message stringlengths 2 44.5k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 42 109k | cluster float64 5 5 | __index_level_0__ int64 84 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Having learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together. He cannot do any other calculation.
Given are two integers A and B.
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1` instead.
Constraints
* 1 \leq A \leq 20
* 1 \leq B \leq 20
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B
Output
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1`.
Examples
Input
2 5
Output
10
Input
5 10
Output
-1
Input
9 9
Output
81
Submitted Solution:
```
a,b=map(int, input().split())
if (9-a)*(9-b)<0:
print(-1)
else:
print(a*b)
``` | instruction | 0 | 86,343 | 5 | 172,686 |
No | output | 1 | 86,343 | 5 | 172,687 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Having learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together. He cannot do any other calculation.
Given are two integers A and B.
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1` instead.
Constraints
* 1 \leq A \leq 20
* 1 \leq B \leq 20
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B
Output
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1`.
Examples
Input
2 5
Output
10
Input
5 10
Output
-1
Input
9 9
Output
81
Submitted Solution:
```
s = input().split()
if A > 10 or B > 10:
print(1)
else:
print(a * b)
``` | instruction | 0 | 86,344 | 5 | 172,688 |
No | output | 1 | 86,344 | 5 | 172,689 |
Provide a correct Python 3 solution for this coding contest problem.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd | instruction | 0 | 86,385 | 5 | 172,770 |
"Correct Solution:
```
print("EOvdedn"[eval(input().replace(" ","*"))%2::2])
``` | output | 1 | 86,385 | 5 | 172,771 |
Provide a correct Python 3 solution for this coding contest problem.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd | instruction | 0 | 86,386 | 5 | 172,772 |
"Correct Solution:
```
a, b = map(int, input().split()); print('Even') if a*b%2 == 0 else print('Odd')
``` | output | 1 | 86,386 | 5 | 172,773 |
Provide a correct Python 3 solution for this coding contest problem.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd | instruction | 0 | 86,387 | 5 | 172,774 |
"Correct Solution:
```
print('EOvdedn'[eval(input().replace(' ','*')+'%2')::2])
``` | output | 1 | 86,387 | 5 | 172,775 |
Provide a correct Python 3 solution for this coding contest problem.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd | instruction | 0 | 86,388 | 5 | 172,776 |
"Correct Solution:
```
print('EOvdedn'[sum(s in'04'for s in input())<1::2])
``` | output | 1 | 86,388 | 5 | 172,777 |
Provide a correct Python 3 solution for this coding contest problem.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd | instruction | 0 | 86,389 | 5 | 172,778 |
"Correct Solution:
```
a,b=[int(x) for x in input().split()]
print("Odd" if a*b%2==1 else "Even")
``` | output | 1 | 86,389 | 5 | 172,779 |
Provide a correct Python 3 solution for this coding contest problem.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd | instruction | 0 | 86,390 | 5 | 172,780 |
"Correct Solution:
```
a, b = map(int,input().split())
print('Even' if (a*b%2 == 0) else 'Odd')
``` | output | 1 | 86,390 | 5 | 172,781 |
Provide a correct Python 3 solution for this coding contest problem.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd | instruction | 0 | 86,391 | 5 | 172,782 |
"Correct Solution:
```
a, b = map(int, input().split())
print('Odd' if a*b%2 != 0 else 'Even')
``` | output | 1 | 86,391 | 5 | 172,783 |
Provide a correct Python 3 solution for this coding contest problem.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd | instruction | 0 | 86,392 | 5 | 172,784 |
"Correct Solution:
```
a,b = map(int, input().split())
print('EOvdedn'[a*b%2==1::2])
``` | output | 1 | 86,392 | 5 | 172,785 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd
Submitted Solution:
```
a, b = map(int, input().split())
if a * b % 2: print('Odd')
else: print('Even')
``` | instruction | 0 | 86,393 | 5 | 172,786 |
Yes | output | 1 | 86,393 | 5 | 172,787 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd
Submitted Solution:
```
a, b = map(int, input().split())
print(a*b % 2 and 'Odd' or 'Even')
``` | instruction | 0 | 86,394 | 5 | 172,788 |
Yes | output | 1 | 86,394 | 5 | 172,789 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd
Submitted Solution:
```
a, b = map(int, input().split())
print(["Even", "Odd"][a * b % 2])
``` | instruction | 0 | 86,395 | 5 | 172,790 |
Yes | output | 1 | 86,395 | 5 | 172,791 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd
Submitted Solution:
```
a, b = map(int, (input().split()))
print("Even" if a * b % 2 == 0 else "Odd")
``` | instruction | 0 | 86,396 | 5 | 172,792 |
Yes | output | 1 | 86,396 | 5 | 172,793 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd
Submitted Solution:
```
a = int(input())
b = int(input())
if a*b % 2 == 0:
print("Even")
else:
print("Odd")
``` | instruction | 0 | 86,397 | 5 | 172,794 |
No | output | 1 | 86,397 | 5 | 172,795 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd
Submitted Solution:
```
a, b = map(int, input().split())
if (a*b) % 2:
print(‘Odd’)
else:
print(‘Even’)
``` | instruction | 0 | 86,398 | 5 | 172,796 |
No | output | 1 | 86,398 | 5 | 172,797 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd
Submitted Solution:
```
a, b = tuple(int(num) for input().split())
ab = a * b
if ab % 2:
print('Odd')
else:
print('Even')
``` | instruction | 0 | 86,399 | 5 | 172,798 |
No | output | 1 | 86,399 | 5 | 172,799 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd
Submitted Solution:
```
#入力値の取得
_in =input().split()
#文字の結合
cont_str = _in[0] + _in[1]
#数字に変換
cont_num = int(cont_str)
#平方数の判定
#総当たり頭悪そう 1<= ab <= 100 なので 4*4~ 100*100
sqrt_flag = False
for i in range(4, 102):
sqrt = i * i
print(sqrt)
if cont_num == sqrt:
sqrt_flag = True
break
if sqrt_flag:
print('Yes')
else:
print('No')
``` | instruction | 0 | 86,400 | 5 | 172,800 |
No | output | 1 | 86,400 | 5 | 172,801 |
Provide a correct Python 3 solution for this coding contest problem.
problem
Given $ N $ different natural numbers $ a_i $. I decided to make a pair by choosing a different natural number from the given natural numbers. Output one pair that can be created with a value difference that is a multiple of $ N -1 $.
