[arr[i]-1]
for ele,ct in Counter(ls).items():
lst[ele] += ct
print(lst)
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You want to perform the combo on your opponent in one popular fighting game. The combo is the string s consisting of n lowercase Latin letters. To perform the combo, you have to press all buttons in the order they appear in s. I.e. if s="abca" then you have to press 'a', then 'b', 'c' and 'a' again.
You know that you will spend m wrong tries to perform the combo and during the i-th try you will make a mistake right after p_i-th button (1 ≤ p_i < n) (i.e. you will press first p_i buttons right and start performing the combo from the beginning). It is guaranteed that during the m+1-th try you press all buttons right and finally perform the combo.
I.e. if s="abca", m=2 and p = [1, 3] then the sequence of pressed buttons will be 'a' (here you're making a mistake and start performing the combo from the beginning), 'a', 'b', 'c', (here you're making a mistake and start performing the combo from the beginning), 'a' (note that at this point you will not perform the combo because of the mistake), 'b', 'c', 'a'.
Your task is to calculate for each button (letter) the number of times you'll press it.
You have to answer t independent test cases.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases.
Then t test cases follow.
The first line of each test case contains two integers n and m (2 ≤ n ≤ 2 ⋅ 10^5, 1 ≤ m ≤ 2 ⋅ 10^5) — the length of s and the number of tries correspondingly.
The second line of each test case contains the string s consisting of n lowercase Latin letters.
The third line of each test case contains m integers p_1, p_2, ..., p_m (1 ≤ p_i < n) — the number of characters pressed right during the i-th try.
It is guaranteed that the sum of n and the sum of m both does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5, ∑ m ≤ 2 ⋅ 10^5).
It is guaranteed that the answer for each letter does not exceed 2 ⋅ 10^9.
Output
For each test case, print the answer — 26 integers: the number of times you press the button 'a', the number of times you press the button 'b', ..., the number of times you press the button 'z'.
Example
Input
3
4 2
abca
1 3
10 5
codeforces
2 8 3 2 9
26 10
qwertyuioplkjhgfdsazxcvbnm
20 10 1 2 3 5 10 5 9 4
Output
4 2 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 9 4 5 3 0 0 0 0 0 0 0 0 9 0 0 3 1 0 0 0 0 0 0 0
2 1 1 2 9 2 2 2 5 2 2 2 1 1 5 4 11 8 2 7 5 1 10 1 5 2
Note
The first test case is described in the problem statement. Wrong tries are "a", "abc" and the final try is "abca". The number of times you press 'a' is 4, 'b' is 2 and 'c' is 2.
In the second test case, there are five wrong tries: "co", "codeforc", "cod", "co", "codeforce" and the final try is "codeforces". The number of times you press 'c' is 9, 'd' is 4, 'e' is 5, 'f' is 3, 'o' is 9, 'r' is 3 and 's' is 1.
Submitted Solution:
```
alphabet = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
t = int(input())
def binsearch(nums, target):
left = 0
right = len(nums) - 1
while left <= right:
mid = (left + right) // 2
if nums[mid] == target:
return mid
elif nums[mid] > target:
right = mid - 1
elif nums[mid] < target:
left = mid + 1
return left
for tc in range(t):
n, m = map(int, input().split())
s = input()
fails = [int(z)-1 for z in input().split()]
occ = {}
fails.sort()
for i in alphabet:
occ[i] = 0
for i in range(n):
pl = binsearch(fails, i)
occ[s[i]] += m - pl
#print(pl, fails)
for i in range(n):
occ[s[i]] += 1
res = []
for i in range(26):
res.append(occ[alphabet[i]])
print(*res)
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given an n × n table T consisting of lowercase English letters. We'll consider some string s good if the table contains a correct path corresponding to the given string. In other words, good strings are all strings we can obtain by moving from the left upper cell of the table only to the right and down. Here's the formal definition of correct paths:
Consider rows of the table are numbered from 1 to n from top to bottom, and columns of the table are numbered from 1 to n from left to the right. Cell (r, c) is a cell of table T on the r-th row and in the c-th column. This cell corresponds to letter Tr, c.
A path of length k is a sequence of table cells [(r1, c1), (r2, c2), ..., (rk, ck)]. The following paths are correct:
1. There is only one correct path of length 1, that is, consisting of a single cell: [(1, 1)];
2. Let's assume that [(r1, c1), ..., (rm, cm)] is a correct path of length m, then paths [(r1, c1), ..., (rm, cm), (rm + 1, cm)] and [(r1, c1), ..., (rm, cm), (rm, cm + 1)] are correct paths of length m + 1.
We should assume that a path [(r1, c1), (r2, c2), ..., (rk, ck)] corresponds to a string of length k: Tr1, c1 + Tr2, c2 + ... + Trk, ck.
Two players play the following game: initially they have an empty string. Then the players take turns to add a letter to the end of the string. After each move (adding a new letter) the resulting string must be good. The game ends after 2n - 1 turns. A player wins by the following scenario:
1. If the resulting string has strictly more letters "a" than letters "b", then the first player wins;
2. If the resulting string has strictly more letters "b" than letters "a", then the second player wins;
3. If the resulting string has the same number of letters "a" and "b", then the players end the game with a draw.
Your task is to determine the result of the game provided that both players played optimally well.
Input
The first line contains a single number n (1 ≤ n ≤ 20).
Next n lines contain n lowercase English letters each — table T.
Output
In a single line print string "FIRST", if the first player wins, "SECOND", if the second player wins and "DRAW", if the game ends with a draw.
Examples
Input
2
ab
cd
Output
DRAW
Input
2
xa
ay
Output
FIRST
Input
3
aab
bcb
bac
Output
DRAW
Note
Consider the first sample:
Good strings are strings: a, ab, ac, abd, acd.
The first player moves first and adds letter a to the string, as there is only one good string of length 1. Then the second player can add b or c and the game will end with strings abd or acd, correspondingly. In the first case it will be a draw (the string has one a and one b), in the second case the first player wins. Naturally, in this case the second player prefers to choose letter b and end the game with a draw.
Consider the second sample:
Good strings are: x, xa, xay.
We can see that the game will end with string xay and the first player wins.
Submitted Solution:
```
n = int(input())
ar = []
for i in range(n):
s = input()
ar.append(s)
a = 0
b = 0
def ans(i, j, k):
if (i > n -1 and j == n -1) or (j > n- 1 and i == n -1):
return 0
if (i > n - 1 or j > n - 1) and k == 1:
return 10000
if (i > n - 1 or j > n - 1) and k == 2:
return -10000
a = 0
if ar[i][j] == 'a':
a = 1
elif ar[i][j] == 'b':
a = -1
if k == 1:
s = max(a + ans(i + 1, j, 2), a + ans(i, j + 1, 2))
return s
else:
s = min(a + ans(i + 1, j, 1), a+ ans(i, j + 1, 1))
return s
#print(ans(0, 0, 2))
if ans(0, 0, 2) > 0:
print('FIRST')
elif ans(0, 0, 2) > 0:
print('SECOND')
else:
print('DRAW')
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given an n × n table T consisting of lowercase English letters. We'll consider some string s good if the table contains a correct path corresponding to the given string. In other words, good strings are all strings we can obtain by moving from the left upper cell of the table only to the right and down. Here's the formal definition of correct paths:
Consider rows of the table are numbered from 1 to n from top to bottom, and columns of the table are numbered from 1 to n from left to the right. Cell (r, c) is a cell of table T on the r-th row and in the c-th column. This cell corresponds to letter Tr, c.
A path of length k is a sequence of table cells [(r1, c1), (r2, c2), ..., (rk, ck)]. The following paths are correct:
1. There is only one correct path of length 1, that is, consisting of a single cell: [(1, 1)];
2. Let's assume that [(r1, c1), ..., (rm, cm)] is a correct path of length m, then paths [(r1, c1), ..., (rm, cm), (rm + 1, cm)] and [(r1, c1), ..., (rm, cm), (rm, cm + 1)] are correct paths of length m + 1.
We should assume that a path [(r1, c1), (r2, c2), ..., (rk, ck)] corresponds to a string of length k: Tr1, c1 + Tr2, c2 + ... + Trk, ck.
Two players play the following game: initially they have an empty string. Then the players take turns to add a letter to the end of the string. After each move (adding a new letter) the resulting string must be good. The game ends after 2n - 1 turns. A player wins by the following scenario:
1. If the resulting string has strictly more letters "a" than letters "b", then the first player wins;
2. If the resulting string has strictly more letters "b" than letters "a", then the second player wins;
3. If the resulting string has the same number of letters "a" and "b", then the players end the game with a draw.
Your task is to determine the result of the game provided that both players played optimally well.
Input
The first line contains a single number n (1 ≤ n ≤ 20).
Next n lines contain n lowercase English letters each — table T.
Output
In a single line print string "FIRST", if the first player wins, "SECOND", if the second player wins and "DRAW", if the game ends with a draw.
Examples
Input
2
ab
cd
Output
DRAW
Input
2
xa
ay
Output
FIRST
Input
3
aab
bcb
bac
Output
DRAW
Note
Consider the first sample:
Good strings are strings: a, ab, ac, abd, acd.
The first player moves first and adds letter a to the string, as there is only one good string of length 1. Then the second player can add b or c and the game will end with strings abd or acd, correspondingly. In the first case it will be a draw (the string has one a and one b), in the second case the first player wins. Naturally, in this case the second player prefers to choose letter b and end the game with a draw.
Consider the second sample:
Good strings are: x, xa, xay.
We can see that the game will end with string xay and the first player wins.
Submitted Solution:
```
n = int(input())
ar = []
for i in range(n):
s = input()
ar.append(s)
a = 0
b = 0
def ans(i, j, k):
if (i > n -1 and j == n -1) or (j > n- 1 and i == n -1):
return 0
if (i > n - 1 or j > n - 1) and k == 1:
return 10000
if (i > n - 1 or j > n - 1) and k == 2:
return -10000
a = 0
if ar[i][j] == 'a':
a = 1
elif ar[i][j] == 'b':
a = -1
if k == 1:
s = max(a + ans(i + 1, j, 2), a + ans(i, j + 1, 2))
return s
else:
s = min(a + ans(i + 1, j, 1), a+ ans(i, j + 1, 1))
return s
#print(ans(0, 0, 2))
if ans(0, 0, 2) > 0:
print('FIRST')
elif ans(0, 0, 2) < 0:
print('SECOND')
else:
print('DRAW')
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given an n × n table T consisting of lowercase English letters. We'll consider some string s good if the table contains a correct path corresponding to the given string. In other words, good strings are all strings we can obtain by moving from the left upper cell of the table only to the right and down. Here's the formal definition of correct paths:
Consider rows of the table are numbered from 1 to n from top to bottom, and columns of the table are numbered from 1 to n from left to the right. Cell (r, c) is a cell of table T on the r-th row and in the c-th column. This cell corresponds to letter Tr, c.
A path of length k is a sequence of table cells [(r1, c1), (r2, c2), ..., (rk, ck)]. The following paths are correct:
1. There is only one correct path of length 1, that is, consisting of a single cell: [(1, 1)];
2. Let's assume that [(r1, c1), ..., (rm, cm)] is a correct path of length m, then paths [(r1, c1), ..., (rm, cm), (rm + 1, cm)] and [(r1, c1), ..., (rm, cm), (rm, cm + 1)] are correct paths of length m + 1.
We should assume that a path [(r1, c1), (r2, c2), ..., (rk, ck)] corresponds to a string of length k: Tr1, c1 + Tr2, c2 + ... + Trk, ck.
