message stringlengths 2 11.9k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 137 108k | cluster float64 18 18 | __index_level_0__ int64 274 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The name of one small but proud corporation consists of n lowercase English letters. The Corporation has decided to try rebranding — an active marketing strategy, that includes a set of measures to change either the brand (both for the company and the goods it produces) or its components: the name, the logo, the slogan. They decided to start with the name.
For this purpose the corporation has consecutively hired m designers. Once a company hires the i-th designer, he immediately contributes to the creation of a new corporation name as follows: he takes the newest version of the name and replaces all the letters xi by yi, and all the letters yi by xi. This results in the new version. It is possible that some of these letters do no occur in the string. It may also happen that xi coincides with yi. The version of the name received after the work of the last designer becomes the new name of the corporation.
Manager Arkady has recently got a job in this company, but is already soaked in the spirit of teamwork and is very worried about the success of the rebranding. Naturally, he can't wait to find out what is the new name the Corporation will receive.
Satisfy Arkady's curiosity and tell him the final version of the name.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 200 000) — the length of the initial name and the number of designers hired, respectively.
The second line consists of n lowercase English letters and represents the original name of the corporation.
Next m lines contain the descriptions of the designers' actions: the i-th of them contains two space-separated lowercase English letters xi and yi.
Output
Print the new name of the corporation.
Examples
Input
6 1
police
p m
Output
molice
Input
11 6
abacabadaba
a b
b c
a d
e g
f a
b b
Output
cdcbcdcfcdc
Note
In the second sample the name of the corporation consecutively changes as follows:
<image>
<image>
<image>
<image>
<image>
<image>
Submitted Solution:
```
def dict_find(d,value):
for k,v in d.items():
if v == value:
return k
n, m = map(int, input().split())
s = input()
d = {chr(c) : chr(c) for c in range(ord('a'), ord('z') + 1)}
for _ in range(m):
x,y = input().split()
c1 = dict_find(d,x)
c2 = dict_find(d,y)
d[c1],d[c2] = d[c2], d[c1]
for character in s:
print(d[character],end='')
print()
``` | instruction | 0 | 22,497 | 18 | 44,994 |
Yes | output | 1 | 22,497 | 18 | 44,995 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The name of one small but proud corporation consists of n lowercase English letters. The Corporation has decided to try rebranding — an active marketing strategy, that includes a set of measures to change either the brand (both for the company and the goods it produces) or its components: the name, the logo, the slogan. They decided to start with the name.
For this purpose the corporation has consecutively hired m designers. Once a company hires the i-th designer, he immediately contributes to the creation of a new corporation name as follows: he takes the newest version of the name and replaces all the letters xi by yi, and all the letters yi by xi. This results in the new version. It is possible that some of these letters do no occur in the string. It may also happen that xi coincides with yi. The version of the name received after the work of the last designer becomes the new name of the corporation.
Manager Arkady has recently got a job in this company, but is already soaked in the spirit of teamwork and is very worried about the success of the rebranding. Naturally, he can't wait to find out what is the new name the Corporation will receive.
Satisfy Arkady's curiosity and tell him the final version of the name.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 200 000) — the length of the initial name and the number of designers hired, respectively.
The second line consists of n lowercase English letters and represents the original name of the corporation.
Next m lines contain the descriptions of the designers' actions: the i-th of them contains two space-separated lowercase English letters xi and yi.
Output
Print the new name of the corporation.
Examples
Input
6 1
police
p m
Output
molice
Input
11 6
abacabadaba
a b
b c
a d
e g
f a
b b
Output
cdcbcdcfcdc
Note
In the second sample the name of the corporation consecutively changes as follows:
<image>
<image>
<image>
<image>
<image>
<image>
Submitted Solution:
```
n,m=map(int,input().split())
l=list(input())
alpha=[chr(i) for i in range(97,123)]
for i in range(m):
ch1,ch2=input().split()
ord1=alpha.index(ch1)
ord2=alpha.index(ch2)
alpha[ord1],alpha[ord2]=alpha[ord2],alpha[ord1]
for i in range(n):
o=ord(l[i])-97
l[i]=alpha[o]
print(''.join(l))
``` | instruction | 0 | 22,498 | 18 | 44,996 |
Yes | output | 1 | 22,498 | 18 | 44,997 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The name of one small but proud corporation consists of n lowercase English letters. The Corporation has decided to try rebranding — an active marketing strategy, that includes a set of measures to change either the brand (both for the company and the goods it produces) or its components: the name, the logo, the slogan. They decided to start with the name.
For this purpose the corporation has consecutively hired m designers. Once a company hires the i-th designer, he immediately contributes to the creation of a new corporation name as follows: he takes the newest version of the name and replaces all the letters xi by yi, and all the letters yi by xi. This results in the new version. It is possible that some of these letters do no occur in the string. It may also happen that xi coincides with yi. The version of the name received after the work of the last designer becomes the new name of the corporation.
Manager Arkady has recently got a job in this company, but is already soaked in the spirit of teamwork and is very worried about the success of the rebranding. Naturally, he can't wait to find out what is the new name the Corporation will receive.
Satisfy Arkady's curiosity and tell him the final version of the name.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 200 000) — the length of the initial name and the number of designers hired, respectively.
The second line consists of n lowercase English letters and represents the original name of the corporation.
Next m lines contain the descriptions of the designers' actions: the i-th of them contains two space-separated lowercase English letters xi and yi.
Output
Print the new name of the corporation.
Examples
Input
6 1
police
p m
Output
molice
Input
11 6
abacabadaba
a b
b c
a d
e g
f a
b b
Output
cdcbcdcfcdc
Note
In the second sample the name of the corporation consecutively changes as follows:
<image>
<image>
<image>
<image>
<image>
<image>
Submitted Solution:
```
n, m = map(int, input().split())
s = input()
t = { c: c for c in map(chr, range(ord('a'), ord('z') + 1)) }
for i in range(m):
a, b = input().split()
t[a], t[b] = t[b], t[a]
for c in s:
print(t[c], end="")
print()
``` | instruction | 0 | 22,499 | 18 | 44,998 |
No | output | 1 | 22,499 | 18 | 44,999 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The name of one small but proud corporation consists of n lowercase English letters. The Corporation has decided to try rebranding — an active marketing strategy, that includes a set of measures to change either the brand (both for the company and the goods it produces) or its components: the name, the logo, the slogan. They decided to start with the name.
For this purpose the corporation has consecutively hired m designers. Once a company hires the i-th designer, he immediately contributes to the creation of a new corporation name as follows: he takes the newest version of the name and replaces all the letters xi by yi, and all the letters yi by xi. This results in the new version. It is possible that some of these letters do no occur in the string. It may also happen that xi coincides with yi. The version of the name received after the work of the last designer becomes the new name of the corporation.
Manager Arkady has recently got a job in this company, but is already soaked in the spirit of teamwork and is very worried about the success of the rebranding. Naturally, he can't wait to find out what is the new name the Corporation will receive.
Satisfy Arkady's curiosity and tell him the final version of the name.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 200 000) — the length of the initial name and the number of designers hired, respectively.
The second line consists of n lowercase English letters and represents the original name of the corporation.
Next m lines contain the descriptions of the designers' actions: the i-th of them contains two space-separated lowercase English letters xi and yi.
Output
Print the new name of the corporation.
Examples
Input
6 1
police
p m
Output
molice
Input
11 6
abacabadaba
a b
b c
a d
e g
f a
b b
Output
cdcbcdcfcdc
Note
In the second sample the name of the corporation consecutively changes as follows:
<image>
<image>
<image>
<image>
<image>
<image>
Submitted Solution:
```
n, m = map(int, input().split())
s = list(input())
for i in range(m):
x, y = input().split()
for j in range(n):
if s[j] == x:
s[j] = y;
st = ''
for i in range(n):
st = st + s[i]
print(st)
``` | instruction | 0 | 22,500 | 18 | 45,000 |
No | output | 1 | 22,500 | 18 | 45,001 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The name of one small but proud corporation consists of n lowercase English letters. The Corporation has decided to try rebranding — an active marketing strategy, that includes a set of measures to change either the brand (both for the company and the goods it produces) or its components: the name, the logo, the slogan. They decided to start with the name.
For this purpose the corporation has consecutively hired m designers. Once a company hires the i-th designer, he immediately contributes to the creation of a new corporation name as follows: he takes the newest version of the name and replaces all the letters xi by yi, and all the letters yi by xi. This results in the new version. It is possible that some of these letters do no occur in the string. It may also happen that xi coincides with yi. The version of the name received after the work of the last designer becomes the new name of the corporation.
Manager Arkady has recently got a job in this company, but is already soaked in the spirit of teamwork and is very worried about the success of the rebranding. Naturally, he can't wait to find out what is the new name the Corporation will receive.
Satisfy Arkady's curiosity and tell him the final version of the name.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 200 000) — the length of the initial name and the number of designers hired, respectively.
The second line consists of n lowercase English letters and represents the original name of the corporation.
Next m lines contain the descriptions of the designers' actions: the i-th of them contains two space-separated lowercase English letters xi and yi.
Output
Print the new name of the corporation.
Examples
Input
6 1
police
p m
Output
molice
Input
11 6
abacabadaba
a b
b c
a d
e g
f a
b b
Output
cdcbcdcfcdc
Note
In the second sample the name of the corporation consecutively changes as follows:
<image>
<image>
<image>
<image>
<image>
<image>
Submitted Solution:
```
import string
n , m = input("").split()
n = int(n)
m = int(m)
s = input("")
l = []
r = ''
t = 'a'
for i in s:
l.append(i)
alpha = list(string.ascii_lowercase)
con = []
v = []
for i in range(0,m):
b,f = input("").split()
v.append([b,f])
for i in range(0,26):
mi = [alpha[i]]
t = alpha[i]
for j in range(0,m):
if t == v[j][0]:
t = v[j][1]
elif t == v[j][1]:
t = v[j][0]
mi.append(t)
con.append(mi)
for i in range(0,n):
for j in range(0,26):
ind = alpha.index(l[i])
l[i] = con[ind][1]
for i in l:
r += i
print(r)
``` | instruction | 0 | 22,501 | 18 | 45,002 |
No | output | 1 | 22,501 | 18 | 45,003 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The name of one small but proud corporation consists of n lowercase English letters. The Corporation has decided to try rebranding — an active marketing strategy, that includes a set of measures to change either the brand (both for the company and the goods it produces) or its components: the name, the logo, the slogan. They decided to start with the name.
