message stringlengths 2 44.5k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 42 109k | cluster float64 5 5 | __index_level_0__ int64 84 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).
Constraints
* 1 \leq N \leq 10^4
* 1 \leq A \leq B \leq 36
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N A B
Output
Print the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).
Examples
Input
20 2 5
Output
84
Input
10 1 2
Output
13
Input
100 4 16
Output
4554
Submitted Solution:
```
N, A, B = map(int, input().split())
print(sum(x for x in range(1, N+1) if A<=sum((map(int, str(x))))<=B))
``` | instruction | 0 | 74,049 | 5 | 148,098 |
Yes | output | 1 | 74,049 | 5 | 148,099 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).
Constraints
* 1 \leq N \leq 10^4
* 1 \leq A \leq B \leq 36
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N A B
Output
Print the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).
Examples
Input
20 2 5
Output
84
Input
10 1 2
Output
13
Input
100 4 16
Output
4554
Submitted Solution:
```
n,a,b = map(int, input().split())
ans = 0
for i in range(1,n+1):
if a <= sum([int(n) for n in str(i)]) <= b:
ans += i
print(ans)
``` | instruction | 0 | 74,050 | 5 | 148,100 |
Yes | output | 1 | 74,050 | 5 | 148,101 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).
Constraints
* 1 \leq N \leq 10^4
* 1 \leq A \leq B \leq 36
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N A B
Output
Print the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).
Examples
Input
20 2 5
Output
84
Input
10 1 2
Output
13
Input
100 4 16
Output
4554
Submitted Solution:
```
N,A,B=map(int,input().split())
C=0
for i in range(N+1):
T=0
for ii in str(i):
T=T+int(ii)
if T>=A and B>=T:
C=C+i
print(C)
``` | instruction | 0 | 74,051 | 5 | 148,102 |
Yes | output | 1 | 74,051 | 5 | 148,103 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).
Constraints
* 1 \leq N \leq 10^4
* 1 \leq A \leq B \leq 36
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N A B
Output
Print the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).
Examples
Input
20 2 5
Output
84
Input
10 1 2
Output
13
Input
100 4 16
Output
4554
Submitted Solution:
```
N,a,b = map(int,[input() for _ in range(3)])
total= 0
ans = 0
for i in range(1,N+1):
st_i = str(i)
for j in range(4):
try:
total += int(st_i[j])
except:
pass
if a <= total <= b:
ans += i
total = 0
print(ans)
``` | instruction | 0 | 74,052 | 5 | 148,104 |
No | output | 1 | 74,052 | 5 | 148,105 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).
Constraints
* 1 \leq N \leq 10^4
* 1 \leq A \leq B \leq 36
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N A B
Output
Print the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).
Examples
Input
20 2 5
Output
84
Input
10 1 2
Output
13
Input
100 4 16
Output
4554
Submitted Solution:
```
n, a, b = map(int, input().split())
count = 0
total = 0
for i in range(1,n+1,1):
str_i = str(i)
for j in range(len(str_i)):
total+=int(str_i[j])
if total >= a and total <= b:
print(i)
count+=i
total=0
print(count)
``` | instruction | 0 | 74,053 | 5 | 148,106 |
No | output | 1 | 74,053 | 5 | 148,107 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).
Constraints
* 1 \leq N \leq 10^4
* 1 \leq A \leq B \leq 36
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N A B
Output
Print the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).
Examples
Input
20 2 5
Output
84
Input
10 1 2
Output
13
Input
100 4 16
Output
4554
Submitted Solution:
```
N, A, B = map(int, input().split())
souwa = 0
for i in range(1, N+1):
sumketa = (i//1000) + ((i%1000)//100) + ((i%100)//10) + (i%10)
if A <= sumketa <= B:
souwa += i
print(souwa)
``` | instruction | 0 | 74,054 | 5 | 148,108 |
No | output | 1 | 74,054 | 5 | 148,109 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).
Constraints
* 1 \leq N \leq 10^4
* 1 \leq A \leq B \leq 36
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N A B
Output
Print the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).
Examples
Input
20 2 5
Output
84
Input
10 1 2
Output
13
Input
100 4 16
Output
4554
Submitted Solution:
```
#!/user/bin/python
# coding: UTF-8
N, a, b = map(int, input().split())
l = []
for i in range(1, N + 1):
if 0 < i and i < 10:
if i >= a and i <= b:
l.append(i)
elif 10 <= i and i <= 99:
n = i
num = []
while n != 0:
num.append(n % 10)
n /= 10
if num[0] + num[1] >= a and num[0] + num[1] <= b + 1:
l.append(i)
elif 100 <= i and i <= 999:
n = i
num = []
while n != 0:
num.append(n % 10)
n /= 10
if num[0] + num[1] + num[2] >= a and num[0] + num[1] + num[2] <= b + 1:
l.append(i)
elif 1000 <= i and i <= 9999:
n = i
num = []
while n != 0:
num.append(n % 10)
n /= 10
if num[0] + num[1] + num[2] + num[3] >= a and num[0] + num[1] + num[2] + num[3] <= b + 1:
l.append(i)
ans = 0
for j in range(len(l)):
ans += l[j]
print(ans)
``` | instruction | 0 | 74,055 | 5 | 148,110 |
No | output | 1 | 74,055 | 5 | 148,111 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a set $T$, which is a subset of $S$. The set $S$ consists of $0, 1, ... n-1$. Print all subsets of $T$. Note that we represent $0, 1, ... n-1$ as 00...0001, 00...0010, 00...0100, ..., 10...0000 in binary respectively and the integer representation of a subset is calculated by bitwise OR of existing elements.
Constraints
* $1 \leq n \leq 28$
* $0 \leq k \leq 18$
* $k \leq n$
* $0 \leq b_i < n$
Input
The input is given in the following format.
$n$
$k \; b_0 \; b_1 \; ... \; b_{k-1}$
$k$ is the number of elements in $T$, and $b_i$ represents elements in $T$.
Output
Print the subsets ordered by their decimal integers. Print a subset in the following format.
$d$: $e_0$ $e_1$ ...
Print ':' after the integer value $d$, then print elements $e_i$ in the subset in ascending order. Separate two adjacency elements by a space character.
Example
Input
4
2 0 2
Output
0:
1: 0
4: 2
5: 0 2 | instruction | 0 | 74,165 | 5 | 148,330 |
"Correct Solution:
```
from itertools import combinations
if __name__ == "__main__":
bit = int(input())
k, *E = map(lambda x: int(x), input().split())
for d, ans in sorted([((sum([1 << cc for cc in c])), ' '.join(map(str, c)))
for i in range(k + 1) for c in combinations(E, i)]):
if d:
print(f"{d}: {ans}")
else:
print(f"0:")
``` | output | 1 | 74,165 | 5 | 148,331 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a set $T$, which is a subset of $S$. The set $S$ consists of $0, 1, ... n-1$. Print all subsets of $T$. Note that we represent $0, 1, ... n-1$ as 00...0001, 00...0010, 00...0100, ..., 10...0000 in binary respectively and the integer representation of a subset is calculated by bitwise OR of existing elements.
Constraints
* $1 \leq n \leq 28$
* $0 \leq k \leq 18$
* $k \leq n$
* $0 \leq b_i < n$
Input
The input is given in the following format.
$n$
$k \; b_0 \; b_1 \; ... \; b_{k-1}$
$k$ is the number of elements in $T$, and $b_i$ represents elements in $T$.
Output
Print the subsets ordered by their decimal integers. Print a subset in the following format.
$d$: $e_0$ $e_1$ ...
Print ':' after the integer value $d$, then print elements $e_i$ in the subset in ascending order. Separate two adjacency elements by a space character.
Example
Input
4
2 0 2
Output
0:
1: 0
4: 2
5: 0 2 | instruction | 0 | 74,166 | 5 | 148,332 |
"Correct Solution:
```
# -*- coding: utf-8 -*-
"""
Bitset II - Enumeration of Subsets III
http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=ITP2_11_C&lang=jp
"""
from itertools import combinations
_ = input()
k, *B = map(int, input().split())
for v, combi in sorted([((sum([1 << cc for cc in c])), ' '.join(map(str, c))) for i in range(k + 1) for c in combinations(B, i)]):
print(f'{v}: {combi}' if v else '0:')
``` | output | 1 | 74,166 | 5 | 148,333 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a set $T$, which is a subset of $S$. The set $S$ consists of $0, 1, ... n-1$. Print all subsets of $T$. Note that we represent $0, 1, ... n-1$ as 00...0001, 00...0010, 00...0100, ..., 10...0000 in binary respectively and the integer representation of a subset is calculated by bitwise OR of existing elements.
Constraints
* $1 \leq n \leq 28$
* $0 \leq k \leq 18$
* $k \leq n$
* $0 \leq b_i < n$
Input
The input is given in the following format.
$n$
$k \; b_0 \; b_1 \; ... \; b_{k-1}$
$k$ is the number of elements in $T$, and $b_i$ represents elements in $T$.
Output
Print the subsets ordered by their decimal integers. Print a subset in the following format.
$d$: $e_0$ $e_1$ ...
Print ':' after the integer value $d$, then print elements $e_i$ in the subset in ascending order. Separate two adjacency elements by a space character.
Example
Input
4
2 0 2
Output
0:
1: 0
4: 2
5: 0 2 | instruction | 0 | 74,167 | 5 | 148,334 |
"Correct Solution:
```
from itertools import combinations
n = int(input())
b = list(map(int,input().split()))
r = b[0]
b = b[1:]
print("0:")
ans = []
for i in range(1,r+1):
for j in combinations(b,i):
comb = list(j)
comb.reverse()
s = 0
for h in comb:
s += 2**h
ans.append([s,list(j)])
ans.sort()
for i,j in ans:
print(str(i)+":",*j)
``` | output | 1 | 74,167 | 5 | 148,335 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a set $T$, which is a subset of $S$. The set $S$ consists of $0, 1, ... n-1$. Print all subsets of $T$. Note that we represent $0, 1, ... n-1$ as 00...0001, 00...0010, 00...0100, ..., 10...0000 in binary respectively and the integer representation of a subset is calculated by bitwise OR of existing elements.
