message stringlengths 2 45.8k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 254 108k | cluster float64 3 3 | __index_level_0__ int64 508 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
Walking through the streets of Marshmallow City, Slastyona have spotted some merchants selling a kind of useless toy which is very popular nowadays – caramel spinner! Wanting to join the craze, she has immediately bought the strange contraption.
Spinners in Sweetland have the form of V-shaped pieces of caramel. Each spinner can, well, spin around an invisible magic axis. At a specific point in time, a spinner can take 4 positions shown below (each one rotated 90 degrees relative to the previous, with the fourth one followed by the first one):
<image>
After the spinner was spun, it starts its rotation, which is described by a following algorithm: the spinner maintains its position for a second then majestically switches to the next position in clockwise or counter-clockwise order, depending on the direction the spinner was spun in.
Slastyona managed to have spinner rotating for exactly n seconds. Being fascinated by elegance of the process, she completely forgot the direction the spinner was spun in! Lucky for her, she managed to recall the starting position, and wants to deduct the direction given the information she knows. Help her do this.
Input
There are two characters in the first string – the starting and the ending position of a spinner. The position is encoded with one of the following characters: v (ASCII code 118, lowercase v), < (ASCII code 60), ^ (ASCII code 94) or > (ASCII code 62) (see the picture above for reference). Characters are separated by a single space.
In the second strings, a single number n is given (0 ≤ n ≤ 109) – the duration of the rotation.
It is guaranteed that the ending position of a spinner is a result of a n second spin in any of the directions, assuming the given starting position.
Output
Output cw, if the direction is clockwise, ccw – if counter-clockwise, and undefined otherwise.
Examples
Input
^ >
1
Output
cw
Input
< ^
3
Output
ccw
Input
^ v
6
Output
undefined
Submitted Solution:
```
s,e=input().split()
n=int(input())
ccw='^<v>^<v>'
cw='^>v<^>v<'
i=n%4
if cw[cw.index(s)+i]==ccw[ccw.index(s)+i]==e:
print("undefined")
elif ccw[ccw.index(s)+i]==e:
print("ccw")
else:
print("cw")
``` | instruction | 0 | 69,522 | 3 | 139,044 |
Yes | output | 1 | 69,522 | 3 | 139,045 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
Walking through the streets of Marshmallow City, Slastyona have spotted some merchants selling a kind of useless toy which is very popular nowadays – caramel spinner! Wanting to join the craze, she has immediately bought the strange contraption.
Spinners in Sweetland have the form of V-shaped pieces of caramel. Each spinner can, well, spin around an invisible magic axis. At a specific point in time, a spinner can take 4 positions shown below (each one rotated 90 degrees relative to the previous, with the fourth one followed by the first one):
<image>
After the spinner was spun, it starts its rotation, which is described by a following algorithm: the spinner maintains its position for a second then majestically switches to the next position in clockwise or counter-clockwise order, depending on the direction the spinner was spun in.
Slastyona managed to have spinner rotating for exactly n seconds. Being fascinated by elegance of the process, she completely forgot the direction the spinner was spun in! Lucky for her, she managed to recall the starting position, and wants to deduct the direction given the information she knows. Help her do this.
Input
There are two characters in the first string – the starting and the ending position of a spinner. The position is encoded with one of the following characters: v (ASCII code 118, lowercase v), < (ASCII code 60), ^ (ASCII code 94) or > (ASCII code 62) (see the picture above for reference). Characters are separated by a single space.
In the second strings, a single number n is given (0 ≤ n ≤ 109) – the duration of the rotation.
It is guaranteed that the ending position of a spinner is a result of a n second spin in any of the directions, assuming the given starting position.
Output
Output cw, if the direction is clockwise, ccw – if counter-clockwise, and undefined otherwise.
Examples
Input
^ >
1
Output
cw
Input
< ^
3
Output
ccw
Input
^ v
6
Output
undefined
Submitted Solution:
```
s=input()
n=int(input())
d={}
d['^']=0
d['>']=1
d['v']=2
d['<']=3
if n%4==2 or n%4==0:
print("undefined")
else:
sum=(d[s[2]]-d[s[0]]+4)%4;
if(sum==n%4):
print("cw")
else:
print("ccw")
``` | instruction | 0 | 69,523 | 3 | 139,046 |
Yes | output | 1 | 69,523 | 3 | 139,047 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
Walking through the streets of Marshmallow City, Slastyona have spotted some merchants selling a kind of useless toy which is very popular nowadays – caramel spinner! Wanting to join the craze, she has immediately bought the strange contraption.
Spinners in Sweetland have the form of V-shaped pieces of caramel. Each spinner can, well, spin around an invisible magic axis. At a specific point in time, a spinner can take 4 positions shown below (each one rotated 90 degrees relative to the previous, with the fourth one followed by the first one):
<image>
After the spinner was spun, it starts its rotation, which is described by a following algorithm: the spinner maintains its position for a second then majestically switches to the next position in clockwise or counter-clockwise order, depending on the direction the spinner was spun in.
Slastyona managed to have spinner rotating for exactly n seconds. Being fascinated by elegance of the process, she completely forgot the direction the spinner was spun in! Lucky for her, she managed to recall the starting position, and wants to deduct the direction given the information she knows. Help her do this.
Input
There are two characters in the first string – the starting and the ending position of a spinner. The position is encoded with one of the following characters: v (ASCII code 118, lowercase v), < (ASCII code 60), ^ (ASCII code 94) or > (ASCII code 62) (see the picture above for reference). Characters are separated by a single space.
In the second strings, a single number n is given (0 ≤ n ≤ 109) – the duration of the rotation.
It is guaranteed that the ending position of a spinner is a result of a n second spin in any of the directions, assuming the given starting position.
Output
Output cw, if the direction is clockwise, ccw – if counter-clockwise, and undefined otherwise.
Examples
Input
^ >
1
Output
cw
Input
< ^
3
Output
ccw
Input
^ v
6
Output
undefined
Submitted Solution:
```
string = input()
s = string[0]
a = string[1]
n = int(input())
b = n%4
if s == '>':
if a == '^':
if b == 1:
print("ccw")
else:
print("cw")
elif a =='v':
if b == 3:
print("ccw")
else:
print("cw")
else:
print("undefined")
elif s == '<':
if a == '^':
if b == 1:
print("cw")
else:
print("ccw")
elif a =='v':
if b == 3:
print("cw")
else:
print("ccw")
else:
print("undefined")
elif s == '^':
if a == '>':
if b == 1:
print("cw")
else:
print("ccw")
elif a =='<':
if b == 3:
print("cw")
else:
print("ccw")
else:
print("undefined")
elif s == 'v':
if a == '>':
if b == 1:
print("ccw")
else:
print("cw")
elif a =='<':
if b == 3:
print("ccw")
else:
print("cw")
else:
print("undefined")
``` | instruction | 0 | 69,524 | 3 | 139,048 |
No | output | 1 | 69,524 | 3 | 139,049 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
Walking through the streets of Marshmallow City, Slastyona have spotted some merchants selling a kind of useless toy which is very popular nowadays – caramel spinner! Wanting to join the craze, she has immediately bought the strange contraption.
Spinners in Sweetland have the form of V-shaped pieces of caramel. Each spinner can, well, spin around an invisible magic axis. At a specific point in time, a spinner can take 4 positions shown below (each one rotated 90 degrees relative to the previous, with the fourth one followed by the first one):
<image>
After the spinner was spun, it starts its rotation, which is described by a following algorithm: the spinner maintains its position for a second then majestically switches to the next position in clockwise or counter-clockwise order, depending on the direction the spinner was spun in.
Slastyona managed to have spinner rotating for exactly n seconds. Being fascinated by elegance of the process, she completely forgot the direction the spinner was spun in! Lucky for her, she managed to recall the starting position, and wants to deduct the direction given the information she knows. Help her do this.
Input
There are two characters in the first string – the starting and the ending position of a spinner. The position is encoded with one of the following characters: v (ASCII code 118, lowercase v), < (ASCII code 60), ^ (ASCII code 94) or > (ASCII code 62) (see the picture above for reference). Characters are separated by a single space.
In the second strings, a single number n is given (0 ≤ n ≤ 109) – the duration of the rotation.
It is guaranteed that the ending position of a spinner is a result of a n second spin in any of the directions, assuming the given starting position.
Output
Output cw, if the direction is clockwise, ccw – if counter-clockwise, and undefined otherwise.
Examples
Input
^ >
1
Output
cw
Input
< ^
3
Output
ccw
Input
^ v
6
Output
undefined
Submitted Solution:
```
a,b = input().split(" ")
n = int(input())
c = ord(a)
d = ord(b)
if (a == b) or (a == '<' and b == '>') or (a == '<' and b == '<') or (a == '^' and b == 'v') or (a == 'v' and b == '^'):
print('undefined')
if (a == '^' and b == '>'):
if ((n - 1)%4 == 0) or n==0:
print('cw')
if ((n-3)%4 == 0) or n == 0:
print('ccw')
if (a == '^' and b == '<'):
if ((n - 1)%4 == 0) or n==0:
print('ccw')
if ((n-3)%4 == 0) or n == 0:
print('cw')
if (a == '>' and b == '^'):
if ((n - 1)%4 == 0) or n==0:
print('ccw')
if ((n-3)%4 == 0) or n == 0:
print('cw')
if (c == '<' and d == '^'):
if ((n - 1)%4 == 0) or n==0:
print('cw')
if ((n-3)%4 == 0) or n == 0:
print('ccw')
if (c == 'v' and d == '>'):
if ((n - 1)%4 == 0) or n==0:
print('ccw')
if ((n-3)%4 == 0) or n == 0:
print('cw')
if (c == 'v' and d == '<'):
if ((n - 1)%4 == 0) or n==0:
print('cw')
if ((n-3)%4 == 0) or n == 0:
print('ccw')
if (c == '<' and d == 'v'):
if ((n - 1)%4 == 0) or n==0:
print('cw')
if ((n-3)%4 == 0) or n == 0:
print('ccw')
if (c == '<' and d == 'v'):
if ((n - 1)%4 == 0) or n==0:
print('ccw')
if ((n-3)%4 == 0) or n == 0:
print('cw')
``` | instruction | 0 | 69,525 | 3 | 139,050 |
No | output | 1 | 69,525 | 3 | 139,051 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
Walking through the streets of Marshmallow City, Slastyona have spotted some merchants selling a kind of useless toy which is very popular nowadays – caramel spinner! Wanting to join the craze, she has immediately bought the strange contraption.
Spinners in Sweetland have the form of V-shaped pieces of caramel. Each spinner can, well, spin around an invisible magic axis. At a specific point in time, a spinner can take 4 positions shown below (each one rotated 90 degrees relative to the previous, with the fourth one followed by the first one):
<image>
After the spinner was spun, it starts its rotation, which is described by a following algorithm: the spinner maintains its position for a second then majestically switches to the next position in clockwise or counter-clockwise order, depending on the direction the spinner was spun in.
Slastyona managed to have spinner rotating for exactly n seconds. Being fascinated by elegance of the process, she completely forgot the direction the spinner was spun in! Lucky for her, she managed to recall the starting position, and wants to deduct the direction given the information she knows. Help her do this.
Input
There are two characters in the first string – the starting and the ending position of a spinner. The position is encoded with one of the following characters: v (ASCII code 118, lowercase v), < (ASCII code 60), ^ (ASCII code 94) or > (ASCII code 62) (see the picture above for reference). Characters are separated by a single space.
In the second strings, a single number n is given (0 ≤ n ≤ 109) – the duration of the rotation.
It is guaranteed that the ending position of a spinner is a result of a n second spin in any of the directions, assuming the given starting position.
Output
Output cw, if the direction is clockwise, ccw – if counter-clockwise, and undefined otherwise.
Examples
Input
^ >
1
Output
cw
Input
< ^
3
Output
ccw
Input
^ v
6
Output
undefined
Submitted Solution:
```
s=input().split()
n=int(input())
#v (ASCII code 118, lowercase v), < (ASCII code 60), ^ (ASCII code 94) or > (ASCII code 62)
if (s[0]==chr(94) and s[1]==chr(62)) or (s[0]==chr(62) and s[1]==chr(118)):
print("cw")
elif (s[0]==chr(60) and s[1]==chr(118)) or(s[0]==chr(60) and s[1]==chr(94)):
print("ccw")
else:
print("undefined")
``` | instruction | 0 | 69,526 | 3 | 139,052 |
No | output | 1 | 69,526 | 3 | 139,053 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
Walking through the streets of Marshmallow City, Slastyona have spotted some merchants selling a kind of useless toy which is very popular nowadays – caramel spinner! Wanting to join the craze, she has immediately bought the strange contraption.
Spinners in Sweetland have the form of V-shaped pieces of caramel. Each spinner can, well, spin around an invisible magic axis. At a specific point in time, a spinner can take 4 positions shown below (each one rotated 90 degrees relative to the previous, with the fourth one followed by the first one):
<image>
After the spinner was spun, it starts its rotation, which is described by a following algorithm: the spinner maintains its position for a second then majestically switches to the next position in clockwise or counter-clockwise order, depending on the direction the spinner was spun in.
Slastyona managed to have spinner rotating for exactly n seconds. Being fascinated by elegance of the process, she completely forgot the direction the spinner was spun in! Lucky for her, she managed to recall the starting position, and wants to deduct the direction given the information she knows. Help her do this.
Input
There are two characters in the first string – the starting and the ending position of a spinner. The position is encoded with one of the following characters: v (ASCII code 118, lowercase v), < (ASCII code 60), ^ (ASCII code 94) or > (ASCII code 62) (see the picture above for reference). Characters are separated by a single space.
In the second strings, a single number n is given (0 ≤ n ≤ 109) – the duration of the rotation.
It is guaranteed that the ending position of a spinner is a result of a n second spin in any of the directions, assuming the given starting position.
Output
Output cw, if the direction is clockwise, ccw – if counter-clockwise, and undefined otherwise.
Examples
Input
^ >
1
Output
cw
Input
< ^
3
Output
ccw
Input
^ v
6
Output
undefined
Submitted Solution:
```
a,b = input().split()
n = int(input())
if a == "v":
a = 0
elif a == "<":
a = 1
elif a == "^":
a = 2
else:
a = 3
if b == "v":
b = 0
elif b == "<":
b = 1
elif b == "^":
b = 2
else:
b = 3
if a+n%4 == b: print ("cw")
elif n-a%4 == b: print ("ccw")
else: print ("undefind")
``` | instruction | 0 | 69,527 | 3 | 139,054 |
No | output | 1 | 69,527 | 3 | 139,055 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In AtCoder city, there are five antennas standing in a straight line. They are called Antenna A, B, C, D and E from west to east, and their coordinates are a, b, c, d and e, respectively.
Two antennas can communicate directly if the distance between them is k or less, and they cannot if the distance is greater than k.
Determine if there exists a pair of antennas that cannot communicate directly.
Here, assume that the distance between two antennas at coordinates p and q (p < q) is q - p.
Constraints
* a, b, c, d, e and k are integers between 0 and 123 (inclusive).
* a < b < c < d < e
Input
Input is given from Standard Input in the following format:
a
b
c
d
e
k
Output
Print `:(` if there exists a pair of antennas that cannot communicate directly, and print `Yay!` if there is no such pair.
Examples
Input
1
2
4
8
9
15
Output
Yay!
Input
15
18
26
35
36
18
Output
:(
Submitted Solution:
```
x = [int(input()) for i in range(6)]
if x[4]-x[0]>x[5]: print(":(")
else: print("Yay!")
