message stringlengths 2 20.2k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 757 108k | cluster float64 4 4 | __index_level_0__ int64 1.51k 217k |
|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
At Aizu Riverside Hospital, inpatients walk twice a day for rehabilitation and health promotion. As the number of people trying to recover their physical strength by walking is increasing day by day in order to leave the hospital energetically, the director plans to give a present to the person who walked the longest distance in a day! I launched it.
Number of patients n (1 ≤ n ≤ 10000), each patient's number pi (1 ≤ pi ≤ 10000), first walk distance d1i, second walk distance d2i (0 ≤ d1i, d2i ≤ 5000) Create a program that outputs the number of the patient with the longest total walking distance and the distance. However, it is assumed that no patient walks the same distance in a day.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
n
p1 d11 d21
p2 d12 d22
::
pn d1n d2n
All inputs are given as integers. The number of datasets does not exceed 50.
Output
For each input dataset, it prints the number of the patient who walked the longest total distance and the distance walked on one line.
Example
Input
5
263 2345 2504
1 3210 1985
5000 1501 4132
10000 503 3107
51 1758 2690
3
345 5000 2396
7 3910 1590
6789 2525 3616
0
Output
5000 5633
345 7396 | instruction | 0 | 30,868 | 4 | 61,736 |
"Correct Solution:
```
# AOJ 0217 Walking in the Hospital
# Python3 2018.6.23 bal4u
while 1:
n = int(input())
if n == 0: break
dmax = 0
for i in range(n):
p, d1, d2 = map(int, input().split())
if d1+d2 > dmax: id, dmax = p, d1+d2
print(id, dmax)
``` | output | 1 | 30,868 | 4 | 61,737 |
Provide a correct Python 3 solution for this coding contest problem.
At Aizu Riverside Hospital, inpatients walk twice a day for rehabilitation and health promotion. As the number of people trying to recover their physical strength by walking is increasing day by day in order to leave the hospital energetically, the director plans to give a present to the person who walked the longest distance in a day! I launched it.
Number of patients n (1 ≤ n ≤ 10000), each patient's number pi (1 ≤ pi ≤ 10000), first walk distance d1i, second walk distance d2i (0 ≤ d1i, d2i ≤ 5000) Create a program that outputs the number of the patient with the longest total walking distance and the distance. However, it is assumed that no patient walks the same distance in a day.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
n
p1 d11 d21
p2 d12 d22
::
pn d1n d2n
All inputs are given as integers. The number of datasets does not exceed 50.
Output
For each input dataset, it prints the number of the patient who walked the longest total distance and the distance walked on one line.
Example
Input
5
263 2345 2504
1 3210 1985
5000 1501 4132
10000 503 3107
51 1758 2690
3
345 5000 2396
7 3910 1590
6789 2525 3616
0
Output
5000 5633
345 7396 | instruction | 0 | 30,869 | 4 | 61,738 |
"Correct Solution:
```
while True:
n = int(input())
if n == 0:
break
lst = []
for _ in range(n):
p, d1, d2 = map(int, input().split())
lst.append((d1 + d2, p))
lst.sort()
print(lst[-1][1], lst[-1][0])
``` | output | 1 | 30,869 | 4 | 61,739 |
Provide a correct Python 3 solution for this coding contest problem.
At Aizu Riverside Hospital, inpatients walk twice a day for rehabilitation and health promotion. As the number of people trying to recover their physical strength by walking is increasing day by day in order to leave the hospital energetically, the director plans to give a present to the person who walked the longest distance in a day! I launched it.
Number of patients n (1 ≤ n ≤ 10000), each patient's number pi (1 ≤ pi ≤ 10000), first walk distance d1i, second walk distance d2i (0 ≤ d1i, d2i ≤ 5000) Create a program that outputs the number of the patient with the longest total walking distance and the distance. However, it is assumed that no patient walks the same distance in a day.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
n
p1 d11 d21
p2 d12 d22
::
pn d1n d2n
All inputs are given as integers. The number of datasets does not exceed 50.
Output
For each input dataset, it prints the number of the patient who walked the longest total distance and the distance walked on one line.
Example
Input
5
263 2345 2504
1 3210 1985
5000 1501 4132
10000 503 3107
51 1758 2690
3
345 5000 2396
7 3910 1590
6789 2525 3616
0
Output
5000 5633
345 7396 | instruction | 0 | 30,870 | 4 | 61,740 |
"Correct Solution:
```
while True:
n = int(input())
if n == 0:
break
large = 0
for _ in range(n):
p, d1, d2 = map(int, input().split())
if large < d1 + d2:
large = d1 + d2
number = p
print(number, large)
``` | output | 1 | 30,870 | 4 | 61,741 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
At Aizu Riverside Hospital, inpatients walk twice a day for rehabilitation and health promotion. As the number of people trying to recover their physical strength by walking is increasing day by day in order to leave the hospital energetically, the director plans to give a present to the person who walked the longest distance in a day! I launched it.
Number of patients n (1 ≤ n ≤ 10000), each patient's number pi (1 ≤ pi ≤ 10000), first walk distance d1i, second walk distance d2i (0 ≤ d1i, d2i ≤ 5000) Create a program that outputs the number of the patient with the longest total walking distance and the distance. However, it is assumed that no patient walks the same distance in a day.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
n
p1 d11 d21
p2 d12 d22
::
pn d1n d2n
All inputs are given as integers. The number of datasets does not exceed 50.
Output
For each input dataset, it prints the number of the patient who walked the longest total distance and the distance walked on one line.
Example
Input
5
263 2345 2504
1 3210 1985
5000 1501 4132
10000 503 3107
51 1758 2690
3
345 5000 2396
7 3910 1590
6789 2525 3616
0
Output
5000 5633
345 7396
Submitted Solution:
```
while True:
N = int(input())
if N == 0:
break
ans1 = -1
ans2 = -1
for i in range(N):
p,d1,d2 = [int(j) for j in input().split()]
if d1+d2 > ans2:
ans1 = p
ans2 = d1+d2
print(ans1,ans2)
``` | instruction | 0 | 30,871 | 4 | 61,742 |
Yes | output | 1 | 30,871 | 4 | 61,743 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
At Aizu Riverside Hospital, inpatients walk twice a day for rehabilitation and health promotion. As the number of people trying to recover their physical strength by walking is increasing day by day in order to leave the hospital energetically, the director plans to give a present to the person who walked the longest distance in a day! I launched it.
Number of patients n (1 ≤ n ≤ 10000), each patient's number pi (1 ≤ pi ≤ 10000), first walk distance d1i, second walk distance d2i (0 ≤ d1i, d2i ≤ 5000) Create a program that outputs the number of the patient with the longest total walking distance and the distance. However, it is assumed that no patient walks the same distance in a day.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
n
p1 d11 d21
p2 d12 d22
::
pn d1n d2n
All inputs are given as integers. The number of datasets does not exceed 50.
Output
For each input dataset, it prints the number of the patient who walked the longest total distance and the distance walked on one line.
Example
Input
5
263 2345 2504
1 3210 1985
5000 1501 4132
10000 503 3107
51 1758 2690
3
345 5000 2396
7 3910 1590
6789 2525 3616
0
Output
5000 5633
345 7396
Submitted Solution:
```
while True:
n = int(input())
if n == 0:
break
patients = [map(int, input().split()) for _ in range(n)]
patients = [(p, d1+d2) for p, d1, d2 in patients]
print(*max(patients, key=lambda x: x[1]))
``` | instruction | 0 | 30,872 | 4 | 61,744 |
Yes | output | 1 | 30,872 | 4 | 61,745 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
At Aizu Riverside Hospital, inpatients walk twice a day for rehabilitation and health promotion. As the number of people trying to recover their physical strength by walking is increasing day by day in order to leave the hospital energetically, the director plans to give a present to the person who walked the longest distance in a day! I launched it.
