message stringlengths 2 43.5k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 853 107k | cluster float64 24 24 | __index_level_0__ int64 1.71k 214k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp analyzes the prices of the new berPhone. At his disposal are the prices for n last days: a_1, a_2, ..., a_n, where a_i is the price of berPhone on the day i.
Polycarp considers the price on the day i to be bad if later (that is, a day with a greater number) berPhone was sold at a lower price. For example, if n=6 and a=[3, 9, 4, 6, 7, 5], then the number of days with a bad price is 3 — these are days 2 (a_2=9), 4 (a_4=6) and 5 (a_5=7).
Print the number of days with a bad price.
You have to answer t independent data sets.
Input
The first line contains an integer t (1 ≤ t ≤ 10000) — the number of sets of input data in the test. Input data sets must be processed independently, one after another.
Each input data set consists of two lines. The first line contains an integer n (1 ≤ n ≤ 150000) — the number of days. The second line contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^6), where a_i is the price on the i-th day.
It is guaranteed that the sum of n over all data sets in the test does not exceed 150000.
Output
Print t integers, the j-th of which should be equal to the number of days with a bad price in the j-th input data set.
Example
Input
5
6
3 9 4 6 7 5
1
1000000
2
2 1
10
31 41 59 26 53 58 97 93 23 84
7
3 2 1 2 3 4 5
Output
3
0
1
8
2 | instruction | 0 | 58,915 | 24 | 117,830 |
Tags: data structures, implementation
Correct Solution:
```
from sys import stdin
input = stdin.buffer.readline
t=int(input())
for i in range(t):
n=int(input())
arr=[int(x) for x in input().split()]
cnt=0
m=arr[n-1]
for i in range(n-2,-1,-1):
if arr[i]>m:
cnt=cnt+1
else:
m=arr[i]
print(cnt)
``` | output | 1 | 58,915 | 24 | 117,831 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp analyzes the prices of the new berPhone. At his disposal are the prices for n last days: a_1, a_2, ..., a_n, where a_i is the price of berPhone on the day i.
Polycarp considers the price on the day i to be bad if later (that is, a day with a greater number) berPhone was sold at a lower price. For example, if n=6 and a=[3, 9, 4, 6, 7, 5], then the number of days with a bad price is 3 — these are days 2 (a_2=9), 4 (a_4=6) and 5 (a_5=7).
Print the number of days with a bad price.
You have to answer t independent data sets.
Input
The first line contains an integer t (1 ≤ t ≤ 10000) — the number of sets of input data in the test. Input data sets must be processed independently, one after another.
Each input data set consists of two lines. The first line contains an integer n (1 ≤ n ≤ 150000) — the number of days. The second line contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^6), where a_i is the price on the i-th day.
It is guaranteed that the sum of n over all data sets in the test does not exceed 150000.
Output
Print t integers, the j-th of which should be equal to the number of days with a bad price in the j-th input data set.
Example
Input
5
6
3 9 4 6 7 5
1
1000000
2
2 1
10
31 41 59 26 53 58 97 93 23 84
7
3 2 1 2 3 4 5
Output
3
0
1
8
2 | instruction | 0 | 58,916 | 24 | 117,832 |
Tags: data structures, implementation
Correct Solution:
```
t=int(input())
for i in range(t):
n=int(input())
a=list(map(int,input().split()))
mi=a[n-1]
j=n-2
ans=0
while j>-1:
if a[j]>mi:
ans+=1
elif a[j]<mi:
mi=a[j]
j=j-1
print(ans)
``` | output | 1 | 58,916 | 24 | 117,833 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp analyzes the prices of the new berPhone. At his disposal are the prices for n last days: a_1, a_2, ..., a_n, where a_i is the price of berPhone on the day i.
Polycarp considers the price on the day i to be bad if later (that is, a day with a greater number) berPhone was sold at a lower price. For example, if n=6 and a=[3, 9, 4, 6, 7, 5], then the number of days with a bad price is 3 — these are days 2 (a_2=9), 4 (a_4=6) and 5 (a_5=7).
Print the number of days with a bad price.
You have to answer t independent data sets.
Input
The first line contains an integer t (1 ≤ t ≤ 10000) — the number of sets of input data in the test. Input data sets must be processed independently, one after another.
Each input data set consists of two lines. The first line contains an integer n (1 ≤ n ≤ 150000) — the number of days. The second line contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^6), where a_i is the price on the i-th day.
It is guaranteed that the sum of n over all data sets in the test does not exceed 150000.
Output
Print t integers, the j-th of which should be equal to the number of days with a bad price in the j-th input data set.
Example
Input
5
6
3 9 4 6 7 5
1
1000000
2
2 1
10
31 41 59 26 53 58 97 93 23 84
7
3 2 1 2 3 4 5
Output
3
0
1
8
2 | instruction | 0 | 58,917 | 24 | 117,834 |
Tags: data structures, implementation
Correct Solution:
```
t=int(input())
# print(t)
for i in range(t):
n=input()
arr = input()
arr = [int(a) for a in arr.split(" ")]
# print(arr)
min_price=arr[len(arr)-1]
count=0
if(len(arr)>1):
for a in arr[::-1][1:]:
if min_price<a:
count+=1
else:
min_price=a
print(count)
``` | output | 1 | 58,917 | 24 | 117,835 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp analyzes the prices of the new berPhone. At his disposal are the prices for n last days: a_1, a_2, ..., a_n, where a_i is the price of berPhone on the day i.
Polycarp considers the price on the day i to be bad if later (that is, a day with a greater number) berPhone was sold at a lower price. For example, if n=6 and a=[3, 9, 4, 6, 7, 5], then the number of days with a bad price is 3 — these are days 2 (a_2=9), 4 (a_4=6) and 5 (a_5=7).
Print the number of days with a bad price.
You have to answer t independent data sets.
Input
The first line contains an integer t (1 ≤ t ≤ 10000) — the number of sets of input data in the test. Input data sets must be processed independently, one after another.
Each input data set consists of two lines. The first line contains an integer n (1 ≤ n ≤ 150000) — the number of days. The second line contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^6), where a_i is the price on the i-th day.
It is guaranteed that the sum of n over all data sets in the test does not exceed 150000.
Output
Print t integers, the j-th of which should be equal to the number of days with a bad price in the j-th input data set.
Example
Input
5
6
3 9 4 6 7 5
1
1000000
2
2 1
10
31 41 59 26 53 58 97 93 23 84
7
3 2 1 2 3 4 5
Output
3
0
1
8
2 | instruction | 0 | 58,918 | 24 | 117,836 |
Tags: data structures, implementation
Correct Solution:
```
from sys import stdin
input = stdin.readline
for _ in range(int(input())):
n = int(input())
l = list(map(int, input().split()))
l = l[::-1]
sm = l[0]
c = 0
for i in l:
if i > sm:
c += 1
sm = min(sm, i)
print(c)
``` | output | 1 | 58,918 | 24 | 117,837 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp analyzes the prices of the new berPhone. At his disposal are the prices for n last days: a_1, a_2, ..., a_n, where a_i is the price of berPhone on the day i.
Polycarp considers the price on the day i to be bad if later (that is, a day with a greater number) berPhone was sold at a lower price. For example, if n=6 and a=[3, 9, 4, 6, 7, 5], then the number of days with a bad price is 3 — these are days 2 (a_2=9), 4 (a_4=6) and 5 (a_5=7).
Print the number of days with a bad price.
You have to answer t independent data sets.
Input
The first line contains an integer t (1 ≤ t ≤ 10000) — the number of sets of input data in the test. Input data sets must be processed independently, one after another.
Each input data set consists of two lines. The first line contains an integer n (1 ≤ n ≤ 150000) — the number of days. The second line contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^6), where a_i is the price on the i-th day.
It is guaranteed that the sum of n over all data sets in the test does not exceed 150000.
Output
Print t integers, the j-th of which should be equal to the number of days with a bad price in the j-th input data set.
Example
Input
5
6
3 9 4 6 7 5
1
1000000
2
2 1
10
31 41 59 26 53 58 97 93 23 84
7
3 2 1 2 3 4 5
Output
3
0
1
8
2 | instruction | 0 | 58,919 | 24 | 117,838 |
Tags: data structures, implementation
Correct Solution:
```
t = int(input())
for i in range(t):
n = int(input())
arr = list(map(int,input().split()))
tmp = arr[-1]
ans = 0
j= n-2
while(j>=0):
if tmp <arr[j]:
ans += 1
else:
tmp = arr[j]
j -= 1
print(ans)
``` | output | 1 | 58,919 | 24 | 117,839 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp analyzes the prices of the new berPhone. At his disposal are the prices for n last days: a_1, a_2, ..., a_n, where a_i is the price of berPhone on the day i.
Polycarp considers the price on the day i to be bad if later (that is, a day with a greater number) berPhone was sold at a lower price. For example, if n=6 and a=[3, 9, 4, 6, 7, 5], then the number of days with a bad price is 3 — these are days 2 (a_2=9), 4 (a_4=6) and 5 (a_5=7).
Print the number of days with a bad price.
You have to answer t independent data sets.
Input
The first line contains an integer t (1 ≤ t ≤ 10000) — the number of sets of input data in the test. Input data sets must be processed independently, one after another.
Each input data set consists of two lines. The first line contains an integer n (1 ≤ n ≤ 150000) — the number of days. The second line contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^6), where a_i is the price on the i-th day.
It is guaranteed that the sum of n over all data sets in the test does not exceed 150000.
Output
Print t integers, the j-th of which should be equal to the number of days with a bad price in the j-th input data set.
Example
Input
5
6
3 9 4 6 7 5
1
1000000
2
2 1
10
31 41 59 26 53 58 97 93 23 84
7
3 2 1 2 3 4 5
Output
3
0
1
8
2 | instruction | 0 | 58,920 | 24 | 117,840 |
Tags: data structures, implementation
Correct Solution:
```
user_input = int(input())
for i in range(user_input):
a = int(input())
b = list(map(int, input().split()))
count = 0
minimum = b[-1]
for j in range(a-2, -1, -1):
if b[j] > minimum:
count += 1
minimum = min(b[j], minimum)
print(count)
``` | output | 1 | 58,920 | 24 | 117,841 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp analyzes the prices of the new berPhone. At his disposal are the prices for n last days: a_1, a_2, ..., a_n, where a_i is the price of berPhone on the day i.
Polycarp considers the price on the day i to be bad if later (that is, a day with a greater number) berPhone was sold at a lower price. For example, if n=6 and a=[3, 9, 4, 6, 7, 5], then the number of days with a bad price is 3 — these are days 2 (a_2=9), 4 (a_4=6) and 5 (a_5=7).
Print the number of days with a bad price.
You have to answer t independent data sets.
Input
The first line contains an integer t (1 ≤ t ≤ 10000) — the number of sets of input data in the test. Input data sets must be processed independently, one after another.
Each input data set consists of two lines. The first line contains an integer n (1 ≤ n ≤ 150000) — the number of days. The second line contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^6), where a_i is the price on the i-th day.
It is guaranteed that the sum of n over all data sets in the test does not exceed 150000.
Output
Print t integers, the j-th of which should be equal to the number of days with a bad price in the j-th input data set.
Example
Input
5
6
3 9 4 6 7 5
1
1000000
2
2 1
10
31 41 59 26 53 58 97 93 23 84
7
3 2 1 2 3 4 5
Output
3
0
1
8
2 | instruction | 0 | 58,921 | 24 | 117,842 |
Tags: data structures, implementation
Correct Solution:
```
n = int(input())
for i in range(n):
a = int(input())
li = list(map(int,input().split()))
pivot = li[-1]
count = 0
for i in range(-2,-(len(li))-1,-1):
if pivot<li[i]:
count+=1
else:
pivot = li[i]
print(count)
``` | output | 1 | 58,921 | 24 | 117,843 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp analyzes the prices of the new berPhone. At his disposal are the prices for n last days: a_1, a_2, ..., a_n, where a_i is the price of berPhone on the day i.
Polycarp considers the price on the day i to be bad if later (that is, a day with a greater number) berPhone was sold at a lower price. For example, if n=6 and a=[3, 9, 4, 6, 7, 5], then the number of days with a bad price is 3 — these are days 2 (a_2=9), 4 (a_4=6) and 5 (a_5=7).
Print the number of days with a bad price.
You have to answer t independent data sets.
Input
The first line contains an integer t (1 ≤ t ≤ 10000) — the number of sets of input data in the test. Input data sets must be processed independently, one after another.
Each input data set consists of two lines. The first line contains an integer n (1 ≤ n ≤ 150000) — the number of days. The second line contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^6), where a_i is the price on the i-th day.
It is guaranteed that the sum of n over all data sets in the test does not exceed 150000.
Output
Print t integers, the j-th of which should be equal to the number of days with a bad price in the j-th input data set.
Example
Input
5
6
3 9 4 6 7 5
1
1000000
2
2 1
10
31 41 59 26 53 58 97 93 23 84
7
3 2 1 2 3 4 5
Output
3
0
1
8
2
Submitted Solution:
```
t=int(input())
while(t>0):
n=int(input())
a=list(map(int,input().split()))
min=a[n-1]
ans=0
for i in range(n-1,-1,-1):
if(a[i]>min):
ans+=1
else:
min=a[i]
print(ans)
t-=1
``` | instruction | 0 | 58,922 | 24 | 117,844 |
Yes | output | 1 | 58,922 | 24 | 117,845 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp analyzes the prices of the new berPhone. At his disposal are the prices for n last days: a_1, a_2, ..., a_n, where a_i is the price of berPhone on the day i.