It should be noted that such a pair always exists.
Example
Input
5
1 2 4 7 10
Output
2 10 | instruction | 0 | 86,538 | 5 | 173,076 |
"Correct Solution:
```
def solve():
n = int(input())
li = [int(_) for _ in input().split()]
for i in range(n):
for j in range(i+1, n):
if abs(li[i]-li[j]) % (n-1) == 0:
print(str(li[i]) + " " + str(li[j]))
return
solve()
``` | output | 1 | 86,538 | 5 | 173,077 |
Provide a correct Python 3 solution for this coding contest problem.
problem
Given $ N $ different natural numbers $ a_i $. I decided to make a pair by choosing a different natural number from the given natural numbers. Output one pair that can be created with a value difference that is a multiple of $ N -1 $.
It should be noted that such a pair always exists.
Example
Input
5
1 2 4 7 10
Output
2 10 | instruction | 0 | 86,539 | 5 | 173,078 |
"Correct Solution:
```
N = int(input())
a = [int(x) for x in input().split()]
x, y = -1, -1
for i in range(N) :
for j in range(N) :
if i != j and abs(a[i] - a[j]) % (N - 1) == 0 :
x, y = i, j
print(a[x], a[y])
``` | output | 1 | 86,539 | 5 | 173,079 |
Provide a correct Python 3 solution for this coding contest problem.
problem
Given $ N $ different natural numbers $ a_i $. I decided to make a pair by choosing a different natural number from the given natural numbers. Output one pair that can be created with a value difference that is a multiple of $ N -1 $.
It should be noted that such a pair always exists.
Example
Input
5
1 2 4 7 10
Output
2 10 | instruction | 0 | 86,540 | 5 | 173,080 |
"Correct Solution:
```
import itertools
n = int(input())
num = list(map(int, input().split()))
for comb in itertools.combinations(num, 2):
diff = abs(comb[0] - comb[1])
if diff % (n-1) == 0:
print(comb[0], comb[1])
break
``` | output | 1 | 86,540 | 5 | 173,081 |
Provide a correct Python 3 solution for this coding contest problem.
problem
Given $ N $ different natural numbers $ a_i $. I decided to make a pair by choosing a different natural number from the given natural numbers. Output one pair that can be created with a value difference that is a multiple of $ N -1 $.
It should be noted that such a pair always exists.
Example
Input
5
1 2 4 7 10
Output
2 10 | instruction | 0 | 86,541 | 5 | 173,082 |
"Correct Solution:
```
n=int(input())
num=list(map(int,input().split()))
num.sort()
flag=0
for i in range(n):
if flag==1:break
for j in range(1,n-i):
if flag==1:break
elif (num[i+j]-num[i])%(n-1)==0:
print(num[i],num[i+j])
flag=1
``` | output | 1 | 86,541 | 5 | 173,083 |
Provide a correct Python 3 solution for this coding contest problem.
problem
Given $ N $ different natural numbers $ a_i $. I decided to make a pair by choosing a different natural number from the given natural numbers. Output one pair that can be created with a value difference that is a multiple of $ N -1 $.
It should be noted that such a pair always exists.
Example
Input
5
1 2 4 7 10
Output
2 10 | instruction | 0 | 86,542 | 5 | 173,084 |
"Correct Solution:
```
import itertools
N = int(input())
num = list(map(int, input().split()))
a = itertools.combinations(num, 2)
for i, j in a:
if abs(i - j) % (N-1) == 0:
print(i , j)
break
``` | output | 1 | 86,542 | 5 | 173,085 |
Provide a correct Python 3 solution for this coding contest problem.
problem
Given $ N $ different natural numbers $ a_i $. I decided to make a pair by choosing a different natural number from the given natural numbers. Output one pair that can be created with a value difference that is a multiple of $ N -1 $.
It should be noted that such a pair always exists.
Example
Input
5
1 2 4 7 10
Output
2 10 | instruction | 0 | 86,543 | 5 | 173,086 |
"Correct Solution:
```
n = int(input())
a = list(map(int, input().split()))
a.sort()
for i in a:
for j in a:
if abs(i-j)%(n-1) == 0 and i != j:
print(i, j)
quit()
``` | output | 1 | 86,543 | 5 | 173,087 |
Provide a correct Python 3 solution for this coding contest problem.
problem
Given $ N $ different natural numbers $ a_i $. I decided to make a pair by choosing a different natural number from the given natural numbers. Output one pair that can be created with a value difference that is a multiple of $ N -1 $.
It should be noted that such a pair always exists.
Example
Input
5
1 2 4 7 10
Output
2 10 | instruction | 0 | 86,544 | 5 | 173,088 |
"Correct Solution:
```
def main():
n = int(input())
a = list(map(int,input().split()))
for i in a:
for j in a:
if(i != j and abs(i-j) % (n-1) == 0):
print(i,j)
return 0
main()
``` | output | 1 | 86,544 | 5 | 173,089 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Greg has an array a = a1, a2, ..., an and m operations. Each operation looks as: li, ri, di, (1 ≤ li ≤ ri ≤ n). To apply operation i to the array means to increase all array elements with numbers li, li + 1, ..., ri by value di.