Number of patients n (1 ≤ n ≤ 10000), each patient's number pi (1 ≤ pi ≤ 10000), first walk distance d1i, second walk distance d2i (0 ≤ d1i, d2i ≤ 5000) Create a program that outputs the number of the patient with the longest total walking distance and the distance. However, it is assumed that no patient walks the same distance in a day.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
n
p1 d11 d21
p2 d12 d22
::
pn d1n d2n
All inputs are given as integers. The number of datasets does not exceed 50.
Output
For each input dataset, it prints the number of the patient who walked the longest total distance and the distance walked on one line.
Example
Input
5
263 2345 2504
1 3210 1985
5000 1501 4132
10000 503 3107
51 1758 2690
3
345 5000 2396
7 3910 1590
6789 2525 3616
0
Output
5000 5633
345 7396
Submitted Solution:
```
while 1:
n = int(input())
if n == 0:
break
large = 0
for _ in range(n):
p, d1, d2 = map(int, input().split())
if large < d1 + d2:
large = d1 + d2
number = p
print(number, large)
``` | instruction | 0 | 30,873 | 4 | 61,746 |
Yes | output | 1 | 30,873 | 4 | 61,747 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
At Aizu Riverside Hospital, inpatients walk twice a day for rehabilitation and health promotion. As the number of people trying to recover their physical strength by walking is increasing day by day in order to leave the hospital energetically, the director plans to give a present to the person who walked the longest distance in a day! I launched it.
Number of patients n (1 ≤ n ≤ 10000), each patient's number pi (1 ≤ pi ≤ 10000), first walk distance d1i, second walk distance d2i (0 ≤ d1i, d2i ≤ 5000) Create a program that outputs the number of the patient with the longest total walking distance and the distance. However, it is assumed that no patient walks the same distance in a day.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
n
p1 d11 d21
p2 d12 d22
::
pn d1n d2n
All inputs are given as integers. The number of datasets does not exceed 50.
Output
For each input dataset, it prints the number of the patient who walked the longest total distance and the distance walked on one line.
Example
Input
5
263 2345 2504
1 3210 1985
5000 1501 4132
10000 503 3107
51 1758 2690
3
345 5000 2396
7 3910 1590
6789 2525 3616
0
Output
5000 5633
345 7396
Submitted Solution:
```
while 1:
n=int(input())
if n==0:break
a=[map(int, input().split()) for _ in range(n)]
a=[[p,d1+d2] for p, d1, d2 in a]
a.sort(key=lambda b:b[1])
print(*a[-1])
``` | instruction | 0 | 30,874 | 4 | 61,748 |
Yes | output | 1 | 30,874 | 4 | 61,749 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One day shooshuns found a sequence of n integers, written on a blackboard. The shooshuns can perform one operation with it, the operation consists of two steps:
1. Find the number that goes k-th in the current sequence and add the same number to the end of the sequence;
2. Delete the first number of the current sequence.
The shooshuns wonder after how many operations all numbers on the board will be the same and whether all numbers will ever be the same.
Input
The first line contains two space-separated integers n and k (1 ≤ k ≤ n ≤ 105).
The second line contains n space-separated integers: a1, a2, ..., an (1 ≤ ai ≤ 105) — the sequence that the shooshuns found.
Output
Print the minimum number of operations, required for all numbers on the blackboard to become the same. If it is impossible to achieve, print -1.
Examples
Input
3 2
3 1 1
Output
1
Input
3 1
3 1 1
Output
-1
Note
In the first test case after the first operation the blackboard will have sequence [1, 1, 1]. So, one operation is enough to make all numbers the same. Thus, the answer equals one.
In the second test case the sequence will never consist of the same numbers. It will always contain at least two distinct numbers 3 and 1. Thus, the answer equals -1.
Submitted Solution:
```
from functools import reduce
from collections import Counter
import time
import datetime
def time_t():
print("Current date and time: " , datetime.datetime.now())
print("Current year: ", datetime.date.today().strftime("%Y"))
print("Month of year: ", datetime.date.today().strftime("%B"))
print("Week number of the year: ", datetime.date.today().strftime("%W"))
print("Weekday of the week: ", datetime.date.today().strftime("%w"))
print("Day of year: ", datetime.date.today().strftime("%j"))
print("Day of the month : ", datetime.date.today().strftime("%d"))
print("Day of week: ", datetime.date.today().strftime("%A"))
def ip():
return int(input())
def sip():
return input()
def mip():
return map(int,input().split())
def mips():
return map(str,input().split())
def lip():
return list(map(int,input().split()))
def matip(n,m):
lst=[]
for i in range(n):
arr = lip()
lst.append(arr)
return lst
def factors(n): # find the factors of a number
return list(set(reduce(list.__add__, ([i, n//i] for i in range(1, int(n**0.5) + 1) if n % i == 0))))
def minJumps(arr, n): #to reach from 0 to n-1 in the array in minimum steps
jumps = [0 for i in range(n)]
if (n == 0) or (arr[0] == 0):
return float('inf')
jumps[0] = 0
for i in range(1, n):
jumps[i] = float('inf')
for j in range(i):
if (i <= j + arr[j]) and (jumps[j] != float('inf')):
jumps[i] = min(jumps[i], jumps[j] + 1)
break
return jumps[n-1]
def dic(arr): # converting list into dict of count
return Counter(arr)
n,k = mip()
arr = lip()
flag = 0
for i in range(k,n):
if arr[i]!=arr[k-1]:
flag = 1
val = -1
for i in range(k-1):
if arr[i]!=arr[k-1]:
val = i
if flag == 0:
print(val+1)
else:
print(-1)
``` | instruction | 0 | 31,266 | 4 | 62,532 |
Yes | output | 1 | 31,266 | 4 | 62,533 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Today Vasya visited a widely known site and learned that the continuation of his favourite game Codecraft II will appear after exactly k months. He looked at the calendar and learned that at the moment is the month number s. Vasya immediately got interested in what month Codecraft III will appear. Help him understand that.
All the twelve months in Vasya's calendar are named using their usual English names: January, February, March, April, May, June, July, August, September, October, November, December.
Input
The first input line contains the name of the current month. It is guaranteed that it is a proper English name of one of twelve months. The first letter is uppercase, the rest are lowercase. The second line contains integer k (0 ≤ k ≤ 100) — the number of months left till the appearance of Codecraft III.
Output
Print starting from an uppercase letter the name of the month in which the continuation of Codeforces II will appear. The printed name must be contained in the list January, February, March, April, May, June, July, August, September, October, November, December.
Examples
Input
November
3
Output
February
Input
May
24
Output
May | instruction | 0 | 31,342 | 4 | 62,684 |
Tags: implementation
Correct Solution:
```
x=str(input())
x=x.replace(' ','')
if x=='January':
ans=1
elif x=='February':
ans=2
elif x=='March':
ans=3
elif x=='April':
ans=4
elif x=='May':
ans=5
elif x=='June':
ans=6
elif x=='July':
ans=7
elif x=='August':
ans=8
elif x=='September':
ans=9
elif x=='October':
ans=10
elif x=='November':
ans=11
elif x=='December':
ans=12
s=int(input())
ans=ans+s
if ans%12==1:
print('January')
elif ans%12==2:
print('February')
elif ans%12==3:
print('March')
elif ans%12==4:
print('April')
elif ans%12==5:
print('May')
elif ans%12==6:
print('June')
elif ans%12==7:
print('July')
elif ans%12==8:
print('August')
elif ans%12==9:
print('September')
elif ans%12==10:
print('October')
elif ans%12==11:
print('November')
elif ans%12==0:
print('December')
``` | output | 1 | 31,342 | 4 | 62,685 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Today Vasya visited a widely known site and learned that the continuation of his favourite game Codecraft II will appear after exactly k months. He looked at the calendar and learned that at the moment is the month number s. Vasya immediately got interested in what month Codecraft III will appear. Help him understand that.
