message stringlengths 2 11.9k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 137 108k | cluster float64 18 18 | __index_level_0__ int64 274 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One day Alex was creating a contest about his friends, but accidentally deleted it. Fortunately, all the problems were saved, but now he needs to find them among other problems.
But there are too many problems, to do it manually. Alex asks you to write a program, which will determine if a problem is from this contest by its name.
It is known, that problem is from this contest if and only if its name contains one of Alex's friends' name exactly once. His friends' names are "Danil", "Olya", "Slava", "Ann" and "Nikita".
Names are case sensitive.
Input
The only line contains string from lowercase and uppercase letters and "_" symbols of length, not more than 100 — the name of the problem.
Output
Print "YES", if problem is from this contest, and "NO" otherwise.
Examples
Input
Alex_and_broken_contest
Output
NO
Input
NikitaAndString
Output
YES
Input
Danil_and_Olya
Output
NO
Submitted Solution:
```
s = input()
a = ['Danil', 'Olya', 'Slava', 'Ann', 'Nikita']
an = 0
for i in range(len(a)):
if a[i] in s:
an += 1
if an == 0:
print('YES')
else:
print('NO')
``` | instruction | 0 | 90,640 | 18 | 181,280 |
No | output | 1 | 90,640 | 18 | 181,281 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One day Alex was creating a contest about his friends, but accidentally deleted it. Fortunately, all the problems were saved, but now he needs to find them among other problems.
But there are too many problems, to do it manually. Alex asks you to write a program, which will determine if a problem is from this contest by its name.
It is known, that problem is from this contest if and only if its name contains one of Alex's friends' name exactly once. His friends' names are "Danil", "Olya", "Slava", "Ann" and "Nikita".
Names are case sensitive.
Input
The only line contains string from lowercase and uppercase letters and "_" symbols of length, not more than 100 — the name of the problem.
Output
Print "YES", if problem is from this contest, and "NO" otherwise.
Examples
Input
Alex_and_broken_contest
Output
NO
Input
NikitaAndString
Output
YES
Input
Danil_and_Olya
Output
NO
Submitted Solution:
```
import sys
def input(): return sys.stdin.readline().strip()
def iinput(): return int(input())
def minput(): return map(int, input().split())
def listinput(): return list(map(int, input().split()))
s=input()
if s.count("Danil")+s.count("Olya")+s.count("Slava")+s.count("Ann")+s.count("Nikita"):
print("YES")
else:
print("NO")
``` | instruction | 0 | 90,641 | 18 | 181,282 |
No | output | 1 | 90,641 | 18 | 181,283 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya is an active Internet user. One day he came across an Internet resource he liked, so he wrote its address in the notebook. We know that the address of the written resource has format:
<protocol>://<domain>.ru[/<context>]
where:
* <protocol> can equal either "http" (without the quotes) or "ftp" (without the quotes),
* <domain> is a non-empty string, consisting of lowercase English letters,
* the /<context> part may not be present. If it is present, then <context> is a non-empty string, consisting of lowercase English letters.
If string <context> isn't present in the address, then the additional character "/" isn't written. Thus, the address has either two characters "/" (the ones that go before the domain), or three (an extra one in front of the context).
When the boy came home, he found out that the address he wrote in his notebook had no punctuation marks. Vasya must have been in a lot of hurry and didn't write characters ":", "/", ".".
Help Vasya to restore the possible address of the recorded Internet resource.
Input
The first line contains a non-empty string that Vasya wrote out in his notebook. This line consists of lowercase English letters only.
It is guaranteed that the given string contains at most 50 letters. It is guaranteed that the given string can be obtained from some correct Internet resource address, described above.
Output
Print a single line — the address of the Internet resource that Vasya liked. If there are several addresses that meet the problem limitations, you are allowed to print any of them.
Examples
Input
httpsunrux
Output
http://sun.ru/x
Input
ftphttprururu
Output
ftp://http.ru/ruru
Note
In the second sample there are two more possible answers: "ftp://httpruru.ru" and "ftp://httpru.ru/ru".
Submitted Solution:
```
s = input()
if s.startswith("http"):
s = s.replace("http", "http://", 1)
else:
s = s.replace("ftp", "ftp://", 1)
ind = s.index("ru")
if s[ind:] == "ru":
s = s.replace("ru", ".ru")
else:
if "//ru" not in s:
s = s.replace("ru", ".ru/", 1)
else:
s = s.replace("//ru", "~~", 1)
s = s.replace("ru", ".ru/", 1)
s = s.replace("~~", "//ru", 1)
print(s)
``` | instruction | 0 | 91,226 | 18 | 182,452 |
Yes | output | 1 | 91,226 | 18 | 182,453 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya is an active Internet user. One day he came across an Internet resource he liked, so he wrote its address in the notebook. We know that the address of the written resource has format:
<protocol>://<domain>.ru[/<context>]
where:
* <protocol> can equal either "http" (without the quotes) or "ftp" (without the quotes),
* <domain> is a non-empty string, consisting of lowercase English letters,
* the /<context> part may not be present. If it is present, then <context> is a non-empty string, consisting of lowercase English letters.
If string <context> isn't present in the address, then the additional character "/" isn't written. Thus, the address has either two characters "/" (the ones that go before the domain), or three (an extra one in front of the context).
When the boy came home, he found out that the address he wrote in his notebook had no punctuation marks. Vasya must have been in a lot of hurry and didn't write characters ":", "/", ".".
Help Vasya to restore the possible address of the recorded Internet resource.
Input
The first line contains a non-empty string that Vasya wrote out in his notebook. This line consists of lowercase English letters only.
It is guaranteed that the given string contains at most 50 letters. It is guaranteed that the given string can be obtained from some correct Internet resource address, described above.
Output
Print a single line — the address of the Internet resource that Vasya liked. If there are several addresses that meet the problem limitations, you are allowed to print any of them.
Examples
Input
httpsunrux
Output
http://sun.ru/x
Input
ftphttprururu
Output
ftp://http.ru/ruru
Note
In the second sample there are two more possible answers: "ftp://httpruru.ru" and "ftp://httpru.ru/ru".
Submitted Solution:
```
def puts(s):
print(s, end='')
s = input()
if s.startswith('http'):
puts('http://')
s = s[4:]
else:
puts('ftp://')
s = s[3:]
i = s.rfind('ru')
domen = s[:i]
puts(domen + '.ru')
if(domen + 'ru' != s):
puts('/' + s[i + 2:])
print()
``` | instruction | 0 | 91,227 | 18 | 182,454 |
Yes | output | 1 | 91,227 | 18 | 182,455 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya is an active Internet user. One day he came across an Internet resource he liked, so he wrote its address in the notebook. We know that the address of the written resource has format:
<protocol>://<domain>.ru[/<context>]
where:
* <protocol> can equal either "http" (without the quotes) or "ftp" (without the quotes),
* <domain> is a non-empty string, consisting of lowercase English letters,
* the /<context> part may not be present. If it is present, then <context> is a non-empty string, consisting of lowercase English letters.
If string <context> isn't present in the address, then the additional character "/" isn't written. Thus, the address has either two characters "/" (the ones that go before the domain), or three (an extra one in front of the context).
When the boy came home, he found out that the address he wrote in his notebook had no punctuation marks. Vasya must have been in a lot of hurry and didn't write characters ":", "/", ".".
Help Vasya to restore the possible address of the recorded Internet resource.
Input
The first line contains a non-empty string that Vasya wrote out in his notebook. This line consists of lowercase English letters only.
It is guaranteed that the given string contains at most 50 letters. It is guaranteed that the given string can be obtained from some correct Internet resource address, described above.
Output
Print a single line — the address of the Internet resource that Vasya liked. If there are several addresses that meet the problem limitations, you are allowed to print any of them.
Examples
Input
httpsunrux
Output
http://sun.ru/x
Input
ftphttprururu
Output
ftp://http.ru/ruru
Note
In the second sample there are two more possible answers: "ftp://httpruru.ru" and "ftp://httpru.ru/ru".
Submitted Solution:
```
s = input()
n = len(s)
http = False
ftp = False
last = 0
i = 0
answer = ''
while i < n:
if http or ftp:
if s[i:i+2] == 'ru':
last = i
i += 2
else:
i += 1
else:
if s[i:i+4] == 'http':
answer += 'http://'
http = True
i += 4
elif s[i:i+3] == 'ftp':
answer += 'ftp://'
ftp = True
i += 3
if http:
answer += s[4:last] + '.ru'
if s[last+2:]:
answer += '/' + s[last+2:]
else:
answer += s[3:last] + '.ru'
if s[last+2:]:
answer += '/' + s[last+2:]
print(answer)
``` | instruction | 0 | 91,228 | 18 | 182,456 |
Yes | output | 1 | 91,228 | 18 | 182,457 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya is an active Internet user. One day he came across an Internet resource he liked, so he wrote its address in the notebook. We know that the address of the written resource has format:
<protocol>://<domain>.ru[/<context>]
where:
* <protocol> can equal either "http" (without the quotes) or "ftp" (without the quotes),
* <domain> is a non-empty string, consisting of lowercase English letters,
* the /<context> part may not be present. If it is present, then <context> is a non-empty string, consisting of lowercase English letters.
If string <context> isn't present in the address, then the additional character "/" isn't written. Thus, the address has either two characters "/" (the ones that go before the domain), or three (an extra one in front of the context).
When the boy came home, he found out that the address he wrote in his notebook had no punctuation marks. Vasya must have been in a lot of hurry and didn't write characters ":", "/", ".".
Help Vasya to restore the possible address of the recorded Internet resource.
Input
The first line contains a non-empty string that Vasya wrote out in his notebook. This line consists of lowercase English letters only.
It is guaranteed that the given string contains at most 50 letters. It is guaranteed that the given string can be obtained from some correct Internet resource address, described above.
Output
Print a single line — the address of the Internet resource that Vasya liked. If there are several addresses that meet the problem limitations, you are allowed to print any of them.
Examples
Input
httpsunrux
Output
http://sun.ru/x
Input
ftphttprururu
Output
ftp://http.ru/ruru
Note
In the second sample there are two more possible answers: "ftp://httpruru.ru" and "ftp://httpru.ru/ru".
Submitted Solution:
```
print('/'.join(input().rpartition('ru')).replace('/', '.', 1)
.replace('tp', 'tp://', 1).rstrip('/'))
``` | instruction | 0 | 91,229 | 18 | 182,458 |
Yes | output | 1 | 91,229 | 18 | 182,459 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya is an active Internet user. One day he came across an Internet resource he liked, so he wrote its address in the notebook. We know that the address of the written resource has format:
<protocol>://<domain>.ru[/<context>]
where:
* <protocol> can equal either "http" (without the quotes) or "ftp" (without the quotes),
* <domain> is a non-empty string, consisting of lowercase English letters,
* the /<context> part may not be present. If it is present, then <context> is a non-empty string, consisting of lowercase English letters.
If string <context> isn't present in the address, then the additional character "/" isn't written. Thus, the address has either two characters "/" (the ones that go before the domain), or three (an extra one in front of the context).
When the boy came home, he found out that the address he wrote in his notebook had no punctuation marks. Vasya must have been in a lot of hurry and didn't write characters ":", "/", ".".
Help Vasya to restore the possible address of the recorded Internet resource.
Input
The first line contains a non-empty string that Vasya wrote out in his notebook. This line consists of lowercase English letters only.
It is guaranteed that the given string contains at most 50 letters. It is guaranteed that the given string can be obtained from some correct Internet resource address, described above.
Output
Print a single line — the address of the Internet resource that Vasya liked. If there are several addresses that meet the problem limitations, you are allowed to print any of them.
Examples
Input
httpsunrux
Output
http://sun.ru/x
Input
ftphttprururu
Output
ftp://http.ru/ruru
Note
In the second sample there are two more possible answers: "ftp://httpruru.ru" and "ftp://httpru.ru/ru".
Submitted Solution:
```
s = input()
n = len(s)
http = False
ftp = False
i = 0
answer = ''
while i < n:
if http or ftp:
if s[i:i+2] == 'ru':
answer += '.ru'
i += 2
if s[i:]:
answer += '/' + s[i:]
break
else:
answer += s[i]
i += 1
if s[i:i+4] == 'http':
answer += 'http://'
http = True
i += 4
elif s[i:i+3] == 'ftp':
answer += 'ftp://'
ftp = True
i += 3
print(answer)
``` | instruction | 0 | 91,230 | 18 | 182,460 |
No | output | 1 | 91,230 | 18 | 182,461 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya is an active Internet user. One day he came across an Internet resource he liked, so he wrote its address in the notebook. We know that the address of the written resource has format:
<protocol>://<domain>.ru[/<context>]
where:
* <protocol> can equal either "http" (without the quotes) or "ftp" (without the quotes),
* <domain> is a non-empty string, consisting of lowercase English letters,
* the /<context> part may not be present. If it is present, then <context> is a non-empty string, consisting of lowercase English letters.
If string <context> isn't present in the address, then the additional character "/" isn't written. Thus, the address has either two characters "/" (the ones that go before the domain), or three (an extra one in front of the context).
When the boy came home, he found out that the address he wrote in his notebook had no punctuation marks. Vasya must have been in a lot of hurry and didn't write characters ":", "/", ".".
Help Vasya to restore the possible address of the recorded Internet resource.
Input
The first line contains a non-empty string that Vasya wrote out in his notebook. This line consists of lowercase English letters only.
It is guaranteed that the given string contains at most 50 letters. It is guaranteed that the given string can be obtained from some correct Internet resource address, described above.
Output
Print a single line — the address of the Internet resource that Vasya liked. If there are several addresses that meet the problem limitations, you are allowed to print any of them.
Examples
Input
httpsunrux
Output
http://sun.ru/x
Input
ftphttprururu
Output
ftp://http.ru/ruru
Note
In the second sample there are two more possible answers: "ftp://httpruru.ru" and "ftp://httpru.ru/ru".
Submitted Solution:
```
a = list(input())
if a[0] == 'f':
print('ftp://',end = '')
a = a[3:]
print(''.join(a[:''.join(a).index('ru')]),end = '')
a = a[''.join(a).index('ru')+2:]
print('.ru',end='')
if len(a) != 0:
print('/',end='')
print(''.join(a))
else:
print('http://',end = '')
a = a[4:]
print(''.join(a[:''.join(a).index('ru')]),end = '')
a = a[''.join(a).index('ru')+2:]
print('.ru',end='')
if len(a) != 0:
print('/',end='')
print(''.join(a))
``` | instruction | 0 | 91,231 | 18 | 182,462 |
No | output | 1 | 91,231 | 18 | 182,463 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya is an active Internet user. One day he came across an Internet resource he liked, so he wrote its address in the notebook. We know that the address of the written resource has format:
<protocol>://<domain>.ru[/<context>]
where:
* <protocol> can equal either "http" (without the quotes) or "ftp" (without the quotes),
* <domain> is a non-empty string, consisting of lowercase English letters,
* the /<context> part may not be present. If it is present, then <context> is a non-empty string, consisting of lowercase English letters.
If string <context> isn't present in the address, then the additional character "/" isn't written. Thus, the address has either two characters "/" (the ones that go before the domain), or three (an extra one in front of the context).
When the boy came home, he found out that the address he wrote in his notebook had no punctuation marks. Vasya must have been in a lot of hurry and didn't write characters ":", "/", ".".
