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Provide tags and a correct Python 3 solution for this coding contest problem. You are given two positive integers a and b. In one move you can increase a by 1 (replace a with a+1). Your task is to find the minimum number of moves you need to do in order to make a divisible by b. It is possible, that you have to make 0 moves, as a is already divisible by b. You have to answer t independent test cases. Input The first line of the input contains one integer t (1 ≀ t ≀ 10^4) β€” the number of test cases. Then t test cases follow. The only line of the test case contains two integers a and b (1 ≀ a, b ≀ 10^9). Output For each test case print the answer β€” the minimum number of moves you need to do in order to make a divisible by b. Example Input 5 10 4 13 9 100 13 123 456 92 46 Output 2 5 4 333 0
instruction
0
34,423
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Tags: math Correct Solution: ``` t = int(input()) for i in range(t): a,b = map(int,input().split()) if a%b == 0: print(0) else: m = a // b print((b*(m+1)) - a) ```
output
1
34,423
22
68,847
Provide tags and a correct Python 3 solution for this coding contest problem. You are given two positive integers a and b. In one move you can increase a by 1 (replace a with a+1). Your task is to find the minimum number of moves you need to do in order to make a divisible by b. It is possible, that you have to make 0 moves, as a is already divisible by b. You have to answer t independent test cases. Input The first line of the input contains one integer t (1 ≀ t ≀ 10^4) β€” the number of test cases. Then t test cases follow. The only line of the test case contains two integers a and b (1 ≀ a, b ≀ 10^9). Output For each test case print the answer β€” the minimum number of moves you need to do in order to make a divisible by b. Example Input 5 10 4 13 9 100 13 123 456 92 46 Output 2 5 4 333 0
instruction
0
34,424
22
68,848
Tags: math Correct Solution: ``` t=int(input()) for i in range(0,t): y=input().split() a=int(y[0]) b=int(y[1]) m=a%b if m==0: print(m) else: print(b-m) ```
output
1
34,424
22
68,849
Provide tags and a correct Python 3 solution for this coding contest problem. You are given two positive integers a and b. In one move you can increase a by 1 (replace a with a+1). Your task is to find the minimum number of moves you need to do in order to make a divisible by b. It is possible, that you have to make 0 moves, as a is already divisible by b. You have to answer t independent test cases. Input The first line of the input contains one integer t (1 ≀ t ≀ 10^4) β€” the number of test cases. Then t test cases follow. The only line of the test case contains two integers a and b (1 ≀ a, b ≀ 10^9). Output For each test case print the answer β€” the minimum number of moves you need to do in order to make a divisible by b. Example Input 5 10 4 13 9 100 13 123 456 92 46 Output 2 5 4 333 0
instruction
0
34,425
22
68,850
Tags: math Correct Solution: ``` def incrementation(a,b): if a % b == 0: return 0 else: r = a % b return b-r testCases = int(input()) for i in range(testCases): a,b = map(int,input().split()) print(incrementation(a,b)) ```
output
1
34,425
22
68,851
Provide tags and a correct Python 3 solution for this coding contest problem. You are given two positive integers a and b. In one move you can increase a by 1 (replace a with a+1). Your task is to find the minimum number of moves you need to do in order to make a divisible by b. It is possible, that you have to make 0 moves, as a is already divisible by b. You have to answer t independent test cases. Input The first line of the input contains one integer t (1 ≀ t ≀ 10^4) β€” the number of test cases. Then t test cases follow. The only line of the test case contains two integers a and b (1 ≀ a, b ≀ 10^9). Output For each test case print the answer β€” the minimum number of moves you need to do in order to make a divisible by b. Example Input 5 10 4 13 9 100 13 123 456 92 46 Output 2 5 4 333 0
instruction
0
34,426
22
68,852
Tags: math Correct Solution: ``` t=int(input()) while t>0: t-=1 a,b=map(int,input().split()) c=a//b d=a%b if d==0: print(0) else: print((c+1)*b-a) ```
output
1
34,426
22
68,853
Provide tags and a correct Python 3 solution for this coding contest problem. You are given two positive integers a and b. In one move you can increase a by 1 (replace a with a+1). Your task is to find the minimum number of moves you need to do in order to make a divisible by b. It is possible, that you have to make 0 moves, as a is already divisible by b. You have to answer t independent test cases. Input The first line of the input contains one integer t (1 ≀ t ≀ 10^4) β€” the number of test cases. Then t test cases follow. The only line of the test case contains two integers a and b (1 ≀ a, b ≀ 10^9). Output For each test case print the answer β€” the minimum number of moves you need to do in order to make a divisible by b. Example Input 5 10 4 13 9 100 13 123 456 92 46 Output 2 5 4 333 0
instruction
0
34,427
22
68,854
Tags: math Correct Solution: ``` for i in range(int(input())): a,b = map(int,input().split()) if a%b == 0 : print(0) else: print(b - a % b) ```
output
1
34,427
22
68,855
Provide tags and a correct Python 3 solution for this coding contest problem. You are given two positive integers a and b. In one move you can increase a by 1 (replace a with a+1). Your task is to find the minimum number of moves you need to do in order to make a divisible by b. It is possible, that you have to make 0 moves, as a is already divisible by b. You have to answer t independent test cases. Input The first line of the input contains one integer t (1 ≀ t ≀ 10^4) β€” the number of test cases. Then t test cases follow. The only line of the test case contains two integers a and b (1 ≀ a, b ≀ 10^9). Output For each test case print the answer β€” the minimum number of moves you need to do in order to make a divisible by b. Example Input 5 10 4 13 9 100 13 123 456 92 46 Output 2 5 4 333 0
instruction
0
34,428
22
68,856
Tags: math Correct Solution: ``` n = int(input()) steps = [] for i in range(n): a, b = map(int, input().split()) if a%b != 0: step = (((a//b)+1)*b)-a steps.append(step) else: steps.append(0) for i in steps: print(i) ```
output
1
34,428
22
68,857
Provide tags and a correct Python 3 solution for this coding contest problem. You are given two positive integers a and b. In one move you can increase a by 1 (replace a with a+1). Your task is to find the minimum number of moves you need to do in order to make a divisible by b. It is possible, that you have to make 0 moves, as a is already divisible by b. You have to answer t independent test cases. Input The first line of the input contains one integer t (1 ≀ t ≀ 10^4) β€” the number of test cases. Then t test cases follow. The only line of the test case contains two integers a and b (1 ≀ a, b ≀ 10^9). Output For each test case print the answer β€” the minimum number of moves you need to do in order to make a divisible by b. Example Input 5 10 4 13 9 100 13 123 456 92 46 Output 2 5 4 333 0
instruction
0
34,429
22
68,858
Tags: math Correct Solution: ``` for t in range(int(input())): a,b=map(int,input().split()) if a<=b: print(b-a) else: if a%b==0: print(0) else: v=a//b+1 print(b*v-a) ```
output
1
34,429
22
68,859
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given two positive integers a and b. In one move you can increase a by 1 (replace a with a+1). Your task is to find the minimum number of moves you need to do in order to make a divisible by b. It is possible, that you have to make 0 moves, as a is already divisible by b. You have to answer t independent test cases. Input The first line of the input contains one integer t (1 ≀ t ≀ 10^4) β€” the number of test cases. Then t test cases follow. The only line of the test case contains two integers a and b (1 ≀ a, b ≀ 10^9). Output For each test case print the answer β€” the minimum number of moves you need to do in order to make a divisible by b. Example Input 5 10 4 13 9 100 13 123 456 92 46 Output 2 5 4 333 0 Submitted Solution: ``` t = int(input()) matrix = [] answer_list = [] for _ in range(t): matrix.append(list(map(int, input().split()))) for row in range(len(matrix)): for col in range(1, len(matrix[row])): if matrix[row][col-1] % matrix[row][col] != 0: remainder = matrix[row][col-1] % matrix[row][col] answer = matrix[row][col]-remainder answer_list.append(answer) elif matrix[row][col-1] % matrix[row][col] == 0: answer = matrix[row][col-1] % matrix[row][col] answer_list.append(answer) for i in answer_list: print(i) ```
instruction
0
34,430
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68,860
Yes
output
1
34,430
22
68,861
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given two positive integers a and b. In one move you can increase a by 1 (replace a with a+1). Your task is to find the minimum number of moves you need to do in order to make a divisible by b. It is possible, that you have to make 0 moves, as a is already divisible by b. You have to answer t independent test cases. Input The first line of the input contains one integer t (1 ≀ t ≀ 10^4) β€” the number of test cases. Then t test cases follow. The only line of the test case contains two integers a and b (1 ≀ a, b ≀ 10^9). Output For each test case print the answer β€” the minimum number of moves you need to do in order to make a divisible by b. Example Input 5 10 4 13 9 100 13 123 456 92 46 Output 2 5 4 333 0 Submitted Solution: ``` for _ in range(int(input())): a,b=map(int,input().split()) if(a%b==0): print(0) else: n=a//b m=(a//b)*b+b-a print(m) ```
instruction
0
34,431
22
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Yes
output
1
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68,863
