message stringlengths 2 67k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 463 109k | cluster float64 19 19 | __index_level_0__ int64 926 217k |
|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
There are N cards placed face down in a row. On each card, an integer 1 or 2 is written.
Let A_i be the integer written on the i-th card.
Your objective is to guess A_1, A_2, ..., A_N correctly.
You know the following facts:
* For each i = 1, 2, ..., M, the value A_{X_i} + A_{Y_i} + Z_i is an even number.
You are a magician and can use the following magic any number of times:
Magic: Choose one card and know the integer A_i written on it. The cost of using this magic is 1.
What is the minimum cost required to determine all of A_1, A_2, ..., A_N?
It is guaranteed that there is no contradiction in given input.
Constraints
* All values in input are integers.
* 2 \leq N \leq 10^5
* 1 \leq M \leq 10^5
* 1 \leq X_i < Y_i \leq N
* 1 \leq Z_i \leq 100
* The pairs (X_i, Y_i) are distinct.
* There is no contradiction in input. (That is, there exist integers A_1, A_2, ..., A_N that satisfy the conditions.)
Input
Input is given from Standard Input in the following format:
N M
X_1 Y_1 Z_1
X_2 Y_2 Z_2
\vdots
X_M Y_M Z_M
Output
Print the minimum total cost required to determine all of A_1, A_2, ..., A_N.
Examples
Input
3 1
1 2 1
Output
2
Input
6 5
1 2 1
2 3 2
1 3 3
4 5 4
5 6 5
Output
2
Input
100000 1
1 100000 100
Output
99999 | instruction | 0 | 85,557 | 19 | 171,114 |
"Correct Solution:
```
N, M = map(int, input().split())
v = set()
def dfs(graph, start, visited):
stack = [start]
visited.add(start)
while stack:
label = stack.pop(0)
for node in g[label]:
if node not in visited:
visited.add(node)
stack.append(node)
return visited
g = {i: [] for i in range(1, N + 1)}
for i in range(M):
x, y, z = map(int, input().split())
g[x].append(y)
g[y].append(x)
ans = 0
for i in range(1, N + 1):
if i not in v:
ans += 1
dfs(g, i, v)
print(ans)
``` | output | 1 | 85,557 | 19 | 171,115 |
Provide a correct Python 3 solution for this coding contest problem.
There are N cards placed face down in a row. On each card, an integer 1 or 2 is written.
Let A_i be the integer written on the i-th card.
Your objective is to guess A_1, A_2, ..., A_N correctly.
You know the following facts:
* For each i = 1, 2, ..., M, the value A_{X_i} + A_{Y_i} + Z_i is an even number.
You are a magician and can use the following magic any number of times:
Magic: Choose one card and know the integer A_i written on it. The cost of using this magic is 1.
What is the minimum cost required to determine all of A_1, A_2, ..., A_N?
It is guaranteed that there is no contradiction in given input.
Constraints
* All values in input are integers.
* 2 \leq N \leq 10^5
* 1 \leq M \leq 10^5
* 1 \leq X_i < Y_i \leq N
* 1 \leq Z_i \leq 100
* The pairs (X_i, Y_i) are distinct.
* There is no contradiction in input. (That is, there exist integers A_1, A_2, ..., A_N that satisfy the conditions.)
Input
Input is given from Standard Input in the following format:
N M
X_1 Y_1 Z_1
X_2 Y_2 Z_2
\vdots
X_M Y_M Z_M
Output
Print the minimum total cost required to determine all of A_1, A_2, ..., A_N.
Examples
Input
3 1
1 2 1
Output
2
Input
6 5
1 2 1
2 3 2
1 3 3
4 5 4
5 6 5
Output
2
Input
100000 1
1 100000 100
Output
99999 | instruction | 0 | 85,558 | 19 | 171,116 |
"Correct Solution:
```
import sys
sys.setrecursionlimit(10**7)
input = sys.stdin.readline
n, m = map(int, input().split())
graph = [[] for _ in range(n)]
for i in range(m):
x, y, z = map(int, input().split())
x -= 1
y -= 1
graph[x].append(y)
graph[y].append(x)
memo = [-1] * n
def dfs(v, memo):
memo[v] = 1
for nv in graph[v]:
if memo[nv] != -1:
continue
dfs(nv, memo)
ans = 0
for i in range(n):
if memo[i] != -1:
continue
dfs(i, memo)
ans += 1
print(ans)
``` | output | 1 | 85,558 | 19 | 171,117 |
Provide a correct Python 3 solution for this coding contest problem.
There are N cards placed face down in a row. On each card, an integer 1 or 2 is written.
Let A_i be the integer written on the i-th card.
Your objective is to guess A_1, A_2, ..., A_N correctly.
You know the following facts:
* For each i = 1, 2, ..., M, the value A_{X_i} + A_{Y_i} + Z_i is an even number.
You are a magician and can use the following magic any number of times:
Magic: Choose one card and know the integer A_i written on it. The cost of using this magic is 1.
What is the minimum cost required to determine all of A_1, A_2, ..., A_N?
It is guaranteed that there is no contradiction in given input.
Constraints
* All values in input are integers.
* 2 \leq N \leq 10^5
* 1 \leq M \leq 10^5
* 1 \leq X_i < Y_i \leq N
* 1 \leq Z_i \leq 100
* The pairs (X_i, Y_i) are distinct.
* There is no contradiction in input. (That is, there exist integers A_1, A_2, ..., A_N that satisfy the conditions.)
Input
Input is given from Standard Input in the following format:
N M
X_1 Y_1 Z_1
X_2 Y_2 Z_2
\vdots
X_M Y_M Z_M
Output
Print the minimum total cost required to determine all of A_1, A_2, ..., A_N.
Examples
Input
3 1
1 2 1
Output
2
Input
6 5
1 2 1
2 3 2
1 3 3
4 5 4
5 6 5
Output
2
Input
100000 1
1 100000 100
Output
99999 | instruction | 0 | 85,559 | 19 | 171,118 |
"Correct Solution:
```
N, M = map(int, input().split())
par = [i for i in range(N+1)]
h = [1 for _ in range(N+1)]
def root(x):
if par[x] == x:
return x
par[x] = root(par[x])
return par[x]
def unite(x,y):
rx = root(x)
ry = root(y)
if h[rx] < h[ry]:
rx, ry = ry, rx
h[rx] += h[ry]
par[ry] = rx
for _ in range(M):
x,y,z = map(int, input().split())
unite(x,y)
for i in range(1,N+1):
par[i] = root(i)
print(len(set(par[1:])))
``` | output | 1 | 85,559 | 19 | 171,119 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N cards placed face down in a row. On each card, an integer 1 or 2 is written.
Let A_i be the integer written on the i-th card.
Your objective is to guess A_1, A_2, ..., A_N correctly.
You know the following facts:
* For each i = 1, 2, ..., M, the value A_{X_i} + A_{Y_i} + Z_i is an even number.
You are a magician and can use the following magic any number of times:
Magic: Choose one card and know the integer A_i written on it. The cost of using this magic is 1.
What is the minimum cost required to determine all of A_1, A_2, ..., A_N?
It is guaranteed that there is no contradiction in given input.
Constraints
* All values in input are integers.
* 2 \leq N \leq 10^5
* 1 \leq M \leq 10^5
* 1 \leq X_i < Y_i \leq N
* 1 \leq Z_i \leq 100
* The pairs (X_i, Y_i) are distinct.
* There is no contradiction in input. (That is, there exist integers A_1, A_2, ..., A_N that satisfy the conditions.)
Input
Input is given from Standard Input in the following format:
N M
X_1 Y_1 Z_1
X_2 Y_2 Z_2
\vdots
X_M Y_M Z_M
Output
Print the minimum total cost required to determine all of A_1, A_2, ..., A_N.
Examples
Input
3 1
1 2 1
Output
2
Input
6 5
1 2 1
2 3 2
1 3 3
4 5 4
5 6 5
Output
2
Input
100000 1
1 100000 100
Output
99999
Submitted Solution:
```
n, m = map(int,input().split())
par = [i for i in range(n+1)]
rank = [0] * (n+1)
def find(x):
if par[x] == x:
return x
return find(par[x])
def unite(x,y):
root_x = find(x)
root_y = find(y)
if rank[root_x] != rank[root_y]:
par[min(root_x,root_y)] = max(root_x,root_y)
else:
par[root_y] = root_x
rank[root_x] += 1
for i in range(m):
x, y, z = map(int,input().split())
unite(x,y)
roo = [-1]
for i in range(n):
roo.append(find(i+1))
print(len(set(roo))-1)
``` | instruction | 0 | 85,560 | 19 | 171,120 |
Yes | output | 1 | 85,560 | 19 | 171,121 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N cards placed face down in a row. On each card, an integer 1 or 2 is written.
Let A_i be the integer written on the i-th card.
Your objective is to guess A_1, A_2, ..., A_N correctly.
You know the following facts:
* For each i = 1, 2, ..., M, the value A_{X_i} + A_{Y_i} + Z_i is an even number.
You are a magician and can use the following magic any number of times:
Magic: Choose one card and know the integer A_i written on it. The cost of using this magic is 1.
What is the minimum cost required to determine all of A_1, A_2, ..., A_N?
It is guaranteed that there is no contradiction in given input.
Constraints
* All values in input are integers.
* 2 \leq N \leq 10^5
* 1 \leq M \leq 10^5
* 1 \leq X_i < Y_i \leq N
* 1 \leq Z_i \leq 100
* The pairs (X_i, Y_i) are distinct.
* There is no contradiction in input. (That is, there exist integers A_1, A_2, ..., A_N that satisfy the conditions.)
Input
Input is given from Standard Input in the following format:
N M
X_1 Y_1 Z_1
X_2 Y_2 Z_2
\vdots
X_M Y_M Z_M
Output
Print the minimum total cost required to determine all of A_1, A_2, ..., A_N.
Examples
Input
3 1
1 2 1
Output
2
Input
6 5
1 2 1
2 3 2
1 3 3
4 5 4
5 6 5
Output
2
Input
100000 1
1 100000 100
Output
99999
Submitted Solution:
```
n, m = map(int, input().split())
a = [i for i in range(n + 1)]
def find(a, x):
if a[x] != x:
a[x] = find(a, a[x])
return a[x]
def unite(a, x, y):
x = find(a, x)
y = find(a, y)
if x != y:
a[x] = min(x, y)
a[y] = a[x]
for i in range(m):
x,y,z=map(int,input().split())
unite(a,x,y)
ans = -1
for i, v in enumerate(a):
if i == v:
ans += 1
print(ans)
``` | instruction | 0 | 85,561 | 19 | 171,122 |
Yes | output | 1 | 85,561 | 19 | 171,123 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N cards placed face down in a row. On each card, an integer 1 or 2 is written.
Let A_i be the integer written on the i-th card.
Your objective is to guess A_1, A_2, ..., A_N correctly.
You know the following facts:
* For each i = 1, 2, ..., M, the value A_{X_i} + A_{Y_i} + Z_i is an even number.
