message stringlengths 2 11.9k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 137 108k | cluster float64 18 18 | __index_level_0__ int64 274 217k |
|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
We have weather records at AtCoder Town for some consecutive three days. A string of length 3, S, represents the records - if the i-th character is `S`, it means it was sunny on the i-th day; if that character is `R`, it means it was rainy on that day.
Find the maximum number of consecutive rainy days in this period.
Constraints
* |S| = 3
* Each character of S is `S` or `R`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the maximum number of consecutive rainy days in the period.
Examples
Input
RRS
Output
2
Input
SSS
Output
0
Input
RSR
Output
1 | instruction | 0 | 4,814 | 18 | 9,628 |
"Correct Solution:
```
s=input()
print(3 if 'RRR' in s else 2 if 'RR' in s else 1 if'R' in s else 0)
``` | output | 1 | 4,814 | 18 | 9,629 |
Provide a correct Python 3 solution for this coding contest problem.
We have weather records at AtCoder Town for some consecutive three days. A string of length 3, S, represents the records - if the i-th character is `S`, it means it was sunny on the i-th day; if that character is `R`, it means it was rainy on that day.
Find the maximum number of consecutive rainy days in this period.
Constraints
* |S| = 3
* Each character of S is `S` or `R`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the maximum number of consecutive rainy days in the period.
Examples
Input
RRS
Output
2
Input
SSS
Output
0
Input
RSR
Output
1 | instruction | 0 | 4,815 | 18 | 9,630 |
"Correct Solution:
```
s=input()
ans=0
if 'R' in s:ans=1
if 'RR' in s:ans=2
if 'RRR' in s:ans=3
print(ans)
``` | output | 1 | 4,815 | 18 | 9,631 |
Provide a correct Python 3 solution for this coding contest problem.
We have weather records at AtCoder Town for some consecutive three days. A string of length 3, S, represents the records - if the i-th character is `S`, it means it was sunny on the i-th day; if that character is `R`, it means it was rainy on that day.
Find the maximum number of consecutive rainy days in this period.
Constraints
* |S| = 3
* Each character of S is `S` or `R`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the maximum number of consecutive rainy days in the period.
Examples
Input
RRS
Output
2
Input
SSS
Output
0
Input
RSR
Output
1 | instruction | 0 | 4,816 | 18 | 9,632 |
"Correct Solution:
```
s=input()
if s[1]=="R":
print(s.count("R"))
else:
print(min(1,s.count("R")))
``` | output | 1 | 4,816 | 18 | 9,633 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have weather records at AtCoder Town for some consecutive three days. A string of length 3, S, represents the records - if the i-th character is `S`, it means it was sunny on the i-th day; if that character is `R`, it means it was rainy on that day.
Find the maximum number of consecutive rainy days in this period.
Constraints
* |S| = 3
* Each character of S is `S` or `R`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the maximum number of consecutive rainy days in the period.
Examples
Input
RRS
Output
2
Input
SSS
Output
0
Input
RSR
Output
1
Submitted Solution:
```
s = str(input())
if s == "RRR":
print(3)
elif s == "SRR" or s == "RRS":
print(2)
elif s == "SSS":
print(1)
else:
print(0)
``` | instruction | 0 | 4,822 | 18 | 9,644 |
No | output | 1 | 4,822 | 18 | 9,645 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Thanks to your help, Heidi is confident that no one can fool her. She has now decided to post some fake news on the HC2 Facebook page. However, she wants to be able to communicate to the HC2 committee that the post is fake, using some secret phrase hidden in the post as a subsequence. To make this method foolproof, she wants the phrase to appear n times in the post. She is asking you to design a post (string) s and a hidden phrase p such that p appears in s as a subsequence exactly n times.
Input
The first and only line of input contains a single integer n (1 ≤ n ≤ 1 000 000).
Output
The output should contain two nonempty strings s and p separated by a single space. Each string should be composed of letters (a-z and A-Z: both lowercase and uppercase are allowed) and have length at most 200. The number of occurrences of p in s as a subsequence should be exactly n. If there are many possible solutions, output any of them. It is guaranteed that at least one solution exists.
Examples
Input
2
Output
hHheidi Hei
Input
4
Output
bbbba ba
Input
6
Output
aaabb ab
Note
An occurrence of p as a subsequence in s should be thought of as a set of positions in s such that the letters at these positions, in order, form p. The number of occurences is thus the number of such sets. For example, ab appears 6 times as a subsequence in aaabb, for the following sets of positions: {1, 4}, {1, 5}, {2, 4}, {2, 5}, {3, 4}, {3, 5} (that is, we should choose one of the a's and one of the b's).
Submitted Solution:
```
n = int(input())
s1 = []
s2 = []
now1 = 0
now2 = 0
v = []
if n==1:
s1.append('a')
s2.append('a')
now1 += 1
while n>1:
v.append(n%2)
n = n//2
v.reverse()
for i in range(len(v)):
if i==0:
if v[i]==0:
s1.append('A')
s1.append('A')
s2.append('A')
now2 += 1
else :
s1.append('a')
s1.append('a')
s1.append('a')
s2.append('a')
now1 += 1
continue
if v[i]==0:
s1.append(chr(ord('A')+now2))
s1.append(chr(ord('A')+now2))
s2.append(chr(ord('A')+now2))
now2 += 1
else:
c = s1[-1]
s1[-1] = chr(ord('a')+now1)
s1.append(c)
s1.append(chr(ord('a')+now1))
s1.append(chr(ord('a')+now1))
s2.append(chr(ord('a')+now1))
now1 += 1
print(''.join(s1),''.join(s2))
``` | instruction | 0 | 5,535 | 18 | 11,070 |
No | output | 1 | 5,535 | 18 | 11,071 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Thanks to your help, Heidi is confident that no one can fool her. She has now decided to post some fake news on the HC2 Facebook page. However, she wants to be able to communicate to the HC2 committee that the post is fake, using some secret phrase hidden in the post as a subsequence. To make this method foolproof, she wants the phrase to appear n times in the post. She is asking you to design a post (string) s and a hidden phrase p such that p appears in s as a subsequence exactly n times.
Input
The first and only line of input contains a single integer n (1 ≤ n ≤ 1 000 000).
Output
The output should contain two nonempty strings s and p separated by a single space. Each string should be composed of letters (a-z and A-Z: both lowercase and uppercase are allowed) and have length at most 200. The number of occurrences of p in s as a subsequence should be exactly n. If there are many possible solutions, output any of them. It is guaranteed that at least one solution exists.
Examples
Input
2
Output
hHheidi Hei
Input
4
Output
bbbba ba
Input
6
Output
aaabb ab
Note
An occurrence of p as a subsequence in s should be thought of as a set of positions in s such that the letters at these positions, in order, form p. The number of occurences is thus the number of such sets. For example, ab appears 6 times as a subsequence in aaabb, for the following sets of positions: {1, 4}, {1, 5}, {2, 4}, {2, 5}, {3, 4}, {3, 5} (that is, we should choose one of the a's and one of the b's).
Submitted Solution:
```
n = int(input())
s1 = []
s2 = []
now1 = 0
now2 = 0
v = []
while n>1:
v.append(n%2)
n = n//2
s1.append('a')
s2.append('a')
now1 += 1
v.reverse()
for i in range(len(v)):
if v[i]==0:
s1.append(chr(ord('A')+now2))
s1.append(chr(ord('A')+now2))
s2.append(chr(ord('A')+now2))
now2 += 1
else:
c = s1[-1]
s1[-1] = chr(ord('a')+now1)
s1.append(c)
s1.append(chr(ord('a')+now1))
s1.append(chr(ord('a')+now1))
s2.append(chr(ord('a')+now1))
now1 += 1
print(''.join(s1),''.join(s2))
``` | instruction | 0 | 5,536 | 18 | 11,072 |
No | output | 1 | 5,536 | 18 | 11,073 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Thanks to your help, Heidi is confident that no one can fool her. She has now decided to post some fake news on the HC2 Facebook page. However, she wants to be able to communicate to the HC2 committee that the post is fake, using some secret phrase hidden in the post as a subsequence. To make this method foolproof, she wants the phrase to appear n times in the post. She is asking you to design a post (string) s and a hidden phrase p such that p appears in s as a subsequence exactly n times.
Input
The first and only line of input contains a single integer n (1 ≤ n ≤ 1 000 000).
Output
The output should contain two nonempty strings s and p separated by a single space. Each string should be composed of letters (a-z and A-Z: both lowercase and uppercase are allowed) and have length at most 200. The number of occurrences of p in s as a subsequence should be exactly n. If there are many possible solutions, output any of them. It is guaranteed that at least one solution exists.
Examples
Input
2
Output
hHheidi Hei
Input
4
Output
bbbba ba
Input
6
Output
aaabb ab
Note
An occurrence of p as a subsequence in s should be thought of as a set of positions in s such that the letters at these positions, in order, form p. The number of occurences is thus the number of such sets. For example, ab appears 6 times as a subsequence in aaabb, for the following sets of positions: {1, 4}, {1, 5}, {2, 4}, {2, 5}, {3, 4}, {3, 5} (that is, we should choose one of the a's and one of the b's).
Submitted Solution:
```
n = int(input())
print('a'*n+' a')
``` | instruction | 0 | 5,537 | 18 | 11,074 |
No | output | 1 | 5,537 | 18 | 11,075 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Thanks to your help, Heidi is confident that no one can fool her. She has now decided to post some fake news on the HC2 Facebook page. However, she wants to be able to communicate to the HC2 committee that the post is fake, using some secret phrase hidden in the post as a subsequence. To make this method foolproof, she wants the phrase to appear n times in the post. She is asking you to design a post (string) s and a hidden phrase p such that p appears in s as a subsequence exactly n times.
Input
The first and only line of input contains a single integer n (1 ≤ n ≤ 1 000 000).