Polycarp considers the price on the day i to be bad if later (that is, a day with a greater number) berPhone was sold at a lower price. For example, if n=6 and a=[3, 9, 4, 6, 7, 5], then the number of days with a bad price is 3 — these are days 2 (a_2=9), 4 (a_4=6) and 5 (a_5=7).
Print the number of days with a bad price.
You have to answer t independent data sets.
Input
The first line contains an integer t (1 ≤ t ≤ 10000) — the number of sets of input data in the test. Input data sets must be processed independently, one after another.
Each input data set consists of two lines. The first line contains an integer n (1 ≤ n ≤ 150000) — the number of days. The second line contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^6), where a_i is the price on the i-th day.
It is guaranteed that the sum of n over all data sets in the test does not exceed 150000.
Output
Print t integers, the j-th of which should be equal to the number of days with a bad price in the j-th input data set.
Example
Input
5
6
3 9 4 6 7 5
1
1000000
2
2 1
10
31 41 59 26 53 58 97 93 23 84
7
3 2 1 2 3 4 5
Output
3
0
1
8
2
Submitted Solution:
```
t=int(input())
for _ in range(t):
n=int(input())
A=list(map(int,input().split()))
c=0
r=1000000000000000000000000000000000000
for i in range(n-1,-1,-1):
if(A[i]>r):
c+=1
r=min(r,A[i]);
print(c)
``` | instruction | 0 | 58,923 | 24 | 117,846 |
Yes | output | 1 | 58,923 | 24 | 117,847 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp analyzes the prices of the new berPhone. At his disposal are the prices for n last days: a_1, a_2, ..., a_n, where a_i is the price of berPhone on the day i.
Polycarp considers the price on the day i to be bad if later (that is, a day with a greater number) berPhone was sold at a lower price. For example, if n=6 and a=[3, 9, 4, 6, 7, 5], then the number of days with a bad price is 3 — these are days 2 (a_2=9), 4 (a_4=6) and 5 (a_5=7).
Print the number of days with a bad price.
You have to answer t independent data sets.
Input
The first line contains an integer t (1 ≤ t ≤ 10000) — the number of sets of input data in the test. Input data sets must be processed independently, one after another.
Each input data set consists of two lines. The first line contains an integer n (1 ≤ n ≤ 150000) — the number of days. The second line contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^6), where a_i is the price on the i-th day.
It is guaranteed that the sum of n over all data sets in the test does not exceed 150000.
Output
Print t integers, the j-th of which should be equal to the number of days with a bad price in the j-th input data set.
Example
Input
5
6
3 9 4 6 7 5
1
1000000
2
2 1
10
31 41 59 26 53 58 97 93 23 84
7
3 2 1 2 3 4 5
Output
3
0
1
8
2
Submitted Solution:
```
t=int(input())
for _ in range(t):
n=int(input())
c=0
arr=[int(x) for x in str(input()).split()]
mini = arr[-1]
for i in arr[::-1]:
#print(i)
if(mini>=i):
mini=i
else:
c+=1
print(c)
``` | instruction | 0 | 58,924 | 24 | 117,848 |
Yes | output | 1 | 58,924 | 24 | 117,849 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp analyzes the prices of the new berPhone. At his disposal are the prices for n last days: a_1, a_2, ..., a_n, where a_i is the price of berPhone on the day i.
Polycarp considers the price on the day i to be bad if later (that is, a day with a greater number) berPhone was sold at a lower price. For example, if n=6 and a=[3, 9, 4, 6, 7, 5], then the number of days with a bad price is 3 — these are days 2 (a_2=9), 4 (a_4=6) and 5 (a_5=7).
Print the number of days with a bad price.
You have to answer t independent data sets.
Input
The first line contains an integer t (1 ≤ t ≤ 10000) — the number of sets of input data in the test. Input data sets must be processed independently, one after another.
Each input data set consists of two lines. The first line contains an integer n (1 ≤ n ≤ 150000) — the number of days. The second line contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^6), where a_i is the price on the i-th day.
It is guaranteed that the sum of n over all data sets in the test does not exceed 150000.
Output
Print t integers, the j-th of which should be equal to the number of days with a bad price in the j-th input data set.
Example
Input
5
6
3 9 4 6 7 5
1
1000000
2
2 1
10
31 41 59 26 53 58 97 93 23 84
7
3 2 1 2 3 4 5
Output
3
0
1
8
2
Submitted Solution:
```
t = int(input())
for i in range(t) :
n = int(input())
a = list(map(int,input().strip().split()))[:n]
count = 0
mn = a[n-1]
for j in range(n-1,-1,-1) :
if a[j] > mn :
count += 1
mn = min(mn,a[j])
print(count)
``` | instruction | 0 | 58,925 | 24 | 117,850 |
Yes | output | 1 | 58,925 | 24 | 117,851 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp analyzes the prices of the new berPhone. At his disposal are the prices for n last days: a_1, a_2, ..., a_n, where a_i is the price of berPhone on the day i.
Polycarp considers the price on the day i to be bad if later (that is, a day with a greater number) berPhone was sold at a lower price. For example, if n=6 and a=[3, 9, 4, 6, 7, 5], then the number of days with a bad price is 3 — these are days 2 (a_2=9), 4 (a_4=6) and 5 (a_5=7).
Print the number of days with a bad price.
You have to answer t independent data sets.
Input
The first line contains an integer t (1 ≤ t ≤ 10000) — the number of sets of input data in the test. Input data sets must be processed independently, one after another.
Each input data set consists of two lines. The first line contains an integer n (1 ≤ n ≤ 150000) — the number of days. The second line contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^6), where a_i is the price on the i-th day.
It is guaranteed that the sum of n over all data sets in the test does not exceed 150000.
Output
Print t integers, the j-th of which should be equal to the number of days with a bad price in the j-th input data set.
Example
Input
5
6
3 9 4 6 7 5
1
1000000
2
2 1
10
31 41 59 26 53 58 97 93 23 84
7
3 2 1 2 3 4 5
Output
3
0
1
8
2
Submitted Solution:
```
t = int(input())
for i in range(t):
n = int(input())
i = list(map(int, input().split()))
bd_count = 1
min_num = i[-1]
# last_index = len(i)-1
for day in i[::-1]:
if day < min_num:
bd_count += 1
# last_index -=1
min_num = day
print(len(i)-bd_count)
``` | instruction | 0 | 58,926 | 24 | 117,852 |
No | output | 1 | 58,926 | 24 | 117,853 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp analyzes the prices of the new berPhone. At his disposal are the prices for n last days: a_1, a_2, ..., a_n, where a_i is the price of berPhone on the day i.
Polycarp considers the price on the day i to be bad if later (that is, a day with a greater number) berPhone was sold at a lower price. For example, if n=6 and a=[3, 9, 4, 6, 7, 5], then the number of days with a bad price is 3 — these are days 2 (a_2=9), 4 (a_4=6) and 5 (a_5=7).
Print the number of days with a bad price.
You have to answer t independent data sets.
Input
The first line contains an integer t (1 ≤ t ≤ 10000) — the number of sets of input data in the test. Input data sets must be processed independently, one after another.
Each input data set consists of two lines. The first line contains an integer n (1 ≤ n ≤ 150000) — the number of days. The second line contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^6), where a_i is the price on the i-th day.
It is guaranteed that the sum of n over all data sets in the test does not exceed 150000.
Output
Print t integers, the j-th of which should be equal to the number of days with a bad price in the j-th input data set.
Example
Input
5
6
3 9 4 6 7 5
1
1000000
2
2 1
10
31 41 59 26 53 58 97 93 23 84
7
3 2 1 2 3 4 5
Output
3
0
1
8
2
Submitted Solution:
```
for _ in range(int(input())):
count = 0
i = 0
n = int(input())
a = list(map(int, input().split()))
while i != n:
i = a.index(max(a[i:]))
i += 1
count += 1
print(count)
``` | instruction | 0 | 58,927 | 24 | 117,854 |
No | output | 1 | 58,927 | 24 | 117,855 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp analyzes the prices of the new berPhone. At his disposal are the prices for n last days: a_1, a_2, ..., a_n, where a_i is the price of berPhone on the day i.
Polycarp considers the price on the day i to be bad if later (that is, a day with a greater number) berPhone was sold at a lower price. For example, if n=6 and a=[3, 9, 4, 6, 7, 5], then the number of days with a bad price is 3 — these are days 2 (a_2=9), 4 (a_4=6) and 5 (a_5=7).
Print the number of days with a bad price.
You have to answer t independent data sets.
Input
The first line contains an integer t (1 ≤ t ≤ 10000) — the number of sets of input data in the test. Input data sets must be processed independently, one after another.
Each input data set consists of two lines. The first line contains an integer n (1 ≤ n ≤ 150000) — the number of days. The second line contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^6), where a_i is the price on the i-th day.
It is guaranteed that the sum of n over all data sets in the test does not exceed 150000.
Output
Print t integers, the j-th of which should be equal to the number of days with a bad price in the j-th input data set.
Example
Input
5
6
3 9 4 6 7 5
1
1000000
2
2 1
10
31 41 59 26 53 58 97 93 23 84
7
3 2 1 2 3 4 5
Output
3
0
1
8
2
Submitted Solution:
```
import heapq
for i in range(int(input())):
N = int(input())
A = [int(_) for _ in input().split()]
count = 0
flag = True
l_i = -1
j = 0
S_A = sorted(A)
dic = {}
for p in range(N):
dic[A[p]] = p
while(flag):
value = S_A[j]
index = dic[value]
if index>l_i:
count += (index-l_i-1)
l_i = index
if index==N-1:
flag = False
j+=1
print(count)
``` | instruction | 0 | 58,928 | 24 | 117,856 |
No | output | 1 | 58,928 | 24 | 117,857 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp analyzes the prices of the new berPhone. At his disposal are the prices for n last days: a_1, a_2, ..., a_n, where a_i is the price of berPhone on the day i.
Polycarp considers the price on the day i to be bad if later (that is, a day with a greater number) berPhone was sold at a lower price. For example, if n=6 and a=[3, 9, 4, 6, 7, 5], then the number of days with a bad price is 3 — these are days 2 (a_2=9), 4 (a_4=6) and 5 (a_5=7).
Print the number of days with a bad price.
You have to answer t independent data sets.
Input
The first line contains an integer t (1 ≤ t ≤ 10000) — the number of sets of input data in the test. Input data sets must be processed independently, one after another.
Each input data set consists of two lines. The first line contains an integer n (1 ≤ n ≤ 150000) — the number of days. The second line contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^6), where a_i is the price on the i-th day.
It is guaranteed that the sum of n over all data sets in the test does not exceed 150000.
Output
Print t integers, the j-th of which should be equal to the number of days with a bad price in the j-th input data set.
Example
Input
5
6
3 9 4 6 7 5
1
1000000
2
2 1
10
31 41 59 26 53 58 97 93 23 84
7
3 2 1 2 3 4 5
Output
3
0
1
8
2
Submitted Solution:
```
t=int(input())
for i in range(t):
count=0
n=int(input())
a=input().split()
Min=a[n-1]
for j in range(n-2,-1,-1):
if a[j]>Min:
count+=1
elif a[j]<Min:
Min=a[j]
print(count)
``` | instruction | 0 | 58,929 | 24 | 117,858 |
No | output | 1 | 58,929 | 24 | 117,859 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp has built his own web service. Being a modern web service it includes login feature. And that always implies password security problems.
Polycarp decided to store the hash of the password, generated by the following algorithm:
1. take the password p, consisting of lowercase Latin letters, and shuffle the letters randomly in it to obtain p' (p' can still be equal to p);
2. generate two random strings, consisting of lowercase Latin letters, s_1 and s_2 (any of these strings can be empty);
3. the resulting hash h = s_1 + p' + s_2, where addition is string concatenation.
For example, let the password p = "abacaba". Then p' can be equal to "aabcaab". Random strings s1 = "zyx" and s2 = "kjh". Then h = "zyxaabcaabkjh".
Note that no letters could be deleted or added to p to obtain p', only the order could be changed.
Now Polycarp asks you to help him to implement the password check module. Given the password p and the hash h, check that h can be the hash for the password p.
Your program should answer t independent test cases.
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
The first line of each test case contains a non-empty string p, consisting of lowercase Latin letters. The length of p does not exceed 100.
The second line of each test case contains a non-empty string h, consisting of lowercase Latin letters. The length of h does not exceed 100.
Output
For each test case print the answer to it — "YES" if the given hash h could be obtained from the given password p or "NO" otherwise.
Example
Input
5
abacaba
zyxaabcaabkjh
onetwothree
threetwoone
one
zzonneyy
one
none
twenty
ten
Output
YES
YES
NO
YES
NO
Note
The first test case is explained in the statement.
In the second test case both s_1 and s_2 are empty and p'= "threetwoone" is p shuffled.
In the third test case the hash could not be obtained from the password.
In the fourth test case s_1= "n", s_2 is empty and p'= "one" is p shuffled (even thought it stayed the same).
In the fifth test case the hash could not be obtained from the password. | instruction | 0 | 58,962 | 24 | 117,924 |
Tags: brute force, implementation, strings
Correct Solution:
```
def ans(p, h):
n = len(p)
for i in range(len(h)-len(p)+1):
if sorted(h[i:i+n]) == sorted(p):
return "YES"
return "NO"
for u in range(int(input())):
p=input()
h = input()
print(ans(p,h))
``` | output | 1 | 58,962 | 24 | 117,925 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp has built his own web service. Being a modern web service it includes login feature. And that always implies password security problems.
Polycarp decided to store the hash of the password, generated by the following algorithm:
1. take the password p, consisting of lowercase Latin letters, and shuffle the letters randomly in it to obtain p' (p' can still be equal to p);
2. generate two random strings, consisting of lowercase Latin letters, s_1 and s_2 (any of these strings can be empty);
3. the resulting hash h = s_1 + p' + s_2, where addition is string concatenation.
