message stringlengths 2 39.6k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 450 109k | cluster float64 2 2 | __index_level_0__ int64 900 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n warriors in a row. The power of the i-th warrior is a_i. All powers are pairwise distinct.
You have two types of spells which you may cast:
1. Fireball: you spend x mana and destroy exactly k consecutive warriors;
2. Berserk: you spend y mana, choose two consecutive warriors, and the warrior with greater power destroys the warrior with smaller power.
For example, let the powers of warriors be [2, 3, 7, 8, 11, 5, 4], and k = 3. If you cast Berserk on warriors with powers 8 and 11, the resulting sequence of powers becomes [2, 3, 7, 11, 5, 4]. Then, for example, if you cast Fireball on consecutive warriors with powers [7, 11, 5], the resulting sequence of powers becomes [2, 3, 4].
You want to turn the current sequence of warriors powers a_1, a_2, ..., a_n into b_1, b_2, ..., b_m. Calculate the minimum amount of mana you need to spend on it.
Input
The first line contains two integers n and m (1 β€ n, m β€ 2 β
10^5) β the length of sequence a and the length of sequence b respectively.
The second line contains three integers x, k, y (1 β€ x, y, β€ 10^9; 1 β€ k β€ n) β the cost of fireball, the range of fireball and the cost of berserk respectively.
The third line contains n integers a_1, a_2, ..., a_n (1 β€ a_i β€ n). It is guaranteed that all integers a_i are pairwise distinct.
The fourth line contains m integers b_1, b_2, ..., b_m (1 β€ b_i β€ n). It is guaranteed that all integers b_i are pairwise distinct.
Output
Print the minimum amount of mana for turning the sequnce a_1, a_2, ..., a_n into b_1, b_2, ..., b_m, or -1 if it is impossible.
Examples
Input
5 2
5 2 3
3 1 4 5 2
3 5
Output
8
Input
4 4
5 1 4
4 3 1 2
2 4 3 1
Output
-1
Input
4 4
2 1 11
1 3 2 4
1 3 2 4
Output
0
Submitted Solution:
```
from sys import stdin
def mp():return map(int,stdin.readline().split())
def ml():return list(map(int,stdin.readline().split()))
n,m=mp();x,k,y=mp();a=ml();b=ml()
def delSeg(st,end,mx):
cnt=(end-st)
aend=a[end] if end<n else a[st-1]
# print("SEG",st,end,mx,aend)
if cnt==0:return 0
if cnt < k and mx>aend:
return -1
if x<=k*y:
return (cnt//k)*x+(cnt%k)*y
else:
if mx<aend: return cnt*y
else: return x+(cnt-k)*y
prev=0;j=0
mx=-1;ans,flag=0,True
for i in range(n):
if j<m and a[i]==b[j]:
ret=delSeg(prev,i,max(a[prev:i]) if prev!=i else 0)
# print("Return:",ret)
if ret==-1:
flag=False;break
else:ans+=ret
j+=1;mx=-1;prev=i+1
elif j>=m:
mx=max(mx,max(a[prev:n]))
ret=delSeg(prev,n,mx)
# print("Return:",ret)
if ret==-1:
flag=False;break
else:ans+=ret
break
i+=1
if flag and j>=m:
print(ans)
else:
print(-1)
``` | instruction | 0 | 81,009 | 2 | 162,018 |
No | output | 1 | 81,009 | 2 | 162,019 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n warriors in a row. The power of the i-th warrior is a_i. All powers are pairwise distinct.
You have two types of spells which you may cast:
1. Fireball: you spend x mana and destroy exactly k consecutive warriors;
2. Berserk: you spend y mana, choose two consecutive warriors, and the warrior with greater power destroys the warrior with smaller power.
For example, let the powers of warriors be [2, 3, 7, 8, 11, 5, 4], and k = 3. If you cast Berserk on warriors with powers 8 and 11, the resulting sequence of powers becomes [2, 3, 7, 11, 5, 4]. Then, for example, if you cast Fireball on consecutive warriors with powers [7, 11, 5], the resulting sequence of powers becomes [2, 3, 4].
You want to turn the current sequence of warriors powers a_1, a_2, ..., a_n into b_1, b_2, ..., b_m. Calculate the minimum amount of mana you need to spend on it.
Input
The first line contains two integers n and m (1 β€ n, m β€ 2 β
10^5) β the length of sequence a and the length of sequence b respectively.
The second line contains three integers x, k, y (1 β€ x, y, β€ 10^9; 1 β€ k β€ n) β the cost of fireball, the range of fireball and the cost of berserk respectively.
The third line contains n integers a_1, a_2, ..., a_n (1 β€ a_i β€ n). It is guaranteed that all integers a_i are pairwise distinct.
The fourth line contains m integers b_1, b_2, ..., b_m (1 β€ b_i β€ n). It is guaranteed that all integers b_i are pairwise distinct.
Output
Print the minimum amount of mana for turning the sequnce a_1, a_2, ..., a_n into b_1, b_2, ..., b_m, or -1 if it is impossible.
Examples
Input
5 2
5 2 3
3 1 4 5 2
3 5
Output
8
Input
4 4
5 1 4
4 3 1 2
2 4 3 1
Output
-1
Input
4 4
2 1 11
1 3 2 4
1 3 2 4
Output
0
Submitted Solution:
```
from math import log2
def SparseTable(arr):
def twoK(i, j):
if i == j:
return 1
return 2 ** int(log2(j-i))
def rangeK(i, j):
t = twoK(i, j)
return [i, t + i -1, j - t +1, j]
def toPos(i):
return int(log2(i))
def Query(i, j):
nonlocal table
i_1, i_2, j_1, j_2 = rangeK(i, j)
return max(table[i_1][toPos(i_2-i_1+1)], table[j_1][toPos(j_2-j_1+1)])
n = len(arr)
i = 1
table = [[] for _ in range(n)]
while i <= n:
for j in range(n - i +1):
if i == 1:
table[j].append(arr[j])
else:
table[j].append(Query(j, j+i-1))
i = i * 2
return Query
#arr = [3, 1, 4, 5, 2]
#query = SparseTable(arr)
n, m = map(int,input().split(' '))
x, k, y = map(int,input().split(' '))
a = list(map(int,input().split(' ')))
b = list(map(int,input().split(' ')))
dic = {}
dic['first'] = 0
dic['last'] = n - 1
b = ['first'] + b + ['last']
for pos, val in enumerate(a):
dic[val] = pos
query = SparseTable(a)
ans = 0
for i in range(m+1):
p1 = dic[b[i]]
p2 = dic[b[i+1]]
if p1 == p2:
continue
if p1 > p2:
ans = -1
break
p1 = p1 + 1
p2 = p2 - 1
if b[i] == 'first':
p1 = p1 - 1
b[i] = a[0]
if b[i+1] == 'last':
p2 = p2 + 1
b[i+1] = a[-1]
dist = p2 - p1 + 1
if dist % k == 0:
ans += dist // k * x
elif dist < k:
mmax = query(p1, p2)
if mmax > max(b[i], b[i+1]):
ans = -1
break
else:
ans += dist * y
else:
num = dist//k
ans += num*x + (dist - num*k)*y
print(ans)
``` | instruction | 0 | 81,010 | 2 | 162,020 |
No | output | 1 | 81,010 | 2 | 162,021 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n warriors in a row. The power of the i-th warrior is a_i. All powers are pairwise distinct.
You have two types of spells which you may cast:
1. Fireball: you spend x mana and destroy exactly k consecutive warriors;
2. Berserk: you spend y mana, choose two consecutive warriors, and the warrior with greater power destroys the warrior with smaller power.
For example, let the powers of warriors be [2, 3, 7, 8, 11, 5, 4], and k = 3. If you cast Berserk on warriors with powers 8 and 11, the resulting sequence of powers becomes [2, 3, 7, 11, 5, 4]. Then, for example, if you cast Fireball on consecutive warriors with powers [7, 11, 5], the resulting sequence of powers becomes [2, 3, 4].
You want to turn the current sequence of warriors powers a_1, a_2, ..., a_n into b_1, b_2, ..., b_m. Calculate the minimum amount of mana you need to spend on it.
Input
The first line contains two integers n and m (1 β€ n, m β€ 2 β
10^5) β the length of sequence a and the length of sequence b respectively.
The second line contains three integers x, k, y (1 β€ x, y, β€ 10^9; 1 β€ k β€ n) β the cost of fireball, the range of fireball and the cost of berserk respectively.
The third line contains n integers a_1, a_2, ..., a_n (1 β€ a_i β€ n). It is guaranteed that all integers a_i are pairwise distinct.
The fourth line contains m integers b_1, b_2, ..., b_m (1 β€ b_i β€ n). It is guaranteed that all integers b_i are pairwise distinct.
Output
Print the minimum amount of mana for turning the sequnce a_1, a_2, ..., a_n into b_1, b_2, ..., b_m, or -1 if it is impossible.
Examples
Input
5 2
5 2 3
3 1 4 5 2
3 5
Output
8
Input
4 4
5 1 4
4 3 1 2
2 4 3 1
Output
-1
Input
4 4
2 1 11
1 3 2 4
1 3 2 4
Output
0
Submitted Solution:
```
inp = lambda: map(int, input().split(" "))
sum = 0
n, m = inp()
x, k, y = inp()
arr1 = list(inp())
arr2 = list(inp())
pos = []
arr1.insert(0,0)
arr1.append(0)
arr2.insert(0,0)
arr2.append(0)
j = 0
for i in range(n+2):
if arr1[i] == arr2[j]:
pos.append(i)
j += 1
if j != m+2:
print(-1)
else:
for i in range(1, m+2):
pos1 = pos[i-1]
pos2 = pos[i]
l = pos2-pos1-1
max_val = max(arr1[pos1], arr1[pos2])
is_max = True
for j in range(pos1, pos2):
if arr1[pos1] > max_val:
is_max = False
break
if is_max:
sum += min(l*y, (l//k)*x + (l%k)*y)
else:
sum += min((l-k)*y +x, (l//k)*x +(l%k)*y)
print(sum)
``` | instruction | 0 | 81,011 | 2 | 162,022 |
No | output | 1 | 81,011 | 2 | 162,023 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n warriors in a row. The power of the i-th warrior is a_i. All powers are pairwise distinct.
You have two types of spells which you may cast:
1. Fireball: you spend x mana and destroy exactly k consecutive warriors;
2. Berserk: you spend y mana, choose two consecutive warriors, and the warrior with greater power destroys the warrior with smaller power.
For example, let the powers of warriors be [2, 3, 7, 8, 11, 5, 4], and k = 3. If you cast Berserk on warriors with powers 8 and 11, the resulting sequence of powers becomes [2, 3, 7, 11, 5, 4]. Then, for example, if you cast Fireball on consecutive warriors with powers [7, 11, 5], the resulting sequence of powers becomes [2, 3, 4].
You want to turn the current sequence of warriors powers a_1, a_2, ..., a_n into b_1, b_2, ..., b_m. Calculate the minimum amount of mana you need to spend on it.
Input
The first line contains two integers n and m (1 β€ n, m β€ 2 β
10^5) β the length of sequence a and the length of sequence b respectively.
The second line contains three integers x, k, y (1 β€ x, y, β€ 10^9; 1 β€ k β€ n) β the cost of fireball, the range of fireball and the cost of berserk respectively.
The third line contains n integers a_1, a_2, ..., a_n (1 β€ a_i β€ n). It is guaranteed that all integers a_i are pairwise distinct.
The fourth line contains m integers b_1, b_2, ..., b_m (1 β€ b_i β€ n). It is guaranteed that all integers b_i are pairwise distinct.
Output
Print the minimum amount of mana for turning the sequnce a_1, a_2, ..., a_n into b_1, b_2, ..., b_m, or -1 if it is impossible.
Examples
Input
5 2
5 2 3
3 1 4 5 2
3 5
Output
8
Input
4 4
5 1 4
4 3 1 2
2 4 3 1
Output
-1
Input
4 4
2 1 11
1 3 2 4
1 3 2 4
Output
0
Submitted Solution:
```
import sys
inpy = [int(x) for x in sys.stdin.read().split()]
n, m, x, k, y = inpy[0:5]
a, b = inpy[5:5+n], inpy[5+n:]
# print(a, b)
prei = -1
i, j = 0, 0
res = 0
while i < len(a) and j < len(b):
# print(a[i], b[j], 'ab')
if a[i] == b[j]:
# print(i, j, 'equal')
flag = True
maxV = 0
for l in range(prei + 1, i):
maxV = max(maxV, a[l])
minMana = None
if max(a[prei] if prei >= 0 else 0, a[i]) > maxV:
minMana = y * (i - prei - 1)
# print(i - prei, k)
if i - prei > k:
minMana = min(((i - prei - 1) // k) * x + ((i - prei - 1) % k) * y, minMana if minMana else 999999999999999999)
# print(i, j, minMana)
if minMana == None:
break
res += minMana
prei = i
j += 1
# print(i, j)
i += 1
# print(i, j)
if j == len(b):
maxV = 0
for j in range(prei + 1, len(a)):
maxV = max(maxV, a[j])
minMana = None
if a[prei] > maxV:
minMana = y * (len(a) - prei - 1)
if i - prei > k:
minMana = min(((len(a) - prei - 1) // k) * x + ((len(a) - prei - 1) % k) * y, minMana)
if minMana == None:
print(-1)
else:
print(res + minMana)
else:
print(-1)
``` | instruction | 0 | 81,012 | 2 | 162,024 |
No | output | 1 | 81,012 | 2 | 162,025 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Romans have attacked again. This time they are much more than the Persians but Shapur is ready to defeat them. He says: "A lion is never afraid of a hundred sheep".
Nevertheless Shapur has to find weaknesses in the Roman army to defeat them. So he gives the army a weakness number.
In Shapur's opinion the weakness of an army is equal to the number of triplets i, j, k such that i < j < k and ai > aj > ak where ax is the power of man standing at position x. The Roman army has one special trait β powers of all the people in it are distinct.
Help Shapur find out how weak the Romans are.
Input
The first line of input contains a single number n (3 β€ n β€ 106) β the number of men in Roman army. Next line contains n different positive integers ai (1 β€ i β€ n, 1 β€ ai β€ 109) β powers of men in the Roman army.
Output
A single integer number, the weakness of the Roman army.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d).
Examples
Input
3
3 2 1
Output
1
Input
3
2 3 1
Output
0
Input
4
10 8 3 1
Output
4
Input
4
1 5 4 3
Output
1 | instruction | 0 | 81,244 | 2 | 162,488 |
Tags: data structures, trees
Correct Solution:
```
from sys import stdin
class order_tree:
def __init__(self, n):
self.tree, self.n = [[0, 0] for _ in range(n << 1)], n
# get interval[l,r)
def query(self, r, col):
res = 0
l = self.n
r += self.n
while l < r:
if l & 1:
res += self.tree[l][col]
l += 1
if r & 1:
r -= 1
res += self.tree[r][col]
l >>= 1
r >>= 1
return res
def update(self, ix, val, col):
ix += self.n
# set new value
self.tree[ix][col] += val
# move up
while ix > 1:
self.tree[ix >> 1][col] = self.tree[ix][col] + self.tree[ix ^ 1][col]
ix >>= 1
def fast3():
import os, sys, atexit
from io import BytesIO
sys.stdout = BytesIO()
_write = sys.stdout.write
sys.stdout.write = lambda s: _write(s.encode())
atexit.register(lambda: os.write(1, sys.stdout.getvalue()))
return BytesIO(os.read(0, os.fstat(0).st_size)).readline
input = fast3()
n, a = int(input()), [int(x) for x in input().split()]
tree, ans = order_tree(n), 0
mem = {i: j for j, i in enumerate(sorted(a))}
for i in range(n - 1, -1, -1):
cur = mem[a[i]]
ans += tree.query(cur, 1)
tree.update(cur, 1, 0)
tree.update(cur, tree.query(cur, 0), 1)
print(ans)
``` | output | 1 | 81,244 | 2 | 162,489 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Romans have attacked again. This time they are much more than the Persians but Shapur is ready to defeat them. He says: "A lion is never afraid of a hundred sheep".
Nevertheless Shapur has to find weaknesses in the Roman army to defeat them. So he gives the army a weakness number.
In Shapur's opinion the weakness of an army is equal to the number of triplets i, j, k such that i < j < k and ai > aj > ak where ax is the power of man standing at position x. The Roman army has one special trait β powers of all the people in it are distinct.
Help Shapur find out how weak the Romans are.
Input
The first line of input contains a single number n (3 β€ n β€ 106) β the number of men in Roman army. Next line contains n different positive integers ai (1 β€ i β€ n, 1 β€ ai β€ 109) β powers of men in the Roman army.
Output
A single integer number, the weakness of the Roman army.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d).
