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Provide tags and a correct Python 3 solution for this coding contest problem. Dima loves representing an odd number as the sum of multiple primes, and Lisa loves it when there are at most three primes. Help them to represent the given number as the sum of at most than three primes. More formally, you are given an odd numer n. Find a set of numbers pi (1 ≤ i ≤ k), such that 1. 1 ≤ k ≤ 3 2. pi is a prime 3. <image> The numbers pi do not necessarily have to be distinct. It is guaranteed that at least one possible solution exists. Input The single line contains an odd number n (3 ≤ n < 109). Output In the first line print k (1 ≤ k ≤ 3), showing how many numbers are in the representation you found. In the second line print numbers pi in any order. If there are multiple possible solutions, you can print any of them. Examples Input 27 Output 3 5 11 11 Note A prime is an integer strictly larger than one that is divisible only by one and by itself.
instruction
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40,029
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Tags: brute force, math, number theory Correct Solution: ``` def check(n): d = 2 while d*d <= n: if n % d == 0: return False d += 1 return True n = int(input()) flag = False if check(n) and n > 10: print(1,'\n',n) elif n >= 9: Ans = [3] n -= 3 for i in range(2,n): if check(i) and check(n-i): print(3) print(3, i , n-i) break elif n == 3: print(1,'\n',3) elif n == 5: print(1,'\n',5) elif n == 7: print(1,'\n',7) ```
output
1
40,029
22
80,059
Provide tags and a correct Python 3 solution for this coding contest problem. Dima loves representing an odd number as the sum of multiple primes, and Lisa loves it when there are at most three primes. Help them to represent the given number as the sum of at most than three primes. More formally, you are given an odd numer n. Find a set of numbers pi (1 ≤ i ≤ k), such that 1. 1 ≤ k ≤ 3 2. pi is a prime 3. <image> The numbers pi do not necessarily have to be distinct. It is guaranteed that at least one possible solution exists. Input The single line contains an odd number n (3 ≤ n < 109). Output In the first line print k (1 ≤ k ≤ 3), showing how many numbers are in the representation you found. In the second line print numbers pi in any order. If there are multiple possible solutions, you can print any of them. Examples Input 27 Output 3 5 11 11 Note A prime is an integer strictly larger than one that is divisible only by one and by itself.
instruction
0
40,030
22
80,060
Tags: brute force, math, number theory Correct Solution: ``` def isPrime(x) : if x == 1: return False if x == 2: return True if x%2 == 0: return False i = 3 while i*i <= x : if x % i == 0 : return False i += 2 return True n = int(input()) if isPrime(n) : ans = [n] else : bigPrime = 0 for i in range(n-1, 0, -1) : if isPrime(i) : bigPrime = i break ans = [bigPrime] n -= bigPrime if isPrime(n) : ans.append(n) else : for i in range(1, n) : j = n - i if isPrime(i) and isPrime(j) : ans.append(i) ans.append(j) break print(len(ans)) for i in ans : print(i, end = ' ') ```
output
1
40,030
22
80,061
Provide tags and a correct Python 3 solution for this coding contest problem. Dima loves representing an odd number as the sum of multiple primes, and Lisa loves it when there are at most three primes. Help them to represent the given number as the sum of at most than three primes. More formally, you are given an odd numer n. Find a set of numbers pi (1 ≤ i ≤ k), such that 1. 1 ≤ k ≤ 3 2. pi is a prime 3. <image> The numbers pi do not necessarily have to be distinct. It is guaranteed that at least one possible solution exists. Input The single line contains an odd number n (3 ≤ n < 109). Output In the first line print k (1 ≤ k ≤ 3), showing how many numbers are in the representation you found. In the second line print numbers pi in any order. If there are multiple possible solutions, you can print any of them. Examples Input 27 Output 3 5 11 11 Note A prime is an integer strictly larger than one that is divisible only by one and by itself.
instruction
0
40,031
22
80,062
Tags: brute force, math, number theory Correct Solution: ``` import math def is_prime(a): for i in range(2, int(math.sqrt(a) + 1)): if a % i == 0: return False return True def solve(): n, = map(int, input().split()) if is_prime(n): print(1) print(n) return number = n while not is_prime(number): number -= 1 n -= number if is_prime(n): print(2) print(number, n) return for i in range(2, n): if is_prime(i) and is_prime(n - i): print(3) print(number, i, n - i) return if __name__ == "__main__": t = 1 # t = int(input()) for _ in range(t): solve() ```
output
1
40,031
22
80,063
Provide tags and a correct Python 3 solution for this coding contest problem. Dima loves representing an odd number as the sum of multiple primes, and Lisa loves it when there are at most three primes. Help them to represent the given number as the sum of at most than three primes. More formally, you are given an odd numer n. Find a set of numbers pi (1 ≤ i ≤ k), such that 1. 1 ≤ k ≤ 3 2. pi is a prime 3. <image> The numbers pi do not necessarily have to be distinct. It is guaranteed that at least one possible solution exists. Input The single line contains an odd number n (3 ≤ n < 109). Output In the first line print k (1 ≤ k ≤ 3), showing how many numbers are in the representation you found. In the second line print numbers pi in any order. If there are multiple possible solutions, you can print any of them. Examples Input 27 Output 3 5 11 11 Note A prime is an integer strictly larger than one that is divisible only by one and by itself.
instruction
0
40,032
22
80,064
Tags: brute force, math, number theory Correct Solution: ``` def isPrime(n) : if (n==3 or n==2) : return True if (n % 2 == 0 or n % 3 == 0) : return False i = 5 while(i * i <= n) : if (n % i == 0 or n % (i + 2) == 0) : return False i = i + 6 return True n=int(input()) if isPrime(n): print(1) print(n) exit() print(3) n-=3 for i in range(2,n): if isPrime(i) and isPrime(n-i): print(3,i,n-i) exit() ```
output
1
40,032
22
80,065
Provide tags and a correct Python 3 solution for this coding contest problem. Dima loves representing an odd number as the sum of multiple primes, and Lisa loves it when there are at most three primes. Help them to represent the given number as the sum of at most than three primes. More formally, you are given an odd numer n. Find a set of numbers pi (1 ≤ i ≤ k), such that 1. 1 ≤ k ≤ 3 2. pi is a prime 3. <image> The numbers pi do not necessarily have to be distinct. It is guaranteed that at least one possible solution exists. Input The single line contains an odd number n (3 ≤ n < 109). Output In the first line print k (1 ≤ k ≤ 3), showing how many numbers are in the representation you found. In the second line print numbers pi in any order. If there are multiple possible solutions, you can print any of them. Examples Input 27 Output 3 5 11 11 Note A prime is an integer strictly larger than one that is divisible only by one and by itself.
instruction
0
40,033
22
80,066
Tags: brute force, math, number theory Correct Solution: ``` l=list() def prime(N): count=0 i=1 while(i*i<=N): if i*i==N: count=count+1 elif N%i==0: count=count+2 if count>2: return 0 i=i+1 if count==2: return 1 else: return 0 n=int(input()) if n%2==0: for j in range(2,n): s=prime(j) t=prime(n-j) if s==1 and t==1: l.append(j) l.append(n-j) break else: l.append(3) if n-3==0: l=[3] elif n-3>2: n=n-3 for j in range(2,n): s=prime(j) t=prime(n-j) if s==1 and t==1: l.append(j) l.append(n-j) break else: l=[5] n=n-5 if n>2: for j in range(2,n): s=prime(j) t=prime(n-j) if s==1 and t==1: l.append(j) l.append(n-j) break print(len(l)) print(*l) ```
output
1
40,033
22
80,067
Provide tags and a correct Python 3 solution for this coding contest problem. Dima loves representing an odd number as the sum of multiple primes, and Lisa loves it when there are at most three primes. Help them to represent the given number as the sum of at most than three primes. More formally, you are given an odd numer n. Find a set of numbers pi (1 ≤ i ≤ k), such that 1. 1 ≤ k ≤ 3 2. pi is a prime 3. <image> The numbers pi do not necessarily have to be distinct. It is guaranteed that at least one possible solution exists. Input The single line contains an odd number n (3 ≤ n < 109). Output In the first line print k (1 ≤ k ≤ 3), showing how many numbers are in the representation you found. In the second line print numbers pi in any order. If there are multiple possible solutions, you can print any of them. Examples Input 27 Output 3 5 11 11 Note A prime is an integer strictly larger than one that is divisible only by one and by itself.
instruction
0
40,034
22
80,068
Tags: brute force, math, number theory Correct Solution: ``` import math as m n=int(input()) def prime(n): if n==1: return False for j in range(2,int(m.sqrt(n))+1): if n%j==0: return False return True if prime(n): print(1) print(n) else : ans=[] ans.append(3) n-=3 for j in range(n,1,-1): if prime(j) and prime(n-j): ans.append(j) ans.append(n-j) break print(3) print(*ans) ```
output
1
40,034
22
80,069
Provide tags and a correct Python 3 solution for this coding contest problem. Dima loves representing an odd number as the sum of multiple primes, and Lisa loves it when there are at most three primes. Help them to represent the given number as the sum of at most than three primes. More formally, you are given an odd numer n. Find a set of numbers pi (1 ≤ i ≤ k), such that 1. 1 ≤ k ≤ 3 2. pi is a prime 3. <image> The numbers pi do not necessarily have to be distinct. It is guaranteed that at least one possible solution exists. Input The single line contains an odd number n (3 ≤ n < 109). Output In the first line print k (1 ≤ k ≤ 3), showing how many numbers are in the representation you found. In the second line print numbers pi in any order. If there are multiple possible solutions, you can print any of them. Examples Input 27 Output 3 5 11 11 Note A prime is an integer strictly larger than one that is divisible only by one and by itself.
instruction
0
40,035
22
80,070
Tags: brute force, math, number theory Correct Solution: ```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erfection is achieved not when there is nothing more to add, but rather when there is nothing more to take away. """ import sys input = sys.stdin.readline # from bisect import bisect_left as lower_bound; # from bisect import bisect_right as upper_bound; # from math import ceil, factorial; def ceil(x): if x != int(x): x = int(x) + 1 return x def factorial(x, m): val = 1 while x>0: val = (val * x) % m x -= 1 return val def fact(x): val = 1 while x > 0: val *= x x -= 1 return val # swap_array function def swaparr(arr, a,b): temp = arr[a]; arr[a] = arr[b]; arr[b] = temp; ## gcd function def gcd(a,b): if b == 0: return a; return gcd(b, a % b); ## lcm function def lcm(a, b): return (a * b) // gcd(a, b) ## nCr function efficient using Binomial Cofficient def nCr(n, k): if k > n: return 0 if(k > n - k): k = n - k res = 1 for i in range(k): res = res * (n - i) res = res / (i + 1) return int(res) ## upper bound function code -- such that e in a[:i] e < x; def upper_bound(a, x, lo=0, hi = None): if hi == None: hi = len(a); while lo < hi: mid = (lo+hi)//2; if a[mid] < x: lo = mid+1; else: hi = mid; return lo; ## prime factorization def primefs(n): ## if n == 1 ## calculating primes primes = {} while(n%2 == 0 and n > 0): primes[2] = primes.get(2, 0) + 1 n = n//2 for i in range(3, int(n**0.5)+2, 2): while(n%i == 0 and n > 0): primes[i] = primes.get(i, 0) + 1 n = n//i if n > 2: primes[n] = primes.get(n, 0) + 1 ## prime factoriazation of n is stored in dictionary ## primes and can be accesed. O(sqrt n) return primes ## MODULAR EXPONENTIATION FUNCTION def power(x, y, p): res = 1 x = x % p if (x == 0) : return 0 while (y > 0) : if ((y & 1) == 1) : res = (res * x) % p y = y >> 1 x = (x * x) % p return res ## DISJOINT SET UNINON FUNCTIONS def swap(a,b): temp = a a = b b = temp return a,b; # find function with path compression included (recursive) # def find(x, link): # if link[x] == x: # return x # link[x] = find(link[x], link); # return link[x]; # find function with path compression (ITERATIVE) def find(x, link): p = x; while( p != link[p]): p = link[p]; while( x != p): nex = link[x]; link[x] = p; x = nex; return p; # the union function which makes union(x,y) # of two nodes x and y def union(x, y, link, size): x = find(x, link) y = find(y, link) if size[x] < size[y]: x,y = swap(x,y) if x != y: size[x] += size[y] link[y] = x ## returns an array of boolean if primes or not USING SIEVE OF ERATOSTHANES def sieve(n): prime = [True for i in range(n+1)] prime[0], prime[1] = False, False p = 2 while (p * p <= n): if (prime[p] == True): for i in range(p * p, n+1, p): prime[i] = False p += 1 return prime # Euler's Toitent Function phi def phi(n) : result = n p = 2 while(p * p<= n) : if (n % p == 0) : while (n % p == 0) : n = n // p result = result * (1.0 - (1.0 / (float) (p))) p = p + 1 if (n > 1) : result = result * (1.0 - (1.0 / (float)(n))) return (int)(result) def is_prime(n): for i in range(2, int(n ** (1 / 2)) + 1): if not n % i: return False return True #### PRIME FACTORIZATION IN O(log n) using Sieve #### MAXN = int(1e5 + 5) def spf_sieve(): spf[1] = 1; for i in range(2, MAXN): spf[i] = i; for i in range(4, MAXN, 2): spf[i] = 2; for i in range(3, ceil(MAXN ** 0.5), 2): if spf[i] == i: for j in range(i*i, MAXN, i): if spf[j] == j: spf[j] = i; ## function for storing smallest prime factors (spf) in the array ################## un-comment below 2 lines when using factorization ################# spf = [0 for i in range(MAXN)] # spf_sieve(); def factoriazation(x): res = [] for i in range(2, int(x ** 0.5) + 1): while x % i == 0: res.append(i) x //= i if x != 1: res.append(x) return res ## this function is useful for multiple queries only, o/w use ## primefs function above. complexity O(log n) def factors(n): res = [] for i in range(1, int(n ** 0.5) + 1): if n % i == 0: res.append(i) res.append(n // i) return list(set(res)) ## taking integer array input def int_array(): return list(map(int, input().strip().split())); def float_array(): return list(map(float, input().strip().split())); ## taking string array input def str_array(): return input().strip().split(); #defining a couple constants MOD = int(1e9)+7; CMOD = 998244353; INF = float('inf'); NINF = -float('inf'); ################### ---------------- TEMPLATE ENDS HERE ---------------- ################### from itertools import permutations import math from bisect import bisect_left def solve(): n = int(input()) # primes = sieve(n) if is_prime(n): print(1) print(n) return ans = [] i = n c = 3 for i in range(n, 1, -1): if is_prime(i): ans.append(i) n -= i break for i in range(2, n + 1): if is_prime(i) and n - i == 0: ans.append(i) break elif is_prime(i) and is_prime(n - i): ans.append(i) ans.append(n - i) break print(len(ans)) print(*ans) if __name__ == '__main__': for _ in range(1): solve() # fin_time = datetime.now() # print("Execution time (for loop): ", (fin_time-init_time)) ```
output
1
40,035
22
80,071
Provide tags and a correct Python 3 solution for this coding contest problem. Dima loves representing an odd number as the sum of multiple primes, and Lisa loves it when there are at most three primes. Help them to represent the given number as the sum of at most than three primes. More formally, you are given an odd numer n. Find a set of numbers pi (1 ≤ i ≤ k), such that 1. 1 ≤ k ≤ 3 2. pi is a prime 3. <image> The numbers pi do not necessarily have to be distinct. It is guaranteed that at least one possible solution exists. Input The single line contains an odd number n (3 ≤ n < 109). Output In the first line print k (1 ≤ k ≤ 3), showing how many numbers are in the representation you found. In the second line print numbers pi in any order. If there are multiple possible solutions, you can print any of them. Examples Input 27 Output 3 5 11 11 Note A prime is an integer strictly larger than one that is divisible only by one and by itself.