``` | instruction | 0 | 69,637 | 3 | 139,274 |
Yes | output | 1 | 69,637 | 3 | 139,275 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In AtCoder city, there are five antennas standing in a straight line. They are called Antenna A, B, C, D and E from west to east, and their coordinates are a, b, c, d and e, respectively.
Two antennas can communicate directly if the distance between them is k or less, and they cannot if the distance is greater than k.
Determine if there exists a pair of antennas that cannot communicate directly.
Here, assume that the distance between two antennas at coordinates p and q (p < q) is q - p.
Constraints
* a, b, c, d, e and k are integers between 0 and 123 (inclusive).
* a < b < c < d < e
Input
Input is given from Standard Input in the following format:
a
b
c
d
e
k
Output
Print `:(` if there exists a pair of antennas that cannot communicate directly, and print `Yay!` if there is no such pair.
Examples
Input
1
2
4
8
9
15
Output
Yay!
Input
15
18
26
35
36
18
Output
:(
Submitted Solution:
```
a,b,c,d,e=(int(input()) for i in range(5))
k=int(input())
print('Yay!' if e-a <= k else ':(')
``` | instruction | 0 | 69,638 | 3 | 139,276 |
Yes | output | 1 | 69,638 | 3 | 139,277 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In AtCoder city, there are five antennas standing in a straight line. They are called Antenna A, B, C, D and E from west to east, and their coordinates are a, b, c, d and e, respectively.
Two antennas can communicate directly if the distance between them is k or less, and they cannot if the distance is greater than k.
Determine if there exists a pair of antennas that cannot communicate directly.
Here, assume that the distance between two antennas at coordinates p and q (p < q) is q - p.
Constraints
* a, b, c, d, e and k are integers between 0 and 123 (inclusive).
* a < b < c < d < e
Input
Input is given from Standard Input in the following format:
a
b
c
d
e
k
Output
Print `:(` if there exists a pair of antennas that cannot communicate directly, and print `Yay!` if there is no such pair.
Examples
Input
1
2
4
8
9
15
Output
Yay!
Input
15
18
26
35
36
18
Output
:(
Submitted Solution:
```
a = [int(input()) for i in range(6)]
if a[4] - a[0] > a[5]:
print(':(')
else:
print('Yay!')
``` | instruction | 0 | 69,639 | 3 | 139,278 |
Yes | output | 1 | 69,639 | 3 | 139,279 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In AtCoder city, there are five antennas standing in a straight line. They are called Antenna A, B, C, D and E from west to east, and their coordinates are a, b, c, d and e, respectively.
Two antennas can communicate directly if the distance between them is k or less, and they cannot if the distance is greater than k.
Determine if there exists a pair of antennas that cannot communicate directly.
Here, assume that the distance between two antennas at coordinates p and q (p < q) is q - p.
Constraints
* a, b, c, d, e and k are integers between 0 and 123 (inclusive).
* a < b < c < d < e
Input
Input is given from Standard Input in the following format:
a
b
c
d
e
k
Output
Print `:(` if there exists a pair of antennas that cannot communicate directly, and print `Yay!` if there is no such pair.
Examples
Input
1
2
4
8
9
15
Output
Yay!
Input
15
18
26
35
36
18
Output
:(
Submitted Solution:
```
a,b,c,d,e=[int(input())for _ in range(5)]
k=int(input())
print(':(' if e-a>k else 'Yay!')
``` | instruction | 0 | 69,640 | 3 | 139,280 |
Yes | output | 1 | 69,640 | 3 | 139,281 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In AtCoder city, there are five antennas standing in a straight line. They are called Antenna A, B, C, D and E from west to east, and their coordinates are a, b, c, d and e, respectively.
Two antennas can communicate directly if the distance between them is k or less, and they cannot if the distance is greater than k.
Determine if there exists a pair of antennas that cannot communicate directly.
Here, assume that the distance between two antennas at coordinates p and q (p < q) is q - p.
Constraints
* a, b, c, d, e and k are integers between 0 and 123 (inclusive).
* a < b < c < d < e
Input
Input is given from Standard Input in the following format:
a
b
c
d
e
k
Output
Print `:(` if there exists a pair of antennas that cannot communicate directly, and print `Yay!` if there is no such pair.
Examples
Input
1
2
4
8
9
15
Output
Yay!
Input
15
18
26
35
36
18
Output
:(
Submitted Solution:
```
list = [int(input()) for i in range(5)]
k = int(input())
a = 0
if i in range(5):
for j in range(5):
if abs(list[i] - list[j]) > k:
a = 1
print('Yay!' if a==0 else ':(')
``` | instruction | 0 | 69,641 | 3 | 139,282 |
No | output | 1 | 69,641 | 3 | 139,283 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In AtCoder city, there are five antennas standing in a straight line. They are called Antenna A, B, C, D and E from west to east, and their coordinates are a, b, c, d and e, respectively.
Two antennas can communicate directly if the distance between them is k or less, and they cannot if the distance is greater than k.
Determine if there exists a pair of antennas that cannot communicate directly.
Here, assume that the distance between two antennas at coordinates p and q (p < q) is q - p.
Constraints
* a, b, c, d, e and k are integers between 0 and 123 (inclusive).
* a < b < c < d < e
Input
Input is given from Standard Input in the following format:
a
b
c
d
e
k
Output
Print `:(` if there exists a pair of antennas that cannot communicate directly, and print `Yay!` if there is no such pair.
Examples
Input
1
2
4
8
9
15
Output
Yay!
Input
15
18
26
35
36
18
Output
:(
Submitted Solution:
```
l = [int(input()) for _ in range(5)]
k = int(input())
for i in range(4):
if l[i+1] - l[i] > k:
print(':(')
break
else:
print('Yay!')
``` | instruction | 0 | 69,642 | 3 | 139,284 |
No | output | 1 | 69,642 | 3 | 139,285 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In AtCoder city, there are five antennas standing in a straight line. They are called Antenna A, B, C, D and E from west to east, and their coordinates are a, b, c, d and e, respectively.
Two antennas can communicate directly if the distance between them is k or less, and they cannot if the distance is greater than k.
Determine if there exists a pair of antennas that cannot communicate directly.
Here, assume that the distance between two antennas at coordinates p and q (p < q) is q - p.
Constraints
* a, b, c, d, e and k are integers between 0 and 123 (inclusive).
* a < b < c < d < e
Input
Input is given from Standard Input in the following format:
a
b
c
d
e
k
Output
Print `:(` if there exists a pair of antennas that cannot communicate directly, and print `Yay!` if there is no such pair.
Examples
Input
1
2
4
8
9
15
Output
Yay!
Input
15
18
26
35
36
18
Output
:(
Submitted Solution:
```
a = [int(input()) for _ in range(5)]
k = int(input())
if a[4] - a[0] < k:
print('Yay!')
else:
print(':(')
``` | instruction | 0 | 69,643 | 3 | 139,286 |
No | output | 1 | 69,643 | 3 | 139,287 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In AtCoder city, there are five antennas standing in a straight line. They are called Antenna A, B, C, D and E from west to east, and their coordinates are a, b, c, d and e, respectively.
Two antennas can communicate directly if the distance between them is k or less, and they cannot if the distance is greater than k.
Determine if there exists a pair of antennas that cannot communicate directly.
Here, assume that the distance between two antennas at coordinates p and q (p < q) is q - p.
Constraints
* a, b, c, d, e and k are integers between 0 and 123 (inclusive).
* a < b < c < d < e
Input
Input is given from Standard Input in the following format:
a
b
c
d
e
k
Output
Print `:(` if there exists a pair of antennas that cannot communicate directly, and print `Yay!` if there is no such pair.
Examples
Input
1
2
4
8
9
15
Output
Yay!
Input
15
18
26
35
36
18
Output
:(
Submitted Solution:
```
a = []
for _ in range(5):
a.append(int(input()))
b =[]
c = []
for i in range(5):
b[i] = a[i]
for i in range(5):
while b[i] > 10:
b[i] = b[i] - 10
if min(b[i]) == 10:
return sum(a)
else:
for i in range(5):
if b[i] == 10:
c[i] = a[i]
else:
c[i] = a[i] +10 -b[i]
d = sum(c)
mini = min(b)
ans = d - 10 + mini
return ans
``` | instruction | 0 | 69,644 | 3 | 139,288 |
No | output | 1 | 69,644 | 3 | 139,289 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Niwango-kun, an employee of Dwango Co., Ltd., likes Niconico TV-chan, so he collected a lot of soft toys of her and spread them on the floor.
Niwango-kun has N black rare soft toys of Niconico TV-chan and they are spread together with ordinary ones. He wanted these black rare soft toys to be close together, so he decided to rearrange them.
In an infinitely large two-dimensional plane, every lattice point has a soft toy on it. The coordinates (x_i,y_i) of N black rare soft toys are given. All soft toys are considered to be points (without a length, area, or volume).
He may perform the following operation arbitrarily many times:
* Put an axis-aligned square with side length D, rotate the square by 90 degrees with four soft toys on the four corners of the square. More specifically, if the left bottom corner's coordinate is (x, y), rotate four points (x,y) \rightarrow (x+D,y) \rightarrow (x+D,y+D) \rightarrow (x,y+D) \rightarrow (x,y) in this order. Each of the four corners of the square must be on a lattice point.
Let's define the scatteredness of an arrangement by the minimum side length of an axis-aligned square enclosing all black rare soft toys. Black rare soft toys on the edges or the vertices of a square are considered to be enclosed by the square.
Find the minimum scatteredness after he performs arbitrarily many operations.
Constraints
* 2 \leq N \leq 10^5
* 1 \leq D \leq 1000
* 0 \leq x_i, y_i \leq 10^9
* Given coordinates are pairwise distinct
* All numbers given in input are integers
Input
Input is given from Standard Input in the following format:
N D
x_1 y_1
:
x_N y_N
Output
Print the answer.
Examples
Input
3 1
0 0
1 0
2 0
Output
1
Input
19 2
1 3
2 3
0 1
1 1
2 1
3 1
4 4
5 4
6 4
7 4
8 4
8 3
8 2
8 1
8 0
7 0
6 0
5 0
4 0
Output
4
Input
8 3
0 0
0 3
3 0
3 3
2 2
2 5
5 2
5 5
Output
4
Submitted Solution:
```
N,D = map(int,input().split())
pos = [[0 for _ in range(D)] for i in range(D)]
flg = [[0 for _ in range(D)] for i in range(D)]
for i in range(N):
x,y = map(int,input().split())
pos[x%D][y%D] += 1
maxn = -1
for i in range(D):
for j in range(D):
maxn = max(maxn,pos[i][j])
sqs = int((maxn-1)**0.5)+1
lx = [0 for _ in range(D)]
ly = [0 for _ in range(D)]
for i in range(D):
for j in range(D):
if pos[i][j]<=(sqs-1)**2:
pass
elif pos[i][j]<=(sqs-1)*sqs:
flg[i][j] = 1
lx[i] = max(lx[i],1)
ly[j] = max(ly[i],1)
else:
flg[i][j] = 2
lx[i] = 2
ly[j] = 2
flaggg = False
for sq in range(D):
for i in range(D):
for j in range(D):
flagg = True
for x in range(D):
for y in range(D):
if (i<=x<=i+sq or i<=x+D<=i+sq)and (j<=y<=j+sq or j<=y+D<=j+sq):
pass
elif (i<=x<=i+sq or i<=x+D<=i+sq) or (j<=y<=j+sq or j<=y+D<=j+sq):
if flg[x][y]==2:
flagg = False
break
else:
if flg[x][y]==1:
flagg = False
break
if not flagg:
break
if flagg:
flaggg = True
break
if flaggg:
break
if flaggg:
break
print((int((maxn-1)**0.5))*D+sq)
``` | instruction | 0 | 69,646 | 3 | 139,292 |
No | output | 1 | 69,646 | 3 | 139,293 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Niwango-kun, an employee of Dwango Co., Ltd., likes Niconico TV-chan, so he collected a lot of soft toys of her and spread them on the floor.
Niwango-kun has N black rare soft toys of Niconico TV-chan and they are spread together with ordinary ones. He wanted these black rare soft toys to be close together, so he decided to rearrange them.
In an infinitely large two-dimensional plane, every lattice point has a soft toy on it. The coordinates (x_i,y_i) of N black rare soft toys are given. All soft toys are considered to be points (without a length, area, or volume).
He may perform the following operation arbitrarily many times:
* Put an axis-aligned square with side length D, rotate the square by 90 degrees with four soft toys on the four corners of the square. More specifically, if the left bottom corner's coordinate is (x, y), rotate four points (x,y) \rightarrow (x+D,y) \rightarrow (x+D,y+D) \rightarrow (x,y+D) \rightarrow (x,y) in this order. Each of the four corners of the square must be on a lattice point.
Let's define the scatteredness of an arrangement by the minimum side length of an axis-aligned square enclosing all black rare soft toys. Black rare soft toys on the edges or the vertices of a square are considered to be enclosed by the square.
Find the minimum scatteredness after he performs arbitrarily many operations.
Constraints
* 2 \leq N \leq 10^5
* 1 \leq D \leq 1000
* 0 \leq x_i, y_i \leq 10^9
* Given coordinates are pairwise distinct
* All numbers given in input are integers
Input
Input is given from Standard Input in the following format:
N D
x_1 y_1
:
x_N y_N
Output
Print the answer.
Examples
Input
3 1
0 0
1 0
2 0
Output
1
Input
19 2
1 3
2 3
0 1
1 1
2 1
3 1
4 4
5 4
6 4
7 4
8 4
8 3
8 2
8 1
8 0
7 0
6 0
5 0
4 0
Output
4
Input
8 3
0 0
0 3
3 0
3 3
2 2
2 5
5 2
5 5
Output
4
Submitted Solution:
```
n,d = map(int,input().split())
num = [[0]*d for i in range(d)]
a = 0
for i in range(n):
x,y = map(int,input().split())
x %=d
y%=d
num[x][y] += 1
a = max(a,num[x][y])
x=1
while x*x<a:
x += 1
r = (x-1)*d
a = x-1
dai = d-1
syo = 0
anum = [[[0]*d for i in range(d)]for i in range(2)]
rui = [[[0]*d for i in range(d)]for i in range(2)]
for i in range(d):
for j in range(d):
if num[i][j]<= a*a:
continue
elif num[i][j]<= a*(a+1):
anum[1][i][j]=1
else:
anum[0][i][j]=1
for x in range(2):
for i in range(d):
for j in range(d):
if i:
rui[x][i][j]+=rui[x][i-1][j]
if j:
rui[x][i][j]+=rui[x][i][j-1]
if i and j:
rui[x][i][j]-=rui[x][i-1][j-1]
rui[x][i][j]+=anum[x][(i-1)%d][(j-1)%d]
def cheak(kon):
for i in range(d):
for j in range(d):
if rui[0][(i+d-1)%d][(j+d-1)%d] - rui[0][(i+kon+1)%d][(j+kon+1)%d]:
return 0
if rui[1][(i+d-1)%d][(j+d-1)%d] + rui[1][(i+kon+1)%d][(j+kon+1)%d] - rui[1][(i+d-1)%d][(j+kon+1)%d] - rui[1][(i+kon+1)%d][(j+d-1)%d]:
return 0
return 1
kon = (dai+syo)//2
while True:
if dai-syo <= 1:
if cheak(syo) == 1:
dai = syo
break
kon = (dai+syo)//2
c = cheak(kon)
if c == 1:
dai = kon
else:
syo = kon
print(dai+r)
``` | instruction | 0 | 69,647 | 3 | 139,294 |
No | output | 1 | 69,647 | 3 | 139,295 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Niwango-kun, an employee of Dwango Co., Ltd., likes Niconico TV-chan, so he collected a lot of soft toys of her and spread them on the floor.