Greg wrote down k queries on a piece of paper. Each query has the following form: xi, yi, (1 ≤ xi ≤ yi ≤ m). That means that one should apply operations with numbers xi, xi + 1, ..., yi to the array.
Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.
Input
The first line contains integers n, m, k (1 ≤ n, m, k ≤ 105). The second line contains n integers: a1, a2, ..., an (0 ≤ ai ≤ 105) — the initial array.
Next m lines contain operations, the operation number i is written as three integers: li, ri, di, (1 ≤ li ≤ ri ≤ n), (0 ≤ di ≤ 105).
Next k lines contain the queries, the query number i is written as two integers: xi, yi, (1 ≤ xi ≤ yi ≤ m).
The numbers in the lines are separated by single spaces.
Output
On a single line print n integers a1, a2, ..., an — the array after executing all the queries. Separate the printed numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.
Examples
Input
3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3
Output
9 18 17
Input
1 1 1
1
1 1 1
1 1
Output
2
Input
4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3
Output
5 18 31 20
Submitted Solution:
```
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
##################################
# University of Wisconsin-Madison
# Author: Yaqi Zhang
##################################
# standard library
import sys
def main():
n, m, k = map(int, input().split())
nums = list(map(int, input().split()))
pre_reps = [0] * (m + 1)
ops = []
for _ in range(m):
l, r, d = map(int, input().split())
ops.append((l - 1, r - 1, d))
for _ in range(k):
x, y = map(int, input().split())
x -= 1
y -= 1
pre_reps[x] += 1
pre_reps[y + 1] -= 1
cur = 0
add = [0] * (n + 1)
for i, (l, r, d) in enumerate(ops):
cur += pre_reps[i]
add[l] += d * cur
add[r + 1] -= d * cur
cur = 0
ans = []
for i, num in enumerate(nums):
cur += add[i]
ans.append(num + cur)
print(' '.join(map(str, ans)))
if __name__ == "__main__":
main()
``` | instruction | 0 | 86,960 | 5 | 173,920 |
Yes | output | 1 | 86,960 | 5 | 173,921 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Greg has an array a = a1, a2, ..., an and m operations. Each operation looks as: li, ri, di, (1 ≤ li ≤ ri ≤ n). To apply operation i to the array means to increase all array elements with numbers li, li + 1, ..., ri by value di.
Greg wrote down k queries on a piece of paper. Each query has the following form: xi, yi, (1 ≤ xi ≤ yi ≤ m). That means that one should apply operations with numbers xi, xi + 1, ..., yi to the array.
Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.
Input
The first line contains integers n, m, k (1 ≤ n, m, k ≤ 105). The second line contains n integers: a1, a2, ..., an (0 ≤ ai ≤ 105) — the initial array.
Next m lines contain operations, the operation number i is written as three integers: li, ri, di, (1 ≤ li ≤ ri ≤ n), (0 ≤ di ≤ 105).
Next k lines contain the queries, the query number i is written as two integers: xi, yi, (1 ≤ xi ≤ yi ≤ m).
The numbers in the lines are separated by single spaces.
Output
On a single line print n integers a1, a2, ..., an — the array after executing all the queries. Separate the printed numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.
Examples
Input
3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3
Output
9 18 17
Input
1 1 1
1
1 1 1
1 1
Output
2
Input
4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3
Output
5 18 31 20
Submitted Solution:
```
import sys
n,m,k=map(int,sys.stdin.readline().split())
a=list(map(int,sys.stdin.readline().split()))
s=sum(a)
m1=[]
for i in range(m):
g=list(map(int,sys.stdin.readline().split()))
m1.append(g)
k1=[]
for i in range(k):
g=list(map(int,sys.stdin.readline().split()))
k1.append(g)
cnt=[0]*(m+1)
for i in range(k):
cnt[k1[i][0]-1]+=1
cnt[k1[i][1]]+=-1
s=0
for i in range(m+1):
s+=cnt[i]
cnt[i]=s
cnt1=[0]*(n+1)
for i in range(m):
cnt1[m1[i][0]-1]+=cnt[i]*m1[i][2]
cnt1[m1[i][1]]+=-cnt[i]*m1[i][2]
s=0
for i in range(n):
s+=cnt1[i]
a[i]+=s
print(a[i],end=" ")
``` | instruction | 0 | 86,961 | 5 | 173,922 |
Yes | output | 1 | 86,961 | 5 | 173,923 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Greg has an array a = a1, a2, ..., an and m operations. Each operation looks as: li, ri, di, (1 ≤ li ≤ ri ≤ n). To apply operation i to the array means to increase all array elements with numbers li, li + 1, ..., ri by value di.
Greg wrote down k queries on a piece of paper. Each query has the following form: xi, yi, (1 ≤ xi ≤ yi ≤ m). That means that one should apply operations with numbers xi, xi + 1, ..., yi to the array.
Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.
Input
The first line contains integers n, m, k (1 ≤ n, m, k ≤ 105). The second line contains n integers: a1, a2, ..., an (0 ≤ ai ≤ 105) — the initial array.
Next m lines contain operations, the operation number i is written as three integers: li, ri, di, (1 ≤ li ≤ ri ≤ n), (0 ≤ di ≤ 105).
Next k lines contain the queries, the query number i is written as two integers: xi, yi, (1 ≤ xi ≤ yi ≤ m).
The numbers in the lines are separated by single spaces.
Output
On a single line print n integers a1, a2, ..., an — the array after executing all the queries. Separate the printed numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.
