message stringlengths 2 67k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 463 109k | cluster float64 19 19 | __index_level_0__ int64 926 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are two persons, numbered 0 and 1, and a variable x whose initial value is 0. The two persons now play a game. The game is played in N rounds. The following should be done in the i-th round (1 \leq i \leq N):
* Person S_i does one of the following:
* Replace x with x \oplus A_i, where \oplus represents bitwise XOR.
* Do nothing.
Person 0 aims to have x=0 at the end of the game, while Person 1 aims to have x \neq 0 at the end of the game.
Determine whether x becomes 0 at the end of the game when the two persons play optimally.
Solve T test cases for each input file.
Constraints
* 1 \leq T \leq 100
* 1 \leq N \leq 200
* 1 \leq A_i \leq 10^{18}
* S is a string of length N consisting of `0` and `1`.
* All numbers in input are integers.
Input
Input is given from Standard Input in the following format. The first line is as follows:
T
Then, T test cases follow. Each test case is given in the following format:
N
A_1 A_2 \cdots A_N
S
Output
For each test case, print a line containing `0` if x becomes 0 at the end of the game, and `1` otherwise.
Example
Input
3
2
1 2
10
2
1 1
10
6
2 3 4 5 6 7
111000
Output
1
0
0
Submitted Solution:
```
T = int(input())
ans = []
for _ in range(T):
N = int(input())
A = [int(_) for _ in input().split()]
S = input()
dp = set([0])
for a, s in zip(A[::-1], S[::-1]):
for b in dp:
a = min(a, a ^ b)
if s == '1':
if a:
dp = set()
break
else:
dp2 = set([a])
for b in dp:
dp2.add(min(b, a ^ b))
dp = dp2
ans += [0 if 0 in dp else 1]
print(*ans, sep='\n')
``` | instruction | 0 | 27,149 | 19 | 54,298 |
Yes | output | 1 | 27,149 | 19 | 54,299 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are two persons, numbered 0 and 1, and a variable x whose initial value is 0. The two persons now play a game. The game is played in N rounds. The following should be done in the i-th round (1 \leq i \leq N):
* Person S_i does one of the following:
* Replace x with x \oplus A_i, where \oplus represents bitwise XOR.
* Do nothing.
Person 0 aims to have x=0 at the end of the game, while Person 1 aims to have x \neq 0 at the end of the game.
Determine whether x becomes 0 at the end of the game when the two persons play optimally.
Solve T test cases for each input file.
Constraints
* 1 \leq T \leq 100
* 1 \leq N \leq 200
* 1 \leq A_i \leq 10^{18}
* S is a string of length N consisting of `0` and `1`.
* All numbers in input are integers.
Input
Input is given from Standard Input in the following format. The first line is as follows:
T
Then, T test cases follow. Each test case is given in the following format:
N
A_1 A_2 \cdots A_N
S
Output
For each test case, print a line containing `0` if x becomes 0 at the end of the game, and `1` otherwise.
Example
Input
3
2
1 2
10
2
1 1
10
6
2 3 4 5 6 7
111000
Output
1
0
0
Submitted Solution:
```
T = int(input())
for t in range(T):
x = 0
N = int(input())
A = list(map(int, input().split()))
S = list(input())
for i in range(N):
# print(S[i], A[i], x)
if S[i] == '0':
if x == 0:
continue
else:
x = x ^ A[i]
else:
if x != 0:
continue
else:
x = x ^ A[i]
# print(x)
if x == 0:
print(0)
else:
print(1)
``` | instruction | 0 | 27,150 | 19 | 54,300 |
No | output | 1 | 27,150 | 19 | 54,301 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are two persons, numbered 0 and 1, and a variable x whose initial value is 0. The two persons now play a game. The game is played in N rounds. The following should be done in the i-th round (1 \leq i \leq N):
* Person S_i does one of the following:
* Replace x with x \oplus A_i, where \oplus represents bitwise XOR.
* Do nothing.
Person 0 aims to have x=0 at the end of the game, while Person 1 aims to have x \neq 0 at the end of the game.
Determine whether x becomes 0 at the end of the game when the two persons play optimally.
Solve T test cases for each input file.
Constraints
* 1 \leq T \leq 100
* 1 \leq N \leq 200
* 1 \leq A_i \leq 10^{18}
* S is a string of length N consisting of `0` and `1`.
* All numbers in input are integers.
Input
Input is given from Standard Input in the following format. The first line is as follows:
T
Then, T test cases follow. Each test case is given in the following format:
N
A_1 A_2 \cdots A_N
S
Output
For each test case, print a line containing `0` if x becomes 0 at the end of the game, and `1` otherwise.
Example
Input
3
2
1 2
10
2
1 1
10
6
2 3 4 5 6 7
111000
Output
1
0
0
Submitted Solution:
```
t = int(input())
cmpx = []
for h in range(t):
n = int(input())
a = list(map(int,input().split()))
s = input()
x = []
y = []
m = len(str(bin(max(a))))
for j in range(n):
if(s[j] == '0'):
x.append(a[j])
else:
y.append(a[j])
t1 = [0]*m
l1 = [0]*m
for i in range(len(x)):
a1 = str(bin(x[i])[2:])
for j in range(1,len(a1)+1):
if(a1[-j] == '1'):
t1[j-1] ^= x[i]
if(t1[j-1]&t1[j-1]-1 == 0):
l1[len(bin(t1[j-1]))-3] = 1
q1 = 0
z1 = []
for i in range(len(l1)):
if(l1[i] == 0):
q1 += 2**i
for i in range(len(t1)):
c = t1[i]&q1
if(c&c-1):
z1.append(c)
t2 = [0]*m
l2 = [0]*m
for i in range(len(y)):
a2 = str(bin(y[i])[2:])
for j in range(1,len(a2)+1):
if(a2[-j] == '1'):
t2[j-1] ^= y[i]
if(t2[j-1]&t2[j-1]-1 == 0):
l2[len(bin(t2[j-1]))-3] = 1
q2 = 0
z2 = []
for i in range(len(l2)):
if(l2[i] == 0):
q2 += 2**i
for i in range(len(t2)):
c = t2[i]&q2
if(c&c-1):
z2.append(c)
cmp = 0
if(q1 <= q2):
for j in range(m):
if(l1[j] > l2[j]):
cmp = 1
break
else:
cmp = 1
print(cmp)
``` | instruction | 0 | 27,151 | 19 | 54,302 |
No | output | 1 | 27,151 | 19 | 54,303 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are two persons, numbered 0 and 1, and a variable x whose initial value is 0. The two persons now play a game. The game is played in N rounds. The following should be done in the i-th round (1 \leq i \leq N):
* Person S_i does one of the following:
* Replace x with x \oplus A_i, where \oplus represents bitwise XOR.
* Do nothing.
Person 0 aims to have x=0 at the end of the game, while Person 1 aims to have x \neq 0 at the end of the game.
Determine whether x becomes 0 at the end of the game when the two persons play optimally.
Solve T test cases for each input file.
Constraints
* 1 \leq T \leq 100
* 1 \leq N \leq 200
* 1 \leq A_i \leq 10^{18}
* S is a string of length N consisting of `0` and `1`.
* All numbers in input are integers.
Input
Input is given from Standard Input in the following format. The first line is as follows:
T
Then, T test cases follow. Each test case is given in the following format:
N
A_1 A_2 \cdots A_N
S
Output
For each test case, print a line containing `0` if x becomes 0 at the end of the game, and `1` otherwise.
Example
Input
3
2
1 2
10
2
1 1
10
6
2 3 4 5 6 7
111000
Output
1
0
0
Submitted Solution:
```
t = int(input())
for _ in range(t):
x = 0
n = int(input())
a = list(map(int,input().split()))
s = input()
for i in range(n):
mode = int(s[i])
target = a[i]
if mode == 0:
if x == 1 and target == 1:
x = 0
else:
if x == 0 and target == 1:
x = 1
print(x)
``` | instruction | 0 | 27,152 | 19 | 54,304 |
No | output | 1 | 27,152 | 19 | 54,305 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are two persons, numbered 0 and 1, and a variable x whose initial value is 0. The two persons now play a game. The game is played in N rounds. The following should be done in the i-th round (1 \leq i \leq N):
* Person S_i does one of the following:
* Replace x with x \oplus A_i, where \oplus represents bitwise XOR.
* Do nothing.
Person 0 aims to have x=0 at the end of the game, while Person 1 aims to have x \neq 0 at the end of the game.
Determine whether x becomes 0 at the end of the game when the two persons play optimally.
Solve T test cases for each input file.
Constraints
* 1 \leq T \leq 100
* 1 \leq N \leq 200
* 1 \leq A_i \leq 10^{18}
* S is a string of length N consisting of `0` and `1`.
* All numbers in input are integers.
Input
Input is given from Standard Input in the following format. The first line is as follows:
T
Then, T test cases follow. Each test case is given in the following format:
N
A_1 A_2 \cdots A_N
S
Output
For each test case, print a line containing `0` if x becomes 0 at the end of the game, and `1` otherwise.
Example
Input
3
2
1 2
10
2
1 1
10
6
2 3 4 5 6 7
111000
Output
1
0
0
Submitted Solution:
```
import bisect
import collections
import copy
import functools
import heapq
import math
import sys
from collections import deque
from collections import defaultdict
input = sys.stdin.readline
MOD = 10**9+7
def ok(now,a,player):
if player == "0":
if now == 0:
return True
else:
if a%2 == 1:
return True
else:
return False
else:
if now == 1:
return True
else:
if a%2 == 1:
return True
else:
return False
T = int(input())
for i in range(T):
N = int(input())
A = list(map(int,(input().split())))
S = list(input().rstrip())
n = 0
for i in range(N):
if ok(n,A[i],S[i]):
n = int(S[i])
else:
n = (int(S[i])+1)%2
if n == 0:
print(0)
else:
print(1)
``` | instruction | 0 | 27,153 | 19 | 54,306 |
No | output | 1 | 27,153 | 19 | 54,307 |
Provide a correct Python 3 solution for this coding contest problem.
We have N dice arranged in a line from left to right. The i-th die from the left shows p_i numbers from 1 to p_i with equal probability when thrown.
We will choose K adjacent dice, throw each of them independently, and compute the sum of the numbers shown. Find the maximum possible value of the expected value of this sum.
Constraints
* 1 β€ K β€ N β€ 200000
* 1 β€ p_i β€ 1000
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N K
p_1 ... p_N
Output
Print the maximum possible value of the expected value of the sum of the numbers shown.
Your output will be considered correct when its absolute or relative error from our answer is at most 10^{-6}.
Examples
Input
5 3
1 2 2 4 5
Output
7.000000000000
Input
4 1
6 6 6 6
Output
3.500000000000
Input
10 4
17 13 13 12 15 20 10 13 17 11
Output
32.000000000000 | instruction | 0 | 27,158 | 19 | 54,316 |
"Correct Solution:
```
from itertools import accumulate
R = lambda: map(int, input().split())
n, k = R()
a = [0] + list(accumulate(R()))
print((max(y - x for x, y in zip(a, a[k:])) + k) / 2)
``` | output | 1 | 27,158 | 19 | 54,317 |
Provide a correct Python 3 solution for this coding contest problem.
We have N dice arranged in a line from left to right. The i-th die from the left shows p_i numbers from 1 to p_i with equal probability when thrown.
We will choose K adjacent dice, throw each of them independently, and compute the sum of the numbers shown. Find the maximum possible value of the expected value of this sum.
Constraints
* 1 β€ K β€ N β€ 200000
* 1 β€ p_i β€ 1000
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N K
p_1 ... p_N
Output
Print the maximum possible value of the expected value of the sum of the numbers shown.
Your output will be considered correct when its absolute or relative error from our answer is at most 10^{-6}.
Examples
Input
5 3
1 2 2 4 5
Output
7.000000000000
Input
4 1
6 6 6 6
Output
3.500000000000
Input
10 4
17 13 13 12 15 20 10 13 17 11
Output
32.000000000000 | instruction | 0 | 27,161 | 19 | 54,322 |
"Correct Solution:
```
from itertools import accumulate
N, K = map(int, input().split())
P = list(map(int, input().split()))
acc = [0] + list(accumulate(P))
print((max(b - a for a, b in zip(acc, acc[K:])) + K) / 2)
``` | output | 1 | 27,161 | 19 | 54,323 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N dice arranged in a line from left to right. The i-th die from the left shows p_i numbers from 1 to p_i with equal probability when thrown.