Output
The output should contain two nonempty strings s and p separated by a single space. Each string should be composed of letters (a-z and A-Z: both lowercase and uppercase are allowed) and have length at most 200. The number of occurrences of p in s as a subsequence should be exactly n. If there are many possible solutions, output any of them. It is guaranteed that at least one solution exists.
Examples
Input
2
Output
hHheidi Hei
Input
4
Output
bbbba ba
Input
6
Output
aaabb ab
Note
An occurrence of p as a subsequence in s should be thought of as a set of positions in s such that the letters at these positions, in order, form p. The number of occurences is thus the number of such sets. For example, ab appears 6 times as a subsequence in aaabb, for the following sets of positions: {1, 4}, {1, 5}, {2, 4}, {2, 5}, {3, 4}, {3, 5} (that is, we should choose one of the a's and one of the b's).
Submitted Solution:
```
n = int(input())
print("a" * n , "a")
``` | instruction | 0 | 5,538 | 18 | 11,076 |
No | output | 1 | 5,538 | 18 | 11,077 |
Provide a correct Python 3 solution for this coding contest problem.
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.
You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.
Constraints
* 3 ≤ |s| ≤ 100 (|s| denotes the length of s.)
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the abbreviation of s.
Examples
Input
internationalization
Output
i18n
Input
smiles
Output
s4s
Input
xyz
Output
x1z | instruction | 0 | 5,677 | 18 | 11,354 |
"Correct Solution:
```
F, *M, L = list(input())
print(F + str(len(M)) + L)
``` | output | 1 | 5,677 | 18 | 11,355 |
Provide a correct Python 3 solution for this coding contest problem.
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.
You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.
Constraints
* 3 ≤ |s| ≤ 100 (|s| denotes the length of s.)
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the abbreviation of s.
Examples
Input
internationalization
Output
i18n
Input
smiles
Output
s4s
Input
xyz
Output
x1z | instruction | 0 | 5,678 | 18 | 11,356 |
"Correct Solution:
```
s = input()
a = len(s)
print(s[0]+str(a-2)+s[a-1])
``` | output | 1 | 5,678 | 18 | 11,357 |
Provide a correct Python 3 solution for this coding contest problem.
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.
You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.
Constraints
* 3 ≤ |s| ≤ 100 (|s| denotes the length of s.)
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the abbreviation of s.
Examples
Input
internationalization
Output
i18n
Input
smiles
Output
s4s
Input
xyz
Output
x1z | instruction | 0 | 5,679 | 18 | 11,358 |
"Correct Solution:
```
S=input()
print(S[:1]+str(len(S)-2)+S[-1:])
``` | output | 1 | 5,679 | 18 | 11,359 |
Provide a correct Python 3 solution for this coding contest problem.
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.
You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.
Constraints
* 3 ≤ |s| ≤ 100 (|s| denotes the length of s.)
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the abbreviation of s.
Examples
Input
internationalization
Output
i18n
Input
smiles
Output
s4s
Input
xyz
Output
x1z | instruction | 0 | 5,680 | 18 | 11,360 |
"Correct Solution:
```
s = input()
print(s[0] + str((len(s)) - 2) + s[-1])
``` | output | 1 | 5,680 | 18 | 11,361 |
Provide a correct Python 3 solution for this coding contest problem.
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.
You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.
Constraints
* 3 ≤ |s| ≤ 100 (|s| denotes the length of s.)
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the abbreviation of s.
Examples
Input
internationalization
Output
i18n
Input
smiles
Output
s4s
Input
xyz
Output
x1z | instruction | 0 | 5,681 | 18 | 11,362 |
"Correct Solution:
```
a,*b,c = input()
print(a + str(len(b)) + c, end="")
``` | output | 1 | 5,681 | 18 | 11,363 |
Provide a correct Python 3 solution for this coding contest problem.
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.
You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.
Constraints
* 3 ≤ |s| ≤ 100 (|s| denotes the length of s.)
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the abbreviation of s.
Examples
Input
internationalization
Output
i18n
Input
smiles
Output
s4s
Input
xyz
Output
x1z | instruction | 0 | 5,682 | 18 | 11,364 |
"Correct Solution:
```
s=input();print(s[0]+str(len(s[1:-1]))+s[-1])
``` | output | 1 | 5,682 | 18 | 11,365 |
Provide a correct Python 3 solution for this coding contest problem.
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.
You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.
Constraints
* 3 ≤ |s| ≤ 100 (|s| denotes the length of s.)
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the abbreviation of s.
Examples
Input
internationalization
Output
i18n
Input
smiles
Output
s4s
Input
xyz
Output
x1z | instruction | 0 | 5,683 | 18 | 11,366 |
"Correct Solution:
```
s=list(input())
y=str(len(s)-2)
print(s[0]+y+s[-1])
``` | output | 1 | 5,683 | 18 | 11,367 |
Provide a correct Python 3 solution for this coding contest problem.
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.
You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.
Constraints
* 3 ≤ |s| ≤ 100 (|s| denotes the length of s.)
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the abbreviation of s.
Examples
Input
internationalization
Output
i18n
Input
smiles
Output
s4s
Input
xyz
Output
x1z | instruction | 0 | 5,684 | 18 | 11,368 |
"Correct Solution:
```
l=list(input())
print(l[0]+str(len(l)-2)+l[-1])
``` | output | 1 | 5,684 | 18 | 11,369 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.
You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.
Constraints
* 3 ≤ |s| ≤ 100 (|s| denotes the length of s.)
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the abbreviation of s.
Examples
Input
internationalization
Output
i18n
Input
smiles
Output
s4s
Input
xyz
Output
x1z
Submitted Solution:
```
S=input()
l=len(S)-2
A=S[0]
B=S[-1]
print(A+str(l)+B)
``` | instruction | 0 | 5,685 | 18 | 11,370 |
Yes | output | 1 | 5,685 | 18 | 11,371 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.
You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.
Constraints
* 3 ≤ |s| ≤ 100 (|s| denotes the length of s.)
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the abbreviation of s.
Examples
Input
internationalization
Output
i18n
Input
smiles
Output
s4s
Input
xyz
Output
x1z
Submitted Solution:
```
S=input()
a=str(len(S)-2)
print(S[:1]+a+S[-1:])
``` | instruction | 0 | 5,686 | 18 | 11,372 |
Yes | output | 1 | 5,686 | 18 | 11,373 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.
You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.
Constraints
* 3 ≤ |s| ≤ 100 (|s| denotes the length of s.)
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the abbreviation of s.
Examples
Input
internationalization
Output
i18n
Input
smiles
Output
s4s
Input
xyz
Output
x1z
Submitted Solution:
```
s=input()
n=int(len(s))
print(s[0]+str(n-2)+s[n-1])
``` | instruction | 0 | 5,687 | 18 | 11,374 |
Yes | output | 1 | 5,687 | 18 | 11,375 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.
You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.
Constraints
* 3 ≤ |s| ≤ 100 (|s| denotes the length of s.)
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the abbreviation of s.
Examples
Input
internationalization
Output
i18n
Input
smiles
Output
s4s
Input
xyz
Output
x1z
Submitted Solution:
```
a = input()
print(f"{a[0]}{len(a[1:-1])}{a[-1]}")
``` | instruction | 0 | 5,688 | 18 | 11,376 |
Yes | output | 1 | 5,688 | 18 | 11,377 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.
You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.
Constraints
* 3 ≤ |s| ≤ 100 (|s| denotes the length of s.)
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the abbreviation of s.
Examples
Input
internationalization
Output
i18n
Input
smiles
Output
s4s
Input
xyz
Output
x1z
Submitted Solution:
```
s = input()
N = len(s)
print(s[0] + len(N - 2) + s[N - 1])
``` | instruction | 0 | 5,689 | 18 | 11,378 |
No | output | 1 | 5,689 | 18 | 11,379 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.
You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.
Constraints
* 3 ≤ |s| ≤ 100 (|s| denotes the length of s.)
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the abbreviation of s.
Examples
Input
internationalization
Output
i18n
Input
smiles
Output
s4s
Input
xyz
Output
x1z
Submitted Solution:
```
temp = input()
l = len(temp)
print(temp[0]+str(l)+temp[l-1])
``` | instruction | 0 | 5,690 | 18 | 11,380 |
No | output | 1 | 5,690 | 18 | 11,381 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.
You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.
Constraints
* 3 ≤ |s| ≤ 100 (|s| denotes the length of s.)
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the abbreviation of s.
Examples
Input
internationalization
Output
i18n
Input
smiles
Output
s4s
Input
xyz
Output
x1z
Submitted Solution:
```
S = input()
l = S.__len__()
print('%s%s%s' % [S[0], l-2, S[l-1]]
``` | instruction | 0 | 5,691 | 18 | 11,382 |
No | output | 1 | 5,691 | 18 | 11,383 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.
You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.
Constraints
* 3 ≤ |s| ≤ 100 (|s| denotes the length of s.)
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the abbreviation of s.
Examples
Input
internationalization
Output
i18n
Input
smiles
Output
s4s
Input
xyz
Output
x1z
Submitted Solution:
```
s=input()
print(s[0])
print(str(len(s)-2))
print(s[-1])
``` | instruction | 0 | 5,692 | 18 | 11,384 |
No | output | 1 | 5,692 | 18 | 11,385 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are developing a robot that processes strings. When the robot is given a string t consisting of lowercase English letters, it processes the string by following the procedure below:
1. Let i be the smallest index such that t_i = t_{i + 1}. If such an index does not exist, terminate the procedure.
2. If t_i is `z`, remove t_i and t_{i + 1} from t. Otherwise, let c be the next letter of t_i in the English alphabet, and replace t_i and t_{i + 1} together with c, reducing the length of t by 1.
3. Go back to step 1.
For example, when the robot is given the string `axxxxza`, it will be processed as follows: `axxxxza` → `ayxxza` → `ayyza` → `azza` → `aa` → `b`.
You are given a string s consisting of lowercase English letters. Answer Q queries. The i-th query is as follows:
* Assume that the robot is given a substring of s that runs from the l_i-th character and up to the r_i-th character (inclusive). Will the string be empty after processing?