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given two positive integers a and b. In one move you can increase a by 1 (replace a with a+1). Your task is to find the minimum number of moves you need to do in order to make a divisible by b. It is possible, that you have to make 0 moves, as a is already divisible by b. You have to answer t independent test cases. Input The first line of the input contains one integer t (1 ≀ t ≀ 10^4) β€” the number of test cases. Then t test cases follow. The only line of the test case contains two integers a and b (1 ≀ a, b ≀ 10^9). Output For each test case print the answer β€” the minimum number of moves you need to do in order to make a divisible by b. Example Input 5 10 4 13 9 100 13 123 456 92 46 Output 2 5 4 333 0 Submitted Solution: ``` results = [] for _ in range(int(input())): a, b = map(int, input().split()) if a % b: results.append(str(b - a % b)) else: results.append('0') print('\n'.join(results)) ```
instruction
0
34,432
22
68,864
Yes
output
1
34,432
22
68,865
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given two positive integers a and b. In one move you can increase a by 1 (replace a with a+1). Your task is to find the minimum number of moves you need to do in order to make a divisible by b. It is possible, that you have to make 0 moves, as a is already divisible by b. You have to answer t independent test cases. Input The first line of the input contains one integer t (1 ≀ t ≀ 10^4) β€” the number of test cases. Then t test cases follow. The only line of the test case contains two integers a and b (1 ≀ a, b ≀ 10^9). Output For each test case print the answer β€” the minimum number of moves you need to do in order to make a divisible by b. Example Input 5 10 4 13 9 100 13 123 456 92 46 Output 2 5 4 333 0 Submitted Solution: ``` t=int(input()) for i in range(t): a,b=map(int,input().split()) if(a%b==0): print('0') else: print(b-(a%b)) ```
instruction
0
34,433
22
68,866
Yes
output
1
34,433
22
68,867
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given two positive integers a and b. In one move you can increase a by 1 (replace a with a+1). Your task is to find the minimum number of moves you need to do in order to make a divisible by b. It is possible, that you have to make 0 moves, as a is already divisible by b. You have to answer t independent test cases. Input The first line of the input contains one integer t (1 ≀ t ≀ 10^4) β€” the number of test cases. Then t test cases follow. The only line of the test case contains two integers a and b (1 ≀ a, b ≀ 10^9). Output For each test case print the answer β€” the minimum number of moves you need to do in order to make a divisible by b. Example Input 5 10 4 13 9 100 13 123 456 92 46 Output 2 5 4 333 0 Submitted Solution: ``` t=int(input()) while t>0: t-=1 n,k=input().split() n,k=int(n),int(k) if n>=k and n%2==k%2: print("YES") else: print("NO") ```
instruction
0
34,434
22
68,868
No
output
1
34,434
22
68,869
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given two positive integers a and b. In one move you can increase a by 1 (replace a with a+1). Your task is to find the minimum number of moves you need to do in order to make a divisible by b. It is possible, that you have to make 0 moves, as a is already divisible by b. You have to answer t independent test cases. Input The first line of the input contains one integer t (1 ≀ t ≀ 10^4) β€” the number of test cases. Then t test cases follow. The only line of the test case contains two integers a and b (1 ≀ a, b ≀ 10^9). Output For each test case print the answer β€” the minimum number of moves you need to do in order to make a divisible by b. Example Input 5 10 4 13 9 100 13 123 456 92 46 Output 2 5 4 333 0 Submitted Solution: ``` import sys def get_array(): return list(map(int , sys.stdin.readline().strip().split())) def get_ints(): return map(int, sys.stdin.readline().strip().split()) def input(): return sys.stdin.readline().strip() for _ in range(int(input())): a,b=get_ints() print(a%b) ```
instruction
0
34,435
22
68,870
No
output
1
34,435
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68,871
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given two positive integers a and b. In one move you can increase a by 1 (replace a with a+1). Your task is to find the minimum number of moves you need to do in order to make a divisible by b. It is possible, that you have to make 0 moves, as a is already divisible by b. You have to answer t independent test cases. Input The first line of the input contains one integer t (1 ≀ t ≀ 10^4) β€” the number of test cases. Then t test cases follow. The only line of the test case contains two integers a and b (1 ≀ a, b ≀ 10^9). Output For each test case print the answer β€” the minimum number of moves you need to do in order to make a divisible by b. Example Input 5 10 4 13 9 100 13 123 456 92 46 Output 2 5 4 333 0 Submitted Solution: ``` for i in range(int(input())): n,k = map(int,input().split()) if n%k == 0 : print(0) else: print(n-(n%k)) ```
instruction
0
34,436
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68,872
No
output
1
34,436
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68,873
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given two positive integers a and b. In one move you can increase a by 1 (replace a with a+1). Your task is to find the minimum number of moves you need to do in order to make a divisible by b. It is possible, that you have to make 0 moves, as a is already divisible by b. You have to answer t independent test cases. Input The first line of the input contains one integer t (1 ≀ t ≀ 10^4) β€” the number of test cases. Then t test cases follow. The only line of the test case contains two integers a and b (1 ≀ a, b ≀ 10^9). Output For each test case print the answer β€” the minimum number of moves you need to do in order to make a divisible by b. Example Input 5 10 4 13 9 100 13 123 456 92 46 Output 2 5 4 333 0 Submitted Solution: ``` def main(a,b): a0 = a for i in range(a,a+11): if not a%b: break else: a+=1 return a-a0 if __name__=='__main__': n = int(input()) for i in range(n): a,b = list(map(int,input().split())) print(main(a, b)) ```
instruction
0
34,437
22
68,874
No
output
1
34,437
22
68,875
Provide tags and a correct Python 3 solution for this coding contest problem. JATC's math teacher always gives the class some interesting math problems so that they don't get bored. Today the problem is as follows. Given an integer n, you can perform the following operations zero or more times: * mul x: multiplies n by x (where x is an arbitrary positive integer). * sqrt: replaces n with √{n} (to apply this operation, √{n} must be an integer). You can perform these operations as many times as you like. What is the minimum value of n, that can be achieved and what is the minimum number of operations, to achieve that minimum value? Apparently, no one in the class knows the answer to this problem, maybe you can help them? Input The only line of the input contains a single integer n (1 ≀ n ≀ 10^6) β€” the initial number. Output Print two integers: the minimum integer n that can be achieved using the described operations and the minimum number of operations required. Examples Input 20 Output 10 2 Input 5184 Output 6 4 Note In the first example, you can apply the operation mul 5 to get 100 and then sqrt to get 10. In the second example, you can first apply sqrt to get 72, then mul 18 to get 1296 and finally two more sqrt and you get 6. Note, that even if the initial value of n is less or equal 10^6, it can still become greater than 10^6 after applying one or more operations.
instruction
0
35,156
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Tags: greedy, math, number theory Correct Solution: ``` import math def list_primes_upto(upto :int): uptop1 = upto+1 uptom1 = upto-1 pcl = [True for x in range(uptop1)] lprimes = [] if upto >= 2: lprimes.append(2) if upto >= 3: lprimes.append(3) i = 5 while i < uptom1: ix2 = i*2 if pcl[i]: lprimes.append(i) for k in range(i*i, uptop1, ix2): pcl[k] = False ip2 = i+2 ip2x2 = ip2*2 if pcl[ip2]: lprimes.append(ip2) for k in range(ip2*ip2, uptop1, ip2x2): pcl[k] = False i += 6 if i <= upto: ix2 = i*2 if pcl[i]: lprimes.append(i) for k in range(i*i, uptop1, ix2): pcl[k] = False return lprimes n0 = int(input()) n = n0 lp = list_primes_upto(int(math.sqrt(n)) + 1) ncp = 0 pmf = [0] * len(lp) while ncp < len(lp) and n != 1: if n % lp[ncp] != 0: ncp += 1 continue n //= lp[ncp] pmf[ncp] += 1 mn = n sf = set(pmf) if n != 1: sf.add(1) for i in range(len(lp)): if pmf[i] == 0: continue mn *= lp[i] if mn == n0: mo = 0 else: mpf = max(sf) impfl2 = int(math.log(mpf, 2)) ls2 = [2**x for x in range(0,1001)] ntm = 0 for f in sf: if f == 0: continue if f not in ls2 or f != mpf: ntm = 1 break if mpf in ls2: sro = impfl2 else: sro = impfl2 + 1 ntm = 1 mo = ntm + sro print(mn, mo) ```
output
1
35,156
22
70,313
Provide tags and a correct Python 3 solution for this coding contest problem. JATC's math teacher always gives the class some interesting math problems so that they don't get bored. Today the problem is as follows. Given an integer n, you can perform the following operations zero or more times: * mul x: multiplies n by x (where x is an arbitrary positive integer). * sqrt: replaces n with √{n} (to apply this operation, √{n} must be an integer). You can perform these operations as many times as you like. What is the minimum value of n, that can be achieved and what is the minimum number of operations, to achieve that minimum value? Apparently, no one in the class knows the answer to this problem, maybe you can help them? Input The only line of the input contains a single integer n (1 ≀ n ≀ 10^6) β€” the initial number. Output Print two integers: the minimum integer n that can be achieved using the described operations and the minimum number of operations required. Examples Input 20 Output 10 2 Input 5184 Output 6 4 Note In the first example, you can apply the operation mul 5 to get 100 and then sqrt to get 10. In the second example, you can first apply sqrt to get 72, then mul 18 to get 1296 and finally two more sqrt and you get 6. Note, that even if the initial value of n is less or equal 10^6, it can still become greater than 10^6 after applying one or more operations.
