message stringlengths 2 57.2k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 61 108k | cluster float64 22 22 | __index_level_0__ int64 122 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are positive integers A and B.
Let us choose some number of positive common divisors of A and B.
Here, any two of the chosen divisors must be coprime.
At most, how many divisors can we ... | instruction | 0 | 73,985 | 22 | 147,970 |
Yes | output | 1 | 73,985 | 22 | 147,971 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are positive integers A and B.
Let us choose some number of positive common divisors of A and B.
Here, any two of the chosen divisors must be coprime.
At most, how many divisors can we ... | instruction | 0 | 73,986 | 22 | 147,972 |
Yes | output | 1 | 73,986 | 22 | 147,973 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are positive integers A and B.
Let us choose some number of positive common divisors of A and B.
Here, any two of the chosen divisors must be coprime.
At most, how many divisors can we ... | instruction | 0 | 73,987 | 22 | 147,974 |
Yes | output | 1 | 73,987 | 22 | 147,975 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are positive integers A and B.
Let us choose some number of positive common divisors of A and B.
Here, any two of the chosen divisors must be coprime.
At most, how many divisors can we ... | instruction | 0 | 73,988 | 22 | 147,976 |
No | output | 1 | 73,988 | 22 | 147,977 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are positive integers A and B.
Let us choose some number of positive common divisors of A and B.
Here, any two of the chosen divisors must be coprime.
At most, how many divisors can we ... | instruction | 0 | 73,989 | 22 | 147,978 |
No | output | 1 | 73,989 | 22 | 147,979 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are positive integers A and B.
Let us choose some number of positive common divisors of A and B.
Here, any two of the chosen divisors must be coprime.
At most, how many divisors can we ... | instruction | 0 | 73,990 | 22 | 147,980 |
No | output | 1 | 73,990 | 22 | 147,981 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are positive integers A and B.
Let us choose some number of positive common divisors of A and B.
Here, any two of the chosen divisors must be coprime.
At most, how many divisors can we ... | instruction | 0 | 73,991 | 22 | 147,982 |
No | output | 1 | 73,991 | 22 | 147,983 |
Provide a correct Python 3 solution for this coding contest problem.
Given n integers a1, a2,…, an and n integers p1, p2,…, pn, integer m. The operation of selecting the kth integer ak with a probability of pk [%] is performed for each k (1 ≤ k ≤ n), and 0 or more and n or less integers are selected. Find the expected... | instruction | 0 | 74,131 | 22 | 148,262 |
"Correct Solution:
```
def GCD(x, y):
if y == 0:
return x
return GCD(y, x % y)
def CountBitFlag(T):
T = (T & 0x55555555) + ((T >> 1) & 0x55555555)
T = (T & 0x33333333) + ((T >> 2) & 0x33333333)
T = (T & 0x0F0F0F0F) + ((T >> 4) & 0x0F0F0F0F)
T = (T & 0x00FF00FF) + ((T >> 8) & 0x00FF00FF... | output | 1 | 74,131 | 22 | 148,263 |
Provide a correct Python 3 solution for this coding contest problem.
Given n integers a1, a2,…, an and n integers p1, p2,…, pn, integer m. The operation of selecting the kth integer ak with a probability of pk [%] is performed for each k (1 ≤ k ≤ n), and 0 or more and n or less integers are selected. Find the expected... | instruction | 0 | 74,132 | 22 | 148,264 |
"Correct Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 10**9+7
dd = [(-1,0),(0,1),(1,0),(0,-1)]
ddn = [(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)]
def LI(): return [int... | output | 1 | 74,132 | 22 | 148,265 |
Provide a correct Python 3 solution for this coding contest problem.
Given n integers a1, a2,…, an and n integers p1, p2,…, pn, integer m. The operation of selecting the kth integer ak with a probability of pk [%] is performed for each k (1 ≤ k ≤ n), and 0 or more and n or less integers are selected. Find the expected... | instruction | 0 | 74,133 | 22 | 148,266 |
"Correct Solution:
```
import sys
readline = sys.stdin.readline
write = sys.stdout.write
def solve():
N, M = map(int, readline().split())
*A, = map(int, readline().split())
*P, = map(int, readline().split())
def lcm(m, n):
m0 = m; n0 = n
while n:
m, n = n, m % n
retur... | output | 1 | 74,133 | 22 | 148,267 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given n integers a1, a2,…, an and n integers p1, p2,…, pn, integer m. The operation of selecting the kth integer ak with a probability of pk [%] is performed for each k (1 ≤ k ≤ n), and 0 or mor... | instruction | 0 | 74,134 | 22 | 148,268 |
No | output | 1 | 74,134 | 22 | 148,269 |
Provide a correct Python 3 solution for this coding contest problem.