Constraints
* 1 ≤ |s| ≤ 5 × 10^5
* s consists of lowercase English letters.
* 1 ≤ Q ≤ 10^5
* 1 ≤ l_i ≤ r_i ≤ |s|
Input
The input is given from Standard Input in the following format:
s
Q
l_1 r_1
l_2 r_2
:
l_Q r_Q
Output
Print Q lines. The i-th line should contain the answer to the i-th query: `Yes` or `No`.
Examples
Input
axxxxza
2
1 7
2 6
Output
No
Yes
Input
aabcdefghijklmnopqrstuvwxyz
1
1 27
Output
Yes
Input
yzyyyzyzyyyz
8
1 6
7 12
1 12
6 11
1 1
1 3
4 9
3 8
Output
Yes
Yes
Yes
Yes
No
No
No
No
Submitted Solution:
```
#MOD = 10**9 + 7
from math import log2
s = input().strip()
#print(s,len(s))
L = len(s)
Q = int(input().strip())
ORD = ord('a')
nextC = [27*[L+1] for _ in range(L+2)]
nextC[L-1][ord(s[-1])-ORD] = L
for i in range(L-2,-1,-1):
char = ord(s[i]) - ORD
nextC[i][char] = i+1
#if i == 0: print('###',nextC[i])
for c in range(char+1,27):
nextC[i][c] = min(nextC[nextC[i][c-1]][c-1], nextC[nextC[i][26]][c])
#if i == 0: print('###',nextC[i])
if char != 0:
nextC[i][0] = nextC[nextC[i][26]][0]
for c in range(1,char):
nextC[i][c] = min(nextC[nextC[i][c-1]][c-1], nextC[nextC[i][26]][c])
#for i in range(L+2):
# print(nextC[i])
numPowers = int(log2(L))
nextPow = [(L+2)*[L+1] for _ in range(numPowers+1)]
for i in range(L+2):
nextPow[0][i] = nextC[i][26]
for power in range(1,numPowers+1):
for i in range(L):
nextPow[power][i] = nextPow[power-1][nextPow[power-1][i]]
#for i in range(L+2): print(nextC[i])
#print(nextPow, L)
for q in range(Q):
l,r = [int(_) for _ in input().split()]
l -= 1
#print(l,r, s[l:r])
p = 0
n = nextPow[0][l]
while n < r:
p += 1
n = nextPow[p][l]
if n == r:
print("Yes")
elif p == 0:
print("No")
else:
n = nextPow[p-1][l]
while n < r:
n = nextC[n][26]
if n == r:
print("Yes")
else:
print("No")
``` | instruction | 0 | 5,693 | 18 | 11,386 |
No | output | 1 | 5,693 | 18 | 11,387 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are developing a robot that processes strings. When the robot is given a string t consisting of lowercase English letters, it processes the string by following the procedure below:
1. Let i be the smallest index such that t_i = t_{i + 1}. If such an index does not exist, terminate the procedure.
2. If t_i is `z`, remove t_i and t_{i + 1} from t. Otherwise, let c be the next letter of t_i in the English alphabet, and replace t_i and t_{i + 1} together with c, reducing the length of t by 1.
3. Go back to step 1.
For example, when the robot is given the string `axxxxza`, it will be processed as follows: `axxxxza` → `ayxxza` → `ayyza` → `azza` → `aa` → `b`.
You are given a string s consisting of lowercase English letters. Answer Q queries. The i-th query is as follows:
* Assume that the robot is given a substring of s that runs from the l_i-th character and up to the r_i-th character (inclusive). Will the string be empty after processing?
Constraints
* 1 ≤ |s| ≤ 5 × 10^5
* s consists of lowercase English letters.
* 1 ≤ Q ≤ 10^5
* 1 ≤ l_i ≤ r_i ≤ |s|
Input
The input is given from Standard Input in the following format:
s
Q
l_1 r_1
l_2 r_2
:
l_Q r_Q
Output
Print Q lines. The i-th line should contain the answer to the i-th query: `Yes` or `No`.
Examples
Input
axxxxza
2
1 7
2 6
Output
No
Yes
Input
aabcdefghijklmnopqrstuvwxyz
1
1 27
Output
Yes
Input
yzyyyzyzyyyz
8
1 6
7 12
1 12
6 11
1 1
1 3
4 9
3 8
Output
Yes
Yes
Yes
Yes
No
No
No
No
Submitted Solution:
```
def solve_loop(s):
count = 0
while len(s) > 1 and count < 100:
s = solve(s)
count += 1
return s
def solve(s):
for i in range(0, len(s)-1):
if s[i] == s[i+1]:
if s[i] == 'z':
s = s.replace(s[i:i+2], '')
else:
next_chr = chr(ord(s[i])+1)
s = s.replace(s[i:i+2], next_chr)
return s
return s
s = input()
q = int(input())
start = []
end = []
for i in range(0, q):
_input = input()
start.append(int(_input.split(' ')[0]))
end.append(int(_input.split(' ')[1]))
for i in range(0, q):
test_st = s[start[i]-1:end[i]]
opt_str = solve_loop(test_st)
if len(opt_str) == 0:
print('YES')
else:
print('NO')
``` | instruction | 0 | 5,694 | 18 | 11,388 |
No | output | 1 | 5,694 | 18 | 11,389 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are developing a robot that processes strings. When the robot is given a string t consisting of lowercase English letters, it processes the string by following the procedure below:
1. Let i be the smallest index such that t_i = t_{i + 1}. If such an index does not exist, terminate the procedure.
2. If t_i is `z`, remove t_i and t_{i + 1} from t. Otherwise, let c be the next letter of t_i in the English alphabet, and replace t_i and t_{i + 1} together with c, reducing the length of t by 1.
3. Go back to step 1.
For example, when the robot is given the string `axxxxza`, it will be processed as follows: `axxxxza` → `ayxxza` → `ayyza` → `azza` → `aa` → `b`.
You are given a string s consisting of lowercase English letters. Answer Q queries. The i-th query is as follows:
* Assume that the robot is given a substring of s that runs from the l_i-th character and up to the r_i-th character (inclusive). Will the string be empty after processing?
Constraints
* 1 ≤ |s| ≤ 5 × 10^5
* s consists of lowercase English letters.
* 1 ≤ Q ≤ 10^5
* 1 ≤ l_i ≤ r_i ≤ |s|
Input
The input is given from Standard Input in the following format:
s
Q
l_1 r_1
l_2 r_2
:
l_Q r_Q
Output
Print Q lines. The i-th line should contain the answer to the i-th query: `Yes` or `No`.
Examples
Input
axxxxza
2
1 7
2 6
Output
No
Yes
Input
aabcdefghijklmnopqrstuvwxyz
1
1 27
Output
Yes
Input
yzyyyzyzyyyz
8
1 6
7 12
1 12
6 11
1 1
1 3
4 9
3 8
Output
Yes
Yes
Yes
Yes
No
No
No
No
Submitted Solution:
```
import sys
def func(s):
i = 0
found = False
for i, c in enumerate(s):
if i < len(s) - 1 and c == s[i+1]:
found = True
break
if found:
a = s[i]
s = s[:i] + s[i+2:]
if a != "z":
s = s[:i] + chr(ord(a) + 1) + s[i:]
return s
return "-"
if __name__ == "__main__":
input = sys.stdin.readlines()
string = input[0]
n = int(input[1])
for i in range(2, 2 + n):
lr = input[i]
l, r = lr.split(" ")
s = string[int(l)-1:int(r)]
result = func(s)
while result != "-":
if result == "":
print("Yes")
break
result = func(result)
else:
print("No")
``` | instruction | 0 | 5,695 | 18 | 11,390 |
No | output | 1 | 5,695 | 18 | 11,391 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are developing a robot that processes strings. When the robot is given a string t consisting of lowercase English letters, it processes the string by following the procedure below:
1. Let i be the smallest index such that t_i = t_{i + 1}. If such an index does not exist, terminate the procedure.
2. If t_i is `z`, remove t_i and t_{i + 1} from t. Otherwise, let c be the next letter of t_i in the English alphabet, and replace t_i and t_{i + 1} together with c, reducing the length of t by 1.
3. Go back to step 1.
For example, when the robot is given the string `axxxxza`, it will be processed as follows: `axxxxza` → `ayxxza` → `ayyza` → `azza` → `aa` → `b`.
You are given a string s consisting of lowercase English letters. Answer Q queries. The i-th query is as follows:
* Assume that the robot is given a substring of s that runs from the l_i-th character and up to the r_i-th character (inclusive). Will the string be empty after processing?
Constraints
* 1 ≤ |s| ≤ 5 × 10^5
* s consists of lowercase English letters.
* 1 ≤ Q ≤ 10^5
* 1 ≤ l_i ≤ r_i ≤ |s|
Input
The input is given from Standard Input in the following format:
s
Q
l_1 r_1
l_2 r_2
:
l_Q r_Q
Output
Print Q lines. The i-th line should contain the answer to the i-th query: `Yes` or `No`.
Examples
Input
axxxxza
2
1 7
2 6
Output
No
Yes
Input
aabcdefghijklmnopqrstuvwxyz
1
1 27
Output
Yes
Input
yzyyyzyzyyyz
8
1 6
7 12
1 12
6 11
1 1
1 3
4 9
3 8
Output
Yes
Yes
Yes
Yes
No
No
No
No
Submitted Solution:
```
def solve_loop(s):
count = 0
while len(s) > 1 and count < 10000000:
s = solve(s)
count += 1
return s
def solve(s):
for i in range(0, len(s)-1):
if s[i] == s[i+1]:
if s[i] == 'z':
s = s.replace(s[i:i+2], '')
else:
next_chr = chr(ord(s[i])+1)
s = s.replace(s[i:i+2], next_chr)
return s
return s
s = input()
q = int(input())
start = []
end = []
for i in range(0, q):
_input = input()
start.append(int(_input.split(' ')[0]))
end.append(int(_input.split(' ')[1]))
for i in range(0, q):
test_st = s[start[i]-1:end[i]]
opt_str = solve_loop(test_st)
if len(opt_str) == 0:
print('YES')
else:
print('NO')
``` | instruction | 0 | 5,696 | 18 | 11,392 |
No | output | 1 | 5,696 | 18 | 11,393 |
Provide a correct Python 3 solution for this coding contest problem.
