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Provide tags and a correct Python 3 solution for this coding contest problem. The main server of Gomble company received a log of one top-secret process, the name of which can't be revealed. The log was written in the following format: «[date:time]: message», where for each «[date:time]» value existed not more than 10 lines. All the files were encoded in a very complicated manner, and only one programmer — Alex — managed to decode them. The code was so complicated that Alex needed four weeks to decode it. Right after the decoding process was finished, all the files were deleted. But after the files deletion, Alex noticed that he saved the recordings in format «[time]: message». So, information about the dates was lost. However, as the lines were added into the log in chronological order, it's not difficult to say if the recordings could appear during one day or not. It is possible also to find the minimum amount of days during which the log was written. So, to make up for his mistake Alex has to find the minimum amount of days covered by the log. Note that Alex doesn't have to find the minimum amount of days between the beginning and the end of the logging, he has to find the minimum amount of dates in which records could be done. (See Sample test 2 for further clarifications). We should remind you that the process made not more than 10 recordings in a minute. Consider that a midnight belongs to coming day. Input The first input line contains number n (1 ≤ n ≤ 100). The following n lines contain recordings in format «[time]: message», where time is given in format «hh:mm x.m.». For hh two-digit numbers from 01 to 12 are used, for mm two-digit numbers from 00 to 59 are used, and x is either character «a» or character «p». A message is a non-empty sequence of Latin letters and/or spaces, it doesn't start or end with a space. The length of each message doesn't exceed 20. Output Output one number — the minimum amount of days covered by the log. Examples Input 5 [05:00 a.m.]: Server is started [05:00 a.m.]: Rescan initialized [01:13 p.m.]: Request processed [01:10 p.m.]: Request processed [11:40 p.m.]: Rescan completed Output 2 Input 3 [09:00 a.m.]: User logged in [08:00 a.m.]: User logged in [07:00 a.m.]: User logged in Output 3 Note Formally the 12-hour time format is described at: * http://en.wikipedia.org/wiki/12-hour_clock. The problem authors recommend you to look through these descriptions before you start with the problem.
instruction
0
55,047
4
110,094
Tags: implementation, strings Correct Solution: ``` def gt(a): hr = a[:2] mi = a[3:5] t = a[6] p = (int(hr)%12)*60+int(mi) if t == "p": return p + 100000 return p n = int(input()) s = [input()[1:8] for i in range(n)] cnt = 1 sc = 1 for i in range(1, n): if s[i] == s[i-1]: sc += 1 if sc == 11: sc = 1 cnt += 1 else: sc = 1 cnt += (gt(s[i-1]) > gt(s[i])) print(cnt) ```
output
1
55,047
4
110,095
Provide tags and a correct Python 3 solution for this coding contest problem. The main server of Gomble company received a log of one top-secret process, the name of which can't be revealed. The log was written in the following format: «[date:time]: message», where for each «[date:time]» value existed not more than 10 lines. All the files were encoded in a very complicated manner, and only one programmer — Alex — managed to decode them. The code was so complicated that Alex needed four weeks to decode it. Right after the decoding process was finished, all the files were deleted. But after the files deletion, Alex noticed that he saved the recordings in format «[time]: message». So, information about the dates was lost. However, as the lines were added into the log in chronological order, it's not difficult to say if the recordings could appear during one day or not. It is possible also to find the minimum amount of days during which the log was written. So, to make up for his mistake Alex has to find the minimum amount of days covered by the log. Note that Alex doesn't have to find the minimum amount of days between the beginning and the end of the logging, he has to find the minimum amount of dates in which records could be done. (See Sample test 2 for further clarifications). We should remind you that the process made not more than 10 recordings in a minute. Consider that a midnight belongs to coming day. Input The first input line contains number n (1 ≤ n ≤ 100). The following n lines contain recordings in format «[time]: message», where time is given in format «hh:mm x.m.». For hh two-digit numbers from 01 to 12 are used, for mm two-digit numbers from 00 to 59 are used, and x is either character «a» or character «p». A message is a non-empty sequence of Latin letters and/or spaces, it doesn't start or end with a space. The length of each message doesn't exceed 20. Output Output one number — the minimum amount of days covered by the log. Examples Input 5 [05:00 a.m.]: Server is started [05:00 a.m.]: Rescan initialized [01:13 p.m.]: Request processed [01:10 p.m.]: Request processed [11:40 p.m.]: Rescan completed Output 2 Input 3 [09:00 a.m.]: User logged in [08:00 a.m.]: User logged in [07:00 a.m.]: User logged in Output 3 Note Formally the 12-hour time format is described at: * http://en.wikipedia.org/wiki/12-hour_clock. The problem authors recommend you to look through these descriptions before you start with the problem.
instruction
0
55,048
4
110,096
Tags: implementation, strings Correct Solution: ``` #------------------------template--------------------------# import os import sys from math import * from collections import * # from fractions import * # from heapq import* from bisect import * from io import BytesIO, IOBase def vsInput(): sys.stdin = open('input.txt', 'r') sys.stdout = open('output.txt', 'w') BUFSIZE = 8192 class FastIO(IOBase): newlines = 0 def __init__(self, file): self._fd = file.fileno() self.buffer = BytesIO() self.writable = "x" in file.mode or "r" not in file.mode self.write = self.buffer.write if self.writable else None def read(self): while True: b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE)) if not b: break ptr = self.buffer.tell() self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr) self.newlines = 0 return self.buffer.read() def readline(self): while self.newlines == 0: b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE)) self.newlines = b.count(b"\n") + (not b) ptr = self.buffer.tell() self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr) self.newlines -= 1 return self.buffer.readline() def flush(self): if self.writable: os.write(self._fd, self.buffer.getvalue()) self.buffer.truncate(0), self.buffer.seek(0) class IOWrapper(IOBase): def __init__(self, file): self.buffer = FastIO(file) self.flush = self.buffer.flush self.writable = self.buffer.writable self.write = lambda s: self.buffer.write(s.encode("ascii")) self.read = lambda: self.buffer.read().decode("ascii") self.readline = lambda: self.buffer.readline().decode("ascii") sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout) input = lambda: sys.stdin.readline().rstrip("\r\n") ALPHA='abcdefghijklmnopqrstuvwxyz' M=10**9+7 EPS=1e-6 def Ceil(a,b): return a//b+int(a%b>0) def value():return tuple(map(int,input().split())) def array():return [int(i) for i in input().split()] def Int():return int(input()) def Str():return input() def arrayS():return [i for i in input().split()] #-------------------------code---------------------------# # vsInput() def To24Format(s): time,pm=s.split() h,sec=[int(i) for i in time.split(':')] h%=12 if(pm=='p.m.'): h+=12 return (h,sec) n=Int() a=[] for i in range(n): s=input() s=s[1:11] a.append(To24Format(s)) last=(inf,inf) day=0 c=0 # print(a) for i in a: if(i<last): day+=1 c=1 elif(i==last): c+=1 else: c=1 if(c>10): c=1 day+=1 last=i print(day) ```
output
1
55,048
4
110,097
Provide tags and a correct Python 3 solution for this coding contest problem. The main server of Gomble company received a log of one top-secret process, the name of which can't be revealed. The log was written in the following format: «[date:time]: message», where for each «[date:time]» value existed not more than 10 lines. All the files were encoded in a very complicated manner, and only one programmer — Alex — managed to decode them. The code was so complicated that Alex needed four weeks to decode it. Right after the decoding process was finished, all the files were deleted. But after the files deletion, Alex noticed that he saved the recordings in format «[time]: message». So, information about the dates was lost. However, as the lines were added into the log in chronological order, it's not difficult to say if the recordings could appear during one day or not. It is possible also to find the minimum amount of days during which the log was written. So, to make up for his mistake Alex has to find the minimum amount of days covered by the log. Note that Alex doesn't have to find the minimum amount of days between the beginning and the end of the logging, he has to find the minimum amount of dates in which records could be done. (See Sample test 2 for further clarifications). We should remind you that the process made not more than 10 recordings in a minute. Consider that a midnight belongs to coming day. Input The first input line contains number n (1 ≤ n ≤ 100). The following n lines contain recordings in format «[time]: message», where time is given in format «hh:mm x.m.». For hh two-digit numbers from 01 to 12 are used, for mm two-digit numbers from 00 to 59 are used, and x is either character «a» or character «p». A message is a non-empty sequence of Latin letters and/or spaces, it doesn't start or end with a space. The length of each message doesn't exceed 20. Output Output one number — the minimum amount of days covered by the log. Examples Input 5 [05:00 a.m.]: Server is started [05:00 a.m.]: Rescan initialized [01:13 p.m.]: Request processed [01:10 p.m.]: Request processed [11:40 p.m.]: Rescan completed Output 2 Input 3 [09:00 a.m.]: User logged in [08:00 a.m.]: User logged in [07:00 a.m.]: User logged in Output 3 Note Formally the 12-hour time format is described at: * http://en.wikipedia.org/wiki/12-hour_clock. The problem authors recommend you to look through these descriptions before you start with the problem.
instruction
0
55,049
4
110,098
Tags: implementation, strings Correct Solution: ``` a=[] for i in range(int(input())): b=input().split('.')[0][1:] h=int(b[:2]) m=int(b[3:5]) c=h*60+m if b[6]=='p': c+=720 if h==12: c-=720 a.append(c%1440) d=1 e=0 for i in range(len(a)): if i!=0 and a[i]!=a[i-1]: d+=(i-e-1)//10+int(a[i]<a[i-1]) e=i d+=(len(a)-e-1)//10 print(d) ```
output
1
55,049
4
110,099
Provide tags and a correct Python 3 solution for this coding contest problem. The main server of Gomble company received a log of one top-secret process, the name of which can't be revealed. The log was written in the following format: «[date:time]: message», where for each «[date:time]» value existed not more than 10 lines. All the files were encoded in a very complicated manner, and only one programmer — Alex — managed to decode them. The code was so complicated that Alex needed four weeks to decode it. Right after the decoding process was finished, all the files were deleted. But after the files deletion, Alex noticed that he saved the recordings in format «[time]: message». So, information about the dates was lost. However, as the lines were added into the log in chronological order, it's not difficult to say if the recordings could appear during one day or not. It is possible also to find the minimum amount of days during which the log was written. So, to make up for his mistake Alex has to find the minimum amount of days covered by the log. Note that Alex doesn't have to find the minimum amount of days between the beginning and the end of the logging, he has to find the minimum amount of dates in which records could be done. (See Sample test 2 for further clarifications). We should remind you that the process made not more than 10 recordings in a minute. Consider that a midnight belongs to coming day. Input The first input line contains number n (1 ≤ n ≤ 100). The following n lines contain recordings in format «[time]: message», where time is given in format «hh:mm x.m.». For hh two-digit numbers from 01 to 12 are used, for mm two-digit numbers from 00 to 59 are used, and x is either character «a» or character «p». A message is a non-empty sequence of Latin letters and/or spaces, it doesn't start or end with a space. The length of each message doesn't exceed 20. Output Output one number — the minimum amount of days covered by the log. Examples Input 5 [05:00 a.m.]: Server is started [05:00 a.m.]: Rescan initialized [01:13 p.m.]: Request processed [01:10 p.m.]: Request processed [11:40 p.m.]: Rescan completed Output 2 Input 3 [09:00 a.m.]: User logged in [08:00 a.m.]: User logged in [07:00 a.m.]: User logged in Output 3 Note Formally the 12-hour time format is described at: * http://en.wikipedia.org/wiki/12-hour_clock. The problem authors recommend you to look through these descriptions before you start with the problem.
