message stringlengths 2 11.9k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 137 108k | cluster float64 18 18 | __index_level_0__ int64 274 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
HQ9+ is a joke programming language which has only four one-character instructions:
* "H" prints "Hello, World!",
* "Q" prints the source code of the program itself,
* "9" prints the lyrics of "99 Bottles of Beer" song,
* "+" increments the value stored in the internal accumulator.
Instructions "H" and "Q" are case-sensitive and must be uppercase. The characters of the program which are not instructions are ignored.
You are given a program written in HQ9+. You have to figure out whether executing this program will produce any output.
Input
The input will consist of a single line p which will give a program in HQ9+. String p will contain between 1 and 100 characters, inclusive. ASCII-code of each character of p will be between 33 (exclamation mark) and 126 (tilde), inclusive.
Output
Output "YES", if executing the program will produce any output, and "NO" otherwise.
Examples
Input
Hi!
Output
YES
Input
Codeforces
Output
NO
Note
In the first case the program contains only one instruction — "H", which prints "Hello, World!".
In the second case none of the program characters are language instructions.
Submitted Solution:
```
#Kinda difficile??
j = 1
word = input()
for i in word:
if i == "H":
print("YES")
break
elif i == "Q":
print("YES")
break
elif i == "9":
print("YES")
break
while j == len(word) :
if word[len(word)-1] != "H":
print("NO")
break
elif word[len(word)-1] != "Q":
print("NO")
break
elif word[len(word)-1] != "9":
print("NO")
break
j += 1
``` | instruction | 0 | 96,268 | 18 | 192,536 |
Yes | output | 1 | 96,268 | 18 | 192,537 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
HQ9+ is a joke programming language which has only four one-character instructions:
* "H" prints "Hello, World!",
* "Q" prints the source code of the program itself,
* "9" prints the lyrics of "99 Bottles of Beer" song,
* "+" increments the value stored in the internal accumulator.
Instructions "H" and "Q" are case-sensitive and must be uppercase. The characters of the program which are not instructions are ignored.
You are given a program written in HQ9+. You have to figure out whether executing this program will produce any output.
Input
The input will consist of a single line p which will give a program in HQ9+. String p will contain between 1 and 100 characters, inclusive. ASCII-code of each character of p will be between 33 (exclamation mark) and 126 (tilde), inclusive.
Output
Output "YES", if executing the program will produce any output, and "NO" otherwise.
Examples
Input
Hi!
Output
YES
Input
Codeforces
Output
NO
Note
In the first case the program contains only one instruction — "H", which prints "Hello, World!".
In the second case none of the program characters are language instructions.
Submitted Solution:
```
x=input()
if ('H' in x) or ('Q' in x) or ('9' in x):
print("YES")
else:
print("NO")
``` | instruction | 0 | 96,269 | 18 | 192,538 |
Yes | output | 1 | 96,269 | 18 | 192,539 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
HQ9+ is a joke programming language which has only four one-character instructions:
* "H" prints "Hello, World!",
* "Q" prints the source code of the program itself,
* "9" prints the lyrics of "99 Bottles of Beer" song,
* "+" increments the value stored in the internal accumulator.
Instructions "H" and "Q" are case-sensitive and must be uppercase. The characters of the program which are not instructions are ignored.
You are given a program written in HQ9+. You have to figure out whether executing this program will produce any output.
Input
The input will consist of a single line p which will give a program in HQ9+. String p will contain between 1 and 100 characters, inclusive. ASCII-code of each character of p will be between 33 (exclamation mark) and 126 (tilde), inclusive.
Output
Output "YES", if executing the program will produce any output, and "NO" otherwise.
Examples
Input
Hi!
Output
YES
Input
Codeforces
Output
NO
Note
In the first case the program contains only one instruction — "H", which prints "Hello, World!".
In the second case none of the program characters are language instructions.
Submitted Solution:
```
n=input()
l=["H","Q","9"]
count=0
for i in n:
if i in l:
count+=1
if(count>=1):
print("YES")
else:
print("NO")
``` | instruction | 0 | 96,270 | 18 | 192,540 |
Yes | output | 1 | 96,270 | 18 | 192,541 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
HQ9+ is a joke programming language which has only four one-character instructions:
* "H" prints "Hello, World!",
* "Q" prints the source code of the program itself,
* "9" prints the lyrics of "99 Bottles of Beer" song,
* "+" increments the value stored in the internal accumulator.
Instructions "H" and "Q" are case-sensitive and must be uppercase. The characters of the program which are not instructions are ignored.
You are given a program written in HQ9+. You have to figure out whether executing this program will produce any output.
Input
The input will consist of a single line p which will give a program in HQ9+. String p will contain between 1 and 100 characters, inclusive. ASCII-code of each character of p will be between 33 (exclamation mark) and 126 (tilde), inclusive.
Output
Output "YES", if executing the program will produce any output, and "NO" otherwise.
Examples
Input
Hi!
Output
YES
Input
Codeforces
Output
NO
Note
In the first case the program contains only one instruction — "H", which prints "Hello, World!".
In the second case none of the program characters are language instructions.
Submitted Solution:
```
import sys
input = sys.stdin.readline
def insr():
s = input()
return(list(s[:len(s) - 1]))
source = insr()
if any(x in source for x in ['H','Q','9']):
print("YES")
else:
print("NO")
``` | instruction | 0 | 96,271 | 18 | 192,542 |
Yes | output | 1 | 96,271 | 18 | 192,543 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
HQ9+ is a joke programming language which has only four one-character instructions:
* "H" prints "Hello, World!",
* "Q" prints the source code of the program itself,
* "9" prints the lyrics of "99 Bottles of Beer" song,
* "+" increments the value stored in the internal accumulator.
Instructions "H" and "Q" are case-sensitive and must be uppercase. The characters of the program which are not instructions are ignored.
You are given a program written in HQ9+. You have to figure out whether executing this program will produce any output.
Input
The input will consist of a single line p which will give a program in HQ9+. String p will contain between 1 and 100 characters, inclusive. ASCII-code of each character of p will be between 33 (exclamation mark) and 126 (tilde), inclusive.
Output
Output "YES", if executing the program will produce any output, and "NO" otherwise.
Examples
Input
Hi!
Output
YES
Input
Codeforces
Output
NO
Note
In the first case the program contains only one instruction — "H", which prints "Hello, World!".
In the second case none of the program characters are language instructions.
Submitted Solution:
```
p = input()
if "H" in p[0] or "Q" in p[0] or "9" in p[0] or "+" in p[0]:
print("YES")
else:
print("NO")
``` | instruction | 0 | 96,272 | 18 | 192,544 |
No | output | 1 | 96,272 | 18 | 192,545 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
HQ9+ is a joke programming language which has only four one-character instructions:
* "H" prints "Hello, World!",
* "Q" prints the source code of the program itself,
* "9" prints the lyrics of "99 Bottles of Beer" song,
* "+" increments the value stored in the internal accumulator.
Instructions "H" and "Q" are case-sensitive and must be uppercase. The characters of the program which are not instructions are ignored.
You are given a program written in HQ9+. You have to figure out whether executing this program will produce any output.
Input
The input will consist of a single line p which will give a program in HQ9+. String p will contain between 1 and 100 characters, inclusive. ASCII-code of each character of p will be between 33 (exclamation mark) and 126 (tilde), inclusive.
Output
Output "YES", if executing the program will produce any output, and "NO" otherwise.
Examples
Input
Hi!
Output
YES
Input
Codeforces
Output
NO
Note
In the first case the program contains only one instruction — "H", which prints "Hello, World!".
In the second case none of the program characters are language instructions.
Submitted Solution:
```
s =input()
if 'H' in s or 'Q' in s or '9' in s or '+' in s:
print('YES')
else:
print('NO')
``` | instruction | 0 | 96,273 | 18 | 192,546 |
No | output | 1 | 96,273 | 18 | 192,547 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
HQ9+ is a joke programming language which has only four one-character instructions:
* "H" prints "Hello, World!",
* "Q" prints the source code of the program itself,
* "9" prints the lyrics of "99 Bottles of Beer" song,
* "+" increments the value stored in the internal accumulator.
