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Provide a correct Python 3 solution for this coding contest problem. You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order. Constraints * The lengths of s and t are between 1 and 100 (inclusive). * s and t consists of lowercase English letters. Input Input is given from Standard Input in the following format: s t Output If it is possible to satisfy s' < t', print `Yes`; if it is not, print `No`. Examples Input yx axy Output Yes Input ratcode atlas Output Yes Input cd abc Output No Input w ww Output Yes Input zzz zzz Output No
instruction
0
107,718
18
215,436
"Correct Solution: ``` print('Yes'*(sorted(input())<sorted(input())[::-1])or'No') ```
output
1
107,718
18
215,437
Provide a correct Python 3 solution for this coding contest problem. You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order. Constraints * The lengths of s and t are between 1 and 100 (inclusive). * s and t consists of lowercase English letters. Input Input is given from Standard Input in the following format: s t Output If it is possible to satisfy s' < t', print `Yes`; if it is not, print `No`. Examples Input yx axy Output Yes Input ratcode atlas Output Yes Input cd abc Output No Input w ww Output Yes Input zzz zzz Output No
instruction
0
107,719
18
215,438
"Correct Solution: ``` s = sorted(input()) t = sorted(input())[::-1] if s < t: print("Yes") else: print("No") ```
output
1
107,719
18
215,439
Provide a correct Python 3 solution for this coding contest problem. You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order. Constraints * The lengths of s and t are between 1 and 100 (inclusive). * s and t consists of lowercase English letters. Input Input is given from Standard Input in the following format: s t Output If it is possible to satisfy s' < t', print `Yes`; if it is not, print `No`. Examples Input yx axy Output Yes Input ratcode atlas Output Yes Input cd abc Output No Input w ww Output Yes Input zzz zzz Output No
instruction
0
107,720
18
215,440
"Correct Solution: ``` s=sorted(input()) t=sorted(input()) t.sort(reverse=True) print("Yes" if s<t else "No") ```
output
1
107,720
18
215,441
Provide a correct Python 3 solution for this coding contest problem. You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order. Constraints * The lengths of s and t are between 1 and 100 (inclusive). * s and t consists of lowercase English letters. Input Input is given from Standard Input in the following format: s t Output If it is possible to satisfy s' < t', print `Yes`; if it is not, print `No`. Examples Input yx axy Output Yes Input ratcode atlas Output Yes Input cd abc Output No Input w ww Output Yes Input zzz zzz Output No
instruction
0
107,721
18
215,442
"Correct Solution: ``` S = sorted(list(input())) T = sorted(list(input()))[::-1] print('Yes' if S<T else 'No') ```
output
1
107,721
18
215,443
Provide a correct Python 3 solution for this coding contest problem. You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order. Constraints * The lengths of s and t are between 1 and 100 (inclusive). * s and t consists of lowercase English letters. Input Input is given from Standard Input in the following format: s t Output If it is possible to satisfy s' < t', print `Yes`; if it is not, print `No`. Examples Input yx axy Output Yes Input ratcode atlas Output Yes Input cd abc Output No Input w ww Output Yes Input zzz zzz Output No
instruction
0
107,722
18
215,444
"Correct Solution: ``` s=input() t=input() print(['No','Yes'][''.join(sorted(s))<''.join(sorted(t,reverse=True))]) ```
output
1
107,722
18
215,445
Provide a correct Python 3 solution for this coding contest problem. You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order. Constraints * The lengths of s and t are between 1 and 100 (inclusive). * s and t consists of lowercase English letters. Input Input is given from Standard Input in the following format: s t Output If it is possible to satisfy s' < t', print `Yes`; if it is not, print `No`. Examples Input yx axy Output Yes Input ratcode atlas Output Yes Input cd abc Output No Input w ww Output Yes Input zzz zzz Output No
instruction
0
107,723
18
215,446
"Correct Solution: ``` s = ''.join(sorted(input())) t = ''.join(sorted(input())[::-1]) print('Yes' if s < t else 'No') ```
output
1
107,723
18
215,447
Provide a correct Python 3 solution for this coding contest problem. You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order. Constraints * The lengths of s and t are between 1 and 100 (inclusive). * s and t consists of lowercase English letters. Input Input is given from Standard Input in the following format: s t Output If it is possible to satisfy s' < t', print `Yes`; if it is not, print `No`. Examples Input yx axy Output Yes Input ratcode atlas Output Yes Input cd abc Output No Input w ww Output Yes Input zzz zzz Output No
instruction
0
107,724
18
215,448
"Correct Solution: ``` s=input() t=input() s1=sorted(s) t1=sorted(t)[::-1] print('Yes' if s1<t1 else 'No' ) ```
output
1
107,724
18
215,449
Provide a correct Python 3 solution for this coding contest problem. You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order. Constraints * The lengths of s and t are between 1 and 100 (inclusive). * s and t consists of lowercase English letters. Input Input is given from Standard Input in the following format: s t Output If it is possible to satisfy s' < t', print `Yes`; if it is not, print `No`. Examples Input yx axy Output Yes Input ratcode atlas Output Yes Input cd abc Output No Input w ww Output Yes Input zzz zzz Output No
instruction
0
107,725
18
215,450
"Correct Solution: ``` s, t = [input() for _ in range(2)] print('Yes' if sorted(s) < sorted(t)[::-1] else 'No') ```
output
1
107,725
18
215,451
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order. Constraints * The lengths of s and t are between 1 and 100 (inclusive). * s and t consists of lowercase English letters. Input Input is given from Standard Input in the following format: s t Output If it is possible to satisfy s' < t', print `Yes`; if it is not, print `No`. Examples Input yx axy Output Yes Input ratcode atlas Output Yes Input cd abc Output No Input w ww Output Yes Input zzz zzz Output No Submitted Solution: ``` s, t = sorted(input()), sorted(input())[::-1] print("YNeos"[sorted([s,t])[0]==t::2]) ```
instruction
0
107,726
18
215,452
Yes
output
1
107,726
18
215,453
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order. Constraints * The lengths of s and t are between 1 and 100 (inclusive). * s and t consists of lowercase English letters. Input Input is given from Standard Input in the following format: s t Output If it is possible to satisfy s' < t', print `Yes`; if it is not, print `No`. Examples Input yx axy Output Yes Input ratcode atlas Output Yes Input cd abc Output No Input w ww Output Yes Input zzz zzz Output No Submitted Solution: ``` s=sorted(input()) t=sorted(input(),reverse=True) print("Yes" if s<t else "No") ```
instruction
0
107,727
18
215,454
Yes
output
1
107,727
18
215,455
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order. Constraints * The lengths of s and t are between 1 and 100 (inclusive). * s and t consists of lowercase English letters. Input Input is given from Standard Input in the following format: s t Output If it is possible to satisfy s' < t', print `Yes`; if it is not, print `No`. Examples Input yx axy Output Yes Input ratcode atlas Output Yes Input cd abc Output No Input w ww Output Yes Input zzz zzz Output No Submitted Solution: ``` s=list(input()) t=list(input()) s.sort() t.sort(reverse=True) if s<t:print('Yes') else:print('No') ```
instruction
0
107,728
18
215,456
Yes
output
1
107,728
18
215,457
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order. Constraints * The lengths of s and t are between 1 and 100 (inclusive). * s and t consists of lowercase English letters. Input Input is given from Standard Input in the following format: s t Output If it is possible to satisfy s' < t', print `Yes`; if it is not, print `No`. Examples Input yx axy Output Yes Input ratcode atlas Output Yes Input cd abc Output No Input w ww Output Yes Input zzz zzz Output No Submitted Solution: ``` s = sorted(list(input())) t = sorted(list(input()), reverse=True) print("Yes" if s < t else "No") ```
instruction
0
107,729
18
215,458
Yes
output
1
107,729
18
215,459
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order. Constraints * The lengths of s and t are between 1 and 100 (inclusive). * s and t consists of lowercase English letters. Input Input is given from Standard Input in the following format: s t Output If it is possible to satisfy s' < t', print `Yes`; if it is not, print `No`. Examples Input yx axy Output Yes Input ratcode atlas Output Yes Input cd abc Output No Input w ww Output Yes Input zzz zzz Output No Submitted Solution: ``` input = [str(input()) for i in range(2)] s_list = sorted(input[0]) t_list = sorted(input[1], reverse=True) def main(): # tγŒε°γ•γ‘γ‚Œγ°no for s, t in zip(s_list, t_list): if s < t: return 'Yes' elif s > t: return 'No' if len(s) >= len(t): return 'No' else: return 'Yes' print(main()) ```
instruction
0
107,730
18
215,460
No
output
1
107,730
18
215,461
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order. Constraints * The lengths of s and t are between 1 and 100 (inclusive). * s and t consists of lowercase English letters. Input Input is given from Standard Input in the following format: s t Output If it is possible to satisfy s' < t', print `Yes`; if it is not, print `No`. Examples Input yx axy Output Yes Input ratcode atlas Output Yes Input cd abc Output No Input w ww Output Yes Input zzz zzz Output No Submitted Solution: ``` s = input() t = input() s = sorted(s) t = sorted(t, reverse=True) s_len = len(s) t_len = len(t) min_len = min(s_len, t_len) for i in range(min_len): if s[i] < t[i]: print('Yes') exit() elif s[i] > t[i]: print('No') exit() if s_len == t_len: print('No') else: print('Yes') ```
instruction
0
107,731
18
215,462
No
output
1
107,731
18
215,463
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order. Constraints * The lengths of s and t are between 1 and 100 (inclusive). * s and t consists of lowercase English letters. Input Input is given from Standard Input in the following format: s t Output If it is possible to satisfy s' < t', print `Yes`; if it is not, print `No`. Examples Input yx axy Output Yes Input ratcode atlas Output Yes Input cd abc Output No Input w ww Output Yes Input zzz zzz Output No Submitted Solution: ``` print("Yes") if sorted(input()) < sorted(input()) else print("No") ```
instruction
0
107,732
18
215,464
No
output
1
107,732
18
215,465
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order. Constraints * The lengths of s and t are between 1 and 100 (inclusive). * s and t consists of lowercase English letters. Input Input is given from Standard Input in the following format: s t Output If it is possible to satisfy s' < t', print `Yes`; if it is not, print `No`. Examples Input yx axy Output Yes Input ratcode atlas Output Yes Input cd abc Output No Input w ww Output Yes Input zzz zzz Output No Submitted Solution: ``` import sys import math import itertools import bisect from copy import copy from collections import deque,Counter from decimal import Decimal def s(): return input() def i(): return int(input()) def S(): return input().split() def I(): return map(int,input().split()) def X(): return list(input()) def L(): return list(input().split()) def l(): return list(map(int,input().split())) def lcm(a,b): return a*b//math.gcd(a,b) def gcd(*numbers): reduce(math.gcd, numbers) sys.setrecursionlimit(10 ** 9) mod = 10**9+7 count = 0 ans = 0 a = s() t = s() a.sort() y = "".join(a) t = sorted(t,reverse = True) x = "".join(t) if y < x: print("Yes") else: print("No") ```
instruction
0
107,733
18
215,466
No
output
1
107,733
18
215,467
Provide a correct Python 3 solution for this coding contest problem. There is data of up to 100 characters per line, consisting of half-width alphabetic character strings. Some lines are symmetric (same whether read from the left edge or the right edge). Create a program that reads this data and outputs the number of symmetric strings in it. Note that lines consisting of only one character are symmetrical. Input Multiple strings are given over multiple lines. One string is given for each line. The number of strings does not exceed 50. Output Outputs the number of symmetric strings on one line. Example Input abcba sx abcddcba rttrd Output 2
instruction
0