For example, let the password p = "abacaba". Then p' can be equal to "aabcaab". Random strings s1 = "zyx" and s2 = "kjh". Then h = "zyxaabcaabkjh".
Note that no letters could be deleted or added to p to obtain p', only the order could be changed.
Now Polycarp asks you to help him to implement the password check module. Given the password p and the hash h, check that h can be the hash for the password p.
Your program should answer t independent test cases.
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
The first line of each test case contains a non-empty string p, consisting of lowercase Latin letters. The length of p does not exceed 100.
The second line of each test case contains a non-empty string h, consisting of lowercase Latin letters. The length of h does not exceed 100.
Output
For each test case print the answer to it — "YES" if the given hash h could be obtained from the given password p or "NO" otherwise.
Example
Input
5
abacaba
zyxaabcaabkjh
onetwothree
threetwoone
one
zzonneyy
one
none
twenty
ten
Output
YES
YES
NO
YES
NO
Note
The first test case is explained in the statement.
In the second test case both s_1 and s_2 are empty and p'= "threetwoone" is p shuffled.
In the third test case the hash could not be obtained from the password.
In the fourth test case s_1= "n", s_2 is empty and p'= "one" is p shuffled (even thought it stayed the same).
In the fifth test case the hash could not be obtained from the password. | instruction | 0 | 58,963 | 24 | 117,926 |
Tags: brute force, implementation, strings
Correct Solution:
```
n = int(input())
for i in range(n):
a = list(input())
b = list(input())
dict_a = {}
dict_b = {}
l = len(a)
L = len(b)
yes = False
for j in range(l):
let = a[j]
dict_a.setdefault(let, 0)
dict_a[let] += 1
for j in range(L):
dict_b.clear()
if j + l <= L:
for k in range(j, j + l):
let = b[k]
dict_b.setdefault(let, 0)
dict_b[let] += 1
if set(dict_a.items()) == set(dict_b.items()):
yes = True
break
if yes == True:
print('YES')
else:
print('NO')
``` | output | 1 | 58,963 | 24 | 117,927 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp has built his own web service. Being a modern web service it includes login feature. And that always implies password security problems.
Polycarp decided to store the hash of the password, generated by the following algorithm:
1. take the password p, consisting of lowercase Latin letters, and shuffle the letters randomly in it to obtain p' (p' can still be equal to p);
2. generate two random strings, consisting of lowercase Latin letters, s_1 and s_2 (any of these strings can be empty);
3. the resulting hash h = s_1 + p' + s_2, where addition is string concatenation.
For example, let the password p = "abacaba". Then p' can be equal to "aabcaab". Random strings s1 = "zyx" and s2 = "kjh". Then h = "zyxaabcaabkjh".
Note that no letters could be deleted or added to p to obtain p', only the order could be changed.
Now Polycarp asks you to help him to implement the password check module. Given the password p and the hash h, check that h can be the hash for the password p.
Your program should answer t independent test cases.
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
The first line of each test case contains a non-empty string p, consisting of lowercase Latin letters. The length of p does not exceed 100.
The second line of each test case contains a non-empty string h, consisting of lowercase Latin letters. The length of h does not exceed 100.
Output
For each test case print the answer to it — "YES" if the given hash h could be obtained from the given password p or "NO" otherwise.
Example
Input
5
abacaba
zyxaabcaabkjh
onetwothree
threetwoone
one
zzonneyy
one
none
twenty
ten
Output
YES
YES
NO
YES
NO
Note
The first test case is explained in the statement.
In the second test case both s_1 and s_2 are empty and p'= "threetwoone" is p shuffled.
In the third test case the hash could not be obtained from the password.
In the fourth test case s_1= "n", s_2 is empty and p'= "one" is p shuffled (even thought it stayed the same).
In the fifth test case the hash could not be obtained from the password. | instruction | 0 | 58,964 | 24 | 117,928 |
Tags: brute force, implementation, strings
Correct Solution:
```
t=int(input())
for _ in range(t):
p=str(input())
h=str(input())
c={}
for i in p:
if i not in c:
c[i]=1
else:
c[i] += 1
ok=False
for i in range(0,len(h)-len(p)+1):
cc={}
k=h[i:i+len(p)]
for j in k:
if j not in cc:
cc[j]=1
else:
cc[j] += 1
if cc==c:
ok=True
if ok:
print("YES")
else:
print("NO")
``` | output | 1 | 58,964 | 24 | 117,929 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp has built his own web service. Being a modern web service it includes login feature. And that always implies password security problems.
Polycarp decided to store the hash of the password, generated by the following algorithm:
1. take the password p, consisting of lowercase Latin letters, and shuffle the letters randomly in it to obtain p' (p' can still be equal to p);
2. generate two random strings, consisting of lowercase Latin letters, s_1 and s_2 (any of these strings can be empty);
3. the resulting hash h = s_1 + p' + s_2, where addition is string concatenation.
For example, let the password p = "abacaba". Then p' can be equal to "aabcaab". Random strings s1 = "zyx" and s2 = "kjh". Then h = "zyxaabcaabkjh".
Note that no letters could be deleted or added to p to obtain p', only the order could be changed.
Now Polycarp asks you to help him to implement the password check module. Given the password p and the hash h, check that h can be the hash for the password p.
Your program should answer t independent test cases.
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
The first line of each test case contains a non-empty string p, consisting of lowercase Latin letters. The length of p does not exceed 100.
The second line of each test case contains a non-empty string h, consisting of lowercase Latin letters. The length of h does not exceed 100.
Output
For each test case print the answer to it — "YES" if the given hash h could be obtained from the given password p or "NO" otherwise.
Example
Input
5
abacaba
zyxaabcaabkjh
onetwothree
threetwoone
one
zzonneyy
one
none
twenty
ten
Output
YES
YES
NO
YES
NO
Note
The first test case is explained in the statement.
In the second test case both s_1 and s_2 are empty and p'= "threetwoone" is p shuffled.
In the third test case the hash could not be obtained from the password.
In the fourth test case s_1= "n", s_2 is empty and p'= "one" is p shuffled (even thought it stayed the same).
In the fifth test case the hash could not be obtained from the password. | instruction | 0 | 58,965 | 24 | 117,930 |
Tags: brute force, implementation, strings
Correct Solution:
```
def hashs(password,hashed):
IsHashedForm = "No"
password = sorted(password)
for i in range(len(hashed)):
for j in range(len(hashed),0,-1):
if sorted(hashed[i:j]) == password:
IsHashedForm = "Yes"
return IsHashedForm
return IsHashedForm
def main():
n = eval(input())
for i in range(n):
password = input()
hashed = input()
var = hashs(password,hashed)
print(var)
main()
``` | output | 1 | 58,965 | 24 | 117,931 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp has built his own web service. Being a modern web service it includes login feature. And that always implies password security problems.
Polycarp decided to store the hash of the password, generated by the following algorithm:
1. take the password p, consisting of lowercase Latin letters, and shuffle the letters randomly in it to obtain p' (p' can still be equal to p);
2. generate two random strings, consisting of lowercase Latin letters, s_1 and s_2 (any of these strings can be empty);
3. the resulting hash h = s_1 + p' + s_2, where addition is string concatenation.
For example, let the password p = "abacaba". Then p' can be equal to "aabcaab". Random strings s1 = "zyx" and s2 = "kjh". Then h = "zyxaabcaabkjh".
Note that no letters could be deleted or added to p to obtain p', only the order could be changed.
Now Polycarp asks you to help him to implement the password check module. Given the password p and the hash h, check that h can be the hash for the password p.
Your program should answer t independent test cases.
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
The first line of each test case contains a non-empty string p, consisting of lowercase Latin letters. The length of p does not exceed 100.
The second line of each test case contains a non-empty string h, consisting of lowercase Latin letters. The length of h does not exceed 100.
Output
For each test case print the answer to it — "YES" if the given hash h could be obtained from the given password p or "NO" otherwise.
Example
Input
5
abacaba
zyxaabcaabkjh
onetwothree
threetwoone
one
zzonneyy
one
none
twenty
ten
Output
YES
YES
NO
YES
NO
Note
The first test case is explained in the statement.
In the second test case both s_1 and s_2 are empty and p'= "threetwoone" is p shuffled.
In the third test case the hash could not be obtained from the password.
In the fourth test case s_1= "n", s_2 is empty and p'= "one" is p shuffled (even thought it stayed the same).
In the fifth test case the hash could not be obtained from the password. | instruction | 0 | 58,966 | 24 | 117,932 |
Tags: brute force, implementation, strings
Correct Solution:
```
t = int(input())
for i in range(t):
word = input()
wordhash = input()
b = True
for j in range(len(wordhash) - len(word) + 1):
a = True
test = wordhash[j:(j+len(word))]
for letter in word:
if word.count(letter) != test.count(letter):
a = False
if a:
print("YES")
b = False
break
if b: print("NO")
``` | output | 1 | 58,966 | 24 | 117,933 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp has built his own web service. Being a modern web service it includes login feature. And that always implies password security problems.
Polycarp decided to store the hash of the password, generated by the following algorithm:
1. take the password p, consisting of lowercase Latin letters, and shuffle the letters randomly in it to obtain p' (p' can still be equal to p);
2. generate two random strings, consisting of lowercase Latin letters, s_1 and s_2 (any of these strings can be empty);
3. the resulting hash h = s_1 + p' + s_2, where addition is string concatenation.
For example, let the password p = "abacaba". Then p' can be equal to "aabcaab". Random strings s1 = "zyx" and s2 = "kjh". Then h = "zyxaabcaabkjh".
Note that no letters could be deleted or added to p to obtain p', only the order could be changed.
Now Polycarp asks you to help him to implement the password check module. Given the password p and the hash h, check that h can be the hash for the password p.
Your program should answer t independent test cases.
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
The first line of each test case contains a non-empty string p, consisting of lowercase Latin letters. The length of p does not exceed 100.
The second line of each test case contains a non-empty string h, consisting of lowercase Latin letters. The length of h does not exceed 100.
Output
For each test case print the answer to it — "YES" if the given hash h could be obtained from the given password p or "NO" otherwise.
Example
Input
5
abacaba
zyxaabcaabkjh
onetwothree
threetwoone
one
zzonneyy
one
none
twenty
ten
Output
YES
YES
NO
YES
NO
Note
The first test case is explained in the statement.
In the second test case both s_1 and s_2 are empty and p'= "threetwoone" is p shuffled.
In the third test case the hash could not be obtained from the password.
In the fourth test case s_1= "n", s_2 is empty and p'= "one" is p shuffled (even thought it stayed the same).
In the fifth test case the hash could not be obtained from the password. | instruction | 0 | 58,967 | 24 | 117,934 |
Tags: brute force, implementation, strings
Correct Solution:
```
t=int(input())
for i in range(0,t):
p=input()
l=len(p)
h=input()
L=len(h)
flag=0
arr=[0 for x in range(0,27)]
for i in p:
n=ord(i)
arr[n-97]=arr[n-97]+1
if(L<l):
print('NO')
elif (L==l):
arr_2=[0 for x in range(0,27)]
for i in h:
n=ord(i)
arr_2[n-97]=arr_2[n-97]+1
if arr==arr_2:
print('YES')
else:
print('NO')
else:
for i in range(0,L-l+1):
test=h[0+i:l+i]
arr_2=[0 for x in range(0,27)]
for i in test:
n=ord(i)
arr_2[n-97]=arr_2[n-97]+1
if arr==arr_2:
print('YES')
flag=1
break
if flag==0:
print('NO')
``` | output | 1 | 58,967 | 24 | 117,935 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp has built his own web service. Being a modern web service it includes login feature. And that always implies password security problems.
Polycarp decided to store the hash of the password, generated by the following algorithm:
1. take the password p, consisting of lowercase Latin letters, and shuffle the letters randomly in it to obtain p' (p' can still be equal to p);
2. generate two random strings, consisting of lowercase Latin letters, s_1 and s_2 (any of these strings can be empty);
3. the resulting hash h = s_1 + p' + s_2, where addition is string concatenation.
For example, let the password p = "abacaba". Then p' can be equal to "aabcaab". Random strings s1 = "zyx" and s2 = "kjh". Then h = "zyxaabcaabkjh".
Note that no letters could be deleted or added to p to obtain p', only the order could be changed.
Now Polycarp asks you to help him to implement the password check module. Given the password p and the hash h, check that h can be the hash for the password p.
Your program should answer t independent test cases.
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
The first line of each test case contains a non-empty string p, consisting of lowercase Latin letters. The length of p does not exceed 100.
The second line of each test case contains a non-empty string h, consisting of lowercase Latin letters. The length of h does not exceed 100.
Output
For each test case print the answer to it — "YES" if the given hash h could be obtained from the given password p or "NO" otherwise.
Example
Input
5
abacaba
zyxaabcaabkjh
onetwothree
threetwoone
one
zzonneyy
one
none
twenty
ten
Output
YES
YES
NO
YES
NO
Note
The first test case is explained in the statement.
In the second test case both s_1 and s_2 are empty and p'= "threetwoone" is p shuffled.
In the third test case the hash could not be obtained from the password.
In the fourth test case s_1= "n", s_2 is empty and p'= "one" is p shuffled (even thought it stayed the same).
In the fifth test case the hash could not be obtained from the password. | instruction | 0 | 58,968 | 24 | 117,936 |
Tags: brute force, implementation, strings
Correct Solution:
```
t = int(input())
for _ in range(t):
p = sorted(input())
h = input()
for i in range(len(h)-len(p)+1):
if sorted(h[i:i+len(p)])==p:
print("YES")
break
else:
print("NO")
``` | output | 1 | 58,968 | 24 | 117,937 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp has built his own web service. Being a modern web service it includes login feature. And that always implies password security problems.
