message stringlengths 2 22.8k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 16 109k | cluster float64 1 1 | __index_level_0__ int64 32 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Barney lives in NYC. NYC has infinite number of intersections numbered with positive integers starting from 1. There exists a bidirectional road between intersections i and 2i and another road between i and 2i + 1 for every positive integer i. You can clearly see that there exists a unique shortest path between any two intersections.
<image>
Initially anyone can pass any road for free. But since SlapsGiving is ahead of us, there will q consecutive events happen soon. There are two types of events:
1. Government makes a new rule. A rule can be denoted by integers v, u and w. As the result of this action, the passing fee of all roads on the shortest path from u to v increases by w dollars.
2. Barney starts moving from some intersection v and goes to intersection u where there's a girl he wants to cuddle (using his fake name Lorenzo Von Matterhorn). He always uses the shortest path (visiting minimum number of intersections or roads) between two intersections.
Government needs your calculations. For each time Barney goes to cuddle a girl, you need to tell the government how much money he should pay (sum of passing fee of all roads he passes).
Input
The first line of input contains a single integer q (1 ≤ q ≤ 1 000).
The next q lines contain the information about the events in chronological order. Each event is described in form 1 v u w if it's an event when government makes a new rule about increasing the passing fee of all roads on the shortest path from u to v by w dollars, or in form 2 v u if it's an event when Barnie goes to cuddle from the intersection v to the intersection u.
1 ≤ v, u ≤ 1018, v ≠ u, 1 ≤ w ≤ 109 states for every description line.
Output
For each event of second type print the sum of passing fee of all roads Barney passes in this event, in one line. Print the answers in chronological order of corresponding events.
Example
Input
7
1 3 4 30
1 4 1 2
1 3 6 8
2 4 3
1 6 1 40
2 3 7
2 2 4
Output
94
0
32
Note
In the example testcase:
Here are the intersections used:
<image>
1. Intersections on the path are 3, 1, 2 and 4.
2. Intersections on the path are 4, 2 and 1.
3. Intersections on the path are only 3 and 6.
4. Intersections on the path are 4, 2, 1 and 3. Passing fee of roads on the path are 32, 32 and 30 in order. So answer equals to 32 + 32 + 30 = 94.
5. Intersections on the path are 6, 3 and 1.
6. Intersections on the path are 3 and 7. Passing fee of the road between them is 0.
7. Intersections on the path are 2 and 4. Passing fee of the road between them is 32 (increased by 30 in the first event and by 2 in the second).
Submitted Solution:
```
from functools import lru_cache
from collections import defaultdict
from itertools import tee
price = defaultdict(dict)
def add(start, end, w):
global price
for x, y in get_way(start, end):
if x in price:
price[x][y] += w
else:
price[x] = defaultdict(lambda: 0)
price[x][y] = w
if y in price:
price[y][x] += w
else:
price[y] = defaultdict(lambda: 0)
price[y][x] = w
def get_price(start, end):
global price
result = 0
for x, y in get_way(start, end):
if x not in price:
price[x] = defaultdict(lambda: 0)
result += price[x][y]
return result
@lru_cache(maxsize=1000)
def get_way(start, end):
def _get_raw_way():
nonlocal start, end
l_way, r_way = [start], [end]
while True:
l = l_way[-1] // 2
if l: l_way.append(l)
r = r_way[-1] // 2
if r: r_way.append(r)
if r_way[-1] == start:
return r_way
if set(l_way) & set(r_way):
del r_way[-1]
r_way.reverse()
return l_way + r_way
a, b = tee(_get_raw_way())
next(b, None)
return list(zip(a, b))
q = int(input())
for _ in range(q):
data = list(map(int, input().split(' ')))
if data[0] == 1:
add(data[1], data[2], data[3])
else:
print(get_price(data[1], data[2]))
``` | instruction | 0 | 10,415 | 1 | 20,830 |
No | output | 1 | 10,415 | 1 | 20,831 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Barney lives in NYC. NYC has infinite number of intersections numbered with positive integers starting from 1. There exists a bidirectional road between intersections i and 2i and another road between i and 2i + 1 for every positive integer i. You can clearly see that there exists a unique shortest path between any two intersections.
<image>
Initially anyone can pass any road for free. But since SlapsGiving is ahead of us, there will q consecutive events happen soon. There are two types of events:
1. Government makes a new rule. A rule can be denoted by integers v, u and w. As the result of this action, the passing fee of all roads on the shortest path from u to v increases by w dollars.
2. Barney starts moving from some intersection v and goes to intersection u where there's a girl he wants to cuddle (using his fake name Lorenzo Von Matterhorn). He always uses the shortest path (visiting minimum number of intersections or roads) between two intersections.
Government needs your calculations. For each time Barney goes to cuddle a girl, you need to tell the government how much money he should pay (sum of passing fee of all roads he passes).
Input
The first line of input contains a single integer q (1 ≤ q ≤ 1 000).
The next q lines contain the information about the events in chronological order. Each event is described in form 1 v u w if it's an event when government makes a new rule about increasing the passing fee of all roads on the shortest path from u to v by w dollars, or in form 2 v u if it's an event when Barnie goes to cuddle from the intersection v to the intersection u.
1 ≤ v, u ≤ 1018, v ≠ u, 1 ≤ w ≤ 109 states for every description line.
Output
For each event of second type print the sum of passing fee of all roads Barney passes in this event, in one line. Print the answers in chronological order of corresponding events.
Example
Input
7
1 3 4 30
1 4 1 2
1 3 6 8
2 4 3
1 6 1 40
2 3 7
2 2 4
Output
94
0
32
Note
In the example testcase:
Here are the intersections used:
<image>
1. Intersections on the path are 3, 1, 2 and 4.
2. Intersections on the path are 4, 2 and 1.
3. Intersections on the path are only 3 and 6.
4. Intersections on the path are 4, 2, 1 and 3. Passing fee of roads on the path are 32, 32 and 30 in order. So answer equals to 32 + 32 + 30 = 94.
5. Intersections on the path are 6, 3 and 1.
6. Intersections on the path are 3 and 7. Passing fee of the road between them is 0.
7. Intersections on the path are 2 and 4. Passing fee of the road between them is 32 (increased by 30 in the first event and by 2 in the second).
Submitted Solution:
```
from functools import lru_cache
from collections import defaultdict
from itertools import tee
price = defaultdict(dict)
def add(start, end, w):
global price
for x, y in get_way(start, end):
if x in price:
price[x][y] += w
else:
price[x] = defaultdict(lambda: 0)
price[x][y] = w
if y in price:
price[y][x] += w
else:
price[y] = defaultdict(lambda: 0)
price[y][x] = w
def get_price(start, end):
result = 0
for x, y in get_way(start, end):
if x in price:
result += price[x][y]
return result
@lru_cache(maxsize=1000)
def get_way(start, end):
def _get_raw_way():
nonlocal start, end
l_way, r_way = [start], [end]
while True:
l = l_way[-1] // 2
if l: l_way.append(l)
r = r_way[-1] // 2
if r: r_way.append(r)
if r_way[-1] == start:
return r_way
if set(l_way) & set(r_way):
del r_way[-1]
r_way.reverse()
return l_way + r_way
a, b = tee(_get_raw_way())
next(b, None)
return zip(a, b)
q = int(input())
for _ in range(q):
data = list(map(int, input().split(' ')))
if data[0] == 1:
add(data[1], data[2], data[3])
else:
print(get_price(data[1], data[2]))
``` | instruction | 0 | 10,416 | 1 | 20,832 |
No | output | 1 | 10,416 | 1 | 20,833 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Winnie-the-Pooh likes honey very much! That is why he decided to visit his friends. Winnie has got three best friends: Rabbit, Owl and Eeyore, each of them lives in his own house. There are winding paths between each pair of houses. The length of a path between Rabbit's and Owl's houses is a meters, between Rabbit's and Eeyore's house is b meters, between Owl's and Eeyore's house is c meters.
For enjoying his life and singing merry songs Winnie-the-Pooh should have a meal n times a day. Now he is in the Rabbit's house and has a meal for the first time. Each time when in the friend's house where Winnie is now the supply of honey is about to end, Winnie leaves that house. If Winnie has not had a meal the required amount of times, he comes out from the house and goes to someone else of his two friends. For this he chooses one of two adjacent paths, arrives to the house on the other end and visits his friend. You may assume that when Winnie is eating in one of his friend's house, the supply of honey in other friend's houses recover (most probably, they go to the supply store).
Winnie-the-Pooh does not like physical activity. He wants to have a meal n times, traveling minimum possible distance. Help him to find this distance.
Input
First line contains an integer n (1 ≤ n ≤ 100) — number of visits.
Second line contains an integer a (1 ≤ a ≤ 100) — distance between Rabbit's and Owl's houses.
Third line contains an integer b (1 ≤ b ≤ 100) — distance between Rabbit's and Eeyore's houses.
Fourth line contains an integer c (1 ≤ c ≤ 100) — distance between Owl's and Eeyore's houses.
Output
Output one number — minimum distance in meters Winnie must go through to have a meal n times.
Examples
Input
3
2
3
1
Output
3
Input
1
2
3
5
Output
0
Note
In the first test case the optimal path for Winnie is the following: first have a meal in Rabbit's house, then in Owl's house, then in Eeyore's house. Thus he will pass the distance 2 + 1 = 3.
In the second test case Winnie has a meal in Rabbit's house and that is for him. So he doesn't have to walk anywhere at all. | instruction | 0 | 10,479 | 1 | 20,958 |
Tags: math
Correct Solution:
```
n = int(input());
a = int(input());
b = int(input());
c = int(input());
ans = 0;
k = 1;
for i in range(n-1):
if (k == 1):
if (a < b):
k = 2;
ans += a;
else:
k = 3;
ans += b;
elif k == 2 :
if (a < c):
k = 1;
ans += a;
else:
k = 3;
ans += c;
else:
if (b < c):
k = 1;
ans += b;
else:
k = 2;
ans += c;
print(ans);
``` | output | 1 | 10,479 | 1 | 20,959 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Winnie-the-Pooh likes honey very much! That is why he decided to visit his friends. Winnie has got three best friends: Rabbit, Owl and Eeyore, each of them lives in his own house. There are winding paths between each pair of houses. The length of a path between Rabbit's and Owl's houses is a meters, between Rabbit's and Eeyore's house is b meters, between Owl's and Eeyore's house is c meters.
For enjoying his life and singing merry songs Winnie-the-Pooh should have a meal n times a day. Now he is in the Rabbit's house and has a meal for the first time. Each time when in the friend's house where Winnie is now the supply of honey is about to end, Winnie leaves that house. If Winnie has not had a meal the required amount of times, he comes out from the house and goes to someone else of his two friends. For this he chooses one of two adjacent paths, arrives to the house on the other end and visits his friend. You may assume that when Winnie is eating in one of his friend's house, the supply of honey in other friend's houses recover (most probably, they go to the supply store).
Winnie-the-Pooh does not like physical activity. He wants to have a meal n times, traveling minimum possible distance. Help him to find this distance.
Input
First line contains an integer n (1 ≤ n ≤ 100) — number of visits.
Second line contains an integer a (1 ≤ a ≤ 100) — distance between Rabbit's and Owl's houses.
Third line contains an integer b (1 ≤ b ≤ 100) — distance between Rabbit's and Eeyore's houses.
Fourth line contains an integer c (1 ≤ c ≤ 100) — distance between Owl's and Eeyore's houses.
Output
Output one number — minimum distance in meters Winnie must go through to have a meal n times.
Examples
Input
3
2
3
1
Output
3
Input
1
2
3
5
Output
0
Note
In the first test case the optimal path for Winnie is the following: first have a meal in Rabbit's house, then in Owl's house, then in Eeyore's house. Thus he will pass the distance 2 + 1 = 3.
In the second test case Winnie has a meal in Rabbit's house and that is for him. So he doesn't have to walk anywhere at all. | instruction | 0 | 10,480 | 1 | 20,960 |
Tags: math
Correct Solution:
```
n,a,b,c=int(input()),int(input()),int(input()),int(input())
if n==1: print(0)
else:
first = a if a<b else b
second = first if first<c else c
print(first+(n-2)*second)
``` | output | 1 | 10,480 | 1 | 20,961 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Winnie-the-Pooh likes honey very much! That is why he decided to visit his friends. Winnie has got three best friends: Rabbit, Owl and Eeyore, each of them lives in his own house. There are winding paths between each pair of houses. The length of a path between Rabbit's and Owl's houses is a meters, between Rabbit's and Eeyore's house is b meters, between Owl's and Eeyore's house is c meters.
For enjoying his life and singing merry songs Winnie-the-Pooh should have a meal n times a day. Now he is in the Rabbit's house and has a meal for the first time. Each time when in the friend's house where Winnie is now the supply of honey is about to end, Winnie leaves that house. If Winnie has not had a meal the required amount of times, he comes out from the house and goes to someone else of his two friends. For this he chooses one of two adjacent paths, arrives to the house on the other end and visits his friend. You may assume that when Winnie is eating in one of his friend's house, the supply of honey in other friend's houses recover (most probably, they go to the supply store).
Winnie-the-Pooh does not like physical activity. He wants to have a meal n times, traveling minimum possible distance. Help him to find this distance.
Input
First line contains an integer n (1 ≤ n ≤ 100) — number of visits.
Second line contains an integer a (1 ≤ a ≤ 100) — distance between Rabbit's and Owl's houses.
Third line contains an integer b (1 ≤ b ≤ 100) — distance between Rabbit's and Eeyore's houses.
Fourth line contains an integer c (1 ≤ c ≤ 100) — distance between Owl's and Eeyore's houses.
Output
Output one number — minimum distance in meters Winnie must go through to have a meal n times.
Examples
Input
3
2
3
1
Output
3
Input
1
2
3
5
Output
0
Note
In the first test case the optimal path for Winnie is the following: first have a meal in Rabbit's house, then in Owl's house, then in Eeyore's house. Thus he will pass the distance 2 + 1 = 3.
In the second test case Winnie has a meal in Rabbit's house and that is for him. So he doesn't have to walk anywhere at all. | instruction | 0 | 10,481 | 1 | 20,962 |
Tags: math
Correct Solution:
```
n = int(input())
dist = []
dist.append(int(input()))
dist.append(int(input()))
dist.append(int(input()))
dist2 = sorted(dist)
if n==1:
print(0)
elif dist2[0]==dist[0]:
print((n-1)*dist[0])
elif dist2[0]==dist[1]:
print((n-1)*dist[1])
else:
if dist2[1]==dist[0]:
print(dist[0]+(n-2)*dist[2])
else:
print(dist[1]+(n-2)*dist[2])
``` | output | 1 | 10,481 | 1 | 20,963 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Winnie-the-Pooh likes honey very much! That is why he decided to visit his friends. Winnie has got three best friends: Rabbit, Owl and Eeyore, each of them lives in his own house. There are winding paths between each pair of houses. The length of a path between Rabbit's and Owl's houses is a meters, between Rabbit's and Eeyore's house is b meters, between Owl's and Eeyore's house is c meters.
