message stringlengths 2 57.2k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 61 108k | cluster float64 22 22 | __index_level_0__ int64 122 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
Mr. F has n positive integers, a_1, a_2, …, a_n.
He thinks the greatest common divisor of these integers is too small. So he wants to enlarge it by removing some of the integers.
But this problem is too simple for him, so he does not want ... | instruction | 0 | 81,727 | 22 | 163,454 |
Tags: number theory
Correct Solution:
```
import sys
input=sys.stdin.buffer.readline
from math import gcd
n=int(input())
a=list(map(int,input().split()))
ma=max(a)
p=[0]*(ma+1)
for i in range(2,ma+1):
if p[i]==0:
for j in range(i*i,ma+1,i):
p[j]=i
for i in range(1,ma+1):
if not p[i]:
p[i]=i
g=a[0]
for... | output | 1 | 81,727 | 22 | 163,455 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr. F has n positive integers, a_1, a_2, …, a_n.
He thinks the greatest common divisor of these integers is too small. So he wants to enlarge it by removing some of the integers.
But this prob... | instruction | 0 | 81,728 | 22 | 163,456 |
No | output | 1 | 81,728 | 22 | 163,457 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr. F has n positive integers, a_1, a_2, …, a_n.
He thinks the greatest common divisor of these integers is too small. So he wants to enlarge it by removing some of the integers.
But this prob... | instruction | 0 | 81,729 | 22 | 163,458 |
No | output | 1 | 81,729 | 22 | 163,459 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr. F has n positive integers, a_1, a_2, …, a_n.
He thinks the greatest common divisor of these integers is too small. So he wants to enlarge it by removing some of the integers.
But this prob... | instruction | 0 | 81,730 | 22 | 163,460 |
No | output | 1 | 81,730 | 22 | 163,461 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr. F has n positive integers, a_1, a_2, …, a_n.
He thinks the greatest common divisor of these integers is too small. So he wants to enlarge it by removing some of the integers.
But this prob... | instruction | 0 | 81,731 | 22 | 163,462 |
No | output | 1 | 81,731 | 22 | 163,463 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In Omkar's last class of math, he learned about the least common multiple, or LCM. LCM(a, b) is the smallest positive integer x which is divisible by both a and b.
Omkar, having a laudably curious mind, immediately thought of a problem invo... | instruction | 0 | 81,870 | 22 | 163,740 |
Tags: greedy, math, number theory
Correct Solution:
```
import math
def get_divisor(n):
res = []
x = 1
while n >= x*x:
if n % x == 0:
res.append(x)
if n != x*x:
res.append(n//x)
x += 1
return sorted(res)
t = int(input())
for _ in range(t):
n ... | output | 1 | 81,870 | 22 | 163,741 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In Omkar's last class of math, he learned about the least common multiple, or LCM. LCM(a, b) is the smallest positive integer x which is divisible by both a and b.
Omkar, having a laudably curious mind, immediately thought of a problem invo... | instruction | 0 | 81,871 | 22 | 163,742 |
Tags: greedy, math, number theory
Correct Solution:
```
for _ in range(int(input())):
n=int(input())
ans=int(n/2)
if n%2==0:
print(ans,ans)
else:
ans=1
for i in range(3,int(n**0.5)+1,2):
if n%i==0:
ans=i
break
if ans!=1:
... | output | 1 | 81,871 | 22 | 163,743 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In Omkar's last class of math, he learned about the least common multiple, or LCM. LCM(a, b) is the smallest positive integer x which is divisible by both a and b.
Omkar, having a laudably curious mind, immediately thought of a problem invo... | instruction | 0 | 81,872 | 22 | 163,744 |
Tags: greedy, math, number theory
Correct Solution:
```
from math import sqrt
def ans(a):
if a % 2 == 0:
print(a // 2, a // 2)
else:
for i in range(2, int(sqrt(a)+1)):
if a % (i) == 0:
print(a // i, a - (a // i))
return
print(1,a-1)
for _ in ra... | output | 1 | 81,872 | 22 | 163,745 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In Omkar's last class of math, he learned about the least common multiple, or LCM. LCM(a, b) is the smallest positive integer x which is divisible by both a and b.