Examples
Input
3
3 2 1
Output
1
Input
3
2 3 1
Output
0
Input
4
10 8 3 1
Output
4
Input
4
1 5 4 3
Output
1 | instruction | 0 | 81,245 | 2 | 162,490 |
Tags: data structures, trees
Correct Solution:
```
# aadiupadhyay
import os.path
from math import gcd, floor, ceil
from collections import *
import sys
mod = 1000000007
INF = float('inf')
def st(): return list(sys.stdin.readline().strip())
def li(): return list(map(int, sys.stdin.readline().split()))
def mp(): return map(int, sys.stdin.readline().split())
def inp(): return int(sys.stdin.readline())
def pr(n): return sys.stdout.write(str(n)+"\n")
def prl(n): return sys.stdout.write(str(n)+" ")
if os.path.exists('input.txt'):
sys.stdin = open('input.txt', 'r')
sys.stdout = open('output.txt', 'w')
def update(index, delta):
while index <= n:
BIT[index] += delta
index += index & -index
def query(index):
s = 0
while index > 0:
s += BIT[index]
index -= index & -index
return s
n = inp()
l = [0]+li()
x = sorted(l)
d = {x[i]: i for i in range(n+1)}
left = [0]
right = [0]
BIT = [0]
for i in range(n+1):
l[i] = d[l[i]]
left.append(0)
right.append(0)
BIT.append(0)
for i in range(1, n+1):
update(l[i], 1)
left[i] = query(n)-query(l[i])
BIT = [0 for i in range(n+2)]
for i in range(n, 0, -1):
update(l[i], 1)
right[i] = query(l[i]-1)
ans = 0
for i in range(1, n+1):
ans += left[i]*right[i]
pr(ans)
``` | output | 1 | 81,245 | 2 | 162,491 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Romans have attacked again. This time they are much more than the Persians but Shapur is ready to defeat them. He says: "A lion is never afraid of a hundred sheep".
Nevertheless Shapur has to find weaknesses in the Roman army to defeat them. So he gives the army a weakness number.
In Shapur's opinion the weakness of an army is equal to the number of triplets i, j, k such that i < j < k and ai > aj > ak where ax is the power of man standing at position x. The Roman army has one special trait β powers of all the people in it are distinct.
Help Shapur find out how weak the Romans are.
Input
The first line of input contains a single number n (3 β€ n β€ 106) β the number of men in Roman army. Next line contains n different positive integers ai (1 β€ i β€ n, 1 β€ ai β€ 109) β powers of men in the Roman army.
Output
A single integer number, the weakness of the Roman army.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d).
Examples
Input
3
3 2 1
Output
1
Input
3
2 3 1
Output
0
Input
4
10 8 3 1
Output
4
Input
4
1 5 4 3
Output
1 | instruction | 0 | 81,246 | 2 | 162,492 |
Tags: data structures, trees
Correct Solution:
```
"""
Approach:
for every element:
a = no of elements greater in left
b = no of elements smaller in right
ans is sigma(a*b) for all elements
Now to efficiently calculate no of such elements for every
element we use BIT
"""
import os
import sys
from io import BytesIO, IOBase
def main():
n = int(input())
lis = list(map(int, input().split()))
ma = n + 1
mp = {}
for i, elem in enumerate(sorted(lis), start=1):
mp[elem] = i
gBIT = [0] * (ma + 1)
def update(BIT, i, x):
while i <= ma:
BIT[i] += x
i += i & -i
def query(BIT, i):
su = 0
while i > 0:
su += BIT[i]
i -= i & -i
return su
Larr = [0] * (n)
for i in range(n):
curElem = mp[lis[i]]
cur = query(gBIT, ma) - query(gBIT, curElem - 1)
Larr[i] = cur
update(gBIT, curElem, 1)
lBIT = [0] * (ma + 1)
Rarr = [0] * n
for i in reversed(range(n)):
curElem = mp[lis[i]]
cur = query(lBIT, curElem) - query(lBIT, 0)
Rarr[i] = cur
update(lBIT, curElem, 1)
print(sum([x * y for x, y in zip(Larr, Rarr)]))
# region fastio
# Credits
# # template credits to cheran-senthil's github Repo
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
# endregion
if __name__ == "__main__":
main()
``` | output | 1 | 81,246 | 2 | 162,493 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Romans have attacked again. This time they are much more than the Persians but Shapur is ready to defeat them. He says: "A lion is never afraid of a hundred sheep".
Nevertheless Shapur has to find weaknesses in the Roman army to defeat them. So he gives the army a weakness number.
In Shapur's opinion the weakness of an army is equal to the number of triplets i, j, k such that i < j < k and ai > aj > ak where ax is the power of man standing at position x. The Roman army has one special trait β powers of all the people in it are distinct.
Help Shapur find out how weak the Romans are.
Input
The first line of input contains a single number n (3 β€ n β€ 106) β the number of men in Roman army. Next line contains n different positive integers ai (1 β€ i β€ n, 1 β€ ai β€ 109) β powers of men in the Roman army.
Output
A single integer number, the weakness of the Roman army.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d).
Examples
Input
3
3 2 1
Output
1
Input
3
2 3 1
Output
0
Input
4
10 8 3 1
Output
4
Input
4
1 5 4 3
Output
1 | instruction | 0 | 81,247 | 2 | 162,494 |
Tags: data structures, trees
Correct Solution:
```
def update(bit ,i ) :
while(i < len(bit)) :
bit[i] += 1
i += (i & (-i))
def getsum(bit, i ) :
res = 0
while (i >0 ) :
res += bit[i]
i -= (i & (-i))
return res
n = int(input())
arr = list(map(int,input().split()))
l = sorted(arr)
d = {}
ind =1
for i in range(n) :
if not d.get(l[i] , 0) :
d[l[i]] = ind
ind +=1
for i in range(n) :
arr[i] = d[arr[i]]
small = [0]*n
maxel = max(arr)
bit = [0]*(maxel +1)
for i in range(n) :
c = getsum(bit, arr[i]-1)
small[i] = i -c
update(bit,arr[i])
bit = [0]*(maxel+1)
large = [0]*n
for i in range(n-1,-1,-1) :
k = getsum(bit,arr[i] -1)
update(bit,arr[i])
large[i] = k
count = 0
for i in range(n) :
count += small[i]*large[i]
print(count)
``` | output | 1 | 81,247 | 2 | 162,495 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Romans have attacked again. This time they are much more than the Persians but Shapur is ready to defeat them. He says: "A lion is never afraid of a hundred sheep".
Nevertheless Shapur has to find weaknesses in the Roman army to defeat them. So he gives the army a weakness number.
In Shapur's opinion the weakness of an army is equal to the number of triplets i, j, k such that i < j < k and ai > aj > ak where ax is the power of man standing at position x. The Roman army has one special trait β powers of all the people in it are distinct.
Help Shapur find out how weak the Romans are.
Input
The first line of input contains a single number n (3 β€ n β€ 106) β the number of men in Roman army. Next line contains n different positive integers ai (1 β€ i β€ n, 1 β€ ai β€ 109) β powers of men in the Roman army.
Output
A single integer number, the weakness of the Roman army.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d).
Examples
Input
3
3 2 1
Output
1
Input
3
2 3 1
Output
0
Input
4
10 8 3 1
Output
4
Input
4
1 5 4 3
Output
1 | instruction | 0 | 81,248 | 2 | 162,496 |
Tags: data structures, trees
Correct Solution:
```
def update(bit, i):
while (i < len(bit)):
bit[i] += 1
i += (i & (-i))
def getsum(bit, i):
res = 0
while (i > 0):
res += bit[i]
i -= (i & (-i))
return res
n = int(input())
arr = list(map(int, input().split()))
d = {}
l = list(sorted(set(arr)))
ind = 1
for i in range(len(l)):
d[l[i]] = ind
ind += 1
l = [0] * n
r = [0] * n
t = 0
bit = [0] * (ind+10)
update(bit, d[arr[0]])
for i in range(1, n):
l[i] = getsum(bit, ind +1) - getsum(bit, d[arr[i]])
update(bit, d[arr[i]])
bit = [0] * (ind +10)
for i in range(n - 1, -1, -1):
r[i] = getsum(bit, d[arr[i]] - 1)
update(bit, d[arr[i]])
ans = 0
for i in range(n):
ans += l[i] * r[i]
print(ans)
``` | output | 1 | 81,248 | 2 | 162,497 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Romans have attacked again. This time they are much more than the Persians but Shapur is ready to defeat them. He says: "A lion is never afraid of a hundred sheep".
Nevertheless Shapur has to find weaknesses in the Roman army to defeat them. So he gives the army a weakness number.
In Shapur's opinion the weakness of an army is equal to the number of triplets i, j, k such that i < j < k and ai > aj > ak where ax is the power of man standing at position x. The Roman army has one special trait β powers of all the people in it are distinct.
Help Shapur find out how weak the Romans are.
Input
The first line of input contains a single number n (3 β€ n β€ 106) β the number of men in Roman army. Next line contains n different positive integers ai (1 β€ i β€ n, 1 β€ ai β€ 109) β powers of men in the Roman army.
Output
A single integer number, the weakness of the Roman army.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d).
Examples
Input
3
3 2 1
Output
1
Input
3
2 3 1
Output
0
Input
4
10 8 3 1
Output
4
Input
4
1 5 4 3
Output
1 | instruction | 0 | 81,249 | 2 | 162,498 |
Tags: data structures, trees
Correct Solution:
```
def update(bit ,i ) :
while(i < len(bit)) :
bit[i] += 1
i += (i & (-i))
def getsum(bit, i ) :
res = 0
while (i >0 ) :
res += bit[i]
i -= (i & (-i))
return res
n = int(input())
lista = list(map(int,input().split()))
poderes = sorted(lista)
d = {}
ind =1
for i in range(n) :
if not d.get(poderes[i] , 0) :
d[poderes[i]] = ind
ind +=1
for i in range(n) :
lista[i] = d[lista[i]]
a = [0]*n
maximo = max(lista)
bit = [0]*(maximo +1)
for i in range(n) :
c = getsum(bit, lista[i]-1)
a[i] = i -c
update(bit,lista[i])
bit = [0]*(maximo+1)
b = [0]*n
for i in range(n-1,-1,-1) :
k = getsum(bit,lista[i] -1)
update(bit,lista[i])
b[i] = k
count = 0
for i in range(n) :
count += a[i]*b[i]
print(count)
``` | output | 1 | 81,249 | 2 | 162,499 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Romans have attacked again. This time they are much more than the Persians but Shapur is ready to defeat them. He says: "A lion is never afraid of a hundred sheep".
Nevertheless Shapur has to find weaknesses in the Roman army to defeat them. So he gives the army a weakness number.
In Shapur's opinion the weakness of an army is equal to the number of triplets i, j, k such that i < j < k and ai > aj > ak where ax is the power of man standing at position x. The Roman army has one special trait β powers of all the people in it are distinct.
Help Shapur find out how weak the Romans are.
Input
The first line of input contains a single number n (3 β€ n β€ 106) β the number of men in Roman army. Next line contains n different positive integers ai (1 β€ i β€ n, 1 β€ ai β€ 109) β powers of men in the Roman army.
Output
A single integer number, the weakness of the Roman army.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d).
Examples
Input
3
3 2 1
Output
1
Input
3
2 3 1
Output
0
Input
4
10 8 3 1
Output
4
Input
4
1 5 4 3
Output
1 | instruction | 0 | 81,250 | 2 | 162,500 |
Tags: data structures, trees
Correct Solution:
```
import sys
# FASTEST IO
from io import BytesIO, IOBase
from types import GeneratorType
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
import os
self.os = os
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = self.os.read(self._fd, max(self.os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = self.os.read(self._fd, max(self.os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
self.os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
# End of FASTEST IO
class fen_tree:
def __init__(self,n):
self.tree=[0 for i in range(n+1)]
self.n=n
def query(self,q):
s=0
while q>0:
s+=self.tree[q]
q-=(q&-q)
return s
def update(self,q,upd):
while q<self.n:
self.tree[q]+=upd
q+=(q&-q)
input=sys.stdin.readline
def main():
n=int(input())
arr=list(map(int,input().split()))
for i in range(n):
arr[i]=(arr[i],i)
arr.sort(key=lambda x:x[0],reverse=True)
obj=fen_tree(n)
gre_before=[0 for i in range(n)]
for _,i in arr:
gre_before[i]=obj.query(i)
obj.update(i+1,1)
res=0
obj2=fen_tree(n)
for _,i in arr[::-1]:
res+=(obj2.query(n-i-1)*gre_before[i])
obj2.update(n-i,1)
sys.stdout.write(str(res)+'\n')
main()
``` | output | 1 | 81,250 | 2 | 162,501 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Romans have attacked again. This time they are much more than the Persians but Shapur is ready to defeat them. He says: "A lion is never afraid of a hundred sheep".
Nevertheless Shapur has to find weaknesses in the Roman army to defeat them. So he gives the army a weakness number.
In Shapur's opinion the weakness of an army is equal to the number of triplets i, j, k such that i < j < k and ai > aj > ak where ax is the power of man standing at position x. The Roman army has one special trait β powers of all the people in it are distinct.
Help Shapur find out how weak the Romans are.
Input
The first line of input contains a single number n (3 β€ n β€ 106) β the number of men in Roman army. Next line contains n different positive integers ai (1 β€ i β€ n, 1 β€ ai β€ 109) β powers of men in the Roman army.
Output
A single integer number, the weakness of the Roman army.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d).
Examples
Input
3
3 2 1
Output
1
Input
3
2 3 1
Output
0
Input
4
10 8 3 1
Output
4
Input
4
1 5 4 3
Output
1 | instruction | 0 | 81,251 | 2 | 162,502 |
Tags: data structures, trees
Correct Solution:
```
def and_i(i):
return i & (i + 1)
def or_i(i):
return i | (i + 1)
class Tree:
def __init__(self, n):
self.n = n
self.tree = [0] * n
def get_sum(self, i):
ans = 0
while i >= 0:
ans += self.tree[i]
i = and_i(i) - 1
return ans
def update_tree(self, i, x=1):
while i < self.n:
self.tree[i] += x
i = or_i(i)
n = int(input())
heights = list(map(int, input().split()))
pos = {x: i for i, x in enumerate(heights)}
for ind, x in enumerate(sorted(heights, reverse=True)):
heights[pos[x]] = ind
tree1 = Tree(n)
tree2 = Tree(n)
count = 0
for h in heights:
count += tree2.get_sum(h - 1)
tree1.update_tree(h)
v = tree1.get_sum(h - 1)
tree2.update_tree(h, v)
print(count)
``` | output | 1 | 81,251 | 2 | 162,503 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Romans have attacked again. This time they are much more than the Persians but Shapur is ready to defeat them. He says: "A lion is never afraid of a hundred sheep".
Nevertheless Shapur has to find weaknesses in the Roman army to defeat them. So he gives the army a weakness number.
In Shapur's opinion the weakness of an army is equal to the number of triplets i, j, k such that i < j < k and ai > aj > ak where ax is the power of man standing at position x. The Roman army has one special trait β powers of all the people in it are distinct.
Help Shapur find out how weak the Romans are.
Input
The first line of input contains a single number n (3 β€ n β€ 106) β the number of men in Roman army. Next line contains n different positive integers ai (1 β€ i β€ n, 1 β€ ai β€ 109) β powers of men in the Roman army.
Output
A single integer number, the weakness of the Roman army.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d).
Examples
Input
3
3 2 1
Output
1
Input
3
2 3 1
Output
0
Input
4
10 8 3 1
Output
4
Input
4
1 5 4 3
Output
1
Submitted Solution:
```
from bisect import bisect_right
from collections import defaultdict
import os
import sys
from io import BytesIO, IOBase
from collections import defaultdict
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
def sum(BIT, i):
s = 0
while i > 0:
s += BIT[i]
i -= i & (-i)
return s
def update(BIT, i, v):
while i < len(BIT):
BIT[i] += v
i += i & (-i)
def find(fen, k):
curr = 0
ans = 0
prevsum = 0
for i in range(19, -1, -1):
if ((curr + (1 << i) < n) and fen[curr + (1 << i)] + prevsum < k):
ans = curr + (1 << i)
curr = ans
prevsum += fen[curr]
return ans + 1
def Rank(x,BIT) :
return sum(BIT,x)
n=int(input())
b=list(map(int,input().split()))
c=[]
for j in range(n):
c.append([b[j],j])
c.sort()
j=0
while(j<n):
b[c[j][1]]=j+1
j+=1
BIT = [0] * (n + 1)
ans=0
for i in range(n):
update(BIT, b[i], 1)
res=i+1-Rank(b[i],BIT)
rem = b[i] - 1 - i + res
ans += ((res) * rem)
print(ans)
``` | instruction | 0 | 81,252 | 2 | 162,504 |
Yes | output | 1 | 81,252 | 2 | 162,505 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Romans have attacked again. This time they are much more than the Persians but Shapur is ready to defeat them. He says: "A lion is never afraid of a hundred sheep".
Nevertheless Shapur has to find weaknesses in the Roman army to defeat them. So he gives the army a weakness number.
In Shapur's opinion the weakness of an army is equal to the number of triplets i, j, k such that i < j < k and ai > aj > ak where ax is the power of man standing at position x. The Roman army has one special trait β powers of all the people in it are distinct.
Help Shapur find out how weak the Romans are.
Input
The first line of input contains a single number n (3 β€ n β€ 106) β the number of men in Roman army. Next line contains n different positive integers ai (1 β€ i β€ n, 1 β€ ai β€ 109) β powers of men in the Roman army.
Output
A single integer number, the weakness of the Roman army.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d).
