message stringlengths 2 67k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 463 109k | cluster float64 19 19 | __index_level_0__ int64 926 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same difference, it's a draw.
The first player wrote number a, the second player wrote number b. How many ways to throw a dice are there, at which the first player wins, or there is a draw, or the second player wins?
Input
The single line contains two integers a and b (1 ≤ a, b ≤ 6) — the numbers written on the paper by the first and second player, correspondingly.
Output
Print three integers: the number of ways to throw the dice at which the first player wins, the game ends with a draw or the second player wins, correspondingly.
Examples
Input
2 5
Output
3 0 3
Input
2 4
Output
2 1 3
Note
The dice is a standard cube-shaped six-sided object with each side containing a number from 1 to 6, and where all numbers on all sides are distinct.
You can assume that number a is closer to number x than number b, if |a - x| < |b - x|. | instruction | 0 | 42,428 | 19 | 84,856 |
Tags: brute force
Correct Solution:
```
x = [int(y) for y in input().split()]
if x[0] == x[1]:
print("0 6 0")
else:
q = 0
r = 0
s = 0
for n in range(1,7):
if abs(n-x[0]) < abs(n-x[1]):
q += 1
elif abs(n-x[0]) == abs(n-x[1]):
r+=1
else:
s+=1
pr = str(q) + " " + str(r) + " " + str(s)
print(pr)
``` | output | 1 | 42,428 | 19 | 84,857 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same difference, it's a draw.
The first player wrote number a, the second player wrote number b. How many ways to throw a dice are there, at which the first player wins, or there is a draw, or the second player wins?
Input
The single line contains two integers a and b (1 ≤ a, b ≤ 6) — the numbers written on the paper by the first and second player, correspondingly.
Output
Print three integers: the number of ways to throw the dice at which the first player wins, the game ends with a draw or the second player wins, correspondingly.
Examples
Input
2 5
Output
3 0 3
Input
2 4
Output
2 1 3
Note
The dice is a standard cube-shaped six-sided object with each side containing a number from 1 to 6, and where all numbers on all sides are distinct.
You can assume that number a is closer to number x than number b, if |a - x| < |b - x|. | instruction | 0 | 42,429 | 19 | 84,858 |
Tags: brute force
Correct Solution:
```
a, b = [int(x) for x in input().split()]
a_win = 0
b_win = 0
tie = 0
for i in range(1, 7):
if abs(i-a) < abs(i-b):
a_win += 1
elif abs(i-a) > abs(i-b):
b_win +=1
else:
tie +=1
print(a_win, tie, b_win)
``` | output | 1 | 42,429 | 19 | 84,859 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same difference, it's a draw.
The first player wrote number a, the second player wrote number b. How many ways to throw a dice are there, at which the first player wins, or there is a draw, or the second player wins?
Input
The single line contains two integers a and b (1 ≤ a, b ≤ 6) — the numbers written on the paper by the first and second player, correspondingly.
Output
Print three integers: the number of ways to throw the dice at which the first player wins, the game ends with a draw or the second player wins, correspondingly.
Examples
Input
2 5
Output
3 0 3
Input
2 4
Output
2 1 3
Note
The dice is a standard cube-shaped six-sided object with each side containing a number from 1 to 6, and where all numbers on all sides are distinct.
You can assume that number a is closer to number x than number b, if |a - x| < |b - x|. | instruction | 0 | 42,430 | 19 | 84,860 |
Tags: brute force
Correct Solution:
```
a, b = map(int, input().split())
c, d, e = 0, 0, 0
for i in range(1, 7):
if abs(i - a) < abs(i - b):
c += 1
elif abs(i - a) > abs(i - b):
e += 1
else:
d += 1
print(c, d, e, sep = ' ')
``` | output | 1 | 42,430 | 19 | 84,861 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same difference, it's a draw.
The first player wrote number a, the second player wrote number b. How many ways to throw a dice are there, at which the first player wins, or there is a draw, or the second player wins?
Input
The single line contains two integers a and b (1 ≤ a, b ≤ 6) — the numbers written on the paper by the first and second player, correspondingly.
Output
Print three integers: the number of ways to throw the dice at which the first player wins, the game ends with a draw or the second player wins, correspondingly.
Examples
Input
2 5
Output
3 0 3
Input
2 4
Output
2 1 3
Note
The dice is a standard cube-shaped six-sided object with each side containing a number from 1 to 6, and where all numbers on all sides are distinct.
You can assume that number a is closer to number x than number b, if |a - x| < |b - x|.
Submitted Solution:
```
import sys
def input(): return sys.stdin.readline().strip()
def iinput(): return int(input())
def rinput(): return map(int, sys.stdin.readline().strip().split())
def get_list(): return list(map(int, sys.stdin.readline().strip().split()))
n,m=map(int,input().split())
a,d,b=0,0,0
for i in range(1,7):
p=abs(n-i)-abs(m-i)
a+=p<0
d+=p==0
b+=p>0
print(a,d,b)
``` | instruction | 0 | 42,431 | 19 | 84,862 |
Yes | output | 1 | 42,431 | 19 | 84,863 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same difference, it's a draw.
The first player wrote number a, the second player wrote number b. How many ways to throw a dice are there, at which the first player wins, or there is a draw, or the second player wins?
Input
The single line contains two integers a and b (1 ≤ a, b ≤ 6) — the numbers written on the paper by the first and second player, correspondingly.
Output
Print three integers: the number of ways to throw the dice at which the first player wins, the game ends with a draw or the second player wins, correspondingly.
Examples
Input
2 5
Output
3 0 3
Input
2 4
Output
2 1 3
Note
The dice is a standard cube-shaped six-sided object with each side containing a number from 1 to 6, and where all numbers on all sides are distinct.
You can assume that number a is closer to number x than number b, if |a - x| < |b - x|.
Submitted Solution:
```
count=0
count1=0
draw=0
a,b=input().split()
a=int(a)
b=int(b)
for i in range(1,7):
if abs(a-i)>abs(b-i):
count+=1
elif abs(a-i)<abs(b-i):
count1+=1
else:
draw+=1
print(count1,draw,count)
``` | instruction | 0 | 42,432 | 19 | 84,864 |
Yes | output | 1 | 42,432 | 19 | 84,865 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same difference, it's a draw.
The first player wrote number a, the second player wrote number b. How many ways to throw a dice are there, at which the first player wins, or there is a draw, or the second player wins?
Input
The single line contains two integers a and b (1 ≤ a, b ≤ 6) — the numbers written on the paper by the first and second player, correspondingly.
Output
Print three integers: the number of ways to throw the dice at which the first player wins, the game ends with a draw or the second player wins, correspondingly.
Examples
Input
2 5
Output
3 0 3
Input
2 4
Output
2 1 3
Note
The dice is a standard cube-shaped six-sided object with each side containing a number from 1 to 6, and where all numbers on all sides are distinct.
You can assume that number a is closer to number x than number b, if |a - x| < |b - x|.
Submitted Solution:
```
#print(" ".join(map(str, r)))
a, b = map(int, input().split())
c = 0
e = 0
r = 0
for i in range(1, 7):
if abs(a-i) < abs(b-i):
c+=1
elif abs(a-i) == abs(b-i):
e+=1
else:
r+=1
print (c, e, r)
``` | instruction | 0 | 42,433 | 19 | 84,866 |
Yes | output | 1 | 42,433 | 19 | 84,867 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same difference, it's a draw.
The first player wrote number a, the second player wrote number b. How many ways to throw a dice are there, at which the first player wins, or there is a draw, or the second player wins?
Input
The single line contains two integers a and b (1 ≤ a, b ≤ 6) — the numbers written on the paper by the first and second player, correspondingly.
Output
Print three integers: the number of ways to throw the dice at which the first player wins, the game ends with a draw or the second player wins, correspondingly.
Examples
Input
2 5
Output
3 0 3
Input
2 4
Output
2 1 3
Note
The dice is a standard cube-shaped six-sided object with each side containing a number from 1 to 6, and where all numbers on all sides are distinct.
You can assume that number a is closer to number x than number b, if |a - x| < |b - x|.
Submitted Solution:
```
n, d = input().split()
n = int (n)
d = int (d)
#n = int(input())
#h = list(map(int, input().split()))
#g = list(map(int, input().split()))
#x1, y1, x2, y2 =map(int,input().split())
#n = int(input())
# = [""]*n
#f = [0]*n
#t = [0]*n
#f = []
#f1 = sorted(f, key = lambda tup: tup[0])
a, b, c = 0, 0, 0
for i in range (1, 7):
if ( abs (n - i) < abs(d -i)):
a += 1
elif ( abs (n - i) > abs(d -i)):
c += 1
else:
b += 1
print (a, b, c)
``` | instruction | 0 | 42,434 | 19 | 84,868 |
Yes | output | 1 | 42,434 | 19 | 84,869 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same difference, it's a draw.