Ikta loves fast programs. Recently, I'm trying to speed up the division program. However, it doesn't get much faster, so I thought it would be better to make it faster only for "common sense and typical" inputs. The problem Ikta is trying to solve is... | instruction | 0 | 74,135 | 22 | 148,270 |
"Correct Solution:
```
# AOJ 2610: Fast Division
# Python3 2018.6.30 bal4u
ans = [1, 2, 1, 0]
n = int(input())
if n > 2: n = 3
print(ans[n])
``` | output | 1 | 74,135 | 22 | 148,271 |
Provide a correct Python 3 solution for this coding contest problem.
Ikta loves fast programs. Recently, I'm trying to speed up the division program. However, it doesn't get much faster, so I thought it would be better to make it faster only for "common sense and typical" inputs. The problem Ikta is trying to solve is... | instruction | 0 | 74,136 | 22 | 148,272 |
"Correct Solution:
```
n=int(input())
if n>3:n=3
print([1,2,1,0][n])
``` | output | 1 | 74,136 | 22 | 148,273 |
Provide a correct Python 3 solution for this coding contest problem.
Ikta loves fast programs. Recently, I'm trying to speed up the division program. However, it doesn't get much faster, so I thought it would be better to make it faster only for "common sense and typical" inputs. The problem Ikta is trying to solve is... | instruction | 0 | 74,137 | 22 | 148,274 |
"Correct Solution:
```
#!usr/bin/env python3
from collections import defaultdict
from collections import deque
from heapq import heappush, heappop
import sys
import math
import bisect
import random
def LI(): return list(map(int, sys.stdin.readline().split()))
def I(): return int(sys.stdin.readline())
def LS():return li... | output | 1 | 74,137 | 22 | 148,275 |
Provide a correct Python 3 solution for this coding contest problem.
Ikta loves fast programs. Recently, I'm trying to speed up the division program. However, it doesn't get much faster, so I thought it would be better to make it faster only for "common sense and typical" inputs. The problem Ikta is trying to solve is... | instruction | 0 | 74,138 | 22 | 148,276 |
"Correct Solution:
```
n=int(input())
if n==0 or n==2:print(1)
else: print(2 if n==1 else 0)
``` | output | 1 | 74,138 | 22 | 148,277 |
Provide a correct Python 3 solution for this coding contest problem.
Ikta loves fast programs. Recently, I'm trying to speed up the division program. However, it doesn't get much faster, so I thought it would be better to make it faster only for "common sense and typical" inputs. The problem Ikta is trying to solve is... | instruction | 0 | 74,139 | 22 | 148,278 |
"Correct Solution:
```
n=int(input())
print(1if n==0else 2//n)
``` | output | 1 | 74,139 | 22 | 148,279 |
Provide a correct Python 3 solution for this coding contest problem.
Ikta loves fast programs. Recently, I'm trying to speed up the division program. However, it doesn't get much faster, so I thought it would be better to make it faster only for "common sense and typical" inputs. The problem Ikta is trying to solve is... | instruction | 0 | 74,140 | 22 | 148,280 |
"Correct Solution:
```
n = int(input())
if n == 0 or n == 2:
print(1)
elif n == 1:
print(2)
else:
print(0)
``` | output | 1 | 74,140 | 22 | 148,281 |
Provide a correct Python 3 solution for this coding contest problem.
Ikta loves fast programs. Recently, I'm trying to speed up the division program. However, it doesn't get much faster, so I thought it would be better to make it faster only for "common sense and typical" inputs. The problem Ikta is trying to solve is... | instruction | 0 | 74,141 | 22 | 148,282 |
"Correct Solution:
```
n = int(input())
if n == 0:
print(1)
elif n == 1:
print(2)
elif n == 2:
print(1)
else:
print(0)
``` | output | 1 | 74,141 | 22 | 148,283 |
Provide a correct Python 3 solution for this coding contest problem.