instruction
0
55,050
4
110,100
Tags: implementation, strings Correct Solution: ``` n = int(input()) ans = 1 last = -1 po = 0 for i in range(n): s = input() h = int(s[1:3]) h %= 12 m = int(s[4:6]) if s[7] == 'p': h += 12 t = h * 60 + m if t == last and po == 10: po = 1 ans += 1 elif t == last: po += 1 elif t > last: po = 1 else: po = 1 ans += 1 last = t print(ans) ```
output
1
55,050
4
110,101
Provide tags and a correct Python 3 solution for this coding contest problem. The main server of Gomble company received a log of one top-secret process, the name of which can't be revealed. The log was written in the following format: «[date:time]: message», where for each «[date:time]» value existed not more than 10 lines. All the files were encoded in a very complicated manner, and only one programmer — Alex — managed to decode them. The code was so complicated that Alex needed four weeks to decode it. Right after the decoding process was finished, all the files were deleted. But after the files deletion, Alex noticed that he saved the recordings in format «[time]: message». So, information about the dates was lost. However, as the lines were added into the log in chronological order, it's not difficult to say if the recordings could appear during one day or not. It is possible also to find the minimum amount of days during which the log was written. So, to make up for his mistake Alex has to find the minimum amount of days covered by the log. Note that Alex doesn't have to find the minimum amount of days between the beginning and the end of the logging, he has to find the minimum amount of dates in which records could be done. (See Sample test 2 for further clarifications). We should remind you that the process made not more than 10 recordings in a minute. Consider that a midnight belongs to coming day. Input The first input line contains number n (1 ≤ n ≤ 100). The following n lines contain recordings in format «[time]: message», where time is given in format «hh:mm x.m.». For hh two-digit numbers from 01 to 12 are used, for mm two-digit numbers from 00 to 59 are used, and x is either character «a» or character «p». A message is a non-empty sequence of Latin letters and/or spaces, it doesn't start or end with a space. The length of each message doesn't exceed 20. Output Output one number — the minimum amount of days covered by the log. Examples Input 5 [05:00 a.m.]: Server is started [05:00 a.m.]: Rescan initialized [01:13 p.m.]: Request processed [01:10 p.m.]: Request processed [11:40 p.m.]: Rescan completed Output 2 Input 3 [09:00 a.m.]: User logged in [08:00 a.m.]: User logged in [07:00 a.m.]: User logged in Output 3 Note Formally the 12-hour time format is described at: * http://en.wikipedia.org/wiki/12-hour_clock. The problem authors recommend you to look through these descriptions before you start with the problem.
instruction
0
55,051
4
110,102
Tags: implementation, strings Correct Solution: ``` n = int(input()) ans = 0 prevHr = 26 prevMin = 26 cnt = 1 for _ in range(n): s = input()[1:10] hr = int(s[:2]) min = int(s[3:5]) pm = s[-3] == 'p' if((hr != 12 and pm) or (hr == 12 and not pm)): hr = (hr + 12) % 24 if(hr < prevHr or (hr == prevHr and min < prevMin)): ans += 1 if(prevHr == hr and prevMin == min): cnt += 1 else: cnt = 1 if(cnt > 10): ans += 1 cnt = 1 prevHr = hr prevMin = min print(ans) ```
output
1
55,051
4
110,103
Provide tags and a correct Python 3 solution for this coding contest problem. The main server of Gomble company received a log of one top-secret process, the name of which can't be revealed. The log was written in the following format: «[date:time]: message», where for each «[date:time]» value existed not more than 10 lines. All the files were encoded in a very complicated manner, and only one programmer — Alex — managed to decode them. The code was so complicated that Alex needed four weeks to decode it. Right after the decoding process was finished, all the files were deleted. But after the files deletion, Alex noticed that he saved the recordings in format «[time]: message». So, information about the dates was lost. However, as the lines were added into the log in chronological order, it's not difficult to say if the recordings could appear during one day or not. It is possible also to find the minimum amount of days during which the log was written. So, to make up for his mistake Alex has to find the minimum amount of days covered by the log. Note that Alex doesn't have to find the minimum amount of days between the beginning and the end of the logging, he has to find the minimum amount of dates in which records could be done. (See Sample test 2 for further clarifications). We should remind you that the process made not more than 10 recordings in a minute. Consider that a midnight belongs to coming day. Input The first input line contains number n (1 ≤ n ≤ 100). The following n lines contain recordings in format «[time]: message», where time is given in format «hh:mm x.m.». For hh two-digit numbers from 01 to 12 are used, for mm two-digit numbers from 00 to 59 are used, and x is either character «a» or character «p». A message is a non-empty sequence of Latin letters and/or spaces, it doesn't start or end with a space. The length of each message doesn't exceed 20. Output Output one number — the minimum amount of days covered by the log. Examples Input 5 [05:00 a.m.]: Server is started [05:00 a.m.]: Rescan initialized [01:13 p.m.]: Request processed [01:10 p.m.]: Request processed [11:40 p.m.]: Rescan completed Output 2 Input 3 [09:00 a.m.]: User logged in [08:00 a.m.]: User logged in [07:00 a.m.]: User logged in Output 3 Note Formally the 12-hour time format is described at: * http://en.wikipedia.org/wiki/12-hour_clock. The problem authors recommend you to look through these descriptions before you start with the problem.
instruction
0
55,052
4
110,104
Tags: implementation, strings Correct Solution: ``` from sys import stdin lines = int(stdin.readline()) days = 1 count = 0 h1 = 0 m1 = 0 for x in range(lines): log = stdin.readline().strip() hour = int(log[1:3]) if hour == 12: hour = 0 if log[7] =='p': hour += 12 minute = int(log[4:6]) #print(hour,minute) #print(h1,m1) if hour < h1 or hour == h1 and minute < m1: days += 1 count = 1 elif hour == h1 and minute == m1: count += 1 if count == 11: count = 1 days += 1 else: count = 1 h1 = hour m1 = minute print(days) ```
output
1
55,052
4
110,105
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The main server of Gomble company received a log of one top-secret process, the name of which can't be revealed. The log was written in the following format: «[date:time]: message», where for each «[date:time]» value existed not more than 10 lines. All the files were encoded in a very complicated manner, and only one programmer — Alex — managed to decode them. The code was so complicated that Alex needed four weeks to decode it. Right after the decoding process was finished, all the files were deleted. But after the files deletion, Alex noticed that he saved the recordings in format «[time]: message». So, information about the dates was lost. However, as the lines were added into the log in chronological order, it's not difficult to say if the recordings could appear during one day or not. It is possible also to find the minimum amount of days during which the log was written. So, to make up for his mistake Alex has to find the minimum amount of days covered by the log. Note that Alex doesn't have to find the minimum amount of days between the beginning and the end of the logging, he has to find the minimum amount of dates in which records could be done. (See Sample test 2 for further clarifications). We should remind you that the process made not more than 10 recordings in a minute. Consider that a midnight belongs to coming day. Input The first input line contains number n (1 ≤ n ≤ 100). The following n lines contain recordings in format «[time]: message», where time is given in format «hh:mm x.m.». For hh two-digit numbers from 01 to 12 are used, for mm two-digit numbers from 00 to 59 are used, and x is either character «a» or character «p». A message is a non-empty sequence of Latin letters and/or spaces, it doesn't start or end with a space. The length of each message doesn't exceed 20. Output Output one number — the minimum amount of days covered by the log. Examples Input 5 [05:00 a.m.]: Server is started [05:00 a.m.]: Rescan initialized [01:13 p.m.]: Request processed [01:10 p.m.]: Request processed [11:40 p.m.]: Rescan completed Output 2 Input 3 [09:00 a.m.]: User logged in [08:00 a.m.]: User logged in [07:00 a.m.]: User logged in Output 3 Note Formally the 12-hour time format is described at: * http://en.wikipedia.org/wiki/12-hour_clock. The problem authors recommend you to look through these descriptions before you start with the problem. Submitted Solution: ``` __author__ = 'Darren' def solve(): n = int(input()) last, days, consecutive = -1, 1, 1 for _i in range(n): record = input().split() time = record[0].split(':') current = 60 * int(time[0][1:]) + int(time[1]) if time[0][1:] == '12': if record[1][0] == 'a': current -= 720 else: pass elif record[1][0] == 'p': current += 720 if current > last: consecutive = 1 elif current == last: if consecutive < 10: consecutive += 1 else: days += 1 consecutive = 1 else: days += 1 consecutive = 1 last = current print(days) if __name__ == '__main__': solve() ```
instruction
0
55,053
4
110,106
Yes
output
1
55,053
4
110,107
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The main server of Gomble company received a log of one top-secret process, the name of which can't be revealed. The log was written in the following format: «[date:time]: message», where for each «[date:time]» value existed not more than 10 lines. All the files were encoded in a very complicated manner, and only one programmer — Alex — managed to decode them. The code was so complicated that Alex needed four weeks to decode it. Right after the decoding process was finished, all the files were deleted. But after the files deletion, Alex noticed that he saved the recordings in format «[time]: message». So, information about the dates was lost. However, as the lines were added into the log in chronological order, it's not difficult to say if the recordings could appear during one day or not. It is possible also to find the minimum amount of days during which the log was written. So, to make up for his mistake Alex has to find the minimum amount of days covered by the log. Note that Alex doesn't have to find the minimum amount of days between the beginning and the end of the logging, he has to find the minimum amount of dates in which records could be done. (See Sample test 2 for further clarifications). We should remind you that the process made not more than 10 recordings in a minute. Consider that a midnight belongs to coming day. Input The first input line contains number n (1 ≤ n ≤ 100). The following n lines contain recordings in format «[time]: message», where time is given in format «hh:mm x.m.». For hh two-digit numbers from 01 to 12 are used, for mm two-digit numbers from 00 to 59 are used, and x is either character «a» or character «p». A message is a non-empty sequence of Latin letters and/or spaces, it doesn't start or end with a space. The length of each message doesn't exceed 20. Output Output one number — the minimum amount of days covered by the log. Examples Input 5 [05:00 a.m.]: Server is started [05:00 a.m.]: Rescan initialized [01:13 p.m.]: Request processed [01:10 p.m.]: Request processed [11:40 p.m.]: Rescan completed Output 2 Input 3 [09:00 a.m.]: User logged in [08:00 a.m.]: User logged in [07:00 a.m.]: User logged in Output 3 Note Formally the 12-hour time format is described at: * http://en.wikipedia.org/wiki/12-hour_clock. The problem authors recommend you to look through these descriptions before you start with the problem. Submitted Solution: ``` n = int(input()) prev_s = '100000' prev_z = '{' a = [] for i in range(n): s = input() h = int(s[1:3]) m = int(s[4:6]) z = s[7] if(h == 12 and z == 'a'): h = 0 if(h != 12 and z == 'p'): h += 12 t = [h,m] a.append(t) ans = 1 c = 1 for i in range(len(a) - 1): if(a[i] == a[i + 1]): c += 1 if(c > 10): ans += 1 c = 1 elif(a[i] < a[i + 1]): c = 1 if(a[i] > a[i + 1]): ans += 1 c = 1 print(ans) ```
instruction
0
55,054
4
110,108
Yes
output
1
55,054
4
110,109
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The main server of Gomble company received a log of one top-secret process, the name of which can't be revealed. The log was written in the following format: «[date:time]: message», where for each «[date:time]» value existed not more than 10 lines. All the files were encoded in a very complicated manner, and only one programmer — Alex — managed to decode them. The code was so complicated that Alex needed four weeks to decode it. Right after the decoding process was finished, all the files were deleted. But after the files deletion, Alex noticed that he saved the recordings in format «[time]: message». So, information about the dates was lost. However, as the lines were added into the log in chronological order, it's not difficult to say if the recordings could appear during one day or not. It is possible also to find the minimum amount of days during which the log was written. So, to make up for his mistake Alex has to find the minimum amount of days covered by the log. Note that Alex doesn't have to find the minimum amount of days between the beginning and the end of the logging, he has to find the minimum amount of dates in which records could be done. (See Sample test 2 for further clarifications). We should remind you that the process made not more than 10 recordings in a minute. Consider that a midnight belongs to coming day. Input The first input line contains number n (1 ≤ n ≤ 100). The following n lines contain recordings in format «[time]: message», where time is given in format «hh:mm x.m.». For hh two-digit numbers from 01 to 12 are used, for mm two-digit numbers from 00 to 59 are used, and x is either character «a» or character «p». A message is a non-empty sequence of Latin letters and/or spaces, it doesn't start or end with a space. The length of each message doesn't exceed 20. Output Output one number — the minimum amount of days covered by the log. Examples Input 5 [05:00 a.m.]: Server is started [05:00 a.m.]: Rescan initialized [01:13 p.m.]: Request processed [01:10 p.m.]: Request processed [11:40 p.m.]: Rescan completed Output 2 Input 3 [09:00 a.m.]: User logged in [08:00 a.m.]: User logged in [07:00 a.m.]: User logged in Output 3 Note Formally the 12-hour time format is described at: * http://en.wikipedia.org/wiki/12-hour_clock. The problem authors recommend you to look through these descriptions before you start with the problem. Submitted Solution: ``` p,c,v=1440,0,0 for i in range(int(input())): s=input() t=60*(int(s[1:3])%12)+int(s[4:6]) if s[7]=="p": t+=720 if t<p: c=1 v+=1 elif t==p: c+=1 if c==11: c=1 v+=1 else: c=1 p=t print(v) ```
