message stringlengths 2 11.9k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 137 108k | cluster float64 18 18 | __index_level_0__ int64 274 217k |
|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
Write a program which replace all the lower-case letters of a given text with the corresponding captital letters.
Input
A text including lower-case letters, periods, and space is given in a line. The number of characters in the text is less than or equal to 200.
Output
Print the converted text.
Example
Input
this is a pen.
Output
THIS IS A PEN. | instruction | 0 | 102,804 | 18 | 205,608 |
"Correct Solution:
```
print(''.join(list(map(lambda i: i.upper(),input()))))
``` | output | 1 | 102,804 | 18 | 205,609 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which replace all the lower-case letters of a given text with the corresponding captital letters.
Input
A text including lower-case letters, periods, and space is given in a line. The number of characters in the text is less than or equal to 200.
Output
Print the converted text.
Example
Input
this is a pen.
Output
THIS IS A PEN. | instruction | 0 | 102,805 | 18 | 205,610 |
"Correct Solution:
```
from functools import reduce
from operator import add
print(reduce(add, map(str.capitalize, input()[:]), ''))
``` | output | 1 | 102,805 | 18 | 205,611 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which replace all the lower-case letters of a given text with the corresponding captital letters.
Input
A text including lower-case letters, periods, and space is given in a line. The number of characters in the text is less than or equal to 200.
Output
Print the converted text.
Example
Input
this is a pen.
Output
THIS IS A PEN. | instruction | 0 | 102,806 | 18 | 205,612 |
"Correct Solution:
```
import math
def run():
text = input().strip()
print(text.upper())
if __name__ == '__main__':
run()
``` | output | 1 | 102,806 | 18 | 205,613 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which replace all the lower-case letters of a given text with the corresponding captital letters.
Input
A text including lower-case letters, periods, and space is given in a line. The number of characters in the text is less than or equal to 200.
Output
Print the converted text.
Example
Input
this is a pen.
Output
THIS IS A PEN. | instruction | 0 | 102,807 | 18 | 205,614 |
"Correct Solution:
```
a=input()
a=str.upper(a)
print(a)
``` | output | 1 | 102,807 | 18 | 205,615 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which replace all the lower-case letters of a given text with the corresponding captital letters.
Input
A text including lower-case letters, periods, and space is given in a line. The number of characters in the text is less than or equal to 200.
Output
Print the converted text.
Example
Input
this is a pen.
Output
THIS IS A PEN. | instruction | 0 | 102,808 | 18 | 205,616 |
"Correct Solution:
```
l = str(input())
print(str.upper(l))
``` | output | 1 | 102,808 | 18 | 205,617 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which replace all the lower-case letters of a given text with the corresponding captital letters.
Input
A text including lower-case letters, periods, and space is given in a line. The number of characters in the text is less than or equal to 200.
Output
Print the converted text.
Example
Input
this is a pen.
Output
THIS IS A PEN. | instruction | 0 | 102,809 | 18 | 205,618 |
"Correct Solution:
```
a=str(input())
b=str.upper(a)
print(b)
``` | output | 1 | 102,809 | 18 | 205,619 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which replace all the lower-case letters of a given text with the corresponding captital letters.
Input
A text including lower-case letters, periods, and space is given in a line. The number of characters in the text is less than or equal to 200.
Output
Print the converted text.
Example
Input
this is a pen.
Output
THIS IS A PEN. | instruction | 0 | 102,810 | 18 | 205,620 |
"Correct Solution:
```
A=input()
print(A.upper())
``` | output | 1 | 102,810 | 18 | 205,621 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which replace all the lower-case letters of a given text with the corresponding captital letters.
Input
A text including lower-case letters, periods, and space is given in a line. The number of characters in the text is less than or equal to 200.
Output
Print the converted text.
Example
Input
this is a pen.
Output
THIS IS A PEN.
Submitted Solution:
```
L = list(input())
LL = []
for i in L:
LL.append(i.upper())
print( "".join(LL) )
``` | instruction | 0 | 102,811 | 18 | 205,622 |
Yes | output | 1 | 102,811 | 18 | 205,623 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which replace all the lower-case letters of a given text with the corresponding captital letters.
Input
A text including lower-case letters, periods, and space is given in a line. The number of characters in the text is less than or equal to 200.
Output
Print the converted text.
Example
Input
this is a pen.
Output
THIS IS A PEN.
Submitted Solution:
```
import sys
a = 'abcdefghijklmnopqrstuvwxyz'
b = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
for s in sys.stdin:
t= s[:-1].translate(str.maketrans(a,b))
print(t)
``` | instruction | 0 | 102,812 | 18 | 205,624 |
Yes | output | 1 | 102,812 | 18 | 205,625 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which replace all the lower-case letters of a given text with the corresponding captital letters.
Input
A text including lower-case letters, periods, and space is given in a line. The number of characters in the text is less than or equal to 200.
Output
Print the converted text.
Example
Input
this is a pen.
Output
THIS IS A PEN.
Submitted Solution:
```
strings = input()
print(strings.upper())
``` | instruction | 0 | 102,813 | 18 | 205,626 |
Yes | output | 1 | 102,813 | 18 | 205,627 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which replace all the lower-case letters of a given text with the corresponding captital letters.
Input
A text including lower-case letters, periods, and space is given in a line. The number of characters in the text is less than or equal to 200.
Output
Print the converted text.
Example
Input
this is a pen.
Output
THIS IS A PEN.
Submitted Solution:
```
s = str(input())
print(s.upper())
``` | instruction | 0 | 102,814 | 18 | 205,628 |
Yes | output | 1 | 102,814 | 18 | 205,629 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which replace all the lower-case letters of a given text with the corresponding captital letters.
Input
A text including lower-case letters, periods, and space is given in a line. The number of characters in the text is less than or equal to 200.
Output
Print the converted text.
Example
Input
this is a pen.
Output
THIS IS A PEN.
Submitted Solution:
```
print(' '.join(list(map(lambda i: i.upper(),input().split()))))
``` | instruction | 0 | 102,815 | 18 | 205,630 |
No | output | 1 | 102,815 | 18 | 205,631 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which replace all the lower-case letters of a given text with the corresponding captital letters.
Input
A text including lower-case letters, periods, and space is given in a line. The number of characters in the text is less than or equal to 200.
Output
Print the converted text.
Example
Input
this is a pen.
Output
THIS IS A PEN.
Submitted Solution:
```
# coding=utf-8
sentence = input()
sentence.upper()
print(sentence)
``` | instruction | 0 | 102,816 | 18 | 205,632 |
No | output | 1 | 102,816 | 18 | 205,633 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which replace all the lower-case letters of a given text with the corresponding captital letters.
Input
A text including lower-case letters, periods, and space is given in a line. The number of characters in the text is less than or equal to 200.
Output
Print the converted text.
Example
Input
this is a pen.
Output
THIS IS A PEN.
Submitted Solution:
```
def Capitalize():
for i in sys.stdin:
print(i.upper())
``` | instruction | 0 | 102,817 | 18 | 205,634 |
No | output | 1 | 102,817 | 18 | 205,635 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which replace all the lower-case letters of a given text with the corresponding captital letters.
Input
A text including lower-case letters, periods, and space is given in a line. The number of characters in the text is less than or equal to 200.
Output
Print the converted text.
Example
Input
this is a pen.
Output
THIS IS A PEN.
Submitted Solution:
```
# -*- coding: utf-8 -*-
def main(_text: str):
print(_text.upper(), end='')
while True:
try:
text = input()
except:
break
main(text)
``` | instruction | 0 | 102,818 | 18 | 205,636 |
No | output | 1 | 102,818 | 18 | 205,637 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Constanze is the smartest girl in her village but she has bad eyesight.
One day, she was able to invent an incredible machine! When you pronounce letters, the machine will inscribe them onto a piece of paper. For example, if you pronounce 'c', 'o', 'd', and 'e' in that order, then the machine will inscribe "code" onto the paper. Thanks to this machine, she can finally write messages without using her glasses.
However, her dumb friend Akko decided to play a prank on her. Akko tinkered with the machine so that if you pronounce 'w', it will inscribe "uu" instead of "w", and if you pronounce 'm', it will inscribe "nn" instead of "m"! Since Constanze had bad eyesight, she was not able to realize what Akko did.
The rest of the letters behave the same as before: if you pronounce any letter besides 'w' and 'm', the machine will just inscribe it onto a piece of paper.
The next day, I received a letter in my mailbox. I can't understand it so I think it's either just some gibberish from Akko, or Constanze made it using her machine. But since I know what Akko did, I can just list down all possible strings that Constanze's machine would have turned into the message I got and see if anything makes sense.
But I need to know how much paper I will need, and that's why I'm asking you for help. Tell me the number of strings that Constanze's machine would've turned into the message I got.
But since this number can be quite large, tell me instead its remainder when divided by 10^9+7.
If there are no strings that Constanze's machine would've turned into the message I got, then print 0.
Input
Input consists of a single line containing a string s (1 ≤ |s| ≤ 10^5) — the received message. s contains only lowercase Latin letters.
Output
Print a single integer — the number of strings that Constanze's machine would've turned into the message s, modulo 10^9+7.
Examples
Input
ouuokarinn
Output
4
Input
banana
Output
1
Input
nnn
Output
3
Input
amanda
Output
0
Note
For the first example, the candidate strings are the following: "ouuokarinn", "ouuokarim", "owokarim", and "owokarinn".
For the second example, there is only one: "banana".
For the third example, the candidate strings are the following: "nm", "mn" and "nnn".
For the last example, there are no candidate strings that the machine can turn into "amanda", since the machine won't inscribe 'm'.
