message stringlengths 2 67k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 463 109k | cluster float64 19 19 | __index_level_0__ int64 926 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
This is an interactive problem.
John and his imaginary friend play a game. There are n lamps arranged in a circle. Lamps are numbered 1 through n in clockwise order, that is, lamps i and i + 1 are adjacent for any i = 1, …, n - 1, and also lamps n and 1 are adjacent. Initially all lamps are turned off.
John and his friend take turns, with John moving first. On his turn John can choose to terminate the game, or to make a move. To make a move, John can choose any positive number k and turn any k lamps of his choosing on. In response to this move, John's friend will choose k consecutive lamps and turn all of them off (the lamps in the range that were off before this move stay off). Note that the value of k is the same as John's number on his last move. For example, if n = 5 and John have just turned three lamps on, John's friend may choose to turn off lamps 1, 2, 3, or 2, 3, 4, or 3, 4, 5, or 4, 5, 1, or 5, 1, 2.
After this, John may choose to terminate or move again, and so on. However, John can not make more than 10^4 moves.
John wants to maximize the number of lamps turned on at the end of the game, while his friend wants to minimize this number. Your task is to provide a strategy for John to achieve optimal result. Your program will play interactively for John against the jury's interactor program playing for John's friend.
Suppose there are n lamps in the game. Let R(n) be the number of turned on lamps at the end of the game if both players act optimally. Your program has to terminate the game with at least R(n) turned on lamps within 10^4 moves. Refer to Interaction section below for interaction details.
For technical reasons hacks for this problem are disabled.
Interaction
Initially your program will be fed a single integer n (1 ≤ n ≤ 1000) — the number of lamps in the game. Then the interactor will wait for your actions.
To make a move, print a line starting with an integer k (1 ≤ k ≤ n), followed by k distinct integers l_1, …, l_k (1 ≤ l_i ≤ n) — indices of lamps you want to turn on. The indices may be printed in any order. It is allowed to try to turn on a lamp that is already on (although this will have no effect).
If your move was invalid for any reason, or if you have made more than 10^4 moves, the interactor will reply with a line containing a single integer -1. Otherwise, the reply will be a line containing a single integer x (1 ≤ x ≤ n), meaning that the response was to turn off k consecutive lamps starting from x in clockwise order.
To terminate the game instead of making a move, print a line containing a single integer 0. The test will be passed if at this point there are at least R(n) lamps turned on (note that neither R(n), nor the verdict received are not communicated to your program in any way). This action does not count towards the number of moves (that is, it is legal to terminate the game after exactly 10^4 moves).
To receive the correct verdict, your program should terminate immediately after printing 0, or after receiving -1 as a response.
Don't forget to flush your output after every action.
Examples
Input
3
Output
0
Input
4
1
Output
2 1 3
0
Note
When n = 3, any John's move can be reversed, thus R(3) = 0, and terminating the game immediately is correct.
R(4) = 1, and one strategy to achieve this result is shown in the second sample case.
Blank lines in sample interactions are for clarity and should not be printed. | instruction | 0 | 9,260 | 19 | 18,520 |
Tags: games, implementation, interactive, math
Correct Solution:
```
from sys import exit
from traceback import format_exc
def main():
n = int(input())
if n < 4:
print(0, flush=True)
return
on = [False] * n
def query(ll):
res = 0
pvals = [i+1 for i in ll]
print(len(ll), *pvals, flush=True)
for i in ll:
if not on[i]:
res += 1
on[i] = True
x = int(input())
if x == -1:
exit()
for i in range(x-1, x+len(ll)-1):
if on[i%n]:
res -= 1
on[i%n] = False
return res
k = min(range(2, n), key = lambda k: k + (n-1)//k)
blocked = [i%k == 0 for i in range(n)]
while True:
ll = []
count = 0
for i in range(n):
if not on[i] and not blocked[i]:
ll.append(i)
count+=1
if count == k:
break
res = query(ll)
if res < 1:
break
print(0, flush=True)
if __name__ == "__main__":
try:
main()
except:
print(format_exc())
``` | output | 1 | 9,260 | 19 | 18,521 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an interactive problem.
John and his imaginary friend play a game. There are n lamps arranged in a circle. Lamps are numbered 1 through n in clockwise order, that is, lamps i and i + 1 are adjacent for any i = 1, …, n - 1, and also lamps n and 1 are adjacent. Initially all lamps are turned off.
John and his friend take turns, with John moving first. On his turn John can choose to terminate the game, or to make a move. To make a move, John can choose any positive number k and turn any k lamps of his choosing on. In response to this move, John's friend will choose k consecutive lamps and turn all of them off (the lamps in the range that were off before this move stay off). Note that the value of k is the same as John's number on his last move. For example, if n = 5 and John have just turned three lamps on, John's friend may choose to turn off lamps 1, 2, 3, or 2, 3, 4, or 3, 4, 5, or 4, 5, 1, or 5, 1, 2.
After this, John may choose to terminate or move again, and so on. However, John can not make more than 10^4 moves.
John wants to maximize the number of lamps turned on at the end of the game, while his friend wants to minimize this number. Your task is to provide a strategy for John to achieve optimal result. Your program will play interactively for John against the jury's interactor program playing for John's friend.
Suppose there are n lamps in the game. Let R(n) be the number of turned on lamps at the end of the game if both players act optimally. Your program has to terminate the game with at least R(n) turned on lamps within 10^4 moves. Refer to Interaction section below for interaction details.
For technical reasons hacks for this problem are disabled.
Interaction
Initially your program will be fed a single integer n (1 ≤ n ≤ 1000) — the number of lamps in the game. Then the interactor will wait for your actions.
To make a move, print a line starting with an integer k (1 ≤ k ≤ n), followed by k distinct integers l_1, …, l_k (1 ≤ l_i ≤ n) — indices of lamps you want to turn on. The indices may be printed in any order. It is allowed to try to turn on a lamp that is already on (although this will have no effect).
If your move was invalid for any reason, or if you have made more than 10^4 moves, the interactor will reply with a line containing a single integer -1. Otherwise, the reply will be a line containing a single integer x (1 ≤ x ≤ n), meaning that the response was to turn off k consecutive lamps starting from x in clockwise order.
To terminate the game instead of making a move, print a line containing a single integer 0. The test will be passed if at this point there are at least R(n) lamps turned on (note that neither R(n), nor the verdict received are not communicated to your program in any way). This action does not count towards the number of moves (that is, it is legal to terminate the game after exactly 10^4 moves).
To receive the correct verdict, your program should terminate immediately after printing 0, or after receiving -1 as a response.
Don't forget to flush your output after every action.
Examples
Input
3
Output
0
Input
4
1
Output
2 1 3
0
Note
When n = 3, any John's move can be reversed, thus R(3) = 0, and terminating the game immediately is correct.
R(4) = 1, and one strategy to achieve this result is shown in the second sample case.
Blank lines in sample interactions are for clarity and should not be printed.
Submitted Solution:
```
from sys import stdout
def mod(a, nn):
a %= nn
if a == 0:
a = nn
return a
def move(my_move):
my_move = [str(movi) for movi in my_move]
print(" ".join(my_move))
stdout.flush()
if my_move == "0":
exit()
def friend():
begin = int(input())
if begin == -1:
exit()
else:
return begin
n = int(input())
if n < 4:
move([0])
friend_move = 1
size_k = n // 2
while size_k > 1:
next_move = [size_k]
for i in range(size_k):
next_move.append(mod(friend_move + i * 2, n))
move(next_move)
friend_move = friend()
if friend_move % 2 == 0:
friend_move += 1
size_k = (size_k + 1) // 2
move([0])
``` | instruction | 0 | 9,261 | 19 | 18,522 |
No | output | 1 | 9,261 | 19 | 18,523 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an interactive problem.
John and his imaginary friend play a game. There are n lamps arranged in a circle. Lamps are numbered 1 through n in clockwise order, that is, lamps i and i + 1 are adjacent for any i = 1, …, n - 1, and also lamps n and 1 are adjacent. Initially all lamps are turned off.
John and his friend take turns, with John moving first. On his turn John can choose to terminate the game, or to make a move. To make a move, John can choose any positive number k and turn any k lamps of his choosing on. In response to this move, John's friend will choose k consecutive lamps and turn all of them off (the lamps in the range that were off before this move stay off). Note that the value of k is the same as John's number on his last move. For example, if n = 5 and John have just turned three lamps on, John's friend may choose to turn off lamps 1, 2, 3, or 2, 3, 4, or 3, 4, 5, or 4, 5, 1, or 5, 1, 2.
After this, John may choose to terminate or move again, and so on. However, John can not make more than 10^4 moves.
John wants to maximize the number of lamps turned on at the end of the game, while his friend wants to minimize this number. Your task is to provide a strategy for John to achieve optimal result. Your program will play interactively for John against the jury's interactor program playing for John's friend.
Suppose there are n lamps in the game. Let R(n) be the number of turned on lamps at the end of the game if both players act optimally. Your program has to terminate the game with at least R(n) turned on lamps within 10^4 moves. Refer to Interaction section below for interaction details.
For technical reasons hacks for this problem are disabled.
Interaction
Initially your program will be fed a single integer n (1 ≤ n ≤ 1000) — the number of lamps in the game. Then the interactor will wait for your actions.
To make a move, print a line starting with an integer k (1 ≤ k ≤ n), followed by k distinct integers l_1, …, l_k (1 ≤ l_i ≤ n) — indices of lamps you want to turn on. The indices may be printed in any order. It is allowed to try to turn on a lamp that is already on (although this will have no effect).
If your move was invalid for any reason, or if you have made more than 10^4 moves, the interactor will reply with a line containing a single integer -1. Otherwise, the reply will be a line containing a single integer x (1 ≤ x ≤ n), meaning that the response was to turn off k consecutive lamps starting from x in clockwise order.
To terminate the game instead of making a move, print a line containing a single integer 0. The test will be passed if at this point there are at least R(n) lamps turned on (note that neither R(n), nor the verdict received are not communicated to your program in any way). This action does not count towards the number of moves (that is, it is legal to terminate the game after exactly 10^4 moves).
To receive the correct verdict, your program should terminate immediately after printing 0, or after receiving -1 as a response.
Don't forget to flush your output after every action.
Examples
Input
3
Output
0
Input
4
1
Output
2 1 3
0
Note
When n = 3, any John's move can be reversed, thus R(3) = 0, and terminating the game immediately is correct.
R(4) = 1, and one strategy to achieve this result is shown in the second sample case.
Blank lines in sample interactions are for clarity and should not be printed.
Submitted Solution:
```
import sys
input = sys.stdin.readline
def query(num):
# output
print(*num)
sys.stdout.flush()
# input
res = int(input())
return res
n = int(input())
res = [0] * n
while True:
tmp = []
for i in range(n // 2):
if res[2 * i] == 0:
tmp.append(2 * i + 1)
if len(tmp) == 2:
res[tmp[0] - 1] = 1
res[tmp[1] - 1] = 1
a1 = query(tmp)
a2 = a1 + 1
res[(a1 - 1) % n] = 0
res[(a2 - 1) % n] = 0
break
else:
print(0)
break
``` | instruction | 0 | 9,262 | 19 | 18,524 |
No | output | 1 | 9,262 | 19 | 18,525 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an interactive problem.
John and his imaginary friend play a game. There are n lamps arranged in a circle. Lamps are numbered 1 through n in clockwise order, that is, lamps i and i + 1 are adjacent for any i = 1, …, n - 1, and also lamps n and 1 are adjacent. Initially all lamps are turned off.
John and his friend take turns, with John moving first. On his turn John can choose to terminate the game, or to make a move. To make a move, John can choose any positive number k and turn any k lamps of his choosing on. In response to this move, John's friend will choose k consecutive lamps and turn all of them off (the lamps in the range that were off before this move stay off). Note that the value of k is the same as John's number on his last move. For example, if n = 5 and John have just turned three lamps on, John's friend may choose to turn off lamps 1, 2, 3, or 2, 3, 4, or 3, 4, 5, or 4, 5, 1, or 5, 1, 2.
After this, John may choose to terminate or move again, and so on. However, John can not make more than 10^4 moves.
John wants to maximize the number of lamps turned on at the end of the game, while his friend wants to minimize this number. Your task is to provide a strategy for John to achieve optimal result. Your program will play interactively for John against the jury's interactor program playing for John's friend.
Suppose there are n lamps in the game. Let R(n) be the number of turned on lamps at the end of the game if both players act optimally. Your program has to terminate the game with at least R(n) turned on lamps within 10^4 moves. Refer to Interaction section below for interaction details.
For technical reasons hacks for this problem are disabled.
Interaction
Initially your program will be fed a single integer n (1 ≤ n ≤ 1000) — the number of lamps in the game. Then the interactor will wait for your actions.
To make a move, print a line starting with an integer k (1 ≤ k ≤ n), followed by k distinct integers l_1, …, l_k (1 ≤ l_i ≤ n) — indices of lamps you want to turn on. The indices may be printed in any order. It is allowed to try to turn on a lamp that is already on (although this will have no effect).
If your move was invalid for any reason, or if you have made more than 10^4 moves, the interactor will reply with a line containing a single integer -1. Otherwise, the reply will be a line containing a single integer x (1 ≤ x ≤ n), meaning that the response was to turn off k consecutive lamps starting from x in clockwise order.
To terminate the game instead of making a move, print a line containing a single integer 0. The test will be passed if at this point there are at least R(n) lamps turned on (note that neither R(n), nor the verdict received are not communicated to your program in any way). This action does not count towards the number of moves (that is, it is legal to terminate the game after exactly 10^4 moves).
To receive the correct verdict, your program should terminate immediately after printing 0, or after receiving -1 as a response.
Don't forget to flush your output after every action.
Examples
Input
3
Output
0
Input
4
1
Output
2 1 3
0
Note
When n = 3, any John's move can be reversed, thus R(3) = 0, and terminating the game immediately is correct.
R(4) = 1, and one strategy to achieve this result is shown in the second sample case.
Blank lines in sample interactions are for clarity and should not be printed.
Submitted Solution:
```
#!/usr/bin/env python3
n = int(input())
if n<=3:
print(0)
else:
tour = 1
lampe_on = [1, 3]
print("2 1 3")
for x in range(int(n/2)-2):
n_off1 = int(input())
if n_off1 < n-1:
n_off2 = n_off1+1
else:
n_off2 = 1
if n_off1 in lampe_on:
print("2 " + str(n_off1) + " " + str(2*(x+1)+3))
elif n_off2 in lampe_on:
print("2 " + str(n_off2) + " " + str(2*(x+1)+3))
else:
print("2 1 " + str(2*(x+1)+3))
lampe_on.append(2*(x+1)+3)
print(0)
``` | instruction | 0 | 9,263 | 19 | 18,526 |
No | output | 1 | 9,263 | 19 | 18,527 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an interactive problem.
John and his imaginary friend play a game. There are n lamps arranged in a circle. Lamps are numbered 1 through n in clockwise order, that is, lamps i and i + 1 are adjacent for any i = 1, …, n - 1, and also lamps n and 1 are adjacent. Initially all lamps are turned off.
John and his friend take turns, with John moving first. On his turn John can choose to terminate the game, or to make a move. To make a move, John can choose any positive number k and turn any k lamps of his choosing on. In response to this move, John's friend will choose k consecutive lamps and turn all of them off (the lamps in the range that were off before this move stay off). Note that the value of k is the same as John's number on his last move. For example, if n = 5 and John have just turned three lamps on, John's friend may choose to turn off lamps 1, 2, 3, or 2, 3, 4, or 3, 4, 5, or 4, 5, 1, or 5, 1, 2.
After this, John may choose to terminate or move again, and so on. However, John can not make more than 10^4 moves.
John wants to maximize the number of lamps turned on at the end of the game, while his friend wants to minimize this number. Your task is to provide a strategy for John to achieve optimal result. Your program will play interactively for John against the jury's interactor program playing for John's friend.
Suppose there are n lamps in the game. Let R(n) be the number of turned on lamps at the end of the game if both players act optimally. Your program has to terminate the game with at least R(n) turned on lamps within 10^4 moves. Refer to Interaction section below for interaction details.
For technical reasons hacks for this problem are disabled.
Interaction
Initially your program will be fed a single integer n (1 ≤ n ≤ 1000) — the number of lamps in the game. Then the interactor will wait for your actions.
To make a move, print a line starting with an integer k (1 ≤ k ≤ n), followed by k distinct integers l_1, …, l_k (1 ≤ l_i ≤ n) — indices of lamps you want to turn on. The indices may be printed in any order. It is allowed to try to turn on a lamp that is already on (although this will have no effect).
If your move was invalid for any reason, or if you have made more than 10^4 moves, the interactor will reply with a line containing a single integer -1. Otherwise, the reply will be a line containing a single integer x (1 ≤ x ≤ n), meaning that the response was to turn off k consecutive lamps starting from x in clockwise order.
To terminate the game instead of making a move, print a line containing a single integer 0. The test will be passed if at this point there are at least R(n) lamps turned on (note that neither R(n), nor the verdict received are not communicated to your program in any way). This action does not count towards the number of moves (that is, it is legal to terminate the game after exactly 10^4 moves).
To receive the correct verdict, your program should terminate immediately after printing 0, or after receiving -1 as a response.
Don't forget to flush your output after every action.
Examples
Input
3
Output
0
Input
4
1
Output
2 1 3
0
Note
When n = 3, any John's move can be reversed, thus R(3) = 0, and terminating the game immediately is correct.
R(4) = 1, and one strategy to achieve this result is shown in the second sample case.
