message stringlengths 2 57.2k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 61 108k | cluster float64 22 22 | __index_level_0__ int64 122 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You're given Q queries of the form (L, R).
For each query you have to find the number of such x that L ≤ x ≤ R and there exist integer numbers a > 0, p > 1 such that x = ap.
Input
The first ... | instruction | 0 | 94,126 | 22 | 188,252 |
No | output | 1 | 94,126 | 22 | 188,253 |
Provide a correct Python 3 solution for this coding contest problem.
Given are a sequence A= {a_1,a_2,......a_N} of N positive even numbers, and an integer M.
Let a semi-common multiple of A be a positive integer X that satisfies the following condition for every k (1 \leq k \leq N):
* There exists a non-negative in... | instruction | 0 | 94,163 | 22 | 188,326 |
"Correct Solution:
```
from fractions import gcd
N, M = map(int, input().split())
A = list(map(int, input().split()))
a = A[0]
n = 1
while a % 2 == 0:
n *= 2
a //= 2
lcm = 1
for a in A:
if a % n != 0 or a % (2 * n) == 0:
print(0)
exit()
lcm = lcm * a // gcd(lcm, a)
if lcm // 2 > M... | output | 1 | 94,163 | 22 | 188,327 |
Provide a correct Python 3 solution for this coding contest problem.
Given are a sequence A= {a_1,a_2,......a_N} of N positive even numbers, and an integer M.
Let a semi-common multiple of A be a positive integer X that satisfies the following condition for every k (1 \leq k \leq N):
* There exists a non-negative in... | instruction | 0 | 94,164 | 22 | 188,328 |
"Correct Solution:
```
from fractions import gcd
from functools import reduce
N, M, *A = map(int, open(0).read().split())
Y = reduce(lambda a, b: a * b // gcd(a, b), A)
print(M // (Y // 2) - (M // Y) if all((Y // a) % 2 for a in A) else 0)
``` | output | 1 | 94,164 | 22 | 188,329 |
Provide a correct Python 3 solution for this coding contest problem.
Given are a sequence A= {a_1,a_2,......a_N} of N positive even numbers, and an integer M.
Let a semi-common multiple of A be a positive integer X that satisfies the following condition for every k (1 \leq k \leq N):
* There exists a non-negative in... | instruction | 0 | 94,165 | 22 | 188,330 |
"Correct Solution:
```
from fractions import gcd
n, m = map(int, input().split())
a = list(map(int, input().split()))
l = 1
num = a[0]
bin = 1
while num % 2 == 0:
bin *= 2
num //= 2
for num in a:
l = (l * num // 2) // gcd(l, num // 2)
if num % bin != 0 or num % (bin * 2) == 0:
print(0)
... | output | 1 | 94,165 | 22 | 188,331 |
Provide a correct Python 3 solution for this coding contest problem.
Given are a sequence A= {a_1,a_2,......a_N} of N positive even numbers, and an integer M.
Let a semi-common multiple of A be a positive integer X that satisfies the following condition for every k (1 \leq k \leq N):
* There exists a non-negative in... | instruction | 0 | 94,166 | 22 | 188,332 |
"Correct Solution:
```
from math import gcd
N, M = map(int, input().split())
A = list(map(int, input().split()))
A = [i // 2 for i in A]
lcd = 1
for a in A:
lcd *= a // gcd(lcd, a)
for a in A:
if lcd // a % 2 == 0:
print(0)
exit()
print((M//lcd+1)//2)
``` | output | 1 | 94,166 | 22 | 188,333 |
Provide a correct Python 3 solution for this coding contest problem.
Given are a sequence A= {a_1,a_2,......a_N} of N positive even numbers, and an integer M.
Let a semi-common multiple of A be a positive integer X that satisfies the following condition for every k (1 \leq k \leq N):
* There exists a non-negative in... | instruction | 0 | 94,167 | 22 | 188,334 |
"Correct Solution:
```
from fractions import gcd
n, m = map(int, input().split())
a = list(map(int, input().split()))
b = [a[i]//2 for i in range(n)]
lcm_a = 1
for i in range(n):
lcm_a = (lcm_a * b[i]) // gcd(lcm_a, b[i])
for i in range(n):
if (lcm_a//b[i]) % 2 == 0:
print(0)
exit()
if m < lcm_... | output | 1 | 94,167 | 22 | 188,335 |
Provide a correct Python 3 solution for this coding contest problem.