Niwango-kun has N black rare soft toys of Niconico TV-chan and they are spread together with ordinary ones. He wanted these black rare soft toys to be close together, so he decided to rearrange them.
In an infinitely large two-dimensional plane, every lattice point has a soft toy on it. The coordinates (x_i,y_i) of N black rare soft toys are given. All soft toys are considered to be points (without a length, area, or volume).
He may perform the following operation arbitrarily many times:
* Put an axis-aligned square with side length D, rotate the square by 90 degrees with four soft toys on the four corners of the square. More specifically, if the left bottom corner's coordinate is (x, y), rotate four points (x,y) \rightarrow (x+D,y) \rightarrow (x+D,y+D) \rightarrow (x,y+D) \rightarrow (x,y) in this order. Each of the four corners of the square must be on a lattice point.
Let's define the scatteredness of an arrangement by the minimum side length of an axis-aligned square enclosing all black rare soft toys. Black rare soft toys on the edges or the vertices of a square are considered to be enclosed by the square.
Find the minimum scatteredness after he performs arbitrarily many operations.
Constraints
* 2 \leq N \leq 10^5
* 1 \leq D \leq 1000
* 0 \leq x_i, y_i \leq 10^9
* Given coordinates are pairwise distinct
* All numbers given in input are integers
Input
Input is given from Standard Input in the following format:
N D
x_1 y_1
:
x_N y_N
Output
Print the answer.
Examples
Input
3 1
0 0
1 0
2 0
Output
1
Input
19 2
1 3
2 3
0 1
1 1
2 1
3 1
4 4
5 4
6 4
7 4
8 4
8 3
8 2
8 1
8 0
7 0
6 0
5 0
4 0
Output
4
Input
8 3
0 0
0 3
3 0
3 3
2 2
2 5
5 2
5 5
Output
4
Submitted Solution:
```
n, d = [int(i) for i in input().split()]
X, Y = zip(*[[int(i) for i in input().split()] for j in range(n)])
S = set()
for x, y in zip(X, Y):
x %= d
y %= d
dy = 0
try:
if x > y:
while True:
for dx in range(dy+1):
if not (x+dx*d, y+dy*d) in S:
S.add((x+dx*d, y+dy*d))
raise()
dx = dy
for dy in range(dx+1):
if not (x+dx*d, y+dy*d) in S:
S.add((x+dx*d, y+dy*d))
raise()
dy += 1
else:
while True:
for ddy in range(dy+1):
if not (x+dy*d, y+ddy*d) in S:
S.add((x+dy*d, y+ddy*d))
raise()
for dx in range(dy+1):
if not (x+dx*d, y+dy*d) in S:
S.add((x+dx*d, y+dy*d))
raise()
dy += 1
except:
pass
X, Y = zip(*tuple(S))
print(max(abs(max(X) - min(X)), (max(Y) - min(Y))))
``` | instruction | 0 | 69,648 | 3 | 139,296 |
No | output | 1 | 69,648 | 3 | 139,297 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Niwango-kun, an employee of Dwango Co., Ltd., likes Niconico TV-chan, so he collected a lot of soft toys of her and spread them on the floor.
Niwango-kun has N black rare soft toys of Niconico TV-chan and they are spread together with ordinary ones. He wanted these black rare soft toys to be close together, so he decided to rearrange them.
In an infinitely large two-dimensional plane, every lattice point has a soft toy on it. The coordinates (x_i,y_i) of N black rare soft toys are given. All soft toys are considered to be points (without a length, area, or volume).
He may perform the following operation arbitrarily many times:
* Put an axis-aligned square with side length D, rotate the square by 90 degrees with four soft toys on the four corners of the square. More specifically, if the left bottom corner's coordinate is (x, y), rotate four points (x,y) \rightarrow (x+D,y) \rightarrow (x+D,y+D) \rightarrow (x,y+D) \rightarrow (x,y) in this order. Each of the four corners of the square must be on a lattice point.
Let's define the scatteredness of an arrangement by the minimum side length of an axis-aligned square enclosing all black rare soft toys. Black rare soft toys on the edges or the vertices of a square are considered to be enclosed by the square.
Find the minimum scatteredness after he performs arbitrarily many operations.
Constraints
* 2 \leq N \leq 10^5
* 1 \leq D \leq 1000
* 0 \leq x_i, y_i \leq 10^9
* Given coordinates are pairwise distinct
* All numbers given in input are integers
Input
Input is given from Standard Input in the following format:
N D
x_1 y_1
:
x_N y_N
Output
Print the answer.
Examples
Input
3 1
0 0
1 0
2 0
Output
1
Input
19 2
1 3
2 3
0 1
1 1
2 1
3 1
4 4
5 4
6 4
7 4
8 4
8 3
8 2
8 1
8 0
7 0
6 0
5 0
4 0
Output
4
Input
8 3
0 0
0 3
3 0
3 3
2 2
2 5
5 2
5 5
Output
4
Submitted Solution:
```
# D
N, D = map(int, input().split())
xyd_list = [[0]*D for _ in range(D)]
for _ in range(N):
x, y = map(int, input().split())
xyd_list[x%D][y%D] += 1
# how many copy we need
mmm = max([max(x) for x in xyd_list])
bound = 1
while bound**2 < mmm:
bound += 1
res = D*bound - 1
# bruce for 500
for i in range(D):
for j in range(D):
res_t = D*(bound - 1)
for k in range(D):
i_ = (i+k)%D
for l in range(D):
j_ = (j+l)%D
if xyd_list[i_][j_] <= (bound - 1)**2:
pass
elif xyd_list[i_][j_] <= (bound - 1)*bound:
res_t = max(res_t, D*(bound - 1) + min(k, l))
else:
res_t = max(res_t, D*(bound - 1) + max(k, l))
if res_t < res:
res = res_t
print(res)
``` | instruction | 0 | 69,649 | 3 | 139,298 |
No | output | 1 | 69,649 | 3 | 139,299 |
Provide a correct Python 3 solution for this coding contest problem.
Consider a closed world and a set of features that are defined for all the objects in the world. Each feature can be answered with "yes" or "no". Using those features, we can identify any object from the rest of the objects in the world. In other words, each object can be represented as a fixed-length sequence of booleans. Any object is different from other objects by at least one feature.
You would like to identify an object from others. For this purpose, you can ask a series of questions to someone who knows what the object is. Every question you can ask is about one of the features. He/she immediately answers each question with "yes" or "no" correctly. You can choose the next question after you get the answer to the previous question.
You kindly pay the answerer 100 yen as a tip for each question. Because you don' t have surplus money, it is necessary to minimize the number of questions in the worst case. You don’t know what is the correct answer, but fortunately know all the objects in the world. Therefore, you can plan an optimal strategy before you start questioning.
The problem you have to solve is: given a set of boolean-encoded objects, minimize the maximum number of questions by which every object in the set is identifiable.
Input
The input is a sequence of multiple datasets. Each dataset begins with a line which consists of two integers, m and n: the number of features, and the number of objects, respectively. You can assume 0 < m ≤ 11 and 0 < n ≤ 128. It is followed by n lines, each of which corresponds to an object. Each line includes a binary string of length m which represent the value ("yes" or "no") of features. There are no two identical objects.
The end of the input is indicated by a line containing two zeros. There are at most 100 datasets.
Output
For each dataset, minimize the maximum number of questions by which every object is identifiable and output the result.
Example
Input
8 1
11010101
11 4
00111001100
01001101011
01010000011
01100110001
11 16
01000101111
01011000000
01011111001
01101101001
01110010111
01110100111
10000001010
10010001000
10010110100
10100010100
10101010110
10110100010
11001010011
11011001001
11111000111
11111011101
11 12
10000000000
01000000000
00100000000
00010000000
00001000000
00000100000
00000010000
00000001000
00000000100
00000000010
00000000001
00000000000
9 32
001000000
000100000
000010000
000001000
000000100
000000010
000000001
000000000
011000000
010100000
010010000
010001000
010000100
010000010
010000001
010000000
101000000
100100000
100010000
100001000
100000100
100000010
100000001
100000000
111000000
110100000
110010000
110001000
110000100
110000010
110000001
110000000
0 0
Output
0
2
4
11
9 | instruction | 0 | 69,751 | 3 | 139,502 |
"Correct Solution:
```
from collections import Counter
while True:
m, n = (int(s) for s in input().split())
if not m:
break
objs = [int(input(), 2) for i in range(n)]
dp = [bytearray(1 << m) for i in range(1 << m)]
bits = [1 << i for i in range(m)]
for mask in reversed(range((1 << m) - 1)):
s = Counter(obj & mask for obj in objs)
for masked, count in s.items():
if count > 1:
dp[mask][masked] = min(max(dp[mask + b][masked],
dp[mask + b][masked + b]) + 1
for b in bits if not b & mask)
print(dp[0][0])
``` | output | 1 | 69,751 | 3 | 139,503 |
Provide a correct Python 3 solution for this coding contest problem.
Consider a closed world and a set of features that are defined for all the objects in the world. Each feature can be answered with "yes" or "no". Using those features, we can identify any object from the rest of the objects in the world. In other words, each object can be represented as a fixed-length sequence of booleans. Any object is different from other objects by at least one feature.
You would like to identify an object from others. For this purpose, you can ask a series of questions to someone who knows what the object is. Every question you can ask is about one of the features. He/she immediately answers each question with "yes" or "no" correctly. You can choose the next question after you get the answer to the previous question.
You kindly pay the answerer 100 yen as a tip for each question. Because you don' t have surplus money, it is necessary to minimize the number of questions in the worst case. You don’t know what is the correct answer, but fortunately know all the objects in the world. Therefore, you can plan an optimal strategy before you start questioning.
The problem you have to solve is: given a set of boolean-encoded objects, minimize the maximum number of questions by which every object in the set is identifiable.
Input
The input is a sequence of multiple datasets. Each dataset begins with a line which consists of two integers, m and n: the number of features, and the number of objects, respectively. You can assume 0 < m ≤ 11 and 0 < n ≤ 128. It is followed by n lines, each of which corresponds to an object. Each line includes a binary string of length m which represent the value ("yes" or "no") of features. There are no two identical objects.
The end of the input is indicated by a line containing two zeros. There are at most 100 datasets.
Output
For each dataset, minimize the maximum number of questions by which every object is identifiable and output the result.
Example
Input
8 1
11010101
11 4
00111001100
01001101011
01010000011
01100110001
11 16
01000101111
01011000000
01011111001
01101101001
01110010111
01110100111
10000001010
10010001000
10010110100
10100010100
10101010110
10110100010
11001010011
11011001001
11111000111
11111011101
11 12
10000000000
01000000000
00100000000
00010000000
00001000000
00000100000
00000010000
00000001000
00000000100
00000000010
00000000001
00000000000
9 32
001000000
000100000
000010000
000001000
000000100
000000010
000000001
000000000
011000000
010100000
010010000
010001000
010000100
010000010
010000001
010000000
101000000
100100000
100010000
100001000
100000100
100000010
100000001
100000000
111000000
110100000
110010000
110001000
110000100
110000010
110000001
110000000
0 0
Output
0
2
4
11
9 | instruction | 0 | 69,752 | 3 | 139,504 |
"Correct Solution:
```
from collections import Counter
while True:
m, n = (int(s) for s in input().split())
if not m:
break
objects = [int(input(), 2) for i in range(n)]
dp = [bytearray(1 << m) for i in range(1 << m)]
bits = [1 << i for i in range(m)]
for asked in reversed(range((1 << m) - 1)):
for masked, count in Counter(obj & asked for obj in objects).items():
if count > 1:
dp[asked][masked] = min(max(dp[asked + b][masked],
dp[asked + b][masked + b])
for b in bits if not b & asked) + 1
print(dp[0][0])
``` | output | 1 | 69,752 | 3 | 139,505 |
Provide a correct Python 3 solution for this coding contest problem.
Consider a closed world and a set of features that are defined for all the objects in the world. Each feature can be answered with "yes" or "no". Using those features, we can identify any object from the rest of the objects in the world. In other words, each object can be represented as a fixed-length sequence of booleans. Any object is different from other objects by at least one feature.
You would like to identify an object from others. For this purpose, you can ask a series of questions to someone who knows what the object is. Every question you can ask is about one of the features. He/she immediately answers each question with "yes" or "no" correctly. You can choose the next question after you get the answer to the previous question.
You kindly pay the answerer 100 yen as a tip for each question. Because you don' t have surplus money, it is necessary to minimize the number of questions in the worst case. You don’t know what is the correct answer, but fortunately know all the objects in the world. Therefore, you can plan an optimal strategy before you start questioning.
The problem you have to solve is: given a set of boolean-encoded objects, minimize the maximum number of questions by which every object in the set is identifiable.
Input
The input is a sequence of multiple datasets. Each dataset begins with a line which consists of two integers, m and n: the number of features, and the number of objects, respectively. You can assume 0 < m ≤ 11 and 0 < n ≤ 128. It is followed by n lines, each of which corresponds to an object. Each line includes a binary string of length m which represent the value ("yes" or "no") of features. There are no two identical objects.
The end of the input is indicated by a line containing two zeros. There are at most 100 datasets.
Output
For each dataset, minimize the maximum number of questions by which every object is identifiable and output the result.
Example
Input
8 1
11010101
11 4
00111001100
01001101011
01010000011
01100110001
11 16
01000101111
01011000000
01011111001
01101101001
01110010111
01110100111
10000001010
10010001000
10010110100
10100010100
10101010110
10110100010
11001010011
11011001001
11111000111
11111011101
11 12
10000000000
01000000000
00100000000
00010000000
00001000000
00000100000
00000010000
00000001000
00000000100
00000000010
00000000001
00000000000
9 32
001000000
000100000
000010000
000001000
000000100
000000010
000000001
000000000
011000000
010100000
010010000
010001000
010000100
010000010
010000001
010000000
101000000
100100000
100010000
100001000
100000100
100000010
100000001
100000000
111000000
110100000
110010000
110001000
110000100
110000010
110000001
110000000
0 0
Output
0
2
4
11
9 | instruction | 0 | 69,753 | 3 | 139,506 |
"Correct Solution:
```
from collections import Counter
import sys
def solve():
readline = sys.stdin.buffer.readline
write = sys.stdout.buffer.write
M, N = map(int, readline().split())
if M == N == 0:
return False
B = [int(readline(), 2) for i in range(N)]
memo = {}
def dfs(s, t):
key = (s, t)
if key in memo:
return memo[key]
c = 0
for b in B:
if (b & s) == t:
c += 1
if c <= 1:
memo[key] = 0
return 0
res = M
for i in range(M):
b = (1 << i)
if s & b == 0:
res = min(res, max(dfs(s|b, t), dfs(s|b, t|b))+1)
memo[key] = res
return res
write(b"%d\n" % dfs(0, 0))
return True
while solve():
...
``` | output | 1 | 69,753 | 3 | 139,507 |
Provide a correct Python 3 solution for this coding contest problem.
Consider a closed world and a set of features that are defined for all the objects in the world. Each feature can be answered with "yes" or "no". Using those features, we can identify any object from the rest of the objects in the world. In other words, each object can be represented as a fixed-length sequence of booleans. Any object is different from other objects by at least one feature.