You are a magician and can use the following magic any number of times:
Magic: Choose one card and know the integer A_i written on it. The cost of using this magic is 1.
What is the minimum cost required to determine all of A_1, A_2, ..., A_N?
It is guaranteed that there is no contradiction in given input.
Constraints
* All values in input are integers.
* 2 \leq N \leq 10^5
* 1 \leq M \leq 10^5
* 1 \leq X_i < Y_i \leq N
* 1 \leq Z_i \leq 100
* The pairs (X_i, Y_i) are distinct.
* There is no contradiction in input. (That is, there exist integers A_1, A_2, ..., A_N that satisfy the conditions.)
Input
Input is given from Standard Input in the following format:
N M
X_1 Y_1 Z_1
X_2 Y_2 Z_2
\vdots
X_M Y_M Z_M
Output
Print the minimum total cost required to determine all of A_1, A_2, ..., A_N.
Examples
Input
3 1
1 2 1
Output
2
Input
6 5
1 2 1
2 3 2
1 3 3
4 5 4
5 6 5
Output
2
Input
100000 1
1 100000 100
Output
99999
Submitted Solution:
```
import sys
sys.setrecursionlimit(100000)
N, M = [int(_) for _ in input().split()]
XYZ = [[int(_) for _ in input().split()] for _ in range(M)]
UF = list(range(N + 1))
def find(x):
if UF[x] != x:
UF[x] = find(UF[x])
return UF[x]
def unite(x, y):
UF[find(x)] = find(y)
def same(x, y):
return find(x) == find(y)
for x, y, z in XYZ:
unite(x, y)
s = set()
for i in range(1, N + 1):
s.add(find(i))
print(len(set(s)))
``` | instruction | 0 | 85,562 | 19 | 171,124 |
Yes | output | 1 | 85,562 | 19 | 171,125 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N cards placed face down in a row. On each card, an integer 1 or 2 is written.
Let A_i be the integer written on the i-th card.
Your objective is to guess A_1, A_2, ..., A_N correctly.
You know the following facts:
* For each i = 1, 2, ..., M, the value A_{X_i} + A_{Y_i} + Z_i is an even number.
You are a magician and can use the following magic any number of times:
Magic: Choose one card and know the integer A_i written on it. The cost of using this magic is 1.
What is the minimum cost required to determine all of A_1, A_2, ..., A_N?
It is guaranteed that there is no contradiction in given input.
Constraints
* All values in input are integers.
* 2 \leq N \leq 10^5
* 1 \leq M \leq 10^5
* 1 \leq X_i < Y_i \leq N
* 1 \leq Z_i \leq 100
* The pairs (X_i, Y_i) are distinct.
* There is no contradiction in input. (That is, there exist integers A_1, A_2, ..., A_N that satisfy the conditions.)
Input
Input is given from Standard Input in the following format:
N M
X_1 Y_1 Z_1
X_2 Y_2 Z_2
\vdots
X_M Y_M Z_M
Output
Print the minimum total cost required to determine all of A_1, A_2, ..., A_N.
Examples
Input
3 1
1 2 1
Output
2
Input
6 5
1 2 1
2 3 2
1 3 3
4 5 4
5 6 5
Output
2
Input
100000 1
1 100000 100
Output
99999
Submitted Solution:
```
import sys
sys.setrecursionlimit(10**6)
def dfs(x, g, vis):
if vis[x]:
return
vis[x] = 1
for y in g[x]:
dfs(y, g, vis)
def main():
N, M = map(int, input().split())
g = [[] for _ in range(N)]
for i in range(M):
X, Y, Z = map(int, input().split())
X -= 1
Y -= 1
g[X].append(Y)
g[Y].append(X)
vis = [0] * N
ans = 0
for i in range(N):
if vis[i] == 0:
dfs(i, g, vis)
ans += 1
print(ans)
main()
``` | instruction | 0 | 85,563 | 19 | 171,126 |
Yes | output | 1 | 85,563 | 19 | 171,127 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N cards placed face down in a row. On each card, an integer 1 or 2 is written.
Let A_i be the integer written on the i-th card.
Your objective is to guess A_1, A_2, ..., A_N correctly.
You know the following facts:
* For each i = 1, 2, ..., M, the value A_{X_i} + A_{Y_i} + Z_i is an even number.
You are a magician and can use the following magic any number of times:
Magic: Choose one card and know the integer A_i written on it. The cost of using this magic is 1.
What is the minimum cost required to determine all of A_1, A_2, ..., A_N?
It is guaranteed that there is no contradiction in given input.
Constraints
* All values in input are integers.
* 2 \leq N \leq 10^5
* 1 \leq M \leq 10^5
* 1 \leq X_i < Y_i \leq N
* 1 \leq Z_i \leq 100
* The pairs (X_i, Y_i) are distinct.
* There is no contradiction in input. (That is, there exist integers A_1, A_2, ..., A_N that satisfy the conditions.)
Input
Input is given from Standard Input in the following format:
N M
X_1 Y_1 Z_1
X_2 Y_2 Z_2
\vdots
X_M Y_M Z_M
Output
Print the minimum total cost required to determine all of A_1, A_2, ..., A_N.
Examples
Input
3 1
1 2 1
Output
2
Input
6 5
1 2 1
2 3 2
1 3 3
4 5 4
5 6 5
Output
2
Input
100000 1
1 100000 100
Output
99999
Submitted Solution:
```
# segtree
N, M = map(int, input().split())
parent = list(range(N + 1))
for _ in range(M):
x, y, _ = map(int, input().split())
x_list = [x]
parent[x] = y
while x != parent[x]:
x = parent[x]
x_list.append(x)
for a in x_list:
parent[a] = x
print(x, x_list)
for i in range(N + 1):
x = i
x_list = [x]
while x != parent[x]:
x = parent[x]
x_list.append(x)
for a in x_list:
parent[a] = x
print(x, x_list)
res = [0] * (N + 1)
res_c = 0
for i in range(1, N + 1):
j = parent[i]
if res[j] == 0:
res_c += 1
res[j] += 1
print(N - (sum(res) - res_c))
``` | instruction | 0 | 85,564 | 19 | 171,128 |
No | output | 1 | 85,564 | 19 | 171,129 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N cards placed face down in a row. On each card, an integer 1 or 2 is written.
Let A_i be the integer written on the i-th card.
Your objective is to guess A_1, A_2, ..., A_N correctly.
You know the following facts:
* For each i = 1, 2, ..., M, the value A_{X_i} + A_{Y_i} + Z_i is an even number.
You are a magician and can use the following magic any number of times:
Magic: Choose one card and know the integer A_i written on it. The cost of using this magic is 1.
What is the minimum cost required to determine all of A_1, A_2, ..., A_N?
It is guaranteed that there is no contradiction in given input.
Constraints
* All values in input are integers.
* 2 \leq N \leq 10^5
* 1 \leq M \leq 10^5
* 1 \leq X_i < Y_i \leq N
* 1 \leq Z_i \leq 100
* The pairs (X_i, Y_i) are distinct.
* There is no contradiction in input. (That is, there exist integers A_1, A_2, ..., A_N that satisfy the conditions.)
Input
Input is given from Standard Input in the following format:
N M
X_1 Y_1 Z_1
X_2 Y_2 Z_2
\vdots
X_M Y_M Z_M
Output
Print the minimum total cost required to determine all of A_1, A_2, ..., A_N.
Examples
Input
3 1
1 2 1
Output
2
Input
6 5
1 2 1
2 3 2
1 3 3
4 5 4
5 6 5
Output
2
Input
100000 1
1 100000 100
Output
99999
Submitted Solution:
```
import sys
import heapq
import re
from itertools import permutations
from bisect import bisect_left, bisect_right
from collections import Counter, deque
from math import factorial, sqrt, ceil, gcd
from functools import lru_cache, reduce
from decimal import Decimal
from operator import mul
INF = 1 << 60
MOD = 1000000007
sys.setrecursionlimit(10 ** 7)
# UnionFind
class UnionFind():
def __init__(self, n):
self.n = n
self.parents = [-1] * n
def find(self, x):
if self.parents[x] < 0:
return x
else:
self.parents[x] = self.find(self.parents[x])
return self.parents[x]
def union(self, x, y):
x = self.find(x)
y = self.find(y)
if x == y:
return
if self.parents[x] > self.parents[y]:
x, y = y, x
self.parents[x] += self.parents[y]
self.parents[y] = x
def size(self, x):
return -self.parents[self.find(x)]
def same(self, x, y):
return self.find(x) == self.find(y)
def members(self, x):
root = self.find(x)
return [i for i in range(self.n) if self.find(i) == root]
def roots(self):
return [i for i, x in enumerate(self.parents) if x < 0]
def group_count(self):
return len(self.roots())
def all_group_members(self):
return {r: self.members(r) for r in self.roots()}
def __str__(self):
return '\n'.join('{}: {}'.format(r, self.members(r)) for r in self.roots())
# ダイクストラ
def dijkstra_heap(s, edge, n):
#始点sから各頂点への最短距離
d = [10**20] * n
used = [True] * n #True:未確定
d[s] = 0
used[s] = False
edgelist = []
for a,b in edge[s]:
heapq.heappush(edgelist,a*(10**6)+b)
while len(edgelist):
minedge = heapq.heappop(edgelist)
#まだ使われてない頂点の中から最小の距離のものを探す
if not used[minedge%(10**6)]:
continue
v = minedge%(10**6)
d[v] = minedge//(10**6)
used[v] = False
for e in edge[v]:
if used[e[1]]:
heapq.heappush(edgelist,(e[0]+d[v])*(10**6)+e[1])
return d
# 素因数分解
def factorization(n):
arr = []
temp = n
for i in range(2, int(-(-n**0.5//1))+1):
if temp%i==0:
cnt=0
while temp%i==0:
cnt+=1
temp //= i
arr.append([i, cnt])
if temp!=1:
arr.append([temp, 1])
if arr==[]:
arr.append([n, 1])
return arr
# 組合せnCr
def combinations_count(n, r):
if n < r:
return 0
r = min(r, n - r)
numer = reduce(mul, range(n, n - r, -1), 1)
denom = reduce(mul, range(1, r + 1), 1)
return numer // denom
# 2数の最小公倍数
def lcm(x, y):
return (x * y) // gcd(x, y)
# リストの要素の最小公倍数
def lcm_list(numbers):
return reduce(lcm, numbers, 1)
# リストの要素の最大公約数
def gcd_list(numbers):
return reduce(gcd, numbers)
# 素数判定
def is_prime(n):
if n <= 1:
return False
p = 2
while True:
if p ** 2 > n:
break
if n % p == 0:
return False
p += 1
return True
# limit以下の素数を列挙
def eratosthenes(limit):
A = [i for i in range(2, limit+1)]
P = []
while True:
prime = min(A)
if prime > sqrt(limit):
break
P.append(prime)
i = 0
while i < len(A):
if A[i] % prime == 0:
A.pop(i)
continue
i += 1
for a in A:
P.append(a)
return P
# 同じものを含む順列
def permutation_with_duplicates(L):
if L == []:
return [[]]
else:
ret = []
# set（集合）型で重複を削除、ソート
S = sorted(set(L))
for i in S:
data = L[:]
data.remove(i)
for j in permutation_with_duplicates(data):
ret.append([i] + j)
return ret
def make_divisors(n):
lower_divisors , upper_divisors = [], []
i = 1
while i*i <= n:
if n % i == 0:
lower_divisors.append(i)
if i != n // i:
upper_divisors.append(n//i)
i += 1
return lower_divisors + upper_divisors[::-1]
# ここから書き始める
n, m = map(int, input().split())
x = [0 for i in range(m)]
y = [0 for i in range(m)]
z = [0 for i in range(m)]
for i in range(m):
x[i], y[i], z[i] = map(int, input().split())
a = [[i] for i in range(n)]
for i in range(m):
a[x[i] - 1].append(y[i] - 1)
a[y[i] - 1].append(x[i] - 1)
a.sort(reverse=True, key=lambda x:len(x))
# print("a =", a)
b = [0 for i in range(n)]
ans = 0
c = []
for i in range(n):
index1 = bisect_left(c, a[i][0])
if index1 == len(c) or c[index1] != a[i][0]:
ans += 1
c += a[i][1:]
c.sort()
print(ans)
``` | instruction | 0 | 85,565 | 19 | 171,130 |
No | output | 1 | 85,565 | 19 | 171,131 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N cards placed face down in a row. On each card, an integer 1 or 2 is written.
