text stringlengths 1.02k 43.5k | conversation_id int64 853 107k | embedding sequence | cluster int64 24 24 |
|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
Each day in Berland consists of n hours. Polycarp likes time management. That's why he has a fixed schedule for each day — it is a sequence a_1, a_2, ..., a_n (each a_i is either 0 or 1), where a_i=0 if Polycarp works during the i-th hour of the day and a_i=1 if Polycarp rests during the i-th hour of the day.
Days go one after another endlessly and Polycarp uses the same schedule for each day.
What is the maximal number of continuous hours during which Polycarp rests? It is guaranteed that there is at least one working hour in a day.
Input
The first line contains n (1 ≤ n ≤ 2⋅10^5) — number of hours per day.
The second line contains n integer numbers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 1), where a_i=0 if the i-th hour in a day is working and a_i=1 if the i-th hour is resting. It is guaranteed that a_i=0 for at least one i.
Output
Print the maximal number of continuous hours during which Polycarp rests. Remember that you should consider that days go one after another endlessly and Polycarp uses the same schedule for each day.
Examples
Input
5
1 0 1 0 1
Output
2
Input
6
0 1 0 1 1 0
Output
2
Input
7
1 0 1 1 1 0 1
Output
3
Input
3
0 0 0
Output
0
Note
In the first example, the maximal rest starts in last hour and goes to the first hour of the next day.
In the second example, Polycarp has maximal rest from the 4-th to the 5-th hour.
In the third example, Polycarp has maximal rest from the 3-rd to the 5-th hour.
In the fourth example, Polycarp has no rest at all.
Tags: implementation
Correct Solution:
```
n=int(input())
a=list(map(int,input().split()))
k,m,s=n-1,0,0
while True:
if k<0 and a[k]!=1:
print(max(m,s))
exit()
if a[k]==1:
s+=1
else:
m=max(m,s)
s=0
k-=1
```
| 853 | [
0.5205078125,
0.446533203125,
0.003475189208984375,
0.12127685546875,
-0.254638671875,
-0.1591796875,
-0.4560546875,
-0.11724853515625,
0.0557861328125,
0.7763671875,
0.7119140625,
-0.0130767822265625,
0.429931640625,
-0.79833984375,
-0.43359375,
-0.1834716796875,
-0.6669921875,
-0... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Each day in Berland consists of n hours. Polycarp likes time management. That's why he has a fixed schedule for each day — it is a sequence a_1, a_2, ..., a_n (each a_i is either 0 or 1), where a_i=0 if Polycarp works during the i-th hour of the day and a_i=1 if Polycarp rests during the i-th hour of the day.
Days go one after another endlessly and Polycarp uses the same schedule for each day.
What is the maximal number of continuous hours during which Polycarp rests? It is guaranteed that there is at least one working hour in a day.
Input
The first line contains n (1 ≤ n ≤ 2⋅10^5) — number of hours per day.
The second line contains n integer numbers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 1), where a_i=0 if the i-th hour in a day is working and a_i=1 if the i-th hour is resting. It is guaranteed that a_i=0 for at least one i.
Output
Print the maximal number of continuous hours during which Polycarp rests. Remember that you should consider that days go one after another endlessly and Polycarp uses the same schedule for each day.
Examples
Input
5
1 0 1 0 1
Output
2
Input
6
0 1 0 1 1 0
Output
2
Input
7
1 0 1 1 1 0 1
Output
3
Input
3
0 0 0
Output
0
Note
In the first example, the maximal rest starts in last hour and goes to the first hour of the next day.
In the second example, Polycarp has maximal rest from the 4-th to the 5-th hour.
In the third example, Polycarp has maximal rest from the 3-rd to the 5-th hour.
In the fourth example, Polycarp has no rest at all.