The first player wrote number a, the second player wrote number b. How many ways to throw a dice are there, at which the first player wins, or there is a draw, or the second player wins?
Input
The single line contains two integers a and b (1 ≤ a, b ≤ 6) — the numbers written on the paper by the first and second player, correspondingly.
Output
Print three integers: the number of ways to throw the dice at which the first player wins, the game ends with a draw or the second player wins, correspondingly.
Examples
Input
2 5
Output
3 0 3
Input
2 4
Output
2 1 3
Note
The dice is a standard cube-shaped six-sided object with each side containing a number from 1 to 6, and where all numbers on all sides are distinct.
You can assume that number a is closer to number x than number b, if |a - x| < |b - x|.
Submitted Solution:
```
a,b=map(int,input().split())
q=0
w=0
e=0
for i in range (1,7):
if abs(a-i)<abs(b-i):q+=1;
if abs(a-i)>abs(b-i):e+=1;
if abs(a-i)==abs(b-i):w+=1;
print(q, e, w)
``` | instruction | 0 | 42,435 | 19 | 84,870 |
No | output | 1 | 42,435 | 19 | 84,871 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same difference, it's a draw.
The first player wrote number a, the second player wrote number b. How many ways to throw a dice are there, at which the first player wins, or there is a draw, or the second player wins?
Input
The single line contains two integers a and b (1 ≤ a, b ≤ 6) — the numbers written on the paper by the first and second player, correspondingly.
Output
Print three integers: the number of ways to throw the dice at which the first player wins, the game ends with a draw or the second player wins, correspondingly.
Examples
Input
2 5
Output
3 0 3
Input
2 4
Output
2 1 3
Note
The dice is a standard cube-shaped six-sided object with each side containing a number from 1 to 6, and where all numbers on all sides are distinct.
You can assume that number a is closer to number x than number b, if |a - x| < |b - x|.
Submitted Solution:
```
def main():
[a, b] = [int(_) for _ in input().split()]
wins = [''] * 7
for i in range(1, 7):
points_a = abs(a - i)
points_b = abs(b - i)
wins[i] = 'a' if points_a > points_b \
else 'b' if points_b > points_a \
else '-'
print(wins.count('a'), wins.count('-'), wins.count('b'))
if __name__ == '__main__':
main()
``` | instruction | 0 | 42,436 | 19 | 84,872 |
No | output | 1 | 42,436 | 19 | 84,873 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same difference, it's a draw.
The first player wrote number a, the second player wrote number b. How many ways to throw a dice are there, at which the first player wins, or there is a draw, or the second player wins?
Input
The single line contains two integers a and b (1 ≤ a, b ≤ 6) — the numbers written on the paper by the first and second player, correspondingly.
Output
Print three integers: the number of ways to throw the dice at which the first player wins, the game ends with a draw or the second player wins, correspondingly.
Examples
Input
2 5
Output
3 0 3
Input
2 4
Output
2 1 3
Note
The dice is a standard cube-shaped six-sided object with each side containing a number from 1 to 6, and where all numbers on all sides are distinct.
You can assume that number a is closer to number x than number b, if |a - x| < |b - x|.
Submitted Solution:
```
from math import fabs
a=[int(i)for i in input().split()]
b,c,d=0,0,0
for i in range(1,7):
if fabs(i-a[0])<fabs(i-a[1]):b+=1
elif 2*i==a[0]+a[1]:c+=1
else:d+=1
print(b,c,d)
``` | instruction | 0 | 42,437 | 19 | 84,874 |
No | output | 1 | 42,437 | 19 | 84,875 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same difference, it's a draw.
The first player wrote number a, the second player wrote number b. How many ways to throw a dice are there, at which the first player wins, or there is a draw, or the second player wins?
Input
The single line contains two integers a and b (1 ≤ a, b ≤ 6) — the numbers written on the paper by the first and second player, correspondingly.
Output
Print three integers: the number of ways to throw the dice at which the first player wins, the game ends with a draw or the second player wins, correspondingly.
Examples
Input
2 5
Output
3 0 3
Input
2 4
Output
2 1 3
Note
The dice is a standard cube-shaped six-sided object with each side containing a number from 1 to 6, and where all numbers on all sides are distinct.
You can assume that number a is closer to number x than number b, if |a - x| < |b - x|.
Submitted Solution:
```
a, b = (int(x) for x in input().split())
f = lambda p: p // 2 + 1 if p % 2 else p // 2
a, b = min(a, b), max(a, b)
x, y = f(a + b) - a + 1, 1 - (a + b) % 2
print(x, y, 6 - x - y)
``` | instruction | 0 | 42,438 | 19 | 84,876 |
No | output | 1 | 42,438 | 19 | 84,877 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
As you know, the game of "Nim" is played with n piles of stones, where the i-th pile initially contains ai stones. Two players alternate the turns. During a turn a player picks any non-empty pile and removes any positive number of stones from it. The one who is not able to make a move loses the game.
Petya and Vasya are tired of playing Nim, so they invented their own version of the game and named it the "Gambling Nim". They have n two-sided cards, one side of the i-th card has number ai written on it, while the other side has number bi. At the beginning of the game the players put all the cards on the table, each card only one of its sides up, and this side is chosen independently and uniformly. Thus they obtain a sequence c1, c2, ..., cn, where ci is equal to ai or bi. Then they take n piles of stones, with i-th pile containing exactly ci stones and play Nim. Petya takes the first turn.
Given that both players play optimally, find the probability of Petya's victory. Output the answer as an irreducible fraction.
Input
The first line of the input contains a single integer n (1 ≤ n ≤ 500 000) — the number of cards in the deck.
Each of the following n lines contains the description of one card, consisting of two integers ai and bi (0 ≤ ai, bi ≤ 1018).
Output
Output the answer as an irreducible fraction p / q. If the probability of Petya's victory is 0, print 0/1.
Examples
Input
2
1 1
1 1
Output
0/1
Input
2
1 2
1 2
Output
1/2
Input
3
0 4
1 5
2 3
Output
1/1
Submitted Solution:
```
n=int(input())
k=((-1+(8*n+1)**0.5)/2)
som=k*(k+1)//2
if n-som==0:
print(k)
else:
print
(n-som)
``` | instruction | 0 | 42,538 | 19 | 85,076 |
No | output | 1 | 42,538 | 19 | 85,077 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
As you know, the game of "Nim" is played with n piles of stones, where the i-th pile initially contains ai stones. Two players alternate the turns. During a turn a player picks any non-empty pile and removes any positive number of stones from it. The one who is not able to make a move loses the game.
Petya and Vasya are tired of playing Nim, so they invented their own version of the game and named it the "Gambling Nim". They have n two-sided cards, one side of the i-th card has number ai written on it, while the other side has number bi. At the beginning of the game the players put all the cards on the table, each card only one of its sides up, and this side is chosen independently and uniformly. Thus they obtain a sequence c1, c2, ..., cn, where ci is equal to ai or bi. Then they take n piles of stones, with i-th pile containing exactly ci stones and play Nim. Petya takes the first turn.
Given that both players play optimally, find the probability of Petya's victory. Output the answer as an irreducible fraction.
Input
The first line of the input contains a single integer n (1 ≤ n ≤ 500 000) — the number of cards in the deck.
Each of the following n lines contains the description of one card, consisting of two integers ai and bi (0 ≤ ai, bi ≤ 1018).
Output
Output the answer as an irreducible fraction p / q. If the probability of Petya's victory is 0, print 0/1.
Examples
Input
2
1 1
1 1
Output
0/1
Input
2
1 2
1 2
Output
1/2
Input
3
0 4
1 5
2 3
Output
1/1
Submitted Solution:
```
n=int(input())
k=(-1+(8*n+1)**0.5)//2
som=k*(k+1)//2
if n-som==0:
print(k)
else:
print
(n-som)
``` | instruction | 0 | 42,539 | 19 | 85,078 |
No | output | 1 | 42,539 | 19 | 85,079 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Shrek and the Donkey (as you can guess, they also live in the far away kingdom) decided to play a card game called YAGame. The rules are very simple: initially Shrek holds m cards and the Donkey holds n cards (the players do not see each other's cards), and one more card lies on the table face down so that both players cannot see it as well. Thus, at the beginning of the game there are overall m + n + 1 cards. Besides, the players know which cards the pack of cards consists of and their own cards (but they do not know which card lies on the table and which ones the other player has). The players move in turn and Shrek starts. During a move a player can:
* Try to guess which card is lying on the table. If he guesses correctly, the game ends and he wins. If his guess is wrong, the game also ends but this time the other player wins.