instruction
0
40,036
22
80,072
Tags: brute force, math, number theory Correct Solution: ``` import math n = int(input()) p = [0 for _ in range(1001)] x = 2 p[0] = 1 p[1] = 1 while x * x <= 1001: for i in range(2 * x, 1001, x): p[i] = 1 x += 1 pr = 0 def isprime(num): for i in range(2, int(math.sqrt(n)) + 1): if num % i == 0: return False return True e = 0 if isprime(n): print(1) print(n) exit(0) for k in range(n, 1, -1): if isprime(k): if (n - k) % 2 == 0: pr = n - k e = 1 break if pr == 2: print(2) print(2, n - 2) exit(0) for i in range(2, 1001): if p[pr - i] == 0 and p[i] == 0: print(3) print(n - pr, i, pr - i) exit(0) ```
output
1
40,036
22
80,073
Provide tags and a correct Python 2 solution for this coding contest problem. Dima loves representing an odd number as the sum of multiple primes, and Lisa loves it when there are at most three primes. Help them to represent the given number as the sum of at most than three primes. More formally, you are given an odd numer n. Find a set of numbers pi (1 ≤ i ≤ k), such that 1. 1 ≤ k ≤ 3 2. pi is a prime 3. <image> The numbers pi do not necessarily have to be distinct. It is guaranteed that at least one possible solution exists. Input The single line contains an odd number n (3 ≤ n < 109). Output In the first line print k (1 ≤ k ≤ 3), showing how many numbers are in the representation you found. In the second line print numbers pi in any order. If there are multiple possible solutions, you can print any of them. Examples Input 27 Output 3 5 11 11 Note A prime is an integer strictly larger than one that is divisible only by one and by itself.
instruction
0
40,037
22
80,074
Tags: brute force, math, number theory Correct Solution: ``` from sys import stdin, stdout from collections import Counter, defaultdict from itertools import permutations, combinations raw_input = stdin.readline pr = stdout.write mod=10**9+7 def ni(): return int(raw_input()) def li(): return map(int,raw_input().split()) def pn(n): stdout.write(str(n)+'\n') def pa(arr): pr(' '.join(map(str,arr))+'\n') # fast read function for total integer input def inp(): # this function returns whole input of # space/line seperated integers # Use Ctrl+D to flush stdin. return map(int,stdin.read().split()) range = xrange # not for python 3.0+ # main code def isPrime(x): i=2 while i*i<=x: if x%i==0: return False i+=1 return True n=ni() if isPrime(n): print 1 print n exit() for i in range(2,10**6): temp=n-3-i if temp>1 and isPrime(i) and isPrime(temp): print 3 print 3,i,temp exit() ```
output
1
40,037
22
80,075
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Dima loves representing an odd number as the sum of multiple primes, and Lisa loves it when there are at most three primes. Help them to represent the given number as the sum of at most than three primes. More formally, you are given an odd numer n. Find a set of numbers pi (1 ≤ i ≤ k), such that 1. 1 ≤ k ≤ 3 2. pi is a prime 3. <image> The numbers pi do not necessarily have to be distinct. It is guaranteed that at least one possible solution exists. Input The single line contains an odd number n (3 ≤ n < 109). Output In the first line print k (1 ≤ k ≤ 3), showing how many numbers are in the representation you found. In the second line print numbers pi in any order. If there are multiple possible solutions, you can print any of them. Examples Input 27 Output 3 5 11 11 Note A prime is an integer strictly larger than one that is divisible only by one and by itself. Submitted Solution: ``` from sys import stdin input=lambda : stdin.readline().strip() lin=lambda :list(map(int,input().split())) iin=lambda :int(input()) main=lambda :map(int,input().split()) from math import ceil,sqrt,factorial,log from collections import deque from bisect import bisect_left def isprime(x): if x==3 or x==5: return 1 for i in range(2,ceil(sqrt(x)+1)): if x%i==0: return 0 return 1 def solve(): n=iin() l=[] z=[2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97,101,103,107,109,113,127,131,137,139,149,151,157,163,167,173,179,181,191,193,197,199,211,223,227,229,233,239,241,251,257,263,269,271,277,281,283,293,307,311,313,317,331,337,347,349,353,359,367,373,379,383,389,397,401,409,419,421,431,433,439,443,449,457,461,463,467,479,487,491,499,503,509,521,523,541,547,557,563,569,571,577,587,593,599,601,607,613,617,619,631,641,643,647,653,659,661,673,677,683,691,701,709,719,727,733,739,743,751,757,761,769,773,787,797,809,811,821,823,827,829,839,853,857,859,863,877,881,883,887,907,911,919,929,937,941,947,953,967,971,977,983,991,997,1009,1013,1019,1021,1031,1033,1039,1049,1051,1061,1063,1069,1087,1091,1093,1097,1103,1109,1117,1123,1129,1151,1153,1163,1171,1181,1187,1193,1201,1213,1217,1223,1229,1231,1237,1249,1259,1277,1279,1283,1289,1291,1297,1301,1303,1307,1319,1321,1327,1361,1367,1373,1381,1399,1409,1423,1427,1429,1433,1439,1447,1451,1453,1459,1471,1481,1483,1487,1489,1493,1499,1511,1523,1531,1543,1549,1553,1559,1567,1571,1579,1583,1597,1601,1607,1609,1613,1619,1621,1627,1637,1657,1663,1667,1669,1693,1697,1699,1709,1721,1723,1733,1741,1747,1753,1759,1777,1783,1787,1789,1801,1811,1823,1831,1847,1861,1867,1871,1873,1877,1879,1889,1901,1907,1913,1931,1933,1949,1951,1973,1979,1987,1993,1997,1999,2003,2011,2017,2027,2029,2039,2053,2063,2069,2081,2083,2087,2089,2099,2111,2113,2129,2131,2137,2141,2143,2153,2161,2179,2203,2207,2213,2221,2237,2239,2243,2251,2267,2269,2273,2281,2287,2293,2297,2309,2311,2333,2339,2341,2347,2351,2357,2371,2377,2381,2383,2389,2393,2399,2411,2417,2423,2437,2441,2447,2459,2467,2473,2477,2503,2521,2531,2539,2543,2549,2551,2557,2579,2591,2593,2609,2617,2621,2633,2647,2657,2659,2663,2671,2677,2683,2687,2689,2693,2699,2707,2711,2713,2719,2729,2731,2741,2749,2753,2767,2777,2789,2791,2797,2801,2803,2819,2833,2837,2843,2851,2857,2861,2879,2887,2897,2903,2909,2917,2927,2939,2953,2957,2963,2969,2971,2999,3001,3011,3019,3023,3037,3041,3049,3061,3067,3079,3083,3089,3109,3119,3121,3137,3163,3167,3169,3181,3187,3191,3203,3209,3217,3221,3229,3251,3253,3257,3259,3271,3299,3301,3307,3313,3319,3323,3329,3331,3343,3347,3359,3361,3371,3373,3389,3391,3407,3413,3433,3449,3457,3461,3463,3467,3469,3491,3499,3511,3517,3527,3529,3533,3539,3541,3547,3557,3559,3571,3581,3583,3593,3607,3613,3617,3623,3631,3637,3643,3659,3671,3673,3677,3691,3697,3701,3709,3719,3727,3733,3739,3761,3767,3769,3779,3793,3797,3803,3821,3823,3833,3847,3851,3853,3863,3877,3881,3889,3907,3911,3917,3919,3923,3929,3931,3943,3947,3967,3989,4001,4003,4007,4013,4019,4021,4027,4049,4051,4057,4073,4079,4091,4093,4099,4111,4127,4129,4133,4139,4153,4157,4159,4177,4201,4211,4217,4219,4229,4231,4241,4243,4253,4259,4261,4271,4273,4283,4289,4297,4327,4337,4339,4349,4357,4363,4373,4391,4397,4409,4421,4423,4441,4447,4451,4457,4463,4481,4483,4493,4507,4513,4517,4519,4523,4547,4549,4561,4567,4583,4591,4597,4603,4621,4637,4639,4643,4649,4651,4657,4663,4673,4679,4691,4703,4721,4723,4729,4733,4751,4759,4783,4787,4789,4793,4799,4801,4813,4817,4831,4861,4871,4877,4889,4903,4909,4919,4931,4933,4937,4943,4951,4957,4967,4969,4973,4987,4993,4999,5003,5009,5011,5021,5023,5039,5051,5059,5077,5081,5087,5099,5101,5107,5113,5119,5147,5153,5167,5171,5179,5189,5197,5209,5227,5231,5233,5237,5261,5273,5279,5281,5297,5303,5309,5323,5333,5347,5351,5381,5387,5393,5399,5407,5413,5417,5419,5431,5437,5441,5443,5449,5471,5477,5479,5483,5501,5503,5507,5519,5521,5527,5531,5557,5563,5569,5573,5581,5591,5623,5639,5641,5647,5651,5653,5657,5659,5669,5683,5689,5693,5701,5711,5717,5737,5741,5743,5749,5779,5783,5791,5801,5807,5813,5821,5827,5839,5843,5849,5851,5857,5861,5867,5869,5879,5881,5897,5903,5923,5927,5939,5953,5981,5987,6007,6011,6029,6037,6043,6047,6053,6067,6073,6079,6089,6091,6101,6113,6121,6131,6133,6143,6151,6163,6173,6197,6199,6203,6211,6217,6221,6229,6247,6257,6263,6269,6271,6277,6287,6299,6301,6311,6317,6323,6329,6337,6343,6353,6359,6361,6367,6373,6379,6389,6397,6421,6427,6449,6451,6469,6473,6481,6491,6521,6529,6547,6551,6553,6563,6569,6571,6577,6581,6599,6607,6619,6637,6653,6659,6661,6673,6679,6689,6691,6701,6703,6709,6719,6733,6737,6761,6763,6779,6781,6791,6793,6803,6823,6827,6829,6833,6841,6857,6863,6869,6871,6883,6899,6907,6911,6917,6947,6949,6959,6961,6967,6971,6977,6983,6991,6997,7001,7013,7019,7027,7039,7043,7057,7069,7079,7103,7109,7121,7127,7129,7151,7159,7177,7187,7193,7207,7211,7213,7219,7229,7237,7243,7247,7253,7283,7297,7307,7309,7321,7331,7333,7349,7351,7369,7393,7411,7417,7433,7451,7457,7459,7477,7481,7487,7489,7499,7507,7517,7523,7529,7537,7541,7547,7549,7559,7561,7573,7577,7583,7589,7591,7603,7607,7621,7639,7643,7649,7669,7673,7681,7687,7691,7699,7703,7717,7723,7727,7741,7753,7757,7759,7789,7793,7817,7823,7829,7841,7853,7867,7873,7877,7879,7883,7901,7907,7919,7927,7933,7937,7949,7951,7963,7993,8009,8011,8017,8039,8053,8059,8069,8081,8087,8089,8093,8101,8111,8117,8123,8147,8161,8167,8171,8179,8191,8209,8219,8221,8231,8233,8237,8243,8263,8269,8273,8287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s=set(z) x=0 while n-2*x>0: if isprime(n-2*x): t=2*x if t!=0: for i in z: if t-i==0: l=[n-2*x,i] break elif t-i in s: l=[n-2*x,i,t-i] break else: l=[n] break x+=1 print(len(l)) print(*l) # print(isprime(61)) qwe=1 # qwe=int(input()) for _ in range(qwe): solve() ```
instruction
0
40,038
22
80,076
Yes
output
1
40,038
22
80,077
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Dima loves representing an odd number as the sum of multiple primes, and Lisa loves it when there are at most three primes. Help them to represent the given number as the sum of at most than three primes. More formally, you are given an odd numer n. Find a set of numbers pi (1 ≤ i ≤ k), such that 1. 1 ≤ k ≤ 3 2. pi is a prime 3. <image> The numbers pi do not necessarily have to be distinct. It is guaranteed that at least one possible solution exists. Input The single line contains an odd number n (3 ≤ n < 109). Output In the first line print k (1 ≤ k ≤ 3), showing how many numbers are in the representation you found. In the second line print numbers pi in any order. If there are multiple possible solutions, you can print any of them. Examples Input 27 Output 3 5 11 11 Note A prime is an integer strictly larger than one that is divisible only by one and by itself. Submitted Solution: ``` gap = 300 m = 1 << 15 isp = [False]*2 + [True]*(m - 1) ps = [] for i in range(2, m + 1): if isp[i]: ps.append(i) for j in range(i * i, m + 1, i): isp[j] = False n = int(input()) assert n % 2 if n >= m: low = n - gap ispg = [True]*(gap + 1) for p in ps: for i in range((low - 1) // p + 1, n // p + 1): ispg[i * p - low] = False def is_prime(k): return isp[k] if k <= m else ispg[k - low] p = n while not is_prime(p): p -= 2 s = [p] if p != n: if n - p == 2: s += [n - p] else: q = 2 while not (is_prime(q) and is_prime(n - p - q)): q += 1 s += [q, n - p - q] print(len(s)) print(*s) ```
instruction
0
40,039
22
80,078
Yes
output
1
40,039
22
80,079
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Dima loves representing an odd number as the sum of multiple primes, and Lisa loves it when there are at most three primes. Help them to represent the given number as the sum of at most than three primes. More formally, you are given an odd numer n. Find a set of numbers pi (1 ≤ i ≤ k), such that 1. 1 ≤ k ≤ 3 2. pi is a prime 3. <image> The numbers pi do not necessarily have to be distinct. It is guaranteed that at least one possible solution exists. Input The single line contains an odd number n (3 ≤ n < 109). Output In the first line print k (1 ≤ k ≤ 3), showing how many numbers are in the representation you found. In the second line print numbers pi in any order. If there are multiple possible solutions, you can print any of them. Examples Input 27 Output 3 5 11 11 Note A prime is an integer strictly larger than one that is divisible only by one and by itself. Submitted Solution: ``` from math import sqrt from array import array from sys import stdin input = stdin.readline n = int(input()) ans = [] if n == 3: ans.append(3) print('{}'.format(len(ans)) + '\n' + ''.join(str(x) + ' ' for x in ans)) exit(0) N = n magic_value = 300 primes = array('L') primes.append(2) lim = int(sqrt(N)) + 1 for number in range(3, lim, 2): isPrime = True for prime in primes: if number % prime == 0: isPrime = False break if isPrime: primes.append(number) def checkPrime(x): lim = int(sqrt(x) + 1) isPrime = True for prime in primes: if x % prime == 0: isPrime = False break if prime > lim: break return isPrime for sub in range(0, magic_value, 2): if checkPrime(n - sub): ans.append(n - sub) n = sub break if n == 0: print('{}'.format(len(ans)) + '\n' + ''.join(str(x) + ' ' for x in ans)) exit(0) for prime in primes: if n == prime: ans.append(n) break if n - prime in primes: ans.append(prime) ans.append(n - prime) break if prime > n: break print('{}'.format(len(ans)) + '\n' + ''.join(str(x) + ' ' for x in ans)) ```