Tags: implementation
Correct Solution:
```
n = int(input())
a = list(map(int, input().split())) * 2
cnt = 0
answ = 0
for i in range(2 * n):
if a[i]:
cnt += 1
else:
answ = max(answ, cnt)
cnt = 0
print(answ)
```
| 854 | [
0.486083984375,
0.4072265625,
0.01346588134765625,
0.11279296875,
-0.2308349609375,
-0.1646728515625,
-0.450927734375,
-0.1387939453125,
0.07305908203125,
0.75439453125,
0.71142578125,
0.0017452239990234375,
0.41162109375,
-0.80859375,
-0.4404296875,
-0.174072265625,
-0.66162109375,
... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Each day in Berland consists of n hours. Polycarp likes time management. That's why he has a fixed schedule for each day — it is a sequence a_1, a_2, ..., a_n (each a_i is either 0 or 1), where a_i=0 if Polycarp works during the i-th hour of the day and a_i=1 if Polycarp rests during the i-th hour of the day.
Days go one after another endlessly and Polycarp uses the same schedule for each day.
What is the maximal number of continuous hours during which Polycarp rests? It is guaranteed that there is at least one working hour in a day.
Input
The first line contains n (1 ≤ n ≤ 2⋅10^5) — number of hours per day.
The second line contains n integer numbers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 1), where a_i=0 if the i-th hour in a day is working and a_i=1 if the i-th hour is resting. It is guaranteed that a_i=0 for at least one i.
Output
Print the maximal number of continuous hours during which Polycarp rests. Remember that you should consider that days go one after another endlessly and Polycarp uses the same schedule for each day.
Examples
Input
5
1 0 1 0 1
Output
2
Input
6
0 1 0 1 1 0
Output
2
Input
7
1 0 1 1 1 0 1
Output
3
Input
3
0 0 0
Output
0
Note
In the first example, the maximal rest starts in last hour and goes to the first hour of the next day.
In the second example, Polycarp has maximal rest from the 4-th to the 5-th hour.
In the third example, Polycarp has maximal rest from the 3-rd to the 5-th hour.
In the fourth example, Polycarp has no rest at all.
Tags: implementation
Correct Solution:
```
num=int(input())
a=list(map(int, input().split()))
b=[]
a+=a #Same list is added to eachother bcz he can take consecutive rests i.e when a[n-1]==1 and a[0]==1 that is he can take rest before work and at end so his rest count increases
count=0
i=0
while i<2*num-1:
count=0
if a[i]==1:
count+=1
for j in range(i+1, 2*num):
#To find consecutive resting 1s
if a[j]==0:
break
else:
count+=1
i=j
else:
i+=1
b+=[count]
print(max(b))
```
| 855 | [
0.54736328125,
0.408447265625,
0.026702880859375,
0.10919189453125,
-0.235595703125,
-0.175537109375,
-0.4658203125,
-0.1298828125,
0.0770263671875,
0.75732421875,
0.7265625,
-0.01397705078125,
0.43212890625,
-0.78662109375,
-0.436767578125,
-0.16650390625,
-0.67626953125,
-0.78857... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Each day in Berland consists of n hours. Polycarp likes time management. That's why he has a fixed schedule for each day — it is a sequence a_1, a_2, ..., a_n (each a_i is either 0 or 1), where a_i=0 if Polycarp works during the i-th hour of the day and a_i=1 if Polycarp rests during the i-th hour of the day.
Days go one after another endlessly and Polycarp uses the same schedule for each day.
What is the maximal number of continuous hours during which Polycarp rests? It is guaranteed that there is at least one working hour in a day.
Input
The first line contains n (1 ≤ n ≤ 2⋅10^5) — number of hours per day.
The second line contains n integer numbers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 1), where a_i=0 if the i-th hour in a day is working and a_i=1 if the i-th hour is resting. It is guaranteed that a_i=0 for at least one i.
Output
Print the maximal number of continuous hours during which Polycarp rests. Remember that you should consider that days go one after another endlessly and Polycarp uses the same schedule for each day.