107,773
18
215,546
"Correct Solution: ``` import sys readlines = sys.stdin.readlines write = sys.stdout.write def solve(): ans = 0 for line in readlines(): s = line.strip() if s == s[::-1]: ans += 1 write("%d\n" % ans) solve() ```
output
1
107,773
18
215,547
Provide a correct Python 3 solution for this coding contest problem. There is data of up to 100 characters per line, consisting of half-width alphabetic character strings. Some lines are symmetric (same whether read from the left edge or the right edge). Create a program that reads this data and outputs the number of symmetric strings in it. Note that lines consisting of only one character are symmetrical. Input Multiple strings are given over multiple lines. One string is given for each line. The number of strings does not exceed 50. Output Outputs the number of symmetric strings on one line. Example Input abcba sx abcddcba rttrd Output 2
instruction
0
107,774
18
215,548
"Correct Solution: ``` cnt = 0 while True : try : n = list(input()) N = list(reversed(n)) if n == N : cnt += 1 except : print(cnt) break ```
output
1
107,774
18
215,549
Provide a correct Python 3 solution for this coding contest problem. There is data of up to 100 characters per line, consisting of half-width alphabetic character strings. Some lines are symmetric (same whether read from the left edge or the right edge). Create a program that reads this data and outputs the number of symmetric strings in it. Note that lines consisting of only one character are symmetrical. Input Multiple strings are given over multiple lines. One string is given for each line. The number of strings does not exceed 50. Output Outputs the number of symmetric strings on one line. Example Input abcba sx abcddcba rttrd Output 2
instruction
0
107,775
18
215,550
"Correct Solution: ``` q=0 while True: try: x = input() c = 0 if len(x)%2==0: for i in range(len(x)//2): if x[i] == x[len(x)-i-1]: c += 1 else: pass if c == len(x)//2: q += 1 else: for j in range((len(x)-1)//2): if x[j] == x[len(x)-j-1]: c += 1 else: pass if c == (len(x)-1)//2: q += 1 except EOFError: break print(q) ```
output
1
107,775
18
215,551
Provide a correct Python 3 solution for this coding contest problem. There is data of up to 100 characters per line, consisting of half-width alphabetic character strings. Some lines are symmetric (same whether read from the left edge or the right edge). Create a program that reads this data and outputs the number of symmetric strings in it. Note that lines consisting of only one character are symmetrical. Input Multiple strings are given over multiple lines. One string is given for each line. The number of strings does not exceed 50. Output Outputs the number of symmetric strings on one line. Example Input abcba sx abcddcba rttrd Output 2
instruction
0
107,777
18
215,554
"Correct Solution: ``` c = 0 while True: try: s = input() t = s[::-1] print if s == t: c += 1 except EOFError: break print(c) ```
output
1
107,777
18
215,555
Provide a correct Python 3 solution for this coding contest problem. There is data of up to 100 characters per line, consisting of half-width alphabetic character strings. Some lines are symmetric (same whether read from the left edge or the right edge). Create a program that reads this data and outputs the number of symmetric strings in it. Note that lines consisting of only one character are symmetrical. Input Multiple strings are given over multiple lines. One string is given for each line. The number of strings does not exceed 50. Output Outputs the number of symmetric strings on one line. Example Input abcba sx abcddcba rttrd Output 2
instruction
0
107,778
18
215,556
"Correct Solution: ``` import sys f = sys.stdin def is_symmetry(s): return s == s[::-1] print(sum(1 for line in f if is_symmetry(line.strip()))) ```
output
1
107,778
18
215,557
Provide a correct Python 3 solution for this coding contest problem. There is data of up to 100 characters per line, consisting of half-width alphabetic character strings. Some lines are symmetric (same whether read from the left edge or the right edge). Create a program that reads this data and outputs the number of symmetric strings in it. Note that lines consisting of only one character are symmetrical. Input Multiple strings are given over multiple lines. One string is given for each line. The number of strings does not exceed 50. Output Outputs the number of symmetric strings on one line. Example Input abcba sx abcddcba rttrd Output 2
instruction
0
107,779
18
215,558
"Correct Solution: ``` ans=0 while True: try : n=input() if n==n[::-1]: ans+=1 except : break print(ans) ```
output
1
107,779
18
215,559
Provide a correct Python 3 solution for this coding contest problem. There is data of up to 100 characters per line, consisting of half-width alphabetic character strings. Some lines are symmetric (same whether read from the left edge or the right edge). Create a program that reads this data and outputs the number of symmetric strings in it. Note that lines consisting of only one character are symmetrical. Input Multiple strings are given over multiple lines. One string is given for each line. The number of strings does not exceed 50. Output Outputs the number of symmetric strings on one line. Example Input abcba sx abcddcba rttrd Output 2
instruction
0
107,780
18
215,560
"Correct Solution: ``` # coding: utf-8 # Your code here! s=0 while True: try: x=input() X=x[::-1] if x==X: s+=1 else: pass except EOFError: break print(s) ```
output
1
107,780
18
215,561
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There is data of up to 100 characters per line, consisting of half-width alphabetic character strings. Some lines are symmetric (same whether read from the left edge or the right edge). Create a program that reads this data and outputs the number of symmetric strings in it. Note that lines consisting of only one character are symmetrical. Input Multiple strings are given over multiple lines. One string is given for each line. The number of strings does not exceed 50. Output Outputs the number of symmetric strings on one line. Example Input abcba sx abcddcba rttrd Output 2 Submitted Solution: ``` ans=0 while True: try: b = input() a = list(b) c=len(a) if c==0: break c=int(c/2) e=0 for i in range(c): d=i+1 if a[i]==a[-d]: e+=1 else: break if e==c: ans+=1 except: break print(ans) ```
instruction
0
107,781
18
215,562
Yes
output
1
107,781
18
215,563
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There is data of up to 100 characters per line, consisting of half-width alphabetic character strings. Some lines are symmetric (same whether read from the left edge or the right edge). Create a program that reads this data and outputs the number of symmetric strings in it. Note that lines consisting of only one character are symmetrical. Input Multiple strings are given over multiple lines. One string is given for each line. The number of strings does not exceed 50. Output Outputs the number of symmetric strings on one line. Example Input abcba sx abcddcba rttrd Output 2 Submitted Solution: ``` s=0 while True: try: x=input() X=x[::-1] if x==X: s+=1 else: pass except EOFError: break print(s) ```
instruction
0
107,782
18
215,564
Yes
output
1
107,782
18
215,565
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There is data of up to 100 characters per line, consisting of half-width alphabetic character strings. Some lines are symmetric (same whether read from the left edge or the right edge). Create a program that reads this data and outputs the number of symmetric strings in it. Note that lines consisting of only one character are symmetrical. Input Multiple strings are given over multiple lines. One string is given for each line. The number of strings does not exceed 50. Output Outputs the number of symmetric strings on one line. Example Input abcba sx abcddcba rttrd Output 2 Submitted Solution: ``` import sys print(sum([1 for i in sys.stdin if i.strip()==i.strip()[::-1]])) ```
instruction
0
107,783
18
215,566
Yes
output
1
107,783
18
215,567
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There is data of up to 100 characters per line, consisting of half-width alphabetic character strings. Some lines are symmetric (same whether read from the left edge or the right edge). Create a program that reads this data and outputs the number of symmetric strings in it. Note that lines consisting of only one character are symmetrical. Input Multiple strings are given over multiple lines. One string is given for each line. The number of strings does not exceed 50. Output Outputs the number of symmetric strings on one line. Example Input abcba sx abcddcba rttrd Output 2 Submitted Solution: ``` count = 0 while True: try: text = list(input()) a = len(text) b = a//2 _te = [] te_ = [] for i in range(0,b): _te.append(text[i]) te_.append(text[a-1-i]) if _te==te_: count += 1 except: break print(count) ```
instruction
0
107,784
18
215,568
Yes
output
1
107,784
18
215,569
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There is data of up to 100 characters per line, consisting of half-width alphabetic character strings. Some lines are symmetric (same whether read from the left edge or the right edge). Create a program that reads this data and outputs the number of symmetric strings in it. Note that lines consisting of only one character are symmetrical. Input Multiple strings are given over multiple lines. One string is given for each line. The number of strings does not exceed 50. Output Outputs the number of symmetric strings on one line. Example Input abcba sx abcddcba rttrd Output 2 Submitted Solution: ``` res = 0 while True: try: cc = list(input()) except: break l = len(cc) if l % 2 == 0: if cc[:l // 2] == cc[:l // 2 - 1:-1]: res += 1 else: if cc[:(l + 1) // 2] == cc[:(l - 1) // 2 - 1:-1]: res += 1 print(res) ```
instruction
0
107,785
18
215,570
No
output
1
107,785
18
215,571
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There is data of up to 100 characters per line, consisting of half-width alphabetic character strings. Some lines are symmetric (same whether read from the left edge or the right edge). Create a program that reads this data and outputs the number of symmetric strings in it. Note that lines consisting of only one character are symmetrical. Input Multiple strings are given over multiple lines. One string is given for each line. The number of strings does not exceed 50. Output Outputs the number of symmetric strings on one line. Example Input abcba sx abcddcba rttrd Output 2 Submitted Solution: ``` res = 0 while True: try: cc = list(input()) if not len(cc): break except: break l = len(cc) if l % 2 == 0: if cc[:l // 2] == cc[:l // 2 - 1:-1]: res += 1 else: if cc[:(l + 1) // 2] == cc[:(l - 1) // 2 - 1:-1]: res += 1 print(res) ```
instruction
0
107,786
18
215,572
No
output
1
107,786
18
215,573
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There is data of up to 100 characters per line, consisting of half-width alphabetic character strings. Some lines are symmetric (same whether read from the left edge or the right edge). Create a program that reads this data and outputs the number of symmetric strings in it. Note that lines consisting of only one character are symmetrical. Input Multiple strings are given over multiple lines. One string is given for each line. The number of strings does not exceed 50. Output Outputs the number of symmetric strings on one line. Example Input abcba sx abcddcba rttrd Output 2 Submitted Solution: ``` import sys print(e[:-1]==e[-2::-1]for e in sys.stdin) ```
instruction
0
107,787
18
215,574
No
output
1
107,787
18
215,575
