message stringlengths 2 44.5k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 276 109k | cluster float64 23 23 | __index_level_0__ int64 552 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two segments [l_1; r_1] and [l_2; r_2] on the x-axis. It is guaranteed that l_1 < r_1 and l_2 < r_2. Segments may intersect, overlap or even coincide with each other.
<image> The example of two segments on the x-axis.
Your problem is to find two integers a and b such that l_1 ≤ a ≤ r_1, l_2 ≤ b ≤ r_2 and a ≠ b. In other words, you have to choose two distinct integer points in such a way that the first point belongs to the segment [l_1; r_1] and the second one belongs to the segment [l_2; r_2].
It is guaranteed that the answer exists. If there are multiple answers, you can print any of them.
You have to answer q independent queries.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 500) — the number of queries.
Each of the next q lines contains four integers l_{1_i}, r_{1_i}, l_{2_i} and r_{2_i} (1 ≤ l_{1_i}, r_{1_i}, l_{2_i}, r_{2_i} ≤ 10^9, l_{1_i} < r_{1_i}, l_{2_i} < r_{2_i}) — the ends of the segments in the i-th query.
Output
Print 2q integers. For the i-th query print two integers a_i and b_i — such numbers that l_{1_i} ≤ a_i ≤ r_{1_i}, l_{2_i} ≤ b_i ≤ r_{2_i} and a_i ≠ b_i. Queries are numbered in order of the input.
It is guaranteed that the answer exists. If there are multiple answers, you can print any.
Example
Input
5
1 2 1 2
2 6 3 4
2 4 1 3
1 2 1 3
1 4 5 8
Output
2 1
3 4
3 2
1 2
3 7
Submitted Solution:
```
n = int(input())
lista = [input().split() for _ in range(n)]
output = []
a = b = 0
for query in lista:
l1,r1,l2,r2 = query[0],query[1],query[2],query[3]
if r1 <= l2:
a = int(l1)
b = int(r2)
print(a,b)
elif l1 == l2 and r1 == r2:
a = int(l1)
b = int(r1)
print(a,b)
else:
a = int(l1)
b = int(r2)
print(a,b)
``` | instruction | 0 | 84,283 | 23 | 168,566 |
No | output | 1 | 84,283 | 23 | 168,567 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two segments [l_1; r_1] and [l_2; r_2] on the x-axis. It is guaranteed that l_1 < r_1 and l_2 < r_2. Segments may intersect, overlap or even coincide with each other.
<image> The example of two segments on the x-axis.
Your problem is to find two integers a and b such that l_1 ≤ a ≤ r_1, l_2 ≤ b ≤ r_2 and a ≠ b. In other words, you have to choose two distinct integer points in such a way that the first point belongs to the segment [l_1; r_1] and the second one belongs to the segment [l_2; r_2].
It is guaranteed that the answer exists. If there are multiple answers, you can print any of them.
You have to answer q independent queries.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 500) — the number of queries.
Each of the next q lines contains four integers l_{1_i}, r_{1_i}, l_{2_i} and r_{2_i} (1 ≤ l_{1_i}, r_{1_i}, l_{2_i}, r_{2_i} ≤ 10^9, l_{1_i} < r_{1_i}, l_{2_i} < r_{2_i}) — the ends of the segments in the i-th query.
Output
Print 2q integers. For the i-th query print two integers a_i and b_i — such numbers that l_{1_i} ≤ a_i ≤ r_{1_i}, l_{2_i} ≤ b_i ≤ r_{2_i} and a_i ≠ b_i. Queries are numbered in order of the input.
It is guaranteed that the answer exists. If there are multiple answers, you can print any.
Example
Input
5
1 2 1 2
2 6 3 4
2 4 1 3
1 2 1 3
1 4 5 8
Output
2 1
3 4
3 2
1 2
3 7
Submitted Solution:
```
n=int(input())
for i in range(n):
a,b,c,d=map(int,input().split())
print(a,d)
``` | instruction | 0 | 84,284 | 23 | 168,568 |
No | output | 1 | 84,284 | 23 | 168,569 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an interactive problem.
Khanh has n points on the Cartesian plane, denoted by a_1, a_2, …, a_n. All points' coordinates are integers between -10^9 and 10^9, inclusive. No three points are collinear. He says that these points are vertices of a convex polygon; in other words, there exists a permutation p_1, p_2, …, p_n of integers from 1 to n such that the polygon a_{p_1} a_{p_2} … a_{p_n} is convex and vertices are listed in counter-clockwise order.
Khanh gives you the number n, but hides the coordinates of his points. Your task is to guess the above permutation by asking multiple queries. In each query, you give Khanh 4 integers t, i, j, k; where either t = 1 or t = 2; and i, j, k are three distinct indices from 1 to n, inclusive. In response, Khanh tells you:
* if t = 1, the area of the triangle a_ia_ja_k multiplied by 2.
* if t = 2, the sign of the cross product of two vectors \overrightarrow{a_ia_j} and \overrightarrow{a_ia_k}.
Recall that the cross product of vector \overrightarrow{a} = (x_a, y_a) and vector \overrightarrow{b} = (x_b, y_b) is the integer x_a ⋅ y_b - x_b ⋅ y_a. The sign of a number is 1 it it is positive, and -1 otherwise. It can be proven that the cross product obtained in the above queries can not be 0.
You can ask at most 3 ⋅ n queries.
Please note that Khanh fixes the coordinates of his points and does not change it while answering your queries. You do not need to guess the coordinates. In your permutation a_{p_1}a_{p_2}… a_{p_n}, p_1 should be equal to 1 and the indices of vertices should be listed in counter-clockwise order.
Interaction
You start the interaction by reading n (3 ≤ n ≤ 1 000) — the number of vertices.
To ask a query, write 4 integers t, i, j, k (1 ≤ t ≤ 2, 1 ≤ i, j, k ≤ n) in a separate line. i, j and k should be distinct.
Then read a single integer to get the answer to this query, as explained above. It can be proven that the answer of a query is always an integer.
When you find the permutation, write a number 0. Then write n integers p_1, p_2, …, p_n in the same line.
After printing a query do not forget to output end of line and flush the output. Otherwise, you will get Idleness limit exceeded. To do this, use:
* fflush(stdout) or cout.flush() in C++;
* System.out.flush() in Java;
* flush(output) in Pascal;
* stdout.flush() in Python;
* see documentation for other languages.
Hack format
To hack, use the following format:
The first line contains an integer n (3 ≤ n ≤ 1 000) — the number of vertices.
The i-th of the next n lines contains two integers x_i and y_i (-10^9 ≤ x_i, y_i ≤ 10^9) — the coordinate of the point a_i.
Example
Input
6
15
-1
1
Output
1 1 4 6
2 1 5 6
2 2 1 4
0 1 3 4 2 6 5
Note
The image below shows the hidden polygon in the example:
<image>
The interaction in the example goes as below:
* Contestant reads n = 6.
* Contestant asks a query with t = 1, i = 1, j = 4, k = 6.
* Jury answers 15. The area of the triangle A_1A_4A_6 is 7.5. Note that the answer is two times the area of the triangle.
* Contestant asks a query with t = 2, i = 1, j = 5, k = 6.
* Jury answers -1. The cross product of \overrightarrow{A_1A_5} = (2, 2) and \overrightarrow{A_1A_6} = (4, 1) is -2. The sign of -2 is -1.
* Contestant asks a query with t = 2, i = 2, j = 1, k = 4.
* Jury answers 1. The cross product of \overrightarrow{A_2A_1} = (-5, 2) and \overrightarrow{A_2A_4} = (-2, -1) is 1. The sign of 1 is 1.
* Contestant says that the permutation is (1, 3, 4, 2, 6, 5).
Submitted Solution:
```
def chk(i):
print(2, 1, 2, i)
a = int(input())
print(1, 1, 2, i)
s = int(input())
return (a, s)
def cha(a, b, c):
print(2, a, b, c)
return int(input())
N = int(input())
PO = []
NE = []
for i in range(3, N+1):
a, s = chk(i)
if a > 0:
PO.append((s, i))
else:
NE.append((s, i))
PO = sorted(PO)
NE = sorted(NE)
# print("PO =", PO)
# print("NE =", NE)
P1 = []
P2 = []
N1 = []
N2 = []
if not PO:
pass
else:
i0 = PO.pop()[1]
P1.append(i0)
while PO:
i = PO.pop()[1]
if cha(1, i0, i) > 0:
P1.append(i)
else:
P2.append(i)
i0 = NE.pop()[1]
N1.append(i0)
while NE:
i = NE.pop()[1]
if cha(1, i0, i) < 0:
N1.append(i)
else:
N2.append(i)
ANS = [0] + [1] + N1[::-1] + N2 + [2] + P2[::-1] + P1
print(*ANS)
``` | instruction | 0 | 84,339 | 23 | 168,678 |
No | output | 1 | 84,339 | 23 | 168,679 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an interactive problem.
Khanh has n points on the Cartesian plane, denoted by a_1, a_2, …, a_n. All points' coordinates are integers between -10^9 and 10^9, inclusive. No three points are collinear. He says that these points are vertices of a convex polygon; in other words, there exists a permutation p_1, p_2, …, p_n of integers from 1 to n such that the polygon a_{p_1} a_{p_2} … a_{p_n} is convex and vertices are listed in counter-clockwise order.
Khanh gives you the number n, but hides the coordinates of his points. Your task is to guess the above permutation by asking multiple queries. In each query, you give Khanh 4 integers t, i, j, k; where either t = 1 or t = 2; and i, j, k are three distinct indices from 1 to n, inclusive. In response, Khanh tells you:
* if t = 1, the area of the triangle a_ia_ja_k multiplied by 2.
* if t = 2, the sign of the cross product of two vectors \overrightarrow{a_ia_j} and \overrightarrow{a_ia_k}.
Recall that the cross product of vector \overrightarrow{a} = (x_a, y_a) and vector \overrightarrow{b} = (x_b, y_b) is the integer x_a ⋅ y_b - x_b ⋅ y_a. The sign of a number is 1 it it is positive, and -1 otherwise. It can be proven that the cross product obtained in the above queries can not be 0.
You can ask at most 3 ⋅ n queries.
Please note that Khanh fixes the coordinates of his points and does not change it while answering your queries. You do not need to guess the coordinates. In your permutation a_{p_1}a_{p_2}… a_{p_n}, p_1 should be equal to 1 and the indices of vertices should be listed in counter-clockwise order.
Interaction
You start the interaction by reading n (3 ≤ n ≤ 1 000) — the number of vertices.
To ask a query, write 4 integers t, i, j, k (1 ≤ t ≤ 2, 1 ≤ i, j, k ≤ n) in a separate line. i, j and k should be distinct.
Then read a single integer to get the answer to this query, as explained above. It can be proven that the answer of a query is always an integer.
When you find the permutation, write a number 0. Then write n integers p_1, p_2, …, p_n in the same line.
After printing a query do not forget to output end of line and flush the output. Otherwise, you will get Idleness limit exceeded. To do this, use:
* fflush(stdout) or cout.flush() in C++;
* System.out.flush() in Java;
* flush(output) in Pascal;
* stdout.flush() in Python;
* see documentation for other languages.
Hack format
To hack, use the following format:
The first line contains an integer n (3 ≤ n ≤ 1 000) — the number of vertices.
The i-th of the next n lines contains two integers x_i and y_i (-10^9 ≤ x_i, y_i ≤ 10^9) — the coordinate of the point a_i.
Example
Input
6
15
-1
1
Output
1 1 4 6
2 1 5 6
2 2 1 4
0 1 3 4 2 6 5
Note
The image below shows the hidden polygon in the example:
<image>
The interaction in the example goes as below:
* Contestant reads n = 6.
* Contestant asks a query with t = 1, i = 1, j = 4, k = 6.
* Jury answers 15. The area of the triangle A_1A_4A_6 is 7.5. Note that the answer is two times the area of the triangle.
* Contestant asks a query with t = 2, i = 1, j = 5, k = 6.
* Jury answers -1. The cross product of \overrightarrow{A_1A_5} = (2, 2) and \overrightarrow{A_1A_6} = (4, 1) is -2. The sign of -2 is -1.
* Contestant asks a query with t = 2, i = 2, j = 1, k = 4.
* Jury answers 1. The cross product of \overrightarrow{A_2A_1} = (-5, 2) and \overrightarrow{A_2A_4} = (-2, -1) is 1. The sign of 1 is 1.
* Contestant says that the permutation is (1, 3, 4, 2, 6, 5).
Submitted Solution:
```
import bisect
import sys
input = sys.stdin.readline
n = int(input())
up = []
down = []
for i in range(2, n):
# 問い合わせる
print(2, 1, i, n)
# 問い合わせた後はflushする
sys.stdout.flush()
# 入力を受け取る
tmp = int(input())
if tmp == -1:
up.append(i)
else:
down.append(i)
up2 = []
down2 = []
for i in up:
# 問い合わせる
print(1, 1, i, n)
# 問い合わせた後はflushする
sys.stdout.flush()
# 入力を受け取る
s = int(input())
up2.append((s, i))
for i in down:
# 問い合わせる
print(1, 1, i, n)
# 問い合わせた後はflushする
sys.stdout.flush()
# 入力を受け取る
s = int(input())
down2.append((s, i))
up2 = sorted(up2)
down2 = sorted(down2)
ans1 = [1]
ans2 = []
ans3 = [n]
ans4 = []
ans = []
if up2:
k = up2[-1][1]
for i in range(len(up2) - 1):
num = up2[i][1]
# 問い合わせる
print(2, 1, num, k)
# 問い合わせた後はflushする
sys.stdout.flush()
# 入力を受け取る
tmp = int(input())
if tmp == -1:
ans1.append(num)
else:
ans2.append(num)
ans += ans1 + [k] + ans2[::-1]
else:
ans += ans1
if down2:
l = down2[-1][1]
for i in range(len(down2) - 1):
num = down2[i][1]
# 問い合わせる
print(2, n, num, l)
# 問い合わせた後はflushする
sys.stdout.flush()
# 入力を受け取る
tmp = int(input())
if tmp == -1:
ans3.append(num)
else:
ans4.append(num)
ans += ans3 + [l] + ans4[::-1]
else:
ans += ans3
print(0, *ans[::-1])
``` | instruction | 0 | 84,340 | 23 | 168,680 |
No | output | 1 | 84,340 | 23 | 168,681 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an interactive problem.