For this purpose the corporation has consecutively hired m designers. Once a company hires the i-th designer, he immediately contributes to the creation of a new corporation name as follows: he takes the newest version of the name and replaces all the letters xi by yi, and all the letters yi by xi. This results in the new version. It is possible that some of these letters do no occur in the string. It may also happen that xi coincides with yi. The version of the name received after the work of the last designer becomes the new name of the corporation.
Manager Arkady has recently got a job in this company, but is already soaked in the spirit of teamwork and is very worried about the success of the rebranding. Naturally, he can't wait to find out what is the new name the Corporation will receive.
Satisfy Arkady's curiosity and tell him the final version of the name.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 200 000) — the length of the initial name and the number of designers hired, respectively.
The second line consists of n lowercase English letters and represents the original name of the corporation.
Next m lines contain the descriptions of the designers' actions: the i-th of them contains two space-separated lowercase English letters xi and yi.
Output
Print the new name of the corporation.
Examples
Input
6 1
police
p m
Output
molice
Input
11 6
abacabadaba
a b
b c
a d
e g
f a
b b
Output
cdcbcdcfcdc
Note
In the second sample the name of the corporation consecutively changes as follows:
<image>
<image>
<image>
<image>
<image>
<image>
Submitted Solution:
```
n,k=list(map(int,input().split()))
p=list(input())
s={}
for x in range(k):
v,c=input().split()
if v not in s:
s[v]=c
else:
for item in s:
if s[item]==v:
s[item]=c
break
if c not in s:
s[c]=v
else:
for item in s:
if s[item]==c:
s[item]=v
break
for x in range(n):
if p[x] not in s:
pass
else:
p[x]=s[p[x]]
print("".join(p))
``` | instruction | 0 | 22,502 | 18 | 45,004 |
No | output | 1 | 22,502 | 18 | 45,005 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Snuke loves "paper cutting": he cuts out characters from a newspaper headline and rearranges them to form another string.
He will receive a headline which contains one of the strings S_1,...,S_n tomorrow. He is excited and already thinking of what string he will create. Since he does not know the string on the headline yet, he is interested in strings that can be created regardless of which string the headline contains.
Find the longest string that can be created regardless of which string among S_1,...,S_n the headline contains. If there are multiple such strings, find the lexicographically smallest one among them.
Constraints
* 1 \leq n \leq 50
* 1 \leq |S_i| \leq 50 for every i = 1, ..., n.
* S_i consists of lowercase English letters (`a` - `z`) for every i = 1, ..., n.
Input
Input is given from Standard Input in the following format:
n
S_1
...
S_n
Output
Print the lexicographically smallest string among the longest strings that satisfy the condition. If the answer is an empty string, print an empty line.
Examples
Input
3
cbaa
daacc
acacac
Output
aac
Input
3
a
aa
b
Output
Submitted Solution:
```
n = int(input())
s = [""] * n
for i in range(n):
s[i] = input()
ans = ""
for i in range(26):
cnt = 50
for j in range(n):
cnt = min(cnt, s[j].count(chr(ord("a") + i)))
ans += chr(ord("a") + i) * cnt
print(ans)
``` | instruction | 0 | 22,730 | 18 | 45,460 |
Yes | output | 1 | 22,730 | 18 | 45,461 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Equation
Identity
English text is not available in this practice contest.
In logical operations, only two types of values, T and F, are handled.
Let "-" be a unary operator (a symbol whose input represents one operation) and "*", "+", "->" be a binary operator (a symbol whose input represents two operations). "-" Is a logical negation (NOT), "*" is a logical product (AND), "+" is a logical sum (OR), and "->" is a logical inclusion (IMP) operator. The truth table of these logical operations is shown in the table below.
x | y | -x | (x * y) | (x + y) | (x-> y)
--- | --- | --- | --- | --- | ---
T | T | F | T | T | T
T | F | F | F | T | F
F | T | T | F | T | T
F | F | T | F | F | T
The logical expression has one of the following forms. X and Y are logical expressions, and binary operators must be enclosed in parentheses.
* Constant: T, F
* Variables: a, b, c, d, e, f, g, h, i, j, k
* Logical negation: -X
* AND: (X * Y)
* OR: (X + Y)
* Logical conditional: (X-> Y)
An equation is given that combines two formulas with the equal sign "=". An identity is an equation that holds regardless of the value of the variable that appears in the equation. I want to make a program that determines whether a given equation is an identity.
Input
The input consists of multiple lines, each line being a dataset. The dataset is a string consisting of T, F, a, b, c, d, e, f, g, h, i, j, k, (,), =,-, +, *,> and is blank. Does not include other characters such as. It can be assumed that the number of characters in one line is 1000 characters or less.
One dataset contains one equation. The grammar of the equation is given by the following BNF. All equations follow this syntax rule.
<equation> :: = <formula> "=" <formula>
<formula> :: = "T" | "F" |
"a" | "b" | "c" | "d" | "e" | "f" |
"g" | "h" | "i" | "j" | "k" |
"-" <formula> |
"(" <formula> "*" <formula> ")" |
"(" <formula> "+" <formula> ")" |
"(" <formula> "->" <formula> ")"
The end of the input is indicated by a line consisting only of "#", which is not a dataset.
Output
For each dataset, print "YES" if the equation is an identity, otherwise "NO" on one line. The output must not contain extra characters.
Sample Input
-(a + b) = (-a * -b)
(a-> b) = (-a + b)
((a * T) + b) = (-c + (a * -b))
Output for Sample Input
YES YES
YES YES
NO
Example
Input
Output
Submitted Solution:
```
# -*- coding: utf-8 -*-
from itertools import product
"""
-> は @と表記する
"""
def parse(S):
"""
構文木を返す
Sは普通の記法の式
opは優先順序 通常は(*/: 1, +-: 2)
"""
S = "{}".format(S)
V = []
op = {"-": 1,
"+": 2,
"*": 2,
"@": 2}
variables = list("abcdefghijk")
for x in list("()+-*@"):
S = S.replace(x, " {} ".format(x))
i = 0
rank = 0
O = []
for s in S.split():
if s == "(":
rank += 1
elif s == ")":
rank -= 1
elif s in variables + ["T", "F"]:
V.append(s)
i += 1
else:
V.append(s)
O.append([-rank, op[s], i])
i += 1
G = [[] for _ in range(len(V))]
P = [-1]*len(V)
O = sorted(O)
def get_pair(i):
while P[i] != -1:
i = P[i]
return i
if len(O):
for _, _, i in O:
if V[i] == "-": # 単項演算子
r = get_pair(i+1)
G[i].append(r)
P[r] = i
else: # 二項演算子
l, r = get_pair(i-1), get_pair(i+1)
G[i].extend([l, r])
P[l], P[r] = i, i
p = P.index(-1)
else:
assert len(V) == 1
p = 0
return G, V, p
def calculate(G, V, p, X):
variables = set(list("abcdefghijk"))
def call(i):
if V[i] in variables:
return X[V[i]]
elif V[i] == "T":
return True
elif V[i] == "F":
return False
elif V[i] == "-":
return not call(G[i][0])
elif V[i] == "@":
x = call(G[i][0])
y = call(G[i][1])
return not (x==True and y==False)
elif V[i] == "*":
x = call(G[i][0])
y = call(G[i][1])
return x & y
elif V[i] == "+":
x = call(G[i][0])
y = call(G[i][1])
return x | y
else:
raise
return call(p)
S = input()
while S != "#":
L, R = S.replace("->", "@").split("=")
abc = list("abcdefghijk")
for Y in product([True, False], repeat=11):
X = dict()
for i in range(11):
X[abc[i]] = Y[i]
G, V, p = parse(L)
l = calculate(G, V, p, X)
G, V, p = parse(R)
r = calculate(G, V, p, X)
if l != r:
print("N0")
break
else:
print("YES")
S = input()
``` | instruction | 0 | 22,808 | 18 | 45,616 |
No | output | 1 | 22,808 | 18 | 45,617 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Equation
Identity
English text is not available in this practice contest.
In logical operations, only two types of values, T and F, are handled.
Let "-" be a unary operator (a symbol whose input represents one operation) and "*", "+", "->" be a binary operator (a symbol whose input represents two operations). "-" Is a logical negation (NOT), "*" is a logical product (AND), "+" is a logical sum (OR), and "->" is a logical inclusion (IMP) operator. The truth table of these logical operations is shown in the table below.
x | y | -x | (x * y) | (x + y) | (x-> y)
--- | --- | --- | --- | --- | ---
T | T | F | T | T | T
T | F | F | F | T | F
F | T | T | F | T | T
F | F | T | F | F | T
The logical expression has one of the following forms. X and Y are logical expressions, and binary operators must be enclosed in parentheses.
* Constant: T, F
* Variables: a, b, c, d, e, f, g, h, i, j, k
* Logical negation: -X
* AND: (X * Y)
* OR: (X + Y)
* Logical conditional: (X-> Y)
An equation is given that combines two formulas with the equal sign "=". An identity is an equation that holds regardless of the value of the variable that appears in the equation. I want to make a program that determines whether a given equation is an identity.
Input
The input consists of multiple lines, each line being a dataset. The dataset is a string consisting of T, F, a, b, c, d, e, f, g, h, i, j, k, (,), =,-, +, *,> and is blank. Does not include other characters such as. It can be assumed that the number of characters in one line is 1000 characters or less.
One dataset contains one equation. The grammar of the equation is given by the following BNF. All equations follow this syntax rule.