Almost Identical Programs
The programming contest named Concours de Programmation Comtemporaine Interuniversitaire (CPCI) has a judging system similar to that of ICPC; contestants have to submit correct outputs for two different inputs to be accepted as a correct solution. Each of the submissions should include the program that generated the output. A pair of submissions is judged to be a correct solution when, in addition to the correctness of the outputs, they include an identical program.
Many contestants, however, do not stop including a different version of their programs in their second submissions, after modifying a single string literal in their programs representing the input file name, attempting to process different input. The organizers of CPCI are exploring the possibility of showing a special error message for such close submissions, indicating contestants what's wrong with such submissions. Your task is to detect such close submissions.
Input
The input consists of at most 100 datasets, each in the following format.
s1
s2
Each of s1 and s2 is a string written in a line, with the length between 1 and 200, inclusive. They are the first and the second submitted programs respectively. A program consists of lowercase letters (`a`, `b`, ..., `z`), uppercase letters (`A`, `B`, ..., `Z`), digits (`0`, `1`, ..., `9`), double quotes (`"`), and semicolons (`;`). When double quotes occur in a program, there are always even number of them.
The end of the input is indicated by a line containing one '`.`' (period).
Output
For each dataset, print the judge result in a line.
If the given two programs are identical, print `IDENTICAL`. If two programs differ with only one corresponding string literal, print `CLOSE`. Otherwise, print `DIFFERENT`. A string literal is a possibly empty sequence of characters between an odd-numbered occurrence of a double quote and the next occurrence of a double quote.
Sample Input
print"hello";print123
print"hello";print123
read"B1input";solve;output;
read"B2";solve;output;
read"C1";solve;output"C1ans";
read"C2";solve;output"C2ans";
""""""""
"""42"""""
slow"program"
fast"code"
"super"fast"program"
"super"faster"program"
X""
X
I"S""CREAM"
I"CE""CREAM"
11"22"11
1"33"111
.
Output for the Sample Input
IDENTICAL
CLOSE
DIFFERENT
CLOSE
DIFFERENT
DIFFERENT
DIFFERENT
CLOSE
DIFFERENT
Example
Input
print"hello";print123
print"hello";print123
read"B1input";solve;output;
read"B2";solve;output;
read"C1";solve;output"C1ans";
read"C2";solve;output"C2ans";
""""""""
"""42"""""
slow"program"
fast"code"
"super"fast"program"
"super"faster"program"
X""
X
I"S""CREAM"
I"CE""CREAM"
11"22"11
1"33"111
.
Output
IDENTICAL
CLOSE
DIFFERENT
CLOSE
DIFFERENT
DIFFERENT
DIFFERENT
CLOSE
DIFFERENT | instruction | 0 | 5,753 | 18 | 11,506 |
"Correct Solution:
```
s1 = input().split('"')
while s1[0]!='.':
miss = 0
ans = "IDENTICAL"
s2 = input().split('"')
if len(s1) != len(s2):
ans="DIFFERENT"
else :
for i in range(len(s1)):
if i % 2 == 0 and s1[i] != s2[i]:
ans="DIFFERENT"
break
if i % 2 == 1 and s1[i] != s2[i]:
if ans == "CLOSE":
ans="DIFFERENT"
break
else:
ans = "CLOSE"
print(ans)
s1=input().split('"')
``` | output | 1 | 5,753 | 18 | 11,507 |
Provide a correct Python 3 solution for this coding contest problem.
Almost Identical Programs
The programming contest named Concours de Programmation Comtemporaine Interuniversitaire (CPCI) has a judging system similar to that of ICPC; contestants have to submit correct outputs for two different inputs to be accepted as a correct solution. Each of the submissions should include the program that generated the output. A pair of submissions is judged to be a correct solution when, in addition to the correctness of the outputs, they include an identical program.
Many contestants, however, do not stop including a different version of their programs in their second submissions, after modifying a single string literal in their programs representing the input file name, attempting to process different input. The organizers of CPCI are exploring the possibility of showing a special error message for such close submissions, indicating contestants what's wrong with such submissions. Your task is to detect such close submissions.
Input
The input consists of at most 100 datasets, each in the following format.
s1
s2
Each of s1 and s2 is a string written in a line, with the length between 1 and 200, inclusive. They are the first and the second submitted programs respectively. A program consists of lowercase letters (`a`, `b`, ..., `z`), uppercase letters (`A`, `B`, ..., `Z`), digits (`0`, `1`, ..., `9`), double quotes (`"`), and semicolons (`;`). When double quotes occur in a program, there are always even number of them.
The end of the input is indicated by a line containing one '`.`' (period).
Output
For each dataset, print the judge result in a line.
If the given two programs are identical, print `IDENTICAL`. If two programs differ with only one corresponding string literal, print `CLOSE`. Otherwise, print `DIFFERENT`. A string literal is a possibly empty sequence of characters between an odd-numbered occurrence of a double quote and the next occurrence of a double quote.
Sample Input
print"hello";print123
print"hello";print123
read"B1input";solve;output;
read"B2";solve;output;
read"C1";solve;output"C1ans";
read"C2";solve;output"C2ans";
""""""""
"""42"""""
slow"program"
fast"code"
"super"fast"program"
"super"faster"program"
X""
X
I"S""CREAM"
I"CE""CREAM"
11"22"11
1"33"111
.
Output for the Sample Input
IDENTICAL
CLOSE
DIFFERENT
CLOSE
DIFFERENT
DIFFERENT
DIFFERENT
CLOSE
DIFFERENT
Example
Input
print"hello";print123
print"hello";print123
read"B1input";solve;output;
read"B2";solve;output;
read"C1";solve;output"C1ans";
read"C2";solve;output"C2ans";
""""""""
"""42"""""
slow"program"
fast"code"
"super"fast"program"
"super"faster"program"
X""
X
I"S""CREAM"
I"CE""CREAM"
11"22"11
1"33"111
.
Output
IDENTICAL
CLOSE
DIFFERENT
CLOSE
DIFFERENT
DIFFERENT
DIFFERENT
CLOSE
DIFFERENT | instruction | 0 | 5,754 | 18 | 11,508 |
"Correct Solution:
```
while True:
s1 = input()
if s1 == ".":
break
s2 = input()
listed_s1 = [[]]
listed_s2 = [[]]
start = 0
now = 0
for i in range(len(s1)):
if s1[i] == "\"" and not start:
listed_s1.append([])
now += 1
start = 1
listed_s1[now].append(s1[i])
elif s1[i] == "\"" and start:
listed_s1[now].append(s1[i])
listed_s1.append([])
now += 1
start = 0
else:
listed_s1[now].append(s1[i])
now = 0
for i in range(len(s2)):
if s2[i] == "\"" and not start:
listed_s2.append([])
now += 1
start = 1
listed_s2[now].append(s2[i])
elif s2[i] == "\"" and start:
listed_s2[now].append(s2[i])
listed_s2.append([])
now += 1
start = 0
else:
listed_s2[now].append(s2[i])
fist_wrong = 0
ans = "IDENTICAL"
if len(listed_s1) != len(listed_s2):
ans = "DIFFERENT"
for i in range(min(len(listed_s1), len(listed_s2))):
if ans == "DIFFERENT":
break
if listed_s1[i] != listed_s2[i]:
if listed_s1[i][0] == "\"" and listed_s2[i][-1] == "\"" and listed_s2[i][0] == "\"" and listed_s2[i][-1] == "\"":
if fist_wrong:
ans = "DIFFERENT"
else:
fist_wrong = 1
ans = "CLOSE"
else:
ans = "DIFFERENT"
print(ans)
``` | output | 1 | 5,754 | 18 | 11,509 |
Provide a correct Python 3 solution for this coding contest problem.
Almost Identical Programs
The programming contest named Concours de Programmation Comtemporaine Interuniversitaire (CPCI) has a judging system similar to that of ICPC; contestants have to submit correct outputs for two different inputs to be accepted as a correct solution. Each of the submissions should include the program that generated the output. A pair of submissions is judged to be a correct solution when, in addition to the correctness of the outputs, they include an identical program.
Many contestants, however, do not stop including a different version of their programs in their second submissions, after modifying a single string literal in their programs representing the input file name, attempting to process different input. The organizers of CPCI are exploring the possibility of showing a special error message for such close submissions, indicating contestants what's wrong with such submissions. Your task is to detect such close submissions.
Input
The input consists of at most 100 datasets, each in the following format.
s1
s2
Each of s1 and s2 is a string written in a line, with the length between 1 and 200, inclusive. They are the first and the second submitted programs respectively. A program consists of lowercase letters (`a`, `b`, ..., `z`), uppercase letters (`A`, `B`, ..., `Z`), digits (`0`, `1`, ..., `9`), double quotes (`"`), and semicolons (`;`). When double quotes occur in a program, there are always even number of them.
The end of the input is indicated by a line containing one '`.`' (period).
Output
For each dataset, print the judge result in a line.
If the given two programs are identical, print `IDENTICAL`. If two programs differ with only one corresponding string literal, print `CLOSE`. Otherwise, print `DIFFERENT`. A string literal is a possibly empty sequence of characters between an odd-numbered occurrence of a double quote and the next occurrence of a double quote.
Sample Input
print"hello";print123
print"hello";print123
read"B1input";solve;output;
read"B2";solve;output;
read"C1";solve;output"C1ans";
read"C2";solve;output"C2ans";
""""""""
"""42"""""
slow"program"
fast"code"
"super"fast"program"
"super"faster"program"
X""
X
I"S""CREAM"
I"CE""CREAM"
11"22"11
1"33"111
.
