message stringlengths 2 44.5k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 42 109k | cluster float64 5 5 | __index_level_0__ int64 84 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let f_{x} = c^{2x-6} β
f_{x-1} β
f_{x-2} β
f_{x-3} for x β₯ 4.
You have given integers n, f_{1}, f_{2}, f_{3}, and c. Find f_{n} mod (10^{9}+7).
Input
The only line contains five integers n, f_{1}, f_{2}, f_{3}, and c (4 β€ n β€ 10^{18}, 1 β€ f_{1}, f_{2}, f_{3}, c β€ 10^{9}).
Output
Print f_{n} mod (10^{9} + 7).
Examples
Input
5 1 2 5 3
Output
72900
Input
17 97 41 37 11
Output
317451037
Note
In the first example, f_{4} = 90, f_{5} = 72900.
In the second example, f_{17} β 2.28 Γ 10^{29587}.
Submitted Solution:
```
from math import ceil
c33 = 33 ** (1 / 2)
q = (586 + 102 * c33) ** (2 / 3) + 4 - 2 * ((586 + 102 * c33) ** (1 / 3))
lol = ((586 + 102 * c33) ** (1 / 3))
M = 10 ** 9 + 7
def trib(n):
c33 = 33 ** 0.5
p = (int((((19 + 3*c33) ** (1 / 3) + (19 - 3 * c33) ** (1 / 3) + 1) / 3) ** n) % M) * lol
return ceil(3 * p / q) - (n == 5)
n, f1, f2, f3, c = map(int, input().split())
if n == 17:
print(317451037)
exit(0)
ans = 1
ans *= pow(c, (pow(2, (n - 2), M - 1) - 2), M)
a = trib(n - 4)
b = trib(n - 3)
d = trib(n - 2)
ans *= pow(f3, d, M)
ans *= pow(f2, a + b, M)
ans *= pow(f1, b, M)
print(ans % M)
``` | instruction | 0 | 99,565 | 5 | 199,130 |
No | output | 1 | 99,565 | 5 | 199,131 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let f_{x} = c^{2x-6} β
f_{x-1} β
f_{x-2} β
f_{x-3} for x β₯ 4.
You have given integers n, f_{1}, f_{2}, f_{3}, and c. Find f_{n} mod (10^{9}+7).
Input
The only line contains five integers n, f_{1}, f_{2}, f_{3}, and c (4 β€ n β€ 10^{18}, 1 β€ f_{1}, f_{2}, f_{3}, c β€ 10^{9}).
Output
Print f_{n} mod (10^{9} + 7).
Examples
Input
5 1 2 5 3
Output
72900
Input
17 97 41 37 11
Output
317451037
Note
In the first example, f_{4} = 90, f_{5} = 72900.
In the second example, f_{17} β 2.28 Γ 10^{29587}.
Submitted Solution:
```
def mat_mul(a, b):
n, m, p = len(a), len(b), len(b[0])
res = [[0]*p for _ in range(n)]
for i in range(n):
for j in range(p):
for k in range(m):
res[i][j] += a[i][k]*b[k][j]
res[i][j] %= 1000000007
return res
def mat_pow(a, n):
if n == 1: return a
if n%2 == 1: return mat_mul(mat_pow(a, n-1), a)
t = mat_pow(a, n//2)
return mat_mul(t, t)
n, f1, f2, f3, c = map(int, input().split())
m1 = [[3, 1000000005, 0, 1000000006, 1], [1, 0, 0, 0, 0], [0, 1, 0, 0, 0], [0, 0, 1, 0, 0], [0, 0, 0, 1, 0]]
m2 = [[2], [0], [0], [0], [0]]
t1 = pow(c, mat_mul(mat_pow(m1, n), m2)[-1][0], 1000000007)
m1 = [[0, 0, 1], [1, 0, 1], [0, 1, 1]]
m2 = [[1], [0], [0]]
m3 = mat_mul(mat_pow(m1, n-1), m2)
t2 = pow(f1, m3[0][0], 1000000007)
t3 = pow(f2, m3[1][0], 1000000007)
t4 = pow(f3, m3[2][0], 1000000007)
print(t1*t2*t3*t4%1000000007)
``` | instruction | 0 | 99,566 | 5 | 199,132 |
No | output | 1 | 99,566 | 5 | 199,133 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's denote as <image> the number of bits set ('1' bits) in the binary representation of the non-negative integer x.
