message stringlengths 2 20.2k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 757 108k | cluster float64 4 4 | __index_level_0__ int64 1.51k 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
Unlucky year in Berland is such a year that its number n can be represented as n = xa + yb, where a and b are non-negative integer numbers.
For example, if x = 2 and y = 3 then the years 4 and 17 are unlucky (4 = 20 + 31, 17 = 23 + 32 = 24 + 30) and year 18 isn't unlucky as there is no such representation for it.
Such interval of years that there are no unlucky years in it is called The Golden Age.
You should write a program which will find maximum length of The Golden Age which starts no earlier than the year l and ends no later than the year r. If all years in the interval [l, r] are unlucky then the answer is 0.
Input
The first line contains four integer numbers x, y, l and r (2 ≤ x, y ≤ 1018, 1 ≤ l ≤ r ≤ 1018).
Output
Print the maximum length of The Golden Age within the interval [l, r].
If all years in the interval [l, r] are unlucky then print 0.
Examples
Input
2 3 1 10
Output
1
Input
3 5 10 22
Output
8
Input
2 3 3 5
Output
0
Note
In the first example the unlucky years are 2, 3, 4, 5, 7, 9 and 10. So maximum length of The Golden Age is achived in the intervals [1, 1], [6, 6] and [8, 8].
In the second example the longest Golden Age is the interval [15, 22]. | instruction | 0 | 9,582 | 4 | 19,164 |
Tags: brute force, math
Correct Solution:
```
x,y,l,r=map(int,input().split())
lst = []
pwdX = 1
pwdY = 1
for i in range(0,65):
pwdY = 1
for j in range(0,65):
if pwdX + pwdY > r:
lst.append(pwdX + pwdY)
break
toAdd = pwdX + pwdY
lst.append(toAdd)
pwdY*=y
pwdX*=x
lst.append(r+1)
lst.append(l-1)
# print(lst)
# sorted(lst)
lst.sort()
maximum = 0
for i in range(0,len(lst)-1):
if lst[i] >= l-1 and lst[i+1] <= r+1:
maximum = max(maximum,lst[i+1]-lst[i] - 1)
print(maximum)
``` | output | 1 | 9,582 | 4 | 19,165 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Unlucky year in Berland is such a year that its number n can be represented as n = xa + yb, where a and b are non-negative integer numbers.
For example, if x = 2 and y = 3 then the years 4 and 17 are unlucky (4 = 20 + 31, 17 = 23 + 32 = 24 + 30) and year 18 isn't unlucky as there is no such representation for it.
Such interval of years that there are no unlucky years in it is called The Golden Age.
You should write a program which will find maximum length of The Golden Age which starts no earlier than the year l and ends no later than the year r. If all years in the interval [l, r] are unlucky then the answer is 0.
Input
The first line contains four integer numbers x, y, l and r (2 ≤ x, y ≤ 1018, 1 ≤ l ≤ r ≤ 1018).
Output
Print the maximum length of The Golden Age within the interval [l, r].
If all years in the interval [l, r] are unlucky then print 0.
Examples
Input
2 3 1 10
Output
1
Input
3 5 10 22
Output
8
Input
2 3 3 5
Output
0
Note
In the first example the unlucky years are 2, 3, 4, 5, 7, 9 and 10. So maximum length of The Golden Age is achived in the intervals [1, 1], [6, 6] and [8, 8].
In the second example the longest Golden Age is the interval [15, 22]. | instruction | 0 | 9,583 | 4 | 19,166 |
Tags: brute force, math
Correct Solution:
```
x, y, l, r = map(int, input().split())
t = []
a = 1
while a <= r:
b = 1
while a + b <= r:
if a + b >= l: t.append(a + b)
b *= y
a *= x
t.sort()
print(max(y - x for x, y in zip([l - 1] + t, t + [r + 1])) - 1)
``` | output | 1 | 9,583 | 4 | 19,167 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Unlucky year in Berland is such a year that its number n can be represented as n = xa + yb, where a and b are non-negative integer numbers.
For example, if x = 2 and y = 3 then the years 4 and 17 are unlucky (4 = 20 + 31, 17 = 23 + 32 = 24 + 30) and year 18 isn't unlucky as there is no such representation for it.
Such interval of years that there are no unlucky years in it is called The Golden Age.
You should write a program which will find maximum length of The Golden Age which starts no earlier than the year l and ends no later than the year r. If all years in the interval [l, r] are unlucky then the answer is 0.
Input
The first line contains four integer numbers x, y, l and r (2 ≤ x, y ≤ 1018, 1 ≤ l ≤ r ≤ 1018).
Output
Print the maximum length of The Golden Age within the interval [l, r].
If all years in the interval [l, r] are unlucky then print 0.
Examples
Input
2 3 1 10
Output
1
Input
3 5 10 22
Output
8
Input
2 3 3 5
Output
0
Note
In the first example the unlucky years are 2, 3, 4, 5, 7, 9 and 10. So maximum length of The Golden Age is achived in the intervals [1, 1], [6, 6] and [8, 8].
In the second example the longest Golden Age is the interval [15, 22]. | instruction | 0 | 9,584 | 4 | 19,168 |
Tags: brute force, math
Correct Solution:
```
import math
import sys
a = list(map(int,input().split()))
x = a[0]
y = a[1]
l = a[2]
r = a[3]
v = []
for i in range(0, 61):
for j in range(0, 61):
if (x ** i + y ** j >= l) and (x ** i + y ** j <= r):
v.append(x ** i + y ** j)
maxi = 0
v.sort()
if len(v) >= 2:
for i in range(1, len(v)):
maxi = max(maxi, v[i] - v[i - 1] - 1)
if len(v) >= 1 and (not v.count(l)):
maxi = max(maxi, v[0] - l)
if len(v) >= 1 and (not v.count(r)):
maxi = max(maxi, r - v[len(v) - 1])
if len(v) == 0 and (not (v.count(l))) and (not (v.count(r))):
maxi = max(maxi, r - l + 1)
print(maxi)
``` | output | 1 | 9,584 | 4 | 19,169 |
Provide tags and a correct Python 2 solution for this coding contest problem.
Unlucky year in Berland is such a year that its number n can be represented as n = xa + yb, where a and b are non-negative integer numbers.
For example, if x = 2 and y = 3 then the years 4 and 17 are unlucky (4 = 20 + 31, 17 = 23 + 32 = 24 + 30) and year 18 isn't unlucky as there is no such representation for it.
Such interval of years that there are no unlucky years in it is called The Golden Age.
You should write a program which will find maximum length of The Golden Age which starts no earlier than the year l and ends no later than the year r. If all years in the interval [l, r] are unlucky then the answer is 0.
Input
The first line contains four integer numbers x, y, l and r (2 ≤ x, y ≤ 1018, 1 ≤ l ≤ r ≤ 1018).
Output
Print the maximum length of The Golden Age within the interval [l, r].
If all years in the interval [l, r] are unlucky then print 0.
Examples
Input
2 3 1 10
Output
1
Input
3 5 10 22
Output
8
Input
2 3 3 5
Output
0
Note
In the first example the unlucky years are 2, 3, 4, 5, 7, 9 and 10. So maximum length of The Golden Age is achived in the intervals [1, 1], [6, 6] and [8, 8].
In the second example the longest Golden Age is the interval [15, 22]. | instruction | 0 | 9,585 | 4 | 19,170 |
Tags: brute force, math
Correct Solution:
```
from sys import stdin, stdout
from collections import Counter, defaultdict
from itertools import permutations, combinations
raw_input = stdin.readline
pr = stdout.write
def in_num():
return int(raw_input())
def in_arr():
return map(int,raw_input().split())
def pr_num(n):
stdout.write(str(n)+'\n')
def pr_arr(arr):
pr(' '.join(map(str,arr))+'\n')
# fast read function for total integer input
def inp():
# this function returns whole input of
# space/line seperated integers
# Use Ctrl+D to flush stdin.
return map(int,stdin.read().split())
range = xrange # not for python 3.0+
# main code
x,y,l,r=in_arr()
mx=10**18
p1=1
temp=set()
temp.add(0)
temp.add(mx+1)
while p1<=mx:
p2=1
while p2<=mx:
temp.add(p1+p2)
p2*=y
p1*=x
temp=list(temp)
temp.sort()
ans=0
n=len(temp)
l-=1
r+=1
for i in range(n-1):
val=max(0,min(r,temp[i+1])-max(l,temp[i])-1)
ans=max(ans,val)
pr_num(ans)
``` | output | 1 | 9,585 | 4 | 19,171 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Unlucky year in Berland is such a year that its number n can be represented as n = xa + yb, where a and b are non-negative integer numbers.
For example, if x = 2 and y = 3 then the years 4 and 17 are unlucky (4 = 20 + 31, 17 = 23 + 32 = 24 + 30) and year 18 isn't unlucky as there is no such representation for it.
Such interval of years that there are no unlucky years in it is called The Golden Age.
You should write a program which will find maximum length of The Golden Age which starts no earlier than the year l and ends no later than the year r. If all years in the interval [l, r] are unlucky then the answer is 0.
Input
The first line contains four integer numbers x, y, l and r (2 ≤ x, y ≤ 1018, 1 ≤ l ≤ r ≤ 1018).
Output
Print the maximum length of The Golden Age within the interval [l, r].
If all years in the interval [l, r] are unlucky then print 0.
Examples
Input
2 3 1 10
Output
1
Input
3 5 10 22
Output
8
Input
2 3 3 5
Output
0
Note
In the first example the unlucky years are 2, 3, 4, 5, 7, 9 and 10. So maximum length of The Golden Age is achived in the intervals [1, 1], [6, 6] and [8, 8].
In the second example the longest Golden Age is the interval [15, 22].
Submitted Solution:
```
x,y,l,r = map(int,input().split())
a = []
for i in range(100):
for j in range(100):
t = pow(x,i)+pow(y,j)
if(t>r):
break
if(l <= t and t <= r):
a.append(t)
a.sort()
res = 0
for i in range(len(a)-1):
if(res < a[i+1] - a[i] - 1):
res = a[i+1]-a[i]-1
if(len(a)>0):
if(a[0] - l > res):
res = a[0]-l
if(r - a[-1] > res):
res = r - a[-1]
if(len(a) == 0):
res = r - l + 1
print(res)
``` | instruction | 0 | 9,586 | 4 | 19,172 |
Yes | output | 1 | 9,586 | 4 | 19,173 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Unlucky year in Berland is such a year that its number n can be represented as n = xa + yb, where a and b are non-negative integer numbers.
For example, if x = 2 and y = 3 then the years 4 and 17 are unlucky (4 = 20 + 31, 17 = 23 + 32 = 24 + 30) and year 18 isn't unlucky as there is no such representation for it.
Such interval of years that there are no unlucky years in it is called The Golden Age.
You should write a program which will find maximum length of The Golden Age which starts no earlier than the year l and ends no later than the year r. If all years in the interval [l, r] are unlucky then the answer is 0.
Input
The first line contains four integer numbers x, y, l and r (2 ≤ x, y ≤ 1018, 1 ≤ l ≤ r ≤ 1018).
Output
Print the maximum length of The Golden Age within the interval [l, r].
If all years in the interval [l, r] are unlucky then print 0.
Examples
Input
2 3 1 10
Output
1
Input
3 5 10 22
Output
8
Input
2 3 3 5
Output
0
Note
In the first example the unlucky years are 2, 3, 4, 5, 7, 9 and 10. So maximum length of The Golden Age is achived in the intervals [1, 1], [6, 6] and [8, 8].
In the second example the longest Golden Age is the interval [15, 22].
Submitted Solution:
```
x,y,l,r=map(int,input().split())
p=set()
p.add(l-1)
p.add(r+1)
for i in range(0,80):
s=x**i
if s>r:
break
for j in range(0,80):
t=y**j
if s+t>r:break
elif s+t>=l:
p.add(s+t)
p=sorted(list(p))
#print(p)
ans=0
for i in range(1,len(p)):
ans=max(ans,p[i]-p[i-1]-1)
print (ans)
``` | instruction | 0 | 9,587 | 4 | 19,174 |
Yes | output | 1 | 9,587 | 4 | 19,175 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Unlucky year in Berland is such a year that its number n can be represented as n = xa + yb, where a and b are non-negative integer numbers.
For example, if x = 2 and y = 3 then the years 4 and 17 are unlucky (4 = 20 + 31, 17 = 23 + 32 = 24 + 30) and year 18 isn't unlucky as there is no such representation for it.
Such interval of years that there are no unlucky years in it is called The Golden Age.
You should write a program which will find maximum length of The Golden Age which starts no earlier than the year l and ends no later than the year r. If all years in the interval [l, r] are unlucky then the answer is 0.
Input
The first line contains four integer numbers x, y, l and r (2 ≤ x, y ≤ 1018, 1 ≤ l ≤ r ≤ 1018).
Output
Print the maximum length of The Golden Age within the interval [l, r].
If all years in the interval [l, r] are unlucky then print 0.
Examples
Input
2 3 1 10
Output
1
Input
3 5 10 22
Output
8
Input
2 3 3 5
Output
0
Note
In the first example the unlucky years are 2, 3, 4, 5, 7, 9 and 10. So maximum length of The Golden Age is achived in the intervals [1, 1], [6, 6] and [8, 8].
In the second example the longest Golden Age is the interval [15, 22].
Submitted Solution:
```
x,y,l,r = map(int, input().split())
X = 1
st = set()
while (X <= r):
Y = 1
while (X + Y <= r):
if (X + Y >= l):
st.add(X + Y)
Y *= y
X *= x
bad = sorted([x for x in st])
prev = l
ans = 0
for x in bad:
ans = max(ans, x - prev)
prev = x + 1
ans = max(ans, r - prev + 1)
print(ans)
``` | instruction | 0 | 9,588 | 4 | 19,176 |
Yes | output | 1 | 9,588 | 4 | 19,177 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Unlucky year in Berland is such a year that its number n can be represented as n = xa + yb, where a and b are non-negative integer numbers.
For example, if x = 2 and y = 3 then the years 4 and 17 are unlucky (4 = 20 + 31, 17 = 23 + 32 = 24 + 30) and year 18 isn't unlucky as there is no such representation for it.
Such interval of years that there are no unlucky years in it is called The Golden Age.
You should write a program which will find maximum length of The Golden Age which starts no earlier than the year l and ends no later than the year r. If all years in the interval [l, r] are unlucky then the answer is 0.