Let A_i be the integer written on the i-th card.
Your objective is to guess A_1, A_2, ..., A_N correctly.
You know the following facts:
* For each i = 1, 2, ..., M, the value A_{X_i} + A_{Y_i} + Z_i is an even number.
You are a magician and can use the following magic any number of times:
Magic: Choose one card and know the integer A_i written on it. The cost of using this magic is 1.
What is the minimum cost required to determine all of A_1, A_2, ..., A_N?
It is guaranteed that there is no contradiction in given input.
Constraints
* All values in input are integers.
* 2 \leq N \leq 10^5
* 1 \leq M \leq 10^5
* 1 \leq X_i < Y_i \leq N
* 1 \leq Z_i \leq 100
* The pairs (X_i, Y_i) are distinct.
* There is no contradiction in input. (That is, there exist integers A_1, A_2, ..., A_N that satisfy the conditions.)
Input
Input is given from Standard Input in the following format:
N M
X_1 Y_1 Z_1
X_2 Y_2 Z_2
\vdots
X_M Y_M Z_M
Output
Print the minimum total cost required to determine all of A_1, A_2, ..., A_N.
Examples
Input
3 1
1 2 1
Output
2
Input
6 5
1 2 1
2 3 2
1 3 3
4 5 4
5 6 5
Output
2
Input
100000 1
1 100000 100
Output
99999
Submitted Solution:
```
from functools import lru_cache
import sys
sys.setrecursionlimit(200000)
n,m,*l=map(int,open(0).read().split())
graph=[[]*n for _ in range(n)]
unvis=[True]*n
@lru_cache(maxsize=None)
def dfs(x):
for y in graph[x]:
if unvis[y]:
unvis[y]=False
dfs(y)
for i,j in zip(l[::3],l[1::3]):
graph[i-1].append(j-1)
graph[j-1].append(i-1)
ans=0
for x in range(n):
if unvis[x]:
unvis[x]=False
dfs(x)
ans+=1
print(ans)
``` | instruction | 0 | 85,566 | 19 | 171,132 |
No | output | 1 | 85,566 | 19 | 171,133 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N cards placed face down in a row. On each card, an integer 1 or 2 is written.
Let A_i be the integer written on the i-th card.
Your objective is to guess A_1, A_2, ..., A_N correctly.
You know the following facts:
* For each i = 1, 2, ..., M, the value A_{X_i} + A_{Y_i} + Z_i is an even number.
You are a magician and can use the following magic any number of times:
Magic: Choose one card and know the integer A_i written on it. The cost of using this magic is 1.
What is the minimum cost required to determine all of A_1, A_2, ..., A_N?
It is guaranteed that there is no contradiction in given input.
Constraints
* All values in input are integers.
* 2 \leq N \leq 10^5
* 1 \leq M \leq 10^5
* 1 \leq X_i < Y_i \leq N
* 1 \leq Z_i \leq 100
* The pairs (X_i, Y_i) are distinct.
* There is no contradiction in input. (That is, there exist integers A_1, A_2, ..., A_N that satisfy the conditions.)
Input
Input is given from Standard Input in the following format:
N M
X_1 Y_1 Z_1
X_2 Y_2 Z_2
\vdots
X_M Y_M Z_M
Output
Print the minimum total cost required to determine all of A_1, A_2, ..., A_N.
Examples
Input
3 1
1 2 1
Output
2
Input
6 5
1 2 1
2 3 2
1 3 3
4 5 4
5 6 5
Output
2
Input
100000 1
1 100000 100
Output
99999
Submitted Solution:
```
n, m = map(int, input().split())
info = set()
xyz = [list(map(int,input().split())) for _ in range(m)]
x, y, z = xyz[0]
info.add(x)
info.add(y)
cnt = 1
new = True
while new:
new = False
for i in range(1, m):
x, y, z = xyz[i]
if x not in info and y in info:
cnt += 1
info.add(x)
new = True
if y not in info and x in info:
cnt += 1
info.add(y)
new = True
for i in range(1, m):
x, y, z = xyz[i]
if x not in info and y not in info:
cnt += 1
info.add(x)
info.add(y)
new = True
while new:
new = False
for i in range(1, m):
x, y, z = xyz[i]
if x not in info and y in info:
cnt += 1
info.add(x)
new = True
if y not in info and x in info:
cnt += 1
info.add(y)
new = True
print(n - cnt)
``` | instruction | 0 | 85,567 | 19 | 171,134 |
No | output | 1 | 85,567 | 19 | 171,135 |
Provide a correct Python 3 solution for this coding contest problem.
Let’s play a stone removing game.
Initially, n stones are arranged on a circle and numbered 1, ... , n clockwise (Figure 1). You are also given two numbers k and m. From this state, remove stones one by one following the rules explained below, until only one remains. In step 1, remove stone m. In step 2, locate the k-th next stone clockwise from m and remove it. In subsequent steps, start from the slot of the stone removed in the last step, make k hops clockwise on the remaining stones and remove the one you reach. In other words, skip (k - 1) remaining stones clockwise and remove the next one. Repeat this until only one stone is left and answer its number.
For example, the answer for the case n = 8, k = 5, m = 3 is 1, as shown in Figure 1.
<image>
Figure 1: An example game
Initial state: Eight stones are arranged on a circle.
Step 1: Stone 3 is removed since m = 3.
Step 2: You start from the slot that was occupied by stone 3. You skip four stones 4, 5, 6 and 7 (since k = 5), and remove the next one, which is 8.
Step 3: You skip stones 1, 2, 4 and 5, and thus remove 6. Note that you only count stones that are still on the circle and ignore those already removed. Stone 3 is ignored in this case.
Steps 4-7: You continue until only one stone is left. Notice that in later steps when only a few stones remain, the same stone may be skipped multiple times. For example, stones 1 and 4 are skipped twice in step 7.
Final State: Finally, only one stone, 1, is on the circle. This is the final state, so the answer is 1.
Input
The input consists of multiple datasets each of which is formatted as follows.
n k m
The last dataset is followed by a line containing three zeros. Numbers in a line are separated by a single space. A dataset satisfies the following conditions.
2 ≤ n ≤ 10000, 1 ≤ k ≤ 10000, 1 ≤ m ≤ n
The number of datasets is less than 100.
Output
For each dataset, output a line containing the stone number left in the final state. No extra characters such as spaces should appear in the output.
Example
Input
8 5 3
100 9999 98
10000 10000 10000
0 0 0
Output
1
93
2019 | instruction | 0 | 85,664 | 19 | 171,328 |
"Correct Solution:
```
"""
Problem A: 次期町長
https://onlinejudge.u-aizu.ac.jp/problems/1159
2≤ N ≤10000、1≤ K ≤10000、1≤ M ≤ Nß
"""
def solve(n, k, m):
table = [i+1 for i in range(n)]
taget = m-1
while(len(table)>1):
table.pop(taget)
taget -= 1
taget = (taget+k)%len(table)
return table[0]
if __name__ == '__main__':
ans = []
while(True):
n, k, m = map(int, input().split())
if n == 0 and k == 0 and m == 0:
break
ans.append(solve(n, k, m))
print(*ans, sep='\n')
``` | output | 1 | 85,664 | 19 | 171,329 |
Provide a correct Python 3 solution for this coding contest problem.
Let’s play a stone removing game.
Initially, n stones are arranged on a circle and numbered 1, ... , n clockwise (Figure 1). You are also given two numbers k and m. From this state, remove stones one by one following the rules explained below, until only one remains. In step 1, remove stone m. In step 2, locate the k-th next stone clockwise from m and remove it. In subsequent steps, start from the slot of the stone removed in the last step, make k hops clockwise on the remaining stones and remove the one you reach. In other words, skip (k - 1) remaining stones clockwise and remove the next one. Repeat this until only one stone is left and answer its number.
For example, the answer for the case n = 8, k = 5, m = 3 is 1, as shown in Figure 1.
<image>
Figure 1: An example game
Initial state: Eight stones are arranged on a circle.
Step 1: Stone 3 is removed since m = 3.
Step 2: You start from the slot that was occupied by stone 3. You skip four stones 4, 5, 6 and 7 (since k = 5), and remove the next one, which is 8.
Step 3: You skip stones 1, 2, 4 and 5, and thus remove 6. Note that you only count stones that are still on the circle and ignore those already removed. Stone 3 is ignored in this case.
Steps 4-7: You continue until only one stone is left. Notice that in later steps when only a few stones remain, the same stone may be skipped multiple times. For example, stones 1 and 4 are skipped twice in step 7.
Final State: Finally, only one stone, 1, is on the circle. This is the final state, so the answer is 1.
Input
The input consists of multiple datasets each of which is formatted as follows.
n k m
The last dataset is followed by a line containing three zeros. Numbers in a line are separated by a single space. A dataset satisfies the following conditions.
2 ≤ n ≤ 10000, 1 ≤ k ≤ 10000, 1 ≤ m ≤ n
The number of datasets is less than 100.
Output
For each dataset, output a line containing the stone number left in the final state. No extra characters such as spaces should appear in the output.