You are given multiple queries consisting of pairs of integers l and r. For each query, find the x, such that l β€ x β€ r, and <image> is maximum possible. If there are multiple such numbers find the smallest of them.
Input
The first line contains integer n β the number of queries (1 β€ n β€ 10000).
Each of the following n lines contain two integers li, ri β the arguments for the corresponding query (0 β€ li β€ ri β€ 1018).
Output
For each query print the answer in a separate line.
Examples
Input
3
1 2
2 4
1 10
Output
1
3
7
Note
The binary representations of numbers from 1 to 10 are listed below:
110 = 12
210 = 102
310 = 112
410 = 1002
510 = 1012
610 = 1102
710 = 1112
810 = 10002
910 = 10012
1010 = 10102 | instruction | 0 | 99,778 | 5 | 199,556 |
Tags: bitmasks, constructive algorithms
Correct Solution:
```
n = int(input())
for i in range(n):
l,r = map(int,input().split())
while ((l|(l+1))<=r): l|=(l+1)
print(l)
``` | output | 1 | 99,778 | 5 | 199,557 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's denote as <image> the number of bits set ('1' bits) in the binary representation of the non-negative integer x.
You are given multiple queries consisting of pairs of integers l and r. For each query, find the x, such that l β€ x β€ r, and <image> is maximum possible. If there are multiple such numbers find the smallest of them.
Input
The first line contains integer n β the number of queries (1 β€ n β€ 10000).
Each of the following n lines contain two integers li, ri β the arguments for the corresponding query (0 β€ li β€ ri β€ 1018).
Output
For each query print the answer in a separate line.
Examples
Input
3
1 2
2 4
1 10
Output
1
3
7
Note
The binary representations of numbers from 1 to 10 are listed below:
110 = 12
210 = 102
310 = 112
410 = 1002
510 = 1012
610 = 1102
710 = 1112
810 = 10002
910 = 10012
1010 = 10102
Submitted Solution:
```
n = int(input())
for i in range(n):
l, r = map(int, input().split())
l = bin(l)[2:]
r = bin(r)[2:]
while len(l) < len(r):
l = '0' + l
x = [0] * len(l)
for i in range(len(l)):
x[i] = l[i]
if l[i] < r[i]:
ok = True
for j in range(i+1, len(l)):
x[j] = '1'
if r[j] == '0':
ok = False
if ok:
x[i] = '1'
break
print(int(''.join(x), 2))
``` | instruction | 0 | 99,785 | 5 | 199,570 |
Yes | output | 1 | 99,785 | 5 | 199,571 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's denote as <image> the number of bits set ('1' bits) in the binary representation of the non-negative integer x.
You are given multiple queries consisting of pairs of integers l and r. For each query, find the x, such that l β€ x β€ r, and <image> is maximum possible. If there are multiple such numbers find the smallest of them.
Input
The first line contains integer n β the number of queries (1 β€ n β€ 10000).
Each of the following n lines contain two integers li, ri β the arguments for the corresponding query (0 β€ li β€ ri β€ 1018).
Output
For each query print the answer in a separate line.
Examples
Input
3
1 2
2 4
1 10
Output
1
3
7
Note
The binary representations of numbers from 1 to 10 are listed below:
110 = 12
210 = 102
310 = 112
410 = 1002
510 = 1012
610 = 1102
710 = 1112
810 = 10002
910 = 10012
1010 = 10102
Submitted Solution:
```
'''
Auther: ghoshashis545 Ashis Ghosh
College: jalpaiguri Govt Enggineerin College
Date:28/03/2020
'''
from math import ceil,sqrt,log,gcd
def ii():return int(input())
def si():return input()
def mi():return map(int,input().split())
def li():return list(mi())
def main():
# for _ in range(ii()):
n=ii()
for i in range(n):
l,r=mi()
s1=bin(r)[2:]
n1=len(s1)
s2=bin(l)[2:]
s2='0'*(n1-len(s2))+s2
s2=list(s2)
s1=list(s1)
x=s1.count('1')
f=0
f1=-1
for i in range(n1):
if(f==1):
s2[i]='1'
elif(s1[i]!=s2[i]):
f1=i
f=1
if(f1!=-1):
s3=s2[:]
s3[f1]='1'
s3="".join(s3)
x=int(s3,2)
if(x<=r):
print(x)
else:
s2="".join(s2)
print(int(s2,2))
else:
s2="".join(s2)
print(int(s2,2))
if __name__ =="__main__":
main()
``` | instruction | 0 | 99,786 | 5 | 199,572 |
Yes | output | 1 | 99,786 | 5 | 199,573 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's denote as <image> the number of bits set ('1' bits) in the binary representation of the non-negative integer x.
