message stringlengths 2 67k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 463 109k | cluster float64 19 19 | __index_level_0__ int64 926 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sugoroku
problem
JOI is playing sugoroku alone. There are N squares in a straight line in this sugoroku, and each has a movement instruction written on it. The starting point is the 1st square and the goal is the Nth square. JOI repeats the following until he reaches the goal.
Roll the dice and proceed from the current square by the number of rolls, and follow the instructions of that square. Do not follow the instructions of the square to which you moved according to the instructions.
The goal is not only when you stop at the Nth square, but also when the destination exceeds the Nth square.
Create a program that outputs how many times you roll the dice to reach the goal when you are given a sugoroku board and M dice rolls.
input
The input consists of multiple datasets. Each dataset is given in the following format.
Each dataset consists of 1 + N + M rows.
Two integers N, M (2 ≤ N ≤ 1000, 1 ≤ M ≤ 1000) are written on the first line of the input, separated by blanks. N represents the number of sugoroku squares, and M represents the number of dice given.
In the following N lines, integers between -999 and 999 are written one by one. The integer on the 1 + i line (1 ≤ i ≤ N) represents the indication of the sugoroku i-th cell. Let X be the written integer. When X = 0, it indicates "do nothing", when X> 0, it indicates "advance X mass", and when X <0, it indicates "| X | mass return". However, | X | represents the absolute value of X.
In the following M line, integers from 1 to 6 are written one by one, and the number on the 1 + N + j line (1 ≤ j ≤ M) represents the dice roll that appears on the jth time.
However, the number of lines 2 and 1 + N is always 0. There is no cell with instructions to move to the cell before the first cell. In addition, the number of times the dice are rolled is M or less in any scoring input data.
When both N and M are 0, it indicates the end of input. The number of data sets does not exceed 5.
output
For each data set, an integer indicating how many times the dice are rolled to reach the goal is output on one line.
Input / output example
Input example
10 5
0
0
Five
6
-3
8
1
8
-Four
0
1
3
Five
1
Five
10 10
0
-1
-1
Four
Four
-Five
0
1
-6
0
1
Five
2
Four
6
Five
Five
Four
1
6
0 0
Output example
Five
6
The following figure shows the first input example.
<image>
The following figure shows the second input example.
<image>
The above question sentences and the data used for the automatic referee are the question sentences created and published by the Japan Committee for Information Olympics and the test data for scoring.
Example
Input
10 5
0
0
5
6
-3
8
1
8
-4
0
1
3
5
1
5
10 10
0
-1
-1
4
4
-5
0
1
-6
0
1
5
2
4
6
5
5
4
1
6
0 0
Output
5
6
Submitted Solution:
```
for e in iter(input,'0 0'):
N,M=map(int,e.split())
S=[int(input())for _ in[0]*N]
print(S)
p=b=1
for i in range(M):
d=int(input())
p+=d
p+=S[~-p]
if(N<=p)*b:print(-~i);b=0
``` | instruction | 0 | 80,757 | 19 | 161,514 |
No | output | 1 | 80,757 | 19 | 161,515 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sugoroku
problem
JOI is playing sugoroku alone. There are N squares in a straight line in this sugoroku, and each has a movement instruction written on it. The starting point is the 1st square and the goal is the Nth square. JOI repeats the following until he reaches the goal.
Roll the dice and proceed from the current square by the number of rolls, and follow the instructions of that square. Do not follow the instructions of the square to which you moved according to the instructions.
The goal is not only when you stop at the Nth square, but also when the destination exceeds the Nth square.
Create a program that outputs how many times you roll the dice to reach the goal when you are given a sugoroku board and M dice rolls.
input
The input consists of multiple datasets. Each dataset is given in the following format.
Each dataset consists of 1 + N + M rows.
Two integers N, M (2 ≤ N ≤ 1000, 1 ≤ M ≤ 1000) are written on the first line of the input, separated by blanks. N represents the number of sugoroku squares, and M represents the number of dice given.
In the following N lines, integers between -999 and 999 are written one by one. The integer on the 1 + i line (1 ≤ i ≤ N) represents the indication of the sugoroku i-th cell. Let X be the written integer. When X = 0, it indicates "do nothing", when X> 0, it indicates "advance X mass", and when X <0, it indicates "| X | mass return". However, | X | represents the absolute value of X.
In the following M line, integers from 1 to 6 are written one by one, and the number on the 1 + N + j line (1 ≤ j ≤ M) represents the dice roll that appears on the jth time.
However, the number of lines 2 and 1 + N is always 0. There is no cell with instructions to move to the cell before the first cell. In addition, the number of times the dice are rolled is M or less in any scoring input data.
When both N and M are 0, it indicates the end of input. The number of data sets does not exceed 5.
output
For each data set, an integer indicating how many times the dice are rolled to reach the goal is output on one line.
Input / output example
Input example
10 5
0
0
Five
6
-3
8
1
8
-Four
0
1
3
Five
1
Five
10 10
0
-1
-1
Four
Four
-Five
0
1
-6
0
1
Five
2
Four
6
Five
Five
Four
1
6
0 0
Output example
Five
6
The following figure shows the first input example.
<image>
The following figure shows the second input example.
<image>
The above question sentences and the data used for the automatic referee are the question sentences created and published by the Japan Committee for Information Olympics and the test data for scoring.
Example
Input
10 5
0
0
5
6
-3
8
1
8
-4
0
1
3
5
1
5
10 10
0
-1
-1
4
4
-5
0
1
-6
0
1
5
2
4
6
5
5
4
1
6
0 0
Output
5
6
Submitted Solution:
```
for e in iter(input,'0 0'):
N,M=map(int,e.split())
k=p=1
S=[int(input()) for _ in[0]*N]
for d in[int(input())for _ in[0]*M]:
p+=n if n-1<=p+i else i+S[p+i]
if n<=p:break
k+=1
print(k)
``` | instruction | 0 | 80,758 | 19 | 161,516 |
No | output | 1 | 80,758 | 19 | 161,517 |
Provide a correct Python 3 solution for this coding contest problem.
Construct a dice from a given sequence of integers in the same way as Dice I.
You are given integers on the top face and the front face after the dice was rolled in the same way as Dice I. Write a program to print an integer on the right side face.
<image>
Constraints
* $0 \leq $ the integer assigned to a face $ \leq 100$
* The integers are all different
* $1 \leq q \leq 24$
Input
In the first line, six integers assigned to faces are given in ascending order of their corresponding labels. In the second line, the number of questions $q$ is given.
In the following $q$ lines, $q$ questions are given. Each question consists of two integers on the top face and the front face respectively.
Output
For each question, print the integer on the right side face.
Example
Input
1 2 3 4 5 6
3
6 5
1 3
3 2
Output
3
5
6 | instruction | 0 | 80,797 | 19 | 161,594 |
"Correct Solution:
```
dice_init = input().split()
dicry = {'search':"152304",'hittop':'024135', 'hitfront':'310542'}
num = int(input())
def dicing(x):
global dice
dice = [dice[int(c)] for c in dicry[x]]
for _ in range(num):
dice = dice_init
top, front = map(int, input().split())
while True:
if int(dice[0]) == top and int(dice[1]) == front:
break
elif int(dice[0]) == top:
dicing('hittop')
elif int(dice[1]) == front:
dicing('hitfront')
else:
dicing('search')
print(dice[2])
``` | output | 1 | 80,797 | 19 | 161,595 |
Provide a correct Python 3 solution for this coding contest problem.
Construct a dice from a given sequence of integers in the same way as Dice I.
You are given integers on the top face and the front face after the dice was rolled in the same way as Dice I. Write a program to print an integer on the right side face.
<image>
Constraints
* $0 \leq $ the integer assigned to a face $ \leq 100$
* The integers are all different
* $1 \leq q \leq 24$
Input
In the first line, six integers assigned to faces are given in ascending order of their corresponding labels. In the second line, the number of questions $q$ is given.
In the following $q$ lines, $q$ questions are given. Each question consists of two integers on the top face and the front face respectively.
Output
For each question, print the integer on the right side face.
Example
Input
1 2 3 4 5 6
3
6 5
1 3
3 2
Output
3
5
6 | instruction | 0 | 80,798 | 19 | 161,596 |
"Correct Solution:
```
rot_set = [
(1,2,4,3,1), #0
(0,3,5,2,0), #1
(0,1,5,4,0), #2
(0,4,5,1,0), #3
(0,2,5,3,0), #4
(1,3,4,2,1) #5
]
dice_int = list(map(int, input().split()))
q = int(input())
right_face = []
for _ in range(q):
a, b = map(int, input().split())
a_idx = dice_int.index(a)
b_idx = dice_int.index(b)
for i in range(6):
for j in range(4):
if (a_idx, b_idx) == (rot_set[i][j], rot_set[i][j+1]):
right_face.append(dice_int[i])
for i in range(q):
print(right_face[i])
``` | output | 1 | 80,798 | 19 | 161,597 |
Provide a correct Python 3 solution for this coding contest problem.
Construct a dice from a given sequence of integers in the same way as Dice I.
You are given integers on the top face and the front face after the dice was rolled in the same way as Dice I. Write a program to print an integer on the right side face.
<image>
Constraints
* $0 \leq $ the integer assigned to a face $ \leq 100$
* The integers are all different
* $1 \leq q \leq 24$
Input
In the first line, six integers assigned to faces are given in ascending order of their corresponding labels. In the second line, the number of questions $q$ is given.
In the following $q$ lines, $q$ questions are given. Each question consists of two integers on the top face and the front face respectively.
Output
For each question, print the integer on the right side face.
Example
Input
1 2 3 4 5 6
3
6 5
1 3
3 2
Output
3
5
6 | instruction | 0 | 80,799 | 19 | 161,598 |
"Correct Solution:
```
class Dice:
def __init__(self,numbers):
self.surface=numbers
def find_right_side(self,top,flont):
tf=str(self.surface.index(top))+str(self.surface.index(flont))
if tf in '12431':
return int(self.surface[0])
elif tf in '03520':
return int(self.surface[1])
elif tf in '01540':
return int(self.surface[2])
elif tf in '04510':
return int(self.surface[3])
elif tf in '02530':
return int(self.surface[4])
else:
return int(self.surface[5])
dice=Dice(input().split())
q=int(input())
for i in range(q):
top,flont=input().split()
print(dice.find_right_side(top,flont))
``` | output | 1 | 80,799 | 19 | 161,599 |
Provide a correct Python 3 solution for this coding contest problem.
Construct a dice from a given sequence of integers in the same way as Dice I.
You are given integers on the top face and the front face after the dice was rolled in the same way as Dice I. Write a program to print an integer on the right side face.
<image>
Constraints
* $0 \leq $ the integer assigned to a face $ \leq 100$
* The integers are all different
* $1 \leq q \leq 24$
Input
In the first line, six integers assigned to faces are given in ascending order of their corresponding labels. In the second line, the number of questions $q$ is given.
In the following $q$ lines, $q$ questions are given. Each question consists of two integers on the top face and the front face respectively.
Output
For each question, print the integer on the right side face.
Example
Input
1 2 3 4 5 6
3
6 5
1 3
3 2
Output
3
5
6 | instruction | 0 | 80,800 | 19 | 161,600 |
"Correct Solution:
```
import random
def rotateDice(direction: str, dice: dict) -> dict:
if direction == 'S':
dice['S'], dice['F'], dice['N'], dice['B'] = dice['F'], dice['N'], dice['B'], dice['S']
elif direction == 'E':
dice['E'], dice['F'], dice['W'], dice['B'] = dice['F'], dice['W'], dice['B'], dice['E']
elif direction == 'W':
dice['W'], dice['F'], dice['E'], dice['B'] = dice['F'], dice['E'], dice['B'], dice['W']
elif direction == 'N':
dice['N'], dice['F'], dice['S'], dice['B'] = dice['F'], dice['S'], dice['B'], dice['N']
return dice
dice_list = list(map(int, input().split()))
dice = {'FSEWNB'[i]: dice_list[i] for i in range(6)}
for i in range(int(input())):
f, s = map(int, input().split())
while True:
dice = rotateDice(random.choice(['S', 'E', 'W', 'N']), dice)
if dice['F'] == f and dice['S'] == s:
print(dice['E'])
break
``` | output | 1 | 80,800 | 19 | 161,601 |
Provide a correct Python 3 solution for this coding contest problem.
Construct a dice from a given sequence of integers in the same way as Dice I.
You are given integers on the top face and the front face after the dice was rolled in the same way as Dice I. Write a program to print an integer on the right side face.
<image>
Constraints
* $0 \leq $ the integer assigned to a face $ \leq 100$
* The integers are all different
* $1 \leq q \leq 24$
Input
In the first line, six integers assigned to faces are given in ascending order of their corresponding labels. In the second line, the number of questions $q$ is given.
In the following $q$ lines, $q$ questions are given. Each question consists of two integers on the top face and the front face respectively.
Output
For each question, print the integer on the right side face.
Example
Input
1 2 3 4 5 6
3
6 5
1 3
3 2
Output
3
5
6 | instruction | 0 | 80,801 | 19 | 161,602 |
"Correct Solution:
```
class dice:
men = [0] * 7
def __init__(self, li):
self.men = [0] + li
def move0(self, a, b, c, d):
self.men[a], self.men[b], self.men[c], self.men[d] = self.men[b], self.men[c], self.men[d], self.men[a]
def move(self, h):
if h == "N":
self.move0(1, 2, 6, 5)
elif h == "S":
self.move0(1, 5, 6, 2)
elif h == "W":
self.move0(1, 3, 6, 4)
elif h == "E":
self.move0(1, 4, 6, 3)
def move2(self, a, b):
if self.men[1] != a:
for i, ss in [(2, "N"), (3, "W"), (4, "E"), (5, "S"), (6, "NN")]:
if self.men[i] == a:
for s in ss:
self.move(s)
break
if self.men[2] != b:
if b == self.men[3]:
self.move0(2, 3, 5, 4)
elif b == self.men[4]:
self.move0(2, 4, 5, 3)
else:
self.men[2], self.men[5], self.men[3], self.men[4] = self.men[5], self.men[2], self.men[4], self.men[3]
saikoro = dice(list(map(int, input().split())))
for _ in range(int(input())):
saikoro.move2(*map(int, input().split()))
print(saikoro.men[3])
``` | output | 1 | 80,801 | 19 | 161,603 |
Provide a correct Python 3 solution for this coding contest problem.
Construct a dice from a given sequence of integers in the same way as Dice I.
You are given integers on the top face and the front face after the dice was rolled in the same way as Dice I. Write a program to print an integer on the right side face.