Given are a sequence A= {a_1,a_2,......a_N} of N positive even numbers, and an integer M.
Let a semi-common multiple of A be a positive integer X that satisfies the following condition for every k (1 \leq k \leq N):
* There exists a non-negative in... | instruction | 0 | 94,168 | 22 | 188,336 |
"Correct Solution:
```
N,M = map(int,input().split())
A = list(map(int,input().split()))
s = set()
B = []
for a in A:
t = a & -a
s.add(t)
if len(s) > 1:
print(0)
exit()
B.append(a // t)
from fractions import gcd
l = 1
for b in B:
l = b*l // gcd(b,l)
x = l*t // 2
ans = M//x - M//(2*... | output | 1 | 94,168 | 22 | 188,337 |
Provide a correct Python 3 solution for this coding contest problem.
Given are a sequence A= {a_1,a_2,......a_N} of N positive even numbers, and an integer M.
Let a semi-common multiple of A be a positive integer X that satisfies the following condition for every k (1 \leq k \leq N):
* There exists a non-negative in... | instruction | 0 | 94,169 | 22 | 188,338 |
"Correct Solution:
```
import sys
def gcd(x,y):
while y:
x,y = y , x % y
return x
n,m=map(int,input().split())
a=tuple(map(int,input().split()))
lcm = 1
for i in a:
lcm = lcm * i // gcd(lcm,i)
for i in a:
if (lcm//i)%2 == 0:
print(0)
sys.exit()
print((m+lcm//2)//lcm)
``` | output | 1 | 94,169 | 22 | 188,339 |
Provide a correct Python 3 solution for this coding contest problem.
Given are a sequence A= {a_1,a_2,......a_N} of N positive even numbers, and an integer M.
Let a semi-common multiple of A be a positive integer X that satisfies the following condition for every k (1 \leq k \leq N):
* There exists a non-negative in... | instruction | 0 | 94,170 | 22 | 188,340 |
"Correct Solution:
```
N, M = map(int, input().split())
A = list(set(map(lambda x : int(x)//2, input().split())))
def gcd(x, y):
return x if y == 0 else gcd(y, x % y)
def lcm(x, y):
return (x * y) // gcd(x, y)
l = A[0]
for a in A[1:]:
l = lcm(l, a)
ans = (M // l + 1) // 2
for a in A[1:]:
if (l // a) % 2 == 0:
... | output | 1 | 94,170 | 22 | 188,341 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are a sequence A= {a_1,a_2,......a_N} of N positive even numbers, and an integer M.
Let a semi-common multiple of A be a positive integer X that satisfies the following condition for ever... | instruction | 0 | 94,171 | 22 | 188,342 |
Yes | output | 1 | 94,171 | 22 | 188,343 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are a sequence A= {a_1,a_2,......a_N} of N positive even numbers, and an integer M.
Let a semi-common multiple of A be a positive integer X that satisfies the following condition for ever... | instruction | 0 | 94,172 | 22 | 188,344 |
Yes | output | 1 | 94,172 | 22 | 188,345 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are a sequence A= {a_1,a_2,......a_N} of N positive even numbers, and an integer M.
Let a semi-common multiple of A be a positive integer X that satisfies the following condition for ever... | instruction | 0 | 94,173 | 22 | 188,346 |
Yes | output | 1 | 94,173 | 22 | 188,347 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are a sequence A= {a_1,a_2,......a_N} of N positive even numbers, and an integer M.
Let a semi-common multiple of A be a positive integer X that satisfies the following condition for ever... | instruction | 0 | 94,174 | 22 | 188,348 |
Yes | output | 1 | 94,174 | 22 | 188,349 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are a sequence A= {a_1,a_2,......a_N} of N positive even numbers, and an integer M.