instruction
0
55,055
4
110,110
Yes
output
1
55,055
4
110,111
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The main server of Gomble company received a log of one top-secret process, the name of which can't be revealed. The log was written in the following format: «[date:time]: message», where for each «[date:time]» value existed not more than 10 lines. All the files were encoded in a very complicated manner, and only one programmer — Alex — managed to decode them. The code was so complicated that Alex needed four weeks to decode it. Right after the decoding process was finished, all the files were deleted. But after the files deletion, Alex noticed that he saved the recordings in format «[time]: message». So, information about the dates was lost. However, as the lines were added into the log in chronological order, it's not difficult to say if the recordings could appear during one day or not. It is possible also to find the minimum amount of days during which the log was written. So, to make up for his mistake Alex has to find the minimum amount of days covered by the log. Note that Alex doesn't have to find the minimum amount of days between the beginning and the end of the logging, he has to find the minimum amount of dates in which records could be done. (See Sample test 2 for further clarifications). We should remind you that the process made not more than 10 recordings in a minute. Consider that a midnight belongs to coming day. Input The first input line contains number n (1 ≤ n ≤ 100). The following n lines contain recordings in format «[time]: message», where time is given in format «hh:mm x.m.». For hh two-digit numbers from 01 to 12 are used, for mm two-digit numbers from 00 to 59 are used, and x is either character «a» or character «p». A message is a non-empty sequence of Latin letters and/or spaces, it doesn't start or end with a space. The length of each message doesn't exceed 20. Output Output one number — the minimum amount of days covered by the log. Examples Input 5 [05:00 a.m.]: Server is started [05:00 a.m.]: Rescan initialized [01:13 p.m.]: Request processed [01:10 p.m.]: Request processed [11:40 p.m.]: Rescan completed Output 2 Input 3 [09:00 a.m.]: User logged in [08:00 a.m.]: User logged in [07:00 a.m.]: User logged in Output 3 Note Formally the 12-hour time format is described at: * http://en.wikipedia.org/wiki/12-hour_clock. The problem authors recommend you to look through these descriptions before you start with the problem. Submitted Solution: ``` i = int(input()) L = [] for i in range(0,i): L.append(input()[1:8]) H = [12,1,2,3,4,5,6,7,8,9,10,11] d = 1 t = '12:00' h = 'a' oc = 1 for i in L: if i[6] == h: if H.index(int(i[:2])) < H.index(int(t[:2])): d += 1 t = i[:5] oc = 1 elif H.index(int(i[:2])) == H.index(int(t[:2])): if int(i[3:5]) < int(t[3:5]): d += 1 t = i[:5] oc = 1 elif int(i[3:5]) == int(t[3:5]): if oc >= 10: d += 1 oc = 1 else: oc += 1 else: t = i[:5] oc = 1 else: t = i[:5] oc = 1 else: if h == 'a': h = 'p' t = i[:5] oc = 1 else: h = 'a' d += 1 t = i[:5] oc = 1 print(d) ```
instruction
0
55,056
4
110,112
Yes
output
1
55,056
4
110,113
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The main server of Gomble company received a log of one top-secret process, the name of which can't be revealed. The log was written in the following format: «[date:time]: message», where for each «[date:time]» value existed not more than 10 lines. All the files were encoded in a very complicated manner, and only one programmer — Alex — managed to decode them. The code was so complicated that Alex needed four weeks to decode it. Right after the decoding process was finished, all the files were deleted. But after the files deletion, Alex noticed that he saved the recordings in format «[time]: message». So, information about the dates was lost. However, as the lines were added into the log in chronological order, it's not difficult to say if the recordings could appear during one day or not. It is possible also to find the minimum amount of days during which the log was written. So, to make up for his mistake Alex has to find the minimum amount of days covered by the log. Note that Alex doesn't have to find the minimum amount of days between the beginning and the end of the logging, he has to find the minimum amount of dates in which records could be done. (See Sample test 2 for further clarifications). We should remind you that the process made not more than 10 recordings in a minute. Consider that a midnight belongs to coming day. Input The first input line contains number n (1 ≤ n ≤ 100). The following n lines contain recordings in format «[time]: message», where time is given in format «hh:mm x.m.». For hh two-digit numbers from 01 to 12 are used, for mm two-digit numbers from 00 to 59 are used, and x is either character «a» or character «p». A message is a non-empty sequence of Latin letters and/or spaces, it doesn't start or end with a space. The length of each message doesn't exceed 20. Output Output one number — the minimum amount of days covered by the log. Examples Input 5 [05:00 a.m.]: Server is started [05:00 a.m.]: Rescan initialized [01:13 p.m.]: Request processed [01:10 p.m.]: Request processed [11:40 p.m.]: Rescan completed Output 2 Input 3 [09:00 a.m.]: User logged in [08:00 a.m.]: User logged in [07:00 a.m.]: User logged in Output 3 Note Formally the 12-hour time format is described at: * http://en.wikipedia.org/wiki/12-hour_clock. The problem authors recommend you to look through these descriptions before you start with the problem. Submitted Solution: ``` def gt(a): hr = a[:2] mi = a[3:5] t = a[6] p = (int(hr)%12)*60+int(mi) if t == "p": return p + 100000 return p n = int(input()) s = [input()[1:8] for i in range(n)] cnt = 1 for i in range(n-1): cnt += (gt(s[i]) > gt(s[i+1])) print(cnt) ```
instruction
0
55,057
4
110,114
No
output
1
55,057
4
110,115
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The main server of Gomble company received a log of one top-secret process, the name of which can't be revealed. The log was written in the following format: «[date:time]: message», where for each «[date:time]» value existed not more than 10 lines. All the files were encoded in a very complicated manner, and only one programmer — Alex — managed to decode them. The code was so complicated that Alex needed four weeks to decode it. Right after the decoding process was finished, all the files were deleted. But after the files deletion, Alex noticed that he saved the recordings in format «[time]: message». So, information about the dates was lost. However, as the lines were added into the log in chronological order, it's not difficult to say if the recordings could appear during one day or not. It is possible also to find the minimum amount of days during which the log was written. So, to make up for his mistake Alex has to find the minimum amount of days covered by the log. Note that Alex doesn't have to find the minimum amount of days between the beginning and the end of the logging, he has to find the minimum amount of dates in which records could be done. (See Sample test 2 for further clarifications). We should remind you that the process made not more than 10 recordings in a minute. Consider that a midnight belongs to coming day. Input The first input line contains number n (1 ≤ n ≤ 100). The following n lines contain recordings in format «[time]: message», where time is given in format «hh:mm x.m.». For hh two-digit numbers from 01 to 12 are used, for mm two-digit numbers from 00 to 59 are used, and x is either character «a» or character «p». A message is a non-empty sequence of Latin letters and/or spaces, it doesn't start or end with a space. The length of each message doesn't exceed 20. Output Output one number — the minimum amount of days covered by the log. Examples Input 5 [05:00 a.m.]: Server is started [05:00 a.m.]: Rescan initialized [01:13 p.m.]: Request processed [01:10 p.m.]: Request processed [11:40 p.m.]: Rescan completed Output 2 Input 3 [09:00 a.m.]: User logged in [08:00 a.m.]: User logged in [07:00 a.m.]: User logged in Output 3 Note Formally the 12-hour time format is described at: * http://en.wikipedia.org/wiki/12-hour_clock. The problem authors recommend you to look through these descriptions before you start with the problem. Submitted Solution: ``` import sys from array import array # noqa: F401 from itertools import groupby def input(): return sys.stdin.buffer.readline().decode('utf-8') n = int(input()) a = [] for line in (input().rstrip() for _ in range(n)): h, m = int(line[1:3]), int(line[4:6]) ap = line[7] if h == 12: m += (720 if ap == 'a' else 0) else: m += h * 60 + (720 if ap == 'p' else 0) a.append(m) prev = -1 ans = 1 for key, val in groupby(a): if prev > key: ans += 1 cnt = len(list(val)) if cnt > 10: ans += (cnt - 1) // 10 prev = key print(ans) ```
instruction
0
55,058
4
110,116
No
output
1
55,058
4
110,117
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The main server of Gomble company received a log of one top-secret process, the name of which can't be revealed. The log was written in the following format: «[date:time]: message», where for each «[date:time]» value existed not more than 10 lines. All the files were encoded in a very complicated manner, and only one programmer — Alex — managed to decode them. The code was so complicated that Alex needed four weeks to decode it. Right after the decoding process was finished, all the files were deleted. But after the files deletion, Alex noticed that he saved the recordings in format «[time]: message». So, information about the dates was lost. However, as the lines were added into the log in chronological order, it's not difficult to say if the recordings could appear during one day or not. It is possible also to find the minimum amount of days during which the log was written. So, to make up for his mistake Alex has to find the minimum amount of days covered by the log. Note that Alex doesn't have to find the minimum amount of days between the beginning and the end of the logging, he has to find the minimum amount of dates in which records could be done. (See Sample test 2 for further clarifications). We should remind you that the process made not more than 10 recordings in a minute. Consider that a midnight belongs to coming day. Input The first input line contains number n (1 ≤ n ≤ 100). The following n lines contain recordings in format «[time]: message», where time is given in format «hh:mm x.m.». For hh two-digit numbers from 01 to 12 are used, for mm two-digit numbers from 00 to 59 are used, and x is either character «a» or character «p». A message is a non-empty sequence of Latin letters and/or spaces, it doesn't start or end with a space. The length of each message doesn't exceed 20. Output Output one number — the minimum amount of days covered by the log. Examples Input 5 [05:00 a.m.]: Server is started [05:00 a.m.]: Rescan initialized [01:13 p.m.]: Request processed [01:10 p.m.]: Request processed [11:40 p.m.]: Rescan completed Output 2 Input 3 [09:00 a.m.]: User logged in [08:00 a.m.]: User logged in [07:00 a.m.]: User logged in Output 3 Note Formally the 12-hour time format is described at: * http://en.wikipedia.org/wiki/12-hour_clock. The problem authors recommend you to look through these descriptions before you start with the problem. Submitted Solution: ``` n = int(input()) prev_s = '-1' prev_z = 'a' ans = 0 for _ in range(n): s = input() h = s[1:3] + s[4:6] z = s[7] if(h > prev_s and z > prev_z): pass else: ans += 1 print(ans) ```
instruction
0
55,059
4
110,118
No
output
1
55,059
4
110,119
