message stringlengths 2 11.9k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 137 108k | cluster float64 18 18 | __index_level_0__ int64 274 217k |
|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
This contest, AtCoder Beginner Contest, is abbreviated as ABC.
When we refer to a specific round of ABC, a three-digit number is appended after ABC. For example, ABC680 is the 680th round of ABC.
What is the abbreviation for the N-th round of ABC? Write a program to output the answer.
Constraints
* 100 ≤ N ≤ 999
Input
Input is given from Standard Input in the following format:
N
Output
Print the abbreviation for the N-th round of ABC.
Examples
Input
100
Output
ABC100
Input
425
Output
ABC425
Input
999
Output
ABC999 | instruction | 0 | 74,058 | 18 | 148,116 |
"Correct Solution:
```
n = input()
print('ABC' + str(n))
``` | output | 1 | 74,058 | 18 | 148,117 |
Provide a correct Python 3 solution for this coding contest problem.
This contest, AtCoder Beginner Contest, is abbreviated as ABC.
When we refer to a specific round of ABC, a three-digit number is appended after ABC. For example, ABC680 is the 680th round of ABC.
What is the abbreviation for the N-th round of ABC? Write a program to output the answer.
Constraints
* 100 ≤ N ≤ 999
Input
Input is given from Standard Input in the following format:
N
Output
Print the abbreviation for the N-th round of ABC.
Examples
Input
100
Output
ABC100
Input
425
Output
ABC425
Input
999
Output
ABC999 | instruction | 0 | 74,059 | 18 | 148,118 |
"Correct Solution:
```
print("ABC{0}".format(input()))
``` | output | 1 | 74,059 | 18 | 148,119 |
Provide a correct Python 3 solution for this coding contest problem.
This contest, AtCoder Beginner Contest, is abbreviated as ABC.
When we refer to a specific round of ABC, a three-digit number is appended after ABC. For example, ABC680 is the 680th round of ABC.
What is the abbreviation for the N-th round of ABC? Write a program to output the answer.
Constraints
* 100 ≤ N ≤ 999
Input
Input is given from Standard Input in the following format:
N
Output
Print the abbreviation for the N-th round of ABC.
Examples
Input
100
Output
ABC100
Input
425
Output
ABC425
Input
999
Output
ABC999 | instruction | 0 | 74,062 | 18 | 148,124 |
"Correct Solution:
```
n = input()
s = 'ABC' + n
print(s)
``` | output | 1 | 74,062 | 18 | 148,125 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You found a mysterious function f. The function takes two strings s1 and s2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function f is another string of the same length. The i-th character of the output is equal to the minimum of the i-th character of s1 and the i-th character of s2.
For example, f("ab", "ba") = "aa", and f("nzwzl", "zizez") = "niwel".
You found two strings x and y of the same length and consisting of only lowercase English letters. Find any string z such that f(x, z) = y, or print -1 if no such string z exists.
Input
The first line of input contains the string x.
The second line of input contains the string y.
Both x and y consist only of lowercase English letters, x and y have same length and this length is between 1 and 100.
Output
If there is no string z such that f(x, z) = y, print -1.
Otherwise, print a string z such that f(x, z) = y. If there are multiple possible answers, print any of them. The string z should be the same length as x and y and consist only of lowercase English letters.
Examples
Input
ab
aa
Output
ba
Input
nzwzl
niwel
Output
xiyez
Input
ab
ba
Output
-1
Note
The first case is from the statement.
Another solution for the second case is "zizez"
There is no solution for the third case. That is, there is no z such that f("ab", z) = "ba". | instruction | 0 | 74,674 | 18 | 149,348 |
Tags: constructive algorithms, greedy, strings
Correct Solution:
```
a=input()
b=input()
ans=""
for i in range(len(a)):
if a[i]==b[i]:
ans+=a[i]
elif a[i]>b[i]:
ans+=b[i]
else:
print(-1)
exit(0);
print(ans)
``` | output | 1 | 74,674 | 18 | 149,349 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You found a mysterious function f. The function takes two strings s1 and s2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function f is another string of the same length. The i-th character of the output is equal to the minimum of the i-th character of s1 and the i-th character of s2.
For example, f("ab", "ba") = "aa", and f("nzwzl", "zizez") = "niwel".
You found two strings x and y of the same length and consisting of only lowercase English letters. Find any string z such that f(x, z) = y, or print -1 if no such string z exists.
Input
The first line of input contains the string x.
The second line of input contains the string y.
Both x and y consist only of lowercase English letters, x and y have same length and this length is between 1 and 100.
Output
If there is no string z such that f(x, z) = y, print -1.
Otherwise, print a string z such that f(x, z) = y. If there are multiple possible answers, print any of them. The string z should be the same length as x and y and consist only of lowercase English letters.
Examples
Input
ab
aa
Output
ba
Input
nzwzl
niwel
Output
xiyez
Input
ab
ba
Output
-1
Note
The first case is from the statement.
Another solution for the second case is "zizez"
There is no solution for the third case. That is, there is no z such that f("ab", z) = "ba". | instruction | 0 | 74,675 | 18 | 149,350 |
Tags: constructive algorithms, greedy, strings
Correct Solution:
```
arg =input()
res =input()
if arg < res:
print ("-1")
quit()
b =""
for i in range(len(arg)):
if arg[i] < res[i]:
print ("-1")
quit()
elif arg[i] == res[i]:b+=str(arg[i])
elif arg[i] > res[i]:b+=str(res[i])
print (b)
``` | output | 1 | 74,675 | 18 | 149,351 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You found a mysterious function f. The function takes two strings s1 and s2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function f is another string of the same length. The i-th character of the output is equal to the minimum of the i-th character of s1 and the i-th character of s2.
For example, f("ab", "ba") = "aa", and f("nzwzl", "zizez") = "niwel".
You found two strings x and y of the same length and consisting of only lowercase English letters. Find any string z such that f(x, z) = y, or print -1 if no such string z exists.
Input
The first line of input contains the string x.
The second line of input contains the string y.
Both x and y consist only of lowercase English letters, x and y have same length and this length is between 1 and 100.
Output
If there is no string z such that f(x, z) = y, print -1.
Otherwise, print a string z such that f(x, z) = y. If there are multiple possible answers, print any of them. The string z should be the same length as x and y and consist only of lowercase English letters.
Examples
Input
ab
aa
Output
ba
Input
nzwzl
niwel
Output
xiyez
Input
ab
ba
Output
-1
Note
The first case is from the statement.
Another solution for the second case is "zizez"
There is no solution for the third case. That is, there is no z such that f("ab", z) = "ba". | instruction | 0 | 74,676 | 18 | 149,352 |
Tags: constructive algorithms, greedy, strings
Correct Solution:
```
word1 = input()
word2 = input()
store = ''
for i in range(len(word1)):
if ord(word1[i]) >= ord(word2[i]):
store = store + word2[i]
else:
store = '-1'
break
# else:
# store = store + word1[i]
print(store)
``` | output | 1 | 74,676 | 18 | 149,353 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You found a mysterious function f. The function takes two strings s1 and s2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function f is another string of the same length. The i-th character of the output is equal to the minimum of the i-th character of s1 and the i-th character of s2.
For example, f("ab", "ba") = "aa", and f("nzwzl", "zizez") = "niwel".
You found two strings x and y of the same length and consisting of only lowercase English letters. Find any string z such that f(x, z) = y, or print -1 if no such string z exists.
Input
The first line of input contains the string x.
The second line of input contains the string y.
Both x and y consist only of lowercase English letters, x and y have same length and this length is between 1 and 100.
Output
If there is no string z such that f(x, z) = y, print -1.
Otherwise, print a string z such that f(x, z) = y. If there are multiple possible answers, print any of them. The string z should be the same length as x and y and consist only of lowercase English letters.
Examples
Input
ab
aa
Output
ba
Input
nzwzl
niwel
Output
xiyez
Input
ab
ba
Output
-1
Note
The first case is from the statement.
Another solution for the second case is "zizez"
There is no solution for the third case. That is, there is no z such that f("ab", z) = "ba". | instruction | 0 | 74,677 | 18 | 149,354 |
Tags: constructive algorithms, greedy, strings
Correct Solution:
```
str1, str2 = input(), input()
ss = ''.join([min(str1[i], str2[i]) for i in range(len(str1))])
for i in range(len(str1)):
if (str1[i] != str2[i]) and (str1[i] < str2[i] or str1[i] == 'a'):
ss = "-1"
break
print(ss)
``` | output | 1 | 74,677 | 18 | 149,355 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You found a mysterious function f. The function takes two strings s1 and s2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function f is another string of the same length. The i-th character of the output is equal to the minimum of the i-th character of s1 and the i-th character of s2.
For example, f("ab", "ba") = "aa", and f("nzwzl", "zizez") = "niwel".
You found two strings x and y of the same length and consisting of only lowercase English letters. Find any string z such that f(x, z) = y, or print -1 if no such string z exists.
Input
The first line of input contains the string x.
The second line of input contains the string y.
Both x and y consist only of lowercase English letters, x and y have same length and this length is between 1 and 100.
Output
If there is no string z such that f(x, z) = y, print -1.
Otherwise, print a string z such that f(x, z) = y. If there are multiple possible answers, print any of them. The string z should be the same length as x and y and consist only of lowercase English letters.
Examples
Input
ab
aa
Output
ba
Input
nzwzl
niwel
Output
xiyez
Input
ab
ba
Output
-1
Note
The first case is from the statement.
Another solution for the second case is "zizez"
There is no solution for the third case. That is, there is no z such that f("ab", z) = "ba". | instruction | 0 | 74,678 | 18 | 149,356 |
Tags: constructive algorithms, greedy, strings
Correct Solution:
```
"""
Author - Satwik Tiwari .
27th Sept , 2020 - Sunday
"""
#===============================================================================================
#importing some useful libraries.
from __future__ import division, print_function
from fractions import Fraction
import sys
import os
from io import BytesIO, IOBase
# from itertools import *
from heapq import *
# from math import gcd, factorial,floor,ceil
from copy import deepcopy
from collections import deque
# from collections import Counter as counter # Counter(list) return a dict with {key: count}
# from itertools import combinations as comb # if a = [1,2,3] then print(list(comb(a,2))) -----> [(1, 2), (1, 3), (2, 3)]
# from itertools import permutations as permutate
from bisect import bisect_left as bl
from bisect import bisect_right as br
from bisect import bisect
#==============================================================================================
#fast I/O region
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
def print(*args, **kwargs):
"""Prints the values to a stream, or to sys.stdout by default."""
sep, file = kwargs.pop("sep", " "), kwargs.pop("file", sys.stdout)
at_start = True
for x in args:
if not at_start:
file.write(sep)
file.write(str(x))
at_start = False
file.write(kwargs.pop("end", "\n"))
if kwargs.pop("flush", False):
file.flush()
if sys.version_info[0] < 3:
sys.stdin, sys.stdout = FastIO(sys.stdin), FastIO(sys.stdout)
else:
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
# inp = lambda: sys.stdin.readline().rstrip("\r\n")
#===============================================================================================
### START ITERATE RECURSION ###
from types import GeneratorType
def iterative(f, stack=[]):
def wrapped_func(*args, **kwargs):
if stack: return f(*args, **kwargs)
to = f(*args, **kwargs)
while True:
if type(to) is GeneratorType:
stack.append(to)
to = next(to)
continue
stack.pop()
if not stack: break
to = stack[-1].send(to)
return to
return wrapped_func
#### END ITERATE RECURSION ####
#===============================================================================================
#some shortcuts
mod = 10**9+7
def inp(): return sys.stdin.readline().rstrip("\r\n") #for fast input
def out(var): sys.stdout.write(str(var)) #for fast output, always take string
def lis(): return list(map(int, inp().split()))
def stringlis(): return list(map(str, inp().split()))
def sep(): return map(int, inp().split())
def strsep(): return map(str, inp().split())
# def graph(vertex): return [[] for i in range(0,vertex+1)]
def zerolist(n): return [0]*n
def nextline(): out("\n") #as stdout.write always print sring.
def testcase(t):
for pp in range(t):
solve(pp)
def printlist(a) :
for p in range(0,len(a)):
out(str(a[p]) + ' ')
def google(p):
print('Case #'+str(p)+': ',end='')
def lcm(a,b): return (a*b)//gcd(a,b)
def power(x, y, p) :
res = 1 # Initialize result
x = x % p # Update x if it is more , than or equal to p
if (x == 0) :
return 0
while (y > 0) :
if ((y & 1) == 1) : # If y is odd, multiply, x with result
res = (res * x) % p
y = y >> 1 # y = y/2
x = (x * x) % p
return res
def ncr(n,r): return factorial(n) // (factorial(r) * factorial(max(n - r, 1)))
def isPrime(n) :
if (n <= 1) : return False
if (n <= 3) : return True
if (n % 2 == 0 or n % 3 == 0) : return False
i = 5
while(i * i <= n) :
if (n % i == 0 or n % (i + 2) == 0) :
return False
i = i + 6
return True
#===============================================================================================
# code here ;))
def solve(case):
a = inp()
b = inp()
for i in range(len(a)):
if(b[i] <=a[i]):
continue
else:
print(-1)
return
print(b)
testcase(1)
# testcase(int(inp()))
``` | output | 1 | 74,678 | 18 | 149,357 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You found a mysterious function f. The function takes two strings s1 and s2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function f is another string of the same length. The i-th character of the output is equal to the minimum of the i-th character of s1 and the i-th character of s2.