Let a semi-common multiple of A be a positive integer X that satisfies the following condition for ever... | instruction | 0 | 94,176 | 22 | 188,352 |
No | output | 1 | 94,176 | 22 | 188,353 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are a sequence A= {a_1,a_2,......a_N} of N positive even numbers, and an integer M.
Let a semi-common multiple of A be a positive integer X that satisfies the following condition for ever... | instruction | 0 | 94,177 | 22 | 188,354 |
No | output | 1 | 94,177 | 22 | 188,355 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are a sequence A= {a_1,a_2,......a_N} of N positive even numbers, and an integer M.
Let a semi-common multiple of A be a positive integer X that satisfies the following condition for ever... | instruction | 0 | 94,178 | 22 | 188,356 |
No | output | 1 | 94,178 | 22 | 188,357 |
Provide a correct Python 3 solution for this coding contest problem.
Given are a prime number p and a sequence of p integers a_0, \ldots, a_{p-1} consisting of zeros and ones.
Find a polynomial of degree at most p-1, f(x) = b_{p-1} x^{p-1} + b_{p-2} x^{p-2} + \ldots + b_0, satisfying the following conditions:
* For ... | instruction | 0 | 94,179 | 22 | 188,358 |
"Correct Solution:
```
p = int(input())
a = list(map(int, input().split()))
MAX = 3000
fact = [1]*(MAX+1)
for i in range(1, MAX+1):
fact[i] = (fact[i-1]*i) % p
inv = [1]*(MAX+1)
for i in range(2, MAX+1):
inv[i] = inv[p % i]*(p-p//i) % p
fact_inv = [1]*(MAX+1)
for i in range(1, MAX+1):
fact_inv[i] = fact_... | output | 1 | 94,179 | 22 | 188,359 |
Provide a correct Python 3 solution for this coding contest problem.
Given are a prime number p and a sequence of p integers a_0, \ldots, a_{p-1} consisting of zeros and ones.
Find a polynomial of degree at most p-1, f(x) = b_{p-1} x^{p-1} + b_{p-2} x^{p-2} + \ldots + b_0, satisfying the following conditions:
* For ... | instruction | 0 | 94,180 | 22 | 188,360 |
"Correct Solution:
```
class Combi():
def __init__(self, N, mod):
self.power = [1 for _ in range(N+1)]
self.rev = [1 for _ in range(N+1)]
self.mod = mod
for i in range(2, N+1):
self.power[i] = (self.power[i-1]*i) % self.mod
self.rev[N] = pow(self.power[N], self.mo... | output | 1 | 94,180 | 22 | 188,361 |
Provide a correct Python 3 solution for this coding contest problem.
Given are a prime number p and a sequence of p integers a_0, \ldots, a_{p-1} consisting of zeros and ones.
Find a polynomial of degree at most p-1, f(x) = b_{p-1} x^{p-1} + b_{p-2} x^{p-2} + \ldots + b_0, satisfying the following conditions:
* For ... | instruction | 0 | 94,181 | 22 | 188,362 |
"Correct Solution:
```
p = int(input())
mod = p
def frac(limit):
frac = [1]*limit
for i in range(2,limit):
frac[i] = i * frac[i-1]%mod
fraci = [None]*limit
fraci[-1] = pow(frac[-1], mod -2, mod)
for i in range(-2, -limit-1, -1):
fraci[i] = fraci[i+1] * (limit + i + 1) % mod
ret... | output | 1 | 94,181 | 22 | 188,363 |
Provide a correct Python 3 solution for this coding contest problem.
Given are a prime number p and a sequence of p integers a_0, \ldots, a_{p-1} consisting of zeros and ones.
Find a polynomial of degree at most p-1, f(x) = b_{p-1} x^{p-1} + b_{p-2} x^{p-2} + \ldots + b_0, satisfying the following conditions:
* For ... | instruction | 0 | 94,182 | 22 | 188,364 |
"Correct Solution:
```
import sys
stdin = sys.stdin
ni = lambda: int(ns())
na = lambda: list(map(int, stdin.readline().split()))
ns = lambda: stdin.readline().rstrip() # ignore trailing spaces
def inv(a, mod):
b = mod
p = 1; q = 0
while b > 0:
c = a // b
a, b = b, a%b
p, q = q, p... | output | 1 | 94,182 | 22 | 188,365 |
Provide a correct Python 3 solution for this coding contest problem.