Omkar, having a laudably curious mind, immediately thought of a problem invo... | instruction | 0 | 81,873 | 22 | 163,746 |
Tags: greedy, math, number theory
Correct Solution:
```
import math
t=int(input())
for _ in range(t):
n=int(input())
if n%2==0:
print(n//2,n//2)
continue
else:
i=1
lis=[]
while i <= math.sqrt(n):
if (n % i == 0) :
if (n / i == i) :
... | output | 1 | 81,873 | 22 | 163,747 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In Omkar's last class of math, he learned about the least common multiple, or LCM. LCM(a, b) is the smallest positive integer x which is divisible by both a and b.
Omkar, having a laudably curious mind, immediately thought of a problem invo... | instruction | 0 | 81,874 | 22 | 163,748 |
Tags: greedy, math, number theory
Correct Solution:
```
from math import sqrt,ceil
t=int(input())
for _ in range(t):
n=int(input())
if(n%2==0):
print(int(n/2),int(n/2))
elif(n%3==0):
print(int(n/3),int(2*n/3))
else:
a=ceil(sqrt(n))
while(n%a!=0 and a>1):
if(n%... | output | 1 | 81,874 | 22 | 163,749 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In Omkar's last class of math, he learned about the least common multiple, or LCM. LCM(a, b) is the smallest positive integer x which is divisible by both a and b.
Omkar, having a laudably curious mind, immediately thought of a problem invo... | instruction | 0 | 81,875 | 22 | 163,750 |
Tags: greedy, math, number theory
Correct Solution:
```
def ans(n):
x = n//2
if n%2 == 0:
return (str(x)+' '+str(x))
a = 1
for i in range(2, int(n**0.5)+1):
if n%i == 0:
a = i
break
if a == 1: return ('1 '+str(n-1))
p = n//a
q = n-p
return (s... | output | 1 | 81,875 | 22 | 163,751 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In Omkar's last class of math, he learned about the least common multiple, or LCM. LCM(a, b) is the smallest positive integer x which is divisible by both a and b.
Omkar, having a laudably curious mind, immediately thought of a problem invo... | instruction | 0 | 81,876 | 22 | 163,752 |
Tags: greedy, math, number theory
Correct Solution:
```
t = int(input())
while t != 0:
t -= 1
n = int(input())
i = 2
m = 1
while i * i <= n:
if n % i == 0:
print(n // i, n - n // i)
m = 0
break
else:
i += 1
if m == 1:
print(... | output | 1 | 81,876 | 22 | 163,753 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In Omkar's last class of math, he learned about the least common multiple, or LCM. LCM(a, b) is the smallest positive integer x which is divisible by both a and b.
Omkar, having a laudably curious mind, immediately thought of a problem invo... | instruction | 0 | 81,877 | 22 | 163,754 |
Tags: greedy, math, number theory
Correct Solution:
```
import time
def SieveOfEratosthenes(n):
# Create a boolean array "prime[0..n]" and
# initialize all entries it as true. A value
# in prime[i] will finally be false if i is
# Not a prime, else true.
prime = [True for i in range(n... | output | 1 | 81,877 | 22 | 163,755 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Omkar's last class of math, he learned about the least common multiple, or LCM. LCM(a, b) is the smallest positive integer x which is divisible by both a and b.
Omkar, having a laudably curi... | instruction | 0 | 81,878 | 22 | 163,756 |
Yes | output | 1 | 81,878 | 22 | 163,757 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Omkar's last class of math, he learned about the least common multiple, or LCM. LCM(a, b) is the smallest positive integer x which is divisible by both a and b.
Omkar, having a laudably curi... | instruction | 0 | 81,879 | 22 | 163,758 |
Yes | output | 1 | 81,879 | 22 | 163,759 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Omkar's last class of math, he learned about the least common multiple, or LCM. LCM(a, b) is the smallest positive integer x which is divisible by both a and b.
Omkar, having a laudably curi... | instruction | 0 | 81,880 | 22 | 163,760 |
Yes | output | 1 | 81,880 | 22 | 163,761 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Omkar's last class of math, he learned about the least common multiple, or LCM. LCM(a, b) is the smallest positive integer x which is divisible by both a and b.
Omkar, having a laudably curi... | instruction | 0 | 81,881 | 22 | 163,762 |
Yes | output | 1 | 81,881 | 22 | 163,763 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Omkar's last class of math, he learned about the least common multiple, or LCM. LCM(a, b) is the smallest positive integer x which is divisible by both a and b.