instruction
0
35,158
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Tags: greedy, math, number theory Correct Solution: ``` import math def primeFactors(n): if n%2==0: dict1[2]=0 while n % 2 == 0: dict1[2]+=1 n = n // 2 for i in range(3,int(math.sqrt(n))+1,2): if n%i==0: dict1[i]=0 while n % i== 0: dict1[i]+=1 n = n //i if n > 2: dict1[n]=0 dict1[n]+=1 n=int(input()) if n==1: print(1,0) else: dict1={} primeFactors(n) max1=1 lst=[] for i in dict1: lst.append(dict1[i]) if max(lst)==min(lst) and max(lst)==1: print(n,0) elif max(lst)==min(lst): prod=1 for i in dict1: prod*=i str1=bin(max(lst)) str2=str1[2:] list1=list(str2) if list1.count('0')==len(list1)-1: print(prod,math.ceil(math.log2(max(lst)))) else: print(prod,math.ceil(math.log2(max(lst)))+1) else: prod=1 for i in dict1: prod*=i print(prod,math.ceil(math.log2(max(lst)))+1) ```
output
1
35,158
22
70,317
Provide tags and a correct Python 3 solution for this coding contest problem. JATC's math teacher always gives the class some interesting math problems so that they don't get bored. Today the problem is as follows. Given an integer n, you can perform the following operations zero or more times: * mul x: multiplies n by x (where x is an arbitrary positive integer). * sqrt: replaces n with √{n} (to apply this operation, √{n} must be an integer). You can perform these operations as many times as you like. What is the minimum value of n, that can be achieved and what is the minimum number of operations, to achieve that minimum value? Apparently, no one in the class knows the answer to this problem, maybe you can help them? Input The only line of the input contains a single integer n (1 ≀ n ≀ 10^6) β€” the initial number. Output Print two integers: the minimum integer n that can be achieved using the described operations and the minimum number of operations required. Examples Input 20 Output 10 2 Input 5184 Output 6 4 Note In the first example, you can apply the operation mul 5 to get 100 and then sqrt to get 10. In the second example, you can first apply sqrt to get 72, then mul 18 to get 1296 and finally two more sqrt and you get 6. Note, that even if the initial value of n is less or equal 10^6, it can still become greater than 10^6 after applying one or more operations.
instruction
0
35,159
22
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Tags: greedy, math, number theory Correct Solution: ``` # Python program to print prime factors import math def primeFactors(n): # Print the number of two's that divide n dic = {} while n % 2 == 0: if 2 in dic: dic[2] += 1 else: dic[2] = 1 n = n / 2 # n must be odd at this point # so a skip of 2 ( i = i + 2) can be used for i in range(3,int(math.sqrt(n))+1,2): # while i divides n , print i ad divide n while n % i== 0: if i in dic: dic[i] += 1 else: dic[i] = 1 n = n / i # Condition if n is a prime # number greater than 2 if n > 2: if n in dic: dic[n] += 1 else: dic[n] = 1 return dic n = int(input()) arr = primeFactors(n) arr2 = [] for key in arr: arr2.append(arr[key]) length = len(arr2) ans = 0 #print("ura") while True: sqrt = True if len(arr2) == 0: break for i in arr2: if i%2 == 1: sqrt = False break if sqrt: ans += 1 for i in range(length): arr2[i] = arr2[i]/2 else: break p = 0 start = 1 if len(arr2) ==0: a = 1 else: a = max(arr2) for i in range(1000): if start<a: start *= 2 p += 1 else: break plus1 = False for i in range(length): if arr2[i] <start: plus1 = True break if plus1: ans += p + 1 else: ans += p ans0 = 1 for i in arr: ans0 *= i print(int(ans0),ans) ```
output
1
35,159
22
70,319
Provide tags and a correct Python 3 solution for this coding contest problem. JATC's math teacher always gives the class some interesting math problems so that they don't get bored. Today the problem is as follows. Given an integer n, you can perform the following operations zero or more times: * mul x: multiplies n by x (where x is an arbitrary positive integer). * sqrt: replaces n with √{n} (to apply this operation, √{n} must be an integer). You can perform these operations as many times as you like. What is the minimum value of n, that can be achieved and what is the minimum number of operations, to achieve that minimum value? Apparently, no one in the class knows the answer to this problem, maybe you can help them? Input The only line of the input contains a single integer n (1 ≀ n ≀ 10^6) β€” the initial number. Output Print two integers: the minimum integer n that can be achieved using the described operations and the minimum number of operations required. Examples Input 20 Output 10 2 Input 5184 Output 6 4 Note In the first example, you can apply the operation mul 5 to get 100 and then sqrt to get 10. In the second example, you can first apply sqrt to get 72, then mul 18 to get 1296 and finally two more sqrt and you get 6. Note, that even if the initial value of n is less or equal 10^6, it can still become greater than 10^6 after applying one or more operations.
instruction
0
35,161
22
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Tags: greedy, math, number theory Correct Solution: ``` def main(): buf = input() n = int(buf) op_count = 0 factor = prime_factorization(n) c_max = 1 first_c = None all_same = True min_number = 1 for f, c in factor.items(): if c > c_max: c_max = c if first_c == None: first_c = c elif c != first_c: all_same = False min_number *= f if check_power_of_2(c_max) and all_same: pass else: op_count += 1 if not check_power_of_2(c_max): c_max = c_max << 1 c_max = c_max & (c_max - 1) while c_max > 1: c_max //= 2 op_count += 1 print(min_number, op_count) def check_power_of_2(x): return (x != 0) and ((x & (x - 1)) == 0) def prime_factorization(number): n = number i = 2 factor = {} while i * i <= n: while n % i == 0: if i in factor: factor[i] += 1 else: factor.update({i : 1}) n //= i i += 1 if n > 1 or not factor: if n in factor: factor[n] += 1 else: factor.update({n : 1}) return factor if __name__ == '__main__': main() ```
output
1
35,161
22
70,323
Provide tags and a correct Python 3 solution for this coding contest problem. JATC's math teacher always gives the class some interesting math problems so that they don't get bored. Today the problem is as follows. Given an integer n, you can perform the following operations zero or more times: * mul x: multiplies n by x (where x is an arbitrary positive integer). * sqrt: replaces n with √{n} (to apply this operation, √{n} must be an integer). You can perform these operations as many times as you like. What is the minimum value of n, that can be achieved and what is the minimum number of operations, to achieve that minimum value? Apparently, no one in the class knows the answer to this problem, maybe you can help them? Input The only line of the input contains a single integer n (1 ≀ n ≀ 10^6) β€” the initial number. Output Print two integers: the minimum integer n that can be achieved using the described operations and the minimum number of operations required. Examples Input 20 Output 10 2 Input 5184 Output 6 4 Note In the first example, you can apply the operation mul 5 to get 100 and then sqrt to get 10. In the second example, you can first apply sqrt to get 72, then mul 18 to get 1296 and finally two more sqrt and you get 6. Note, that even if the initial value of n is less or equal 10^6, it can still become greater than 10^6 after applying one or more operations.