Examples
Input
3
3 2 1
Output
1
Input
3
2 3 1
Output
0
Input
4
10 8 3 1
Output
4
Input
4
1 5 4 3
Output
1
Submitted Solution:
```
#!/usr/bin/env python3
# from typing import *
import sys
import io
import math
import collections
import decimal
import itertools
import bisect
import heapq
def input():
return sys.stdin.readline()[:-1]
# sys.setrecursionlimit(1000000)
# _INPUT = """3
# 3 2 1
# """
# sys.stdin = io.StringIO(_INPUT)
class BIT:
"""
Binary Indexed Tree (Fenwick Tree), 1-indexed
"""
def __init__(self, n):
"""
Parameters
----------
n : int
θ¦η΄ ζ°γindex γ― 0..n γ«γͺγγ
"""
self.size = n
self.data = [0] * (n+1)
# self.depth = n.bit_length()
def add(self, i, x):
while i <= self.size:
self.data[i] += x
i += i & -i
def get_sum(self, i):
s = 0
while i > 0:
s += self.data[i]
i -= i & -i
return s
N = int(input())
A = list(map(int, input().split()))
D = {a: i for i, a in enumerate(sorted(set(A)))}
B = [D[a] for a in A]
bit1 = BIT(N)
T1 = [0] * N
for i in reversed(range(N)):
T1[B[i]] = bit1.get_sum(B[i])
bit1.add(B[i]+1, 1)
bit2 = BIT(N)
T2 = [0] * N
for i in range(N):
T2[B[i]] = i - bit2.get_sum(B[i])
bit2.add(B[i]+1, 1)
ans = sum(T1[i] * T2[i] for i in range(N))
print(ans)
``` | instruction | 0 | 81,253 | 2 | 162,506 |
Yes | output | 1 | 81,253 | 2 | 162,507 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Romans have attacked again. This time they are much more than the Persians but Shapur is ready to defeat them. He says: "A lion is never afraid of a hundred sheep".
Nevertheless Shapur has to find weaknesses in the Roman army to defeat them. So he gives the army a weakness number.
In Shapur's opinion the weakness of an army is equal to the number of triplets i, j, k such that i < j < k and ai > aj > ak where ax is the power of man standing at position x. The Roman army has one special trait β powers of all the people in it are distinct.
Help Shapur find out how weak the Romans are.
Input
The first line of input contains a single number n (3 β€ n β€ 106) β the number of men in Roman army. Next line contains n different positive integers ai (1 β€ i β€ n, 1 β€ ai β€ 109) β powers of men in the Roman army.
Output
A single integer number, the weakness of the Roman army.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d).
Examples
Input
3
3 2 1
Output
1
Input
3
2 3 1
Output
0
Input
4
10 8 3 1
Output
4
Input
4
1 5 4 3
Output
1
Submitted Solution:
```
# by the authority of GOD author: manhar singh sachdev #
import os,sys
from io import BytesIO, IOBase
class SortedList:
def __init__(self, iterable=None, _load=200):
"""Initialize sorted list instance."""
if iterable is None:
iterable = []
values = sorted(iterable)
self._len = _len = len(values)
self._load = _load
self._lists = _lists = [values[i:i + _load] for i in range(0, _len, _load)]
self._list_lens = [len(_list) for _list in _lists]
self._mins = [_list[0] for _list in _lists]
self._fen_tree = []
self._rebuild = True
def _fen_build(self):
"""Build a fenwick tree instance."""
self._fen_tree[:] = self._list_lens
_fen_tree = self._fen_tree
for i in range(len(_fen_tree)):
if i | i + 1 < len(_fen_tree):
_fen_tree[i | i + 1] += _fen_tree[i]
self._rebuild = False
def _fen_update(self, index, value):
"""Update `fen_tree[index] += value`."""
if not self._rebuild:
_fen_tree = self._fen_tree
while index < len(_fen_tree):
_fen_tree[index] += value
index |= index + 1
def _fen_query(self, end):
"""Return `sum(_fen_tree[:end])`."""
if self._rebuild:
self._fen_build()
_fen_tree = self._fen_tree
x = 0
while end:
x += _fen_tree[end - 1]
end &= end - 1
return x
def _fen_findkth(self, k):
"""Return a pair of (the largest `idx` such that `sum(_fen_tree[:idx]) <= k`, `k - sum(_fen_tree[:idx])`)."""
_list_lens = self._list_lens
if k < _list_lens[0]:
return 0, k
if k >= self._len - _list_lens[-1]:
return len(_list_lens) - 1, k + _list_lens[-1] - self._len
if self._rebuild:
self._fen_build()
_fen_tree = self._fen_tree
idx = -1
for d in reversed(range(len(_fen_tree).bit_length())):
right_idx = idx + (1 << d)
if right_idx < len(_fen_tree) and k >= _fen_tree[right_idx]:
idx = right_idx
k -= _fen_tree[idx]
return idx + 1, k
def _delete(self, pos, idx):
"""Delete value at the given `(pos, idx)`."""
_lists = self._lists
_mins = self._mins
_list_lens = self._list_lens
self._len -= 1
self._fen_update(pos, -1)
del _lists[pos][idx]
_list_lens[pos] -= 1
if _list_lens[pos]:
_mins[pos] = _lists[pos][0]
else:
del _lists[pos]
del _list_lens[pos]
del _mins[pos]
self._rebuild = True
def _loc_left(self, value):
"""Return an index pair that corresponds to the first position of `value` in the sorted list."""
if not self._len:
return 0, 0
_lists = self._lists
_mins = self._mins
lo, pos = -1, len(_lists) - 1
while lo + 1 < pos:
mi = (lo + pos) >> 1
if value <= _mins[mi]:
pos = mi
else:
lo = mi
if pos and value <= _lists[pos - 1][-1]:
pos -= 1
_list = _lists[pos]
lo, idx = -1, len(_list)
while lo + 1 < idx:
mi = (lo + idx) >> 1
if value <= _list[mi]:
idx = mi
else:
lo = mi
return pos, idx
def _loc_right(self, value):
"""Return an index pair that corresponds to the last position of `value` in the sorted list."""
if not self._len:
return 0, 0
_lists = self._lists
_mins = self._mins
pos, hi = 0, len(_lists)
while pos + 1 < hi:
mi = (pos + hi) >> 1
if value < _mins[mi]:
hi = mi
else:
pos = mi
_list = _lists[pos]
lo, idx = -1, len(_list)
while lo + 1 < idx:
mi = (lo + idx) >> 1
if value < _list[mi]:
idx = mi
else:
lo = mi
return pos, idx
def add(self, value):
"""Add `value` to sorted list."""
_load = self._load
_lists = self._lists
_mins = self._mins
_list_lens = self._list_lens
self._len += 1
if _lists:
pos, idx = self._loc_right(value)
self._fen_update(pos, 1)
_list = _lists[pos]
_list.insert(idx, value)
_list_lens[pos] += 1
_mins[pos] = _list[0]
if _load + _load < len(_list):
_lists.insert(pos + 1, _list[_load:])
_list_lens.insert(pos + 1, len(_list) - _load)
_mins.insert(pos + 1, _list[_load])
_list_lens[pos] = _load
del _list[_load:]
self._rebuild = True
else:
_lists.append([value])
_mins.append(value)
_list_lens.append(1)
self._rebuild = True
def discard(self, value):
"""Remove `value` from sorted list if it is a member."""
_lists = self._lists
if _lists:
pos, idx = self._loc_right(value)
if idx and _lists[pos][idx - 1] == value:
self._delete(pos, idx - 1)
def remove(self, value):
"""Remove `value` from sorted list; `value` must be a member."""
_len = self._len
self.discard(value)
if _len == self._len:
raise ValueError('{0!r} not in list'.format(value))
def pop(self, index=-1):
"""Remove and return value at `index` in sorted list."""
pos, idx = self._fen_findkth(self._len + index if index < 0 else index)
value = self._lists[pos][idx]
self._delete(pos, idx)
return value
def bisect_left(self, value):
"""Return the first index to insert `value` in the sorted list."""
pos, idx = self._loc_left(value)
return self._fen_query(pos) + idx
def bisect_right(self, value):
"""Return the last index to insert `value` in the sorted list."""
pos, idx = self._loc_right(value)
return self._fen_query(pos) + idx
def count(self, value):
"""Return number of occurrences of `value` in the sorted list."""
return self.bisect_right(value) - self.bisect_left(value)
def __len__(self):
"""Return the size of the sorted list."""
return self._len
def __getitem__(self, index):
"""Lookup value at `index` in sorted list."""
pos, idx = self._fen_findkth(self._len + index if index < 0 else index)
return self._lists[pos][idx]
def __delitem__(self, index):
"""Remove value at `index` from sorted list."""
pos, idx = self._fen_findkth(self._len + index if index < 0 else index)
self._delete(pos, idx)
def __contains__(self, value):
"""Return true if `value` is an element of the sorted list."""
_lists = self._lists
if _lists:
pos, idx = self._loc_left(value)
return idx < len(_lists[pos]) and _lists[pos][idx] == value
return False
def __iter__(self):
"""Return an iterator over the sorted list."""
return (value for _list in self._lists for value in _list)
def __reversed__(self):
"""Return a reverse iterator over the sorted list."""
return (value for _list in reversed(self._lists) for value in reversed(_list))
def __repr__(self):
"""Return string representation of sorted list."""
return 'SortedList({0})'.format(list(self))
def main():
n = int(input())
a = list(map(int,input().split()))
one,two = SortedList(),SortedList(a)
ans = 0
for i in range(n):
two.discard(a[i])
ans += (len(one)-one.bisect_left(a[i]))*two.bisect_left(a[i])
one.add(a[i])
print(ans)
# Fast IO Region
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
if __name__ == "__main__":
main()
``` | instruction | 0 | 81,254 | 2 | 162,508 |
Yes | output | 1 | 81,254 | 2 | 162,509 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Romans have attacked again. This time they are much more than the Persians but Shapur is ready to defeat them. He says: "A lion is never afraid of a hundred sheep".
Nevertheless Shapur has to find weaknesses in the Roman army to defeat them. So he gives the army a weakness number.
In Shapur's opinion the weakness of an army is equal to the number of triplets i, j, k such that i < j < k and ai > aj > ak where ax is the power of man standing at position x. The Roman army has one special trait β powers of all the people in it are distinct.
Help Shapur find out how weak the Romans are.
Input
The first line of input contains a single number n (3 β€ n β€ 106) β the number of men in Roman army. Next line contains n different positive integers ai (1 β€ i β€ n, 1 β€ ai β€ 109) β powers of men in the Roman army.
Output
A single integer number, the weakness of the Roman army.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d).
Examples
Input
3
3 2 1
Output
1
Input
3
2 3 1
Output
0
Input
4
10 8 3 1
Output
4
Input
4
1 5 4 3
Output
1
Submitted Solution:
```
import sys
from array import array # noqa: F401
def input():
return sys.stdin.buffer.readline().decode('utf-8')
class BIT_RSQ(object):
__slots__ = ['nodes', 'size']
def __init__(self, size: int):
self.nodes = [0] * (size + 1)
self.size = size + 1
def add(self, index: int, value: int):
while index < self.size:
self.nodes[index] += value
index += index & -index
def sum(self, right: int):
result = 0
while right:
result += self.nodes[right]
right -= right & -right
return result
n = int(input())
a = list(map(int, input().split()))
comp_dict = {x: i for i, x in enumerate(sorted(a, reverse=True), start=1)}
bit1 = BIT_RSQ(n + 10)
bit2 = BIT_RSQ(n + 10)
ans = 0
for x in a:
x = comp_dict[x]
ans += bit2.sum(x)
bit2.add(x, bit1.sum(x))
bit1.add(x, 1)
print(ans)
``` | instruction | 0 | 81,255 | 2 | 162,510 |
Yes | output | 1 | 81,255 | 2 | 162,511 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Romans have attacked again. This time they are much more than the Persians but Shapur is ready to defeat them. He says: "A lion is never afraid of a hundred sheep".
Nevertheless Shapur has to find weaknesses in the Roman army to defeat them. So he gives the army a weakness number.
In Shapur's opinion the weakness of an army is equal to the number of triplets i, j, k such that i < j < k and ai > aj > ak where ax is the power of man standing at position x. The Roman army has one special trait β powers of all the people in it are distinct.
Help Shapur find out how weak the Romans are.
Input
The first line of input contains a single number n (3 β€ n β€ 106) β the number of men in Roman army. Next line contains n different positive integers ai (1 β€ i β€ n, 1 β€ ai β€ 109) β powers of men in the Roman army.
Output
A single integer number, the weakness of the Roman army.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d).
Examples
Input
3
3 2 1
Output
1
Input
3
2 3 1
Output
0
Input
4
10 8 3 1
Output
4
Input
4
1 5 4 3
Output
1
Submitted Solution:
```
mV = 20
def update(i, v, t):
while i < mV:
if i not in t:
t[i] = 1
else:
t[i] += v
i += (i & -i)
def getSum(i, t):
s = 0
while i > 0:
if i not in t:
s += 0
else:
s += t[i]
i -= (i & -i)
return s
n = int(input())
a = input().split(' ')
def main():
# n = 4
# a = ['10', '8', '3', '1']
j = 1
lr = []
lrt = {}
for i in a:
update(int(i), 1, lrt)
lr.append(j - getSum(int(i), lrt))
j += 1
ans = 0
rlt = {}
for i in range(n - 1, -1, -1):
update(int(a[i]), 1, rlt)
ans += (lr[i] * (getSum(int(a[i]), rlt) - 1))
print(ans)
main()
``` | instruction | 0 | 81,256 | 2 | 162,512 |
No | output | 1 | 81,256 | 2 | 162,513 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Romans have attacked again. This time they are much more than the Persians but Shapur is ready to defeat them. He says: "A lion is never afraid of a hundred sheep".
Nevertheless Shapur has to find weaknesses in the Roman army to defeat them. So he gives the army a weakness number.
In Shapur's opinion the weakness of an army is equal to the number of triplets i, j, k such that i < j < k and ai > aj > ak where ax is the power of man standing at position x. The Roman army has one special trait β powers of all the people in it are distinct.
Help Shapur find out how weak the Romans are.
Input
The first line of input contains a single number n (3 β€ n β€ 106) β the number of men in Roman army. Next line contains n different positive integers ai (1 β€ i β€ n, 1 β€ ai β€ 109) β powers of men in the Roman army.
Output
A single integer number, the weakness of the Roman army.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d).
Examples
Input
3
3 2 1
Output
1
Input
3
2 3 1
Output
0
Input
4
10 8 3 1
Output
4
Input
4
1 5 4 3
Output
1
Submitted Solution:
```
n = int(input())
l = list(map(int,input().split(' ')))
nb = 0
for i in range(n):
for j in range(i+1,n):
if l[i]<=l[j]:
break
for k in range(j+1,n):
if l[k]<l[j]:
nb += 1
print(nb)
``` | instruction | 0 | 81,257 | 2 | 162,514 |
No | output | 1 | 81,257 | 2 | 162,515 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Romans have attacked again. This time they are much more than the Persians but Shapur is ready to defeat them. He says: "A lion is never afraid of a hundred sheep".
Nevertheless Shapur has to find weaknesses in the Roman army to defeat them. So he gives the army a weakness number.
In Shapur's opinion the weakness of an army is equal to the number of triplets i, j, k such that i < j < k and ai > aj > ak where ax is the power of man standing at position x. The Roman army has one special trait β powers of all the people in it are distinct.
Help Shapur find out how weak the Romans are.
Input
The first line of input contains a single number n (3 β€ n β€ 106) β the number of men in Roman army. Next line contains n different positive integers ai (1 β€ i β€ n, 1 β€ ai β€ 109) β powers of men in the Roman army.
Output
A single integer number, the weakness of the Roman army.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d).
Examples
Input
3
3 2 1
Output
1
Input
3
2 3 1
Output
0
Input
4
10 8 3 1
Output
4
Input
4
1 5 4 3
Output
1
Submitted Solution:
```
# 61E
import sys
class BIT():
def __init__(self, n):
self.n = n
self.tree = [0] * n
def _F(self, i):
return i & (i + 1)
def _get_sum(self, r):
'''
sum on interval [0, r]
'''
result = 0
while r >= 0:
result += self.tree[r]
r = self._F(r) - 1
return result
def get_sum(self, l, r):
'''
sum on interval [l, r]
'''
return self._get_sum(r) - self._get_sum(l - 1)
def _H(self, i):
return i | (i + 1)
def add(self, i, value=1):
while i < self.n:
self.tree[i] += value
i = self._H(i)
# inf = open('input.txt', 'r')
# reader = (line.rstrip() for line in inf)
reader = (line.rstrip() for line in sys.stdin)
input = reader.__next__
n = int(input())
A = list(map(int, input().split()))
# inf.close()
a = [(val, i) for i, val in enumerate(A)]
a.sort()
for comp, (val, i) in enumerate(a):
A[i] = n - comp - 1
print(A)
met = BIT(n)
metPairs = BIT(n)
ans = 0
for i in A:
ans += metPairs.get_sum(0, i-1)
met.add(i, 1)
less = met.get_sum(0, i-1)
metPairs.add(i, less)
print(ans)
``` | instruction | 0 | 81,258 | 2 | 162,516 |
No | output | 1 | 81,258 | 2 | 162,517 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Romans have attacked again. This time they are much more than the Persians but Shapur is ready to defeat them. He says: "A lion is never afraid of a hundred sheep".
Nevertheless Shapur has to find weaknesses in the Roman army to defeat them. So he gives the army a weakness number.