You would like to identify an object from others. For this purpose, you can ask a series of questions to someone who knows what the object is. Every question you can ask is about one of the features. He/she immediately answers each question with "yes" or "no" correctly. You can choose the next question after you get the answer to the previous question.
You kindly pay the answerer 100 yen as a tip for each question. Because you don' t have surplus money, it is necessary to minimize the number of questions in the worst case. You don’t know what is the correct answer, but fortunately know all the objects in the world. Therefore, you can plan an optimal strategy before you start questioning.
The problem you have to solve is: given a set of boolean-encoded objects, minimize the maximum number of questions by which every object in the set is identifiable.
Input
The input is a sequence of multiple datasets. Each dataset begins with a line which consists of two integers, m and n: the number of features, and the number of objects, respectively. You can assume 0 < m ≤ 11 and 0 < n ≤ 128. It is followed by n lines, each of which corresponds to an object. Each line includes a binary string of length m which represent the value ("yes" or "no") of features. There are no two identical objects.
The end of the input is indicated by a line containing two zeros. There are at most 100 datasets.
Output
For each dataset, minimize the maximum number of questions by which every object is identifiable and output the result.
Example
Input
8 1
11010101
11 4
00111001100
01001101011
01010000011
01100110001
11 16
01000101111
01011000000
01011111001
01101101001
01110010111
01110100111
10000001010
10010001000
10010110100
10100010100
10101010110
10110100010
11001010011
11011001001
11111000111
11111011101
11 12
10000000000
01000000000
00100000000
00010000000
00001000000
00000100000
00000010000
00000001000
00000000100
00000000010
00000000001
00000000000
9 32
001000000
000100000
000010000
000001000
000000100
000000010
000000001
000000000
011000000
010100000
010010000
010001000
010000100
010000010
010000001
010000000
101000000
100100000
100010000
100001000
100000100
100000010
100000001
100000000
111000000
110100000
110010000
110001000
110000100
110000010
110000001
110000000
0 0
Output
0
2
4
11
9 | instruction | 0 | 69,754 | 3 | 139,508 |
"Correct Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**13
mod = 10**9+7
dd = [(-1,0),(0,1),(1,0),(0,-1)]
ddn = [(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)]
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)
def main():
rr = []
def f(n,m):
a = [int(S(), 2) for _ in range(m)]
mi = 0
ma = max(a)
while 2**mi <= ma:
mi += 1
ii = [2**i for i in range(mi+1)]
fm = {}
def _f(a):
k = tuple(a)
if k in fm:
return fm[k]
if len(a) < 2:
fm[k] = 0
return 0
r = inf
for i in ii:
a1 = []
a2 = []
for c in a:
if i & c:
a1.append(c)
else:
a2.append(c)
if not a1 or not a2:
continue
r1 = _f(a1)
r2 = _f(a2)
tr = max(r1, r2) + 1
if r > tr:
r = tr
fm[k] = r
return r
r = _f(a)
return r
while 1:
n,m = LI()
if n == 0:
break
rr.append(f(n,m))
return '\n'.join(map(str,rr))
print(main())
``` | output | 1 | 69,754 | 3 | 139,509 |
Provide a correct Python 3 solution for this coding contest problem.
Consider a closed world and a set of features that are defined for all the objects in the world. Each feature can be answered with "yes" or "no". Using those features, we can identify any object from the rest of the objects in the world. In other words, each object can be represented as a fixed-length sequence of booleans. Any object is different from other objects by at least one feature.
You would like to identify an object from others. For this purpose, you can ask a series of questions to someone who knows what the object is. Every question you can ask is about one of the features. He/she immediately answers each question with "yes" or "no" correctly. You can choose the next question after you get the answer to the previous question.
You kindly pay the answerer 100 yen as a tip for each question. Because you don' t have surplus money, it is necessary to minimize the number of questions in the worst case. You don’t know what is the correct answer, but fortunately know all the objects in the world. Therefore, you can plan an optimal strategy before you start questioning.
The problem you have to solve is: given a set of boolean-encoded objects, minimize the maximum number of questions by which every object in the set is identifiable.
Input
The input is a sequence of multiple datasets. Each dataset begins with a line which consists of two integers, m and n: the number of features, and the number of objects, respectively. You can assume 0 < m ≤ 11 and 0 < n ≤ 128. It is followed by n lines, each of which corresponds to an object. Each line includes a binary string of length m which represent the value ("yes" or "no") of features. There are no two identical objects.
The end of the input is indicated by a line containing two zeros. There are at most 100 datasets.
Output
For each dataset, minimize the maximum number of questions by which every object is identifiable and output the result.
Example
Input
8 1
11010101
11 4
00111001100
01001101011
01010000011
01100110001
11 16
01000101111
01011000000
01011111001
01101101001
01110010111
01110100111
10000001010
10010001000
10010110100
10100010100
10101010110
10110100010
11001010011
11011001001
11111000111
11111011101
11 12
10000000000
01000000000
00100000000
00010000000
00001000000
00000100000
00000010000
00000001000
00000000100
00000000010
00000000001
00000000000
9 32
001000000
000100000
000010000
000001000
000000100
000000010
000000001
000000000
011000000
010100000
010010000
010001000
010000100
010000010
010000001
010000000
101000000
100100000
100010000
100001000
100000100
100000010
100000001
100000000
111000000
110100000
110010000
110001000
110000100
110000010
110000001
110000000
0 0
Output
0
2
4
11
9 | instruction | 0 | 69,755 | 3 | 139,510 |
"Correct Solution:
```
from collections import Counter
while True:
m, n = (int(s) for s in input().split())
if not m:
break
objs = [int(input(), 2) for i in range(n)]
dp = [[0] * (1 << m) for i in range(1 << m)]
bits = [1 << i for i in range(m)]
for mask in reversed(range(1 << m)):
s = Counter(obj & mask for obj in objs)
for masked, value in s.items():
if value > 1:
dp[mask][masked] = min(max(dp[mask | b][masked],
dp[mask | b][masked | b]) + 1
for b in bits if not b & mask)
print(dp[0][0])
``` | output | 1 | 69,755 | 3 | 139,511 |
Provide a correct Python 3 solution for this coding contest problem.
Consider a closed world and a set of features that are defined for all the objects in the world. Each feature can be answered with "yes" or "no". Using those features, we can identify any object from the rest of the objects in the world. In other words, each object can be represented as a fixed-length sequence of booleans. Any object is different from other objects by at least one feature.
You would like to identify an object from others. For this purpose, you can ask a series of questions to someone who knows what the object is. Every question you can ask is about one of the features. He/she immediately answers each question with "yes" or "no" correctly. You can choose the next question after you get the answer to the previous question.
You kindly pay the answerer 100 yen as a tip for each question. Because you don' t have surplus money, it is necessary to minimize the number of questions in the worst case. You don’t know what is the correct answer, but fortunately know all the objects in the world. Therefore, you can plan an optimal strategy before you start questioning.
The problem you have to solve is: given a set of boolean-encoded objects, minimize the maximum number of questions by which every object in the set is identifiable.
Input
The input is a sequence of multiple datasets. Each dataset begins with a line which consists of two integers, m and n: the number of features, and the number of objects, respectively. You can assume 0 < m ≤ 11 and 0 < n ≤ 128. It is followed by n lines, each of which corresponds to an object. Each line includes a binary string of length m which represent the value ("yes" or "no") of features. There are no two identical objects.
The end of the input is indicated by a line containing two zeros. There are at most 100 datasets.
Output
For each dataset, minimize the maximum number of questions by which every object is identifiable and output the result.
Example
Input
8 1
11010101
11 4
00111001100
01001101011
01010000011
01100110001
11 16
01000101111
01011000000
01011111001
01101101001
01110010111
01110100111
10000001010
10010001000
10010110100
10100010100
10101010110
10110100010
11001010011
11011001001
11111000111
11111011101
11 12
10000000000
01000000000
00100000000
00010000000
00001000000
00000100000
00000010000
00000001000
00000000100
00000000010
00000000001
00000000000
9 32
001000000
000100000
000010000
000001000
000000100
000000010
000000001
000000000
011000000
010100000
010010000
010001000
010000100
010000010
010000001
010000000
101000000
100100000
100010000
100001000
100000100
100000010
100000001
100000000
111000000
110100000
110010000
110001000
110000100
110000010
110000001
110000000
0 0
Output
0
2
4
11
9 | instruction | 0 | 69,756 | 3 | 139,512 |
"Correct Solution:
```
from collections import Counter
while True:
m, n = (int(s) for s in input().split())
if not m:
break
objects = [int(input(), 2) for i in range(n)]
dp = [bytearray(1 << m) for i in range(1 << m)]
bits = [1 << i for i in range(m)]
for mask in reversed(range((1 << m) - 1)):
for masked, count in Counter(obj & mask for obj in objects).items():
if count > 1:
dp[mask][masked] = min(max(dp[mask + b][masked],
dp[mask + b][masked + b]) + 1
for b in bits if not b & mask)
print(dp[0][0])
``` | output | 1 | 69,756 | 3 | 139,513 |
Provide a correct Python 3 solution for this coding contest problem.
Notes
For this problem, it is recommended to use floating point numbers, which are more accurate than double.
Input
m n x
k l y
For input, six integers m, n, x, k, l, y are given in the above input format.
These six integers correspond to those in the problem statement, repeating the horizontal m: n cut x times and the vertical k: l cut y times.
1 ≤ m, n, k, l ≤ 100, 0 ≤ x, y ≤ 40, and m, n and l, k are relatively prime.
Output
Print out the expected number of planarians that are regenerating to their original form after a few weeks in a row.
The output is acceptable with an error of 10-6 or less.
Examples
Input
1 1 1
1 1 1
Output
0.562500
Input
1 2 2
1 1 1
Output
0.490741
Input
1 2 0
3 4 0
Output
1.000000 | instruction | 0 | 69,759 | 3 | 139,518 |
"Correct Solution:
```
m,n,x=[int(i) for i in input().split()]
k,l,y=[int(i) for i in input().split()]
res=0.5*(1.0+((m**2+n**2)**x)/((m+n)**(2*x)))
res*=0.5*(1.0+((k**2+l**2)**y)/((k+l)**(2*y)))
print(res)
``` | output | 1 | 69,759 | 3 | 139,519 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One morning when you woke up, it was in a springy labyrinth.
I don't know why I'm in such a strange place. You have the option of waiting for help here, but you know from experience that if you stay in a labyrinth like this for a long time, a gust of wind will surely blow you away. It was. However, the time until the gust blows cannot be judged. So you thought it was best to act to minimize the expected number of moves required to escape the labyrinth.
When I picked up an unidentified scroll that had fallen under my feet and read it as a trial, I happened to be able to perceive the entire map of the labyrinth. Furthermore, by drinking the grass that I happened to have, I was able to know the positions of all the traps. Apparently, there are no traps other than dangerous monsters and springs in this labyrinth.
This labyrinth is shaped like a rectangle with several types of tiles, for example:
.. ## g. #
* #. * #. #
...... #
* s # *. * #
".":floor. You can walk around freely on this.
"#":wall. You can't get inside the wall.
"S": Your first position. Below this tile is the floor.
"G": Stairs. If you ride on this tile, you have escaped from the labyrinth.
"*":Spring. If you ride on this tile, it will be randomly blown onto one of the floors (excluding stairs and spring tiles). The odds of being hit on each floor are all equal.
The type of tile is one of these five.
You can move one square at a time from the tile you are currently riding to an adjacent tile in either the up, down, left, or right direction. However, you cannot move to Naname.
Given a map of the labyrinth, find the expected number of moves required to escape the labyrinth if you take the best strategy. It is not included in the number of movements that is blown by the spring.
Input
W H
c11 c12 ... c1w
c21 c22 ... c2w
:::
ch1 ch2 ... ccw
On the first line of input, the integer W (3 ≤ W ≤ 500) and the integer H (3 ≤ H ≤ 500) are written in this order, separated by blanks. The integer W represents the width of the labyrinth, and the integer H represents the height of the labyrinth.
The following H line contains W letters (not blank delimiters) that represent the map of the labyrinth. The format of this part is as in the example given above. Note that "s" and "g" appear exactly once in the data. In addition, one square around the labyrinth is always surrounded by a wall.
In addition, in the given labyrinth, no matter how you move and how it is blown by the spring, you will fall into a state where you cannot escape even if you can arbitrarily set the floor to be blown by the spring. You can assume that there is no such thing.
Output
Output the expected number of moves to escape when you take the best strategy. The output may contain errors, but the relative error to the true value must be less than 10-9.
Examples
Input
8 6
########
#..##g.#
#*#.*#.#
#......#
#*s#*.*#
########
Output
5.857142857143
Input
8 6
..##g.#
*#.*#.#
......#
*s#*.*#
Output
5.857142857143
Input
21 11
*#*.*.*.*.*.*.*.*#*#
*#...............#*#
*#.#.#.#.#.#.#.#.#*#
.#.#.#.#.#.#.#.#.##
...................#
.#.#.#.#.#.#.#.#.##
s#.#.#.#.#.#.#.#.#g#
...................#
...................#
Output
20.000000000000
Input
9 8
...#*.*#
.*.#...#
...#*.*#
.s....g#
.*#.*..#
Output
5.000000000000
Submitted Solution:
```
from collections import deque
w, h = map(int, input().split())
mp = [input() for _ in range(h)]
springs = []
tile_cnt = 0
for y in range(h):
for x in range(w):
if mp[y][x] == "*":
springs.append((x, y))
if mp[y][x] == "g":
gx, gy = x, y
if mp[y][x] == "s":
sx, sy = x, y
tile_cnt += 1
if mp[y][x] == ".":
tile_cnt += 1
vec = ((1, 0), (0, -1), (-1, 0), (0, 1))
INF = 10 ** 10
g_dist = [[INF] * w for _ in range(h)]
que = deque()
que.append((0, gx, gy))
g_dist[gy][gx] = 0
while que:
score, x, y = que.popleft()
for dx, dy in vec:
nx, ny = x + dx, y + dy
if mp[ny][nx] in (".", "s"):
if g_dist[ny][nx] == INF:
g_dist[ny][nx] = score + 1
que.append((score + 1, nx, ny))
s_dist = [[INF] * w for _ in range(h)]
que = deque()
for x, y in springs:
s_dist[y][x] = 0
que.append((0, x, y))
while que:
score, x, y = que.popleft()
for dx, dy in vec:
nx, ny = x + dx, y + dy
if mp[ny][nx] in (".", "s"):
if s_dist[ny][nx] == INF:
s_dist[ny][nx] = score + 1
que.append((score + 1, nx, ny))
sorted_tiles = sorted([(g_dist[y][x] - s_dist[y][x], x, y) for y in range(h) for x in range(w) if mp[y][x] in (".", "s")])
acc_g = 0
acc_s = 0
acc_t = 0
acc_g_dic = {}
acc_s_dic = {}
acc_t_dic = {}
keys = set()
for key, x, y in sorted_tiles:
acc_g += g_dist[y][x]
acc_s += s_dist[y][x]
acc_t += 1
acc_g_dic[key] = acc_g
acc_s_dic[key] = acc_s
acc_t_dic[key] = acc_t
keys.add(key)
keys = sorted(list(keys))
length = len(keys)
for i in range(length - 1):
key = keys[i]
next_key = keys[i + 1]
E = (acc_g_dic[key] + acc_s - acc_s_dic[key]) / acc_t_dic[key]
if key <= E < next_key:
break
print(min(g_dist[sy][sx], s_dist[y][x] + E))
``` | instruction | 0 | 69,784 | 3 | 139,568 |
No | output | 1 | 69,784 | 3 | 139,569 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One morning when you woke up, it was in a springy labyrinth.