* Name any card from the pack. If the other player has such card, he must show it and put it aside (so that this card is no longer used in the game). If the other player doesn't have such card, he says about that.
Recently Donkey started taking some yellow pills and winning over Shrek. Now Shrek wants to evaluate his chances to win if he too starts taking the pills.
Help Shrek assuming the pills are good in quality and that both players using them start playing in the optimal manner.
Input
The first line contains space-separated integers m and n (0 ≤ m, n ≤ 1000).
Output
Print space-separated probabilities that Shrek wins and Donkey wins correspondingly; the absolute error should not exceed 10 - 9.
Examples
Input
0 3
Output
0.25 0.75
Input
1 0
Output
1 0
Input
1 1
Output
0.5 0.5
Submitted Solution:
```
print('nan')
``` | instruction | 0 | 42,647 | 19 | 85,294 |
No | output | 1 | 42,647 | 19 | 85,295 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ilya plays a card game by the following rules.
A player has several cards. Each card contains two non-negative integers inscribed, one at the top of the card and one at the bottom. At the beginning of the round the player chooses one of his cards to play it. If the top of the card contains number ai, and the bottom contains number bi, then when the player is playing the card, he gets ai points and also gets the opportunity to play additional bi cards. After the playing the card is discarded.
More formally: let's say that there is a counter of the cards that can be played. At the beginning of the round the counter equals one. When a card is played, the counter decreases by one for the played card and increases by the number bi, which is written at the bottom of the card. Then the played card is discarded. If after that the counter is not equal to zero, the player gets the opportunity to play another card from the remaining cards. The round ends when the counter reaches zero or the player runs out of cards.
Of course, Ilya wants to get as many points as possible. Can you determine the maximum number of points he can score provided that you know his cards?
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of cards Ilya has.
Each of the next n lines contains two non-negative space-separated integers — ai and bi (0 ≤ ai, bi ≤ 104) — the numbers, written at the top and the bottom of the i-th card correspondingly.
Output
Print the single number — the maximum number of points you can score in one round by the described rules.
Examples
Input
2
1 0
2 0
Output
2
Input
3
1 0
2 0
0 2
Output
3
Note
In the first sample none of two cards brings extra moves, so you should play the one that will bring more points.
In the second sample you should first play the third card that doesn't bring any points but lets you play both remaining cards. | instruction | 0 | 43,237 | 19 | 86,474 |
Tags: greedy, sortings
Correct Solution:
```
n=int(input())
l=[]
for i in range(n):
l.append([int(x) for x in input().split()])
ans=0
t=0
z=[]
for i in range(n):
if l[i][1]==0:
z.append(l[i][0])
else:
ans+=l[i][0]
t+=l[i][1]-1
z.sort(reverse=True)
ans+=sum(z[0:t+1])
print(ans)
``` | output | 1 | 43,237 | 19 | 86,475 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ilya plays a card game by the following rules.
A player has several cards. Each card contains two non-negative integers inscribed, one at the top of the card and one at the bottom. At the beginning of the round the player chooses one of his cards to play it. If the top of the card contains number ai, and the bottom contains number bi, then when the player is playing the card, he gets ai points and also gets the opportunity to play additional bi cards. After the playing the card is discarded.
More formally: let's say that there is a counter of the cards that can be played. At the beginning of the round the counter equals one. When a card is played, the counter decreases by one for the played card and increases by the number bi, which is written at the bottom of the card. Then the played card is discarded. If after that the counter is not equal to zero, the player gets the opportunity to play another card from the remaining cards. The round ends when the counter reaches zero or the player runs out of cards.
Of course, Ilya wants to get as many points as possible. Can you determine the maximum number of points he can score provided that you know his cards?
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of cards Ilya has.
Each of the next n lines contains two non-negative space-separated integers — ai and bi (0 ≤ ai, bi ≤ 104) — the numbers, written at the top and the bottom of the i-th card correspondingly.
Output
Print the single number — the maximum number of points you can score in one round by the described rules.
Examples
Input
2
1 0
2 0
Output
2
Input
3
1 0
2 0
0 2
Output
3
Note
In the first sample none of two cards brings extra moves, so you should play the one that will bring more points.
In the second sample you should first play the third card that doesn't bring any points but lets you play both remaining cards. | instruction | 0 | 43,238 | 19 | 86,476 |
Tags: greedy, sortings
Correct Solution:
```
#from collections import *
#from math import *
from operator import *
I=lambda:map(int,input().split())
def main():
n=int(input())
a=[]
for _ in range(n):
a.append(tuple(I()))
a.sort(key=itemgetter(0),reverse=True)
a.sort(key=itemgetter(1),reverse=True)
s=1
p=0
pos=0
while(s and pos<n):
p+=a[pos][0]
s+=a[pos][1]
s-=1
pos+=1
print(p)
main()
``` | output | 1 | 43,238 | 19 | 86,477 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ilya plays a card game by the following rules.
A player has several cards. Each card contains two non-negative integers inscribed, one at the top of the card and one at the bottom. At the beginning of the round the player chooses one of his cards to play it. If the top of the card contains number ai, and the bottom contains number bi, then when the player is playing the card, he gets ai points and also gets the opportunity to play additional bi cards. After the playing the card is discarded.
More formally: let's say that there is a counter of the cards that can be played. At the beginning of the round the counter equals one. When a card is played, the counter decreases by one for the played card and increases by the number bi, which is written at the bottom of the card. Then the played card is discarded. If after that the counter is not equal to zero, the player gets the opportunity to play another card from the remaining cards. The round ends when the counter reaches zero or the player runs out of cards.
Of course, Ilya wants to get as many points as possible. Can you determine the maximum number of points he can score provided that you know his cards?
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of cards Ilya has.
Each of the next n lines contains two non-negative space-separated integers — ai and bi (0 ≤ ai, bi ≤ 104) — the numbers, written at the top and the bottom of the i-th card correspondingly.
Output
Print the single number — the maximum number of points you can score in one round by the described rules.
Examples
Input
2
1 0
2 0
Output
2
Input
3
1 0
2 0
0 2
Output
3
Note
In the first sample none of two cards brings extra moves, so you should play the one that will bring more points.
In the second sample you should first play the third card that doesn't bring any points but lets you play both remaining cards. | instruction | 0 | 43,239 | 19 | 86,478 |
Tags: greedy, sortings
Correct Solution:
```
input=__import__('sys').stdin.readline
n = int(input())
lis=[]
li=[]
for i in range(n):
a,b = map(int,input().split())
if b>0:
lis.append([b,a])
else:
li.append([a,b])
lis = sorted(lis,reverse=True)
li.sort(reverse=True)
c=1
ans=0
for i in range(len(lis)):
if lis[i][0]>0:
ans+=lis[i][1]
c+=lis[i][0]-1
#print(ans,c)
for i in range(min(c,len(li))):
ans+=li[i][0]
print(ans)
``` | output | 1 | 43,239 | 19 | 86,479 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ilya plays a card game by the following rules.
A player has several cards. Each card contains two non-negative integers inscribed, one at the top of the card and one at the bottom. At the beginning of the round the player chooses one of his cards to play it. If the top of the card contains number ai, and the bottom contains number bi, then when the player is playing the card, he gets ai points and also gets the opportunity to play additional bi cards. After the playing the card is discarded.
More formally: let's say that there is a counter of the cards that can be played. At the beginning of the round the counter equals one. When a card is played, the counter decreases by one for the played card and increases by the number bi, which is written at the bottom of the card. Then the played card is discarded. If after that the counter is not equal to zero, the player gets the opportunity to play another card from the remaining cards. The round ends when the counter reaches zero or the player runs out of cards.
Of course, Ilya wants to get as many points as possible. Can you determine the maximum number of points he can score provided that you know his cards?
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of cards Ilya has.
Each of the next n lines contains two non-negative space-separated integers — ai and bi (0 ≤ ai, bi ≤ 104) — the numbers, written at the top and the bottom of the i-th card correspondingly.
Output
Print the single number — the maximum number of points you can score in one round by the described rules.
Examples
Input
2
1 0
2 0
Output
2
Input
3
1 0
2 0
0 2
Output
3
Note
In the first sample none of two cards brings extra moves, so you should play the one that will bring more points.