For enjoying his life and singing merry songs Winnie-the-Pooh should have a meal n times a day. Now he is in the Rabbit's house and has a meal for the first time. Each time when in the friend's house where Winnie is now the supply of honey is about to end, Winnie leaves that house. If Winnie has not had a meal the required amount of times, he comes out from the house and goes to someone else of his two friends. For this he chooses one of two adjacent paths, arrives to the house on the other end and visits his friend. You may assume that when Winnie is eating in one of his friend's house, the supply of honey in other friend's houses recover (most probably, they go to the supply store).
Winnie-the-Pooh does not like physical activity. He wants to have a meal n times, traveling minimum possible distance. Help him to find this distance.
Input
First line contains an integer n (1 ≤ n ≤ 100) — number of visits.
Second line contains an integer a (1 ≤ a ≤ 100) — distance between Rabbit's and Owl's houses.
Third line contains an integer b (1 ≤ b ≤ 100) — distance between Rabbit's and Eeyore's houses.
Fourth line contains an integer c (1 ≤ c ≤ 100) — distance between Owl's and Eeyore's houses.
Output
Output one number — minimum distance in meters Winnie must go through to have a meal n times.
Examples
Input
3
2
3
1
Output
3
Input
1
2
3
5
Output
0
Note
In the first test case the optimal path for Winnie is the following: first have a meal in Rabbit's house, then in Owl's house, then in Eeyore's house. Thus he will pass the distance 2 + 1 = 3.
In the second test case Winnie has a meal in Rabbit's house and that is for him. So he doesn't have to walk anywhere at all. | instruction | 0 | 10,482 | 1 | 20,964 |
Tags: math
Correct Solution:
```
d={}
n=int(input())
ab=int(input())
ac=int(input())
bc=int(input())
d[1]=[[2,ab],[3,ac]]
d[2]=[[1,ab],[3,bc]]
d[3]=[[2,bc],[1,ac]]
ans=0
k=1
x=1
while k<n:
ans+=min(d[x][0][1],d[x][1][1])
if d[x][0][1]<d[x][1][1]:
x=d[x][0][0]
else:
x=d[x][1][0]
k+=1
print(ans)
``` | output | 1 | 10,482 | 1 | 20,965 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Winnie-the-Pooh likes honey very much! That is why he decided to visit his friends. Winnie has got three best friends: Rabbit, Owl and Eeyore, each of them lives in his own house. There are winding paths between each pair of houses. The length of a path between Rabbit's and Owl's houses is a meters, between Rabbit's and Eeyore's house is b meters, between Owl's and Eeyore's house is c meters.
For enjoying his life and singing merry songs Winnie-the-Pooh should have a meal n times a day. Now he is in the Rabbit's house and has a meal for the first time. Each time when in the friend's house where Winnie is now the supply of honey is about to end, Winnie leaves that house. If Winnie has not had a meal the required amount of times, he comes out from the house and goes to someone else of his two friends. For this he chooses one of two adjacent paths, arrives to the house on the other end and visits his friend. You may assume that when Winnie is eating in one of his friend's house, the supply of honey in other friend's houses recover (most probably, they go to the supply store).
Winnie-the-Pooh does not like physical activity. He wants to have a meal n times, traveling minimum possible distance. Help him to find this distance.
Input
First line contains an integer n (1 ≤ n ≤ 100) — number of visits.
Second line contains an integer a (1 ≤ a ≤ 100) — distance between Rabbit's and Owl's houses.
Third line contains an integer b (1 ≤ b ≤ 100) — distance between Rabbit's and Eeyore's houses.
Fourth line contains an integer c (1 ≤ c ≤ 100) — distance between Owl's and Eeyore's houses.
Output
Output one number — minimum distance in meters Winnie must go through to have a meal n times.
Examples
Input
3
2
3
1
Output
3
Input
1
2
3
5
Output
0
Note
In the first test case the optimal path for Winnie is the following: first have a meal in Rabbit's house, then in Owl's house, then in Eeyore's house. Thus he will pass the distance 2 + 1 = 3.
In the second test case Winnie has a meal in Rabbit's house and that is for him. So he doesn't have to walk anywhere at all. | instruction | 0 | 10,483 | 1 | 20,966 |
Tags: math
Correct Solution:
```
n=int(input())
a=int(input())#1-2
b=int(input())#1-3
c=int(input())#3-2
nowat=1
ans=0
for i in range(n-1):
if nowat==1:
if a<b:
ans+=a
nowat=2
else:
ans+=b
nowat=3
elif nowat==2:
if a<c:
ans+=a
nowat=1
else:
ans+=c
nowat=3
elif nowat==3:
if b<c:
ans+=b
nowat=1
else:
ans+=c
nowat=2
print(ans)
``` | output | 1 | 10,483 | 1 | 20,967 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Winnie-the-Pooh likes honey very much! That is why he decided to visit his friends. Winnie has got three best friends: Rabbit, Owl and Eeyore, each of them lives in his own house. There are winding paths between each pair of houses. The length of a path between Rabbit's and Owl's houses is a meters, between Rabbit's and Eeyore's house is b meters, between Owl's and Eeyore's house is c meters.
For enjoying his life and singing merry songs Winnie-the-Pooh should have a meal n times a day. Now he is in the Rabbit's house and has a meal for the first time. Each time when in the friend's house where Winnie is now the supply of honey is about to end, Winnie leaves that house. If Winnie has not had a meal the required amount of times, he comes out from the house and goes to someone else of his two friends. For this he chooses one of two adjacent paths, arrives to the house on the other end and visits his friend. You may assume that when Winnie is eating in one of his friend's house, the supply of honey in other friend's houses recover (most probably, they go to the supply store).
Winnie-the-Pooh does not like physical activity. He wants to have a meal n times, traveling minimum possible distance. Help him to find this distance.
Input
First line contains an integer n (1 ≤ n ≤ 100) — number of visits.
Second line contains an integer a (1 ≤ a ≤ 100) — distance between Rabbit's and Owl's houses.
Third line contains an integer b (1 ≤ b ≤ 100) — distance between Rabbit's and Eeyore's houses.
Fourth line contains an integer c (1 ≤ c ≤ 100) — distance between Owl's and Eeyore's houses.
Output
Output one number — minimum distance in meters Winnie must go through to have a meal n times.
Examples
Input
3
2
3
1
Output
3
Input
1
2
3
5
Output
0
Note
In the first test case the optimal path for Winnie is the following: first have a meal in Rabbit's house, then in Owl's house, then in Eeyore's house. Thus he will pass the distance 2 + 1 = 3.
In the second test case Winnie has a meal in Rabbit's house and that is for him. So he doesn't have to walk anywhere at all. | instruction | 0 | 10,484 | 1 | 20,968 |
Tags: math
Correct Solution:
```
n = int(input())
a = int(input())
b = int(input())
c = int(input())
ans = 0
t = 0
n-=1
if n == 0:
print(0)
exit(0)
if c < a and c < b:
ans = min(a, b) + (n-1)*c
else:
ans = min(a, b)*(n)
print(ans)
``` | output | 1 | 10,484 | 1 | 20,969 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Winnie-the-Pooh likes honey very much! That is why he decided to visit his friends. Winnie has got three best friends: Rabbit, Owl and Eeyore, each of them lives in his own house. There are winding paths between each pair of houses. The length of a path between Rabbit's and Owl's houses is a meters, between Rabbit's and Eeyore's house is b meters, between Owl's and Eeyore's house is c meters.
For enjoying his life and singing merry songs Winnie-the-Pooh should have a meal n times a day. Now he is in the Rabbit's house and has a meal for the first time. Each time when in the friend's house where Winnie is now the supply of honey is about to end, Winnie leaves that house. If Winnie has not had a meal the required amount of times, he comes out from the house and goes to someone else of his two friends. For this he chooses one of two adjacent paths, arrives to the house on the other end and visits his friend. You may assume that when Winnie is eating in one of his friend's house, the supply of honey in other friend's houses recover (most probably, they go to the supply store).
Winnie-the-Pooh does not like physical activity. He wants to have a meal n times, traveling minimum possible distance. Help him to find this distance.
Input
First line contains an integer n (1 ≤ n ≤ 100) — number of visits.
Second line contains an integer a (1 ≤ a ≤ 100) — distance between Rabbit's and Owl's houses.
Third line contains an integer b (1 ≤ b ≤ 100) — distance between Rabbit's and Eeyore's houses.
Fourth line contains an integer c (1 ≤ c ≤ 100) — distance between Owl's and Eeyore's houses.
Output
Output one number — minimum distance in meters Winnie must go through to have a meal n times.
Examples
Input
3
2
3
1
Output
3
Input
1
2
3
5
Output
0
Note
In the first test case the optimal path for Winnie is the following: first have a meal in Rabbit's house, then in Owl's house, then in Eeyore's house. Thus he will pass the distance 2 + 1 = 3.
In the second test case Winnie has a meal in Rabbit's house and that is for him. So he doesn't have to walk anywhere at all. | instruction | 0 | 10,485 | 1 | 20,970 |
Tags: math
Correct Solution:
```
#https://codeforces.com/problemset/problem/876/A
n=int(input())
a=int(input())
b=int(input())
c=int(input())
n=n-1
ans=0
if n:
n-=1
ans+=min(a,b)
#print(c,n)
ans+=(min(a,b,c)*n)
print(ans)
``` | output | 1 | 10,485 | 1 | 20,971 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Winnie-the-Pooh likes honey very much! That is why he decided to visit his friends. Winnie has got three best friends: Rabbit, Owl and Eeyore, each of them lives in his own house. There are winding paths between each pair of houses. The length of a path between Rabbit's and Owl's houses is a meters, between Rabbit's and Eeyore's house is b meters, between Owl's and Eeyore's house is c meters.
For enjoying his life and singing merry songs Winnie-the-Pooh should have a meal n times a day. Now he is in the Rabbit's house and has a meal for the first time. Each time when in the friend's house where Winnie is now the supply of honey is about to end, Winnie leaves that house. If Winnie has not had a meal the required amount of times, he comes out from the house and goes to someone else of his two friends. For this he chooses one of two adjacent paths, arrives to the house on the other end and visits his friend. You may assume that when Winnie is eating in one of his friend's house, the supply of honey in other friend's houses recover (most probably, they go to the supply store).
Winnie-the-Pooh does not like physical activity. He wants to have a meal n times, traveling minimum possible distance. Help him to find this distance.
Input
First line contains an integer n (1 ≤ n ≤ 100) — number of visits.
Second line contains an integer a (1 ≤ a ≤ 100) — distance between Rabbit's and Owl's houses.
Third line contains an integer b (1 ≤ b ≤ 100) — distance between Rabbit's and Eeyore's houses.
Fourth line contains an integer c (1 ≤ c ≤ 100) — distance between Owl's and Eeyore's houses.
Output
Output one number — minimum distance in meters Winnie must go through to have a meal n times.
Examples
Input
3
2
3
1
Output
3
Input
1
2
3
5
Output
0
Note
In the first test case the optimal path for Winnie is the following: first have a meal in Rabbit's house, then in Owl's house, then in Eeyore's house. Thus he will pass the distance 2 + 1 = 3.
In the second test case Winnie has a meal in Rabbit's house and that is for him. So he doesn't have to walk anywhere at all. | instruction | 0 | 10,486 | 1 | 20,972 |
Tags: math
Correct Solution:
```
#problem65
n=int(input())
a=int(input())
b=int(input())
c=int(input())
if n==1:
print(0)
elif min(a,b,c)==a or min(a,b,c)==b:
print(min(a,b)*(n-1))
else:
print(min(a,b)+c*(n-2))
``` | output | 1 | 10,486 | 1 | 20,973 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Peter likes to travel by train. He likes it so much that on the train he falls asleep.
Once in summer Peter was going by train from city A to city B, and as usual, was sleeping. Then he woke up, started to look through the window and noticed that every railway station has a flag of a particular colour.
The boy started to memorize the order of the flags' colours that he had seen. But soon he fell asleep again. Unfortunately, he didn't sleep long, he woke up and went on memorizing the colours. Then he fell asleep again, and that time he slept till the end of the journey.
At the station he told his parents about what he was doing, and wrote two sequences of the colours that he had seen before and after his sleep, respectively.
Peter's parents know that their son likes to fantasize. They give you the list of the flags' colours at the stations that the train passes sequentially on the way from A to B, and ask you to find out if Peter could see those sequences on the way from A to B, or from B to A. Remember, please, that Peter had two periods of wakefulness.
Peter's parents put lowercase Latin letters for colours. The same letter stands for the same colour, different letters — for different colours.
Input
The input data contains three lines. The first line contains a non-empty string, whose length does not exceed 105, the string consists of lowercase Latin letters — the flags' colours at the stations on the way from A to B. On the way from B to A the train passes the same stations, but in reverse order.
The second line contains the sequence, written by Peter during the first period of wakefulness. The third line contains the sequence, written during the second period of wakefulness. Both sequences are non-empty, consist of lowercase Latin letters, and the length of each does not exceed 100 letters. Each of the sequences is written in chronological order.
Output
Output one of the four words without inverted commas:
* «forward» — if Peter could see such sequences only on the way from A to B;
* «backward» — if Peter could see such sequences on the way from B to A;
* «both» — if Peter could see such sequences both on the way from A to B, and on the way from B to A;
* «fantasy» — if Peter could not see such sequences.
Examples
Input
atob
a
b
Output
forward
Input
aaacaaa
aca
aa
Output
both
Note
It is assumed that the train moves all the time, so one flag cannot be seen twice. There are no flags at stations A and B. | instruction | 0 | 10,495 | 1 | 20,990 |
Tags: strings
Correct Solution:
```
import sys
import string
from collections import Counter, defaultdict
from math import fsum, sqrt, gcd, ceil, factorial
from operator import *
from itertools import accumulate
inf = float("inf")
# input = sys.stdin.readline
flush = lambda: sys.stdout.flush
comb = lambda x, y: (factorial(x) // factorial(y)) // factorial(x - y)
# inputs
# ip = lambda : input().rstrip()
ip = lambda: input()
ii = lambda: int(input())
r = lambda: map(int, input().split())
rr = lambda: list(r())
import re
a = ip()
b = a[::-1]
x = ip()
y = ip()
a = re.match(f'(.*){x}(.*){y}', a)
b = re.match(f'(.*){x}(.*){y}', b)
# print(a, b)
if a and b:
print("both")
elif a and not b:
print("forward")
elif not a and b:
print("backward")
else:
print("fantasy")
``` | output | 1 | 10,495 | 1 | 20,991 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Peter likes to travel by train. He likes it so much that on the train he falls asleep.
Once in summer Peter was going by train from city A to city B, and as usual, was sleeping. Then he woke up, started to look through the window and noticed that every railway station has a flag of a particular colour.
The boy started to memorize the order of the flags' colours that he had seen. But soon he fell asleep again. Unfortunately, he didn't sleep long, he woke up and went on memorizing the colours. Then he fell asleep again, and that time he slept till the end of the journey.