Submitted Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,copy,functools
# import time,random,resource
# sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 10**9+7
mod2 = 998244353
dd = [(-1,0),(0,1),(1,0),(0,-1)]
ddn = [(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)]
def LI(): return list(map(int, sys.stdin.readline().split()))
def LLI(): return [list(map(int, l.split())) for l in sys.stdin.readlines()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)
def pe(s): return print(str(s), file=sys.stderr)
def JA(a, sep): return sep.join(map(str, a))
def JAA(a, s, t): return s.join(t.join(map(str, b)) for b in a)
def IF(c, t, f): return t if c else f
def YES(c): return IF(c, "YES", "NO")
def Yes(c): return IF(c, "Yes", "No")
def main():
t = 1
rr = []
for _ in range(t):
s = S()
dp = [1,0,0]
for c in s:
np = [0] * 3
t = sum(dp) % mod
if c == 'u':
np[0] = dp[1]
np[1] = t
elif c == 'n':
np[0] = dp[2]
np[2] = t
elif c in 'mw':
dp = [0]
break
else:
np[0] = t
dp = np
rr.append(sum(dp) % mod)
return JA(rr, "\n")
print(main())
``` | instruction | 0 | 103,018 | 18 | 206,036 |
Yes | output | 1 | 103,018 | 18 | 206,037 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Constanze is the smartest girl in her village but she has bad eyesight.
One day, she was able to invent an incredible machine! When you pronounce letters, the machine will inscribe them onto a piece of paper. For example, if you pronounce 'c', 'o', 'd', and 'e' in that order, then the machine will inscribe "code" onto the paper. Thanks to this machine, she can finally write messages without using her glasses.
However, her dumb friend Akko decided to play a prank on her. Akko tinkered with the machine so that if you pronounce 'w', it will inscribe "uu" instead of "w", and if you pronounce 'm', it will inscribe "nn" instead of "m"! Since Constanze had bad eyesight, she was not able to realize what Akko did.
The rest of the letters behave the same as before: if you pronounce any letter besides 'w' and 'm', the machine will just inscribe it onto a piece of paper.
The next day, I received a letter in my mailbox. I can't understand it so I think it's either just some gibberish from Akko, or Constanze made it using her machine. But since I know what Akko did, I can just list down all possible strings that Constanze's machine would have turned into the message I got and see if anything makes sense.
But I need to know how much paper I will need, and that's why I'm asking you for help. Tell me the number of strings that Constanze's machine would've turned into the message I got.
But since this number can be quite large, tell me instead its remainder when divided by 10^9+7.
If there are no strings that Constanze's machine would've turned into the message I got, then print 0.
Input
Input consists of a single line containing a string s (1 ≤ |s| ≤ 10^5) — the received message. s contains only lowercase Latin letters.
Output
Print a single integer — the number of strings that Constanze's machine would've turned into the message s, modulo 10^9+7.
Examples
Input
ouuokarinn
Output
4
Input
banana
Output
1
Input
nnn
Output
3
Input
amanda
Output
0
Note
For the first example, the candidate strings are the following: "ouuokarinn", "ouuokarim", "owokarim", and "owokarinn".
For the second example, there is only one: "banana".
For the third example, the candidate strings are the following: "nm", "mn" and "nnn".
For the last example, there are no candidate strings that the machine can turn into "amanda", since the machine won't inscribe 'm'.
Submitted Solution:
```
MOD = 1000000007
ii = lambda: int(input())
si = lambda: input()
dgl = lambda: list(map(int, input()))
f = lambda: list(map(int, input().split()))
il = lambda: list(map(int, input().split()))
ls = lambda: list(input())
s=si()
n=len(s)
dp=[0]*(n+2)
dp[0]=1
dp[1]=1 if not s[0] in ['m','w'] else 0
for i in range(2,n+1):
if s[i-1] in ['m','w']:
exit(print(0))
dp[i]=dp[i-1]
if s[i-1]=='n' or s[i-1]=='u':
if s[i-2]==s[i-1]:
dp[i]+=dp[i-2]
dp[i]%=MOD
print(dp[n])
``` | instruction | 0 | 103,019 | 18 | 206,038 |
Yes | output | 1 | 103,019 | 18 | 206,039 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Constanze is the smartest girl in her village but she has bad eyesight.
One day, she was able to invent an incredible machine! When you pronounce letters, the machine will inscribe them onto a piece of paper. For example, if you pronounce 'c', 'o', 'd', and 'e' in that order, then the machine will inscribe "code" onto the paper. Thanks to this machine, she can finally write messages without using her glasses.
However, her dumb friend Akko decided to play a prank on her. Akko tinkered with the machine so that if you pronounce 'w', it will inscribe "uu" instead of "w", and if you pronounce 'm', it will inscribe "nn" instead of "m"! Since Constanze had bad eyesight, she was not able to realize what Akko did.
The rest of the letters behave the same as before: if you pronounce any letter besides 'w' and 'm', the machine will just inscribe it onto a piece of paper.
The next day, I received a letter in my mailbox. I can't understand it so I think it's either just some gibberish from Akko, or Constanze made it using her machine. But since I know what Akko did, I can just list down all possible strings that Constanze's machine would have turned into the message I got and see if anything makes sense.
But I need to know how much paper I will need, and that's why I'm asking you for help. Tell me the number of strings that Constanze's machine would've turned into the message I got.
But since this number can be quite large, tell me instead its remainder when divided by 10^9+7.
If there are no strings that Constanze's machine would've turned into the message I got, then print 0.
Input
Input consists of a single line containing a string s (1 ≤ |s| ≤ 10^5) — the received message. s contains only lowercase Latin letters.
Output
Print a single integer — the number of strings that Constanze's machine would've turned into the message s, modulo 10^9+7.
Examples
Input
ouuokarinn
Output
4
Input
banana
Output
1
Input
nnn
Output
3
Input
amanda
Output
0
Note
For the first example, the candidate strings are the following: "ouuokarinn", "ouuokarim", "owokarim", and "owokarinn".
For the second example, there is only one: "banana".
For the third example, the candidate strings are the following: "nm", "mn" and "nnn".
For the last example, there are no candidate strings that the machine can turn into "amanda", since the machine won't inscribe 'm'.
Submitted Solution:
```
n = input()
count = 1
for i in n:
if i in ['w', 'm']:
print(0)
exit()
dp = [0] * (len(n) + 1)
dp[0] = 1
dp[1] = 1
for i in range(2, len(n) + 1):
dp[i] = dp[i - 1]
if n[i - 1] == n[i - 2] and n[i - 1] in ['u', 'n']:
dp[i] = (dp[i] + dp[i - 2]) % 1000000007
print(dp[len(n)])
``` | instruction | 0 | 103,020 | 18 | 206,040 |
Yes | output | 1 | 103,020 | 18 | 206,041 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Constanze is the smartest girl in her village but she has bad eyesight.
One day, she was able to invent an incredible machine! When you pronounce letters, the machine will inscribe them onto a piece of paper. For example, if you pronounce 'c', 'o', 'd', and 'e' in that order, then the machine will inscribe "code" onto the paper. Thanks to this machine, she can finally write messages without using her glasses.
However, her dumb friend Akko decided to play a prank on her. Akko tinkered with the machine so that if you pronounce 'w', it will inscribe "uu" instead of "w", and if you pronounce 'm', it will inscribe "nn" instead of "m"! Since Constanze had bad eyesight, she was not able to realize what Akko did.
The rest of the letters behave the same as before: if you pronounce any letter besides 'w' and 'm', the machine will just inscribe it onto a piece of paper.
The next day, I received a letter in my mailbox. I can't understand it so I think it's either just some gibberish from Akko, or Constanze made it using her machine. But since I know what Akko did, I can just list down all possible strings that Constanze's machine would have turned into the message I got and see if anything makes sense.
But I need to know how much paper I will need, and that's why I'm asking you for help. Tell me the number of strings that Constanze's machine would've turned into the message I got.
But since this number can be quite large, tell me instead its remainder when divided by 10^9+7.
If there are no strings that Constanze's machine would've turned into the message I got, then print 0.
Input
Input consists of a single line containing a string s (1 ≤ |s| ≤ 10^5) — the received message. s contains only lowercase Latin letters.
Output
Print a single integer — the number of strings that Constanze's machine would've turned into the message s, modulo 10^9+7.
Examples
Input
ouuokarinn
Output
4
Input
banana
Output
1
Input
nnn
Output
3
Input
amanda
Output
0
Note
For the first example, the candidate strings are the following: "ouuokarinn", "ouuokarim", "owokarim", and "owokarinn".
For the second example, there is only one: "banana".
For the third example, the candidate strings are the following: "nm", "mn" and "nnn".
For the last example, there are no candidate strings that the machine can turn into "amanda", since the machine won't inscribe 'm'.
Submitted Solution:
```
import math
import bisect
import copy
from collections import defaultdict
from collections import OrderedDict
#for _ in range(int(input())):
#n = int(input())
s = list(input())
n = len(s)
#print(s)
#a,b,n = map(int,input().split())
#ar = list(map(int,input().split()))
#br = list(map(int,input().split()))
c = []
i = 0
x = 1
while i < n :
while i < n-1 and s[i] == s[i+1] == 'u':
x += 1
i += 1
if i == n-1 or s[i] != s[i+1]:
break
if x>1:
c.append(x)
x = 1
while i < n-1 and s[i] == s[i+1] == 'n':
x += 1
i += 1
if i == n-1 or s[i] != s[i+1]:
break
if x>1:
c.append(x)
x = 1
if x == 1:
i += 1
fibo = [1,2]
#print(c,fibo)
ans = 0
if n == 1:
if s[0] == 'w' or s[0] == 'm':
ans = -1
else:
for i in range(n):
if i== 0:
if s[i] =='w' and s[i] != s[i+1]:
ans = -1
break
elif s[i] == 'm' and s[i] != s[i+1]:
ans = -1
break
elif i == n-1:
if s[i] =='w' and s[i] != s[i-1]:
ans = -1
break
elif s[i] == 'm' and s[i] != s[i-1]:
ans = -1
break
else:
if s[i] == 'w' and s[i-1] != 'w' and s[i+1] != 'w':
ans = -1
break
elif s[i] == 'm' and s[i-1]!= 'm' and s[i-1] != 'm':
ans = -1
break
if ans == -1:
print(0)
else:
if len(c) == 0:
print(1)
else:
for i in range(2,max(c)):
fibo.append((fibo[i-2] + fibo[i-1])%int(1e9 + 7))
ans = 1
for j in range(len(c)):
ans *= fibo[c[j]-1]
ans %= int(1e9 + 7)
print(ans)
"""
stuff you should look for
* int overflow, array bounds
* special cases (n=1?)
