message stringlengths 2 39.6k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 450 109k | cluster float64 2 2 | __index_level_0__ int64 900 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are playing one RPG from the 2010s. You are planning to raise your smithing skill, so you need as many resources as possible. So how to get resources? By stealing, of course.
You decided to rob a town's blacksmith and you take a follower with you. You can carry at most p units and your follower โ at most f units.
In the blacksmith shop, you found cnt_s swords and cnt_w war axes. Each sword weights s units and each war axe โ w units. You don't care what to take, since each of them will melt into one steel ingot.
What is the maximum number of weapons (both swords and war axes) you and your follower can carry out from the shop?
Input
The first line contains a single integer t (1 โค t โค 10^4) โ the number of test cases.
The first line of each test case contains two integers p and f (1 โค p, f โค 10^9) โ yours and your follower's capacities.
The second line of each test case contains two integers cnt_s and cnt_w (1 โค cnt_s, cnt_w โค 2 โ
10^5) โ the number of swords and war axes in the shop.
The third line of each test case contains two integers s and w (1 โค s, w โค 10^9) โ the weights of each sword and each war axe.
It's guaranteed that the total number of swords and the total number of war axes in all test cases don't exceed 2 โ
10^5.
Output
For each test case, print the maximum number of weapons (both swords and war axes) you and your follower can carry.
Example
Input
3
33 27
6 10
5 6
100 200
10 10
5 5
1 19
1 3
19 5
Output
11
20
3
Note
In the first test case:
* you should take 3 swords and 3 war axes: 3 โ
5 + 3 โ
6 = 33 โค 33
* and your follower โ 3 swords and 2 war axes: 3 โ
5 + 2 โ
6 = 27 โค 27.
3 + 3 + 3 + 2 = 11 weapons in total.
In the second test case, you can take all available weapons even without your follower's help, since 5 โ
10 + 5 โ
10 โค 100.
In the third test case, you can't take anything, but your follower can take 3 war axes: 3 โ
5 โค 19. | instruction | 0 | 66,625 | 2 | 133,250 |
Tags: brute force, greedy, math
Correct Solution:
```
for _ in range(int(input())):
p, f = map(int, input().split())
scnt, wcnt = map(int, input().split())
s, w = map(int, input().split())
ans = 0
if s > w:
s, w = w, s
scnt, wcnt = wcnt, scnt
for i in range(scnt + 1):
if i * s > p: break
j = (p - i * s) // w
k = min(scnt - i, f // s)
l = min(wcnt - j, (f - k * s) // w)
ans = max(ans, i + j + k + l)
print(ans)
``` | output | 1 | 66,625 | 2 | 133,251 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are playing one RPG from the 2010s. You are planning to raise your smithing skill, so you need as many resources as possible. So how to get resources? By stealing, of course.
You decided to rob a town's blacksmith and you take a follower with you. You can carry at most p units and your follower โ at most f units.
In the blacksmith shop, you found cnt_s swords and cnt_w war axes. Each sword weights s units and each war axe โ w units. You don't care what to take, since each of them will melt into one steel ingot.
What is the maximum number of weapons (both swords and war axes) you and your follower can carry out from the shop?
Input
The first line contains a single integer t (1 โค t โค 10^4) โ the number of test cases.
The first line of each test case contains two integers p and f (1 โค p, f โค 10^9) โ yours and your follower's capacities.
The second line of each test case contains two integers cnt_s and cnt_w (1 โค cnt_s, cnt_w โค 2 โ
10^5) โ the number of swords and war axes in the shop.
The third line of each test case contains two integers s and w (1 โค s, w โค 10^9) โ the weights of each sword and each war axe.
It's guaranteed that the total number of swords and the total number of war axes in all test cases don't exceed 2 โ
10^5.
Output
For each test case, print the maximum number of weapons (both swords and war axes) you and your follower can carry.
Example
Input
3
33 27
6 10
5 6
100 200
10 10
5 5
1 19
1 3
19 5
Output
11
20
3
Note
In the first test case:
* you should take 3 swords and 3 war axes: 3 โ
5 + 3 โ
6 = 33 โค 33
* and your follower โ 3 swords and 2 war axes: 3 โ
5 + 2 โ
6 = 27 โค 27.
3 + 3 + 3 + 2 = 11 weapons in total.
In the second test case, you can take all available weapons even without your follower's help, since 5 โ
10 + 5 โ
10 โค 100.
In the third test case, you can't take anything, but your follower can take 3 war axes: 3 โ
5 โค 19. | instruction | 0 | 66,626 | 2 | 133,252 |
Tags: brute force, greedy, math
Correct Solution:
```
for _ in range(int(input())):
p,f=[int(j) for j in input().split()]
counts,countw=[int(j) for j in input().split()]
s,w=[int(j) for j in input().split()]
if(s>w):
g=w
w=s
s=g
g=countw
countw=counts
counts=g
ans=0
g=p//s
g=min(g,counts)
while g>=0:
temp=0
temp+=g
p1=p-g*s
s1=counts-g
b=min(p1//w,countw)
temp+=b
w1=countw-b
f1=min(s1,f//s)
temp+=f1
f2=f-f1*s
cc=min(w1,f2//w)
temp+=cc
g-=1
ans=max(ans,temp)
g=f//s
g=min(g,counts)
while g>=0:
temp=0
temp+=g
p1=f-g*s
s1=counts-g
b=min(p1//w,countw)
temp+=b
w1=countw-b
f1=min(s1,p//s)
temp+=f1
f2=p-f1*s
cc=min(w1,f2//w)
temp+=cc
g-=1
ans=max(ans,temp)
print(ans)
``` | output | 1 | 66,626 | 2 | 133,253 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are playing one RPG from the 2010s. You are planning to raise your smithing skill, so you need as many resources as possible. So how to get resources? By stealing, of course.
You decided to rob a town's blacksmith and you take a follower with you. You can carry at most p units and your follower โ at most f units.
In the blacksmith shop, you found cnt_s swords and cnt_w war axes. Each sword weights s units and each war axe โ w units. You don't care what to take, since each of them will melt into one steel ingot.
What is the maximum number of weapons (both swords and war axes) you and your follower can carry out from the shop?
Input
The first line contains a single integer t (1 โค t โค 10^4) โ the number of test cases.
The first line of each test case contains two integers p and f (1 โค p, f โค 10^9) โ yours and your follower's capacities.
The second line of each test case contains two integers cnt_s and cnt_w (1 โค cnt_s, cnt_w โค 2 โ
10^5) โ the number of swords and war axes in the shop.
The third line of each test case contains two integers s and w (1 โค s, w โค 10^9) โ the weights of each sword and each war axe.
It's guaranteed that the total number of swords and the total number of war axes in all test cases don't exceed 2 โ
10^5.
Output
For each test case, print the maximum number of weapons (both swords and war axes) you and your follower can carry.
Example
Input
3
33 27
6 10
5 6
100 200
10 10
5 5
1 19
1 3
19 5
Output
11
20
3
Note
In the first test case:
* you should take 3 swords and 3 war axes: 3 โ
5 + 3 โ
6 = 33 โค 33
* and your follower โ 3 swords and 2 war axes: 3 โ
5 + 2 โ
6 = 27 โค 27.
3 + 3 + 3 + 2 = 11 weapons in total.
In the second test case, you can take all available weapons even without your follower's help, since 5 โ
10 + 5 โ
10 โค 100.
In the third test case, you can't take anything, but your follower can take 3 war axes: 3 โ
5 โค 19. | instruction | 0 | 66,627 | 2 | 133,254 |
Tags: brute force, greedy, math
Correct Solution:
```
def maxItem(p, f, cnts, cntw, s, w):
if s > w:
return maxItem(p, f, cntw, cnts, w, s)
if p < f:
return maxItem(f, p, cntw, cnts, w, s)
ans = 0
for s1 in range(min(cnts, p // s) + 1):
w1 = min(cntw, (p - s1 * s) // w)
s2 = min(cnts - s1, f // s)
w2 = min(cntw - w1, (f - s2 * s) // w)
ans = max(ans, s1 + s2 + w1 + w2)
return ans
if __name__ == '__main__':
t = int(input())
for _ in range(t):
p, f = [*map(int, input().split())][:2]
cnts, cntw = [*map(int, input().split())][:2]
s, w = [*map(int, input().split())][:2]
print(maxItem(p, f, cnts, cntw, s, w))
``` | output | 1 | 66,627 | 2 | 133,255 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are playing one RPG from the 2010s. You are planning to raise your smithing skill, so you need as many resources as possible. So how to get resources? By stealing, of course.
You decided to rob a town's blacksmith and you take a follower with you. You can carry at most p units and your follower โ at most f units.
In the blacksmith shop, you found cnt_s swords and cnt_w war axes. Each sword weights s units and each war axe โ w units. You don't care what to take, since each of them will melt into one steel ingot.
What is the maximum number of weapons (both swords and war axes) you and your follower can carry out from the shop?
Input
The first line contains a single integer t (1 โค t โค 10^4) โ the number of test cases.
The first line of each test case contains two integers p and f (1 โค p, f โค 10^9) โ yours and your follower's capacities.
The second line of each test case contains two integers cnt_s and cnt_w (1 โค cnt_s, cnt_w โค 2 โ
10^5) โ the number of swords and war axes in the shop.
The third line of each test case contains two integers s and w (1 โค s, w โค 10^9) โ the weights of each sword and each war axe.
It's guaranteed that the total number of swords and the total number of war axes in all test cases don't exceed 2 โ
10^5.
Output
For each test case, print the maximum number of weapons (both swords and war axes) you and your follower can carry.
Example
Input
3
33 27
6 10
5 6
100 200
10 10
5 5
1 19
1 3
19 5
Output
11
20
3
Note
In the first test case:
* you should take 3 swords and 3 war axes: 3 โ
5 + 3 โ
6 = 33 โค 33
* and your follower โ 3 swords and 2 war axes: 3 โ
5 + 2 โ
6 = 27 โค 27.
3 + 3 + 3 + 2 = 11 weapons in total.
In the second test case, you can take all available weapons even without your follower's help, since 5 โ
10 + 5 โ
10 โค 100.
In the third test case, you can't take anything, but your follower can take 3 war axes: 3 โ
5 โค 19.
Submitted Solution:
```
# https://codeforces.com/contest/1400/problem/B
'''
Author @Subhajit Das (sdsubhajitdas.github.io)
SWE @Turbot HQ India PVT Ltd.
30/08/2020
'''
def main():
myCapacity, folCapacity = map(int, input().strip().split())
# 33 27
swords, axes = map(int, input().strip().split())
# 6 10
swordWeight, axeWeight = map(int, input().strip().split())
# 5 6
if(swordWeight > axeWeight):
swordWeight, axeWeight = axeWeight, swordWeight
swords, axes = axes, swords
maxWeapons = 0
for takenSword in range(swords+1):
if(takenSword*swordWeight > myCapacity):
continue
folTakenSword = min(swords-takenSword, folCapacity//swordWeight)
leftMyCapacity = myCapacity - swordWeight*takenSword
leftFolCapacity = folCapacity - swordWeight*folTakenSword
takenAxe = min(leftMyCapacity//axeWeight, axes)
folTakenAxe = min(leftFolCapacity//axeWeight, axes - takenAxe)
maxWeapons = max(maxWeapons, takenSword+folTakenSword+takenAxe+folTakenAxe)
print(maxWeapons)
if __name__ == "__main__":
for _ in range(int(input())):
main()
# main()
``` | instruction | 0 | 66,628 | 2 | 133,256 |
Yes | output | 1 | 66,628 | 2 | 133,257 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are playing one RPG from the 2010s. You are planning to raise your smithing skill, so you need as many resources as possible. So how to get resources? By stealing, of course.
You decided to rob a town's blacksmith and you take a follower with you. You can carry at most p units and your follower โ at most f units.
In the blacksmith shop, you found cnt_s swords and cnt_w war axes. Each sword weights s units and each war axe โ w units. You don't care what to take, since each of them will melt into one steel ingot.
What is the maximum number of weapons (both swords and war axes) you and your follower can carry out from the shop?
Input
The first line contains a single integer t (1 โค t โค 10^4) โ the number of test cases.
The first line of each test case contains two integers p and f (1 โค p, f โค 10^9) โ yours and your follower's capacities.
The second line of each test case contains two integers cnt_s and cnt_w (1 โค cnt_s, cnt_w โค 2 โ
10^5) โ the number of swords and war axes in the shop.
The third line of each test case contains two integers s and w (1 โค s, w โค 10^9) โ the weights of each sword and each war axe.
It's guaranteed that the total number of swords and the total number of war axes in all test cases don't exceed 2 โ
10^5.
Output
For each test case, print the maximum number of weapons (both swords and war axes) you and your follower can carry.
Example
Input
3
33 27
6 10
5 6
100 200
10 10
5 5
1 19
1 3
19 5
Output
11
20
3
Note
In the first test case:
* you should take 3 swords and 3 war axes: 3 โ
5 + 3 โ
6 = 33 โค 33
* and your follower โ 3 swords and 2 war axes: 3 โ
5 + 2 โ
6 = 27 โค 27.
3 + 3 + 3 + 2 = 11 weapons in total.
In the second test case, you can take all available weapons even without your follower's help, since 5 โ
10 + 5 โ
10 โค 100.
In the third test case, you can't take anything, but your follower can take 3 war axes: 3 โ
5 โค 19.
Submitted Solution:
```
for test in range(int(input())):
p, f = map(int, input().split())
cnt1, cnt2 = map(int, input().split())
s, w = map(int, input().split())
if s > w:
s, w = w, s
cnt1, cnt2 = cnt2, cnt1
ans = 0
f1 = f
p1 = p
for i in range(cnt1 + 1):
f = f1
p = p1
if s * i <= p:
now = i
p -= s * i
d = min(cnt1 - i, f // s)
f -= d * s
now += d
x = min(cnt2, p // w)
z = cnt2 - x
now += x
x = min(z, f // w)
now += x
ans = max(ans, now)
print(ans)
``` | instruction | 0 | 66,629 | 2 | 133,258 |
Yes | output | 1 | 66,629 | 2 | 133,259 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are playing one RPG from the 2010s. You are planning to raise your smithing skill, so you need as many resources as possible. So how to get resources? By stealing, of course.
You decided to rob a town's blacksmith and you take a follower with you. You can carry at most p units and your follower โ at most f units.
In the blacksmith shop, you found cnt_s swords and cnt_w war axes. Each sword weights s units and each war axe โ w units. You don't care what to take, since each of them will melt into one steel ingot.
What is the maximum number of weapons (both swords and war axes) you and your follower can carry out from the shop?
Input
The first line contains a single integer t (1 โค t โค 10^4) โ the number of test cases.
The first line of each test case contains two integers p and f (1 โค p, f โค 10^9) โ yours and your follower's capacities.
The second line of each test case contains two integers cnt_s and cnt_w (1 โค cnt_s, cnt_w โค 2 โ
10^5) โ the number of swords and war axes in the shop.
The third line of each test case contains two integers s and w (1 โค s, w โค 10^9) โ the weights of each sword and each war axe.
It's guaranteed that the total number of swords and the total number of war axes in all test cases don't exceed 2 โ
10^5.
Output
For each test case, print the maximum number of weapons (both swords and war axes) you and your follower can carry.
Example
Input
3
33 27
6 10
5 6
100 200
10 10
5 5
1 19
1 3
19 5
Output
11
20
3
Note
In the first test case:
* you should take 3 swords and 3 war axes: 3 โ
5 + 3 โ
6 = 33 โค 33
* and your follower โ 3 swords and 2 war axes: 3 โ
5 + 2 โ
6 = 27 โค 27.
3 + 3 + 3 + 2 = 11 weapons in total.
In the second test case, you can take all available weapons even without your follower's help, since 5 โ
10 + 5 โ
10 โค 100.
