message stringlengths 2 43.5k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 853 107k | cluster float64 24 24 | __index_level_0__ int64 1.71k 214k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A PIN code is a string that consists of exactly 4 digits. Examples of possible PIN codes: 7013, 0000 and 0990. Please note that the PIN code can begin with any digit, even with 0.
Polycarp has n (2 ≤ n ≤ 10) bank cards, the PIN code of the i-th card is p_i.
Polycarp has recently read a recommendation that it is better to set different PIN codes on different cards. Thus he wants to change the minimal number of digits in the PIN codes of his cards so that all n codes would become different.
Formally, in one step, Polycarp picks i-th card (1 ≤ i ≤ n), then in its PIN code p_i selects one position (from 1 to 4), and changes the digit in this position to any other. He needs to change the minimum number of digits so that all PIN codes become different.
Polycarp quickly solved this problem. Can you solve it?
Input
The first line contains integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then test cases follow.
The first line of each of t test sets contains a single integer n (2 ≤ n ≤ 10) — the number of Polycarp's bank cards. The next n lines contain the PIN codes p_1, p_2, ..., p_n — one per line. The length of each of them is 4. All PIN codes consist of digits only.
Output
Print the answers to t test sets. The answer to each set should consist of a n + 1 lines
In the first line print k — the least number of changes to make all PIN codes different. In the next n lines output the changed PIN codes in the order corresponding to their appearance in the input. If there are several optimal answers, print any of them.
Example
Input
3
2
1234
0600
2
1337
1337
4
3139
3139
3139
3139
Output
0
1234
0600
1
1337
1237
3
3139
3138
3939
6139
Submitted Solution:
```
import sys
input = lambda: sys.stdin.readline().rstrip()
for _ in range(int(input())):
a = int(input())
mas = []
ans = 0
jk = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
for i in range(a):
s = input()
mas.append(s)
for i in range(a):
if mas[i] in mas[:i] or mas[i] in mas[i + 1::]:
for j in jk:
if str(j) + mas[i][1::] in mas[:i] or str(j) + mas[i][1::] in mas[i + 1::]:
continue
else:
mas[i] = str(j) + mas[i][1::]
ans += 1
break
print(ans)
for row in mas:
print(row)
``` | instruction | 0 | 34,406 | 24 | 68,812 |
Yes | output | 1 | 34,406 | 24 | 68,813 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A PIN code is a string that consists of exactly 4 digits. Examples of possible PIN codes: 7013, 0000 and 0990. Please note that the PIN code can begin with any digit, even with 0.
Polycarp has n (2 ≤ n ≤ 10) bank cards, the PIN code of the i-th card is p_i.
Polycarp has recently read a recommendation that it is better to set different PIN codes on different cards. Thus he wants to change the minimal number of digits in the PIN codes of his cards so that all n codes would become different.
Formally, in one step, Polycarp picks i-th card (1 ≤ i ≤ n), then in its PIN code p_i selects one position (from 1 to 4), and changes the digit in this position to any other. He needs to change the minimum number of digits so that all PIN codes become different.
Polycarp quickly solved this problem. Can you solve it?
Input
The first line contains integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then test cases follow.
The first line of each of t test sets contains a single integer n (2 ≤ n ≤ 10) — the number of Polycarp's bank cards. The next n lines contain the PIN codes p_1, p_2, ..., p_n — one per line. The length of each of them is 4. All PIN codes consist of digits only.
Output
Print the answers to t test sets. The answer to each set should consist of a n + 1 lines
In the first line print k — the least number of changes to make all PIN codes different. In the next n lines output the changed PIN codes in the order corresponding to their appearance in the input. If there are several optimal answers, print any of them.
Example
Input
3
2
1234
0600
2
1337
1337
4
3139
3139
3139
3139
Output
0
1234
0600
1
1337
1237
3
3139
3138
3939
6139
Submitted Solution:
```
import sys
input = lambda:sys.stdin.readline()
int_arr = lambda: list(map(int,input().split()))
str_arr = lambda: list(map(str,input().split()))
get_str = lambda: map(str,input().split())
get_int = lambda: map(int,input().split())
get_flo = lambda: map(float,input().split())
mod = 1000000007
def solve(n,lis):
c = 0
for i in lis:
tmp = 0
for j in range(10):
if lis.count(i) == 1:
break
else:
tmp = 1
i[-1] = str(j)
c += tmp
print(c)
for i in lis:
print(''.join(i))
for _ in range(int(input())):
lis = []
n = int(input())
for i in range(n):
lis.append(list(str(input())[:-1]))
solve(n,lis)
``` | instruction | 0 | 34,407 | 24 | 68,814 |
Yes | output | 1 | 34,407 | 24 | 68,815 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A PIN code is a string that consists of exactly 4 digits. Examples of possible PIN codes: 7013, 0000 and 0990. Please note that the PIN code can begin with any digit, even with 0.
Polycarp has n (2 ≤ n ≤ 10) bank cards, the PIN code of the i-th card is p_i.
Polycarp has recently read a recommendation that it is better to set different PIN codes on different cards. Thus he wants to change the minimal number of digits in the PIN codes of his cards so that all n codes would become different.
Formally, in one step, Polycarp picks i-th card (1 ≤ i ≤ n), then in its PIN code p_i selects one position (from 1 to 4), and changes the digit in this position to any other. He needs to change the minimum number of digits so that all PIN codes become different.
Polycarp quickly solved this problem. Can you solve it?
Input
The first line contains integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then test cases follow.
The first line of each of t test sets contains a single integer n (2 ≤ n ≤ 10) — the number of Polycarp's bank cards. The next n lines contain the PIN codes p_1, p_2, ..., p_n — one per line. The length of each of them is 4. All PIN codes consist of digits only.
Output
Print the answers to t test sets. The answer to each set should consist of a n + 1 lines
In the first line print k — the least number of changes to make all PIN codes different. In the next n lines output the changed PIN codes in the order corresponding to their appearance in the input. If there are several optimal answers, print any of them.
Example
Input
3
2
1234
0600
2
1337
1337
4
3139
3139
3139
3139
Output
0
1234
0600
1
1337
1237
3
3139
3138
3939
6139
Submitted Solution:
```
"""
This template is made by Satwik_Tiwari.
python programmers can use this template :)) .
"""
#===============================================================================================
#importing some useful libraries.
import sys
import bisect
import heapq
from math import *
from collections import Counter as counter # Counter(list) return a dict with {key: count}
from itertools import combinations as comb # if a = [1,2,3] then print(list(comb(a,2))) -----> [(1, 2), (1, 3), (2, 3)]
from itertools import permutations as permutate
from bisect import bisect_left as bl #
from bisect import bisect_right as br
from bisect import bisect
#===============================================================================================
#some shortcuts
mod = pow(10, 9) + 7
def inp(): return sys.stdin.readline().strip() #for fast input
def out(var): sys.stdout.write(str(var)) #for fast output, always take string
def lis(): return list(map(int, inp().split()))
def stringlis(): return list(map(str, inp().split()))
def sep(): return map(int, inp().split())
def strsep(): return map(str, inp().split())
def graph(vertex): return [[] for i in range(0,vertex+1)]
def zerolist(n): return [0]*n
def nextline(): out("\n") #as stdout.write always print sring.
def testcase():
for p in range(int(inp())):
solve()
def printlist(a) :
for p in range(0,len(a)):
out(str(a[p]) + ' ')
#===============================================================================================
# code here ;))
def solve():
n = int(inp())
a = []
for i in range(0,n):
a.append(inp())
lastdigit = set([])
for i in range(0,n):
lastdigit.add(a[i][3])
# print(lastdigit,end=' == lastdigit')
# print(a,end=' ==a')
changes = 0
for i in range(0,n):
for j in range(i+1,n):
if(a[i]==a[j]):
changes +=1
for k in range(0,10):
if(str(k) not in lastdigit):
a[j] = a[j][:3] + str(k)
lastdigit.add(str(k))
break
out(changes)
nextline()
for i in range(0,n):
out(a[i])
nextline()
testcase()
``` | instruction | 0 | 34,408 | 24 | 68,816 |
Yes | output | 1 | 34,408 | 24 | 68,817 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A PIN code is a string that consists of exactly 4 digits. Examples of possible PIN codes: 7013, 0000 and 0990. Please note that the PIN code can begin with any digit, even with 0.
Polycarp has n (2 ≤ n ≤ 10) bank cards, the PIN code of the i-th card is p_i.
Polycarp has recently read a recommendation that it is better to set different PIN codes on different cards. Thus he wants to change the minimal number of digits in the PIN codes of his cards so that all n codes would become different.
Formally, in one step, Polycarp picks i-th card (1 ≤ i ≤ n), then in its PIN code p_i selects one position (from 1 to 4), and changes the digit in this position to any other. He needs to change the minimum number of digits so that all PIN codes become different.
Polycarp quickly solved this problem. Can you solve it?
Input
The first line contains integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then test cases follow.
The first line of each of t test sets contains a single integer n (2 ≤ n ≤ 10) — the number of Polycarp's bank cards. The next n lines contain the PIN codes p_1, p_2, ..., p_n — one per line. The length of each of them is 4. All PIN codes consist of digits only.
Output
Print the answers to t test sets. The answer to each set should consist of a n + 1 lines
In the first line print k — the least number of changes to make all PIN codes different. In the next n lines output the changed PIN codes in the order corresponding to their appearance in the input. If there are several optimal answers, print any of them.