* do smth instead of nothing and stay organized
* WRITE STUFF DOWN
* DON'T GET STUCK ON ONE APPROACH
"""
``` | instruction | 0 | 103,021 | 18 | 206,042 |
Yes | output | 1 | 103,021 | 18 | 206,043 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Constanze is the smartest girl in her village but she has bad eyesight.
One day, she was able to invent an incredible machine! When you pronounce letters, the machine will inscribe them onto a piece of paper. For example, if you pronounce 'c', 'o', 'd', and 'e' in that order, then the machine will inscribe "code" onto the paper. Thanks to this machine, she can finally write messages without using her glasses.
However, her dumb friend Akko decided to play a prank on her. Akko tinkered with the machine so that if you pronounce 'w', it will inscribe "uu" instead of "w", and if you pronounce 'm', it will inscribe "nn" instead of "m"! Since Constanze had bad eyesight, she was not able to realize what Akko did.
The rest of the letters behave the same as before: if you pronounce any letter besides 'w' and 'm', the machine will just inscribe it onto a piece of paper.
The next day, I received a letter in my mailbox. I can't understand it so I think it's either just some gibberish from Akko, or Constanze made it using her machine. But since I know what Akko did, I can just list down all possible strings that Constanze's machine would have turned into the message I got and see if anything makes sense.
But I need to know how much paper I will need, and that's why I'm asking you for help. Tell me the number of strings that Constanze's machine would've turned into the message I got.
But since this number can be quite large, tell me instead its remainder when divided by 10^9+7.
If there are no strings that Constanze's machine would've turned into the message I got, then print 0.
Input
Input consists of a single line containing a string s (1 ≤ |s| ≤ 10^5) — the received message. s contains only lowercase Latin letters.
Output
Print a single integer — the number of strings that Constanze's machine would've turned into the message s, modulo 10^9+7.
Examples
Input
ouuokarinn
Output
4
Input
banana
Output
1
Input
nnn
Output
3
Input
amanda
Output
0
Note
For the first example, the candidate strings are the following: "ouuokarinn", "ouuokarim", "owokarim", and "owokarinn".
For the second example, there is only one: "banana".
For the third example, the candidate strings are the following: "nm", "mn" and "nnn".
For the last example, there are no candidate strings that the machine can turn into "amanda", since the machine won't inscribe 'm'.
Submitted Solution:
```
mas = [0,1,2]
b = 0
for i in range(3,10**5 + 1):
mas.append((mas[i-1] + mas[i-2])%(10**9 + 7))
ans = 1
s = input()
f = -1
for i in range(len(s)):
if i > f:
if i < len(s) and s[i] == 'n':
lans = 0
while i < len(s) and s[i] == 'n':
lans += 1
i += 1
ans *= mas[lans]
ans = ans % (10**9 + 7)
if i < len(s) and s[i] == 'u':
lans = 0
while i < len(s) and s[i] == 'u':
lans += 1
i += 1
ans *= mas[lans]
ans = ans % (10**9 + 7)
if i < len(s) and (s[i] == 'm' or s[i] == 'w'):
b = 1
break
f = i
if b == 1:
print(0)
else:
print(ans % (10**9 + 7))
``` | instruction | 0 | 103,022 | 18 | 206,044 |
No | output | 1 | 103,022 | 18 | 206,045 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Constanze is the smartest girl in her village but she has bad eyesight.
One day, she was able to invent an incredible machine! When you pronounce letters, the machine will inscribe them onto a piece of paper. For example, if you pronounce 'c', 'o', 'd', and 'e' in that order, then the machine will inscribe "code" onto the paper. Thanks to this machine, she can finally write messages without using her glasses.
However, her dumb friend Akko decided to play a prank on her. Akko tinkered with the machine so that if you pronounce 'w', it will inscribe "uu" instead of "w", and if you pronounce 'm', it will inscribe "nn" instead of "m"! Since Constanze had bad eyesight, she was not able to realize what Akko did.
The rest of the letters behave the same as before: if you pronounce any letter besides 'w' and 'm', the machine will just inscribe it onto a piece of paper.
The next day, I received a letter in my mailbox. I can't understand it so I think it's either just some gibberish from Akko, or Constanze made it using her machine. But since I know what Akko did, I can just list down all possible strings that Constanze's machine would have turned into the message I got and see if anything makes sense.
But I need to know how much paper I will need, and that's why I'm asking you for help. Tell me the number of strings that Constanze's machine would've turned into the message I got.
But since this number can be quite large, tell me instead its remainder when divided by 10^9+7.
If there are no strings that Constanze's machine would've turned into the message I got, then print 0.
Input
Input consists of a single line containing a string s (1 ≤ |s| ≤ 10^5) — the received message. s contains only lowercase Latin letters.
Output
Print a single integer — the number of strings that Constanze's machine would've turned into the message s, modulo 10^9+7.
Examples
Input
ouuokarinn
Output
4
Input
banana
Output
1
Input
nnn
Output
3
Input
amanda
Output
0
Note
For the first example, the candidate strings are the following: "ouuokarinn", "ouuokarim", "owokarim", and "owokarinn".
For the second example, there is only one: "banana".
For the third example, the candidate strings are the following: "nm", "mn" and "nnn".
For the last example, there are no candidate strings that the machine can turn into "amanda", since the machine won't inscribe 'm'.
Submitted Solution:
```
from sys import stdin,stdout
mod=10**9 + 7
s=input().rstrip()
s=[ i for i in s]
n=len(s)
dp=[1]*(n)
if 'm' in s or 'w' in s:
print(0)
exit()
if len(s)==2:
if s[0]=='u' and s[1]=='u':
print(2)
elif s[0]=='n' and s[0]=='n':
print(2)
else:
print(1)
exit()
dp[0]=0
if len(s)>2:
if s[0]==s[1] and (s[0]=='u' or s[0]=='n'):
dp[0]=1
for i in range(2,len(s)):
dp[i]=dp[i-1]
if s[i]=='n' and s[i-1]=='n':
dp[i]=max(dp[i-2]+2,dp[i])
if s[i]=='u' and s[i-1]=='u':
dp[i]=max(dp[i-2]+2,dp[i])
print(dp[n-1]%mod)
``` | instruction | 0 | 103,023 | 18 | 206,046 |
No | output | 1 | 103,023 | 18 | 206,047 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Constanze is the smartest girl in her village but she has bad eyesight.
One day, she was able to invent an incredible machine! When you pronounce letters, the machine will inscribe them onto a piece of paper. For example, if you pronounce 'c', 'o', 'd', and 'e' in that order, then the machine will inscribe "code" onto the paper. Thanks to this machine, she can finally write messages without using her glasses.
However, her dumb friend Akko decided to play a prank on her. Akko tinkered with the machine so that if you pronounce 'w', it will inscribe "uu" instead of "w", and if you pronounce 'm', it will inscribe "nn" instead of "m"! Since Constanze had bad eyesight, she was not able to realize what Akko did.
The rest of the letters behave the same as before: if you pronounce any letter besides 'w' and 'm', the machine will just inscribe it onto a piece of paper.
The next day, I received a letter in my mailbox. I can't understand it so I think it's either just some gibberish from Akko, or Constanze made it using her machine. But since I know what Akko did, I can just list down all possible strings that Constanze's machine would have turned into the message I got and see if anything makes sense.
But I need to know how much paper I will need, and that's why I'm asking you for help. Tell me the number of strings that Constanze's machine would've turned into the message I got.
But since this number can be quite large, tell me instead its remainder when divided by 10^9+7.
If there are no strings that Constanze's machine would've turned into the message I got, then print 0.
Input
Input consists of a single line containing a string s (1 ≤ |s| ≤ 10^5) — the received message. s contains only lowercase Latin letters.
Output
Print a single integer — the number of strings that Constanze's machine would've turned into the message s, modulo 10^9+7.
Examples
Input
ouuokarinn
Output
4
Input
banana
Output
1
Input
nnn
Output
3
Input
amanda
Output
0
Note
For the first example, the candidate strings are the following: "ouuokarinn", "ouuokarim", "owokarim", and "owokarinn".
For the second example, there is only one: "banana".
For the third example, the candidate strings are the following: "nm", "mn" and "nnn".
For the last example, there are no candidate strings that the machine can turn into "amanda", since the machine won't inscribe 'm'.
Submitted Solution:
```
s=input()
dp=[0]*(len(s))
dp[0]=1
temp=0
for i in range(1,len(s)):
if(s[i]=='w' or s[i]=='m'):
temp=1
break
elif((s[i]=='u' and s[i-1]=='u') or (s[i]=='n' and s[i-1]=='n')):
if(i!=1):
dp[i]=dp[i-1]+dp[i-2]
else:
dp[i]=dp[i-1]+1
else:
dp[i]=dp[i-1]
# print(dp)
if(temp==1):
print(0)
else:
print(dp[len(s)-1])
``` | instruction | 0 | 103,024 | 18 | 206,048 |
No | output | 1 | 103,024 | 18 | 206,049 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Constanze is the smartest girl in her village but she has bad eyesight.
