message stringlengths 2 22.8k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 16 109k | cluster float64 1 1 | __index_level_0__ int64 32 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N towns on a line running east-west. The towns are numbered 1 through N, in order from west to east. Each point on the line has a one-dimensional coordinate, and a point that is farther east has a greater coordinate value. The coordinate of town i is X_i.
You are now at town 1, and you want to visit all the other towns. You have two ways to travel:
* Walk on the line. Your fatigue level increases by A each time you travel a distance of 1, regardless of direction.
* Teleport to any location of your choice. Your fatigue level increases by B, regardless of the distance covered.
Find the minimum possible total increase of your fatigue level when you visit all the towns in these two ways.
Constraints
* All input values are integers.
* 2≤N≤10^5
* 1≤X_i≤10^9
* For all i(1≤i≤N-1), X_i<X_{i+1}.
* 1≤A≤10^9
* 1≤B≤10^9
Input
The input is given from Standard Input in the following format:
N A B
X_1 X_2 ... X_N
Output
Print the minimum possible total increase of your fatigue level when you visit all the towns.
Examples
Input
4 2 5
1 2 5 7
Output
11
Input
7 1 100
40 43 45 105 108 115 124
Output
84
Input
7 1 2
24 35 40 68 72 99 103
Output
12
Submitted Solution:
```
N, A, B = map(int, input().split())
X = list(map(int, input().split()))
ans = sum([min(A * (X[i+1]-X[i]), B) for i in range(N-1)])
print(ans)
``` | instruction | 0 | 75,766 | 1 | 151,532 |
Yes | output | 1 | 75,766 | 1 | 151,533 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N towns on a line running east-west. The towns are numbered 1 through N, in order from west to east. Each point on the line has a one-dimensional coordinate, and a point that is farther east has a greater coordinate value. The coordinate of town i is X_i.
You are now at town 1, and you want to visit all the other towns. You have two ways to travel:
* Walk on the line. Your fatigue level increases by A each time you travel a distance of 1, regardless of direction.
* Teleport to any location of your choice. Your fatigue level increases by B, regardless of the distance covered.
Find the minimum possible total increase of your fatigue level when you visit all the towns in these two ways.
Constraints
* All input values are integers.
* 2≤N≤10^5
* 1≤X_i≤10^9
* For all i(1≤i≤N-1), X_i<X_{i+1}.
* 1≤A≤10^9
* 1≤B≤10^9
Input
The input is given from Standard Input in the following format:
N A B
X_1 X_2 ... X_N
Output
Print the minimum possible total increase of your fatigue level when you visit all the towns.
Examples
Input
4 2 5
1 2 5 7
Output
11
Input
7 1 100
40 43 45 105 108 115 124
Output
84
Input
7 1 2
24 35 40 68 72 99 103
Output
12
Submitted Solution:
```
n, a, b = map(int, input().split())
x = list(map(int, input().split()))
diff = [x[i] - x[i-1] for i in range(1, n)]
res = 0
for d in diff:
res += min(d, b)
print(res)
``` | instruction | 0 | 75,767 | 1 | 151,534 |
No | output | 1 | 75,767 | 1 | 151,535 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N towns on a line running east-west. The towns are numbered 1 through N, in order from west to east. Each point on the line has a one-dimensional coordinate, and a point that is farther east has a greater coordinate value. The coordinate of town i is X_i.
You are now at town 1, and you want to visit all the other towns. You have two ways to travel:
* Walk on the line. Your fatigue level increases by A each time you travel a distance of 1, regardless of direction.
* Teleport to any location of your choice. Your fatigue level increases by B, regardless of the distance covered.
Find the minimum possible total increase of your fatigue level when you visit all the towns in these two ways.
Constraints
* All input values are integers.
* 2≤N≤10^5
* 1≤X_i≤10^9
* For all i(1≤i≤N-1), X_i<X_{i+1}.
* 1≤A≤10^9
* 1≤B≤10^9
Input
The input is given from Standard Input in the following format:
N A B
X_1 X_2 ... X_N
Output
Print the minimum possible total increase of your fatigue level when you visit all the towns.
Examples
Input
4 2 5
1 2 5 7
Output
11
Input
7 1 100
40 43 45 105 108 115 124
Output
84
Input
7 1 2
24 35 40 68 72 99 103
Output
12
Submitted Solution:
```
n,a,b = map(int, input().split())
x = sorted(list(map(int, input().split())))
if b <= a:
print(n*b)
exit()
diff = [0]*(n-1)
for i in range(n-1):
diff[i] = x[i+1] - x[i]
m = b/a
ans = 0
for i in diff:
if i <= m: ans += a*i
else: ans += b
print(ans)
``` | instruction | 0 | 75,768 | 1 | 151,536 |
No | output | 1 | 75,768 | 1 | 151,537 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N towns on a line running east-west. The towns are numbered 1 through N, in order from west to east. Each point on the line has a one-dimensional coordinate, and a point that is farther east has a greater coordinate value. The coordinate of town i is X_i.
You are now at town 1, and you want to visit all the other towns. You have two ways to travel:
* Walk on the line. Your fatigue level increases by A each time you travel a distance of 1, regardless of direction.
* Teleport to any location of your choice. Your fatigue level increases by B, regardless of the distance covered.
Find the minimum possible total increase of your fatigue level when you visit all the towns in these two ways.
Constraints
* All input values are integers.
* 2≤N≤10^5
* 1≤X_i≤10^9
* For all i(1≤i≤N-1), X_i<X_{i+1}.
* 1≤A≤10^9
* 1≤B≤10^9
Input
The input is given from Standard Input in the following format:
N A B
X_1 X_2 ... X_N
Output
Print the minimum possible total increase of your fatigue level when you visit all the towns.
Examples
Input
4 2 5
1 2 5 7
Output
11
Input
7 1 100
40 43 45 105 108 115 124
Output
84
Input
7 1 2
24 35 40 68 72 99 103
Output
12
Submitted Solution:
```
n, a, b = map(int, input().split())
x = list(map(int, input().split()))
hp = 0
good = min(a, b)
bad = max(a, b)
for i in range(n):
if i+1 == n:
break
if bad >= abs(x[i+1] - x[i])*good:
hp += abs(x[i+1] - x[i]) * good
else:
hp += bad
print(hp)
``` | instruction | 0 | 75,769 | 1 | 151,538 |
No | output | 1 | 75,769 | 1 | 151,539 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N towns on a line running east-west. The towns are numbered 1 through N, in order from west to east. Each point on the line has a one-dimensional coordinate, and a point that is farther east has a greater coordinate value. The coordinate of town i is X_i.
You are now at town 1, and you want to visit all the other towns. You have two ways to travel:
* Walk on the line. Your fatigue level increases by A each time you travel a distance of 1, regardless of direction.
* Teleport to any location of your choice. Your fatigue level increases by B, regardless of the distance covered.
Find the minimum possible total increase of your fatigue level when you visit all the towns in these two ways.
Constraints
* All input values are integers.
* 2≤N≤10^5
* 1≤X_i≤10^9
* For all i(1≤i≤N-1), X_i<X_{i+1}.
* 1≤A≤10^9
* 1≤B≤10^9
Input
The input is given from Standard Input in the following format:
N A B
X_1 X_2 ... X_N
Output
Print the minimum possible total increase of your fatigue level when you visit all the towns.
Examples
Input
4 2 5
1 2 5 7
Output
11
Input
7 1 100
40 43 45 105 108 115 124
Output
84
Input
7 1 2
24 35 40 68 72 99 103
Output
12
Submitted Solution:
```
N, A, B = map(int, input().split())
X = list(map(int, input().split()))
x1 = X[0]
cost = [min(A * abs(x - x1), B) for x in X]
print(sum(cost))
``` | instruction | 0 | 75,770 | 1 | 151,540 |
No | output | 1 | 75,770 | 1 | 151,541 |
Provide tags and a correct Python 3 solution for this coding contest problem.
During a recent research Berland scientists found out that there were n cities in Ancient Berland, joined by two-way paths. Any two cities are joined by no more than one path. No path joins a city with itself. According to a well-known tradition, the road network was built so that it would be impossible to choose three cities from each of which one can get to any other one directly. That is, there was no cycle exactly as long as 3. Unfortunately, the road map has not been preserved till nowadays. Now the scientists are interested how much developed a country Ancient Berland was. Help them - find, what maximal number of roads could be in the country. You also have to restore any of the possible road maps.
Input
The first line contains an integer n (1 ≤ n ≤ 100) — the number of cities in Berland.
Output
On the first line must be printed number m — the maximal number of roads in Berland. Then print m lines containing two numbers each — the numbers of cities that the given road joins. The cities are numbered with integers from 1 to n. If there are several variants of solving the problem, print any of them.
Examples
Input
3
Output
2
1 2
2 3
Input
4
Output
4
1 2
2 3
3 4
4 1 | instruction | 0 | 76,215 | 1 | 152,430 |
Tags: constructive algorithms, graphs, greedy
Correct Solution:
```
###### https://codeforces.com/problemset/problem/41/E
n = int(input())
a = list(range(1, n+1))
edge = []
used = []
for i, u in enumerate(a):
for j in range(1, n, 2):
if i + j >= n : continue
ind = i+j
edge.append([u, a[ind]])
print(len(edge))
for u, v in edge:
print('{} {}'.format(u, v))
``` | output | 1 | 76,215 | 1 | 152,431 |
Provide tags and a correct Python 3 solution for this coding contest problem.
During a recent research Berland scientists found out that there were n cities in Ancient Berland, joined by two-way paths. Any two cities are joined by no more than one path. No path joins a city with itself. According to a well-known tradition, the road network was built so that it would be impossible to choose three cities from each of which one can get to any other one directly. That is, there was no cycle exactly as long as 3. Unfortunately, the road map has not been preserved till nowadays. Now the scientists are interested how much developed a country Ancient Berland was. Help them - find, what maximal number of roads could be in the country. You also have to restore any of the possible road maps.
Input
The first line contains an integer n (1 ≤ n ≤ 100) — the number of cities in Berland.
Output
On the first line must be printed number m — the maximal number of roads in Berland. Then print m lines containing two numbers each — the numbers of cities that the given road joins. The cities are numbered with integers from 1 to n. If there are several variants of solving the problem, print any of them.
Examples
Input
3
Output
2
1 2
2 3
Input
4
Output
4
1 2
2 3
3 4
4 1 | instruction | 0 | 76,216 | 1 | 152,432 |
Tags: constructive algorithms, graphs, greedy
Correct Solution:
```
# from dust i have come, dust i will be
n=int(input())
adj=[[0]*(n+1) for i in range(n+1)]
if n<=3:
if n==1:
print(0)
elif n==2:
print(1)
print(1,2)
else:
print(2)
print(1,2)
print(2,3)
exit(0)
m=0
ans=[]
#make a cycle
for i in range(1,n):
ans.append([i,i+1])
adj[i][i+1]=1
adj[i+1][i]=1
for i in range(1,n+1):
for j in range(1,n+1):
if i==j:
continue
elif adj[i][j]==1 or adj[j][i]==1:
continue
else:
#see if there's a common node
f=1
for k in range(1,n+1):
if adj[i][k]==1 and adj[j][k]==1:
f=0
break
if f==1:
adj[i][j]=1
adj[j][i]=1
ans.append([i,j])
print(len(ans))
for i in range(len(ans)):
print(ans[i][0],ans[i][1])
# http://codeforces.com/problemset/problem/41/E
``` | output | 1 | 76,216 | 1 | 152,433 |
Provide tags and a correct Python 3 solution for this coding contest problem.
During a recent research Berland scientists found out that there were n cities in Ancient Berland, joined by two-way paths. Any two cities are joined by no more than one path. No path joins a city with itself. According to a well-known tradition, the road network was built so that it would be impossible to choose three cities from each of which one can get to any other one directly. That is, there was no cycle exactly as long as 3. Unfortunately, the road map has not been preserved till nowadays. Now the scientists are interested how much developed a country Ancient Berland was. Help them - find, what maximal number of roads could be in the country. You also have to restore any of the possible road maps.
Input
The first line contains an integer n (1 ≤ n ≤ 100) — the number of cities in Berland.
Output
On the first line must be printed number m — the maximal number of roads in Berland. Then print m lines containing two numbers each — the numbers of cities that the given road joins. The cities are numbered with integers from 1 to n. If there are several variants of solving the problem, print any of them.