Two players play the following game: initially they have an empty string. Then the players take turns to add a letter to the end of the string. After each move (adding a new letter) the resulting string must be good. The game ends after 2n - 1 turns. A player wins by the following scenario:
1. If the resulting string has strictly more letters "a" than letters "b", then the first player wins;
2. If the resulting string has strictly more letters "b" than letters "a", then the second player wins;
3. If the resulting string has the same number of letters "a" and "b", then the players end the game with a draw.
Your task is to determine the result of the game provided that both players played optimally well.
Input
The first line contains a single number n (1 ≤ n ≤ 20).
Next n lines contain n lowercase English letters each — table T.
Output
In a single line print string "FIRST", if the first player wins, "SECOND", if the second player wins and "DRAW", if the game ends with a draw.
Examples
Input
2
ab
cd
Output
DRAW
Input
2
xa
ay
Output
FIRST
Input
3
aab
bcb
bac
Output
DRAW
Note
Consider the first sample:
Good strings are strings: a, ab, ac, abd, acd.
The first player moves first and adds letter a to the string, as there is only one good string of length 1. Then the second player can add b or c and the game will end with strings abd or acd, correspondingly. In the first case it will be a draw (the string has one a and one b), in the second case the first player wins. Naturally, in this case the second player prefers to choose letter b and end the game with a draw.
Consider the second sample:
Good strings are: x, xa, xay.
We can see that the game will end with string xay and the first player wins.
Submitted Solution:
```
def p(i, j):
if s[i][j] == 'a':
return 1
elif s[i][j] == 'b':
return -1
else:
return 0
n = int(input())
s = [1 for i in range(n)]
for i in range(n):
s[i] = input()
t = [[0] * n for i in range(n)]
if s[n - 1][n - 1] == 'a':
t[n - 1][n - 1] = 1
elif s[n - 1][n - 1] == 'b':
t[n - 1][n - 1] = -1
else:
t[n - 1][n - 1] = 0
for i in range(n - 2, -1, -1):
t[n - 1][i] = p(n - 1, i) + t[n - 1][i + 1]
t[i][n - 1] = p(i, n - 1) + t[i + 1][n - 1]
for i in range(n - 2, -1, -1):
for j in range(n - 2, -1, -1):
if (i % 2 == 0 and j % 2 == 0) or (i % 2 == 1 and j % 2 == 1):
t[i][j] = p(i, j) + min(t[i + 1][j], t[i][j + 1])
else:
t[i][j] = p(i, j) + max(t[i + 1][j], t[i][j + 1])
if t[0][0] == 0:
print('DRAW')
if t[0][0] > 0:
print('FIRST')
if t[0][0] < 0:
print('SECOND')
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given an n × n table T consisting of lowercase English letters. We'll consider some string s good if the table contains a correct path corresponding to the given string. In other words, good strings are all strings we can obtain by moving from the left upper cell of the table only to the right and down. Here's the formal definition of correct paths:
Consider rows of the table are numbered from 1 to n from top to bottom, and columns of the table are numbered from 1 to n from left to the right. Cell (r, c) is a cell of table T on the r-th row and in the c-th column. This cell corresponds to letter Tr, c.
A path of length k is a sequence of table cells [(r1, c1), (r2, c2), ..., (rk, ck)]. The following paths are correct:
1. There is only one correct path of length 1, that is, consisting of a single cell: [(1, 1)];
2. Let's assume that [(r1, c1), ..., (rm, cm)] is a correct path of length m, then paths [(r1, c1), ..., (rm, cm), (rm + 1, cm)] and [(r1, c1), ..., (rm, cm), (rm, cm + 1)] are correct paths of length m + 1.
We should assume that a path [(r1, c1), (r2, c2), ..., (rk, ck)] corresponds to a string of length k: Tr1, c1 + Tr2, c2 + ... + Trk, ck.
Two players play the following game: initially they have an empty string. Then the players take turns to add a letter to the end of the string. After each move (adding a new letter) the resulting string must be good. The game ends after 2n - 1 turns. A player wins by the following scenario:
1. If the resulting string has strictly more letters "a" than letters "b", then the first player wins;
2. If the resulting string has strictly more letters "b" than letters "a", then the second player wins;
3. If the resulting string has the same number of letters "a" and "b", then the players end the game with a draw.
Your task is to determine the result of the game provided that both players played optimally well.
Input
The first line contains a single number n (1 ≤ n ≤ 20).
Next n lines contain n lowercase English letters each — table T.
Output
In a single line print string "FIRST", if the first player wins, "SECOND", if the second player wins and "DRAW", if the game ends with a draw.
Examples
Input
2
ab
cd
Output
DRAW
Input
2
xa
ay
Output
FIRST
Input
3
aab
bcb
bac
Output
DRAW
Note
Consider the first sample:
Good strings are strings: a, ab, ac, abd, acd.
The first player moves first and adds letter a to the string, as there is only one good string of length 1. Then the second player can add b or c and the game will end with strings abd or acd, correspondingly. In the first case it will be a draw (the string has one a and one b), in the second case the first player wins. Naturally, in this case the second player prefers to choose letter b and end the game with a draw.
Consider the second sample:
Good strings are: x, xa, xay.
We can see that the game will end with string xay and the first player wins.
Submitted Solution:
```
n = int(input())
ar = []
for i in range(n):
s = input()
ar.append(s)
a = 0
b = 0
def ans(i, j, k):
if (i > n -1 and j == n -1) or (j > n- 1 and i == n -1):
return 0
if (i > n - 1 or j > n - 1) and k == 1:
return 10000
if (i > n - 1 or j > n - 1) and k == 2:
return -10000
a = 0
if ar[i][j] == 'a':
a = 1
elif ar[i][j] == 'b':
a = -1
if k == 1:
s = max(a + ans(i + 1, j, 2), a + ans(i, j + 1, 2))
return s
else:
s = min(a + ans(i + 1, j, 1), a+ ans(i, j + 1, 1))
return s
#print(ans(0, 0, 2))
if ans(0, 0, 2) == 1:
print('FIRST')
elif ans(0, 0, 2) == -1:
print('SECOND')
else:
print('DRAW')
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Malek has recently found a treasure map. While he was looking for a treasure he found a locked door. There was a string s written on the door consisting of characters '(', ')' and '#'. Below there was a manual on how to open the door. After spending a long time Malek managed to decode the manual and found out that the goal is to replace each '#' with one or more ')' characters so that the final string becomes beautiful.
Below there was also written that a string is called beautiful if for each i (1 ≤ i ≤ |s|) there are no more ')' characters than '(' characters among the first i characters of s and also the total number of '(' characters is equal to the total number of ')' characters.
Help Malek open the door by telling him for each '#' character how many ')' characters he must replace it with.
Input
The first line of the input contains a string s (1 ≤ |s| ≤ 105). Each character of this string is one of the characters '(', ')' or '#'. It is guaranteed that s contains at least one '#' character.
Output
If there is no way of replacing '#' characters which leads to a beautiful string print - 1. Otherwise for each character '#' print a separate line containing a positive integer, the number of ')' characters this character must be replaced with.
If there are several possible answers, you may output any of them.
Examples
Input
(((#)((#)
Output
1
2
Input
()((#((#(#()
Output
2
2
1
Input
#
Output
-1
Input
(#)
Output
-1
Note
|s| denotes the length of the string s.
Submitted Solution:
```
s = input()
n = s.rfind("#")
error = 0
s1 = 0
s2 = 0
s3 = 0
s4 = s.count("(")
s5 = s.count(")")
s6 = 0
for num in range(n):
if s[num]=="(" :
s2 += 1
elif s[num]==")":
s3 += 1
if s[num]=="#" :
s1 += 1
s3 += 1
if s3 > s2:
error=1
if s1+s5 < s4:
s6 = s4-s5-s1
s3 += s6
else:
error = 1
for num in range(n,len(s)):
if s[num]=="(" :
s2 += 1
elif s[num]==")":
s3 += 1
if s3 > s2:
error=1
if error == 1:
print(-1)
else:
while s1>0:
print(1)
s1-=1
print(s6)
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Malek has recently found a treasure map. While he was looking for a treasure he found a locked door. There was a string s written on the door consisting of characters '(', ')' and '#'. Below there was a manual on how to open the door. After spending a long time Malek managed to decode the manual and found out that the goal is to replace each '#' with one or more ')' characters so that the final string becomes beautiful.
Below there was also written that a string is called beautiful if for each i (1 ≤ i ≤ |s|) there are no more ')' characters than '(' characters among the first i characters of s and also the total number of '(' characters is equal to the total number of ')' characters.
Help Malek open the door by telling him for each '#' character how many ')' characters he must replace it with.
Input
The first line of the input contains a string s (1 ≤ |s| ≤ 105). Each character of this string is one of the characters '(', ')' or '#'. It is guaranteed that s contains at least one '#' character.
Output
If there is no way of replacing '#' characters which leads to a beautiful string print - 1. Otherwise for each character '#' print a separate line containing a positive integer, the number of ')' characters this character must be replaced with.
If there are several possible answers, you may output any of them.
Examples
Input
(((#)((#)
Output
1
2
Input
()((#((#(#()
Output
2
2
1
Input
#
Output
-1
Input
(#)
Output
-1
Note
|s| denotes the length of the string s.
Submitted Solution:
```
s = input()
last = s.rfind('#')
dif = s.count('(')-s.count(')')-s.count('#')
try:
assert dif >= 0
lev = 0
out = []
for i in range(len(s)):
c = s[i]
if c == '(': lev += 1
elif c == ')':
lev -= 1
assert lev >= 0
elif c == '#':
lev -= 1
if i == last:
out.append(dif+1)
lev -= dif
else:
out.append(1)
assert lev >= 0
assert lev == 0
for x in out: print(x)
except AssertionError:
print(-1)
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Malek has recently found a treasure map. While he was looking for a treasure he found a locked door. There was a string s written on the door consisting of characters '(', ')' and '#'. Below there was a manual on how to open the door. After spending a long time Malek managed to decode the manual and found out that the goal is to replace each '#' with one or more ')' characters so that the final string becomes beautiful.
Below there was also written that a string is called beautiful if for each i (1 ≤ i ≤ |s|) there are no more ')' characters than '(' characters among the first i characters of s and also the total number of '(' characters is equal to the total number of ')' characters.
Help Malek open the door by telling him for each '#' character how many ')' characters he must replace it with.
Input
The first line of the input contains a string s (1 ≤ |s| ≤ 105). Each character of this string is one of the characters '(', ')' or '#'. It is guaranteed that s contains at least one '#' character.
Output
If there is no way of replacing '#' characters which leads to a beautiful string print - 1. Otherwise for each character '#' print a separate line containing a positive integer, the number of ')' characters this character must be replaced with.
If there are several possible answers, you may output any of them.
Examples
Input
(((#)((#)
Output
1
2
Input
()((#((#(#()
Output
2
2
1
Input
#
Output
-1
Input
(#)
Output
-1
Note
|s| denotes the length of the string s.
Submitted Solution:
```
#!/usr/bin/env python
txt = input()
hli = txt.rfind('#')
fail = False
def check(s,e):
return 0
sc1 = 0
for i in range(0,hli):
if txt[i] == '(':
sc1 += 1
else:
sc1 -= 1
if sc1 < 0:
fail = True
break
sc2 = 0
if not fail:
for i in range(len(txt)-1,hli,-1):
if txt[i] == ')':
sc2 += 1
else:
sc2 -= 1
if sc2 < 0:
fail = True
break
if fail or (sc1-sc2<1):
print(-1)
else:
for i in range(txt.count('#')-1):
print(1)
print(sc1-sc2)
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Malek has recently found a treasure map. While he was looking for a treasure he found a locked door. There was a string s written on the door consisting of characters '(', ')' and '#'. Below there was a manual on how to open the door. After spending a long time Malek managed to decode the manual and found out that the goal is to replace each '#' with one or more ')' characters so that the final string becomes beautiful.