<image>
Constraints
* $0 \leq $ the integer assigned to a face $ \leq 100$
* The integers are all different
* $1 \leq q \leq 24$
Input
In the first line, six integers assigned to faces are given in ascending order of their corresponding labels. In the second line, the number of questions $q$ is given.
In the following $q$ lines, $q$ questions are given. Each question consists of two integers on the top face and the front face respectively.
Output
For each question, print the integer on the right side face.
Example
Input
1 2 3 4 5 6
3
6 5
1 3
3 2
Output
3
5
6 | instruction | 0 | 80,802 | 19 | 161,604 |
"Correct Solution:
```
N = list(map(int,input().split()))
q = int(input())
S = []
S += [42,23,35,54],
S += [14,46,63,31],
S += [12,26,65,51],
S += [21,15,56,62],
S += [13,36,64,41],
S += [24,45,53,32],
for i in range(q):
a,b = map(int,input().split())
c = [str(N.index(a)+1)]
c += str(N.index(b)+1),
c = "".join(c)
for j in range(6):
if int(c) in S[j]:
print(N[j])
``` | output | 1 | 80,802 | 19 | 161,605 |
Provide a correct Python 3 solution for this coding contest problem.
Construct a dice from a given sequence of integers in the same way as Dice I.
You are given integers on the top face and the front face after the dice was rolled in the same way as Dice I. Write a program to print an integer on the right side face.
<image>
Constraints
* $0 \leq $ the integer assigned to a face $ \leq 100$
* The integers are all different
* $1 \leq q \leq 24$
Input
In the first line, six integers assigned to faces are given in ascending order of their corresponding labels. In the second line, the number of questions $q$ is given.
In the following $q$ lines, $q$ questions are given. Each question consists of two integers on the top face and the front face respectively.
Output
For each question, print the integer on the right side face.
Example
Input
1 2 3 4 5 6
3
6 5
1 3
3 2
Output
3
5
6 | instruction | 0 | 80,803 | 19 | 161,606 |
"Correct Solution:
```
dice_ = [int(i) for i in input().split()]
dice = {
(0,0,1):dice_[0],
(0,-1,0):dice_[1],
(1,0,0):dice_[2],
(-1,0,0):dice_[3],
(0,1,0):dice_[4],
(0,0,-1):dice_[5]
}
rdice = {
dice_[0]:(0,0,1),
dice_[1]:(0,-1,0),
dice_[2]:(1,0,0),
dice_[3]:(-1,0,0),
dice_[4]:(0,1,0),
dice_[5]:(0,0,-1)
}
def cross(a,b):
return(a[1]*b[2]-a[2]*b[1], a[2]*b[0]-a[0]*b[2], a[0]*b[1]-a[1]*b[0])
n = int(input())
for _ in range(n):
a_,b_ = [int(i) for i in input().split()]
a = rdice[a_]
b = rdice[b_]
print(dice[cross(a,b)])
``` | output | 1 | 80,803 | 19 | 161,607 |
Provide a correct Python 3 solution for this coding contest problem.
Construct a dice from a given sequence of integers in the same way as Dice I.
You are given integers on the top face and the front face after the dice was rolled in the same way as Dice I. Write a program to print an integer on the right side face.
<image>
Constraints
* $0 \leq $ the integer assigned to a face $ \leq 100$
* The integers are all different
* $1 \leq q \leq 24$
Input
In the first line, six integers assigned to faces are given in ascending order of their corresponding labels. In the second line, the number of questions $q$ is given.
In the following $q$ lines, $q$ questions are given. Each question consists of two integers on the top face and the front face respectively.
Output
For each question, print the integer on the right side face.
Example
Input
1 2 3 4 5 6
3
6 5
1 3
3 2
Output
3
5
6 | instruction | 0 | 80,804 | 19 | 161,608 |
"Correct Solution:
```
c=[int(i) for i in input().split()]
Q=int(input())
inp=[map(int,input().split()) for i in range(Q)]
d=[(0,0,1),(-1,0,0),(0,1,0),(0,-1,0),(1,0,0),(0,0,-1)]
def north(r):
res=[]
for p in r:
res.append((p[2],p[1],-p[0]))
return res
def south(r):
res=[]
for p in r:
res.append((-p[2],p[1],p[0]))
return res
def east(r):
res=[]
for p in r:
res.append((p[0],p[2],-p[1]))
return res
def west(r):
res=[]
for p in r:
res.append((p[0],-p[2],p[1]))
return res
for k in range(Q):
x=(0,0,0)
y=(0,0,0)
a,b=inp[k]
for i in range(6):
if a==c[i]:
x=d[i]
if b==c[i]:
y=d[i]
z=(y[1]*x[2]-y[2]*x[1],y[2]*x[0]-y[0]*x[2],y[0]*x[1]-y[1]*x[0])
for i in range(6):
if d[i]==z:
print(c[i])
``` | output | 1 | 80,804 | 19 | 161,609 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Construct a dice from a given sequence of integers in the same way as Dice I.
You are given integers on the top face and the front face after the dice was rolled in the same way as Dice I. Write a program to print an integer on the right side face.
<image>
Constraints
* $0 \leq $ the integer assigned to a face $ \leq 100$
* The integers are all different
* $1 \leq q \leq 24$
Input
In the first line, six integers assigned to faces are given in ascending order of their corresponding labels. In the second line, the number of questions $q$ is given.
In the following $q$ lines, $q$ questions are given. Each question consists of two integers on the top face and the front face respectively.
Output
For each question, print the integer on the right side face.
Example
Input
1 2 3 4 5 6
3
6 5
1 3
3 2
Output
3
5
6
Submitted Solution:
```
d, q = list(map(int, input().split())), int(input())
dd = {v: k for k, v in enumerate(d)}
dms = ((1, 2, 4, 3), (0, 3, 5, 2), (0, 1, 5, 4), (0, 4, 5, 1), (0, 2, 5, 3), (1, 3, 4, 2))
while q:
t, f = map(int, input().split())
dm = dms[dd[t]]
print(d[dm[(dm.index(dd[f]) + 1) % 4]])
q -= 1
``` | instruction | 0 | 80,805 | 19 | 161,610 |
Yes | output | 1 | 80,805 | 19 | 161,611 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Construct a dice from a given sequence of integers in the same way as Dice I.
You are given integers on the top face and the front face after the dice was rolled in the same way as Dice I. Write a program to print an integer on the right side face.
<image>
Constraints
* $0 \leq $ the integer assigned to a face $ \leq 100$
* The integers are all different
* $1 \leq q \leq 24$
Input
In the first line, six integers assigned to faces are given in ascending order of their corresponding labels. In the second line, the number of questions $q$ is given.
In the following $q$ lines, $q$ questions are given. Each question consists of two integers on the top face and the front face respectively.
Output
For each question, print the integer on the right side face.
Example
Input
1 2 3 4 5 6
3
6 5
1 3
3 2
Output
3
5
6
Submitted Solution:
```
def move(dice, order):
if order == "E":
temp = dice[0]
dice[0] = dice[3]
dice[3] = dice[5]
dice[5] = dice[2]
dice[2] = temp
elif order == "N":
temp = dice[0]
dice[0] = dice[1]
dice[1] = dice[5]
dice[5] = dice[4]
dice[4] = temp
elif order == "S":
temp = dice[0]
dice[0] = dice[4]
dice[4] = dice[5]
dice[5] = dice[1]
dice[1] = temp
elif order == "W":
temp = dice[0]
dice[0] = dice[2]
dice[2] = dice[5]
dice[5] = dice[3]
dice[3] = temp
else:
pass
return dice
def roll(dice):
temp = dice[1]
dice[1] = dice[2]
dice[2] = dice[4]
dice[4] = dice[3]
dice[3] = temp
return dice
dice = list(map(int, input().split()))
q = int(input())
for i in range(q):
up, front = map(int, input().split())
cnt = 0
while (dice[0] != up and cnt <= 3):
dice = move(dice, "E")
cnt += 1
while dice[0] != up:
dice = move(dice, "N")
while dice[1] != front:
dice = roll(dice)
print(dice[2])
``` | instruction | 0 | 80,806 | 19 | 161,612 |
Yes | output | 1 | 80,806 | 19 | 161,613 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Construct a dice from a given sequence of integers in the same way as Dice I.
You are given integers on the top face and the front face after the dice was rolled in the same way as Dice I. Write a program to print an integer on the right side face.
<image>
Constraints
* $0 \leq $ the integer assigned to a face $ \leq 100$
* The integers are all different
* $1 \leq q \leq 24$
Input
In the first line, six integers assigned to faces are given in ascending order of their corresponding labels. In the second line, the number of questions $q$ is given.
In the following $q$ lines, $q$ questions are given. Each question consists of two integers on the top face and the front face respectively.
Output
For each question, print the integer on the right side face.
Example
Input
1 2 3 4 5 6
3
6 5
1 3
3 2
Output
3
5
6
Submitted Solution:
```
data = list(map(int, input().split()))
n = int(input())
dice = ['12431', '03520', '01540', '04510', '02530', '13421']
for i in range(n):
up, front = map(int, input().split())
u = data.index(up)
f = data.index(front)
a = dice[u].find(str(f))
print(data[int(dice[u][a+1])])
``` | instruction | 0 | 80,807 | 19 | 161,614 |
Yes | output | 1 | 80,807 | 19 | 161,615 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Construct a dice from a given sequence of integers in the same way as Dice I.
You are given integers on the top face and the front face after the dice was rolled in the same way as Dice I. Write a program to print an integer on the right side face.
<image>
Constraints
* $0 \leq $ the integer assigned to a face $ \leq 100$
* The integers are all different
* $1 \leq q \leq 24$
Input
In the first line, six integers assigned to faces are given in ascending order of their corresponding labels. In the second line, the number of questions $q$ is given.
In the following $q$ lines, $q$ questions are given. Each question consists of two integers on the top face and the front face respectively.
Output
For each question, print the integer on the right side face.
Example
Input
1 2 3 4 5 6
3
6 5
1 3
3 2
Output
3
5
6
Submitted Solution:
```
class Dice:
def __init__(self,t,f,r,l,b,u):
self.t = t
self.f = f
self.r = r
self.l = l
self.b = b
self.u = u
self.a=[t,f,r,l,b,u]
self.direction={'S':(4,0,2,3,5,1),'N':(1,5,2,3,0,4),'E':(3,1,0,5,4,2),'W':(2,1,5,0,4,3),'Y':(0,3,1,4,2,5)}
def roll(self,d):
self.a=[self.a[i] for i in self.direction[d]]
self.t = self.a[0]
self.f = self.a[1]
self.r = self.a[2]
self.l = self.a[3]
self.b = self.a[4]
self.u = self.a[5]
t,f,r,l,b,u=map(int,input().split())
dice=Dice(t,f,r,l,b,u)
n=int(input())
s='SSSEWW'
yw='YYY'
for j in range(n):
t,f=map(int,input().split())
for d in s:
if dice.t==t:
break
dice.roll(d)
for t in yw:
if dice.f==f:
break
dice.roll(t)
print(dice.r)
``` | instruction | 0 | 80,808 | 19 | 161,616 |
Yes | output | 1 | 80,808 | 19 | 161,617 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Construct a dice from a given sequence of integers in the same way as Dice I.
You are given integers on the top face and the front face after the dice was rolled in the same way as Dice I. Write a program to print an integer on the right side face.
<image>
Constraints
* $0 \leq $ the integer assigned to a face $ \leq 100$
* The integers are all different
* $1 \leq q \leq 24$
Input
In the first line, six integers assigned to faces are given in ascending order of their corresponding labels. In the second line, the number of questions $q$ is given.
In the following $q$ lines, $q$ questions are given. Each question consists of two integers on the top face and the front face respectively.
Output
For each question, print the integer on the right side face.
Example
Input
1 2 3 4 5 6
3
6 5
1 3
3 2
Output
3
5
6
Submitted Solution:
```
# coding: utf-8
# ?????????????????¨????????????
class Dice(object):
def __init__(self):
# ???????????????????????°
# ????????¶???
self.dice = (2, 5), (3, 4), (1, 6) # x, y, z
self.ax = [[0, False], [1, False], [2, False]]
self.axmap = [0, 1, 2]
self.mm = {"N": (0, 2), "S": (2, 0), "E": (1, 2), "W": (2, 1), "R": (0, 1), "L": (1, 0)}
def rotate(self, dir):
def rot(k, r):
# k?????????????????????????????????????????§?§????
# r?????????????????¢???????§????
t = self.axmap[r]
self.axmap[k], self.axmap[r] = t, self.axmap[k]
self.ax[t][1] = not self.ax[t][1]
rot(*self.mm[dir])
def top(self):
z = self.ax[self.axmap[2]]
return self.dice[z[0]][z[1]]
def right(self):
y = self.ax[self.axmap[1]]
return self.dice[y[0]][y[1]]
def front(self):
x = self.ax[self.axmap[0]]
return self.dice[x[0]][x[1]]
if __name__=="__main__":
dice = Dice()
labels = input().split()
q = int(input())
for _ in range(q):
a, b = input().split()
p = labels.index(a) + 1
for _ in range(4):
if p==dice.top():
break
dice.rotate("N")
for _ in range(4):
if p==dice.top():
break
dice.rotate("E")
p = labels.index(b) + 1
for _ in range(4):
if p==dice.front():
break;
dice.rotate("R")
print(dice.right())
``` | instruction | 0 | 80,809 | 19 | 161,618 |
No | output | 1 | 80,809 | 19 | 161,619 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Construct a dice from a given sequence of integers in the same way as Dice I.
You are given integers on the top face and the front face after the dice was rolled in the same way as Dice I. Write a program to print an integer on the right side face.
<image>
Constraints
* $0 \leq $ the integer assigned to a face $ \leq 100$
* The integers are all different
* $1 \leq q \leq 24$
Input
In the first line, six integers assigned to faces are given in ascending order of their corresponding labels. In the second line, the number of questions $q$ is given.
In the following $q$ lines, $q$ questions are given. Each question consists of two integers on the top face and the front face respectively.
Output
For each question, print the integer on the right side face.