instruction
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Tags: greedy, math, number theory Correct Solution: ``` def factorize(n): fct = [] # prime factor b, e = 2, 0 # base, exponent while b * b <= n: while n % b == 0: n = n // b e = e + 1 if e > 0: fct.append((b, e)) b, e = b + 1, 0 if n > 1: fct.append((n, 1)) return fct def main(): n = int(input()) l = factorize(n) anscnt = 0 ma = 0 for i in range(len(l)): ma = max(ma, l[i][1]) c = 0 a = 1 while True: if a >= ma: break a *= 2 c += 1 v = 1 for i in range(len(l)): for j in range(a - l[i][1]): v *= l[i][0] anscnt = 1 n *= v for i in range(c): n = n**(1/2) anscnt += 1 print(int(n), anscnt, sep=" ") if __name__ == '__main__': main() ```
output
1
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. If an integer a is divisible by another integer b, then b is called the divisor of a. For example: 12 has positive 6 divisors. They are 1, 2, 3, 4, 6 and 12. Let’s define a function D(n) β€” number of integers between 1 and n (inclusive) which has exactly four positive divisors. Between 1 and 10 only the integers 6, 8 and 10 has exactly four positive divisors. So, D(10) = 3. You are given an integer n. You have to calculate D(n). Input The only line contains integer n (1 ≀ n ≀ 1011) β€” the parameter from the problem statement. Output Print the only integer c β€” the number of integers between 1 and n with exactly four divisors. Examples Input 10 Output 3 Input 20 Output 5 Submitted Solution: ``` n=int(input("")) if n==1: print("I hate it") else: for i in range(1,n): if i%2==0: print("I love that",end=" ") else: print("I hate that",end=" ") if n%2==0: print("") else: print("") #https://codeforces.com/problemset/problem/705/A ```
instruction
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No
output
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. If an integer a is divisible by another integer b, then b is called the divisor of a. For example: 12 has positive 6 divisors. They are 1, 2, 3, 4, 6 and 12. Let’s define a function D(n) β€” number of integers between 1 and n (inclusive) which has exactly four positive divisors. Between 1 and 10 only the integers 6, 8 and 10 has exactly four positive divisors. So, D(10) = 3. You are given an integer n. You have to calculate D(n). Input The only line contains integer n (1 ≀ n ≀ 1011) β€” the parameter from the problem statement. Output Print the only integer c β€” the number of integers between 1 and n with exactly four divisors. Examples Input 10 Output 3 Input 20 Output 5 Submitted Solution: ``` def D(n): for i in range(1,n+1): c = 0 for j in range(1, i): if(i%j==0): c=c+1 print(c) n = int(input()) D(n) ```
instruction
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No
output
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. If an integer a is divisible by another integer b, then b is called the divisor of a. For example: 12 has positive 6 divisors. They are 1, 2, 3, 4, 6 and 12. Let’s define a function D(n) β€” number of integers between 1 and n (inclusive) which has exactly four positive divisors. Between 1 and 10 only the integers 6, 8 and 10 has exactly four positive divisors. So, D(10) = 3. You are given an integer n. You have to calculate D(n). Input The only line contains integer n (1 ≀ n ≀ 1011) β€” the parameter from the problem statement. Output Print the only integer c β€” the number of integers between 1 and n with exactly four divisors. Examples Input 10 Output 3 Input 20 Output 5 Submitted Solution: ``` import sys def divi(n,k): if k==1: return 0 elif n%k==0: return 1+divi(n,k-1) else: return 0+divi(n,k-1) n=int(sys.stdin.readline().strip()) print(divi(n,n)) ```
instruction
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No
output
1
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71,221
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. If an integer a is divisible by another integer b, then b is called the divisor of a. For example: 12 has positive 6 divisors. They are 1, 2, 3, 4, 6 and 12. Let’s define a function D(n) β€” number of integers between 1 and n (inclusive) which has exactly four positive divisors. Between 1 and 10 only the integers 6, 8 and 10 has exactly four positive divisors. So, D(10) = 3. You are given an integer n. You have to calculate D(n). Input The only line contains integer n (1 ≀ n ≀ 1011) β€” the parameter from the problem statement. Output Print the only integer c β€” the number of integers between 1 and n with exactly four divisors. Examples Input 10 Output 3 Input 20 Output 5 Submitted Solution: ``` n = input() n = int(n) tw = 0 th = 0 fi = 0 while(n > 1): if((n % 2) == 0): n = n/2 tw = tw + 1 elif((n % 3) == 0): n = n/3 th = th + 1 elif((n % 5) == 0): n = n/5 fi = fi + 1 div = (tw + 1)*(th + 1)*(fi + 1) print(div) ```
instruction
0
35,611
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No
output
1
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22
71,223
Provide tags and a correct Python 3 solution for this coding contest problem. Bash has set out on a journey to become the greatest Pokemon master. To get his first Pokemon, he went to Professor Zulu's Lab. Since Bash is Professor Zulu's favourite student, Zulu allows him to take as many Pokemon from his lab as he pleases. But Zulu warns him that a group of k > 1 Pokemon with strengths {s1, s2, s3, ..., sk} tend to fight among each other if gcd(s1, s2, s3, ..., sk) = 1 (see notes for gcd definition). Bash, being smart, does not want his Pokemon to fight among each other. However, he also wants to maximize the number of Pokemon he takes from the lab. Can you help Bash find out the maximum number of Pokemon he can take? Note: A Pokemon cannot fight with itself. Input The input consists of two lines. The first line contains an integer n (1 ≀ n ≀ 105), the number of Pokemon in the lab. The next line contains n space separated integers, where the i-th of them denotes si (1 ≀ si ≀ 105), the strength of the i-th Pokemon. Output Print single integer β€” the maximum number of Pokemons Bash can take. Examples Input 3 2 3 4 Output 2 Input 5 2 3 4 6 7 Output 3 Note gcd (greatest common divisor) of positive integers set {a1, a2, ..., an} is the maximum positive integer that divides all the integers {a1, a2, ..., an}. In the first sample, we can take Pokemons with strengths {2, 4} since gcd(2, 4) = 2. In the second sample, we can take Pokemons with strengths {2, 4, 6}, and there is no larger group with gcd β‰  1.
instruction
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Tags: greedy, math, number theory Correct Solution: ``` def prime_t(t): i=2 while i**2<=t: if t%i==0: return 0 i+=1 return 1 def prime_list(tt): p_list=[] for i in range(2,tt+1): if prime_t(i): p_list.append(i) return p_list chk=prime_list(318) ans=[0]*(len(chk)+1) ans[-1]=1 n=int(input()) l=[int(i) for i in input().split() if i!='1'] d={} for i in l: if i in d: d[i]+=1 ans[-1]=max(ans[-1],d[i]) else: d[i]=1 l=list(set(l)) l.sort() over={} for i in l: tmp=i for j,k in enumerate(chk): if i%k==0: ans[j]+=d[tmp] while i%k==0: i//=k if i<k: break if i>317: if i in over: over[i]+=d[tmp] ans[-1]=max(ans[-1],over[i]) else: over[i]=d[tmp] print(max(ans)) ```
output
1
35,646
22
71,293
Provide tags and a correct Python 3 solution for this coding contest problem. Bash has set out on a journey to become the greatest Pokemon master. To get his first Pokemon, he went to Professor Zulu's Lab. Since Bash is Professor Zulu's favourite student, Zulu allows him to take as many Pokemon from his lab as he pleases. But Zulu warns him that a group of k > 1 Pokemon with strengths {s1, s2, s3, ..., sk} tend to fight among each other if gcd(s1, s2, s3, ..., sk) = 1 (see notes for gcd definition). Bash, being smart, does not want his Pokemon to fight among each other. However, he also wants to maximize the number of Pokemon he takes from the lab. Can you help Bash find out the maximum number of Pokemon he can take? Note: A Pokemon cannot fight with itself. Input The input consists of two lines. The first line contains an integer n (1 ≀ n ≀ 105), the number of Pokemon in the lab. The next line contains n space separated integers, where the i-th of them denotes si (1 ≀ si ≀ 105), the strength of the i-th Pokemon. Output Print single integer β€” the maximum number of Pokemons Bash can take. Examples Input 3 2 3 4 Output 2 Input 5 2 3 4 6 7 Output 3 Note gcd (greatest common divisor) of positive integers set {a1, a2, ..., an} is the maximum positive integer that divides all the integers {a1, a2, ..., an}. In the first sample, we can take Pokemons with strengths {2, 4} since gcd(2, 4) = 2. In the second sample, we can take Pokemons with strengths {2, 4, 6}, and there is no larger group with gcd β‰  1.
instruction
0
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22
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Tags: greedy, math, number theory Correct Solution: ``` from collections import Counter newn = int(input()) unfs = list(map(int, input().split())) s = [] n = 0 p = [2, 3] for i in range(1, 55): p.append(6*i - 1) p.append(6*i + 1) if newn == 1 and unfs[0] == 1: print(1) else: for i in unfs: if i != 1: s.append(i) n += 1 a = [] for i in range(n): found = False for j in range(1, 1+int(s[i]**0.5)): if s[i]%j == 0: if j != 1: a.append(j) if s[i]//j != 1 and s[i]//j != j: a.append(s[i]//j) c = Counter(a).most_common() if len(c) == 0: print(1) else: print(c[0][1]) ```
output
1
35,647
22
71,295
Provide tags and a correct Python 3 solution for this coding contest problem. Bash has set out on a journey to become the greatest Pokemon master. To get his first Pokemon, he went to Professor Zulu's Lab. Since Bash is Professor Zulu's favourite student, Zulu allows him to take as many Pokemon from his lab as he pleases. But Zulu warns him that a group of k > 1 Pokemon with strengths {s1, s2, s3, ..., sk} tend to fight among each other if gcd(s1, s2, s3, ..., sk) = 1 (see notes for gcd definition). Bash, being smart, does not want his Pokemon to fight among each other. However, he also wants to maximize the number of Pokemon he takes from the lab. Can you help Bash find out the maximum number of Pokemon he can take? Note: A Pokemon cannot fight with itself. Input The input consists of two lines. The first line contains an integer n (1 ≀ n ≀ 105), the number of Pokemon in the lab. The next line contains n space separated integers, where the i-th of them denotes si (1 ≀ si ≀ 105), the strength of the i-th Pokemon. Output Print single integer β€” the maximum number of Pokemons Bash can take. Examples Input 3 2 3 4 Output 2 Input 5 2 3 4 6 7 Output 3 Note gcd (greatest common divisor) of positive integers set {a1, a2, ..., an} is the maximum positive integer that divides all the integers {a1, a2, ..., an}. In the first sample, we can take Pokemons with strengths {2, 4} since gcd(2, 4) = 2. In the second sample, we can take Pokemons with strengths {2, 4, 6}, and there is no larger group with gcd β‰  1.
instruction
0
35,648
22
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Tags: greedy, math, number theory Correct Solution: ``` n=int(input()) a=list(map(int,input().split())) b=[0]*100001 c=[] for i in a: b[i]+=1 for i in range(2,100001): sum=0 for j in range(i,100001,i): sum+=b[j] c.append(sum) print(max(max(c),1)) ```
output
1
35,648
22
71,297
Provide tags and a correct Python 3 solution for this coding contest problem. Bash has set out on a journey to become the greatest Pokemon master. To get his first Pokemon, he went to Professor Zulu's Lab. Since Bash is Professor Zulu's favourite student, Zulu allows him to take as many Pokemon from his lab as he pleases. But Zulu warns him that a group of k > 1 Pokemon with strengths {s1, s2, s3, ..., sk} tend to fight among each other if gcd(s1, s2, s3, ..., sk) = 1 (see notes for gcd definition). Bash, being smart, does not want his Pokemon to fight among each other. However, he also wants to maximize the number of Pokemon he takes from the lab. Can you help Bash find out the maximum number of Pokemon he can take? Note: A Pokemon cannot fight with itself. Input The input consists of two lines. The first line contains an integer n (1 ≀ n ≀ 105), the number of Pokemon in the lab. The next line contains n space separated integers, where the i-th of them denotes si (1 ≀ si ≀ 105), the strength of the i-th Pokemon. Output Print single integer β€” the maximum number of Pokemons Bash can take. Examples Input 3 2 3 4 Output 2 Input 5 2 3 4 6 7 Output 3 Note gcd (greatest common divisor) of positive integers set {a1, a2, ..., an} is the maximum positive integer that divides all the integers {a1, a2, ..., an}. In the first sample, we can take Pokemons with strengths {2, 4} since gcd(2, 4) = 2. In the second sample, we can take Pokemons with strengths {2, 4, 6}, and there is no larger group with gcd β‰  1.