Examples
Input
3
Output
2
1 2
2 3
Input
4
Output
4
1 2
2 3
3 4
4 1 | instruction | 0 | 76,217 | 1 | 152,434 |
Tags: constructive algorithms, graphs, greedy
Correct Solution:
```
p = int(input())
print( ( p // 2 ) ** 2 + ( p // 2) * ( p % 2 ) )
for i in range(p//2):
for j in range(p//2, p):
print(i+1, j+1)
``` | output | 1 | 76,217 | 1 | 152,435 |
Provide tags and a correct Python 3 solution for this coding contest problem.
During a recent research Berland scientists found out that there were n cities in Ancient Berland, joined by two-way paths. Any two cities are joined by no more than one path. No path joins a city with itself. According to a well-known tradition, the road network was built so that it would be impossible to choose three cities from each of which one can get to any other one directly. That is, there was no cycle exactly as long as 3. Unfortunately, the road map has not been preserved till nowadays. Now the scientists are interested how much developed a country Ancient Berland was. Help them - find, what maximal number of roads could be in the country. You also have to restore any of the possible road maps.
Input
The first line contains an integer n (1 ≤ n ≤ 100) — the number of cities in Berland.
Output
On the first line must be printed number m — the maximal number of roads in Berland. Then print m lines containing two numbers each — the numbers of cities that the given road joins. The cities are numbered with integers from 1 to n. If there are several variants of solving the problem, print any of them.
Examples
Input
3
Output
2
1 2
2 3
Input
4
Output
4
1 2
2 3
3 4
4 1 | instruction | 0 | 76,218 | 1 | 152,436 |
Tags: constructive algorithms, graphs, greedy
Correct Solution:
```
a = int(input())
l, r = a//2, (a+1)//2
print(l*r)
for i in range(0, l):
for j in range(0, r):
print(i+1, j+l+1)
``` | output | 1 | 76,218 | 1 | 152,437 |
Provide tags and a correct Python 3 solution for this coding contest problem.
During a recent research Berland scientists found out that there were n cities in Ancient Berland, joined by two-way paths. Any two cities are joined by no more than one path. No path joins a city with itself. According to a well-known tradition, the road network was built so that it would be impossible to choose three cities from each of which one can get to any other one directly. That is, there was no cycle exactly as long as 3. Unfortunately, the road map has not been preserved till nowadays. Now the scientists are interested how much developed a country Ancient Berland was. Help them - find, what maximal number of roads could be in the country. You also have to restore any of the possible road maps.
Input
The first line contains an integer n (1 ≤ n ≤ 100) — the number of cities in Berland.
Output
On the first line must be printed number m — the maximal number of roads in Berland. Then print m lines containing two numbers each — the numbers of cities that the given road joins. The cities are numbered with integers from 1 to n. If there are several variants of solving the problem, print any of them.
Examples
Input
3
Output
2
1 2
2 3
Input
4
Output
4
1 2
2 3
3 4
4 1 | instruction | 0 | 76,219 | 1 | 152,438 |
Tags: constructive algorithms, graphs, greedy
Correct Solution:
```
n = int(input())
ans = 0
for i in range(2, n+1):
ans+=1
for j in range(i-3, 0, -2):
ans+=1
print(ans)
for i in range(2, n+1):
print(i, i-1)
for j in range(i-3, 0, -2):
print(i, j)
``` | output | 1 | 76,219 | 1 | 152,439 |
Provide tags and a correct Python 3 solution for this coding contest problem.
During a recent research Berland scientists found out that there were n cities in Ancient Berland, joined by two-way paths. Any two cities are joined by no more than one path. No path joins a city with itself. According to a well-known tradition, the road network was built so that it would be impossible to choose three cities from each of which one can get to any other one directly. That is, there was no cycle exactly as long as 3. Unfortunately, the road map has not been preserved till nowadays. Now the scientists are interested how much developed a country Ancient Berland was. Help them - find, what maximal number of roads could be in the country. You also have to restore any of the possible road maps.
Input
The first line contains an integer n (1 ≤ n ≤ 100) — the number of cities in Berland.
Output
On the first line must be printed number m — the maximal number of roads in Berland. Then print m lines containing two numbers each — the numbers of cities that the given road joins. The cities are numbered with integers from 1 to n. If there are several variants of solving the problem, print any of them.
Examples
Input
3
Output
2
1 2
2 3
Input
4
Output
4
1 2
2 3
3 4
4 1 | instruction | 0 | 76,220 | 1 | 152,440 |
Tags: constructive algorithms, graphs, greedy
Correct Solution:
```
import sys
n = int(sys.stdin.readline())
# Mantel's theorem
print((n ** 2) // 4)
for i in range(n // 2):
for j in range(n // 2, n):
print(str(i+1) + ' ' + str(j+1))
``` | output | 1 | 76,220 | 1 | 152,441 |
Provide tags and a correct Python 3 solution for this coding contest problem.
During a recent research Berland scientists found out that there were n cities in Ancient Berland, joined by two-way paths. Any two cities are joined by no more than one path. No path joins a city with itself. According to a well-known tradition, the road network was built so that it would be impossible to choose three cities from each of which one can get to any other one directly. That is, there was no cycle exactly as long as 3. Unfortunately, the road map has not been preserved till nowadays. Now the scientists are interested how much developed a country Ancient Berland was. Help them - find, what maximal number of roads could be in the country. You also have to restore any of the possible road maps.
Input
The first line contains an integer n (1 ≤ n ≤ 100) — the number of cities in Berland.
Output
On the first line must be printed number m — the maximal number of roads in Berland. Then print m lines containing two numbers each — the numbers of cities that the given road joins. The cities are numbered with integers from 1 to n. If there are several variants of solving the problem, print any of them.
Examples
Input
3
Output
2
1 2
2 3
Input
4
Output
4
1 2
2 3
3 4
4 1 | instruction | 0 | 76,221 | 1 | 152,442 |
Tags: constructive algorithms, graphs, greedy
Correct Solution:
```
import math as m
n = int(input())
print(m.ceil(n/2)*m.floor(n/2))
for i in range(1,n+1):
for j in range(1,n+1):
if i%2==0 and j%2==1:
print(i,j)
``` | output | 1 | 76,221 | 1 | 152,443 |
Provide tags and a correct Python 3 solution for this coding contest problem.
During a recent research Berland scientists found out that there were n cities in Ancient Berland, joined by two-way paths. Any two cities are joined by no more than one path. No path joins a city with itself. According to a well-known tradition, the road network was built so that it would be impossible to choose three cities from each of which one can get to any other one directly. That is, there was no cycle exactly as long as 3. Unfortunately, the road map has not been preserved till nowadays. Now the scientists are interested how much developed a country Ancient Berland was. Help them - find, what maximal number of roads could be in the country. You also have to restore any of the possible road maps.
Input
The first line contains an integer n (1 ≤ n ≤ 100) — the number of cities in Berland.
Output
On the first line must be printed number m — the maximal number of roads in Berland. Then print m lines containing two numbers each — the numbers of cities that the given road joins. The cities are numbered with integers from 1 to n. If there are several variants of solving the problem, print any of them.
Examples
Input
3
Output
2
1 2
2 3
Input
4
Output
4
1 2
2 3
3 4
4 1 | instruction | 0 | 76,222 | 1 | 152,444 |
Tags: constructive algorithms, graphs, greedy
Correct Solution:
```
n = int(input())
if n == 1:
print(0)
elif n == 2:
print(1)
print(1, 2)
else:
fh = []
sh = []
for i in range(1, (n - 2) // 2 + 1):
fh.append(i + 2)
for i in range(3 + (n - 2) // 2, n + 1):
sh.append(i)
total = 1 + len(fh) * len(sh) + len(fh) + len(sh)
print(total)
print(1, 2)
for elm in fh:
print(1, elm)
for elm in sh:
print(2, elm)
for elm1 in fh:
for elm2 in sh:
print(elm1, elm2)
``` | output | 1 | 76,222 | 1 | 152,445 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
During a recent research Berland scientists found out that there were n cities in Ancient Berland, joined by two-way paths. Any two cities are joined by no more than one path. No path joins a city with itself. According to a well-known tradition, the road network was built so that it would be impossible to choose three cities from each of which one can get to any other one directly. That is, there was no cycle exactly as long as 3. Unfortunately, the road map has not been preserved till nowadays. Now the scientists are interested how much developed a country Ancient Berland was. Help them - find, what maximal number of roads could be in the country. You also have to restore any of the possible road maps.
Input
The first line contains an integer n (1 ≤ n ≤ 100) — the number of cities in Berland.
Output
On the first line must be printed number m — the maximal number of roads in Berland. Then print m lines containing two numbers each — the numbers of cities that the given road joins. The cities are numbered with integers from 1 to n. If there are several variants of solving the problem, print any of them.
Examples
Input
3
Output
2
1 2
2 3
Input
4
Output
4
1 2
2 3
3 4
4 1
Submitted Solution:
```
p = int(input())
n = ( p // 2 ) ** 2 + ( p // 2) * ( p % 2 )
print(n)
for i in range(p//2):
for j in range(p//2, p):
print(i+1, j+1)
``` | instruction | 0 | 76,223 | 1 | 152,446 |
Yes | output | 1 | 76,223 | 1 | 152,447 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
During a recent research Berland scientists found out that there were n cities in Ancient Berland, joined by two-way paths. Any two cities are joined by no more than one path. No path joins a city with itself. According to a well-known tradition, the road network was built so that it would be impossible to choose three cities from each of which one can get to any other one directly. That is, there was no cycle exactly as long as 3. Unfortunately, the road map has not been preserved till nowadays. Now the scientists are interested how much developed a country Ancient Berland was. Help them - find, what maximal number of roads could be in the country. You also have to restore any of the possible road maps.
Input
The first line contains an integer n (1 ≤ n ≤ 100) — the number of cities in Berland.
Output
On the first line must be printed number m — the maximal number of roads in Berland. Then print m lines containing two numbers each — the numbers of cities that the given road joins. The cities are numbered with integers from 1 to n. If there are several variants of solving the problem, print any of them.
Examples
Input
3
Output
2
1 2
2 3
Input
4
Output
4
1 2
2 3
3 4
4 1
Submitted Solution:
```
# 41E
def do():
n = int(input())
ln = n >> 1
res = []
for i in range(1, ln + 1):
for j in range(ln + 1, n + 1):
res.append((i, j))
return res
res = do()
print(len(res))
for x, y in res:
print(str(x) + " " + str(y))
``` | instruction | 0 | 76,224 | 1 | 152,448 |
Yes | output | 1 | 76,224 | 1 | 152,449 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
During a recent research Berland scientists found out that there were n cities in Ancient Berland, joined by two-way paths. Any two cities are joined by no more than one path. No path joins a city with itself. According to a well-known tradition, the road network was built so that it would be impossible to choose three cities from each of which one can get to any other one directly. That is, there was no cycle exactly as long as 3. Unfortunately, the road map has not been preserved till nowadays. Now the scientists are interested how much developed a country Ancient Berland was. Help them - find, what maximal number of roads could be in the country. You also have to restore any of the possible road maps.
Input
The first line contains an integer n (1 ≤ n ≤ 100) — the number of cities in Berland.
Output
On the first line must be printed number m — the maximal number of roads in Berland. Then print m lines containing two numbers each — the numbers of cities that the given road joins. The cities are numbered with integers from 1 to n. If there are several variants of solving the problem, print any of them.
Examples
Input
3
Output
2
1 2
2 3
Input
4
Output
4
1 2
2 3
3 4
4 1
Submitted Solution:
```
import sys
input=sys.stdin.readline
n=int(input())
if(n==1):
print(0)
quit()
if(n==2):
print(1)
print(1,2)
quit()
if(n%2==0):
k=(n-2)//2
l=(n-2)//2
z=(k*l+l+k+1)
print(z)
l1=[]
l2=[]
print(1,2)
for i in range(3,3+k):
l1.append(i)
for i in range(3+k,3+k+l):
l2.append(i)
for i in l1:
print(1,i)
for i in l2:
print(2,i)
for i in l1:
for j in l2:
print(i,j)
quit()
k=(n-2)//2
l=n-2-k
z=(k*l+l+k+1)
print(z)
l1=[]
l2=[]
print(1,2)
for i in range(3,3+k):
l1.append(i)
for i in range(3+k,3+k+l):
l2.append(i)
#print(l1)
#print(l2)
for i in l1:
print(1,i)
for i in l2:
print(2,i)
for i in l1:
for j in l2:
print(i,j)
quit()
``` | instruction | 0 | 76,225 | 1 | 152,450 |
Yes | output | 1 | 76,225 | 1 | 152,451 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
During a recent research Berland scientists found out that there were n cities in Ancient Berland, joined by two-way paths. Any two cities are joined by no more than one path. No path joins a city with itself. According to a well-known tradition, the road network was built so that it would be impossible to choose three cities from each of which one can get to any other one directly. That is, there was no cycle exactly as long as 3. Unfortunately, the road map has not been preserved till nowadays. Now the scientists are interested how much developed a country Ancient Berland was. Help them - find, what maximal number of roads could be in the country. You also have to restore any of the possible road maps.