Example
Input
3
2
1234
0600
2
1337
1337
4
3139
3139
3139
3139
Output
0
1234
0600
1
1337
1237
3
3139
3138
3939
6139
Submitted Solution:
```
t = int(input())
for zz in range(t):
n = int(input())
p = []
for i in range(n):
p.append(input())
d = {}
for i in p:
try:
d[i] += 1
except:
d[i] = 1
#print(d)
k = 0
for v in d.values():
k += v - 1
print(k)
s = set(p)
for i in range(len(p)):
if d[p[i]] > 1:
d[p[i]] -= 1
cop = p[i]
while len(cop) <= 3:
cop.insert(0, 0)
po = 0
c = 9
st = True
while st:
p[i] = list(cop)
p[i][po] = str(c)
p[i] = ''.join(p[i])
c -= 1
if p[i] not in s:
st = False
if c == 0:
c = 9
po += 1
s = set(p)
for i in p:
print(i)
``` | instruction | 0 | 34,409 | 24 | 68,818 |
Yes | output | 1 | 34,409 | 24 | 68,819 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A PIN code is a string that consists of exactly 4 digits. Examples of possible PIN codes: 7013, 0000 and 0990. Please note that the PIN code can begin with any digit, even with 0.
Polycarp has n (2 ≤ n ≤ 10) bank cards, the PIN code of the i-th card is p_i.
Polycarp has recently read a recommendation that it is better to set different PIN codes on different cards. Thus he wants to change the minimal number of digits in the PIN codes of his cards so that all n codes would become different.
Formally, in one step, Polycarp picks i-th card (1 ≤ i ≤ n), then in its PIN code p_i selects one position (from 1 to 4), and changes the digit in this position to any other. He needs to change the minimum number of digits so that all PIN codes become different.
Polycarp quickly solved this problem. Can you solve it?
Input
The first line contains integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then test cases follow.
The first line of each of t test sets contains a single integer n (2 ≤ n ≤ 10) — the number of Polycarp's bank cards. The next n lines contain the PIN codes p_1, p_2, ..., p_n — one per line. The length of each of them is 4. All PIN codes consist of digits only.
Output
Print the answers to t test sets. The answer to each set should consist of a n + 1 lines
In the first line print k — the least number of changes to make all PIN codes different. In the next n lines output the changed PIN codes in the order corresponding to their appearance in the input. If there are several optimal answers, print any of them.
Example
Input
3
2
1234
0600
2
1337
1337
4
3139
3139
3139
3139
Output
0
1234
0600
1
1337
1237
3
3139
3138
3939
6139
Submitted Solution:
```
from sys import *
from math import *
t=int(stdin.readline())
for _ in range(t):
n=int(stdin.readline())
m=[]
ans=0
for i in range(n):
m.append(int(input()))
for i in range(n):
c=m[i]
m[i]-=1
if c in m:
m[i]+=1
f=0
v=m[i]%10
k=m[i]-v
for j in range(10):
if k not in m:
m[i]=k
f=1
ans+=1
break
else:
k+=i
if f==0:
if m[i]+10 not in m:
m[i]+=10
f=1
ans+=1
if f==0:
if m[i]+100 not in m:
m[i]+=100
ans+=1
f=1
if f==0:
if m[i]+1000 not in m:
m[i]+=1000
ans+=1
f=1
else:
m[i]+=1
print(ans)
f=[]
for i in range(n):
d=int(log10(m[i]))
x=4-d
a=[]
for j in range(x-1):
a.append(0)
a.append(m[i])
f.append(a)
for i in range(n):
print(*f[i],sep="")
``` | instruction | 0 | 34,410 | 24 | 68,820 |
No | output | 1 | 34,410 | 24 | 68,821 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A PIN code is a string that consists of exactly 4 digits. Examples of possible PIN codes: 7013, 0000 and 0990. Please note that the PIN code can begin with any digit, even with 0.
Polycarp has n (2 ≤ n ≤ 10) bank cards, the PIN code of the i-th card is p_i.
Polycarp has recently read a recommendation that it is better to set different PIN codes on different cards. Thus he wants to change the minimal number of digits in the PIN codes of his cards so that all n codes would become different.
Formally, in one step, Polycarp picks i-th card (1 ≤ i ≤ n), then in its PIN code p_i selects one position (from 1 to 4), and changes the digit in this position to any other. He needs to change the minimum number of digits so that all PIN codes become different.
Polycarp quickly solved this problem. Can you solve it?
Input
The first line contains integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then test cases follow.
The first line of each of t test sets contains a single integer n (2 ≤ n ≤ 10) — the number of Polycarp's bank cards. The next n lines contain the PIN codes p_1, p_2, ..., p_n — one per line. The length of each of them is 4. All PIN codes consist of digits only.
Output
Print the answers to t test sets. The answer to each set should consist of a n + 1 lines
In the first line print k — the least number of changes to make all PIN codes different. In the next n lines output the changed PIN codes in the order corresponding to their appearance in the input. If there are several optimal answers, print any of them.
Example
Input
3
2
1234
0600
2
1337
1337
4
3139
3139
3139
3139
Output
0
1234
0600
1
1337
1237
3
3139
3138
3939
6139
Submitted Solution:
```
t = int(input())
for _ in range(t):
n = int(input())
arr = []
for i in range(n):
arr.append(input())
ar = set(arr)
print(n - len(arr))
new_arr = []
for i in arr:
if i not in new_arr:
new_arr.append(i)
else:
for j in range(10):
val = str(j) + i[1:]
if val not in ar:
ar.add(val)
new_arr.append(val)
break
print("\n".join(new_arr))
``` | instruction | 0 | 34,411 | 24 | 68,822 |
No | output | 1 | 34,411 | 24 | 68,823 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A PIN code is a string that consists of exactly 4 digits. Examples of possible PIN codes: 7013, 0000 and 0990. Please note that the PIN code can begin with any digit, even with 0.
Polycarp has n (2 ≤ n ≤ 10) bank cards, the PIN code of the i-th card is p_i.
Polycarp has recently read a recommendation that it is better to set different PIN codes on different cards. Thus he wants to change the minimal number of digits in the PIN codes of his cards so that all n codes would become different.
Formally, in one step, Polycarp picks i-th card (1 ≤ i ≤ n), then in its PIN code p_i selects one position (from 1 to 4), and changes the digit in this position to any other. He needs to change the minimum number of digits so that all PIN codes become different.
Polycarp quickly solved this problem. Can you solve it?
Input
The first line contains integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then test cases follow.
The first line of each of t test sets contains a single integer n (2 ≤ n ≤ 10) — the number of Polycarp's bank cards. The next n lines contain the PIN codes p_1, p_2, ..., p_n — one per line. The length of each of them is 4. All PIN codes consist of digits only.
Output
Print the answers to t test sets. The answer to each set should consist of a n + 1 lines
In the first line print k — the least number of changes to make all PIN codes different. In the next n lines output the changed PIN codes in the order corresponding to their appearance in the input. If there are several optimal answers, print any of them.
Example
Input
3
2
1234
0600
2
1337
1337
4
3139
3139
3139
3139
Output
0
1234
0600
1
1337
1237
3
3139
3138
3939
6139
Submitted Solution:
```
for i in range(int(input())):
n,l=int(input()),[]
for i in range(n):
r=input()
if r not in l:l.append(r)
x=0
for j in range(10):
if len(l)==n:break
q=l[0].replace(l[0][0],str(j),1)
if q not in l:
l.append(q);x+=1
print(x)
for i in l:
print(i)
``` | instruction | 0 | 34,412 | 24 | 68,824 |
No | output | 1 | 34,412 | 24 | 68,825 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A PIN code is a string that consists of exactly 4 digits. Examples of possible PIN codes: 7013, 0000 and 0990. Please note that the PIN code can begin with any digit, even with 0.
Polycarp has n (2 ≤ n ≤ 10) bank cards, the PIN code of the i-th card is p_i.
Polycarp has recently read a recommendation that it is better to set different PIN codes on different cards. Thus he wants to change the minimal number of digits in the PIN codes of his cards so that all n codes would become different.
Formally, in one step, Polycarp picks i-th card (1 ≤ i ≤ n), then in its PIN code p_i selects one position (from 1 to 4), and changes the digit in this position to any other. He needs to change the minimum number of digits so that all PIN codes become different.
Polycarp quickly solved this problem. Can you solve it?
Input
The first line contains integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then test cases follow.
The first line of each of t test sets contains a single integer n (2 ≤ n ≤ 10) — the number of Polycarp's bank cards. The next n lines contain the PIN codes p_1, p_2, ..., p_n — one per line. The length of each of them is 4. All PIN codes consist of digits only.
Output
Print the answers to t test sets. The answer to each set should consist of a n + 1 lines
In the first line print k — the least number of changes to make all PIN codes different. In the next n lines output the changed PIN codes in the order corresponding to their appearance in the input. If there are several optimal answers, print any of them.