Below there was also written that a string is called beautiful if for each i (1 ≤ i ≤ |s|) there are no more ')' characters than '(' characters among the first i characters of s and also the total number of '(' characters is equal to the total number of ')' characters.
Help Malek open the door by telling him for each '#' character how many ')' characters he must replace it with.
Input
The first line of the input contains a string s (1 ≤ |s| ≤ 105). Each character of this string is one of the characters '(', ')' or '#'. It is guaranteed that s contains at least one '#' character.
Output
If there is no way of replacing '#' characters which leads to a beautiful string print - 1. Otherwise for each character '#' print a separate line containing a positive integer, the number of ')' characters this character must be replaced with.
If there are several possible answers, you may output any of them.
Examples
Input
(((#)((#)
Output
1
2
Input
()((#((#(#()
Output
2
2
1
Input
#
Output
-1
Input
(#)
Output
-1
Note
|s| denotes the length of the string s.
Submitted Solution:
```
x=input()
c=0
d=0
for i in x:
if i=='(':
c+=1
if i==')':
c-=1
if i=='#':
d+=1
if (c<=0) or (d>c) :
print(-1)
else :
y=0
flag=True
dd=d
cc=c
for i in x:
if(y<0):
flag=False
break
if i=='(':
y+=1
if i==')':
y-=1
if i=='#':
if dd>1:
dd-=1
cc-=1
y-=1
else :
y-=cc
if(flag):
while d>1:
print (1)
d-=1
c-=1
print(c)
else:
print(-1)
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Malek has recently found a treasure map. While he was looking for a treasure he found a locked door. There was a string s written on the door consisting of characters '(', ')' and '#'. Below there was a manual on how to open the door. After spending a long time Malek managed to decode the manual and found out that the goal is to replace each '#' with one or more ')' characters so that the final string becomes beautiful.
Below there was also written that a string is called beautiful if for each i (1 ≤ i ≤ |s|) there are no more ')' characters than '(' characters among the first i characters of s and also the total number of '(' characters is equal to the total number of ')' characters.
Help Malek open the door by telling him for each '#' character how many ')' characters he must replace it with.
Input
The first line of the input contains a string s (1 ≤ |s| ≤ 105). Each character of this string is one of the characters '(', ')' or '#'. It is guaranteed that s contains at least one '#' character.
Output
If there is no way of replacing '#' characters which leads to a beautiful string print - 1. Otherwise for each character '#' print a separate line containing a positive integer, the number of ')' characters this character must be replaced with.
If there are several possible answers, you may output any of them.
Examples
Input
(((#)((#)
Output
1
2
Input
()((#((#(#()
Output
2
2
1
Input
#
Output
-1
Input
(#)
Output
-1
Note
|s| denotes the length of the string s.
Submitted Solution:
```
x=input()
c=0
d=0
for i in x:
if i=='(':
c+=1
if i==')':
c-=1
if i=='#':
d+=1
if (c<=0) or (d>c) :
print(-1)
else :
y=0
flag=True
dd=d
cc=c
for i in x:
if(y<0):
flag=False
break
if i=='(':
y+=1
if i==')':
y-=1
if i=='#':
while dd>1:
dd-=1
cc-=1
y-=1
y-=c
if(flag):
while d>1:
print (1)
d-=1
c-=1
print(c)
else:
print(-1)
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Malek has recently found a treasure map. While he was looking for a treasure he found a locked door. There was a string s written on the door consisting of characters '(', ')' and '#'. Below there was a manual on how to open the door. After spending a long time Malek managed to decode the manual and found out that the goal is to replace each '#' with one or more ')' characters so that the final string becomes beautiful.
Below there was also written that a string is called beautiful if for each i (1 ≤ i ≤ |s|) there are no more ')' characters than '(' characters among the first i characters of s and also the total number of '(' characters is equal to the total number of ')' characters.
Help Malek open the door by telling him for each '#' character how many ')' characters he must replace it with.
Input
The first line of the input contains a string s (1 ≤ |s| ≤ 105). Each character of this string is one of the characters '(', ')' or '#'. It is guaranteed that s contains at least one '#' character.
Output
If there is no way of replacing '#' characters which leads to a beautiful string print - 1. Otherwise for each character '#' print a separate line containing a positive integer, the number of ')' characters this character must be replaced with.
If there are several possible answers, you may output any of them.
Examples
Input
(((#)((#)
Output
1
2
Input
()((#((#(#()
Output
2
2
1
Input
#
Output
-1
Input
(#)
Output
-1
Note
|s| denotes the length of the string s.
Submitted Solution:
```
s=input()
l=[]
c=0
c1=0
c2=0
x=0
y=0
for i in s:
if(i=='('):
c1+=1
elif(i==')'):
c2+=1
if(c1==c2 or c1<c2):
print(-1)
else:
for i in s:
if(x>y):
y=y+1
continue
x=x+1
y+=1
if(i=='('):
c+=1
elif(i==')'):
c-=1
elif(i=='#' and x==len(s)):
l.append(c)
break
elif(i=='#'):
while(s[x]==')'):
c-=1
x+=1
if(x==len(s)):
break
l.append(c)
c=0
for i in l:
print(i)
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Malek has recently found a treasure map. While he was looking for a treasure he found a locked door. There was a string s written on the door consisting of characters '(', ')' and '#'. Below there was a manual on how to open the door. After spending a long time Malek managed to decode the manual and found out that the goal is to replace each '#' with one or more ')' characters so that the final string becomes beautiful.
Below there was also written that a string is called beautiful if for each i (1 ≤ i ≤ |s|) there are no more ')' characters than '(' characters among the first i characters of s and also the total number of '(' characters is equal to the total number of ')' characters.
Help Malek open the door by telling him for each '#' character how many ')' characters he must replace it with.
Input
The first line of the input contains a string s (1 ≤ |s| ≤ 105). Each character of this string is one of the characters '(', ')' or '#'. It is guaranteed that s contains at least one '#' character.
Output
If there is no way of replacing '#' characters which leads to a beautiful string print - 1. Otherwise for each character '#' print a separate line containing a positive integer, the number of ')' characters this character must be replaced with.
If there are several possible answers, you may output any of them.
Examples
Input
(((#)((#)
Output
1
2
Input
()((#((#(#()
Output
2
2
1
Input
#
Output
-1
Input
(#)
Output
-1
Note
|s| denotes the length of the string s.
Submitted Solution:
```
s=input()
lis=[0 for i in range(len(s))]
lis1=[]
for i in range(len(s)):
if s[i]=='(':
lis[i]=1
if s[i]==')':
lis[i]=-1
if s[i]=="#":
lis[i]=0
lis1.append(i)
def check(lis):
if sum(lis)>=0:
return 1
else:
return 0
if sum(lis)<=0:
print(-1)
else:
n=sum(lis)
if n<len(lis1):
print(-1)
else:
for i in range(len(lis1)-1):
lis[lis1[i]]=-1
lis[lis1[len(lis1)-1]]=n+1-len(lis1)
lis2=[lis[0]]
c=1
for i in range(1,len(lis)):
lis2.append(lis[i]+lis2[i-1])
if lis2[i]<0:
c=0
break
if c==0:
print(-1)
else:
for i in range(len(lis1)-1):
print(1)
print(n+1-len(lis1))
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Malek has recently found a treasure map. While he was looking for a treasure he found a locked door. There was a string s written on the door consisting of characters '(', ')' and '#'. Below there was a manual on how to open the door. After spending a long time Malek managed to decode the manual and found out that the goal is to replace each '#' with one or more ')' characters so that the final string becomes beautiful.
Below there was also written that a string is called beautiful if for each i (1 ≤ i ≤ |s|) there are no more ')' characters than '(' characters among the first i characters of s and also the total number of '(' characters is equal to the total number of ')' characters.
Help Malek open the door by telling him for each '#' character how many ')' characters he must replace it with.
Input
The first line of the input contains a string s (1 ≤ |s| ≤ 105). Each character of this string is one of the characters '(', ')' or '#'. It is guaranteed that s contains at least one '#' character.
Output
If there is no way of replacing '#' characters which leads to a beautiful string print - 1. Otherwise for each character '#' print a separate line containing a positive integer, the number of ')' characters this character must be replaced with.
If there are several possible answers, you may output any of them.
Examples
Input
(((#)((#)
Output
1
2
Input
()((#((#(#()
Output
2
2
1
Input
#
Output
-1
Input
(#)
Output
-1
Note
|s| denotes the length of the string s.
Submitted Solution:
```
s=input()
a=0
ans=''
c=1
c1=s.count('#')
for i in s:
if(i=='#'):
ans+=')'
else:
ans+=i
for i in ans:
if(i=='('):
a+=1
else:
a-=1
if(a<0):
c=0
break
if(c==0):
print(-1)
elif(a!=0):
print(-1)
else:
c2=ans.count('(')
c3=ans.count(')')
for i in range(c1-1):
print(1)
print(c2-c3+1)
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have multiset of n strings of the same length, consisting of lowercase English letters. We will say that those strings are easy to remember if for each string there is some position i and some letter c of the English alphabet, such that this string is the only string in the multiset that has letter c in position i.
For example, a multiset of strings {"abc", "aba", "adc", "ada"} are not easy to remember. And multiset {"abc", "ada", "ssa"} is easy to remember because:
* the first string is the only string that has character c in position 3;
* the second string is the only string that has character d in position 2;
* the third string is the only string that has character s in position 2.
You want to change your multiset a little so that it is easy to remember. For aij coins, you can change character in the j-th position of the i-th string into any other lowercase letter of the English alphabet. Find what is the minimum sum you should pay in order to make the multiset of strings easy to remember.
Input
The first line contains two integers n, m (1 ≤ n, m ≤ 20) — the number of strings in the multiset and the length of the strings respectively. Next n lines contain the strings of the multiset, consisting only of lowercase English letters, each string's length is m.
Next n lines contain m integers each, the i-th of them contains integers ai1, ai2, ..., aim (0 ≤ aij ≤ 106).
Output
Print a single number — the answer to the problem.
Examples
Input
4 5
abcde
abcde
abcde
abcde
1 1 1 1 1
1 1 1 1 1
1 1 1 1 1
1 1 1 1 1
Output
3
Input
4 3
abc
aba
adc
ada
10 10 10
10 1 10
10 10 10
10 1 10
Output
2
Input
3 3
abc
ada
ssa
1 1 1
1 1 1
1 1 1
Output
0
Submitted Solution:
```
from sys import stdin
n,m=map(int,stdin.readline().strip().split())
s=[]
for i in range(n):
s.append(list(map(ord,list(stdin.readline().strip()))))
for j in range(m):
s[-1][j]=s[-1][j]-97
mn=[min(tuple(map(int,stdin.readline().strip().split()))) for i in range(n)]
maxmask=2**n
dp=[0 for i in range(26)]
ans=10**9
for i in range(maxmask):
aux=[]
t=0
for j in range(n):
if i & (1<<j):
aux.append(j)
else:
t+=mn[j]
aux1=aux.copy()
for j in range(m):
for k in aux:
dp[s[k][j]]+=1
for k in aux:
if dp[s[k][j]]==1:
aux.remove(k)
dp=[0 for i in range(26)]
if len(aux)==0:
if t<ans:
ans=t
print(ans)
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have multiset of n strings of the same length, consisting of lowercase English letters. We will say that those strings are easy to remember if for each string there is some position i and some letter c of the English alphabet, such that this string is the only string in the multiset that has letter c in position i.
For example, a multiset of strings {"abc", "aba", "adc", "ada"} are not easy to remember. And multiset {"abc", "ada", "ssa"} is easy to remember because:
* the first string is the only string that has character c in position 3;
* the second string is the only string that has character d in position 2;
* the third string is the only string that has character s in position 2.
