message stringlengths 2 44.5k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 276 109k | cluster float64 23 23 | __index_level_0__ int64 552 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a grid with (2^N - 1) rows and (2^M-1) columns. You are asked to write 0 or 1 in each of these squares. Let a_{i,j} be the number written in the square at the i-th row from the top and the j-th column from the left.
For a quadruple of integers (i_1, i_2, j_1, j_2) such that 1\leq i_1 \leq i_2\leq 2^N-1, 1\leq j_1 \leq j_2\leq 2^M-1, let S(i_1, i_2, j_1, j_2) = \displaystyle \sum_{r=i_1}^{i_2}\sum_{c=j_1}^{j_2}a_{r,c}. Then, let the oddness of the grid be the number of quadruples (i_1, i_2, j_1, j_2) such that S(i_1, i_2, j_1, j_2) is odd.
Find a way to fill in the grid that maximizes its oddness.
Constraints
* N and M are integers between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
N M
Output
Print numbers to write in the grid so that its oddness is maximized, in the following format:
a_{1,1}a_{1,2}\cdots a_{1,2^M-1}
a_{2,1}a_{2,2}\cdots a_{2,2^M-1}
\vdots
a_{2^N-1,1}a_{2^N-1,2}\cdots a_{2^N-1,2^M-1}
If there are multiple solutions, you can print any of them.
Example
Input
1 2
Output
111
Submitted Solution:
```
def main():
N, M = (int(i) for i in input().split())
A = [[1 for j in range(2**M-1)] for i in range(2**N-1)]
for i in range(N//2 + N, 2**N-1, N):
for j in range(M//2 + M, 2**M-1, M):
A[i][j] = 0
for i in range(2**N-1):
for j in range(2**M-1):
print(A[i][j], end="")
print()
if __name__ == '__main__':
main()
``` | instruction | 0 | 26,258 | 23 | 52,516 |
No | output | 1 | 26,258 | 23 | 52,517 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a grid with (2^N - 1) rows and (2^M-1) columns. You are asked to write 0 or 1 in each of these squares. Let a_{i,j} be the number written in the square at the i-th row from the top and the j-th column from the left.
For a quadruple of integers (i_1, i_2, j_1, j_2) such that 1\leq i_1 \leq i_2\leq 2^N-1, 1\leq j_1 \leq j_2\leq 2^M-1, let S(i_1, i_2, j_1, j_2) = \displaystyle \sum_{r=i_1}^{i_2}\sum_{c=j_1}^{j_2}a_{r,c}. Then, let the oddness of the grid be the number of quadruples (i_1, i_2, j_1, j_2) such that S(i_1, i_2, j_1, j_2) is odd.
Find a way to fill in the grid that maximizes its oddness.
Constraints
* N and M are integers between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
N M
Output
Print numbers to write in the grid so that its oddness is maximized, in the following format:
a_{1,1}a_{1,2}\cdots a_{1,2^M-1}
a_{2,1}a_{2,2}\cdots a_{2,2^M-1}
\vdots
a_{2^N-1,1}a_{2^N-1,2}\cdots a_{2^N-1,2^M-1}
If there are multiple solutions, you can print any of them.
Example
Input
1 2
Output
111
Submitted Solution:
```
N, M = (int(i) for i in input().split())
for i in range(2**N - 1):
if i % 2 == 0:
print("".join(["1"] * (2**M - 1)))
else:
print("".join([str((j + 1) % 2) for j in range(2**M - 1)]))
``` | instruction | 0 | 26,259 | 23 | 52,518 |
No | output | 1 | 26,259 | 23 | 52,519 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a grid with (2^N - 1) rows and (2^M-1) columns. You are asked to write 0 or 1 in each of these squares. Let a_{i,j} be the number written in the square at the i-th row from the top and the j-th column from the left.
For a quadruple of integers (i_1, i_2, j_1, j_2) such that 1\leq i_1 \leq i_2\leq 2^N-1, 1\leq j_1 \leq j_2\leq 2^M-1, let S(i_1, i_2, j_1, j_2) = \displaystyle \sum_{r=i_1}^{i_2}\sum_{c=j_1}^{j_2}a_{r,c}. Then, let the oddness of the grid be the number of quadruples (i_1, i_2, j_1, j_2) such that S(i_1, i_2, j_1, j_2) is odd.
Find a way to fill in the grid that maximizes its oddness.
Constraints
* N and M are integers between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
N M
Output
Print numbers to write in the grid so that its oddness is maximized, in the following format:
a_{1,1}a_{1,2}\cdots a_{1,2^M-1}
a_{2,1}a_{2,2}\cdots a_{2,2^M-1}
\vdots
a_{2^N-1,1}a_{2^N-1,2}\cdots a_{2^N-1,2^M-1}
If there are multiple solutions, you can print any of them.
Example
Input
1 2
Output
111
Submitted Solution:
```
def examA():
S = SI()
if len(S)%2==1:
print("No")
return
for i in range(len(S)//2):
if S[i*2:i*2+2]!="hi":
print("No")
return
print("Yes")
return
def examB():
a, b, M = LI()
A = LI()
B = LI()
D = [LI()for _ in range(M)]
ans = min(A) + min(B)
for x,y,c in D:
cur = A[x-1]+B[y-1]-c
ans = min(ans,cur)
print(ans)
return
def examC():
def bfs(n, e, fordfs):
# 点の数、スタートの点、有向グラフ
W = [-1] * n
# 各点の状態量、最短距離とか,見たかどうかとか
W[e] = 0
que = deque()
que.append(e)
while que:
now = que.popleft()
nowW = W[now]
for ne in fordfs[now]:
if W[ne] == -1:
W[ne] = nowW + 1
que.append(ne)
return W
N = I()
V = [[]for _ in range(N)]
for _ in range(N-1):
a, b = LI()
a -= 1
b -= 1
V[a].append(b)
V[b].append(a)
L = bfs(N,0,V)
#print(L)
odd = 0
for l in L:
if l==-1:
print(-1)
return
if l%2==1:
odd += 1
G = []
if odd*2<N:
for i in range(N):
if L[i]%2==1:
G.append(i)
else:
for i in range(N):
if L[i]%2==0:
G.append(i)
used = [False]*(N+1)
ans = [0]*N
if N//3>=len(G):
cur = 3
for g in G:
ans[g] = cur
used[cur] = True
cur += 3
cur = 1
for i in range(N):
if ans[i]!=0:
continue
while(used[cur]):
cur += 1
ans[i] = cur
used[cur] = True
else:
cur = 1
for g in G:
ans[g] = cur
used[cur] = True
cur += 3
if cur>N:
cur = 3
cur = 1
for i in range(N):
if ans[i]!=0:
continue
while(used[cur]):
cur += 1
ans[i] = cur
used[cur] = True
print(" ".join(map(str,ans)))
return
def examD():
N, T = LI()
ans = 0
print(ans)
return
def examE():
N, M = LI()
H = 2**N-1; W = 2**M -1
ans = [[0]*W for _ in range(H)]
for h in range(H):
for w in range(W):
if (h%2)==(w%2):
ans[h][w] = 1
for v in ans:
print("".join(map(str,v)))
return
def examF():
ans = 0
print(ans)
return
import sys,bisect,itertools,heapq,math,random
from copy import deepcopy
from heapq import heappop,heappush,heapify
from collections import Counter,defaultdict,deque
def I(): return int(sys.stdin.readline())
def LI(): return list(map(int,sys.stdin.readline().split()))
def LSI(): return list(map(str,sys.stdin.readline().split()))
def LS(): return sys.stdin.readline().split()
def SI(): return sys.stdin.readline().strip()
global mod,mod2,inf,alphabet,_ep
mod = 10**9 + 7
mod2 = 998244353
inf = 10**18
_ep = 10**(-12)
alphabet = [chr(ord('a') + i) for i in range(26)]
sys.setrecursionlimit(10**6)
if __name__ == '__main__':
examE()
"""
"""
``` | instruction | 0 | 26,260 | 23 | 52,520 |
No | output | 1 | 26,260 | 23 | 52,521 |
Provide a correct Python 3 solution for this coding contest problem.
Problem Statement
We can describe detailed direction by repeating the directional names: north, south, east and west. For example, northwest is the direction halfway between north and west, and northnorthwest is between north and northwest.
In this problem, we describe more detailed direction between north and west as follows.
* "north" means $0$ degrees.
* "west" means $90$ degrees.
* If the direction $dir$ means $a$ degrees and the sum of the occurrences of "north" and "west" in $dir$ is $n$ ($\geq$ 1), "north"$dir$ (the concatenation of "north" and $dir$) means $a - \frac{90}{2^n}$ degrees and "west"$dir$ means $a + \frac{90}{2^n}$ degrees.
Your task is to calculate the angle in degrees described by the given direction.
* * *
Input
The input contains several datasets. The number of datasets does not exceed $100$.
Each dataset is described by a single line that contains a string denoting a direction. You may assume the given string can be obtained by concatenating some "north" and "west", the sum of the occurrences of "north" and "west" in the given string is between $1$ and $20$, inclusive, and the angle denoted by the given direction is between $0$ and $90$, inclusive. The final dataset is followed by a single line containing only a single "#".
Output
For each dataset, print an integer if the angle described by the given direction can be represented as an integer, otherwise print it as an irreducible fraction. Follow the format of the sample output.
* * *
Sample Input
north
west
northwest
northnorthwest
westwestwestnorth
Output for the Sample Input
0
90
45
45/2
315/4
Example
Input
north
west
northwest
northnorthwest
westwestwestnorth
#
Output
0
90
45
45/2
315/4 | instruction | 0 | 26,475 | 23 | 52,950 |
"Correct Solution:
```
from fractions import Fraction
while True:
s = input()
if s == '#':
break
if s[-4:] == 'west':
ans = Fraction(90)
s = s[:-4]
else:
ans = Fraction(0)
s = s[:-5]
i = 1
while s:
if s[-4:] == 'west':
ans += Fraction(90, 1 << i)
s = s[:-4]
else:
ans -= Fraction(90, 1 << i)
s = s[:-5]
i += 1
print(ans)
``` | output | 1 | 26,475 | 23 | 52,951 |
Provide a correct Python 3 solution for this coding contest problem.
Problem Statement
We can describe detailed direction by repeating the directional names: north, south, east and west. For example, northwest is the direction halfway between north and west, and northnorthwest is between north and northwest.
In this problem, we describe more detailed direction between north and west as follows.
* "north" means $0$ degrees.
* "west" means $90$ degrees.
* If the direction $dir$ means $a$ degrees and the sum of the occurrences of "north" and "west" in $dir$ is $n$ ($\geq$ 1), "north"$dir$ (the concatenation of "north" and $dir$) means $a - \frac{90}{2^n}$ degrees and "west"$dir$ means $a + \frac{90}{2^n}$ degrees.
Your task is to calculate the angle in degrees described by the given direction.
* * *
Input
The input contains several datasets. The number of datasets does not exceed $100$.
Each dataset is described by a single line that contains a string denoting a direction. You may assume the given string can be obtained by concatenating some "north" and "west", the sum of the occurrences of "north" and "west" in the given string is between $1$ and $20$, inclusive, and the angle denoted by the given direction is between $0$ and $90$, inclusive. The final dataset is followed by a single line containing only a single "#".
Output
For each dataset, print an integer if the angle described by the given direction can be represented as an integer, otherwise print it as an irreducible fraction. Follow the format of the sample output.
* * *
Sample Input
north
west
northwest
northnorthwest
westwestwestnorth
Output for the Sample Input
0
90
45
45/2
315/4
Example
Input
north
west
northwest
northnorthwest
westwestwestnorth
#
Output
0
90
45
45/2
315/4 | instruction | 0 | 26,476 | 23 | 52,952 |
"Correct Solution:
```
#!/usr/bin/env python
# -*- coding: utf-8 -*-
while True:
direction = ''.join(reversed(input()))
if direction == '#':
break
count = 0
ans = 0
while direction != '':
if direction[0] == 'h':
if count == 0:
ans = 0
else:
ans = ans * 2 - 90
direction = direction[len('north'):]
else:
if count == 0:
ans = 90
else:
ans = ans * 2 + 90
direction = direction[len('west'):]
count += 1
while ans % 2 == 0 and count > 1:
ans //= 2
count -= 1
if count <= 1:
print(ans)
else:
print(str(ans)+'/'+str(2**(count-1)))
``` | output | 1 | 26,476 | 23 | 52,953 |
Provide a correct Python 3 solution for this coding contest problem.
Problem Statement
We can describe detailed direction by repeating the directional names: north, south, east and west. For example, northwest is the direction halfway between north and west, and northnorthwest is between north and northwest.
In this problem, we describe more detailed direction between north and west as follows.
* "north" means $0$ degrees.
* "west" means $90$ degrees.
* If the direction $dir$ means $a$ degrees and the sum of the occurrences of "north" and "west" in $dir$ is $n$ ($\geq$ 1), "north"$dir$ (the concatenation of "north" and $dir$) means $a - \frac{90}{2^n}$ degrees and "west"$dir$ means $a + \frac{90}{2^n}$ degrees.