instruction
0
40,040
22
80,080
Yes
output
1
40,040
22
80,081
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Dima loves representing an odd number as the sum of multiple primes, and Lisa loves it when there are at most three primes. Help them to represent the given number as the sum of at most than three primes. More formally, you are given an odd numer n. Find a set of numbers pi (1 ≤ i ≤ k), such that 1. 1 ≤ k ≤ 3 2. pi is a prime 3. <image> The numbers pi do not necessarily have to be distinct. It is guaranteed that at least one possible solution exists. Input The single line contains an odd number n (3 ≤ n < 109). Output In the first line print k (1 ≤ k ≤ 3), showing how many numbers are in the representation you found. In the second line print numbers pi in any order. If there are multiple possible solutions, you can print any of them. Examples Input 27 Output 3 5 11 11 Note A prime is an integer strictly larger than one that is divisible only by one and by itself. Submitted Solution: ``` def main(): n = int(input()) if n == 3: print(1) print(3) elif n == 4: print(2) print(2, 2) elif n == 5: print(2) print(2, 3) elif n == 6: print(2) print(3, 3) elif n == 7: print(2) print(2, 5) elif n == 8: print(2) print(3, 5) elif n == 9: print(2) print(2, 7) elif n == 10: print(2) print(3, 7) if n <= 10: return for i in range(n, -1, -1): j = 2 simple = True while (j * j <= i): if (i % j == 0): simple = False j += 1 if simple: n -= i break ans = [i] prime = [True] * (n+2) prime[0] = False prime[1] = False #print(prime) for i in range(2, n+1): if prime[i]: if i * i <= n: for j in range(i * i, n+1, i): #print(j) prime[j] = False #print(i, prime) i = k = 0 for i in range(2, n+1): k = n - i if prime[i] and prime[k]: break if i != 0: ans.append(i) if k != 0: ans.append(k) print(len(ans)) for x in ans: print(x, end=" ") main() ```
instruction
0
40,041
22
80,082
Yes
output
1
40,041
22
80,083
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Dima loves representing an odd number as the sum of multiple primes, and Lisa loves it when there are at most three primes. Help them to represent the given number as the sum of at most than three primes. More formally, you are given an odd numer n. Find a set of numbers pi (1 ≤ i ≤ k), such that 1. 1 ≤ k ≤ 3 2. pi is a prime 3. <image> The numbers pi do not necessarily have to be distinct. It is guaranteed that at least one possible solution exists. Input The single line contains an odd number n (3 ≤ n < 109). Output In the first line print k (1 ≤ k ≤ 3), showing how many numbers are in the representation you found. In the second line print numbers pi in any order. If there are multiple possible solutions, you can print any of them. Examples Input 27 Output 3 5 11 11 Note A prime is an integer strictly larger than one that is divisible only by one and by itself. Submitted Solution: ``` from math import * prime = [ 0,2 , 3 , 5 , 7 , 11 , 13, 17, 19, 23, 29, 31 , 37 , 41 , 43 , 47 , 53 , 59, 61, 67, 71, 73 , 79 , 83 , 89 , 97 , 101 , 103, 107, 109 , 113, 127 , 131 , 137 , 139 , 149 , 151 , 157 , 163 , 167, 173, 179 , 181 , 191 , 193 , 197 , 199 , 211 , 223 , 227 , 229, 233 , 239 , 241 , 251 , 257 , 263 , 269 , 271 , 277 , 281, 283 , 293 , 307 , 311 , 313 , 317 , 331 , 337 , 347 , 349, 353 , 359 , 367 , 373 , 379 , 383 , 389 , 397 , 401 , 409, 419 , 421 , 431 , 433 , 439 , 443 , 449 , 457 , 461 , 463, 467 , 479 , 487 , 491 , 499 , 503 , 509 , 521 , 523 , 541, 547 , 557 , 563 , 569 , 571 , 577 , 587 , 593 , 599 , 601, 607 , 613 , 617 , 619 , 631 , 641 , 643 , 647 , 653 , 659, 661 , 673 , 677 , 683 , 691 , 701 , 709 , 719 , 727 , 733, 739 , 743 , 751 , 757 , 761 , 769 , 773 , 787 , 797 , 809, 811 , 821 , 823 , 827 , 829 , 839 , 853 , 857 , 859 , 863, 877 , 881 , 883 , 887 , 907 , 911 , 919 , 929 , 937 , 941, 947 , 953 , 967 , 971, 977, 983 , 991, 997, 1009, 1013] def divider(n): if n==1: return 0 i = 2 j = 0 while i**2 <= n and j != 1: if n%i == 0: j = 1 i += 1 if j == 1: return 0 else: return 1 n = int(input()) if n==3: print(3) quit() for i in range(len(prime)): for j in range(len(prime)): if divider(n-prime[i]-prime[j])==1: if prime[j]==0 and prime[i]==0: print(n) quit() if prime[i]==0: print(prime[j],n-prime[j]) quit() if prime[j]==0: print(prime[i],n-prime[i]) quit() print(prime[i],prime[i],prime[j]) quit() ```
instruction
0
40,042
22
80,084
No
output
1
40,042
22
80,085
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Dima loves representing an odd number as the sum of multiple primes, and Lisa loves it when there are at most three primes. Help them to represent the given number as the sum of at most than three primes. More formally, you are given an odd numer n. Find a set of numbers pi (1 ≤ i ≤ k), such that 1. 1 ≤ k ≤ 3 2. pi is a prime 3. <image> The numbers pi do not necessarily have to be distinct. It is guaranteed that at least one possible solution exists. Input The single line contains an odd number n (3 ≤ n < 109). Output In the first line print k (1 ≤ k ≤ 3), showing how many numbers are in the representation you found. In the second line print numbers pi in any order. If there are multiple possible solutions, you can print any of them. Examples Input 27 Output 3 5 11 11 Note A prime is an integer strictly larger than one that is divisible only by one and by itself. Submitted Solution: ``` #rOkY #FuCk ############################### kOpAl ################################## t=int(input()) print(1,1,t-2) ```
instruction
0
40,043
22
80,086
No
output
1
40,043
22
80,087
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Dima loves representing an odd number as the sum of multiple primes, and Lisa loves it when there are at most three primes. Help them to represent the given number as the sum of at most than three primes. More formally, you are given an odd numer n. Find a set of numbers pi (1 ≤ i ≤ k), such that 1. 1 ≤ k ≤ 3 2. pi is a prime 3. <image> The numbers pi do not necessarily have to be distinct. It is guaranteed that at least one possible solution exists. Input The single line contains an odd number n (3 ≤ n < 109). Output In the first line print k (1 ≤ k ≤ 3), showing how many numbers are in the representation you found. In the second line print numbers pi in any order. If there are multiple possible solutions, you can print any of them. Examples Input 27 Output 3 5 11 11 Note A prime is an integer strictly larger than one that is divisible only by one and by itself. Submitted Solution: ``` from sys import stdin input=lambda : stdin.readline().strip() lin=lambda :list(map(int,input().split())) iin=lambda :int(input()) main=lambda :map(int,input().split()) from math import ceil,sqrt,factorial,log from collections import deque from bisect import bisect_left def isprime(x): if x==3 or x==5: return 1 for i in range(2,ceil(sqrt(x)+1)): if x%i==0: return 0 return 1 def solve(): n=iin() if isprime(n): print(1) print(n) elif isprime(n-2): print(2) print(n-2,2) else: print(3) print(n-4,2,2) qwe=1 # qwe=int(input()) for _ in range(qwe): solve() ```
instruction
0
40,044
22
80,088
No
output
1
40,044
22
80,089
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Dima loves representing an odd number as the sum of multiple primes, and Lisa loves it when there are at most three primes. Help them to represent the given number as the sum of at most than three primes. More formally, you are given an odd numer n. Find a set of numbers pi (1 ≤ i ≤ k), such that 1. 1 ≤ k ≤ 3 2. pi is a prime 3. <image> The numbers pi do not necessarily have to be distinct. It is guaranteed that at least one possible solution exists. Input The single line contains an odd number n (3 ≤ n < 109). Output In the first line print k (1 ≤ k ≤ 3), showing how many numbers are in the representation you found. In the second line print numbers pi in any order. If there are multiple possible solutions, you can print any of them. Examples Input 27 Output 3 5 11 11 Note A prime is an integer strictly larger than one that is divisible only by one and by itself. Submitted Solution: ``` def prost(n): k=0 for i in range(2,n): if n%i==0: k+=1 if k==0: return(0) else: return(1) n=int(input()) np=n bo=prost(n) kol=0 sd='' s='' if bo==0: print(1,n,sep='\n') else: for i in range(n-1,1,-1): if np==0: break else: bo=prost(i) if bo==0: np=n-i kol+=1 sd+=str(i)+' ' while np>0: if np>2: for i in range(2,np): bo=prost(i) if bo==0: if np-i>=0: np=np-i kol+=1 sd+=str(i)+' ' if prost(np)==0: kol+=1 print(kol,sd+str(np),sep='\n') np=0 break else: pass if np!=0: np=0 if np!=0: np=n n=n-1 sd=s kol=0 ```
instruction
0
40,045
22
80,090
No
output
1
40,045
22
80,091
Provide tags and a correct Python 3 solution for this coding contest problem. You are given an image, that can be represented with a 2-d n by m grid of pixels. Each pixel of the image is either on or off, denoted by the characters "0" or "1", respectively. You would like to compress this image. You want to choose an integer k > 1 and split the image into k by k blocks. If n and m are not divisible by k, the image is padded with only zeros on the right and bottom so that they are divisible by k. Each pixel in each individual block must have the same value. The given image may not be compressible in its current state. Find the minimum number of pixels you need to toggle (after padding) in order for the image to be compressible for some k. More specifically, the steps are to first choose k, then the image is padded with zeros, then, we can toggle the pixels so it is compressible for this k. The image must be compressible in that state. Input The first line of input will contain two integers n, m (2 ≤ n, m ≤ 2 500), the dimensions of the image. The next n lines of input will contain a binary string with exactly m characters, representing the image. Output Print a single integer, the minimum number of pixels needed to toggle to make the image compressible. Example Input 3 5 00100 10110 11001 Output 5 Note We first choose k = 2. The image is padded as follows: 001000 101100 110010 000000 We can toggle the image to look as follows: 001100 001100 000000 000000 We can see that this image is compressible for k = 2.
instruction
0
40,113
22
80,226
Tags: brute force Correct Solution: ``` def debug(*a): return print('[DEBUG]', *a) is_prime = [False, False] + [True] * (2600-2) for i in range(2, 2600): if is_prime[i]: for j in range(i+i, 2600, i): is_prime[j] = False n, m = map(int, input().split()) a = [None] * n for i in range(n): a[i] = input() b = [None] * (n+1) b[n] = [0] * (m+1) for i in range(n-1, -1, -1): b[i] = [0] * (m+1) for j in range(m-1, -1, -1): b[i][j] = b[i+1][j] + b[i][j+1] - b[i+1][j+1] + int(a[i][j]) # debug(b[i]) ans = None for k in range(2, max(n, m)+1): # if is_prime[k]: # debug('k=', k) kk = k*k aa = 0 for i in range(0, n, k): for j in range(0, m, k): bb = b[i][j] if i + k < n: bb -= b[i+k][j] if j + k < m: bb -= b[i][j+k] if i + k < n and j + k < m: bb += b[i+k][j+k] # debug(i, j, bb) aa += min(bb, kk-bb) # debug('aa=', aa) if ans == None or aa < ans: ans = aa print(ans) ```
output
1
40,113
22
80,227
Provide tags and a correct Python 3 solution for this coding contest problem. You are given an image, that can be represented with a 2-d n by m grid of pixels. Each pixel of the image is either on or off, denoted by the characters "0" or "1", respectively. You would like to compress this image. You want to choose an integer k > 1 and split the image into k by k blocks. If n and m are not divisible by k, the image is padded with only zeros on the right and bottom so that they are divisible by k. Each pixel in each individual block must have the same value. The given image may not be compressible in its current state. Find the minimum number of pixels you need to toggle (after padding) in order for the image to be compressible for some k. More specifically, the steps are to first choose k, then the image is padded with zeros, then, we can toggle the pixels so it is compressible for this k. The image must be compressible in that state. Input The first line of input will contain two integers n, m (2 ≤ n, m ≤ 2 500), the dimensions of the image. The next n lines of input will contain a binary string with exactly m characters, representing the image. Output Print a single integer, the minimum number of pixels needed to toggle to make the image compressible. Example Input 3 5 00100 10110 11001 Output 5 Note We first choose k = 2. The image is padded as follows: 001000 101100 110010 000000 We can toggle the image to look as follows: 001100 001100 000000 000000 We can see that this image is compressible for k = 2.