You want to change your multiset a little so that it is easy to remember. For aij coins, you can change character in the j-th position of the i-th string into any other lowercase letter of the English alphabet. Find what is the minimum sum you should pay in order to make the multiset of strings easy to remember.
Input
The first line contains two integers n, m (1 ≤ n, m ≤ 20) — the number of strings in the multiset and the length of the strings respectively. Next n lines contain the strings of the multiset, consisting only of lowercase English letters, each string's length is m.
Next n lines contain m integers each, the i-th of them contains integers ai1, ai2, ..., aim (0 ≤ aij ≤ 106).
Output
Print a single number — the answer to the problem.
Examples
Input
4 5
abcde
abcde
abcde
abcde
1 1 1 1 1
1 1 1 1 1
1 1 1 1 1
1 1 1 1 1
Output
3
Input
4 3
abc
aba
adc
ada
10 10 10
10 1 10
10 10 10
10 1 10
Output
2
Input
3 3
abc
ada
ssa
1 1 1
1 1 1
1 1 1
Output
0
Submitted Solution:
```
# from copy import deepcopy
size = [int(x) for x in input().split(" ")]
n = size[0]
m = size[1]
inputs = []
for i in range(0, n):
inputs.append(input())
def check(arr):
for num in arr:
if all(i > 1 for i in num):
return False
return True
arr = []
for i in range(0, m):
arr.append({})
for j in range(0, n):
if inputs[j][i] in arr[i]:
arr[i][inputs[j][i]] += 1
else:
arr[i][inputs[j][i]] = 1
coins = []
count_arr = []
for i in range(0, n):
cost = input().split(" ")
cost = [int(x) for x in cost]
count_arr.append([arr[j][inputs[i][j]] for j in range(0, m)])
coins.append(cost)
cost_arr = []
for i in range(0, n):
summ_arr = []
for j in range(0, m):
z = 0
summ = float(0)
summ_arr.append(coins[i][j])
for k in range(0, n):
if k == i:
z += 1
continue
if z == count_arr[i][j]:
break
if inputs[k][j] == inputs[i][j]:
summ += float(coins[k][j])
z += 1
summ_arr.append(summ)
cost_arr.append(summ_arr)
def modify_count_arr(arr, index, min_index):
arr[index][min_index] = 1
for i in range(0,n):
if index == i: continue
if inputs[i][min_index] == inputs[index][min_index]:
arr[i][min_index] -= 1
# min_cost = []
out = 0
done = []
for i in range(0, n):
if check(count_arr): break
min_num = min(cost_arr[i])
min_index = int(cost_arr[i].index(min_num) / 2)
# min_cost.append((min_num, min_index))
if cost_arr[i].index(min_num) % 2 == 0:
if (i, inputs[i][min_index]) in done: continue
out += min_num
done.append((i, inputs[i][min_index]))
# count_arr[i][min_index] = 1
modify_count_arr(count_arr, i, min_index)
elif min_num != 0:
for j in range(0, n):
if (j, inputs[j][min_index]) in done or j == i: continue
if inputs[i][min_index] == inputs[j][min_index]:
out += coins[j][min_index]
done.append((j, inputs[j][min_index]))
# count_arr[j][min_index] = 1
modify_count_arr(count_arr, i, min_index)
# print(count_arr)
# print(cost_arr)
print(out)
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have multiset of n strings of the same length, consisting of lowercase English letters. We will say that those strings are easy to remember if for each string there is some position i and some letter c of the English alphabet, such that this string is the only string in the multiset that has letter c in position i.
For example, a multiset of strings {"abc", "aba", "adc", "ada"} are not easy to remember. And multiset {"abc", "ada", "ssa"} is easy to remember because:
* the first string is the only string that has character c in position 3;
* the second string is the only string that has character d in position 2;
* the third string is the only string that has character s in position 2.
You want to change your multiset a little so that it is easy to remember. For aij coins, you can change character in the j-th position of the i-th string into any other lowercase letter of the English alphabet. Find what is the minimum sum you should pay in order to make the multiset of strings easy to remember.
Input
The first line contains two integers n, m (1 ≤ n, m ≤ 20) — the number of strings in the multiset and the length of the strings respectively. Next n lines contain the strings of the multiset, consisting only of lowercase English letters, each string's length is m.
Next n lines contain m integers each, the i-th of them contains integers ai1, ai2, ..., aim (0 ≤ aij ≤ 106).
Output
Print a single number — the answer to the problem.
Examples
Input
4 5
abcde
abcde
abcde
abcde
1 1 1 1 1
1 1 1 1 1
1 1 1 1 1
1 1 1 1 1
Output
3
Input
4 3
abc
aba
adc
ada
10 10 10
10 1 10
10 10 10
10 1 10
Output
2
Input
3 3
abc
ada
ssa
1 1 1
1 1 1
1 1 1
Output
0
Submitted Solution:
```
# from copy import deepcopy
size = [int(x) for x in input().split(" ")]
n = size[0]
m = size[1]
inputs = []
for i in range(0, n):
inputs.append(input())
def check(arr):
for num in arr:
if all(i > 1 for i in num):
return False
return True
arr = []
for i in range(0, m):
arr.append({})
for j in range(0, n):
if inputs[j][i] in arr[i]:
arr[i][inputs[j][i]] += 1
else:
arr[i][inputs[j][i]] = 1
coins = []
count_arr = []
for i in range(0, n):
cost = input().split(" ")
cost = [int(x) for x in cost]
count_arr.append([arr[j][inputs[i][j]] for j in range(0, m)])
coins.append(cost)
cost_arr = []
for i in range(0, n):
summ_arr = []
for j in range(0, m):
z = 0
summ = float(0)
summ_arr.append(coins[i][j])
for k in range(0, n):
if k == i:
z += 1
continue
if z == count_arr[i][j]:
break
if inputs[k][j] == inputs[i][j]:
summ += float(coins[k][j])
z += 1
summ_arr.append(summ)
cost_arr.append(summ_arr)
def modify_count_arr(arr, index, min_index):
arr[index][min_index] = 1
for i in range(0,n):
if index == i: continue
if inputs[i][min_index] == inputs[index][min_index]:
arr[i][min_index] -= 1
# min_cost = []
out = 0
done = []
for i in range(0, n):
if check(count_arr): break
min_num = min(cost_arr[i])
min_index = int(cost_arr[i].index(min_num) / 2)
# min_cost.append((min_num, min_index))
if count_arr[i][min_index] == 1: continue
if cost_arr[i].index(min_num) % 2 == 0:
# print(min_num)
if (i, min_index, inputs[i][min_index]) in done: continue
out += min_num
done.append((i, min_index, inputs[i][min_index]))
# count_arr[i][min_index] = 1
modify_count_arr(count_arr, i, min_index)
elif min_num != 0:
# print(min_num)
for j in range(0, n):
if (j, min_index, inputs[j][min_index]) in done or j == i: continue
if inputs[i][min_index] == inputs[j][min_index]:
out += coins[j][min_index]
done.append((j, min_index, inputs[j][min_index]))
# count_arr[j][min_index] = 1
modify_count_arr(count_arr, i, min_index)
# print(count_arr)
# print(cost_arr)
print(out)
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have multiset of n strings of the same length, consisting of lowercase English letters. We will say that those strings are easy to remember if for each string there is some position i and some letter c of the English alphabet, such that this string is the only string in the multiset that has letter c in position i.
For example, a multiset of strings {"abc", "aba", "adc", "ada"} are not easy to remember. And multiset {"abc", "ada", "ssa"} is easy to remember because:
* the first string is the only string that has character c in position 3;
* the second string is the only string that has character d in position 2;
* the third string is the only string that has character s in position 2.
You want to change your multiset a little so that it is easy to remember. For aij coins, you can change character in the j-th position of the i-th string into any other lowercase letter of the English alphabet. Find what is the minimum sum you should pay in order to make the multiset of strings easy to remember.
Input
The first line contains two integers n, m (1 ≤ n, m ≤ 20) — the number of strings in the multiset and the length of the strings respectively. Next n lines contain the strings of the multiset, consisting only of lowercase English letters, each string's length is m.
Next n lines contain m integers each, the i-th of them contains integers ai1, ai2, ..., aim (0 ≤ aij ≤ 106).
Output
Print a single number — the answer to the problem.
Examples
Input
4 5
abcde
abcde
abcde
abcde
1 1 1 1 1
1 1 1 1 1
1 1 1 1 1
1 1 1 1 1
Output
3
Input
4 3
abc
aba
adc
ada
10 10 10
10 1 10
10 10 10
10 1 10
Output
2
Input
3 3
abc
ada
ssa
1 1 1
1 1 1
1 1 1
Output
0
Submitted Solution:
```
# from copy import deepcopy
size = [int(x) for x in input().split(" ")]
n = size[0]
m = size[1]
inputs = []
for i in range(0, n):
inputs.append(input())
def check(arr):
for num in arr:
if all(i > 1 for i in num):
return False
return True
arr = []
for i in range(0, m):
arr.append({})
for j in range(0, n):
if inputs[j][i] in arr[i]:
arr[i][inputs[j][i]] += 1
else:
arr[i][inputs[j][i]] = 1
coins = []
count_arr = []
for i in range(0, n):
cost = input().split(" ")
cost = [int(x) for x in cost]
count_arr.append([arr[j][inputs[i][j]] for j in range(0, m)])
coins.append(cost)
cost_arr = []
for i in range(0, n):
summ_arr = []
for j in range(0, m):
z = 0
summ = float(0)
summ_arr.append(coins[i][j])
for k in range(0, n):
if k == i:
z += 1
continue
if z == count_arr[i][j]:
break
if inputs[k][j] == inputs[i][j]:
summ += float(coins[k][j])
z += 1
summ_arr.append(summ)
cost_arr.append(summ_arr)
def modify_count_arr(arr, index, min_index):
arr[index][min_index] = 1
for i in range(0,n):
if index == i: continue
if inputs[i][min_index] == inputs[index][min_index]:
arr[i][min_index] -= 1
# min_cost = []
out = 0
done = []
for i in range(0, n):
if check(count_arr): break
min_num = min(cost_arr[i])
min_index = int(cost_arr[i].index(min_num) / 2)
# min_cost.append((min_num, min_index))
if count_arr[i][min_index] == 1: continue
if cost_arr[i].index(min_num) % 2 == 0:
# print(min_num)
if (i, inputs[i][min_index]) in done: continue
out += min_num
done.append((i, inputs[i][min_index]))
# count_arr[i][min_index] = 1
modify_count_arr(count_arr, i, min_index)
elif min_num != 0:
# print(min_num)
for j in range(0, n):
if (j, inputs[j][min_index]) in done or j == i: continue
if inputs[i][min_index] == inputs[j][min_index]:
out += coins[j][min_index]
done.append((j, inputs[j][min_index]))
# count_arr[j][min_index] = 1
modify_count_arr(count_arr, i, min_index)
# print(count_arr)
# print(cost_arr)
print(out)
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Stepan likes to repeat vowel letters when he writes words. For example, instead of the word "pobeda" he can write "pobeeeedaaaaa".
Sergey does not like such behavior, so he wants to write a program to format the words written by Stepan. This program must combine all consecutive equal vowels to a single vowel. The vowel letters are "a", "e", "i", "o", "u" and "y".
There are exceptions: if letters "e" or "o" repeat in a row exactly 2 times, like in words "feet" and "foot", the program must skip them and do not transform in one vowel. For example, the word "iiiimpleeemeentatiioon" must be converted to the word "implemeentatioon".
Sergey is very busy and asks you to help him and write the required program.
Input
The first line contains the integer n (1 ≤ n ≤ 100 000) — the number of letters in the word written by Stepan.
The second line contains the string s which has length that equals to n and contains only lowercase English letters — the word written by Stepan.
Output
Print the single string — the word written by Stepan converted according to the rules described in the statement.