Instructions "H" and "Q" are case-sensitive and must be uppercase. The characters of the program which are not instructions are ignored.
You are given a program written in HQ9+. You have to figure out whether executing this program will produce any output.
Input
The input will consist of a single line p which will give a program in HQ9+. String p will contain between 1 and 100 characters, inclusive. ASCII-code of each character of p will be between 33 (exclamation mark) and 126 (tilde), inclusive.
Output
Output "YES", if executing the program will produce any output, and "NO" otherwise.
Examples
Input
Hi!
Output
YES
Input
Codeforces
Output
NO
Note
In the first case the program contains only one instruction — "H", which prints "Hello, World!".
In the second case none of the program characters are language instructions.
Submitted Solution:
```
s = input()
def solve(s):
for x in s:
if x in "HQ9":
return "YES"
return "NO"
print(solve(s))
``` | instruction | 0 | 96,274 | 18 | 192,548 |
No | output | 1 | 96,274 | 18 | 192,549 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
HQ9+ is a joke programming language which has only four one-character instructions:
* "H" prints "Hello, World!",
* "Q" prints the source code of the program itself,
* "9" prints the lyrics of "99 Bottles of Beer" song,
* "+" increments the value stored in the internal accumulator.
Instructions "H" and "Q" are case-sensitive and must be uppercase. The characters of the program which are not instructions are ignored.
You are given a program written in HQ9+. You have to figure out whether executing this program will produce any output.
Input
The input will consist of a single line p which will give a program in HQ9+. String p will contain between 1 and 100 characters, inclusive. ASCII-code of each character of p will be between 33 (exclamation mark) and 126 (tilde), inclusive.
Output
Output "YES", if executing the program will produce any output, and "NO" otherwise.
Examples
Input
Hi!
Output
YES
Input
Codeforces
Output
NO
Note
In the first case the program contains only one instruction — "H", which prints "Hello, World!".
In the second case none of the program characters are language instructions.
Submitted Solution:
```
w=str(input())
a=0
l=['H','Q','9','+']
for i in l:
if w.find(i)!=-1:
a=1
if a==1:
print('YES')
else:
print('NO')
``` | instruction | 0 | 96,275 | 18 | 192,550 |
No | output | 1 | 96,275 | 18 | 192,551 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Eudokimus, a system administrator is in trouble again. As a result of an error in some script, a list of names of very important files has been damaged. Since they were files in the BerFS file system, it is known that each file name has a form "name.ext", where:
* name is a string consisting of lowercase Latin letters, its length is from 1 to 8 characters;
* ext is a string consisting of lowercase Latin letters, its length is from 1 to 3 characters.
For example, "read.me", "example.txt" and "b.cpp" are valid file names and "version.info", "ntldr" and "contestdata.zip" are not.
Damage to the list meant that all the file names were recorded one after another, without any separators. So now Eudokimus has a single string.
Eudokimus needs to set everything right as soon as possible. He should divide the resulting string into parts so that each part would be a valid file name in BerFS. Since Eudokimus has already proved that he is not good at programming, help him. The resulting file list can contain the same file names.
Input
The input data consists of a single string s, its length is from 1 to 4·105 characters. The string can contain only lowercase Latin letters ('a' - 'z') and periods ('.').
Output
In the first line print "YES" (without the quotes), if it is possible to divide s into parts as required. In this case, the following lines should contain the parts of the required partition, one per line in the order in which they appear in s. The required partition can contain the same file names. If there are multiple solutions, print any of them.
If the solution does not exist, then print in a single line "NO" (without the quotes).
Examples
Input
read.meexample.txtb.cpp
Output
YES
read.m
eexample.t
xtb.cpp
Input
version.infontldrcontestdata.zip
Output
NO
Submitted Solution:
```
s=input().split('.')
y=0<len(s[0])<9and 0<len(s[-1])<4 and len(s)>1
for i in range(1,len(s)-1):
if len(s[i])<2or len(s[i])>11:y=0
print(['NO','YES'][y])
if y<1:exit()
print(s[0],end='')
for i in range(1,len(s)-1):print('.'+[s[i][0]+'\n'+s[i][1:],s[i][:3]+'\n'+s[i][3:]][len(s[i])>3],end='')
print('.'+s[-1])
``` | instruction | 0 | 96,380 | 18 | 192,760 |
Yes | output | 1 | 96,380 | 18 | 192,761 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Eudokimus, a system administrator is in trouble again. As a result of an error in some script, a list of names of very important files has been damaged. Since they were files in the BerFS file system, it is known that each file name has a form "name.ext", where:
* name is a string consisting of lowercase Latin letters, its length is from 1 to 8 characters;
* ext is a string consisting of lowercase Latin letters, its length is from 1 to 3 characters.
For example, "read.me", "example.txt" and "b.cpp" are valid file names and "version.info", "ntldr" and "contestdata.zip" are not.
Damage to the list meant that all the file names were recorded one after another, without any separators. So now Eudokimus has a single string.
Eudokimus needs to set everything right as soon as possible. He should divide the resulting string into parts so that each part would be a valid file name in BerFS. Since Eudokimus has already proved that he is not good at programming, help him. The resulting file list can contain the same file names.
Input
The input data consists of a single string s, its length is from 1 to 4·105 characters. The string can contain only lowercase Latin letters ('a' - 'z') and periods ('.').
Output
In the first line print "YES" (without the quotes), if it is possible to divide s into parts as required. In this case, the following lines should contain the parts of the required partition, one per line in the order in which they appear in s. The required partition can contain the same file names. If there are multiple solutions, print any of them.
If the solution does not exist, then print in a single line "NO" (without the quotes).
Examples
Input
read.meexample.txtb.cpp
Output
YES
read.m
eexample.t
xtb.cpp
Input
version.infontldrcontestdata.zip
Output
NO
Submitted Solution:
```
#
# 24.06.2021
#
# ������������ ����� �� ����� 4
ok = 1
s = (input ()).split ('.')
n = len (s)
ver = 0
if ( n < 2 ) :
ok = 0
ver = 1
for i in range (1, n-1) :
t = s [i]
if ( not t.isalpha () or not t.islower () or len (t) < 2 or len (t) > 11 ) :
ok = 0
ver = 2
break
t = s [0]
if ( not t.isalpha () or not t.islower () or len (t) < 1 or len (t) > 8 ) :
ok = 0
ver = 3
t = s [n-1]
if ( not t.isalpha () or not t.islower () or len (t) < 1 or len (t) > 3 ) :
ok = 0
ver = 4
if ( ok == 0 ) :
print ("NO")
# print (ver)
else :
print ("YES")
if ( n == 2 ) :
print (".".join (s))
else :
r = ["1", "2"]
m0 = len (s [0])
for i in range (1, n) :
k = m0
m = len (s [i])
if ( m > 3 ) :
m0 = m - 3
m = 3
else :
if ( i < n-1 ) :
m0 = m - 1
m = 1
l = len (s [i-1])
r [0] = s [i-1][l-k:l]
r [1] = s [i][0:m]
print (".".join (r))
``` | instruction | 0 | 96,381 | 18 | 192,762 |
Yes | output | 1 | 96,381 | 18 | 192,763 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Eudokimus, a system administrator is in trouble again. As a result of an error in some script, a list of names of very important files has been damaged. Since they were files in the BerFS file system, it is known that each file name has a form "name.ext", where:
* name is a string consisting of lowercase Latin letters, its length is from 1 to 8 characters;
* ext is a string consisting of lowercase Latin letters, its length is from 1 to 3 characters.
For example, "read.me", "example.txt" and "b.cpp" are valid file names and "version.info", "ntldr" and "contestdata.zip" are not.
Damage to the list meant that all the file names were recorded one after another, without any separators. So now Eudokimus has a single string.
Eudokimus needs to set everything right as soon as possible. He should divide the resulting string into parts so that each part would be a valid file name in BerFS. Since Eudokimus has already proved that he is not good at programming, help him. The resulting file list can contain the same file names.