At the station he told his parents about what he was doing, and wrote two sequences of the colours that he had seen before and after his sleep, respectively.
Peter's parents know that their son likes to fantasize. They give you the list of the flags' colours at the stations that the train passes sequentially on the way from A to B, and ask you to find out if Peter could see those sequences on the way from A to B, or from B to A. Remember, please, that Peter had two periods of wakefulness.
Peter's parents put lowercase Latin letters for colours. The same letter stands for the same colour, different letters — for different colours.
Input
The input data contains three lines. The first line contains a non-empty string, whose length does not exceed 105, the string consists of lowercase Latin letters — the flags' colours at the stations on the way from A to B. On the way from B to A the train passes the same stations, but in reverse order.
The second line contains the sequence, written by Peter during the first period of wakefulness. The third line contains the sequence, written during the second period of wakefulness. Both sequences are non-empty, consist of lowercase Latin letters, and the length of each does not exceed 100 letters. Each of the sequences is written in chronological order.
Output
Output one of the four words without inverted commas:
* «forward» — if Peter could see such sequences only on the way from A to B;
* «backward» — if Peter could see such sequences on the way from B to A;
* «both» — if Peter could see such sequences both on the way from A to B, and on the way from B to A;
* «fantasy» — if Peter could not see such sequences.
Examples
Input
atob
a
b
Output
forward
Input
aaacaaa
aca
aa
Output
both
Note
It is assumed that the train moves all the time, so one flag cannot be seen twice. There are no flags at stations A and B. | instruction | 0 | 10,496 | 1 | 20,992 |
Tags: strings
Correct Solution:
```
truepath=input()
firstwake=input()
secondwake=input()
d=-1
f=-1
a1=0
a2=0
h=0
if len(firstwake)+len(secondwake)>len(truepath):
print('fantasy') #Peters wakefulness faulted
h=1
if h==0:
for i in range (0,len(truepath)-len(firstwake)+1):
if truepath[i:i+len(firstwake)]==firstwake:
d=i #checking if first path is correct
break
for i in range (0,len(truepath)-len(secondwake)+1):
if truepath[i:i+len(secondwake)]==secondwake:
f=i #checking if second path is correct
if d+len(firstwake)-1<f and d>-1:
a1=1
d=-1
f=-1
truepath=list(truepath)
truepath.reverse()
truepath=''.join(truepath) #introducing this to the array
for i in range (0,len(truepath)-len(firstwake)+1):
if truepath[i:i+len(firstwake)]==firstwake:
d=i
break
for i in range (0,len(truepath)-len(secondwake)+1):
if truepath[i:i+len(secondwake)]==secondwake:
f=i
if d+len(firstwake)-1<f and d>-1:
a2=1
if a1==1 and a2==0:
print('forward')
if a1==0 and a2==1:
print('backward')
if a1==1 and a2==1:
print('both')
if a1==0 and a2==0:
print('fantasy')
``` | output | 1 | 10,496 | 1 | 20,993 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Peter likes to travel by train. He likes it so much that on the train he falls asleep.
Once in summer Peter was going by train from city A to city B, and as usual, was sleeping. Then he woke up, started to look through the window and noticed that every railway station has a flag of a particular colour.
The boy started to memorize the order of the flags' colours that he had seen. But soon he fell asleep again. Unfortunately, he didn't sleep long, he woke up and went on memorizing the colours. Then he fell asleep again, and that time he slept till the end of the journey.
At the station he told his parents about what he was doing, and wrote two sequences of the colours that he had seen before and after his sleep, respectively.
Peter's parents know that their son likes to fantasize. They give you the list of the flags' colours at the stations that the train passes sequentially on the way from A to B, and ask you to find out if Peter could see those sequences on the way from A to B, or from B to A. Remember, please, that Peter had two periods of wakefulness.
Peter's parents put lowercase Latin letters for colours. The same letter stands for the same colour, different letters — for different colours.
Input
The input data contains three lines. The first line contains a non-empty string, whose length does not exceed 105, the string consists of lowercase Latin letters — the flags' colours at the stations on the way from A to B. On the way from B to A the train passes the same stations, but in reverse order.
The second line contains the sequence, written by Peter during the first period of wakefulness. The third line contains the sequence, written during the second period of wakefulness. Both sequences are non-empty, consist of lowercase Latin letters, and the length of each does not exceed 100 letters. Each of the sequences is written in chronological order.
Output
Output one of the four words without inverted commas:
* «forward» — if Peter could see such sequences only on the way from A to B;
* «backward» — if Peter could see such sequences on the way from B to A;
* «both» — if Peter could see such sequences both on the way from A to B, and on the way from B to A;
* «fantasy» — if Peter could not see such sequences.
Examples
Input
atob
a
b
Output
forward
Input
aaacaaa
aca
aa
Output
both
Note
It is assumed that the train moves all the time, so one flag cannot be seen twice. There are no flags at stations A and B. | instruction | 0 | 10,497 | 1 | 20,994 |
Tags: strings
Correct Solution:
```
ss=input()
ns=ss[::-1]
a=input()
b=input()
f1=0
f2=0
k1=ss.find(a)
k2=ss.find(b,k1+len(a))
if ((k1>-1)&(k2>-1)):f1=1
k1=ns.find(a)
k2=ns.find(b,k1+len(a))
if ((k1>-1)&(k2>-1)):f2=1
if f1+f2==2:
print("both")
elif f1==1:
print("forward")
elif f2==1:print("backward")
else:
print("fantasy")
``` | output | 1 | 10,497 | 1 | 20,995 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Peter likes to travel by train. He likes it so much that on the train he falls asleep.
Once in summer Peter was going by train from city A to city B, and as usual, was sleeping. Then he woke up, started to look through the window and noticed that every railway station has a flag of a particular colour.
The boy started to memorize the order of the flags' colours that he had seen. But soon he fell asleep again. Unfortunately, he didn't sleep long, he woke up and went on memorizing the colours. Then he fell asleep again, and that time he slept till the end of the journey.
At the station he told his parents about what he was doing, and wrote two sequences of the colours that he had seen before and after his sleep, respectively.
Peter's parents know that their son likes to fantasize. They give you the list of the flags' colours at the stations that the train passes sequentially on the way from A to B, and ask you to find out if Peter could see those sequences on the way from A to B, or from B to A. Remember, please, that Peter had two periods of wakefulness.
Peter's parents put lowercase Latin letters for colours. The same letter stands for the same colour, different letters — for different colours.
Input
The input data contains three lines. The first line contains a non-empty string, whose length does not exceed 105, the string consists of lowercase Latin letters — the flags' colours at the stations on the way from A to B. On the way from B to A the train passes the same stations, but in reverse order.
The second line contains the sequence, written by Peter during the first period of wakefulness. The third line contains the sequence, written during the second period of wakefulness. Both sequences are non-empty, consist of lowercase Latin letters, and the length of each does not exceed 100 letters. Each of the sequences is written in chronological order.
Output
Output one of the four words without inverted commas:
* «forward» — if Peter could see such sequences only on the way from A to B;
* «backward» — if Peter could see such sequences on the way from B to A;
* «both» — if Peter could see such sequences both on the way from A to B, and on the way from B to A;
* «fantasy» — if Peter could not see such sequences.
Examples
Input
atob
a
b
Output
forward
Input
aaacaaa
aca
aa
Output
both
Note
It is assumed that the train moves all the time, so one flag cannot be seen twice. There are no flags at stations A and B. | instruction | 0 | 10,498 | 1 | 20,996 |
Tags: strings
Correct Solution:
```
def check(flags: str, first: str, second: str) -> bool:
if first not in flags or second not in flags:
return False
f_f_ind = flags.index(first)
l_s_ind = flags.rindex(second)
return f_f_ind + len(first) - 1 < l_s_ind
flags, first, second = input(), input(), input()
f = check(flags, first, second)
flags = flags[::-1]
b = check(flags, first, second)
if f and b:
print('both')
elif f:
print('forward')
elif b:
print('backward')
else:
print('fantasy')
``` | output | 1 | 10,498 | 1 | 20,997 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Peter likes to travel by train. He likes it so much that on the train he falls asleep.
Once in summer Peter was going by train from city A to city B, and as usual, was sleeping. Then he woke up, started to look through the window and noticed that every railway station has a flag of a particular colour.
The boy started to memorize the order of the flags' colours that he had seen. But soon he fell asleep again. Unfortunately, he didn't sleep long, he woke up and went on memorizing the colours. Then he fell asleep again, and that time he slept till the end of the journey.
At the station he told his parents about what he was doing, and wrote two sequences of the colours that he had seen before and after his sleep, respectively.
Peter's parents know that their son likes to fantasize. They give you the list of the flags' colours at the stations that the train passes sequentially on the way from A to B, and ask you to find out if Peter could see those sequences on the way from A to B, or from B to A. Remember, please, that Peter had two periods of wakefulness.
Peter's parents put lowercase Latin letters for colours. The same letter stands for the same colour, different letters — for different colours.
Input
The input data contains three lines. The first line contains a non-empty string, whose length does not exceed 105, the string consists of lowercase Latin letters — the flags' colours at the stations on the way from A to B. On the way from B to A the train passes the same stations, but in reverse order.
The second line contains the sequence, written by Peter during the first period of wakefulness. The third line contains the sequence, written during the second period of wakefulness. Both sequences are non-empty, consist of lowercase Latin letters, and the length of each does not exceed 100 letters. Each of the sequences is written in chronological order.
Output
Output one of the four words without inverted commas:
* «forward» — if Peter could see such sequences only on the way from A to B;
* «backward» — if Peter could see such sequences on the way from B to A;
* «both» — if Peter could see such sequences both on the way from A to B, and on the way from B to A;
* «fantasy» — if Peter could not see such sequences.
Examples
Input
atob
a
b
Output
forward
Input
aaacaaa
aca
aa
Output
both
Note
It is assumed that the train moves all the time, so one flag cannot be seen twice. There are no flags at stations A and B. | instruction | 0 | 10,499 | 1 | 20,998 |
Tags: strings
Correct Solution:
```
a=input()
b=input()
c=input()
d=-1
f=-1
a1=0
a2=0
h=0
if len(b)+len(c)>len(a):
print('fantasy')
h=1
if h==0:
for i in range (0,len(a)-len(b)+1):
#print(a[i:i+len(b)])
if a[i:i+len(b)]==b:
d=i
break
for i in range (0,len(a)-len(c)+1):
#print(a[i:i+len(c)])
if a[i:i+len(c)]==c:
f=i
if d+len(b)-1<f and d>-1:
a1=1
d=-1
f=-1
a=list(a)
a.reverse()
a=''.join(a)
for i in range (0,len(a)-len(b)+1):
if a[i:i+len(b)]==b:
d=i
break
for i in range (0,len(a)-len(c)+1):
if a[i:i+len(c)]==c:
f=i
if d+len(b)-1<f and d>-1:
a2=1
if a1==1 and a2==0:
print('forward')
if a1==0 and a2==1:
print('backward')
if a1==1 and a2==1:
print('both')
if a1==0 and a2==0:
print('fantasy')
``` | output | 1 | 10,499 | 1 | 20,999 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Peter likes to travel by train. He likes it so much that on the train he falls asleep.
Once in summer Peter was going by train from city A to city B, and as usual, was sleeping. Then he woke up, started to look through the window and noticed that every railway station has a flag of a particular colour.
The boy started to memorize the order of the flags' colours that he had seen. But soon he fell asleep again. Unfortunately, he didn't sleep long, he woke up and went on memorizing the colours. Then he fell asleep again, and that time he slept till the end of the journey.
At the station he told his parents about what he was doing, and wrote two sequences of the colours that he had seen before and after his sleep, respectively.
Peter's parents know that their son likes to fantasize. They give you the list of the flags' colours at the stations that the train passes sequentially on the way from A to B, and ask you to find out if Peter could see those sequences on the way from A to B, or from B to A. Remember, please, that Peter had two periods of wakefulness.
Peter's parents put lowercase Latin letters for colours. The same letter stands for the same colour, different letters — for different colours.
Input
The input data contains three lines. The first line contains a non-empty string, whose length does not exceed 105, the string consists of lowercase Latin letters — the flags' colours at the stations on the way from A to B. On the way from B to A the train passes the same stations, but in reverse order.
The second line contains the sequence, written by Peter during the first period of wakefulness. The third line contains the sequence, written during the second period of wakefulness. Both sequences are non-empty, consist of lowercase Latin letters, and the length of each does not exceed 100 letters. Each of the sequences is written in chronological order.
Output
Output one of the four words without inverted commas:
* «forward» — if Peter could see such sequences only on the way from A to B;
* «backward» — if Peter could see such sequences on the way from B to A;
* «both» — if Peter could see such sequences both on the way from A to B, and on the way from B to A;
* «fantasy» — if Peter could not see such sequences.
Examples
Input
atob
a
b
Output
forward
Input
aaacaaa
aca
aa
Output
both
Note
It is assumed that the train moves all the time, so one flag cannot be seen twice. There are no flags at stations A and B. | instruction | 0 | 10,500 | 1 | 21,000 |
Tags: strings
Correct Solution:
```
import string
def main():
flags = input()
s1 = input()
s2 = input()
# flags = "aaabbaa"
# s1 = "aab"
# s2 = "aaa"
revFlags = flags[::-1]
foundF = canSee(flags, s1, s2)
foundRevF = canSee(revFlags, s1, s2)
if foundF == True:
if foundRevF == True:
print("both")
else:
print("forward")
else:
if foundRevF == True:
print("backward")
else:
print("fantasy")
def canSee(flags, s1, s2):
foundS1 = flags.find(s1)
if foundS1 != -1:
rem = flags[foundS1+len(s1):]
if rem.find(s2) != -1:
return True
return False
main()
#print(canSee("abacabb", "aca", "aa"))
``` | output | 1 | 10,500 | 1 | 21,001 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Peter likes to travel by train. He likes it so much that on the train he falls asleep.
Once in summer Peter was going by train from city A to city B, and as usual, was sleeping. Then he woke up, started to look through the window and noticed that every railway station has a flag of a particular colour.
The boy started to memorize the order of the flags' colours that he had seen. But soon he fell asleep again. Unfortunately, he didn't sleep long, he woke up and went on memorizing the colours. Then he fell asleep again, and that time he slept till the end of the journey.
At the station he told his parents about what he was doing, and wrote two sequences of the colours that he had seen before and after his sleep, respectively.
Peter's parents know that their son likes to fantasize. They give you the list of the flags' colours at the stations that the train passes sequentially on the way from A to B, and ask you to find out if Peter could see those sequences on the way from A to B, or from B to A. Remember, please, that Peter had two periods of wakefulness.
Peter's parents put lowercase Latin letters for colours. The same letter stands for the same colour, different letters — for different colours.
Input
The input data contains three lines. The first line contains a non-empty string, whose length does not exceed 105, the string consists of lowercase Latin letters — the flags' colours at the stations on the way from A to B. On the way from B to A the train passes the same stations, but in reverse order.