Examples
Input
13
pobeeeedaaaaa
Output
pobeda
Input
22
iiiimpleeemeentatiioon
Output
implemeentatioon
Input
18
aeiouyaaeeiioouuyy
Output
aeiouyaeeioouy
Input
24
aaaoooiiiuuuyyyeeeggghhh
Output
aoiuyeggghhh
Submitted Solution:
```
# coding: utf-8
# In[21]:
odd = input()
s = input()
res = ""
vows = "aeiouy"
e = "eo"
a = []
pr = '@'
for ch in s:
if pr == ch:
a[-1] += ch
else:
a.append(str(ch))
pr = ch
for g in a:
if len(g) == 1 or len(g) == 2 and g[0] in e or g[0] not in vows:
res += g
else:
res += g[0]
print(res)
# In[ ]:
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Stepan likes to repeat vowel letters when he writes words. For example, instead of the word "pobeda" he can write "pobeeeedaaaaa".
Sergey does not like such behavior, so he wants to write a program to format the words written by Stepan. This program must combine all consecutive equal vowels to a single vowel. The vowel letters are "a", "e", "i", "o", "u" and "y".
There are exceptions: if letters "e" or "o" repeat in a row exactly 2 times, like in words "feet" and "foot", the program must skip them and do not transform in one vowel. For example, the word "iiiimpleeemeentatiioon" must be converted to the word "implemeentatioon".
Sergey is very busy and asks you to help him and write the required program.
Input
The first line contains the integer n (1 ≤ n ≤ 100 000) — the number of letters in the word written by Stepan.
The second line contains the string s which has length that equals to n and contains only lowercase English letters — the word written by Stepan.
Output
Print the single string — the word written by Stepan converted according to the rules described in the statement.
Examples
Input
13
pobeeeedaaaaa
Output
pobeda
Input
22
iiiimpleeemeentatiioon
Output
implemeentatioon
Input
18
aeiouyaaeeiioouuyy
Output
aeiouyaeeioouy
Input
24
aaaoooiiiuuuyyyeeeggghhh
Output
aoiuyeggghhh
Submitted Solution:
```
n = int(input())
s = input()
ar = []
gl= [ 'a', 'e', 'i','o', 'u', 'y' ]
i = 0
while i < len(s):
it = False
if (s[i] in gl):
it = True
if (it):
cnt = 0;
c = s[i];
j = i;
while (j < len(s) and s[j] == s[i]):
cnt += 1;
j += 1;
if ((s[i] == 'e' or s[i] == 'o') and j - i == 2):
ar.append(s[i]);
ar.append(s[i]);
else:
ar.append(s[i]);
i = j;
else:
ar.append(s[i]);
i += 1;
print(''.join(ar))
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Stepan likes to repeat vowel letters when he writes words. For example, instead of the word "pobeda" he can write "pobeeeedaaaaa".
Sergey does not like such behavior, so he wants to write a program to format the words written by Stepan. This program must combine all consecutive equal vowels to a single vowel. The vowel letters are "a", "e", "i", "o", "u" and "y".
There are exceptions: if letters "e" or "o" repeat in a row exactly 2 times, like in words "feet" and "foot", the program must skip them and do not transform in one vowel. For example, the word "iiiimpleeemeentatiioon" must be converted to the word "implemeentatioon".
Sergey is very busy and asks you to help him and write the required program.
Input
The first line contains the integer n (1 ≤ n ≤ 100 000) — the number of letters in the word written by Stepan.
The second line contains the string s which has length that equals to n and contains only lowercase English letters — the word written by Stepan.
Output
Print the single string — the word written by Stepan converted according to the rules described in the statement.
Examples
Input
13
pobeeeedaaaaa
Output
pobeda
Input
22
iiiimpleeemeentatiioon
Output
implemeentatioon
Input
18
aeiouyaaeeiioouuyy
Output
aeiouyaeeioouy
Input
24
aaaoooiiiuuuyyyeeeggghhh
Output
aoiuyeggghhh
Submitted Solution:
```
n = int(input())
s = list(input())
ans = ''
vowels = ['a', 'e', 'i', 'o', 'u', 'y']
prev = ''
eo = False
for i in range(0, s.__len__()):
if s[i] in vowels:
if s[i] != prev:
ans += s[i]
eo = False
elif not eo:
if i != s.__len__() - 1:
if prev == s[i] == 'e' and s[i + 1] == 'e' or prev == s[i] == 'o' and s[i + 1] == 'o':
eo = True
elif prev == s[i] == 'e' and s[i + 1] != 'e' or prev == s[i] == 'o' and s[i + 1] != 'o':
eo = True
ans += prev
else:
if prev == s[i] == 'e' or prev == s[i] == 'o':
ans += prev
else:
eo = False
ans += s[i]
prev = s[i]
print(ans)
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Stepan likes to repeat vowel letters when he writes words. For example, instead of the word "pobeda" he can write "pobeeeedaaaaa".
Sergey does not like such behavior, so he wants to write a program to format the words written by Stepan. This program must combine all consecutive equal vowels to a single vowel. The vowel letters are "a", "e", "i", "o", "u" and "y".
There are exceptions: if letters "e" or "o" repeat in a row exactly 2 times, like in words "feet" and "foot", the program must skip them and do not transform in one vowel. For example, the word "iiiimpleeemeentatiioon" must be converted to the word "implemeentatioon".
Sergey is very busy and asks you to help him and write the required program.
Input
The first line contains the integer n (1 ≤ n ≤ 100 000) — the number of letters in the word written by Stepan.
The second line contains the string s which has length that equals to n and contains only lowercase English letters — the word written by Stepan.
Output
Print the single string — the word written by Stepan converted according to the rules described in the statement.
Examples
Input
13
pobeeeedaaaaa
Output
pobeda
Input
22
iiiimpleeemeentatiioon
Output
implemeentatioon
Input
18
aeiouyaaeeiioouuyy
Output
aeiouyaeeioouy
Input
24
aaaoooiiiuuuyyyeeeggghhh
Output
aoiuyeggghhh
Submitted Solution:
```
def end(r, curr_s, curr_l):
if curr_l == 0:
return
if (curr_s == "o" or curr_s == "e") and curr_l == 2:
r.append(curr_s * 2)
else:
r.append(curr_s)
def main():
n = int(input())
s = input()
glasnie = "aeiouy"
curr_s = ""
curr_l = 0
r = []
for e in s:
if e in glasnie:
if e != curr_s:
end(r, curr_s, curr_l)
curr_s = e
curr_l = 1
else:
curr_l += 1
else:
end(r, curr_s, curr_l)
r.append(e)
curr_s = ""
curr_l = 0
end(r, curr_s, curr_l)
print("".join(r))
if __name__ == "__main__":
main()
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Stepan likes to repeat vowel letters when he writes words. For example, instead of the word "pobeda" he can write "pobeeeedaaaaa".
Sergey does not like such behavior, so he wants to write a program to format the words written by Stepan. This program must combine all consecutive equal vowels to a single vowel. The vowel letters are "a", "e", "i", "o", "u" and "y".
There are exceptions: if letters "e" or "o" repeat in a row exactly 2 times, like in words "feet" and "foot", the program must skip them and do not transform in one vowel. For example, the word "iiiimpleeemeentatiioon" must be converted to the word "implemeentatioon".
Sergey is very busy and asks you to help him and write the required program.
Input
The first line contains the integer n (1 ≤ n ≤ 100 000) — the number of letters in the word written by Stepan.
The second line contains the string s which has length that equals to n and contains only lowercase English letters — the word written by Stepan.
Output
Print the single string — the word written by Stepan converted according to the rules described in the statement.
Examples
Input
13
pobeeeedaaaaa
Output
pobeda
Input
22
iiiimpleeemeentatiioon
Output
implemeentatioon
Input
18
aeiouyaaeeiioouuyy
Output
aeiouyaeeioouy
Input
24
aaaoooiiiuuuyyyeeeggghhh
Output
aoiuyeggghhh
Submitted Solution:
```
n = int(input())
s = input()
print(s[0], end = '')
for i in range(1, len(s)):
if not(s[i - 1] == s[i] == 'a' or s[i - 1] == s[i] == 'i' or s[i - 1] == s[i] == 'u' or s[i - 1] == s[i] == 'y'):
if i >= 2 and (i < len(s) - 1 and (s[i - 2] != s[i - 1] == s[i] == 'e' != s[i + 1] or s[i - 2] != s[i - 1] == s[i] == 'o' != s[i + 1]) or i == len(s) - 1 and (s[i - 2] != s[i - 1] == s[i] == 'e' or s[i - 2] != s[i - 1] == s[i] == 'o')) or i == 2 and (i < len(s) - 1 and (s[i - 1] == s[i] == 'e' != s[i + 1] or s[i - 1] == s[i] == 'o' != s[i + 1]) or i == len(s) - 1 and (s[i - 1] == s[i] == 'e' or s[i - 1] == s[i] == 'o')):
print(s[i], end = '')
elif not(s[i - 1] == s[i] == 'e' or s[i - 1] == s[i] == 'o'):
print(s[i], end = '')
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Stepan likes to repeat vowel letters when he writes words. For example, instead of the word "pobeda" he can write "pobeeeedaaaaa".
Sergey does not like such behavior, so he wants to write a program to format the words written by Stepan. This program must combine all consecutive equal vowels to a single vowel. The vowel letters are "a", "e", "i", "o", "u" and "y".
There are exceptions: if letters "e" or "o" repeat in a row exactly 2 times, like in words "feet" and "foot", the program must skip them and do not transform in one vowel. For example, the word "iiiimpleeemeentatiioon" must be converted to the word "implemeentatioon".
Sergey is very busy and asks you to help him and write the required program.
Input
The first line contains the integer n (1 ≤ n ≤ 100 000) — the number of letters in the word written by Stepan.
The second line contains the string s which has length that equals to n and contains only lowercase English letters — the word written by Stepan.
Output
Print the single string — the word written by Stepan converted according to the rules described in the statement.
Examples
Input
13
pobeeeedaaaaa
Output
pobeda
Input
22
iiiimpleeemeentatiioon
Output
implemeentatioon
Input
18
aeiouyaaeeiioouuyy
Output
aeiouyaeeioouy
Input
24
aaaoooiiiuuuyyyeeeggghhh
Output
aoiuyeggghhh
Submitted Solution:
```
n = int(input())
s = input()
if len(s)==1:
print(s)
else:
co=0
ce=0
ca=0
cy=0
cu=0
ci=0
r=''
s+='0'
if s[0]!=s[1]:
r+=s[0]
if s[0]=='e':
ce+=1
if s[0]=='a':
ca+=1
if s[0]=='o':
co+=1
if s[0]=='i':
ci+=1
if s[0]=='y':
cy+=1
if s[0]=='u':
cu+=1
for i in range(1, len(s)-1):
p = True
p1 = False
if s[i]=='o':
p=False
co+=1
p = co==1 and s[i+1]!='o'
if p==False:
p= co>2 and s[i+1]!='o'
if p==False:
p1 = co==2 and s[i+1]!='o'
else:
co=0
if s[i]=='e':
p=False
ce+=1
p = ce==1 and s[i+1]!='e'
if p==False:
p= ce>2 and s[i+1]!='e'
if p==False:
p1 = ce==2 and s[i+1]!='e'
else:
ce=0
if s[i]=='a':
ca+=1
p=ca==1
else:
ca=0
if s[i]=='u':
cu+=1
p=cu==1
else:
cu=0
if s[i]=='i':
ci+=1
p=ci==1
else:
ci=0
if s[i]=='y':
cy+=1
p=cy==1
else:
cy=0
if p1:
r+=s[i]+s[i]
if p:
r+=s[i]
print(r)
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Stepan likes to repeat vowel letters when he writes words. For example, instead of the word "pobeda" he can write "pobeeeedaaaaa".