Output for the Sample Input
IDENTICAL
CLOSE
DIFFERENT
CLOSE
DIFFERENT
DIFFERENT
DIFFERENT
CLOSE
DIFFERENT
Example
Input
print"hello";print123
print"hello";print123
read"B1input";solve;output;
read"B2";solve;output;
read"C1";solve;output"C1ans";
read"C2";solve;output"C2ans";
""""""""
"""42"""""
slow"program"
fast"code"
"super"fast"program"
"super"faster"program"
X""
X
I"S""CREAM"
I"CE""CREAM"
11"22"11
1"33"111
.
Output
IDENTICAL
CLOSE
DIFFERENT
CLOSE
DIFFERENT
DIFFERENT
DIFFERENT
CLOSE
DIFFERENT | instruction | 0 | 5,755 | 18 | 11,510 |
"Correct Solution:
```
ans_list = []
def solve():
S = input()
if S == ".":
return "end"
T = input()
if S == T:
return "IDENTICAL"
cs = []
ct = []
ns = []
nt = []
tmp = ""
flag = False
for s in S:
if s == '"':
if flag:
flag = False
cs.append(tmp)
else:
flag = True
ns.append(tmp)
tmp = ""
continue
tmp += s
ns.append(tmp)
tmp = ""
flag = False
for t in T:
if t == '"':
if flag:
flag = False
ct.append(tmp)
else:
flag = True
nt.append(tmp)
tmp = ""
continue
tmp += t
nt.append(tmp)
if ns != nt or len(cs) != len(ct):
return "DIFFERENT"
cnt = 0
for csi, cti in zip(cs, ct):
if csi != cti:
cnt += 1
if cnt == 1:
return "CLOSE"
else:
return "DIFFERENT"
while True:
ans = solve()
if ans == "end":
break
ans_list.append(ans)
for ans in ans_list:
print(ans)
``` | output | 1 | 5,755 | 18 | 11,511 |
Provide a correct Python 3 solution for this coding contest problem.
Almost Identical Programs
The programming contest named Concours de Programmation Comtemporaine Interuniversitaire (CPCI) has a judging system similar to that of ICPC; contestants have to submit correct outputs for two different inputs to be accepted as a correct solution. Each of the submissions should include the program that generated the output. A pair of submissions is judged to be a correct solution when, in addition to the correctness of the outputs, they include an identical program.
Many contestants, however, do not stop including a different version of their programs in their second submissions, after modifying a single string literal in their programs representing the input file name, attempting to process different input. The organizers of CPCI are exploring the possibility of showing a special error message for such close submissions, indicating contestants what's wrong with such submissions. Your task is to detect such close submissions.
Input
The input consists of at most 100 datasets, each in the following format.
s1
s2
Each of s1 and s2 is a string written in a line, with the length between 1 and 200, inclusive. They are the first and the second submitted programs respectively. A program consists of lowercase letters (`a`, `b`, ..., `z`), uppercase letters (`A`, `B`, ..., `Z`), digits (`0`, `1`, ..., `9`), double quotes (`"`), and semicolons (`;`). When double quotes occur in a program, there are always even number of them.
The end of the input is indicated by a line containing one '`.`' (period).
Output
For each dataset, print the judge result in a line.
If the given two programs are identical, print `IDENTICAL`. If two programs differ with only one corresponding string literal, print `CLOSE`. Otherwise, print `DIFFERENT`. A string literal is a possibly empty sequence of characters between an odd-numbered occurrence of a double quote and the next occurrence of a double quote.
Sample Input
print"hello";print123
print"hello";print123
read"B1input";solve;output;
read"B2";solve;output;
read"C1";solve;output"C1ans";
read"C2";solve;output"C2ans";
""""""""
"""42"""""
slow"program"
fast"code"
"super"fast"program"
"super"faster"program"
X""
X
I"S""CREAM"
I"CE""CREAM"
11"22"11
1"33"111
.
Output for the Sample Input
IDENTICAL
CLOSE
DIFFERENT
CLOSE
DIFFERENT
DIFFERENT
DIFFERENT
CLOSE
DIFFERENT
Example
Input
print"hello";print123
print"hello";print123
read"B1input";solve;output;
read"B2";solve;output;
read"C1";solve;output"C1ans";
read"C2";solve;output"C2ans";
""""""""
"""42"""""
slow"program"
fast"code"
"super"fast"program"
"super"faster"program"
X""
X
I"S""CREAM"
I"CE""CREAM"
11"22"11
1"33"111
.
Output
IDENTICAL
CLOSE
DIFFERENT
CLOSE
DIFFERENT
DIFFERENT
DIFFERENT
CLOSE
DIFFERENT | instruction | 0 | 5,756 | 18 | 11,512 |
"Correct Solution:
```
results=[]
while True:
a=input().split("\"")
if a[0]==".":
break
b=input().split("\"")
count1=0
count2=0
if len(a) != len(b):
results.append(2)
else:
for i in range(len(a)):
if(i%2==1):
if len(a[i]) != len(b[i]):
count1+=1
else:
for k,l in zip(a[i],b[i]):
if(k!=l):
count1+=1
else:
if len(a[i]) != len(b[i]):
count2+=1
else:
for k,l in zip(a[i],b[i]):
if(k!=l):
count2+=1
if count1==0 and count2==0:
results.append(0)
elif count1==1 and count2==0:
results.append(1)
else:
results.append(2)
for i in results:
if i==0:
print("IDENTICAL")
if i==1:
print("CLOSE")
if i==2:
print("DIFFERENT")
``` | output | 1 | 5,756 | 18 | 11,513 |
Provide a correct Python 3 solution for this coding contest problem.
Almost Identical Programs
The programming contest named Concours de Programmation Comtemporaine Interuniversitaire (CPCI) has a judging system similar to that of ICPC; contestants have to submit correct outputs for two different inputs to be accepted as a correct solution. Each of the submissions should include the program that generated the output. A pair of submissions is judged to be a correct solution when, in addition to the correctness of the outputs, they include an identical program.
Many contestants, however, do not stop including a different version of their programs in their second submissions, after modifying a single string literal in their programs representing the input file name, attempting to process different input. The organizers of CPCI are exploring the possibility of showing a special error message for such close submissions, indicating contestants what's wrong with such submissions. Your task is to detect such close submissions.
Input
The input consists of at most 100 datasets, each in the following format.
s1
s2
Each of s1 and s2 is a string written in a line, with the length between 1 and 200, inclusive. They are the first and the second submitted programs respectively. A program consists of lowercase letters (`a`, `b`, ..., `z`), uppercase letters (`A`, `B`, ..., `Z`), digits (`0`, `1`, ..., `9`), double quotes (`"`), and semicolons (`;`). When double quotes occur in a program, there are always even number of them.
The end of the input is indicated by a line containing one '`.`' (period).
Output
For each dataset, print the judge result in a line.
If the given two programs are identical, print `IDENTICAL`. If two programs differ with only one corresponding string literal, print `CLOSE`. Otherwise, print `DIFFERENT`. A string literal is a possibly empty sequence of characters between an odd-numbered occurrence of a double quote and the next occurrence of a double quote.
Sample Input
print"hello";print123
print"hello";print123
read"B1input";solve;output;
read"B2";solve;output;
read"C1";solve;output"C1ans";
read"C2";solve;output"C2ans";
""""""""
"""42"""""
slow"program"
fast"code"
"super"fast"program"
"super"faster"program"
X""
X
I"S""CREAM"
I"CE""CREAM"
11"22"11
1"33"111
.
Output for the Sample Input
IDENTICAL
CLOSE
DIFFERENT
CLOSE
DIFFERENT
DIFFERENT
DIFFERENT
CLOSE
DIFFERENT
Example
Input
print"hello";print123
print"hello";print123
read"B1input";solve;output;
read"B2";solve;output;
read"C1";solve;output"C1ans";
read"C2";solve;output"C2ans";
""""""""
"""42"""""
slow"program"
fast"code"
"super"fast"program"
"super"faster"program"
X""
X
I"S""CREAM"
I"CE""CREAM"
11"22"11
1"33"111
.
Output
IDENTICAL
CLOSE
DIFFERENT
CLOSE
DIFFERENT
DIFFERENT
DIFFERENT
CLOSE
DIFFERENT | instruction | 0 | 5,757 | 18 | 11,514 |
"Correct Solution:
```
while 1:
s1 = input().split('"')
if s1 == ['.']: # 強制終了
break
s2 = input().split('"')
if len(s1) != len(s2): # 長さが違う場合
print("DIFFERENT")
continue
cnt = 0
for i in range(len(s1)):
if s1[i] != s2[i]:
cnt += 1
if i%2==0:
cnt += 2
else:
i+=1
if cnt == 0:
print("IDENTICAL") # 完全一致
elif cnt == 1:
print("CLOSE") # 一つ違い
else:
print("DIFFERENT") # それ以外
``` | output | 1 | 5,757 | 18 | 11,515 |
Provide a correct Python 3 solution for this coding contest problem.
Almost Identical Programs
The programming contest named Concours de Programmation Comtemporaine Interuniversitaire (CPCI) has a judging system similar to that of ICPC; contestants have to submit correct outputs for two different inputs to be accepted as a correct solution. Each of the submissions should include the program that generated the output. A pair of submissions is judged to be a correct solution when, in addition to the correctness of the outputs, they include an identical program.
Many contestants, however, do not stop including a different version of their programs in their second submissions, after modifying a single string literal in their programs representing the input file name, attempting to process different input. The organizers of CPCI are exploring the possibility of showing a special error message for such close submissions, indicating contestants what's wrong with such submissions. Your task is to detect such close submissions.
Input
The input consists of at most 100 datasets, each in the following format.
s1
s2
Each of s1 and s2 is a string written in a line, with the length between 1 and 200, inclusive. They are the first and the second submitted programs respectively. A program consists of lowercase letters (`a`, `b`, ..., `z`), uppercase letters (`A`, `B`, ..., `Z`), digits (`0`, `1`, ..., `9`), double quotes (`"`), and semicolons (`;`). When double quotes occur in a program, there are always even number of them.