Your task is to calculate the angle in degrees described by the given direction.
* * *
Input
The input contains several datasets. The number of datasets does not exceed $100$.
Each dataset is described by a single line that contains a string denoting a direction. You may assume the given string can be obtained by concatenating some "north" and "west", the sum of the occurrences of "north" and "west" in the given string is between $1$ and $20$, inclusive, and the angle denoted by the given direction is between $0$ and $90$, inclusive. The final dataset is followed by a single line containing only a single "#".
Output
For each dataset, print an integer if the angle described by the given direction can be represented as an integer, otherwise print it as an irreducible fraction. Follow the format of the sample output.
* * *
Sample Input
north
west
northwest
northnorthwest
westwestwestnorth
Output for the Sample Input
0
90
45
45/2
315/4
Example
Input
north
west
northwest
northnorthwest
westwestwestnorth
#
Output
0
90
45
45/2
315/4 | instruction | 0 | 26,477 | 23 | 52,954 |
"Correct Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 998244353
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)
def main():
rr = []
def f(a):
if len(a) == 1:
if a[0] == 'n':
return 0
return 90
t = f(a[1:])
if a[0] == 'n':
return t - 90 / (2**(len(a)-1))
return t + 90 / (2**(len(a)-1))
while True:
s = S()
if s == '#':
break
a = []
while len(s) > 0:
if s[:5] == 'north':
a.append('n')
s = s[5:]
else:
a.append('w')
s = s[4:]
t = f(a)
b = 2**(len(a))
a = int(t*b)
g = fractions.gcd(a,b)
a //= g
b //= g
if b > 1:
rr.append('{}/{}'.format(a,b))
else:
rr.append(a)
return '\n'.join(map(str, rr))
print(main())
``` | output | 1 | 26,477 | 23 | 52,955 |
Provide a correct Python 3 solution for this coding contest problem.
Problem Statement
We can describe detailed direction by repeating the directional names: north, south, east and west. For example, northwest is the direction halfway between north and west, and northnorthwest is between north and northwest.
In this problem, we describe more detailed direction between north and west as follows.
* "north" means $0$ degrees.
* "west" means $90$ degrees.
* If the direction $dir$ means $a$ degrees and the sum of the occurrences of "north" and "west" in $dir$ is $n$ ($\geq$ 1), "north"$dir$ (the concatenation of "north" and $dir$) means $a - \frac{90}{2^n}$ degrees and "west"$dir$ means $a + \frac{90}{2^n}$ degrees.
Your task is to calculate the angle in degrees described by the given direction.
* * *
Input
The input contains several datasets. The number of datasets does not exceed $100$.
Each dataset is described by a single line that contains a string denoting a direction. You may assume the given string can be obtained by concatenating some "north" and "west", the sum of the occurrences of "north" and "west" in the given string is between $1$ and $20$, inclusive, and the angle denoted by the given direction is between $0$ and $90$, inclusive. The final dataset is followed by a single line containing only a single "#".
Output
For each dataset, print an integer if the angle described by the given direction can be represented as an integer, otherwise print it as an irreducible fraction. Follow the format of the sample output.
* * *
Sample Input
north
west
northwest
northnorthwest
westwestwestnorth
Output for the Sample Input
0
90
45
45/2
315/4
Example
Input
north
west
northwest
northnorthwest
westwestwestnorth
#
Output
0
90
45
45/2
315/4 | instruction | 0 | 26,478 | 23 | 52,956 |
"Correct Solution:
```
from fractions import *
while True:
s=input()[::-1]
if s=='#':break
if s[0]=='h':
angle=Fraction(0)
cnt=5
else:
angle=Fraction(90)
cnt=4
i=1
while cnt<len(s):
if s[cnt]=='h':
angle-=Fraction(90/2**i)
cnt+=5
else:
angle+=Fraction(90/2**i)
cnt+=4
i+=1
print(angle)
``` | output | 1 | 26,478 | 23 | 52,957 |
Provide a correct Python 3 solution for this coding contest problem.
Problem Statement
We can describe detailed direction by repeating the directional names: north, south, east and west. For example, northwest is the direction halfway between north and west, and northnorthwest is between north and northwest.
In this problem, we describe more detailed direction between north and west as follows.
* "north" means $0$ degrees.
* "west" means $90$ degrees.
* If the direction $dir$ means $a$ degrees and the sum of the occurrences of "north" and "west" in $dir$ is $n$ ($\geq$ 1), "north"$dir$ (the concatenation of "north" and $dir$) means $a - \frac{90}{2^n}$ degrees and "west"$dir$ means $a + \frac{90}{2^n}$ degrees.
Your task is to calculate the angle in degrees described by the given direction.
* * *
Input
The input contains several datasets. The number of datasets does not exceed $100$.
Each dataset is described by a single line that contains a string denoting a direction. You may assume the given string can be obtained by concatenating some "north" and "west", the sum of the occurrences of "north" and "west" in the given string is between $1$ and $20$, inclusive, and the angle denoted by the given direction is between $0$ and $90$, inclusive. The final dataset is followed by a single line containing only a single "#".
Output
For each dataset, print an integer if the angle described by the given direction can be represented as an integer, otherwise print it as an irreducible fraction. Follow the format of the sample output.
* * *
Sample Input
north
west
northwest
northnorthwest
westwestwestnorth
Output for the Sample Input
0
90
45
45/2
315/4
Example
Input
north
west
northwest
northnorthwest
westwestwestnorth
#
Output
0
90
45
45/2
315/4 | instruction | 0 | 26,479 | 23 | 52,958 |
"Correct Solution:
```
import re
while 1:
s=input()
if s=='#':break
s=re.split('[w|n]',s)[1:];c=1
d=90 if s[-1]=='est' else 0
for x in s[:-1][::-1]:
d*=2
d+=90if x=='est'else-90
c*=2
while d&1==0 and c&1==0:d//=2;c//=2
if c==1:print(d)
else:print(d,c,sep='/')
``` | output | 1 | 26,479 | 23 | 52,959 |
Provide a correct Python 3 solution for this coding contest problem.
Problem Statement
We can describe detailed direction by repeating the directional names: north, south, east and west. For example, northwest is the direction halfway between north and west, and northnorthwest is between north and northwest.
In this problem, we describe more detailed direction between north and west as follows.
* "north" means $0$ degrees.
* "west" means $90$ degrees.
* If the direction $dir$ means $a$ degrees and the sum of the occurrences of "north" and "west" in $dir$ is $n$ ($\geq$ 1), "north"$dir$ (the concatenation of "north" and $dir$) means $a - \frac{90}{2^n}$ degrees and "west"$dir$ means $a + \frac{90}{2^n}$ degrees.
Your task is to calculate the angle in degrees described by the given direction.
* * *
Input
The input contains several datasets. The number of datasets does not exceed $100$.
Each dataset is described by a single line that contains a string denoting a direction. You may assume the given string can be obtained by concatenating some "north" and "west", the sum of the occurrences of "north" and "west" in the given string is between $1$ and $20$, inclusive, and the angle denoted by the given direction is between $0$ and $90$, inclusive. The final dataset is followed by a single line containing only a single "#".
Output
For each dataset, print an integer if the angle described by the given direction can be represented as an integer, otherwise print it as an irreducible fraction. Follow the format of the sample output.
* * *
Sample Input
north
west
northwest
northnorthwest
westwestwestnorth
Output for the Sample Input
0
90
45
45/2
315/4
Example
Input
north
west
northwest
northnorthwest
westwestwestnorth
#
Output
0
90
45
45/2
315/4 | instruction | 0 | 26,480 | 23 | 52,960 |
"Correct Solution:
```
from fractions import Fraction
while True:
s=input()
if s=="#": break
s="".join([c for c in s if c=='n' or c=='w'])
x=0 if s[-1]=='n' else 90
for i in range(len(s)-1):
if s[-2-i]=='n':
x-=Fraction(45,1<<i)
else:
x+=Fraction(45,1<<i)
print(x)
``` | output | 1 | 26,480 | 23 | 52,961 |
Provide a correct Python 3 solution for this coding contest problem.
Problem Statement
We can describe detailed direction by repeating the directional names: north, south, east and west. For example, northwest is the direction halfway between north and west, and northnorthwest is between north and northwest.
In this problem, we describe more detailed direction between north and west as follows.
* "north" means $0$ degrees.
* "west" means $90$ degrees.
* If the direction $dir$ means $a$ degrees and the sum of the occurrences of "north" and "west" in $dir$ is $n$ ($\geq$ 1), "north"$dir$ (the concatenation of "north" and $dir$) means $a - \frac{90}{2^n}$ degrees and "west"$dir$ means $a + \frac{90}{2^n}$ degrees.
Your task is to calculate the angle in degrees described by the given direction.
* * *
Input
The input contains several datasets. The number of datasets does not exceed $100$.
Each dataset is described by a single line that contains a string denoting a direction. You may assume the given string can be obtained by concatenating some "north" and "west", the sum of the occurrences of "north" and "west" in the given string is between $1$ and $20$, inclusive, and the angle denoted by the given direction is between $0$ and $90$, inclusive. The final dataset is followed by a single line containing only a single "#".
Output
For each dataset, print an integer if the angle described by the given direction can be represented as an integer, otherwise print it as an irreducible fraction. Follow the format of the sample output.
* * *
Sample Input
north
west
northwest
northnorthwest
westwestwestnorth
Output for the Sample Input
0
90
45
45/2
315/4
Example
Input
north
west
northwest
northnorthwest
westwestwestnorth
#
Output
0
90
45
45/2
315/4 | instruction | 0 | 26,481 | 23 | 52,962 |
"Correct Solution:
```
from fractions import Fraction
while True:
s = input()
if s == '#':
break
N = len(s)
if s[-1] == 't':
ans = Fraction(90)
p = 4
else:
ans = Fraction(0)
p = 5
i = 1
while p < N:
if s[-1-p] == 't':
ans += Fraction(90, 1 << i)
p += 4
else:
ans -= Fraction(90, 1 << i)
p += 5
i += 1
print(ans)
``` | output | 1 | 26,481 | 23 | 52,963 |
Provide a correct Python 3 solution for this coding contest problem.
Problem Statement
We can describe detailed direction by repeating the directional names: north, south, east and west. For example, northwest is the direction halfway between north and west, and northnorthwest is between north and northwest.
In this problem, we describe more detailed direction between north and west as follows.
* "north" means $0$ degrees.
* "west" means $90$ degrees.
* If the direction $dir$ means $a$ degrees and the sum of the occurrences of "north" and "west" in $dir$ is $n$ ($\geq$ 1), "north"$dir$ (the concatenation of "north" and $dir$) means $a - \frac{90}{2^n}$ degrees and "west"$dir$ means $a + \frac{90}{2^n}$ degrees.
Your task is to calculate the angle in degrees described by the given direction.
* * *
Input
The input contains several datasets. The number of datasets does not exceed $100$.
Each dataset is described by a single line that contains a string denoting a direction. You may assume the given string can be obtained by concatenating some "north" and "west", the sum of the occurrences of "north" and "west" in the given string is between $1$ and $20$, inclusive, and the angle denoted by the given direction is between $0$ and $90$, inclusive. The final dataset is followed by a single line containing only a single "#".
Output
For each dataset, print an integer if the angle described by the given direction can be represented as an integer, otherwise print it as an irreducible fraction. Follow the format of the sample output.
* * *
Sample Input
north
west
northwest
northnorthwest
westwestwestnorth
Output for the Sample Input
0
90
45
45/2
315/4
Example
Input
north
west
northwest
northnorthwest
westwestwestnorth
#
Output
0
90
45
45/2
315/4 | instruction | 0 | 26,482 | 23 | 52,964 |
"Correct Solution:
```
from math import gcd
while True:
s = str(input())
if s == "#":
break
li = list()
while s:
if s[:5] == "north":
li.append(-1)
s = s[5:]
else:
li.append(1)
s = s[4:]
ans = li[-1] * 45 + 45
li = li[:-1]
mot = 1
for d in reversed(li):
ans = ans * 2 + d * 90
mot *= 2
g = gcd(ans, mot)
ans, mot = ans // g, mot // g
if mot == 1:
print(ans)
else:
print("{0}/{1}".format(ans, mot))
``` | output | 1 | 26,482 | 23 | 52,965 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Problem Statement
We can describe detailed direction by repeating the directional names: north, south, east and west. For example, northwest is the direction halfway between north and west, and northnorthwest is between north and northwest.
In this problem, we describe more detailed direction between north and west as follows.
* "north" means $0$ degrees.
* "west" means $90$ degrees.
* If the direction $dir$ means $a$ degrees and the sum of the occurrences of "north" and "west" in $dir$ is $n$ ($\geq$ 1), "north"$dir$ (the concatenation of "north" and $dir$) means $a - \frac{90}{2^n}$ degrees and "west"$dir$ means $a + \frac{90}{2^n}$ degrees.
Your task is to calculate the angle in degrees described by the given direction.
* * *
Input
The input contains several datasets. The number of datasets does not exceed $100$.