Given are a prime number p and a sequence of p integers a_0, \ldots, a_{p-1} consisting of zeros and ones.
Find a polynomial of degree at most p-1, f(x) = b_{p-1} x^{p-1} + b_{p-2} x^{p-2} + \ldots + b_0, satisfying the following conditions:
* For ... | instruction | 0 | 94,183 | 22 | 188,366 |
"Correct Solution:
```
def f_polynomal_construction(P, A):
class Combination(object):
"""参考: https://harigami.net/contents?id=5f169f85-5707-4137-87a5-f0068749d9bb"""
__slots__ = ["mod", "factorial", "inverse"]
def __init__(self, max_n: int = 10**6, mod: int = 10**9 + 7):
fac, in... | output | 1 | 94,183 | 22 | 188,367 |
Provide a correct Python 3 solution for this coding contest problem.
Given are a prime number p and a sequence of p integers a_0, \ldots, a_{p-1} consisting of zeros and ones.
Find a polynomial of degree at most p-1, f(x) = b_{p-1} x^{p-1} + b_{p-2} x^{p-2} + \ldots + b_0, satisfying the following conditions:
* For ... | instruction | 0 | 94,184 | 22 | 188,368 |
"Correct Solution:
```
p = int(input())
a = list(map(int, input().split()))
MOD = p
MAX = p + 10
fact = [1] * (MAX + 1) # i!
finv = [1] * (MAX + 1) # (i!)^{-1}
iinv = [1] * (MAX + 1) # i^{-1}
for i in range(2, MAX + 1):
fact[i] = fact[i - 1] * i % MOD
iinv[i] = MOD - iinv[MOD % i] * (MOD // i) % MOD
fin... | output | 1 | 94,184 | 22 | 188,369 |
Provide a correct Python 3 solution for this coding contest problem.
Given are a prime number p and a sequence of p integers a_0, \ldots, a_{p-1} consisting of zeros and ones.
Find a polynomial of degree at most p-1, f(x) = b_{p-1} x^{p-1} + b_{p-2} x^{p-2} + \ldots + b_0, satisfying the following conditions:
* For ... | instruction | 0 | 94,186 | 22 | 188,372 |
"Correct Solution:
```
import os
import sys
if os.getenv("LOCAL"):
sys.stdin = open("_in.txt", "r")
sys.setrecursionlimit(10 ** 9)
INF = float("inf")
IINF = 10 ** 18
MOD = 10 ** 9 + 7
# MOD = 998244353
def get_factorials(max, mod=None):
"""
階乗 0!, 1!, 2!, ..., max!
:param int max:
:param int m... | output | 1 | 94,186 | 22 | 188,373 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Dreamoon loves summing up something for no reason. One day he obtains two integers a and b occasionally. He wants to calculate the sum of all nice integers. Positive integer x is called nice if <image> and <image>, where k is some integer nu... | instruction | 0 | 94,768 | 22 | 189,536 |
Tags: math
Correct Solution:
```
a,b=map(int, input().split())
m=1000000007
B = int((b*(b-1)/2) % m );
A1 = int((a*(a+1)/2) % m );
A = int((A1*b+a) % m );
res = int((A*B) % m) ;
print(res)
``` | output | 1 | 94,768 | 22 | 189,537 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Dreamoon loves summing up something for no reason. One day he obtains two integers a and b occasionally. He wants to calculate the sum of all nice integers. Positive integer x is called nice if <image> and <image>, where k is some integer nu... | instruction | 0 | 94,769 | 22 | 189,538 |
Tags: math
Correct Solution:
```
a,b = map(int,input().split())
MOD = 1000000007
x = a*(a + 1)
x = x // 2
x = x % MOD
x = (x * b) % MOD
x = (x + a) % MOD
x = ((x*b*(b - 1)) // 2) % MOD
print(x)
``` | output | 1 | 94,769 | 22 | 189,539 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Dreamoon loves summing up something for no reason. One day he obtains two integers a and b occasionally. He wants to calculate the sum of all nice integers. Positive integer x is called nice if <image> and <image>, where k is some integer nu... | instruction | 0 | 94,770 | 22 | 189,540 |
Tags: math
Correct Solution:
```
a,b=map(int,input().split())
h=1000000007
c=((a*(b*b-b))//2)%h;
d=((a*a+a)//2)%h;
e=((b*b*b-b*b)//2)%h;
print((c+(d*e)%h)%h)
``` | output | 1 | 94,770 | 22 | 189,541 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Dreamoon loves summing up something for no reason. One day he obtains two integers a and b occasionally. He wants to calculate the sum of all nice integers. Positive integer x is called nice if <image> and <image>, where k is some integer nu... | instruction | 0 | 94,771 | 22 | 189,542 |