instruction
0
35,649
22
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Tags: greedy, math, number theory Correct Solution: ``` n = int(input()) a = list(map(int, input().split())) ans = 1 count = [0] * 100001 for i in a: count[i] += 1 for i in range(2, 100001): s = 0 for j in range(i, 100001, i): s += count[j] ans = max(ans, s) print(ans) ```
output
1
35,649
22
71,299
Provide tags and a correct Python 3 solution for this coding contest problem. Bash has set out on a journey to become the greatest Pokemon master. To get his first Pokemon, he went to Professor Zulu's Lab. Since Bash is Professor Zulu's favourite student, Zulu allows him to take as many Pokemon from his lab as he pleases. But Zulu warns him that a group of k > 1 Pokemon with strengths {s1, s2, s3, ..., sk} tend to fight among each other if gcd(s1, s2, s3, ..., sk) = 1 (see notes for gcd definition). Bash, being smart, does not want his Pokemon to fight among each other. However, he also wants to maximize the number of Pokemon he takes from the lab. Can you help Bash find out the maximum number of Pokemon he can take? Note: A Pokemon cannot fight with itself. Input The input consists of two lines. The first line contains an integer n (1 ≀ n ≀ 105), the number of Pokemon in the lab. The next line contains n space separated integers, where the i-th of them denotes si (1 ≀ si ≀ 105), the strength of the i-th Pokemon. Output Print single integer β€” the maximum number of Pokemons Bash can take. Examples Input 3 2 3 4 Output 2 Input 5 2 3 4 6 7 Output 3 Note gcd (greatest common divisor) of positive integers set {a1, a2, ..., an} is the maximum positive integer that divides all the integers {a1, a2, ..., an}. In the first sample, we can take Pokemons with strengths {2, 4} since gcd(2, 4) = 2. In the second sample, we can take Pokemons with strengths {2, 4, 6}, and there is no larger group with gcd β‰  1.
instruction
0
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22
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Tags: greedy, math, number theory Correct Solution: ``` n=int(input()) d={} l=list(map(int,input().split())) for i in range(n): x=int(l[i]**0.5)+1 for j in range(2,x): if l[i]%j==0: d[j]=d.get(j,0)+1 while l[i]%j==0: l[i]//=j if l[i]>1: d[l[i]]=d.get(l[i],0)+1 # print(d) if d=={}: print(1) exit(0) print(max(1,max(d.values()))) ```
output
1
35,650
22
71,301
Provide tags and a correct Python 3 solution for this coding contest problem. Bash has set out on a journey to become the greatest Pokemon master. To get his first Pokemon, he went to Professor Zulu's Lab. Since Bash is Professor Zulu's favourite student, Zulu allows him to take as many Pokemon from his lab as he pleases. But Zulu warns him that a group of k > 1 Pokemon with strengths {s1, s2, s3, ..., sk} tend to fight among each other if gcd(s1, s2, s3, ..., sk) = 1 (see notes for gcd definition). Bash, being smart, does not want his Pokemon to fight among each other. However, he also wants to maximize the number of Pokemon he takes from the lab. Can you help Bash find out the maximum number of Pokemon he can take? Note: A Pokemon cannot fight with itself. Input The input consists of two lines. The first line contains an integer n (1 ≀ n ≀ 105), the number of Pokemon in the lab. The next line contains n space separated integers, where the i-th of them denotes si (1 ≀ si ≀ 105), the strength of the i-th Pokemon. Output Print single integer β€” the maximum number of Pokemons Bash can take. Examples Input 3 2 3 4 Output 2 Input 5 2 3 4 6 7 Output 3 Note gcd (greatest common divisor) of positive integers set {a1, a2, ..., an} is the maximum positive integer that divides all the integers {a1, a2, ..., an}. In the first sample, we can take Pokemons with strengths {2, 4} since gcd(2, 4) = 2. In the second sample, we can take Pokemons with strengths {2, 4, 6}, and there is no larger group with gcd β‰  1.
instruction
0
35,651
22
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Tags: greedy, math, number theory Correct Solution: ``` n = int(input()) s = map(int, input().split()) pf = [[] for _ in range(10 ** 5 + 1)] for i in range(2, 10 ** 5 + 1): if len(pf[i]) > 0: continue for j in range(i, 10 ** 5 + 1, i): pf[j].append(i) f = [0] * (10 ** 5 + 1) for x in s: for i in pf[x]: f[i] += 1 print(max(1, max(f))) ```
output
1
35,651
22
71,303
Provide tags and a correct Python 3 solution for this coding contest problem. Not long ago Billy came across such a problem, where there were given three natural numbers A, B and C from the range [1, N], and it was asked to check whether the equation AB = C is correct. Recently Billy studied the concept of a digital root of a number. We should remind you that a digital root d(x) of the number x is the sum s(x) of all the digits of this number, if s(x) ≀ 9, otherwise it is d(s(x)). For example, a digital root of the number 6543 is calculated as follows: d(6543) = d(6 + 5 + 4 + 3) = d(18) = 9. Billy has counted that the digital root of a product of numbers is equal to the digital root of the product of the factors' digital roots, i.e. d(xy) = d(d(x)d(y)). And the following solution to the problem came to his mind: to calculate the digital roots and check if this condition is met. However, Billy has doubts that this condition is sufficient. That's why he asks you to find out the amount of test examples for the given problem such that the algorithm proposed by Billy makes mistakes. Input The first line contains the only number N (1 ≀ N ≀ 106). Output Output one number β€” the amount of required A, B and C from the range [1, N]. Examples Input 4 Output 2 Input 5 Output 6 Note For the first sample the required triples are (3, 4, 3) and (4, 3, 3).
instruction
0
36,047
22
72,094
Tags: number theory Correct Solution: ``` n = int(input()) c = [0] * 9 ans = 0 for i in range(1, n + 1): ans -= n // i c[i % 9] += 1 for i in range(9): for j in range(9): ans += c[i] * c[j] * c[i * j % 9] print(ans) ```
output
1
36,047
22
72,095
Provide tags and a correct Python 3 solution for this coding contest problem. Not long ago Billy came across such a problem, where there were given three natural numbers A, B and C from the range [1, N], and it was asked to check whether the equation AB = C is correct. Recently Billy studied the concept of a digital root of a number. We should remind you that a digital root d(x) of the number x is the sum s(x) of all the digits of this number, if s(x) ≀ 9, otherwise it is d(s(x)). For example, a digital root of the number 6543 is calculated as follows: d(6543) = d(6 + 5 + 4 + 3) = d(18) = 9. Billy has counted that the digital root of a product of numbers is equal to the digital root of the product of the factors' digital roots, i.e. d(xy) = d(d(x)d(y)). And the following solution to the problem came to his mind: to calculate the digital roots and check if this condition is met. However, Billy has doubts that this condition is sufficient. That's why he asks you to find out the amount of test examples for the given problem such that the algorithm proposed by Billy makes mistakes. Input The first line contains the only number N (1 ≀ N ≀ 106). Output Output one number β€” the amount of required A, B and C from the range [1, N]. Examples Input 4 Output 2 Input 5 Output 6 Note For the first sample the required triples are (3, 4, 3) and (4, 3, 3).
instruction
0
36,048
22
72,096
Tags: number theory Correct Solution: ``` n, ans, a = int(input()), 0, [0] * 10 for i in range(1, n + 1): ans -= int(n/i) a[i % 9] += 1 for i in range(9): for j in range(9): ans += a[i] * a[j] * a[(i * j) % 9] print(ans) ```
output
1
36,048
22
72,097
Provide tags and a correct Python 3 solution for this coding contest problem. Not long ago Billy came across such a problem, where there were given three natural numbers A, B and C from the range [1, N], and it was asked to check whether the equation AB = C is correct. Recently Billy studied the concept of a digital root of a number. We should remind you that a digital root d(x) of the number x is the sum s(x) of all the digits of this number, if s(x) ≀ 9, otherwise it is d(s(x)). For example, a digital root of the number 6543 is calculated as follows: d(6543) = d(6 + 5 + 4 + 3) = d(18) = 9. Billy has counted that the digital root of a product of numbers is equal to the digital root of the product of the factors' digital roots, i.e. d(xy) = d(d(x)d(y)). And the following solution to the problem came to his mind: to calculate the digital roots and check if this condition is met. However, Billy has doubts that this condition is sufficient. That's why he asks you to find out the amount of test examples for the given problem such that the algorithm proposed by Billy makes mistakes. Input The first line contains the only number N (1 ≀ N ≀ 106). Output Output one number β€” the amount of required A, B and C from the range [1, N]. Examples Input 4 Output 2 Input 5 Output 6 Note For the first sample the required triples are (3, 4, 3) and (4, 3, 3).