We will choose K adjacent dice, throw each of them independently, and compute the sum of the numbers shown. Find the maximum possible value of the expected value of this sum.
Constraints
* 1 β€ K β€ N β€ 200000
* 1 β€ p_i β€ 1000
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N K
p_1 ... p_N
Output
Print the maximum possible value of the expected value of the sum of the numbers shown.
Your output will be considered correct when its absolute or relative error from our answer is at most 10^{-6}.
Examples
Input
5 3
1 2 2 4 5
Output
7.000000000000
Input
4 1
6 6 6 6
Output
3.500000000000
Input
10 4
17 13 13 12 15 20 10 13 17 11
Output
32.000000000000
Submitted Solution:
```
N,K=map(int,input().split())
P=list(map(int,input().split()))
from itertools import accumulate
acc=[0]+list(accumulate(P))
print((max(b-a for a,b in zip(acc,acc[K:]))+K)/2)
``` | instruction | 0 | 27,162 | 19 | 54,324 |
Yes | output | 1 | 27,162 | 19 | 54,325 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N dice arranged in a line from left to right. The i-th die from the left shows p_i numbers from 1 to p_i with equal probability when thrown.
We will choose K adjacent dice, throw each of them independently, and compute the sum of the numbers shown. Find the maximum possible value of the expected value of this sum.
Constraints
* 1 β€ K β€ N β€ 200000
* 1 β€ p_i β€ 1000
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N K
p_1 ... p_N
Output
Print the maximum possible value of the expected value of the sum of the numbers shown.
Your output will be considered correct when its absolute or relative error from our answer is at most 10^{-6}.
Examples
Input
5 3
1 2 2 4 5
Output
7.000000000000
Input
4 1
6 6 6 6
Output
3.500000000000
Input
10 4
17 13 13 12 15 20 10 13 17 11
Output
32.000000000000
Submitted Solution:
```
from itertools import accumulate
N, K = map(int, input().split())
ans = [0] + list(accumulate(map(lambda x: (int(x)+1)/2., input().split())))
print(max([y-x for x,y in zip(ans, ans[K:])]))
``` | instruction | 0 | 27,164 | 19 | 54,328 |
Yes | output | 1 | 27,164 | 19 | 54,329 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N dice arranged in a line from left to right. The i-th die from the left shows p_i numbers from 1 to p_i with equal probability when thrown.
We will choose K adjacent dice, throw each of them independently, and compute the sum of the numbers shown. Find the maximum possible value of the expected value of this sum.
Constraints
* 1 β€ K β€ N β€ 200000
* 1 β€ p_i β€ 1000
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N K
p_1 ... p_N
Output
Print the maximum possible value of the expected value of the sum of the numbers shown.
Your output will be considered correct when its absolute or relative error from our answer is at most 10^{-6}.
Examples
Input
5 3
1 2 2 4 5
Output
7.000000000000
Input
4 1
6 6 6 6
Output
3.500000000000
Input
10 4
17 13 13 12 15 20 10 13 17 11
Output
32.000000000000
Submitted Solution:
```
n,k =map(int,input().split())
p = list(map(int,input().split()))
kitai = []
for i in range(1,n+1):
sum_k = 0
for j in range(1,p[i-1]+1):
sum_k += j *(1/p[i-1])
kitai.append(sum_k)
ans = []
sum_ans = 0
for i in range(k):
sum_ans += kitai[i]
ans.append(sum_ans)
j = 0
cnt = 0
for i in range(k,len(kitai)):
sum_ans = ans[cnt]
sum_ans -=kitai[j]
sum_ans += kitai[k]
cnt +=1
j +=1
ans.append(sum_ans)
print(max(ans))
``` | instruction | 0 | 27,167 | 19 | 54,334 |
No | output | 1 | 27,167 | 19 | 54,335 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N dice arranged in a line from left to right. The i-th die from the left shows p_i numbers from 1 to p_i with equal probability when thrown.
We will choose K adjacent dice, throw each of them independently, and compute the sum of the numbers shown. Find the maximum possible value of the expected value of this sum.
Constraints
* 1 β€ K β€ N β€ 200000
* 1 β€ p_i β€ 1000
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N K
p_1 ... p_N
Output
Print the maximum possible value of the expected value of the sum of the numbers shown.
Your output will be considered correct when its absolute or relative error from our answer is at most 10^{-6}.
Examples
Input
5 3
1 2 2 4 5
Output
7.000000000000
Input
4 1
6 6 6 6
Output
3.500000000000
Input
10 4
17 13 13 12 15 20 10 13 17 11
Output
32.000000000000
Submitted Solution:
```
import numpy as np
N, K = [int(i) for i in input().split()]
array = [int(i) for i in input().split()]
ary = np.array([(1 + n) / 2 for n in array])
cumsum = ary.cumsum()
exv.append(cumsum[K-1])
for i in range(N - K):
exv.append([cumsum[i+K] - cumsum[i]])
print(max(exv)[0])
``` | instruction | 0 | 27,168 | 19 | 54,336 |
No | output | 1 | 27,168 | 19 | 54,337 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N dice arranged in a line from left to right. The i-th die from the left shows p_i numbers from 1 to p_i with equal probability when thrown.
We will choose K adjacent dice, throw each of them independently, and compute the sum of the numbers shown. Find the maximum possible value of the expected value of this sum.
Constraints
* 1 β€ K β€ N β€ 200000
* 1 β€ p_i β€ 1000
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N K
p_1 ... p_N
Output
Print the maximum possible value of the expected value of the sum of the numbers shown.
Your output will be considered correct when its absolute or relative error from our answer is at most 10^{-6}.
Examples
Input
5 3
1 2 2 4 5
Output
7.000000000000
Input
4 1
6 6 6 6
Output
3.500000000000
Input
10 4
17 13 13 12 15 20 10 13 17 11
Output
32.000000000000
Submitted Solution:
```
def h(j):
l = int(j)
return 0.5 * (l + 1)
n, k = map(int, input().split())
ls = list(map(h, input().split()))
s = [sum(ls[0:i]) for i in range(1,n+1)]
a = s[k] - s[0]
for i in range(0,n-k-1):
if s[i + k] - s[i] < s[i + k + 1] - s[i + 1]:
a = s[i + k + 1] - s[i + 1]
print(a)
``` | instruction | 0 | 27,169 | 19 | 54,338 |
No | output | 1 | 27,169 | 19 | 54,339 |
Provide a correct Python 3 solution for this coding contest problem.
I decided to play rock-paper-scissors with a group of five good friends. Rock-paper-scissors has three hands: goo, choki, and par. If the game between goo and choki is a match between goo and choki, goo is "winning" and choki is "losing". , Par and Goo have the rule that Par is "winning" and Goo is "losing". If everyone has the same hand, or if all of Goo, Choki, and Par come out, it will be "Aiko".
Create a program that inputs the hands of five rock-paper-scissors players and outputs the wins and losses of each person. Rock-paper-scissors hands are represented by the numbers 1 for goo, 2 for choki, and 3 for par. Win / loss is represented by a number of 1, "win" is 1, "los" is 2, and "Aiko" is 3, and they are output according to the input order.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
h1
h2
h3
h4
h5
The i-th line is given the i-th hand hi (1, 2 or 3).
The number of datasets does not exceed 200.
Output
Outputs the wins and losses of 5 players for each input dataset. Output the win / loss (1, 2 or 3) of the i-th person on the i-line.
Example
Input
1
2
3
2
1
1
2
2
2
1
0
Output
3
3
3
3
3
1
2
2
2
1 | instruction | 0 | 27,299 | 19 | 54,598 |
"Correct Solution:
```
while True:
L = []
H = []
for _ in range(5):
c = int(input())
if c == 0:
exit()
L.append(c)
h = set(L)
if len(h) in [1, 3]:
for _ in range(5):
H.append(3)
else:
r = list(set([1,2,3])-h)[0]
if r == 1:
w = 2
elif r == 2:
w = 3
else:
w = 1
for i in L:
if i == w:
H.append(1)
else:
H.append(2)
for i in H:
print(i)
``` | output | 1 | 27,299 | 19 | 54,599 |
Provide a correct Python 3 solution for this coding contest problem.
I decided to play rock-paper-scissors with a group of five good friends. Rock-paper-scissors has three hands: goo, choki, and par. If the game between goo and choki is a match between goo and choki, goo is "winning" and choki is "losing". , Par and Goo have the rule that Par is "winning" and Goo is "losing". If everyone has the same hand, or if all of Goo, Choki, and Par come out, it will be "Aiko".
Create a program that inputs the hands of five rock-paper-scissors players and outputs the wins and losses of each person. Rock-paper-scissors hands are represented by the numbers 1 for goo, 2 for choki, and 3 for par. Win / loss is represented by a number of 1, "win" is 1, "los" is 2, and "Aiko" is 3, and they are output according to the input order.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
h1
h2
h3
h4
h5
The i-th line is given the i-th hand hi (1, 2 or 3).
The number of datasets does not exceed 200.
Output
Outputs the wins and losses of 5 players for each input dataset. Output the win / loss (1, 2 or 3) of the i-th person on the i-line.
Example
Input
1
2
3
2
1
1
2
2
2
1
0
Output
3
3
3
3
3
1
2
2
2
1 | instruction | 0 | 27,300 | 19 | 54,600 |
"Correct Solution:
```
from sys import stdin
readline = stdin.readline
R, S, P = 1, 2, 3 # rock, scissors, paper
W, L, D = 1, 2, 3 # win, lose, draw
rps = {
(R, S, P): {R: D, S: D, P: D},
(R, S): {R: W, S: L},
(S, P): {S: W, P: L},
(R, P): {P: W, R: L},
(R,): {R: D},
(S,): {S: D},
(P,): {P: D}
}
while True:
hands = []
hands.append(int(readline()))
if hands[0] == 0:
break
for _ in range(4):
hands.append(int(readline()))
hands_set = tuple(sorted(set(hands)))
for h in hands:
print(rps[hands_set][h])
``` | output | 1 | 27,300 | 19 | 54,601 |
Provide a correct Python 3 solution for this coding contest problem.
I decided to play rock-paper-scissors with a group of five good friends. Rock-paper-scissors has three hands: goo, choki, and par. If the game between goo and choki is a match between goo and choki, goo is "winning" and choki is "losing". , Par and Goo have the rule that Par is "winning" and Goo is "losing". If everyone has the same hand, or if all of Goo, Choki, and Par come out, it will be "Aiko".
Create a program that inputs the hands of five rock-paper-scissors players and outputs the wins and losses of each person. Rock-paper-scissors hands are represented by the numbers 1 for goo, 2 for choki, and 3 for par. Win / loss is represented by a number of 1, "win" is 1, "los" is 2, and "Aiko" is 3, and they are output according to the input order.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
h1
h2
h3
h4
h5
The i-th line is given the i-th hand hi (1, 2 or 3).
The number of datasets does not exceed 200.
Output
Outputs the wins and losses of 5 players for each input dataset. Output the win / loss (1, 2 or 3) of the i-th person on the i-line.
Example
Input
1
2
3
2
1
1
2
2
2
1
0
Output
3
3
3
3
3
1
2
2
2
1 | instruction | 0 | 27,301 | 19 | 54,602 |
"Correct Solution:
```
d = {1:2, 2:3, 3:1}
while True:
h = int(input())
if h == 0:
break
h = [h] + [int(input()) for _ in range(4)]
if len(set(h)) == 3 or len(set(h)) == 1:
print(*[3]*5, sep='\n')
continue
for c in h:
print([2, 1][d[c] in h])
``` | output | 1 | 27,301 | 19 | 54,603 |
Provide a correct Python 3 solution for this coding contest problem.
I decided to play rock-paper-scissors with a group of five good friends. Rock-paper-scissors has three hands: goo, choki, and par. If the game between goo and choki is a match between goo and choki, goo is "winning" and choki is "losing". , Par and Goo have the rule that Par is "winning" and Goo is "losing". If everyone has the same hand, or if all of Goo, Choki, and Par come out, it will be "Aiko".
Create a program that inputs the hands of five rock-paper-scissors players and outputs the wins and losses of each person. Rock-paper-scissors hands are represented by the numbers 1 for goo, 2 for choki, and 3 for par. Win / loss is represented by a number of 1, "win" is 1, "los" is 2, and "Aiko" is 3, and they are output according to the input order.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
h1
h2
h3
h4
h5
The i-th line is given the i-th hand hi (1, 2 or 3).