Tags: math
Correct Solution:
```
# -*- coding: utf-8 -*-
"""
Created on Wed Jul 7 23:26:09 2021
@author: Kevin Chang
Project: Codeforces Problem 476C
"""
a, b = list(map(int, input().split()))
modu = 10**9+7
res = (b*(b-1)//2)*((b*a*(a+1)//2)+a)%modu
print(res)
``` | output | 1 | 94,771 | 22 | 189,543 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Dreamoon loves summing up something for no reason. One day he obtains two integers a and b occasionally. He wants to calculate the sum of all nice integers. Positive integer x is called nice if <image> and <image>, where k is some integer nu... | instruction | 0 | 94,772 | 22 | 189,544 |
Tags: math
Correct Solution:
```
mod =10**9+7
a,b = map(int,input().split())
t1 = (b*(b-1)//2)%mod
t2 = (a*(a+1)//2)%mod
t3= (t2*b)%mod +a
ans = (t1 * t3)%mod
print(ans)
``` | output | 1 | 94,772 | 22 | 189,545 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Dreamoon loves summing up something for no reason. One day he obtains two integers a and b occasionally. He wants to calculate the sum of all nice integers. Positive integer x is called nice if <image> and <image>, where k is some integer nu... | instruction | 0 | 94,773 | 22 | 189,546 |
Tags: math
Correct Solution:
```
a,b = list(map(int,input().split()))
if b ==1 :
print(0)
else :
res = a + b*a*(a+1)//2
res = (res*(b)*(b-1)//2)
print(res%(10**9 +7))
``` | output | 1 | 94,773 | 22 | 189,547 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Dreamoon loves summing up something for no reason. One day he obtains two integers a and b occasionally. He wants to calculate the sum of all nice integers. Positive integer x is called nice if <image> and <image>, where k is some integer nu... | instruction | 0 | 94,774 | 22 | 189,548 |
Tags: math
Correct Solution:
```
a = input()
a = a.split()
a,b = int(a[0]),int(a[1])
k2 = b*(b-1)*a // 2
k = (b-1)*b//2 * b* (1+a)*a // 2
res = (k + k2) % 1000000007
print(res)
``` | output | 1 | 94,774 | 22 | 189,549 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Dreamoon loves summing up something for no reason. One day he obtains two integers a and b occasionally. He wants to calculate the sum of all nice integers. Positive integer x is called nice if <image> and <image>, where k is some integer nu... | instruction | 0 | 94,775 | 22 | 189,550 |
Tags: math
Correct Solution:
```
import sys
import math
MAXNUM = math.inf
MINNUM = -1 * math.inf
ASCIILOWER = 97
ASCIIUPPER = 65
MODMAX = 1000000007
def getInt():
return int(sys.stdin.readline().rstrip())
def getInts():
return map(int, sys.stdin.readline().rstrip().split(" "))
def getString():
return... | output | 1 | 94,775 | 22 | 189,551 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dreamoon loves summing up something for no reason. One day he obtains two integers a and b occasionally. He wants to calculate the sum of all nice integers. Positive integer x is called nice if ... | instruction | 0 | 94,776 | 22 | 189,552 |
Yes | output | 1 | 94,776 | 22 | 189,553 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dreamoon loves summing up something for no reason. One day he obtains two integers a and b occasionally. He wants to calculate the sum of all nice integers. Positive integer x is called nice if ... | instruction | 0 | 94,777 | 22 | 189,554 |
Yes | output | 1 | 94,777 | 22 | 189,555 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dreamoon loves summing up something for no reason. One day he obtains two integers a and b occasionally. He wants to calculate the sum of all nice integers. Positive integer x is called nice if ... | instruction | 0 | 94,778 | 22 | 189,556 |