<equation> :: = <formula> "=" <formula>
<formula> :: = "T" | "F" |
"a" | "b" | "c" | "d" | "e" | "f" |
"g" | "h" | "i" | "j" | "k" |
"-" <formula> |
"(" <formula> "*" <formula> ")" |
"(" <formula> "+" <formula> ")" |
"(" <formula> "->" <formula> ")"
The end of the input is indicated by a line consisting only of "#", which is not a dataset.
Output
For each dataset, print "YES" if the equation is an identity, otherwise "NO" on one line. The output must not contain extra characters.
Sample Input
-(a + b) = (-a * -b)
(a-> b) = (-a + b)
((a * T) + b) = (-c + (a * -b))
Output for Sample Input
YES YES
YES YES
NO
Example
Input
Output
Submitted Solution:
```
# -*- coding: utf-8 -*-
from itertools import product
"""
-> は @と表記する
"""
def parse(S):
"""
構文木を返す
Sは普通の記法の式
opは優先順序 通常は(*/: 1, +-: 2)
"""
S = "{}".format(S)
V = []
op = {"-": 1,
"+": 2,
"*": 2,
"@": 2}
variables = list("abcdefghijk")
for x in list("()+-*@"):
S = S.replace(x, " {} ".format(x))
i = 0
rank = 0
O = []
for s in S.split():
if s == "(":
rank += 1
elif s == ")":
rank -= 1
elif s in variables + ["T", "F"]:
V.append(s)
i += 1
else:
V.append(s)
O.append([-rank, op[s], i])
i += 1
G = [[] for _ in range(len(V))]
P = [-1]*len(V)
O = sorted(O)
def get_pair(i):
while P[i] != -1:
i = P[i]
return i
if len(O):
for _, _, i in O:
if V[i] == "-": # 単項演算子
r = get_pair(i+1)
G[i].append(r)
P[r] = i
else: # 二項演算子
l, r = get_pair(i-1), get_pair(i+1)
G[i].extend([l, r])
P[l], P[r] = i, i
p = O[-1][2]
else:
assert len(V) == 1
p = 0
return G, V, p
def calculate(G, V, p, X):
variables = set(list("abcdefghijk"))
def call(i):
if V[i] in variables:
return X[V[i]]
elif V[i] == "T":
return True
elif V[i] == "F":
return False
elif V[i] == "-":
return not call(G[i][0])
elif V[i] == "@":
x = call(G[i][0])
y = call(G[i][1])
return not (x==True and y==False)
elif V[i] == "*":
x = call(G[i][0])
y = call(G[i][1])
return x & y
elif V[i] == "+":
x = call(G[i][0])
y = call(G[i][1])
return x | y
else:
raise
return call(p)
S = input()
while S != "#":
L, R = S.replace("->", "@").split("=")
abc = list("abcdefghijk")
for Y in product([True, False], repeat=11):
X = dict()
for i in range(11):
X[abc[i]] = Y[i]
G, V, p = parse(L)
l = calculate(G, V, p, X)
G, V, p = parse(R)
r = calculate(G, V, p, X)
if l != r:
print("N0")
break
else:
print("YES")
S = input()
``` | instruction | 0 | 22,809 | 18 | 45,618 |
No | output | 1 | 22,809 | 18 | 45,619 |
Provide a correct Python 3 solution for this coding contest problem.
Given are strings S and T. Consider changing S to T by repeating the operation below. Find the minimum number of operations required to do so.
Operation: Choose one character of S and replace it with a different character.
Constraints
* S and T have lengths between 1 and 2\times 10^5 (inclusive).
* S and T consists of lowercase English letters.
* S and T have equal lengths.
Input
Input is given from Standard Input in the following format:
S
T
Output
Print the answer.
Examples
Input
cupofcoffee
cupofhottea
Output
4
Input
abcde
bcdea
Output
5
Input
apple
apple
Output
0 | instruction | 0 | 23,559 | 18 | 47,118 |
"Correct Solution:
```
s=input()
t=input()
ans=0
for i,j in zip(s,t):
if(i!=j):ans+=1
print(ans)
``` | output | 1 | 23,559 | 18 | 47,119 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are strings S and T. Consider changing S to T by repeating the operation below. Find the minimum number of operations required to do so.
Operation: Choose one character of S and replace it with a different character.
Constraints
* S and T have lengths between 1 and 2\times 10^5 (inclusive).
* S and T consists of lowercase English letters.
* S and T have equal lengths.
Input
Input is given from Standard Input in the following format:
S
T
Output
Print the answer.
Examples
Input
cupofcoffee
cupofhottea
Output
4
Input
abcde
bcdea
Output
5
Input
apple
apple
Output
0
Submitted Solution:
```
s = input()
t = input()
result = [x != y for x, y in zip(s, t)]
print(sum(result))
``` | instruction | 0 | 23,566 | 18 | 47,132 |
Yes | output | 1 | 23,566 | 18 | 47,133 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are strings S and T. Consider changing S to T by repeating the operation below. Find the minimum number of operations required to do so.
Operation: Choose one character of S and replace it with a different character.
Constraints
* S and T have lengths between 1 and 2\times 10^5 (inclusive).
* S and T consists of lowercase English letters.
* S and T have equal lengths.
Input
Input is given from Standard Input in the following format:
S
T
Output
Print the answer.
Examples
Input
cupofcoffee
cupofhottea
Output
4
Input
abcde
bcdea
Output
5
Input
apple
apple
Output
0
Submitted Solution:
```
s,t=input(),input()
print(len([1 for i,j in zip(s,t) if i!=j]))
``` | instruction | 0 | 23,567 | 18 | 47,134 |
Yes | output | 1 | 23,567 | 18 | 47,135 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are strings S and T. Consider changing S to T by repeating the operation below. Find the minimum number of operations required to do so.
Operation: Choose one character of S and replace it with a different character.
Constraints
* S and T have lengths between 1 and 2\times 10^5 (inclusive).
* S and T consists of lowercase English letters.
* S and T have equal lengths.
Input
Input is given from Standard Input in the following format:
S
T
Output
Print the answer.
Examples
Input
cupofcoffee
cupofhottea
Output
4
Input
abcde
bcdea
Output
5
Input
apple
apple
Output
0
Submitted Solution:
```
ans = 0
for (s_i,t_i) in zip(input(),input()):
if s_i != t_i:
ans += 1
print(ans)
``` | instruction | 0 | 23,568 | 18 | 47,136 |
Yes | output | 1 | 23,568 | 18 | 47,137 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are strings S and T. Consider changing S to T by repeating the operation below. Find the minimum number of operations required to do so.
Operation: Choose one character of S and replace it with a different character.
Constraints
* S and T have lengths between 1 and 2\times 10^5 (inclusive).
* S and T consists of lowercase English letters.
* S and T have equal lengths.
Input
Input is given from Standard Input in the following format:
S
T
Output
Print the answer.
Examples
Input
cupofcoffee
cupofhottea
Output
4
Input
abcde
bcdea
Output
5
Input
apple
apple
Output
0
Submitted Solution:
```
S, T = input(), input()
print(sum(s!=t for s, t in zip(S, T)))
``` | instruction | 0 | 23,569 | 18 | 47,138 |
Yes | output | 1 | 23,569 | 18 | 47,139 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are strings S and T. Consider changing S to T by repeating the operation below. Find the minimum number of operations required to do so.
Operation: Choose one character of S and replace it with a different character.
Constraints
* S and T have lengths between 1 and 2\times 10^5 (inclusive).
* S and T consists of lowercase English letters.
* S and T have equal lengths.
Input
Input is given from Standard Input in the following format:
S
T
Output
Print the answer.
Examples
Input
cupofcoffee
cupofhottea
Output
4
Input
abcde
bcdea
Output
5
Input
apple
apple
Output
0
Submitted Solution:
```
s = input()
t = input()
result = len([a,b for a,b in zip(s,t) if a != b])
print(result)
``` | instruction | 0 | 23,570 | 18 | 47,140 |
No | output | 1 | 23,570 | 18 | 47,141 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are strings S and T. Consider changing S to T by repeating the operation below. Find the minimum number of operations required to do so.
Operation: Choose one character of S and replace it with a different character.
Constraints
* S and T have lengths between 1 and 2\times 10^5 (inclusive).
* S and T consists of lowercase English letters.
* S and T have equal lengths.
Input
Input is given from Standard Input in the following format:
S
T
Output
Print the answer.
Examples
Input
cupofcoffee
cupofhottea
Output
4
Input
abcde
bcdea
Output
5
Input
apple
apple
Output
0
Submitted Solution:
```
line1 = input()
line2 = input()
ans = 0
for i in range(len(line1)):
if line1[i] == line2[i]:
ans += 1
print(ans)
``` | instruction | 0 | 23,571 | 18 | 47,142 |
No | output | 1 | 23,571 | 18 | 47,143 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are strings S and T. Consider changing S to T by repeating the operation below. Find the minimum number of operations required to do so.
Operation: Choose one character of S and replace it with a different character.
Constraints
* S and T have lengths between 1 and 2\times 10^5 (inclusive).
* S and T consists of lowercase English letters.
* S and T have equal lengths.
Input
Input is given from Standard Input in the following format:
S
T
Output
Print the answer.
Examples
Input
cupofcoffee
cupofhottea
Output
4
Input
abcde
bcdea
Output
5
Input
apple
apple
Output
0
Submitted Solution:
```
s = input()
t = input()
a = 0
for i in range(len(s)):
if s[i] == t[i]:a = a + 1
print(a)
``` | instruction | 0 | 23,572 | 18 | 47,144 |
No | output | 1 | 23,572 | 18 | 47,145 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are strings S and T. Consider changing S to T by repeating the operation below. Find the minimum number of operations required to do so.
Operation: Choose one character of S and replace it with a different character.
Constraints
* S and T have lengths between 1 and 2\times 10^5 (inclusive).
* S and T consists of lowercase English letters.
* S and T have equal lengths.