Input
The first line contains an integer n (1 ≤ n ≤ 100) — the number of cities in Berland.
Output
On the first line must be printed number m — the maximal number of roads in Berland. Then print m lines containing two numbers each — the numbers of cities that the given road joins. The cities are numbered with integers from 1 to n. If there are several variants of solving the problem, print any of them.
Examples
Input
3
Output
2
1 2
2 3
Input
4
Output
4
1 2
2 3
3 4
4 1
Submitted Solution:
```
# from itertools import permutations,combinations
# import math
n=int(input())
a=range(1,n//2+1)
b=range(n//2+1,n+1)
print((n//2)*(n-(n//2)))
for i in a:
for j in b:
print(i,j)
``` | instruction | 0 | 76,226 | 1 | 152,452 |
Yes | output | 1 | 76,226 | 1 | 152,453 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
During a recent research Berland scientists found out that there were n cities in Ancient Berland, joined by two-way paths. Any two cities are joined by no more than one path. No path joins a city with itself. According to a well-known tradition, the road network was built so that it would be impossible to choose three cities from each of which one can get to any other one directly. That is, there was no cycle exactly as long as 3. Unfortunately, the road map has not been preserved till nowadays. Now the scientists are interested how much developed a country Ancient Berland was. Help them - find, what maximal number of roads could be in the country. You also have to restore any of the possible road maps.
Input
The first line contains an integer n (1 ≤ n ≤ 100) — the number of cities in Berland.
Output
On the first line must be printed number m — the maximal number of roads in Berland. Then print m lines containing two numbers each — the numbers of cities that the given road joins. The cities are numbered with integers from 1 to n. If there are several variants of solving the problem, print any of them.
Examples
Input
3
Output
2
1 2
2 3
Input
4
Output
4
1 2
2 3
3 4
4 1
Submitted Solution:
```
# https://codeforces.com/problemset/problem/41/E
n = int(input())
a = list(range(1, n+1))
edge = []
used = []
for i, u in enumerate(a):
for j in range(1, n):
if j == 2 or i + j >= n : continue
ind = i+j
edge.append([u, a[ind]])
print(len(edge))
for u, v in edge:
print('{} {}'.format(u, v))
``` | instruction | 0 | 76,227 | 1 | 152,454 |
No | output | 1 | 76,227 | 1 | 152,455 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
During a recent research Berland scientists found out that there were n cities in Ancient Berland, joined by two-way paths. Any two cities are joined by no more than one path. No path joins a city with itself. According to a well-known tradition, the road network was built so that it would be impossible to choose three cities from each of which one can get to any other one directly. That is, there was no cycle exactly as long as 3. Unfortunately, the road map has not been preserved till nowadays. Now the scientists are interested how much developed a country Ancient Berland was. Help them - find, what maximal number of roads could be in the country. You also have to restore any of the possible road maps.
Input
The first line contains an integer n (1 ≤ n ≤ 100) — the number of cities in Berland.
Output
On the first line must be printed number m — the maximal number of roads in Berland. Then print m lines containing two numbers each — the numbers of cities that the given road joins. The cities are numbered with integers from 1 to n. If there are several variants of solving the problem, print any of them.
Examples
Input
3
Output
2
1 2
2 3
Input
4
Output
4
1 2
2 3
3 4
4 1
Submitted Solution:
```
#------------------------template--------------------------#
import os
import sys
from math import *
from collections import *
#from fractions import *
from bisect import *
from io import BytesIO, IOBase
def vsInput():
sys.stdin = open('input.txt', 'r')
sys.stdout = open('output.txt', 'w')
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
def value():return tuple(map(int,input().split()))
def array():return [int(i) for i in input().split()]
def Int():return int(input())
def Str():return input()
def arrayS():return [i for i in input().split()]
#-------------------------code---------------------------#
#vsInput()
n=Int()
ans=set()
for i in range(1,n+1):
for j in range(1,n+1):
if(i!=j and abs(i-j)!=2):
if(i<j):ans.add((i,j))
else:ans.add((j,i))
print(len(ans))
for i in ans:
print(*i)
``` | instruction | 0 | 76,228 | 1 | 152,456 |
No | output | 1 | 76,228 | 1 | 152,457 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
During a recent research Berland scientists found out that there were n cities in Ancient Berland, joined by two-way paths. Any two cities are joined by no more than one path. No path joins a city with itself. According to a well-known tradition, the road network was built so that it would be impossible to choose three cities from each of which one can get to any other one directly. That is, there was no cycle exactly as long as 3. Unfortunately, the road map has not been preserved till nowadays. Now the scientists are interested how much developed a country Ancient Berland was. Help them - find, what maximal number of roads could be in the country. You also have to restore any of the possible road maps.
Input
The first line contains an integer n (1 ≤ n ≤ 100) — the number of cities in Berland.
Output
On the first line must be printed number m — the maximal number of roads in Berland. Then print m lines containing two numbers each — the numbers of cities that the given road joins. The cities are numbered with integers from 1 to n. If there are several variants of solving the problem, print any of them.
Examples
Input
3
Output
2
1 2
2 3
Input
4
Output
4
1 2
2 3
3 4
4 1
Submitted Solution:
```
import sys
input=sys.stdin.readline
n=int(input())
if(n==1):
print(0)
quit()
if(n==2):
print(1)
print(1,2)
quit()
if(n%2==0):
k=(n-2)//2
l=(n-2)//2
z=(k*l+l+k+1)
print(z)
l1=[]
l2=[]
print(1,2)
for i in range(3,3+k):
l1.append(i)
for i in range(3+k,3+k+l):
l2.append(i)
for i in l1:
print(1,i)
for i in l2:
print(2,i)
for i in l1:
for j in l2:
print(i,j)
quit()
k=(n-2)//2
l=n-2-k
z=(k*l+l+k+1)
print(z)
l1=[]
l2=[]
print(1,2)
for i in range(3,3+k):
l1.append(i)
for i in range(3+k,3+k+l):
l2.append(i)
for i in l1:
print(1,i)
for i in l2:
print(2,i)
for i in l1:
for j in l2:
print(i,j)
quit()
``` | instruction | 0 | 76,229 | 1 | 152,458 |
No | output | 1 | 76,229 | 1 | 152,459 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
During a recent research Berland scientists found out that there were n cities in Ancient Berland, joined by two-way paths. Any two cities are joined by no more than one path. No path joins a city with itself. According to a well-known tradition, the road network was built so that it would be impossible to choose three cities from each of which one can get to any other one directly. That is, there was no cycle exactly as long as 3. Unfortunately, the road map has not been preserved till nowadays. Now the scientists are interested how much developed a country Ancient Berland was. Help them - find, what maximal number of roads could be in the country. You also have to restore any of the possible road maps.
Input
The first line contains an integer n (1 ≤ n ≤ 100) — the number of cities in Berland.
Output
On the first line must be printed number m — the maximal number of roads in Berland. Then print m lines containing two numbers each — the numbers of cities that the given road joins. The cities are numbered with integers from 1 to n. If there are several variants of solving the problem, print any of them.
Examples
Input
3
Output
2
1 2
2 3
Input
4
Output
4
1 2
2 3
3 4
4 1
Submitted Solution:
```
p = int(input())
n = ( p // 2 ) ** 2 + ( p // 2) * ( p % 2 )
print(n)
for i in range(n):
for j in range(n, 2*n + p % 2):
print(i+1, j+1)
``` | instruction | 0 | 76,230 | 1 | 152,460 |
No | output | 1 | 76,230 | 1 | 152,461 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A stowaway and a controller play the following game.
The train is represented by n wagons which are numbered with positive integers from 1 to n from the head to the tail. The stowaway and the controller are initially in some two different wagons. Every minute the train can be in one of two conditions — moving or idle. Every minute the players move.
The controller's move is as follows. The controller has the movement direction — to the train's head or to its tail. During a move the controller moves to the neighbouring wagon correspondingly to its movement direction. If at the end of his move the controller enters the 1-st or the n-th wagon, that he changes the direction of his movement into the other one. In other words, the controller cyclically goes from the train's head to its tail and back again during all the time of a game, shifting during each move by one wagon. Note, that the controller always have exactly one possible move.
The stowaway's move depends from the state of the train. If the train is moving, then the stowaway can shift to one of neighbouring wagons or he can stay where he is without moving. If the train is at a station and is idle, then the stowaway leaves the train (i.e. he is now not present in any train wagon) and then, if it is not the terminal train station, he enters the train again into any of n wagons (not necessarily into the one he's just left and not necessarily into the neighbouring one). If the train is idle for several minutes then each such minute the stowaway leaves the train and enters it back.
Let's determine the order of the players' moves. If at the given minute the train is moving, then first the stowaway moves and then the controller does. If at this minute the train is idle, then first the stowaway leaves the train, then the controller moves and then the stowaway enters the train.
If at some point in time the stowaway and the controller happen to be in one wagon, then the controller wins: he makes the stowaway pay fine. If after a while the stowaway reaches the terminal train station, then the stowaway wins: he simply leaves the station during his move and never returns there again.
At any moment of time the players know each other's positions. The players play in the optimal way. Specifically, if the controller wins, then the stowaway plays so as to lose as late as possible. As all the possible moves for the controller are determined uniquely, then he is considered to play optimally always. Determine the winner.
Input
The first line contains three integers n, m and k. They represent the number of wagons in the train, the stowaway's and the controller's initial positions correspondingly (2 ≤ n ≤ 50, 1 ≤ m, k ≤ n, m ≠ k).
The second line contains the direction in which a controller moves. "to head" means that the controller moves to the train's head and "to tail" means that the controller moves to its tail. It is guaranteed that in the direction in which the controller is moving, there is at least one wagon. Wagon 1 is the head, and wagon n is the tail.
The third line has the length from 1 to 200 and consists of symbols "0" and "1". The i-th symbol contains information about the train's state at the i-th minute of time. "0" means that in this very minute the train moves and "1" means that the train in this very minute stands idle. The last symbol of the third line is always "1" — that's the terminal train station.
Output
If the stowaway wins, print "Stowaway" without quotes. Otherwise, print "Controller" again without quotes, then, separated by a space, print the number of a minute, at which the stowaway will be caught.
Examples
Input
5 3 2
to head
0001001
Output
Stowaway
Input
3 2 1
to tail
0001
Output
Controller 2 | instruction | 0 | 76,350 | 1 | 152,700 |
Tags: dp, games, greedy
Correct Solution:
```
n, rider, cop = map(int, input().split())
rider, cop = rider - 1, cop - 1
if input().strip() == 'to head':
cop_dir = -1
else:
cop_dir = 1
for pos, ch in enumerate(input().strip()):
#print(pos, ch, rider, cop, cop_dir)
if ch == '1':
rider = -1
else:
if cop_dir == -1 and rider < cop:
rider = max(0, rider - 1)
elif cop_dir == 1 and rider > cop:
rider = min(n - 1, rider + 1)
cop += cop_dir
if cop == rider:
print('Controller %d' % (pos + 1))
import sys; sys.exit()
if cop == 0:
cop_dir = 1
elif cop == n - 1:
cop_dir = -1
if ch == '1':
if cop_dir == -1:
if cop == n - 1:
rider = 0
else:
rider = n - 1
else:
if cop == 0:
rider = n - 1
else:
rider = 0
print('Stowaway')
``` | output | 1 | 76,350 | 1 | 152,701 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A stowaway and a controller play the following game.
The train is represented by n wagons which are numbered with positive integers from 1 to n from the head to the tail. The stowaway and the controller are initially in some two different wagons. Every minute the train can be in one of two conditions — moving or idle. Every minute the players move.
The controller's move is as follows. The controller has the movement direction — to the train's head or to its tail. During a move the controller moves to the neighbouring wagon correspondingly to its movement direction. If at the end of his move the controller enters the 1-st or the n-th wagon, that he changes the direction of his movement into the other one. In other words, the controller cyclically goes from the train's head to its tail and back again during all the time of a game, shifting during each move by one wagon. Note, that the controller always have exactly one possible move.