Help Vasya to restore the possible address of the recorded Internet resource.
Input
The first line contains a non-empty string that Vasya wrote out in his notebook. This line consists of lowercase English letters only.
It is guaranteed that the given string contains at most 50 letters. It is guaranteed that the given string can be obtained from some correct Internet resource address, described above.
Output
Print a single line — the address of the Internet resource that Vasya liked. If there are several addresses that meet the problem limitations, you are allowed to print any of them.
Examples
Input
httpsunrux
Output
http://sun.ru/x
Input
ftphttprururu
Output
ftp://http.ru/ruru
Note
In the second sample there are two more possible answers: "ftp://httpruru.ru" and "ftp://httpru.ru/ru".
Submitted Solution:
```
s = input()
if(s[0]=='h'):
s1 = s[:4]+"://"
s2 = list(s[4:])
s3=''
c=0
s4=''
for i in range(len(s2)-1):
if s2[i]=='r' and s2[i+1]=='u':
a = s2[i]+s2[i+1]
break
else:
s3 = s3+s2[i]
for i in range(len(s)):
if(s[i]=='r' and s[i+1]=='u'):
s4 = s4+s[i+2:]
print(s1+s3+'.'+a+'/'+s4)
elif(s[0]=='f'):
s1 = s[:3]+"://"+s[3:7]
s2 = list(s[7:])
s3=''
s4=''
for i in range(len(s2)-1):
if s2[i]=='r' and s2[i+1]=='u':
a = s2[i]+s2[i+1]
break
else:
s3=s3+s2[i]
for i in range(len(s)):
if(s[i]=='r' and s[i+1]=='u'):
s4 = s4+s[i+2:]
break
print(s1+s3+'.'+a+'/'+s4)
``` | instruction | 0 | 91,232 | 18 | 182,464 |
No | output | 1 | 91,232 | 18 | 182,465 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya is an active Internet user. One day he came across an Internet resource he liked, so he wrote its address in the notebook. We know that the address of the written resource has format:
<protocol>://<domain>.ru[/<context>]
where:
* <protocol> can equal either "http" (without the quotes) or "ftp" (without the quotes),
* <domain> is a non-empty string, consisting of lowercase English letters,
* the /<context> part may not be present. If it is present, then <context> is a non-empty string, consisting of lowercase English letters.
If string <context> isn't present in the address, then the additional character "/" isn't written. Thus, the address has either two characters "/" (the ones that go before the domain), or three (an extra one in front of the context).
When the boy came home, he found out that the address he wrote in his notebook had no punctuation marks. Vasya must have been in a lot of hurry and didn't write characters ":", "/", ".".
Help Vasya to restore the possible address of the recorded Internet resource.
Input
The first line contains a non-empty string that Vasya wrote out in his notebook. This line consists of lowercase English letters only.
It is guaranteed that the given string contains at most 50 letters. It is guaranteed that the given string can be obtained from some correct Internet resource address, described above.
Output
Print a single line — the address of the Internet resource that Vasya liked. If there are several addresses that meet the problem limitations, you are allowed to print any of them.
Examples
Input
httpsunrux
Output
http://sun.ru/x
Input
ftphttprururu
Output
ftp://http.ru/ruru
Note
In the second sample there are two more possible answers: "ftp://httpruru.ru" and "ftp://httpru.ru/ru".
Submitted Solution:
```
s = input()
if(s[0]=='h'):
s1 = s[:4]+"://"
s2 = list(s[4:])
s3=''
s4=''
for i in range(len(s2)-1):
if s2[i]=='r' and s2[i+1]=='u' and i!=0:
a = s2[i]+s2[i+1]
break
else:
s3 = s3+s2[i]
for i in range(len(s)):
if(s[i]=='r' and s[i+1]=='u' and i!=4):
s4 = s4+s[i+2:]
break
print(s1+s3+'.'+a+'/'+s4)
elif(s[0]=='f'):
s1 = s[:3]+"://"+s[3:7]
s2 = list(s[7:])
s3=''
s4=''
for i in range(len(s2)-1):
if s2[i]=='r' and s2[i+1]=='u':
a = s2[i]+s2[i+1]
break
else:
s3=s3+s2[i]
for i in range(len(s)):
if(s[i]=='r' and s[i+1]=='u'):
s4 = s4+s[i+2:]
break
print(s1+s3+'.'+a+'/'+s4)
``` | instruction | 0 | 91,233 | 18 | 182,466 |
No | output | 1 | 91,233 | 18 | 182,467 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos being duplicated). A photo booklet can be described as a string of lowercase letters, consisting of the photos in the booklet in order. He now wants to sell some "special edition" photobooks, each with one extra photo inserted anywhere in the book. He wants to make as many distinct photobooks as possible, so he can make more money. He asks Haruhi, how many distinct photobooks can he make by inserting one extra photo into the photobook he already has?
Please help Haruhi solve this problem.
Input
The first line of input will be a single string s (1 ≤ |s| ≤ 20). String s consists only of lowercase English letters.
Output
Output a single integer equal to the number of distinct photobooks Kyoya Ootori can make.
Examples
Input
a
Output
51
Input
hi
Output
76
Note
In the first case, we can make 'ab','ac',...,'az','ba','ca',...,'za', and 'aa', producing a total of 51 distinct photo booklets.
Submitted Solution:
```
a=input()
print(((len(a)+1)*26)-len(a))
``` | instruction | 0 | 91,300 | 18 | 182,600 |
Yes | output | 1 | 91,300 | 18 | 182,601 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos being duplicated). A photo booklet can be described as a string of lowercase letters, consisting of the photos in the booklet in order. He now wants to sell some "special edition" photobooks, each with one extra photo inserted anywhere in the book. He wants to make as many distinct photobooks as possible, so he can make more money. He asks Haruhi, how many distinct photobooks can he make by inserting one extra photo into the photobook he already has?
Please help Haruhi solve this problem.
Input
The first line of input will be a single string s (1 ≤ |s| ≤ 20). String s consists only of lowercase English letters.
Output
Output a single integer equal to the number of distinct photobooks Kyoya Ootori can make.
Examples
Input
a
Output
51
Input
hi
Output
76
Note
In the first case, we can make 'ab','ac',...,'az','ba','ca',...,'za', and 'aa', producing a total of 51 distinct photo booklets.
Submitted Solution:
```
d=len(input())
print((d+1)*26-d)
``` | instruction | 0 | 91,301 | 18 | 182,602 |
Yes | output | 1 | 91,301 | 18 | 182,603 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos being duplicated). A photo booklet can be described as a string of lowercase letters, consisting of the photos in the booklet in order. He now wants to sell some "special edition" photobooks, each with one extra photo inserted anywhere in the book. He wants to make as many distinct photobooks as possible, so he can make more money. He asks Haruhi, how many distinct photobooks can he make by inserting one extra photo into the photobook he already has?
Please help Haruhi solve this problem.
Input
The first line of input will be a single string s (1 ≤ |s| ≤ 20). String s consists only of lowercase English letters.
Output
Output a single integer equal to the number of distinct photobooks Kyoya Ootori can make.
Examples
Input
a
Output
51
Input
hi
Output
76
Note
In the first case, we can make 'ab','ac',...,'az','ba','ca',...,'za', and 'aa', producing a total of 51 distinct photo booklets.
Submitted Solution:
```
#-------------Program--------------
#----Kuzlyaev-Nikita-Codeforces----
#-------------Training-------------
#----------------------------------
s=str(input())
print(26*len(s+"s")-len(s))
``` | instruction | 0 | 91,302 | 18 | 182,604 |
Yes | output | 1 | 91,302 | 18 | 182,605 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos being duplicated). A photo booklet can be described as a string of lowercase letters, consisting of the photos in the booklet in order. He now wants to sell some "special edition" photobooks, each with one extra photo inserted anywhere in the book. He wants to make as many distinct photobooks as possible, so he can make more money. He asks Haruhi, how many distinct photobooks can he make by inserting one extra photo into the photobook he already has?
Please help Haruhi solve this problem.
Input
The first line of input will be a single string s (1 ≤ |s| ≤ 20). String s consists only of lowercase English letters.
Output
Output a single integer equal to the number of distinct photobooks Kyoya Ootori can make.
Examples
Input
a
Output
51
Input
hi
Output
76
Note
In the first case, we can make 'ab','ac',...,'az','ba','ca',...,'za', and 'aa', producing a total of 51 distinct photo booklets.
Submitted Solution:
```
s = input()
se = set()
for j in "qwertyuiopasdfghjklzxcvbnm":
for i in range(len(s)+1):
se.add(s[:i]+j+s[i:])
print(len(se))
``` | instruction | 0 | 91,303 | 18 | 182,606 |
Yes | output | 1 | 91,303 | 18 | 182,607 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos being duplicated). A photo booklet can be described as a string of lowercase letters, consisting of the photos in the booklet in order. He now wants to sell some "special edition" photobooks, each with one extra photo inserted anywhere in the book. He wants to make as many distinct photobooks as possible, so he can make more money. He asks Haruhi, how many distinct photobooks can he make by inserting one extra photo into the photobook he already has?
Please help Haruhi solve this problem.
Input
The first line of input will be a single string s (1 ≤ |s| ≤ 20). String s consists only of lowercase English letters.
Output
Output a single integer equal to the number of distinct photobooks Kyoya Ootori can make.
Examples
Input
a
Output
51
Input
hi
Output
76
Note
In the first case, we can make 'ab','ac',...,'az','ba','ca',...,'za', and 'aa', producing a total of 51 distinct photo booklets.
Submitted Solution:
```
st = input()
a = [1]*20
a0 = st[0]
j = 0
for i in range(1,len(st)):
if st[i] == a0:
a[j] += 1
else:
a0 = st[i]
j += 1
if a0 != st[len(st)-2]:
j += 1
i = j+1
while i < len(st):
del a[j+1]
i += 1
print(len(a) * 25 + 26)
``` | instruction | 0 | 91,304 | 18 | 182,608 |
No | output | 1 | 91,304 | 18 | 182,609 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos being duplicated). A photo booklet can be described as a string of lowercase letters, consisting of the photos in the booklet in order. He now wants to sell some "special edition" photobooks, each with one extra photo inserted anywhere in the book. He wants to make as many distinct photobooks as possible, so he can make more money. He asks Haruhi, how many distinct photobooks can he make by inserting one extra photo into the photobook he already has?
Please help Haruhi solve this problem.
Input
The first line of input will be a single string s (1 ≤ |s| ≤ 20). String s consists only of lowercase English letters.
Output
Output a single integer equal to the number of distinct photobooks Kyoya Ootori can make.
Examples
Input
a
Output
51
Input
hi
Output
76
Note
In the first case, we can make 'ab','ac',...,'az','ba','ca',...,'za', and 'aa', producing a total of 51 distinct photo booklets.
Submitted Solution:
```
PRIME_COUNT = 10 ** 6
is_prime = [True] * PRIME_COUNT
primes = []
for i in range(2, 1000):
if is_prime[i]:
for j in range(i * i, PRIME_COUNT, i):
is_prime[j] = False
for i in range(len(is_prime)):
if is_prime[i]:
primes.append(i)
``` | instruction | 0 | 91,305 | 18 | 182,610 |
No | output | 1 | 91,305 | 18 | 182,611 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos being duplicated). A photo booklet can be described as a string of lowercase letters, consisting of the photos in the booklet in order. He now wants to sell some "special edition" photobooks, each with one extra photo inserted anywhere in the book. He wants to make as many distinct photobooks as possible, so he can make more money. He asks Haruhi, how many distinct photobooks can he make by inserting one extra photo into the photobook he already has?
Please help Haruhi solve this problem.
Input
The first line of input will be a single string s (1 ≤ |s| ≤ 20). String s consists only of lowercase English letters.
Output
Output a single integer equal to the number of distinct photobooks Kyoya Ootori can make.
Examples
Input
a
Output
51
Input
hi
Output
76
Note
In the first case, we can make 'ab','ac',...,'az','ba','ca',...,'za', and 'aa', producing a total of 51 distinct photo booklets.
Submitted Solution:
```
a=input()
print(26*(len(a)+1)-len(set(a)))
``` | instruction | 0 | 91,306 | 18 | 182,612 |
No | output | 1 | 91,306 | 18 | 182,613 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos being duplicated). A photo booklet can be described as a string of lowercase letters, consisting of the photos in the booklet in order. He now wants to sell some "special edition" photobooks, each with one extra photo inserted anywhere in the book. He wants to make as many distinct photobooks as possible, so he can make more money. He asks Haruhi, how many distinct photobooks can he make by inserting one extra photo into the photobook he already has?
Please help Haruhi solve this problem.
Input
The first line of input will be a single string s (1 ≤ |s| ≤ 20). String s consists only of lowercase English letters.
Output
Output a single integer equal to the number of distinct photobooks Kyoya Ootori can make.
Examples
Input
a
Output
51
Input
hi
Output
76
Note
In the first case, we can make 'ab','ac',...,'az','ba','ca',...,'za', and 'aa', producing a total of 51 distinct photo booklets.
Submitted Solution:
```
'''
Welcome to GDB Online.
GDB online is an online compiler and debugger tool for C, C++, Python, Java, PHP, Ruby, Perl,
C#, VB, Swift, Pascal, Fortran, Haskell, Objective-C, Assembly, HTML, CSS, JS, SQLite, Prolog.
Code, Compile, Run and Debug online from anywhere in world.
'''
s=input()
n=len(s)
if(n>1):
a=(26-n)*(n+1)+(n*2)
else:
a=(26-n)*(n+1)+1
print(a)
``` | instruction | 0 | 91,307 | 18 | 182,614 |
No | output | 1 | 91,307 | 18 | 182,615 |
Provide a correct Python 3 solution for this coding contest problem.
Dr .: Peter, I've finally done it.
Peter: What's wrong, Dr. David? Is it a silly invention again?
Dr .: This table, this table.
| Character | Sign
--- | ---
(Blank) | 101
'| 000000
, | 000011
-| 10010001
. | 010001
? | 000001
A | 100101
B | 10011010
| Character | Sign
--- | ---
C | 0101
D | 0001
E | 110
F | 01001
G | 10011011
H | 010000
I | 0111
J | 10011000
| Character | Sign
--- | ---
K | 0110
L | 00100
M | 10011001
N | 10011110
O | 00101
P | 111
Q | 10011111
R | 1000
| Character | Sign
--- | ---
S | 00110
T | 00111
U | 10011100
V | 10011101
W | 000010
X | 10010010
Y | 10010011
Z | 10010000
Peter: What? This table is.
Dr .: Okay, just do what you say. First, write your name on a piece of paper.
Peter: Yes, "PETER POTTER".
Dr .: Then, replace each character with the "code" in this table.
Peter: Well, change "P" to "111" and "E" to "110" ... It's quite annoying.
111 110 00111 110 1000 101 111 00101 00111 00111 110 1000
became. It looks like a barcode.
Dr .: All right. Then connect all the replaced strings and separate them by 5 characters.
Peter: Yes, if you connect and separate.
11111 00011 11101 00010 11110 01010 01110 01111 10100 0
It turned out to be something like this. But what about the last "0" guy?
Dr .: Add 0 to make it 5 letters.
Peter: Well, there is only one 0 at the end, so I should add four more 0s. I was able to do it.