Example
Input
3
2
1234
0600
2
1337
1337
4
3139
3139
3139
3139
Output
0
1234
0600
1
1337
1237
3
3139
3138
3939
6139
Submitted Solution:
```
t = int(input())
for _ in range(t):
n = int(input())
arr = []
for i in range(n):
arr.append(input())
print(n - len(set(arr)))
new_arr = []
for i in arr:
if i not in new_arr:
new_arr.append(i)
else:
for j in range(10):
val = str(j) + i[1:]
if val not in new_arr:
new_arr.append(val)
break
print("\n".join(new_arr))
``` | instruction | 0 | 34,413 | 24 | 68,826 |
No | output | 1 | 34,413 | 24 | 68,827 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000 | instruction | 0 | 34,508 | 24 | 69,016 |
Tags: math
Correct Solution:
```
import sys
for _ in range(int(input())):
n, m, x = map(int, sys.stdin.readline().split())
c, r = divmod(x-1, n)
print(m*r+c+1)
``` | output | 1 | 34,508 | 24 | 69,017 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000 | instruction | 0 | 34,509 | 24 | 69,018 |
Tags: math
Correct Solution:
```
import sys, math, itertools, random, bisect
from collections import defaultdict
INF = 10**18
def get_ints(): return map(int, sys.stdin.readline().strip().split())
def get_array(): return list(map(int, sys.stdin.readline().strip().split()))
def input(): return sys.stdin.readline().strip()
mod = 10**9 + 7
# MAX = 100001
# def sieve():
# isPrime = [True]*(MAX)
# isPrime[0] = False
# isPrime[1] = False
# for i in range(2,MAX):
# if isPrime[i]:
# for j in range(i*i, MAX, i):
# isPrime[j] = False
# primes = [2]
# for i in range(3,MAX,2):
# if isPrime[i]: primes.append(i)
# return primes
for _ in range(int(input())):
n,m,x = get_ints()
row = (x-1)%n + 1
col = math.ceil(x/n)
# print(row,col)
print(m*(row-1) + col)
``` | output | 1 | 34,509 | 24 | 69,019 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000 | instruction | 0 | 34,510 | 24 | 69,020 |
Tags: math
Correct Solution:
```
#!/usr/bin/env python
# -*- coding: utf-8 -*-
"""Codeforces Round #710 (Div. 3)
Problem A. Strange Table
:author: Kitchen Tong
:mail: kctong529@gmail.com
Please feel free to contact me if you have any question
regarding the implementation below.
"""
__version__ = '0.1'
__date__ = '2021-03-25'
import sys
def solve(n, m, x) -> int:
col = (x - 1) // n + 1
row = x % n
if row == 0:
row = n
row -= 1
return m * row + col
def main(argv=None):
t = int(input())
for _ in range(t):
n, m, x = map(int, input().split())
print(solve(n, m, x))
return 0
if __name__ == "__main__":
STATUS = main()
sys.exit(STATUS)
``` | output | 1 | 34,510 | 24 | 69,021 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000 | instruction | 0 | 34,511 | 24 | 69,022 |
Tags: math
Correct Solution:
```
t = int(input())
for i in range(t):
n, m, x = map(int, input().split())
# print((x + n - 1) // n, x % n)
print(((x + n - 1) // n - 1) + ((x % n - 1) % n) * m + 1)
``` | output | 1 | 34,511 | 24 | 69,023 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000 | instruction | 0 | 34,512 | 24 | 69,024 |
Tags: math
Correct Solution:
```
for _ in range(int(input())):
n, m, x = map(int, input().split())
x -= 1
r, q = divmod(x, n)
res = q*m + r + 1
print(res)
``` | output | 1 | 34,512 | 24 | 69,025 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000 | instruction | 0 | 34,513 | 24 | 69,026 |
Tags: math
Correct Solution:
```
for _ in [0]*int(input()):
n,m,x = map(int,input().split())
x-=1
i,j = x//n, x%n
print(i+j*m+1)
``` | output | 1 | 34,513 | 24 | 69,027 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000 | instruction | 0 | 34,514 | 24 | 69,028 |
Tags: math
Correct Solution:
```
for i in range(int(input())):
n,m,x = map(int,input().split())
c=n
a=x//n
if x%n!=0:
a+=1
c=x%n
print(m*(c-1)+a)
``` | output | 1 | 34,514 | 24 | 69,029 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000 | instruction | 0 | 34,515 | 24 | 69,030 |
Tags: math
Correct Solution:
```
t = int(input())
for case in range(t):
n, m, x = map(int, input().split())
a = (x - 1) // n
b = (x - 1) % n
print(((b * m) + a) + 1)
``` | output | 1 | 34,515 | 24 | 69,031 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000
Submitted Solution:
```
n = int(input())
ans = list()
for i in range(n):
inp = input().split(" ")
modulus = int(inp[2])%int(inp[0])
division = int(int(inp[2])/int(inp[0]))
if(modulus == 0):
modulus = int(inp[0])
division -= 1
ans.append(int(inp[1])*(modulus-1)+(division+1))
for i in ans:
print(i,end = "\n")
``` | instruction | 0 | 34,516 | 24 | 69,032 |
Yes | output | 1 | 34,516 | 24 | 69,033 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000
Submitted Solution:
```
test = int(input())
for i in range(test,0,-1):
arr = input().split(" ")
n =int(arr[0])
m =int(arr[1])
t =int(arr[2])
answer = (t-1)//n + 1
if t%n==0:
answer +=(n-1)*m
else:
answer+=(t%n-1)*m
print(answer)
``` | instruction | 0 | 34,517 | 24 | 69,034 |
Yes | output | 1 | 34,517 | 24 | 69,035 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000
Submitted Solution:
```
def zip_sorted(a,b):
# sorted by a
a,b = zip(*sorted(zip(a,b)))
# sorted by b
sorted(zip(a, b), key=lambda x: x[1])
return a,b
def number_to_list(a):
b = []
while a>=1:
c = a%10
a = int(a/10)
b.append(c)
return list(reversed(b))
def str_list_to_int_list(a):
a = list(map(int,a))
return a
def make_1d_array(n,inti= 0):
a = [inti for _ in range(n)]
return a
def make_2d_array(n,m,inti= 0):
a = [[inti for _ in range(m)] for _ in range(n)]
return a
def make_3d_array(n,m,k,inti= 0):
a = [[[inti for _ in range(k)] for _ in range(m)] for _ in range(n)]
return a
def gcd(a,b):
if(b==0):
return a
else:
return gcd(b,a%b);
import sys
input = sys.stdin.readline
I = lambda : list(map(int,input().split()))
S = lambda : list(map(str,input()))
t,=I()
for t1 in range(t):
n,m,x = I()
x1,y1 = x//n,x%n
if y1==0:
y1 = n
x1 = x1-1
print((y1-1)*m+x1+1)
``` | instruction | 0 | 34,518 | 24 | 69,036 |
Yes | output | 1 | 34,518 | 24 | 69,037 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000
Submitted Solution:
```
from sys import stdin, stdout
def main():
t = int(stdin.readline())
for t in range(t):
nmx = [int(x) for x in stdin.readline().split()]
idash = nmx[-1]%nmx[0]
if idash==0:
idash = nmx[0]
jdash = ((nmx[-1] - idash)/nmx[0]) + 1
y = (nmx[1]*(idash-1)) + jdash
print(int(y))
if __name__ == "__main__":
main()
``` | instruction | 0 | 34,519 | 24 | 69,038 |
Yes | output | 1 | 34,519 | 24 | 69,039 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000
Submitted Solution:
```
for _ in range(int(input())):
n,m,x = map(int, input().split())
print(((x-1)%n)*m + (x//n) + 1)
``` | instruction | 0 | 34,520 | 24 | 69,040 |
No | output | 1 | 34,520 | 24 | 69,041 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000
Submitted Solution:
```
#THIS CODE IS MADE BY "harshest2020"
from sys import *
from math import floor,ceil,sqrt
ws=lambda:map(int,stdin.readline().strip().split())
li=lambda:list(map(int,stdin.readline().strip().split()))
mod=1000000007
def ncr(n, r, p):
num = den = 1
for i in range(r):
num = (num * (n - i)) % p
den = (den * (i + 1)) % p
return (num * pow(den, p - 2, p)) % p
def gcd(a,b):
if (b == 0):
return a
return gcd(b, a%b)
def prod(l):
ans=1
for i in range(len(l)):
ans=ans*l[i]
return ans
def sortindex(l,a):
c=[]
if(a==-1):
rev=True
else:
rev=False
for i in range(len(l)):
c.append([l[i],i])
x=sorted(c,reverse=rev)
print(x)
c=[]
for i in range(len(l)):
c.append(x[i][1])
return c
for _ in range(int(input())):
n,m,x=ws()
f=x//n
g=x%n
print(m*(g-1)+f+1)
``` | instruction | 0 | 34,521 | 24 | 69,042 |
No | output | 1 | 34,521 | 24 | 69,043 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000
Submitted Solution:
```
import math
t = int(input())
def get_answer(n, m, x):
if x == m * n:
return x
c = x // n
r = x % n
return (r - 1) * m + c + 1
for _ in range(t):
n, m, x = list(map(int, input().split()))
print(get_answer(n, m, x))
``` | instruction | 0 | 34,522 | 24 | 69,044 |
No | output | 1 | 34,522 | 24 | 69,045 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000
Submitted Solution:
```
def func():
n, m, x = [int(x) for x in input().split()]
if(n == 1 and m == 1):
return 1
a = (x - 1)%n
b = (x + 1)//n
c = a*m + b
return c
n = int(input())
for i in range(n):
print(func())
``` | instruction | 0 | 34,523 | 24 | 69,046 |
No | output | 1 | 34,523 | 24 | 69,047 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO | instruction | 0 | 36,589 | 24 | 73,178 |
Tags: data structures, greedy, sortings
Correct Solution:
```
n = int(input())
arr = list()
for i in range(n):
l, r = map(int, input().split())
arr.append((l, r))
e1, e2 = -1, -1
arr.sort()
ans = 'YES'
for i in arr:
if i[0] > e1:
e1 = i[1]
elif i[0] > e2:
e2 = i[1]
else:
ans = 'NO'
print(ans)
``` | output | 1 | 36,589 | 24 | 73,179 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO | instruction | 0 | 36,590 | 24 | 73,180 |
Tags: data structures, greedy, sortings
Correct Solution:
```
n = int(input())
segment = []
for _ in range(n):
segment.append(list(map(int, input().split())))
segment.sort(key = lambda x: x[0])
start1 = 0
end1 = -float('inf')
start2 = 0
end2 = -float('inf')
for x in segment:
start = x[0]
end = x[1]
if start > end1:
start1 = start
end1 = end
elif start > end2:
start2 = start
end2 = end
else:
print("NO")
exit()
print("YES")
``` | output | 1 | 36,590 | 24 | 73,181 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO | instruction | 0 | 36,591 | 24 | 73,182 |
Tags: data structures, greedy, sortings
Correct Solution:
```
n=int(input())
a=-1
b=-1
c=[]
for _ in range(n):
c.append(list(map(int,input().split())))
c.sort()
for i in range(n):