Input
The first line contains four integer numbers x, y, l and r (2 ≤ x, y ≤ 1018, 1 ≤ l ≤ r ≤ 1018).
Output
Print the maximum length of The Golden Age within the interval [l, r].
If all years in the interval [l, r] are unlucky then print 0.
Examples
Input
2 3 1 10
Output
1
Input
3 5 10 22
Output
8
Input
2 3 3 5
Output
0
Note
In the first example the unlucky years are 2, 3, 4, 5, 7, 9 and 10. So maximum length of The Golden Age is achived in the intervals [1, 1], [6, 6] and [8, 8].
In the second example the longest Golden Age is the interval [15, 22].
Submitted Solution:
```
x,y,l,r=[int(i) for i in input().split()]
M=int(1e18)
i=1
ul=[]
while (i<=M):
j=1
while (i+j<=M):
ul.append(i+j)
j*=y
i*=x
ul=[0]+sorted(ul)+[M+1]
n=len(ul)
mx=0
for i in range(1,n):
cur=min(ul[i],r+1)-max(l-1,ul[i-1])-1
mx=max(mx,cur)
print(mx)
``` | instruction | 0 | 9,589 | 4 | 19,178 |
Yes | output | 1 | 9,589 | 4 | 19,179 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Unlucky year in Berland is such a year that its number n can be represented as n = xa + yb, where a and b are non-negative integer numbers.
For example, if x = 2 and y = 3 then the years 4 and 17 are unlucky (4 = 20 + 31, 17 = 23 + 32 = 24 + 30) and year 18 isn't unlucky as there is no such representation for it.
Such interval of years that there are no unlucky years in it is called The Golden Age.
You should write a program which will find maximum length of The Golden Age which starts no earlier than the year l and ends no later than the year r. If all years in the interval [l, r] are unlucky then the answer is 0.
Input
The first line contains four integer numbers x, y, l and r (2 ≤ x, y ≤ 1018, 1 ≤ l ≤ r ≤ 1018).
Output
Print the maximum length of The Golden Age within the interval [l, r].
If all years in the interval [l, r] are unlucky then print 0.
Examples
Input
2 3 1 10
Output
1
Input
3 5 10 22
Output
8
Input
2 3 3 5
Output
0
Note
In the first example the unlucky years are 2, 3, 4, 5, 7, 9 and 10. So maximum length of The Golden Age is achived in the intervals [1, 1], [6, 6] and [8, 8].
In the second example the longest Golden Age is the interval [15, 22].
Submitted Solution:
```
from math import log,pow
import enum
x,y,l,r= [int(x) for x in input().split()]
a1 = int(log(l,x))
a2 = int(log(r,x))
s1 = [int(pow(x,a)) for a in range(a1,a2+1)]
print(s1)
b1 = int(log(l,y))
b2 = int(log(r,y))
s2 =[int(pow(y,a)) for a in range(b1,b2+1)]
s3 = []
for b in s1:
for c in s2:
s3.append(b+c)
ans = 0
s3.sort()
print(s3)
for i in range(len(s3)-1):
ans = max(ans, min(r,s3[i+1]-1)-max(l,s3[i]+1) +1)
print(ans)
``` | instruction | 0 | 9,590 | 4 | 19,180 |
No | output | 1 | 9,590 | 4 | 19,181 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Unlucky year in Berland is such a year that its number n can be represented as n = xa + yb, where a and b are non-negative integer numbers.
For example, if x = 2 and y = 3 then the years 4 and 17 are unlucky (4 = 20 + 31, 17 = 23 + 32 = 24 + 30) and year 18 isn't unlucky as there is no such representation for it.
Such interval of years that there are no unlucky years in it is called The Golden Age.
You should write a program which will find maximum length of The Golden Age which starts no earlier than the year l and ends no later than the year r. If all years in the interval [l, r] are unlucky then the answer is 0.
Input
The first line contains four integer numbers x, y, l and r (2 ≤ x, y ≤ 1018, 1 ≤ l ≤ r ≤ 1018).
Output
Print the maximum length of The Golden Age within the interval [l, r].
If all years in the interval [l, r] are unlucky then print 0.
Examples
Input
2 3 1 10
Output
1
Input
3 5 10 22
Output
8
Input
2 3 3 5
Output
0
Note
In the first example the unlucky years are 2, 3, 4, 5, 7, 9 and 10. So maximum length of The Golden Age is achived in the intervals [1, 1], [6, 6] and [8, 8].
In the second example the longest Golden Age is the interval [15, 22].
Submitted Solution:
```
import math
(x,y,l,r) = (int(i) for i in input().split())
vvrs = []
vvrs.append(l)
for i in range(60):
for j in range(60):
cur = x**i + y**j
if cur>r: break
if cur>=l:
vvrs.append(cur)
vvrs.append(r)
vvrs.sort()
maxcnt = 0
for i in range(len(vvrs)-1):
rzn = vvrs[i+1]-vvrs[i]
if rzn>maxcnt: maxcnt = rzn
print(maxcnt-1)
``` | instruction | 0 | 9,591 | 4 | 19,182 |
No | output | 1 | 9,591 | 4 | 19,183 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Unlucky year in Berland is such a year that its number n can be represented as n = xa + yb, where a and b are non-negative integer numbers.
For example, if x = 2 and y = 3 then the years 4 and 17 are unlucky (4 = 20 + 31, 17 = 23 + 32 = 24 + 30) and year 18 isn't unlucky as there is no such representation for it.
Such interval of years that there are no unlucky years in it is called The Golden Age.
You should write a program which will find maximum length of The Golden Age which starts no earlier than the year l and ends no later than the year r. If all years in the interval [l, r] are unlucky then the answer is 0.
Input
The first line contains four integer numbers x, y, l and r (2 ≤ x, y ≤ 1018, 1 ≤ l ≤ r ≤ 1018).
Output
Print the maximum length of The Golden Age within the interval [l, r].
If all years in the interval [l, r] are unlucky then print 0.
Examples
Input
2 3 1 10
Output
1
Input
3 5 10 22
Output
8
Input
2 3 3 5
Output
0
Note
In the first example the unlucky years are 2, 3, 4, 5, 7, 9 and 10. So maximum length of The Golden Age is achived in the intervals [1, 1], [6, 6] and [8, 8].
In the second example the longest Golden Age is the interval [15, 22].
Submitted Solution:
```
x,y,l,r=map(int,input().split())
p=set()
p.add(l-1)
p.add(r+1)
for i in range(0,65):
s=x**i
if x>r:
break
for j in range(0,65):
t=y**j
if s+t>r:break
elif s+t>=l:
p.add(s+t)
p=sorted(list(p))
#print(p)
ans=0
for i in range(1,len(p)):
ans=max(ans,p[i]-p[i-1]-1)
print (ans)
``` | instruction | 0 | 9,592 | 4 | 19,184 |
No | output | 1 | 9,592 | 4 | 19,185 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Unlucky year in Berland is such a year that its number n can be represented as n = xa + yb, where a and b are non-negative integer numbers.
For example, if x = 2 and y = 3 then the years 4 and 17 are unlucky (4 = 20 + 31, 17 = 23 + 32 = 24 + 30) and year 18 isn't unlucky as there is no such representation for it.
Such interval of years that there are no unlucky years in it is called The Golden Age.
You should write a program which will find maximum length of The Golden Age which starts no earlier than the year l and ends no later than the year r. If all years in the interval [l, r] are unlucky then the answer is 0.
Input
The first line contains four integer numbers x, y, l and r (2 ≤ x, y ≤ 1018, 1 ≤ l ≤ r ≤ 1018).
Output
Print the maximum length of The Golden Age within the interval [l, r].
If all years in the interval [l, r] are unlucky then print 0.
Examples
Input
2 3 1 10
Output
1
Input
3 5 10 22
Output
8
Input
2 3 3 5
Output
0
Note
In the first example the unlucky years are 2, 3, 4, 5, 7, 9 and 10. So maximum length of The Golden Age is achived in the intervals [1, 1], [6, 6] and [8, 8].
In the second example the longest Golden Age is the interval [15, 22].
Submitted Solution:
```
s = [int(x) for x in input().split()]
x = s[0]
y = s[1]
l = s[2]
r = s[3]
v = [l - 1, r + 1]
xx = 1
yy = 1
for i in range(64):
yy = 1
for j in range(64):
if(xx + yy <= r):
v.append(xx + yy)
yy = y * yy
else: break
xx = xx * x;
v = sorted(v)
ans = 0
for i in range(len(v)):
ans = max(ans, v[i] - v[i - 1] - 1)
print(ans)
# your code goes here
``` | instruction | 0 | 9,593 | 4 | 19,186 |
No | output | 1 | 9,593 | 4 | 19,187 |
Provide a correct Python 3 solution for this coding contest problem.
I decided to plant vegetables in the vegetable garden. There were n seeds, so I sown n seeds one by one a day over n days. All seeds sprout and grow quickly. I can't wait for the harvest time.
One day, when I was watering the seedlings as usual, I noticed something strange. There should be n vegetable seedlings, but one more. Weeds have grown. I want to pull it out immediately, but the trouble is that all the seedlings are very similar and I can't tell the difference between vegetables and weeds.
The clue is the growth rate of vegetables. This vegetable continues to grow for a fixed length of day after sowing. However, I don't know how many centimeters this "fixed length" is. I also forgot how many days ago I sown the first seed. The seedlings are lined up in a row, but the only thing I remember is that when I sowed the seeds, I planted one seed each day, starting from the right.
Create a program that inputs the length of n + 1 seedlings and outputs the length of weeds.
input
The input consists of multiple datasets. The end of the input is indicated by a single zero line. The input is given in the following format.
n
h1 h2 h3 ... hn + 1
The first line n (4 ≤ n ≤ 100) is an integer representing the number of vegetable seedlings. The second line contains n + 1 integers separated by one space, and hi (1 ≤ hi ≤ 109) indicates the length of the i-th seedling from the left.
No input is given such that h1 h2 ... hn + 1 is an arithmetic progression.
The number of datasets does not exceed 500.
output
Outputs the length of weeds for each dataset.
Example
Input
5
1 2 3 6 4 5
6
1 3 6 9 12 15 18
4
5 7 9 11 12
0
Output
6
1
12 | instruction | 0 | 9,800 | 4 | 19,600 |
"Correct Solution:
```
while 1:
n = int(input())
if n == 0:
break
l = list(map(int,input().split()))
d = [ l[i+1] - l[i] for i in range(n)]
if d[0] == d[n-1]:
for i in range(1,n-1):
if d[i]!= d[0]:
print(l[i+1])
break
elif d[n-1] == d[n-2] and d[n-2] == d[n-3] and d[1] == d[2]:
print(l[0])
elif d[n-1] == d[n-2] and d[n-2] == d[n-3] and d[1] != d[2]:
print(l[1])
elif d[0] == d[1] and d[1] == d[2] and d[n-2] == d[n-3]:
print(l[n])
else:
print(l[n-1])
``` | output | 1 | 9,800 | 4 | 19,601 |
Provide a correct Python 3 solution for this coding contest problem.
I decided to plant vegetables in the vegetable garden. There were n seeds, so I sown n seeds one by one a day over n days. All seeds sprout and grow quickly. I can't wait for the harvest time.
One day, when I was watering the seedlings as usual, I noticed something strange. There should be n vegetable seedlings, but one more. Weeds have grown. I want to pull it out immediately, but the trouble is that all the seedlings are very similar and I can't tell the difference between vegetables and weeds.
The clue is the growth rate of vegetables. This vegetable continues to grow for a fixed length of day after sowing. However, I don't know how many centimeters this "fixed length" is. I also forgot how many days ago I sown the first seed. The seedlings are lined up in a row, but the only thing I remember is that when I sowed the seeds, I planted one seed each day, starting from the right.
Create a program that inputs the length of n + 1 seedlings and outputs the length of weeds.
input
The input consists of multiple datasets. The end of the input is indicated by a single zero line. The input is given in the following format.
n
h1 h2 h3 ... hn + 1
The first line n (4 ≤ n ≤ 100) is an integer representing the number of vegetable seedlings. The second line contains n + 1 integers separated by one space, and hi (1 ≤ hi ≤ 109) indicates the length of the i-th seedling from the left.
No input is given such that h1 h2 ... hn + 1 is an arithmetic progression.
The number of datasets does not exceed 500.
output
Outputs the length of weeds for each dataset.
Example
Input
5
1 2 3 6 4 5
6
1 3 6 9 12 15 18
4
5 7 9 11 12
0
Output
6
1
12 | instruction | 0 | 9,801 | 4 | 19,602 |
"Correct Solution:
```
def check(h):
flag = True
for i in range(len(h)-2):
if h[i+1] - h[i] != h[i+2] - h[i+1]:
flag = False
break
return flag
while True:
n = int(input())
if n == 0:
break
h = [int(i) for i in input().split()]
ans = -1
for k in range(n+1):
tmp = h.pop(k)
if check(h):
print(tmp)
break
h.insert(k, tmp)
``` | output | 1 | 9,801 | 4 | 19,603 |
Provide a correct Python 3 solution for this coding contest problem.
I decided to plant vegetables in the vegetable garden. There were n seeds, so I sown n seeds one by one a day over n days. All seeds sprout and grow quickly. I can't wait for the harvest time.
One day, when I was watering the seedlings as usual, I noticed something strange. There should be n vegetable seedlings, but one more. Weeds have grown. I want to pull it out immediately, but the trouble is that all the seedlings are very similar and I can't tell the difference between vegetables and weeds.
The clue is the growth rate of vegetables. This vegetable continues to grow for a fixed length of day after sowing. However, I don't know how many centimeters this "fixed length" is. I also forgot how many days ago I sown the first seed. The seedlings are lined up in a row, but the only thing I remember is that when I sowed the seeds, I planted one seed each day, starting from the right.
Create a program that inputs the length of n + 1 seedlings and outputs the length of weeds.
input
The input consists of multiple datasets. The end of the input is indicated by a single zero line. The input is given in the following format.
n
h1 h2 h3 ... hn + 1
The first line n (4 ≤ n ≤ 100) is an integer representing the number of vegetable seedlings. The second line contains n + 1 integers separated by one space, and hi (1 ≤ hi ≤ 109) indicates the length of the i-th seedling from the left.
No input is given such that h1 h2 ... hn + 1 is an arithmetic progression.