Input
Input is given from Standard Input in the following format:
S
T
Output
Print the answer.
Examples
Input
cupofcoffee
cupofhottea
Output
4
Input
abcde
bcdea
Output
5
Input
apple
apple
Output
0
Submitted Solution:
```
s = input()
t = input()
ans = 0
for i in xrange(len(s)):
if s[i] != t[i]:
ans += 1
print(ans)
``` | instruction | 0 | 23,573 | 18 | 47,146 |
No | output | 1 | 23,573 | 18 | 47,147 |
Provide a correct Python 3 solution for this coding contest problem.
Meikyokan University is very famous for its research and education in the area of computer science. This university has a computer center that has advanced and secure computing facilities including supercomputers and many personal computers connected to the Internet.
One of the policies of the computer center is to let the students select their own login names. Unfortunately, students are apt to select similar login names, and troubles caused by mistakes in entering or specifying login names are relatively common. These troubles are a burden on the staff of the computer center.
To avoid such troubles, Dr. Choei Takano, the chief manager of the computer center, decided to stamp out similar and confusing login names. To this end, Takano has to develop a program that detects confusing login names.
Based on the following four operations on strings, the distance between two login names is determined as the minimum number of operations that transforms one login name to the other.
1. Deleting a character at an arbitrary position.
2. Inserting a character into an arbitrary position.
3. Replacing a character at an arbitrary position with another character.
4. Swapping two adjacent characters at an arbitrary position.
For example, the distance between “omura” and “murai” is two, because the following sequence of operations transforms “omura” to “murai”.
delete ‘o’ insert ‘i’
omura --> mura --> murai
Another example is that the distance between “akasan” and “kaason” is also two.
swap ‘a’ and ‘k’ replace ‘a’ with ‘o’
akasan --> kaasan --> kaason
Takano decided that two login names with a small distance are confusing and thus must be avoided.
Your job is to write a program that enumerates all the confusing pairs of login names.
Beware that the rules may combine in subtle ways. For instance, the distance between “ant” and “neat” is two.
swap ‘a’ and ‘n’ insert ‘e’
ant --> nat --> neat
Input
The input consists of multiple datasets. Each dataset is given in the following format.
n
d
name1
name2
...
namen
The first integer n is the number of login names. Then comes a positive integer d. Two login names whose distance is less than or equal to d are deemed to be confusing. You may assume that 0 < n ≤ 200 and 0 < d ≤ 2. The i-th student’s login name is given by namei, which is composed of only lowercase letters. Its length is less than 16. You can assume that there are no duplicates in namei (1 ≤ i ≤ n).
The end of the input is indicated by a line that solely contains a zero.
Output
For each dataset, your program should output all pairs of confusing login names, one pair per line, followed by the total number of confusing pairs in the dataset.
In each pair, the two login names are to be separated only by a comma character (,), and the login name that is alphabetically preceding the other should appear first. The entire output of confusing pairs for each dataset must be sorted as follows. For two pairs “w1,w2” and “w3,w4”, if w1 alphabetically precedes w3, or they are the same and w2 precedes w4, then “w1,w2” must appear before “w3,w4”.
Example
Input
8
2
omura
toshio
raku
tanaka
imura
yoshoi
hayashi
miura
3
1
tasaka
nakata
tanaka
1
1
foo
5
2
psqt
abcdef
abzdefa
pqrst
abdxcef
0
Output
imura,miura
imura,omura
miura,omura
toshio,yoshoi
4
tanaka,tasaka
1
0
abcdef,abdxcef
abcdef,abzdefa
pqrst,psqt
3 | instruction | 0 | 23,773 | 18 | 47,546 |
"Correct Solution:
```
from collections import Counter
from itertools import permutations
import sys
readline = sys.stdin.readline
write = sys.stdout.write
def solve():
N = int(readline())
if N == 0:
return False
def dist(a, b):
LA = len(a); LB = len(b)
dp = [[10**18]*(LB+1) for i in range(LA+1)]
dp[0][0] = 0
for i in range(LA):
for j in range(LB):
v = dp[i][j]
if a[i] == b[j]:
dp[i+1][j+1] = min(dp[i+1][j+1], v)
else:
dp[i+1][j+1] = min(dp[i+1][j+1], v+1)
dp[i+1][j] = min(dp[i+1][j], v+1)
dp[i][j+1] = min(dp[i][j+1], v+1)
dp[i+1][LB] = min(dp[i+1][LB], dp[i][LB]+1)
for j in range(LB):
dp[LA][j+1] = min(dp[LA][j+1], dp[LA][j] + 1)
return dp[LA][LB]
def check(a, b):
LA = len(a); LB = len(b)
if abs(LA - LB) > D:
return False
d = dist(a, b)
if d <= D:
return True
if d == 2 and LA == LB:
ra = []; rb = []; rp = []
for i in range(LA):
if a[i] != b[i]:
rp.append(i)
ra.append(a[i])
rb.append(b[i])
if len(rp) == 2 and rp[1] - rp[0] == 1:
ra.reverse()
if ra == rb:
return True
if D == 2:
if d == 4 and LA == LB:
ra = []; rb = []; rp = []
for i in range(LA):
if a[i] != b[i]:
rp.append(i)
ra.append(a[i])
rb.append(b[i])
if len(rp) == 4 and rp[1] - rp[0] == 1 and rp[3] - rp[2] == 1:
ra[0], ra[1] = ra[1], ra[0]
ra[2], ra[3] = ra[3], ra[2]
return ra == rb
if d == 3 and abs(LA - LB) < D:
a = list(a); b = list(b)
if not LA < LB:
LA, LB = LB, LA
a, b = b, a
for i in range(LA-1):
a[i], a[i+1] = a[i+1], a[i]
if dist(a, b) <= D-1:
return True
for j in range(LA-1):
a[j], a[j+1] = a[j+1], a[j]
if a == b:
return True
a[j], a[j+1] = a[j+1], a[j]
a[i], a[i+1] = a[i+1], a[i]
return False
D = int(readline())
S = [readline().strip() for i in range(N)]
ans = []
for i in range(N):
for j in range(i+1, N):
if check(S[i], S[j]):
ans.append((S[i], S[j]) if S[i] < S[j] else (S[j], S[i]))
ans.sort()
for e in ans:
write("%s,%s\n" % e)
write("%d\n" % len(ans))
return True
while solve():
...
``` | output | 1 | 23,773 | 18 | 47,547 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.
Constraints
* The number of characters in the sentence < 1200
Input
A sentence in English is given in several lines.
Output
Prints the number of alphabetical letters in the following format:
a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'
Example
Input
This is a pen.
Output
a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0 | instruction | 0 | 23,815 | 18 | 47,630 |
"Correct Solution:
```
import sys
alphabet = "abcdefghijklmnopqrstuvwxyz"
string = sys.stdin.read()
for s in alphabet:
print(s+" : "+str(string.lower().count(s)))
``` | output | 1 | 23,815 | 18 | 47,631 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.
Constraints
* The number of characters in the sentence < 1200
Input
A sentence in English is given in several lines.
Output
Prints the number of alphabetical letters in the following format:
a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'
Example
Input
This is a pen.
Output
a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0 | instruction | 0 | 23,816 | 18 | 47,632 |
"Correct Solution:
```
import sys
s=sys.stdin.read().lower()
for i in range(26):
s.count(chr(97+i))
print(chr(97+i)+" : "+str(s.count(chr(97+i))))
``` | output | 1 | 23,816 | 18 | 47,633 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.
Constraints
* The number of characters in the sentence < 1200
Input
A sentence in English is given in several lines.
Output
Prints the number of alphabetical letters in the following format:
a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'
Example
Input
This is a pen.
Output
a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0 | instruction | 0 | 23,817 | 18 | 47,634 |
"Correct Solution:
```
sm = ""
while True:
try:
sm += input().lower()
except:
break
for i in 'abcdefghijklmnopqrstuvwxyz':
print('{} : {}'.format(i, sm.count(i)))
``` | output | 1 | 23,817 | 18 | 47,635 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.
Constraints
* The number of characters in the sentence < 1200
Input
A sentence in English is given in several lines.
Output
Prints the number of alphabetical letters in the following format:
a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'
Example
Input
This is a pen.
Output
a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0 | instruction | 0 | 23,818 | 18 | 47,636 |
"Correct Solution:
```
s = ""
try:
while True:
s += input().lower()
except:
pass
for i in range(ord("a"),ord("z")+1):
print(chr(i)+" : "+str(s.count(chr(i))))
``` | output | 1 | 23,818 | 18 | 47,637 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.
Constraints
* The number of characters in the sentence < 1200
Input
A sentence in English is given in several lines.
Output
Prints the number of alphabetical letters in the following format:
a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'
Example
Input
This is a pen.
Output
a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0 | instruction | 0 | 23,819 | 18 | 47,638 |
"Correct Solution:
```
import sys
cnts = []
alpha = "abcdefghijklmnopqrstuvwxyz"
for line in sys.stdin:
for c in list(line.lower()):
cnts.append(c)
for a in alpha:
print("{} : {}".format(a,cnts.count(a)))
``` | output | 1 | 23,819 | 18 | 47,639 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.
Constraints
* The number of characters in the sentence < 1200
Input
A sentence in English is given in several lines.
Output
Prints the number of alphabetical letters in the following format:
a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'
Example
Input
This is a pen.
Output
a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0 | instruction | 0 | 23,820 | 18 | 47,640 |
"Correct Solution:
```
import sys
char = "abcdefghijklmnopqrstuvwxyz"
inp = sys.stdin.read()
for char_tmp in char:
print(char_tmp + ' : ' + str(inp.lower().count(char_tmp)))
``` | output | 1 | 23,820 | 18 | 47,641 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.
Constraints
* The number of characters in the sentence < 1200
Input
A sentence in English is given in several lines.
Output
Prints the number of alphabetical letters in the following format:
a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'
Example
Input
This is a pen.