For example, f("ab", "ba") = "aa", and f("nzwzl", "zizez") = "niwel".
You found two strings x and y of the same length and consisting of only lowercase English letters. Find any string z such that f(x, z) = y, or print -1 if no such string z exists.
Input
The first line of input contains the string x.
The second line of input contains the string y.
Both x and y consist only of lowercase English letters, x and y have same length and this length is between 1 and 100.
Output
If there is no string z such that f(x, z) = y, print -1.
Otherwise, print a string z such that f(x, z) = y. If there are multiple possible answers, print any of them. The string z should be the same length as x and y and consist only of lowercase English letters.
Examples
Input
ab
aa
Output
ba
Input
nzwzl
niwel
Output
xiyez
Input
ab
ba
Output
-1
Note
The first case is from the statement.
Another solution for the second case is "zizez"
There is no solution for the third case. That is, there is no z such that f("ab", z) = "ba". | instruction | 0 | 74,679 | 18 | 149,358 |
Tags: constructive algorithms, greedy, strings
Correct Solution:
```
s = input()
t = input()
for i in range(len(s)):
if s[i] < t[i]:
print(-1)
exit()
print(t)
``` | output | 1 | 74,679 | 18 | 149,359 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You found a mysterious function f. The function takes two strings s1 and s2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function f is another string of the same length. The i-th character of the output is equal to the minimum of the i-th character of s1 and the i-th character of s2.
For example, f("ab", "ba") = "aa", and f("nzwzl", "zizez") = "niwel".
You found two strings x and y of the same length and consisting of only lowercase English letters. Find any string z such that f(x, z) = y, or print -1 if no such string z exists.
Input
The first line of input contains the string x.
The second line of input contains the string y.
Both x and y consist only of lowercase English letters, x and y have same length and this length is between 1 and 100.
Output
If there is no string z such that f(x, z) = y, print -1.
Otherwise, print a string z such that f(x, z) = y. If there are multiple possible answers, print any of them. The string z should be the same length as x and y and consist only of lowercase English letters.
Examples
Input
ab
aa
Output
ba
Input
nzwzl
niwel
Output
xiyez
Input
ab
ba
Output
-1
Note
The first case is from the statement.
Another solution for the second case is "zizez"
There is no solution for the third case. That is, there is no z such that f("ab", z) = "ba". | instruction | 0 | 74,680 | 18 | 149,360 |
Tags: constructive algorithms, greedy, strings
Correct Solution:
```
x = input()
y = input()
z = ""
n = len(x)
t = True
for i in range(n):
if y[i]>x[i]:
t = False
break
if y[i]<=x[i]:
z += y[i]
if t:
print(z)
else:
print(-1)
``` | output | 1 | 74,680 | 18 | 149,361 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You found a mysterious function f. The function takes two strings s1 and s2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function f is another string of the same length. The i-th character of the output is equal to the minimum of the i-th character of s1 and the i-th character of s2.
For example, f("ab", "ba") = "aa", and f("nzwzl", "zizez") = "niwel".
You found two strings x and y of the same length and consisting of only lowercase English letters. Find any string z such that f(x, z) = y, or print -1 if no such string z exists.
Input
The first line of input contains the string x.
The second line of input contains the string y.
Both x and y consist only of lowercase English letters, x and y have same length and this length is between 1 and 100.
Output
If there is no string z such that f(x, z) = y, print -1.
Otherwise, print a string z such that f(x, z) = y. If there are multiple possible answers, print any of them. The string z should be the same length as x and y and consist only of lowercase English letters.
Examples
Input
ab
aa
Output
ba
Input
nzwzl
niwel
Output
xiyez
Input
ab
ba
Output
-1
Note
The first case is from the statement.
Another solution for the second case is "zizez"
There is no solution for the third case. That is, there is no z such that f("ab", z) = "ba". | instruction | 0 | 74,681 | 18 | 149,362 |
Tags: constructive algorithms, greedy, strings
Correct Solution:
```
import sys
def solve():
x = input()
y = input()
for cx, cy in zip(x, y):
if cx < cy:
print(-1)
return
print(y)
def debug(x, table):
for name, val in table.items():
if x is val:
print('DEBUG:{} -> {}'.format(name, val), file=sys.stderr)
return None
if __name__ == '__main__':
solve()
``` | output | 1 | 74,681 | 18 | 149,363 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You found a mysterious function f. The function takes two strings s1 and s2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function f is another string of the same length. The i-th character of the output is equal to the minimum of the i-th character of s1 and the i-th character of s2.
For example, f("ab", "ba") = "aa", and f("nzwzl", "zizez") = "niwel".
You found two strings x and y of the same length and consisting of only lowercase English letters. Find any string z such that f(x, z) = y, or print -1 if no such string z exists.
Input
The first line of input contains the string x.
The second line of input contains the string y.
Both x and y consist only of lowercase English letters, x and y have same length and this length is between 1 and 100.
Output
If there is no string z such that f(x, z) = y, print -1.
Otherwise, print a string z such that f(x, z) = y. If there are multiple possible answers, print any of them. The string z should be the same length as x and y and consist only of lowercase English letters.
Examples
Input
ab
aa
Output
ba
Input
nzwzl
niwel
Output
xiyez
Input
ab
ba
Output
-1
Note
The first case is from the statement.
Another solution for the second case is "zizez"
There is no solution for the third case. That is, there is no z such that f("ab", z) = "ba".
Submitted Solution:
```
s = input()
t = input()
for i in range(len(s)):
if t[i] > s[i]:
print(-1)
exit()
print(t)
``` | instruction | 0 | 74,682 | 18 | 149,364 |
Yes | output | 1 | 74,682 | 18 | 149,365 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You found a mysterious function f. The function takes two strings s1 and s2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function f is another string of the same length. The i-th character of the output is equal to the minimum of the i-th character of s1 and the i-th character of s2.
For example, f("ab", "ba") = "aa", and f("nzwzl", "zizez") = "niwel".
You found two strings x and y of the same length and consisting of only lowercase English letters. Find any string z such that f(x, z) = y, or print -1 if no such string z exists.
Input
The first line of input contains the string x.
The second line of input contains the string y.
Both x and y consist only of lowercase English letters, x and y have same length and this length is between 1 and 100.
Output
If there is no string z such that f(x, z) = y, print -1.
Otherwise, print a string z such that f(x, z) = y. If there are multiple possible answers, print any of them. The string z should be the same length as x and y and consist only of lowercase English letters.
Examples
Input
ab
aa
Output
ba
Input
nzwzl
niwel
Output
xiyez
Input
ab
ba
Output
-1
Note
The first case is from the statement.
Another solution for the second case is "zizez"
There is no solution for the third case. That is, there is no z such that f("ab", z) = "ba".
Submitted Solution:
```
x = input()
y = input()
l = len(x)
impossible = False
z = [''] * l
for i in range(l):
if y[i] > x[i]:
impossible = True
break
elif y[i] == x[i]:
z[i] = 'z'
else:
z[i] = y[i]
if impossible:
print(-1)
else:
print(''.join(z))
``` | instruction | 0 | 74,683 | 18 | 149,366 |
Yes | output | 1 | 74,683 | 18 | 149,367 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You found a mysterious function f. The function takes two strings s1 and s2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function f is another string of the same length. The i-th character of the output is equal to the minimum of the i-th character of s1 and the i-th character of s2.
For example, f("ab", "ba") = "aa", and f("nzwzl", "zizez") = "niwel".
You found two strings x and y of the same length and consisting of only lowercase English letters. Find any string z such that f(x, z) = y, or print -1 if no such string z exists.
Input
The first line of input contains the string x.
The second line of input contains the string y.
Both x and y consist only of lowercase English letters, x and y have same length and this length is between 1 and 100.
Output
If there is no string z such that f(x, z) = y, print -1.
Otherwise, print a string z such that f(x, z) = y. If there are multiple possible answers, print any of them. The string z should be the same length as x and y and consist only of lowercase English letters.
Examples
Input
ab
aa
Output
ba
Input
nzwzl
niwel
Output
xiyez
Input
ab
ba
Output
-1
Note
The first case is from the statement.
Another solution for the second case is "zizez"
There is no solution for the third case. That is, there is no z such that f("ab", z) = "ba".
Submitted Solution:
```
x=input()
y=input()
for i in range(len(x)):
if ord(y[i])>ord(x[i]):
print(-1)
exit()
print(y)
``` | instruction | 0 | 74,684 | 18 | 149,368 |
Yes | output | 1 | 74,684 | 18 | 149,369 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You found a mysterious function f. The function takes two strings s1 and s2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function f is another string of the same length. The i-th character of the output is equal to the minimum of the i-th character of s1 and the i-th character of s2.
For example, f("ab", "ba") = "aa", and f("nzwzl", "zizez") = "niwel".
You found two strings x and y of the same length and consisting of only lowercase English letters. Find any string z such that f(x, z) = y, or print -1 if no such string z exists.
Input
The first line of input contains the string x.
The second line of input contains the string y.
Both x and y consist only of lowercase English letters, x and y have same length and this length is between 1 and 100.
Output
If there is no string z such that f(x, z) = y, print -1.
Otherwise, print a string z such that f(x, z) = y. If there are multiple possible answers, print any of them. The string z should be the same length as x and y and consist only of lowercase English letters.
Examples
Input
ab
aa
Output
ba
Input
nzwzl
niwel
Output
xiyez
Input
ab
ba
Output
-1
Note
The first case is from the statement.
Another solution for the second case is "zizez"
There is no solution for the third case. That is, there is no z such that f("ab", z) = "ba".
Submitted Solution:
```
x = input()
z = input()
y = ""
r = True
for i in range( len(x) ):
if x[i] == z[i]:
y += "z"
elif x[i] > z[i]:
y += z[i]
else:
r = False
if r:
print(y)
else:
print("-1")
``` | instruction | 0 | 74,685 | 18 | 149,370 |
Yes | output | 1 | 74,685 | 18 | 149,371 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You found a mysterious function f. The function takes two strings s1 and s2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function f is another string of the same length. The i-th character of the output is equal to the minimum of the i-th character of s1 and the i-th character of s2.
For example, f("ab", "ba") = "aa", and f("nzwzl", "zizez") = "niwel".
You found two strings x and y of the same length and consisting of only lowercase English letters. Find any string z such that f(x, z) = y, or print -1 if no such string z exists.
Input
The first line of input contains the string x.
The second line of input contains the string y.
Both x and y consist only of lowercase English letters, x and y have same length and this length is between 1 and 100.
Output
If there is no string z such that f(x, z) = y, print -1.
Otherwise, print a string z such that f(x, z) = y. If there are multiple possible answers, print any of them. The string z should be the same length as x and y and consist only of lowercase English letters.
Examples
Input
ab
aa
Output
ba
Input
nzwzl
niwel
Output
xiyez
Input
ab
ba
Output
-1
Note
The first case is from the statement.
Another solution for the second case is "zizez"
There is no solution for the third case. That is, there is no z such that f("ab", z) = "ba".
Submitted Solution:
```
# -*- coding: utf-8 -*-
"""
Created on Mon Jan 15 14:15:15 2018
@author: Paras Sharma
"""
a=input()
c=[]
b=input()
d=[]
for i in range(len(a)):
c.append(a[i])
d.append(b[i])
for i in range(len(a)):
print(min(a[i],b[i]),end="")
``` | instruction | 0 | 74,686 | 18 | 149,372 |
No | output | 1 | 74,686 | 18 | 149,373 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You found a mysterious function f. The function takes two strings s1 and s2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function f is another string of the same length. The i-th character of the output is equal to the minimum of the i-th character of s1 and the i-th character of s2.