Example
Input
1 2 3 4 5 6
3
6 5
1 3
3 2
Output
3
5
6
Submitted Solution:
```
class Dice2():
def front(self,up,front,dice):
#index == 5
if (up==dice[2] and front==dice[1])
or(up==dice[1] and front==dice[3])
or(up==dice[3] and front==dice[4])
or(up==dice[4] and front==dice[2]):
return dice[5]
#index == 4
elif (up==dice[0] and front==dice[2])
or(up==dice[2] and front==dice[5])
or(up==dice[5] and front==dice[3])
or(up==dice[3] and front==dice[0]):
return dice[4]
#index == 3
elif (front==dice[5] and up==dice[4])
or(front==dice[4] and up==dice[0])
or(front==dice[0] and up==dice[1])
or(front==dice[1] and up==dice[5]):
return dice[3]
#index == 2
elif (up==dice[5] and front==dice[4])
or(up==dice[4] and front==dice[0])
or(up==dice[0] and front==dice[1])
or(up==dice[1] and front==dice[5]):
return dice[2]
#index == 1
elif (front==dice[0] and up==dice[2])
or(front==dice[2] and up==dice[5])
or(front==dice[5] and up==dice[3])
or(front==dice[3] and up==dice[0]):
return dice[1]
#index == 0
else:
return dice[0]
dice = [int(i) for i in input().split()]
p = int(input())
dc2 = Dice2()
ans = []
for i in range(p):
up,front = map(int,input().split())
ans.append(dc2.front(up,front,dice))
for i in range(p):
print(ans[i])
``` | instruction | 0 | 80,810 | 19 | 161,620 |
No | output | 1 | 80,810 | 19 | 161,621 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Construct a dice from a given sequence of integers in the same way as Dice I.
You are given integers on the top face and the front face after the dice was rolled in the same way as Dice I. Write a program to print an integer on the right side face.
<image>
Constraints
* $0 \leq $ the integer assigned to a face $ \leq 100$
* The integers are all different
* $1 \leq q \leq 24$
Input
In the first line, six integers assigned to faces are given in ascending order of their corresponding labels. In the second line, the number of questions $q$ is given.
In the following $q$ lines, $q$ questions are given. Each question consists of two integers on the top face and the front face respectively.
Output
For each question, print the integer on the right side face.
Example
Input
1 2 3 4 5 6
3
6 5
1 3
3 2
Output
3
5
6
Submitted Solution:
```
class Dice:
def __init__(self, face_vals):
self.faces = dict(zip(['top', 'front', 'right',
'left', 'back', 'bottom'], face_vals.split()))
def roll(self, direction):
if direction == 'N':
self.faces['top'], self.faces['front'], self.faces['bottom'], \
self.faces['back'] = self.faces['front'], self.faces['bottom'], \
self.faces['back'], self.faces['top']
elif direction == 'S':
self.faces['top'], self.faces['front'], self.faces['bottom'], \
self.faces['back'] = self.faces['back'], self.faces['top'], \
self.faces['front'], self.faces['bottom']
elif direction == 'E':
self.faces['top'], self.faces['right'], self.faces['bottom'], \
self.faces['left'] = self.faces['left'], self.faces['top'], \
self.faces['right'], self.faces['bottom']
else:
self.faces['top'], self.faces['right'], self.faces['bottom'], \
self.faces['left'] = self.faces['right'], self.faces['bottom'], \
self.faces['left'], self.faces['top']
def _revolve(self, direction):
if direction == 'R':
self.faces['front'], self.faces['left'], self.faces['back'], \
self.faces['right'] = self.faces['right'], self.faces['front'], \
self.faces['left'], self.faces['back']
else:
self.faces['front'], self.faces['left'], self.faces['back'], \
self.faces['right'] = self.faces['left'], self.faces['back'], \
self.faces['right'], self.faces['front']
def show_right_face(self, top, front):
if front == self.faces['back']:
if top == self.faces['top']:
self._revolve('R')
self._revolve('R')
else:
self.roll('S')
self.roll('S')
elif front == self.faces['right']:
self._revolve('R')
elif front == self.faces['left']:
self._revolve('L')
elif front == self.faces('bottom'):
self.roll('N')
if top == self.faces['bottom']:
self.roll('E')
self.roll('E')
elif top == self.faces['right']:
self.roll('W')
elif top == self.faces['left']:
self.roll('E')
print(self.faces['right'])
import sys
face_vals = sys.stdin.readline()
dice = Dice(face_vals)
n = int(sys.stdin.readline())
for i in range(n):
top, front = sys.stdin.readline().split()
dice.show_right_face(top, front)
``` | instruction | 0 | 80,811 | 19 | 161,622 |
No | output | 1 | 80,811 | 19 | 161,623 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Construct a dice from a given sequence of integers in the same way as Dice I.
You are given integers on the top face and the front face after the dice was rolled in the same way as Dice I. Write a program to print an integer on the right side face.
<image>
Constraints
* $0 \leq $ the integer assigned to a face $ \leq 100$
* The integers are all different
* $1 \leq q \leq 24$
Input
In the first line, six integers assigned to faces are given in ascending order of their corresponding labels. In the second line, the number of questions $q$ is given.
In the following $q$ lines, $q$ questions are given. Each question consists of two integers on the top face and the front face respectively.
Output
For each question, print the integer on the right side face.
Example
Input
1 2 3 4 5 6
3
6 5
1 3
3 2
Output
3
5
6
Submitted Solution:
```
class Dice(object):
def __init__(self, top, south, east, west, north, bottom):
self.top = top
self.south = south
self.east = east
self.west = west
self.north = north
self.bottom = bottom
def get_top(self):
return self.top
def rotate(self, directions):
for direction in directions:
if direction == 'S':
self.prev_top = self.top
self.top = self.north
self.north = self.bottom
self.bottom = self.south
self.south = self.prev_top
elif direction == 'E':
self.prev_top = self.top
self.top = self.west
self.west = self.bottom
self.bottom = self.east
self.east = self.prev_top
elif direction == 'W':
self.prev_top = self.top
self.top = self.east
self.east = self.bottom
self.bottom = self.west
self.west = self.prev_top
elif direction == 'N':
self.prev_top = self.top
self.top = self.south
self.south = self.bottom
self.bottom = self.north
self.north = self.prev_top
dice = Dice(*map(int,input().split()))
n = int(input())
for i in range(n):
a, b = input().split()
if dice.east == b or dice.west == b:
dice.rotate("W")
while a != dice.top:
dice.rotate("N")
while b != dice.south:
dice.rotate("W")
print(dice.east)
``` | instruction | 0 | 80,812 | 19 | 161,624 |
No | output | 1 | 80,812 | 19 | 161,625 |
Provide tags and a correct Python 3 solution for this coding contest problem.
On a weekend, Qingshan suggests that she and her friend Daniel go hiking. Unfortunately, they are busy high school students, so they can only go hiking on scratch paper.
A permutation p is written from left to right on the paper. First Qingshan chooses an integer index x (1≤ x≤ n) and tells it to Daniel. After that, Daniel chooses another integer index y (1≤ y≤ n, y ≠ x).
The game progresses turn by turn and as usual, Qingshan moves first. The rules follow:
* If it is Qingshan's turn, Qingshan must change x to such an index x' that 1≤ x'≤ n, |x'-x|=1, x'≠ y, and p_{x'}<p_x at the same time.
* If it is Daniel's turn, Daniel must change y to such an index y' that 1≤ y'≤ n, |y'-y|=1, y'≠ x, and p_{y'}>p_y at the same time.
The person who can't make her or his move loses, and the other wins. You, as Qingshan's fan, are asked to calculate the number of possible x to make Qingshan win in the case both players play optimally.
Input
The first line contains a single integer n (2≤ n≤ 10^5) — the length of the permutation.
The second line contains n distinct integers p_1,p_2,...,p_n (1≤ p_i≤ n) — the permutation.
Output
Print the number of possible values of x that Qingshan can choose to make her win.
Examples
Input
5
1 2 5 4 3
Output
1
Input
7
1 2 4 6 5 3 7
Output
0
Note
In the first test case, Qingshan can only choose x=3 to win, so the answer is 1.
In the second test case, if Qingshan will choose x=4, Daniel can choose y=1. In the first turn (Qingshan's) Qingshan chooses x'=3 and changes x to 3. In the second turn (Daniel's) Daniel chooses y'=2 and changes y to 2. Qingshan can't choose x'=2 because y=2 at this time. Then Qingshan loses. | instruction | 0 | 81,045 | 19 | 162,090 |
Tags: games, greedy
Correct Solution:
```
n = int(input())
p = list(map(int,input().split()))
h1,h2 = [0]*n,[0]*n
for i in range(1,n):
if p[i]>p[i-1]:
h1[i] = h1[i-1]+1
for i in range(n-2,-1,-1):
if p[i]>p[i+1]:
h2[i] = h2[i+1]+1
m = max(max(h1),max(h2))
two,one = 0,h1.count(m)+h2.count(m)
for i in range(n):
if h1[i]==m and h2[i]==m:
two+=1
if two==1 and one==2 and m%2==0:
print(1)
else:
print(0)
``` | output | 1 | 81,045 | 19 | 162,091 |
Provide tags and a correct Python 3 solution for this coding contest problem.
On a weekend, Qingshan suggests that she and her friend Daniel go hiking. Unfortunately, they are busy high school students, so they can only go hiking on scratch paper.
A permutation p is written from left to right on the paper. First Qingshan chooses an integer index x (1≤ x≤ n) and tells it to Daniel. After that, Daniel chooses another integer index y (1≤ y≤ n, y ≠ x).
The game progresses turn by turn and as usual, Qingshan moves first. The rules follow:
* If it is Qingshan's turn, Qingshan must change x to such an index x' that 1≤ x'≤ n, |x'-x|=1, x'≠ y, and p_{x'}<p_x at the same time.
* If it is Daniel's turn, Daniel must change y to such an index y' that 1≤ y'≤ n, |y'-y|=1, y'≠ x, and p_{y'}>p_y at the same time.
The person who can't make her or his move loses, and the other wins. You, as Qingshan's fan, are asked to calculate the number of possible x to make Qingshan win in the case both players play optimally.
Input
The first line contains a single integer n (2≤ n≤ 10^5) — the length of the permutation.
The second line contains n distinct integers p_1,p_2,...,p_n (1≤ p_i≤ n) — the permutation.
Output
Print the number of possible values of x that Qingshan can choose to make her win.
Examples
Input
5
1 2 5 4 3
Output
1
Input
7
1 2 4 6 5 3 7
Output
0
Note
In the first test case, Qingshan can only choose x=3 to win, so the answer is 1.
In the second test case, if Qingshan will choose x=4, Daniel can choose y=1. In the first turn (Qingshan's) Qingshan chooses x'=3 and changes x to 3. In the second turn (Daniel's) Daniel chooses y'=2 and changes y to 2. Qingshan can't choose x'=2 because y=2 at this time. Then Qingshan loses. | instruction | 0 | 81,046 | 19 | 162,092 |
Tags: games, greedy
Correct Solution:
```
import os,io,math
input=io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
n=int(input())
a=list(map(int,input().split()))
cuml=[0]*n
cumr=[0]*n
curr=0
maxi=0
for i in range(1,n):
if a[i]>a[i-1]:
curr+=1
else:
curr=0
cuml[i]=curr
maxi=max(maxi,curr)
curr=0
for i in range(n-2,-1,-1):
if a[i]>a[i+1]:
curr+=1
else:
curr=0
cumr[i]=curr
maxi=max(maxi,curr)
l=set()
for i in range(n):
if cuml[i]==maxi or cumr[i]==maxi:
l.add(i)
if len(l)>=2:
print(0)
exit()
if maxi%2==0:
for i in l:
if cuml[i]==cumr[i]:
print(1)
else:
print(0)
else:
print(0)
``` | output | 1 | 81,046 | 19 | 162,093 |
Provide tags and a correct Python 3 solution for this coding contest problem.
On a weekend, Qingshan suggests that she and her friend Daniel go hiking. Unfortunately, they are busy high school students, so they can only go hiking on scratch paper.
A permutation p is written from left to right on the paper. First Qingshan chooses an integer index x (1≤ x≤ n) and tells it to Daniel. After that, Daniel chooses another integer index y (1≤ y≤ n, y ≠ x).
The game progresses turn by turn and as usual, Qingshan moves first. The rules follow:
* If it is Qingshan's turn, Qingshan must change x to such an index x' that 1≤ x'≤ n, |x'-x|=1, x'≠ y, and p_{x'}<p_x at the same time.
* If it is Daniel's turn, Daniel must change y to such an index y' that 1≤ y'≤ n, |y'-y|=1, y'≠ x, and p_{y'}>p_y at the same time.
The person who can't make her or his move loses, and the other wins. You, as Qingshan's fan, are asked to calculate the number of possible x to make Qingshan win in the case both players play optimally.
Input
The first line contains a single integer n (2≤ n≤ 10^5) — the length of the permutation.
The second line contains n distinct integers p_1,p_2,...,p_n (1≤ p_i≤ n) — the permutation.
Output
Print the number of possible values of x that Qingshan can choose to make her win.
Examples
Input
5
1 2 5 4 3
Output
1
Input
7
1 2 4 6 5 3 7
Output
0
Note
In the first test case, Qingshan can only choose x=3 to win, so the answer is 1.
In the second test case, if Qingshan will choose x=4, Daniel can choose y=1. In the first turn (Qingshan's) Qingshan chooses x'=3 and changes x to 3. In the second turn (Daniel's) Daniel chooses y'=2 and changes y to 2. Qingshan can't choose x'=2 because y=2 at this time. Then Qingshan loses. | instruction | 0 | 81,047 | 19 | 162,094 |
Tags: games, greedy
Correct Solution:
```
n = int(input())
p = [0] + list(map(int, input().split())) + [0]
left = [0 for _ in range(n+3)]
right = [0 for _ in range(n+3)]
for i in range(2, n+1):
if p[i-1] < p[i]:
left[i] = left[i-1] + 1
for i in range(n-1, 0, -1):
if p[i+1] < p[i]:
right[i] = right[i+1] + 1
left_less = [0 for _ in range(n+3)]
right_less = [0 for _ in range(n+3)]
for i in range(1, n+1):
left_less[i] = max(left_less[i-1], left[i], right[i])
for i in range(n, 0, -1):
right_less[i] = max(right_less[i+1], right[i], left[i])
ans = 0
for i in range(1, n+1):
mx = max(left[i], right[i])
if max(left_less[i - left[i] - 1], right_less[i + right[i] + 1]) < mx:
if p[i] > p[i-1] and p[i] > p[i+1]:
if left[i] == right[i] and (left[i] & 1 == 0):
ans += 1
# print(left_less)
# print(right_less)
# print(left)
# print(right)
print(ans)
``` | output | 1 | 81,047 | 19 | 162,095 |
Provide tags and a correct Python 3 solution for this coding contest problem.
On a weekend, Qingshan suggests that she and her friend Daniel go hiking. Unfortunately, they are busy high school students, so they can only go hiking on scratch paper.
A permutation p is written from left to right on the paper. First Qingshan chooses an integer index x (1≤ x≤ n) and tells it to Daniel. After that, Daniel chooses another integer index y (1≤ y≤ n, y ≠ x).