Sergey does not like such behavior, so he wants to write a program to format the words written by Stepan. This program must combine all consecutive equal vowels to a single vowel. The vowel letters are "a", "e", "i", "o", "u" and "y".
There are exceptions: if letters "e" or "o" repeat in a row exactly 2 times, like in words "feet" and "foot", the program must skip them and do not transform in one vowel. For example, the word "iiiimpleeemeentatiioon" must be converted to the word "implemeentatioon".
Sergey is very busy and asks you to help him and write the required program.
Input
The first line contains the integer n (1 ≤ n ≤ 100 000) — the number of letters in the word written by Stepan.
The second line contains the string s which has length that equals to n and contains only lowercase English letters — the word written by Stepan.
Output
Print the single string — the word written by Stepan converted according to the rules described in the statement.
Examples
Input
13
pobeeeedaaaaa
Output
pobeda
Input
22
iiiimpleeemeentatiioon
Output
implemeentatioon
Input
18
aeiouyaaeeiioouuyy
Output
aeiouyaeeioouy
Input
24
aaaoooiiiuuuyyyeeeggghhh
Output
aoiuyeggghhh
Submitted Solution:
```
# your code goes here
from sys import stdin
line = stdin.readline()
line = stdin.readline()
i = 0
ans = ""
while i<len(line):
if (i==0 or line[i] != line[i-1] or ((line[i]=='e' or line[i]=='o') and (i < 2 or line[i-1]!=line[i-2]))):
ans = ans + line[i];
i = i + 1;
print(ans)
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Stepan likes to repeat vowel letters when he writes words. For example, instead of the word "pobeda" he can write "pobeeeedaaaaa".
Sergey does not like such behavior, so he wants to write a program to format the words written by Stepan. This program must combine all consecutive equal vowels to a single vowel. The vowel letters are "a", "e", "i", "o", "u" and "y".
There are exceptions: if letters "e" or "o" repeat in a row exactly 2 times, like in words "feet" and "foot", the program must skip them and do not transform in one vowel. For example, the word "iiiimpleeemeentatiioon" must be converted to the word "implemeentatioon".
Sergey is very busy and asks you to help him and write the required program.
Input
The first line contains the integer n (1 ≤ n ≤ 100 000) — the number of letters in the word written by Stepan.
The second line contains the string s which has length that equals to n and contains only lowercase English letters — the word written by Stepan.
Output
Print the single string — the word written by Stepan converted according to the rules described in the statement.
Examples
Input
13
pobeeeedaaaaa
Output
pobeda
Input
22
iiiimpleeemeentatiioon
Output
implemeentatioon
Input
18
aeiouyaaeeiioouuyy
Output
aeiouyaeeioouy
Input
24
aaaoooiiiuuuyyyeeeggghhh
Output
aoiuyeggghhh
Submitted Solution:
```
# your code goes here
from sys import stdin
line = stdin.readline()
line = stdin.readline()
i = 0
ans = ""
while i<len(line):
if (i==0 or line[i] != line[i-1]):
ans = ans + line[i];
i = i + 1;
print(ans)
```
### Response:
| No |
### Instruction:
Provide a correct Python 3 solution for this coding contest problem.
A string is called a KEYENCE string when it can be changed to `keyence` by removing its contiguous substring (possibly empty) only once.
Given a string S consisting of lowercase English letters, determine if S is a KEYENCE string.
Constraints
* The length of S is between 7 and 100 (inclusive).
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a KEYENCE string, print `YES`; otherwise, print `NO`.
Examples
Input
keyofscience
Output
YES
Input
mpyszsbznf
Output
NO
Input
ashlfyha
Output
NO
Input
keyence
Output
YES
### Response:
| "Correct Solution:
```
S = input()
for i in range(1,7):
if S[:i] + S[len(S)-(7-i):] == "keyence":
print("YES")
exit()
print("NO")
``` |
### Instruction:
Provide a correct Python 3 solution for this coding contest problem.
A string is called a KEYENCE string when it can be changed to `keyence` by removing its contiguous substring (possibly empty) only once.
Given a string S consisting of lowercase English letters, determine if S is a KEYENCE string.
Constraints
* The length of S is between 7 and 100 (inclusive).
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a KEYENCE string, print `YES`; otherwise, print `NO`.
Examples
Input
keyofscience
Output
YES
Input
mpyszsbznf
Output
NO
Input
ashlfyha
Output
NO
Input
keyence
Output
YES
### Response:
| "Correct Solution:
```
S = input()
k = "keyence"
n = len(S)-7
for i in range(len(S)-n+1):
if S[:i]+S[i+n:] == k:
print("YES")
break
else:
print("NO")
``` |
### Instruction:
Provide a correct Python 3 solution for this coding contest problem.
A string is called a KEYENCE string when it can be changed to `keyence` by removing its contiguous substring (possibly empty) only once.
Given a string S consisting of lowercase English letters, determine if S is a KEYENCE string.
Constraints
* The length of S is between 7 and 100 (inclusive).
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a KEYENCE string, print `YES`; otherwise, print `NO`.
Examples
Input
keyofscience
Output
YES
Input
mpyszsbznf
Output
NO
Input
ashlfyha
Output
NO
Input
keyence
Output
YES
### Response:
| "Correct Solution:
```
s = input()
for i in range(len(s)) :
for j in range(i,len(s)+1) :
if s[:i]+s[j:] == 'keyence' :
print('YES')
exit()
print('NO')
``` |
### Instruction:
Provide a correct Python 3 solution for this coding contest problem.
A string is called a KEYENCE string when it can be changed to `keyence` by removing its contiguous substring (possibly empty) only once.
Given a string S consisting of lowercase English letters, determine if S is a KEYENCE string.
Constraints
* The length of S is between 7 and 100 (inclusive).
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a KEYENCE string, print `YES`; otherwise, print `NO`.
Examples
Input
keyofscience
Output
YES
Input
mpyszsbznf
Output
NO
Input
ashlfyha
Output
NO
Input
keyence
Output
YES
### Response:
| "Correct Solution:
```
s=input()
n=len(s)
k='keyence'
ans='NO'
for i in range(n):
if s[:i]+s[i+n-7:]==k:
ans='YES'
print(ans)
``` |
### Instruction:
Provide a correct Python 3 solution for this coding contest problem.
A string is called a KEYENCE string when it can be changed to `keyence` by removing its contiguous substring (possibly empty) only once.
Given a string S consisting of lowercase English letters, determine if S is a KEYENCE string.
Constraints
* The length of S is between 7 and 100 (inclusive).
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a KEYENCE string, print `YES`; otherwise, print `NO`.
Examples
Input
keyofscience
Output
YES
Input
mpyszsbznf
Output
NO
Input
ashlfyha
Output
NO
Input
keyence
Output
YES
### Response:
| "Correct Solution:
```
s = input()
print(
"YES" if any(
s[:i] + s[j:] == "keyence"
for i in range(len(s))
for j in range(len(s))
if i <= j) else
"NO"
)
``` |
### Instruction:
Provide a correct Python 3 solution for this coding contest problem.
A string is called a KEYENCE string when it can be changed to `keyence` by removing its contiguous substring (possibly empty) only once.
Given a string S consisting of lowercase English letters, determine if S is a KEYENCE string.
Constraints
* The length of S is between 7 and 100 (inclusive).
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a KEYENCE string, print `YES`; otherwise, print `NO`.
Examples
Input
keyofscience
Output
YES
Input
mpyszsbznf
Output
NO
Input
ashlfyha
Output
NO
Input
keyence
Output
YES
### Response:
| "Correct Solution:
```
S = input()
s = "keyence"
for i in range(len(s)+1):
if S[:i] == s[:i] and S[-len(s)+i:] == s[-len(s)+i:]:
print("YES")
exit()
print("NO")
``` |
### Instruction:
Provide a correct Python 3 solution for this coding contest problem.
A string is called a KEYENCE string when it can be changed to `keyence` by removing its contiguous substring (possibly empty) only once.
Given a string S consisting of lowercase English letters, determine if S is a KEYENCE string.
Constraints
* The length of S is between 7 and 100 (inclusive).
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a KEYENCE string, print `YES`; otherwise, print `NO`.
Examples
Input
keyofscience
Output
YES
Input
mpyszsbznf
Output
NO
Input
ashlfyha
Output
NO
Input
keyence
Output
YES
### Response:
| "Correct Solution:
```
s=input();print('NYOE S'['f'>s[-1]and'ke'in s::2])
``` |
### Instruction:
Provide a correct Python 3 solution for this coding contest problem.
A string is called a KEYENCE string when it can be changed to `keyence` by removing its contiguous substring (possibly empty) only once.
Given a string S consisting of lowercase English letters, determine if S is a KEYENCE string.
Constraints
* The length of S is between 7 and 100 (inclusive).
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a KEYENCE string, print `YES`; otherwise, print `NO`.
Examples
Input
keyofscience
Output
YES
Input
mpyszsbznf
Output
NO
Input
ashlfyha
Output
NO
Input
keyence
Output
YES
### Response:
| "Correct Solution:
```
S=input()
n=len(S)
ans="NO"
for i in range(n):
for j in range(i,n):
if S[:i]+S[j:]=="keyence":
ans="YES"
break
print(ans)
``` |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string is called a KEYENCE string when it can be changed to `keyence` by removing its contiguous substring (possibly empty) only once.
Given a string S consisting of lowercase English letters, determine if S is a KEYENCE string.
Constraints
* The length of S is between 7 and 100 (inclusive).
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a KEYENCE string, print `YES`; otherwise, print `NO`.
Examples
Input
keyofscience
Output
YES
Input
mpyszsbznf
Output
NO
Input
ashlfyha
Output
NO
Input
keyence
Output
YES
Submitted Solution:
```
import sys
s = input()
l = len(s) - 7
for i in range(l+8):
if (s[:i] + s[i+l:]) == 'keyence':
print('YES')
sys.exit()
print('NO')
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string is called a KEYENCE string when it can be changed to `keyence` by removing its contiguous substring (possibly empty) only once.
Given a string S consisting of lowercase English letters, determine if S is a KEYENCE string.
Constraints
* The length of S is between 7 and 100 (inclusive).
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a KEYENCE string, print `YES`; otherwise, print `NO`.
Examples
Input
keyofscience
Output
YES
Input
mpyszsbznf
Output
NO
Input
ashlfyha
Output
NO
Input
keyence
Output
YES
Submitted Solution:
```
s = input()
n = len(s) - 7
for i in range(7):
if s[:i] + s[i+n:] == 'keyence':
print("YES")
exit()
print("NO")
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string is called a KEYENCE string when it can be changed to `keyence` by removing its contiguous substring (possibly empty) only once.
Given a string S consisting of lowercase English letters, determine if S is a KEYENCE string.
Constraints
* The length of S is between 7 and 100 (inclusive).
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a KEYENCE string, print `YES`; otherwise, print `NO`.
Examples
Input
keyofscience
Output
YES
Input
mpyszsbznf
Output
NO
Input
ashlfyha
Output
NO
Input
keyence
Output
YES
Submitted Solution:
```
s=input()
t="keyence"
if s==t:print("YES");exit()
n=len(s)
for i in range(n):
for j in range(i,n):
if s[:i]+s[j+1:]==t:print("YES");exit()
print("NO")
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string is called a KEYENCE string when it can be changed to `keyence` by removing its contiguous substring (possibly empty) only once.
Given a string S consisting of lowercase English letters, determine if S is a KEYENCE string.
Constraints
* The length of S is between 7 and 100 (inclusive).
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a KEYENCE string, print `YES`; otherwise, print `NO`.