For example, f("ab", "ba") = "aa", and f("nzwzl", "zizez") = "niwel".
You found two strings x and y of the same length and consisting of only lowercase English letters. Find any string z such that f(x, z) = y, or print -1 if no such string z exists.
Input
The first line of input contains the string x.
The second line of input contains the string y.
Both x and y consist only of lowercase English letters, x and y have same length and this length is between 1 and 100.
Output
If there is no string z such that f(x, z) = y, print -1.
Otherwise, print a string z such that f(x, z) = y. If there are multiple possible answers, print any of them. The string z should be the same length as x and y and consist only of lowercase English letters.
Examples
Input
ab
aa
Output
ba
Input
nzwzl
niwel
Output
xiyez
Input
ab
ba
Output
-1
Note
The first case is from the statement.
Another solution for the second case is "zizez"
There is no solution for the third case. That is, there is no z such that f("ab", z) = "ba".
Submitted Solution:
```
def mys(s1, s2):
s3 = ''
for i in range(len(s1)):
if s1[i] == s2[i]:
s3 += s1[i]
elif s1[i] > s2[i]:
s3 += s2[i]
else:
c = ord(s1[i]) + 1
s3 += chr(c)
return s3
x = input()
y = input()
l_x = sorted(list(x))
l_y = sorted(list(y))
if l_x == l_y:
print(-1)
else:
res = mys(x, y)
print(res)
``` | instruction | 0 | 74,687 | 18 | 149,374 |
No | output | 1 | 74,687 | 18 | 149,375 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You found a mysterious function f. The function takes two strings s1 and s2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function f is another string of the same length. The i-th character of the output is equal to the minimum of the i-th character of s1 and the i-th character of s2.
For example, f("ab", "ba") = "aa", and f("nzwzl", "zizez") = "niwel".
You found two strings x and y of the same length and consisting of only lowercase English letters. Find any string z such that f(x, z) = y, or print -1 if no such string z exists.
Input
The first line of input contains the string x.
The second line of input contains the string y.
Both x and y consist only of lowercase English letters, x and y have same length and this length is between 1 and 100.
Output
If there is no string z such that f(x, z) = y, print -1.
Otherwise, print a string z such that f(x, z) = y. If there are multiple possible answers, print any of them. The string z should be the same length as x and y and consist only of lowercase English letters.
Examples
Input
ab
aa
Output
ba
Input
nzwzl
niwel
Output
xiyez
Input
ab
ba
Output
-1
Note
The first case is from the statement.
Another solution for the second case is "zizez"
There is no solution for the third case. That is, there is no z such that f("ab", z) = "ba".
Submitted Solution:
```
arg =input()
res =input()
if arg < res:
print ("-1")
quit()
b =""
for i in range(len(arg)):
if arg[i] == res[i]:b+=str(chr(ord(arg[i])+1))
elif arg[i] > res[i]:b+=str(res[i])
print (b)
``` | instruction | 0 | 74,688 | 18 | 149,376 |
No | output | 1 | 74,688 | 18 | 149,377 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You found a mysterious function f. The function takes two strings s1 and s2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function f is another string of the same length. The i-th character of the output is equal to the minimum of the i-th character of s1 and the i-th character of s2.
For example, f("ab", "ba") = "aa", and f("nzwzl", "zizez") = "niwel".
You found two strings x and y of the same length and consisting of only lowercase English letters. Find any string z such that f(x, z) = y, or print -1 if no such string z exists.
Input
The first line of input contains the string x.
The second line of input contains the string y.
Both x and y consist only of lowercase English letters, x and y have same length and this length is between 1 and 100.
Output
If there is no string z such that f(x, z) = y, print -1.
Otherwise, print a string z such that f(x, z) = y. If there are multiple possible answers, print any of them. The string z should be the same length as x and y and consist only of lowercase English letters.
Examples
Input
ab
aa
Output
ba
Input
nzwzl
niwel
Output
xiyez
Input
ab
ba
Output
-1
Note
The first case is from the statement.
Another solution for the second case is "zizez"
There is no solution for the third case. That is, there is no z such that f("ab", z) = "ba".
Submitted Solution:
```
x=input()
y=input()
z=''
for i in range(len(x)):
if x[i]==y[i]:
if x[i]=='a':
z+='c'
elif x[i]=='b':
z+='m'
elif x[i]=='c':
z+='z'
elif x[i]=='d':
z+='f'
elif x[i]=='e':
z+='k'
elif x[i]=='f':
z+='r'
elif x[i]=='g':
z+='s'
elif x[i]=='h':
z+='t'
elif x[i]=='i':
z+='u'
elif x[i]=='j':
z+='v'
elif x[i]=='k':
z+='w'
elif x[i]=='l':
z+='x'
elif x[i]=='m':
z+='y'
elif x[i]=='n':
z+='z'
elif x[i]=='o':
z+='c'
elif x[i]=='p':
z+='v'
elif x[i]=='q':
z+='g'
elif x[i]=='r':
z+='r'
elif x[i]=='s':
z+='l'
elif x[i]=='t':
z+='h'
elif x[i]=='u':
z+='t'
elif x[i]=='v':
z+='r'
elif x[i]=='w':
z+='q'
elif x[i]=='x':
z+='j'
elif x[i]=='y':
z+='g'
elif x[i]=='z':
z+='a'
else:
z+=y[i]
f=0
for i in range(len(z)):
if (x[i]<y[i] and x[i]!=z[i]) or (x[i]>y[i] and y[i]!=z[i]):
print(-1)
f=1
break
if f==0:
print(z)
``` | instruction | 0 | 74,689 | 18 | 149,378 |
No | output | 1 | 74,689 | 18 | 149,379 |
Provide a correct Python 3 solution for this coding contest problem.
One of the simple ciphers is the affine cipher. First, replace the letters a to z with the numbers a = 0, b = 1, c = 2, ..., x = 23, y = 24, z = 25 and 0 to 25. Then replace the original alphabet with the following formula.
$ F (\ gamma) = (\ alpha \ cdot \ gamma + \ beta) $ mod $ 26 $
However, mod 26 represents the remainder after dividing by 26. For example, when $ \ alpha = 3, \ beta = 2 $, the alphabet'a'(= 0) is $ F (0) = (3 \ cdot 0 + 2) $ mod $ 26 = 2 $ and'c In', the alphabet'n'(= 13) is replaced with'p' at $ F (13) = (3 \ cdot 13 + 2) $ mod $ 26 = 15 $. At this time, it is assumed that $ \ alpha $ and $ \ beta $ are carefully selected so that $ F (\ gamma) $ is always associated with $ \ gamma $ on a one-to-one basis ($ \ alpha). As long as $ and 26 are relatively prime). $ F ('a') = 7, F ('n') = 7 $, as in $ \ alpha = 4, \ beta = 7 $, and'a'and'n' are the same'h' It will not be replaced by. Also, non-alphabetic characters are not replaced.
Create a program that outputs the encrypted character string decrypted into the original text. In the original text, as a keyword
that
this
It is assumed that one of the above is always included.
Input
Given multiple datasets. The first line gives the number of datasets $ n $ ($ n \ leq 30 $). It is followed by $ n $ rows of data. Each dataset is given an encrypted sentence of up to 256 characters consisting of lowercase letters and blanks on one line.
Output
For each dataset, output the decrypted original text on one line.
Example
Input
1
y eazqyp pnop pngtg ye obmpngt xmybp mr lygw
Output
i submit that there is another point of view | instruction | 0 | 74,861 | 18 | 149,722 |
"Correct Solution:
```
for _ in range(int(input())):
s=input()
for i in range(1,27,2):
for j in range(27):
a=[]
for k in range(len(s)):
if s[k].islower():a+=chr(((ord(s[k])-97)*i+j)%26+97)
else:a+=s[k]
a=''.join(a)
if 'this' in a or 'that' in a:print(a);break
``` | output | 1 | 74,861 | 18 | 149,723 |
Provide a correct Python 3 solution for this coding contest problem.
One of the simple ciphers is the affine cipher. First, replace the letters a to z with the numbers a = 0, b = 1, c = 2, ..., x = 23, y = 24, z = 25 and 0 to 25. Then replace the original alphabet with the following formula.
$ F (\ gamma) = (\ alpha \ cdot \ gamma + \ beta) $ mod $ 26 $
However, mod 26 represents the remainder after dividing by 26. For example, when $ \ alpha = 3, \ beta = 2 $, the alphabet'a'(= 0) is $ F (0) = (3 \ cdot 0 + 2) $ mod $ 26 = 2 $ and'c In', the alphabet'n'(= 13) is replaced with'p' at $ F (13) = (3 \ cdot 13 + 2) $ mod $ 26 = 15 $. At this time, it is assumed that $ \ alpha $ and $ \ beta $ are carefully selected so that $ F (\ gamma) $ is always associated with $ \ gamma $ on a one-to-one basis ($ \ alpha). As long as $ and 26 are relatively prime). $ F ('a') = 7, F ('n') = 7 $, as in $ \ alpha = 4, \ beta = 7 $, and'a'and'n' are the same'h' It will not be replaced by. Also, non-alphabetic characters are not replaced.
Create a program that outputs the encrypted character string decrypted into the original text. In the original text, as a keyword
that
this
It is assumed that one of the above is always included.
Input
Given multiple datasets. The first line gives the number of datasets $ n $ ($ n \ leq 30 $). It is followed by $ n $ rows of data. Each dataset is given an encrypted sentence of up to 256 characters consisting of lowercase letters and blanks on one line.
Output
For each dataset, output the decrypted original text on one line.
Example
Input
1
y eazqyp pnop pngtg ye obmpngt xmybp mr lygw
Output
i submit that there is another point of view | instruction | 0 | 74,862 | 18 | 149,724 |
"Correct Solution:
```
z='abcdefghijklmnopqrstuvwxyz'
e=lambda x,i,j:z[(z.index(x)*i+j)%26]
def f():
for i in(1,3,5,7,9,11,15,17,19,21,23,25):
for j in range(26):
if''.join(e(c,i,j)for c in'that')in s or''.join(e(c,i,j)for c in'this')in s:return(i,j)
def g(x,y,s=0,t=1):
q,r=x//y,x%y
return g(y,r,t,s-q*t) if r else t
for _ in[0]*int(input()):
s=input()
a,b=f()
h=g(26,a)
print(''.join(z[h*(z.index(c)-b)%26]if c in z else c for c in s))
``` | output | 1 | 74,862 | 18 | 149,725 |
Provide a correct Python 3 solution for this coding contest problem.
One of the simple ciphers is the affine cipher. First, replace the letters a to z with the numbers a = 0, b = 1, c = 2, ..., x = 23, y = 24, z = 25 and 0 to 25. Then replace the original alphabet with the following formula.
$ F (\ gamma) = (\ alpha \ cdot \ gamma + \ beta) $ mod $ 26 $
However, mod 26 represents the remainder after dividing by 26. For example, when $ \ alpha = 3, \ beta = 2 $, the alphabet'a'(= 0) is $ F (0) = (3 \ cdot 0 + 2) $ mod $ 26 = 2 $ and'c In', the alphabet'n'(= 13) is replaced with'p' at $ F (13) = (3 \ cdot 13 + 2) $ mod $ 26 = 15 $. At this time, it is assumed that $ \ alpha $ and $ \ beta $ are carefully selected so that $ F (\ gamma) $ is always associated with $ \ gamma $ on a one-to-one basis ($ \ alpha). As long as $ and 26 are relatively prime). $ F ('a') = 7, F ('n') = 7 $, as in $ \ alpha = 4, \ beta = 7 $, and'a'and'n' are the same'h' It will not be replaced by. Also, non-alphabetic characters are not replaced.
Create a program that outputs the encrypted character string decrypted into the original text. In the original text, as a keyword
that
this
It is assumed that one of the above is always included.
Input
Given multiple datasets. The first line gives the number of datasets $ n $ ($ n \ leq 30 $). It is followed by $ n $ rows of data. Each dataset is given an encrypted sentence of up to 256 characters consisting of lowercase letters and blanks on one line.
Output
For each dataset, output the decrypted original text on one line.
Example
Input
1
y eazqyp pnop pngtg ye obmpngt xmybp mr lygw
Output
i submit that there is another point of view | instruction | 0 | 74,863 | 18 | 149,726 |
"Correct Solution:
```
z='abcdefghijklmnopqrstuvwxyz'
for _ in[0]*int(input()):
e=input()
for i in range(1,26,2):
for j in range(26):
a=''
for c in e:
a+=z[(z.index(c)*i+j)%26]if c in z else c
if'that'in a or'this'in a:print(a);break
``` | output | 1 | 74,863 | 18 | 149,727 |
Provide a correct Python 3 solution for this coding contest problem.