instruction
0
40,114
22
80,228
Tags: brute force Correct Solution: ``` def debug(*a): return print('[DEBUG]', *a) is_prime = [False, False] + [True] * (2600-2) for i in range(2, 2600): if is_prime[i]: for j in range(i+i, 2600, i): is_prime[j] = False n, m = map(int, input().split()) a = [None] * n for i in range(n): a[i] = input() b = [None] * (n+1) b[n] = [0] * (m+1) for i in range(n-1, -1, -1): b[i] = [0] * (m+1) for j in range(m-1, -1, -1): b[i][j] = b[i+1][j] + b[i][j+1] - b[i+1][j+1] + int(a[i][j]) # debug(b[i]) ans = None for k in range(2, max(n, m)+1): if is_prime[k]: # debug('k=', k) kk = k*k aa = 0 for i in range(0, n, k): for j in range(0, m, k): bb = b[i][j] if i + k < n: bb -= b[i+k][j] if j + k < m: bb -= b[i][j+k] if i + k < n and j + k < m: bb += b[i+k][j+k] # debug(i, j, bb) aa += min(bb, kk-bb) # debug('aa=', aa) if ans == None or aa < ans: ans = aa print(ans) ```
output
1
40,114
22
80,229
Provide a correct Python 3 solution for this coding contest problem. Let M be a positive integer. You are given 2 N integers a_1, a_2, \ldots, a_{2 N}, where 0 \leq a_i < M for each i. Consider dividing the 2 N integers into N pairs. Here, each integer must belong to exactly one pair. We define the ugliness of a pair (x, y) as (x + y) \mod M. Let Z be the largest ugliness of the N pairs. Find the minimum possible value of Z. Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * 1 \leq M \leq 10^9 * 0 \leq a_i < M Input Input is given from Standard Input in the following format: N M a_1 a_2 \cdots a_{2N} Output Print the minimum possible value of Z, where Z is the largest ugliness of the N pairs. Examples Input 3 10 0 2 3 4 5 9 Output 5 Input 2 10 1 9 1 9 Output 0
instruction
0
40,240
22
80,480
"Correct Solution: ``` def modulo_pairing(N: int, M: int, A: list)->int: A.sort() def check(n: int)->bool: '''2*n の位置を区切りとして、右側が全て赤のペアになることを確認する。 ''' for i in range(2*n, N+n): if A[i] + A[2*N+2*n-i-1] < M: return False return True l, r = -1, N+1 while r - l > 1: m = (l + r) // 2 if check(m): r = m else: l = m blue = [A[i]+A[2*r-i-1] for i in range(r)] red = [A[i]+A[2*N+2*r-i-1]-M for i in range(2*r, N+r)] return max(blue + red) if __name__ == "__main__": N, M = map(int, input().split()) A = [int(s) for s in input().split()] ans = modulo_pairing(N, M, A) print(ans) ```
output
1
40,240
22
80,481
Provide a correct Python 3 solution for this coding contest problem. Kenus, the organizer of International Euclidean Olympiad, is seeking a pair of two integers that requires many steps to find its greatest common divisor using the Euclidean algorithm. You are given Q queries. The i-th query is represented as a pair of two integers X_i and Y_i, and asks you the following: among all pairs of two integers (x,y) such that 1 ≤ x ≤ X_i and 1 ≤ y ≤ Y_i, find the maximum Euclidean step count (defined below), and how many pairs have the maximum step count, modulo 10^9+7. Process all the queries. Here, the Euclidean step count of a pair of two non-negative integers (a,b) is defined as follows: * (a,b) and (b,a) have the same Euclidean step count. * (0,a) has a Euclidean step count of 0. * If a > 0 and a ≤ b, let p and q be a unique pair of integers such that b=pa+q and 0 ≤ q < a. Then, the Euclidean step count of (a,b) is the Euclidean step count of (q,a) plus 1. Constraints * 1 ≤ Q ≤ 3 × 10^5 * 1 ≤ X_i,Y_i ≤ 10^{18}(1 ≤ i ≤ Q) Input The input is given from Standard Input in the following format: Q X_1 Y_1 : X_Q Y_Q Output For each query, print the maximum Euclidean step count, and the number of the pairs that have the maximum step count, modulo 10^9+7, with a space in between. Examples Input 3 4 4 6 10 12 11 Output 2 4 4 1 4 7 Input 10 1 1 2 2 5 1000000000000000000 7 3 1 334334334334334334 23847657 23458792534 111111111 111111111 7 7 4 19 9 10 Output 1 1 1 4 4 600000013 3 1 1 993994017 35 37447 38 2 3 6 3 9 4 2
instruction
0
40,294
22
80,588
"Correct Solution: ``` m=10**9+7;f=max;r=range for _ in r(int(input())): x,y=sorted(map(int,input().split()));s=-1;i=j=1 while j<=x and i+j<=y:i,j,s=j,i+j,s+1 if x<2 or y<3:print(1,x*y%m);continue a=f(0,(y-j)//i+1)+f(0,(x-j)//i+1);i=j=1 for c in r(s): k,l=j,i+j*2 for _ in r(s-c):k,l=l,k+l a+=(y>=k)*f(0,(x-l)//k+1)+(x>=k)*f(0,(y-l)//k+1) i,j=j,i+j print(s+1,a%m) ```
output
1
40,294
22
80,589
Provide a correct Python 3 solution for this coding contest problem. Kenus, the organizer of International Euclidean Olympiad, is seeking a pair of two integers that requires many steps to find its greatest common divisor using the Euclidean algorithm. You are given Q queries. The i-th query is represented as a pair of two integers X_i and Y_i, and asks you the following: among all pairs of two integers (x,y) such that 1 ≤ x ≤ X_i and 1 ≤ y ≤ Y_i, find the maximum Euclidean step count (defined below), and how many pairs have the maximum step count, modulo 10^9+7. Process all the queries. Here, the Euclidean step count of a pair of two non-negative integers (a,b) is defined as follows: * (a,b) and (b,a) have the same Euclidean step count. * (0,a) has a Euclidean step count of 0. * If a > 0 and a ≤ b, let p and q be a unique pair of integers such that b=pa+q and 0 ≤ q < a. Then, the Euclidean step count of (a,b) is the Euclidean step count of (q,a) plus 1. Constraints * 1 ≤ Q ≤ 3 × 10^5 * 1 ≤ X_i,Y_i ≤ 10^{18}(1 ≤ i ≤ Q) Input The input is given from Standard Input in the following format: Q X_1 Y_1 : X_Q Y_Q Output For each query, print the maximum Euclidean step count, and the number of the pairs that have the maximum step count, modulo 10^9+7, with a space in between. Examples Input 3 4 4 6 10 12 11 Output 2 4 4 1 4 7 Input 10 1 1 2 2 5 1000000000000000000 7 3 1 334334334334334334 23847657 23458792534 111111111 111111111 7 7 4 19 9 10 Output 1 1 1 4 4 600000013 3 1 1 993994017 35 37447 38 2 3 6 3 9 4 2
instruction
0
40,295
22
80,590
"Correct Solution: ``` from math import gcd import random,time def gcdcount(n,m): x,y=min(n,m),max(n,m) if x==0: return 0 else: return 1+gcdcount(x,y%x) fibo=[0,1,2] for i in range(100): fibo.append(fibo[-1]+fibo[-2]) gcdfibo=[[],[(1,2)],[(2,3)],[(3,5),(4,7)]] for i in range(4,101): temp=[] for a,b in gcdfibo[-1]: temp.append((b,a+b)) b=gcdfibo[-1][1][1] a=fibo[i] temp.append((b,a+b)) temp.sort() gcdfibo.append(temp) def solve(x,y): if x>y: x,y=y,x mod=10**9+7 if x==1: return (1,y%mod) if (x,y)==(2,2): return (1,3) id=1 t=-1 while True: if fibo[id+1]<=x and fibo[id+2]<=y: id+=1 else: if fibo[id+1]>x: if fibo[id+2]>y: t=0 else: t=1 else: t=2 break #print(t) if t==0: res=0 for a,b in gcdfibo[id]: if a<=x and b<=y: res+=1 return (id,res) elif t==1: res=0 for a,b in gcdfibo[id]: if a<=x: res+=(y-b)//a+1 res%=mod return (id,res) else: res=0 for a,b in gcdfibo[id+1]: u,v=b-a,a if u<=x and v<=y: res+=1 res%=mod if u<=y and v<=x: res+=1 res%=mod return (id,res) mod=10**9+7 Q=int(input()) start=time.time() for _ in range(Q): x,y=map(int,input().split()) id,res=solve(x,y) if (x,y)==(2,2): res+=1 print(id,res) #print(time.time()-start) ```
output
1
40,295
22
80,591
Provide a correct Python 3 solution for this coding contest problem. Kenus, the organizer of International Euclidean Olympiad, is seeking a pair of two integers that requires many steps to find its greatest common divisor using the Euclidean algorithm. You are given Q queries. The i-th query is represented as a pair of two integers X_i and Y_i, and asks you the following: among all pairs of two integers (x,y) such that 1 ≤ x ≤ X_i and 1 ≤ y ≤ Y_i, find the maximum Euclidean step count (defined below), and how many pairs have the maximum step count, modulo 10^9+7. Process all the queries. Here, the Euclidean step count of a pair of two non-negative integers (a,b) is defined as follows: * (a,b) and (b,a) have the same Euclidean step count. * (0,a) has a Euclidean step count of 0. * If a > 0 and a ≤ b, let p and q be a unique pair of integers such that b=pa+q and 0 ≤ q < a. Then, the Euclidean step count of (a,b) is the Euclidean step count of (q,a) plus 1. Constraints * 1 ≤ Q ≤ 3 × 10^5 * 1 ≤ X_i,Y_i ≤ 10^{18}(1 ≤ i ≤ Q) Input The input is given from Standard Input in the following format: Q X_1 Y_1 : X_Q Y_Q Output For each query, print the maximum Euclidean step count, and the number of the pairs that have the maximum step count, modulo 10^9+7, with a space in between. Examples Input 3 4 4 6 10 12 11 Output 2 4 4 1 4 7 Input 10 1 1 2 2 5 1000000000000000000 7 3 1 334334334334334334 23847657 23458792534 111111111 111111111 7 7 4 19 9 10 Output 1 1 1 4 4 600000013 3 1 1 993994017 35 37447 38 2 3 6 3 9 4 2
instruction
0
40,296
22
80,592
"Correct Solution: ``` m=10**9+7;f=lambda a:max(0,(a-l)//k+1);r=range for _ in r(int(input())): x,y=sorted(map(int,input().split()));s=-1;i=j=k=l=1 while l<=x and k+l<=y:k,l,s=l,k+l,s+1;a=f(y)+f(x) for c in r(s): k,l=j,i+j*2 for _ in r(s-c):k,l=l,k+l a,i,j=a+(y>=k)*f(x)+(x>=k)*f(y),j,i+j if x<2 or y<3:print(1,x*y%m) else:print(s+1,a%m) ```
output
1
40,296
22
80,593
Provide a correct Python 3 solution for this coding contest problem. Kenus, the organizer of International Euclidean Olympiad, is seeking a pair of two integers that requires many steps to find its greatest common divisor using the Euclidean algorithm. You are given Q queries. The i-th query is represented as a pair of two integers X_i and Y_i, and asks you the following: among all pairs of two integers (x,y) such that 1 ≤ x ≤ X_i and 1 ≤ y ≤ Y_i, find the maximum Euclidean step count (defined below), and how many pairs have the maximum step count, modulo 10^9+7. Process all the queries. Here, the Euclidean step count of a pair of two non-negative integers (a,b) is defined as follows: * (a,b) and (b,a) have the same Euclidean step count. * (0,a) has a Euclidean step count of 0. * If a > 0 and a ≤ b, let p and q be a unique pair of integers such that b=pa+q and 0 ≤ q < a. Then, the Euclidean step count of (a,b) is the Euclidean step count of (q,a) plus 1. Constraints * 1 ≤ Q ≤ 3 × 10^5 * 1 ≤ X_i,Y_i ≤ 10^{18}(1 ≤ i ≤ Q) Input The input is given from Standard Input in the following format: Q X_1 Y_1 : X_Q Y_Q Output For each query, print the maximum Euclidean step count, and the number of the pairs that have the maximum step count, modulo 10^9+7, with a space in between. Examples Input 3 4 4 6 10 12 11 Output 2 4 4 1 4 7 Input 10 1 1 2 2 5 1000000000000000000 7 3 1 334334334334334334 23847657 23458792534 111111111 111111111 7 7 4 19 9 10 Output 1 1 1 4 4 600000013 3 1 1 993994017 35 37447 38 2 3 6 3 9 4 2
instruction
0
40,297
22
80,594
"Correct Solution: ``` m=10**9+7 f=lambda x:max(x,0) r=range for _ in r(int(input())): x,y=sorted(map(int,input().split())) s=-1 i=j=1 while j<=x and i+j<=y:i,j,s=j,i+j,s+1 if x==1 or y<3:print(1,x*y%m) else: a=f((y-j)//i+1)+f((x-j)//i+1) i=j=1 for c in r(s): k,l=j,i+j*2 for _ in r(s-c):k,l=l,k+l if x>=k:a+=f((y-l)//k+1) if y>=k:a+=f((x-l)//k+1) i,j=j,i+j print(s+1,a%m) ```
output
1
40,297
22
80,595
Provide a correct Python 3 solution for this coding contest problem. Kenus, the organizer of International Euclidean Olympiad, is seeking a pair of two integers that requires many steps to find its greatest common divisor using the Euclidean algorithm. You are given Q queries. The i-th query is represented as a pair of two integers X_i and Y_i, and asks you the following: among all pairs of two integers (x,y) such that 1 ≤ x ≤ X_i and 1 ≤ y ≤ Y_i, find the maximum Euclidean step count (defined below), and how many pairs have the maximum step count, modulo 10^9+7. Process all the queries. Here, the Euclidean step count of a pair of two non-negative integers (a,b) is defined as follows: * (a,b) and (b,a) have the same Euclidean step count. * (0,a) has a Euclidean step count of 0. * If a > 0 and a ≤ b, let p and q be a unique pair of integers such that b=pa+q and 0 ≤ q < a. Then, the Euclidean step count of (a,b) is the Euclidean step count of (q,a) plus 1. Constraints * 1 ≤ Q ≤ 3 × 10^5 * 1 ≤ X_i,Y_i ≤ 10^{18}(1 ≤ i ≤ Q) Input The input is given from Standard Input in the following format: Q X_1 Y_1 : X_Q Y_Q Output For each query, print the maximum Euclidean step count, and the number of the pairs that have the maximum step count, modulo 10^9+7, with a space in between. Examples Input 3 4 4 6 10 12 11 Output 2 4 4 1 4 7 Input 10 1 1 2 2 5 1000000000000000000 7 3 1 334334334334334334 23847657 23458792534 111111111 111111111 7 7 4 19 9 10 Output 1 1 1 4 4 600000013 3 1 1 993994017 35 37447 38 2 3 6 3 9 4 2
instruction
0
40,298
22
80,596
"Correct Solution: ``` m=10**9+7 f=max r=range for _ in r(int(input())): x,y=sorted(map(int,input().split())) s=-1 i=j=1 while j<=x and i+j<=y:i,j,s=j,i+j,s+1 if x<2 or y<3:print(1,x*y%m);continue else: a=f(0,(y-j)//i+1)+f(0,(x-j)//i+1) i=j=1 for c in r(s): k,l=j,i+j*2 for _ in r(s-c):k,l=l,k+l if x>=k:a+=f(0,(y-l)//k+1) if y>=k:a+=f(0,(x-l)//k+1) i,j=j,i+j print(s+1,a%m) ```