11111 00011 11101 00010 11110 01010 01110 01111 10100 00000
Dr .: Next, use this table.
| Sign | Character
--- | ---
00000 | A
00001 | B
00010 | C
00011 | D
00100 | E
00101 | F
00110 | G
00111 | H
| Sign | Character
--- | ---
01000 | I
01001 | J
01010 | K
01011 | L
01100 | M
01101 | N
01110 | O
01111 | P
| Sign | Character
--- | ---
10000 | Q
10001 | R
10010 | S
10011 | T
10100 | U
10101 | V
10110 | W
10111 | X
| Sign | Character
--- | ---
11000 | Y
11001 | Z
11010 | (blank)
11011 | ..
11100 |,
11101 |-
11110 |'
11111 |?
Peter: How do you use this ... yeah! Now you're going to replace the code with a letter!
Dr .: That's right. If it is "11111", go to "?", If it is "00011", go to "D".
Peter: This is simple ... well, it became "? D-C'KOPUA". But it doesn't make sense.
Dr .: Count the number of characters.
Peter: It's 10 characters. Oh, "PETER POTTER" was 12 characters, but 2 characters are reduced.
Dr .: Yes, you can use this table to reduce the number of letters. Now do the same thing in this sentence.
PETER PIPER PICKED A PECK OF PICKLED PEPPERS. A PECK OF PICKLED PEPPERS
PETER PIPER PICKED. IF PETER PIPER PICKED A PECK OF PICKLED PEPPERS, WHERE'S
THE PECK OF PICKLED PEPPERS PETER PIPER PICKED?
Peter: Gyogyo, the lines are separated, what do you do?
Dr .: Due to space limitations, there are only 3 lines, but think of it as a long line with a space instead of a newline character.
Peter: Yes, yes. There is a blank space between the lines. But it's a hassle ...
Dr .: Then why not let the program do it?
So, instead of Peter, create a program that converts the read character string into a code and outputs it.
input
Given multiple datasets. Each dataset is given a line of strings (consisting of the characters contained in the table). The string contains at least 1 and no more than 100 characters.
The number of datasets does not exceed 200.
output
For each data set, output the converted character string on one line.
Example
Input
PETER POTTER
Output
?D-C'KOPUA | instruction | 0 | 91,611 | 18 | 183,222 |
"Correct Solution:
```
L = { " ": "101",
"'": "000000",
",": "000011",
"-": "10010001",
".": "010001",
"?": "000001",
"A": "100101",
"B": "10011010",
"C": "0101",
"D": "0001",
"E": "110",
"F": "01001",
"G": "10011011",
"H": "010000",
"I": "0111",
"J": "10011000",
"K": "0110",
"L": "00100",
"M": "10011001",
"N": "10011110",
"O": "00101",
"P": "111",
"Q": "10011111",
"R": "1000",
"S": "00110",
"T": "00111",
"U": "10011100",
"V": "10011101",
"W": "000010",
"X": "10010010",
"Y": "10010011",
"Z": "10010000" }
M = { "00000": "A",
"00001": "B",
"00010": "C",
"00011": "D",
"00100": "E",
"00101": "F",
"00110": "G",
"00111": "H",
"01000": "I",
"01001": "J",
"01010": "K",
"01011": "L",
"01100": "M",
"01101": "N",
"01110": "O",
"01111": "P",
"10000": "Q",
"10001": "R",
"10010": "S",
"10011": "T",
"10100": "U",
"10101": "V",
"10110": "W",
"10111": "X",
"11000": "Y",
"11001": "Z",
"11010": " ",
"11011": ".",
"11100": ",",
"11101": "-",
"11110": "'",
"11111": "?" }
while True:
try:
s = input()
except:
break
t = ""
for i in s:
t += L[i]
t += "0" * ( (-len(t))%5 )
o = ""
for i in range( len(t) // 5 ):
u = t[i*5:i*5+5]
o += M[u]
print(o)
``` | output | 1 | 91,611 | 18 | 183,223 |
Provide a correct Python 3 solution for this coding contest problem.
Dr .: Peter, I've finally done it.
Peter: What's wrong, Dr. David? Is it a silly invention again?
Dr .: This table, this table.
| Character | Sign
--- | ---
(Blank) | 101
'| 000000
, | 000011
-| 10010001
. | 010001
? | 000001
A | 100101
B | 10011010
| Character | Sign
--- | ---
C | 0101
D | 0001
E | 110
F | 01001
G | 10011011
H | 010000
I | 0111
J | 10011000
| Character | Sign
--- | ---
K | 0110
L | 00100
M | 10011001
N | 10011110
O | 00101
P | 111
Q | 10011111
R | 1000
| Character | Sign
--- | ---
S | 00110
T | 00111
U | 10011100
V | 10011101
W | 000010
X | 10010010
Y | 10010011
Z | 10010000
Peter: What? This table is.
Dr .: Okay, just do what you say. First, write your name on a piece of paper.
Peter: Yes, "PETER POTTER".
Dr .: Then, replace each character with the "code" in this table.
Peter: Well, change "P" to "111" and "E" to "110" ... It's quite annoying.
111 110 00111 110 1000 101 111 00101 00111 00111 110 1000
became. It looks like a barcode.
Dr .: All right. Then connect all the replaced strings and separate them by 5 characters.
Peter: Yes, if you connect and separate.
11111 00011 11101 00010 11110 01010 01110 01111 10100 0
It turned out to be something like this. But what about the last "0" guy?
Dr .: Add 0 to make it 5 letters.
Peter: Well, there is only one 0 at the end, so I should add four more 0s. I was able to do it.
11111 00011 11101 00010 11110 01010 01110 01111 10100 00000
Dr .: Next, use this table.
| Sign | Character
--- | ---
00000 | A
00001 | B
00010 | C
00011 | D
00100 | E
00101 | F
00110 | G
00111 | H
| Sign | Character
--- | ---
01000 | I
01001 | J
01010 | K
01011 | L
01100 | M
01101 | N
01110 | O
01111 | P
| Sign | Character
--- | ---
10000 | Q
10001 | R
10010 | S
10011 | T
10100 | U
10101 | V
10110 | W
10111 | X
| Sign | Character
--- | ---
11000 | Y
11001 | Z
11010 | (blank)
11011 | ..
11100 |,
11101 |-
11110 |'
11111 |?
Peter: How do you use this ... yeah! Now you're going to replace the code with a letter!
Dr .: That's right. If it is "11111", go to "?", If it is "00011", go to "D".
Peter: This is simple ... well, it became "? D-C'KOPUA". But it doesn't make sense.
Dr .: Count the number of characters.
Peter: It's 10 characters. Oh, "PETER POTTER" was 12 characters, but 2 characters are reduced.
Dr .: Yes, you can use this table to reduce the number of letters. Now do the same thing in this sentence.
PETER PIPER PICKED A PECK OF PICKLED PEPPERS. A PECK OF PICKLED PEPPERS
PETER PIPER PICKED. IF PETER PIPER PICKED A PECK OF PICKLED PEPPERS, WHERE'S
THE PECK OF PICKLED PEPPERS PETER PIPER PICKED?
Peter: Gyogyo, the lines are separated, what do you do?
Dr .: Due to space limitations, there are only 3 lines, but think of it as a long line with a space instead of a newline character.
Peter: Yes, yes. There is a blank space between the lines. But it's a hassle ...
Dr .: Then why not let the program do it?
So, instead of Peter, create a program that converts the read character string into a code and outputs it.
input
Given multiple datasets. Each dataset is given a line of strings (consisting of the characters contained in the table). The string contains at least 1 and no more than 100 characters.
The number of datasets does not exceed 200.
output
For each data set, output the converted character string on one line.
Example
Input
PETER POTTER
Output
?D-C'KOPUA | instruction | 0 | 91,612 | 18 | 183,224 |
"Correct Solution:
```
en=[chr(i) for i in range(65,91)]+list(' .,-\'?')
de={
' ':'101','\'':'000000',',':'000011','-':'10010001','.':'010001','?':'000001',
'A':'100101','B':'10011010','C':'0101','D':'0001','E':'110','F':'01001',
'G':'10011011','H':'010000','I':'0111','J':'10011000','K':'0110','L':'00100',
'M':'10011001','N':'10011110','O':'00101','P':'111','Q':'10011111','R':'1000',
'S':'00110','T':'00111','U':'10011100','V':'10011101','W':'000010','X':'10010010',
'Y':'10010011','Z':'10010000'
}
while 1:
try:s=input()
except:break
a=b=''
for x in s:a+=de[x]
a+='0'*(-len(a)%5)
for i in range(len(a)//5):b+=en[int(a[i*5:i*5+5],2)]
print(b)
``` | output | 1 | 91,612 | 18 | 183,225 |
Provide a correct Python 3 solution for this coding contest problem.
Dr .: Peter, I've finally done it.
Peter: What's wrong, Dr. David? Is it a silly invention again?
Dr .: This table, this table.
| Character | Sign
--- | ---
(Blank) | 101
'| 000000
, | 000011
-| 10010001
. | 010001
? | 000001
A | 100101
B | 10011010
| Character | Sign
--- | ---
C | 0101
D | 0001
E | 110
F | 01001
G | 10011011
H | 010000
I | 0111
J | 10011000
| Character | Sign
--- | ---
K | 0110
L | 00100
M | 10011001
N | 10011110
O | 00101
P | 111
Q | 10011111
R | 1000
| Character | Sign
--- | ---
S | 00110
T | 00111
U | 10011100
V | 10011101
W | 000010
X | 10010010
Y | 10010011
Z | 10010000
Peter: What? This table is.
Dr .: Okay, just do what you say. First, write your name on a piece of paper.
Peter: Yes, "PETER POTTER".
Dr .: Then, replace each character with the "code" in this table.
Peter: Well, change "P" to "111" and "E" to "110" ... It's quite annoying.
111 110 00111 110 1000 101 111 00101 00111 00111 110 1000
became. It looks like a barcode.
Dr .: All right. Then connect all the replaced strings and separate them by 5 characters.
Peter: Yes, if you connect and separate.
11111 00011 11101 00010 11110 01010 01110 01111 10100 0
It turned out to be something like this. But what about the last "0" guy?
Dr .: Add 0 to make it 5 letters.
Peter: Well, there is only one 0 at the end, so I should add four more 0s. I was able to do it.
11111 00011 11101 00010 11110 01010 01110 01111 10100 00000
Dr .: Next, use this table.
| Sign | Character
--- | ---
00000 | A
00001 | B
00010 | C
00011 | D
00100 | E
00101 | F
00110 | G
00111 | H
| Sign | Character
--- | ---
01000 | I
01001 | J
01010 | K
01011 | L
01100 | M
01101 | N
01110 | O
01111 | P
| Sign | Character
--- | ---
10000 | Q
10001 | R
10010 | S
10011 | T
10100 | U
10101 | V
10110 | W
10111 | X
| Sign | Character
--- | ---
11000 | Y
11001 | Z
11010 | (blank)
11011 | ..
11100 |,
11101 |-
11110 |'
11111 |?
Peter: How do you use this ... yeah! Now you're going to replace the code with a letter!
Dr .: That's right. If it is "11111", go to "?", If it is "00011", go to "D".
Peter: This is simple ... well, it became "? D-C'KOPUA". But it doesn't make sense.
Dr .: Count the number of characters.
Peter: It's 10 characters. Oh, "PETER POTTER" was 12 characters, but 2 characters are reduced.
Dr .: Yes, you can use this table to reduce the number of letters. Now do the same thing in this sentence.
PETER PIPER PICKED A PECK OF PICKLED PEPPERS. A PECK OF PICKLED PEPPERS
PETER PIPER PICKED. IF PETER PIPER PICKED A PECK OF PICKLED PEPPERS, WHERE'S
THE PECK OF PICKLED PEPPERS PETER PIPER PICKED?
Peter: Gyogyo, the lines are separated, what do you do?
Dr .: Due to space limitations, there are only 3 lines, but think of it as a long line with a space instead of a newline character.
Peter: Yes, yes. There is a blank space between the lines. But it's a hassle ...
Dr .: Then why not let the program do it?
So, instead of Peter, create a program that converts the read character string into a code and outputs it.
input
Given multiple datasets. Each dataset is given a line of strings (consisting of the characters contained in the table). The string contains at least 1 and no more than 100 characters.
The number of datasets does not exceed 200.
output
For each data set, output the converted character string on one line.
Example
Input
PETER POTTER
Output
?D-C'KOPUA | instruction | 0 | 91,613 | 18 | 183,226 |
"Correct Solution:
```
_encode={
" ":"101",
"'":"000000",
",":"000011",
"-":"10010001",
".":"010001",
"?":"000001",
"A":"100101",
"B":"10011010",
"C":"0101",
"D":"0001",
"E":"110",
"F":"01001",
"G":"10011011",
"H":"010000",
"I":"0111",
"J":"10011000",
"K":"0110",
"L":"00100",
"M":"10011001",
"N":"10011110",
"O":"00101",
"P":"111",
"Q":"10011111",
"R":"1000",
"S":"00110",
"T":"00111",
"U":"10011100",
"V":"10011101",
"W":"000010",
"X":"10010010",
"Y":"10010011",
"Z":"10010000"
}
def encode(c):
return _encode[c]
def decode(s):
num=0
for i,c in enumerate(s):
if c=="1":
num+=2**(4-i)
if num<26:
return chr(ord('A')+num)
elif num==26:
return " "
elif num==27:
return "."
elif num==28:
return ","
elif num==29:
return "-"
elif num==30:
return "'"
else:
return "?"
while True:
try:
s=input()
encoded=""
for c in s:
encoded+=encode(c)
while(len(encoded)%5!=0):
encoded+="0"
decoded=""
for i in range(len(encoded)//5):
decoded+=decode(encoded[5*i:5*i+5])
print(decoded)
except EOFError:
break
``` | output | 1 | 91,613 | 18 | 183,227 |
Provide a correct Python 3 solution for this coding contest problem.
Dr .: Peter, I've finally done it.
Peter: What's wrong, Dr. David? Is it a silly invention again?
Dr .: This table, this table.
| Character | Sign
--- | ---
(Blank) | 101
'| 000000
, | 000011
-| 10010001
. | 010001
? | 000001
A | 100101
B | 10011010
| Character | Sign
--- | ---
C | 0101
D | 0001
E | 110
F | 01001
G | 10011011
H | 010000
I | 0111
J | 10011000
| Character | Sign
--- | ---
K | 0110
L | 00100
M | 10011001
N | 10011110
O | 00101
P | 111
Q | 10011111
R | 1000
| Character | Sign
--- | ---
S | 00110
T | 00111
U | 10011100
V | 10011101
W | 000010
X | 10010010
Y | 10010011
Z | 10010000
Peter: What? This table is.
Dr .: Okay, just do what you say. First, write your name on a piece of paper.
Peter: Yes, "PETER POTTER".
Dr .: Then, replace each character with the "code" in this table.
Peter: Well, change "P" to "111" and "E" to "110" ... It's quite annoying.
111 110 00111 110 1000 101 111 00101 00111 00111 110 1000
became. It looks like a barcode.
Dr .: All right. Then connect all the replaced strings and separate them by 5 characters.
Peter: Yes, if you connect and separate.
11111 00011 11101 00010 11110 01010 01110 01111 10100 0
It turned out to be something like this. But what about the last "0" guy?