Output
a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0 | instruction | 0 | 23,821 | 18 | 47,642 |
"Correct Solution:
```
alpha = 'abcdefghijklmnopqrstuvwxyz'
text = ''
while True:
try:
text += input().lower()
except EOFError:
break
for a in alpha:
print('{} : {}'.format(a, text.count(a)))
``` | output | 1 | 23,821 | 18 | 47,643 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.
Constraints
* The number of characters in the sentence < 1200
Input
A sentence in English is given in several lines.
Output
Prints the number of alphabetical letters in the following format:
a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'
Example
Input
This is a pen.
Output
a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0 | instruction | 0 | 23,822 | 18 | 47,644 |
"Correct Solution:
```
s=""
while True:
try:
s += input().lower()
except:
break
for c in 'abcdefghijklmnopqrstuvwxyz':
print(c,':',s.count(c))
``` | output | 1 | 23,822 | 18 | 47,645 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.
Constraints
* The number of characters in the sentence < 1200
Input
A sentence in English is given in several lines.
Output
Prints the number of alphabetical letters in the following format:
a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'
Example
Input
This is a pen.
Output
a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0
Submitted Solution:
```
import re
import string
import sys
s = sys.stdin.read()
s = re.sub(r"[^a-z]", "", s.lower())
s = list(s)
for a in string.ascii_lowercase:
print(f"{a} : {s.count(a)}")
``` | instruction | 0 | 23,823 | 18 | 47,646 |
Yes | output | 1 | 23,823 | 18 | 47,647 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.
Constraints
* The number of characters in the sentence < 1200
Input
A sentence in English is given in several lines.
Output
Prints the number of alphabetical letters in the following format:
a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'
Example
Input
This is a pen.
Output
a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0
Submitted Solution:
```
import sys
cnt = {}
for e in sys.stdin:
for c in list(e.lower()):
cnt[c] = cnt.get(c, 0) + 1
for c in range(ord('a'), ord('z')+1):
print(chr(c), ':', cnt.get(chr(c), 0))
``` | instruction | 0 | 23,824 | 18 | 47,648 |
Yes | output | 1 | 23,824 | 18 | 47,649 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.
Constraints
* The number of characters in the sentence < 1200
Input
A sentence in English is given in several lines.
Output
Prints the number of alphabetical letters in the following format:
a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'
Example
Input
This is a pen.
Output
a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0
Submitted Solution:
```
import sys
ch = sys.stdin.read().lower()
for i in range(97, 123):
print(chr(i), ':', ch.count(chr(i)))
``` | instruction | 0 | 23,825 | 18 | 47,650 |
Yes | output | 1 | 23,825 | 18 | 47,651 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.
Constraints
* The number of characters in the sentence < 1200
Input
A sentence in English is given in several lines.
Output
Prints the number of alphabetical letters in the following format:
a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'
Example
Input
This is a pen.
Output
a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0
Submitted Solution:
```
import sys
str = ""
for e in sys.stdin:
str += e
alphabets = "abcdefghijklmnopqrstuvwxyz"
for c in list(alphabets):
print("{} : {}".format(c, list(str.lower()).count(c)))
``` | instruction | 0 | 23,826 | 18 | 47,652 |
Yes | output | 1 | 23,826 | 18 | 47,653 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.
Constraints
* The number of characters in the sentence < 1200
Input
A sentence in English is given in several lines.
Output
Prints the number of alphabetical letters in the following format:
a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'
Example
Input
This is a pen.
Output
a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0
Submitted Solution:
```
a = {x:0 for x in range(ord('a'), ord('z') + 1)}
while True:
text = input()
if text == ' ':
break
for x in text:
a[ord(x.lower())] += 1
for x in range(ord('a'), ord('z') + 1):
print(chr(x), ':', a[x])
``` | instruction | 0 | 23,827 | 18 | 47,654 |
No | output | 1 | 23,827 | 18 | 47,655 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.
Constraints
* The number of characters in the sentence < 1200
Input
A sentence in English is given in several lines.
Output
Prints the number of alphabetical letters in the following format:
a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'
Example
Input
This is a pen.
Output
a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0
Submitted Solution:
```
bigALlist = list('ABCDEFGHIJKLMNOPQRSTUVWXYZ')
smoALlist = list('abcdefghijklmnopqrstuvwxyz')
cnt = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
while True:
try:
text = list(input())
for j in range(len(bigALlist)):
cnt = 0
for i in text:
if (bigALlist[j] in i) or (smoALlist[j] in i):
cnt = cnt + 1
print('{0} : {1}'.format(smoALlist[j],cnt))
except EOFError:
break
``` | instruction | 0 | 23,828 | 18 | 47,656 |
No | output | 1 | 23,828 | 18 | 47,657 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.
Constraints
* The number of characters in the sentence < 1200
Input
A sentence in English is given in several lines.
Output
Prints the number of alphabetical letters in the following format:
a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'
Example
Input
This is a pen.
Output
a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0
Submitted Solution:
```
import string
alphabets = {k:0 for k in string.ascii_lowercase}
for c in input().lower():
if alphabets.get(c) is None:
continue
alphabets[c] += 1
for c, n in sorted(alphabets.items()):
print("{} : {}".format(c, n))
``` | instruction | 0 | 23,829 | 18 | 47,658 |
No | output | 1 | 23,829 | 18 | 47,659 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.
Constraints
* The number of characters in the sentence < 1200
Input
A sentence in English is given in several lines.
Output
Prints the number of alphabetical letters in the following format:
a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'
Example
Input
This is a pen.
Output
a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0
Submitted Solution:
```
s=input().lower()
str=list(s)
for i in range(97,97+26):
count=0
for j in str:
if chr(i)==j:
count+=1
print(chr(i),':',count)
``` | instruction | 0 | 23,830 | 18 | 47,660 |
No | output | 1 | 23,830 | 18 | 47,661 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is working on a new operating system called BerOS. He asks you to help with implementation of a file suggestion feature.
There are n files on hard drive and their names are f_1, f_2, ..., f_n. Any file name contains between 1 and 8 characters, inclusive. All file names are unique.
The file suggestion feature handles queries, each represented by a string s. For each query s it should count number of files containing s as a substring (i.e. some continuous segment of characters in a file name equals s) and suggest any such file name.
For example, if file names are "read.me", "hosts", "ops", and "beros.18", and the query is "os", the number of matched files is 2 (two file names contain "os" as a substring) and suggested file name can be either "hosts" or "beros.18".
Input
The first line of the input contains integer n (1 ≤ n ≤ 10000) — the total number of files.
The following n lines contain file names, one per line. The i-th line contains f_i — the name of the i-th file. Each file name contains between 1 and 8 characters, inclusive. File names contain only lowercase Latin letters, digits and dot characters ('.'). Any sequence of valid characters can be a file name (for example, in BerOS ".", ".." and "..." are valid file names). All file names are unique.
The following line contains integer q (1 ≤ q ≤ 50000) — the total number of queries.
The following q lines contain queries s_1, s_2, ..., s_q, one per line. Each s_j has length between 1 and 8 characters, inclusive. It contains only lowercase Latin letters, digits and dot characters ('.').
Output
Print q lines, one per query. The j-th line should contain the response on the j-th query — two values c_j and t_j, where
* c_j is the number of matched files for the j-th query,
* t_j is the name of any file matched by the j-th query. If there is no such file, print a single character '-' instead. If there are multiple matched files, print any.
Example
Input
4
test
contests
test.
.test
6
ts
.
st.
.test
contes.
st
Output
1 contests
2 .test
1 test.
1 .test
0 -
4 test.
Submitted Solution:
```
#!/usr/bin/env python3
import collections
import sys
import traceback
class Input(object):
def __init__(self):
self.fh = sys.stdin
def next_line(self):
while True:
line = sys.stdin.readline()
if line == '\n':
continue
return line
def next_line_ints(self):
line = self.next_line()
return [int(x) for x in line.split()]
def next_line_strs(self):
line = self.next_line()
return line.split()
class TrieNode(object):
def __init__(self):
self.children = {} # child nodes
self.match_count = 0
self.first_match_file_id = -1
self.last_add_file_id = -1
def get_child(self, ch):
if ch in self.children:
return self.children[ch]
child = TrieNode()
self.children[ch] = child
return child
def build_trie(files):
trie = TrieNode()
for i in range(len(files)):
s = files[i]
for start in range(0, len(s)):
node = trie
while start < len(s):
node = node.get_child(s[start])
if node.last_add_file_id != i:
node.match_count += 1
node.last_add_file_id = i
if node.first_match_file_id == -1:
node.first_match_file_id = i
start += 1
return trie
def find_match(trie, query):
"""Return match count and any_match_file_id"""
node = trie
for ch in query:
if ch in node.children:
node = node.children[ch]
else:
node = None
break
if node is None:
return 0, None
return node.match_count, node.first_match_file_id
def main():
input = Input()
while True:
try:
nums = input.next_line_ints()
if not nums:
break
n, = nums
if n == -1:
break
files = []
for _ in range(n):
files.append(input.next_line_strs()[0])
q = input.next_line_ints()[0]
queries = []
for _ in range(q):
queries.append(input.next_line_strs()[0])
except:
print('read input failed')
try:
trie = build_trie(files)
for q in queries:
count, any_file_id = find_match(trie, q)
if count == 0:
print("0 -")
else:
print("{} {}".format(count, files[any_file_id]))
except:
traceback.print_exc(file=sys.stdout)
print('get_min_dist failed')
main()
``` | instruction | 0 | 23,873 | 18 | 47,746 |
Yes | output | 1 | 23,873 | 18 | 47,747 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is working on a new operating system called BerOS. He asks you to help with implementation of a file suggestion feature.
There are n files on hard drive and their names are f_1, f_2, ..., f_n. Any file name contains between 1 and 8 characters, inclusive. All file names are unique.
The file suggestion feature handles queries, each represented by a string s. For each query s it should count number of files containing s as a substring (i.e. some continuous segment of characters in a file name equals s) and suggest any such file name.