Khanh has n points on the Cartesian plane, denoted by a_1, a_2, …, a_n. All points' coordinates are integers between -10^9 and 10^9, inclusive. No three points are collinear. He says that these points are vertices of a convex polygon; in other words, there exists a permutation p_1, p_2, …, p_n of integers from 1 to n such that the polygon a_{p_1} a_{p_2} … a_{p_n} is convex and vertices are listed in counter-clockwise order.
Khanh gives you the number n, but hides the coordinates of his points. Your task is to guess the above permutation by asking multiple queries. In each query, you give Khanh 4 integers t, i, j, k; where either t = 1 or t = 2; and i, j, k are three distinct indices from 1 to n, inclusive. In response, Khanh tells you:
* if t = 1, the area of the triangle a_ia_ja_k multiplied by 2.
* if t = 2, the sign of the cross product of two vectors \overrightarrow{a_ia_j} and \overrightarrow{a_ia_k}.
Recall that the cross product of vector \overrightarrow{a} = (x_a, y_a) and vector \overrightarrow{b} = (x_b, y_b) is the integer x_a ⋅ y_b - x_b ⋅ y_a. The sign of a number is 1 it it is positive, and -1 otherwise. It can be proven that the cross product obtained in the above queries can not be 0.
You can ask at most 3 ⋅ n queries.
Please note that Khanh fixes the coordinates of his points and does not change it while answering your queries. You do not need to guess the coordinates. In your permutation a_{p_1}a_{p_2}… a_{p_n}, p_1 should be equal to 1 and the indices of vertices should be listed in counter-clockwise order.
Interaction
You start the interaction by reading n (3 ≤ n ≤ 1 000) — the number of vertices.
To ask a query, write 4 integers t, i, j, k (1 ≤ t ≤ 2, 1 ≤ i, j, k ≤ n) in a separate line. i, j and k should be distinct.
Then read a single integer to get the answer to this query, as explained above. It can be proven that the answer of a query is always an integer.
When you find the permutation, write a number 0. Then write n integers p_1, p_2, …, p_n in the same line.
After printing a query do not forget to output end of line and flush the output. Otherwise, you will get Idleness limit exceeded. To do this, use:
* fflush(stdout) or cout.flush() in C++;
* System.out.flush() in Java;
* flush(output) in Pascal;
* stdout.flush() in Python;
* see documentation for other languages.
Hack format
To hack, use the following format:
The first line contains an integer n (3 ≤ n ≤ 1 000) — the number of vertices.
The i-th of the next n lines contains two integers x_i and y_i (-10^9 ≤ x_i, y_i ≤ 10^9) — the coordinate of the point a_i.
Example
Input
6
15
-1
1
Output
1 1 4 6
2 1 5 6
2 2 1 4
0 1 3 4 2 6 5
Note
The image below shows the hidden polygon in the example:
<image>
The interaction in the example goes as below:
* Contestant reads n = 6.
* Contestant asks a query with t = 1, i = 1, j = 4, k = 6.
* Jury answers 15. The area of the triangle A_1A_4A_6 is 7.5. Note that the answer is two times the area of the triangle.
* Contestant asks a query with t = 2, i = 1, j = 5, k = 6.
* Jury answers -1. The cross product of \overrightarrow{A_1A_5} = (2, 2) and \overrightarrow{A_1A_6} = (4, 1) is -2. The sign of -2 is -1.
* Contestant asks a query with t = 2, i = 2, j = 1, k = 4.
* Jury answers 1. The cross product of \overrightarrow{A_2A_1} = (-5, 2) and \overrightarrow{A_2A_4} = (-2, -1) is 1. The sign of 1 is 1.
* Contestant says that the permutation is (1, 3, 4, 2, 6, 5).
Submitted Solution:
```
mod = 1000000007
eps = 10**-9
def main():
import sys
input = sys.stdin.readline
def ask(t, i, j, k):
print(t, i, j, k)
sys.stdout.flush()
N = int(input())
p1 = 1
p2 = 2
for k in range(3, N+1):
ask(2, 1, p2, k)
flg = int(input())
if flg == -1:
p2 = k
SK = []
for k in range(2, N+1):
if k == p2:
continue
ask(1, 1, p2, k)
S = int(input())
SK.append((S, k))
SK.sort(key=lambda x: x[0])
pmax = SK[-1][1]
p_first = []
p_second = []
for S, k in SK[:-1]:
ask(2, 1, pmax, k)
flg = int(input())
if flg == -1:
p_second.append((S, k))
else:
p_first.append((S, k))
p_first.sort(key=lambda x: x[0])
p_second.sort(key=lambda x: x[0], reverse=True)
ans = [0, 1, p2]
for _, p in p_first:
ans.append(p)
ans.append(pmax)
for _, p in p_second:
ans.append(p)
print(*ans)
sys.stdout.flush()
if __name__ == '__main__':
main()
``` | instruction | 0 | 84,341 | 23 | 168,682 |
No | output | 1 | 84,341 | 23 | 168,683 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an interactive problem.
Khanh has n points on the Cartesian plane, denoted by a_1, a_2, …, a_n. All points' coordinates are integers between -10^9 and 10^9, inclusive. No three points are collinear. He says that these points are vertices of a convex polygon; in other words, there exists a permutation p_1, p_2, …, p_n of integers from 1 to n such that the polygon a_{p_1} a_{p_2} … a_{p_n} is convex and vertices are listed in counter-clockwise order.
Khanh gives you the number n, but hides the coordinates of his points. Your task is to guess the above permutation by asking multiple queries. In each query, you give Khanh 4 integers t, i, j, k; where either t = 1 or t = 2; and i, j, k are three distinct indices from 1 to n, inclusive. In response, Khanh tells you:
* if t = 1, the area of the triangle a_ia_ja_k multiplied by 2.
* if t = 2, the sign of the cross product of two vectors \overrightarrow{a_ia_j} and \overrightarrow{a_ia_k}.
Recall that the cross product of vector \overrightarrow{a} = (x_a, y_a) and vector \overrightarrow{b} = (x_b, y_b) is the integer x_a ⋅ y_b - x_b ⋅ y_a. The sign of a number is 1 it it is positive, and -1 otherwise. It can be proven that the cross product obtained in the above queries can not be 0.
You can ask at most 3 ⋅ n queries.
Please note that Khanh fixes the coordinates of his points and does not change it while answering your queries. You do not need to guess the coordinates. In your permutation a_{p_1}a_{p_2}… a_{p_n}, p_1 should be equal to 1 and the indices of vertices should be listed in counter-clockwise order.
Interaction
You start the interaction by reading n (3 ≤ n ≤ 1 000) — the number of vertices.
To ask a query, write 4 integers t, i, j, k (1 ≤ t ≤ 2, 1 ≤ i, j, k ≤ n) in a separate line. i, j and k should be distinct.
Then read a single integer to get the answer to this query, as explained above. It can be proven that the answer of a query is always an integer.
When you find the permutation, write a number 0. Then write n integers p_1, p_2, …, p_n in the same line.
After printing a query do not forget to output end of line and flush the output. Otherwise, you will get Idleness limit exceeded. To do this, use:
* fflush(stdout) or cout.flush() in C++;
* System.out.flush() in Java;
* flush(output) in Pascal;
* stdout.flush() in Python;
* see documentation for other languages.
Hack format
To hack, use the following format:
The first line contains an integer n (3 ≤ n ≤ 1 000) — the number of vertices.
The i-th of the next n lines contains two integers x_i and y_i (-10^9 ≤ x_i, y_i ≤ 10^9) — the coordinate of the point a_i.
Example
Input
6
15
-1
1
Output
1 1 4 6
2 1 5 6
2 2 1 4
0 1 3 4 2 6 5
Note
The image below shows the hidden polygon in the example:
<image>
The interaction in the example goes as below:
* Contestant reads n = 6.
* Contestant asks a query with t = 1, i = 1, j = 4, k = 6.
* Jury answers 15. The area of the triangle A_1A_4A_6 is 7.5. Note that the answer is two times the area of the triangle.
* Contestant asks a query with t = 2, i = 1, j = 5, k = 6.
* Jury answers -1. The cross product of \overrightarrow{A_1A_5} = (2, 2) and \overrightarrow{A_1A_6} = (4, 1) is -2. The sign of -2 is -1.
* Contestant asks a query with t = 2, i = 2, j = 1, k = 4.
* Jury answers 1. The cross product of \overrightarrow{A_2A_1} = (-5, 2) and \overrightarrow{A_2A_4} = (-2, -1) is 1. The sign of 1 is 1.
* Contestant says that the permutation is (1, 3, 4, 2, 6, 5).
Submitted Solution:
```
import bisect
import sys
input = sys.stdin.readline
n = int(input())
up = []
down = []
print(2, 1, 3, n)
sys.stdout.flush()
tmp = int(input())
print(tmp)
``` | instruction | 0 | 84,342 | 23 | 168,684 |
No | output | 1 | 84,342 | 23 | 168,685 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a rectangular grid with n rows and m columns. The cell located on the i-th row from the top and the j-th column from the left has a value a_{ij} written in it.
You can perform the following operation any number of times (possibly zero):
* Choose any two adjacent cells and multiply the values in them by -1. Two cells are called adjacent if they share a side.
Note that you can use a cell more than once in different operations.
You are interested in X, the sum of all the numbers in the grid.
What is the maximum X you can achieve with these operations?
Input
Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100). Description of the test cases follows.
The first line of each test case contains two integers n,m (2 ≤ n, m ≤ 10).
The following n lines contain m integers each, the j-th element in the i-th line is a_{ij} (-100≤ a_{ij}≤ 100).
Output
For each testcase, print one integer X, the maximum possible sum of all the values in the grid after applying the operation as many times as you want.
Example
Input
2
2 2
-1 1
1 1
3 4
0 -1 -2 -3
-1 -2 -3 -4
-2 -3 -4 -5
Output
2
30
Note
In the first test case, there will always be at least one -1, so the answer is 2.
In the second test case, we can use the operation six times to elements adjacent horizontally and get all numbers to be non-negative. So the answer is: 2× 1 + 3×2 + 3× 3 + 2× 4 + 1× 5 = 30. | instruction | 0 | 84,428 | 23 | 168,856 |
Tags: greedy, math
Correct Solution:
```
T = int(input())
for _ in range(T):
N, M = map(int, input().split())
g = [list(map(int, input().split())) for _ in range(N)]
c = sum([sum([int(n < 0) for n in g[i]]) for i in range(N)])
S = sum([sum([abs(n) for n in g[i]]) for i in range(N)])
M = min([min([abs(n) for n in g[i]]) for i in range(N)])
if ~c & 1: print(S)
else: print(S - 2 * abs(M))
``` | output | 1 | 84,428 | 23 | 168,857 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a rectangular grid with n rows and m columns. The cell located on the i-th row from the top and the j-th column from the left has a value a_{ij} written in it.
You can perform the following operation any number of times (possibly zero):
* Choose any two adjacent cells and multiply the values in them by -1. Two cells are called adjacent if they share a side.
Note that you can use a cell more than once in different operations.
You are interested in X, the sum of all the numbers in the grid.
What is the maximum X you can achieve with these operations?
Input
Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100). Description of the test cases follows.
The first line of each test case contains two integers n,m (2 ≤ n, m ≤ 10).
The following n lines contain m integers each, the j-th element in the i-th line is a_{ij} (-100≤ a_{ij}≤ 100).
Output
For each testcase, print one integer X, the maximum possible sum of all the values in the grid after applying the operation as many times as you want.
Example
Input
2
2 2
-1 1
1 1
3 4
0 -1 -2 -3
-1 -2 -3 -4
-2 -3 -4 -5
Output
2
30
Note
In the first test case, there will always be at least one -1, so the answer is 2.
In the second test case, we can use the operation six times to elements adjacent horizontally and get all numbers to be non-negative. So the answer is: 2× 1 + 3×2 + 3× 3 + 2× 4 + 1× 5 = 30. | instruction | 0 | 84,430 | 23 | 168,860 |
Tags: greedy, math
Correct Solution:
```
t = int(input())
for i in range(t):
n,m = [int(j) for j in input().split()]
l = []
temp = []
zero = 0
for j in range(n):
l.append([int(k) for k in input().split()])
for k in range(m):
temp.append(abs(l[-1][k]))
if (l[-1][k]==0):
zero+=1
sum = 0
neg = 0
for j in range(n):
for k in range(m):
sum +=abs(l[j][k])
if (l[j][k]<0):
neg+=1
if (zero or neg==0):
print (sum)
else:
temp.sort()
sum1 = 0
for j in range(n*m):
sum1 = temp[j] + sum1
if (neg%2 == 0):
print (sum1)
else:
print (sum1 - (2*temp[0]))
``` | output | 1 | 84,430 | 23 | 168,861 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a rectangular grid with n rows and m columns. The cell located on the i-th row from the top and the j-th column from the left has a value a_{ij} written in it.
You can perform the following operation any number of times (possibly zero):
* Choose any two adjacent cells and multiply the values in them by -1. Two cells are called adjacent if they share a side.
Note that you can use a cell more than once in different operations.
You are interested in X, the sum of all the numbers in the grid.
What is the maximum X you can achieve with these operations?
Input
Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100). Description of the test cases follows.
The first line of each test case contains two integers n,m (2 ≤ n, m ≤ 10).
The following n lines contain m integers each, the j-th element in the i-th line is a_{ij} (-100≤ a_{ij}≤ 100).
Output
For each testcase, print one integer X, the maximum possible sum of all the values in the grid after applying the operation as many times as you want.
Example
Input
2
2 2
-1 1
1 1
3 4
0 -1 -2 -3
-1 -2 -3 -4
-2 -3 -4 -5
Output
2
30
Note
In the first test case, there will always be at least one -1, so the answer is 2.