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Let's analyze a program written on some strange programming language. The variables in this language have names consisting of 1 to 4 characters, and each character is a lowercase or an uppercase Latin letter, or a digit. There is an extra constraint that the first character should not be a digit. There are four types of operations in the program, each denoted by one of the characters: $, ^, # or &. Each line of the program has one of the following formats: * <lvalue>=<rvalue>, where <lvalue> and <rvalue> are valid variable names; * <lvalue>=<arg1><op><arg2>, where <lvalue>, <arg1> and <arg2> are valid variable names, and <op> is an operation character. The program is executed line-by-line, and the result of execution is stored in a variable having the name res. If res is never assigned in the program, then the result will be equal to the value of res before running the program. Two programs are called equivalent if no matter which operations do characters $, ^, # and & denote (but, obviously, performing the same operation on the same arguments gives the same result) and which values do variables have before execution of program, the value of res after running the first program is equal to the value of res after running the second program (the programs are executed independently). You are given a program consisting of n lines. Your task is to write a program consisting of minimum possible number of lines that is equivalent to the program you are given. Input The first line contains one integer n (1 ≀ n ≀ 1000) β€” the number of lines in the program. Then n lines follow β€” the program itself. Each line corresponds to the format described in the statement and has no extra whitespaces. Output In the first line print k β€” the minimum number of lines in the equivalent program. Then print k lines without any whitespaces β€” an equivalent program having exactly k lines, in the same format it is described in the statement. Examples Input 4 c=aa#bb d12=c res=c^d12 tmp=aa$c Output 2 aaaa=aa#bb res=aaaa^aaaa Input 2 max=aaaa$bbbb min=bbbb^aaaa Output 0 Submitted Solution: ``` import string import random def simplify_params(value): value = value the_sign = '' lv = '' rest = '' for i in range(len(value)): charr = value[i] # print('character i = {} , a charr = {}'.format(i, charr)) if charr == '^' or charr =='#' or charr =='$' or charr=='&': the_sign = charr lv = value[:i] rest = value[i+1:] # print("KAO TUJ TREBA DA ISKOCI ? ") break if not lv: lv = value # print('lv = {}, the_sign = {}, rest = {}'.format(lv, the_sign, rest)) return lv, the_sign, rest def req(value, lista): lista.append(value) # print("VALUE -> {} ".format(value)) if not value: return '' if value in main_dict.keys(): # print("return main_dict[value] = {}".format(main_dict[value])) req(main_dict[value], lista) lv, first_sign, rest = simplify_params(value) if lv in main_dict.keys(): # print('return {} + {} + req({})'.format(lv, first_sign, rest)) return req(main_dict[lv] + first_sign, lista) + req(rest, lista) else: # print('return {} + {} + req({})'.format(lv, first_sign, rest)) return (lv + first_sign) + req(rest, lista) main_dict = {} n = input() for i in range(int(n)): text_line = input() lv, rv = text_line.split('=') # temp_val = main_dict.get(lv, []) # temp_val.append(rv) # main_dict[lv] = temp_val main_dict[lv] = rv if not 'res' in main_dict.keys(): # print('0') pass res = main_dict.get('res') # print("main_dict -> {}".format(main_dict)) # print("RES -> {}".format(res)) # print('pred REQ') listata = [] stringat = req(res, listata) # print( "STRINGAT -> {} ".format(stringat)) # print('listata -> ') # print(listata) # print('2') # print('bbb=aa#bb') # print('res=bbb^bbb') print_lista = [] for item in listata: if not item: continue charr = item[len(item)-1] # print('charr -> {}'.format(charr)) if charr == '^' or charr =='#' or charr =='$' or charr=='&': item = item[:-1] if item in stringat: rand_name = ''.join(random.choice(string.ascii_uppercase) for _ in range(4)) print_lista.append(str(rand_name) + '=' + str(item)) stringat = stringat.replace(str(item), str(rand_name)) # print('stringat = {}'.format(stringat)) print_lista.append('res=' +str(stringat)) # print("PRINT LISTAAA -> ") # print(print_lista) [print(item) for item in print_lista] ```
instruction
0
107,894
18
215,788
No
output
1
107,894
18
215,789
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Let's analyze a program written on some strange programming language. The variables in this language have names consisting of 1 to 4 characters, and each character is a lowercase or an uppercase Latin letter, or a digit. There is an extra constraint that the first character should not be a digit. There are four types of operations in the program, each denoted by one of the characters: $, ^, # or &. Each line of the program has one of the following formats: * <lvalue>=<rvalue>, where <lvalue> and <rvalue> are valid variable names; * <lvalue>=<arg1><op><arg2>, where <lvalue>, <arg1> and <arg2> are valid variable names, and <op> is an operation character. The program is executed line-by-line, and the result of execution is stored in a variable having the name res. If res is never assigned in the program, then the result will be equal to the value of res before running the program. Two programs are called equivalent if no matter which operations do characters $, ^, # and & denote (but, obviously, performing the same operation on the same arguments gives the same result) and which values do variables have before execution of program, the value of res after running the first program is equal to the value of res after running the second program (the programs are executed independently). You are given a program consisting of n lines. Your task is to write a program consisting of minimum possible number of lines that is equivalent to the program you are given. Input The first line contains one integer n (1 ≀ n ≀ 1000) β€” the number of lines in the program. Then n lines follow β€” the program itself. Each line corresponds to the format described in the statement and has no extra whitespaces. Output In the first line print k β€” the minimum number of lines in the equivalent program. Then print k lines without any whitespaces β€” an equivalent program having exactly k lines, in the same format it is described in the statement. Examples Input 4 c=aa#bb d12=c res=c^d12 tmp=aa$c Output 2 aaaa=aa#bb res=aaaa^aaaa Input 2 max=aaaa$bbbb min=bbbb^aaaa Output 0 Submitted Solution: ``` # print('mau -> ? ') def simplify_params(value): value = value the_sign = '' lv = '' rest = '' for i in range(len(value)): charr = value[i] # print('character i = {} , a charr = {}'.format(i, charr)) if charr == '^' or charr =='#' or charr =='$' or charr=='&': the_sign = charr lv = value[:i] rest = value[i+1:] # print("KAO TUJ TREBA DA ISKOCI ? ") break if not lv: lv = value # print('lv = {}, the_sign = {}, rest = {}'.format(lv, the_sign, rest)) return lv, the_sign, rest def req(value): # print("VALUE -> {} ".format(value)) if not value: return '' if value in main_dict.keys(): # print("return main_dict[value] = {}".format(main_dict[value])) req(main_dict[value]) lv, first_sign, rest = simplify_params(value) if lv in main_dict.keys(): # print('return {} + {} + req({})'.format(lv, first_sign, rest)) return req(main_dict[lv] + first_sign) + req(rest) else: # print('return {} + {} + req({})'.format(lv, first_sign, rest)) return (lv + first_sign) + req(rest) main_dict = {} n = input() for i in range(int(n)): text_line = input() lv, rv = text_line.split('=') # temp_val = main_dict.get(lv, []) # temp_val.append(rv) # main_dict[lv] = temp_val main_dict[lv] = rv if not 'res' in main_dict.keys(): print('0') res = main_dict.get('res') # print("main_dict -> {}".format(main_dict)) # print("RES -> {}".format(res)) # print('pred REQ') stringat = req(res) # print( "STRINGAT -> {} ".format(stringat)) print('2') print('aaaa=aa#bb') print('res=aaaa^aaaa') ```
instruction
0
107,895
18
215,790
No
output
1
107,895
18
215,791
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Let's analyze a program written on some strange programming language. The variables in this language have names consisting of 1 to 4 characters, and each character is a lowercase or an uppercase Latin letter, or a digit. There is an extra constraint that the first character should not be a digit. There are four types of operations in the program, each denoted by one of the characters: $, ^, # or &. Each line of the program has one of the following formats: * <lvalue>=<rvalue>, where <lvalue> and <rvalue> are valid variable names; * <lvalue>=<arg1><op><arg2>, where <lvalue>, <arg1> and <arg2> are valid variable names, and <op> is an operation character. The program is executed line-by-line, and the result of execution is stored in a variable having the name res. If res is never assigned in the program, then the result will be equal to the value of res before running the program. Two programs are called equivalent if no matter which operations do characters $, ^, # and & denote (but, obviously, performing the same operation on the same arguments gives the same result) and which values do variables have before execution of program, the value of res after running the first program is equal to the value of res after running the second program (the programs are executed independently). You are given a program consisting of n lines. Your task is to write a program consisting of minimum possible number of lines that is equivalent to the program you are given. Input The first line contains one integer n (1 ≀ n ≀ 1000) β€” the number of lines in the program. Then n lines follow β€” the program itself. Each line corresponds to the format described in the statement and has no extra whitespaces. Output In the first line print k β€” the minimum number of lines in the equivalent program. Then print k lines without any whitespaces β€” an equivalent program having exactly k lines, in the same format it is described in the statement. Examples Input 4 c=aa#bb d12=c res=c^d12 tmp=aa$c Output 2 aaaa=aa#bb res=aaaa^aaaa Input 2 max=aaaa$bbbb min=bbbb^aaaa Output 0 Submitted Solution: ``` import string import random def simplify_params(value): value = value the_sign = '' lv = '' rest = '' for i in range(len(value)): charr = value[i] # print('character i = {} , a charr = {}'.format(i, charr)) if charr == '^' or charr =='#' or charr =='$' or charr=='&': the_sign = charr lv = value[:i] rest = value[i+1:] # print("KAO TUJ TREBA DA ISKOCI ? ") break if not lv: lv = value # print('lv = {}, the_sign = {}, rest = {}'.format(lv, the_sign, rest)) return lv, the_sign, rest def req(value, lista): lista.append(value) # print("VALUE -> {} ".format(value)) if not value: return '' if value in main_dict.keys(): # print("return main_dict[value] = {}".format(main_dict[value])) req(main_dict[value], lista) lv, first_sign, rest = simplify_params(value) if lv in main_dict.keys(): # print('return {} + {} + req({})'.format(lv, first_sign, rest)) return req(main_dict[lv] + first_sign, lista) + req(rest, lista) else: # print('return {} + {} + req({})'.format(lv, first_sign, rest)) return (lv + first_sign) + req(rest, lista) main_dict = {} n = input() for i in range(int(n)): text_line = input() lv, rv = text_line.split('=') # temp_val = main_dict.get(lv, []) # temp_val.append(rv) # main_dict[lv] = temp_val main_dict[lv] = rv if not 'res' in main_dict.keys(): # print('0') pass res = main_dict.get('res') # print("main_dict -> {}".format(main_dict)) # print("RES -> {}".format(res)) # print('pred REQ') listata = [] stringat = req(res, listata) # print( "STRINGAT -> {} ".format(stringat)) # print('listata -> ') # print(listata) # print('2') # print('bbb=aa#bb') # print('res=bbb^bbb') print_lista = [] for item in listata: if not item: continue charr = item[len(item)-1] # print('charr -> {}'.format(charr)) if charr == '^' or charr =='#' or charr =='$' or charr=='&': item = item[:-1] if item in stringat: rand_name = ''.join(random.choice(string.ascii_uppercase) for _ in range(4)) print_lista.append(str(rand_name) + '=' + str(item)) stringat = stringat.replace(str(item), str(rand_name)) # print('stringat = {}'.format(stringat)) print_lista.append('res=' +str(stringat)) # print("PRINT LISTAAA -> ") # print(print_lista) print(len(print_lista)) [print(item) for item in print_lista] ```
instruction
0
107,896
18
215,792
No
output
1
107,896
18
215,793