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The main server of Gomble company received a log of one top-secret process, the name of which can't be revealed. The log was written in the following format: «[date:time]: message», where for each «[date:time]» value existed not more than 10 lines. All the files were encoded in a very complicated manner, and only one programmer — Alex — managed to decode them. The code was so complicated that Alex needed four weeks to decode it. Right after the decoding process was finished, all the files were deleted. But after the files deletion, Alex noticed that he saved the recordings in format «[time]: message». So, information about the dates was lost. However, as the lines were added into the log in chronological order, it's not difficult to say if the recordings could appear during one day or not. It is possible also to find the minimum amount of days during which the log was written. So, to make up for his mistake Alex has to find the minimum amount of days covered by the log. Note that Alex doesn't have to find the minimum amount of days between the beginning and the end of the logging, he has to find the minimum amount of dates in which records could be done. (See Sample test 2 for further clarifications). We should remind you that the process made not more than 10 recordings in a minute. Consider that a midnight belongs to coming day. Input The first input line contains number n (1 ≤ n ≤ 100). The following n lines contain recordings in format «[time]: message», where time is given in format «hh:mm x.m.». For hh two-digit numbers from 01 to 12 are used, for mm two-digit numbers from 00 to 59 are used, and x is either character «a» or character «p». A message is a non-empty sequence of Latin letters and/or spaces, it doesn't start or end with a space. The length of each message doesn't exceed 20. Output Output one number — the minimum amount of days covered by the log. Examples Input 5 [05:00 a.m.]: Server is started [05:00 a.m.]: Rescan initialized [01:13 p.m.]: Request processed [01:10 p.m.]: Request processed [11:40 p.m.]: Rescan completed Output 2 Input 3 [09:00 a.m.]: User logged in [08:00 a.m.]: User logged in [07:00 a.m.]: User logged in Output 3 Note Formally the 12-hour time format is described at: * http://en.wikipedia.org/wiki/12-hour_clock. The problem authors recommend you to look through these descriptions before you start with the problem. Submitted Solution: ``` import sys from array import array # noqa: F401 from itertools import groupby def input(): return sys.stdin.buffer.readline().decode('utf-8') n = int(input()) a = [] for line in (input().rstrip() for _ in range(n)): h, m = int(line[1:3]), int(line[4:6]) ap = line[7] if h == 12: m += (720 * 12 if ap == 'a' else 0) else: m += h * 60 + (720 if ap == 'p' else 0) a.append(m) prev = -1 ans = 1 for key, val in groupby(a): if prev > key: ans += 1 cnt = len(list(val)) if cnt > 10: ans += (cnt - 1) // 10 prev = key print(ans) ```
instruction
0
55,060
4
110,120
No
output
1
55,060
4
110,121
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. ZS the Coder has recently found an interesting concept called the Birthday Paradox. It states that given a random set of 23 people, there is around 50% chance that some two of them share the same birthday. ZS the Coder finds this very interesting, and decides to test this with the inhabitants of Udayland. In Udayland, there are 2n days in a year. ZS the Coder wants to interview k people from Udayland, each of them has birthday in one of 2n days (each day with equal probability). He is interested in the probability of at least two of them have the birthday at the same day. ZS the Coder knows that the answer can be written as an irreducible fraction <image>. He wants to find the values of A and B (he does not like to deal with floating point numbers). Can you help him? Input The first and only line of the input contains two integers n and k (1 ≤ n ≤ 1018, 2 ≤ k ≤ 1018), meaning that there are 2n days in a year and that ZS the Coder wants to interview exactly k people. Output If the probability of at least two k people having the same birthday in 2n days long year equals <image> (A ≥ 0, B ≥ 1, <image>), print the A and B in a single line. Since these numbers may be too large, print them modulo 106 + 3. Note that A and B must be coprime before their remainders modulo 106 + 3 are taken. Examples Input 3 2 Output 1 8 Input 1 3 Output 1 1 Input 4 3 Output 23 128 Note In the first sample case, there are 23 = 8 days in Udayland. The probability that 2 people have the same birthday among 2 people is clearly <image>, so A = 1, B = 8. In the second sample case, there are only 21 = 2 days in Udayland, but there are 3 people, so it is guaranteed that two of them have the same birthday. Thus, the probability is 1 and A = B = 1. Submitted Solution: ``` n, k = map(int, input().split()) if n <= 100 and k > (2 ** n): print(1, 1) exit(0) MOD = 1000 * 1000 + 3 INV2 = (MOD + 1) // 2 def add(x, y): return (x + y) % MOD def sub(x, y): rez = x - y rez %= MOD rez += MOD rez %= MOD return rez def mult(x, y): return (x * y) % MOD def binpow(x, y): if x == 1 or y == 0: return 1 if x == 0: return 0 rez = binpow(x, y//2) rez = mult(rez, rez) if y % 2 == 1: rez = mult(rez, x) return rez A = n * k B = n temp = k - 1 while temp >= 2: B += temp // 2 temp //= 2 G = min(A, B) # print('G=', G) m = binpow(2, n) # print('m=', m) P = 1 for i in range(k): P = mult(P, sub(m, i)) if P == 0: break P = mult(P, binpow(INV2, G)) Q = binpow(m, k) Q = mult(Q, binpow(INV2, G)) P = sub(Q, P) print(P, Q) ```
instruction
0
55,293
4
110,586
Yes
output
1
55,293
4
110,587
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. ZS the Coder has recently found an interesting concept called the Birthday Paradox. It states that given a random set of 23 people, there is around 50% chance that some two of them share the same birthday. ZS the Coder finds this very interesting, and decides to test this with the inhabitants of Udayland. In Udayland, there are 2n days in a year. ZS the Coder wants to interview k people from Udayland, each of them has birthday in one of 2n days (each day with equal probability). He is interested in the probability of at least two of them have the birthday at the same day. ZS the Coder knows that the answer can be written as an irreducible fraction <image>. He wants to find the values of A and B (he does not like to deal with floating point numbers). Can you help him? Input The first and only line of the input contains two integers n and k (1 ≤ n ≤ 1018, 2 ≤ k ≤ 1018), meaning that there are 2n days in a year and that ZS the Coder wants to interview exactly k people. Output If the probability of at least two k people having the same birthday in 2n days long year equals <image> (A ≥ 0, B ≥ 1, <image>), print the A and B in a single line. Since these numbers may be too large, print them modulo 106 + 3. Note that A and B must be coprime before their remainders modulo 106 + 3 are taken. Examples Input 3 2 Output 1 8 Input 1 3 Output 1 1 Input 4 3 Output 23 128 Note In the first sample case, there are 23 = 8 days in Udayland. The probability that 2 people have the same birthday among 2 people is clearly <image>, so A = 1, B = 8. In the second sample case, there are only 21 = 2 days in Udayland, but there are 3 people, so it is guaranteed that two of them have the same birthday. Thus, the probability is 1 and A = B = 1. Submitted Solution: ``` n, k = [int(x) for x in input().split()] if 2**(min(n,62)) < k: print("1 1") exit(0) mod = int(1000003) x=n mult=2 while mult<=k-1: x+=(k-1)//mult mult*=2 def modpow(x,n,m): mult=x%m a=1 ans=1 while a<=n: if a&n: ans*=mult ans%=m mult*=mult mult%=m a*=2 return ans #print(x) denom = modpow(2,n*k-x,mod) num = modpow(2,n*k-x,mod) if(k<mod): s=1 for i in range(1,k): val=i y=0 while not val%2: val//=2 y+=1 #print(n-y) s*=modpow(2,(n-y)%(mod-1),mod)-val s%=mod #print(s) num-=s num%=mod if num<0: s+=mod print(num,denom) ```
instruction
0
55,294
4
110,588
Yes
output
1
55,294
4
110,589
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. ZS the Coder has recently found an interesting concept called the Birthday Paradox. It states that given a random set of 23 people, there is around 50% chance that some two of them share the same birthday. ZS the Coder finds this very interesting, and decides to test this with the inhabitants of Udayland. In Udayland, there are 2n days in a year. ZS the Coder wants to interview k people from Udayland, each of them has birthday in one of 2n days (each day with equal probability). He is interested in the probability of at least two of them have the birthday at the same day. ZS the Coder knows that the answer can be written as an irreducible fraction <image>. He wants to find the values of A and B (he does not like to deal with floating point numbers). Can you help him? Input The first and only line of the input contains two integers n and k (1 ≤ n ≤ 1018, 2 ≤ k ≤ 1018), meaning that there are 2n days in a year and that ZS the Coder wants to interview exactly k people. Output If the probability of at least two k people having the same birthday in 2n days long year equals <image> (A ≥ 0, B ≥ 1, <image>), print the A and B in a single line. Since these numbers may be too large, print them modulo 106 + 3. Note that A and B must be coprime before their remainders modulo 106 + 3 are taken. Examples Input 3 2 Output 1 8 Input 1 3 Output 1 1 Input 4 3 Output 23 128 Note In the first sample case, there are 23 = 8 days in Udayland. The probability that 2 people have the same birthday among 2 people is clearly <image>, so A = 1, B = 8. In the second sample case, there are only 21 = 2 days in Udayland, but there are 3 people, so it is guaranteed that two of them have the same birthday. Thus, the probability is 1 and A = B = 1. Submitted Solution: ``` from fractions import gcd def factorial(n): if n <= 0: return 1 else: return n * factorial(n-1) n, k = map(int, input().split()) if k * (k - 1) // 2 >= n: print("1 1") exit(0) znam = ((2 ** n) ** k) * factorial(2 ** n - k) chis = znam - factorial(2 ** n) g = gcd(chis, znam) chis //= g znam //= g znam %= (10 ** 9 + 7) chis %= (10**9 + 7) print(chis, znam) ```
instruction
0
55,295
4
110,590
No
output
1
55,295
4
110,591
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. ZS the Coder has recently found an interesting concept called the Birthday Paradox. It states that given a random set of 23 people, there is around 50% chance that some two of them share the same birthday. ZS the Coder finds this very interesting, and decides to test this with the inhabitants of Udayland. In Udayland, there are 2n days in a year. ZS the Coder wants to interview k people from Udayland, each of them has birthday in one of 2n days (each day with equal probability). He is interested in the probability of at least two of them have the birthday at the same day. ZS the Coder knows that the answer can be written as an irreducible fraction <image>. He wants to find the values of A and B (he does not like to deal with floating point numbers). Can you help him? Input The first and only line of the input contains two integers n and k (1 ≤ n ≤ 1018, 2 ≤ k ≤ 1018), meaning that there are 2n days in a year and that ZS the Coder wants to interview exactly k people. Output If the probability of at least two k people having the same birthday in 2n days long year equals <image> (A ≥ 0, B ≥ 1, <image>), print the A and B in a single line. Since these numbers may be too large, print them modulo 106 + 3. Note that A and B must be coprime before their remainders modulo 106 + 3 are taken. Examples Input 3 2 Output 1 8 Input 1 3 Output 1 1 Input 4 3 Output 23 128 Note In the first sample case, there are 23 = 8 days in Udayland. The probability that 2 people have the same birthday among 2 people is clearly <image>, so A = 1, B = 8. In the second sample case, there are only 21 = 2 days in Udayland, but there are 3 people, so it is guaranteed that two of them have the same birthday. Thus, the probability is 1 and A = B = 1. Submitted Solution: ``` import math n, k = [int(x) for x in input().split()] if n<70 and k>=2**n: print(1,1) exit(0) mod = int(1e6)+3 def fastpow(a,b): t, ans = a, 1 while b: if(b&1): ans = ans*t%mod t = t*t %mod b>>=1 return ans t=k-1 cnt=0 while t: cnt += t>>1 t>>=1 x=0 t=fastpow(2,n) if k<mod: x=1 for i in range(1,k): x = x*(t-i)%mod y=fastpow(2,n*(k-1)) # print(x,y) # print("cnt =",cnt) inv = fastpow(2,mod-2) inv = fastpow(inv,cnt) x=x*inv%mod y=y*inv%mod x=(y-x+mod)%mod y=(mod+y)%mod print(x,y) ```
instruction
0
55,296
4
110,592
No
output
1
55,296
4
110,593
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. ZS the Coder has recently found an interesting concept called the Birthday Paradox. It states that given a random set of 23 people, there is around 50% chance that some two of them share the same birthday. ZS the Coder finds this very interesting, and decides to test this with the inhabitants of Udayland. In Udayland, there are 2n days in a year. ZS the Coder wants to interview k people from Udayland, each of them has birthday in one of 2n days (each day with equal probability). He is interested in the probability of at least two of them have the birthday at the same day. ZS the Coder knows that the answer can be written as an irreducible fraction <image>. He wants to find the values of A and B (he does not like to deal with floating point numbers). Can you help him? Input The first and only line of the input contains two integers n and k (1 ≤ n ≤ 1018, 2 ≤ k ≤ 1018), meaning that there are 2n days in a year and that ZS the Coder wants to interview exactly k people. Output If the probability of at least two k people having the same birthday in 2n days long year equals <image> (A ≥ 0, B ≥ 1, <image>), print the A and B in a single line. Since these numbers may be too large, print them modulo 106 + 3. Note that A and B must be coprime before their remainders modulo 106 + 3 are taken. Examples Input 3 2 Output 1 8 Input 1 3 Output 1 1 Input 4 3 Output 23 128 Note In the first sample case, there are 23 = 8 days in Udayland. The probability that 2 people have the same birthday among 2 people is clearly <image>, so A = 1, B = 8. In the second sample case, there are only 21 = 2 days in Udayland, but there are 3 people, so it is guaranteed that two of them have the same birthday. Thus, the probability is 1 and A = B = 1. Submitted Solution: ``` n, k = map(int, input().split()) MOD = 100003 K = k - 1 max_deg = 0 while K > 0: max_deg += K // 2 K //= 2 den_deg = n * (k-1) - max_deg kk = 1 for i in range(n): kk *= 2 if kk >= k: break else: print(1, 1) exit(0) numerator = 1 two_p_n = pow(2, n, MOD) for i in range(1, min(k, MOD + 1)): numerator *= (two_p_n - i + MOD) % MOD numerator %= MOD rev = (MOD + 1) // 2 numerator *= pow(rev, max_deg, MOD) numerator %= MOD denumerator = pow(2, den_deg, MOD) numerator = (denumerator + MOD - numerator) % MOD print(numerator, denumerator) ```
instruction
0
55,297
4
110,594
No
output
1
55,297
4
110,595