You are given multiple queries consisting of pairs of integers l and r. For each query, find the x, such that l β€ x β€ r, and <image> is maximum possible. If there are multiple such numbers find the smallest of them.
Input
The first line contains integer n β the number of queries (1 β€ n β€ 10000).
Each of the following n lines contain two integers li, ri β the arguments for the corresponding query (0 β€ li β€ ri β€ 1018).
Output
For each query print the answer in a separate line.
Examples
Input
3
1 2
2 4
1 10
Output
1
3
7
Note
The binary representations of numbers from 1 to 10 are listed below:
110 = 12
210 = 102
310 = 112
410 = 1002
510 = 1012
610 = 1102
710 = 1112
810 = 10002
910 = 10012
1010 = 10102
Submitted Solution:
```
import sys
import math
import collections
import heapq
input=sys.stdin.readline
n=int(input())
for i in range(n):
l,r=(int(i) for i in input().split())
while(l|(l+1)<=r):
l|=(l+1)
print(l)
``` | instruction | 0 | 99,787 | 5 | 199,574 |
Yes | output | 1 | 99,787 | 5 | 199,575 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's denote as <image> the number of bits set ('1' bits) in the binary representation of the non-negative integer x.
You are given multiple queries consisting of pairs of integers l and r. For each query, find the x, such that l β€ x β€ r, and <image> is maximum possible. If there are multiple such numbers find the smallest of them.
Input
The first line contains integer n β the number of queries (1 β€ n β€ 10000).
Each of the following n lines contain two integers li, ri β the arguments for the corresponding query (0 β€ li β€ ri β€ 1018).
Output
For each query print the answer in a separate line.
Examples
Input
3
1 2
2 4
1 10
Output
1
3
7
Note
The binary representations of numbers from 1 to 10 are listed below:
110 = 12
210 = 102
310 = 112
410 = 1002
510 = 1012
610 = 1102
710 = 1112
810 = 10002
910 = 10012
1010 = 10102
Submitted Solution:
```
'''
Auther: ghoshashis545 Ashis Ghosh
College: jalpaiguri Govt Enggineerin College
Date:28/03/2020
'''
from math import ceil,sqrt,log,gcd
def ii():return int(input())
def si():return input()
def mi():return map(int,input().split())
def li():return list(mi())
def main():
# for _ in range(ii()):
n=ii()
for i in range(n):
l,r=mi()
s1=bin(r)[2:]
n1=len(s1)
s2=bin(l)[2:]
s2='0'*(n1-len(s2))+s2
s2=list(s2)
s1=list(s1)
x=s1.count('1')
f=0
for i in range(n1):
if(f==1):
s2[i]='1'
elif(s1[i]!=s2[i]):
f=1
s2="".join(s2)
if(x==n1):
print(r)
else:
print(int(s2,2))
if __name__ =="__main__":
main()
``` | instruction | 0 | 99,788 | 5 | 199,576 |
No | output | 1 | 99,788 | 5 | 199,577 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's denote as <image> the number of bits set ('1' bits) in the binary representation of the non-negative integer x.
You are given multiple queries consisting of pairs of integers l and r. For each query, find the x, such that l β€ x β€ r, and <image> is maximum possible. If there are multiple such numbers find the smallest of them.
Input
The first line contains integer n β the number of queries (1 β€ n β€ 10000).
Each of the following n lines contain two integers li, ri β the arguments for the corresponding query (0 β€ li β€ ri β€ 1018).
Output
For each query print the answer in a separate line.
Examples
Input
3
1 2
2 4
1 10
Output
1
3
7
Note
The binary representations of numbers from 1 to 10 are listed below:
110 = 12
210 = 102
310 = 112
410 = 1002
510 = 1012
610 = 1102
710 = 1112
810 = 10002
910 = 10012
1010 = 10102
Submitted Solution:
```
import sys
def binary(a):
s = ""
for i in range(64):
if(a%2 == 0):
s += "0"
else:
s += "1"
a //= 2
return s
def dec(s):
resp = 0;
for k in s:
resp *= 2
if(k == '1'):
resp += 1
return resp
def solve(a, b):
x = binary(a)
y = binary(b)
resp = 0
gen = ""
for i in range(len(x)-1, -1, -1):
if(x[i] == y[i]):
gen += x[i]
else:
gen += "0"
for j in range(i-1, -1, -1):
gen += "1"
break
# print(x, y, gen)
return dec(gen)
casos = int(input())
for i in range(casos):
line = input()
v = [int(x) for x in line.split()]
print(solve(v[0], v[1]))
``` | instruction | 0 | 99,789 | 5 | 199,578 |
No | output | 1 | 99,789 | 5 | 199,579 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's denote as <image> the number of bits set ('1' bits) in the binary representation of the non-negative integer x.