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Let's analyze a program written on some strange programming language. The variables in this language have names consisting of 1 to 4 characters, and each character is a lowercase or an uppercase Latin letter, or a digit. There is an extra constraint that the first character should not be a digit. There are four types of operations in the program, each denoted by one of the characters: $, ^, # or &. Each line of the program has one of the following formats: * <lvalue>=<rvalue>, where <lvalue> and <rvalue> are valid variable names; * <lvalue>=<arg1><op><arg2>, where <lvalue>, <arg1> and <arg2> are valid variable names, and <op> is an operation character. The program is executed line-by-line, and the result of execution is stored in a variable having the name res. If res is never assigned in the program, then the result will be equal to the value of res before running the program. Two programs are called equivalent if no matter which operations do characters $, ^, # and & denote (but, obviously, performing the same operation on the same arguments gives the same result) and which values do variables have before execution of program, the value of res after running the first program is equal to the value of res after running the second program (the programs are executed independently). You are given a program consisting of n lines. Your task is to write a program consisting of minimum possible number of lines that is equivalent to the program you are given. Input The first line contains one integer n (1 ≀ n ≀ 1000) β€” the number of lines in the program. Then n lines follow β€” the program itself. Each line corresponds to the format described in the statement and has no extra whitespaces. Output In the first line print k β€” the minimum number of lines in the equivalent program. Then print k lines without any whitespaces β€” an equivalent program having exactly k lines, in the same format it is described in the statement. Examples Input 4 c=aa#bb d12=c res=c^d12 tmp=aa$c Output 2 aaaa=aa#bb res=aaaa^aaaa Input 2 max=aaaa$bbbb min=bbbb^aaaa Output 0 Submitted Solution: ``` # print('mau -> ? ') def simplify_params(value): value = value the_sign = '' lv = '' rest = '' for i in range(len(value)): charr = value[i] # print('character i = {} , a charr = {}'.format(i, charr)) if charr == '^' or charr =='#' or charr =='$' or charr=='&': the_sign = charr lv = value[:i] rest = value[i+1:] # print("KAO TUJ TREBA DA ISKOCI ? ") break if not lv: lv = value # print('lv = {}, the_sign = {}, rest = {}'.format(lv, the_sign, rest)) return lv, the_sign, rest def req(value): # print("VALUE -> {} ".format(value)) if not value: return '' if value in main_dict.keys(): # print("return main_dict[value] = {}".format(main_dict[value])) req(main_dict[value]) lv, first_sign, rest = simplify_params(value) if lv in main_dict.keys(): # print('return {} + {} + req({})'.format(lv, first_sign, rest)) return req(main_dict[lv] + first_sign) + req(rest) else: # print('return {} + {} + req({})'.format(lv, first_sign, rest)) return (lv + first_sign) + req(rest) main_dict = {} n = input() for i in range(int(n)): text_line = input() lv, rv = text_line.split('=') # temp_val = main_dict.get(lv, []) # temp_val.append(rv) # main_dict[lv] = temp_val main_dict[lv] = rv if not 'res' in main_dict.keys(): # print('0') pass res = main_dict.get('res') # print("main_dict -> {}".format(main_dict)) # print("RES -> {}".format(res)) # print('pred REQ') stringat = req(res) # print( "STRINGAT -> {} ".format(stringat)) print('2') print('bbb=aa#bb') print('res=bbb^bbb') ```
instruction
0
107,897
18
215,794
No
output
1
107,897
18
215,795
Provide tags and a correct Python 3 solution for this coding contest problem. It's hard times now. Today Petya needs to score 100 points on Informatics exam. The tasks seem easy to Petya, but he thinks he lacks time to finish them all, so he asks you to help with one.. There is a glob pattern in the statements (a string consisting of lowercase English letters, characters "?" and "*"). It is known that character "*" occurs no more than once in the pattern. Also, n query strings are given, it is required to determine for each of them if the pattern matches it or not. Everything seemed easy to Petya, but then he discovered that the special pattern characters differ from their usual meaning. A pattern matches a string if it is possible to replace each character "?" with one good lowercase English letter, and the character "*" (if there is one) with any, including empty, string of bad lowercase English letters, so that the resulting string is the same as the given string. The good letters are given to Petya. All the others are bad. Input The first line contains a string with length from 1 to 26 consisting of distinct lowercase English letters. These letters are good letters, all the others are bad. The second line contains the pattern β€” a string s of lowercase English letters, characters "?" and "*" (1 ≀ |s| ≀ 105). It is guaranteed that character "*" occurs in s no more than once. The third line contains integer n (1 ≀ n ≀ 105) β€” the number of query strings. n lines follow, each of them contains single non-empty string consisting of lowercase English letters β€” a query string. It is guaranteed that the total length of all query strings is not greater than 105. Output Print n lines: in the i-th of them print "YES" if the pattern matches the i-th query string, and "NO" otherwise. You can choose the case (lower or upper) for each letter arbitrary. Examples Input ab a?a 2 aaa aab Output YES NO Input abc a?a?a* 4 abacaba abaca apapa aaaaax Output NO YES NO YES Note In the first example we can replace "?" with good letters "a" and "b", so we can see that the answer for the first query is "YES", and the answer for the second query is "NO", because we can't match the third letter. Explanation of the second example. * The first query: "NO", because character "*" can be replaced with a string of bad letters only, but the only way to match the query string is to replace it with the string "ba", in which both letters are good. * The second query: "YES", because characters "?" can be replaced with corresponding good letters, and character "*" can be replaced with empty string, and the strings will coincide. * The third query: "NO", because characters "?" can't be replaced with bad letters. * The fourth query: "YES", because characters "?" can be replaced with good letters "a", and character "*" can be replaced with a string of bad letters "x".
instruction
0
108,330
18
216,660
Tags: implementation, strings Correct Solution: ``` l = input() s = input() n = int(input()) a = [] for _ in range(n): c = input() nl = s if '*' in nl: if len(nl) <= len(c): nl = nl.replace('*', '*'*(abs(len(nl)-len(c))+1)) elif len(nl)==len(c)+1: nl = nl.replace('*', '') if len(c)!=len(nl): a.append("NO") else: for i in range(len(c)): if nl[i] == '*': if c[i] in l: a.append("NO") break elif nl[i] == '?': if c[i] not in l: a.append("NO") break else: if nl[i] != c[i]: a.append("NO") break else: a.append("YES") for i in a: print(i) ```
output
1
108,330
18
216,661
Provide tags and a correct Python 3 solution for this coding contest problem. It's hard times now. Today Petya needs to score 100 points on Informatics exam. The tasks seem easy to Petya, but he thinks he lacks time to finish them all, so he asks you to help with one.. There is a glob pattern in the statements (a string consisting of lowercase English letters, characters "?" and "*"). It is known that character "*" occurs no more than once in the pattern. Also, n query strings are given, it is required to determine for each of them if the pattern matches it or not. Everything seemed easy to Petya, but then he discovered that the special pattern characters differ from their usual meaning. A pattern matches a string if it is possible to replace each character "?" with one good lowercase English letter, and the character "*" (if there is one) with any, including empty, string of bad lowercase English letters, so that the resulting string is the same as the given string. The good letters are given to Petya. All the others are bad. Input The first line contains a string with length from 1 to 26 consisting of distinct lowercase English letters. These letters are good letters, all the others are bad. The second line contains the pattern β€” a string s of lowercase English letters, characters "?" and "*" (1 ≀ |s| ≀ 105). It is guaranteed that character "*" occurs in s no more than once. The third line contains integer n (1 ≀ n ≀ 105) β€” the number of query strings. n lines follow, each of them contains single non-empty string consisting of lowercase English letters β€” a query string. It is guaranteed that the total length of all query strings is not greater than 105. Output Print n lines: in the i-th of them print "YES" if the pattern matches the i-th query string, and "NO" otherwise. You can choose the case (lower or upper) for each letter arbitrary. Examples Input ab a?a 2 aaa aab Output YES NO Input abc a?a?a* 4 abacaba abaca apapa aaaaax Output NO YES NO YES Note In the first example we can replace "?" with good letters "a" and "b", so we can see that the answer for the first query is "YES", and the answer for the second query is "NO", because we can't match the third letter. Explanation of the second example. * The first query: "NO", because character "*" can be replaced with a string of bad letters only, but the only way to match the query string is to replace it with the string "ba", in which both letters are good. * The second query: "YES", because characters "?" can be replaced with corresponding good letters, and character "*" can be replaced with empty string, and the strings will coincide. * The third query: "NO", because characters "?" can't be replaced with bad letters. * The fourth query: "YES", because characters "?" can be replaced with good letters "a", and character "*" can be replaced with a string of bad letters "x".
instruction
0
108,331
18
216,662
Tags: implementation, strings Correct Solution: ``` a=input() s=input() k=int(input()) def qw(c): t=True w=-1 if len(s)>len(c)+1: t=False try: for j in range(len(s)): w+=1 if s[j]=='?': if c[w] not in a: t=False elif s[j]=='*': b=len(c)-len(s)+1 for e in c[j:j+b]: if e in a: t=False w+=b-1 else: if s[j]!=c[w]: t=False if t==False: break except IndexError: return False return t if len(c)==w+1 else False for i in range(k): c=input() print('YES') if qw(c) else print('NO') ```
output
1
108,331
18
216,663
Provide tags and a correct Python 3 solution for this coding contest problem. It's hard times now. Today Petya needs to score 100 points on Informatics exam. The tasks seem easy to Petya, but he thinks he lacks time to finish them all, so he asks you to help with one.. There is a glob pattern in the statements (a string consisting of lowercase English letters, characters "?" and "*"). It is known that character "*" occurs no more than once in the pattern. Also, n query strings are given, it is required to determine for each of them if the pattern matches it or not. Everything seemed easy to Petya, but then he discovered that the special pattern characters differ from their usual meaning. A pattern matches a string if it is possible to replace each character "?" with one good lowercase English letter, and the character "*" (if there is one) with any, including empty, string of bad lowercase English letters, so that the resulting string is the same as the given string. The good letters are given to Petya. All the others are bad. Input The first line contains a string with length from 1 to 26 consisting of distinct lowercase English letters. These letters are good letters, all the others are bad. The second line contains the pattern β€” a string s of lowercase English letters, characters "?" and "*" (1 ≀ |s| ≀ 105). It is guaranteed that character "*" occurs in s no more than once. The third line contains integer n (1 ≀ n ≀ 105) β€” the number of query strings. n lines follow, each of them contains single non-empty string consisting of lowercase English letters β€” a query string. It is guaranteed that the total length of all query strings is not greater than 105. Output Print n lines: in the i-th of them print "YES" if the pattern matches the i-th query string, and "NO" otherwise. You can choose the case (lower or upper) for each letter arbitrary. Examples Input ab a?a 2 aaa aab Output YES NO Input abc a?a?a* 4 abacaba abaca apapa aaaaax Output NO YES NO YES Note In the first example we can replace "?" with good letters "a" and "b", so we can see that the answer for the first query is "YES", and the answer for the second query is "NO", because we can't match the third letter. Explanation of the second example. * The first query: "NO", because character "*" can be replaced with a string of bad letters only, but the only way to match the query string is to replace it with the string "ba", in which both letters are good. * The second query: "YES", because characters "?" can be replaced with corresponding good letters, and character "*" can be replaced with empty string, and the strings will coincide. * The third query: "NO", because characters "?" can't be replaced with bad letters. * The fourth query: "YES", because characters "?" can be replaced with good letters "a", and character "*" can be replaced with a string of bad letters "x".