One of the simple ciphers is the affine cipher. First, replace the letters a to z with the numbers a = 0, b = 1, c = 2, ..., x = 23, y = 24, z = 25 and 0 to 25. Then replace the original alphabet with the following formula.
$ F (\ gamma) = (\ alpha \ cdot \ gamma + \ beta) $ mod $ 26 $
However, mod 26 represents the remainder after dividing by 26. For example, when $ \ alpha = 3, \ beta = 2 $, the alphabet'a'(= 0) is $ F (0) = (3 \ cdot 0 + 2) $ mod $ 26 = 2 $ and'c In', the alphabet'n'(= 13) is replaced with'p' at $ F (13) = (3 \ cdot 13 + 2) $ mod $ 26 = 15 $. At this time, it is assumed that $ \ alpha $ and $ \ beta $ are carefully selected so that $ F (\ gamma) $ is always associated with $ \ gamma $ on a one-to-one basis ($ \ alpha). As long as $ and 26 are relatively prime). $ F ('a') = 7, F ('n') = 7 $, as in $ \ alpha = 4, \ beta = 7 $, and'a'and'n' are the same'h' It will not be replaced by. Also, non-alphabetic characters are not replaced.
Create a program that outputs the encrypted character string decrypted into the original text. In the original text, as a keyword
that
this
It is assumed that one of the above is always included.
Input
Given multiple datasets. The first line gives the number of datasets $ n $ ($ n \ leq 30 $). It is followed by $ n $ rows of data. Each dataset is given an encrypted sentence of up to 256 characters consisting of lowercase letters and blanks on one line.
Output
For each dataset, output the decrypted original text on one line.
Example
Input
1
y eazqyp pnop pngtg ye obmpngt xmybp mr lygw
Output
i submit that there is another point of view | instruction | 0 | 74,864 | 18 | 149,728 |
"Correct Solution:
```
base = ord("a")
alst = [i for i in range(1, 26, 2) if i % 13]
def restore(s):
for a in alst:
for b in range(26):
new = "".join([chr((a * (ord(x) - base) + b) % 26 + base) if x != " " else " " for x in s])
if "that" in new or "this" in new:
return new
n = int(input())
for _ in range(n):
print(restore(input()))
``` | output | 1 | 74,864 | 18 | 149,729 |
Provide a correct Python 3 solution for this coding contest problem.
One of the simple ciphers is the affine cipher. First, replace the letters a to z with the numbers a = 0, b = 1, c = 2, ..., x = 23, y = 24, z = 25 and 0 to 25. Then replace the original alphabet with the following formula.
$ F (\ gamma) = (\ alpha \ cdot \ gamma + \ beta) $ mod $ 26 $
However, mod 26 represents the remainder after dividing by 26. For example, when $ \ alpha = 3, \ beta = 2 $, the alphabet'a'(= 0) is $ F (0) = (3 \ cdot 0 + 2) $ mod $ 26 = 2 $ and'c In', the alphabet'n'(= 13) is replaced with'p' at $ F (13) = (3 \ cdot 13 + 2) $ mod $ 26 = 15 $. At this time, it is assumed that $ \ alpha $ and $ \ beta $ are carefully selected so that $ F (\ gamma) $ is always associated with $ \ gamma $ on a one-to-one basis ($ \ alpha). As long as $ and 26 are relatively prime). $ F ('a') = 7, F ('n') = 7 $, as in $ \ alpha = 4, \ beta = 7 $, and'a'and'n' are the same'h' It will not be replaced by. Also, non-alphabetic characters are not replaced.
Create a program that outputs the encrypted character string decrypted into the original text. In the original text, as a keyword
that
this
It is assumed that one of the above is always included.
Input
Given multiple datasets. The first line gives the number of datasets $ n $ ($ n \ leq 30 $). It is followed by $ n $ rows of data. Each dataset is given an encrypted sentence of up to 256 characters consisting of lowercase letters and blanks on one line.
Output
For each dataset, output the decrypted original text on one line.
Example
Input
1
y eazqyp pnop pngtg ye obmpngt xmybp mr lygw
Output
i submit that there is another point of view | instruction | 0 | 74,865 | 18 | 149,730 |
"Correct Solution:
```
def F(alpha, beta, c):
gamma = ord(c) - ord("a")
return chr((alpha*gamma + beta) % 26 + ord("a"))
alphalist = [1,3,5,7,9,11,15,17,19,21,23,25]
N = int(input())
for lines in range(N):
S = input()
words = S.split()
keyA = -1
keyB = -1
for i in range(len(words)):
if len(words[i]) == 4:
w = words[i]
for k in range(len(alphalist)):
for l in range(26):
alpha = alphalist[k]
beta = l
if F(alpha,beta,w[0]) == "t" and F(alpha,beta,w[1]) == "h":
if F(alpha,beta,w[2]) == "a" and F(alpha,beta,w[3]) == "t":
keyA = alpha
keyB = beta
elif F(alpha,beta,w[2]) == "i" and F(alpha,beta,w[3]) == "s":
keyA = alpha
keyB = beta
if keyA > 0:
break
if keyB > 0:
break
if keyA > 0:
break
for i in range(len(S)):
if S[i] == " ":
print(" ", end="")
else:
print(F(keyA,keyB,S[i]), end="")
print("")
``` | output | 1 | 74,865 | 18 | 149,731 |
Provide a correct Python 3 solution for this coding contest problem.
One of the simple ciphers is the affine cipher. First, replace the letters a to z with the numbers a = 0, b = 1, c = 2, ..., x = 23, y = 24, z = 25 and 0 to 25. Then replace the original alphabet with the following formula.
$ F (\ gamma) = (\ alpha \ cdot \ gamma + \ beta) $ mod $ 26 $
However, mod 26 represents the remainder after dividing by 26. For example, when $ \ alpha = 3, \ beta = 2 $, the alphabet'a'(= 0) is $ F (0) = (3 \ cdot 0 + 2) $ mod $ 26 = 2 $ and'c In', the alphabet'n'(= 13) is replaced with'p' at $ F (13) = (3 \ cdot 13 + 2) $ mod $ 26 = 15 $. At this time, it is assumed that $ \ alpha $ and $ \ beta $ are carefully selected so that $ F (\ gamma) $ is always associated with $ \ gamma $ on a one-to-one basis ($ \ alpha). As long as $ and 26 are relatively prime). $ F ('a') = 7, F ('n') = 7 $, as in $ \ alpha = 4, \ beta = 7 $, and'a'and'n' are the same'h' It will not be replaced by. Also, non-alphabetic characters are not replaced.
Create a program that outputs the encrypted character string decrypted into the original text. In the original text, as a keyword
that
this
It is assumed that one of the above is always included.
Input
Given multiple datasets. The first line gives the number of datasets $ n $ ($ n \ leq 30 $). It is followed by $ n $ rows of data. Each dataset is given an encrypted sentence of up to 256 characters consisting of lowercase letters and blanks on one line.
Output
For each dataset, output the decrypted original text on one line.
Example
Input
1
y eazqyp pnop pngtg ye obmpngt xmybp mr lygw
Output
i submit that there is another point of view | instruction | 0 | 74,866 | 18 | 149,732 |
"Correct Solution:
```
def affine(word, alpha, beta):
word = list(word)
for i in range(len(word)):
ascii = ((ord(word[i]) - ord('a')) * alpha + beta) % 26;
word[i] = chr(ascii + ord('a'));
return ''.join(word)
alphas = [1, 3, 5, 7, 9, 11, 15, 17, 19, 21, 23, 25]
for x in range(int(input())):
words = input().split(' ')
for alpha in range(26):
for beta in range(26):
string = list(map(lambda x: affine(x, alpha, beta), words))
if 'that' in string or 'this' in string:
print(*string)
break
else:
continue
break
``` | output | 1 | 74,866 | 18 | 149,733 |
Provide a correct Python 3 solution for this coding contest problem.
One of the simple ciphers is the affine cipher. First, replace the letters a to z with the numbers a = 0, b = 1, c = 2, ..., x = 23, y = 24, z = 25 and 0 to 25. Then replace the original alphabet with the following formula.
$ F (\ gamma) = (\ alpha \ cdot \ gamma + \ beta) $ mod $ 26 $
However, mod 26 represents the remainder after dividing by 26. For example, when $ \ alpha = 3, \ beta = 2 $, the alphabet'a'(= 0) is $ F (0) = (3 \ cdot 0 + 2) $ mod $ 26 = 2 $ and'c In', the alphabet'n'(= 13) is replaced with'p' at $ F (13) = (3 \ cdot 13 + 2) $ mod $ 26 = 15 $. At this time, it is assumed that $ \ alpha $ and $ \ beta $ are carefully selected so that $ F (\ gamma) $ is always associated with $ \ gamma $ on a one-to-one basis ($ \ alpha). As long as $ and 26 are relatively prime). $ F ('a') = 7, F ('n') = 7 $, as in $ \ alpha = 4, \ beta = 7 $, and'a'and'n' are the same'h' It will not be replaced by. Also, non-alphabetic characters are not replaced.
Create a program that outputs the encrypted character string decrypted into the original text. In the original text, as a keyword
that
this
It is assumed that one of the above is always included.
Input
Given multiple datasets. The first line gives the number of datasets $ n $ ($ n \ leq 30 $). It is followed by $ n $ rows of data. Each dataset is given an encrypted sentence of up to 256 characters consisting of lowercase letters and blanks on one line.
Output
For each dataset, output the decrypted original text on one line.
Example
Input
1
y eazqyp pnop pngtg ye obmpngt xmybp mr lygw
Output
i submit that there is another point of view | instruction | 0 | 74,867 | 18 | 149,734 |
"Correct Solution:
```
z='abcdefghijklmnopqrstuvwxyz'
def f(x):
for i in range(1,26,2):
for j in range(26):
a=''.join(z[(z.index(c)*i+j)%26]if c in z else c for c in x)
if'that'in a or'this'in a:return a
for _ in[0]*int(input()):print(f(input()))
``` | output | 1 | 74,867 | 18 | 149,735 |
Provide a correct Python 3 solution for this coding contest problem.
One of the simple ciphers is the affine cipher. First, replace the letters a to z with the numbers a = 0, b = 1, c = 2, ..., x = 23, y = 24, z = 25 and 0 to 25. Then replace the original alphabet with the following formula.
$ F (\ gamma) = (\ alpha \ cdot \ gamma + \ beta) $ mod $ 26 $
However, mod 26 represents the remainder after dividing by 26. For example, when $ \ alpha = 3, \ beta = 2 $, the alphabet'a'(= 0) is $ F (0) = (3 \ cdot 0 + 2) $ mod $ 26 = 2 $ and'c In', the alphabet'n'(= 13) is replaced with'p' at $ F (13) = (3 \ cdot 13 + 2) $ mod $ 26 = 15 $. At this time, it is assumed that $ \ alpha $ and $ \ beta $ are carefully selected so that $ F (\ gamma) $ is always associated with $ \ gamma $ on a one-to-one basis ($ \ alpha). As long as $ and 26 are relatively prime). $ F ('a') = 7, F ('n') = 7 $, as in $ \ alpha = 4, \ beta = 7 $, and'a'and'n' are the same'h' It will not be replaced by. Also, non-alphabetic characters are not replaced.
Create a program that outputs the encrypted character string decrypted into the original text. In the original text, as a keyword
that
this
It is assumed that one of the above is always included.
Input
Given multiple datasets. The first line gives the number of datasets $ n $ ($ n \ leq 30 $). It is followed by $ n $ rows of data. Each dataset is given an encrypted sentence of up to 256 characters consisting of lowercase letters and blanks on one line.
Output
For each dataset, output the decrypted original text on one line.
Example
Input
1
y eazqyp pnop pngtg ye obmpngt xmybp mr lygw
Output
i submit that there is another point of view | instruction | 0 | 74,868 | 18 | 149,736 |
"Correct Solution:
```
z='abcdefghijklmnopqrstuvwxyz'
e=lambda x,i,j:z[(z.index(x)*i+j)%26]
def f():
for i in range(1,26,2):
for j in range(26):
if''.join(e(c,i,j)for c in'that')in s or''.join(e(c,i,j)for c in'this')in s:return(i,j)
for _ in[0]*int(input()):
s=input()
k=f()
a=''.join(e(c,*k)for c in z)
t=str.maketrans(a,z)
print(s.translate(t))
``` | output | 1 | 74,868 | 18 | 149,737 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One of the simple ciphers is the affine cipher. First, replace the letters a to z with the numbers a = 0, b = 1, c = 2, ..., x = 23, y = 24, z = 25 and 0 to 25. Then replace the original alphabet with the following formula.