Dr .: Add 0 to make it 5 letters.
Peter: Well, there is only one 0 at the end, so I should add four more 0s. I was able to do it.
11111 00011 11101 00010 11110 01010 01110 01111 10100 00000
Dr .: Next, use this table.
| Sign | Character
--- | ---
00000 | A
00001 | B
00010 | C
00011 | D
00100 | E
00101 | F
00110 | G
00111 | H
| Sign | Character
--- | ---
01000 | I
01001 | J
01010 | K
01011 | L
01100 | M
01101 | N
01110 | O
01111 | P
| Sign | Character
--- | ---
10000 | Q
10001 | R
10010 | S
10011 | T
10100 | U
10101 | V
10110 | W
10111 | X
| Sign | Character
--- | ---
11000 | Y
11001 | Z
11010 | (blank)
11011 | ..
11100 |,
11101 |-
11110 |'
11111 |?
Peter: How do you use this ... yeah! Now you're going to replace the code with a letter!
Dr .: That's right. If it is "11111", go to "?", If it is "00011", go to "D".
Peter: This is simple ... well, it became "? D-C'KOPUA". But it doesn't make sense.
Dr .: Count the number of characters.
Peter: It's 10 characters. Oh, "PETER POTTER" was 12 characters, but 2 characters are reduced.
Dr .: Yes, you can use this table to reduce the number of letters. Now do the same thing in this sentence.
PETER PIPER PICKED A PECK OF PICKLED PEPPERS. A PECK OF PICKLED PEPPERS
PETER PIPER PICKED. IF PETER PIPER PICKED A PECK OF PICKLED PEPPERS, WHERE'S
THE PECK OF PICKLED PEPPERS PETER PIPER PICKED?
Peter: Gyogyo, the lines are separated, what do you do?
Dr .: Due to space limitations, there are only 3 lines, but think of it as a long line with a space instead of a newline character.
Peter: Yes, yes. There is a blank space between the lines. But it's a hassle ...
Dr .: Then why not let the program do it?
So, instead of Peter, create a program that converts the read character string into a code and outputs it.
input
Given multiple datasets. Each dataset is given a line of strings (consisting of the characters contained in the table). The string contains at least 1 and no more than 100 characters.
The number of datasets does not exceed 200.
output
For each data set, output the converted character string on one line.
Example
Input
PETER POTTER
Output
?D-C'KOPUA | instruction | 0 | 91,614 | 18 | 183,228 |
"Correct Solution:
```
chA = {' ':'101', "'":'000000', ',':'000011', '-':'10010001', '.':'010001', '?':'000001', 'A':'100101',
'B':'10011010', 'C':'0101', 'D':'0001', 'E':'110', 'F':'01001', 'G':'10011011', 'H':'010000',
'I':'0111', 'J':'10011000', 'K':'0110', 'L':'00100', 'M':'10011001', 'N':'10011110', 'O':'00101',
'P':'111', 'Q':'10011111', 'R':'1000', 'S':'00110', 'T':'00111', 'U':'10011100', 'V':'10011101',
'W':'000010', 'X':'10010010', 'Y':'10010011', 'Z':'10010000'}
chB = {'00000':'A', '00001':'B', '00010':'C', '00011':'D', '00100':'E', '00101':'F',
'00110':'G', '00111':'H', '01000':'I', '01001':'J', '01010':'K', '01011':'L',
'01100':'M', '01101':'N', '01110':'O', '01111':'P', '10000':'Q', '10001':'R',
'10010':'S', '10011':'T', '10100':'U', '10101':'V', '10110':'W', '10111':'X',
'11000':'Y', '11001':'Z', '11010':' ', '11011':'.', '11100':',', '11101':'-', '11110':"'", '11111':'?'}
while True:
try:
s = input()
except EOFError:
break
chlst = ''
numlst = []
anslst = ''
for i in s:
if i == '\\':
chlst = chlst + chA[' ']
else:
chlst = chlst + chA[i]
if len(chlst)%5 != 0:
for k in range(5-(len(chlst)%5)):
chlst += '0'
for j in range(len(chlst)//5):
numlst.append(chlst[5*j: 5*j+5])
for l in numlst:
anslst = anslst + chB[l]
print(anslst)
``` | output | 1 | 91,614 | 18 | 183,229 |
Provide a correct Python 3 solution for this coding contest problem.
Dr .: Peter, I've finally done it.
Peter: What's wrong, Dr. David? Is it a silly invention again?
Dr .: This table, this table.
| Character | Sign
--- | ---
(Blank) | 101
'| 000000
, | 000011
-| 10010001
. | 010001
? | 000001
A | 100101
B | 10011010
| Character | Sign
--- | ---
C | 0101
D | 0001
E | 110
F | 01001
G | 10011011
H | 010000
I | 0111
J | 10011000
| Character | Sign
--- | ---
K | 0110
L | 00100
M | 10011001
N | 10011110
O | 00101
P | 111
Q | 10011111
R | 1000
| Character | Sign
--- | ---
S | 00110
T | 00111
U | 10011100
V | 10011101
W | 000010
X | 10010010
Y | 10010011
Z | 10010000
Peter: What? This table is.
Dr .: Okay, just do what you say. First, write your name on a piece of paper.
Peter: Yes, "PETER POTTER".
Dr .: Then, replace each character with the "code" in this table.
Peter: Well, change "P" to "111" and "E" to "110" ... It's quite annoying.
111 110 00111 110 1000 101 111 00101 00111 00111 110 1000
became. It looks like a barcode.
Dr .: All right. Then connect all the replaced strings and separate them by 5 characters.
Peter: Yes, if you connect and separate.
11111 00011 11101 00010 11110 01010 01110 01111 10100 0
It turned out to be something like this. But what about the last "0" guy?
Dr .: Add 0 to make it 5 letters.
Peter: Well, there is only one 0 at the end, so I should add four more 0s. I was able to do it.
11111 00011 11101 00010 11110 01010 01110 01111 10100 00000
Dr .: Next, use this table.
| Sign | Character
--- | ---
00000 | A
00001 | B
00010 | C
00011 | D
00100 | E
00101 | F
00110 | G
00111 | H
| Sign | Character
--- | ---
01000 | I
01001 | J
01010 | K
01011 | L
01100 | M
01101 | N
01110 | O
01111 | P
| Sign | Character
--- | ---
10000 | Q
10001 | R
10010 | S
10011 | T
10100 | U
10101 | V
10110 | W
10111 | X
| Sign | Character
--- | ---
11000 | Y
11001 | Z
11010 | (blank)
11011 | ..
11100 |,
11101 |-
11110 |'
11111 |?
Peter: How do you use this ... yeah! Now you're going to replace the code with a letter!
Dr .: That's right. If it is "11111", go to "?", If it is "00011", go to "D".
Peter: This is simple ... well, it became "? D-C'KOPUA". But it doesn't make sense.
Dr .: Count the number of characters.
Peter: It's 10 characters. Oh, "PETER POTTER" was 12 characters, but 2 characters are reduced.
Dr .: Yes, you can use this table to reduce the number of letters. Now do the same thing in this sentence.
PETER PIPER PICKED A PECK OF PICKLED PEPPERS. A PECK OF PICKLED PEPPERS
PETER PIPER PICKED. IF PETER PIPER PICKED A PECK OF PICKLED PEPPERS, WHERE'S
THE PECK OF PICKLED PEPPERS PETER PIPER PICKED?
Peter: Gyogyo, the lines are separated, what do you do?
Dr .: Due to space limitations, there are only 3 lines, but think of it as a long line with a space instead of a newline character.
Peter: Yes, yes. There is a blank space between the lines. But it's a hassle ...
Dr .: Then why not let the program do it?
So, instead of Peter, create a program that converts the read character string into a code and outputs it.
input
Given multiple datasets. Each dataset is given a line of strings (consisting of the characters contained in the table). The string contains at least 1 and no more than 100 characters.
The number of datasets does not exceed 200.
output
For each data set, output the converted character string on one line.
Example
Input
PETER POTTER
Output
?D-C'KOPUA | instruction | 0 | 91,615 | 18 | 183,230 |
"Correct Solution:
```
# AOJ 0088: The Code A Doctor Loved
# Python3 2018.6.28 bal4u
c2d = {'A':"100101", 'B':"10011010", 'C':"0101", 'D':"0001", 'E':"110", 'F':"01001", \
'G':"10011011", 'H':"010000", 'I':"0111", 'J':"10011000", 'K':"0110", 'L':"00100", \
'M':"10011001", 'N':"10011110", 'O':"00101", 'P':"111", 'Q':"10011111", 'R':"1000", \
'S':"00110", 'T':"00111", 'U':"10011100", 'V':"10011101", 'W':"000010", 'X':"10010010", \
'Y':"10010011", 'Z':"10010000", ' ':"101", "'":"000000", ',':"000011", \
'-':"10010001", '.':"010001", '?':"000001"}
d2c = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', \
'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z', ' ', '.', ',', '-', '\'', '?']
while True:
try: p = input()
except: break
ans, tmp = '', ''
for c in p: tmp += c2d[c]
if len(tmp) % 5 > 0: tmp += '0'*(5-len(tmp)%5)
for i in range(0, len(tmp), 5): ans += d2c[int(tmp[i:i+5], 2)]
print(ans)
``` | output | 1 | 91,615 | 18 | 183,231 |
Provide a correct Python 3 solution for this coding contest problem.
Dr .: Peter, I've finally done it.
Peter: What's wrong, Dr. David? Is it a silly invention again?
Dr .: This table, this table.
| Character | Sign
--- | ---
(Blank) | 101
'| 000000
, | 000011
-| 10010001
. | 010001
? | 000001
A | 100101
B | 10011010
| Character | Sign
--- | ---
C | 0101
D | 0001
E | 110
F | 01001
G | 10011011
H | 010000
I | 0111
J | 10011000
| Character | Sign
--- | ---
K | 0110
L | 00100
M | 10011001
N | 10011110
O | 00101
P | 111
Q | 10011111
R | 1000
| Character | Sign
--- | ---
S | 00110
T | 00111
U | 10011100
V | 10011101
W | 000010
X | 10010010
Y | 10010011
Z | 10010000
Peter: What? This table is.
Dr .: Okay, just do what you say. First, write your name on a piece of paper.
Peter: Yes, "PETER POTTER".
Dr .: Then, replace each character with the "code" in this table.
Peter: Well, change "P" to "111" and "E" to "110" ... It's quite annoying.
111 110 00111 110 1000 101 111 00101 00111 00111 110 1000
became. It looks like a barcode.
Dr .: All right. Then connect all the replaced strings and separate them by 5 characters.
Peter: Yes, if you connect and separate.
11111 00011 11101 00010 11110 01010 01110 01111 10100 0
It turned out to be something like this. But what about the last "0" guy?
Dr .: Add 0 to make it 5 letters.
Peter: Well, there is only one 0 at the end, so I should add four more 0s. I was able to do it.
11111 00011 11101 00010 11110 01010 01110 01111 10100 00000
Dr .: Next, use this table.
| Sign | Character
--- | ---
00000 | A
00001 | B
00010 | C
00011 | D
00100 | E
00101 | F
00110 | G
00111 | H
| Sign | Character
--- | ---
01000 | I
01001 | J
01010 | K
01011 | L
01100 | M
01101 | N
01110 | O
01111 | P
| Sign | Character
--- | ---
10000 | Q
10001 | R
10010 | S
10011 | T
10100 | U
10101 | V
10110 | W
10111 | X
| Sign | Character
--- | ---
11000 | Y
11001 | Z
11010 | (blank)
11011 | ..
11100 |,
11101 |-
11110 |'
11111 |?
Peter: How do you use this ... yeah! Now you're going to replace the code with a letter!
Dr .: That's right. If it is "11111", go to "?", If it is "00011", go to "D".
Peter: This is simple ... well, it became "? D-C'KOPUA". But it doesn't make sense.
Dr .: Count the number of characters.
Peter: It's 10 characters. Oh, "PETER POTTER" was 12 characters, but 2 characters are reduced.
Dr .: Yes, you can use this table to reduce the number of letters. Now do the same thing in this sentence.
PETER PIPER PICKED A PECK OF PICKLED PEPPERS. A PECK OF PICKLED PEPPERS
PETER PIPER PICKED. IF PETER PIPER PICKED A PECK OF PICKLED PEPPERS, WHERE'S
THE PECK OF PICKLED PEPPERS PETER PIPER PICKED?
Peter: Gyogyo, the lines are separated, what do you do?
Dr .: Due to space limitations, there are only 3 lines, but think of it as a long line with a space instead of a newline character.
Peter: Yes, yes. There is a blank space between the lines. But it's a hassle ...
Dr .: Then why not let the program do it?
So, instead of Peter, create a program that converts the read character string into a code and outputs it.
input
Given multiple datasets. Each dataset is given a line of strings (consisting of the characters contained in the table). The string contains at least 1 and no more than 100 characters.
The number of datasets does not exceed 200.
output
For each data set, output the converted character string on one line.
Example
Input
PETER POTTER
Output
?D-C'KOPUA | instruction | 0 | 91,616 | 18 | 183,232 |
"Correct Solution:
```
from itertools import chain
import sys
table1 = dict(zip(
chain(" ',-.?", map(chr, range(65, 91))),
"101 000000 000011 10010001 010001 000001 100101 10011010\
0101 0001 110 01001 10011011 010000 0111 10011000\
0110 00100 10011001 10011110 00101 111 10011111 1000\
00110 00111 10011100 10011101 000010 10010010 10010011 10010000".split()
))
table2 = dict(enumerate(chain(map(chr, range(65, 91)), " .,-'?")))
for l in sys.stdin:
code = "".join(table1[c] for c in l.rstrip("\n"))
code += "0"*(5-(len(code)%5)) if len(code)%5 else ""
print("".join(table2[int(code[i*5:(i+1)*5], 2)] for i in range(len(code)//5)))
``` | output | 1 | 91,616 | 18 | 183,233 |
Provide a correct Python 3 solution for this coding contest problem.
Dr .: Peter, I've finally done it.
Peter: What's wrong, Dr. David? Is it a silly invention again?
Dr .: This table, this table.
| Character | Sign
--- | ---
(Blank) | 101
'| 000000
, | 000011
-| 10010001
. | 010001
? | 000001
A | 100101
B | 10011010
| Character | Sign
--- | ---
C | 0101
D | 0001
E | 110
F | 01001
G | 10011011
H | 010000
I | 0111
J | 10011000
| Character | Sign
--- | ---
K | 0110
L | 00100
M | 10011001
N | 10011110
O | 00101
P | 111
Q | 10011111
R | 1000
| Character | Sign
--- | ---
S | 00110
T | 00111
U | 10011100
V | 10011101
W | 000010
X | 10010010
Y | 10010011
Z | 10010000
Peter: What? This table is.
Dr .: Okay, just do what you say. First, write your name on a piece of paper.
Peter: Yes, "PETER POTTER".
Dr .: Then, replace each character with the "code" in this table.
Peter: Well, change "P" to "111" and "E" to "110" ... It's quite annoying.
111 110 00111 110 1000 101 111 00101 00111 00111 110 1000
became. It looks like a barcode.
Dr .: All right. Then connect all the replaced strings and separate them by 5 characters.
Peter: Yes, if you connect and separate.