Constraints
* $1 \leq n \leq 28$
* $0 \leq k \leq 18$
* $k \leq n$
* $0 \leq b_i < n$
Input
The input is given in the following format.
$n$
$k \; b_0 \; b_1 \; ... \; b_{k-1}$
$k$ is the number of elements in $T$, and $b_i$ represents elements in $T$.
Output
Print the subsets ordered by their decimal integers. Print a subset in the following format.
$d$: $e_0$ $e_1$ ...
Print ':' after the integer value $d$, then print elements $e_i$ in the subset in ascending order. Separate two adjacency elements by a space character.
Example
Input
4
2 0 2
Output
0:
1: 0
4: 2
5: 0 2 | instruction | 0 | 74,168 | 5 | 148,336 |
"Correct Solution:
```
import sys
readline = sys.stdin.readline
write = sys.stdout.write
N = int(readline())
k, *B = map(int, readline().split())
M = sum(1 << b for b in B)
R = []
v = (-1) & M
while v:
R.append(v)
v = (v - 1) & M
R.sort()
write("0:\n")
for i in R:
write("%d: %s\n" % (i, " ".join(str(j) for j in range(N) if i & (1 << j))))
``` | output | 1 | 74,168 | 5 | 148,337 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a set $T$, which is a subset of $S$. The set $S$ consists of $0, 1, ... n-1$. Print all subsets of $T$. Note that we represent $0, 1, ... n-1$ as 00...0001, 00...0010, 00...0100, ..., 10...0000 in binary respectively and the integer representation of a subset is calculated by bitwise OR of existing elements.
Constraints
* $1 \leq n \leq 28$
* $0 \leq k \leq 18$
* $k \leq n$
* $0 \leq b_i < n$
Input
The input is given in the following format.
$n$
$k \; b_0 \; b_1 \; ... \; b_{k-1}$
$k$ is the number of elements in $T$, and $b_i$ represents elements in $T$.
Output
Print the subsets ordered by their decimal integers. Print a subset in the following format.
$d$: $e_0$ $e_1$ ...
Print ':' after the integer value $d$, then print elements $e_i$ in the subset in ascending order. Separate two adjacency elements by a space character.
Example
Input
4
2 0 2
Output
0:
1: 0
4: 2
5: 0 2 | instruction | 0 | 74,169 | 5 | 148,338 |
"Correct Solution:
```
import itertools
n = int(input())
k, *list_b = map(int, input().split())
list_d = []
for k in range(len(list_b) + 1):
for tuple_e in itertools.combinations(list_b, k):
d = 0
for bit in tuple_e:
d += 2 ** bit
list_d.append((d, tuple_e))
for d, tuple_e in sorted(list_d):
if tuple_e:
print(f"{d}: ", end="")
print(*tuple_e)
else:
print(f"{d}:")
``` | output | 1 | 74,169 | 5 | 148,339 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a set $T$, which is a subset of $S$. The set $S$ consists of $0, 1, ... n-1$. Print all subsets of $T$. Note that we represent $0, 1, ... n-1$ as 00...0001, 00...0010, 00...0100, ..., 10...0000 in binary respectively and the integer representation of a subset is calculated by bitwise OR of existing elements.
Constraints
* $1 \leq n \leq 28$
* $0 \leq k \leq 18$
* $k \leq n$
* $0 \leq b_i < n$
Input
The input is given in the following format.
$n$
$k \; b_0 \; b_1 \; ... \; b_{k-1}$
$k$ is the number of elements in $T$, and $b_i$ represents elements in $T$.
Output
Print the subsets ordered by their decimal integers. Print a subset in the following format.
$d$: $e_0$ $e_1$ ...
Print ':' after the integer value $d$, then print elements $e_i$ in the subset in ascending order. Separate two adjacency elements by a space character.
Example
Input
4
2 0 2
Output
0:
1: 0
4: 2
5: 0 2 | instruction | 0 | 74,170 | 5 | 148,340 |
"Correct Solution:
```
#!/usr/bin/env python3
# ITP2_11_C: Bitset 2 - Enumeration of Subsets 3
from functools import lru_cache
def subset(n, mask):
@lru_cache(maxsize=None)
def _subset(i):
if i < 0:
return [(0, [])]
m = mask[i]
return (_subset(i-1) +
[(v + (1 << m), vs + [m]) for v, vs in _subset(i-1)])
return _subset(len(mask)-1)
def run():
n = int(input())
mask = tuple([int(i) for i in input().split()][1:])
for i, vs in subset(n, mask):
print("{}:{}".format(i, "".join([" {}".format(v) for v in vs])))
if __name__ == '__main__':
run()
``` | output | 1 | 74,170 | 5 | 148,341 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a set $T$, which is a subset of $S$. The set $S$ consists of $0, 1, ... n-1$. Print all subsets of $T$. Note that we represent $0, 1, ... n-1$ as 00...0001, 00...0010, 00...0100, ..., 10...0000 in binary respectively and the integer representation of a subset is calculated by bitwise OR of existing elements.
Constraints
* $1 \leq n \leq 28$
* $0 \leq k \leq 18$
* $k \leq n$
* $0 \leq b_i < n$
Input
The input is given in the following format.
$n$
$k \; b_0 \; b_1 \; ... \; b_{k-1}$
$k$ is the number of elements in $T$, and $b_i$ represents elements in $T$.
Output
Print the subsets ordered by their decimal integers. Print a subset in the following format.
$d$: $e_0$ $e_1$ ...
Print ':' after the integer value $d$, then print elements $e_i$ in the subset in ascending order. Separate two adjacency elements by a space character.
Example
Input
4
2 0 2
Output
0:
1: 0
4: 2
5: 0 2 | instruction | 0 | 74,171 | 5 | 148,342 |
"Correct Solution:
```
n=int(input())
ind='0'+str(n)+'b'
t=list(map(int,input().split()))
k=t[0]
t.pop(0)
T=t
T.reverse()
ind='0'+str(k)+'b'
for i in range(2**k):
compare=[int(j) for j in format(i,ind)]
disp=[T[j] for j in range(k) if compare[j]==1]
disp.reverse()
if len(disp)==0:
print("0:")
else:
calc=[2**j for j in disp]
print(str(sum(calc))+":",end="")
print(" "+' '.join(map(str,disp)))
``` | output | 1 | 74,171 | 5 | 148,343 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a set $T$, which is a subset of $S$. The set $S$ consists of $0, 1, ... n-1$. Print all subsets of $T$. Note that we represent $0, 1, ... n-1$ as 00...0001, 00...0010, 00...0100, ..., 10...0000 in binary respectively and the integer representation of a subset is calculated by bitwise OR of existing elements.
Constraints
* $1 \leq n \leq 28$
* $0 \leq k \leq 18$
* $k \leq n$
* $0 \leq b_i < n$
Input
The input is given in the following format.
$n$
$k \; b_0 \; b_1 \; ... \; b_{k-1}$
$k$ is the number of elements in $T$, and $b_i$ represents elements in $T$.
Output
Print the subsets ordered by their decimal integers. Print a subset in the following format.
$d$: $e_0$ $e_1$ ...
Print ':' after the integer value $d$, then print elements $e_i$ in the subset in ascending order. Separate two adjacency elements by a space character.
Example
Input
4
2 0 2
Output
0:
1: 0
4: 2
5: 0 2 | instruction | 0 | 74,172 | 5 | 148,344 |
"Correct Solution:
```
from itertools import combinations
n = int(input())
k, *b_arr = map(int, input().split())
def calc_int(arr):
ret = 0
for i in arr:
ret += 1 << i
return ret
subsets = []
for i in range(len(b_arr)+1):
i_subsets = []
for sub in combinations(b_arr, i):
i_subsets.append((calc_int(sub), sub))
subsets.extend(i_subsets)
subsets.sort()
for sub in subsets:
print('{}: {}'.format(sub[0], ' '.join(map(str, sub[1])))) if len(sub[1]) != 0 else print(f'{sub[0]}:')
``` | output | 1 | 74,172 | 5 | 148,345 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a set $T$, which is a subset of $S$. The set $S$ consists of $0, 1, ... n-1$. Print all subsets of $T$. Note that we represent $0, 1, ... n-1$ as 00...0001, 00...0010, 00...0100, ..., 10...0000 in binary respectively and the integer representation of a subset is calculated by bitwise OR of existing elements.
Constraints
* $1 \leq n \leq 28$
* $0 \leq k \leq 18$
* $k \leq n$
* $0 \leq b_i < n$
Input
The input is given in the following format.
$n$
$k \; b_0 \; b_1 \; ... \; b_{k-1}$
$k$ is the number of elements in $T$, and $b_i$ represents elements in $T$.
Output
Print the subsets ordered by their decimal integers. Print a subset in the following format.
$d$: $e_0$ $e_1$ ...
Print ':' after the integer value $d$, then print elements $e_i$ in the subset in ascending order. Separate two adjacency elements by a space character.
Example
Input
4
2 0 2
Output
0:
1: 0
4: 2
5: 0 2
Submitted Solution:
```
n = int(input())
k, *b = map(int, input().split())
t = sum(1<<i for i in b)
for i in range(1 << k):
tmp = 0
rs = []
for j in range(k):
if i & (1 << j) != 0:
tmp |= 1 << b[j]
rs.append(b[j])
print(str(tmp)+":",*rs)
``` | instruction | 0 | 74,173 | 5 | 148,346 |
Yes | output | 1 | 74,173 | 5 | 148,347 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a set $T$, which is a subset of $S$. The set $S$ consists of $0, 1, ... n-1$. Print all subsets of $T$. Note that we represent $0, 1, ... n-1$ as 00...0001, 00...0010, 00...0100, ..., 10...0000 in binary respectively and the integer representation of a subset is calculated by bitwise OR of existing elements.