$ F (\ gamma) = (\ alpha \ cdot \ gamma + \ beta) $ mod $ 26 $
However, mod 26 represents the remainder after dividing by 26. For example, when $ \ alpha = 3, \ beta = 2 $, the alphabet'a'(= 0) is $ F (0) = (3 \ cdot 0 + 2) $ mod $ 26 = 2 $ and'c In', the alphabet'n'(= 13) is replaced with'p' at $ F (13) = (3 \ cdot 13 + 2) $ mod $ 26 = 15 $. At this time, it is assumed that $ \ alpha $ and $ \ beta $ are carefully selected so that $ F (\ gamma) $ is always associated with $ \ gamma $ on a one-to-one basis ($ \ alpha). As long as $ and 26 are relatively prime). $ F ('a') = 7, F ('n') = 7 $, as in $ \ alpha = 4, \ beta = 7 $, and'a'and'n' are the same'h' It will not be replaced by. Also, non-alphabetic characters are not replaced.
Create a program that outputs the encrypted character string decrypted into the original text. In the original text, as a keyword
that
this
It is assumed that one of the above is always included.
Input
Given multiple datasets. The first line gives the number of datasets $ n $ ($ n \ leq 30 $). It is followed by $ n $ rows of data. Each dataset is given an encrypted sentence of up to 256 characters consisting of lowercase letters and blanks on one line.
Output
For each dataset, output the decrypted original text on one line.
Example
Input
1
y eazqyp pnop pngtg ye obmpngt xmybp mr lygw
Output
i submit that there is another point of view
Submitted Solution:
```
from itertools import product
n = int(input())
for _ in range(n):
s = input()
for alpha,beta in product([1,3,5,7,9,11,15,17,19,21,23,25],range(26)):
g = "".join(chr((alpha*(ord(e)-ord("a"))+beta)%26+ord("a")) if not e == " " else " " for e in s)
if "that" in g or "this" in g: print(g); break
``` | instruction | 0 | 74,869 | 18 | 149,738 |
Yes | output | 1 | 74,869 | 18 | 149,739 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One of the simple ciphers is the affine cipher. First, replace the letters a to z with the numbers a = 0, b = 1, c = 2, ..., x = 23, y = 24, z = 25 and 0 to 25. Then replace the original alphabet with the following formula.
$ F (\ gamma) = (\ alpha \ cdot \ gamma + \ beta) $ mod $ 26 $
However, mod 26 represents the remainder after dividing by 26. For example, when $ \ alpha = 3, \ beta = 2 $, the alphabet'a'(= 0) is $ F (0) = (3 \ cdot 0 + 2) $ mod $ 26 = 2 $ and'c In', the alphabet'n'(= 13) is replaced with'p' at $ F (13) = (3 \ cdot 13 + 2) $ mod $ 26 = 15 $. At this time, it is assumed that $ \ alpha $ and $ \ beta $ are carefully selected so that $ F (\ gamma) $ is always associated with $ \ gamma $ on a one-to-one basis ($ \ alpha). As long as $ and 26 are relatively prime). $ F ('a') = 7, F ('n') = 7 $, as in $ \ alpha = 4, \ beta = 7 $, and'a'and'n' are the same'h' It will not be replaced by. Also, non-alphabetic characters are not replaced.
Create a program that outputs the encrypted character string decrypted into the original text. In the original text, as a keyword
that
this
It is assumed that one of the above is always included.
Input
Given multiple datasets. The first line gives the number of datasets $ n $ ($ n \ leq 30 $). It is followed by $ n $ rows of data. Each dataset is given an encrypted sentence of up to 256 characters consisting of lowercase letters and blanks on one line.
Output
For each dataset, output the decrypted original text on one line.
Example
Input
1
y eazqyp pnop pngtg ye obmpngt xmybp mr lygw
Output
i submit that there is another point of view
Submitted Solution:
```
for _ in[0]*int(input()):
e=input()
for i in range(26):
for j in range(26):
a=''.join([c,chr(((ord(c)-97)*i+j)%26+97)][c.islower()]for c in e)
if'that'in a or'this'in a:print(a);break
``` | instruction | 0 | 74,870 | 18 | 149,740 |
Yes | output | 1 | 74,870 | 18 | 149,741 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One of the simple ciphers is the affine cipher. First, replace the letters a to z with the numbers a = 0, b = 1, c = 2, ..., x = 23, y = 24, z = 25 and 0 to 25. Then replace the original alphabet with the following formula.
$ F (\ gamma) = (\ alpha \ cdot \ gamma + \ beta) $ mod $ 26 $
However, mod 26 represents the remainder after dividing by 26. For example, when $ \ alpha = 3, \ beta = 2 $, the alphabet'a'(= 0) is $ F (0) = (3 \ cdot 0 + 2) $ mod $ 26 = 2 $ and'c In', the alphabet'n'(= 13) is replaced with'p' at $ F (13) = (3 \ cdot 13 + 2) $ mod $ 26 = 15 $. At this time, it is assumed that $ \ alpha $ and $ \ beta $ are carefully selected so that $ F (\ gamma) $ is always associated with $ \ gamma $ on a one-to-one basis ($ \ alpha). As long as $ and 26 are relatively prime). $ F ('a') = 7, F ('n') = 7 $, as in $ \ alpha = 4, \ beta = 7 $, and'a'and'n' are the same'h' It will not be replaced by. Also, non-alphabetic characters are not replaced.
Create a program that outputs the encrypted character string decrypted into the original text. In the original text, as a keyword
that
this
It is assumed that one of the above is always included.
Input
Given multiple datasets. The first line gives the number of datasets $ n $ ($ n \ leq 30 $). It is followed by $ n $ rows of data. Each dataset is given an encrypted sentence of up to 256 characters consisting of lowercase letters and blanks on one line.
Output
For each dataset, output the decrypted original text on one line.
Example
Input
1
y eazqyp pnop pngtg ye obmpngt xmybp mr lygw
Output
i submit that there is another point of view
Submitted Solution:
```
E = 10**-10
def decy(a):
return [ord(i)-97 for i in a]
def encr(a):
return "".join([chr(i+97) for i in a])
def deaffin(j,a,b):
cont_ = 1
for i in range(100):
if cont_ == 0:
break
elif ((j-b+26*i)/a)//1 == (j-b+26*i)/a:
cont_ = 0
return int((j-b+26*i)/a)%26
n = int(input())
for _ in range(n):
sen = input()
words = sen.split()
wordsl = [len(i) for i in words]
wordsn = [decy(i) for i in words]
fourn = []
for i in range(len(wordsl)):
if wordsl[i] == 4:
fourn.append(wordsn[i])
a_ = 0
b_ = 0
cont = 1
for a in [1,3,5,7,9,11,15,17,19,21,23,25]:
if cont != 0:
for b in range(26):
if cont != 0:
for i in fourn:
deco = [chr(deaffin(j,a,b)+97) for j in i]
if deco == ["t","h","i","s"] or deco == ["t","h","a","t"]:
a_ = a
b_ = b
cont = 0
break
dec_wordsn = [[deaffin(j,a_,b_) for j in i] for i in wordsn]
dec_words = [encr(i) for i in dec_wordsn]
print(" ".join(dec_words))
``` | instruction | 0 | 74,871 | 18 | 149,742 |
Yes | output | 1 | 74,871 | 18 | 149,743 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One of the simple ciphers is the affine cipher. First, replace the letters a to z with the numbers a = 0, b = 1, c = 2, ..., x = 23, y = 24, z = 25 and 0 to 25. Then replace the original alphabet with the following formula.
$ F (\ gamma) = (\ alpha \ cdot \ gamma + \ beta) $ mod $ 26 $
However, mod 26 represents the remainder after dividing by 26. For example, when $ \ alpha = 3, \ beta = 2 $, the alphabet'a'(= 0) is $ F (0) = (3 \ cdot 0 + 2) $ mod $ 26 = 2 $ and'c In', the alphabet'n'(= 13) is replaced with'p' at $ F (13) = (3 \ cdot 13 + 2) $ mod $ 26 = 15 $. At this time, it is assumed that $ \ alpha $ and $ \ beta $ are carefully selected so that $ F (\ gamma) $ is always associated with $ \ gamma $ on a one-to-one basis ($ \ alpha). As long as $ and 26 are relatively prime). $ F ('a') = 7, F ('n') = 7 $, as in $ \ alpha = 4, \ beta = 7 $, and'a'and'n' are the same'h' It will not be replaced by. Also, non-alphabetic characters are not replaced.
Create a program that outputs the encrypted character string decrypted into the original text. In the original text, as a keyword
that
this
It is assumed that one of the above is always included.
Input
Given multiple datasets. The first line gives the number of datasets $ n $ ($ n \ leq 30 $). It is followed by $ n $ rows of data. Each dataset is given an encrypted sentence of up to 256 characters consisting of lowercase letters and blanks on one line.
Output
For each dataset, output the decrypted original text on one line.
Example
Input
1
y eazqyp pnop pngtg ye obmpngt xmybp mr lygw
Output
i submit that there is another point of view
Submitted Solution:
```
m = [chr(ord('a')+i) for i in range(26)]
t = {}
for i in range(26):
t[m[i]] = i
def affine(s):
for a in range(26):
for b in range(26):
text = ''.join([m[a * (t[x] - b + 26) % 26]
if x != ' ' else ' ' for x in s])
if 'that' in text or 'this' in text:
return text
n = int(input())
for i in range(n):
print(affine(input()))
``` | instruction | 0 | 74,872 | 18 | 149,744 |
Yes | output | 1 | 74,872 | 18 | 149,745 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One of the simple ciphers is the affine cipher. First, replace the letters a to z with the numbers a = 0, b = 1, c = 2, ..., x = 23, y = 24, z = 25 and 0 to 25. Then replace the original alphabet with the following formula.
$ F (\ gamma) = (\ alpha \ cdot \ gamma + \ beta) $ mod $ 26 $
However, mod 26 represents the remainder after dividing by 26. For example, when $ \ alpha = 3, \ beta = 2 $, the alphabet'a'(= 0) is $ F (0) = (3 \ cdot 0 + 2) $ mod $ 26 = 2 $ and'c In', the alphabet'n'(= 13) is replaced with'p' at $ F (13) = (3 \ cdot 13 + 2) $ mod $ 26 = 15 $. At this time, it is assumed that $ \ alpha $ and $ \ beta $ are carefully selected so that $ F (\ gamma) $ is always associated with $ \ gamma $ on a one-to-one basis ($ \ alpha). As long as $ and 26 are relatively prime). $ F ('a') = 7, F ('n') = 7 $, as in $ \ alpha = 4, \ beta = 7 $, and'a'and'n' are the same'h' It will not be replaced by. Also, non-alphabetic characters are not replaced.
Create a program that outputs the encrypted character string decrypted into the original text. In the original text, as a keyword
that
this
It is assumed that one of the above is always included.
Input
Given multiple datasets. The first line gives the number of datasets $ n $ ($ n \ leq 30 $). It is followed by $ n $ rows of data. Each dataset is given an encrypted sentence of up to 256 characters consisting of lowercase letters and blanks on one line.
Output
For each dataset, output the decrypted original text on one line.
Example
Input
1
y eazqyp pnop pngtg ye obmpngt xmybp mr lygw
Output
i submit that there is another point of view
Submitted Solution:
```
string = 'abcdefghijklmnopqrstuvwxyz'
table = []
for i in string:
table.append(i)
def encode(string,a,b):
data = list(string)
s = []
flag = 0
for c in data:
try:
i = table.index(c)
tmp = (a*i+b)%26
s[-1:] += table[tmp]
except:
s.append(' ')
s = ''.join(s)
return s
n = int(input())
for i in range(n):
code = str(input())
for a in range(1,26):
for b in range(1,26):
s = encode(code,a,b)
if 'that' in s:
print(s)
elif 'this' in s:
print(s)
``` | instruction | 0 | 74,873 | 18 | 149,746 |
No | output | 1 | 74,873 | 18 | 149,747 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One of the simple ciphers is the affine cipher. First, replace the letters a to z with the numbers a = 0, b = 1, c = 2, ..., x = 23, y = 24, z = 25 and 0 to 25. Then replace the original alphabet with the following formula.