The number of datasets does not exceed 500.
output
Outputs the length of weeds for each dataset.
Example
Input
5
1 2 3 6 4 5
6
1 3 6 9 12 15 18
4
5 7 9 11 12
0
Output
6
1
12 | instruction | 0 | 9,802 | 4 | 19,604 |
"Correct Solution:
```
import copy
while True:
n = int(input())
if n == 0:
break
h = list(map(int, input().split()))
for i in range(n+1):
k = copy.deepcopy(h)
kanade = k.pop(i)
res = []
for j in range(n-1):
res.append(k[j+1] - k[j])
if all([1 if x == res[0] else 0 for x in res]):
print(kanade)
break
``` | output | 1 | 9,802 | 4 | 19,605 |
Provide a correct Python 3 solution for this coding contest problem.
I decided to plant vegetables in the vegetable garden. There were n seeds, so I sown n seeds one by one a day over n days. All seeds sprout and grow quickly. I can't wait for the harvest time.
One day, when I was watering the seedlings as usual, I noticed something strange. There should be n vegetable seedlings, but one more. Weeds have grown. I want to pull it out immediately, but the trouble is that all the seedlings are very similar and I can't tell the difference between vegetables and weeds.
The clue is the growth rate of vegetables. This vegetable continues to grow for a fixed length of day after sowing. However, I don't know how many centimeters this "fixed length" is. I also forgot how many days ago I sown the first seed. The seedlings are lined up in a row, but the only thing I remember is that when I sowed the seeds, I planted one seed each day, starting from the right.
Create a program that inputs the length of n + 1 seedlings and outputs the length of weeds.
input
The input consists of multiple datasets. The end of the input is indicated by a single zero line. The input is given in the following format.
n
h1 h2 h3 ... hn + 1
The first line n (4 ≤ n ≤ 100) is an integer representing the number of vegetable seedlings. The second line contains n + 1 integers separated by one space, and hi (1 ≤ hi ≤ 109) indicates the length of the i-th seedling from the left.
No input is given such that h1 h2 ... hn + 1 is an arithmetic progression.
The number of datasets does not exceed 500.
output
Outputs the length of weeds for each dataset.
Example
Input
5
1 2 3 6 4 5
6
1 3 6 9 12 15 18
4
5 7 9 11 12
0
Output
6
1
12 | instruction | 0 | 9,803 | 4 | 19,606 |
"Correct Solution:
```
from sys import exit
while(True):
N = int(input())
# print(N)
if N == 0:
break
h = list(map(int, input().split()))
for i in range(N+1):
targ = h[:i] + h[i+1:]
diff = targ[1] - targ[0]
OK = True
for j in range(1, N):
if diff != targ[j] - targ[j-1]:
OK = False
break
if not OK:
continue
else:
print(h[i])
break
``` | output | 1 | 9,803 | 4 | 19,607 |
Provide a correct Python 3 solution for this coding contest problem.
I decided to plant vegetables in the vegetable garden. There were n seeds, so I sown n seeds one by one a day over n days. All seeds sprout and grow quickly. I can't wait for the harvest time.
One day, when I was watering the seedlings as usual, I noticed something strange. There should be n vegetable seedlings, but one more. Weeds have grown. I want to pull it out immediately, but the trouble is that all the seedlings are very similar and I can't tell the difference between vegetables and weeds.
The clue is the growth rate of vegetables. This vegetable continues to grow for a fixed length of day after sowing. However, I don't know how many centimeters this "fixed length" is. I also forgot how many days ago I sown the first seed. The seedlings are lined up in a row, but the only thing I remember is that when I sowed the seeds, I planted one seed each day, starting from the right.
Create a program that inputs the length of n + 1 seedlings and outputs the length of weeds.
input
The input consists of multiple datasets. The end of the input is indicated by a single zero line. The input is given in the following format.
n
h1 h2 h3 ... hn + 1
The first line n (4 ≤ n ≤ 100) is an integer representing the number of vegetable seedlings. The second line contains n + 1 integers separated by one space, and hi (1 ≤ hi ≤ 109) indicates the length of the i-th seedling from the left.
No input is given such that h1 h2 ... hn + 1 is an arithmetic progression.
The number of datasets does not exceed 500.
output
Outputs the length of weeds for each dataset.
Example
Input
5
1 2 3 6 4 5
6
1 3 6 9 12 15 18
4
5 7 9 11 12
0
Output
6
1
12 | instruction | 0 | 9,804 | 4 | 19,608 |
"Correct Solution:
```
while True:
n = int(input())
if n == 0:
break
h = list(map(int,input().split()))
for i in range(n+1):
s = 0
if i == 0:
s = 1
d = None
k = 1
cnt = 0
for j in range(s+1,n+1):
if j == i:
continue
if d == None:
d = h[j]-h[s]
elif h[j]-h[s] != d*k:
cnt += 1
k += 1
if cnt == 0:
print(h[i])
break
``` | output | 1 | 9,804 | 4 | 19,609 |
Provide a correct Python 3 solution for this coding contest problem.
I decided to plant vegetables in the vegetable garden. There were n seeds, so I sown n seeds one by one a day over n days. All seeds sprout and grow quickly. I can't wait for the harvest time.
One day, when I was watering the seedlings as usual, I noticed something strange. There should be n vegetable seedlings, but one more. Weeds have grown. I want to pull it out immediately, but the trouble is that all the seedlings are very similar and I can't tell the difference between vegetables and weeds.
The clue is the growth rate of vegetables. This vegetable continues to grow for a fixed length of day after sowing. However, I don't know how many centimeters this "fixed length" is. I also forgot how many days ago I sown the first seed. The seedlings are lined up in a row, but the only thing I remember is that when I sowed the seeds, I planted one seed each day, starting from the right.
Create a program that inputs the length of n + 1 seedlings and outputs the length of weeds.
input
The input consists of multiple datasets. The end of the input is indicated by a single zero line. The input is given in the following format.
n
h1 h2 h3 ... hn + 1
The first line n (4 ≤ n ≤ 100) is an integer representing the number of vegetable seedlings. The second line contains n + 1 integers separated by one space, and hi (1 ≤ hi ≤ 109) indicates the length of the i-th seedling from the left.
No input is given such that h1 h2 ... hn + 1 is an arithmetic progression.
The number of datasets does not exceed 500.
output
Outputs the length of weeds for each dataset.
Example
Input
5
1 2 3 6 4 5
6
1 3 6 9 12 15 18
4
5 7 9 11 12
0
Output
6
1
12 | instruction | 0 | 9,805 | 4 | 19,610 |
"Correct Solution:
```
from collections import Counter
while 1:
n = int(input())
if n == 0:break
a = tuple(map(int, input().split()))
b = [a[i + 1] - a[i] for i in range(n)]
d = Counter(b).most_common()[0][0]
for i in range(n):
if b[i] != d:
if i < n - 1 and b[i + 1] == d:print(a[i])
else:print(a[i + 1])
break
``` | output | 1 | 9,805 | 4 | 19,611 |
Provide a correct Python 3 solution for this coding contest problem.
I decided to plant vegetables in the vegetable garden. There were n seeds, so I sown n seeds one by one a day over n days. All seeds sprout and grow quickly. I can't wait for the harvest time.
One day, when I was watering the seedlings as usual, I noticed something strange. There should be n vegetable seedlings, but one more. Weeds have grown. I want to pull it out immediately, but the trouble is that all the seedlings are very similar and I can't tell the difference between vegetables and weeds.
The clue is the growth rate of vegetables. This vegetable continues to grow for a fixed length of day after sowing. However, I don't know how many centimeters this "fixed length" is. I also forgot how many days ago I sown the first seed. The seedlings are lined up in a row, but the only thing I remember is that when I sowed the seeds, I planted one seed each day, starting from the right.
Create a program that inputs the length of n + 1 seedlings and outputs the length of weeds.
input
The input consists of multiple datasets. The end of the input is indicated by a single zero line. The input is given in the following format.
n
h1 h2 h3 ... hn + 1
The first line n (4 ≤ n ≤ 100) is an integer representing the number of vegetable seedlings. The second line contains n + 1 integers separated by one space, and hi (1 ≤ hi ≤ 109) indicates the length of the i-th seedling from the left.
No input is given such that h1 h2 ... hn + 1 is an arithmetic progression.
The number of datasets does not exceed 500.
output
Outputs the length of weeds for each dataset.
Example
Input
5
1 2 3 6 4 5
6
1 3 6 9 12 15 18
4
5 7 9 11 12
0
Output
6
1
12 | instruction | 0 | 9,806 | 4 | 19,612 |
"Correct Solution:
```
while True:
n = int(input())
if n == 0:
break
lst = list(map(int, input().split()))
for i in range(n + 1):
sample = lst[:i] + lst[i + 1:]
correct = [sample[0] + (sample[1] - sample[0]) * j for j in range(n)]
if sample == correct:
print(lst[i])
break
``` | output | 1 | 9,806 | 4 | 19,613 |
Provide a correct Python 3 solution for this coding contest problem.
I decided to plant vegetables in the vegetable garden. There were n seeds, so I sown n seeds one by one a day over n days. All seeds sprout and grow quickly. I can't wait for the harvest time.
One day, when I was watering the seedlings as usual, I noticed something strange. There should be n vegetable seedlings, but one more. Weeds have grown. I want to pull it out immediately, but the trouble is that all the seedlings are very similar and I can't tell the difference between vegetables and weeds.
The clue is the growth rate of vegetables. This vegetable continues to grow for a fixed length of day after sowing. However, I don't know how many centimeters this "fixed length" is. I also forgot how many days ago I sown the first seed. The seedlings are lined up in a row, but the only thing I remember is that when I sowed the seeds, I planted one seed each day, starting from the right.
Create a program that inputs the length of n + 1 seedlings and outputs the length of weeds.
input
The input consists of multiple datasets. The end of the input is indicated by a single zero line. The input is given in the following format.
n
h1 h2 h3 ... hn + 1
The first line n (4 ≤ n ≤ 100) is an integer representing the number of vegetable seedlings. The second line contains n + 1 integers separated by one space, and hi (1 ≤ hi ≤ 109) indicates the length of the i-th seedling from the left.
No input is given such that h1 h2 ... hn + 1 is an arithmetic progression.
The number of datasets does not exceed 500.
output
Outputs the length of weeds for each dataset.
Example
Input
5
1 2 3 6 4 5
6
1 3 6 9 12 15 18
4
5 7 9 11 12
0
Output
6
1
12 | instruction | 0 | 9,807 | 4 | 19,614 |
"Correct Solution:
```
while 1:
N = int(input())
if N == 0:
break
*H, = map(int, input().split())
def gen(k):
for i in range(N+1):
if i == k:
continue
yield H[i]
for i in range(N+1):
ok = 1
g = gen(i).__next__
h0 = g(); h1 = g()
d = h1 - h0
for j in range(N-2):
h2 = g()
if h2 - h1 != d:
ok = 0
break
h1 = h2
if ok:
print(H[i])
break
``` | output | 1 | 9,807 | 4 | 19,615 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The new camp by widely-known over the country Spring Programming Camp is going to start soon. Hence, all the team of friendly curators and teachers started composing the camp's schedule. After some continuous discussion, they came up with a schedule s, which can be represented as a binary string, in which the i-th symbol is '1' if students will write the contest in the i-th day and '0' if they will have a day off.
At the last moment Gleb said that the camp will be the most productive if it runs with the schedule t (which can be described in the same format as schedule s). Since the number of days in the current may be different from number of days in schedule t, Gleb required that the camp's schedule must be altered so that the number of occurrences of t in it as a substring is maximum possible. At the same time, the number of contest days and days off shouldn't change, only their order may change.
Could you rearrange the schedule in the best possible way?
Input
The first line contains string s (1 ⩽ |s| ⩽ 500 000), denoting the current project of the camp's schedule.
The second line contains string t (1 ⩽ |t| ⩽ 500 000), denoting the optimal schedule according to Gleb.
Strings s and t contain characters '0' and '1' only.
Output
In the only line print the schedule having the largest number of substrings equal to t. Printed schedule should consist of characters '0' and '1' only and the number of zeros should be equal to the number of zeros in s and the number of ones should be equal to the number of ones in s.
In case there multiple optimal schedules, print any of them.
Examples
Input
101101
110
Output
110110
Input
10010110
100011
Output
01100011
Input
10
11100
Output
01
Note
In the first example there are two occurrences, one starting from first position and one starting from fourth position.
In the second example there is only one occurrence, which starts from third position. Note, that the answer is not unique. For example, if we move the first day (which is a day off) to the last position, the number of occurrences of t wouldn't change.
In the third example it's impossible to make even a single occurrence. | instruction | 0 | 9,956 | 4 | 19,912 |
Tags: greedy, hashing, strings
Correct Solution:
```
s = input()
t = input()
lens,lent=len(s),len(t)
from sys import exit
if lens<lent:print(s);exit()
else:
onet,zerot=0,0
for i,x in enumerate(t):
if x=='0':zerot+=1
else:onet+=1
ones,zeros=0,0
for i,x in enumerate(s):
if x=='0':zeros+=1
else:ones+=1
res=''
if onet<=ones and zerot<=zeros:
res,ones,zeros=t,ones-onet,zeros-zerot
if ones==0 and zeros==0:
print(res);exit()
else:print(s);exit()
item,k,ot,zt,ont,zet='',lent,0,0,0,0
for i in range(lent-1):
if t[i]=='1':ot+=1
else:zt+=1
item+=t[i]
if t[lent-i-1:]==item:
k,ont,zet=i,ot,zt
ont,zet=onet-ont,zerot-zet
if k<lent:plus=t[k+1:]
else:plus=t
while ont<=ones and zet<=zeros:
res+=plus
ones-=ont
zeros-=zet
res+='1'*ones+'0'*zeros
print(res)
``` | output | 1 | 9,956 | 4 | 19,913 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The new camp by widely-known over the country Spring Programming Camp is going to start soon. Hence, all the team of friendly curators and teachers started composing the camp's schedule. After some continuous discussion, they came up with a schedule s, which can be represented as a binary string, in which the i-th symbol is '1' if students will write the contest in the i-th day and '0' if they will have a day off.
At the last moment Gleb said that the camp will be the most productive if it runs with the schedule t (which can be described in the same format as schedule s). Since the number of days in the current may be different from number of days in schedule t, Gleb required that the camp's schedule must be altered so that the number of occurrences of t in it as a substring is maximum possible. At the same time, the number of contest days and days off shouldn't change, only their order may change.