Input
The input data consists of a single string s, its length is from 1 to 4·105 characters. The string can contain only lowercase Latin letters ('a' - 'z') and periods ('.').
Output
In the first line print "YES" (without the quotes), if it is possible to divide s into parts as required. In this case, the following lines should contain the parts of the required partition, one per line in the order in which they appear in s. The required partition can contain the same file names. If there are multiple solutions, print any of them.
If the solution does not exist, then print in a single line "NO" (without the quotes).
Examples
Input
read.meexample.txtb.cpp
Output
YES
read.m
eexample.t
xtb.cpp
Input
version.infontldrcontestdata.zip
Output
NO
Submitted Solution:
```
def swap():
global flag, c
flag ^= 1
return [8, 3][flag]
s = input() + ' '
if s[0] == '.':
exit(print('NO'))
flag, cur, ans, c = 0, '', [], 8
for i in range(len(s) - 2):
if s[i] == '.':
if s[i + 1] in '. ' or s[i + 2] == '.':
exit(print('NO'))
c = swap()
cur = (cur + '.') * flag
else:
if (s[i + 1] == '.' or not c) and flag :
ans.append(cur)
cur = s[i]
c = swap() - (c == 0)
elif c:
cur += s[i]
c -= 1
else:
exit(print('NO'))
if '.' not in cur:
exit(print('NO'))
print('YES', *ans, cur, sep='\n')
``` | instruction | 0 | 96,382 | 18 | 192,764 |
Yes | output | 1 | 96,382 | 18 | 192,765 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Eudokimus, a system administrator is in trouble again. As a result of an error in some script, a list of names of very important files has been damaged. Since they were files in the BerFS file system, it is known that each file name has a form "name.ext", where:
* name is a string consisting of lowercase Latin letters, its length is from 1 to 8 characters;
* ext is a string consisting of lowercase Latin letters, its length is from 1 to 3 characters.
For example, "read.me", "example.txt" and "b.cpp" are valid file names and "version.info", "ntldr" and "contestdata.zip" are not.
Damage to the list meant that all the file names were recorded one after another, without any separators. So now Eudokimus has a single string.
Eudokimus needs to set everything right as soon as possible. He should divide the resulting string into parts so that each part would be a valid file name in BerFS. Since Eudokimus has already proved that he is not good at programming, help him. The resulting file list can contain the same file names.
Input
The input data consists of a single string s, its length is from 1 to 4·105 characters. The string can contain only lowercase Latin letters ('a' - 'z') and periods ('.').
Output
In the first line print "YES" (without the quotes), if it is possible to divide s into parts as required. In this case, the following lines should contain the parts of the required partition, one per line in the order in which they appear in s. The required partition can contain the same file names. If there are multiple solutions, print any of them.
If the solution does not exist, then print in a single line "NO" (without the quotes).
Examples
Input
read.meexample.txtb.cpp
Output
YES
read.m
eexample.t
xtb.cpp
Input
version.infontldrcontestdata.zip
Output
NO
Submitted Solution:
```
s = input()
s = s.split('.')
f = 0
if (len(s[0])<=8 and len(s[0])>=1) and (len(s[-1])<=3 and len(s[-1])>=1):
pass
else:
f = 1
if len(s)<2:
f = 1
for i in range(1,len(s)-1):
if len(s[i])<=11 and len(s[i])>1:
pass
else:
f = 1
if f==1:
print("NO")
else:
print("YES")
prev = 0
last = s[0]+'.'
for i in range(1,len(s)-1):
if len(s[i])>=9:
last+=(s[i][:len(s[i])-8])
print(last)
last = s[i][len(s[i])-8::]+'.'
else:
last+=s[i][0]
print(last)
last = s[i][1::]+'.'
print(last+s[-1])
``` | instruction | 0 | 96,383 | 18 | 192,766 |
Yes | output | 1 | 96,383 | 18 | 192,767 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Eudokimus, a system administrator is in trouble again. As a result of an error in some script, a list of names of very important files has been damaged. Since they were files in the BerFS file system, it is known that each file name has a form "name.ext", where:
* name is a string consisting of lowercase Latin letters, its length is from 1 to 8 characters;
* ext is a string consisting of lowercase Latin letters, its length is from 1 to 3 characters.
For example, "read.me", "example.txt" and "b.cpp" are valid file names and "version.info", "ntldr" and "contestdata.zip" are not.
Damage to the list meant that all the file names were recorded one after another, without any separators. So now Eudokimus has a single string.
Eudokimus needs to set everything right as soon as possible. He should divide the resulting string into parts so that each part would be a valid file name in BerFS. Since Eudokimus has already proved that he is not good at programming, help him. The resulting file list can contain the same file names.
Input
The input data consists of a single string s, its length is from 1 to 4·105 characters. The string can contain only lowercase Latin letters ('a' - 'z') and periods ('.').
Output
In the first line print "YES" (without the quotes), if it is possible to divide s into parts as required. In this case, the following lines should contain the parts of the required partition, one per line in the order in which they appear in s. The required partition can contain the same file names. If there are multiple solutions, print any of them.
If the solution does not exist, then print in a single line "NO" (without the quotes).
Examples
Input
read.meexample.txtb.cpp
Output
YES
read.m
eexample.t
xtb.cpp
Input
version.infontldrcontestdata.zip
Output
NO
Submitted Solution:
```
s = input().split('.')
if len(s) == 1:
print('NO')
exit()
elif len(s[0]) > 8:
print('NO')
exit()
D = []
a = s[0]
for i in range(1, len(s) - 1):
if len(s[i]) <= 1:
print('NO')
exit()
elif len(s[i]) > 11:
print('NO')
exit()
else:
b = s[i][:min(len(s) - 1, 3)]
D.append(a + '.' + b)
a = s[i][min(len(s) - 1, 3):]
if len(s[-1]) > 3:
print('NO')
exit()
D.append(a + '.' + s[-1])
print('YES')
for i in D:
print(i)
``` | instruction | 0 | 96,384 | 18 | 192,768 |
No | output | 1 | 96,384 | 18 | 192,769 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Eudokimus, a system administrator is in trouble again. As a result of an error in some script, a list of names of very important files has been damaged. Since they were files in the BerFS file system, it is known that each file name has a form "name.ext", where:
* name is a string consisting of lowercase Latin letters, its length is from 1 to 8 characters;
* ext is a string consisting of lowercase Latin letters, its length is from 1 to 3 characters.
For example, "read.me", "example.txt" and "b.cpp" are valid file names and "version.info", "ntldr" and "contestdata.zip" are not.
Damage to the list meant that all the file names were recorded one after another, without any separators. So now Eudokimus has a single string.
Eudokimus needs to set everything right as soon as possible. He should divide the resulting string into parts so that each part would be a valid file name in BerFS. Since Eudokimus has already proved that he is not good at programming, help him. The resulting file list can contain the same file names.
Input
The input data consists of a single string s, its length is from 1 to 4·105 characters. The string can contain only lowercase Latin letters ('a' - 'z') and periods ('.').
Output
In the first line print "YES" (without the quotes), if it is possible to divide s into parts as required. In this case, the following lines should contain the parts of the required partition, one per line in the order in which they appear in s. The required partition can contain the same file names. If there are multiple solutions, print any of them.
If the solution does not exist, then print in a single line "NO" (without the quotes).