The number of datasets does not exceed 200.
Output
Outputs the wins and losses of 5 players for each input dataset. Output the win / loss (1, 2 or 3) of the i-th person on the i-line.
Example
Input
1
2
3
2
1
1
2
2
2
1
0
Output
3
3
3
3
3
1
2
2
2
1 | instruction | 0 | 27,302 | 19 | 54,604 |
"Correct Solution:
```
# γ°γΌ:1,γγ§γ:2,γγΌ:3
# εγ‘:1,θ² γ:2,γγγ:3
datas = [0] * 5
while(1):
try:
lens = [0] * 3
status = [0] * 3
for i in range(0,5):
datas[i] = int(input())
lens[datas[i] - 1] += 1
# γγγ
if (lens[0] > 0 and lens[1] > 0 and lens[2] > 0) or (lens[0] == 5 or lens[1] == 5 or lens[2] == 5):
for i in range(0,5):
print(3)
else:
# γ°γΌ
if lens[0] > 0:
status[1] = 2
status[2] = 1
# γγ§γ
if lens[1] > 0:
status[0] = 1
status[2] = 2
# γγΌ
if lens[2] > 0:
status[0] = 2
status[1] = 1
for i in range(0,5):
print(status[datas[i] - 1])
except:
break
``` | output | 1 | 27,302 | 19 | 54,605 |
Provide a correct Python 3 solution for this coding contest problem.
I decided to play rock-paper-scissors with a group of five good friends. Rock-paper-scissors has three hands: goo, choki, and par. If the game between goo and choki is a match between goo and choki, goo is "winning" and choki is "losing". , Par and Goo have the rule that Par is "winning" and Goo is "losing". If everyone has the same hand, or if all of Goo, Choki, and Par come out, it will be "Aiko".
Create a program that inputs the hands of five rock-paper-scissors players and outputs the wins and losses of each person. Rock-paper-scissors hands are represented by the numbers 1 for goo, 2 for choki, and 3 for par. Win / loss is represented by a number of 1, "win" is 1, "los" is 2, and "Aiko" is 3, and they are output according to the input order.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
h1
h2
h3
h4
h5
The i-th line is given the i-th hand hi (1, 2 or 3).
The number of datasets does not exceed 200.
Output
Outputs the wins and losses of 5 players for each input dataset. Output the win / loss (1, 2 or 3) of the i-th person on the i-line.
Example
Input
1
2
3
2
1
1
2
2
2
1
0
Output
3
3
3
3
3
1
2
2
2
1 | instruction | 0 | 27,303 | 19 | 54,606 |
"Correct Solution:
```
a = []
while(True):
n = int(input())
if n == 0:
break
a.append(n)
if len(a) == 5:
uni = set(a)
if len(uni) == 2 and 1 in uni and 2 in uni:
for b in a: print(2 if b == 2 else 1)
elif len(uni) == 2 and 2 in uni and 3 in uni:
for b in a: print(2 if b == 3 else 1)
elif len(uni) == 2 and 3 in uni and 1 in uni:
for b in a: print(2 if b == 1 else 1)
else:
for _ in range(5): print(3)
a = []
``` | output | 1 | 27,303 | 19 | 54,607 |
Provide a correct Python 3 solution for this coding contest problem.
I decided to play rock-paper-scissors with a group of five good friends. Rock-paper-scissors has three hands: goo, choki, and par. If the game between goo and choki is a match between goo and choki, goo is "winning" and choki is "losing". , Par and Goo have the rule that Par is "winning" and Goo is "losing". If everyone has the same hand, or if all of Goo, Choki, and Par come out, it will be "Aiko".
Create a program that inputs the hands of five rock-paper-scissors players and outputs the wins and losses of each person. Rock-paper-scissors hands are represented by the numbers 1 for goo, 2 for choki, and 3 for par. Win / loss is represented by a number of 1, "win" is 1, "los" is 2, and "Aiko" is 3, and they are output according to the input order.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
h1
h2
h3
h4
h5
The i-th line is given the i-th hand hi (1, 2 or 3).
The number of datasets does not exceed 200.
Output
Outputs the wins and losses of 5 players for each input dataset. Output the win / loss (1, 2 or 3) of the i-th person on the i-line.
Example
Input
1
2
3
2
1
1
2
2
2
1
0
Output
3
3
3
3
3
1
2
2
2
1 | instruction | 0 | 27,304 | 19 | 54,608 |
"Correct Solution:
```
# Aizu Problem 0205: Rock Paper Scissor
#
import sys, math, os
# read input:
PYDEV = os.environ.get('PYDEV')
if PYDEV=="True":
sys.stdin = open("sample-input.txt", "rt")
while True:
try:
game = [int(input()) for _ in range(5)]
except EOFError:
break
if 1 in game and 2 in game:
w = 1
elif 1 in game:
w = 3
else:
w = 2
if len(set(game)) != 2:
for g in game:
print(3)
else:
for g in game:
print(1 if g == w else 2)
``` | output | 1 | 27,304 | 19 | 54,609 |
Provide a correct Python 3 solution for this coding contest problem.
I decided to play rock-paper-scissors with a group of five good friends. Rock-paper-scissors has three hands: goo, choki, and par. If the game between goo and choki is a match between goo and choki, goo is "winning" and choki is "losing". , Par and Goo have the rule that Par is "winning" and Goo is "losing". If everyone has the same hand, or if all of Goo, Choki, and Par come out, it will be "Aiko".
Create a program that inputs the hands of five rock-paper-scissors players and outputs the wins and losses of each person. Rock-paper-scissors hands are represented by the numbers 1 for goo, 2 for choki, and 3 for par. Win / loss is represented by a number of 1, "win" is 1, "los" is 2, and "Aiko" is 3, and they are output according to the input order.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
h1
h2
h3
h4
h5
The i-th line is given the i-th hand hi (1, 2 or 3).
The number of datasets does not exceed 200.
Output
Outputs the wins and losses of 5 players for each input dataset. Output the win / loss (1, 2 or 3) of the i-th person on the i-line.
Example
Input
1
2
3
2
1
1
2
2
2
1
0
Output
3
3
3
3
3
1
2
2
2
1 | instruction | 0 | 27,305 | 19 | 54,610 |
"Correct Solution:
```
while True:
try:
a = [int(input()) for i in range(5)]
except:
break
if (1 in a and 2 in a and 3 in a) or a.count(a[0]) == 5:
for i in range(5):
print(3)
elif not 3 in a:
for b in a:
if b == 1:
print(1)
else:
print(2)
elif not 2 in a:
for b in a:
if b == 1:
print(2)
else:
print(1)
else:
for b in a:
if b == 2:
print(1)
else:
print(2)
``` | output | 1 | 27,305 | 19 | 54,611 |
Provide a correct Python 3 solution for this coding contest problem.
I decided to play rock-paper-scissors with a group of five good friends. Rock-paper-scissors has three hands: goo, choki, and par. If the game between goo and choki is a match between goo and choki, goo is "winning" and choki is "losing". , Par and Goo have the rule that Par is "winning" and Goo is "losing". If everyone has the same hand, or if all of Goo, Choki, and Par come out, it will be "Aiko".
Create a program that inputs the hands of five rock-paper-scissors players and outputs the wins and losses of each person. Rock-paper-scissors hands are represented by the numbers 1 for goo, 2 for choki, and 3 for par. Win / loss is represented by a number of 1, "win" is 1, "los" is 2, and "Aiko" is 3, and they are output according to the input order.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
h1
h2
h3
h4
h5
The i-th line is given the i-th hand hi (1, 2 or 3).
The number of datasets does not exceed 200.
Output
Outputs the wins and losses of 5 players for each input dataset. Output the win / loss (1, 2 or 3) of the i-th person on the i-line.
Example
Input
1
2
3
2
1
1
2
2
2
1
0
Output
3
3
3
3
3
1
2
2
2
1 | instruction | 0 | 27,306 | 19 | 54,612 |
"Correct Solution:
```
while True:
h1 = int(input())
if h1 == 0:
break
h = [h1] + [int(input()) for _ in range(4)]
if len(set(h)) == 1 or len(set(h)) == 3:
print(*[3]*5, sep="\n")
continue
for hi in h:
print([2, 1][(hi%3)+1 in h])
``` | output | 1 | 27,306 | 19 | 54,613 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
I decided to play rock-paper-scissors with a group of five good friends. Rock-paper-scissors has three hands: goo, choki, and par. If the game between goo and choki is a match between goo and choki, goo is "winning" and choki is "losing". , Par and Goo have the rule that Par is "winning" and Goo is "losing". If everyone has the same hand, or if all of Goo, Choki, and Par come out, it will be "Aiko".
Create a program that inputs the hands of five rock-paper-scissors players and outputs the wins and losses of each person. Rock-paper-scissors hands are represented by the numbers 1 for goo, 2 for choki, and 3 for par. Win / loss is represented by a number of 1, "win" is 1, "los" is 2, and "Aiko" is 3, and they are output according to the input order.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
h1
h2
h3
h4
h5
The i-th line is given the i-th hand hi (1, 2 or 3).
The number of datasets does not exceed 200.
Output
Outputs the wins and losses of 5 players for each input dataset. Output the win / loss (1, 2 or 3) of the i-th person on the i-line.
Example
Input
1
2
3
2
1
1
2
2
2
1
0
Output
3
3
3
3
3
1
2
2
2
1
Submitted Solution:
```
while True:
has=[False, False, False, False]
n=input()
if n=='0':
break
te=[]
te.append(n)
has[int(n)]=True
for adf in range(4):
n=input()
has[int(n)] = True
te.append(n)
if has[1] and has[2] and has[3]:
for qwer in range(5):
print(3)
elif te[1]==te[2] and te[2]==te[3] and te[3]==te[4] and te[0]==te[4]:
for asdd in range(5):
print(3)
elif not has[3]:
for g in range(5):
if te[g]=='1':
print('1')
else:
print('2')
elif not has[2]:
for g in range(5):
if te[g]=='3':
print('1')
else:
print('2')
else:
for g in range(5):
if te[g]=='2':
print('1')
else:
print('2')
``` | instruction | 0 | 27,307 | 19 | 54,614 |
Yes | output | 1 | 27,307 | 19 | 54,615 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
I decided to play rock-paper-scissors with a group of five good friends. Rock-paper-scissors has three hands: goo, choki, and par. If the game between goo and choki is a match between goo and choki, goo is "winning" and choki is "losing". , Par and Goo have the rule that Par is "winning" and Goo is "losing". If everyone has the same hand, or if all of Goo, Choki, and Par come out, it will be "Aiko".
Create a program that inputs the hands of five rock-paper-scissors players and outputs the wins and losses of each person. Rock-paper-scissors hands are represented by the numbers 1 for goo, 2 for choki, and 3 for par. Win / loss is represented by a number of 1, "win" is 1, "los" is 2, and "Aiko" is 3, and they are output according to the input order.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
h1
h2
h3
h4
h5
The i-th line is given the i-th hand hi (1, 2 or 3).
The number of datasets does not exceed 200.
Output
Outputs the wins and losses of 5 players for each input dataset. Output the win / loss (1, 2 or 3) of the i-th person on the i-line.
Example
Input
1
2
3
2
1
1
2
2
2
1
0
Output
3
3
3
3
3
1
2
2
2
1
Submitted Solution:
```
# -*- coding: utf-8 -*-
#import pdb; pdb.set_trace()
import sys
def solv(v):
w = set(v)
if len(w)==1 or len(w)==3:
d={1:3, 2:3, 3:3}
elif 1 in w and 2 in w:
d={1:1, 2:2}
elif 2 in w and 3 in w:
d={2:1, 3:2}
else:
d={3:1, 1:2}
return(list(map(lambda x:d[x], v) ))
def main():
if True:
fh = sys.stdin
else:
fh = open('vol2_0205.txt', 'r')
try:
while True:
te = []
for _ in range(5):
x=int(fh.readline().strip())
if x==0:
raise Exception
te.append(x)
b=(solv(te))
for i in b:
print(i)
except Exception:
1
fh.close()
if __name__ == '__main__':
main()
``` | instruction | 0 | 27,308 | 19 | 54,616 |
Yes | output | 1 | 27,308 | 19 | 54,617 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
I decided to play rock-paper-scissors with a group of five good friends. Rock-paper-scissors has three hands: goo, choki, and par. If the game between goo and choki is a match between goo and choki, goo is "winning" and choki is "losing". , Par and Goo have the rule that Par is "winning" and Goo is "losing". If everyone has the same hand, or if all of Goo, Choki, and Par come out, it will be "Aiko".