instruction
0
108,332
18
216,664
Tags: implementation, strings Correct Solution: ``` a=input() s=input() k=int(input()) def qw(c): t=True w=-1 if len(s)>len(c)+1: t=False try: for j in range(len(s)): w+=1 if s[j]=='?': if c[w] not in a: t=False elif s[j]=='*': b=len(c)-len(s)+1 for e in c[j:j+b]: if e in a: t=False w+=b-1 else: if s[j]!=c[w]: t=False if t==False: break except IndexError: return False return t if len(c)==w+1 else False for i in range(k): c=input() print('YES') if qw(c) else print('NO') # Made By Mostafa_Khaled ```
output
1
108,332
18
216,665
Provide tags and a correct Python 3 solution for this coding contest problem. It's hard times now. Today Petya needs to score 100 points on Informatics exam. The tasks seem easy to Petya, but he thinks he lacks time to finish them all, so he asks you to help with one.. There is a glob pattern in the statements (a string consisting of lowercase English letters, characters "?" and "*"). It is known that character "*" occurs no more than once in the pattern. Also, n query strings are given, it is required to determine for each of them if the pattern matches it or not. Everything seemed easy to Petya, but then he discovered that the special pattern characters differ from their usual meaning. A pattern matches a string if it is possible to replace each character "?" with one good lowercase English letter, and the character "*" (if there is one) with any, including empty, string of bad lowercase English letters, so that the resulting string is the same as the given string. The good letters are given to Petya. All the others are bad. Input The first line contains a string with length from 1 to 26 consisting of distinct lowercase English letters. These letters are good letters, all the others are bad. The second line contains the pattern β€” a string s of lowercase English letters, characters "?" and "*" (1 ≀ |s| ≀ 105). It is guaranteed that character "*" occurs in s no more than once. The third line contains integer n (1 ≀ n ≀ 105) β€” the number of query strings. n lines follow, each of them contains single non-empty string consisting of lowercase English letters β€” a query string. It is guaranteed that the total length of all query strings is not greater than 105. Output Print n lines: in the i-th of them print "YES" if the pattern matches the i-th query string, and "NO" otherwise. You can choose the case (lower or upper) for each letter arbitrary. Examples Input ab a?a 2 aaa aab Output YES NO Input abc a?a?a* 4 abacaba abaca apapa aaaaax Output NO YES NO YES Note In the first example we can replace "?" with good letters "a" and "b", so we can see that the answer for the first query is "YES", and the answer for the second query is "NO", because we can't match the third letter. Explanation of the second example. * The first query: "NO", because character "*" can be replaced with a string of bad letters only, but the only way to match the query string is to replace it with the string "ba", in which both letters are good. * The second query: "YES", because characters "?" can be replaced with corresponding good letters, and character "*" can be replaced with empty string, and the strings will coincide. * The third query: "NO", because characters "?" can't be replaced with bad letters. * The fourth query: "YES", because characters "?" can be replaced with good letters "a", and character "*" can be replaced with a string of bad letters "x".
instruction
0
108,333
18
216,666
Tags: implementation, strings Correct Solution: ``` p=q=[] g=input() a=input() for _ in range(int(input())): ans=1 x=input() if len(x)<len(a)-1 or ('*' not in a and len(x)!=len(a)): ans=0 if ans: i=0 while i<min(len(a), len(x)) and a[i]!='*': if a[i]=='?': if x[i] not in g: ans=0 break else: if a[i]!=x[i]: ans=0 break i+=1 j=i if ans and i<len(a): i=len(a)-1 z=len(x)-1 while a[i]!='*': if a[i]=='?': if x[z] not in g: ans=0 break else: if a[i]!=x[z]: ans=0 break i-=1 z-=1 k=z+1 if ans: for i in range(j, k): if x[i] in g: ans=0 break print(['NO', 'YES'][ans]) ```
output
1
108,333
18
216,667
Provide tags and a correct Python 3 solution for this coding contest problem. It's hard times now. Today Petya needs to score 100 points on Informatics exam. The tasks seem easy to Petya, but he thinks he lacks time to finish them all, so he asks you to help with one.. There is a glob pattern in the statements (a string consisting of lowercase English letters, characters "?" and "*"). It is known that character "*" occurs no more than once in the pattern. Also, n query strings are given, it is required to determine for each of them if the pattern matches it or not. Everything seemed easy to Petya, but then he discovered that the special pattern characters differ from their usual meaning. A pattern matches a string if it is possible to replace each character "?" with one good lowercase English letter, and the character "*" (if there is one) with any, including empty, string of bad lowercase English letters, so that the resulting string is the same as the given string. The good letters are given to Petya. All the others are bad. Input The first line contains a string with length from 1 to 26 consisting of distinct lowercase English letters. These letters are good letters, all the others are bad. The second line contains the pattern β€” a string s of lowercase English letters, characters "?" and "*" (1 ≀ |s| ≀ 105). It is guaranteed that character "*" occurs in s no more than once. The third line contains integer n (1 ≀ n ≀ 105) β€” the number of query strings. n lines follow, each of them contains single non-empty string consisting of lowercase English letters β€” a query string. It is guaranteed that the total length of all query strings is not greater than 105. Output Print n lines: in the i-th of them print "YES" if the pattern matches the i-th query string, and "NO" otherwise. You can choose the case (lower or upper) for each letter arbitrary. Examples Input ab a?a 2 aaa aab Output YES NO Input abc a?a?a* 4 abacaba abaca apapa aaaaax Output NO YES NO YES Note In the first example we can replace "?" with good letters "a" and "b", so we can see that the answer for the first query is "YES", and the answer for the second query is "NO", because we can't match the third letter. Explanation of the second example. * The first query: "NO", because character "*" can be replaced with a string of bad letters only, but the only way to match the query string is to replace it with the string "ba", in which both letters are good. * The second query: "YES", because characters "?" can be replaced with corresponding good letters, and character "*" can be replaced with empty string, and the strings will coincide. * The third query: "NO", because characters "?" can't be replaced with bad letters. * The fourth query: "YES", because characters "?" can be replaced with good letters "a", and character "*" can be replaced with a string of bad letters "x".
instruction
0
108,334
18
216,668
Tags: implementation, strings Correct Solution: ``` import pdb good_letters = set(input()) pattern = input() n = int(input()) def ismatch(pattern, query): if len(pattern) != len(query): return False zipped = zip(pattern, query) for (a, b) in zipped: if a.isalpha(): if b != a: return False elif a == '?': if b not in good_letters: return False return True if pattern.find('*') == -1: for i in range(n): if ismatch(pattern, input()): print("YES") else: print("NO") else: (p1, sep, p2) = pattern.partition('*') #pdb.set_trace() for i in range(n): query = input() if len(query) < len(pattern) - 1: print("NO") else: s1 = query[:len(p1)] if len(p2) > 0: s2 = query[-len(p2):] mid = set(query[len(p1):-len(p2)]) else: s2 = "" mid = set(query[len(p1):]) if ismatch(p1, s1) and ismatch(p2, s2) and mid.isdisjoint(good_letters): print("YES") else: print("NO") ```
output
1
108,334
18
216,669
Provide tags and a correct Python 3 solution for this coding contest problem. It's hard times now. Today Petya needs to score 100 points on Informatics exam. The tasks seem easy to Petya, but he thinks he lacks time to finish them all, so he asks you to help with one.. There is a glob pattern in the statements (a string consisting of lowercase English letters, characters "?" and "*"). It is known that character "*" occurs no more than once in the pattern. Also, n query strings are given, it is required to determine for each of them if the pattern matches it or not. Everything seemed easy to Petya, but then he discovered that the special pattern characters differ from their usual meaning. A pattern matches a string if it is possible to replace each character "?" with one good lowercase English letter, and the character "*" (if there is one) with any, including empty, string of bad lowercase English letters, so that the resulting string is the same as the given string. The good letters are given to Petya. All the others are bad. Input The first line contains a string with length from 1 to 26 consisting of distinct lowercase English letters. These letters are good letters, all the others are bad. The second line contains the pattern β€” a string s of lowercase English letters, characters "?" and "*" (1 ≀ |s| ≀ 105). It is guaranteed that character "*" occurs in s no more than once. The third line contains integer n (1 ≀ n ≀ 105) β€” the number of query strings. n lines follow, each of them contains single non-empty string consisting of lowercase English letters β€” a query string. It is guaranteed that the total length of all query strings is not greater than 105. Output Print n lines: in the i-th of them print "YES" if the pattern matches the i-th query string, and "NO" otherwise. You can choose the case (lower or upper) for each letter arbitrary. Examples Input ab a?a 2 aaa aab Output YES NO Input abc a?a?a* 4 abacaba abaca apapa aaaaax Output NO YES NO YES Note In the first example we can replace "?" with good letters "a" and "b", so we can see that the answer for the first query is "YES", and the answer for the second query is "NO", because we can't match the third letter. Explanation of the second example. * The first query: "NO", because character "*" can be replaced with a string of bad letters only, but the only way to match the query string is to replace it with the string "ba", in which both letters are good. * The second query: "YES", because characters "?" can be replaced with corresponding good letters, and character "*" can be replaced with empty string, and the strings will coincide. * The third query: "NO", because characters "?" can't be replaced with bad letters. * The fourth query: "YES", because characters "?" can be replaced with good letters "a", and character "*" can be replaced with a string of bad letters "x".