Example
Input
8 5 3
100 9999 98
10000 10000 10000
0 0 0
Output
1
93
2019 | instruction | 0 | 85,665 | 19 | 171,330 |
"Correct Solution:
```
#!/usr/bin/env python
# -*- coding: utf-8 -*-
"""
Problems 1275
2007年 アジア地区予選 東京大会 問題A And Then There Was One
"""
while True:
n, k, m = map(int, input().split())
if n == 0 and k == 0 and m == 0:
break
list = [int(i) for i in range(1,n+1)]
m -= 1
while True:
if 1 < n:
list.pop(m)
n -= 1
m = (m+k-1) % n
else:
print(list[0])
break
``` | output | 1 | 85,665 | 19 | 171,331 |
Provide a correct Python 3 solution for this coding contest problem.
Let’s play a stone removing game.
Initially, n stones are arranged on a circle and numbered 1, ... , n clockwise (Figure 1). You are also given two numbers k and m. From this state, remove stones one by one following the rules explained below, until only one remains. In step 1, remove stone m. In step 2, locate the k-th next stone clockwise from m and remove it. In subsequent steps, start from the slot of the stone removed in the last step, make k hops clockwise on the remaining stones and remove the one you reach. In other words, skip (k - 1) remaining stones clockwise and remove the next one. Repeat this until only one stone is left and answer its number.
For example, the answer for the case n = 8, k = 5, m = 3 is 1, as shown in Figure 1.
<image>
Figure 1: An example game
Initial state: Eight stones are arranged on a circle.
Step 1: Stone 3 is removed since m = 3.
Step 2: You start from the slot that was occupied by stone 3. You skip four stones 4, 5, 6 and 7 (since k = 5), and remove the next one, which is 8.
Step 3: You skip stones 1, 2, 4 and 5, and thus remove 6. Note that you only count stones that are still on the circle and ignore those already removed. Stone 3 is ignored in this case.
Steps 4-7: You continue until only one stone is left. Notice that in later steps when only a few stones remain, the same stone may be skipped multiple times. For example, stones 1 and 4 are skipped twice in step 7.
Final State: Finally, only one stone, 1, is on the circle. This is the final state, so the answer is 1.
Input
The input consists of multiple datasets each of which is formatted as follows.
n k m
The last dataset is followed by a line containing three zeros. Numbers in a line are separated by a single space. A dataset satisfies the following conditions.
2 ≤ n ≤ 10000, 1 ≤ k ≤ 10000, 1 ≤ m ≤ n
The number of datasets is less than 100.
Output
For each dataset, output a line containing the stone number left in the final state. No extra characters such as spaces should appear in the output.
Example
Input
8 5 3
100 9999 98
10000 10000 10000
0 0 0
Output
1
93
2019 | instruction | 0 | 85,666 | 19 | 171,332 |
"Correct Solution:
```
ans = []
while True:
N, K, M = map(int, input().split())
if not N and not K and not M:
break
remind = [i for i in range(N)]
now = M - 1
while len(remind) > 1:
remind.pop(now)
now = (now + K - 1) % len(remind)
ans.append(remind[0])
[print(i + 1) for i in ans]
``` | output | 1 | 85,666 | 19 | 171,333 |
Provide a correct Python 3 solution for this coding contest problem.
Let’s play a stone removing game.
Initially, n stones are arranged on a circle and numbered 1, ... , n clockwise (Figure 1). You are also given two numbers k and m. From this state, remove stones one by one following the rules explained below, until only one remains. In step 1, remove stone m. In step 2, locate the k-th next stone clockwise from m and remove it. In subsequent steps, start from the slot of the stone removed in the last step, make k hops clockwise on the remaining stones and remove the one you reach. In other words, skip (k - 1) remaining stones clockwise and remove the next one. Repeat this until only one stone is left and answer its number.
For example, the answer for the case n = 8, k = 5, m = 3 is 1, as shown in Figure 1.
<image>
Figure 1: An example game
Initial state: Eight stones are arranged on a circle.
Step 1: Stone 3 is removed since m = 3.
Step 2: You start from the slot that was occupied by stone 3. You skip four stones 4, 5, 6 and 7 (since k = 5), and remove the next one, which is 8.
Step 3: You skip stones 1, 2, 4 and 5, and thus remove 6. Note that you only count stones that are still on the circle and ignore those already removed. Stone 3 is ignored in this case.
Steps 4-7: You continue until only one stone is left. Notice that in later steps when only a few stones remain, the same stone may be skipped multiple times. For example, stones 1 and 4 are skipped twice in step 7.
Final State: Finally, only one stone, 1, is on the circle. This is the final state, so the answer is 1.
Input
The input consists of multiple datasets each of which is formatted as follows.
n k m
The last dataset is followed by a line containing three zeros. Numbers in a line are separated by a single space. A dataset satisfies the following conditions.
2 ≤ n ≤ 10000, 1 ≤ k ≤ 10000, 1 ≤ m ≤ n
The number of datasets is less than 100.
Output
For each dataset, output a line containing the stone number left in the final state. No extra characters such as spaces should appear in the output.
Example
Input
8 5 3
100 9999 98
10000 10000 10000
0 0 0
Output
1
93
2019 | instruction | 0 | 85,667 | 19 | 171,334 |
"Correct Solution:
```
#!/usr/bin/env python
# -*- coding: utf-8 -*-
while True:
n,k,m = map(int,input().split())
if (n,k,m) == (0,0,0):
break
stones = [i + 1 for i in range(n)]
pointer = m - 1
stones_length = len(stones)
while stones_length > 1:
stones.pop(pointer)
stones_length -= 1
pointer = (pointer - 1 + k) % stones_length
print(stones[0])
``` | output | 1 | 85,667 | 19 | 171,335 |
Provide a correct Python 3 solution for this coding contest problem.
Let’s play a stone removing game.
Initially, n stones are arranged on a circle and numbered 1, ... , n clockwise (Figure 1). You are also given two numbers k and m. From this state, remove stones one by one following the rules explained below, until only one remains. In step 1, remove stone m. In step 2, locate the k-th next stone clockwise from m and remove it. In subsequent steps, start from the slot of the stone removed in the last step, make k hops clockwise on the remaining stones and remove the one you reach. In other words, skip (k - 1) remaining stones clockwise and remove the next one. Repeat this until only one stone is left and answer its number.
For example, the answer for the case n = 8, k = 5, m = 3 is 1, as shown in Figure 1.
<image>
Figure 1: An example game
Initial state: Eight stones are arranged on a circle.
Step 1: Stone 3 is removed since m = 3.
Step 2: You start from the slot that was occupied by stone 3. You skip four stones 4, 5, 6 and 7 (since k = 5), and remove the next one, which is 8.
Step 3: You skip stones 1, 2, 4 and 5, and thus remove 6. Note that you only count stones that are still on the circle and ignore those already removed. Stone 3 is ignored in this case.
Steps 4-7: You continue until only one stone is left. Notice that in later steps when only a few stones remain, the same stone may be skipped multiple times. For example, stones 1 and 4 are skipped twice in step 7.
Final State: Finally, only one stone, 1, is on the circle. This is the final state, so the answer is 1.
Input
The input consists of multiple datasets each of which is formatted as follows.
n k m
The last dataset is followed by a line containing three zeros. Numbers in a line are separated by a single space. A dataset satisfies the following conditions.
2 ≤ n ≤ 10000, 1 ≤ k ≤ 10000, 1 ≤ m ≤ n
The number of datasets is less than 100.
Output
For each dataset, output a line containing the stone number left in the final state. No extra characters such as spaces should appear in the output.
Example
Input
8 5 3
100 9999 98
10000 10000 10000
0 0 0
Output
1
93
2019 | instruction | 0 | 85,668 | 19 | 171,336 |
"Correct Solution:
```
while True:
N,K,M = map(int,input().split())
if N == 0: break
li = list(range(1,N+1))
i = M-1
while len(li) > 1:
li.pop(i)
i = (i+K-1) % len(li)
print(li[0])
``` | output | 1 | 85,668 | 19 | 171,337 |
Provide a correct Python 3 solution for this coding contest problem.
Let’s play a stone removing game.
Initially, n stones are arranged on a circle and numbered 1, ... , n clockwise (Figure 1). You are also given two numbers k and m. From this state, remove stones one by one following the rules explained below, until only one remains. In step 1, remove stone m. In step 2, locate the k-th next stone clockwise from m and remove it. In subsequent steps, start from the slot of the stone removed in the last step, make k hops clockwise on the remaining stones and remove the one you reach. In other words, skip (k - 1) remaining stones clockwise and remove the next one. Repeat this until only one stone is left and answer its number.
For example, the answer for the case n = 8, k = 5, m = 3 is 1, as shown in Figure 1.
<image>
Figure 1: An example game
Initial state: Eight stones are arranged on a circle.
Step 1: Stone 3 is removed since m = 3.
Step 2: You start from the slot that was occupied by stone 3. You skip four stones 4, 5, 6 and 7 (since k = 5), and remove the next one, which is 8.
Step 3: You skip stones 1, 2, 4 and 5, and thus remove 6. Note that you only count stones that are still on the circle and ignore those already removed. Stone 3 is ignored in this case.
Steps 4-7: You continue until only one stone is left. Notice that in later steps when only a few stones remain, the same stone may be skipped multiple times. For example, stones 1 and 4 are skipped twice in step 7.
Final State: Finally, only one stone, 1, is on the circle. This is the final state, so the answer is 1.
Input
The input consists of multiple datasets each of which is formatted as follows.
n k m
The last dataset is followed by a line containing three zeros. Numbers in a line are separated by a single space. A dataset satisfies the following conditions.
2 ≤ n ≤ 10000, 1 ≤ k ≤ 10000, 1 ≤ m ≤ n
The number of datasets is less than 100.
Output
For each dataset, output a line containing the stone number left in the final state. No extra characters such as spaces should appear in the output.
Example
Input
8 5 3
100 9999 98
10000 10000 10000
0 0 0
Output
1
93
2019 | instruction | 0 | 85,669 | 19 | 171,338 |
"Correct Solution:
```
#!/usr/bin/env python3
# -*- coding: utf-8 -*-/
import sys
def main():
for line in sys.stdin:
n, k, m = map(int, line.split()) # ??\???
if not(n or k or m): # 0 0 0??§??????
break
stone = list(range(1, n + 1)) # 1 ~ n????????????????????§??¨???
m -= 1 # ????????????????????¨????????????????????¬?????????
while len(stone) > 1: # ??????1?????????????????§
stone.pop(m) # ?????????????????????m???????´??????????
m = (m + k - 1) % len(stone) # ?¬??????????????????????????±????
print(stone[0]) # ?????£??????????????????
if __name__ == "__main__":
main()
``` | output | 1 | 85,669 | 19 | 171,339 |
Provide a correct Python 3 solution for this coding contest problem.
Let’s play a stone removing game.
Initially, n stones are arranged on a circle and numbered 1, ... , n clockwise (Figure 1). You are also given two numbers k and m. From this state, remove stones one by one following the rules explained below, until only one remains. In step 1, remove stone m. In step 2, locate the k-th next stone clockwise from m and remove it. In subsequent steps, start from the slot of the stone removed in the last step, make k hops clockwise on the remaining stones and remove the one you reach. In other words, skip (k - 1) remaining stones clockwise and remove the next one. Repeat this until only one stone is left and answer its number.