Create a program that inputs the hands of five rock-paper-scissors players and outputs the wins and losses of each person. Rock-paper-scissors hands are represented by the numbers 1 for goo, 2 for choki, and 3 for par. Win / loss is represented by a number of 1, "win" is 1, "los" is 2, and "Aiko" is 3, and they are output according to the input order.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
h1
h2
h3
h4
h5
The i-th line is given the i-th hand hi (1, 2 or 3).
The number of datasets does not exceed 200.
Output
Outputs the wins and losses of 5 players for each input dataset. Output the win / loss (1, 2 or 3) of the i-th person on the i-line.
Example
Input
1
2
3
2
1
1
2
2
2
1
0
Output
3
3
3
3
3
1
2
2
2
1
Submitted Solution:
```
# -*- coding: utf-8 -*-
"""
http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0205
"""
import sys
from sys import stdin
input = stdin.readline
def main(args):
while True:
hands = [0] * 5
hands[0] = int(input())
if hands[0] == 0:
break
hands[1] = int(input())
hands[2] = int(input())
hands[3] = int(input())
hands[4] = int(input())
# ?????????????????????????????Β±???????????????
if 1 in hands and 2 in hands and 3 in hands: # ??Β¨????????????????????Β΄???
for _ in range(5):
print(3)
elif hands.count(hands[0]) == 5: # ??Β¨????????????????????Β΄???
for _ in range(5):
print(3)
# ??????????????????????????Β±???????????????
else:
for h in hands:
if (h+1 in hands) or (h==3 and 1 in hands):
print(1)
else:
print(2)
if __name__ == '__main__':
main(sys.argv[1:])
``` | instruction | 0 | 27,309 | 19 | 54,618 |
Yes | output | 1 | 27,309 | 19 | 54,619 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
I decided to play rock-paper-scissors with a group of five good friends. Rock-paper-scissors has three hands: goo, choki, and par. If the game between goo and choki is a match between goo and choki, goo is "winning" and choki is "losing". , Par and Goo have the rule that Par is "winning" and Goo is "losing". If everyone has the same hand, or if all of Goo, Choki, and Par come out, it will be "Aiko".
Create a program that inputs the hands of five rock-paper-scissors players and outputs the wins and losses of each person. Rock-paper-scissors hands are represented by the numbers 1 for goo, 2 for choki, and 3 for par. Win / loss is represented by a number of 1, "win" is 1, "los" is 2, and "Aiko" is 3, and they are output according to the input order.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
h1
h2
h3
h4
h5
The i-th line is given the i-th hand hi (1, 2 or 3).
The number of datasets does not exceed 200.
Output
Outputs the wins and losses of 5 players for each input dataset. Output the win / loss (1, 2 or 3) of the i-th person on the i-line.
Example
Input
1
2
3
2
1
1
2
2
2
1
0
Output
3
3
3
3
3
1
2
2
2
1
Submitted Solution:
```
while 1:
hands = []
h = int(input())
if h == 0:
break
hands.append(h)
for _ in range(4):
h = int(input())
hands.append(h)
h_uni = list(set(hands))
if len(h_uni) != 2:
for _ in range(5):
print(3)
continue
h_uni.sort()
if h_uni[0] == 1 and h_uni[1] == 2:
for h in hands:
if h == 1:
print(1)
else:
print(2)
elif h_uni[0] == 1 and h_uni[1] == 3:
for h in hands:
if h == 1:
print(2)
else:
print(1)
else:
for h in hands:
if h == 2:
print(1)
else:
print(2)
``` | instruction | 0 | 27,310 | 19 | 54,620 |
Yes | output | 1 | 27,310 | 19 | 54,621 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
I decided to play rock-paper-scissors with a group of five good friends. Rock-paper-scissors has three hands: goo, choki, and par. If the game between goo and choki is a match between goo and choki, goo is "winning" and choki is "losing". , Par and Goo have the rule that Par is "winning" and Goo is "losing". If everyone has the same hand, or if all of Goo, Choki, and Par come out, it will be "Aiko".
Create a program that inputs the hands of five rock-paper-scissors players and outputs the wins and losses of each person. Rock-paper-scissors hands are represented by the numbers 1 for goo, 2 for choki, and 3 for par. Win / loss is represented by a number of 1, "win" is 1, "los" is 2, and "Aiko" is 3, and they are output according to the input order.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
h1
h2
h3
h4
h5
The i-th line is given the i-th hand hi (1, 2 or 3).
The number of datasets does not exceed 200.
Output
Outputs the wins and losses of 5 players for each input dataset. Output the win / loss (1, 2 or 3) of the i-th person on the i-line.
Example
Input
1
2
3
2
1
1
2
2
2
1
0
Output
3
3
3
3
3
1
2
2
2
1
Submitted Solution:
```
# -*- coding: utf-8 -*-
#import pdb; pdb.set_trace()
import sys
def solv(v):
w = set(v)
if len(w)==1 or len(w)==3:
d={1:2, 2:2, 3:2}
elif 1 in w and 2 in w:
d={1:1, 2:2}
elif 2 in w and 3 in w:
d={2:1, 3:2}
else:
d={3:1, 1:2}
return(list(map(lambda x:d[x], v) ))
def main():
if True:
fh = sys.stdin
else:
fh = open('vol2_0205.txt', 'r')
try:
while True:
te = []
for _ in range(5):
x=int(fh.readline().strip())
if x==0:
raise Exception
te.append(x)
b=(solv(te))
for i in b:
print(i)
except Exception:
1
fh.close()
if __name__ == '__main__':
main()
``` | instruction | 0 | 27,311 | 19 | 54,622 |
No | output | 1 | 27,311 | 19 | 54,623 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
I decided to play rock-paper-scissors with a group of five good friends. Rock-paper-scissors has three hands: goo, choki, and par. If the game between goo and choki is a match between goo and choki, goo is "winning" and choki is "losing". , Par and Goo have the rule that Par is "winning" and Goo is "losing". If everyone has the same hand, or if all of Goo, Choki, and Par come out, it will be "Aiko".
Create a program that inputs the hands of five rock-paper-scissors players and outputs the wins and losses of each person. Rock-paper-scissors hands are represented by the numbers 1 for goo, 2 for choki, and 3 for par. Win / loss is represented by a number of 1, "win" is 1, "los" is 2, and "Aiko" is 3, and they are output according to the input order.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
h1
h2
h3
h4
h5
The i-th line is given the i-th hand hi (1, 2 or 3).
The number of datasets does not exceed 200.
Output
Outputs the wins and losses of 5 players for each input dataset. Output the win / loss (1, 2 or 3) of the i-th person on the i-line.
Example
Input
1
2
3
2
1
1
2
2
2
1
0
Output
3
3
3
3
3
1
2
2
2
1
Submitted Solution:
```
from sys import stdin
readline = stdin.readline
def main():
R, S, P = 1, 2, 3
W, L, D = 1, 2, 3
rps = {
(R, S, P):{R:D, S:D, P:D},
(R, S) :{R:W, S:L},
(S, P) :{S:W, P:L},
(R, P) :{P:W, R:L}
}
while True:
try:
hands = [int(readline()) for _ in range(5)]
except:
break
hand_set = tuple(sorted(set(hands)))
for h in hands:
print(rps[hand_set][h])
main()
``` | instruction | 0 | 27,312 | 19 | 54,624 |
No | output | 1 | 27,312 | 19 | 54,625 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
I decided to play rock-paper-scissors with a group of five good friends. Rock-paper-scissors has three hands: goo, choki, and par. If the game between goo and choki is a match between goo and choki, goo is "winning" and choki is "losing". , Par and Goo have the rule that Par is "winning" and Goo is "losing". If everyone has the same hand, or if all of Goo, Choki, and Par come out, it will be "Aiko".
Create a program that inputs the hands of five rock-paper-scissors players and outputs the wins and losses of each person. Rock-paper-scissors hands are represented by the numbers 1 for goo, 2 for choki, and 3 for par. Win / loss is represented by a number of 1, "win" is 1, "los" is 2, and "Aiko" is 3, and they are output according to the input order.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
h1
h2
h3
h4
h5
The i-th line is given the i-th hand hi (1, 2 or 3).
The number of datasets does not exceed 200.
Output
Outputs the wins and losses of 5 players for each input dataset. Output the win / loss (1, 2 or 3) of the i-th person on the i-line.
Example
Input
1
2
3
2
1
1
2
2
2
1
0
Output
3
3
3
3
3
1
2
2
2
1
Submitted Solution:
```
while True:
h1= int(input())
if h1== 0: break
h2, h3, h4, h5= [int(input()) for _ in range(4)]
sh= set([h1, h2, h3, h4, h5])
if len(sh)== 3:
print("\n".join(["3","3","3","3","3"]))
else:
for h in [h1, h2, h3, h4, h5]:
if h== 1:
print(1 if 2 in sh else 2)
elif h== 2:
print(1 if 3 in sh else 2)
else:
print(1 if 1 in sh else 2)
``` | instruction | 0 | 27,313 | 19 | 54,626 |
No | output | 1 | 27,313 | 19 | 54,627 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
I decided to play rock-paper-scissors with a group of five good friends. Rock-paper-scissors has three hands: goo, choki, and par. If the game between goo and choki is a match between goo and choki, goo is "winning" and choki is "losing". , Par and Goo have the rule that Par is "winning" and Goo is "losing". If everyone has the same hand, or if all of Goo, Choki, and Par come out, it will be "Aiko".
Create a program that inputs the hands of five rock-paper-scissors players and outputs the wins and losses of each person. Rock-paper-scissors hands are represented by the numbers 1 for goo, 2 for choki, and 3 for par. Win / loss is represented by a number of 1, "win" is 1, "los" is 2, and "Aiko" is 3, and they are output according to the input order.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
h1
h2
h3
h4
h5
The i-th line is given the i-th hand hi (1, 2 or 3).
The number of datasets does not exceed 200.
Output
Outputs the wins and losses of 5 players for each input dataset. Output the win / loss (1, 2 or 3) of the i-th person on the i-line.
Example
Input
1
2
3
2
1
1
2
2
2
1
0
Output
3
3
3
3
3
1
2
2
2
1
Submitted Solution:
```
from sys import stdin
readline = stdin.readline
def main():
R, S, P = 1, 2, 3
W, L, D = 1, 2, 3
rps = {
(R, S, P):{R:D, S:D, P:D},
(R, S) :{R:W, S:L},
(S, P) :{S:W, P:L},
(R, P) :{P:W, R:L}
}
while True:
try:
hands = [int(readline()) for _ in range(5)]
except:
break
#hand_set = tuple(sorted(set(hands)))
for h in hands:
if h < 1 or 3 < h:
raise ValueError
#print(rps[hand_set][h])
main()
``` | instruction | 0 | 27,314 | 19 | 54,628 |
No | output | 1 | 27,314 | 19 | 54,629 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alica and Bob are playing a game.
Initially they have a binary string s consisting of only characters 0 and 1.
Alice and Bob make alternating moves: Alice makes the first move, Bob makes the second move, Alice makes the third one, and so on. During each move, the current player must choose two different adjacent characters of string s and delete them. For example, if s = 1011001 then the following moves are possible:
1. delete s_1 and s_2: 1011001 β 11001;
2. delete s_2 and s_3: 1011001 β 11001;
3. delete s_4 and s_5: 1011001 β 10101;
4. delete s_6 and s_7: 1011001 β 10110.
If a player can't make any move, they lose. Both players play optimally. You have to determine if Alice can win.
Input
First line contains one integer t (1 β€ t β€ 1000) β the number of test cases.
Only line of each test case contains one string s (1 β€ |s| β€ 100), consisting of only characters 0 and 1.
Output
For each test case print answer in the single line.
If Alice can win print DA (YES in Russian) in any register. Otherwise print NET (NO in Russian) in any register.
Example
Input
3
01
1111
0011
Output
DA
NET
NET
Note
In the first test case after Alice's move string s become empty and Bob can not make any move.
In the second test case Alice can not make any move initially.
In the third test case after Alice's move string s turn into 01. Then, after Bob's move string s become empty and Alice can not make any move.