instruction
0
108,335
18
216,670
Tags: implementation, strings Correct Solution: ``` good = set(input().strip()) pattern = input().strip() n = int(input()) minlen = len(pattern) is_star = '*' in pattern if is_star: minlen -= 1 maxlen = 1000000000 leftlen = pattern.find('*') rightlen = len(pattern) - leftlen - 1 else: maxlen = minlen def check_simple_pattern(task, pattern): #print(task +" -> " + pattern) for i in range(len(task)): if pattern[i] != task[i] and not (pattern[i] == '?' and task[i] in good): return False return True def check(task): if len(task) < minlen or len(task) > maxlen: return False if is_star: if rightlen == 0: cond = all([i not in good for i in task[leftlen:]]) else: cond = all([i not in good for i in task[leftlen:-rightlen]]) return check_simple_pattern(task[:leftlen], pattern[:leftlen]) \ and (rightlen == 0 or check_simple_pattern(task[-rightlen:], pattern[-rightlen:])) \ and cond else: return check_simple_pattern(task, pattern) for i in range(n): task = input().strip() if check(task): print("YES") else: print("NO") ```
output
1
108,335
18
216,671
Provide tags and a correct Python 3 solution for this coding contest problem. It's hard times now. Today Petya needs to score 100 points on Informatics exam. The tasks seem easy to Petya, but he thinks he lacks time to finish them all, so he asks you to help with one.. There is a glob pattern in the statements (a string consisting of lowercase English letters, characters "?" and "*"). It is known that character "*" occurs no more than once in the pattern. Also, n query strings are given, it is required to determine for each of them if the pattern matches it or not. Everything seemed easy to Petya, but then he discovered that the special pattern characters differ from their usual meaning. A pattern matches a string if it is possible to replace each character "?" with one good lowercase English letter, and the character "*" (if there is one) with any, including empty, string of bad lowercase English letters, so that the resulting string is the same as the given string. The good letters are given to Petya. All the others are bad. Input The first line contains a string with length from 1 to 26 consisting of distinct lowercase English letters. These letters are good letters, all the others are bad. The second line contains the pattern β€” a string s of lowercase English letters, characters "?" and "*" (1 ≀ |s| ≀ 105). It is guaranteed that character "*" occurs in s no more than once. The third line contains integer n (1 ≀ n ≀ 105) β€” the number of query strings. n lines follow, each of them contains single non-empty string consisting of lowercase English letters β€” a query string. It is guaranteed that the total length of all query strings is not greater than 105. Output Print n lines: in the i-th of them print "YES" if the pattern matches the i-th query string, and "NO" otherwise. You can choose the case (lower or upper) for each letter arbitrary. Examples Input ab a?a 2 aaa aab Output YES NO Input abc a?a?a* 4 abacaba abaca apapa aaaaax Output NO YES NO YES Note In the first example we can replace "?" with good letters "a" and "b", so we can see that the answer for the first query is "YES", and the answer for the second query is "NO", because we can't match the third letter. Explanation of the second example. * The first query: "NO", because character "*" can be replaced with a string of bad letters only, but the only way to match the query string is to replace it with the string "ba", in which both letters are good. * The second query: "YES", because characters "?" can be replaced with corresponding good letters, and character "*" can be replaced with empty string, and the strings will coincide. * The third query: "NO", because characters "?" can't be replaced with bad letters. * The fourth query: "YES", because characters "?" can be replaced with good letters "a", and character "*" can be replaced with a string of bad letters "x".
instruction
0
108,336
18
216,672
Tags: implementation, strings Correct Solution: ``` goods = input() query = input().split('*') l = [len(s) for s in query] def match(pat, s): if len(pat) != len(s): return False for x, y in zip(pat, s): if x == '?': if y not in goods: return False else: if x != y: return False return True for tc in range(int(input())): s = input() if len(query) == 1: left = match(query[0], s) mid = True right = True else: left = match(query[0], s[:l[0]]) mid = len(s) >= sum(l) and all(c not in goods for c in s[l[0]:len(s) - l[1]]) right = match(query[1], s[len(s) - l[1]:]) print('YES' if left and mid and right else 'NO') ```
output
1
108,336
18
216,673
Provide tags and a correct Python 3 solution for this coding contest problem. It's hard times now. Today Petya needs to score 100 points on Informatics exam. The tasks seem easy to Petya, but he thinks he lacks time to finish them all, so he asks you to help with one.. There is a glob pattern in the statements (a string consisting of lowercase English letters, characters "?" and "*"). It is known that character "*" occurs no more than once in the pattern. Also, n query strings are given, it is required to determine for each of them if the pattern matches it or not. Everything seemed easy to Petya, but then he discovered that the special pattern characters differ from their usual meaning. A pattern matches a string if it is possible to replace each character "?" with one good lowercase English letter, and the character "*" (if there is one) with any, including empty, string of bad lowercase English letters, so that the resulting string is the same as the given string. The good letters are given to Petya. All the others are bad. Input The first line contains a string with length from 1 to 26 consisting of distinct lowercase English letters. These letters are good letters, all the others are bad. The second line contains the pattern β€” a string s of lowercase English letters, characters "?" and "*" (1 ≀ |s| ≀ 105). It is guaranteed that character "*" occurs in s no more than once. The third line contains integer n (1 ≀ n ≀ 105) β€” the number of query strings. n lines follow, each of them contains single non-empty string consisting of lowercase English letters β€” a query string. It is guaranteed that the total length of all query strings is not greater than 105. Output Print n lines: in the i-th of them print "YES" if the pattern matches the i-th query string, and "NO" otherwise. You can choose the case (lower or upper) for each letter arbitrary. Examples Input ab a?a 2 aaa aab Output YES NO Input abc a?a?a* 4 abacaba abaca apapa aaaaax Output NO YES NO YES Note In the first example we can replace "?" with good letters "a" and "b", so we can see that the answer for the first query is "YES", and the answer for the second query is "NO", because we can't match the third letter. Explanation of the second example. * The first query: "NO", because character "*" can be replaced with a string of bad letters only, but the only way to match the query string is to replace it with the string "ba", in which both letters are good. * The second query: "YES", because characters "?" can be replaced with corresponding good letters, and character "*" can be replaced with empty string, and the strings will coincide. * The third query: "NO", because characters "?" can't be replaced with bad letters. * The fourth query: "YES", because characters "?" can be replaced with good letters "a", and character "*" can be replaced with a string of bad letters "x".
instruction
0
108,337
18
216,674
Tags: implementation, strings Correct Solution: ``` import re abc = set(list('abcdefghijklmnopqrstuvwxyz')) good = set(input()) sp = {'?', '*'} bad = abc - good ans = [] pat = input() pl = len(pat) for _ in range(int(input())): hasstar = False answered = False q = input() d = len(q) - pl if d < -1 or (d == -1 and "*" not in pat): ans.append("NO") continue else: i = 0 j = 0 while i < pl: if (pat[i] == '?' and q[j] in bad) or (pat[i] not in sp and q[j] != pat[i]): ans.append("NO") answered = True break elif pat[i] == '*': hasstar = True if any(q[k] in good for k in range(j, j+d+1)): ans.append("NO") answered = True break j += d i += 1 j += 1 if not answered: if not hasstar: if pl == len(q): ans.append('YES') answered = True else: ans.append('NO') answered = True else: ans.append("YES") answered = True print('\n'.join(ans)) ```
output
1
108,337
18
216,675
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. It's hard times now. Today Petya needs to score 100 points on Informatics exam. The tasks seem easy to Petya, but he thinks he lacks time to finish them all, so he asks you to help with one.. There is a glob pattern in the statements (a string consisting of lowercase English letters, characters "?" and "*"). It is known that character "*" occurs no more than once in the pattern. Also, n query strings are given, it is required to determine for each of them if the pattern matches it or not. Everything seemed easy to Petya, but then he discovered that the special pattern characters differ from their usual meaning. A pattern matches a string if it is possible to replace each character "?" with one good lowercase English letter, and the character "*" (if there is one) with any, including empty, string of bad lowercase English letters, so that the resulting string is the same as the given string. The good letters are given to Petya. All the others are bad. Input The first line contains a string with length from 1 to 26 consisting of distinct lowercase English letters. These letters are good letters, all the others are bad. The second line contains the pattern β€” a string s of lowercase English letters, characters "?" and "*" (1 ≀ |s| ≀ 105). It is guaranteed that character "*" occurs in s no more than once. The third line contains integer n (1 ≀ n ≀ 105) β€” the number of query strings. n lines follow, each of them contains single non-empty string consisting of lowercase English letters β€” a query string. It is guaranteed that the total length of all query strings is not greater than 105. Output Print n lines: in the i-th of them print "YES" if the pattern matches the i-th query string, and "NO" otherwise. You can choose the case (lower or upper) for each letter arbitrary. Examples Input ab a?a 2 aaa aab Output YES NO Input abc a?a?a* 4 abacaba abaca apapa aaaaax Output NO YES NO YES Note In the first example we can replace "?" with good letters "a" and "b", so we can see that the answer for the first query is "YES", and the answer for the second query is "NO", because we can't match the third letter. Explanation of the second example. * The first query: "NO", because character "*" can be replaced with a string of bad letters only, but the only way to match the query string is to replace it with the string "ba", in which both letters are good. * The second query: "YES", because characters "?" can be replaced with corresponding good letters, and character "*" can be replaced with empty string, and the strings will coincide. * The third query: "NO", because characters "?" can't be replaced with bad letters. * The fourth query: "YES", because characters "?" can be replaced with good letters "a", and character "*" can be replaced with a string of bad letters "x". Submitted Solution: ``` good, p, n = input(), input(), int(input()) plen = len(p) if '*' not in p: pflag = True else: pflag = False for c in range(n): s = input() slen, i, j, flag = len(s), 0, 0, True if slen < plen: if pflag: flag = False elif slen < plen - 1: flag = False while i < plen and flag: if p[i] == '*': break elif p[i] == '?': if s[j] not in good: flag = False else: if p[i] != s[j]: flag = False i += 1 j += 1 if i < plen and flag: sp = j i, j = plen-1, slen-1 while i >= 0 and flag: if p[i] == '*': break elif p[i] == '?': if s[j] not in good: flag = False else: if p[i] != s[j]: flag = False i -= 1 j -= 1 while j >= sp and flag: if s[j] in good: flag = False j -= 1 else: if j < slen: flag = False if flag: print("YES") else: print("NO") ```
instruction
0
108,338
18
216,676
Yes
output
1
108,338
18
216,677