Examples
Input
read.meexample.txtb.cpp
Output
YES
read.m
eexample.t
xtb.cpp
Input
version.infontldrcontestdata.zip
Output
NO
Submitted Solution:
```
import math as mt
import sys,string
input=sys.stdin.readline
import random
from collections import deque,defaultdict
L=lambda : list(map(int,input().split()))
Ls=lambda : list(input().split())
M=lambda : map(int,input().split())
I=lambda :int(input())
s=input().strip()
if(s.count('.')==0):
print("NO")
else:
s=s.split()
if(len(s[0])>8 or len(s)<1):
print("NO")
elif(len(s[-1])>3 or len(s[-1])<1):
print("NO")
else:
x=[]
#print(s)
for i in range(1,len(s)-1):
if(len(s[i])<2 or len(s[i])>11):
print("NO")
exit()
else:
x.append(str(s[i-1]+'.'+s[i][:min(3,len(s[i])-1)]))
s[i]=s[i][min(3,len(s[i])-1)::]
x.append(s[-2]+'.'+s[-1])
print("YES")
for i in x:
print(i)
``` | instruction | 0 | 96,385 | 18 | 192,770 |
No | output | 1 | 96,385 | 18 | 192,771 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Eudokimus, a system administrator is in trouble again. As a result of an error in some script, a list of names of very important files has been damaged. Since they were files in the BerFS file system, it is known that each file name has a form "name.ext", where:
* name is a string consisting of lowercase Latin letters, its length is from 1 to 8 characters;
* ext is a string consisting of lowercase Latin letters, its length is from 1 to 3 characters.
For example, "read.me", "example.txt" and "b.cpp" are valid file names and "version.info", "ntldr" and "contestdata.zip" are not.
Damage to the list meant that all the file names were recorded one after another, without any separators. So now Eudokimus has a single string.
Eudokimus needs to set everything right as soon as possible. He should divide the resulting string into parts so that each part would be a valid file name in BerFS. Since Eudokimus has already proved that he is not good at programming, help him. The resulting file list can contain the same file names.
Input
The input data consists of a single string s, its length is from 1 to 4·105 characters. The string can contain only lowercase Latin letters ('a' - 'z') and periods ('.').
Output
In the first line print "YES" (without the quotes), if it is possible to divide s into parts as required. In this case, the following lines should contain the parts of the required partition, one per line in the order in which they appear in s. The required partition can contain the same file names. If there are multiple solutions, print any of them.
If the solution does not exist, then print in a single line "NO" (without the quotes).
Examples
Input
read.meexample.txtb.cpp
Output
YES
read.m
eexample.t
xtb.cpp
Input
version.infontldrcontestdata.zip
Output
NO
Submitted Solution:
```
s = input()
words = s.split('.')
n = s.count('.')
numberOfWordsWithSizeLessThanTwo = len([x for x in words[1:-1] if len(x) < 2])
numberOfWordsWithSizeMoreThanEleven = len([x for x in words[1:-1] if len(x) > 11])
if len(words) == 1:
print('NO')
elif len(words[0]) < 1 or len(words[0]) > 8 or len(words[-1]) < 1 or len(words[-1]) > 3 or numberOfWordsWithSizeLessThanTwo != 0 or numberOfWordsWithSizeMoreThanEleven != 0:
print('NO')
else:
s0 = words[0]
sn = words[-1]
s1 = ''
s2 = ''
print('YES')
for word in words[1:-1]:
if len(word) > 10:
s2 = word[-8:]
s1 = word[:-8]
else:
s1 = word[0]
s2 = word[1:]
res = s0 + '.' + s1
print(res)
s0 = s2
print(s0 + '.' + sn)
# print(words, len(words), n, numberOfWordsWithSizeLessThanTwo, numberOfWordsWithSizeMoreThanEleven)
# print(words[1:-1])
``` | instruction | 0 | 96,386 | 18 | 192,772 |
No | output | 1 | 96,386 | 18 | 192,773 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Eudokimus, a system administrator is in trouble again. As a result of an error in some script, a list of names of very important files has been damaged. Since they were files in the BerFS file system, it is known that each file name has a form "name.ext", where:
* name is a string consisting of lowercase Latin letters, its length is from 1 to 8 characters;
* ext is a string consisting of lowercase Latin letters, its length is from 1 to 3 characters.
For example, "read.me", "example.txt" and "b.cpp" are valid file names and "version.info", "ntldr" and "contestdata.zip" are not.
Damage to the list meant that all the file names were recorded one after another, without any separators. So now Eudokimus has a single string.
Eudokimus needs to set everything right as soon as possible. He should divide the resulting string into parts so that each part would be a valid file name in BerFS. Since Eudokimus has already proved that he is not good at programming, help him. The resulting file list can contain the same file names.
Input
The input data consists of a single string s, its length is from 1 to 4·105 characters. The string can contain only lowercase Latin letters ('a' - 'z') and periods ('.').
Output
In the first line print "YES" (without the quotes), if it is possible to divide s into parts as required. In this case, the following lines should contain the parts of the required partition, one per line in the order in which they appear in s. The required partition can contain the same file names. If there are multiple solutions, print any of them.
If the solution does not exist, then print in a single line "NO" (without the quotes).
Examples
Input
read.meexample.txtb.cpp
Output
YES
read.m
eexample.t
xtb.cpp
Input
version.infontldrcontestdata.zip
Output
NO
Submitted Solution:
```
s = input()
l = []
for i in range(len(s)):
if s[i] == ".":
l.append(i)
if len(l) == 0:
print("NO")
exit()
if len(s)-1-l[-1] > 3:
print("N0")
i = 0
t1 = 0
while i < len(l)-1:
if l[i+1]-l[i] > 11 or l[i+1]-l[i] == 1:
print("NO")
exit()
i = i + 1
i = 0
print("YES")
while i < len(l)-1:
if l[i+1]-l[i] > 11:
print("NO")
exit()
elif l[i+1]-l[i] > 4:
t = 4
elif l[i+1]-l[i] == 1:
print("NO")
exit()
else:
t = 2
str1 = s[t1:l[i]] + "." + s[l[i]+1:l[i]+t]
t1 = l[i]+t
print(str1)
i = i + 1
print(s[t1:l[i]] + "." + s[l[i]+1:])
``` | instruction | 0 | 96,387 | 18 | 192,774 |
No | output | 1 | 96,387 | 18 | 192,775 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Input
The input contains a single integer a (1 ≤ a ≤ 40).
Output
Output a single string.
Examples
Input
2
Output
Adams
Input
8
Output
Van Buren
Input
29
Output
Harding
Submitted Solution:
```
print(["Washington","Adams","Jefferson","Madison","Monroe","Adams","Jackson","Van Buren","Harrison","Tyler","Polk","Taylor","Fillmore","Pierce","Buchanan","Lincoln","Johnson","Grant","Hayes","Garfield","Arthur","Cleveland","Harrison","Cleveland","McKinley","Roosevelt","Taft","Wilson","Harding","Coolidge","Hoover","Roosevelt","Truman","Eisenhower","Kennedy","Johnson","Nixon","Ford","Carter","Reagan","Bush"][int(input())-1])
``` | instruction | 0 | 96,447 | 18 | 192,894 |
Yes | output | 1 | 96,447 | 18 | 192,895 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Input
The input contains a single integer a (1 ≤ a ≤ 40).
Output
Output a single string.
Examples
Input
2
Output
Adams
Input
8
Output
Van Buren
Input
29
Output
Harding
Submitted Solution:
```
a = ["Washington", "Adams", "Jefferson", "Madison", "Monroe", "Adams", "Jackson", "Van Buren", "Harrison", "Tyler", "Polk", "Taylor", "Fillmore", "Pierce", "Buchanan", "Lincoln", "Johnson", "Grant", "Hayes", "Garfield", "Arthur", "Cleveland", "Harrison", "Cleveland", "McKinley", "Roosevelt", "Taft", "Wilson", "Harding", "Coolidge", "Hoover", "Roosevelt", "Truman", "Eisenhower", "Kennedy", "Johnson", "Nixon", "Ford", "Carter", "Reagan"]
print(a[int(input())-1])
``` | instruction | 0 | 96,448 | 18 | 192,896 |
Yes | output | 1 | 96,448 | 18 | 192,897 |
Provide a correct Python 3 solution for this coding contest problem.
Given is a string S. Replace every character in S with `x` and print the result.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Replace every character in S with `x` and print the result.
Examples
Input
sardine
Output
xxxxxxx
Input
xxxx
Output
xxxx
Input
gone
Output
xxxx | instruction | 0 | 96,746 | 18 | 193,492 |
"Correct Solution:
```
s = input()
q = len(s)
print("x"*q)
``` | output | 1 | 96,746 | 18 | 193,493 |
Provide a correct Python 3 solution for this coding contest problem.