Yes | output | 1 | 94,778 | 22 | 189,557 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dreamoon loves summing up something for no reason. One day he obtains two integers a and b occasionally. He wants to calculate the sum of all nice integers. Positive integer x is called nice if ... | instruction | 0 | 94,779 | 22 | 189,558 |
Yes | output | 1 | 94,779 | 22 | 189,559 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dreamoon loves summing up something for no reason. One day he obtains two integers a and b occasionally. He wants to calculate the sum of all nice integers. Positive integer x is called nice if ... | instruction | 0 | 94,782 | 22 | 189,564 |
No | output | 1 | 94,782 | 22 | 189,565 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dreamoon loves summing up something for no reason. One day he obtains two integers a and b occasionally. He wants to calculate the sum of all nice integers. Positive integer x is called nice if ... | instruction | 0 | 94,783 | 22 | 189,566 |
No | output | 1 | 94,783 | 22 | 189,567 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Well, here is another math class task. In mathematics, GCD is the greatest common divisor, and it's an easy task to calculate the GCD between two positive integers.
A common divisor for two positive numbers is a number which both numbers ar... | instruction | 0 | 94,898 | 22 | 189,796 |
Tags: binary search, number theory
Correct Solution:
```
import math
from sys import stdout
def print_fast(string):
stdout.write(string + '\n')
def MGCD(_gcd, low, high):
answer = -1
botton = low
index = min(_gcd, high)
while index >= botton:
if _gcd % index == 0:
return inde... | output | 1 | 94,898 | 22 | 189,797 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Well, here is another math class task. In mathematics, GCD is the greatest common divisor, and it's an easy task to calculate the GCD between two positive integers.
A common divisor for two positive numbers is a number which both numbers ar... | instruction | 0 | 94,899 | 22 | 189,798 |
Tags: binary search, number theory
Correct Solution:
```
from math import gcd
a,b = list(map(int, input().split()))
cd = gcd(a,b)
ar =[]
for i in range(1,int(cd**0.5)+1):
if cd % i == 0:
ar.append(i)
if(i*i != cd):
ar.append(cd//i)
for _ in range(int(input())):
l,h = list(map(int,... | output | 1 | 94,899 | 22 | 189,799 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Well, here is another math class task. In mathematics, GCD is the greatest common divisor, and it's an easy task to calculate the GCD between two positive integers.
A common divisor for two positive numbers is a number which both numbers ar... | instruction | 0 | 94,900 | 22 | 189,800 |
Tags: binary search, number theory
Correct Solution:
```
n,m = [int(i) for i in input().split()]
l = []
for i in range(1,int(n**0.5)+1):
if n%i == 0 and m%i == 0:
l.append(i)
if n%(n//i) == 0 and m%(n//i) == 0:
l.append(n//i)
l.sort()
n = int(input())
for i in range(n):
q,w = [int(j) for j in input().split()]
m... | output | 1 | 94,900 | 22 | 189,801 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Well, here is another math class task. In mathematics, GCD is the greatest common divisor, and it's an easy task to calculate the GCD between two positive integers.
A common divisor for two positive numbers is a number which both numbers ar... | instruction | 0 | 94,901 | 22 | 189,802 |
Tags: binary search, number theory
Correct Solution:
```
import math,bisect
a,b=map(int,input().split())
gcd=math.gcd(a,b)
arr=[i for i in range(1,int(math.sqrt(gcd))+1) if gcd%i==0]
for i in arr[::-1]:arr.append(gcd//i)
for _ in range(int(input())):
l,h=map(int,input().split())
idx=bisect.bisect(arr,h)-1
... | output | 1 | 94,901 | 22 | 189,803 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Well, here is another math class task. In mathematics, GCD is the greatest common divisor, and it's an easy task to calculate the GCD between two positive integers.