All the twelve months in Vasya's calendar are named using their usual English names: January, February, March, April, May, June, July, August, September, October, November, December.
Input
The first input line contains the name of the current month. It is guaranteed that it is a proper English name of one of twelve months. The first letter is uppercase, the rest are lowercase. The second line contains integer k (0 ≤ k ≤ 100) — the number of months left till the appearance of Codecraft III.
Output
Print starting from an uppercase letter the name of the month in which the continuation of Codeforces II will appear. The printed name must be contained in the list January, February, March, April, May, June, July, August, September, October, November, December.
Examples
Input
November
3
Output
February
Input
May
24
Output
May | instruction | 0 | 31,343 | 4 | 62,686 |
Tags: implementation
Correct Solution:
```
m = ['January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December']
s = input()
k = int(input())
for i in range(12):
if(s==m[i]):
print(m[(i+k)%12])
``` | output | 1 | 31,343 | 4 | 62,687 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Today Vasya visited a widely known site and learned that the continuation of his favourite game Codecraft II will appear after exactly k months. He looked at the calendar and learned that at the moment is the month number s. Vasya immediately got interested in what month Codecraft III will appear. Help him understand that.
All the twelve months in Vasya's calendar are named using their usual English names: January, February, March, April, May, June, July, August, September, October, November, December.
Input
The first input line contains the name of the current month. It is guaranteed that it is a proper English name of one of twelve months. The first letter is uppercase, the rest are lowercase. The second line contains integer k (0 ≤ k ≤ 100) — the number of months left till the appearance of Codecraft III.
Output
Print starting from an uppercase letter the name of the month in which the continuation of Codeforces II will appear. The printed name must be contained in the list January, February, March, April, May, June, July, August, September, October, November, December.
Examples
Input
November
3
Output
February
Input
May
24
Output
May | instruction | 0 | 31,344 | 4 | 62,688 |
Tags: implementation
Correct Solution:
```
months = ['January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December']
m = input()
n = int(input())
q = months.index(m)
# print(q)
r = (q + n) % 12
print(months[r])
``` | output | 1 | 31,344 | 4 | 62,689 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Today Vasya visited a widely known site and learned that the continuation of his favourite game Codecraft II will appear after exactly k months. He looked at the calendar and learned that at the moment is the month number s. Vasya immediately got interested in what month Codecraft III will appear. Help him understand that.
All the twelve months in Vasya's calendar are named using their usual English names: January, February, March, April, May, June, July, August, September, October, November, December.
Input
The first input line contains the name of the current month. It is guaranteed that it is a proper English name of one of twelve months. The first letter is uppercase, the rest are lowercase. The second line contains integer k (0 ≤ k ≤ 100) — the number of months left till the appearance of Codecraft III.
Output
Print starting from an uppercase letter the name of the month in which the continuation of Codeforces II will appear. The printed name must be contained in the list January, February, March, April, May, June, July, August, September, October, November, December.
Examples
Input
November
3
Output
February
Input
May
24
Output
May | instruction | 0 | 31,345 | 4 | 62,690 |
Tags: implementation
Correct Solution:
```
cont = ['January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November',
'December']
m = input()
n = int(input())
print(cont[(cont.index(m) + n) % 12])
``` | output | 1 | 31,345 | 4 | 62,691 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Today Vasya visited a widely known site and learned that the continuation of his favourite game Codecraft II will appear after exactly k months. He looked at the calendar and learned that at the moment is the month number s. Vasya immediately got interested in what month Codecraft III will appear. Help him understand that.
All the twelve months in Vasya's calendar are named using their usual English names: January, February, March, April, May, June, July, August, September, October, November, December.
Input
The first input line contains the name of the current month. It is guaranteed that it is a proper English name of one of twelve months. The first letter is uppercase, the rest are lowercase. The second line contains integer k (0 ≤ k ≤ 100) — the number of months left till the appearance of Codecraft III.
Output
Print starting from an uppercase letter the name of the month in which the continuation of Codeforces II will appear. The printed name must be contained in the list January, February, March, April, May, June, July, August, September, October, November, December.
Examples
Input
November
3
Output
February
Input
May
24
Output
May | instruction | 0 | 31,346 | 4 | 62,692 |
Tags: implementation
Correct Solution:
```
s = input()
k = int(input())
d1 = {'January': 1, 'February': 2, 'March': 3, 'April': 4, 'May': 5, 'June': 6,
'July': 7, 'August': 8, 'September': 9, 'October': 10, 'November': 11, 'December': 12}
d2 = {1: 'January', 2: 'February', 3: 'March', 4: 'April', 5: 'May', 6: 'June',
7: 'July', 8: 'August', 9: 'September', 10: 'October', 11: 'November', 12: 'December'}
if (d1[s] + k) % 12 != 0:
print(d2[(d1[s] + k) % 12])
else:
print('December')
``` | output | 1 | 31,346 | 4 | 62,693 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Today Vasya visited a widely known site and learned that the continuation of his favourite game Codecraft II will appear after exactly k months. He looked at the calendar and learned that at the moment is the month number s. Vasya immediately got interested in what month Codecraft III will appear. Help him understand that.
All the twelve months in Vasya's calendar are named using their usual English names: January, February, March, April, May, June, July, August, September, October, November, December.
Input
The first input line contains the name of the current month. It is guaranteed that it is a proper English name of one of twelve months. The first letter is uppercase, the rest are lowercase. The second line contains integer k (0 ≤ k ≤ 100) — the number of months left till the appearance of Codecraft III.
Output
Print starting from an uppercase letter the name of the month in which the continuation of Codeforces II will appear. The printed name must be contained in the list January, February, March, April, May, June, July, August, September, October, November, December.
Examples
Input
November
3
Output
February
Input
May
24
Output
May | instruction | 0 | 31,347 | 4 | 62,694 |
Tags: implementation
Correct Solution:
```
month = input()
n = int(input())
d = {"January": 1, "February": 2, "March": 3, "April": 4, "May": 5, "June": 6, "July": 7, "August": 8, "September": 9,
"October": 10, "November": 11, "December": 12}
l = list(d.keys())
ans = (d[month] + n) % 12
print(l[ans-1])
``` | output | 1 | 31,347 | 4 | 62,695 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Today Vasya visited a widely known site and learned that the continuation of his favourite game Codecraft II will appear after exactly k months. He looked at the calendar and learned that at the moment is the month number s. Vasya immediately got interested in what month Codecraft III will appear. Help him understand that.
All the twelve months in Vasya's calendar are named using their usual English names: January, February, March, April, May, June, July, August, September, October, November, December.
Input
The first input line contains the name of the current month. It is guaranteed that it is a proper English name of one of twelve months. The first letter is uppercase, the rest are lowercase. The second line contains integer k (0 ≤ k ≤ 100) — the number of months left till the appearance of Codecraft III.
Output
Print starting from an uppercase letter the name of the month in which the continuation of Codeforces II will appear. The printed name must be contained in the list January, February, March, April, May, June, July, August, September, October, November, December.
Examples
Input
November
3
Output
February
Input
May
24
Output
May | instruction | 0 | 31,349 | 4 | 62,698 |
Tags: implementation
Correct Solution:
```
months = ['January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December']
m = str(input())
x = months.index(m)
d = int(input())
print(months[(x+d)%12])
``` | output | 1 | 31,349 | 4 | 62,699 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Today Vasya visited a widely known site and learned that the continuation of his favourite game Codecraft II will appear after exactly k months. He looked at the calendar and learned that at the moment is the month number s. Vasya immediately got interested in what month Codecraft III will appear. Help him understand that.