Examples
Input
5
1 0 1 0 1
Output
2
Input
6
0 1 0 1 1 0
Output
2
Input
7
1 0 1 1 1 0 1
Output
3
Input
3
0 0 0
Output
0
Note
In the first example, the maximal rest starts in last hour and goes to the first hour of the next day.
In the second example, Polycarp has maximal rest from the 4-th to the 5-th hour.
In the third example, Polycarp has maximal rest from the 3-rd to the 5-th hour.
In the fourth example, Polycarp has no rest at all.
Tags: implementation
Correct Solution:
```
hours = int(input().strip())
schedule = input().strip().replace(' ', '')
schedule = ''.join([schedule, schedule])
schedule = schedule.split('0')
print(len(sorted(schedule, key=len)[-1]))
```
| 856 | [
0.5380859375,
0.426513671875,
-0.0160369873046875,
0.11956787109375,
-0.2476806640625,
-0.1358642578125,
-0.46875,
-0.1005859375,
0.061065673828125,
0.72509765625,
0.71875,
-0.03387451171875,
0.45068359375,
-0.80908203125,
-0.440673828125,
-0.1495361328125,
-0.6787109375,
-0.713378... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Each day in Berland consists of n hours. Polycarp likes time management. That's why he has a fixed schedule for each day — it is a sequence a_1, a_2, ..., a_n (each a_i is either 0 or 1), where a_i=0 if Polycarp works during the i-th hour of the day and a_i=1 if Polycarp rests during the i-th hour of the day.
Days go one after another endlessly and Polycarp uses the same schedule for each day.
What is the maximal number of continuous hours during which Polycarp rests? It is guaranteed that there is at least one working hour in a day.
Input
The first line contains n (1 ≤ n ≤ 2⋅10^5) — number of hours per day.
The second line contains n integer numbers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 1), where a_i=0 if the i-th hour in a day is working and a_i=1 if the i-th hour is resting. It is guaranteed that a_i=0 for at least one i.
Output
Print the maximal number of continuous hours during which Polycarp rests. Remember that you should consider that days go one after another endlessly and Polycarp uses the same schedule for each day.
Examples
Input
5
1 0 1 0 1
Output
2
Input
6
0 1 0 1 1 0
Output
2
Input
7
1 0 1 1 1 0 1
Output
3
Input
3
0 0 0
Output
0
Note
In the first example, the maximal rest starts in last hour and goes to the first hour of the next day.
In the second example, Polycarp has maximal rest from the 4-th to the 5-th hour.
In the third example, Polycarp has maximal rest from the 3-rd to the 5-th hour.
In the fourth example, Polycarp has no rest at all.
Tags: implementation
Correct Solution:
```
f = int(input())
lis = list(map(int, input().split())) * 2
maxi = 0
cont = 0
for i in lis:
if(i == 1):
cont += 1
if (cont > maxi):
maxi = cont
else:
cont = 0
print(maxi)
```
| 857 | [
0.5,
0.36572265625,
0.1031494140625,
0.12481689453125,
-0.2208251953125,
-0.205078125,
-0.459716796875,
-0.1619873046875,
0.0462646484375,
0.72412109375,
0.66845703125,
0.0227508544921875,
0.479736328125,
-0.80859375,
-0.41943359375,
-0.1905517578125,
-0.67822265625,
-0.6923828125,... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Each day in Berland consists of n hours. Polycarp likes time management. That's why he has a fixed schedule for each day — it is a sequence a_1, a_2, ..., a_n (each a_i is either 0 or 1), where a_i=0 if Polycarp works during the i-th hour of the day and a_i=1 if Polycarp rests during the i-th hour of the day.
Days go one after another endlessly and Polycarp uses the same schedule for each day.
What is the maximal number of continuous hours during which Polycarp rests? It is guaranteed that there is at least one working hour in a day.
Input
The first line contains n (1 ≤ n ≤ 2⋅10^5) — number of hours per day.
The second line contains n integer numbers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 1), where a_i=0 if the i-th hour in a day is working and a_i=1 if the i-th hour is resting. It is guaranteed that a_i=0 for at least one i.