In the second sample you should first play the third card that doesn't bring any points but lets you play both remaining cards. | instruction | 0 | 43,240 | 19 | 86,480 |
Tags: greedy, sortings
Correct Solution:
```
def zip_sorted(a,b):
# sorted by a
a,b = zip(*sorted(zip(a,b),reverse=True))
# sorted by b
sorted(zip(a, b), key=lambda x: x[0],reverse=True)
return a,b
import sys
input = sys.stdin.readline
I = lambda : list(map(int,input().split()))
S = lambda : list(map(str,input().split()))
n,=I()
a = [0]*n
b = [0]*n
for t1 in range(n):
a[t1],b[t1] = I()
b,a = zip_sorted(b,a)
count = 1
pt = 0
for i in range(len(b)):
if count==0:
break
else:
count = count - 1
count += b[i]
pt = pt + a[i]
print(pt)
'''
for i in range(n):
for j in range(n):
for k1 in range(len(a)):
for k2 in range(len(a)):
for k3 in range(len(a)):
'''
``` | output | 1 | 43,240 | 19 | 86,481 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ilya plays a card game by the following rules.
A player has several cards. Each card contains two non-negative integers inscribed, one at the top of the card and one at the bottom. At the beginning of the round the player chooses one of his cards to play it. If the top of the card contains number ai, and the bottom contains number bi, then when the player is playing the card, he gets ai points and also gets the opportunity to play additional bi cards. After the playing the card is discarded.
More formally: let's say that there is a counter of the cards that can be played. At the beginning of the round the counter equals one. When a card is played, the counter decreases by one for the played card and increases by the number bi, which is written at the bottom of the card. Then the played card is discarded. If after that the counter is not equal to zero, the player gets the opportunity to play another card from the remaining cards. The round ends when the counter reaches zero or the player runs out of cards.
Of course, Ilya wants to get as many points as possible. Can you determine the maximum number of points he can score provided that you know his cards?
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of cards Ilya has.
Each of the next n lines contains two non-negative space-separated integers — ai and bi (0 ≤ ai, bi ≤ 104) — the numbers, written at the top and the bottom of the i-th card correspondingly.
Output
Print the single number — the maximum number of points you can score in one round by the described rules.
Examples
Input
2
1 0
2 0
Output
2
Input
3
1 0
2 0
0 2
Output
3
Note
In the first sample none of two cards brings extra moves, so you should play the one that will bring more points.
In the second sample you should first play the third card that doesn't bring any points but lets you play both remaining cards. | instruction | 0 | 43,241 | 19 | 86,482 |
Tags: greedy, sortings
Correct Solution:
```
v=[]
r=0
k=1
for _ in range(int(input())):
a,b=map(int,input().split())
if b==0:v+=[a]
else: r,k=r+a,k+b-1
print(r+sum((sorted(v)[::-1])[:min(len(v),k)]))
``` | output | 1 | 43,241 | 19 | 86,483 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ilya plays a card game by the following rules.
A player has several cards. Each card contains two non-negative integers inscribed, one at the top of the card and one at the bottom. At the beginning of the round the player chooses one of his cards to play it. If the top of the card contains number ai, and the bottom contains number bi, then when the player is playing the card, he gets ai points and also gets the opportunity to play additional bi cards. After the playing the card is discarded.
More formally: let's say that there is a counter of the cards that can be played. At the beginning of the round the counter equals one. When a card is played, the counter decreases by one for the played card and increases by the number bi, which is written at the bottom of the card. Then the played card is discarded. If after that the counter is not equal to zero, the player gets the opportunity to play another card from the remaining cards. The round ends when the counter reaches zero or the player runs out of cards.
Of course, Ilya wants to get as many points as possible. Can you determine the maximum number of points he can score provided that you know his cards?
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of cards Ilya has.
Each of the next n lines contains two non-negative space-separated integers — ai and bi (0 ≤ ai, bi ≤ 104) — the numbers, written at the top and the bottom of the i-th card correspondingly.
Output
Print the single number — the maximum number of points you can score in one round by the described rules.
Examples
Input
2
1 0
2 0
Output
2
Input
3
1 0
2 0
0 2
Output
3
Note
In the first sample none of two cards brings extra moves, so you should play the one that will bring more points.
In the second sample you should first play the third card that doesn't bring any points but lets you play both remaining cards. | instruction | 0 | 43,242 | 19 | 86,484 |
Tags: greedy, sortings
Correct Solution:
```
t = int(input())
mat=[]
for _ in range(t):
a,b = map(int,input().split())
mat.append([a,b])
k = mat.copy()
c=0
p=1
k.sort(key=lambda x:x[0],reverse=True)
mat.sort(key=lambda x:x[1],reverse=True)
for i in range(len(mat)):
if mat[i][1]==0:
break
p+= mat[i][1]
c+=mat[i][0]
p-=1
if mat[i] in k:
k.remove(mat[i])
for i in k:
if p==0:
break
c+=i[0]
p-=1
print(c)
``` | output | 1 | 43,242 | 19 | 86,485 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ilya plays a card game by the following rules.
A player has several cards. Each card contains two non-negative integers inscribed, one at the top of the card and one at the bottom. At the beginning of the round the player chooses one of his cards to play it. If the top of the card contains number ai, and the bottom contains number bi, then when the player is playing the card, he gets ai points and also gets the opportunity to play additional bi cards. After the playing the card is discarded.
More formally: let's say that there is a counter of the cards that can be played. At the beginning of the round the counter equals one. When a card is played, the counter decreases by one for the played card and increases by the number bi, which is written at the bottom of the card. Then the played card is discarded. If after that the counter is not equal to zero, the player gets the opportunity to play another card from the remaining cards. The round ends when the counter reaches zero or the player runs out of cards.
Of course, Ilya wants to get as many points as possible. Can you determine the maximum number of points he can score provided that you know his cards?
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of cards Ilya has.
Each of the next n lines contains two non-negative space-separated integers — ai and bi (0 ≤ ai, bi ≤ 104) — the numbers, written at the top and the bottom of the i-th card correspondingly.
Output
Print the single number — the maximum number of points you can score in one round by the described rules.
Examples
Input
2
1 0
2 0
Output
2
Input
3
1 0
2 0
0 2
Output
3
Note
In the first sample none of two cards brings extra moves, so you should play the one that will bring more points.
In the second sample you should first play the third card that doesn't bring any points but lets you play both remaining cards. | instruction | 0 | 43,243 | 19 | 86,486 |
Tags: greedy, sortings
Correct Solution:
```
n = int(input().strip())
L = []
points,turns = 0,1
for i in range(n):
t = list(map(int,input().strip().split()))
if t[1] == 0:
L.append(t)
else:
points += t[0]
turns -= 1
turns += (t[1])
def f1(x):
return x[0]
L.sort(reverse=True,key=f1)
#print(L)
#print(turns)
j = min(len(L),turns)
#print(j)
m = 0
for i in range(0,j):
m += L[i][0]
print(str(points+m))
``` | output | 1 | 43,243 | 19 | 86,487 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ilya plays a card game by the following rules.
A player has several cards. Each card contains two non-negative integers inscribed, one at the top of the card and one at the bottom. At the beginning of the round the player chooses one of his cards to play it. If the top of the card contains number ai, and the bottom contains number bi, then when the player is playing the card, he gets ai points and also gets the opportunity to play additional bi cards. After the playing the card is discarded.
More formally: let's say that there is a counter of the cards that can be played. At the beginning of the round the counter equals one. When a card is played, the counter decreases by one for the played card and increases by the number bi, which is written at the bottom of the card. Then the played card is discarded. If after that the counter is not equal to zero, the player gets the opportunity to play another card from the remaining cards. The round ends when the counter reaches zero or the player runs out of cards.
Of course, Ilya wants to get as many points as possible. Can you determine the maximum number of points he can score provided that you know his cards?
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of cards Ilya has.
Each of the next n lines contains two non-negative space-separated integers — ai and bi (0 ≤ ai, bi ≤ 104) — the numbers, written at the top and the bottom of the i-th card correspondingly.
Output
Print the single number — the maximum number of points you can score in one round by the described rules.
Examples
Input
2
1 0
2 0
Output
2
Input
3
1 0
2 0
0 2
Output
3
Note
In the first sample none of two cards brings extra moves, so you should play the one that will bring more points.
In the second sample you should first play the third card that doesn't bring any points but lets you play both remaining cards. | instruction | 0 | 43,244 | 19 | 86,488 |
Tags: greedy, sortings
Correct Solution:
```
n=int(input())
l1=[]
cnt=1
ans=0
for i in range(n):
a,b=map(int,input().split())
if b==0:
l1.append(a)
else:
cnt+=b-1
ans+=a
l1.sort()
if cnt>len(l1):
ans+=sum(l1)
else:
leng=len(l1)
for i in range(cnt):
ans+=l1[leng-1-i]
print(ans)
``` | output | 1 | 43,244 | 19 | 86,489 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ilya plays a card game by the following rules.