One day, she was able to invent an incredible machine! When you pronounce letters, the machine will inscribe them onto a piece of paper. For example, if you pronounce 'c', 'o', 'd', and 'e' in that order, then the machine will inscribe "code" onto the paper. Thanks to this machine, she can finally write messages without using her glasses.
However, her dumb friend Akko decided to play a prank on her. Akko tinkered with the machine so that if you pronounce 'w', it will inscribe "uu" instead of "w", and if you pronounce 'm', it will inscribe "nn" instead of "m"! Since Constanze had bad eyesight, she was not able to realize what Akko did.
The rest of the letters behave the same as before: if you pronounce any letter besides 'w' and 'm', the machine will just inscribe it onto a piece of paper.
The next day, I received a letter in my mailbox. I can't understand it so I think it's either just some gibberish from Akko, or Constanze made it using her machine. But since I know what Akko did, I can just list down all possible strings that Constanze's machine would have turned into the message I got and see if anything makes sense.
But I need to know how much paper I will need, and that's why I'm asking you for help. Tell me the number of strings that Constanze's machine would've turned into the message I got.
But since this number can be quite large, tell me instead its remainder when divided by 10^9+7.
If there are no strings that Constanze's machine would've turned into the message I got, then print 0.
Input
Input consists of a single line containing a string s (1 ≤ |s| ≤ 10^5) — the received message. s contains only lowercase Latin letters.
Output
Print a single integer — the number of strings that Constanze's machine would've turned into the message s, modulo 10^9+7.
Examples
Input
ouuokarinn
Output
4
Input
banana
Output
1
Input
nnn
Output
3
Input
amanda
Output
0
Note
For the first example, the candidate strings are the following: "ouuokarinn", "ouuokarim", "owokarim", and "owokarinn".
For the second example, there is only one: "banana".
For the third example, the candidate strings are the following: "nm", "mn" and "nnn".
For the last example, there are no candidate strings that the machine can turn into "amanda", since the machine won't inscribe 'm'.
Submitted Solution:
```
S = input()
N = len(S)
out = 1
mod = (10**9)+7
"""def f(num):
if num%6 == 1:
return 1
elif num%6 == 2:
return 2
elif num%6 == 3:
return 1
elif num%6 == 4:
return (10**9)+6
elif num%6 == 5:
return (10**9) +5
else:
return (10**9)+6"""
f = [0 for a in range(10**5)]
f[1] = 1
f[2] = 2
for b in range(3, (10**5)):
f[b] = ((f[b-1]%mod)+(f[b-2]%mod))%mod
for i in range(N):
if i < N and S[i] == "u":
c = 1
i += 1
while i < N and S[i] == "u":
c += 1
i += 1
out = ((out%mod)*(f[c]%mod))%mod
if i == N:
break
if i < N and S[i] == "n":
c = 1
i += 1
while i < N and S[i] == "n":
c += 1
i += 1
out = ((out%mod)*(f[c]%mod))%mod
if i == N:
break
if i < N and (S[i] == "m" or S[i] == "w"):
out = 0
break
print(out)
``` | instruction | 0 | 103,025 | 18 | 206,050 |
No | output | 1 | 103,025 | 18 | 206,051 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This problem is different with easy version only by constraints on total answers length
It is an interactive problem
Venya joined a tour to the madhouse, in which orderlies play with patients the following game. Orderlies pick a string s of length n, consisting only of lowercase English letters. The player can ask two types of queries:
* ? l r – ask to list all substrings of s[l..r]. Substrings will be returned in random order, and in every substring, all characters will be randomly shuffled.
* ! s – guess the string picked by the orderlies. This query can be asked exactly once, after that the game will finish. If the string is guessed correctly, the player wins, otherwise he loses.
The player can ask no more than 3 queries of the first type.
To make it easier for the orderlies, there is an additional limitation: the total number of returned substrings in all queries of the first type must not exceed \left⌈ 0.777(n+1)^2 \right⌉ (⌈ x ⌉ is x rounded up).
Venya asked you to write a program, which will guess the string by interacting with the orderlies' program and acting by the game's rules.
Your program should immediately terminate after guessing the string using a query of the second type. In case your program guessed the string incorrectly, or it violated the game rules, it will receive verdict Wrong answer.
Note that in every test case the string is fixed beforehand and will not change during the game, which means that the interactor is not adaptive.
Input
First line contains number n (1 ≤ n ≤ 100) — the length of the picked string.
Interaction
You start the interaction by reading the number n.
To ask a query about a substring from l to r inclusively (1 ≤ l ≤ r ≤ n), you should output
? l r
on a separate line. After this, all substrings of s[l..r] will be returned in random order, each substring exactly once. In every returned substring all characters will be randomly shuffled.
In the case, if you ask an incorrect query, ask more than 3 queries of the first type or there will be more than \left⌈ 0.777(n+1)^2 \right⌉ substrings returned in total, you will receive verdict Wrong answer.
To guess the string s, you should output
! s
on a separate line.
After printing each query, do not forget to flush the output. Otherwise, you will get Idleness limit exceeded. To flush the output, you can use:
* fflush(stdout) or cout.flush() in C++;
* System.out.flush() in Java;
* flush(output) in Pascal;
* stdout.flush() in Python;
* see documentation for other languages.
If you received - (dash) as an answer to any query, you need to terminate your program with exit code 0 (for example, by calling exit(0)). This means that there was an error in the interaction protocol. If you don't terminate with exit code 0, you can receive any unsuccessful verdict.
Hack format
To hack a solution, use the following format:
The first line should contain one integer n (1 ≤ n ≤ 100) — the length of the string, and the following line should contain the string s.
Example
Input
4
a
aa
a
cb
b
c
c
Output
? 1 2
? 3 4
? 4 4
! aabc
Submitted Solution:
```
from sys import stdout
class String2:
def __init__(self, s, b=None):
if b is not None:
self.b = b
return
self.b = [0] * 26
for i in s:
self.b[ord(i) - ord('a')] += 1
def __add__(self, other):
b = self.b.copy()
for i in range(26):
b[i] += other.b[i]
return String2('', b)
def __sub__(self, other):
b = self.b.copy()
for i in range(26):
b[i] -= other.b[i]
return b
def __mul__(self, other):
ans = String2('', self.b)
for i in range(26):
ans.b[i] *= other
return ans
def req(l, r, k=0):
print('?', l, r)
v = [''.join(sorted(input())) for i in range((r - l + 1) * (r - l + 2) // 2)]
stdout.flush()
return v
def compute(v):
bukvi = [[0] * (n + 2) for _ in range(26)]
for el in v:
cur = len(el)
for e in el:
bukvi[ord(e) - ord('a')][cur] += 1
return bukvi
def compute2(bukvi):
bukvis = [set() for i in range(n + 2)]
for i in range(26):
prev = bukvi[i][1]
for j in range(1, n // 2 + n % 2 + 1):
while bukvi[i][j] != prev:
bukvis[j].add(chr(ord('a') + i))
prev += 1
return bukvis
def solve(va, va2):
for i in va2:
va.remove(i)
va.sort(key=len)
s = va[0]
for i in range(1, len(va)):
for j in range(26):
if va[i].count(chr(ord('a') + j)) != va[i - 1].count(chr(ord('a') + j)):
s += chr(ord('a') + j)
return s
def check(v, s, s2, f):
s3 = String2(v[0])
for i in range(1, len(v)):
s3 = s3 + String2(v[i])
le = len(v[0])
cur = String2('', String2('', f - String2(s)) - String2(s2)) * le
for i in range(le - 2):
cur = cur + (String2(s[i]) * (i + 1)) + (String2(s2[-i]) * (i + 1))
cur = cur + (String2(s[le - 2]) * (le - 1)) + (String2(s[le - 1]) * le)
e = cur - s3
for i in range(26):
if e[i]:
return chr(ord('a') + i)
def main():
va = req(1, n)
va2 = req(1, n // 2 + n % 2)
va3 = req(2, n // 2 + n % 2)
# bukvi2 = compute(va2)
# bukvi3 = compute(va3)
if n == 1:
print('!', va[0][0])
return
ma = [[] for i in range(n * 2)]
for i in va:
ma[len(i)].append(i)
a = String2(''.join(ma[1]))
s = solve(va2, va3)
s2 = ''
for i in range(2, n // 2 + 1):
s2 = check(ma[i], s, s2, a) + s2
se = String2('', a - String2(s)) - String2(s2)
for i in range(len(se)):
if se[i]:
s += chr(ord('a') + i)
break
print(s + s2)
n = int(input())
main()
``` | instruction | 0 | 103,042 | 18 | 206,084 |
No | output | 1 | 103,042 | 18 | 206,085 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This problem is different with easy version only by constraints on total answers length
It is an interactive problem
Venya joined a tour to the madhouse, in which orderlies play with patients the following game. Orderlies pick a string s of length n, consisting only of lowercase English letters. The player can ask two types of queries:
* ? l r – ask to list all substrings of s[l..r]. Substrings will be returned in random order, and in every substring, all characters will be randomly shuffled.
* ! s – guess the string picked by the orderlies. This query can be asked exactly once, after that the game will finish. If the string is guessed correctly, the player wins, otherwise he loses.
The player can ask no more than 3 queries of the first type.
To make it easier for the orderlies, there is an additional limitation: the total number of returned substrings in all queries of the first type must not exceed \left⌈ 0.777(n+1)^2 \right⌉ (⌈ x ⌉ is x rounded up).
Venya asked you to write a program, which will guess the string by interacting with the orderlies' program and acting by the game's rules.
Your program should immediately terminate after guessing the string using a query of the second type. In case your program guessed the string incorrectly, or it violated the game rules, it will receive verdict Wrong answer.