Output
Print the maximal number of continuous hours during which Polycarp rests. Remember that you should consider that days go one after another endlessly and Polycarp uses the same schedule for each day.
Examples
Input
5
1 0 1 0 1
Output
2
Input
6
0 1 0 1 1 0
Output
2
Input
7
1 0 1 1 1 0 1
Output
3
Input
3
0 0 0
Output
0
Note
In the first example, the maximal rest starts in last hour and goes to the first hour of the next day.
In the second example, Polycarp has maximal rest from the 4-th to the 5-th hour.
In the third example, Polycarp has maximal rest from the 3-rd to the 5-th hour.
In the fourth example, Polycarp has no rest at all.
Tags: implementation
Correct Solution:
```
from itertools import groupby
print(max([0] + [sum(1 for _ in g) for k, g in groupby(list(map(int, (input(), input())[1].split(' '))) * 2) if k == 1]))
```
| 858 | [
0.5078125,
0.36865234375,
-0.02166748046875,
0.1346435546875,
-0.235595703125,
-0.1722412109375,
-0.464599609375,
-0.1463623046875,
0.11065673828125,
0.7392578125,
0.6826171875,
-0.02490234375,
0.443603515625,
-0.771484375,
-0.427978515625,
-0.15380859375,
-0.69384765625,
-0.762207... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Each day in Berland consists of n hours. Polycarp likes time management. That's why he has a fixed schedule for each day — it is a sequence a_1, a_2, ..., a_n (each a_i is either 0 or 1), where a_i=0 if Polycarp works during the i-th hour of the day and a_i=1 if Polycarp rests during the i-th hour of the day.
Days go one after another endlessly and Polycarp uses the same schedule for each day.
What is the maximal number of continuous hours during which Polycarp rests? It is guaranteed that there is at least one working hour in a day.
Input
The first line contains n (1 ≤ n ≤ 2⋅10^5) — number of hours per day.
The second line contains n integer numbers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 1), where a_i=0 if the i-th hour in a day is working and a_i=1 if the i-th hour is resting. It is guaranteed that a_i=0 for at least one i.
Output
Print the maximal number of continuous hours during which Polycarp rests. Remember that you should consider that days go one after another endlessly and Polycarp uses the same schedule for each day.
Examples
Input
5
1 0 1 0 1
Output
2
Input
6
0 1 0 1 1 0
Output
2
Input
7
1 0 1 1 1 0 1
Output
3
Input
3
0 0 0
Output
0
Note
In the first example, the maximal rest starts in last hour and goes to the first hour of the next day.
In the second example, Polycarp has maximal rest from the 4-th to the 5-th hour.
In the third example, Polycarp has maximal rest from the 3-rd to the 5-th hour.
In the fourth example, Polycarp has no rest at all.
Tags: implementation
Correct Solution:
```
n = int(input())
a = list(map(lambda w: len(w), (''.join(input().split())).split('0')))
ans = max(a)
if len(a) > 1:
ans = max(ans, a[0]+a[-1])
print(ans)
```
| 859 | [
0.5029296875,
0.410400390625,
0.0216217041015625,
0.12841796875,
-0.2423095703125,
-0.14892578125,
-0.457275390625,
-0.12890625,
0.06842041015625,
0.73876953125,
0.6943359375,
-0.02484130859375,
0.42041015625,
-0.7666015625,
-0.431640625,
-0.1634521484375,
-0.6767578125,
-0.7319335... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Each day in Berland consists of n hours. Polycarp likes time management. That's why he has a fixed schedule for each day — it is a sequence a_1, a_2, ..., a_n (each a_i is either 0 or 1), where a_i=0 if Polycarp works during the i-th hour of the day and a_i=1 if Polycarp rests during the i-th hour of the day.
Days go one after another endlessly and Polycarp uses the same schedule for each day.
What is the maximal number of continuous hours during which Polycarp rests? It is guaranteed that there is at least one working hour in a day.