In the second test case, we can use the operation six times to elements adjacent horizontally and get all numbers to be non-negative. So the answer is: 2× 1 + 3×2 + 3× 3 + 2× 4 + 1× 5 = 30. | instruction | 0 | 84,431 | 23 | 168,862 |
Tags: greedy, math
Correct Solution:
```
import os
import sys
from io import BytesIO, IOBase
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline()
# ------------------------------
def RL(): return map(int, sys.stdin.readline().split())
def RLL(): return list(map(int, sys.stdin.readline().split()))
def N(): return int(input())
def print_list(l):
print(' '.join(map(str,l)))
# sys.setrecursionlimit(100000)
# from heapq import *
# from collections import deque as dq
# from math import ceil,floor,sqrt,pow,gcd,log
import bisect as bs
# from collections import Counter
# from collections import defaultdict as dc
# from functools import reduce
# from functools import lru_cache
for _ in range(N()):
n,m = RL()
d = []
for _ in range(n):
d+=RLL()
d.sort()
t = bs.bisect_right(d,0)
res = sum(d[t:])-sum(d[:t])
if t&1:
if t<n*m:
res-=2*min(-d[t-1],d[t])
else:
res+=2*d[-1]
print(res)
``` | output | 1 | 84,431 | 23 | 168,863 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a rectangular grid with n rows and m columns. The cell located on the i-th row from the top and the j-th column from the left has a value a_{ij} written in it.
You can perform the following operation any number of times (possibly zero):
* Choose any two adjacent cells and multiply the values in them by -1. Two cells are called adjacent if they share a side.
Note that you can use a cell more than once in different operations.
You are interested in X, the sum of all the numbers in the grid.
What is the maximum X you can achieve with these operations?
Input
Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100). Description of the test cases follows.
The first line of each test case contains two integers n,m (2 ≤ n, m ≤ 10).
The following n lines contain m integers each, the j-th element in the i-th line is a_{ij} (-100≤ a_{ij}≤ 100).
Output
For each testcase, print one integer X, the maximum possible sum of all the values in the grid after applying the operation as many times as you want.
Example
Input
2
2 2
-1 1
1 1
3 4
0 -1 -2 -3
-1 -2 -3 -4
-2 -3 -4 -5
Output
2
30
Note
In the first test case, there will always be at least one -1, so the answer is 2.
In the second test case, we can use the operation six times to elements adjacent horizontally and get all numbers to be non-negative. So the answer is: 2× 1 + 3×2 + 3× 3 + 2× 4 + 1× 5 = 30. | instruction | 0 | 84,434 | 23 | 168,868 |
Tags: greedy, math
Correct Solution:
```
from sys import stdout, stdin, setrecursionlimit
from io import BytesIO, IOBase
from collections import *
from itertools import *
# from random import *
from bisect import *
from string import *
from queue import *
from heapq import *
from math import *
from re import *
from os import *
####################################---fast-input-output----#########################################
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = read(self._fd, max(fstat(self._fd).st_size, 8192))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = read(self._fd, max(fstat(self._fd).st_size, 8192))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
stdin, stdout = IOWrapper(stdin), IOWrapper(stdout)
graph, mod, szzz = {}, 10**9 + 7, lambda: sorted(zzz())
def getStr(): return input()
def getInt(): return int(input())
def listStr(): return list(input())
def getStrs(): return input().split()
def isInt(s): return '0' <= s[0] <= '9'
def input(): return stdin.readline().strip()
def zzz(): return [int(i) for i in input().split()]
def output(answer, end='\n'): stdout.write(str(answer) + end)
def lcd(xnum1, xnum2): return (xnum1 * xnum2 // gcd(xnum1, xnum2))
dx = [-1, 1, 0, 0, 1, -1, 1, -1]
dy = [0, 0, 1, -1, 1, -1, -1, 1]
daysInMounth = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
#################################################---Some Rule For Me To Follow---#################################
"""
--instants of Reading problem continuously try to understand them.
--If you Know some-one , Then you probably don't know him !
--Try & again try
"""
##################################################---START-CODING---###############################################
num = getInt()
for _ in range(num):
n,m=zzz()
s=0
mn= float('inf')
neg = 0
for j in range(n):
arr = zzz()
for i in arr:
s+=abs(i)
if i<0:
neg+=1
mn = min(mn,abs(i))
print(s-2*mn if neg%2 else s)
``` | output | 1 | 84,434 | 23 | 168,869 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a rectangular grid with n rows and m columns. The cell located on the i-th row from the top and the j-th column from the left has a value a_{ij} written in it.
You can perform the following operation any number of times (possibly zero):
* Choose any two adjacent cells and multiply the values in them by -1. Two cells are called adjacent if they share a side.
Note that you can use a cell more than once in different operations.
You are interested in X, the sum of all the numbers in the grid.
What is the maximum X you can achieve with these operations?
Input
Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100). Description of the test cases follows.
The first line of each test case contains two integers n,m (2 ≤ n, m ≤ 10).
The following n lines contain m integers each, the j-th element in the i-th line is a_{ij} (-100≤ a_{ij}≤ 100).
Output
For each testcase, print one integer X, the maximum possible sum of all the values in the grid after applying the operation as many times as you want.
Example
Input
2
2 2
-1 1
1 1
3 4
0 -1 -2 -3
-1 -2 -3 -4
-2 -3 -4 -5
Output
2
30
Note
In the first test case, there will always be at least one -1, so the answer is 2.
In the second test case, we can use the operation six times to elements adjacent horizontally and get all numbers to be non-negative. So the answer is: 2× 1 + 3×2 + 3× 3 + 2× 4 + 1× 5 = 30. | instruction | 0 | 84,435 | 23 | 168,870 |
Tags: greedy, math
Correct Solution:
```
for _ in range(int(input())):
n, m = map(int, input().split())
X = 0
M = 100
Y = 0
for i in range(n):
for a in map(int, input().split()):
if a < 0:
X ^= 1
M = min(M, abs(a))
Y += abs(a)
if X:
print(Y - 2 * M)
else:
print(Y)
``` | output | 1 | 84,435 | 23 | 168,871 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a rectangular grid with n rows and m columns. The cell located on the i-th row from the top and the j-th column from the left has a value a_{ij} written in it.
You can perform the following operation any number of times (possibly zero):
* Choose any two adjacent cells and multiply the values in them by -1. Two cells are called adjacent if they share a side.
Note that you can use a cell more than once in different operations.
You are interested in X, the sum of all the numbers in the grid.
What is the maximum X you can achieve with these operations?
Input
Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100). Description of the test cases follows.
The first line of each test case contains two integers n,m (2 ≤ n, m ≤ 10).
The following n lines contain m integers each, the j-th element in the i-th line is a_{ij} (-100≤ a_{ij}≤ 100).
Output
For each testcase, print one integer X, the maximum possible sum of all the values in the grid after applying the operation as many times as you want.
Example
Input
2
2 2
-1 1
1 1
3 4
0 -1 -2 -3
-1 -2 -3 -4
-2 -3 -4 -5
Output
2
30
Note
In the first test case, there will always be at least one -1, so the answer is 2.
In the second test case, we can use the operation six times to elements adjacent horizontally and get all numbers to be non-negative. So the answer is: 2× 1 + 3×2 + 3× 3 + 2× 4 + 1× 5 = 30.
Submitted Solution:
```
#!/usr/bin/python3
if __name__ == "__main__":
for _ in range(int(input())):
n, m = list(map(int, input().split()))
ans, mn = 0, 100
count = 0
for i in range(n):
temp = list(map(int, input().split()))
for elt in temp:
ans += abs(elt)
mn = min(mn, abs(elt))
if( elt < 0 ):
count += 1
if( count%2 == 0 ):
print( ans )
else:
print( ans - 2*mn )
``` | instruction | 0 | 84,436 | 23 | 168,872 |
Yes | output | 1 | 84,436 | 23 | 168,873 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a rectangular grid with n rows and m columns. The cell located on the i-th row from the top and the j-th column from the left has a value a_{ij} written in it.
You can perform the following operation any number of times (possibly zero):
* Choose any two adjacent cells and multiply the values in them by -1. Two cells are called adjacent if they share a side.
Note that you can use a cell more than once in different operations.
You are interested in X, the sum of all the numbers in the grid.
What is the maximum X you can achieve with these operations?
Input
Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100). Description of the test cases follows.
The first line of each test case contains two integers n,m (2 ≤ n, m ≤ 10).
The following n lines contain m integers each, the j-th element in the i-th line is a_{ij} (-100≤ a_{ij}≤ 100).
Output
For each testcase, print one integer X, the maximum possible sum of all the values in the grid after applying the operation as many times as you want.
Example
Input
2
2 2
-1 1
1 1
3 4
0 -1 -2 -3
-1 -2 -3 -4
-2 -3 -4 -5
Output
2
30
Note
In the first test case, there will always be at least one -1, so the answer is 2.
In the second test case, we can use the operation six times to elements adjacent horizontally and get all numbers to be non-negative. So the answer is: 2× 1 + 3×2 + 3× 3 + 2× 4 + 1× 5 = 30.
Submitted Solution:
```
import sys
import bisect as bi
import math
from collections import defaultdict as dd
import queue
##import heapq
import itertools
##import io
##import os
##import operator
input=sys.stdin.readline
##input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
##import random
##sys.setrecursionlimit(10**7)
##fo=open("output2.txt","w")
##fi=open("input2.txt","w")
mo=10**9+7
def cin():return map(int,sin().split())
def ain():return list(map(int,sin().split()))
def sin():return input().strip()
def inin():return int(input())
def pref(a,n,f):
pre=[0]*n
if(f==0): ##from beginning
pre[0]=a[0]
for i in range(1,n):
pre[i]=a[i]+pre[i-1]
else: ##from end
pre[-1]=a[-1]
for i in range(n-2,-1,-1):
pre[i]=pre[i+1]+a[i]
return pre
#-----------------------------------------------------------------------------------------------------------------------#
for _ in range(inin()):
n,m=cin()
mat=[]
for i in range(n):
l=ain()
mat+=[l]
s=0;mi=111111111111135;c=0;f=0
for i in range(n):
for j in range(m):
a=mat[i][j]
if(a==0):f=1
if(mat[i][j]<0):
c+=1
a=abs(a)
s+=a
mi=min(mi,a)
if(c%2 and f==0):
print(s-mi-mi)
else:print(s)
#-----------------------------------------------------------------------------------------------------------------------#
##def msb(n):n|=n>>1;n|=n>>2;n|=n>>4;n|=n>>8;n|=n>>16;n|=n>>32;n|=n>>64;return n-(n>>1) #2 ki power
##def pref(a,n,f):
## pre=[0]*n
## if(f==0): ##from beginning
## pre[0]=a[0]
## for i in range(1,n):
## pre[i]=a[i]+pre[i-1]
## else: ##from end
## pre[-1]=a[-1]
## for i in range(n-2,-1,-1):
## pre[i]=pre[i+1]+a[i]
## return pre
##maxint=10**24
##def kadane(a,size):
## max_so_far = -maxint - 1
## max_ending_here = 0
##
## for i in range(0, size):
## max_ending_here = max_ending_here + a[i]
## if (max_so_far < max_ending_here):
## max_so_far = max_ending_here
##
## if max_ending_here < 0:
## max_ending_here = 0
## return max_so_far
##def modFact(n, p):
## if(n<0):return 0
## if n >= p: return 0
## result = 1
## for i in range(1, n + 1):result = (result * i) % p
## return result
##def ncr(n, r, p):
## if(n<r or n<0): return 0
## num = den = 1
## for i in range(r):
## num = (num * (n - i)) % p ;den = (den * (i + 1)) % p
## return (num * pow(den,p - 2, p)) % p
``` | instruction | 0 | 84,437 | 23 | 168,874 |
Yes | output | 1 | 84,437 | 23 | 168,875 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a rectangular grid with n rows and m columns. The cell located on the i-th row from the top and the j-th column from the left has a value a_{ij} written in it.
You can perform the following operation any number of times (possibly zero):
* Choose any two adjacent cells and multiply the values in them by -1. Two cells are called adjacent if they share a side.
Note that you can use a cell more than once in different operations.
You are interested in X, the sum of all the numbers in the grid.
What is the maximum X you can achieve with these operations?
Input
Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100). Description of the test cases follows.
The first line of each test case contains two integers n,m (2 ≤ n, m ≤ 10).
The following n lines contain m integers each, the j-th element in the i-th line is a_{ij} (-100≤ a_{ij}≤ 100).
Output
For each testcase, print one integer X, the maximum possible sum of all the values in the grid after applying the operation as many times as you want.
Example
Input
2
2 2
-1 1
1 1
3 4
0 -1 -2 -3
-1 -2 -3 -4
-2 -3 -4 -5
Output
2
30
Note
In the first test case, there will always be at least one -1, so the answer is 2.
In the second test case, we can use the operation six times to elements adjacent horizontally and get all numbers to be non-negative. So the answer is: 2× 1 + 3×2 + 3× 3 + 2× 4 + 1× 5 = 30.
Submitted Solution:
```
t = int(input())
for _ in range(t):
n, m = [int(x) for x in input().split()]
a = [[int(x) for x in input().split()] for i in range(n)]
b = 0
sum_ = 0
min_ = 101
for row in range(n):
for column in range(m):
y = a[row][column]
sum_ += abs(y)
if abs(y) < min_:
min_ = abs(y)
if y <= 0:
b += 1
if b % 2 == 0:
print(sum_)
else:
print(sum_ - 2*min_)
``` | instruction | 0 | 84,438 | 23 | 168,876 |
Yes | output | 1 | 84,438 | 23 | 168,877 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a rectangular grid with n rows and m columns. The cell located on the i-th row from the top and the j-th column from the left has a value a_{ij} written in it.
You can perform the following operation any number of times (possibly zero):
* Choose any two adjacent cells and multiply the values in them by -1. Two cells are called adjacent if they share a side.
Note that you can use a cell more than once in different operations.
You are interested in X, the sum of all the numbers in the grid.
What is the maximum X you can achieve with these operations?
Input
Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100). Description of the test cases follows.
The first line of each test case contains two integers n,m (2 ≤ n, m ≤ 10).
