message stringlengths 2 57.2k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 61 108k | cluster float64 22 22 | __index_level_0__ int64 122 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Positive integer x is called divisor of positive integer y, if y is divisible by x without remainder. For example, 1 is a divisor of 7 and 3 is not divisor of 8.
We gave you an integer d and as... | instruction | 0 | 45,619 | 22 | 91,238 |
No | output | 1 | 45,619 | 22 | 91,239 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction <image> is called proper iff its numerator is smaller than its denominator (a < b) and that the fraction is called irreducible i... | instruction | 0 | 45,844 | 22 | 91,688 |
Tags: brute force, constructive algorithms, math
Correct Solution:
```
from math import *
n= int(input())
if n%2==1:
print((n-1)//2,(n-1)//2+1 )
else:
r= n//2
for i in reversed(range(1,r)):
if gcd(i,n-i)==1:
print(i,n-i); exit(0)
``` | output | 1 | 45,844 | 22 | 91,689 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction <image> is called proper iff its numerator is smaller than its denominator (a < b) and that the fraction is called irreducible i... | instruction | 0 | 45,845 | 22 | 91,690 |
Tags: brute force, constructive algorithms, math
Correct Solution:
```
a=int(input())
thesum=0
if a%2==0:
firstnumber=int(a/2)
secondnumber=int(a/2)
elif a%2==1:
firstnumber=int((a-1)/2)
secondnumber=int((a+1)/2)
killnumber=0
primenumber=2
rocketnumber=0
while rocketnumber==0:
while killnumber==0 ... | output | 1 | 45,845 | 22 | 91,691 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction <image> is called proper iff its numerator is smaller than its denominator (a < b) and that the fraction is called irreducible i... | instruction | 0 | 45,846 | 22 | 91,692 |
Tags: brute force, constructive algorithms, math
Correct Solution:
```
from fractions import gcd
import math
n = int(input())
a = 0
b = 0
x = int(n/2) + 1
for i in range(1,x):
if gcd(i, n-i) == 1:
a = i
b = n - i
# print(a,b)
print(a,b)
``` | output | 1 | 45,846 | 22 | 91,693 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction <image> is called proper iff its numerator is smaller than its denominator (a < b) and that the fraction is called irreducible i... | instruction | 0 | 45,847 | 22 | 91,694 |
Tags: brute force, constructive algorithms, math
Correct Solution:
```
import math
n=int(input())
if n%2==1:
a,b=n//2,n//2+1
else:
a,b=n//2-1, n//2+1
while math.gcd(a,b)!=1:
a-=1
b+=1
print(a,b)
``` | output | 1 | 45,847 | 22 | 91,695 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction <image> is called proper iff its numerator is smaller than its denominator (a < b) and that the fraction is called irreducible i... | instruction | 0 | 45,848 | 22 | 91,696 |
Tags: brute force, constructive algorithms, math
Correct Solution:
```
from math import gcd as bltin_gcd
def coprime(a, b):
return bltin_gcd(a, b) == 1
def II(): return int(SI())
# def MI(): return map(int, SI().split())
# def LI(): return list(MI())
def SI(): return input()
N = II()
pairs = []
for a ... | output | 1 | 45,848 | 22 | 91,697 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction <image> is called proper iff its numerator is smaller than its denominator (a < b) and that the fraction is called irreducible i... | instruction | 0 | 45,849 | 22 | 91,698 |
Tags: brute force, constructive algorithms, math
Correct Solution:
```
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
def irr(a, b):
for k in range(1, a + 1):
if a % k == 0 and b % k == 0 and k != 1:
return False
return True
def gener(n):
l = []
for i in range(1, n // 2):
... | output | 1 | 45,849 | 22 | 91,699 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction <image> is called proper iff its numerator is smaller than its denominator (a < b) and that the fraction is called irreducible i... | instruction | 0 | 45,850 | 22 | 91,700 |
Tags: brute force, constructive algorithms, math
Correct Solution:
```
def gcd(a, b):
if b < a: return gcd(b, a)
if b%a==0: return a
return gcd(b%a, a)
total = int(input())
num = total // 2
den = total - num
while True:
if gcd(num, den)==1:
print(num, den)
break
num-=1
den+=1
``` | output | 1 | 45,850 | 22 | 91,701 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction <image> is called proper iff its numerator is smaller than its denominator (a < b) and that the fraction is called irreducible i... | instruction | 0 | 45,851 | 22 | 91,702 |
Tags: brute force, constructive algorithms, math
Correct Solution:
```
n = int(input())
from fractions import gcd
for a in reversed(range(1,n//2+1)):