In the third test case, you can't take anything, but your follower can take 3 war axes: 3 โ
5 โค 19.
Submitted Solution:
```
from sys import stdin
tt = int(stdin.readline())
for loop in range(tt):
p,f = map(int,stdin.readline().split())
cs,cw = map(int,stdin.readline().split())
s,w = map(int,stdin.readline().split())
if s > w:
cs,cw = cw,cs
s,w = w,s
ans = 0
for ps in range(cs+1):
if ps * s > p:
break
pw = min(cw , (p-ps*s)//w)
fs = min( cs-ps , f//s )
fw = min( cw-pw , (f-fs*s)//w )
ans = max(ans , ps+pw+fs+fw)
print (ans)
``` | instruction | 0 | 66,630 | 2 | 133,260 |
Yes | output | 1 | 66,630 | 2 | 133,261 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are playing one RPG from the 2010s. You are planning to raise your smithing skill, so you need as many resources as possible. So how to get resources? By stealing, of course.
You decided to rob a town's blacksmith and you take a follower with you. You can carry at most p units and your follower โ at most f units.
In the blacksmith shop, you found cnt_s swords and cnt_w war axes. Each sword weights s units and each war axe โ w units. You don't care what to take, since each of them will melt into one steel ingot.
What is the maximum number of weapons (both swords and war axes) you and your follower can carry out from the shop?
Input
The first line contains a single integer t (1 โค t โค 10^4) โ the number of test cases.
The first line of each test case contains two integers p and f (1 โค p, f โค 10^9) โ yours and your follower's capacities.
The second line of each test case contains two integers cnt_s and cnt_w (1 โค cnt_s, cnt_w โค 2 โ
10^5) โ the number of swords and war axes in the shop.
The third line of each test case contains two integers s and w (1 โค s, w โค 10^9) โ the weights of each sword and each war axe.
It's guaranteed that the total number of swords and the total number of war axes in all test cases don't exceed 2 โ
10^5.
Output
For each test case, print the maximum number of weapons (both swords and war axes) you and your follower can carry.
Example
Input
3
33 27
6 10
5 6
100 200
10 10
5 5
1 19
1 3
19 5
Output
11
20
3
Note
In the first test case:
* you should take 3 swords and 3 war axes: 3 โ
5 + 3 โ
6 = 33 โค 33
* and your follower โ 3 swords and 2 war axes: 3 โ
5 + 2 โ
6 = 27 โค 27.
3 + 3 + 3 + 2 = 11 weapons in total.
In the second test case, you can take all available weapons even without your follower's help, since 5 โ
10 + 5 โ
10 โค 100.
In the third test case, you can't take anything, but your follower can take 3 war axes: 3 โ
5 โค 19.
Submitted Solution:
```
import sys
import math
import heapq
import bisect
from collections import Counter
from collections import defaultdict
from io import BytesIO, IOBase
import string
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
import os
self.os = os
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
self.BUFSIZE = 8192
def read(self):
while True:
b = self.os.read(self._fd, max(self.os.fstat(self._fd).st_size, self.BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = self.os.read(self._fd, max(self.os.fstat(self._fd).st_size, self.BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
self.os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
def get_int():
return int(input())
def get_ints():
return list(map(int, input().split(' ')))
def get_int_grid(n):
return [get_ints() for _ in range(n)]
def get_str():
return input().strip()
def get_strs():
return get_str().split(' ')
def flat_list(arr):
return [item for subarr in arr for item in subarr]
def yes_no(b):
if b:
return "YES"
else:
return "NO"
def binary_search(good, left, right, delta=1, right_true=False):
"""
Performs binary search
----------
Parameters
----------
:param good: Function used to perform the binary search
:param left: Starting value of left limit
:param right: Starting value of the right limit
:param delta: Margin of error, defaults value of 1 for integer binary search
:param right_true: Boolean, for whether the right limit is the true invariant
:return: Returns the most extremal value interval [left, right] which is good function evaluates to True,
alternatively returns False if no such value found
"""
limits = [left, right]
while limits[1] - limits[0] > delta:
if delta == 1:
mid = sum(limits) // 2
else:
mid = sum(limits) / 2
if good(mid):
limits[int(right_true)] = mid
else:
limits[int(~right_true)] = mid
if good(limits[int(right_true)]):
return limits[int(right_true)]
else:
return False
def prefix_sums(a):
p = [0]
for x in a:
p.append(p[-1] + x)
return p
def solve_a():
n = get_int()
s = get_str()
return s[::2]
def solve_b():
p, f = get_ints()
cnt_s, cnt_w = get_ints()
s, w = get_ints()
if s > w:
s, w = w, s
cnt_s, cnt_w = cnt_w, cnt_s
best = 0
for swords in range(cnt_s + 1):
curr = 0
p_copy, f_copy = p, f
cnt_s_copy, cnt_w_copy = cnt_s, cnt_w
if swords * s > p:
break
p_copy -= s * swords
cnt_s_copy -= swords
curr += swords
axes = min(cnt_w_copy, p_copy // w)
cnt_w_copy -= axes
curr += axes
p_copy -= w * axes
swords2 = min(cnt_s_copy, f_copy // s)
cnt_s_copy -= swords2
curr += swords2
f_copy -= s * swords2
axes2 = min(cnt_w_copy, f_copy // w)
cnt_w_copy -= axes2
curr += axes2
f_copy -= w * axes2
best = max(curr, best)
return best
def solve_c():
s = get_str()
n = len(s)
x = get_int()
w = ['1'] * n
for i in range(n):
if s[i] == '0':
if i >= x:
w[i - x] = '0'
if i + x < n:
w[i + x] = '0'
for i in range(n):
if s[i] == '1':
good = False
if i >= x:
if w[i - x] == '1':
good = True
if i + x < n:
if w[i + x] == '1':
good = True
if not good:
return -1
return ''.join(w)
t = get_int()
for _ in range(t):
print(solve_b())
``` | instruction | 0 | 66,631 | 2 | 133,262 |
Yes | output | 1 | 66,631 | 2 | 133,263 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are playing one RPG from the 2010s. You are planning to raise your smithing skill, so you need as many resources as possible. So how to get resources? By stealing, of course.
You decided to rob a town's blacksmith and you take a follower with you. You can carry at most p units and your follower โ at most f units.
In the blacksmith shop, you found cnt_s swords and cnt_w war axes. Each sword weights s units and each war axe โ w units. You don't care what to take, since each of them will melt into one steel ingot.
What is the maximum number of weapons (both swords and war axes) you and your follower can carry out from the shop?
Input
The first line contains a single integer t (1 โค t โค 10^4) โ the number of test cases.
The first line of each test case contains two integers p and f (1 โค p, f โค 10^9) โ yours and your follower's capacities.
The second line of each test case contains two integers cnt_s and cnt_w (1 โค cnt_s, cnt_w โค 2 โ
10^5) โ the number of swords and war axes in the shop.
The third line of each test case contains two integers s and w (1 โค s, w โค 10^9) โ the weights of each sword and each war axe.
It's guaranteed that the total number of swords and the total number of war axes in all test cases don't exceed 2 โ
10^5.
Output
For each test case, print the maximum number of weapons (both swords and war axes) you and your follower can carry.
Example
Input
3
33 27
6 10
5 6
100 200
10 10
5 5
1 19
1 3
19 5
Output
11
20
3
Note
In the first test case:
* you should take 3 swords and 3 war axes: 3 โ
5 + 3 โ
6 = 33 โค 33
* and your follower โ 3 swords and 2 war axes: 3 โ
5 + 2 โ
6 = 27 โค 27.
3 + 3 + 3 + 2 = 11 weapons in total.
In the second test case, you can take all available weapons even without your follower's help, since 5 โ
10 + 5 โ
10 โค 100.
In the third test case, you can't take anything, but your follower can take 3 war axes: 3 โ
5 โค 19.
Submitted Solution:
```
# -*- coding: utf-8 -*-
"""
Created on Thu Aug 20 23:24:39 2020
@author: Syed Ishtiyaq Ahmed
"""
t=int(input())
answers=[]
for i in range(t):
p,f=map(int,input().split())
cnts,cntw=map(int,input().split())
s,w=map(int,input().split())
total=p+f
count=0
weight_check=0
if s<w and s<total and w<total:
while(count<cnts and weight_check<total):
count+=1
weight_check+=s
if s>(total-weight_check):
break
if weight_check<total and w<=(total-weight_check):
while(count<(cnts+cntw) and weight_check<total):
count+=1
weight_check+=w
if w>(total-weight_check):
break
elif w<s and s<total and w<total:
while(count<cntw and weight_check<total):
weight_check+=w
count+=1
if w>(total-weight_check):
break
if weight_check<total and s<=(total-weight_check):
while(count<(cnts+cntw) and weight_check<total):
count+=1
weight_check+=s
if s>(total-weight_check):
break
elif w==s and s<total and w<total:
while(count<(cnts+cntw) and weight_check<total):
count+=1
weight_check+=s
if s>(total-weight_check):
break
answers.append(count)
for i in answers:
print(i)
``` | instruction | 0 | 66,632 | 2 | 133,264 |
No | output | 1 | 66,632 | 2 | 133,265 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are playing one RPG from the 2010s. You are planning to raise your smithing skill, so you need as many resources as possible. So how to get resources? By stealing, of course.
You decided to rob a town's blacksmith and you take a follower with you. You can carry at most p units and your follower โ at most f units.
In the blacksmith shop, you found cnt_s swords and cnt_w war axes. Each sword weights s units and each war axe โ w units. You don't care what to take, since each of them will melt into one steel ingot.
What is the maximum number of weapons (both swords and war axes) you and your follower can carry out from the shop?
Input
The first line contains a single integer t (1 โค t โค 10^4) โ the number of test cases.
The first line of each test case contains two integers p and f (1 โค p, f โค 10^9) โ yours and your follower's capacities.
The second line of each test case contains two integers cnt_s and cnt_w (1 โค cnt_s, cnt_w โค 2 โ
10^5) โ the number of swords and war axes in the shop.
The third line of each test case contains two integers s and w (1 โค s, w โค 10^9) โ the weights of each sword and each war axe.
It's guaranteed that the total number of swords and the total number of war axes in all test cases don't exceed 2 โ
10^5.
Output
For each test case, print the maximum number of weapons (both swords and war axes) you and your follower can carry.
Example
Input
3
33 27
6 10
5 6
100 200
10 10
5 5
1 19
1 3
19 5
Output
11
20
3
Note
In the first test case:
* you should take 3 swords and 3 war axes: 3 โ
5 + 3 โ
6 = 33 โค 33
* and your follower โ 3 swords and 2 war axes: 3 โ
5 + 2 โ
6 = 27 โค 27.
3 + 3 + 3 + 2 = 11 weapons in total.
In the second test case, you can take all available weapons even without your follower's help, since 5 โ
10 + 5 โ
10 โค 100.
In the third test case, you can't take anything, but your follower can take 3 war axes: 3 โ
5 โค 19.
Submitted Solution:
```
#Code by Sounak, IIESTS
#------------------------------warmup----------------------------
import os
import sys
import math
from io import BytesIO, IOBase
from fractions import Fraction
import collections
from itertools import permutations
from collections import defaultdict
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
#-------------------game starts now-----------------------------------------------------
for _ in range (int(input())):
p,f=map(int,input().split())
cs,cw=map(int,input().split())
s,w=map(int,input().split())
copy1,copy2=cs,cw
if s<w:
s,w=w,s
cs,cw=cw,cs
copy1,copy2=cs,cw
m1=p//w
m1=min(m1,cw)
cw-=m1
p-=m1*w
m2=p//s
m2=min(m2,cs)
cs-=m2
m=m1+m2
m1=f//w
m1=min(m1,cw)
cw-=m1
f-=m1*w
m2=f//s
m2=min(m2,cs)
cs-=m2
m+=m1+m2
mx=m
cs,cw=copy1,copy2
m1=f//w
m1=min(m1,cw)
cw-=m1
f-=m1*w
m2=f//s
m2=min(m2,cs)
cs-=m2
m=m1+m2
m1=p//w
m1=min(m1,cw)
cw-=m1
p-=m1*w
m2=p//s
m2=min(m2,cs)
cs-=m2
m+=m1+m2
mx=max(mx,m)
print(mx)
``` | instruction | 0 | 66,633 | 2 | 133,266 |
No | output | 1 | 66,633 | 2 | 133,267 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are playing one RPG from the 2010s. You are planning to raise your smithing skill, so you need as many resources as possible. So how to get resources? By stealing, of course.
You decided to rob a town's blacksmith and you take a follower with you. You can carry at most p units and your follower โ at most f units.
In the blacksmith shop, you found cnt_s swords and cnt_w war axes. Each sword weights s units and each war axe โ w units. You don't care what to take, since each of them will melt into one steel ingot.
What is the maximum number of weapons (both swords and war axes) you and your follower can carry out from the shop?
Input
The first line contains a single integer t (1 โค t โค 10^4) โ the number of test cases.
The first line of each test case contains two integers p and f (1 โค p, f โค 10^9) โ yours and your follower's capacities.
The second line of each test case contains two integers cnt_s and cnt_w (1 โค cnt_s, cnt_w โค 2 โ
10^5) โ the number of swords and war axes in the shop.
The third line of each test case contains two integers s and w (1 โค s, w โค 10^9) โ the weights of each sword and each war axe.
It's guaranteed that the total number of swords and the total number of war axes in all test cases don't exceed 2 โ
10^5.
Output
For each test case, print the maximum number of weapons (both swords and war axes) you and your follower can carry.
Example
Input
3
33 27
6 10
5 6
100 200
10 10
5 5
1 19
1 3
19 5
Output
11
20
3
Note
In the first test case:
* you should take 3 swords and 3 war axes: 3 โ
5 + 3 โ
6 = 33 โค 33
* and your follower โ 3 swords and 2 war axes: 3 โ
5 + 2 โ
6 = 27 โค 27.
3 + 3 + 3 + 2 = 11 weapons in total.
In the second test case, you can take all available weapons even without your follower's help, since 5 โ
10 + 5 โ
10 โค 100.
In the third test case, you can't take anything, but your follower can take 3 war axes: 3 โ
5 โค 19.
Submitted Solution:
```
def take_item(p, f, s_n, a_n, s_w, a_w):
item_taken = 0
axe = min(p // a_w, a_n)
a_n -= axe
item_taken += axe
if a_w <= s_w:
axe = min(f // a_w, a_n)
f -= axe * a_w
sword = min (f // s_w, s_n)
item_taken += sword + axe
else:
sword = min (f // s_w, s_n)
f -= sword * s_w
axe = min(f // a_w, a_n)
item_taken += sword + axe
return item_taken
for _ in range(int(input())):
p, f = [int(x) for x in input().split()] # p1 + p2 cap
s_n, a_n = [int(x) for x in input().split()] # sword + axe num
s_w, a_w = [int(x) for x in input().split()] # sword + axe weight
res = 0
for i in range(s_n + 1):
tmp = i # took i swords
p1 = p - i * s_w
s_n_1 = s_n - i
tmp += take_item(p1, f, s_n_1, a_n, s_w, a_w)
res = max(res, tmp)
if tmp == 12: print(f'i:{i}')
print(res)
``` | instruction | 0 | 66,634 | 2 | 133,268 |
No | output | 1 | 66,634 | 2 | 133,269 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are playing one RPG from the 2010s. You are planning to raise your smithing skill, so you need as many resources as possible. So how to get resources? By stealing, of course.
You decided to rob a town's blacksmith and you take a follower with you. You can carry at most p units and your follower โ at most f units.
In the blacksmith shop, you found cnt_s swords and cnt_w war axes. Each sword weights s units and each war axe โ w units. You don't care what to take, since each of them will melt into one steel ingot.