Each dataset is described by a single line that contains a string denoting a direction. You may assume the given string can be obtained by concatenating some "north" and "west", the sum of the occurrences of "north" and "west" in the given string is between $1$ and $20$, inclusive, and the angle denoted by the given direction is between $0$ and $90$, inclusive. The final dataset is followed by a single line containing only a single "#".
Output
For each dataset, print an integer if the angle described by the given direction can be represented as an integer, otherwise print it as an irreducible fraction. Follow the format of the sample output.
* * *
Sample Input
north
west
northwest
northnorthwest
westwestwestnorth
Output for the Sample Input
0
90
45
45/2
315/4
Example
Input
north
west
northwest
northnorthwest
westwestwestnorth
#
Output
0
90
45
45/2
315/4
Submitted Solution:
```
from fractions import Fraction
def calc(s):
n = ans = 0
while len(s) >= 4:
if s[-4] == 'w':
s = s[:-4]
if n == 0:
ans = Fraction(90,1)
else:
ans += Fraction(90, 2**n)
else:
s = s[:-5]
if n == 0:
ans = Fraction(0,1)
else:
ans -= Fraction(90, 2**n)
n += 1
return ans
while True:
S = input()
if S == '#': break
print(calc(S))
``` | instruction | 0 | 26,483 | 23 | 52,966 |
Yes | output | 1 | 26,483 | 23 | 52,967 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Problem Statement
We can describe detailed direction by repeating the directional names: north, south, east and west. For example, northwest is the direction halfway between north and west, and northnorthwest is between north and northwest.
In this problem, we describe more detailed direction between north and west as follows.
* "north" means $0$ degrees.
* "west" means $90$ degrees.
* If the direction $dir$ means $a$ degrees and the sum of the occurrences of "north" and "west" in $dir$ is $n$ ($\geq$ 1), "north"$dir$ (the concatenation of "north" and $dir$) means $a - \frac{90}{2^n}$ degrees and "west"$dir$ means $a + \frac{90}{2^n}$ degrees.
Your task is to calculate the angle in degrees described by the given direction.
* * *
Input
The input contains several datasets. The number of datasets does not exceed $100$.
Each dataset is described by a single line that contains a string denoting a direction. You may assume the given string can be obtained by concatenating some "north" and "west", the sum of the occurrences of "north" and "west" in the given string is between $1$ and $20$, inclusive, and the angle denoted by the given direction is between $0$ and $90$, inclusive. The final dataset is followed by a single line containing only a single "#".
Output
For each dataset, print an integer if the angle described by the given direction can be represented as an integer, otherwise print it as an irreducible fraction. Follow the format of the sample output.
* * *
Sample Input
north
west
northwest
northnorthwest
westwestwestnorth
Output for the Sample Input
0
90
45
45/2
315/4
Example
Input
north
west
northwest
northnorthwest
westwestwestnorth
#
Output
0
90
45
45/2
315/4
Submitted Solution:
```
from fractions import Fraction
def rec(s):
if s[0] == 'n':
if len(s) > 5:
t = rec(s[5:])
return [(t[0] - 45) * 2, t[1] + 1]
else:
return [0, 0]
else:
if len(s) > 4:
t = rec(s[4:])
return [(t[0] + 45) * 2, t[1] + 1]
else:
return [90, 0]
while True:
s = input()
if s == "#":
break
[n, d] = rec(s)
d = 2 ** d
ans = Fraction(n, d)
print(ans)
``` | instruction | 0 | 26,484 | 23 | 52,968 |
Yes | output | 1 | 26,484 | 23 | 52,969 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Problem Statement
We can describe detailed direction by repeating the directional names: north, south, east and west. For example, northwest is the direction halfway between north and west, and northnorthwest is between north and northwest.
In this problem, we describe more detailed direction between north and west as follows.
* "north" means $0$ degrees.
* "west" means $90$ degrees.
* If the direction $dir$ means $a$ degrees and the sum of the occurrences of "north" and "west" in $dir$ is $n$ ($\geq$ 1), "north"$dir$ (the concatenation of "north" and $dir$) means $a - \frac{90}{2^n}$ degrees and "west"$dir$ means $a + \frac{90}{2^n}$ degrees.
Your task is to calculate the angle in degrees described by the given direction.
* * *
Input
The input contains several datasets. The number of datasets does not exceed $100$.
Each dataset is described by a single line that contains a string denoting a direction. You may assume the given string can be obtained by concatenating some "north" and "west", the sum of the occurrences of "north" and "west" in the given string is between $1$ and $20$, inclusive, and the angle denoted by the given direction is between $0$ and $90$, inclusive. The final dataset is followed by a single line containing only a single "#".
Output
For each dataset, print an integer if the angle described by the given direction can be represented as an integer, otherwise print it as an irreducible fraction. Follow the format of the sample output.
* * *
Sample Input
north
west
northwest
northnorthwest
westwestwestnorth
Output for the Sample Input
0
90
45
45/2
315/4
Example
Input
north
west
northwest
northnorthwest
westwestwestnorth
#
Output
0
90
45
45/2
315/4
Submitted Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 998244353
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)
def main():
rr = []
while True:
s = S()
if s == '#':
break
a = 0
i = 0
b = 1
while len(s) > 0:
if s[:5] == 'north':
s = s[5:]
if a > 0:
a -= 90 / b
else:
s = s[4:]
if a < 90:
a += 90 / b
b *= 2
a *= b
g = fractions.gcd(a,b)
a = int(a//g)
b = int(b//g)
if b > 1:
rr.append('{}/{}'.format(a,b))
else:
rr.append(a)
return '\n'.join(map(str, rr))
print(main())
``` | instruction | 0 | 26,485 | 23 | 52,970 |
No | output | 1 | 26,485 | 23 | 52,971 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Problem Statement
We can describe detailed direction by repeating the directional names: north, south, east and west. For example, northwest is the direction halfway between north and west, and northnorthwest is between north and northwest.
In this problem, we describe more detailed direction between north and west as follows.
* "north" means $0$ degrees.
* "west" means $90$ degrees.
* If the direction $dir$ means $a$ degrees and the sum of the occurrences of "north" and "west" in $dir$ is $n$ ($\geq$ 1), "north"$dir$ (the concatenation of "north" and $dir$) means $a - \frac{90}{2^n}$ degrees and "west"$dir$ means $a + \frac{90}{2^n}$ degrees.
Your task is to calculate the angle in degrees described by the given direction.
* * *
Input
The input contains several datasets. The number of datasets does not exceed $100$.
Each dataset is described by a single line that contains a string denoting a direction. You may assume the given string can be obtained by concatenating some "north" and "west", the sum of the occurrences of "north" and "west" in the given string is between $1$ and $20$, inclusive, and the angle denoted by the given direction is between $0$ and $90$, inclusive. The final dataset is followed by a single line containing only a single "#".
Output
For each dataset, print an integer if the angle described by the given direction can be represented as an integer, otherwise print it as an irreducible fraction. Follow the format of the sample output.
* * *
Sample Input
north
west
northwest
northnorthwest
westwestwestnorth
Output for the Sample Input
0
90
45
45/2
315/4
Example
Input
north
west
northwest
northnorthwest
westwestwestnorth
#
Output
0
90
45
45/2
315/4
Submitted Solution:
```
from fractions import Fraction
def calc(s):
i = n = ans = 0
while i < len(s):
if s[i] == 'n':
i += 5
if n == 0:
ans = Fraction(0,1)
elif ans > 0:
ans -= Fraction(90, 2**n)
else:
i += 4
if n == 0:
ans = Fraction(90,1)
elif ans < 90:
ans += Fraction(90, 2**n)
n += 1
return ans
while True:
S = input()
if S == '#': break
print(calc(S))
``` | instruction | 0 | 26,486 | 23 | 52,972 |
No | output | 1 | 26,486 | 23 | 52,973 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Problem Statement
We can describe detailed direction by repeating the directional names: north, south, east and west. For example, northwest is the direction halfway between north and west, and northnorthwest is between north and northwest.
In this problem, we describe more detailed direction between north and west as follows.
* "north" means $0$ degrees.
* "west" means $90$ degrees.
* If the direction $dir$ means $a$ degrees and the sum of the occurrences of "north" and "west" in $dir$ is $n$ ($\geq$ 1), "north"$dir$ (the concatenation of "north" and $dir$) means $a - \frac{90}{2^n}$ degrees and "west"$dir$ means $a + \frac{90}{2^n}$ degrees.
Your task is to calculate the angle in degrees described by the given direction.
* * *
Input
The input contains several datasets. The number of datasets does not exceed $100$.
Each dataset is described by a single line that contains a string denoting a direction. You may assume the given string can be obtained by concatenating some "north" and "west", the sum of the occurrences of "north" and "west" in the given string is between $1$ and $20$, inclusive, and the angle denoted by the given direction is between $0$ and $90$, inclusive. The final dataset is followed by a single line containing only a single "#".
Output
For each dataset, print an integer if the angle described by the given direction can be represented as an integer, otherwise print it as an irreducible fraction. Follow the format of the sample output.
* * *
Sample Input
north
west
northwest
northnorthwest
westwestwestnorth
Output for the Sample Input
0
90
45
45/2
315/4
Example
Input
north
west
northwest
northnorthwest
westwestwestnorth
#
Output
0
90
45
45/2
315/4
Submitted Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 998244353
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)
def main():
rr = []
while True:
s = S()
if s == '#':
break
a = 0
b = 1
while len(s) > 0:
b *= 2
if s[:5] == 'north':
s = s[5:]
else:
s = s[4:]
a += 90 / b
if len(s) == 0:
a += 90 / b
a *= b
g = fractions.gcd(a,b)
a = int(a//g)
b = int(b//g)
if b > 1:
rr.append('{}/{}'.format(a,b))
else:
rr.append(a)
return '\n'.join(map(str, rr))
print(main())
``` | instruction | 0 | 26,487 | 23 | 52,974 |
No | output | 1 | 26,487 | 23 | 52,975 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Problem Statement
We can describe detailed direction by repeating the directional names: north, south, east and west. For example, northwest is the direction halfway between north and west, and northnorthwest is between north and northwest.
In this problem, we describe more detailed direction between north and west as follows.
* "north" means $0$ degrees.
* "west" means $90$ degrees.
* If the direction $dir$ means $a$ degrees and the sum of the occurrences of "north" and "west" in $dir$ is $n$ ($\geq$ 1), "north"$dir$ (the concatenation of "north" and $dir$) means $a - \frac{90}{2^n}$ degrees and "west"$dir$ means $a + \frac{90}{2^n}$ degrees.
Your task is to calculate the angle in degrees described by the given direction.
* * *
Input
The input contains several datasets. The number of datasets does not exceed $100$.
Each dataset is described by a single line that contains a string denoting a direction. You may assume the given string can be obtained by concatenating some "north" and "west", the sum of the occurrences of "north" and "west" in the given string is between $1$ and $20$, inclusive, and the angle denoted by the given direction is between $0$ and $90$, inclusive. The final dataset is followed by a single line containing only a single "#".
Output
For each dataset, print an integer if the angle described by the given direction can be represented as an integer, otherwise print it as an irreducible fraction. Follow the format of the sample output.
* * *
Sample Input
north
west
northwest
northnorthwest
westwestwestnorth
Output for the Sample Input
0
90
45
45/2
315/4
Example
Input
north
west
northwest
northnorthwest
westwestwestnorth
#
Output
0
90
45
45/2
315/4
Submitted Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 998244353
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)
def main():
rr = []
while True:
s = S()
if s == '#':
break
a = 0
i = 0
while len(s) > 0:
i += 1
a *= 2
if s[:5] == 'north':
s = s[5:]
else:
s = s[4:]
a += 90
b = 2**(i-1)
g = fractions.gcd(a,b)
if b//g > 1:
rr.append('{}/{}'.format(a//g,b//g))
else:
rr.append(a // g)
return '\n'.join(map(str, rr))
print(main())
``` | instruction | 0 | 26,488 | 23 | 52,976 |
No | output | 1 | 26,488 | 23 | 52,977 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nastya came to her informatics lesson, and her teacher who is, by the way, a little bit famous here gave her the following task.
Two matrices A and B are given, each of them has size n × m. Nastya can perform the following operation to matrix A unlimited number of times:
* take any square square submatrix of A and transpose it (i.e. the element of the submatrix which was in the i-th row and j-th column of the submatrix will be in the j-th row and i-th column after transposing, and the transposed submatrix itself will keep its place in the matrix A).
Nastya's task is to check whether it is possible to transform the matrix A to the matrix B.
<image> Example of the operation
As it may require a lot of operations, you are asked to answer this question for Nastya.
A square submatrix of matrix M is a matrix which consist of all elements which comes from one of the rows with indeces x, x+1, ..., x+k-1 of matrix M and comes from one of the columns with indeces y, y+1, ..., y+k-1 of matrix M. k is the size of square submatrix. In other words, square submatrix is the set of elements of source matrix which form a solid square (i.e. without holes).
Input
The first line contains two integers n and m separated by space (1 ≤ n, m ≤ 500) — the numbers of rows and columns in A and B respectively.
Each of the next n lines contains m integers, the j-th number in the i-th of these lines denotes the j-th element of the i-th row of the matrix A (1 ≤ A_{ij} ≤ 10^{9}).