Submitted Solution:
```
for i in range(int(input())):
s=input()
p=0
while(len(s)!=0):
z=s
if "10" in s:
a=s.find('10')
s=s[:a]+s[a+2:]
p+=1
elif "01" in s:
a=s.find('01')
s=s[:a]+s[a+2:]
p+=1
if z==s:
break
if p%2==0:
print("NET")
else:
print("DA")
``` | instruction | 0 | 27,593 | 19 | 55,186 |
Yes | output | 1 | 27,593 | 19 | 55,187 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alica and Bob are playing a game.
Initially they have a binary string s consisting of only characters 0 and 1.
Alice and Bob make alternating moves: Alice makes the first move, Bob makes the second move, Alice makes the third one, and so on. During each move, the current player must choose two different adjacent characters of string s and delete them. For example, if s = 1011001 then the following moves are possible:
1. delete s_1 and s_2: 1011001 β 11001;
2. delete s_2 and s_3: 1011001 β 11001;
3. delete s_4 and s_5: 1011001 β 10101;
4. delete s_6 and s_7: 1011001 β 10110.
If a player can't make any move, they lose. Both players play optimally. You have to determine if Alice can win.
Input
First line contains one integer t (1 β€ t β€ 1000) β the number of test cases.
Only line of each test case contains one string s (1 β€ |s| β€ 100), consisting of only characters 0 and 1.
Output
For each test case print answer in the single line.
If Alice can win print DA (YES in Russian) in any register. Otherwise print NET (NO in Russian) in any register.
Example
Input
3
01
1111
0011
Output
DA
NET
NET
Note
In the first test case after Alice's move string s become empty and Bob can not make any move.
In the second test case Alice can not make any move initially.
In the third test case after Alice's move string s turn into 01. Then, after Bob's move string s become empty and Alice can not make any move.
Submitted Solution:
```
for i in range(int(input())):
a = input()
zero = a.count('0')
one = a.count('1')
if min(zero , one) % 2 == 1:
print('DA')
else:
print('NET')
``` | instruction | 0 | 27,594 | 19 | 55,188 |
Yes | output | 1 | 27,594 | 19 | 55,189 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alica and Bob are playing a game.
Initially they have a binary string s consisting of only characters 0 and 1.
Alice and Bob make alternating moves: Alice makes the first move, Bob makes the second move, Alice makes the third one, and so on. During each move, the current player must choose two different adjacent characters of string s and delete them. For example, if s = 1011001 then the following moves are possible:
1. delete s_1 and s_2: 1011001 β 11001;
2. delete s_2 and s_3: 1011001 β 11001;
3. delete s_4 and s_5: 1011001 β 10101;
4. delete s_6 and s_7: 1011001 β 10110.
If a player can't make any move, they lose. Both players play optimally. You have to determine if Alice can win.
Input
First line contains one integer t (1 β€ t β€ 1000) β the number of test cases.
Only line of each test case contains one string s (1 β€ |s| β€ 100), consisting of only characters 0 and 1.
Output
For each test case print answer in the single line.
If Alice can win print DA (YES in Russian) in any register. Otherwise print NET (NO in Russian) in any register.
Example
Input
3
01
1111
0011
Output
DA
NET
NET
Note
In the first test case after Alice's move string s become empty and Bob can not make any move.
In the second test case Alice can not make any move initially.
In the third test case after Alice's move string s turn into 01. Then, after Bob's move string s become empty and Alice can not make any move.
Submitted Solution:
```
t = int(input())
for _ in range(t):
s = list(input())
Q = []
Q.append(s[0])
top, count = 0, 0
for i in range(1, len(s)):
if (not Q or s[i] == Q[top]):
Q.append(s[i])
top += 1
else:
count += 1
Q.pop()
top -=1
if (count % 2 == 0):
print("NET")
else:
print("DA")
``` | instruction | 0 | 27,595 | 19 | 55,190 |
Yes | output | 1 | 27,595 | 19 | 55,191 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alica and Bob are playing a game.
Initially they have a binary string s consisting of only characters 0 and 1.
Alice and Bob make alternating moves: Alice makes the first move, Bob makes the second move, Alice makes the third one, and so on. During each move, the current player must choose two different adjacent characters of string s and delete them. For example, if s = 1011001 then the following moves are possible:
1. delete s_1 and s_2: 1011001 β 11001;
2. delete s_2 and s_3: 1011001 β 11001;
3. delete s_4 and s_5: 1011001 β 10101;
4. delete s_6 and s_7: 1011001 β 10110.
If a player can't make any move, they lose. Both players play optimally. You have to determine if Alice can win.
Input
First line contains one integer t (1 β€ t β€ 1000) β the number of test cases.
Only line of each test case contains one string s (1 β€ |s| β€ 100), consisting of only characters 0 and 1.
Output
For each test case print answer in the single line.
If Alice can win print DA (YES in Russian) in any register. Otherwise print NET (NO in Russian) in any register.
Example
Input
3
01
1111
0011
Output
DA
NET
NET
Note
In the first test case after Alice's move string s become empty and Bob can not make any move.
In the second test case Alice can not make any move initially.
In the third test case after Alice's move string s turn into 01. Then, after Bob's move string s become empty and Alice can not make any move.
Submitted Solution:
```
def read_int():
return int(input())
def read_string_array():
return input().split()
def read_int_array():
return [int(_) for _ in read_string_array()]
def read_line():
return input()
from itertools import groupby
def solve(s):
l = [(list(__))for _, __ in groupby(sorted(s))]
# for i in range(len(l)):
if len(l) <= 1:
return 'NET'
return 'DA' if min(len(l[1]), len(l[0])) % 2 == 1 else 'NET'
if __name__ == '__main__':
T = read_int()
for _ in range(T):
# read inputs
# read_int()
# read_int_array()
# read_string_array()
S = read_line()
# solve
print(solve(S))
``` | instruction | 0 | 27,596 | 19 | 55,192 |
Yes | output | 1 | 27,596 | 19 | 55,193 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alica and Bob are playing a game.
Initially they have a binary string s consisting of only characters 0 and 1.
Alice and Bob make alternating moves: Alice makes the first move, Bob makes the second move, Alice makes the third one, and so on. During each move, the current player must choose two different adjacent characters of string s and delete them. For example, if s = 1011001 then the following moves are possible:
1. delete s_1 and s_2: 1011001 β 11001;
2. delete s_2 and s_3: 1011001 β 11001;
3. delete s_4 and s_5: 1011001 β 10101;
4. delete s_6 and s_7: 1011001 β 10110.
If a player can't make any move, they lose. Both players play optimally. You have to determine if Alice can win.
Input
First line contains one integer t (1 β€ t β€ 1000) β the number of test cases.
Only line of each test case contains one string s (1 β€ |s| β€ 100), consisting of only characters 0 and 1.
Output
For each test case print answer in the single line.
If Alice can win print DA (YES in Russian) in any register. Otherwise print NET (NO in Russian) in any register.
Example
Input
3
01
1111
0011
Output
DA
NET
NET
Note
In the first test case after Alice's move string s become empty and Bob can not make any move.
In the second test case Alice can not make any move initially.
In the third test case after Alice's move string s turn into 01. Then, after Bob's move string s become empty and Alice can not make any move.
Submitted Solution:
```
for _ in range(int(input())):
s=list(input())
cnt=0
while(True):
flag=0
for i in range(len(s)-1):
if s[i]=='0' and s[i+1]=='1':
s.pop(i)
s.pop(i)
cnt+=1
flag=1
break
if flag==0:
break
if cnt%2==0:
print("NET")
else:
print("DA")
``` | instruction | 0 | 27,597 | 19 | 55,194 |
No | output | 1 | 27,597 | 19 | 55,195 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alica and Bob are playing a game.
Initially they have a binary string s consisting of only characters 0 and 1.
Alice and Bob make alternating moves: Alice makes the first move, Bob makes the second move, Alice makes the third one, and so on. During each move, the current player must choose two different adjacent characters of string s and delete them. For example, if s = 1011001 then the following moves are possible:
1. delete s_1 and s_2: 1011001 β 11001;
2. delete s_2 and s_3: 1011001 β 11001;
3. delete s_4 and s_5: 1011001 β 10101;
4. delete s_6 and s_7: 1011001 β 10110.
If a player can't make any move, they lose. Both players play optimally. You have to determine if Alice can win.
Input
First line contains one integer t (1 β€ t β€ 1000) β the number of test cases.
Only line of each test case contains one string s (1 β€ |s| β€ 100), consisting of only characters 0 and 1.
Output
For each test case print answer in the single line.
If Alice can win print DA (YES in Russian) in any register. Otherwise print NET (NO in Russian) in any register.
Example
Input
3
01
1111
0011
Output
DA
NET
NET
Note
In the first test case after Alice's move string s become empty and Bob can not make any move.
In the second test case Alice can not make any move initially.
In the third test case after Alice's move string s turn into 01. Then, after Bob's move string s become empty and Alice can not make any move.
Submitted Solution:
```
for _ in range(int(input())):
s=len(input())
k=s//2
if (s%2==0 and s%4!=0) or (k%2!=0 and s%4!=0):
print("DA")
else:
print("NET")
``` | instruction | 0 | 27,599 | 19 | 55,198 |
No | output | 1 | 27,599 | 19 | 55,199 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alica and Bob are playing a game.
Initially they have a binary string s consisting of only characters 0 and 1.
Alice and Bob make alternating moves: Alice makes the first move, Bob makes the second move, Alice makes the third one, and so on. During each move, the current player must choose two different adjacent characters of string s and delete them. For example, if s = 1011001 then the following moves are possible:
1. delete s_1 and s_2: 1011001 β 11001;
2. delete s_2 and s_3: 1011001 β 11001;
3. delete s_4 and s_5: 1011001 β 10101;
4. delete s_6 and s_7: 1011001 β 10110.
If a player can't make any move, they lose. Both players play optimally. You have to determine if Alice can win.
Input
First line contains one integer t (1 β€ t β€ 1000) β the number of test cases.
Only line of each test case contains one string s (1 β€ |s| β€ 100), consisting of only characters 0 and 1.
Output
For each test case print answer in the single line.
If Alice can win print DA (YES in Russian) in any register. Otherwise print NET (NO in Russian) in any register.
Example
Input
3
01
1111
0011
Output
DA
NET
NET
Note
In the first test case after Alice's move string s become empty and Bob can not make any move.
In the second test case Alice can not make any move initially.
In the third test case after Alice's move string s turn into 01. Then, after Bob's move string s become empty and Alice can not make any move.
Submitted Solution:
```
for i in range(int(input())):
s=input()
n=len(s)
if n - n//4 <= 1:
print ("NET")
else:
print("DA")
``` | instruction | 0 | 27,600 | 19 | 55,200 |
No | output | 1 | 27,600 | 19 | 55,201 |
Provide tags and a correct Python 3 solution for this coding contest problem.
User ainta loves to play with cards. He has a cards containing letter "o" and b cards containing letter "x". He arranges the cards in a row, and calculates the score of the deck by the formula below.
1. At first, the score is 0.
2. For each block of contiguous "o"s with length x the score increases by x2.
3. For each block of contiguous "x"s with length y the score decreases by y2.
For example, if a = 6, b = 3 and ainta have arranged the cards in the order, that is described by string "ooxoooxxo", the score of the deck equals 22 - 12 + 32 - 22 + 12 = 9. That is because the deck has 5 blocks in total: "oo", "x", "ooo", "xx", "o".
User ainta likes big numbers, so he wants to maximize the score with the given cards. Help ainta make the score as big as possible. Note, that he has to arrange all his cards.
Input
The first line contains two space-separated integers a and b (0 β€ a, b β€ 105; a + b β₯ 1) β the number of "o" cards and the number of "x" cards.
Output
In the first line print a single integer v β the maximum score that ainta can obtain.
In the second line print a + b characters describing the deck. If the k-th card of the deck contains "o", the k-th character must be "o". If the k-th card of the deck contains "x", the k-th character must be "x". The number of "o" characters must be equal to a, and the number of "x " characters must be equal to b. If there are many ways to maximize v, print any.