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. ZS the Coder has recently found an interesting concept called the Birthday Paradox. It states that given a random set of 23 people, there is around 50% chance that some two of them share the same birthday. ZS the Coder finds this very interesting, and decides to test this with the inhabitants of Udayland. In Udayland, there are 2n days in a year. ZS the Coder wants to interview k people from Udayland, each of them has birthday in one of 2n days (each day with equal probability). He is interested in the probability of at least two of them have the birthday at the same day. ZS the Coder knows that the answer can be written as an irreducible fraction <image>. He wants to find the values of A and B (he does not like to deal with floating point numbers). Can you help him? Input The first and only line of the input contains two integers n and k (1 ≤ n ≤ 1018, 2 ≤ k ≤ 1018), meaning that there are 2n days in a year and that ZS the Coder wants to interview exactly k people. Output If the probability of at least two k people having the same birthday in 2n days long year equals <image> (A ≥ 0, B ≥ 1, <image>), print the A and B in a single line. Since these numbers may be too large, print them modulo 106 + 3. Note that A and B must be coprime before their remainders modulo 106 + 3 are taken. Examples Input 3 2 Output 1 8 Input 1 3 Output 1 1 Input 4 3 Output 23 128 Note In the first sample case, there are 23 = 8 days in Udayland. The probability that 2 people have the same birthday among 2 people is clearly <image>, so A = 1, B = 8. In the second sample case, there are only 21 = 2 days in Udayland, but there are 3 people, so it is guaranteed that two of them have the same birthday. Thus, the probability is 1 and A = B = 1. Submitted Solution: ``` n, k = [int(x) for x in input().split()] if 2**(min(n,62)) < k: print("1 1") exit(0) mod = int(1000003) x=n mult=2 while mult<=k-1: x+=(k-1)//mult mult*=2 def modpow(x,n,m): mult=x%m a=1 ans=1 while a<=n: if a&n: ans*=mult ans%=m mult*=mult mult%=m a*=2 return ans #print(x) denom = modpow(2,n*k-x,mod) num = modpow(2,n*k-x,mod) if(k<mod): s=1 for i in range(1,k): val=i y=0 while not val%2: val//=2 y+=1 #print(n-y) s*=modpow(2,(n-y)%(mod-1),mod)-val s%=mod #print(s) num-=s if num<0: s+=mod print(num,denom) ```
instruction
0
55,298
4
110,596
No
output
1
55,298
4
110,597
Provide a correct Python 3 solution for this coding contest problem. Alice and Bob are controlling a robot. They each have one switch that controls the robot. Alice started holding down her button A second after the start-up of the robot, and released her button B second after the start-up. Bob started holding down his button C second after the start-up, and released his button D second after the start-up. For how many seconds both Alice and Bob were holding down their buttons? Constraints * 0≤A<B≤100 * 0≤C<D≤100 * All input values are integers. Input Input is given from Standard Input in the following format: A B C D Output Print the length of the duration (in seconds) in which both Alice and Bob were holding down their buttons. Examples Input 0 75 25 100 Output 50 Input 0 33 66 99 Output 0 Input 10 90 20 80 Output 60
instruction
0
55,486
4
110,972
"Correct Solution: ``` a,b,c,d=map(int,input().split()) cnt = 0 for i in range(a,b): if c<=i<d: cnt+=1 print(cnt) ```
output
1
55,486
4
110,973
Provide a correct Python 3 solution for this coding contest problem. Alice and Bob are controlling a robot. They each have one switch that controls the robot. Alice started holding down her button A second after the start-up of the robot, and released her button B second after the start-up. Bob started holding down his button C second after the start-up, and released his button D second after the start-up. For how many seconds both Alice and Bob were holding down their buttons? Constraints * 0≤A<B≤100 * 0≤C<D≤100 * All input values are integers. Input Input is given from Standard Input in the following format: A B C D Output Print the length of the duration (in seconds) in which both Alice and Bob were holding down their buttons. Examples Input 0 75 25 100 Output 50 Input 0 33 66 99 Output 0 Input 10 90 20 80 Output 60
instruction
0
55,487
4
110,974
"Correct Solution: ``` a,b,c,d=[int(x) for x in input().split()] print(max(0,min(d,b)-max(a,c))) ```
output
1
55,487
4
110,975
Provide a correct Python 3 solution for this coding contest problem. Alice and Bob are controlling a robot. They each have one switch that controls the robot. Alice started holding down her button A second after the start-up of the robot, and released her button B second after the start-up. Bob started holding down his button C second after the start-up, and released his button D second after the start-up. For how many seconds both Alice and Bob were holding down their buttons? Constraints * 0≤A<B≤100 * 0≤C<D≤100 * All input values are integers. Input Input is given from Standard Input in the following format: A B C D Output Print the length of the duration (in seconds) in which both Alice and Bob were holding down their buttons. Examples Input 0 75 25 100 Output 50 Input 0 33 66 99 Output 0 Input 10 90 20 80 Output 60
instruction
0
55,488
4
110,976
"Correct Solution: ``` a, b, c, d = map(int, input().split()) ans = min(b, d) - max(a, c) print(max(ans, 0)) ```
output
1
55,488
4
110,977
Provide a correct Python 3 solution for this coding contest problem. Alice and Bob are controlling a robot. They each have one switch that controls the robot. Alice started holding down her button A second after the start-up of the robot, and released her button B second after the start-up. Bob started holding down his button C second after the start-up, and released his button D second after the start-up. For how many seconds both Alice and Bob were holding down their buttons? Constraints * 0≤A<B≤100 * 0≤C<D≤100 * All input values are integers. Input Input is given from Standard Input in the following format: A B C D Output Print the length of the duration (in seconds) in which both Alice and Bob were holding down their buttons. Examples Input 0 75 25 100 Output 50 Input 0 33 66 99 Output 0 Input 10 90 20 80 Output 60
instruction
0
55,489
4
110,978
"Correct Solution: ``` a,b,c,d=map(int,input().split()) s=min(b,d)-max(a,c) print(s) if s>0 else print(0) ```
output
1
55,489
4
110,979
Provide a correct Python 3 solution for this coding contest problem. Alice and Bob are controlling a robot. They each have one switch that controls the robot. Alice started holding down her button A second after the start-up of the robot, and released her button B second after the start-up. Bob started holding down his button C second after the start-up, and released his button D second after the start-up. For how many seconds both Alice and Bob were holding down their buttons? Constraints * 0≤A<B≤100 * 0≤C<D≤100 * All input values are integers. Input Input is given from Standard Input in the following format: A B C D Output Print the length of the duration (in seconds) in which both Alice and Bob were holding down their buttons. Examples Input 0 75 25 100 Output 50 Input 0 33 66 99 Output 0 Input 10 90 20 80 Output 60
instruction
0
55,490
4
110,980
"Correct Solution: ``` a,b,c,d=map(int,input().split()) a = min(b,d)-max(a,c) print(a if a>0 else 0) ```
output
1
55,490
4
110,981
Provide a correct Python 3 solution for this coding contest problem. Alice and Bob are controlling a robot. They each have one switch that controls the robot. Alice started holding down her button A second after the start-up of the robot, and released her button B second after the start-up. Bob started holding down his button C second after the start-up, and released his button D second after the start-up. For how many seconds both Alice and Bob were holding down their buttons? Constraints * 0≤A<B≤100 * 0≤C<D≤100 * All input values are integers. Input Input is given from Standard Input in the following format: A B C D Output Print the length of the duration (in seconds) in which both Alice and Bob were holding down their buttons. Examples Input 0 75 25 100 Output 50 Input 0 33 66 99 Output 0 Input 10 90 20 80 Output 60
instruction
0
55,491
4
110,982
"Correct Solution: ``` a, b, c, d = map(int, input().split()) ans = max(0, min(b, d) - max(a, c)) print(ans) ```
output
1
55,491
4
110,983
Provide a correct Python 3 solution for this coding contest problem. Alice and Bob are controlling a robot. They each have one switch that controls the robot. Alice started holding down her button A second after the start-up of the robot, and released her button B second after the start-up. Bob started holding down his button C second after the start-up, and released his button D second after the start-up. For how many seconds both Alice and Bob were holding down their buttons? Constraints * 0≤A<B≤100 * 0≤C<D≤100 * All input values are integers. Input Input is given from Standard Input in the following format: A B C D Output Print the length of the duration (in seconds) in which both Alice and Bob were holding down their buttons. Examples Input 0 75 25 100 Output 50 Input 0 33 66 99 Output 0 Input 10 90 20 80 Output 60
instruction
0
55,492
4
110,984
"Correct Solution: ``` A,B,C,D=map(int,input().split()) d=min(B,D)-max(A,C) print(d if d>=0 else 0) ```
output
1
55,492
4
110,985
Provide a correct Python 3 solution for this coding contest problem. Alice and Bob are controlling a robot. They each have one switch that controls the robot. Alice started holding down her button A second after the start-up of the robot, and released her button B second after the start-up. Bob started holding down his button C second after the start-up, and released his button D second after the start-up. For how many seconds both Alice and Bob were holding down their buttons? Constraints * 0≤A<B≤100 * 0≤C<D≤100 * All input values are integers. Input Input is given from Standard Input in the following format: A B C D Output Print the length of the duration (in seconds) in which both Alice and Bob were holding down their buttons. Examples Input 0 75 25 100 Output 50 Input 0 33 66 99 Output 0 Input 10 90 20 80 Output 60
instruction
0
55,493
4
110,986
"Correct Solution: ``` A,B,C,D=map(int, input().split()) x=min(B,D)-max(A,C) if x<0: print(0) else: print(x) ```
output
1
55,493
4
110,987
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Alice and Bob are controlling a robot. They each have one switch that controls the robot. Alice started holding down her button A second after the start-up of the robot, and released her button B second after the start-up. Bob started holding down his button C second after the start-up, and released his button D second after the start-up. For how many seconds both Alice and Bob were holding down their buttons? Constraints * 0≤A<B≤100 * 0≤C<D≤100 * All input values are integers. Input Input is given from Standard Input in the following format: A B C D Output Print the length of the duration (in seconds) in which both Alice and Bob were holding down their buttons. Examples Input 0 75 25 100 Output 50 Input 0 33 66 99 Output 0 Input 10 90 20 80 Output 60 Submitted Solution: ``` A, B, C, D = map(int, input().split()) x = min(B, D) - max(A, C) print(x) if x > 0 else print(0) ```
instruction
0
55,494
4
110,988
Yes
output
1
55,494
4
110,989
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Alice and Bob are controlling a robot. They each have one switch that controls the robot. Alice started holding down her button A second after the start-up of the robot, and released her button B second after the start-up. Bob started holding down his button C second after the start-up, and released his button D second after the start-up. For how many seconds both Alice and Bob were holding down their buttons? Constraints * 0≤A<B≤100 * 0≤C<D≤100 * All input values are integers. Input Input is given from Standard Input in the following format: A B C D Output Print the length of the duration (in seconds) in which both Alice and Bob were holding down their buttons. Examples Input 0 75 25 100 Output 50 Input 0 33 66 99 Output 0 Input 10 90 20 80 Output 60 Submitted Solution: ``` a,b,c,d=map(int,input().split()) s=max(a,c) f=min(b,d) print(max(f-s,0)) ```
instruction
0
55,495
4
110,990
Yes
output
1
55,495
4
110,991
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Alice and Bob are controlling a robot. They each have one switch that controls the robot. Alice started holding down her button A second after the start-up of the robot, and released her button B second after the start-up. Bob started holding down his button C second after the start-up, and released his button D second after the start-up. For how many seconds both Alice and Bob were holding down their buttons? Constraints * 0≤A<B≤100 * 0≤C<D≤100 * All input values are integers. Input Input is given from Standard Input in the following format: A B C D Output Print the length of the duration (in seconds) in which both Alice and Bob were holding down their buttons. Examples Input 0 75 25 100 Output 50 Input 0 33 66 99 Output 0 Input 10 90 20 80 Output 60 Submitted Solution: ``` a, b, c, d = map(int, input().split()) print(max([0, min([b, d])-max([a, c])])) ```
instruction
0
55,496
4
110,992
Yes
output
1
55,496
4
110,993
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Alice and Bob are controlling a robot. They each have one switch that controls the robot. Alice started holding down her button A second after the start-up of the robot, and released her button B second after the start-up. Bob started holding down his button C second after the start-up, and released his button D second after the start-up. For how many seconds both Alice and Bob were holding down their buttons? Constraints * 0≤A<B≤100 * 0≤C<D≤100 * All input values are integers. Input Input is given from Standard Input in the following format: A B C D Output Print the length of the duration (in seconds) in which both Alice and Bob were holding down their buttons. Examples Input 0 75 25 100 Output 50 Input 0 33 66 99 Output 0 Input 10 90 20 80 Output 60 Submitted Solution: ``` A, B, C, D = [int(s) for s in input().split()] print(max([0, min([B, D]) - max([A, C])])) ```