11111 00011 11101 00010 11110 01010 01110 01111 10100 0
It turned out to be something like this. But what about the last "0" guy?
Dr .: Add 0 to make it 5 letters.
Peter: Well, there is only one 0 at the end, so I should add four more 0s. I was able to do it.
11111 00011 11101 00010 11110 01010 01110 01111 10100 00000
Dr .: Next, use this table.
| Sign | Character
--- | ---
00000 | A
00001 | B
00010 | C
00011 | D
00100 | E
00101 | F
00110 | G
00111 | H
| Sign | Character
--- | ---
01000 | I
01001 | J
01010 | K
01011 | L
01100 | M
01101 | N
01110 | O
01111 | P
| Sign | Character
--- | ---
10000 | Q
10001 | R
10010 | S
10011 | T
10100 | U
10101 | V
10110 | W
10111 | X
| Sign | Character
--- | ---
11000 | Y
11001 | Z
11010 | (blank)
11011 | ..
11100 |,
11101 |-
11110 |'
11111 |?
Peter: How do you use this ... yeah! Now you're going to replace the code with a letter!
Dr .: That's right. If it is "11111", go to "?", If it is "00011", go to "D".
Peter: This is simple ... well, it became "? D-C'KOPUA". But it doesn't make sense.
Dr .: Count the number of characters.
Peter: It's 10 characters. Oh, "PETER POTTER" was 12 characters, but 2 characters are reduced.
Dr .: Yes, you can use this table to reduce the number of letters. Now do the same thing in this sentence.
PETER PIPER PICKED A PECK OF PICKLED PEPPERS. A PECK OF PICKLED PEPPERS
PETER PIPER PICKED. IF PETER PIPER PICKED A PECK OF PICKLED PEPPERS, WHERE'S
THE PECK OF PICKLED PEPPERS PETER PIPER PICKED?
Peter: Gyogyo, the lines are separated, what do you do?
Dr .: Due to space limitations, there are only 3 lines, but think of it as a long line with a space instead of a newline character.
Peter: Yes, yes. There is a blank space between the lines. But it's a hassle ...
Dr .: Then why not let the program do it?
So, instead of Peter, create a program that converts the read character string into a code and outputs it.
input
Given multiple datasets. Each dataset is given a line of strings (consisting of the characters contained in the table). The string contains at least 1 and no more than 100 characters.
The number of datasets does not exceed 200.
output
For each data set, output the converted character string on one line.
Example
Input
PETER POTTER
Output
?D-C'KOPUA | instruction | 0 | 91,617 | 18 | 183,234 |
"Correct Solution:
```
encode = "ABCDEFGHIJKLMNOPQRSTUVWXYZ" + " .,-\'?"
decode = {" ":"101","\'":"000000",",":"000011","-":"10010001",".":"010001","?":"000001",
"A":"100101","B":"10011010","C":"0101","D":"0001","E":"110","F":"01001",
"G":"10011011","H":"010000","I":"0111","J":"10011000","K":"0110","L":"00100",
"M":"10011001","N":"10011110","O":"00101","P":"111","Q":"10011111","R":"1000",
"S":"00110","T":"00111","U":"10011100","V":"10011101","W":"000010","X":"10010010",
"Y":"10010011","Z":"10010000"}
while True:
try:
a = input()
code = ""
for inp in a:
code += decode[inp]
code += "0"*(-len(code)%5)
ans = ""
for i in range(len(code)//5):
ans += encode[int(code[i*5:i*5 + 5], 2)]
print(ans)
except:
break
``` | output | 1 | 91,617 | 18 | 183,235 |
Provide a correct Python 3 solution for this coding contest problem.
Dr .: Peter, I've finally done it.
Peter: What's wrong, Dr. David? Is it a silly invention again?
Dr .: This table, this table.
| Character | Sign
--- | ---
(Blank) | 101
'| 000000
, | 000011
-| 10010001
. | 010001
? | 000001
A | 100101
B | 10011010
| Character | Sign
--- | ---
C | 0101
D | 0001
E | 110
F | 01001
G | 10011011
H | 010000
I | 0111
J | 10011000
| Character | Sign
--- | ---
K | 0110
L | 00100
M | 10011001
N | 10011110
O | 00101
P | 111
Q | 10011111
R | 1000
| Character | Sign
--- | ---
S | 00110
T | 00111
U | 10011100
V | 10011101
W | 000010
X | 10010010
Y | 10010011
Z | 10010000
Peter: What? This table is.
Dr .: Okay, just do what you say. First, write your name on a piece of paper.
Peter: Yes, "PETER POTTER".
Dr .: Then, replace each character with the "code" in this table.
Peter: Well, change "P" to "111" and "E" to "110" ... It's quite annoying.
111 110 00111 110 1000 101 111 00101 00111 00111 110 1000
became. It looks like a barcode.
Dr .: All right. Then connect all the replaced strings and separate them by 5 characters.
Peter: Yes, if you connect and separate.
11111 00011 11101 00010 11110 01010 01110 01111 10100 0
It turned out to be something like this. But what about the last "0" guy?
Dr .: Add 0 to make it 5 letters.
Peter: Well, there is only one 0 at the end, so I should add four more 0s. I was able to do it.
11111 00011 11101 00010 11110 01010 01110 01111 10100 00000
Dr .: Next, use this table.
| Sign | Character
--- | ---
00000 | A
00001 | B
00010 | C
00011 | D
00100 | E
00101 | F
00110 | G
00111 | H
| Sign | Character
--- | ---
01000 | I
01001 | J
01010 | K
01011 | L
01100 | M
01101 | N
01110 | O
01111 | P
| Sign | Character
--- | ---
10000 | Q
10001 | R
10010 | S
10011 | T
10100 | U
10101 | V
10110 | W
10111 | X
| Sign | Character
--- | ---
11000 | Y
11001 | Z
11010 | (blank)
11011 | ..
11100 |,
11101 |-
11110 |'
11111 |?
Peter: How do you use this ... yeah! Now you're going to replace the code with a letter!
Dr .: That's right. If it is "11111", go to "?", If it is "00011", go to "D".
Peter: This is simple ... well, it became "? D-C'KOPUA". But it doesn't make sense.
Dr .: Count the number of characters.
Peter: It's 10 characters. Oh, "PETER POTTER" was 12 characters, but 2 characters are reduced.
Dr .: Yes, you can use this table to reduce the number of letters. Now do the same thing in this sentence.
PETER PIPER PICKED A PECK OF PICKLED PEPPERS. A PECK OF PICKLED PEPPERS
PETER PIPER PICKED. IF PETER PIPER PICKED A PECK OF PICKLED PEPPERS, WHERE'S
THE PECK OF PICKLED PEPPERS PETER PIPER PICKED?
Peter: Gyogyo, the lines are separated, what do you do?
Dr .: Due to space limitations, there are only 3 lines, but think of it as a long line with a space instead of a newline character.
Peter: Yes, yes. There is a blank space between the lines. But it's a hassle ...
Dr .: Then why not let the program do it?
So, instead of Peter, create a program that converts the read character string into a code and outputs it.
input
Given multiple datasets. Each dataset is given a line of strings (consisting of the characters contained in the table). The string contains at least 1 and no more than 100 characters.
The number of datasets does not exceed 200.
output
For each data set, output the converted character string on one line.
Example
Input
PETER POTTER
Output
?D-C'KOPUA | instruction | 0 | 91,618 | 18 | 183,236 |
"Correct Solution:
```
en=[chr(i) for i in range(65,91)]+list(' .,-\'?')
de={
' ':'101','\'':'000000',',':'000011','-':'10010001','.':'010001','?':'000001',
'A':'100101','B':'10011010','C':'0101','D':'0001','E':'110','F':'01001',
'G':'10011011','H':'010000','I':'0111','J':'10011000','K':'0110','L':'00100',
'M':'10011001','N':'10011110','O':'00101','P':'111','Q':'10011111','R':'1000',
'S':'00110','T':'00111','U':'10011100','V':'10011101','W':'000010','X':'10010010',
'Y':'10010011','Z':'10010000'
}
while 1:
try:s=list(input())
except:break
a=b=''
for x in s:a+=de[x]
a+='0'*(-len(a)%5)
for i in range(len(a)//5):
b+=en[int(a[i*5:i*5+5],2)]
print(b)
``` | output | 1 | 91,618 | 18 | 183,237 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dr .: Peter, I've finally done it.
Peter: What's wrong, Dr. David? Is it a silly invention again?
Dr .: This table, this table.
| Character | Sign
--- | ---
(Blank) | 101
'| 000000
, | 000011
-| 10010001
. | 010001
? | 000001
A | 100101
B | 10011010
| Character | Sign
--- | ---
C | 0101
D | 0001
E | 110
F | 01001
G | 10011011
H | 010000
I | 0111
J | 10011000
| Character | Sign
--- | ---
K | 0110
L | 00100
M | 10011001
N | 10011110
O | 00101
P | 111
Q | 10011111
R | 1000
| Character | Sign
--- | ---
S | 00110
T | 00111
U | 10011100
V | 10011101
W | 000010
X | 10010010
Y | 10010011
Z | 10010000
Peter: What? This table is.
Dr .: Okay, just do what you say. First, write your name on a piece of paper.
Peter: Yes, "PETER POTTER".
Dr .: Then, replace each character with the "code" in this table.
Peter: Well, change "P" to "111" and "E" to "110" ... It's quite annoying.
111 110 00111 110 1000 101 111 00101 00111 00111 110 1000
became. It looks like a barcode.
Dr .: All right. Then connect all the replaced strings and separate them by 5 characters.
Peter: Yes, if you connect and separate.
11111 00011 11101 00010 11110 01010 01110 01111 10100 0
It turned out to be something like this. But what about the last "0" guy?
Dr .: Add 0 to make it 5 letters.
Peter: Well, there is only one 0 at the end, so I should add four more 0s. I was able to do it.
11111 00011 11101 00010 11110 01010 01110 01111 10100 00000
Dr .: Next, use this table.
| Sign | Character
--- | ---
00000 | A
00001 | B
00010 | C
00011 | D
00100 | E
00101 | F
00110 | G
00111 | H
| Sign | Character
--- | ---
01000 | I
01001 | J
01010 | K
01011 | L
01100 | M
01101 | N
01110 | O
01111 | P
| Sign | Character
--- | ---
10000 | Q
10001 | R
10010 | S
10011 | T
10100 | U
10101 | V
10110 | W
10111 | X
| Sign | Character
--- | ---
11000 | Y
11001 | Z
11010 | (blank)
11011 | ..
11100 |,
11101 |-
11110 |'
11111 |?
Peter: How do you use this ... yeah! Now you're going to replace the code with a letter!
Dr .: That's right. If it is "11111", go to "?", If it is "00011", go to "D".
Peter: This is simple ... well, it became "? D-C'KOPUA". But it doesn't make sense.
Dr .: Count the number of characters.
Peter: It's 10 characters. Oh, "PETER POTTER" was 12 characters, but 2 characters are reduced.
Dr .: Yes, you can use this table to reduce the number of letters. Now do the same thing in this sentence.
PETER PIPER PICKED A PECK OF PICKLED PEPPERS. A PECK OF PICKLED PEPPERS
PETER PIPER PICKED. IF PETER PIPER PICKED A PECK OF PICKLED PEPPERS, WHERE'S
THE PECK OF PICKLED PEPPERS PETER PIPER PICKED?
Peter: Gyogyo, the lines are separated, what do you do?
Dr .: Due to space limitations, there are only 3 lines, but think of it as a long line with a space instead of a newline character.
Peter: Yes, yes. There is a blank space between the lines. But it's a hassle ...
Dr .: Then why not let the program do it?
So, instead of Peter, create a program that converts the read character string into a code and outputs it.
input
Given multiple datasets. Each dataset is given a line of strings (consisting of the characters contained in the table). The string contains at least 1 and no more than 100 characters.
The number of datasets does not exceed 200.
output
For each data set, output the converted character string on one line.
Example
Input
PETER POTTER
Output
?D-C'KOPUA
Submitted Solution:
```
# -*- coding: utf-8 -*-
"""
http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0088
"""
import sys
from sys import stdin
input = stdin.readline
def main(args):
encoder = {' ':'101', "'":'000000', ',':'000011', '-':'10010001', '.':'010001', '?':'000001', 'A':'100101', 'B':'10011010',
'C':'0101','D':'0001', 'E':'110', 'F':'01001', 'G':'10011011', 'H':'010000', 'I':'0111','J':'10011000',
'K':'0110', 'L':'00100', 'M':'10011001', 'N':'10011110', 'O':'00101', 'P':'111', 'Q':'10011111', 'R':'1000',
'S':'00110', 'T':'00111', 'U':'10011100', 'V':'10011101', 'W':'000010', 'X':'10010010', 'Y':'10010011', 'Z':'10010000'
}
decoder = {'00000':'A', '00001':'B', '00010':'C', '00011':'D', '00100':'E', '00101':'F', '00110':'G', '00111':'H',
'01000':'I', '01001':'J', '01010':'K', '01011':'L', '01100':'M', '01101':'N', '01110':'O', '01111':'P',
'10000':'Q', '10001':'R', '10010':'S', '10011':'T', '10100':'U', '10101':'V', '10110':'W', '10111':'X',
'11000':'Y', '11001':'Z', '11010':' ', '11011':'.', '11100':',', '11101':'-', '11110':"'", '11111':'?'
}
for line in sys.stdin:
txt = line.strip('\n')
ans = ''
for c in txt:
ans += encoder[c]
if len(ans) % 5 != 0:
ans += '0'*(5-len(ans)%5)
# print(ans)
result = ''
while ans:
temp = ans[:5]
result += decoder[temp]
ans = ans[5:]
print(result)
if __name__ == '__main__':
main(sys.argv[1:])
``` | instruction | 0 | 91,619 | 18 | 183,238 |
Yes | output | 1 | 91,619 | 18 | 183,239 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dr .: Peter, I've finally done it.
Peter: What's wrong, Dr. David? Is it a silly invention again?
Dr .: This table, this table.
| Character | Sign
--- | ---
(Blank) | 101
'| 000000
, | 000011
-| 10010001
. | 010001
? | 000001
A | 100101
B | 10011010
| Character | Sign
--- | ---
C | 0101
D | 0001
E | 110
F | 01001
G | 10011011
H | 010000
I | 0111
J | 10011000
| Character | Sign
--- | ---
K | 0110
L | 00100
M | 10011001
N | 10011110
O | 00101
P | 111
Q | 10011111
R | 1000
| Character | Sign
--- | ---
S | 00110
T | 00111
U | 10011100
V | 10011101
W | 000010
X | 10010010
Y | 10010011
Z | 10010000
Peter: What? This table is.
Dr .: Okay, just do what you say. First, write your name on a piece of paper.
Peter: Yes, "PETER POTTER".
Dr .: Then, replace each character with the "code" in this table.
Peter: Well, change "P" to "111" and "E" to "110" ... It's quite annoying.
111 110 00111 110 1000 101 111 00101 00111 00111 110 1000
became. It looks like a barcode.
Dr .: All right. Then connect all the replaced strings and separate them by 5 characters.
Peter: Yes, if you connect and separate.
11111 00011 11101 00010 11110 01010 01110 01111 10100 0
It turned out to be something like this. But what about the last "0" guy?