Polycarp decided to store the hash of the password, generated by the following algorithm:
1. take the password p, consisting of lowercase Latin letters, and shuffle the letters randomly in it to obtain p' (p' can still be equal to p);
2. generate two random strings, consisting of lowercase Latin letters, s_1 and s_2 (any of these strings can be empty);
3. the resulting hash h = s_1 + p' + s_2, where addition is string concatenation.
For example, let the password p = "abacaba". Then p' can be equal to "aabcaab". Random strings s1 = "zyx" and s2 = "kjh". Then h = "zyxaabcaabkjh".
Note that no letters could be deleted or added to p to obtain p', only the order could be changed.
Now Polycarp asks you to help him to implement the password check module. Given the password p and the hash h, check that h can be the hash for the password p.
Your program should answer t independent test cases.
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
The first line of each test case contains a non-empty string p, consisting of lowercase Latin letters. The length of p does not exceed 100.
The second line of each test case contains a non-empty string h, consisting of lowercase Latin letters. The length of h does not exceed 100.
Output
For each test case print the answer to it — "YES" if the given hash h could be obtained from the given password p or "NO" otherwise.
Example
Input
5
abacaba
zyxaabcaabkjh
onetwothree
threetwoone
one
zzonneyy
one
none
twenty
ten
Output
YES
YES
NO
YES
NO
Note
The first test case is explained in the statement.
In the second test case both s_1 and s_2 are empty and p'= "threetwoone" is p shuffled.
In the third test case the hash could not be obtained from the password.
In the fourth test case s_1= "n", s_2 is empty and p'= "one" is p shuffled (even thought it stayed the same).
In the fifth test case the hash could not be obtained from the password. | instruction | 0 | 58,969 | 24 | 117,938 |
Tags: brute force, implementation, strings
Correct Solution:
```
t = int(input())
for i in range(t):
p = input()
h = input()
f = True
for i in range(len(h) - len(p) + 1):
if sorted(h[i: i + len(p)]) == sorted(p):
print('YES')
f = False
break
if f:
print('NO')
``` | output | 1 | 58,969 | 24 | 117,939 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp has built his own web service. Being a modern web service it includes login feature. And that always implies password security problems.
Polycarp decided to store the hash of the password, generated by the following algorithm:
1. take the password p, consisting of lowercase Latin letters, and shuffle the letters randomly in it to obtain p' (p' can still be equal to p);
2. generate two random strings, consisting of lowercase Latin letters, s_1 and s_2 (any of these strings can be empty);
3. the resulting hash h = s_1 + p' + s_2, where addition is string concatenation.
For example, let the password p = "abacaba". Then p' can be equal to "aabcaab". Random strings s1 = "zyx" and s2 = "kjh". Then h = "zyxaabcaabkjh".
Note that no letters could be deleted or added to p to obtain p', only the order could be changed.
Now Polycarp asks you to help him to implement the password check module. Given the password p and the hash h, check that h can be the hash for the password p.
Your program should answer t independent test cases.
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
The first line of each test case contains a non-empty string p, consisting of lowercase Latin letters. The length of p does not exceed 100.
The second line of each test case contains a non-empty string h, consisting of lowercase Latin letters. The length of h does not exceed 100.
Output
For each test case print the answer to it — "YES" if the given hash h could be obtained from the given password p or "NO" otherwise.
Example
Input
5
abacaba
zyxaabcaabkjh
onetwothree
threetwoone
one
zzonneyy
one
none
twenty
ten
Output
YES
YES
NO
YES
NO
Note
The first test case is explained in the statement.
In the second test case both s_1 and s_2 are empty and p'= "threetwoone" is p shuffled.
In the third test case the hash could not be obtained from the password.
In the fourth test case s_1= "n", s_2 is empty and p'= "one" is p shuffled (even thought it stayed the same).
In the fifth test case the hash could not be obtained from the password.
Submitted Solution:
```
from collections import Counter
for _ in range(int(input())):
p = input()
h = input()
cnt = Counter(h[:len(p)])
cnt1 = Counter(p)
diff = {k for k in cnt1.keys() if cnt[k] != cnt1[k]}
for i in range(len(h) - len(p)):
if not diff:
break
c = h[i]
cnt[c] -= 1
if cnt[c] == cnt1[c]:
diff.discard(c)
else:
diff.add(c)
c = h[i + len(p)]
cnt[c] += 1
if cnt[c] == cnt1[c]:
diff.discard(c)
else:
diff.add(c)
if diff:
print("NO")
else:
print("YES")
``` | instruction | 0 | 58,970 | 24 | 117,940 |
Yes | output | 1 | 58,970 | 24 | 117,941 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp has built his own web service. Being a modern web service it includes login feature. And that always implies password security problems.
Polycarp decided to store the hash of the password, generated by the following algorithm:
1. take the password p, consisting of lowercase Latin letters, and shuffle the letters randomly in it to obtain p' (p' can still be equal to p);
2. generate two random strings, consisting of lowercase Latin letters, s_1 and s_2 (any of these strings can be empty);
3. the resulting hash h = s_1 + p' + s_2, where addition is string concatenation.
For example, let the password p = "abacaba". Then p' can be equal to "aabcaab". Random strings s1 = "zyx" and s2 = "kjh". Then h = "zyxaabcaabkjh".
Note that no letters could be deleted or added to p to obtain p', only the order could be changed.
Now Polycarp asks you to help him to implement the password check module. Given the password p and the hash h, check that h can be the hash for the password p.
Your program should answer t independent test cases.
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
The first line of each test case contains a non-empty string p, consisting of lowercase Latin letters. The length of p does not exceed 100.
The second line of each test case contains a non-empty string h, consisting of lowercase Latin letters. The length of h does not exceed 100.
Output
For each test case print the answer to it — "YES" if the given hash h could be obtained from the given password p or "NO" otherwise.
Example
Input
5
abacaba
zyxaabcaabkjh
onetwothree
threetwoone
one
zzonneyy
one
none
twenty
ten
Output
YES
YES
NO
YES
NO
Note
The first test case is explained in the statement.
In the second test case both s_1 and s_2 are empty and p'= "threetwoone" is p shuffled.
In the third test case the hash could not be obtained from the password.
In the fourth test case s_1= "n", s_2 is empty and p'= "one" is p shuffled (even thought it stayed the same).
In the fifth test case the hash could not be obtained from the password.
Submitted Solution:
```
for _ in range(int(input())):
s=list(input())
h=list(input())
a,b=len(h),len(s)
if a<b:
print("NO")
elif a==b:
d={}
c=0
dd={}
for i in s:
d[i]=d.get(i,0)+1
for i in h:
dd[i]=dd.get(i,0)+1
for i in d:
if i not in dd:
c=1
break
if i in d:
if d[i]!=dd[i]:
c=1
break
if c:
print("NO")
else:
print("YES")
else:
x=sorted(s)
c=0
for i in range(a-b+1):
if sorted(h[i:i+b])==x:
c=1
break
if c:
print("YES")
else:
print("NO")
``` | instruction | 0 | 58,971 | 24 | 117,942 |
Yes | output | 1 | 58,971 | 24 | 117,943 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp has built his own web service. Being a modern web service it includes login feature. And that always implies password security problems.
Polycarp decided to store the hash of the password, generated by the following algorithm:
1. take the password p, consisting of lowercase Latin letters, and shuffle the letters randomly in it to obtain p' (p' can still be equal to p);
2. generate two random strings, consisting of lowercase Latin letters, s_1 and s_2 (any of these strings can be empty);
3. the resulting hash h = s_1 + p' + s_2, where addition is string concatenation.
For example, let the password p = "abacaba". Then p' can be equal to "aabcaab". Random strings s1 = "zyx" and s2 = "kjh". Then h = "zyxaabcaabkjh".
Note that no letters could be deleted or added to p to obtain p', only the order could be changed.
Now Polycarp asks you to help him to implement the password check module. Given the password p and the hash h, check that h can be the hash for the password p.
Your program should answer t independent test cases.
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
The first line of each test case contains a non-empty string p, consisting of lowercase Latin letters. The length of p does not exceed 100.
The second line of each test case contains a non-empty string h, consisting of lowercase Latin letters. The length of h does not exceed 100.
Output
For each test case print the answer to it — "YES" if the given hash h could be obtained from the given password p or "NO" otherwise.
Example
Input
5
abacaba
zyxaabcaabkjh
onetwothree
threetwoone
one
zzonneyy
one
none
twenty
ten
Output
YES
YES
NO
YES
NO
Note
The first test case is explained in the statement.
In the second test case both s_1 and s_2 are empty and p'= "threetwoone" is p shuffled.
In the third test case the hash could not be obtained from the password.
In the fourth test case s_1= "n", s_2 is empty and p'= "one" is p shuffled (even thought it stayed the same).
In the fifth test case the hash could not be obtained from the password.
Submitted Solution:
```
'''
Welcome to GDB Online.
GDB online is an online compiler and debugger tool for C, C++, Python, Java, PHP, Ruby, Perl,
C#, VB, Swift, Pascal, Fortran, Haskell, Objective-C, Assembly, HTML, CSS, JS, SQLite, Prolog.
Code, Compile, Run and Debug online from anywhere in world.
'''
tt = int(input())
for ghg in range(tt):
word = str(input())
after = str(input())
dicts = {}
for i in word:
if i not in dicts:
dicts[i] = 1
else:
dicts[i] += 1
n = len(word)
n2 = len(after)
flag = 0
for i in range(n2):
tmp = {}
count = n
for j in range(i,n2):
if after[j] not in dicts:
break
j = after[j]
if j not in tmp:
tmp[j] = 1
count -= 1
else:
tmp[j] += 1
if tmp[j] > dicts[j]:
break
count -=1
if count == 0:
# print(tmp)
# print(dicts)
flag = 1
break
if flag == 1:
print("YES")
break
if flag == 0:
print("NO")
``` | instruction | 0 | 58,972 | 24 | 117,944 |
Yes | output | 1 | 58,972 | 24 | 117,945 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp has built his own web service. Being a modern web service it includes login feature. And that always implies password security problems.
Polycarp decided to store the hash of the password, generated by the following algorithm:
1. take the password p, consisting of lowercase Latin letters, and shuffle the letters randomly in it to obtain p' (p' can still be equal to p);
2. generate two random strings, consisting of lowercase Latin letters, s_1 and s_2 (any of these strings can be empty);
3. the resulting hash h = s_1 + p' + s_2, where addition is string concatenation.
For example, let the password p = "abacaba". Then p' can be equal to "aabcaab". Random strings s1 = "zyx" and s2 = "kjh". Then h = "zyxaabcaabkjh".
Note that no letters could be deleted or added to p to obtain p', only the order could be changed.
Now Polycarp asks you to help him to implement the password check module. Given the password p and the hash h, check that h can be the hash for the password p.
Your program should answer t independent test cases.
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
The first line of each test case contains a non-empty string p, consisting of lowercase Latin letters. The length of p does not exceed 100.
The second line of each test case contains a non-empty string h, consisting of lowercase Latin letters. The length of h does not exceed 100.
Output
For each test case print the answer to it — "YES" if the given hash h could be obtained from the given password p or "NO" otherwise.
Example
Input
5
abacaba
zyxaabcaabkjh
onetwothree
threetwoone
one
zzonneyy
one
none
twenty
ten
Output
YES
YES
NO
YES
NO
Note
The first test case is explained in the statement.
In the second test case both s_1 and s_2 are empty and p'= "threetwoone" is p shuffled.
In the third test case the hash could not be obtained from the password.
In the fourth test case s_1= "n", s_2 is empty and p'= "one" is p shuffled (even thought it stayed the same).
In the fifth test case the hash could not be obtained from the password.
Submitted Solution:
```
from collections import Counter
numTestCases = int(input())
answers = []
for test in range(numTestCases):
answer = "NO"
password = input()
passwordShuffled = input()
passwordLetterFrequency = Counter(password)
for i in range(len(passwordShuffled) - len(password) + 1):
if Counter(passwordShuffled[i : len(password) + i]) == passwordLetterFrequency:
answer = "YES"
break
answers.append(answer)
for answer in answers:
print(answer)
``` | instruction | 0 | 58,973 | 24 | 117,946 |
Yes | output | 1 | 58,973 | 24 | 117,947 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp has built his own web service. Being a modern web service it includes login feature. And that always implies password security problems.
Polycarp decided to store the hash of the password, generated by the following algorithm:
1. take the password p, consisting of lowercase Latin letters, and shuffle the letters randomly in it to obtain p' (p' can still be equal to p);
2. generate two random strings, consisting of lowercase Latin letters, s_1 and s_2 (any of these strings can be empty);
3. the resulting hash h = s_1 + p' + s_2, where addition is string concatenation.
For example, let the password p = "abacaba". Then p' can be equal to "aabcaab". Random strings s1 = "zyx" and s2 = "kjh". Then h = "zyxaabcaabkjh".
Note that no letters could be deleted or added to p to obtain p', only the order could be changed.
Now Polycarp asks you to help him to implement the password check module. Given the password p and the hash h, check that h can be the hash for the password p.
Your program should answer t independent test cases.
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
The first line of each test case contains a non-empty string p, consisting of lowercase Latin letters. The length of p does not exceed 100.
The second line of each test case contains a non-empty string h, consisting of lowercase Latin letters. The length of h does not exceed 100.
Output
For each test case print the answer to it — "YES" if the given hash h could be obtained from the given password p or "NO" otherwise.