output
1
40,298
22
80,597
Provide a correct Python 3 solution for this coding contest problem. Kenus, the organizer of International Euclidean Olympiad, is seeking a pair of two integers that requires many steps to find its greatest common divisor using the Euclidean algorithm. You are given Q queries. The i-th query is represented as a pair of two integers X_i and Y_i, and asks you the following: among all pairs of two integers (x,y) such that 1 ≤ x ≤ X_i and 1 ≤ y ≤ Y_i, find the maximum Euclidean step count (defined below), and how many pairs have the maximum step count, modulo 10^9+7. Process all the queries. Here, the Euclidean step count of a pair of two non-negative integers (a,b) is defined as follows: * (a,b) and (b,a) have the same Euclidean step count. * (0,a) has a Euclidean step count of 0. * If a > 0 and a ≤ b, let p and q be a unique pair of integers such that b=pa+q and 0 ≤ q < a. Then, the Euclidean step count of (a,b) is the Euclidean step count of (q,a) plus 1. Constraints * 1 ≤ Q ≤ 3 × 10^5 * 1 ≤ X_i,Y_i ≤ 10^{18}(1 ≤ i ≤ Q) Input The input is given from Standard Input in the following format: Q X_1 Y_1 : X_Q Y_Q Output For each query, print the maximum Euclidean step count, and the number of the pairs that have the maximum step count, modulo 10^9+7, with a space in between. Examples Input 3 4 4 6 10 12 11 Output 2 4 4 1 4 7 Input 10 1 1 2 2 5 1000000000000000000 7 3 1 334334334334334334 23847657 23458792534 111111111 111111111 7 7 4 19 9 10 Output 1 1 1 4 4 600000013 3 1 1 993994017 35 37447 38 2 3 6 3 9 4 2
instruction
0
40,299
22
80,598
"Correct Solution: ``` m=10**9+7 f=max r=range for _ in r(int(input())): x,y=sorted(map(int,input().split())) s=-1 i=j=1 while j<=x and i+j<=y:i,j,s=j,i+j,s+1 if x==1 or y<3:print(1,x*y%m) else: a=f(0,(y-j)//i+1)+f(0,(x-j)//i+1) i=j=1 for c in r(s): k,l=j,i+j*2 for _ in r(s-c):k,l=l,k+l if x>=k:a+=f(0,(y-l)//k+1) if y>=k:a+=f(0,(x-l)//k+1) i,j=j,i+j print(s+1,a%m) ```
output
1
40,299
22
80,599
Provide a correct Python 3 solution for this coding contest problem. Kenus, the organizer of International Euclidean Olympiad, is seeking a pair of two integers that requires many steps to find its greatest common divisor using the Euclidean algorithm. You are given Q queries. The i-th query is represented as a pair of two integers X_i and Y_i, and asks you the following: among all pairs of two integers (x,y) such that 1 ≤ x ≤ X_i and 1 ≤ y ≤ Y_i, find the maximum Euclidean step count (defined below), and how many pairs have the maximum step count, modulo 10^9+7. Process all the queries. Here, the Euclidean step count of a pair of two non-negative integers (a,b) is defined as follows: * (a,b) and (b,a) have the same Euclidean step count. * (0,a) has a Euclidean step count of 0. * If a > 0 and a ≤ b, let p and q be a unique pair of integers such that b=pa+q and 0 ≤ q < a. Then, the Euclidean step count of (a,b) is the Euclidean step count of (q,a) plus 1. Constraints * 1 ≤ Q ≤ 3 × 10^5 * 1 ≤ X_i,Y_i ≤ 10^{18}(1 ≤ i ≤ Q) Input The input is given from Standard Input in the following format: Q X_1 Y_1 : X_Q Y_Q Output For each query, print the maximum Euclidean step count, and the number of the pairs that have the maximum step count, modulo 10^9+7, with a space in between. Examples Input 3 4 4 6 10 12 11 Output 2 4 4 1 4 7 Input 10 1 1 2 2 5 1000000000000000000 7 3 1 334334334334334334 23847657 23458792534 111111111 111111111 7 7 4 19 9 10 Output 1 1 1 4 4 600000013 3 1 1 993994017 35 37447 38 2 3 6 3 9 4 2
instruction
0
40,300
22
80,600
"Correct Solution: ``` q=int(input()) m=10**9+7 for _ in range(q): x,y=sorted(map(int,input().split())) s=-1 i=j=1 while j<=x and i+j<=y: i,j=j,i+j s+=1 if x==1 or y<3:print(1,x*y%m) else: a=max(0,(y-j)//i+1)+max(0,(x-j)//i+1) i=j=1 for c in range(s): k,l=j,i+j*2 for _ in range(s-c):k,l=l,k+l if x>=k:a+=max(0,(y-l)//k+1) if y>=k:a+=max(0,(x-l)//k+1) i,j=j,i+j print(s+1,a%m) ```
output
1
40,300
22
80,601
Provide a correct Python 3 solution for this coding contest problem. Kenus, the organizer of International Euclidean Olympiad, is seeking a pair of two integers that requires many steps to find its greatest common divisor using the Euclidean algorithm. You are given Q queries. The i-th query is represented as a pair of two integers X_i and Y_i, and asks you the following: among all pairs of two integers (x,y) such that 1 ≤ x ≤ X_i and 1 ≤ y ≤ Y_i, find the maximum Euclidean step count (defined below), and how many pairs have the maximum step count, modulo 10^9+7. Process all the queries. Here, the Euclidean step count of a pair of two non-negative integers (a,b) is defined as follows: * (a,b) and (b,a) have the same Euclidean step count. * (0,a) has a Euclidean step count of 0. * If a > 0 and a ≤ b, let p and q be a unique pair of integers such that b=pa+q and 0 ≤ q < a. Then, the Euclidean step count of (a,b) is the Euclidean step count of (q,a) plus 1. Constraints * 1 ≤ Q ≤ 3 × 10^5 * 1 ≤ X_i,Y_i ≤ 10^{18}(1 ≤ i ≤ Q) Input The input is given from Standard Input in the following format: Q X_1 Y_1 : X_Q Y_Q Output For each query, print the maximum Euclidean step count, and the number of the pairs that have the maximum step count, modulo 10^9+7, with a space in between. Examples Input 3 4 4 6 10 12 11 Output 2 4 4 1 4 7 Input 10 1 1 2 2 5 1000000000000000000 7 3 1 334334334334334334 23847657 23458792534 111111111 111111111 7 7 4 19 9 10 Output 1 1 1 4 4 600000013 3 1 1 993994017 35 37447 38 2 3 6 3 9 4 2
instruction
0
40,301
22
80,602
"Correct Solution: ``` from math import gcd import random,time def gcdcount(n,m): x,y=min(n,m),max(n,m) if x==0: return 0 else: return 1+gcdcount(x,y%x) fibo=[0,1,2] for i in range(100): fibo.append(fibo[-1]+fibo[-2]) gcdfibo=[[],[(1,2),(1,3)]] for i in range(2,101): temp=[] for a,b in gcdfibo[-1]: temp.append((b,a+b)) a,b=fibo[i],fibo[i+2] temp.append((a,b)) temp.sort() gcdfibo.append(temp) def solve(x,y): if x>y: x,y=y,x mod=10**9+7 if x==1: return (1,y%mod) if (x,y)==(2,2): return (1,3) id=1 t=-1 while True: if fibo[id+1]<=x and fibo[id+2]<=y: id+=1 else: if fibo[id+1]>x: if fibo[id+2]>y: t=0 else: t=1 else: t=2 break #print(t) if t==0: res=0 for a,b in gcdfibo[id]: if a<=x and b<=y: res+=1 return (id,res) elif t==1: res=0 for a,b in gcdfibo[id]: if a<=x and (a,b)!=(fibo[id],fibo[id+2]) and b<=y: res+=(y-b)//a+1 res%=mod return (id,res) else: res=0 for a,b in gcdfibo[id+1]: u,v=b-a,a if u<=x and v<=y: res+=1 res%=mod if u<=y and v<=x: res+=1 res%=mod return (id,res) mod=10**9+7 Q=int(input()) start=time.time() for _ in range(Q): x,y=map(int,input().split()) id,res=solve(x,y) if (x,y)==(2,2): res+=1 print(id,res) #print(time.time()-start) ```
output
1
40,301
22
80,603
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Kenus, the organizer of International Euclidean Olympiad, is seeking a pair of two integers that requires many steps to find its greatest common divisor using the Euclidean algorithm. You are given Q queries. The i-th query is represented as a pair of two integers X_i and Y_i, and asks you the following: among all pairs of two integers (x,y) such that 1 ≤ x ≤ X_i and 1 ≤ y ≤ Y_i, find the maximum Euclidean step count (defined below), and how many pairs have the maximum step count, modulo 10^9+7. Process all the queries. Here, the Euclidean step count of a pair of two non-negative integers (a,b) is defined as follows: * (a,b) and (b,a) have the same Euclidean step count. * (0,a) has a Euclidean step count of 0. * If a > 0 and a ≤ b, let p and q be a unique pair of integers such that b=pa+q and 0 ≤ q < a. Then, the Euclidean step count of (a,b) is the Euclidean step count of (q,a) plus 1. Constraints * 1 ≤ Q ≤ 3 × 10^5 * 1 ≤ X_i,Y_i ≤ 10^{18}(1 ≤ i ≤ Q) Input The input is given from Standard Input in the following format: Q X_1 Y_1 : X_Q Y_Q Output For each query, print the maximum Euclidean step count, and the number of the pairs that have the maximum step count, modulo 10^9+7, with a space in between. Examples Input 3 4 4 6 10 12 11 Output 2 4 4 1 4 7 Input 10 1 1 2 2 5 1000000000000000000 7 3 1 334334334334334334 23847657 23458792534 111111111 111111111 7 7 4 19 9 10 Output 1 1 1 4 4 600000013 3 1 1 993994017 35 37447 38 2 3 6 3 9 4 2 Submitted Solution: ``` q = int(input()) mod = 10**9+7 for _ in range(q): x, y = sorted(map(int, input().split())) ma = 0 i, j = 1, 1 while j <= x and i+j <= y: i, j = j, i+j ma += 1 if x == 1 or y <= 2: print(1, x*y % mod) else: ans = 0 if x >= i: ans += max(0, (y-j) // i+1) if y >= i: ans += max(0, (x-j) // i+1) i, j = 1, 1 for c in range(ma-1): k, l = j, i+j*2 for _ in range(ma-c-1): k, l = l, k+l if x >= k: ans += max(0, (y-l) // k+1) if y >= k: ans += max(0, (x-l) // k+1) i, j = j, i+j print(ma, ans % mod) ```
instruction
0
40,302
22
80,604
Yes
output
1
40,302
22
80,605
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Kenus, the organizer of International Euclidean Olympiad, is seeking a pair of two integers that requires many steps to find its greatest common divisor using the Euclidean algorithm. You are given Q queries. The i-th query is represented as a pair of two integers X_i and Y_i, and asks you the following: among all pairs of two integers (x,y) such that 1 ≤ x ≤ X_i and 1 ≤ y ≤ Y_i, find the maximum Euclidean step count (defined below), and how many pairs have the maximum step count, modulo 10^9+7. Process all the queries. Here, the Euclidean step count of a pair of two non-negative integers (a,b) is defined as follows: * (a,b) and (b,a) have the same Euclidean step count. * (0,a) has a Euclidean step count of 0. * If a > 0 and a ≤ b, let p and q be a unique pair of integers such that b=pa+q and 0 ≤ q < a. Then, the Euclidean step count of (a,b) is the Euclidean step count of (q,a) plus 1. Constraints * 1 ≤ Q ≤ 3 × 10^5 * 1 ≤ X_i,Y_i ≤ 10^{18}(1 ≤ i ≤ Q) Input The input is given from Standard Input in the following format: Q X_1 Y_1 : X_Q Y_Q Output For each query, print the maximum Euclidean step count, and the number of the pairs that have the maximum step count, modulo 10^9+7, with a space in between. Examples Input 3 4 4 6 10 12 11 Output 2 4 4 1 4 7 Input 10 1 1 2 2 5 1000000000000000000 7 3 1 334334334334334334 23847657 23458792534 111111111 111111111 7 7 4 19 9 10 Output 1 1 1 4 4 600000013 3 1 1 993994017 35 37447 38 2 3 6 3 9 4 2 Submitted Solution: ``` m=10**9+7 f=max r=range p=print for _ in r(int(input())): x,y=sorted(map(int,input().split())) s=-1 i=j=1 while j<=x and i+j<=y: i,j=j,i+j s+=1 if x==1 or y<3:p(1,x*y%m) else: a=max(0,(y-j)//i+1)+f(0,(x-j)//i+1) i=j=1 for c in r(s): k,l=j,i+j*2 for _ in r(s-c):k,l=l,k+l if x>=k:a+=f(0,(y-l)//k+1) if y>=k:a+=f(0,(x-l)//k+1) i,j=j,i+j p(s+1,a%m) ```
instruction
0
40,303
22
80,606
Yes
output
1
40,303
22
80,607
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Kenus, the organizer of International Euclidean Olympiad, is seeking a pair of two integers that requires many steps to find its greatest common divisor using the Euclidean algorithm. You are given Q queries. The i-th query is represented as a pair of two integers X_i and Y_i, and asks you the following: among all pairs of two integers (x,y) such that 1 ≤ x ≤ X_i and 1 ≤ y ≤ Y_i, find the maximum Euclidean step count (defined below), and how many pairs have the maximum step count, modulo 10^9+7. Process all the queries. Here, the Euclidean step count of a pair of two non-negative integers (a,b) is defined as follows: * (a,b) and (b,a) have the same Euclidean step count. * (0,a) has a Euclidean step count of 0. * If a > 0 and a ≤ b, let p and q be a unique pair of integers such that b=pa+q and 0 ≤ q < a. Then, the Euclidean step count of (a,b) is the Euclidean step count of (q,a) plus 1. Constraints * 1 ≤ Q ≤ 3 × 10^5 * 1 ≤ X_i,Y_i ≤ 10^{18}(1 ≤ i ≤ Q) Input The input is given from Standard Input in the following format: Q X_1 Y_1 : X_Q Y_Q Output For each query, print the maximum Euclidean step count, and the number of the pairs that have the maximum step count, modulo 10^9+7, with a space in between. Examples Input 3 4 4 6 10 12 11 Output 2 4 4 1 4 7 Input 10 1 1 2 2 5 1000000000000000000 7 3 1 334334334334334334 23847657 23458792534 111111111 111111111 7 7 4 19 9 10 Output 1 1 1 4 4 600000013 3 1 1 993994017 35 37447 38 2 3 6 3 9 4 2 Submitted Solution: ``` q=int(input()) m=10**9+7 for _ in range(q): x,y=sorted(map(int,input().split())) s=0 i=j=1 while j<=x and i+j<=y: i,j=j,i+j s+=1 if x==1 or y<3: print(1,x*y%m) else: a=max(0,(y-j)//i+1)+max(0,(x-j)//i+1) i=j=1 for c in range(s-1): k,l=j,i+j*2 for _ in range(s-c-1): k,l=l,k+l if x>=k: a+=max(0,(y-l)//k+1) if y>=k: a+=max(0,(x-l)//k+1) i,j=j,i+j print(s,a % m) ```