What is the maximum number of weapons (both swords and war axes) you and your follower can carry out from the shop?
Input
The first line contains a single integer t (1 โค t โค 10^4) โ the number of test cases.
The first line of each test case contains two integers p and f (1 โค p, f โค 10^9) โ yours and your follower's capacities.
The second line of each test case contains two integers cnt_s and cnt_w (1 โค cnt_s, cnt_w โค 2 โ
10^5) โ the number of swords and war axes in the shop.
The third line of each test case contains two integers s and w (1 โค s, w โค 10^9) โ the weights of each sword and each war axe.
It's guaranteed that the total number of swords and the total number of war axes in all test cases don't exceed 2 โ
10^5.
Output
For each test case, print the maximum number of weapons (both swords and war axes) you and your follower can carry.
Example
Input
3
33 27
6 10
5 6
100 200
10 10
5 5
1 19
1 3
19 5
Output
11
20
3
Note
In the first test case:
* you should take 3 swords and 3 war axes: 3 โ
5 + 3 โ
6 = 33 โค 33
* and your follower โ 3 swords and 2 war axes: 3 โ
5 + 2 โ
6 = 27 โค 27.
3 + 3 + 3 + 2 = 11 weapons in total.
In the second test case, you can take all available weapons even without your follower's help, since 5 โ
10 + 5 โ
10 โค 100.
In the third test case, you can't take anything, but your follower can take 3 war axes: 3 โ
5 โค 19.
Submitted Solution:
```
from sys import stdin, stdout
t=int(stdin.readline())
for _ in range(t):
p,f=map(int,input().split())
ns,na=map(int,input().split())
sw,aw=map(int,input().split())
total=0
if p<f:
t=p
p=f
f=t
if sw>aw:
t=aw
aw=sw
sw=t
t=ns
ns=na
na=t
for i in range(1,ns+1):
if i*sw>p:
continue
pa=min((p-i*sw)//aw,na)
fs=min(f//sw,ns-i)
fa=min((f-fs*sw)//aw,na-pa)
t=i+pa+fs+fa
if t>total:
total=t
print(total)
``` | instruction | 0 | 66,635 | 2 | 133,270 |
No | output | 1 | 66,635 | 2 | 133,271 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It's now 260 AD. Shapur, being extremely smart, became the King of Persia. He is now called Shapur, His majesty King of kings of Iran and Aniran.
Recently the Romans declared war on Persia. They dreamed to occupy Armenia. In the recent war, the Romans were badly defeated. Now their senior army general, Philip is captured by Shapur and Shapur is now going to capture Valerian, the Roman emperor.
Being defeated, the cowardly Valerian hid in a room at the top of one of his castles. To capture him, Shapur has to open many doors. Fortunately Valerian was too scared to make impenetrable locks for the doors.
Each door has 4 parts. The first part is an integer number a. The second part is either an integer number b or some really odd sign which looks like R. The third one is an integer c and the fourth part is empty! As if it was laid for writing something. Being extremely gifted, after opening the first few doors, Shapur found out the secret behind the locks.
c is an integer written in base a, to open the door we should write it in base b. The only bad news is that this R is some sort of special numbering system that is used only in Roman empire, so opening the doors is not just a piece of cake!
Here's an explanation of this really weird number system that even doesn't have zero:
Roman numerals are based on seven symbols: a stroke (identified with the letter I) for a unit, a chevron (identified with the letter V) for a five, a cross-stroke (identified with the letter X) for a ten, a C (identified as an abbreviation of Centum) for a hundred, etc.:
* I=1
* V=5
* X=10
* L=50
* C=100
* D=500
* M=1000
Symbols are iterated to produce multiples of the decimal (1, 10, 100, 1, 000) values, with V, L, D substituted for a multiple of five, and the iteration continuing: I 1, II 2, III 3, V 5, VI 6, VII 7, etc., and the same for other bases: X 10, XX 20, XXX 30, L 50, LXXX 80; CC 200, DCC 700, etc. At the fourth and ninth iteration, a subtractive principle must be employed, with the base placed before the higher base: IV 4, IX 9, XL 40, XC 90, CD 400, CM 900.
Also in bases greater than 10 we use A for 10, B for 11, etc.
Help Shapur capture Valerian and bring peace back to Persia, especially Armenia.
Input
The first line contains two integers a and b (2 โค a, b โค 25). Only b may be replaced by an R which indicates Roman numbering system.
The next line contains a single non-negative integer c in base a which may contain leading zeros but its length doesn't exceed 103.
It is guaranteed that if we have Roman numerals included the number would be less than or equal to 300010 and it won't be 0. In any other case the number won't be greater than 101510.
Output
Write a single line that contains integer c in base b. You must omit leading zeros.
Examples
Input
10 2
1
Output
1
Input
16 R
5
Output
V
Input
5 R
4
Output
IV
Input
2 2
1111001
Output
1111001
Input
12 13
A
Output
A
Note
You can find more information about roman numerals here: http://en.wikipedia.org/wiki/Roman_numerals | instruction | 0 | 66,832 | 2 | 133,664 |
Tags: math
Correct Solution:
```
from collections import OrderedDict
def romanConverter(num):
roman = OrderedDict()
roman[1000] = "M"
roman[900] = "CM"
roman[500] = "D"
roman[400] = "CD"
roman[100] = "C"
roman[90] = "XC"
roman[50] = "L"
roman[40] = "XL"
roman[10] = "X"
roman[9] = "IX"
roman[5] = "V"
roman[4] = "IV"
roman[1] = "I"
def roman_num(num):
for r in roman.keys():
x, y = divmod(num, r)
yield roman[r] * x
num -= (r * x)
if num > 0:
roman_num(num)
else:
break
return "".join([a for a in roman_num(num)])
pass
def int2base(x, base):
digs = []
if x == 0:
return x
while x:
if x%base < 10:
digs.append(str(x % base))
else:
digs.append( chr( ord('A') + (x % base) - 10 ) )
x //= base
digs.reverse()
return ''.join(digs)
def function():
c = input()
a, b = int(c[:c.find(' ')]), c[c.find(' ')+1:]
c = input()
c = int( c, base = int(a))
if b == 'R':
c = romanConverter(c)
else:
c = int2base(c, int(b))
return c
pass
#-------------main calls ---------------------------------
print(function())
``` | output | 1 | 66,832 | 2 | 133,665 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It's now 260 AD. Shapur, being extremely smart, became the King of Persia. He is now called Shapur, His majesty King of kings of Iran and Aniran.
Recently the Romans declared war on Persia. They dreamed to occupy Armenia. In the recent war, the Romans were badly defeated. Now their senior army general, Philip is captured by Shapur and Shapur is now going to capture Valerian, the Roman emperor.
Being defeated, the cowardly Valerian hid in a room at the top of one of his castles. To capture him, Shapur has to open many doors. Fortunately Valerian was too scared to make impenetrable locks for the doors.
Each door has 4 parts. The first part is an integer number a. The second part is either an integer number b or some really odd sign which looks like R. The third one is an integer c and the fourth part is empty! As if it was laid for writing something. Being extremely gifted, after opening the first few doors, Shapur found out the secret behind the locks.
c is an integer written in base a, to open the door we should write it in base b. The only bad news is that this R is some sort of special numbering system that is used only in Roman empire, so opening the doors is not just a piece of cake!
Here's an explanation of this really weird number system that even doesn't have zero:
Roman numerals are based on seven symbols: a stroke (identified with the letter I) for a unit, a chevron (identified with the letter V) for a five, a cross-stroke (identified with the letter X) for a ten, a C (identified as an abbreviation of Centum) for a hundred, etc.:
* I=1
* V=5
* X=10
* L=50
* C=100
* D=500
* M=1000
Symbols are iterated to produce multiples of the decimal (1, 10, 100, 1, 000) values, with V, L, D substituted for a multiple of five, and the iteration continuing: I 1, II 2, III 3, V 5, VI 6, VII 7, etc., and the same for other bases: X 10, XX 20, XXX 30, L 50, LXXX 80; CC 200, DCC 700, etc. At the fourth and ninth iteration, a subtractive principle must be employed, with the base placed before the higher base: IV 4, IX 9, XL 40, XC 90, CD 400, CM 900.
Also in bases greater than 10 we use A for 10, B for 11, etc.
Help Shapur capture Valerian and bring peace back to Persia, especially Armenia.
Input
The first line contains two integers a and b (2 โค a, b โค 25). Only b may be replaced by an R which indicates Roman numbering system.
The next line contains a single non-negative integer c in base a which may contain leading zeros but its length doesn't exceed 103.
It is guaranteed that if we have Roman numerals included the number would be less than or equal to 300010 and it won't be 0. In any other case the number won't be greater than 101510.
Output
Write a single line that contains integer c in base b. You must omit leading zeros.
Examples
Input
10 2
1
Output
1
Input
16 R
5
Output
V
Input
5 R
4
Output
IV
Input
2 2
1111001
Output
1111001
Input
12 13
A
Output
A
Note
You can find more information about roman numerals here: http://en.wikipedia.org/wiki/Roman_numerals | instruction | 0 | 66,833 | 2 | 133,666 |
Tags: math
Correct Solution:
```
digs = [chr(c) for c in range(ord('0'),ord('9')+1)]
digs += [chr(c) for c in range(ord('A'),ord('Z')+1)]
def int2base(x, base):
if x < 0: sign = -1
elif x == 0: return digs[0]
else: sign = 1
x *= sign
digits = []
while x:
digits.append(digs[x % base])
x //= base
if sign < 0:
digits.append('-')
digits.reverse()
return ''.join(digits)
def int2roman(x):
ints = (1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1)
nums = ('M', 'CM', 'D', 'CD','C', 'XC','L','XL','X','IX','V','IV','I')
result = ""
for i in range(len(ints)):
count = int(x / ints[i])
result += nums[i] * count
x -= ints[i] * count
return result
x = input().split()
a = int(x[0])
roman = False
b = x[1]
if b[0] == 'R':
roman = True
else:
b = int(b)
na = int(input(),a)
if roman :
print(int2roman(na))
else:
print(int2base(na,b))
# Made By Mostafa_Khaled
``` | output | 1 | 66,833 | 2 | 133,667 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It's now 260 AD. Shapur, being extremely smart, became the King of Persia. He is now called Shapur, His majesty King of kings of Iran and Aniran.
Recently the Romans declared war on Persia. They dreamed to occupy Armenia. In the recent war, the Romans were badly defeated. Now their senior army general, Philip is captured by Shapur and Shapur is now going to capture Valerian, the Roman emperor.
Being defeated, the cowardly Valerian hid in a room at the top of one of his castles. To capture him, Shapur has to open many doors. Fortunately Valerian was too scared to make impenetrable locks for the doors.
Each door has 4 parts. The first part is an integer number a. The second part is either an integer number b or some really odd sign which looks like R. The third one is an integer c and the fourth part is empty! As if it was laid for writing something. Being extremely gifted, after opening the first few doors, Shapur found out the secret behind the locks.
c is an integer written in base a, to open the door we should write it in base b. The only bad news is that this R is some sort of special numbering system that is used only in Roman empire, so opening the doors is not just a piece of cake!
Here's an explanation of this really weird number system that even doesn't have zero:
Roman numerals are based on seven symbols: a stroke (identified with the letter I) for a unit, a chevron (identified with the letter V) for a five, a cross-stroke (identified with the letter X) for a ten, a C (identified as an abbreviation of Centum) for a hundred, etc.:
* I=1
* V=5
* X=10
* L=50
* C=100
* D=500
* M=1000
Symbols are iterated to produce multiples of the decimal (1, 10, 100, 1, 000) values, with V, L, D substituted for a multiple of five, and the iteration continuing: I 1, II 2, III 3, V 5, VI 6, VII 7, etc., and the same for other bases: X 10, XX 20, XXX 30, L 50, LXXX 80; CC 200, DCC 700, etc. At the fourth and ninth iteration, a subtractive principle must be employed, with the base placed before the higher base: IV 4, IX 9, XL 40, XC 90, CD 400, CM 900.
Also in bases greater than 10 we use A for 10, B for 11, etc.
Help Shapur capture Valerian and bring peace back to Persia, especially Armenia.
Input
The first line contains two integers a and b (2 โค a, b โค 25). Only b may be replaced by an R which indicates Roman numbering system.
The next line contains a single non-negative integer c in base a which may contain leading zeros but its length doesn't exceed 103.
It is guaranteed that if we have Roman numerals included the number would be less than or equal to 300010 and it won't be 0. In any other case the number won't be greater than 101510.
Output
Write a single line that contains integer c in base b. You must omit leading zeros.
Examples
Input
10 2
1
Output
1
Input
16 R
5
Output
V
Input
5 R
4
Output
IV
Input
2 2
1111001
Output
1111001
Input
12 13
A
Output
A
Note
You can find more information about roman numerals here: http://en.wikipedia.org/wiki/Roman_numerals | instruction | 0 | 66,834 | 2 | 133,668 |
Tags: math
Correct Solution:
```
ab = input().split()
alphabet = ['A', 'B','C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']
try:
a = int(ab[0])
except TypeError:
a = alphabet.index(ab[0])+10
b = ab[1]
if b!='R':
b = int(b)
c = input()
c2 = ''
found = False
for i in c:
if i!='0':
found = True
if found:
c2+=i
c = c2
result = 0
for i in range(len(c)):
try:
result+=int(c[i])*(a**(len(c)-i-1))
except ValueError:
result+=(alphabet.index(c[i])+10)*(a**(len(c)-i-1))
strresult = ''
if c=='':
strresult=0
elif b!='R':
while result!=0:
if result%b<10:
strresult = str(result%b) + strresult
else:
strresult = alphabet[result%b-10] + strresult
result = result//b
else:
while result!=0:
if result>=1000:
strresult+='M'
result-=1000
elif result>=900:
strresult+='CM'
result-=900
elif result>=500:
strresult+='D'
result-=500
elif result>=400:
strresult+='CD'
result-=400
elif result>=100:
strresult+='C'
result-=100
elif result>=90:
strresult+='XC'
result-=90
elif result>=50:
strresult+='L'
result-=50
elif result>=40:
strresult+='XL'
result-=40
elif result>=10:
strresult+='X'
result-=10
elif result>=9:
strresult+='IX'
result-=9
elif result>=5:
strresult+='V'
result-=5
elif result>=4:
strresult+='IV'
result-=4
else:
strresult+='I'
result-=1
print(strresult)
``` | output | 1 | 66,834 | 2 | 133,669 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It's now 260 AD. Shapur, being extremely smart, became the King of Persia. He is now called Shapur, His majesty King of kings of Iran and Aniran.
Recently the Romans declared war on Persia. They dreamed to occupy Armenia. In the recent war, the Romans were badly defeated. Now their senior army general, Philip is captured by Shapur and Shapur is now going to capture Valerian, the Roman emperor.
Being defeated, the cowardly Valerian hid in a room at the top of one of his castles. To capture him, Shapur has to open many doors. Fortunately Valerian was too scared to make impenetrable locks for the doors.
Each door has 4 parts. The first part is an integer number a. The second part is either an integer number b or some really odd sign which looks like R. The third one is an integer c and the fourth part is empty! As if it was laid for writing something. Being extremely gifted, after opening the first few doors, Shapur found out the secret behind the locks.
c is an integer written in base a, to open the door we should write it in base b. The only bad news is that this R is some sort of special numbering system that is used only in Roman empire, so opening the doors is not just a piece of cake!