The end of the input is indicated by a line containing one '`.`' (period).
Output
For each dataset, print the judge result in a line.
If the given two programs are identical, print `IDENTICAL`. If two programs differ with only one corresponding string literal, print `CLOSE`. Otherwise, print `DIFFERENT`. A string literal is a possibly empty sequence of characters between an odd-numbered occurrence of a double quote and the next occurrence of a double quote.
Sample Input
print"hello";print123
print"hello";print123
read"B1input";solve;output;
read"B2";solve;output;
read"C1";solve;output"C1ans";
read"C2";solve;output"C2ans";
""""""""
"""42"""""
slow"program"
fast"code"
"super"fast"program"
"super"faster"program"
X""
X
I"S""CREAM"
I"CE""CREAM"
11"22"11
1"33"111
.
Output for the Sample Input
IDENTICAL
CLOSE
DIFFERENT
CLOSE
DIFFERENT
DIFFERENT
DIFFERENT
CLOSE
DIFFERENT
Example
Input
print"hello";print123
print"hello";print123
read"B1input";solve;output;
read"B2";solve;output;
read"C1";solve;output"C1ans";
read"C2";solve;output"C2ans";
""""""""
"""42"""""
slow"program"
fast"code"
"super"fast"program"
"super"faster"program"
X""
X
I"S""CREAM"
I"CE""CREAM"
11"22"11
1"33"111
.
Output
IDENTICAL
CLOSE
DIFFERENT
CLOSE
DIFFERENT
DIFFERENT
DIFFERENT
CLOSE
DIFFERENT | instruction | 0 | 5,758 | 18 | 11,516 |
"Correct Solution:
```
while 1:
s1 = input().split('\"')
if s1[0] == '.': break
s2 = input().split('\"')
jdg = 1
cnt_d = 0
if len(s1) != len(s2): print("DIFFERENT")
else:
l = len(s1)
i = 0
while i < l:
if s1[i] != s2[i]:
cnt_d += 1
if cnt_d == 1 and i % 2 == 1:
jdg = 1
else:
jdg = 0
break
i += 1
if jdg == 1 and cnt_d == 1: print("CLOSE")
elif jdg == 0 or cnt_d > 1: print("DIFFERENT")
else: print("IDENTICAL")
``` | output | 1 | 5,758 | 18 | 11,517 |
Provide a correct Python 3 solution for this coding contest problem.
Almost Identical Programs
The programming contest named Concours de Programmation Comtemporaine Interuniversitaire (CPCI) has a judging system similar to that of ICPC; contestants have to submit correct outputs for two different inputs to be accepted as a correct solution. Each of the submissions should include the program that generated the output. A pair of submissions is judged to be a correct solution when, in addition to the correctness of the outputs, they include an identical program.
Many contestants, however, do not stop including a different version of their programs in their second submissions, after modifying a single string literal in their programs representing the input file name, attempting to process different input. The organizers of CPCI are exploring the possibility of showing a special error message for such close submissions, indicating contestants what's wrong with such submissions. Your task is to detect such close submissions.
Input
The input consists of at most 100 datasets, each in the following format.
s1
s2
Each of s1 and s2 is a string written in a line, with the length between 1 and 200, inclusive. They are the first and the second submitted programs respectively. A program consists of lowercase letters (`a`, `b`, ..., `z`), uppercase letters (`A`, `B`, ..., `Z`), digits (`0`, `1`, ..., `9`), double quotes (`"`), and semicolons (`;`). When double quotes occur in a program, there are always even number of them.
The end of the input is indicated by a line containing one '`.`' (period).
Output
For each dataset, print the judge result in a line.
If the given two programs are identical, print `IDENTICAL`. If two programs differ with only one corresponding string literal, print `CLOSE`. Otherwise, print `DIFFERENT`. A string literal is a possibly empty sequence of characters between an odd-numbered occurrence of a double quote and the next occurrence of a double quote.
Sample Input
print"hello";print123
print"hello";print123
read"B1input";solve;output;
read"B2";solve;output;
read"C1";solve;output"C1ans";
read"C2";solve;output"C2ans";
""""""""
"""42"""""
slow"program"
fast"code"
"super"fast"program"
"super"faster"program"
X""
X
I"S""CREAM"
I"CE""CREAM"
11"22"11
1"33"111
.
Output for the Sample Input
IDENTICAL
CLOSE
DIFFERENT
CLOSE
DIFFERENT
DIFFERENT
DIFFERENT
CLOSE
DIFFERENT
Example
Input
print"hello";print123
print"hello";print123
read"B1input";solve;output;
read"B2";solve;output;
read"C1";solve;output"C1ans";
read"C2";solve;output"C2ans";
""""""""
"""42"""""
slow"program"
fast"code"
"super"fast"program"
"super"faster"program"
X""
X
I"S""CREAM"
I"CE""CREAM"
11"22"11
1"33"111
.
Output
IDENTICAL
CLOSE
DIFFERENT
CLOSE
DIFFERENT
DIFFERENT
DIFFERENT
CLOSE
DIFFERENT | instruction | 0 | 5,759 | 18 | 11,518 |
"Correct Solution:
```
A=[]
while True:
a=input().split('"')
if a[0]==".":
break
b=input().split('"')
cnt=0
if len(a)!=len(b):
A.append(-1)
else:
for i in range(len(a)):
if(a[i]==b[i]):
pass
else:
if i%2==1:
cnt+=1
else:
cnt+=2
if cnt>=2:
A.append(-1)
if cnt==1:
A.append(0)
if cnt==0:
A.append(1)
A.reverse()
#print(A)
for i in range(len(A)):
tmp=A.pop()
if tmp==-1:
print("DIFFERENT")
elif tmp==0:
print("CLOSE")
else:
print("IDENTICAL")
``` | output | 1 | 5,759 | 18 | 11,519 |
Provide a correct Python 3 solution for this coding contest problem.
Almost Identical Programs
The programming contest named Concours de Programmation Comtemporaine Interuniversitaire (CPCI) has a judging system similar to that of ICPC; contestants have to submit correct outputs for two different inputs to be accepted as a correct solution. Each of the submissions should include the program that generated the output. A pair of submissions is judged to be a correct solution when, in addition to the correctness of the outputs, they include an identical program.
Many contestants, however, do not stop including a different version of their programs in their second submissions, after modifying a single string literal in their programs representing the input file name, attempting to process different input. The organizers of CPCI are exploring the possibility of showing a special error message for such close submissions, indicating contestants what's wrong with such submissions. Your task is to detect such close submissions.
Input
The input consists of at most 100 datasets, each in the following format.
s1
s2
Each of s1 and s2 is a string written in a line, with the length between 1 and 200, inclusive. They are the first and the second submitted programs respectively. A program consists of lowercase letters (`a`, `b`, ..., `z`), uppercase letters (`A`, `B`, ..., `Z`), digits (`0`, `1`, ..., `9`), double quotes (`"`), and semicolons (`;`). When double quotes occur in a program, there are always even number of them.
The end of the input is indicated by a line containing one '`.`' (period).
Output
For each dataset, print the judge result in a line.
If the given two programs are identical, print `IDENTICAL`. If two programs differ with only one corresponding string literal, print `CLOSE`. Otherwise, print `DIFFERENT`. A string literal is a possibly empty sequence of characters between an odd-numbered occurrence of a double quote and the next occurrence of a double quote.
Sample Input
print"hello";print123
print"hello";print123
read"B1input";solve;output;
read"B2";solve;output;
read"C1";solve;output"C1ans";
read"C2";solve;output"C2ans";
""""""""
"""42"""""
slow"program"
fast"code"
"super"fast"program"
"super"faster"program"
X""
X
I"S""CREAM"
I"CE""CREAM"
11"22"11
1"33"111
.
Output for the Sample Input
IDENTICAL
CLOSE
DIFFERENT
CLOSE
DIFFERENT
DIFFERENT
DIFFERENT
CLOSE
DIFFERENT
Example
Input
print"hello";print123
print"hello";print123
read"B1input";solve;output;
read"B2";solve;output;
read"C1";solve;output"C1ans";
read"C2";solve;output"C2ans";
""""""""
"""42"""""
slow"program"
fast"code"
"super"fast"program"
"super"faster"program"
X""
X
I"S""CREAM"
I"CE""CREAM"
11"22"11
1"33"111
.
Output
IDENTICAL
CLOSE
DIFFERENT
CLOSE
DIFFERENT
DIFFERENT
DIFFERENT
CLOSE
DIFFERENT | instruction | 0 | 5,760 | 18 | 11,520 |
"Correct Solution:
```
while True:
s = input().split('"')
if s == ['.']:
exit()
t = input().split('"')
is_diff = False
is_close = 0
if len(s) == len(t):
for i in range(len(s)):
if i % 2 == 0:
if s[i] != t[i]:
is_diff = True
else:
if s[i] != t[i]:
is_close += 1
else:
is_diff = True
if is_diff:
print('DIFFERENT')
elif is_close == 0:
print('IDENTICAL')
else:
print(['CLOSE', 'DIFFERENT'][is_close > 1])
``` | output | 1 | 5,760 | 18 | 11,521 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:
* S is a palindrome.
* Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.
* The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.
Determine whether S is a strong palindrome.
Constraints
* S consists of lowercase English letters.
* The length of S is an odd number between 3 and 99 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
If S is a strong palindrome, print `Yes`; otherwise, print `No`.
Examples
Input
akasaka
Output
Yes
Input
level
Output
No
Input
atcoder
Output
No
Submitted Solution:
```
S = input()
H = len(S)//2
if S[:H] == S[-H:] and S[:H] == S[-H:][::-1]:
print("Yes")
else:
print("No")
``` | instruction | 0 | 6,389 | 18 | 12,778 |
Yes | output | 1 | 6,389 | 18 | 12,779 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:
* S is a palindrome.
* Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.
* The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.
Determine whether S is a strong palindrome.