b = n-a
if gcd(a,b) == 1:
print(a,b)
break
``` | output | 1 | 45,851 | 22 | 91,703 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction <image> is called proper iff its numerator is smaller than its denominator (a < b... | instruction | 0 | 45,852 | 22 | 91,704 |
Yes | output | 1 | 45,852 | 22 | 91,705 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction <image> is called proper iff its numerator is smaller than its denominator (a < b... | instruction | 0 | 45,853 | 22 | 91,706 |
Yes | output | 1 | 45,853 | 22 | 91,707 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction <image> is called proper iff its numerator is smaller than its denominator (a < b... | instruction | 0 | 45,854 | 22 | 91,708 |
Yes | output | 1 | 45,854 | 22 | 91,709 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction <image> is called proper iff its numerator is smaller than its denominator (a < b... | instruction | 0 | 45,855 | 22 | 91,710 |
Yes | output | 1 | 45,855 | 22 | 91,711 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction <image> is called proper iff its numerator is smaller than its denominator (a < b... | instruction | 0 | 45,856 | 22 | 91,712 |
No | output | 1 | 45,856 | 22 | 91,713 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction <image> is called proper iff its numerator is smaller than its denominator (a < b... | instruction | 0 | 45,857 | 22 | 91,714 |
No | output | 1 | 45,857 | 22 | 91,715 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction <image> is called proper iff its numerator is smaller than its denominator (a < b... | instruction | 0 | 45,858 | 22 | 91,716 |
No | output | 1 | 45,858 | 22 | 91,717 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction <image> is called proper iff its numerator is smaller than its denominator (a < b... | instruction | 0 | 45,859 | 22 | 91,718 |
No | output | 1 | 45,859 | 22 | 91,719 |
Provide a correct Python 3 solution for this coding contest problem.
Fibonacci number f(i) appear in a variety of puzzles in nature and math, including packing problems, family trees or Pythagorean triangles. They obey the rule f(i) = f(i - 1) + f(i - 2), where we set f(0) = 1 = f(-1).
Let V and d be two certain posi... | instruction | 0 | 46,118 | 22 | 92,236 |
"Correct Solution:
```
# AOJ 1016: Fibonacci Sets
# Python3 2018.7.4 bal4u
f = [0]*1001
f[0], f[1] = 2, 3
for i in range(2, 1001): f[i] = (f[i-1]+f[i-2])%1001
while True:
try: V, d = map(int, input().split())
except: break
ans, a = 1, sorted(f[:V])
for i in range(1, V):
if a[i]-a[i-1] >= d: ans += 1
print(ans)
... | output | 1 | 46,118 | 22 | 92,237 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Orac is studying number theory, and he is interested in the properties of divisors.
For two positive integers a and b, a is a divisor of b if and only if there exists an integer c, such that a⋅ c=b.
For n ≥ 2, we will denote as f(n) the sm... | instruction | 0 | 46,414 | 22 | 92,828 |
Tags: math
Correct Solution:
```
import sys
content = sys.stdin.read().strip().splitlines()
content = content[1:]
def f(n):
divisor = 0
for i in range(2, int(n ** 0.5) + 1):
if n % i == 0:
divisor = i
break
if divisor == 0:
divisor = n
return divisor
for c in co... | output | 1 | 46,414 | 22 | 92,829 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Orac is studying number theory, and he is interested in the properties of divisors.
For two positive integers a and b, a is a divisor of b if and only if there exists an integer c, such that a⋅ c=b.
For n ≥ 2, we will denote as f(n) the sm... | instruction | 0 | 46,415 | 22 | 92,830 |
Tags: math
Correct Solution:
```
for _ in range(int(input())):
n, k = map(int, input().split())
if n % 2 == 0:
n += 2 * k
else:
if k == 1:
n = 2 * n
else:
backUp = 0
for i in range(3, n + 1, 2):
if n % i == 0:
ba... | output | 1 | 46,415 | 22 | 92,831 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Orac is studying number theory, and he is interested in the properties of divisors.
For two positive integers a and b, a is a divisor of b if and only if there exists an integer c, such that a⋅ c=b.
For n ≥ 2, we will denote as f(n) the sm... | instruction | 0 | 46,416 | 22 | 92,832 |
Tags: math
Correct Solution:
```
for _ in range(int(input())):
n,k = map(int,input().split())
if(n%2==0):
n=2*(k)+n
else:
for i in range(3,n+1,2):
if(n%i)==0:
# print(i)
n=n+i
break
n=2*(k-1)+n
print(n) ... | output | 1 | 46,416 | 22 | 92,833 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Orac is studying number theory, and he is interested in the properties of divisors.