Note that in every test case the string is fixed beforehand and will not change during the game, which means that the interactor is not adaptive.
Input
First line contains number n (1 ≤ n ≤ 100) — the length of the picked string.
Interaction
You start the interaction by reading the number n.
To ask a query about a substring from l to r inclusively (1 ≤ l ≤ r ≤ n), you should output
? l r
on a separate line. After this, all substrings of s[l..r] will be returned in random order, each substring exactly once. In every returned substring all characters will be randomly shuffled.
In the case, if you ask an incorrect query, ask more than 3 queries of the first type or there will be more than \left⌈ 0.777(n+1)^2 \right⌉ substrings returned in total, you will receive verdict Wrong answer.
To guess the string s, you should output
! s
on a separate line.
After printing each query, do not forget to flush the output. Otherwise, you will get Idleness limit exceeded. To flush the output, you can use:
* fflush(stdout) or cout.flush() in C++;
* System.out.flush() in Java;
* flush(output) in Pascal;
* stdout.flush() in Python;
* see documentation for other languages.
If you received - (dash) as an answer to any query, you need to terminate your program with exit code 0 (for example, by calling exit(0)). This means that there was an error in the interaction protocol. If you don't terminate with exit code 0, you can receive any unsuccessful verdict.
Hack format
To hack a solution, use the following format:
The first line should contain one integer n (1 ≤ n ≤ 100) — the length of the string, and the following line should contain the string s.
Example
Input
4
a
aa
a
cb
b
c
c
Output
? 1 2
? 3 4
? 4 4
! aabc
Submitted Solution:
```
from sys import stdout
class String2:
def __init__(self, s, b=None):
if b is not None:
self.b = b
return
self.b = [0] * 26
for i in s:
self.b[ord(i) - ord('a')] += 1
def __add__(self, other):
b = self.b.copy()
for i in range(26):
b[i] += other.b[i]
return String2('', b)
def __sub__(self, other):
b = self.b.copy()
for i in range(26):
b[i] -= other.b[i]
return b
def __mul__(self, other):
ans = String2('', self.b)
for i in range(26):
ans.b[i] *= other
return ans
def req(l, r, k=0):
print('?', l, r)
v = [''.join(sorted(input())) for i in range((r - l + 1) * (r - l + 2) // 2)]
stdout.flush()
return v
def compute(v):
bukvi = [[0] * (n + 2) for _ in range(26)]
for el in v:
cur = len(el)
for e in el:
bukvi[ord(e) - ord('a')][cur] += 1
return bukvi
def compute2(bukvi):
bukvis = [set() for i in range(n + 2)]
for i in range(26):
prev = bukvi[i][1]
for j in range(1, n // 2 + n % 2 + 1):
while bukvi[i][j] != prev:
bukvis[j].add(chr(ord('a') + i))
prev += 1
return bukvis
def solve(va, va2):
for i in va2:
va.remove(i)
va.sort(key=len)
s = va[0]
for i in range(1, len(va)):
for j in range(26):
if va[i].count(chr(ord('a') + j)) != va[i - 1].count(chr(ord('a') + j)):
s += chr(ord('a') + j)
return s
def check(v, s, s2, f):
s3 = String2(v[0])
for i in range(1, len(v)):
s3 = s3 + String2(v[i])
le = len(v[0])
cur = String2('', String2('', f - String2(s)) - String2(s2)) * le
for i in range(le - 2):
cur = cur + (String2(s[i]) * (i + 1)) + (String2(s2[-i]) * (i + 1))
cur = cur + (String2(s[le - 2]) * (le - 1)) + (String2(s[le - 1]) * le)
e = cur - s3
for i in range(26):
if e[i]:
return chr(ord('a') + i)
def main():
if n == 1:
va = req(1, 1)
print('!', va[0])
return
elif n == 2:
va2 = req(1, 1)
va3 = req(2, 2)
print('!', va2[0] + va3[0])
return
elif n == 3:
va = req(1, 1)
va2 = req(2, 2)
va3 = req(3, 3)
print('!', va[0] + va2[0] + va3[0])
return
va = req(1, n)
va2 = req(1, max(n // 2 + n % 2, 2))
va3 = req(2, max(n // 2 + n % 2, 2))
# bukvi2 = compute(va2)
# bukvi3 = compute(va3)
ma = [[] for i in range(n * 2)]
for i in va:
ma[len(i)].append(i)
a = String2(''.join(ma[1]))
s = solve(va2, va3)
s2 = ''
for i in range(2, n // 2 + 1):
s2 = check(ma[i], s, s2, a) + s2
se = String2('', a - String2(s)) - String2(s2)
for i in range(len(se)):
if se[i]:
s += chr(ord('a') + i)
break
print('!', s + s2)
n = int(input())
main()
``` | instruction | 0 | 103,043 | 18 | 206,086 |
No | output | 1 | 103,043 | 18 | 206,087 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This problem is different with easy version only by constraints on total answers length
It is an interactive problem
Venya joined a tour to the madhouse, in which orderlies play with patients the following game. Orderlies pick a string s of length n, consisting only of lowercase English letters. The player can ask two types of queries:
* ? l r – ask to list all substrings of s[l..r]. Substrings will be returned in random order, and in every substring, all characters will be randomly shuffled.
* ! s – guess the string picked by the orderlies. This query can be asked exactly once, after that the game will finish. If the string is guessed correctly, the player wins, otherwise he loses.
The player can ask no more than 3 queries of the first type.
To make it easier for the orderlies, there is an additional limitation: the total number of returned substrings in all queries of the first type must not exceed \left⌈ 0.777(n+1)^2 \right⌉ (⌈ x ⌉ is x rounded up).
Venya asked you to write a program, which will guess the string by interacting with the orderlies' program and acting by the game's rules.
Your program should immediately terminate after guessing the string using a query of the second type. In case your program guessed the string incorrectly, or it violated the game rules, it will receive verdict Wrong answer.
Note that in every test case the string is fixed beforehand and will not change during the game, which means that the interactor is not adaptive.
Input
First line contains number n (1 ≤ n ≤ 100) — the length of the picked string.
Interaction
You start the interaction by reading the number n.
To ask a query about a substring from l to r inclusively (1 ≤ l ≤ r ≤ n), you should output
? l r
on a separate line. After this, all substrings of s[l..r] will be returned in random order, each substring exactly once. In every returned substring all characters will be randomly shuffled.
In the case, if you ask an incorrect query, ask more than 3 queries of the first type or there will be more than \left⌈ 0.777(n+1)^2 \right⌉ substrings returned in total, you will receive verdict Wrong answer.
To guess the string s, you should output
! s
on a separate line.
After printing each query, do not forget to flush the output. Otherwise, you will get Idleness limit exceeded. To flush the output, you can use:
* fflush(stdout) or cout.flush() in C++;
* System.out.flush() in Java;
* flush(output) in Pascal;
* stdout.flush() in Python;
* see documentation for other languages.
If you received - (dash) as an answer to any query, you need to terminate your program with exit code 0 (for example, by calling exit(0)). This means that there was an error in the interaction protocol. If you don't terminate with exit code 0, you can receive any unsuccessful verdict.
Hack format
To hack a solution, use the following format:
The first line should contain one integer n (1 ≤ n ≤ 100) — the length of the string, and the following line should contain the string s.
Example
Input
4
a
aa
a
cb
b
c
c
Output
? 1 2
? 3 4
? 4 4
! aabc
Submitted Solution:
```
from sys import stdout
class String2:
def __init__(self, s, b=None):
if b is not None:
self.b = b
return
self.b = [0] * 26
for i in s:
self.b[ord(i) - ord('a')] += 1
def __add__(self, other):
b = self.b.copy()
for i in range(26):
b[i] += other.b[i]
return String2('', b)
def __sub__(self, other):
b = self.b.copy()
for i in range(26):
b[i] -= other.b[i]
return b
def __mul__(self, other):
ans = String2('', self.b)
for i in range(26):
ans.b[i] *= other
return ans
def req(l, r, k=0):
print('?', l, r)
v = [''.join(sorted(input())) for i in range((r - l + 1) * (r - l + 2) // 2)]
stdout.flush()
return v
def compute(v):
bukvi = [[0] * (n + 2) for _ in range(26)]
for el in v:
cur = len(el)
for e in el:
bukvi[ord(e) - ord('a')][cur] += 1
return bukvi
def compute2(bukvi):
bukvis = [set() for i in range(n + 2)]
for i in range(26):
prev = bukvi[i][1]
for j in range(1, n // 2 + n % 2 + 1):
while bukvi[i][j] != prev:
bukvis[j].add(chr(ord('a') + i))
prev += 1
return bukvis
def solve(va, va2):
for i in va2:
va.remove(i)
va.sort(key=len)
s = va[0]
for i in range(1, len(va)):
for j in range(26):
if va[i].count(chr(ord('a') + j)) != va[i - 1].count(chr(ord('a') + j)):
s += chr(ord('a') + j)
return s
def check(v, s, s2, f):
s3 = String2(v[0])
for i in range(1, len(v)):
s3 = s3 + String2(v[i])
le = len(v[0])
cur = String2('', String2('', f - String2(s)) - String2(s2)) * le
for i in range(le - 2):
cur = cur + (String2(s[i]) * (i + 1)) + (String2(s2[-i]) * (i + 1))
cur = cur + (String2(s[le - 2]) * (le - 1)) + (String2(s[le - 1]) * le)
e = cur - s3
for i in range(26):
if e[i]:
return chr(ord('a') + i)
def main():
va = req(1, n)
va2 = req(1, n // 2 + n % 2)
va3 = req(2, n // 2 + n % 2)
# bukvi2 = compute(va2)
# bukvi3 = compute(va3)
if n == 1:
print('!', va[0][0])
return
ma = [[] for i in range(n * 2)]
for i in va:
ma[len(i)].append(i)
a = String2(''.join(ma[1]))
s = solve(va2, va3)
s2 = ''
for i in range(2, n // 2 + 1):
s2 = check(ma[i], s, s2, a) + s2
se = String2('', a - String2(s)) - String2(s2)
for i in range(len(se)):
if se[i]:
s += chr(ord('a') + i)
break
print('!', s + s2)
n = int(input())
main()
``` | instruction | 0 | 103,044 | 18 | 206,088 |
No | output | 1 | 103,044 | 18 | 206,089 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi is practicing shiritori alone again today.