A player has several cards. Each card contains two non-negative integers inscribed, one at the top of the card and one at the bottom. At the beginning of the round the player chooses one of his cards to play it. If the top of the card contains number ai, and the bottom contains number bi, then when the player is playing the card, he gets ai points and also gets the opportunity to play additional bi cards. After the playing the card is discarded.
More formally: let's say that there is a counter of the cards that can be played. At the beginning of the round the counter equals one. When a card is played, the counter decreases by one for the played card and increases by the number bi, which is written at the bottom of the card. Then the played card is discarded. If after that the counter is not equal to zero, the player gets the opportunity to play another card from the remaining cards. The round ends when the counter reaches zero or the player runs out of cards.
Of course, Ilya wants to get as many points as possible. Can you determine the maximum number of points he can score provided that you know his cards?
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of cards Ilya has.
Each of the next n lines contains two non-negative space-separated integers — ai and bi (0 ≤ ai, bi ≤ 104) — the numbers, written at the top and the bottom of the i-th card correspondingly.
Output
Print the single number — the maximum number of points you can score in one round by the described rules.
Examples
Input
2
1 0
2 0
Output
2
Input
3
1 0
2 0
0 2
Output
3
Note
In the first sample none of two cards brings extra moves, so you should play the one that will bring more points.
In the second sample you should first play the third card that doesn't bring any points but lets you play both remaining cards.
Submitted Solution:
```
n = int(input())
l = []
s = 0
h = 1
for x in range(n):
i, j = [int(x) for x in input().split(' ')]
if j:
h += j - 1
s += i
else:
l.append(i)
l.sort(reverse=True)
for x in l:
if h == 0:
break
s += x
h -= 1
print(s)
``` | instruction | 0 | 43,245 | 19 | 86,490 |
Yes | output | 1 | 43,245 | 19 | 86,491 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ilya plays a card game by the following rules.
A player has several cards. Each card contains two non-negative integers inscribed, one at the top of the card and one at the bottom. At the beginning of the round the player chooses one of his cards to play it. If the top of the card contains number ai, and the bottom contains number bi, then when the player is playing the card, he gets ai points and also gets the opportunity to play additional bi cards. After the playing the card is discarded.
More formally: let's say that there is a counter of the cards that can be played. At the beginning of the round the counter equals one. When a card is played, the counter decreases by one for the played card and increases by the number bi, which is written at the bottom of the card. Then the played card is discarded. If after that the counter is not equal to zero, the player gets the opportunity to play another card from the remaining cards. The round ends when the counter reaches zero or the player runs out of cards.
Of course, Ilya wants to get as many points as possible. Can you determine the maximum number of points he can score provided that you know his cards?
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of cards Ilya has.
Each of the next n lines contains two non-negative space-separated integers — ai and bi (0 ≤ ai, bi ≤ 104) — the numbers, written at the top and the bottom of the i-th card correspondingly.
Output
Print the single number — the maximum number of points you can score in one round by the described rules.
Examples
Input
2
1 0
2 0
Output
2
Input
3
1 0
2 0
0 2
Output
3
Note
In the first sample none of two cards brings extra moves, so you should play the one that will bring more points.
In the second sample you should first play the third card that doesn't bring any points but lets you play both remaining cards.
Submitted Solution:
```
n=int(input())
l1=[]
l2=[]
c=1
for i in range(n):
a,b=map(int,input().split())
l1.append([a,b])
l2.append([b,a])
l1.sort()
l2.sort()
s=0
j=n-1
while(c!=0 and j>=0):
c=c+l2[j][0]
s=s+l2[j][1]
c=c-1
j=j-1
print(s)
``` | instruction | 0 | 43,246 | 19 | 86,492 |
Yes | output | 1 | 43,246 | 19 | 86,493 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ilya plays a card game by the following rules.
A player has several cards. Each card contains two non-negative integers inscribed, one at the top of the card and one at the bottom. At the beginning of the round the player chooses one of his cards to play it. If the top of the card contains number ai, and the bottom contains number bi, then when the player is playing the card, he gets ai points and also gets the opportunity to play additional bi cards. After the playing the card is discarded.
More formally: let's say that there is a counter of the cards that can be played. At the beginning of the round the counter equals one. When a card is played, the counter decreases by one for the played card and increases by the number bi, which is written at the bottom of the card. Then the played card is discarded. If after that the counter is not equal to zero, the player gets the opportunity to play another card from the remaining cards. The round ends when the counter reaches zero or the player runs out of cards.
Of course, Ilya wants to get as many points as possible. Can you determine the maximum number of points he can score provided that you know his cards?
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of cards Ilya has.
Each of the next n lines contains two non-negative space-separated integers — ai and bi (0 ≤ ai, bi ≤ 104) — the numbers, written at the top and the bottom of the i-th card correspondingly.
Output
Print the single number — the maximum number of points you can score in one round by the described rules.
Examples
Input
2
1 0
2 0
Output
2
Input
3
1 0
2 0
0 2
Output
3
Note
In the first sample none of two cards brings extra moves, so you should play the one that will bring more points.
In the second sample you should first play the third card that doesn't bring any points but lets you play both remaining cards.
Submitted Solution:
```
n=int(input())
a=[]
count0=0
for i in range(n):
b,c=list(map(int,input().split()))
a.append((b,c))
if c==0:
count0+=1
if count0==n:
sum1=0
a.sort(key=lambda x:x[0])
print(a[-1][0])
exit()
totalsum=0
a.sort(key=lambda x:x[1],reverse=True)
sum1=0
sum2=0
r=[]
for i in a:
if i[1]==0:
r.append(i)
r.sort(key=lambda x:x[0],reverse=True)
count=0
for i in range(n):
if a[i][1]!=0:
sum1+=a[i][1]
sum2+=a[i][0]
count+=1
y=sum1-count+1
#print(y)
for i in r:
if y>0:
sum2+=i[0]
y-=1
print(sum2)
``` | instruction | 0 | 43,247 | 19 | 86,494 |
Yes | output | 1 | 43,247 | 19 | 86,495 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ilya plays a card game by the following rules.
A player has several cards. Each card contains two non-negative integers inscribed, one at the top of the card and one at the bottom. At the beginning of the round the player chooses one of his cards to play it. If the top of the card contains number ai, and the bottom contains number bi, then when the player is playing the card, he gets ai points and also gets the opportunity to play additional bi cards. After the playing the card is discarded.
More formally: let's say that there is a counter of the cards that can be played. At the beginning of the round the counter equals one. When a card is played, the counter decreases by one for the played card and increases by the number bi, which is written at the bottom of the card. Then the played card is discarded. If after that the counter is not equal to zero, the player gets the opportunity to play another card from the remaining cards. The round ends when the counter reaches zero or the player runs out of cards.
Of course, Ilya wants to get as many points as possible. Can you determine the maximum number of points he can score provided that you know his cards?
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of cards Ilya has.
Each of the next n lines contains two non-negative space-separated integers — ai and bi (0 ≤ ai, bi ≤ 104) — the numbers, written at the top and the bottom of the i-th card correspondingly.
Output
Print the single number — the maximum number of points you can score in one round by the described rules.
Examples
Input
2
1 0
2 0
Output
2
Input
3
1 0
2 0
0 2
Output
3
Note
In the first sample none of two cards brings extra moves, so you should play the one that will bring more points.
In the second sample you should first play the third card that doesn't bring any points but lets you play both remaining cards.
Submitted Solution:
```
n = int(input())
arr = []
for i in range(n):
a,b = map(int, input().split())
arr.append([a,b])
arr.sort(reverse = True, key = lambda x: x[0])
arr.sort(reverse = True, key = lambda x: x[1])
points = arr[0][0]
cards = arr[0][1]
i = 1
while cards > 0 and i < len(arr):
points += arr[i][0]
cards += arr[i][1]
cards -= 1
i+=1
print(points)
``` | instruction | 0 | 43,248 | 19 | 86,496 |
Yes | output | 1 | 43,248 | 19 | 86,497 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ilya plays a card game by the following rules.
A player has several cards. Each card contains two non-negative integers inscribed, one at the top of the card and one at the bottom. At the beginning of the round the player chooses one of his cards to play it. If the top of the card contains number ai, and the bottom contains number bi, then when the player is playing the card, he gets ai points and also gets the opportunity to play additional bi cards. After the playing the card is discarded.