Omkar, having a laudably curi... | instruction | 0 | 81,882 | 22 | 163,764 |
No | output | 1 | 81,882 | 22 | 163,765 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Omkar's last class of math, he learned about the least common multiple, or LCM. LCM(a, b) is the smallest positive integer x which is divisible by both a and b.
Omkar, having a laudably curi... | instruction | 0 | 81,883 | 22 | 163,766 |
No | output | 1 | 81,883 | 22 | 163,767 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Omkar's last class of math, he learned about the least common multiple, or LCM. LCM(a, b) is the smallest positive integer x which is divisible by both a and b.
Omkar, having a laudably curi... | instruction | 0 | 81,884 | 22 | 163,768 |
No | output | 1 | 81,884 | 22 | 163,769 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Omkar's last class of math, he learned about the least common multiple, or LCM. LCM(a, b) is the smallest positive integer x which is divisible by both a and b.
Omkar, having a laudably curi... | instruction | 0 | 81,885 | 22 | 163,770 |
No | output | 1 | 81,885 | 22 | 163,771 |
Provide tags and a correct Python 3 solution for this coding contest problem.
DZY has a hash table with p buckets, numbered from 0 to p - 1. He wants to insert n numbers, in the order they are given, into the hash table. For the i-th number xi, DZY will put it into the bucket numbered h(xi), where h(x) is the hash fun... | instruction | 0 | 82,065 | 22 | 164,130 |
Tags: implementation
Correct Solution:
```
def solve():
p, n = map(int, input().split())
a = []
for _ in range(n):
a.append(int(input()))
myset = set()
for i in range(n):
x = a[i]
if x % p in myset:
return i + 1
else:
myset.add(x % p)
return -1
print(solve())
``` | output | 1 | 82,065 | 22 | 164,131 |
Provide tags and a correct Python 3 solution for this coding contest problem.
DZY has a hash table with p buckets, numbered from 0 to p - 1. He wants to insert n numbers, in the order they are given, into the hash table. For the i-th number xi, DZY will put it into the bucket numbered h(xi), where h(x) is the hash fun... | instruction | 0 | 82,070 | 22 | 164,140 |
Tags: implementation
Correct Solution:
```
pn = list(map(int, input().split()))
p = pn[0]
n = pn[1]
res = [0] * p
inp = []
flag = 0
for i in range(n):
inp.append(int(input()))
for i in range(len(inp)):
if res[inp[i] % p] == 0:
res[inp[i] % p] = 1
elif res[inp[i] % p] == 1:
flag = 1
b... | output | 1 | 82,070 | 22 | 164,141 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Some time ago Leonid have known about idempotent functions. Idempotent function defined on a set {1, 2, ..., n} is such function <image>, that for any <image> the formula g(g(x)) = g(x) holds.
Let's denote as f(k)(x) the function f applied ... | instruction | 0 | 82,129 | 22 | 164,258 |
Tags: constructive algorithms, graphs, math
Correct Solution:
```
from random import randint
from copy import deepcopy
n = int(input())
a = list(map(int, input().split()))
for i in range(n):
a[i] -= 1
def gen(n):
a = []
for i in range(n):
a.append(randint(0, n - 1))
return a
def stupid(a, v=F... | output | 1 | 82,129 | 22 | 164,259 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Some time ago Leonid have known about idempotent functions. Idempotent function defined on a set {1, 2, ..., n} is such function <image>, that for any <image> the formula g(g(x)) = g(x) holds.
Let's denote as f(k)(x) the function f applied ... | instruction | 0 | 82,130 | 22 | 164,260 |
Tags: constructive algorithms, graphs, math
Correct Solution:
```
n = int(input())
p = list(map(int, input().split()))
g = {}
deg = {}
first = []
circle = {}
ans = []
def push_d(deg, u, val):
if u not in deg:
deg[u] = 0
deg[u] += val
def push_g(g, u, v):
if u not in g:
g[u]... | output | 1 | 82,130 | 22 | 164,261 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Some time ago Leonid have known about idempotent functions. Idempotent function defined on a set {1, 2, ..., n} is such function <image>, that for any <image> the formula g(g(x)) = g(x) holds.