For two positive integers a and b, a is a divisor of b if and only if there exists an integer c, such that a⋅ c=b.
For n ≥ 2, we will denote as f(n) the sm... | instruction | 0 | 46,417 | 22 | 92,834 |
Tags: math
Correct Solution:
```
def f(n):
i = 2
while i * i <= n:
if n % i == 0:
return i
i += 1
return n
def solve(n, k):
return n + f(n) + 2 * (k - 1)
[print(solve(*map(int, input().split()))) for t in range(int(input()))]
``` | output | 1 | 46,417 | 22 | 92,835 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Orac is studying number theory, and he is interested in the properties of divisors.
For two positive integers a and b, a is a divisor of b if and only if there exists an integer c, such that a⋅ c=b.
For n ≥ 2, we will denote as f(n) the sm... | instruction | 0 | 46,418 | 22 | 92,836 |
Tags: math
Correct Solution:
```
def f(x):
if x % 2 == 0:
return 2
i=3
val=x # if while loop doesnt change the value, then the no is prime, so the output should be the no. itself
while(i*i<=x):
if(x%i==0):
val=i
break
else:
i+=2
return val
... | output | 1 | 46,418 | 22 | 92,837 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Orac is studying number theory, and he is interested in the properties of divisors.
For two positive integers a and b, a is a divisor of b if and only if there exists an integer c, such that a⋅ c=b.
For n ≥ 2, we will denote as f(n) the sm... | instruction | 0 | 46,419 | 22 | 92,838 |
Tags: math
Correct Solution:
```
def func(N):
if N==1:
return 1
elif N%2==0:
return 2
else:
for i in range(3,int(N/3)+1):
if N%i==0:
return i
return N
T=int(input())
for t in range(T):
[N,K]=list(map(int,input().strip().split()))
N+=func(N... | output | 1 | 46,419 | 22 | 92,839 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Orac is studying number theory, and he is interested in the properties of divisors.
For two positive integers a and b, a is a divisor of b if and only if there exists an integer c, such that a⋅ c=b.
For n ≥ 2, we will denote as f(n) the sm... | instruction | 0 | 46,420 | 22 | 92,840 |
Tags: math
Correct Solution:
```
import sys
from math import log,sqrt,factorial
def ii(): return int(input())
def si(): return input()
def mi(): return map(int,input().strip().split(" "))
def msi(): return map(str,input().strip().split(" "))
def li(): return list(mi())
#def read():
t=ii()
while(t):
t-=1
n,... | output | 1 | 46,420 | 22 | 92,841 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Orac is studying number theory, and he is interested in the properties of divisors.
For two positive integers a and b, a is a divisor of b if and only if there exists an integer c, such that a⋅ c=b.
For n ≥ 2, we will denote as f(n) the sm... | instruction | 0 | 46,421 | 22 | 92,842 |
Tags: math
Correct Solution:
```
def f(a):
b = 2;
while a % b > 0:
b += 1
return b
for _ in range(int(input())):
n, k = [int(x) for x in input().split()]
if not (n % 2):
print(n + 2 * k)
continue
x = f(n)
print(n + x + 2 * (k-1))
``` | output | 1 | 46,421 | 22 | 92,843 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Orac is studying number theory, and he is interested in the properties of divisors.
For two positive integers a and b, a is a divisor of b if and only if there exists an integer c, such that a⋅... | instruction | 0 | 46,422 | 22 | 92,844 |
Yes | output | 1 | 46,422 | 22 | 92,845 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Orac is studying number theory, and he is interested in the properties of divisors.
For two positive integers a and b, a is a divisor of b if and only if there exists an integer c, such that a⋅... | instruction | 0 | 46,423 | 22 | 92,846 |
Yes | output | 1 | 46,423 | 22 | 92,847 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Orac is studying number theory, and he is interested in the properties of divisors.
For two positive integers a and b, a is a divisor of b if and only if there exists an integer c, such that a⋅... | instruction | 0 | 46,424 | 22 | 92,848 |
Yes | output | 1 | 46,424 | 22 | 92,849 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Orac is studying number theory, and he is interested in the properties of divisors.
For two positive integers a and b, a is a divisor of b if and only if there exists an integer c, such that a⋅... | instruction | 0 | 46,425 | 22 | 92,850 |
Yes | output | 1 | 46,425 | 22 | 92,851 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Orac is studying number theory, and he is interested in the properties of divisors.