For example, the answer for the case n = 8, k = 5, m = 3 is 1, as shown in Figure 1.
<image>
Figure 1: An example game
Initial state: Eight stones are arranged on a circle.
Step 1: Stone 3 is removed since m = 3.
Step 2: You start from the slot that was occupied by stone 3. You skip four stones 4, 5, 6 and 7 (since k = 5), and remove the next one, which is 8.
Step 3: You skip stones 1, 2, 4 and 5, and thus remove 6. Note that you only count stones that are still on the circle and ignore those already removed. Stone 3 is ignored in this case.
Steps 4-7: You continue until only one stone is left. Notice that in later steps when only a few stones remain, the same stone may be skipped multiple times. For example, stones 1 and 4 are skipped twice in step 7.
Final State: Finally, only one stone, 1, is on the circle. This is the final state, so the answer is 1.
Input
The input consists of multiple datasets each of which is formatted as follows.
n k m
The last dataset is followed by a line containing three zeros. Numbers in a line are separated by a single space. A dataset satisfies the following conditions.
2 ≤ n ≤ 10000, 1 ≤ k ≤ 10000, 1 ≤ m ≤ n
The number of datasets is less than 100.
Output
For each dataset, output a line containing the stone number left in the final state. No extra characters such as spaces should appear in the output.
Example
Input
8 5 3
100 9999 98
10000 10000 10000
0 0 0
Output
1
93
2019 | instruction | 0 | 85,670 | 19 | 171,340 |
"Correct Solution:
```
while 1:
n,k,m=map(int,input().split())
if not n and not k and not m:break
l=list(range(1,n+1))
p=l.index(m)
while len(l)>1:
l.pop(p)
p=(p+k-1)%len(l)
print(l[0])
``` | output | 1 | 85,670 | 19 | 171,341 |
Provide a correct Python 3 solution for this coding contest problem.
Let’s play a stone removing game.
Initially, n stones are arranged on a circle and numbered 1, ... , n clockwise (Figure 1). You are also given two numbers k and m. From this state, remove stones one by one following the rules explained below, until only one remains. In step 1, remove stone m. In step 2, locate the k-th next stone clockwise from m and remove it. In subsequent steps, start from the slot of the stone removed in the last step, make k hops clockwise on the remaining stones and remove the one you reach. In other words, skip (k - 1) remaining stones clockwise and remove the next one. Repeat this until only one stone is left and answer its number.
For example, the answer for the case n = 8, k = 5, m = 3 is 1, as shown in Figure 1.
<image>
Figure 1: An example game
Initial state: Eight stones are arranged on a circle.
Step 1: Stone 3 is removed since m = 3.
Step 2: You start from the slot that was occupied by stone 3. You skip four stones 4, 5, 6 and 7 (since k = 5), and remove the next one, which is 8.
Step 3: You skip stones 1, 2, 4 and 5, and thus remove 6. Note that you only count stones that are still on the circle and ignore those already removed. Stone 3 is ignored in this case.
Steps 4-7: You continue until only one stone is left. Notice that in later steps when only a few stones remain, the same stone may be skipped multiple times. For example, stones 1 and 4 are skipped twice in step 7.
Final State: Finally, only one stone, 1, is on the circle. This is the final state, so the answer is 1.
Input
The input consists of multiple datasets each of which is formatted as follows.
n k m
The last dataset is followed by a line containing three zeros. Numbers in a line are separated by a single space. A dataset satisfies the following conditions.
2 ≤ n ≤ 10000, 1 ≤ k ≤ 10000, 1 ≤ m ≤ n
The number of datasets is less than 100.
Output
For each dataset, output a line containing the stone number left in the final state. No extra characters such as spaces should appear in the output.
Example
Input
8 5 3
100 9999 98
10000 10000 10000
0 0 0
Output
1
93
2019 | instruction | 0 | 85,671 | 19 | 171,342 |
"Correct Solution:
```
ans = []
while True:
n, k, m = map(int, input().split())
if n == k == m == 0:
break
stones = [i + 1 for i in range(n)]
m -= 1
while n > 1:
stones.pop(m)
n -= 1
m = ((m + k) - 1) % n
ans.append(stones[0])
for i in ans:
print(i)
``` | output | 1 | 85,671 | 19 | 171,343 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let’s play a stone removing game.
Initially, n stones are arranged on a circle and numbered 1, ... , n clockwise (Figure 1). You are also given two numbers k and m. From this state, remove stones one by one following the rules explained below, until only one remains. In step 1, remove stone m. In step 2, locate the k-th next stone clockwise from m and remove it. In subsequent steps, start from the slot of the stone removed in the last step, make k hops clockwise on the remaining stones and remove the one you reach. In other words, skip (k - 1) remaining stones clockwise and remove the next one. Repeat this until only one stone is left and answer its number.
For example, the answer for the case n = 8, k = 5, m = 3 is 1, as shown in Figure 1.
<image>
Figure 1: An example game
Initial state: Eight stones are arranged on a circle.
Step 1: Stone 3 is removed since m = 3.
Step 2: You start from the slot that was occupied by stone 3. You skip four stones 4, 5, 6 and 7 (since k = 5), and remove the next one, which is 8.
Step 3: You skip stones 1, 2, 4 and 5, and thus remove 6. Note that you only count stones that are still on the circle and ignore those already removed. Stone 3 is ignored in this case.
Steps 4-7: You continue until only one stone is left. Notice that in later steps when only a few stones remain, the same stone may be skipped multiple times. For example, stones 1 and 4 are skipped twice in step 7.
Final State: Finally, only one stone, 1, is on the circle. This is the final state, so the answer is 1.
Input
The input consists of multiple datasets each of which is formatted as follows.
n k m
The last dataset is followed by a line containing three zeros. Numbers in a line are separated by a single space. A dataset satisfies the following conditions.
2 ≤ n ≤ 10000, 1 ≤ k ≤ 10000, 1 ≤ m ≤ n
The number of datasets is less than 100.
Output
For each dataset, output a line containing the stone number left in the final state. No extra characters such as spaces should appear in the output.
Example
Input
8 5 3
100 9999 98
10000 10000 10000
0 0 0
Output
1
93
2019
Submitted Solution:
```
while True :
n, k, m = map(int, input().split())
if n == 0 and k == 0 and m == 0 :
break
stone = []
for i in range(n) :
stone.append(i+1)
i = m-1
while True :
del stone[i]
if len(stone) == 1 :
break
i += k-1
if i >= len(stone) :
i = i % len(stone)
print(stone[0])
``` | instruction | 0 | 85,672 | 19 | 171,344 |
Yes | output | 1 | 85,672 | 19 | 171,345 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let’s play a stone removing game.
Initially, n stones are arranged on a circle and numbered 1, ... , n clockwise (Figure 1). You are also given two numbers k and m. From this state, remove stones one by one following the rules explained below, until only one remains. In step 1, remove stone m. In step 2, locate the k-th next stone clockwise from m and remove it. In subsequent steps, start from the slot of the stone removed in the last step, make k hops clockwise on the remaining stones and remove the one you reach. In other words, skip (k - 1) remaining stones clockwise and remove the next one. Repeat this until only one stone is left and answer its number.
For example, the answer for the case n = 8, k = 5, m = 3 is 1, as shown in Figure 1.
<image>
Figure 1: An example game
Initial state: Eight stones are arranged on a circle.
Step 1: Stone 3 is removed since m = 3.
Step 2: You start from the slot that was occupied by stone 3. You skip four stones 4, 5, 6 and 7 (since k = 5), and remove the next one, which is 8.
Step 3: You skip stones 1, 2, 4 and 5, and thus remove 6. Note that you only count stones that are still on the circle and ignore those already removed. Stone 3 is ignored in this case.
Steps 4-7: You continue until only one stone is left. Notice that in later steps when only a few stones remain, the same stone may be skipped multiple times. For example, stones 1 and 4 are skipped twice in step 7.
Final State: Finally, only one stone, 1, is on the circle. This is the final state, so the answer is 1.
Input
The input consists of multiple datasets each of which is formatted as follows.
n k m
The last dataset is followed by a line containing three zeros. Numbers in a line are separated by a single space. A dataset satisfies the following conditions.
2 ≤ n ≤ 10000, 1 ≤ k ≤ 10000, 1 ≤ m ≤ n
The number of datasets is less than 100.
Output
For each dataset, output a line containing the stone number left in the final state. No extra characters such as spaces should appear in the output.
Example
Input
8 5 3
100 9999 98
10000 10000 10000
0 0 0
Output
1
93
2019
Submitted Solution:
```
import sys
if sys.version_info[0]>=3: raw_input=input
while True:
n,k,m=[int(e) for e in raw_input().split()]
if n==0:break
r=0
for i in range(1,n):r=(r+k)%i
print((r+m)%n+1)
``` | instruction | 0 | 85,673 | 19 | 171,346 |
Yes | output | 1 | 85,673 | 19 | 171,347 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n cows playing poker at a table. For the current betting phase, each player's status is either "ALLIN", "IN", or "FOLDED", and does not change throughout the phase. To increase the suspense, a player whose current status is not "FOLDED" may show his/her hand to the table. However, so as not to affect any betting decisions, he/she may only do so if all other players have a status of either "ALLIN" or "FOLDED". The player's own status may be either "ALLIN" or "IN".
Find the number of cows that can currently show their hands without affecting any betting decisions.
Input
The first line contains a single integer, n (2 ≤ n ≤ 2·105). The second line contains n characters, each either "A", "I", or "F". The i-th character is "A" if the i-th player's status is "ALLIN", "I" if the i-th player's status is "IN", or "F" if the i-th player's status is "FOLDED".
Output
The first line should contain a single integer denoting the number of players that can currently show their hands.
Examples
Input
6
AFFAAA
Output
4
Input
3
AFI
Output
1
Note
In the first sample, cows 1, 4, 5, and 6 can show their hands. In the second sample, only cow 3 can show her hand. | instruction | 0 | 86,022 | 19 | 172,044 |
Tags: brute force, implementation
Correct Solution:
```
n, s = int(input()), input()
a, i = s.count('A'), s.count('I')
f = n - (a + i)
if i == 1 and (f > 0 or a > 0):
print(i)
elif i == 0 and a > 0:
print(a)
else:
print(0)
``` | output | 1 | 86,022 | 19 | 172,045 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n cows playing poker at a table. For the current betting phase, each player's status is either "ALLIN", "IN", or "FOLDED", and does not change throughout the phase. To increase the suspense, a player whose current status is not "FOLDED" may show his/her hand to the table. However, so as not to affect any betting decisions, he/she may only do so if all other players have a status of either "ALLIN" or "FOLDED". The player's own status may be either "ALLIN" or "IN".
Find the number of cows that can currently show their hands without affecting any betting decisions.