Constraints
* $1 \leq n \leq 28$
* $0 \leq k \leq 18$
* $k \leq n$
* $0 \leq b_i < n$
Input
The input is given in the following format.
$n$
$k \; b_0 \; b_1 \; ... \; b_{k-1}$
$k$ is the number of elements in $T$, and $b_i$ represents elements in $T$.
Output
Print the subsets ordered by their decimal integers. Print a subset in the following format.
$d$: $e_0$ $e_1$ ...
Print ':' after the integer value $d$, then print elements $e_i$ in the subset in ascending order. Separate two adjacency elements by a space character.
Example
Input
4
2 0 2
Output
0:
1: 0
4: 2
5: 0 2
Submitted Solution:
```
n = int(input())
k, *l = [int(x) for x in input().split()]
mbit =[]
for i in l:
mbit.append(i)
print("0:")
for i in range(1, 1<<len(mbit)):
num = 0
p = []
for j in range(len(mbit)):
if i & (1<<j) != 0:
num |= 1<<mbit[j]
p.append(mbit[j])
print("{}: ".format(num), end="")
print( *p )
``` | instruction | 0 | 74,174 | 5 | 148,348 |
Yes | output | 1 | 74,174 | 5 | 148,349 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a set $T$, which is a subset of $S$. The set $S$ consists of $0, 1, ... n-1$. Print all subsets of $T$. Note that we represent $0, 1, ... n-1$ as 00...0001, 00...0010, 00...0100, ..., 10...0000 in binary respectively and the integer representation of a subset is calculated by bitwise OR of existing elements.
Constraints
* $1 \leq n \leq 28$
* $0 \leq k \leq 18$
* $k \leq n$
* $0 \leq b_i < n$
Input
The input is given in the following format.
$n$
$k \; b_0 \; b_1 \; ... \; b_{k-1}$
$k$ is the number of elements in $T$, and $b_i$ represents elements in $T$.
Output
Print the subsets ordered by their decimal integers. Print a subset in the following format.
$d$: $e_0$ $e_1$ ...
Print ':' after the integer value $d$, then print elements $e_i$ in the subset in ascending order. Separate two adjacency elements by a space character.
Example
Input
4
2 0 2
Output
0:
1: 0
4: 2
5: 0 2
Submitted Solution:
```
from itertools import combinations
_ = input()
k, *B = map(int, input().split())
for v, combi in sorted([((sum([1 << cc for cc in c])), ' '.join(map(str, c))) for i in range(k + 1) for c in combinations(B, i)]):
print(f'{v}: {combi}' if v else '0:')
``` | instruction | 0 | 74,175 | 5 | 148,350 |
Yes | output | 1 | 74,175 | 5 | 148,351 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a set $T$, which is a subset of $S$. The set $S$ consists of $0, 1, ... n-1$. Print all subsets of $T$. Note that we represent $0, 1, ... n-1$ as 00...0001, 00...0010, 00...0100, ..., 10...0000 in binary respectively and the integer representation of a subset is calculated by bitwise OR of existing elements.
Constraints
* $1 \leq n \leq 28$
* $0 \leq k \leq 18$
* $k \leq n$
* $0 \leq b_i < n$
Input
The input is given in the following format.
$n$
$k \; b_0 \; b_1 \; ... \; b_{k-1}$
$k$ is the number of elements in $T$, and $b_i$ represents elements in $T$.
Output
Print the subsets ordered by their decimal integers. Print a subset in the following format.
$d$: $e_0$ $e_1$ ...
Print ':' after the integer value $d$, then print elements $e_i$ in the subset in ascending order. Separate two adjacency elements by a space character.
Example
Input
4
2 0 2
Output
0:
1: 0
4: 2
5: 0 2
Submitted Solution:
```
import itertools
n = int(input())
tlist = list(map(int, input().split()))
k = tlist[0]
tlist.remove(tlist[0])
if k == 0:
print("0:")
exit()
combslist = []
for i in range(1, k+1):
combs = list(itertools.combinations(tlist, i))
for comb in combs:
combslist.append(comb)
sumlist = []
for comb in combslist:
sum = 0
for c in comb:
sum += pow(2, c)
sumlist.append(sum)
z = zip(sumlist, combslist)
z = sorted(z)
sumlist, combslist = zip(*z)
print("0:")
for sum, comb in zip(sumlist, combslist):
c_str = (' '.join(str(c) for c in comb))
print(str(sum) + ": " + c_str)
``` | instruction | 0 | 74,176 | 5 | 148,352 |
Yes | output | 1 | 74,176 | 5 | 148,353 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence of n integers a_1, a_2, ..., a_n. Let us call an index j (2 ≤ j ≤ {{n-1}}) a hill if a_j > a_{{j+1}} and a_j > a_{{j-1}}; and let us call it a valley if a_j < a_{{j+1}} and a_j < a_{{j-1}}.
Let us define the intimidation value of a sequence as the sum of the number of hills and the number of valleys in the sequence. You can change exactly one integer in the sequence to any number that you want, or let the sequence remain unchanged. What is the minimum intimidation value that you can achieve?
Input
The first line of the input contains a single integer t (1 ≤ t ≤ 10000) — the number of test cases. The description of the test cases follows.
The first line of each test case contains a single integer n (1 ≤ n ≤ 3⋅10^5).
The second line of each test case contains n space-separated integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9).
It is guaranteed that the sum of n over all test cases does not exceed 3⋅10^5.
Output
For each test case, print a single integer — the minimum intimidation value that you can achieve.
Example
Input
4
3
1 5 3
5
2 2 2 2 2
6
1 6 2 5 2 10
5
1 6 2 5 1
Output
0
0
1
0
Note
In the first test case, changing a_2 to 2 results in no hills and no valleys.
In the second test case, the best answer is just to leave the array as it is.
In the third test case, changing a_3 to 6 results in only one valley (at the index 5).
In the fourth test case, changing a_3 to 6 results in no hills and no valleys.
Submitted Solution:
```
#!/usr/bin/env pypy3
from sys import stdin, stdout
def input(): return stdin.readline().strip()
def read_int_list(): return list(map(int, input().split()))
def read_int_tuple(): return tuple(map(int, input().split()))
def read_int(): return int(input())
### CODE HERE
def is_hv(A, i):
if not (0 <= i-1 < i+1 < len(A)): return False
if A[i] > max(A[i-1], A[i+1]): return True
if A[i] < min(A[i-1], A[i+1]): return True
return False
def is_hill(A, i):
if not (0 <= i-1 < i+1 < len(A)): return False
if A[i] > max(A[i-1], A[i+1]): return True
return False
def is_valley(A, i):
if not (0 <= i-1 < i+1 < len(A)): return False
if A[i] < min(A[i-1], A[i+1]): return True
return False
def count_hv(A):
ret = 0
for i in range(len(A)):
if is_hv(A, i):
ret += 1
return ret
def is_hv_cf(A, i, k, j):
old = A[i]
A[i] = k
ret = is_hv(A, j)
A[i] = old
return ret
def decrease_two(A):
for i in range(len(A)):
if is_hv(A, i) and is_hv(A, i+1):
if not is_hv_cf(A, i+1, A[i], i+2): return True
if not is_hv_cf(A, i, A[i+1], i-1): return True
return False
def decrease_three(A):
for i in range(len(A)):
if is_hv(A, i) and is_hv(A, i+1) and is_hv(A, i+2):
return True
return False
def ans(A):
initial_hv = count_hv(A)
if initial_hv in [0, 1]: return 0
if decrease_three(A): return initial_hv - 3
if decrease_two(A): return initial_hv - 2
return initial_hv - 1
return '?'
def ans_slow(A):
ret = count_hv(A)
for d in range(min(A), max(A)+1):
for i in range(len(A)):
new_A = A[:]
new_A[i] = d
ret = min(ret, count_hv(new_A))
return ret
for _ in range(read_int()):
input()
A = read_int_list()
print(ans(A))
``` | instruction | 0 | 74,394 | 5 | 148,788 |
Yes | output | 1 | 74,394 | 5 | 148,789 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence of n integers a_1, a_2, ..., a_n. Let us call an index j (2 ≤ j ≤ {{n-1}}) a hill if a_j > a_{{j+1}} and a_j > a_{{j-1}}; and let us call it a valley if a_j < a_{{j+1}} and a_j < a_{{j-1}}.
Let us define the intimidation value of a sequence as the sum of the number of hills and the number of valleys in the sequence. You can change exactly one integer in the sequence to any number that you want, or let the sequence remain unchanged. What is the minimum intimidation value that you can achieve?
Input
The first line of the input contains a single integer t (1 ≤ t ≤ 10000) — the number of test cases. The description of the test cases follows.
The first line of each test case contains a single integer n (1 ≤ n ≤ 3⋅10^5).
The second line of each test case contains n space-separated integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9).
It is guaranteed that the sum of n over all test cases does not exceed 3⋅10^5.
Output
For each test case, print a single integer — the minimum intimidation value that you can achieve.
Example
Input
4
3
1 5 3
5
2 2 2 2 2
6
1 6 2 5 2 10
5
1 6 2 5 1
Output
0
0
1
0
Note
In the first test case, changing a_2 to 2 results in no hills and no valleys.
In the second test case, the best answer is just to leave the array as it is.
In the third test case, changing a_3 to 6 results in only one valley (at the index 5).
In the fourth test case, changing a_3 to 6 results in no hills and no valleys.