You are given multiple queries consisting of pairs of integers l and r. For each query, find the x, such that l β€ x β€ r, and <image> is maximum possible. If there are multiple such numbers find the smallest of them.
Input
The first line contains integer n β the number of queries (1 β€ n β€ 10000).
Each of the following n lines contain two integers li, ri β the arguments for the corresponding query (0 β€ li β€ ri β€ 1018).
Output
For each query print the answer in a separate line.
Examples
Input
3
1 2
2 4
1 10
Output
1
3
7
Note
The binary representations of numbers from 1 to 10 are listed below:
110 = 12
210 = 102
310 = 112
410 = 1002
510 = 1012
610 = 1102
710 = 1112
810 = 10002
910 = 10012
1010 = 10102
Submitted Solution:
```
from sys import stdin
lines = list(filter(None, stdin.read().split('\n')))
def parseline(line):
return list(map(int, line.split()))
lines = list(map(parseline, lines))
n, = lines[0]
def round_to_power_of_2(k):
k |= k >> 1
k |= k >> 2
k |= k >> 4
k |= k >> 8
k |= k >> 16
k += 1
return k
def is_power_of_2(k):
return 0 == k & (k-1)
for li, ri in lines[1:n+1]:
if is_power_of_2(ri + 1):
print(ri)
else:
z = round_to_power_of_2((li ^ ri)) >> 1
y = round_to_power_of_2(ri) - 1
print(z ^ y)
``` | instruction | 0 | 99,790 | 5 | 199,580 |
No | output | 1 | 99,790 | 5 | 199,581 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's denote as <image> the number of bits set ('1' bits) in the binary representation of the non-negative integer x.
You are given multiple queries consisting of pairs of integers l and r. For each query, find the x, such that l β€ x β€ r, and <image> is maximum possible. If there are multiple such numbers find the smallest of them.
Input
The first line contains integer n β the number of queries (1 β€ n β€ 10000).
Each of the following n lines contain two integers li, ri β the arguments for the corresponding query (0 β€ li β€ ri β€ 1018).
Output
For each query print the answer in a separate line.
Examples
Input
3
1 2
2 4
1 10
Output
1
3
7
Note
The binary representations of numbers from 1 to 10 are listed below:
110 = 12
210 = 102
310 = 112
410 = 1002
510 = 1012
610 = 1102
710 = 1112
810 = 10002
910 = 10012
1010 = 10102
Submitted Solution:
```
for i in range(int(input())):
l,r=map(int,input().split())
L=list(bin(l))
R=list(bin(r))
L=L[2:]
R=R[2:]
w=0
c=0
L=['0']*(len(R)-len(L))+L
# print(L,R)
ans=0
for i in range(len(R)):
if L[i]!=R[i]:
for j in range(i+1,len(R)):
if(R[j]=='0'):
w=1
if w==1:
ans=c+(2**(len(R)-i-1))-1
break
else:
ans=c+(2**len(R)-i)-1
break
elif L[i]=='1':
c=c+(2**(len(R)-i)-1)
print(ans)
``` | instruction | 0 | 99,791 | 5 | 199,582 |
No | output | 1 | 99,791 | 5 | 199,583 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Consider the function p(x), where x is an array of m integers, which returns an array y consisting of m + 1 integers such that yi is equal to the sum of first i elements of array x (0 β€ i β€ m).
You have an infinite sequence of arrays A0, A1, A2..., where A0 is given in the input, and for each i β₯ 1 Ai = p(Ai - 1). Also you have a positive integer k. You have to find minimum possible i such that Ai contains a number which is larger or equal than k.
Input
The first line contains two integers n and k (2 β€ n β€ 200000, 1 β€ k β€ 1018). n is the size of array A0.
The second line contains n integers A00, A01... A0n - 1 β the elements of A0 (0 β€ A0i β€ 109). At least two elements of A0 are positive.
Output
Print the minimum i such that Ai contains a number which is larger or equal than k.