In Shapur's opinion the weakness of an army is equal to the number of triplets i, j, k such that i < j < k and ai > aj > ak where ax is the power of man standing at position x. The Roman army has one special trait β powers of all the people in it are distinct.
Help Shapur find out how weak the Romans are.
Input
The first line of input contains a single number n (3 β€ n β€ 106) β the number of men in Roman army. Next line contains n different positive integers ai (1 β€ i β€ n, 1 β€ ai β€ 109) β powers of men in the Roman army.
Output
A single integer number, the weakness of the Roman army.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d).
Examples
Input
3
3 2 1
Output
1
Input
3
2 3 1
Output
0
Input
4
10 8 3 1
Output
4
Input
4
1 5 4 3
Output
1
Submitted Solution:
```
l=int(input())
m=list(map(int,input().split()))
i=0
j=1
k=2
c=0
while(True):
if (k==l-1):
break
if (m[i]>m[j]>m[k]):
c+=1
i+=1
j+=1
k+=1
print(c)
``` | instruction | 0 | 81,259 | 2 | 162,518 |
No | output | 1 | 81,259 | 2 | 162,519 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ivar the Boneless is a great leader. He is trying to capture Kattegat from Lagertha. The war has begun and wave after wave Ivar's warriors are falling in battle.
Ivar has n warriors, he places them on a straight line in front of the main gate, in a way that the i-th warrior stands right after (i-1)-th warrior. The first warrior leads the attack.
Each attacker can take up to a_i arrows before he falls to the ground, where a_i is the i-th warrior's strength.
Lagertha orders her warriors to shoot k_i arrows during the i-th minute, the arrows one by one hit the first still standing warrior. After all Ivar's warriors fall and all the currently flying arrows fly by, Thor smashes his hammer and all Ivar's warriors get their previous strengths back and stand up to fight again. In other words, if all warriors die in minute t, they will all be standing to fight at the end of minute t.
The battle will last for q minutes, after each minute you should tell Ivar what is the number of his standing warriors.
Input
The first line contains two integers n and q (1 β€ n, q β€ 200 000) β the number of warriors and the number of minutes in the battle.
The second line contains n integers a_1, a_2, β¦, a_n (1 β€ a_i β€ 10^9) that represent the warriors' strengths.
The third line contains q integers k_1, k_2, β¦, k_q (1 β€ k_i β€ 10^{14}), the i-th of them represents Lagertha's order at the i-th minute: k_i arrows will attack the warriors.
Output
Output q lines, the i-th of them is the number of standing warriors after the i-th minute.
Examples
Input
5 5
1 2 1 2 1
3 10 1 1 1
Output
3
5
4
4
3
Input
4 4
1 2 3 4
9 1 10 6
Output
1
4
4
1
Note
In the first example:
* after the 1-st minute, the 1-st and 2-nd warriors die.
* after the 2-nd minute all warriors die (and all arrows left over are wasted), then they will be revived thus answer is 5 β all warriors are alive.
* after the 3-rd minute, the 1-st warrior dies.
* after the 4-th minute, the 2-nd warrior takes a hit and his strength decreases by 1.
* after the 5-th minute, the 2-nd warrior dies. | instruction | 0 | 81,410 | 2 | 162,820 |
Tags: binary search
Correct Solution:
```
from bisect import bisect as bs
n, q = map(int, input().split())
a = list(map(int, input().split()))
k = list(map(int, input().split()))
tmp = 0
sumA = []
for i in range(n):
tmp += a[i]
sumA.append(tmp)
# print(sumA)
def bin_search(left, right, v):
if left > right:
return left
mid = (left + right) // 2
if sumA[mid] == v:
return mid
elif sumA[mid] < v:
return bin_search(mid+1, right, v)
else:
return bin_search(left, mid-1, v)
now = 0
ansList = []
for i in range(q):
now += k[i]
ans_id = bs(sumA, now)
if ans_id == n:
now = 0
ans_id = 0
ansList.append(n-ans_id)
print("\n".join(map(str, ansList)))
``` | output | 1 | 81,410 | 2 | 162,821 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ivar the Boneless is a great leader. He is trying to capture Kattegat from Lagertha. The war has begun and wave after wave Ivar's warriors are falling in battle.
Ivar has n warriors, he places them on a straight line in front of the main gate, in a way that the i-th warrior stands right after (i-1)-th warrior. The first warrior leads the attack.
Each attacker can take up to a_i arrows before he falls to the ground, where a_i is the i-th warrior's strength.
Lagertha orders her warriors to shoot k_i arrows during the i-th minute, the arrows one by one hit the first still standing warrior. After all Ivar's warriors fall and all the currently flying arrows fly by, Thor smashes his hammer and all Ivar's warriors get their previous strengths back and stand up to fight again. In other words, if all warriors die in minute t, they will all be standing to fight at the end of minute t.
The battle will last for q minutes, after each minute you should tell Ivar what is the number of his standing warriors.
Input
The first line contains two integers n and q (1 β€ n, q β€ 200 000) β the number of warriors and the number of minutes in the battle.
The second line contains n integers a_1, a_2, β¦, a_n (1 β€ a_i β€ 10^9) that represent the warriors' strengths.
The third line contains q integers k_1, k_2, β¦, k_q (1 β€ k_i β€ 10^{14}), the i-th of them represents Lagertha's order at the i-th minute: k_i arrows will attack the warriors.
Output
Output q lines, the i-th of them is the number of standing warriors after the i-th minute.
Examples
Input
5 5
1 2 1 2 1
3 10 1 1 1
Output
3
5
4
4
3
Input
4 4
1 2 3 4
9 1 10 6
Output
1
4
4
1
Note
In the first example:
* after the 1-st minute, the 1-st and 2-nd warriors die.
* after the 2-nd minute all warriors die (and all arrows left over are wasted), then they will be revived thus answer is 5 β all warriors are alive.
* after the 3-rd minute, the 1-st warrior dies.
* after the 4-th minute, the 2-nd warrior takes a hit and his strength decreases by 1.
* after the 5-th minute, the 2-nd warrior dies. | instruction | 0 | 81,411 | 2 | 162,822 |
Tags: binary search
Correct Solution:
```
from bisect import bisect
n,t=map(int,input().split())
a=list(map(int,input().split()))
k=list(map(int,input().split()))
arr=[]
s=0
b=n
for i in a:
s+=i
arr.append(s)
ar=arr.copy()
s=0
for i in k:
s+=i
j=bisect(ar,s)
if j==n:
s=0
j=0
print(n-j)
``` | output | 1 | 81,411 | 2 | 162,823 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ivar the Boneless is a great leader. He is trying to capture Kattegat from Lagertha. The war has begun and wave after wave Ivar's warriors are falling in battle.
Ivar has n warriors, he places them on a straight line in front of the main gate, in a way that the i-th warrior stands right after (i-1)-th warrior. The first warrior leads the attack.
Each attacker can take up to a_i arrows before he falls to the ground, where a_i is the i-th warrior's strength.
Lagertha orders her warriors to shoot k_i arrows during the i-th minute, the arrows one by one hit the first still standing warrior. After all Ivar's warriors fall and all the currently flying arrows fly by, Thor smashes his hammer and all Ivar's warriors get their previous strengths back and stand up to fight again. In other words, if all warriors die in minute t, they will all be standing to fight at the end of minute t.
The battle will last for q minutes, after each minute you should tell Ivar what is the number of his standing warriors.
Input
The first line contains two integers n and q (1 β€ n, q β€ 200 000) β the number of warriors and the number of minutes in the battle.
The second line contains n integers a_1, a_2, β¦, a_n (1 β€ a_i β€ 10^9) that represent the warriors' strengths.
The third line contains q integers k_1, k_2, β¦, k_q (1 β€ k_i β€ 10^{14}), the i-th of them represents Lagertha's order at the i-th minute: k_i arrows will attack the warriors.
Output
Output q lines, the i-th of them is the number of standing warriors after the i-th minute.
Examples
Input
5 5
1 2 1 2 1
3 10 1 1 1
Output
3
5
4
4
3
Input
4 4
1 2 3 4
9 1 10 6
Output
1
4
4
1
Note
In the first example:
* after the 1-st minute, the 1-st and 2-nd warriors die.
* after the 2-nd minute all warriors die (and all arrows left over are wasted), then they will be revived thus answer is 5 β all warriors are alive.
* after the 3-rd minute, the 1-st warrior dies.
* after the 4-th minute, the 2-nd warrior takes a hit and his strength decreases by 1.
* after the 5-th minute, the 2-nd warrior dies. | instruction | 0 | 81,412 | 2 | 162,824 |
Tags: binary search
Correct Solution:
```
# Link: https://codeforces.com/problemset/problem/975/C
def binarySearch(power, arr):
low, high = 0, len(arr) - 1
ans = -1
while low <= high:
mid = (low + high) // 2
if arr[mid] <= power:
ans = mid
low = mid + 1
else:
high = mid - 1
return ans
n, q = map(int, input().split())
arr = list(map(int, input().split()))
k = list(map(int, input().split()))
# prefix array
for i in range(1, n):
arr[i] += arr[i-1]
power = 0
for i in range(q):
power += k[i]
index = binarySearch(power, arr)
# If end index is returned that means all warriors have died
# So according to question we have to get their previous strengths back and fight again.
if index == n - 1:
print(n)
power = 0
# -1 means that the arrows of lagertha's warriors are not enough to kill the warriors of IVAR THE BONELESS.
elif index == -1:
print(n)
# Just print the remaining warriors
else:
print(n-index-1)
``` | output | 1 | 81,412 | 2 | 162,825 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ivar the Boneless is a great leader. He is trying to capture Kattegat from Lagertha. The war has begun and wave after wave Ivar's warriors are falling in battle.
Ivar has n warriors, he places them on a straight line in front of the main gate, in a way that the i-th warrior stands right after (i-1)-th warrior. The first warrior leads the attack.
Each attacker can take up to a_i arrows before he falls to the ground, where a_i is the i-th warrior's strength.
Lagertha orders her warriors to shoot k_i arrows during the i-th minute, the arrows one by one hit the first still standing warrior. After all Ivar's warriors fall and all the currently flying arrows fly by, Thor smashes his hammer and all Ivar's warriors get their previous strengths back and stand up to fight again. In other words, if all warriors die in minute t, they will all be standing to fight at the end of minute t.
The battle will last for q minutes, after each minute you should tell Ivar what is the number of his standing warriors.
Input
The first line contains two integers n and q (1 β€ n, q β€ 200 000) β the number of warriors and the number of minutes in the battle.
The second line contains n integers a_1, a_2, β¦, a_n (1 β€ a_i β€ 10^9) that represent the warriors' strengths.
The third line contains q integers k_1, k_2, β¦, k_q (1 β€ k_i β€ 10^{14}), the i-th of them represents Lagertha's order at the i-th minute: k_i arrows will attack the warriors.
Output
Output q lines, the i-th of them is the number of standing warriors after the i-th minute.
Examples
Input
5 5
1 2 1 2 1
3 10 1 1 1
Output
3
5
4
4
3
Input
4 4
1 2 3 4
9 1 10 6
Output
1
4
4
1
Note
In the first example:
* after the 1-st minute, the 1-st and 2-nd warriors die.
* after the 2-nd minute all warriors die (and all arrows left over are wasted), then they will be revived thus answer is 5 β all warriors are alive.
* after the 3-rd minute, the 1-st warrior dies.
* after the 4-th minute, the 2-nd warrior takes a hit and his strength decreases by 1.
* after the 5-th minute, the 2-nd warrior dies. | instruction | 0 | 81,413 | 2 | 162,826 |
Tags: binary search
Correct Solution:
```
def search(arr,low,high,val):
while(low<=high):
mid=low+(high-low)//2
if(arr[mid]>=val):
high=mid-1
else:
low=mid+1
return low
n,m=map(int,input().split())
l=list(map(int,input().split()))
q=list(map(int,input().split()))
for i in range(1,len(l)):
l[i]+=l[i-1]
val=0
k=l[-1]
a,b=min(l),max(l)
for i in q:
val+=i
if(val>=l[-1]):
print(n)
val=0
else:
pos=search(l,0,len(l)-1,val)
if(l[pos]==val):
print((n-pos-1))
else:
print(n-pos)
``` | output | 1 | 81,413 | 2 | 162,827 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ivar the Boneless is a great leader. He is trying to capture Kattegat from Lagertha. The war has begun and wave after wave Ivar's warriors are falling in battle.
Ivar has n warriors, he places them on a straight line in front of the main gate, in a way that the i-th warrior stands right after (i-1)-th warrior. The first warrior leads the attack.
Each attacker can take up to a_i arrows before he falls to the ground, where a_i is the i-th warrior's strength.
Lagertha orders her warriors to shoot k_i arrows during the i-th minute, the arrows one by one hit the first still standing warrior. After all Ivar's warriors fall and all the currently flying arrows fly by, Thor smashes his hammer and all Ivar's warriors get their previous strengths back and stand up to fight again. In other words, if all warriors die in minute t, they will all be standing to fight at the end of minute t.
The battle will last for q minutes, after each minute you should tell Ivar what is the number of his standing warriors.
Input
The first line contains two integers n and q (1 β€ n, q β€ 200 000) β the number of warriors and the number of minutes in the battle.
The second line contains n integers a_1, a_2, β¦, a_n (1 β€ a_i β€ 10^9) that represent the warriors' strengths.
The third line contains q integers k_1, k_2, β¦, k_q (1 β€ k_i β€ 10^{14}), the i-th of them represents Lagertha's order at the i-th minute: k_i arrows will attack the warriors.
Output
Output q lines, the i-th of them is the number of standing warriors after the i-th minute.
Examples
Input
5 5
1 2 1 2 1
3 10 1 1 1
Output
3
5
4
4
3
Input
4 4
1 2 3 4
9 1 10 6
Output
1
4
4
1
Note
In the first example:
* after the 1-st minute, the 1-st and 2-nd warriors die.
* after the 2-nd minute all warriors die (and all arrows left over are wasted), then they will be revived thus answer is 5 β all warriors are alive.
* after the 3-rd minute, the 1-st warrior dies.
* after the 4-th minute, the 2-nd warrior takes a hit and his strength decreases by 1.
* after the 5-th minute, the 2-nd warrior dies. | instruction | 0 | 81,414 | 2 | 162,828 |
Tags: binary search
Correct Solution:
```
import sys
import math
MAXNUM = math.inf
MINNUM = -1 * math.inf
ASCIILOWER = 97
ASCIIUPPER = 65
def getInt():
return int(sys.stdin.readline().rstrip())
def getInts():
return map(int, sys.stdin.readline().rstrip().split(" "))
def getString():
return sys.stdin.readline().rstrip()
def printOutput(ans):
sys.stdout.write()
pass
def binsearch(strlist, health):
#print('binhealth',health)
l = 0
r = len(strlist) - 1
ans = None
while l <= r:
m = (l + r) // 2
if strlist[m][0] <= health:
ans = m
l = m + 1
else:
r = m - 1
return strlist[ans][1]
def solve(n, q, strengths, orders):
totalstrength = sum(strengths)
curs = totalstrength
strlist = [(totalstrength - strengths[0] + 1, len(strengths))]
for i in range(1, len(strengths)):
strlist.append((strlist[-1][0] - strengths[i], strlist[-1][1] - 1))
strlist.sort()
#print(strlist)
health = totalstrength
for q in orders:
health -= q
#print('health', health)
if health <= 0:
health = totalstrength
print(n)
else:
print(binsearch(strlist, health))
#print(strlist)
def readinput():
n, q = getInts()
strengths = list(getInts())
orders = list(getInts())
solve(n, q, strengths, orders)
readinput()
``` | output | 1 | 81,414 | 2 | 162,829 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ivar the Boneless is a great leader. He is trying to capture Kattegat from Lagertha. The war has begun and wave after wave Ivar's warriors are falling in battle.
Ivar has n warriors, he places them on a straight line in front of the main gate, in a way that the i-th warrior stands right after (i-1)-th warrior. The first warrior leads the attack.
Each attacker can take up to a_i arrows before he falls to the ground, where a_i is the i-th warrior's strength.
Lagertha orders her warriors to shoot k_i arrows during the i-th minute, the arrows one by one hit the first still standing warrior. After all Ivar's warriors fall and all the currently flying arrows fly by, Thor smashes his hammer and all Ivar's warriors get their previous strengths back and stand up to fight again. In other words, if all warriors die in minute t, they will all be standing to fight at the end of minute t.
The battle will last for q minutes, after each minute you should tell Ivar what is the number of his standing warriors.
Input
The first line contains two integers n and q (1 β€ n, q β€ 200 000) β the number of warriors and the number of minutes in the battle.
The second line contains n integers a_1, a_2, β¦, a_n (1 β€ a_i β€ 10^9) that represent the warriors' strengths.
The third line contains q integers k_1, k_2, β¦, k_q (1 β€ k_i β€ 10^{14}), the i-th of them represents Lagertha's order at the i-th minute: k_i arrows will attack the warriors.
Output
Output q lines, the i-th of them is the number of standing warriors after the i-th minute.
Examples
Input
5 5
1 2 1 2 1
3 10 1 1 1
Output
3
5
4
4
3
Input
4 4
1 2 3 4
9 1 10 6
Output
1
4
4
1
Note
In the first example:
* after the 1-st minute, the 1-st and 2-nd warriors die.