Here's an explanation of this really weird number system that even doesn't have zero:
Roman numerals are based on seven symbols: a stroke (identified with the letter I) for a unit, a chevron (identified with the letter V) for a five, a cross-stroke (identified with the letter X) for a ten, a C (identified as an abbreviation of Centum) for a hundred, etc.:
* I=1
* V=5
* X=10
* L=50
* C=100
* D=500
* M=1000
Symbols are iterated to produce multiples of the decimal (1, 10, 100, 1, 000) values, with V, L, D substituted for a multiple of five, and the iteration continuing: I 1, II 2, III 3, V 5, VI 6, VII 7, etc., and the same for other bases: X 10, XX 20, XXX 30, L 50, LXXX 80; CC 200, DCC 700, etc. At the fourth and ninth iteration, a subtractive principle must be employed, with the base placed before the higher base: IV 4, IX 9, XL 40, XC 90, CD 400, CM 900.
Also in bases greater than 10 we use A for 10, B for 11, etc.
Help Shapur capture Valerian and bring peace back to Persia, especially Armenia.
Input
The first line contains two integers a and b (2 โค a, b โค 25). Only b may be replaced by an R which indicates Roman numbering system.
The next line contains a single non-negative integer c in base a which may contain leading zeros but its length doesn't exceed 103.
It is guaranteed that if we have Roman numerals included the number would be less than or equal to 300010 and it won't be 0. In any other case the number won't be greater than 101510.
Output
Write a single line that contains integer c in base b. You must omit leading zeros.
Examples
Input
10 2
1
Output
1
Input
16 R
5
Output
V
Input
5 R
4
Output
IV
Input
2 2
1111001
Output
1111001
Input
12 13
A
Output
A
Note
You can find more information about roman numerals here: http://en.wikipedia.org/wiki/Roman_numerals | instruction | 0 | 66,835 | 2 | 133,670 |
Tags: math
Correct Solution:
```
import sys
from array import array # noqa: F401
def input():
return sys.stdin.buffer.readline().decode('utf-8')
a, b = input().split()
a = int(a)
num = int(input().rstrip(), a)
if b != 'R':
b = int(b)
ans = []
while num:
rem = num % b
if rem >= 10:
ans.append(chr(65 + rem - 10))
else:
ans.append(str(rem))
num //= b
if not ans:
ans.append(0)
print(*ans[::-1], sep='')
else:
ans = []
ans.append('M' * (num // 1000))
num %= 1000
if num >= 500:
if num >= 900:
ans.append('CM')
num -= 900
else:
ans.append('D' + 'C' * ((num - 500) // 100))
num %= 100
if num >= 100:
if num >= 400:
ans.append('CD')
num -= 400
else:
ans.append('C' * (num // 100))
num %= 100
if num >= 50:
if num >= 90:
ans.append('XC')
num -= 90
else:
ans.append('L' + 'X' * ((num - 50) // 10))
num %= 10
if num >= 10:
if num >= 40:
ans.append('XL')
num -= 40
else:
ans.append('X' * (num // 10))
num %= 10
if num >= 5:
if num >= 9:
ans.append('IX')
num -= 9
else:
ans.append('V' + 'I' * (num - 5))
num = 0
if num > 0:
if num == 4:
ans.append('IV')
else:
ans.append('I' * num)
print(*ans, sep='')
``` | output | 1 | 66,835 | 2 | 133,671 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It's now 260 AD. Shapur, being extremely smart, became the King of Persia. He is now called Shapur, His majesty King of kings of Iran and Aniran.
Recently the Romans declared war on Persia. They dreamed to occupy Armenia. In the recent war, the Romans were badly defeated. Now their senior army general, Philip is captured by Shapur and Shapur is now going to capture Valerian, the Roman emperor.
Being defeated, the cowardly Valerian hid in a room at the top of one of his castles. To capture him, Shapur has to open many doors. Fortunately Valerian was too scared to make impenetrable locks for the doors.
Each door has 4 parts. The first part is an integer number a. The second part is either an integer number b or some really odd sign which looks like R. The third one is an integer c and the fourth part is empty! As if it was laid for writing something. Being extremely gifted, after opening the first few doors, Shapur found out the secret behind the locks.
c is an integer written in base a, to open the door we should write it in base b. The only bad news is that this R is some sort of special numbering system that is used only in Roman empire, so opening the doors is not just a piece of cake!
Here's an explanation of this really weird number system that even doesn't have zero:
Roman numerals are based on seven symbols: a stroke (identified with the letter I) for a unit, a chevron (identified with the letter V) for a five, a cross-stroke (identified with the letter X) for a ten, a C (identified as an abbreviation of Centum) for a hundred, etc.:
* I=1
* V=5
* X=10
* L=50
* C=100
* D=500
* M=1000
Symbols are iterated to produce multiples of the decimal (1, 10, 100, 1, 000) values, with V, L, D substituted for a multiple of five, and the iteration continuing: I 1, II 2, III 3, V 5, VI 6, VII 7, etc., and the same for other bases: X 10, XX 20, XXX 30, L 50, LXXX 80; CC 200, DCC 700, etc. At the fourth and ninth iteration, a subtractive principle must be employed, with the base placed before the higher base: IV 4, IX 9, XL 40, XC 90, CD 400, CM 900.
Also in bases greater than 10 we use A for 10, B for 11, etc.
Help Shapur capture Valerian and bring peace back to Persia, especially Armenia.
Input
The first line contains two integers a and b (2 โค a, b โค 25). Only b may be replaced by an R which indicates Roman numbering system.
The next line contains a single non-negative integer c in base a which may contain leading zeros but its length doesn't exceed 103.
It is guaranteed that if we have Roman numerals included the number would be less than or equal to 300010 and it won't be 0. In any other case the number won't be greater than 101510.
Output
Write a single line that contains integer c in base b. You must omit leading zeros.
Examples
Input
10 2
1
Output
1
Input
16 R
5
Output
V
Input
5 R
4
Output
IV
Input
2 2
1111001
Output
1111001
Input
12 13
A
Output
A
Note
You can find more information about roman numerals here: http://en.wikipedia.org/wiki/Roman_numerals | instruction | 0 | 66,836 | 2 | 133,672 |
Tags: math
Correct Solution:
```
import math
y = [i for i in input().split()]
a = int(y[0])
b = y[1]
c = input()
def btb(oldbase,newbase,num):
#return "?????????"
n = reversed(str(num))
s10 = 0
p = 0
#oldbase to base 10
for i in n:
d = ord(i)-48
if(d>=10): d=ord(i)-65+10
s10 += d * oldbase**p
p+=1
#print('D=',d,'s10=',s10)
if(newbase==100): return s10
#print("Base10",s10)
#base10 to newbase
n = s10
r = ""
if(n==0): r='0';
while(n>0):
d=n%newbase
if(d>=10):
d = chr(65+d-10)
r+=str(d)
n//=newbase
r = list(reversed(r))
return ''.join(r)
'''
print(btb(4,5,321))
print(btb(14,12,'A'))
print(btb(10,16,282))
print(btb(16,10,'11A'))
'''
roman = {1:'I',4:'IV',5:'V',9:'IX',10:'X',40:'XL',50:'L',90:'XC',100:'C',400:'CD'
,500:'D',900:'CM',1000:'M'}
roman = dict(reversed(list(roman.items())))
roman3 = {900:'CM',4:'IV',9:'IX',40:'XL',90:'XC',400:'CD',100:'C'
,500:'D',5:'V',1:'I',10:'X',50:'L',1000:'M'}
#print(roman)
def DTR(dec):
r=""
while(dec>0):
for k,v in roman.items():
#print(dec)
if(dec>=k):
r+=v*(dec//k)
dec%=k
return r
#print(DTR(3549))
def RTD(R):
s10 = 0
for k,v in roman3.items():
#print(R,s10,k,v)
if(R.count(v)>0):
s10+=R.count(v)*k
R = R.replace(v,'')
return s10
#print(RTD("MMMDXLIX"))
if(b=='R'):
#print(btb(a,100,c))
print(DTR(int(btb(a,100,c))))
else:
print(btb(a,int(b),c))
``` | output | 1 | 66,836 | 2 | 133,673 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It's now 260 AD. Shapur, being extremely smart, became the King of Persia. He is now called Shapur, His majesty King of kings of Iran and Aniran.
Recently the Romans declared war on Persia. They dreamed to occupy Armenia. In the recent war, the Romans were badly defeated. Now their senior army general, Philip is captured by Shapur and Shapur is now going to capture Valerian, the Roman emperor.
Being defeated, the cowardly Valerian hid in a room at the top of one of his castles. To capture him, Shapur has to open many doors. Fortunately Valerian was too scared to make impenetrable locks for the doors.
Each door has 4 parts. The first part is an integer number a. The second part is either an integer number b or some really odd sign which looks like R. The third one is an integer c and the fourth part is empty! As if it was laid for writing something. Being extremely gifted, after opening the first few doors, Shapur found out the secret behind the locks.
c is an integer written in base a, to open the door we should write it in base b. The only bad news is that this R is some sort of special numbering system that is used only in Roman empire, so opening the doors is not just a piece of cake!
Here's an explanation of this really weird number system that even doesn't have zero:
Roman numerals are based on seven symbols: a stroke (identified with the letter I) for a unit, a chevron (identified with the letter V) for a five, a cross-stroke (identified with the letter X) for a ten, a C (identified as an abbreviation of Centum) for a hundred, etc.:
* I=1
* V=5
* X=10
* L=50
* C=100
* D=500
* M=1000
Symbols are iterated to produce multiples of the decimal (1, 10, 100, 1, 000) values, with V, L, D substituted for a multiple of five, and the iteration continuing: I 1, II 2, III 3, V 5, VI 6, VII 7, etc., and the same for other bases: X 10, XX 20, XXX 30, L 50, LXXX 80; CC 200, DCC 700, etc. At the fourth and ninth iteration, a subtractive principle must be employed, with the base placed before the higher base: IV 4, IX 9, XL 40, XC 90, CD 400, CM 900.
Also in bases greater than 10 we use A for 10, B for 11, etc.
Help Shapur capture Valerian and bring peace back to Persia, especially Armenia.
Input
The first line contains two integers a and b (2 โค a, b โค 25). Only b may be replaced by an R which indicates Roman numbering system.
The next line contains a single non-negative integer c in base a which may contain leading zeros but its length doesn't exceed 103.
It is guaranteed that if we have Roman numerals included the number would be less than or equal to 300010 and it won't be 0. In any other case the number won't be greater than 101510.
Output
Write a single line that contains integer c in base b. You must omit leading zeros.
Examples
Input
10 2
1
Output
1
Input
16 R
5
Output
V
Input
5 R
4
Output
IV
Input
2 2
1111001
Output
1111001
Input
12 13
A
Output
A
Note
You can find more information about roman numerals here: http://en.wikipedia.org/wiki/Roman_numerals | instruction | 0 | 66,837 | 2 | 133,674 |
Tags: math
Correct Solution:
```
a, b = input().strip().split(' ')
c = input()
a = int(a)
def conv(num,b):
convStr = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ"
if num < b:
return convStr[num]
else:
return conv(num//b,b) + convStr[num % b]
def write_roman(num):
val = [
1000, 900, 500, 400,
100, 90, 50, 40,
10, 9, 5, 4,
1
]
syb = [
"M", "CM", "D", "CD",
"C", "XC", "L", "XL",
"X", "IX", "V", "IV",
"I"
]
roman_num = ''
i = 0
while num > 0:
for _ in range(num // val[i]):
roman_num += syb[i]
num -= val[i]
i += 1
return roman_num
t = int(c.lower(),a)
if b != 'R':
print(conv(t,int(b)))
else:
print(write_roman(t))
``` | output | 1 | 66,837 | 2 | 133,675 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It's now 260 AD. Shapur, being extremely smart, became the King of Persia. He is now called Shapur, His majesty King of kings of Iran and Aniran.
Recently the Romans declared war on Persia. They dreamed to occupy Armenia. In the recent war, the Romans were badly defeated. Now their senior army general, Philip is captured by Shapur and Shapur is now going to capture Valerian, the Roman emperor.
Being defeated, the cowardly Valerian hid in a room at the top of one of his castles. To capture him, Shapur has to open many doors. Fortunately Valerian was too scared to make impenetrable locks for the doors.
Each door has 4 parts. The first part is an integer number a. The second part is either an integer number b or some really odd sign which looks like R. The third one is an integer c and the fourth part is empty! As if it was laid for writing something. Being extremely gifted, after opening the first few doors, Shapur found out the secret behind the locks.
c is an integer written in base a, to open the door we should write it in base b. The only bad news is that this R is some sort of special numbering system that is used only in Roman empire, so opening the doors is not just a piece of cake!
Here's an explanation of this really weird number system that even doesn't have zero:
Roman numerals are based on seven symbols: a stroke (identified with the letter I) for a unit, a chevron (identified with the letter V) for a five, a cross-stroke (identified with the letter X) for a ten, a C (identified as an abbreviation of Centum) for a hundred, etc.:
* I=1
* V=5
* X=10
* L=50
* C=100
* D=500
* M=1000
Symbols are iterated to produce multiples of the decimal (1, 10, 100, 1, 000) values, with V, L, D substituted for a multiple of five, and the iteration continuing: I 1, II 2, III 3, V 5, VI 6, VII 7, etc., and the same for other bases: X 10, XX 20, XXX 30, L 50, LXXX 80; CC 200, DCC 700, etc. At the fourth and ninth iteration, a subtractive principle must be employed, with the base placed before the higher base: IV 4, IX 9, XL 40, XC 90, CD 400, CM 900.
Also in bases greater than 10 we use A for 10, B for 11, etc.
Help Shapur capture Valerian and bring peace back to Persia, especially Armenia.
Input
The first line contains two integers a and b (2 โค a, b โค 25). Only b may be replaced by an R which indicates Roman numbering system.
The next line contains a single non-negative integer c in base a which may contain leading zeros but its length doesn't exceed 103.
It is guaranteed that if we have Roman numerals included the number would be less than or equal to 300010 and it won't be 0. In any other case the number won't be greater than 101510.
Output
Write a single line that contains integer c in base b. You must omit leading zeros.
Examples
Input
10 2
1
Output
1
Input
16 R
5
Output
V
Input
5 R
4
Output
IV
Input
2 2
1111001
Output
1111001
Input
12 13
A
Output
A
Note
You can find more information about roman numerals here: http://en.wikipedia.org/wiki/Roman_numerals | instruction | 0 | 66,838 | 2 | 133,676 |
Tags: math
Correct Solution:
```
from sys import stdin, stdout
def first(number, pw):
cnt = 0
for i in range(len(number)):
if number[i] >= 'A':
cnt += (ord(number[i]) - 55) * (pw ** (len(number) - i - 1))
else:
cnt += int(number[i]) * (pw ** (len(number) - i - 1))
return cnt
def second(number, pw):
s = []
if number:
value = 1
else:
return '0'
cnt = 0
while value * pw <= number:
value *= pw
cnt += 1
while cnt >= 0:
for i in range(pw - 1, -1, -1):
if value * i <= number:
if i <= 9:
s.append(str(i))
else:
s.append(chr(65 + i - 10))
number -= value * i
value //= pw
cnt -= 1
break
return s
chouse1 = ['', 'I', 'II', 'III', 'IV', 'V', 'VI', 'VII', 'VIII', 'IX']
chouse10 = ['', 'X', 'XX', 'XXX', 'XL', 'L', 'LX', 'LXX', 'LXXX', 'XC']
chouse100 = ['', 'C', 'CC', 'CCC', 'CD', 'D', 'DC', 'DCC', 'DCCC', 'CM']
chouse1000 = ['', 'M', 'MM', 'MMM']
s = stdin.readline().split()
c = stdin.readline().strip()
if s[-1] != 'R':
a, b = map(int, s)
stdout.write(''.join(second(first(list(c), a), b)))
else:
a = int(s[0])
ans = ''
value = first(list(c), a)
if value >= 1000:
ans += chouse1000[value // 1000]
value %= 1000
if value >= 100:
ans += chouse100[value // 100]
value %= 100
if value >= 10:
ans += chouse10[value // 10]
value %= 10
if value >= 1:
ans += chouse1[value]
stdout.write(ans + '\n')
``` | output | 1 | 66,838 | 2 | 133,677 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It's now 260 AD. Shapur, being extremely smart, became the King of Persia. He is now called Shapur, His majesty King of kings of Iran and Aniran.