instruction
0
40,304
22
80,608
Yes
output
1
40,304
22
80,609
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Kenus, the organizer of International Euclidean Olympiad, is seeking a pair of two integers that requires many steps to find its greatest common divisor using the Euclidean algorithm. You are given Q queries. The i-th query is represented as a pair of two integers X_i and Y_i, and asks you the following: among all pairs of two integers (x,y) such that 1 ≤ x ≤ X_i and 1 ≤ y ≤ Y_i, find the maximum Euclidean step count (defined below), and how many pairs have the maximum step count, modulo 10^9+7. Process all the queries. Here, the Euclidean step count of a pair of two non-negative integers (a,b) is defined as follows: * (a,b) and (b,a) have the same Euclidean step count. * (0,a) has a Euclidean step count of 0. * If a > 0 and a ≤ b, let p and q be a unique pair of integers such that b=pa+q and 0 ≤ q < a. Then, the Euclidean step count of (a,b) is the Euclidean step count of (q,a) plus 1. Constraints * 1 ≤ Q ≤ 3 × 10^5 * 1 ≤ X_i,Y_i ≤ 10^{18}(1 ≤ i ≤ Q) Input The input is given from Standard Input in the following format: Q X_1 Y_1 : X_Q Y_Q Output For each query, print the maximum Euclidean step count, and the number of the pairs that have the maximum step count, modulo 10^9+7, with a space in between. Examples Input 3 4 4 6 10 12 11 Output 2 4 4 1 4 7 Input 10 1 1 2 2 5 1000000000000000000 7 3 1 334334334334334334 23847657 23458792534 111111111 111111111 7 7 4 19 9 10 Output 1 1 1 4 4 600000013 3 1 1 993994017 35 37447 38 2 3 6 3 9 4 2 Submitted Solution: ``` m=10**9+7 f=max for _ in range(int(input())): x,y=sorted(map(int,input().split())) s=-1 i=j=1 while j<=x and i+j<=y: i,j=j,i+j s+=1 if x==1 or y<3:print(1,x*y%m) else: a=max(0,(y-j)//i+1)+f(0,(x-j)//i+1) i=j=1 for c in range(s): k,l=j,i+j*2 for _ in range(s-c):k,l=l,k+l if x>=k:a+=f(0,(y-l)//k+1) if y>=k:a+=f(0,(x-l)//k+1) i,j=j,i+j print(s+1,a%m) ```
instruction
0
40,305
22
80,610
Yes
output
1
40,305
22
80,611
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Kenus, the organizer of International Euclidean Olympiad, is seeking a pair of two integers that requires many steps to find its greatest common divisor using the Euclidean algorithm. You are given Q queries. The i-th query is represented as a pair of two integers X_i and Y_i, and asks you the following: among all pairs of two integers (x,y) such that 1 ≤ x ≤ X_i and 1 ≤ y ≤ Y_i, find the maximum Euclidean step count (defined below), and how many pairs have the maximum step count, modulo 10^9+7. Process all the queries. Here, the Euclidean step count of a pair of two non-negative integers (a,b) is defined as follows: * (a,b) and (b,a) have the same Euclidean step count. * (0,a) has a Euclidean step count of 0. * If a > 0 and a ≤ b, let p and q be a unique pair of integers such that b=pa+q and 0 ≤ q < a. Then, the Euclidean step count of (a,b) is the Euclidean step count of (q,a) plus 1. Constraints * 1 ≤ Q ≤ 3 × 10^5 * 1 ≤ X_i,Y_i ≤ 10^{18}(1 ≤ i ≤ Q) Input The input is given from Standard Input in the following format: Q X_1 Y_1 : X_Q Y_Q Output For each query, print the maximum Euclidean step count, and the number of the pairs that have the maximum step count, modulo 10^9+7, with a space in between. Examples Input 3 4 4 6 10 12 11 Output 2 4 4 1 4 7 Input 10 1 1 2 2 5 1000000000000000000 7 3 1 334334334334334334 23847657 23458792534 111111111 111111111 7 7 4 19 9 10 Output 1 1 1 4 4 600000013 3 1 1 993994017 35 37447 38 2 3 6 3 9 4 2 Submitted Solution: ``` F=[0,1,1] for i in range(100): F.append(F[-1]+F[-2]) P=0 X,Y=0,0 def f(a,b,c): if (a*F[c]+b*F[c+1]>X or a*F[c+2]+b*F[c+1]>Y)and(a*F[c]+b*F[c+1]>Y or a*F[c+2]+b*F[c+1]>X): return True global P if c: d=a+b while d<=X: if f(b,d,c-1): break d+=b else: d=a+b if b<=X and d<=Y: P+=(Y-d)//b+1 if d<=X and b<=Y: P+=(Y-b)//d+1 return False mod=10**9+7 for i in range(int(input())): P=0 X,Y=map(int,input().split()) if X==1 and Y==1: print('1 1') continue if X>Y: X,Y=Y,X for j in range(100): if F[j+1]>Y: M=j-2 print(M,end=' ') break if F[j]>X: M=j-2 print(M,end=' ') break f(0,1,M) if M==1: print(X*Y%mod) else: print(P%mod) ```
instruction
0
40,306
22
80,612
No
output
1
40,306
22
80,613
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Kenus, the organizer of International Euclidean Olympiad, is seeking a pair of two integers that requires many steps to find its greatest common divisor using the Euclidean algorithm. You are given Q queries. The i-th query is represented as a pair of two integers X_i and Y_i, and asks you the following: among all pairs of two integers (x,y) such that 1 ≤ x ≤ X_i and 1 ≤ y ≤ Y_i, find the maximum Euclidean step count (defined below), and how many pairs have the maximum step count, modulo 10^9+7. Process all the queries. Here, the Euclidean step count of a pair of two non-negative integers (a,b) is defined as follows: * (a,b) and (b,a) have the same Euclidean step count. * (0,a) has a Euclidean step count of 0. * If a > 0 and a ≤ b, let p and q be a unique pair of integers such that b=pa+q and 0 ≤ q < a. Then, the Euclidean step count of (a,b) is the Euclidean step count of (q,a) plus 1. Constraints * 1 ≤ Q ≤ 3 × 10^5 * 1 ≤ X_i,Y_i ≤ 10^{18}(1 ≤ i ≤ Q) Input The input is given from Standard Input in the following format: Q X_1 Y_1 : X_Q Y_Q Output For each query, print the maximum Euclidean step count, and the number of the pairs that have the maximum step count, modulo 10^9+7, with a space in between. Examples Input 3 4 4 6 10 12 11 Output 2 4 4 1 4 7 Input 10 1 1 2 2 5 1000000000000000000 7 3 1 334334334334334334 23847657 23458792534 111111111 111111111 7 7 4 19 9 10 Output 1 1 1 4 4 600000013 3 1 1 993994017 35 37447 38 2 3 6 3 9 4 2 Submitted Solution: ``` from math import gcd q = int(input()) mod = 10**9+7 for _ in range(q): x, y = sorted(map(int, input().split())) ma = 0 i, j = 1, 1 while j <= x and i+j <= y: i, j = j, i+j ma += 1 if x == 1: print(1, x*y % mod) else: ans = 0 if x >= i: ans += max(0, (y-j) // i+1) if y >= i: ans += max(0, (x-j) // i+1) i, j = 1, 1 for c in range(ma-1): k, l = j, i+j*2 if gcd(k, l) == 1: for _ in range(ma-c-1): k, l = l, k+l if x >= k: ans += max(0, (y-l) // k+1) if y >= k: ans += max(0, (x-l) // k+1) i, j = j, i+j print(ma, ans % mod) ```
instruction
0
40,307
22
80,614
No
output
1
40,307
22
80,615
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Kenus, the organizer of International Euclidean Olympiad, is seeking a pair of two integers that requires many steps to find its greatest common divisor using the Euclidean algorithm. You are given Q queries. The i-th query is represented as a pair of two integers X_i and Y_i, and asks you the following: among all pairs of two integers (x,y) such that 1 ≤ x ≤ X_i and 1 ≤ y ≤ Y_i, find the maximum Euclidean step count (defined below), and how many pairs have the maximum step count, modulo 10^9+7. Process all the queries. Here, the Euclidean step count of a pair of two non-negative integers (a,b) is defined as follows: * (a,b) and (b,a) have the same Euclidean step count. * (0,a) has a Euclidean step count of 0. * If a > 0 and a ≤ b, let p and q be a unique pair of integers such that b=pa+q and 0 ≤ q < a. Then, the Euclidean step count of (a,b) is the Euclidean step count of (q,a) plus 1. Constraints * 1 ≤ Q ≤ 3 × 10^5 * 1 ≤ X_i,Y_i ≤ 10^{18}(1 ≤ i ≤ Q) Input The input is given from Standard Input in the following format: Q X_1 Y_1 : X_Q Y_Q Output For each query, print the maximum Euclidean step count, and the number of the pairs that have the maximum step count, modulo 10^9+7, with a space in between. Examples Input 3 4 4 6 10 12 11 Output 2 4 4 1 4 7 Input 10 1 1 2 2 5 1000000000000000000 7 3 1 334334334334334334 23847657 23458792534 111111111 111111111 7 7 4 19 9 10 Output 1 1 1 4 4 600000013 3 1 1 993994017 35 37447 38 2 3 6 3 9 4 2 Submitted Solution: ``` from math import gcd q = int(input()) mod = 10**9+7 for _ in range(q): x, y = sorted(map(int, input().split())) ma = 0 i, j = 1, 1 while j <= x and i+j <= y: i, j = j, i+j ma += 1 if x == 1 or y<=2: print(1, x*y % mod) else: ans = 0 if x >= i: ans += max(0, (y-j) // i+1) if y >= i: ans += max(0, (x-j) // i+1) i, j = 1, 1 for c in range(ma-1): k, l = j, i+j*2 if gcd(k, l) == 1: for _ in range(ma-c-1): k, l = l, k+l if x >= k: ans += max(0, (y-l) // k+1) if y >= k: ans += max(0, (x-l) // k+1) i, j = j, i+j print(ma, ans % mod) ```
instruction
0
40,308
22
80,616
No
output
1
40,308
22
80,617
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Kenus, the organizer of International Euclidean Olympiad, is seeking a pair of two integers that requires many steps to find its greatest common divisor using the Euclidean algorithm. You are given Q queries. The i-th query is represented as a pair of two integers X_i and Y_i, and asks you the following: among all pairs of two integers (x,y) such that 1 ≤ x ≤ X_i and 1 ≤ y ≤ Y_i, find the maximum Euclidean step count (defined below), and how many pairs have the maximum step count, modulo 10^9+7. Process all the queries. Here, the Euclidean step count of a pair of two non-negative integers (a,b) is defined as follows: * (a,b) and (b,a) have the same Euclidean step count. * (0,a) has a Euclidean step count of 0. * If a > 0 and a ≤ b, let p and q be a unique pair of integers such that b=pa+q and 0 ≤ q < a. Then, the Euclidean step count of (a,b) is the Euclidean step count of (q,a) plus 1. Constraints * 1 ≤ Q ≤ 3 × 10^5 * 1 ≤ X_i,Y_i ≤ 10^{18}(1 ≤ i ≤ Q) Input The input is given from Standard Input in the following format: Q X_1 Y_1 : X_Q Y_Q Output For each query, print the maximum Euclidean step count, and the number of the pairs that have the maximum step count, modulo 10^9+7, with a space in between. Examples Input 3 4 4 6 10 12 11 Output 2 4 4 1 4 7 Input 10 1 1 2 2 5 1000000000000000000 7 3 1 334334334334334334 23847657 23458792534 111111111 111111111 7 7 4 19 9 10 Output 1 1 1 4 4 600000013 3 1 1 993994017 35 37447 38 2 3 6 3 9 4 2 Submitted Solution: ``` from math import gcd q = int(input()) mod = 10**9+7 for _ in range(q): x, y = sorted(map(int, input().split())) ma = 0 i, j = 1, 1 while j <= x and i+j <= y: i, j = j, i+j ma += 1 if x == 1: print(ma, x*y % mod) else: ans = 0 if x >= i: ans += max(0, (y-j) // i+1) if y >= i: ans += max(0, (x-j) // i+1) i, j = 1, 1 for c in range(ma-1): k, l = j, i+j*2 if gcd(k, l) == 1: for _ in range(ma-c-1): k, l = l, k+l if x >= k: ans += max(0, (y-l) // k+1) if y >= k: ans += max(0, (x-l) // k+1) i, j = j, i+j print(ma, ans % mod) ```
instruction
0
40,309
22
80,618
No
output
1
40,309
22
80,619
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given an array a consisting of n positive integers. Initially, you have an integer x = 0. During one move, you can do one of the following two operations: 1. Choose exactly one i from 1 to n and increase a_i by x (a_i := a_i + x), then increase x by 1 (x := x + 1). 2. Just increase x by 1 (x := x + 1). The first operation can be applied no more than once to each i from 1 to n. Your task is to find the minimum number of moves required to obtain such an array that each its element is divisible by k (the value k is given). You have to answer t independent test cases. Input The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow. The first line of the test case contains two integers n and k (1 ≤ n ≤ 2 ⋅ 10^5; 1 ≤ k ≤ 10^9) — the length of a and the required divisior. The second line of the test case contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is the i-th element of a. It is guaranteed that the sum of n does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5). Output For each test case, print the answer — the minimum number of moves required to obtain such an array that each its element is divisible by k. Example Input 5 4 3 1 2 1 3 10 6 8 7 1 8 3 7 5 10 8 9 5 10 20 100 50 20 100500 10 25 24 24 24 24 24 24 24 24 24 24 8 8 1 2 3 4 5 6 7 8 Output 6 18 0 227 8 Note Consider the first test case of the example: 1. x=0, a = [1, 2, 1, 3]. Just increase x; 2. x=1, a = [1, 2, 1, 3]. Add x to the second element and increase x; 3. x=2, a = [1, 3, 1, 3]. Add x to the third element and increase x; 4. x=3, a = [1, 3, 3, 3]. Add x to the fourth element and increase x; 5. x=4, a = [1, 3, 3, 6]. Just increase x; 6. x=5, a = [1, 3, 3, 6]. Add x to the first element and increase x; 7. x=6, a = [6, 3, 3, 6]. We obtained the required array. Note that you can't add x to the same element more than once. Submitted Solution: ``` t=int(input()) while t: t-=1 n, k=list(map(int,input().split())) a=list(map(int,input().split())) s=set() s.add(0) d=dict() for i in a: x=k-(i%k) if x==k: continue else: y=d.get(x,x) s.add(y) d[x]=y+k if len(s)==1: print(0) else: print(max(s)+1) ```