Each of the next n lines contains m integers, the j-th number in the i-th of these lines denotes the j-th element of the i-th row of the matrix B (1 ≤ B_{ij} ≤ 10^{9}).
Output
Print "YES" (without quotes) if it is possible to transform A to B and "NO" (without quotes) otherwise.
You can print each letter in any case (upper or lower).
Examples
Input
2 2
1 1
6 1
1 6
1 1
Output
YES
Input
2 2
4 4
4 5
5 4
4 4
Output
NO
Input
3 3
1 2 3
4 5 6
7 8 9
1 4 7
2 5 6
3 8 9
Output
YES
Note
Consider the third example. The matrix A initially looks as follows.
$$$ \begin{bmatrix} 1 & 2 & 3\\\ 4 & 5 & 6\\\ 7 & 8 & 9 \end{bmatrix} $$$
Then we choose the whole matrix as transposed submatrix and it becomes
$$$ \begin{bmatrix} 1 & 4 & 7\\\ 2 & 5 & 8\\\ 3 & 6 & 9 \end{bmatrix} $$$
Then we transpose the submatrix with corners in cells (2, 2) and (3, 3).
$$$ \begin{bmatrix} 1 & 4 & 7\\\ 2 & 5 & 8\\\ 3 & 6 & 9 \end{bmatrix} $$$
So matrix becomes
$$$ \begin{bmatrix} 1 & 4 & 7\\\ 2 & 5 & 6\\\ 3 & 8 & 9 \end{bmatrix} $$$
and it is B.
Submitted Solution:
```
N,M = map(int,input().split())
A = [list(map(int,input().split())) for i in range(N)]
B = [list(map(int,input().split())) for i in range(N)]
ans = 'YES'
for i in range(N):
t1 = sorted([A[i - j][j] for j in range(min(N, M)) if i-j>=0])
t2 = sorted([B[i - j][j] for j in range(min(N, M)) if i-j>=0])
#print(t1,t2)
if t1!=t2:
ans='NO'
break
for j in range(M):
t1 = sorted([A[N - i -1][j+i] for i in range(min(N, M)) if j+i<M])
t2 = sorted([B[N - i -1][j+i] for i in range(min(N, M)) if j+i<M])
#print(t1,t2)
if t1!=t2:
ans='NO'
break
print(ans)
``` | instruction | 0 | 26,606 | 23 | 53,212 |
Yes | output | 1 | 26,606 | 23 | 53,213 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nastya came to her informatics lesson, and her teacher who is, by the way, a little bit famous here gave her the following task.
Two matrices A and B are given, each of them has size n × m. Nastya can perform the following operation to matrix A unlimited number of times:
* take any square square submatrix of A and transpose it (i.e. the element of the submatrix which was in the i-th row and j-th column of the submatrix will be in the j-th row and i-th column after transposing, and the transposed submatrix itself will keep its place in the matrix A).
Nastya's task is to check whether it is possible to transform the matrix A to the matrix B.
<image> Example of the operation
As it may require a lot of operations, you are asked to answer this question for Nastya.
A square submatrix of matrix M is a matrix which consist of all elements which comes from one of the rows with indeces x, x+1, ..., x+k-1 of matrix M and comes from one of the columns with indeces y, y+1, ..., y+k-1 of matrix M. k is the size of square submatrix. In other words, square submatrix is the set of elements of source matrix which form a solid square (i.e. without holes).
Input
The first line contains two integers n and m separated by space (1 ≤ n, m ≤ 500) — the numbers of rows and columns in A and B respectively.
Each of the next n lines contains m integers, the j-th number in the i-th of these lines denotes the j-th element of the i-th row of the matrix A (1 ≤ A_{ij} ≤ 10^{9}).
Each of the next n lines contains m integers, the j-th number in the i-th of these lines denotes the j-th element of the i-th row of the matrix B (1 ≤ B_{ij} ≤ 10^{9}).
Output
Print "YES" (without quotes) if it is possible to transform A to B and "NO" (without quotes) otherwise.
You can print each letter in any case (upper or lower).
Examples
Input
2 2
1 1
6 1
1 6
1 1
Output
YES
Input
2 2
4 4
4 5
5 4
4 4
Output
NO
Input
3 3
1 2 3
4 5 6
7 8 9
1 4 7
2 5 6
3 8 9
Output
YES
Note
Consider the third example. The matrix A initially looks as follows.
$$$ \begin{bmatrix} 1 & 2 & 3\\\ 4 & 5 & 6\\\ 7 & 8 & 9 \end{bmatrix} $$$
Then we choose the whole matrix as transposed submatrix and it becomes
$$$ \begin{bmatrix} 1 & 4 & 7\\\ 2 & 5 & 8\\\ 3 & 6 & 9 \end{bmatrix} $$$
Then we transpose the submatrix with corners in cells (2, 2) and (3, 3).
$$$ \begin{bmatrix} 1 & 4 & 7\\\ 2 & 5 & 8\\\ 3 & 6 & 9 \end{bmatrix} $$$
So matrix becomes
$$$ \begin{bmatrix} 1 & 4 & 7\\\ 2 & 5 & 6\\\ 3 & 8 & 9 \end{bmatrix} $$$
and it is B.
Submitted Solution:
```
#------------------------------warmup----------------------------
import os
import sys
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
#-------------------game starts now-----------------------------------------------------
n,m=map(int,input().split())
a=[]
b=[]
for i in range(n):
a.append(list(map(int,input().split())))
for j in range(n):
b.append(list(map(int,input().split())))
f=0
for i in range(m):
t=i
r=[]
d=0
r1=[]
for j in range(t+1):
r.append(a[d][i-j])
r1.append(b[d][i-j])
d+=1
if d==n:
break
r.sort()
r1.sort()
if r!=r1:
f=1
break
for i in range(1,n):
t=m-1
r=[]
d=i
r1=[]
for j in range(t+1):
r.append(a[d][t-j])
r1.append(b[d][t-j])
d+=1
if d==n:
break
r.sort()
r1.sort()
if r!=r1:
f=1
break
if f==1:
print("NO")
else:
print("YES")
``` | instruction | 0 | 26,607 | 23 | 53,214 |
Yes | output | 1 | 26,607 | 23 | 53,215 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nastya came to her informatics lesson, and her teacher who is, by the way, a little bit famous here gave her the following task.
Two matrices A and B are given, each of them has size n × m. Nastya can perform the following operation to matrix A unlimited number of times:
* take any square square submatrix of A and transpose it (i.e. the element of the submatrix which was in the i-th row and j-th column of the submatrix will be in the j-th row and i-th column after transposing, and the transposed submatrix itself will keep its place in the matrix A).
Nastya's task is to check whether it is possible to transform the matrix A to the matrix B.
<image> Example of the operation
As it may require a lot of operations, you are asked to answer this question for Nastya.
A square submatrix of matrix M is a matrix which consist of all elements which comes from one of the rows with indeces x, x+1, ..., x+k-1 of matrix M and comes from one of the columns with indeces y, y+1, ..., y+k-1 of matrix M. k is the size of square submatrix. In other words, square submatrix is the set of elements of source matrix which form a solid square (i.e. without holes).
Input
The first line contains two integers n and m separated by space (1 ≤ n, m ≤ 500) — the numbers of rows and columns in A and B respectively.
Each of the next n lines contains m integers, the j-th number in the i-th of these lines denotes the j-th element of the i-th row of the matrix A (1 ≤ A_{ij} ≤ 10^{9}).
Each of the next n lines contains m integers, the j-th number in the i-th of these lines denotes the j-th element of the i-th row of the matrix B (1 ≤ B_{ij} ≤ 10^{9}).
Output
Print "YES" (without quotes) if it is possible to transform A to B and "NO" (without quotes) otherwise.
You can print each letter in any case (upper or lower).
Examples
Input
2 2
1 1
6 1
1 6
1 1
Output
YES
Input
2 2
4 4
4 5
5 4
4 4
Output
NO
Input
3 3
1 2 3
4 5 6
7 8 9
1 4 7
2 5 6
3 8 9
Output
YES
Note
Consider the third example. The matrix A initially looks as follows.
$$$ \begin{bmatrix} 1 & 2 & 3\\\ 4 & 5 & 6\\\ 7 & 8 & 9 \end{bmatrix} $$$
Then we choose the whole matrix as transposed submatrix and it becomes
$$$ \begin{bmatrix} 1 & 4 & 7\\\ 2 & 5 & 8\\\ 3 & 6 & 9 \end{bmatrix} $$$
Then we transpose the submatrix with corners in cells (2, 2) and (3, 3).
$$$ \begin{bmatrix} 1 & 4 & 7\\\ 2 & 5 & 8\\\ 3 & 6 & 9 \end{bmatrix} $$$
So matrix becomes
$$$ \begin{bmatrix} 1 & 4 & 7\\\ 2 & 5 & 6\\\ 3 & 8 & 9 \end{bmatrix} $$$
and it is B.
Submitted Solution:
```
n, m = map(int,input().split())
a = [list(map(int,input().split())) for _ in range(n)]
b = [list(map(int,input().split())) for _ in range(n)]
l1, l2 = [[] for _ in range(n+m)], [[] for _ in range(n+m)]
for i in range(n):
for j in range(m):
l1[i+j].append(a[i][j])
l2[i+j].append(b[i][j])
for i in l1:
i.sort()
for i in l2:
i.sort()
print("YES" if l1 == l2 else "NO")
``` | instruction | 0 | 26,608 | 23 | 53,216 |
Yes | output | 1 | 26,608 | 23 | 53,217 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nastya came to her informatics lesson, and her teacher who is, by the way, a little bit famous here gave her the following task.
Two matrices A and B are given, each of them has size n × m. Nastya can perform the following operation to matrix A unlimited number of times:
* take any square square submatrix of A and transpose it (i.e. the element of the submatrix which was in the i-th row and j-th column of the submatrix will be in the j-th row and i-th column after transposing, and the transposed submatrix itself will keep its place in the matrix A).
Nastya's task is to check whether it is possible to transform the matrix A to the matrix B.
<image> Example of the operation
As it may require a lot of operations, you are asked to answer this question for Nastya.
A square submatrix of matrix M is a matrix which consist of all elements which comes from one of the rows with indeces x, x+1, ..., x+k-1 of matrix M and comes from one of the columns with indeces y, y+1, ..., y+k-1 of matrix M. k is the size of square submatrix. In other words, square submatrix is the set of elements of source matrix which form a solid square (i.e. without holes).
Input
The first line contains two integers n and m separated by space (1 ≤ n, m ≤ 500) — the numbers of rows and columns in A and B respectively.
Each of the next n lines contains m integers, the j-th number in the i-th of these lines denotes the j-th element of the i-th row of the matrix A (1 ≤ A_{ij} ≤ 10^{9}).
Each of the next n lines contains m integers, the j-th number in the i-th of these lines denotes the j-th element of the i-th row of the matrix B (1 ≤ B_{ij} ≤ 10^{9}).
Output
Print "YES" (without quotes) if it is possible to transform A to B and "NO" (without quotes) otherwise.
You can print each letter in any case (upper or lower).
Examples
Input
2 2
1 1
6 1
1 6
1 1
Output
YES
Input
2 2
4 4
4 5
5 4
4 4
Output
NO
Input
3 3
1 2 3
4 5 6
7 8 9
1 4 7
2 5 6
3 8 9
Output
YES
Note
Consider the third example. The matrix A initially looks as follows.
$$$ \begin{bmatrix} 1 & 2 & 3\\\ 4 & 5 & 6\\\ 7 & 8 & 9 \end{bmatrix} $$$
Then we choose the whole matrix as transposed submatrix and it becomes
$$$ \begin{bmatrix} 1 & 4 & 7\\\ 2 & 5 & 8\\\ 3 & 6 & 9 \end{bmatrix} $$$
Then we transpose the submatrix with corners in cells (2, 2) and (3, 3).
$$$ \begin{bmatrix} 1 & 4 & 7\\\ 2 & 5 & 8\\\ 3 & 6 & 9 \end{bmatrix} $$$
So matrix becomes
$$$ \begin{bmatrix} 1 & 4 & 7\\\ 2 & 5 & 6\\\ 3 & 8 & 9 \end{bmatrix} $$$
and it is B.
Submitted Solution:
```
# inp = lambda: map(int,input().split())
n,m = map(int,input().split())
def mtr(r):
for _ in range(r):
temp = map(int,input().split())
yield list(temp)
def diag(x,t):
temp = [[] for _ in range(1,m+n)]
for i,j in list(zip(*[[i for i in range(t)],[i for i in range(t)]])):
for k in x[j]:
temp[i].append(k)
i += 1
for i in range(0,m+n-1):
temp[i].sort()
return temp
a = diag(list(mtr(n)),n)
b = diag(list(mtr(n)),n)
print('YES' if a == b else 'NO')
``` | instruction | 0 | 26,609 | 23 | 53,218 |
Yes | output | 1 | 26,609 | 23 | 53,219 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nastya came to her informatics lesson, and her teacher who is, by the way, a little bit famous here gave her the following task.