More formally: let's say that there is a counter of the cards that can be played. At the beginning of the round the counter equals one. When a card is played, the counter decreases by one for the played card and increases by the number bi, which is written at the bottom of the card. Then the played card is discarded. If after that the counter is not equal to zero, the player gets the opportunity to play another card from the remaining cards. The round ends when the counter reaches zero or the player runs out of cards.
Of course, Ilya wants to get as many points as possible. Can you determine the maximum number of points he can score provided that you know his cards?
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of cards Ilya has.
Each of the next n lines contains two non-negative space-separated integers — ai and bi (0 ≤ ai, bi ≤ 104) — the numbers, written at the top and the bottom of the i-th card correspondingly.
Output
Print the single number — the maximum number of points you can score in one round by the described rules.
Examples
Input
2
1 0
2 0
Output
2
Input
3
1 0
2 0
0 2
Output
3
Note
In the first sample none of two cards brings extra moves, so you should play the one that will bring more points.
In the second sample you should first play the third card that doesn't bring any points but lets you play both remaining cards.
Submitted Solution:
```
n = int(input())
a = []
z = 1
points = 0
tr = False
for i in range(n):
x, y = map(int,input().split())
if y != 0:
tr = True
a.append([x, y])
if tr == True:
a = sorted(a, key = lambda x: x[1], reverse = True)
else:
a = sorted(a, key = lambda x: x[0], reverse = True)
for i in a:
z -= 1
z += i[1]
points += i[0]
if z == 0:
break
print(points)
``` | instruction | 0 | 43,249 | 19 | 86,498 |
No | output | 1 | 43,249 | 19 | 86,499 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ilya plays a card game by the following rules.
A player has several cards. Each card contains two non-negative integers inscribed, one at the top of the card and one at the bottom. At the beginning of the round the player chooses one of his cards to play it. If the top of the card contains number ai, and the bottom contains number bi, then when the player is playing the card, he gets ai points and also gets the opportunity to play additional bi cards. After the playing the card is discarded.
More formally: let's say that there is a counter of the cards that can be played. At the beginning of the round the counter equals one. When a card is played, the counter decreases by one for the played card and increases by the number bi, which is written at the bottom of the card. Then the played card is discarded. If after that the counter is not equal to zero, the player gets the opportunity to play another card from the remaining cards. The round ends when the counter reaches zero or the player runs out of cards.
Of course, Ilya wants to get as many points as possible. Can you determine the maximum number of points he can score provided that you know his cards?
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of cards Ilya has.
Each of the next n lines contains two non-negative space-separated integers — ai and bi (0 ≤ ai, bi ≤ 104) — the numbers, written at the top and the bottom of the i-th card correspondingly.
Output
Print the single number — the maximum number of points you can score in one round by the described rules.
Examples
Input
2
1 0
2 0
Output
2
Input
3
1 0
2 0
0 2
Output
3
Note
In the first sample none of two cards brings extra moves, so you should play the one that will bring more points.
In the second sample you should first play the third card that doesn't bring any points but lets you play both remaining cards.
Submitted Solution:
```
#ya8sdfy7897z89222
``` | instruction | 0 | 43,250 | 19 | 86,500 |
No | output | 1 | 43,250 | 19 | 86,501 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ilya plays a card game by the following rules.
A player has several cards. Each card contains two non-negative integers inscribed, one at the top of the card and one at the bottom. At the beginning of the round the player chooses one of his cards to play it. If the top of the card contains number ai, and the bottom contains number bi, then when the player is playing the card, he gets ai points and also gets the opportunity to play additional bi cards. After the playing the card is discarded.
More formally: let's say that there is a counter of the cards that can be played. At the beginning of the round the counter equals one. When a card is played, the counter decreases by one for the played card and increases by the number bi, which is written at the bottom of the card. Then the played card is discarded. If after that the counter is not equal to zero, the player gets the opportunity to play another card from the remaining cards. The round ends when the counter reaches zero or the player runs out of cards.
Of course, Ilya wants to get as many points as possible. Can you determine the maximum number of points he can score provided that you know his cards?
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of cards Ilya has.
Each of the next n lines contains two non-negative space-separated integers — ai and bi (0 ≤ ai, bi ≤ 104) — the numbers, written at the top and the bottom of the i-th card correspondingly.
Output
Print the single number — the maximum number of points you can score in one round by the described rules.
Examples
Input
2
1 0
2 0
Output
2
Input
3
1 0
2 0
0 2
Output
3
Note
In the first sample none of two cards brings extra moves, so you should play the one that will bring more points.
In the second sample you should first play the third card that doesn't bring any points but lets you play both remaining cards.
Submitted Solution:
```
flag = False
n = int(input())
ino =[]
A = []
B = []
for i in range(n):
A.append(list(map(int, input().split())))
#+list(str(i))
B.append(list(map(int, A[i])))
#print(A)
#print(B)
for i in range(n):
while i > 0 and A[i][0] > A[i - 1][0]:
A[i], A[i - 1] = A[i - 1], A[i]
i -= 1
for i in range(n):
while i > 0 and B[i][1] > B[i - 1][1]:
B[i], B[i - 1] = B[i - 1], B[i]
i -= 1
#print('GGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGg')
#print(A)
#print(B)
bb = 1
wincount = 0
ost = 0
j = 0
while j < n and i < n and bb > 0:
bb -= 1
bb += B[i][1]
wincount += B[i][0]
if bb == 1:
wincount = wincount - B[i][0] + A[j][0]
break
while bb > 1:
if A[j] == [-1, -1]:
j += 1
break
else:
if A[j] != B[i]:
wincount += A[j][0]
bb -= 1
j += 1
else:
j += 1
A[j] = [-1, -1]
flag = True
if not flag:
k = j
for k in range(len(B)):
if A[k] == B[i]:
A[k] = [-1, -1]
print(wincount)
``` | instruction | 0 | 43,251 | 19 | 86,502 |
No | output | 1 | 43,251 | 19 | 86,503 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ilya plays a card game by the following rules.
A player has several cards. Each card contains two non-negative integers inscribed, one at the top of the card and one at the bottom. At the beginning of the round the player chooses one of his cards to play it. If the top of the card contains number ai, and the bottom contains number bi, then when the player is playing the card, he gets ai points and also gets the opportunity to play additional bi cards. After the playing the card is discarded.
More formally: let's say that there is a counter of the cards that can be played. At the beginning of the round the counter equals one. When a card is played, the counter decreases by one for the played card and increases by the number bi, which is written at the bottom of the card. Then the played card is discarded. If after that the counter is not equal to zero, the player gets the opportunity to play another card from the remaining cards. The round ends when the counter reaches zero or the player runs out of cards.
Of course, Ilya wants to get as many points as possible. Can you determine the maximum number of points he can score provided that you know his cards?
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of cards Ilya has.
Each of the next n lines contains two non-negative space-separated integers — ai and bi (0 ≤ ai, bi ≤ 104) — the numbers, written at the top and the bottom of the i-th card correspondingly.
Output
Print the single number — the maximum number of points you can score in one round by the described rules.
Examples
Input
2
1 0
2 0
Output
2
Input
3
1 0
2 0
0 2
Output
3
Note
In the first sample none of two cards brings extra moves, so you should play the one that will bring more points.
In the second sample you should first play the third card that doesn't bring any points but lets you play both remaining cards.
Submitted Solution:
```
testcases = int(input())
import sys
def get_ints(): return list(map(int, sys.stdin.readline().strip().split()))
nochance = []
ans = 0
totalchance = 0
for testcase in range(testcases):
temparr = get_ints()
point = temparr[0]
chance = temparr[1]
if chance >= 1:
ans += point
totalchance += chance
else:
nochance.append(point)
nochance = sorted(nochance)
nochance = nochance[::-1]
if totalchance == 0 :
print(nochance[0])
else:
index = 0
n = len(nochance)
while index < n:
ans += nochance[index]
index += 1
print(ans)
``` | instruction | 0 | 43,252 | 19 | 86,504 |
No | output | 1 | 43,252 | 19 | 86,505 |
Provide tags and a correct Python 3 solution for this coding contest problem.
<image>
You have one chip and one chance to play roulette. Are you feeling lucky?
Output
Print your bet. Your chip must be placed entirely within some square (not on an edge or a corner shared by adjacent squares). | instruction | 0 | 43,510 | 19 | 87,020 |
Tags: probabilities
Correct Solution:
```
x=[2,4,6,8,10,11,13,15,17,20,22,24,26,28,29,31,33,35]
if input() in x:
print("input")
else:
print("Red")
``` | output | 1 | 43,510 | 19 | 87,021 |
Provide tags and a correct Python 3 solution for this coding contest problem.