Please, do not write the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
2 3
Output
-1
xoxox
Input
4 0
Output
16
oooo
Input
0 4
Output
-16
xxxx | instruction | 0 | 27,800 | 19 | 55,600 |
Tags: constructive algorithms, implementation
Correct Solution:
```
def main():
a, b = map(int, input().split(' '))
answer = -b ** 2
a_cluster = a
if a:
for i in range(a):
answer_candicate = (a - i) ** 2 + i
quotient = b // (i + 2)
remainder = b % (i + 2)
answer_candicate -= ((i + 2) - remainder) * quotient ** 2 \
+ remainder * (quotient + 1) ** 2
if answer_candicate > answer:
answer = answer_candicate
a_cluster = a - i
print(answer)
if a:
quotient = b // (a - a_cluster + 2)
remainder = b % (a - a_cluster + 2)
print('x' * quotient, end='')
print('o' * a_cluster, end='')
print('x' * (quotient + (1 if remainder else 0)), end='')
remainder = max(remainder - 1, 0)
for i in range(a - a_cluster):
print('o', end='')
print('x' * (quotient + (1 if remainder else 0)), end='')
remainder = max(remainder - 1, 0)
print()
else:
print('x' * b)
if __name__ == '__main__':
main()
``` | output | 1 | 27,800 | 19 | 55,601 |
Provide tags and a correct Python 3 solution for this coding contest problem.
User ainta loves to play with cards. He has a cards containing letter "o" and b cards containing letter "x". He arranges the cards in a row, and calculates the score of the deck by the formula below.
1. At first, the score is 0.
2. For each block of contiguous "o"s with length x the score increases by x2.
3. For each block of contiguous "x"s with length y the score decreases by y2.
For example, if a = 6, b = 3 and ainta have arranged the cards in the order, that is described by string "ooxoooxxo", the score of the deck equals 22 - 12 + 32 - 22 + 12 = 9. That is because the deck has 5 blocks in total: "oo", "x", "ooo", "xx", "o".
User ainta likes big numbers, so he wants to maximize the score with the given cards. Help ainta make the score as big as possible. Note, that he has to arrange all his cards.
Input
The first line contains two space-separated integers a and b (0 β€ a, b β€ 105; a + b β₯ 1) β the number of "o" cards and the number of "x" cards.
Output
In the first line print a single integer v β the maximum score that ainta can obtain.
In the second line print a + b characters describing the deck. If the k-th card of the deck contains "o", the k-th character must be "o". If the k-th card of the deck contains "x", the k-th character must be "x". The number of "o" characters must be equal to a, and the number of "x " characters must be equal to b. If there are many ways to maximize v, print any.
Please, do not write the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
2 3
Output
-1
xoxox
Input
4 0
Output
16
oooo
Input
0 4
Output
-16
xxxx | instruction | 0 | 27,801 | 19 | 55,602 |
Tags: constructive algorithms, implementation
Correct Solution:
```
a,b=map(int,input().split())
def sqr(x):
return x*x
def work( num, flag=0 ):
ans=sqr(a-num+1)+num-1
could = min(b, num+1)
cc=b//could
res=b%could
ans-=res * sqr(cc+1) + (could-res)*sqr(cc)
if flag:
print(ans)
list=''
res2=could-res
if could==num+1:
list+='x'*cc
res2-=1
ta=a
list+='o'*(a-num+1)
ta-=a-num+1
while ta>0:
u=cc+int(res>0)
if res>0:
res-=1
else:
res2-=1
list+='x'*u
list+='o'
ta-=1
if res>0 or res2>0:
list+='x'*(cc+int(res>0))
print(str(list))
return ans
if a==0:
print(-sqr(b))
print('x'*b)
elif b==0:
print(sqr(a))
print('o'*a)
else:
now=1
for i in range(1,a+1):
if i-1<=b and work(i)>work(now):
now=i
work(now,1)
``` | output | 1 | 27,801 | 19 | 55,603 |
Provide tags and a correct Python 3 solution for this coding contest problem.
User ainta loves to play with cards. He has a cards containing letter "o" and b cards containing letter "x". He arranges the cards in a row, and calculates the score of the deck by the formula below.
1. At first, the score is 0.
2. For each block of contiguous "o"s with length x the score increases by x2.
3. For each block of contiguous "x"s with length y the score decreases by y2.
For example, if a = 6, b = 3 and ainta have arranged the cards in the order, that is described by string "ooxoooxxo", the score of the deck equals 22 - 12 + 32 - 22 + 12 = 9. That is because the deck has 5 blocks in total: "oo", "x", "ooo", "xx", "o".
User ainta likes big numbers, so he wants to maximize the score with the given cards. Help ainta make the score as big as possible. Note, that he has to arrange all his cards.
Input
The first line contains two space-separated integers a and b (0 β€ a, b β€ 105; a + b β₯ 1) β the number of "o" cards and the number of "x" cards.
Output
In the first line print a single integer v β the maximum score that ainta can obtain.
In the second line print a + b characters describing the deck. If the k-th card of the deck contains "o", the k-th character must be "o". If the k-th card of the deck contains "x", the k-th character must be "x". The number of "o" characters must be equal to a, and the number of "x " characters must be equal to b. If there are many ways to maximize v, print any.
Please, do not write the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
2 3
Output
-1
xoxox
Input
4 0
Output
16
oooo
Input
0 4
Output
-16
xxxx | instruction | 0 | 27,802 | 19 | 55,604 |
Tags: constructive algorithms, implementation
Correct Solution:
```
import math
import sys
inp = input().split()
a = int(inp[0])
b = int(inp[1])
if a == 0:
print(str(-b**2))
out = "x" * b
print(out)
elif b == 0:
print(str(a**2))
out = "o" * a
print(out)
else:
ind = -1
buk = -1
quo = -1
rem = -1
sco = -sys.maxsize - 1
for i in range(a):
buk_i = i + 2
quo_i = int(b / buk_i)
rem_i = b % buk_i
sco_i = (a - i)**2 + i - rem_i * (quo_i + 1)**2 - (buk_i - rem_i) * quo_i**2
if sco_i > sco:
buk = buk_i
quo = quo_i
rem = rem_i
sco = sco_i
ind = i
print(sco)
out = "x" * quo + "o" * (a - ind - 1)
for i in range(rem):
out += "o" + "x" * (quo + 1)
for i in range(buk - rem - 1):
out += "o" + "x" * quo
print(out)
``` | output | 1 | 27,802 | 19 | 55,605 |
Provide tags and a correct Python 3 solution for this coding contest problem.
User ainta loves to play with cards. He has a cards containing letter "o" and b cards containing letter "x". He arranges the cards in a row, and calculates the score of the deck by the formula below.
1. At first, the score is 0.
2. For each block of contiguous "o"s with length x the score increases by x2.
3. For each block of contiguous "x"s with length y the score decreases by y2.
For example, if a = 6, b = 3 and ainta have arranged the cards in the order, that is described by string "ooxoooxxo", the score of the deck equals 22 - 12 + 32 - 22 + 12 = 9. That is because the deck has 5 blocks in total: "oo", "x", "ooo", "xx", "o".
User ainta likes big numbers, so he wants to maximize the score with the given cards. Help ainta make the score as big as possible. Note, that he has to arrange all his cards.
Input
The first line contains two space-separated integers a and b (0 β€ a, b β€ 105; a + b β₯ 1) β the number of "o" cards and the number of "x" cards.
Output
In the first line print a single integer v β the maximum score that ainta can obtain.
In the second line print a + b characters describing the deck. If the k-th card of the deck contains "o", the k-th character must be "o". If the k-th card of the deck contains "x", the k-th character must be "x". The number of "o" characters must be equal to a, and the number of "x " characters must be equal to b. If there are many ways to maximize v, print any.
Please, do not write the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
2 3
Output
-1
xoxox
Input
4 0
Output
16
oooo
Input
0 4
Output
-16
xxxx | instruction | 0 | 27,803 | 19 | 55,606 |
Tags: constructive algorithms, implementation
Correct Solution:
```
# Made By Mostafa_Khaled
bot = True
a,b=map(int,input().split())
def sqr(x):
return x*x
def work( num, flag=0 ):
ans=sqr(a-num+1)+num-1
could = min(b, num+1)
cc=b//could
res=b%could
ans-=res * sqr(cc+1) + (could-res)*sqr(cc)
if flag:
print(ans)
list=''
res2=could-res
if could==num+1:
list+='x'*cc
res2-=1
ta=a
list+='o'*(a-num+1)
ta-=a-num+1
while ta>0:
u=cc+int(res>0)
if res>0:
res-=1
else:
res2-=1
list+='x'*u
list+='o'
ta-=1
if res>0 or res2>0:
list+='x'*(cc+int(res>0))
print(str(list))
return ans
if a==0:
print(-sqr(b))
print('x'*b)
elif b==0:
print(sqr(a))
print('o'*a)
else:
now=1
for i in range(1,a+1):
if i-1<=b and work(i)>work(now):
now=i
work(now,1)
# Made By Mostafa_Khaled
``` | output | 1 | 27,803 | 19 | 55,607 |
Provide tags and a correct Python 3 solution for this coding contest problem.
User ainta loves to play with cards. He has a cards containing letter "o" and b cards containing letter "x". He arranges the cards in a row, and calculates the score of the deck by the formula below.
1. At first, the score is 0.
2. For each block of contiguous "o"s with length x the score increases by x2.
3. For each block of contiguous "x"s with length y the score decreases by y2.
For example, if a = 6, b = 3 and ainta have arranged the cards in the order, that is described by string "ooxoooxxo", the score of the deck equals 22 - 12 + 32 - 22 + 12 = 9. That is because the deck has 5 blocks in total: "oo", "x", "ooo", "xx", "o".
User ainta likes big numbers, so he wants to maximize the score with the given cards. Help ainta make the score as big as possible. Note, that he has to arrange all his cards.
Input
The first line contains two space-separated integers a and b (0 β€ a, b β€ 105; a + b β₯ 1) β the number of "o" cards and the number of "x" cards.
Output
In the first line print a single integer v β the maximum score that ainta can obtain.
In the second line print a + b characters describing the deck. If the k-th card of the deck contains "o", the k-th character must be "o". If the k-th card of the deck contains "x", the k-th character must be "x". The number of "o" characters must be equal to a, and the number of "x " characters must be equal to b. If there are many ways to maximize v, print any.
Please, do not write the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
2 3
Output
-1
xoxox
Input
4 0
Output
16
oooo
Input
0 4
Output
-16
xxxx | instruction | 0 | 27,804 | 19 | 55,608 |
Tags: constructive algorithms, implementation
Correct Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect
from itertools import chain, dropwhile, permutations, combinations
from collections import defaultdict
def main2(a,b):
if a==0:
print(-b**2)
print("x"*b)
return
if b==0:
print(a**2)
print("o"*a)
return
if 2*a>=b:
ans = a**2 - (b//2)**2 - (b-b//2)**2
print(ans)
print("x"*(b//2),end="")
print("o"*a,end="")
print("x"*(b-b//2))
else:
x = b//(a+1)
m = b % x
bb = [x+1]*m + [x]*(a+1-m)
ans = -m*(x+1)**2 - (a+1-m)*x**2 + a
print(ans)
bbb = ["x"*j for j in bb]
print("o".join(bbb))
def main(a,b):
if a==0:
print(-b**2)
print("x"*b)
return
if b<=1:
print(a**2-b**2)
print("o"*a + "x"*b)
return
ans = None
for p in range(1,a+1):
q = p+1
curr = (a-p+1)**2 + (p-1) - ((b//q+1)**2*(b%q)+(b//q)**2*(q-(b%q)))
#print(p,q,curr)
if ans is None or curr > ans:
ans = curr
best_p = p
print(ans)
p = best_p
q = p+1
x = b//q
m = b-x*q
bb = [x+1]*m + [x]*(q-m)
bbb = ["x"*j for j in bb]
aaa = ["o"*j for j in ([a-p+1]+[1]*(p-1))]
#print("o".join(bbb))
#print(p,q,aaa,bbb,x,m,bb)
print(bbb[0],end="")
for i in range(p):
print(aaa[i],end="")
print(bbb[i+1],end="")
print()
def main_input(info=0):
a,b = map(int,input().split())
#t = [(int(x)-1,i+1) for i,x in enumerate(input().split())]
#l,r = list(range(n)), list(range(n))
#for i in range(n):
# l[i],r[i] = map(int,input().split())
# t = [map(int,input().split()) for x in range(n)]
main(a,b)
if __name__ == "__main__":
main_input()
``` | output | 1 | 27,804 | 19 | 55,609 |
Provide tags and a correct Python 3 solution for this coding contest problem.