Ikta loves fast programs. Recently, I'm trying to speed up the division program. However, it doesn't get much faster, so I thought it would be better to make it faster only for "common sense and typical" inputs. The problem Ikta is trying to solve is... | instruction | 0 | 74,142 | 22 | 148,284 |
"Correct Solution:
```
# p(n) = 2^^n より大きい最小の素数 (ただし^^はクヌースの二重矢印記号) と定義したとき、
# x = (10^(p(n)-1)-1)/9 (mod p(n)) を求めよ
# 「フェルマーの小定理」
# pが素数ならば、a^p == a (mod p(n))
# とくに、aとpが互いに素 (gcd(a,p)=1) のとき
# a^p * a^-1 == a * a^-1 (mod p(n))
# a^(p-1) == 1 (mod p)
#
# 9とp(n)が互いに素ならば
# x * 9^-1 = 10^(p(n)-1)-1 (mod p(n))
# 10とp(n)が互... | output | 1 | 74,142 | 22 | 148,285 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ikta loves fast programs. Recently, I'm trying to speed up the division program. However, it doesn't get much faster, so I thought it would be better to make it faster only for "common sense and... | instruction | 0 | 74,143 | 22 | 148,286 |
Yes | output | 1 | 74,143 | 22 | 148,287 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ikta loves fast programs. Recently, I'm trying to speed up the division program. However, it doesn't get much faster, so I thought it would be better to make it faster only for "common sense and... | instruction | 0 | 74,144 | 22 | 148,288 |
Yes | output | 1 | 74,144 | 22 | 148,289 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ikta loves fast programs. Recently, I'm trying to speed up the division program. However, it doesn't get much faster, so I thought it would be better to make it faster only for "common sense and... | instruction | 0 | 74,145 | 22 | 148,290 |
No | output | 1 | 74,145 | 22 | 148,291 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Find out if it is possible to partition the first n positive integers into two non-empty disjoint sets S_1 and S_2 such that:
gcd(sum(S_1), sum(S_2)) > 1
Here sum(S) denotes the sum of all elements present in set S and gcd means the[great... | instruction | 0 | 74,181 | 22 | 148,362 |
Tags: constructive algorithms, math
Correct Solution:
```
# -*- coding: utf-8 -*-
"""
Created on Sat Aug 22 21:39:13 2020
@author: Dark Soul
"""
n=int(input(''))
if n<3:
print('No')
else:
s=n*(n+1)//2
sol=[]
for i in range(1,n+1):
sol.append(i)
if s%2==0:
print('Yes')
print(... | output | 1 | 74,181 | 22 | 148,363 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Find out if it is possible to partition the first n positive integers into two non-empty disjoint sets S_1 and S_2 such that:
gcd(sum(S_1), sum(S_2)) > 1
Here sum(S) denotes the sum of all elements present in set S and gcd means the[great... | instruction | 0 | 74,182 | 22 | 148,364 |
Tags: constructive algorithms, math
Correct Solution:
```
import math as m
n = int(input())
l1 = []
l2 = []
for i in range(1,n+1):
if i%2==0:
l1.append(i)
else:
l2.append(i)
if m.gcd(sum(l1),sum(l2))<=1:
print("No")
else:
print("Yes")
print(len(l1),*l1)
print(len(l2),*l2)
``` | output | 1 | 74,182 | 22 | 148,365 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Find out if it is possible to partition the first n positive integers into two non-empty disjoint sets S_1 and S_2 such that:
gcd(sum(S_1), sum(S_2)) > 1
Here sum(S) denotes the sum of all elements present in set S and gcd means the[great... | instruction | 0 | 74,183 | 22 | 148,366 |
Tags: constructive algorithms, math
Correct Solution:
```
n=int(input())
if n<3:print("No")
else:print("Yes",1,n,n-1,*range(1,n))
``` | output | 1 | 74,183 | 22 | 148,367 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Find out if it is possible to partition the first n positive integers into two non-empty disjoint sets S_1 and S_2 such that:
gcd(sum(S_1), sum(S_2)) > 1
Here sum(S) denotes the sum of all elements present in set S and gcd means the[great... | instruction | 0 | 74,184 | 22 | 148,368 |
Tags: constructive algorithms, math
Correct Solution:
```
import io
import sys
from math import gcd
def solve(n):
return [list(range(1, n+1, 2)), list(range(2, n+1, 2))]
inp = sys.stdin
n = int(inp.readline().strip())
if n <= 2:
print("No")
else:
print("Yes")
ans = solve(n)