I don't know why I'm in such a strange place. You have the option of waiting for help here, but you know from experience that if you stay in a labyrinth like this for a long time, a gust of wind will surely blow you away. It was. However, the time until the gust blows cannot be judged. So you thought it was best to act to minimize the expected number of moves required to escape the labyrinth.
When I picked up an unidentified scroll that had fallen under my feet and read it as a trial, I happened to be able to perceive the entire map of the labyrinth. Furthermore, by drinking the grass that I happened to have, I was able to know the positions of all the traps. Apparently, there are no traps other than dangerous monsters and springs in this labyrinth.
This labyrinth is shaped like a rectangle with several types of tiles, for example:
.. ## g. #
* #. * #. #
...... #
* s # *. * #
".":floor. You can walk around freely on this.
"#":wall. You can't get inside the wall.
"S": Your first position. Below this tile is the floor.
"G": Stairs. If you ride on this tile, you have escaped from the labyrinth.
"*":Spring. If you ride on this tile, it will be randomly blown onto one of the floors (excluding stairs and spring tiles). The odds of being hit on each floor are all equal.
The type of tile is one of these five.
You can move one square at a time from the tile you are currently riding to an adjacent tile in either the up, down, left, or right direction. However, you cannot move to Naname.
Given a map of the labyrinth, find the expected number of moves required to escape the labyrinth if you take the best strategy. It is not included in the number of movements that is blown by the spring.
Input
W H
c11 c12 ... c1w
c21 c22 ... c2w
:::
ch1 ch2 ... ccw
On the first line of input, the integer W (3 ≤ W ≤ 500) and the integer H (3 ≤ H ≤ 500) are written in this order, separated by blanks. The integer W represents the width of the labyrinth, and the integer H represents the height of the labyrinth.
The following H line contains W letters (not blank delimiters) that represent the map of the labyrinth. The format of this part is as in the example given above. Note that "s" and "g" appear exactly once in the data. In addition, one square around the labyrinth is always surrounded by a wall.
In addition, in the given labyrinth, no matter how you move and how it is blown by the spring, you will fall into a state where you cannot escape even if you can arbitrarily set the floor to be blown by the spring. You can assume that there is no such thing.
Output
Output the expected number of moves to escape when you take the best strategy. The output may contain errors, but the relative error to the true value must be less than 10-9.
Examples
Input
8 6
########
#..##g.#
#*#.*#.#
#......#
#*s#*.*#
########
Output
5.857142857143
Input
8 6
..##g.#
*#.*#.#
......#
*s#*.*#
Output
5.857142857143
Input
21 11
*#*.*.*.*.*.*.*.*#*#
*#...............#*#
*#.#.#.#.#.#.#.#.#*#
.#.#.#.#.#.#.#.#.##
...................#
.#.#.#.#.#.#.#.#.##
s#.#.#.#.#.#.#.#.#g#
...................#
...................#
Output
20.000000000000
Input
9 8
...#*.*#
.*.#...#
...#*.*#
.s....g#
.*#.*..#
Output
5.000000000000
Submitted Solution:
```
from collections import deque
w, h = map(int, input().split())
mp = [input() for _ in range(h)]
springs = []
tile_cnt = 0
for y in range(h):
for x in range(w):
if mp[y][x] == "*":
springs.append((x, y))
if mp[y][x] == "g":
gx, gy = x, y
if mp[y][x] == "s":
sx, sy = x, y
tile_cnt += 1
if mp[y][x] == ".":
tile_cnt += 1
vec = ((1, 0), (0, -1), (-1, 0), (0, 1))
INF = 10 ** 10
g_dist = [[INF] * w for _ in range(h)]
que = deque()
que.append((0, gx, gy))
g_dist[gy][gx] = 0
while que:
score, x, y = que.popleft()
for dx, dy in vec:
nx, ny = x + dx, y + dy
if mp[ny][nx] in (".", "s"):
if g_dist[ny][nx] == INF:
g_dist[ny][nx] = score + 1
que.append((score + 1, nx, ny))
s_dist = [[INF] * w for _ in range(h)]
que = deque()
for x, y in springs:
s_dist[y][x] = 0
que.append((0, x, y))
while que:
score, x, y = que.popleft()
for dx, dy in vec:
nx, ny = x + dx, y + dy
if mp[ny][nx] in (".", "s"):
if s_dist[ny][nx] == INF:
s_dist[ny][nx] = score + 1
que.append((score + 1, nx, ny))
sorted_tiles = sorted([(g_dist[y][x] - s_dist[y][x] if g_dist[y][x] != INF else INF, x, y) for y in range(h) for x in range(w) if mp[y][x] in (".", "s")])
acc_g = 0
acc_s = 0
acc_t = 0
acc_g_dic = {}
acc_s_dic = {}
acc_t_dic = {}
keys = set()
for key, x, y in sorted_tiles:
acc_g += g_dist[y][x]
acc_s += s_dist[y][x]
acc_t += 1
acc_g_dic[key] = acc_g
acc_s_dic[key] = acc_s
acc_t_dic[key] = acc_t
keys.add(key)
keys = sorted(list(keys))
length = len(keys)
for i in range(length - 1):
key = keys[i]
next_key = keys[i + 1]
E = (acc_g_dic[key] + acc_s - acc_s_dic[key]) / acc_t_dic[key]
if key <= E < next_key:
break
print(min(g_dist[sy][sx], s_dist[sy][sx] + E))
``` | instruction | 0 | 69,785 | 3 | 139,570 |
No | output | 1 | 69,785 | 3 | 139,571 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya is the most responsible worker in the Research Institute. So he was asked to make a very important experiment: to melt the chocolate bar with a new laser device. The device consists of a rectangular field of n × m cells and a robotic arm. Each cell of the field is a 1 × 1 square. The robotic arm has two lasers pointed at the field perpendicularly to its surface. At any one time lasers are pointed at the centres of some two cells. Since the lasers are on the robotic hand, their movements are synchronized — if you move one of the lasers by a vector, another one moves by the same vector.
The following facts about the experiment are known:
* initially the whole field is covered with a chocolate bar of the size n × m, both lasers are located above the field and are active;
* the chocolate melts within one cell of the field at which the laser is pointed;
* all moves of the robotic arm should be parallel to the sides of the field, after each move the lasers should be pointed at the centres of some two cells;
* at any one time both lasers should be pointed at the field. Petya doesn't want to become a second Gordon Freeman.
You are given n, m and the cells (x1, y1) and (x2, y2), where the lasers are initially pointed at (xi is a column number, yi is a row number). Rows are numbered from 1 to m from top to bottom and columns are numbered from 1 to n from left to right. You are to find the amount of cells of the field on which the chocolate can't be melted in the given conditions.
Input
The first line contains one integer number t (1 ≤ t ≤ 10000) — the number of test sets. Each of the following t lines describes one test set. Each line contains integer numbers n, m, x1, y1, x2, y2, separated by a space (2 ≤ n, m ≤ 109, 1 ≤ x1, x2 ≤ n, 1 ≤ y1, y2 ≤ m). Cells (x1, y1) and (x2, y2) are distinct.
Output
Each of the t lines of the output should contain the answer to the corresponding input test set.
Examples
Input
2
4 4 1 1 3 3
4 3 1 1 2 2
Output
8
2 | instruction | 0 | 70,096 | 3 | 140,192 |
Tags: math
Correct Solution:
```
from sys import stdin
for case in range(int(stdin.readline())):
n,m,x1,y1,x2,y2 = [int(x) for x in stdin.readline().split()]
total = n*m
xDiff = abs(x1-x2)
yDiff = abs(y1-y2)
rectX = n-xDiff
rectY = m-yDiff
midSquare = (rectX*2-n)*(rectY*2-m)
total -= 2*(n-xDiff)*(m-yDiff)
if rectX*2 > n:
total += max(midSquare,0)
print(total)
``` | output | 1 | 70,096 | 3 | 140,193 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya is the most responsible worker in the Research Institute. So he was asked to make a very important experiment: to melt the chocolate bar with a new laser device. The device consists of a rectangular field of n × m cells and a robotic arm. Each cell of the field is a 1 × 1 square. The robotic arm has two lasers pointed at the field perpendicularly to its surface. At any one time lasers are pointed at the centres of some two cells. Since the lasers are on the robotic hand, their movements are synchronized — if you move one of the lasers by a vector, another one moves by the same vector.
The following facts about the experiment are known:
* initially the whole field is covered with a chocolate bar of the size n × m, both lasers are located above the field and are active;
* the chocolate melts within one cell of the field at which the laser is pointed;
* all moves of the robotic arm should be parallel to the sides of the field, after each move the lasers should be pointed at the centres of some two cells;
* at any one time both lasers should be pointed at the field. Petya doesn't want to become a second Gordon Freeman.
You are given n, m and the cells (x1, y1) and (x2, y2), where the lasers are initially pointed at (xi is a column number, yi is a row number). Rows are numbered from 1 to m from top to bottom and columns are numbered from 1 to n from left to right. You are to find the amount of cells of the field on which the chocolate can't be melted in the given conditions.
Input
The first line contains one integer number t (1 ≤ t ≤ 10000) — the number of test sets. Each of the following t lines describes one test set. Each line contains integer numbers n, m, x1, y1, x2, y2, separated by a space (2 ≤ n, m ≤ 109, 1 ≤ x1, x2 ≤ n, 1 ≤ y1, y2 ≤ m). Cells (x1, y1) and (x2, y2) are distinct.
Output
Each of the t lines of the output should contain the answer to the corresponding input test set.
Examples
Input
2
4 4 1 1 3 3
4 3 1 1 2 2
Output
8
2 | instruction | 0 | 70,097 | 3 | 140,194 |
Tags: math
Correct Solution:
```
for i in range(int(input())):
n, m, x1, y1, x2, y2 = map(int, input().split())
w,h=abs(x2-x1),abs(y2-y1)
if w*2>n or h*2>m:
print(n*m-2*(n-w)*(m-h))
else:
print(2*w*h)
``` | output | 1 | 70,097 | 3 | 140,195 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya is the most responsible worker in the Research Institute. So he was asked to make a very important experiment: to melt the chocolate bar with a new laser device. The device consists of a rectangular field of n × m cells and a robotic arm. Each cell of the field is a 1 × 1 square. The robotic arm has two lasers pointed at the field perpendicularly to its surface. At any one time lasers are pointed at the centres of some two cells. Since the lasers are on the robotic hand, their movements are synchronized — if you move one of the lasers by a vector, another one moves by the same vector.
The following facts about the experiment are known:
* initially the whole field is covered with a chocolate bar of the size n × m, both lasers are located above the field and are active;
* the chocolate melts within one cell of the field at which the laser is pointed;
* all moves of the robotic arm should be parallel to the sides of the field, after each move the lasers should be pointed at the centres of some two cells;
* at any one time both lasers should be pointed at the field. Petya doesn't want to become a second Gordon Freeman.
You are given n, m and the cells (x1, y1) and (x2, y2), where the lasers are initially pointed at (xi is a column number, yi is a row number). Rows are numbered from 1 to m from top to bottom and columns are numbered from 1 to n from left to right. You are to find the amount of cells of the field on which the chocolate can't be melted in the given conditions.
Input
The first line contains one integer number t (1 ≤ t ≤ 10000) — the number of test sets. Each of the following t lines describes one test set. Each line contains integer numbers n, m, x1, y1, x2, y2, separated by a space (2 ≤ n, m ≤ 109, 1 ≤ x1, x2 ≤ n, 1 ≤ y1, y2 ≤ m). Cells (x1, y1) and (x2, y2) are distinct.
Output
Each of the t lines of the output should contain the answer to the corresponding input test set.
Examples
Input
2
4 4 1 1 3 3
4 3 1 1 2 2
Output
8
2 | instruction | 0 | 70,098 | 3 | 140,196 |
Tags: math
Correct Solution:
```
I = lambda : map(int,input().split())
for _ in range (int(input())) :
n , m , x1 , y1 , x2 , y2 = I()
if y1 > y2 :
x1 , y1 , x2 , y2 = x1 , y2 , x2 , y1
if x1 <= x2 :
xmin = x1
xmax = x2
xmin = x1 + max(0,n-x2)
xmax = x2 - (x1-1)
ymin = y1 + m-y2
ymax = y2 - (y1-1)
#print(xmin , xmax)
rect = n*m
a1 = xmin * ymin
a2 = (n-xmax+1)*(m-ymax+1)
com = max(xmin - xmax + 1 , 0) * max(ymin - ymax + 1 , 0)
#print(rect , a1 ,a2 ,com)
print(rect - a1 - a2 + com)
else :
x1 = n+1 - x1
x2 = n+1 - x2
xmin = x1
xmax = x2
xmin = x1 + max(0,n-x2)
xmax = x2 - (x1-1)
ymin = y1 + m-y2
ymax = y2 - (y1-1)
#print(xmin , xmax)
rect = n*m
a1 = xmin * ymin
a2 = (n-xmax+1)*(m-ymax+1)
com = max(xmin - xmax + 1 , 0) * max(ymin - ymax + 1 , 0)
#print(rect , a1 ,a2 ,com)
print(rect - a1 - a2 + com)
``` | output | 1 | 70,098 | 3 | 140,197 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya is the most responsible worker in the Research Institute. So he was asked to make a very important experiment: to melt the chocolate bar with a new laser device. The device consists of a rectangular field of n × m cells and a robotic arm. Each cell of the field is a 1 × 1 square. The robotic arm has two lasers pointed at the field perpendicularly to its surface. At any one time lasers are pointed at the centres of some two cells. Since the lasers are on the robotic hand, their movements are synchronized — if you move one of the lasers by a vector, another one moves by the same vector.
The following facts about the experiment are known:
* initially the whole field is covered with a chocolate bar of the size n × m, both lasers are located above the field and are active;
* the chocolate melts within one cell of the field at which the laser is pointed;
* all moves of the robotic arm should be parallel to the sides of the field, after each move the lasers should be pointed at the centres of some two cells;
* at any one time both lasers should be pointed at the field. Petya doesn't want to become a second Gordon Freeman.
You are given n, m and the cells (x1, y1) and (x2, y2), where the lasers are initially pointed at (xi is a column number, yi is a row number). Rows are numbered from 1 to m from top to bottom and columns are numbered from 1 to n from left to right. You are to find the amount of cells of the field on which the chocolate can't be melted in the given conditions.
Input
The first line contains one integer number t (1 ≤ t ≤ 10000) — the number of test sets. Each of the following t lines describes one test set. Each line contains integer numbers n, m, x1, y1, x2, y2, separated by a space (2 ≤ n, m ≤ 109, 1 ≤ x1, x2 ≤ n, 1 ≤ y1, y2 ≤ m). Cells (x1, y1) and (x2, y2) are distinct.
Output
Each of the t lines of the output should contain the answer to the corresponding input test set.
Examples
Input
2
4 4 1 1 3 3
4 3 1 1 2 2
Output
8
2 | instruction | 0 | 70,099 | 3 | 140,198 |
Tags: math
Correct Solution:
```
for z in range(int(input())):
n,m,a,b,c,d=[int(i) for i in input().split()]
l=min(a,c)
o=min(b,d)
r=min(n-a,n-c)
u=min(m-b,m-d)
if a<=c:
h=a+r-c+l
else:
h=c+r-a+l
h=max(h,0)
if b<=d:
v=b+u-d+o
else:
v=d+u-b+o
v=max(v,0)
print(n*m-2*(l+r)*(o+u)+h*v)
``` | output | 1 | 70,099 | 3 | 140,199 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya is the most responsible worker in the Research Institute. So he was asked to make a very important experiment: to melt the chocolate bar with a new laser device. The device consists of a rectangular field of n × m cells and a robotic arm. Each cell of the field is a 1 × 1 square. The robotic arm has two lasers pointed at the field perpendicularly to its surface. At any one time lasers are pointed at the centres of some two cells. Since the lasers are on the robotic hand, their movements are synchronized — if you move one of the lasers by a vector, another one moves by the same vector.