Input
The first line contains a single integer, n (2 ≤ n ≤ 2·105). The second line contains n characters, each either "A", "I", or "F". The i-th character is "A" if the i-th player's status is "ALLIN", "I" if the i-th player's status is "IN", or "F" if the i-th player's status is "FOLDED".
Output
The first line should contain a single integer denoting the number of players that can currently show their hands.
Examples
Input
6
AFFAAA
Output
4
Input
3
AFI
Output
1
Note
In the first sample, cows 1, 4, 5, and 6 can show their hands. In the second sample, only cow 3 can show her hand. | instruction | 0 | 86,023 | 19 | 172,046 |
Tags: brute force, implementation
Correct Solution:
```
from collections import Counter
n = int(input())
cnt = Counter(input())
if cnt['I']:
if cnt['I'] == 1:
print(1)
else:
print(0)
else:
print(cnt['A'])
``` | output | 1 | 86,023 | 19 | 172,047 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n cows playing poker at a table. For the current betting phase, each player's status is either "ALLIN", "IN", or "FOLDED", and does not change throughout the phase. To increase the suspense, a player whose current status is not "FOLDED" may show his/her hand to the table. However, so as not to affect any betting decisions, he/she may only do so if all other players have a status of either "ALLIN" or "FOLDED". The player's own status may be either "ALLIN" or "IN".
Find the number of cows that can currently show their hands without affecting any betting decisions.
Input
The first line contains a single integer, n (2 ≤ n ≤ 2·105). The second line contains n characters, each either "A", "I", or "F". The i-th character is "A" if the i-th player's status is "ALLIN", "I" if the i-th player's status is "IN", or "F" if the i-th player's status is "FOLDED".
Output
The first line should contain a single integer denoting the number of players that can currently show their hands.
Examples
Input
6
AFFAAA
Output
4
Input
3
AFI
Output
1
Note
In the first sample, cows 1, 4, 5, and 6 can show their hands. In the second sample, only cow 3 can show her hand. | instruction | 0 | 86,024 | 19 | 172,048 |
Tags: brute force, implementation
Correct Solution:
```
from collections import Counter
def go():
n = int(input())
d = Counter()
for c in input():
d[c] += 1
if d['I'] == 0: return d['A']
elif d['I'] == 1: return 1
else: return 0
print(go())
``` | output | 1 | 86,024 | 19 | 172,049 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n cows playing poker at a table. For the current betting phase, each player's status is either "ALLIN", "IN", or "FOLDED", and does not change throughout the phase. To increase the suspense, a player whose current status is not "FOLDED" may show his/her hand to the table. However, so as not to affect any betting decisions, he/she may only do so if all other players have a status of either "ALLIN" or "FOLDED". The player's own status may be either "ALLIN" or "IN".
Find the number of cows that can currently show their hands without affecting any betting decisions.
Input
The first line contains a single integer, n (2 ≤ n ≤ 2·105). The second line contains n characters, each either "A", "I", or "F". The i-th character is "A" if the i-th player's status is "ALLIN", "I" if the i-th player's status is "IN", or "F" if the i-th player's status is "FOLDED".
Output
The first line should contain a single integer denoting the number of players that can currently show their hands.
Examples
Input
6
AFFAAA
Output
4
Input
3
AFI
Output
1
Note
In the first sample, cows 1, 4, 5, and 6 can show their hands. In the second sample, only cow 3 can show her hand. | instruction | 0 | 86,025 | 19 | 172,050 |
Tags: brute force, implementation
Correct Solution:
```
#!/usr/bin/env python
import os
import re
import sys
from bisect import bisect, bisect_left, insort, insort_left
from collections import Counter, defaultdict, deque
from copy import deepcopy
from decimal import Decimal
from fractions import gcd
from io import BytesIO, IOBase
from itertools import (
accumulate, combinations, combinations_with_replacement, groupby,
permutations, product)
from math import (
acos, asin, atan, ceil, cos, degrees, factorial, hypot, log2, pi, radians,
sin, sqrt, tan)
from operator import itemgetter, mul
from string import ascii_lowercase, ascii_uppercase, digits
def inp():
return(int(input()))
def inlist():
return(list(map(int, input().split())))
def instr():
s = input()
return(list(s[:len(s)]))
def invr():
return(map(int, input().split()))
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
def input(): return sys.stdin.readline().rstrip("\r\n")
# endregion
n = inp()
a = input()
count = defaultdict(lambda: 0)
for i in a:
count[i] += 1
res = 0
for i in a:
if i == "A":
if count["A"] + count["F"] == n:
res += 1
elif i == "I":
if count["A"] + count["F"] == n-1:
res += 1
print(res)
``` | output | 1 | 86,025 | 19 | 172,051 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n cows playing poker at a table. For the current betting phase, each player's status is either "ALLIN", "IN", or "FOLDED", and does not change throughout the phase. To increase the suspense, a player whose current status is not "FOLDED" may show his/her hand to the table. However, so as not to affect any betting decisions, he/she may only do so if all other players have a status of either "ALLIN" or "FOLDED". The player's own status may be either "ALLIN" or "IN".
Find the number of cows that can currently show their hands without affecting any betting decisions.
Input
The first line contains a single integer, n (2 ≤ n ≤ 2·105). The second line contains n characters, each either "A", "I", or "F". The i-th character is "A" if the i-th player's status is "ALLIN", "I" if the i-th player's status is "IN", or "F" if the i-th player's status is "FOLDED".
Output
The first line should contain a single integer denoting the number of players that can currently show their hands.
Examples
Input
6
AFFAAA
Output
4
Input
3
AFI
Output
1
Note
In the first sample, cows 1, 4, 5, and 6 can show their hands. In the second sample, only cow 3 can show her hand. | instruction | 0 | 86,026 | 19 | 172,052 |
Tags: brute force, implementation
Correct Solution:
```
input()
s = input()
x = s.count('I')
print(0 if x>1 else s.count('A') if x<1 else 1)
``` | output | 1 | 86,026 | 19 | 172,053 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n cows playing poker at a table. For the current betting phase, each player's status is either "ALLIN", "IN", or "FOLDED", and does not change throughout the phase. To increase the suspense, a player whose current status is not "FOLDED" may show his/her hand to the table. However, so as not to affect any betting decisions, he/she may only do so if all other players have a status of either "ALLIN" or "FOLDED". The player's own status may be either "ALLIN" or "IN".
Find the number of cows that can currently show their hands without affecting any betting decisions.
Input
The first line contains a single integer, n (2 ≤ n ≤ 2·105). The second line contains n characters, each either "A", "I", or "F". The i-th character is "A" if the i-th player's status is "ALLIN", "I" if the i-th player's status is "IN", or "F" if the i-th player's status is "FOLDED".
Output
The first line should contain a single integer denoting the number of players that can currently show their hands.
Examples
Input
6
AFFAAA
Output
4
Input
3
AFI
Output
1
Note
In the first sample, cows 1, 4, 5, and 6 can show their hands. In the second sample, only cow 3 can show her hand. | instruction | 0 | 86,027 | 19 | 172,054 |
Tags: brute force, implementation
Correct Solution:
```
n = int(input())
s = input()
c = 0
for i in s :
if i == "I" :
c += 1
if c > 1 :
ans = 0
break
if c == 0 :
ans = s.count("A")
elif c == 1 :
ans = 1
print (ans)
``` | output | 1 | 86,027 | 19 | 172,055 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n cows playing poker at a table. For the current betting phase, each player's status is either "ALLIN", "IN", or "FOLDED", and does not change throughout the phase. To increase the suspense, a player whose current status is not "FOLDED" may show his/her hand to the table. However, so as not to affect any betting decisions, he/she may only do so if all other players have a status of either "ALLIN" or "FOLDED". The player's own status may be either "ALLIN" or "IN".
Find the number of cows that can currently show their hands without affecting any betting decisions.
Input
The first line contains a single integer, n (2 ≤ n ≤ 2·105). The second line contains n characters, each either "A", "I", or "F". The i-th character is "A" if the i-th player's status is "ALLIN", "I" if the i-th player's status is "IN", or "F" if the i-th player's status is "FOLDED".
Output
The first line should contain a single integer denoting the number of players that can currently show their hands.
Examples
Input
6
AFFAAA
Output
4
Input
3
AFI
Output
1
Note
In the first sample, cows 1, 4, 5, and 6 can show their hands. In the second sample, only cow 3 can show her hand. | instruction | 0 | 86,028 | 19 | 172,056 |
Tags: brute force, implementation
Correct Solution:
```
n = int(input())
arr = input()
if arr.count('I') > 1:
print(0)
elif arr.count('I') == 1:
print(1)
else:
print(arr.count('A'))
``` | output | 1 | 86,028 | 19 | 172,057 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n cows playing poker at a table. For the current betting phase, each player's status is either "ALLIN", "IN", or "FOLDED", and does not change throughout the phase. To increase the suspense, a player whose current status is not "FOLDED" may show his/her hand to the table. However, so as not to affect any betting decisions, he/she may only do so if all other players have a status of either "ALLIN" or "FOLDED". The player's own status may be either "ALLIN" or "IN".
Find the number of cows that can currently show their hands without affecting any betting decisions.
Input
The first line contains a single integer, n (2 ≤ n ≤ 2·105). The second line contains n characters, each either "A", "I", or "F". The i-th character is "A" if the i-th player's status is "ALLIN", "I" if the i-th player's status is "IN", or "F" if the i-th player's status is "FOLDED".
Output
The first line should contain a single integer denoting the number of players that can currently show their hands.
Examples
Input
6
AFFAAA
Output
4
Input
3
AFI
Output
1
Note
In the first sample, cows 1, 4, 5, and 6 can show their hands. In the second sample, only cow 3 can show her hand. | instruction | 0 | 86,029 | 19 | 172,058 |
Tags: brute force, implementation
Correct Solution:
```
n=int(input())
s=input()
koli=0
kola=0
for i in range(n):
if s[i]=='I':
koli+=1
if s[i]=='A':
kola+=1
if koli>1:
print(0)
exit()
if koli==1:
print(1)
exit()
print(kola)
``` | output | 1 | 86,029 | 19 | 172,059 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n cows playing poker at a table. For the current betting phase, each player's status is either "ALLIN", "IN", or "FOLDED", and does not change throughout the phase. To increase the suspense, a player whose current status is not "FOLDED" may show his/her hand to the table. However, so as not to affect any betting decisions, he/she may only do so if all other players have a status of either "ALLIN" or "FOLDED". The player's own status may be either "ALLIN" or "IN".
Find the number of cows that can currently show their hands without affecting any betting decisions.
Input
The first line contains a single integer, n (2 ≤ n ≤ 2·105). The second line contains n characters, each either "A", "I", or "F". The i-th character is "A" if the i-th player's status is "ALLIN", "I" if the i-th player's status is "IN", or "F" if the i-th player's status is "FOLDED".
Output
The first line should contain a single integer denoting the number of players that can currently show their hands.
Examples
Input
6
AFFAAA
Output
4
Input
3
AFI
Output
1
Note
In the first sample, cows 1, 4, 5, and 6 can show their hands. In the second sample, only cow 3 can show her hand.