Two matrices A and B are given, each of them has size n × m. Nastya can perform the following operation to matrix A unlimited number of times:
* take any square square submatrix of A and transpose it (i.e. the element of the submatrix which was in the i-th row and j-th column of the submatrix will be in the j-th row and i-th column after transposing, and the transposed submatrix itself will keep its place in the matrix A).
Nastya's task is to check whether it is possible to transform the matrix A to the matrix B.
<image> Example of the operation
As it may require a lot of operations, you are asked to answer this question for Nastya.
A square submatrix of matrix M is a matrix which consist of all elements which comes from one of the rows with indeces x, x+1, ..., x+k-1 of matrix M and comes from one of the columns with indeces y, y+1, ..., y+k-1 of matrix M. k is the size of square submatrix. In other words, square submatrix is the set of elements of source matrix which form a solid square (i.e. without holes).
Input
The first line contains two integers n and m separated by space (1 ≤ n, m ≤ 500) — the numbers of rows and columns in A and B respectively.
Each of the next n lines contains m integers, the j-th number in the i-th of these lines denotes the j-th element of the i-th row of the matrix A (1 ≤ A_{ij} ≤ 10^{9}).
Each of the next n lines contains m integers, the j-th number in the i-th of these lines denotes the j-th element of the i-th row of the matrix B (1 ≤ B_{ij} ≤ 10^{9}).
Output
Print "YES" (without quotes) if it is possible to transform A to B and "NO" (without quotes) otherwise.
You can print each letter in any case (upper or lower).
Examples
Input
2 2
1 1
6 1
1 6
1 1
Output
YES
Input
2 2
4 4
4 5
5 4
4 4
Output
NO
Input
3 3
1 2 3
4 5 6
7 8 9
1 4 7
2 5 6
3 8 9
Output
YES
Note
Consider the third example. The matrix A initially looks as follows.
$$$ \begin{bmatrix} 1 & 2 & 3\\\ 4 & 5 & 6\\\ 7 & 8 & 9 \end{bmatrix} $$$
Then we choose the whole matrix as transposed submatrix and it becomes
$$$ \begin{bmatrix} 1 & 4 & 7\\\ 2 & 5 & 8\\\ 3 & 6 & 9 \end{bmatrix} $$$
Then we transpose the submatrix with corners in cells (2, 2) and (3, 3).
$$$ \begin{bmatrix} 1 & 4 & 7\\\ 2 & 5 & 8\\\ 3 & 6 & 9 \end{bmatrix} $$$
So matrix becomes
$$$ \begin{bmatrix} 1 & 4 & 7\\\ 2 & 5 & 6\\\ 3 & 8 & 9 \end{bmatrix} $$$
and it is B.
Submitted Solution:
```
#Code by Sounak, IIESTS
#------------------------------warmup----------------------------
import os
import sys
import math
from io import BytesIO, IOBase
from fractions import Fraction
from collections import defaultdict
from itertools import permutations
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
#-------------------game starts now-----------------------------------------------------
n,m=map(int,input().split())
a=[[*list(map(int,input().split()))]for j in range (n)]
b=[[*list(map(int,input().split()))]for j in range (n)]
ch=1
for i in range (min(n,m)):
#print(a[i][i],b[i][i])
if a[i][i]!=b[i][i]:
ch=0
break
if ch==1:
print("YES")
else:
print("NO")
``` | instruction | 0 | 26,610 | 23 | 53,220 |
No | output | 1 | 26,610 | 23 | 53,221 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nastya came to her informatics lesson, and her teacher who is, by the way, a little bit famous here gave her the following task.
Two matrices A and B are given, each of them has size n × m. Nastya can perform the following operation to matrix A unlimited number of times:
* take any square square submatrix of A and transpose it (i.e. the element of the submatrix which was in the i-th row and j-th column of the submatrix will be in the j-th row and i-th column after transposing, and the transposed submatrix itself will keep its place in the matrix A).
Nastya's task is to check whether it is possible to transform the matrix A to the matrix B.
<image> Example of the operation
As it may require a lot of operations, you are asked to answer this question for Nastya.
A square submatrix of matrix M is a matrix which consist of all elements which comes from one of the rows with indeces x, x+1, ..., x+k-1 of matrix M and comes from one of the columns with indeces y, y+1, ..., y+k-1 of matrix M. k is the size of square submatrix. In other words, square submatrix is the set of elements of source matrix which form a solid square (i.e. without holes).
Input
The first line contains two integers n and m separated by space (1 ≤ n, m ≤ 500) — the numbers of rows and columns in A and B respectively.
Each of the next n lines contains m integers, the j-th number in the i-th of these lines denotes the j-th element of the i-th row of the matrix A (1 ≤ A_{ij} ≤ 10^{9}).
Each of the next n lines contains m integers, the j-th number in the i-th of these lines denotes the j-th element of the i-th row of the matrix B (1 ≤ B_{ij} ≤ 10^{9}).
Output
Print "YES" (without quotes) if it is possible to transform A to B and "NO" (without quotes) otherwise.
You can print each letter in any case (upper or lower).
Examples
Input
2 2
1 1
6 1
1 6
1 1
Output
YES
Input
2 2
4 4
4 5
5 4
4 4
Output
NO
Input
3 3
1 2 3
4 5 6
7 8 9
1 4 7
2 5 6
3 8 9
Output
YES
Note
Consider the third example. The matrix A initially looks as follows.
$$$ \begin{bmatrix} 1 & 2 & 3\\\ 4 & 5 & 6\\\ 7 & 8 & 9 \end{bmatrix} $$$
Then we choose the whole matrix as transposed submatrix and it becomes
$$$ \begin{bmatrix} 1 & 4 & 7\\\ 2 & 5 & 8\\\ 3 & 6 & 9 \end{bmatrix} $$$
Then we transpose the submatrix with corners in cells (2, 2) and (3, 3).
$$$ \begin{bmatrix} 1 & 4 & 7\\\ 2 & 5 & 8\\\ 3 & 6 & 9 \end{bmatrix} $$$
So matrix becomes
$$$ \begin{bmatrix} 1 & 4 & 7\\\ 2 & 5 & 6\\\ 3 & 8 & 9 \end{bmatrix} $$$
and it is B.
Submitted Solution:
```
def check_matrix(a, b, n, m):
mini, maxi = n, 0
minj, maxj = m, 0
for i in range(n):
for j in range(m):
if a[i][j] != b[i][j]:
mini, maxi = min(mini, i), max(maxi, i)
minj, maxj = min(minj, j), max(maxj, j)
return min(mini, minj), max(maxi, maxj)
n, m = [int(i) for i in input().split()]
a = [[int(j) for j in input().split()] for i in range(n)]
b = [[int(j) for j in input().split()] for i in range(n)]
aa = a
bb = b
find = False
nn, mm = n, m
for k in range(10):
mini, maxi = check_matrix(aa, bb, nn, mm)
if mini == nn and maxi == 0:
find = True
break
mm = nn = maxi - mini + 1
aa_prev = aa
aa = [[0] * nn for i in range(nn)]
bb = [[0] * nn for i in range(nn)]
for i in range(mini, maxi + 1):
for j in range(mini, maxi + 1):
aa[j - mini][i - mini] = a[i][j]
bb[i - mini][j - mini] = b[i][j]
if aa_prev == aa:
find = False
break
if find:
print("YES")
else:
print("NO")
``` | instruction | 0 | 26,611 | 23 | 53,222 |
No | output | 1 | 26,611 | 23 | 53,223 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nastya came to her informatics lesson, and her teacher who is, by the way, a little bit famous here gave her the following task.
Two matrices A and B are given, each of them has size n × m. Nastya can perform the following operation to matrix A unlimited number of times:
* take any square square submatrix of A and transpose it (i.e. the element of the submatrix which was in the i-th row and j-th column of the submatrix will be in the j-th row and i-th column after transposing, and the transposed submatrix itself will keep its place in the matrix A).
Nastya's task is to check whether it is possible to transform the matrix A to the matrix B.
<image> Example of the operation
As it may require a lot of operations, you are asked to answer this question for Nastya.
A square submatrix of matrix M is a matrix which consist of all elements which comes from one of the rows with indeces x, x+1, ..., x+k-1 of matrix M and comes from one of the columns with indeces y, y+1, ..., y+k-1 of matrix M. k is the size of square submatrix. In other words, square submatrix is the set of elements of source matrix which form a solid square (i.e. without holes).
Input
The first line contains two integers n and m separated by space (1 ≤ n, m ≤ 500) — the numbers of rows and columns in A and B respectively.
Each of the next n lines contains m integers, the j-th number in the i-th of these lines denotes the j-th element of the i-th row of the matrix A (1 ≤ A_{ij} ≤ 10^{9}).
Each of the next n lines contains m integers, the j-th number in the i-th of these lines denotes the j-th element of the i-th row of the matrix B (1 ≤ B_{ij} ≤ 10^{9}).
Output
Print "YES" (without quotes) if it is possible to transform A to B and "NO" (without quotes) otherwise.
You can print each letter in any case (upper or lower).
Examples
Input
2 2
1 1
6 1
1 6
1 1
Output
YES
Input
2 2
4 4
4 5
5 4
4 4
Output
NO
Input
3 3
1 2 3
4 5 6
7 8 9
1 4 7
2 5 6
3 8 9
Output
YES
Note
Consider the third example. The matrix A initially looks as follows.
$$$ \begin{bmatrix} 1 & 2 & 3\\\ 4 & 5 & 6\\\ 7 & 8 & 9 \end{bmatrix} $$$
Then we choose the whole matrix as transposed submatrix and it becomes
$$$ \begin{bmatrix} 1 & 4 & 7\\\ 2 & 5 & 8\\\ 3 & 6 & 9 \end{bmatrix} $$$
Then we transpose the submatrix with corners in cells (2, 2) and (3, 3).
$$$ \begin{bmatrix} 1 & 4 & 7\\\ 2 & 5 & 8\\\ 3 & 6 & 9 \end{bmatrix} $$$
So matrix becomes
$$$ \begin{bmatrix} 1 & 4 & 7\\\ 2 & 5 & 6\\\ 3 & 8 & 9 \end{bmatrix} $$$
and it is B.
Submitted Solution:
```
def main():
import sys
ss = sys.stdin.readline
n, m = map(int, ss().split())
a = [[i for i in map(int, ss().split())] for i in range(n)]
b = [[i for i in map(int, ss().split())] for i in range(n)]
ans = 1; op = 1
for j in range(m):
da = {}; db = {}
i = 0
while j >= 0 and i < n:
da[a[i][j]] = da.get(a[i][j], 0) + 1
db[b[i][j]] = db.get(b[i][j], 0) + 1
j -= 1; i += 1
if da != db: ans = 0
if not ans: break
for i in range(1, n):
da = {}; db = {}
j = m - 1
while j >= 0 and i < n:
da[a[i][j]] = da.get(a[i][j], 0) + 1
db[b[i][j]] = db.get(b[i][j], 0) + 1
j -= 1; i += 1
if da != db: ans = 0
if not ans: break
if ans:
print('YES')
else:
print('NO')
main()
``` | instruction | 0 | 26,612 | 23 | 53,224 |
No | output | 1 | 26,612 | 23 | 53,225 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nastya came to her informatics lesson, and her teacher who is, by the way, a little bit famous here gave her the following task.
Two matrices A and B are given, each of them has size n × m. Nastya can perform the following operation to matrix A unlimited number of times:
* take any square square submatrix of A and transpose it (i.e. the element of the submatrix which was in the i-th row and j-th column of the submatrix will be in the j-th row and i-th column after transposing, and the transposed submatrix itself will keep its place in the matrix A).
Nastya's task is to check whether it is possible to transform the matrix A to the matrix B.
<image> Example of the operation
As it may require a lot of operations, you are asked to answer this question for Nastya.
A square submatrix of matrix M is a matrix which consist of all elements which comes from one of the rows with indeces x, x+1, ..., x+k-1 of matrix M and comes from one of the columns with indeces y, y+1, ..., y+k-1 of matrix M. k is the size of square submatrix. In other words, square submatrix is the set of elements of source matrix which form a solid square (i.e. without holes).
Input
The first line contains two integers n and m separated by space (1 ≤ n, m ≤ 500) — the numbers of rows and columns in A and B respectively.
Each of the next n lines contains m integers, the j-th number in the i-th of these lines denotes the j-th element of the i-th row of the matrix A (1 ≤ A_{ij} ≤ 10^{9}).
Each of the next n lines contains m integers, the j-th number in the i-th of these lines denotes the j-th element of the i-th row of the matrix B (1 ≤ B_{ij} ≤ 10^{9}).
Output
Print "YES" (without quotes) if it is possible to transform A to B and "NO" (without quotes) otherwise.
You can print each letter in any case (upper or lower).