* after the 2-nd minute all warriors die (and all arrows left over are wasted), then they will be revived thus answer is 5 β all warriors are alive.
* after the 3-rd minute, the 1-st warrior dies.
* after the 4-th minute, the 2-nd warrior takes a hit and his strength decreases by 1.
* after the 5-th minute, the 2-nd warrior dies. | instruction | 0 | 81,415 | 2 | 162,830 |
Tags: binary search
Correct Solution:
```
import sys
import os
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
n,q = map(int,input().split())
strength = [0]
for x in map(int,input().split()):
strength.append(strength[-1] + x)
arrows = list(map(int,input().split()))
fallen = 0
standing = n
final = []
for i in range(q):
ans = -1
l = 1
r = n
while l <= r:
mid = l + (r-l)//2
if strength[mid]-fallen-arrows[i]>0:
ans = mid
r = mid-1
else:
l = mid+1
if ans == -1:
fallen = 0
final.append(n)
else:
fallen += arrows[i]
final.append(n-ans+1)
print(*final,sep='\n')
``` | output | 1 | 81,415 | 2 | 162,831 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ivar the Boneless is a great leader. He is trying to capture Kattegat from Lagertha. The war has begun and wave after wave Ivar's warriors are falling in battle.
Ivar has n warriors, he places them on a straight line in front of the main gate, in a way that the i-th warrior stands right after (i-1)-th warrior. The first warrior leads the attack.
Each attacker can take up to a_i arrows before he falls to the ground, where a_i is the i-th warrior's strength.
Lagertha orders her warriors to shoot k_i arrows during the i-th minute, the arrows one by one hit the first still standing warrior. After all Ivar's warriors fall and all the currently flying arrows fly by, Thor smashes his hammer and all Ivar's warriors get their previous strengths back and stand up to fight again. In other words, if all warriors die in minute t, they will all be standing to fight at the end of minute t.
The battle will last for q minutes, after each minute you should tell Ivar what is the number of his standing warriors.
Input
The first line contains two integers n and q (1 β€ n, q β€ 200 000) β the number of warriors and the number of minutes in the battle.
The second line contains n integers a_1, a_2, β¦, a_n (1 β€ a_i β€ 10^9) that represent the warriors' strengths.
The third line contains q integers k_1, k_2, β¦, k_q (1 β€ k_i β€ 10^{14}), the i-th of them represents Lagertha's order at the i-th minute: k_i arrows will attack the warriors.
Output
Output q lines, the i-th of them is the number of standing warriors after the i-th minute.
Examples
Input
5 5
1 2 1 2 1
3 10 1 1 1
Output
3
5
4
4
3
Input
4 4
1 2 3 4
9 1 10 6
Output
1
4
4
1
Note
In the first example:
* after the 1-st minute, the 1-st and 2-nd warriors die.
* after the 2-nd minute all warriors die (and all arrows left over are wasted), then they will be revived thus answer is 5 β all warriors are alive.
* after the 3-rd minute, the 1-st warrior dies.
* after the 4-th minute, the 2-nd warrior takes a hit and his strength decreases by 1.
* after the 5-th minute, the 2-nd warrior dies. | instruction | 0 | 81,416 | 2 | 162,832 |
Tags: binary search
Correct Solution:
```
I=lambda:map(int,input().split())
from bisect import bisect_left as bl
n,q=I()
a=list(I())
b=list(I())
c=[];m=0
for i in a:
m+=i;c.append(m)
m=0
for i in range(q):
k=bl(c,b[i]+m)
if k==len(c) or b[i]+m==c[-1]:
print(n)
m=0
continue
elif c[k]==b[i]+m:
m+=b[i]
print(n-k-1)
else:
m+=b[i]
print(n-k)
``` | output | 1 | 81,416 | 2 | 162,833 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ivar the Boneless is a great leader. He is trying to capture Kattegat from Lagertha. The war has begun and wave after wave Ivar's warriors are falling in battle.
Ivar has n warriors, he places them on a straight line in front of the main gate, in a way that the i-th warrior stands right after (i-1)-th warrior. The first warrior leads the attack.
Each attacker can take up to a_i arrows before he falls to the ground, where a_i is the i-th warrior's strength.
Lagertha orders her warriors to shoot k_i arrows during the i-th minute, the arrows one by one hit the first still standing warrior. After all Ivar's warriors fall and all the currently flying arrows fly by, Thor smashes his hammer and all Ivar's warriors get their previous strengths back and stand up to fight again. In other words, if all warriors die in minute t, they will all be standing to fight at the end of minute t.
The battle will last for q minutes, after each minute you should tell Ivar what is the number of his standing warriors.
Input
The first line contains two integers n and q (1 β€ n, q β€ 200 000) β the number of warriors and the number of minutes in the battle.
The second line contains n integers a_1, a_2, β¦, a_n (1 β€ a_i β€ 10^9) that represent the warriors' strengths.
The third line contains q integers k_1, k_2, β¦, k_q (1 β€ k_i β€ 10^{14}), the i-th of them represents Lagertha's order at the i-th minute: k_i arrows will attack the warriors.
Output
Output q lines, the i-th of them is the number of standing warriors after the i-th minute.
Examples
Input
5 5
1 2 1 2 1
3 10 1 1 1
Output
3
5
4
4
3
Input
4 4
1 2 3 4
9 1 10 6
Output
1
4
4
1
Note
In the first example:
* after the 1-st minute, the 1-st and 2-nd warriors die.
* after the 2-nd minute all warriors die (and all arrows left over are wasted), then they will be revived thus answer is 5 β all warriors are alive.
* after the 3-rd minute, the 1-st warrior dies.
* after the 4-th minute, the 2-nd warrior takes a hit and his strength decreases by 1.
* after the 5-th minute, the 2-nd warrior dies. | instruction | 0 | 81,417 | 2 | 162,834 |
Tags: binary search
Correct Solution:
```
import os
import sys
from io import BytesIO, IOBase
from collections import Counter
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
def gcd(a, b):
if a == 0:
return b
return gcd(b % a, a)
def lcm(a, b):
return (a * b) / gcd(a, b)
def main():
n,q=map(int, input().split())
t=list(map(int, input().split()))
k=list(map(int , input().split()))
a=[t[0]]
for i in range(1,n):
a.append(a[i-1]+t[i])
now=0
for i in range(q):
now+=k[i]
if now>=a[n-1]:
now=0
print(n)
else:
l=0
r=n-1
ans=n
while l<=r:
mid=(l+r)//2
if now>=a[mid]:
ans=min(ans, n-1-mid)
l=mid+1
else:
r=mid-1
print(ans)
return
if __name__ == "__main__":
main()
``` | output | 1 | 81,417 | 2 | 162,835 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ivar the Boneless is a great leader. He is trying to capture Kattegat from Lagertha. The war has begun and wave after wave Ivar's warriors are falling in battle.
Ivar has n warriors, he places them on a straight line in front of the main gate, in a way that the i-th warrior stands right after (i-1)-th warrior. The first warrior leads the attack.
Each attacker can take up to a_i arrows before he falls to the ground, where a_i is the i-th warrior's strength.
Lagertha orders her warriors to shoot k_i arrows during the i-th minute, the arrows one by one hit the first still standing warrior. After all Ivar's warriors fall and all the currently flying arrows fly by, Thor smashes his hammer and all Ivar's warriors get their previous strengths back and stand up to fight again. In other words, if all warriors die in minute t, they will all be standing to fight at the end of minute t.
The battle will last for q minutes, after each minute you should tell Ivar what is the number of his standing warriors.
Input
The first line contains two integers n and q (1 β€ n, q β€ 200 000) β the number of warriors and the number of minutes in the battle.
The second line contains n integers a_1, a_2, β¦, a_n (1 β€ a_i β€ 10^9) that represent the warriors' strengths.
The third line contains q integers k_1, k_2, β¦, k_q (1 β€ k_i β€ 10^{14}), the i-th of them represents Lagertha's order at the i-th minute: k_i arrows will attack the warriors.
Output
Output q lines, the i-th of them is the number of standing warriors after the i-th minute.
Examples
Input
5 5
1 2 1 2 1
3 10 1 1 1
Output
3
5
4
4
3
Input
4 4
1 2 3 4
9 1 10 6
Output
1
4
4
1
Note
In the first example:
* after the 1-st minute, the 1-st and 2-nd warriors die.
* after the 2-nd minute all warriors die (and all arrows left over are wasted), then they will be revived thus answer is 5 β all warriors are alive.
* after the 3-rd minute, the 1-st warrior dies.
* after the 4-th minute, the 2-nd warrior takes a hit and his strength decreases by 1.
* after the 5-th minute, the 2-nd warrior dies.
Submitted Solution:
```
n, q = list(map(int, input().split()))
soldiers = list(map(int, input().split()))
arrows = list(map(int, input().split()))
soldier_sum = [0]
for soldier in soldiers:
soldier_sum.append(soldier_sum[-1] + soldier)
soldier_sum.append(10**16)
# 0 1 3 4 6 7
current_pos = 1
damage_carried_over = 0
for arrow in arrows:
# print(current_pos, arrow, damage_carried_over)
arrow += damage_carried_over
l, r = current_pos, len(soldier_sum) - 1
res = None
while l <= r:
mid = (l + r) // 2
if soldier_sum[mid] - soldier_sum[current_pos - 1] > arrow:
res = mid
r = mid - 1
else:
l = mid + 1
damage_carried_over = arrow - (soldier_sum[res - 1] - soldier_sum[current_pos - 1])
current_pos = res
if current_pos == len(soldier_sum) - 1:
current_pos = 1
damage_carried_over = 0
# print('reset')
print(len(soldiers) + 1 - current_pos)
``` | instruction | 0 | 81,418 | 2 | 162,836 |
Yes | output | 1 | 81,418 | 2 | 162,837 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ivar the Boneless is a great leader. He is trying to capture Kattegat from Lagertha. The war has begun and wave after wave Ivar's warriors are falling in battle.
Ivar has n warriors, he places them on a straight line in front of the main gate, in a way that the i-th warrior stands right after (i-1)-th warrior. The first warrior leads the attack.
Each attacker can take up to a_i arrows before he falls to the ground, where a_i is the i-th warrior's strength.
Lagertha orders her warriors to shoot k_i arrows during the i-th minute, the arrows one by one hit the first still standing warrior. After all Ivar's warriors fall and all the currently flying arrows fly by, Thor smashes his hammer and all Ivar's warriors get their previous strengths back and stand up to fight again. In other words, if all warriors die in minute t, they will all be standing to fight at the end of minute t.
The battle will last for q minutes, after each minute you should tell Ivar what is the number of his standing warriors.
Input
The first line contains two integers n and q (1 β€ n, q β€ 200 000) β the number of warriors and the number of minutes in the battle.
The second line contains n integers a_1, a_2, β¦, a_n (1 β€ a_i β€ 10^9) that represent the warriors' strengths.
The third line contains q integers k_1, k_2, β¦, k_q (1 β€ k_i β€ 10^{14}), the i-th of them represents Lagertha's order at the i-th minute: k_i arrows will attack the warriors.
Output
Output q lines, the i-th of them is the number of standing warriors after the i-th minute.
Examples
Input
5 5
1 2 1 2 1
3 10 1 1 1
Output
3
5
4
4
3
Input
4 4
1 2 3 4
9 1 10 6
Output
1
4
4
1
Note
In the first example:
* after the 1-st minute, the 1-st and 2-nd warriors die.
* after the 2-nd minute all warriors die (and all arrows left over are wasted), then they will be revived thus answer is 5 β all warriors are alive.
* after the 3-rd minute, the 1-st warrior dies.
* after the 4-th minute, the 2-nd warrior takes a hit and his strength decreases by 1.
* after the 5-th minute, the 2-nd warrior dies.
Submitted Solution:
```
import bisect
n,q = map(int,input().split())
a = list(map(int,input().split()))
b = list(map(int,input().split()))
for i in range(1,n):
a[i]+=a[i-1]
surplus = 0
for i in range(q):
pos = bisect.bisect_right(a,b[i]+surplus)
if pos>=n:
pos = 0
surplus = 0
else:
surplus+= b[i]
print(n-pos)
``` | instruction | 0 | 81,419 | 2 | 162,838 |
Yes | output | 1 | 81,419 | 2 | 162,839 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ivar the Boneless is a great leader. He is trying to capture Kattegat from Lagertha. The war has begun and wave after wave Ivar's warriors are falling in battle.
Ivar has n warriors, he places them on a straight line in front of the main gate, in a way that the i-th warrior stands right after (i-1)-th warrior. The first warrior leads the attack.
Each attacker can take up to a_i arrows before he falls to the ground, where a_i is the i-th warrior's strength.
Lagertha orders her warriors to shoot k_i arrows during the i-th minute, the arrows one by one hit the first still standing warrior. After all Ivar's warriors fall and all the currently flying arrows fly by, Thor smashes his hammer and all Ivar's warriors get their previous strengths back and stand up to fight again. In other words, if all warriors die in minute t, they will all be standing to fight at the end of minute t.
The battle will last for q minutes, after each minute you should tell Ivar what is the number of his standing warriors.
Input
The first line contains two integers n and q (1 β€ n, q β€ 200 000) β the number of warriors and the number of minutes in the battle.
The second line contains n integers a_1, a_2, β¦, a_n (1 β€ a_i β€ 10^9) that represent the warriors' strengths.
The third line contains q integers k_1, k_2, β¦, k_q (1 β€ k_i β€ 10^{14}), the i-th of them represents Lagertha's order at the i-th minute: k_i arrows will attack the warriors.
Output
Output q lines, the i-th of them is the number of standing warriors after the i-th minute.
Examples
Input
5 5
1 2 1 2 1
3 10 1 1 1
Output
3
5
4
4
3
Input
4 4
1 2 3 4
9 1 10 6
Output
1
4
4
1
Note
In the first example:
* after the 1-st minute, the 1-st and 2-nd warriors die.
* after the 2-nd minute all warriors die (and all arrows left over are wasted), then they will be revived thus answer is 5 β all warriors are alive.
* after the 3-rd minute, the 1-st warrior dies.
* after the 4-th minute, the 2-nd warrior takes a hit and his strength decreases by 1.
* after the 5-th minute, the 2-nd warrior dies.
Submitted Solution:
```
n,q=map(int,input().split())
a=list(map(int,input().split()))
a.insert(0,0)
k=list(map(int,input().split()))
j,g=0,0
for i in range(1,n+1) :
a[i]=a[i]+a[i-1]
while q > 0 :
g=g+k[j]
r,l,h=-1,0,n
while l<=h :
m=(l+h)//2
if g >= a[m] :
res=m
l=m+1
else :
h=m-1
if res==n :
res=0
g=0
print(n-res)
j+=1
q-=1
``` | instruction | 0 | 81,420 | 2 | 162,840 |
Yes | output | 1 | 81,420 | 2 | 162,841 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ivar the Boneless is a great leader. He is trying to capture Kattegat from Lagertha. The war has begun and wave after wave Ivar's warriors are falling in battle.
Ivar has n warriors, he places them on a straight line in front of the main gate, in a way that the i-th warrior stands right after (i-1)-th warrior. The first warrior leads the attack.
Each attacker can take up to a_i arrows before he falls to the ground, where a_i is the i-th warrior's strength.
Lagertha orders her warriors to shoot k_i arrows during the i-th minute, the arrows one by one hit the first still standing warrior. After all Ivar's warriors fall and all the currently flying arrows fly by, Thor smashes his hammer and all Ivar's warriors get their previous strengths back and stand up to fight again. In other words, if all warriors die in minute t, they will all be standing to fight at the end of minute t.
The battle will last for q minutes, after each minute you should tell Ivar what is the number of his standing warriors.
Input
The first line contains two integers n and q (1 β€ n, q β€ 200 000) β the number of warriors and the number of minutes in the battle.
The second line contains n integers a_1, a_2, β¦, a_n (1 β€ a_i β€ 10^9) that represent the warriors' strengths.
The third line contains q integers k_1, k_2, β¦, k_q (1 β€ k_i β€ 10^{14}), the i-th of them represents Lagertha's order at the i-th minute: k_i arrows will attack the warriors.
Output
Output q lines, the i-th of them is the number of standing warriors after the i-th minute.
Examples
Input
5 5
1 2 1 2 1
3 10 1 1 1
Output
3
5
4
4
3
Input
4 4
1 2 3 4
9 1 10 6
Output
1
4
4
1
Note
In the first example:
* after the 1-st minute, the 1-st and 2-nd warriors die.
* after the 2-nd minute all warriors die (and all arrows left over are wasted), then they will be revived thus answer is 5 β all warriors are alive.
* after the 3-rd minute, the 1-st warrior dies.
* after the 4-th minute, the 2-nd warrior takes a hit and his strength decreases by 1.
* after the 5-th minute, the 2-nd warrior dies.
Submitted Solution:
```
#!/usr/bin/env python3
import bisect
[n, q] = map(int, input().strip().split())
ais = list(map(int, input().strip().split()))
kis = list(map(int, input().strip().split()))
iais = [0 for _ in range(n + 1)]
for i in range(n):
iais[i + 1] = iais[i] + ais[i]
s = 0
tot = iais[-1]
r = 0
for k in kis:
s += k
if s >= tot:
print (n)
s = 0
r = 0
else:
r = bisect.bisect_right(iais, s, r) - 1
print (n - r)
``` | instruction | 0 | 81,421 | 2 | 162,842 |
Yes | output | 1 | 81,421 | 2 | 162,843 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ivar the Boneless is a great leader. He is trying to capture Kattegat from Lagertha. The war has begun and wave after wave Ivar's warriors are falling in battle.