User ainta loves to play with cards. He has a cards containing letter "o" and b cards containing letter "x". He arranges the cards in a row, and calculates the score of the deck by the formula below.
1. At first, the score is 0.
2. For each block of contiguous "o"s with length x the score increases by x2.
3. For each block of contiguous "x"s with length y the score decreases by y2.
For example, if a = 6, b = 3 and ainta have arranged the cards in the order, that is described by string "ooxoooxxo", the score of the deck equals 22 - 12 + 32 - 22 + 12 = 9. That is because the deck has 5 blocks in total: "oo", "x", "ooo", "xx", "o".
User ainta likes big numbers, so he wants to maximize the score with the given cards. Help ainta make the score as big as possible. Note, that he has to arrange all his cards.
Input
The first line contains two space-separated integers a and b (0 β€ a, b β€ 105; a + b β₯ 1) β the number of "o" cards and the number of "x" cards.
Output
In the first line print a single integer v β the maximum score that ainta can obtain.
In the second line print a + b characters describing the deck. If the k-th card of the deck contains "o", the k-th character must be "o". If the k-th card of the deck contains "x", the k-th character must be "x". The number of "o" characters must be equal to a, and the number of "x " characters must be equal to b. If there are many ways to maximize v, print any.
Please, do not write the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
2 3
Output
-1
xoxox
Input
4 0
Output
16
oooo
Input
0 4
Output
-16
xxxx | instruction | 0 | 27,805 | 19 | 55,610 |
Tags: constructive algorithms, implementation
Correct Solution:
```
a,b=map(int,input().split())
def sqr(x):
return x*x
def work( num, flag=0 ):
ans=sqr(a-num+1)+num-1
could = min(b, num+1)
cc=b//could
res=b%could
ans-=res * sqr(cc+1) + (could-res)*sqr(cc)
if flag:
print(ans)
list=''
res2=could-res
if could==num+1:
list+='x'*cc
res2-=1
ta=a
list+='o'*(a-num+1)
ta-=a-num+1
while ta>0:
u=cc+int(res>0)
if res>0:
res-=1
else:
res2-=1
list+='x'*u
list+='o'
ta-=1
if res>0 or res2>0:
list+='x'*(cc+int(res>0))
print(str(list))
return ans
if a==0:
print(-sqr(b))
print('x'*b)
elif b==0:
print(sqr(a))
print('o'*a)
else:
now=1
for i in range(1,a+1):
if i-1<=b and work(i)>work(now):
now=i
work(now,1)
# Made By Mostafa_Khaled
``` | output | 1 | 27,805 | 19 | 55,611 |
Provide tags and a correct Python 3 solution for this coding contest problem.
User ainta loves to play with cards. He has a cards containing letter "o" and b cards containing letter "x". He arranges the cards in a row, and calculates the score of the deck by the formula below.
1. At first, the score is 0.
2. For each block of contiguous "o"s with length x the score increases by x2.
3. For each block of contiguous "x"s with length y the score decreases by y2.
For example, if a = 6, b = 3 and ainta have arranged the cards in the order, that is described by string "ooxoooxxo", the score of the deck equals 22 - 12 + 32 - 22 + 12 = 9. That is because the deck has 5 blocks in total: "oo", "x", "ooo", "xx", "o".
User ainta likes big numbers, so he wants to maximize the score with the given cards. Help ainta make the score as big as possible. Note, that he has to arrange all his cards.
Input
The first line contains two space-separated integers a and b (0 β€ a, b β€ 105; a + b β₯ 1) β the number of "o" cards and the number of "x" cards.
Output
In the first line print a single integer v β the maximum score that ainta can obtain.
In the second line print a + b characters describing the deck. If the k-th card of the deck contains "o", the k-th character must be "o". If the k-th card of the deck contains "x", the k-th character must be "x". The number of "o" characters must be equal to a, and the number of "x " characters must be equal to b. If there are many ways to maximize v, print any.
Please, do not write the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
2 3
Output
-1
xoxox
Input
4 0
Output
16
oooo
Input
0 4
Output
-16
xxxx | instruction | 0 | 27,806 | 19 | 55,612 |
Tags: constructive algorithms, implementation
Correct Solution:
```
a,b=[int(i) for i in input().split()]
if(a==0):
print(-b**2)
print('x'*b)
elif(b==0):
print(a**2)
print('o'*a)
elif(b==1):
print(a**2-1)
print('x'+'o'*a)
else:
ans=-float('inf')
gr_no=None
for i in range(2,min(a+2,b+1)):
v1=(a+2-i)**2 + i-2
quo=b//i
rem=b%i
v2=rem*((quo+1)**2) + (i-rem)*((quo**2))
if(v1-v2>ans):
gr_no=i
ans=v1-v2
quo=b//gr_no
rem=b%gr_no
if(rem>0):
s='x'*(quo+1)+'o'*(a+2-gr_no)
rem-=1
else:
s='x'*(quo)+'o'*(a+2-gr_no)
gr_no-=1
s1='x'*(quo+1)+'o'
s2='x'*quo + 'o'
for i in range(rem):
s+=s1
for i in range(gr_no-rem-1):
s+=s2
s+='x'*(quo)
print(ans)
print(s)
``` | output | 1 | 27,806 | 19 | 55,613 |
Provide tags and a correct Python 3 solution for this coding contest problem.
User ainta loves to play with cards. He has a cards containing letter "o" and b cards containing letter "x". He arranges the cards in a row, and calculates the score of the deck by the formula below.
1. At first, the score is 0.
2. For each block of contiguous "o"s with length x the score increases by x2.
3. For each block of contiguous "x"s with length y the score decreases by y2.
For example, if a = 6, b = 3 and ainta have arranged the cards in the order, that is described by string "ooxoooxxo", the score of the deck equals 22 - 12 + 32 - 22 + 12 = 9. That is because the deck has 5 blocks in total: "oo", "x", "ooo", "xx", "o".
User ainta likes big numbers, so he wants to maximize the score with the given cards. Help ainta make the score as big as possible. Note, that he has to arrange all his cards.
Input
The first line contains two space-separated integers a and b (0 β€ a, b β€ 105; a + b β₯ 1) β the number of "o" cards and the number of "x" cards.
Output
In the first line print a single integer v β the maximum score that ainta can obtain.
In the second line print a + b characters describing the deck. If the k-th card of the deck contains "o", the k-th character must be "o". If the k-th card of the deck contains "x", the k-th character must be "x". The number of "o" characters must be equal to a, and the number of "x " characters must be equal to b. If there are many ways to maximize v, print any.
Please, do not write the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
2 3
Output
-1
xoxox
Input
4 0
Output
16
oooo
Input
0 4
Output
-16
xxxx | instruction | 0 | 27,807 | 19 | 55,614 |
Tags: constructive algorithms, implementation
Correct Solution:
```
a, b = map(int, input().split())
if b < 2:
print(a * a - b)
print('o' * a + 'x' * b)
elif a == 0:
print(- b * b)
print('x' * b)
else:
s = a * a - b * b
for i in range(2, min(a + 1, b) + 1):
u, v = b // i, b % i
d = i - 2 + (a - i + 2) ** 2 - (u ** 2) * (i - v) - ((u + 1) ** 2) * v
if d > s: s, q, p, j = d, u, v, i
k = 2 * j - 1
t = [0] * k
t[1: k: 2] = ['o'] * (j - 2) + ['o' * (a - j + 2)]
t[0: k: 2] = ['x' * q] * (j - p) + ['x' * (q + 1)] * p
print(s)
print(''.join(t))
``` | output | 1 | 27,807 | 19 | 55,615 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
User ainta loves to play with cards. He has a cards containing letter "o" and b cards containing letter "x". He arranges the cards in a row, and calculates the score of the deck by the formula below.
1. At first, the score is 0.
2. For each block of contiguous "o"s with length x the score increases by x2.
3. For each block of contiguous "x"s with length y the score decreases by y2.
For example, if a = 6, b = 3 and ainta have arranged the cards in the order, that is described by string "ooxoooxxo", the score of the deck equals 22 - 12 + 32 - 22 + 12 = 9. That is because the deck has 5 blocks in total: "oo", "x", "ooo", "xx", "o".
User ainta likes big numbers, so he wants to maximize the score with the given cards. Help ainta make the score as big as possible. Note, that he has to arrange all his cards.
Input
The first line contains two space-separated integers a and b (0 β€ a, b β€ 105; a + b β₯ 1) β the number of "o" cards and the number of "x" cards.
Output
In the first line print a single integer v β the maximum score that ainta can obtain.
In the second line print a + b characters describing the deck. If the k-th card of the deck contains "o", the k-th character must be "o". If the k-th card of the deck contains "x", the k-th character must be "x". The number of "o" characters must be equal to a, and the number of "x " characters must be equal to b. If there are many ways to maximize v, print any.
Please, do not write the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
2 3
Output
-1
xoxox
Input
4 0
Output
16
oooo
Input
0 4
Output
-16
xxxx
Submitted Solution:
```
x, y = map(int, input().split(' '))
def f(b, g):
x = b // g
y = x + 1
nx = y * g - b
ny = g - nx
return [nx*x**2+ny*y**2, x, nx, y, ny]
if (x == 0):
print(-y**2)
print('x'*y)
quit()
if (y == 0):
print(x**2)
print('o'*x)
quit()
maxx = -10**15
for go in range(1, x+1):
for gx in [go-1, go, go+1]:
if (not (1 <= gx <= y)):
continue
maxx = max(maxx, -f(y, gx)[0]+(x-go+1)**2+(go-1))
for go in range(1, x+1):
for gx in [go-1, go, go+1]:
if (not (1 <= gx <= y)):
continue
if -f(y, gx)[0] + (x-go+1)**2+(go-1) == maxx:
go2 = ['o'] * (go-1) + ['o'*(x-go+1)]
k = f(y, gx)
gp = ['x'*k[1]]*k[2] + ['x'*k[3]] * k[4]
print(maxx)
if (gx == go):
for i in range(gx):
print(go2[i], end = '')
print(gp[i], end = '')
quit()
if gx == go-1:
print(go2[0], end = '')
for i in range(gx):
print(gp[i], end = '')
print(go2[i+1], end = '')
quit()
if gx == go+1:
print(gp[0], end = '')
for i in range(go):
print(go2[i], end = '')
print(gp[i+1], end = '')
quit()
``` | instruction | 0 | 27,808 | 19 | 55,616 |
Yes | output | 1 | 27,808 | 19 | 55,617 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
User ainta loves to play with cards. He has a cards containing letter "o" and b cards containing letter "x". He arranges the cards in a row, and calculates the score of the deck by the formula below.
1. At first, the score is 0.
2. For each block of contiguous "o"s with length x the score increases by x2.
3. For each block of contiguous "x"s with length y the score decreases by y2.
For example, if a = 6, b = 3 and ainta have arranged the cards in the order, that is described by string "ooxoooxxo", the score of the deck equals 22 - 12 + 32 - 22 + 12 = 9. That is because the deck has 5 blocks in total: "oo", "x", "ooo", "xx", "o".
User ainta likes big numbers, so he wants to maximize the score with the given cards. Help ainta make the score as big as possible. Note, that he has to arrange all his cards.
Input
The first line contains two space-separated integers a and b (0 β€ a, b β€ 105; a + b β₯ 1) β the number of "o" cards and the number of "x" cards.
Output
In the first line print a single integer v β the maximum score that ainta can obtain.
In the second line print a + b characters describing the deck. If the k-th card of the deck contains "o", the k-th character must be "o". If the k-th card of the deck contains "x", the k-th character must be "x". The number of "o" characters must be equal to a, and the number of "x " characters must be equal to b. If there are many ways to maximize v, print any.