if a<c[i][0]:
a=c[i][1]
elif b<c[i][0]:
b=c[i][1]
else:
print("NO")
exit(0)
print("YES")
``` | output | 1 | 36,591 | 24 | 73,183 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO | instruction | 0 | 36,592 | 24 | 73,184 |
Tags: data structures, greedy, sortings
Correct Solution:
```
def lol(a):
c = 0
for x in a:
if x[1]==1:
c+=1
else:
c-=1
if c>=3:
return 0
return 1
n = int(input())
a = []
for _ in range(n):
x,y = map(int,input().split())
a.append([x,1])
a.append([y,2])
a = sorted(a)
print("YES" if lol(a) else "NO")
``` | output | 1 | 36,592 | 24 | 73,185 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO | instruction | 0 | 36,593 | 24 | 73,186 |
Tags: data structures, greedy, sortings
Correct Solution:
```
n = int(input())
pair = list()
pair1 = list()
pair2= list()
for i in range(n):
x,y = map(int,input().split())
pair.append((x,y))
pair.sort()
f = True
for i in range (n):
x = pair[i][0]
y = pair[i][1]
len1 = len(pair1)
len2 = len(pair2)
if(len1==0 or x>pair1[len1-1][1]):
pair1.append((x,y))
elif(len2==0 or x>pair2[len2-1][1]):
pair2.append((x,y))
else:
f=False
break
if(f):
print('YES')
else:
print('NO')
``` | output | 1 | 36,593 | 24 | 73,187 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO | instruction | 0 | 36,594 | 24 | 73,188 |
Tags: data structures, greedy, sortings
Correct Solution:
```
def main():
n = int(input())
events = []
for _ in range(n):
l, r = (int(x) for x in input().split())
events.append((l, 1))
events.append((r + 1, -1))
cur = 0
for _, event in sorted(events):
cur += event
if cur > 2:
print("NO")
break
else:
print("YES")
if __name__ == "__main__":
main()
``` | output | 1 | 36,594 | 24 | 73,189 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO | instruction | 0 | 36,595 | 24 | 73,190 |
Tags: data structures, greedy, sortings
Correct Solution:
```
n = int(input())
shows = []
for i in range(n):
start, end = [int(c) for c in input().split(" ")]
shows.append((start, end))
shows.sort(key=lambda tup: tup[0])
last_show_tv1 = None
last_show_tv2 = None
can_watch = True
for show in shows:
if last_show_tv1 == None:
last_show_tv1 = show
elif last_show_tv2 == None:
last_show_tv2 = show
elif not show[0] <= last_show_tv1[1]:
last_show_tv1 = show
elif not show[0] <= last_show_tv2[1]:
last_show_tv2 = show
else:
can_watch = False
break
if can_watch:
print("YES")
else:
print("NO")
``` | output | 1 | 36,595 | 24 | 73,191 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO | instruction | 0 | 36,596 | 24 | 73,192 |
Tags: data structures, greedy, sortings
Correct Solution:
```
# import os
import sys
# from io import BytesIO, IOBase
# _str = str
# str = lambda x=b"": x if type(x) is bytes else _str(x).encode()
# BUFSIZE = 8192
# class FastIO(IOBase):
# newlines = 0
# def __init__(self, file):
# self._fd = file.fileno()
# self.buffer = BytesIO()
# self.writable = "x" in file.mode or "r" not in file.mode
# self.write = self.buffer.write if self.writable else None
# def read(self):
# while True:
# b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
# if not b:
# break
# ptr = self.buffer.tell()
# self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
# self.newlines = 0
# return self.buffer.read()
# def readline(self):
# while self.newlines == 0:
# b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
# self.newlines = b.count(b"\n") + (not b)
# ptr = self.buffer.tell()
# self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
# self.newlines -= 1
# return self.buffer.readline()
# def flush(self):
# if self.writable:
# os.write(self._fd, self.buffer.getvalue())
# self.buffer.truncate(0), self.buffer.seek(0)
# class IOWrapper(IOBase):
# def __init__(self, file):
# self.buffer = FastIO(file)
# self.flush = self.buffer.flush
# self.writable = self.buffer.writable
# self.write = lambda s: self.buffer.write(s.encode("ascii"))
# self.read = lambda: self.buffer.read().decode("ascii")
# self.readline = lambda: self.buffer.readline().decode("ascii")
input = lambda: sys.stdin.readline().rstrip("\r\n")
import time
start = time.time()
from collections import deque
shows = []
for i in range(int(input())):
shows.append([int(i) for i in input().split()])
shows.sort()
shows = deque(shows)
workers = [-1, -1]
enough_tvs = True
while shows and enough_tvs:
show = shows.popleft()
if workers[0] < show[0]:
workers[0] = show[1]
if workers[1] < show[0]:
workers[1] = -1
elif workers[1] < show[0]:
workers[1] = show[1]
else:
enough_tvs = False
if enough_tvs:
print("YES")
else:
print("NO")
# print(time.time()-start)
# with open('input.txt', 'w') as file:
# for i in range(100000):
# file.writelines(f'{i} {i+1}\n')
# from collections import defaultdict
# def main():
# conflict_found = False
# times = defaultdict(int)
# for _ in range(int(input())):
# if conflict_found:
# break
# a, b = map(int, input().split())
# if not conflict_found:
# for j in range(a, b + 1):
# times[j] += 1
# if times[j] > 2:
# conflict_found = True
# break
# if conflict_found:
# return 'NO'
# else:
# return 'YES'
# print(main())
``` | output | 1 | 36,596 | 24 | 73,193 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO
Submitted Solution:
```
n = int(input())
d = []
for i in range(n):
a, b = map(int, input().split())
d.append((a, -1))
d.append((b, 1))
d.sort()
t = 0
for a, b in d:
t -= b
if t > 2:
print("NO")
exit(0)
print("YES")
``` | instruction | 0 | 36,597 | 24 | 73,194 |
Yes | output | 1 | 36,597 | 24 | 73,195 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO
Submitted Solution:
```
from collections import defaultdict
n = int(input())
times = defaultdict(lambda: 0)
for _ in range(n):
start, end = map(int, input().split(' '))
times[start] += 1
times[end + 1] -= 1
cur_time = 0
for time in sorted(times.keys()):
cur_time += times[time]
if cur_time > 2:
print('NO')
break
else:
print('YES')
``` | instruction | 0 | 36,598 | 24 | 73,196 |
Yes | output | 1 | 36,598 | 24 | 73,197 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO
Submitted Solution:
```
n=int(input())
shows=[]
for i in range(n):
temp = [int(j) for j in input().split(" ")]
temp[1]+=1
shows.append(temp[::])
shows.sort()
if n>1:
tv1=shows[0][1]
tv2=shows[1][1]
flag1,flag2=0,0
c=0
shows.append([1000000001,1000000001])
for i in range(2,n,1):
if tv1 <= shows[i][0] and flag1==0:
tv1=shows[i][1]
if (shows[i+1][0]>=tv1):
flag1=0
else:
flag1=1
if (shows[i + 1][0] >= tv2):
flag2 = 0
else:
flag2 = 1
elif tv2 <= shows[i][0] and flag2==0:
tv2=shows[i][1]
if (shows[i+1][0]>=tv1):
flag1=0
else:
flag1=1
if (shows[i + 1][0] >= tv2):
flag2 = 0
else:
flag2 = 1
else:
c=-1
if c==0:
print ("YES")
else:
print("NO")
else:
print("YES")
``` | instruction | 0 | 36,599 | 24 | 73,198 |
Yes | output | 1 | 36,599 | 24 | 73,199 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO
Submitted Solution:
```
n = int(input())
shows = []
for i in range(n):
l, r = map(int, input().split())
shows.append((l,r))
shows.sort()
a_endtime, b_endtime = -1, -1
for show in shows:
if show[0] <= a_endtime:
print('NO')
break
else:
a_endtime = show[1]
if a_endtime > b_endtime:
a_endtime, b_endtime = b_endtime, a_endtime
else:
print('YES')
``` | instruction | 0 | 36,600 | 24 | 73,200 |
Yes | output | 1 | 36,600 | 24 | 73,201 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO
Submitted Solution:
```
n = int(input())
def conflicts(a, b):
return a[1] >= b[0]
shows = []
for i in range(n):
x, y = map(int, input().split())
shows.append((x, y))
shows.sort(key=lambda x: x[0])
ok = True
tv1 = [(-1, -1)]
tv2 = [(-1, -1)]
for s in shows:
if not conflicts(tv1[-1], s):
tv1.append(s)
elif not conflicts(tv2[-1], s):
tv1.append(s)
else:
ok = False
break
if ok:
print('YES')
else:
print('NO')
``` | instruction | 0 | 36,601 | 24 | 73,202 |
No | output | 1 | 36,601 | 24 | 73,203 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO
Submitted Solution:
```
n = int(input())
shows = []
for i in range(n):
shows.append([int(x) for x in input().split()])
def fit(show, tv):
if show[1]<tv[0] or show[0]>tv[1]:
return True
return False
def main():
if n<2:
print("YES")
return
tv1 = shows[0]
tv2 = shows[1]
for show in shows[2:]:
if fit(show, tv1):
tv1 = [min(show[0],tv1[0]), max(show[1], tv1[1])]
elif fit(show, tv2):
tv2 = [min(show[0],tv2[0]), max(show[1], tv2[1])]
else:
print("NO")
return
print("YES")
return
main()
``` | instruction | 0 | 36,602 | 24 | 73,204 |
No | output | 1 | 36,602 | 24 | 73,205 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO
Submitted Solution:
```
n = int(input())
tv1 = set()
tv2 = set()
can_watch = True
for i in range(n):
start, end = input().split(" ")
if not start in tv1 and not end in tv1:
tv1.add(start)
tv1.add(end)
elif not start in tv2 and not end in tv2:
tv2.add(start)
tv2.add(end)
else:
can_watch = False
print(can_watch)
``` | instruction | 0 | 36,603 | 24 | 73,206 |
No | output | 1 | 36,603 | 24 | 73,207 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO
Submitted Solution:
```
n = int(input())
def conflicts(a, b):
return a[1] >= b[0]
shows = []
for i in range(n):
x, y = map(int, input().split())
shows.append((x, y))
shows.sort(key=lambda x: x[0])
ok = True
i = 2
while i < n:
if conflicts(shows[i - 1], shows[i]) and conflicts(shows[i - 2], shows[i - 1]):
ok = False
break
i += 1
if ok:
print('YES')
else:
print('NO')
``` | instruction | 0 | 36,604 | 24 | 73,208 |
No | output | 1 | 36,604 | 24 | 73,209 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp wrote on the board a string s containing only lowercase Latin letters ('a'-'z'). This string is known for you and given in the input.