Examples
Input
3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3
Output
9 18 17
Input
1 1 1
1
1 1 1
1 1
Output
2
Input
4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3
Output
5 18 31 20
Submitted Solution:
```
first_line = [int(num) for num in input().split()]
n = first_line[0]
m = first_line[1]
k = first_line[2]
initial_array = [int(num) for num in input().split()]
operations = []
for _ in range(m):
curr_line = [int(num) for num in input().split()]
operations.append(curr_line)
queries = []
for _ in range(k):
curr_line = [int(num) for num in input().split()]
queries.append(curr_line)
counter = [0] * (m+1)
for query in queries:
x = query[0]
y = query[1]
counter[x-1] += 1
counter[y] -= 1
res = 0
other = [0] * (n+1)
for index in range(m):
operation = operations[index]
l = operation[0]
r = operation[1]
d = operation[2]
res += counter[index]
other[l-1] += res*d
other[r] -= res*d
res = 0
for index in range(n):
res += other[index]
initial_array[index] += res
print(" ".join(str(value) for value in initial_array))
``` | instruction | 0 | 86,962 | 5 | 173,924 |
Yes | output | 1 | 86,962 | 5 | 173,925 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Greg has an array a = a1, a2, ..., an and m operations. Each operation looks as: li, ri, di, (1 ≤ li ≤ ri ≤ n). To apply operation i to the array means to increase all array elements with numbers li, li + 1, ..., ri by value di.
Greg wrote down k queries on a piece of paper. Each query has the following form: xi, yi, (1 ≤ xi ≤ yi ≤ m). That means that one should apply operations with numbers xi, xi + 1, ..., yi to the array.
Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.
Input
The first line contains integers n, m, k (1 ≤ n, m, k ≤ 105). The second line contains n integers: a1, a2, ..., an (0 ≤ ai ≤ 105) — the initial array.
Next m lines contain operations, the operation number i is written as three integers: li, ri, di, (1 ≤ li ≤ ri ≤ n), (0 ≤ di ≤ 105).
Next k lines contain the queries, the query number i is written as two integers: xi, yi, (1 ≤ xi ≤ yi ≤ m).
The numbers in the lines are separated by single spaces.
Output
On a single line print n integers a1, a2, ..., an — the array after executing all the queries. Separate the printed numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.
Examples
Input
3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3
Output
9 18 17
Input
1 1 1
1
1 1 1
1 1
Output
2
Input
4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3
Output
5 18 31 20
Submitted Solution:
```
import sys
input = sys.stdin.readline
n,m,k=map(int,input().split())
arr=list(map(int,input().split()))
querry_arr=[list(map(int, input().split())) for _ in range(m)]
tmp_ans=[0]*n
tmp=[0]*(m+1)
for _ in range(k):
l,r=map(lambda k:int(k)-1,input().split())
tmp[l]+=1
tmp[r+1]-=1
for x in range(1,m):
tmp[x]+=tmp[x-1]
arr_tmp=[0]*(n+1)
tmp.pop()
for x in range(m):
u,v,w=querry_arr[x]
u-=1
v-=1
arr_tmp[u]+=w*tmp[x]
arr_tmp[v+1]-=w*tmp[x]
arr[0]+=arr_tmp[0]
for x in range(1,n):
arr_tmp[x]+=arr_tmp[x-1]
arr[x]+=arr_tmp[x]
print(' '.join(map(str, arr)))
``` | instruction | 0 | 86,963 | 5 | 173,926 |
Yes | output | 1 | 86,963 | 5 | 173,927 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Greg has an array a = a1, a2, ..., an and m operations. Each operation looks as: li, ri, di, (1 ≤ li ≤ ri ≤ n). To apply operation i to the array means to increase all array elements with numbers li, li + 1, ..., ri by value di.
Greg wrote down k queries on a piece of paper. Each query has the following form: xi, yi, (1 ≤ xi ≤ yi ≤ m). That means that one should apply operations with numbers xi, xi + 1, ..., yi to the array.
Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.
Input
The first line contains integers n, m, k (1 ≤ n, m, k ≤ 105). The second line contains n integers: a1, a2, ..., an (0 ≤ ai ≤ 105) — the initial array.
Next m lines contain operations, the operation number i is written as three integers: li, ri, di, (1 ≤ li ≤ ri ≤ n), (0 ≤ di ≤ 105).
Next k lines contain the queries, the query number i is written as two integers: xi, yi, (1 ≤ xi ≤ yi ≤ m).
The numbers in the lines are separated by single spaces.
Output
On a single line print n integers a1, a2, ..., an — the array after executing all the queries. Separate the printed numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.
Examples
Input
3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3
Output
9 18 17
Input
1 1 1
1
1 1 1
1 1
Output
2
Input
4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3
Output
5 18 31 20
Submitted Solution:
```
if __name__ == '__main__':
n, m, k = map(int, input().split())
nums = list(map(int, input().split()))
operations = [tuple(map(int, input().split())) for _ in range(m)]
op_counter = [0] * (m+1)
# queries
for _ in range(k):
x, y = map(int, input().split())
op_counter[x-1] += 1
op_counter[y] -= 1
acc = 0
offset = [0]*(n+1)
for i in range(m):
l, r, d = operations[i]
acc += op_counter[i]
offset[l-1] += acc * d
offset[r] -= acc * d
acc = 0
for i in range(n):
acc += offset[i]
nums[i] += acc
print(nums)
``` | instruction | 0 | 86,964 | 5 | 173,928 |
No | output | 1 | 86,964 | 5 | 173,929 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Greg has an array a = a1, a2, ..., an and m operations. Each operation looks as: li, ri, di, (1 ≤ li ≤ ri ≤ n). To apply operation i to the array means to increase all array elements with numbers li, li + 1, ..., ri by value di.
Greg wrote down k queries on a piece of paper. Each query has the following form: xi, yi, (1 ≤ xi ≤ yi ≤ m). That means that one should apply operations with numbers xi, xi + 1, ..., yi to the array.
Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.