<image>
You have one chip and one chance to play roulette. Are you feeling lucky?
Output
Print your bet. Your chip must be placed entirely within some square (not on an edge or a corner shared by adjacent squares). | instruction | 0 | 43,511 | 19 | 87,022 |
Tags: probabilities
Correct Solution:
```
from random import randint
print("black")
``` | output | 1 | 43,511 | 19 | 87,023 |
Provide tags and a correct Python 3 solution for this coding contest problem.
<image>
You have one chip and one chance to play roulette. Are you feeling lucky?
Output
Print your bet. Your chip must be placed entirely within some square (not on an edge or a corner shared by adjacent squares). | instruction | 0 | 43,512 | 19 | 87,024 |
Tags: probabilities
Correct Solution:
```
print('red')
``` | output | 1 | 43,512 | 19 | 87,025 |
Provide tags and a correct Python 3 solution for this coding contest problem.
<image>
You have one chip and one chance to play roulette. Are you feeling lucky?
Output
Print your bet. Your chip must be placed entirely within some square (not on an edge or a corner shared by adjacent squares). | instruction | 0 | 43,513 | 19 | 87,026 |
Tags: probabilities
Correct Solution:
```
print('2nd 12')
``` | output | 1 | 43,513 | 19 | 87,027 |
Provide tags and a correct Python 3 solution for this coding contest problem.
<image>
You have one chip and one chance to play roulette. Are you feeling lucky?
Output
Print your bet. Your chip must be placed entirely within some square (not on an edge or a corner shared by adjacent squares). | instruction | 0 | 43,514 | 19 | 87,028 |
Tags: probabilities
Correct Solution:
```
from random import randint
a=input()
b=randint(1,2)
if b==1:
print('Red')
else:
print('Black')
``` | output | 1 | 43,514 | 19 | 87,029 |
Provide tags and a correct Python 3 solution for this coding contest problem.
<image>
You have one chip and one chance to play roulette. Are you feeling lucky?
Output
Print your bet. Your chip must be placed entirely within some square (not on an edge or a corner shared by adjacent squares). | instruction | 0 | 43,515 | 19 | 87,030 |
Tags: probabilities
Correct Solution:
```
import random
if(random.random() > 0.52):
print('black')
else:
print('red')
``` | output | 1 | 43,515 | 19 | 87,031 |
Provide tags and a correct Python 3 solution for this coding contest problem.
<image>
You have one chip and one chance to play roulette. Are you feeling lucky?
Output
Print your bet. Your chip must be placed entirely within some square (not on an edge or a corner shared by adjacent squares). | instruction | 0 | 43,516 | 19 | 87,032 |
Tags: probabilities
Correct Solution:
```
print("BLACK")
``` | output | 1 | 43,516 | 19 | 87,033 |
Provide tags and a correct Python 3 solution for this coding contest problem.
<image>
You have one chip and one chance to play roulette. Are you feeling lucky?
Output
Print your bet. Your chip must be placed entirely within some square (not on an edge or a corner shared by adjacent squares). | instruction | 0 | 43,517 | 19 | 87,034 |
Tags: probabilities
Correct Solution:
```
print('19 to 36')
``` | output | 1 | 43,517 | 19 | 87,035 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
You have one chip and one chance to play roulette. Are you feeling lucky?
Output
Print your bet. Your chip must be placed entirely within some square (not on an edge or a corner shared by adjacent squares).
Submitted Solution:
```
import random
random.seed()
x = random.randint(0, 1)
if x == 0:
print('red')
else:
print('black')
``` | instruction | 0 | 43,518 | 19 | 87,036 |
Yes | output | 1 | 43,518 | 19 | 87,037 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
You have one chip and one chance to play roulette. Are you feeling lucky?
Output
Print your bet. Your chip must be placed entirely within some square (not on an edge or a corner shared by adjacent squares).
Submitted Solution:
```
from random import randint
r = randint(1, 2)
if r == 1:
print('Red')
else:
print('Black')
``` | instruction | 0 | 43,519 | 19 | 87,038 |
Yes | output | 1 | 43,519 | 19 | 87,039 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
You have one chip and one chance to play roulette. Are you feeling lucky?
Output
Print your bet. Your chip must be placed entirely within some square (not on an edge or a corner shared by adjacent squares).
Submitted Solution:
```
#tum gaandu h
import random
a=['1 to 18','19 to 36']
print(a[random.randint(0,1)])
``` | instruction | 0 | 43,520 | 19 | 87,040 |
Yes | output | 1 | 43,520 | 19 | 87,041 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
You have one chip and one chance to play roulette. Are you feeling lucky?
Output
Print your bet. Your chip must be placed entirely within some square (not on an edge or a corner shared by adjacent squares).
Submitted Solution:
```
def mp():
return map(int, input().split())
print('Black')
``` | instruction | 0 | 43,521 | 19 | 87,042 |
Yes | output | 1 | 43,521 | 19 | 87,043 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
You have one chip and one chance to play roulette. Are you feeling lucky?
Output
Print your bet. Your chip must be placed entirely within some square (not on an edge or a corner shared by adjacent squares).
Submitted Solution:
```
print("1 1")
``` | instruction | 0 | 43,522 | 19 | 87,044 |
No | output | 1 | 43,522 | 19 | 87,045 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
You have one chip and one chance to play roulette. Are you feeling lucky?
Output
Print your bet. Your chip must be placed entirely within some square (not on an edge or a corner shared by adjacent squares).
Submitted Solution:
```
print('3')
``` | instruction | 0 | 43,523 | 19 | 87,046 |
No | output | 1 | 43,523 | 19 | 87,047 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
You have one chip and one chance to play roulette. Are you feeling lucky?
Output
Print your bet. Your chip must be placed entirely within some square (not on an edge or a corner shared by adjacent squares).
Submitted Solution:
```
print(13)
# 2
``` | instruction | 0 | 43,524 | 19 | 87,048 |
No | output | 1 | 43,524 | 19 | 87,049 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
You have one chip and one chance to play roulette. Are you feeling lucky?
Output
Print your bet. Your chip must be placed entirely within some square (not on an edge or a corner shared by adjacent squares).
Submitted Solution:
```
print('2nd 12')
``` | instruction | 0 | 43,525 | 19 | 87,050 |
No | output | 1 | 43,525 | 19 | 87,051 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Gennady was presented with a set of domino for his birthday. The set consists of 28 different dominoes of size 2 × 1. Both halves of each domino contain one digit from 0 to 6.
0-0 0-1 0-2 0-3 0-4 0-5 0-6
1-1 1-2 1-3 1-4 1-5 1-6
2-2 2-3 2-4 2-5 2-6
3-3 3-4 3-5 3-6
4-4 4-5 4-6
5-5 5-6
6-6
The figure that consists of 28 dominoes is called magic, if it can be fully covered with 14 non-intersecting squares of size 2 × 2 so that each square contained four equal numbers. Every time Gennady assembles a magic figure, some magic properties of the set appear — he wins the next contest. Gennady noticed that he can't assemble a figure that has already been assembled, otherwise someone else wins the contest.
<image>
Gennady chose a checked field of size n × m and put there rectangular chips of sizes 1 × 2 and 2 × 1. Each chip fully occupies exactly two neighboring squares of the field. Those chips do not overlap but they can touch each other. Overall the field has exactly 28 chips, equal to the number of dominoes in the set. Now Gennady wants to replace each chip with a domino so that a magic figure appeared as a result. Different chips should be replaced by different dominoes. Determine in what number of contests Gennady can win over at the given position of the chips. You are also required to find one of the possible ways of replacing chips with dominoes to win the next Codeforces round.
Input
The first line contains two positive integers n and m (1 ≤ n, m ≤ 30). Each of the following n lines contains m characters, which is the position of chips on the field. The dots stand for empty spaces, Latin letters from "a" to "z" and "A", "B" stand for the positions of the chips. There are exactly 28 chips on the field. The squares covered by the same chip are marked by the same letter, different chips are marked by different letters. It is guaranteed that the field's description is correct.
It is also guaranteed that at least one solution exists.
Output
Print on the first line the number of ways to replace chips with dominoes to get a magic figure. That is the total number of contests that can be won using this arrangement of the chips. Next n lines containing m characters each, should contain a field from dots and numbers from 0 to 6 — any of the possible solutions. All dominoes should be different.
Examples
Input
8 8
.aabbcc.
.defghi.
kdefghij
klmnopqj
.lmnopq.
.rstuvw.
xrstuvwy
xzzAABBy
Output
10080
.001122.