After that, he erased some letters from the string s, and he rewrote the remaining letters in any order. As a result, he got some new string t. You have to find it with some additional information.
Suppose that the string t has length m and the characters are numbered from left to right from 1 to m. You are given a sequence of m integers: b_1, b_2, …, b_m, where b_i is the sum of the distances |i-j| from the index i to all such indices j that t_j > t_i (consider that 'a'<'b'<...<'z'). In other words, to calculate b_i, Polycarp finds all such indices j that the index j contains a letter that is later in the alphabet than t_i and sums all the values |i-j|.
For example, if t = "abzb", then:
* since t_1='a', all other indices contain letters which are later in the alphabet, that is: b_1=|1-2|+|1-3|+|1-4|=1+2+3=6;
* since t_2='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_2=|2-3|=1;
* since t_3='z', then there are no indexes j such that t_j>t_i, thus b_3=0;
* since t_4='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_4=|4-3|=1.
Thus, if t = "abzb", then b=[6,1,0,1].
Given the string s and the array b, find any possible string t for which the following two requirements are fulfilled simultaneously:
* t is obtained from s by erasing some letters (possibly zero) and then writing the rest in any order;
* the array, constructed from the string t according to the rules above, equals to the array b specified in the input data.
Input
The first line contains an integer q (1 ≤ q ≤ 100) — the number of test cases in the test. Then q test cases follow.
Each test case consists of three lines:
* the first line contains string s, which has a length from 1 to 50 and consists of lowercase English letters;
* the second line contains positive integer m (1 ≤ m ≤ |s|), where |s| is the length of the string s, and m is the length of the array b;
* the third line contains the integers b_1, b_2, ..., b_m (0 ≤ b_i ≤ 1225).
It is guaranteed that in each test case an answer exists.
Output
Output q lines: the k-th of them should contain the answer (string t) to the k-th test case. It is guaranteed that an answer to each test case exists. If there are several answers, output any.
Example
Input
4
abac
3
2 1 0
abc
1
0
abba
3
1 0 1
ecoosdcefr
10
38 13 24 14 11 5 3 24 17 0
Output
aac
b
aba
codeforces
Note
In the first test case, such strings t are suitable: "aac', "aab".
In the second test case, such trings t are suitable: "a", "b", "c".
In the third test case, only the string t equals to "aba" is suitable, but the character 'b' can be from the second or third position. | instruction | 0 | 36,979 | 24 | 73,958 |
Tags: constructive algorithms, greedy, implementation, sortings
Correct Solution:
```
for _ in range(int(input())):
s = list(input())
s.sort()
m = int(input())
a = list(map(int, input().split()))
while a.count(0):
qani = []
for i in range(m):
if a[i] == 0:
qani.append(i)
while s.count(s[-1]) < len(qani):
while len(s) > 1 and s[-1] == s[-2]:
s.pop()
s.pop()
now = s[-1]
while len(s) and s[-1] == now:
s.pop()
for i in qani:
a[i] = now
for i in range(m):
for x in qani:
try:
a[i] -= abs(i-x)
except:
pass
print(''.join(a))
``` | output | 1 | 36,979 | 24 | 73,959 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp wrote on the board a string s containing only lowercase Latin letters ('a'-'z'). This string is known for you and given in the input.
After that, he erased some letters from the string s, and he rewrote the remaining letters in any order. As a result, he got some new string t. You have to find it with some additional information.
Suppose that the string t has length m and the characters are numbered from left to right from 1 to m. You are given a sequence of m integers: b_1, b_2, …, b_m, where b_i is the sum of the distances |i-j| from the index i to all such indices j that t_j > t_i (consider that 'a'<'b'<...<'z'). In other words, to calculate b_i, Polycarp finds all such indices j that the index j contains a letter that is later in the alphabet than t_i and sums all the values |i-j|.
For example, if t = "abzb", then:
* since t_1='a', all other indices contain letters which are later in the alphabet, that is: b_1=|1-2|+|1-3|+|1-4|=1+2+3=6;
* since t_2='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_2=|2-3|=1;
* since t_3='z', then there are no indexes j such that t_j>t_i, thus b_3=0;
* since t_4='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_4=|4-3|=1.
Thus, if t = "abzb", then b=[6,1,0,1].
Given the string s and the array b, find any possible string t for which the following two requirements are fulfilled simultaneously:
* t is obtained from s by erasing some letters (possibly zero) and then writing the rest in any order;
* the array, constructed from the string t according to the rules above, equals to the array b specified in the input data.
Input
The first line contains an integer q (1 ≤ q ≤ 100) — the number of test cases in the test. Then q test cases follow.
Each test case consists of three lines:
* the first line contains string s, which has a length from 1 to 50 and consists of lowercase English letters;
* the second line contains positive integer m (1 ≤ m ≤ |s|), where |s| is the length of the string s, and m is the length of the array b;
* the third line contains the integers b_1, b_2, ..., b_m (0 ≤ b_i ≤ 1225).
It is guaranteed that in each test case an answer exists.
Output
Output q lines: the k-th of them should contain the answer (string t) to the k-th test case. It is guaranteed that an answer to each test case exists. If there are several answers, output any.
Example
Input
4
abac
3
2 1 0
abc
1
0
abba
3
1 0 1
ecoosdcefr
10
38 13 24 14 11 5 3 24 17 0
Output
aac
b
aba
codeforces
Note
In the first test case, such strings t are suitable: "aac', "aab".
In the second test case, such trings t are suitable: "a", "b", "c".
In the third test case, only the string t equals to "aba" is suitable, but the character 'b' can be from the second or third position. | instruction | 0 | 36,980 | 24 | 73,960 |
Tags: constructive algorithms, greedy, implementation, sortings
Correct Solution:
```
n = int(input())
for _ in range(n):
s = sorted(input())
m = len(s)
input()
b = list(map(int, input().split()))
res = ["" for _ in range(len(b))]
found = 0
while found < len(b):
for i in range(len(b)):
if b[i] != -1:
min_v = b[i]
min_i = i
break
for i, x in enumerate(b):
if x < min_v and x != -1:
min_i = i
min_v = x
min_indices = []
for i in range(len(b)):
if b[i] == min_v:
min_indices.append(i)
b[i] = -1
c = 1
prev = s.pop()
while s and c < len(min_indices):
x = s.pop()
if x != prev:
c = 0
c += 1
prev = x
while s and s[-1] == prev:
s.pop()
found += len(min_indices)
for j in min_indices:
res[j] = prev
for i in range(len(b)):
if b[i] != -1:
b[i] -= abs(i - j)
print("".join(res))
``` | output | 1 | 36,980 | 24 | 73,961 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp wrote on the board a string s containing only lowercase Latin letters ('a'-'z'). This string is known for you and given in the input.
After that, he erased some letters from the string s, and he rewrote the remaining letters in any order. As a result, he got some new string t. You have to find it with some additional information.