The following n lines contain m integers each, the j-th element in the i-th line is a_{ij} (-100≤ a_{ij}≤ 100).
Output
For each testcase, print one integer X, the maximum possible sum of all the values in the grid after applying the operation as many times as you want.
Example
Input
2
2 2
-1 1
1 1
3 4
0 -1 -2 -3
-1 -2 -3 -4
-2 -3 -4 -5
Output
2
30
Note
In the first test case, there will always be at least one -1, so the answer is 2.
In the second test case, we can use the operation six times to elements adjacent horizontally and get all numbers to be non-negative. So the answer is: 2× 1 + 3×2 + 3× 3 + 2× 4 + 1× 5 = 30.
Submitted Solution:
```
import sys
max_int = 1000000001 # 10^9+1
min_int = -max_int
t = int(input())
for _t in range(t):
min_abs = max_int
sum_abs = 0
neg_count = 0
rows, cols = map(int, sys.stdin.readline().split())
for i in range(rows):
row = map(int, sys.stdin.readline().split())
for one in row:
if one <= 0:
neg_count += 1
min_abs = min(min_abs, abs(one))
sum_abs += abs(one)
if neg_count % 2:
print(sum_abs - 2 * min_abs)
else:
print(sum_abs)
``` | instruction | 0 | 84,439 | 23 | 168,878 |
Yes | output | 1 | 84,439 | 23 | 168,879 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a rectangular grid with n rows and m columns. The cell located on the i-th row from the top and the j-th column from the left has a value a_{ij} written in it.
You can perform the following operation any number of times (possibly zero):
* Choose any two adjacent cells and multiply the values in them by -1. Two cells are called adjacent if they share a side.
Note that you can use a cell more than once in different operations.
You are interested in X, the sum of all the numbers in the grid.
What is the maximum X you can achieve with these operations?
Input
Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100). Description of the test cases follows.
The first line of each test case contains two integers n,m (2 ≤ n, m ≤ 10).
The following n lines contain m integers each, the j-th element in the i-th line is a_{ij} (-100≤ a_{ij}≤ 100).
Output
For each testcase, print one integer X, the maximum possible sum of all the values in the grid after applying the operation as many times as you want.
Example
Input
2
2 2
-1 1
1 1
3 4
0 -1 -2 -3
-1 -2 -3 -4
-2 -3 -4 -5
Output
2
30
Note
In the first test case, there will always be at least one -1, so the answer is 2.
In the second test case, we can use the operation six times to elements adjacent horizontally and get all numbers to be non-negative. So the answer is: 2× 1 + 3×2 + 3× 3 + 2× 4 + 1× 5 = 30.
Submitted Solution:
```
def count_negative(matrix):
count = 0
for i in range(len(matrix)):
for j in range(len(matrix[0])):
count += (matrix[i][j] <= 0)
return count
def matrix_sum(matrix):
summa = 0
for i in range(len(matrix)):
for j in range(len(matrix[0])):
summa += abs(matrix[i][j])
return summa
def matrix_min(matrix):
minimum = matrix[0][0]
for i in range(len(matrix)):
for j in range(len(matrix[0])):
minimum = minimum if matrix[i][j] > minimum else matrix[i][j]
return minimum
matrices = []
length = int(input())
for _ in range(length):
n, m = map(int, input().split())
matrix = []
for i in range(n):
matrix.append(list(map(int, input().split())))
matrices.append(matrix)
for matrix in matrices:
delta = 0 if count_negative(matrix) % 2 == 0 else 2 * abs(matrix_min(matrix))
print(matrix_sum(matrix) - delta)
``` | instruction | 0 | 84,440 | 23 | 168,880 |
No | output | 1 | 84,440 | 23 | 168,881 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a rectangular grid with n rows and m columns. The cell located on the i-th row from the top and the j-th column from the left has a value a_{ij} written in it.
You can perform the following operation any number of times (possibly zero):
* Choose any two adjacent cells and multiply the values in them by -1. Two cells are called adjacent if they share a side.
Note that you can use a cell more than once in different operations.
You are interested in X, the sum of all the numbers in the grid.
What is the maximum X you can achieve with these operations?
Input
Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100). Description of the test cases follows.
The first line of each test case contains two integers n,m (2 ≤ n, m ≤ 10).
The following n lines contain m integers each, the j-th element in the i-th line is a_{ij} (-100≤ a_{ij}≤ 100).
Output
For each testcase, print one integer X, the maximum possible sum of all the values in the grid after applying the operation as many times as you want.
Example
Input
2
2 2
-1 1
1 1
3 4
0 -1 -2 -3
-1 -2 -3 -4
-2 -3 -4 -5
Output
2
30
Note
In the first test case, there will always be at least one -1, so the answer is 2.
In the second test case, we can use the operation six times to elements adjacent horizontally and get all numbers to be non-negative. So the answer is: 2× 1 + 3×2 + 3× 3 + 2× 4 + 1× 5 = 30.
Submitted Solution:
```
N = int(input())
for _ in range(N):
n,m = map(int,input().split())
a = list()
for i in range(n):
a += list(map(int,input().split()))
a.sort()
maxNegative = 0
countNegative = 0
for i in range(len(a)):
if a[i] < 0:
countNegative += 1
a[i] = -a[i]
if maxNegative == 0:
maxNegative = a[i]
if countNegative % 2 == 1:
print(sum(a) - maxNegative*2)
else:
print(sum(a))
``` | instruction | 0 | 84,441 | 23 | 168,882 |
No | output | 1 | 84,441 | 23 | 168,883 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a rectangular grid with n rows and m columns. The cell located on the i-th row from the top and the j-th column from the left has a value a_{ij} written in it.
You can perform the following operation any number of times (possibly zero):
* Choose any two adjacent cells and multiply the values in them by -1. Two cells are called adjacent if they share a side.
Note that you can use a cell more than once in different operations.
You are interested in X, the sum of all the numbers in the grid.
What is the maximum X you can achieve with these operations?
Input
Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100). Description of the test cases follows.
The first line of each test case contains two integers n,m (2 ≤ n, m ≤ 10).
The following n lines contain m integers each, the j-th element in the i-th line is a_{ij} (-100≤ a_{ij}≤ 100).
Output
For each testcase, print one integer X, the maximum possible sum of all the values in the grid after applying the operation as many times as you want.
Example
Input
2
2 2
-1 1
1 1
3 4
0 -1 -2 -3
-1 -2 -3 -4
-2 -3 -4 -5
Output
2
30
Note
In the first test case, there will always be at least one -1, so the answer is 2.
In the second test case, we can use the operation six times to elements adjacent horizontally and get all numbers to be non-negative. So the answer is: 2× 1 + 3×2 + 3× 3 + 2× 4 + 1× 5 = 30.
Submitted Solution:
```
def count_negative(matrix):
count = 0
for i in range(len(matrix)):
for j in range(len(matrix[0])):
count += (matrix[i][j] < 0)
return count
def matrix_sum(matrix):
summa = 0
for i in range(len(matrix)):
for j in range(len(matrix[0])):
summa += abs(matrix[i][j])
return summa
def matrix_min(matrix):
minimum = 0
for i in range(len(matrix)):
for j in range(len(matrix[0])):
minimum = minimum if matrix[i][j] > minimum else matrix[i][j]
return minimum
matrices = []
length = int(input())
for _ in range(length):
n, m = map(int, input().split())
matrix = []
for i in range(n):
matrix.append(list(map(int, input().split())))
matrices.append(matrix)
for matrix in matrices:
delta = 0 if count_negative(matrix) == 0 else 2 * abs(matrix_min(matrix))
print(matrix_sum(matrix) - delta)
``` | instruction | 0 | 84,442 | 23 | 168,884 |
No | output | 1 | 84,442 | 23 | 168,885 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a rectangular grid with n rows and m columns. The cell located on the i-th row from the top and the j-th column from the left has a value a_{ij} written in it.
You can perform the following operation any number of times (possibly zero):
* Choose any two adjacent cells and multiply the values in them by -1. Two cells are called adjacent if they share a side.
Note that you can use a cell more than once in different operations.
You are interested in X, the sum of all the numbers in the grid.
What is the maximum X you can achieve with these operations?
Input
Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100). Description of the test cases follows.
The first line of each test case contains two integers n,m (2 ≤ n, m ≤ 10).
The following n lines contain m integers each, the j-th element in the i-th line is a_{ij} (-100≤ a_{ij}≤ 100).
Output
For each testcase, print one integer X, the maximum possible sum of all the values in the grid after applying the operation as many times as you want.
Example
Input
2
2 2
-1 1
1 1
3 4
0 -1 -2 -3
-1 -2 -3 -4
-2 -3 -4 -5
Output
2
30
Note
In the first test case, there will always be at least one -1, so the answer is 2.
In the second test case, we can use the operation six times to elements adjacent horizontally and get all numbers to be non-negative. So the answer is: 2× 1 + 3×2 + 3× 3 + 2× 4 + 1× 5 = 30.
Submitted Solution:
```
t=int(input())
ansl=[]
for i in range(t):
n,m=map(int,input().split())
totl=[]
for i in range(n):
templ=list(map(int,input().split()))
totl.append(templ[:])
suml=0
for i in totl:
negatives=0
for e in i:
if e<0:
negatives+=1
if negatives%2==0:
for a in i:
suml+=abs(a)
else:
for a in i:
i[i.index(a)]=abs(a)
suml+=sum(i)
suml-=2*min(i)
ansl.append(suml)
for i in ansl:
print(i)
``` | instruction | 0 | 84,443 | 23 | 168,886 |
No | output | 1 | 84,443 | 23 | 168,887 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vanya has a table consisting of 100 rows, each row contains 100 cells. The rows are numbered by integers from 1 to 100 from bottom to top, the columns are numbered from 1 to 100 from left to right.
In this table, Vanya chose n rectangles with sides that go along borders of squares (some rectangles probably occur multiple times). After that for each cell of the table he counted the number of rectangles it belongs to and wrote this number into it. Now he wants to find the sum of values in all cells of the table and as the table is too large, he asks you to help him find the result.
Input
The first line contains integer n (1 ≤ n ≤ 100) — the number of rectangles.
Each of the following n lines contains four integers x1, y1, x2, y2 (1 ≤ x1 ≤ x2 ≤ 100, 1 ≤ y1 ≤ y2 ≤ 100), where x1 and y1 are the number of the column and row of the lower left cell and x2 and y2 are the number of the column and row of the upper right cell of a rectangle.
Output
In a single line print the sum of all values in the cells of the table.
Examples
Input
2
1 1 2 3
2 2 3 3
Output
10
Input
2
1 1 3 3
1 1 3 3
Output
18
Note
Note to the first sample test:
Values of the table in the first three rows and columns will be as follows:
121
121
110
So, the sum of values will be equal to 10.
Note to the second sample test:
Values of the table in the first three rows and columns will be as follows:
222
222
222
So, the sum of values will be equal to 18. | instruction | 0 | 84,579 | 23 | 169,158 |
Tags: implementation, math
Correct Solution:
```
n=int(input())
d={}
for i in range(1,101):
for j in range(1,101):
d[(i,j)]=0
for _ in range(n):
x1,y1,x2,y2=map(int,input().split())
for i in range(x1,x2+1):
for j in range(y1,y2+1):
d[(i,j)]+=1
count=0
for i in d:
count+=d[i]
print(count)
``` | output | 1 | 84,579 | 23 | 169,159 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vanya has a table consisting of 100 rows, each row contains 100 cells. The rows are numbered by integers from 1 to 100 from bottom to top, the columns are numbered from 1 to 100 from left to right.
In this table, Vanya chose n rectangles with sides that go along borders of squares (some rectangles probably occur multiple times). After that for each cell of the table he counted the number of rectangles it belongs to and wrote this number into it. Now he wants to find the sum of values in all cells of the table and as the table is too large, he asks you to help him find the result.
Input
The first line contains integer n (1 ≤ n ≤ 100) — the number of rectangles.
Each of the following n lines contains four integers x1, y1, x2, y2 (1 ≤ x1 ≤ x2 ≤ 100, 1 ≤ y1 ≤ y2 ≤ 100), where x1 and y1 are the number of the column and row of the lower left cell and x2 and y2 are the number of the column and row of the upper right cell of a rectangle.
Output
In a single line print the sum of all values in the cells of the table.
Examples
Input
2
1 1 2 3
2 2 3 3
Output
10
Input
2
1 1 3 3
1 1 3 3
Output
18
Note
Note to the first sample test:
Values of the table in the first three rows and columns will be as follows:
121
121
110
So, the sum of values will be equal to 10.
Note to the second sample test:
Values of the table in the first three rows and columns will be as follows:
222
222
222
So, the sum of values will be equal to 18. | instruction | 0 | 84,580 | 23 | 169,160 |
Tags: implementation, math
Correct Solution:
```
n = int(input())
ll = [list(map(int,input().split())) for _ in range(n)]
print(sum([(l[2]-l[0]+1)*(l[3]-l[1]+1) for l in ll]))
``` | output | 1 | 84,580 | 23 | 169,161 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vanya has a table consisting of 100 rows, each row contains 100 cells. The rows are numbered by integers from 1 to 100 from bottom to top, the columns are numbered from 1 to 100 from left to right.
In this table, Vanya chose n rectangles with sides that go along borders of squares (some rectangles probably occur multiple times). After that for each cell of the table he counted the number of rectangles it belongs to and wrote this number into it. Now he wants to find the sum of values in all cells of the table and as the table is too large, he asks you to help him find the result.
Input
The first line contains integer n (1 ≤ n ≤ 100) — the number of rectangles.
Each of the following n lines contains four integers x1, y1, x2, y2 (1 ≤ x1 ≤ x2 ≤ 100, 1 ≤ y1 ≤ y2 ≤ 100), where x1 and y1 are the number of the column and row of the lower left cell and x2 and y2 are the number of the column and row of the upper right cell of a rectangle.
Output
In a single line print the sum of all values in the cells of the table.
Examples
Input
2
1 1 2 3
2 2 3 3
Output
10
Input
2
1 1 3 3
1 1 3 3
Output
18
Note
Note to the first sample test:
Values of the table in the first three rows and columns will be as follows:
121
121
110
So, the sum of values will be equal to 10.