The stowaway's move depends from the state of the train. If the train is moving, then the stowaway can shift to one of neighbouring wagons or he can stay where he is without moving. If the train is at a station and is idle, then the stowaway leaves the train (i.e. he is now not present in any train wagon) and then, if it is not the terminal train station, he enters the train again into any of n wagons (not necessarily into the one he's just left and not necessarily into the neighbouring one). If the train is idle for several minutes then each such minute the stowaway leaves the train and enters it back.
Let's determine the order of the players' moves. If at the given minute the train is moving, then first the stowaway moves and then the controller does. If at this minute the train is idle, then first the stowaway leaves the train, then the controller moves and then the stowaway enters the train.
If at some point in time the stowaway and the controller happen to be in one wagon, then the controller wins: he makes the stowaway pay fine. If after a while the stowaway reaches the terminal train station, then the stowaway wins: he simply leaves the station during his move and never returns there again.
At any moment of time the players know each other's positions. The players play in the optimal way. Specifically, if the controller wins, then the stowaway plays so as to lose as late as possible. As all the possible moves for the controller are determined uniquely, then he is considered to play optimally always. Determine the winner.
Input
The first line contains three integers n, m and k. They represent the number of wagons in the train, the stowaway's and the controller's initial positions correspondingly (2 ≤ n ≤ 50, 1 ≤ m, k ≤ n, m ≠ k).
The second line contains the direction in which a controller moves. "to head" means that the controller moves to the train's head and "to tail" means that the controller moves to its tail. It is guaranteed that in the direction in which the controller is moving, there is at least one wagon. Wagon 1 is the head, and wagon n is the tail.
The third line has the length from 1 to 200 and consists of symbols "0" and "1". The i-th symbol contains information about the train's state at the i-th minute of time. "0" means that in this very minute the train moves and "1" means that the train in this very minute stands idle. The last symbol of the third line is always "1" — that's the terminal train station.
Output
If the stowaway wins, print "Stowaway" without quotes. Otherwise, print "Controller" again without quotes, then, separated by a space, print the number of a minute, at which the stowaway will be caught.
Examples
Input
5 3 2
to head
0001001
Output
Stowaway
Input
3 2 1
to tail
0001
Output
Controller 2 | instruction | 0 | 76,351 | 1 | 152,702 |
Tags: dp, games, greedy
Correct Solution:
```
n,m,k=list(map(int,input().split()))
a={'to head':-1, 'to tail':1}[input()]
b=input()
l=len(b)
for i in range(l-1):
if b[i]=='0':
if k+a==m or not(1<=k+a<=n) and k-a==m:
if 1<=m+a<=n and 1<=k+a<=n or not(1<=k+a<=n) and 1<=m-a<=n:
m+=a
elif not(1<=k+a<=n) and 1<=m-a<=n:
m-=a
else:
print('Controller',i+1)
break
else:
if a==-1 and k!=1 or a==1 and k==n:
m=n
else:
m=1
if not(1<=k+a<=n):
a=-a
k+=a
else:
print('Stowaway')
``` | output | 1 | 76,351 | 1 | 152,703 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A stowaway and a controller play the following game.
The train is represented by n wagons which are numbered with positive integers from 1 to n from the head to the tail. The stowaway and the controller are initially in some two different wagons. Every minute the train can be in one of two conditions — moving or idle. Every minute the players move.
The controller's move is as follows. The controller has the movement direction — to the train's head or to its tail. During a move the controller moves to the neighbouring wagon correspondingly to its movement direction. If at the end of his move the controller enters the 1-st or the n-th wagon, that he changes the direction of his movement into the other one. In other words, the controller cyclically goes from the train's head to its tail and back again during all the time of a game, shifting during each move by one wagon. Note, that the controller always have exactly one possible move.
The stowaway's move depends from the state of the train. If the train is moving, then the stowaway can shift to one of neighbouring wagons or he can stay where he is without moving. If the train is at a station and is idle, then the stowaway leaves the train (i.e. he is now not present in any train wagon) and then, if it is not the terminal train station, he enters the train again into any of n wagons (not necessarily into the one he's just left and not necessarily into the neighbouring one). If the train is idle for several minutes then each such minute the stowaway leaves the train and enters it back.
Let's determine the order of the players' moves. If at the given minute the train is moving, then first the stowaway moves and then the controller does. If at this minute the train is idle, then first the stowaway leaves the train, then the controller moves and then the stowaway enters the train.
If at some point in time the stowaway and the controller happen to be in one wagon, then the controller wins: he makes the stowaway pay fine. If after a while the stowaway reaches the terminal train station, then the stowaway wins: he simply leaves the station during his move and never returns there again.
At any moment of time the players know each other's positions. The players play in the optimal way. Specifically, if the controller wins, then the stowaway plays so as to lose as late as possible. As all the possible moves for the controller are determined uniquely, then he is considered to play optimally always. Determine the winner.
Input
The first line contains three integers n, m and k. They represent the number of wagons in the train, the stowaway's and the controller's initial positions correspondingly (2 ≤ n ≤ 50, 1 ≤ m, k ≤ n, m ≠ k).
The second line contains the direction in which a controller moves. "to head" means that the controller moves to the train's head and "to tail" means that the controller moves to its tail. It is guaranteed that in the direction in which the controller is moving, there is at least one wagon. Wagon 1 is the head, and wagon n is the tail.
The third line has the length from 1 to 200 and consists of symbols "0" and "1". The i-th symbol contains information about the train's state at the i-th minute of time. "0" means that in this very minute the train moves and "1" means that the train in this very minute stands idle. The last symbol of the third line is always "1" — that's the terminal train station.
Output
If the stowaway wins, print "Stowaway" without quotes. Otherwise, print "Controller" again without quotes, then, separated by a space, print the number of a minute, at which the stowaway will be caught.
Examples
Input
5 3 2
to head
0001001
Output
Stowaway
Input
3 2 1
to tail
0001
Output
Controller 2 | instruction | 0 | 76,352 | 1 | 152,704 |
Tags: dp, games, greedy
Correct Solution:
```
J = lambda: map(int, input().split())
v, y, z = J()
dir = 'to tail' == input()
for t, x in enumerate(map(int, input())):
if z == 1:
dir = 1
elif z == v:
dir = 0
if not x:
y = min(v, y + 1) if z < y else max(1, y - 1)
else:
y = 1 if dir else v
z = z + 1 if dir else z - 1
if y == z:
print('Controller ' + str(t + 1))
exit(0)
print('Stowaway')
``` | output | 1 | 76,352 | 1 | 152,705 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A stowaway and a controller play the following game.
The train is represented by n wagons which are numbered with positive integers from 1 to n from the head to the tail. The stowaway and the controller are initially in some two different wagons. Every minute the train can be in one of two conditions — moving or idle. Every minute the players move.
The controller's move is as follows. The controller has the movement direction — to the train's head or to its tail. During a move the controller moves to the neighbouring wagon correspondingly to its movement direction. If at the end of his move the controller enters the 1-st or the n-th wagon, that he changes the direction of his movement into the other one. In other words, the controller cyclically goes from the train's head to its tail and back again during all the time of a game, shifting during each move by one wagon. Note, that the controller always have exactly one possible move.
The stowaway's move depends from the state of the train. If the train is moving, then the stowaway can shift to one of neighbouring wagons or he can stay where he is without moving. If the train is at a station and is idle, then the stowaway leaves the train (i.e. he is now not present in any train wagon) and then, if it is not the terminal train station, he enters the train again into any of n wagons (not necessarily into the one he's just left and not necessarily into the neighbouring one). If the train is idle for several minutes then each such minute the stowaway leaves the train and enters it back.
Let's determine the order of the players' moves. If at the given minute the train is moving, then first the stowaway moves and then the controller does. If at this minute the train is idle, then first the stowaway leaves the train, then the controller moves and then the stowaway enters the train.
If at some point in time the stowaway and the controller happen to be in one wagon, then the controller wins: he makes the stowaway pay fine. If after a while the stowaway reaches the terminal train station, then the stowaway wins: he simply leaves the station during his move and never returns there again.
At any moment of time the players know each other's positions. The players play in the optimal way. Specifically, if the controller wins, then the stowaway plays so as to lose as late as possible. As all the possible moves for the controller are determined uniquely, then he is considered to play optimally always. Determine the winner.
Input
The first line contains three integers n, m and k. They represent the number of wagons in the train, the stowaway's and the controller's initial positions correspondingly (2 ≤ n ≤ 50, 1 ≤ m, k ≤ n, m ≠ k).
The second line contains the direction in which a controller moves. "to head" means that the controller moves to the train's head and "to tail" means that the controller moves to its tail. It is guaranteed that in the direction in which the controller is moving, there is at least one wagon. Wagon 1 is the head, and wagon n is the tail.
The third line has the length from 1 to 200 and consists of symbols "0" and "1". The i-th symbol contains information about the train's state at the i-th minute of time. "0" means that in this very minute the train moves and "1" means that the train in this very minute stands idle. The last symbol of the third line is always "1" — that's the terminal train station.
Output
If the stowaway wins, print "Stowaway" without quotes. Otherwise, print "Controller" again without quotes, then, separated by a space, print the number of a minute, at which the stowaway will be caught.
Examples
Input
5 3 2
to head
0001001
Output
Stowaway
Input
3 2 1
to tail
0001
Output
Controller 2 | instruction | 0 | 76,353 | 1 | 152,706 |
Tags: dp, games, greedy
Correct Solution:
```
from sys import stdin, stdout, exit
n, m, k = map(int, stdin.readline().split())
d = 1 if stdin.readline()[6] == 'l' else -1
m = 1 if m < k else n
for i in range(5):
pass
for i, c in enumerate(stdin.readline(), 1):
if c == '0':
if k == 1: k, d = 2, 1
elif k == n: k, d = n - 1, -1
else: k += d
if m == k:
stdout.write('Controller ' + str(i))
exit(0)
else:
if k == 1: k, d, m = 2, 1, 1
elif k == n: k, d, m = n - 1, -1, n
elif d == 1:
k += 1
m = 1
else:
k -= 1
m = n
stdout.write('Stowaway')
``` | output | 1 | 76,353 | 1 | 152,707 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A stowaway and a controller play the following game.
The train is represented by n wagons which are numbered with positive integers from 1 to n from the head to the tail. The stowaway and the controller are initially in some two different wagons. Every minute the train can be in one of two conditions — moving or idle. Every minute the players move.
The controller's move is as follows. The controller has the movement direction — to the train's head or to its tail. During a move the controller moves to the neighbouring wagon correspondingly to its movement direction. If at the end of his move the controller enters the 1-st or the n-th wagon, that he changes the direction of his movement into the other one. In other words, the controller cyclically goes from the train's head to its tail and back again during all the time of a game, shifting during each move by one wagon. Note, that the controller always have exactly one possible move.
The stowaway's move depends from the state of the train. If the train is moving, then the stowaway can shift to one of neighbouring wagons or he can stay where he is without moving. If the train is at a station and is idle, then the stowaway leaves the train (i.e. he is now not present in any train wagon) and then, if it is not the terminal train station, he enters the train again into any of n wagons (not necessarily into the one he's just left and not necessarily into the neighbouring one). If the train is idle for several minutes then each such minute the stowaway leaves the train and enters it back.
Let's determine the order of the players' moves. If at the given minute the train is moving, then first the stowaway moves and then the controller does. If at this minute the train is idle, then first the stowaway leaves the train, then the controller moves and then the stowaway enters the train.
If at some point in time the stowaway and the controller happen to be in one wagon, then the controller wins: he makes the stowaway pay fine. If after a while the stowaway reaches the terminal train station, then the stowaway wins: he simply leaves the station during his move and never returns there again.
At any moment of time the players know each other's positions. The players play in the optimal way. Specifically, if the controller wins, then the stowaway plays so as to lose as late as possible. As all the possible moves for the controller are determined uniquely, then he is considered to play optimally always. Determine the winner.
Input
The first line contains three integers n, m and k. They represent the number of wagons in the train, the stowaway's and the controller's initial positions correspondingly (2 ≤ n ≤ 50, 1 ≤ m, k ≤ n, m ≠ k).
The second line contains the direction in which a controller moves. "to head" means that the controller moves to the train's head and "to tail" means that the controller moves to its tail. It is guaranteed that in the direction in which the controller is moving, there is at least one wagon. Wagon 1 is the head, and wagon n is the tail.