A common divisor for two positive numbers is a number which both numbers ar... | instruction | 0 | 94,902 | 22 | 189,804 |
Tags: binary search, number theory
Correct Solution:
```
def make_divisors(n):
divisors = []
for i in range(1, int(n**0.5)+1):
if n % i == 0:
divisors.append(i)
if i != n // i:
divisors.append(n//i)
divisors.sort()
return divisors
a, b = map(int, input()... | output | 1 | 94,902 | 22 | 189,805 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Well, here is another math class task. In mathematics, GCD is the greatest common divisor, and it's an easy task to calculate the GCD between two positive integers.
A common divisor for two positive numbers is a number which both numbers ar... | instruction | 0 | 94,903 | 22 | 189,806 |
Tags: binary search, number theory
Correct Solution:
```
from functools import reduce
import io,os,sys,math
def binarySearchkeeb(data,target,low,high):
if low > high:
return high
else:
mid=(low+high)//2
if data[mid] <=target:
return binarySearchkeeb(data,target,mid+1,high)
... | output | 1 | 94,903 | 22 | 189,807 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Well, here is another math class task. In mathematics, GCD is the greatest common divisor, and it's an easy task to calculate the GCD between two positive integers.
A common divisor for two positive numbers is a number which both numbers ar... | instruction | 0 | 94,904 | 22 | 189,808 |
Tags: binary search, number theory
Correct Solution:
```
# import sys
# sys.stdin = open("input.in","r")
from sys import stdin
input = stdin.readline
from heapq import heapify,heappush,heappop,heappushpop
from collections import defaultdict as dd, deque as dq,Counter as C
from math import factorial as f ,ceil,gcd,sqrt... | output | 1 | 94,904 | 22 | 189,809 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Well, here is another math class task. In mathematics, GCD is the greatest common divisor, and it's an easy task to calculate the GCD between two positive integers.
A common divisor for two positive numbers is a number which both numbers ar... | instruction | 0 | 94,905 | 22 | 189,810 |
Tags: binary search, number theory
Correct Solution:
```
from math import gcd
from bisect import bisect
a,b=map(int,input().split())
d=gcd(a,b)
c=int(d**0.5)
m=[]
for i in range(1,c+1):
if d%i==0:
m.append(i)
m.append(d//i)
m.sort()
n=int(input())
for i in range(n):
c,d=map(int,input().split()... | output | 1 | 94,905 | 22 | 189,811 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Well, here is another math class task. In mathematics, GCD is the greatest common divisor, and it's an easy task to calculate the GCD between two positive integers.
A common divisor for two pos... | instruction | 0 | 94,906 | 22 | 189,812 |
Yes | output | 1 | 94,906 | 22 | 189,813 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Well, here is another math class task. In mathematics, GCD is the greatest common divisor, and it's an easy task to calculate the GCD between two positive integers.
A common divisor for two pos... | instruction | 0 | 94,907 | 22 | 189,814 |
Yes | output | 1 | 94,907 | 22 | 189,815 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Well, here is another math class task. In mathematics, GCD is the greatest common divisor, and it's an easy task to calculate the GCD between two positive integers.
A common divisor for two pos... | instruction | 0 | 94,908 | 22 | 189,816 |
Yes | output | 1 | 94,908 | 22 | 189,817 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Well, here is another math class task. In mathematics, GCD is the greatest common divisor, and it's an easy task to calculate the GCD between two positive integers.
A common divisor for two pos... | instruction | 0 | 94,909 | 22 | 189,818 |
Yes | output | 1 | 94,909 | 22 | 189,819 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Well, here is another math class task. In mathematics, GCD is the greatest common divisor, and it's an easy task to calculate the GCD between two positive integers.
A common divisor for two pos... | instruction | 0 | 94,910 | 22 | 189,820 |
No | output | 1 | 94,910 | 22 | 189,821 |
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