Input
The first line contains integers n, m, k (1 ≤ n, m, k ≤ 105). The second line contains n integers: a1, a2, ..., an (0 ≤ ai ≤ 105) — the initial array.
Next m lines contain operations, the operation number i is written as three integers: li, ri, di, (1 ≤ li ≤ ri ≤ n), (0 ≤ di ≤ 105).
Next k lines contain the queries, the query number i is written as two integers: xi, yi, (1 ≤ xi ≤ yi ≤ m).
The numbers in the lines are separated by single spaces.
Output
On a single line print n integers a1, a2, ..., an — the array after executing all the queries. Separate the printed numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.
Examples
Input
3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3
Output
9 18 17
Input
1 1 1
1
1 1 1
1 1
Output
2
Input
4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3
Output
5 18 31 20
Submitted Solution:
```
# Legends Always Come Up with Solution
# Author: Manvir Singh
import os
import sys
from io import BytesIO, IOBase
def main():
n,m,k=map(int,input().split())
a=list(map(int,input().split()))
ma=max(a)
q=[tuple(map(int,input().split())) for _ in range(m)]
qans=[0]*(m+1)
for i in range(k):
x,y=map(int,input().split())
x-=1
qans[x]+=1
qans[y]-=1
for i in range(1,m+1):
qans[i]+=qans[i-1]
ans=[0]*(ma+2)
for j,i in enumerate(q):
x=qans[j]*i[2]
ans[i[0]]+=x
ans[i[1]+1]-=x
for i in range(1,ma+1):
ans[i]+=ans[i-1]
for i in a:
print(i+ans[i],end=" ")
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
if __name__ == "__main__":
main()
``` | instruction | 0 | 86,965 | 5 | 173,930 |
No | output | 1 | 86,965 | 5 | 173,931 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Greg has an array a = a1, a2, ..., an and m operations. Each operation looks as: li, ri, di, (1 ≤ li ≤ ri ≤ n). To apply operation i to the array means to increase all array elements with numbers li, li + 1, ..., ri by value di.
Greg wrote down k queries on a piece of paper. Each query has the following form: xi, yi, (1 ≤ xi ≤ yi ≤ m). That means that one should apply operations with numbers xi, xi + 1, ..., yi to the array.
Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.
Input
The first line contains integers n, m, k (1 ≤ n, m, k ≤ 105). The second line contains n integers: a1, a2, ..., an (0 ≤ ai ≤ 105) — the initial array.
Next m lines contain operations, the operation number i is written as three integers: li, ri, di, (1 ≤ li ≤ ri ≤ n), (0 ≤ di ≤ 105).
Next k lines contain the queries, the query number i is written as two integers: xi, yi, (1 ≤ xi ≤ yi ≤ m).
The numbers in the lines are separated by single spaces.
Output
On a single line print n integers a1, a2, ..., an — the array after executing all the queries. Separate the printed numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.
Examples
Input
3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3
Output
9 18 17
Input
1 1 1
1
1 1 1
1 1
Output
2
Input
4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3
Output
5 18 31 20
Submitted Solution:
```
def fastio():
import sys
from io import StringIO
from atexit import register
global input
sys.stdin = StringIO(sys.stdin.read())
input = lambda : sys.stdin.readline().rstrip('\r\n')
sys.stdout = StringIO()
register(lambda : sys.__stdout__.write(sys.stdout.getvalue()))
fastio()
MOD = 10**9 + 7
I = lambda:list(map(int,input().split()))
n, m, k = I()
l = I()
a = [0]*(100005)
q = []
b = [0]*(100005)
for i in range(m):
o = I()
o[0] -= 1
q.append(o)
for i in range(k):
x, y = I()
b[x-1] += 1
b[y] -= 1
for i in range(1, n):
b[i] += b[i-1]
for i in range(m):
x, y, z = q[i]
a[x] += b[i]*z
a[y] -= b[i]*z
for i in range(n):
a[i] += a[i-1]
print(a[i] + l[i], end = ' ')
``` | instruction | 0 | 86,966 | 5 | 173,932 |
No | output | 1 | 86,966 | 5 | 173,933 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Greg has an array a = a1, a2, ..., an and m operations. Each operation looks as: li, ri, di, (1 ≤ li ≤ ri ≤ n). To apply operation i to the array means to increase all array elements with numbers li, li + 1, ..., ri by value di.
Greg wrote down k queries on a piece of paper. Each query has the following form: xi, yi, (1 ≤ xi ≤ yi ≤ m). That means that one should apply operations with numbers xi, xi + 1, ..., yi to the array.
Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.
Input
The first line contains integers n, m, k (1 ≤ n, m, k ≤ 105). The second line contains n integers: a1, a2, ..., an (0 ≤ ai ≤ 105) — the initial array.
Next m lines contain operations, the operation number i is written as three integers: li, ri, di, (1 ≤ li ≤ ri ≤ n), (0 ≤ di ≤ 105).
Next k lines contain the queries, the query number i is written as two integers: xi, yi, (1 ≤ xi ≤ yi ≤ m).
The numbers in the lines are separated by single spaces.
Output
On a single line print n integers a1, a2, ..., an — the array after executing all the queries. Separate the printed numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.