Note to the second sample test:
Values of the table in the first three rows and columns will be as follows:
222
222
222
So, the sum of values will be equal to 18. | instruction | 0 | 84,581 | 23 | 169,162 |
Tags: implementation, math
Correct Solution:
```
def build():
arr = []
for i in range(100):
arr.append([0]*100)
return arr
def solve(arr):
res = build()
for i,v in enumerate(arr):
for row in range(v[2]-(v[0]-1)):
for col in range(v[3]-(v[1]-1)):
res[row][col] += 1
tot = 0
for i in res:
tot += sum(i)
return tot
def main() :
n = int(input())
arr = []
for _ in range(n):
i = list(map(int, input().split(' ')))
arr.append(i)
print(solve(arr))
main()
``` | output | 1 | 84,581 | 23 | 169,163 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vanya has a table consisting of 100 rows, each row contains 100 cells. The rows are numbered by integers from 1 to 100 from bottom to top, the columns are numbered from 1 to 100 from left to right.
In this table, Vanya chose n rectangles with sides that go along borders of squares (some rectangles probably occur multiple times). After that for each cell of the table he counted the number of rectangles it belongs to and wrote this number into it. Now he wants to find the sum of values in all cells of the table and as the table is too large, he asks you to help him find the result.
Input
The first line contains integer n (1 ≤ n ≤ 100) — the number of rectangles.
Each of the following n lines contains four integers x1, y1, x2, y2 (1 ≤ x1 ≤ x2 ≤ 100, 1 ≤ y1 ≤ y2 ≤ 100), where x1 and y1 are the number of the column and row of the lower left cell and x2 and y2 are the number of the column and row of the upper right cell of a rectangle.
Output
In a single line print the sum of all values in the cells of the table.
Examples
Input
2
1 1 2 3
2 2 3 3
Output
10
Input
2
1 1 3 3
1 1 3 3
Output
18
Note
Note to the first sample test:
Values of the table in the first three rows and columns will be as follows:
121
121
110
So, the sum of values will be equal to 10.
Note to the second sample test:
Values of the table in the first three rows and columns will be as follows:
222
222
222
So, the sum of values will be equal to 18. | instruction | 0 | 84,582 | 23 | 169,164 |
Tags: implementation, math
Correct Solution:
```
# coding=utf-8
# sys.stdin = open('in.txt')
R = lambda: list(map(int, input().split()))
cnt = [[0 for i in range(101)] for j in range(101)]
n = R()[0]
for _ in range(n):
x1, y1, x2, y2 = R()
for x in range(x1, x2 + 1):
for y in range(y1, y2 + 1):
cnt[x][y] += 1
print(sum(sum(i) for i in cnt))
``` | output | 1 | 84,582 | 23 | 169,165 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vanya has a table consisting of 100 rows, each row contains 100 cells. The rows are numbered by integers from 1 to 100 from bottom to top, the columns are numbered from 1 to 100 from left to right.
In this table, Vanya chose n rectangles with sides that go along borders of squares (some rectangles probably occur multiple times). After that for each cell of the table he counted the number of rectangles it belongs to and wrote this number into it. Now he wants to find the sum of values in all cells of the table and as the table is too large, he asks you to help him find the result.
Input
The first line contains integer n (1 ≤ n ≤ 100) — the number of rectangles.
Each of the following n lines contains four integers x1, y1, x2, y2 (1 ≤ x1 ≤ x2 ≤ 100, 1 ≤ y1 ≤ y2 ≤ 100), where x1 and y1 are the number of the column and row of the lower left cell and x2 and y2 are the number of the column and row of the upper right cell of a rectangle.
Output
In a single line print the sum of all values in the cells of the table.
Examples
Input
2
1 1 2 3
2 2 3 3
Output
10
Input
2
1 1 3 3
1 1 3 3
Output
18
Note
Note to the first sample test:
Values of the table in the first three rows and columns will be as follows:
121
121
110
So, the sum of values will be equal to 10.
Note to the second sample test:
Values of the table in the first three rows and columns will be as follows:
222
222
222
So, the sum of values will be equal to 18. | instruction | 0 | 84,583 | 23 | 169,166 |
Tags: implementation, math
Correct Solution:
```
L=[[0]*100]*100
n=int(input())
for k in range(n):
x1,y1,x2,y2=map(int,input().split())
y=y1
for j in range(y1-1,y2):
for i in range(x1-1,x2):
L[j][i]+=1
suma=0
for k in range(100):
for j in range(100):
suma+=L[k][j]
print(suma//100)
``` | output | 1 | 84,583 | 23 | 169,167 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vanya has a table consisting of 100 rows, each row contains 100 cells. The rows are numbered by integers from 1 to 100 from bottom to top, the columns are numbered from 1 to 100 from left to right.
In this table, Vanya chose n rectangles with sides that go along borders of squares (some rectangles probably occur multiple times). After that for each cell of the table he counted the number of rectangles it belongs to and wrote this number into it. Now he wants to find the sum of values in all cells of the table and as the table is too large, he asks you to help him find the result.
Input
The first line contains integer n (1 ≤ n ≤ 100) — the number of rectangles.
Each of the following n lines contains four integers x1, y1, x2, y2 (1 ≤ x1 ≤ x2 ≤ 100, 1 ≤ y1 ≤ y2 ≤ 100), where x1 and y1 are the number of the column and row of the lower left cell and x2 and y2 are the number of the column and row of the upper right cell of a rectangle.
Output
In a single line print the sum of all values in the cells of the table.
Examples
Input
2
1 1 2 3
2 2 3 3
Output
10
Input
2
1 1 3 3
1 1 3 3
Output
18
Note
Note to the first sample test:
Values of the table in the first three rows and columns will be as follows:
121
121
110
So, the sum of values will be equal to 10.
Note to the second sample test:
Values of the table in the first three rows and columns will be as follows:
222
222
222
So, the sum of values will be equal to 18. | instruction | 0 | 84,584 | 23 | 169,168 |
Tags: implementation, math
Correct Solution:
```
n=int(input())
res=0
for i in range(n):
a,b,c,d=map(int,input().split(' '))
res+=(abs(a-c)+1)*(abs(b-d)+1)
print(res)
``` | output | 1 | 84,584 | 23 | 169,169 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vanya has a table consisting of 100 rows, each row contains 100 cells. The rows are numbered by integers from 1 to 100 from bottom to top, the columns are numbered from 1 to 100 from left to right.
In this table, Vanya chose n rectangles with sides that go along borders of squares (some rectangles probably occur multiple times). After that for each cell of the table he counted the number of rectangles it belongs to and wrote this number into it. Now he wants to find the sum of values in all cells of the table and as the table is too large, he asks you to help him find the result.
Input
The first line contains integer n (1 ≤ n ≤ 100) — the number of rectangles.
Each of the following n lines contains four integers x1, y1, x2, y2 (1 ≤ x1 ≤ x2 ≤ 100, 1 ≤ y1 ≤ y2 ≤ 100), where x1 and y1 are the number of the column and row of the lower left cell and x2 and y2 are the number of the column and row of the upper right cell of a rectangle.
Output
In a single line print the sum of all values in the cells of the table.
Examples
Input
2
1 1 2 3
2 2 3 3
Output
10
Input
2
1 1 3 3
1 1 3 3
Output
18
Note
Note to the first sample test:
Values of the table in the first three rows and columns will be as follows:
121
121
110
So, the sum of values will be equal to 10.
Note to the second sample test:
Values of the table in the first three rows and columns will be as follows:
222
222
222
So, the sum of values will be equal to 18. | instruction | 0 | 84,585 | 23 | 169,170 |
Tags: implementation, math
Correct Solution:
```
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
import time
n = int(input())
ans = 0
for k in range(n):
(x1, y1, x2, y2) = (int(i) for i in input().split())
ans += (x2-x1+1) * ( y2-y1+1)
start = time.time()
print(ans)
finish = time.time()
#print(finish - start)
``` | output | 1 | 84,585 | 23 | 169,171 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vanya has a table consisting of 100 rows, each row contains 100 cells. The rows are numbered by integers from 1 to 100 from bottom to top, the columns are numbered from 1 to 100 from left to right.
In this table, Vanya chose n rectangles with sides that go along borders of squares (some rectangles probably occur multiple times). After that for each cell of the table he counted the number of rectangles it belongs to and wrote this number into it. Now he wants to find the sum of values in all cells of the table and as the table is too large, he asks you to help him find the result.
Input
The first line contains integer n (1 ≤ n ≤ 100) — the number of rectangles.
Each of the following n lines contains four integers x1, y1, x2, y2 (1 ≤ x1 ≤ x2 ≤ 100, 1 ≤ y1 ≤ y2 ≤ 100), where x1 and y1 are the number of the column and row of the lower left cell and x2 and y2 are the number of the column and row of the upper right cell of a rectangle.
Output
In a single line print the sum of all values in the cells of the table.
Examples
Input
2
1 1 2 3
2 2 3 3
Output
10
Input
2
1 1 3 3
1 1 3 3
Output
18
Note
Note to the first sample test:
Values of the table in the first three rows and columns will be as follows:
121
121
110
So, the sum of values will be equal to 10.
Note to the second sample test:
Values of the table in the first three rows and columns will be as follows:
222
222
222
So, the sum of values will be equal to 18. | instruction | 0 | 84,586 | 23 | 169,172 |
Tags: implementation, math
Correct Solution:
```
# In this template you are not required to write code in main
import sys
inf = float("inf")
#sys.setrecursionlimit(1000000)
#from cmath import sqrt
#from collections import deque, Counter, OrderedDict,defaultdict
#from heapq import nsmallest, nlargest, heapify,heappop ,heappush, heapreplace
#from math import ceil,floor,log,sqrt,factorial,pow,pi,gcd
#from bisect import bisect_left,bisect_right
#import numpy as np
abc='abcdefghijklmnopqrstuvwxyz'
abd={'a': 0, 'b': 1, 'c': 2, 'd': 3, 'e': 4, 'f': 5, 'g': 6, 'h': 7, 'i': 8, 'j': 9, 'k': 10, 'l': 11, 'm': 12, 'n': 13, 'o': 14, 'p': 15, 'q': 16, 'r': 17, 's': 18, 't': 19, 'u': 20, 'v': 21, 'w': 22, 'x': 23, 'y': 24, 'z': 25}
mod,MOD=1000000007,998244353
vow=['a','e','i','o','u']
dx,dy=[-1,1,0,0],[0,0,1,-1]
def get_array(): return list(map(int , sys.stdin.readline().strip().split()))
def get_ints(): return map(int, sys.stdin.readline().strip().split())
def input(): return sys.stdin.readline().strip()
mat=[[0 for i in range(100)] for i in range(100)]
n=int(input())
while n>0:
x1,y1,x2,y2=get_ints()
x1=abs(100-x1);x2=abs(100-x2)
y1-=1;y2-=1
mini=min(x1,x2);maxi=max(x1,x2)
for i in range(mini,maxi+1):
for j in range(y1,y2+1):
mat[i][j]+=1
n-=1
total=0
for i in range(100):
for j in range(100):
total+=mat[i][j]
print(total)
``` | output | 1 | 84,586 | 23 | 169,173 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vanya has a table consisting of 100 rows, each row contains 100 cells. The rows are numbered by integers from 1 to 100 from bottom to top, the columns are numbered from 1 to 100 from left to right.
In this table, Vanya chose n rectangles with sides that go along borders of squares (some rectangles probably occur multiple times). After that for each cell of the table he counted the number of rectangles it belongs to and wrote this number into it. Now he wants to find the sum of values in all cells of the table and as the table is too large, he asks you to help him find the result.
Input
The first line contains integer n (1 ≤ n ≤ 100) — the number of rectangles.
Each of the following n lines contains four integers x1, y1, x2, y2 (1 ≤ x1 ≤ x2 ≤ 100, 1 ≤ y1 ≤ y2 ≤ 100), where x1 and y1 are the number of the column and row of the lower left cell and x2 and y2 are the number of the column and row of the upper right cell of a rectangle.
Output
In a single line print the sum of all values in the cells of the table.
Examples
Input
2
1 1 2 3
2 2 3 3
Output
10
Input
2
1 1 3 3
1 1 3 3
Output
18
Note
Note to the first sample test:
Values of the table in the first three rows and columns will be as follows:
121
121
110
So, the sum of values will be equal to 10.
Note to the second sample test:
Values of the table in the first three rows and columns will be as follows:
222
222
222
So, the sum of values will be equal to 18.
Submitted Solution:
```
n = int(input())
ret = 0
for _ in range(n):
x1, y1, x2, y2 = map(int, input().split())
ret += (x2 - x1 + 1) * (y2 - y1 + 1)
print(ret)
``` | instruction | 0 | 84,587 | 23 | 169,174 |
Yes | output | 1 | 84,587 | 23 | 169,175 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vanya has a table consisting of 100 rows, each row contains 100 cells. The rows are numbered by integers from 1 to 100 from bottom to top, the columns are numbered from 1 to 100 from left to right.
In this table, Vanya chose n rectangles with sides that go along borders of squares (some rectangles probably occur multiple times). After that for each cell of the table he counted the number of rectangles it belongs to and wrote this number into it. Now he wants to find the sum of values in all cells of the table and as the table is too large, he asks you to help him find the result.
Input
The first line contains integer n (1 ≤ n ≤ 100) — the number of rectangles.
Each of the following n lines contains four integers x1, y1, x2, y2 (1 ≤ x1 ≤ x2 ≤ 100, 1 ≤ y1 ≤ y2 ≤ 100), where x1 and y1 are the number of the column and row of the lower left cell and x2 and y2 are the number of the column and row of the upper right cell of a rectangle.
Output
In a single line print the sum of all values in the cells of the table.
Examples
Input
2
1 1 2 3
2 2 3 3
Output
10
Input
2
1 1 3 3
1 1 3 3
Output
18
Note
Note to the first sample test:
Values of the table in the first three rows and columns will be as follows:
121
121
110
So, the sum of values will be equal to 10.