Shiritori is a game as follows:
* In the first turn, a player announces any one word.
* In the subsequent turns, a player announces a word that satisfies the following conditions:
* That word is not announced before.
* The first character of that word is the same as the last character of the last word announced.
In this game, he is practicing to announce as many words as possible in ten seconds.
You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.
Constraints
* N is an integer satisfying 2 \leq N \leq 100.
* W_i is a string of length between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
W_1
W_2
:
W_N
Output
If every word announced by Takahashi satisfied the conditions, print `Yes`; otherwise, print `No`.
Examples
Input
4
hoge
english
hoge
enigma
Output
No
Input
9
basic
c
cpp
php
python
nadesico
ocaml
lua
assembly
Output
Yes
Input
8
a
aa
aaa
aaaa
aaaaa
aaaaaa
aaa
aaaaaaa
Output
No
Input
3
abc
arc
agc
Output
No | instruction | 0 | 103,495 | 18 | 206,990 |
"Correct Solution:
```
n=int(input())
li=[input() for _ in range(n)]
if len(set(li))!=n:
print("No");exit()
else:
for i,j in zip(li,li[1:]):
if i[-1]!=j[0]:
print("No");exit()
print("Yes")
``` | output | 1 | 103,495 | 18 | 206,991 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi is practicing shiritori alone again today.
Shiritori is a game as follows:
* In the first turn, a player announces any one word.
* In the subsequent turns, a player announces a word that satisfies the following conditions:
* That word is not announced before.
* The first character of that word is the same as the last character of the last word announced.
In this game, he is practicing to announce as many words as possible in ten seconds.
You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.
Constraints
* N is an integer satisfying 2 \leq N \leq 100.
* W_i is a string of length between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
W_1
W_2
:
W_N
Output
If every word announced by Takahashi satisfied the conditions, print `Yes`; otherwise, print `No`.
Examples
Input
4
hoge
english
hoge
enigma
Output
No
Input
9
basic
c
cpp
php
python
nadesico
ocaml
lua
assembly
Output
Yes
Input
8
a
aa
aaa
aaaa
aaaaa
aaaaaa
aaa
aaaaaaa
Output
No
Input
3
abc
arc
agc
Output
No | instruction | 0 | 103,496 | 18 | 206,992 |
"Correct Solution:
```
print("No" if (lambda w:(sum([w.count(s)-1 for s in w])) or sum([1-(w[i][0] == w[i-1][-1]) for i in range(1,len(w))]))([input() for i in range(int(input()))]) else "Yes")
``` | output | 1 | 103,496 | 18 | 206,993 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi is practicing shiritori alone again today.
Shiritori is a game as follows:
* In the first turn, a player announces any one word.
* In the subsequent turns, a player announces a word that satisfies the following conditions:
* That word is not announced before.
* The first character of that word is the same as the last character of the last word announced.
In this game, he is practicing to announce as many words as possible in ten seconds.
You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.
Constraints
* N is an integer satisfying 2 \leq N \leq 100.
* W_i is a string of length between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
W_1
W_2
:
W_N
Output
If every word announced by Takahashi satisfied the conditions, print `Yes`; otherwise, print `No`.
Examples
Input
4
hoge
english
hoge
enigma
Output
No
Input
9
basic
c
cpp
php
python
nadesico
ocaml
lua
assembly
Output
Yes
Input
8
a
aa
aaa
aaaa
aaaaa
aaaaaa
aaa
aaaaaaa
Output
No
Input
3
abc
arc
agc
Output
No | instruction | 0 | 103,497 | 18 | 206,994 |
"Correct Solution:
```
L=[input()for x in' '*int(input())];print('YNeos'[any(i[-1]!=j[0]*(L.count(i))for i,j in zip(L,L[1:]))::2])
``` | output | 1 | 103,497 | 18 | 206,995 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi is practicing shiritori alone again today.
Shiritori is a game as follows:
* In the first turn, a player announces any one word.
* In the subsequent turns, a player announces a word that satisfies the following conditions:
* That word is not announced before.
* The first character of that word is the same as the last character of the last word announced.
In this game, he is practicing to announce as many words as possible in ten seconds.
You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.
Constraints
* N is an integer satisfying 2 \leq N \leq 100.
* W_i is a string of length between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
W_1
W_2
:
W_N
Output
If every word announced by Takahashi satisfied the conditions, print `Yes`; otherwise, print `No`.
Examples
Input
4
hoge
english
hoge
enigma
Output
No
Input
9
basic
c
cpp
php
python
nadesico
ocaml
lua
assembly
Output
Yes
Input
8
a
aa
aaa
aaaa
aaaaa
aaaaaa
aaa
aaaaaaa
Output
No
Input
3
abc
arc
agc
Output
No | instruction | 0 | 103,498 | 18 | 206,996 |
"Correct Solution:
```
n = int(input())
w = [input() for i in range(n)]
x = False
if n == len(set(w)):
if all(w[i-1][-1] == w[i][0] for i in range(1,n)):
x = True
print('Yes' if x else 'No')
``` | output | 1 | 103,498 | 18 | 206,997 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi is practicing shiritori alone again today.
Shiritori is a game as follows:
* In the first turn, a player announces any one word.
* In the subsequent turns, a player announces a word that satisfies the following conditions:
* That word is not announced before.
* The first character of that word is the same as the last character of the last word announced.
In this game, he is practicing to announce as many words as possible in ten seconds.
You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.
Constraints
* N is an integer satisfying 2 \leq N \leq 100.
* W_i is a string of length between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
W_1
W_2
:
W_N
Output
If every word announced by Takahashi satisfied the conditions, print `Yes`; otherwise, print `No`.
Examples
Input
4
hoge
english
hoge
enigma
Output
No
Input
9
basic
c
cpp
php
python
nadesico
ocaml
lua
assembly
Output
Yes
Input
8
a
aa
aaa
aaaa
aaaaa
aaaaaa
aaa
aaaaaaa
Output
No
Input
3
abc
arc
agc
Output
No | instruction | 0 | 103,499 | 18 | 206,998 |
"Correct Solution:
```
N = int(input())
w = [input()]
ans = 'Yes'
for i in range(N-1):
tmp = input()
if (tmp in w) or (w[-1][-1] != tmp[0]):
ans = 'No'
break
w.append(tmp)
print(ans)
``` | output | 1 | 103,499 | 18 | 206,999 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi is practicing shiritori alone again today.
Shiritori is a game as follows:
* In the first turn, a player announces any one word.
* In the subsequent turns, a player announces a word that satisfies the following conditions:
* That word is not announced before.
* The first character of that word is the same as the last character of the last word announced.
In this game, he is practicing to announce as many words as possible in ten seconds.
You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.
Constraints
* N is an integer satisfying 2 \leq N \leq 100.
* W_i is a string of length between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
W_1
W_2
:
W_N
Output
If every word announced by Takahashi satisfied the conditions, print `Yes`; otherwise, print `No`.
Examples
Input
4
hoge
english
hoge
enigma
Output
No
Input
9
basic
c
cpp
php
python
nadesico
ocaml
lua
assembly
Output
Yes
Input
8
a
aa
aaa
aaaa
aaaaa
aaaaaa
aaa
aaaaaaa
Output
No
Input
3
abc
arc
agc
Output
No | instruction | 0 | 103,500 | 18 | 207,000 |
"Correct Solution:
```
l=[input() for _ in range(int(input()))]
for i,w in enumerate(l):
if i:
if l[i][0]==l[i-1][-1] and w not in l[:i]:
continue
exit(print('No'))
print('Yes')
``` | output | 1 | 103,500 | 18 | 207,001 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi is practicing shiritori alone again today.
Shiritori is a game as follows:
* In the first turn, a player announces any one word.
* In the subsequent turns, a player announces a word that satisfies the following conditions:
* That word is not announced before.
* The first character of that word is the same as the last character of the last word announced.
In this game, he is practicing to announce as many words as possible in ten seconds.
You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.
Constraints
* N is an integer satisfying 2 \leq N \leq 100.
* W_i is a string of length between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
W_1
W_2
:
W_N
Output
If every word announced by Takahashi satisfied the conditions, print `Yes`; otherwise, print `No`.
Examples
Input
4
hoge
english
hoge
enigma
Output
No
Input
9
basic
c
cpp
php
python
nadesico
ocaml
lua
assembly
Output
Yes
Input
8
a
aa
aaa
aaaa
aaaaa
aaaaaa
aaa
aaaaaaa
Output
No
Input
3
abc
arc
agc
Output
No | instruction | 0 | 103,501 | 18 | 207,002 |
"Correct Solution:
```
#b
N=int(input())
W=[None]*N
for i in range(N):
W[i] = input()
if all( W[i][0]==W[i-1][-1] for i in range(1,N) ) and len(set(W))==N:
print("Yes")
else:
print("No")
``` | output | 1 | 103,501 | 18 | 207,003 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi is practicing shiritori alone again today.
Shiritori is a game as follows:
* In the first turn, a player announces any one word.
* In the subsequent turns, a player announces a word that satisfies the following conditions:
* That word is not announced before.
* The first character of that word is the same as the last character of the last word announced.
In this game, he is practicing to announce as many words as possible in ten seconds.
You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.
Constraints
* N is an integer satisfying 2 \leq N \leq 100.