instruction
0
36,049
22
72,098
Tags: number theory Correct Solution: ``` def main(): ans = 0 a = [0] * 10 n = int(input()) for i in range (1, 9): a[i] = n // 9 + int(n % 9 >= i) a[9] = n // 9 for i in range(1, 10): for j in range(1, 10): k = i * j % 9 if k == 0: k = 9 ans += a[i] * a[j] * a[k] for i in range(1, n + 1): ans -= n // i print(ans) return if __name__ == "__main__": main() ```
output
1
36,049
22
72,099
Provide tags and a correct Python 3 solution for this coding contest problem. Not long ago Billy came across such a problem, where there were given three natural numbers A, B and C from the range [1, N], and it was asked to check whether the equation AB = C is correct. Recently Billy studied the concept of a digital root of a number. We should remind you that a digital root d(x) of the number x is the sum s(x) of all the digits of this number, if s(x) ≀ 9, otherwise it is d(s(x)). For example, a digital root of the number 6543 is calculated as follows: d(6543) = d(6 + 5 + 4 + 3) = d(18) = 9. Billy has counted that the digital root of a product of numbers is equal to the digital root of the product of the factors' digital roots, i.e. d(xy) = d(d(x)d(y)). And the following solution to the problem came to his mind: to calculate the digital roots and check if this condition is met. However, Billy has doubts that this condition is sufficient. That's why he asks you to find out the amount of test examples for the given problem such that the algorithm proposed by Billy makes mistakes. Input The first line contains the only number N (1 ≀ N ≀ 106). Output Output one number β€” the amount of required A, B and C from the range [1, N]. Examples Input 4 Output 2 Input 5 Output 6 Note For the first sample the required triples are (3, 4, 3) and (4, 3, 3).
instruction
0
36,050
22
72,100
Tags: number theory Correct Solution: ``` __author__ = 'Darren' # d(x) = (x-1) % 9 + 1 def solve(): n = int(input()) # count[i]: the number of x's in [1,n] such that d(x) = i count = [0] * 10 for i in range((n-1) % 9 + 2): count[i] = (n + 8) // 9 for i in range((n-1) % 9 + 2, 10): count[i] = n // 9 result = 0 # Count all triples (i, j, k) such that d(d(i)*d(j)) = d(k) for i in range(1, 10): for j in range(1, 10): result += count[i] * count[j] * count[(i*j-1) % 9 + 1] # For each i, there are n/i triples (i,j,k) such that i*j = k, # i.e., the correct cases for i in range(1, n+1): result -= n // i print(result) if __name__ == '__main__': solve() ```
output
1
36,050
22
72,101
Provide tags and a correct Python 3 solution for this coding contest problem. Not long ago Billy came across such a problem, where there were given three natural numbers A, B and C from the range [1, N], and it was asked to check whether the equation AB = C is correct. Recently Billy studied the concept of a digital root of a number. We should remind you that a digital root d(x) of the number x is the sum s(x) of all the digits of this number, if s(x) ≀ 9, otherwise it is d(s(x)). For example, a digital root of the number 6543 is calculated as follows: d(6543) = d(6 + 5 + 4 + 3) = d(18) = 9. Billy has counted that the digital root of a product of numbers is equal to the digital root of the product of the factors' digital roots, i.e. d(xy) = d(d(x)d(y)). And the following solution to the problem came to his mind: to calculate the digital roots and check if this condition is met. However, Billy has doubts that this condition is sufficient. That's why he asks you to find out the amount of test examples for the given problem such that the algorithm proposed by Billy makes mistakes. Input The first line contains the only number N (1 ≀ N ≀ 106). Output Output one number β€” the amount of required A, B and C from the range [1, N]. Examples Input 4 Output 2 Input 5 Output 6 Note For the first sample the required triples are (3, 4, 3) and (4, 3, 3).
instruction
0
36,051
22
72,102
Tags: number theory Correct Solution: ``` __author__ = 'Darren' # d(x) = (x-1) % 9 + 1 def solve(): n = int(input()) # count[i]: the number of x's in [1,n] such that d(x) = i count = [0] * 10 for i in range((n-1) % 9 + 2): count[i] = (n + 8) // 9 for i in range((n-1) % 9 + 2, 10): count[i] = n // 9 result = 0 # Count all triples (i, j, k) such that d(d(i)*d(j)) = d(k) for i in range(1, 10): for j in range(1, 10): result += count[i] * count[j] * count[(i*j-1) % 9 + 1] # For each i, there are n/i triples (i,j,k) such that i*j = k, # i.e., the correct cases for i in range(1, n+1): result -= n // i print(result) if __name__ == '__main__': solve() # Made By Mostafa_Khaled ```
output
1
36,051
22
72,103
Provide tags and a correct Python 3 solution for this coding contest problem. Not long ago Billy came across such a problem, where there were given three natural numbers A, B and C from the range [1, N], and it was asked to check whether the equation AB = C is correct. Recently Billy studied the concept of a digital root of a number. We should remind you that a digital root d(x) of the number x is the sum s(x) of all the digits of this number, if s(x) ≀ 9, otherwise it is d(s(x)). For example, a digital root of the number 6543 is calculated as follows: d(6543) = d(6 + 5 + 4 + 3) = d(18) = 9. Billy has counted that the digital root of a product of numbers is equal to the digital root of the product of the factors' digital roots, i.e. d(xy) = d(d(x)d(y)). And the following solution to the problem came to his mind: to calculate the digital roots and check if this condition is met. However, Billy has doubts that this condition is sufficient. That's why he asks you to find out the amount of test examples for the given problem such that the algorithm proposed by Billy makes mistakes. Input The first line contains the only number N (1 ≀ N ≀ 106). Output Output one number β€” the amount of required A, B and C from the range [1, N]. Examples Input 4 Output 2 Input 5 Output 6 Note For the first sample the required triples are (3, 4, 3) and (4, 3, 3).
instruction
0
36,052
22
72,104
Tags: number theory Correct Solution: ``` def digital_root(x: int) -> int: if x <= 9: return x tot = 0 while x: tot += x % 10 x //= 10 return digital_root(tot) n = int(input()) counts = [0]*10 d = [0]*(n+1) for i in range(1,n+1): d[i] = digital_root(i) counts[d[i]] += 1 answer = 0 # number of triples such that relation holds. i = d(c) j = d(a) k = d(b) for i in range(1,10): for j in range(1,10): for k in range(1,10): if i == digital_root(j*k): answer += counts[i]*counts[j]*counts[k] # subtract number of triples such that the relation holds but c = a*b for a in range(1,n+1): for c in range(a,n+1,a): b = c//a if d[c] == d[d[a]*d[b]]: answer -= 1 print(answer) ```
output
1
36,052
22
72,105
Provide tags and a correct Python 3 solution for this coding contest problem. Not long ago Billy came across such a problem, where there were given three natural numbers A, B and C from the range [1, N], and it was asked to check whether the equation AB = C is correct. Recently Billy studied the concept of a digital root of a number. We should remind you that a digital root d(x) of the number x is the sum s(x) of all the digits of this number, if s(x) ≀ 9, otherwise it is d(s(x)). For example, a digital root of the number 6543 is calculated as follows: d(6543) = d(6 + 5 + 4 + 3) = d(18) = 9. Billy has counted that the digital root of a product of numbers is equal to the digital root of the product of the factors' digital roots, i.e. d(xy) = d(d(x)d(y)). And the following solution to the problem came to his mind: to calculate the digital roots and check if this condition is met. However, Billy has doubts that this condition is sufficient. That's why he asks you to find out the amount of test examples for the given problem such that the algorithm proposed by Billy makes mistakes. Input The first line contains the only number N (1 ≀ N ≀ 106). Output Output one number β€” the amount of required A, B and C from the range [1, N]. Examples Input 4 Output 2 Input 5 Output 6 Note For the first sample the required triples are (3, 4, 3) and (4, 3, 3).