Dr .: Add 0 to make it 5 letters.
Peter: Well, there is only one 0 at the end, so I should add four more 0s. I was able to do it.
11111 00011 11101 00010 11110 01010 01110 01111 10100 00000
Dr .: Next, use this table.
| Sign | Character
--- | ---
00000 | A
00001 | B
00010 | C
00011 | D
00100 | E
00101 | F
00110 | G
00111 | H
| Sign | Character
--- | ---
01000 | I
01001 | J
01010 | K
01011 | L
01100 | M
01101 | N
01110 | O
01111 | P
| Sign | Character
--- | ---
10000 | Q
10001 | R
10010 | S
10011 | T
10100 | U
10101 | V
10110 | W
10111 | X
| Sign | Character
--- | ---
11000 | Y
11001 | Z
11010 | (blank)
11011 | ..
11100 |,
11101 |-
11110 |'
11111 |?
Peter: How do you use this ... yeah! Now you're going to replace the code with a letter!
Dr .: That's right. If it is "11111", go to "?", If it is "00011", go to "D".
Peter: This is simple ... well, it became "? D-C'KOPUA". But it doesn't make sense.
Dr .: Count the number of characters.
Peter: It's 10 characters. Oh, "PETER POTTER" was 12 characters, but 2 characters are reduced.
Dr .: Yes, you can use this table to reduce the number of letters. Now do the same thing in this sentence.
PETER PIPER PICKED A PECK OF PICKLED PEPPERS. A PECK OF PICKLED PEPPERS
PETER PIPER PICKED. IF PETER PIPER PICKED A PECK OF PICKLED PEPPERS, WHERE'S
THE PECK OF PICKLED PEPPERS PETER PIPER PICKED?
Peter: Gyogyo, the lines are separated, what do you do?
Dr .: Due to space limitations, there are only 3 lines, but think of it as a long line with a space instead of a newline character.
Peter: Yes, yes. There is a blank space between the lines. But it's a hassle ...
Dr .: Then why not let the program do it?
So, instead of Peter, create a program that converts the read character string into a code and outputs it.
input
Given multiple datasets. Each dataset is given a line of strings (consisting of the characters contained in the table). The string contains at least 1 and no more than 100 characters.
The number of datasets does not exceed 200.
output
For each data set, output the converted character string on one line.
Example
Input
PETER POTTER
Output
?D-C'KOPUA
Submitted Solution:
```
import sys
f = sys.stdin
k1 = {
" ":"101",
"'":"000000",
",":"000011",
"-":"10010001",
".":"010001",
"?":"000001",
"A":"100101",
"B":"10011010",
"C":"0101",
"D":"0001",
"E":"110",
"F":"01001",
"G":"10011011",
"H":"010000",
"I":"0111",
"J":"10011000",
"K":"0110",
"L":"00100",
"M":"10011001",
"N":"10011110",
"O":"00101",
"P":"111",
"Q":"10011111",
"R":"1000",
"S":"00110",
"T":"00111",
"U":"10011100",
"V":"10011101",
"W":"000010",
"X":"10010010",
"Y":"10010011",
"Z":"10010000"}
import string
k2 = string.ascii_uppercase + " .,-'?"
for line in f:
c1 = c2 = ''
for c in line.rstrip('\n'):
c1 += k1[c]
#5の倍数に0フィル
c1 += '0' * (- len(c1) % 5)
for i in range(0, len(c1),5):
c2 += k2[ int(c1[i:i + 5],2)]
print(c2)
``` | instruction | 0 | 91,620 | 18 | 183,240 |
Yes | output | 1 | 91,620 | 18 | 183,241 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dr .: Peter, I've finally done it.
Peter: What's wrong, Dr. David? Is it a silly invention again?
Dr .: This table, this table.
| Character | Sign
--- | ---
(Blank) | 101
'| 000000
, | 000011
-| 10010001
. | 010001
? | 000001
A | 100101
B | 10011010
| Character | Sign
--- | ---
C | 0101
D | 0001
E | 110
F | 01001
G | 10011011
H | 010000
I | 0111
J | 10011000
| Character | Sign
--- | ---
K | 0110
L | 00100
M | 10011001
N | 10011110
O | 00101
P | 111
Q | 10011111
R | 1000
| Character | Sign
--- | ---
S | 00110
T | 00111
U | 10011100
V | 10011101
W | 000010
X | 10010010
Y | 10010011
Z | 10010000
Peter: What? This table is.
Dr .: Okay, just do what you say. First, write your name on a piece of paper.
Peter: Yes, "PETER POTTER".
Dr .: Then, replace each character with the "code" in this table.
Peter: Well, change "P" to "111" and "E" to "110" ... It's quite annoying.
111 110 00111 110 1000 101 111 00101 00111 00111 110 1000
became. It looks like a barcode.
Dr .: All right. Then connect all the replaced strings and separate them by 5 characters.
Peter: Yes, if you connect and separate.
11111 00011 11101 00010 11110 01010 01110 01111 10100 0
It turned out to be something like this. But what about the last "0" guy?
Dr .: Add 0 to make it 5 letters.
Peter: Well, there is only one 0 at the end, so I should add four more 0s. I was able to do it.
11111 00011 11101 00010 11110 01010 01110 01111 10100 00000
Dr .: Next, use this table.
| Sign | Character
--- | ---
00000 | A
00001 | B
00010 | C
00011 | D
00100 | E
00101 | F
00110 | G
00111 | H
| Sign | Character
--- | ---
01000 | I
01001 | J
01010 | K
01011 | L
01100 | M
01101 | N
01110 | O
01111 | P
| Sign | Character
--- | ---
10000 | Q
10001 | R
10010 | S
10011 | T
10100 | U
10101 | V
10110 | W
10111 | X
| Sign | Character
--- | ---
11000 | Y
11001 | Z
11010 | (blank)
11011 | ..
11100 |,
11101 |-
11110 |'
11111 |?
Peter: How do you use this ... yeah! Now you're going to replace the code with a letter!
Dr .: That's right. If it is "11111", go to "?", If it is "00011", go to "D".
Peter: This is simple ... well, it became "? D-C'KOPUA". But it doesn't make sense.
Dr .: Count the number of characters.
Peter: It's 10 characters. Oh, "PETER POTTER" was 12 characters, but 2 characters are reduced.
Dr .: Yes, you can use this table to reduce the number of letters. Now do the same thing in this sentence.
PETER PIPER PICKED A PECK OF PICKLED PEPPERS. A PECK OF PICKLED PEPPERS
PETER PIPER PICKED. IF PETER PIPER PICKED A PECK OF PICKLED PEPPERS, WHERE'S
THE PECK OF PICKLED PEPPERS PETER PIPER PICKED?
Peter: Gyogyo, the lines are separated, what do you do?
Dr .: Due to space limitations, there are only 3 lines, but think of it as a long line with a space instead of a newline character.
Peter: Yes, yes. There is a blank space between the lines. But it's a hassle ...
Dr .: Then why not let the program do it?
So, instead of Peter, create a program that converts the read character string into a code and outputs it.
input
Given multiple datasets. Each dataset is given a line of strings (consisting of the characters contained in the table). The string contains at least 1 and no more than 100 characters.
The number of datasets does not exceed 200.
output
For each data set, output the converted character string on one line.
Example
Input
PETER POTTER
Output
?D-C'KOPUA
Submitted Solution:
```
def get_input():
while True:
try:
yield ''.join(input())
except EOFError:
break
dict1 = {"A":"00000",\
"B":"00001",\
"C":"00010",\
"D":"00011",\
"E":"00100",\
"F":"00101",\
"G":"00110", \
"H":"00111", \
"I":"01000", \
"J":"01001", \
"K":"01010", \
"L":"01011", \
"M":"01100", \
"N":"01101", \
"O":"01110", \
"P":"01111", \
"Q":"10000", \
"R":"10001", \
"S":"10010", \
"T":"10011", \
"U":"10100", \
"V":"10101", \
"W":"10110", \
"X":"10111", \
"Y":"11000", \
"Z":"11001", \
" ":"11010", \
".":"11011", \
",":"11100", \
"-":"11101", \
"'":"11110", \
"?":"11111"}
dict2 = {"101":" ",\
"000000":"'",\
"000011":",", \
"10010001":"-", \
"010001":".",\
"000001":"?",\
"100101":"A",\
"10011010":"B",\
"0101":"C",\
"0001":"D",\
"110":"E",\
"01001":"F",\
"10011011":"G",\
"010000":"H",\
"0111":"I",\
"10011000":"J",\
"0110":"K",\
"00100":"L",\
"10011001":"M",\
"10011110":"N",\
"00101":"O",\
"111":"P",\
"10011111":"Q",\
"1000":"R",\
"00110":"S",\
"00111":"T",\
"10011100":"U",\
"10011101":"V",\
"000010":"W",\
"10010010":"X",\
"10010011":"Y",\
"10010000":"Z"}
d1 = {v:k for k, v in dict1.items()}
d2 = {v:k for k, v in dict2.items()}
N = list(get_input())
for l in range(len(N)):
S1 = N[l]
S2 = ""
for i in range(len(S1)):
S2 = S2 + d2[S1[i]]
S3 = ""
while S2 != "":
if len(S2) >= 5:
s = S2[0:5]
S3 = S3 + d1[s]
S2 = S2[5:]
else:
while len(S2) < 5:
S2 = S2 + "0"
S3 = S3 + d1[S2]
break
print(S3)
``` | instruction | 0 | 91,621 | 18 | 183,242 |
Yes | output | 1 | 91,621 | 18 | 183,243 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dr .: Peter, I've finally done it.
Peter: What's wrong, Dr. David? Is it a silly invention again?
Dr .: This table, this table.
| Character | Sign
--- | ---
(Blank) | 101
'| 000000
, | 000011
-| 10010001
. | 010001
? | 000001
A | 100101
B | 10011010
| Character | Sign
--- | ---
C | 0101
D | 0001
E | 110
F | 01001
G | 10011011
H | 010000
I | 0111
J | 10011000
| Character | Sign
--- | ---
K | 0110
L | 00100
M | 10011001
N | 10011110
O | 00101
P | 111
Q | 10011111
R | 1000
| Character | Sign
--- | ---
S | 00110
T | 00111
U | 10011100
V | 10011101
W | 000010
X | 10010010
Y | 10010011
Z | 10010000
Peter: What? This table is.
Dr .: Okay, just do what you say. First, write your name on a piece of paper.
Peter: Yes, "PETER POTTER".
Dr .: Then, replace each character with the "code" in this table.
Peter: Well, change "P" to "111" and "E" to "110" ... It's quite annoying.
111 110 00111 110 1000 101 111 00101 00111 00111 110 1000
became. It looks like a barcode.
Dr .: All right. Then connect all the replaced strings and separate them by 5 characters.
Peter: Yes, if you connect and separate.
11111 00011 11101 00010 11110 01010 01110 01111 10100 0
It turned out to be something like this. But what about the last "0" guy?
Dr .: Add 0 to make it 5 letters.
Peter: Well, there is only one 0 at the end, so I should add four more 0s. I was able to do it.
11111 00011 11101 00010 11110 01010 01110 01111 10100 00000
Dr .: Next, use this table.
| Sign | Character
--- | ---
00000 | A
00001 | B
00010 | C
00011 | D
00100 | E
00101 | F
00110 | G
00111 | H
| Sign | Character
--- | ---
01000 | I
01001 | J
01010 | K
01011 | L
01100 | M
01101 | N
01110 | O
01111 | P
| Sign | Character
--- | ---
10000 | Q
10001 | R
10010 | S
10011 | T
10100 | U
10101 | V
10110 | W
10111 | X
| Sign | Character
--- | ---
11000 | Y
11001 | Z
11010 | (blank)
11011 | ..
11100 |,
11101 |-
11110 |'
11111 |?
Peter: How do you use this ... yeah! Now you're going to replace the code with a letter!
Dr .: That's right. If it is "11111", go to "?", If it is "00011", go to "D".
Peter: This is simple ... well, it became "? D-C'KOPUA". But it doesn't make sense.
Dr .: Count the number of characters.
Peter: It's 10 characters. Oh, "PETER POTTER" was 12 characters, but 2 characters are reduced.
Dr .: Yes, you can use this table to reduce the number of letters. Now do the same thing in this sentence.
PETER PIPER PICKED A PECK OF PICKLED PEPPERS. A PECK OF PICKLED PEPPERS
PETER PIPER PICKED. IF PETER PIPER PICKED A PECK OF PICKLED PEPPERS, WHERE'S
THE PECK OF PICKLED PEPPERS PETER PIPER PICKED?
Peter: Gyogyo, the lines are separated, what do you do?
Dr .: Due to space limitations, there are only 3 lines, but think of it as a long line with a space instead of a newline character.
Peter: Yes, yes. There is a blank space between the lines. But it's a hassle ...
Dr .: Then why not let the program do it?
So, instead of Peter, create a program that converts the read character string into a code and outputs it.
input
Given multiple datasets. Each dataset is given a line of strings (consisting of the characters contained in the table). The string contains at least 1 and no more than 100 characters.
The number of datasets does not exceed 200.
output
For each data set, output the converted character string on one line.
Example
Input
PETER POTTER
Output
?D-C'KOPUA
Submitted Solution:
```
en='ABCDEFGHIJKLMNOPQRSTUVWXYZ'+' .,-\'?'
de={
' ':'101','\'':'000000',',':'000011','-':'10010001','.':'010001','?':'000001',
'A':'100101','B':'10011010','C':'0101','D':'0001','E':'110','F':'01001',
'G':'10011011','H':'010000','I':'0111','J':'10011000','K':'0110','L':'00100',
'M':'10011001','N':'10011110','O':'00101','P':'111','Q':'10011111','R':'1000',
'S':'00110','T':'00111','U':'10011100','V':'10011101','W':'000010','X':'10010010',
'Y':'10010011','Z':'10010000'
}
while 1:
try:s=input()
except:break
a=b=''
for x in s:a+=de[x]
a+='0'*(-len(a)%5)
for i in range(len(a)//5):b+=en[int(a[i*5:i*5+5],2)]
print(b)
``` | instruction | 0 | 91,622 | 18 | 183,244 |
Yes | output | 1 | 91,622 | 18 | 183,245 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dr .: Peter, I've finally done it.
Peter: What's wrong, Dr. David? Is it a silly invention again?
Dr .: This table, this table.
| Character | Sign
--- | ---
(Blank) | 101
'| 000000
, | 000011
-| 10010001
. | 010001
? | 000001
A | 100101
B | 10011010
| Character | Sign
--- | ---
C | 0101
D | 0001
E | 110
F | 01001
G | 10011011
H | 010000
I | 0111
J | 10011000
| Character | Sign
--- | ---
K | 0110
L | 00100
M | 10011001
N | 10011110
O | 00101
P | 111
Q | 10011111
R | 1000
| Character | Sign
--- | ---
S | 00110
T | 00111
U | 10011100
V | 10011101
W | 000010
X | 10010010
Y | 10010011
Z | 10010000
Peter: What? This table is.
Dr .: Okay, just do what you say. First, write your name on a piece of paper.
Peter: Yes, "PETER POTTER".
Dr .: Then, replace each character with the "code" in this table.
Peter: Well, change "P" to "111" and "E" to "110" ... It's quite annoying.