Examples
Input
3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3
Output
9 18 17
Input
1 1 1
1
1 1 1
1 1
Output
2
Input
4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3
Output
5 18 31 20
Submitted Solution:
```
import sys, os, io
def rs(): return sys.stdin.readline().rstrip()
def ri(): return int(sys.stdin.readline())
def ria(): return list(map(int, sys.stdin.readline().split()))
def ws(s): sys.stdout.write(s + '\n')
def wi(n): sys.stdout.write(str(n) + '\n')
def wia(a): sys.stdout.write(' '.join([str(x) for x in a]) + '\n')
import math,datetime,functools,itertools,operator,bisect,fractions,statistics
from collections import deque,defaultdict,OrderedDict,Counter
from fractions import Fraction
from decimal import Decimal
from sys import stdout
from heapq import heappush, heappop, heapify ,_heapify_max,_heappop_max,nsmallest,nlargest
sys.setrecursionlimit(111111)
INF=99999999999999999999999999999999
def main():
mod=1000000007
# InverseofNumber(mod)
# InverseofFactorial(mod)
# factorial(mod)
starttime=datetime.datetime.now()
if(os.path.exists('input.txt')):
sys.stdin = open("input.txt","r")
sys.stdout = open("output.txt","w")
###CODE
tc = 1
for _ in range(tc):
n,m,k=ria()
arr=ria()
operations=[]
queries=[]
ansrange=[0]*(100005)
oprange=[0]*(m+5)
for i in range(m):
operations.append(ria())
for i in range(k):
a,b=ria()
oprange[a-1]+=1
oprange[b]-=1
for i in range(1,len(oprange)):
oprange[i]+=oprange[i-1]
# print(oprange)
for i in range(len(oprange)):
if oprange[i]:
l,r,d=operations[i]
ansrange[l]+=d*oprange[i]
ansrange[r+1]-=d*oprange[i]
for i in range(1,len(oprange)):
ansrange[i]+=ansrange[i-1]
ans=[]
for i in arr:
ans.append(i+ansrange[i])
wia(ans)
#<--Solving Area Ends
endtime=datetime.datetime.now()
time=(endtime-starttime).total_seconds()*1000
if(os.path.exists('input.txt')):
print("Time:",time,"ms")
class FastReader(io.IOBase):
newlines = 0
def __init__(self, fd, chunk_size=1024 * 8):
self._fd = fd
self._chunk_size = chunk_size
self.buffer = io.BytesIO()
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, self._chunk_size))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self, size=-1):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, self._chunk_size if size == -1 else size))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
class FastWriter(io.IOBase):
def __init__(self, fd):
self._fd = fd
self.buffer = io.BytesIO()
self.write = self.buffer.write
def flush(self):
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class FastStdin(io.IOBase):
def __init__(self, fd=0):
self.buffer = FastReader(fd)
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
class FastStdout(io.IOBase):
def __init__(self, fd=1):
self.buffer = FastWriter(fd)
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.flush = self.buffer.flush
if __name__ == '__main__':
sys.stdin = FastStdin()
sys.stdout = FastStdout()
main()
``` | instruction | 0 | 86,967 | 5 | 173,934 |
No | output | 1 | 86,967 | 5 | 173,935 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try?
Input
The input contains two integers a and b (0 ≤ a, b ≤ 103), separated by a single space.
Output
Output the sum of the given integers.
Examples
Input
5 14
Output
19
Input
381 492
Output
873 | instruction | 0 | 87,000 | 5 | 174,000 |
Tags: *special, brute force, constructive algorithms, dsu, implementation
Correct Solution:
```
print(sum( [int (x) for x in input().strip().split()]))
``` | output | 1 | 87,000 | 5 | 174,001 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try?
Input
The input contains two integers a and b (0 ≤ a, b ≤ 103), separated by a single space.
Output
Output the sum of the given integers.
Examples
Input
5 14
Output
19
Input
381 492
Output
873 | instruction | 0 | 87,001 | 5 | 174,002 |
Tags: *special, brute force, constructive algorithms, dsu, implementation
Correct Solution:
```
a,b=map(int,input().split())
print(a+b )
``` | output | 1 | 87,001 | 5 | 174,003 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try?
Input
The input contains two integers a and b (0 ≤ a, b ≤ 103), separated by a single space.
Output
Output the sum of the given integers.
Examples
Input
5 14
Output
19
Input
381 492
Output
873 | instruction | 0 | 87,002 | 5 | 174,004 |
Tags: *special, brute force, constructive algorithms, dsu, implementation
Correct Solution:
```
a, b = map(int, input().split(" "))
print(a + b)
#
#
#
#
#
#
#
#
``` | output | 1 | 87,002 | 5 | 174,005 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try?
Input
The input contains two integers a and b (0 ≤ a, b ≤ 103), separated by a single space.
Output
Output the sum of the given integers.
Examples
Input
5 14
Output
19
Input
381 492
Output
873 | instruction | 0 | 87,003 | 5 | 174,006 |
Tags: *special, brute force, constructive algorithms, dsu, implementation
Correct Solution:
```
#This should work, stupid contest!!!
a,b = map(int, input().split())
print(a + b)
``` | output | 1 | 87,003 | 5 | 174,007 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try?
Input
The input contains two integers a and b (0 ≤ a, b ≤ 103), separated by a single space.
Output
Output the sum of the given integers.
Examples
Input
5 14
Output
19
Input
381 492
Output
873 | instruction | 0 | 87,004 | 5 | 174,008 |
Tags: *special, brute force, constructive algorithms, dsu, implementation
Correct Solution:
```
from sys import stdin,stdout
def main():
inp = [int (i) for i in input().split(" ")]
print(inp[0]+inp[1])
if __name__ == "__main__":
main()
``` | output | 1 | 87,004 | 5 | 174,009 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try?
Input
The input contains two integers a and b (0 ≤ a, b ≤ 103), separated by a single space.
Output
Output the sum of the given integers.
Examples
Input
5 14
Output
19
Input
381 492
Output
873 | instruction | 0 | 87,005 | 5 | 174,010 |
Tags: *special, brute force, constructive algorithms, dsu, implementation
Correct Solution:
```
n,m = map(int,input().split())
r=0
print(int(n)+int(m))
``` | output | 1 | 87,005 | 5 | 174,011 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try?
Input
The input contains two integers a and b (0 ≤ a, b ≤ 103), separated by a single space.