* W_i is a string of length between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
W_1
W_2
:
W_N
Output
If every word announced by Takahashi satisfied the conditions, print `Yes`; otherwise, print `No`.
Examples
Input
4
hoge
english
hoge
enigma
Output
No
Input
9
basic
c
cpp
php
python
nadesico
ocaml
lua
assembly
Output
Yes
Input
8
a
aa
aaa
aaaa
aaaaa
aaaaaa
aaa
aaaaaaa
Output
No
Input
3
abc
arc
agc
Output
No | instruction | 0 | 103,502 | 18 | 207,004 |
"Correct Solution:
```
N = int(input())
W = [input()]
for i in range(1,N):
w = input()
if W[i-1][-1] != w[0] or w in W:
print('No')
break
else:
W.append(w)
if len(W)==N:
print('Yes')
``` | output | 1 | 103,502 | 18 | 207,005 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi is practicing shiritori alone again today.
Shiritori is a game as follows:
* In the first turn, a player announces any one word.
* In the subsequent turns, a player announces a word that satisfies the following conditions:
* That word is not announced before.
* The first character of that word is the same as the last character of the last word announced.
In this game, he is practicing to announce as many words as possible in ten seconds.
You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.
Constraints
* N is an integer satisfying 2 \leq N \leq 100.
* W_i is a string of length between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
W_1
W_2
:
W_N
Output
If every word announced by Takahashi satisfied the conditions, print `Yes`; otherwise, print `No`.
Examples
Input
4
hoge
english
hoge
enigma
Output
No
Input
9
basic
c
cpp
php
python
nadesico
ocaml
lua
assembly
Output
Yes
Input
8
a
aa
aaa
aaaa
aaaaa
aaaaaa
aaa
aaaaaaa
Output
No
Input
3
abc
arc
agc
Output
No
Submitted Solution:
```
N=int(input())
W = [input()]
flg = "Yes"
for i in range(1,N):
W.append(input())
if not(W[i-1][-1]==W[i][0] and W.count(W[i])==1):
flg = "No"
break
print(flg)
``` | instruction | 0 | 103,503 | 18 | 207,006 |
Yes | output | 1 | 103,503 | 18 | 207,007 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi is practicing shiritori alone again today.
Shiritori is a game as follows:
* In the first turn, a player announces any one word.
* In the subsequent turns, a player announces a word that satisfies the following conditions:
* That word is not announced before.
* The first character of that word is the same as the last character of the last word announced.
In this game, he is practicing to announce as many words as possible in ten seconds.
You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.
Constraints
* N is an integer satisfying 2 \leq N \leq 100.
* W_i is a string of length between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
W_1
W_2
:
W_N
Output
If every word announced by Takahashi satisfied the conditions, print `Yes`; otherwise, print `No`.
Examples
Input
4
hoge
english
hoge
enigma
Output
No
Input
9
basic
c
cpp
php
python
nadesico
ocaml
lua
assembly
Output
Yes
Input
8
a
aa
aaa
aaaa
aaaaa
aaaaaa
aaa
aaaaaaa
Output
No
Input
3
abc
arc
agc
Output
No
Submitted Solution:
```
n = int(input())
W = [input()]
for i in range(n-1):
w = input()
if w in W or W[-1][-1] != w[0]:
print("No")
break
else:
W.append(w)
else:
print("Yes")
``` | instruction | 0 | 103,504 | 18 | 207,008 |
Yes | output | 1 | 103,504 | 18 | 207,009 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi is practicing shiritori alone again today.
Shiritori is a game as follows:
* In the first turn, a player announces any one word.
* In the subsequent turns, a player announces a word that satisfies the following conditions:
* That word is not announced before.
* The first character of that word is the same as the last character of the last word announced.
In this game, he is practicing to announce as many words as possible in ten seconds.
You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.
Constraints
* N is an integer satisfying 2 \leq N \leq 100.
* W_i is a string of length between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
W_1
W_2
:
W_N
Output
If every word announced by Takahashi satisfied the conditions, print `Yes`; otherwise, print `No`.
Examples
Input
4
hoge
english
hoge
enigma
Output
No
Input
9
basic
c
cpp
php
python
nadesico
ocaml
lua
assembly
Output
Yes
Input
8
a
aa
aaa
aaaa
aaaaa
aaaaaa
aaa
aaaaaaa
Output
No
Input
3
abc
arc
agc
Output
No
Submitted Solution:
```
N=int(input())
S=[input() for i in range(N)]
ans = "Yes"
if len(set(S)) != N:
ans = "No"
for i in range(N-1):
if S[i][-1] != S[i+1][0]:
ans = "No"
print(ans)
``` | instruction | 0 | 103,505 | 18 | 207,010 |
Yes | output | 1 | 103,505 | 18 | 207,011 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi is practicing shiritori alone again today.
Shiritori is a game as follows:
* In the first turn, a player announces any one word.
* In the subsequent turns, a player announces a word that satisfies the following conditions:
* That word is not announced before.
* The first character of that word is the same as the last character of the last word announced.
In this game, he is practicing to announce as many words as possible in ten seconds.
You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.
Constraints
* N is an integer satisfying 2 \leq N \leq 100.
* W_i is a string of length between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
W_1
W_2
:
W_N
Output
If every word announced by Takahashi satisfied the conditions, print `Yes`; otherwise, print `No`.
Examples
Input
4
hoge
english
hoge
enigma
Output
No
Input
9
basic
c
cpp
php
python
nadesico
ocaml
lua
assembly
Output
Yes
Input
8
a
aa
aaa
aaaa
aaaaa
aaaaaa
aaa
aaaaaaa
Output
No
Input
3
abc
arc
agc
Output
No
Submitted Solution:
```
_,*l=open(0);print('YNeos'[any(a[-2]!=b[0]*l.count(a)for a,b in zip(l,l[1:]))::2])
``` | instruction | 0 | 103,506 | 18 | 207,012 |
Yes | output | 1 | 103,506 | 18 | 207,013 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi is practicing shiritori alone again today.
Shiritori is a game as follows:
* In the first turn, a player announces any one word.
* In the subsequent turns, a player announces a word that satisfies the following conditions:
* That word is not announced before.
* The first character of that word is the same as the last character of the last word announced.
In this game, he is practicing to announce as many words as possible in ten seconds.
You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.
Constraints
* N is an integer satisfying 2 \leq N \leq 100.
* W_i is a string of length between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
W_1
W_2
:
W_N
Output
If every word announced by Takahashi satisfied the conditions, print `Yes`; otherwise, print `No`.
Examples
Input
4
hoge
english
hoge
enigma
Output
No
Input
9
basic
c
cpp
php
python
nadesico
ocaml
lua
assembly
Output
Yes
Input
8
a
aa
aaa
aaaa
aaaaa
aaaaaa
aaa
aaaaaaa
Output
No
Input
3
abc
arc
agc
Output
No
Submitted Solution:
```
N = int(input())
W = [input() for i in range(N)]
word_stock = []
for word in W:
#同じワード確認
if word in word_stock:
print('No')
#最後の文字確認
try:
if word_stock[-1][-1] != word[0]:
print('No')
except:
pass
word_stock.append(word)
print('Yes')
``` | instruction | 0 | 103,507 | 18 | 207,014 |
No | output | 1 | 103,507 | 18 | 207,015 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi is practicing shiritori alone again today.
Shiritori is a game as follows:
* In the first turn, a player announces any one word.
* In the subsequent turns, a player announces a word that satisfies the following conditions:
* That word is not announced before.
* The first character of that word is the same as the last character of the last word announced.
In this game, he is practicing to announce as many words as possible in ten seconds.
You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.
Constraints
* N is an integer satisfying 2 \leq N \leq 100.
* W_i is a string of length between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
W_1
W_2
:
W_N
Output
If every word announced by Takahashi satisfied the conditions, print `Yes`; otherwise, print `No`.
Examples
Input
4
hoge
english
hoge
enigma
Output
No
Input
9
basic
c
cpp
php
python
nadesico
ocaml
lua
assembly
Output
Yes
Input
8
a
aa
aaa
aaaa
aaaaa
aaaaaa
aaa
aaaaaaa
Output
No
Input
3
abc
arc
agc
Output
No
Submitted Solution:
```
N=int(input())
words=[input() for _ in range(N)]
tmp=set(words)
#print(tmp)
c=1
if len(words)!=len(tmp):
c=0
else:
for i in range(N):
print(words)
if i==0:
continue
elif words[i][0]!=words[i-1][-1]:
c=0
break
#print(c)
if c:
print("Yes")
else:
print("No")
``` | instruction | 0 | 103,508 | 18 | 207,016 |
No | output | 1 | 103,508 | 18 | 207,017 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi is practicing shiritori alone again today.
Shiritori is a game as follows:
* In the first turn, a player announces any one word.
* In the subsequent turns, a player announces a word that satisfies the following conditions:
* That word is not announced before.
* The first character of that word is the same as the last character of the last word announced.
In this game, he is practicing to announce as many words as possible in ten seconds.
You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.
Constraints
* N is an integer satisfying 2 \leq N \leq 100.
* W_i is a string of length between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
W_1
W_2
:
W_N
Output
If every word announced by Takahashi satisfied the conditions, print `Yes`; otherwise, print `No`.
Examples
Input
4
hoge
english
hoge
enigma
Output
No
Input
9
basic
c
cpp
php
python
nadesico
ocaml
lua
assembly
Output
Yes
Input
8
a
aa
aaa
aaaa
aaaaa
aaaaaa
aaa
aaaaaaa
Output
No
Input
3
abc
arc
agc
Output
No
Submitted Solution:
```
#! /usr/bin/python
from sys import stdin
n = int(input())
W = stdin.read().splitlines()
if n != len(set(W)):
print("No")
exit()
for i in range(1, n-1):
if W[i][-1] != W[i][0]:
print("No")
exit()
``` | instruction | 0 | 103,509 | 18 | 207,018 |
No | output | 1 | 103,509 | 18 | 207,019 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi is practicing shiritori alone again today.