Constraints
* S consists of lowercase English letters.
* The length of S is an odd number between 3 and 99 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
If S is a strong palindrome, print `Yes`; otherwise, print `No`.
Examples
Input
akasaka
Output
Yes
Input
level
Output
No
Input
atcoder
Output
No
Submitted Solution:
```
s = list(input())
if s[0:(len(s) - 1)//2] == s[(len(s)+2)//2:len(s)]:
print('Yes')
else:
print('No')
``` | instruction | 0 | 6,390 | 18 | 12,780 |
Yes | output | 1 | 6,390 | 18 | 12,781 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:
* S is a palindrome.
* Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.
* The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.
Determine whether S is a strong palindrome.
Constraints
* S consists of lowercase English letters.
* The length of S is an odd number between 3 and 99 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
If S is a strong palindrome, print `Yes`; otherwise, print `No`.
Examples
Input
akasaka
Output
Yes
Input
level
Output
No
Input
atcoder
Output
No
Submitted Solution:
```
s = input()
n = len(s)
a = s[:((n-1)//2)]
if a == a[::-1] and s == s[::-1]:
print('Yes')
else:
print('No')
``` | instruction | 0 | 6,391 | 18 | 12,782 |
Yes | output | 1 | 6,391 | 18 | 12,783 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:
* S is a palindrome.
* Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.
* The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.
Determine whether S is a strong palindrome.
Constraints
* S consists of lowercase English letters.
* The length of S is an odd number between 3 and 99 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
If S is a strong palindrome, print `Yes`; otherwise, print `No`.
Examples
Input
akasaka
Output
Yes
Input
level
Output
No
Input
atcoder
Output
No
Submitted Solution:
```
S = input()
N = len(S)
if S[0:(N-1)//2] == S[((N+3)//2)-1:N]:
print("Yes")
else:
print("No")
``` | instruction | 0 | 6,392 | 18 | 12,784 |
Yes | output | 1 | 6,392 | 18 | 12,785 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:
* S is a palindrome.
* Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.
* The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.
Determine whether S is a strong palindrome.
Constraints
* S consists of lowercase English letters.
* The length of S is an odd number between 3 and 99 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
If S is a strong palindrome, print `Yes`; otherwise, print `No`.
Examples
Input
akasaka
Output
Yes
Input
level
Output
No
Input
atcoder
Output
No
Submitted Solution:
```
s = list(input())
n = len(s)
ls = []
l1 = (n-1)//2
l2 = (n+3)//2
h = l1//2
f = True
for i in range(h):
if s[i] == s[l1-i-1]:
pass
else:
f = False
if s[-i-1] == s[l2+i-1]:
pass
else:
f = False
if f:
print("Yes")
else:
print("No")
``` | instruction | 0 | 6,393 | 18 | 12,786 |
No | output | 1 | 6,393 | 18 | 12,787 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:
* S is a palindrome.
* Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.
* The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.
Determine whether S is a strong palindrome.
Constraints
* S consists of lowercase English letters.
* The length of S is an odd number between 3 and 99 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
If S is a strong palindrome, print `Yes`; otherwise, print `No`.
Examples
Input
akasaka
Output
Yes
Input
level
Output
No
Input
atcoder
Output
No
Submitted Solution:
```
S = input()
N = len(S)
i = list(S)
if i[0:((N+3)//2-2)] == [((N+3)//2):N]:
print('Yes')
elif:
print('No')
``` | instruction | 0 | 6,394 | 18 | 12,788 |
No | output | 1 | 6,394 | 18 | 12,789 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:
* S is a palindrome.
* Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.
* The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.
Determine whether S is a strong palindrome.
Constraints
* S consists of lowercase English letters.
* The length of S is an odd number between 3 and 99 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
If S is a strong palindrome, print `Yes`; otherwise, print `No`.
Examples
Input
akasaka
Output
Yes
Input
level
Output
No
Input
atcoder
Output
No
Submitted Solution:
```
def palindrome(str):
n = len(str)
for i in range(n // 2):
if str[i] != str[n - 1 - i]:
return False
return True
str = input()
is_palindrome = palindrome(str)
n = len(str)
if n % 2 == 1:
is_palindrome = palindrome(str[:n // 2]) and palindrome(str[n // 2 + 1:])
print("Yes" if is_palindrome else "No")
``` | instruction | 0 | 6,395 | 18 | 12,790 |
No | output | 1 | 6,395 | 18 | 12,791 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:
* S is a palindrome.
* Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.
* The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.
Determine whether S is a strong palindrome.
Constraints
* S consists of lowercase English letters.
* The length of S is an odd number between 3 and 99 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
If S is a strong palindrome, print `Yes`; otherwise, print `No`.
Examples
Input
akasaka
Output
Yes
Input
level
Output
No
Input
atcoder
Output
No
Submitted Solution:
```
def check(a):
i=0
j=len(a)-1
b=True
while(i<=j):
if(a[i]!=a[j]):
return False
i+=1;
j-=1
return b
a=(input())
b=a[:(len(a)-1)//2:]
c=a[(len(a)+3)//2::]
if(check(a)==True and check(b)==True and check(c)==True):
print("Yes")
else:
print("No")
``` | instruction | 0 | 6,396 | 18 | 12,792 |
No | output | 1 | 6,396 | 18 | 12,793 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Codehorses has just hosted the second Codehorses Cup. This year, the same as the previous one, organizers are giving T-shirts for the winners.
The valid sizes of T-shirts are either "M" or from 0 to 3 "X" followed by "S" or "L". For example, sizes "M", "XXS", "L", "XXXL" are valid and "XM", "Z", "XXXXL" are not.
There are n winners to the cup for both the previous year and the current year. Ksenia has a list with the T-shirt sizes printed for the last year cup and is yet to send the new list to the printing office.
Organizers want to distribute the prizes as soon as possible, so now Ksenia is required not to write the whole list from the scratch but just make some changes to the list of the previous year. In one second she can choose arbitrary position in any word and replace its character with some uppercase Latin letter. Ksenia can't remove or add letters in any of the words.
What is the minimal number of seconds Ksenia is required to spend to change the last year list to the current one?
The lists are unordered. That means, two lists are considered equal if and only if the number of occurrences of any string is the same in both lists.
Input
The first line contains one integer n (1 ≤ n ≤ 100) — the number of T-shirts.
The i-th of the next n lines contains a_i — the size of the i-th T-shirt of the list for the previous year.
The i-th of the next n lines contains b_i — the size of the i-th T-shirt of the list for the current year.
It is guaranteed that all the sizes in the input are valid. It is also guaranteed that Ksenia can produce list b from the list a.
Output
Print the minimal number of seconds Ksenia is required to spend to change the last year list to the current one. If the lists are already equal, print 0.
Examples
Input
3
XS
XS
M
XL
S
XS
Output
2
Input
2
XXXL
XXL
XXL
XXXS
Output
1
Input
2
M
XS
XS
M
Output
0
Note
In the first example Ksenia can replace "M" with "S" and "S" in one of the occurrences of "XS" with "L".
In the second example Ksenia should replace "L" in "XXXL" with "S".
In the third example lists are equal.
Submitted Solution:
```
n = int(input())
l1 = [input() for i in range(n)]
l2 = [input() for i in range(n)]
count = 0
for item in l1:
if item in l2:
l2.remove(item)
count += 1
print(n - count)
``` | instruction | 0 | 6,580 | 18 | 13,160 |
Yes | output | 1 | 6,580 | 18 | 13,161 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Codehorses has just hosted the second Codehorses Cup. This year, the same as the previous one, organizers are giving T-shirts for the winners.
The valid sizes of T-shirts are either "M" or from 0 to 3 "X" followed by "S" or "L". For example, sizes "M", "XXS", "L", "XXXL" are valid and "XM", "Z", "XXXXL" are not.
There are n winners to the cup for both the previous year and the current year. Ksenia has a list with the T-shirt sizes printed for the last year cup and is yet to send the new list to the printing office.
Organizers want to distribute the prizes as soon as possible, so now Ksenia is required not to write the whole list from the scratch but just make some changes to the list of the previous year. In one second she can choose arbitrary position in any word and replace its character with some uppercase Latin letter. Ksenia can't remove or add letters in any of the words.
What is the minimal number of seconds Ksenia is required to spend to change the last year list to the current one?
The lists are unordered. That means, two lists are considered equal if and only if the number of occurrences of any string is the same in both lists.
Input
The first line contains one integer n (1 ≤ n ≤ 100) — the number of T-shirts.
The i-th of the next n lines contains a_i — the size of the i-th T-shirt of the list for the previous year.
The i-th of the next n lines contains b_i — the size of the i-th T-shirt of the list for the current year.
It is guaranteed that all the sizes in the input are valid. It is also guaranteed that Ksenia can produce list b from the list a.
Output
Print the minimal number of seconds Ksenia is required to spend to change the last year list to the current one. If the lists are already equal, print 0.
Examples
Input
3
XS
XS
M
XL
S
XS
Output
2
Input
2
XXXL
XXL
XXL
XXXS
Output
1
Input
2
M
XS
XS
M
Output
0
Note
In the first example Ksenia can replace "M" with "S" and "S" in one of the occurrences of "XS" with "L".
In the second example Ksenia should replace "L" in "XXXL" with "S".
In the third example lists are equal.
Submitted Solution:
```
n=int(input())
a=[[0,0,0],[0,0,0],[0,0,0],[0,0,0]]
b='SLM'
o=0
for i in range(n):
i=input()
a[len(i)-1][b.index(i[-1])]+=1
for i in range(n):
i=input()
o+=1
if a[len(i)-1][b.index(i[-1])]>0:
a[len(i)-1][b.index(i[-1])]-=1
o-=1
print(o)
``` | instruction | 0 | 6,581 | 18 | 13,162 |
Yes | output | 1 | 6,581 | 18 | 13,163 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Codehorses has just hosted the second Codehorses Cup. This year, the same as the previous one, organizers are giving T-shirts for the winners.