For example, if file names are "read.me", "hosts", "ops", and "beros.18", and the query is "os", the number of matched files is 2 (two file names contain "os" as a substring) and suggested file name can be either "hosts" or "beros.18".
Input
The first line of the input contains integer n (1 ≤ n ≤ 10000) — the total number of files.
The following n lines contain file names, one per line. The i-th line contains f_i — the name of the i-th file. Each file name contains between 1 and 8 characters, inclusive. File names contain only lowercase Latin letters, digits and dot characters ('.'). Any sequence of valid characters can be a file name (for example, in BerOS ".", ".." and "..." are valid file names). All file names are unique.
The following line contains integer q (1 ≤ q ≤ 50000) — the total number of queries.
The following q lines contain queries s_1, s_2, ..., s_q, one per line. Each s_j has length between 1 and 8 characters, inclusive. It contains only lowercase Latin letters, digits and dot characters ('.').
Output
Print q lines, one per query. The j-th line should contain the response on the j-th query — two values c_j and t_j, where
* c_j is the number of matched files for the j-th query,
* t_j is the name of any file matched by the j-th query. If there is no such file, print a single character '-' instead. If there are multiple matched files, print any.
Example
Input
4
test
contests
test.
.test
6
ts
.
st.
.test
contes.
st
Output
1 contests
2 .test
1 test.
1 .test
0 -
4 test.
Submitted Solution:
```
n = int(input())
dictionary={}
file = []
query = []
for _ in range(n):
file.append(input())
m = int(input())
for _ in range(m):
query.append(input())
for index in range(n):
for i in range(len(file[index])):
for j in range(i+1,len(file[index])+1):
temp=file[index][i:j]
if temp not in dictionary:
dictionary[temp]=set()
dictionary[temp].add(index)
for i in range(m):
if query[i] in dictionary:
for s in dictionary[query[i]]:
print(len(dictionary[query[i]]), file[s])
break
else:
print(0,'-')
``` | instruction | 0 | 23,874 | 18 | 47,748 |
Yes | output | 1 | 23,874 | 18 | 47,749 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is working on a new operating system called BerOS. He asks you to help with implementation of a file suggestion feature.
There are n files on hard drive and their names are f_1, f_2, ..., f_n. Any file name contains between 1 and 8 characters, inclusive. All file names are unique.
The file suggestion feature handles queries, each represented by a string s. For each query s it should count number of files containing s as a substring (i.e. some continuous segment of characters in a file name equals s) and suggest any such file name.
For example, if file names are "read.me", "hosts", "ops", and "beros.18", and the query is "os", the number of matched files is 2 (two file names contain "os" as a substring) and suggested file name can be either "hosts" or "beros.18".
Input
The first line of the input contains integer n (1 ≤ n ≤ 10000) — the total number of files.
The following n lines contain file names, one per line. The i-th line contains f_i — the name of the i-th file. Each file name contains between 1 and 8 characters, inclusive. File names contain only lowercase Latin letters, digits and dot characters ('.'). Any sequence of valid characters can be a file name (for example, in BerOS ".", ".." and "..." are valid file names). All file names are unique.
The following line contains integer q (1 ≤ q ≤ 50000) — the total number of queries.
The following q lines contain queries s_1, s_2, ..., s_q, one per line. Each s_j has length between 1 and 8 characters, inclusive. It contains only lowercase Latin letters, digits and dot characters ('.').
Output
Print q lines, one per query. The j-th line should contain the response on the j-th query — two values c_j and t_j, where
* c_j is the number of matched files for the j-th query,
* t_j is the name of any file matched by the j-th query. If there is no such file, print a single character '-' instead. If there are multiple matched files, print any.
Example
Input
4
test
contests
test.
.test
6
ts
.
st.
.test
contes.
st
Output
1 contests
2 .test
1 test.
1 .test
0 -
4 test.
Submitted Solution:
```
def main():
n = int(input())
d = [{},{},{},{},{},{},{},{}]
for i in range(n):
s = input()
l = len(s)
for b in range(1,l + 1):
for tmp in set([s[a-b:a] for a in range(b, l + 1)]):
if tmp in d[b-1]:
d[b-1][tmp][0] += 1
else:
d[b-1][tmp] = [1, s]
q = int(input())
for i in range(q):
s = input()
l = len(s)
if s in d[l-1]:
print(' '.join(str(x) for x in d[l-1][s]))
else:
print('0 -')
main()
``` | instruction | 0 | 23,875 | 18 | 47,750 |
Yes | output | 1 | 23,875 | 18 | 47,751 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is working on a new operating system called BerOS. He asks you to help with implementation of a file suggestion feature.
There are n files on hard drive and their names are f_1, f_2, ..., f_n. Any file name contains between 1 and 8 characters, inclusive. All file names are unique.
The file suggestion feature handles queries, each represented by a string s. For each query s it should count number of files containing s as a substring (i.e. some continuous segment of characters in a file name equals s) and suggest any such file name.
For example, if file names are "read.me", "hosts", "ops", and "beros.18", and the query is "os", the number of matched files is 2 (two file names contain "os" as a substring) and suggested file name can be either "hosts" or "beros.18".
Input
The first line of the input contains integer n (1 ≤ n ≤ 10000) — the total number of files.
The following n lines contain file names, one per line. The i-th line contains f_i — the name of the i-th file. Each file name contains between 1 and 8 characters, inclusive. File names contain only lowercase Latin letters, digits and dot characters ('.'). Any sequence of valid characters can be a file name (for example, in BerOS ".", ".." and "..." are valid file names). All file names are unique.
The following line contains integer q (1 ≤ q ≤ 50000) — the total number of queries.
The following q lines contain queries s_1, s_2, ..., s_q, one per line. Each s_j has length between 1 and 8 characters, inclusive. It contains only lowercase Latin letters, digits and dot characters ('.').
Output
Print q lines, one per query. The j-th line should contain the response on the j-th query — two values c_j and t_j, where
* c_j is the number of matched files for the j-th query,
* t_j is the name of any file matched by the j-th query. If there is no such file, print a single character '-' instead. If there are multiple matched files, print any.
Example
Input
4
test
contests
test.
.test
6
ts
.
st.
.test
contes.
st
Output
1 contests
2 .test
1 test.
1 .test
0 -
4 test.
Submitted Solution:
```
n = int(input())
a = []
for i in range(n):
a.append(input().strip())
class Value:
def __init__(self, owner):
self.cnt = 1
self.owner = owner
m = {}
for s in a:
for i in range(0, len(s)):
for j in range(i, len(s)):
sub = s[i:j+1]
if sub in m:
m[sub].add(s)
else:
m[sub] = {s}
q = int(input())
for i in range(q):
sub = input().strip()
if sub in m:
print(len(m[sub]), next(iter(m[sub])))
else:
print(0, '-')
``` | instruction | 0 | 23,876 | 18 | 47,752 |
Yes | output | 1 | 23,876 | 18 | 47,753 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is working on a new operating system called BerOS. He asks you to help with implementation of a file suggestion feature.
There are n files on hard drive and their names are f_1, f_2, ..., f_n. Any file name contains between 1 and 8 characters, inclusive. All file names are unique.
The file suggestion feature handles queries, each represented by a string s. For each query s it should count number of files containing s as a substring (i.e. some continuous segment of characters in a file name equals s) and suggest any such file name.
For example, if file names are "read.me", "hosts", "ops", and "beros.18", and the query is "os", the number of matched files is 2 (two file names contain "os" as a substring) and suggested file name can be either "hosts" or "beros.18".
Input
The first line of the input contains integer n (1 ≤ n ≤ 10000) — the total number of files.
The following n lines contain file names, one per line. The i-th line contains f_i — the name of the i-th file. Each file name contains between 1 and 8 characters, inclusive. File names contain only lowercase Latin letters, digits and dot characters ('.'). Any sequence of valid characters can be a file name (for example, in BerOS ".", ".." and "..." are valid file names). All file names are unique.
The following line contains integer q (1 ≤ q ≤ 50000) — the total number of queries.
The following q lines contain queries s_1, s_2, ..., s_q, one per line. Each s_j has length between 1 and 8 characters, inclusive. It contains only lowercase Latin letters, digits and dot characters ('.').
Output
Print q lines, one per query. The j-th line should contain the response on the j-th query — two values c_j and t_j, where
* c_j is the number of matched files for the j-th query,
* t_j is the name of any file matched by the j-th query. If there is no such file, print a single character '-' instead. If there are multiple matched files, print any.
Example
Input
4
test
contests
test.
.test
6
ts
.
st.
.test
contes.
st
Output
1 contests
2 .test
1 test.
1 .test
0 -
4 test.
Submitted Solution:
```
n = int(input())
dic = {}
for i in range(0,n):
s = input()
for j in range(0,len(s)):
for k in range(j+1,len(s)+1):
if s[j:k] not in dic:
dic[s[j:k]] = [s,1]
else:
dic[s[j:k]][1] += 1
for _ in range(0,int(input())):
ss = input()
if ss in dic:
print(dic[ss][1],dic[ss][0])
else:
print(0,"-")
``` | instruction | 0 | 23,877 | 18 | 47,754 |
No | output | 1 | 23,877 | 18 | 47,755 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is working on a new operating system called BerOS. He asks you to help with implementation of a file suggestion feature.
There are n files on hard drive and their names are f_1, f_2, ..., f_n. Any file name contains between 1 and 8 characters, inclusive. All file names are unique.
The file suggestion feature handles queries, each represented by a string s. For each query s it should count number of files containing s as a substring (i.e. some continuous segment of characters in a file name equals s) and suggest any such file name.
For example, if file names are "read.me", "hosts", "ops", and "beros.18", and the query is "os", the number of matched files is 2 (two file names contain "os" as a substring) and suggested file name can be either "hosts" or "beros.18".
Input
The first line of the input contains integer n (1 ≤ n ≤ 10000) — the total number of files.