The second line contains the sequence, written by Peter during the first period of wakefulness. The third line contains the sequence, written during the second period of wakefulness. Both sequences are non-empty, consist of lowercase Latin letters, and the length of each does not exceed 100 letters. Each of the sequences is written in chronological order.
Output
Output one of the four words without inverted commas:
* «forward» — if Peter could see such sequences only on the way from A to B;
* «backward» — if Peter could see such sequences on the way from B to A;
* «both» — if Peter could see such sequences both on the way from A to B, and on the way from B to A;
* «fantasy» — if Peter could not see such sequences.
Examples
Input
atob
a
b
Output
forward
Input
aaacaaa
aca
aa
Output
both
Note
It is assumed that the train moves all the time, so one flag cannot be seen twice. There are no flags at stations A and B. | instruction | 0 | 10,501 | 1 | 21,002 |
Tags: strings
Correct Solution:
```
m1 = input()
a = input()
b = input()
length = len(m1)
m2 = ""
r1 = False
r2 = False
for i in range(length):
m2 = m2 + m1[length-i-1]
for i in range(length):
if m1[i:i+len(a)] == a :
r1 = True
if r1 == True and m1[i+len(a):i+len(a)+len(b)] == b :
r2 = True
break
r3 = False
r4 = False
for i in range(length):
if m2[i:i + len(a)] == a:
r3 = True
if r3 == True and m2[i+len(a):i+len(b)+len(a)] == b:
r4 = True
break
if r2 == True and r4 == True : print("both")
if r2 == True and r4 == False : print("forward")
if r2 == False and r4 == True : print("backward")
if r2 == False and r4 == False : print("fantasy")
``` | output | 1 | 10,501 | 1 | 21,003 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Peter likes to travel by train. He likes it so much that on the train he falls asleep.
Once in summer Peter was going by train from city A to city B, and as usual, was sleeping. Then he woke up, started to look through the window and noticed that every railway station has a flag of a particular colour.
The boy started to memorize the order of the flags' colours that he had seen. But soon he fell asleep again. Unfortunately, he didn't sleep long, he woke up and went on memorizing the colours. Then he fell asleep again, and that time he slept till the end of the journey.
At the station he told his parents about what he was doing, and wrote two sequences of the colours that he had seen before and after his sleep, respectively.
Peter's parents know that their son likes to fantasize. They give you the list of the flags' colours at the stations that the train passes sequentially on the way from A to B, and ask you to find out if Peter could see those sequences on the way from A to B, or from B to A. Remember, please, that Peter had two periods of wakefulness.
Peter's parents put lowercase Latin letters for colours. The same letter stands for the same colour, different letters — for different colours.
Input
The input data contains three lines. The first line contains a non-empty string, whose length does not exceed 105, the string consists of lowercase Latin letters — the flags' colours at the stations on the way from A to B. On the way from B to A the train passes the same stations, but in reverse order.
The second line contains the sequence, written by Peter during the first period of wakefulness. The third line contains the sequence, written during the second period of wakefulness. Both sequences are non-empty, consist of lowercase Latin letters, and the length of each does not exceed 100 letters. Each of the sequences is written in chronological order.
Output
Output one of the four words without inverted commas:
* «forward» — if Peter could see such sequences only on the way from A to B;
* «backward» — if Peter could see such sequences on the way from B to A;
* «both» — if Peter could see such sequences both on the way from A to B, and on the way from B to A;
* «fantasy» — if Peter could not see such sequences.
Examples
Input
atob
a
b
Output
forward
Input
aaacaaa
aca
aa
Output
both
Note
It is assumed that the train moves all the time, so one flag cannot be seen twice. There are no flags at stations A and B. | instruction | 0 | 10,502 | 1 | 21,004 |
Tags: strings
Correct Solution:
```
def train_and_peter():
flags = input()
a = input()
b = input()
i = flags.find(a)
if i == -1:
forward = False
else:
forward = flags.find(b, i + len(a)) != -1
reversed_flags = flags[::-1]
j = reversed_flags.find(a)
if j == -1:
backward = False
else:
backward = reversed_flags.find(b, j + len(a)) != -1
if forward and backward:
print('both')
elif forward:
print('forward')
elif backward:
print('backward')
else:
print('fantasy')
train_and_peter()
``` | output | 1 | 10,502 | 1 | 21,005 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Peter likes to travel by train. He likes it so much that on the train he falls asleep.
Once in summer Peter was going by train from city A to city B, and as usual, was sleeping. Then he woke up, started to look through the window and noticed that every railway station has a flag of a particular colour.
The boy started to memorize the order of the flags' colours that he had seen. But soon he fell asleep again. Unfortunately, he didn't sleep long, he woke up and went on memorizing the colours. Then he fell asleep again, and that time he slept till the end of the journey.
At the station he told his parents about what he was doing, and wrote two sequences of the colours that he had seen before and after his sleep, respectively.
Peter's parents know that their son likes to fantasize. They give you the list of the flags' colours at the stations that the train passes sequentially on the way from A to B, and ask you to find out if Peter could see those sequences on the way from A to B, or from B to A. Remember, please, that Peter had two periods of wakefulness.
Peter's parents put lowercase Latin letters for colours. The same letter stands for the same colour, different letters — for different colours.
Input
The input data contains three lines. The first line contains a non-empty string, whose length does not exceed 105, the string consists of lowercase Latin letters — the flags' colours at the stations on the way from A to B. On the way from B to A the train passes the same stations, but in reverse order.
The second line contains the sequence, written by Peter during the first period of wakefulness. The third line contains the sequence, written during the second period of wakefulness. Both sequences are non-empty, consist of lowercase Latin letters, and the length of each does not exceed 100 letters. Each of the sequences is written in chronological order.
Output
Output one of the four words without inverted commas:
* «forward» — if Peter could see such sequences only on the way from A to B;
* «backward» — if Peter could see such sequences on the way from B to A;
* «both» — if Peter could see such sequences both on the way from A to B, and on the way from B to A;
* «fantasy» — if Peter could not see such sequences.
Examples
Input
atob
a
b
Output
forward
Input
aaacaaa
aca
aa
Output
both
Note
It is assumed that the train moves all the time, so one flag cannot be seen twice. There are no flags at stations A and B.
Submitted Solution:
```
allflags = input() #input list of flags
flags1 = input()
flags2 = input()
searchresult = [0]*2 #array of search results
#check if Petya has written flags forward
res1 = allflags.find(flags1)
if res1 != -1: #if first string is in general list of flags
res2 = allflags.find(flags2, res1+len(flags1))
if res2 != -1: #if second string is in general list of flags
searchresult[0] = 1 #if two conditions are carried out
flags = list(allflags) #reverse list of flags
flags.reverse()
flagsrev = ''.join(flags)
#check if Petya has written flags backward
res1 = flagsrev.find(flags1)
if res1 != -1: #if first string is in general list of flags
res2 = flagsrev.find(flags2, res1+len(flags1))
if res2 != -1: #if second string is in general list of flags
searchresult[1] = 1 #if two conditions are carried out
#print the solution
if searchresult[0] == 1 and searchresult[1] == 1:
print('both')
elif searchresult[0] == 1:
print('forward')
elif searchresult[1] == 1:
print('backward')
else:
print('fantasy')
``` | instruction | 0 | 10,503 | 1 | 21,006 |
Yes | output | 1 | 10,503 | 1 | 21,007 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Peter likes to travel by train. He likes it so much that on the train he falls asleep.
Once in summer Peter was going by train from city A to city B, and as usual, was sleeping. Then he woke up, started to look through the window and noticed that every railway station has a flag of a particular colour.
The boy started to memorize the order of the flags' colours that he had seen. But soon he fell asleep again. Unfortunately, he didn't sleep long, he woke up and went on memorizing the colours. Then he fell asleep again, and that time he slept till the end of the journey.
At the station he told his parents about what he was doing, and wrote two sequences of the colours that he had seen before and after his sleep, respectively.
Peter's parents know that their son likes to fantasize. They give you the list of the flags' colours at the stations that the train passes sequentially on the way from A to B, and ask you to find out if Peter could see those sequences on the way from A to B, or from B to A. Remember, please, that Peter had two periods of wakefulness.
Peter's parents put lowercase Latin letters for colours. The same letter stands for the same colour, different letters — for different colours.
Input
The input data contains three lines. The first line contains a non-empty string, whose length does not exceed 105, the string consists of lowercase Latin letters — the flags' colours at the stations on the way from A to B. On the way from B to A the train passes the same stations, but in reverse order.
The second line contains the sequence, written by Peter during the first period of wakefulness. The third line contains the sequence, written during the second period of wakefulness. Both sequences are non-empty, consist of lowercase Latin letters, and the length of each does not exceed 100 letters. Each of the sequences is written in chronological order.
Output
Output one of the four words without inverted commas:
* «forward» — if Peter could see such sequences only on the way from A to B;
* «backward» — if Peter could see such sequences on the way from B to A;
* «both» — if Peter could see such sequences both on the way from A to B, and on the way from B to A;
* «fantasy» — if Peter could not see such sequences.
Examples
Input
atob
a
b
Output
forward
Input
aaacaaa
aca
aa
Output
both
Note
It is assumed that the train moves all the time, so one flag cannot be seen twice. There are no flags at stations A and B.
Submitted Solution:
```
i,ii,iii = [input() for i in range(3)]
def check(a):
try:
c = a.index(ii)
cc = a.index(iii,c+len(ii))
except:
return 0,0
return c,cc
c = check(i)
cc = check(i[::-1])
if c[0] < c[1] and cc[0] < cc[1]: print("both")
elif c[0] < c[1]: print("forward")
elif cc[0] < cc[1]: print("backward")
else: print("fantasy")
``` | instruction | 0 | 10,504 | 1 | 21,008 |
Yes | output | 1 | 10,504 | 1 | 21,009 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Peter likes to travel by train. He likes it so much that on the train he falls asleep.
Once in summer Peter was going by train from city A to city B, and as usual, was sleeping. Then he woke up, started to look through the window and noticed that every railway station has a flag of a particular colour.
The boy started to memorize the order of the flags' colours that he had seen. But soon he fell asleep again. Unfortunately, he didn't sleep long, he woke up and went on memorizing the colours. Then he fell asleep again, and that time he slept till the end of the journey.
At the station he told his parents about what he was doing, and wrote two sequences of the colours that he had seen before and after his sleep, respectively.
Peter's parents know that their son likes to fantasize. They give you the list of the flags' colours at the stations that the train passes sequentially on the way from A to B, and ask you to find out if Peter could see those sequences on the way from A to B, or from B to A. Remember, please, that Peter had two periods of wakefulness.
Peter's parents put lowercase Latin letters for colours. The same letter stands for the same colour, different letters — for different colours.
Input
The input data contains three lines. The first line contains a non-empty string, whose length does not exceed 105, the string consists of lowercase Latin letters — the flags' colours at the stations on the way from A to B. On the way from B to A the train passes the same stations, but in reverse order.
The second line contains the sequence, written by Peter during the first period of wakefulness. The third line contains the sequence, written during the second period of wakefulness. Both sequences are non-empty, consist of lowercase Latin letters, and the length of each does not exceed 100 letters. Each of the sequences is written in chronological order.
Output
Output one of the four words without inverted commas:
* «forward» — if Peter could see such sequences only on the way from A to B;
* «backward» — if Peter could see such sequences on the way from B to A;
* «both» — if Peter could see such sequences both on the way from A to B, and on the way from B to A;
* «fantasy» — if Peter could not see such sequences.
Examples
Input
atob
a
b
Output
forward
Input
aaacaaa
aca
aa
Output
both
Note
It is assumed that the train moves all the time, so one flag cannot be seen twice. There are no flags at stations A and B.
Submitted Solution:
```
def CF_8A():
flag=input()
one=input()
two=input()
rev_flag=flag[::-1]
forward=0
a=flag.find(one)
b=flag.rfind(two)
if a!=-1 and b!=-1 and a+len(one)<=b:
forward=1
backward=0
a=rev_flag.find(one)
b=rev_flag.rfind(two)
if a!=-1 and b!=-1 and a+len(one)<=b:
backward=1
if forward and backward:
print('both')
elif forward:
print('forward')
elif backward:
print('backward')
else:
print('fantasy')
return
CF_8A()
``` | instruction | 0 | 10,505 | 1 | 21,010 |
Yes | output | 1 | 10,505 | 1 | 21,011 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Peter likes to travel by train. He likes it so much that on the train he falls asleep.
Once in summer Peter was going by train from city A to city B, and as usual, was sleeping. Then he woke up, started to look through the window and noticed that every railway station has a flag of a particular colour.
The boy started to memorize the order of the flags' colours that he had seen. But soon he fell asleep again. Unfortunately, he didn't sleep long, he woke up and went on memorizing the colours. Then he fell asleep again, and that time he slept till the end of the journey.
At the station he told his parents about what he was doing, and wrote two sequences of the colours that he had seen before and after his sleep, respectively.
Peter's parents know that their son likes to fantasize. They give you the list of the flags' colours at the stations that the train passes sequentially on the way from A to B, and ask you to find out if Peter could see those sequences on the way from A to B, or from B to A. Remember, please, that Peter had two periods of wakefulness.
Peter's parents put lowercase Latin letters for colours. The same letter stands for the same colour, different letters — for different colours.
Input
The input data contains three lines. The first line contains a non-empty string, whose length does not exceed 105, the string consists of lowercase Latin letters — the flags' colours at the stations on the way from A to B. On the way from B to A the train passes the same stations, but in reverse order.
The second line contains the sequence, written by Peter during the first period of wakefulness. The third line contains the sequence, written during the second period of wakefulness. Both sequences are non-empty, consist of lowercase Latin letters, and the length of each does not exceed 100 letters. Each of the sequences is written in chronological order.
Output
Output one of the four words without inverted commas:
* «forward» — if Peter could see such sequences only on the way from A to B;
* «backward» — if Peter could see such sequences on the way from B to A;
* «both» — if Peter could see such sequences both on the way from A to B, and on the way from B to A;
* «fantasy» — if Peter could not see such sequences.
Examples
Input
atob
a
b
Output
forward
Input
aaacaaa
aca
aa
Output
both
Note
It is assumed that the train moves all the time, so one flag cannot be seen twice. There are no flags at stations A and B.
Submitted Solution:
```
s=input()
s1=input()
s2=input()
index1=s.find(s1)
i=0
temp=index1
forward=0
backward=0
if(index1!=-1):
for x in range(temp,len(s)):
# print(s1[i],s[x],i)
if(i<len(s1)):
if(s1[i]==s[x]):
index1=index1+1
i=i+1
else:
break
else:
break
# print(s1[i],s[x],i)
# print(index1)
index2=s.find(s2,index1)
# print(index1,index2)
if(index2!=-1):
forward=1
s=s[::-1]
# s1,s2=s2,s1
index1=s.find(s1)
i=0
temp=index1
if(index1!=-1):
for x in range(temp,len(s)):
if(i<len(s1)):
if(s1[i]==s[x]):
index1=index1+1
i=i+1
else:
break
else:
break
index2=s.find(s2,index1)
# print(s,index1,index2)
if(index2!=-1):
backward=1
if(forward==1) and (backward==1):
print("both")
elif(forward==0) and (backward==0):
print("fantasy")
elif(forward==1):
print("forward")
else:
print("backward")
``` | instruction | 0 | 10,506 | 1 | 21,012 |
Yes | output | 1 | 10,506 | 1 | 21,013 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Peter likes to travel by train. He likes it so much that on the train he falls asleep.