instruction
0
55,497
4
110,994
Yes
output
1
55,497
4
110,995
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Alice and Bob are controlling a robot. They each have one switch that controls the robot. Alice started holding down her button A second after the start-up of the robot, and released her button B second after the start-up. Bob started holding down his button C second after the start-up, and released his button D second after the start-up. For how many seconds both Alice and Bob were holding down their buttons? Constraints * 0≤A<B≤100 * 0≤C<D≤100 * All input values are integers. Input Input is given from Standard Input in the following format: A B C D Output Print the length of the duration (in seconds) in which both Alice and Bob were holding down their buttons. Examples Input 0 75 25 100 Output 50 Input 0 33 66 99 Output 0 Input 10 90 20 80 Output 60 Submitted Solution: ``` a,b,c,d=map(int,input()) if a<=c<=b: if b<d: print(b-c) else: print(d-c): elif c<=a<=d: if b<d: print(b-a) else: print(d-a): else: print(0) ```
instruction
0
55,498
4
110,996
No
output
1
55,498
4
110,997
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Alice and Bob are controlling a robot. They each have one switch that controls the robot. Alice started holding down her button A second after the start-up of the robot, and released her button B second after the start-up. Bob started holding down his button C second after the start-up, and released his button D second after the start-up. For how many seconds both Alice and Bob were holding down their buttons? Constraints * 0≤A<B≤100 * 0≤C<D≤100 * All input values are integers. Input Input is given from Standard Input in the following format: A B C D Output Print the length of the duration (in seconds) in which both Alice and Bob were holding down their buttons. Examples Input 0 75 25 100 Output 50 Input 0 33 66 99 Output 0 Input 10 90 20 80 Output 60 Submitted Solution: ``` import sys a,b,c,d=map(int,input().split()) if c>=b : print(c-b) else : print("0") ```
instruction
0
55,499
4
110,998
No
output
1
55,499
4
110,999
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Alice and Bob are controlling a robot. They each have one switch that controls the robot. Alice started holding down her button A second after the start-up of the robot, and released her button B second after the start-up. Bob started holding down his button C second after the start-up, and released his button D second after the start-up. For how many seconds both Alice and Bob were holding down their buttons? Constraints * 0≤A<B≤100 * 0≤C<D≤100 * All input values are integers. Input Input is given from Standard Input in the following format: A B C D Output Print the length of the duration (in seconds) in which both Alice and Bob were holding down their buttons. Examples Input 0 75 25 100 Output 50 Input 0 33 66 99 Output 0 Input 10 90 20 80 Output 60 Submitted Solution: ``` A,B,C,D = map(int,input().split()) line1 = list(range(A,B+1)) line2 = list(range(C,D+1)) line1_line2_and = set(line1) & set(line2) Alice_Bob_sim_botton = len(line1_line2_and) - 1 print(str(Alice_Bob_sim_botton)) ```
instruction
0
55,500
4
111,000
No
output
1
55,500
4
111,001
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Alice and Bob are controlling a robot. They each have one switch that controls the robot. Alice started holding down her button A second after the start-up of the robot, and released her button B second after the start-up. Bob started holding down his button C second after the start-up, and released his button D second after the start-up. For how many seconds both Alice and Bob were holding down their buttons? Constraints * 0≤A<B≤100 * 0≤C<D≤100 * All input values are integers. Input Input is given from Standard Input in the following format: A B C D Output Print the length of the duration (in seconds) in which both Alice and Bob were holding down their buttons. Examples Input 0 75 25 100 Output 50 Input 0 33 66 99 Output 0 Input 10 90 20 80 Output 60 Submitted Solution: ``` a, b, c, d = map(int, input().split()) if b < c or d < a: print(0) elif a <= c and d <= b: print(d-c) elif c <= a and b <= d: print(a-b) elif a <= c and b <= d: print(b-c) elif c <= a and d <= b: print(d-a) ```
instruction
0
55,501
4
111,002
No
output
1
55,501
4
111,003
Provide a correct Python 3 solution for this coding contest problem. The ICPC committee would like to have its meeting as soon as possible to address every little issue of the next contest. However, members of the committee are so busy maniacally developing (possibly useless) programs that it is very difficult to arrange their schedules for the meeting. So, in order to settle the meeting date, the chairperson requested every member to send back a list of convenient dates by E-mail. Your mission is to help the chairperson, who is now dedicated to other issues of the contest, by writing a program that chooses the best date from the submitted lists. Your program should find the date convenient for the most members. If there is more than one such day, the earliest is the best. Input The input has multiple data sets, each starting with a line containing the number of committee members and the quorum of the meeting. > N Q Here, N, meaning the size of the committee, and Q meaning the quorum, are positive integers. N is less than 50, and, of course, Q is less than or equal to N. N lines follow, each describing convenient dates for a committee member in the following format. > M Date1 Date2 ... DateM Here, M means the number of convenient dates for the member, which is an integer greater than or equal to zero. The remaining items in the line are his/her dates of convenience, which are positive integers less than 100, that is, 1 means tomorrow, 2 means the day after tomorrow, and so on. They are in ascending order without any repetition and separated by a space character. Lines have neither leading nor trailing spaces. A line containing two zeros indicates the end of the input. Output For each data set, print a single line containing the date number convenient for the largest number of committee members. If there is more than one such date, print the earliest. However, if no dates are convenient for more than or equal to the quorum number of members, print 0 instead. Example Input 3 2 2 1 4 0 3 3 4 8 3 2 4 1 5 8 9 3 2 5 9 5 2 4 5 7 9 3 3 2 1 4 3 2 5 9 2 2 4 3 3 2 1 2 3 1 2 9 2 2 4 0 0 Output 4 5 0 2
instruction
0
56,354
4
112,708
"Correct Solution: ``` def get_input(): data_list = input().split() for i in range(len(data_list)): data_list[i] = int(data_list[i]) return data_list def make_dict(day_dict, data_list): candidate_num =data_list[0] + 1 for i in range(1, candidate_num): data = data_list[i] if data in day_dict: day_dict[data] += 1 else: day_dict[data] = 1 return day_dict def decide_open_day(day_dict, quorum): max_num = max(day_dict.values()) if max_num < quorum: return 0 max_k_list = [kv[0] for kv in day_dict.items() if kv[1] == max_num] open_day = min(max_k_list) return open_day if __name__ == "__main__": while True: member_num, quorum = get_input() if member_num == 0: break day_dict = dict() for i in range(member_num): data_list = get_input() day_dict = make_dict(day_dict, data_list) if day_dict == {}: # remove candidate_day is None print(0) else: open_day = decide_open_day(day_dict, quorum) print(open_day) ```
output
1
56,354
4
112,709
Provide a correct Python 3 solution for this coding contest problem. The ICPC committee would like to have its meeting as soon as possible to address every little issue of the next contest. However, members of the committee are so busy maniacally developing (possibly useless) programs that it is very difficult to arrange their schedules for the meeting. So, in order to settle the meeting date, the chairperson requested every member to send back a list of convenient dates by E-mail. Your mission is to help the chairperson, who is now dedicated to other issues of the contest, by writing a program that chooses the best date from the submitted lists. Your program should find the date convenient for the most members. If there is more than one such day, the earliest is the best. Input The input has multiple data sets, each starting with a line containing the number of committee members and the quorum of the meeting. > N Q Here, N, meaning the size of the committee, and Q meaning the quorum, are positive integers. N is less than 50, and, of course, Q is less than or equal to N. N lines follow, each describing convenient dates for a committee member in the following format. > M Date1 Date2 ... DateM Here, M means the number of convenient dates for the member, which is an integer greater than or equal to zero. The remaining items in the line are his/her dates of convenience, which are positive integers less than 100, that is, 1 means tomorrow, 2 means the day after tomorrow, and so on. They are in ascending order without any repetition and separated by a space character. Lines have neither leading nor trailing spaces. A line containing two zeros indicates the end of the input. Output For each data set, print a single line containing the date number convenient for the largest number of committee members. If there is more than one such date, print the earliest. However, if no dates are convenient for more than or equal to the quorum number of members, print 0 instead. Example Input 3 2 2 1 4 0 3 3 4 8 3 2 4 1 5 8 9 3 2 5 9 5 2 4 5 7 9 3 3 2 1 4 3 2 5 9 2 2 4 3 3 2 1 2 3 1 2 9 2 2 4 0 0 Output 4 5 0 2
instruction
0
56,355
4
112,710
"Correct Solution: ``` while(1): N,Q=tuple(map(int,input().split())) if not(N or Q): break data=[] temp=[] for i in range(N): temp=list(map(int,input().split())) temp.pop(0) data.append(temp) sum=0 max=0 index=0 for i in range(100): sum=0 for j in range(N): sum=sum+int((i in data[j])) if sum >= Q and sum > max: max = sum index=i print(index) ```
output
1
56,355
4
112,711
Provide a correct Python 3 solution for this coding contest problem. The ICPC committee would like to have its meeting as soon as possible to address every little issue of the next contest. However, members of the committee are so busy maniacally developing (possibly useless) programs that it is very difficult to arrange their schedules for the meeting. So, in order to settle the meeting date, the chairperson requested every member to send back a list of convenient dates by E-mail. Your mission is to help the chairperson, who is now dedicated to other issues of the contest, by writing a program that chooses the best date from the submitted lists. Your program should find the date convenient for the most members. If there is more than one such day, the earliest is the best. Input The input has multiple data sets, each starting with a line containing the number of committee members and the quorum of the meeting. > N Q Here, N, meaning the size of the committee, and Q meaning the quorum, are positive integers. N is less than 50, and, of course, Q is less than or equal to N. N lines follow, each describing convenient dates for a committee member in the following format. > M Date1 Date2 ... DateM Here, M means the number of convenient dates for the member, which is an integer greater than or equal to zero. The remaining items in the line are his/her dates of convenience, which are positive integers less than 100, that is, 1 means tomorrow, 2 means the day after tomorrow, and so on. They are in ascending order without any repetition and separated by a space character. Lines have neither leading nor trailing spaces. A line containing two zeros indicates the end of the input. Output For each data set, print a single line containing the date number convenient for the largest number of committee members. If there is more than one such date, print the earliest. However, if no dates are convenient for more than or equal to the quorum number of members, print 0 instead. Example Input 3 2 2 1 4 0 3 3 4 8 3 2 4 1 5 8 9 3 2 5 9 5 2 4 5 7 9 3 3 2 1 4 3 2 5 9 2 2 4 3 3 2 1 2 3 1 2 9 2 2 4 0 0 Output 4 5 0 2
instruction
0
56,356
4
112,712
"Correct Solution: ``` from collections import Counter while True: N,Q = map(int,input().split()) if N == 0: break ctr = Counter() for i in range(N): src = list(map(int,input().split())) ctr.update(src[1:]) ans_n = 0 ans_d = -1 for d,n in sorted(ctr.items()): if n > ans_n: ans_n = n ans_d = d if ans_n >= Q: print(ans_d) else: print(0) ```
output
1
56,356
4
112,713
Provide a correct Python 3 solution for this coding contest problem. The ICPC committee would like to have its meeting as soon as possible to address every little issue of the next contest. However, members of the committee are so busy maniacally developing (possibly useless) programs that it is very difficult to arrange their schedules for the meeting. So, in order to settle the meeting date, the chairperson requested every member to send back a list of convenient dates by E-mail. Your mission is to help the chairperson, who is now dedicated to other issues of the contest, by writing a program that chooses the best date from the submitted lists. Your program should find the date convenient for the most members. If there is more than one such day, the earliest is the best. Input The input has multiple data sets, each starting with a line containing the number of committee members and the quorum of the meeting. > N Q Here, N, meaning the size of the committee, and Q meaning the quorum, are positive integers. N is less than 50, and, of course, Q is less than or equal to N. N lines follow, each describing convenient dates for a committee member in the following format. > M Date1 Date2 ... DateM Here, M means the number of convenient dates for the member, which is an integer greater than or equal to zero. The remaining items in the line are his/her dates of convenience, which are positive integers less than 100, that is, 1 means tomorrow, 2 means the day after tomorrow, and so on. They are in ascending order without any repetition and separated by a space character. Lines have neither leading nor trailing spaces. A line containing two zeros indicates the end of the input. Output For each data set, print a single line containing the date number convenient for the largest number of committee members. If there is more than one such date, print the earliest. However, if no dates are convenient for more than or equal to the quorum number of members, print 0 instead. Example Input 3 2 2 1 4 0 3 3 4 8 3 2 4 1 5 8 9 3 2 5 9 5 2 4 5 7 9 3 3 2 1 4 3 2 5 9 2 2 4 3 3 2 1 2 3 1 2 9 2 2 4 0 0 Output 4 5 0 2