Suppose that the string t has length m and the characters are numbered from left to right from 1 to m. You are given a sequence of m integers: b_1, b_2, …, b_m, where b_i is the sum of the distances |i-j| from the index i to all such indices j that t_j > t_i (consider that 'a'<'b'<...<'z'). In other words, to calculate b_i, Polycarp finds all such indices j that the index j contains a letter that is later in the alphabet than t_i and sums all the values |i-j|.
For example, if t = "abzb", then:
* since t_1='a', all other indices contain letters which are later in the alphabet, that is: b_1=|1-2|+|1-3|+|1-4|=1+2+3=6;
* since t_2='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_2=|2-3|=1;
* since t_3='z', then there are no indexes j such that t_j>t_i, thus b_3=0;
* since t_4='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_4=|4-3|=1.
Thus, if t = "abzb", then b=[6,1,0,1].
Given the string s and the array b, find any possible string t for which the following two requirements are fulfilled simultaneously:
* t is obtained from s by erasing some letters (possibly zero) and then writing the rest in any order;
* the array, constructed from the string t according to the rules above, equals to the array b specified in the input data.
Input
The first line contains an integer q (1 ≤ q ≤ 100) — the number of test cases in the test. Then q test cases follow.
Each test case consists of three lines:
* the first line contains string s, which has a length from 1 to 50 and consists of lowercase English letters;
* the second line contains positive integer m (1 ≤ m ≤ |s|), where |s| is the length of the string s, and m is the length of the array b;
* the third line contains the integers b_1, b_2, ..., b_m (0 ≤ b_i ≤ 1225).
It is guaranteed that in each test case an answer exists.
Output
Output q lines: the k-th of them should contain the answer (string t) to the k-th test case. It is guaranteed that an answer to each test case exists. If there are several answers, output any.
Example
Input
4
abac
3
2 1 0
abc
1
0
abba
3
1 0 1
ecoosdcefr
10
38 13 24 14 11 5 3 24 17 0
Output
aac
b
aba
codeforces
Note
In the first test case, such strings t are suitable: "aac', "aab".
In the second test case, such trings t are suitable: "a", "b", "c".
In the third test case, only the string t equals to "aba" is suitable, but the character 'b' can be from the second or third position. | instruction | 0 | 36,981 | 24 | 73,962 |
Tags: constructive algorithms, greedy, implementation, sortings
Correct Solution:
```
t = int(input())
def process_array(b):
partial_sum = [0 for i in range(len(b))]
placement = [0 for i in range(len(b))]
for i in range(len(b)):
matches = [j for j in range(len(b)) if b[j]==partial_sum[j]]
if len(matches)==0:
break
for m in matches:
partial_sum[m] = -1
placement[m] = i
for j in range(len(b)):
if partial_sum[j]>=0:
for m in matches:
partial_sum[j] += abs(j-m)
return placement
for i in range(t):
s = input()
m = int(input())
b = [int(x) for x in input().split(" ")]
placement = process_array(b)
#print("placement",placement)
dic = {}
for ss in range(len(s)):
if s[ss] not in dic:
dic[s[ss]]=1
else:
dic[s[ss]]+=1
#print("dic",dic)
d_k = list(dic.keys())
d_k = sorted(d_k, reverse=True)
b_d = {}
for bb in placement:
if bb not in b_d:
b_d[bb]=1
else:
b_d[bb]+=1
#print("b_d",b_d)
b_k = list(b_d.keys())
b_k = sorted(b_k)
count_list = [b_d[x] for x in b_k]
#print("count_list",count_list)
ans_k = []
d_iter = 0
for c in count_list:
while dic[d_k[d_iter]]<c:
d_iter+=1
ans_k.append(d_k[d_iter])
d_iter+=1
ans = [0 for j in range(len(placement))]
for j in range(len(ans)):
ans[j] = ans_k[placement[j]]
print("".join(ans))
``` | output | 1 | 36,981 | 24 | 73,963 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp wrote on the board a string s containing only lowercase Latin letters ('a'-'z'). This string is known for you and given in the input.
After that, he erased some letters from the string s, and he rewrote the remaining letters in any order. As a result, he got some new string t. You have to find it with some additional information.
Suppose that the string t has length m and the characters are numbered from left to right from 1 to m. You are given a sequence of m integers: b_1, b_2, …, b_m, where b_i is the sum of the distances |i-j| from the index i to all such indices j that t_j > t_i (consider that 'a'<'b'<...<'z'). In other words, to calculate b_i, Polycarp finds all such indices j that the index j contains a letter that is later in the alphabet than t_i and sums all the values |i-j|.
For example, if t = "abzb", then:
* since t_1='a', all other indices contain letters which are later in the alphabet, that is: b_1=|1-2|+|1-3|+|1-4|=1+2+3=6;
* since t_2='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_2=|2-3|=1;
* since t_3='z', then there are no indexes j such that t_j>t_i, thus b_3=0;
* since t_4='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_4=|4-3|=1.
Thus, if t = "abzb", then b=[6,1,0,1].
Given the string s and the array b, find any possible string t for which the following two requirements are fulfilled simultaneously:
* t is obtained from s by erasing some letters (possibly zero) and then writing the rest in any order;
* the array, constructed from the string t according to the rules above, equals to the array b specified in the input data.
Input
The first line contains an integer q (1 ≤ q ≤ 100) — the number of test cases in the test. Then q test cases follow.
Each test case consists of three lines:
* the first line contains string s, which has a length from 1 to 50 and consists of lowercase English letters;
* the second line contains positive integer m (1 ≤ m ≤ |s|), where |s| is the length of the string s, and m is the length of the array b;
* the third line contains the integers b_1, b_2, ..., b_m (0 ≤ b_i ≤ 1225).
It is guaranteed that in each test case an answer exists.
Output
Output q lines: the k-th of them should contain the answer (string t) to the k-th test case. It is guaranteed that an answer to each test case exists. If there are several answers, output any.
Example
Input
4
abac
3
2 1 0
abc
1
0
abba
3
1 0 1
ecoosdcefr
10
38 13 24 14 11 5 3 24 17 0
Output
aac
b
aba
codeforces
Note
In the first test case, such strings t are suitable: "aac', "aab".
In the second test case, such trings t are suitable: "a", "b", "c".
In the third test case, only the string t equals to "aba" is suitable, but the character 'b' can be from the second or third position. | instruction | 0 | 36,982 | 24 | 73,964 |
Tags: constructive algorithms, greedy, implementation, sortings
Correct Solution:
```
def works(c, i, prob, btgt, m):
val = 0
for j in range(m):
if prob[j] != ' ' and c < prob[j]:
val += abs(i-j)
return val == btgt
def solve0(prob, s, slack, b, m, depth):
# print(' ' * depth + '|' + prob + '|')
if prob.find(' ') == -1:
return prob, True
c = s.pop()
for i in range(m):
if prob[i] != ' ':
continue
if works(c, i, prob, b[i], m):
ans, ok = solve0( prob[:i] + c + prob[i+1:], s.copy(), slack, b, m, depth+1)
if ok:
return ans, True
if slack > 0:
ans, ok = solve0( prob, s, slack-1, b, m, depth+1)
if ok:
return ans, True
return '', False
def solve(s, m, b):
s = sorted(s)
slack = len(s) - m
ans, correct = solve0(' ' * m, s, slack, b, m, 0)
return ans
cases = int(input().strip())
for _ in range(cases):
s = input().strip()
m = int(input().strip())
b = list(map(int, input().strip().split()))
print(solve(s, m, b))
``` | output | 1 | 36,982 | 24 | 73,965 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp wrote on the board a string s containing only lowercase Latin letters ('a'-'z'). This string is known for you and given in the input.
After that, he erased some letters from the string s, and he rewrote the remaining letters in any order. As a result, he got some new string t. You have to find it with some additional information.
Suppose that the string t has length m and the characters are numbered from left to right from 1 to m. You are given a sequence of m integers: b_1, b_2, …, b_m, where b_i is the sum of the distances |i-j| from the index i to all such indices j that t_j > t_i (consider that 'a'<'b'<...<'z'). In other words, to calculate b_i, Polycarp finds all such indices j that the index j contains a letter that is later in the alphabet than t_i and sums all the values |i-j|.
For example, if t = "abzb", then:
* since t_1='a', all other indices contain letters which are later in the alphabet, that is: b_1=|1-2|+|1-3|+|1-4|=1+2+3=6;
* since t_2='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_2=|2-3|=1;
* since t_3='z', then there are no indexes j such that t_j>t_i, thus b_3=0;
* since t_4='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_4=|4-3|=1.
Thus, if t = "abzb", then b=[6,1,0,1].
Given the string s and the array b, find any possible string t for which the following two requirements are fulfilled simultaneously:
* t is obtained from s by erasing some letters (possibly zero) and then writing the rest in any order;
* the array, constructed from the string t according to the rules above, equals to the array b specified in the input data.
Input
The first line contains an integer q (1 ≤ q ≤ 100) — the number of test cases in the test. Then q test cases follow.
Each test case consists of three lines:
* the first line contains string s, which has a length from 1 to 50 and consists of lowercase English letters;
* the second line contains positive integer m (1 ≤ m ≤ |s|), where |s| is the length of the string s, and m is the length of the array b;
* the third line contains the integers b_1, b_2, ..., b_m (0 ≤ b_i ≤ 1225).
It is guaranteed that in each test case an answer exists.
Output
Output q lines: the k-th of them should contain the answer (string t) to the k-th test case. It is guaranteed that an answer to each test case exists. If there are several answers, output any.