Once in summer Peter was going by train from city A to city B, and as usual, was sleeping. Then he woke up, started to look through the window and noticed that every railway station has a flag of a particular colour.
The boy started to memorize the order of the flags' colours that he had seen. But soon he fell asleep again. Unfortunately, he didn't sleep long, he woke up and went on memorizing the colours. Then he fell asleep again, and that time he slept till the end of the journey.
At the station he told his parents about what he was doing, and wrote two sequences of the colours that he had seen before and after his sleep, respectively.
Peter's parents know that their son likes to fantasize. They give you the list of the flags' colours at the stations that the train passes sequentially on the way from A to B, and ask you to find out if Peter could see those sequences on the way from A to B, or from B to A. Remember, please, that Peter had two periods of wakefulness.
Peter's parents put lowercase Latin letters for colours. The same letter stands for the same colour, different letters — for different colours.
Input
The input data contains three lines. The first line contains a non-empty string, whose length does not exceed 105, the string consists of lowercase Latin letters — the flags' colours at the stations on the way from A to B. On the way from B to A the train passes the same stations, but in reverse order.
The second line contains the sequence, written by Peter during the first period of wakefulness. The third line contains the sequence, written during the second period of wakefulness. Both sequences are non-empty, consist of lowercase Latin letters, and the length of each does not exceed 100 letters. Each of the sequences is written in chronological order.
Output
Output one of the four words without inverted commas:
* «forward» — if Peter could see such sequences only on the way from A to B;
* «backward» — if Peter could see such sequences on the way from B to A;
* «both» — if Peter could see such sequences both on the way from A to B, and on the way from B to A;
* «fantasy» — if Peter could not see such sequences.
Examples
Input
atob
a
b
Output
forward
Input
aaacaaa
aca
aa
Output
both
Note
It is assumed that the train moves all the time, so one flag cannot be seen twice. There are no flags at stations A and B.
Submitted Solution:
```
Way = input()
L1 = input()
L2 = input()
WayB = Way[::-1]
forw = True
back = True
if Way.find(L1) == Way.rfind(L2) == -1:
print('fantasy')
else:
if Way.find(L1) + len(L1) > Way.rfind(L2):
forw = False
if WayB.find(L1) + len(L2) > WayB.rfind(L2):
back = False
if forw and back:
print('both')
if (not forw) and back:
print('backward')
if forw and (not back):
print('forward')
if (not forw) and (not back):
print('fantasy')
``` | instruction | 0 | 10,507 | 1 | 21,014 |
No | output | 1 | 10,507 | 1 | 21,015 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Peter likes to travel by train. He likes it so much that on the train he falls asleep.
Once in summer Peter was going by train from city A to city B, and as usual, was sleeping. Then he woke up, started to look through the window and noticed that every railway station has a flag of a particular colour.
The boy started to memorize the order of the flags' colours that he had seen. But soon he fell asleep again. Unfortunately, he didn't sleep long, he woke up and went on memorizing the colours. Then he fell asleep again, and that time he slept till the end of the journey.
At the station he told his parents about what he was doing, and wrote two sequences of the colours that he had seen before and after his sleep, respectively.
Peter's parents know that their son likes to fantasize. They give you the list of the flags' colours at the stations that the train passes sequentially on the way from A to B, and ask you to find out if Peter could see those sequences on the way from A to B, or from B to A. Remember, please, that Peter had two periods of wakefulness.
Peter's parents put lowercase Latin letters for colours. The same letter stands for the same colour, different letters — for different colours.
Input
The input data contains three lines. The first line contains a non-empty string, whose length does not exceed 105, the string consists of lowercase Latin letters — the flags' colours at the stations on the way from A to B. On the way from B to A the train passes the same stations, but in reverse order.
The second line contains the sequence, written by Peter during the first period of wakefulness. The third line contains the sequence, written during the second period of wakefulness. Both sequences are non-empty, consist of lowercase Latin letters, and the length of each does not exceed 100 letters. Each of the sequences is written in chronological order.
Output
Output one of the four words without inverted commas:
* «forward» — if Peter could see such sequences only on the way from A to B;
* «backward» — if Peter could see such sequences on the way from B to A;
* «both» — if Peter could see such sequences both on the way from A to B, and on the way from B to A;
* «fantasy» — if Peter could not see such sequences.
Examples
Input
atob
a
b
Output
forward
Input
aaacaaa
aca
aa
Output
both
Note
It is assumed that the train moves all the time, so one flag cannot be seen twice. There are no flags at stations A and B.
Submitted Solution:
```
r = input()
r2 = r[::-1]
a = input()
b = input()
if (a in r) * (b in r):
ai = []; ai2 = []
bi = []; bi2 = []
a = list(a); b = list(b)
forward = 0; backward = 0
for i in range(len(r)):
if forward == 0:
ai.append(r[i])
if len(ai) > len(a): del ai[0]
if ai == a: forward = 1
elif forward == 1:
bi.append(r[i])
if len(bi) > len(b): del bi[0]
if bi == b: forward = 2
if backward == 0:
ai2.append(r2[i])
if len(ai2) > len(a): del ai2[0]
if ai2 == a: backward = 1
elif backward == 1:
bi2.append(r2[i])
if len(bi2) > len(b): del bi2[0]
if bi2 == b: backward = 2
if forward == 2 and backward == 2: print("both")
elif forward == 2: print("forward")
elif backward == 2: print("backward")
else: print("fantasy")
else: print("fantasy")
``` | instruction | 0 | 10,508 | 1 | 21,016 |
No | output | 1 | 10,508 | 1 | 21,017 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Peter likes to travel by train. He likes it so much that on the train he falls asleep.
Once in summer Peter was going by train from city A to city B, and as usual, was sleeping. Then he woke up, started to look through the window and noticed that every railway station has a flag of a particular colour.
The boy started to memorize the order of the flags' colours that he had seen. But soon he fell asleep again. Unfortunately, he didn't sleep long, he woke up and went on memorizing the colours. Then he fell asleep again, and that time he slept till the end of the journey.
At the station he told his parents about what he was doing, and wrote two sequences of the colours that he had seen before and after his sleep, respectively.
Peter's parents know that their son likes to fantasize. They give you the list of the flags' colours at the stations that the train passes sequentially on the way from A to B, and ask you to find out if Peter could see those sequences on the way from A to B, or from B to A. Remember, please, that Peter had two periods of wakefulness.
Peter's parents put lowercase Latin letters for colours. The same letter stands for the same colour, different letters — for different colours.
Input
The input data contains three lines. The first line contains a non-empty string, whose length does not exceed 105, the string consists of lowercase Latin letters — the flags' colours at the stations on the way from A to B. On the way from B to A the train passes the same stations, but in reverse order.
The second line contains the sequence, written by Peter during the first period of wakefulness. The third line contains the sequence, written during the second period of wakefulness. Both sequences are non-empty, consist of lowercase Latin letters, and the length of each does not exceed 100 letters. Each of the sequences is written in chronological order.
Output
Output one of the four words without inverted commas:
* «forward» — if Peter could see such sequences only on the way from A to B;
* «backward» — if Peter could see such sequences on the way from B to A;
* «both» — if Peter could see such sequences both on the way from A to B, and on the way from B to A;
* «fantasy» — if Peter could not see such sequences.
Examples
Input
atob
a
b
Output
forward
Input
aaacaaa
aca
aa
Output
both
Note
It is assumed that the train moves all the time, so one flag cannot be seen twice. There are no flags at stations A and B.
Submitted Solution:
```
s = input()
a = input()
b = input()
l = list(reversed(s))
s1 = "".join(l)
try:
a1 = s.index(a)
b1 = s.index(b)
if a == b :
print("fantasy")
elif s1 == s:
print("both")
elif a1 < b1:
print("forward")
elif b1<a1:
print("backward")
except ValueError:
print("fantasy")
``` | instruction | 0 | 10,509 | 1 | 21,018 |
No | output | 1 | 10,509 | 1 | 21,019 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Peter likes to travel by train. He likes it so much that on the train he falls asleep.
Once in summer Peter was going by train from city A to city B, and as usual, was sleeping. Then he woke up, started to look through the window and noticed that every railway station has a flag of a particular colour.
The boy started to memorize the order of the flags' colours that he had seen. But soon he fell asleep again. Unfortunately, he didn't sleep long, he woke up and went on memorizing the colours. Then he fell asleep again, and that time he slept till the end of the journey.
At the station he told his parents about what he was doing, and wrote two sequences of the colours that he had seen before and after his sleep, respectively.
Peter's parents know that their son likes to fantasize. They give you the list of the flags' colours at the stations that the train passes sequentially on the way from A to B, and ask you to find out if Peter could see those sequences on the way from A to B, or from B to A. Remember, please, that Peter had two periods of wakefulness.
Peter's parents put lowercase Latin letters for colours. The same letter stands for the same colour, different letters — for different colours.
Input
The input data contains three lines. The first line contains a non-empty string, whose length does not exceed 105, the string consists of lowercase Latin letters — the flags' colours at the stations on the way from A to B. On the way from B to A the train passes the same stations, but in reverse order.
The second line contains the sequence, written by Peter during the first period of wakefulness. The third line contains the sequence, written during the second period of wakefulness. Both sequences are non-empty, consist of lowercase Latin letters, and the length of each does not exceed 100 letters. Each of the sequences is written in chronological order.
Output
Output one of the four words without inverted commas:
* «forward» — if Peter could see such sequences only on the way from A to B;
* «backward» — if Peter could see such sequences on the way from B to A;
* «both» — if Peter could see such sequences both on the way from A to B, and on the way from B to A;
* «fantasy» — if Peter could not see such sequences.
Examples
Input
atob
a
b
Output
forward
Input
aaacaaa
aca
aa
Output
both
Note
It is assumed that the train moves all the time, so one flag cannot be seen twice. There are no flags at stations A and B.
Submitted Solution:
```
s = input()
a, b = input(), input()
ind = s.find(a)
first, second = 0, 0
if ind != -1:
ind = s[ind:].find(b)
if ind != -1:
first = 1
s = s[::-1]
ind = s.find(a)
if ind != -1:
ind = s[ind:].find(b)
if ind != -1:
second = 1
if first and second:
print('both')
elif first:
print('forward')
elif second:
print('backward')
else:
print('fantasy')
``` | instruction | 0 | 10,510 | 1 | 21,020 |
No | output | 1 | 10,510 | 1 | 21,021 |
Provide a correct Python 3 solution for this coding contest problem.
RJ Freight, a Japanese railroad company for freight operations has recently constructed exchange lines at Hazawa, Yokohama. The layout of the lines is shown in Figure B-1.
<image>
Figure B-1: Layout of the exchange lines
A freight train consists of 2 to 72 freight cars. There are 26 types of freight cars, which are denoted by 26 lowercase letters from "a" to "z". The cars of the same type are indistinguishable from each other, and each car's direction doesn't matter either. Thus, a string of lowercase letters of length 2 to 72 is sufficient to completely express the configuration of a train.
Upon arrival at the exchange lines, a train is divided into two sub-trains at an arbitrary position (prior to entering the storage lines). Each of the sub-trains may have its direction reversed (using the reversal line). Finally, the two sub-trains are connected in either order to form the final configuration. Note that the reversal operation is optional for each of the sub-trains.
For example, if the arrival configuration is "abcd", the train is split into two sub-trains of either 3:1, 2:2 or 1:3 cars. For each of the splitting, possible final configurations are as follows ("+" indicates final concatenation position):
[3:1]
abc+d cba+d d+abc d+cba
[2:2]
ab+cd ab+dc ba+cd ba+dc cd+ab cd+ba dc+ab dc+ba
[1:3]
a+bcd a+dcb bcd+a dcb+a
Excluding duplicates, 12 distinct configurations are possible.
Given an arrival configuration, answer the number of distinct configurations which can be constructed using the exchange lines described above.
Input
The entire input looks like the following.
> the number of datasets = m
> 1st dataset
> 2nd dataset
> ...
> m-th dataset
>
Each dataset represents an arriving train, and is a string of 2 to 72 lowercase letters in an input line.
Output
For each dataset, output the number of possible train configurations in a line. No other characters should appear in the output.
Example
Input
4
aa
abba
abcd
abcde
Output
1
6
12
18 | instruction | 0 | 10,714 | 1 | 21,428 |
"Correct Solution:
```
#!/usr/bin/env python3
#AOJ B
m = int(input())
for _ in range(m):
s = list(input())
all = []
for i in range(1,len(s)):
front = s[:i]
back = s[i:]
fr = list(reversed(front))
br = list(reversed(back))
pair = [front,fr,back,br]
for j in range(4):
if j > 1:
for k in range(2):
p = pair[j] + pair[k]
if p not in all:
all.append(p)
else:
for k in range(2,4):
p = pair[j] + pair[k]
if p not in all:
all.append(p)
if len(all) == 0:
print(1)
else:
print(len(all))
``` | output | 1 | 10,714 | 1 | 21,429 |
Provide a correct Python 3 solution for this coding contest problem.
RJ Freight, a Japanese railroad company for freight operations has recently constructed exchange lines at Hazawa, Yokohama. The layout of the lines is shown in Figure B-1.
<image>
Figure B-1: Layout of the exchange lines
A freight train consists of 2 to 72 freight cars. There are 26 types of freight cars, which are denoted by 26 lowercase letters from "a" to "z". The cars of the same type are indistinguishable from each other, and each car's direction doesn't matter either. Thus, a string of lowercase letters of length 2 to 72 is sufficient to completely express the configuration of a train.
Upon arrival at the exchange lines, a train is divided into two sub-trains at an arbitrary position (prior to entering the storage lines). Each of the sub-trains may have its direction reversed (using the reversal line). Finally, the two sub-trains are connected in either order to form the final configuration. Note that the reversal operation is optional for each of the sub-trains.
For example, if the arrival configuration is "abcd", the train is split into two sub-trains of either 3:1, 2:2 or 1:3 cars. For each of the splitting, possible final configurations are as follows ("+" indicates final concatenation position):
[3:1]
abc+d cba+d d+abc d+cba
[2:2]
ab+cd ab+dc ba+cd ba+dc cd+ab cd+ba dc+ab dc+ba
[1:3]
a+bcd a+dcb bcd+a dcb+a
Excluding duplicates, 12 distinct configurations are possible.
Given an arrival configuration, answer the number of distinct configurations which can be constructed using the exchange lines described above.
Input
The entire input looks like the following.