Submitted Solution:
```
from sys import stdin, stdout
import math
import heapq
import collections
input = stdin.readline
def inputnum():
return(int(input()))
def inputnums():
return(map(int,input().split()))
def inputlist():
return(list(map(int,input().split())))
def inputstring():
return([x for x in input()])
def inputstrings():
return([x for x in input().split()])
def inputstringnum():
return([ord(x)-ord('a') for x in input()])
def inputmatrixchar(rows):
arr2d = [[j for j in input().strip()] for i in range(rows)]
return arr2d
def inputmatrixint(rows):
arr2d = []
for _ in range(rows):
arr2d.append([int(i) for i in input().split()])
return arr2d
t = int(input())
for q in range(t):
n = inputnum()
a = inputlist()
b = [0]*n
rtn = 0
for i in range(1, n-1):
if a[i] > a[i-1] and a[i] > a[i+1]:
rtn += 1
b[i] = 1
elif a[i] < a[i-1] and a[i] < a[i+1]:
rtn += 1
b[i] = -1
best = 0
for i in range(1, n-1):
cur = 0;
if b[i] != 0:
cur += 1
if b[i-1] != 0:
cur += 1
if b[i+1] != 0:
cur += 1
new1 = 0
if i > 1 and a[i-1] < a[i-2] and a[i-1] < a[i+1]:
new1 += 1
if i > 1 and a[i-1] > a[i-2] and a[i-1] > a[i+1]:
new1 += 1
new2 = 0
if i < n-2 and a[i+1] > a[i-1] and a[i+1] > a[i+2]:
new2 += 1
if i < n-2 and a[i+1] < a[i-1] and a[i+1] < a[i+2]:
new2 += 1
temp = max(cur-new1, cur-new2)
best = max(best, temp)
print(rtn-best)
``` | instruction | 0 | 74,396 | 5 | 148,792 |
Yes | output | 1 | 74,396 | 5 | 148,793 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence of n integers a_1, a_2, ..., a_n. Let us call an index j (2 ≤ j ≤ {{n-1}}) a hill if a_j > a_{{j+1}} and a_j > a_{{j-1}}; and let us call it a valley if a_j < a_{{j+1}} and a_j < a_{{j-1}}.
Let us define the intimidation value of a sequence as the sum of the number of hills and the number of valleys in the sequence. You can change exactly one integer in the sequence to any number that you want, or let the sequence remain unchanged. What is the minimum intimidation value that you can achieve?
Input
The first line of the input contains a single integer t (1 ≤ t ≤ 10000) — the number of test cases. The description of the test cases follows.
The first line of each test case contains a single integer n (1 ≤ n ≤ 3⋅10^5).
The second line of each test case contains n space-separated integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9).
It is guaranteed that the sum of n over all test cases does not exceed 3⋅10^5.
Output
For each test case, print a single integer — the minimum intimidation value that you can achieve.
Example
Input
4
3
1 5 3
5
2 2 2 2 2
6
1 6 2 5 2 10
5
1 6 2 5 1
Output
0
0
1
0
Note
In the first test case, changing a_2 to 2 results in no hills and no valleys.
In the second test case, the best answer is just to leave the array as it is.
In the third test case, changing a_3 to 6 results in only one valley (at the index 5).
In the fourth test case, changing a_3 to 6 results in no hills and no valleys.
Submitted Solution:
```
t=int(input())
for _ in range(t):
n=int(input())
a=list(map(int, input().split()))
hv=0
for i in range(1,n-1):
if (a[i]>a[i-1] and a[i]>a[i+1]) or (a[i]<a[i+1] and a[i]<a[i-1]):
hv+=1
if hv<=3:
print(0)
else:
print(hv-3)
``` | instruction | 0 | 74,398 | 5 | 148,796 |
No | output | 1 | 74,398 | 5 | 148,797 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence of n integers a_1, a_2, ..., a_n. Let us call an index j (2 ≤ j ≤ {{n-1}}) a hill if a_j > a_{{j+1}} and a_j > a_{{j-1}}; and let us call it a valley if a_j < a_{{j+1}} and a_j < a_{{j-1}}.
Let us define the intimidation value of a sequence as the sum of the number of hills and the number of valleys in the sequence. You can change exactly one integer in the sequence to any number that you want, or let the sequence remain unchanged. What is the minimum intimidation value that you can achieve?
Input
The first line of the input contains a single integer t (1 ≤ t ≤ 10000) — the number of test cases. The description of the test cases follows.
The first line of each test case contains a single integer n (1 ≤ n ≤ 3⋅10^5).
The second line of each test case contains n space-separated integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9).
It is guaranteed that the sum of n over all test cases does not exceed 3⋅10^5.
Output
For each test case, print a single integer — the minimum intimidation value that you can achieve.
Example
Input
4
3
1 5 3
5
2 2 2 2 2
6
1 6 2 5 2 10
5
1 6 2 5 1
Output
0
0
1
0
Note
In the first test case, changing a_2 to 2 results in no hills and no valleys.
In the second test case, the best answer is just to leave the array as it is.
In the third test case, changing a_3 to 6 results in only one valley (at the index 5).
In the fourth test case, changing a_3 to 6 results in no hills and no valleys.
Submitted Solution:
```
t = int(input())
for _ in range(t):
n= int(input())
A = list(map(int, input().split()))
#print(A)
x=0
flag = 0
for i in range(n):
if(i>=2 and i<=n-2):
if((A[i]>A[i-1] and A[i]>A[i+1]) or (A[i]<A[i-1] and A[i]<A[i+1])):
x+=1
if(A[i-1]==A[i+1]):
flag = 1
print(max(0, x-2, flag*(x-3)))
``` | instruction | 0 | 74,399 | 5 | 148,798 |
No | output | 1 | 74,399 | 5 | 148,799 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence of n integers a_1, a_2, ..., a_n. Let us call an index j (2 ≤ j ≤ {{n-1}}) a hill if a_j > a_{{j+1}} and a_j > a_{{j-1}}; and let us call it a valley if a_j < a_{{j+1}} and a_j < a_{{j-1}}.
Let us define the intimidation value of a sequence as the sum of the number of hills and the number of valleys in the sequence. You can change exactly one integer in the sequence to any number that you want, or let the sequence remain unchanged. What is the minimum intimidation value that you can achieve?
Input
The first line of the input contains a single integer t (1 ≤ t ≤ 10000) — the number of test cases. The description of the test cases follows.
The first line of each test case contains a single integer n (1 ≤ n ≤ 3⋅10^5).
The second line of each test case contains n space-separated integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9).
It is guaranteed that the sum of n over all test cases does not exceed 3⋅10^5.
Output
For each test case, print a single integer — the minimum intimidation value that you can achieve.
Example
Input
4
3
1 5 3
5
2 2 2 2 2
6
1 6 2 5 2 10
5
1 6 2 5 1
Output
0
0
1
0
Note
In the first test case, changing a_2 to 2 results in no hills and no valleys.
In the second test case, the best answer is just to leave the array as it is.
In the third test case, changing a_3 to 6 results in only one valley (at the index 5).
In the fourth test case, changing a_3 to 6 results in no hills and no valleys.
Submitted Solution:
```
for _ in range(int(input())):
n=int(input())
l=list(map(int,input().split()))
for i in range(n-2):
if l[i]<l[i+1]:
if l[i+1]>l[i+2]:
l[i+2]=l[i+1]
break
else:
if l[i+1]<l[i+2]:
l[i+2]=l[i+1]
break
hv=0
ma=l[0]
for i in range(1,n-1):
if l[i]>ma and l[i+1]<l[i]:
hv+=1
if ma>l[i] and l[i+1]>l[i]:
hv+=1
ma=l[i]
print(hv)
``` | instruction | 0 | 74,400 | 5 | 148,800 |
No | output | 1 | 74,400 | 5 | 148,801 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Baby Badawy's first words were "AND 0 SUM BIG", so he decided to solve the following problem. Given two integers n and k, count the number of arrays of length n such that:
* all its elements are integers between 0 and 2^k-1 (inclusive);
* the [bitwise AND](https://en.wikipedia.org/wiki/Bitwise_operation#AND) of all its elements is 0;
* the sum of its elements is as large as possible.
Since the answer can be very large, print its remainder when divided by 10^9+7.
Input
The first line contains an integer t (1 ≤ t ≤ 10) — the number of test cases you need to solve.
Each test case consists of a line containing two integers n and k (1 ≤ n ≤ 10^{5}, 1 ≤ k ≤ 20).
Output
For each test case, print the number of arrays satisfying the conditions. Since the answer can be very large, print its remainder when divided by 10^9+7.
Example
Input
2
2 2
100000 20
Output
4
226732710
Note
In the first example, the 4 arrays are:
* [3,0],
* [0,3],
* [1,2],
* [2,1].
Submitted Solution:
```
t = int(input())
CONST = (10**9 + 7)
for i in range(t):
n, k = [int(i) for i in input().split()]
ans = n**k
print(ans % CONST)
``` | instruction | 0 | 74,426 | 5 | 148,852 |
Yes | output | 1 | 74,426 | 5 | 148,853 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Baby Badawy's first words were "AND 0 SUM BIG", so he decided to solve the following problem. Given two integers n and k, count the number of arrays of length n such that:
* all its elements are integers between 0 and 2^k-1 (inclusive);
* the [bitwise AND](https://en.wikipedia.org/wiki/Bitwise_operation#AND) of all its elements is 0;
* the sum of its elements is as large as possible.
Since the answer can be very large, print its remainder when divided by 10^9+7.
Input
The first line contains an integer t (1 ≤ t ≤ 10) — the number of test cases you need to solve.
Each test case consists of a line containing two integers n and k (1 ≤ n ≤ 10^{5}, 1 ≤ k ≤ 20).
Output
For each test case, print the number of arrays satisfying the conditions. Since the answer can be very large, print its remainder when divided by 10^9+7.