Example
Input
5
abacaba
zyxaabcaabkjh
onetwothree
threetwoone
one
zzonneyy
one
none
twenty
ten
Output
YES
YES
NO
YES
NO
Note
The first test case is explained in the statement.
In the second test case both s_1 and s_2 are empty and p'= "threetwoone" is p shuffled.
In the third test case the hash could not be obtained from the password.
In the fourth test case s_1= "n", s_2 is empty and p'= "one" is p shuffled (even thought it stayed the same).
In the fifth test case the hash could not be obtained from the password.
Submitted Solution:
```
t = int(input())
ans = []
for i in range(t):
p = input()
h = input()
pw_length = len(h)
p_set = set(p)
right_lock = 0
left_lock = 0
right_index = 0
left_index = pw_length - 1
for j in range(pw_length):
if h[j] in p_set and right_lock == 0:
right_index = j
right_lock = 1
if h[pw_length - j - 1] in p_set and left_lock == 0:
left_index = pw_length - j - 1
left_lock = 1
if left_lock == 1 and right_lock == 1: break
f = h[right_index : left_index + 1]
dif = abs(len(f) - len(p))
if(len(f) < len(p)): ans.append("no"); continue
p_list = list(p)
p_list.sort()
lock = 0
for j in range(len(f) - dif):
a = list(f[j : len(f)])
a.sort()
if a == p_list: ans.append("yes"); lock = 1; break
if lock == 0: ans.append("no")
for i in range(t): print(ans[i])
``` | instruction | 0 | 58,974 | 24 | 117,948 |
No | output | 1 | 58,974 | 24 | 117,949 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp has built his own web service. Being a modern web service it includes login feature. And that always implies password security problems.
Polycarp decided to store the hash of the password, generated by the following algorithm:
1. take the password p, consisting of lowercase Latin letters, and shuffle the letters randomly in it to obtain p' (p' can still be equal to p);
2. generate two random strings, consisting of lowercase Latin letters, s_1 and s_2 (any of these strings can be empty);
3. the resulting hash h = s_1 + p' + s_2, where addition is string concatenation.
For example, let the password p = "abacaba". Then p' can be equal to "aabcaab". Random strings s1 = "zyx" and s2 = "kjh". Then h = "zyxaabcaabkjh".
Note that no letters could be deleted or added to p to obtain p', only the order could be changed.
Now Polycarp asks you to help him to implement the password check module. Given the password p and the hash h, check that h can be the hash for the password p.
Your program should answer t independent test cases.
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
The first line of each test case contains a non-empty string p, consisting of lowercase Latin letters. The length of p does not exceed 100.
The second line of each test case contains a non-empty string h, consisting of lowercase Latin letters. The length of h does not exceed 100.
Output
For each test case print the answer to it — "YES" if the given hash h could be obtained from the given password p or "NO" otherwise.
Example
Input
5
abacaba
zyxaabcaabkjh
onetwothree
threetwoone
one
zzonneyy
one
none
twenty
ten
Output
YES
YES
NO
YES
NO
Note
The first test case is explained in the statement.
In the second test case both s_1 and s_2 are empty and p'= "threetwoone" is p shuffled.
In the third test case the hash could not be obtained from the password.
In the fourth test case s_1= "n", s_2 is empty and p'= "one" is p shuffled (even thought it stayed the same).
In the fifth test case the hash could not be obtained from the password.
Submitted Solution:
```
def substr(ps,hash):
x=0
j=len(hash)-1
ps2=""
for i in range(len(hash)):
if hash[x] not in ps:
x+=1
if hash[j] not in ps:
j-=1
ps2=list(hash[x:j+1])
ps=list(ps)
ps2.sort()
ps.sort()
if ps2==ps:
print("YES")
else:
print("NO")
def runner():
val=input()
for i in range(int(val)):
ans=input()
an2=input()
substr(ans,an2)
runner()
``` | instruction | 0 | 58,975 | 24 | 117,950 |
No | output | 1 | 58,975 | 24 | 117,951 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp has built his own web service. Being a modern web service it includes login feature. And that always implies password security problems.
Polycarp decided to store the hash of the password, generated by the following algorithm:
1. take the password p, consisting of lowercase Latin letters, and shuffle the letters randomly in it to obtain p' (p' can still be equal to p);
2. generate two random strings, consisting of lowercase Latin letters, s_1 and s_2 (any of these strings can be empty);
3. the resulting hash h = s_1 + p' + s_2, where addition is string concatenation.
For example, let the password p = "abacaba". Then p' can be equal to "aabcaab". Random strings s1 = "zyx" and s2 = "kjh". Then h = "zyxaabcaabkjh".
Note that no letters could be deleted or added to p to obtain p', only the order could be changed.
Now Polycarp asks you to help him to implement the password check module. Given the password p and the hash h, check that h can be the hash for the password p.
Your program should answer t independent test cases.
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
The first line of each test case contains a non-empty string p, consisting of lowercase Latin letters. The length of p does not exceed 100.
The second line of each test case contains a non-empty string h, consisting of lowercase Latin letters. The length of h does not exceed 100.
Output
For each test case print the answer to it — "YES" if the given hash h could be obtained from the given password p or "NO" otherwise.
Example
Input
5
abacaba
zyxaabcaabkjh
onetwothree
threetwoone
one
zzonneyy
one
none
twenty
ten
Output
YES
YES
NO
YES
NO
Note
The first test case is explained in the statement.
In the second test case both s_1 and s_2 are empty and p'= "threetwoone" is p shuffled.
In the third test case the hash could not be obtained from the password.
In the fourth test case s_1= "n", s_2 is empty and p'= "one" is p shuffled (even thought it stayed the same).
In the fifth test case the hash could not be obtained from the password.
Submitted Solution:
```
def freq(test_str):
all_freq = {}
for i in test_str:
if i in all_freq:
all_freq[i] += 1
else:
all_freq[i] = 1
return all_freq
def compare_freq(p_freq: dict, h_freq: dict):
ret_val = 0
if p_freq.keys() != h_freq.keys():
return -1
for key in p_freq.keys():
if p_freq[key] != h_freq[key]:
return -1
# if p_freq[key] < h_freq[key]:
# ret_val = 1
return ret_val
if __name__ == "__main__":
for t in range(int(input())):
password = input()
hashstr = input()
if len(password) > len(hashstr):
print('NO')
break
password_freq = freq(password)
hash_freq = freq(hashstr)
for i in range(len(password)):
try:
temp_h = hashstr[i:i + len(password)]
temp_freq = freq(temp_h)
if compare_freq(password_freq, temp_freq) == 0:
print('YES')
break
except :
print('NO')
break
else:
print('NO')
``` | instruction | 0 | 58,976 | 24 | 117,952 |
No | output | 1 | 58,976 | 24 | 117,953 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp has built his own web service. Being a modern web service it includes login feature. And that always implies password security problems.
Polycarp decided to store the hash of the password, generated by the following algorithm:
1. take the password p, consisting of lowercase Latin letters, and shuffle the letters randomly in it to obtain p' (p' can still be equal to p);
2. generate two random strings, consisting of lowercase Latin letters, s_1 and s_2 (any of these strings can be empty);
3. the resulting hash h = s_1 + p' + s_2, where addition is string concatenation.
For example, let the password p = "abacaba". Then p' can be equal to "aabcaab". Random strings s1 = "zyx" and s2 = "kjh". Then h = "zyxaabcaabkjh".
Note that no letters could be deleted or added to p to obtain p', only the order could be changed.
Now Polycarp asks you to help him to implement the password check module. Given the password p and the hash h, check that h can be the hash for the password p.
Your program should answer t independent test cases.
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
The first line of each test case contains a non-empty string p, consisting of lowercase Latin letters. The length of p does not exceed 100.
The second line of each test case contains a non-empty string h, consisting of lowercase Latin letters. The length of h does not exceed 100.
Output
For each test case print the answer to it — "YES" if the given hash h could be obtained from the given password p or "NO" otherwise.
Example
Input
5
abacaba
zyxaabcaabkjh
onetwothree
threetwoone
one
zzonneyy
one
none
twenty
ten
Output
YES
YES
NO
YES
NO
Note
The first test case is explained in the statement.
In the second test case both s_1 and s_2 are empty and p'= "threetwoone" is p shuffled.
In the third test case the hash could not be obtained from the password.
In the fourth test case s_1= "n", s_2 is empty and p'= "one" is p shuffled (even thought it stayed the same).
In the fifth test case the hash could not be obtained from the password.
Submitted Solution:
```
print("""YES
YES
NO
YES
NO
""")
``` | instruction | 0 | 58,977 | 24 | 117,954 |
No | output | 1 | 58,977 | 24 | 117,955 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp likes to play with numbers. He takes some integer number x, writes it down on the board, and then performs with it n - 1 operations of the two kinds:
* divide the number x by 3 (x must be divisible by 3);
* multiply the number x by 2.
After each operation, Polycarp writes down the result on the board and replaces x by the result. So there will be n numbers on the board after all.
You are given a sequence of length n — the numbers that Polycarp wrote down. This sequence is given in arbitrary order, i.e. the order of the sequence can mismatch the order of the numbers written on the board.
Your problem is to rearrange (reorder) elements of this sequence in such a way that it can match possible Polycarp's game in the order of the numbers written on the board. I.e. each next number will be exactly two times of the previous number or exactly one third of previous number.
It is guaranteed that the answer exists.
Input
The first line of the input contatins an integer number n (2 ≤ n ≤ 100) — the number of the elements in the sequence. The second line of the input contains n integer numbers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 3 ⋅ 10^{18}) — rearranged (reordered) sequence that Polycarp can wrote down on the board.
Output
Print n integer numbers — rearranged (reordered) input sequence that can be the sequence that Polycarp could write down on the board.
It is guaranteed that the answer exists.
Examples
Input
6
4 8 6 3 12 9
Output
9 3 6 12 4 8
Input
4
42 28 84 126
Output
126 42 84 28
Input
2
1000000000000000000 3000000000000000000
Output
3000000000000000000 1000000000000000000
Note
In the first example the given sequence can be rearranged in the following way: [9, 3, 6, 12, 4, 8]. It can match possible Polycarp's game which started with x = 9. | instruction | 0 | 59,399 | 24 | 118,798 |
Tags: dfs and similar, math, sortings
Correct Solution:
```
n = input()
c = {}
for x in [int(x) for x in input().split()]:
u, t = x, 0
while 0 == u%3:
u //= 3
t += 1
c[t] = c.get(t, []) + [x]
for x in sorted(c)[::-1]:
for y in sorted(c[x]):
print(y, end=' ')
``` | output | 1 | 59,399 | 24 | 118,799 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp likes to play with numbers. He takes some integer number x, writes it down on the board, and then performs with it n - 1 operations of the two kinds:
* divide the number x by 3 (x must be divisible by 3);
* multiply the number x by 2.
After each operation, Polycarp writes down the result on the board and replaces x by the result. So there will be n numbers on the board after all.
You are given a sequence of length n — the numbers that Polycarp wrote down. This sequence is given in arbitrary order, i.e. the order of the sequence can mismatch the order of the numbers written on the board.
Your problem is to rearrange (reorder) elements of this sequence in such a way that it can match possible Polycarp's game in the order of the numbers written on the board. I.e. each next number will be exactly two times of the previous number or exactly one third of previous number.
It is guaranteed that the answer exists.
Input
The first line of the input contatins an integer number n (2 ≤ n ≤ 100) — the number of the elements in the sequence. The second line of the input contains n integer numbers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 3 ⋅ 10^{18}) — rearranged (reordered) sequence that Polycarp can wrote down on the board.
Output
Print n integer numbers — rearranged (reordered) input sequence that can be the sequence that Polycarp could write down on the board.
It is guaranteed that the answer exists.
Examples
Input
6
4 8 6 3 12 9
Output
9 3 6 12 4 8
Input
4
42 28 84 126
Output
126 42 84 28
Input
2
1000000000000000000 3000000000000000000
Output
3000000000000000000 1000000000000000000
Note
In the first example the given sequence can be rearranged in the following way: [9, 3, 6, 12, 4, 8]. It can match possible Polycarp's game which started with x = 9. | instruction | 0 | 59,400 | 24 | 118,800 |
Tags: dfs and similar, math, sortings
Correct Solution:
```
input()
v = list(map(int,input().split()))
# v = [2999999999999999997 ,999999999999999999]
# # v = [9, 8, 6, 3, 12, 4]
def find_last_position(li):
li = []
for i in v:
if (i % 3 == 0) and (i // 3 in v):
li.append(i)
elif (i * 2 in v):
li.append(i)
for i in v:
if i not in li:
return i
def find_path(li):
v_new = []
e = find_last_position(li)
v_new.append(e)
li.remove(e)
while True:
if (e*3 in li):
e = e*3
v_new.append(e)
li.remove(e)
elif(e>>1 in li):
e = e>>1
v_new.append(e)
li.remove(e)
else:break
return v_new
for i in reversed(find_path(v)):
print(i,end=' ')
``` | output | 1 | 59,400 | 24 | 118,801 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp likes to play with numbers. He takes some integer number x, writes it down on the board, and then performs with it n - 1 operations of the two kinds:
* divide the number x by 3 (x must be divisible by 3);
* multiply the number x by 2.
After each operation, Polycarp writes down the result on the board and replaces x by the result. So there will be n numbers on the board after all.
You are given a sequence of length n — the numbers that Polycarp wrote down. This sequence is given in arbitrary order, i.e. the order of the sequence can mismatch the order of the numbers written on the board.
Your problem is to rearrange (reorder) elements of this sequence in such a way that it can match possible Polycarp's game in the order of the numbers written on the board. I.e. each next number will be exactly two times of the previous number or exactly one third of previous number.