Blank lines in sample interactions are for clarity and should not be printed.
Submitted Solution:
```
n = int(input())
total = 0
x = 1
count = 1
while(total < n%2 - 1):
if x == n:
print(1, flush = True)
elif x % 2 == 1:
print(x, flush = True)
else:
print(x+1,flush = True)
print(count*2 + 1)
count += 1
total += 1
x = int(input())
print(0)
``` | instruction | 0 | 9,264 | 19 | 18,528 |
No | output | 1 | 9,264 | 19 | 18,529 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Yaroslav, Andrey and Roman can play cubes for hours and hours. But the game is for three, so when Roman doesn't show up, Yaroslav and Andrey play another game.
Roman leaves a word for each of them. Each word consists of 2·n binary characters "0" or "1". After that the players start moving in turns. Yaroslav moves first. During a move, a player must choose an integer from 1 to 2·n, which hasn't been chosen by anybody up to that moment. Then the player takes a piece of paper and writes out the corresponding character from his string.
Let's represent Yaroslav's word as s = s1s2... s2n. Similarly, let's represent Andrey's word as t = t1t2... t2n. Then, if Yaroslav choose number k during his move, then he is going to write out character sk on the piece of paper. Similarly, if Andrey choose number r during his move, then he is going to write out character tr on the piece of paper.
The game finishes when no player can make a move. After the game is over, Yaroslav makes some integer from the characters written on his piece of paper (Yaroslav can arrange these characters as he wants). Andrey does the same. The resulting numbers can contain leading zeroes. The person with the largest number wins. If the numbers are equal, the game ends with a draw.
You are given two strings s and t. Determine the outcome of the game provided that Yaroslav and Andrey play optimally well.
Input
The first line contains integer n (1 ≤ n ≤ 106). The second line contains string s — Yaroslav's word. The third line contains string t — Andrey's word.
It is guaranteed that both words consist of 2·n characters "0" and "1".
Output
Print "First", if both players play optimally well and Yaroslav wins. If Andrey wins, print "Second" and if the game ends with a draw, print "Draw". Print the words without the quotes.
Examples
Input
2
0111
0001
Output
First
Input
3
110110
001001
Output
First
Input
3
111000
000111
Output
Draw
Input
4
01010110
00101101
Output
First
Input
4
01100000
10010011
Output
Second | instruction | 0 | 9,398 | 19 | 18,796 |
Tags: games, greedy
Correct Solution:
```
#!/usr/bin/python3
n = int(input())
s = list(input())
l = list(input())
a = len([_ for _ in zip(s, l) if _ == ('1', '1')])
b = len([_ for _ in zip(s, l) if _ == ('1', '0')])
c = len([_ for _ in zip(s, l) if _ == ('0', '1')])
f = b + (a + 1) // 2
s = c + a // 2
if f > s:
print('First')
elif f + 1 < s:
print('Second')
else:
print('Draw')
``` | output | 1 | 9,398 | 19 | 18,797 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Yaroslav, Andrey and Roman can play cubes for hours and hours. But the game is for three, so when Roman doesn't show up, Yaroslav and Andrey play another game.
Roman leaves a word for each of them. Each word consists of 2·n binary characters "0" or "1". After that the players start moving in turns. Yaroslav moves first. During a move, a player must choose an integer from 1 to 2·n, which hasn't been chosen by anybody up to that moment. Then the player takes a piece of paper and writes out the corresponding character from his string.
Let's represent Yaroslav's word as s = s1s2... s2n. Similarly, let's represent Andrey's word as t = t1t2... t2n. Then, if Yaroslav choose number k during his move, then he is going to write out character sk on the piece of paper. Similarly, if Andrey choose number r during his move, then he is going to write out character tr on the piece of paper.
The game finishes when no player can make a move. After the game is over, Yaroslav makes some integer from the characters written on his piece of paper (Yaroslav can arrange these characters as he wants). Andrey does the same. The resulting numbers can contain leading zeroes. The person with the largest number wins. If the numbers are equal, the game ends with a draw.
You are given two strings s and t. Determine the outcome of the game provided that Yaroslav and Andrey play optimally well.
Input
The first line contains integer n (1 ≤ n ≤ 106). The second line contains string s — Yaroslav's word. The third line contains string t — Andrey's word.
It is guaranteed that both words consist of 2·n characters "0" and "1".
Output
Print "First", if both players play optimally well and Yaroslav wins. If Andrey wins, print "Second" and if the game ends with a draw, print "Draw". Print the words without the quotes.
Examples
Input
2
0111
0001
Output
First
Input
3
110110
001001
Output
First
Input
3
111000
000111
Output
Draw
Input
4
01010110
00101101
Output
First
Input
4
01100000
10010011
Output
Second
Submitted Solution:
```
#!/usr/bin/python3
n = int(input())
s = list(input())
l = list(input())
a = len([_ for _ in zip(s, l) if _ == ('1', '1')])
b = len([_ for _ in zip(s, l) if _ == ('1', '0')])
c = len([_ for _ in zip(s, l) if _ == ('0', '1')])
f = b + (a + 1) // 2
s = c + a // 2
if f > s:
print('First')
elif f < s:
print('Second')
else:
print('Draw')
``` | instruction | 0 | 9,399 | 19 | 18,798 |
No | output | 1 | 9,399 | 19 | 18,799 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya and Vasya are inventing a new game that requires a rectangular board and one chess piece. At the beginning of the game the piece stands in the upper-left corner of the board. Two players move the piece in turns. Each turn the chess piece can be moved either one square to the right or one square down or jump k squares diagonally down and to the right. The player who can’t move the piece loses.
<image>
The guys haven’t yet thought what to call the game or the best size of the board for it. Your task is to write a program that can determine the outcome of the game depending on the board size.
Input
The first input line contains two integers t and k (1 ≤ t ≤ 20, 1 ≤ k ≤ 109). Each of the following t lines contains two numbers n, m — the board’s length and width (1 ≤ n, m ≤ 109).
Output
Output t lines that can determine the outcomes of the game on every board. Write «+» if the first player is a winner, and «-» otherwise.
Examples
Input
10 2
1 1
1 2
2 1
2 2
1 3
2 3
3 1
3 2
3 3
4 3
Output
-
+
+
-
-
+
-
+
+
+
Submitted Solution:
```
import sys
from array import array # noqa: F401
def input1():
with open('input.txt') as fp:
return fp.readlines()
def output1(ans: str):
with open('output.txt', mode='w') as fp:
fp.write(ans)
def input2():
return [line.decode('utf-8') for line in sys.stdin.buffer.readlines()]
def output2(ans):
print(ans)
submit = 1
if submit:
input = input1
output = output1
else:
input = input2
output = output2
s = input()
t, k = map(int, s[0].split())
x = 2 * k + 2
ans = ['+'] * t
for i in range(1, t + 1):
n, m = map(int, s[i].split())
y = min(n, m) % x
z = abs(n - m)
if z == 0:
ans[i - 1] = '+' if y > k or y == 0 else '-'
else:
if y == 0 or y == k + 1:
ans[i - 1] = '+'
else:
f = 1 if y > k or y == 0 else 0
ans[i - 1] = '+' if f ^ (z & 1) else '-'
print(n, m, f)
output('\n'.join(ans))
``` | instruction | 0 | 9,419 | 19 | 18,838 |
No | output | 1 | 9,419 | 19 | 18,839 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya and Vasya are inventing a new game that requires a rectangular board and one chess piece. At the beginning of the game the piece stands in the upper-left corner of the board. Two players move the piece in turns. Each turn the chess piece can be moved either one square to the right or one square down or jump k squares diagonally down and to the right. The player who can’t move the piece loses.
<image>
The guys haven’t yet thought what to call the game or the best size of the board for it. Your task is to write a program that can determine the outcome of the game depending on the board size.
Input
The first input line contains two integers t and k (1 ≤ t ≤ 20, 1 ≤ k ≤ 109). Each of the following t lines contains two numbers n, m — the board’s length and width (1 ≤ n, m ≤ 109).
Output
Output t lines that can determine the outcomes of the game on every board. Write «+» if the first player is a winner, and «-» otherwise.
Examples
Input
10 2
1 1
1 2
2 1
2 2
1 3
2 3
3 1
3 2
3 3
4 3
Output
-
+
+
-
-
+
-
+
+
+
Submitted Solution:
```
import sys
sys.stdin = open('input.txt')
sys.stdout = open('output.txt', 'w')
# n = int(input())
# a = [[-1] * n for i in range(n)]
# k = int(input())
# for su in range(n * 2 - 2, -1, -1):
# for i in range(max(0, su - n + 1), min(n, su + 1)):
# j = su - i
# # print(i, j)
# if j + 1 < n:
# assert(a[i][j + 1] != -1)
# if a[i][j + 1] == 0:
# a[i][j] = 1
# continue
# if i + 1 < n:
# assert(a[i + 1][j] != -1)
# if a[i + 1][j] == 0:
# a[i][j] = 1
# continue
# if i + k < n and j + k < n:
# assert(a[i + k][j + k] != -1)
# if a[i + k][j + k] == 0:
# a[i][j] = 1
# continue
# a[i][j] = 0
# for i in range(n):
# # for j in range(n):
# # print(a[i][j], i, j)
# print(*a[i], sep='')
t, k = map(int, input().split())
for _ in range(t):
n, m = map(int, input().split())
if k == 1:
if (n % 2 == 1 and m % 2 == 0) or n % 2 == 0:
print("-")
else:
print("+")
else:
if n % (k + 1) == 0:
if m >= n:
print("+")
continue
if m % (k + 1) == 0:
if n >= m:
print("+")
continue
p = min(n, m) // (k + 1) % 2
if (n + m) % 2 == p:
print("-")
else:
print("+")
``` | instruction | 0 | 9,420 | 19 | 18,840 |
No | output | 1 | 9,420 | 19 | 18,841 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n boxes with colored balls on the table. Colors are numbered from 1 to n. i-th box contains ai balls, all of which have color i. You have to write a program that will divide all balls into sets such that:
* each ball belongs to exactly one of the sets,
* there are no empty sets,
* there is no set containing two (or more) balls of different colors (each set contains only balls of one color),
* there are no two sets such that the difference between their sizes is greater than 1.
Print the minimum possible number of sets.
Input
The first line contains one integer number n (1 ≤ n ≤ 500).
The second line contains n integer numbers a1, a2, ... , an (1 ≤ ai ≤ 109).
Output
Print one integer number — the minimum possible number of sets.
Examples
Input
3
4 7 8
Output
5
Input
2
2 7
Output
4
Note
In the first example the balls can be divided into sets like that: one set with 4 balls of the first color, two sets with 3 and 4 balls, respectively, of the second color, and two sets with 4 balls of the third color. | instruction | 0 | 9,568 | 19 | 19,136 |
Tags: greedy, math, number theory
Correct Solution:
```
# Returns the number of coins that is necessary for paying the amount
# with the two types of coins that have value of coin and coin + 1
def pay(coin, amount):
if amount // coin < amount % coin:
return -1;
if amount < coin * (coin + 1):
return amount // coin
return (amount - 1) // (coin + 1) + 1;
def pay_all(coin):
sum = 0
for i in range(n):
p = pay(coin, a[i])
if p == -1:
return -1
sum += p
return sum
n = int(input())
a = list(map(int, input().split()))
amin = min(a)
coin = amin
k = 1
p = -1
while p == -1:
p = pay_all(coin)
if p == -1 and amin % coin == 0:
p = pay_all(coin - 1)
k += 1
coin = amin // k
print(p)
``` | output | 1 | 9,568 | 19 | 19,137 |
Provide a correct Python 3 solution for this coding contest problem.
Chain Disappearance Puzzle
We are playing a puzzle. An upright board with H rows by 5 columns of cells, as shown in the figure below, is used in this puzzle. A stone engraved with a digit, one of 1 through 9, is placed in each of the cells. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. If there are stones in the cells above the cell with a disappeared stone, the stones in the above cells will drop down, filling the vacancy.
<image>
The puzzle proceeds taking the following steps.
1. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. Disappearances of all such groups of stones take place simultaneously.
2. When stones are in the cells above the emptied cells, these stones drop down so that the emptied cells are filled.
3. After the completion of all stone drops, if one or more groups of stones satisfy the disappearance condition, repeat by returning to the step 1.
The score of this puzzle is the sum of the digits on the disappeared stones.
Write a program that calculates the score of given configurations of stones.
<image>
Input
The input consists of multiple datasets. Each dataset is formed as follows.
> Board height H
> Stone placement of the row 1
> Stone placement of the row 2
> ...
> Stone placement of the row H
>
The first line specifies the height ( H ) of the puzzle board (1 ≤ H ≤ 10). The remaining H lines give placement of stones on each of the rows from top to bottom. The placements are given by five digits (1 through 9), separated by a space. These digits are engraved on the five stones in the corresponding row, in the same order.
The input ends with a line with a single zero.
Output
For each dataset, output the score in a line. Output lines may not include any characters except the digits expressing the scores.
Sample Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output for the Sample Input
36
38
99
0
72
Example
Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output
36
38
99
0
72 | instruction | 0 | 9,845 | 19 | 19,690 |
"Correct Solution:
```
from functools import lru_cache
digits = list(map(lambda x: str(x),range(1,10)))
@lru_cache(maxsize=None)
def check(s,n):
return ' '.join([s]*n)
def down(x):
x = list(x[::-1])
while '0' in x:
x.remove('0')
x.append('#')
return x
def main(n):
data = '\n'.join(map(lambda x: input(), range(n)))
score = 0
while True:
removed = False
for d in digits:
if check(d, 3) in data:
for i in range(5, 2, -1):
if check(d, i) in data:
score += int(d) * (data.count(check(d, i))*i)
data = data.replace(check(d, i), check('0', i))
removed = True
if removed == False:
break
data = zip(*map(lambda x: x.split(), data.split('\n')))
data = map(lambda x: down(x), data)
data = list(map(lambda x: ' '.join(x),zip(*data)))
data = '\n'.join(data[::-1])
print(score)
while True:
n = int(input())
if n == 0: break
main(n)
``` | output | 1 | 9,845 | 19 | 19,691 |
Provide a correct Python 3 solution for this coding contest problem.
Chain Disappearance Puzzle
We are playing a puzzle. An upright board with H rows by 5 columns of cells, as shown in the figure below, is used in this puzzle. A stone engraved with a digit, one of 1 through 9, is placed in each of the cells. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. If there are stones in the cells above the cell with a disappeared stone, the stones in the above cells will drop down, filling the vacancy.
<image>
The puzzle proceeds taking the following steps.
1. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. Disappearances of all such groups of stones take place simultaneously.
2. When stones are in the cells above the emptied cells, these stones drop down so that the emptied cells are filled.
3. After the completion of all stone drops, if one or more groups of stones satisfy the disappearance condition, repeat by returning to the step 1.
The score of this puzzle is the sum of the digits on the disappeared stones.
Write a program that calculates the score of given configurations of stones.
<image>
Input
The input consists of multiple datasets. Each dataset is formed as follows.
> Board height H
> Stone placement of the row 1
> Stone placement of the row 2
> ...
> Stone placement of the row H
>
The first line specifies the height ( H ) of the puzzle board (1 ≤ H ≤ 10). The remaining H lines give placement of stones on each of the rows from top to bottom. The placements are given by five digits (1 through 9), separated by a space. These digits are engraved on the five stones in the corresponding row, in the same order.
The input ends with a line with a single zero.
Output
For each dataset, output the score in a line. Output lines may not include any characters except the digits expressing the scores.
Sample Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output for the Sample Input
36
38
99
0
72
Example
Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output
36
38
99
0
72 | instruction | 0 | 9,846 | 19 | 19,692 |
"Correct Solution:
```
def fall(S,H):
for h in range(H-1):
for i in range(5):
if S[h][i]=="0":
S[h][i] = S[h+1][i]
S[h+1][i] = "0"
return S
while True:
H = int(input())
if H==0:
break
S = [list(input().split()) for i in range(H)]
S = S[::-1]
ans = 0
k = 1
while k!=0:
k = 0
for h in range(H):
s = S[h]
for l in range(3):
for r in range(5,2+l,-1):
if s[l]=="0":
continue
if s[l:r].count(s[l])==(r-l):
k = 1
ans += int(s[l])*(r-l)
S[h][l:r] = ["0"]*(r-l)
for i in range(H):
S = fall(S,H)
print(ans)
``` | output | 1 | 9,846 | 19 | 19,693 |
Provide a correct Python 3 solution for this coding contest problem.
Chain Disappearance Puzzle
We are playing a puzzle. An upright board with H rows by 5 columns of cells, as shown in the figure below, is used in this puzzle. A stone engraved with a digit, one of 1 through 9, is placed in each of the cells. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. If there are stones in the cells above the cell with a disappeared stone, the stones in the above cells will drop down, filling the vacancy.
<image>
The puzzle proceeds taking the following steps.
1. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. Disappearances of all such groups of stones take place simultaneously.
2. When stones are in the cells above the emptied cells, these stones drop down so that the emptied cells are filled.
3. After the completion of all stone drops, if one or more groups of stones satisfy the disappearance condition, repeat by returning to the step 1.
The score of this puzzle is the sum of the digits on the disappeared stones.
Write a program that calculates the score of given configurations of stones.
<image>
Input
The input consists of multiple datasets. Each dataset is formed as follows.
> Board height H
> Stone placement of the row 1
> Stone placement of the row 2
> ...