Ivar has n warriors, he places them on a straight line in front of the main gate, in a way that the i-th warrior stands right after (i-1)-th warrior. The first warrior leads the attack.
Each attacker can take up to a_i arrows before he falls to the ground, where a_i is the i-th warrior's strength.
Lagertha orders her warriors to shoot k_i arrows during the i-th minute, the arrows one by one hit the first still standing warrior. After all Ivar's warriors fall and all the currently flying arrows fly by, Thor smashes his hammer and all Ivar's warriors get their previous strengths back and stand up to fight again. In other words, if all warriors die in minute t, they will all be standing to fight at the end of minute t.
The battle will last for q minutes, after each minute you should tell Ivar what is the number of his standing warriors.
Input
The first line contains two integers n and q (1 β€ n, q β€ 200 000) β the number of warriors and the number of minutes in the battle.
The second line contains n integers a_1, a_2, β¦, a_n (1 β€ a_i β€ 10^9) that represent the warriors' strengths.
The third line contains q integers k_1, k_2, β¦, k_q (1 β€ k_i β€ 10^{14}), the i-th of them represents Lagertha's order at the i-th minute: k_i arrows will attack the warriors.
Output
Output q lines, the i-th of them is the number of standing warriors after the i-th minute.
Examples
Input
5 5
1 2 1 2 1
3 10 1 1 1
Output
3
5
4
4
3
Input
4 4
1 2 3 4
9 1 10 6
Output
1
4
4
1
Note
In the first example:
* after the 1-st minute, the 1-st and 2-nd warriors die.
* after the 2-nd minute all warriors die (and all arrows left over are wasted), then they will be revived thus answer is 5 β all warriors are alive.
* after the 3-rd minute, the 1-st warrior dies.
* after the 4-th minute, the 2-nd warrior takes a hit and his strength decreases by 1.
* after the 5-th minute, the 2-nd warrior dies.
Submitted Solution:
```
def bin_ser(arr,curr):
l=0
r=len(arr)
ans=-100
while l<=r:
mid=(l+r)//2
if arr[mid]<=curr:
ans=mid
r=mid-1
else:
l=mid+1
return ans
def main():
n,q=map(int,input().split())
arr=list(map(int,input().split()))
brr=list(map(int,input().split()))
su=sum(arr)
curr=0
for i in range(n-2,-1,-1):
arr[i]=arr[i]+arr[i+1]
for b in brr:
curr+=b
pos=bin_ser(arr,curr)
if pos==0:
pos=n
print(pos)
if curr>=su:
curr=0
main()
``` | instruction | 0 | 81,422 | 2 | 162,844 |
No | output | 1 | 81,422 | 2 | 162,845 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ivar the Boneless is a great leader. He is trying to capture Kattegat from Lagertha. The war has begun and wave after wave Ivar's warriors are falling in battle.
Ivar has n warriors, he places them on a straight line in front of the main gate, in a way that the i-th warrior stands right after (i-1)-th warrior. The first warrior leads the attack.
Each attacker can take up to a_i arrows before he falls to the ground, where a_i is the i-th warrior's strength.
Lagertha orders her warriors to shoot k_i arrows during the i-th minute, the arrows one by one hit the first still standing warrior. After all Ivar's warriors fall and all the currently flying arrows fly by, Thor smashes his hammer and all Ivar's warriors get their previous strengths back and stand up to fight again. In other words, if all warriors die in minute t, they will all be standing to fight at the end of minute t.
The battle will last for q minutes, after each minute you should tell Ivar what is the number of his standing warriors.
Input
The first line contains two integers n and q (1 β€ n, q β€ 200 000) β the number of warriors and the number of minutes in the battle.
The second line contains n integers a_1, a_2, β¦, a_n (1 β€ a_i β€ 10^9) that represent the warriors' strengths.
The third line contains q integers k_1, k_2, β¦, k_q (1 β€ k_i β€ 10^{14}), the i-th of them represents Lagertha's order at the i-th minute: k_i arrows will attack the warriors.
Output
Output q lines, the i-th of them is the number of standing warriors after the i-th minute.
Examples
Input
5 5
1 2 1 2 1
3 10 1 1 1
Output
3
5
4
4
3
Input
4 4
1 2 3 4
9 1 10 6
Output
1
4
4
1
Note
In the first example:
* after the 1-st minute, the 1-st and 2-nd warriors die.
* after the 2-nd minute all warriors die (and all arrows left over are wasted), then they will be revived thus answer is 5 β all warriors are alive.
* after the 3-rd minute, the 1-st warrior dies.
* after the 4-th minute, the 2-nd warrior takes a hit and his strength decreases by 1.
* after the 5-th minute, the 2-nd warrior dies.
Submitted Solution:
```
# link: https://codeforces.com/problemset/problem/975/C
import os, sys, copy
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
from math import ceil
mod = 10 ** 9 + 7
# number of test cases
for _ in range(1):
n, q = map(int, input().split())
strength = list(map(int, input().split()))
arrow = list(map(int, input().split()))
prefix_strength = [0] * (n)
for i in range(n):
if i==0:
prefix_strength[i] = strength[i]
else:
prefix_strength[i] = strength[i] + prefix_strength[i-1]
s = 0
for i in range(q):
s += arrow[i]
if s >= prefix_strength[-1]:
s = 0
arrow[i] = -1
#print(arrow)
# so prefix is going to be my original array which I will restore
# so prefix is going to be my original array which I will restore
ps = 0
temp_s = 0
temp = prefix_strength.copy()
for i in range(q):
if arrow[i] == -1:
ps = 0
print(n)
temp_s = 0
continue
s = temp_s
e = n-1
r = -1
while s<=e:
m = s + (e - s) // 2
if temp[m] - ps >= arrow[i]:
r = m
e = m - 1
else:
s = m + 1
left = temp[r] - arrow[i] - ps
if left == 0:
ps += temp[r]
temp_s = r + 1
print(n - (r + 1))
else:
ps += arrow[i]
temp_s = r
print(n - r)
``` | instruction | 0 | 81,423 | 2 | 162,846 |
No | output | 1 | 81,423 | 2 | 162,847 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ivar the Boneless is a great leader. He is trying to capture Kattegat from Lagertha. The war has begun and wave after wave Ivar's warriors are falling in battle.
Ivar has n warriors, he places them on a straight line in front of the main gate, in a way that the i-th warrior stands right after (i-1)-th warrior. The first warrior leads the attack.
Each attacker can take up to a_i arrows before he falls to the ground, where a_i is the i-th warrior's strength.
Lagertha orders her warriors to shoot k_i arrows during the i-th minute, the arrows one by one hit the first still standing warrior. After all Ivar's warriors fall and all the currently flying arrows fly by, Thor smashes his hammer and all Ivar's warriors get their previous strengths back and stand up to fight again. In other words, if all warriors die in minute t, they will all be standing to fight at the end of minute t.
The battle will last for q minutes, after each minute you should tell Ivar what is the number of his standing warriors.
Input
The first line contains two integers n and q (1 β€ n, q β€ 200 000) β the number of warriors and the number of minutes in the battle.
The second line contains n integers a_1, a_2, β¦, a_n (1 β€ a_i β€ 10^9) that represent the warriors' strengths.
The third line contains q integers k_1, k_2, β¦, k_q (1 β€ k_i β€ 10^{14}), the i-th of them represents Lagertha's order at the i-th minute: k_i arrows will attack the warriors.
Output
Output q lines, the i-th of them is the number of standing warriors after the i-th minute.
Examples
Input
5 5
1 2 1 2 1
3 10 1 1 1
Output
3
5
4
4
3
Input
4 4
1 2 3 4
9 1 10 6
Output
1
4
4
1
Note
In the first example:
* after the 1-st minute, the 1-st and 2-nd warriors die.
* after the 2-nd minute all warriors die (and all arrows left over are wasted), then they will be revived thus answer is 5 β all warriors are alive.
* after the 3-rd minute, the 1-st warrior dies.
* after the 4-th minute, the 2-nd warrior takes a hit and his strength decreases by 1.
* after the 5-th minute, the 2-nd warrior dies.
Submitted Solution:
```
#n = list(map(int , input().split()))
w,m = input().split(" ")
w = int(w)
strengths = list(map(int, input().split()))
arrows = list(map(int, input().split()))
# print(w,m)
# print(strengths)
# print(arrows)
sum_str = sum(strengths)
j=0
flag = sum_str
counter = -1
stre = 0
for i in arrows:
#print("start","counter: ",counter,"strength: ",stre)
if(i>sum_str):
print(w)
counter = -1
stre = 0
continue
while(stre <= i):
counter += 1
counter = counter % (w)
stre += strengths[counter]
if(stre == i):
stre = 0
if(stre > i):
stre = stre - i
print(w-counter,counter,stre)
``` | instruction | 0 | 81,424 | 2 | 162,848 |
No | output | 1 | 81,424 | 2 | 162,849 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ivar the Boneless is a great leader. He is trying to capture Kattegat from Lagertha. The war has begun and wave after wave Ivar's warriors are falling in battle.
Ivar has n warriors, he places them on a straight line in front of the main gate, in a way that the i-th warrior stands right after (i-1)-th warrior. The first warrior leads the attack.
Each attacker can take up to a_i arrows before he falls to the ground, where a_i is the i-th warrior's strength.
Lagertha orders her warriors to shoot k_i arrows during the i-th minute, the arrows one by one hit the first still standing warrior. After all Ivar's warriors fall and all the currently flying arrows fly by, Thor smashes his hammer and all Ivar's warriors get their previous strengths back and stand up to fight again. In other words, if all warriors die in minute t, they will all be standing to fight at the end of minute t.
The battle will last for q minutes, after each minute you should tell Ivar what is the number of his standing warriors.
Input
The first line contains two integers n and q (1 β€ n, q β€ 200 000) β the number of warriors and the number of minutes in the battle.
The second line contains n integers a_1, a_2, β¦, a_n (1 β€ a_i β€ 10^9) that represent the warriors' strengths.
The third line contains q integers k_1, k_2, β¦, k_q (1 β€ k_i β€ 10^{14}), the i-th of them represents Lagertha's order at the i-th minute: k_i arrows will attack the warriors.
Output
Output q lines, the i-th of them is the number of standing warriors after the i-th minute.
Examples
Input
5 5
1 2 1 2 1
3 10 1 1 1
Output
3
5
4
4
3
Input
4 4
1 2 3 4
9 1 10 6
Output
1
4
4
1
Note
In the first example:
* after the 1-st minute, the 1-st and 2-nd warriors die.
* after the 2-nd minute all warriors die (and all arrows left over are wasted), then they will be revived thus answer is 5 β all warriors are alive.
* after the 3-rd minute, the 1-st warrior dies.
* after the 4-th minute, the 2-nd warrior takes a hit and his strength decreases by 1.
* after the 5-th minute, the 2-nd warrior dies.
Submitted Solution:
```
n, q = map(int, input().split())
a = list(map(int, input().split()))
z = list(map(int, input().split()))
def binsearch(x, k):
left = 0
right = len(x)
while left != right - 1:
mid = (left + right) // 2
if x[mid] > k:
right = mid
else:
left = mid
return right
#print(binsearch([1, 2, 3, 4, 5, 8 ,67], 3))
prefix = [0 for i in range(n)]
summ = 0
for i in range(n):
summ += a[i]
prefix[i] = summ
summ1 = 0
#print(prefix)
for i in range(q):
summ1 += z[i]
r = binsearch(prefix, summ1)
#print(r, summ1)
if r == n:
print(n)
summ1 = 0
else:
print(n - r)
``` | instruction | 0 | 81,425 | 2 | 162,850 |
No | output | 1 | 81,425 | 2 | 162,851 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mr. Chanek The Ninja is one day tasked with a mission to handle mad snakes that are attacking a site. Now, Mr. Chanek already arrived at the hills where the destination is right below these hills. The mission area can be divided into a grid of size 1000 Γ 1000 squares. There are N mad snakes on the site, the i'th mad snake is located on square (X_i, Y_i) and has a danger level B_i.
Mr. Chanek is going to use the Shadow Clone Jutsu and Rasengan that he learned from Lord Seventh to complete this mission. His attack strategy is as follows:
1. Mr. Chanek is going to make M clones.
2. Each clone will choose a mad snake as the attack target. Each clone must pick a different mad snake to attack.
3. All clones jump off the hills and attack their respective chosen target at once with Rasengan of radius R. If the mad snake at square (X, Y) is attacked with a direct Rasengan, it and all mad snakes at squares (X', Y') where max(|X' - X|, |Y' - Y|) β€ R will die.
4. The real Mr. Chanek will calculate the score of this attack. The score is defined as the square of the sum of the danger levels of all the killed snakes.
Now Mr. Chanek is curious, what is the sum of scores for every possible attack strategy? Because this number can be huge, Mr. Chanek only needs the output modulo 10^9 + 7.
Input
The first line contains three integers N M R (1 β€ M β€ N β€ 2 β
10^3, 0 β€ R < 10^3), the number of mad snakes, the number of clones, and the radius of the Rasengan.
The next N lines each contains three integers, X_i, Y_i, dan B_i (1 β€ X_i, Y_i β€ 10^3, 1 β€ B_i β€ 10^6). It is guaranteed that no two mad snakes occupy the same square.
Output
A line with an integer that denotes the sum of scores for every possible attack strategy.
Example
Input
4 2 1
1 1 10
2 2 20
2 3 30
5 2 40
Output
33800
Note
Here is the illustration of all six possible attack strategies. The circles denote the chosen mad snakes, and the blue squares denote the region of the Rasengan:
<image>
So, the total score of all attacks is: 3.600 + 3.600 + 4.900 + 3.600 + 10.000 + 8.100 = 33.800. | instruction | 0 | 84,422 | 2 | 168,844 |
Tags: combinatorics, dp, math
Correct Solution:
```
import sys
input = sys.stdin.readline
from sys import stdin, stdout
from collections import defaultdict, Counter
from functools import lru_cache
M = 10**9+7
fact = [1]*(2001)
def fac(n):
if(n==0 or n==1):
return 1
elif fact[n]!=1:
return fact[n]
fact[n] = (fac(n-1)*(n%M))%M
return fact[n]
ncr = [[0 for i in range(2001)] for j in range(2001)]
def choose(n,k):
if n<k:
return 0
if k==0 or k==n:
return 1
elif k==1 or k==n-1:
return n%M
elif ncr[n][k]!=0:
return ncr[n][k]
else:
ncr[n][k] = ( fac(n) * ( pow(fac(k),M-2,M) * pow(fac(n-k),M-2,M))%M )%M
return ncr[n][k]
def find_inter(x1, y1, x2, y2, x3, y3, x4, y4):
x5 = max(x1, x3)
y5 = max(y1, y3)
x6 = min(x2, x4)
y6 = min(y2, y4)
if (x5 > x6 or y5 > y6) :
return [0]
return [1, x5, y5, x6, y6]
def main():
n,m,r = [int(s) for s in input().split()]
snakes = [[int(s) for s in input().split()] for i in range(n)]
X = max([i[0] for i in snakes])
Y = max([i[1] for i in snakes])
num = [1]*n
for i in range(n-1):
for j in range(i+1,n):
if max(abs(snakes[i][0]-snakes[j][0]),abs(snakes[i][1]-snakes[j][1])) <= r:
num[i]+=1
num[j]+=1
ans = 0
ncm = choose(n,m)
for i in range(n):
v = (((ncm - choose(n-num[i],m))%M)*((snakes[i][2]**2)%M))%M
ans = (ans + v)%M
pre = [[0 for i in range(Y+r+1)] for j in range(X+r+1)]
for i in range(n):
pre[snakes[i][0]][snakes[i][1]] = 1
for i in range(1,X+r+1):
pre[i][0] += pre[i-1][0]
for i in range(1,Y+r+1):
pre[0][i] += pre[0][i-1]
for i in range(1,X+r+1):
for j in range(1,Y+r+1):
pre[i][j] += pre[i][j-1] + pre[i-1][j]-pre[i-1][j-1]
num1 = [[0 for i in range(n)]for j in range(n)]
for i in range(n-1):
for j in range(i+1,n):
x1,y1,x2,y2 = snakes[i][0], snakes[i][1], snakes[j][0],snakes[j][1]
inter = find_inter(max(x1-r,0),max(y1-r,0),x1+r,y1+r,max(x2-r,0),max(y2-r,0),x2+r,y2+r)
if inter[0]==1:
blx,bly,trx,ty = inter[1:]
# print(inter[1:])
num1[i][j] = pre[trx][ty]
if blx-1>=0 and bly-1>=0:
num1[i][j] += pre[blx-1][bly-1]
if blx-1>=0:
num1[i][j] -= pre[blx-1][ty]
if bly-1>=0:
num1[i][j] -= pre[trx][bly-1]
ans1 = 0
for i in range(n-1):
for j in range(i+1,n):
x = num[i]
y = num[j]
z = num1[i][j]
v = ( (( ncm + ( choose(n-x-y+z,m) - (choose(n-x,m) + choose(n-y,m))%M )%M )%M) * ((snakes[i][2]*snakes[j][2])%M) )%M
ans1 = (ans1 + v)%M
print((ans+(2*ans1)%M)%M)
if __name__== '__main__':
main()
``` | output | 1 | 84,422 | 2 | 168,845 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mr. Chanek The Ninja is one day tasked with a mission to handle mad snakes that are attacking a site. Now, Mr. Chanek already arrived at the hills where the destination is right below these hills. The mission area can be divided into a grid of size 1000 Γ 1000 squares. There are N mad snakes on the site, the i'th mad snake is located on square (X_i, Y_i) and has a danger level B_i.