The game progresses turn by turn and as usual, Qingshan moves first. The rules follow:
* If it is Qingshan's turn, Qingshan must change x to such an index x' that 1≤ x'≤ n, |x'-x|=1, x'≠ y, and p_{x'}<p_x at the same time.
* If it is Daniel's turn, Daniel must change y to such an index y' that 1≤ y'≤ n, |y'-y|=1, y'≠ x, and p_{y'}>p_y at the same time.
The person who can't make her or his move loses, and the other wins. You, as Qingshan's fan, are asked to calculate the number of possible x to make Qingshan win in the case both players play optimally.
Input
The first line contains a single integer n (2≤ n≤ 10^5) — the length of the permutation.
The second line contains n distinct integers p_1,p_2,...,p_n (1≤ p_i≤ n) — the permutation.
Output
Print the number of possible values of x that Qingshan can choose to make her win.
Examples
Input
5
1 2 5 4 3
Output
1
Input
7
1 2 4 6 5 3 7
Output
0
Note
In the first test case, Qingshan can only choose x=3 to win, so the answer is 1.
In the second test case, if Qingshan will choose x=4, Daniel can choose y=1. In the first turn (Qingshan's) Qingshan chooses x'=3 and changes x to 3. In the second turn (Daniel's) Daniel chooses y'=2 and changes y to 2. Qingshan can't choose x'=2 because y=2 at this time. Then Qingshan loses. | instruction | 0 | 81,048 | 19 | 162,096 |
Tags: games, greedy
Correct Solution:
```
n = int(input())
nums = list(map(int, input().split()))
left = [0]*n
right = [0]*n
for i in range(1, n):
if nums[i] > nums[i-1]:
left[i] = left[i-1]+1
for i in range(n-2, -1, -1):
if nums[i] > nums[i+1]:
right[i] = right[i+1]+1
def main():
ml = max(left)
mr = max(right)
if ml != mr:
return print(0)
mlc, mrc = left.count(ml), right.count(mr)
if mlc + mrc == 2:
for p in range(n):
if right[p] == mr and left[p] == ml and not ml % 2:
return print(1)
return print(0)
main()
``` | output | 1 | 81,048 | 19 | 162,097 |
Provide tags and a correct Python 3 solution for this coding contest problem.
On a weekend, Qingshan suggests that she and her friend Daniel go hiking. Unfortunately, they are busy high school students, so they can only go hiking on scratch paper.
A permutation p is written from left to right on the paper. First Qingshan chooses an integer index x (1≤ x≤ n) and tells it to Daniel. After that, Daniel chooses another integer index y (1≤ y≤ n, y ≠ x).
The game progresses turn by turn and as usual, Qingshan moves first. The rules follow:
* If it is Qingshan's turn, Qingshan must change x to such an index x' that 1≤ x'≤ n, |x'-x|=1, x'≠ y, and p_{x'}<p_x at the same time.
* If it is Daniel's turn, Daniel must change y to such an index y' that 1≤ y'≤ n, |y'-y|=1, y'≠ x, and p_{y'}>p_y at the same time.
The person who can't make her or his move loses, and the other wins. You, as Qingshan's fan, are asked to calculate the number of possible x to make Qingshan win in the case both players play optimally.
Input
The first line contains a single integer n (2≤ n≤ 10^5) — the length of the permutation.
The second line contains n distinct integers p_1,p_2,...,p_n (1≤ p_i≤ n) — the permutation.
Output
Print the number of possible values of x that Qingshan can choose to make her win.
Examples
Input
5
1 2 5 4 3
Output
1
Input
7
1 2 4 6 5 3 7
Output
0
Note
In the first test case, Qingshan can only choose x=3 to win, so the answer is 1.
In the second test case, if Qingshan will choose x=4, Daniel can choose y=1. In the first turn (Qingshan's) Qingshan chooses x'=3 and changes x to 3. In the second turn (Daniel's) Daniel chooses y'=2 and changes y to 2. Qingshan can't choose x'=2 because y=2 at this time. Then Qingshan loses. | instruction | 0 | 81,049 | 19 | 162,098 |
Tags: games, greedy
Correct Solution:
```
import sys
from math import sqrt
input = lambda: sys.stdin.readline().rstrip("\r\n")
n=int(input())
a=list(map(int,input().split()))
i=0
ans=1
tot=1
while i+1<n:
t1=1
while i+1<n and a[i+1]>a[i]:
t1+=1
i+=1
t2=1
while i+1<n and a[i+1]<a[i]:
t2+=1
i+=1
if ans<t1 or ans<t2:
ans=max(ans,t1,t2)
tot=min(t1,t2)
elif ans==t1 or ans==t2:
tot=0
if ans%2 and tot==ans:
print(1)
else:
print(0)
``` | output | 1 | 81,049 | 19 | 162,099 |
Provide tags and a correct Python 3 solution for this coding contest problem.
On a weekend, Qingshan suggests that she and her friend Daniel go hiking. Unfortunately, they are busy high school students, so they can only go hiking on scratch paper.
A permutation p is written from left to right on the paper. First Qingshan chooses an integer index x (1≤ x≤ n) and tells it to Daniel. After that, Daniel chooses another integer index y (1≤ y≤ n, y ≠ x).
The game progresses turn by turn and as usual, Qingshan moves first. The rules follow:
* If it is Qingshan's turn, Qingshan must change x to such an index x' that 1≤ x'≤ n, |x'-x|=1, x'≠ y, and p_{x'}<p_x at the same time.
* If it is Daniel's turn, Daniel must change y to such an index y' that 1≤ y'≤ n, |y'-y|=1, y'≠ x, and p_{y'}>p_y at the same time.
The person who can't make her or his move loses, and the other wins. You, as Qingshan's fan, are asked to calculate the number of possible x to make Qingshan win in the case both players play optimally.
Input
The first line contains a single integer n (2≤ n≤ 10^5) — the length of the permutation.
The second line contains n distinct integers p_1,p_2,...,p_n (1≤ p_i≤ n) — the permutation.
Output
Print the number of possible values of x that Qingshan can choose to make her win.
Examples
Input
5
1 2 5 4 3
Output
1
Input
7
1 2 4 6 5 3 7
Output
0
Note
In the first test case, Qingshan can only choose x=3 to win, so the answer is 1.
In the second test case, if Qingshan will choose x=4, Daniel can choose y=1. In the first turn (Qingshan's) Qingshan chooses x'=3 and changes x to 3. In the second turn (Daniel's) Daniel chooses y'=2 and changes y to 2. Qingshan can't choose x'=2 because y=2 at this time. Then Qingshan loses. | instruction | 0 | 81,050 | 19 | 162,100 |
Tags: games, greedy
Correct Solution:
```
import sys
def get_diagram(nums):
diagram = [0]
max_ = 0
abs_maxs = []
for i, num in enumerate(nums):
if i == 0:
continue
if num > nums[i - 1]:
if diagram[-1] < 0:
counter = 1
diagram.append(counter)
else:
diagram[-1] = diagram[-1] + 1
elif num < nums[i - 1]:
if diagram[-1] > 0:
counter = -1
diagram.append(counter)
else:
diagram[-1] = diagram[-1] - 1
else:
diagram.append(0)
if abs(diagram[-1]) > max_:
max_ = abs(diagram[-1])
abs_maxs = [len(diagram) - 1]
elif abs(diagram[-1]) == max_:
abs_maxs.append(len(diagram) - 1)
return diagram, abs_maxs
def solve(nums):
if len(nums) == 2:
return 0
diagram, abs_maxs = get_diagram(nums)
counter = 0
for i in range(len(diagram) - 1):
if diagram[i] > 0 > diagram[i + 1]:
if diagram[i] != abs(diagram[i + 1]):
continue
local_best = [i, i + 1]
if abs(diagram[local_best[0]]) < abs(diagram[abs_maxs[0]]):
continue
if abs(diagram[local_best[0]]) == abs(diagram[abs_maxs[0]]) and abs_maxs != local_best:
continue
if len(local_best) == 2:
if abs(diagram[local_best[0]]) % 2 == 0:
counter += 1
# continue
# else:
# if abs(abs(diagram[local_best[0]]) - abs(diagram[local_worst[0]])) == 1:
# if abs(diagram[local_worst[0]]) % 2 == 0: # even, odd
# continue
# else:
# if abs(diagram[local_best[0]]) % 2 == 0:
# if abs(diagram[local_best[0]]) == abs(diagram[abs_maxs[0]]):
# if len(abs_maxs) > 1:
# if abs_maxs == local_best:
# counter += 1
# else:
# continue
# elif abs_maxs[0] in local_best:
# counter += 1
# else:
# continue
# else:
# counter += 1
# else:
# continue
else:
continue
return counter
if __name__ == "__main__":
n = int(sys.stdin.readline().strip())
line = sys.stdin.readline().strip()
values = list(map(int, line.split()))
print(solve(values))
``` | output | 1 | 81,050 | 19 | 162,101 |
Provide tags and a correct Python 3 solution for this coding contest problem.
On a weekend, Qingshan suggests that she and her friend Daniel go hiking. Unfortunately, they are busy high school students, so they can only go hiking on scratch paper.
A permutation p is written from left to right on the paper. First Qingshan chooses an integer index x (1≤ x≤ n) and tells it to Daniel. After that, Daniel chooses another integer index y (1≤ y≤ n, y ≠ x).
The game progresses turn by turn and as usual, Qingshan moves first. The rules follow:
* If it is Qingshan's turn, Qingshan must change x to such an index x' that 1≤ x'≤ n, |x'-x|=1, x'≠ y, and p_{x'}<p_x at the same time.
* If it is Daniel's turn, Daniel must change y to such an index y' that 1≤ y'≤ n, |y'-y|=1, y'≠ x, and p_{y'}>p_y at the same time.
The person who can't make her or his move loses, and the other wins. You, as Qingshan's fan, are asked to calculate the number of possible x to make Qingshan win in the case both players play optimally.
Input
The first line contains a single integer n (2≤ n≤ 10^5) — the length of the permutation.
The second line contains n distinct integers p_1,p_2,...,p_n (1≤ p_i≤ n) — the permutation.
Output
Print the number of possible values of x that Qingshan can choose to make her win.
Examples
Input
5
1 2 5 4 3
Output
1
Input
7
1 2 4 6 5 3 7
Output
0
Note
In the first test case, Qingshan can only choose x=3 to win, so the answer is 1.
In the second test case, if Qingshan will choose x=4, Daniel can choose y=1. In the first turn (Qingshan's) Qingshan chooses x'=3 and changes x to 3. In the second turn (Daniel's) Daniel chooses y'=2 and changes y to 2. Qingshan can't choose x'=2 because y=2 at this time. Then Qingshan loses. | instruction | 0 | 81,051 | 19 | 162,102 |
Tags: games, greedy
Correct Solution:
```
from sys import stdin, stdout
from collections import defaultdict
import math
def main():
n = int(stdin.readline())
arr = list(map(int, stdin.readline().split()))
if n < 4:
stdout.write("0\n")
return
peak_pos = []
for i in range(1, n - 1):
if arr[i - 1] < arr[i] and arr[i] > arr[i + 1]:
peak_pos.append(i)
if len(peak_pos) == 0:
stdout.write("0\n")
return
mx = -1
mx_l, mx_r = -1, -1
peak_cnt = defaultdict(int)
for peak in peak_pos:
long_left = 0
l = peak - 1
while l >= 0 and arr[l] < arr[l + 1]:
long_left += 1
l -= 1
r = peak + 1
long_right = 0
while r < n and arr[r] < arr[r - 1]:
long_right += 1
r += 1
longest = max(long_left, long_right)
peak_cnt[longest] += 1
if longest > mx:
mx = longest
mx_l = long_left
mx_r = long_right
longest = max(mx_l, mx_r)
if peak_cnt[longest] > 1:
stdout.write("0\n")
return
# check last 2
left_p = 0
for i in range(1, n-1):
if arr[i - 1] > arr[i]:
left_p += 1
else:
break
left_r = 0
for i in range(n-2, -1, -1):
if arr[i + 1] > arr[i]:
left_r += 1
else:
break
if left_p >= longest or left_r >= longest:
stdout.write("0\n")
return
if mx_l == mx_r and mx_l % 2 == 0:
stdout.write("1\n")
else:
stdout.write("0\n")
main()
``` | output | 1 | 81,051 | 19 | 162,103 |
Provide tags and a correct Python 3 solution for this coding contest problem.
On a weekend, Qingshan suggests that she and her friend Daniel go hiking. Unfortunately, they are busy high school students, so they can only go hiking on scratch paper.
A permutation p is written from left to right on the paper. First Qingshan chooses an integer index x (1≤ x≤ n) and tells it to Daniel. After that, Daniel chooses another integer index y (1≤ y≤ n, y ≠ x).
The game progresses turn by turn and as usual, Qingshan moves first. The rules follow:
* If it is Qingshan's turn, Qingshan must change x to such an index x' that 1≤ x'≤ n, |x'-x|=1, x'≠ y, and p_{x'}<p_x at the same time.
* If it is Daniel's turn, Daniel must change y to such an index y' that 1≤ y'≤ n, |y'-y|=1, y'≠ x, and p_{y'}>p_y at the same time.
The person who can't make her or his move loses, and the other wins. You, as Qingshan's fan, are asked to calculate the number of possible x to make Qingshan win in the case both players play optimally.
Input
The first line contains a single integer n (2≤ n≤ 10^5) — the length of the permutation.
The second line contains n distinct integers p_1,p_2,...,p_n (1≤ p_i≤ n) — the permutation.
Output
Print the number of possible values of x that Qingshan can choose to make her win.
Examples
Input
5
1 2 5 4 3
Output
1
Input
7
1 2 4 6 5 3 7
Output
0
Note
In the first test case, Qingshan can only choose x=3 to win, so the answer is 1.
In the second test case, if Qingshan will choose x=4, Daniel can choose y=1. In the first turn (Qingshan's) Qingshan chooses x'=3 and changes x to 3. In the second turn (Daniel's) Daniel chooses y'=2 and changes y to 2. Qingshan can't choose x'=2 because y=2 at this time. Then Qingshan loses. | instruction | 0 | 81,052 | 19 | 162,104 |
Tags: games, greedy
Correct Solution:
```
import sys
input=sys.stdin.buffer.readline
N=int(input())
P=list(map(int,input().split()))
DP=[[0]*N for i in range(2)]
for i in range(N-1):
if P[i]<P[i+1]:
DP[0][i+1]=DP[0][i]+1
for i in range(N-2,-1,-1):
if P[i]>P[i+1]:
DP[1][i]=DP[1][i+1]+1
M=max(max(DP[0]),max(DP[1]))
C=0
for i in range(2):
for j in range(N):
if M==DP[i][j]:
C+=1
ANS=0
for i in range(N):
if DP[0][i]==DP[1][i] and DP[0][i]>0 and DP[0][i]&1==0:
if DP[0][i]==M and C<=2:
ANS+=1
print(ANS)
``` | output | 1 | 81,052 | 19 | 162,105 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
On a weekend, Qingshan suggests that she and her friend Daniel go hiking. Unfortunately, they are busy high school students, so they can only go hiking on scratch paper.