instruction
0
36,053
22
72,106
Tags: number theory Correct Solution: ``` def main(): ans = 0 a = [0] * 10 n = int(input()) for i in range (0, 9): a[i] = n // 9 + int(n % 9 >= i) a[0] -= 1 for i in range(0, 9): for j in range(0, 9): k = i * j % 9 ans += a[i] * a[j] * a[k] for i in range(1, n + 1): ans -= n // i print(ans) return if __name__ == "__main__": main() ```
output
1
36,053
22
72,107
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Not long ago Billy came across such a problem, where there were given three natural numbers A, B and C from the range [1, N], and it was asked to check whether the equation AB = C is correct. Recently Billy studied the concept of a digital root of a number. We should remind you that a digital root d(x) of the number x is the sum s(x) of all the digits of this number, if s(x) ≀ 9, otherwise it is d(s(x)). For example, a digital root of the number 6543 is calculated as follows: d(6543) = d(6 + 5 + 4 + 3) = d(18) = 9. Billy has counted that the digital root of a product of numbers is equal to the digital root of the product of the factors' digital roots, i.e. d(xy) = d(d(x)d(y)). And the following solution to the problem came to his mind: to calculate the digital roots and check if this condition is met. However, Billy has doubts that this condition is sufficient. That's why he asks you to find out the amount of test examples for the given problem such that the algorithm proposed by Billy makes mistakes. Input The first line contains the only number N (1 ≀ N ≀ 106). Output Output one number β€” the amount of required A, B and C from the range [1, N]. Examples Input 4 Output 2 Input 5 Output 6 Note For the first sample the required triples are (3, 4, 3) and (4, 3, 3). Submitted Solution: ``` ''' Jana Goodman6 10C Digital Root this is true: d(xy) = d(d(x)d(y)) need to count AB question is how many d(AB) == d(C) but AB != C ''' import math import time def dr(n): return (n - 1) % 9 + 1 def digsum(n): return sum(map(int, list(str(n)))) def persist(n): m = n ans = 1 while True: x = digsum(m) if x < 10: return ans ans += 1 m = x def bad_ones(n): # take advantage of the repeating nature of dig_root # and that d(ab) == d(d(a)d(b)) ndiv9, nmod9 = n // 9, n % 9 if nmod9 == 0: drs = [ndiv9] * 10 else: drs = [ndiv9 + 1] * (nmod9 + 1) + [ndiv9] * (9 - nmod9) answer = sum(drs[i] * drs[j] * drs[dr(i * j)] for j in range(1, 10) for i in range(1, 10)) answer -= sum(n // i for i in range(1, n + 1)) return answer if __name__ == '__main__': print(bad_ones(int(input().strip()))) ```
instruction
0
36,056
22
72,112
Yes
output
1
36,056
22
72,113
Provide tags and a correct Python 3 solution for this coding contest problem. A continued fraction of height n is a fraction of form <image>. You are given two rational numbers, one is represented as <image> and the other one is represented as a finite fraction of height n. Check if they are equal. Input The first line contains two space-separated integers p, q (1 ≀ q ≀ p ≀ 1018) β€” the numerator and the denominator of the first fraction. The second line contains integer n (1 ≀ n ≀ 90) β€” the height of the second fraction. The third line contains n space-separated integers a1, a2, ..., an (1 ≀ ai ≀ 1018) β€” the continued fraction. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Output Print "YES" if these fractions are equal and "NO" otherwise. Examples Input 9 4 2 2 4 Output YES Input 9 4 3 2 3 1 Output YES Input 9 4 3 1 2 4 Output NO Note In the first sample <image>. In the second sample <image>. In the third sample <image>.
instruction
0
36,410
22
72,820
Tags: brute force, implementation, math Correct Solution: ``` p, q = map(int,input().split()) n = int(input()) l = list(map(int, input().split())) for i in l: if q == 0 or i > p // q: print('NO') exit() p -= i * q p, q = q, p print('YES' if q == 0 else 'NO') ```
output
1
36,410
22
72,821
Provide tags and a correct Python 3 solution for this coding contest problem. A continued fraction of height n is a fraction of form <image>. You are given two rational numbers, one is represented as <image> and the other one is represented as a finite fraction of height n. Check if they are equal. Input The first line contains two space-separated integers p, q (1 ≀ q ≀ p ≀ 1018) β€” the numerator and the denominator of the first fraction. The second line contains integer n (1 ≀ n ≀ 90) β€” the height of the second fraction. The third line contains n space-separated integers a1, a2, ..., an (1 ≀ ai ≀ 1018) β€” the continued fraction. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Output Print "YES" if these fractions are equal and "NO" otherwise. Examples Input 9 4 2 2 4 Output YES Input 9 4 3 2 3 1 Output YES Input 9 4 3 1 2 4 Output NO Note In the first sample <image>. In the second sample <image>. In the third sample <image>.
instruction
0
36,411
22
72,822
Tags: brute force, implementation, math Correct Solution: ``` p,q=list(map(int,input().split())) n=int(input()) ara= list(map(int,input().split())) b=0 a=1 l=0 for i in ara[::-1]: l=a a=(i*a)+b b=l #print(a*q,b*p) if a*q==b*p: print("YES") else: print("NO") ```
output
1
36,411
22
72,823
Provide tags and a correct Python 3 solution for this coding contest problem. A continued fraction of height n is a fraction of form <image>. You are given two rational numbers, one is represented as <image> and the other one is represented as a finite fraction of height n. Check if they are equal. Input The first line contains two space-separated integers p, q (1 ≀ q ≀ p ≀ 1018) β€” the numerator and the denominator of the first fraction. The second line contains integer n (1 ≀ n ≀ 90) β€” the height of the second fraction. The third line contains n space-separated integers a1, a2, ..., an (1 ≀ ai ≀ 1018) β€” the continued fraction. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Output Print "YES" if these fractions are equal and "NO" otherwise. Examples Input 9 4 2 2 4 Output YES Input 9 4 3 2 3 1 Output YES Input 9 4 3 1 2 4 Output NO Note In the first sample <image>. In the second sample <image>. In the third sample <image>.
instruction
0
36,412
22
72,824
Tags: brute force, implementation, math Correct Solution: ``` from decimal import * getcontext().prec = 75 p = input().split() n = int(input()) c = input().split() a='0' for i in range(n-1,0,-1): a=str(Decimal(a)+Decimal(c[i])) a=str(Decimal('1')/Decimal(str(a))) a=str(Decimal(a)+Decimal(c[0])) b=str(Decimal(p[0])/Decimal(p[1])) if(a==b): print("YES") else: print("NO") ```
output
1
36,412
22
72,825
Provide tags and a correct Python 3 solution for this coding contest problem. A continued fraction of height n is a fraction of form <image>. You are given two rational numbers, one is represented as <image> and the other one is represented as a finite fraction of height n. Check if they are equal. Input The first line contains two space-separated integers p, q (1 ≀ q ≀ p ≀ 1018) β€” the numerator and the denominator of the first fraction. The second line contains integer n (1 ≀ n ≀ 90) β€” the height of the second fraction. The third line contains n space-separated integers a1, a2, ..., an (1 ≀ ai ≀ 1018) β€” the continued fraction. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Output Print "YES" if these fractions are equal and "NO" otherwise. Examples Input 9 4 2 2 4 Output YES Input 9 4 3 2 3 1 Output YES Input 9 4 3 1 2 4 Output NO Note In the first sample <image>. In the second sample <image>. In the third sample <image>.
instruction
0
36,413
22
72,826
Tags: brute force, implementation, math Correct Solution: ``` p,q=tuple(map(int,input().split())) n1=input().split() n=int(n1[0]) a=list(map(int,input().split())) x=1 y=a[n-1] for i in range (n-2,-1,-1): x1=a[i]*y+x x=y y=x1 if p*x==q*y: print('YES') else: print('NO') ```
output
1
36,413
22
72,827
Provide tags and a correct Python 3 solution for this coding contest problem. A continued fraction of height n is a fraction of form <image>. You are given two rational numbers, one is represented as <image> and the other one is represented as a finite fraction of height n. Check if they are equal. Input The first line contains two space-separated integers p, q (1 ≀ q ≀ p ≀ 1018) β€” the numerator and the denominator of the first fraction. The second line contains integer n (1 ≀ n ≀ 90) β€” the height of the second fraction. The third line contains n space-separated integers a1, a2, ..., an (1 ≀ ai ≀ 1018) β€” the continued fraction. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Output Print "YES" if these fractions are equal and "NO" otherwise. Examples Input 9 4 2 2 4 Output YES Input 9 4 3 2 3 1 Output YES Input 9 4 3 1 2 4 Output NO Note In the first sample <image>. In the second sample <image>. In the third sample <image>.
instruction
0
36,414
22
72,828
Tags: brute force, implementation, math Correct Solution: ``` P,Q=map(int,input().split()) n=int(input()) a = [int(i) for i in input().split()] p=[] q=[] p.append(a[0]) q.append(1) if (n==1): if(p[0]*Q==q[0]*P): print("YES") else: print("NO") else: p.append(a[1]*a[0]+1) q.append(a[1]) for i in range(2,n): p.append(a[i]*p[i-1]+p[i-2]) q.append(a[i]*q[i-1]+q[i-2]) if (p[n-1]*Q==q[n-1]*P): print("YES") else: print("NO") ```
output
1
36,414
22
72,829
Provide tags and a correct Python 3 solution for this coding contest problem. A continued fraction of height n is a fraction of form <image>. You are given two rational numbers, one is represented as <image> and the other one is represented as a finite fraction of height n. Check if they are equal. Input The first line contains two space-separated integers p, q (1 ≀ q ≀ p ≀ 1018) β€” the numerator and the denominator of the first fraction. The second line contains integer n (1 ≀ n ≀ 90) β€” the height of the second fraction. The third line contains n space-separated integers a1, a2, ..., an (1 ≀ ai ≀ 1018) β€” the continued fraction. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Output Print "YES" if these fractions are equal and "NO" otherwise. Examples Input 9 4 2 2 4 Output YES Input 9 4 3 2 3 1 Output YES Input 9 4 3 1 2 4 Output NO Note In the first sample <image>. In the second sample <image>. In the third sample <image>.
instruction
0
36,415
22
72,830
Tags: brute force, implementation, math Correct Solution: ``` from fractions import Fraction pq = Fraction(*map(int, input().split())) input() a = list(map(int, input().split())) a.reverse() f = Fraction(a[0], 1) for i in a[1:]: f = i + Fraction(1, f) if pq == f: print("YES") else: print("NO") ```
output
1
36,415
22
72,831
Provide tags and a correct Python 3 solution for this coding contest problem. A continued fraction of height n is a fraction of form <image>. You are given two rational numbers, one is represented as <image> and the other one is represented as a finite fraction of height n. Check if they are equal. Input The first line contains two space-separated integers p, q (1 ≀ q ≀ p ≀ 1018) β€” the numerator and the denominator of the first fraction. The second line contains integer n (1 ≀ n ≀ 90) β€” the height of the second fraction. The third line contains n space-separated integers a1, a2, ..., an (1 ≀ ai ≀ 1018) β€” the continued fraction. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Output Print "YES" if these fractions are equal and "NO" otherwise. Examples Input 9 4 2 2 4 Output YES Input 9 4 3 2 3 1 Output YES Input 9 4 3 1 2 4 Output NO Note In the first sample <image>. In the second sample <image>. In the third sample <image>.