All the twelve months in Vasya's calendar are named using their usual English names: January, February, March, April, May, June, July, August, September, October, November, December.
Input
The first input line contains the name of the current month. It is guaranteed that it is a proper English name of one of twelve months. The first letter is uppercase, the rest are lowercase. The second line contains integer k (0 ≤ k ≤ 100) — the number of months left till the appearance of Codecraft III.
Output
Print starting from an uppercase letter the name of the month in which the continuation of Codeforces II will appear. The printed name must be contained in the list January, February, March, April, May, June, July, August, September, October, November, December.
Examples
Input
November
3
Output
February
Input
May
24
Output
May
Submitted Solution:
```
str='January, February, March, April, May, June, July, August, September, October, November, December'
list=str.split(', ')
#print(list[1])
m=input()
n=0
for i in range(len(list)):
if m==list[i]:
n=i
break
n2=int(input())
n2=(n2+n)%12
print(list[n2])
``` | instruction | 0 | 31,350 | 4 | 62,700 |
Yes | output | 1 | 31,350 | 4 | 62,701 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Today Vasya visited a widely known site and learned that the continuation of his favourite game Codecraft II will appear after exactly k months. He looked at the calendar and learned that at the moment is the month number s. Vasya immediately got interested in what month Codecraft III will appear. Help him understand that.
All the twelve months in Vasya's calendar are named using their usual English names: January, February, March, April, May, June, July, August, September, October, November, December.
Input
The first input line contains the name of the current month. It is guaranteed that it is a proper English name of one of twelve months. The first letter is uppercase, the rest are lowercase. The second line contains integer k (0 ≤ k ≤ 100) — the number of months left till the appearance of Codecraft III.
Output
Print starting from an uppercase letter the name of the month in which the continuation of Codeforces II will appear. The printed name must be contained in the list January, February, March, April, May, June, July, August, September, October, November, December.
Examples
Input
November
3
Output
February
Input
May
24
Output
May
Submitted Solution:
```
months = [ 'January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December']
month = input()
idx = months.index(month)
tonext = (int(input()) + idx )% 12
print(months[tonext])
``` | instruction | 0 | 31,351 | 4 | 62,702 |
Yes | output | 1 | 31,351 | 4 | 62,703 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Today Vasya visited a widely known site and learned that the continuation of his favourite game Codecraft II will appear after exactly k months. He looked at the calendar and learned that at the moment is the month number s. Vasya immediately got interested in what month Codecraft III will appear. Help him understand that.
All the twelve months in Vasya's calendar are named using their usual English names: January, February, March, April, May, June, July, August, September, October, November, December.
Input
The first input line contains the name of the current month. It is guaranteed that it is a proper English name of one of twelve months. The first letter is uppercase, the rest are lowercase. The second line contains integer k (0 ≤ k ≤ 100) — the number of months left till the appearance of Codecraft III.
Output
Print starting from an uppercase letter the name of the month in which the continuation of Codeforces II will appear. The printed name must be contained in the list January, February, March, April, May, June, July, August, September, October, November, December.
Examples
Input
November
3
Output
February
Input
May
24
Output
May
Submitted Solution:
```
a = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]
m = input().rstrip()
k = int(input())
i = 0
while m != a[i]:
i += 1
print(a[(i + k) % 12])
``` | instruction | 0 | 31,352 | 4 | 62,704 |
Yes | output | 1 | 31,352 | 4 | 62,705 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Today Vasya visited a widely known site and learned that the continuation of his favourite game Codecraft II will appear after exactly k months. He looked at the calendar and learned that at the moment is the month number s. Vasya immediately got interested in what month Codecraft III will appear. Help him understand that.
All the twelve months in Vasya's calendar are named using their usual English names: January, February, March, April, May, June, July, August, September, October, November, December.
Input
The first input line contains the name of the current month. It is guaranteed that it is a proper English name of one of twelve months. The first letter is uppercase, the rest are lowercase. The second line contains integer k (0 ≤ k ≤ 100) — the number of months left till the appearance of Codecraft III.
Output
Print starting from an uppercase letter the name of the month in which the continuation of Codeforces II will appear. The printed name must be contained in the list January, February, March, April, May, June, July, August, September, October, November, December.
Examples
Input
November
3
Output
February
Input
May
24
Output
May
Submitted Solution:
```
m = ['January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December']
print(m[(m.index(input()) + int(input())) % 12])
``` | instruction | 0 | 31,353 | 4 | 62,706 |
Yes | output | 1 | 31,353 | 4 | 62,707 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Today Vasya visited a widely known site and learned that the continuation of his favourite game Codecraft II will appear after exactly k months. He looked at the calendar and learned that at the moment is the month number s. Vasya immediately got interested in what month Codecraft III will appear. Help him understand that.
All the twelve months in Vasya's calendar are named using their usual English names: January, February, March, April, May, June, July, August, September, October, November, December.
Input
The first input line contains the name of the current month. It is guaranteed that it is a proper English name of one of twelve months. The first letter is uppercase, the rest are lowercase. The second line contains integer k (0 ≤ k ≤ 100) — the number of months left till the appearance of Codecraft III.
Output
Print starting from an uppercase letter the name of the month in which the continuation of Codeforces II will appear. The printed name must be contained in the list January, February, March, April, May, June, July, August, September, October, November, December.
Examples
Input
November
3
Output
February
Input
May
24
Output
May
Submitted Solution:
```
dict={}
dict["January"]=1
dict["February"]=2
dict["March"]=3
dict["April"]=4
dict["May"]=5
dict["June"]=6
dict["July"]=7
dict["August"]=8
dict["September"]=9
dict["October"]=10
dict["November"]=11
dict["December"]=12
tmp=input()
s=int(input())
s+=dict[tmp]
s%=12
for i in dict:
if(dict[i]==s):
print(i)
break
``` | instruction | 0 | 31,354 | 4 | 62,708 |
No | output | 1 | 31,354 | 4 | 62,709 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Today Vasya visited a widely known site and learned that the continuation of his favourite game Codecraft II will appear after exactly k months. He looked at the calendar and learned that at the moment is the month number s. Vasya immediately got interested in what month Codecraft III will appear. Help him understand that.
All the twelve months in Vasya's calendar are named using their usual English names: January, February, March, April, May, June, July, August, September, October, November, December.
Input
The first input line contains the name of the current month. It is guaranteed that it is a proper English name of one of twelve months. The first letter is uppercase, the rest are lowercase. The second line contains integer k (0 ≤ k ≤ 100) — the number of months left till the appearance of Codecraft III.
Output
Print starting from an uppercase letter the name of the month in which the continuation of Codeforces II will appear. The printed name must be contained in the list January, February, March, April, May, June, July, August, September, October, November, December.
Examples
Input
November
3
Output
February
Input
May
24
Output
May
Submitted Solution:
```
month = ['January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December']
m = input()
k = int(input())
for i in range(12):
chk = k % 12
diff = 12 - (i+1)
if month[i] == m:
if chk > diff:
print(month[chk-(diff+1)])
elif chk == 0:
print(month[i])
elif chk < diff:
print(month[i+k])
else:
continue
``` | instruction | 0 | 31,355 | 4 | 62,710 |
No | output | 1 | 31,355 | 4 | 62,711 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Today Vasya visited a widely known site and learned that the continuation of his favourite game Codecraft II will appear after exactly k months. He looked at the calendar and learned that at the moment is the month number s. Vasya immediately got interested in what month Codecraft III will appear. Help him understand that.