Output
Output the sum of the given integers.
Examples
Input
5 14
Output
19
Input
381 492
Output
873 | instruction | 0 | 87,006 | 5 | 174,012 |
Tags: *special, brute force, constructive algorithms, dsu, implementation
Correct Solution:
```
x,y = map(int,input().split())
print(x+y)
``` | output | 1 | 87,006 | 5 | 174,013 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try?
Input
The input contains two integers a and b (0 ≤ a, b ≤ 103), separated by a single space.
Output
Output the sum of the given integers.
Examples
Input
5 14
Output
19
Input
381 492
Output
873 | instruction | 0 | 87,007 | 5 | 174,014 |
Tags: *special, brute force, constructive algorithms, dsu, implementation
Correct Solution:
```
a, b = map(int, input().split())
print((a&b)+(a|b)) #6
``` | output | 1 | 87,007 | 5 | 174,015 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try?
Input
The input contains two integers a and b (0 ≤ a, b ≤ 103), separated by a single space.
Output
Output the sum of the given integers.
Examples
Input
5 14
Output
19
Input
381 492
Output
873
Submitted Solution:
```
a, b = [int(i) for i in input().split()]
print(a+b)
``` | instruction | 0 | 87,008 | 5 | 174,016 |
Yes | output | 1 | 87,008 | 5 | 174,017 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try?
Input
The input contains two integers a and b (0 ≤ a, b ≤ 103), separated by a single space.
Output
Output the sum of the given integers.
Examples
Input
5 14
Output
19
Input
381 492
Output
873
Submitted Solution:
```
a,b=map(int,input().split(" "))
b+=a
print(b)
``` | instruction | 0 | 87,009 | 5 | 174,018 |
Yes | output | 1 | 87,009 | 5 | 174,019 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try?
Input
The input contains two integers a and b (0 ≤ a, b ≤ 103), separated by a single space.
Output
Output the sum of the given integers.
Examples
Input
5 14
Output
19
Input
381 492
Output
873
Submitted Solution:
```
print(sum(map(int,input().split(' '))))
``` | instruction | 0 | 87,010 | 5 | 174,020 |
Yes | output | 1 | 87,010 | 5 | 174,021 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try?
Input
The input contains two integers a and b (0 ≤ a, b ≤ 103), separated by a single space.
Output
Output the sum of the given integers.
Examples
Input
5 14
Output
19
Input
381 492
Output
873
Submitted Solution:
```
a, b = map(int, input().split())
print(a+b)
#6
``` | instruction | 0 | 87,011 | 5 | 174,022 |
Yes | output | 1 | 87,011 | 5 | 174,023 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try?
Input
The input contains two integers a and b (0 ≤ a, b ≤ 103), separated by a single space.
Output
Output the sum of the given integers.
Examples
Input
5 14
Output
19
Input
381 492
Output
873
Submitted Solution:
```
#ddd]1111
a, b = map(int, input().split())
print(a + b)
``` | instruction | 0 | 87,012 | 5 | 174,024 |
No | output | 1 | 87,012 | 5 | 174,025 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try?
Input
The input contains two integers a and b (0 ≤ a, b ≤ 103), separated by a single space.
Output
Output the sum of the given integers.
Examples
Input
5 14
Output
19
Input
381 492
Output
873
Submitted Solution:
```
a,b=map(int,input().split())
print(a+b&1023)
``` | instruction | 0 | 87,013 | 5 | 174,026 |
No | output | 1 | 87,013 | 5 | 174,027 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try?
Input
The input contains two integers a and b (0 ≤ a, b ≤ 103), separated by a single space.
Output
Output the sum of the given integers.
Examples
Input
5 14
Output
19
Input
381 492
Output
873
Submitted Solution:
```
a,b = map(int,input().split())
print(0+a+b)
``` | instruction | 0 | 87,014 | 5 | 174,028 |
No | output | 1 | 87,014 | 5 | 174,029 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try?
Input
The input contains two integers a and b (0 ≤ a, b ≤ 103), separated by a single space.
Output
Output the sum of the given integers.
Examples
Input
5 14
Output
19
Input
381 492
Output
873
Submitted Solution:
```
a,b=int(input()).split()
sum=a+b
print(sum)
``` | instruction | 0 | 87,015 | 5 | 174,030 |
No | output | 1 | 87,015 | 5 | 174,031 |
Provide a correct Python 3 solution for this coding contest problem.
Given are integer sequences A and B of length 3N. Each of these two sequences contains three copies of each of 1, 2, \dots, N. In other words, A and B are both arrangements of (1, 1, 1, 2, 2, 2, \dots, N, N, N).
Tak can perform the following operation to the sequence A arbitrarily many times:
* Pick a value from 1, 2, \dots, N and call it x. A contains exactly three copies of x. Remove the middle element of these three. After that, append x to the beginning or the end of A.
Check if he can turn A into B. If he can, print the minimum required number of operations to achieve that.
Constraints
* 1 \leq N \leq 33
* A and B are both arrangements of (1, 1, 1, 2, 2, 2, \dots, N, N, N).
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_{3N}
B_1 B_2 ... B_{3N}
Output
If Tak can turn A into B, print the minimum required number of operations to achieve that. Otherwise, print -1.