Could you rearrange the schedule in the best possible way?
Input
The first line contains string s (1 ⩽ |s| ⩽ 500 000), denoting the current project of the camp's schedule.
The second line contains string t (1 ⩽ |t| ⩽ 500 000), denoting the optimal schedule according to Gleb.
Strings s and t contain characters '0' and '1' only.
Output
In the only line print the schedule having the largest number of substrings equal to t. Printed schedule should consist of characters '0' and '1' only and the number of zeros should be equal to the number of zeros in s and the number of ones should be equal to the number of ones in s.
In case there multiple optimal schedules, print any of them.
Examples
Input
101101
110
Output
110110
Input
10010110
100011
Output
01100011
Input
10
11100
Output
01
Note
In the first example there are two occurrences, one starting from first position and one starting from fourth position.
In the second example there is only one occurrence, which starts from third position. Note, that the answer is not unique. For example, if we move the first day (which is a day off) to the last position, the number of occurrences of t wouldn't change.
In the third example it's impossible to make even a single occurrence. | instruction | 0 | 9,957 | 4 | 19,914 |
Tags: greedy, hashing, strings
Correct Solution:
```
import sys
s=sys.stdin.readline()[:-1]
t=sys.stdin.readline()[:-1]
count0,count1=0,0
n,m=len(s),len(t)
for i in range(n):
if s[i]=='0':
count0+=1
continue
count1+=1
#print(count0,'count0',count1,'count1')
lps=[0 for _ in range(m)]
i,j=1,0
while i<m:
if t[i]==t[j]:
j+=1
lps[i]=j
i+=1
else:
if j!=0:
j=lps[j-1]
else:
lps[i]=0
i+=1
#print(lps,'lps')
x=lps[-1]
z=True
i,j=0,0
ans=[0 for _ in range(n)]
while z:
if t[i]=='1':
if count1>0:
ans[j]='1'
count1-=1
i+=1
j+=1
if i==m:
i=x
else:
z=False
else:
if count0>0:
ans[j]='0'
count0-=1
i+=1
j+=1
if i==m:
i=x
else:
z=False
while count0>0:
ans[j]='0'
j+=1
count0-=1
while count1>0:
ans[j]='1'
j+=1
count1-=1
print(''.join(x for x in ans))
``` | output | 1 | 9,957 | 4 | 19,915 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The new camp by widely-known over the country Spring Programming Camp is going to start soon. Hence, all the team of friendly curators and teachers started composing the camp's schedule. After some continuous discussion, they came up with a schedule s, which can be represented as a binary string, in which the i-th symbol is '1' if students will write the contest in the i-th day and '0' if they will have a day off.
At the last moment Gleb said that the camp will be the most productive if it runs with the schedule t (which can be described in the same format as schedule s). Since the number of days in the current may be different from number of days in schedule t, Gleb required that the camp's schedule must be altered so that the number of occurrences of t in it as a substring is maximum possible. At the same time, the number of contest days and days off shouldn't change, only their order may change.
Could you rearrange the schedule in the best possible way?
Input
The first line contains string s (1 ⩽ |s| ⩽ 500 000), denoting the current project of the camp's schedule.
The second line contains string t (1 ⩽ |t| ⩽ 500 000), denoting the optimal schedule according to Gleb.
Strings s and t contain characters '0' and '1' only.
Output
In the only line print the schedule having the largest number of substrings equal to t. Printed schedule should consist of characters '0' and '1' only and the number of zeros should be equal to the number of zeros in s and the number of ones should be equal to the number of ones in s.
In case there multiple optimal schedules, print any of them.
Examples
Input
101101
110
Output
110110
Input
10010110
100011
Output
01100011
Input
10
11100
Output
01
Note
In the first example there are two occurrences, one starting from first position and one starting from fourth position.
In the second example there is only one occurrence, which starts from third position. Note, that the answer is not unique. For example, if we move the first day (which is a day off) to the last position, the number of occurrences of t wouldn't change.
In the third example it's impossible to make even a single occurrence. | instruction | 0 | 9,958 | 4 | 19,916 |
Tags: greedy, hashing, strings
Correct Solution:
```
import sys
input=sys.stdin.readline
def z_algorithm(s):
res=[0]*len(s)
res[0]=len(s)
i,j=1,0
while i<len(s):
while i+j<len(s) and s[j]==s[i+j]:
j+=1
res[i]=j
if j==0:
i+=1
continue
k = 1
while i+k<len(s) and k+res[k]<j:
res[i+k]=res[k]
k+=1
i,j=i+k,j-k
return res
s=input().rstrip()
t=input().rstrip()
cnt=[0]*2
for i in range(len(s)):
cnt[int(s[i])]+=1
tbl=z_algorithm(t)
for lap in range(1,len(t)+1):
i=0
while i<len(t):
if tbl[i]!=len(t)-i:
break
i+=lap
else:
break
t=t[0:lap]
ans=[]
while True:
for c in t:
if cnt[int(c)]>0:
cnt[int(c)]-=1
ans.append(c)
else:
break
else:
continue
break
ans.extend(["0"]*cnt[0]+["1"]*cnt[1])
print("".join(ans))
``` | output | 1 | 9,958 | 4 | 19,917 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The new camp by widely-known over the country Spring Programming Camp is going to start soon. Hence, all the team of friendly curators and teachers started composing the camp's schedule. After some continuous discussion, they came up with a schedule s, which can be represented as a binary string, in which the i-th symbol is '1' if students will write the contest in the i-th day and '0' if they will have a day off.
At the last moment Gleb said that the camp will be the most productive if it runs with the schedule t (which can be described in the same format as schedule s). Since the number of days in the current may be different from number of days in schedule t, Gleb required that the camp's schedule must be altered so that the number of occurrences of t in it as a substring is maximum possible. At the same time, the number of contest days and days off shouldn't change, only their order may change.
Could you rearrange the schedule in the best possible way?
Input
The first line contains string s (1 ⩽ |s| ⩽ 500 000), denoting the current project of the camp's schedule.
The second line contains string t (1 ⩽ |t| ⩽ 500 000), denoting the optimal schedule according to Gleb.
Strings s and t contain characters '0' and '1' only.
Output
In the only line print the schedule having the largest number of substrings equal to t. Printed schedule should consist of characters '0' and '1' only and the number of zeros should be equal to the number of zeros in s and the number of ones should be equal to the number of ones in s.
In case there multiple optimal schedules, print any of them.
Examples
Input
101101
110
Output
110110
Input
10010110
100011
Output
01100011
Input
10
11100
Output
01
Note
In the first example there are two occurrences, one starting from first position and one starting from fourth position.
In the second example there is only one occurrence, which starts from third position. Note, that the answer is not unique. For example, if we move the first day (which is a day off) to the last position, the number of occurrences of t wouldn't change.
In the third example it's impossible to make even a single occurrence. | instruction | 0 | 9,959 | 4 | 19,918 |
Tags: greedy, hashing, strings
Correct Solution:
```
import sys
input = sys.stdin.readline
def MP(s):
a = [0] * (len(s) + 1)
a[0] = -1
j = -1
for i in range(len(s)):
while j >= 0 and s[i] != s[j]:
j = a[j]
j += 1
a[i + 1] = j
return a
s = input()[:-1]
t = input()[:-1]
cnt = [0, 0]
for char in s:
cnt[int(char)] += 1
tbl = MP(t)
lap = len(tbl) - tbl[-1] - 1
t = t[0:lap]
ans = []
while True:
for char in t:
if cnt[int(char)] > 0:
ans.append(char)
cnt[int(char)] -= 1
else:
break
else:
continue
break
for i in range(cnt[0]):
ans.append("0")
for i in range(cnt[1]):
ans.append("1")
print(''.join(ans))
``` | output | 1 | 9,959 | 4 | 19,919 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The new camp by widely-known over the country Spring Programming Camp is going to start soon. Hence, all the team of friendly curators and teachers started composing the camp's schedule. After some continuous discussion, they came up with a schedule s, which can be represented as a binary string, in which the i-th symbol is '1' if students will write the contest in the i-th day and '0' if they will have a day off.
At the last moment Gleb said that the camp will be the most productive if it runs with the schedule t (which can be described in the same format as schedule s). Since the number of days in the current may be different from number of days in schedule t, Gleb required that the camp's schedule must be altered so that the number of occurrences of t in it as a substring is maximum possible. At the same time, the number of contest days and days off shouldn't change, only their order may change.
Could you rearrange the schedule in the best possible way?
Input
The first line contains string s (1 ⩽ |s| ⩽ 500 000), denoting the current project of the camp's schedule.
The second line contains string t (1 ⩽ |t| ⩽ 500 000), denoting the optimal schedule according to Gleb.
Strings s and t contain characters '0' and '1' only.
Output
In the only line print the schedule having the largest number of substrings equal to t. Printed schedule should consist of characters '0' and '1' only and the number of zeros should be equal to the number of zeros in s and the number of ones should be equal to the number of ones in s.
In case there multiple optimal schedules, print any of them.
Examples
Input
101101
110
Output
110110
Input
10010110
100011
Output
01100011
Input
10
11100
Output
01
Note
In the first example there are two occurrences, one starting from first position and one starting from fourth position.
In the second example there is only one occurrence, which starts from third position. Note, that the answer is not unique. For example, if we move the first day (which is a day off) to the last position, the number of occurrences of t wouldn't change.
In the third example it's impossible to make even a single occurrence. | instruction | 0 | 9,960 | 4 | 19,920 |
Tags: greedy, hashing, strings
Correct Solution:
```
# import time
import random
def helper(s):
size = len(s)
c_l, c_r = [0, 0], [0, 0]
candidate_overlaps = []
for i in range(size):
if s[i] == '0':
c_l[0] += 1
else:
c_l[1] += 1
if s[size - 1 - i] == '0':
c_r[0] += 1
else:
c_r[1] += 1
if c_l == c_r:
candidate_overlaps.append(i + 1)
# Get ride of the trivial overlap size, with is the length of s.
candidate_overlaps.pop()
result = 0
# print('candidates:', candidate_overlaps)
for overlap in reversed(candidate_overlaps):
# print('overlap:', overlap)
delta = size - overlap
# print('delta:', delta)
found = True
for start in range(overlap):
if s[start] != s[start + delta]:
found = False
break
if found:
result = overlap
break
return result
def counter(s):
a, b = 0, 0
for ele in s:
if ele == '0':
a += 1
else:
b += 1
return a, b
def test_helper():
i = [''.join(('1' if random.random() > .05 else '0' for i in range(500000)))]
i = ['1'] * 500000
i[-2] = '0'
i = [''.join(i)]
i = ['101', '110']
print('haha')
for ele in i:
print(helper(ele))
def solve(s, t):
s_0, s_1 = counter(s)
m = helper(t)
t_repeat = t[:m]
t_remain = t[m:]
t_repeat_0, t_repeat_1 = counter(t_repeat)
t_remain_0, t_remain_1 = counter(t_remain)
if t_repeat_0 > s_0 or t_repeat_1 > s_1:
return s
result = []
s_0 -= t_repeat_0
s_1 -= t_repeat_1
result.append(t_repeat)
if t_remain_0 == 0:
n = s_1 // t_remain_1
elif t_remain_1 == 0:
n = s_0 // t_remain_0
else:
n = min(s_0 // t_remain_0, s_1 // t_remain_1)
s_0 -= n * t_remain_0
s_1 -= n * t_remain_1
result.append(t_remain * n)
result.append('0' * s_0)
result.append('1' * s_1)
return ''.join(result)
def main():
# Deal with input.
s = input()
t = input()
# tick = time.time()
result = solve(s, t)
# tock = time.time()
# Deal with output.
print(result)
# Printe time.
# print('T:', round(tock - tick ,5))
def test():
pass
if __name__ == "__main__":
main()
``` | output | 1 | 9,960 | 4 | 19,921 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The new camp by widely-known over the country Spring Programming Camp is going to start soon. Hence, all the team of friendly curators and teachers started composing the camp's schedule. After some continuous discussion, they came up with a schedule s, which can be represented as a binary string, in which the i-th symbol is '1' if students will write the contest in the i-th day and '0' if they will have a day off.
At the last moment Gleb said that the camp will be the most productive if it runs with the schedule t (which can be described in the same format as schedule s). Since the number of days in the current may be different from number of days in schedule t, Gleb required that the camp's schedule must be altered so that the number of occurrences of t in it as a substring is maximum possible. At the same time, the number of contest days and days off shouldn't change, only their order may change.
Could you rearrange the schedule in the best possible way?
Input
The first line contains string s (1 ⩽ |s| ⩽ 500 000), denoting the current project of the camp's schedule.
The second line contains string t (1 ⩽ |t| ⩽ 500 000), denoting the optimal schedule according to Gleb.
Strings s and t contain characters '0' and '1' only.
Output
In the only line print the schedule having the largest number of substrings equal to t. Printed schedule should consist of characters '0' and '1' only and the number of zeros should be equal to the number of zeros in s and the number of ones should be equal to the number of ones in s.
In case there multiple optimal schedules, print any of them.
Examples
Input
101101
110
Output
110110
Input
10010110
100011
Output
01100011
Input
10
11100
Output
01
Note
In the first example there are two occurrences, one starting from first position and one starting from fourth position.
In the second example there is only one occurrence, which starts from third position. Note, that the answer is not unique. For example, if we move the first day (which is a day off) to the last position, the number of occurrences of t wouldn't change.
In the third example it's impossible to make even a single occurrence. | instruction | 0 | 9,961 | 4 | 19,922 |
Tags: greedy, hashing, strings
Correct Solution:
```
s = input()
t = input()
overlap = t
tt = ''
for i in range(len(t) - 1):
tt = tt + t[i]
if (t.endswith(tt)):
overlap = t[i + 1:]
zro = s.count('0')
mek = s.count('1')
zro_tum = t.count('0')
mek_tum = t.count('1')
zro_toxum = overlap.count('0')
mek_toxum = overlap.count('1')
if (zro >= zro_tum and mek >= mek_tum):
print(t, end='')
zro -= zro_tum
mek -= mek_tum
if zro_toxum:
k = zro//zro_toxum
else:
k = 10000000000
if mek_toxum:
n = mek//mek_toxum
else:
n = 10000000000
ans = min(n, k)
print(overlap * ans, end='')
zro -= zro_toxum * ans
mek -= mek_toxum * ans
print('0' * zro + '1' * mek)
``` | output | 1 | 9,961 | 4 | 19,923 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The new camp by widely-known over the country Spring Programming Camp is going to start soon. Hence, all the team of friendly curators and teachers started composing the camp's schedule. After some continuous discussion, they came up with a schedule s, which can be represented as a binary string, in which the i-th symbol is '1' if students will write the contest in the i-th day and '0' if they will have a day off.