All the twelve months in Vasya's calendar are named using their usual English names: January, February, March, April, May, June, July, August, September, October, November, December.
Input
The first input line contains the name of the current month. It is guaranteed that it is a proper English name of one of twelve months. The first letter is uppercase, the rest are lowercase. The second line contains integer k (0 ≤ k ≤ 100) — the number of months left till the appearance of Codecraft III.
Output
Print starting from an uppercase letter the name of the month in which the continuation of Codeforces II will appear. The printed name must be contained in the list January, February, March, April, May, June, July, August, September, October, November, December.
Examples
Input
November
3
Output
February
Input
May
24
Output
May
Submitted Solution:
```
month, skip = input(''), int(input())
months = ['January', 'February', 'March', 'April', 'May', 'June', 'July',
'August', 'September', 'October', 'November', 'December']
print(months[skip - int(skip/12)*12 + month.index(month)])
``` | instruction | 0 | 31,356 | 4 | 62,712 |
No | output | 1 | 31,356 | 4 | 62,713 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Today Vasya visited a widely known site and learned that the continuation of his favourite game Codecraft II will appear after exactly k months. He looked at the calendar and learned that at the moment is the month number s. Vasya immediately got interested in what month Codecraft III will appear. Help him understand that.
All the twelve months in Vasya's calendar are named using their usual English names: January, February, March, April, May, June, July, August, September, October, November, December.
Input
The first input line contains the name of the current month. It is guaranteed that it is a proper English name of one of twelve months. The first letter is uppercase, the rest are lowercase. The second line contains integer k (0 ≤ k ≤ 100) — the number of months left till the appearance of Codecraft III.
Output
Print starting from an uppercase letter the name of the month in which the continuation of Codeforces II will appear. The printed name must be contained in the list January, February, March, April, May, June, July, August, September, October, November, December.
Examples
Input
November
3
Output
February
Input
May
24
Output
May
Submitted Solution:
```
l = ['January',"February","March","April","May","June","July","August","September","October","November","December"]
m = input()
n = int(input())
p=0
if n%12==0:
print(m)
exit()
a = l.index(m)
while(n):
if a==12:
p=1
a=1
a+=1
n-=1
if p:
print(l[a-1])
exit()
print(l[a])
``` | instruction | 0 | 31,357 | 4 | 62,714 |
No | output | 1 | 31,357 | 4 | 62,715 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that outputs all leap years between the year a and year b.
The leap year conditions are as follows. However, 0 <a ≤ b <3,000. If there is no leap year in the given period, output "NA".
* The year is divisible by 4.
* However, a year divisible by 100 is not a leap year.
* However, a year divisible by 400 is a leap year.
Input
Given multiple datasets. The format of each dataset is as follows:
a b
Input ends when both a and b are 0. The number of datasets does not exceed 50.
Output
Print the year or NA for each dataset.
Insert one blank line between the datasets.
Example
Input
2001 2010
2005 2005
2001 2010
0 0
Output
2004
2008
NA
2004
2008 | instruction | 0 | 31,686 | 4 | 63,372 |
"Correct Solution:
```
def get_data():
while True:
a, b = map(int, input().split())
if a == b == 0:
break
yield a, b
input_data = list(get_data())
for i, data in enumerate(input_data):
a, b = data
flg = False
for x in range(a, b + 1):
if (x % 4 == 0 and x % 100 != 0) or x % 400 == 0:
if not flg:
flg = True
print(x)
if not flg:
print('NA')
if i != len(input_data) - 1:
print()
``` | output | 1 | 31,686 | 4 | 63,373 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that outputs all leap years between the year a and year b.
The leap year conditions are as follows. However, 0 <a ≤ b <3,000. If there is no leap year in the given period, output "NA".
* The year is divisible by 4.
* However, a year divisible by 100 is not a leap year.
* However, a year divisible by 400 is a leap year.
Input
Given multiple datasets. The format of each dataset is as follows:
a b
Input ends when both a and b are 0. The number of datasets does not exceed 50.
Output
Print the year or NA for each dataset.
Insert one blank line between the datasets.
Example
Input
2001 2010
2005 2005
2001 2010
0 0
Output
2004
2008
NA
2004
2008 | instruction | 0 | 31,687 | 4 | 63,374 |
"Correct Solution:
```
is_not_first = 0
while True:
a, b = map(int, input().split())
if not a:
break
if is_not_first:
print()
is_not_first += 1
print_flag = 0
for year in range(a, b + 1):
if (not year % 4) and ((not (not year % 100)) or (not year % 400)):
print(year)
print_flag = 1
if not print_flag:
print("NA")
``` | output | 1 | 31,687 | 4 | 63,375 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that outputs all leap years between the year a and year b.
The leap year conditions are as follows. However, 0 <a ≤ b <3,000. If there is no leap year in the given period, output "NA".
* The year is divisible by 4.
* However, a year divisible by 100 is not a leap year.
* However, a year divisible by 400 is a leap year.
Input
Given multiple datasets. The format of each dataset is as follows:
a b
Input ends when both a and b are 0. The number of datasets does not exceed 50.
Output
Print the year or NA for each dataset.
Insert one blank line between the datasets.
Example
Input
2001 2010
2005 2005
2001 2010
0 0
Output
2004
2008
NA
2004
2008 | instruction | 0 | 31,688 | 4 | 63,376 |
"Correct Solution:
```
# AOJ 0093 Leap Year
# Python3 2018.6.11 bal4u
def leap_year(y):
return y % 4 == 0 and (y % 100 != 0 or y % 400 == 0)
import sys
first = True
for line in sys.stdin:
a, b = list(map(int, line.split()))
if a == 0:
break
else:
if first:
first = False
else:
print()
f = False
for y in range(a, b+1):
if leap_year(y):
print(y)
f = True
if not f:
print('NA')
``` | output | 1 | 31,688 | 4 | 63,377 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that outputs all leap years between the year a and year b.
The leap year conditions are as follows. However, 0 <a ≤ b <3,000. If there is no leap year in the given period, output "NA".
* The year is divisible by 4.
* However, a year divisible by 100 is not a leap year.
* However, a year divisible by 400 is a leap year.
Input
Given multiple datasets. The format of each dataset is as follows:
a b
Input ends when both a and b are 0. The number of datasets does not exceed 50.
Output
Print the year or NA for each dataset.
Insert one blank line between the datasets.
Example
Input
2001 2010
2005 2005
2001 2010
0 0
Output
2004
2008
NA
2004
2008 | instruction | 0 | 31,689 | 4 | 63,378 |
"Correct Solution:
```
count = 0
while True:
a,b = map(int,input().split())
if (a,b) == (0,0):
break
if count:
print()
flag = 0
for i in range(a,b+1):
if (not (i % 400)) or ((i % 100) and (not (i % 4))):
print(i)
flag = 1
if not flag:
print("NA")
count += 1
``` | output | 1 | 31,689 | 4 | 63,379 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that outputs all leap years between the year a and year b.
The leap year conditions are as follows. However, 0 <a ≤ b <3,000. If there is no leap year in the given period, output "NA".
* The year is divisible by 4.
* However, a year divisible by 100 is not a leap year.
* However, a year divisible by 400 is a leap year.
Input
Given multiple datasets. The format of each dataset is as follows:
a b
Input ends when both a and b are 0. The number of datasets does not exceed 50.
Output
Print the year or NA for each dataset.
Insert one blank line between the datasets.