Recently the Romans declared war on Persia. They dreamed to occupy Armenia. In the recent war, the Romans were badly defeated. Now their senior army general, Philip is captured by Shapur and Shapur is now going to capture Valerian, the Roman emperor.
Being defeated, the cowardly Valerian hid in a room at the top of one of his castles. To capture him, Shapur has to open many doors. Fortunately Valerian was too scared to make impenetrable locks for the doors.
Each door has 4 parts. The first part is an integer number a. The second part is either an integer number b or some really odd sign which looks like R. The third one is an integer c and the fourth part is empty! As if it was laid for writing something. Being extremely gifted, after opening the first few doors, Shapur found out the secret behind the locks.
c is an integer written in base a, to open the door we should write it in base b. The only bad news is that this R is some sort of special numbering system that is used only in Roman empire, so opening the doors is not just a piece of cake!
Here's an explanation of this really weird number system that even doesn't have zero:
Roman numerals are based on seven symbols: a stroke (identified with the letter I) for a unit, a chevron (identified with the letter V) for a five, a cross-stroke (identified with the letter X) for a ten, a C (identified as an abbreviation of Centum) for a hundred, etc.:
* I=1
* V=5
* X=10
* L=50
* C=100
* D=500
* M=1000
Symbols are iterated to produce multiples of the decimal (1, 10, 100, 1, 000) values, with V, L, D substituted for a multiple of five, and the iteration continuing: I 1, II 2, III 3, V 5, VI 6, VII 7, etc., and the same for other bases: X 10, XX 20, XXX 30, L 50, LXXX 80; CC 200, DCC 700, etc. At the fourth and ninth iteration, a subtractive principle must be employed, with the base placed before the higher base: IV 4, IX 9, XL 40, XC 90, CD 400, CM 900.
Also in bases greater than 10 we use A for 10, B for 11, etc.
Help Shapur capture Valerian and bring peace back to Persia, especially Armenia.
Input
The first line contains two integers a and b (2 โค a, b โค 25). Only b may be replaced by an R which indicates Roman numbering system.
The next line contains a single non-negative integer c in base a which may contain leading zeros but its length doesn't exceed 103.
It is guaranteed that if we have Roman numerals included the number would be less than or equal to 300010 and it won't be 0. In any other case the number won't be greater than 101510.
Output
Write a single line that contains integer c in base b. You must omit leading zeros.
Examples
Input
10 2
1
Output
1
Input
16 R
5
Output
V
Input
5 R
4
Output
IV
Input
2 2
1111001
Output
1111001
Input
12 13
A
Output
A
Note
You can find more information about roman numerals here: http://en.wikipedia.org/wiki/Roman_numerals | instruction | 0 | 66,839 | 2 | 133,678 |
Tags: math
Correct Solution:
```
import string
digs = string.digits + string.ascii_uppercase
def int2base(x, base):
if x < 0:
sign = -1
elif x == 0:
return digs[0]
else:
sign = 1
x *= sign
digits = []
while x:
digits.append(digs[int(x % base)])
x = int(x / base)
if sign < 0:
digits.append('-')
digits.reverse()
return ''.join(digits)
a, b = input().split()
c = input()
R = {1:'I', 5:'V', 10:'X', 50:'L', 100:'C', 500:'D', 1000:'M'}
s = int(c, int(a))
if b != 'R':
print(int2base(s, int(b)))
else:
s = int(int2base(s, 10))
M = s//1000
s -= 1000 * M
C = s // 100
s -= 100 * C
X = s // 10
s -= 10 * X
I = s
r = ''
if M:
r+=M*'M'
if C:
if C <= 3: r+=C*'C'
elif C == 4: r+='CD'
elif C >= 5 and C < 9: r+='D'+'C'*(C - 5)
elif C == 9: r+='CM'
if X:
if X <= 3: r+=X*'X'
elif X == 4: r+='XL'
elif X >= 5 and X < 9: r+='L'+'X'*(X - 5)
elif X == 9: r+='XC'
if I:
if I <= 3: r+=I*'I'
elif I == 4: r+='IV'
elif I >= 5 and I < 9: r+='V'+'I'*(I - 5)
elif I == 9: r+='IX'
print(r)
``` | output | 1 | 66,839 | 2 | 133,679 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In a strategic computer game "Settlers II" one has to build defense structures to expand and protect the territory. Let's take one of these buildings. At the moment the defense structure accommodates exactly n soldiers. Within this task we can assume that the number of soldiers in the defense structure won't either increase or decrease.
Every soldier has a rank โ some natural number from 1 to k. 1 stands for a private and k stands for a general. The higher the rank of the soldier is, the better he fights. Therefore, the player profits from having the soldiers of the highest possible rank.
To increase the ranks of soldiers they need to train. But the soldiers won't train for free, and each training session requires one golden coin. On each training session all the n soldiers are present.
At the end of each training session the soldiers' ranks increase as follows. First all the soldiers are divided into groups with the same rank, so that the least possible number of groups is formed. Then, within each of the groups where the soldiers below the rank k are present, exactly one soldier increases his rank by one.
You know the ranks of all n soldiers at the moment. Determine the number of golden coins that are needed to increase the ranks of all the soldiers to the rank k.
Input
The first line contains two integers n and k (1 โค n, k โค 100). They represent the number of soldiers and the number of different ranks correspondingly. The second line contains n numbers in the non-decreasing order. The i-th of them, ai, represents the rank of the i-th soldier in the defense building (1 โค i โค n, 1 โค ai โค k).
Output
Print a single integer โ the number of golden coins needed to raise all the soldiers to the maximal rank.
Examples
Input
4 4
1 2 2 3
Output
4
Input
4 3
1 1 1 1
Output
5
Note
In the first example the ranks will be raised in the following manner:
1 2 2 3 โ 2 2 3 4 โ 2 3 4 4 โ 3 4 4 4 โ 4 4 4 4
Thus totals to 4 training sessions that require 4 golden coins.
Submitted Solution:
```
"""
Oh, Grantors of Dark Disgrace,
Do Not Wake Me Again.
"""
ii = lambda: int(input())
mi = lambda: map(int, input().split())
li = lambda: list(mi())
si = lambda: input()
n, k = mi()
l = li()
from collections import Counter
cc = Counter(l)
coins = 0
while cc[k] != n:
t = 0
for i in range(1, k):
if t+1 <= cc[i]:
cc[i] -= 1
cc[i+1] += 1
t = 1
else: t = 0
coins += 1
print(coins)
``` | instruction | 0 | 66,856 | 2 | 133,712 |
Yes | output | 1 | 66,856 | 2 | 133,713 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In a strategic computer game "Settlers II" one has to build defense structures to expand and protect the territory. Let's take one of these buildings. At the moment the defense structure accommodates exactly n soldiers. Within this task we can assume that the number of soldiers in the defense structure won't either increase or decrease.
Every soldier has a rank โ some natural number from 1 to k. 1 stands for a private and k stands for a general. The higher the rank of the soldier is, the better he fights. Therefore, the player profits from having the soldiers of the highest possible rank.
To increase the ranks of soldiers they need to train. But the soldiers won't train for free, and each training session requires one golden coin. On each training session all the n soldiers are present.
At the end of each training session the soldiers' ranks increase as follows. First all the soldiers are divided into groups with the same rank, so that the least possible number of groups is formed. Then, within each of the groups where the soldiers below the rank k are present, exactly one soldier increases his rank by one.
You know the ranks of all n soldiers at the moment. Determine the number of golden coins that are needed to increase the ranks of all the soldiers to the rank k.
Input
The first line contains two integers n and k (1 โค n, k โค 100). They represent the number of soldiers and the number of different ranks correspondingly. The second line contains n numbers in the non-decreasing order. The i-th of them, ai, represents the rank of the i-th soldier in the defense building (1 โค i โค n, 1 โค ai โค k).
Output
Print a single integer โ the number of golden coins needed to raise all the soldiers to the maximal rank.
Examples
Input
4 4
1 2 2 3
Output
4
Input
4 3
1 1 1 1
Output
5
Note
In the first example the ranks will be raised in the following manner:
1 2 2 3 โ 2 2 3 4 โ 2 3 4 4 โ 3 4 4 4 โ 4 4 4 4
Thus totals to 4 training sessions that require 4 golden coins.
Submitted Solution:
```
numSoldiers, maxRank = map(int, input().split())
ranks = list(map(int, input().split()))
count = 0
while True:
usedRank = set()
for i, rank in enumerate(ranks):
if rank == maxRank or rank in usedRank:
continue
ranks[i] += 1
usedRank.add(rank)
if len(usedRank) == 0:
break
count += 1
print(count)
``` | instruction | 0 | 66,858 | 2 | 133,716 |
Yes | output | 1 | 66,858 | 2 | 133,717 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In a strategic computer game "Settlers II" one has to build defense structures to expand and protect the territory. Let's take one of these buildings. At the moment the defense structure accommodates exactly n soldiers. Within this task we can assume that the number of soldiers in the defense structure won't either increase or decrease.
Every soldier has a rank โ some natural number from 1 to k. 1 stands for a private and k stands for a general. The higher the rank of the soldier is, the better he fights. Therefore, the player profits from having the soldiers of the highest possible rank.
To increase the ranks of soldiers they need to train. But the soldiers won't train for free, and each training session requires one golden coin. On each training session all the n soldiers are present.
At the end of each training session the soldiers' ranks increase as follows. First all the soldiers are divided into groups with the same rank, so that the least possible number of groups is formed. Then, within each of the groups where the soldiers below the rank k are present, exactly one soldier increases his rank by one.
You know the ranks of all n soldiers at the moment. Determine the number of golden coins that are needed to increase the ranks of all the soldiers to the rank k.
Input
The first line contains two integers n and k (1 โค n, k โค 100). They represent the number of soldiers and the number of different ranks correspondingly. The second line contains n numbers in the non-decreasing order. The i-th of them, ai, represents the rank of the i-th soldier in the defense building (1 โค i โค n, 1 โค ai โค k).
Output
Print a single integer โ the number of golden coins needed to raise all the soldiers to the maximal rank.
Examples
Input
4 4
1 2 2 3
Output
4
Input
4 3
1 1 1 1
Output
5
Note
In the first example the ranks will be raised in the following manner:
1 2 2 3 โ 2 2 3 4 โ 2 3 4 4 โ 3 4 4 4 โ 4 4 4 4
Thus totals to 4 training sessions that require 4 golden coins.
Submitted Solution:
```
"""
Oh, Grantors of Dark Disgrace,
Do Not Wake Me Again.
"""
from collections import Counter
n, k = map(int, input().split())
cc = Counter(map(int, input().split()))
coins = 0
while cc[k] != n:
t = 0
for i in range(1, k):
if t+1 <= cc[i]:
cc[i] -= 1
cc[i+1] += 1
t = 1
else:
t = 0
coins += 1
print(coins)
``` | instruction | 0 | 66,859 | 2 | 133,718 |
Yes | output | 1 | 66,859 | 2 | 133,719 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In a strategic computer game "Settlers II" one has to build defense structures to expand and protect the territory. Let's take one of these buildings. At the moment the defense structure accommodates exactly n soldiers. Within this task we can assume that the number of soldiers in the defense structure won't either increase or decrease.
Every soldier has a rank โ some natural number from 1 to k. 1 stands for a private and k stands for a general. The higher the rank of the soldier is, the better he fights. Therefore, the player profits from having the soldiers of the highest possible rank.
To increase the ranks of soldiers they need to train. But the soldiers won't train for free, and each training session requires one golden coin. On each training session all the n soldiers are present.
At the end of each training session the soldiers' ranks increase as follows. First all the soldiers are divided into groups with the same rank, so that the least possible number of groups is formed. Then, within each of the groups where the soldiers below the rank k are present, exactly one soldier increases his rank by one.
You know the ranks of all n soldiers at the moment. Determine the number of golden coins that are needed to increase the ranks of all the soldiers to the rank k.
Input
The first line contains two integers n and k (1 โค n, k โค 100). They represent the number of soldiers and the number of different ranks correspondingly. The second line contains n numbers in the non-decreasing order. The i-th of them, ai, represents the rank of the i-th soldier in the defense building (1 โค i โค n, 1 โค ai โค k).
Output
Print a single integer โ the number of golden coins needed to raise all the soldiers to the maximal rank.
Examples
Input
4 4
1 2 2 3
Output
4
Input
4 3
1 1 1 1
Output
5
Note
In the first example the ranks will be raised in the following manner:
1 2 2 3 โ 2 2 3 4 โ 2 3 4 4 โ 3 4 4 4 โ 4 4 4 4
Thus totals to 4 training sessions that require 4 golden coins.
Submitted Solution:
```
n,rank=list(map(int,input().split()))
arr=list(map(int,input().split()))
arr.sort()
i=0
while arr[-1]==rank :
arr.pop()
if arr==[]:
break
while arr!=[]:
for j in range(len(arr)):
if j==len(arr)-1:
arr[j]+=1
elif arr[j]!=arr[j+1]:
arr[j]+=1
else:
continue
if arr[-1]==rank:
arr.pop()
i+=1
print(arr)
print(i)
``` | instruction | 0 | 66,860 | 2 | 133,720 |
No | output | 1 | 66,860 | 2 | 133,721 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In a strategic computer game "Settlers II" one has to build defense structures to expand and protect the territory. Let's take one of these buildings. At the moment the defense structure accommodates exactly n soldiers. Within this task we can assume that the number of soldiers in the defense structure won't either increase or decrease.
Every soldier has a rank โ some natural number from 1 to k. 1 stands for a private and k stands for a general. The higher the rank of the soldier is, the better he fights. Therefore, the player profits from having the soldiers of the highest possible rank.
To increase the ranks of soldiers they need to train. But the soldiers won't train for free, and each training session requires one golden coin. On each training session all the n soldiers are present.
At the end of each training session the soldiers' ranks increase as follows. First all the soldiers are divided into groups with the same rank, so that the least possible number of groups is formed. Then, within each of the groups where the soldiers below the rank k are present, exactly one soldier increases his rank by one.
You know the ranks of all n soldiers at the moment. Determine the number of golden coins that are needed to increase the ranks of all the soldiers to the rank k.
Input
The first line contains two integers n and k (1 โค n, k โค 100). They represent the number of soldiers and the number of different ranks correspondingly. The second line contains n numbers in the non-decreasing order. The i-th of them, ai, represents the rank of the i-th soldier in the defense building (1 โค i โค n, 1 โค ai โค k).
Output
Print a single integer โ the number of golden coins needed to raise all the soldiers to the maximal rank.
Examples
Input
4 4
1 2 2 3
Output
4
Input
4 3
1 1 1 1
Output
5
Note
In the first example the ranks will be raised in the following manner:
1 2 2 3 โ 2 2 3 4 โ 2 3 4 4 โ 3 4 4 4 โ 4 4 4 4
Thus totals to 4 training sessions that require 4 golden coins.
Submitted Solution:
```
import sys
import math
n, k = [int(x) for x in (sys.stdin.readline()).split()]
ai = [int(x) for x in (sys.stdin.readline()).split()]
z = n
res = 0
while(z > 0):
i = 0
res += 1
while(i < z):
if(ai[i] == k):
z = i - 1
break
else:
v = ai[i]
j = i
while(j < z):
if(v != ai[j]):
break
j += 1
i = j
ai[j - 1] += 1
print(res)
``` | instruction | 0 | 66,861 | 2 | 133,722 |
No | output | 1 | 66,861 | 2 | 133,723 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In a strategic computer game "Settlers II" one has to build defense structures to expand and protect the territory. Let's take one of these buildings. At the moment the defense structure accommodates exactly n soldiers. Within this task we can assume that the number of soldiers in the defense structure won't either increase or decrease.