Input
The first line contains n (1 ≤ n ≤ 2⋅10^5) — number of hours per day.
The second line contains n integer numbers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 1), where a_i=0 if the i-th hour in a day is working and a_i=1 if the i-th hour is resting. It is guaranteed that a_i=0 for at least one i.
Output
Print the maximal number of continuous hours during which Polycarp rests. Remember that you should consider that days go one after another endlessly and Polycarp uses the same schedule for each day.
Examples
Input
5
1 0 1 0 1
Output
2
Input
6
0 1 0 1 1 0
Output
2
Input
7
1 0 1 1 1 0 1
Output
3
Input
3
0 0 0
Output
0
Note
In the first example, the maximal rest starts in last hour and goes to the first hour of the next day.
In the second example, Polycarp has maximal rest from the 4-th to the 5-th hour.
In the third example, Polycarp has maximal rest from the 3-rd to the 5-th hour.
In the fourth example, Polycarp has no rest at all.
Tags: implementation
Correct Solution:
```
n = int(input())
b = input()
b = b+" "+b
b = b.split("0")
b = [len(x.split()) for x in b]
print(max(b))
```
| 860 | [
0.51220703125,
0.411865234375,
-0.0022563934326171875,
0.147216796875,
-0.25732421875,
-0.1285400390625,
-0.4287109375,
-0.1309814453125,
0.060760498046875,
0.73681640625,
0.71875,
-0.02288818359375,
0.42822265625,
-0.80859375,
-0.422119140625,
-0.1890869140625,
-0.6669921875,
-0.7... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Each day in Berland consists of n hours. Polycarp likes time management. That's why he has a fixed schedule for each day — it is a sequence a_1, a_2, ..., a_n (each a_i is either 0 or 1), where a_i=0 if Polycarp works during the i-th hour of the day and a_i=1 if Polycarp rests during the i-th hour of the day.
Days go one after another endlessly and Polycarp uses the same schedule for each day.
What is the maximal number of continuous hours during which Polycarp rests? It is guaranteed that there is at least one working hour in a day.
Input
The first line contains n (1 ≤ n ≤ 2⋅10^5) — number of hours per day.
The second line contains n integer numbers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 1), where a_i=0 if the i-th hour in a day is working and a_i=1 if the i-th hour is resting. It is guaranteed that a_i=0 for at least one i.
Output
Print the maximal number of continuous hours during which Polycarp rests. Remember that you should consider that days go one after another endlessly and Polycarp uses the same schedule for each day.
Examples
Input
5
1 0 1 0 1
Output
2
Input
6
0 1 0 1 1 0
Output
2
Input
7
1 0 1 1 1 0 1
Output
3
Input
3
0 0 0
Output
0
Note
In the first example, the maximal rest starts in last hour and goes to the first hour of the next day.
In the second example, Polycarp has maximal rest from the 4-th to the 5-th hour.
In the third example, Polycarp has maximal rest from the 3-rd to the 5-th hour.
In the fourth example, Polycarp has no rest at all.
Submitted Solution:
```
n=int(input())
d=input().split()
f=0
rest=[0]
for i in range(n-1,-1*n,-1):
if d[i]=='1':
f+=1
rest.append(f)
else:
f=0
print(max(rest))
```
Yes
| 861 | [
0.53076171875,
0.40869140625,
0.037506103515625,
0.1685791015625,
-0.344482421875,
-0.0435791015625,
-0.4091796875,
0.029815673828125,
0.06353759765625,
0.6728515625,
0.69189453125,
-0.021331787109375,
0.33837890625,
-0.76220703125,
-0.404296875,
-0.1710205078125,
-0.58544921875,
-... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Each day in Berland consists of n hours. Polycarp likes time management. That's why he has a fixed schedule for each day — it is a sequence a_1, a_2, ..., a_n (each a_i is either 0 or 1), where a_i=0 if Polycarp works during the i-th hour of the day and a_i=1 if Polycarp rests during the i-th hour of the day.