Example
Input
2001 2010
2005 2005
2001 2010
0 0
Output
2004
2008
NA
2004
2008 | instruction | 0 | 31,690 | 4 | 63,380 |
"Correct Solution:
```
# Aizu Problem 0093: Leap Yeark
#
import sys, math, os
# read input:
PYDEV = os.environ.get('PYDEV')
if PYDEV=="True":
sys.stdin = open("sample-input.txt", "rt")
def is_leap_year(year):
return year % 400 == 0 or (year % 4 == 0 and year % 100 != 0)
first = True
while True:
y1, y2 = [int(_) for _ in input().split()]
if y1 == y2 == 0:
break
if first:
first = False
else:
print()
leap_years = [year for year in range(y1, y2 + 1) if is_leap_year(year)]
if len(leap_years) == 0:
print("NA")
else:
for year in leap_years:
print(year)
``` | output | 1 | 31,690 | 4 | 63,381 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that outputs all leap years between the year a and year b.
The leap year conditions are as follows. However, 0 <a ≤ b <3,000. If there is no leap year in the given period, output "NA".
* The year is divisible by 4.
* However, a year divisible by 100 is not a leap year.
* However, a year divisible by 400 is a leap year.
Input
Given multiple datasets. The format of each dataset is as follows:
a b
Input ends when both a and b are 0. The number of datasets does not exceed 50.
Output
Print the year or NA for each dataset.
Insert one blank line between the datasets.
Example
Input
2001 2010
2005 2005
2001 2010
0 0
Output
2004
2008
NA
2004
2008 | instruction | 0 | 31,691 | 4 | 63,382 |
"Correct Solution:
```
first = True
while True:
a, b = map(int, input().split())
if a == b == 0: break
if not first: print()
first = False
count = 0
for y in range(a, b + 1):
if y % 400 == 0 or y % 4 == 0 and y % 100 != 0:
count += 1
print(y)
if count == 0: print('NA')
``` | output | 1 | 31,691 | 4 | 63,383 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that outputs all leap years between the year a and year b.
The leap year conditions are as follows. However, 0 <a ≤ b <3,000. If there is no leap year in the given period, output "NA".
* The year is divisible by 4.
* However, a year divisible by 100 is not a leap year.
* However, a year divisible by 400 is a leap year.
Input
Given multiple datasets. The format of each dataset is as follows:
a b
Input ends when both a and b are 0. The number of datasets does not exceed 50.
Output
Print the year or NA for each dataset.
Insert one blank line between the datasets.
Example
Input
2001 2010
2005 2005
2001 2010
0 0
Output
2004
2008
NA
2004
2008 | instruction | 0 | 31,692 | 4 | 63,384 |
"Correct Solution:
```
p=print
b=1
for e in iter(input,'0 0'):
b or p()
b=f=0;s,t=map(int,e.split())
for y in range(s,t+1):
if(y%4==0)*(y%100)or y%400==0:p(y);f=1
f or p('NA')
``` | output | 1 | 31,692 | 4 | 63,385 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that outputs all leap years between the year a and year b.
The leap year conditions are as follows. However, 0 <a ≤ b <3,000. If there is no leap year in the given period, output "NA".
* The year is divisible by 4.
* However, a year divisible by 100 is not a leap year.
* However, a year divisible by 400 is a leap year.
Input
Given multiple datasets. The format of each dataset is as follows:
a b
Input ends when both a and b are 0. The number of datasets does not exceed 50.
Output
Print the year or NA for each dataset.
Insert one blank line between the datasets.
Example
Input
2001 2010
2005 2005
2001 2010
0 0
Output
2004
2008
NA
2004
2008 | instruction | 0 | 31,693 | 4 | 63,386 |
"Correct Solution:
```
flag = False
while True:
A,B = map(int,input().split())
if A == 0:
break
ans = []
for i in range(A,B + 1):
if i % 400 == 0 or (i % 100 != 0 and i % 4 == 0):
ans.append(i)
if flag:
print('')
flag = True
if len(ans) != 0:
for i in ans:
print(i)
else:
print('NA')
``` | output | 1 | 31,693 | 4 | 63,387 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Create a program that outputs all leap years between the year a and year b.
The leap year conditions are as follows. However, 0 <a ≤ b <3,000. If there is no leap year in the given period, output "NA".
* The year is divisible by 4.
* However, a year divisible by 100 is not a leap year.
* However, a year divisible by 400 is a leap year.
Input
Given multiple datasets. The format of each dataset is as follows:
a b
Input ends when both a and b are 0. The number of datasets does not exceed 50.
Output
Print the year or NA for each dataset.
Insert one blank line between the datasets.
Example
Input
2001 2010
2005 2005
2001 2010
0 0
Output
2004
2008
NA
2004
2008
Submitted Solution:
```
result = []
while True:
a, b = map(int, input().split())
if a == b == 0:
break
result.append("\n".join([str(i) for i in range(a, b+1) if i%400 == 0 or i%4 == 0 and i%100]) or "NA")
print("\n\n".join(result))
``` | instruction | 0 | 31,694 | 4 | 63,388 |
Yes | output | 1 | 31,694 | 4 | 63,389 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Create a program that outputs all leap years between the year a and year b.
The leap year conditions are as follows. However, 0 <a ≤ b <3,000. If there is no leap year in the given period, output "NA".
* The year is divisible by 4.
* However, a year divisible by 100 is not a leap year.
* However, a year divisible by 400 is a leap year.
Input
Given multiple datasets. The format of each dataset is as follows:
a b
Input ends when both a and b are 0. The number of datasets does not exceed 50.
Output
Print the year or NA for each dataset.
Insert one blank line between the datasets.
Example
Input
2001 2010
2005 2005
2001 2010
0 0
Output
2004
2008
NA
2004
2008
Submitted Solution:
```
first=1
while 1:
a,b=map(int,input().split())
if a==b==0:break
if first==1:
first=0
else:
print()
count=0
for i in range(a,b+1):
if i%400==0:
print(i)
count+=1
elif i%100==0:
pass
elif i%4==0:
print(i)
count+=1
if count==0:print("NA")
``` | instruction | 0 | 31,695 | 4 | 63,390 |
Yes | output | 1 | 31,695 | 4 | 63,391 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Create a program that outputs all leap years between the year a and year b.
The leap year conditions are as follows. However, 0 <a ≤ b <3,000. If there is no leap year in the given period, output "NA".
* The year is divisible by 4.
* However, a year divisible by 100 is not a leap year.
* However, a year divisible by 400 is a leap year.
Input
Given multiple datasets. The format of each dataset is as follows:
a b
Input ends when both a and b are 0. The number of datasets does not exceed 50.
Output
Print the year or NA for each dataset.
Insert one blank line between the datasets.
Example
Input
2001 2010
2005 2005
2001 2010
0 0
Output
2004
2008
NA
2004
2008
Submitted Solution:
```
flag = 1
while True:
a, b = map(int, input().split())
if a == b == 0:
quit()
if flag == 0:
print()
else:
flag = 0
count = 0
for i in range(a, b+1):
if i % 400 == 0:
print(i)
count += 1
elif i % 100 != 0 and i % 4 == 0:
print(i)
count += 1
if count == 0:
print('NA')
``` | instruction | 0 | 31,696 | 4 | 63,392 |
Yes | output | 1 | 31,696 | 4 | 63,393 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Create a program that outputs all leap years between the year a and year b.
The leap year conditions are as follows. However, 0 <a ≤ b <3,000. If there is no leap year in the given period, output "NA".
* The year is divisible by 4.
* However, a year divisible by 100 is not a leap year.
* However, a year divisible by 400 is a leap year.
Input
Given multiple datasets. The format of each dataset is as follows:
a b
Input ends when both a and b are 0. The number of datasets does not exceed 50.
Output
Print the year or NA for each dataset.
Insert one blank line between the datasets.