Every soldier has a rank โ some natural number from 1 to k. 1 stands for a private and k stands for a general. The higher the rank of the soldier is, the better he fights. Therefore, the player profits from having the soldiers of the highest possible rank.
To increase the ranks of soldiers they need to train. But the soldiers won't train for free, and each training session requires one golden coin. On each training session all the n soldiers are present.
At the end of each training session the soldiers' ranks increase as follows. First all the soldiers are divided into groups with the same rank, so that the least possible number of groups is formed. Then, within each of the groups where the soldiers below the rank k are present, exactly one soldier increases his rank by one.
You know the ranks of all n soldiers at the moment. Determine the number of golden coins that are needed to increase the ranks of all the soldiers to the rank k.
Input
The first line contains two integers n and k (1 โค n, k โค 100). They represent the number of soldiers and the number of different ranks correspondingly. The second line contains n numbers in the non-decreasing order. The i-th of them, ai, represents the rank of the i-th soldier in the defense building (1 โค i โค n, 1 โค ai โค k).
Output
Print a single integer โ the number of golden coins needed to raise all the soldiers to the maximal rank.
Examples
Input
4 4
1 2 2 3
Output
4
Input
4 3
1 1 1 1
Output
5
Note
In the first example the ranks will be raised in the following manner:
1 2 2 3 โ 2 2 3 4 โ 2 3 4 4 โ 3 4 4 4 โ 4 4 4 4
Thus totals to 4 training sessions that require 4 golden coins.
Submitted Solution:
```
n, k = map(int, input().split())
t = list(map(int, input().split()))
p = [0] * (k + 1)
for i in t:
p[i] += 1
j = 1
while p[j] == 0: j += 1
print(sum(p[i] for i in range(j, k)) + p[j: k].count(0))
``` | instruction | 0 | 66,862 | 2 | 133,724 |
No | output | 1 | 66,862 | 2 | 133,725 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In a strategic computer game "Settlers II" one has to build defense structures to expand and protect the territory. Let's take one of these buildings. At the moment the defense structure accommodates exactly n soldiers. Within this task we can assume that the number of soldiers in the defense structure won't either increase or decrease.
Every soldier has a rank โ some natural number from 1 to k. 1 stands for a private and k stands for a general. The higher the rank of the soldier is, the better he fights. Therefore, the player profits from having the soldiers of the highest possible rank.
To increase the ranks of soldiers they need to train. But the soldiers won't train for free, and each training session requires one golden coin. On each training session all the n soldiers are present.
At the end of each training session the soldiers' ranks increase as follows. First all the soldiers are divided into groups with the same rank, so that the least possible number of groups is formed. Then, within each of the groups where the soldiers below the rank k are present, exactly one soldier increases his rank by one.
You know the ranks of all n soldiers at the moment. Determine the number of golden coins that are needed to increase the ranks of all the soldiers to the rank k.
Input
The first line contains two integers n and k (1 โค n, k โค 100). They represent the number of soldiers and the number of different ranks correspondingly. The second line contains n numbers in the non-decreasing order. The i-th of them, ai, represents the rank of the i-th soldier in the defense building (1 โค i โค n, 1 โค ai โค k).
Output
Print a single integer โ the number of golden coins needed to raise all the soldiers to the maximal rank.
Examples
Input
4 4
1 2 2 3
Output
4
Input
4 3
1 1 1 1
Output
5
Note
In the first example the ranks will be raised in the following manner:
1 2 2 3 โ 2 2 3 4 โ 2 3 4 4 โ 3 4 4 4 โ 4 4 4 4
Thus totals to 4 training sessions that require 4 golden coins.
Submitted Solution:
```
"""
Template written to be used by Python Programmers.
Use at your own risk!!!!
Owned by adi0311(rating - 5 star at CodeChef and Specialist at Codeforces).
"""
import sys
from functools import lru_cache, cmp_to_key
from heapq import merge, heapify, heappop, heappush, nlargest, nsmallest, _heapify_max, _heapreplace_max
from math import ceil, floor, gcd, fabs, factorial, fmod, sqrt, inf, log
from collections import defaultdict as dd, deque, Counter as c
from itertools import combinations as comb, permutations as perm
from bisect import bisect_left as bl, bisect_right as br, bisect
# sys.setrecursionlimit(2*pow(10, 6))
# sys.stdin = open("input.txt", "r")
# sys.stdout = open("output.txt", "w")
mod = pow(10, 9) + 7
mod2 = 998244353
def data(): return sys.stdin.readline().strip()
def out(var): sys.stdout.write(str(var))
def outln(var): sys.stdout.write(str(var)+"\n")
def l(): return list(sp())
def sl(): return list(ssp())
def sp(): return map(int, data().split())
def ssp(): return map(str, data().split())
def l1d(n, val=0): return [val for i in range(n)]
def l2d(n, m, val=0): return [l1d(n, val) for j in range(m)]
n, k = sp()
arr = l()
dp = c(arr)
answer = 0
while dp[k] != n:
answer += 1
temp = dp.copy()
for i in dp.keys():
if i != k:
temp[i] -= 1
temp[i+1] += 1
dp = temp.copy()
outln(answer)
``` | instruction | 0 | 66,863 | 2 | 133,726 |
No | output | 1 | 66,863 | 2 | 133,727 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The hero of our story, Valera, and his best friend Arcady are still in school, and therefore they spend all the free time playing turn-based strategy "GAGA: Go And Go Again". The gameplay is as follows.
There are two armies on the playing field each of which consists of n men (n is always even). The current player specifies for each of her soldiers an enemy's soldier he will shoot (a target) and then all the player's soldiers shot simultaneously. This is a game world, and so each soldier shoots perfectly, that is he absolutely always hits the specified target. If an enemy soldier is hit, he will surely die. It may happen that several soldiers had been indicated the same target. Killed soldiers do not participate in the game anymore.
The game "GAGA" consists of three steps: first Valera makes a move, then Arcady, then Valera again and the game ends.
You are asked to calculate the maximum total number of soldiers that may be killed during the game.
Input
The input data consist of a single integer n (2 โค n โค 108, n is even). Please note that before the game starts there are 2n soldiers on the fields.
Output
Print a single number โ a maximum total number of soldiers that could be killed in the course of the game in three turns.
Examples
Input
2
Output
3
Input
4
Output
6
Note
The first sample test:
1) Valera's soldiers 1 and 2 shoot at Arcady's soldier 1.
2) Arcady's soldier 2 shoots at Valera's soldier 1.
3) Valera's soldier 1 shoots at Arcady's soldier 2.
There are 3 soldiers killed in total: Valera's soldier 1 and Arcady's soldiers 1 and 2. | instruction | 0 | 66,921 | 2 | 133,842 |
Tags: math, number theory
Correct Solution:
```
print(int(int(input()) * 1.5))
``` | output | 1 | 66,921 | 2 | 133,843 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The hero of our story, Valera, and his best friend Arcady are still in school, and therefore they spend all the free time playing turn-based strategy "GAGA: Go And Go Again". The gameplay is as follows.
There are two armies on the playing field each of which consists of n men (n is always even). The current player specifies for each of her soldiers an enemy's soldier he will shoot (a target) and then all the player's soldiers shot simultaneously. This is a game world, and so each soldier shoots perfectly, that is he absolutely always hits the specified target. If an enemy soldier is hit, he will surely die. It may happen that several soldiers had been indicated the same target. Killed soldiers do not participate in the game anymore.
The game "GAGA" consists of three steps: first Valera makes a move, then Arcady, then Valera again and the game ends.
You are asked to calculate the maximum total number of soldiers that may be killed during the game.
Input
The input data consist of a single integer n (2 โค n โค 108, n is even). Please note that before the game starts there are 2n soldiers on the fields.
Output
Print a single number โ a maximum total number of soldiers that could be killed in the course of the game in three turns.
Examples
Input
2
Output
3
Input
4
Output
6
Note
The first sample test:
1) Valera's soldiers 1 and 2 shoot at Arcady's soldier 1.
2) Arcady's soldier 2 shoots at Valera's soldier 1.
3) Valera's soldier 1 shoots at Arcady's soldier 2.
There are 3 soldiers killed in total: Valera's soldier 1 and Arcady's soldiers 1 and 2. | instruction | 0 | 66,922 | 2 | 133,844 |
Tags: math, number theory
Correct Solution:
```
n=int(input())
print(n+(n//2))
``` | output | 1 | 66,922 | 2 | 133,845 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The hero of our story, Valera, and his best friend Arcady are still in school, and therefore they spend all the free time playing turn-based strategy "GAGA: Go And Go Again". The gameplay is as follows.
There are two armies on the playing field each of which consists of n men (n is always even). The current player specifies for each of her soldiers an enemy's soldier he will shoot (a target) and then all the player's soldiers shot simultaneously. This is a game world, and so each soldier shoots perfectly, that is he absolutely always hits the specified target. If an enemy soldier is hit, he will surely die. It may happen that several soldiers had been indicated the same target. Killed soldiers do not participate in the game anymore.
The game "GAGA" consists of three steps: first Valera makes a move, then Arcady, then Valera again and the game ends.
You are asked to calculate the maximum total number of soldiers that may be killed during the game.
Input
The input data consist of a single integer n (2 โค n โค 108, n is even). Please note that before the game starts there are 2n soldiers on the fields.
Output
Print a single number โ a maximum total number of soldiers that could be killed in the course of the game in three turns.
Examples
Input
2
Output
3
Input
4
Output
6
Note
The first sample test:
1) Valera's soldiers 1 and 2 shoot at Arcady's soldier 1.
2) Arcady's soldier 2 shoots at Valera's soldier 1.
3) Valera's soldier 1 shoots at Arcady's soldier 2.
There are 3 soldiers killed in total: Valera's soldier 1 and Arcady's soldiers 1 and 2. | instruction | 0 | 66,923 | 2 | 133,846 |
Tags: math, number theory
Correct Solution:
```
x = int(input())
print(2*x - (x // 2))
``` | output | 1 | 66,923 | 2 | 133,847 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The hero of our story, Valera, and his best friend Arcady are still in school, and therefore they spend all the free time playing turn-based strategy "GAGA: Go And Go Again". The gameplay is as follows.
There are two armies on the playing field each of which consists of n men (n is always even). The current player specifies for each of her soldiers an enemy's soldier he will shoot (a target) and then all the player's soldiers shot simultaneously. This is a game world, and so each soldier shoots perfectly, that is he absolutely always hits the specified target. If an enemy soldier is hit, he will surely die. It may happen that several soldiers had been indicated the same target. Killed soldiers do not participate in the game anymore.
The game "GAGA" consists of three steps: first Valera makes a move, then Arcady, then Valera again and the game ends.
You are asked to calculate the maximum total number of soldiers that may be killed during the game.
Input
The input data consist of a single integer n (2 โค n โค 108, n is even). Please note that before the game starts there are 2n soldiers on the fields.
Output
Print a single number โ a maximum total number of soldiers that could be killed in the course of the game in three turns.
Examples
Input
2
Output
3
Input
4
Output
6
Note
The first sample test:
1) Valera's soldiers 1 and 2 shoot at Arcady's soldier 1.
2) Arcady's soldier 2 shoots at Valera's soldier 1.
3) Valera's soldier 1 shoots at Arcady's soldier 2.
There are 3 soldiers killed in total: Valera's soldier 1 and Arcady's soldiers 1 and 2. | instruction | 0 | 66,924 | 2 | 133,848 |
Tags: math, number theory
Correct Solution:
```
import sys
n = sys.stdin.readline()
print(3*int(n)>>1)
``` | output | 1 | 66,924 | 2 | 133,849 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The hero of our story, Valera, and his best friend Arcady are still in school, and therefore they spend all the free time playing turn-based strategy "GAGA: Go And Go Again". The gameplay is as follows.
There are two armies on the playing field each of which consists of n men (n is always even). The current player specifies for each of her soldiers an enemy's soldier he will shoot (a target) and then all the player's soldiers shot simultaneously. This is a game world, and so each soldier shoots perfectly, that is he absolutely always hits the specified target. If an enemy soldier is hit, he will surely die. It may happen that several soldiers had been indicated the same target. Killed soldiers do not participate in the game anymore.
The game "GAGA" consists of three steps: first Valera makes a move, then Arcady, then Valera again and the game ends.
You are asked to calculate the maximum total number of soldiers that may be killed during the game.
Input
The input data consist of a single integer n (2 โค n โค 108, n is even). Please note that before the game starts there are 2n soldiers on the fields.
Output
Print a single number โ a maximum total number of soldiers that could be killed in the course of the game in three turns.
Examples
Input
2
Output
3
Input
4
Output
6
Note
The first sample test:
1) Valera's soldiers 1 and 2 shoot at Arcady's soldier 1.
2) Arcady's soldier 2 shoots at Valera's soldier 1.
3) Valera's soldier 1 shoots at Arcady's soldier 2.
There are 3 soldiers killed in total: Valera's soldier 1 and Arcady's soldiers 1 and 2. | instruction | 0 | 66,925 | 2 | 133,850 |
Tags: math, number theory
Correct Solution:
```
n=int(input())
print(n//2*3)
``` | output | 1 | 66,925 | 2 | 133,851 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The hero of our story, Valera, and his best friend Arcady are still in school, and therefore they spend all the free time playing turn-based strategy "GAGA: Go And Go Again". The gameplay is as follows.
There are two armies on the playing field each of which consists of n men (n is always even). The current player specifies for each of her soldiers an enemy's soldier he will shoot (a target) and then all the player's soldiers shot simultaneously. This is a game world, and so each soldier shoots perfectly, that is he absolutely always hits the specified target. If an enemy soldier is hit, he will surely die. It may happen that several soldiers had been indicated the same target. Killed soldiers do not participate in the game anymore.
The game "GAGA" consists of three steps: first Valera makes a move, then Arcady, then Valera again and the game ends.
You are asked to calculate the maximum total number of soldiers that may be killed during the game.
Input
The input data consist of a single integer n (2 โค n โค 108, n is even). Please note that before the game starts there are 2n soldiers on the fields.
Output
Print a single number โ a maximum total number of soldiers that could be killed in the course of the game in three turns.
Examples
Input
2
Output
3
Input
4
Output
6
Note
The first sample test:
1) Valera's soldiers 1 and 2 shoot at Arcady's soldier 1.
2) Arcady's soldier 2 shoots at Valera's soldier 1.
3) Valera's soldier 1 shoots at Arcady's soldier 2.
There are 3 soldiers killed in total: Valera's soldier 1 and Arcady's soldiers 1 and 2. | instruction | 0 | 66,926 | 2 | 133,852 |
Tags: math, number theory
Correct Solution:
```
t=int(input())
print(t*3 //2)
``` | output | 1 | 66,926 | 2 | 133,853 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The hero of our story, Valera, and his best friend Arcady are still in school, and therefore they spend all the free time playing turn-based strategy "GAGA: Go And Go Again". The gameplay is as follows.
There are two armies on the playing field each of which consists of n men (n is always even). The current player specifies for each of her soldiers an enemy's soldier he will shoot (a target) and then all the player's soldiers shot simultaneously. This is a game world, and so each soldier shoots perfectly, that is he absolutely always hits the specified target. If an enemy soldier is hit, he will surely die. It may happen that several soldiers had been indicated the same target. Killed soldiers do not participate in the game anymore.
The game "GAGA" consists of three steps: first Valera makes a move, then Arcady, then Valera again and the game ends.
You are asked to calculate the maximum total number of soldiers that may be killed during the game.
Input
The input data consist of a single integer n (2 โค n โค 108, n is even). Please note that before the game starts there are 2n soldiers on the fields.