> Stone placement of the row H
>
The first line specifies the height ( H ) of the puzzle board (1 ≤ H ≤ 10). The remaining H lines give placement of stones on each of the rows from top to bottom. The placements are given by five digits (1 through 9), separated by a space. These digits are engraved on the five stones in the corresponding row, in the same order.
The input ends with a line with a single zero.
Output
For each dataset, output the score in a line. Output lines may not include any characters except the digits expressing the scores.
Sample Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output for the Sample Input
36
38
99
0
72
Example
Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output
36
38
99
0
72 | instruction | 0 | 9,847 | 19 | 19,694 |
"Correct Solution:
```
while True:
H = int(input())
if H==0:
exit()
board = [[0]*5 for _ in range(H+1)]
for i in range(1,H+1):
board[i] = list(map(int, input().split()))
board = board[::-1]
change = True
score = 0
while change==True:
change = False
for i in range(H-1,-1,-1):
if len(set(board[i]))==1 and board[i][0]>0:
score += sum(board[i])
change = True
for j in range(i,H):
board[j] = board[j+1]
elif len(set(board[i][:4]))==1 and board[i][:4][0]>0:
score += sum(board[i][:4])
change = True
for j in range(i,H):
board[j][:4] = board[j+1][:4]
elif len(set(board[i][1:]))==1 and board[i][1:][0]>0:
score += sum(board[i][1:])
change = True
for j in range(i,H):
board[j][1:] = board[j+1][1:]
elif len(set(board[i][:3]))==1 and board[i][:3][0]>0:
score += sum(board[i][:3])
change = True
for j in range(i,H):
board[j][:3] = board[j+1][:3]
elif len(set(board[i][1:4]))==1 and board[i][1:4][0]>0:
score += sum(board[i][1:4])
change = True
for j in range(i,H):
board[j][1:4] = board[j+1][1:4]
elif len(set(board[i][2:]))==1 and board[i][2:][0]>0:
score += sum(board[i][2:])
change = True
for j in range(i,H):
board[j][2:] = board[j+1][2:]
print(score)
``` | output | 1 | 9,847 | 19 | 19,695 |
Provide a correct Python 3 solution for this coding contest problem.
Chain Disappearance Puzzle
We are playing a puzzle. An upright board with H rows by 5 columns of cells, as shown in the figure below, is used in this puzzle. A stone engraved with a digit, one of 1 through 9, is placed in each of the cells. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. If there are stones in the cells above the cell with a disappeared stone, the stones in the above cells will drop down, filling the vacancy.
<image>
The puzzle proceeds taking the following steps.
1. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. Disappearances of all such groups of stones take place simultaneously.
2. When stones are in the cells above the emptied cells, these stones drop down so that the emptied cells are filled.
3. After the completion of all stone drops, if one or more groups of stones satisfy the disappearance condition, repeat by returning to the step 1.
The score of this puzzle is the sum of the digits on the disappeared stones.
Write a program that calculates the score of given configurations of stones.
<image>
Input
The input consists of multiple datasets. Each dataset is formed as follows.
> Board height H
> Stone placement of the row 1
> Stone placement of the row 2
> ...
> Stone placement of the row H
>
The first line specifies the height ( H ) of the puzzle board (1 ≤ H ≤ 10). The remaining H lines give placement of stones on each of the rows from top to bottom. The placements are given by five digits (1 through 9), separated by a space. These digits are engraved on the five stones in the corresponding row, in the same order.
The input ends with a line with a single zero.
Output
For each dataset, output the score in a line. Output lines may not include any characters except the digits expressing the scores.
Sample Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output for the Sample Input
36
38
99
0
72
Example
Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output
36
38
99
0
72 | instruction | 0 | 9,848 | 19 | 19,696 |
"Correct Solution:
```
H = int(input())
while H:
Ali = [list(map(int,input().split())) for _ in range(H)]
score = 0
while True:
sc = score
for i in range(H):
Row = Ali[i]
#5つ
if Row[0] == Row[1] == Row[2] == Row[3] == Row[4]:
score += Row[0]*5
Ali[i][0] = Ali[i][1] = Ali[i][2] = Ali[i][3] = Ali[i][4] = 0
#4つ
if Row[0] == Row[1] == Row[2] == Row[3]:
score += Row[0]*4
Ali[i][0] = Ali[i][1] = Ali[i][2] = Ali[i][3] = 0
if Row[1] == Row[2] == Row[3] == Row[4]:
score += Row[1]*4
Ali[i][1] = Ali[i][2] = Ali[i][3] = Ali[i][4] = 0
#3つ
if Row[0] == Row[1] == Row[2]:
score += Row[0]*3
Ali[i][0] = Ali[i][1] = Ali[i][2] = 0
if Row[1] == Row[2] == Row[3]:
score += Row[1]*3
Ali[i][1] = Ali[i][2] = Ali[i][3] = 0
if Row[2] == Row[3] == Row[4]:
score += Row[2]*3
Ali[i][2] = Ali[i][3] = Ali[i][4] = 0
if sc == score:
break
#落としていく処理
#下から上に見ていく
for i in range(1,H+1):
for j in range(0,5):
if Ali[-i][j] == 0:
for k in range(i+1,H+1):
if Ali[-k][j] != 0:
Ali[-i][j] = Ali[-k][j]
Ali[-k][j] = 0
break
print(score)
H = int(input())
``` | output | 1 | 9,848 | 19 | 19,697 |
Provide a correct Python 3 solution for this coding contest problem.
Chain Disappearance Puzzle
We are playing a puzzle. An upright board with H rows by 5 columns of cells, as shown in the figure below, is used in this puzzle. A stone engraved with a digit, one of 1 through 9, is placed in each of the cells. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. If there are stones in the cells above the cell with a disappeared stone, the stones in the above cells will drop down, filling the vacancy.
<image>
The puzzle proceeds taking the following steps.
1. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. Disappearances of all such groups of stones take place simultaneously.
2. When stones are in the cells above the emptied cells, these stones drop down so that the emptied cells are filled.
3. After the completion of all stone drops, if one or more groups of stones satisfy the disappearance condition, repeat by returning to the step 1.
The score of this puzzle is the sum of the digits on the disappeared stones.
Write a program that calculates the score of given configurations of stones.
<image>
Input
The input consists of multiple datasets. Each dataset is formed as follows.
> Board height H
> Stone placement of the row 1
> Stone placement of the row 2
> ...
> Stone placement of the row H
>
The first line specifies the height ( H ) of the puzzle board (1 ≤ H ≤ 10). The remaining H lines give placement of stones on each of the rows from top to bottom. The placements are given by five digits (1 through 9), separated by a space. These digits are engraved on the five stones in the corresponding row, in the same order.
The input ends with a line with a single zero.
Output
For each dataset, output the score in a line. Output lines may not include any characters except the digits expressing the scores.
Sample Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output for the Sample Input
36
38
99
0
72
Example
Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output
36
38
99
0
72 | instruction | 0 | 9,849 | 19 | 19,698 |
"Correct Solution:
```
from itertools import groupby
def main():
while True:
h = int(input())
w = 5
if h == 0: break
field = []
for i in range(h):
field.append(list(map(int,input().split())))
score = 0
while True:
scoreinc = 0
for i in range(h):
c = 0
for key, value in groupby(field[i]):
newlist = list(value)
if len(newlist) >= 3:
scoreinc += newlist[0] * len(newlist)
newlist = [0 for i in range(len(newlist))]
if c == 0:
field[i] = newlist
else:
field[i] += newlist
c += 1
if scoreinc == 0: break
score += scoreinc
for i in range(w):
ydata = []
for j in range(h):
ydata.append(field[j][i])
ydata = sorted(ydata, key = return0)
for j in range(h):
field[j][i] = ydata[j]
#print(field)
print(score)
def return0(num):
if num == 0: return 0
else: return 1
main()
``` | output | 1 | 9,849 | 19 | 19,699 |
Provide a correct Python 3 solution for this coding contest problem.
Chain Disappearance Puzzle
We are playing a puzzle. An upright board with H rows by 5 columns of cells, as shown in the figure below, is used in this puzzle. A stone engraved with a digit, one of 1 through 9, is placed in each of the cells. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. If there are stones in the cells above the cell with a disappeared stone, the stones in the above cells will drop down, filling the vacancy.
<image>
The puzzle proceeds taking the following steps.
1. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. Disappearances of all such groups of stones take place simultaneously.
2. When stones are in the cells above the emptied cells, these stones drop down so that the emptied cells are filled.
3. After the completion of all stone drops, if one or more groups of stones satisfy the disappearance condition, repeat by returning to the step 1.
The score of this puzzle is the sum of the digits on the disappeared stones.
Write a program that calculates the score of given configurations of stones.
<image>
Input
The input consists of multiple datasets. Each dataset is formed as follows.
> Board height H
> Stone placement of the row 1
> Stone placement of the row 2
> ...
> Stone placement of the row H
>
The first line specifies the height ( H ) of the puzzle board (1 ≤ H ≤ 10). The remaining H lines give placement of stones on each of the rows from top to bottom. The placements are given by five digits (1 through 9), separated by a space. These digits are engraved on the five stones in the corresponding row, in the same order.
The input ends with a line with a single zero.
Output
For each dataset, output the score in a line. Output lines may not include any characters except the digits expressing the scores.
Sample Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output for the Sample Input
36
38
99
0
72
Example
Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output
36
38
99
0
72 | instruction | 0 | 9,850 | 19 | 19,700 |
"Correct Solution:
```
#!usr/bin/env python3
from collections import defaultdict,deque
from heapq import heappush, heappop
from itertools import permutations
import sys
import math
import bisect
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def I(): return int(sys.stdin.readline())
def LS():return [list(x) for x in sys.stdin.readline().split()]
def S():
res = list(sys.stdin.readline())
if res[-1] == "\n":
return res[:-1]
return res
def IR(n):
return [I() for i in range(n)]
def LIR(n):
return [LI() for i in range(n)]
def SR(n):
return [S() for i in range(n)]
def LSR(n):
return [LS() for i in range(n)]
sys.setrecursionlimit(1000000)
mod = 1000000007
def solve():
def check(y,x):
res = 0
c = s[x][y]
for x in range(x,5):
if s[x][y] != c:
break
res += 1
if res < 3:
return 0
else:
return res
def update(y,x,d):
for i in range(x,x+d):
s[i][y] = 0
def fall(s):
q = [[] for i in range(5)]
for x in range(5):
for y in range(h):
if s[x][y]:
q[x].append(s[x][y])
for y in range(h-len(q[x])):
q[x].append(0)
return q
while 1:
h = I()
if h == 0:
break
s = LIR(h)
s = [[s[-1-y][x] for y in range(h)] for x in range(5)]
ans = 0
f = 1
while f:
f = 0
for y in range(h):
for x in range(3):
if s[x][y]:
d = check(y,x)
ans += s[x][y]*d
if d:
update(y,x,d)
f = 1
if f:
s = fall(s)
print(ans)
return
#Solve
if __name__ == "__main__":
solve()
``` | output | 1 | 9,850 | 19 | 19,701 |
Provide a correct Python 3 solution for this coding contest problem.
Chain Disappearance Puzzle
We are playing a puzzle. An upright board with H rows by 5 columns of cells, as shown in the figure below, is used in this puzzle. A stone engraved with a digit, one of 1 through 9, is placed in each of the cells. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. If there are stones in the cells above the cell with a disappeared stone, the stones in the above cells will drop down, filling the vacancy.
<image>
The puzzle proceeds taking the following steps.
1. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. Disappearances of all such groups of stones take place simultaneously.
2. When stones are in the cells above the emptied cells, these stones drop down so that the emptied cells are filled.
3. After the completion of all stone drops, if one or more groups of stones satisfy the disappearance condition, repeat by returning to the step 1.
The score of this puzzle is the sum of the digits on the disappeared stones.
Write a program that calculates the score of given configurations of stones.
<image>
Input
The input consists of multiple datasets. Each dataset is formed as follows.
> Board height H
> Stone placement of the row 1
> Stone placement of the row 2
> ...
> Stone placement of the row H
>
The first line specifies the height ( H ) of the puzzle board (1 ≤ H ≤ 10). The remaining H lines give placement of stones on each of the rows from top to bottom. The placements are given by five digits (1 through 9), separated by a space. These digits are engraved on the five stones in the corresponding row, in the same order.
The input ends with a line with a single zero.
Output
For each dataset, output the score in a line. Output lines may not include any characters except the digits expressing the scores.
Sample Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output for the Sample Input
36
38
99
0
72
Example
Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output
36
38
99
0
72 | instruction | 0 | 9,851 | 19 | 19,702 |
"Correct Solution:
```
while True:
h = int(input())
if h==0:
break
puyo = [list(map(int, input().split())) for _ in range(h)]
p = 0
fin = 0
turn = 1
while fin==0:
#[print(*puyo[i]) for i in range(h)]
fin = 1
for i in range(h):
cnt = 1
for j in range(1, 5):
if puyo[i][j-1] == puyo[i][j] and puyo[i][j]>0:
cnt += 1
else:
if cnt>=3:
p += cnt * puyo[i][j-1]
for k in range(cnt):
puyo[i][j-k-1] = -1
fin = 0
cnt = 1
if j==4:
if cnt>=3:
p += cnt * puyo[i][j-1]
for k in range(cnt):
puyo[i][j-k] = -1
fin = 0
#print('after remove')
#[print(*puyo[i]) for i in range(h)]
for i in range(5):
d_fin = 0
while d_fin==0:
d_fin = 1
for j in range(h-1, 0, -1):
if puyo[j][i]==-1 and puyo[j-1][i]>0:
puyo[j][i] = puyo[j-1][i]
puyo[j-1][i] = -1
d_fin = 0
#print(f'turn {turn}')
turn += 1
print(p)
``` | output | 1 | 9,851 | 19 | 19,703 |
Provide a correct Python 3 solution for this coding contest problem.
Chain Disappearance Puzzle
We are playing a puzzle. An upright board with H rows by 5 columns of cells, as shown in the figure below, is used in this puzzle. A stone engraved with a digit, one of 1 through 9, is placed in each of the cells. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. If there are stones in the cells above the cell with a disappeared stone, the stones in the above cells will drop down, filling the vacancy.
<image>
The puzzle proceeds taking the following steps.
1. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. Disappearances of all such groups of stones take place simultaneously.
2. When stones are in the cells above the emptied cells, these stones drop down so that the emptied cells are filled.
3. After the completion of all stone drops, if one or more groups of stones satisfy the disappearance condition, repeat by returning to the step 1.
The score of this puzzle is the sum of the digits on the disappeared stones.
Write a program that calculates the score of given configurations of stones.
<image>
Input
The input consists of multiple datasets. Each dataset is formed as follows.
> Board height H
> Stone placement of the row 1
> Stone placement of the row 2
> ...
> Stone placement of the row H
>
The first line specifies the height ( H ) of the puzzle board (1 ≤ H ≤ 10). The remaining H lines give placement of stones on each of the rows from top to bottom. The placements are given by five digits (1 through 9), separated by a space. These digits are engraved on the five stones in the corresponding row, in the same order.
The input ends with a line with a single zero.
Output
For each dataset, output the score in a line. Output lines may not include any characters except the digits expressing the scores.
Sample Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output for the Sample Input
36
38
99
0
72
Example
Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output
36
38
99
0
72 | instruction | 0 | 9,852 | 19 | 19,704 |
"Correct Solution:
```
W = 5
def calc_score(ban, score):
add_score = 0
after_ban = []
H = len(ban)
for h in range(H):
row = []
cnt = 1
cur = ban[h][0]
for w in range(1, W):
if cur == ban[h][w]:
cnt += 1
else:
row.append([cur, cnt])
cur = ban[h][w]
cnt = 1
row.append([cur, cnt])
after_row = []
for cur, cnt in row:
if cnt >= 3:
add_score += cur * cnt
after_row.extend([0]*cnt)
else:
after_row.extend([cur]*cnt)
after_ban.append(after_row)
# 下が0のマスだったら落ちる
for _ in range(10):
for h in range(0, H-1):
for w in range(W):
if after_ban[h+1][w] == 0:
after_ban[h+1][w] = after_ban[h][w]
after_ban[h][w] = 0
score += add_score
if add_score == 0:
return score
else:
return calc_score(after_ban, score)
ans = []
while True:
H = int(input())
if H == 0:
break
ban = [list(map(int, input().split())) for _ in range(H)]
ans.append(calc_score(ban, 0))
print(*ans, sep='\n')
``` | output | 1 | 9,852 | 19 | 19,705 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Chain Disappearance Puzzle
We are playing a puzzle. An upright board with H rows by 5 columns of cells, as shown in the figure below, is used in this puzzle. A stone engraved with a digit, one of 1 through 9, is placed in each of the cells. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. If there are stones in the cells above the cell with a disappeared stone, the stones in the above cells will drop down, filling the vacancy.
<image>
The puzzle proceeds taking the following steps.
1. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. Disappearances of all such groups of stones take place simultaneously.
2. When stones are in the cells above the emptied cells, these stones drop down so that the emptied cells are filled.
3. After the completion of all stone drops, if one or more groups of stones satisfy the disappearance condition, repeat by returning to the step 1.
The score of this puzzle is the sum of the digits on the disappeared stones.
Write a program that calculates the score of given configurations of stones.
<image>
Input
The input consists of multiple datasets. Each dataset is formed as follows.
> Board height H
> Stone placement of the row 1
> Stone placement of the row 2
> ...
> Stone placement of the row H
>
The first line specifies the height ( H ) of the puzzle board (1 ≤ H ≤ 10). The remaining H lines give placement of stones on each of the rows from top to bottom. The placements are given by five digits (1 through 9), separated by a space. These digits are engraved on the five stones in the corresponding row, in the same order.