The third line has the length from 1 to 200 and consists of symbols "0" and "1". The i-th symbol contains information about the train's state at the i-th minute of time. "0" means that in this very minute the train moves and "1" means that the train in this very minute stands idle. The last symbol of the third line is always "1" — that's the terminal train station.
Output
If the stowaway wins, print "Stowaway" without quotes. Otherwise, print "Controller" again without quotes, then, separated by a space, print the number of a minute, at which the stowaway will be caught.
Examples
Input
5 3 2
to head
0001001
Output
Stowaway
Input
3 2 1
to tail
0001
Output
Controller 2 | instruction | 0 | 76,354 | 1 | 152,708 |
Tags: dp, games, greedy
Correct Solution:
```
n, z1, k1 = map(int, input().split())
z1 -= 1
k1 -= 1
s = input()
if (s == 'to head'):
napr = -1
else:
napr = 1
s = input()
for i in range(len(s)):
if (k1 == z1):
print('Controller', i)
exit(0)
if (s[i] == '0'):
if (k1 > z1 and z1 != 0):
z1 -= 1
elif (k1 < z1 and z1 != n - 1):
z1 += 1
k1 += napr
if (k1 == 0 or k1 == n - 1):
napr = -napr
else:
k1 += napr
if (k1 == 0 or k1 == n - 1):
napr = -napr
if (k1 == 0):
z1 = n - 1
elif (k1 == n - 1):
z1 = 0
elif (napr == 1 and k1 != 0):
z1 = 0
else:
z1 = n - 1
#print(z1 + 1, k1 + 1)
if (k1 == z1):
print('Controller', i + 1)
exit(0)
print('Stowaway')
``` | output | 1 | 76,354 | 1 | 152,709 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A stowaway and a controller play the following game.
The train is represented by n wagons which are numbered with positive integers from 1 to n from the head to the tail. The stowaway and the controller are initially in some two different wagons. Every minute the train can be in one of two conditions — moving or idle. Every minute the players move.
The controller's move is as follows. The controller has the movement direction — to the train's head or to its tail. During a move the controller moves to the neighbouring wagon correspondingly to its movement direction. If at the end of his move the controller enters the 1-st or the n-th wagon, that he changes the direction of his movement into the other one. In other words, the controller cyclically goes from the train's head to its tail and back again during all the time of a game, shifting during each move by one wagon. Note, that the controller always have exactly one possible move.
The stowaway's move depends from the state of the train. If the train is moving, then the stowaway can shift to one of neighbouring wagons or he can stay where he is without moving. If the train is at a station and is idle, then the stowaway leaves the train (i.e. he is now not present in any train wagon) and then, if it is not the terminal train station, he enters the train again into any of n wagons (not necessarily into the one he's just left and not necessarily into the neighbouring one). If the train is idle for several minutes then each such minute the stowaway leaves the train and enters it back.
Let's determine the order of the players' moves. If at the given minute the train is moving, then first the stowaway moves and then the controller does. If at this minute the train is idle, then first the stowaway leaves the train, then the controller moves and then the stowaway enters the train.
If at some point in time the stowaway and the controller happen to be in one wagon, then the controller wins: he makes the stowaway pay fine. If after a while the stowaway reaches the terminal train station, then the stowaway wins: he simply leaves the station during his move and never returns there again.
At any moment of time the players know each other's positions. The players play in the optimal way. Specifically, if the controller wins, then the stowaway plays so as to lose as late as possible. As all the possible moves for the controller are determined uniquely, then he is considered to play optimally always. Determine the winner.
Input
The first line contains three integers n, m and k. They represent the number of wagons in the train, the stowaway's and the controller's initial positions correspondingly (2 ≤ n ≤ 50, 1 ≤ m, k ≤ n, m ≠ k).
The second line contains the direction in which a controller moves. "to head" means that the controller moves to the train's head and "to tail" means that the controller moves to its tail. It is guaranteed that in the direction in which the controller is moving, there is at least one wagon. Wagon 1 is the head, and wagon n is the tail.
The third line has the length from 1 to 200 and consists of symbols "0" and "1". The i-th symbol contains information about the train's state at the i-th minute of time. "0" means that in this very minute the train moves and "1" means that the train in this very minute stands idle. The last symbol of the third line is always "1" — that's the terminal train station.
Output
If the stowaway wins, print "Stowaway" without quotes. Otherwise, print "Controller" again without quotes, then, separated by a space, print the number of a minute, at which the stowaway will be caught.
Examples
Input
5 3 2
to head
0001001
Output
Stowaway
Input
3 2 1
to tail
0001
Output
Controller 2 | instruction | 0 | 76,355 | 1 | 152,710 |
Tags: dp, games, greedy
Correct Solution:
```
R = lambda: map(int, input().split())
n, k, m = R()
dir = 'to tail' == input()
for t, x in enumerate(map(int, input())):
if m == 1:
dir = 1
elif m == n:
dir = 0
if not x:
k = min(n, k + 1) if m < k else max(1, k - 1)
else:
k = 1 if dir else n
m = m + 1 if dir else m - 1
if k == m:
print('Controller ' + str(t + 1))
exit(0)
print('Stowaway')
``` | output | 1 | 76,355 | 1 | 152,711 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A stowaway and a controller play the following game.
The train is represented by n wagons which are numbered with positive integers from 1 to n from the head to the tail. The stowaway and the controller are initially in some two different wagons. Every minute the train can be in one of two conditions — moving or idle. Every minute the players move.
The controller's move is as follows. The controller has the movement direction — to the train's head or to its tail. During a move the controller moves to the neighbouring wagon correspondingly to its movement direction. If at the end of his move the controller enters the 1-st or the n-th wagon, that he changes the direction of his movement into the other one. In other words, the controller cyclically goes from the train's head to its tail and back again during all the time of a game, shifting during each move by one wagon. Note, that the controller always have exactly one possible move.
The stowaway's move depends from the state of the train. If the train is moving, then the stowaway can shift to one of neighbouring wagons or he can stay where he is without moving. If the train is at a station and is idle, then the stowaway leaves the train (i.e. he is now not present in any train wagon) and then, if it is not the terminal train station, he enters the train again into any of n wagons (not necessarily into the one he's just left and not necessarily into the neighbouring one). If the train is idle for several minutes then each such minute the stowaway leaves the train and enters it back.
Let's determine the order of the players' moves. If at the given minute the train is moving, then first the stowaway moves and then the controller does. If at this minute the train is idle, then first the stowaway leaves the train, then the controller moves and then the stowaway enters the train.
If at some point in time the stowaway and the controller happen to be in one wagon, then the controller wins: he makes the stowaway pay fine. If after a while the stowaway reaches the terminal train station, then the stowaway wins: he simply leaves the station during his move and never returns there again.
At any moment of time the players know each other's positions. The players play in the optimal way. Specifically, if the controller wins, then the stowaway plays so as to lose as late as possible. As all the possible moves for the controller are determined uniquely, then he is considered to play optimally always. Determine the winner.
Input
The first line contains three integers n, m and k. They represent the number of wagons in the train, the stowaway's and the controller's initial positions correspondingly (2 ≤ n ≤ 50, 1 ≤ m, k ≤ n, m ≠ k).
The second line contains the direction in which a controller moves. "to head" means that the controller moves to the train's head and "to tail" means that the controller moves to its tail. It is guaranteed that in the direction in which the controller is moving, there is at least one wagon. Wagon 1 is the head, and wagon n is the tail.
The third line has the length from 1 to 200 and consists of symbols "0" and "1". The i-th symbol contains information about the train's state at the i-th minute of time. "0" means that in this very minute the train moves and "1" means that the train in this very minute stands idle. The last symbol of the third line is always "1" — that's the terminal train station.
Output
If the stowaway wins, print "Stowaway" without quotes. Otherwise, print "Controller" again without quotes, then, separated by a space, print the number of a minute, at which the stowaway will be caught.
Examples
Input
5 3 2
to head
0001001
Output
Stowaway
Input
3 2 1
to tail
0001
Output
Controller 2 | instruction | 0 | 76,356 | 1 | 152,712 |
Tags: dp, games, greedy
Correct Solution:
```
n,p1,p2=map(int,input().split())
s=input()
state=list(input())
l=len(state)
head=1 if s=="to head" else 0
for i in range(l):
s=state[i]
if s=="0":
if head:
if p1<p2:
if p1>1:
p1-=1
elif p2<p1:
if p1<n:
p1+=1
if p2>1:
p2-=1
else:
head=1-head
p2+=1
else:
if p1<p2:
if p1>1:
p1-=1
elif p2<p1:
if p1<n:
p1+=1
if p2<n:
p2+=1
else:
head=1-head
p2-=1
if p1==p2:
print("Controller",i+1)
exit()
else:
if head:
if p2>1:
p2-=1
else:
head=1-head
p2+=1
else:
if p2<n:
p2+=1
else:
head=1-head
p2-=1
if head and p2!=n:
p1=n
elif head and p2==n:
p1=1
elif p2!=1:
p1=1
else:
p1=n
print("Stowaway")
``` | output | 1 | 76,356 | 1 | 152,713 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A stowaway and a controller play the following game.
The train is represented by n wagons which are numbered with positive integers from 1 to n from the head to the tail. The stowaway and the controller are initially in some two different wagons. Every minute the train can be in one of two conditions — moving or idle. Every minute the players move.
The controller's move is as follows. The controller has the movement direction — to the train's head or to its tail. During a move the controller moves to the neighbouring wagon correspondingly to its movement direction. If at the end of his move the controller enters the 1-st or the n-th wagon, that he changes the direction of his movement into the other one. In other words, the controller cyclically goes from the train's head to its tail and back again during all the time of a game, shifting during each move by one wagon. Note, that the controller always have exactly one possible move.
The stowaway's move depends from the state of the train. If the train is moving, then the stowaway can shift to one of neighbouring wagons or he can stay where he is without moving. If the train is at a station and is idle, then the stowaway leaves the train (i.e. he is now not present in any train wagon) and then, if it is not the terminal train station, he enters the train again into any of n wagons (not necessarily into the one he's just left and not necessarily into the neighbouring one). If the train is idle for several minutes then each such minute the stowaway leaves the train and enters it back.
Let's determine the order of the players' moves. If at the given minute the train is moving, then first the stowaway moves and then the controller does. If at this minute the train is idle, then first the stowaway leaves the train, then the controller moves and then the stowaway enters the train.
If at some point in time the stowaway and the controller happen to be in one wagon, then the controller wins: he makes the stowaway pay fine. If after a while the stowaway reaches the terminal train station, then the stowaway wins: he simply leaves the station during his move and never returns there again.
At any moment of time the players know each other's positions. The players play in the optimal way. Specifically, if the controller wins, then the stowaway plays so as to lose as late as possible. As all the possible moves for the controller are determined uniquely, then he is considered to play optimally always. Determine the winner.
Input
The first line contains three integers n, m and k. They represent the number of wagons in the train, the stowaway's and the controller's initial positions correspondingly (2 ≤ n ≤ 50, 1 ≤ m, k ≤ n, m ≠ k).
The second line contains the direction in which a controller moves. "to head" means that the controller moves to the train's head and "to tail" means that the controller moves to its tail. It is guaranteed that in the direction in which the controller is moving, there is at least one wagon. Wagon 1 is the head, and wagon n is the tail.
The third line has the length from 1 to 200 and consists of symbols "0" and "1". The i-th symbol contains information about the train's state at the i-th minute of time. "0" means that in this very minute the train moves and "1" means that the train in this very minute stands idle. The last symbol of the third line is always "1" — that's the terminal train station.
Output
If the stowaway wins, print "Stowaway" without quotes. Otherwise, print "Controller" again without quotes, then, separated by a space, print the number of a minute, at which the stowaway will be caught.
Examples
Input
5 3 2
to head
0001001
Output
Stowaway
Input
3 2 1
to tail
0001
Output
Controller 2 | instruction | 0 | 76,357 | 1 | 152,714 |
Tags: dp, games, greedy
Correct Solution:
```
from sys import stdin, stdout, exit
n, m, k = map(int, stdin.readline().split())
d = 1 if stdin.readline()[6] == 'l' else -1
m = 1 if m < k else n
for i, c in enumerate(stdin.readline(), 1):
if c == '0':
if k == 1: k, d = 2, 1
elif k == n: k, d = n - 1, -1
else: k += d
if m == k:
stdout.write('Controller ' + str(i))
exit(0)
else:
if k == 1: k, d, m = 2, 1, 1
elif k == n: k, d, m = n - 1, -1, n
elif d == 1:
k += 1
m = 1
else:
k -= 1
m = n
stdout.write('Stowaway')
``` | output | 1 | 76,357 | 1 | 152,715 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A stowaway and a controller play the following game.