Submitted Solution:
```
n = int(input())
c = {'A': 0, 'F': 0, 'I': 0}
for ch in input():
c[ch] += 1
if c['I'] == 0:
print(c['A'])
elif c['I'] == 1:
print(1)
else:
print(0)
``` | instruction | 0 | 86,030 | 19 | 172,060 |
Yes | output | 1 | 86,030 | 19 | 172,061 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n cows playing poker at a table. For the current betting phase, each player's status is either "ALLIN", "IN", or "FOLDED", and does not change throughout the phase. To increase the suspense, a player whose current status is not "FOLDED" may show his/her hand to the table. However, so as not to affect any betting decisions, he/she may only do so if all other players have a status of either "ALLIN" or "FOLDED". The player's own status may be either "ALLIN" or "IN".
Find the number of cows that can currently show their hands without affecting any betting decisions.
Input
The first line contains a single integer, n (2 ≤ n ≤ 2·105). The second line contains n characters, each either "A", "I", or "F". The i-th character is "A" if the i-th player's status is "ALLIN", "I" if the i-th player's status is "IN", or "F" if the i-th player's status is "FOLDED".
Output
The first line should contain a single integer denoting the number of players that can currently show their hands.
Examples
Input
6
AFFAAA
Output
4
Input
3
AFI
Output
1
Note
In the first sample, cows 1, 4, 5, and 6 can show their hands. In the second sample, only cow 3 can show her hand.
Submitted Solution:
```
# https://codeforces.com/contest/284/problem/B
import sys
import math
def main():
# sys.stdin = open('E:\\Sublime\\in.txt', 'r')
# sys.stdout = open('E:\\Sublime\\out.txt', 'w')
# sys.stderr = open('E:\\Sublime\\err.txt', 'w')
n = int(sys.stdin.readline().strip())
s = sys.stdin.readline().strip()
print([s.count('A'), 1, 0][min(s.count('I'), 2)])
if __name__ == '__main__':
main()
# hajj
# ＿＿
# ／＞ フ
# | _ _ l
# ／` ミ＿xノ
# / |
# / ヽ ﾉ
# │ | | |
# ／￣| | | |
# | (￣ヽ＿_ヽ_)__)
# ＼二つ
``` | instruction | 0 | 86,031 | 19 | 172,062 |
Yes | output | 1 | 86,031 | 19 | 172,063 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n cows playing poker at a table. For the current betting phase, each player's status is either "ALLIN", "IN", or "FOLDED", and does not change throughout the phase. To increase the suspense, a player whose current status is not "FOLDED" may show his/her hand to the table. However, so as not to affect any betting decisions, he/she may only do so if all other players have a status of either "ALLIN" or "FOLDED". The player's own status may be either "ALLIN" or "IN".
Find the number of cows that can currently show their hands without affecting any betting decisions.
Input
The first line contains a single integer, n (2 ≤ n ≤ 2·105). The second line contains n characters, each either "A", "I", or "F". The i-th character is "A" if the i-th player's status is "ALLIN", "I" if the i-th player's status is "IN", or "F" if the i-th player's status is "FOLDED".
Output
The first line should contain a single integer denoting the number of players that can currently show their hands.
Examples
Input
6
AFFAAA
Output
4
Input
3
AFI
Output
1
Note
In the first sample, cows 1, 4, 5, and 6 can show their hands. In the second sample, only cow 3 can show her hand.
Submitted Solution:
```
import sys
import math
n = int(sys.stdin.readline())
an = sys.stdin.readline()
d = [0] * 3
for i in range(n):
if(an[i] == 'A'):
d[0] += 1
elif(an[i] == 'I'):
d[2] += 1
if(d[2] == 1):
print(d[2])
elif(d[0] != 0 and d[2] == 0):
print(d[0])
else:
print(0)
``` | instruction | 0 | 86,032 | 19 | 172,064 |
Yes | output | 1 | 86,032 | 19 | 172,065 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n cows playing poker at a table. For the current betting phase, each player's status is either "ALLIN", "IN", or "FOLDED", and does not change throughout the phase. To increase the suspense, a player whose current status is not "FOLDED" may show his/her hand to the table. However, so as not to affect any betting decisions, he/she may only do so if all other players have a status of either "ALLIN" or "FOLDED". The player's own status may be either "ALLIN" or "IN".
Find the number of cows that can currently show their hands without affecting any betting decisions.
Input
The first line contains a single integer, n (2 ≤ n ≤ 2·105). The second line contains n characters, each either "A", "I", or "F". The i-th character is "A" if the i-th player's status is "ALLIN", "I" if the i-th player's status is "IN", or "F" if the i-th player's status is "FOLDED".
Output
The first line should contain a single integer denoting the number of players that can currently show their hands.
Examples
Input
6
AFFAAA
Output
4
Input
3
AFI
Output
1
Note
In the first sample, cows 1, 4, 5, and 6 can show their hands. In the second sample, only cow 3 can show her hand.
Submitted Solution:
```
from collections import Counter
n = int(input())
s = input()
c = Counter(s)
res = 0
for i in s:
c[i] -= 1
if i in 'AI':
if c['I'] == 0:
res += 1
c[i] += 1
print(res)
``` | instruction | 0 | 86,033 | 19 | 172,066 |
Yes | output | 1 | 86,033 | 19 | 172,067 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n cows playing poker at a table. For the current betting phase, each player's status is either "ALLIN", "IN", or "FOLDED", and does not change throughout the phase. To increase the suspense, a player whose current status is not "FOLDED" may show his/her hand to the table. However, so as not to affect any betting decisions, he/she may only do so if all other players have a status of either "ALLIN" or "FOLDED". The player's own status may be either "ALLIN" or "IN".
Find the number of cows that can currently show their hands without affecting any betting decisions.
Input
The first line contains a single integer, n (2 ≤ n ≤ 2·105). The second line contains n characters, each either "A", "I", or "F". The i-th character is "A" if the i-th player's status is "ALLIN", "I" if the i-th player's status is "IN", or "F" if the i-th player's status is "FOLDED".
Output
The first line should contain a single integer denoting the number of players that can currently show their hands.
Examples
Input
6
AFFAAA
Output
4
Input
3
AFI
Output
1
Note
In the first sample, cows 1, 4, 5, and 6 can show their hands. In the second sample, only cow 3 can show her hand.
Submitted Solution:
```
import math
z = int(input())
m = input()
i = 0
n = 0
if 'I' in m: i = 1
for i in range(z):
if i == 1 and m[i] == 'I': n = n + 1
elif i != 1 and m[i] == 'A': n = n + 1
print(n)
``` | instruction | 0 | 86,034 | 19 | 172,068 |
No | output | 1 | 86,034 | 19 | 172,069 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n cows playing poker at a table. For the current betting phase, each player's status is either "ALLIN", "IN", or "FOLDED", and does not change throughout the phase. To increase the suspense, a player whose current status is not "FOLDED" may show his/her hand to the table. However, so as not to affect any betting decisions, he/she may only do so if all other players have a status of either "ALLIN" or "FOLDED". The player's own status may be either "ALLIN" or "IN".
Find the number of cows that can currently show their hands without affecting any betting decisions.
Input
The first line contains a single integer, n (2 ≤ n ≤ 2·105). The second line contains n characters, each either "A", "I", or "F". The i-th character is "A" if the i-th player's status is "ALLIN", "I" if the i-th player's status is "IN", or "F" if the i-th player's status is "FOLDED".
Output
The first line should contain a single integer denoting the number of players that can currently show their hands.
Examples
Input
6
AFFAAA
Output
4
Input
3
AFI
Output
1
Note
In the first sample, cows 1, 4, 5, and 6 can show their hands. In the second sample, only cow 3 can show her hand.
Submitted Solution:
```
n = int(input())
s=input()
"""
c=0
for i in range(n):
if i==0 and (s[i]=="A" or s[i]=="I") and "I" not in s[i+1:]:
c=c+1
elif i==n-1 and (s[i]=="A" or s[i]=="I") and "I" not in s[:n-1]:
c=c+1
elif (s[i]=="A" or s[i]=="I") and ("I" not in s[:i] and "I" not in s[i+1:]):
c=c+1
"""
print(s.count("A"))
``` | instruction | 0 | 86,035 | 19 | 172,070 |
No | output | 1 | 86,035 | 19 | 172,071 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n cows playing poker at a table. For the current betting phase, each player's status is either "ALLIN", "IN", or "FOLDED", and does not change throughout the phase. To increase the suspense, a player whose current status is not "FOLDED" may show his/her hand to the table. However, so as not to affect any betting decisions, he/she may only do so if all other players have a status of either "ALLIN" or "FOLDED". The player's own status may be either "ALLIN" or "IN".
Find the number of cows that can currently show their hands without affecting any betting decisions.
Input
The first line contains a single integer, n (2 ≤ n ≤ 2·105). The second line contains n characters, each either "A", "I", or "F". The i-th character is "A" if the i-th player's status is "ALLIN", "I" if the i-th player's status is "IN", or "F" if the i-th player's status is "FOLDED".
Output
The first line should contain a single integer denoting the number of players that can currently show their hands.
Examples
Input
6
AFFAAA
Output
4
Input
3
AFI
Output
1
Note
In the first sample, cows 1, 4, 5, and 6 can show their hands. In the second sample, only cow 3 can show her hand.
Submitted Solution:
```
n = int(input())
s = input()
dic = {}
for x in s:
if x in dic:
dic[x]+=1
else:
dic[x] = 1
if 'I' not in dic:
dic['I']=0
if 'A' not in dic:
dic['A'] = 0
if 'F' not in dic:
dic['F'] = 0
if dic['I']==0:
print(dic['A'])
elif dic['A']>0 or dic['F']>0:
print(dic['I'])
else:
print(0)
# def f(n,k,ls):
# print(ls,type(n),k)
# if k==0 and (n=="" or n==None):
# return ls
# elif k==0:
# return -1;
# for x in range(1,len(n)+1):
# s =ls.copy()
# s.append(n[0:x])
# res = f(n[x:],k-1,s)
# if res!=-1:
# print("res="+str(res))
# f("123456",3,[])
``` | instruction | 0 | 86,036 | 19 | 172,072 |
No | output | 1 | 86,036 | 19 | 172,073 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n cows playing poker at a table. For the current betting phase, each player's status is either "ALLIN", "IN", or "FOLDED", and does not change throughout the phase. To increase the suspense, a player whose current status is not "FOLDED" may show his/her hand to the table. However, so as not to affect any betting decisions, he/she may only do so if all other players have a status of either "ALLIN" or "FOLDED". The player's own status may be either "ALLIN" or "IN".
Find the number of cows that can currently show their hands without affecting any betting decisions.
Input
The first line contains a single integer, n (2 ≤ n ≤ 2·105). The second line contains n characters, each either "A", "I", or "F". The i-th character is "A" if the i-th player's status is "ALLIN", "I" if the i-th player's status is "IN", or "F" if the i-th player's status is "FOLDED".