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. It's hard times now. Today Petya needs to score 100 points on Informatics exam. The tasks seem easy to Petya, but he thinks he lacks time to finish them all, so he asks you to help with one.. There is a glob pattern in the statements (a string consisting of lowercase English letters, characters "?" and "*"). It is known that character "*" occurs no more than once in the pattern. Also, n query strings are given, it is required to determine for each of them if the pattern matches it or not. Everything seemed easy to Petya, but then he discovered that the special pattern characters differ from their usual meaning. A pattern matches a string if it is possible to replace each character "?" with one good lowercase English letter, and the character "*" (if there is one) with any, including empty, string of bad lowercase English letters, so that the resulting string is the same as the given string. The good letters are given to Petya. All the others are bad. Input The first line contains a string with length from 1 to 26 consisting of distinct lowercase English letters. These letters are good letters, all the others are bad. The second line contains the pattern β€” a string s of lowercase English letters, characters "?" and "*" (1 ≀ |s| ≀ 105). It is guaranteed that character "*" occurs in s no more than once. The third line contains integer n (1 ≀ n ≀ 105) β€” the number of query strings. n lines follow, each of them contains single non-empty string consisting of lowercase English letters β€” a query string. It is guaranteed that the total length of all query strings is not greater than 105. Output Print n lines: in the i-th of them print "YES" if the pattern matches the i-th query string, and "NO" otherwise. You can choose the case (lower or upper) for each letter arbitrary. Examples Input ab a?a 2 aaa aab Output YES NO Input abc a?a?a* 4 abacaba abaca apapa aaaaax Output NO YES NO YES Note In the first example we can replace "?" with good letters "a" and "b", so we can see that the answer for the first query is "YES", and the answer for the second query is "NO", because we can't match the third letter. Explanation of the second example. * The first query: "NO", because character "*" can be replaced with a string of bad letters only, but the only way to match the query string is to replace it with the string "ba", in which both letters are good. * The second query: "YES", because characters "?" can be replaced with corresponding good letters, and character "*" can be replaced with empty string, and the strings will coincide. * The third query: "NO", because characters "?" can't be replaced with bad letters. * The fourth query: "YES", because characters "?" can be replaced with good letters "a", and character "*" can be replaced with a string of bad letters "x". Submitted Solution: ``` a = [0] * 26 s = str(input()) for c in s: a[ord(c) - 97] = 1 t = str(input()) n = len(t) idx = n for j, c in enumerate(t): if c == '*': idx = j break q = int(input()) for i in range(q): p = str(input()) m = len(p) l, r = 0, 0 possible = True if idx == n: if n != m: possible = False else: for j in range(n): if t[j] == '?': if not a[ord(p[j]) - 97]: possible = False break else: if t[j] != p[j]: possible = False break if possible: print('YES') else: print('NO') else: while t[l] != '*': if l == m: possible = False break if t[l] == '?': if not a[ord(p[l]) - 97]: possible = False break else: if t[l] != p[l]: possible = False break l += 1 while t[n - r - 1] != '*': if r == m: possible = False break if t[n - r - 1] == '?': if not a[ord(p[m - r - 1]) - 97]: possible = False break else: if t[n - r - 1] != p[m - r - 1]: possible = False break r += 1 for j in range(l, l + m - r - l): if a[ord(p[j]) - 97]: possible = False break if l + r > m: possible = False if possible: print('YES') else: print('NO') ```
instruction
0
108,339
18
216,678
Yes
output
1
108,339
18
216,679
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. It's hard times now. Today Petya needs to score 100 points on Informatics exam. The tasks seem easy to Petya, but he thinks he lacks time to finish them all, so he asks you to help with one.. There is a glob pattern in the statements (a string consisting of lowercase English letters, characters "?" and "*"). It is known that character "*" occurs no more than once in the pattern. Also, n query strings are given, it is required to determine for each of them if the pattern matches it or not. Everything seemed easy to Petya, but then he discovered that the special pattern characters differ from their usual meaning. A pattern matches a string if it is possible to replace each character "?" with one good lowercase English letter, and the character "*" (if there is one) with any, including empty, string of bad lowercase English letters, so that the resulting string is the same as the given string. The good letters are given to Petya. All the others are bad. Input The first line contains a string with length from 1 to 26 consisting of distinct lowercase English letters. These letters are good letters, all the others are bad. The second line contains the pattern β€” a string s of lowercase English letters, characters "?" and "*" (1 ≀ |s| ≀ 105). It is guaranteed that character "*" occurs in s no more than once. The third line contains integer n (1 ≀ n ≀ 105) β€” the number of query strings. n lines follow, each of them contains single non-empty string consisting of lowercase English letters β€” a query string. It is guaranteed that the total length of all query strings is not greater than 105. Output Print n lines: in the i-th of them print "YES" if the pattern matches the i-th query string, and "NO" otherwise. You can choose the case (lower or upper) for each letter arbitrary. Examples Input ab a?a 2 aaa aab Output YES NO Input abc a?a?a* 4 abacaba abaca apapa aaaaax Output NO YES NO YES Note In the first example we can replace "?" with good letters "a" and "b", so we can see that the answer for the first query is "YES", and the answer for the second query is "NO", because we can't match the third letter. Explanation of the second example. * The first query: "NO", because character "*" can be replaced with a string of bad letters only, but the only way to match the query string is to replace it with the string "ba", in which both letters are good. * The second query: "YES", because characters "?" can be replaced with corresponding good letters, and character "*" can be replaced with empty string, and the strings will coincide. * The third query: "NO", because characters "?" can't be replaced with bad letters. * The fourth query: "YES", because characters "?" can be replaced with good letters "a", and character "*" can be replaced with a string of bad letters "x". Submitted Solution: ``` #------------------------------warmup---------------------------- import os import sys import math from io import BytesIO, IOBase from fractions import Fraction BUFSIZE = 8192 class FastIO(IOBase): newlines = 0 def __init__(self, file): self._fd = file.fileno() self.buffer = BytesIO() self.writable = "x" in file.mode or "r" not in file.mode self.write = self.buffer.write if self.writable else None def read(self): while True: b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE)) if not b: break ptr = self.buffer.tell() self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr) self.newlines = 0 return self.buffer.read() def readline(self): while self.newlines == 0: b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE)) self.newlines = b.count(b"\n") + (not b) ptr = self.buffer.tell() self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr) self.newlines -= 1 return self.buffer.readline() def flush(self): if self.writable: os.write(self._fd, self.buffer.getvalue()) self.buffer.truncate(0), self.buffer.seek(0) class IOWrapper(IOBase): def __init__(self, file): self.buffer = FastIO(file) self.flush = self.buffer.flush self.writable = self.buffer.writable self.write = lambda s: self.buffer.write(s.encode("ascii")) self.read = lambda: self.buffer.read().decode("ascii") self.readline = lambda: self.buffer.readline().decode("ascii") sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout) input = lambda: sys.stdin.readline().rstrip("\r\n") #-------------------game starts now---------------------------------------------------- s=input() ls=[0 for i in range(26)] for i in range(len(s)): ls[ord(s[i])-97]=1 s=input() n=int(input()) while n: q=input() if(len(q)<len(s)-1):print("NO") elif('*' not in s): if(len(s)!=len(q)):print("NO") else: flag=True for j in range(len(s)): if(s[j]!=q[j]): if(s[j]=='?'): if(ls[ord(q[j])-97]!=1): flag=False break else: flag=False break if(flag):print("YES") else:print("NO") else: flag=True i=s.index('*') for j in range(i): if(s[j]!=q[j]): if(s[j]=='?'): if(ls[ord(q[j])-97]!=1): flag=False break else: flag=False break for j in range(i,len(q)-(len(s)-i-1)): if(ls[ord(q[j])-97]!=0): flag=False break k=len(q)-(len(s)-i-1) for j in range(i+1,len(s)): if(s[j]!=q[k]): if(s[j]=='?'): if(ls[ord(q[k])-97]!=1): flag=False break else: flag=False break k+=1 if(flag):print("YES") else:print("NO") n-=1 ```
instruction
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108,340
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Yes
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108,340
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216,681
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. It's hard times now. Today Petya needs to score 100 points on Informatics exam. The tasks seem easy to Petya, but he thinks he lacks time to finish them all, so he asks you to help with one.. There is a glob pattern in the statements (a string consisting of lowercase English letters, characters "?" and "*"). It is known that character "*" occurs no more than once in the pattern. Also, n query strings are given, it is required to determine for each of them if the pattern matches it or not. Everything seemed easy to Petya, but then he discovered that the special pattern characters differ from their usual meaning. A pattern matches a string if it is possible to replace each character "?" with one good lowercase English letter, and the character "*" (if there is one) with any, including empty, string of bad lowercase English letters, so that the resulting string is the same as the given string. The good letters are given to Petya. All the others are bad. Input The first line contains a string with length from 1 to 26 consisting of distinct lowercase English letters. These letters are good letters, all the others are bad. The second line contains the pattern β€” a string s of lowercase English letters, characters "?" and "*" (1 ≀ |s| ≀ 105). It is guaranteed that character "*" occurs in s no more than once. The third line contains integer n (1 ≀ n ≀ 105) β€” the number of query strings. n lines follow, each of them contains single non-empty string consisting of lowercase English letters β€” a query string. It is guaranteed that the total length of all query strings is not greater than 105. Output Print n lines: in the i-th of them print "YES" if the pattern matches the i-th query string, and "NO" otherwise. You can choose the case (lower or upper) for each letter arbitrary. Examples Input ab a?a 2 aaa aab Output YES NO Input abc a?a?a* 4 abacaba abaca apapa aaaaax Output NO YES NO YES Note In the first example we can replace "?" with good letters "a" and "b", so we can see that the answer for the first query is "YES", and the answer for the second query is "NO", because we can't match the third letter. Explanation of the second example. * The first query: "NO", because character "*" can be replaced with a string of bad letters only, but the only way to match the query string is to replace it with the string "ba", in which both letters are good. * The second query: "YES", because characters "?" can be replaced with corresponding good letters, and character "*" can be replaced with empty string, and the strings will coincide. * The third query: "NO", because characters "?" can't be replaced with bad letters. * The fourth query: "YES", because characters "?" can be replaced with good letters "a", and character "*" can be replaced with a string of bad letters "x". Submitted Solution: ``` all_letters = {chr(i) for i in range(97, 97 + 26)} good_letters = {letter for letter in input()} bad_letters = all_letters - good_letters pattern = input() n = int(input()) star_index = pattern.find('*') def check(s, m_pattern): for i in range(len(s)): if m_pattern[i] == '$': if s[i] not in bad_letters: return False elif m_pattern[i] == '?': if s[i] not in good_letters: return False else: if m_pattern[i] != s[i]: return False return True def match(s): if len(s) < len(pattern) - 1: return False else: if len(s) == len(pattern) - 1: if star_index == -1: return False else: return check(s, pattern[:star_index] + pattern[star_index + 1:]) else: m_pattern = '' if star_index == -1: if len(s) > len(pattern): return False else: m_pattern = pattern[:] else: m_pattern += pattern[:star_index] m_sec_pattern = pattern[:star_index] for i in range(len(s) - len(pattern) + 1): m_pattern += '$' m_pattern += pattern[star_index + 1:] return check(s, m_pattern) for i in range(n): qs = input() print('YES' if match(qs) else 'NO') ```
instruction
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108,341
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Yes
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1
108,341
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216,683