The train is represented by n wagons which are numbered with positive integers from 1 to n from the head to the tail. The stowaway and the controller are initially in some two different wagons. Every minute the train can be in one of two conditions — moving or idle. Every minute the players move.
The controller's move is as follows. The controller has the movement direction — to the train's head or to its tail. During a move the controller moves to the neighbouring wagon correspondingly to its movement direction. If at the end of his move the controller enters the 1-st or the n-th wagon, that he changes the direction of his movement into the other one. In other words, the controller cyclically goes from the train's head to its tail and back again during all the time of a game, shifting during each move by one wagon. Note, that the controller always have exactly one possible move.
The stowaway's move depends from the state of the train. If the train is moving, then the stowaway can shift to one of neighbouring wagons or he can stay where he is without moving. If the train is at a station and is idle, then the stowaway leaves the train (i.e. he is now not present in any train wagon) and then, if it is not the terminal train station, he enters the train again into any of n wagons (not necessarily into the one he's just left and not necessarily into the neighbouring one). If the train is idle for several minutes then each such minute the stowaway leaves the train and enters it back.
Let's determine the order of the players' moves. If at the given minute the train is moving, then first the stowaway moves and then the controller does. If at this minute the train is idle, then first the stowaway leaves the train, then the controller moves and then the stowaway enters the train.
If at some point in time the stowaway and the controller happen to be in one wagon, then the controller wins: he makes the stowaway pay fine. If after a while the stowaway reaches the terminal train station, then the stowaway wins: he simply leaves the station during his move and never returns there again.
At any moment of time the players know each other's positions. The players play in the optimal way. Specifically, if the controller wins, then the stowaway plays so as to lose as late as possible. As all the possible moves for the controller are determined uniquely, then he is considered to play optimally always. Determine the winner.
Input
The first line contains three integers n, m and k. They represent the number of wagons in the train, the stowaway's and the controller's initial positions correspondingly (2 ≤ n ≤ 50, 1 ≤ m, k ≤ n, m ≠ k).
The second line contains the direction in which a controller moves. "to head" means that the controller moves to the train's head and "to tail" means that the controller moves to its tail. It is guaranteed that in the direction in which the controller is moving, there is at least one wagon. Wagon 1 is the head, and wagon n is the tail.
The third line has the length from 1 to 200 and consists of symbols "0" and "1". The i-th symbol contains information about the train's state at the i-th minute of time. "0" means that in this very minute the train moves and "1" means that the train in this very minute stands idle. The last symbol of the third line is always "1" — that's the terminal train station.
Output
If the stowaway wins, print "Stowaway" without quotes. Otherwise, print "Controller" again without quotes, then, separated by a space, print the number of a minute, at which the stowaway will be caught.
Examples
Input
5 3 2
to head
0001001
Output
Stowaway
Input
3 2 1
to tail
0001
Output
Controller 2
Submitted Solution:
```
# вводим кол-во вагонов, начальное положение зайца и контролера
n, z1, k1 = map(int, input().split())
z1 -= 1
k1 -= 1
# вводим направление
s = input()
# направление контролера
if (s == 'to head'):
napr = -1
else:
napr = 1
# вводим состояние электрички
s = input()
# условие проверки встречи зайца и контролера
for i in range(len(s)):
# если заяц и контролер в одном вагоне
if (k1 == z1):
print('Controller', i)
exit(0)
# если электричка движется
if (s[i] == '0'):
# если контролер ближе к хвосту и заяц не в голове, заяц ходит ближе к голове
if (k1 > z1 and z1 != 0):
z1 -= 1
# если заяц ближе к хвосту, но не в конце, заяц ходит ближе к хвосту
elif (k1 < z1 and z1 != n - 1):
z1 += 1
# шаг контролера
k1 += napr
# если контролер дошел до края поезда, поменять направление
if (k1 == 0 or k1 == n - 1):
napr = -napr
else:
# шаг контролера
k1 += napr
# если контролер дошел до края поезда, поменять направление
if (k1 == 0 or k1 == n - 1):
napr = -napr
# если контролер в голове, заяц в хвосте
if (k1 == 0):
z1 = n - 1
# если контролер в хвосте, заяц в голове
elif (k1 == n - 1):
z1 = 0
# если направление к хвосту и контролер не в голове, заяц в голове
elif (napr == 1 and k1 != 0):
z1 = 0
else:
z1 = n - 1
# если заяц и контролер в одном вагоне
if (k1 == z1):
print('Controller', i + 1)
exit(0)
print('Stowaway')
``` | instruction | 0 | 76,358 | 1 | 152,716 |
Yes | output | 1 | 76,358 | 1 | 152,717 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A stowaway and a controller play the following game.
The train is represented by n wagons which are numbered with positive integers from 1 to n from the head to the tail. The stowaway and the controller are initially in some two different wagons. Every minute the train can be in one of two conditions — moving or idle. Every minute the players move.
The controller's move is as follows. The controller has the movement direction — to the train's head or to its tail. During a move the controller moves to the neighbouring wagon correspondingly to its movement direction. If at the end of his move the controller enters the 1-st or the n-th wagon, that he changes the direction of his movement into the other one. In other words, the controller cyclically goes from the train's head to its tail and back again during all the time of a game, shifting during each move by one wagon. Note, that the controller always have exactly one possible move.
The stowaway's move depends from the state of the train. If the train is moving, then the stowaway can shift to one of neighbouring wagons or he can stay where he is without moving. If the train is at a station and is idle, then the stowaway leaves the train (i.e. he is now not present in any train wagon) and then, if it is not the terminal train station, he enters the train again into any of n wagons (not necessarily into the one he's just left and not necessarily into the neighbouring one). If the train is idle for several minutes then each such minute the stowaway leaves the train and enters it back.
Let's determine the order of the players' moves. If at the given minute the train is moving, then first the stowaway moves and then the controller does. If at this minute the train is idle, then first the stowaway leaves the train, then the controller moves and then the stowaway enters the train.
If at some point in time the stowaway and the controller happen to be in one wagon, then the controller wins: he makes the stowaway pay fine. If after a while the stowaway reaches the terminal train station, then the stowaway wins: he simply leaves the station during his move and never returns there again.
At any moment of time the players know each other's positions. The players play in the optimal way. Specifically, if the controller wins, then the stowaway plays so as to lose as late as possible. As all the possible moves for the controller are determined uniquely, then he is considered to play optimally always. Determine the winner.
Input
The first line contains three integers n, m and k. They represent the number of wagons in the train, the stowaway's and the controller's initial positions correspondingly (2 ≤ n ≤ 50, 1 ≤ m, k ≤ n, m ≠ k).
The second line contains the direction in which a controller moves. "to head" means that the controller moves to the train's head and "to tail" means that the controller moves to its tail. It is guaranteed that in the direction in which the controller is moving, there is at least one wagon. Wagon 1 is the head, and wagon n is the tail.
The third line has the length from 1 to 200 and consists of symbols "0" and "1". The i-th symbol contains information about the train's state at the i-th minute of time. "0" means that in this very minute the train moves and "1" means that the train in this very minute stands idle. The last symbol of the third line is always "1" — that's the terminal train station.
Output
If the stowaway wins, print "Stowaway" without quotes. Otherwise, print "Controller" again without quotes, then, separated by a space, print the number of a minute, at which the stowaway will be caught.
Examples
Input
5 3 2
to head
0001001
Output
Stowaway
Input
3 2 1
to tail
0001
Output
Controller 2
Submitted Solution:
```
n, z1, k1 = map(int, input().split())
z1 -= 1
k1 -= 1
s = input()
if (s == 'to head'):
napr = -1
else:
napr = 1
s = input()
for i in range(len(s)):
if (k1 == z1):
print('Controller', i)
exit(0)
if (s[i] == '0'):
if (k1 > z1 and z1 != 0):
z1 -= 1
elif (k1 < z1 and z1 != n - 1):
z1 += 1
k1 += napr
if (k1 == 0 or k1 == n - 1):
napr = -napr
else:
k1 += napr
if (k1 == 0 or k1 == n - 1):
napr = -napr
if (k1 == 0):
z1 = n - 1
elif (k1 == n - 1):
z1 = 0
elif (napr == 1 and k1 != 0):
z1 = 0
else:
z1 = n - 1
#print(z1 + 1, k1 + 1)
if (k1 == z1):
print('Controller', i + 1)
exit(0)
print('Stowaway')
# Made By Mostafa_Khaled
``` | instruction | 0 | 76,359 | 1 | 152,718 |
Yes | output | 1 | 76,359 | 1 | 152,719 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A stowaway and a controller play the following game.
The train is represented by n wagons which are numbered with positive integers from 1 to n from the head to the tail. The stowaway and the controller are initially in some two different wagons. Every minute the train can be in one of two conditions — moving or idle. Every minute the players move.
The controller's move is as follows. The controller has the movement direction — to the train's head or to its tail. During a move the controller moves to the neighbouring wagon correspondingly to its movement direction. If at the end of his move the controller enters the 1-st or the n-th wagon, that he changes the direction of his movement into the other one. In other words, the controller cyclically goes from the train's head to its tail and back again during all the time of a game, shifting during each move by one wagon. Note, that the controller always have exactly one possible move.
The stowaway's move depends from the state of the train. If the train is moving, then the stowaway can shift to one of neighbouring wagons or he can stay where he is without moving. If the train is at a station and is idle, then the stowaway leaves the train (i.e. he is now not present in any train wagon) and then, if it is not the terminal train station, he enters the train again into any of n wagons (not necessarily into the one he's just left and not necessarily into the neighbouring one). If the train is idle for several minutes then each such minute the stowaway leaves the train and enters it back.
Let's determine the order of the players' moves. If at the given minute the train is moving, then first the stowaway moves and then the controller does. If at this minute the train is idle, then first the stowaway leaves the train, then the controller moves and then the stowaway enters the train.
If at some point in time the stowaway and the controller happen to be in one wagon, then the controller wins: he makes the stowaway pay fine. If after a while the stowaway reaches the terminal train station, then the stowaway wins: he simply leaves the station during his move and never returns there again.
At any moment of time the players know each other's positions. The players play in the optimal way. Specifically, if the controller wins, then the stowaway plays so as to lose as late as possible. As all the possible moves for the controller are determined uniquely, then he is considered to play optimally always. Determine the winner.
Input
The first line contains three integers n, m and k. They represent the number of wagons in the train, the stowaway's and the controller's initial positions correspondingly (2 ≤ n ≤ 50, 1 ≤ m, k ≤ n, m ≠ k).
The second line contains the direction in which a controller moves. "to head" means that the controller moves to the train's head and "to tail" means that the controller moves to its tail. It is guaranteed that in the direction in which the controller is moving, there is at least one wagon. Wagon 1 is the head, and wagon n is the tail.
The third line has the length from 1 to 200 and consists of symbols "0" and "1". The i-th symbol contains information about the train's state at the i-th minute of time. "0" means that in this very minute the train moves and "1" means that the train in this very minute stands idle. The last symbol of the third line is always "1" — that's the terminal train station.
Output
If the stowaway wins, print "Stowaway" without quotes. Otherwise, print "Controller" again without quotes, then, separated by a space, print the number of a minute, at which the stowaway will be caught.
Examples
Input
5 3 2
to head
0001001
Output
Stowaway
Input
3 2 1
to tail
0001
Output
Controller 2
Submitted Solution:
```
n,m,k=list(map(int,input().split()))
a={'to head':-1, 'to tail':1}[input()]
b=input()
l=len(b)
for i in range(l-1):
if b[i]=='0':
if k+a==m:
if 1<=m+a<=n:
m+=a
else:
print('Controller',i+1)
break
else:
if a==-1:
m=n
else:
m=1
if not(1<=k+a<=n):
a=-a
k+=a
else:
print('Stowaway')
``` | instruction | 0 | 76,360 | 1 | 152,720 |
No | output | 1 | 76,360 | 1 | 152,721 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A stowaway and a controller play the following game.
The train is represented by n wagons which are numbered with positive integers from 1 to n from the head to the tail. The stowaway and the controller are initially in some two different wagons. Every minute the train can be in one of two conditions — moving or idle. Every minute the players move.
The controller's move is as follows. The controller has the movement direction — to the train's head or to its tail. During a move the controller moves to the neighbouring wagon correspondingly to its movement direction. If at the end of his move the controller enters the 1-st or the n-th wagon, that he changes the direction of his movement into the other one. In other words, the controller cyclically goes from the train's head to its tail and back again during all the time of a game, shifting during each move by one wagon. Note, that the controller always have exactly one possible move.