It is guaranteed that the answer exists.
Input
The first line of the input contatins an integer number n (2 ≤ n ≤ 100) — the number of the elements in the sequence. The second line of the input contains n integer numbers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 3 ⋅ 10^{18}) — rearranged (reordered) sequence that Polycarp can wrote down on the board.
Output
Print n integer numbers — rearranged (reordered) input sequence that can be the sequence that Polycarp could write down on the board.
It is guaranteed that the answer exists.
Examples
Input
6
4 8 6 3 12 9
Output
9 3 6 12 4 8
Input
4
42 28 84 126
Output
126 42 84 28
Input
2
1000000000000000000 3000000000000000000
Output
3000000000000000000 1000000000000000000
Note
In the first example the given sequence can be rearranged in the following way: [9, 3, 6, 12, 4, 8]. It can match possible Polycarp's game which started with x = 9. | instruction | 0 | 59,401 | 24 | 118,802 |
Tags: dfs and similar, math, sortings
Correct Solution:
```
f = int(input())
c = input().split()
d = []
e = 0
for i in c:
d.append(int(i))
# This first for loop gets the first element in the ordered list
for i in range(f):
check = 0
# in this next loop, we find the unique element which is not divisible by 2
# and 2 * any other element is equal to it, and you can't multiple it by 3 to get
# any other element
for j in range(f):
if d[j] == 3 * d[i]:
check = 1
if d[i] % 2 == 0 and d[i] == 2 * d[j]:
check = 1
if check == 0:
e = d[i]
# This next for loop goes through and finds all remaining elements
print(e, end = ' ')
for i in range(f-1):
# f-1 because we already found one element
for j in range(f):
# since we know we have the correct first element, our next element is e/3
if 3*d[j] == e:
e = d[j]
break
# to find the element to multiply by 2, we update e and look for e*2 in our series
elif 2*e == d[j]:
e = d[j]
break
print(e, end = ' ')
``` | output | 1 | 59,401 | 24 | 118,803 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp likes to play with numbers. He takes some integer number x, writes it down on the board, and then performs with it n - 1 operations of the two kinds:
* divide the number x by 3 (x must be divisible by 3);
* multiply the number x by 2.
After each operation, Polycarp writes down the result on the board and replaces x by the result. So there will be n numbers on the board after all.
You are given a sequence of length n — the numbers that Polycarp wrote down. This sequence is given in arbitrary order, i.e. the order of the sequence can mismatch the order of the numbers written on the board.
Your problem is to rearrange (reorder) elements of this sequence in such a way that it can match possible Polycarp's game in the order of the numbers written on the board. I.e. each next number will be exactly two times of the previous number or exactly one third of previous number.
It is guaranteed that the answer exists.
Input
The first line of the input contatins an integer number n (2 ≤ n ≤ 100) — the number of the elements in the sequence. The second line of the input contains n integer numbers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 3 ⋅ 10^{18}) — rearranged (reordered) sequence that Polycarp can wrote down on the board.
Output
Print n integer numbers — rearranged (reordered) input sequence that can be the sequence that Polycarp could write down on the board.
It is guaranteed that the answer exists.
Examples
Input
6
4 8 6 3 12 9
Output
9 3 6 12 4 8
Input
4
42 28 84 126
Output
126 42 84 28
Input
2
1000000000000000000 3000000000000000000
Output
3000000000000000000 1000000000000000000
Note
In the first example the given sequence can be rearranged in the following way: [9, 3, 6, 12, 4, 8]. It can match possible Polycarp's game which started with x = 9. | instruction | 0 | 59,402 | 24 | 118,804 |
Tags: dfs and similar, math, sortings
Correct Solution:
```
# _
#####################################################################################################################
def main():
n, sequence = input(), set(map(int, input().split()))
firstElement = nThrees = 0
for element in sequence:
value = element
for i in range(39):
if value%3:
if nThrees < i:
firstElement, nThrees = element, i
break
value //= 3
if not nThrees:
return ' '.join(map(str, sorted(sequence)))
return ' '.join(map(str, rearrangeElements(sequence, firstElement)))
def rearrangeElements(sequence, firstElement):
newSequence = []
if not firstElement%2:
elementBeforeFirst = firstElement//2
while elementBeforeFirst in sequence:
newSequence.append(elementBeforeFirst)
elementBeforeFirst //= 2
newSequence.reverse()
while True:
if firstElement not in sequence:
return newSequence
while firstElement in sequence:
newSequence.append(firstElement)
firstElement += firstElement
firstElement //= 6
if __name__ == '__main__':
print(main())
# main()
``` | output | 1 | 59,402 | 24 | 118,805 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp likes to play with numbers. He takes some integer number x, writes it down on the board, and then performs with it n - 1 operations of the two kinds:
* divide the number x by 3 (x must be divisible by 3);
* multiply the number x by 2.
After each operation, Polycarp writes down the result on the board and replaces x by the result. So there will be n numbers on the board after all.
You are given a sequence of length n — the numbers that Polycarp wrote down. This sequence is given in arbitrary order, i.e. the order of the sequence can mismatch the order of the numbers written on the board.
Your problem is to rearrange (reorder) elements of this sequence in such a way that it can match possible Polycarp's game in the order of the numbers written on the board. I.e. each next number will be exactly two times of the previous number or exactly one third of previous number.
It is guaranteed that the answer exists.
Input
The first line of the input contatins an integer number n (2 ≤ n ≤ 100) — the number of the elements in the sequence. The second line of the input contains n integer numbers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 3 ⋅ 10^{18}) — rearranged (reordered) sequence that Polycarp can wrote down on the board.
Output
Print n integer numbers — rearranged (reordered) input sequence that can be the sequence that Polycarp could write down on the board.
It is guaranteed that the answer exists.
Examples
Input
6
4 8 6 3 12 9
Output
9 3 6 12 4 8
Input
4
42 28 84 126
Output
126 42 84 28
Input
2
1000000000000000000 3000000000000000000
Output
3000000000000000000 1000000000000000000
Note
In the first example the given sequence can be rearranged in the following way: [9, 3, 6, 12, 4, 8]. It can match possible Polycarp's game which started with x = 9. | instruction | 0 | 59,403 | 24 | 118,806 |
Tags: dfs and similar, math, sortings
Correct Solution:
```
z,zz,dgraphs=input,lambda:list(map(int,z().split())),{}
from string import *
from collections import *
from queue import *
from sys import *
from collections import *
from math import *
from heapq import *
from itertools import *
from bisect import *
from collections import Counter as cc
from math import factorial as f
def lcd(xnum1,xnum2):return (xnum1*xnum2//gcd(xnum1,xnum2))
def prime(x):
p=ceil(x**.5)+1
for i in range(2,p):
if x%i==0:return 0
return 1
def dfs(u,visit,graph):
visit[u]=True
for i in graph[u]:
if not visit[i]:
dfs(i,visit,graph)
################################################################################
"""
led=(6,2,5,5,4,5,6,3,7,6)
vowel={'a':0,'e':0,'i':0,'o':0,'u':0}
color4=["G", "GB", "YGB", "YGBI", "OYGBI" ,"OYGBIV",'ROYGBIV' ]
z,zz,dgraphs=input,lambda:list(map(int,z().split())),{}
d,l,r,b=[],0,1,{}
for _ in range(int(z())):d.append(z().split())
for i in d:
id_ =int(i[1])
if i[0]=='L':
b[id_]=l
l-=1
if i[0]=='R':
b[id_]=r
r+=1
if i[0]=='?':
p = b[id_]
print(min(p-l-1,r-p-1))
"""
###########################---START-CODING---####################################
num=int(z())
l=zz()
for i in sorted(l)[::-1]:
p=[i]
for _ in range(num):
if i%3==0 and i//3 in l:
p.append(i//3)
i=i//3
elif i*2 in l:
p.append(i*2)
i=i*2
else:break
if sorted(p)==sorted(l):
break
print(*p)
``` | output | 1 | 59,403 | 24 | 118,807 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp likes to play with numbers. He takes some integer number x, writes it down on the board, and then performs with it n - 1 operations of the two kinds:
* divide the number x by 3 (x must be divisible by 3);
* multiply the number x by 2.
After each operation, Polycarp writes down the result on the board and replaces x by the result. So there will be n numbers on the board after all.
You are given a sequence of length n — the numbers that Polycarp wrote down. This sequence is given in arbitrary order, i.e. the order of the sequence can mismatch the order of the numbers written on the board.
Your problem is to rearrange (reorder) elements of this sequence in such a way that it can match possible Polycarp's game in the order of the numbers written on the board. I.e. each next number will be exactly two times of the previous number or exactly one third of previous number.
It is guaranteed that the answer exists.
Input
The first line of the input contatins an integer number n (2 ≤ n ≤ 100) — the number of the elements in the sequence. The second line of the input contains n integer numbers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 3 ⋅ 10^{18}) — rearranged (reordered) sequence that Polycarp can wrote down on the board.
Output
Print n integer numbers — rearranged (reordered) input sequence that can be the sequence that Polycarp could write down on the board.
It is guaranteed that the answer exists.
Examples
Input
6
4 8 6 3 12 9
Output
9 3 6 12 4 8
Input
4
42 28 84 126
Output
126 42 84 28
Input
2
1000000000000000000 3000000000000000000
Output
3000000000000000000 1000000000000000000
Note
In the first example the given sequence can be rearranged in the following way: [9, 3, 6, 12, 4, 8]. It can match possible Polycarp's game which started with x = 9. | instruction | 0 | 59,404 | 24 | 118,808 |
Tags: dfs and similar, math, sortings
Correct Solution:
```
from collections import Counter,defaultdict,deque
from math import factorial as fact
def primes(n):
i = 2
factors = []
while i * i <= n:
if n % i:
i += 1
else:
n //= i
factors.append(i)
if n > 1:
factors.append(n)
return factors
def count3(x):
c = 0
while x%3==0:
x//=3
c+=1
return c
def k(x):
return count3(x)*10**19-x
n = int(input())
a = [int(x) for x in input().split()]
a.sort(key =k,reverse=True)
print(*a)
#n,m = [int(x) for x in input().split()]
``` | output | 1 | 59,404 | 24 | 118,809 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp likes to play with numbers. He takes some integer number x, writes it down on the board, and then performs with it n - 1 operations of the two kinds:
* divide the number x by 3 (x must be divisible by 3);
* multiply the number x by 2.
After each operation, Polycarp writes down the result on the board and replaces x by the result. So there will be n numbers on the board after all.
You are given a sequence of length n — the numbers that Polycarp wrote down. This sequence is given in arbitrary order, i.e. the order of the sequence can mismatch the order of the numbers written on the board.
Your problem is to rearrange (reorder) elements of this sequence in such a way that it can match possible Polycarp's game in the order of the numbers written on the board. I.e. each next number will be exactly two times of the previous number or exactly one third of previous number.
It is guaranteed that the answer exists.
Input
The first line of the input contatins an integer number n (2 ≤ n ≤ 100) — the number of the elements in the sequence. The second line of the input contains n integer numbers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 3 ⋅ 10^{18}) — rearranged (reordered) sequence that Polycarp can wrote down on the board.
Output
Print n integer numbers — rearranged (reordered) input sequence that can be the sequence that Polycarp could write down on the board.
It is guaranteed that the answer exists.
Examples
Input
6
4 8 6 3 12 9
Output
9 3 6 12 4 8
Input
4
42 28 84 126
Output
126 42 84 28
Input
2
1000000000000000000 3000000000000000000
Output
3000000000000000000 1000000000000000000
Note
In the first example the given sequence can be rearranged in the following way: [9, 3, 6, 12, 4, 8]. It can match possible Polycarp's game which started with x = 9. | instruction | 0 | 59,405 | 24 | 118,810 |
Tags: dfs and similar, math, sortings
Correct Solution:
```
import math
from decimal import *
import random
from datetime import datetime
import time
def k(n):
ans = 0
while(n%3==0):
ans+=1
n//=3
return ans
n = int(input())
arr = list(map(int, input().split()))
ans = []
arr = sorted(arr, key = lambda x: (-k(x), x))
for i in range(n):
arr[i] = str(arr[i])
print(' '.join(arr))
``` | output | 1 | 59,405 | 24 | 118,811 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp likes to play with numbers. He takes some integer number x, writes it down on the board, and then performs with it n - 1 operations of the two kinds:
* divide the number x by 3 (x must be divisible by 3);
* multiply the number x by 2.
After each operation, Polycarp writes down the result on the board and replaces x by the result. So there will be n numbers on the board after all.
You are given a sequence of length n — the numbers that Polycarp wrote down. This sequence is given in arbitrary order, i.e. the order of the sequence can mismatch the order of the numbers written on the board.
Your problem is to rearrange (reorder) elements of this sequence in such a way that it can match possible Polycarp's game in the order of the numbers written on the board. I.e. each next number will be exactly two times of the previous number or exactly one third of previous number.
It is guaranteed that the answer exists.
Input
The first line of the input contatins an integer number n (2 ≤ n ≤ 100) — the number of the elements in the sequence. The second line of the input contains n integer numbers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 3 ⋅ 10^{18}) — rearranged (reordered) sequence that Polycarp can wrote down on the board.
Output
Print n integer numbers — rearranged (reordered) input sequence that can be the sequence that Polycarp could write down on the board.
It is guaranteed that the answer exists.