Example
Input
2
2 2
100000 20
Output
4
226732710
Note
In the first example, the 4 arrays are:
* [3,0],
* [0,3],
* [1,2],
* [2,1].
Submitted Solution:
```
import math
def main():
for i in range(int(input())):
n,k =map(int,input().split())
print((n**k)%(10**9+7))
if __name__ == '__main__':
main()
``` | instruction | 0 | 74,427 | 5 | 148,854 |
Yes | output | 1 | 74,427 | 5 | 148,855 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Baby Badawy's first words were "AND 0 SUM BIG", so he decided to solve the following problem. Given two integers n and k, count the number of arrays of length n such that:
* all its elements are integers between 0 and 2^k-1 (inclusive);
* the [bitwise AND](https://en.wikipedia.org/wiki/Bitwise_operation#AND) of all its elements is 0;
* the sum of its elements is as large as possible.
Since the answer can be very large, print its remainder when divided by 10^9+7.
Input
The first line contains an integer t (1 ≤ t ≤ 10) — the number of test cases you need to solve.
Each test case consists of a line containing two integers n and k (1 ≤ n ≤ 10^{5}, 1 ≤ k ≤ 20).
Output
For each test case, print the number of arrays satisfying the conditions. Since the answer can be very large, print its remainder when divided by 10^9+7.
Example
Input
2
2 2
100000 20
Output
4
226732710
Note
In the first example, the 4 arrays are:
* [3,0],
* [0,3],
* [1,2],
* [2,1].
Submitted Solution:
```
T=int(input())
for x in range(T):
a=[int(y) for y in input().split()]
n=a[0]
k=a[1]
b=n**k
print(b%1000000007)
``` | instruction | 0 | 74,428 | 5 | 148,856 |
Yes | output | 1 | 74,428 | 5 | 148,857 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Baby Badawy's first words were "AND 0 SUM BIG", so he decided to solve the following problem. Given two integers n and k, count the number of arrays of length n such that:
* all its elements are integers between 0 and 2^k-1 (inclusive);
* the [bitwise AND](https://en.wikipedia.org/wiki/Bitwise_operation#AND) of all its elements is 0;
* the sum of its elements is as large as possible.
Since the answer can be very large, print its remainder when divided by 10^9+7.
Input
The first line contains an integer t (1 ≤ t ≤ 10) — the number of test cases you need to solve.
Each test case consists of a line containing two integers n and k (1 ≤ n ≤ 10^{5}, 1 ≤ k ≤ 20).
Output
For each test case, print the number of arrays satisfying the conditions. Since the answer can be very large, print its remainder when divided by 10^9+7.
Example
Input
2
2 2
100000 20
Output
4
226732710
Note
In the first example, the 4 arrays are:
* [3,0],
* [0,3],
* [1,2],
* [2,1].
Submitted Solution:
```
MOD = pow(10, 9) + 7
def Solve(n, k):
return pow(n, k)%MOD
for _ in range(int(input())):
n, k = map(int, input().split())
print(Solve(n, k))
``` | instruction | 0 | 74,429 | 5 | 148,858 |
Yes | output | 1 | 74,429 | 5 | 148,859 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Baby Badawy's first words were "AND 0 SUM BIG", so he decided to solve the following problem. Given two integers n and k, count the number of arrays of length n such that:
* all its elements are integers between 0 and 2^k-1 (inclusive);
* the [bitwise AND](https://en.wikipedia.org/wiki/Bitwise_operation#AND) of all its elements is 0;
* the sum of its elements is as large as possible.
Since the answer can be very large, print its remainder when divided by 10^9+7.
Input
The first line contains an integer t (1 ≤ t ≤ 10) — the number of test cases you need to solve.
Each test case consists of a line containing two integers n and k (1 ≤ n ≤ 10^{5}, 1 ≤ k ≤ 20).
Output
For each test case, print the number of arrays satisfying the conditions. Since the answer can be very large, print its remainder when divided by 10^9+7.
Example
Input
2
2 2
100000 20
Output
4
226732710
Note
In the first example, the 4 arrays are:
* [3,0],
* [0,3],
* [1,2],
* [2,1].
Submitted Solution:
```
for _ in range(0,int(input())):
l, power = map(int, input().split())
count = 0
n = 2**power
choices = l+1
for i in range(0,2**power):
if(i&1 == 0):
count += choices
print(count%(10**9+7))
``` | instruction | 0 | 74,430 | 5 | 148,860 |
No | output | 1 | 74,430 | 5 | 148,861 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Baby Badawy's first words were "AND 0 SUM BIG", so he decided to solve the following problem. Given two integers n and k, count the number of arrays of length n such that:
* all its elements are integers between 0 and 2^k-1 (inclusive);
* the [bitwise AND](https://en.wikipedia.org/wiki/Bitwise_operation#AND) of all its elements is 0;
* the sum of its elements is as large as possible.
Since the answer can be very large, print its remainder when divided by 10^9+7.
Input
The first line contains an integer t (1 ≤ t ≤ 10) — the number of test cases you need to solve.
Each test case consists of a line containing two integers n and k (1 ≤ n ≤ 10^{5}, 1 ≤ k ≤ 20).
Output
For each test case, print the number of arrays satisfying the conditions. Since the answer can be very large, print its remainder when divided by 10^9+7.
Example
Input
2
2 2
100000 20
Output
4
226732710
Note
In the first example, the 4 arrays are:
* [3,0],
* [0,3],
* [1,2],
* [2,1].
Submitted Solution:
```
t = int(input())
for i in range(t):
line = input().split(" ")
n = int(line[0])
k = int(line[1])
mod = 1**9 + 7
ans = n
for i in range(k):
ans = (n * ans) % mod
print(ans)
``` | instruction | 0 | 74,431 | 5 | 148,862 |
No | output | 1 | 74,431 | 5 | 148,863 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Baby Badawy's first words were "AND 0 SUM BIG", so he decided to solve the following problem. Given two integers n and k, count the number of arrays of length n such that:
* all its elements are integers between 0 and 2^k-1 (inclusive);
* the [bitwise AND](https://en.wikipedia.org/wiki/Bitwise_operation#AND) of all its elements is 0;
* the sum of its elements is as large as possible.
Since the answer can be very large, print its remainder when divided by 10^9+7.
Input
The first line contains an integer t (1 ≤ t ≤ 10) — the number of test cases you need to solve.
Each test case consists of a line containing two integers n and k (1 ≤ n ≤ 10^{5}, 1 ≤ k ≤ 20).
Output
For each test case, print the number of arrays satisfying the conditions. Since the answer can be very large, print its remainder when divided by 10^9+7.
Example
Input
2
2 2
100000 20
Output
4
226732710
Note
In the first example, the 4 arrays are:
* [3,0],
* [0,3],
* [1,2],
* [2,1].
Submitted Solution:
```
import math
for _ in range(int(input())):
n,k=map(int,input().split())
print(int(math.pow(n,k)%1000000007))
``` | instruction | 0 | 74,432 | 5 | 148,864 |
No | output | 1 | 74,432 | 5 | 148,865 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Baby Badawy's first words were "AND 0 SUM BIG", so he decided to solve the following problem. Given two integers n and k, count the number of arrays of length n such that:
* all its elements are integers between 0 and 2^k-1 (inclusive);
* the [bitwise AND](https://en.wikipedia.org/wiki/Bitwise_operation#AND) of all its elements is 0;
* the sum of its elements is as large as possible.
Since the answer can be very large, print its remainder when divided by 10^9+7.
Input
The first line contains an integer t (1 ≤ t ≤ 10) — the number of test cases you need to solve.
Each test case consists of a line containing two integers n and k (1 ≤ n ≤ 10^{5}, 1 ≤ k ≤ 20).
Output
For each test case, print the number of arrays satisfying the conditions. Since the answer can be very large, print its remainder when divided by 10^9+7.
Example
Input
2
2 2
100000 20
Output
4
226732710
Note
In the first example, the 4 arrays are:
* [3,0],
* [0,3],
* [1,2],
* [2,1].
Submitted Solution:
```
def fun(n,k):
ans=1
while(k):
ans*=n
k-=1
return ans
m=10**9+7
for _ in range(int(input())):
n,k=map(int,input().split())
k=min(k,n)
ans=n+fun(n,k)
print(ans%m)
``` | instruction | 0 | 74,433 | 5 | 148,866 |
No | output | 1 | 74,433 | 5 | 148,867 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array a_1, a_2, ..., a_n consisting of n distinct integers. Count the number of pairs of indices (i, j) such that i < j and a_i ⋅ a_j = i + j.
Input
The first line contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t cases follow.
The first line of each test case contains one integer n (2 ≤ n ≤ 10^5) — the length of array a.
The second line of each test case contains n space separated integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 2 ⋅ n) — the array a. It is guaranteed that all elements are distinct.
It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5.
Output
For each test case, output the number of pairs of indices (i, j) such that i < j and a_i ⋅ a_j = i + j.
Example
Input
3
2
3 1
3
6 1 5
5
3 1 5 9 2
Output
1
1
3
Note
For the first test case, the only pair that satisfies the constraints is (1, 2), as a_1 ⋅ a_2 = 1 + 2 = 3
For the second test case, the only pair that satisfies the constraints is (2, 3).
For the third test case, the pairs that satisfy the constraints are (1, 2), (1, 5), and (2, 3).
Submitted Solution:
```
from sys import stdin
input=stdin.readline
rn=lambda:int(input())
rns=lambda:map(int,input().split())
rl=lambda:list(map(int,input().split()))
rs=lambda:input().strip()
YN=lambda x:print('YES') if x else print('NO')
mod=10**9+7
for _ in range(rn()):
n=rn()
a=rl()
a = [(a[i], i+1) for i in range(n)]
a.sort()
ans = 0
for i in range(n):
for j in range(i+1, n):
if a[i][0] * a[j][0] > 2*n:
break
if a[i][0] * a[j][0] == a[i][1]+a[j][1]:
ans+=1
print(ans)
``` | instruction | 0 | 74,442 | 5 | 148,884 |
Yes | output | 1 | 74,442 | 5 | 148,885 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array a_1, a_2, ..., a_n consisting of n distinct integers. Count the number of pairs of indices (i, j) such that i < j and a_i ⋅ a_j = i + j.