print(len(ans[0])... | output | 1 | 74,184 | 22 | 148,369 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Find out if it is possible to partition the first n positive integers into two non-empty disjoint sets S_1 and S_2 such that:
gcd(sum(S_1), sum(S_2)) > 1
Here sum(S) denotes the sum of all elements present in set S and gcd means the[great... | instruction | 0 | 74,185 | 22 | 148,370 |
Tags: constructive algorithms, math
Correct Solution:
```
n=int(input())
if n ==1 or n == 2:
print('No')
else:
print('Yes')
evenlist = [str(2*i) for i in range(1,int((n+2)/2))]
oddlist = [str(2*i+1) for i in range(0,int((n+1)/2))]
print(len(evenlist),' '.join(evenlist))
print(len(oddlist), ' '.j... | output | 1 | 74,185 | 22 | 148,371 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Find out if it is possible to partition the first n positive integers into two non-empty disjoint sets S_1 and S_2 such that:
gcd(sum(S_1), sum(S_2)) > 1
Here sum(S) denotes the sum of all elements present in set S and gcd means the[great... | instruction | 0 | 74,186 | 22 | 148,372 |
Tags: constructive algorithms, math
Correct Solution:
```
from math import gcd
n=int(input());odd=[];even=[];print
for i in range(1,n+1):
if i%2==1:odd.append(i)
else:even.append(i)
if len(odd)>0 and len(even)>0 and gcd(sum(odd),sum(even))>1:
print('Yes');print(len(odd),*odd);print(len(even),*even)
else:print(... | output | 1 | 74,186 | 22 | 148,373 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Find out if it is possible to partition the first n positive integers into two non-empty disjoint sets S_1 and S_2 such that:
gcd(sum(S_1), sum(S_2)) > 1
Here sum(S) denotes the sum of all elements present in set S and gcd means the[great... | instruction | 0 | 74,187 | 22 | 148,374 |
Tags: constructive algorithms, math
Correct Solution:
```
# cook your dish here
from math import gcd
def evenodd(integer):
a = []
b = []
for i in range(1,integer+1):
if i%2 is 0:
a.append(i)
else:
b.append(i)
sa = sum(a)
sb = sum(b)
# print(sum(a))
... | output | 1 | 74,187 | 22 | 148,375 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Find out if it is possible to partition the first n positive integers into two non-empty disjoint sets S_1 and S_2 such that:
gcd(sum(S_1), sum(S_2)) > 1
Here sum(S) denotes the sum of all elements present in set S and gcd means the[great... | instruction | 0 | 74,188 | 22 | 148,376 |
Tags: constructive algorithms, math
Correct Solution:
```
# print("Input n")
n = int(input())
# Special cases
if n==1 or n==2:
print("No")
# Which of n/2 and (n+1)/2 is an int is correct
elif n%2 == 0:
print("Yes")
print("1 " + str(n//2))
print(str(n-1), end = " ")
for i in range(1, n+1):
i... | output | 1 | 74,188 | 22 | 148,377 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Find out if it is possible to partition the first n positive integers into two non-empty disjoint sets S_1 and S_2 such that:
gcd(sum(S_1), sum(S_2)) > 1
Here sum(S) denotes the sum of all el... | instruction | 0 | 74,189 | 22 | 148,378 |
Yes | output | 1 | 74,189 | 22 | 148,379 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Find out if it is possible to partition the first n positive integers into two non-empty disjoint sets S_1 and S_2 such that:
gcd(sum(S_1), sum(S_2)) > 1
Here sum(S) denotes the sum of all el... | instruction | 0 | 74,190 | 22 | 148,380 |
Yes | output | 1 | 74,190 | 22 | 148,381 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Find out if it is possible to partition the first n positive integers into two non-empty disjoint sets S_1 and S_2 such that:
gcd(sum(S_1), sum(S_2)) > 1
Here sum(S) denotes the sum of all el... | instruction | 0 | 74,191 | 22 | 148,382 |
Yes | output | 1 | 74,191 | 22 | 148,383 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Find out if it is possible to partition the first n positive integers into two non-empty disjoint sets S_1 and S_2 such that:
gcd(sum(S_1), sum(S_2)) > 1
Here sum(S) denotes the sum of all el... | instruction | 0 | 74,192 | 22 | 148,384 |