> the number of datasets = m
> 1st dataset
> 2nd dataset
> ...
> m-th dataset
>
Each dataset represents an arriving train, and is a string of 2 to 72 lowercase letters in an input line.
Output
For each dataset, output the number of possible train configurations in a line. No other characters should appear in the output.
Example
Input
4
aa
abba
abcd
abcde
Output
1
6
12
18 | instruction | 0 | 10,715 | 1 | 21,430 |
"Correct Solution:
```
# coding: utf-8
for i in range(int(input())):
data = input()
d_set = set()
for i in range(len(data)-1):
str1 = data[ 0 : i+1 ]
str2 = data[ i+1 : len(data) ]
d_set.add(str1+str2)
d_set.add(str1+str2[::-1])
d_set.add(str1[::-1]+str2)
d_set.add(str1[::-1]+str2[::-1])
d_set.add(str2+str1)
d_set.add(str2+str1[::-1])
d_set.add(str2[::-1]+str1)
d_set.add(str2[::-1]+str1[::-1])
print(len(d_set))
``` | output | 1 | 10,715 | 1 | 21,431 |
Provide a correct Python 3 solution for this coding contest problem.
RJ Freight, a Japanese railroad company for freight operations has recently constructed exchange lines at Hazawa, Yokohama. The layout of the lines is shown in Figure B-1.
<image>
Figure B-1: Layout of the exchange lines
A freight train consists of 2 to 72 freight cars. There are 26 types of freight cars, which are denoted by 26 lowercase letters from "a" to "z". The cars of the same type are indistinguishable from each other, and each car's direction doesn't matter either. Thus, a string of lowercase letters of length 2 to 72 is sufficient to completely express the configuration of a train.
Upon arrival at the exchange lines, a train is divided into two sub-trains at an arbitrary position (prior to entering the storage lines). Each of the sub-trains may have its direction reversed (using the reversal line). Finally, the two sub-trains are connected in either order to form the final configuration. Note that the reversal operation is optional for each of the sub-trains.
For example, if the arrival configuration is "abcd", the train is split into two sub-trains of either 3:1, 2:2 or 1:3 cars. For each of the splitting, possible final configurations are as follows ("+" indicates final concatenation position):
[3:1]
abc+d cba+d d+abc d+cba
[2:2]
ab+cd ab+dc ba+cd ba+dc cd+ab cd+ba dc+ab dc+ba
[1:3]
a+bcd a+dcb bcd+a dcb+a
Excluding duplicates, 12 distinct configurations are possible.
Given an arrival configuration, answer the number of distinct configurations which can be constructed using the exchange lines described above.
Input
The entire input looks like the following.
> the number of datasets = m
> 1st dataset
> 2nd dataset
> ...
> m-th dataset
>
Each dataset represents an arriving train, and is a string of 2 to 72 lowercase letters in an input line.
Output
For each dataset, output the number of possible train configurations in a line. No other characters should appear in the output.
Example
Input
4
aa
abba
abcd
abcde
Output
1
6
12
18 | instruction | 0 | 10,716 | 1 | 21,432 |
"Correct Solution:
```
m = int(input())
for i in range(m):
d = input()
trains = [d]
for j in range(1, len(d)):
f, b = d[:j], d[j:]
rf, rb = f[::-1], b[::-1]
trains.extend([rf+b, f+rb, rf+rb, b+f, rb+f, b+rf, rb+rf])
print(len(set(trains)))
``` | output | 1 | 10,716 | 1 | 21,433 |
Provide a correct Python 3 solution for this coding contest problem.
RJ Freight, a Japanese railroad company for freight operations has recently constructed exchange lines at Hazawa, Yokohama. The layout of the lines is shown in Figure B-1.
<image>
Figure B-1: Layout of the exchange lines
A freight train consists of 2 to 72 freight cars. There are 26 types of freight cars, which are denoted by 26 lowercase letters from "a" to "z". The cars of the same type are indistinguishable from each other, and each car's direction doesn't matter either. Thus, a string of lowercase letters of length 2 to 72 is sufficient to completely express the configuration of a train.
Upon arrival at the exchange lines, a train is divided into two sub-trains at an arbitrary position (prior to entering the storage lines). Each of the sub-trains may have its direction reversed (using the reversal line). Finally, the two sub-trains are connected in either order to form the final configuration. Note that the reversal operation is optional for each of the sub-trains.
For example, if the arrival configuration is "abcd", the train is split into two sub-trains of either 3:1, 2:2 or 1:3 cars. For each of the splitting, possible final configurations are as follows ("+" indicates final concatenation position):
[3:1]
abc+d cba+d d+abc d+cba
[2:2]
ab+cd ab+dc ba+cd ba+dc cd+ab cd+ba dc+ab dc+ba
[1:3]
a+bcd a+dcb bcd+a dcb+a
Excluding duplicates, 12 distinct configurations are possible.
Given an arrival configuration, answer the number of distinct configurations which can be constructed using the exchange lines described above.
Input
The entire input looks like the following.
> the number of datasets = m
> 1st dataset
> 2nd dataset
> ...
> m-th dataset
>
Each dataset represents an arriving train, and is a string of 2 to 72 lowercase letters in an input line.
Output
For each dataset, output the number of possible train configurations in a line. No other characters should appear in the output.
Example
Input
4
aa
abba
abcd
abcde
Output
1
6
12
18 | instruction | 0 | 10,717 | 1 | 21,434 |
"Correct Solution:
```
#!/usr/bin/env python3
m = int(input())
for _ in range(m):
s = input()
ans = set()
for i in range(1, len(s)):
for j in range(4):
ans.add(s[:i][::[-1, 1][j // 2]] + s[i:][::[-1, 1][j % 2]])
ans.add(s[i:][::[-1, 1][j // 2]] + s[:i][::[-1, 1][j % 2]])
print(len(ans))
``` | output | 1 | 10,717 | 1 | 21,435 |
Provide a correct Python 3 solution for this coding contest problem.
RJ Freight, a Japanese railroad company for freight operations has recently constructed exchange lines at Hazawa, Yokohama. The layout of the lines is shown in Figure B-1.
<image>
Figure B-1: Layout of the exchange lines
A freight train consists of 2 to 72 freight cars. There are 26 types of freight cars, which are denoted by 26 lowercase letters from "a" to "z". The cars of the same type are indistinguishable from each other, and each car's direction doesn't matter either. Thus, a string of lowercase letters of length 2 to 72 is sufficient to completely express the configuration of a train.
Upon arrival at the exchange lines, a train is divided into two sub-trains at an arbitrary position (prior to entering the storage lines). Each of the sub-trains may have its direction reversed (using the reversal line). Finally, the two sub-trains are connected in either order to form the final configuration. Note that the reversal operation is optional for each of the sub-trains.
For example, if the arrival configuration is "abcd", the train is split into two sub-trains of either 3:1, 2:2 or 1:3 cars. For each of the splitting, possible final configurations are as follows ("+" indicates final concatenation position):
[3:1]
abc+d cba+d d+abc d+cba
[2:2]
ab+cd ab+dc ba+cd ba+dc cd+ab cd+ba dc+ab dc+ba
[1:3]
a+bcd a+dcb bcd+a dcb+a
Excluding duplicates, 12 distinct configurations are possible.
Given an arrival configuration, answer the number of distinct configurations which can be constructed using the exchange lines described above.
Input
The entire input looks like the following.
> the number of datasets = m
> 1st dataset
> 2nd dataset
> ...
> m-th dataset
>
Each dataset represents an arriving train, and is a string of 2 to 72 lowercase letters in an input line.
Output
For each dataset, output the number of possible train configurations in a line. No other characters should appear in the output.
Example
Input
4
aa
abba
abcd
abcde
Output
1
6
12
18 | instruction | 0 | 10,718 | 1 | 21,436 |
"Correct Solution:
```
#!/usr/bin/env python
# -*- coding: utf-8 -*-
from itertools import product
m = int(input())
for i in range(m):
train = list(input())
train_set = set()
for j in range(0,len(train)):
A = ''.join(train[:j+1])
B = ''.join(train[j+1:])
invA = ''.join(reversed(train[:j+1]))
invB = ''.join(reversed(train[j+1:]))
for t in product((A,invA),(B,invB)):
train_set.add(''.join(t))
for t in product((B,invB),(A,invA)):
train_set.add(''.join(t))
print(len(train_set))
``` | output | 1 | 10,718 | 1 | 21,437 |
Provide a correct Python 3 solution for this coding contest problem.
RJ Freight, a Japanese railroad company for freight operations has recently constructed exchange lines at Hazawa, Yokohama. The layout of the lines is shown in Figure B-1.
<image>
Figure B-1: Layout of the exchange lines
A freight train consists of 2 to 72 freight cars. There are 26 types of freight cars, which are denoted by 26 lowercase letters from "a" to "z". The cars of the same type are indistinguishable from each other, and each car's direction doesn't matter either. Thus, a string of lowercase letters of length 2 to 72 is sufficient to completely express the configuration of a train.
Upon arrival at the exchange lines, a train is divided into two sub-trains at an arbitrary position (prior to entering the storage lines). Each of the sub-trains may have its direction reversed (using the reversal line). Finally, the two sub-trains are connected in either order to form the final configuration. Note that the reversal operation is optional for each of the sub-trains.
For example, if the arrival configuration is "abcd", the train is split into two sub-trains of either 3:1, 2:2 or 1:3 cars. For each of the splitting, possible final configurations are as follows ("+" indicates final concatenation position):
[3:1]
abc+d cba+d d+abc d+cba
[2:2]
ab+cd ab+dc ba+cd ba+dc cd+ab cd+ba dc+ab dc+ba
[1:3]
a+bcd a+dcb bcd+a dcb+a
Excluding duplicates, 12 distinct configurations are possible.
Given an arrival configuration, answer the number of distinct configurations which can be constructed using the exchange lines described above.
Input
The entire input looks like the following.
> the number of datasets = m
> 1st dataset
> 2nd dataset
> ...
> m-th dataset
>
Each dataset represents an arriving train, and is a string of 2 to 72 lowercase letters in an input line.
Output
For each dataset, output the number of possible train configurations in a line. No other characters should appear in the output.
Example
Input
4
aa
abba
abcd
abcde
Output
1
6
12
18 | instruction | 0 | 10,719 | 1 | 21,438 |
"Correct Solution:
```
def main_a():
y, m, d = map(int, input().split())
a = (y - 1) // 3
b = (y - 1) % 3
c = a * 590 + 195 * b
if y % 3:
a = (m - 1) // 2
b = (m - 1) % 2
c += a * 39 + b * 20
else:
c += (m - 1) * 20
c += d - 1
print(196470 - c)
def a():
n = int(input())
for i in range(n):
main_a()
def main_b():
s = input()
ans = []
for i in range(1,len(s)):
ans.append(s[:i] + s[i:])
ans.append(s[i-1::-1] + s[i:])
ans.append(s[i-1::-1] + s[len(s):i-1:-1])
ans.append(s[:i] + s[len(s):i - 1:-1])
ans.append(s[i:] + s[:i])
ans.append(s[i:] + s[i - 1::-1])
ans.append(s[len(s):i - 1:-1] + s[i - 1::-1])
ans.append(s[len(s):i - 1:-1] + s[:i])
print(len(set(ans)))
def b():
n = int(input())
for i in range(n):
main_b()
b()
``` | output | 1 | 10,719 | 1 | 21,439 |
Provide a correct Python 3 solution for this coding contest problem.
RJ Freight, a Japanese railroad company for freight operations has recently constructed exchange lines at Hazawa, Yokohama. The layout of the lines is shown in Figure B-1.
<image>
Figure B-1: Layout of the exchange lines
A freight train consists of 2 to 72 freight cars. There are 26 types of freight cars, which are denoted by 26 lowercase letters from "a" to "z". The cars of the same type are indistinguishable from each other, and each car's direction doesn't matter either. Thus, a string of lowercase letters of length 2 to 72 is sufficient to completely express the configuration of a train.
Upon arrival at the exchange lines, a train is divided into two sub-trains at an arbitrary position (prior to entering the storage lines). Each of the sub-trains may have its direction reversed (using the reversal line). Finally, the two sub-trains are connected in either order to form the final configuration. Note that the reversal operation is optional for each of the sub-trains.
For example, if the arrival configuration is "abcd", the train is split into two sub-trains of either 3:1, 2:2 or 1:3 cars. For each of the splitting, possible final configurations are as follows ("+" indicates final concatenation position):
[3:1]
abc+d cba+d d+abc d+cba
[2:2]
ab+cd ab+dc ba+cd ba+dc cd+ab cd+ba dc+ab dc+ba
[1:3]
a+bcd a+dcb bcd+a dcb+a
Excluding duplicates, 12 distinct configurations are possible.
Given an arrival configuration, answer the number of distinct configurations which can be constructed using the exchange lines described above.
Input
The entire input looks like the following.
> the number of datasets = m
> 1st dataset
> 2nd dataset
> ...
> m-th dataset
>
Each dataset represents an arriving train, and is a string of 2 to 72 lowercase letters in an input line.
Output
For each dataset, output the number of possible train configurations in a line. No other characters should appear in the output.
Example
Input
4
aa
abba
abcd
abcde
Output
1
6
12
18 | instruction | 0 | 10,720 | 1 | 21,440 |
"Correct Solution:
```
import sys
sys.setrecursionlimit(10000000)
MOD = 10 ** 9 + 7
INF = 10 ** 15
def solve(S):
before = set()
for i in range(1,len(S)):
a,b = S[:i],S[i:]
ab = (a,a[::-1])
cd = (b,b[::-1])
for j in range(2):
for k in range(2):
before.add(ab[j] + cd[k])
before.add(cd[k] + ab[j])
print(len(before))
def main():
M = int(input())
for _ in range(M):
S = input()
solve(S)
if __name__ == '__main__':
main()
``` | output | 1 | 10,720 | 1 | 21,441 |
Provide a correct Python 3 solution for this coding contest problem.
RJ Freight, a Japanese railroad company for freight operations has recently constructed exchange lines at Hazawa, Yokohama. The layout of the lines is shown in Figure B-1.
<image>
Figure B-1: Layout of the exchange lines
A freight train consists of 2 to 72 freight cars. There are 26 types of freight cars, which are denoted by 26 lowercase letters from "a" to "z". The cars of the same type are indistinguishable from each other, and each car's direction doesn't matter either. Thus, a string of lowercase letters of length 2 to 72 is sufficient to completely express the configuration of a train.
Upon arrival at the exchange lines, a train is divided into two sub-trains at an arbitrary position (prior to entering the storage lines). Each of the sub-trains may have its direction reversed (using the reversal line). Finally, the two sub-trains are connected in either order to form the final configuration. Note that the reversal operation is optional for each of the sub-trains.