The input ends with a line with a single zero.
Output
For each dataset, output the score in a line. Output lines may not include any characters except the digits expressing the scores.
Sample Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output for the Sample Input
36
38
99
0
72
Example
Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output
36
38
99
0
72
Submitted Solution:
```
while True:
H = int(input())
if H == 0:
exit()
L = [input().split() for _ in range(H)]
L1 = list(reversed([l[0] for l in L]))
L2 = list(reversed([l[1] for l in L]))
L3 = list(reversed([l[2] for l in L]))
L4 = list(reversed([l[3] for l in L]))
L5 = list(reversed([l[4] for l in L]))
ans = 0
while True:
changed = False
for i in range(H):
if L1[i] != 'X' and L1[i] == L2[i] == L3[i] == L4[i] == L5[i]:
changed = True
ans += 5*int(L1[i])
L1[i] = 'X'
L2[i] = 'X'
L3[i] = 'X'
L4[i] = 'X'
L5[i] = 'X'
elif L1[i] != 'X' and L1[i] == L2[i] == L3[i] == L4[i]:
changed = True
ans += 4*int(L1[i])
L1[i] = 'X'
L2[i] = 'X'
L3[i] = 'X'
L4[i] = 'X'
elif L2[i] != 'X' and L2[i] == L3[i] == L4[i] == L5[i]:
changed = True
ans += 4*int(L2[i])
L2[i] = 'X'
L3[i] = 'X'
L4[i] = 'X'
L5[i] = 'X'
elif L1[i] != 'X' and L1[i] == L2[i] == L3[i]:
changed = True
ans += 3*int(L1[i])
L1[i] = 'X'
L2[i] = 'X'
L3[i] = 'X'
elif L2[i] != 'X' and L2[i] == L3[i] == L4[i]:
changed = True
ans += 3*int(L2[i])
L2[i] = 'X'
L3[i] = 'X'
L4[i] = 'X'
elif L3[i] != 'X' and L3[i] == L4[i] == L5[i]:
changed = True
ans += 3*int(L3[i])
L3[i] = 'X'
L4[i] = 'X'
L5[i] = 'X'
if not changed:
break
L1 = list(filter(lambda x: x!='X',L1)) + ['X']*L1.count('X')
L2 = list(filter(lambda x: x!='X',L2)) + ['X']*L2.count('X')
L3 = list(filter(lambda x: x!='X',L3)) + ['X']*L3.count('X')
L4 = list(filter(lambda x: x!='X',L4)) + ['X']*L4.count('X')
L5 = list(filter(lambda x: x!='X',L5)) + ['X']*L5.count('X')
print(ans)
``` | instruction | 0 | 9,853 | 19 | 19,706 |
Yes | output | 1 | 9,853 | 19 | 19,707 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Chain Disappearance Puzzle
We are playing a puzzle. An upright board with H rows by 5 columns of cells, as shown in the figure below, is used in this puzzle. A stone engraved with a digit, one of 1 through 9, is placed in each of the cells. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. If there are stones in the cells above the cell with a disappeared stone, the stones in the above cells will drop down, filling the vacancy.
<image>
The puzzle proceeds taking the following steps.
1. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. Disappearances of all such groups of stones take place simultaneously.
2. When stones are in the cells above the emptied cells, these stones drop down so that the emptied cells are filled.
3. After the completion of all stone drops, if one or more groups of stones satisfy the disappearance condition, repeat by returning to the step 1.
The score of this puzzle is the sum of the digits on the disappeared stones.
Write a program that calculates the score of given configurations of stones.
<image>
Input
The input consists of multiple datasets. Each dataset is formed as follows.
> Board height H
> Stone placement of the row 1
> Stone placement of the row 2
> ...
> Stone placement of the row H
>
The first line specifies the height ( H ) of the puzzle board (1 ≤ H ≤ 10). The remaining H lines give placement of stones on each of the rows from top to bottom. The placements are given by five digits (1 through 9), separated by a space. These digits are engraved on the five stones in the corresponding row, in the same order.
The input ends with a line with a single zero.
Output
For each dataset, output the score in a line. Output lines may not include any characters except the digits expressing the scores.
Sample Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output for the Sample Input
36
38
99
0
72
Example
Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output
36
38
99
0
72
Submitted Solution:
```
from itertools import zip_longest
while True:
n = int(input())
if not n:
break
field = [list(map(int, input().split())) for _ in range(n)]
field.reverse()
score = 0
while True:
no_more_disappear = True
for y, row in enumerate(field):
for i, stone in enumerate(row[:3]):
if stone is None:
continue
cnt = 1
for stone2 in row[i + 1:]:
if stone != stone2:
break
cnt += 1
if cnt >= 3:
row[i:i + cnt] = [None] * cnt
score += stone * cnt
no_more_disappear = False
if no_more_disappear:
break
fieldT = map(lambda row: filter(None, row), zip(*field))
field = list(map(list, zip_longest(*fieldT)))
print(score)
``` | instruction | 0 | 9,854 | 19 | 19,708 |
Yes | output | 1 | 9,854 | 19 | 19,709 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Chain Disappearance Puzzle
We are playing a puzzle. An upright board with H rows by 5 columns of cells, as shown in the figure below, is used in this puzzle. A stone engraved with a digit, one of 1 through 9, is placed in each of the cells. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. If there are stones in the cells above the cell with a disappeared stone, the stones in the above cells will drop down, filling the vacancy.
<image>
The puzzle proceeds taking the following steps.
1. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. Disappearances of all such groups of stones take place simultaneously.
2. When stones are in the cells above the emptied cells, these stones drop down so that the emptied cells are filled.
3. After the completion of all stone drops, if one or more groups of stones satisfy the disappearance condition, repeat by returning to the step 1.
The score of this puzzle is the sum of the digits on the disappeared stones.
Write a program that calculates the score of given configurations of stones.
<image>
Input
The input consists of multiple datasets. Each dataset is formed as follows.
> Board height H
> Stone placement of the row 1
> Stone placement of the row 2
> ...
> Stone placement of the row H
>
The first line specifies the height ( H ) of the puzzle board (1 ≤ H ≤ 10). The remaining H lines give placement of stones on each of the rows from top to bottom. The placements are given by five digits (1 through 9), separated by a space. These digits are engraved on the five stones in the corresponding row, in the same order.
The input ends with a line with a single zero.
Output
For each dataset, output the score in a line. Output lines may not include any characters except the digits expressing the scores.
Sample Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output for the Sample Input
36
38
99
0
72
Example
Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output
36
38
99
0
72
Submitted Solution:
```
class Puzzle():
def __init__(self, mat, N):
self.mat = mat
self.h = N
self.score = 0
def calc(self):
tmp_score = self.score
for i in range(self.h):
for j in range(3):
if self.mat[i][j] > 0:
# 5,2
for k in range(5, 2, -1):
if j+k <= 7 and k-j >= 3:
s = set(self.mat[i][j:k])
if len(s) == 1 and -1 not in s:
tmp_score += list(s)[0] * (k-j)
for l in range(j, k):
self.mat[i][l] = -1
break
if self.score >= tmp_score:
return False
else:
self.score = tmp_score
return True
def flatten(self):
pivot_mat = []
for i in range(5):
row = []
for j in range(self.h):
if self.mat[j][i] != -1:
row.append(self.mat[j][i])
short = self.h - len(row)
if short > 0:
row.reverse()
for k in range(short):
row.append(-1)
row.reverse()
pivot_mat.append(row)
mat = [ [-1]*5 for i in range(self.h) ]
for i in range(self.h):
for j in range(5):
mat[i][j] = pivot_mat[j][i]
self.mat = mat
while True:
h = int(input())
if h==0: exit()
mat = []
for _ in range(h):
mat.append(list(map(int,input().split())))
puzzle = Puzzle(mat, h)
while True:
if puzzle.calc():
puzzle.flatten()
else:
break
print(puzzle.score)
``` | instruction | 0 | 9,855 | 19 | 19,710 |
Yes | output | 1 | 9,855 | 19 | 19,711 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Chain Disappearance Puzzle
We are playing a puzzle. An upright board with H rows by 5 columns of cells, as shown in the figure below, is used in this puzzle. A stone engraved with a digit, one of 1 through 9, is placed in each of the cells. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. If there are stones in the cells above the cell with a disappeared stone, the stones in the above cells will drop down, filling the vacancy.
<image>
The puzzle proceeds taking the following steps.
1. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. Disappearances of all such groups of stones take place simultaneously.
2. When stones are in the cells above the emptied cells, these stones drop down so that the emptied cells are filled.
3. After the completion of all stone drops, if one or more groups of stones satisfy the disappearance condition, repeat by returning to the step 1.
The score of this puzzle is the sum of the digits on the disappeared stones.
Write a program that calculates the score of given configurations of stones.
<image>
Input
The input consists of multiple datasets. Each dataset is formed as follows.
> Board height H
> Stone placement of the row 1
> Stone placement of the row 2
> ...
> Stone placement of the row H
>
The first line specifies the height ( H ) of the puzzle board (1 ≤ H ≤ 10). The remaining H lines give placement of stones on each of the rows from top to bottom. The placements are given by five digits (1 through 9), separated by a space. These digits are engraved on the five stones in the corresponding row, in the same order.
The input ends with a line with a single zero.
Output
For each dataset, output the score in a line. Output lines may not include any characters except the digits expressing the scores.
Sample Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output for the Sample Input
36
38
99
0
72
Example
Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output
36
38
99
0
72
Submitted Solution:
```
from inspect import currentframe
def debug_print(s):
# print(s)
return
def debug_key(*args):
names = {id(v): k for k, v in currentframe().f_back.f_locals.items()}
debug_print(', '.join(names.get(id(arg), '???')+' = '+repr(arg) for arg in args))
def solve(H, stone):
debug_print("\n-----solve-----")
debug_key(stone)
ans = -1
tmp = 1
while tmp:
ans += tmp
tmp = 0
erase = [set() for _ in range(5)]
for i in range(H):
for j in range(1, 4):
if stone[i][j - 1] == stone[i][j] == stone[i][j + 1]:
for k in range(j - 1, j + 2):
erase[k].add(i)
stone2 = list(map(list, zip(*stone)))
for j in range(5):
for i in sorted(erase[j], reverse=True):
tmp += stone[i][j]
del stone2[j][i]
stone2[j] = [0] * len(erase[j]) + stone2[j]
stone = list(map(list, zip(*stone2)))
print(ans)
return
if __name__ == '__main__':
while True:
H_input = int(input())
if H_input == 0:
break
stone_input = [list(map(int, input().split())) for _ in range(H_input)]
solve(H_input, stone_input)
``` | instruction | 0 | 9,856 | 19 | 19,712 |
Yes | output | 1 | 9,856 | 19 | 19,713 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Chain Disappearance Puzzle
We are playing a puzzle. An upright board with H rows by 5 columns of cells, as shown in the figure below, is used in this puzzle. A stone engraved with a digit, one of 1 through 9, is placed in each of the cells. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. If there are stones in the cells above the cell with a disappeared stone, the stones in the above cells will drop down, filling the vacancy.
<image>
The puzzle proceeds taking the following steps.
1. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. Disappearances of all such groups of stones take place simultaneously.
2. When stones are in the cells above the emptied cells, these stones drop down so that the emptied cells are filled.
3. After the completion of all stone drops, if one or more groups of stones satisfy the disappearance condition, repeat by returning to the step 1.
The score of this puzzle is the sum of the digits on the disappeared stones.
Write a program that calculates the score of given configurations of stones.
<image>
Input
The input consists of multiple datasets. Each dataset is formed as follows.
> Board height H
> Stone placement of the row 1
> Stone placement of the row 2
> ...
> Stone placement of the row H
>
The first line specifies the height ( H ) of the puzzle board (1 ≤ H ≤ 10). The remaining H lines give placement of stones on each of the rows from top to bottom. The placements are given by five digits (1 through 9), separated by a space. These digits are engraved on the five stones in the corresponding row, in the same order.
The input ends with a line with a single zero.
Output
For each dataset, output the score in a line. Output lines may not include any characters except the digits expressing the scores.
Sample Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output for the Sample Input
36
38
99
0
72
Example
Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output
36
38
99
0
72
Submitted Solution:
```
from itertools import zip_longest
while True:
n = int(input())
if not n:
break
field = [list(map(int, input().split())) for _ in range(n)]
field.reverse()
score = 0
while True:
no_more_disappear = True
for y, row in enumerate(field):
for i, stone in enumerate(row):
if stone is None:
continue
cnt = 1
for stone2 in row[i + 1:]:
if stone != stone2:
break
cnt += 1
if cnt >= 3:
row[i:i + cnt] = [None] * cnt
score += stone * cnt
no_more_disappear = False
if no_more_disappear:
break
fieldT = map(lambda row: filter(None, row), zip(*field))
field = map(list, zip_longest(*fieldT))
print(score)
``` | instruction | 0 | 9,857 | 19 | 19,714 |
No | output | 1 | 9,857 | 19 | 19,715 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Chain Disappearance Puzzle
We are playing a puzzle. An upright board with H rows by 5 columns of cells, as shown in the figure below, is used in this puzzle. A stone engraved with a digit, one of 1 through 9, is placed in each of the cells. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. If there are stones in the cells above the cell with a disappeared stone, the stones in the above cells will drop down, filling the vacancy.
<image>
The puzzle proceeds taking the following steps.
1. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. Disappearances of all such groups of stones take place simultaneously.
2. When stones are in the cells above the emptied cells, these stones drop down so that the emptied cells are filled.
3. After the completion of all stone drops, if one or more groups of stones satisfy the disappearance condition, repeat by returning to the step 1.
The score of this puzzle is the sum of the digits on the disappeared stones.
Write a program that calculates the score of given configurations of stones.
<image>
Input
The input consists of multiple datasets. Each dataset is formed as follows.
> Board height H
> Stone placement of the row 1
> Stone placement of the row 2
> ...
> Stone placement of the row H
>
The first line specifies the height ( H ) of the puzzle board (1 ≤ H ≤ 10). The remaining H lines give placement of stones on each of the rows from top to bottom. The placements are given by five digits (1 through 9), separated by a space. These digits are engraved on the five stones in the corresponding row, in the same order.
The input ends with a line with a single zero.
Output
For each dataset, output the score in a line. Output lines may not include any characters except the digits expressing the scores.
Sample Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output for the Sample Input
36
38
99
0
72
Example
Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output
36
38
99
0
72
Submitted Solution:
```
a = int(input())
global s
s = 0
def de(ppp,h):
re = False
co = 0
global s
for lo in ppp:
for j ,cell in enumerate(lo):
k = j
p = j
if k <= 2:
while cell == lo[k+1] and cell != None:
co += 1
if k == 3:
j = k
break
k += 1
j = k
if co >= 2:
re = True
s += (co+1)*cell
for l in range(5):
if l >= p and l <= k:
lo[l] = None
co = 0
return re
def mo(ppp,h):
for i ,roe in enumerate(ppp):
for j , cell in enumerate(roe):
kkk = i
while i != 0 and ppp[kkk-1][j] == None:
ppp[kkk-1][j] = ppp[kkk][j]
ppp[kkk][j] = None
if kkk == 1:
break
kkk -= 1
while a != 0:
ppp = [list(map(int,input().split())) for i in range(a)]
ppp.reverse()
while(de(ppp,a) == True):
mo(ppp,a)
print(s)
s = 0
a = int(input())
``` | instruction | 0 | 9,858 | 19 | 19,716 |
No | output | 1 | 9,858 | 19 | 19,717 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Chain Disappearance Puzzle
We are playing a puzzle. An upright board with H rows by 5 columns of cells, as shown in the figure below, is used in this puzzle. A stone engraved with a digit, one of 1 through 9, is placed in each of the cells. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. If there are stones in the cells above the cell with a disappeared stone, the stones in the above cells will drop down, filling the vacancy.
<image>
The puzzle proceeds taking the following steps.
1. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. Disappearances of all such groups of stones take place simultaneously.
2. When stones are in the cells above the emptied cells, these stones drop down so that the emptied cells are filled.
3. After the completion of all stone drops, if one or more groups of stones satisfy the disappearance condition, repeat by returning to the step 1.
The score of this puzzle is the sum of the digits on the disappeared stones.
Write a program that calculates the score of given configurations of stones.
<image>
Input
The input consists of multiple datasets. Each dataset is formed as follows.
> Board height H
> Stone placement of the row 1
> Stone placement of the row 2
> ...
> Stone placement of the row H
>
The first line specifies the height ( H ) of the puzzle board (1 ≤ H ≤ 10). The remaining H lines give placement of stones on each of the rows from top to bottom. The placements are given by five digits (1 through 9), separated by a space. These digits are engraved on the five stones in the corresponding row, in the same order.
The input ends with a line with a single zero.
Output
For each dataset, output the score in a line. Output lines may not include any characters except the digits expressing the scores.