The following n lines contain file names, one per line. The i-th line contains f_i — the name of the i-th file. Each file name contains between 1 and 8 characters, inclusive. File names contain only lowercase Latin letters, digits and dot characters ('.'). Any sequence of valid characters can be a file name (for example, in BerOS ".", ".." and "..." are valid file names). All file names are unique.
The following line contains integer q (1 ≤ q ≤ 50000) — the total number of queries.
The following q lines contain queries s_1, s_2, ..., s_q, one per line. Each s_j has length between 1 and 8 characters, inclusive. It contains only lowercase Latin letters, digits and dot characters ('.').
Output
Print q lines, one per query. The j-th line should contain the response on the j-th query — two values c_j and t_j, where
* c_j is the number of matched files for the j-th query,
* t_j is the name of any file matched by the j-th query. If there is no such file, print a single character '-' instead. If there are multiple matched files, print any.
Example
Input
4
test
contests
test.
.test
6
ts
.
st.
.test
contes.
st
Output
1 contests
2 .test
1 test.
1 .test
0 -
4 test.
Submitted Solution:
```
n = int(input())
f = []
for i in range(0, n):
f.append(str(input()))
q = int(input())
s = {}
for i in range(0, q):
s[str(input())] = [0, "-"]
for fn in f:
for k in s.keys():
if (fn.find(k) != -1):
s[k][0] += 1
if (s[k][1] == "-"):
s[k][1] = fn
for a in s.values():
print(a[0], a[1])
``` | instruction | 0 | 23,878 | 18 | 47,756 |
No | output | 1 | 23,878 | 18 | 47,757 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is working on a new operating system called BerOS. He asks you to help with implementation of a file suggestion feature.
There are n files on hard drive and their names are f_1, f_2, ..., f_n. Any file name contains between 1 and 8 characters, inclusive. All file names are unique.
The file suggestion feature handles queries, each represented by a string s. For each query s it should count number of files containing s as a substring (i.e. some continuous segment of characters in a file name equals s) and suggest any such file name.
For example, if file names are "read.me", "hosts", "ops", and "beros.18", and the query is "os", the number of matched files is 2 (two file names contain "os" as a substring) and suggested file name can be either "hosts" or "beros.18".
Input
The first line of the input contains integer n (1 ≤ n ≤ 10000) — the total number of files.
The following n lines contain file names, one per line. The i-th line contains f_i — the name of the i-th file. Each file name contains between 1 and 8 characters, inclusive. File names contain only lowercase Latin letters, digits and dot characters ('.'). Any sequence of valid characters can be a file name (for example, in BerOS ".", ".." and "..." are valid file names). All file names are unique.
The following line contains integer q (1 ≤ q ≤ 50000) — the total number of queries.
The following q lines contain queries s_1, s_2, ..., s_q, one per line. Each s_j has length between 1 and 8 characters, inclusive. It contains only lowercase Latin letters, digits and dot characters ('.').
Output
Print q lines, one per query. The j-th line should contain the response on the j-th query — two values c_j and t_j, where
* c_j is the number of matched files for the j-th query,
* t_j is the name of any file matched by the j-th query. If there is no such file, print a single character '-' instead. If there are multiple matched files, print any.
Example
Input
4
test
contests
test.
.test
6
ts
.
st.
.test
contes.
st
Output
1 contests
2 .test
1 test.
1 .test
0 -
4 test.
Submitted Solution:
```
d = {}
n = int(input())
for _ in range(n):
s = input()
for i in range(len(s)):
curr = ''
for j in range(i,len(s)):
curr += s[j]
if curr in d.keys():
d[curr][0] += 1
else:
d[curr] = [1,s]
#print(d)
q = int(input())
for _ in range(q):
s = input()
if s in d.keys():
print(d[s][0],d[s][1])
else:
print(0,'-')
``` | instruction | 0 | 23,879 | 18 | 47,758 |
No | output | 1 | 23,879 | 18 | 47,759 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is working on a new operating system called BerOS. He asks you to help with implementation of a file suggestion feature.
There are n files on hard drive and their names are f_1, f_2, ..., f_n. Any file name contains between 1 and 8 characters, inclusive. All file names are unique.
The file suggestion feature handles queries, each represented by a string s. For each query s it should count number of files containing s as a substring (i.e. some continuous segment of characters in a file name equals s) and suggest any such file name.
For example, if file names are "read.me", "hosts", "ops", and "beros.18", and the query is "os", the number of matched files is 2 (two file names contain "os" as a substring) and suggested file name can be either "hosts" or "beros.18".
Input
The first line of the input contains integer n (1 ≤ n ≤ 10000) — the total number of files.
The following n lines contain file names, one per line. The i-th line contains f_i — the name of the i-th file. Each file name contains between 1 and 8 characters, inclusive. File names contain only lowercase Latin letters, digits and dot characters ('.'). Any sequence of valid characters can be a file name (for example, in BerOS ".", ".." and "..." are valid file names). All file names are unique.
The following line contains integer q (1 ≤ q ≤ 50000) — the total number of queries.
The following q lines contain queries s_1, s_2, ..., s_q, one per line. Each s_j has length between 1 and 8 characters, inclusive. It contains only lowercase Latin letters, digits and dot characters ('.').
Output
Print q lines, one per query. The j-th line should contain the response on the j-th query — two values c_j and t_j, where
* c_j is the number of matched files for the j-th query,
* t_j is the name of any file matched by the j-th query. If there is no such file, print a single character '-' instead. If there are multiple matched files, print any.
Example
Input
4
test
contests
test.
.test
6
ts
.
st.
.test
contes.
st
Output
1 contests
2 .test
1 test.
1 .test
0 -
4 test.
Submitted Solution:
```
t = int(input())
l = []
for i in range(t):
l.append(str(input()))
q = int(input())
l1 = []
for i in range(q):
l1.append(str(input()))
cou = []
for i in range(q):
coun = 0
for j in range(t):
for k in range(len(l[j])):
if(l1[i] == l[j][k:len(l1[i])+k]):
coun += 1
cou.append(coun)
for i in range(q):
print(cou[i],end=' ')
if(cou[i]==0):
print("-")
else:
print(l1[i])
``` | instruction | 0 | 23,880 | 18 | 47,760 |
No | output | 1 | 23,880 | 18 | 47,761 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Haiku is a genre of Japanese traditional poetry.
A haiku poem consists of 17 syllables split into three phrases, containing 5, 7 and 5 syllables correspondingly (the first phrase should contain exactly 5 syllables, the second phrase should contain exactly 7 syllables, and the third phrase should contain exactly 5 syllables). A haiku masterpiece contains a description of a moment in those three phrases. Every word is important in a small poem, which is why haiku are rich with symbols. Each word has a special meaning, a special role. The main principle of haiku is to say much using a few words.
To simplify the matter, in the given problem we will consider that the number of syllable in the phrase is equal to the number of vowel letters there. Only the following letters are regarded as vowel letters: "a", "e", "i", "o" and "u".
Three phases from a certain poem are given. Determine whether it is haiku or not.
Input
The input data consists of three lines. The length of each line is between 1 and 100, inclusive. The i-th line contains the i-th phrase of the poem. Each phrase consists of one or more words, which are separated by one or more spaces. A word is a non-empty sequence of lowercase Latin letters. Leading and/or trailing spaces in phrases are allowed. Every phrase has at least one non-space character. See the example for clarification.
Output
Print "YES" (without the quotes) if the poem is a haiku. Otherwise, print "NO" (also without the quotes).
Examples
Input
on codeforces
beta round is running
a rustling of keys
Output
YES
Input
how many gallons
of edo s rain did you drink
cuckoo
Output
NO
Submitted Solution:
```
import sys
vowels = "aeiou"
def vowel_count(line):
return len([char for char in line if char in vowels])
haiku_syllables = [5, 7, 5]
for i in range(0, 3):
line = sys.stdin.readline()
if vowel_count(line) != haiku_syllables[i]:
print("NO")
exit(0)
print("YES")
``` | instruction | 0 | 24,388 | 18 | 48,776 |
Yes | output | 1 | 24,388 | 18 | 48,777 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Haiku is a genre of Japanese traditional poetry.
A haiku poem consists of 17 syllables split into three phrases, containing 5, 7 and 5 syllables correspondingly (the first phrase should contain exactly 5 syllables, the second phrase should contain exactly 7 syllables, and the third phrase should contain exactly 5 syllables). A haiku masterpiece contains a description of a moment in those three phrases. Every word is important in a small poem, which is why haiku are rich with symbols. Each word has a special meaning, a special role. The main principle of haiku is to say much using a few words.
To simplify the matter, in the given problem we will consider that the number of syllable in the phrase is equal to the number of vowel letters there. Only the following letters are regarded as vowel letters: "a", "e", "i", "o" and "u".
Three phases from a certain poem are given. Determine whether it is haiku or not.
Input
The input data consists of three lines. The length of each line is between 1 and 100, inclusive. The i-th line contains the i-th phrase of the poem. Each phrase consists of one or more words, which are separated by one or more spaces. A word is a non-empty sequence of lowercase Latin letters. Leading and/or trailing spaces in phrases are allowed. Every phrase has at least one non-space character. See the example for clarification.
Output
Print "YES" (without the quotes) if the poem is a haiku. Otherwise, print "NO" (also without the quotes).
Examples
Input
on codeforces
beta round is running
a rustling of keys
Output
YES
Input
how many gallons
of edo s rain did you drink
cuckoo
Output
NO
Submitted Solution:
```
def is_v(c):
if(c=='a' or c=='e' or c=='i' or c=='o' or c=='u'):
return 1
else:
return 0
a = input()
b = input()
c = input()
c_a = 0
c_b = 0
c_c = 0
for i in range(len(a)):
if(is_v(a[i])):
c_a+=1
for i in range(len(b)):
if(is_v(b[i])):
c_b+=1
for i in range(len(c)):
if(is_v(c[i])):
c_c+=1
if(c_a==5 and c_b==7 and c_c==5):
print("YES")
else:
print("NO")
``` | instruction | 0 | 24,389 | 18 | 48,778 |
Yes | output | 1 | 24,389 | 18 | 48,779 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Haiku is a genre of Japanese traditional poetry.