For example, if the arrival configuration is "abcd", the train is split into two sub-trains of either 3:1, 2:2 or 1:3 cars. For each of the splitting, possible final configurations are as follows ("+" indicates final concatenation position):
[3:1]
abc+d cba+d d+abc d+cba
[2:2]
ab+cd ab+dc ba+cd ba+dc cd+ab cd+ba dc+ab dc+ba
[1:3]
a+bcd a+dcb bcd+a dcb+a
Excluding duplicates, 12 distinct configurations are possible.
Given an arrival configuration, answer the number of distinct configurations which can be constructed using the exchange lines described above.
Input
The entire input looks like the following.
> the number of datasets = m
> 1st dataset
> 2nd dataset
> ...
> m-th dataset
>
Each dataset represents an arriving train, and is a string of 2 to 72 lowercase letters in an input line.
Output
For each dataset, output the number of possible train configurations in a line. No other characters should appear in the output.
Example
Input
4
aa
abba
abcd
abcde
Output
1
6
12
18 | instruction | 0 | 10,721 | 1 | 21,442 |
"Correct Solution:
```
#頭から分ける場合とけつから分ける場合を考えよう
"""メモ
1142
なんかあってそう
漏れがある
#######################################
blkA_train = arr_train[0:3]
blkB_train = arr_train[3:4]
abcd
4
4
abc
d
all_list = ['abcd', 'cbad', 'dabc', 'dabc'] setなし
######################################
blkA_train = arr_train[0:2]
blkB_train = arr_train[2:5]
abcd
4
4
ab
cd
alllist = ['abcd', 'bacd', 'cdab', 'dcab'] setなし
#####################################
blkA_train = arr_train[0:1]
blkB_train = arr_train[1:4]
abcd
4
4
a
bcd
['abcd', 'abcd', 'bcda', 'dcba'] setなし
######################################
"""
arr_train = []
m = input() #kは繰り返す回数
m = int(m)
while(True):
if m == 0:
break
x = input()
arr_train = str(x)
#arr_train.append(x) #多分appendする必要ない
counter = 0
"""
print(len(x)) #len(x) - 1 = n-1 みたいな感じでループ
print(len(arr_train))
"""
#blkA_train = [] #最初の分割 これを真ん中のindexの要素を中心に反転しようかな
#blkB_train = [] #分割されたもの あとで反転したリストと連結
all_list = []
#文字分割にはリストは必要ない。多分str変数を用意しておいて、ループごとに初期化する。処理終了、連結したstrをリストに保存
#リストは多分1つだけでよく最後にset+lenで数え上げ
#blkA_train = None
#blkB_train = None
#right = 0 #列車の分割の右分け数
#left = 0 #列車の分割の左分け数
left = len(arr_train) -1 # まず n-1
right = 1 #まず1
"""
blkA_train = arr_train[0:3] #スライスで文字列を指定 このindexを一般化 i j len 左スライスは0で良い 右スライスはleftでいいんじゃない?
blkB_train = arr_train[3:4] #右スライスは増加していく ループ変数を使え
"""
"""
blkA_train = arr_train[0:2]
blkB_train = arr_train[2:5]
"""
"""
blkA_train = arr_train[0:1]
blkB_train = arr_train[1:4]
"""
#反転するものとそうでないもので1ループごとに2つの文字列をリストにappend
"""
#頭が反転の場合
all_list.append(blkA_train+blkB_train) #そのまま連結
all_list.append(blkA_train[::-1]+blkB_train) #反転して連結 ok
#けつが反転の場合
all_list.append(blkB_train+blkA_train)
all_list.append(blkB_train[::-1]+blkA_train)
#頭、けつが反転する 頭から連結
all_list.append(blkA_train[::-1]+blkB_train[::-1])
all_list.append(blkB_train[::-1]+blkA_train[::-1])
all_list.append(blkA_train+blkB_train[::-1])
all_list.append(blkB_train+blkA_train[::-1])
"""
while(True):
blkA_train = None
blkB_train = None
blkA_train = arr_train[0:left]
blkB_train = arr_train[left:len(arr_train)-1+left]
all_list.append(blkA_train+blkB_train) #そのまま連結
all_list.append(blkA_train[::-1]+blkB_train) #反転して連結 ok
all_list.append(blkB_train+blkA_train)
all_list.append(blkB_train[::-1]+blkA_train)
all_list.append(blkA_train[::-1]+blkB_train[::-1])
all_list.append(blkB_train[::-1]+blkA_train[::-1])
all_list.append(blkA_train+blkB_train[::-1])
all_list.append(blkB_train+blkA_train[::-1])
if left == 1: #左分割フラグが1になったら終了
break
left -= 1
#right += 1
all_list = set(all_list)
all_list = list(all_list)
print(len(all_list))
m -=1
"""
print(blkA_train)
print(blkB_train)
"""
"""
print()
print(all_list)
all_list = set(all_list)
all_list = list(all_list)
print(all_list)
print(len(all_list))
"""
"""
print(blkA_train)
print(blkB_train)
print()
print(all_list)
print()
all_list = set(all_list)
all_list = list(all_list)
print(all_list)
"""
``` | output | 1 | 10,721 | 1 | 21,443 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
RJ Freight, a Japanese railroad company for freight operations has recently constructed exchange lines at Hazawa, Yokohama. The layout of the lines is shown in Figure B-1.
<image>
Figure B-1: Layout of the exchange lines
A freight train consists of 2 to 72 freight cars. There are 26 types of freight cars, which are denoted by 26 lowercase letters from "a" to "z". The cars of the same type are indistinguishable from each other, and each car's direction doesn't matter either. Thus, a string of lowercase letters of length 2 to 72 is sufficient to completely express the configuration of a train.
Upon arrival at the exchange lines, a train is divided into two sub-trains at an arbitrary position (prior to entering the storage lines). Each of the sub-trains may have its direction reversed (using the reversal line). Finally, the two sub-trains are connected in either order to form the final configuration. Note that the reversal operation is optional for each of the sub-trains.
For example, if the arrival configuration is "abcd", the train is split into two sub-trains of either 3:1, 2:2 or 1:3 cars. For each of the splitting, possible final configurations are as follows ("+" indicates final concatenation position):
[3:1]
abc+d cba+d d+abc d+cba
[2:2]
ab+cd ab+dc ba+cd ba+dc cd+ab cd+ba dc+ab dc+ba
[1:3]
a+bcd a+dcb bcd+a dcb+a
Excluding duplicates, 12 distinct configurations are possible.
Given an arrival configuration, answer the number of distinct configurations which can be constructed using the exchange lines described above.
Input
The entire input looks like the following.
> the number of datasets = m
> 1st dataset
> 2nd dataset
> ...
> m-th dataset
>
Each dataset represents an arriving train, and is a string of 2 to 72 lowercase letters in an input line.
Output
For each dataset, output the number of possible train configurations in a line. No other characters should appear in the output.
Example
Input
4
aa
abba
abcd
abcde
Output
1
6
12
18
Submitted Solution:
```
n = int(input())
for i in range(n):
s = input()
ss = set()
for i in range(len(s)-1):
s1 = s[0:i+1]
s2 = s[i+1:]
ss.add(s1+s2)
ss.add(s1+s2[::-1])
ss.add(s1[::-1]+s2)
ss.add(s1[::-1]+s2[::-1])
ss.add(s2+s1)
ss.add(s2+s1[::-1])
ss.add(s2[::-1]+s1)
ss.add(s2[::-1]+s1[::-1])
print(len(ss))
``` | instruction | 0 | 10,722 | 1 | 21,444 |
Yes | output | 1 | 10,722 | 1 | 21,445 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
RJ Freight, a Japanese railroad company for freight operations has recently constructed exchange lines at Hazawa, Yokohama. The layout of the lines is shown in Figure B-1.
<image>
Figure B-1: Layout of the exchange lines
A freight train consists of 2 to 72 freight cars. There are 26 types of freight cars, which are denoted by 26 lowercase letters from "a" to "z". The cars of the same type are indistinguishable from each other, and each car's direction doesn't matter either. Thus, a string of lowercase letters of length 2 to 72 is sufficient to completely express the configuration of a train.
Upon arrival at the exchange lines, a train is divided into two sub-trains at an arbitrary position (prior to entering the storage lines). Each of the sub-trains may have its direction reversed (using the reversal line). Finally, the two sub-trains are connected in either order to form the final configuration. Note that the reversal operation is optional for each of the sub-trains.
For example, if the arrival configuration is "abcd", the train is split into two sub-trains of either 3:1, 2:2 or 1:3 cars. For each of the splitting, possible final configurations are as follows ("+" indicates final concatenation position):
[3:1]
abc+d cba+d d+abc d+cba
[2:2]
ab+cd ab+dc ba+cd ba+dc cd+ab cd+ba dc+ab dc+ba
[1:3]
a+bcd a+dcb bcd+a dcb+a
Excluding duplicates, 12 distinct configurations are possible.
Given an arrival configuration, answer the number of distinct configurations which can be constructed using the exchange lines described above.
Input
The entire input looks like the following.
> the number of datasets = m
> 1st dataset
> 2nd dataset
> ...
> m-th dataset
>
Each dataset represents an arriving train, and is a string of 2 to 72 lowercase letters in an input line.
Output
For each dataset, output the number of possible train configurations in a line. No other characters should appear in the output.
Example
Input
4
aa
abba
abcd
abcde
Output
1
6
12
18
Submitted Solution:
```
m=int(input())
for i in range(m):
s=input()
ptn=set()
ptn.add(s)
for j in range(len(s)):
l=s[:j]
r=s[j:]
l_r=l[::-1]
r_r=r[::-1]
ptn.add(l+r_r)
ptn.add(l_r+r)
ptn.add(l_r+r_r)
ptn.add(r+l)
ptn.add(r+l_r)
ptn.add(r_r+l)
ptn.add(r_r+l_r)
print(len(ptn))
``` | instruction | 0 | 10,723 | 1 | 21,446 |
Yes | output | 1 | 10,723 | 1 | 21,447 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
RJ Freight, a Japanese railroad company for freight operations has recently constructed exchange lines at Hazawa, Yokohama. The layout of the lines is shown in Figure B-1.
<image>
Figure B-1: Layout of the exchange lines
A freight train consists of 2 to 72 freight cars. There are 26 types of freight cars, which are denoted by 26 lowercase letters from "a" to "z". The cars of the same type are indistinguishable from each other, and each car's direction doesn't matter either. Thus, a string of lowercase letters of length 2 to 72 is sufficient to completely express the configuration of a train.
Upon arrival at the exchange lines, a train is divided into two sub-trains at an arbitrary position (prior to entering the storage lines). Each of the sub-trains may have its direction reversed (using the reversal line). Finally, the two sub-trains are connected in either order to form the final configuration. Note that the reversal operation is optional for each of the sub-trains.
For example, if the arrival configuration is "abcd", the train is split into two sub-trains of either 3:1, 2:2 or 1:3 cars. For each of the splitting, possible final configurations are as follows ("+" indicates final concatenation position):
[3:1]
abc+d cba+d d+abc d+cba
[2:2]
ab+cd ab+dc ba+cd ba+dc cd+ab cd+ba dc+ab dc+ba
[1:3]
a+bcd a+dcb bcd+a dcb+a
Excluding duplicates, 12 distinct configurations are possible.
Given an arrival configuration, answer the number of distinct configurations which can be constructed using the exchange lines described above.
Input
The entire input looks like the following.
> the number of datasets = m
> 1st dataset
> 2nd dataset
> ...
> m-th dataset
>
Each dataset represents an arriving train, and is a string of 2 to 72 lowercase letters in an input line.
Output
For each dataset, output the number of possible train configurations in a line. No other characters should appear in the output.
Example
Input
4
aa
abba
abcd
abcde
Output
1
6
12
18
Submitted Solution:
```
m = int(input())
for i in range(m):
s = list(input())
kouho = []
for i in range(1, len(s)):
this1 = s[:i]
this2 = s[i:]
kouho.append([this1 + this2])
kouho.append([this1[::-1] + this2])
kouho.append([this1[::-1] + this2[::-1]])
kouho.append([this1 + this2[::-1]])
kouho.append([this2 + this1])
kouho.append([this2[::-1] + this1])
kouho.append([this2[::-1] + this1[::-1]])
kouho.append([this2 + this1[::-1]])
kouho.sort()
#print(len(kouho))
cnt = 0
i = 1
while i < len(kouho):
if kouho[i] == kouho[i - 1]:
del kouho[i]
i -= 1
i += 1
print(len(kouho))
``` | instruction | 0 | 10,724 | 1 | 21,448 |
Yes | output | 1 | 10,724 | 1 | 21,449 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
RJ Freight, a Japanese railroad company for freight operations has recently constructed exchange lines at Hazawa, Yokohama. The layout of the lines is shown in Figure B-1.
<image>
Figure B-1: Layout of the exchange lines
A freight train consists of 2 to 72 freight cars. There are 26 types of freight cars, which are denoted by 26 lowercase letters from "a" to "z". The cars of the same type are indistinguishable from each other, and each car's direction doesn't matter either. Thus, a string of lowercase letters of length 2 to 72 is sufficient to completely express the configuration of a train.
Upon arrival at the exchange lines, a train is divided into two sub-trains at an arbitrary position (prior to entering the storage lines). Each of the sub-trains may have its direction reversed (using the reversal line). Finally, the two sub-trains are connected in either order to form the final configuration. Note that the reversal operation is optional for each of the sub-trains.
For example, if the arrival configuration is "abcd", the train is split into two sub-trains of either 3:1, 2:2 or 1:3 cars. For each of the splitting, possible final configurations are as follows ("+" indicates final concatenation position):
[3:1]
abc+d cba+d d+abc d+cba
[2:2]
ab+cd ab+dc ba+cd ba+dc cd+ab cd+ba dc+ab dc+ba
[1:3]
a+bcd a+dcb bcd+a dcb+a
Excluding duplicates, 12 distinct configurations are possible.
Given an arrival configuration, answer the number of distinct configurations which can be constructed using the exchange lines described above.
Input
The entire input looks like the following.
> the number of datasets = m
> 1st dataset
> 2nd dataset
> ...
> m-th dataset
>
Each dataset represents an arriving train, and is a string of 2 to 72 lowercase letters in an input line.
Output
For each dataset, output the number of possible train configurations in a line. No other characters should appear in the output.
Example
Input
4
aa
abba
abcd
abcde
Output
1
6
12
18
Submitted Solution:
```
import itertools
def main():
n = int(input())
for _ in range(n):
s = input()
ssum = set()
for i in range(len(s)):
l = s[:i]
rl = l[::-1]
r = s[i:]
rr = r[::-1]
ssum.add(l+r)
ssum.add(r+l)
ssum.add(rl+r)
ssum.add(r+rl)
ssum.add(l+rr)
ssum.add(rr+l)
ssum.add(rl+rr)
ssum.add(rr+rl)
print(len(ssum))
if __name__ == '__main__':
main()
``` | instruction | 0 | 10,725 | 1 | 21,450 |
Yes | output | 1 | 10,725 | 1 | 21,451 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
RJ Freight, a Japanese railroad company for freight operations has recently constructed exchange lines at Hazawa, Yokohama. The layout of the lines is shown in Figure B-1.