A permutation p is written from left to right on the paper. First Qingshan chooses an integer index x (1≤ x≤ n) and tells it to Daniel. After that, Daniel chooses another integer index y (1≤ y≤ n, y ≠ x).
The game progresses turn by turn and as usual, Qingshan moves first. The rules follow:
* If it is Qingshan's turn, Qingshan must change x to such an index x' that 1≤ x'≤ n, |x'-x|=1, x'≠ y, and p_{x'}<p_x at the same time.
* If it is Daniel's turn, Daniel must change y to such an index y' that 1≤ y'≤ n, |y'-y|=1, y'≠ x, and p_{y'}>p_y at the same time.
The person who can't make her or his move loses, and the other wins. You, as Qingshan's fan, are asked to calculate the number of possible x to make Qingshan win in the case both players play optimally.
Input
The first line contains a single integer n (2≤ n≤ 10^5) — the length of the permutation.
The second line contains n distinct integers p_1,p_2,...,p_n (1≤ p_i≤ n) — the permutation.
Output
Print the number of possible values of x that Qingshan can choose to make her win.
Examples
Input
5
1 2 5 4 3
Output
1
Input
7
1 2 4 6 5 3 7
Output
0
Note
In the first test case, Qingshan can only choose x=3 to win, so the answer is 1.
In the second test case, if Qingshan will choose x=4, Daniel can choose y=1. In the first turn (Qingshan's) Qingshan chooses x'=3 and changes x to 3. In the second turn (Daniel's) Daniel chooses y'=2 and changes y to 2. Qingshan can't choose x'=2 because y=2 at this time. Then Qingshan loses.
Submitted Solution:
```
# search for mountain of highest peak
# there should be just 1 mountain
# both sides should have equal height
#height must be odd
a=int(input())
z=list(map(int,input().split()))
ans=[]
cnt=1
for i in range(1,len(z)):
if(z[i]>z[i-1]):
if(i==1):
cnt+=1
trend=1
continue;
if(trend==1):
cnt+=1
else:
ans.append([cnt,0])
cnt=2
trend=1
else:
if(i==1):
cnt+=1
trend=0
continue;
if(trend==0):
cnt+=1
else:
ans.append([cnt,1])
cnt=2
trend=0
from collections import *
ans.append([cnt,trend])
dl=defaultdict(int)
maxa=0
for i in range(len(ans)):
dl[ans[i][0]]+=1
maxa=max(maxa,ans[i][0])
if(dl[maxa]==2 and maxa%2==1):
flag=0
for i in range(len(ans)-1):
if(ans[i][0]==ans[i+1][0] and ans[i][0]==maxa and ans[i][1]==1):
flag=1
break;
if(flag==1):
print('1')
exit(0)
print(0)
``` | instruction | 0 | 81,053 | 19 | 162,106 |
Yes | output | 1 | 81,053 | 19 | 162,107 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
On a weekend, Qingshan suggests that she and her friend Daniel go hiking. Unfortunately, they are busy high school students, so they can only go hiking on scratch paper.
A permutation p is written from left to right on the paper. First Qingshan chooses an integer index x (1≤ x≤ n) and tells it to Daniel. After that, Daniel chooses another integer index y (1≤ y≤ n, y ≠ x).
The game progresses turn by turn and as usual, Qingshan moves first. The rules follow:
* If it is Qingshan's turn, Qingshan must change x to such an index x' that 1≤ x'≤ n, |x'-x|=1, x'≠ y, and p_{x'}<p_x at the same time.
* If it is Daniel's turn, Daniel must change y to such an index y' that 1≤ y'≤ n, |y'-y|=1, y'≠ x, and p_{y'}>p_y at the same time.
The person who can't make her or his move loses, and the other wins. You, as Qingshan's fan, are asked to calculate the number of possible x to make Qingshan win in the case both players play optimally.
Input
The first line contains a single integer n (2≤ n≤ 10^5) — the length of the permutation.
The second line contains n distinct integers p_1,p_2,...,p_n (1≤ p_i≤ n) — the permutation.
Output
Print the number of possible values of x that Qingshan can choose to make her win.
Examples
Input
5
1 2 5 4 3
Output
1
Input
7
1 2 4 6 5 3 7
Output
0
Note
In the first test case, Qingshan can only choose x=3 to win, so the answer is 1.
In the second test case, if Qingshan will choose x=4, Daniel can choose y=1. In the first turn (Qingshan's) Qingshan chooses x'=3 and changes x to 3. In the second turn (Daniel's) Daniel chooses y'=2 and changes y to 2. Qingshan can't choose x'=2 because y=2 at this time. Then Qingshan loses.
Submitted Solution:
```
import sys;Z=sys.stdin.readline
n=int(Z());p=[*map(int,Z().split())];a=p[0];r=[];s=c=t=m=0
for i in range(1,n):
if p[i]>a:w=1
else:w=-1
if s==w:c+=1
else:
if s<0 and r[-1]==c and c%2:
if c==m:t=0
elif c>m:t=1;m=c
r.append(c);c=2;s=w
a=p[i]
if s<0 and r[-1]==c and c%2:
if c==m:t=0
elif c>m:t=1;m=c
r.append(c)
if max(r)>m:t=0
elif r.count(m)>2:t=0
print(t)
``` | instruction | 0 | 81,054 | 19 | 162,108 |
Yes | output | 1 | 81,054 | 19 | 162,109 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
On a weekend, Qingshan suggests that she and her friend Daniel go hiking. Unfortunately, they are busy high school students, so they can only go hiking on scratch paper.
A permutation p is written from left to right on the paper. First Qingshan chooses an integer index x (1≤ x≤ n) and tells it to Daniel. After that, Daniel chooses another integer index y (1≤ y≤ n, y ≠ x).
The game progresses turn by turn and as usual, Qingshan moves first. The rules follow:
* If it is Qingshan's turn, Qingshan must change x to such an index x' that 1≤ x'≤ n, |x'-x|=1, x'≠ y, and p_{x'}<p_x at the same time.
* If it is Daniel's turn, Daniel must change y to such an index y' that 1≤ y'≤ n, |y'-y|=1, y'≠ x, and p_{y'}>p_y at the same time.
The person who can't make her or his move loses, and the other wins. You, as Qingshan's fan, are asked to calculate the number of possible x to make Qingshan win in the case both players play optimally.
Input
The first line contains a single integer n (2≤ n≤ 10^5) — the length of the permutation.
The second line contains n distinct integers p_1,p_2,...,p_n (1≤ p_i≤ n) — the permutation.
Output
Print the number of possible values of x that Qingshan can choose to make her win.
Examples
Input
5
1 2 5 4 3
Output
1
Input
7
1 2 4 6 5 3 7
Output
0
Note
In the first test case, Qingshan can only choose x=3 to win, so the answer is 1.
In the second test case, if Qingshan will choose x=4, Daniel can choose y=1. In the first turn (Qingshan's) Qingshan chooses x'=3 and changes x to 3. In the second turn (Daniel's) Daniel chooses y'=2 and changes y to 2. Qingshan can't choose x'=2 because y=2 at this time. Then Qingshan loses.
Submitted Solution:
```
#!/usr/bin/env python3
import sys, getpass
import math, random
import functools, itertools, collections, heapq, bisect
from collections import Counter, defaultdict, deque
input = sys.stdin.readline # to read input quickly
# available on Google, AtCoder Python3, not available on Codeforces
# import numpy as np
# import scipy
M9 = 10**9 + 7 # 998244353
# d4 = [(1,0),(0,1),(-1,0),(0,-1)]
# d8 = [(1,0),(1,1),(0,1),(-1,1),(-1,0),(-1,-1),(0,-1),(1,-1)]
# d6 = [(2,0),(1,1),(-1,1),(-2,0),(-1,-1),(1,-1)] # hexagonal layout
MAXINT = sys.maxsize
# if testing locally, print to terminal with a different color
OFFLINE_TEST = getpass.getuser() == "hkmac"
# OFFLINE_TEST = False # codechef does not allow getpass
def log(*args):
if OFFLINE_TEST:
print('\033[36m', *args, '\033[0m', file=sys.stderr)
def solve(*args):
# screen input
if OFFLINE_TEST:
log("----- solving ------")
log(*args)
log("----- ------- ------")
return solve_(*args)
def read_matrix(rows):
return [list(map(int,input().split())) for _ in range(rows)]
def read_strings(rows):
return [input().strip() for _ in range(rows)]
# ---------------------------- template ends here ----------------------------
def solve_(arr):
# must be the single largest peak
# must have equal branches
if len(arr) <= 4:
return 0
xrr = [0]
rise_count = 0
for a,b in zip(arr,arr[1:]):
if b > a:
rise_count += 1
else:
rise_count = 0
xrr.append(rise_count)
yrr = [0]
rise_count = 0
for a,b in zip(arr[::-1],arr[::-1][1:]):
if b > a:
rise_count += 1
else:
rise_count = 0
yrr.append(rise_count)
yrr = yrr[::-1]
zrr = [max(a,b) for a,b in zip(xrr,yrr)]
mxrr = max(xrr)
myrr = max(yrr)
mzrr = max(zrr)
# log(xrr)
# log(yrr)
# log(zrr)
if mxrr != myrr:
return 0
if mxrr != mzrr:
return 0
if zrr.count(mzrr) > 1:
return 0
if mzrr%2:
return 0
return 1
for case_num in [0]: # no loop over test case
# for case_num in range(100): # if the number of test cases is specified
# for case_num in range(int(input())):
# read line as an integer
k = int(input())
# read line as a string
# srr = input().strip()
# read one line and parse each word as a string
# lst = input().split()
# read one line and parse each word as an integer
# a,b,c = list(map(int,input().split()))
lst = list(map(int,input().split()))
# read multiple rows
# mrr = read_matrix(k) # and return as a list of list of int
# arr = read_strings(k) # and return as a list of str
res = solve(lst) # include input here
# print result
# Google and Facebook - case number required
# print("Case #{}: {}".format(case_num+1, res))
# Other platforms - no case number required
print(res)
# print(len(res))
# print(*res) # print a list with elements
# for r in res: # print each list in a different line
# print(res)
# print(*res)
``` | instruction | 0 | 81,055 | 19 | 162,110 |
Yes | output | 1 | 81,055 | 19 | 162,111 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
On a weekend, Qingshan suggests that she and her friend Daniel go hiking. Unfortunately, they are busy high school students, so they can only go hiking on scratch paper.
A permutation p is written from left to right on the paper. First Qingshan chooses an integer index x (1≤ x≤ n) and tells it to Daniel. After that, Daniel chooses another integer index y (1≤ y≤ n, y ≠ x).
The game progresses turn by turn and as usual, Qingshan moves first. The rules follow:
* If it is Qingshan's turn, Qingshan must change x to such an index x' that 1≤ x'≤ n, |x'-x|=1, x'≠ y, and p_{x'}<p_x at the same time.
* If it is Daniel's turn, Daniel must change y to such an index y' that 1≤ y'≤ n, |y'-y|=1, y'≠ x, and p_{y'}>p_y at the same time.
The person who can't make her or his move loses, and the other wins. You, as Qingshan's fan, are asked to calculate the number of possible x to make Qingshan win in the case both players play optimally.
Input
The first line contains a single integer n (2≤ n≤ 10^5) — the length of the permutation.
The second line contains n distinct integers p_1,p_2,...,p_n (1≤ p_i≤ n) — the permutation.
Output
Print the number of possible values of x that Qingshan can choose to make her win.
Examples
Input
5
1 2 5 4 3
Output
1
Input
7
1 2 4 6 5 3 7
Output
0
Note
In the first test case, Qingshan can only choose x=3 to win, so the answer is 1.
In the second test case, if Qingshan will choose x=4, Daniel can choose y=1. In the first turn (Qingshan's) Qingshan chooses x'=3 and changes x to 3. In the second turn (Daniel's) Daniel chooses y'=2 and changes y to 2. Qingshan can't choose x'=2 because y=2 at this time. Then Qingshan loses.
Submitted Solution:
```
mod = 1000000007
eps = 10**-9
def main():
import sys
input = sys.stdin.readline
N = int(input())
P = list(map(int, input().split()))
L = [0] * N
R = [0] * N
for i in range(1, N):
if P[i] > P[i-1]:
L[i] = L[i-1] + 1
for i in range(N-2, -1, -1):
if P[i] > P[i+1]:
R[i] = R[i+1] + 1
ma_L = max(L)
ma_R = max(R)
ma = max(ma_L, ma_R)
flg = 0
for i in range(N):
if L[i] == R[i] == ma:
flg += 1
elif L[i] == ma or R[i] == ma:
flg = 2
if ma & 1:
flg = 2
if flg == 1:
print(1)
else:
print(0)
if __name__ == '__main__':
main()
``` | instruction | 0 | 81,056 | 19 | 162,112 |
Yes | output | 1 | 81,056 | 19 | 162,113 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
On a weekend, Qingshan suggests that she and her friend Daniel go hiking. Unfortunately, they are busy high school students, so they can only go hiking on scratch paper.
A permutation p is written from left to right on the paper. First Qingshan chooses an integer index x (1≤ x≤ n) and tells it to Daniel. After that, Daniel chooses another integer index y (1≤ y≤ n, y ≠ x).
The game progresses turn by turn and as usual, Qingshan moves first. The rules follow:
* If it is Qingshan's turn, Qingshan must change x to such an index x' that 1≤ x'≤ n, |x'-x|=1, x'≠ y, and p_{x'}<p_x at the same time.
* If it is Daniel's turn, Daniel must change y to such an index y' that 1≤ y'≤ n, |y'-y|=1, y'≠ x, and p_{y'}>p_y at the same time.
The person who can't make her or his move loses, and the other wins. You, as Qingshan's fan, are asked to calculate the number of possible x to make Qingshan win in the case both players play optimally.
Input
The first line contains a single integer n (2≤ n≤ 10^5) — the length of the permutation.
The second line contains n distinct integers p_1,p_2,...,p_n (1≤ p_i≤ n) — the permutation.