Mr. Chanek is going to use the Shadow Clone Jutsu and Rasengan that he learned from Lord Seventh to complete this mission. His attack strategy is as follows:
1. Mr. Chanek is going to make M clones.
2. Each clone will choose a mad snake as the attack target. Each clone must pick a different mad snake to attack.
3. All clones jump off the hills and attack their respective chosen target at once with Rasengan of radius R. If the mad snake at square (X, Y) is attacked with a direct Rasengan, it and all mad snakes at squares (X', Y') where max(|X' - X|, |Y' - Y|) β€ R will die.
4. The real Mr. Chanek will calculate the score of this attack. The score is defined as the square of the sum of the danger levels of all the killed snakes.
Now Mr. Chanek is curious, what is the sum of scores for every possible attack strategy? Because this number can be huge, Mr. Chanek only needs the output modulo 10^9 + 7.
Input
The first line contains three integers N M R (1 β€ M β€ N β€ 2 β
10^3, 0 β€ R < 10^3), the number of mad snakes, the number of clones, and the radius of the Rasengan.
The next N lines each contains three integers, X_i, Y_i, dan B_i (1 β€ X_i, Y_i β€ 10^3, 1 β€ B_i β€ 10^6). It is guaranteed that no two mad snakes occupy the same square.
Output
A line with an integer that denotes the sum of scores for every possible attack strategy.
Example
Input
4 2 1
1 1 10
2 2 20
2 3 30
5 2 40
Output
33800
Note
Here is the illustration of all six possible attack strategies. The circles denote the chosen mad snakes, and the blue squares denote the region of the Rasengan:
<image>
So, the total score of all attacks is: 3.600 + 3.600 + 4.900 + 3.600 + 10.000 + 8.100 = 33.800. | instruction | 0 | 84,423 | 2 | 168,846 |
Tags: combinatorics, dp, math
Correct Solution:
```
# from __future__ import print_function,division
# range = xrange
import sys
input = sys.stdin.readline
sys.setrecursionlimit(10**4)
from sys import stdin, stdout
from collections import defaultdict, Counter
from functools import lru_cache
M = 10**9+7
fact = [1]*(2001)
def fac(n):
if(n==0 or n==1):
return 1
elif fact[n]!=1:
return fact[n]
fact[n] = (fac(n-1)*(n%M))%M
return fact[n]
ncr = [[0 for i in range(2001)] for j in range(2001)]
def choose(n,k):
if n<k:
return 0
if k==0 or k==n:
return 1
elif k==1 or k==n-1:
return n%M
elif ncr[n][k]!=0:
return ncr[n][k]
else:
ncr[n][k] = ( fac(n) * ( pow(fac(k),M-2,M) * pow(fac(n-k),M-2,M))%M )%M
return ncr[n][k]
def find_inter(x1, y1, x2, y2, x3, y3, x4, y4):
x5 = max(x1, x3)
y5 = max(y1, y3)
x6 = min(x2, x4)
y6 = min(y2, y4)
if (x5 > x6 or y5 > y6) :
return [0]
return [1, x5, y5, x6, y6]
def main():
n,m,r = [int(s) for s in input().split()]
snakes = [[int(s) for s in input().split()] for i in range(n)]
X = max([i[0] for i in snakes])
Y = max([i[1] for i in snakes])
num = [1]*n
for i in range(n-1):
for j in range(i+1,n):
if max(abs(snakes[i][0]-snakes[j][0]),abs(snakes[i][1]-snakes[j][1])) <= r:
num[i]+=1
num[j]+=1
ans = 0
ncm = choose(n,m)
for i in range(n):
v = (((ncm - choose(n-num[i],m))%M)*((snakes[i][2]**2)%M))%M
ans = (ans + v)%M
pre = [[0 for i in range(Y+r+1)] for j in range(X+r+1)]
for i in range(n):
pre[snakes[i][0]][snakes[i][1]] = 1
for i in range(1,X+r+1):
pre[i][0] += pre[i-1][0]
for i in range(1,Y+r+1):
pre[0][i] += pre[0][i-1]
for i in range(1,X+r+1):
for j in range(1,Y+r+1):
pre[i][j] += pre[i][j-1] + pre[i-1][j]-pre[i-1][j-1]
num1 = [[0 for i in range(n)]for j in range(n)]
for i in range(n-1):
for j in range(i+1,n):
x1,y1,x2,y2 = snakes[i][0], snakes[i][1], snakes[j][0],snakes[j][1]
inter = find_inter(max(x1-r,0),max(y1-r,0),x1+r,y1+r,max(x2-r,0),max(y2-r,0),x2+r,y2+r)
if inter[0]==1:
blx,bly,trx,ty = inter[1:]
# print(inter[1:])
num1[i][j] = pre[trx][ty]
if blx-1>=0 and bly-1>=0:
num1[i][j] += pre[blx-1][bly-1]
if blx-1>=0:
num1[i][j] -= pre[blx-1][ty]
if bly-1>=0:
num1[i][j] -= pre[trx][bly-1]
ans1 = 0
# print("num")
# print(*num)
# print("num1:")
# for i in num1:
# print(*i)
for i in range(n-1):
for j in range(i+1,n):
x = num[i]
y = num[j]
z = num1[i][j]
v = ( (( ncm + ( choose(n-x-y+z,m) - (choose(n-x,m) + choose(n-y,m))%M )%M )%M) * ((snakes[i][2]*snakes[j][2])%M) )%M
ans1 = (ans1 + v)%M
# print(i+1,j+1,v)
# print("ans:",ans,"ans1",ans1)
print((ans+(2*ans1)%M)%M)
if __name__== '__main__':
main()
``` | output | 1 | 84,423 | 2 | 168,847 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr. Chanek The Ninja is one day tasked with a mission to handle mad snakes that are attacking a site. Now, Mr. Chanek already arrived at the hills where the destination is right below these hills. The mission area can be divided into a grid of size 1000 Γ 1000 squares. There are N mad snakes on the site, the i'th mad snake is located on square (X_i, Y_i) and has a danger level B_i.
Mr. Chanek is going to use the Shadow Clone Jutsu and Rasengan that he learned from Lord Seventh to complete this mission. His attack strategy is as follows:
1. Mr. Chanek is going to make M clones.
2. Each clone will choose a mad snake as the attack target. Each clone must pick a different mad snake to attack.
3. All clones jump off the hills and attack their respective chosen target at once with Rasengan of radius R. If the mad snake at square (X, Y) is attacked with a direct Rasengan, it and all mad snakes at squares (X', Y') where max(|X' - X|, |Y' - Y|) β€ R will die.
4. The real Mr. Chanek will calculate the score of this attack. The score is defined as the square of the sum of the danger levels of all the killed snakes.
Now Mr. Chanek is curious, what is the sum of scores for every possible attack strategy? Because this number can be huge, Mr. Chanek only needs the output modulo 10^9 + 7.
Input
The first line contains three integers N M R (1 β€ M β€ N β€ 2 β
10^3, 0 β€ R < 10^3), the number of mad snakes, the number of clones, and the radius of the Rasengan.
The next N lines each contains three integers, X_i, Y_i, dan B_i (1 β€ X_i, Y_i β€ 10^3, 1 β€ B_i β€ 10^6). It is guaranteed that no two mad snakes occupy the same square.
Output
A line with an integer that denotes the sum of scores for every possible attack strategy.
Example
Input
4 2 1
1 1 10
2 2 20
2 3 30
5 2 40
Output
33800
Note
Here is the illustration of all six possible attack strategies. The circles denote the chosen mad snakes, and the blue squares denote the region of the Rasengan:
<image>
So, the total score of all attacks is: 3.600 + 3.600 + 4.900 + 3.600 + 10.000 + 8.100 = 33.800.
Submitted Solution:
```
# from __future__ import print_function,division
# range = xrange
import sys
input = sys.stdin.readline
sys.setrecursionlimit(10**4)
from sys import stdin, stdout
from collections import defaultdict, Counter
from functools import lru_cache
M = 10**9+7
fact = [1]*(2001)
def fac(n):
if(n==0 or n==1):
return 1
elif fact[n]!=1:
return fact[n]
fact[n] = (fac(n-1)*(n%M))%M
return fact[n]
ncr = [[0 for i in range(2001)] for j in range(2001)]
def choose(n,k):
if n<k:
return 0
if k==0 or k==n:
return 1
elif k==1 or k==n-1:
return n%M
elif ncr[n][k]!=0:
return ncr[n][k]
else:
ncr[n][k] = (fac(n)*pow(fac(k),M-2,M)*pow(fac(n-k),M-2,M))%M
return ncr[n][k]
def find_inter(x1, y1, x2, y2, x3, y3, x4, y4):
x5 = max(x1, x3)
y5 = max(y1, y3)
x6 = min(x2, x4)
y6 = min(y2, y4)
if (x5 > x6 or y5 > y6) :
return [0]
return [1, x5, y5, x6, y6]
def main():
n,m,r = [int(s) for s in input().split()]
snakes = [[int(s) for s in input().split()] for i in range(n)]
X = max([i[0] for i in snakes])
Y = max([i[1] for i in snakes])
num = [1]*n
for i in range(n-1):
for j in range(i+1,n):
if max(abs(snakes[i][0]-snakes[j][0]),abs(snakes[i][1]-snakes[j][1])) <= r:
num[i]+=1
num[j]+=1
ans = 0
ncm = choose(n,m)
for i in range(n):
v = (((ncm - choose(n-num[i],m))%M)*(snakes[i][2]**2))%M
# print(v)
ans = (ans + v)%M
pre = [[0 for i in range(Y+r+1)] for j in range(X+r+1)]
for i in range(n):
pre[snakes[i][0]][snakes[i][1]] = 1
for i in range(1,X+r+1):
pre[i][0] += pre[i-1][0]
for i in range(1,Y+r+1):
pre[0][i] += pre[0][i-1]
for i in range(1,X+r+1):
for j in range(1,Y+r+1):
pre[i][j] += pre[i][j-1] + pre[i-1][j]-pre[i-1][j-1]
num1 = [[0 for i in range(n)]for j in range(n)]
for i in range(n-1):
for j in range(i+1,n):
x1,y1,x2,y2 = snakes[i][0], snakes[i][1], snakes[j][0],snakes[j][1]
inter = find_inter(max(x1-r,0),max(y1-r,0),x1+r,y1+r,max(x2-r,0),max(y2-r,0),x2+r,y2+r)
if inter[0]==1:
blx,bly,trx,ty = inter[1:]
# print(inter[1:])
num1[i][j] = pre[trx][ty] + pre[blx-1][bly-1] - pre[blx-1][ty] - pre[trx][bly-1]
ans1 = 0
# print("num")
# print(*num)
# print("num1:")
# for i in num1:
# print(*i)
for i in range(n-1):
for j in range(i+1,n):
x = num[i]
y = num[j]
z = num1[i][j]
v = ( (( ncm + ( choose(n-x-y+z,m) - (choose(n-x,m) + choose(n-y,m))%M )%M )%M ) * ((snakes[i][2]*snakes[j][2])%M) )%M
ans1 = (ans1 + v)%M
# print(i+1,j+1,v)
# print("ans:",ans,"ans1",ans1)
print((ans+(2*ans1)%M)%M)
if __name__== '__main__':
main()
``` | instruction | 0 | 84,424 | 2 | 168,848 |
No | output | 1 | 84,424 | 2 | 168,849 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr. Chanek The Ninja is one day tasked with a mission to handle mad snakes that are attacking a site. Now, Mr. Chanek already arrived at the hills where the destination is right below these hills. The mission area can be divided into a grid of size 1000 Γ 1000 squares. There are N mad snakes on the site, the i'th mad snake is located on square (X_i, Y_i) and has a danger level B_i.
Mr. Chanek is going to use the Shadow Clone Jutsu and Rasengan that he learned from Lord Seventh to complete this mission. His attack strategy is as follows:
1. Mr. Chanek is going to make M clones.
2. Each clone will choose a mad snake as the attack target. Each clone must pick a different mad snake to attack.
3. All clones jump off the hills and attack their respective chosen target at once with Rasengan of radius R. If the mad snake at square (X, Y) is attacked with a direct Rasengan, it and all mad snakes at squares (X', Y') where max(|X' - X|, |Y' - Y|) β€ R will die.
4. The real Mr. Chanek will calculate the score of this attack. The score is defined as the square of the sum of the danger levels of all the killed snakes.
Now Mr. Chanek is curious, what is the sum of scores for every possible attack strategy? Because this number can be huge, Mr. Chanek only needs the output modulo 10^9 + 7.
Input
The first line contains three integers N M R (1 β€ M β€ N β€ 2 β
10^3, 0 β€ R < 10^3), the number of mad snakes, the number of clones, and the radius of the Rasengan.
The next N lines each contains three integers, X_i, Y_i, dan B_i (1 β€ X_i, Y_i β€ 10^3, 1 β€ B_i β€ 10^6). It is guaranteed that no two mad snakes occupy the same square.
Output
A line with an integer that denotes the sum of scores for every possible attack strategy.
Example
Input
4 2 1
1 1 10
2 2 20
2 3 30
5 2 40
Output
33800
Note
Here is the illustration of all six possible attack strategies. The circles denote the chosen mad snakes, and the blue squares denote the region of the Rasengan:
<image>
So, the total score of all attacks is: 3.600 + 3.600 + 4.900 + 3.600 + 10.000 + 8.100 = 33.800.
Submitted Solution:
```
from itertools import combinations
values = list(map(int,input().strip().split()))[:3]
matrix = []
for i in range(0,values[0]):
a = list(list(map(int,input().strip().split()))[:3])
matrix.append(a)
list_index = list(combinations(range(values[0]), values[1]))
combination_number = len(list_index)
total = 0
for i in range(0,combination_number):
sum = 0
pos = []
for j in list_index[i]:
sum = sum + matrix[j][2]
repeat_snake = []
for j in range(0, values[0]):
if j in list_index[i]:
continue
for position in list_index[i]:
if ( max(abs(matrix[j][0]-matrix[position][0]) , abs(matrix[j][1] - matrix[position][1])) <= values[2] and j not in repeat_snake ):
sum = sum + matrix[j][2]
repeat_snake.append(j)
total = total + (sum ** 2)
print(total)
``` | instruction | 0 | 84,425 | 2 | 168,850 |
No | output | 1 | 84,425 | 2 | 168,851 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr. Chanek The Ninja is one day tasked with a mission to handle mad snakes that are attacking a site. Now, Mr. Chanek already arrived at the hills where the destination is right below these hills. The mission area can be divided into a grid of size 1000 Γ 1000 squares. There are N mad snakes on the site, the i'th mad snake is located on square (X_i, Y_i) and has a danger level B_i.
Mr. Chanek is going to use the Shadow Clone Jutsu and Rasengan that he learned from Lord Seventh to complete this mission. His attack strategy is as follows:
1. Mr. Chanek is going to make M clones.
2. Each clone will choose a mad snake as the attack target. Each clone must pick a different mad snake to attack.
3. All clones jump off the hills and attack their respective chosen target at once with Rasengan of radius R. If the mad snake at square (X, Y) is attacked with a direct Rasengan, it and all mad snakes at squares (X', Y') where max(|X' - X|, |Y' - Y|) β€ R will die.
4. The real Mr. Chanek will calculate the score of this attack. The score is defined as the square of the sum of the danger levels of all the killed snakes.
Now Mr. Chanek is curious, what is the sum of scores for every possible attack strategy? Because this number can be huge, Mr. Chanek only needs the output modulo 10^9 + 7.
Input
The first line contains three integers N M R (1 β€ M β€ N β€ 2 β
10^3, 0 β€ R < 10^3), the number of mad snakes, the number of clones, and the radius of the Rasengan.
The next N lines each contains three integers, X_i, Y_i, dan B_i (1 β€ X_i, Y_i β€ 10^3, 1 β€ B_i β€ 10^6). It is guaranteed that no two mad snakes occupy the same square.
Output
A line with an integer that denotes the sum of scores for every possible attack strategy.
Example
Input
4 2 1
1 1 10
2 2 20
2 3 30
5 2 40
Output
33800
Note
Here is the illustration of all six possible attack strategies. The circles denote the chosen mad snakes, and the blue squares denote the region of the Rasengan:
<image>
So, the total score of all attacks is: 3.600 + 3.600 + 4.900 + 3.600 + 10.000 + 8.100 = 33.800.