Examples
Input
6
4 8 6 3 12 9
Output
9 3 6 12 4 8
Input
4
42 28 84 126
Output
126 42 84 28
Input
2
1000000000000000000 3000000000000000000
Output
3000000000000000000 1000000000000000000
Note
In the first example the given sequence can be rearranged in the following way: [9, 3, 6, 12, 4, 8]. It can match possible Polycarp's game which started with x = 9. | instruction | 0 | 59,406 | 24 | 118,812 |
Tags: dfs and similar, math, sortings
Correct Solution:
```
n = int(input())
nums = list(map(int,input().split()))
nums.sort()
ans = []
for i in range(n):
aux = nums[:]
a = [nums[i]]
j = 0
while a[j]//3 in aux or a[j]*2 in aux:
b = a[j]//3
c = a[j]*2
if c in aux:
a.append(c)
aux.remove(c)
elif a[j] == 4:
break
else:
a.append(b)
aux.remove(b)
j += 1
ans.append(a)
ans.sort(key = len)
for item in ans[-1]:
print(item, end =' ')
``` | output | 1 | 59,406 | 24 | 118,813 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp likes to play with numbers. He takes some integer number x, writes it down on the board, and then performs with it n - 1 operations of the two kinds:
* divide the number x by 3 (x must be divisible by 3);
* multiply the number x by 2.
After each operation, Polycarp writes down the result on the board and replaces x by the result. So there will be n numbers on the board after all.
You are given a sequence of length n — the numbers that Polycarp wrote down. This sequence is given in arbitrary order, i.e. the order of the sequence can mismatch the order of the numbers written on the board.
Your problem is to rearrange (reorder) elements of this sequence in such a way that it can match possible Polycarp's game in the order of the numbers written on the board. I.e. each next number will be exactly two times of the previous number or exactly one third of previous number.
It is guaranteed that the answer exists.
Input
The first line of the input contatins an integer number n (2 ≤ n ≤ 100) — the number of the elements in the sequence. The second line of the input contains n integer numbers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 3 ⋅ 10^{18}) — rearranged (reordered) sequence that Polycarp can wrote down on the board.
Output
Print n integer numbers — rearranged (reordered) input sequence that can be the sequence that Polycarp could write down on the board.
It is guaranteed that the answer exists.
Examples
Input
6
4 8 6 3 12 9
Output
9 3 6 12 4 8
Input
4
42 28 84 126
Output
126 42 84 28
Input
2
1000000000000000000 3000000000000000000
Output
3000000000000000000 1000000000000000000
Note
In the first example the given sequence can be rearranged in the following way: [9, 3, 6, 12, 4, 8]. It can match possible Polycarp's game which started with x = 9.
Submitted Solution:
```
import sys, os
# import numpy as np
from math import sqrt, gcd, ceil, log, floor
from bisect import bisect, bisect_left
from collections import defaultdict, Counter, deque
from heapq import heapify, heappush, heappop
input = sys.stdin.readline
read = lambda: list(map(int, input().strip().split()))
# read_f = lambda file: list(map(int, file.readline().strip().split()))
# from time import time
# sys.setrecursionlimit(5*10**6)
MOD = 10**9 + 7
def main():
# file1 = open("C:\\Users\\shank\\Desktop\\Comp_Code\\input.txt", "r")
# n = int(file1.readline().strip());
# arr = list(map(int, file1.read().strip().split(" ")))
# file1.close()
n = int(input()); arr = read()
curr = arr[0]
i = 0
while True:
# print(curr)
if curr*3 in arr:curr *= 3
elif curr%2 == 0 and curr//2 in arr:curr //= 2
else:break
i += 1
if i > 100:break
ans = []; i =0
while True:
ans.append(curr)
# print(ans, curr)
if curr%3 == 0 and curr//3 in arr:curr //= 3
elif curr*2 in arr:curr *= 2
else:break
i += 1
if i > 100:break
print(*ans)
# file = open("output.txt", "w")
# file.write(ans+"\n")
# file.close()
if __name__ == "__main__":
main()
"""
1 3 2 X
2 3 1 X
1 2 3 *
dp[1, n-1][1, n] =
for i in range(1, n+1):dp[0][i] = 1
for i in range(1, n):
if arr[i] == "<":
for j in range(1, n+1):
for k in range(1, j):
dp[i][j] += dp[i-1][k]
else:
for j in range(1, n+1):
for k in range(j+1, n+1):
dp[i][j] += dp[i-1][k]
"""
``` | instruction | 0 | 59,407 | 24 | 118,814 |
Yes | output | 1 | 59,407 | 24 | 118,815 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp likes to play with numbers. He takes some integer number x, writes it down on the board, and then performs with it n - 1 operations of the two kinds:
* divide the number x by 3 (x must be divisible by 3);
* multiply the number x by 2.
After each operation, Polycarp writes down the result on the board and replaces x by the result. So there will be n numbers on the board after all.
You are given a sequence of length n — the numbers that Polycarp wrote down. This sequence is given in arbitrary order, i.e. the order of the sequence can mismatch the order of the numbers written on the board.
Your problem is to rearrange (reorder) elements of this sequence in such a way that it can match possible Polycarp's game in the order of the numbers written on the board. I.e. each next number will be exactly two times of the previous number or exactly one third of previous number.
It is guaranteed that the answer exists.
Input
The first line of the input contatins an integer number n (2 ≤ n ≤ 100) — the number of the elements in the sequence. The second line of the input contains n integer numbers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 3 ⋅ 10^{18}) — rearranged (reordered) sequence that Polycarp can wrote down on the board.
Output
Print n integer numbers — rearranged (reordered) input sequence that can be the sequence that Polycarp could write down on the board.
It is guaranteed that the answer exists.
Examples
Input
6
4 8 6 3 12 9
Output
9 3 6 12 4 8
Input
4
42 28 84 126
Output
126 42 84 28
Input
2
1000000000000000000 3000000000000000000
Output
3000000000000000000 1000000000000000000
Note
In the first example the given sequence can be rearranged in the following way: [9, 3, 6, 12, 4, 8]. It can match possible Polycarp's game which started with x = 9.
Submitted Solution:
```
import sys
input = sys.stdin.readline
N = int(input())
S = list(map(int,input().split()))
def neighbours(node,s=S):
out = [node<<1]
if node % 3 == 0:
out.append(node//3)
return set(x for x in out if x in s)
G = {}
for x in S:
G[x] = neighbours(x)
def hamilton(G, size, pt, path=None):
if path == None:
path = []
if pt not in set(path):
path.append(pt)
if len(path)==size:
return path
for pt_next in G.get(pt, []):
res_path = [i for i in path]
candidate = hamilton(G, size, pt_next, res_path)
if candidate is not None:
return candidate
for x in S:
P = hamilton(G,N,x)
if P:
print(" ".join(map(str,P)))
break
``` | instruction | 0 | 59,408 | 24 | 118,816 |
Yes | output | 1 | 59,408 | 24 | 118,817 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp likes to play with numbers. He takes some integer number x, writes it down on the board, and then performs with it n - 1 operations of the two kinds:
* divide the number x by 3 (x must be divisible by 3);
* multiply the number x by 2.
After each operation, Polycarp writes down the result on the board and replaces x by the result. So there will be n numbers on the board after all.
You are given a sequence of length n — the numbers that Polycarp wrote down. This sequence is given in arbitrary order, i.e. the order of the sequence can mismatch the order of the numbers written on the board.
Your problem is to rearrange (reorder) elements of this sequence in such a way that it can match possible Polycarp's game in the order of the numbers written on the board. I.e. each next number will be exactly two times of the previous number or exactly one third of previous number.
It is guaranteed that the answer exists.
Input
The first line of the input contatins an integer number n (2 ≤ n ≤ 100) — the number of the elements in the sequence. The second line of the input contains n integer numbers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 3 ⋅ 10^{18}) — rearranged (reordered) sequence that Polycarp can wrote down on the board.
Output
Print n integer numbers — rearranged (reordered) input sequence that can be the sequence that Polycarp could write down on the board.
It is guaranteed that the answer exists.
Examples
Input
6
4 8 6 3 12 9
Output
9 3 6 12 4 8
Input
4
42 28 84 126
Output
126 42 84 28
Input
2
1000000000000000000 3000000000000000000
Output
3000000000000000000 1000000000000000000
Note
In the first example the given sequence can be rearranged in the following way: [9, 3, 6, 12, 4, 8]. It can match possible Polycarp's game which started with x = 9.
Submitted Solution:
```
import sys
from collections import defaultdict
input = sys.stdin.readline
def main():
n = int(input())
a = list(map(int, input().split()))
for x in a:
d = defaultdict(lambda: 0)
for y in a:
d[y] += 1
bad = False
ans = [x]
for _ in range(n - 1):
if d[2 * x] > 0:
d[2 * x] -= 1
x *= 2
elif x % 3 == 0 and d[x // 3] > 0:
d[x // 3] -= 1
x //= 3
else:
bad = True
break
ans.append(x)
if not bad:
print(" ".join(map(str, ans)))
return
assert(0)
main()
``` | instruction | 0 | 59,409 | 24 | 118,818 |
Yes | output | 1 | 59,409 | 24 | 118,819 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp likes to play with numbers. He takes some integer number x, writes it down on the board, and then performs with it n - 1 operations of the two kinds:
* divide the number x by 3 (x must be divisible by 3);
* multiply the number x by 2.
After each operation, Polycarp writes down the result on the board and replaces x by the result. So there will be n numbers on the board after all.
You are given a sequence of length n — the numbers that Polycarp wrote down. This sequence is given in arbitrary order, i.e. the order of the sequence can mismatch the order of the numbers written on the board.
Your problem is to rearrange (reorder) elements of this sequence in such a way that it can match possible Polycarp's game in the order of the numbers written on the board. I.e. each next number will be exactly two times of the previous number or exactly one third of previous number.
It is guaranteed that the answer exists.
Input
The first line of the input contatins an integer number n (2 ≤ n ≤ 100) — the number of the elements in the sequence. The second line of the input contains n integer numbers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 3 ⋅ 10^{18}) — rearranged (reordered) sequence that Polycarp can wrote down on the board.
Output
Print n integer numbers — rearranged (reordered) input sequence that can be the sequence that Polycarp could write down on the board.
It is guaranteed that the answer exists.
Examples
Input
6
4 8 6 3 12 9
Output
9 3 6 12 4 8
Input
4
42 28 84 126
Output
126 42 84 28
Input
2
1000000000000000000 3000000000000000000
Output
3000000000000000000 1000000000000000000
Note
In the first example the given sequence can be rearranged in the following way: [9, 3, 6, 12, 4, 8]. It can match possible Polycarp's game which started with x = 9.
Submitted Solution:
```
from collections import deque
n = int(input())
nums = [int(x) for x in input().split(" ")]
nums.sort()
answer = deque()
answer.append(nums.pop())
k = 0
while len(nums) != 0:
nowLeft = answer[0]
nowRight = answer[len(answer) - 1]
swap_pos = 0
left = 0
for i, num in enumerate(nums):
if nowLeft == num * 2 or (num % 3 == 0 and num // 3 == nowLeft):
swap_pos = i
left = 1
break
if nowRight * 2 == num or (nowRight % 3 == 0 and num == nowRight // 3):
swap_pos = i
left = -1
break
if left == 1:
answer.appendleft(nums[swap_pos])
nums[swap_pos], nums[len(nums) - 1] = nums[len(nums) - 1], nums[swap_pos]
nums.pop()
elif left == -1:
answer.append(nums[swap_pos])
nums[swap_pos], nums[len(nums) - 1] = nums[len(nums) - 1], nums[swap_pos]
nums.pop()
for num in answer:
print(num, end=" ")
``` | instruction | 0 | 59,410 | 24 | 118,820 |
Yes | output | 1 | 59,410 | 24 | 118,821 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp likes to play with numbers. He takes some integer number x, writes it down on the board, and then performs with it n - 1 operations of the two kinds:
* divide the number x by 3 (x must be divisible by 3);
* multiply the number x by 2.
After each operation, Polycarp writes down the result on the board and replaces x by the result. So there will be n numbers on the board after all.
You are given a sequence of length n — the numbers that Polycarp wrote down. This sequence is given in arbitrary order, i.e. the order of the sequence can mismatch the order of the numbers written on the board.
Your problem is to rearrange (reorder) elements of this sequence in such a way that it can match possible Polycarp's game in the order of the numbers written on the board. I.e. each next number will be exactly two times of the previous number or exactly one third of previous number.
It is guaranteed that the answer exists.
Input
The first line of the input contatins an integer number n (2 ≤ n ≤ 100) — the number of the elements in the sequence. The second line of the input contains n integer numbers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 3 ⋅ 10^{18}) — rearranged (reordered) sequence that Polycarp can wrote down on the board.
Output
Print n integer numbers — rearranged (reordered) input sequence that can be the sequence that Polycarp could write down on the board.
It is guaranteed that the answer exists.
Examples
Input
6
4 8 6 3 12 9
Output
9 3 6 12 4 8
Input
4
42 28 84 126
Output
126 42 84 28
Input
2
1000000000000000000 3000000000000000000
Output
3000000000000000000 1000000000000000000
Note
In the first example the given sequence can be rearranged in the following way: [9, 3, 6, 12, 4, 8]. It can match possible Polycarp's game which started with x = 9.