$ F (\ gamma) = (\ alpha \ cdot \ gamma + \ beta) $ mod $ 26 $
However, mod 26 represents the remainder after dividing by 26. For example, when $ \ alpha = 3, \ beta = 2 $, the alphabet'a'(= 0) is $ F (0) = (3 \ cdot 0 + 2) $ mod $ 26 = 2 $ and'c In', the alphabet'n'(= 13) is replaced with'p' at $ F (13) = (3 \ cdot 13 + 2) $ mod $ 26 = 15 $. At this time, it is assumed that $ \ alpha $ and $ \ beta $ are carefully selected so that $ F (\ gamma) $ is always associated with $ \ gamma $ on a one-to-one basis ($ \ alpha). As long as $ and 26 are relatively prime). $ F ('a') = 7, F ('n') = 7 $, as in $ \ alpha = 4, \ beta = 7 $, and'a'and'n' are the same'h' It will not be replaced by. Also, non-alphabetic characters are not replaced.
Create a program that outputs the encrypted character string decrypted into the original text. In the original text, as a keyword
that
this
It is assumed that one of the above is always included.
Input
Given multiple datasets. The first line gives the number of datasets $ n $ ($ n \ leq 30 $). It is followed by $ n $ rows of data. Each dataset is given an encrypted sentence of up to 256 characters consisting of lowercase letters and blanks on one line.
Output
For each dataset, output the decrypted original text on one line.
Example
Input
1
y eazqyp pnop pngtg ye obmpngt xmybp mr lygw
Output
i submit that there is another point of view
Submitted Solution:
```
string = 'abcdefghijklmnopqrstuvwxyz'
table = []
for i in string:
table.append(i)
def encode(string,a,b):
data = list(string)
s = []
flag = 0
for c in data:
try:
i = table.index(c)
tmp = (a*i+b)%26
s[-1:] += table[tmp]
except:
s.append(' ')
s = ''.join(s)
return s
n = int(input())
for i in range(n):
code = str(input())
for a in range(1,26):
for b in range(1,26):
s = encode(code,a,b)
if 'that' in s or 'this' in s:
print(s)
``` | instruction | 0 | 74,874 | 18 | 149,748 |
No | output | 1 | 74,874 | 18 | 149,749 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One of the simple ciphers is the affine cipher. First, replace the letters a to z with the numbers a = 0, b = 1, c = 2, ..., x = 23, y = 24, z = 25 and 0 to 25. Then replace the original alphabet with the following formula.
$ F (\ gamma) = (\ alpha \ cdot \ gamma + \ beta) $ mod $ 26 $
However, mod 26 represents the remainder after dividing by 26. For example, when $ \ alpha = 3, \ beta = 2 $, the alphabet'a'(= 0) is $ F (0) = (3 \ cdot 0 + 2) $ mod $ 26 = 2 $ and'c In', the alphabet'n'(= 13) is replaced with'p' at $ F (13) = (3 \ cdot 13 + 2) $ mod $ 26 = 15 $. At this time, it is assumed that $ \ alpha $ and $ \ beta $ are carefully selected so that $ F (\ gamma) $ is always associated with $ \ gamma $ on a one-to-one basis ($ \ alpha). As long as $ and 26 are relatively prime). $ F ('a') = 7, F ('n') = 7 $, as in $ \ alpha = 4, \ beta = 7 $, and'a'and'n' are the same'h' It will not be replaced by. Also, non-alphabetic characters are not replaced.
Create a program that outputs the encrypted character string decrypted into the original text. In the original text, as a keyword
that
this
It is assumed that one of the above is always included.
Input
Given multiple datasets. The first line gives the number of datasets $ n $ ($ n \ leq 30 $). It is followed by $ n $ rows of data. Each dataset is given an encrypted sentence of up to 256 characters consisting of lowercase letters and blanks on one line.
Output
For each dataset, output the decrypted original text on one line.
Example
Input
1
y eazqyp pnop pngtg ye obmpngt xmybp mr lygw
Output
i submit that there is another point of view
Submitted Solution:
```
def affine(word, alpha, beta):
word = list(word)
for i in range(len(word)):
word[i] = albs[(albs.index(word[i]) * alpha + beta) % 26]
return ''.join(word)
albs = 'abcdefghijklmnopqrstuvwxyz'
alphas = [1, 3, 5, 7, 9, 11, 15, 17, 19, 21, 23, 25]
betas = list(range(26))
for _ in range(int(input())):
words = input().split(' ')
for alpha in alphas:
for beta in betas:
words = list(map(lambda x: affine(x, alpha, beta), words))
if 'that' in words or 'this' in words:
print(*words)
break
else:
continue
break
``` | instruction | 0 | 74,875 | 18 | 149,750 |
No | output | 1 | 74,875 | 18 | 149,751 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One of the simple ciphers is the affine cipher. First, replace the letters a to z with the numbers a = 0, b = 1, c = 2, ..., x = 23, y = 24, z = 25 and 0 to 25. Then replace the original alphabet with the following formula.
$ F (\ gamma) = (\ alpha \ cdot \ gamma + \ beta) $ mod $ 26 $
However, mod 26 represents the remainder after dividing by 26. For example, when $ \ alpha = 3, \ beta = 2 $, the alphabet'a'(= 0) is $ F (0) = (3 \ cdot 0 + 2) $ mod $ 26 = 2 $ and'c In', the alphabet'n'(= 13) is replaced with'p' at $ F (13) = (3 \ cdot 13 + 2) $ mod $ 26 = 15 $. At this time, it is assumed that $ \ alpha $ and $ \ beta $ are carefully selected so that $ F (\ gamma) $ is always associated with $ \ gamma $ on a one-to-one basis ($ \ alpha). As long as $ and 26 are relatively prime). $ F ('a') = 7, F ('n') = 7 $, as in $ \ alpha = 4, \ beta = 7 $, and'a'and'n' are the same'h' It will not be replaced by. Also, non-alphabetic characters are not replaced.
Create a program that outputs the encrypted character string decrypted into the original text. In the original text, as a keyword
that
this
It is assumed that one of the above is always included.
Input
Given multiple datasets. The first line gives the number of datasets $ n $ ($ n \ leq 30 $). It is followed by $ n $ rows of data. Each dataset is given an encrypted sentence of up to 256 characters consisting of lowercase letters and blanks on one line.
Output
For each dataset, output the decrypted original text on one line.
Example
Input
1
y eazqyp pnop pngtg ye obmpngt xmybp mr lygw
Output
i submit that there is another point of view
Submitted Solution:
```
# Edit : 2014/11/16
# Lang : Python3
# Time : 00. s
# judge: not Accepted
# File: pc0021.py
from itertools import product
if __name__ == "__main__":
mycode0 = "abcdefghijklmnopqrstuvwxyz"
mycode1 = {
"a": 0,
"b": 1,
"c": 2,
"d": 3,
"e": 4,
"f": 5,
"g": 6,
"h": 7,
"i": 8,
"j": 9,
"k": 10,
"l": 11,
"m": 12,
"n": 13,
"o": 14,
"p": 15,
"q": 16,
"r": 17,
"s": 18,
"t": 19,
"u": 20,
"v": 21,
"w": 22,
"x": 23,
"y": 24,
"z": 25,
}
nset = int(input())
for i in range(0, nset):
inl = input()
for a, b in product(range(1, 26, 2), range(1, 26)):
outl = ""
if a == 13:
continue
# print(a, b)
for i in range(0, len(inl)):
if inl[i] == " ":
# print(" ")
outl += " "
else:
# print(inl[i], mycode1[inl[i]], mycode0[mycode1[inl[i]]])
decode = (a * mycode1[inl[i]] + b) % 26
#print(mycode0[decode])
#outl[i] = mycode0[decode]
outl += mycode0[decode]
if "this" in outl or "that" in outl:
print(outl)
continue
#
``` | instruction | 0 | 74,876 | 18 | 149,752 |
No | output | 1 | 74,876 | 18 | 149,753 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Many modern text editors automatically check the spelling of the user's text. Some editors even suggest how to correct typos.
In this problem your task to implement a small functionality to correct two types of typos in a word. We will assume that three identical letters together is a typo (for example, word "helllo" contains a typo). Besides, a couple of identical letters immediately followed by another couple of identical letters is a typo too (for example, words "helloo" and "wwaatt" contain typos).
Write a code that deletes the minimum number of letters from a word, correcting described typos in the word. You are allowed to delete letters from both ends and from the middle of the word.
Input
The single line of the input contains word s, its length is from 1 to 200000 characters. The given word s consists of lowercase English letters.
Output
Print such word t that it doesn't contain any typos described in the problem statement and is obtained from s by deleting the least number of letters.
If there are multiple solutions, print any of them.
Examples
Input
helloo
Output
hello
Input
woooooow
Output
woow
Note
The second valid answer to the test from the statement is "heloo".
Submitted Solution:
```
import sys
from functools import lru_cache, cmp_to_key
from heapq import merge, heapify, heappop, heappush
# from math import *
from collections import defaultdict as dd, deque, Counter as C
from itertools import combinations as comb, permutations as perm
from bisect import bisect_left as bl, bisect_right as br, bisect
from time import perf_counter
from fractions import Fraction
import copy
import time
# import numpy as np
starttime = time.time()
# import numpy as np
mod = int(pow(10, 9) + 7)
mod2 = 998244353
def data(): return sys.stdin.readline().strip()
def out(*var, end="\n"): sys.stdout.write(' '.join(map(str, var))+end)
def L(): return list(sp())
def sl(): return list(ssp())
def sp(): return map(int, data().split())
def ssp(): return map(str, data().split())
def l1d(n, val=0): return [val for i in range(n)]
def l2d(n, m, val=0): return [l1d(n, val) for j in range(m)]
try:
# sys.setrecursionlimit(int(pow(10,6)))
sys.stdin = open("input.txt", "r")
# sys.stdout = open("../output.txt", "w")
except:
pass
s=input()
x=[]
i=0
while(i<len(s)):
k=0
while(i+k<len(s) and s[i]==s[i+k]):
k+=1
x.append(s[i:i+k])
i+=k
count=0
for i in range(len(x)):
if len(x[i])>2:
count+=(len(x[i])-2)
x[i]=x[i][:2]
if i-1>=0 and len(x[i-1])==2 and len(x[i])==2:
count+=1
x[i]=x[i][:1]
print("".join(x))
endtime = time.time()
# print(f"Runtime of the program is {endtime - starttime}")
``` | instruction | 0 | 75,377 | 18 | 150,754 |
Yes | output | 1 | 75,377 | 18 | 150,755 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Many modern text editors automatically check the spelling of the user's text. Some editors even suggest how to correct typos.
In this problem your task to implement a small functionality to correct two types of typos in a word. We will assume that three identical letters together is a typo (for example, word "helllo" contains a typo). Besides, a couple of identical letters immediately followed by another couple of identical letters is a typo too (for example, words "helloo" and "wwaatt" contain typos).
Write a code that deletes the minimum number of letters from a word, correcting described typos in the word. You are allowed to delete letters from both ends and from the middle of the word.
Input
The single line of the input contains word s, its length is from 1 to 200000 characters. The given word s consists of lowercase English letters.
Output
Print such word t that it doesn't contain any typos described in the problem statement and is obtained from s by deleting the least number of letters.
If there are multiple solutions, print any of them.
Examples
Input
helloo
Output
hello
Input
woooooow
Output
woow
Note
The second valid answer to the test from the statement is "heloo".
Submitted Solution:
```
'''input
helloo
'''
# I am Mr.Inconsistent
from sys import stdin
import math
def remove_three(string):
mystack = ['-1']
freq = 0
for i in range(len(string)):
if mystack[-1] == string[i]:
freq += 1
if freq == 3:
freq -= 1
continue
else:
mystack.append(string[i])
else:
mystack.append(string[i])
freq = 1
return mystack[1:]
def remove_two(string):
mystack = [-1]
index = []
freq = 0
for i in range(len(string)):
if mystack[-1] == string[i]:
freq += 1
if freq == 2:
index.append(i)
else:
freq = 1
mystack.append(string[i])
remove = []
if len(index) > 0:
last = index[0]
for i in range(1, len(index)):
if index[i] - last == 2:
remove.append(index[i])
else:
last = index[i]
remove.append(float('inf'))
mystack = []
j = 0
for i in range(len(string)):
if i == remove[j]:
j += 1
continue
else:
mystack.append(string[i])
return mystack
# main starts
string = list(stdin.readline().strip())
string = remove_three(string)
string = remove_two(string)
print(''.join(string))
``` | instruction | 0 | 75,378 | 18 | 150,756 |
Yes | output | 1 | 75,378 | 18 | 150,757 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Many modern text editors automatically check the spelling of the user's text. Some editors even suggest how to correct typos.