Submitted Solution:
```
# from __future__ import print_function,division
# range = xrange
import sys
input = sys.stdin.readline
sys.setrecursionlimit(10**4)
from sys import stdin, stdout
from collections import defaultdict, Counter
from functools import lru_cache
M = 10**9+7
fact = [1]*(2001)
def fac(n):
if(n==0 or n==1):
return 1
elif fact[n]!=1:
return fact[n]
fact[n] = (fac(n-1)*(n%M))%M
return fact[n]
ncr = [[0 for i in range(2001)] for j in range(2001)]
def choose(n,k):
if n<k:
return 0
if k==0 or k==n:
return 1
elif k==1 or k==n-1:
return n%M
elif ncr[n][k]!=0:
return ncr[n][k]
else:
ncr[n][k] = (fac(n)*pow(fac(k),M-2,M)*pow(fac(n-k),M-2,M))%M
return ncr[n][k]
def find_inter(x1, y1, x2, y2, x3, y3, x4, y4):
x5 = max(x1, x3)
y5 = max(y1, y3)
x6 = min(x2, x4)
y6 = min(y2, y4)
if (x5 > x6 or y5 > y6) :
return [0]
return [1, x5, y5, x6, y6]
def main():
n,m,r = [int(s) for s in input().split()]
snakes = [[int(s) for s in input().split()] for i in range(n)]
X = max([i[0] for i in snakes])
Y = max([i[1] for i in snakes])
num = [1]*n
for i in range(n-1):
for j in range(i+1,n):
if max(abs(snakes[i][0]-snakes[j][0]),abs(snakes[i][1]-snakes[j][1])) <= r:
num[i]+=1
num[j]+=1
ans = 0
ncm = choose(n,m)
for i in range(n):
v = (((ncm - choose(n-num[i],m))%M)*((snakes[i][2]**2)%M))%M
ans = (ans + v)%M
pre = [[0 for i in range(Y+r+1)] for j in range(X+r+1)]
for i in range(n):
pre[snakes[i][0]][snakes[i][1]] = 1
for i in range(1,X+r+1):
pre[i][0] += pre[i-1][0]
for i in range(1,Y+r+1):
pre[0][i] += pre[0][i-1]
for i in range(1,X+r+1):
for j in range(1,Y+r+1):
pre[i][j] += pre[i][j-1] + pre[i-1][j]-pre[i-1][j-1]
num1 = [[0 for i in range(n)]for j in range(n)]
for i in range(n-1):
for j in range(i+1,n):
x1,y1,x2,y2 = snakes[i][0], snakes[i][1], snakes[j][0],snakes[j][1]
inter = find_inter(max(x1-r,0),max(y1-r,0),x1+r,y1+r,max(x2-r,0),max(y2-r,0),x2+r,y2+r)
if inter[0]==1:
blx,bly,trx,ty = inter[1:]
# print(inter[1:])
num1[i][j] = pre[trx][ty] + pre[blx-1][bly-1] - pre[blx-1][ty] - pre[trx][bly-1]
ans1 = 0
# print("num")
# print(*num)
# print("num1:")
# for i in num1:
# print(*i)
for i in range(n-1):
for j in range(i+1,n):
x = num[i]
y = num[j]
z = num1[i][j]
v = ( (( ncm + ( choose(n-x-y+z,m) - (choose(n-x,m) + choose(n-y,m))%M )%M )%M ) * ((snakes[i][2]*snakes[j][2])%M) )%M
ans1 = (ans1 + v)%M
# print(i+1,j+1,v)
# print("ans:",ans,"ans1",ans1)
print((ans+(2*ans1)%M)%M)
if __name__== '__main__':
main()
``` | instruction | 0 | 84,426 | 2 | 168,852 |
No | output | 1 | 84,426 | 2 | 168,853 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr. Chanek The Ninja is one day tasked with a mission to handle mad snakes that are attacking a site. Now, Mr. Chanek already arrived at the hills where the destination is right below these hills. The mission area can be divided into a grid of size 1000 Γ 1000 squares. There are N mad snakes on the site, the i'th mad snake is located on square (X_i, Y_i) and has a danger level B_i.
Mr. Chanek is going to use the Shadow Clone Jutsu and Rasengan that he learned from Lord Seventh to complete this mission. His attack strategy is as follows:
1. Mr. Chanek is going to make M clones.
2. Each clone will choose a mad snake as the attack target. Each clone must pick a different mad snake to attack.
3. All clones jump off the hills and attack their respective chosen target at once with Rasengan of radius R. If the mad snake at square (X, Y) is attacked with a direct Rasengan, it and all mad snakes at squares (X', Y') where max(|X' - X|, |Y' - Y|) β€ R will die.
4. The real Mr. Chanek will calculate the score of this attack. The score is defined as the square of the sum of the danger levels of all the killed snakes.
Now Mr. Chanek is curious, what is the sum of scores for every possible attack strategy? Because this number can be huge, Mr. Chanek only needs the output modulo 10^9 + 7.
Input
The first line contains three integers N M R (1 β€ M β€ N β€ 2 β
10^3, 0 β€ R < 10^3), the number of mad snakes, the number of clones, and the radius of the Rasengan.
The next N lines each contains three integers, X_i, Y_i, dan B_i (1 β€ X_i, Y_i β€ 10^3, 1 β€ B_i β€ 10^6). It is guaranteed that no two mad snakes occupy the same square.
Output
A line with an integer that denotes the sum of scores for every possible attack strategy.
Example
Input
4 2 1
1 1 10
2 2 20
2 3 30
5 2 40
Output
33800
Note
Here is the illustration of all six possible attack strategies. The circles denote the chosen mad snakes, and the blue squares denote the region of the Rasengan:
<image>
So, the total score of all attacks is: 3.600 + 3.600 + 4.900 + 3.600 + 10.000 + 8.100 = 33.800.
Submitted Solution:
```
# from __future__ import print_function,division
# range = xrange
import sys
input = sys.stdin.readline
sys.setrecursionlimit(10**4)
from sys import stdin, stdout
from collections import defaultdict, Counter
from functools import lru_cache
M = 10**9+7
fact = [1]*(2001)
def fac(n):
if(n==0 or n==1):
return 1
elif fact[n]!=1:
return fact[n]
fact[n] = (fac(n-1)*(n%M))%M
return fact[n]
ncr = [[0 for i in range(2001)] for j in range(2001)]
def choose(n,k):
if n<k:
return 0
if k==0 or k==n:
return 1
elif k==1 or k==n-1:
return n%M
elif ncr[n][k]!=0:
return ncr[n][k]
else:
ncr[n][k] = ( fac(n) * ( pow(fac(k),M-2,M) * pow(fac(n-k),M-2,M))%M )%M
return ncr[n][k]
def find_inter(x1, y1, x2, y2, x3, y3, x4, y4):
x5 = max(x1, x3)
y5 = max(y1, y3)
x6 = min(x2, x4)
y6 = min(y2, y4)
if (x5 > x6 or y5 > y6) :
return [0]
return [1, x5, y5, x6, y6]
def main():
n,m,r = [int(s) for s in input().split()]
snakes = [[int(s) for s in input().split()] for i in range(n)]
X = max([i[0] for i in snakes])
Y = max([i[1] for i in snakes])
num = [1]*n
for i in range(n-1):
for j in range(i+1,n):
if max(abs(snakes[i][0]-snakes[j][0]),abs(snakes[i][1]-snakes[j][1])) <= r:
num[i]+=1
num[j]+=1
ans = 0
ncm = choose(n,m)
for i in range(n):
v = (((ncm - choose(n-num[i],m))%M)*((snakes[i][2]**2)%M))%M
ans = (ans + v)%M
pre = [[0 for i in range(Y+r+1)] for j in range(X+r+1)]
for i in range(n):
pre[snakes[i][0]][snakes[i][1]] = 1
for i in range(1,X+r+1):
pre[i][0] += pre[i-1][0]
for i in range(1,Y+r+1):
pre[0][i] += pre[0][i-1]
for i in range(1,X+r+1):
for j in range(1,Y+r+1):
pre[i][j] += pre[i][j-1] + pre[i-1][j]-pre[i-1][j-1]
num1 = [[0 for i in range(n)]for j in range(n)]
for i in range(n-1):
for j in range(i+1,n):
x1,y1,x2,y2 = snakes[i][0], snakes[i][1], snakes[j][0],snakes[j][1]
inter = find_inter(max(x1-r,0),max(y1-r,0),x1+r,y1+r,max(x2-r,0),max(y2-r,0),x2+r,y2+r)
if inter[0]==1:
blx,bly,trx,ty = inter[1:]
# print(inter[1:])
num1[i][j] = pre[trx][ty] + pre[blx-1][bly-1] - pre[blx-1][ty] - pre[trx][bly-1]
ans1 = 0
# print("num")
# print(*num)
# print("num1:")
# for i in num1:
# print(*i)
for i in range(n-1):
for j in range(i+1,n):
x = num[i]
y = num[j]
z = num1[i][j]
v = ( (( ncm + ( choose(n-x-y+z,m) - (choose(n-x,m) + choose(n-y,m))%M )%M )%M ) * ((snakes[i][2]*snakes[j][2])%M) )%M
ans1 = (ans1 + v)%M
# print(i+1,j+1,v)
# print("ans:",ans,"ans1",ans1)
print((ans+(2*ans1)%M)%M)
if __name__== '__main__':
main()
``` | instruction | 0 | 84,427 | 2 | 168,854 |
No | output | 1 | 84,427 | 2 | 168,855 |
Provide a correct Python 3 solution for this coding contest problem.
Fennec is fighting with N monsters.
The health of the i-th monster is H_i.
Fennec can do the following two actions:
* Attack: Fennec chooses one monster. That monster's health will decrease by 1.
* Special Move: Fennec chooses one monster. That monster's health will become 0.
There is no way other than Attack and Special Move to decrease the monsters' health.
Fennec wins when all the monsters' healths become 0 or below.
Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 0 \leq K \leq 2 \times 10^5
* 1 \leq H_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N K
H_1 ... H_N
Output
Print the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning.
Examples
Input
3 1
4 1 5
Output
5
Input
8 9
7 9 3 2 3 8 4 6
Output
0
Input
3 0
1000000000 1000000000 1000000000
Output
3000000000 | instruction | 0 | 84,805 | 2 | 169,610 |
"Correct Solution:
```
n,k,*h=map(int,open(0).read().split())
if k>=n:
print(0)
exit()
h.sort()
print(sum(h[:n-k]))
``` | output | 1 | 84,805 | 2 | 169,611 |
Provide a correct Python 3 solution for this coding contest problem.
Fennec is fighting with N monsters.
The health of the i-th monster is H_i.
Fennec can do the following two actions:
* Attack: Fennec chooses one monster. That monster's health will decrease by 1.
* Special Move: Fennec chooses one monster. That monster's health will become 0.
There is no way other than Attack and Special Move to decrease the monsters' health.
Fennec wins when all the monsters' healths become 0 or below.
Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 0 \leq K \leq 2 \times 10^5
* 1 \leq H_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N K
H_1 ... H_N
Output
Print the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning.
Examples
Input
3 1
4 1 5
Output
5
Input
8 9
7 9 3 2 3 8 4 6
Output
0
Input
3 0
1000000000 1000000000 1000000000
Output
3000000000 | instruction | 0 | 84,806 | 2 | 169,612 |
"Correct Solution:
```
R = lambda: map(int, input().split())
n, k = R()
print(sum(sorted(R())[:n - k]) if k < n else 0)
``` | output | 1 | 84,806 | 2 | 169,613 |
Provide a correct Python 3 solution for this coding contest problem.
Fennec is fighting with N monsters.
The health of the i-th monster is H_i.
Fennec can do the following two actions:
* Attack: Fennec chooses one monster. That monster's health will decrease by 1.
* Special Move: Fennec chooses one monster. That monster's health will become 0.
There is no way other than Attack and Special Move to decrease the monsters' health.
Fennec wins when all the monsters' healths become 0 or below.
Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 0 \leq K \leq 2 \times 10^5
* 1 \leq H_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N K
H_1 ... H_N
Output
Print the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning.
Examples
Input
3 1
4 1 5
Output
5
Input
8 9
7 9 3 2 3 8 4 6
Output
0
Input
3 0
1000000000 1000000000 1000000000
Output
3000000000 | instruction | 0 | 84,807 | 2 | 169,614 |
"Correct Solution:
```
N,H=map(int,input().split())
Mon=list(map(int,input().split()))
Mon=sorted(Mon)[::-1]
print(sum(Mon[H::]))
``` | output | 1 | 84,807 | 2 | 169,615 |
Provide a correct Python 3 solution for this coding contest problem.
Fennec is fighting with N monsters.
The health of the i-th monster is H_i.
Fennec can do the following two actions:
* Attack: Fennec chooses one monster. That monster's health will decrease by 1.
* Special Move: Fennec chooses one monster. That monster's health will become 0.
There is no way other than Attack and Special Move to decrease the monsters' health.
Fennec wins when all the monsters' healths become 0 or below.
Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 0 \leq K \leq 2 \times 10^5
* 1 \leq H_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N K
H_1 ... H_N
Output
Print the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning.
Examples
Input
3 1
4 1 5
Output
5
Input
8 9
7 9 3 2 3 8 4 6
Output
0
Input
3 0
1000000000 1000000000 1000000000
Output
3000000000 | instruction | 0 | 84,808 | 2 | 169,616 |
"Correct Solution:
```
N, K = map(int, input().split())
*H, = sorted(map(int, input().split()), reverse=True)
print(sum(H[K:]))
``` | output | 1 | 84,808 | 2 | 169,617 |
Provide a correct Python 3 solution for this coding contest problem.
Fennec is fighting with N monsters.
The health of the i-th monster is H_i.
Fennec can do the following two actions:
* Attack: Fennec chooses one monster. That monster's health will decrease by 1.
* Special Move: Fennec chooses one monster. That monster's health will become 0.
There is no way other than Attack and Special Move to decrease the monsters' health.
Fennec wins when all the monsters' healths become 0 or below.
Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 0 \leq K \leq 2 \times 10^5
* 1 \leq H_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N K
H_1 ... H_N
Output
Print the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning.
Examples
Input
3 1
4 1 5
Output
5
Input
8 9
7 9 3 2 3 8 4 6
Output
0
Input
3 0
1000000000 1000000000 1000000000
Output
3000000000 | instruction | 0 | 84,809 | 2 | 169,618 |
"Correct Solution:
```
N,K = map(int,input().split())
print(sum(sorted(map(int,input().split()))[:max(0,N-K)]))
``` | output | 1 | 84,809 | 2 | 169,619 |
Provide a correct Python 3 solution for this coding contest problem.
Fennec is fighting with N monsters.
The health of the i-th monster is H_i.
Fennec can do the following two actions:
* Attack: Fennec chooses one monster. That monster's health will decrease by 1.
* Special Move: Fennec chooses one monster. That monster's health will become 0.
There is no way other than Attack and Special Move to decrease the monsters' health.
Fennec wins when all the monsters' healths become 0 or below.
Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 0 \leq K \leq 2 \times 10^5
* 1 \leq H_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N K
H_1 ... H_N
Output
Print the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning.
Examples
Input
3 1
4 1 5
Output
5
Input
8 9
7 9 3 2 3 8 4 6
Output
0
Input
3 0
1000000000 1000000000 1000000000
Output
3000000000 | instruction | 0 | 84,810 | 2 | 169,620 |
"Correct Solution:
```
N,K = map(int,input().split())
H = sorted(list(map(int,input().split())))[::-1]
print(sum(H[K:]))
``` | output | 1 | 84,810 | 2 | 169,621 |
Provide a correct Python 3 solution for this coding contest problem.
Fennec is fighting with N monsters.
The health of the i-th monster is H_i.
Fennec can do the following two actions:
* Attack: Fennec chooses one monster. That monster's health will decrease by 1.
* Special Move: Fennec chooses one monster. That monster's health will become 0.
There is no way other than Attack and Special Move to decrease the monsters' health.
Fennec wins when all the monsters' healths become 0 or below.
Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 0 \leq K \leq 2 \times 10^5
* 1 \leq H_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N K
H_1 ... H_N
Output
Print the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning.
Examples
Input
3 1
4 1 5
Output
5
Input
8 9
7 9 3 2 3 8 4 6
Output
0
Input
3 0
1000000000 1000000000 1000000000
Output
3000000000 | instruction | 0 | 84,811 | 2 | 169,622 |
"Correct Solution:
```
N,K = map(int,input().split())
H = list(map(int,input().split()))
H.sort(reverse=True)
print(sum(H[K::]))
``` | output | 1 | 84,811 | 2 | 169,623 |
Provide a correct Python 3 solution for this coding contest problem.
Fennec is fighting with N monsters.
The health of the i-th monster is H_i.
Fennec can do the following two actions:
* Attack: Fennec chooses one monster. That monster's health will decrease by 1.
* Special Move: Fennec chooses one monster. That monster's health will become 0.
There is no way other than Attack and Special Move to decrease the monsters' health.
Fennec wins when all the monsters' healths become 0 or below.
Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 0 \leq K \leq 2 \times 10^5
* 1 \leq H_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N K
H_1 ... H_N
Output
Print the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning.
Examples
Input
3 1
4 1 5
Output
5
Input
8 9
7 9 3 2 3 8 4 6
Output
0
Input
3 0
1000000000 1000000000 1000000000
Output
3000000000 | instruction | 0 | 84,812 | 2 | 169,624 |
"Correct Solution:
```
n,k = map(int,input().split())
l=sorted(list(map(int,input().split())))
print(sum(l[:max(0,n-k)]))
``` | output | 1 | 84,812 | 2 | 169,625 |
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