At the last moment Gleb said that the camp will be the most productive if it runs with the schedule t (which can be described in the same format as schedule s). Since the number of days in the current may be different from number of days in schedule t, Gleb required that the camp's schedule must be altered so that the number of occurrences of t in it as a substring is maximum possible. At the same time, the number of contest days and days off shouldn't change, only their order may change.
Could you rearrange the schedule in the best possible way?
Input
The first line contains string s (1 ⩽ |s| ⩽ 500 000), denoting the current project of the camp's schedule.
The second line contains string t (1 ⩽ |t| ⩽ 500 000), denoting the optimal schedule according to Gleb.
Strings s and t contain characters '0' and '1' only.
Output
In the only line print the schedule having the largest number of substrings equal to t. Printed schedule should consist of characters '0' and '1' only and the number of zeros should be equal to the number of zeros in s and the number of ones should be equal to the number of ones in s.
In case there multiple optimal schedules, print any of them.
Examples
Input
101101
110
Output
110110
Input
10010110
100011
Output
01100011
Input
10
11100
Output
01
Note
In the first example there are two occurrences, one starting from first position and one starting from fourth position.
In the second example there is only one occurrence, which starts from third position. Note, that the answer is not unique. For example, if we move the first day (which is a day off) to the last position, the number of occurrences of t wouldn't change.
In the third example it's impossible to make even a single occurrence. | instruction | 0 | 9,962 | 4 | 19,924 |
Tags: greedy, hashing, strings
Correct Solution:
```
from collections import defaultdict
def Prefix_Array(t):
m=len(t)
arr=[-1]*m
k=-1
for i in range(1,m):
while k>-1 and t[k+1]!=t[i]:
k=arr[k]
if t[k+1]==t[i]:
k+=1
arr[i]=k
#print(arr)
return arr[-1]
def fun(ds,dt):
check=Prefix_Array(t)
if check==-1:
if ds['1']<dt['1'] or ds['0']<dt['0']:
return s
if dt['1']==0 and ds['0']!=0:
n=ds['0']//dt['0']
temp=t*n
ds['0']-=n*dt['0']
while ds['1']>0:
temp+='1'
ds['1']-=1
while ds['0']>0:
temp+='0'
ds['0']-=1
return temp
if dt['0']==0 and ds['1']!=0:
n=ds['1']//dt['1']
temp=t*n
ds['1']-=n*dt['1']
while ds['1']>0:
temp+='1'
ds['1']-=1
while ds['0']>0:
temp+='0'
ds['0']-=1
return temp
m1=ds['1']//dt['1']
m2=ds['0']//dt['0']
n=min(m1,m2)
temp=t*n
ds['1']-=n*dt['1']
ds['0']-=n*dt['0']
while ds['1']>0:
temp+='1'
ds['1']-=1
while ds['0']>0:
temp+='0'
ds['0']-=1
return temp
else:
if ds['1']<dt['1'] or ds['0']<dt['0']:
return s
r=t[check+1:]
dr=defaultdict(int)
for v in r:
dr[v]+=1
temp=t
ds['1']-=dt['1']
ds['0']-=dt['0']
if ds['1']<dr['1'] or ds['0']<dr['0']:
while ds['1']>0:
temp+='1'
ds['1']-=1
while ds['0']>0:
temp+='0'
ds['0']-=1
return temp
if dr['1']==0 and ds['0']!=0:
n=ds['0']//dr['0']
temp+=r*n
ds['0']-=n*dr['0']
while ds['1']>0:
temp+='1'
ds['1']-=1
while ds['0']>0:
temp+='0'
ds['0']-=1
return temp
if dr['0']==0 and ds['1']!=0:
n=ds['1']//dr['1']
temp+=r*n
ds['1']-=n*dr['1']
while ds['1']>0:
temp+='1'
ds['1']-=1
while ds['0']>0:
temp+='0'
ds['0']-=1
return temp
m1=ds['1']//dr['1']
m2=ds['0']//dr['0']
n=min(m1,m2)
temp+=r*n
ds['1']-=n*dr['1']
ds['0']-=n*dr['0']
while ds['1']>0:
temp+='1'
ds['1']-=1
while ds['0']>0:
temp+='0'
ds['0']-=1
return temp
s=input()
t=input()
ds=defaultdict(int)
dt=defaultdict(int)
for c in s:
ds[c]+=1
for c in t:
dt[c]+=1
print(fun(ds,dt))
``` | output | 1 | 9,962 | 4 | 19,925 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The new camp by widely-known over the country Spring Programming Camp is going to start soon. Hence, all the team of friendly curators and teachers started composing the camp's schedule. After some continuous discussion, they came up with a schedule s, which can be represented as a binary string, in which the i-th symbol is '1' if students will write the contest in the i-th day and '0' if they will have a day off.
At the last moment Gleb said that the camp will be the most productive if it runs with the schedule t (which can be described in the same format as schedule s). Since the number of days in the current may be different from number of days in schedule t, Gleb required that the camp's schedule must be altered so that the number of occurrences of t in it as a substring is maximum possible. At the same time, the number of contest days and days off shouldn't change, only their order may change.
Could you rearrange the schedule in the best possible way?
Input
The first line contains string s (1 ⩽ |s| ⩽ 500 000), denoting the current project of the camp's schedule.
The second line contains string t (1 ⩽ |t| ⩽ 500 000), denoting the optimal schedule according to Gleb.
Strings s and t contain characters '0' and '1' only.
Output
In the only line print the schedule having the largest number of substrings equal to t. Printed schedule should consist of characters '0' and '1' only and the number of zeros should be equal to the number of zeros in s and the number of ones should be equal to the number of ones in s.
In case there multiple optimal schedules, print any of them.
Examples
Input
101101
110
Output
110110
Input
10010110
100011
Output
01100011
Input
10
11100
Output
01
Note
In the first example there are two occurrences, one starting from first position and one starting from fourth position.
In the second example there is only one occurrence, which starts from third position. Note, that the answer is not unique. For example, if we move the first day (which is a day off) to the last position, the number of occurrences of t wouldn't change.
In the third example it's impossible to make even a single occurrence. | instruction | 0 | 9,963 | 4 | 19,926 |
Tags: greedy, hashing, strings
Correct Solution:
```
s = input()
t = input()
s_count = 0
t_count = 0
s_count_0 = 0
t_count_0 = 0
for i in s:
if i is '1':
s_count += 1
for i in t:
if i is '1':
t_count += 1
s_count_0 = len(s) - s_count
t_count_0 = len(t) - t_count
match = [0]
j = 0
i = 1
while i < len(t):
while t[j] is not t[i]:
j -= 1
if j < 0:
break
j = match[j]
if j < 0:
j = 0
match.append(0)
else:
match.append(j+1)
j += 1
i += 1
remaining_1 = s_count - t_count
remaining_0 = s_count_0 - t_count_0
if remaining_0 < 0 or remaining_1 < 0:
print(s)
exit(0)
for a in t[:match[-1]]:
if a is '1':
t_count -= 1
else:
t_count_0 -= 1
result = [t]
if t_count is not 0 and t_count_0 is not 0:
val = int(min(remaining_1/t_count, remaining_0/t_count_0))
elif t_count is 0:
val = int(remaining_0/t_count_0)
else:
val = int(remaining_1/t_count)
for _ in range(val):
result.append(t[match[-1]:])
for _ in range(remaining_0 - val * t_count_0):
result.append('0')
for _ in range(remaining_1 - val * t_count):
result.append('1')
print("".join(result))
``` | output | 1 | 9,963 | 4 | 19,927 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The new camp by widely-known over the country Spring Programming Camp is going to start soon. Hence, all the team of friendly curators and teachers started composing the camp's schedule. After some continuous discussion, they came up with a schedule s, which can be represented as a binary string, in which the i-th symbol is '1' if students will write the contest in the i-th day and '0' if they will have a day off.
At the last moment Gleb said that the camp will be the most productive if it runs with the schedule t (which can be described in the same format as schedule s). Since the number of days in the current may be different from number of days in schedule t, Gleb required that the camp's schedule must be altered so that the number of occurrences of t in it as a substring is maximum possible. At the same time, the number of contest days and days off shouldn't change, only their order may change.
Could you rearrange the schedule in the best possible way?
Input
The first line contains string s (1 ⩽ |s| ⩽ 500 000), denoting the current project of the camp's schedule.
The second line contains string t (1 ⩽ |t| ⩽ 500 000), denoting the optimal schedule according to Gleb.
Strings s and t contain characters '0' and '1' only.
Output
In the only line print the schedule having the largest number of substrings equal to t. Printed schedule should consist of characters '0' and '1' only and the number of zeros should be equal to the number of zeros in s and the number of ones should be equal to the number of ones in s.
In case there multiple optimal schedules, print any of them.
Examples
Input
101101
110
Output
110110
Input
10010110
100011
Output
01100011
Input
10
11100
Output
01
Note
In the first example there are two occurrences, one starting from first position and one starting from fourth position.
In the second example there is only one occurrence, which starts from third position. Note, that the answer is not unique. For example, if we move the first day (which is a day off) to the last position, the number of occurrences of t wouldn't change.
In the third example it's impossible to make even a single occurrence.
Submitted Solution:
```
def longestPrefixSuffix(s,n):
lps = [0 for i in range(n)]
l = 0
i = 1
while(i<n):
if(s[i] == s[l]):
l += 1
lps[i] = l
i += 1
else:
if(l!=0):
l = lps[l-1]
else:
lps[i] = 0
i += 1
res = lps[n-1]
return res
s1 = input()
s2 = input()
n1 = len(s1)
n2 = len(s2)
lcsp = longestPrefixSuffix(s2 ,n2)
no_1 = s1.count('1')
no_0 = n1 - no_1
re_1 = s2.count('1')
re_0 = n2 - re_1
if(re_1>no_1 or re_0 > no_0):
print(s1)
else:
ans = s2
no_1 = no_1 - re_1
no_0 = no_0 - re_0
#print(lcsp, no_1, no_0, re_1 , re_0,ans)
re_1 = re_1 - s2[:lcsp].count('1')
re_0 = re_0 - s2[:lcsp].count('0')
#print(lcsp, no_1, no_0, re_1 , re_0,ans)
if(re_1!=0):
_1 = no_1//re_1
else:
_1 = float('inf')
if(re_0!=0):
_0 = no_0//re_0
else:
_0 = float('inf')
_min = min(_1,_0)
ans = ans + s2[lcsp:]*_min
no_1 = no_1 - _min*re_1
no_0 = no_0 - _min*re_0
# while(no_1>=re_1 and no_0>=re_0):
# ans = ans + s2[lcsp:]
# no_1 -= re_1
# no_0 -= re_0
ans = ans + '1'*no_1 +'0'*no_0
print(ans)
``` | instruction | 0 | 9,964 | 4 | 19,928 |
Yes | output | 1 | 9,964 | 4 | 19,929 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The new camp by widely-known over the country Spring Programming Camp is going to start soon. Hence, all the team of friendly curators and teachers started composing the camp's schedule. After some continuous discussion, they came up with a schedule s, which can be represented as a binary string, in which the i-th symbol is '1' if students will write the contest in the i-th day and '0' if they will have a day off.
At the last moment Gleb said that the camp will be the most productive if it runs with the schedule t (which can be described in the same format as schedule s). Since the number of days in the current may be different from number of days in schedule t, Gleb required that the camp's schedule must be altered so that the number of occurrences of t in it as a substring is maximum possible. At the same time, the number of contest days and days off shouldn't change, only their order may change.
Could you rearrange the schedule in the best possible way?
Input
The first line contains string s (1 ⩽ |s| ⩽ 500 000), denoting the current project of the camp's schedule.
The second line contains string t (1 ⩽ |t| ⩽ 500 000), denoting the optimal schedule according to Gleb.
Strings s and t contain characters '0' and '1' only.
Output
In the only line print the schedule having the largest number of substrings equal to t. Printed schedule should consist of characters '0' and '1' only and the number of zeros should be equal to the number of zeros in s and the number of ones should be equal to the number of ones in s.
In case there multiple optimal schedules, print any of them.
Examples
Input
101101
110
Output
110110
Input
10010110
100011
Output
01100011
Input
10
11100
Output
01
Note
In the first example there are two occurrences, one starting from first position and one starting from fourth position.
In the second example there is only one occurrence, which starts from third position. Note, that the answer is not unique. For example, if we move the first day (which is a day off) to the last position, the number of occurrences of t wouldn't change.
In the third example it's impossible to make even a single occurrence.
Submitted Solution:
```
string = input()
sub_string = input()
if len(string)<len(sub_string):
print(string)
else:
nof1_st = string.count('1')
nof0_st = string.count('0')
nof1_su = sub_string.count('1')
nof0_su = sub_string.count('0')
if nof1_su==0:
print((nof0_st//nof0_su)*sub_string+"0"*(nof0_st - (nof0_st//nof0_su)*nof0_su)+"1"*nof1_st)
elif nof0_su==0:
print((nof1_st//nof1_su)*sub_string+"1"*(nof1_st - (nof1_st//nof1_su)*nof1_su)+"0"*nof0_st)
else:
l = 0
i = 1
length = len(sub_string)
lps = [0 for i in range(length)]
while(i<length):
if(sub_string[i] == sub_string[l]):
l += 1
lps[i] = l
i += 1
else:
if(l!=0):
l = lps[l-1]
else:
lps[i] = 0
i += 1
le = lps[length-1]
answer = ""
if nof0_st>=nof0_su and nof1_st>=nof1_su:
nof1_st-=nof1_su
nof0_st-=nof0_su
answer+=sub_string
nof0_su-=sub_string[:le].count('0')
nof1_su-=sub_string[:le].count('1')
tot = min(nof0_st//nof0_su,nof1_st//nof1_su)
print(answer+tot*sub_string[le:]+"0"*(nof0_st-tot*nof0_su)+"1"*(nof1_st-tot*nof1_su))
``` | instruction | 0 | 9,965 | 4 | 19,930 |
Yes | output | 1 | 9,965 | 4 | 19,931 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The new camp by widely-known over the country Spring Programming Camp is going to start soon. Hence, all the team of friendly curators and teachers started composing the camp's schedule. After some continuous discussion, they came up with a schedule s, which can be represented as a binary string, in which the i-th symbol is '1' if students will write the contest in the i-th day and '0' if they will have a day off.