Shiritori is a game as follows:
* In the first turn, a player announces any one word.
* In the subsequent turns, a player announces a word that satisfies the following conditions:
* That word is not announced before.
* The first character of that word is the same as the last character of the last word announced.
In this game, he is practicing to announce as many words as possible in ten seconds.
You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.
Constraints
* N is an integer satisfying 2 \leq N \leq 100.
* W_i is a string of length between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
W_1
W_2
:
W_N
Output
If every word announced by Takahashi satisfied the conditions, print `Yes`; otherwise, print `No`.
Examples
Input
4
hoge
english
hoge
enigma
Output
No
Input
9
basic
c
cpp
php
python
nadesico
ocaml
lua
assembly
Output
Yes
Input
8
a
aa
aaa
aaaa
aaaaa
aaaaaa
aaa
aaaaaaa
Output
No
Input
3
abc
arc
agc
Output
No
Submitted Solution:
```
n=int(input())
lw=[input() for i in range(n)]
used=set()
last=lw[0][0]
for w in lw:
if w in used or last !=w[0]:
cond=False
break
used.add(w)
last=w[-1]
print("Yes" if cond else "No")
``` | instruction | 0 | 103,510 | 18 | 207,020 |
No | output | 1 | 103,510 | 18 | 207,021 |
Provide a correct Python 3 solution for this coding contest problem.
Rng is going to a festival.
The name of the festival is given to you as a string S, which ends with `FESTIVAL`, from input. Answer the question: "Rng is going to a festival of what?" Output the answer.
Here, assume that the name of "a festival of s" is a string obtained by appending `FESTIVAL` to the end of s. For example, `CODEFESTIVAL` is a festival of `CODE`.
Constraints
* 9 \leq |S| \leq 50
* S consists of uppercase English letters.
* S ends with `FESTIVAL`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the answer to the question: "Rng is going to a festival of what?"
Examples
Input
CODEFESTIVAL
Output
CODE
Input
CODEFESTIVALFESTIVAL
Output
CODEFESTIVAL
Input
YAKINIKUFESTIVAL
Output
YAKINIKU | instruction | 0 | 103,527 | 18 | 207,054 |
"Correct Solution:
```
S = input()
print(S[:S.rfind("FESTIVAL")])
``` | output | 1 | 103,527 | 18 | 207,055 |
Provide a correct Python 3 solution for this coding contest problem.
Rng is going to a festival.
The name of the festival is given to you as a string S, which ends with `FESTIVAL`, from input. Answer the question: "Rng is going to a festival of what?" Output the answer.
Here, assume that the name of "a festival of s" is a string obtained by appending `FESTIVAL` to the end of s. For example, `CODEFESTIVAL` is a festival of `CODE`.
Constraints
* 9 \leq |S| \leq 50
* S consists of uppercase English letters.
* S ends with `FESTIVAL`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the answer to the question: "Rng is going to a festival of what?"
Examples
Input
CODEFESTIVAL
Output
CODE
Input
CODEFESTIVALFESTIVAL
Output
CODEFESTIVAL
Input
YAKINIKUFESTIVAL
Output
YAKINIKU | instruction | 0 | 103,528 | 18 | 207,056 |
"Correct Solution:
```
#CODE FESTIVAL 2017 qual B a
s=input()
n=len(s)-len("FESTIVAL")
ans=""
for i in range(n):
ans+=s[i]
print(ans)
``` | output | 1 | 103,528 | 18 | 207,057 |
Provide a correct Python 3 solution for this coding contest problem.
Rng is going to a festival.
The name of the festival is given to you as a string S, which ends with `FESTIVAL`, from input. Answer the question: "Rng is going to a festival of what?" Output the answer.
Here, assume that the name of "a festival of s" is a string obtained by appending `FESTIVAL` to the end of s. For example, `CODEFESTIVAL` is a festival of `CODE`.
Constraints
* 9 \leq |S| \leq 50
* S consists of uppercase English letters.
* S ends with `FESTIVAL`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the answer to the question: "Rng is going to a festival of what?"
Examples
Input
CODEFESTIVAL
Output
CODE
Input
CODEFESTIVALFESTIVAL
Output
CODEFESTIVAL
Input
YAKINIKUFESTIVAL
Output
YAKINIKU | instruction | 0 | 103,529 | 18 | 207,058 |
"Correct Solution:
```
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
sys.setrecursionlimit(10 ** 7)
s = input()
print(s[:len(s) - 8])
``` | output | 1 | 103,529 | 18 | 207,059 |
Provide a correct Python 3 solution for this coding contest problem.
Rng is going to a festival.
The name of the festival is given to you as a string S, which ends with `FESTIVAL`, from input. Answer the question: "Rng is going to a festival of what?" Output the answer.
Here, assume that the name of "a festival of s" is a string obtained by appending `FESTIVAL` to the end of s. For example, `CODEFESTIVAL` is a festival of `CODE`.
Constraints
* 9 \leq |S| \leq 50
* S consists of uppercase English letters.
* S ends with `FESTIVAL`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the answer to the question: "Rng is going to a festival of what?"
Examples
Input
CODEFESTIVAL
Output
CODE
Input
CODEFESTIVALFESTIVAL
Output
CODEFESTIVAL
Input
YAKINIKUFESTIVAL
Output
YAKINIKU | instruction | 0 | 103,530 | 18 | 207,060 |
"Correct Solution:
```
s=str(input())
print(s[:-8])
``` | output | 1 | 103,530 | 18 | 207,061 |
Provide a correct Python 3 solution for this coding contest problem.
Rng is going to a festival.
The name of the festival is given to you as a string S, which ends with `FESTIVAL`, from input. Answer the question: "Rng is going to a festival of what?" Output the answer.
Here, assume that the name of "a festival of s" is a string obtained by appending `FESTIVAL` to the end of s. For example, `CODEFESTIVAL` is a festival of `CODE`.
Constraints
* 9 \leq |S| \leq 50
* S consists of uppercase English letters.
* S ends with `FESTIVAL`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the answer to the question: "Rng is going to a festival of what?"
Examples
Input
CODEFESTIVAL
Output
CODE
Input
CODEFESTIVALFESTIVAL
Output
CODEFESTIVAL
Input
YAKINIKUFESTIVAL
Output
YAKINIKU | instruction | 0 | 103,531 | 18 | 207,062 |
"Correct Solution:
```
# CODE FESTIVAL 2017 予選 B: A – XXFESTIVAL
s = input()
print(s[:-8])
``` | output | 1 | 103,531 | 18 | 207,063 |
Provide a correct Python 3 solution for this coding contest problem.
Rng is going to a festival.
The name of the festival is given to you as a string S, which ends with `FESTIVAL`, from input. Answer the question: "Rng is going to a festival of what?" Output the answer.
Here, assume that the name of "a festival of s" is a string obtained by appending `FESTIVAL` to the end of s. For example, `CODEFESTIVAL` is a festival of `CODE`.
Constraints
* 9 \leq |S| \leq 50
* S consists of uppercase English letters.
* S ends with `FESTIVAL`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the answer to the question: "Rng is going to a festival of what?"
Examples
Input
CODEFESTIVAL
Output
CODE
Input
CODEFESTIVALFESTIVAL
Output
CODEFESTIVAL
Input
YAKINIKUFESTIVAL
Output
YAKINIKU | instruction | 0 | 103,532 | 18 | 207,064 |
"Correct Solution:
```
S = input()
if S[-8:] == "FESTIVAL":
print("{}".format(S[0:-8]))
``` | output | 1 | 103,532 | 18 | 207,065 |
Provide a correct Python 3 solution for this coding contest problem.
Rng is going to a festival.
The name of the festival is given to you as a string S, which ends with `FESTIVAL`, from input. Answer the question: "Rng is going to a festival of what?" Output the answer.
Here, assume that the name of "a festival of s" is a string obtained by appending `FESTIVAL` to the end of s. For example, `CODEFESTIVAL` is a festival of `CODE`.
Constraints
* 9 \leq |S| \leq 50
* S consists of uppercase English letters.
* S ends with `FESTIVAL`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the answer to the question: "Rng is going to a festival of what?"
Examples
Input
CODEFESTIVAL
Output
CODE
Input
CODEFESTIVALFESTIVAL
Output
CODEFESTIVAL
Input
YAKINIKUFESTIVAL
Output
YAKINIKU | instruction | 0 | 103,533 | 18 | 207,066 |
"Correct Solution:
```
def main():
s = input()
print(s[:-8])
if __name__ == "__main__":
main()
``` | output | 1 | 103,533 | 18 | 207,067 |
Provide a correct Python 3 solution for this coding contest problem.
Rng is going to a festival.
The name of the festival is given to you as a string S, which ends with `FESTIVAL`, from input. Answer the question: "Rng is going to a festival of what?" Output the answer.
Here, assume that the name of "a festival of s" is a string obtained by appending `FESTIVAL` to the end of s. For example, `CODEFESTIVAL` is a festival of `CODE`.
Constraints
* 9 \leq |S| \leq 50
* S consists of uppercase English letters.
* S ends with `FESTIVAL`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the answer to the question: "Rng is going to a festival of what?"
Examples
Input
CODEFESTIVAL
Output
CODE
Input
CODEFESTIVALFESTIVAL
Output
CODEFESTIVAL
Input
YAKINIKUFESTIVAL
Output
YAKINIKU | instruction | 0 | 103,534 | 18 | 207,068 |
"Correct Solution:
```
a = input().strip()
print(a[:-8])
``` | output | 1 | 103,534 | 18 | 207,069 |
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