Examples
Input
2 2
1 1
6 1
1 6
1 1
Output
YES
Input
2 2
4 4
4 5
5 4
4 4
Output
NO
Input
3 3
1 2 3
4 5 6
7 8 9
1 4 7
2 5 6
3 8 9
Output
YES
Note
Consider the third example. The matrix A initially looks as follows.
$$$ \begin{bmatrix} 1 & 2 & 3\\\ 4 & 5 & 6\\\ 7 & 8 & 9 \end{bmatrix} $$$
Then we choose the whole matrix as transposed submatrix and it becomes
$$$ \begin{bmatrix} 1 & 4 & 7\\\ 2 & 5 & 8\\\ 3 & 6 & 9 \end{bmatrix} $$$
Then we transpose the submatrix with corners in cells (2, 2) and (3, 3).
$$$ \begin{bmatrix} 1 & 4 & 7\\\ 2 & 5 & 8\\\ 3 & 6 & 9 \end{bmatrix} $$$
So matrix becomes
$$$ \begin{bmatrix} 1 & 4 & 7\\\ 2 & 5 & 6\\\ 3 & 8 & 9 \end{bmatrix} $$$
and it is B.
Submitted Solution:
```
n,m=map(int,input().split())
L=[list(map(int,input().split())) for i in range(n)]
L1=[list(map(int,input().split())) for i in range(n)]
for i in range(m) :
d={}
for j in range(min(n,i+1)) :
v=L[j][i-j]
d[v]=d.get(v,0)+1
for j in range(min(n,i+1)) :
v=L1[j][i-j]
d[v]=d.get(v,0)-1
for x in d :
if d[x]!=0 :
print("NO")
exit()
for i in range(m) :
d={}
for j in range(min(n,m-i)) :
v=L[n-j-1][i+j]
d[v]=d.get(v,0)+1
for j in range(min(n,m-i)) :
v=L1[n-j-1][i+j]
d[v]=d.get(v,0)-1
for x in d :
if d[x]!=0 :
print("NO")
exit()
print("YES")
``` | instruction | 0 | 26,613 | 23 | 53,226 |
No | output | 1 | 26,613 | 23 | 53,227 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A coordinate line has n segments, the i-th segment starts at the position li and ends at the position ri. We will denote such a segment as [li, ri].
You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all other ones. Now you want to test your assumption. Find in the given set the segment which covers all other segments, and print its number. If such a segment doesn't exist, print -1.
Formally we will assume that segment [a, b] covers segment [c, d], if they meet this condition a ≤ c ≤ d ≤ b.
Input
The first line contains integer n (1 ≤ n ≤ 105) — the number of segments. Next n lines contain the descriptions of the segments. The i-th line contains two space-separated integers li, ri (1 ≤ li ≤ ri ≤ 109) — the borders of the i-th segment.
It is guaranteed that no two segments coincide.
Output
Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1.
The segments are numbered starting from 1 in the order in which they appear in the input.
Examples
Input
3
1 1
2 2
3 3
Output
-1
Input
6
1 5
2 3
1 10
7 10
7 7
10 10
Output
3 | instruction | 0 | 26,812 | 23 | 53,624 |
Tags: implementation, sortings
Correct Solution:
```
n = int(input())
arr = [tuple(map(int, input().split())) for _ in range(n)]
l = min(arr, key=lambda x: x[0])[0]
h = max(arr, key=lambda x: x[1])[1]
ans = -1
for i in range(n):
if arr[i][0] == l and arr[i][1] == h:
ans = i+1
break
print(ans)
``` | output | 1 | 26,812 | 23 | 53,625 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A coordinate line has n segments, the i-th segment starts at the position li and ends at the position ri. We will denote such a segment as [li, ri].
You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all other ones. Now you want to test your assumption. Find in the given set the segment which covers all other segments, and print its number. If such a segment doesn't exist, print -1.
Formally we will assume that segment [a, b] covers segment [c, d], if they meet this condition a ≤ c ≤ d ≤ b.
Input
The first line contains integer n (1 ≤ n ≤ 105) — the number of segments. Next n lines contain the descriptions of the segments. The i-th line contains two space-separated integers li, ri (1 ≤ li ≤ ri ≤ 109) — the borders of the i-th segment.
It is guaranteed that no two segments coincide.
Output
Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1.
The segments are numbered starting from 1 in the order in which they appear in the input.
Examples
Input
3
1 1
2 2
3 3
Output
-1
Input
6
1 5
2 3
1 10
7 10
7 7
10 10
Output
3 | instruction | 0 | 26,813 | 23 | 53,626 |
Tags: implementation, sortings
Correct Solution:
```
R=input
I=lambda:map(int,R().split())
n=int(R())
a=[]
b=[]
for i in range(n):
x,y=I()
a.append(x)
b.append(y)
x=min(a)
y=max(b)
for i in range(n):
if a[i]==x and b[i]==y:
print(i+1)
exit()
print(-1)
``` | output | 1 | 26,813 | 23 | 53,627 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A coordinate line has n segments, the i-th segment starts at the position li and ends at the position ri. We will denote such a segment as [li, ri].
You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all other ones. Now you want to test your assumption. Find in the given set the segment which covers all other segments, and print its number. If such a segment doesn't exist, print -1.
Formally we will assume that segment [a, b] covers segment [c, d], if they meet this condition a ≤ c ≤ d ≤ b.
Input
The first line contains integer n (1 ≤ n ≤ 105) — the number of segments. Next n lines contain the descriptions of the segments. The i-th line contains two space-separated integers li, ri (1 ≤ li ≤ ri ≤ 109) — the borders of the i-th segment.
It is guaranteed that no two segments coincide.
Output
Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1.
The segments are numbered starting from 1 in the order in which they appear in the input.
Examples
Input
3
1 1
2 2
3 3
Output
-1
Input
6
1 5
2 3
1 10
7 10
7 7
10 10
Output
3 | instruction | 0 | 26,814 | 23 | 53,628 |
Tags: implementation, sortings
Correct Solution:
```
def main():
n = int(input())
mi = int(1e10)
ma = int(-1e10)
l = []
for i in range(n):
(a, b) = map(int, input().split(' '))
mi = min(mi, a)
ma = max(ma, b)
l.append((a, b))
for i, (a, b) in enumerate(l):
if a == mi and b == ma:
return i + 1
return -1
print(main())
``` | output | 1 | 26,814 | 23 | 53,629 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A coordinate line has n segments, the i-th segment starts at the position li and ends at the position ri. We will denote such a segment as [li, ri].
You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all other ones. Now you want to test your assumption. Find in the given set the segment which covers all other segments, and print its number. If such a segment doesn't exist, print -1.
Formally we will assume that segment [a, b] covers segment [c, d], if they meet this condition a ≤ c ≤ d ≤ b.
Input
The first line contains integer n (1 ≤ n ≤ 105) — the number of segments. Next n lines contain the descriptions of the segments. The i-th line contains two space-separated integers li, ri (1 ≤ li ≤ ri ≤ 109) — the borders of the i-th segment.
It is guaranteed that no two segments coincide.
Output
Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1.
The segments are numbered starting from 1 in the order in which they appear in the input.
Examples
Input
3
1 1
2 2
3 3
Output
-1
Input
6
1 5
2 3
1 10
7 10
7 7
10 10
Output
3 | instruction | 0 | 26,815 | 23 | 53,630 |
Tags: implementation, sortings
Correct Solution:
```
n = int(input())
dict_seg = {}
cover_seg = 1
for i in range(1, n+1):
dict_seg[i] = list(map(int, input().split(' ')))
max_seg = dict_seg[1][1]
min_seg = dict_seg[1][0]
for i in range(2, n+1):
if min_seg >= dict_seg[i][0] and max_seg <= dict_seg[i][1]:
min_seg = dict_seg[i][0]
max_seg = dict_seg[i][1]
cover_seg = i
for i in range(1, n+1):
if min_seg > dict_seg[i][0] or max_seg < dict_seg[i][1]:
print("-1")
exit(0)
print(cover_seg)
exit(0)
``` | output | 1 | 26,815 | 23 | 53,631 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A coordinate line has n segments, the i-th segment starts at the position li and ends at the position ri. We will denote such a segment as [li, ri].
You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all other ones. Now you want to test your assumption. Find in the given set the segment which covers all other segments, and print its number. If such a segment doesn't exist, print -1.
Formally we will assume that segment [a, b] covers segment [c, d], if they meet this condition a ≤ c ≤ d ≤ b.
Input
The first line contains integer n (1 ≤ n ≤ 105) — the number of segments. Next n lines contain the descriptions of the segments. The i-th line contains two space-separated integers li, ri (1 ≤ li ≤ ri ≤ 109) — the borders of the i-th segment.
It is guaranteed that no two segments coincide.
Output
Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1.
The segments are numbered starting from 1 in the order in which they appear in the input.
Examples
Input
3
1 1
2 2
3 3
Output
-1
Input
6
1 5
2 3
1 10
7 10
7 7
10 10
Output
3 | instruction | 0 | 26,816 | 23 | 53,632 |
Tags: implementation, sortings
Correct Solution:
```
n = int(input())
mx = float("inf")
mxs = set()
my = -1
mys = set()
for i in range(n):
x, y = map(int, input().split())
if x < mx:
mx = x
mxs = {i + 1}
elif x == mx:
mxs.add(i + 1)
if y > my:
my = y
mys = {i + 1}
elif y == my:
mys.add(i + 1)
if mxs & mys:
print(list(mxs & mys)[0])
else:
print(-1)
``` | output | 1 | 26,816 | 23 | 53,633 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A coordinate line has n segments, the i-th segment starts at the position li and ends at the position ri. We will denote such a segment as [li, ri].
You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all other ones. Now you want to test your assumption. Find in the given set the segment which covers all other segments, and print its number. If such a segment doesn't exist, print -1.
Formally we will assume that segment [a, b] covers segment [c, d], if they meet this condition a ≤ c ≤ d ≤ b.
Input
The first line contains integer n (1 ≤ n ≤ 105) — the number of segments. Next n lines contain the descriptions of the segments. The i-th line contains two space-separated integers li, ri (1 ≤ li ≤ ri ≤ 109) — the borders of the i-th segment.
It is guaranteed that no two segments coincide.
Output
Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1.
The segments are numbered starting from 1 in the order in which they appear in the input.
Examples
Input
3
1 1
2 2
3 3
Output
-1
Input
6
1 5
2 3
1 10
7 10
7 7
10 10
Output
3 | instruction | 0 | 26,817 | 23 | 53,634 |
Tags: implementation, sortings
Correct Solution:
```
def findNumberCover(matrix):
# find min value and list index_min
min_value = min(matrix[0])
listMin = [i for i, j in enumerate(matrix[0]) if j == min_value]
# find max value and list index_manx
max_value = max(matrix[1])
listMax = [i for i, j in enumerate(matrix[1]) if j == max_value]
result = list(set(listMin).intersection(listMax))
if(not result):
return -1
else:
return result[0] + 1
def transpose(matrix):
matrixT = []
row1 = []
row2 = []
for index in matrix:
row1.append(index[0])
row2.append(index[1])
matrixT.append(row1)
matrixT.append(row2)
return matrixT
# Input data
rows = int(input())
matrix = []
row = []
for i in range(rows):
row = list(map(int, input().split()))
matrix.append(row)
matrixT = transpose(matrix)
# Find the number of segment that covers all
print(findNumberCover(matrixT))
``` | output | 1 | 26,817 | 23 | 53,635 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A coordinate line has n segments, the i-th segment starts at the position li and ends at the position ri. We will denote such a segment as [li, ri].
You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all other ones. Now you want to test your assumption. Find in the given set the segment which covers all other segments, and print its number. If such a segment doesn't exist, print -1.
Formally we will assume that segment [a, b] covers segment [c, d], if they meet this condition a ≤ c ≤ d ≤ b.
Input
The first line contains integer n (1 ≤ n ≤ 105) — the number of segments. Next n lines contain the descriptions of the segments. The i-th line contains two space-separated integers li, ri (1 ≤ li ≤ ri ≤ 109) — the borders of the i-th segment.
It is guaranteed that no two segments coincide.
Output
Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1.
The segments are numbered starting from 1 in the order in which they appear in the input.
Examples
Input
3
1 1
2 2
3 3
Output
-1
Input
6
1 5
2 3
1 10
7 10
7 7
10 10
Output
3 | instruction | 0 | 26,818 | 23 | 53,636 |
Tags: implementation, sortings
Correct Solution:
```
class lines:
def __init__(self, l, r):
self.r = r
self.l = l
n = int(input())
arr = []
for i in range(n):
l, r = map(int, input().split())
arr.append(lines(l, r))
index = -1
lc = 10 ** 9
rc = 0
for i in range(0, n):
if arr[i].l < lc:
lc = arr[i].l
for i in range(0, n):
if arr[i].r > rc:
rc = arr[i].r
for i in range(n):
if arr[i].l == lc and arr[i].r == rc:
index = i + 1
break
print(index)
``` | output | 1 | 26,818 | 23 | 53,637 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A coordinate line has n segments, the i-th segment starts at the position li and ends at the position ri. We will denote such a segment as [li, ri].
You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all other ones. Now you want to test your assumption. Find in the given set the segment which covers all other segments, and print its number. If such a segment doesn't exist, print -1.
Formally we will assume that segment [a, b] covers segment [c, d], if they meet this condition a ≤ c ≤ d ≤ b.
Input
The first line contains integer n (1 ≤ n ≤ 105) — the number of segments. Next n lines contain the descriptions of the segments. The i-th line contains two space-separated integers li, ri (1 ≤ li ≤ ri ≤ 109) — the borders of the i-th segment.