Given is a string S. Replace every character in S with `x` and print the result.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Replace every character in S with `x` and print the result.
Examples
Input
sardine
Output
xxxxxxx
Input
xxxx
Output
xxxx
Input
gone
Output
xxxx | instruction | 0 | 96,747 | 18 | 193,494 |
"Correct Solution:
```
print(''.join('x' for x in input()))
``` | output | 1 | 96,747 | 18 | 193,495 |
Provide a correct Python 3 solution for this coding contest problem.
Given is a string S. Replace every character in S with `x` and print the result.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Replace every character in S with `x` and print the result.
Examples
Input
sardine
Output
xxxxxxx
Input
xxxx
Output
xxxx
Input
gone
Output
xxxx | instruction | 0 | 96,748 | 18 | 193,496 |
"Correct Solution:
```
S = input()
L = len(S)
print('x'*L)
``` | output | 1 | 96,748 | 18 | 193,497 |
Provide a correct Python 3 solution for this coding contest problem.
Given is a string S. Replace every character in S with `x` and print the result.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Replace every character in S with `x` and print the result.
Examples
Input
sardine
Output
xxxxxxx
Input
xxxx
Output
xxxx
Input
gone
Output
xxxx | instruction | 0 | 96,749 | 18 | 193,498 |
"Correct Solution:
```
S = input()
l=len(S)
print("x"*l)
``` | output | 1 | 96,749 | 18 | 193,499 |
Provide a correct Python 3 solution for this coding contest problem.
Given is a string S. Replace every character in S with `x` and print the result.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Replace every character in S with `x` and print the result.
Examples
Input
sardine
Output
xxxxxxx
Input
xxxx
Output
xxxx
Input
gone
Output
xxxx | instruction | 0 | 96,750 | 18 | 193,500 |
"Correct Solution:
```
s = input()
y = len(s)
print('x'*y)
``` | output | 1 | 96,750 | 18 | 193,501 |
Provide a correct Python 3 solution for this coding contest problem.
Given is a string S. Replace every character in S with `x` and print the result.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Replace every character in S with `x` and print the result.
Examples
Input
sardine
Output
xxxxxxx
Input
xxxx
Output
xxxx
Input
gone
Output
xxxx | instruction | 0 | 96,751 | 18 | 193,502 |
"Correct Solution:
```
b = input()
print("x" * len(b))
``` | output | 1 | 96,751 | 18 | 193,503 |
Provide a correct Python 3 solution for this coding contest problem.
Given is a string S. Replace every character in S with `x` and print the result.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Replace every character in S with `x` and print the result.
Examples
Input
sardine
Output
xxxxxxx
Input
xxxx
Output
xxxx
Input
gone
Output
xxxx | instruction | 0 | 96,752 | 18 | 193,504 |
"Correct Solution:
```
s = input()
n = len(s)
print("x"*n)
``` | output | 1 | 96,752 | 18 | 193,505 |
Provide a correct Python 3 solution for this coding contest problem.
Given is a string S. Replace every character in S with `x` and print the result.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Replace every character in S with `x` and print the result.
Examples
Input
sardine
Output
xxxxxxx
Input
xxxx
Output
xxxx
Input
gone
Output
xxxx | instruction | 0 | 96,753 | 18 | 193,506 |
"Correct Solution:
```
S = input()
print(['x'*len(S)][0])
``` | output | 1 | 96,753 | 18 | 193,507 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given is a string S. Replace every character in S with `x` and print the result.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Replace every character in S with `x` and print the result.
Examples
Input
sardine
Output
xxxxxxx
Input
xxxx
Output
xxxx
Input
gone
Output
xxxx
Submitted Solution:
```
S= input()
t= len(S)
print("x" * t)
``` | instruction | 0 | 96,754 | 18 | 193,508 |
Yes | output | 1 | 96,754 | 18 | 193,509 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given is a string S. Replace every character in S with `x` and print the result.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Replace every character in S with `x` and print the result.
Examples
Input
sardine
Output
xxxxxxx
Input
xxxx
Output
xxxx
Input
gone
Output
xxxx
Submitted Solution:
```
s = input()
print((len(s)*chr(120)))
``` | instruction | 0 | 96,755 | 18 | 193,510 |
Yes | output | 1 | 96,755 | 18 | 193,511 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given is a string S. Replace every character in S with `x` and print the result.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Replace every character in S with `x` and print the result.
Examples
Input
sardine
Output
xxxxxxx
Input
xxxx
Output
xxxx
Input
gone
Output
xxxx
Submitted Solution:
```
#B
S=input()
print("x"*len(S))
``` | instruction | 0 | 96,756 | 18 | 193,512 |
Yes | output | 1 | 96,756 | 18 | 193,513 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given is a string S. Replace every character in S with `x` and print the result.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Replace every character in S with `x` and print the result.
Examples
Input
sardine
Output
xxxxxxx
Input
xxxx
Output
xxxx
Input
gone
Output
xxxx
Submitted Solution:
```
s=input()
l=len(s)
k="x"*l
print(k)
``` | instruction | 0 | 96,757 | 18 | 193,514 |
Yes | output | 1 | 96,757 | 18 | 193,515 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given is a string S. Replace every character in S with `x` and print the result.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Replace every character in S with `x` and print the result.
Examples
Input
sardine
Output
xxxxxxx
Input
xxxx
Output
xxxx
Input
gone
Output
xxxx
Submitted Solution:
```
def resolve_B():
s = input()
l = len(s)
print("x" * l)
resolve_B
``` | instruction | 0 | 96,758 | 18 | 193,516 |
No | output | 1 | 96,758 | 18 | 193,517 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given is a string S. Replace every character in S with `x` and print the result.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Replace every character in S with `x` and print the result.
Examples
Input
sardine
Output
xxxxxxx
Input
xxxx
Output
xxxx
Input
gone
Output
xxxx
Submitted Solution:
```
S = input()
L = len[S]
for i in rnage(L):
print("x")
``` | instruction | 0 | 96,759 | 18 | 193,518 |
No | output | 1 | 96,759 | 18 | 193,519 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given is a string S. Replace every character in S with `x` and print the result.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Replace every character in S with `x` and print the result.
Examples
Input
sardine
Output
xxxxxxx
Input
xxxx
Output
xxxx
Input
gone
Output
xxxx
Submitted Solution:
```
print('x'for i in range(len(input())))
``` | instruction | 0 | 96,760 | 18 | 193,520 |
No | output | 1 | 96,760 | 18 | 193,521 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given is a string S. Replace every character in S with `x` and print the result.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Replace every character in S with `x` and print the result.
Examples
Input
sardine
Output
xxxxxxx
Input
xxxx
Output
xxxx
Input
gone
Output
xxxx
Submitted Solution:
```
u = input()
for i in len(u):
u[i]="x"
print(u)
``` | instruction | 0 | 96,761 | 18 | 193,522 |
No | output | 1 | 96,761 | 18 | 193,523 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bomboslav set up a branding agency and now helps companies to create new logos and advertising slogans. In term of this problems, slogan of the company should be a non-empty substring of its name. For example, if the company name is "hornsandhoofs", then substrings "sand" and "hor" could be its slogans, while strings "e" and "hornss" can not.
Sometimes the company performs rebranding and changes its slogan. Slogan A is considered to be cooler than slogan B if B appears in A as a substring at least twice (this occurrences are allowed to overlap). For example, slogan A = "abacaba" is cooler than slogan B = "ba", slogan A = "abcbcbe" is cooler than slogan B = "bcb", but slogan A = "aaaaaa" is not cooler than slogan B = "aba".
You are given the company name w and your task is to help Bomboslav determine the length of the longest sequence of slogans s1, s2, ..., sk, such that any slogan in the sequence is cooler than the previous one.
Input
The first line of the input contains a single integer n (1 ≤ n ≤ 200 000) — the length of the company name that asks Bomboslav to help. The second line contains the string w of length n, that consists of lowercase English letters.