For two positive integers a and b, a is a divisor of b if and only if there exists an integer c, such that a⋅... | instruction | 0 | 46,426 | 22 | 92,852 |
No | output | 1 | 46,426 | 22 | 92,853 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Orac is studying number theory, and he is interested in the properties of divisors.
For two positive integers a and b, a is a divisor of b if and only if there exists an integer c, such that a⋅... | instruction | 0 | 46,427 | 22 | 92,854 |
No | output | 1 | 46,427 | 22 | 92,855 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Orac is studying number theory, and he is interested in the properties of divisors.
For two positive integers a and b, a is a divisor of b if and only if there exists an integer c, such that a⋅... | instruction | 0 | 46,428 | 22 | 92,856 |
No | output | 1 | 46,428 | 22 | 92,857 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Orac is studying number theory, and he is interested in the properties of divisors.
For two positive integers a and b, a is a divisor of b if and only if there exists an integer c, such that a⋅... | instruction | 0 | 46,429 | 22 | 92,858 |
No | output | 1 | 46,429 | 22 | 92,859 |
Evaluate the correctness of the submitted Python 2 solution to the coding contest problem. Provide a "Yes" or "No" response.
Orac is studying number theory, and he is interested in the properties of divisors.
For two positive integers a and b, a is a divisor of b if and only if there exists an integer c, such that a⋅... | instruction | 0 | 46,430 | 22 | 92,860 |
No | output | 1 | 46,430 | 22 | 92,861 |
Evaluate the correctness of the submitted Python 2 solution to the coding contest problem. Provide a "Yes" or "No" response.
Orac is studying number theory, and he is interested in the properties of divisors.
For two positive integers a and b, a is a divisor of b if and only if there exists an integer c, such that a⋅... | instruction | 0 | 46,431 | 22 | 92,862 |
No | output | 1 | 46,431 | 22 | 92,863 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A pair of positive integers (a,b) is called special if ⌊ a/b ⌋ = a mod b. Here, ⌊ a/b ⌋ is the result of the integer division between a and b, while a mod b is its remainder.
You are given two integers x and y. Find the number of special pa... | instruction | 0 | 46,496 | 22 | 92,992 |
Tags: binary search, brute force, math, number theory
Correct Solution:
```
from bisect import *
from collections import *
from math import gcd,ceil,sqrt,floor,inf
from heapq import *
from itertools import *
from operator import add,mul,sub,xor,truediv,floordiv
from functools import *
#-------------------------------... | output | 1 | 46,496 | 22 | 92,993 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A pair of positive integers (a,b) is called special if ⌊ a/b ⌋ = a mod b. Here, ⌊ a/b ⌋ is the result of the integer division between a and b, while a mod b is its remainder.
You are given two integers x and y. Find the number of special pa... | instruction | 0 | 46,497 | 22 | 92,994 |
Tags: binary search, brute force, math, number theory
Correct Solution:
```
# for a in range(1,50):
# for b in range(1,50):
# left=(a//b)
# right=a%b
# if left==right:
# print(a,b)
al=[]
for _ in range(int(input())):
x,y=map(int, input().split())
ans=0
for r in range... | output | 1 | 46,497 | 22 | 92,995 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A pair of positive integers (a,b) is called special if ⌊ a/b ⌋ = a mod b. Here, ⌊ a/b ⌋ is the result of the integer division between a and b, while a mod b is its remainder.
You are given two integers x and y. Find the number of special pa... | instruction | 0 | 46,498 | 22 | 92,996 |
Tags: binary search, brute force, math, number theory
Correct Solution:
```
'''
Aaditya Upadhyay
ud$$$**$$$$$$bc.
u@**" 4$$$$$$Nu
J ""#$$$$$r
@ $$$b
.F ... | output | 1 | 46,498 | 22 | 92,997 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A pair of positive integers (a,b) is called special if ⌊ a/b ⌋ = a mod b. Here, ⌊ a/b ⌋ is the result of the integer division between a and b, while a mod b is its remainder.
You are given two integers x and y. Find the number of special pa... | instruction | 0 | 46,499 | 22 | 92,998 |
Tags: binary search, brute force, math, number theory
Correct Solution:
```
def testcase():
[X,Y]=[int(c) for c in input().split()]
res = 0
b = 1
while b**2-1 <= X and b <= Y:
res += b-1 #b-1 valid a
b += 1
c = 1 #number of valid a
while c < b:
hi = (X//c)-1
lo =... | output | 1 | 46,499 | 22 | 92,999 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A pair of positive integers (a,b) is called special if ⌊ a/b ⌋ = a mod b. Here, ⌊ a/b ⌋ is the result of the integer division between a and b, while a mod b is its remainder.