instruction
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40,599
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81,198
Yes
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40,599
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81,199
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given an array a consisting of n positive integers. Initially, you have an integer x = 0. During one move, you can do one of the following two operations: 1. Choose exactly one i from 1 to n and increase a_i by x (a_i := a_i + x), then increase x by 1 (x := x + 1). 2. Just increase x by 1 (x := x + 1). The first operation can be applied no more than once to each i from 1 to n. Your task is to find the minimum number of moves required to obtain such an array that each its element is divisible by k (the value k is given). You have to answer t independent test cases. Input The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow. The first line of the test case contains two integers n and k (1 ≤ n ≤ 2 ⋅ 10^5; 1 ≤ k ≤ 10^9) — the length of a and the required divisior. The second line of the test case contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is the i-th element of a. It is guaranteed that the sum of n does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5). Output For each test case, print the answer — the minimum number of moves required to obtain such an array that each its element is divisible by k. Example Input 5 4 3 1 2 1 3 10 6 8 7 1 8 3 7 5 10 8 9 5 10 20 100 50 20 100500 10 25 24 24 24 24 24 24 24 24 24 24 8 8 1 2 3 4 5 6 7 8 Output 6 18 0 227 8 Note Consider the first test case of the example: 1. x=0, a = [1, 2, 1, 3]. Just increase x; 2. x=1, a = [1, 2, 1, 3]. Add x to the second element and increase x; 3. x=2, a = [1, 3, 1, 3]. Add x to the third element and increase x; 4. x=3, a = [1, 3, 3, 3]. Add x to the fourth element and increase x; 5. x=4, a = [1, 3, 3, 6]. Just increase x; 6. x=5, a = [1, 3, 3, 6]. Add x to the first element and increase x; 7. x=6, a = [6, 3, 3, 6]. We obtained the required array. Note that you can't add x to the same element more than once. Submitted Solution: ``` import atexit import io import sys import math from collections import defaultdict,Counter # _INPUT_LINES = sys.stdin.read().splitlines() # input = iter(_INPUT_LINES).__next__ # _OUTPUT_BUFFER = io.StringIO() # sys.stdout = _OUTPUT_BUFFER # @atexit.register # def write(): # sys.__stdout__.write(_OUTPUT_BUFFER.getvalue()) # sys.stdout=open("CP3/output.txt",'w') # sys.stdin=open("CP3/input.txt",'r') # m=pow(10,9)+7 t=int(input()) for i in range(t): n,k=map(int,input().split()) l=[-1]*n a=list(map(int,input().split())) s=set() d1={} for j in range(n): if a[j]%k!=0: d=k-(a[j]%k) if d in s: d1[d]+=1 d+=(d1[d]-1)*k l[j]=d s.add(d) s1=d1.setdefault(d,1) print(max(l)+1) ```
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Yes
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81,201
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given an array a consisting of n positive integers. Initially, you have an integer x = 0. During one move, you can do one of the following two operations: 1. Choose exactly one i from 1 to n and increase a_i by x (a_i := a_i + x), then increase x by 1 (x := x + 1). 2. Just increase x by 1 (x := x + 1). The first operation can be applied no more than once to each i from 1 to n. Your task is to find the minimum number of moves required to obtain such an array that each its element is divisible by k (the value k is given). You have to answer t independent test cases. Input The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow. The first line of the test case contains two integers n and k (1 ≤ n ≤ 2 ⋅ 10^5; 1 ≤ k ≤ 10^9) — the length of a and the required divisior. The second line of the test case contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is the i-th element of a. It is guaranteed that the sum of n does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5). Output For each test case, print the answer — the minimum number of moves required to obtain such an array that each its element is divisible by k. Example Input 5 4 3 1 2 1 3 10 6 8 7 1 8 3 7 5 10 8 9 5 10 20 100 50 20 100500 10 25 24 24 24 24 24 24 24 24 24 24 8 8 1 2 3 4 5 6 7 8 Output 6 18 0 227 8 Note Consider the first test case of the example: 1. x=0, a = [1, 2, 1, 3]. Just increase x; 2. x=1, a = [1, 2, 1, 3]. Add x to the second element and increase x; 3. x=2, a = [1, 3, 1, 3]. Add x to the third element and increase x; 4. x=3, a = [1, 3, 3, 3]. Add x to the fourth element and increase x; 5. x=4, a = [1, 3, 3, 6]. Just increase x; 6. x=5, a = [1, 3, 3, 6]. Add x to the first element and increase x; 7. x=6, a = [6, 3, 3, 6]. We obtained the required array. Note that you can't add x to the same element more than once. Submitted Solution: ``` from sys import stdin inp = lambda : stdin.readline().strip() t = int(inp()) for _ in range(t): n, k = [int(x) for x in inp().split()] a = [int(x) for x in inp().split()] ar = [] for i in a: if i%k: ar.append(i) ar.sort(key = lambda x: x%k) rem = dict() for i in ar: if rem.get(i%k,-1) != -1: rem[i%k] += 1 else: rem[i%k] = 1 ans = 0 maximum = 0 for i in rem.keys(): if rem[i] > maximum: ans = 0 ans +=1 ans += k-i ans += (rem[i]-1)*k maximum = rem[i] print(ans) ```
instruction
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Yes
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40,601
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81,203
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given an array a consisting of n positive integers. Initially, you have an integer x = 0. During one move, you can do one of the following two operations: 1. Choose exactly one i from 1 to n and increase a_i by x (a_i := a_i + x), then increase x by 1 (x := x + 1). 2. Just increase x by 1 (x := x + 1). The first operation can be applied no more than once to each i from 1 to n. Your task is to find the minimum number of moves required to obtain such an array that each its element is divisible by k (the value k is given). You have to answer t independent test cases. Input The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow. The first line of the test case contains two integers n and k (1 ≤ n ≤ 2 ⋅ 10^5; 1 ≤ k ≤ 10^9) — the length of a and the required divisior. The second line of the test case contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is the i-th element of a. It is guaranteed that the sum of n does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5). Output For each test case, print the answer — the minimum number of moves required to obtain such an array that each its element is divisible by k. Example Input 5 4 3 1 2 1 3 10 6 8 7 1 8 3 7 5 10 8 9 5 10 20 100 50 20 100500 10 25 24 24 24 24 24 24 24 24 24 24 8 8 1 2 3 4 5 6 7 8 Output 6 18 0 227 8 Note Consider the first test case of the example: 1. x=0, a = [1, 2, 1, 3]. Just increase x; 2. x=1, a = [1, 2, 1, 3]. Add x to the second element and increase x; 3. x=2, a = [1, 3, 1, 3]. Add x to the third element and increase x; 4. x=3, a = [1, 3, 3, 3]. Add x to the fourth element and increase x; 5. x=4, a = [1, 3, 3, 6]. Just increase x; 6. x=5, a = [1, 3, 3, 6]. Add x to the first element and increase x; 7. x=6, a = [6, 3, 3, 6]. We obtained the required array. Note that you can't add x to the same element more than once. Submitted Solution: ``` t=int(input()) for i in range(t): n,k=map(int,input().split()) ar=[int(i)for i in input().split()] for x in range(n): ar[x]=(ar[x])%k ar.sort() freq = {} check=0 for item in ar: if item==0: pass elif (item in freq): freq[item] += 1 else: freq[item] = 1 check+=1 if check==0: print(0) else: Keymax = max(freq, key=freq.get) print(k*(ar.count(Keymax)-1)+k-Keymax+1) ```
instruction
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40,602
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81,204
Yes
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40,602
22
81,205
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given an array a consisting of n positive integers. Initially, you have an integer x = 0. During one move, you can do one of the following two operations: 1. Choose exactly one i from 1 to n and increase a_i by x (a_i := a_i + x), then increase x by 1 (x := x + 1). 2. Just increase x by 1 (x := x + 1). The first operation can be applied no more than once to each i from 1 to n. Your task is to find the minimum number of moves required to obtain such an array that each its element is divisible by k (the value k is given). You have to answer t independent test cases. Input The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow. The first line of the test case contains two integers n and k (1 ≤ n ≤ 2 ⋅ 10^5; 1 ≤ k ≤ 10^9) — the length of a and the required divisior. The second line of the test case contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is the i-th element of a. It is guaranteed that the sum of n does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5). Output For each test case, print the answer — the minimum number of moves required to obtain such an array that each its element is divisible by k. Example Input 5 4 3 1 2 1 3 10 6 8 7 1 8 3 7 5 10 8 9 5 10 20 100 50 20 100500 10 25 24 24 24 24 24 24 24 24 24 24 8 8 1 2 3 4 5 6 7 8 Output 6 18 0 227 8 Note Consider the first test case of the example: 1. x=0, a = [1, 2, 1, 3]. Just increase x; 2. x=1, a = [1, 2, 1, 3]. Add x to the second element and increase x; 3. x=2, a = [1, 3, 1, 3]. Add x to the third element and increase x; 4. x=3, a = [1, 3, 3, 3]. Add x to the fourth element and increase x; 5. x=4, a = [1, 3, 3, 6]. Just increase x; 6. x=5, a = [1, 3, 3, 6]. Add x to the first element and increase x; 7. x=6, a = [6, 3, 3, 6]. We obtained the required array. Note that you can't add x to the same element more than once. Submitted Solution: ``` t = int(input()) for i in range(t): n,k = map(int,input().split()) A = list(map(int,input().split())) B = {} for j in A: if j % k not in B: B[j % k] = 0 B[j % k] += 1 max = 0 c = k + 1 for j in B: if j != 0 and B[j] >= max and j <= c: max = B[j] c = j if c == k + 1: print(0) else: print(max * k - c + 1) ```
instruction
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40,603
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No
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40,603
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81,207
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given an array a consisting of n positive integers. Initially, you have an integer x = 0. During one move, you can do one of the following two operations: 1. Choose exactly one i from 1 to n and increase a_i by x (a_i := a_i + x), then increase x by 1 (x := x + 1). 2. Just increase x by 1 (x := x + 1). The first operation can be applied no more than once to each i from 1 to n. Your task is to find the minimum number of moves required to obtain such an array that each its element is divisible by k (the value k is given). You have to answer t independent test cases. Input The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow. The first line of the test case contains two integers n and k (1 ≤ n ≤ 2 ⋅ 10^5; 1 ≤ k ≤ 10^9) — the length of a and the required divisior. The second line of the test case contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is the i-th element of a. It is guaranteed that the sum of n does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5). Output For each test case, print the answer — the minimum number of moves required to obtain such an array that each its element is divisible by k. Example Input 5 4 3 1 2 1 3 10 6 8 7 1 8 3 7 5 10 8 9 5 10 20 100 50 20 100500 10 25 24 24 24 24 24 24 24 24 24 24 8 8 1 2 3 4 5 6 7 8 Output 6 18 0 227 8 Note Consider the first test case of the example: 1. x=0, a = [1, 2, 1, 3]. Just increase x; 2. x=1, a = [1, 2, 1, 3]. Add x to the second element and increase x; 3. x=2, a = [1, 3, 1, 3]. Add x to the third element and increase x; 4. x=3, a = [1, 3, 3, 3]. Add x to the fourth element and increase x; 5. x=4, a = [1, 3, 3, 6]. Just increase x; 6. x=5, a = [1, 3, 3, 6]. Add x to the first element and increase x; 7. x=6, a = [6, 3, 3, 6]. We obtained the required array. Note that you can't add x to the same element more than once. Submitted Solution: ``` from collections import defaultdict as dd t=int(input()) for _ in range(t): n,k=map(int,input().split()) a=list(map(int,input().split())) amod=[] d=dd(int) ct=0 mx=0 for i in range(n): amod.append((k-(a[i]%k))%k) d[amod[i]]+=1 if amod[i]!=0: mx=max(mx,d[amod[i]]) ct+=(max(0,(mx-1))*k) ct+=max(amod) if mx==0: print(0) else: print(ct+1) ```