Yes | output | 1 | 74,192 | 22 | 148,385 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Find out if it is possible to partition the first n positive integers into two non-empty disjoint sets S_1 and S_2 such that:
gcd(sum(S_1), sum(S_2)) > 1
Here sum(S) denotes the sum of all el... | instruction | 0 | 74,193 | 22 | 148,386 |
No | output | 1 | 74,193 | 22 | 148,387 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Find out if it is possible to partition the first n positive integers into two non-empty disjoint sets S_1 and S_2 such that:
gcd(sum(S_1), sum(S_2)) > 1
Here sum(S) denotes the sum of all el... | instruction | 0 | 74,194 | 22 | 148,388 |
No | output | 1 | 74,194 | 22 | 148,389 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Find out if it is possible to partition the first n positive integers into two non-empty disjoint sets S_1 and S_2 such that:
gcd(sum(S_1), sum(S_2)) > 1
Here sum(S) denotes the sum of all el... | instruction | 0 | 74,195 | 22 | 148,390 |
No | output | 1 | 74,195 | 22 | 148,391 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Find out if it is possible to partition the first n positive integers into two non-empty disjoint sets S_1 and S_2 such that:
gcd(sum(S_1), sum(S_2)) > 1
Here sum(S) denotes the sum of all el... | instruction | 0 | 74,196 | 22 | 148,392 |
No | output | 1 | 74,196 | 22 | 148,393 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little Petya loves looking for numbers' divisors. One day Petya came across the following problem:
You are given n queries in the form "xi yi". For each query Petya should count how many divisors of number xi divide none of the numbers xi -... | instruction | 0 | 74,219 | 22 | 148,438 |
Tags: binary search, data structures, number theory
Correct Solution:
```
import sys,collections as cc
input = sys.stdin.readline
I = lambda : list(map(int,input().split()))
def div(b):
an=[]
for i in range(1,int(b**0.5)+1):
if b%i==0:
an.append(i)
if i!=b//i:
an.append(b//i)
return an
n,=I()
ar=[]
vi... | output | 1 | 74,219 | 22 | 148,439 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little Petya loves looking for numbers' divisors. One day Petya came across the following problem:
You are given n queries in the form "xi yi". For each query Petya should count how many divisors of number xi divide none of the numbers xi -... | instruction | 0 | 74,220 | 22 | 148,440 |
Tags: binary search, data structures, number theory
Correct Solution:
```
import sys
import collections as cc
input=sys.stdin.buffer.readline
I=lambda:list(map(int,input().split()))
prev=cc.defaultdict(int)
for tc in range(int(input())):
x,y=I()
div=set()
for i in range(1,int(x**0.5)+1):
if x%i==0:
div.add(i)
... | output | 1 | 74,220 | 22 | 148,441 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little Petya loves looking for numbers' divisors. One day Petya came across the following problem:
You are given n queries in the form "xi yi". For each query Petya should count how many divisors of number xi divide none of the numbers xi -... | instruction | 0 | 74,221 | 22 | 148,442 |
Tags: binary search, data structures, number theory
Correct Solution:
```
from collections import defaultdict
mp=defaultdict(lambda :0)
x=int(input())
for k in range(1,x+1):
a,b=map(int,input().split())
res=0
for n in range(1,int(a**.5)+1):
if a%n==0:
if mp[n]==0:
res+=1
... | output | 1 | 74,221 | 22 | 148,443 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little Petya loves looking for numbers' divisors. One day Petya came across the following problem:
You are given n queries in the form "xi yi". For each query Petya should count how many divisors of number xi divide none of the numbers xi -... | instruction | 0 | 74,222 | 22 | 148,444 |
Tags: binary search, data structures, number theory
Correct Solution:
```
import sys
import collections as cc
input=sys.stdin.readline
I=lambda:list(map(int,input().split()))
prev=cc.defaultdict(int)
for tc in range(int(input())):
x,y=I()
div=set()
for i in range(1,int(x**0.5)+1):
if x%i==0:
div.add(i)