Input
The first line contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t cases follow.
The first line of each test case contains one integer n (2 ≤ n ≤ 10^5) — the length of array a.
The second line of each test case contains n space separated integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 2 ⋅ n) — the array a. It is guaranteed that all elements are distinct.
It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5.
Output
For each test case, output the number of pairs of indices (i, j) such that i < j and a_i ⋅ a_j = i + j.
Example
Input
3
2
3 1
3
6 1 5
5
3 1 5 9 2
Output
1
1
3
Note
For the first test case, the only pair that satisfies the constraints is (1, 2), as a_1 ⋅ a_2 = 1 + 2 = 3
For the second test case, the only pair that satisfies the constraints is (2, 3).
For the third test case, the pairs that satisfy the constraints are (1, 2), (1, 5), and (2, 3).
Submitted Solution:
```
import math
for _ in range(int(input())):
n = int(input())
l = [10**6 for i in range(2*n+1)]
l1 =list(map(int,input().split()))
for i in range(n):
l[l1[i]] = i + 1
#print(l)
count = 0
for i in range(3,2*n):
for j in range(1,int(math.sqrt(i))+1):
if i % j == 0 and i != j*j:
if l[j] + l[int(i/j)] == i:
count = count + 1
print(count)
``` | instruction | 0 | 74,443 | 5 | 148,886 |
Yes | output | 1 | 74,443 | 5 | 148,887 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array a_1, a_2, ..., a_n consisting of n distinct integers. Count the number of pairs of indices (i, j) such that i < j and a_i ⋅ a_j = i + j.
Input
The first line contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t cases follow.
The first line of each test case contains one integer n (2 ≤ n ≤ 10^5) — the length of array a.
The second line of each test case contains n space separated integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 2 ⋅ n) — the array a. It is guaranteed that all elements are distinct.
It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5.
Output
For each test case, output the number of pairs of indices (i, j) such that i < j and a_i ⋅ a_j = i + j.
Example
Input
3
2
3 1
3
6 1 5
5
3 1 5 9 2
Output
1
1
3
Note
For the first test case, the only pair that satisfies the constraints is (1, 2), as a_1 ⋅ a_2 = 1 + 2 = 3
For the second test case, the only pair that satisfies the constraints is (2, 3).
For the third test case, the pairs that satisfy the constraints are (1, 2), (1, 5), and (2, 3).
Submitted Solution:
```
import sys
import math
import random
from queue import PriorityQueue as PQ
from bisect import bisect_left as BSL
from bisect import bisect_right as BSR
from collections import OrderedDict as OD
from collections import Counter
from itertools import permutations
# mod = 998244353
mod = 1000000007
sys.setrecursionlimit(1000000)
try:
sys.stdin = open("actext.txt", "r")
OPENFILE = 1
except:
pass
def get_ints():
return map(int,input().split())
def palindrome(s):
mid = len(s)//2
for i in range(mid):
if(s[i]!=s[len(s)-i-1]):
return False
return True
def check(i,n):
if(0<=i<n):
return True
else:
return False
# --------------------------------------------------------------------------
def solve(arr,n):
counter = 0
for num,i in enumerate(arr):
num = num+1
val = 1
j = 0
# print(i)
while(val<=n):
val = i*j - num
# print(val,j,i,num)
# if(1<= val <=n):
# print(arr[val-1])
if(1<= val <=n and arr[val-1]==j and val>num):
counter+=1
j+=1
print(counter)
t = int(input())
for tt in range(t):
n = int(input())
arr = list(get_ints())
solve(arr,n)
``` | instruction | 0 | 74,444 | 5 | 148,888 |
Yes | output | 1 | 74,444 | 5 | 148,889 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array a_1, a_2, ..., a_n consisting of n distinct integers. Count the number of pairs of indices (i, j) such that i < j and a_i ⋅ a_j = i + j.
Input
The first line contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t cases follow.
The first line of each test case contains one integer n (2 ≤ n ≤ 10^5) — the length of array a.
The second line of each test case contains n space separated integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 2 ⋅ n) — the array a. It is guaranteed that all elements are distinct.
It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5.
Output
For each test case, output the number of pairs of indices (i, j) such that i < j and a_i ⋅ a_j = i + j.
Example
Input
3
2
3 1
3
6 1 5
5
3 1 5 9 2
Output
1
1
3
Note
For the first test case, the only pair that satisfies the constraints is (1, 2), as a_1 ⋅ a_2 = 1 + 2 = 3
For the second test case, the only pair that satisfies the constraints is (2, 3).
For the third test case, the pairs that satisfy the constraints are (1, 2), (1, 5), and (2, 3).
Submitted Solution:
```
n = int(input())
for m in range(n):
x = int(input())
l = list(map(int, input().split()))
k = 0
for i in range(x - 1):
for j in range (i + 1, x, l[i]):
if (l[i]*l[j]==i+j+2):
k = k+1
print(k)
``` | instruction | 0 | 74,446 | 5 | 148,892 |
No | output | 1 | 74,446 | 5 | 148,893 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array a_1, a_2, ..., a_n consisting of n distinct integers. Count the number of pairs of indices (i, j) such that i < j and a_i ⋅ a_j = i + j.
Input
The first line contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t cases follow.
The first line of each test case contains one integer n (2 ≤ n ≤ 10^5) — the length of array a.
The second line of each test case contains n space separated integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 2 ⋅ n) — the array a. It is guaranteed that all elements are distinct.
It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5.
Output
For each test case, output the number of pairs of indices (i, j) such that i < j and a_i ⋅ a_j = i + j.
Example
Input
3
2
3 1
3
6 1 5
5
3 1 5 9 2
Output
1
1
3
Note
For the first test case, the only pair that satisfies the constraints is (1, 2), as a_1 ⋅ a_2 = 1 + 2 = 3
For the second test case, the only pair that satisfies the constraints is (2, 3).
For the third test case, the pairs that satisfy the constraints are (1, 2), (1, 5), and (2, 3).
Submitted Solution:
```
for h in range(int(input())):
r=int(input())
u=list(map(int,input().split()))
#print(u)
res=0
#print()
for i in range(r):
for j in range(u[i]-2, r, u[i]):
x = u[i]-i-2, r, u[i]
#print(str(x))
#print(i)
#print(j)
if i+j+2==u[i]*u[j] and i<j:
res+=1
#print("ADDED" + str(i)+ " " +str(j))
print(res)
#print()
``` | instruction | 0 | 74,447 | 5 | 148,894 |
No | output | 1 | 74,447 | 5 | 148,895 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array a_1, a_2, ..., a_n consisting of n distinct integers. Count the number of pairs of indices (i, j) such that i < j and a_i ⋅ a_j = i + j.
Input
The first line contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t cases follow.
The first line of each test case contains one integer n (2 ≤ n ≤ 10^5) — the length of array a.
The second line of each test case contains n space separated integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 2 ⋅ n) — the array a. It is guaranteed that all elements are distinct.
It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5.
Output
For each test case, output the number of pairs of indices (i, j) such that i < j and a_i ⋅ a_j = i + j.
Example
Input
3
2
3 1
3
6 1 5
5
3 1 5 9 2
Output
1
1
3
Note
For the first test case, the only pair that satisfies the constraints is (1, 2), as a_1 ⋅ a_2 = 1 + 2 = 3
For the second test case, the only pair that satisfies the constraints is (2, 3).
For the third test case, the pairs that satisfy the constraints are (1, 2), (1, 5), and (2, 3).
Submitted Solution:
```
from sys import stdin
input=stdin.readline
for _ in range(int(input())):
n=int(input())
arr=list(map(int,input().split()))
req=(2*n)**0.5+100
l=[]
ind=-1
ans = 0
for i in range(n):
if (arr[i]==1):
ind=i
break
if (ind!=-1):
arr[ind]=-1
for i in range(n):
if (i!=ind and (i+1+ind+1)==arr[i]):
ans+=1
for i in range(n):
if (arr[i]>req or arr[i]==-1):
arr[i]=-1
else:
l.append([arr[i],i])
l.sort()
for i in range(len(l)):
for j in range(i+1,len(l)):
if (l[i][0]*l[j][0]==l[i][1]+l[j][1]+2):
ans+=1
else:
break
print(ans)
``` | instruction | 0 | 74,448 | 5 | 148,896 |
No | output | 1 | 74,448 | 5 | 148,897 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array a_1, a_2, ..., a_n consisting of n distinct integers. Count the number of pairs of indices (i, j) such that i < j and a_i ⋅ a_j = i + j.
Input
The first line contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t cases follow.
The first line of each test case contains one integer n (2 ≤ n ≤ 10^5) — the length of array a.
The second line of each test case contains n space separated integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 2 ⋅ n) — the array a. It is guaranteed that all elements are distinct.
It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5.
Output
For each test case, output the number of pairs of indices (i, j) such that i < j and a_i ⋅ a_j = i + j.
Example
Input
3
2
3 1
3
6 1 5
5
3 1 5 9 2
Output
1
1
3
Note
For the first test case, the only pair that satisfies the constraints is (1, 2), as a_1 ⋅ a_2 = 1 + 2 = 3
For the second test case, the only pair that satisfies the constraints is (2, 3).
For the third test case, the pairs that satisfy the constraints are (1, 2), (1, 5), and (2, 3).