Output
The first line should contain a single integer denoting the number of players that can currently show their hands.
Examples
Input
6
AFFAAA
Output
4
Input
3
AFI
Output
1
Note
In the first sample, cows 1, 4, 5, and 6 can show their hands. In the second sample, only cow 3 can show her hand.
Submitted Solution:
```
n=int(input())
s=input()
arr=[0]*3
c=0
for i in range(0,n):
if s[i]=='A':
arr[0]=arr[0]+1
if s[i]=='F':
arr[0]=arr[1]+1
if s[i]=='I':
arr[0]=arr[2]+1
for i in range(0,n):
if s[i]=='A':
if arr[2]==0:
c=c+1
if s[i]=='I':
if arr[2]-1==0:
c=c+1
print(c)
``` | instruction | 0 | 86,037 | 19 | 172,074 |
No | output | 1 | 86,037 | 19 | 172,075 |
Provide a correct Python 3 solution for this coding contest problem.
Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).
The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.
Note
解説
Input
In the first line, the number of cards n (n ≤ 52) is given.
In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.
Output
Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line. Arrange the missing cards in the following priorities:
* Print cards of spades, hearts, clubs and diamonds in this order.
* If the suits are equal, print cards with lower ranks first.
Example
Input
47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13
Output
S 1
H 3
H 7
C 12
D 8 | instruction | 0 | 86,561 | 19 | 173,122 |
"Correct Solution:
```
all = [suit + ' ' + str(rank) for suit in 'SHCD' for rank in range(1, 14)]
for _ in range(int(input())):
all.remove(input())
for card in all:
print(card)
``` | output | 1 | 86,561 | 19 | 173,123 |
Provide a correct Python 3 solution for this coding contest problem.
Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).
The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.
Note
解説
Input
In the first line, the number of cards n (n ≤ 52) is given.
In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.
Output
Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line. Arrange the missing cards in the following priorities:
* Print cards of spades, hearts, clubs and diamonds in this order.
* If the suits are equal, print cards with lower ranks first.
Example
Input
47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13
Output
S 1
H 3
H 7
C 12
D 8 | instruction | 0 | 86,562 | 19 | 173,124 |
"Correct Solution:
```
cards = []
for suit in ['S', 'H', 'C', 'D']:
for i in range(13):
cards.append(' '.join([suit, str(i + 1)]))
N = int(input())
for _ in range(N):
cards.remove(input())
for card in cards:
print(card)
``` | output | 1 | 86,562 | 19 | 173,125 |
Provide a correct Python 3 solution for this coding contest problem.
Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).
The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.
Note
解説
Input
In the first line, the number of cards n (n ≤ 52) is given.
In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.
Output
Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line. Arrange the missing cards in the following priorities:
* Print cards of spades, hearts, clubs and diamonds in this order.
* If the suits are equal, print cards with lower ranks first.
Example
Input
47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13
Output
S 1
H 3
H 7
C 12
D 8 | instruction | 0 | 86,563 | 19 | 173,126 |
"Correct Solution:
```
n = int(input())
a = [input() for i in range(n)]
for x in 'SHCD':
for y in range(1, 14):
z = '{} {}'.format(x, y)
if z not in a:
print(z)
``` | output | 1 | 86,563 | 19 | 173,127 |
Provide a correct Python 3 solution for this coding contest problem.
Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).
The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.
Note
解説
Input
In the first line, the number of cards n (n ≤ 52) is given.
In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.
Output
Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line. Arrange the missing cards in the following priorities:
* Print cards of spades, hearts, clubs and diamonds in this order.
* If the suits are equal, print cards with lower ranks first.
Example
Input
47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13
Output
S 1
H 3
H 7
C 12
D 8 | instruction | 0 | 86,564 | 19 | 173,128 |
"Correct Solution:
```
num = int(input())
cards = [ (design, rank) for design in ['S','H','C','D'] for rank in range(1,14) ]
for i in range(num):
design, rank = input().split()
cards.remove((design, int(rank)))
for (design, rank) in cards:
print(design, rank)
``` | output | 1 | 86,564 | 19 | 173,129 |
Provide a correct Python 3 solution for this coding contest problem.
Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).
The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.
Note
解説
Input
In the first line, the number of cards n (n ≤ 52) is given.
In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.
Output
Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line. Arrange the missing cards in the following priorities:
* Print cards of spades, hearts, clubs and diamonds in this order.
* If the suits are equal, print cards with lower ranks first.
Example
Input
47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13
Output
S 1
H 3
H 7
C 12
D 8 | instruction | 0 | 86,565 | 19 | 173,130 |
"Correct Solution:
```
c=[s+' '+str(i)for s in'SHCD'for i in range(1,14)]
for _ in[0]*int(input()):c.remove(input())
if c:print(*c,sep='\n')
``` | output | 1 | 86,565 | 19 | 173,131 |
Provide a correct Python 3 solution for this coding contest problem.
Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).
The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.
Note
解説
Input
In the first line, the number of cards n (n ≤ 52) is given.
In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.
Output
Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line. Arrange the missing cards in the following priorities:
* Print cards of spades, hearts, clubs and diamonds in this order.
* If the suits are equal, print cards with lower ranks first.
Example
Input
47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13
Output
S 1
H 3
H 7
C 12
D 8 | instruction | 0 | 86,566 | 19 | 173,132 |
"Correct Solution:
```
P = []
for X in "SHCD":
for i in range(1, 13+1):
P.append("{} {}".format(X, i))
n = int(input())
for _ in range(n):
c = input()
P.remove(c)
for c in P:
print(c)
``` | output | 1 | 86,566 | 19 | 173,133 |
Provide a correct Python 3 solution for this coding contest problem.
Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).
The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.
Note
解説
Input
In the first line, the number of cards n (n ≤ 52) is given.
In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.
Output
Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line. Arrange the missing cards in the following priorities:
* Print cards of spades, hearts, clubs and diamonds in this order.
* If the suits are equal, print cards with lower ranks first.
Example
Input
47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13
Output
S 1
H 3
H 7
C 12
D 8 | instruction | 0 | 86,567 | 19 | 173,134 |
"Correct Solution:
```
cards = []
for i in ['S','H','C','D']:
for j in range(1, 14):
cards.append(i + " " + str(j))
N = int(input())
for i in range(N):
cards.remove(input())
for i in range(len(cards)):
print (cards[i])
``` | output | 1 | 86,567 | 19 | 173,135 |
Provide a correct Python 3 solution for this coding contest problem.
Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).
The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.
Note
解説
Input
In the first line, the number of cards n (n ≤ 52) is given.
In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.
Output
Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line. Arrange the missing cards in the following priorities:
* Print cards of spades, hearts, clubs and diamonds in this order.
* If the suits are equal, print cards with lower ranks first.
Example
Input
47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13
Output
S 1
H 3
H 7
C 12
D 8 | instruction | 0 | 86,568 | 19 | 173,136 |
"Correct Solution:
```
N = int(input())
cards = []
for i in range(N):
s,r = input().split()
cards.append((s,int(r)))
for s,r in [(s,r) for s in 'SHCD' for r in range(1,14) if (s,r) not in cards]:
print(s, r)
``` | output | 1 | 86,568 | 19 | 173,137 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).
The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.
Note
解説
Input
In the first line, the number of cards n (n ≤ 52) is given.
In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.
Output
Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line. Arrange the missing cards in the following priorities:
* Print cards of spades, hearts, clubs and diamonds in this order.
* If the suits are equal, print cards with lower ranks first.
Example
Input
47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13
Output
S 1
H 3
H 7
C 12
D 8
Submitted Solution:
```
cards = [
"{0} {1}".format(s, r)
for s in ('S', 'H', 'C', 'D')
for r in range(1, 13 + 1)
]
count = int(input())
for n in range(count):
card = input()
cards.remove(card)
for n in cards:
print(n)
``` | instruction | 0 | 86,569 | 19 | 173,138 |
Yes | output | 1 | 86,569 | 19 | 173,139 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).
The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.
Note
解説
Input
In the first line, the number of cards n (n ≤ 52) is given.
In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.
Output
Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line. Arrange the missing cards in the following priorities:
* Print cards of spades, hearts, clubs and diamonds in this order.
* If the suits are equal, print cards with lower ranks first.
Example
Input
47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13
Output
S 1
H 3
H 7
C 12
D 8
Submitted Solution:
```
cards = [(e, str(n)) for e in "SHCD" for n in range(1, 13+1)]
n = int(input())
for _ in range(n):
card = tuple(input().split())
cards.remove(card)
for card in cards:
print(*card)
``` | instruction | 0 | 86,570 | 19 | 173,140 |
Yes | output | 1 | 86,570 | 19 | 173,141 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).
The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.
Note
解説
Input
In the first line, the number of cards n (n ≤ 52) is given.
In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.
Output
Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line. Arrange the missing cards in the following priorities:
* Print cards of spades, hearts, clubs and diamonds in this order.
* If the suits are equal, print cards with lower ranks first.
Example
Input
47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13
Output
S 1
H 3
H 7
C 12
D 8
Submitted Solution:
```
a = ['S','H','C','D']
b =[]
for i in range(4):
for j in range(1,14):
b.append(str(a[i])+' '+str(j))
n = int(input())
for i in range(n):
c = input()
b.remove(c)
for i in range(len(b)):
print(b[i])
``` | instruction | 0 | 86,571 | 19 | 173,142 |
Yes | output | 1 | 86,571 | 19 | 173,143 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).
The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.
Note
解説
Input
In the first line, the number of cards n (n ≤ 52) is given.
In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.
Output
Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line. Arrange the missing cards in the following priorities:
* Print cards of spades, hearts, clubs and diamonds in this order.
* If the suits are equal, print cards with lower ranks first.
Example
Input
47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13
Output
S 1
H 3
H 7
C 12
D 8
Submitted Solution:
```
n = int(input())
s = "SHCD"
cards = [[0] * 13 for i in range(4)]
for i in range(n):
a, b = input().split()
cards[s.find(a)][int(b)-1] = 1
for i in range(4):
for j in range(13):
if cards[i][j] == 0:
print(s[i], j+1)
``` | instruction | 0 | 86,572 | 19 | 173,144 |
Yes | output | 1 | 86,572 | 19 | 173,145 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).
The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.
Note
解説
Input
In the first line, the number of cards n (n ≤ 52) is given.
In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.
Output
Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line. Arrange the missing cards in the following priorities:
* Print cards of spades, hearts, clubs and diamonds in this order.
* If the suits are equal, print cards with lower ranks first.
Example
Input
47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13
Output
S 1
H 3
H 7
C 12
D 8
Submitted Solution:
```
ans = []
for i in range(4):
for j in range(13):
ans.append("SHCD"[i] + " " + str(j + 1))
n = int(input())
for i in range(n):
a = input()
ans.remove(a)
print("\n".join(ans))
``` | instruction | 0 | 86,573 | 19 | 173,146 |
No | output | 1 | 86,573 | 19 | 173,147 |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.