Examples
Input
keyofscience
Output
YES
Input
mpyszsbznf
Output
NO
Input
ashlfyha
Output
NO
Input
keyence
Output
YES
Submitted Solution:
```
s = input()
for i in range(8):
temp = s[:i] + s[-7 + i:]
if temp == "keyence":
print("YES")
break
else:
print("NO")
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string is called a KEYENCE string when it can be changed to `keyence` by removing its contiguous substring (possibly empty) only once.
Given a string S consisting of lowercase English letters, determine if S is a KEYENCE string.
Constraints
* The length of S is between 7 and 100 (inclusive).
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a KEYENCE string, print `YES`; otherwise, print `NO`.
Examples
Input
keyofscience
Output
YES
Input
mpyszsbznf
Output
NO
Input
ashlfyha
Output
NO
Input
keyence
Output
YES
Submitted Solution:
```
import copy
s=input()
check="keyence"
tmp=0
if check in s:
print("YES")
exit()
for i in s:
if i == check[tmp]:
tmp+=1
else:
break
tmp2=copy.copy(tmp)
for i in s[tmp:]:
if i != check[tmp]:
tmp2+=1
else:
break
if tmp2 == len(s):
print("NO")
exit()
for i in s[tmp2:]:
if i == check[tmp]:
tmp+=1
else:
print("NO")
exit()
print("YES")
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string is called a KEYENCE string when it can be changed to `keyence` by removing its contiguous substring (possibly empty) only once.
Given a string S consisting of lowercase English letters, determine if S is a KEYENCE string.
Constraints
* The length of S is between 7 and 100 (inclusive).
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a KEYENCE string, print `YES`; otherwise, print `NO`.
Examples
Input
keyofscience
Output
YES
Input
mpyszsbznf
Output
NO
Input
ashlfyha
Output
NO
Input
keyence
Output
YES
Submitted Solution:
```
# coding: utf-8
cnt=0
keyence="keyence"
flg=[-1,-1,-1,-1,-1,-1,-1]
s=input()
for i in range(len(s)):
for j in range(len(keyence)):
if s[i]==keyence[j] and flg[j]==-1:
flg[j]=i
elif flg[j]==-1:
break
for i in range(len(flg)-1):
if flg[i+1]-flg[i]!=1:
cnt+=1
if cnt<=2:
print("YES")
else:
print("NO")
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string is called a KEYENCE string when it can be changed to `keyence` by removing its contiguous substring (possibly empty) only once.
Given a string S consisting of lowercase English letters, determine if S is a KEYENCE string.
Constraints
* The length of S is between 7 and 100 (inclusive).
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a KEYENCE string, print `YES`; otherwise, print `NO`.
Examples
Input
keyofscience
Output
YES
Input
mpyszsbznf
Output
NO
Input
ashlfyha
Output
NO
Input
keyence
Output
YES
Submitted Solution:
```
S = str(input())
for i in range(8):
word = S[:i]+S[-7:][i:]
if word == "keyence":
print("Yes")
exit()
print("No")
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string is called a KEYENCE string when it can be changed to `keyence` by removing its contiguous substring (possibly empty) only once.
Given a string S consisting of lowercase English letters, determine if S is a KEYENCE string.
Constraints
* The length of S is between 7 and 100 (inclusive).
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a KEYENCE string, print `YES`; otherwise, print `NO`.
Examples
Input
keyofscience
Output
YES
Input
mpyszsbznf
Output
NO
Input
ashlfyha
Output
NO
Input
keyence
Output
YES
Submitted Solution:
```
s=input()
string="keyence"
flag1=0
flag2=0
flag3=0
v=0
for i in range(len(s)):
try:
if s[i]==string[v]:
v+=1
if flag1==1:
flag2=1
else:
flag1=1
if flag1==1 and flag2==1:
print("NO")
exit()
if v==len(string)+1:
print('NO')
exit()
except IndexError:
if flag1==0 and flag2==0:
print('YES')
exit()
else:
print('NO')
exit()
if flag1==0 and flag2==0:
print('YES')
elif flag1==1 and flag2==0:
print('NO')
else:
print('YES')
```
### Response:
| No |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The King of a little Kingdom on a little island in the Pacific Ocean frequently has childish ideas. One day he said, “You shall make use of a message relaying game when you inform me of something.” In response to the King’s statement, six servants were selected as messengers whose names were Mr. J, Miss C, Mr. E, Mr. A, Dr. P, and Mr. M. They had to relay a message to the next messenger until the message got to the King.
Messages addressed to the King consist of digits (‘0’-‘9’) and alphabet characters (‘a’-‘z’, ‘A’-‘Z’). Capital and small letters are distinguished in messages. For example, “ke3E9Aa” is a message.
Contrary to King’s expectations, he always received wrong messages, because each messenger changed messages a bit before passing them to the next messenger. Since it irritated the King, he told you who are the Minister of the Science and Technology Agency of the Kingdom, “We don’t want such a wrong message any more. You shall develop software to correct it!” In response to the King’s new statement, you analyzed the messengers’ mistakes with all technologies in the Kingdom, and acquired the following features of mistakes of each messenger. A surprising point was that each messenger made the same mistake whenever relaying a message. The following facts were observed.
Mr. J rotates all characters of the message to the left by one. For example, he transforms “aB23d” to “B23da”.
Miss C rotates all characters of the message to the right by one. For example, she transforms “aB23d” to “daB23”.
Mr. E swaps the left half of the message with the right half. If the message has an odd number of characters, the middle one does not move. For example, he transforms “e3ac” to “ace3”, and “aB23d” to “3d2aB”.
Mr. A reverses the message. For example, he transforms “aB23d” to “d32Ba”.
Dr. P increments by one all the digits in the message. If a digit is ‘9’, it becomes ‘0’. The alphabet characters do not change. For example, he transforms “aB23d” to “aB34d”, and “e9ac” to “e0ac”.
Mr. M decrements by one all the digits in the message. If a digit is ‘0’, it becomes ‘9’. The alphabet characters do not change. For example, he transforms “aB23d” to “aB12d”, and “e0ac” to “e9ac”.
The software you must develop is to infer the original message from the final message, given the order of the messengers. For example, if the order of the messengers is A -> J -> M -> P and the message given to the King is “aB23d”, what is the original message? According to the features of the messengers’ mistakes, the sequence leading to the final message is
A J M P
“32Bad” --> “daB23” --> “aB23d” --> “aB12d” --> “aB23d”.
As a result, the original message should be “32Bad”.
Input
The input format is as follows.
n
The order of messengers
The message given to the King
.
.
.
The order of messengers
The message given to the King
The first line of the input contains a positive integer n, which denotes the number of data sets. Each data set is a pair of the order of messengers and the message given to the King. The number of messengers relaying a message is between 1 and 6 inclusive. The same person may not appear more than once in the order of messengers. The length of a message is between 1 and 25 inclusive.
Output
The inferred messages are printed each on a separate line.
Example
Input
5
AJMP
aB23d
E
86AE
AM
6
JPEM
WaEaETC302Q
CP
rTurnAGundam1isdefferentf
Output
32Bad
AE86
7
EC302QTWaEa
TurnAGundam0isdefferentfr
Submitted Solution:
```
funcs = {
'J': lambda s: s[-1:]+s[:-1],
'C': lambda s: s[1:]+s[0],
'E': lambda s: s[(len(s)+1)//2:]+s[len(s)//2:(len(s)+1)//2]+s[:len(s)//2],
'A': lambda s: s[::-1],
'P': lambda s: s.translate(str.maketrans('0123456789', '9012345678')),
'M': lambda s: s.translate(str.maketrans('0123456789', '1234567890')),
}
n = int(input())
for i in range(n):
s, t = [input().strip() for j in '01']
for c in s[::-1]:
t = funcs[c](t)
else:
print(t)
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The King of a little Kingdom on a little island in the Pacific Ocean frequently has childish ideas. One day he said, “You shall make use of a message relaying game when you inform me of something.” In response to the King’s statement, six servants were selected as messengers whose names were Mr. J, Miss C, Mr. E, Mr. A, Dr. P, and Mr. M. They had to relay a message to the next messenger until the message got to the King.
Messages addressed to the King consist of digits (‘0’-‘9’) and alphabet characters (‘a’-‘z’, ‘A’-‘Z’). Capital and small letters are distinguished in messages. For example, “ke3E9Aa” is a message.
Contrary to King’s expectations, he always received wrong messages, because each messenger changed messages a bit before passing them to the next messenger. Since it irritated the King, he told you who are the Minister of the Science and Technology Agency of the Kingdom, “We don’t want such a wrong message any more. You shall develop software to correct it!” In response to the King’s new statement, you analyzed the messengers’ mistakes with all technologies in the Kingdom, and acquired the following features of mistakes of each messenger. A surprising point was that each messenger made the same mistake whenever relaying a message. The following facts were observed.
Mr. J rotates all characters of the message to the left by one. For example, he transforms “aB23d” to “B23da”.
Miss C rotates all characters of the message to the right by one. For example, she transforms “aB23d” to “daB23”.
Mr. E swaps the left half of the message with the right half. If the message has an odd number of characters, the middle one does not move. For example, he transforms “e3ac” to “ace3”, and “aB23d” to “3d2aB”.
Mr. A reverses the message. For example, he transforms “aB23d” to “d32Ba”.
Dr. P increments by one all the digits in the message. If a digit is ‘9’, it becomes ‘0’. The alphabet characters do not change. For example, he transforms “aB23d” to “aB34d”, and “e9ac” to “e0ac”.
Mr. M decrements by one all the digits in the message. If a digit is ‘0’, it becomes ‘9’. The alphabet characters do not change. For example, he transforms “aB23d” to “aB12d”, and “e0ac” to “e9ac”.
The software you must develop is to infer the original message from the final message, given the order of the messengers. For example, if the order of the messengers is A -> J -> M -> P and the message given to the King is “aB23d”, what is the original message? According to the features of the messengers’ mistakes, the sequence leading to the final message is
A J M P
“32Bad” --> “daB23” --> “aB23d” --> “aB12d” --> “aB23d”.
As a result, the original message should be “32Bad”.
Input
The input format is as follows.
n
The order of messengers
The message given to the King
.
.
.
The order of messengers
The message given to the King
The first line of the input contains a positive integer n, which denotes the number of data sets. Each data set is a pair of the order of messengers and the message given to the King. The number of messengers relaying a message is between 1 and 6 inclusive. The same person may not appear more than once in the order of messengers. The length of a message is between 1 and 25 inclusive.
Output
The inferred messages are printed each on a separate line.
Example
Input
5
AJMP
aB23d
E
86AE
AM
6
JPEM
WaEaETC302Q
CP
rTurnAGundam1isdefferentf
Output
32Bad
AE86
7
EC302QTWaEa
TurnAGundam0isdefferentfr
Submitted Solution:
```
def J(string):
return string[-1] + string[:-1] if len(string) >= 2 else string
def C(string):
return string[1:] + string[0] if len(string) >= 2 else string
def E(string):
if len(string) == 1:
return string
if len(string) % 2:
return string[len(string) // 2 + 1:] + string[len(string) // 2] + string[0:len(string) // 2]
else:
return string[len(string) // 2:] + string[0:len(string) // 2]
def A(string):
return string[::-1]
def M(string):
new = ''
for i in string:
if ord(i) < 57 and ord(i) >= 48:
new += chr(ord(i) + 1)
elif ord(i) == 57:
new += '0'
else:
new += i
return new
def P(string):
new = ''
for i in string:
if ord(i) <= 57 and ord(i) > 48:
new += chr(ord(i) - 1)
elif ord(i) == 48:
new += '9'
else:
new += i
return new
ans = []
for i in range(int(input())):
to_do = input()
message = input().strip()
for i in to_do[::-1]:
if i == 'C':
message = C(message)
if i == 'J':
message = J(message)
if i == 'E':
message = E(message)
if i == 'A':
message = A(message)
if i == 'P':
message = P(message)
if i == 'M':
message = M(message)
ans.append(message)
[print(i) for i in ans]
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The King of a little Kingdom on a little island in the Pacific Ocean frequently has childish ideas. One day he said, “You shall make use of a message relaying game when you inform me of something.” In response to the King’s statement, six servants were selected as messengers whose names were Mr. J, Miss C, Mr. E, Mr. A, Dr. P, and Mr. M. They had to relay a message to the next messenger until the message got to the King.