At the last moment Gleb said that the camp will be the most productive if it runs with the schedule t (which can be described in the same format as schedule s). Since the number of days in the current may be different from number of days in schedule t, Gleb required that the camp's schedule must be altered so that the number of occurrences of t in it as a substring is maximum possible. At the same time, the number of contest days and days off shouldn't change, only their order may change.
Could you rearrange the schedule in the best possible way?
Input
The first line contains string s (1 ⩽ |s| ⩽ 500 000), denoting the current project of the camp's schedule.
The second line contains string t (1 ⩽ |t| ⩽ 500 000), denoting the optimal schedule according to Gleb.
Strings s and t contain characters '0' and '1' only.
Output
In the only line print the schedule having the largest number of substrings equal to t. Printed schedule should consist of characters '0' and '1' only and the number of zeros should be equal to the number of zeros in s and the number of ones should be equal to the number of ones in s.
In case there multiple optimal schedules, print any of them.
Examples
Input
101101
110
Output
110110
Input
10010110
100011
Output
01100011
Input
10
11100
Output
01
Note
In the first example there are two occurrences, one starting from first position and one starting from fourth position.
In the second example there is only one occurrence, which starts from third position. Note, that the answer is not unique. For example, if we move the first day (which is a day off) to the last position, the number of occurrences of t wouldn't change.
In the third example it's impossible to make even a single occurrence.
Submitted Solution:
```
import sys
def count_bits(s):
return [s.count("0"), s.count("1")]
# 1 - in case where a >= b
# 0 - otherwise
def compare_bits_count(a, b):
if a[0] >= b[0] and a[1] >= b[1]:
return 1
else:
return 0
def subtract_bits_count(a, b):
return [a[0] - b[0], a[1] - b[1]]
def z_function(s):
n = len(s)
l = 0
r = 0
z = [0 for x in range(n)]
for i in range(1, n):
z[i] = max(0, min(r - i, z[i - l]))
while i + z[i] < n and s[z[i]] == s[i + z[i]]:
z[i] += 1
if i + z[i] > r:
l = i
r = i + z[i]
return z
s = input()
t = input()
s_bits_count = count_bits(s)
t_bits_count = count_bits(t)
if compare_bits_count(s_bits_count, t_bits_count) == 0:
print(s)
sys.exit()
result = t
s_bits_count = subtract_bits_count(s_bits_count, t_bits_count)
r = ""
z = z_function(t)
for i in range(len(t) // 2, len(t)):
if z[i] == len(t) - i:
r = t[len(t) - i:]
r_bits_count = count_bits(r)
break
if len(r) == 0:
r = t
r_bits_count = t_bits_count
while s_bits_count[0] > 0 or s_bits_count[1] > 0:
if compare_bits_count(s_bits_count, r_bits_count) == 1:
result += r
s_bits_count = subtract_bits_count(s_bits_count, r_bits_count)
else:
result += '0' * s_bits_count[0]
result += '1' * s_bits_count[1]
break
print(result)
``` | instruction | 0 | 9,966 | 4 | 19,932 |
Yes | output | 1 | 9,966 | 4 | 19,933 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The new camp by widely-known over the country Spring Programming Camp is going to start soon. Hence, all the team of friendly curators and teachers started composing the camp's schedule. After some continuous discussion, they came up with a schedule s, which can be represented as a binary string, in which the i-th symbol is '1' if students will write the contest in the i-th day and '0' if they will have a day off.
At the last moment Gleb said that the camp will be the most productive if it runs with the schedule t (which can be described in the same format as schedule s). Since the number of days in the current may be different from number of days in schedule t, Gleb required that the camp's schedule must be altered so that the number of occurrences of t in it as a substring is maximum possible. At the same time, the number of contest days and days off shouldn't change, only their order may change.
Could you rearrange the schedule in the best possible way?
Input
The first line contains string s (1 ⩽ |s| ⩽ 500 000), denoting the current project of the camp's schedule.
The second line contains string t (1 ⩽ |t| ⩽ 500 000), denoting the optimal schedule according to Gleb.
Strings s and t contain characters '0' and '1' only.
Output
In the only line print the schedule having the largest number of substrings equal to t. Printed schedule should consist of characters '0' and '1' only and the number of zeros should be equal to the number of zeros in s and the number of ones should be equal to the number of ones in s.
In case there multiple optimal schedules, print any of them.
Examples
Input
101101
110
Output
110110
Input
10010110
100011
Output
01100011
Input
10
11100
Output
01
Note
In the first example there are two occurrences, one starting from first position and one starting from fourth position.
In the second example there is only one occurrence, which starts from third position. Note, that the answer is not unique. For example, if we move the first day (which is a day off) to the last position, the number of occurrences of t wouldn't change.
In the third example it's impossible to make even a single occurrence.
Submitted Solution:
```
import sys
def count_bits(s):
return [s.count("0"), s.count("1")]
# 1 - in case where a >= b
# 0 - otherwise
def compare_bits_count(a, b):
if a[0] >= b[0] and a[1] >= b[1]:
return 1
else:
return 0
def subtract_bits_count(a, b):
return [a[0] - b[0], a[1] - b[1]]
def hash_values(s):
hs = [0 for x in range(len(s))]
if s[0] == '1':
hs[0] = 1
for i in range(1, len(s)):
if s[i] == '1':
hs[i] = hs[i - 1] + 1
else:
hs[i] = hs[i - 1]
return hs
s = input()
t = input()
s_bits_count = count_bits(s)
t_bits_count = count_bits(t)
if compare_bits_count(s_bits_count, t_bits_count) == 0:
print(s)
sys.exit()
result = t
s_bits_count = subtract_bits_count(s_bits_count, t_bits_count)
r = ""
hs = hash_values(t)
for i in range(len(t) - 1):
if hs[len(t) - 1] - hs[i] == hs[len(t) - i - 2] and t[i + 1:] == t[:len(t) - i - 1]:
r = t[len(t) - i - 1:]
r_bits_count = count_bits(r)
break
if len(r) == 0:
r = t
r_bits_count = t_bits_count
while s_bits_count[0] > 0 or s_bits_count[1] > 0:
if compare_bits_count(s_bits_count, r_bits_count) == 1:
result += r
s_bits_count = subtract_bits_count(s_bits_count, r_bits_count)
else:
result += '0' * s_bits_count[0]
result += '1' * s_bits_count[1]
break
print(result)
``` | instruction | 0 | 9,967 | 4 | 19,934 |
Yes | output | 1 | 9,967 | 4 | 19,935 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The new camp by widely-known over the country Spring Programming Camp is going to start soon. Hence, all the team of friendly curators and teachers started composing the camp's schedule. After some continuous discussion, they came up with a schedule s, which can be represented as a binary string, in which the i-th symbol is '1' if students will write the contest in the i-th day and '0' if they will have a day off.
At the last moment Gleb said that the camp will be the most productive if it runs with the schedule t (which can be described in the same format as schedule s). Since the number of days in the current may be different from number of days in schedule t, Gleb required that the camp's schedule must be altered so that the number of occurrences of t in it as a substring is maximum possible. At the same time, the number of contest days and days off shouldn't change, only their order may change.
Could you rearrange the schedule in the best possible way?
Input
The first line contains string s (1 ⩽ |s| ⩽ 500 000), denoting the current project of the camp's schedule.
The second line contains string t (1 ⩽ |t| ⩽ 500 000), denoting the optimal schedule according to Gleb.
Strings s and t contain characters '0' and '1' only.
Output
In the only line print the schedule having the largest number of substrings equal to t. Printed schedule should consist of characters '0' and '1' only and the number of zeros should be equal to the number of zeros in s and the number of ones should be equal to the number of ones in s.
In case there multiple optimal schedules, print any of them.
Examples
Input
101101
110
Output
110110
Input
10010110
100011
Output
01100011
Input
10
11100
Output
01
Note
In the first example there are two occurrences, one starting from first position and one starting from fourth position.
In the second example there is only one occurrence, which starts from third position. Note, that the answer is not unique. For example, if we move the first day (which is a day off) to the last position, the number of occurrences of t wouldn't change.
In the third example it's impossible to make even a single occurrence.
Submitted Solution:
```
#########################################################################################################\
#########################################################################################################
###################################The_Apurv_Rathore#####################################################
#########################################################################################################
#########################################################################################################
import sys,os,io
from sys import stdin
from math import log, gcd, ceil
from collections import defaultdict, deque, Counter
from heapq import heappush, heappop
from bisect import bisect_left , bisect_right
import math
alphabets = list('abcdefghijklmnopqrstuvwxyz')
def ncr(n, r, p):
num = den = 1
for i in range(r):
num = (num * (n - i)) % p
den = (den * (i + 1)) % p
return (num * pow(den,
p - 2, p)) % p
def primeFactors(n):
l = []
while n % 2 == 0:
l.append(2)
n = n / 2
for i in range(3,int(math.sqrt(n))+1,2):
while n % i== 0:
l.append(int(i))
n = n / i
if n > 2:
l.append(n)
return list(set(l))
def power(x, y, p) :
res = 1
x = x % p
if (x == 0) :
return 0
while (y > 0) :
if ((y & 1) == 1) :
res = (res * x) % p
y = y >> 1 # y = y/2
x = (x * x) % p
return res
def SieveOfEratosthenes(n):
prime = [True for i in range(n+1)]
p = 2
while (p * p <= n):
if (prime[p] == True):
for i in range(p * p, n+1, p):
prime[i] = False
p += 1
return prime
def countdig(n):
c = 0
while (n > 0):
n //= 10
c += 1
return c
def si():
return input()
def prefix_sum(arr):
r = [0] * (len(arr)+1)
for i, el in enumerate(arr):
r[i+1] = r[i] + el
return r
def divideCeil(n,x):
if (n%x==0):
return n//x
return n//x+1
def ii():
return int(input())
def li():
return list(map(int,input().split()))
def ws(s): sys.stdout.write(s + '\n')
def wi(n): sys.stdout.write(str(n) + '\n')
def wia(a): sys.stdout.write(' '.join([str(x) for x in a]) + '\n')
#__________________________TEMPLATE__________________OVER_______________________________________________________
if(os.path.exists('input.txt')):
sys.stdin = open("input.txt","r") ; sys.stdout = open("output.txt","w")
# else:
# input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
t = 1
# t = int(input())
for _ in range(t):
s = list(si())
t1 = si()
t = list(t1)
if (len(t)>len(s)):
print(''.join(s))
continue
suf = defaultdict(lambda:0)
for i in range(len(t)//2+abs(len(t)%2),len(t)):
suf[t1[i:]]=1
#print(suf)
mx = -1
for i in range(1,len(t)//2+abs(len(t)%2)):
#print(t1[:i])
if (suf[t1[:i]]==1):
mx = i
if (mx==-1):
x = s.count('1')
y = s.count('0')
x1 = t.count('1')
y1 = t.count('0')
if (x1!=0 and y1!=0):
a = min(x//x1,y//y1)
elif (x1!=0 and y1==0):
a = x//x1
elif (x1==0 and y1!=0):
a = y//y1
ans = []
for i in range(a):
ans+=t
x = x - a*x1
y = y - a*y1
ans+=['1']*x+['0']*y
print(''.join(ans))
else:
ans= []
first = t[:mx+1]
last = t[mx+1:]
x = s.count('1')
y = s.count('0')
x1 = first.count('1')
y1 = first.count('0')
x2 = last.count('1')
y2 = last.count('0')
ans = []
i = 0
while(1):
if i%2==0:
if (x-x1<0) or y-y1<0:
break
x-=x1
y-=y1
ans+=first
else:
if (x-x2<0) or y-y2<0:
break
x-=x2
y-=y2
ans+=last
i+=1
ans+=['1']*x + ['0']*y
print(''.join(ans))
``` | instruction | 0 | 9,968 | 4 | 19,936 |
No | output | 1 | 9,968 | 4 | 19,937 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The new camp by widely-known over the country Spring Programming Camp is going to start soon. Hence, all the team of friendly curators and teachers started composing the camp's schedule. After some continuous discussion, they came up with a schedule s, which can be represented as a binary string, in which the i-th symbol is '1' if students will write the contest in the i-th day and '0' if they will have a day off.
At the last moment Gleb said that the camp will be the most productive if it runs with the schedule t (which can be described in the same format as schedule s). Since the number of days in the current may be different from number of days in schedule t, Gleb required that the camp's schedule must be altered so that the number of occurrences of t in it as a substring is maximum possible. At the same time, the number of contest days and days off shouldn't change, only their order may change.
Could you rearrange the schedule in the best possible way?
Input
The first line contains string s (1 ⩽ |s| ⩽ 500 000), denoting the current project of the camp's schedule.
The second line contains string t (1 ⩽ |t| ⩽ 500 000), denoting the optimal schedule according to Gleb.
Strings s and t contain characters '0' and '1' only.
Output
In the only line print the schedule having the largest number of substrings equal to t. Printed schedule should consist of characters '0' and '1' only and the number of zeros should be equal to the number of zeros in s and the number of ones should be equal to the number of ones in s.
In case there multiple optimal schedules, print any of them.
Examples
Input
101101
110
Output
110110
Input
10010110
100011
Output
01100011
Input
10
11100
Output
01
Note
In the first example there are two occurrences, one starting from first position and one starting from fourth position.
In the second example there is only one occurrence, which starts from third position. Note, that the answer is not unique. For example, if we move the first day (which is a day off) to the last position, the number of occurrences of t wouldn't change.
In the third example it's impossible to make even a single occurrence.