The following facts about the experiment are known:
* initially the whole field is covered with a chocolate bar of the size n × m, both lasers are located above the field and are active;
* the chocolate melts within one cell of the field at which the laser is pointed;
* all moves of the robotic arm should be parallel to the sides of the field, after each move the lasers should be pointed at the centres of some two cells;
* at any one time both lasers should be pointed at the field. Petya doesn't want to become a second Gordon Freeman.
You are given n, m and the cells (x1, y1) and (x2, y2), where the lasers are initially pointed at (xi is a column number, yi is a row number). Rows are numbered from 1 to m from top to bottom and columns are numbered from 1 to n from left to right. You are to find the amount of cells of the field on which the chocolate can't be melted in the given conditions.
Input
The first line contains one integer number t (1 ≤ t ≤ 10000) — the number of test sets. Each of the following t lines describes one test set. Each line contains integer numbers n, m, x1, y1, x2, y2, separated by a space (2 ≤ n, m ≤ 109, 1 ≤ x1, x2 ≤ n, 1 ≤ y1, y2 ≤ m). Cells (x1, y1) and (x2, y2) are distinct.
Output
Each of the t lines of the output should contain the answer to the corresponding input test set.
Examples
Input
2
4 4 1 1 3 3
4 3 1 1 2 2
Output
8
2 | instruction | 0 | 70,100 | 3 | 140,200 |
Tags: math
Correct Solution:
```
t = int( input() )
for i in range(t):
n, m, x1, y1, x2, y2 = map( int, input().split() )
#print(n,m,x1,y1,x2,y2)
l = min( x1-1, x2-1 )
r = min( n-x1, n-x2 )
d = min( y1-1, y2-1 )
u = min( m-y1, m-y2 )
#print(l,r,d,u)
srange = [ ( x1-l, x1+r, y1-d, y1+u ), ( x2-l, x2+r, y2-d, y2+u ) ]
sortRan = sorted( srange, key = lambda e: e[0] )
s = (l+r+1) * (d+u+1) * 2
#print(sortRan)
#print(s)
if sortRan[1][0] <= sortRan[0][1]:
if sortRan[0][2] <= sortRan[1][3] <= sortRan[0][3]:
s -= (sortRan[0][1] - sortRan[1][0] + 1) * ( sortRan[1][3] - sortRan[0][2] + 1)
elif sortRan[0][2] <= sortRan[1][2] <= sortRan[0][3]:
s -= (sortRan[0][1] - sortRan[1][0] + 1) * ( sortRan[0][3] - sortRan[1][2] + 1)
print( n*m - s )
``` | output | 1 | 70,100 | 3 | 140,201 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya is the most responsible worker in the Research Institute. So he was asked to make a very important experiment: to melt the chocolate bar with a new laser device. The device consists of a rectangular field of n × m cells and a robotic arm. Each cell of the field is a 1 × 1 square. The robotic arm has two lasers pointed at the field perpendicularly to its surface. At any one time lasers are pointed at the centres of some two cells. Since the lasers are on the robotic hand, their movements are synchronized — if you move one of the lasers by a vector, another one moves by the same vector.
The following facts about the experiment are known:
* initially the whole field is covered with a chocolate bar of the size n × m, both lasers are located above the field and are active;
* the chocolate melts within one cell of the field at which the laser is pointed;
* all moves of the robotic arm should be parallel to the sides of the field, after each move the lasers should be pointed at the centres of some two cells;
* at any one time both lasers should be pointed at the field. Petya doesn't want to become a second Gordon Freeman.
You are given n, m and the cells (x1, y1) and (x2, y2), where the lasers are initially pointed at (xi is a column number, yi is a row number). Rows are numbered from 1 to m from top to bottom and columns are numbered from 1 to n from left to right. You are to find the amount of cells of the field on which the chocolate can't be melted in the given conditions.
Input
The first line contains one integer number t (1 ≤ t ≤ 10000) — the number of test sets. Each of the following t lines describes one test set. Each line contains integer numbers n, m, x1, y1, x2, y2, separated by a space (2 ≤ n, m ≤ 109, 1 ≤ x1, x2 ≤ n, 1 ≤ y1, y2 ≤ m). Cells (x1, y1) and (x2, y2) are distinct.
Output
Each of the t lines of the output should contain the answer to the corresponding input test set.
Examples
Input
2
4 4 1 1 3 3
4 3 1 1 2 2
Output
8
2 | instruction | 0 | 70,101 | 3 | 140,202 |
Tags: math
Correct Solution:
```
t = int(input())
for q in range(t):
n,m,x1,y1,x2,y2 = map(int,input().split(' '))
print(n*m-2*((n-abs(x1-x2))*(m-abs(y1-y2)))+(min(0,(n-2*(n-abs(x1-x2))))*min(0,m-2*(m-abs(y1-y2)))))
``` | output | 1 | 70,101 | 3 | 140,203 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya is the most responsible worker in the Research Institute. So he was asked to make a very important experiment: to melt the chocolate bar with a new laser device. The device consists of a rectangular field of n × m cells and a robotic arm. Each cell of the field is a 1 × 1 square. The robotic arm has two lasers pointed at the field perpendicularly to its surface. At any one time lasers are pointed at the centres of some two cells. Since the lasers are on the robotic hand, their movements are synchronized — if you move one of the lasers by a vector, another one moves by the same vector.
The following facts about the experiment are known:
* initially the whole field is covered with a chocolate bar of the size n × m, both lasers are located above the field and are active;
* the chocolate melts within one cell of the field at which the laser is pointed;
* all moves of the robotic arm should be parallel to the sides of the field, after each move the lasers should be pointed at the centres of some two cells;
* at any one time both lasers should be pointed at the field. Petya doesn't want to become a second Gordon Freeman.
You are given n, m and the cells (x1, y1) and (x2, y2), where the lasers are initially pointed at (xi is a column number, yi is a row number). Rows are numbered from 1 to m from top to bottom and columns are numbered from 1 to n from left to right. You are to find the amount of cells of the field on which the chocolate can't be melted in the given conditions.
Input
The first line contains one integer number t (1 ≤ t ≤ 10000) — the number of test sets. Each of the following t lines describes one test set. Each line contains integer numbers n, m, x1, y1, x2, y2, separated by a space (2 ≤ n, m ≤ 109, 1 ≤ x1, x2 ≤ n, 1 ≤ y1, y2 ≤ m). Cells (x1, y1) and (x2, y2) are distinct.
Output
Each of the t lines of the output should contain the answer to the corresponding input test set.
Examples
Input
2
4 4 1 1 3 3
4 3 1 1 2 2
Output
8
2 | instruction | 0 | 70,102 | 3 | 140,204 |
Tags: math
Correct Solution:
```
class CodeforcesTask15BSolution:
def __init__(self):
self.result = ''
self.t = 0
self.tests = []
def read_input(self):
self.t = int(input())
for x in range(self.t):
self.tests.append([int(y) for y in input().split(" ")])
def process_task(self):
results = []
for test in self.tests:
vert = abs(test[3] - test[5])
hori = abs(test[2] - test[4])
if vert * 2 <= test[1]:
vert_unr = 0
else:
vert_unr = 2 * vert - test[1]
if hori * 2 <= test[0]:
hori_unr = 0
else:
hori_unr = 2 * hori - test[0]
unr = test[0] * vert_unr + test[1] * hori_unr - hori_unr * vert_unr
unr += 2 * (vert - vert_unr) * (hori - hori_unr)
results.append(unr)
self.result = "\n".join([str(x) for x in results])
def get_result(self):
return self.result
if __name__ == "__main__":
Solution = CodeforcesTask15BSolution()
Solution.read_input()
Solution.process_task()
print(Solution.get_result())
``` | output | 1 | 70,102 | 3 | 140,205 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya is the most responsible worker in the Research Institute. So he was asked to make a very important experiment: to melt the chocolate bar with a new laser device. The device consists of a rectangular field of n × m cells and a robotic arm. Each cell of the field is a 1 × 1 square. The robotic arm has two lasers pointed at the field perpendicularly to its surface. At any one time lasers are pointed at the centres of some two cells. Since the lasers are on the robotic hand, their movements are synchronized — if you move one of the lasers by a vector, another one moves by the same vector.
The following facts about the experiment are known:
* initially the whole field is covered with a chocolate bar of the size n × m, both lasers are located above the field and are active;
* the chocolate melts within one cell of the field at which the laser is pointed;
* all moves of the robotic arm should be parallel to the sides of the field, after each move the lasers should be pointed at the centres of some two cells;
* at any one time both lasers should be pointed at the field. Petya doesn't want to become a second Gordon Freeman.
You are given n, m and the cells (x1, y1) and (x2, y2), where the lasers are initially pointed at (xi is a column number, yi is a row number). Rows are numbered from 1 to m from top to bottom and columns are numbered from 1 to n from left to right. You are to find the amount of cells of the field on which the chocolate can't be melted in the given conditions.
Input
The first line contains one integer number t (1 ≤ t ≤ 10000) — the number of test sets. Each of the following t lines describes one test set. Each line contains integer numbers n, m, x1, y1, x2, y2, separated by a space (2 ≤ n, m ≤ 109, 1 ≤ x1, x2 ≤ n, 1 ≤ y1, y2 ≤ m). Cells (x1, y1) and (x2, y2) are distinct.
Output
Each of the t lines of the output should contain the answer to the corresponding input test set.
Examples
Input
2
4 4 1 1 3 3
4 3 1 1 2 2
Output
8
2 | instruction | 0 | 70,103 | 3 | 140,206 |
Tags: math
Correct Solution:
```
for _ in range(int(input())):
n, m, x1, y1, x2, y2 = map(int, input().split())
ans = abs(x1 - x2) * abs(y1 - y2) * 2
if 2 * abs(x1 - x2) > n:
if 2 * abs(y1 - y2) > m:
ans -= max(0, 2 * abs(x1 - x2) - n) * max(0, 2 * abs(y1 - y2) - m)
else:
ans += max(0, 2 * abs(x1 - x2) - n) * max(0, m - 2 * abs(y1 - y2))
else:
if 2 * abs(y1 - y2) > m:
ans += max(0, n - 2 * abs(x1 - x2)) * max(0, 2 * abs(y1 - y2) - m)
print(ans)
``` | output | 1 | 70,103 | 3 | 140,207 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya is the most responsible worker in the Research Institute. So he was asked to make a very important experiment: to melt the chocolate bar with a new laser device. The device consists of a rectangular field of n × m cells and a robotic arm. Each cell of the field is a 1 × 1 square. The robotic arm has two lasers pointed at the field perpendicularly to its surface. At any one time lasers are pointed at the centres of some two cells. Since the lasers are on the robotic hand, their movements are synchronized — if you move one of the lasers by a vector, another one moves by the same vector.
The following facts about the experiment are known:
* initially the whole field is covered with a chocolate bar of the size n × m, both lasers are located above the field and are active;
* the chocolate melts within one cell of the field at which the laser is pointed;
* all moves of the robotic arm should be parallel to the sides of the field, after each move the lasers should be pointed at the centres of some two cells;
* at any one time both lasers should be pointed at the field. Petya doesn't want to become a second Gordon Freeman.
You are given n, m and the cells (x1, y1) and (x2, y2), where the lasers are initially pointed at (xi is a column number, yi is a row number). Rows are numbered from 1 to m from top to bottom and columns are numbered from 1 to n from left to right. You are to find the amount of cells of the field on which the chocolate can't be melted in the given conditions.
Input
The first line contains one integer number t (1 ≤ t ≤ 10000) — the number of test sets. Each of the following t lines describes one test set. Each line contains integer numbers n, m, x1, y1, x2, y2, separated by a space (2 ≤ n, m ≤ 109, 1 ≤ x1, x2 ≤ n, 1 ≤ y1, y2 ≤ m). Cells (x1, y1) and (x2, y2) are distinct.
Output
Each of the t lines of the output should contain the answer to the corresponding input test set.
Examples
Input
2
4 4 1 1 3 3
4 3 1 1 2 2
Output
8
2
Submitted Solution:
```
t = int(input())
for _ in range(t):
n, m, x1, y1, x2, y2 = map(int, input().split())
x, y = abs(x1 - x2), abs(y1 - y2)
if n >= x * 2 and m >= y * 2: #overlap
print(x * y * 2)
else:
print(n * m - ((n - x) * (m - y) * 2))
``` | instruction | 0 | 70,104 | 3 | 140,208 |
Yes | output | 1 | 70,104 | 3 | 140,209 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya is the most responsible worker in the Research Institute. So he was asked to make a very important experiment: to melt the chocolate bar with a new laser device. The device consists of a rectangular field of n × m cells and a robotic arm. Each cell of the field is a 1 × 1 square. The robotic arm has two lasers pointed at the field perpendicularly to its surface. At any one time lasers are pointed at the centres of some two cells. Since the lasers are on the robotic hand, their movements are synchronized — if you move one of the lasers by a vector, another one moves by the same vector.
The following facts about the experiment are known:
* initially the whole field is covered with a chocolate bar of the size n × m, both lasers are located above the field and are active;
* the chocolate melts within one cell of the field at which the laser is pointed;
* all moves of the robotic arm should be parallel to the sides of the field, after each move the lasers should be pointed at the centres of some two cells;
* at any one time both lasers should be pointed at the field. Petya doesn't want to become a second Gordon Freeman.
You are given n, m and the cells (x1, y1) and (x2, y2), where the lasers are initially pointed at (xi is a column number, yi is a row number). Rows are numbered from 1 to m from top to bottom and columns are numbered from 1 to n from left to right. You are to find the amount of cells of the field on which the chocolate can't be melted in the given conditions.
Input
The first line contains one integer number t (1 ≤ t ≤ 10000) — the number of test sets. Each of the following t lines describes one test set. Each line contains integer numbers n, m, x1, y1, x2, y2, separated by a space (2 ≤ n, m ≤ 109, 1 ≤ x1, x2 ≤ n, 1 ≤ y1, y2 ≤ m). Cells (x1, y1) and (x2, y2) are distinct.
Output
Each of the t lines of the output should contain the answer to the corresponding input test set.