Let's denote as f(k)(x) the function f applied ... | instruction | 0 | 82,131 | 22 | 164,262 |
Tags: constructive algorithms, graphs, math
Correct Solution:
```
import math
def ciclos(arr, i):
d = {i:0}
cnt = 1
while True:
i = arr[i]-1
if i in d:
return d[i],cnt-d[i]
d[i] = cnt
cnt+=1
def mcm(a,b):
return (a*b//math.gcd(a,b))
n = int(input())
a = [int(x) for x in input().split()]
max_offs... | output | 1 | 82,131 | 22 | 164,263 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Some time ago Leonid have known about idempotent functions. Idempotent function defined on a set {1, 2, ..., n} is such function <image>, that for any <image> the formula g(g(x)) = g(x) holds.
Let's denote as f(k)(x) the function f applied ... | instruction | 0 | 82,132 | 22 | 164,264 |
Tags: constructive algorithms, graphs, math
Correct Solution:
```
import math
def ciclos(arr, i):
de = {i:0}
cnt = 1
while True:
i = arr[i]-1
if i in de:
return de[i],cnt-de[i]
de[i] = cnt
cnt+=1
def mcm(a,b):
return (a*b//math.gcd(a,b))
n = int(input())
a = [int(x) for x in input().split()]
max... | output | 1 | 82,132 | 22 | 164,265 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Some time ago Leonid have known about idempotent functions. Idempotent function defined on a set {1, 2, ..., n} is such function <image>, that for any <image> the formula g(g(x)) = g(x) holds.
Let's denote as f(k)(x) the function f applied ... | instruction | 0 | 82,133 | 22 | 164,266 |
Tags: constructive algorithms, graphs, math
Correct Solution:
```
def gcd(x, y):
if y == 0:
return x
return gcd(y, x % y)
n = int(input())
v = [(int(i) - 1) for i in input().split()]
b = [0] * n
r = 1
for i in range(n):
j, k = 1, v[i]
while j <= 2 * n + 10 and k != i:
k = v[k]
j ... | output | 1 | 82,133 | 22 | 164,267 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Some time ago Leonid have known about idempotent functions. Idempotent function defined on a set {1, 2, ..., n} is such function <image>, that for any <image> the formula g(g(x)) = g(x) holds.
Let's denote as f(k)(x) the function f applied ... | instruction | 0 | 82,134 | 22 | 164,268 |
Tags: constructive algorithms, graphs, math
Correct Solution:
```
import sys
import fractions
n = int(input())
refs = [0] * n
used = [0] * n
to = [int(x)-1 for x in input().split(' ')]
for i in to:
refs[i] += 1
times = []
max_a = 0
depth = [-1] * n
def dfs(u, d, depth):
if depth[u] != -1:
loop = d - d... | output | 1 | 82,134 | 22 | 164,269 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Some time ago Leonid have known about idempotent functions. Idempotent function defined on a set {1, 2, ..., n} is such function <image>, that for any <image> the formula g(g(x)) = g(x) holds.
Let's denote as f(k)(x) the function f applied ... | instruction | 0 | 82,135 | 22 | 164,270 |
Tags: constructive algorithms, graphs, math
Correct Solution:
```
from math import *
from random import *
from copy import *
import os
import sys
import fractions
n = int(input())
A = [0] + list(map(int, input().split()))
X, Y = 0, 1
for i in range(1, n + 1):
cnt = [-1] * (n + 1)
now = i
x = 0
while ... | output | 1 | 82,135 | 22 | 164,271 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Some time ago Leonid have known about idempotent functions. Idempotent function defined on a set {1, 2, ..., n} is such function <image>, that for any <image> the formula g(g(x)) = g(x) holds.
Let's denote as f(k)(x) the function f applied ... | instruction | 0 | 82,136 | 22 | 164,272 |
Tags: constructive algorithms, graphs, math
Correct Solution:
```
n = int(input())
f = list(map(int, input().split()))
def proov(res):
for i in range(len(f)):
if res[i] != res[res[i]]:
return False
return True
for i in range(len(f)):
f[i] -= 1
def gcd(a, b):
while b != 0:
... | output | 1 | 82,136 | 22 | 164,273 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little Johnny has recently learned about set theory. Now he is studying binary relations. You've probably heard the term "equivalence relation". These relations are very important in many areas of mathematics. For example, the equality of th... | instruction | 0 | 82,145 | 22 | 164,290 |
Tags: combinatorics, dp, math
Correct Solution:
```
def main():
mod = 10 ** 9 + 7
n = int(input())
a = [[0] * (n + 1) for i in range(n + 1)]
a[0][0] = 1
for i in range(1, n + 1):
a[i][0] = a[i - 1][i - 1]
for j in range(1, i + 1):
a[i][j] = (a[i][j - 1] + a[i - 1][j - 1])... | output | 1 | 82,145 | 22 | 164,291 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The following problem is well-known: given integers n and m, calculate
<image>,
where 2n = 2·2·...·2 (n factors), and <image> denotes the remainder of division of x by y.