Example
Input
2001 2010
2005 2005
2001 2010
0 0
Output
2004
2008
NA
2004
2008
Submitted Solution:
```
cnt = 0
while True:
a, b = map(int, input().split())
if a + b == 0:
break
flag = True
if cnt != 0:
print()
for i in range(a, b + 1):
if i % 4 == 0:
if i % 100 == 0:
if i % 400 == 0:
flag = False
print(i)
else:
flag = False
print(i)
if flag == True:
print("NA")
cnt += 1
``` | instruction | 0 | 31,697 | 4 | 63,394 |
Yes | output | 1 | 31,697 | 4 | 63,395 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Create a program that outputs all leap years between the year a and year b.
The leap year conditions are as follows. However, 0 <a ≤ b <3,000. If there is no leap year in the given period, output "NA".
* The year is divisible by 4.
* However, a year divisible by 100 is not a leap year.
* However, a year divisible by 400 is a leap year.
Input
Given multiple datasets. The format of each dataset is as follows:
a b
Input ends when both a and b are 0. The number of datasets does not exceed 50.
Output
Print the year or NA for each dataset.
Insert one blank line between the datasets.
Example
Input
2001 2010
2005 2005
2001 2010
0 0
Output
2004
2008
NA
2004
2008
Submitted Solution:
```
from calendar import isleap
while True:
a, b = map(int, input().split())
if a == 0:
break
print(sum(isleap(i) for i in range(a, b+1)))
``` | instruction | 0 | 31,698 | 4 | 63,396 |
No | output | 1 | 31,698 | 4 | 63,397 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Create a program that outputs all leap years between the year a and year b.
The leap year conditions are as follows. However, 0 <a ≤ b <3,000. If there is no leap year in the given period, output "NA".
* The year is divisible by 4.
* However, a year divisible by 100 is not a leap year.
* However, a year divisible by 400 is a leap year.
Input
Given multiple datasets. The format of each dataset is as follows:
a b
Input ends when both a and b are 0. The number of datasets does not exceed 50.
Output
Print the year or NA for each dataset.
Insert one blank line between the datasets.
Example
Input
2001 2010
2005 2005
2001 2010
0 0
Output
2004
2008
NA
2004
2008
Submitted Solution:
```
b=1
for e in iter(input,'0 0'):
if b:print();b=0
s,t=map(int,e.split())
u=[y for y in range(s,t+1)if y%4==0 and y%100!=0 or y%400==0]
if u:
for y in u:print(y)
else:print('NA')
``` | instruction | 0 | 31,699 | 4 | 63,398 |
No | output | 1 | 31,699 | 4 | 63,399 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Create a program that outputs all leap years between the year a and year b.
The leap year conditions are as follows. However, 0 <a ≤ b <3,000. If there is no leap year in the given period, output "NA".
* The year is divisible by 4.
* However, a year divisible by 100 is not a leap year.
* However, a year divisible by 400 is a leap year.
Input
Given multiple datasets. The format of each dataset is as follows:
a b
Input ends when both a and b are 0. The number of datasets does not exceed 50.
Output
Print the year or NA for each dataset.
Insert one blank line between the datasets.
Example
Input
2001 2010
2005 2005
2001 2010
0 0
Output
2004
2008
NA
2004
2008
Submitted Solution:
```
import calendar as C
while 1:
a,b=map(int, input().split())
if a==0:break
if sum([1 for i in range(a,b+1) if C.isleap(i)])==0:
print("NA")
else:
for i in range(a,b+1):
if C.isleap(i):print(i)
print()
``` | instruction | 0 | 31,700 | 4 | 63,400 |
No | output | 1 | 31,700 | 4 | 63,401 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Create a program that outputs all leap years between the year a and year b.
The leap year conditions are as follows. However, 0 <a ≤ b <3,000. If there is no leap year in the given period, output "NA".
* The year is divisible by 4.
* However, a year divisible by 100 is not a leap year.
* However, a year divisible by 400 is a leap year.
Input
Given multiple datasets. The format of each dataset is as follows:
a b
Input ends when both a and b are 0. The number of datasets does not exceed 50.
Output
Print the year or NA for each dataset.
Insert one blank line between the datasets.
Example
Input
2001 2010
2005 2005
2001 2010
0 0
Output
2004
2008
NA
2004
2008
Submitted Solution:
```
for e in iter(input,'0 0'):
s,t=map(int,e.split())
u=[y for y in range(s+1,t)if y%4==0 and y%100!=0 or y%400==0]
if u:
for y in u:print(y)
else:print('NA')
print()
``` | instruction | 0 | 31,701 | 4 | 63,402 |
No | output | 1 | 31,701 | 4 | 63,403 |
Provide a correct Python 3 solution for this coding contest problem.
In order to pass the entrance examination tomorrow, Taro has to study for T more hours.
Fortunately, he can leap to World B where time passes X times as fast as it does in our world (World A).
While (X \times t) hours pass in World B, t hours pass in World A.
How many hours will pass in World A while Taro studies for T hours in World B?
Constraints
* All values in input are integers.
* 1 \leq T \leq 100
* 1 \leq X \leq 100
Input
Input is given from Standard Input in the following format:
T X
Output
Print the number of hours that will pass in World A.
The output will be regarded as correct when its absolute or relative error from the judge's output is at most 10^{-3}.
Examples
Input
8 3
Output
2.6666666667
Input
99 1
Output
99.0000000000
Input
1 100
Output
0.0100000000 | instruction | 0 | 32,303 | 4 | 64,606 |
"Correct Solution:
```
t,x=map(int,input().split(' '))
print(t/x)
``` | output | 1 | 32,303 | 4 | 64,607 |
Provide a correct Python 3 solution for this coding contest problem.
In order to pass the entrance examination tomorrow, Taro has to study for T more hours.
Fortunately, he can leap to World B where time passes X times as fast as it does in our world (World A).
While (X \times t) hours pass in World B, t hours pass in World A.
How many hours will pass in World A while Taro studies for T hours in World B?
Constraints
* All values in input are integers.
* 1 \leq T \leq 100
* 1 \leq X \leq 100
Input
Input is given from Standard Input in the following format:
T X
Output
Print the number of hours that will pass in World A.
The output will be regarded as correct when its absolute or relative error from the judge's output is at most 10^{-3}.
Examples
Input
8 3
Output
2.6666666667
Input
99 1
Output
99.0000000000
Input
1 100
Output
0.0100000000 | instruction | 0 | 32,304 | 4 | 64,608 |
"Correct Solution:
```
a = list(map(int, input().split()))
print(a[0]/a[1])
``` | output | 1 | 32,304 | 4 | 64,609 |
Provide a correct Python 3 solution for this coding contest problem.
In order to pass the entrance examination tomorrow, Taro has to study for T more hours.
Fortunately, he can leap to World B where time passes X times as fast as it does in our world (World A).
While (X \times t) hours pass in World B, t hours pass in World A.
How many hours will pass in World A while Taro studies for T hours in World B?
Constraints
* All values in input are integers.
* 1 \leq T \leq 100
* 1 \leq X \leq 100
Input
Input is given from Standard Input in the following format:
T X
Output
Print the number of hours that will pass in World A.
The output will be regarded as correct when its absolute or relative error from the judge's output is at most 10^{-3}.
Examples
Input
8 3
Output
2.6666666667
Input
99 1
Output
99.0000000000
Input
1 100
Output
0.0100000000 | instruction | 0 | 32,305 | 4 | 64,610 |
"Correct Solution:
```
a, b, = map(int,input().split())
print ( a / b )
``` | output | 1 | 32,305 | 4 | 64,611 |
Provide a correct Python 3 solution for this coding contest problem.
In order to pass the entrance examination tomorrow, Taro has to study for T more hours.