.001122.
33440055
33440055
.225566.
.225566.
66113344
66113344
Submitted Solution:
```
n, k = map(int,input().split())
for i in range(k):
if n%10 == 0:
n = n//10
else:
n-=1
print(n)
``` | instruction | 0 | 43,526 | 19 | 87,052 |
No | output | 1 | 43,526 | 19 | 87,053 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Gennady was presented with a set of domino for his birthday. The set consists of 28 different dominoes of size 2 × 1. Both halves of each domino contain one digit from 0 to 6.
0-0 0-1 0-2 0-3 0-4 0-5 0-6
1-1 1-2 1-3 1-4 1-5 1-6
2-2 2-3 2-4 2-5 2-6
3-3 3-4 3-5 3-6
4-4 4-5 4-6
5-5 5-6
6-6
The figure that consists of 28 dominoes is called magic, if it can be fully covered with 14 non-intersecting squares of size 2 × 2 so that each square contained four equal numbers. Every time Gennady assembles a magic figure, some magic properties of the set appear — he wins the next contest. Gennady noticed that he can't assemble a figure that has already been assembled, otherwise someone else wins the contest.
<image>
Gennady chose a checked field of size n × m and put there rectangular chips of sizes 1 × 2 and 2 × 1. Each chip fully occupies exactly two neighboring squares of the field. Those chips do not overlap but they can touch each other. Overall the field has exactly 28 chips, equal to the number of dominoes in the set. Now Gennady wants to replace each chip with a domino so that a magic figure appeared as a result. Different chips should be replaced by different dominoes. Determine in what number of contests Gennady can win over at the given position of the chips. You are also required to find one of the possible ways of replacing chips with dominoes to win the next Codeforces round.
Input
The first line contains two positive integers n and m (1 ≤ n, m ≤ 30). Each of the following n lines contains m characters, which is the position of chips on the field. The dots stand for empty spaces, Latin letters from "a" to "z" and "A", "B" stand for the positions of the chips. There are exactly 28 chips on the field. The squares covered by the same chip are marked by the same letter, different chips are marked by different letters. It is guaranteed that the field's description is correct.
It is also guaranteed that at least one solution exists.
Output
Print on the first line the number of ways to replace chips with dominoes to get a magic figure. That is the total number of contests that can be won using this arrangement of the chips. Next n lines containing m characters each, should contain a field from dots and numbers from 0 to 6 — any of the possible solutions. All dominoes should be different.
Examples
Input
8 8
.aabbcc.
.defghi.
kdefghij
klmnopqj
.lmnopq.
.rstuvw.
xrstuvwy
xzzAABBy
Output
10080
.001122.
.001122.
33440055
33440055
.225566.
.225566.
66113344
66113344
Submitted Solution:
```
players = input()
count = 0
if len(players)> 7:
for i in range(0,(len(players)-7)):
if players[i] == players[i+1] and players[i] == players[i+1] and players[i] == players[i+2] and players[i] == players[i+3] and players[i] == players[i+4] and players[i] == players[i+5] and players[i] == players[i+6]:
count = count +1
else:
print('NO')
count = 500000
if count > 0 and count!= 50000:
print('YES')
elif count ==0:
print('NO')
``` | instruction | 0 | 43,527 | 19 | 87,054 |
No | output | 1 | 43,527 | 19 | 87,055 |
Provide a correct Python 3 solution for this coding contest problem.
We have N cards numbered 1, 2, ..., N. Card i (1 \leq i \leq N) has an integer A_i written in red ink on one side and an integer B_i written in blue ink on the other side. Initially, these cards are arranged from left to right in the order from Card 1 to Card N, with the red numbers facing up.
Determine whether it is possible to have a non-decreasing sequence facing up from left to right (that is, for each i (1 \leq i \leq N - 1), the integer facing up on the (i+1)-th card from the left is not less than the integer facing up on the i-th card from the left) by repeating the operation below. If the answer is yes, find the minimum number of operations required to achieve it.
* Choose an integer i (1 \leq i \leq N - 1). Swap the i-th and (i+1)-th cards from the left, then flip these two cards.
Constraints
* 1 \leq N \leq 18
* 1 \leq A_i, B_i \leq 50 (1 \leq i \leq N)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
B_1 B_2 ... B_N
Output
If it is impossible to have a non-decreasing sequence, print `-1`. If it is possible, print the minimum number of operations required to achieve it.
Examples
Input
3
3 4 3
3 2 3
Output
1
Input
2
2 1
1 2
Output
-1
Input
4
1 2 3 4
5 6 7 8
Output
0
Input
5
28 15 22 43 31
20 22 43 33 32
Output
-1
Input
5
4 46 6 38 43
33 15 18 27 37
Output
3 | instruction | 0 | 43,576 | 19 | 87,152 |
"Correct Solution:
```
N = int(input())
A = list(map(int, input().split()))
B = list(map(int, input().split()))
v = [[0, 0] for _ in range(N)]
s = []
ans = 500
for i in range(1<<N):
tmp = 0
for j in range(N):
if ((i>>j)&1): v[j] = [B[j], j]
else: v[j] = [A[j], j]
for j in range(N):
p = j
while (p and v[p][0] < v[p-1][0]):
v[p], v[p-1] = v[p-1], v[p]
tmp += 1
p -= 1
for j in range(N):
if (((i>>v[j][1])+v[j][1]-j)&1):
s.append(v[j][0]*500+j)
if (len(s)&1):
tmp = 500
s.pop()
while s:
p = s.pop()
q = s.pop()
if ((p-q)&1): tmp += p-q
else: tmp += 500
ans = min(ans, tmp)
if ans < 500:
print(ans)
else:
print(-1)
``` | output | 1 | 43,576 | 19 | 87,153 |
Provide a correct Python 3 solution for this coding contest problem.
We have N cards numbered 1, 2, ..., N. Card i (1 \leq i \leq N) has an integer A_i written in red ink on one side and an integer B_i written in blue ink on the other side. Initially, these cards are arranged from left to right in the order from Card 1 to Card N, with the red numbers facing up.
Determine whether it is possible to have a non-decreasing sequence facing up from left to right (that is, for each i (1 \leq i \leq N - 1), the integer facing up on the (i+1)-th card from the left is not less than the integer facing up on the i-th card from the left) by repeating the operation below. If the answer is yes, find the minimum number of operations required to achieve it.
* Choose an integer i (1 \leq i \leq N - 1). Swap the i-th and (i+1)-th cards from the left, then flip these two cards.
Constraints
* 1 \leq N \leq 18
* 1 \leq A_i, B_i \leq 50 (1 \leq i \leq N)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
B_1 B_2 ... B_N
Output
If it is impossible to have a non-decreasing sequence, print `-1`. If it is possible, print the minimum number of operations required to achieve it.
Examples
Input
3
3 4 3
3 2 3
Output
1
Input
2
2 1
1 2
Output
-1
Input
4
1 2 3 4
5 6 7 8
Output
0
Input
5
28 15 22 43 31
20 22 43 33 32
Output
-1
Input
5
4 46 6 38 43
33 15 18 27 37
Output
3 | instruction | 0 | 43,577 | 19 | 87,154 |
"Correct Solution:
```
# from collections import defaultdict,deque
# import sys,heapq,bisect,math,itertools,string,queue,copy,time
# sys.setrecursionlimit(10**8)
#
#
import sys
import itertools
INF = float("INF")
N = int(input())
AA = list(map(int, sys.stdin.readline().split()))
BB = list(map(int, sys.stdin.readline().split()))
cards = set()
for i,(a,b) in enumerate(zip(AA,BB)):
if i%2 == 0:
cards.add((a, b, i))
else:
cards.add((b, a, i))
# In[]:
def solve(ii):
tmp = 0
for _ in range(N):
next = []
for k, i in enumerate(ii):
if i == 0:
tmp += k
else:
next.append(i-1)
ii = next[:]
return tmp
# In[]:
ans = INF
for Acards in itertools.combinations(cards, (N+1)//2):
Bcards = cards - set(Acards)
Ais = sorted([(card[0], card[2]) for card in Acards])
Bis = sorted([(card[1], card[2]) for card in Bcards])
nums = []
ii = []
for i in range(N):
if i%2 == 0:
n,i = Ais[i//2]
else:
n,i = Bis[i//2]
nums.append(n)
ii.append(i)
if nums != sorted(nums):
continue
else:
ans = min(ans,solve(ii))
if ans == 0:
print(0)
sys.exit()
if ans == INF:
print(-1)
else:
print(ans)
``` | output | 1 | 43,577 | 19 | 87,155 |
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