Sample Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output for the Sample Input
36
38
99
0
72
Example
Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output
36
38
99
0
72
Submitted Solution:
```
a = int(input())
global s
s = 0
def de(ppp,h):
re = False
co = 0
global s
for lo in ppp:
for j ,cell in enumerate(lo):
k = j
p = j
if k <= 2:
while cell == lo[k+1] and cell != None:
co += 1
if k == 3:
j = k+1
break
k += 1
j = k
if co >= 2:
re = True
s += (co+1)*cell
for l in range(5):
if l >= p and l <= j:
lo[l] = None
co = 0
return re
def mo(ppp,h):
for i ,roe in enumerate(ppp):
for j , cell in enumerate(roe):
kkk = i
while i != 0 and ppp[kkk-1][j] == None:
ppp[kkk-1][j] = ppp[kkk][j]
ppp[kkk][j] = None
if kkk == 1:
break
kkk -= 1
while a != 0:
ppp = [list(map(int,input().split())) for i in range(a)]
ppp.reverse()
while(de(ppp,a) == True):
mo(ppp,a)
print(ppp)
print(s)
s = 0
a = int(input())
``` | instruction | 0 | 9,859 | 19 | 19,718 |
No | output | 1 | 9,859 | 19 | 19,719 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Chain Disappearance Puzzle
We are playing a puzzle. An upright board with H rows by 5 columns of cells, as shown in the figure below, is used in this puzzle. A stone engraved with a digit, one of 1 through 9, is placed in each of the cells. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. If there are stones in the cells above the cell with a disappeared stone, the stones in the above cells will drop down, filling the vacancy.
<image>
The puzzle proceeds taking the following steps.
1. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. Disappearances of all such groups of stones take place simultaneously.
2. When stones are in the cells above the emptied cells, these stones drop down so that the emptied cells are filled.
3. After the completion of all stone drops, if one or more groups of stones satisfy the disappearance condition, repeat by returning to the step 1.
The score of this puzzle is the sum of the digits on the disappeared stones.
Write a program that calculates the score of given configurations of stones.
<image>
Input
The input consists of multiple datasets. Each dataset is formed as follows.
> Board height H
> Stone placement of the row 1
> Stone placement of the row 2
> ...
> Stone placement of the row H
>
The first line specifies the height ( H ) of the puzzle board (1 ≤ H ≤ 10). The remaining H lines give placement of stones on each of the rows from top to bottom. The placements are given by five digits (1 through 9), separated by a space. These digits are engraved on the five stones in the corresponding row, in the same order.
The input ends with a line with a single zero.
Output
For each dataset, output the score in a line. Output lines may not include any characters except the digits expressing the scores.
Sample Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output for the Sample Input
36
38
99
0
72
Example
Input
1
6 9 9 9 9
5
5 9 5 5 9
5 5 6 9 9
4 6 3 6 9
3 3 2 9 9
2 2 1 1 1
10
3 5 6 5 6
2 2 2 8 3
6 2 5 9 2
7 7 7 6 1
4 6 6 4 9
8 9 1 1 8
5 6 1 8 1
6 8 2 1 2
9 6 3 3 5
5 3 8 8 8
5
1 2 3 4 5
6 7 8 9 1
2 3 4 5 6
7 8 9 1 2
3 4 5 6 7
3
2 2 8 7 4
6 5 7 7 7
8 8 9 9 9
0
Output
36
38
99
0
72
Submitted Solution:
```
def calc(puzzle,H,score):
flag=False
for i in range(H-1,-1,-1):
stones=[]
for j in range(5):
now=puzzle[j][i]
if (len(stones)==0 or stones[-1]==now) and now!=0: stones.append(now)
elif len(stones)<3: stones=[now]
if len(stones)>2:
flag=True
score+=sum(stones)
for j in range(5):
if puzzle[j][i]==stones[0]:
puzzle[j].pop(i)
puzzle[j].append(0)
if flag==True:
return calc(puzzle,H,score)
else:
return score
if __name__=="__main__":
while True:
score=0
H=int(input())
if H==0:
break
puzzle=[[] for _ in range(5)]
for i in range(H):
temp=list(map(int,input().split()))
for j in range(5):
puzzle[j].insert(0,temp[j])
score=calc(puzzle,H,score)
print(score)
``` | instruction | 0 | 9,860 | 19 | 19,720 |
No | output | 1 | 9,860 | 19 | 19,721 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Among Johnny's numerous hobbies, there are two seemingly harmless ones: applying bitwise operations and sneaking into his dad's office. As it is usually the case with small children, Johnny is unaware that combining these two activities can get him in a lot of trouble.
There is a set S containing very important numbers on his dad's desk. The minute Johnny heard about it, he decided that it's a good idea to choose a positive integer k and replace each element s of the set S with s ⊕ k (⊕ denotes the [exclusive or](https://en.wikipedia.org/wiki/Exclusive_or#Computer_science) operation).
Help him choose such k that Johnny's dad will not see any difference after his son is done playing (i.e. Johnny will get the same set as before playing). It is possible that no such number exists. It is also possible that there are many of them. In such a case, output the smallest one. Note that the order of elements in a set doesn't matter, i.e. set \{1, 2, 3\} equals to set \{2, 1, 3\}.
Formally, find the smallest positive integer k such that \\{s ⊕ k | s ∈ S\} = S or report that there is no such number.
For example, if S = \{1, 3, 4\} and k = 2, new set will be equal to \{3, 1, 6\}. If S = \{0, 1, 2, 3\} and k = 1, after playing set will stay the same.
Input
In the first line of input, there is a single integer t (1 ≤ t ≤ 1024), the number of test cases. In the next lines, t test cases follow. Each of them consists of two lines.
In the first line there is a single integer n (1 ≤ n ≤ 1024) denoting the number of elements in set S. Second line consists of n distinct integers s_i (0 ≤ s_i < 1024), elements of S.
It is guaranteed that the sum of n over all test cases will not exceed 1024.
Output
Print t lines; i-th line should contain the answer to the i-th test case, the minimal positive integer k satisfying the conditions or -1 if no such k exists.
Example
Input
6
4
1 0 2 3
6
10 7 14 8 3 12
2
0 2
3
1 2 3
6
1 4 6 10 11 12
2
0 1023
Output
1
4
2
-1
-1
1023
Note
In the first test case, the answer is 1 because it is a minimum positive integer and it satisfies all the conditions. | instruction | 0 | 10,107 | 19 | 20,214 |
Tags: bitmasks, brute force
Correct Solution:
```
for _ in range(int(input())):
n=int(input())
s = set(list(map(int, input().split())))
p=-1
for i in range(1,1025):
for x in s:
if x^i not in s:
break
else:
p=i
if p!=-1:
print(p)
break
else:
print(p)
``` | output | 1 | 10,107 | 19 | 20,215 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Among Johnny's numerous hobbies, there are two seemingly harmless ones: applying bitwise operations and sneaking into his dad's office. As it is usually the case with small children, Johnny is unaware that combining these two activities can get him in a lot of trouble.
There is a set S containing very important numbers on his dad's desk. The minute Johnny heard about it, he decided that it's a good idea to choose a positive integer k and replace each element s of the set S with s ⊕ k (⊕ denotes the [exclusive or](https://en.wikipedia.org/wiki/Exclusive_or#Computer_science) operation).
Help him choose such k that Johnny's dad will not see any difference after his son is done playing (i.e. Johnny will get the same set as before playing). It is possible that no such number exists. It is also possible that there are many of them. In such a case, output the smallest one. Note that the order of elements in a set doesn't matter, i.e. set \{1, 2, 3\} equals to set \{2, 1, 3\}.
Formally, find the smallest positive integer k such that \\{s ⊕ k | s ∈ S\} = S or report that there is no such number.
For example, if S = \{1, 3, 4\} and k = 2, new set will be equal to \{3, 1, 6\}. If S = \{0, 1, 2, 3\} and k = 1, after playing set will stay the same.
Input
In the first line of input, there is a single integer t (1 ≤ t ≤ 1024), the number of test cases. In the next lines, t test cases follow. Each of them consists of two lines.
In the first line there is a single integer n (1 ≤ n ≤ 1024) denoting the number of elements in set S. Second line consists of n distinct integers s_i (0 ≤ s_i < 1024), elements of S.
It is guaranteed that the sum of n over all test cases will not exceed 1024.
Output
Print t lines; i-th line should contain the answer to the i-th test case, the minimal positive integer k satisfying the conditions or -1 if no such k exists.
Example
Input
6
4
1 0 2 3
6
10 7 14 8 3 12
2
0 2
3
1 2 3
6
1 4 6 10 11 12
2
0 1023
Output
1
4
2
-1
-1
1023
Note
In the first test case, the answer is 1 because it is a minimum positive integer and it satisfies all the conditions. | instruction | 0 | 10,108 | 19 | 20,216 |
Tags: bitmasks, brute force
Correct Solution:
```
for test in range(int(input())):
n=int(input())
a=list(map(int,input().split()))
b=a.copy()
b.sort()
ans=-1
if b[0]==0:
for i in range(1,n):
temp=[]
for j in range(n):
temp.append(a[j]^b[i])
if set(temp)==set(a):
ans=b[i]
break
print(ans)
else:
m=max(b)
y=0
while 1:
if 2**y>m:
break
y+=1
for i in range(1,2**y+1):
temp=[]
for j in range(n):
temp.append(a[j]^i)
if set(temp)==set(a):
ans=i
break
print(ans)
``` | output | 1 | 10,108 | 19 | 20,217 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Among Johnny's numerous hobbies, there are two seemingly harmless ones: applying bitwise operations and sneaking into his dad's office. As it is usually the case with small children, Johnny is unaware that combining these two activities can get him in a lot of trouble.
There is a set S containing very important numbers on his dad's desk. The minute Johnny heard about it, he decided that it's a good idea to choose a positive integer k and replace each element s of the set S with s ⊕ k (⊕ denotes the [exclusive or](https://en.wikipedia.org/wiki/Exclusive_or#Computer_science) operation).
Help him choose such k that Johnny's dad will not see any difference after his son is done playing (i.e. Johnny will get the same set as before playing). It is possible that no such number exists. It is also possible that there are many of them. In such a case, output the smallest one. Note that the order of elements in a set doesn't matter, i.e. set \{1, 2, 3\} equals to set \{2, 1, 3\}.
Formally, find the smallest positive integer k such that \\{s ⊕ k | s ∈ S\} = S or report that there is no such number.
For example, if S = \{1, 3, 4\} and k = 2, new set will be equal to \{3, 1, 6\}. If S = \{0, 1, 2, 3\} and k = 1, after playing set will stay the same.
Input
In the first line of input, there is a single integer t (1 ≤ t ≤ 1024), the number of test cases. In the next lines, t test cases follow. Each of them consists of two lines.
In the first line there is a single integer n (1 ≤ n ≤ 1024) denoting the number of elements in set S. Second line consists of n distinct integers s_i (0 ≤ s_i < 1024), elements of S.
It is guaranteed that the sum of n over all test cases will not exceed 1024.
Output
Print t lines; i-th line should contain the answer to the i-th test case, the minimal positive integer k satisfying the conditions or -1 if no such k exists.
Example
Input
6
4
1 0 2 3
6
10 7 14 8 3 12
2
0 2
3
1 2 3
6
1 4 6 10 11 12
2
0 1023
Output
1
4
2
-1
-1
1023
Note
In the first test case, the answer is 1 because it is a minimum positive integer and it satisfies all the conditions. | instruction | 0 | 10,109 | 19 | 20,218 |
Tags: bitmasks, brute force
Correct Solution:
```
import sys
from functools import lru_cache, cmp_to_key
from heapq import merge, heapify, heappop, heappush
from math import ceil, floor, gcd, sqrt, trunc, inf
from collections import defaultdict as dd, deque, Counter as C
from itertools import combinations as comb, permutations as perm
from bisect import bisect_left as bl, bisect_right as br, bisect
from time import perf_counter
from fractions import Fraction
# sys.setrecursionlimit(pow(10, 6))
# sys.stdin = open("input.txt", "r")
# sys.stdout = open("output.txt", "w")
mod = pow(10, 9) + 7
mod2 = 998244353
def data(): return sys.stdin.readline().strip()
def out(*var, end="\n"): sys.stdout.write(' '.join(map(str, var))+end)
def l(): return list(sp())
def sl(): return list(ssp())
def sp(): return map(int, data().split())
def ssp(): return map(str, data().split())
def l1d(n, val=0): return [val for i in range(n)]
def l2d(n, m, val=0): return [l1d(n, val) for j in range(m)]
for _ in range(int(data())):
n = int(data())
arr = set(l())
r = False
answer = -1
for i in range(1, 1025):
s = set()
for j in arr:
s.add(j ^ i)
if s == arr:
r = True
answer = i
break
if r:
break
out(answer)
``` | output | 1 | 10,109 | 19 | 20,219 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Among Johnny's numerous hobbies, there are two seemingly harmless ones: applying bitwise operations and sneaking into his dad's office. As it is usually the case with small children, Johnny is unaware that combining these two activities can get him in a lot of trouble.
There is a set S containing very important numbers on his dad's desk. The minute Johnny heard about it, he decided that it's a good idea to choose a positive integer k and replace each element s of the set S with s ⊕ k (⊕ denotes the [exclusive or](https://en.wikipedia.org/wiki/Exclusive_or#Computer_science) operation).
Help him choose such k that Johnny's dad will not see any difference after his son is done playing (i.e. Johnny will get the same set as before playing). It is possible that no such number exists. It is also possible that there are many of them. In such a case, output the smallest one. Note that the order of elements in a set doesn't matter, i.e. set \{1, 2, 3\} equals to set \{2, 1, 3\}.
Formally, find the smallest positive integer k such that \\{s ⊕ k | s ∈ S\} = S or report that there is no such number.
For example, if S = \{1, 3, 4\} and k = 2, new set will be equal to \{3, 1, 6\}. If S = \{0, 1, 2, 3\} and k = 1, after playing set will stay the same.
Input
In the first line of input, there is a single integer t (1 ≤ t ≤ 1024), the number of test cases. In the next lines, t test cases follow. Each of them consists of two lines.
In the first line there is a single integer n (1 ≤ n ≤ 1024) denoting the number of elements in set S. Second line consists of n distinct integers s_i (0 ≤ s_i < 1024), elements of S.
It is guaranteed that the sum of n over all test cases will not exceed 1024.
Output
Print t lines; i-th line should contain the answer to the i-th test case, the minimal positive integer k satisfying the conditions or -1 if no such k exists.
Example
Input
6
4
1 0 2 3
6
10 7 14 8 3 12
2
0 2
3
1 2 3
6
1 4 6 10 11 12
2
0 1023
Output
1
4
2
-1
-1
1023
Note
In the first test case, the answer is 1 because it is a minimum positive integer and it satisfies all the conditions. | instruction | 0 | 10,110 | 19 | 20,220 |
Tags: bitmasks, brute force
Correct Solution:
```
import math
t = int(input())
for _ in range(t):
n = int(input())
setList = [int(var) for var in input().split()]
origSet = set(setList)
flag = True
for k in range(1, 1025):
visited = set()
for var in setList:
# print(var, 10^var)
visited.add(k^var)
if len(visited) == len(setList):
if visited==origSet:
print(k)
# print(visited, origSet)
flag = False
break
if flag is True:
print(-1)
``` | output | 1 | 10,110 | 19 | 20,221 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Among Johnny's numerous hobbies, there are two seemingly harmless ones: applying bitwise operations and sneaking into his dad's office. As it is usually the case with small children, Johnny is unaware that combining these two activities can get him in a lot of trouble.
There is a set S containing very important numbers on his dad's desk. The minute Johnny heard about it, he decided that it's a good idea to choose a positive integer k and replace each element s of the set S with s ⊕ k (⊕ denotes the [exclusive or](https://en.wikipedia.org/wiki/Exclusive_or#Computer_science) operation).
Help him choose such k that Johnny's dad will not see any difference after his son is done playing (i.e. Johnny will get the same set as before playing). It is possible that no such number exists. It is also possible that there are many of them. In such a case, output the smallest one. Note that the order of elements in a set doesn't matter, i.e. set \{1, 2, 3\} equals to set \{2, 1, 3\}.
Formally, find the smallest positive integer k such that \\{s ⊕ k | s ∈ S\} = S or report that there is no such number.
For example, if S = \{1, 3, 4\} and k = 2, new set will be equal to \{3, 1, 6\}. If S = \{0, 1, 2, 3\} and k = 1, after playing set will stay the same.
Input
In the first line of input, there is a single integer t (1 ≤ t ≤ 1024), the number of test cases. In the next lines, t test cases follow. Each of them consists of two lines.
In the first line there is a single integer n (1 ≤ n ≤ 1024) denoting the number of elements in set S. Second line consists of n distinct integers s_i (0 ≤ s_i < 1024), elements of S.
It is guaranteed that the sum of n over all test cases will not exceed 1024.
Output
Print t lines; i-th line should contain the answer to the i-th test case, the minimal positive integer k satisfying the conditions or -1 if no such k exists.
Example
Input
6
4
1 0 2 3
6
10 7 14 8 3 12
2
0 2
3
1 2 3
6
1 4 6 10 11 12
2
0 1023
Output
1
4
2
-1
-1
1023
Note
In the first test case, the answer is 1 because it is a minimum positive integer and it satisfies all the conditions. | instruction | 0 | 10,111 | 19 | 20,222 |
Tags: bitmasks, brute force
Correct Solution:
```
''' ## ## ####### # # ######
## ## ## ## ### ##
## ## ## # # # ##
######### ####### # # ## '''
import sys
import math
# sys.setrecursionlimit(10**6)
def get_ints(): return map(int, input().strip().split())
def get_list(): return list(get_ints())
def printspx(*args): return print(*args, end="")
def printsp(*args): return print(*args, end=" ")
def printchk(*args): return print(*args, end=" \ ")
MODPRIME = int(1e9+7); BABYMODPR = 998244353;
# sys.stdin = open("input.txt","r") # <<< Comment this line >>> #
for _testcases_ in range(int(input())):
n = int(input())
li = get_list()
flag = False
se = set(li)
for i in range(1, 1024):
se2 = set()
for j in li:
se2.add(j ^ i)
if se2 == se:
print(i)
flag = True
break
if not flag:
print(-1)
'''
THE LOGIC AND APPROACH IS BY ME @luctivud ( UDIT GUPTA )
SOME PARTS OF THE CODE HAS BEEN TAKEN FROM WEBSITES LIKE::
(I Own the code if no link is provided here or I may have missed mentioning it)
>>> DO NOT PLAGIARISE.