Submitted Solution:
```
from sys import stdin,stdout
stdin.readline
def mp(): return list(map(int, stdin.readline().strip().split()))
def it():return int(stdin.readline().strip())
from collections import defaultdict as dd,Counter as C,deque
from math import ceil,gcd,sqrt,factorial,log2,floor
# from bisect import bisect_right as br,bisect_left as bl
import heapq
for _ in range(it()):
n = it()
l = mp()
ans = 0
for i in range(n):
for j in range(l[i]-i , n , l[i]):
if j+1>0:
if l[i]*l[j] == i+j+2:
ans += 1
print(ans)
``` | instruction | 0 | 74,449 | 5 | 148,898 |
No | output | 1 | 74,449 | 5 | 148,899 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two very long integers a, b (leading zeroes are allowed). You should check what number a or b is greater or determine that they are equal.
The input size is very large so don't use the reading of symbols one by one. Instead of that use the reading of a whole line or token.
As input/output can reach huge size it is recommended to use fast input/output methods: for example, prefer to use scanf/printf instead of cin/cout in C++, prefer to use BufferedReader/PrintWriter instead of Scanner/System.out in Java. Don't use the function input() in Python2 instead of it use the function raw_input().
Input
The first line contains a non-negative integer a.
The second line contains a non-negative integer b.
The numbers a, b may contain leading zeroes. Each of them contains no more than 106 digits.
Output
Print the symbol "<" if a < b and the symbol ">" if a > b. If the numbers are equal print the symbol "=".
Examples
Input
9
10
Output
<
Input
11
10
Output
>
Input
00012345
12345
Output
=
Input
0123
9
Output
>
Input
0123
111
Output
>
Submitted Solution:
```
import sys
input=sys.stdin.readline
inst=lambda: input().rstrip('\n\r')
inin=lambda: int(input())
inar=lambda: list(map(int,input().split()))
a=inst().lstrip('0')
b=inst().lstrip('0')
if len(a)<len(b):
print('<')
elif len(a)>len(b):
print('>')
else:
if a<b:
print('<')
elif a>b:
print('>')
else:
print('=')
``` | instruction | 0 | 74,580 | 5 | 149,160 |
Yes | output | 1 | 74,580 | 5 | 149,161 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two very long integers a, b (leading zeroes are allowed). You should check what number a or b is greater or determine that they are equal.
The input size is very large so don't use the reading of symbols one by one. Instead of that use the reading of a whole line or token.
As input/output can reach huge size it is recommended to use fast input/output methods: for example, prefer to use scanf/printf instead of cin/cout in C++, prefer to use BufferedReader/PrintWriter instead of Scanner/System.out in Java. Don't use the function input() in Python2 instead of it use the function raw_input().
Input
The first line contains a non-negative integer a.
The second line contains a non-negative integer b.
The numbers a, b may contain leading zeroes. Each of them contains no more than 106 digits.
Output
Print the symbol "<" if a < b and the symbol ">" if a > b. If the numbers are equal print the symbol "=".
Examples
Input
9
10
Output
<
Input
11
10
Output
>
Input
00012345
12345
Output
=
Input
0123
9
Output
>
Input
0123
111
Output
>
Submitted Solution:
```
a = input()
b = input()
l = max(len(a), len(b))
da = len(a) - l
db = len(b) - l
for i in range(l):
start_a = '0'
if da + i >= 0:
start_a = a[da+i]
start_b = '0'
if db + i >= 0:
start_b = b[db + i]
if start_a < start_b:
print('<')
exit(0)
else:
if start_a > start_b:
print('>')
exit(0)
print('=')
``` | instruction | 0 | 74,581 | 5 | 149,162 |
Yes | output | 1 | 74,581 | 5 | 149,163 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two very long integers a, b (leading zeroes are allowed). You should check what number a or b is greater or determine that they are equal.
The input size is very large so don't use the reading of symbols one by one. Instead of that use the reading of a whole line or token.
As input/output can reach huge size it is recommended to use fast input/output methods: for example, prefer to use scanf/printf instead of cin/cout in C++, prefer to use BufferedReader/PrintWriter instead of Scanner/System.out in Java. Don't use the function input() in Python2 instead of it use the function raw_input().
Input
The first line contains a non-negative integer a.
The second line contains a non-negative integer b.
The numbers a, b may contain leading zeroes. Each of them contains no more than 106 digits.
Output
Print the symbol "<" if a < b and the symbol ">" if a > b. If the numbers are equal print the symbol "=".
Examples
Input
9
10
Output
<
Input
11
10
Output
>
Input
00012345
12345
Output
=
Input
0123
9
Output
>
Input
0123
111
Output
>
Submitted Solution:
```
a=input()
b=input()
for x in a:
if x!="0":
a=a[a.index(x):]
break
else:
a="0"
for y in b:
if y!="0":
b=b[b.index(y):]
break
else:
b="0"
if a==b:
print("=")
elif len(a)>len(b):
print(">")
elif len(a)<len(b):
print("<")
else:
if a>b:
print(">")
elif a<b:
print("<")
``` | instruction | 0 | 74,582 | 5 | 149,164 |
Yes | output | 1 | 74,582 | 5 | 149,165 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two very long integers a, b (leading zeroes are allowed). You should check what number a or b is greater or determine that they are equal.
The input size is very large so don't use the reading of symbols one by one. Instead of that use the reading of a whole line or token.
As input/output can reach huge size it is recommended to use fast input/output methods: for example, prefer to use scanf/printf instead of cin/cout in C++, prefer to use BufferedReader/PrintWriter instead of Scanner/System.out in Java. Don't use the function input() in Python2 instead of it use the function raw_input().
Input
The first line contains a non-negative integer a.
The second line contains a non-negative integer b.
The numbers a, b may contain leading zeroes. Each of them contains no more than 106 digits.
Output
Print the symbol "<" if a < b and the symbol ">" if a > b. If the numbers are equal print the symbol "=".
Examples
Input
9
10
Output
<
Input
11
10
Output
>
Input
00012345
12345
Output
=
Input
0123
9
Output
>
Input
0123
111
Output
>
Submitted Solution:
```
a, b = input(), input()
a = '0'*(len(b) - len(a)) + a
b = '0'*(len(a) - len(b)) + b
if a < b:
print('<')
elif a > b:
print('>')
else:
print('=')
``` | instruction | 0 | 74,583 | 5 | 149,166 |
Yes | output | 1 | 74,583 | 5 | 149,167 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two very long integers a, b (leading zeroes are allowed). You should check what number a or b is greater or determine that they are equal.
The input size is very large so don't use the reading of symbols one by one. Instead of that use the reading of a whole line or token.
As input/output can reach huge size it is recommended to use fast input/output methods: for example, prefer to use scanf/printf instead of cin/cout in C++, prefer to use BufferedReader/PrintWriter instead of Scanner/System.out in Java. Don't use the function input() in Python2 instead of it use the function raw_input().
Input
The first line contains a non-negative integer a.
The second line contains a non-negative integer b.
The numbers a, b may contain leading zeroes. Each of them contains no more than 106 digits.
Output
Print the symbol "<" if a < b and the symbol ">" if a > b. If the numbers are equal print the symbol "=".
Examples
Input
9
10
Output
<
Input
11
10
Output
>
Input
00012345
12345
Output
=
Input
0123
9
Output
>
Input
0123
111
Output
>
Submitted Solution:
```
a = input()
b = input()
l = max(len(a), len(b))
da = len(a) - 1
db = len(b) - 1
for i in range(1):
start_a = '0'
if da + i >= 0:
start_a = a[da+i]
start_b = '0'
if db + i >= 0:
start_b = b[db + i]
if start_a < start_b:
print('<')
exit(0)
elif start_a > start_b:
print('>')
exit(0)
else:
print('=')
exit(0)
``` | instruction | 0 | 74,584 | 5 | 149,168 |
No | output | 1 | 74,584 | 5 | 149,169 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two very long integers a, b (leading zeroes are allowed). You should check what number a or b is greater or determine that they are equal.
The input size is very large so don't use the reading of symbols one by one. Instead of that use the reading of a whole line or token.
As input/output can reach huge size it is recommended to use fast input/output methods: for example, prefer to use scanf/printf instead of cin/cout in C++, prefer to use BufferedReader/PrintWriter instead of Scanner/System.out in Java. Don't use the function input() in Python2 instead of it use the function raw_input().
Input
The first line contains a non-negative integer a.
The second line contains a non-negative integer b.
The numbers a, b may contain leading zeroes. Each of them contains no more than 106 digits.
Output
Print the symbol "<" if a < b and the symbol ">" if a > b. If the numbers are equal print the symbol "=".
Examples
Input
9
10
Output
<
Input
11
10
Output
>
Input
00012345
12345
Output
=
Input
0123
9
Output
>
Input
0123
111
Output
>
Submitted Solution:
```
a = input()
b = input()
l1 = len(a)
l2 = len(b)
k = int(a)
t = int(b)
if l1>l2: print('>')
elif k>t: print('>')
elif k<t: print('<')
else: print('=')
``` | instruction | 0 | 74,585 | 5 | 149,170 |
No | output | 1 | 74,585 | 5 | 149,171 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two very long integers a, b (leading zeroes are allowed). You should check what number a or b is greater or determine that they are equal.
The input size is very large so don't use the reading of symbols one by one. Instead of that use the reading of a whole line or token.
As input/output can reach huge size it is recommended to use fast input/output methods: for example, prefer to use scanf/printf instead of cin/cout in C++, prefer to use BufferedReader/PrintWriter instead of Scanner/System.out in Java. Don't use the function input() in Python2 instead of it use the function raw_input().
Input
The first line contains a non-negative integer a.
The second line contains a non-negative integer b.
The numbers a, b may contain leading zeroes. Each of them contains no more than 106 digits.
Output
Print the symbol "<" if a < b and the symbol ">" if a > b. If the numbers are equal print the symbol "=".