Output
Print a single integer — the maximum possible length of the sequence of slogans of the company named w, such that any slogan in the sequence (except the first one) is cooler than the previous
Examples
Input
3
abc
Output
1
Input
5
ddddd
Output
5
Input
11
abracadabra
Output
3
Submitted Solution:
```
def search(word):
max = 1
for i in range(len(word)-1):
for j in range(i+1,len(word)):
if word[i]==word[j]:
new = 0
for k in range(1,len(word)-j):
if (word[i+k]!=word[j+k]):
new = search(word[j:j+k-len(word)])
break
elif (k+j==len(word)-1):
new = search(word[j:])
if new >= max:
max = new + 1
return max
n=int(input())
word = str(input())
print(search(word))
``` | instruction | 0 | 97,480 | 18 | 194,960 |
No | output | 1 | 97,480 | 18 | 194,961 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bomboslav set up a branding agency and now helps companies to create new logos and advertising slogans. In term of this problems, slogan of the company should be a non-empty substring of its name. For example, if the company name is "hornsandhoofs", then substrings "sand" and "hor" could be its slogans, while strings "e" and "hornss" can not.
Sometimes the company performs rebranding and changes its slogan. Slogan A is considered to be cooler than slogan B if B appears in A as a substring at least twice (this occurrences are allowed to overlap). For example, slogan A = "abacaba" is cooler than slogan B = "ba", slogan A = "abcbcbe" is cooler than slogan B = "bcb", but slogan A = "aaaaaa" is not cooler than slogan B = "aba".
You are given the company name w and your task is to help Bomboslav determine the length of the longest sequence of slogans s1, s2, ..., sk, such that any slogan in the sequence is cooler than the previous one.
Input
The first line of the input contains a single integer n (1 ≤ n ≤ 200 000) — the length of the company name that asks Bomboslav to help. The second line contains the string w of length n, that consists of lowercase English letters.
Output
Print a single integer — the maximum possible length of the sequence of slogans of the company named w, such that any slogan in the sequence (except the first one) is cooler than the previous
Examples
Input
3
abc
Output
1
Input
5
ddddd
Output
5
Input
11
abracadabra
Output
3
Submitted Solution:
```
# cool slogans
number = int(input())
name = input()
def isset_twice_substring(string,substring):
result = 0
for i in range((int(len(string))-(int(len(substring))-1))):
if string[i:(i+int(len(substring)))] == substring:
result+=1
if result >= 2:
return True
break
if result <= 1:
return False
def get_sub_slogan(string,counter):
longest_length = 0
longest_index = 0
for i in range (number):
for j in range(int(len(string))-(i+1)):
if isset_twice_substring(string,string[i:(j+i+1)]) and (j+1)>longest_length:
longest_length = j+1
longest_index = i
else:
break
if longest_length !=0:
get_sub_slogan(string[longest_index:(longest_index+longest_length)],(counter+1))
else:
print(counter)
get_sub_slogan(name,1)
``` | instruction | 0 | 97,481 | 18 | 194,962 |
No | output | 1 | 97,481 | 18 | 194,963 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Your friend has n cards.
You know that each card has a lowercase English letter on one side and a digit on the other.
Currently, your friend has laid out the cards on a table so only one side of each card is visible.
You would like to know if the following statement is true for cards that your friend owns: "If a card has a vowel on one side, then it has an even digit on the other side." More specifically, a vowel is one of 'a', 'e', 'i', 'o' or 'u', and even digit is one of '0', '2', '4', '6' or '8'.
For example, if a card has 'a' on one side, and '6' on the other side, then this statement is true for it. Also, the statement is true, for example, for a card with 'b' and '4', and for a card with 'b' and '3' (since the letter is not a vowel). The statement is false, for example, for card with 'e' and '5'. You are interested if the statement is true for all cards. In particular, if no card has a vowel, the statement is true.
To determine this, you can flip over some cards to reveal the other side. You would like to know what is the minimum number of cards you need to flip in the worst case in order to verify that the statement is true.
Input
The first and only line of input will contain a string s (1 ≤ |s| ≤ 50), denoting the sides of the cards that you can see on the table currently. Each character of s is either a lowercase English letter or a digit.
Output
Print a single integer, the minimum number of cards you must turn over to verify your claim.
Examples
Input
ee
Output
2
Input
z
Output
0
Input
0ay1
Output
2
Note
In the first sample, we must turn over both cards. Note that even though both cards have the same letter, they could possibly have different numbers on the other side.
In the second sample, we don't need to turn over any cards. The statement is vacuously true, since you know your friend has no cards with a vowel on them.
In the third sample, we need to flip the second and fourth cards.
Submitted Solution:
```
s = input()
cnt = 0
for c in s:
cnt += 1 if "aeiou13579".find(c) != -1 else 0
print(cnt)
``` | instruction | 0 | 97,554 | 18 | 195,108 |
Yes | output | 1 | 97,554 | 18 | 195,109 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Your friend has n cards.
You know that each card has a lowercase English letter on one side and a digit on the other.
Currently, your friend has laid out the cards on a table so only one side of each card is visible.
You would like to know if the following statement is true for cards that your friend owns: "If a card has a vowel on one side, then it has an even digit on the other side." More specifically, a vowel is one of 'a', 'e', 'i', 'o' or 'u', and even digit is one of '0', '2', '4', '6' or '8'.
For example, if a card has 'a' on one side, and '6' on the other side, then this statement is true for it. Also, the statement is true, for example, for a card with 'b' and '4', and for a card with 'b' and '3' (since the letter is not a vowel). The statement is false, for example, for card with 'e' and '5'. You are interested if the statement is true for all cards. In particular, if no card has a vowel, the statement is true.
To determine this, you can flip over some cards to reveal the other side. You would like to know what is the minimum number of cards you need to flip in the worst case in order to verify that the statement is true.
Input
The first and only line of input will contain a string s (1 ≤ |s| ≤ 50), denoting the sides of the cards that you can see on the table currently. Each character of s is either a lowercase English letter or a digit.
Output
Print a single integer, the minimum number of cards you must turn over to verify your claim.
Examples
Input
ee
Output
2
Input
z
Output
0
Input
0ay1
Output
2
Note
In the first sample, we must turn over both cards. Note that even though both cards have the same letter, they could possibly have different numbers on the other side.
In the second sample, we don't need to turn over any cards. The statement is vacuously true, since you know your friend has no cards with a vowel on them.
In the third sample, we need to flip the second and fourth cards.
Submitted Solution:
```
cards = input()
relevants = ['a', 'e', 'i', 'o', 'u', '1', '3', '5', '7', '9']
count = 0
for i in cards:
if(i in relevants):
count += 1
print(count)
``` | instruction | 0 | 97,555 | 18 | 195,110 |
Yes | output | 1 | 97,555 | 18 | 195,111 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Your friend has n cards.
You know that each card has a lowercase English letter on one side and a digit on the other.
Currently, your friend has laid out the cards on a table so only one side of each card is visible.
You would like to know if the following statement is true for cards that your friend owns: "If a card has a vowel on one side, then it has an even digit on the other side." More specifically, a vowel is one of 'a', 'e', 'i', 'o' or 'u', and even digit is one of '0', '2', '4', '6' or '8'.
For example, if a card has 'a' on one side, and '6' on the other side, then this statement is true for it. Also, the statement is true, for example, for a card with 'b' and '4', and for a card with 'b' and '3' (since the letter is not a vowel). The statement is false, for example, for card with 'e' and '5'. You are interested if the statement is true for all cards. In particular, if no card has a vowel, the statement is true.
To determine this, you can flip over some cards to reveal the other side. You would like to know what is the minimum number of cards you need to flip in the worst case in order to verify that the statement is true.
Input
The first and only line of input will contain a string s (1 ≤ |s| ≤ 50), denoting the sides of the cards that you can see on the table currently. Each character of s is either a lowercase English letter or a digit.
Output
Print a single integer, the minimum number of cards you must turn over to verify your claim.
Examples
Input
ee
Output
2
Input
z
Output
0
Input
0ay1
Output
2
Note
In the first sample, we must turn over both cards. Note that even though both cards have the same letter, they could possibly have different numbers on the other side.