Output
Print the number of possible values of x that Qingshan can choose to make her win.
Examples
Input
5
1 2 5 4 3
Output
1
Input
7
1 2 4 6 5 3 7
Output
0
Note
In the first test case, Qingshan can only choose x=3 to win, so the answer is 1.
In the second test case, if Qingshan will choose x=4, Daniel can choose y=1. In the first turn (Qingshan's) Qingshan chooses x'=3 and changes x to 3. In the second turn (Daniel's) Daniel chooses y'=2 and changes y to 2. Qingshan can't choose x'=2 because y=2 at this time. Then Qingshan loses.
Submitted Solution:
```
from collections import defaultdict
import sys
input=sys.stdin.readline
n=int(input())
pi=list(map(int,input().split()))
risesandfalls=[]
li=[pi[0]]
increasing=1
length=-5
dictt=defaultdict(int)
if pi[1]<pi[0]:increasing=0
for i in range(1,n):
if increasing:
if pi[i]>pi[i-1]:
li.append(pi[i])
else:
if len(risesandfalls)==0:
length=max(length,len(li))
dictt[len(li)]+=1
else:
length=max(length,len(li)+1)
dictt[len(li)+1]+=1
risesandfalls.append(li)
li=[pi[i]]
increasing=0
else:
if pi[i]<pi[i-1]:
li.append(pi[i])
else:
if len(risesandfalls)==0:
length=max(length,len(li))
dictt[len(li)]+=1
else:
length=max(length,len(li)+1)
dictt[len(li)+1]+=1
risesandfalls.append(li)
li=[pi[i]]
increasing=1
risesandfalls.append(li)
length=max(length,len(li))
dictt[len(li)]+=1
if length%2:
print(dictt[length])
else:print(0)
``` | instruction | 0 | 81,057 | 19 | 162,114 |
No | output | 1 | 81,057 | 19 | 162,115 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
On a weekend, Qingshan suggests that she and her friend Daniel go hiking. Unfortunately, they are busy high school students, so they can only go hiking on scratch paper.
A permutation p is written from left to right on the paper. First Qingshan chooses an integer index x (1≤ x≤ n) and tells it to Daniel. After that, Daniel chooses another integer index y (1≤ y≤ n, y ≠ x).
The game progresses turn by turn and as usual, Qingshan moves first. The rules follow:
* If it is Qingshan's turn, Qingshan must change x to such an index x' that 1≤ x'≤ n, |x'-x|=1, x'≠ y, and p_{x'}<p_x at the same time.
* If it is Daniel's turn, Daniel must change y to such an index y' that 1≤ y'≤ n, |y'-y|=1, y'≠ x, and p_{y'}>p_y at the same time.
The person who can't make her or his move loses, and the other wins. You, as Qingshan's fan, are asked to calculate the number of possible x to make Qingshan win in the case both players play optimally.
Input
The first line contains a single integer n (2≤ n≤ 10^5) — the length of the permutation.
The second line contains n distinct integers p_1,p_2,...,p_n (1≤ p_i≤ n) — the permutation.
Output
Print the number of possible values of x that Qingshan can choose to make her win.
Examples
Input
5
1 2 5 4 3
Output
1
Input
7
1 2 4 6 5 3 7
Output
0
Note
In the first test case, Qingshan can only choose x=3 to win, so the answer is 1.
In the second test case, if Qingshan will choose x=4, Daniel can choose y=1. In the first turn (Qingshan's) Qingshan chooses x'=3 and changes x to 3. In the second turn (Daniel's) Daniel chooses y'=2 and changes y to 2. Qingshan can't choose x'=2 because y=2 at this time. Then Qingshan loses.
Submitted Solution:
```
import sys
input = sys.stdin.readline
from collections import Counter
n = int(input())
x = [*map(int, input().split())]
m = n - 1
i = 0
a = b = 0
top = []
bot = []
t = 0
while i < m:
if x[i] > x[i+1]:
a = i
while i < m and x[i] > x[i+1]:
i += 1
a = i - a
top.append((b, a))
else:
b = i
while i < m and x[i] < x[i+1]:
i += 1
b = i - b
t = max(t, a, b)
y = Counter()
for a, b in top:
if a != b or a % 2:
continue
y[a] += 1
print(1 if (y and y[t] == 1) else 0)
``` | instruction | 0 | 81,058 | 19 | 162,116 |
No | output | 1 | 81,058 | 19 | 162,117 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
On a weekend, Qingshan suggests that she and her friend Daniel go hiking. Unfortunately, they are busy high school students, so they can only go hiking on scratch paper.
A permutation p is written from left to right on the paper. First Qingshan chooses an integer index x (1≤ x≤ n) and tells it to Daniel. After that, Daniel chooses another integer index y (1≤ y≤ n, y ≠ x).
The game progresses turn by turn and as usual, Qingshan moves first. The rules follow:
* If it is Qingshan's turn, Qingshan must change x to such an index x' that 1≤ x'≤ n, |x'-x|=1, x'≠ y, and p_{x'}<p_x at the same time.
* If it is Daniel's turn, Daniel must change y to such an index y' that 1≤ y'≤ n, |y'-y|=1, y'≠ x, and p_{y'}>p_y at the same time.
The person who can't make her or his move loses, and the other wins. You, as Qingshan's fan, are asked to calculate the number of possible x to make Qingshan win in the case both players play optimally.
Input
The first line contains a single integer n (2≤ n≤ 10^5) — the length of the permutation.
The second line contains n distinct integers p_1,p_2,...,p_n (1≤ p_i≤ n) — the permutation.
Output
Print the number of possible values of x that Qingshan can choose to make her win.
Examples
Input
5
1 2 5 4 3
Output
1
Input
7
1 2 4 6 5 3 7
Output
0
Note
In the first test case, Qingshan can only choose x=3 to win, so the answer is 1.
In the second test case, if Qingshan will choose x=4, Daniel can choose y=1. In the first turn (Qingshan's) Qingshan chooses x'=3 and changes x to 3. In the second turn (Daniel's) Daniel chooses y'=2 and changes y to 2. Qingshan can't choose x'=2 because y=2 at this time. Then Qingshan loses.
Submitted Solution:
```
import sys
input = sys.stdin.readline
import math
import copy
n = int(input())
p = list(map(int,input().split()))
up = []
down = []
i = 0
if p[1] > p[0]:
None
else:
while p[i+1] < p[i]:
i += 1
if i == n-1:
exit(print(0))
up_num = 0
down_num = 0
for j in range(n-1-i):
if p[j+i+1] > p[j+i]:
if down_num != 0:
down.append(down_num)
down_num = 0
up_num += 1
else:
if up_num != 0:
up.append(up_num)
up_num = 0
down_num += 1
if down_num != 0:
down.append(down_num)
if len(up) == 0 or len(down) == 0:
exit(print(0))
lim = max(max(up),max(down), up_num)
ans = 0
for j in range(len(up)):
if (max(up[j],down[j]) == lim) and (up[j]//2 != down[j]//2 or up[j] == down[j]):
ans += 1
if ans >= 2:
ans = 0
print(ans)
``` | instruction | 0 | 81,059 | 19 | 162,118 |
No | output | 1 | 81,059 | 19 | 162,119 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
On a weekend, Qingshan suggests that she and her friend Daniel go hiking. Unfortunately, they are busy high school students, so they can only go hiking on scratch paper.
A permutation p is written from left to right on the paper. First Qingshan chooses an integer index x (1≤ x≤ n) and tells it to Daniel. After that, Daniel chooses another integer index y (1≤ y≤ n, y ≠ x).
The game progresses turn by turn and as usual, Qingshan moves first. The rules follow:
* If it is Qingshan's turn, Qingshan must change x to such an index x' that 1≤ x'≤ n, |x'-x|=1, x'≠ y, and p_{x'}<p_x at the same time.
* If it is Daniel's turn, Daniel must change y to such an index y' that 1≤ y'≤ n, |y'-y|=1, y'≠ x, and p_{y'}>p_y at the same time.
The person who can't make her or his move loses, and the other wins. You, as Qingshan's fan, are asked to calculate the number of possible x to make Qingshan win in the case both players play optimally.
Input
The first line contains a single integer n (2≤ n≤ 10^5) — the length of the permutation.
The second line contains n distinct integers p_1,p_2,...,p_n (1≤ p_i≤ n) — the permutation.
Output
Print the number of possible values of x that Qingshan can choose to make her win.
Examples
Input
5
1 2 5 4 3
Output
1
Input
7
1 2 4 6 5 3 7
Output
0
Note
In the first test case, Qingshan can only choose x=3 to win, so the answer is 1.
In the second test case, if Qingshan will choose x=4, Daniel can choose y=1. In the first turn (Qingshan's) Qingshan chooses x'=3 and changes x to 3. In the second turn (Daniel's) Daniel chooses y'=2 and changes y to 2. Qingshan can't choose x'=2 because y=2 at this time. Then Qingshan loses.
Submitted Solution:
```
#!/usr/bin/env python3
import sys, getpass
import math, random
import functools, itertools, collections, heapq, bisect
from collections import Counter, defaultdict, deque
input = sys.stdin.readline # to read input quickly
# available on Google, AtCoder Python3, not available on Codeforces
# import numpy as np
# import scipy
M9 = 10**9 + 7 # 998244353
# d4 = [(1,0),(0,1),(-1,0),(0,-1)]
# d8 = [(1,0),(1,1),(0,1),(-1,1),(-1,0),(-1,-1),(0,-1),(1,-1)]
# d6 = [(2,0),(1,1),(-1,1),(-2,0),(-1,-1),(1,-1)] # hexagonal layout
MAXINT = sys.maxsize
# if testing locally, print to terminal with a different color
OFFLINE_TEST = getpass.getuser() == "hkmac"
# OFFLINE_TEST = False # codechef does not allow getpass
def log(*args):
if OFFLINE_TEST:
print('\033[36m', *args, '\033[0m', file=sys.stderr)
def solve(*args):
# screen input
if OFFLINE_TEST:
log("----- solving ------")
log(*args)
log("----- ------- ------")
return solve_(*args)
def read_matrix(rows):
return [list(map(int,input().split())) for _ in range(rows)]
def read_strings(rows):
return [input().strip() for _ in range(rows)]
# ---------------------------- template ends here ----------------------------
def solve_(arr):
# must be the single largest peak
# must have equal branches
if len(arr) <= 4:
return 0
xrr = [0]
rise_count = 0
for a,b in zip(arr,arr[1:]):
if b > a:
rise_count += 1
else:
rise_count = 0
xrr.append(rise_count)
yrr = [0]
rise_count = 0
for a,b in zip(arr[::-1],arr[::-1][1:]):
if b > a:
rise_count += 1
else:
rise_count = 0
yrr.append(rise_count)
yrr = yrr[::-1]
zrr = [max(a,b) for a,b in zip(xrr,yrr)]
mxrr = max(xrr)
myrr = max(yrr)
mzrr = max(zrr)
if mxrr != myrr:
return 0
if mxrr != mzrr:
return 0
if zrr.count(mzrr) > 1:
return 0
return 1
for case_num in [0]: # no loop over test case
# for case_num in range(100): # if the number of test cases is specified
# for case_num in range(int(input())):
# read line as an integer
k = int(input())
# read line as a string
# srr = input().strip()
# read one line and parse each word as a string
# lst = input().split()
# read one line and parse each word as an integer
# a,b,c = list(map(int,input().split()))
lst = list(map(int,input().split()))
# read multiple rows
# mrr = read_matrix(k) # and return as a list of list of int
# arr = read_strings(k) # and return as a list of str
res = solve(lst) # include input here
# print result
# Google and Facebook - case number required
# print("Case #{}: {}".format(case_num+1, res))
# Other platforms - no case number required
print(res)
# print(len(res))
# print(*res) # print a list with elements
# for r in res: # print each list in a different line
# print(res)
# print(*res)
``` | instruction | 0 | 81,060 | 19 | 162,120 |
No | output | 1 | 81,060 | 19 | 162,121 |
Provide a correct Python 3 solution for this coding contest problem.
There are a number of ways to shuffle a deck of cards. Hanafuda shuffling for Japanese card game 'Hanafuda' is one such example. The following is how to perform Hanafuda shuffling.
There is a deck of n cards. Starting from the p-th card from the top of the deck, c cards are pulled out and put on the top of the deck, as shown in Figure 1. This operation, called a cutting operation, is repeated.
Write a program that simulates Hanafuda shuffling and answers which card will be finally placed on the top of the deck.
<image>
---
Figure 1: Cutting operation
Input
The input consists of multiple data sets. Each data set starts with a line containing two positive integers n (1 <= n <= 50) and r (1 <= r <= 50); n and r are the number of cards in the deck and the number of cutting operations, respectively.
There are r more lines in the data set, each of which represents a cutting operation. These cutting operations are performed in the listed order. Each line contains two positive integers p and c (p + c <= n + 1). Starting from the p-th card from the top of the deck, c cards should be pulled out and put on the top.
The end of the input is indicated by a line which contains two zeros.
Each input line contains exactly two integers separated by a space character. There are no other characters in the line.
Output
For each data set in the input, your program should write the number of the top card after the shuffle. Assume that at the beginning the cards are numbered from 1 to n, from the bottom to the top. Each number should be written in a separate line without any superfluous characters such as leading or following spaces.
Example
Input
5 2
3 1
3 1
10 3
1 10
10 1
8 3
0 0
Output
4
4 | instruction | 0 | 81,643 | 19 | 163,286 |
"Correct Solution:
```
while True:
amount, count = map(int, input().split())
if amount == 0 and count == 0:
break
cards = [i for i in reversed(range(1, amount + 1))]
for _ in range(count):
p_th, length = map(int, input().split())
swapper = cards[p_th - 1:p_th + length - 1]
cards[p_th - 1:p_th + length - 1] = []
cards[0:0] = swapper
print(cards[0])
``` | output | 1 | 81,643 | 19 | 163,287 |
Provide a correct Python 3 solution for this coding contest problem.
There are a number of ways to shuffle a deck of cards. Hanafuda shuffling for Japanese card game 'Hanafuda' is one such example. The following is how to perform Hanafuda shuffling.
There is a deck of n cards. Starting from the p-th card from the top of the deck, c cards are pulled out and put on the top of the deck, as shown in Figure 1. This operation, called a cutting operation, is repeated.
Write a program that simulates Hanafuda shuffling and answers which card will be finally placed on the top of the deck.
<image>
---
Figure 1: Cutting operation
Input
The input consists of multiple data sets. Each data set starts with a line containing two positive integers n (1 <= n <= 50) and r (1 <= r <= 50); n and r are the number of cards in the deck and the number of cutting operations, respectively.