Note to the second sample test:
Values of the table in the first three rows and columns will be as follows:
222
222
222
So, the sum of values will be equal to 18.
Submitted Solution:
```
sum=0
for _ in range(int(input())):
a,b,c,d=map(int,input().split())
sum+=(c - a + 1) * (d - b + 1)
print(sum)
``` | instruction | 0 | 84,588 | 23 | 169,176 |
Yes | output | 1 | 84,588 | 23 | 169,177 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vanya has a table consisting of 100 rows, each row contains 100 cells. The rows are numbered by integers from 1 to 100 from bottom to top, the columns are numbered from 1 to 100 from left to right.
In this table, Vanya chose n rectangles with sides that go along borders of squares (some rectangles probably occur multiple times). After that for each cell of the table he counted the number of rectangles it belongs to and wrote this number into it. Now he wants to find the sum of values in all cells of the table and as the table is too large, he asks you to help him find the result.
Input
The first line contains integer n (1 ≤ n ≤ 100) — the number of rectangles.
Each of the following n lines contains four integers x1, y1, x2, y2 (1 ≤ x1 ≤ x2 ≤ 100, 1 ≤ y1 ≤ y2 ≤ 100), where x1 and y1 are the number of the column and row of the lower left cell and x2 and y2 are the number of the column and row of the upper right cell of a rectangle.
Output
In a single line print the sum of all values in the cells of the table.
Examples
Input
2
1 1 2 3
2 2 3 3
Output
10
Input
2
1 1 3 3
1 1 3 3
Output
18
Note
Note to the first sample test:
Values of the table in the first three rows and columns will be as follows:
121
121
110
So, the sum of values will be equal to 10.
Note to the second sample test:
Values of the table in the first three rows and columns will be as follows:
222
222
222
So, the sum of values will be equal to 18.
Submitted Solution:
```
n = int(input())
res = 0
for i in range(n):
x1, y1, x2, y2 = map(int, input().split())
res += (abs(x2 - x1) + 1) * (abs(y2 - y1) + 1)
print(res)
``` | instruction | 0 | 84,589 | 23 | 169,178 |
Yes | output | 1 | 84,589 | 23 | 169,179 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vanya has a table consisting of 100 rows, each row contains 100 cells. The rows are numbered by integers from 1 to 100 from bottom to top, the columns are numbered from 1 to 100 from left to right.
In this table, Vanya chose n rectangles with sides that go along borders of squares (some rectangles probably occur multiple times). After that for each cell of the table he counted the number of rectangles it belongs to and wrote this number into it. Now he wants to find the sum of values in all cells of the table and as the table is too large, he asks you to help him find the result.
Input
The first line contains integer n (1 ≤ n ≤ 100) — the number of rectangles.
Each of the following n lines contains four integers x1, y1, x2, y2 (1 ≤ x1 ≤ x2 ≤ 100, 1 ≤ y1 ≤ y2 ≤ 100), where x1 and y1 are the number of the column and row of the lower left cell and x2 and y2 are the number of the column and row of the upper right cell of a rectangle.
Output
In a single line print the sum of all values in the cells of the table.
Examples
Input
2
1 1 2 3
2 2 3 3
Output
10
Input
2
1 1 3 3
1 1 3 3
Output
18
Note
Note to the first sample test:
Values of the table in the first three rows and columns will be as follows:
121
121
110
So, the sum of values will be equal to 10.
Note to the second sample test:
Values of the table in the first three rows and columns will be as follows:
222
222
222
So, the sum of values will be equal to 18.
Submitted Solution:
```
n = int(input())
ans = 0
for _ in range(n):
x1, y1, x2, y2 = map(int, input().split())
ans += (x2 - x1 + 1) * (y2 - y1 + 1)
print(ans)
``` | instruction | 0 | 84,590 | 23 | 169,180 |
Yes | output | 1 | 84,590 | 23 | 169,181 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vanya has a table consisting of 100 rows, each row contains 100 cells. The rows are numbered by integers from 1 to 100 from bottom to top, the columns are numbered from 1 to 100 from left to right.
In this table, Vanya chose n rectangles with sides that go along borders of squares (some rectangles probably occur multiple times). After that for each cell of the table he counted the number of rectangles it belongs to and wrote this number into it. Now he wants to find the sum of values in all cells of the table and as the table is too large, he asks you to help him find the result.
Input
The first line contains integer n (1 ≤ n ≤ 100) — the number of rectangles.
Each of the following n lines contains four integers x1, y1, x2, y2 (1 ≤ x1 ≤ x2 ≤ 100, 1 ≤ y1 ≤ y2 ≤ 100), where x1 and y1 are the number of the column and row of the lower left cell and x2 and y2 are the number of the column and row of the upper right cell of a rectangle.
Output
In a single line print the sum of all values in the cells of the table.
Examples
Input
2
1 1 2 3
2 2 3 3
Output
10
Input
2
1 1 3 3
1 1 3 3
Output
18
Note
Note to the first sample test:
Values of the table in the first three rows and columns will be as follows:
121
121
110
So, the sum of values will be equal to 10.
Note to the second sample test:
Values of the table in the first three rows and columns will be as follows:
222
222
222
So, the sum of values will be equal to 18.
Submitted Solution:
```
n = int(input())
points = []
for i in range(0, n):
points.append(list(map(int, input().split())))
nrt = 0
for p in points:
nrt += abs(p[3] - p[0] + 1) * abs(p[2] - p[0] + 1)
print(nrt)
``` | instruction | 0 | 84,591 | 23 | 169,182 |
No | output | 1 | 84,591 | 23 | 169,183 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vanya has a table consisting of 100 rows, each row contains 100 cells. The rows are numbered by integers from 1 to 100 from bottom to top, the columns are numbered from 1 to 100 from left to right.
In this table, Vanya chose n rectangles with sides that go along borders of squares (some rectangles probably occur multiple times). After that for each cell of the table he counted the number of rectangles it belongs to and wrote this number into it. Now he wants to find the sum of values in all cells of the table and as the table is too large, he asks you to help him find the result.
Input
The first line contains integer n (1 ≤ n ≤ 100) — the number of rectangles.
Each of the following n lines contains four integers x1, y1, x2, y2 (1 ≤ x1 ≤ x2 ≤ 100, 1 ≤ y1 ≤ y2 ≤ 100), where x1 and y1 are the number of the column and row of the lower left cell and x2 and y2 are the number of the column and row of the upper right cell of a rectangle.
Output
In a single line print the sum of all values in the cells of the table.
Examples
Input
2
1 1 2 3
2 2 3 3
Output
10
Input
2
1 1 3 3
1 1 3 3
Output
18
Note
Note to the first sample test:
Values of the table in the first three rows and columns will be as follows:
121
121
110
So, the sum of values will be equal to 10.
Note to the second sample test:
Values of the table in the first three rows and columns will be as follows:
222
222
222
So, the sum of values will be equal to 18.
Submitted Solution:
```
n = int(input())
points = []
table = [[0]*101] * 101
for i in range(0, n):
points.append(list(map(int, input().split())))
nrt = 0
for p in points:
nrt += (p[3] - p[0] + 1) * (p[2] - p[0] + 1)
print(nrt)
``` | instruction | 0 | 84,592 | 23 | 169,184 |
No | output | 1 | 84,592 | 23 | 169,185 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vanya has a table consisting of 100 rows, each row contains 100 cells. The rows are numbered by integers from 1 to 100 from bottom to top, the columns are numbered from 1 to 100 from left to right.
In this table, Vanya chose n rectangles with sides that go along borders of squares (some rectangles probably occur multiple times). After that for each cell of the table he counted the number of rectangles it belongs to and wrote this number into it. Now he wants to find the sum of values in all cells of the table and as the table is too large, he asks you to help him find the result.
Input
The first line contains integer n (1 ≤ n ≤ 100) — the number of rectangles.
Each of the following n lines contains four integers x1, y1, x2, y2 (1 ≤ x1 ≤ x2 ≤ 100, 1 ≤ y1 ≤ y2 ≤ 100), where x1 and y1 are the number of the column and row of the lower left cell and x2 and y2 are the number of the column and row of the upper right cell of a rectangle.
Output
In a single line print the sum of all values in the cells of the table.
Examples
Input
2
1 1 2 3
2 2 3 3
Output
10
Input
2
1 1 3 3
1 1 3 3
Output
18
Note
Note to the first sample test:
Values of the table in the first three rows and columns will be as follows:
121
121
110
So, the sum of values will be equal to 10.
Note to the second sample test:
Values of the table in the first three rows and columns will be as follows:
222
222
222
So, the sum of values will be equal to 18.
Submitted Solution:
```
n = int(input())
sum = 0
for i in range(n):
x1,y1,x2,y2=map(int,input().split())
sum += (x2-x2+1)*(y2-y1+1)
print(sum)
``` | instruction | 0 | 84,593 | 23 | 169,186 |
No | output | 1 | 84,593 | 23 | 169,187 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vanya has a table consisting of 100 rows, each row contains 100 cells. The rows are numbered by integers from 1 to 100 from bottom to top, the columns are numbered from 1 to 100 from left to right.
In this table, Vanya chose n rectangles with sides that go along borders of squares (some rectangles probably occur multiple times). After that for each cell of the table he counted the number of rectangles it belongs to and wrote this number into it. Now he wants to find the sum of values in all cells of the table and as the table is too large, he asks you to help him find the result.
Input
The first line contains integer n (1 ≤ n ≤ 100) — the number of rectangles.
Each of the following n lines contains four integers x1, y1, x2, y2 (1 ≤ x1 ≤ x2 ≤ 100, 1 ≤ y1 ≤ y2 ≤ 100), where x1 and y1 are the number of the column and row of the lower left cell and x2 and y2 are the number of the column and row of the upper right cell of a rectangle.
Output
In a single line print the sum of all values in the cells of the table.
Examples
Input
2
1 1 2 3
2 2 3 3
Output
10
Input
2
1 1 3 3
1 1 3 3
Output
18
Note
Note to the first sample test:
Values of the table in the first three rows and columns will be as follows:
121
121
110
So, the sum of values will be equal to 10.
Note to the second sample test:
Values of the table in the first three rows and columns will be as follows:
222
222
222
So, the sum of values will be equal to 18.
Submitted Solution:
```
n = int(input())
a = [1]
sum = 0
for i in (0,n):
n = n-1
a = input().split()
a = [int(i) for i in a]
sum = sum + (a[2]-a[0]+1)*(a[3]-a[1]+1)
print(sum)
``` | instruction | 0 | 84,594 | 23 | 169,188 |
No | output | 1 | 84,594 | 23 | 169,189 |
Provide a correct Python 3 solution for this coding contest problem.
In your garden, there is a long and narrow flowerbed that stretches infinitely to the east. You have decided to plant N kinds of flowers in this empty flowerbed. For convenience, we will call these N kinds of flowers Flower 1, 2, …, N. Also, we will call the position that is p centimeters from the west end of the flowerbed Position p.
You will plant Flower i (1 ≤ i ≤ N) as follows: first, plant one at Position w_i, then plant one every d_i centimeters endlessly toward the east. That is, Flower i will be planted at the positions w_i, w_i + d_i, w_i + 2 d_i, … Note that more than one flower may be planted at the same position.
Find the position at which the K-th flower from the west is planted. If more than one flower is planted at the same position, they are counted individually.
Constraints
* 1 ≤ N ≤ 10^5
* 1 ≤ K ≤ 10^9
* 1 ≤ w_i ≤ 10^{18}
* 1 ≤ d_i ≤ 10^9
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N K
w_1 d_1
:
w_N d_N
Output
When the K-th flower from the west is planted at Position X, print the value of X. (The westmost flower is counted as the 1-st flower.)
Examples
Input
2 6
20 10
25 15
Output
50
Input
3 9
10 10
10 10
10 10
Output
30
Input
1 1000000000
1000000000000000000 1000000000
Output
1999999999000000000 | instruction | 0 | 84,880 | 23 | 169,760 |
"Correct Solution:
```
from bisect import bisect
def solve(l, r):
if l > r:
return l
m = (l + r) // 2
j = bisect(flowers, (m, float('inf')))
t = sum((m - w) // d + 1 for w, d in flowers[:j])
if t < k:
l = m + 1
else:
r = m - 1
return solve(l, r)
n, k = map(int, input().split())
flowers = [tuple(map(int, input().split())) for _ in range(n)]
flowers.sort()
print(solve(1, flowers[0][0] + flowers[0][1] * k))
``` | output | 1 | 84,880 | 23 | 169,761 |
Provide a correct Python 3 solution for this coding contest problem.
In your garden, there is a long and narrow flowerbed that stretches infinitely to the east. You have decided to plant N kinds of flowers in this empty flowerbed. For convenience, we will call these N kinds of flowers Flower 1, 2, …, N. Also, we will call the position that is p centimeters from the west end of the flowerbed Position p.
You will plant Flower i (1 ≤ i ≤ N) as follows: first, plant one at Position w_i, then plant one every d_i centimeters endlessly toward the east. That is, Flower i will be planted at the positions w_i, w_i + d_i, w_i + 2 d_i, … Note that more than one flower may be planted at the same position.
Find the position at which the K-th flower from the west is planted. If more than one flower is planted at the same position, they are counted individually.
Constraints
* 1 ≤ N ≤ 10^5
* 1 ≤ K ≤ 10^9
* 1 ≤ w_i ≤ 10^{18}
* 1 ≤ d_i ≤ 10^9
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N K
w_1 d_1
:
w_N d_N
Output
When the K-th flower from the west is planted at Position X, print the value of X. (The westmost flower is counted as the 1-st flower.)
Examples
Input
2 6
20 10
25 15
Output
50
Input
3 9
10 10
10 10
10 10
Output
30
Input
1 1000000000
1000000000000000000 1000000000
Output
1999999999000000000 | instruction | 0 | 84,881 | 23 | 169,762 |
"Correct Solution:
```
import sys
input = sys.stdin.readline
N, K = map(int, input().split())
a = []
for _ in range(N):
w, d = map(int, input().split())
a.append((w, d))
def check(x):
res = 0
for t in a:
w, d = t
res += max(0, x - w) // d + int(x >= w)
return res >= K
ok = 10 ** 19
ng = 0
while ok - ng > 1:
m = (ok + ng) // 2
if check(m): ok = m
else: ng = m
print(ok)
``` | output | 1 | 84,881 | 23 | 169,763 |
Provide a correct Python 3 solution for this coding contest problem.