Submitted Solution:
```
def get_len(t, z):
ori_len = len(t)
length = 0
for i in range(1, ori_len):
if t[i] == t[length]:
length += 1
z[i] = length
else:
if len != 0:
length = z[length-1]
else:
z[i] = 0
return z[ori_len-1]
def problem_1137b():
maxn = int(1e4)
s = input()
t = input()
zs, os, zt, ot = 0, 0, 0, 0
for i in range(len(s)):
if s[i] == '0':
zs += 1
else:
os += 1
for i in range(len(t)):
if t[i] == '0':
zt += 1
else:
ot += 1
if zt > zs or ot > os:
print(s)
return
z = [0 for _ in range(maxn)]
len_t = get_len(t, z)
answer = t
add = t[len_t:max(len_t + 1, len(t))]
nz, no = 0, 0
currz, curro = zt, ot
for i in range(len(add)):
if add[i] == '0':
nz += 1
else:
no += 1
while currz + nz <= zs and curro + no <= os:
answer += add
currz += nz
curro += no
for i in range(zs-currz):
answer += '0'
for i in range(os-curro):
answer += '1'
print(answer)
return
if __name__ == '__main__':
problem_1137b()
``` | instruction | 0 | 9,969 | 4 | 19,938 |
No | output | 1 | 9,969 | 4 | 19,939 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The new camp by widely-known over the country Spring Programming Camp is going to start soon. Hence, all the team of friendly curators and teachers started composing the camp's schedule. After some continuous discussion, they came up with a schedule s, which can be represented as a binary string, in which the i-th symbol is '1' if students will write the contest in the i-th day and '0' if they will have a day off.
At the last moment Gleb said that the camp will be the most productive if it runs with the schedule t (which can be described in the same format as schedule s). Since the number of days in the current may be different from number of days in schedule t, Gleb required that the camp's schedule must be altered so that the number of occurrences of t in it as a substring is maximum possible. At the same time, the number of contest days and days off shouldn't change, only their order may change.
Could you rearrange the schedule in the best possible way?
Input
The first line contains string s (1 ⩽ |s| ⩽ 500 000), denoting the current project of the camp's schedule.
The second line contains string t (1 ⩽ |t| ⩽ 500 000), denoting the optimal schedule according to Gleb.
Strings s and t contain characters '0' and '1' only.
Output
In the only line print the schedule having the largest number of substrings equal to t. Printed schedule should consist of characters '0' and '1' only and the number of zeros should be equal to the number of zeros in s and the number of ones should be equal to the number of ones in s.
In case there multiple optimal schedules, print any of them.
Examples
Input
101101
110
Output
110110
Input
10010110
100011
Output
01100011
Input
10
11100
Output
01
Note
In the first example there are two occurrences, one starting from first position and one starting from fourth position.
In the second example there is only one occurrence, which starts from third position. Note, that the answer is not unique. For example, if we move the first day (which is a day off) to the last position, the number of occurrences of t wouldn't change.
In the third example it's impossible to make even a single occurrence.
Submitted Solution:
```
#########################################################################################################\
#########################################################################################################
###################################The_Apurv_Rathore#####################################################
#########################################################################################################
#########################################################################################################
import sys,os,io
from sys import stdin
from math import log, gcd, ceil
from collections import defaultdict, deque, Counter
from heapq import heappush, heappop
from bisect import bisect_left , bisect_right
import math
alphabets = list('abcdefghijklmnopqrstuvwxyz')
def ncr(n, r, p):
num = den = 1
for i in range(r):
num = (num * (n - i)) % p
den = (den * (i + 1)) % p
return (num * pow(den,
p - 2, p)) % p
def primeFactors(n):
l = []
while n % 2 == 0:
l.append(2)
n = n / 2
for i in range(3,int(math.sqrt(n))+1,2):
while n % i== 0:
l.append(int(i))
n = n / i
if n > 2:
l.append(n)
return list(set(l))
def power(x, y, p) :
res = 1
x = x % p
if (x == 0) :
return 0
while (y > 0) :
if ((y & 1) == 1) :
res = (res * x) % p
y = y >> 1 # y = y/2
x = (x * x) % p
return res
def SieveOfEratosthenes(n):
prime = [True for i in range(n+1)]
p = 2
while (p * p <= n):
if (prime[p] == True):
for i in range(p * p, n+1, p):
prime[i] = False
p += 1
return prime
def countdig(n):
c = 0
while (n > 0):
n //= 10
c += 1
return c
def si():
return input()
def prefix_sum(arr):
r = [0] * (len(arr)+1)
for i, el in enumerate(arr):
r[i+1] = r[i] + el
return r
def divideCeil(n,x):
if (n%x==0):
return n//x
return n//x+1
def ii():
return int(input())
def li():
return list(map(int,input().split()))
def ws(s): sys.stdout.write(s + '\n')
def wi(n): sys.stdout.write(str(n) + '\n')
def wia(a): sys.stdout.write(' '.join([str(x) for x in a]) + '\n')
#__________________________TEMPLATE__________________OVER_______________________________________________________
if(os.path.exists('input.txt')):
sys.stdin = open("input.txt","r") ; sys.stdout = open("output.txt","w")
# else:
# input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
t = 1
# t = int(input())
for _ in range(t):
s = list(si())
t = list(si())
if (len(t)>len(s)):
print(''.join(s))
continue
x = s.count('1')
y = s.count('0')
x1 = t.count('1')
y1 = t.count('0')
if (x1!=0 and y1!=0):
a = min(x//x1,y//y1)
elif (x1!=0 and y1==0):
a = x//x1
elif (x1==0 and y1!=0):
a = y//y1
ans = []
for i in range(a):
ans+=t
x = x - a*x1
y = y - a*y1
ans+=['1']*x+['0']*y
print(''.join(ans))
``` | instruction | 0 | 9,970 | 4 | 19,940 |
No | output | 1 | 9,970 | 4 | 19,941 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The new camp by widely-known over the country Spring Programming Camp is going to start soon. Hence, all the team of friendly curators and teachers started composing the camp's schedule. After some continuous discussion, they came up with a schedule s, which can be represented as a binary string, in which the i-th symbol is '1' if students will write the contest in the i-th day and '0' if they will have a day off.
At the last moment Gleb said that the camp will be the most productive if it runs with the schedule t (which can be described in the same format as schedule s). Since the number of days in the current may be different from number of days in schedule t, Gleb required that the camp's schedule must be altered so that the number of occurrences of t in it as a substring is maximum possible. At the same time, the number of contest days and days off shouldn't change, only their order may change.
Could you rearrange the schedule in the best possible way?
Input
The first line contains string s (1 ⩽ |s| ⩽ 500 000), denoting the current project of the camp's schedule.
The second line contains string t (1 ⩽ |t| ⩽ 500 000), denoting the optimal schedule according to Gleb.
Strings s and t contain characters '0' and '1' only.
Output
In the only line print the schedule having the largest number of substrings equal to t. Printed schedule should consist of characters '0' and '1' only and the number of zeros should be equal to the number of zeros in s and the number of ones should be equal to the number of ones in s.
In case there multiple optimal schedules, print any of them.
Examples
Input
101101
110
Output
110110
Input
10010110
100011
Output
01100011
Input
10
11100
Output
01
Note
In the first example there are two occurrences, one starting from first position and one starting from fourth position.
In the second example there is only one occurrence, which starts from third position. Note, that the answer is not unique. For example, if we move the first day (which is a day off) to the last position, the number of occurrences of t wouldn't change.
In the third example it's impossible to make even a single occurrence.
Submitted Solution:
```
def longestPrefixSuffix(s) :
n = len(s)
lps = [0] * n
l = 0
i = 1
while (i < n) :
if (s[i] == s[l]) :
l = l + 1
lps[i] = l
i = i + 1
else :
if (l != 0) :
l = lps[l-1]
else :
lps[i] = 0
i = i + 1
res = lps[n-1]
if(res > n/2) :
return n//2
else :
return res
s=input()
q=input()
if len(q)>len(s):
print(s)
else:
a=0
b=0
for i in s:
if i=='0':
a+=1
else:
b+=1
c=0
d=0
for i in q:
if i=='0':
c+=1
else:
d+=1
z=""
if a>=c and b>=d:
z+=q
a-=c
b-=d
y=longestPrefixSuffix(q)
x=""
for i in range(y,len(q)):
x+=q[i]
c=0
d=0
for i in x:
if i=='0':
c+=1
else:
d+=1
while a>=c and b>=d:
z+=x
a-=c
b-=d
z+='0'*(a)+'1'*(b)
print(z)
else:
print(s)
``` | instruction | 0 | 9,971 | 4 | 19,942 |
No | output | 1 | 9,971 | 4 | 19,943 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given the current time in 24-hour format hh:mm. Find and print the time after a minutes.
Note that you should find only the time after a minutes, see the examples to clarify the problem statement.
You can read more about 24-hour format here <https://en.wikipedia.org/wiki/24-hour_clock>.
Input
The first line contains the current time in the format hh:mm (0 ≤ hh < 24, 0 ≤ mm < 60). The hours and the minutes are given with two digits (the hours or the minutes less than 10 are given with the leading zeroes).
The second line contains integer a (0 ≤ a ≤ 104) — the number of the minutes passed.
Output
The only line should contain the time after a minutes in the format described in the input. Note that you should print exactly two digits for the hours and the minutes (add leading zeroes to the numbers if needed).
See the examples to check the input/output format.
Examples
Input
23:59
10
Output
00:09
Input
20:20
121
Output
22:21
Input
10:10
0
Output
10:10 | instruction | 0 | 10,370 | 4 | 20,740 |
Tags: implementation
Correct Solution:
```
def main():
time = input()
passed = int(input())
time = time.split(":")
time[0] = int(time[0])
time[1] = int(time[1])
hours = int(passed/60)
minutes = passed%60
time[1] = (time[1] + minutes)
if time[1] > 59:
time[1] = time[1]%60
time[0] = (time[0] + 1) % 24
time[0] = (time[0] + hours) % 24
if int(time[0]/10) == 0:
time[0] = "0" + str(time[0])
if int(time[1]/10) == 0:
time[1] = "0" + str(time[1])
time[0] = str(time[0])
time[1] = str(time[1])
print(time[0] + ":" + time[1])
if __name__ == "__main__":
main()
``` | output | 1 | 10,370 | 4 | 20,741 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given the current time in 24-hour format hh:mm. Find and print the time after a minutes.
Note that you should find only the time after a minutes, see the examples to clarify the problem statement.
You can read more about 24-hour format here <https://en.wikipedia.org/wiki/24-hour_clock>.
Input
The first line contains the current time in the format hh:mm (0 ≤ hh < 24, 0 ≤ mm < 60). The hours and the minutes are given with two digits (the hours or the minutes less than 10 are given with the leading zeroes).
The second line contains integer a (0 ≤ a ≤ 104) — the number of the minutes passed.
Output
The only line should contain the time after a minutes in the format described in the input. Note that you should print exactly two digits for the hours and the minutes (add leading zeroes to the numbers if needed).
See the examples to check the input/output format.
Examples
Input
23:59
10
Output
00:09
Input
20:20
121
Output
22:21
Input
10:10
0
Output
10:10 | instruction | 0 | 10,371 | 4 | 20,742 |
Tags: implementation
Correct Solution:
```
import sys
import math
input = sys.stdin.readline
h, m = map(int, input().split(":"))
ext = int(input())
time = h * 60 + m + ext
h, m = (time // 60) % 24, time % 60
if h < 10:
h = str('0' + str(h))
if m < 10:
m = str('0' + str(m))
print("{}:{}".format(h,m))
``` | output | 1 | 10,371 | 4 | 20,743 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given the current time in 24-hour format hh:mm. Find and print the time after a minutes.
Note that you should find only the time after a minutes, see the examples to clarify the problem statement.
You can read more about 24-hour format here <https://en.wikipedia.org/wiki/24-hour_clock>.
Input
The first line contains the current time in the format hh:mm (0 ≤ hh < 24, 0 ≤ mm < 60). The hours and the minutes are given with two digits (the hours or the minutes less than 10 are given with the leading zeroes).
The second line contains integer a (0 ≤ a ≤ 104) — the number of the minutes passed.
Output
The only line should contain the time after a minutes in the format described in the input. Note that you should print exactly two digits for the hours and the minutes (add leading zeroes to the numbers if needed).
See the examples to check the input/output format.
Examples
Input
23:59
10
Output
00:09
Input
20:20
121
Output
22:21
Input
10:10
0
Output
10:10 | instruction | 0 | 10,372 | 4 | 20,744 |
Tags: implementation
Correct Solution:
```
from datetime import datetime, timedelta
time = input()
hour = int(time[0:2])
mins = int(time[3:5])
add = int(input())
op = datetime(2021, 5 , 18, hour, mins) + timedelta(minutes= add)
print(op.strftime("%H:%M"))
``` | output | 1 | 10,372 | 4 | 20,745 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given the current time in 24-hour format hh:mm. Find and print the time after a minutes.
Note that you should find only the time after a minutes, see the examples to clarify the problem statement.
You can read more about 24-hour format here <https://en.wikipedia.org/wiki/24-hour_clock>.
Input
The first line contains the current time in the format hh:mm (0 ≤ hh < 24, 0 ≤ mm < 60). The hours and the minutes are given with two digits (the hours or the minutes less than 10 are given with the leading zeroes).
The second line contains integer a (0 ≤ a ≤ 104) — the number of the minutes passed.
Output
The only line should contain the time after a minutes in the format described in the input. Note that you should print exactly two digits for the hours and the minutes (add leading zeroes to the numbers if needed).
See the examples to check the input/output format.
Examples
Input
23:59
10
Output
00:09
Input
20:20
121
Output
22:21
Input
10:10
0
Output
10:10 | instruction | 0 | 10,373 | 4 | 20,746 |
Tags: implementation
Correct Solution:
```
s = input()
n = int(input())
h = n // 60
min = n%60
a=0
if (int(s[3:])+min)//60 :a=(int(s[3:])+min)//60
min = str((int(s[3:])+min)%60)
if len(min)==1:min='0'+min
h = str((int(s[0:2])+h+a)%24)
if len(h)==1:h='0'+h
print(h+':'+min)
``` | output | 1 | 10,373 | 4 | 20,747 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given the current time in 24-hour format hh:mm. Find and print the time after a minutes.
Note that you should find only the time after a minutes, see the examples to clarify the problem statement.
You can read more about 24-hour format here <https://en.wikipedia.org/wiki/24-hour_clock>.
Input
The first line contains the current time in the format hh:mm (0 ≤ hh < 24, 0 ≤ mm < 60). The hours and the minutes are given with two digits (the hours or the minutes less than 10 are given with the leading zeroes).
The second line contains integer a (0 ≤ a ≤ 104) — the number of the minutes passed.