It is guaranteed that no two segments coincide.
Output
Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1.
The segments are numbered starting from 1 in the order in which they appear in the input.
Examples
Input
3
1 1
2 2
3 3
Output
-1
Input
6
1 5
2 3
1 10
7 10
7 7
10 10
Output
3 | instruction | 0 | 26,819 | 23 | 53,638 |
Tags: implementation, sortings
Correct Solution:
```
segment_arr = []
size = int(input())
max_right = 0
min_left = 1000000000
index = 0
for i in range(size):
li, ri = map(int, input().split())
if li <= min_left and ri >= max_right:
index = i + 1
elif li < min_left or ri > max_right:
index = -1
max_right = max(ri, max_right)
min_left = min(li, min_left)
print(index)
``` | output | 1 | 26,819 | 23 | 53,639 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A coordinate line has n segments, the i-th segment starts at the position li and ends at the position ri. We will denote such a segment as [li, ri].
You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all other ones. Now you want to test your assumption. Find in the given set the segment which covers all other segments, and print its number. If such a segment doesn't exist, print -1.
Formally we will assume that segment [a, b] covers segment [c, d], if they meet this condition a ≤ c ≤ d ≤ b.
Input
The first line contains integer n (1 ≤ n ≤ 105) — the number of segments. Next n lines contain the descriptions of the segments. The i-th line contains two space-separated integers li, ri (1 ≤ li ≤ ri ≤ 109) — the borders of the i-th segment.
It is guaranteed that no two segments coincide.
Output
Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1.
The segments are numbered starting from 1 in the order in which they appear in the input.
Examples
Input
3
1 1
2 2
3 3
Output
-1
Input
6
1 5
2 3
1 10
7 10
7 7
10 10
Output
3
Submitted Solution:
```
n = int(input())
minn, maxn = (int(i) for i in input().split())
numbers = {(minn, maxn):0}
for j in range(1, n):
a, b = (int(i) for i in input().split())
numbers[(a,b)] = j
if b > maxn: maxn = b
if a < minn: minn = a
if (minn, maxn) in numbers:
print(numbers[(minn, maxn)] + 1)
else:
print(-1)
``` | instruction | 0 | 26,820 | 23 | 53,640 |
Yes | output | 1 | 26,820 | 23 | 53,641 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A coordinate line has n segments, the i-th segment starts at the position li and ends at the position ri. We will denote such a segment as [li, ri].
You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all other ones. Now you want to test your assumption. Find in the given set the segment which covers all other segments, and print its number. If such a segment doesn't exist, print -1.
Formally we will assume that segment [a, b] covers segment [c, d], if they meet this condition a ≤ c ≤ d ≤ b.
Input
The first line contains integer n (1 ≤ n ≤ 105) — the number of segments. Next n lines contain the descriptions of the segments. The i-th line contains two space-separated integers li, ri (1 ≤ li ≤ ri ≤ 109) — the borders of the i-th segment.
It is guaranteed that no two segments coincide.
Output
Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1.
The segments are numbered starting from 1 in the order in which they appear in the input.
Examples
Input
3
1 1
2 2
3 3
Output
-1
Input
6
1 5
2 3
1 10
7 10
7 7
10 10
Output
3
Submitted Solution:
```
n = int(input())
a = []
mn = 1e9
mx = -1e9
for i in range(n):
l, r = map(int, input().split())
a.append([l, r])
mn = min(l, mn)
mx = max(r, mx)
for i in range(n):
if a[i][0] == mn and a[i][1] == mx:
print(i + 1)
exit(0)
print(-1)
``` | instruction | 0 | 26,821 | 23 | 53,642 |
Yes | output | 1 | 26,821 | 23 | 53,643 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A coordinate line has n segments, the i-th segment starts at the position li and ends at the position ri. We will denote such a segment as [li, ri].
You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all other ones. Now you want to test your assumption. Find in the given set the segment which covers all other segments, and print its number. If such a segment doesn't exist, print -1.
Formally we will assume that segment [a, b] covers segment [c, d], if they meet this condition a ≤ c ≤ d ≤ b.
Input
The first line contains integer n (1 ≤ n ≤ 105) — the number of segments. Next n lines contain the descriptions of the segments. The i-th line contains two space-separated integers li, ri (1 ≤ li ≤ ri ≤ 109) — the borders of the i-th segment.
It is guaranteed that no two segments coincide.
Output
Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1.
The segments are numbered starting from 1 in the order in which they appear in the input.
Examples
Input
3
1 1
2 2
3 3
Output
-1
Input
6
1 5
2 3
1 10
7 10
7 7
10 10
Output
3
Submitted Solution:
```
n = int(input())
segs = [list(map(int, input().split())) for _ in range(n)]
l = 99999999999999999
r = 0
for s in segs:
l = min(l, s[0])
r = max(r, s[1])
for i, s in enumerate(segs):
if s[0] == l and s[1] == r:
print(i + 1)
break
else:
print('-1')
``` | instruction | 0 | 26,822 | 23 | 53,644 |
Yes | output | 1 | 26,822 | 23 | 53,645 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A coordinate line has n segments, the i-th segment starts at the position li and ends at the position ri. We will denote such a segment as [li, ri].
You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all other ones. Now you want to test your assumption. Find in the given set the segment which covers all other segments, and print its number. If such a segment doesn't exist, print -1.
Formally we will assume that segment [a, b] covers segment [c, d], if they meet this condition a ≤ c ≤ d ≤ b.
Input
The first line contains integer n (1 ≤ n ≤ 105) — the number of segments. Next n lines contain the descriptions of the segments. The i-th line contains two space-separated integers li, ri (1 ≤ li ≤ ri ≤ 109) — the borders of the i-th segment.
It is guaranteed that no two segments coincide.
Output
Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1.
The segments are numbered starting from 1 in the order in which they appear in the input.
Examples
Input
3
1 1
2 2
3 3
Output
-1
Input
6
1 5
2 3
1 10
7 10
7 7
10 10
Output
3
Submitted Solution:
```
z=[]
n=int(input())
c1=1000000000
c2=0
for x in range(n):
p,q=map(int,input().split())
if p<c1:c1=p
if q>c2:c2=q
z.append([p,q])
for x in range(n):
if z[x][0]==c1 and z[x][1]==c2:
print(x+1)
break
else:print(-1)
``` | instruction | 0 | 26,823 | 23 | 53,646 |
Yes | output | 1 | 26,823 | 23 | 53,647 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A coordinate line has n segments, the i-th segment starts at the position li and ends at the position ri. We will denote such a segment as [li, ri].
You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all other ones. Now you want to test your assumption. Find in the given set the segment which covers all other segments, and print its number. If such a segment doesn't exist, print -1.
Formally we will assume that segment [a, b] covers segment [c, d], if they meet this condition a ≤ c ≤ d ≤ b.
Input
The first line contains integer n (1 ≤ n ≤ 105) — the number of segments. Next n lines contain the descriptions of the segments. The i-th line contains two space-separated integers li, ri (1 ≤ li ≤ ri ≤ 109) — the borders of the i-th segment.
It is guaranteed that no two segments coincide.
Output
Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1.
The segments are numbered starting from 1 in the order in which they appear in the input.
Examples
Input
3
1 1
2 2
3 3
Output
-1
Input
6
1 5
2 3
1 10
7 10
7 7
10 10
Output
3
Submitted Solution:
```
num_segment = int(input())
segment_list = []
for i in range(num_segment):
a = input()
a = list(map(int, a.split()))
segment_list.append(a)
min_val = segment_list[0][0]
max_val = segment_list[0][1]
result = -1
for segment in segment_list:
if segment[0] <= min_val and segment[1] >= max_val:
min_val = segment[0]
max_val = segment[1]
result = segment_list.index(segment) + 1
print(result)
``` | instruction | 0 | 26,824 | 23 | 53,648 |
No | output | 1 | 26,824 | 23 | 53,649 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A coordinate line has n segments, the i-th segment starts at the position li and ends at the position ri. We will denote such a segment as [li, ri].
You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all other ones. Now you want to test your assumption. Find in the given set the segment which covers all other segments, and print its number. If such a segment doesn't exist, print -1.
Formally we will assume that segment [a, b] covers segment [c, d], if they meet this condition a ≤ c ≤ d ≤ b.
Input
The first line contains integer n (1 ≤ n ≤ 105) — the number of segments. Next n lines contain the descriptions of the segments. The i-th line contains two space-separated integers li, ri (1 ≤ li ≤ ri ≤ 109) — the borders of the i-th segment.
It is guaranteed that no two segments coincide.
Output
Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1.
The segments are numbered starting from 1 in the order in which they appear in the input.
Examples
Input
3
1 1
2 2
3 3
Output
-1
Input
6
1 5
2 3
1 10
7 10
7 7
10 10
Output
3
Submitted Solution:
```
n=int(input())
prel,prei=0,0
l=[]
for i in range(n):
s,i=map(int,input().split())
l.append([s,i])
ans=1
prel,prei=l[0][0],l[0][1]
for i in range(1,n):
if l[i][0]<=prel and l[i][1]>=prei:
prel,prei=l[i][0],l[i][1]
ans=i+1
t=False
for i in range(n):
if i==ans-1:
continue
if l[i][0]>=l[ans-1][0] and l[i][1]<=l[ans-1][1]:
t=True
if t:
print(ans)
else:
print(-1)
``` | instruction | 0 | 26,825 | 23 | 53,650 |
No | output | 1 | 26,825 | 23 | 53,651 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A coordinate line has n segments, the i-th segment starts at the position li and ends at the position ri. We will denote such a segment as [li, ri].
You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all other ones. Now you want to test your assumption. Find in the given set the segment which covers all other segments, and print its number. If such a segment doesn't exist, print -1.
Formally we will assume that segment [a, b] covers segment [c, d], if they meet this condition a ≤ c ≤ d ≤ b.
Input
The first line contains integer n (1 ≤ n ≤ 105) — the number of segments. Next n lines contain the descriptions of the segments. The i-th line contains two space-separated integers li, ri (1 ≤ li ≤ ri ≤ 109) — the borders of the i-th segment.
It is guaranteed that no two segments coincide.
Output
Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1.
The segments are numbered starting from 1 in the order in which they appear in the input.
Examples
Input
3
1 1
2 2
3 3
Output
-1
Input
6
1 5
2 3
1 10
7 10
7 7
10 10
Output
3
Submitted Solution:
```
def check_cover(_l, _r, _n):
min_left, max_right = _l[0], _r[0]
pos = -2
for i in range(1, n):
if _l[i] < min_left:
min_left = _l[i]
if _r[i] >= max_right:
pos = i
max_right = _r[i]
else:
pos = -2
elif _r[i] > max_right:
max_right = _r[i]
if _l[i] <= min_left:
pos = i
min_left = _l[i]
else:
pos = -2
return pos + 1
n = int(input())
l, r = [], []
for i in range(n):
li, ri = map(int, input().split())
l.append(li)
r.append(ri)
print(check_cover(l, r, n))
``` | instruction | 0 | 26,826 | 23 | 53,652 |
No | output | 1 | 26,826 | 23 | 53,653 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A coordinate line has n segments, the i-th segment starts at the position li and ends at the position ri. We will denote such a segment as [li, ri].
You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all other ones. Now you want to test your assumption. Find in the given set the segment which covers all other segments, and print its number. If such a segment doesn't exist, print -1.
Formally we will assume that segment [a, b] covers segment [c, d], if they meet this condition a ≤ c ≤ d ≤ b.
Input
The first line contains integer n (1 ≤ n ≤ 105) — the number of segments. Next n lines contain the descriptions of the segments. The i-th line contains two space-separated integers li, ri (1 ≤ li ≤ ri ≤ 109) — the borders of the i-th segment.
It is guaranteed that no two segments coincide.
Output
Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1.
The segments are numbered starting from 1 in the order in which they appear in the input.
Examples
Input
3
1 1
2 2
3 3
Output
-1
Input
6
1 5
2 3
1 10
7 10
7 7
10 10
Output
3
Submitted Solution:
```
def BigSegment(n, a):
min1 = a[0][0]
max1 = a[0][1]
for i in range(len(a)):
print(a[i][0])
if a[i][0] < min1:
min1 = a[i][0]
if a[i][1] > max1:
max1 = a[i][1]
b = []
b.append(min1)
b.append(max1)
if b in a:
return a.index(b)+1
else:
return -1
n = int(input())
a = []
for i in range(n):
b = [int(x) for x in input().split()]
a.append(b)
print(BigSegment(n, a))
``` | instruction | 0 | 26,827 | 23 | 53,654 |
No | output | 1 | 26,827 | 23 | 53,655 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya writes his own library for building graphical user interface. Vasya called his creation VTK (VasyaToolKit). One of the interesting aspects of this library is that widgets are packed in each other.
A widget is some element of graphical interface. Each widget has width and height, and occupies some rectangle on the screen. Any widget in Vasya's library is of type Widget. For simplicity we will identify the widget and its type.