Days go one after another endlessly and Polycarp uses the same schedule for each day.
What is the maximal number of continuous hours during which Polycarp rests? It is guaranteed that there is at least one working hour in a day.
Input
The first line contains n (1 ≤ n ≤ 2⋅10^5) — number of hours per day.
The second line contains n integer numbers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 1), where a_i=0 if the i-th hour in a day is working and a_i=1 if the i-th hour is resting. It is guaranteed that a_i=0 for at least one i.
Output
Print the maximal number of continuous hours during which Polycarp rests. Remember that you should consider that days go one after another endlessly and Polycarp uses the same schedule for each day.
Examples
Input
5
1 0 1 0 1
Output
2
Input
6
0 1 0 1 1 0
Output
2
Input
7
1 0 1 1 1 0 1
Output
3
Input
3
0 0 0
Output
0
Note
In the first example, the maximal rest starts in last hour and goes to the first hour of the next day.
In the second example, Polycarp has maximal rest from the 4-th to the 5-th hour.
In the third example, Polycarp has maximal rest from the 3-rd to the 5-th hour.
In the fourth example, Polycarp has no rest at all.
Submitted Solution:
```
n = int(input())
a = list(map(int, input().split()))
contigous = 0
max_cont = 0
from_0 = False
for i in range(n):
if a[i]:
contigous += 1
else:
max_cont = max(max_cont, contigous)
contigous = 0
max_cont = max(max_cont, contigous)
if a[0] and a[-1]:
contigous = 0
for i in range(n):
if a[i]:
contigous += 1
else:
break
for j in range(n-1, -1, -1):
if a[j]:
contigous += 1
else:
break
max_cont = max(max_cont, contigous)
print(max_cont)
```
Yes
| 862 | [
0.51171875,
0.407958984375,
0.041046142578125,
0.1767578125,
-0.34521484375,
-0.043914794921875,
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0.047576904296875,
0.08038330078125,
0.67578125,
0.650390625,
-0.027099609375,
0.35986328125,
-0.7919921875,
-0.406005859375,
-0.19287109375,
-0.60205078125,
-0.7744140... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Each day in Berland consists of n hours. Polycarp likes time management. That's why he has a fixed schedule for each day — it is a sequence a_1, a_2, ..., a_n (each a_i is either 0 or 1), where a_i=0 if Polycarp works during the i-th hour of the day and a_i=1 if Polycarp rests during the i-th hour of the day.
Days go one after another endlessly and Polycarp uses the same schedule for each day.
What is the maximal number of continuous hours during which Polycarp rests? It is guaranteed that there is at least one working hour in a day.
Input
The first line contains n (1 ≤ n ≤ 2⋅10^5) — number of hours per day.
The second line contains n integer numbers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 1), where a_i=0 if the i-th hour in a day is working and a_i=1 if the i-th hour is resting. It is guaranteed that a_i=0 for at least one i.
Output
Print the maximal number of continuous hours during which Polycarp rests. Remember that you should consider that days go one after another endlessly and Polycarp uses the same schedule for each day.
Examples
Input
5
1 0 1 0 1
Output
2
Input
6
0 1 0 1 1 0
Output
2
Input
7
1 0 1 1 1 0 1
Output
3
Input
3
0 0 0
Output
0
Note
In the first example, the maximal rest starts in last hour and goes to the first hour of the next day.
In the second example, Polycarp has maximal rest from the 4-th to the 5-th hour.
In the third example, Polycarp has maximal rest from the 3-rd to the 5-th hour.
In the fourth example, Polycarp has no rest at all.
Submitted Solution:
```
n = int(input())
s = input().split(' ')
mas = []
k = 0
for i in range(n):
if s[i] == '0':
mas.append(k)
mas.append(0)
k = 0
else:
k += 1
mas.append(k)
mas.append(mas[0]+mas[-1])
print(max(mas))
```
Yes
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0.30859375,
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... | 24 |
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