You are asked to solve the "reverse" problem. Given integers n and... | instruction | 0 | 82,299 | 22 | 164,598 |
Tags: implementation, math
Correct Solution:
```
import math
n = int(input())
m = int(input())
if n <= 32 :
print(int(m%math.pow(2,n)))
else :
print(m)
``` | output | 1 | 82,299 | 22 | 164,599 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The following problem is well-known: given integers n and m, calculate
<image>,
where 2n = 2·2·...·2 (n factors), and <image> denotes the remainder of division of x by y.
You are asked to solve the "reverse" problem. Given integers n and... | instruction | 0 | 82,300 | 22 | 164,600 |
Tags: implementation, math
Correct Solution:
```
n=int(input())
print(int(input())%(2**min(n,40)))
``` | output | 1 | 82,300 | 22 | 164,601 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The following problem is well-known: given integers n and m, calculate
<image>,
where 2n = 2·2·...·2 (n factors), and <image> denotes the remainder of division of x by y.
You are asked to solve the "reverse" problem. Given integers n and... | instruction | 0 | 82,301 | 22 | 164,602 |
Tags: implementation, math
Correct Solution:
```
a = int(input())
b = int(input())
if a >= 32:
print(b)
else:
print(b % (2 ** a))
``` | output | 1 | 82,301 | 22 | 164,603 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The following problem is well-known: given integers n and m, calculate
<image>,
where 2n = 2·2·...·2 (n factors), and <image> denotes the remainder of division of x by y.
You are asked to solve the "reverse" problem. Given integers n and... | instruction | 0 | 82,302 | 22 | 164,604 |
Tags: implementation, math
Correct Solution:
```
import sys
def main():
input = sys.stdin.readline
n = int(input())
m = int(input())
print(m % (1 << n))
main()
``` | output | 1 | 82,302 | 22 | 164,605 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The following problem is well-known: given integers n and m, calculate
<image>,
where 2n = 2·2·...·2 (n factors), and <image> denotes the remainder of division of x by y.
You are asked to solve the "reverse" problem. Given integers n and... | instruction | 0 | 82,303 | 22 | 164,606 |
Tags: implementation, math
Correct Solution:
```
import math
n=int(input())
m=int(input())
if n>=27 :
print(m)
else :
print(m%(pow(2,n)))
``` | output | 1 | 82,303 | 22 | 164,607 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The following problem is well-known: given integers n and m, calculate
<image>,
where 2n = 2·2·...·2 (n factors), and <image> denotes the remainder of division of x by y.
You are asked to solve the "reverse" problem. Given integers n and... | instruction | 0 | 82,304 | 22 | 164,608 |
Tags: implementation, math
Correct Solution:
```
n = int(input())
m = int(input())
if n > 300:
print(m)
else:
x = m % 2**n
print(x)
``` | output | 1 | 82,304 | 22 | 164,609 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The following problem is well-known: given integers n and m, calculate
<image>,
where 2n = 2·2·...·2 (n factors), and <image> denotes the remainder of division of x by y.
You are asked to solve the "reverse" problem. Given integers n and... | instruction | 0 | 82,305 | 22 | 164,610 |
Tags: implementation, math
Correct Solution:
```
# Modular Expo
import sys
import math
import collections
from pprint import pprint as pp
mod = 1000000007
MAX = 10**10
def vector(size, val=0):
vec = [val for i in range(size)]
return vec
def matrix(rowNum, colNum, val=0):
mat = []
for i in range(rowN... | output | 1 | 82,305 | 22 | 164,611 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The following problem is well-known: given integers n and m, calculate
<image>,
where 2n = 2·2·...·2 (n factors), and <image> denotes the remainder of division of x by y.