div.a... | output | 1 | 74,222 | 22 | 148,445 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Greatest common divisor GCD(a, b) of two positive integers a and b is equal to the biggest integer d such that both integers a and b are divisible by d. There are many efficient algorithms to find greatest common divisor GCD(a, b), for examp... | instruction | 0 | 74,604 | 22 | 149,208 |
Tags: math, number theory
Correct Solution:
```
s , s1 = map(str , input().split())
print(s if s == s1 else 1)
``` | output | 1 | 74,604 | 22 | 149,209 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Greatest common divisor GCD(a, b) of two positive integers a and b is equal to the biggest integer d such that both integers a and b are divisible by d. There are many efficient algorithms to find greatest common divisor GCD(a, b), for examp... | instruction | 0 | 74,605 | 22 | 149,210 |
Tags: math, number theory
Correct Solution:
```
num,num2 = map(str,input().split())
if num == num2:
print(num)
else:
print(1)
``` | output | 1 | 74,605 | 22 | 149,211 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Greatest common divisor GCD(a, b) of two positive integers a and b is equal to the biggest integer d such that both integers a and b are divisible by d. There are many efficient algorithms to find greatest common divisor GCD(a, b), for examp... | instruction | 0 | 74,606 | 22 | 149,212 |
Tags: math, number theory
Correct Solution:
```
a, b = [int(x) for x in input().split()]
print(1 if a != b else a)
``` | output | 1 | 74,606 | 22 | 149,213 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Greatest common divisor GCD(a, b) of two positive integers a and b is equal to the biggest integer d such that both integers a and b are divisible by d. There are many efficient algorithms to find greatest common divisor GCD(a, b), for examp... | instruction | 0 | 74,607 | 22 | 149,214 |
Tags: math, number theory
Correct Solution:
```
import math
n = input()
n = n.split()
s = eval(n[0])
n = eval(n[1])
if n == s:
print(n)
else:
print(1)
``` | output | 1 | 74,607 | 22 | 149,215 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Greatest common divisor GCD(a, b) of two positive integers a and b is equal to the biggest integer d such that both integers a and b are divisible by d. There are many efficient algorithms to find greatest common divisor GCD(a, b), for examp... | instruction | 0 | 74,608 | 22 | 149,216 |
Tags: math, number theory
Correct Solution:
```
m,g=map(int,input().split())
if m==g:
print(m)
else:
print("1")
``` | output | 1 | 74,608 | 22 | 149,217 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Greatest common divisor GCD(a, b) of two positive integers a and b is equal to the biggest integer d such that both integers a and b are divisible by d. There are many efficient algorithms to find greatest common divisor GCD(a, b), for examp... | instruction | 0 | 74,609 | 22 | 149,218 |
Tags: math, number theory
Correct Solution:
```
x,y=map(int,input().split())
print(x if x==y else 1)
``` | output | 1 | 74,609 | 22 | 149,219 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Greatest common divisor GCD(a, b) of two positive integers a and b is equal to the biggest integer d such that both integers a and b are divisible by d. There are many efficient algorithms to find greatest common divisor GCD(a, b), for examp... | instruction | 0 | 74,610 | 22 | 149,220 |
Tags: math, number theory
Correct Solution:
```
def my_gcd(x, y):
temp = x % y
if temp == 0:
return y
return my_gcd(y, temp)
m, n = map(int, input().split())
if m == n:
print(m)
else:
if m < n:
s = m
l = n
else:
s = n
l = m
gcd = 0
for i in rang... | output | 1 | 74,610 | 22 | 149,221 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Greatest common divisor GCD(a, b) of two positive integers a and b is equal to the biggest integer d such that both integers a and b are divisible by d. There are many efficient algorithms to find greatest common divisor GCD(a, b), for examp... | instruction | 0 | 74,611 | 22 | 149,222 |
Tags: math, number theory
Correct Solution:
```
#print("muri")
a, b = map(int, input().split())
if a==b:print(a)
else: print("1")
``` | output | 1 | 74,611 | 22 | 149,223 |
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