In your garden, there is a long and narrow flowerbed that stretches infinitely to the east. You have decided to plant N kinds of flowers in this empty flowerbed. For convenience, we will call these N kinds of flowers Flower 1, 2, …, N. Also, we will call the position that is p centimeters from the west end of the flowerbed Position p.
You will plant Flower i (1 ≤ i ≤ N) as follows: first, plant one at Position w_i, then plant one every d_i centimeters endlessly toward the east. That is, Flower i will be planted at the positions w_i, w_i + d_i, w_i + 2 d_i, … Note that more than one flower may be planted at the same position.
Find the position at which the K-th flower from the west is planted. If more than one flower is planted at the same position, they are counted individually.
Constraints
* 1 ≤ N ≤ 10^5
* 1 ≤ K ≤ 10^9
* 1 ≤ w_i ≤ 10^{18}
* 1 ≤ d_i ≤ 10^9
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N K
w_1 d_1
:
w_N d_N
Output
When the K-th flower from the west is planted at Position X, print the value of X. (The westmost flower is counted as the 1-st flower.)
Examples
Input
2 6
20 10
25 15
Output
50
Input
3 9
10 10
10 10
10 10
Output
30
Input
1 1000000000
1000000000000000000 1000000000
Output
1999999999000000000 | instruction | 0 | 84,883 | 23 | 169,766 |
"Correct Solution:
```
n,k=map(int,input().split())
a=[list(map(int,input().split()))for i in range(n)]
l,r=2*(10**18)+1,0
while l-r>1:
t=(l+r)//2
c=0
for i,j in a:
c+=max(0,(t-i)//j+1)
if c<k:
r=t
else:
l=t
print(l)
``` | output | 1 | 84,883 | 23 | 169,767 |
Provide a correct Python 3 solution for this coding contest problem.
In your garden, there is a long and narrow flowerbed that stretches infinitely to the east. You have decided to plant N kinds of flowers in this empty flowerbed. For convenience, we will call these N kinds of flowers Flower 1, 2, …, N. Also, we will call the position that is p centimeters from the west end of the flowerbed Position p.
You will plant Flower i (1 ≤ i ≤ N) as follows: first, plant one at Position w_i, then plant one every d_i centimeters endlessly toward the east. That is, Flower i will be planted at the positions w_i, w_i + d_i, w_i + 2 d_i, … Note that more than one flower may be planted at the same position.
Find the position at which the K-th flower from the west is planted. If more than one flower is planted at the same position, they are counted individually.
Constraints
* 1 ≤ N ≤ 10^5
* 1 ≤ K ≤ 10^9
* 1 ≤ w_i ≤ 10^{18}
* 1 ≤ d_i ≤ 10^9
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N K
w_1 d_1
:
w_N d_N
Output
When the K-th flower from the west is planted at Position X, print the value of X. (The westmost flower is counted as the 1-st flower.)
Examples
Input
2 6
20 10
25 15
Output
50
Input
3 9
10 10
10 10
10 10
Output
30
Input
1 1000000000
1000000000000000000 1000000000
Output
1999999999000000000 | instruction | 0 | 84,884 | 23 | 169,768 |
"Correct Solution:
```
import sys
input=sys.stdin.readline
N,K=map(int,input().split())
L=[]
for i in range(N):
s,d=map(int,input().split())
L.append([s,d])
High=10**20
Low =0
while High - Low >1:
Mid=(High + Low)//2
cnt=0
for j in range(N):
if Mid-L[j][0]<0:
continue
else:
cnt+=max(0,1+(Mid - L[j][0])//L[j][1])
if cnt>=K:
High = Mid
else:
Low = Mid
#print(High , Low)
Mid=int(Mid)
ans=0
for j in range(N):
ans+=max(0,1+(Mid - L[j][0])//L[j][1])
if ans>=K:
print(Mid)
else:
print(Mid+1)
``` | output | 1 | 84,884 | 23 | 169,769 |
Provide a correct Python 3 solution for this coding contest problem.
The numbers 1 to n x n are contained in the n x n square squares one by one, and the sum of the squares in any vertical column and the sum of the squares in any horizontal column are diagonal squares. Those with the same sum of eyes are called magic squares.
There are the following methods to create a magic square with an odd number of squares on each side.
1. Put 1 in the square just below the center square.
2. Put the following numbers in the square at the bottom right.
However, if the square you are trying to insert a number is out of the square, or if the number is already filled, search for the square to insert the number according to the following method.
* If it extends to the right, it will be on the left side of the same row, if it extends to the left, it will be on the right side of the same row, and if it extends below, it will be on the top of the same column. Put in.
* If the square you are trying to enter is filled, put it in the square diagonally below the left of the filled square.
3. Repeat 2 until all the squares are filled.
Follow this method to create a program that takes the number n of squares on one side as input and outputs magic squares of that size. However, n is an odd number between 3 and 15. Output each number in the square as a right-justified 4-digit number.
input
Multiple inputs are given. Each input gives n (a positive integer) on one line. The input ends with 0. The number of inputs does not exceed 10.
output
Output n x n magic squares for each input.
Example
Input
3
5
0
Output
4 9 2
3 5 7
8 1 6
11 24 7 20 3
4 12 25 8 16
17 5 13 21 9
10 18 1 14 22
23 6 19 2 15 | instruction | 0 | 84,921 | 23 | 169,842 |
"Correct Solution:
```
def check_range(xy, n):
for i in range(2):
if xy[i] == -1:
xy[i] = n - 1
elif xy[i] == n:
xy[i] = 0
return xy
while True:
n = int(input())
if n == 0:
break
ms = [[0 for i in range(n)] for j in range(n)]
xy = [n//2, n//2 - 1]
i = 1
while i <= n*n:
if ms[xy[1]][xy[0]] != 0:
xy[0] -= 1
xy[1] -= 1
xy = check_range(xy, n)
continue
ms[xy[1]][xy[0]] = i
xy[0] += 1
xy[1] -= 1
xy = check_range(xy, n)
i += 1
for i in range(n):
s = ""
for j in range(n):
s += "{0:>4}".format(str(ms[n - i - 1][j]))
print(s)
``` | output | 1 | 84,921 | 23 | 169,843 |
Provide a correct Python 3 solution for this coding contest problem.
The numbers 1 to n x n are contained in the n x n square squares one by one, and the sum of the squares in any vertical column and the sum of the squares in any horizontal column are diagonal squares. Those with the same sum of eyes are called magic squares.
There are the following methods to create a magic square with an odd number of squares on each side.
1. Put 1 in the square just below the center square.
2. Put the following numbers in the square at the bottom right.
However, if the square you are trying to insert a number is out of the square, or if the number is already filled, search for the square to insert the number according to the following method.
* If it extends to the right, it will be on the left side of the same row, if it extends to the left, it will be on the right side of the same row, and if it extends below, it will be on the top of the same column. Put in.
* If the square you are trying to enter is filled, put it in the square diagonally below the left of the filled square.
3. Repeat 2 until all the squares are filled.
Follow this method to create a program that takes the number n of squares on one side as input and outputs magic squares of that size. However, n is an odd number between 3 and 15. Output each number in the square as a right-justified 4-digit number.
input
Multiple inputs are given. Each input gives n (a positive integer) on one line. The input ends with 0. The number of inputs does not exceed 10.
output
Output n x n magic squares for each input.
Example
Input
3
5
0
Output
4 9 2
3 5 7
8 1 6
11 24 7 20 3
4 12 25 8 16
17 5 13 21 9
10 18 1 14 22
23 6 19 2 15 | instruction | 0 | 84,922 | 23 | 169,844 |
"Correct Solution:
```
from sys import stdin
def sqmatrix(n):
return [[0] * n for i in range(n)]
def magicsq(m):
n = len(m)
j = int(n/2)
i = j + 1
for num in range(1, n**2 + 1):
m[i][j] = num
i += 1
j += 1
i = i%n
j = j % n
if m[i][j] != 0:
i += 1
j -= 1
if j < 0:
j = n -1
i = i % n
return m
for line in stdin:
n = int(line)
if n == 0:
break
sm = sqmatrix(n)
for row in magicsq(sm): print (''.join(map(lambda x: str(x).rjust(4, ' '),row)))
``` | output | 1 | 84,922 | 23 | 169,845 |
Provide a correct Python 3 solution for this coding contest problem.
The numbers 1 to n x n are contained in the n x n square squares one by one, and the sum of the squares in any vertical column and the sum of the squares in any horizontal column are diagonal squares. Those with the same sum of eyes are called magic squares.
There are the following methods to create a magic square with an odd number of squares on each side.
1. Put 1 in the square just below the center square.
2. Put the following numbers in the square at the bottom right.
However, if the square you are trying to insert a number is out of the square, or if the number is already filled, search for the square to insert the number according to the following method.
* If it extends to the right, it will be on the left side of the same row, if it extends to the left, it will be on the right side of the same row, and if it extends below, it will be on the top of the same column. Put in.
* If the square you are trying to enter is filled, put it in the square diagonally below the left of the filled square.
3. Repeat 2 until all the squares are filled.
Follow this method to create a program that takes the number n of squares on one side as input and outputs magic squares of that size. However, n is an odd number between 3 and 15. Output each number in the square as a right-justified 4-digit number.
input
Multiple inputs are given. Each input gives n (a positive integer) on one line. The input ends with 0. The number of inputs does not exceed 10.
output
Output n x n magic squares for each input.
Example
Input
3
5
0
Output
4 9 2
3 5 7
8 1 6
11 24 7 20 3
4 12 25 8 16
17 5 13 21 9
10 18 1 14 22
23 6 19 2 15 | instruction | 0 | 84,923 | 23 | 169,846 |
"Correct Solution:
```
def square(n):
mp = [[0 for _ in range(n)] for _ in range(n)]
x, y = n // 2 , n // 2 + 1
mp[y][x] = 1
for i in range(2, n ** 2 + 1):
x = (x + 1) % n
y = (y + 1) % n
while mp[y][x]:
y = (y + 1) % n
x = (x - 1) % n
mp[y][x] = i
for line in mp:
s = ""
for i in line:
si = str(i)
s += si.rjust(4)
print(s)
while True:
n = int(input())
if not n:
break
square(n)
``` | output | 1 | 84,923 | 23 | 169,847 |
Provide a correct Python 3 solution for this coding contest problem.
The numbers 1 to n x n are contained in the n x n square squares one by one, and the sum of the squares in any vertical column and the sum of the squares in any horizontal column are diagonal squares. Those with the same sum of eyes are called magic squares.
There are the following methods to create a magic square with an odd number of squares on each side.
1. Put 1 in the square just below the center square.
2. Put the following numbers in the square at the bottom right.
However, if the square you are trying to insert a number is out of the square, or if the number is already filled, search for the square to insert the number according to the following method.
* If it extends to the right, it will be on the left side of the same row, if it extends to the left, it will be on the right side of the same row, and if it extends below, it will be on the top of the same column. Put in.
* If the square you are trying to enter is filled, put it in the square diagonally below the left of the filled square.
3. Repeat 2 until all the squares are filled.
Follow this method to create a program that takes the number n of squares on one side as input and outputs magic squares of that size. However, n is an odd number between 3 and 15. Output each number in the square as a right-justified 4-digit number.
input
Multiple inputs are given. Each input gives n (a positive integer) on one line. The input ends with 0. The number of inputs does not exceed 10.
output
Output n x n magic squares for each input.
Example
Input
3
5
0
Output
4 9 2
3 5 7
8 1 6
11 24 7 20 3
4 12 25 8 16
17 5 13 21 9
10 18 1 14 22
23 6 19 2 15 | instruction | 0 | 84,924 | 23 | 169,848 |
"Correct Solution:
```
# AOJ 0078 Magic Square
# Python3 2018.6.17 bal4u
MAX = 15
tbl = [0]*MAX
while True:
n = int(input())
if n == 0: break
tbl = [[0 for r in range(n)] for c in range(n)]
r, c = n//2+1, n//2
tbl[r][c] = i = 1
while i < n*n:
r += 1
c += 1
while True:
if c >= n: c = 0;
elif c < 0: c = n - 1;
if r >= n: r = 0;
if tbl[r][c] == 0:
i += 1
tbl[r][c] = i
break
r += 1
c -= 1
for r in range(n):
for c in range(n):
print(format(tbl[r][c], '4d'), end='')
print()
``` | output | 1 | 84,924 | 23 | 169,849 |
Provide a correct Python 3 solution for this coding contest problem.
The numbers 1 to n x n are contained in the n x n square squares one by one, and the sum of the squares in any vertical column and the sum of the squares in any horizontal column are diagonal squares. Those with the same sum of eyes are called magic squares.
There are the following methods to create a magic square with an odd number of squares on each side.
1. Put 1 in the square just below the center square.
2. Put the following numbers in the square at the bottom right.
However, if the square you are trying to insert a number is out of the square, or if the number is already filled, search for the square to insert the number according to the following method.
* If it extends to the right, it will be on the left side of the same row, if it extends to the left, it will be on the right side of the same row, and if it extends below, it will be on the top of the same column. Put in.
* If the square you are trying to enter is filled, put it in the square diagonally below the left of the filled square.
3. Repeat 2 until all the squares are filled.
Follow this method to create a program that takes the number n of squares on one side as input and outputs magic squares of that size. However, n is an odd number between 3 and 15. Output each number in the square as a right-justified 4-digit number.
input
Multiple inputs are given. Each input gives n (a positive integer) on one line. The input ends with 0. The number of inputs does not exceed 10.
output
Output n x n magic squares for each input.