instruction
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40,604
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81,208
No
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40,604
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81,209
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given an array a consisting of n positive integers. Initially, you have an integer x = 0. During one move, you can do one of the following two operations: 1. Choose exactly one i from 1 to n and increase a_i by x (a_i := a_i + x), then increase x by 1 (x := x + 1). 2. Just increase x by 1 (x := x + 1). The first operation can be applied no more than once to each i from 1 to n. Your task is to find the minimum number of moves required to obtain such an array that each its element is divisible by k (the value k is given). You have to answer t independent test cases. Input The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow. The first line of the test case contains two integers n and k (1 ≤ n ≤ 2 ⋅ 10^5; 1 ≤ k ≤ 10^9) — the length of a and the required divisior. The second line of the test case contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is the i-th element of a. It is guaranteed that the sum of n does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5). Output For each test case, print the answer — the minimum number of moves required to obtain such an array that each its element is divisible by k. Example Input 5 4 3 1 2 1 3 10 6 8 7 1 8 3 7 5 10 8 9 5 10 20 100 50 20 100500 10 25 24 24 24 24 24 24 24 24 24 24 8 8 1 2 3 4 5 6 7 8 Output 6 18 0 227 8 Note Consider the first test case of the example: 1. x=0, a = [1, 2, 1, 3]. Just increase x; 2. x=1, a = [1, 2, 1, 3]. Add x to the second element and increase x; 3. x=2, a = [1, 3, 1, 3]. Add x to the third element and increase x; 4. x=3, a = [1, 3, 3, 3]. Add x to the fourth element and increase x; 5. x=4, a = [1, 3, 3, 6]. Just increase x; 6. x=5, a = [1, 3, 3, 6]. Add x to the first element and increase x; 7. x=6, a = [6, 3, 3, 6]. We obtained the required array. Note that you can't add x to the same element more than once. Submitted Solution: ``` t = int(input()) for tc in range(t): n, k = map(int, input().split()); x = 0 arr = [int(z) for z in input().split()] needed = [] cnt = 0 usages = {} for i in range(n): elem = arr[i] if elem % k == 0: d = 0 continue else: d = k - (elem % k) if not usages.get(d): usages[d] = 1 else: usages[d] += 1 for i, j in sorted(usages.items()): cnt = max(cnt, j) res = 0 for i, j in sorted(usages.items()): if j == cnt: res = k * (j-1) + i print(res+1) ```
instruction
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40,605
22
81,210
No
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40,605
22
81,211
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given an array a consisting of n positive integers. Initially, you have an integer x = 0. During one move, you can do one of the following two operations: 1. Choose exactly one i from 1 to n and increase a_i by x (a_i := a_i + x), then increase x by 1 (x := x + 1). 2. Just increase x by 1 (x := x + 1). The first operation can be applied no more than once to each i from 1 to n. Your task is to find the minimum number of moves required to obtain such an array that each its element is divisible by k (the value k is given). You have to answer t independent test cases. Input The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow. The first line of the test case contains two integers n and k (1 ≤ n ≤ 2 ⋅ 10^5; 1 ≤ k ≤ 10^9) — the length of a and the required divisior. The second line of the test case contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is the i-th element of a. It is guaranteed that the sum of n does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5). Output For each test case, print the answer — the minimum number of moves required to obtain such an array that each its element is divisible by k. Example Input 5 4 3 1 2 1 3 10 6 8 7 1 8 3 7 5 10 8 9 5 10 20 100 50 20 100500 10 25 24 24 24 24 24 24 24 24 24 24 8 8 1 2 3 4 5 6 7 8 Output 6 18 0 227 8 Note Consider the first test case of the example: 1. x=0, a = [1, 2, 1, 3]. Just increase x; 2. x=1, a = [1, 2, 1, 3]. Add x to the second element and increase x; 3. x=2, a = [1, 3, 1, 3]. Add x to the third element and increase x; 4. x=3, a = [1, 3, 3, 3]. Add x to the fourth element and increase x; 5. x=4, a = [1, 3, 3, 6]. Just increase x; 6. x=5, a = [1, 3, 3, 6]. Add x to the first element and increase x; 7. x=6, a = [6, 3, 3, 6]. We obtained the required array. Note that you can't add x to the same element more than once. Submitted Solution: ``` import sys input=sys.stdin.readline f=lambda :list(map(int, input().split())) res=[] for _ in range(int(input())): n, k=f() inp=f() cnt={} for i in range(n): if inp[i]%k==0: inp[i]=0 else: inp[i]=(inp[i]//k+1)*k-inp[i] cnt[inp[i]]=cnt.get(inp[i], 0)+1 inp.sort() ans=0 if inp[n-1]==0 else 1 done={} for i in range(n): if inp[i]: if not done.get(inp[i], False): done[inp[i]]=True else: cur=inp[i] l=1; r=cnt[cur]+1 ret=0 while l<=r: m=(l+r)//2 if done.get(cur+m*k, False): l=m+1 else: ret=m r=m-1 cur+=k*ret # while done.get(cur, False): # cur+=k inp[i]=cur done[cur]=True res.append(ans+inp[n-1]) print('\n'.join(map(str, res))) ```
instruction
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40,606
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81,212
No
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40,606
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81,213
Provide tags and a correct Python 3 solution for this coding contest problem. The cows have just learned what a primitive root is! Given a prime p, a primitive root <image> is an integer x (1 ≤ x < p) such that none of integers x - 1, x2 - 1, ..., xp - 2 - 1 are divisible by p, but xp - 1 - 1 is. Unfortunately, computing primitive roots can be time consuming, so the cows need your help. Given a prime p, help the cows find the number of primitive roots <image>. Input The input contains a single line containing an integer p (2 ≤ p < 2000). It is guaranteed that p is a prime. Output Output on a single line the number of primitive roots <image>. Examples Input 3 Output 1 Input 5 Output 2 Note The only primitive root <image> is 2. The primitive roots <image> are 2 and 3.
instruction
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Tags: implementation, math, number theory Correct Solution: ``` def prim_roots(number): if number == 2: return 1 elif number == 4: return 2 z, h = 1, 2 p = list() while h < number: k = pow(h, z, number) while k > 1: z += 1 k = (k * h) % number if z == number - 1: p.append(h) z = 1 h += 1 return len(p) print(prim_roots(int(input()))) ```
output
1
40,724
22
81,449
Provide tags and a correct Python 3 solution for this coding contest problem. The cows have just learned what a primitive root is! Given a prime p, a primitive root <image> is an integer x (1 ≤ x < p) such that none of integers x - 1, x2 - 1, ..., xp - 2 - 1 are divisible by p, but xp - 1 - 1 is. Unfortunately, computing primitive roots can be time consuming, so the cows need your help. Given a prime p, help the cows find the number of primitive roots <image>. Input The input contains a single line containing an integer p (2 ≤ p < 2000). It is guaranteed that p is a prime. Output Output on a single line the number of primitive roots <image>. Examples Input 3 Output 1 Input 5 Output 2 Note The only primitive root <image> is 2. The primitive roots <image> are 2 and 3.
instruction
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Tags: implementation, math, number theory Correct Solution: ``` def isPrimitiveRoot(x,p): i = 2 m = phi = p - 1 while i*i <= m: if m%i == 0: if pow(x,phi//i,p) == 1: return 0 while m%i == 0: m //= i i += 1 if m > 1: return pow(x,phi//m,p) != 1 return pow(x,phi,p) == 1 p = int(input()) ans = 0 for g in range(1,p): if isPrimitiveRoot(g,p): ans += 1 print(ans) ```
output
1
40,725
22
81,451
Provide tags and a correct Python 3 solution for this coding contest problem. The cows have just learned what a primitive root is! Given a prime p, a primitive root <image> is an integer x (1 ≤ x < p) such that none of integers x - 1, x2 - 1, ..., xp - 2 - 1 are divisible by p, but xp - 1 - 1 is. Unfortunately, computing primitive roots can be time consuming, so the cows need your help. Given a prime p, help the cows find the number of primitive roots <image>. Input The input contains a single line containing an integer p (2 ≤ p < 2000). It is guaranteed that p is a prime. Output Output on a single line the number of primitive roots <image>. Examples Input 3 Output 1 Input 5 Output 2 Note The only primitive root <image> is 2. The primitive roots <image> are 2 and 3.
instruction
0
40,726
22
81,452
Tags: implementation, math, number theory Correct Solution: ``` p = int(input()) ans = 0 for i in range(1, p): result = True temp = i for j in range(1, p): if j == p-1: if (temp-1) % p != 0: result = False else: if (temp-1) % p == 0: result = False break temp *= i temp %= p if result: ans += 1 print(ans) ```
output
1
40,726
22
81,453
Provide tags and a correct Python 3 solution for this coding contest problem. The cows have just learned what a primitive root is! Given a prime p, a primitive root <image> is an integer x (1 ≤ x < p) such that none of integers x - 1, x2 - 1, ..., xp - 2 - 1 are divisible by p, but xp - 1 - 1 is. Unfortunately, computing primitive roots can be time consuming, so the cows need your help. Given a prime p, help the cows find the number of primitive roots <image>. Input The input contains a single line containing an integer p (2 ≤ p < 2000). It is guaranteed that p is a prime. Output Output on a single line the number of primitive roots <image>. Examples Input 3 Output 1 Input 5 Output 2 Note The only primitive root <image> is 2. The primitive roots <image> are 2 and 3.
instruction
0
40,727
22
81,454
Tags: implementation, math, number theory Correct Solution: ``` # python 3 """ Modular arithmetic: This has something to do with Extended Euclidean Algorithm """ def cows_and_primitive_roots(p_int): if p_int == 2: return 1 count = 0 for x in range(2, p_int): x_to_i_mod_p = x divisible = False for i in range(2, p_int-1): x_to_i_mod_p = (x * x_to_i_mod_p) % p_int if x_to_i_mod_p == 1: divisible = True break if not divisible: count += 1 # print(x) return count if __name__ == "__main__": """ Inside of this is the test. Outside is the API """ p = int(input()) print(cows_and_primitive_roots(p)) ```
output
1
40,727
22
81,455
Provide tags and a correct Python 3 solution for this coding contest problem. The cows have just learned what a primitive root is! Given a prime p, a primitive root <image> is an integer x (1 ≤ x < p) such that none of integers x - 1, x2 - 1, ..., xp - 2 - 1 are divisible by p, but xp - 1 - 1 is. Unfortunately, computing primitive roots can be time consuming, so the cows need your help. Given a prime p, help the cows find the number of primitive roots <image>. Input The input contains a single line containing an integer p (2 ≤ p < 2000). It is guaranteed that p is a prime. Output Output on a single line the number of primitive roots <image>. Examples Input 3 Output 1 Input 5 Output 2 Note The only primitive root <image> is 2. The primitive roots <image> are 2 and 3.
instruction
0
40,728
22
81,456
Tags: implementation, math, number theory Correct Solution: ``` p=int(input()) count=0 for i in range(1,p): z,x=1,1 for j in range(1,p-1): x*=i x%=p if x==1: z=0 break if z==1: x*=i x%=p if x==1: count+=1 print(count) ```
output
1
40,728
22
81,457
Provide tags and a correct Python 3 solution for this coding contest problem. The cows have just learned what a primitive root is! Given a prime p, a primitive root <image> is an integer x (1 ≤ x < p) such that none of integers x - 1, x2 - 1, ..., xp - 2 - 1 are divisible by p, but xp - 1 - 1 is. Unfortunately, computing primitive roots can be time consuming, so the cows need your help. Given a prime p, help the cows find the number of primitive roots <image>. Input The input contains a single line containing an integer p (2 ≤ p < 2000). It is guaranteed that p is a prime. Output Output on a single line the number of primitive roots <image>. Examples Input 3 Output 1 Input 5 Output 2 Note The only primitive root <image> is 2. The primitive roots <image> are 2 and 3.
instruction
0
40,729
22
81,458
Tags: implementation, math, number theory Correct Solution: ``` p = int(input()) - 1 def hcf(a, b): if a is 0: return b else: return hcf(b % a, a) cnt = 0 for i in range(1, p + 1): if hcf(i, p) is 1: cnt += 1 print(cnt) ```
output
1
40,729
22
81,459