instruction
0
56,357
4
112,714
"Correct Solution: ``` while True: n, q = map(int, input().split()) if n == 0: break data = [list(map(int, input().split())) for i in range(n)] for li in data: if li[0] > 0: del(li[0]) q -= 1 day = 0 for d in range(1,100): cnt = 0 for li in data: if d in li: cnt += 1 if cnt > q: q = cnt day = d print(day) ```
output
1
56,357
4
112,715
Provide a correct Python 3 solution for this coding contest problem. The ICPC committee would like to have its meeting as soon as possible to address every little issue of the next contest. However, members of the committee are so busy maniacally developing (possibly useless) programs that it is very difficult to arrange their schedules for the meeting. So, in order to settle the meeting date, the chairperson requested every member to send back a list of convenient dates by E-mail. Your mission is to help the chairperson, who is now dedicated to other issues of the contest, by writing a program that chooses the best date from the submitted lists. Your program should find the date convenient for the most members. If there is more than one such day, the earliest is the best. Input The input has multiple data sets, each starting with a line containing the number of committee members and the quorum of the meeting. > N Q Here, N, meaning the size of the committee, and Q meaning the quorum, are positive integers. N is less than 50, and, of course, Q is less than or equal to N. N lines follow, each describing convenient dates for a committee member in the following format. > M Date1 Date2 ... DateM Here, M means the number of convenient dates for the member, which is an integer greater than or equal to zero. The remaining items in the line are his/her dates of convenience, which are positive integers less than 100, that is, 1 means tomorrow, 2 means the day after tomorrow, and so on. They are in ascending order without any repetition and separated by a space character. Lines have neither leading nor trailing spaces. A line containing two zeros indicates the end of the input. Output For each data set, print a single line containing the date number convenient for the largest number of committee members. If there is more than one such date, print the earliest. However, if no dates are convenient for more than or equal to the quorum number of members, print 0 instead. Example Input 3 2 2 1 4 0 3 3 4 8 3 2 4 1 5 8 9 3 2 5 9 5 2 4 5 7 9 3 3 2 1 4 3 2 5 9 2 2 4 3 3 2 1 2 3 1 2 9 2 2 4 0 0 Output 4 5 0 2
instruction
0
56,358
4
112,716
"Correct Solution: ``` while True: tmp = input().split(' ') n = int(tmp[0]) q = int(tmp[1]) if n == 0 and q == 0: break a = [] d = [0]*100 for i in range(n): a = input().split(' ') for j in range(int(a[0])): qq = int(a[ j+1 ]) d[qq] = d[qq] + 1 mx = max(d) if mx < q: print(0) else: for i in range(len(d)): if mx == d[i]: print( i ) break ```
output
1
56,358
4
112,717
Provide a correct Python 3 solution for this coding contest problem. The ICPC committee would like to have its meeting as soon as possible to address every little issue of the next contest. However, members of the committee are so busy maniacally developing (possibly useless) programs that it is very difficult to arrange their schedules for the meeting. So, in order to settle the meeting date, the chairperson requested every member to send back a list of convenient dates by E-mail. Your mission is to help the chairperson, who is now dedicated to other issues of the contest, by writing a program that chooses the best date from the submitted lists. Your program should find the date convenient for the most members. If there is more than one such day, the earliest is the best. Input The input has multiple data sets, each starting with a line containing the number of committee members and the quorum of the meeting. > N Q Here, N, meaning the size of the committee, and Q meaning the quorum, are positive integers. N is less than 50, and, of course, Q is less than or equal to N. N lines follow, each describing convenient dates for a committee member in the following format. > M Date1 Date2 ... DateM Here, M means the number of convenient dates for the member, which is an integer greater than or equal to zero. The remaining items in the line are his/her dates of convenience, which are positive integers less than 100, that is, 1 means tomorrow, 2 means the day after tomorrow, and so on. They are in ascending order without any repetition and separated by a space character. Lines have neither leading nor trailing spaces. A line containing two zeros indicates the end of the input. Output For each data set, print a single line containing the date number convenient for the largest number of committee members. If there is more than one such date, print the earliest. However, if no dates are convenient for more than or equal to the quorum number of members, print 0 instead. Example Input 3 2 2 1 4 0 3 3 4 8 3 2 4 1 5 8 9 3 2 5 9 5 2 4 5 7 9 3 3 2 1 4 3 2 5 9 2 2 4 3 3 2 1 2 3 1 2 9 2 2 4 0 0 Output 4 5 0 2
instruction
0
56,359
4
112,718
"Correct Solution: ``` while True: N,Q = map(int,input().split()) if N+Q==0: break date = [0 for i in range(1000)] for i in range(N): M = list(map(int,input().split())) for i in M[1:]: date[i]+=1 a = max(date) if a>=N: for i in range(1000): if N==date[i]: print(i) break elif N>a>=Q: for i in range(1000): if a==date[i]: print(i) break else: print(0) ```
output
1
56,359
4
112,719
Provide a correct Python 3 solution for this coding contest problem. The ICPC committee would like to have its meeting as soon as possible to address every little issue of the next contest. However, members of the committee are so busy maniacally developing (possibly useless) programs that it is very difficult to arrange their schedules for the meeting. So, in order to settle the meeting date, the chairperson requested every member to send back a list of convenient dates by E-mail. Your mission is to help the chairperson, who is now dedicated to other issues of the contest, by writing a program that chooses the best date from the submitted lists. Your program should find the date convenient for the most members. If there is more than one such day, the earliest is the best. Input The input has multiple data sets, each starting with a line containing the number of committee members and the quorum of the meeting. > N Q Here, N, meaning the size of the committee, and Q meaning the quorum, are positive integers. N is less than 50, and, of course, Q is less than or equal to N. N lines follow, each describing convenient dates for a committee member in the following format. > M Date1 Date2 ... DateM Here, M means the number of convenient dates for the member, which is an integer greater than or equal to zero. The remaining items in the line are his/her dates of convenience, which are positive integers less than 100, that is, 1 means tomorrow, 2 means the day after tomorrow, and so on. They are in ascending order without any repetition and separated by a space character. Lines have neither leading nor trailing spaces. A line containing two zeros indicates the end of the input. Output For each data set, print a single line containing the date number convenient for the largest number of committee members. If there is more than one such date, print the earliest. However, if no dates are convenient for more than or equal to the quorum number of members, print 0 instead. Example Input 3 2 2 1 4 0 3 3 4 8 3 2 4 1 5 8 9 3 2 5 9 5 2 4 5 7 9 3 3 2 1 4 3 2 5 9 2 2 4 3 3 2 1 2 3 1 2 9 2 2 4 0 0 Output 4 5 0 2
instruction
0
56,360
4
112,720
"Correct Solution: ``` while True: n, q = map(int, input().split()) if n == 0: break c_dates = [] for i in range(n): data = input().split() del data[0] for j in range(len(data)): data[j] = int(data[j]) c_dates = c_dates + data c_dates.sort() #print(c_dates) #print("データの個数" + str(len(c_dates))) c_day = 0 c_num = 1 max_num = 0 #print(str(q) + "人以上") if len(c_dates) == 1 and q == 1: print(c_dates[0]) continue for i in range(len(c_dates) - 1): if c_dates[i] == c_dates[i + 1] and i != len(c_dates) - 1: c_num += 1 if i != len(c_dates) - 2: continue if c_num >= q and c_num > max_num: c_day = c_dates[i] #print("c_day " + str(c_day)) #print("c_num " + str(c_num)) max_num = c_num c_num = 1 else: c_num = 1 print(c_day) #print("") ```
output
1
56,360
4
112,721
Provide a correct Python 3 solution for this coding contest problem. The ICPC committee would like to have its meeting as soon as possible to address every little issue of the next contest. However, members of the committee are so busy maniacally developing (possibly useless) programs that it is very difficult to arrange their schedules for the meeting. So, in order to settle the meeting date, the chairperson requested every member to send back a list of convenient dates by E-mail. Your mission is to help the chairperson, who is now dedicated to other issues of the contest, by writing a program that chooses the best date from the submitted lists. Your program should find the date convenient for the most members. If there is more than one such day, the earliest is the best. Input The input has multiple data sets, each starting with a line containing the number of committee members and the quorum of the meeting. > N Q Here, N, meaning the size of the committee, and Q meaning the quorum, are positive integers. N is less than 50, and, of course, Q is less than or equal to N. N lines follow, each describing convenient dates for a committee member in the following format. > M Date1 Date2 ... DateM Here, M means the number of convenient dates for the member, which is an integer greater than or equal to zero. The remaining items in the line are his/her dates of convenience, which are positive integers less than 100, that is, 1 means tomorrow, 2 means the day after tomorrow, and so on. They are in ascending order without any repetition and separated by a space character. Lines have neither leading nor trailing spaces. A line containing two zeros indicates the end of the input. Output For each data set, print a single line containing the date number convenient for the largest number of committee members. If there is more than one such date, print the earliest. However, if no dates are convenient for more than or equal to the quorum number of members, print 0 instead. Example Input 3 2 2 1 4 0 3 3 4 8 3 2 4 1 5 8 9 3 2 5 9 5 2 4 5 7 9 3 3 2 1 4 3 2 5 9 2 2 4 3 3 2 1 2 3 1 2 9 2 2 4 0 0 Output 4 5 0 2
instruction
0
56,361
4
112,722
"Correct Solution: ``` import collections while True: N, Q = map(int, input().split()) if N == 0 and Q == 0: break D = [] for _ in range(N): i = list(map(int, input().split())) del i[0] [D.append(ii) for ii in i] if not len(D) == 0: c = collections.Counter(D) cc = c.most_common() # print(cc) if cc[0][1] >= Q: ans = 1000000 tmp = cc[0][1] for i in range(len(cc)): if cc[i][1] == tmp: ans = min(cc[i][0], ans) print(ans) else: print(0) else: print(0) ```
output
1
56,361
4
112,723
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The ICPC committee would like to have its meeting as soon as possible to address every little issue of the next contest. However, members of the committee are so busy maniacally developing (possibly useless) programs that it is very difficult to arrange their schedules for the meeting. So, in order to settle the meeting date, the chairperson requested every member to send back a list of convenient dates by E-mail. Your mission is to help the chairperson, who is now dedicated to other issues of the contest, by writing a program that chooses the best date from the submitted lists. Your program should find the date convenient for the most members. If there is more than one such day, the earliest is the best. Input The input has multiple data sets, each starting with a line containing the number of committee members and the quorum of the meeting. > N Q Here, N, meaning the size of the committee, and Q meaning the quorum, are positive integers. N is less than 50, and, of course, Q is less than or equal to N. N lines follow, each describing convenient dates for a committee member in the following format. > M Date1 Date2 ... DateM Here, M means the number of convenient dates for the member, which is an integer greater than or equal to zero. The remaining items in the line are his/her dates of convenience, which are positive integers less than 100, that is, 1 means tomorrow, 2 means the day after tomorrow, and so on. They are in ascending order without any repetition and separated by a space character. Lines have neither leading nor trailing spaces. A line containing two zeros indicates the end of the input. Output For each data set, print a single line containing the date number convenient for the largest number of committee members. If there is more than one such date, print the earliest. However, if no dates are convenient for more than or equal to the quorum number of members, print 0 instead. Example Input 3 2 2 1 4 0 3 3 4 8 3 2 4 1 5 8 9 3 2 5 9 5 2 4 5 7 9 3 3 2 1 4 3 2 5 9 2 2 4 3 3 2 1 2 3 1 2 9 2 2 4 0 0 Output 4 5 0 2 Submitted Solution: ``` while True: N, Q = map(int, input().split()) if N == 0 and Q == 0: break counts = [0 for i in range(100)] for i in range(N): tmp = list(map(int, input().split())) M = tmp[0] for i in range(M): counts[tmp[i + 1] - 1] += 1 max_count = max(counts) if max_count < Q: print(0) else: for i in range(100): if counts[i] == max_count: print(i + 1) break ```