<image>
Figure B-1: Layout of the exchange lines
A freight train consists of 2 to 72 freight cars. There are 26 types of freight cars, which are denoted by 26 lowercase letters from "a" to "z". The cars of the same type are indistinguishable from each other, and each car's direction doesn't matter either. Thus, a string of lowercase letters of length 2 to 72 is sufficient to completely express the configuration of a train.
Upon arrival at the exchange lines, a train is divided into two sub-trains at an arbitrary position (prior to entering the storage lines). Each of the sub-trains may have its direction reversed (using the reversal line). Finally, the two sub-trains are connected in either order to form the final configuration. Note that the reversal operation is optional for each of the sub-trains.
For example, if the arrival configuration is "abcd", the train is split into two sub-trains of either 3:1, 2:2 or 1:3 cars. For each of the splitting, possible final configurations are as follows ("+" indicates final concatenation position):
[3:1]
abc+d cba+d d+abc d+cba
[2:2]
ab+cd ab+dc ba+cd ba+dc cd+ab cd+ba dc+ab dc+ba
[1:3]
a+bcd a+dcb bcd+a dcb+a
Excluding duplicates, 12 distinct configurations are possible.
Given an arrival configuration, answer the number of distinct configurations which can be constructed using the exchange lines described above.
Input
The entire input looks like the following.
> the number of datasets = m
> 1st dataset
> 2nd dataset
> ...
> m-th dataset
>
Each dataset represents an arriving train, and is a string of 2 to 72 lowercase letters in an input line.
Output
For each dataset, output the number of possible train configurations in a line. No other characters should appear in the output.
Example
Input
4
aa
abba
abcd
abcde
Output
1
6
12
18
Submitted Solution:
```
ls = []
def add(t):
if t not in ls:
ls.append(t)
n = int(input())
for i in range(n):
t = input()[:-1]
ls = [t]
for j in range(1,len(t)):
f, b = t[:j], t[j:]
add(f+b[::-1])
add(f[::-1]+b)
add(f[::-1]+b[::-1])
add(b+f)
add(b+f[::-1])
add(b[::-1]+f)
add(b[::-1]+f[::-1])
print(len(ls))
``` | instruction | 0 | 10,726 | 1 | 21,452 |
No | output | 1 | 10,726 | 1 | 21,453 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
RJ Freight, a Japanese railroad company for freight operations has recently constructed exchange lines at Hazawa, Yokohama. The layout of the lines is shown in Figure B-1.
<image>
Figure B-1: Layout of the exchange lines
A freight train consists of 2 to 72 freight cars. There are 26 types of freight cars, which are denoted by 26 lowercase letters from "a" to "z". The cars of the same type are indistinguishable from each other, and each car's direction doesn't matter either. Thus, a string of lowercase letters of length 2 to 72 is sufficient to completely express the configuration of a train.
Upon arrival at the exchange lines, a train is divided into two sub-trains at an arbitrary position (prior to entering the storage lines). Each of the sub-trains may have its direction reversed (using the reversal line). Finally, the two sub-trains are connected in either order to form the final configuration. Note that the reversal operation is optional for each of the sub-trains.
For example, if the arrival configuration is "abcd", the train is split into two sub-trains of either 3:1, 2:2 or 1:3 cars. For each of the splitting, possible final configurations are as follows ("+" indicates final concatenation position):
[3:1]
abc+d cba+d d+abc d+cba
[2:2]
ab+cd ab+dc ba+cd ba+dc cd+ab cd+ba dc+ab dc+ba
[1:3]
a+bcd a+dcb bcd+a dcb+a
Excluding duplicates, 12 distinct configurations are possible.
Given an arrival configuration, answer the number of distinct configurations which can be constructed using the exchange lines described above.
Input
The entire input looks like the following.
> the number of datasets = m
> 1st dataset
> 2nd dataset
> ...
> m-th dataset
>
Each dataset represents an arriving train, and is a string of 2 to 72 lowercase letters in an input line.
Output
For each dataset, output the number of possible train configurations in a line. No other characters should appear in the output.
Example
Input
4
aa
abba
abcd
abcde
Output
1
6
12
18
Submitted Solution:
```
m = int(input())
for i in range(4):
d = input()
trains = [d]
for j in range(1, len(d)):
trains.extend([d[:j][::-1] + d[j:], d[:j] + d[j:][::-1], d[:j][::-1] + d[j:][::-1], d[j:] + d[:j], d[j:][::-1] + d[:j], d[j:] + d[:j][::-1], d[j:][::-1] + d[:j][::-1]])
print(len(set(trains)))
``` | instruction | 0 | 10,727 | 1 | 21,454 |
No | output | 1 | 10,727 | 1 | 21,455 |
Provide a correct Python 3 solution for this coding contest problem.
In Manhattan, roads run where the x or y coordinate is an integer. Both Sunuke-kun's house and Sumeke-kun's house are on the road, and the straight line distance (Euclidean distance) is just d. Find the maximum value that can be considered as the shortest distance when traveling along the road from Sunuke-kun's house to Sumek-kun's house.
Constraints
* 0 <d ≤ 10
* d is given up to exactly three decimal places
Input
d
Output
Print the answer on one line. If the absolute error or relative error is 10-9 or less, the answer is judged to be correct.
Examples
Input
1.000
Output
2.000000000000
Input
2.345
Output
3.316330803765 | instruction | 0 | 10,747 | 1 | 21,494 |
"Correct Solution:
```
n=float(input())
print(n//1+1 if n*2**0.5<n//1+1 else n*2**0.5)
``` | output | 1 | 10,747 | 1 | 21,495 |
Provide a correct Python 3 solution for this coding contest problem.
In Manhattan, roads run where the x or y coordinate is an integer. Both Sunuke-kun's house and Sumeke-kun's house are on the road, and the straight line distance (Euclidean distance) is just d. Find the maximum value that can be considered as the shortest distance when traveling along the road from Sunuke-kun's house to Sumek-kun's house.
Constraints
* 0 <d ≤ 10
* d is given up to exactly three decimal places
Input
d
Output
Print the answer on one line. If the absolute error or relative error is 10-9 or less, the answer is judged to be correct.
Examples
Input
1.000
Output
2.000000000000
Input
2.345
Output
3.316330803765 | instruction | 0 | 10,748 | 1 | 21,496 |
"Correct Solution:
```
d = float(input())
ans = d * pow(2, 0.5)
for i in range(1, 11):
if i <= d <= pow(1 + i ** 2, 0.5):
ans = max(ans, i + 1)
print("{:.020f}".format(ans))
``` | output | 1 | 10,748 | 1 | 21,497 |
Provide a correct Python 3 solution for this coding contest problem.
In Manhattan, roads run where the x or y coordinate is an integer. Both Sunuke-kun's house and Sumeke-kun's house are on the road, and the straight line distance (Euclidean distance) is just d. Find the maximum value that can be considered as the shortest distance when traveling along the road from Sunuke-kun's house to Sumek-kun's house.
Constraints
* 0 <d ≤ 10
* d is given up to exactly three decimal places
Input
d
Output
Print the answer on one line. If the absolute error or relative error is 10-9 or less, the answer is judged to be correct.
Examples
Input
1.000
Output
2.000000000000
Input
2.345
Output
3.316330803765 | instruction | 0 | 10,749 | 1 | 21,498 |
"Correct Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 998244353
dd = [(0,-1),(1,0),(0,1),(-1,0)]
ddn = [(0,-1),(1,-1),(1,0),(1,1),(0,1),(-1,-1),(-1,0),(-1,1)]
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)
def main():
n = F()
nn = n**2
r = n * (2**0.5)
for i in range(int(n)+1):
kk = nn - i**2
if kk < 0:
break
k = kk ** 0.5
tr = i + k
if k < 1:
tr += 1-k
if r < tr:
r = tr
return r
print(main())
``` | output | 1 | 10,749 | 1 | 21,499 |
Provide a correct Python 3 solution for this coding contest problem.
In Manhattan, roads run where the x or y coordinate is an integer. Both Sunuke-kun's house and Sumeke-kun's house are on the road, and the straight line distance (Euclidean distance) is just d. Find the maximum value that can be considered as the shortest distance when traveling along the road from Sunuke-kun's house to Sumek-kun's house.
Constraints
* 0 <d ≤ 10
* d is given up to exactly three decimal places
Input
d
Output
Print the answer on one line. If the absolute error or relative error is 10-9 or less, the answer is judged to be correct.
Examples
Input
1.000
Output
2.000000000000
Input
2.345
Output
3.316330803765 | instruction | 0 | 10,750 | 1 | 21,500 |
"Correct Solution:
```
n=float(input())
print(int(n)+1 if n*2**0.5<int(n)+1 else n*2**0.5)
``` | output | 1 | 10,750 | 1 | 21,501 |
Provide a correct Python 3 solution for this coding contest problem.
In Manhattan, roads run where the x or y coordinate is an integer. Both Sunuke-kun's house and Sumeke-kun's house are on the road, and the straight line distance (Euclidean distance) is just d. Find the maximum value that can be considered as the shortest distance when traveling along the road from Sunuke-kun's house to Sumek-kun's house.
Constraints
* 0 <d ≤ 10
* d is given up to exactly three decimal places
Input
d
Output
Print the answer on one line. If the absolute error or relative error is 10-9 or less, the answer is judged to be correct.
Examples
Input
1.000
Output
2.000000000000
Input
2.345
Output
3.316330803765 | instruction | 0 | 10,751 | 1 | 21,502 |
"Correct Solution:
```
#!/usr/bin/env python3
d = float(input())
ans = max(2**0.5 * d, int(d) + 1)
print(ans)
``` | output | 1 | 10,751 | 1 | 21,503 |
Provide a correct Python 3 solution for this coding contest problem.
In Manhattan, roads run where the x or y coordinate is an integer. Both Sunuke-kun's house and Sumeke-kun's house are on the road, and the straight line distance (Euclidean distance) is just d. Find the maximum value that can be considered as the shortest distance when traveling along the road from Sunuke-kun's house to Sumek-kun's house.
Constraints
* 0 <d ≤ 10
* d is given up to exactly three decimal places
Input
d
Output
Print the answer on one line. If the absolute error or relative error is 10-9 or less, the answer is judged to be correct.
Examples
Input
1.000
Output
2.000000000000
Input
2.345
Output
3.316330803765 | instruction | 0 | 10,752 | 1 | 21,504 |
"Correct Solution:
```
n=float(input())
print(int(n)+1 if n*2**0.5<n//1+1 else n*2**0.5)
``` | output | 1 | 10,752 | 1 | 21,505 |
Provide a correct Python 3 solution for this coding contest problem.
In Manhattan, roads run where the x or y coordinate is an integer. Both Sunuke-kun's house and Sumeke-kun's house are on the road, and the straight line distance (Euclidean distance) is just d. Find the maximum value that can be considered as the shortest distance when traveling along the road from Sunuke-kun's house to Sumek-kun's house.
Constraints
* 0 <d ≤ 10
* d is given up to exactly three decimal places
Input
d
Output
Print the answer on one line. If the absolute error or relative error is 10-9 or less, the answer is judged to be correct.
Examples
Input
1.000
Output
2.000000000000
Input
2.345
Output
3.316330803765 | instruction | 0 | 10,753 | 1 | 21,506 |
"Correct Solution:
```
d=float(input());print(max(int(d)+1,d*2**0.5))
``` | output | 1 | 10,753 | 1 | 21,507 |
Provide a correct Python 3 solution for this coding contest problem.
In Manhattan, roads run where the x or y coordinate is an integer. Both Sunuke-kun's house and Sumeke-kun's house are on the road, and the straight line distance (Euclidean distance) is just d. Find the maximum value that can be considered as the shortest distance when traveling along the road from Sunuke-kun's house to Sumek-kun's house.
Constraints
* 0 <d ≤ 10
* d is given up to exactly three decimal places
Input
d
Output
Print the answer on one line. If the absolute error or relative error is 10-9 or less, the answer is judged to be correct.
Examples
Input
1.000
Output
2.000000000000
Input
2.345
Output
3.316330803765 | instruction | 0 | 10,754 | 1 | 21,508 |
"Correct Solution:
```
import math
n=float(input())
print(int(n)+1 if n*math.sqrt(2)<int(n)+1 else n*math.sqrt(2))
``` | output | 1 | 10,754 | 1 | 21,509 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Manhattan, roads run where the x or y coordinate is an integer. Both Sunuke-kun's house and Sumeke-kun's house are on the road, and the straight line distance (Euclidean distance) is just d. Find the maximum value that can be considered as the shortest distance when traveling along the road from Sunuke-kun's house to Sumek-kun's house.
Constraints
* 0 <d ≤ 10
* d is given up to exactly three decimal places
Input
d
Output
Print the answer on one line. If the absolute error or relative error is 10-9 or less, the answer is judged to be correct.
Examples
Input
1.000
Output
2.000000000000
Input
2.345
Output
3.316330803765
Submitted Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 998244353
dd = [(0,-1),(1,0),(0,1),(-1,0)]
ddn = [(0,-1),(1,-1),(1,0),(1,1),(0,1),(-1,-1),(-1,0),(-1,1)]
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)
def main():
rr = []
while True:
n = F()
nn = n**2
r = n
if n % 1 == 0:
r = n + 1
for i in range(11):
if n < i:
break
t = nn - i**2
tt = t ** 0.5
if tt < 0.5:
tt = 0.5 + (tt-0.5)
tr = i + tt
if r < tr:
r = tr
tr = n / (2**0.5) * 2
if r < tr:
r = tr
rr.append('{:0.10f}'.format(r))
break
return '\n'.join(map(str, rr))
print(main())
``` | instruction | 0 | 10,755 | 1 | 21,510 |
No | output | 1 | 10,755 | 1 | 21,511 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Manhattan, roads run where the x or y coordinate is an integer. Both Sunuke-kun's house and Sumeke-kun's house are on the road, and the straight line distance (Euclidean distance) is just d. Find the maximum value that can be considered as the shortest distance when traveling along the road from Sunuke-kun's house to Sumek-kun's house.
Constraints
* 0 <d ≤ 10
* d is given up to exactly three decimal places
Input
d
Output
Print the answer on one line. If the absolute error or relative error is 10-9 or less, the answer is judged to be correct.
Examples
Input
1.000
Output
2.000000000000
Input
2.345
Output
3.316330803765
Submitted Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 998244353
dd = [(0,-1),(1,0),(0,1),(-1,0)]
ddn = [(0,-1),(1,-1),(1,0),(1,1),(0,1),(-1,-1),(-1,0),(-1,1)]
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)
def main():
rr = []
while True:
n = F()
nn = n**2
r = n
if n % 1 == 0:
r = n + 1
tr = n / (2**0.5) * 2
if r < tr:
r = tr
rr.append('{:0.10f}'.format(r))
break
return '\n'.join(map(str, rr))
print(main())
``` | instruction | 0 | 10,756 | 1 | 21,512 |
No | output | 1 | 10,756 | 1 | 21,513 |
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