Examples
Input
2
4 4 1 1 3 3
4 3 1 1 2 2
Output
8
2
Submitted Solution:
```
import sys
def its (x1, y1, x2, y2, x3, y3, x4, y4):
x5 = max(x1,x3); y5=max(y1,y3)
x6 = min(x2,x4); y6=min(y2,y4)
if (x5<=x6 and y5<=y6):
return (x6+1-x5)*(y6+1-y5)
else: return 0
def main():
t = int(input())
for it in range(0,t):
n,m,x1,y1,x2,y2=[int(x) for x in sys.stdin.readline().split()]
"""
n=int(sys.stdin().read())
m=int(sys.stdin().read())
x1=int(sys.stdin().read())
y1=int(sys.stdin().read())
x2=int(sys.stdin().read())
y2=int(sys.stdin().read())
"""
dr=min(n-x1,n-x2)
dl=min(x1-1,x2-1)
du=min(y1-1,y2-1)
dd=min(m-y1,m-y2)
x1p, y1p = x1-dl, y1-du
x2p, y2p = x1+dr, y1+dd
x3p, y3p = x2-dl, y2-du
x4p, y4p = x2+dr, y2+dd
#print(x1p,y1p,x2p,y2p,x3p,y3p,x4p,y4p)
ans=(x2p+1-x1p)*(y2p+1-y1p)+(x4p+1-x3p)*(y4p+1-y3p)
ans-=its(x1p,y1p,x2p,y2p,x3p,y3p,x4p,y4p)
print(n*m-ans);
main()
``` | instruction | 0 | 70,105 | 3 | 140,210 |
Yes | output | 1 | 70,105 | 3 | 140,211 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya is the most responsible worker in the Research Institute. So he was asked to make a very important experiment: to melt the chocolate bar with a new laser device. The device consists of a rectangular field of n × m cells and a robotic arm. Each cell of the field is a 1 × 1 square. The robotic arm has two lasers pointed at the field perpendicularly to its surface. At any one time lasers are pointed at the centres of some two cells. Since the lasers are on the robotic hand, their movements are synchronized — if you move one of the lasers by a vector, another one moves by the same vector.
The following facts about the experiment are known:
* initially the whole field is covered with a chocolate bar of the size n × m, both lasers are located above the field and are active;
* the chocolate melts within one cell of the field at which the laser is pointed;
* all moves of the robotic arm should be parallel to the sides of the field, after each move the lasers should be pointed at the centres of some two cells;
* at any one time both lasers should be pointed at the field. Petya doesn't want to become a second Gordon Freeman.
You are given n, m and the cells (x1, y1) and (x2, y2), where the lasers are initially pointed at (xi is a column number, yi is a row number). Rows are numbered from 1 to m from top to bottom and columns are numbered from 1 to n from left to right. You are to find the amount of cells of the field on which the chocolate can't be melted in the given conditions.
Input
The first line contains one integer number t (1 ≤ t ≤ 10000) — the number of test sets. Each of the following t lines describes one test set. Each line contains integer numbers n, m, x1, y1, x2, y2, separated by a space (2 ≤ n, m ≤ 109, 1 ≤ x1, x2 ≤ n, 1 ≤ y1, y2 ≤ m). Cells (x1, y1) and (x2, y2) are distinct.
Output
Each of the t lines of the output should contain the answer to the corresponding input test set.
Examples
Input
2
4 4 1 1 3 3
4 3 1 1 2 2
Output
8
2
Submitted Solution:
```
__author__ = 'Darren'
def solve():
t = int(input())
while t:
run()
t -= 1
def run():
n, m, x1, y1, x2, y2 = map(int, input().split())
width, height = abs(x1 - x2), abs(y1 - y2)
count = width * height * 2
x, y = width * 2 - n, height * 2 - m
if not (x < 0 and y < 0):
count -= x * y
print(count)
if __name__ == '__main__':
solve()
# Made By Mostafa_Khaled
``` | instruction | 0 | 70,106 | 3 | 140,212 |
Yes | output | 1 | 70,106 | 3 | 140,213 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya is the most responsible worker in the Research Institute. So he was asked to make a very important experiment: to melt the chocolate bar with a new laser device. The device consists of a rectangular field of n × m cells and a robotic arm. Each cell of the field is a 1 × 1 square. The robotic arm has two lasers pointed at the field perpendicularly to its surface. At any one time lasers are pointed at the centres of some two cells. Since the lasers are on the robotic hand, their movements are synchronized — if you move one of the lasers by a vector, another one moves by the same vector.
The following facts about the experiment are known:
* initially the whole field is covered with a chocolate bar of the size n × m, both lasers are located above the field and are active;
* the chocolate melts within one cell of the field at which the laser is pointed;
* all moves of the robotic arm should be parallel to the sides of the field, after each move the lasers should be pointed at the centres of some two cells;
* at any one time both lasers should be pointed at the field. Petya doesn't want to become a second Gordon Freeman.
You are given n, m and the cells (x1, y1) and (x2, y2), where the lasers are initially pointed at (xi is a column number, yi is a row number). Rows are numbered from 1 to m from top to bottom and columns are numbered from 1 to n from left to right. You are to find the amount of cells of the field on which the chocolate can't be melted in the given conditions.
Input
The first line contains one integer number t (1 ≤ t ≤ 10000) — the number of test sets. Each of the following t lines describes one test set. Each line contains integer numbers n, m, x1, y1, x2, y2, separated by a space (2 ≤ n, m ≤ 109, 1 ≤ x1, x2 ≤ n, 1 ≤ y1, y2 ≤ m). Cells (x1, y1) and (x2, y2) are distinct.
Output
Each of the t lines of the output should contain the answer to the corresponding input test set.
Examples
Input
2
4 4 1 1 3 3
4 3 1 1 2 2
Output
8
2
Submitted Solution:
```
n = int(input())
for i in range(n):
n, m, x1, y1, x2, y2 = map(int, input().split())
#print(n, m, x1, y1, x2, y2)
if x1 <= x2 and y1 <= y2:
pass
elif x1 >= x2 and y1 >= y2:
x1, y1, x2, y2 = x2, y2, x1, y1
else:
x1, y1, x2, y2 = x2, y1, x1, y2
if x1 <= x2 and y1 <= y2:
pass
elif x1 >= x2 and y1 >= y2:
x1, y1, x2, y2 = x2, y2, x1, y1
#print(n, m, x1, y1, x2, y2)
print(n*m - ((n - (x2 - x1)) * (m - (y2 - y1)) * 2 - max(0, (n - (x2 - x1)) * 2 - n) * max(0, (m - (y2 - y1)) * 2 - m)))
#printf("%d\n", ($n * $m) - (($n - ($x2 - $x1)) * ($m - ($y2 - $y1)) * 2
#- max(0, ($n - ($x2 - $x1)) * 2 - $n) * max(0, ($m - ($y2 - $y1)) * 2 - $m)));
``` | instruction | 0 | 70,107 | 3 | 140,214 |
Yes | output | 1 | 70,107 | 3 | 140,215 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya is the most responsible worker in the Research Institute. So he was asked to make a very important experiment: to melt the chocolate bar with a new laser device. The device consists of a rectangular field of n × m cells and a robotic arm. Each cell of the field is a 1 × 1 square. The robotic arm has two lasers pointed at the field perpendicularly to its surface. At any one time lasers are pointed at the centres of some two cells. Since the lasers are on the robotic hand, their movements are synchronized — if you move one of the lasers by a vector, another one moves by the same vector.
The following facts about the experiment are known:
* initially the whole field is covered with a chocolate bar of the size n × m, both lasers are located above the field and are active;
* the chocolate melts within one cell of the field at which the laser is pointed;
* all moves of the robotic arm should be parallel to the sides of the field, after each move the lasers should be pointed at the centres of some two cells;
* at any one time both lasers should be pointed at the field. Petya doesn't want to become a second Gordon Freeman.
You are given n, m and the cells (x1, y1) and (x2, y2), where the lasers are initially pointed at (xi is a column number, yi is a row number). Rows are numbered from 1 to m from top to bottom and columns are numbered from 1 to n from left to right. You are to find the amount of cells of the field on which the chocolate can't be melted in the given conditions.
Input
The first line contains one integer number t (1 ≤ t ≤ 10000) — the number of test sets. Each of the following t lines describes one test set. Each line contains integer numbers n, m, x1, y1, x2, y2, separated by a space (2 ≤ n, m ≤ 109, 1 ≤ x1, x2 ≤ n, 1 ≤ y1, y2 ≤ m). Cells (x1, y1) and (x2, y2) are distinct.
Output
Each of the t lines of the output should contain the answer to the corresponding input test set.
Examples
Input
2
4 4 1 1 3 3
4 3 1 1 2 2
Output
8
2
Submitted Solution:
```
from sys import stdin
for case in range(int(stdin.readline())):
n,m,x1,y1,x2,y2 = [int(x) for x in stdin.readline().split()]
total = n*m
xDiff = abs(x1-x2)
yDiff = abs(y1-y2)
rectX = n-xDiff
rectY = m-yDiff
midSquare = (rectX*2-n)*(rectY*2-m)
total -= 2*(n-xDiff)*(m-yDiff)
total += max(midSquare,0)
print(total)
``` | instruction | 0 | 70,108 | 3 | 140,216 |
No | output | 1 | 70,108 | 3 | 140,217 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya is the most responsible worker in the Research Institute. So he was asked to make a very important experiment: to melt the chocolate bar with a new laser device. The device consists of a rectangular field of n × m cells and a robotic arm. Each cell of the field is a 1 × 1 square. The robotic arm has two lasers pointed at the field perpendicularly to its surface. At any one time lasers are pointed at the centres of some two cells. Since the lasers are on the robotic hand, their movements are synchronized — if you move one of the lasers by a vector, another one moves by the same vector.
The following facts about the experiment are known:
* initially the whole field is covered with a chocolate bar of the size n × m, both lasers are located above the field and are active;
* the chocolate melts within one cell of the field at which the laser is pointed;
* all moves of the robotic arm should be parallel to the sides of the field, after each move the lasers should be pointed at the centres of some two cells;
* at any one time both lasers should be pointed at the field. Petya doesn't want to become a second Gordon Freeman.
You are given n, m and the cells (x1, y1) and (x2, y2), where the lasers are initially pointed at (xi is a column number, yi is a row number). Rows are numbered from 1 to m from top to bottom and columns are numbered from 1 to n from left to right. You are to find the amount of cells of the field on which the chocolate can't be melted in the given conditions.
Input
The first line contains one integer number t (1 ≤ t ≤ 10000) — the number of test sets. Each of the following t lines describes one test set. Each line contains integer numbers n, m, x1, y1, x2, y2, separated by a space (2 ≤ n, m ≤ 109, 1 ≤ x1, x2 ≤ n, 1 ≤ y1, y2 ≤ m). Cells (x1, y1) and (x2, y2) are distinct.
Output
Each of the t lines of the output should contain the answer to the corresponding input test set.
Examples
Input
2
4 4 1 1 3 3
4 3 1 1 2 2
Output
8
2
Submitted Solution:
```
t = int(input())
for i in range(t):
n,m,x1,y1,x2,y2 = map(int,input().split(' '))
print(n*m-2*((n-abs(x1-x2))*(m-abs(y1*y2)))+max(0,(n-2*abs(x1-x2))*(m-2*abs(y1*y2))))
``` | instruction | 0 | 70,109 | 3 | 140,218 |
No | output | 1 | 70,109 | 3 | 140,219 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya is the most responsible worker in the Research Institute. So he was asked to make a very important experiment: to melt the chocolate bar with a new laser device. The device consists of a rectangular field of n × m cells and a robotic arm. Each cell of the field is a 1 × 1 square. The robotic arm has two lasers pointed at the field perpendicularly to its surface. At any one time lasers are pointed at the centres of some two cells. Since the lasers are on the robotic hand, their movements are synchronized — if you move one of the lasers by a vector, another one moves by the same vector.
The following facts about the experiment are known:
* initially the whole field is covered with a chocolate bar of the size n × m, both lasers are located above the field and are active;
* the chocolate melts within one cell of the field at which the laser is pointed;
* all moves of the robotic arm should be parallel to the sides of the field, after each move the lasers should be pointed at the centres of some two cells;
* at any one time both lasers should be pointed at the field. Petya doesn't want to become a second Gordon Freeman.
You are given n, m and the cells (x1, y1) and (x2, y2), where the lasers are initially pointed at (xi is a column number, yi is a row number). Rows are numbered from 1 to m from top to bottom and columns are numbered from 1 to n from left to right. You are to find the amount of cells of the field on which the chocolate can't be melted in the given conditions.
Input
The first line contains one integer number t (1 ≤ t ≤ 10000) — the number of test sets. Each of the following t lines describes one test set. Each line contains integer numbers n, m, x1, y1, x2, y2, separated by a space (2 ≤ n, m ≤ 109, 1 ≤ x1, x2 ≤ n, 1 ≤ y1, y2 ≤ m). Cells (x1, y1) and (x2, y2) are distinct.
Output
Each of the t lines of the output should contain the answer to the corresponding input test set.
Examples
Input
2
4 4 1 1 3 3
4 3 1 1 2 2
Output
8
2
Submitted Solution:
```
t = int( input() )
for i in range(t):
m, n, y1, x1, y2, x2 = map( int, input().split() )
x1, y1, x2, y2 = x1-1, y1-1, x2-1, y2-1
visit = [ [0] * m for i in range(n) ]
xl = min( x1, x2 )
xr = min( m-1-x1, m-1-x2 )
yd = min( y1, y2 )
yu = min( n-1-y1, n-1-y2 )
#print(n,m,x1,y1,x2,y2)
#print(xl,xr,yd,yu)
for x in range(n):
for y in range(m):
if ( ( (y1 - xl) <= y <= (y1 + xr) and (x1 - yd) <= x <= (x1 + yu) ) \
or ( (y2 - xl) <= y <= (y2 + xr) and (x2 - yd) <= x <= (x2 + yu) ) ):
#print(x,y)
visit[x][y] = 1
#print(visit)
s = 0
#print(visit)
for j in range(n):
s += sum(visit[j])
print( n*m - s )
``` | instruction | 0 | 70,110 | 3 | 140,220 |
No | output | 1 | 70,110 | 3 | 140,221 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya is the most responsible worker in the Research Institute. So he was asked to make a very important experiment: to melt the chocolate bar with a new laser device. The device consists of a rectangular field of n × m cells and a robotic arm. Each cell of the field is a 1 × 1 square. The robotic arm has two lasers pointed at the field perpendicularly to its surface. At any one time lasers are pointed at the centres of some two cells. Since the lasers are on the robotic hand, their movements are synchronized — if you move one of the lasers by a vector, another one moves by the same vector.
The following facts about the experiment are known:
* initially the whole field is covered with a chocolate bar of the size n × m, both lasers are located above the field and are active;
* the chocolate melts within one cell of the field at which the laser is pointed;
* all moves of the robotic arm should be parallel to the sides of the field, after each move the lasers should be pointed at the centres of some two cells;
* at any one time both lasers should be pointed at the field. Petya doesn't want to become a second Gordon Freeman.
You are given n, m and the cells (x1, y1) and (x2, y2), where the lasers are initially pointed at (xi is a column number, yi is a row number). Rows are numbered from 1 to m from top to bottom and columns are numbered from 1 to n from left to right. You are to find the amount of cells of the field on which the chocolate can't be melted in the given conditions.
Input
The first line contains one integer number t (1 ≤ t ≤ 10000) — the number of test sets. Each of the following t lines describes one test set. Each line contains integer numbers n, m, x1, y1, x2, y2, separated by a space (2 ≤ n, m ≤ 109, 1 ≤ x1, x2 ≤ n, 1 ≤ y1, y2 ≤ m). Cells (x1, y1) and (x2, y2) are distinct.
Output
Each of the t lines of the output should contain the answer to the corresponding input test set.
Examples
Input
2
4 4 1 1 3 3
4 3 1 1 2 2
Output
8
2
Submitted Solution:
```
t = int(input())
for q in range(t):
n,m,x1,y1,x2,y2 = map(int,input().split(' '))
print(n*m-2*((n-abs(x1-x2))*(m-abs(y1-y2)))+(min(0,(n-2*(n-abs(x1-x2)))*min(0,m-2*m-abs(y1-y2)))))
``` | instruction | 0 | 70,111 | 3 | 140,222 |
No | output | 1 | 70,111 | 3 | 140,223 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This problem consists of two subproblems: for solving subproblem D1 you will receive 3 points, and for solving subproblem D2 you will receive 16 points.