The stowaway's move depends from the state of the train. If the train is moving, then the stowaway can shift to one of neighbouring wagons or he can stay where he is without moving. If the train is at a station and is idle, then the stowaway leaves the train (i.e. he is now not present in any train wagon) and then, if it is not the terminal train station, he enters the train again into any of n wagons (not necessarily into the one he's just left and not necessarily into the neighbouring one). If the train is idle for several minutes then each such minute the stowaway leaves the train and enters it back.
Let's determine the order of the players' moves. If at the given minute the train is moving, then first the stowaway moves and then the controller does. If at this minute the train is idle, then first the stowaway leaves the train, then the controller moves and then the stowaway enters the train.
If at some point in time the stowaway and the controller happen to be in one wagon, then the controller wins: he makes the stowaway pay fine. If after a while the stowaway reaches the terminal train station, then the stowaway wins: he simply leaves the station during his move and never returns there again.
At any moment of time the players know each other's positions. The players play in the optimal way. Specifically, if the controller wins, then the stowaway plays so as to lose as late as possible. As all the possible moves for the controller are determined uniquely, then he is considered to play optimally always. Determine the winner.
Input
The first line contains three integers n, m and k. They represent the number of wagons in the train, the stowaway's and the controller's initial positions correspondingly (2 ≤ n ≤ 50, 1 ≤ m, k ≤ n, m ≠ k).
The second line contains the direction in which a controller moves. "to head" means that the controller moves to the train's head and "to tail" means that the controller moves to its tail. It is guaranteed that in the direction in which the controller is moving, there is at least one wagon. Wagon 1 is the head, and wagon n is the tail.
The third line has the length from 1 to 200 and consists of symbols "0" and "1". The i-th symbol contains information about the train's state at the i-th minute of time. "0" means that in this very minute the train moves and "1" means that the train in this very minute stands idle. The last symbol of the third line is always "1" — that's the terminal train station.
Output
If the stowaway wins, print "Stowaway" without quotes. Otherwise, print "Controller" again without quotes, then, separated by a space, print the number of a minute, at which the stowaway will be caught.
Examples
Input
5 3 2
to head
0001001
Output
Stowaway
Input
3 2 1
to tail
0001
Output
Controller 2
Submitted Solution:
```
n,m,k=list(map(int,input().split()))
a={'to head':-1, 'to tail':1}[input()]
b=input()
l=len(b)
for i in range(l-1):
if b[i]=='0':
if k+a==m:
if 1<=m+a<=n:
m+=a
else:
print('Controller',i+1)
break
else:
if a==-1 and k!=1 or a==1 and k==n:
m=n
else:
m=1
if not(1<=k+a<=n):
a=-a
k+=a
else:
print('Stowaway')
``` | instruction | 0 | 76,361 | 1 | 152,722 |
No | output | 1 | 76,361 | 1 | 152,723 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A stowaway and a controller play the following game.
The train is represented by n wagons which are numbered with positive integers from 1 to n from the head to the tail. The stowaway and the controller are initially in some two different wagons. Every minute the train can be in one of two conditions — moving or idle. Every minute the players move.
The controller's move is as follows. The controller has the movement direction — to the train's head or to its tail. During a move the controller moves to the neighbouring wagon correspondingly to its movement direction. If at the end of his move the controller enters the 1-st or the n-th wagon, that he changes the direction of his movement into the other one. In other words, the controller cyclically goes from the train's head to its tail and back again during all the time of a game, shifting during each move by one wagon. Note, that the controller always have exactly one possible move.
The stowaway's move depends from the state of the train. If the train is moving, then the stowaway can shift to one of neighbouring wagons or he can stay where he is without moving. If the train is at a station and is idle, then the stowaway leaves the train (i.e. he is now not present in any train wagon) and then, if it is not the terminal train station, he enters the train again into any of n wagons (not necessarily into the one he's just left and not necessarily into the neighbouring one). If the train is idle for several minutes then each such minute the stowaway leaves the train and enters it back.
Let's determine the order of the players' moves. If at the given minute the train is moving, then first the stowaway moves and then the controller does. If at this minute the train is idle, then first the stowaway leaves the train, then the controller moves and then the stowaway enters the train.
If at some point in time the stowaway and the controller happen to be in one wagon, then the controller wins: he makes the stowaway pay fine. If after a while the stowaway reaches the terminal train station, then the stowaway wins: he simply leaves the station during his move and never returns there again.
At any moment of time the players know each other's positions. The players play in the optimal way. Specifically, if the controller wins, then the stowaway plays so as to lose as late as possible. As all the possible moves for the controller are determined uniquely, then he is considered to play optimally always. Determine the winner.
Input
The first line contains three integers n, m and k. They represent the number of wagons in the train, the stowaway's and the controller's initial positions correspondingly (2 ≤ n ≤ 50, 1 ≤ m, k ≤ n, m ≠ k).
The second line contains the direction in which a controller moves. "to head" means that the controller moves to the train's head and "to tail" means that the controller moves to its tail. It is guaranteed that in the direction in which the controller is moving, there is at least one wagon. Wagon 1 is the head, and wagon n is the tail.
The third line has the length from 1 to 200 and consists of symbols "0" and "1". The i-th symbol contains information about the train's state at the i-th minute of time. "0" means that in this very minute the train moves and "1" means that the train in this very minute stands idle. The last symbol of the third line is always "1" — that's the terminal train station.
Output
If the stowaway wins, print "Stowaway" without quotes. Otherwise, print "Controller" again without quotes, then, separated by a space, print the number of a minute, at which the stowaway will be caught.
Examples
Input
5 3 2
to head
0001001
Output
Stowaway
Input
3 2 1
to tail
0001
Output
Controller 2
Submitted Solution:
```
n, m, k = map(int, input().split())
s=input()
ans=True
l2=input()
if s[3]=='h':
dr=0
else:
dr=1
for i in range(len(l2)):
if l2[i]=='1':
if k==n or k==0:
dr=dr+1%2
if dr==0:
k-=1
else:
k+=1
if dr==1:
if k!=1:
m=1
else:
m=n
elif dr==0:
if k!=m:
m=n
else:
m=1
if dr==0 and m<k:
if m>1:
m-=1
if dr==0 and m>k:
if m<n:
m+=1
if dr==1 and m<k:
if m>1:
m-=1
if dr==1 and m>k:
if m<n:
m+=1
if m==k:
ans=False
break
if k==n or k==0:
dr=dr+1%2
if dr==0:
k-=1
else:
k+=1
if m==k:
ans=False
time=i
break
if ans==False:
print("Controller {0}".format(i+1))
else:
print("Stowaway")
``` | instruction | 0 | 76,362 | 1 | 152,724 |
No | output | 1 | 76,362 | 1 | 152,725 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A stowaway and a controller play the following game.
The train is represented by n wagons which are numbered with positive integers from 1 to n from the head to the tail. The stowaway and the controller are initially in some two different wagons. Every minute the train can be in one of two conditions — moving or idle. Every minute the players move.
The controller's move is as follows. The controller has the movement direction — to the train's head or to its tail. During a move the controller moves to the neighbouring wagon correspondingly to its movement direction. If at the end of his move the controller enters the 1-st or the n-th wagon, that he changes the direction of his movement into the other one. In other words, the controller cyclically goes from the train's head to its tail and back again during all the time of a game, shifting during each move by one wagon. Note, that the controller always have exactly one possible move.
The stowaway's move depends from the state of the train. If the train is moving, then the stowaway can shift to one of neighbouring wagons or he can stay where he is without moving. If the train is at a station and is idle, then the stowaway leaves the train (i.e. he is now not present in any train wagon) and then, if it is not the terminal train station, he enters the train again into any of n wagons (not necessarily into the one he's just left and not necessarily into the neighbouring one). If the train is idle for several minutes then each such minute the stowaway leaves the train and enters it back.
Let's determine the order of the players' moves. If at the given minute the train is moving, then first the stowaway moves and then the controller does. If at this minute the train is idle, then first the stowaway leaves the train, then the controller moves and then the stowaway enters the train.
If at some point in time the stowaway and the controller happen to be in one wagon, then the controller wins: he makes the stowaway pay fine. If after a while the stowaway reaches the terminal train station, then the stowaway wins: he simply leaves the station during his move and never returns there again.
At any moment of time the players know each other's positions. The players play in the optimal way. Specifically, if the controller wins, then the stowaway plays so as to lose as late as possible. As all the possible moves for the controller are determined uniquely, then he is considered to play optimally always. Determine the winner.
Input
The first line contains three integers n, m and k. They represent the number of wagons in the train, the stowaway's and the controller's initial positions correspondingly (2 ≤ n ≤ 50, 1 ≤ m, k ≤ n, m ≠ k).
The second line contains the direction in which a controller moves. "to head" means that the controller moves to the train's head and "to tail" means that the controller moves to its tail. It is guaranteed that in the direction in which the controller is moving, there is at least one wagon. Wagon 1 is the head, and wagon n is the tail.
The third line has the length from 1 to 200 and consists of symbols "0" and "1". The i-th symbol contains information about the train's state at the i-th minute of time. "0" means that in this very minute the train moves and "1" means that the train in this very minute stands idle. The last symbol of the third line is always "1" — that's the terminal train station.
Output
If the stowaway wins, print "Stowaway" without quotes. Otherwise, print "Controller" again without quotes, then, separated by a space, print the number of a minute, at which the stowaway will be caught.
Examples
Input
5 3 2
to head
0001001
Output
Stowaway
Input
3 2 1
to tail
0001
Output
Controller 2
Submitted Solution:
```
from sys import stdin, stdout, exit
n, m, k = map(int, stdin.readline().split())
if stdin.readline()[-1] == 'l': d, m = 1, n if k == 1 else 1
else: d, m = -1, 1 if k == n else n
for i, c in enumerate(stdin.readline(), 1):
if c == '0':
if k == 1: k, d = 2, 1
elif k == n: k, d = n - 1, -1
else: k += d
if m == k:
stdout.write('Controller ' + str(i))
exit(0)
else:
if k == 1: k, d, m = 2, 1, 1
elif k == n: k, d, m = n - 1, -1, n
elif d == 1:
k += 1
m = 1
else:
k -= 1
m = n
stdout.write('Stowaway')
``` | instruction | 0 | 76,363 | 1 | 152,726 |
No | output | 1 | 76,363 | 1 | 152,727 |
Provide a correct Python 3 solution for this coding contest problem.
There is a circular pond with a perimeter of K meters, and N houses around them.
The i-th house is built at a distance of A_i meters from the northmost point of the pond, measured clockwise around the pond.
When traveling between these houses, you can only go around the pond.
Find the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Constraints
* 2 \leq K \leq 10^6
* 2 \leq N \leq 2 \times 10^5
* 0 \leq A_1 < ... < A_N < K
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
K N
A_1 A_2 ... A_N
Output
Print the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Examples
Input
20 3
5 10 15
Output
10
Input
20 3
0 5 15
Output
10 | instruction | 0 | 76,473 | 1 | 152,946 |
"Correct Solution:
```
K,N=map(int,input().split())
*A,=sorted(map(int,input().split()))
print(K-max([*[A[i+1]-A[i] for i in range(N-1)], A[0]+(K-A[-1])]))
``` | output | 1 | 76,473 | 1 | 152,947 |
Provide a correct Python 3 solution for this coding contest problem.
There is a circular pond with a perimeter of K meters, and N houses around them.
The i-th house is built at a distance of A_i meters from the northmost point of the pond, measured clockwise around the pond.
When traveling between these houses, you can only go around the pond.
Find the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Constraints
* 2 \leq K \leq 10^6
* 2 \leq N \leq 2 \times 10^5
* 0 \leq A_1 < ... < A_N < K
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
K N
A_1 A_2 ... A_N
Output
Print the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Examples
Input
20 3
5 10 15
Output
10
Input
20 3
0 5 15
Output
10 | instruction | 0 | 76,474 | 1 | 152,948 |
"Correct Solution:
```
f=lambda:[*map(int,input().split())]
k,n=f()
l=f()
l+=[l[0]+k]
a=0
for i in range(n):
a=max(a,l[i+1]-l[i])
print(k-a)
``` | output | 1 | 76,474 | 1 | 152,949 |
Provide a correct Python 3 solution for this coding contest problem.
There is a circular pond with a perimeter of K meters, and N houses around them.