There are r more lines in the data set, each of which represents a cutting operation. These cutting operations are performed in the listed order. Each line contains two positive integers p and c (p + c <= n + 1). Starting from the p-th card from the top of the deck, c cards should be pulled out and put on the top.
The end of the input is indicated by a line which contains two zeros.
Each input line contains exactly two integers separated by a space character. There are no other characters in the line.
Output
For each data set in the input, your program should write the number of the top card after the shuffle. Assume that at the beginning the cards are numbered from 1 to n, from the bottom to the top. Each number should be written in a separate line without any superfluous characters such as leading or following spaces.
Example
Input
5 2
3 1
3 1
10 3
1 10
10 1
8 3
0 0
Output
4
4 | instruction | 0 | 81,644 | 19 | 163,288 |
"Correct Solution:
```
while True:
n, r = list(map(lambda x: int(x), input().split(" ")))
if n == 0 and r == 0:
break
cards = [i for i in range(1,n+1)]
cards = cards[::-1]
for i in range(r):
p, c = list(map(lambda x: int(x), input().split(" ")))
p -= 1
cards = cards[p:p+c] + cards[0:p] + cards[p+c:]
print(cards[0])
``` | output | 1 | 81,644 | 19 | 163,289 |
Provide a correct Python 3 solution for this coding contest problem.
There are a number of ways to shuffle a deck of cards. Hanafuda shuffling for Japanese card game 'Hanafuda' is one such example. The following is how to perform Hanafuda shuffling.
There is a deck of n cards. Starting from the p-th card from the top of the deck, c cards are pulled out and put on the top of the deck, as shown in Figure 1. This operation, called a cutting operation, is repeated.
Write a program that simulates Hanafuda shuffling and answers which card will be finally placed on the top of the deck.
<image>
---
Figure 1: Cutting operation
Input
The input consists of multiple data sets. Each data set starts with a line containing two positive integers n (1 <= n <= 50) and r (1 <= r <= 50); n and r are the number of cards in the deck and the number of cutting operations, respectively.
There are r more lines in the data set, each of which represents a cutting operation. These cutting operations are performed in the listed order. Each line contains two positive integers p and c (p + c <= n + 1). Starting from the p-th card from the top of the deck, c cards should be pulled out and put on the top.
The end of the input is indicated by a line which contains two zeros.
Each input line contains exactly two integers separated by a space character. There are no other characters in the line.
Output
For each data set in the input, your program should write the number of the top card after the shuffle. Assume that at the beginning the cards are numbered from 1 to n, from the bottom to the top. Each number should be written in a separate line without any superfluous characters such as leading or following spaces.
Example
Input
5 2
3 1
3 1
10 3
1 10
10 1
8 3
0 0
Output
4
4 | instruction | 0 | 81,645 | 19 | 163,290 |
"Correct Solution:
```
class Deck:
def __init__(self, card_num):
self.deck_list = self.make_deck(card_num)
def make_deck(self, card_num):
deck_list = [None] * card_num
order = 0
for i in reversed(range(1, card_num + 1)):
deck_list[order] = i
order += 1
return deck_list
def shuffled(self, cut_pos1, cut_pos2):
above_card = self.deck_list[0:cut_pos1]
below_card = self.deck_list[cut_pos1:cut_pos2]
remain_card = self.deck_list[cut_pos2:]
self.deck_list = below_card + above_card + remain_card
def get_two_int():
two_int = input().split()
for i in range(2):
two_int[i] = int(two_int[i])
return two_int
if __name__ == "__main__":
while True:
card_num, shuffle_num = get_two_int()
if card_num == shuffle_num == 0:
break
deck = Deck(card_num)
for i in range(shuffle_num):
c, p = get_two_int()
cut_pos1 = c - 1
cut_pos2 = c - 1 + p
deck.shuffled(cut_pos1, cut_pos2)
print(deck.deck_list[0])
``` | output | 1 | 81,645 | 19 | 163,291 |
Provide a correct Python 3 solution for this coding contest problem.
There are a number of ways to shuffle a deck of cards. Hanafuda shuffling for Japanese card game 'Hanafuda' is one such example. The following is how to perform Hanafuda shuffling.
There is a deck of n cards. Starting from the p-th card from the top of the deck, c cards are pulled out and put on the top of the deck, as shown in Figure 1. This operation, called a cutting operation, is repeated.
Write a program that simulates Hanafuda shuffling and answers which card will be finally placed on the top of the deck.
<image>
---
Figure 1: Cutting operation
Input
The input consists of multiple data sets. Each data set starts with a line containing two positive integers n (1 <= n <= 50) and r (1 <= r <= 50); n and r are the number of cards in the deck and the number of cutting operations, respectively.
There are r more lines in the data set, each of which represents a cutting operation. These cutting operations are performed in the listed order. Each line contains two positive integers p and c (p + c <= n + 1). Starting from the p-th card from the top of the deck, c cards should be pulled out and put on the top.
The end of the input is indicated by a line which contains two zeros.
Each input line contains exactly two integers separated by a space character. There are no other characters in the line.
Output
For each data set in the input, your program should write the number of the top card after the shuffle. Assume that at the beginning the cards are numbered from 1 to n, from the bottom to the top. Each number should be written in a separate line without any superfluous characters such as leading or following spaces.
Example
Input
5 2
3 1
3 1
10 3
1 10
10 1
8 3
0 0
Output
4
4 | instruction | 0 | 81,646 | 19 | 163,292 |
"Correct Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**3
eps = 1.0 / 10**10
mod = 10**9+7
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)
def main():
rr = []
while True:
n,r = LI()
if n == 0:
break
a = list(range(n))
for _ in range(r):
p,c = LI()
a = a[p-1:p-1+c] + a[:p-1] + a[p-1+c:]
rr.append(n - a[0])
return '\n'.join(map(str, rr))
print(main())
``` | output | 1 | 81,646 | 19 | 163,293 |
Provide a correct Python 3 solution for this coding contest problem.
There are a number of ways to shuffle a deck of cards. Hanafuda shuffling for Japanese card game 'Hanafuda' is one such example. The following is how to perform Hanafuda shuffling.
There is a deck of n cards. Starting from the p-th card from the top of the deck, c cards are pulled out and put on the top of the deck, as shown in Figure 1. This operation, called a cutting operation, is repeated.
Write a program that simulates Hanafuda shuffling and answers which card will be finally placed on the top of the deck.
<image>
---
Figure 1: Cutting operation
Input
The input consists of multiple data sets. Each data set starts with a line containing two positive integers n (1 <= n <= 50) and r (1 <= r <= 50); n and r are the number of cards in the deck and the number of cutting operations, respectively.
There are r more lines in the data set, each of which represents a cutting operation. These cutting operations are performed in the listed order. Each line contains two positive integers p and c (p + c <= n + 1). Starting from the p-th card from the top of the deck, c cards should be pulled out and put on the top.
The end of the input is indicated by a line which contains two zeros.
Each input line contains exactly two integers separated by a space character. There are no other characters in the line.
Output
For each data set in the input, your program should write the number of the top card after the shuffle. Assume that at the beginning the cards are numbered from 1 to n, from the bottom to the top. Each number should be written in a separate line without any superfluous characters such as leading or following spaces.
Example
Input
5 2
3 1
3 1
10 3
1 10
10 1
8 3
0 0
Output
4
4 | instruction | 0 | 81,647 | 19 | 163,294 |
"Correct Solution:
```
def main():
ans = []
while True:
n, r = map(int, input().split())
if n == 0 and r == 0:
break
cards = []
for i in range(n):
cards.append(i+1)
cards = cards[::-1]
for i in range(r):
p, c = map(int, input().split())
cards = cards[p-1:p-1+c] + cards[:p-1] + cards[p-1+c:]
ans.append(cards[0])
for i in range(len(ans)):
print(ans[i])
main()
``` | output | 1 | 81,647 | 19 | 163,295 |
Provide a correct Python 3 solution for this coding contest problem.
There are a number of ways to shuffle a deck of cards. Hanafuda shuffling for Japanese card game 'Hanafuda' is one such example. The following is how to perform Hanafuda shuffling.
There is a deck of n cards. Starting from the p-th card from the top of the deck, c cards are pulled out and put on the top of the deck, as shown in Figure 1. This operation, called a cutting operation, is repeated.
Write a program that simulates Hanafuda shuffling and answers which card will be finally placed on the top of the deck.
<image>
---
Figure 1: Cutting operation
Input
The input consists of multiple data sets. Each data set starts with a line containing two positive integers n (1 <= n <= 50) and r (1 <= r <= 50); n and r are the number of cards in the deck and the number of cutting operations, respectively.
There are r more lines in the data set, each of which represents a cutting operation. These cutting operations are performed in the listed order. Each line contains two positive integers p and c (p + c <= n + 1). Starting from the p-th card from the top of the deck, c cards should be pulled out and put on the top.
The end of the input is indicated by a line which contains two zeros.
Each input line contains exactly two integers separated by a space character. There are no other characters in the line.
Output
For each data set in the input, your program should write the number of the top card after the shuffle. Assume that at the beginning the cards are numbered from 1 to n, from the bottom to the top. Each number should be written in a separate line without any superfluous characters such as leading or following spaces.
Example
Input
5 2
3 1
3 1
10 3
1 10
10 1
8 3
0 0
Output
4
4 | instruction | 0 | 81,648 | 19 | 163,296 |
"Correct Solution:
```
while 1:
n, r = map(int, input().split())
if n+r < 1 : break
*l, = range(n, 0, -1)
for i in [0]*r:
p, c = map(int, input().split())
p -= 1
l = l[p:p+c] + l[:p] + l[p+c:]
print(l[0])
``` | output | 1 | 81,648 | 19 | 163,297 |
Provide a correct Python 3 solution for this coding contest problem.
There are a number of ways to shuffle a deck of cards. Hanafuda shuffling for Japanese card game 'Hanafuda' is one such example. The following is how to perform Hanafuda shuffling.
There is a deck of n cards. Starting from the p-th card from the top of the deck, c cards are pulled out and put on the top of the deck, as shown in Figure 1. This operation, called a cutting operation, is repeated.
Write a program that simulates Hanafuda shuffling and answers which card will be finally placed on the top of the deck.
<image>
---
Figure 1: Cutting operation
Input
The input consists of multiple data sets. Each data set starts with a line containing two positive integers n (1 <= n <= 50) and r (1 <= r <= 50); n and r are the number of cards in the deck and the number of cutting operations, respectively.
There are r more lines in the data set, each of which represents a cutting operation. These cutting operations are performed in the listed order. Each line contains two positive integers p and c (p + c <= n + 1). Starting from the p-th card from the top of the deck, c cards should be pulled out and put on the top.
The end of the input is indicated by a line which contains two zeros.
Each input line contains exactly two integers separated by a space character. There are no other characters in the line.
Output
For each data set in the input, your program should write the number of the top card after the shuffle. Assume that at the beginning the cards are numbered from 1 to n, from the bottom to the top. Each number should be written in a separate line without any superfluous characters such as leading or following spaces.
Example
Input
5 2
3 1
3 1
10 3
1 10
10 1
8 3
0 0
Output
4
4 | instruction | 0 | 81,649 | 19 | 163,298 |
"Correct Solution:
```
while True:
n, r = map(int, input().split())
if n == 0 and r == 0:
break
cards = list(range(1, n+1))[::-1]
for _ in range(r):
p, c = map(int, input().split())
cards = cards[p-1:p-1+c] + cards[:p-1] + cards[p-1+c:]
print(cards[0])
``` | output | 1 | 81,649 | 19 | 163,299 |
Provide a correct Python 3 solution for this coding contest problem.
There are a number of ways to shuffle a deck of cards. Hanafuda shuffling for Japanese card game 'Hanafuda' is one such example. The following is how to perform Hanafuda shuffling.
There is a deck of n cards. Starting from the p-th card from the top of the deck, c cards are pulled out and put on the top of the deck, as shown in Figure 1. This operation, called a cutting operation, is repeated.
Write a program that simulates Hanafuda shuffling and answers which card will be finally placed on the top of the deck.
<image>
---
Figure 1: Cutting operation
Input
The input consists of multiple data sets. Each data set starts with a line containing two positive integers n (1 <= n <= 50) and r (1 <= r <= 50); n and r are the number of cards in the deck and the number of cutting operations, respectively.
There are r more lines in the data set, each of which represents a cutting operation. These cutting operations are performed in the listed order. Each line contains two positive integers p and c (p + c <= n + 1). Starting from the p-th card from the top of the deck, c cards should be pulled out and put on the top.
The end of the input is indicated by a line which contains two zeros.
Each input line contains exactly two integers separated by a space character. There are no other characters in the line.
Output
For each data set in the input, your program should write the number of the top card after the shuffle. Assume that at the beginning the cards are numbered from 1 to n, from the bottom to the top. Each number should be written in a separate line without any superfluous characters such as leading or following spaces.
Example
Input
5 2
3 1
3 1
10 3
1 10
10 1
8 3
0 0
Output
4
4 | instruction | 0 | 81,650 | 19 | 163,300 |
"Correct Solution:
```
# Hanafuda Shuffle
ans = []
while True:
n, r = map(int, input().split())
if n == 0 and r == 0:
break
deck = [i + 1 for i in range(n)]
deck.reverse()
for i in range(r):
p, c = map(int, input().split())
p -= 1
deck = deck[p:p+c] + deck[:p] + deck[p+c:]
ans.append(deck[0])
for i in ans:
print(i)
``` | output | 1 | 81,650 | 19 | 163,301 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are a number of ways to shuffle a deck of cards. Hanafuda shuffling for Japanese card game 'Hanafuda' is one such example. The following is how to perform Hanafuda shuffling.
There is a deck of n cards. Starting from the p-th card from the top of the deck, c cards are pulled out and put on the top of the deck, as shown in Figure 1. This operation, called a cutting operation, is repeated.
Write a program that simulates Hanafuda shuffling and answers which card will be finally placed on the top of the deck.
<image>
---
Figure 1: Cutting operation
Input
The input consists of multiple data sets. Each data set starts with a line containing two positive integers n (1 <= n <= 50) and r (1 <= r <= 50); n and r are the number of cards in the deck and the number of cutting operations, respectively.
There are r more lines in the data set, each of which represents a cutting operation. These cutting operations are performed in the listed order. Each line contains two positive integers p and c (p + c <= n + 1). Starting from the p-th card from the top of the deck, c cards should be pulled out and put on the top.
The end of the input is indicated by a line which contains two zeros.
Each input line contains exactly two integers separated by a space character. There are no other characters in the line.