instruction
0
36,416
22
72,832
Tags: brute force, implementation, math Correct Solution: ``` p, q = map(int, input().split()) n = int(input()) A = list(map(int, input().split())) for i in range(n): p, q = q, p - A[i] * q if p != 0 and q == 0: print('YES') else: print('NO') # Made By Mostafa_Khaled ```
output
1
36,416
22
72,833
Provide tags and a correct Python 3 solution for this coding contest problem. A continued fraction of height n is a fraction of form <image>. You are given two rational numbers, one is represented as <image> and the other one is represented as a finite fraction of height n. Check if they are equal. Input The first line contains two space-separated integers p, q (1 ≀ q ≀ p ≀ 1018) β€” the numerator and the denominator of the first fraction. The second line contains integer n (1 ≀ n ≀ 90) β€” the height of the second fraction. The third line contains n space-separated integers a1, a2, ..., an (1 ≀ ai ≀ 1018) β€” the continued fraction. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Output Print "YES" if these fractions are equal and "NO" otherwise. Examples Input 9 4 2 2 4 Output YES Input 9 4 3 2 3 1 Output YES Input 9 4 3 1 2 4 Output NO Note In the first sample <image>. In the second sample <image>. In the third sample <image>.
instruction
0
36,417
22
72,834
Tags: brute force, implementation, math Correct Solution: ``` def gcd(a,b): if(b==0): return a return gcd(b,a%b) p,q=map(int,input().split()) N=int(input()) A=list(map(int,input().split())) znam=1 chisl=A[N-1] for i in range (N-1,0,-1): chisl,znam=znam,chisl #print(chisl,znam) chisl += znam*A[i-1] #print(chisl,znam) if(p*znam==q*chisl): print('YES') else: print('NO') ```
output
1
36,417
22
72,835
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A continued fraction of height n is a fraction of form <image>. You are given two rational numbers, one is represented as <image> and the other one is represented as a finite fraction of height n. Check if they are equal. Input The first line contains two space-separated integers p, q (1 ≀ q ≀ p ≀ 1018) β€” the numerator and the denominator of the first fraction. The second line contains integer n (1 ≀ n ≀ 90) β€” the height of the second fraction. The third line contains n space-separated integers a1, a2, ..., an (1 ≀ ai ≀ 1018) β€” the continued fraction. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Output Print "YES" if these fractions are equal and "NO" otherwise. Examples Input 9 4 2 2 4 Output YES Input 9 4 3 2 3 1 Output YES Input 9 4 3 1 2 4 Output NO Note In the first sample <image>. In the second sample <image>. In the third sample <image>. Submitted Solution: ``` arr = [0 for i in range(100)] def gcd(a,b): if(b == 0): return a return gcd(b,a%b) def compute(a,b,c): ret = [a*c[0]+b*c[1],c[0]] return tuple(ret) def dfs(idx): if(idx == n-2): return compute(arr[idx],1,tuple([arr[idx+1],1])) return compute(arr[idx],1,dfs(idx+1)) p,q = list(map(int,input().split())) n = int(input()) arr = list(map(int,input().split())) if(n >= 2): ans = dfs(0) else: ans = tuple([arr[0],1]) d = gcd(ans[0],ans[1]) ans = tuple([ans[0]//d,ans[1]//d]) d = gcd(p,q) ans2 = tuple([p//d,q//d]) if(ans[0] == ans2[0] and ans[1] == ans2[1]): print("YES") else: print("NO") ```
instruction
0
36,418
22
72,836
Yes
output
1
36,418
22
72,837
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A continued fraction of height n is a fraction of form <image>. You are given two rational numbers, one is represented as <image> and the other one is represented as a finite fraction of height n. Check if they are equal. Input The first line contains two space-separated integers p, q (1 ≀ q ≀ p ≀ 1018) β€” the numerator and the denominator of the first fraction. The second line contains integer n (1 ≀ n ≀ 90) β€” the height of the second fraction. The third line contains n space-separated integers a1, a2, ..., an (1 ≀ ai ≀ 1018) β€” the continued fraction. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Output Print "YES" if these fractions are equal and "NO" otherwise. Examples Input 9 4 2 2 4 Output YES Input 9 4 3 2 3 1 Output YES Input 9 4 3 1 2 4 Output NO Note In the first sample <image>. In the second sample <image>. In the third sample <image>. Submitted Solution: ``` from math import gcd q,p = map(int,input().split()) n = int(input()) t = [*map(int,input().split())] d = gcd(p,q) p//=d q//=d a=int(1) b=int(t[n-1]) i=n-2 while i>=0 : a=b*t[i]+a d = gcd(a,b) a//=d b//=d i-=1 c=a a=b b=c if a==p and q==b : print("YES") else : print("NO") ```
instruction
0
36,419
22
72,838
Yes
output
1
36,419
22
72,839
Provide tags and a correct Python 3 solution for this coding contest problem. Stepan has a very big positive integer. Let's consider all cyclic shifts of Stepan's integer (if we look at his integer like at a string) which are also integers (i.e. they do not have leading zeros). Let's call such shifts as good shifts. For example, for the integer 10203 the good shifts are the integer itself 10203 and integers 20310 and 31020. Stepan wants to know the minimum remainder of the division by the given number m among all good shifts. Your task is to determine the minimum remainder of the division by m. Input The first line contains the integer which Stepan has. The length of Stepan's integer is between 2 and 200 000 digits, inclusive. It is guaranteed that Stepan's integer does not contain leading zeros. The second line contains the integer m (2 ≀ m ≀ 108) β€” the number by which Stepan divides good shifts of his integer. Output Print the minimum remainder which Stepan can get if he divides all good shifts of his integer by the given number m. Examples Input 521 3 Output 2 Input 1001 5 Output 0 Input 5678901234567890123456789 10000 Output 123 Note In the first example all good shifts of the integer 521 (good shifts are equal to 521, 215 and 152) has same remainder 2 when dividing by 3. In the second example there are only two good shifts: the Stepan's integer itself and the shift by one position to the right. The integer itself is 1001 and the remainder after dividing it by 5 equals 1. The shift by one position to the right equals to 1100 and the remainder after dividing it by 5 equals 0, which is the minimum possible remainder.
instruction
0
36,569
22
73,138
Tags: *special, math, number theory Correct Solution: ``` s = input() m = int(input()) pw = [0] * (len(s) + 1) pw[0] = 1 for i in range(1, len(s) + 1): pw[i] = pw[i - 1] * 10 % m cur = 0 for i in range(len(s)): cur *= 10 cur += ord(s[i]) - ord('0') cur %= m ans = cur for i in range(1, len(s)): cur *= 10 cur %= m cur -= ((ord(s[i - 1]) - ord('0')) * pw[len(s)] % m); cur += m cur %= m cur += ord(s[i - 1]) - ord('0') cur %= m if (s[i] != '0'): ans = min(ans, cur) print(ans) ```
output
1
36,569
22
73,139
Provide tags and a correct Python 3 solution for this coding contest problem. Stepan has a very big positive integer. Let's consider all cyclic shifts of Stepan's integer (if we look at his integer like at a string) which are also integers (i.e. they do not have leading zeros). Let's call such shifts as good shifts. For example, for the integer 10203 the good shifts are the integer itself 10203 and integers 20310 and 31020. Stepan wants to know the minimum remainder of the division by the given number m among all good shifts. Your task is to determine the minimum remainder of the division by m. Input The first line contains the integer which Stepan has. The length of Stepan's integer is between 2 and 200 000 digits, inclusive. It is guaranteed that Stepan's integer does not contain leading zeros. The second line contains the integer m (2 ≀ m ≀ 108) β€” the number by which Stepan divides good shifts of his integer. Output Print the minimum remainder which Stepan can get if he divides all good shifts of his integer by the given number m. Examples Input 521 3 Output 2 Input 1001 5 Output 0 Input 5678901234567890123456789 10000 Output 123 Note In the first example all good shifts of the integer 521 (good shifts are equal to 521, 215 and 152) has same remainder 2 when dividing by 3. In the second example there are only two good shifts: the Stepan's integer itself and the shift by one position to the right. The integer itself is 1001 and the remainder after dividing it by 5 equals 1. The shift by one position to the right equals to 1100 and the remainder after dividing it by 5 equals 0, which is the minimum possible remainder.
instruction
0
36,570
22
73,140
Tags: *special, math, number theory Correct Solution: ``` s=input() m=int(input()) N=int(s) MIN=N%m L=len(s)-1 temp1=N temp2=0 big=pow(10,L,m) for i in range(0,len(s)-1): temp2*=10 temp2+=int(s[i]) temp2%=m temp1-=big*int(s[i]) temp1*=10 temp1%=m temp=temp1+temp2 #print(temp1,temp2) #print(temp) temp%=m if s[i+1]!='0': if temp<MIN: MIN=temp print(MIN) ```
output
1
36,570
22
73,141