Output
The only line should contain the time after a minutes in the format described in the input. Note that you should print exactly two digits for the hours and the minutes (add leading zeroes to the numbers if needed).
See the examples to check the input/output format.
Examples
Input
23:59
10
Output
00:09
Input
20:20
121
Output
22:21
Input
10:10
0
Output
10:10 | instruction | 0 | 10,374 | 4 | 20,748 |
Tags: implementation
Correct Solution:
```
s=input()
a=int(input())
arr=s.split(":")
hr,mini=int(arr[0]),int(arr[1])
if(a < 60):
if(mini+a < 60):
l=str(mini+a)
if(len(l)==1):
print(arr[0]+":"+"0"+l)
else:
print(arr[0]+":"+l)
else:
k=(mini+a)//60
rem=(mini+a) % 60
if(hr==23):
hr=0
hr+=k-1
else:
hr+=k
hr%=24
h=str(hr)
m=str(rem)
if(len(h)==1 and len(m)==1):
print("0"+h+":"+"0"+m)
elif(len(h)==1):
print("0"+h+":"+m)
elif(len(m)==1):
print(h+":"+"0"+m)
else:
print(h+":"+m)
else:
k=a//60
rem=a % 60
if(hr==23):
hr=0
hr+=k-1
else:
hr+=k
hr%=24
if(rem+mini< 60):
m=str(mini+rem)
h=str(hr)
if(len(h)==1 and len(m)==1):
print("0"+h+":"+"0"+m)
elif(len(h)==1):
print("0"+h+":"+m)
elif(len(m)==1):
print(h+":"+"0"+m)
else:
print(h+":"+m)
else:
k=(mini+rem)//60
rem=(mini+rem) % 60
if(hr==23):
hr=0
hr+=k-1
else:
hr+=k
hr%=24
h=str(hr)
m=str(rem)
if(len(h)==1 and len(m)==1):
print("0"+h+":"+"0"+m)
elif(len(h)==1):
print("0"+h+":"+m)
elif(len(m)==1):
print(h+":"+"0"+m)
else:
print(h+":"+m)
``` | output | 1 | 10,374 | 4 | 20,749 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given the current time in 24-hour format hh:mm. Find and print the time after a minutes.
Note that you should find only the time after a minutes, see the examples to clarify the problem statement.
You can read more about 24-hour format here <https://en.wikipedia.org/wiki/24-hour_clock>.
Input
The first line contains the current time in the format hh:mm (0 ≤ hh < 24, 0 ≤ mm < 60). The hours and the minutes are given with two digits (the hours or the minutes less than 10 are given with the leading zeroes).
The second line contains integer a (0 ≤ a ≤ 104) — the number of the minutes passed.
Output
The only line should contain the time after a minutes in the format described in the input. Note that you should print exactly two digits for the hours and the minutes (add leading zeroes to the numbers if needed).
See the examples to check the input/output format.
Examples
Input
23:59
10
Output
00:09
Input
20:20
121
Output
22:21
Input
10:10
0
Output
10:10 | instruction | 0 | 10,375 | 4 | 20,750 |
Tags: implementation
Correct Solution:
```
start_time = input()
minutes = int(input())
end_time_in_minutes = (int(start_time[:2]) * 60 + int(start_time[3:]) + minutes) % (24 * 60)
ans = str(end_time_in_minutes // 60).zfill(2) + ':' + str(end_time_in_minutes % 60).zfill(2)
print(ans)
``` | output | 1 | 10,375 | 4 | 20,751 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given the current time in 24-hour format hh:mm. Find and print the time after a minutes.
Note that you should find only the time after a minutes, see the examples to clarify the problem statement.
You can read more about 24-hour format here <https://en.wikipedia.org/wiki/24-hour_clock>.
Input
The first line contains the current time in the format hh:mm (0 ≤ hh < 24, 0 ≤ mm < 60). The hours and the minutes are given with two digits (the hours or the minutes less than 10 are given with the leading zeroes).
The second line contains integer a (0 ≤ a ≤ 104) — the number of the minutes passed.
Output
The only line should contain the time after a minutes in the format described in the input. Note that you should print exactly two digits for the hours and the minutes (add leading zeroes to the numbers if needed).
See the examples to check the input/output format.
Examples
Input
23:59
10
Output
00:09
Input
20:20
121
Output
22:21
Input
10:10
0
Output
10:10 | instruction | 0 | 10,376 | 4 | 20,752 |
Tags: implementation
Correct Solution:
```
a,b=map(int,input().split(':'))
n=int(input())
b+=n
a+=b//60
b=b%60
a%=24
if b<10:b='0'+str(b)
else:b=str(b)
if a<10:a='0'+str(a)
else:a=str(a)
print(a+':'+b)
``` | output | 1 | 10,376 | 4 | 20,753 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given the current time in 24-hour format hh:mm. Find and print the time after a minutes.
Note that you should find only the time after a minutes, see the examples to clarify the problem statement.
You can read more about 24-hour format here <https://en.wikipedia.org/wiki/24-hour_clock>.
Input
The first line contains the current time in the format hh:mm (0 ≤ hh < 24, 0 ≤ mm < 60). The hours and the minutes are given with two digits (the hours or the minutes less than 10 are given with the leading zeroes).
The second line contains integer a (0 ≤ a ≤ 104) — the number of the minutes passed.
Output
The only line should contain the time after a minutes in the format described in the input. Note that you should print exactly two digits for the hours and the minutes (add leading zeroes to the numbers if needed).
See the examples to check the input/output format.
Examples
Input
23:59
10
Output
00:09
Input
20:20
121
Output
22:21
Input
10:10
0
Output
10:10 | instruction | 0 | 10,377 | 4 | 20,754 |
Tags: implementation
Correct Solution:
```
hh, mm = [int(t) for t in input().split(':')]
dm = int(input())
mm += dm
hh += mm//60
mm %= 60
hh %= 24
print("{0:02}:{1:02}".format(hh, mm))
``` | output | 1 | 10,377 | 4 | 20,755 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given the current time in 24-hour format hh:mm. Find and print the time after a minutes.
Note that you should find only the time after a minutes, see the examples to clarify the problem statement.
You can read more about 24-hour format here <https://en.wikipedia.org/wiki/24-hour_clock>.
Input
The first line contains the current time in the format hh:mm (0 ≤ hh < 24, 0 ≤ mm < 60). The hours and the minutes are given with two digits (the hours or the minutes less than 10 are given with the leading zeroes).
The second line contains integer a (0 ≤ a ≤ 104) — the number of the minutes passed.
Output
The only line should contain the time after a minutes in the format described in the input. Note that you should print exactly two digits for the hours and the minutes (add leading zeroes to the numbers if needed).
See the examples to check the input/output format.
Examples
Input
23:59
10
Output
00:09
Input
20:20
121
Output
22:21
Input
10:10
0
Output
10:10
Submitted Solution:
```
t= list(map(int,input().split(":")))
x= t[0]*60+t[1]+int(input())
a= int(x/60)
b= x%60
if a>=24:
a= a%24
if a<10:
a= "0"+str(a)
if b<10:
b= "0"+str(b)
a= str(a)
b= str(b)
s= a+":"+b
print(s)
``` | instruction | 0 | 10,378 | 4 | 20,756 |
Yes | output | 1 | 10,378 | 4 | 20,757 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given the current time in 24-hour format hh:mm. Find and print the time after a minutes.
Note that you should find only the time after a minutes, see the examples to clarify the problem statement.
You can read more about 24-hour format here <https://en.wikipedia.org/wiki/24-hour_clock>.
Input
The first line contains the current time in the format hh:mm (0 ≤ hh < 24, 0 ≤ mm < 60). The hours and the minutes are given with two digits (the hours or the minutes less than 10 are given with the leading zeroes).
The second line contains integer a (0 ≤ a ≤ 104) — the number of the minutes passed.
Output
The only line should contain the time after a minutes in the format described in the input. Note that you should print exactly two digits for the hours and the minutes (add leading zeroes to the numbers if needed).
See the examples to check the input/output format.
Examples
Input
23:59
10
Output
00:09
Input
20:20
121
Output
22:21
Input
10:10
0
Output
10:10
Submitted Solution:
```
X = list(map(int, input().split(":")))
Min = X[0] * 60 + X[1] + int(input())
Hour = str((Min // 60) % 24)
Minute = str(Min % 60)
print(Hour if len(Hour) == 2 else '0' + Hour, end=':')
print(Minute if len(Minute) == 2 else '0' + Minute)
# UB_CodeForces
# Advice: Falling down is an accident, staying down is a choice
# Location: At Grandma's house
# Caption: Start for new exam
# CodeNumber: 593
``` | instruction | 0 | 10,379 | 4 | 20,758 |
Yes | output | 1 | 10,379 | 4 | 20,759 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given the current time in 24-hour format hh:mm. Find and print the time after a minutes.
Note that you should find only the time after a minutes, see the examples to clarify the problem statement.
You can read more about 24-hour format here <https://en.wikipedia.org/wiki/24-hour_clock>.
Input
The first line contains the current time in the format hh:mm (0 ≤ hh < 24, 0 ≤ mm < 60). The hours and the minutes are given with two digits (the hours or the minutes less than 10 are given with the leading zeroes).
The second line contains integer a (0 ≤ a ≤ 104) — the number of the minutes passed.
Output
The only line should contain the time after a minutes in the format described in the input. Note that you should print exactly two digits for the hours and the minutes (add leading zeroes to the numbers if needed).
See the examples to check the input/output format.
Examples
Input
23:59
10
Output
00:09
Input
20:20
121
Output
22:21
Input
10:10
0
Output
10:10
Submitted Solution:
```
__author__ = 'Logan'
strin = str(input())
time = [int(x.strip()) for x in strin.split(':')]
minutes = int(input())
time[1] += minutes
time[0] += int(time[1]/60)
time[0] = time[0] % 24
time[1] = time[1] % 60
print("%02d:%02d" %(time[0], time[1]) )
``` | instruction | 0 | 10,380 | 4 | 20,760 |
Yes | output | 1 | 10,380 | 4 | 20,761 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given the current time in 24-hour format hh:mm. Find and print the time after a minutes.
Note that you should find only the time after a minutes, see the examples to clarify the problem statement.
You can read more about 24-hour format here <https://en.wikipedia.org/wiki/24-hour_clock>.
Input
The first line contains the current time in the format hh:mm (0 ≤ hh < 24, 0 ≤ mm < 60). The hours and the minutes are given with two digits (the hours or the minutes less than 10 are given with the leading zeroes).
The second line contains integer a (0 ≤ a ≤ 104) — the number of the minutes passed.
Output
The only line should contain the time after a minutes in the format described in the input. Note that you should print exactly two digits for the hours and the minutes (add leading zeroes to the numbers if needed).
See the examples to check the input/output format.
Examples
Input
23:59
10
Output
00:09
Input
20:20
121
Output
22:21
Input
10:10
0
Output
10:10
Submitted Solution:
```
h, m = input().split(':')
h = int(h)
m = int(m)
tot = h * 60 + m
add = eval(input())
tot += add
tot %= (24 * 60)
h = tot // 60
m = tot % 60
if h < 10:
print('0'+str(h)+':', end = '')
else:
print(str(h)+':', end = '')
if m < 10:
print('0'+str(m))
else:
print(str(m))
``` | instruction | 0 | 10,381 | 4 | 20,762 |
Yes | output | 1 | 10,381 | 4 | 20,763 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given the current time in 24-hour format hh:mm. Find and print the time after a minutes.
Note that you should find only the time after a minutes, see the examples to clarify the problem statement.
You can read more about 24-hour format here <https://en.wikipedia.org/wiki/24-hour_clock>.
Input
The first line contains the current time in the format hh:mm (0 ≤ hh < 24, 0 ≤ mm < 60). The hours and the minutes are given with two digits (the hours or the minutes less than 10 are given with the leading zeroes).
The second line contains integer a (0 ≤ a ≤ 104) — the number of the minutes passed.
Output
The only line should contain the time after a minutes in the format described in the input. Note that you should print exactly two digits for the hours and the minutes (add leading zeroes to the numbers if needed).
See the examples to check the input/output format.
Examples
Input
23:59
10
Output
00:09
Input
20:20
121
Output
22:21
Input
10:10
0
Output
10:10
Submitted Solution:
```
st=input()
ex=int(input())
h=int(st[:2])
m=int(st[3:])
time=h*60+m+ex
if time/60>=24:
print("00:",end="")
elif time/60<=9:
print("0"+str(time//60)+":",end="")
else:
print(str(time//60)+":",end="")
if time-(time//60)*60<=9:
print("0",end="")
print(str(time-(time//60)*60))
``` | instruction | 0 | 10,382 | 4 | 20,764 |
No | output | 1 | 10,382 | 4 | 20,765 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given the current time in 24-hour format hh:mm. Find and print the time after a minutes.
Note that you should find only the time after a minutes, see the examples to clarify the problem statement.
You can read more about 24-hour format here <https://en.wikipedia.org/wiki/24-hour_clock>.
Input
The first line contains the current time in the format hh:mm (0 ≤ hh < 24, 0 ≤ mm < 60). The hours and the minutes are given with two digits (the hours or the minutes less than 10 are given with the leading zeroes).
The second line contains integer a (0 ≤ a ≤ 104) — the number of the minutes passed.
Output
The only line should contain the time after a minutes in the format described in the input. Note that you should print exactly two digits for the hours and the minutes (add leading zeroes to the numbers if needed).
See the examples to check the input/output format.
Examples
Input
23:59
10
Output
00:09
Input
20:20
121
Output
22:21
Input
10:10
0
Output
10:10
Submitted Solution:
```
t0=input()
t1=int(input())
hh=int(t0[0:2])
mm=int(t0[3:5])
x=t1%60
y=int(t1/1440)
z=int(t1/60)
th=z-24*y
tm=x
q=tm+mm
t=int(q/60)
q=q%60
p=hh+th
if(t+p>23):
p=24-p-t
if(p<0):
p=-p
if(p<10 and q<10):
print(f"0{p}:0{q}")
elif(p<10 and q>=10):
print(f"0{p}:{q}")
elif(p>=10 and q<10):
print(f"{p}:0{q}")
else:
print(f"{p}:{q}")
``` | instruction | 0 | 10,383 | 4 | 20,766 |
No | output | 1 | 10,383 | 4 | 20,767 |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.