111 110 00111 110 1000 101 111 00101 00111 00111 110 1000
became. It looks like a barcode.
Dr .: All right. Then connect all the replaced strings and separate them by 5 characters.
Peter: Yes, if you connect and separate.
11111 00011 11101 00010 11110 01010 01110 01111 10100 0
It turned out to be something like this. But what about the last "0" guy?
Dr .: Add 0 to make it 5 letters.
Peter: Well, there is only one 0 at the end, so I should add four more 0s. I was able to do it.
11111 00011 11101 00010 11110 01010 01110 01111 10100 00000
Dr .: Next, use this table.
| Sign | Character
--- | ---
00000 | A
00001 | B
00010 | C
00011 | D
00100 | E
00101 | F
00110 | G
00111 | H
| Sign | Character
--- | ---
01000 | I
01001 | J
01010 | K
01011 | L
01100 | M
01101 | N
01110 | O
01111 | P
| Sign | Character
--- | ---
10000 | Q
10001 | R
10010 | S
10011 | T
10100 | U
10101 | V
10110 | W
10111 | X
| Sign | Character
--- | ---
11000 | Y
11001 | Z
11010 | (blank)
11011 | ..
11100 |,
11101 |-
11110 |'
11111 |?
Peter: How do you use this ... yeah! Now you're going to replace the code with a letter!
Dr .: That's right. If it is "11111", go to "?", If it is "00011", go to "D".
Peter: This is simple ... well, it became "? D-C'KOPUA". But it doesn't make sense.
Dr .: Count the number of characters.
Peter: It's 10 characters. Oh, "PETER POTTER" was 12 characters, but 2 characters are reduced.
Dr .: Yes, you can use this table to reduce the number of letters. Now do the same thing in this sentence.
PETER PIPER PICKED A PECK OF PICKLED PEPPERS. A PECK OF PICKLED PEPPERS
PETER PIPER PICKED. IF PETER PIPER PICKED A PECK OF PICKLED PEPPERS, WHERE'S
THE PECK OF PICKLED PEPPERS PETER PIPER PICKED?
Peter: Gyogyo, the lines are separated, what do you do?
Dr .: Due to space limitations, there are only 3 lines, but think of it as a long line with a space instead of a newline character.
Peter: Yes, yes. There is a blank space between the lines. But it's a hassle ...
Dr .: Then why not let the program do it?
So, instead of Peter, create a program that converts the read character string into a code and outputs it.
input
Given multiple datasets. Each dataset is given a line of strings (consisting of the characters contained in the table). The string contains at least 1 and no more than 100 characters.
The number of datasets does not exceed 200.
output
For each data set, output the converted character string on one line.
Example
Input
PETER POTTER
Output
?D-C'KOPUA
Submitted Solution:
```
# -*- coding: utf-8 -*-
import sys
import os
import math
d1 = {
' ': '101'
, '\'': '000000'
, ',': '000011'
, '-': '10010001'
, '.': '010001'
, '?': '000001'
, 'A': '100101'
, 'B': '10011010'
, 'C': '0101'
, 'D': '0001'
, 'E': '110'
, 'F': '01001'
, 'G': '10011011'
, 'H': '010000'
, 'I': '0111'
, 'J': '10011000'
, 'K': '0110'
, 'L': '00100'
, 'M': '10011001'
, 'N': '10011110'
, 'O': '00101'
, 'P': '111'
, 'Q': '10011111'
, 'R': '1000'
, 'S': '00110'
, 'T': '00111'
, 'U': '10011100'
, 'V': '10011101'
, 'W': '000010'
, 'X': '10010010'
, 'Y': '10010011'
, 'Z': '10010000'
}
d2 = {
'00000': 'A'
, '00001': 'B'
, '00010': 'C'
, '00011': 'D'
, '00100': 'E'
, '00101': 'F'
, '00110': 'G'
, '00111': 'H'
, '01000': 'I'
, '01001': 'J'
, '01010': 'K'
, '01011': 'L'
, '01100': 'M'
, '01101': 'N'
, '01110': 'O'
, '01111': 'P'
, '10000': 'Q'
, '10001': 'R'
, '10010': 'S'
, '10011': 'T'
, '10100': 'U'
, '10101': 'V'
, '10110': 'W'
, '10111': 'X'
, '11000': 'Y'
, '11001': 'Z'
, '11010': ' '
, '11011': '.'
, '11100': ','
, '11101': '-'
, '11110': '\''
, '11111': '?'
}
S = ''
for s in sys.stdin:
s = s.rstrip('\n')
S += s + ' '
S = S[:-1]
T = ''
for c in S:
T += d1[c]
# zero addition
if len(T) % 5 != 0:
add_zero_num = 5 - len(T) % 5
T += '0' * add_zero_num
U = ''
for i in range(0, len(T), 5):
binary = T[i:i+5]
U += d2[binary]
print(U)
``` | instruction | 0 | 91,623 | 18 | 183,246 |
No | output | 1 | 91,623 | 18 | 183,247 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dr .: Peter, I've finally done it.
Peter: What's wrong, Dr. David? Is it a silly invention again?
Dr .: This table, this table.
| Character | Sign
--- | ---
(Blank) | 101
'| 000000
, | 000011
-| 10010001
. | 010001
? | 000001
A | 100101
B | 10011010
| Character | Sign
--- | ---
C | 0101
D | 0001
E | 110
F | 01001
G | 10011011
H | 010000
I | 0111
J | 10011000
| Character | Sign
--- | ---
K | 0110
L | 00100
M | 10011001
N | 10011110
O | 00101
P | 111
Q | 10011111
R | 1000
| Character | Sign
--- | ---
S | 00110
T | 00111
U | 10011100
V | 10011101
W | 000010
X | 10010010
Y | 10010011
Z | 10010000
Peter: What? This table is.
Dr .: Okay, just do what you say. First, write your name on a piece of paper.
Peter: Yes, "PETER POTTER".
Dr .: Then, replace each character with the "code" in this table.
Peter: Well, change "P" to "111" and "E" to "110" ... It's quite annoying.
111 110 00111 110 1000 101 111 00101 00111 00111 110 1000
became. It looks like a barcode.
Dr .: All right. Then connect all the replaced strings and separate them by 5 characters.
Peter: Yes, if you connect and separate.
11111 00011 11101 00010 11110 01010 01110 01111 10100 0
It turned out to be something like this. But what about the last "0" guy?
Dr .: Add 0 to make it 5 letters.
Peter: Well, there is only one 0 at the end, so I should add four more 0s. I was able to do it.
11111 00011 11101 00010 11110 01010 01110 01111 10100 00000
Dr .: Next, use this table.
| Sign | Character
--- | ---
00000 | A
00001 | B
00010 | C
00011 | D
00100 | E
00101 | F
00110 | G
00111 | H
| Sign | Character
--- | ---
01000 | I
01001 | J
01010 | K
01011 | L
01100 | M
01101 | N
01110 | O
01111 | P
| Sign | Character
--- | ---
10000 | Q
10001 | R
10010 | S
10011 | T
10100 | U
10101 | V
10110 | W
10111 | X
| Sign | Character
--- | ---
11000 | Y
11001 | Z
11010 | (blank)
11011 | ..
11100 |,
11101 |-
11110 |'
11111 |?
Peter: How do you use this ... yeah! Now you're going to replace the code with a letter!
Dr .: That's right. If it is "11111", go to "?", If it is "00011", go to "D".
Peter: This is simple ... well, it became "? D-C'KOPUA". But it doesn't make sense.
Dr .: Count the number of characters.
Peter: It's 10 characters. Oh, "PETER POTTER" was 12 characters, but 2 characters are reduced.
Dr .: Yes, you can use this table to reduce the number of letters. Now do the same thing in this sentence.
PETER PIPER PICKED A PECK OF PICKLED PEPPERS. A PECK OF PICKLED PEPPERS
PETER PIPER PICKED. IF PETER PIPER PICKED A PECK OF PICKLED PEPPERS, WHERE'S
THE PECK OF PICKLED PEPPERS PETER PIPER PICKED?
Peter: Gyogyo, the lines are separated, what do you do?
Dr .: Due to space limitations, there are only 3 lines, but think of it as a long line with a space instead of a newline character.
Peter: Yes, yes. There is a blank space between the lines. But it's a hassle ...
Dr .: Then why not let the program do it?
So, instead of Peter, create a program that converts the read character string into a code and outputs it.
input
Given multiple datasets. Each dataset is given a line of strings (consisting of the characters contained in the table). The string contains at least 1 and no more than 100 characters.
The number of datasets does not exceed 200.
output
For each data set, output the converted character string on one line.
Example
Input
PETER POTTER
Output
?D-C'KOPUA
Submitted Solution:
```
dic1 = {" ":"101", "'":"000000", ",":"000011", "-":"10010001", "?":"000001",
"A":"100101", "B":"10011010", "C":"0101", "D":"0101", "E":"110",
"F":"01001", "G":"10011011", "H":"010000", "I":"0111", "J":"10011000",
"K":"0110", "L":"00100", "M":"10011001", "N":"10011110", "O":"00101",
"P":"111", "Q":"10011111", "R":"1000", "S":"00110", "T":"00111",
"U":"10011100", "V":"10011101", "W":"000010", "X":"10010010", "Y":"10010011", "Z":"10010000"}
dic2 = {"00000":"A", "00001":"B", "00010":"C", "00011":"D", "00100":"E",
"00101":"F", "00110":"G", "00111":"H", "01000":"I", "01001":"J",
"01010":"K", "01011":"L", "01100":"M", "01101":"N", "01110":"O",
"01111":"P", "10000":"Q", "10001":"R", "10010":"S", "10011":"T",
"10100":"U", "10101":"V", "10110":"W", "10111":"X", "11000":"Y",
"11001":"Z", "11010":" ", "11011":".", "11100":",", "11101":"-",
"11110":"'", "11111":"?"}
def to_digit(ss):
ret = ""
for s in ss:
ret += dic1[s]
return ret
def to_alpha(digit):
ret = ""
ind = 0
end = len(digit)
while ind + 5 < end:
ret += dic2[digit[ind:ind + 5]]
ind += 5
if digit[ind:]:
ret += dic2[digit[ind:] + "0" * (5 - end + ind)]
return ret
while True:
try:
ss = input()
print(to_alpha(to_digit(ss)))
except EOFError:
break
``` | instruction | 0 | 91,624 | 18 | 183,248 |
No | output | 1 | 91,624 | 18 | 183,249 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dr .: Peter, I've finally done it.
Peter: What's wrong, Dr. David? Is it a silly invention again?
Dr .: This table, this table.
| Character | Sign
--- | ---
(Blank) | 101
'| 000000
, | 000011
-| 10010001
. | 010001
? | 000001
A | 100101
B | 10011010
| Character | Sign
--- | ---
C | 0101
D | 0001
E | 110
F | 01001
G | 10011011
H | 010000
I | 0111
J | 10011000
| Character | Sign
--- | ---
K | 0110
L | 00100
M | 10011001
N | 10011110
O | 00101
P | 111
Q | 10011111
R | 1000
| Character | Sign
--- | ---
S | 00110
T | 00111
U | 10011100
V | 10011101
W | 000010
X | 10010010
Y | 10010011
Z | 10010000
Peter: What? This table is.
Dr .: Okay, just do what you say. First, write your name on a piece of paper.
Peter: Yes, "PETER POTTER".
Dr .: Then, replace each character with the "code" in this table.
Peter: Well, change "P" to "111" and "E" to "110" ... It's quite annoying.
111 110 00111 110 1000 101 111 00101 00111 00111 110 1000
became. It looks like a barcode.
Dr .: All right. Then connect all the replaced strings and separate them by 5 characters.
Peter: Yes, if you connect and separate.
11111 00011 11101 00010 11110 01010 01110 01111 10100 0
It turned out to be something like this. But what about the last "0" guy?
Dr .: Add 0 to make it 5 letters.
Peter: Well, there is only one 0 at the end, so I should add four more 0s. I was able to do it.
11111 00011 11101 00010 11110 01010 01110 01111 10100 00000
Dr .: Next, use this table.
| Sign | Character
--- | ---
00000 | A
00001 | B
00010 | C
00011 | D
00100 | E
00101 | F
00110 | G
00111 | H
| Sign | Character
--- | ---
01000 | I
01001 | J
01010 | K
01011 | L
01100 | M
01101 | N
01110 | O
01111 | P
| Sign | Character
--- | ---
10000 | Q
10001 | R
10010 | S
10011 | T
10100 | U
10101 | V
10110 | W
10111 | X
| Sign | Character
--- | ---
11000 | Y
11001 | Z
11010 | (blank)
11011 | ..
11100 |,
11101 |-
11110 |'
11111 |?
Peter: How do you use this ... yeah! Now you're going to replace the code with a letter!
Dr .: That's right. If it is "11111", go to "?", If it is "00011", go to "D".
Peter: This is simple ... well, it became "? D-C'KOPUA". But it doesn't make sense.
Dr .: Count the number of characters.
Peter: It's 10 characters. Oh, "PETER POTTER" was 12 characters, but 2 characters are reduced.
Dr .: Yes, you can use this table to reduce the number of letters. Now do the same thing in this sentence.
PETER PIPER PICKED A PECK OF PICKLED PEPPERS. A PECK OF PICKLED PEPPERS
PETER PIPER PICKED. IF PETER PIPER PICKED A PECK OF PICKLED PEPPERS, WHERE'S
THE PECK OF PICKLED PEPPERS PETER PIPER PICKED?
Peter: Gyogyo, the lines are separated, what do you do?
Dr .: Due to space limitations, there are only 3 lines, but think of it as a long line with a space instead of a newline character.
Peter: Yes, yes. There is a blank space between the lines. But it's a hassle ...
Dr .: Then why not let the program do it?
So, instead of Peter, create a program that converts the read character string into a code and outputs it.
input
Given multiple datasets. Each dataset is given a line of strings (consisting of the characters contained in the table). The string contains at least 1 and no more than 100 characters.
The number of datasets does not exceed 200.
output
For each data set, output the converted character string on one line.
Example
Input
PETER POTTER
Output
?D-C'KOPUA
Submitted Solution:
```
en=[chr(i) for i in range(65,91)]+list(' .,-\'?')
de={
' ':'101'
,'\'':'000000'
,',':'000011'
,'-':'10010001'
,'.':'010001'
,'?':'000001'
,'A':'100101'
,'B':'10011010'
,'C':'0101'
,'D':'0001'
,'E':'110'
,'F':'01001'
,'G':'10011011'
,'H':'010000'
,'I':'0111'
,'J':'10011000'
,'K':'0110'
,'L':'00100'
,'M':'10011001'
,'N':'10011110'
,'O':'00101'
,'P':'111'
,'Q':'10011111'
,'R':'1000'
,'S':'00110'
,'T':'00111'
,'U':'10011100'
,'V':'10011101'
,'W':'000010'
,'X':'10010010'
,'Y':'10010011'
,'Z':'10010000'
}
a=b=''
for x in list(input()):
a+=de[x]
a+='0'*(-len(a)%5)
for i in range(len(a)//5):
b+=en[int(a[i*5:(i+1)*5],2)]
print(b)
``` | instruction | 0 | 91,625 | 18 | 183,250 |
No | output | 1 | 91,625 | 18 | 183,251 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dr .: Peter, I've finally done it.