You are asked to solve the "reverse" problem. Given integers n and... | instruction | 0 | 82,306 | 22 | 164,612 |
Tags: implementation, math
Correct Solution:
```
x = int(input())
y = int(input())
if x < 27:
print(y % (2 ** x))
else:
print(y)
``` | output | 1 | 82,306 | 22 | 164,613 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The following problem is well-known: given integers n and m, calculate
<image>,
where 2n = 2·2·...·2 (n factors), and <image> denotes the remainder of division of x by y.
You are asked to so... | instruction | 0 | 82,307 | 22 | 164,614 |
Yes | output | 1 | 82,307 | 22 | 164,615 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The following problem is well-known: given integers n and m, calculate
<image>,
where 2n = 2·2·...·2 (n factors), and <image> denotes the remainder of division of x by y.
You are asked to so... | instruction | 0 | 82,308 | 22 | 164,616 |
Yes | output | 1 | 82,308 | 22 | 164,617 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The following problem is well-known: given integers n and m, calculate
<image>,
where 2n = 2·2·...·2 (n factors), and <image> denotes the remainder of division of x by y.
You are asked to so... | instruction | 0 | 82,309 | 22 | 164,618 |
Yes | output | 1 | 82,309 | 22 | 164,619 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The following problem is well-known: given integers n and m, calculate
<image>,
where 2n = 2·2·...·2 (n factors), and <image> denotes the remainder of division of x by y.
You are asked to so... | instruction | 0 | 82,310 | 22 | 164,620 |
Yes | output | 1 | 82,310 | 22 | 164,621 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The following problem is well-known: given integers n and m, calculate
<image>,
where 2n = 2·2·...·2 (n factors), and <image> denotes the remainder of division of x by y.
You are asked to so... | instruction | 0 | 82,311 | 22 | 164,622 |
No | output | 1 | 82,311 | 22 | 164,623 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The following problem is well-known: given integers n and m, calculate
<image>,
where 2n = 2·2·...·2 (n factors), and <image> denotes the remainder of division of x by y.
You are asked to so... | instruction | 0 | 82,312 | 22 | 164,624 |
No | output | 1 | 82,312 | 22 | 164,625 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The following problem is well-known: given integers n and m, calculate
<image>,
where 2n = 2·2·...·2 (n factors), and <image> denotes the remainder of division of x by y.
You are asked to so... | instruction | 0 | 82,313 | 22 | 164,626 |
No | output | 1 | 82,313 | 22 | 164,627 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The following problem is well-known: given integers n and m, calculate
<image>,
where 2n = 2·2·...·2 (n factors), and <image> denotes the remainder of division of x by y.
You are asked to so... | instruction | 0 | 82,314 | 22 | 164,628 |
No | output | 1 | 82,314 | 22 | 164,629 |
Provide a correct Python 3 solution for this coding contest problem.
You are given four integers A, B, C, and D. Find the number of integers between A and B (inclusive) that can be evenly divided by neither C nor D.
Constraints
* 1\leq A\leq B\leq 10^{18}
* 1\leq C,D\leq 10^9
* All values in input are integers.
Inp... | instruction | 0 | 82,395 | 22 | 164,790 |
"Correct Solution:
```
a,b,c,d = map(int,input().split())
import fractions
a = a-1
e = c*d // fractions.gcd(c,d)
cnt = b//c + b//d + a//e - a//c - a//d - b//e
print(b-a-cnt)
``` | output | 1 | 82,395 | 22 | 164,791 |
Provide a correct Python 3 solution for this coding contest problem.
You are given four integers A, B, C, and D. Find the number of integers between A and B (inclusive) that can be evenly divided by neither C nor D.
Constraints
* 1\leq A\leq B\leq 10^{18}
* 1\leq C,D\leq 10^9
* All values in input are integers.
Inp... | instruction | 0 | 82,396 | 22 | 164,792 |
"Correct Solution:
```
import fractions
a, b, c, d=map(int, input().split())
k=fractions.gcd(c, d)
lcm=c*d//k
x=b//c - (a-1)//c
y=b//d - (a-1)//d
z=b//lcm - (a-1)//lcm
print(b-a+1-(x+y-z))
``` | output | 1 | 82,396 | 22 | 164,793 |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.