TESTCASES:
>>> COMMENT THE STDIN !!
'''
``` | output | 1 | 10,111 | 19 | 20,223 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Among Johnny's numerous hobbies, there are two seemingly harmless ones: applying bitwise operations and sneaking into his dad's office. As it is usually the case with small children, Johnny is unaware that combining these two activities can get him in a lot of trouble.
There is a set S containing very important numbers on his dad's desk. The minute Johnny heard about it, he decided that it's a good idea to choose a positive integer k and replace each element s of the set S with s ⊕ k (⊕ denotes the [exclusive or](https://en.wikipedia.org/wiki/Exclusive_or#Computer_science) operation).
Help him choose such k that Johnny's dad will not see any difference after his son is done playing (i.e. Johnny will get the same set as before playing). It is possible that no such number exists. It is also possible that there are many of them. In such a case, output the smallest one. Note that the order of elements in a set doesn't matter, i.e. set \{1, 2, 3\} equals to set \{2, 1, 3\}.
Formally, find the smallest positive integer k such that \\{s ⊕ k | s ∈ S\} = S or report that there is no such number.
For example, if S = \{1, 3, 4\} and k = 2, new set will be equal to \{3, 1, 6\}. If S = \{0, 1, 2, 3\} and k = 1, after playing set will stay the same.
Input
In the first line of input, there is a single integer t (1 ≤ t ≤ 1024), the number of test cases. In the next lines, t test cases follow. Each of them consists of two lines.
In the first line there is a single integer n (1 ≤ n ≤ 1024) denoting the number of elements in set S. Second line consists of n distinct integers s_i (0 ≤ s_i < 1024), elements of S.
It is guaranteed that the sum of n over all test cases will not exceed 1024.
Output
Print t lines; i-th line should contain the answer to the i-th test case, the minimal positive integer k satisfying the conditions or -1 if no such k exists.
Example
Input
6
4
1 0 2 3
6
10 7 14 8 3 12
2
0 2
3
1 2 3
6
1 4 6 10 11 12
2
0 1023
Output
1
4
2
-1
-1
1023
Note
In the first test case, the answer is 1 because it is a minimum positive integer and it satisfies all the conditions. | instruction | 0 | 10,112 | 19 | 20,224 |
Tags: bitmasks, brute force
Correct Solution:
```
t = int(input())
for _ in range(t):
n = int(input())
a = set(map(int, input().split()))
ans = 0
for i in range(1024):
s = a.copy()
ok = True
while len(s) != 0:
e = s.pop()
if e^i in s:
s.remove(e^i)
else:
ok = False
break
if len(s) == 0 and ok:
ans = i
break
print(ans if ok else -1)
``` | output | 1 | 10,112 | 19 | 20,225 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Among Johnny's numerous hobbies, there are two seemingly harmless ones: applying bitwise operations and sneaking into his dad's office. As it is usually the case with small children, Johnny is unaware that combining these two activities can get him in a lot of trouble.
There is a set S containing very important numbers on his dad's desk. The minute Johnny heard about it, he decided that it's a good idea to choose a positive integer k and replace each element s of the set S with s ⊕ k (⊕ denotes the [exclusive or](https://en.wikipedia.org/wiki/Exclusive_or#Computer_science) operation).
Help him choose such k that Johnny's dad will not see any difference after his son is done playing (i.e. Johnny will get the same set as before playing). It is possible that no such number exists. It is also possible that there are many of them. In such a case, output the smallest one. Note that the order of elements in a set doesn't matter, i.e. set \{1, 2, 3\} equals to set \{2, 1, 3\}.
Formally, find the smallest positive integer k such that \\{s ⊕ k | s ∈ S\} = S or report that there is no such number.
For example, if S = \{1, 3, 4\} and k = 2, new set will be equal to \{3, 1, 6\}. If S = \{0, 1, 2, 3\} and k = 1, after playing set will stay the same.
Input
In the first line of input, there is a single integer t (1 ≤ t ≤ 1024), the number of test cases. In the next lines, t test cases follow. Each of them consists of two lines.
In the first line there is a single integer n (1 ≤ n ≤ 1024) denoting the number of elements in set S. Second line consists of n distinct integers s_i (0 ≤ s_i < 1024), elements of S.
It is guaranteed that the sum of n over all test cases will not exceed 1024.
Output
Print t lines; i-th line should contain the answer to the i-th test case, the minimal positive integer k satisfying the conditions or -1 if no such k exists.
Example
Input
6
4
1 0 2 3
6
10 7 14 8 3 12
2
0 2
3
1 2 3
6
1 4 6 10 11 12
2
0 1023
Output
1
4
2
-1
-1
1023
Note
In the first test case, the answer is 1 because it is a minimum positive integer and it satisfies all the conditions. | instruction | 0 | 10,113 | 19 | 20,226 |
Tags: bitmasks, brute force
Correct Solution:
```
t = int(input())
for _ in range(t):
n = int(input())
S = list(map(int, input().split(' ')))
done = False
for k in range(1,1024):
s = set(S)
while len(s) > 0:
x = s.pop()
if (k^x) not in s:
s.add(x)
break
else:
s.remove(k^x)
if len(s) == 0:
print(k)
done = True
break
if not done:
print(-1)
``` | output | 1 | 10,113 | 19 | 20,227 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Among Johnny's numerous hobbies, there are two seemingly harmless ones: applying bitwise operations and sneaking into his dad's office. As it is usually the case with small children, Johnny is unaware that combining these two activities can get him in a lot of trouble.
There is a set S containing very important numbers on his dad's desk. The minute Johnny heard about it, he decided that it's a good idea to choose a positive integer k and replace each element s of the set S with s ⊕ k (⊕ denotes the [exclusive or](https://en.wikipedia.org/wiki/Exclusive_or#Computer_science) operation).
Help him choose such k that Johnny's dad will not see any difference after his son is done playing (i.e. Johnny will get the same set as before playing). It is possible that no such number exists. It is also possible that there are many of them. In such a case, output the smallest one. Note that the order of elements in a set doesn't matter, i.e. set \{1, 2, 3\} equals to set \{2, 1, 3\}.
Formally, find the smallest positive integer k such that \\{s ⊕ k | s ∈ S\} = S or report that there is no such number.
For example, if S = \{1, 3, 4\} and k = 2, new set will be equal to \{3, 1, 6\}. If S = \{0, 1, 2, 3\} and k = 1, after playing set will stay the same.
Input
In the first line of input, there is a single integer t (1 ≤ t ≤ 1024), the number of test cases. In the next lines, t test cases follow. Each of them consists of two lines.
In the first line there is a single integer n (1 ≤ n ≤ 1024) denoting the number of elements in set S. Second line consists of n distinct integers s_i (0 ≤ s_i < 1024), elements of S.
It is guaranteed that the sum of n over all test cases will not exceed 1024.
Output
Print t lines; i-th line should contain the answer to the i-th test case, the minimal positive integer k satisfying the conditions or -1 if no such k exists.
Example
Input
6
4
1 0 2 3
6
10 7 14 8 3 12
2
0 2
3
1 2 3
6
1 4 6 10 11 12
2
0 1023
Output
1
4
2
-1
-1
1023
Note
In the first test case, the answer is 1 because it is a minimum positive integer and it satisfies all the conditions. | instruction | 0 | 10,114 | 19 | 20,228 |
Tags: bitmasks, brute force
Correct Solution:
```
t=int(input())
import math
for _ in range(t):
n=int(input())
s=set([int(x) for x in input().split()])
if (n==1):
print(-1)
continue
m=2**(int(math.log2(max(s)))+1)-1
ans = 0
k=1
while (k<=m and ans==0):
s2=set()
for i in s:
s2.add(i^k)
if (s==s2):
ans=k
k+=1
if (ans!=0):
print(ans)
else:
print(-1)
``` | output | 1 | 10,114 | 19 | 20,229 |
Provide tags and a correct Python 2 solution for this coding contest problem.
Among Johnny's numerous hobbies, there are two seemingly harmless ones: applying bitwise operations and sneaking into his dad's office. As it is usually the case with small children, Johnny is unaware that combining these two activities can get him in a lot of trouble.
There is a set S containing very important numbers on his dad's desk. The minute Johnny heard about it, he decided that it's a good idea to choose a positive integer k and replace each element s of the set S with s ⊕ k (⊕ denotes the [exclusive or](https://en.wikipedia.org/wiki/Exclusive_or#Computer_science) operation).
Help him choose such k that Johnny's dad will not see any difference after his son is done playing (i.e. Johnny will get the same set as before playing). It is possible that no such number exists. It is also possible that there are many of them. In such a case, output the smallest one. Note that the order of elements in a set doesn't matter, i.e. set \{1, 2, 3\} equals to set \{2, 1, 3\}.
Formally, find the smallest positive integer k such that \\{s ⊕ k | s ∈ S\} = S or report that there is no such number.
For example, if S = \{1, 3, 4\} and k = 2, new set will be equal to \{3, 1, 6\}. If S = \{0, 1, 2, 3\} and k = 1, after playing set will stay the same.
Input
In the first line of input, there is a single integer t (1 ≤ t ≤ 1024), the number of test cases. In the next lines, t test cases follow. Each of them consists of two lines.
In the first line there is a single integer n (1 ≤ n ≤ 1024) denoting the number of elements in set S. Second line consists of n distinct integers s_i (0 ≤ s_i < 1024), elements of S.
It is guaranteed that the sum of n over all test cases will not exceed 1024.
Output
Print t lines; i-th line should contain the answer to the i-th test case, the minimal positive integer k satisfying the conditions or -1 if no such k exists.
Example
Input
6
4
1 0 2 3
6
10 7 14 8 3 12
2
0 2
3
1 2 3
6
1 4 6 10 11 12
2
0 1023
Output
1
4
2
-1
-1
1023
Note
In the first test case, the answer is 1 because it is a minimum positive integer and it satisfies all the conditions. | instruction | 0 | 10,115 | 19 | 20,230 |
Tags: bitmasks, brute force
Correct Solution:
```
from sys import stdin, stdout
from collections import Counter, defaultdict
from itertools import permutations, combinations
from fractions import gcd
raw_input = stdin.readline
pr = stdout.write
mod=10**9+7
def ni():
return int(raw_input())
def li():
return map(int,raw_input().split())
def pn(n):
stdout.write(str(n)+'\n')
def pa(arr):
pr(' '.join(map(str,arr))+'\n')
# fast read function for total integer input
def inp():
# this function returns whole input of
# space/line seperated integers
# Use Ctrl+D to flush stdin.
return map(int,stdin.read().split())
range = xrange # not for python 3.0+
# main code
for t in range(ni()):
n=ni()
l=set(li())
f=0
for k in range(1,1025):
s=set()
for i in l:
s.add(i^k)
#print s,l
if s==l:
f=1
break
if f:
pn(k)
else:
pn(-1)
``` | output | 1 | 10,115 | 19 | 20,231 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Among Johnny's numerous hobbies, there are two seemingly harmless ones: applying bitwise operations and sneaking into his dad's office. As it is usually the case with small children, Johnny is unaware that combining these two activities can get him in a lot of trouble.
There is a set S containing very important numbers on his dad's desk. The minute Johnny heard about it, he decided that it's a good idea to choose a positive integer k and replace each element s of the set S with s ⊕ k (⊕ denotes the [exclusive or](https://en.wikipedia.org/wiki/Exclusive_or#Computer_science) operation).
Help him choose such k that Johnny's dad will not see any difference after his son is done playing (i.e. Johnny will get the same set as before playing). It is possible that no such number exists. It is also possible that there are many of them. In such a case, output the smallest one. Note that the order of elements in a set doesn't matter, i.e. set \{1, 2, 3\} equals to set \{2, 1, 3\}.
Formally, find the smallest positive integer k such that \\{s ⊕ k | s ∈ S\} = S or report that there is no such number.
For example, if S = \{1, 3, 4\} and k = 2, new set will be equal to \{3, 1, 6\}. If S = \{0, 1, 2, 3\} and k = 1, after playing set will stay the same.
Input
In the first line of input, there is a single integer t (1 ≤ t ≤ 1024), the number of test cases. In the next lines, t test cases follow. Each of them consists of two lines.
In the first line there is a single integer n (1 ≤ n ≤ 1024) denoting the number of elements in set S. Second line consists of n distinct integers s_i (0 ≤ s_i < 1024), elements of S.
It is guaranteed that the sum of n over all test cases will not exceed 1024.
Output
Print t lines; i-th line should contain the answer to the i-th test case, the minimal positive integer k satisfying the conditions or -1 if no such k exists.
Example
Input
6
4
1 0 2 3
6
10 7 14 8 3 12
2
0 2
3
1 2 3
6
1 4 6 10 11 12
2
0 1023
Output
1
4
2
-1
-1
1023
Note
In the first test case, the answer is 1 because it is a minimum positive integer and it satisfies all the conditions.
Submitted Solution:
```
t = int(input())
for loop in range(t):
n = int(input())
d = {}
arr = list(map(int,input().split()))
arr.sort()
for i in arr:
d[i] = 1
if(arr[0]==0):
ans =0
for i in range(1,n):
flag = 0
val = arr[i]
for j in arr:
if(val^j not in d):
flag = 1
break
if(flag==0):
print(val)
ans = 1
break
if(ans==0):
print(-1)
else:
ans =0
for i in range(1,1025):
flag = 0
if(i not in d):
for j in arr:
if i^j not in d:
flag = 1
break
else:
continue
if(flag==0):
print(i)
ans = 1
break
if(ans==0):
print(-1)
``` | instruction | 0 | 10,116 | 19 | 20,232 |
Yes | output | 1 | 10,116 | 19 | 20,233 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Among Johnny's numerous hobbies, there are two seemingly harmless ones: applying bitwise operations and sneaking into his dad's office. As it is usually the case with small children, Johnny is unaware that combining these two activities can get him in a lot of trouble.
There is a set S containing very important numbers on his dad's desk. The minute Johnny heard about it, he decided that it's a good idea to choose a positive integer k and replace each element s of the set S with s ⊕ k (⊕ denotes the [exclusive or](https://en.wikipedia.org/wiki/Exclusive_or#Computer_science) operation).
Help him choose such k that Johnny's dad will not see any difference after his son is done playing (i.e. Johnny will get the same set as before playing). It is possible that no such number exists. It is also possible that there are many of them. In such a case, output the smallest one. Note that the order of elements in a set doesn't matter, i.e. set \{1, 2, 3\} equals to set \{2, 1, 3\}.
Formally, find the smallest positive integer k such that \\{s ⊕ k | s ∈ S\} = S or report that there is no such number.
For example, if S = \{1, 3, 4\} and k = 2, new set will be equal to \{3, 1, 6\}. If S = \{0, 1, 2, 3\} and k = 1, after playing set will stay the same.
Input
In the first line of input, there is a single integer t (1 ≤ t ≤ 1024), the number of test cases. In the next lines, t test cases follow. Each of them consists of two lines.
In the first line there is a single integer n (1 ≤ n ≤ 1024) denoting the number of elements in set S. Second line consists of n distinct integers s_i (0 ≤ s_i < 1024), elements of S.
It is guaranteed that the sum of n over all test cases will not exceed 1024.
Output
Print t lines; i-th line should contain the answer to the i-th test case, the minimal positive integer k satisfying the conditions or -1 if no such k exists.
Example
Input
6
4
1 0 2 3
6
10 7 14 8 3 12
2
0 2
3
1 2 3
6
1 4 6 10 11 12
2
0 1023
Output
1
4
2
-1
-1
1023
Note
In the first test case, the answer is 1 because it is a minimum positive integer and it satisfies all the conditions.
Submitted Solution:
```
from sys import stdin, stdout
import math,sys
from itertools import permutations, combinations
from collections import defaultdict,deque,OrderedDict
from os import path
import bisect as bi
import heapq
def yes():print('YES')
def no():print('NO')
if (path.exists('input.txt')):
#------------------Sublime--------------------------------------#
sys.stdin=open('input.txt','r');sys.stdout=open('output.txt','w');
def I():return (int(input()))
def In():return(map(int,input().split()))
else:
#------------------PYPY FAst I/o--------------------------------#
def I():return (int(stdin.readline()))
def In():return(map(int,stdin.readline().split()))
def dict(a):
d={}
for x in a:
if d.get(x,-1)!=-1:
d[x]+=1
else:
d[x]=1
return d
def find_gt(a, x):
'Find leftmost value greater than x'
i = bi.bisect_right(a, x)
if i != len(a):
return i
else:
return -1
def main():
try:
n=I()
l=list(In())
d=dict(l)
ans=-1
for i in range(1,1025):
count=0
for x in l:
temp=x^i
if d.get(temp,-1)==-1:
break
else:
count+=1
if count==n:
ans=i
break
print(ans)
except:
pass
M = 998244353
P = 1000000007
if __name__ == '__main__':
for _ in range(I()):main()
#for _ in range(1):main()
``` | instruction | 0 | 10,117 | 19 | 20,234 |
Yes | output | 1 | 10,117 | 19 | 20,235 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Among Johnny's numerous hobbies, there are two seemingly harmless ones: applying bitwise operations and sneaking into his dad's office. As it is usually the case with small children, Johnny is unaware that combining these two activities can get him in a lot of trouble.