In the second sample, we don't need to turn over any cards. The statement is vacuously true, since you know your friend has no cards with a vowel on them.
In the third sample, we need to flip the second and fourth cards.
Submitted Solution:
```
ins = input()
cnt = sum([1 for x in ins if x in "aeiou13579"])
print(cnt)
``` | instruction | 0 | 97,556 | 18 | 195,112 |
Yes | output | 1 | 97,556 | 18 | 195,113 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Your friend has n cards.
You know that each card has a lowercase English letter on one side and a digit on the other.
Currently, your friend has laid out the cards on a table so only one side of each card is visible.
You would like to know if the following statement is true for cards that your friend owns: "If a card has a vowel on one side, then it has an even digit on the other side." More specifically, a vowel is one of 'a', 'e', 'i', 'o' or 'u', and even digit is one of '0', '2', '4', '6' or '8'.
For example, if a card has 'a' on one side, and '6' on the other side, then this statement is true for it. Also, the statement is true, for example, for a card with 'b' and '4', and for a card with 'b' and '3' (since the letter is not a vowel). The statement is false, for example, for card with 'e' and '5'. You are interested if the statement is true for all cards. In particular, if no card has a vowel, the statement is true.
To determine this, you can flip over some cards to reveal the other side. You would like to know what is the minimum number of cards you need to flip in the worst case in order to verify that the statement is true.
Input
The first and only line of input will contain a string s (1 ≤ |s| ≤ 50), denoting the sides of the cards that you can see on the table currently. Each character of s is either a lowercase English letter or a digit.
Output
Print a single integer, the minimum number of cards you must turn over to verify your claim.
Examples
Input
ee
Output
2
Input
z
Output
0
Input
0ay1
Output
2
Note
In the first sample, we must turn over both cards. Note that even though both cards have the same letter, they could possibly have different numbers on the other side.
In the second sample, we don't need to turn over any cards. The statement is vacuously true, since you know your friend has no cards with a vowel on them.
In the third sample, we need to flip the second and fourth cards.
Submitted Solution:
```
s = input()
print(sum(1 for c in s if c in 'aeiou13579'))
``` | instruction | 0 | 97,557 | 18 | 195,114 |
Yes | output | 1 | 97,557 | 18 | 195,115 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Your friend has n cards.
You know that each card has a lowercase English letter on one side and a digit on the other.
Currently, your friend has laid out the cards on a table so only one side of each card is visible.
You would like to know if the following statement is true for cards that your friend owns: "If a card has a vowel on one side, then it has an even digit on the other side." More specifically, a vowel is one of 'a', 'e', 'i', 'o' or 'u', and even digit is one of '0', '2', '4', '6' or '8'.
For example, if a card has 'a' on one side, and '6' on the other side, then this statement is true for it. Also, the statement is true, for example, for a card with 'b' and '4', and for a card with 'b' and '3' (since the letter is not a vowel). The statement is false, for example, for card with 'e' and '5'. You are interested if the statement is true for all cards. In particular, if no card has a vowel, the statement is true.
To determine this, you can flip over some cards to reveal the other side. You would like to know what is the minimum number of cards you need to flip in the worst case in order to verify that the statement is true.
Input
The first and only line of input will contain a string s (1 ≤ |s| ≤ 50), denoting the sides of the cards that you can see on the table currently. Each character of s is either a lowercase English letter or a digit.
Output
Print a single integer, the minimum number of cards you must turn over to verify your claim.
Examples
Input
ee
Output
2
Input
z
Output
0
Input
0ay1
Output
2
Note
In the first sample, we must turn over both cards. Note that even though both cards have the same letter, they could possibly have different numbers on the other side.
In the second sample, we don't need to turn over any cards. The statement is vacuously true, since you know your friend has no cards with a vowel on them.
In the third sample, we need to flip the second and fourth cards.
Submitted Solution:
```
l=list(input())
x=["a","o","e","i","u"]
x2=["0","1","2","3","4","5","6","7","8","9"]
x1=[0,2,4,6,8]
d=0
x3,x4=[],[]
for i in range(len(l)):
if l[i] in x2:
x3.append(l[i])
else:
x4.append(l[i])
for i in range(len(x3)):
if not x3[i] in x1:
d=d+1
for j in range(len(x4)):
if x4[i] in x:
d=d+1
print(d)
``` | instruction | 0 | 97,558 | 18 | 195,116 |
No | output | 1 | 97,558 | 18 | 195,117 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Your friend has n cards.
You know that each card has a lowercase English letter on one side and a digit on the other.
Currently, your friend has laid out the cards on a table so only one side of each card is visible.
You would like to know if the following statement is true for cards that your friend owns: "If a card has a vowel on one side, then it has an even digit on the other side." More specifically, a vowel is one of 'a', 'e', 'i', 'o' or 'u', and even digit is one of '0', '2', '4', '6' or '8'.
For example, if a card has 'a' on one side, and '6' on the other side, then this statement is true for it. Also, the statement is true, for example, for a card with 'b' and '4', and for a card with 'b' and '3' (since the letter is not a vowel). The statement is false, for example, for card with 'e' and '5'. You are interested if the statement is true for all cards. In particular, if no card has a vowel, the statement is true.
To determine this, you can flip over some cards to reveal the other side. You would like to know what is the minimum number of cards you need to flip in the worst case in order to verify that the statement is true.
Input
The first and only line of input will contain a string s (1 ≤ |s| ≤ 50), denoting the sides of the cards that you can see on the table currently. Each character of s is either a lowercase English letter or a digit.
Output
Print a single integer, the minimum number of cards you must turn over to verify your claim.
Examples
Input
ee
Output
2
Input
z
Output
0
Input
0ay1
Output
2
Note
In the first sample, we must turn over both cards. Note that even though both cards have the same letter, they could possibly have different numbers on the other side.
In the second sample, we don't need to turn over any cards. The statement is vacuously true, since you know your friend has no cards with a vowel on them.
In the third sample, we need to flip the second and fourth cards.
Submitted Solution:
```
import sys
lst = list(sys.stdin.read())
try:
lst.remove('\n')
except:
pass
count = 0
vowels = set(['i', 'e', 'a', 'o', 'u'])
for item in lst:
try:
i = int(item)
if i % 2 == 1:
print(item)
count += 1
except:
s = str(item)
if s in vowels:
print(item)
count += 1
print(count)
``` | instruction | 0 | 97,559 | 18 | 195,118 |
No | output | 1 | 97,559 | 18 | 195,119 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Your friend has n cards.
You know that each card has a lowercase English letter on one side and a digit on the other.
Currently, your friend has laid out the cards on a table so only one side of each card is visible.
You would like to know if the following statement is true for cards that your friend owns: "If a card has a vowel on one side, then it has an even digit on the other side." More specifically, a vowel is one of 'a', 'e', 'i', 'o' or 'u', and even digit is one of '0', '2', '4', '6' or '8'.
For example, if a card has 'a' on one side, and '6' on the other side, then this statement is true for it. Also, the statement is true, for example, for a card with 'b' and '4', and for a card with 'b' and '3' (since the letter is not a vowel). The statement is false, for example, for card with 'e' and '5'. You are interested if the statement is true for all cards. In particular, if no card has a vowel, the statement is true.
To determine this, you can flip over some cards to reveal the other side. You would like to know what is the minimum number of cards you need to flip in the worst case in order to verify that the statement is true.
Input
The first and only line of input will contain a string s (1 ≤ |s| ≤ 50), denoting the sides of the cards that you can see on the table currently. Each character of s is either a lowercase English letter or a digit.
Output
Print a single integer, the minimum number of cards you must turn over to verify your claim.
Examples
Input
ee
Output
2
Input
z
Output
0
Input
0ay1
Output
2
Note
In the first sample, we must turn over both cards. Note that even though both cards have the same letter, they could possibly have different numbers on the other side.
In the second sample, we don't need to turn over any cards. The statement is vacuously true, since you know your friend has no cards with a vowel on them.
In the third sample, we need to flip the second and fourth cards.