The i-th house is built at a distance of A_i meters from the northmost point of the pond, measured clockwise around the pond.
When traveling between these houses, you can only go around the pond.
Find the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Constraints
* 2 \leq K \leq 10^6
* 2 \leq N \leq 2 \times 10^5
* 0 \leq A_1 < ... < A_N < K
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
K N
A_1 A_2 ... A_N
Output
Print the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Examples
Input
20 3
5 10 15
Output
10
Input
20 3
0 5 15
Output
10 | instruction | 0 | 76,475 | 1 | 152,950 |
"Correct Solution:
```
k,n,*l=map(int,open(0).read().split())
print(k-max((l[i]-l[i-1])%k for i in range(n)))
``` | output | 1 | 76,475 | 1 | 152,951 |
Provide a correct Python 3 solution for this coding contest problem.
There is a circular pond with a perimeter of K meters, and N houses around them.
The i-th house is built at a distance of A_i meters from the northmost point of the pond, measured clockwise around the pond.
When traveling between these houses, you can only go around the pond.
Find the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Constraints
* 2 \leq K \leq 10^6
* 2 \leq N \leq 2 \times 10^5
* 0 \leq A_1 < ... < A_N < K
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
K N
A_1 A_2 ... A_N
Output
Print the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Examples
Input
20 3
5 10 15
Output
10
Input
20 3
0 5 15
Output
10 | instruction | 0 | 76,476 | 1 | 152,952 |
"Correct Solution:
```
K,N = map(int,input().split())
A = list(map(int,input().split()))
D=[A[0]-A[-1]+K]
for i in range(N-1):
D.append(A[i+1]-A[i])
print(K-max(D))
``` | output | 1 | 76,476 | 1 | 152,953 |
Provide a correct Python 3 solution for this coding contest problem.
There is a circular pond with a perimeter of K meters, and N houses around them.
The i-th house is built at a distance of A_i meters from the northmost point of the pond, measured clockwise around the pond.
When traveling between these houses, you can only go around the pond.
Find the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Constraints
* 2 \leq K \leq 10^6
* 2 \leq N \leq 2 \times 10^5
* 0 \leq A_1 < ... < A_N < K
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
K N
A_1 A_2 ... A_N
Output
Print the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Examples
Input
20 3
5 10 15
Output
10
Input
20 3
0 5 15
Output
10 | instruction | 0 | 76,477 | 1 | 152,954 |
"Correct Solution:
```
k,n=list(map(int,input().split()))
A=list(map(int,input().split()))
l=[k-A[-1]+A[0]]
[l.append(A[i+1]-A[i]) for i in range(n-1)]
print(k-max(l))
``` | output | 1 | 76,477 | 1 | 152,955 |
Provide a correct Python 3 solution for this coding contest problem.
There is a circular pond with a perimeter of K meters, and N houses around them.
The i-th house is built at a distance of A_i meters from the northmost point of the pond, measured clockwise around the pond.
When traveling between these houses, you can only go around the pond.
Find the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Constraints
* 2 \leq K \leq 10^6
* 2 \leq N \leq 2 \times 10^5
* 0 \leq A_1 < ... < A_N < K
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
K N
A_1 A_2 ... A_N
Output
Print the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Examples
Input
20 3
5 10 15
Output
10
Input
20 3
0 5 15
Output
10 | instruction | 0 | 76,478 | 1 | 152,956 |
"Correct Solution:
```
k,n=map(int,input().split())
a=list(map(int,input().split()))
p=a[0]+k-a[-1]
for i in range(n-1):
s=a[i+1]-a[i]
p=max([p,s])
print(k-p)
``` | output | 1 | 76,478 | 1 | 152,957 |
Provide a correct Python 3 solution for this coding contest problem.
There is a circular pond with a perimeter of K meters, and N houses around them.
The i-th house is built at a distance of A_i meters from the northmost point of the pond, measured clockwise around the pond.
When traveling between these houses, you can only go around the pond.
Find the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Constraints
* 2 \leq K \leq 10^6
* 2 \leq N \leq 2 \times 10^5
* 0 \leq A_1 < ... < A_N < K
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
K N
A_1 A_2 ... A_N
Output
Print the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Examples
Input
20 3
5 10 15
Output
10
Input
20 3
0 5 15
Output
10 | instruction | 0 | 76,479 | 1 | 152,958 |
"Correct Solution:
```
k,n,*a=map(int,open(0).read().split())
a+=[a[0]+k]
d=[abs(a[i]-a[i+1]) for i in range(n)]
print(k-max(d))
``` | output | 1 | 76,479 | 1 | 152,959 |
Provide a correct Python 3 solution for this coding contest problem.
There is a circular pond with a perimeter of K meters, and N houses around them.
The i-th house is built at a distance of A_i meters from the northmost point of the pond, measured clockwise around the pond.
When traveling between these houses, you can only go around the pond.
Find the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Constraints
* 2 \leq K \leq 10^6
* 2 \leq N \leq 2 \times 10^5
* 0 \leq A_1 < ... < A_N < K
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
K N
A_1 A_2 ... A_N
Output
Print the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Examples
Input
20 3
5 10 15
Output
10
Input
20 3
0 5 15
Output
10 | instruction | 0 | 76,480 | 1 | 152,960 |
"Correct Solution:
```
k,n=map(int,input().split())
a=list(map(int,input().split()))
a.append(a[0]+k)
ans=0
for i in range(n):
ans=max(ans,a[i+1]-a[i])
print(k-ans)
``` | output | 1 | 76,480 | 1 | 152,961 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a circular pond with a perimeter of K meters, and N houses around them.
The i-th house is built at a distance of A_i meters from the northmost point of the pond, measured clockwise around the pond.
When traveling between these houses, you can only go around the pond.
Find the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Constraints
* 2 \leq K \leq 10^6
* 2 \leq N \leq 2 \times 10^5
* 0 \leq A_1 < ... < A_N < K
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
K N
A_1 A_2 ... A_N
Output
Print the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Examples
Input
20 3
5 10 15
Output
10
Input
20 3
0 5 15
Output
10
Submitted Solution:
```
K, N = map(int, input().split())
A = [int(a) for a in input().split()]
A.append(A[0] + K)
print(K - max([A[i+1] - A[i] for i in range(N)]))
``` | instruction | 0 | 76,481 | 1 | 152,962 |
Yes | output | 1 | 76,481 | 1 | 152,963 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a circular pond with a perimeter of K meters, and N houses around them.
The i-th house is built at a distance of A_i meters from the northmost point of the pond, measured clockwise around the pond.
When traveling between these houses, you can only go around the pond.
Find the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Constraints
* 2 \leq K \leq 10^6
* 2 \leq N \leq 2 \times 10^5
* 0 \leq A_1 < ... < A_N < K
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
K N
A_1 A_2 ... A_N
Output
Print the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Examples
Input
20 3
5 10 15
Output
10
Input
20 3
0 5 15
Output
10
Submitted Solution:
```
k, n, *aa = map(int, open(0).read().split())
aa.append(k+aa[0])
print(k - max(a - b for a, b in zip(aa[1:], aa[:-1])))
``` | instruction | 0 | 76,482 | 1 | 152,964 |
Yes | output | 1 | 76,482 | 1 | 152,965 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a circular pond with a perimeter of K meters, and N houses around them.
The i-th house is built at a distance of A_i meters from the northmost point of the pond, measured clockwise around the pond.
When traveling between these houses, you can only go around the pond.
Find the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Constraints
* 2 \leq K \leq 10^6
* 2 \leq N \leq 2 \times 10^5
* 0 \leq A_1 < ... < A_N < K
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
K N
A_1 A_2 ... A_N
Output
Print the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Examples
Input
20 3
5 10 15
Output
10
Input
20 3
0 5 15
Output
10
Submitted Solution:
```
k, n = map(int, input().split())
a = list(map(int, input().split()))
a.append(k + a[0])
print(k - max(a[i + 1] - a[i] for i in range(n)))
``` | instruction | 0 | 76,483 | 1 | 152,966 |
Yes | output | 1 | 76,483 | 1 | 152,967 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a circular pond with a perimeter of K meters, and N houses around them.
The i-th house is built at a distance of A_i meters from the northmost point of the pond, measured clockwise around the pond.
When traveling between these houses, you can only go around the pond.
Find the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Constraints
* 2 \leq K \leq 10^6
* 2 \leq N \leq 2 \times 10^5
* 0 \leq A_1 < ... < A_N < K
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
K N
A_1 A_2 ... A_N
Output
Print the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Examples
Input
20 3
5 10 15
Output
10
Input
20 3
0 5 15
Output
10
Submitted Solution:
```
k,n = map(int,input().split())
a = list(map(int,input().split()))
d=a[0]+(k-a[n-1])
for i in range(1,n):
d=max(d,a[i]-a[i-1])
print(k-d)
``` | instruction | 0 | 76,484 | 1 | 152,968 |
Yes | output | 1 | 76,484 | 1 | 152,969 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a circular pond with a perimeter of K meters, and N houses around them.
The i-th house is built at a distance of A_i meters from the northmost point of the pond, measured clockwise around the pond.
When traveling between these houses, you can only go around the pond.
Find the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Constraints
* 2 \leq K \leq 10^6
* 2 \leq N \leq 2 \times 10^5
* 0 \leq A_1 < ... < A_N < K
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
K N
A_1 A_2 ... A_N
Output
Print the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Examples
Input
20 3
5 10 15
Output
10
Input
20 3
0 5 15
Output
10
Submitted Solution:
```
K, N = map(int, input().split())
A = list(map(int, input().split()))
distance = []
for i in range(N-1):
dis = A[i + 1] - A[i]
# if i == N - 1:
# dis = A[i] - A[1]
distance.append(dis)
dis = K - A[N - 1] + A[0]
distance.append(dis)
# print(distance)
# print(max(distance))
# print(distance.index(max(distance)))
sum = 0
count = int(len(distance))
for i in range(count):
if i != distance.index(max(distance)):
sum += distance[i]
print(sum)
``` | instruction | 0 | 76,485 | 1 | 152,970 |
No | output | 1 | 76,485 | 1 | 152,971 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a circular pond with a perimeter of K meters, and N houses around them.
The i-th house is built at a distance of A_i meters from the northmost point of the pond, measured clockwise around the pond.
When traveling between these houses, you can only go around the pond.
Find the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Constraints
* 2 \leq K \leq 10^6
* 2 \leq N \leq 2 \times 10^5
* 0 \leq A_1 < ... < A_N < K
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
K N
A_1 A_2 ... A_N
Output
Print the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Examples
Input
20 3
5 10 15
Output
10
Input
20 3
0 5 15
Output
10
Submitted Solution:
```
syu,n=map(int,input().split())
a=[int(i) for i in input().split()]
clock=a[n-1]-a[0]
han_clock=(a[n-2]-a[0])+(a[0]+syu-a[n-1])
print(min(clock,han_clock))
``` | instruction | 0 | 76,486 | 1 | 152,972 |
No | output | 1 | 76,486 | 1 | 152,973 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a circular pond with a perimeter of K meters, and N houses around them.
The i-th house is built at a distance of A_i meters from the northmost point of the pond, measured clockwise around the pond.
When traveling between these houses, you can only go around the pond.
Find the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Constraints
* 2 \leq K \leq 10^6
* 2 \leq N \leq 2 \times 10^5
* 0 \leq A_1 < ... < A_N < K
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
K N
A_1 A_2 ... A_N
Output
Print the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.
Examples
Input
20 3
5 10 15
Output
10
Input
20 3
0 5 15
Output
10
Submitted Solution:
```
k, n = map(int, input().split())
a = list(map(int, input().split()))
dist = []
dist.append([k-a[len(a)-1]+a[0], a[1]-a[0]])
for num in range(1, len(a)):
if num == len(a) - 1:
dist.append([a[num]-a[num-1], k-a[num]+a[0]])
else:
dist.append([a[num]-a[num-1], a[num+1]-a[num]])
#print(dist)
start = 0
result = []
while(start!=len(dist)):
right = 0
left = 0
for x in range(0, len(dist)-1):
n = start+x
if n > len(dist)-1:
n = (len(dist) - x - start) * -1
right += dist[n][1]
for y in range(0, len(dist)-1):
n = start-y
if n < 0:
n = len(dist)-y
left += dist[n][0]
result.append(min(right, left))
# print(right, left)
start += 1
print(min(result))
``` | instruction | 0 | 76,487 | 1 | 152,974 |
No | output | 1 | 76,487 | 1 | 152,975 |
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