You are given two integers x and y. Find the number of special pa... | instruction | 0 | 46,500 | 22 | 93,000 |
Tags: binary search, brute force, math, number theory
Correct Solution:
```
t=int(input())
for _ in range(t):
a,b=map(int,input().split())
ans=0
c=1
while c*c<=a:
x = (a-c)//c
if x>b:
x=b
ans+=max(x-c,0)
c+=1
print(ans)
``` | output | 1 | 46,500 | 22 | 93,001 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A pair of positive integers (a,b) is called special if ⌊ a/b ⌋ = a mod b. Here, ⌊ a/b ⌋ is the result of the integer division between a and b, while a mod b is its remainder.
You are given two integers x and y. Find the number of special pa... | instruction | 0 | 46,501 | 22 | 93,002 |
Tags: binary search, brute force, math, number theory
Correct Solution:
```
import collections
import string
import math
import copy
import os
import sys
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.b... | output | 1 | 46,501 | 22 | 93,003 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A pair of positive integers (a,b) is called special if ⌊ a/b ⌋ = a mod b. Here, ⌊ a/b ⌋ is the result of the integer division between a and b, while a mod b is its remainder.
You are given two integers x and y. Find the number of special pa... | instruction | 0 | 46,502 | 22 | 93,004 |
Tags: binary search, brute force, math, number theory
Correct Solution:
```
t = int(input())
for i in range(t):
l1 = input().split(' ')
x, y = int(l1[0]), int(l1[1])
s = 0
for j in range(1, y):
k = (x-j) // j
if k <= j :
break
s += min(k, y) - j
# print(j, s)... | output | 1 | 46,502 | 22 | 93,005 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A pair of positive integers (a,b) is called special if ⌊ a/b ⌋ = a mod b. Here, ⌊ a/b ⌋ is the result of the integer division between a and b, while a mod b is its remainder.
You are given two integers x and y. Find the number of special pa... | instruction | 0 | 46,503 | 22 | 93,006 |
Tags: binary search, brute force, math, number theory
Correct Solution:
```
def main():
t=int(input())
allAns=[]
for _ in range(t):
x,y=readIntArr()
ans=0
nK=1
while min((x//nK-1),y)>=nK:
ans+=min((x//nK-1),y)-nK
nK+=1
allAns.app... | output | 1 | 46,503 | 22 | 93,007 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A pair of positive integers (a,b) is called special if ⌊ a/b ⌋ = a mod b. Here, ⌊ a/b ⌋ is the result of the integer division between a and b, while a mod b is its remainder.
You are given two ... | instruction | 0 | 46,504 | 22 | 93,008 |
Yes | output | 1 | 46,504 | 22 | 93,009 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A pair of positive integers (a,b) is called special if ⌊ a/b ⌋ = a mod b. Here, ⌊ a/b ⌋ is the result of the integer division between a and b, while a mod b is its remainder.
You are given two ... | instruction | 0 | 46,505 | 22 | 93,010 |
Yes | output | 1 | 46,505 | 22 | 93,011 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A pair of positive integers (a,b) is called special if ⌊ a/b ⌋ = a mod b. Here, ⌊ a/b ⌋ is the result of the integer division between a and b, while a mod b is its remainder.
You are given two ... | instruction | 0 | 46,506 | 22 | 93,012 |
Yes | output | 1 | 46,506 | 22 | 93,013 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A pair of positive integers (a,b) is called special if ⌊ a/b ⌋ = a mod b. Here, ⌊ a/b ⌋ is the result of the integer division between a and b, while a mod b is its remainder.
You are given two ... | instruction | 0 | 46,507 | 22 | 93,014 |
Yes | output | 1 | 46,507 | 22 | 93,015 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A pair of positive integers (a,b) is called special if ⌊ a/b ⌋ = a mod b. Here, ⌊ a/b ⌋ is the result of the integer division between a and b, while a mod b is its remainder.
You are given two ... | instruction | 0 | 46,508 | 22 | 93,016 |
No | output | 1 | 46,508 | 22 | 93,017 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A pair of positive integers (a,b) is called special if ⌊ a/b ⌋ = a mod b. Here, ⌊ a/b ⌋ is the result of the integer division between a and b, while a mod b is its remainder.
You are given two ... | instruction | 0 | 46,509 | 22 | 93,018 |
No | output | 1 | 46,509 | 22 | 93,019 |
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