A haiku poem consists of 17 syllables split into three phrases, containing 5, 7 and 5 syllables correspondingly (the first phrase should contain exactly 5 syllables, the second phrase should contain exactly 7 syllables, and the third phrase should contain exactly 5 syllables). A haiku masterpiece contains a description of a moment in those three phrases. Every word is important in a small poem, which is why haiku are rich with symbols. Each word has a special meaning, a special role. The main principle of haiku is to say much using a few words.
To simplify the matter, in the given problem we will consider that the number of syllable in the phrase is equal to the number of vowel letters there. Only the following letters are regarded as vowel letters: "a", "e", "i", "o" and "u".
Three phases from a certain poem are given. Determine whether it is haiku or not.
Input
The input data consists of three lines. The length of each line is between 1 and 100, inclusive. The i-th line contains the i-th phrase of the poem. Each phrase consists of one or more words, which are separated by one or more spaces. A word is a non-empty sequence of lowercase Latin letters. Leading and/or trailing spaces in phrases are allowed. Every phrase has at least one non-space character. See the example for clarification.
Output
Print "YES" (without the quotes) if the poem is a haiku. Otherwise, print "NO" (also without the quotes).
Examples
Input
on codeforces
beta round is running
a rustling of keys
Output
YES
Input
how many gallons
of edo s rain did you drink
cuckoo
Output
NO
Submitted Solution:
```
d = {"a","e","i","o","u"}
for i in range(3):
count = 0
t = input()
for j in t:
if j in d:
count = count + 1
if count == 5 and i == 0 or count == 5 and i == 2:
continue
elif i == 0 or i == 2:
print("NO")
exit()
if count == 7 and i == 1:
continue
else:
print("NO")
exit()
print("YES")
``` | instruction | 0 | 24,390 | 18 | 48,780 |
Yes | output | 1 | 24,390 | 18 | 48,781 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Haiku is a genre of Japanese traditional poetry.
A haiku poem consists of 17 syllables split into three phrases, containing 5, 7 and 5 syllables correspondingly (the first phrase should contain exactly 5 syllables, the second phrase should contain exactly 7 syllables, and the third phrase should contain exactly 5 syllables). A haiku masterpiece contains a description of a moment in those three phrases. Every word is important in a small poem, which is why haiku are rich with symbols. Each word has a special meaning, a special role. The main principle of haiku is to say much using a few words.
To simplify the matter, in the given problem we will consider that the number of syllable in the phrase is equal to the number of vowel letters there. Only the following letters are regarded as vowel letters: "a", "e", "i", "o" and "u".
Three phases from a certain poem are given. Determine whether it is haiku or not.
Input
The input data consists of three lines. The length of each line is between 1 and 100, inclusive. The i-th line contains the i-th phrase of the poem. Each phrase consists of one or more words, which are separated by one or more spaces. A word is a non-empty sequence of lowercase Latin letters. Leading and/or trailing spaces in phrases are allowed. Every phrase has at least one non-space character. See the example for clarification.
Output
Print "YES" (without the quotes) if the poem is a haiku. Otherwise, print "NO" (also without the quotes).
Examples
Input
on codeforces
beta round is running
a rustling of keys
Output
YES
Input
how many gallons
of edo s rain did you drink
cuckoo
Output
NO
Submitted Solution:
```
a=list(input())
b=list(input())
c=list(input())
v =["a", "e", "i", "o","u"]
d,t,y=0,0,0
for j in a:
if j in v:
d+=1
for k in b:
if k in v:
t+=1
for s in c:
if s in v:
y+=1
if d==5 and t==7 and y==5:
print('YES')
else:
print('NO')
``` | instruction | 0 | 24,391 | 18 | 48,782 |
Yes | output | 1 | 24,391 | 18 | 48,783 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Haiku is a genre of Japanese traditional poetry.
A haiku poem consists of 17 syllables split into three phrases, containing 5, 7 and 5 syllables correspondingly (the first phrase should contain exactly 5 syllables, the second phrase should contain exactly 7 syllables, and the third phrase should contain exactly 5 syllables). A haiku masterpiece contains a description of a moment in those three phrases. Every word is important in a small poem, which is why haiku are rich with symbols. Each word has a special meaning, a special role. The main principle of haiku is to say much using a few words.
To simplify the matter, in the given problem we will consider that the number of syllable in the phrase is equal to the number of vowel letters there. Only the following letters are regarded as vowel letters: "a", "e", "i", "o" and "u".
Three phases from a certain poem are given. Determine whether it is haiku or not.
Input
The input data consists of three lines. The length of each line is between 1 and 100, inclusive. The i-th line contains the i-th phrase of the poem. Each phrase consists of one or more words, which are separated by one or more spaces. A word is a non-empty sequence of lowercase Latin letters. Leading and/or trailing spaces in phrases are allowed. Every phrase has at least one non-space character. See the example for clarification.
Output
Print "YES" (without the quotes) if the poem is a haiku. Otherwise, print "NO" (also without the quotes).
Examples
Input
on codeforces
beta round is running
a rustling of keys
Output
YES
Input
how many gallons
of edo s rain did you drink
cuckoo
Output
NO
Submitted Solution:
```
# It's all about what U BELIEVE
import sys
input = sys.stdin.readline
def gint(): return int(input())
def gint_arr(): return list(map(int, input().split()))
def gfloat(): return float(input())
def gfloat_arr(): return list(map(float, input().split()))
def pair_int(): return map(int, input().split())
###############################################################################
INF = (1 << 31)
MOD = "1000000007"
dx = [-1, 0, 1, 0]
dy = [ 0, 1, 0, -1]
############################ SOLUTION IS COMING ###############################
a = input()
b = input()
c = input()
v = ['a', 'i', 'e', 'o', 'u']
cnt = [5, 7, 5]
print("yes" if [sum(a.count(x) for x in v),
sum(b.count(x) for x in v),
sum(c.count(x) for x in v)] == cnt
else "NO"
)
``` | instruction | 0 | 24,392 | 18 | 48,784 |
No | output | 1 | 24,392 | 18 | 48,785 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Haiku is a genre of Japanese traditional poetry.
A haiku poem consists of 17 syllables split into three phrases, containing 5, 7 and 5 syllables correspondingly (the first phrase should contain exactly 5 syllables, the second phrase should contain exactly 7 syllables, and the third phrase should contain exactly 5 syllables). A haiku masterpiece contains a description of a moment in those three phrases. Every word is important in a small poem, which is why haiku are rich with symbols. Each word has a special meaning, a special role. The main principle of haiku is to say much using a few words.
To simplify the matter, in the given problem we will consider that the number of syllable in the phrase is equal to the number of vowel letters there. Only the following letters are regarded as vowel letters: "a", "e", "i", "o" and "u".
Three phases from a certain poem are given. Determine whether it is haiku or not.
Input
The input data consists of three lines. The length of each line is between 1 and 100, inclusive. The i-th line contains the i-th phrase of the poem. Each phrase consists of one or more words, which are separated by one or more spaces. A word is a non-empty sequence of lowercase Latin letters. Leading and/or trailing spaces in phrases are allowed. Every phrase has at least one non-space character. See the example for clarification.
Output
Print "YES" (without the quotes) if the poem is a haiku. Otherwise, print "NO" (also without the quotes).
Examples
Input
on codeforces
beta round is running
a rustling of keys
Output
YES
Input
how many gallons
of edo s rain did you drink
cuckoo
Output
NO
Submitted Solution:
```
a = input()
b = input()
c = input()
gl = ['a', 'e', 'u', 'o', 'i']
sp1 = a.split(" ")
sp2 = b.split(' ')
sp3 = c.split(' ')
i = 0
ii = 0
iii = 0
# слово
for elem in sp1:
for g in elem:
if g.lower() in gl:
i += 1
for elem in sp2:
for g in elem:
if g.lower() in gl:
ii += 1
for elem in sp3:
for g in elem:
if g.lower() in gl:
iii += 1
if i == 5 and ii == 7 and iii == 5:
print('Yes')
else:
print ('No')
``` | instruction | 0 | 24,393 | 18 | 48,786 |
No | output | 1 | 24,393 | 18 | 48,787 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Haiku is a genre of Japanese traditional poetry.
A haiku poem consists of 17 syllables split into three phrases, containing 5, 7 and 5 syllables correspondingly (the first phrase should contain exactly 5 syllables, the second phrase should contain exactly 7 syllables, and the third phrase should contain exactly 5 syllables). A haiku masterpiece contains a description of a moment in those three phrases. Every word is important in a small poem, which is why haiku are rich with symbols. Each word has a special meaning, a special role. The main principle of haiku is to say much using a few words.
To simplify the matter, in the given problem we will consider that the number of syllable in the phrase is equal to the number of vowel letters there. Only the following letters are regarded as vowel letters: "a", "e", "i", "o" and "u".
Three phases from a certain poem are given. Determine whether it is haiku or not.
Input
The input data consists of three lines. The length of each line is between 1 and 100, inclusive. The i-th line contains the i-th phrase of the poem. Each phrase consists of one or more words, which are separated by one or more spaces. A word is a non-empty sequence of lowercase Latin letters. Leading and/or trailing spaces in phrases are allowed. Every phrase has at least one non-space character. See the example for clarification.
Output
Print "YES" (without the quotes) if the poem is a haiku. Otherwise, print "NO" (also without the quotes).
Examples
Input
on codeforces
beta round is running
a rustling of keys
Output
YES
Input
how many gallons
of edo s rain did you drink
cuckoo
Output
NO
Submitted Solution:
```
z = q = d = 0
for _ in range(3):
k = input().split(" ")
for i in k:
for x in i:
if x == "a" or x == "i" or x == "e" or x == "o" or x == "u":
d += 1
print("YES" if d == 17 else "NO")
``` | instruction | 0 | 24,394 | 18 | 48,788 |
No | output | 1 | 24,394 | 18 | 48,789 |
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