Example
Input
4
abac
3
2 1 0
abc
1
0
abba
3
1 0 1
ecoosdcefr
10
38 13 24 14 11 5 3 24 17 0
Output
aac
b
aba
codeforces
Note
In the first test case, such strings t are suitable: "aac', "aab".
In the second test case, such trings t are suitable: "a", "b", "c".
In the third test case, only the string t equals to "aba" is suitable, but the character 'b' can be from the second or third position. | instruction | 0 | 36,983 | 24 | 73,966 |
Tags: constructive algorithms, greedy, implementation, sortings
Correct Solution:
```
t = int(input())
for _ in range(t):
freq = {}
a = input()
for ax in a:
freq[ax] = freq.get(ax, 0) + 1
a = sorted(set(a), reverse=True)
bl = int(input())
b = list(map(int, input().split()))
l = []
li = 0
while li < bl:
sm = []
for bi in range(bl):
if b[bi] == 0:
sm.append(bi)
b[bi] = -1
for bi in range(bl):
if b[bi] != -1:
dis = 0
for x in sm:
dis += abs(bi - x)
b[bi] -= dis
l.append(sm)
li += len(sm)
ans = ['a' for _ in range(bl)]
ai = 0
for lx in l:
while freq[a[ai]] < len(lx):
ai += 1
for ii in lx:
ans[ii] = a[ai]
ai += 1
print("".join(ans))
``` | output | 1 | 36,983 | 24 | 73,967 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp wrote on the board a string s containing only lowercase Latin letters ('a'-'z'). This string is known for you and given in the input.
After that, he erased some letters from the string s, and he rewrote the remaining letters in any order. As a result, he got some new string t. You have to find it with some additional information.
Suppose that the string t has length m and the characters are numbered from left to right from 1 to m. You are given a sequence of m integers: b_1, b_2, …, b_m, where b_i is the sum of the distances |i-j| from the index i to all such indices j that t_j > t_i (consider that 'a'<'b'<...<'z'). In other words, to calculate b_i, Polycarp finds all such indices j that the index j contains a letter that is later in the alphabet than t_i and sums all the values |i-j|.
For example, if t = "abzb", then:
* since t_1='a', all other indices contain letters which are later in the alphabet, that is: b_1=|1-2|+|1-3|+|1-4|=1+2+3=6;
* since t_2='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_2=|2-3|=1;
* since t_3='z', then there are no indexes j such that t_j>t_i, thus b_3=0;
* since t_4='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_4=|4-3|=1.
Thus, if t = "abzb", then b=[6,1,0,1].
Given the string s and the array b, find any possible string t for which the following two requirements are fulfilled simultaneously:
* t is obtained from s by erasing some letters (possibly zero) and then writing the rest in any order;
* the array, constructed from the string t according to the rules above, equals to the array b specified in the input data.
Input
The first line contains an integer q (1 ≤ q ≤ 100) — the number of test cases in the test. Then q test cases follow.
Each test case consists of three lines:
* the first line contains string s, which has a length from 1 to 50 and consists of lowercase English letters;
* the second line contains positive integer m (1 ≤ m ≤ |s|), where |s| is the length of the string s, and m is the length of the array b;
* the third line contains the integers b_1, b_2, ..., b_m (0 ≤ b_i ≤ 1225).
It is guaranteed that in each test case an answer exists.
Output
Output q lines: the k-th of them should contain the answer (string t) to the k-th test case. It is guaranteed that an answer to each test case exists. If there are several answers, output any.
Example
Input
4
abac
3
2 1 0
abc
1
0
abba
3
1 0 1
ecoosdcefr
10
38 13 24 14 11 5 3 24 17 0
Output
aac
b
aba
codeforces
Note
In the first test case, such strings t are suitable: "aac', "aab".
In the second test case, such trings t are suitable: "a", "b", "c".
In the third test case, only the string t equals to "aba" is suitable, but the character 'b' can be from the second or third position. | instruction | 0 | 36,984 | 24 | 73,968 |
Tags: constructive algorithms, greedy, implementation, sortings
Correct Solution:
```
import sys
q=int(sys.stdin.readline())
ans_arr=[]
for i in range(q):
s=sys.stdin.readline().strip()
m=int(sys.stdin.readline())
b=[int(j) for j in sys.stdin.readline().split()]
arr=[]
freq=[0]*26
for g in range(len(s)):
arr.append(s[g])
freq[ord(s[g])-97]+=1
arr.sort()
ans=[]
for g in range(m):
ans.append("a")
ptr=len(arr)-1
d_idx={}
d_ch={}
for sol in range(m):
ind=-2
ctr=0
for e in range(m):
if(b[e]==0 and (e not in d_idx)):
if(ind==-2):
ind=e
ctr+=1
num=ord(arr[ptr])-97
while(freq[num]<ctr):
for g in range(freq[num]):
ptr-=1
num=ord(arr[ptr])-97
d_idx[ind]=1
ans[ind]=arr[ptr]
if(arr[ptr] not in d_ch):
d_ch[arr[ptr]]=1
else:
d_ch[arr[ptr]]+=1
if(ctr==1 and freq[num]-d_ch[arr[ptr]]>0):
for g in range(freq[num]-d_ch[arr[ptr]]):
ptr-=1
ptr-=1
for g in range(m):
if(b[g]!=0):
b[g]=b[g]-abs(g-ind)
answer=""
for h in range(m):
answer+=ans[h]
ans_arr.append(answer)
print("\n".join(ans_arr))
``` | output | 1 | 36,984 | 24 | 73,969 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp wrote on the board a string s containing only lowercase Latin letters ('a'-'z'). This string is known for you and given in the input.
After that, he erased some letters from the string s, and he rewrote the remaining letters in any order. As a result, he got some new string t. You have to find it with some additional information.
Suppose that the string t has length m and the characters are numbered from left to right from 1 to m. You are given a sequence of m integers: b_1, b_2, …, b_m, where b_i is the sum of the distances |i-j| from the index i to all such indices j that t_j > t_i (consider that 'a'<'b'<...<'z'). In other words, to calculate b_i, Polycarp finds all such indices j that the index j contains a letter that is later in the alphabet than t_i and sums all the values |i-j|.
For example, if t = "abzb", then:
* since t_1='a', all other indices contain letters which are later in the alphabet, that is: b_1=|1-2|+|1-3|+|1-4|=1+2+3=6;
* since t_2='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_2=|2-3|=1;
* since t_3='z', then there are no indexes j such that t_j>t_i, thus b_3=0;
* since t_4='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_4=|4-3|=1.
Thus, if t = "abzb", then b=[6,1,0,1].
Given the string s and the array b, find any possible string t for which the following two requirements are fulfilled simultaneously:
* t is obtained from s by erasing some letters (possibly zero) and then writing the rest in any order;
* the array, constructed from the string t according to the rules above, equals to the array b specified in the input data.
Input
The first line contains an integer q (1 ≤ q ≤ 100) — the number of test cases in the test. Then q test cases follow.
Each test case consists of three lines:
* the first line contains string s, which has a length from 1 to 50 and consists of lowercase English letters;
* the second line contains positive integer m (1 ≤ m ≤ |s|), where |s| is the length of the string s, and m is the length of the array b;
* the third line contains the integers b_1, b_2, ..., b_m (0 ≤ b_i ≤ 1225).
It is guaranteed that in each test case an answer exists.
Output
Output q lines: the k-th of them should contain the answer (string t) to the k-th test case. It is guaranteed that an answer to each test case exists. If there are several answers, output any.
Example
Input
4
abac
3
2 1 0
abc
1
0
abba
3
1 0 1
ecoosdcefr
10
38 13 24 14 11 5 3 24 17 0
Output
aac
b
aba
codeforces
Note
In the first test case, such strings t are suitable: "aac', "aab".
In the second test case, such trings t are suitable: "a", "b", "c".
In the third test case, only the string t equals to "aba" is suitable, but the character 'b' can be from the second or third position. | instruction | 0 | 36,985 | 24 | 73,970 |
Tags: constructive algorithms, greedy, implementation, sortings
Correct Solution:
```
T = int(input())
for _ in range(T):
S = input()
M = int(input())
B = list(map(int, input().split()))
Alpha = {}
for elt in S:
try:
Alpha[elt] += 1
except KeyError:
Alpha[elt] = 1
Alpha = list(Alpha.items())
Alpha.sort(key = lambda x: x[0])
ans = [None]*M
Done = 0
while Done < M:
Zeros = []
Count = 0
for i, elt in enumerate(B):
if elt == 0:
Zeros += i,
Count += 1
toRemove = 0
for letter, count in Alpha[::-1]:
toRemove -= 1
if count >= Count:
for i in Zeros:
ans[i] = letter
Done += Count
break
del Alpha[toRemove:]
for elt in Zeros:
for i in range(len(B)):
if i == elt:
B[i] = -1
else:
B[i] -= abs(i-elt)
print("".join(ans))
``` | output | 1 | 36,985 | 24 | 73,971 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp wrote on the board a string s containing only lowercase Latin letters ('a'-'z'). This string is known for you and given in the input.
After that, he erased some letters from the string s, and he rewrote the remaining letters in any order. As a result, he got some new string t. You have to find it with some additional information.
Suppose that the string t has length m and the characters are numbered from left to right from 1 to m. You are given a sequence of m integers: b_1, b_2, …, b_m, where b_i is the sum of the distances |i-j| from the index i to all such indices j that t_j > t_i (consider that 'a'<'b'<...<'z'). In other words, to calculate b_i, Polycarp finds all such indices j that the index j contains a letter that is later in the alphabet than t_i and sums all the values |i-j|.