In this problem your task to implement a small functionality to correct two types of typos in a word. We will assume that three identical letters together is a typo (for example, word "helllo" contains a typo). Besides, a couple of identical letters immediately followed by another couple of identical letters is a typo too (for example, words "helloo" and "wwaatt" contain typos).
Write a code that deletes the minimum number of letters from a word, correcting described typos in the word. You are allowed to delete letters from both ends and from the middle of the word.
Input
The single line of the input contains word s, its length is from 1 to 200000 characters. The given word s consists of lowercase English letters.
Output
Print such word t that it doesn't contain any typos described in the problem statement and is obtained from s by deleting the least number of letters.
If there are multiple solutions, print any of them.
Examples
Input
helloo
Output
hello
Input
woooooow
Output
woow
Note
The second valid answer to the test from the statement is "heloo".
Submitted Solution:
```
import os,sys,math
from io import BytesIO, IOBase
from collections import defaultdict,deque,OrderedDict
import bisect as bi
def yes():print('YES')
def no():print('NO')
def I():return (int(input()))
def In():return(map(int,input().split()))
def ln():return list(map(int,input().split()))
def Sn():return input().strip()
BUFSIZE = 8192
#complete the main function with number of test cases to complete greater than x
def find_gt(a, x):
i = bi.bisect_left(a, x)
if i != len(a):
return i
else:
return len(a)
def solve():
s=Sn()
n=len(s)
an,frq=[],[]
last,cnt=s[0],1
for x in s[1:]:
if x!=last:
an.append(last)
frq.append(min(cnt,2))
last=x
cnt=1
else:
cnt+=1
an.append(last)
frq.append(min(2,cnt))
for i in range(len(frq)-1):
if frq[i]==2 and frq[i+1]==2:
frq[i+1]=1
for i in range(len(an)):
for j in range(frq[i]):
print(an[i],end='')
pass
def main():
T=1
for i in range(T):
solve()
M = 998244353
P = 1000000007
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
# endregion
if __name__ == "__main__":
main()
``` | instruction | 0 | 75,379 | 18 | 150,758 |
Yes | output | 1 | 75,379 | 18 | 150,759 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Many modern text editors automatically check the spelling of the user's text. Some editors even suggest how to correct typos.
In this problem your task to implement a small functionality to correct two types of typos in a word. We will assume that three identical letters together is a typo (for example, word "helllo" contains a typo). Besides, a couple of identical letters immediately followed by another couple of identical letters is a typo too (for example, words "helloo" and "wwaatt" contain typos).
Write a code that deletes the minimum number of letters from a word, correcting described typos in the word. You are allowed to delete letters from both ends and from the middle of the word.
Input
The single line of the input contains word s, its length is from 1 to 200000 characters. The given word s consists of lowercase English letters.
Output
Print such word t that it doesn't contain any typos described in the problem statement and is obtained from s by deleting the least number of letters.
If there are multiple solutions, print any of them.
Examples
Input
helloo
Output
hello
Input
woooooow
Output
woow
Note
The second valid answer to the test from the statement is "heloo".
Submitted Solution:
```
def STR(): return list(input())
def INT(): return int(input())
def MAP(): return map(int, input().split())
def MAP2():return map(float,input().split())
def LIST(): return list(map(int, input().split()))
def STRING(): return input()
import string
import sys
from heapq import heappop , heappush, heapify
from bisect import *
from collections import deque , Counter , defaultdict
from math import *
from itertools import permutations , accumulate
dx = [-1 , 1 , 0 , 0 ]
dy = [0 , 0 , 1 , - 1]
# for tt in range(INT()):
s=STRING()
s=list(s)
a=[1]*len(s)
x=s[0]
for i in range(1,len(a)):
if s[i]==s[i-1]:
a[i]=a[i-1]+1
if a[i]>2:
continue
else:
x+=s[i]
s=list(x)
a=[1]*len(s)
x=s[0]
last=1
c=1
for i in range(1,len(a)):
if x[-1]!=s[i]:
x+=s[i]
c+=1
if c>=2:
last=1
elif x[-1]==s[i] and last<2:
x+=s[i]
last=2
c=0
elif x[-1]==s[i] and last>=2:
continue
print(x)
``` | instruction | 0 | 75,380 | 18 | 150,760 |
Yes | output | 1 | 75,380 | 18 | 150,761 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Many modern text editors automatically check the spelling of the user's text. Some editors even suggest how to correct typos.
In this problem your task to implement a small functionality to correct two types of typos in a word. We will assume that three identical letters together is a typo (for example, word "helllo" contains a typo). Besides, a couple of identical letters immediately followed by another couple of identical letters is a typo too (for example, words "helloo" and "wwaatt" contain typos).
Write a code that deletes the minimum number of letters from a word, correcting described typos in the word. You are allowed to delete letters from both ends and from the middle of the word.
Input
The single line of the input contains word s, its length is from 1 to 200000 characters. The given word s consists of lowercase English letters.
Output
Print such word t that it doesn't contain any typos described in the problem statement and is obtained from s by deleting the least number of letters.
If there are multiple solutions, print any of them.
Examples
Input
helloo
Output
hello
Input
woooooow
Output
woow
Note
The second valid answer to the test from the statement is "heloo".
Submitted Solution:
```
import sys
import functools
sys.setrecursionlimit(100000)
s = sys.stdin.readline().strip()
s_ = s[0]
d = {}
c_conti = 1
last = s[0]
for i in s[1:]:
if last==i:
c_conti+=1
else:
c_conti = 1
last = i
if c_conti<3:
s_+=i
s=''
i = 0
l = len(s_)
ind_m = -1
while i<=l-4:
if s_[i]==s_[i+1] and s_[i+2]==s_[i+3]:
s+=s_[i]+s_[i+1]+s_[i+3]
ind_m = i+3
i+=4
else:
s+=s_[i]
i+=1
s+=s_[ind_m+1:]
# k = list(s_)
# for i in range(0,len(s_)):
# try :
# d[i]
# except KeyError:
# s+=s_[i]
if len(s)>=4 and s[-1]==s[-2] and s[-3]==s[-4]:
print(s[:-1])
else:
print(s)
``` | instruction | 0 | 75,381 | 18 | 150,762 |
No | output | 1 | 75,381 | 18 | 150,763 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Many modern text editors automatically check the spelling of the user's text. Some editors even suggest how to correct typos.
In this problem your task to implement a small functionality to correct two types of typos in a word. We will assume that three identical letters together is a typo (for example, word "helllo" contains a typo). Besides, a couple of identical letters immediately followed by another couple of identical letters is a typo too (for example, words "helloo" and "wwaatt" contain typos).
Write a code that deletes the minimum number of letters from a word, correcting described typos in the word. You are allowed to delete letters from both ends and from the middle of the word.
Input
The single line of the input contains word s, its length is from 1 to 200000 characters. The given word s consists of lowercase English letters.
Output
Print such word t that it doesn't contain any typos described in the problem statement and is obtained from s by deleting the least number of letters.
If there are multiple solutions, print any of them.
Examples
Input
helloo
Output
hello
Input
woooooow
Output
woow
Note
The second valid answer to the test from the statement is "heloo".
Submitted Solution:
```
from sys import stdin as sin
def aint():return int(sin.readline())
def amap():return map(int,sin.readline().split())
def alist():return list(map(int,sin.readline().split()))
def astr():return str(sin.readline().split())
from collections import defaultdict as dd
s = input()
n=len(s)
if n==1:
print(s)
else:
ans=s[0]+s[1]
f=False
if s[0]==s[1]:
f=True
for i in range(2,n):
if s[i]==s[i-1] and s[i]==s[i-2]:
pass
elif s[i]==s[i-1]:
if f:
f=False
pass
else:
f=True
ans+=s[i]
else:
ans+=s[i]
f=False
print(ans)
``` | instruction | 0 | 75,382 | 18 | 150,764 |
No | output | 1 | 75,382 | 18 | 150,765 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Many modern text editors automatically check the spelling of the user's text. Some editors even suggest how to correct typos.
In this problem your task to implement a small functionality to correct two types of typos in a word. We will assume that three identical letters together is a typo (for example, word "helllo" contains a typo). Besides, a couple of identical letters immediately followed by another couple of identical letters is a typo too (for example, words "helloo" and "wwaatt" contain typos).
Write a code that deletes the minimum number of letters from a word, correcting described typos in the word. You are allowed to delete letters from both ends and from the middle of the word.
Input
The single line of the input contains word s, its length is from 1 to 200000 characters. The given word s consists of lowercase English letters.
Output
Print such word t that it doesn't contain any typos described in the problem statement and is obtained from s by deleting the least number of letters.
If there are multiple solutions, print any of them.
Examples
Input
helloo
Output
hello
Input
woooooow
Output
woow
Note
The second valid answer to the test from the statement is "heloo".
Submitted Solution:
```
def fixing(s):
i, n = 2, len(s)
mark = False
while i < n:
if mark:
while i<n and s[i] == s[i-1]:
del s[i]
n -= 1
mark = False
else:
while i<n and s[i] == s[i-1] and s[i] == s[i-2]:
del s[i]
n -= 1
mark = True
i += 1
return str(s)
def main():
s = list(input())
print(fixing(s))
if __name__ == '__main__':
main()
``` | instruction | 0 | 75,383 | 18 | 150,766 |
No | output | 1 | 75,383 | 18 | 150,767 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Many modern text editors automatically check the spelling of the user's text. Some editors even suggest how to correct typos.
In this problem your task to implement a small functionality to correct two types of typos in a word. We will assume that three identical letters together is a typo (for example, word "helllo" contains a typo). Besides, a couple of identical letters immediately followed by another couple of identical letters is a typo too (for example, words "helloo" and "wwaatt" contain typos).
Write a code that deletes the minimum number of letters from a word, correcting described typos in the word. You are allowed to delete letters from both ends and from the middle of the word.
Input
The single line of the input contains word s, its length is from 1 to 200000 characters. The given word s consists of lowercase English letters.
Output
Print such word t that it doesn't contain any typos described in the problem statement and is obtained from s by deleting the least number of letters.
If there are multiple solutions, print any of them.
Examples
Input
helloo
Output
hello
Input
woooooow
Output
woow
Note
The second valid answer to the test from the statement is "heloo".
Submitted Solution:
```
s = list(input())
if len(set(s))==1:
print(s[0]*min(len(s),2))
exit()
n = len(s)
lis=[]
c=1
for i in range(1,n):
if s[i]==s[i-1]:
c+=1
else:
lis.append([s[i-1],c])
c=1
lis.append([s[-1],c])
#print(lis,'lis')
a = len(lis)
ans=''
ans+=min(lis[0][1],2)*lis[0][0] + min(lis[1][1],2)*lis[1][0]
if len(ans)==4:
ans=ans[:3]
lis[1][0]=1
else:
lis[1][1]=2
for i in range(2,len(lis)):
# print(lis[i],lis[i-1])
if lis[i][1]>1:
if lis[i-1][1]==2:
ans+=lis[i][0]
lis[i][1]=1
else:
ans+=min(lis[i][1],2)*lis[i][0]
lis[i][1]=min(lis[i][1],2)
else:
if lis[i-1][1]==2:
ans+=lis[i][0]
lis[i][0]=1
else:
ans+=min(lis[i][1],2)*lis[i][0]
lis[i][1]=min(lis[i][1],2)
print(ans)
``` | instruction | 0 | 75,384 | 18 | 150,768 |
No | output | 1 | 75,384 | 18 | 150,769 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Smith wakes up at the side of a dirty, disused bathroom, his ankle chained to pipes. Next to him is tape-player with a hand-written message "Play Me". He finds a tape in his own back pocket. After putting the tape in the tape-player, he sees a key hanging from a ceiling, chained to some kind of a machine, which is connected to the terminal next to him. After pressing a Play button a rough voice starts playing from the tape:
"Listen up Smith. As you can see, you are in pretty tough situation and in order to escape, you have to solve a puzzle.
You are given N strings which represent words. Each word is of the maximum length L and consists of characters 'a'-'e'. You are also given M strings which represent patterns. Pattern is a string of length ≤ L and consists of characters 'a'-'e' as well as the maximum 3 characters '?'. Character '?' is an unknown character, meaning it can be equal to any character 'a'-'e', or even an empty character. For each pattern find the number of words that matches with the given pattern. After solving it and typing the result in the terminal, the key will drop from the ceiling and you may escape. Let the game begin."