Peter: What's wrong, Dr. David? Is it a silly invention again?
Dr .: This table, this table.
| Character | Sign
--- | ---
(Blank) | 101
'| 000000
, | 000011
-| 10010001
. | 010001
? | 000001
A | 100101
B | 10011010
| Character | Sign
--- | ---
C | 0101
D | 0001
E | 110
F | 01001
G | 10011011
H | 010000
I | 0111
J | 10011000
| Character | Sign
--- | ---
K | 0110
L | 00100
M | 10011001
N | 10011110
O | 00101
P | 111
Q | 10011111
R | 1000
| Character | Sign
--- | ---
S | 00110
T | 00111
U | 10011100
V | 10011101
W | 000010
X | 10010010
Y | 10010011
Z | 10010000
Peter: What? This table is.
Dr .: Okay, just do what you say. First, write your name on a piece of paper.
Peter: Yes, "PETER POTTER".
Dr .: Then, replace each character with the "code" in this table.
Peter: Well, change "P" to "111" and "E" to "110" ... It's quite annoying.
111 110 00111 110 1000 101 111 00101 00111 00111 110 1000
became. It looks like a barcode.
Dr .: All right. Then connect all the replaced strings and separate them by 5 characters.
Peter: Yes, if you connect and separate.
11111 00011 11101 00010 11110 01010 01110 01111 10100 0
It turned out to be something like this. But what about the last "0" guy?
Dr .: Add 0 to make it 5 letters.
Peter: Well, there is only one 0 at the end, so I should add four more 0s. I was able to do it.
11111 00011 11101 00010 11110 01010 01110 01111 10100 00000
Dr .: Next, use this table.
| Sign | Character
--- | ---
00000 | A
00001 | B
00010 | C
00011 | D
00100 | E
00101 | F
00110 | G
00111 | H
| Sign | Character
--- | ---
01000 | I
01001 | J
01010 | K
01011 | L
01100 | M
01101 | N
01110 | O
01111 | P
| Sign | Character
--- | ---
10000 | Q
10001 | R
10010 | S
10011 | T
10100 | U
10101 | V
10110 | W
10111 | X
| Sign | Character
--- | ---
11000 | Y
11001 | Z
11010 | (blank)
11011 | ..
11100 |,
11101 |-
11110 |'
11111 |?
Peter: How do you use this ... yeah! Now you're going to replace the code with a letter!
Dr .: That's right. If it is "11111", go to "?", If it is "00011", go to "D".
Peter: This is simple ... well, it became "? D-C'KOPUA". But it doesn't make sense.
Dr .: Count the number of characters.
Peter: It's 10 characters. Oh, "PETER POTTER" was 12 characters, but 2 characters are reduced.
Dr .: Yes, you can use this table to reduce the number of letters. Now do the same thing in this sentence.
PETER PIPER PICKED A PECK OF PICKLED PEPPERS. A PECK OF PICKLED PEPPERS
PETER PIPER PICKED. IF PETER PIPER PICKED A PECK OF PICKLED PEPPERS, WHERE'S
THE PECK OF PICKLED PEPPERS PETER PIPER PICKED?
Peter: Gyogyo, the lines are separated, what do you do?
Dr .: Due to space limitations, there are only 3 lines, but think of it as a long line with a space instead of a newline character.
Peter: Yes, yes. There is a blank space between the lines. But it's a hassle ...
Dr .: Then why not let the program do it?
So, instead of Peter, create a program that converts the read character string into a code and outputs it.
input
Given multiple datasets. Each dataset is given a line of strings (consisting of the characters contained in the table). The string contains at least 1 and no more than 100 characters.
The number of datasets does not exceed 200.
output
For each data set, output the converted character string on one line.
Example
Input
PETER POTTER
Output
?D-C'KOPUA
Submitted Solution:
```
en=[chr(i) for i in range(65,91)]+list(' .,-\'?')
de={
' ':'101','\'':'000000',',':'000011','-':'10010001','.':'010001','?':'000001',
'A':'100101','B':'10011010','C':'0101','D':'0001','E':'110','F':'01001',
'G':'10011011','H':'010000','I':'0111','J':'10011000','K':'0110','L':'00100',
'M':'10011001','N':'10011110','O':'00101','P':'111','Q':'10011111','R':'1000',
'S':'00110','T':'00111','U':'10011100','V':'10011101','W':'000010','X':'10010010',
'Y':'10010011','Z':'10010000'}
a=''
for x in list(input()):
a+=de[x]
a+='0'*(-len(a)%5)
for i in range(0,len(a),5):
print(en[int(a[i:i+5],2)],end='')
print()
``` | instruction | 0 | 91,626 | 18 | 183,252 |
No | output | 1 | 91,626 | 18 | 183,253 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi loves palindromes. Non-palindromic strings are unacceptable to him. Each time he hugs a string, he can change one of its characters to any character of his choice.
Given is a string S. Find the minimum number of hugs needed to make S palindromic.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Print the minimum number of hugs needed to make S palindromic.
Examples
Input
redcoder
Output
1
Input
vvvvvv
Output
0
Input
abcdabc
Output
2
Submitted Solution:
```
s = input()
l = sum(x != y for x,y in zip(s,s[::-1]))
print((l+1)//2)
``` | instruction | 0 | 92,425 | 18 | 184,850 |
Yes | output | 1 | 92,425 | 18 | 184,851 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi loves palindromes. Non-palindromic strings are unacceptable to him. Each time he hugs a string, he can change one of its characters to any character of his choice.
Given is a string S. Find the minimum number of hugs needed to make S palindromic.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Print the minimum number of hugs needed to make S palindromic.
Examples
Input
redcoder
Output
1
Input
vvvvvv
Output
0
Input
abcdabc
Output
2
Submitted Solution:
```
s=input();print(sum(a>b for a,b in zip(s,s[::-1])))
``` | instruction | 0 | 92,426 | 18 | 184,852 |
Yes | output | 1 | 92,426 | 18 | 184,853 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi loves palindromes. Non-palindromic strings are unacceptable to him. Each time he hugs a string, he can change one of its characters to any character of his choice.
Given is a string S. Find the minimum number of hugs needed to make S palindromic.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Print the minimum number of hugs needed to make S palindromic.
Examples
Input
redcoder
Output
1
Input
vvvvvv
Output
0
Input
abcdabc
Output
2
Submitted Solution:
```
s=input()
l=len(s)
ans=0
for i in range(l//2):
if s[i]!=s[-(i+1)]:
ans+=1
print(ans)
``` | instruction | 0 | 92,427 | 18 | 184,854 |
Yes | output | 1 | 92,427 | 18 | 184,855 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi loves palindromes. Non-palindromic strings are unacceptable to him. Each time he hugs a string, he can change one of its characters to any character of his choice.
Given is a string S. Find the minimum number of hugs needed to make S palindromic.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Print the minimum number of hugs needed to make S palindromic.
Examples
Input
redcoder
Output
1
Input
vvvvvv
Output
0
Input
abcdabc
Output
2
Submitted Solution:
```
S = input()
print(sum([S[i] != S[-i-1] for i in range(len(S)//2)]))
``` | instruction | 0 | 92,428 | 18 | 184,856 |
Yes | output | 1 | 92,428 | 18 | 184,857 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi loves palindromes. Non-palindromic strings are unacceptable to him. Each time he hugs a string, he can change one of its characters to any character of his choice.
Given is a string S. Find the minimum number of hugs needed to make S palindromic.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Print the minimum number of hugs needed to make S palindromic.
Examples
Input
redcoder
Output
1
Input
vvvvvv
Output
0
Input
abcdabc
Output
2
Submitted Solution:
```
s = input()
p = len(s)
q = p-1
qq = q%2
ss = list(s)
r=0
if qq == 1:
for i in range(0,q+1/2):
if ss[i] != ss[q-i]:
ss[i] = ss[q-i]
r= r+1
elif qq == 0:
for i in range(0,q//2):
if ss[i] != ss[q-i]:
ss[i] = ss[q-i]
r = r+1
print(r)
``` | instruction | 0 | 92,429 | 18 | 184,858 |
No | output | 1 | 92,429 | 18 | 184,859 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi loves palindromes. Non-palindromic strings are unacceptable to him. Each time he hugs a string, he can change one of its characters to any character of his choice.
Given is a string S. Find the minimum number of hugs needed to make S palindromic.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Print the minimum number of hugs needed to make S palindromic.
Examples
Input
redcoder
Output
1
Input
vvvvvv
Output
0
Input
abcdabc
Output
2
Submitted Solution:
```
s = input()
s2 = list(reversed(s))
ans = 0
for i in range(len(s)):
if s[i] != s2[i]:
ans += 1
if (len(s) % 2 == 0 and i == int(len(s) / 2)):
ans -= 1
print(ans)
``` | instruction | 0 | 92,430 | 18 | 184,860 |
No | output | 1 | 92,430 | 18 | 184,861 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi loves palindromes. Non-palindromic strings are unacceptable to him. Each time he hugs a string, he can change one of its characters to any character of his choice.
Given is a string S. Find the minimum number of hugs needed to make S palindromic.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Print the minimum number of hugs needed to make S palindromic.
Examples
Input
redcoder
Output
1
Input
vvvvvv
Output
0
Input
abcdabc
Output
2
Submitted Solution:
```
s=input()
n=len(s)
sum=0
for i in range(n):
if s(i)!=s(n-i):
sum+=1
print(sum//2)
``` | instruction | 0 | 92,431 | 18 | 184,862 |
No | output | 1 | 92,431 | 18 | 184,863 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi loves palindromes. Non-palindromic strings are unacceptable to him. Each time he hugs a string, he can change one of its characters to any character of his choice.
Given is a string S. Find the minimum number of hugs needed to make S palindromic.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Print the minimum number of hugs needed to make S palindromic.
Examples
Input
redcoder
Output
1
Input
vvvvvv
Output
0
Input
abcdabc
Output
2
Submitted Solution:
```
s = list(input())
l = len(s)
m = l//2
h = 0
count=0
if l%2!=0:
h = 1
for i in range(m):
if s[i]!=s[m+i+h]:
count+=1
print(count)
``` | instruction | 0 | 92,432 | 18 | 184,864 |
No | output | 1 | 92,432 | 18 | 184,865 |
Provide a correct Python 3 solution for this coding contest problem.
Example
Input
mmemewwemeww
Output
Cat | instruction | 0 | 92,570 | 18 | 185,140 |
"Correct Solution:
```
import re
b=s=input()
while 1:
s=re.sub(r'(m|e)mew(e|w)','\\1\\2',s)
if b==s:break
b=s
print(['Rabbit','Cat'][s=='mew'])
``` | output | 1 | 92,570 | 18 | 185,141 |
Provide a correct Python 3 solution for this coding contest problem.
Example
Input
mmemewwemeww
Output
Cat | instruction | 0 | 92,571 | 18 | 185,142 |
"Correct Solution:
```
S = input()
L = len(S)
dp = [[False] * (L + 1) for _ in range(L + 1)]
# [left, right)
for i in range(L + 1):
dp[i][i] = True
for w in range(3, L + 1):
for left in range(L - w + 1):
right = left + w
if S[left] != 'm' or S[right - 1] != 'w':
continue
for mid in range(left + 1, right):
if S[mid] == 'e' and dp[left + 1][mid] and dp[mid + 1][right - 1]:
dp[left][right] = True
break
print("Cat" if dp[0][L] else "Rabbit")
``` | output | 1 | 92,571 | 18 | 185,143 |
Provide a correct Python 3 solution for this coding contest problem.
Example
Input
mmemewwemeww
Output
Cat | instruction | 0 | 92,572 | 18 | 185,144 |
"Correct Solution:
```
import re
s=input()
while s!=re.sub(r'(m|e)mew(e|w)','\\1\\2',s):s=re.sub(r'(m|e)mew(e|w)','\\1\\2',s)
print(['Rabbit','Cat'][s=='mew'])
``` | output | 1 | 92,572 | 18 | 185,145 |
Provide a correct Python 3 solution for this coding contest problem.
Example
Input
mmemewwemeww
Output
Cat | instruction | 0 | 92,573 | 18 | 185,146 |
"Correct Solution:
```
s = input()
tmp = s
while True:
s = s.replace("mew", "Y")
s = s.replace("mXeXw", "Y")
s = s.replace("meXw", "Y")
s = s.replace("mXew", "Y")
s = s.replace("Y", "X")
if s == tmp:
if s == "X" or s == "":
print("Cat")
else:
print("Rabbit")
break
tmp = s
``` | output | 1 | 92,573 | 18 | 185,147 |
Provide a correct Python 3 solution for this coding contest problem.
Example
Input
mmemewwemeww
Output
Cat | instruction | 0 | 92,574 | 18 | 185,148 |
"Correct Solution:
```
S = input()
L = len(S)
dp = [[False] * (L + 1) for _ in range(L + 1)]
# [left, right)
for i in range(L + 1):
dp[i][i] = True
for w in range(3, L + 1, 3):
for left in range(L - w + 1):
right = left + w
if S[left] != 'm' or S[right - 1] != 'w':
continue
for mid in range(left + 1, right):
if S[mid] == 'e' and dp[left + 1][mid] and dp[mid + 1][right - 1]:
dp[left][right] = True
break
print("Cat" if dp[0][L] else "Rabbit")
``` | output | 1 | 92,574 | 18 | 185,149 |
Provide a correct Python 3 solution for this coding contest problem.
Example
Input
mmemewwemeww
Output
Cat | instruction | 0 | 92,577 | 18 | 185,154 |
"Correct Solution:
```
inf = 1000000007
def check(roar,i):
if roar[i]!='m':return inf
i+=1
if roar[i]=='e':i+=1
else :
j = check(roar,i)
if j==inf:return inf
i = j+1
if roar[i]=='w':i+=1
else :
j = check(roar,i)
if j==inf:return inf
i = j+1
return i
def main():
roar = input()
if check(roar,0)==len(roar):print ('Cat')
else :print ('Rabbit')
if __name__ == '__main__':
main()
``` | output | 1 | 92,577 | 18 | 185,155 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Example
Input
mmemewwemeww
Output
Cat
Submitted Solution:
```
#include <bits/stdc++.h>
using namespace std;
int main(void) {
string s;
cin >> s;
bool isCat = false;
while (true) {
if (s == "mew") {
isCat = true;
break;
}
string buf_s = s;
s = regex_replace(s, regex("mmewe"), "me");
s = regex_replace(s, regex("emeww"), "ew");
if (buf_s == s) break;
}
if (isCat)
cout << "Cat" << endl;
else
cout << "Rabbit" << endl;
return 0;
}
``` | instruction | 0 | 92,578 | 18 | 185,156 |
No | output | 1 | 92,578 | 18 | 185,157 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Example
Input
mmemewwemeww
Output
Cat
Submitted Solution:
```
# -*- coding: utf-8 -*-
def inpl(): return list(map(int, input().split()))
S0 = input()
while S0:
S = S0.replace("mew", "*")
S = S.replace("m*ew", "*")
S = S.replace("me*w", "*")
S = S.replace("m*e*w", "*")
if S=="*":
print("Cat")
break
if S == S0:
print("Rabit")
break
S0 = S
else:
print("Rabit")
``` | instruction | 0 | 92,579 | 18 | 185,158 |
No | output | 1 | 92,579 | 18 | 185,159 |
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