Output
For each data set in the input, your program should write the number of the top card after the shuffle. Assume that at the beginning the cards are numbered from 1 to n, from the bottom to the top. Each number should be written in a separate line without any superfluous characters such as leading or following spaces.
Example
Input
5 2
3 1
3 1
10 3
1 10
10 1
8 3
0 0
Output
4
4
Submitted Solution:
```
while True:
n,r = map(int,input().split())
if n == r == 0: break
cards = [n-i for i in range(n)]
for i in range(r):
p,c = map(int,input().split())
cards = cards[p-1:p-1+c] + cards[:p-1] + cards[p-1+c:]
print(cards[0])
``` | instruction | 0 | 81,651 | 19 | 163,302 |
Yes | output | 1 | 81,651 | 19 | 163,303 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are a number of ways to shuffle a deck of cards. Hanafuda shuffling for Japanese card game 'Hanafuda' is one such example. The following is how to perform Hanafuda shuffling.
There is a deck of n cards. Starting from the p-th card from the top of the deck, c cards are pulled out and put on the top of the deck, as shown in Figure 1. This operation, called a cutting operation, is repeated.
Write a program that simulates Hanafuda shuffling and answers which card will be finally placed on the top of the deck.
<image>
---
Figure 1: Cutting operation
Input
The input consists of multiple data sets. Each data set starts with a line containing two positive integers n (1 <= n <= 50) and r (1 <= r <= 50); n and r are the number of cards in the deck and the number of cutting operations, respectively.
There are r more lines in the data set, each of which represents a cutting operation. These cutting operations are performed in the listed order. Each line contains two positive integers p and c (p + c <= n + 1). Starting from the p-th card from the top of the deck, c cards should be pulled out and put on the top.
The end of the input is indicated by a line which contains two zeros.
Each input line contains exactly two integers separated by a space character. There are no other characters in the line.
Output
For each data set in the input, your program should write the number of the top card after the shuffle. Assume that at the beginning the cards are numbered from 1 to n, from the bottom to the top. Each number should be written in a separate line without any superfluous characters such as leading or following spaces.
Example
Input
5 2
3 1
3 1
10 3
1 10
10 1
8 3
0 0
Output
4
4
Submitted Solution:
```
def main(n, m):
dp = [(i + 1) for i in range(n)]
dp = dp[::-1]
for _ in range(m):
p, c = map(int, input().split())
dp = dp[p - 1:p + c - 1] + dp[:p - 1] + dp[p + c - 1:]
print(dp[0])
while 1:
n, r = map(int, input().split())
if n == r == 0:
break
main(n,r)
``` | instruction | 0 | 81,652 | 19 | 163,304 |
Yes | output | 1 | 81,652 | 19 | 163,305 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are a number of ways to shuffle a deck of cards. Hanafuda shuffling for Japanese card game 'Hanafuda' is one such example. The following is how to perform Hanafuda shuffling.
There is a deck of n cards. Starting from the p-th card from the top of the deck, c cards are pulled out and put on the top of the deck, as shown in Figure 1. This operation, called a cutting operation, is repeated.
Write a program that simulates Hanafuda shuffling and answers which card will be finally placed on the top of the deck.
<image>
---
Figure 1: Cutting operation
Input
The input consists of multiple data sets. Each data set starts with a line containing two positive integers n (1 <= n <= 50) and r (1 <= r <= 50); n and r are the number of cards in the deck and the number of cutting operations, respectively.
There are r more lines in the data set, each of which represents a cutting operation. These cutting operations are performed in the listed order. Each line contains two positive integers p and c (p + c <= n + 1). Starting from the p-th card from the top of the deck, c cards should be pulled out and put on the top.
The end of the input is indicated by a line which contains two zeros.
Each input line contains exactly two integers separated by a space character. There are no other characters in the line.
Output
For each data set in the input, your program should write the number of the top card after the shuffle. Assume that at the beginning the cards are numbered from 1 to n, from the bottom to the top. Each number should be written in a separate line without any superfluous characters such as leading or following spaces.
Example
Input
5 2
3 1
3 1
10 3
1 10
10 1
8 3
0 0
Output
4
4
Submitted Solution:
```
# encoding: utf-8
def create_deck(deck_size):
deck = []
for i in range(0,deck_size):
deck.append(i+1)
return deck
def shuffle_deck(deck, start, cut_size):
after = []
cut_cards = []
b = len(deck) - cut_size - start
for i in range(0,len(deck)):
if b >= i:
after.append(deck[i])
continue
if (b+cut_size) >= i:
cut_cards.append(deck[i])
continue
after.append(deck[i])
after.extend(cut_cards)
return after
while True:
data = input().split()
deck_size, shuffle_count = int(data[0]),int(data[1])
if deck_size == shuffle_count == 0: break
deck = create_deck(deck_size)
for i in range(0,shuffle_count):
cut_info = data = input().split()
start, cut_size = int(cut_info[0]),int(cut_info[1])
deck = shuffle_deck(deck, start, cut_size)
print(deck[len(deck)-1])
``` | instruction | 0 | 81,653 | 19 | 163,306 |
Yes | output | 1 | 81,653 | 19 | 163,307 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are a number of ways to shuffle a deck of cards. Hanafuda shuffling for Japanese card game 'Hanafuda' is one such example. The following is how to perform Hanafuda shuffling.
There is a deck of n cards. Starting from the p-th card from the top of the deck, c cards are pulled out and put on the top of the deck, as shown in Figure 1. This operation, called a cutting operation, is repeated.
Write a program that simulates Hanafuda shuffling and answers which card will be finally placed on the top of the deck.
<image>
---
Figure 1: Cutting operation
Input
The input consists of multiple data sets. Each data set starts with a line containing two positive integers n (1 <= n <= 50) and r (1 <= r <= 50); n and r are the number of cards in the deck and the number of cutting operations, respectively.
There are r more lines in the data set, each of which represents a cutting operation. These cutting operations are performed in the listed order. Each line contains two positive integers p and c (p + c <= n + 1). Starting from the p-th card from the top of the deck, c cards should be pulled out and put on the top.
The end of the input is indicated by a line which contains two zeros.
Each input line contains exactly two integers separated by a space character. There are no other characters in the line.
Output
For each data set in the input, your program should write the number of the top card after the shuffle. Assume that at the beginning the cards are numbered from 1 to n, from the bottom to the top. Each number should be written in a separate line without any superfluous characters such as leading or following spaces.
Example
Input
5 2
3 1
3 1
10 3
1 10
10 1
8 3
0 0
Output
4
4
Submitted Solution:
```
while (True):
n, r = map(lambda i: int(i), input().split())
if n == 0:
break
inds = [i for i in reversed(range(1, n+1))]
for i in range(r):
p, c = map(lambda j: int(j), input().split())
inds = inds[p-1:p-1+c] + inds[:p-1] + inds[p-1+c:]
print(inds[0])
``` | instruction | 0 | 81,654 | 19 | 163,308 |
Yes | output | 1 | 81,654 | 19 | 163,309 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are a number of ways to shuffle a deck of cards. Hanafuda shuffling for Japanese card game 'Hanafuda' is one such example. The following is how to perform Hanafuda shuffling.
There is a deck of n cards. Starting from the p-th card from the top of the deck, c cards are pulled out and put on the top of the deck, as shown in Figure 1. This operation, called a cutting operation, is repeated.
Write a program that simulates Hanafuda shuffling and answers which card will be finally placed on the top of the deck.
<image>
---
Figure 1: Cutting operation
Input
The input consists of multiple data sets. Each data set starts with a line containing two positive integers n (1 <= n <= 50) and r (1 <= r <= 50); n and r are the number of cards in the deck and the number of cutting operations, respectively.
There are r more lines in the data set, each of which represents a cutting operation. These cutting operations are performed in the listed order. Each line contains two positive integers p and c (p + c <= n + 1). Starting from the p-th card from the top of the deck, c cards should be pulled out and put on the top.
The end of the input is indicated by a line which contains two zeros.
Each input line contains exactly two integers separated by a space character. There are no other characters in the line.
Output
For each data set in the input, your program should write the number of the top card after the shuffle. Assume that at the beginning the cards are numbered from 1 to n, from the bottom to the top. Each number should be written in a separate line without any superfluous characters such as leading or following spaces.
Example
Input
5 2
3 1
3 1
10 3
1 10
10 1
8 3
0 0
Output
4
4
Submitted Solution:
```
cond = [int(n) for n in input().split(" ")]
while True:
case = []
cards = [n for n in range(1,cond[0] + 1)]
for c in range(cond[1]):
case = [int(n) for n in input().split(" ")]
disp = cards[case[0]:case[0]+case[1]]
cards[case[0]:case[0]+case[1]] = cards[case[0]-case[1]:case[0]]
cards[case[0]-case[1]:case[0]] = disp
else:
print(cards[0])
cond = [int(n) for n in input().split(" ")]
if cond[0] == 0 and cond[1] == 0:
break
else:
continue
``` | instruction | 0 | 81,655 | 19 | 163,310 |
No | output | 1 | 81,655 | 19 | 163,311 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are a number of ways to shuffle a deck of cards. Hanafuda shuffling for Japanese card game 'Hanafuda' is one such example. The following is how to perform Hanafuda shuffling.
There is a deck of n cards. Starting from the p-th card from the top of the deck, c cards are pulled out and put on the top of the deck, as shown in Figure 1. This operation, called a cutting operation, is repeated.
Write a program that simulates Hanafuda shuffling and answers which card will be finally placed on the top of the deck.
<image>
---
Figure 1: Cutting operation
Input
The input consists of multiple data sets. Each data set starts with a line containing two positive integers n (1 <= n <= 50) and r (1 <= r <= 50); n and r are the number of cards in the deck and the number of cutting operations, respectively.
There are r more lines in the data set, each of which represents a cutting operation. These cutting operations are performed in the listed order. Each line contains two positive integers p and c (p + c <= n + 1). Starting from the p-th card from the top of the deck, c cards should be pulled out and put on the top.
The end of the input is indicated by a line which contains two zeros.
Each input line contains exactly two integers separated by a space character. There are no other characters in the line.
Output
For each data set in the input, your program should write the number of the top card after the shuffle. Assume that at the beginning the cards are numbered from 1 to n, from the bottom to the top. Each number should be written in a separate line without any superfluous characters such as leading or following spaces.
Example
Input
5 2
3 1
3 1
10 3
1 10
10 1
8 3
0 0
Output
4
4
Submitted Solution:
```
#hanafuda
N,r=(int(i) for i in input().split())
H=[int(i) for i in range(N)]
for i in range(N):
p,c=(int(i) for i in input().split())
T=[]
for j in range(p,p+c-1):
T.append(H[p])
H.pop(p)
H=T+H
print(H[0])
``` | instruction | 0 | 81,656 | 19 | 163,312 |
No | output | 1 | 81,656 | 19 | 163,313 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are a number of ways to shuffle a deck of cards. Hanafuda shuffling for Japanese card game 'Hanafuda' is one such example. The following is how to perform Hanafuda shuffling.
There is a deck of n cards. Starting from the p-th card from the top of the deck, c cards are pulled out and put on the top of the deck, as shown in Figure 1. This operation, called a cutting operation, is repeated.
Write a program that simulates Hanafuda shuffling and answers which card will be finally placed on the top of the deck.
<image>
---
Figure 1: Cutting operation
Input
The input consists of multiple data sets. Each data set starts with a line containing two positive integers n (1 <= n <= 50) and r (1 <= r <= 50); n and r are the number of cards in the deck and the number of cutting operations, respectively.
There are r more lines in the data set, each of which represents a cutting operation. These cutting operations are performed in the listed order. Each line contains two positive integers p and c (p + c <= n + 1). Starting from the p-th card from the top of the deck, c cards should be pulled out and put on the top.
The end of the input is indicated by a line which contains two zeros.
Each input line contains exactly two integers separated by a space character. There are no other characters in the line.
Output
For each data set in the input, your program should write the number of the top card after the shuffle. Assume that at the beginning the cards are numbered from 1 to n, from the bottom to the top. Each number should be written in a separate line without any superfluous characters such as leading or following spaces.
Example
Input
5 2
3 1
3 1
10 3
1 10
10 1
8 3
0 0
Output
4
4
Submitted Solution:
```
while True:
n, r = list(map(lambda x: int(x), input().split(" ")))
if n == 0 and r == 0:
break
cards = [i for i in range(1,n+1)]
cards = cards[::-1]
for i in range(r):
print(cards)
p, c = list(map(lambda x: int(x), input().split(" ")))
p -= 1
cards = cards[p:p+c] + cards[0:p] + cards[p+c:]
print(cards[0])
``` | instruction | 0 | 81,657 | 19 | 163,314 |
No | output | 1 | 81,657 | 19 | 163,315 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are a number of ways to shuffle a deck of cards. Hanafuda shuffling for Japanese card game 'Hanafuda' is one such example. The following is how to perform Hanafuda shuffling.
There is a deck of n cards. Starting from the p-th card from the top of the deck, c cards are pulled out and put on the top of the deck, as shown in Figure 1. This operation, called a cutting operation, is repeated.
Write a program that simulates Hanafuda shuffling and answers which card will be finally placed on the top of the deck.
<image>
---
Figure 1: Cutting operation
Input
The input consists of multiple data sets. Each data set starts with a line containing two positive integers n (1 <= n <= 50) and r (1 <= r <= 50); n and r are the number of cards in the deck and the number of cutting operations, respectively.
There are r more lines in the data set, each of which represents a cutting operation. These cutting operations are performed in the listed order. Each line contains two positive integers p and c (p + c <= n + 1). Starting from the p-th card from the top of the deck, c cards should be pulled out and put on the top.
The end of the input is indicated by a line which contains two zeros.
Each input line contains exactly two integers separated by a space character. There are no other characters in the line.
Output
For each data set in the input, your program should write the number of the top card after the shuffle. Assume that at the beginning the cards are numbered from 1 to n, from the bottom to the top. Each number should be written in a separate line without any superfluous characters such as leading or following spaces.
Example
Input
5 2
3 1
3 1
10 3
1 10
10 1
8 3
0 0
Output
4
4
Submitted Solution:
```
while True:
sousa=input().sprit() #?????????
sousa=[int(sousa[0]),int(sousa[1])]
if sousa==[0,0]:break
yama=[]
for k in range(sousa[0]):yama.append(k+1)
yama=yama[::-1]
for r in range(sousa[1]):
[p,c]=input().sprit()
[p,c]=[int(p),int(c)]
yama[:p+c-1]=yama[p-1:p+c-1]+yama[:p-2]
print(yama[0])
``` | instruction | 0 | 81,658 | 19 | 163,316 |
No | output | 1 | 81,658 | 19 | 163,317 |
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