Examples
Input
3
2 3 1 1 3 2 2 1 3
1 2 2 3 1 2 3 1 3
Output
4
Input
3
1 1 1 2 2 2 3 3 3
1 1 1 2 2 2 3 3 3
Output
0
Input
3
2 3 3 1 1 1 2 2 3
3 2 2 1 1 1 3 3 2
Output
-1
Input
8
3 6 7 5 4 8 4 1 1 3 8 7 3 8 2 4 7 5 2 2 6 5 6 1
7 5 8 1 3 6 7 5 4 8 1 3 3 8 2 4 2 6 5 6 1 4 7 2
Output
7 | instruction | 0 | 87,303 | 5 | 174,606 |
"Correct Solution:
```
import sys
readline = sys.stdin.buffer.readline
class E:
def __init__(self,to,nx):
self.to=to
self.nx=nx
class Graph:
def __init__(self,n):
self.n=n
self.head=[None]*n
def ae(self,a,b):
head=self.head
head[a]=E(b,head[a])
#head[b]=E(a,head[b])
return head[a]
def scc(g):
n=g.n
cur=g.head
last=[None]*n
order=[-1]*n
low=[-1]*n
bl=[-1]*n
idx=[]
st=[]
num=0
for i in range(n):
if order[i]!=-1:
continue
rec=[i]
while rec:
v=rec[-1]
if last[v] is None:
#first in v
order[v]=low[v]=num
num+=1
st.append(v)
else:
#process last edge
low[v]=min(low[v],low[last[v].to])
found=False
while cur[v] is not None:
#process next edge
e=cur[v]
cur[v]=e.nx
to=e.to
if order[to]==-1:
#visit another node
rec.append(to)
last[v]=e
found=True
break
elif bl[to]==-1:
low[v]=min(low[v],order[to])
if not found:
#last out v
rec.pop()
if order[v]==low[v]:
c=len(idx)
tmp=[]
while True:
a=st.pop()
bl[a]=c
tmp.append(a)
if v==a:
break
idx.append(tmp)
s=len(idx)
for i in range(n):
bl[i]=s-1-bl[i]
idx.reverse()
return (s,bl,idx)
class twosat:
def __init__(self,n):
self.n=n
self.g=Graph(2*n)
def add(self,x,y):
self.g.ae(x^1,y)
self.g.ae(y^1,x)
def solve(self):
s,bl,idx=scc(self.g)
for i in range(self.n):
if bl[i*2]==bl[i*2+1]:
return False
return True
n=int(readline())
N=n*3
a=list(map(int,readline().split()))
b=list(map(int,readline().split()))
for i in range(N):
a[i]-=1
b[i]-=1
apos=[[] for i in range(n)]
for i in range(N):
apos[a[i]].append(i)
bpos=[[] for i in range(n)]
for i in range(N):
bpos[b[i]].append(i)
def feasible(l,r):
t=[False]*N
def issubseq():
head=l
for i in range(N):
if t[i]:
while head<r and a[i]!=b[head]:
head+=1
if head==r:
return False
head+=1
return True
l2r=[]
r2l=[]
w=[]
for val in range(n):
z=[]
for x in bpos[val]:
if x<l:
z.append(0)
elif x<r:
z.append(1)
else:
z.append(2)
if z==[0,0,0]:
return False
elif z==[0,0,1]:
t[apos[val][2]]=1
elif z==[0,0,2]:
x=l-bpos[val][0]
y=bpos[val][2]-r
r2l.append((x,y))
elif z==[0,1,1]:
t[apos[val][0]]=1
t[apos[val][2]]=1
elif z==[0,1,2]:
x=l-bpos[val][0]
y=bpos[val][2]-r
w.append((apos[val][0],apos[val][2],x,y))
elif z==[0,2,2]:
x=l-bpos[val][0]
y=bpos[val][2]-r
l2r.append((x,y))
elif z==[1,1,1]:
t[apos[val][0]]=1
t[apos[val][1]]=1
t[apos[val][2]]=1
elif z==[1,1,2]:
t[apos[val][0]]=1
t[apos[val][2]]=1
elif z==[1,2,2]:
t[apos[val][0]]=1
elif z==[2,2,2]:
return False
else:
assert False
if not issubseq():
return False
def conflict(xa,xb,ya,yb):
return ya<=xa and xb<=yb
for xa,xb in l2r:
for ya,yb in r2l:
if conflict(xa,xb,ya,yb):
return False
s=len(w)
ts=twosat(s)
for i in range(s):
pa,pb,qa,qb=w[i]
#left is ok?
ok=True
t[pa]=1
if not issubseq():
ok=False
t[pa]=0;
if ok:
for xa,xb in l2r:
if conflict(xa,xb,qa,qb):
ok=False
if not ok:
ts.add(i*2+1,i*2+1)
#right is ok?
ok=True
t[pb]=1;
if not issubseq():
ok=False
t[pb]=0;
if ok:
for ya,yb in r2l:
if conflict(qa,qb,ya,yb):
ok=False
if not ok:
ts.add(i*2,i*2)
for i in range(s):
for j in range(i+1,s):
p0a,p0b,q0a,q0b=w[i]
p1a,p1b,q1a,q1b=w[j]
t0=bpos[a[p0a]][1]
t1=bpos[a[p1a]][1]
#left-left is ok?
ok=True
if (p0a<p1a)!=(t0<t1):
ok=False
if not ok:
ts.add(i*2+1,j*2+1)
#left-right is ok?
ok=True
if (p0a<p1b)!=(t0<t1):
ok=False
if conflict(q1a,q1b,q0a,q0b):
ok=False
if not ok:
ts.add(i*2+1,j*2)
#right-left is ok?
ok=True
if (p0b<p1a)!=(t0<t1):
ok=False;
if conflict(q0a,q0b,q1a,q1b):
ok=False
if not ok:
ts.add(i*2,j*2+1)
#right-right is ok?
ok=True
if (p0b<p1b)!=(t0<t1):
ok=False
if not ok:
ts.add(i*2,j*2);
return ts.solve();
ans=10**18
for i in range(N):
for j in range(i,N+1):
if feasible(i,j):
ans=min(ans,N-(j-i))
if ans==10**18:
ans=-1
print(ans)
``` | output | 1 | 87,303 | 5 | 174,607 |
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