Messages addressed to the King consist of digits (‘0’-‘9’) and alphabet characters (‘a’-‘z’, ‘A’-‘Z’). Capital and small letters are distinguished in messages. For example, “ke3E9Aa” is a message.
Contrary to King’s expectations, he always received wrong messages, because each messenger changed messages a bit before passing them to the next messenger. Since it irritated the King, he told you who are the Minister of the Science and Technology Agency of the Kingdom, “We don’t want such a wrong message any more. You shall develop software to correct it!” In response to the King’s new statement, you analyzed the messengers’ mistakes with all technologies in the Kingdom, and acquired the following features of mistakes of each messenger. A surprising point was that each messenger made the same mistake whenever relaying a message. The following facts were observed.
Mr. J rotates all characters of the message to the left by one. For example, he transforms “aB23d” to “B23da”.
Miss C rotates all characters of the message to the right by one. For example, she transforms “aB23d” to “daB23”.
Mr. E swaps the left half of the message with the right half. If the message has an odd number of characters, the middle one does not move. For example, he transforms “e3ac” to “ace3”, and “aB23d” to “3d2aB”.
Mr. A reverses the message. For example, he transforms “aB23d” to “d32Ba”.
Dr. P increments by one all the digits in the message. If a digit is ‘9’, it becomes ‘0’. The alphabet characters do not change. For example, he transforms “aB23d” to “aB34d”, and “e9ac” to “e0ac”.
Mr. M decrements by one all the digits in the message. If a digit is ‘0’, it becomes ‘9’. The alphabet characters do not change. For example, he transforms “aB23d” to “aB12d”, and “e0ac” to “e9ac”.
The software you must develop is to infer the original message from the final message, given the order of the messengers. For example, if the order of the messengers is A -> J -> M -> P and the message given to the King is “aB23d”, what is the original message? According to the features of the messengers’ mistakes, the sequence leading to the final message is
A J M P
“32Bad” --> “daB23” --> “aB23d” --> “aB12d” --> “aB23d”.
As a result, the original message should be “32Bad”.
Input
The input format is as follows.
n
The order of messengers
The message given to the King
.
.
.
The order of messengers
The message given to the King
The first line of the input contains a positive integer n, which denotes the number of data sets. Each data set is a pair of the order of messengers and the message given to the King. The number of messengers relaying a message is between 1 and 6 inclusive. The same person may not appear more than once in the order of messengers. The length of a message is between 1 and 25 inclusive.
Output
The inferred messages are printed each on a separate line.
Example
Input
5
AJMP
aB23d
E
86AE
AM
6
JPEM
WaEaETC302Q
CP
rTurnAGundam1isdefferentf
Output
32Bad
AE86
7
EC302QTWaEa
TurnAGundam0isdefferentfr
Submitted Solution:
```
def main():
s = input()
ans = list(input())
s = reversed(s)
for si in s:
if si == "C":
ans = ans[1:] + [ans[0]]
if si == "J":
ans = [ans[-1]] + ans[:-1]
if si == "E":
tmp = [ans[len(ans) // 2]] if len(ans) & 1 else []
ans = ans[len(ans) // 2 + (len(ans) & 1):] + tmp + ans[: len(ans) // 2]
if si == "A":
ans = ans[::-1]
if si == "M":
for i in range(len(ans)):
if ans[i].isdecimal():
ans[i] = int(ans[i])
ans[i] = str((ans[i] + 1) % 10)
if si == "P":
for i in range(len(ans)):
if ans[i].isdecimal():
ans[i] = int(ans[i])
ans[i] = str((ans[i] - 1) % 10)
print("".join(ans))
if __name__ == "__main__":
for _ in range(int(input())):
main()
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The King of a little Kingdom on a little island in the Pacific Ocean frequently has childish ideas. One day he said, “You shall make use of a message relaying game when you inform me of something.” In response to the King’s statement, six servants were selected as messengers whose names were Mr. J, Miss C, Mr. E, Mr. A, Dr. P, and Mr. M. They had to relay a message to the next messenger until the message got to the King.
Messages addressed to the King consist of digits (‘0’-‘9’) and alphabet characters (‘a’-‘z’, ‘A’-‘Z’). Capital and small letters are distinguished in messages. For example, “ke3E9Aa” is a message.
Contrary to King’s expectations, he always received wrong messages, because each messenger changed messages a bit before passing them to the next messenger. Since it irritated the King, he told you who are the Minister of the Science and Technology Agency of the Kingdom, “We don’t want such a wrong message any more. You shall develop software to correct it!” In response to the King’s new statement, you analyzed the messengers’ mistakes with all technologies in the Kingdom, and acquired the following features of mistakes of each messenger. A surprising point was that each messenger made the same mistake whenever relaying a message. The following facts were observed.
Mr. J rotates all characters of the message to the left by one. For example, he transforms “aB23d” to “B23da”.
Miss C rotates all characters of the message to the right by one. For example, she transforms “aB23d” to “daB23”.
Mr. E swaps the left half of the message with the right half. If the message has an odd number of characters, the middle one does not move. For example, he transforms “e3ac” to “ace3”, and “aB23d” to “3d2aB”.
Mr. A reverses the message. For example, he transforms “aB23d” to “d32Ba”.
Dr. P increments by one all the digits in the message. If a digit is ‘9’, it becomes ‘0’. The alphabet characters do not change. For example, he transforms “aB23d” to “aB34d”, and “e9ac” to “e0ac”.
Mr. M decrements by one all the digits in the message. If a digit is ‘0’, it becomes ‘9’. The alphabet characters do not change. For example, he transforms “aB23d” to “aB12d”, and “e0ac” to “e9ac”.
The software you must develop is to infer the original message from the final message, given the order of the messengers. For example, if the order of the messengers is A -> J -> M -> P and the message given to the King is “aB23d”, what is the original message? According to the features of the messengers’ mistakes, the sequence leading to the final message is
A J M P
“32Bad” --> “daB23” --> “aB23d” --> “aB12d” --> “aB23d”.
As a result, the original message should be “32Bad”.
Input
The input format is as follows.
n
The order of messengers
The message given to the King
.
.
.
The order of messengers
The message given to the King
The first line of the input contains a positive integer n, which denotes the number of data sets. Each data set is a pair of the order of messengers and the message given to the King. The number of messengers relaying a message is between 1 and 6 inclusive. The same person may not appear more than once in the order of messengers. The length of a message is between 1 and 25 inclusive.
Output
The inferred messages are printed each on a separate line.
Example
Input
5
AJMP
aB23d
E
86AE
AM
6
JPEM
WaEaETC302Q
CP
rTurnAGundam1isdefferentf
Output
32Bad
AE86
7
EC302QTWaEa
TurnAGundam0isdefferentfr
Submitted Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 998244353
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)
def main():
rr = []
n = I()
ni = 0
d = '0123456789'
while ni < n:
ni += 1
s = S()
m = S()
l = len(m)
for c in s[::-1]:
if c == 'J':
m = m[-1] + m[:-1]
elif c == 'C':
m = m[1:] + m[0]
elif c == 'E':
if l % 2 == 0:
m = m[l//2:] + m[:l//2]
else:
m = m[l//2+1:] + m[l//2] + m[:l//2]
elif c == 'A':
m = m[::-1]
elif c == 'P':
m = ''.join([t if not t in d else d[d.index(t)-1] for t in m])
elif c == 'M':
m = ''.join([t if not t in d else d[(d.index(t)+1)%10] for t in m])
rr.append(m)
return '\n'.join(map(str, rr))
print(main())
```
### Response:
| Yes |
### Instruction:
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The King of a little Kingdom on a little island in the Pacific Ocean frequently has childish ideas. One day he said, “You shall make use of a message relaying game when you inform me of something.” In response to the King’s statement, six servants were selected as messengers whose names were Mr. J, Miss C, Mr. E, Mr. A, Dr. P, and Mr. M. They had to relay a message to the next messenger until the message got to the King.
Messages addressed to the King consist of digits (‘0’-‘9’) and alphabet characters (‘a’-‘z’, ‘A’-‘Z’). Capital and small letters are distinguished in messages. For example, “ke3E9Aa” is a message.
Contrary to King’s expectations, he always received wrong messages, because each messenger changed messages a bit before passing them to the next messenger. Since it irritated the King, he told you who are the Minister of the Science and Technology Agency of the Kingdom, “We don’t want such a wrong message any more. You shall develop software to correct it!” In response to the King’s new statement, you analyzed the messengers’ mistakes with all technologies in the Kingdom, and acquired the following features of mistakes of each messenger. A surprising point was that each messenger made the same mistake whenever relaying a message. The following facts were observed.
Mr. J rotates all characters of the message to the left by one. For example, he transforms “aB23d” to “B23da”.
Miss C rotates all characters of the message to the right by one. For example, she transforms “aB23d” to “daB23”.
Mr. E swaps the left half of the message with the right half. If the message has an odd number of characters, the middle one does not move. For example, he transforms “e3ac” to “ace3”, and “aB23d” to “3d2aB”.
Mr. A reverses the message. For example, he transforms “aB23d” to “d32Ba”.
Dr. P increments by one all the digits in the message. If a digit is ‘9’, it becomes ‘0’. The alphabet characters do not change. For example, he transforms “aB23d” to “aB34d”, and “e9ac” to “e0ac”.
Mr. M decrements by one all the digits in the message. If a digit is ‘0’, it becomes ‘9’. The alphabet characters do not change. For example, he transforms “aB23d” to “aB12d”, and “e0ac” to “e9ac”.
The software you must develop is to infer the original message from the final message, given the order of the messengers. For example, if the order of the messengers is A -> J -> M -> P and the message given to the King is “aB23d”, what is the original message? According to the features of the messengers’ mistakes, the sequence leading to the final message is
A J M P
“32Bad” --> “daB23” --> “aB23d” --> “aB12d” --> “aB23d”.
As a result, the original message should be “32Bad”.
Input
The input format is as follows.
n
The order of messengers
The message given to the King
.
.
.
The order of messengers
The message given to the King
The first line of the input contains a positive integer n, which denotes the number of data sets. Each data set is a pair of the order of messengers and the message given to the King. The number of messengers relaying a message is between 1 and 6 inclusive. The same person may not appear more than once in the order of messengers. The length of a message is between 1 and 25 inclusive.
Output
The inferred messages are printed each on a separate line.
Example
Input
5
AJMP
aB23d
E
86AE
AM
6
JPEM
WaEaETC302Q
CP
rTurnAGundam1isdefferentf
Output
32Bad
AE86
7
EC302QTWaEa
TurnAGundam0isdefferentfr
Submitted Solution:
```
n = int(input())
for i in range(n):
order = input()
message = input()
for s in order:
if s == 'J':
message = message[1:] + message[0]
elif s == 'C':
message = message[len(message) - 1] + message[:len(message) - 1]
elif s == 'E':
message = message[len(message)//2:] + message[:len(message)//2]
elif s == 'A':
message = message[::-1]
elif s == 'P':
for c in message:
if c == '9':
c = '0'
elif c >= '0' and c < '9':
c = chr(ord(c) + 1)
elif s == 'M':
for c in message:
if c == '0':
c = '9'
elif c > '0' and c <= '9':
c = chr(ord(c) - 1)
print(message)
```
### Response:
| No |
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