Fortunately, he can leap to World B where time passes X times as fast as it does in our world (World A).
While (X \times t) hours pass in World B, t hours pass in World A.
How many hours will pass in World A while Taro studies for T hours in World B?
Constraints
* All values in input are integers.
* 1 \leq T \leq 100
* 1 \leq X \leq 100
Input
Input is given from Standard Input in the following format:
T X
Output
Print the number of hours that will pass in World A.
The output will be regarded as correct when its absolute or relative error from the judge's output is at most 10^{-3}.
Examples
Input
8 3
Output
2.6666666667
Input
99 1
Output
99.0000000000
Input
1 100
Output
0.0100000000 | instruction | 0 | 32,306 | 4 | 64,612 |
"Correct Solution:
```
t,x=map(float,input().split())
print(round(t/x, 10))
``` | output | 1 | 32,306 | 4 | 64,613 |
Provide a correct Python 3 solution for this coding contest problem.
In order to pass the entrance examination tomorrow, Taro has to study for T more hours.
Fortunately, he can leap to World B where time passes X times as fast as it does in our world (World A).
While (X \times t) hours pass in World B, t hours pass in World A.
How many hours will pass in World A while Taro studies for T hours in World B?
Constraints
* All values in input are integers.
* 1 \leq T \leq 100
* 1 \leq X \leq 100
Input
Input is given from Standard Input in the following format:
T X
Output
Print the number of hours that will pass in World A.
The output will be regarded as correct when its absolute or relative error from the judge's output is at most 10^{-3}.
Examples
Input
8 3
Output
2.6666666667
Input
99 1
Output
99.0000000000
Input
1 100
Output
0.0100000000 | instruction | 0 | 32,307 | 4 | 64,614 |
"Correct Solution:
```
t,x = map(int, input().split(" "))
print(t/x)
``` | output | 1 | 32,307 | 4 | 64,615 |
Provide a correct Python 3 solution for this coding contest problem.
In order to pass the entrance examination tomorrow, Taro has to study for T more hours.
Fortunately, he can leap to World B where time passes X times as fast as it does in our world (World A).
While (X \times t) hours pass in World B, t hours pass in World A.
How many hours will pass in World A while Taro studies for T hours in World B?
Constraints
* All values in input are integers.
* 1 \leq T \leq 100
* 1 \leq X \leq 100
Input
Input is given from Standard Input in the following format:
T X
Output
Print the number of hours that will pass in World A.
The output will be regarded as correct when its absolute or relative error from the judge's output is at most 10^{-3}.
Examples
Input
8 3
Output
2.6666666667
Input
99 1
Output
99.0000000000
Input
1 100
Output
0.0100000000 | instruction | 0 | 32,308 | 4 | 64,616 |
"Correct Solution:
```
n,x = map(int,input().split())
print(n/x)
``` | output | 1 | 32,308 | 4 | 64,617 |
Provide a correct Python 3 solution for this coding contest problem.
In order to pass the entrance examination tomorrow, Taro has to study for T more hours.
Fortunately, he can leap to World B where time passes X times as fast as it does in our world (World A).
While (X \times t) hours pass in World B, t hours pass in World A.
How many hours will pass in World A while Taro studies for T hours in World B?
Constraints
* All values in input are integers.
* 1 \leq T \leq 100
* 1 \leq X \leq 100
Input
Input is given from Standard Input in the following format:
T X
Output
Print the number of hours that will pass in World A.
The output will be regarded as correct when its absolute or relative error from the judge's output is at most 10^{-3}.
Examples
Input
8 3
Output
2.6666666667
Input
99 1
Output
99.0000000000
Input
1 100
Output
0.0100000000 | instruction | 0 | 32,309 | 4 | 64,618 |
"Correct Solution:
```
t, x = list(map(float, input().split()))
print(t/x)
``` | output | 1 | 32,309 | 4 | 64,619 |
Provide a correct Python 3 solution for this coding contest problem.
In order to pass the entrance examination tomorrow, Taro has to study for T more hours.
Fortunately, he can leap to World B where time passes X times as fast as it does in our world (World A).
While (X \times t) hours pass in World B, t hours pass in World A.
How many hours will pass in World A while Taro studies for T hours in World B?
Constraints
* All values in input are integers.
* 1 \leq T \leq 100
* 1 \leq X \leq 100
Input
Input is given from Standard Input in the following format:
T X
Output
Print the number of hours that will pass in World A.
The output will be regarded as correct when its absolute or relative error from the judge's output is at most 10^{-3}.
Examples
Input
8 3
Output
2.6666666667
Input
99 1
Output
99.0000000000
Input
1 100
Output
0.0100000000 | instruction | 0 | 32,310 | 4 | 64,620 |
"Correct Solution:
```
t = list(map(int,input().split()))
print(t[0]/t[1])
``` | output | 1 | 32,310 | 4 | 64,621 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In order to pass the entrance examination tomorrow, Taro has to study for T more hours.
Fortunately, he can leap to World B where time passes X times as fast as it does in our world (World A).
While (X \times t) hours pass in World B, t hours pass in World A.
How many hours will pass in World A while Taro studies for T hours in World B?
Constraints
* All values in input are integers.
* 1 \leq T \leq 100
* 1 \leq X \leq 100
Input
Input is given from Standard Input in the following format:
T X
Output
Print the number of hours that will pass in World A.
The output will be regarded as correct when its absolute or relative error from the judge's output is at most 10^{-3}.
Examples
Input
8 3
Output
2.6666666667
Input
99 1
Output
99.0000000000
Input
1 100
Output
0.0100000000
Submitted Solution:
```
A, B = map(float, input().split())
print(A/B)
``` | instruction | 0 | 32,311 | 4 | 64,622 |
Yes | output | 1 | 32,311 | 4 | 64,623 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In order to pass the entrance examination tomorrow, Taro has to study for T more hours.
Fortunately, he can leap to World B where time passes X times as fast as it does in our world (World A).
While (X \times t) hours pass in World B, t hours pass in World A.
How many hours will pass in World A while Taro studies for T hours in World B?
Constraints
* All values in input are integers.
* 1 \leq T \leq 100
* 1 \leq X \leq 100
Input
Input is given from Standard Input in the following format:
T X
Output
Print the number of hours that will pass in World A.
The output will be regarded as correct when its absolute or relative error from the judge's output is at most 10^{-3}.
Examples
Input
8 3
Output
2.6666666667
Input
99 1
Output
99.0000000000
Input
1 100
Output
0.0100000000
Submitted Solution:
```
T,X = map(int,input().split())
C = T / X
print(C)
``` | instruction | 0 | 32,312 | 4 | 64,624 |
Yes | output | 1 | 32,312 | 4 | 64,625 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In order to pass the entrance examination tomorrow, Taro has to study for T more hours.
Fortunately, he can leap to World B where time passes X times as fast as it does in our world (World A).
While (X \times t) hours pass in World B, t hours pass in World A.
How many hours will pass in World A while Taro studies for T hours in World B?
Constraints
* All values in input are integers.
* 1 \leq T \leq 100
* 1 \leq X \leq 100
Input
Input is given from Standard Input in the following format:
T X
Output
Print the number of hours that will pass in World A.
The output will be regarded as correct when its absolute or relative error from the judge's output is at most 10^{-3}.
Examples
Input
8 3
Output
2.6666666667
Input
99 1
Output
99.0000000000
Input
1 100
Output
0.0100000000
Submitted Solution:
```
x,y=input().split(" ")
x=int(x)
y=int(y)
print(x/y)
``` | instruction | 0 | 32,313 | 4 | 64,626 |
Yes | output | 1 | 32,313 | 4 | 64,627 |
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