There is a set S containing very important numbers on his dad's desk. The minute Johnny heard about it, he decided that it's a good idea to choose a positive integer k and replace each element s of the set S with s ⊕ k (⊕ denotes the [exclusive or](https://en.wikipedia.org/wiki/Exclusive_or#Computer_science) operation).
Help him choose such k that Johnny's dad will not see any difference after his son is done playing (i.e. Johnny will get the same set as before playing). It is possible that no such number exists. It is also possible that there are many of them. In such a case, output the smallest one. Note that the order of elements in a set doesn't matter, i.e. set \{1, 2, 3\} equals to set \{2, 1, 3\}.
Formally, find the smallest positive integer k such that \\{s ⊕ k | s ∈ S\} = S or report that there is no such number.
For example, if S = \{1, 3, 4\} and k = 2, new set will be equal to \{3, 1, 6\}. If S = \{0, 1, 2, 3\} and k = 1, after playing set will stay the same.
Input
In the first line of input, there is a single integer t (1 ≤ t ≤ 1024), the number of test cases. In the next lines, t test cases follow. Each of them consists of two lines.
In the first line there is a single integer n (1 ≤ n ≤ 1024) denoting the number of elements in set S. Second line consists of n distinct integers s_i (0 ≤ s_i < 1024), elements of S.
It is guaranteed that the sum of n over all test cases will not exceed 1024.
Output
Print t lines; i-th line should contain the answer to the i-th test case, the minimal positive integer k satisfying the conditions or -1 if no such k exists.
Example
Input
6
4
1 0 2 3
6
10 7 14 8 3 12
2
0 2
3
1 2 3
6
1 4 6 10 11 12
2
0 1023
Output
1
4
2
-1
-1
1023
Note
In the first test case, the answer is 1 because it is a minimum positive integer and it satisfies all the conditions.
Submitted Solution:
```
t = int(input())
import math
delay = []
for _ in range(t):
n = int(input())
arr = input().split()
arr = [int(a) for a in arr]
res = 1
found = False
while(res <= 1024):
go = True
result = [(res ^ a) for a in arr]
dic = {}
for r in result:
if r in dic:
dic[r] += 1
else:
dic[r] = 1
for a in arr:
if a not in dic:
go = False
break
else:
dic[a] -= 1
if go:
for k in dic:
if dic[k] == 0:
continue
else:
go = False
break
if go:
print(res)
found = True
break
res += 1
if not found:
print(-1)
``` | instruction | 0 | 10,118 | 19 | 20,236 |
Yes | output | 1 | 10,118 | 19 | 20,237 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Among Johnny's numerous hobbies, there are two seemingly harmless ones: applying bitwise operations and sneaking into his dad's office. As it is usually the case with small children, Johnny is unaware that combining these two activities can get him in a lot of trouble.
There is a set S containing very important numbers on his dad's desk. The minute Johnny heard about it, he decided that it's a good idea to choose a positive integer k and replace each element s of the set S with s ⊕ k (⊕ denotes the [exclusive or](https://en.wikipedia.org/wiki/Exclusive_or#Computer_science) operation).
Help him choose such k that Johnny's dad will not see any difference after his son is done playing (i.e. Johnny will get the same set as before playing). It is possible that no such number exists. It is also possible that there are many of them. In such a case, output the smallest one. Note that the order of elements in a set doesn't matter, i.e. set \{1, 2, 3\} equals to set \{2, 1, 3\}.
Formally, find the smallest positive integer k such that \\{s ⊕ k | s ∈ S\} = S or report that there is no such number.
For example, if S = \{1, 3, 4\} and k = 2, new set will be equal to \{3, 1, 6\}. If S = \{0, 1, 2, 3\} and k = 1, after playing set will stay the same.
Input
In the first line of input, there is a single integer t (1 ≤ t ≤ 1024), the number of test cases. In the next lines, t test cases follow. Each of them consists of two lines.
In the first line there is a single integer n (1 ≤ n ≤ 1024) denoting the number of elements in set S. Second line consists of n distinct integers s_i (0 ≤ s_i < 1024), elements of S.
It is guaranteed that the sum of n over all test cases will not exceed 1024.
Output
Print t lines; i-th line should contain the answer to the i-th test case, the minimal positive integer k satisfying the conditions or -1 if no such k exists.
Example
Input
6
4
1 0 2 3
6
10 7 14 8 3 12
2
0 2
3
1 2 3
6
1 4 6 10 11 12
2
0 1023
Output
1
4
2
-1
-1
1023
Note
In the first test case, the answer is 1 because it is a minimum positive integer and it satisfies all the conditions.
Submitted Solution:
```
from functools import reduce
for _ in range(int(input())):
n = int(input())
s = [int(i) for i in input().split()]
s.sort()
for j in range(1, 1025):
if j == 1024:
print(-1)
break
t = [j ^ x for x in s]
t.sort()
if all([t[i] == s[i] for i in range(n)]):
print(j)
break
``` | instruction | 0 | 10,119 | 19 | 20,238 |
Yes | output | 1 | 10,119 | 19 | 20,239 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Among Johnny's numerous hobbies, there are two seemingly harmless ones: applying bitwise operations and sneaking into his dad's office. As it is usually the case with small children, Johnny is unaware that combining these two activities can get him in a lot of trouble.
There is a set S containing very important numbers on his dad's desk. The minute Johnny heard about it, he decided that it's a good idea to choose a positive integer k and replace each element s of the set S with s ⊕ k (⊕ denotes the [exclusive or](https://en.wikipedia.org/wiki/Exclusive_or#Computer_science) operation).
Help him choose such k that Johnny's dad will not see any difference after his son is done playing (i.e. Johnny will get the same set as before playing). It is possible that no such number exists. It is also possible that there are many of them. In such a case, output the smallest one. Note that the order of elements in a set doesn't matter, i.e. set \{1, 2, 3\} equals to set \{2, 1, 3\}.
Formally, find the smallest positive integer k such that \\{s ⊕ k | s ∈ S\} = S or report that there is no such number.
For example, if S = \{1, 3, 4\} and k = 2, new set will be equal to \{3, 1, 6\}. If S = \{0, 1, 2, 3\} and k = 1, after playing set will stay the same.
Input
In the first line of input, there is a single integer t (1 ≤ t ≤ 1024), the number of test cases. In the next lines, t test cases follow. Each of them consists of two lines.
In the first line there is a single integer n (1 ≤ n ≤ 1024) denoting the number of elements in set S. Second line consists of n distinct integers s_i (0 ≤ s_i < 1024), elements of S.
It is guaranteed that the sum of n over all test cases will not exceed 1024.
Output
Print t lines; i-th line should contain the answer to the i-th test case, the minimal positive integer k satisfying the conditions or -1 if no such k exists.
Example
Input
6
4
1 0 2 3
6
10 7 14 8 3 12
2
0 2
3
1 2 3
6
1 4 6 10 11 12
2
0 1023
Output
1
4
2
-1
-1
1023
Note
In the first test case, the answer is 1 because it is a minimum positive integer and it satisfies all the conditions.
Submitted Solution:
```
import sys,math
input=sys.stdin.readline
t=int(input())
for r in range(t):
n=int(input())
l=list(map(int,input().split()))
d1 = {}
for i in l:
try:
d1[i]+=1
except:
d1[i]=1
maxi = max(l)
ans = 0
for i in range(1,maxi+1):
temp = []
for j in l:
temp.append(j^i)
d2 = {}
for j in temp:
try:
d2[j]+=1
except:
d2[j]=1
if d1 == d2:
ans = i
break
if ans == 0:
print(-1)
else:
print(ans)
``` | instruction | 0 | 10,120 | 19 | 20,240 |
No | output | 1 | 10,120 | 19 | 20,241 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Among Johnny's numerous hobbies, there are two seemingly harmless ones: applying bitwise operations and sneaking into his dad's office. As it is usually the case with small children, Johnny is unaware that combining these two activities can get him in a lot of trouble.
There is a set S containing very important numbers on his dad's desk. The minute Johnny heard about it, he decided that it's a good idea to choose a positive integer k and replace each element s of the set S with s ⊕ k (⊕ denotes the [exclusive or](https://en.wikipedia.org/wiki/Exclusive_or#Computer_science) operation).
Help him choose such k that Johnny's dad will not see any difference after his son is done playing (i.e. Johnny will get the same set as before playing). It is possible that no such number exists. It is also possible that there are many of them. In such a case, output the smallest one. Note that the order of elements in a set doesn't matter, i.e. set \{1, 2, 3\} equals to set \{2, 1, 3\}.
Formally, find the smallest positive integer k such that \\{s ⊕ k | s ∈ S\} = S or report that there is no such number.
For example, if S = \{1, 3, 4\} and k = 2, new set will be equal to \{3, 1, 6\}. If S = \{0, 1, 2, 3\} and k = 1, after playing set will stay the same.
Input
In the first line of input, there is a single integer t (1 ≤ t ≤ 1024), the number of test cases. In the next lines, t test cases follow. Each of them consists of two lines.
In the first line there is a single integer n (1 ≤ n ≤ 1024) denoting the number of elements in set S. Second line consists of n distinct integers s_i (0 ≤ s_i < 1024), elements of S.
It is guaranteed that the sum of n over all test cases will not exceed 1024.
Output
Print t lines; i-th line should contain the answer to the i-th test case, the minimal positive integer k satisfying the conditions or -1 if no such k exists.
Example
Input
6
4
1 0 2 3
6
10 7 14 8 3 12
2
0 2
3
1 2 3
6
1 4 6 10 11 12
2
0 1023
Output
1
4
2
-1
-1
1023
Note
In the first test case, the answer is 1 because it is a minimum positive integer and it satisfies all the conditions.
Submitted Solution:
```
import sys
input=sys.stdin.readline
def N(): return int(input())
def NM():return map(int,input().split())
def L():return list(NM())
def LN(n):return [N() for i in range(n)]
def LL(n):return [L() for i in range(n)]
t=N()
def f():
n=N()
l=set(L())
x=l.pop()
for i in l:
k=x^i
for j in l:
if not (j==i or j^k in l):
break
else:
print(k)
break
else:
print(-1)
for i in range(t):
f()
``` | instruction | 0 | 10,121 | 19 | 20,242 |
No | output | 1 | 10,121 | 19 | 20,243 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Among Johnny's numerous hobbies, there are two seemingly harmless ones: applying bitwise operations and sneaking into his dad's office. As it is usually the case with small children, Johnny is unaware that combining these two activities can get him in a lot of trouble.
There is a set S containing very important numbers on his dad's desk. The minute Johnny heard about it, he decided that it's a good idea to choose a positive integer k and replace each element s of the set S with s ⊕ k (⊕ denotes the [exclusive or](https://en.wikipedia.org/wiki/Exclusive_or#Computer_science) operation).
Help him choose such k that Johnny's dad will not see any difference after his son is done playing (i.e. Johnny will get the same set as before playing). It is possible that no such number exists. It is also possible that there are many of them. In such a case, output the smallest one. Note that the order of elements in a set doesn't matter, i.e. set \{1, 2, 3\} equals to set \{2, 1, 3\}.
Formally, find the smallest positive integer k such that \\{s ⊕ k | s ∈ S\} = S or report that there is no such number.
For example, if S = \{1, 3, 4\} and k = 2, new set will be equal to \{3, 1, 6\}. If S = \{0, 1, 2, 3\} and k = 1, after playing set will stay the same.
Input
In the first line of input, there is a single integer t (1 ≤ t ≤ 1024), the number of test cases. In the next lines, t test cases follow. Each of them consists of two lines.
In the first line there is a single integer n (1 ≤ n ≤ 1024) denoting the number of elements in set S. Second line consists of n distinct integers s_i (0 ≤ s_i < 1024), elements of S.
It is guaranteed that the sum of n over all test cases will not exceed 1024.
Output
Print t lines; i-th line should contain the answer to the i-th test case, the minimal positive integer k satisfying the conditions or -1 if no such k exists.
Example
Input
6
4
1 0 2 3
6
10 7 14 8 3 12
2
0 2
3
1 2 3
6
1 4 6 10 11 12
2
0 1023
Output
1
4
2
-1
-1
1023
Note
In the first test case, the answer is 1 because it is a minimum positive integer and it satisfies all the conditions.
Submitted Solution:
```
def newxtPow(n):
cur = math.log(n,2)
return 2**math.ceil(cur)
import math
for _ in range(int(input())):
n = int(input())
s = set(map(int,input().split()))
l = list(s)
# p = 1/max(l)
if n==1:
print(-1)
continue
ans = -1
if max(l)!=0:
for i in range(1,newxtPow(max(l))+1):
new = set([])
for j in l:
new.add(j^i)
# print(i,new,s)
if new==s:
ans = i
break
print(ans)
``` | instruction | 0 | 10,122 | 19 | 20,244 |
No | output | 1 | 10,122 | 19 | 20,245 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Among Johnny's numerous hobbies, there are two seemingly harmless ones: applying bitwise operations and sneaking into his dad's office. As it is usually the case with small children, Johnny is unaware that combining these two activities can get him in a lot of trouble.
There is a set S containing very important numbers on his dad's desk. The minute Johnny heard about it, he decided that it's a good idea to choose a positive integer k and replace each element s of the set S with s ⊕ k (⊕ denotes the [exclusive or](https://en.wikipedia.org/wiki/Exclusive_or#Computer_science) operation).
Help him choose such k that Johnny's dad will not see any difference after his son is done playing (i.e. Johnny will get the same set as before playing). It is possible that no such number exists. It is also possible that there are many of them. In such a case, output the smallest one. Note that the order of elements in a set doesn't matter, i.e. set \{1, 2, 3\} equals to set \{2, 1, 3\}.
Formally, find the smallest positive integer k such that \\{s ⊕ k | s ∈ S\} = S or report that there is no such number.
For example, if S = \{1, 3, 4\} and k = 2, new set will be equal to \{3, 1, 6\}. If S = \{0, 1, 2, 3\} and k = 1, after playing set will stay the same.
Input
In the first line of input, there is a single integer t (1 ≤ t ≤ 1024), the number of test cases. In the next lines, t test cases follow. Each of them consists of two lines.
In the first line there is a single integer n (1 ≤ n ≤ 1024) denoting the number of elements in set S. Second line consists of n distinct integers s_i (0 ≤ s_i < 1024), elements of S.
It is guaranteed that the sum of n over all test cases will not exceed 1024.
Output
Print t lines; i-th line should contain the answer to the i-th test case, the minimal positive integer k satisfying the conditions or -1 if no such k exists.
Example
Input
6
4
1 0 2 3
6
10 7 14 8 3 12
2
0 2
3
1 2 3
6
1 4 6 10 11 12
2
0 1023
Output
1
4
2
-1
-1
1023
Note
In the first test case, the answer is 1 because it is a minimum positive integer and it satisfies all the conditions.
Submitted Solution:
```
kl = int(input())
for l in range(kl):
for er in range(1):
pr=1
n = int(input())
a=[int(i) for i in input().split()]
if n%2!=0:
pr=0
break
d, mn1, mn2=0, 1024, 1024
for i in range(n):
d=d^a[i]
if a[i]<mn1:
mn1, mn2 = a[i], mn1
if n%4!=0:
if d==0:
pr=0
break
else:
for i in range(n):
if d^a[i] not in a:
pr=0
break
else:
if d!=0:
pr=0
break
else:
d=mn1^mn2
if pr:
print(d)
else:
print(-1)
``` | instruction | 0 | 10,123 | 19 | 20,246 |
No | output | 1 | 10,123 | 19 | 20,247 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya plays the Geometry Horse.
The game goal is to destroy geometric figures of the game world. A certain number of points is given for destroying each figure depending on the figure type and the current factor value.
There are n types of geometric figures. The number of figures of type ki and figure cost ci is known for each figure type. A player gets ci·f points for destroying one figure of type i, where f is the current factor. The factor value can be an integer number from 1 to t + 1, inclusive. At the beginning of the game the factor value is equal to 1. The factor is set to i + 1 after destruction of pi (1 ≤ i ≤ t) figures, so the (pi + 1)-th figure to be destroyed is considered with factor equal to i + 1.
Your task is to determine the maximum number of points Vasya can get after he destroys all figures. Take into account that Vasya is so tough that he can destroy figures in any order chosen by him.
Input
The first line contains the only integer number n (1 ≤ n ≤ 100) — the number of figure types.
Each of the following n lines contains two integer numbers ki and ci (1 ≤ ki ≤ 109, 0 ≤ ci ≤ 1000), separated with space — the number of figures of the i-th type and the cost of one i-type figure, correspondingly.
The next line contains the only integer number t (1 ≤ t ≤ 100) — the number that describe the factor's changes.
The next line contains t integer numbers pi (1 ≤ p1 < p2 < ... < pt ≤ 1012), separated with spaces.
Please, do not use the %lld specificator to read or write 64-bit integers in С++. It is preferred to use cin, cout streams or the %I64d specificator.
Output
Print the only number — the maximum number of points Vasya can get.
Examples
Input
1
5 10
2
3 6
Output
70
Input
2
3 8
5 10
1
20
Output
74
Note
In the first example Vasya destroys three figures first and gets 3·1·10 = 30 points. Then the factor will become equal to 2 and after destroying the last two figures Vasya will get 2·2·10 = 40 points. As a result Vasya will get 70 points.
In the second example all 8 figures will be destroyed with factor 1, so Vasya will get (3·8 + 5·10)·1 = 74 points.