instruction
0
56,362
4
112,724
Yes
output
1
56,362
4
112,725
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The ICPC committee would like to have its meeting as soon as possible to address every little issue of the next contest. However, members of the committee are so busy maniacally developing (possibly useless) programs that it is very difficult to arrange their schedules for the meeting. So, in order to settle the meeting date, the chairperson requested every member to send back a list of convenient dates by E-mail. Your mission is to help the chairperson, who is now dedicated to other issues of the contest, by writing a program that chooses the best date from the submitted lists. Your program should find the date convenient for the most members. If there is more than one such day, the earliest is the best. Input The input has multiple data sets, each starting with a line containing the number of committee members and the quorum of the meeting. > N Q Here, N, meaning the size of the committee, and Q meaning the quorum, are positive integers. N is less than 50, and, of course, Q is less than or equal to N. N lines follow, each describing convenient dates for a committee member in the following format. > M Date1 Date2 ... DateM Here, M means the number of convenient dates for the member, which is an integer greater than or equal to zero. The remaining items in the line are his/her dates of convenience, which are positive integers less than 100, that is, 1 means tomorrow, 2 means the day after tomorrow, and so on. They are in ascending order without any repetition and separated by a space character. Lines have neither leading nor trailing spaces. A line containing two zeros indicates the end of the input. Output For each data set, print a single line containing the date number convenient for the largest number of committee members. If there is more than one such date, print the earliest. However, if no dates are convenient for more than or equal to the quorum number of members, print 0 instead. Example Input 3 2 2 1 4 0 3 3 4 8 3 2 4 1 5 8 9 3 2 5 9 5 2 4 5 7 9 3 3 2 1 4 3 2 5 9 2 2 4 3 3 2 1 2 3 1 2 9 2 2 4 0 0 Output 4 5 0 2 Submitted Solution: ``` cond = [int(n) for n in input().split(" ")] while True: answer = [101,0] case = [] sets = set() for c in range(cond[0]): case.append([int(n) for n in input().split(" ")[1:]]) sets = sets | {n for n in case[-1]} #print(sets,case) else: for num in sets: disp = [num,0] for c in case: if num in c: disp[1] += 1 else: #print(disp,answer,cond) if (disp[1] >= cond[1] and disp[1] > answer[1] ) or (disp[1] == answer[1] and disp[0] < answer[0]): answer = disp else: if answer[0] == 101: print(0) else: print(answer[0]) cond = [int(n) for n in input().split(" ")] if cond == [0,0]: break ```
instruction
0
56,363
4
112,726
Yes
output
1
56,363
4
112,727
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The ICPC committee would like to have its meeting as soon as possible to address every little issue of the next contest. However, members of the committee are so busy maniacally developing (possibly useless) programs that it is very difficult to arrange their schedules for the meeting. So, in order to settle the meeting date, the chairperson requested every member to send back a list of convenient dates by E-mail. Your mission is to help the chairperson, who is now dedicated to other issues of the contest, by writing a program that chooses the best date from the submitted lists. Your program should find the date convenient for the most members. If there is more than one such day, the earliest is the best. Input The input has multiple data sets, each starting with a line containing the number of committee members and the quorum of the meeting. > N Q Here, N, meaning the size of the committee, and Q meaning the quorum, are positive integers. N is less than 50, and, of course, Q is less than or equal to N. N lines follow, each describing convenient dates for a committee member in the following format. > M Date1 Date2 ... DateM Here, M means the number of convenient dates for the member, which is an integer greater than or equal to zero. The remaining items in the line are his/her dates of convenience, which are positive integers less than 100, that is, 1 means tomorrow, 2 means the day after tomorrow, and so on. They are in ascending order without any repetition and separated by a space character. Lines have neither leading nor trailing spaces. A line containing two zeros indicates the end of the input. Output For each data set, print a single line containing the date number convenient for the largest number of committee members. If there is more than one such date, print the earliest. However, if no dates are convenient for more than or equal to the quorum number of members, print 0 instead. Example Input 3 2 2 1 4 0 3 3 4 8 3 2 4 1 5 8 9 3 2 5 9 5 2 4 5 7 9 3 3 2 1 4 3 2 5 9 2 2 4 3 3 2 1 2 3 1 2 9 2 2 4 0 0 Output 4 5 0 2 Submitted Solution: ``` while(True): N, Q = map(int, input().split()) if (N+Q) == 0:break D = list(list(int(i) for i in input().split()) for i in range(N)) D_i = [1]*N answer = 0 now_max = Q -1 for i in range(1,100): member = 0 for j in range(N): if D[j][0] < D_i[j]: continue if D[j][D_i[j]] == i: member += 1 D_i[j] += 1 if member > now_max : answer = i now_max = member if member == N: answer = i break print(answer) ```
instruction
0
56,364
4
112,728
Yes
output
1
56,364
4
112,729
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The ICPC committee would like to have its meeting as soon as possible to address every little issue of the next contest. However, members of the committee are so busy maniacally developing (possibly useless) programs that it is very difficult to arrange their schedules for the meeting. So, in order to settle the meeting date, the chairperson requested every member to send back a list of convenient dates by E-mail. Your mission is to help the chairperson, who is now dedicated to other issues of the contest, by writing a program that chooses the best date from the submitted lists. Your program should find the date convenient for the most members. If there is more than one such day, the earliest is the best. Input The input has multiple data sets, each starting with a line containing the number of committee members and the quorum of the meeting. > N Q Here, N, meaning the size of the committee, and Q meaning the quorum, are positive integers. N is less than 50, and, of course, Q is less than or equal to N. N lines follow, each describing convenient dates for a committee member in the following format. > M Date1 Date2 ... DateM Here, M means the number of convenient dates for the member, which is an integer greater than or equal to zero. The remaining items in the line are his/her dates of convenience, which are positive integers less than 100, that is, 1 means tomorrow, 2 means the day after tomorrow, and so on. They are in ascending order without any repetition and separated by a space character. Lines have neither leading nor trailing spaces. A line containing two zeros indicates the end of the input. Output For each data set, print a single line containing the date number convenient for the largest number of committee members. If there is more than one such date, print the earliest. However, if no dates are convenient for more than or equal to the quorum number of members, print 0 instead. Example Input 3 2 2 1 4 0 3 3 4 8 3 2 4 1 5 8 9 3 2 5 9 5 2 4 5 7 9 3 3 2 1 4 3 2 5 9 2 2 4 3 3 2 1 2 3 1 2 9 2 2 4 0 0 Output 4 5 0 2 Submitted Solution: ``` import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools sys.setrecursionlimit(10**7) inf = 10**3 eps = 1.0 / 10**10 mod = 10**9+7 def LI(): return [int(x) for x in sys.stdin.readline().split()] def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()] def LF(): return [float(x) for x in sys.stdin.readline().split()] def LS(): return sys.stdin.readline().split() def I(): return int(sys.stdin.readline()) def F(): return float(sys.stdin.readline()) def S(): return input() def pf(s): return print(s, flush=True) def main(): rr = [] while True: n,q = LI() if n == 0: break a = [LI() for _ in range(n)] d = collections.defaultdict(int) for c in a: for cc in c[1:]: d[cc] += 1 t = sorted([[-v,k] for k,v in d.items() if v >= q]) if len(t) == 0: rr.append(0) else: rr.append(t[0][1]) return '\n'.join(map(str, rr)) print(main()) ```
instruction
0
56,365
4
112,730
Yes
output
1
56,365
4
112,731
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The ICPC committee would like to have its meeting as soon as possible to address every little issue of the next contest. However, members of the committee are so busy maniacally developing (possibly useless) programs that it is very difficult to arrange their schedules for the meeting. So, in order to settle the meeting date, the chairperson requested every member to send back a list of convenient dates by E-mail. Your mission is to help the chairperson, who is now dedicated to other issues of the contest, by writing a program that chooses the best date from the submitted lists. Your program should find the date convenient for the most members. If there is more than one such day, the earliest is the best. Input The input has multiple data sets, each starting with a line containing the number of committee members and the quorum of the meeting. > N Q Here, N, meaning the size of the committee, and Q meaning the quorum, are positive integers. N is less than 50, and, of course, Q is less than or equal to N. N lines follow, each describing convenient dates for a committee member in the following format. > M Date1 Date2 ... DateM Here, M means the number of convenient dates for the member, which is an integer greater than or equal to zero. The remaining items in the line are his/her dates of convenience, which are positive integers less than 100, that is, 1 means tomorrow, 2 means the day after tomorrow, and so on. They are in ascending order without any repetition and separated by a space character. Lines have neither leading nor trailing spaces. A line containing two zeros indicates the end of the input. Output For each data set, print a single line containing the date number convenient for the largest number of committee members. If there is more than one such date, print the earliest. However, if no dates are convenient for more than or equal to the quorum number of members, print 0 instead. Example Input 3 2 2 1 4 0 3 3 4 8 3 2 4 1 5 8 9 3 2 5 9 5 2 4 5 7 9 3 3 2 1 4 3 2 5 9 2 2 4 3 3 2 1 2 3 1 2 9 2 2 4 0 0 Output 4 5 0 2 Submitted Solution: ``` from collections import Counter while 1: N,Q=map(int,input().split()) if (N,Q)==(0,0): break M,l=[list(map(int,input().split())) for _ in range(N)],[] for mm in M: if len(mm)!=1: for i in range(1,len(mm)): l.append(mm[i]) c=Counter(l) _,mv=c.most_common(1)[0] print(min([k for k,v in c.most_common() if mv==v]) if mv>=Q else 0) ```
instruction
0
56,366
4
112,732
No
output
1
56,366
4
112,733
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The ICPC committee would like to have its meeting as soon as possible to address every little issue of the next contest. However, members of the committee are so busy maniacally developing (possibly useless) programs that it is very difficult to arrange their schedules for the meeting. So, in order to settle the meeting date, the chairperson requested every member to send back a list of convenient dates by E-mail. Your mission is to help the chairperson, who is now dedicated to other issues of the contest, by writing a program that chooses the best date from the submitted lists. Your program should find the date convenient for the most members. If there is more than one such day, the earliest is the best. Input The input has multiple data sets, each starting with a line containing the number of committee members and the quorum of the meeting. > N Q Here, N, meaning the size of the committee, and Q meaning the quorum, are positive integers. N is less than 50, and, of course, Q is less than or equal to N. N lines follow, each describing convenient dates for a committee member in the following format. > M Date1 Date2 ... DateM Here, M means the number of convenient dates for the member, which is an integer greater than or equal to zero. The remaining items in the line are his/her dates of convenience, which are positive integers less than 100, that is, 1 means tomorrow, 2 means the day after tomorrow, and so on. They are in ascending order without any repetition and separated by a space character. Lines have neither leading nor trailing spaces. A line containing two zeros indicates the end of the input. Output For each data set, print a single line containing the date number convenient for the largest number of committee members. If there is more than one such date, print the earliest. However, if no dates are convenient for more than or equal to the quorum number of members, print 0 instead. Example Input 3 2 2 1 4 0 3 3 4 8 3 2 4 1 5 8 9 3 2 5 9 5 2 4 5 7 9 3 3 2 1 4 3 2 5 9 2 2 4 3 3 2 1 2 3 1 2 9 2 2 4 0 0 Output 4 5 0 2 Submitted Solution: ``` while True: n, q = map(int, input().split()) if n == 0: break ls = [] for i in range(n): ls.append(list(map(int, input().split()))) for i in range(1, 101): count = 0 for j in range(len(ls)): if i in ls[j][1:]: count += 1 if count == q: break else: continue print(i) break else: print(0) ```
instruction
0
56,367
4
112,734
No
output
1
56,367
4
112,735