Submitted Solution:
```
cards = input()
vowels = "aeiou02468"
total = 0
for c in cards:
if c in vowels:
total += 1
print(total)
``` | instruction | 0 | 97,560 | 18 | 195,120 |
No | output | 1 | 97,560 | 18 | 195,121 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Your friend has n cards.
You know that each card has a lowercase English letter on one side and a digit on the other.
Currently, your friend has laid out the cards on a table so only one side of each card is visible.
You would like to know if the following statement is true for cards that your friend owns: "If a card has a vowel on one side, then it has an even digit on the other side." More specifically, a vowel is one of 'a', 'e', 'i', 'o' or 'u', and even digit is one of '0', '2', '4', '6' or '8'.
For example, if a card has 'a' on one side, and '6' on the other side, then this statement is true for it. Also, the statement is true, for example, for a card with 'b' and '4', and for a card with 'b' and '3' (since the letter is not a vowel). The statement is false, for example, for card with 'e' and '5'. You are interested if the statement is true for all cards. In particular, if no card has a vowel, the statement is true.
To determine this, you can flip over some cards to reveal the other side. You would like to know what is the minimum number of cards you need to flip in the worst case in order to verify that the statement is true.
Input
The first and only line of input will contain a string s (1 ≤ |s| ≤ 50), denoting the sides of the cards that you can see on the table currently. Each character of s is either a lowercase English letter or a digit.
Output
Print a single integer, the minimum number of cards you must turn over to verify your claim.
Examples
Input
ee
Output
2
Input
z
Output
0
Input
0ay1
Output
2
Note
In the first sample, we must turn over both cards. Note that even though both cards have the same letter, they could possibly have different numbers on the other side.
In the second sample, we don't need to turn over any cards. The statement is vacuously true, since you know your friend has no cards with a vowel on them.
In the third sample, we need to flip the second and fourth cards.
Submitted Solution:
```
s = input()
cnt = 0
lis = ["a", "e", "i", "o", "u"]
for i in s:
if i in lis: cnt += 1
print(cnt)
``` | instruction | 0 | 97,561 | 18 | 195,122 |
No | output | 1 | 97,561 | 18 | 195,123 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a image with a height of H pixels and a width of W pixels. Each pixel is represented by a lowercase English letter. The pixel at the i-th row from the top and j-th column from the left is a_{ij}.
Put a box around this image and output the result. The box should consist of `#` and have a thickness of 1.
Constraints
* 1 ≤ H, W ≤ 100
* a_{ij} is a lowercase English letter.
Input
Input is given from Standard Input in the following format:
H W
a_{11} ... a_{1W}
:
a_{H1} ... a_{HW}
Output
Print the image surrounded by a box that consists of `#` and has a thickness of 1.
Examples
Input
2 3
abc
arc
Output
#####
#abc#
#arc#
#####
Input
1 1
z
Output
z# | instruction | 0 | 97,719 | 18 | 195,438 |
"Correct Solution:
```
H,W = map(int,input().split())
print('#'*(W+2))
for i in range(H):
pixel = input()
print(f'#{pixel}#')
print('#'*(W+2))
``` | output | 1 | 97,719 | 18 | 195,439 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a image with a height of H pixels and a width of W pixels. Each pixel is represented by a lowercase English letter. The pixel at the i-th row from the top and j-th column from the left is a_{ij}.
Put a box around this image and output the result. The box should consist of `#` and have a thickness of 1.
Constraints
* 1 ≤ H, W ≤ 100
* a_{ij} is a lowercase English letter.
Input
Input is given from Standard Input in the following format:
H W
a_{11} ... a_{1W}
:
a_{H1} ... a_{HW}
Output
Print the image surrounded by a box that consists of `#` and has a thickness of 1.
Examples
Input
2 3
abc
arc
Output
#####
#abc#
#arc#
#####
Input
1 1
z
Output
z# | instruction | 0 | 97,720 | 18 | 195,440 |
"Correct Solution:
```
H,W = map(int,input().split())
print("#"*(W+2))
for i in range(H):
row = input()
print("#"+row+"#")
print("#"*(W+2))
``` | output | 1 | 97,720 | 18 | 195,441 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a image with a height of H pixels and a width of W pixels. Each pixel is represented by a lowercase English letter. The pixel at the i-th row from the top and j-th column from the left is a_{ij}.
Put a box around this image and output the result. The box should consist of `#` and have a thickness of 1.
Constraints
* 1 ≤ H, W ≤ 100
* a_{ij} is a lowercase English letter.
Input
Input is given from Standard Input in the following format:
H W
a_{11} ... a_{1W}
:
a_{H1} ... a_{HW}
Output
Print the image surrounded by a box that consists of `#` and has a thickness of 1.
Examples
Input
2 3
abc
arc
Output
#####
#abc#
#arc#
#####
Input
1 1
z
Output
z# | instruction | 0 | 97,721 | 18 | 195,442 |
"Correct Solution:
```
H,W=map(int,input().split())
A=["#"*(W+2)]+["#"+input()+"#" for i in range(H)]+["#"*(W+2)]
for a in A:
print(*a,sep="")
``` | output | 1 | 97,721 | 18 | 195,443 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a image with a height of H pixels and a width of W pixels. Each pixel is represented by a lowercase English letter. The pixel at the i-th row from the top and j-th column from the left is a_{ij}.
Put a box around this image and output the result. The box should consist of `#` and have a thickness of 1.
Constraints
* 1 ≤ H, W ≤ 100
* a_{ij} is a lowercase English letter.
Input
Input is given from Standard Input in the following format:
H W
a_{11} ... a_{1W}
:
a_{H1} ... a_{HW}
Output
Print the image surrounded by a box that consists of `#` and has a thickness of 1.
Examples
Input
2 3
abc
arc
Output
#####
#abc#
#arc#
#####
Input
1 1
z
Output
z# | instruction | 0 | 97,722 | 18 | 195,444 |
"Correct Solution:
```
h, w = map(int, input().split())
print('\n'.join(['#' * (w+2)] + ['#' + input() + '#' for _ in range(h)] + ['#' * (w+2)]))
``` | output | 1 | 97,722 | 18 | 195,445 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a image with a height of H pixels and a width of W pixels. Each pixel is represented by a lowercase English letter. The pixel at the i-th row from the top and j-th column from the left is a_{ij}.
Put a box around this image and output the result. The box should consist of `#` and have a thickness of 1.
Constraints
* 1 ≤ H, W ≤ 100
* a_{ij} is a lowercase English letter.
Input
Input is given from Standard Input in the following format:
H W
a_{11} ... a_{1W}
:
a_{H1} ... a_{HW}
Output
Print the image surrounded by a box that consists of `#` and has a thickness of 1.
Examples
Input
2 3
abc
arc
Output
#####
#abc#
#arc#
#####
Input
1 1
z
Output
z# | instruction | 0 | 97,723 | 18 | 195,446 |
"Correct Solution:
```
h, w = map(int, input().split())
a = ['#'*(w+2)]+['#'+input()+"#" for _ in range(h)]+['#'*(w+2)]
for x in a:
print(x)
``` | output | 1 | 97,723 | 18 | 195,447 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a image with a height of H pixels and a width of W pixels. Each pixel is represented by a lowercase English letter. The pixel at the i-th row from the top and j-th column from the left is a_{ij}.
Put a box around this image and output the result. The box should consist of `#` and have a thickness of 1.
Constraints
* 1 ≤ H, W ≤ 100
* a_{ij} is a lowercase English letter.
Input
Input is given from Standard Input in the following format:
H W
a_{11} ... a_{1W}
:
a_{H1} ... a_{HW}
Output
Print the image surrounded by a box that consists of `#` and has a thickness of 1.
Examples
Input
2 3
abc
arc
Output
#####
#abc#
#arc#
#####
Input
1 1
z
Output
z# | instruction | 0 | 97,724 | 18 | 195,448 |
"Correct Solution:
```
h,w=map(int,input().split())
A=["#"+input()+"#" for i in range(h)]
A=["#"*(w+2)]+A+["#"*(w+2)]
print(*A,sep="\n")
``` | output | 1 | 97,724 | 18 | 195,449 |
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