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. It's hard times now. Today Petya needs to score 100 points on Informatics exam. The tasks seem easy to Petya, but he thinks he lacks time to finish them all, so he asks you to help with one.. There is a glob pattern in the statements (a string consisting of lowercase English letters, characters "?" and "*"). It is known that character "*" occurs no more than once in the pattern. Also, n query strings are given, it is required to determine for each of them if the pattern matches it or not. Everything seemed easy to Petya, but then he discovered that the special pattern characters differ from their usual meaning. A pattern matches a string if it is possible to replace each character "?" with one good lowercase English letter, and the character "*" (if there is one) with any, including empty, string of bad lowercase English letters, so that the resulting string is the same as the given string. The good letters are given to Petya. All the others are bad. Input The first line contains a string with length from 1 to 26 consisting of distinct lowercase English letters. These letters are good letters, all the others are bad. The second line contains the pattern β€” a string s of lowercase English letters, characters "?" and "*" (1 ≀ |s| ≀ 105). It is guaranteed that character "*" occurs in s no more than once. The third line contains integer n (1 ≀ n ≀ 105) β€” the number of query strings. n lines follow, each of them contains single non-empty string consisting of lowercase English letters β€” a query string. It is guaranteed that the total length of all query strings is not greater than 105. Output Print n lines: in the i-th of them print "YES" if the pattern matches the i-th query string, and "NO" otherwise. You can choose the case (lower or upper) for each letter arbitrary. Examples Input ab a?a 2 aaa aab Output YES NO Input abc a?a?a* 4 abacaba abaca apapa aaaaax Output NO YES NO YES Note In the first example we can replace "?" with good letters "a" and "b", so we can see that the answer for the first query is "YES", and the answer for the second query is "NO", because we can't match the third letter. Explanation of the second example. * The first query: "NO", because character "*" can be replaced with a string of bad letters only, but the only way to match the query string is to replace it with the string "ba", in which both letters are good. * The second query: "YES", because characters "?" can be replaced with corresponding good letters, and character "*" can be replaced with empty string, and the strings will coincide. * The third query: "NO", because characters "?" can't be replaced with bad letters. * The fourth query: "YES", because characters "?" can be replaced with good letters "a", and character "*" can be replaced with a string of bad letters "x". Submitted Solution: ``` good = input() sh = input() pr = int(input()) ind = -1 if '*' in sh: ind = sh.index('*') for i in range(pr): t = input() res = "NO" for j in range(len(sh)): if len(t) < len(sh): t = t[:ind] + ' ' + t[ind:] elif len(t) > len(sh): res = "NO" break if t[j] == sh[j]: res = "YES" elif sh[j] == '?': if t[j] in good: res = "YES" else: res = "NO" break elif sh[j] == '*': if t[j] not in good: res = "YES" else: res = "NO" print(res) ```
instruction
0
108,342
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216,684
No
output
1
108,342
18
216,685
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. It's hard times now. Today Petya needs to score 100 points on Informatics exam. The tasks seem easy to Petya, but he thinks he lacks time to finish them all, so he asks you to help with one.. There is a glob pattern in the statements (a string consisting of lowercase English letters, characters "?" and "*"). It is known that character "*" occurs no more than once in the pattern. Also, n query strings are given, it is required to determine for each of them if the pattern matches it or not. Everything seemed easy to Petya, but then he discovered that the special pattern characters differ from their usual meaning. A pattern matches a string if it is possible to replace each character "?" with one good lowercase English letter, and the character "*" (if there is one) with any, including empty, string of bad lowercase English letters, so that the resulting string is the same as the given string. The good letters are given to Petya. All the others are bad. Input The first line contains a string with length from 1 to 26 consisting of distinct lowercase English letters. These letters are good letters, all the others are bad. The second line contains the pattern β€” a string s of lowercase English letters, characters "?" and "*" (1 ≀ |s| ≀ 105). It is guaranteed that character "*" occurs in s no more than once. The third line contains integer n (1 ≀ n ≀ 105) β€” the number of query strings. n lines follow, each of them contains single non-empty string consisting of lowercase English letters β€” a query string. It is guaranteed that the total length of all query strings is not greater than 105. Output Print n lines: in the i-th of them print "YES" if the pattern matches the i-th query string, and "NO" otherwise. You can choose the case (lower or upper) for each letter arbitrary. Examples Input ab a?a 2 aaa aab Output YES NO Input abc a?a?a* 4 abacaba abaca apapa aaaaax Output NO YES NO YES Note In the first example we can replace "?" with good letters "a" and "b", so we can see that the answer for the first query is "YES", and the answer for the second query is "NO", because we can't match the third letter. Explanation of the second example. * The first query: "NO", because character "*" can be replaced with a string of bad letters only, but the only way to match the query string is to replace it with the string "ba", in which both letters are good. * The second query: "YES", because characters "?" can be replaced with corresponding good letters, and character "*" can be replaced with empty string, and the strings will coincide. * The third query: "NO", because characters "?" can't be replaced with bad letters. * The fourth query: "YES", because characters "?" can be replaced with good letters "a", and character "*" can be replaced with a string of bad letters "x". Submitted Solution: ``` lower = "azertyuiopqsdfghjklmwxcvbn" alphabet = input() pattern_str = input() n = int(input()) for i in range(n): line = list(input()) pattern = list(pattern_str) result = "NO" while len(line) > 0 and len(pattern) > 0: if line[0] not in lower: break if line[0] == pattern[0]: line.pop(0) pattern.pop(0) continue if line[0] in alphabet: if pattern[0] == "?": line.pop(0) pattern.pop(0) elif pattern[0] == "*": pattern.pop(0) else: break else: if pattern[0] == "*": line.pop(0) else: break if len(line) + len(pattern) == 0 or (len(pattern) == 1 and pattern[0] == "*"): result = "YES" print(result) ```
instruction
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108,343
18
216,686
No
output
1
108,343
18
216,687
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. It's hard times now. Today Petya needs to score 100 points on Informatics exam. The tasks seem easy to Petya, but he thinks he lacks time to finish them all, so he asks you to help with one.. There is a glob pattern in the statements (a string consisting of lowercase English letters, characters "?" and "*"). It is known that character "*" occurs no more than once in the pattern. Also, n query strings are given, it is required to determine for each of them if the pattern matches it or not. Everything seemed easy to Petya, but then he discovered that the special pattern characters differ from their usual meaning. A pattern matches a string if it is possible to replace each character "?" with one good lowercase English letter, and the character "*" (if there is one) with any, including empty, string of bad lowercase English letters, so that the resulting string is the same as the given string. The good letters are given to Petya. All the others are bad. Input The first line contains a string with length from 1 to 26 consisting of distinct lowercase English letters. These letters are good letters, all the others are bad. The second line contains the pattern β€” a string s of lowercase English letters, characters "?" and "*" (1 ≀ |s| ≀ 105). It is guaranteed that character "*" occurs in s no more than once. The third line contains integer n (1 ≀ n ≀ 105) β€” the number of query strings. n lines follow, each of them contains single non-empty string consisting of lowercase English letters β€” a query string. It is guaranteed that the total length of all query strings is not greater than 105. Output Print n lines: in the i-th of them print "YES" if the pattern matches the i-th query string, and "NO" otherwise. You can choose the case (lower or upper) for each letter arbitrary. Examples Input ab a?a 2 aaa aab Output YES NO Input abc a?a?a* 4 abacaba abaca apapa aaaaax Output NO YES NO YES Note In the first example we can replace "?" with good letters "a" and "b", so we can see that the answer for the first query is "YES", and the answer for the second query is "NO", because we can't match the third letter. Explanation of the second example. * The first query: "NO", because character "*" can be replaced with a string of bad letters only, but the only way to match the query string is to replace it with the string "ba", in which both letters are good. * The second query: "YES", because characters "?" can be replaced with corresponding good letters, and character "*" can be replaced with empty string, and the strings will coincide. * The third query: "NO", because characters "?" can't be replaced with bad letters. * The fourth query: "YES", because characters "?" can be replaced with good letters "a", and character "*" can be replaced with a string of bad letters "x". Submitted Solution: ``` l=['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'] s1=input().strip() s1=list(s1) s2=[] for i in l: if i not in s1: s2.append(i) pattern=input().strip() pattern=list(pattern) if ("*" not in pattern): length_main=len(pattern) n=int(input().strip()) for i in range(n): f=0 string=input().strip() length=len(string) if (length_main==length): for j in range(length_main): if (string[j]!=pattern[j]): if (pattern[j]!="?"): print ('NO') f=1 break else: if (string[j] not in s1): print ('NO') f=1 break else: print ('NO') if (f==0): print ('YES') else: ind=pattern.index("*") length_main=len(pattern) n=int(input().strip()) for i in range(n): string=input().strip() length=len(string) if (length<length_main-1): print ('NO') else: f=0 for j in range(ind): if (string[j]!=pattern[j]): if (pattern[j]!="?"): print ('NO') f=1 break else: if (string[j] not in s1): print ('NO') f=1 break if (f!=1): q=length_main-length for j in range(length_main-1,ind,-1): if (string[j-q]!=pattern[j]): if (pattern[j]!="?"): print ('NO') f=1 break else: if (string[j-q] not in s1): print ('NO') f=1 break if (f!=1): save= ind+1-q string=list(string) x=string[ind:save] for j in x: if (j not in s2): print ('NO') f=1 break if (f==0): print ('YES') ```
instruction
0
108,344
18
216,688
No
output
1
108,344
18
216,689
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. It's hard times now. Today Petya needs to score 100 points on Informatics exam. The tasks seem easy to Petya, but he thinks he lacks time to finish them all, so he asks you to help with one.. There is a glob pattern in the statements (a string consisting of lowercase English letters, characters "?" and "*"). It is known that character "*" occurs no more than once in the pattern. Also, n query strings are given, it is required to determine for each of them if the pattern matches it or not. Everything seemed easy to Petya, but then he discovered that the special pattern characters differ from their usual meaning. A pattern matches a string if it is possible to replace each character "?" with one good lowercase English letter, and the character "*" (if there is one) with any, including empty, string of bad lowercase English letters, so that the resulting string is the same as the given string. The good letters are given to Petya. All the others are bad. Input The first line contains a string with length from 1 to 26 consisting of distinct lowercase English letters. These letters are good letters, all the others are bad. The second line contains the pattern β€” a string s of lowercase English letters, characters "?" and "*" (1 ≀ |s| ≀ 105). It is guaranteed that character "*" occurs in s no more than once. The third line contains integer n (1 ≀ n ≀ 105) β€” the number of query strings. n lines follow, each of them contains single non-empty string consisting of lowercase English letters β€” a query string. It is guaranteed that the total length of all query strings is not greater than 105. Output Print n lines: in the i-th of them print "YES" if the pattern matches the i-th query string, and "NO" otherwise. You can choose the case (lower or upper) for each letter arbitrary. Examples Input ab a?a 2 aaa aab Output YES NO Input abc a?a?a* 4 abacaba abaca apapa aaaaax Output NO YES NO YES Note In the first example we can replace "?" with good letters "a" and "b", so we can see that the answer for the first query is "YES", and the answer for the second query is "NO", because we can't match the third letter. Explanation of the second example. * The first query: "NO", because character "*" can be replaced with a string of bad letters only, but the only way to match the query string is to replace it with the string "ba", in which both letters are good. * The second query: "YES", because characters "?" can be replaced with corresponding good letters, and character "*" can be replaced with empty string, and the strings will coincide. * The third query: "NO", because characters "?" can't be replaced with bad letters. * The fourth query: "YES", because characters "?" can be replaced with good letters "a", and character "*" can be replaced with a string of bad letters "x". Submitted Solution: ``` def do(cur)->str: i=j=0 while i<len(pt) and j<len(cur): if pt[i]=="?": if cur[j] not in good:return"NO" elif pt[i]=="*": while j<len(cur) and cur[j] not in good:j+=1 if j==len(cur): if i==len(pt)-1:break return"NO" elif i==len(pt)-1:return "NO" i+=1;continue else: if pt[i]!=cur[j]:return"NO" i+=1;j+=1 return "YES" if j==len(cur) and i==len(pt) else "NO" good=set(input()) pt=input() for _ in range(int(input())): cur=input() print(do(cur)) ```
instruction
0
108,345
18
216,690
No
output
1
108,345
18
216,691