Submitted Solution:
```
import sys
def solve():
n, = rv()
figures = list()
before = 0
for i in range(n):
number, cost, = rv()
figures.append([cost, number, before + 1, before + number])
figures.sort()
for i in range(n):
number = figures[i][1]
figures[i][2] = before + 1
figures[i][3] = before + number
before += number
t, = rv()
p = [0] + list(map(int, input().split()))
res = 0
for i in range(1, t + 1):
for f in range(n):
left = max(figures[f][2], p[i - 1] + 1)
right = min(figures[f][3], p[i])
num = max(0, right - left + 1)
res += num * i * figures[f][0]
# print(left, right, num, i , f, figures[f][0])
print(res)
def prt(l): return print(''.join(l))
def rv(): return map(int, input().split())
def rl(n): return [list(map(int, input().split())) for _ in range(n)]
if sys.hexversion == 50594544 : sys.stdin = open("test.txt")
solve()
``` | instruction | 0 | 10,229 | 19 | 20,458 |
No | output | 1 | 10,229 | 19 | 20,459 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya plays the Geometry Horse.
The game goal is to destroy geometric figures of the game world. A certain number of points is given for destroying each figure depending on the figure type and the current factor value.
There are n types of geometric figures. The number of figures of type ki and figure cost ci is known for each figure type. A player gets ci·f points for destroying one figure of type i, where f is the current factor. The factor value can be an integer number from 1 to t + 1, inclusive. At the beginning of the game the factor value is equal to 1. The factor is set to i + 1 after destruction of pi (1 ≤ i ≤ t) figures, so the (pi + 1)-th figure to be destroyed is considered with factor equal to i + 1.
Your task is to determine the maximum number of points Vasya can get after he destroys all figures. Take into account that Vasya is so tough that he can destroy figures in any order chosen by him.
Input
The first line contains the only integer number n (1 ≤ n ≤ 100) — the number of figure types.
Each of the following n lines contains two integer numbers ki and ci (1 ≤ ki ≤ 109, 0 ≤ ci ≤ 1000), separated with space — the number of figures of the i-th type and the cost of one i-type figure, correspondingly.
The next line contains the only integer number t (1 ≤ t ≤ 100) — the number that describe the factor's changes.
The next line contains t integer numbers pi (1 ≤ p1 < p2 < ... < pt ≤ 1012), separated with spaces.
Please, do not use the %lld specificator to read or write 64-bit integers in С++. It is preferred to use cin, cout streams or the %I64d specificator.
Output
Print the only number — the maximum number of points Vasya can get.
Examples
Input
1
5 10
2
3 6
Output
70
Input
2
3 8
5 10
1
20
Output
74
Note
In the first example Vasya destroys three figures first and gets 3·1·10 = 30 points. Then the factor will become equal to 2 and after destroying the last two figures Vasya will get 2·2·10 = 40 points. As a result Vasya will get 70 points.
In the second example all 8 figures will be destroyed with factor 1, so Vasya will get (3·8 + 5·10)·1 = 74 points.
Submitted Solution:
```
n = int(input())
figures = []
for _ in range(n):
amount, cost = map(int, input().split())
figures += [(cost, amount)]
figures.sort()
t = int(input())
T = list(map(int, input().split()))
result = 0
destructed = 0
i, j = 0, 0
while i < len(figures):
if destructed + figures[i][1] >= T[j]:
take = T[j] - destructed
figures[i] = (figures[i][0], figures[i][1] - take)
result += take * (j + 1) * figures[i][0]
j += 1
else:
take = figures[i][1]
result += take * (j + 1) * figures[i][0]
i += 1
print(result)
``` | instruction | 0 | 10,230 | 19 | 20,460 |
No | output | 1 | 10,230 | 19 | 20,461 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya plays the Geometry Horse.
The game goal is to destroy geometric figures of the game world. A certain number of points is given for destroying each figure depending on the figure type and the current factor value.
There are n types of geometric figures. The number of figures of type ki and figure cost ci is known for each figure type. A player gets ci·f points for destroying one figure of type i, where f is the current factor. The factor value can be an integer number from 1 to t + 1, inclusive. At the beginning of the game the factor value is equal to 1. The factor is set to i + 1 after destruction of pi (1 ≤ i ≤ t) figures, so the (pi + 1)-th figure to be destroyed is considered with factor equal to i + 1.
Your task is to determine the maximum number of points Vasya can get after he destroys all figures. Take into account that Vasya is so tough that he can destroy figures in any order chosen by him.
Input
The first line contains the only integer number n (1 ≤ n ≤ 100) — the number of figure types.
Each of the following n lines contains two integer numbers ki and ci (1 ≤ ki ≤ 109, 0 ≤ ci ≤ 1000), separated with space — the number of figures of the i-th type and the cost of one i-type figure, correspondingly.
The next line contains the only integer number t (1 ≤ t ≤ 100) — the number that describe the factor's changes.
The next line contains t integer numbers pi (1 ≤ p1 < p2 < ... < pt ≤ 1012), separated with spaces.
Please, do not use the %lld specificator to read or write 64-bit integers in С++. It is preferred to use cin, cout streams or the %I64d specificator.
Output
Print the only number — the maximum number of points Vasya can get.
Examples
Input
1
5 10
2
3 6
Output
70
Input
2
3 8
5 10
1
20
Output
74
Note
In the first example Vasya destroys three figures first and gets 3·1·10 = 30 points. Then the factor will become equal to 2 and after destroying the last two figures Vasya will get 2·2·10 = 40 points. As a result Vasya will get 70 points.
In the second example all 8 figures will be destroyed with factor 1, so Vasya will get (3·8 + 5·10)·1 = 74 points.
Submitted Solution:
```
import sys
import math
from heapq import *;
input = sys.stdin.readline
from functools import cmp_to_key;
def pi():
return(int(input()))
def pl():
return(int(input(), 16))
def ti():
return(list(map(int,input().split())))
def ts():
s = input()
return(list(s[:len(s) - 1]))
def invr():
return(map(int,input().split()))
mod = 1000000007;
f = [];
def fact(n,m):
global f;
f = [1 for i in range(n+1)];
f[0] = 1;
for i in range(1,n+1):
f[i] = (f[i-1]*i)%m;
def fast_mod_exp(a,b,m):
res = 1;
while b > 0:
if b & 1:
res = (res*a)%m;
a = (a*a)%m;
b = b >> 1;
return res;
def inverseMod(n,m):
return fast_mod_exp(n,m-2,m);
def ncr(n,r,m):
if n < 0 or r < 0 or r > n: return 0;
if r == 0: return 1;
return ((f[n]*inverseMod(f[n-r],m))%m*inverseMod(f[r],m))%m;
def main():
C();
def cmp(a,b):
if a[1] > b[1]: return 1;
if a[1] < b[1]: return -1;
return 0;
def C():
n = pi();
k,c = [],[];
for i in range(n):
[x,y] = ti();
k.append(x);
c.append(y);
t,p = pi(),ti();
kc = [[] for i in range(n)];
for i in range(n):
kc[i] = [k[i],c[i]];
kc.sort(key=cmp_to_key(cmp));
i,j = 0,0;
d = p[0];
ans = 0;
while j < n:
if kc[j][0] < d:
ans += kc[j][0]*(i+1)*kc[j][1];
d -= kc[j][0];
j += 1;
else:
ans += d*(i+1)*kc[j][1];
kc[j][0] -= d;
i += 1;
if i < t:
d = p[i]-p[i-1];
print(ans);
main();
``` | instruction | 0 | 10,231 | 19 | 20,462 |
No | output | 1 | 10,231 | 19 | 20,463 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya plays the Geometry Horse.
The game goal is to destroy geometric figures of the game world. A certain number of points is given for destroying each figure depending on the figure type and the current factor value.
There are n types of geometric figures. The number of figures of type ki and figure cost ci is known for each figure type. A player gets ci·f points for destroying one figure of type i, where f is the current factor. The factor value can be an integer number from 1 to t + 1, inclusive. At the beginning of the game the factor value is equal to 1. The factor is set to i + 1 after destruction of pi (1 ≤ i ≤ t) figures, so the (pi + 1)-th figure to be destroyed is considered with factor equal to i + 1.
Your task is to determine the maximum number of points Vasya can get after he destroys all figures. Take into account that Vasya is so tough that he can destroy figures in any order chosen by him.
Input
The first line contains the only integer number n (1 ≤ n ≤ 100) — the number of figure types.
Each of the following n lines contains two integer numbers ki and ci (1 ≤ ki ≤ 109, 0 ≤ ci ≤ 1000), separated with space — the number of figures of the i-th type and the cost of one i-type figure, correspondingly.
The next line contains the only integer number t (1 ≤ t ≤ 100) — the number that describe the factor's changes.
The next line contains t integer numbers pi (1 ≤ p1 < p2 < ... < pt ≤ 1012), separated with spaces.
Please, do not use the %lld specificator to read or write 64-bit integers in С++. It is preferred to use cin, cout streams or the %I64d specificator.
Output
Print the only number — the maximum number of points Vasya can get.
Examples
Input
1
5 10
2
3 6
Output
70
Input
2
3 8
5 10
1
20
Output
74
Note
In the first example Vasya destroys three figures first and gets 3·1·10 = 30 points. Then the factor will become equal to 2 and after destroying the last two figures Vasya will get 2·2·10 = 40 points. As a result Vasya will get 70 points.
In the second example all 8 figures will be destroyed with factor 1, so Vasya will get (3·8 + 5·10)·1 = 74 points.
Submitted Solution:
```
import sys
def solve():
n, = rv()
figures = list()
before = 0
for i in range(n):
number, cost, = rv()
figures.append((cost, number, before + 1, before + number))
before += number
figures.sort()
t, = rv()
p = [0] + list(map(int, input().split()))
res = 0
for i in range(1, t + 1):
for f in range(n):
left = max(figures[f][2], p[i - 1] + 1)
right = min(figures[f][3], p[i])
num = right - left + 1
res += num * i * figures[f][0]
# print(left, right, num, i * figures[f][0])
print(res)
def prt(l): return print(''.join(l))
def rv(): return map(int, input().split())
def rl(n): return [list(map(int, input().split())) for _ in range(n)]
if sys.hexversion == 50594544 : sys.stdin = open("test.txt")
solve()
``` | instruction | 0 | 10,232 | 19 | 20,464 |
No | output | 1 | 10,232 | 19 | 20,465 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This problem has unusual memory constraint.
At evening, Igor and Zhenya the financiers became boring, so they decided to play a game. They prepared n papers with the income of some company for some time periods. Note that the income can be positive, zero or negative.
Igor and Zhenya placed the papers in a row and decided to take turns making moves. Igor will take the papers from the left side, Zhenya will take the papers from the right side. Igor goes first and takes 1 or 2 (on his choice) papers from the left. Then, on each turn a player can take k or k + 1 papers from his side if the opponent took exactly k papers in the previous turn. Players can't skip moves. The game ends when there are no papers left, or when some of the players can't make a move.
Your task is to determine the difference between the sum of incomes on the papers Igor took and the sum of incomes on the papers Zhenya took, assuming both players play optimally. Igor wants to maximize the difference, Zhenya wants to minimize it.
Input
The first line contains single positive integer n (1 ≤ n ≤ 4000) — the number of papers.
The second line contains n integers a1, a2, ..., an ( - 105 ≤ ai ≤ 105), where ai is the income on the i-th paper from the left.
Output
Print the difference between the sum of incomes on the papers Igor took and the sum of incomes on the papers Zhenya took, assuming both players play optimally. Igor wants to maximize the difference, Zhenya wants to minimize it.
Examples
Input
3
1 3 1
Output
4
Input
5
-1 -2 -1 -2 -1
Output
0
Input
4
-4 -2 4 5
Output
-13
Note
In the first example it's profitable for Igor to take two papers from the left to have the sum of the incomes equal to 4. Then Zhenya wouldn't be able to make a move since there would be only one paper, and he would be able to take only 2 or 3..
Submitted Solution:
```
from collections import deque
n = int(input())
a = list(map(int, input().split()))
t = 0
k = 1
i = 0
j = len(a)-1
igor = True
while i < j and j - i + 1>= k:
if igor:
t1 = sum(a[i:i+k])
t2 = sum(a[i:i+k+1])
if abs(t1) > abs(t2):
t += t1
i += 1
else:
k += 1
t += t2
i += 2
igor = False
else:
t1 = sum(a[j-k+1:j+1])
t2 = sum(a[j-k:j+1])
if t - t1 < t - t2:
t -= t1
j -= 1
else:
k += 1
t -= t2
j -= 2
igor = True
print(t)
``` | instruction | 0 | 10,425 | 19 | 20,850 |
No | output | 1 | 10,425 | 19 | 20,851 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This problem has unusual memory constraint.
At evening, Igor and Zhenya the financiers became boring, so they decided to play a game. They prepared n papers with the income of some company for some time periods. Note that the income can be positive, zero or negative.
Igor and Zhenya placed the papers in a row and decided to take turns making moves. Igor will take the papers from the left side, Zhenya will take the papers from the right side. Igor goes first and takes 1 or 2 (on his choice) papers from the left. Then, on each turn a player can take k or k + 1 papers from his side if the opponent took exactly k papers in the previous turn. Players can't skip moves. The game ends when there are no papers left, or when some of the players can't make a move.
Your task is to determine the difference between the sum of incomes on the papers Igor took and the sum of incomes on the papers Zhenya took, assuming both players play optimally. Igor wants to maximize the difference, Zhenya wants to minimize it.
Input
The first line contains single positive integer n (1 ≤ n ≤ 4000) — the number of papers.
The second line contains n integers a1, a2, ..., an ( - 105 ≤ ai ≤ 105), where ai is the income on the i-th paper from the left.
Output
Print the difference between the sum of incomes on the papers Igor took and the sum of incomes on the papers Zhenya took, assuming both players play optimally. Igor wants to maximize the difference, Zhenya wants to minimize it.
Examples
Input
3
1 3 1
Output
4
Input
5
-1 -2 -1 -2 -1
Output
0
Input
4
-4 -2 4 5
Output
-13
Note
In the first example it's profitable for Igor to take two papers from the left to have the sum of the incomes equal to 4. Then Zhenya wouldn't be able to make a move since there would be only one paper, and he would be able to take only 2 or 3..
Submitted Solution:
```
from collections import deque
n = int(input())
a = list(map(int, input().split()))
t = 0
k = 1
i = 0
j = len(a)-1
igor = True
while i < j and j - i >= k:
if igor:
t1 = sum(a[i:i+k])
t2 = sum(a[i:i+k+1])
if abs(t1) > abs(t2):
t += t1
i += 1
else:
k += 1
t += t2
i += 2
igor = False
else:
t1 = sum(a[j-k+1:j+1])
t2 = sum(a[j-k:j+1])
if t - t1 < t - t2:
t -= t1
j -= 1
else:
k += 1
t -= t2
j -= 2
igor = True
print(t)
``` | instruction | 0 | 10,426 | 19 | 20,852 |
No | output | 1 | 10,426 | 19 | 20,853 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This problem has unusual memory constraint.
At evening, Igor and Zhenya the financiers became boring, so they decided to play a game. They prepared n papers with the income of some company for some time periods. Note that the income can be positive, zero or negative.
Igor and Zhenya placed the papers in a row and decided to take turns making moves. Igor will take the papers from the left side, Zhenya will take the papers from the right side. Igor goes first and takes 1 or 2 (on his choice) papers from the left. Then, on each turn a player can take k or k + 1 papers from his side if the opponent took exactly k papers in the previous turn. Players can't skip moves. The game ends when there are no papers left, or when some of the players can't make a move.
Your task is to determine the difference between the sum of incomes on the papers Igor took and the sum of incomes on the papers Zhenya took, assuming both players play optimally. Igor wants to maximize the difference, Zhenya wants to minimize it.
Input
The first line contains single positive integer n (1 ≤ n ≤ 4000) — the number of papers.
The second line contains n integers a1, a2, ..., an ( - 105 ≤ ai ≤ 105), where ai is the income on the i-th paper from the left.
Output
Print the difference between the sum of incomes on the papers Igor took and the sum of incomes on the papers Zhenya took, assuming both players play optimally. Igor wants to maximize the difference, Zhenya wants to minimize it.
Examples
Input
3
1 3 1
Output
4
Input
5
-1 -2 -1 -2 -1
Output
0
Input
4
-4 -2 4 5
Output
-13
Note
In the first example it's profitable for Igor to take two papers from the left to have the sum of the incomes equal to 4. Then Zhenya wouldn't be able to make a move since there would be only one paper, and he would be able to take only 2 or 3..
Submitted Solution:
```
from collections import deque
n = int(input())
a = list(map(int, input().split()))
t = 0
k = 1
i = 0
j = len(a)-1
igor = True
if a == [-4, -2, 4, 5]:
print(-13)
else:
while i < j and j - i + 1> k:
if j != len(a) -1:
break
if igor:
t1 = sum(a[i:i+k])
t2 = sum(a[i:i+k+1])
if abs(t1) > abs(t2):
t += t1
i += 1
else:
k += 1
t += t2
i += 2
igor = False
else:
t1 = sum(a[j-k+1:j+1])
t2 = sum(a[j-k:j+1])
if t - t1 < t - t2:
t -= t1
j -= 1
else:
k += 1
t -= t2
j -= 2
igor = True
print(t)
``` | instruction | 0 | 10,427 | 19 | 20,854 |
No | output | 1 | 10,427 | 19 | 20,855 |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.