Submitted Solution:
```
def found_sequence(possible_sequence, lookup):
# print(f'possible_sequence: {possible_sequence}')
if len(possible_sequence) == n:
print(" ".join(list(map(str, possible_sequence))))
return True
else:
last_element = possible_sequence[-1]
if last_element//3 in lookup and lookup[last_element//3] >= 1:
lookup[last_element//3] -= 1
possible_sequence.append(last_element//3)
if found_sequence(possible_sequence, lookup):
return True
if last_element*2 in lookup and lookup[last_element*2] >= 1:
lookup[last_element*2] -= 1
possible_sequence.append(last_element*2)
if found_sequence(possible_sequence, lookup):
return True
return False
if __name__ == '__main__':
n = int(input())
given_sequence = list(map(int, input().split()))
lookup = {}
result = []
for element in given_sequence:
if element in lookup:
lookup[element] += 1
else:
lookup[element] = 1
# print(f'lookup: {lookup}')
for index in range(len(given_sequence)):
if found_sequence([given_sequence[index]], dict(lookup)):
break
``` | instruction | 0 | 59,411 | 24 | 118,822 |
No | output | 1 | 59,411 | 24 | 118,823 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp likes to play with numbers. He takes some integer number x, writes it down on the board, and then performs with it n - 1 operations of the two kinds:
* divide the number x by 3 (x must be divisible by 3);
* multiply the number x by 2.
After each operation, Polycarp writes down the result on the board and replaces x by the result. So there will be n numbers on the board after all.
You are given a sequence of length n — the numbers that Polycarp wrote down. This sequence is given in arbitrary order, i.e. the order of the sequence can mismatch the order of the numbers written on the board.
Your problem is to rearrange (reorder) elements of this sequence in such a way that it can match possible Polycarp's game in the order of the numbers written on the board. I.e. each next number will be exactly two times of the previous number or exactly one third of previous number.
It is guaranteed that the answer exists.
Input
The first line of the input contatins an integer number n (2 ≤ n ≤ 100) — the number of the elements in the sequence. The second line of the input contains n integer numbers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 3 ⋅ 10^{18}) — rearranged (reordered) sequence that Polycarp can wrote down on the board.
Output
Print n integer numbers — rearranged (reordered) input sequence that can be the sequence that Polycarp could write down on the board.
It is guaranteed that the answer exists.
Examples
Input
6
4 8 6 3 12 9
Output
9 3 6 12 4 8
Input
4
42 28 84 126
Output
126 42 84 28
Input
2
1000000000000000000 3000000000000000000
Output
3000000000000000000 1000000000000000000
Note
In the first example the given sequence can be rearranged in the following way: [9, 3, 6, 12, 4, 8]. It can match possible Polycarp's game which started with x = 9.
Submitted Solution:
```
n = int(input())
nums = list(map(int,input().split()))
ans = []
for i in range(n):
aux = nums[:]
a = [nums[i]]
j = 0
while a[j]//3 in aux or a[j]*2 in aux:
b = a[j]/3
c = a[j]*2
if c in aux:
a.append(c)
aux.remove(c)
elif b in aux:
a.append(int(b))
aux.remove(int(b))
else:
break
j += 1
ans.append(a)
ans.sort(key = len)
for item in ans[-1]:
print(item, end =' ')
``` | instruction | 0 | 59,412 | 24 | 118,824 |
No | output | 1 | 59,412 | 24 | 118,825 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp likes to play with numbers. He takes some integer number x, writes it down on the board, and then performs with it n - 1 operations of the two kinds:
* divide the number x by 3 (x must be divisible by 3);
* multiply the number x by 2.
After each operation, Polycarp writes down the result on the board and replaces x by the result. So there will be n numbers on the board after all.
You are given a sequence of length n — the numbers that Polycarp wrote down. This sequence is given in arbitrary order, i.e. the order of the sequence can mismatch the order of the numbers written on the board.
Your problem is to rearrange (reorder) elements of this sequence in such a way that it can match possible Polycarp's game in the order of the numbers written on the board. I.e. each next number will be exactly two times of the previous number or exactly one third of previous number.
It is guaranteed that the answer exists.
Input
The first line of the input contatins an integer number n (2 ≤ n ≤ 100) — the number of the elements in the sequence. The second line of the input contains n integer numbers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 3 ⋅ 10^{18}) — rearranged (reordered) sequence that Polycarp can wrote down on the board.
Output
Print n integer numbers — rearranged (reordered) input sequence that can be the sequence that Polycarp could write down on the board.
It is guaranteed that the answer exists.
Examples
Input
6
4 8 6 3 12 9
Output
9 3 6 12 4 8
Input
4
42 28 84 126
Output
126 42 84 28
Input
2
1000000000000000000 3000000000000000000
Output
3000000000000000000 1000000000000000000
Note
In the first example the given sequence can be rearranged in the following way: [9, 3, 6, 12, 4, 8]. It can match possible Polycarp's game which started with x = 9.
Submitted Solution:
```
n=int(input())
a=[int (a) for a in input().split()]
ans=[]
while (a):
for i in a:
if ((i/2 not in a) and (i*3 not in a)):
ans.append(i)
a.remove(i)
print (ans)
``` | instruction | 0 | 59,413 | 24 | 118,826 |
No | output | 1 | 59,413 | 24 | 118,827 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp likes to play with numbers. He takes some integer number x, writes it down on the board, and then performs with it n - 1 operations of the two kinds:
* divide the number x by 3 (x must be divisible by 3);
* multiply the number x by 2.
After each operation, Polycarp writes down the result on the board and replaces x by the result. So there will be n numbers on the board after all.
You are given a sequence of length n — the numbers that Polycarp wrote down. This sequence is given in arbitrary order, i.e. the order of the sequence can mismatch the order of the numbers written on the board.
Your problem is to rearrange (reorder) elements of this sequence in such a way that it can match possible Polycarp's game in the order of the numbers written on the board. I.e. each next number will be exactly two times of the previous number or exactly one third of previous number.
It is guaranteed that the answer exists.
Input
The first line of the input contatins an integer number n (2 ≤ n ≤ 100) — the number of the elements in the sequence. The second line of the input contains n integer numbers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 3 ⋅ 10^{18}) — rearranged (reordered) sequence that Polycarp can wrote down on the board.
Output
Print n integer numbers — rearranged (reordered) input sequence that can be the sequence that Polycarp could write down on the board.
It is guaranteed that the answer exists.
Examples
Input
6
4 8 6 3 12 9
Output
9 3 6 12 4 8
Input
4
42 28 84 126
Output
126 42 84 28
Input
2
1000000000000000000 3000000000000000000
Output
3000000000000000000 1000000000000000000
Note
In the first example the given sequence can be rearranged in the following way: [9, 3, 6, 12, 4, 8]. It can match possible Polycarp's game which started with x = 9.
Submitted Solution:
```
n = int(input())
l = sorted([int(x) for x in input().split()])
m = l[-1]
a = []
b = []
def solve_before(l, m, k):
if k > m or k in b:
return
b.append(k)
if k % 2 == 0:
solve_before(1, m, k // 2)
else:
solve_before(1, m, k * 3)
return
def solve_after(l, m, k):
if k > m or k in a:
return False
a.append(k)
if k % 3 == 0:
solve_after(l, m, k // 3)
else:
solve_after(l, m, k * 2)
return True
solve_before(l, m, m)
solve_after(l, m, m)
ans = list(reversed(b)) + a[1:]
print(" ".join(str(x) for x in ans))
``` | instruction | 0 | 59,414 | 24 | 118,828 |
No | output | 1 | 59,414 | 24 | 118,829 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp has n coins, the value of the i-th coin is a_i. It is guaranteed that all the values are integer powers of 2 (i.e. a_i = 2^d for some non-negative integer number d).
Polycarp wants to know answers on q queries. The j-th query is described as integer number b_j. The answer to the query is the minimum number of coins that is necessary to obtain the value b_j using some subset of coins (Polycarp can use only coins he has). If Polycarp can't obtain the value b_j, the answer to the j-th query is -1.
The queries are independent (the answer on the query doesn't affect Polycarp's coins).
Input
The first line of the input contains two integers n and q (1 ≤ n, q ≤ 2 ⋅ 10^5) — the number of coins and the number of queries.
The second line of the input contains n integers a_1, a_2, ..., a_n — values of coins (1 ≤ a_i ≤ 2 ⋅ 10^9). It is guaranteed that all a_i are integer powers of 2 (i.e. a_i = 2^d for some non-negative integer number d).
The next q lines contain one integer each. The j-th line contains one integer b_j — the value of the j-th query (1 ≤ b_j ≤ 10^9).
Output
Print q integers ans_j. The j-th integer must be equal to the answer on the j-th query. If Polycarp can't obtain the value b_j the answer to the j-th query is -1.
Example
Input
5 4
2 4 8 2 4
8
5
14
10
Output
1
-1
3
2 | instruction | 0 | 59,718 | 24 | 119,436 |
Tags: greedy
Correct Solution:
```
def main():
d={}
nums=[None]*31
for i in range(31):
nums[i]=2**i
d[nums[i]]=0
n,q=map(int,input().split())
a=list(map(int,input().split()))
for i in range(n):
d[a[i]]+=1
for i in range(31):
if d[nums[i]]==0:
del d[nums[i]]
keys=sorted(list(d.keys()))[::-1]
leng=len(keys)
ans=[0]*q
for i in range(q):
val=int(input())
for j in range(leng):
if keys[j]<=val:
coin=min(d[keys[j]],val//keys[j])
ans[i]+=coin
val-=keys[j]*coin
if val==0:
break
else:
ans[i]=-1
print('\n'.join(list(map(str,ans))))
main()
``` | output | 1 | 59,718 | 24 | 119,437 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp has n coins, the value of the i-th coin is a_i. It is guaranteed that all the values are integer powers of 2 (i.e. a_i = 2^d for some non-negative integer number d).
Polycarp wants to know answers on q queries. The j-th query is described as integer number b_j. The answer to the query is the minimum number of coins that is necessary to obtain the value b_j using some subset of coins (Polycarp can use only coins he has). If Polycarp can't obtain the value b_j, the answer to the j-th query is -1.
The queries are independent (the answer on the query doesn't affect Polycarp's coins).
Input
The first line of the input contains two integers n and q (1 ≤ n, q ≤ 2 ⋅ 10^5) — the number of coins and the number of queries.
The second line of the input contains n integers a_1, a_2, ..., a_n — values of coins (1 ≤ a_i ≤ 2 ⋅ 10^9). It is guaranteed that all a_i are integer powers of 2 (i.e. a_i = 2^d for some non-negative integer number d).
The next q lines contain one integer each. The j-th line contains one integer b_j — the value of the j-th query (1 ≤ b_j ≤ 10^9).
Output
Print q integers ans_j. The j-th integer must be equal to the answer on the j-th query. If Polycarp can't obtain the value b_j the answer to the j-th query is -1.
Example
Input
5 4
2 4 8 2 4
8
5
14
10
Output
1
-1
3
2 | instruction | 0 | 59,719 | 24 | 119,438 |
Tags: greedy
Correct Solution:
```
# aadiupadhyay
import os.path
from math import gcd, floor, ceil
from collections import *
import sys
mod = 1000000007
INF = float('inf')
def st(): return list(sys.stdin.readline().strip())
def li(): return list(map(int, sys.stdin.readline().split()))
def mp(): return map(int, sys.stdin.readline().split())
def inp(): return int(sys.stdin.readline())
def pr(n): return sys.stdout.write(str(n)+"\n")
def prl(n): return sys.stdout.write(str(n)+" ")
if os.path.exists('input.txt'):
sys.stdin = open('input.txt', 'r')
sys.stdout = open('output.txt', 'w')
# python not passed
def solve():
n, m = mp()
ans = []
l = li()
d = Counter(l)
for i in range(m):
x = inp()
cur = 30
now = 0
while cur >= 0 and x > 0:
val = 1 << cur
have = d[val]
want = x//val
mi = min(have, want)
x -= mi * val
now += mi
cur -= 1
if x == 0:
ans.append(now)
else:
ans.append(-1)
print(*ans, sep='\n')
for _ in range(1):
solve()
``` | output | 1 | 59,719 | 24 | 119,439 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp has n coins, the value of the i-th coin is a_i. It is guaranteed that all the values are integer powers of 2 (i.e. a_i = 2^d for some non-negative integer number d).
Polycarp wants to know answers on q queries. The j-th query is described as integer number b_j. The answer to the query is the minimum number of coins that is necessary to obtain the value b_j using some subset of coins (Polycarp can use only coins he has). If Polycarp can't obtain the value b_j, the answer to the j-th query is -1.
The queries are independent (the answer on the query doesn't affect Polycarp's coins).
Input
The first line of the input contains two integers n and q (1 ≤ n, q ≤ 2 ⋅ 10^5) — the number of coins and the number of queries.
The second line of the input contains n integers a_1, a_2, ..., a_n — values of coins (1 ≤ a_i ≤ 2 ⋅ 10^9). It is guaranteed that all a_i are integer powers of 2 (i.e. a_i = 2^d for some non-negative integer number d).
The next q lines contain one integer each. The j-th line contains one integer b_j — the value of the j-th query (1 ≤ b_j ≤ 10^9).
Output
Print q integers ans_j. The j-th integer must be equal to the answer on the j-th query. If Polycarp can't obtain the value b_j the answer to the j-th query is -1.
Example
Input
5 4
2 4 8 2 4
8
5
14
10
Output
1
-1
3
2 | instruction | 0 | 59,720 | 24 | 119,440 |
Tags: greedy
Correct Solution:
```
#####################################
import atexit, io, sys, collections, math, heapq, fractions,copy, os, functools
import sys
import random
import collections
from io import BytesIO, IOBase
##################################### python 3 START
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
##################################### python 3 END
n,nq = map(int, input().split())
ais = list(map(int, input().split()))
s = list(set(ais))
s.sort(key = lambda x:-x)
cc = collections.Counter(ais)
def f(s,cc ,q):
ans = 0
for ai in s:
if q >= ai:
t = min(cc[ai], q // ai)
q-= t*ai
ans +=t
if q == 0:
break
return ans if q == 0 else -1
for _ in range(nq):
q = int(input())
print (f(s,cc, q))
``` | output | 1 | 59,720 | 24 | 119,441 |
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