Help Smith escape.
Input
The first line of input contains two integers N and M (1 ≤ N ≤ 100 000, 1 ≤ M ≤ 5000), representing the number of words and patterns respectively.
The next N lines represent each word, and after those N lines, following M lines represent each pattern. Each word and each pattern has a maximum length L (1 ≤ L ≤ 50). Each pattern has no more that three characters '?'. All other characters in words and patters are lowercase English letters from 'a' to 'e'.
Output
Output contains M lines and each line consists of one integer, representing the number of words that match the corresponding pattern.
Example
Input
3 1
abc
aec
ac
a?c
Output
3
Note
If we switch '?' with 'b', 'e' and with empty character, we get 'abc', 'aec' and 'ac' respectively.
Submitted Solution:
```
n, m=map(int, input().split())
M=dict()
for i in range(n):
s=input()
if s not in M:
M[s]=1
t=['', 'a', 'b', 'c', 'd', 'e']
for i in range(m):
s=input()
ans=0
if '?' in s:
for p in t:
ans+=M.get(s.replace('?', p), 0)
else:
ans=M.get(s, 0)
print(ans)
``` | instruction | 0 | 75,559 | 18 | 151,118 |
No | output | 1 | 75,559 | 18 | 151,119 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Smith wakes up at the side of a dirty, disused bathroom, his ankle chained to pipes. Next to him is tape-player with a hand-written message "Play Me". He finds a tape in his own back pocket. After putting the tape in the tape-player, he sees a key hanging from a ceiling, chained to some kind of a machine, which is connected to the terminal next to him. After pressing a Play button a rough voice starts playing from the tape:
"Listen up Smith. As you can see, you are in pretty tough situation and in order to escape, you have to solve a puzzle.
You are given N strings which represent words. Each word is of the maximum length L and consists of characters 'a'-'e'. You are also given M strings which represent patterns. Pattern is a string of length ≤ L and consists of characters 'a'-'e' as well as the maximum 3 characters '?'. Character '?' is an unknown character, meaning it can be equal to any character 'a'-'e', or even an empty character. For each pattern find the number of words that matches with the given pattern. After solving it and typing the result in the terminal, the key will drop from the ceiling and you may escape. Let the game begin."
Help Smith escape.
Input
The first line of input contains two integers N and M (1 ≤ N ≤ 100 000, 1 ≤ M ≤ 5000), representing the number of words and patterns respectively.
The next N lines represent each word, and after those N lines, following M lines represent each pattern. Each word and each pattern has a maximum length L (1 ≤ L ≤ 50). Each pattern has no more that three characters '?'. All other characters in words and patters are lowercase English letters from 'a' to 'e'.
Output
Output contains M lines and each line consists of one integer, representing the number of words that match the corresponding pattern.
Example
Input
3 1
abc
aec
ac
a?c
Output
3
Note
If we switch '?' with 'b', 'e' and with empty character, we get 'abc', 'aec' and 'ac' respectively.
Submitted Solution:
```
import re
n,m=map(int,input().split())
a=[]
for i in range(n):
s=input()
a+=[s]
for j in range(m):
s=list(input())
for i in range(len(s)):
if s[i]=='?':s[i]='.?'
s=''.join(s)
p=re.compile(s)
ans=0
for i in a:
if(p.match(i)):ans+=1;print(i,s)
print(ans)
``` | instruction | 0 | 75,560 | 18 | 151,120 |
No | output | 1 | 75,560 | 18 | 151,121 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Smith wakes up at the side of a dirty, disused bathroom, his ankle chained to pipes. Next to him is tape-player with a hand-written message "Play Me". He finds a tape in his own back pocket. After putting the tape in the tape-player, he sees a key hanging from a ceiling, chained to some kind of a machine, which is connected to the terminal next to him. After pressing a Play button a rough voice starts playing from the tape:
"Listen up Smith. As you can see, you are in pretty tough situation and in order to escape, you have to solve a puzzle.
You are given N strings which represent words. Each word is of the maximum length L and consists of characters 'a'-'e'. You are also given M strings which represent patterns. Pattern is a string of length ≤ L and consists of characters 'a'-'e' as well as the maximum 3 characters '?'. Character '?' is an unknown character, meaning it can be equal to any character 'a'-'e', or even an empty character. For each pattern find the number of words that matches with the given pattern. After solving it and typing the result in the terminal, the key will drop from the ceiling and you may escape. Let the game begin."
Help Smith escape.
Input
The first line of input contains two integers N and M (1 ≤ N ≤ 100 000, 1 ≤ M ≤ 5000), representing the number of words and patterns respectively.
The next N lines represent each word, and after those N lines, following M lines represent each pattern. Each word and each pattern has a maximum length L (1 ≤ L ≤ 50). Each pattern has no more that three characters '?'. All other characters in words and patters are lowercase English letters from 'a' to 'e'.
Output
Output contains M lines and each line consists of one integer, representing the number of words that match the corresponding pattern.
Example
Input
3 1
abc
aec
ac
a?c
Output
3
Note
If we switch '?' with 'b', 'e' and with empty character, we get 'abc', 'aec' and 'ac' respectively.
Submitted Solution:
```
import re
n,m=map(int,input().split())
a=[]
for i in range(n):
s=input()
a+=[s]
s=list(input())
for i in range(len(s)):
if s[i]=='?':s[i]='.?'
s=''.join(s)
p=re.compile(s)
ans=0
for i in a:
if(p.match(i)):ans+=1
print(ans)
``` | instruction | 0 | 75,561 | 18 | 151,122 |
No | output | 1 | 75,561 | 18 | 151,123 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Smith wakes up at the side of a dirty, disused bathroom, his ankle chained to pipes. Next to him is tape-player with a hand-written message "Play Me". He finds a tape in his own back pocket. After putting the tape in the tape-player, he sees a key hanging from a ceiling, chained to some kind of a machine, which is connected to the terminal next to him. After pressing a Play button a rough voice starts playing from the tape:
"Listen up Smith. As you can see, you are in pretty tough situation and in order to escape, you have to solve a puzzle.
You are given N strings which represent words. Each word is of the maximum length L and consists of characters 'a'-'e'. You are also given M strings which represent patterns. Pattern is a string of length ≤ L and consists of characters 'a'-'e' as well as the maximum 3 characters '?'. Character '?' is an unknown character, meaning it can be equal to any character 'a'-'e', or even an empty character. For each pattern find the number of words that matches with the given pattern. After solving it and typing the result in the terminal, the key will drop from the ceiling and you may escape. Let the game begin."
Help Smith escape.
Input
The first line of input contains two integers N and M (1 ≤ N ≤ 100 000, 1 ≤ M ≤ 5000), representing the number of words and patterns respectively.
The next N lines represent each word, and after those N lines, following M lines represent each pattern. Each word and each pattern has a maximum length L (1 ≤ L ≤ 50). Each pattern has no more that three characters '?'. All other characters in words and patters are lowercase English letters from 'a' to 'e'.
Output
Output contains M lines and each line consists of one integer, representing the number of words that match the corresponding pattern.
Example
Input
3 1
abc
aec
ac
a?c
Output
3
Note
If we switch '?' with 'b', 'e' and with empty character, we get 'abc', 'aec' and 'ac' respectively.
Submitted Solution:
```
import sys
from itertools import product
r=sys.stdin.readline
N,M=map(int,r().split())
words=[]
class Node(object):
def __init__(self, key, data=None):
self.key=key
self.data=data
self.children={}
class Trie:
def __init__(self):
self.head=Node(None)
def insert(self,string):
cur_node=self.head
for ch in string:
if ch not in cur_node.children:
cur_node.children[ch]=Node(ch)
cur_node=cur_node.children[ch]
cur_node.data=string
def search(self, string):
cur_node=self.head
for ch in string:
if ch in cur_node.children:
cur_node=cur_node.children[ch]
else:
return False
if cur_node.data:
return True
else:
return False
trie=Trie()
def replaceStrPos(string,pos,ch):
if ch==" ":
return string[:pos]+string[pos+1:]
return string[:pos]+ch+string[pos+1:]
for _ in range(N):
word=r().strip()
words.append(word)
trie.insert(word)
for _ in range(M):
cnt=0
pattern=r().strip()
tmpPattern=pattern[:]
tb=dict()
lst=[]
idx=-1
while tmpPattern.find('?',idx+1)!=-1:
idx=tmpPattern.find('?',idx+1)
lst.append(idx)
ck=set()
for res in product(" abced",repeat=len(lst)):
patternLst=list(pattern)
for a,b in zip(lst,res):
if b==" ":
b=""
patternLst[a]=b
cur=''.join(patternLst)
if cur in ck:
continue
if trie.search(cur):
cnt+=1
ck.add(cur)
continue
print(cnt)
``` | instruction | 0 | 75,562 | 18 | 151,124 |
No | output | 1 | 75,562 | 18 | 151,125 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Input
The input consists of a single string of uppercase letters A-Z. The length of the string is between 1 and 10 characters, inclusive.
Output
Output "YES" or "NO".
Examples
Input
GENIUS
Output
YES
Input
DOCTOR
Output
NO
Input
IRENE
Output
YES
Input
MARY
Output
NO
Input
SMARTPHONE
Output
NO
Input
REVOLVER
Output
YES
Input
HOLMES
Output
NO
Input
WATSON
Output
YES | instruction | 0 | 76,007 | 18 | 152,014 |
Tags: *special, brute force, dp, strings
Correct Solution:
```
l=set(["H","HE","LI","BE","B","C","N","O","F","NE","NA","MG","AL","SI","P","S","CL","AR","K","CA","SC","TI","V","CR","MN","FE","CO","NI","CU","ZN","GA","GE","AS","SE","BR","KR","RB","SR","Y","ZR","NB","MO","TC","RU","RH","PD","AG","CD","IN","SN","SB","TE","I","XE","CS","BA","LA","CE","PR","ND","PM","SM","EU","GD","TB","DY","HO","ER","TM","YB","LU","HF","TA","W","RE","OS","IR","PT","AU","HG","TL","PB","BI","PO","AT","RN","FR","RA","AC","TH","PA","U","NP","PU","AM","CM","BK","CF","ES","FM","MD","NO","LR","RF","DB","SG","BH","HS","MT","DS","RG","CN","NH","FL","MC","LV","TS","OG"])
def dfs(s):
res=True
if len(s)==0:
return True
elif len(s)==1:
return s[:1] in l
else:
return (dfs(s[1:]) if s[:1] in l else False) or (dfs(s[2:]) if s[:2] in l else False)
print('YES' if dfs(input()) else 'NO')
``` | output | 1 | 76,007 | 18 | 152,015 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Input
The input consists of a single string of uppercase letters A-Z. The length of the string is between 1 and 10 characters, inclusive.
Output
Output "YES" or "NO".
Examples
Input
GENIUS
Output
YES
Input
DOCTOR
Output
NO
Input
IRENE
Output
YES
Input
MARY
Output
NO
Input
SMARTPHONE
Output
NO
Input
REVOLVER
Output
YES
Input
HOLMES
Output
NO
Input
WATSON
Output
YES | instruction | 0 | 76,010 | 18 | 152,020 |
Tags: *special, brute force, dp, strings
Correct Solution:
```
S=input()
X=[ord(s)-65 for s in S]
for i in range(2,len(X)):
if (X[i-1]+X[i-2])%26==X[i]:
True
else:
print("NO")
exit()
print("YES")
``` | output | 1 | 76,010 | 18 | 152,021 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Input
The input consists of a single string of uppercase letters A-Z. The length of the string is between 1 and 10 characters, inclusive.
Output
Output "YES" or "NO".
Examples
Input
GENIUS
Output
YES
Input
DOCTOR
Output
NO
Input
IRENE
Output
YES
Input
MARY
Output
NO
Input
SMARTPHONE
Output
NO
Input
REVOLVER
Output
YES
Input
HOLMES
Output
NO
Input
WATSON
Output
YES | instruction | 0 | 76,011 | 18 | 152,022 |
Tags: *special, brute force, dp, strings
Correct Solution:
```
n=input()
if(len(n)<=2):
print("YES")
else:
a=ord(n[0])-ord('A')
b=ord(n[1])-ord('A')
# print(ord(a)+ord(b)-2*ord('A'))
for i in range(2,len(n)):
m=(a+b)%26
j=n[i]
k=ord(j)-ord('A')
if m!=k:
# print(m,k)
print("NO")
break
else:
a=b
b=m
else:
print("YES")
``` | output | 1 | 76,011 | 18 | 152,023 |
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