Examples
Input
9
10
Output
<
Input
11
10
Output
>
Input
00012345
12345
Output
=
Input
0123
9
Output
>
Input
0123
111
Output
>
Submitted Solution:
```
a = int(input())
b = int(input())
if((a*1)<(b*1),1<=a<=10**6,1<=b<=10**6):
print("<")
elif((a*1)==(b*1),1<=a<=10**6,1<=b<=10**6):
print("=")
else:
print(">")
``` | instruction | 0 | 74,586 | 5 | 149,172 |
No | output | 1 | 74,586 | 5 | 149,173 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two very long integers a, b (leading zeroes are allowed). You should check what number a or b is greater or determine that they are equal.
The input size is very large so don't use the reading of symbols one by one. Instead of that use the reading of a whole line or token.
As input/output can reach huge size it is recommended to use fast input/output methods: for example, prefer to use scanf/printf instead of cin/cout in C++, prefer to use BufferedReader/PrintWriter instead of Scanner/System.out in Java. Don't use the function input() in Python2 instead of it use the function raw_input().
Input
The first line contains a non-negative integer a.
The second line contains a non-negative integer b.
The numbers a, b may contain leading zeroes. Each of them contains no more than 106 digits.
Output
Print the symbol "<" if a < b and the symbol ">" if a > b. If the numbers are equal print the symbol "=".
Examples
Input
9
10
Output
<
Input
11
10
Output
>
Input
00012345
12345
Output
=
Input
0123
9
Output
>
Input
0123
111
Output
>
Submitted Solution:
```
s1 , s2 = input() , input()
index1 , index2 = 0 , 0
for i,j in enumerate(s1):
if j is not '0':
index1 = i
break
for i,j in enumerate(s2):
if j is not '0':
index2 = i
break
s1=s1[index1:]
s2=s2[index2:]
if len(s1) > len(s2): print('>')
elif len(s1) < len(s2): print('<')
else :
for i in zip(s1,s2):
if i[0] > i[1]:
print('>')
quit()
elif i[0] < i[1]:
print('<')
quit()
print('=')
``` | instruction | 0 | 74,587 | 5 | 149,174 |
No | output | 1 | 74,587 | 5 | 149,175 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.
Input
The only line contains odd integer n (1 ≤ n ≤ 49).
Output
Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.
Examples
Input
1
Output
1
Input
3
Output
2 1 4
3 5 7
6 9 8 | instruction | 0 | 74,629 | 5 | 149,258 |
Tags: constructive algorithms, math
Correct Solution:
```
#!/usr/bin/env python
#-*-coding:utf-8 -*-
n=int(input())
i=n>>1
a=1
b=2
for x in range(n):
l=abs(x-i)
r=n-l
for y in range(n):
if l<=y<r:
c=a
a+=2
else:
c=b
b+=2
print(c,end=' 'if n-1>y else'\n')
``` | output | 1 | 74,629 | 5 | 149,259 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.
Input
The only line contains odd integer n (1 ≤ n ≤ 49).
Output
Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.
Examples
Input
1
Output
1
Input
3
Output
2 1 4
3 5 7
6 9 8 | instruction | 0 | 74,631 | 5 | 149,262 |
Tags: constructive algorithms, math
Correct Solution:
```
#import sys
#sys.stdin = open('in', 'r')
n = int(input())
#a = [int(x) for x in input().split()]
#n,m = map(int, input().split())
r = [[0]*n for i in range(n)]
c = n // 2
cur = 1
for i in range(n):
r[c][i] = cur
cur += 2
for i in range(n):
if i != c:
r[i][c] = cur
cur += 2
if cur < n*n:
for i in range(1, c + 1):
for j in range(1, c + 1):
r[c-i][c+j] = cur
cur += 2
r[c-i][c-j] = cur
cur += 2
r[c+i][c+j] = cur
cur += 2
r[c+i][c-j] = cur
cur += 2
if cur >= n*n:
break
if cur >= n*n:
break
cur = 2
for i in range(n):
for j in range(n):
if r[i][j] == 0:
r[i][j] = cur
cur += 2
for i in range(n):
print(str.join(' ', map(str,r[i])))
``` | output | 1 | 74,631 | 5 | 149,263 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.
Input
The only line contains odd integer n (1 ≤ n ≤ 49).
Output
Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.
Examples
Input
1
Output
1
Input
3
Output
2 1 4
3 5 7
6 9 8
Submitted Solution:
```
#imports
import sys
sys.setrecursionlimit(30000)
from collections import Counter, defaultdict, deque
from math import ceil, floor, factorial, fsum, isinf, exp, log, log10, log2, isfinite, sqrt
from math import pi as PI, e as E
from fractions import Fraction
from itertools import starmap, tee, chain, filterfalse, combinations as combos
from itertools import permutations as perms, product as prod, combinations_with_replacement as rcombos
from functools import reduce, partial
import operator as ops #lt, le, eq, ne, ge, gt, xor notit, lshift, rshift, neg, add, mul, sub,
from operator import __not__ as notit
from operator import __abs__ as absit
from operator import __or__ as orit
#PI, E, PHI, INF
PHI, PHI2 = (1 + 5 ** 0.5) / 2, (5 ** 0.5 - 1) / 2
INF = float('inf')
#structures
class TreeNode:
def __init__(self, v):
self.val = v
self.left = None
self.right = None
#Bit Manipulation
#<<, >>, bin(), int(s, 2)
def setBit(x, offset):
return x | 1 << offset #RHS: mask
def clearBit(x, offset):
return x & ~(1 << offset) #RHS: mask
def getBit(x, offset):
return 1 if testBit(x, offset) > 0 else 0
def testBit(x, offset):
return x & 1 << offset #RHS: mask
def flipBitAt(x, offset):
return x ^ 1 << offset #RHS: mask
def flipBits(x, length=-1): #default: x.bit_length() - 1
length = x.bit_length()-1 if length == -1 else length
return x ^ (1 << length) - 1
def numBits(x):
return x.bit_length() #int.bit_length()
def countOnes(x):
return bin(x).count('1')
def countZeros(x, length=-1):
length = x.bit_length() if length == -1 else length
return length - countOnes(x)
#IO
def getList(tcast=str):
return [tcast(x) for x in input().strip().split(' ')]
def getItems(*tcast):
return map(lambda f, x: f(x), tcast, getList())
def getVal(tcast=str):
return tcast(input().strip())
def getMatrix(r, tcast=str):
return [getList(tcast) for row in range(r)]
#Math
def isOdd(n):
return n & 1 > 0
def isEven(n):
return not n & 1
def numDigits(n):
return len(str(n)) - (1 if n < 0 else 0)
def getRecip(f):
return Fraction(f.denominator, f.numerator)
def _gcd(a, b):
while b: #is not zero
a, b = b, a % b
return a
def gcd(*xs):
nums = xs[0] if type(xs[0]) == list else list(xs)
cur = nums[0]
for n in nums[1:]:
if cur == 1:
return cur
cur = _gcd(cur, n)
return cur
def _lcm(a, b):
return (a // gcd(a, b)) * b
def lcm(*xs):
nums = xs[0] if type(xs[0]) == list else list(xs)
cur = nums[0]
for n in nums[1:]:
cur = _lcm(cur, n)
return cur
def primesUpto(n):
isp = [True] * (n + 1)
isp[0], isp[1] = False, False
primes = []
for i, x in enumerate(isp): #for each number
if x: #found a prime
primes.append(i)
mults = i * i
while mults <= n:
isp[mults] = False
mults += i
return primes
def primeFactor(n): #without a sieve
factors = Counter()
while not n&1:
factors[2] += 1
n >>= 1
trynum = 3
while trynum <= ceil(sqrt(n)): #just in case
while n % trynum == 0:
factors[trynum] += 1
n //= trynum
trynum += 2
if n != 1:
factors[n] += 1
return factors
def isPrime(n): #num -> boolean
if n&1 and n >= 2:
trynum = 3
limit = ceil(sqrt(n))
while trynum < limit:
if n % trynum == 0:
return False
trynum += 2
else:
return True
else:
return False
def nthFib(n):
if n <= 2:
return 1
else:
a, b = 1, 1
while n > 2:
a, b = b, a + b
n -= 1
return b
#Iteration
def zipNWith(f, *x): #xs, ys, ... zs -> elementwise f -> os #return map(lambda *y: f(y), x) #list way: [f(y) for y in zip(*xs)]
return (f(y) for y in zip(*x))
def zipWith(f, xs, ys):
return (f(x, y) for x, y in zip(xs, ys))
def flatten(xs):
return reduce(ops.concat, xs)
def quantify(pred, it):
return sum(map(pred, it))
def dotproduct(xs, ys):
return sum(map(ops.mul, xs, ys))
def pairwise(it):
a, b = tee(it)
next(b, None)
return zip(a, b)
def bipartition(pred, it):
t, f = tee(it)
return filter(pred, t), filterfalse(pred, f)
def powerset(it):
s = list(it)
return chain.from_iterable(combos(s, r) for r in range(len(s) + 1))
#Input
#Body
#Output
def printmat(mat):
for row in mat:
print(*row)
def nextwrap(coords):
global n
r, c = coords
r, c = (r - 1) % n, (c + 1) % n
return r, c
def nextdown(coords):
global n
r, c = coords
r, c = (r + 1) % n, (c) % n
return r, c
n = getVal(int)
if n == 1:
print(1)
else:
mat = []
for i in range(n):
mat.append([0] * n)
start = [0, n//2]
mat[start[0]][start[1]] = 1
for i in range(n ** 2 - 1):
r, c = nextwrap(start)
if mat[r][c] != 0:
#print('oops',)
r, c = nextdown(start)
mat[r][c] = i + 2
start = [r, c]
printmat(mat)
#print(start)
``` | instruction | 0 | 74,635 | 5 | 149,270 |
Yes | output | 1 | 74,635 | 5 | 149,271 |
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