Example
Input
3
5
0
Output
4 9 2
3 5 7
8 1 6
11 24 7 20 3
4 12 25 8 16
17 5 13 21 9
10 18 1 14 22
23 6 19 2 15 | instruction | 0 | 84,925 | 23 | 169,850 |
"Correct Solution:
```
import sys
readline = sys.stdin.readline
write = sys.stdout.write
def solve():
N = int(readline())
if N == 0:
return False
x = N//2; y = x+1
P = [[-1]*N for i in range(N)]
c = 0
N2 = N*N
while c < N2:
if P[y][x] == -1:
c += 1
P[y][x] = c
x = (x + 1) % N; y = (y + 1) % N
else:
x = (x - 1) % N; y = (y + 1) % N
for line in P:
write("".join(map("{:4d}".format, line)))
write("\n")
return True
while solve():
...
``` | output | 1 | 84,925 | 23 | 169,851 |
Provide a correct Python 3 solution for this coding contest problem.
The numbers 1 to n x n are contained in the n x n square squares one by one, and the sum of the squares in any vertical column and the sum of the squares in any horizontal column are diagonal squares. Those with the same sum of eyes are called magic squares.
There are the following methods to create a magic square with an odd number of squares on each side.
1. Put 1 in the square just below the center square.
2. Put the following numbers in the square at the bottom right.
However, if the square you are trying to insert a number is out of the square, or if the number is already filled, search for the square to insert the number according to the following method.
* If it extends to the right, it will be on the left side of the same row, if it extends to the left, it will be on the right side of the same row, and if it extends below, it will be on the top of the same column. Put in.
* If the square you are trying to enter is filled, put it in the square diagonally below the left of the filled square.
3. Repeat 2 until all the squares are filled.
Follow this method to create a program that takes the number n of squares on one side as input and outputs magic squares of that size. However, n is an odd number between 3 and 15. Output each number in the square as a right-justified 4-digit number.
input
Multiple inputs are given. Each input gives n (a positive integer) on one line. The input ends with 0. The number of inputs does not exceed 10.
output
Output n x n magic squares for each input.
Example
Input
3
5
0
Output
4 9 2
3 5 7
8 1 6
11 24 7 20 3
4 12 25 8 16
17 5 13 21 9
10 18 1 14 22
23 6 19 2 15 | instruction | 0 | 84,926 | 23 | 169,852 |
"Correct Solution:
```
import sys
for n in map(int, sys.stdin):
if not n:
break
a = [[-1]*(n+2)]+[[-1]+[0]*n+[-1] for _ in [0]*n]+[[-1]*(n+2)]
x, y = (n+1)//2, (n+1)//2+1
for i in range(1, n**2+1):
while a[y][x]:
if a[y][x] == -1:
if x in {0, n+1}:
x = (1, n)[x==0]
if y in {0, n+1}:
y = (1, n)[y==0]
else:
x, y = x-1, y+1
a[y][x] = i
x, y = x+1, y+1
for l in a[1:-1]:
print("".join(map(lambda x: "{:>4d}".format(x), l[1:-1])))
``` | output | 1 | 84,926 | 23 | 169,853 |
Provide a correct Python 3 solution for this coding contest problem.
The numbers 1 to n x n are contained in the n x n square squares one by one, and the sum of the squares in any vertical column and the sum of the squares in any horizontal column are diagonal squares. Those with the same sum of eyes are called magic squares.
There are the following methods to create a magic square with an odd number of squares on each side.
1. Put 1 in the square just below the center square.
2. Put the following numbers in the square at the bottom right.
However, if the square you are trying to insert a number is out of the square, or if the number is already filled, search for the square to insert the number according to the following method.
* If it extends to the right, it will be on the left side of the same row, if it extends to the left, it will be on the right side of the same row, and if it extends below, it will be on the top of the same column. Put in.
* If the square you are trying to enter is filled, put it in the square diagonally below the left of the filled square.
3. Repeat 2 until all the squares are filled.
Follow this method to create a program that takes the number n of squares on one side as input and outputs magic squares of that size. However, n is an odd number between 3 and 15. Output each number in the square as a right-justified 4-digit number.
input
Multiple inputs are given. Each input gives n (a positive integer) on one line. The input ends with 0. The number of inputs does not exceed 10.
output
Output n x n magic squares for each input.
Example
Input
3
5
0
Output
4 9 2
3 5 7
8 1 6
11 24 7 20 3
4 12 25 8 16
17 5 13 21 9
10 18 1 14 22
23 6 19 2 15 | instruction | 0 | 84,927 | 23 | 169,854 |
"Correct Solution:
```
def print_board(A,n):
for i in range(n):
s = ""
for j in range(n):
st = str(A[i][j])
if len(st) == 1:
s += " "
elif len(st) == 2:
s += " "
elif len(st) == 3:
s += " "
s += str(st)
print(s)
def check_leftdown(A,h,w,n):
if h + 1 > n - 1:
#下に抜けるならば,左に-1してその列に値が入っていない箇所を探す
w -= 1
for x in range(n):
if A[x][w] == 0:
h = x
break
else:
#左に抜けるならば
if w - 1 < 0:
w = n
h += 1
else:
h += 1
w -= 1
return h,w
def check_rightdown(A,h,w,n):
if h + 1 > n - 1:
#下にも右にも抜ける場合
if w + 1 > n - 1:
None
else:
#下に抜けるならば,右に＋1してその列に値が入っていない箇所を探す
w += 1
for x in range(n):
if A[x][w] == 0:
h = x
break
else:
if w + 1 > n - 1:
#右に抜けるならば
w = 0
h += 1
else:
#通常パターン
h += 1
w += 1
if A[h][w] != 0:
#値が既に埋まっている
#左下をチェック
h,w = check_leftdown(A,h,w,n)
return h,w
if __name__ == '__main__':
while True:
try:
n = int(input())
if n == 0:
break
A = [[0 for i in range(n)] for j in range(n)]
cnt = n * n
for x in range(cnt):
if x == 0:
mid = n // 2
h = mid + 1
w = mid
A[h][w] = x + 1
else:
h,w = check_rightdown(A,h,w,n)
A[h][w] = x+1
print_board(A,n)
except EOFError:
break
``` | output | 1 | 84,927 | 23 | 169,855 |
Provide a correct Python 3 solution for this coding contest problem.
The numbers 1 to n x n are contained in the n x n square squares one by one, and the sum of the squares in any vertical column and the sum of the squares in any horizontal column are diagonal squares. Those with the same sum of eyes are called magic squares.
There are the following methods to create a magic square with an odd number of squares on each side.
1. Put 1 in the square just below the center square.
2. Put the following numbers in the square at the bottom right.
However, if the square you are trying to insert a number is out of the square, or if the number is already filled, search for the square to insert the number according to the following method.
* If it extends to the right, it will be on the left side of the same row, if it extends to the left, it will be on the right side of the same row, and if it extends below, it will be on the top of the same column. Put in.
* If the square you are trying to enter is filled, put it in the square diagonally below the left of the filled square.
3. Repeat 2 until all the squares are filled.
Follow this method to create a program that takes the number n of squares on one side as input and outputs magic squares of that size. However, n is an odd number between 3 and 15. Output each number in the square as a right-justified 4-digit number.
input
Multiple inputs are given. Each input gives n (a positive integer) on one line. The input ends with 0. The number of inputs does not exceed 10.
output
Output n x n magic squares for each input.
Example
Input
3
5
0
Output
4 9 2
3 5 7
8 1 6
11 24 7 20 3
4 12 25 8 16
17 5 13 21 9
10 18 1 14 22
23 6 19 2 15 | instruction | 0 | 84,928 | 23 | 169,856 |
"Correct Solution:
```
while 1:
n = int(input())
if n == 0:
break
l = [[ 0 for i in range(n)] for j in range(n)]
i = n//2 + 1
j = n//2
l[i][j] = ' 1'
c = 2
d = '{: >4}'.format(c)
for x in range(n**2 - 1):
i = (i + 1) % n
j = (j + 1) % n
while l[i][j] != 0:
i = (i + 1) % n
j = (j - 1) % n
l[i][j] = d
c += 1
d = '{: >4}'.format(c)
for s in range(n):
print(*l[s],sep="")
``` | output | 1 | 84,928 | 23 | 169,857 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The numbers 1 to n x n are contained in the n x n square squares one by one, and the sum of the squares in any vertical column and the sum of the squares in any horizontal column are diagonal squares. Those with the same sum of eyes are called magic squares.
There are the following methods to create a magic square with an odd number of squares on each side.
1. Put 1 in the square just below the center square.
2. Put the following numbers in the square at the bottom right.
However, if the square you are trying to insert a number is out of the square, or if the number is already filled, search for the square to insert the number according to the following method.
* If it extends to the right, it will be on the left side of the same row, if it extends to the left, it will be on the right side of the same row, and if it extends below, it will be on the top of the same column. Put in.
* If the square you are trying to enter is filled, put it in the square diagonally below the left of the filled square.
3. Repeat 2 until all the squares are filled.
Follow this method to create a program that takes the number n of squares on one side as input and outputs magic squares of that size. However, n is an odd number between 3 and 15. Output each number in the square as a right-justified 4-digit number.
input
Multiple inputs are given. Each input gives n (a positive integer) on one line. The input ends with 0. The number of inputs does not exceed 10.
output
Output n x n magic squares for each input.
Example
Input
3
5
0
Output
4 9 2
3 5 7
8 1 6
11 24 7 20 3
4 12 25 8 16
17 5 13 21 9
10 18 1 14 22
23 6 19 2 15
Submitted Solution:
```
while True:
n = int(input())
if n==0:
break
else:
l = [[0 for i in range(n)] for j in range(n)]
x = n//2
y = n//2+1
c = 0
while c < n**2:
c += 1
while l[y][x] != 0:
y += 1
if y >= n:
y = 0
x -= 1
if x <= -1:
x = n-1
l[y][x] = c
x += 1
if x >= n:
x = 0
y += 1
if y >= n:
y = 0
for i in l:
a = ''
for j in i:
if 0 <= j < 10**1:
a = a + ' ' + str(j)
elif 10**1<=j<10**2:
a = a + ' ' + str(j)
elif 10**2<=j<10**3:
a = a + ' ' + str(j)
print(a)
``` | instruction | 0 | 84,929 | 23 | 169,858 |
Yes | output | 1 | 84,929 | 23 | 169,859 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The numbers 1 to n x n are contained in the n x n square squares one by one, and the sum of the squares in any vertical column and the sum of the squares in any horizontal column are diagonal squares. Those with the same sum of eyes are called magic squares.
There are the following methods to create a magic square with an odd number of squares on each side.
1. Put 1 in the square just below the center square.
2. Put the following numbers in the square at the bottom right.
However, if the square you are trying to insert a number is out of the square, or if the number is already filled, search for the square to insert the number according to the following method.
* If it extends to the right, it will be on the left side of the same row, if it extends to the left, it will be on the right side of the same row, and if it extends below, it will be on the top of the same column. Put in.
* If the square you are trying to enter is filled, put it in the square diagonally below the left of the filled square.
3. Repeat 2 until all the squares are filled.
Follow this method to create a program that takes the number n of squares on one side as input and outputs magic squares of that size. However, n is an odd number between 3 and 15. Output each number in the square as a right-justified 4-digit number.
input
Multiple inputs are given. Each input gives n (a positive integer) on one line. The input ends with 0. The number of inputs does not exceed 10.
output
Output n x n magic squares for each input.
Example
Input
3
5
0
Output
4 9 2
3 5 7
8 1 6
11 24 7 20 3
4 12 25 8 16
17 5 13 21 9
10 18 1 14 22
23 6 19 2 15
Submitted Solution:
```
while True :
n = int(input())
if n == 0 :
break
magic = list([0] * n for i in range(n))
x = (n+1)//2 - 1
y = (n+1)//2 - 2
for i in range(1, n**2+1) :
x += 1
y += 1
while True :
if x >= n :
x = 0
if y >= n :
y = 0
if magic[x][y] != 0 :
x += 1
y -= 1
if y == -1 :
y = n - 1
if x < n and y < n and magic[x][y] == 0 :
break
magic[x][y] = i
for i in range(n) :
for j in range(n) :
print('{:4}'.format(magic[i][j]), end="")
print()
``` | instruction | 0 | 84,930 | 23 | 169,860 |
Yes | output | 1 | 84,930 | 23 | 169,861 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The numbers 1 to n x n are contained in the n x n square squares one by one, and the sum of the squares in any vertical column and the sum of the squares in any horizontal column are diagonal squares. Those with the same sum of eyes are called magic squares.
There are the following methods to create a magic square with an odd number of squares on each side.
1. Put 1 in the square just below the center square.
2. Put the following numbers in the square at the bottom right.
However, if the square you are trying to insert a number is out of the square, or if the number is already filled, search for the square to insert the number according to the following method.
* If it extends to the right, it will be on the left side of the same row, if it extends to the left, it will be on the right side of the same row, and if it extends below, it will be on the top of the same column. Put in.
* If the square you are trying to enter is filled, put it in the square diagonally below the left of the filled square.
3. Repeat 2 until all the squares are filled.
Follow this method to create a program that takes the number n of squares on one side as input and outputs magic squares of that size. However, n is an odd number between 3 and 15. Output each number in the square as a right-justified 4-digit number.
input
Multiple inputs are given. Each input gives n (a positive integer) on one line. The input ends with 0. The number of inputs does not exceed 10.
output
Output n x n magic squares for each input.
Example
Input
3
5
0
Output
4 9 2
3 5 7
8 1 6
11 24 7 20 3
4 12 25 8 16
17 5 13 21 9
10 18 1 14 22
23 6 19 2 15
Submitted Solution:
```
while 1:
n=int(input())
if n==0:break
ans=[[0 for i in range(n)] for j in range(n)]
y=n//2
x=n//2-1
for i in range(1,n**2+1):
y=[y+1,y+1-n][y+1==n]
x=[x+1,x+1-n][x+1==n]
if ans[y][x]==0:ans[y][x]=str(i).rjust(4)
else:
y=[y+1,y+1-n][y+1==n]
x=[x-1,x-1+n][x==0]
ans[y][x]=str(i).rjust(4)
for i in ans:print(''.join(map(str,i)))
``` | instruction | 0 | 84,931 | 23 | 169,862 |
Yes | output | 1 | 84,931 | 23 | 169,863 |
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