Types HBox and VBox are derivatives of type Widget, so they also are types Widget. Widgets HBox and VBox are special. They can store other widgets. Both those widgets can use the pack() method to pack directly in itself some other widget. Widgets of types HBox and VBox can store several other widgets, even several equal widgets — they will simply appear several times. As a result of using the method pack() only the link to the packed widget is saved, that is when the packed widget is changed, its image in the widget, into which it is packed, will also change.
We shall assume that the widget a is packed in the widget b if there exists a chain of widgets a = c1, c2, ..., ck = b, k ≥ 2, for which ci is packed directly to ci + 1 for any 1 ≤ i < k. In Vasya's library the situation when the widget a is packed in the widget a (that is, in itself) is not allowed. If you try to pack the widgets into each other in this manner immediately results in an error.
Also, the widgets HBox and VBox have parameters border and spacing, which are determined by the methods set_border() and set_spacing() respectively. By default both of these options equal 0.
<image>
The picture above shows how the widgets are packed into HBox and VBox. At that HBox and VBox automatically change their size depending on the size of packed widgets. As for HBox and VBox, they only differ in that in HBox the widgets are packed horizontally and in VBox — vertically. The parameter spacing sets the distance between adjacent widgets, and border — a frame around all packed widgets of the desired width. Packed widgets are placed exactly in the order in which the pack() method was called for them. If within HBox or VBox there are no packed widgets, their sizes are equal to 0 × 0, regardless of the options border and spacing.
The construction of all the widgets is performed using a scripting language VasyaScript. The description of the language can be found in the input data.
For the final verification of the code Vasya asks you to write a program that calculates the sizes of all the widgets on the source code in the language of VasyaScript.
Input
The first line contains an integer n — the number of instructions (1 ≤ n ≤ 100). Next n lines contain instructions in the language VasyaScript — one instruction per line. There is a list of possible instructions below.
* "Widget [name]([x],[y])" — create a new widget [name] of the type Widget possessing the width of [x] units and the height of [y] units.
* "HBox [name]" — create a new widget [name] of the type HBox.
* "VBox [name]" — create a new widget [name] of the type VBox.
* "[name1].pack([name2])" — pack the widget [name2] in the widget [name1]. At that, the widget [name1] must be of type HBox or VBox.
* "[name].set_border([x])" — set for a widget [name] the border parameter to [x] units. The widget [name] must be of type HBox or VBox.
* "[name].set_spacing([x])" — set for a widget [name] the spacing parameter to [x] units. The widget [name] must be of type HBox or VBox.
All instructions are written without spaces at the beginning and at the end of the string. The words inside the instruction are separated by exactly one space. There are no spaces directly before the numbers and directly after them.
The case matters, for example, "wiDget x" is not a correct instruction. The case of the letters is correct in the input data.
All names of the widgets consist of lowercase Latin letters and has the length from 1 to 10 characters inclusive. The names of all widgets are pairwise different. All numbers in the script are integers from 0 to 100 inclusive
It is guaranteed that the above-given script is correct, that is that all the operations with the widgets take place after the widgets are created and no widget is packed in itself. It is guaranteed that the script creates at least one widget.
Output
For each widget print on a single line its name, width and height, separated by spaces. The lines must be ordered lexicographically by a widget's name.
Please, do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use cout stream (also you may use %I64d specificator)
Examples
Input
12
Widget me(50,40)
VBox grandpa
HBox father
grandpa.pack(father)
father.pack(me)
grandpa.set_border(10)
grandpa.set_spacing(20)
Widget brother(30,60)
father.pack(brother)
Widget friend(20,60)
Widget uncle(100,20)
grandpa.pack(uncle)
Output
brother 30 60
father 80 60
friend 20 60
grandpa 120 120
me 50 40
uncle 100 20
Input
15
Widget pack(10,10)
HBox dummy
HBox x
VBox y
y.pack(dummy)
y.set_border(5)
y.set_spacing(55)
dummy.set_border(10)
dummy.set_spacing(20)
x.set_border(10)
x.set_spacing(10)
x.pack(pack)
x.pack(dummy)
x.pack(pack)
x.set_border(0)
Output
dummy 0 0
pack 10 10
x 40 10
y 10 10
Note
In the first sample the widgets are arranged as follows:
<image>
Submitted Solution:
```
n = int(input())
space = 2 * n
for i in range(n + 1):
s = []
for j in range(i):
s.append(j)
print(space * ' ', end='')
print(*s, i, *s[::-1])
space -= 2
space = 2
for i in range(n - 1, -1, -1):
s = []
for j in range(i):
s.append(j)
print(space * ' ', end='')
print(*s, i, *s[::-1])
space += 2
``` | instruction | 0 | 27,090 | 23 | 54,180 |
No | output | 1 | 27,090 | 23 | 54,181 |
Provide a correct Python 3 solution for this coding contest problem.
Two circles A, B are given on a two-dimensional plane. The coordinate of the center and radius of circle A is (x_A, y_A) and r_A respectively. The coordinate of the center and radius of circle B is (x_B, y_B) and r_B respectively. These two circles have no intersection inside. Here, we consider a set of circles S that satisfies the following conditions.
* Each circle in S touches both A and B, and does not have common points with them inside the circle.
* Any two different circles in S have no common points inside them.
Write a program that finds the maximum number of elements in S.
Constraints
* 1 \leq T \leq 50000
* -10^5 \leq x_A \leq 10^5
* -10^5 \leq y_A \leq 10^5
* -10^5 \leq x_B \leq 10^5
* -10^5 \leq y_B \leq 10^5
* 1 \leq r_A \leq 10^5
* 1 \leq r_B \leq 10^5
* {r_A}^2 + {r_B}^2 < (x_A - x_B)^2 + (y_A - y_B)^2
* All values given as input are integers.
* It is guaranteed that, when the radiuses of A and B change by 0.0005, the answer does not change.
Input
The input consists of multiple test cases and is given from Standard Input in the following format:
T
testcase_1
:
testcase_T
Each test case is given with the following format.
x_A y_A r_A x_B y_B r_B
Output
The output consists of T lines. On line i (1 \leq i \leq T), putput the maximum number of elements in S in i-th test case.
Example
Input
4
0 -3 2 0 3 2
0 0 9 8 8 2
0 0 9 10 10 5
0 0 707 1000 1000 707
Output
3
10
21
180 | instruction | 0 | 27,282 | 23 | 54,564 |
"Correct Solution:
```
import sys
input = sys.stdin.readline
sys.setrecursionlimit(10 ** 7)
import math
# 反転で同心円に帰着する
T = int(input())
query = [[int(x) for x in input().split()] for _ in range(T)]
def solve_2_eq(a,b,c):
return (-b + (b*b-4*a*c)**.5) / (2*a)
def F(r,R,d):
# 複比
ratio = ((d+r+R)*(d-R-r)) / (4*r*R)
R = solve_2_eq(1,-2-4*ratio, 1)
# 内側の円が1, 外側の円が半径Rであるような同心円に帰着
r = (R-1)/2
theta = math.asin(r/(1+r))
return int(math.pi // theta)
answer = []
for data in query:
d = ((data[3]-data[0])**2 + (data[4]-data[1])**2) ** .5
answer.append(str(F(data[2],data[5],d)))
print('\n'.join(answer))
``` | output | 1 | 27,282 | 23 | 54,565 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that outputs the surface area S of a square cone with a height of h, with a square with one side x as the base. However, assume that the line segment connecting the apex and the center of the base is orthogonal to the base. Also, x and h are positive integers less than or equal to 100.
Input
Given multiple datasets. Each dataset is given in the following format:
x
h
When both x and h are 0, it indicates the end of input.
Output
Output S (real number) on one line for each data set. The output may contain an error of 0.00001 or less.
Example
Input
6
4
7
9
0
0
Output
96.000000
184.192455 | instruction | 0 | 27,283 | 23 | 54,566 |
"Correct Solution:
```
import math
while True:
x = float(input())
h = float(input())
if x==h==0: break
f = math.hypot(1/2*x,h)
S = x**2 + 4*f*x/2
print(S)
``` | output | 1 | 27,283 | 23 | 54,567 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that outputs the surface area S of a square cone with a height of h, with a square with one side x as the base. However, assume that the line segment connecting the apex and the center of the base is orthogonal to the base. Also, x and h are positive integers less than or equal to 100.
Input
Given multiple datasets. Each dataset is given in the following format:
x
h
When both x and h are 0, it indicates the end of input.
Output
Output S (real number) on one line for each data set. The output may contain an error of 0.00001 or less.
Example
Input
6
4
7
9
0
0
Output
96.000000
184.192455 | instruction | 0 | 27,284 | 23 | 54,568 |
"Correct Solution:
```
import sys
import math
def main():
for line in sys.stdin:
x = int(line)
h = int(input())
if x != 0 and h != 0:
s1 = x * math.sqrt(4 * (h ** 2) + x ** 2)
s2 = s1 + x ** 2
print("{:.6f}".format(s2))
else:
break
if __name__ == "__main__":
main()
``` | output | 1 | 27,284 | 23 | 54,569 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that outputs the surface area S of a square cone with a height of h, with a square with one side x as the base. However, assume that the line segment connecting the apex and the center of the base is orthogonal to the base. Also, x and h are positive integers less than or equal to 100.
Input
Given multiple datasets. Each dataset is given in the following format:
x
h
When both x and h are 0, it indicates the end of input.
Output
Output S (real number) on one line for each data set. The output may contain an error of 0.00001 or less.
Example
Input
6
4
7
9
0
0
Output
96.000000
184.192455 | instruction | 0 | 27,285 | 23 | 54,570 |
"Correct Solution:
```
import math
while True:
x = int(input())
h = int(input())
if x == 0 and h == 0:
break
x = float(x)
h = float(h)
y = math.sqrt(h**2 + x**2/4.0)
print(x**2 + 2.0*x*y)
``` | output | 1 | 27,285 | 23 | 54,571 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that outputs the surface area S of a square cone with a height of h, with a square with one side x as the base. However, assume that the line segment connecting the apex and the center of the base is orthogonal to the base. Also, x and h are positive integers less than or equal to 100.
Input
Given multiple datasets. Each dataset is given in the following format:
x
h
When both x and h are 0, it indicates the end of input.
Output
Output S (real number) on one line for each data set. The output may contain an error of 0.00001 or less.
Example
Input
6
4
7
9
0
0
Output
96.000000
184.192455 | instruction | 0 | 27,286 | 23 | 54,572 |
"Correct Solution:
```
while True:
x = int(input())
h = int(input())
if x == 0 and h == 0:break
s = x ** 2 + x * (4 * h ** 2 + x ** 2) ** (1 / 2)
print(s)
``` | output | 1 | 27,286 | 23 | 54,573 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that outputs the surface area S of a square cone with a height of h, with a square with one side x as the base. However, assume that the line segment connecting the apex and the center of the base is orthogonal to the base. Also, x and h are positive integers less than or equal to 100.
Input
Given multiple datasets. Each dataset is given in the following format:
x
h
When both x and h are 0, it indicates the end of input.
Output
Output S (real number) on one line for each data set. The output may contain an error of 0.00001 or less.
Example
Input
6
4
7
9
0
0
Output
96.000000
184.192455 | instruction | 0 | 27,287 | 23 | 54,574 |
"Correct Solution:
```
while True:
x = float(input())
h = float(input())
if x + h == 0: break
S = 0
a = ((x / 2) ** 2 + h ** 2) ** 0.5
S += x * x
S += (a * x * 0.5) * 4
print(S)
``` | output | 1 | 27,287 | 23 | 54,575 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that outputs the surface area S of a square cone with a height of h, with a square with one side x as the base. However, assume that the line segment connecting the apex and the center of the base is orthogonal to the base. Also, x and h are positive integers less than or equal to 100.
Input
Given multiple datasets. Each dataset is given in the following format:
x
h
When both x and h are 0, it indicates the end of input.
Output
Output S (real number) on one line for each data set. The output may contain an error of 0.00001 or less.
Example
Input
6
4
7
9
0
0
Output
96.000000
184.192455 | instruction | 0 | 27,288 | 23 | 54,576 |
"Correct Solution:
```
import math
while True:
x = int(input())
h = int(input())
if x == 0 and h == 0:
break
S = 1/2 * x * 4*(1/4 * x**2 + h**2)**0.5 + x**2
print(S)
``` | output | 1 | 27,288 | 23 | 54,577 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that outputs the surface area S of a square cone with a height of h, with a square with one side x as the base. However, assume that the line segment connecting the apex and the center of the base is orthogonal to the base. Also, x and h are positive integers less than or equal to 100.
Input
Given multiple datasets. Each dataset is given in the following format:
x
h
When both x and h are 0, it indicates the end of input.
Output
Output S (real number) on one line for each data set. The output may contain an error of 0.00001 or less.
Example
Input
6
4
7
9
0
0
Output
96.000000
184.192455 | instruction | 0 | 27,289 | 23 | 54,578 |
"Correct Solution:
```
import math
while True:
x = int(input())
h = int(input())
if x == 0 and h == 0: break
h2 = math.sqrt((x/2)*(x/2) + h*h)
print(float(x*x + 2*x*h2))
``` | output | 1 | 27,289 | 23 | 54,579 |
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