Please, do not write the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
2 3
Output
-1
xoxox
Input
4 0
Output
16
oooo
Input
0 4
Output
-16
xxxx
Submitted Solution:
```
a, b = map(int, input().split())
sx = lambda p: (a - p + 1) ** 2 + p - 1
sy = lambda q: (b % q) * (1 + b // q) ** 2 + (b // q) ** 2 * (q - b % q)
n = min(a, b)
if a == 0:
print( -b ** 2)
print( b * "x" )
elif b <= 1:
print( a ** 2 - b ** 2 )
print ( a * "o" + b * "x" )
else:
res = - (a + b) ** 2
for p in range(1, n + 1):
for q in range(p-1, p+2):
if(1 <= q <= b):
pos = sx( p )
neg = sy( q )
if res < pos - neg:
res = pos - neg
res_p = p
res_q = q
print( res )
s = ""
if res_p >= res_q:
for i in range(res_p):
wl = 1 if i > 0 else a - (res_p-1)
s += wl * "x"
ll = b // res_q + 1 if i < b % res_q else b // res_q
if i < res_q: s += ll * "o"
else:
for i in range(res_q):
ll = b // res_q + 1 if i < b % res_q else b // res_q;
s += ll * "x"
wl = 1 if i > 0 else a - (res_p-1)
if i < res_p: s+= wl * "o"
print( s )
``` | instruction | 0 | 27,809 | 19 | 55,618 |
Yes | output | 1 | 27,809 | 19 | 55,619 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
User ainta loves to play with cards. He has a cards containing letter "o" and b cards containing letter "x". He arranges the cards in a row, and calculates the score of the deck by the formula below.
1. At first, the score is 0.
2. For each block of contiguous "o"s with length x the score increases by x2.
3. For each block of contiguous "x"s with length y the score decreases by y2.
For example, if a = 6, b = 3 and ainta have arranged the cards in the order, that is described by string "ooxoooxxo", the score of the deck equals 22 - 12 + 32 - 22 + 12 = 9. That is because the deck has 5 blocks in total: "oo", "x", "ooo", "xx", "o".
User ainta likes big numbers, so he wants to maximize the score with the given cards. Help ainta make the score as big as possible. Note, that he has to arrange all his cards.
Input
The first line contains two space-separated integers a and b (0 β€ a, b β€ 105; a + b β₯ 1) β the number of "o" cards and the number of "x" cards.
Output
In the first line print a single integer v β the maximum score that ainta can obtain.
In the second line print a + b characters describing the deck. If the k-th card of the deck contains "o", the k-th character must be "o". If the k-th card of the deck contains "x", the k-th character must be "x". The number of "o" characters must be equal to a, and the number of "x " characters must be equal to b. If there are many ways to maximize v, print any.
Please, do not write the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
2 3
Output
-1
xoxox
Input
4 0
Output
16
oooo
Input
0 4
Output
-16
xxxx
Submitted Solution:
```
a,b = map(int,input().split())
i = 1
s = ''
cnt = 0
while i <= a + 1:
if i < a+1:
if i <= b%(a+1):
s += 'x'*(b//(a+1)+1) + 'o'
cnt -= -1 + (b//(a+1)+1)**2
elif i > b%(a+1):
if b//(a+1) == 0:
cnt += (a-i+1)**2
s += 'o'*(a-i+1)
break
else:
cnt -= -1 + (b//(a+1))**2
s += 'x'*(b//(a+1)) + 'o'
elif i == a+1:
s += 'x'*(b//(a+1))
cnt -= (b//(a+1))**2
i += 1
print(cnt)
print(s)
``` | instruction | 0 | 27,810 | 19 | 55,620 |
No | output | 1 | 27,810 | 19 | 55,621 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
User ainta loves to play with cards. He has a cards containing letter "o" and b cards containing letter "x". He arranges the cards in a row, and calculates the score of the deck by the formula below.
1. At first, the score is 0.
2. For each block of contiguous "o"s with length x the score increases by x2.
3. For each block of contiguous "x"s with length y the score decreases by y2.
For example, if a = 6, b = 3 and ainta have arranged the cards in the order, that is described by string "ooxoooxxo", the score of the deck equals 22 - 12 + 32 - 22 + 12 = 9. That is because the deck has 5 blocks in total: "oo", "x", "ooo", "xx", "o".
User ainta likes big numbers, so he wants to maximize the score with the given cards. Help ainta make the score as big as possible. Note, that he has to arrange all his cards.
Input
The first line contains two space-separated integers a and b (0 β€ a, b β€ 105; a + b β₯ 1) β the number of "o" cards and the number of "x" cards.
Output
In the first line print a single integer v β the maximum score that ainta can obtain.
In the second line print a + b characters describing the deck. If the k-th card of the deck contains "o", the k-th character must be "o". If the k-th card of the deck contains "x", the k-th character must be "x". The number of "o" characters must be equal to a, and the number of "x " characters must be equal to b. If there are many ways to maximize v, print any.
Please, do not write the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
2 3
Output
-1
xoxox
Input
4 0
Output
16
oooo
Input
0 4
Output
-16
xxxx
Submitted Solution:
```
import math
c = input().split(' ')
a = int(c[0])
b = int(c[1])
ans = 0
if a-b > 0:
if b == 0:
ans = a**2
else:
ans = (a-b+1)**2 - 1
elif a-b < 0:
if a == 0:
ans = -(b**2)
else:
ans = -((a-b)**2)
else:
ans = 0
print(ans)
``` | instruction | 0 | 27,811 | 19 | 55,622 |
No | output | 1 | 27,811 | 19 | 55,623 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
User ainta loves to play with cards. He has a cards containing letter "o" and b cards containing letter "x". He arranges the cards in a row, and calculates the score of the deck by the formula below.
1. At first, the score is 0.
2. For each block of contiguous "o"s with length x the score increases by x2.
3. For each block of contiguous "x"s with length y the score decreases by y2.
For example, if a = 6, b = 3 and ainta have arranged the cards in the order, that is described by string "ooxoooxxo", the score of the deck equals 22 - 12 + 32 - 22 + 12 = 9. That is because the deck has 5 blocks in total: "oo", "x", "ooo", "xx", "o".
User ainta likes big numbers, so he wants to maximize the score with the given cards. Help ainta make the score as big as possible. Note, that he has to arrange all his cards.
Input
The first line contains two space-separated integers a and b (0 β€ a, b β€ 105; a + b β₯ 1) β the number of "o" cards and the number of "x" cards.
Output
In the first line print a single integer v β the maximum score that ainta can obtain.
In the second line print a + b characters describing the deck. If the k-th card of the deck contains "o", the k-th character must be "o". If the k-th card of the deck contains "x", the k-th character must be "x". The number of "o" characters must be equal to a, and the number of "x " characters must be equal to b. If there are many ways to maximize v, print any.
Please, do not write the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
2 3
Output
-1
xoxox
Input
4 0
Output
16
oooo
Input
0 4
Output
-16
xxxx
Submitted Solution:
```
cards=input().split(' ')
if int(cards[0])==0:
print(pow(int(cards[1]),2)*-1)
print('x'*int(cards[1]))
elif int(cards[1])==0:
print(pow(int(cards[0]),2))
print('o'*int(cards[0]))
else:
if int(cards[0])<int(cards[1]):
xgroups=int(cards[0])+1
xgroupssize=int(cards[1])//xgroups
bigxgroups=(int(cards[1])-xgroupssize)%int(cards[0])
smallxgroups=xgroups-bigxgroups
print(bigxgroups*-pow(xgroupssize+1,2)+smallxgroups*-pow(xgroupssize,2)+int(cards[0]))
print(('x'*(xgroupssize+1)+'o')*bigxgroups+('x'*(xgroupssize)+'o')*(smallxgroups-1)+'x'*(xgroupssize))
else:
print(pow((int(cards[1])//2)+(int(cards[1])%2),2)*-1+pow(int(cards[0]),2)+pow((int(cards[1])//2),2)*-1)
print('x'*(int(cards[1])//2)+'x'*(int(cards[1])%2)+'o'*int(cards[0])+'x'*(int(cards[1])//2))
``` | instruction | 0 | 27,812 | 19 | 55,624 |
No | output | 1 | 27,812 | 19 | 55,625 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
User ainta loves to play with cards. He has a cards containing letter "o" and b cards containing letter "x". He arranges the cards in a row, and calculates the score of the deck by the formula below.
1. At first, the score is 0.
2. For each block of contiguous "o"s with length x the score increases by x2.
3. For each block of contiguous "x"s with length y the score decreases by y2.
For example, if a = 6, b = 3 and ainta have arranged the cards in the order, that is described by string "ooxoooxxo", the score of the deck equals 22 - 12 + 32 - 22 + 12 = 9. That is because the deck has 5 blocks in total: "oo", "x", "ooo", "xx", "o".
User ainta likes big numbers, so he wants to maximize the score with the given cards. Help ainta make the score as big as possible. Note, that he has to arrange all his cards.
Input
The first line contains two space-separated integers a and b (0 β€ a, b β€ 105; a + b β₯ 1) β the number of "o" cards and the number of "x" cards.
Output
In the first line print a single integer v β the maximum score that ainta can obtain.
In the second line print a + b characters describing the deck. If the k-th card of the deck contains "o", the k-th character must be "o". If the k-th card of the deck contains "x", the k-th character must be "x". The number of "o" characters must be equal to a, and the number of "x " characters must be equal to b. If there are many ways to maximize v, print any.
Please, do not write the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
2 3
Output
-1
xoxox
Input
4 0
Output
16
oooo
Input
0 4
Output
-16
xxxx
Submitted Solution:
```
cards=input().split(' ')
def punctuationofxbygroups(amount,groups):
xgroupssize=amount//groups
bigxgroups=amount%groups
return pow(xgroupssize,2)*(groups-bigxgroups)+pow(xgroupssize+1,2)*bigxgroups
if int(cards[0])==0:
print(pow(int(cards[1]),2)*-1)
print('x'*int(cards[1]))
elif int(cards[1])==0:
print(pow(int(cards[0]),2))
print('o'*int(cards[0]))
else:
if False:
print('LOL')
else:
xgroups=2
while(xgroups<int(cards[0])+1 and punctuationofxbygroups(int(cards[1]),xgroups)-punctuationofxbygroups(int(cards[1]),xgroups+1)>pow(int(cards[0])-xgroups+2,2)-pow(int(cards[0])-xgroups+1,2)):
xgroups+=1
xgroupssize=int(cards[1])//xgroups
bigxgroups=int(cards[1])%xgroups
smallxgroups=xgroups-bigxgroups
print(pow(int(cards[0])-xgroups+2,2)-punctuationofxbygroups(int(cards[1]),xgroups)+xgroups-2)
print(('x'*(xgroupssize+1)+'o')*bigxgroups+('x'*(xgroupssize)+'o')*(smallxgroups-1)+'o'*(int(cards[0])-xgroups+1)+'x'*(xgroupssize))
``` | instruction | 0 | 27,813 | 19 | 55,626 |
No | output | 1 | 27,813 | 19 | 55,627 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In one of the games Arkady is fond of the game process happens on a rectangular field. In the game process Arkady can buy extensions for his field, each extension enlarges one of the field sizes in a particular number of times. Formally, there are n extensions, the i-th of them multiplies the width or the length (by Arkady's choice) by ai. Each extension can't be used more than once, the extensions can be used in any order.
Now Arkady's field has size h Γ w. He wants to enlarge it so that it is possible to place a rectangle of size a Γ b on it (along the width or along the length, with sides parallel to the field sides). Find the minimum number of extensions needed to reach Arkady's goal.
Input
The first line contains five integers a, b, h, w and n (1 β€ a, b, h, w, n β€ 100 000) β the sizes of the rectangle needed to be placed, the initial sizes of the field and the number of available extensions.
The second line contains n integers a1, a2, ..., an (2 β€ ai β€ 100 000), where ai equals the integer a side multiplies by when the i-th extension is applied.
Output
Print the minimum number of extensions needed to reach Arkady's goal. If it is not possible to place the rectangle on the field with all extensions, print -1. If the rectangle can be placed on the initial field, print 0.
Examples
Input
3 3 2 4 4
2 5 4 10
Output
1
Input
3 3 3 3 5
2 3 5 4 2
Output
0
Input
5 5 1 2 3
2 2 3
Output
-1
Input
3 4 1 1 3
2 3 2
Output
3
Note
In the first example it is enough to use any of the extensions available. For example, we can enlarge h in 5 times using the second extension. Then h becomes equal 10 and it is now possible to place the rectangle on the field. | instruction | 0 | 27,949 | 19 | 55,898 |
Tags: brute force, dp, meet-in-the-middle
Correct Solution:
```
f = lambda: map(int, input().split())
a, b, h, w, n = f()
c = sorted(list(f()), key=lambda x: -x)
d = {(h, w), (w, h)}
for i, q in enumerate([1] + c):
for u, v in d.copy():
h, w = u, v * q
if a <= w and b <= h or a <= h and b <= w:
print(i)
exit()
d.add((h, w))
d.add((w, h))
print(-1)
``` | output | 1 | 27,949 | 19 | 55,899 |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.