The valid sizes of T-shirts are either "M" or from 0 to 3 "X" followed by "S" or "L". For example, sizes "M", "XXS", "L", "XXXL" are valid and "XM", "Z", "XXXXL" are not.
There are n winners to the cup for both the previous year and the current year. Ksenia has a list with the T-shirt sizes printed for the last year cup and is yet to send the new list to the printing office.
Organizers want to distribute the prizes as soon as possible, so now Ksenia is required not to write the whole list from the scratch but just make some changes to the list of the previous year. In one second she can choose arbitrary position in any word and replace its character with some uppercase Latin letter. Ksenia can't remove or add letters in any of the words.
What is the minimal number of seconds Ksenia is required to spend to change the last year list to the current one?
The lists are unordered. That means, two lists are considered equal if and only if the number of occurrences of any string is the same in both lists.
Input
The first line contains one integer n (1 ≤ n ≤ 100) — the number of T-shirts.
The i-th of the next n lines contains a_i — the size of the i-th T-shirt of the list for the previous year.
The i-th of the next n lines contains b_i — the size of the i-th T-shirt of the list for the current year.
It is guaranteed that all the sizes in the input are valid. It is also guaranteed that Ksenia can produce list b from the list a.
Output
Print the minimal number of seconds Ksenia is required to spend to change the last year list to the current one. If the lists are already equal, print 0.
Examples
Input
3
XS
XS
M
XL
S
XS
Output
2
Input
2
XXXL
XXL
XXL
XXXS
Output
1
Input
2
M
XS
XS
M
Output
0
Note
In the first example Ksenia can replace "M" with "S" and "S" in one of the occurrences of "XS" with "L".
In the second example Ksenia should replace "L" in "XXXL" with "S".
In the third example lists are equal.
Submitted Solution:
```
t=int(input())
pre=[]
curr=[]
for i in range(t):
s1=input()
pre.append(s1)
for i in range(t):
s2=input()
curr.append(s2)
z=0
for i in range(t):
if pre[i] in curr:
curr.remove(pre[i])
pass
else:
z+=1
print(z)
``` | instruction | 0 | 6,582 | 18 | 13,164 |
Yes | output | 1 | 6,582 | 18 | 13,165 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Codehorses has just hosted the second Codehorses Cup. This year, the same as the previous one, organizers are giving T-shirts for the winners.
The valid sizes of T-shirts are either "M" or from 0 to 3 "X" followed by "S" or "L". For example, sizes "M", "XXS", "L", "XXXL" are valid and "XM", "Z", "XXXXL" are not.
There are n winners to the cup for both the previous year and the current year. Ksenia has a list with the T-shirt sizes printed for the last year cup and is yet to send the new list to the printing office.
Organizers want to distribute the prizes as soon as possible, so now Ksenia is required not to write the whole list from the scratch but just make some changes to the list of the previous year. In one second she can choose arbitrary position in any word and replace its character with some uppercase Latin letter. Ksenia can't remove or add letters in any of the words.
What is the minimal number of seconds Ksenia is required to spend to change the last year list to the current one?
The lists are unordered. That means, two lists are considered equal if and only if the number of occurrences of any string is the same in both lists.
Input
The first line contains one integer n (1 ≤ n ≤ 100) — the number of T-shirts.
The i-th of the next n lines contains a_i — the size of the i-th T-shirt of the list for the previous year.
The i-th of the next n lines contains b_i — the size of the i-th T-shirt of the list for the current year.
It is guaranteed that all the sizes in the input are valid. It is also guaranteed that Ksenia can produce list b from the list a.
Output
Print the minimal number of seconds Ksenia is required to spend to change the last year list to the current one. If the lists are already equal, print 0.
Examples
Input
3
XS
XS
M
XL
S
XS
Output
2
Input
2
XXXL
XXL
XXL
XXXS
Output
1
Input
2
M
XS
XS
M
Output
0
Note
In the first example Ksenia can replace "M" with "S" and "S" in one of the occurrences of "XS" with "L".
In the second example Ksenia should replace "L" in "XXXL" with "S".
In the third example lists are equal.
Submitted Solution:
```
n = int(input())
li_a = []
li_b = []
flag = 0
for i in range(n):
li_a.append(input())
for i in range(n):
li_b.append(input())
for i in range(n):
if li_a[i] in li_b:
li_b.remove(li_a[i])
else:
flag+=1
print(flag)
``` | instruction | 0 | 6,583 | 18 | 13,166 |
Yes | output | 1 | 6,583 | 18 | 13,167 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Codehorses has just hosted the second Codehorses Cup. This year, the same as the previous one, organizers are giving T-shirts for the winners.
The valid sizes of T-shirts are either "M" or from 0 to 3 "X" followed by "S" or "L". For example, sizes "M", "XXS", "L", "XXXL" are valid and "XM", "Z", "XXXXL" are not.
There are n winners to the cup for both the previous year and the current year. Ksenia has a list with the T-shirt sizes printed for the last year cup and is yet to send the new list to the printing office.
Organizers want to distribute the prizes as soon as possible, so now Ksenia is required not to write the whole list from the scratch but just make some changes to the list of the previous year. In one second she can choose arbitrary position in any word and replace its character with some uppercase Latin letter. Ksenia can't remove or add letters in any of the words.
What is the minimal number of seconds Ksenia is required to spend to change the last year list to the current one?
The lists are unordered. That means, two lists are considered equal if and only if the number of occurrences of any string is the same in both lists.
Input
The first line contains one integer n (1 ≤ n ≤ 100) — the number of T-shirts.
The i-th of the next n lines contains a_i — the size of the i-th T-shirt of the list for the previous year.
The i-th of the next n lines contains b_i — the size of the i-th T-shirt of the list for the current year.
It is guaranteed that all the sizes in the input are valid. It is also guaranteed that Ksenia can produce list b from the list a.
Output
Print the minimal number of seconds Ksenia is required to spend to change the last year list to the current one. If the lists are already equal, print 0.
Examples
Input
3
XS
XS
M
XL
S
XS
Output
2
Input
2
XXXL
XXL
XXL
XXXS
Output
1
Input
2
M
XS
XS
M
Output
0
Note
In the first example Ksenia can replace "M" with "S" and "S" in one of the occurrences of "XS" with "L".
In the second example Ksenia should replace "L" in "XXXL" with "S".
In the third example lists are equal.
Submitted Solution:
```
# -*- coding: utf-8 -*-
"""
Created on Mon Aug 5 19:42:00 2019
@author: Akshay
"""
n=int(input())
arr=[]
for i in range(0,n):
arr.append(input())
d={}
for i in range(0,n):
temp=input()
if temp not in d:
d[temp]=1
else:
d[temp]+=1
count=0
for i in arr:
last=i[-1]
if i in d and d[i]!=0:
d[i]-=1
elif len(i)==1:
if last=="M":
if d["S"]!=0:
d["S"]-=1
count+=1
elif d["L"]!=0:
d["L"]-=1
count+=1
elif last=="S":
if d["M"]!=0:
d["M"]-=1
count+=1
elif d["L"]!=0:
d["L"]-=1
count+=1
elif last=="L":
if d["M"]!=0:
d["M"]-=1
count+=1
elif d["S"]!=0:
d["S"]-=1
count+=1
else:
if last=="L" and (i[:-1]+"S") in d and d[i[:-1]+"S"]!=0:
count+=1
if last=="S" and (i[:-1]+"L") in d and d[i[:-1]+"L"]!=0:
count+=1
print(count)
``` | instruction | 0 | 6,584 | 18 | 13,168 |
No | output | 1 | 6,584 | 18 | 13,169 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Codehorses has just hosted the second Codehorses Cup. This year, the same as the previous one, organizers are giving T-shirts for the winners.
The valid sizes of T-shirts are either "M" or from 0 to 3 "X" followed by "S" or "L". For example, sizes "M", "XXS", "L", "XXXL" are valid and "XM", "Z", "XXXXL" are not.
There are n winners to the cup for both the previous year and the current year. Ksenia has a list with the T-shirt sizes printed for the last year cup and is yet to send the new list to the printing office.
Organizers want to distribute the prizes as soon as possible, so now Ksenia is required not to write the whole list from the scratch but just make some changes to the list of the previous year. In one second she can choose arbitrary position in any word and replace its character with some uppercase Latin letter. Ksenia can't remove or add letters in any of the words.
What is the minimal number of seconds Ksenia is required to spend to change the last year list to the current one?
The lists are unordered. That means, two lists are considered equal if and only if the number of occurrences of any string is the same in both lists.
Input
The first line contains one integer n (1 ≤ n ≤ 100) — the number of T-shirts.
The i-th of the next n lines contains a_i — the size of the i-th T-shirt of the list for the previous year.
The i-th of the next n lines contains b_i — the size of the i-th T-shirt of the list for the current year.
It is guaranteed that all the sizes in the input are valid. It is also guaranteed that Ksenia can produce list b from the list a.
Output
Print the minimal number of seconds Ksenia is required to spend to change the last year list to the current one. If the lists are already equal, print 0.
Examples
Input
3
XS
XS
M
XL
S
XS
Output
2
Input
2
XXXL
XXL
XXL
XXXS
Output
1
Input
2
M
XS
XS
M
Output
0
Note
In the first example Ksenia can replace "M" with "S" and "S" in one of the occurrences of "XS" with "L".
In the second example Ksenia should replace "L" in "XXXL" with "S".
In the third example lists are equal.
Submitted Solution:
```
num = int(input())
old, new = set(), set()
count = 0
for i in range(num):
old.add(input())
for i in range(num):
new.add(input())
intersec = old & new
old - intersec
new - intersec
old = sorted(old, key = lambda item: len(item))
new = sorted(new, key = lambda item: len(item))
for i in range(len(old)):
if (len(old[i]) == len(new[i])):
for j in range(len(old[i])):
if (old[i][j] != new[i][j]):
count += 1
print(count)
``` | instruction | 0 | 6,585 | 18 | 13,170 |
No | output | 1 | 6,585 | 18 | 13,171 |
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