Output
Print a single number โ a maximum total number of soldiers that could be killed in the course of the game in three turns.
Examples
Input
2
Output
3
Input
4
Output
6
Note
The first sample test:
1) Valera's soldiers 1 and 2 shoot at Arcady's soldier 1.
2) Arcady's soldier 2 shoots at Valera's soldier 1.
3) Valera's soldier 1 shoots at Arcady's soldier 2.
There are 3 soldiers killed in total: Valera's soldier 1 and Arcady's soldiers 1 and 2. | instruction | 0 | 66,927 | 2 | 133,854 |
Tags: math, number theory
Correct Solution:
```
n = int(input())
ans = int(n*3/2)
print(ans)
``` | output | 1 | 66,927 | 2 | 133,855 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The hero of our story, Valera, and his best friend Arcady are still in school, and therefore they spend all the free time playing turn-based strategy "GAGA: Go And Go Again". The gameplay is as follows.
There are two armies on the playing field each of which consists of n men (n is always even). The current player specifies for each of her soldiers an enemy's soldier he will shoot (a target) and then all the player's soldiers shot simultaneously. This is a game world, and so each soldier shoots perfectly, that is he absolutely always hits the specified target. If an enemy soldier is hit, he will surely die. It may happen that several soldiers had been indicated the same target. Killed soldiers do not participate in the game anymore.
The game "GAGA" consists of three steps: first Valera makes a move, then Arcady, then Valera again and the game ends.
You are asked to calculate the maximum total number of soldiers that may be killed during the game.
Input
The input data consist of a single integer n (2 โค n โค 108, n is even). Please note that before the game starts there are 2n soldiers on the fields.
Output
Print a single number โ a maximum total number of soldiers that could be killed in the course of the game in three turns.
Examples
Input
2
Output
3
Input
4
Output
6
Note
The first sample test:
1) Valera's soldiers 1 and 2 shoot at Arcady's soldier 1.
2) Arcady's soldier 2 shoots at Valera's soldier 1.
3) Valera's soldier 1 shoots at Arcady's soldier 2.
There are 3 soldiers killed in total: Valera's soldier 1 and Arcady's soldiers 1 and 2. | instruction | 0 | 66,928 | 2 | 133,856 |
Tags: math, number theory
Correct Solution:
```
n = int(input())
print((n + (n//2)))
``` | output | 1 | 66,928 | 2 | 133,857 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The hero of our story, Valera, and his best friend Arcady are still in school, and therefore they spend all the free time playing turn-based strategy "GAGA: Go And Go Again". The gameplay is as follows.
There are two armies on the playing field each of which consists of n men (n is always even). The current player specifies for each of her soldiers an enemy's soldier he will shoot (a target) and then all the player's soldiers shot simultaneously. This is a game world, and so each soldier shoots perfectly, that is he absolutely always hits the specified target. If an enemy soldier is hit, he will surely die. It may happen that several soldiers had been indicated the same target. Killed soldiers do not participate in the game anymore.
The game "GAGA" consists of three steps: first Valera makes a move, then Arcady, then Valera again and the game ends.
You are asked to calculate the maximum total number of soldiers that may be killed during the game.
Input
The input data consist of a single integer n (2 โค n โค 108, n is even). Please note that before the game starts there are 2n soldiers on the fields.
Output
Print a single number โ a maximum total number of soldiers that could be killed in the course of the game in three turns.
Examples
Input
2
Output
3
Input
4
Output
6
Note
The first sample test:
1) Valera's soldiers 1 and 2 shoot at Arcady's soldier 1.
2) Arcady's soldier 2 shoots at Valera's soldier 1.
3) Valera's soldier 1 shoots at Arcady's soldier 2.
There are 3 soldiers killed in total: Valera's soldier 1 and Arcady's soldiers 1 and 2.
Submitted Solution:
```
import math
from collections import defaultdict
def input_ints():
return list(map(int, input().split()))
def solve():
n = int(input())
print(3 * n // 2)
if __name__ == '__main__':
solve()
``` | instruction | 0 | 66,929 | 2 | 133,858 |
Yes | output | 1 | 66,929 | 2 | 133,859 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The hero of our story, Valera, and his best friend Arcady are still in school, and therefore they spend all the free time playing turn-based strategy "GAGA: Go And Go Again". The gameplay is as follows.
There are two armies on the playing field each of which consists of n men (n is always even). The current player specifies for each of her soldiers an enemy's soldier he will shoot (a target) and then all the player's soldiers shot simultaneously. This is a game world, and so each soldier shoots perfectly, that is he absolutely always hits the specified target. If an enemy soldier is hit, he will surely die. It may happen that several soldiers had been indicated the same target. Killed soldiers do not participate in the game anymore.
The game "GAGA" consists of three steps: first Valera makes a move, then Arcady, then Valera again and the game ends.
You are asked to calculate the maximum total number of soldiers that may be killed during the game.
Input
The input data consist of a single integer n (2 โค n โค 108, n is even). Please note that before the game starts there are 2n soldiers on the fields.
Output
Print a single number โ a maximum total number of soldiers that could be killed in the course of the game in three turns.
Examples
Input
2
Output
3
Input
4
Output
6
Note
The first sample test:
1) Valera's soldiers 1 and 2 shoot at Arcady's soldier 1.
2) Arcady's soldier 2 shoots at Valera's soldier 1.
3) Valera's soldier 1 shoots at Arcady's soldier 2.
There are 3 soldiers killed in total: Valera's soldier 1 and Arcady's soldiers 1 and 2.
Submitted Solution:
```
from sys import stdin,stdout
n=int(stdin.readline())
stdout.write(str(n*3//2))
``` | instruction | 0 | 66,930 | 2 | 133,860 |
Yes | output | 1 | 66,930 | 2 | 133,861 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The hero of our story, Valera, and his best friend Arcady are still in school, and therefore they spend all the free time playing turn-based strategy "GAGA: Go And Go Again". The gameplay is as follows.
There are two armies on the playing field each of which consists of n men (n is always even). The current player specifies for each of her soldiers an enemy's soldier he will shoot (a target) and then all the player's soldiers shot simultaneously. This is a game world, and so each soldier shoots perfectly, that is he absolutely always hits the specified target. If an enemy soldier is hit, he will surely die. It may happen that several soldiers had been indicated the same target. Killed soldiers do not participate in the game anymore.
The game "GAGA" consists of three steps: first Valera makes a move, then Arcady, then Valera again and the game ends.
You are asked to calculate the maximum total number of soldiers that may be killed during the game.
Input
The input data consist of a single integer n (2 โค n โค 108, n is even). Please note that before the game starts there are 2n soldiers on the fields.
Output
Print a single number โ a maximum total number of soldiers that could be killed in the course of the game in three turns.
Examples
Input
2
Output
3
Input
4
Output
6
Note
The first sample test:
1) Valera's soldiers 1 and 2 shoot at Arcady's soldier 1.
2) Arcady's soldier 2 shoots at Valera's soldier 1.
3) Valera's soldier 1 shoots at Arcady's soldier 2.
There are 3 soldiers killed in total: Valera's soldier 1 and Arcady's soldiers 1 and 2.
Submitted Solution:
```
n=int(input());print(3*n//2)
``` | instruction | 0 | 66,931 | 2 | 133,862 |
Yes | output | 1 | 66,931 | 2 | 133,863 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The hero of our story, Valera, and his best friend Arcady are still in school, and therefore they spend all the free time playing turn-based strategy "GAGA: Go And Go Again". The gameplay is as follows.
There are two armies on the playing field each of which consists of n men (n is always even). The current player specifies for each of her soldiers an enemy's soldier he will shoot (a target) and then all the player's soldiers shot simultaneously. This is a game world, and so each soldier shoots perfectly, that is he absolutely always hits the specified target. If an enemy soldier is hit, he will surely die. It may happen that several soldiers had been indicated the same target. Killed soldiers do not participate in the game anymore.
The game "GAGA" consists of three steps: first Valera makes a move, then Arcady, then Valera again and the game ends.
You are asked to calculate the maximum total number of soldiers that may be killed during the game.
Input
The input data consist of a single integer n (2 โค n โค 108, n is even). Please note that before the game starts there are 2n soldiers on the fields.
Output
Print a single number โ a maximum total number of soldiers that could be killed in the course of the game in three turns.
Examples
Input
2
Output
3
Input
4
Output
6
Note
The first sample test:
1) Valera's soldiers 1 and 2 shoot at Arcady's soldier 1.
2) Arcady's soldier 2 shoots at Valera's soldier 1.
3) Valera's soldier 1 shoots at Arcady's soldier 2.
There are 3 soldiers killed in total: Valera's soldier 1 and Arcady's soldiers 1 and 2.
Submitted Solution:
```
n=int(input())
print(2*n-int(n/2))
##########################
``` | instruction | 0 | 66,932 | 2 | 133,864 |
Yes | output | 1 | 66,932 | 2 | 133,865 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The hero of our story, Valera, and his best friend Arcady are still in school, and therefore they spend all the free time playing turn-based strategy "GAGA: Go And Go Again". The gameplay is as follows.
There are two armies on the playing field each of which consists of n men (n is always even). The current player specifies for each of her soldiers an enemy's soldier he will shoot (a target) and then all the player's soldiers shot simultaneously. This is a game world, and so each soldier shoots perfectly, that is he absolutely always hits the specified target. If an enemy soldier is hit, he will surely die. It may happen that several soldiers had been indicated the same target. Killed soldiers do not participate in the game anymore.
The game "GAGA" consists of three steps: first Valera makes a move, then Arcady, then Valera again and the game ends.
You are asked to calculate the maximum total number of soldiers that may be killed during the game.
Input
The input data consist of a single integer n (2 โค n โค 108, n is even). Please note that before the game starts there are 2n soldiers on the fields.
Output
Print a single number โ a maximum total number of soldiers that could be killed in the course of the game in three turns.
Examples
Input
2
Output
3
Input
4
Output
6
Note
The first sample test:
1) Valera's soldiers 1 and 2 shoot at Arcady's soldier 1.
2) Arcady's soldier 2 shoots at Valera's soldier 1.
3) Valera's soldier 1 shoots at Arcady's soldier 2.
There are 3 soldiers killed in total: Valera's soldier 1 and Arcady's soldiers 1 and 2.
Submitted Solution:
```
import bisect
import math
import collections
import sys
import copy
from functools import reduce
import decimal
from io import BytesIO, IOBase
import os
sys.setrecursionlimit(10 ** 9)
decimal.getcontext().rounding = decimal.ROUND_HALF_UP
graphDict = collections.defaultdict
queue = collections.deque
class Graphs:
def __init__(self):
self.graph = graphDict(list)
def add_edge(self, u, v):
self.graph[u].append(v)
def dfs_utility(self, nodes, visited_nodes):
visited_nodes.add(nodes)
for neighbour in self.graph[nodes]:
if neighbour not in visited_nodes:
self.dfs_utility(neighbour, visited_nodes)
else:
return neighbour
def dfs(self, node):
Visited = set()
self.dfs_utility(node, Visited)
def bfs(self, node):
visited = set()
if node not in visited:
queue.append(node)
visited.add(node)
while queue:
parent = queue.popleft()
print(parent)
for item in self.graph[parent]:
if item not in visited:
queue.append(item)
visited.add(item)
def rounding(n):
return int(decimal.Decimal(f'{n}').to_integral_value())
def factors(n):
return set(reduce(list.__add__,
([i, n // i] for i in range(1, int(n ** 0.5) + 1) if n % i == 0)))
################################ <fast I/O> ###########################################
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
#############################################<I/O Region >##############################################
def inp():
return sys.stdin.readline().strip()
def map_inp(v_type):
return map(v_type, inp().split())
def list_inp(v_type):
return list(map_inp(v_type))
######################################## Solution ####################################
n = int(inp())
ans = 2 * n - math.ceil(n / 4)
if n % 4 == 0:
ans -= 1
print(ans)
``` | instruction | 0 | 66,933 | 2 | 133,866 |
No | output | 1 | 66,933 | 2 | 133,867 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The hero of our story, Valera, and his best friend Arcady are still in school, and therefore they spend all the free time playing turn-based strategy "GAGA: Go And Go Again". The gameplay is as follows.
There are two armies on the playing field each of which consists of n men (n is always even). The current player specifies for each of her soldiers an enemy's soldier he will shoot (a target) and then all the player's soldiers shot simultaneously. This is a game world, and so each soldier shoots perfectly, that is he absolutely always hits the specified target. If an enemy soldier is hit, he will surely die. It may happen that several soldiers had been indicated the same target. Killed soldiers do not participate in the game anymore.
The game "GAGA" consists of three steps: first Valera makes a move, then Arcady, then Valera again and the game ends.
You are asked to calculate the maximum total number of soldiers that may be killed during the game.
Input
The input data consist of a single integer n (2 โค n โค 108, n is even). Please note that before the game starts there are 2n soldiers on the fields.
Output
Print a single number โ a maximum total number of soldiers that could be killed in the course of the game in three turns.
Examples
Input
2
Output
3
Input
4
Output
6
Note
The first sample test:
1) Valera's soldiers 1 and 2 shoot at Arcady's soldier 1.
2) Arcady's soldier 2 shoots at Valera's soldier 1.
3) Valera's soldier 1 shoots at Arcady's soldier 2.
There are 3 soldiers killed in total: Valera's soldier 1 and Arcady's soldiers 1 and 2.
Submitted Solution:
```
import sys
from functools import reduce
from collections import Counter
import time
import datetime
from math import sqrt,gcd
# def time_t():
# print("Current date and time: " , datetime.datetime.now())
# print("Current year: ", datetime.date.today().strftime("%Y"))
# print("Month of year: ", datetime.date.today().strftime("%B"))
# print("Week number of the year: ", datetime.date.today().strftime("%W"))
# print("Weekday of the week: ", datetime.date.today().strftime("%w"))
# print("Day of year: ", datetime.date.today().strftime("%j"))
# print("Day of the month : ", datetime.date.today().strftime("%d"))
# print("Day of week: ", datetime.date.today().strftime("%A"))
def ip(): return int(sys.stdin.readline())
def sip(): return sys.stdin.readline()
def mip(): return map(int,sys.stdin.readline().split())
def mips(): return map(str,sys.stdin.readline().split())
def lip(): return list(map(int,sys.stdin.readline().split()))
def matip(n,m):
lst=[]
for i in range(n):
arr = lip()
lst.insert(i,arr)
return lst
def factors(n): # find the factors of a number
return list(set(reduce(list.__add__, ([i, n//i] for i in range(1, int(n**0.5) + 1) if n % i == 0))))
def minJumps(arr, n): #to reach from 0 to n-1 in the array in minimum steps
jumps = [0 for i in range(n)]
if (n == 0) or (arr[0] == 0):
return float('inf')
jumps[0] = 0
for i in range(1, n):
jumps[i] = float('inf')
for j in range(i):
if (i <= j + arr[j]) and (jumps[j] != float('inf')):
jumps[i] = min(jumps[i], jumps[j] + 1)
break
return jumps[n-1]
def dic(arr): # converting list into dict of count
return Counter(arr)
def check_prime(n):
if n<2:
return False
for i in range(2,int(n**(0.5))+1,2):
if n%i==0:
return False
return True
# --------------------------------------------------------- #
# sys.stdin = open('input.txt','r')
# sys.stdout = open('output.txt','w')
# --------------------------------------------------------- #
n = ip()
if n==2:
print(3)
else:
print(2*n-2)
``` | instruction | 0 | 66,934 | 2 | 133,868 |
No | output | 1 | 66,934 | 2 | 133,869 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The hero of our story, Valera, and his best friend Arcady are still in school, and therefore they spend all the free time playing turn-based strategy "GAGA: Go And Go Again". The gameplay is as follows.