Manao is the chief architect involved in planning a new supercollider. He has to identify a plot of land where the largest possible supercollider can be built. The supercollider he is building requires four-way orthogonal collisions of particles traveling at the same speed, so it will consist of four accelerating chambers and be shaped like a plus sign (i.e., +). Each of the four accelerating chambers must be the same length and must be aligned with the Earth's magnetic field (parallel or orthogonal) to minimize interference.
The accelerating chambers need to be laid down across long flat stretches of land to keep costs under control. Thus, Manao has already commissioned a topographical study that has identified all possible maximal length tracts of land available for building accelerating chambers that are either parallel or orthogonal to the Earth's magnetic field. To build the largest possible supercollider, Manao must identify the largest symmetric plus shape from among these candidate tracts. That is, he must find the two tracts of land that form an axis-aligned plus shape with the largest distance from the center of the plus to the tip of the shortest of the four arms of the plus. Note that the collider need not use the entire length of the tracts identified (see the example in the notes).
Input
The first line of the input will contain two single-space-separated integers n, the number of north-south tracts and m, the number of west-east tracts.
Each of the n lines following the first describes a north-south tract. Each such tract is described by three single-space-separated integers xi, yi, li representing the vertical line segment from (xi, yi) to (xi, yi + li).
Similarly, after the n lines describing north-south tracts follow m similar lines describing the west-east tracts. Each such tract is described by three single-space-separated integers xi, yi, li representing the horizontal line segment from (xi, yi) to (xi + li, yi).
All xi and yi are between -100000000 and 100000000, inclusive. All li are between 1 and 100000000, inclusive. No pair of horizontal segments will touch or intersect, and no pair of vertical segments will touch or intersect.
The problem consists of two subproblems. The subproblems have different constraints on the input. You will get some score for the correct submission of the subproblem. The description of the subproblems follows.
* In subproblem D1 (3 points), n and m will be between 1 and 1000, inclusive.
* In subproblem D2 (16 points), n and m will be between 1 and 50000, inclusive.
Output
Print one line containing a single integer, the size of the largest supercollider that can be built on one north-south tract and one west-east tract. The size of the supercollider is defined to be the length of one of the four accelerating chambers. In other words, the size of the resulting supercollider is defined to be the distance from the intersection of the two line segments to the closest endpoint of either of the two segments. If no pair of north-south and west-east tracts intersects, it is not possible to build a supercollider and the program should report a maximum size of zero.
Examples
Input
1 2
4 0 9
1 1 8
1 2 7
Output
2
Note
Consider the example. There is one vertical line segment from (4, 0) to (4, 9) and two horizontal line segments: from (1, 1) to (9, 1) and from (1, 2) to (8, 2). The largest plus shape that can be found among these segments is formed from the only vertical segment and the second of horizontal segments, and is centered at (4, 2).
The program should output 2 because the closest end point of those segments to the center is (4, 0), which is distance 2 from the center point of (4, 2). The collider will be formed by the line segments from (2, 2) to (6, 2) and from (4, 0) to (4, 4).
Submitted Solution:
```
n, m = map(int, input().split())
CHUNK_SIZE = 128
def calc_u(xh, yh, lh, xv, yv, lv):
return min(
xh-xv,
xh+lh-xv,
yv-yh,
yv + lv - yh,
)
chunker = dict()
def add_h(inp):
x, y, l = inp
cx = x // CHUNK_SIZE
cy = y // CHUNK_SIZE
cl = l // CHUNK_SIZE
for i in range(-1, cl+1):
crd = (cx + i, cy)
v = chunker.get(crd)
if v is None:
v = []
chunker[crd] = v
v.append(inp)
def get_v(inp):
x, y, l = inp
cx = x // CHUNK_SIZE
cy = y // CHUNK_SIZE
cl = l // CHUNK_SIZE
for i in range(-1, cl+1):
crd = (cx, cy + i)
#print("Checking", *crd)
v = chunker.get(crd)
if v is not None:
#print("Found", len(v))
yield from v
for i in range(n):
inp = tuple(map(int, input().split()))
add_h(inp)
#print(chunker)
mxv = 0
for i in range(m):
inp = tuple(map(int, input().split()))
for j in get_v(inp):
#print(inp, j)
v = calc_u(*j, *inp)
if v > mxv:
mxv = v
print(mxv)
``` | instruction | 0 | 70,170 | 3 | 140,340 |
No | output | 1 | 70,170 | 3 | 140,341 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp takes part in a quadcopter competition. According to the rules a flying robot should:
* start the race from some point of a field,
* go around the flag,
* close cycle returning back to the starting point.
Polycarp knows the coordinates of the starting point (x1, y1) and the coordinates of the point where the flag is situated (x2, y2). Polycarp’s quadcopter can fly only parallel to the sides of the field each tick changing exactly one coordinate by 1. It means that in one tick the quadcopter can fly from the point (x, y) to any of four points: (x - 1, y), (x + 1, y), (x, y - 1) or (x, y + 1).
Thus the quadcopter path is a closed cycle starting and finishing in (x1, y1) and containing the point (x2, y2) strictly inside.
<image> The picture corresponds to the first example: the starting (and finishing) point is in (1, 5) and the flag is in (5, 2).
What is the minimal length of the quadcopter path?
Input
The first line contains two integer numbers x1 and y1 ( - 100 ≤ x1, y1 ≤ 100) — coordinates of the quadcopter starting (and finishing) point.
The second line contains two integer numbers x2 and y2 ( - 100 ≤ x2, y2 ≤ 100) — coordinates of the flag.
It is guaranteed that the quadcopter starting point and the flag do not coincide.
Output
Print the length of minimal path of the quadcopter to surround the flag and return back.
Examples
Input
1 5
5 2
Output
18
Input
0 1
0 0
Output
8
Submitted Solution:
```
x1, y1 = map(int, input().split())
x2, y2 = map(int, input().split())
if x1 == x2:
x1 += 1
elif y1 == y2:
y1 += 1
print((abs(x2 - x1) + 1 + abs(y2 - y1) + 1) * 2)
``` | instruction | 0 | 70,426 | 3 | 140,852 |
Yes | output | 1 | 70,426 | 3 | 140,853 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp takes part in a quadcopter competition. According to the rules a flying robot should:
* start the race from some point of a field,
* go around the flag,
* close cycle returning back to the starting point.
Polycarp knows the coordinates of the starting point (x1, y1) and the coordinates of the point where the flag is situated (x2, y2). Polycarp’s quadcopter can fly only parallel to the sides of the field each tick changing exactly one coordinate by 1. It means that in one tick the quadcopter can fly from the point (x, y) to any of four points: (x - 1, y), (x + 1, y), (x, y - 1) or (x, y + 1).
Thus the quadcopter path is a closed cycle starting and finishing in (x1, y1) and containing the point (x2, y2) strictly inside.
<image> The picture corresponds to the first example: the starting (and finishing) point is in (1, 5) and the flag is in (5, 2).
What is the minimal length of the quadcopter path?
Input
The first line contains two integer numbers x1 and y1 ( - 100 ≤ x1, y1 ≤ 100) — coordinates of the quadcopter starting (and finishing) point.
The second line contains two integer numbers x2 and y2 ( - 100 ≤ x2, y2 ≤ 100) — coordinates of the flag.
It is guaranteed that the quadcopter starting point and the flag do not coincide.
Output
Print the length of minimal path of the quadcopter to surround the flag and return back.
Examples
Input
1 5
5 2
Output
18
Input
0 1
0 0
Output
8
Submitted Solution:
```
x1, y1 = [int(i) for i in input().split()]
x2, y2 = [int(i) for i in input().split()]
minx = min(x1, x2 - 1)
miny = min(y1, y2 - 1)
maxx = max(x1, x2 + 1)
maxy = max(y1, y2 + 1)
print(2 * ((maxx - minx) + (maxy - miny)))
``` | instruction | 0 | 70,427 | 3 | 140,854 |
Yes | output | 1 | 70,427 | 3 | 140,855 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp takes part in a quadcopter competition. According to the rules a flying robot should:
* start the race from some point of a field,
* go around the flag,
* close cycle returning back to the starting point.
Polycarp knows the coordinates of the starting point (x1, y1) and the coordinates of the point where the flag is situated (x2, y2). Polycarp’s quadcopter can fly only parallel to the sides of the field each tick changing exactly one coordinate by 1. It means that in one tick the quadcopter can fly from the point (x, y) to any of four points: (x - 1, y), (x + 1, y), (x, y - 1) or (x, y + 1).
Thus the quadcopter path is a closed cycle starting and finishing in (x1, y1) and containing the point (x2, y2) strictly inside.
<image> The picture corresponds to the first example: the starting (and finishing) point is in (1, 5) and the flag is in (5, 2).
What is the minimal length of the quadcopter path?
Input
The first line contains two integer numbers x1 and y1 ( - 100 ≤ x1, y1 ≤ 100) — coordinates of the quadcopter starting (and finishing) point.
The second line contains two integer numbers x2 and y2 ( - 100 ≤ x2, y2 ≤ 100) — coordinates of the flag.
It is guaranteed that the quadcopter starting point and the flag do not coincide.
Output
Print the length of minimal path of the quadcopter to surround the flag and return back.
Examples
Input
1 5
5 2
Output
18
Input
0 1
0 0
Output
8
Submitted Solution:
```
x1, y1 = map(int, input().split())
x2, y2 = map(int, input().split())
x = 1 if not abs(x1-x2) else abs(x1-x2)
y = 1 if not abs(y1-y2) else abs(y1-y2)
print((x+1)*2 + (y+1)*2)
``` | instruction | 0 | 70,428 | 3 | 140,856 |
Yes | output | 1 | 70,428 | 3 | 140,857 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp takes part in a quadcopter competition. According to the rules a flying robot should:
* start the race from some point of a field,
* go around the flag,
* close cycle returning back to the starting point.
Polycarp knows the coordinates of the starting point (x1, y1) and the coordinates of the point where the flag is situated (x2, y2). Polycarp’s quadcopter can fly only parallel to the sides of the field each tick changing exactly one coordinate by 1. It means that in one tick the quadcopter can fly from the point (x, y) to any of four points: (x - 1, y), (x + 1, y), (x, y - 1) or (x, y + 1).
Thus the quadcopter path is a closed cycle starting and finishing in (x1, y1) and containing the point (x2, y2) strictly inside.
<image> The picture corresponds to the first example: the starting (and finishing) point is in (1, 5) and the flag is in (5, 2).
What is the minimal length of the quadcopter path?
Input
The first line contains two integer numbers x1 and y1 ( - 100 ≤ x1, y1 ≤ 100) — coordinates of the quadcopter starting (and finishing) point.
The second line contains two integer numbers x2 and y2 ( - 100 ≤ x2, y2 ≤ 100) — coordinates of the flag.
It is guaranteed that the quadcopter starting point and the flag do not coincide.
Output
Print the length of minimal path of the quadcopter to surround the flag and return back.
Examples
Input
1 5
5 2
Output
18
Input
0 1
0 0
Output
8
Submitted Solution:
```
from math import inf,sqrt,floor,ceil
from collections import Counter,defaultdict,deque
from heapq import heappush as hpush,heappop as hpop,heapify as h
from operator import itemgetter
from itertools import product
from bisect import bisect_left,bisect_right
x1,y1=map(int,input().split( ))
x2,y2=map(int,input().split( ))
l=abs(x1-x2)+1
b=abs(y1-y2)+1
if x1==x2:
l=abs(x1-x2)+2
if y1==y2:
b=abs(y1-y2)+2
print(2*(l+b))
``` | instruction | 0 | 70,429 | 3 | 140,858 |
Yes | output | 1 | 70,429 | 3 | 140,859 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp takes part in a quadcopter competition. According to the rules a flying robot should:
* start the race from some point of a field,
* go around the flag,
* close cycle returning back to the starting point.
Polycarp knows the coordinates of the starting point (x1, y1) and the coordinates of the point where the flag is situated (x2, y2). Polycarp’s quadcopter can fly only parallel to the sides of the field each tick changing exactly one coordinate by 1. It means that in one tick the quadcopter can fly from the point (x, y) to any of four points: (x - 1, y), (x + 1, y), (x, y - 1) or (x, y + 1).
Thus the quadcopter path is a closed cycle starting and finishing in (x1, y1) and containing the point (x2, y2) strictly inside.
<image> The picture corresponds to the first example: the starting (and finishing) point is in (1, 5) and the flag is in (5, 2).
What is the minimal length of the quadcopter path?
Input
The first line contains two integer numbers x1 and y1 ( - 100 ≤ x1, y1 ≤ 100) — coordinates of the quadcopter starting (and finishing) point.
The second line contains two integer numbers x2 and y2 ( - 100 ≤ x2, y2 ≤ 100) — coordinates of the flag.
It is guaranteed that the quadcopter starting point and the flag do not coincide.
Output
Print the length of minimal path of the quadcopter to surround the flag and return back.
Examples
Input
1 5
5 2
Output
18
Input
0 1
0 0
Output
8
Submitted Solution:
```
i,j = input("Enter two values: ").split()
i = int(i)
j = int(j)
o,p = input("Enter two values: ").split()
o = int(o)
p = int(p)
a = i - o
b = j - p
if a < 0:
a = 0-a
if a == 0:
a = 1
if b == 0:
b = 1
if b < 0:
b = 0-b
x =(a+b+2)*2
print(x)
``` | instruction | 0 | 70,430 | 3 | 140,860 |
No | output | 1 | 70,430 | 3 | 140,861 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp takes part in a quadcopter competition. According to the rules a flying robot should:
* start the race from some point of a field,
* go around the flag,
* close cycle returning back to the starting point.
Polycarp knows the coordinates of the starting point (x1, y1) and the coordinates of the point where the flag is situated (x2, y2). Polycarp’s quadcopter can fly only parallel to the sides of the field each tick changing exactly one coordinate by 1. It means that in one tick the quadcopter can fly from the point (x, y) to any of four points: (x - 1, y), (x + 1, y), (x, y - 1) or (x, y + 1).
Thus the quadcopter path is a closed cycle starting and finishing in (x1, y1) and containing the point (x2, y2) strictly inside.
<image> The picture corresponds to the first example: the starting (and finishing) point is in (1, 5) and the flag is in (5, 2).
What is the minimal length of the quadcopter path?
Input
The first line contains two integer numbers x1 and y1 ( - 100 ≤ x1, y1 ≤ 100) — coordinates of the quadcopter starting (and finishing) point.
The second line contains two integer numbers x2 and y2 ( - 100 ≤ x2, y2 ≤ 100) — coordinates of the flag.
It is guaranteed that the quadcopter starting point and the flag do not coincide.
Output
Print the length of minimal path of the quadcopter to surround the flag and return back.
Examples
Input
1 5
5 2
Output
18
Input
0 1
0 0
Output
8
Submitted Solution:
```
x1,y1=map(int,input().split())
x2,y2=map(int,input().split())
x,y=x2,y2
if abs(x1-x2)>1:
if x1>x2:
x=x2+1
else:
x=x2-1
if abs(y1-y2)>1:
if y1>y2:
y=y2+1
else:
y=y2-1
if x==x2 or y==y2:
print(8)
else:
print(8+2*(abs(x1-x)+abs(y1-y)))
``` | instruction | 0 | 70,431 | 3 | 140,862 |
No | output | 1 | 70,431 | 3 | 140,863 |
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