For example, if t = "abzb", then:
* since t_1='a', all other indices contain letters which are later in the alphabet, that is: b_1=|1-2|+|1-3|+|1-4|=1+2+3=6;
* since t_2='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_2=|2-3|=1;
* since t_3='z', then there are no indexes j such that t_j>t_i, thus b_3=0;
* since t_4='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_4=|4-3|=1.
Thus, if t = "abzb", then b=[6,1,0,1].
Given the string s and the array b, find any possible string t for which the following two requirements are fulfilled simultaneously:
* t is obtained from s by erasing some letters (possibly zero) and then writing the rest in any order;
* the array, constructed from the string t according to the rules above, equals to the array b specified in the input data.
Input
The first line contains an integer q (1 ≤ q ≤ 100) — the number of test cases in the test. Then q test cases follow.
Each test case consists of three lines:
* the first line contains string s, which has a length from 1 to 50 and consists of lowercase English letters;
* the second line contains positive integer m (1 ≤ m ≤ |s|), where |s| is the length of the string s, and m is the length of the array b;
* the third line contains the integers b_1, b_2, ..., b_m (0 ≤ b_i ≤ 1225).
It is guaranteed that in each test case an answer exists.
Output
Output q lines: the k-th of them should contain the answer (string t) to the k-th test case. It is guaranteed that an answer to each test case exists. If there are several answers, output any.
Example
Input
4
abac
3
2 1 0
abc
1
0
abba
3
1 0 1
ecoosdcefr
10
38 13 24 14 11 5 3 24 17 0
Output
aac
b
aba
codeforces
Note
In the first test case, such strings t are suitable: "aac', "aab".
In the second test case, such trings t are suitable: "a", "b", "c".
In the third test case, only the string t equals to "aba" is suitable, but the character 'b' can be from the second or third position. | instruction | 0 | 36,986 | 24 | 73,972 |
Tags: constructive algorithms, greedy, implementation, sortings
Correct Solution:
```
q=int(input())
for i in range(q):
s=input()
m=int(input())
b=list(map(int, input().split()))
d={}
l=sorted(list(set(s)), reverse=True)
for alphabet in l:
d[alphabet]=s.count(alphabet)
ret='0'*m
l0=-1
while 1:
bcopy=b.copy()
n=b.count(0)
if n==0:
break
for j in range(1,30):
if d[l[l0+j]]>=n:
l0+=j
alphabet=l[l0]
break
for j in range(m):
if b[j]==0:
ret=ret[0:j]+alphabet+ret[j+1:]
for k in range(m):
if b[k]!=0:
bcopy[k]-=abs(k-j)
bcopy[j]=-1
b=bcopy
print(ret)
``` | output | 1 | 36,986 | 24 | 73,973 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp wrote on the board a string s containing only lowercase Latin letters ('a'-'z'). This string is known for you and given in the input.
After that, he erased some letters from the string s, and he rewrote the remaining letters in any order. As a result, he got some new string t. You have to find it with some additional information.
Suppose that the string t has length m and the characters are numbered from left to right from 1 to m. You are given a sequence of m integers: b_1, b_2, …, b_m, where b_i is the sum of the distances |i-j| from the index i to all such indices j that t_j > t_i (consider that 'a'<'b'<...<'z'). In other words, to calculate b_i, Polycarp finds all such indices j that the index j contains a letter that is later in the alphabet than t_i and sums all the values |i-j|.
For example, if t = "abzb", then:
* since t_1='a', all other indices contain letters which are later in the alphabet, that is: b_1=|1-2|+|1-3|+|1-4|=1+2+3=6;
* since t_2='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_2=|2-3|=1;
* since t_3='z', then there are no indexes j such that t_j>t_i, thus b_3=0;
* since t_4='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_4=|4-3|=1.
Thus, if t = "abzb", then b=[6,1,0,1].
Given the string s and the array b, find any possible string t for which the following two requirements are fulfilled simultaneously:
* t is obtained from s by erasing some letters (possibly zero) and then writing the rest in any order;
* the array, constructed from the string t according to the rules above, equals to the array b specified in the input data.
Input
The first line contains an integer q (1 ≤ q ≤ 100) — the number of test cases in the test. Then q test cases follow.
Each test case consists of three lines:
* the first line contains string s, which has a length from 1 to 50 and consists of lowercase English letters;
* the second line contains positive integer m (1 ≤ m ≤ |s|), where |s| is the length of the string s, and m is the length of the array b;
* the third line contains the integers b_1, b_2, ..., b_m (0 ≤ b_i ≤ 1225).
It is guaranteed that in each test case an answer exists.
Output
Output q lines: the k-th of them should contain the answer (string t) to the k-th test case. It is guaranteed that an answer to each test case exists. If there are several answers, output any.
Example
Input
4
abac
3
2 1 0
abc
1
0
abba
3
1 0 1
ecoosdcefr
10
38 13 24 14 11 5 3 24 17 0
Output
aac
b
aba
codeforces
Note
In the first test case, such strings t are suitable: "aac', "aab".
In the second test case, such trings t are suitable: "a", "b", "c".
In the third test case, only the string t equals to "aba" is suitable, but the character 'b' can be from the second or third position.
Submitted Solution:
```
for _ in range(int(input())):
s = input()
n = int(input())
m = n
b = list(map(int,input().split()))
c = ['']*m
freq = [0]*26
i = 25
for elem in s:
freq[ord(elem)-ord('a')]+=1
while n>0 and i>=0:
zero=[]
count = 0
for j in range(m):
if b[j]==0:
zero.append(j)
b[j]=-1
count+=1
while i>=0:
if freq[i]>=count:
for elem in zero:
c[elem]=chr(i + ord('a'))
n -= count
for j in range(m):
for elem in zero:
if b[j] > 0:
b[j] -= abs(j - elem)
i -= 1
break
else:
i -= 1
print(''.join(c))
``` | instruction | 0 | 36,987 | 24 | 73,974 |
Yes | output | 1 | 36,987 | 24 | 73,975 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp wrote on the board a string s containing only lowercase Latin letters ('a'-'z'). This string is known for you and given in the input.
After that, he erased some letters from the string s, and he rewrote the remaining letters in any order. As a result, he got some new string t. You have to find it with some additional information.
Suppose that the string t has length m and the characters are numbered from left to right from 1 to m. You are given a sequence of m integers: b_1, b_2, …, b_m, where b_i is the sum of the distances |i-j| from the index i to all such indices j that t_j > t_i (consider that 'a'<'b'<...<'z'). In other words, to calculate b_i, Polycarp finds all such indices j that the index j contains a letter that is later in the alphabet than t_i and sums all the values |i-j|.
For example, if t = "abzb", then:
* since t_1='a', all other indices contain letters which are later in the alphabet, that is: b_1=|1-2|+|1-3|+|1-4|=1+2+3=6;
* since t_2='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_2=|2-3|=1;
* since t_3='z', then there are no indexes j such that t_j>t_i, thus b_3=0;
* since t_4='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_4=|4-3|=1.
Thus, if t = "abzb", then b=[6,1,0,1].
Given the string s and the array b, find any possible string t for which the following two requirements are fulfilled simultaneously:
* t is obtained from s by erasing some letters (possibly zero) and then writing the rest in any order;
* the array, constructed from the string t according to the rules above, equals to the array b specified in the input data.
Input
The first line contains an integer q (1 ≤ q ≤ 100) — the number of test cases in the test. Then q test cases follow.
Each test case consists of three lines:
* the first line contains string s, which has a length from 1 to 50 and consists of lowercase English letters;
* the second line contains positive integer m (1 ≤ m ≤ |s|), where |s| is the length of the string s, and m is the length of the array b;
* the third line contains the integers b_1, b_2, ..., b_m (0 ≤ b_i ≤ 1225).
It is guaranteed that in each test case an answer exists.
Output
Output q lines: the k-th of them should contain the answer (string t) to the k-th test case. It is guaranteed that an answer to each test case exists. If there are several answers, output any.
Example
Input
4
abac
3
2 1 0
abc
1
0
abba
3
1 0 1
ecoosdcefr
10
38 13 24 14 11 5 3 24 17 0
Output
aac
b
aba
codeforces
Note
In the first test case, such strings t are suitable: "aac', "aab".
In the second test case, such trings t are suitable: "a", "b", "c".
In the third test case, only the string t equals to "aba" is suitable, but the character 'b' can be from the second or third position.
Submitted Solution:
```
from collections import defaultdict
letters = list(reversed([chr(x) for x in range(ord('a'), ord('z') + 1)]))
t = int(input())
for case in range(t):
s = input()
n = len(s)
letter_count = defaultdict(int)
for l in s:
letter_count[l] += 1
m = int(input())
b = list(map(int, input().split()))
visited = [0] * m
counter = 0
i = 0
output = ['a'] * m
while counter < m:
zeros = []
for j in range(m):
if not visited[j] and b[j] == 0:
visited[j] = 1
zeros.append(j)
counter += 1
while i <= 26 and letter_count[letters[i]] < len(zeros):
i += 1
for j in zeros:
output[j] = letters[i]
for j in range(m):
for k in zeros:
b[j] -= abs(j - k)
i += 1
print(''.join(output))
``` | instruction | 0 | 36,988 | 24 | 73,976 |
Yes | output | 1 | 36,988 | 24 | 73,977 |
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