There are two armies on the playing field each of which consists of n men (n is always even). The current player specifies for each of her soldiers an enemy's soldier he will shoot (a target) and then all the player's soldiers shot simultaneously. This is a game world, and so each soldier shoots perfectly, that is he absolutely always hits the specified target. If an enemy soldier is hit, he will surely die. It may happen that several soldiers had been indicated the same target. Killed soldiers do not participate in the game anymore.
The game "GAGA" consists of three steps: first Valera makes a move, then Arcady, then Valera again and the game ends.
You are asked to calculate the maximum total number of soldiers that may be killed during the game.
Input
The input data consist of a single integer n (2 โค n โค 108, n is even). Please note that before the game starts there are 2n soldiers on the fields.
Output
Print a single number โ a maximum total number of soldiers that could be killed in the course of the game in three turns.
Examples
Input
2
Output
3
Input
4
Output
6
Note
The first sample test:
1) Valera's soldiers 1 and 2 shoot at Arcady's soldier 1.
2) Arcady's soldier 2 shoots at Valera's soldier 1.
3) Valera's soldier 1 shoots at Arcady's soldier 2.
There are 3 soldiers killed in total: Valera's soldier 1 and Arcady's soldiers 1 and 2.
Submitted Solution:
```
print(3 * (int(input()) / 2))
``` | instruction | 0 | 66,935 | 2 | 133,870 |
No | output | 1 | 66,935 | 2 | 133,871 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The hero of our story, Valera, and his best friend Arcady are still in school, and therefore they spend all the free time playing turn-based strategy "GAGA: Go And Go Again". The gameplay is as follows.
There are two armies on the playing field each of which consists of n men (n is always even). The current player specifies for each of her soldiers an enemy's soldier he will shoot (a target) and then all the player's soldiers shot simultaneously. This is a game world, and so each soldier shoots perfectly, that is he absolutely always hits the specified target. If an enemy soldier is hit, he will surely die. It may happen that several soldiers had been indicated the same target. Killed soldiers do not participate in the game anymore.
The game "GAGA" consists of three steps: first Valera makes a move, then Arcady, then Valera again and the game ends.
You are asked to calculate the maximum total number of soldiers that may be killed during the game.
Input
The input data consist of a single integer n (2 โค n โค 108, n is even). Please note that before the game starts there are 2n soldiers on the fields.
Output
Print a single number โ a maximum total number of soldiers that could be killed in the course of the game in three turns.
Examples
Input
2
Output
3
Input
4
Output
6
Note
The first sample test:
1) Valera's soldiers 1 and 2 shoot at Arcady's soldier 1.
2) Arcady's soldier 2 shoots at Valera's soldier 1.
3) Valera's soldier 1 shoots at Arcady's soldier 2.
There are 3 soldiers killed in total: Valera's soldier 1 and Arcady's soldiers 1 and 2.
Submitted Solution:
```
b=int(input())
print(b+b-1)
``` | instruction | 0 | 66,936 | 2 | 133,872 |
No | output | 1 | 66,936 | 2 | 133,873 |
Provide a correct Python 3 solution for this coding contest problem.
Silver Fox is fighting with N monsters.
The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the health of H_i.
Silver Fox can use bombs to attack the monsters. Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A. There is no way other than bombs to decrease the monster's health.
Silver Fox wins when all the monsters' healths become 0 or below.
Find the minimum number of bombs needed to win.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 0 \leq D \leq 10^9
* 1 \leq A \leq 10^9
* 0 \leq X_i \leq 10^9
* 1 \leq H_i \leq 10^9
* X_i are distinct.
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N D A
X_1 H_1
:
X_N H_N
Output
Print the minimum number of bombs needed to win.
Examples
Input
3 3 2
1 2
5 4
9 2
Output
2
Input
9 4 1
1 5
2 4
3 3
4 2
5 1
6 2
7 3
8 4
9 5
Output
5
Input
3 0 1
300000000 1000000000
100000000 1000000000
200000000 1000000000
Output
3000000000 | instruction | 0 | 67,910 | 2 | 135,820 |
"Correct Solution:
```
from math import ceil
from collections import deque
n,d,a = map(int,input().split())
m = [list(map(int,input().split())) for _ in range(n)]
m.sort()
l = [(x, ceil(h/a)) for x,h in m]
ans = 0
damage = 0
que = deque([])
for x,h in l:
while que and que[0][0] < x:
s,t = que.popleft()
damage -= t
need = max(0, h - damage)
ans += need
damage += need
if need:
que.append((x+2*d, need))
print(ans)
``` | output | 1 | 67,910 | 2 | 135,821 |
Provide a correct Python 3 solution for this coding contest problem.
Silver Fox is fighting with N monsters.
The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the health of H_i.
Silver Fox can use bombs to attack the monsters. Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A. There is no way other than bombs to decrease the monster's health.
Silver Fox wins when all the monsters' healths become 0 or below.
Find the minimum number of bombs needed to win.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 0 \leq D \leq 10^9
* 1 \leq A \leq 10^9
* 0 \leq X_i \leq 10^9
* 1 \leq H_i \leq 10^9
* X_i are distinct.
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N D A
X_1 H_1
:
X_N H_N
Output
Print the minimum number of bombs needed to win.
Examples
Input
3 3 2
1 2
5 4
9 2
Output
2
Input
9 4 1
1 5
2 4
3 3
4 2
5 1
6 2
7 3
8 4
9 5
Output
5
Input
3 0 1
300000000 1000000000
100000000 1000000000
200000000 1000000000
Output
3000000000 | instruction | 0 | 67,911 | 2 | 135,822 |
"Correct Solution:
```
def main():
import sys
from collections import deque
from operator import itemgetter
b=sys.stdin.buffer
n,d,a=map(int,b.readline().split())
m=map(int,b.read().split())
q=deque()
popleft,append=q.popleft,q.append
s=b=0
for x,h in sorted(zip(m,m),key=itemgetter(0)):
while q and q[0][0]<x:b-=popleft()[1]
h-=b
t=-(-h//a)
if t>0:
s+=t
t*=a
b+=t
append((x+d+d,t))
print(s)
main()
``` | output | 1 | 67,911 | 2 | 135,823 |
Provide a correct Python 3 solution for this coding contest problem.
Silver Fox is fighting with N monsters.
The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the health of H_i.
Silver Fox can use bombs to attack the monsters. Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A. There is no way other than bombs to decrease the monster's health.
Silver Fox wins when all the monsters' healths become 0 or below.
Find the minimum number of bombs needed to win.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 0 \leq D \leq 10^9
* 1 \leq A \leq 10^9
* 0 \leq X_i \leq 10^9
* 1 \leq H_i \leq 10^9
* X_i are distinct.
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N D A
X_1 H_1
:
X_N H_N
Output
Print the minimum number of bombs needed to win.
Examples
Input
3 3 2
1 2
5 4
9 2
Output
2
Input
9 4 1
1 5
2 4
3 3
4 2
5 1
6 2
7 3
8 4
9 5
Output
5
Input
3 0 1
300000000 1000000000
100000000 1000000000
200000000 1000000000
Output
3000000000 | instruction | 0 | 67,912 | 2 | 135,824 |
"Correct Solution:
```
def main():
import sys
from bisect import bisect
from operator import itemgetter
b=sys.stdin.buffer
n,d,a=map(int,b.readline().split())
m=map(int,b.read().split())
c=[0]*(n+1)
z=sorted(zip(m,m),key=itemgetter(0))
y=[x for x,_ in z]
s=b=0
for i,(x,h)in enumerate(z):
c[i]+=b
b=c[i]
h-=b
t=-h//a
if t<0:
b-=t*a
c[bisect(y,x+d+d)]+=t*a
s-=t
print(s)
main()
``` | output | 1 | 67,912 | 2 | 135,825 |
Provide a correct Python 3 solution for this coding contest problem.
Silver Fox is fighting with N monsters.
The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the health of H_i.
Silver Fox can use bombs to attack the monsters. Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A. There is no way other than bombs to decrease the monster's health.
Silver Fox wins when all the monsters' healths become 0 or below.
Find the minimum number of bombs needed to win.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 0 \leq D \leq 10^9
* 1 \leq A \leq 10^9
* 0 \leq X_i \leq 10^9
* 1 \leq H_i \leq 10^9
* X_i are distinct.
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N D A
X_1 H_1
:
X_N H_N
Output
Print the minimum number of bombs needed to win.
Examples
Input
3 3 2
1 2
5 4
9 2
Output
2
Input
9 4 1
1 5
2 4
3 3
4 2
5 1
6 2
7 3
8 4
9 5
Output
5
Input
3 0 1
300000000 1000000000
100000000 1000000000
200000000 1000000000
Output
3000000000 | instruction | 0 | 67,913 | 2 | 135,826 |
"Correct Solution:
```
import collections
N, D, A = [int(i) for i in input().split()] # ๆฐ, ็ฏๅฒ, ๆปๆๅ
XH = [tuple(map(int, input().split())) for _ in range(N)] # ๅบงๆจ, ไฝๅ
XH.sort()
queue = collections.deque()
ans = 0
damage = 0
for x, h in XH:
while queue and queue[0][0] < x:
damage -= queue.popleft()[1]
h -= damage
if h > 0:
count = -(-h // A)
ans += count
queue.append((x + 2*D, count * A))
damage += count * A
print(ans)
``` | output | 1 | 67,913 | 2 | 135,827 |
Provide a correct Python 3 solution for this coding contest problem.
Silver Fox is fighting with N monsters.
The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the health of H_i.
Silver Fox can use bombs to attack the monsters. Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A. There is no way other than bombs to decrease the monster's health.
Silver Fox wins when all the monsters' healths become 0 or below.
Find the minimum number of bombs needed to win.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 0 \leq D \leq 10^9
* 1 \leq A \leq 10^9
* 0 \leq X_i \leq 10^9
* 1 \leq H_i \leq 10^9
* X_i are distinct.
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N D A
X_1 H_1
:
X_N H_N
Output
Print the minimum number of bombs needed to win.
Examples
Input
3 3 2
1 2
5 4
9 2
Output
2
Input
9 4 1
1 5
2 4
3 3
4 2
5 1
6 2
7 3
8 4
9 5
Output
5
Input
3 0 1
300000000 1000000000
100000000 1000000000
200000000 1000000000
Output
3000000000 | instruction | 0 | 67,914 | 2 | 135,828 |
"Correct Solution:
```
import math
n,d,a=map(int,input().split())
XH=[[int(i)for i in input().split()] for _ in range(n)]
XH.sort(key=lambda x:x[0])
ans=0
l=0
before=0
T=[0]*n
for i,xh in enumerate(XH):
x,h=xh
while XH[l][0]+2*d<x:
before-=T[l]
l+=1
h-=before*a
if h<=0:
continue
T[i]=math.ceil(h/a)
ans+=T[i]
before+=T[i]
print(ans)
``` | output | 1 | 67,914 | 2 | 135,829 |
Provide a correct Python 3 solution for this coding contest problem.
Silver Fox is fighting with N monsters.
The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the health of H_i.
Silver Fox can use bombs to attack the monsters. Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A. There is no way other than bombs to decrease the monster's health.
Silver Fox wins when all the monsters' healths become 0 or below.
Find the minimum number of bombs needed to win.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 0 \leq D \leq 10^9
* 1 \leq A \leq 10^9
* 0 \leq X_i \leq 10^9
* 1 \leq H_i \leq 10^9
* X_i are distinct.
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N D A
X_1 H_1
:
X_N H_N
Output
Print the minimum number of bombs needed to win.
Examples
Input
3 3 2
1 2
5 4
9 2
Output
2
Input
9 4 1
1 5
2 4
3 3
4 2
5 1
6 2
7 3
8 4
9 5
Output
5
Input
3 0 1
300000000 1000000000
100000000 1000000000
200000000 1000000000
Output
3000000000 | instruction | 0 | 67,915 | 2 | 135,830 |
"Correct Solution:
```
N,D,A=[int(x) for x in input().split()]
xh = [[int(x) for x in input().split()] for _ in range(N)]
xh = sorted(xh)
r=0
l=0
ans = 0
mi = 10**9
d = [0]*(N+1)
for l in range(N):
if d[l]<xh[l][1]:
la = (xh[l][1]-d[l]+A-1)//A
for _ in range(N):
if l<N and r<N and 2*D>=xh[r][0]-xh[l][0]:
r+=1
else:
break
ans += la
d[l]+=la*A
d[r]-=la*A
d[l+1]+=d[l]
print(ans)
``` | output | 1 | 67,915 | 2 | 135,831 |
Provide a correct Python 3 solution for this coding contest problem.
Silver Fox is fighting with N monsters.
The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the health of H_i.
Silver Fox can use bombs to attack the monsters. Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A. There is no way other than bombs to decrease the monster's health.
Silver Fox wins when all the monsters' healths become 0 or below.
Find the minimum number of bombs needed to win.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 0 \leq D \leq 10^9
* 1 \leq A \leq 10^9
* 0 \leq X_i \leq 10^9
* 1 \leq H_i \leq 10^9
* X_i are distinct.
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N D A
X_1 H_1
:
X_N H_N
Output
Print the minimum number of bombs needed to win.
Examples
Input
3 3 2
1 2
5 4
9 2
Output
2
Input
9 4 1
1 5
2 4
3 3
4 2
5 1
6 2
7 3
8 4
9 5
Output
5
Input
3 0 1
300000000 1000000000
100000000 1000000000
200000000 1000000000
Output
3000000000 | instruction | 0 | 67,916 | 2 | 135,832 |
"Correct Solution:
```
from bisect import bisect_right
N, D, A = map(int, input().split())
M = []
for i in range(N):
x, h = map(int, input().split())
M.append((x, -(-h//A)))
M.sort(key=lambda x: x[0])
X = list(map(lambda x: x[0], M))
H = list(map(lambda x: x[1], M))
dmg = [0] * (N+1)
ans = 0
for i in range(N):
x, h = M[i]
h = max(0, h - dmg[i])
dmg[bisect_right(X, x + 2*D)] -= h
dmg[i+1] += dmg[i] + h
ans += h
print(ans)
``` | output | 1 | 67,916 | 2 | 135,833 |
Provide a correct Python 3 solution for this coding contest problem.
Silver Fox is fighting with N monsters.
The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the health of H_i.
Silver Fox can use bombs to attack the monsters. Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A. There is no way other than bombs to decrease the monster's health.
Silver Fox wins when all the monsters' healths become 0 or below.
Find the minimum number of bombs needed to win.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 0 \leq D \leq 10^9
* 1 \leq A \leq 10^9
* 0 \leq X_i \leq 10^9
* 1 \leq H_i \leq 10^9
* X_i are distinct.
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N D A
X_1 H_1
:
X_N H_N
Output
Print the minimum number of bombs needed to win.
Examples
Input
3 3 2
1 2
5 4
9 2
Output
2
Input
9 4 1
1 5
2 4
3 3
4 2
5 1
6 2
7 3
8 4
9 5
Output
5
Input
3 0 1
300000000 1000000000
100000000 1000000000
200000000 1000000000
Output
3000000000 | instruction | 0 | 67,917 | 2 | 135,834 |
"Correct Solution:
```
import math
from collections import deque
N,D,A = map(int,input().split())
monsters = sorted([ list(map(int,input().split())) for _ in range(N) ])
monsters = [ [x, math.ceil(h/A)] for x,h in monsters ]
# print(monsters)
que = deque()
cur = 0
ans = 0
for x,h in monsters:
while que and x > que[0][0]:
_,n = que.popleft()
cur -= n
need = max(0, h-cur)
ans += need
cur += need
if h:
# ๅฏพ่ฑกใฎใขใณในใฟใผใๆใๅทฆ็ซฏใซใใใใจใๆณๅฎ
que.append([x+2*D, need])
print(ans)
``` | output | 1 | 67,917 | 2 | 135,835 |
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