Examples
Input
2 2
1 1
Output
1
Input
3 6
1 1 1
Output
2
Input
3 1
1 0 1
Output
0
Submitted Solution:
```
import sys
from time import sleep
def increment(a):
for i in range(1, n):
a[i] += a[i-1]
class DimensionError(ValueError):
pass
class Matrix:
def __init__(self, m, n, data=None):
self.m = m
self.n = n
self.mn = m * n
if data is None:
self.data = [0] * self.mn
else:
if len(data) == self.mn:
self.data = data
else:
raise DimensionError()
def __repr__(self):
return 'Matrix({}, {}, {})'.format(self.m, self.n, self.data)
def __call__(self, i, j):
if i < 0 or i >= self.m or j < 0 or j >= self.n:
raise IndexError("({}, {})".format(i, j))
return self.data[i * self.n + j]
def set_elem(self, i, j, x):
if i < 0 or i >= self.m or j < 0 or j >= self.n:
raise IndexError("({}, {})".format(i, j))
self.data[i * self.n + j] = x
def add_to_elem(self, i, j, x):
if i < 0 or i >= self.m or j < 0 or j >= self.n:
raise IndexError("({}, {})".format(i, j))
self.data[i * self.n + j] += x
def last(self):
return self.data[-1]
def scalar_mul_ip(self, s):
for i in range(len(data)):
self.data[i] *= s
return self
def scalar_mul(self, s):
data2 = [x * s for x in self.data]
return Matrix(self.m, self.n, data2)
def matrix_mul(self, B):
if self.n != B.m:
raise DimensionError()
m = self.m
p = self.n
n = B.n
C = Matrix(m, n)
for i in range(m):
for j in range(n):
for k in range(p):
C.add_to_elem(i, j, self(i, k) * B(k, j))
return C
def __imul__(self, x):
if isinstance(x, int):
return self.scalar_mul_ip(x)
# Matrix multiplication will be handled by __mul__
else:
return NotImplemented
def __mul__(self, x):
if isinstance(x, int):
return self.scalar_mul(x)
elif isinstance(x, Matrix):
return self.matrix_mul(x)
else:
return NotImplemented
def __rmul__(self, x):
if isinstance(x, int):
return self.scalar_mul(x)
# Matrix multiplication will be handled by __mul__
else:
return NotImplemented
if __name__ == '__main__':
n, k = [int(x) for x in input().split()]
a = [int(x) for x in input().split()]
assert(len(a) == n)
for i, x in enumerate(a):
if x > 0:
break
if i > 0:
a = a[i:]
n = len(a)
if max(a) >= k:
print(0)
sys.exit(0)
else:
increment(a)
if n > 10:
p = 0
while a[-1] < k:
increment(a)
p += 1
"""
if p % 100 == 0 and sys.stderr.isatty():
print(' ' * 40, end='\r', file=sys.stderr)
print(p, a[-1], end='\r', file=sys.stderr)
"""
"""
if sys.stderr.isatty():
print(file=sys.stderr)
"""
print(p+1)
sys.exit(0)
if a[-1] >= k:
print(1)
sys.exit(0)
A = Matrix(n, n)
for i in range(n):
for j in range(i+1):
A.set_elem(i, j, 1)
X = Matrix(n, 1, a)
pA = [A] # pA[i] = A^(2^i)
i=0
while (pA[i]*X).last() < k:
# print('len(pA) =', len(pA), file=sys.stderr)
# print('pA[-1] =', pA[-1].data, file=sys.stderr)
pA.append(pA[i] * pA[i])
i += 1
# print('pA computed', file=sys.stderr)
B = Matrix(n, n)
for i in range(n):
B.set_elem(i, i, 1)
p = 0
for i, A2 in reversed(list(enumerate(pA))):
# invariant: B = A^p and B is a power of A such that (B*X).last() < k
B2 = B * A2
if (B2 * X).last() < k:
p += (1 << i)
B = B2
# Now increment X so that X.last() becomes >= k
X = B * X
p += 1
increment(X.data)
# Print p+1 because we had incremented X in the beginning of program
print(p+1)
``` | instruction | 0 | 99,989 | 5 | 199,978 |
Yes | output | 1 | 99,989 | 5 | 199,979 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Consider the function p(x), where x is an array of m integers, which returns an array y consisting of m + 1 integers such that yi is equal to the sum of first i elements of array x (0 β€ i β€ m).
You have an infinite sequence of arrays A0, A1, A2..., where A0 is given in the input, and for each i β₯ 1 Ai = p(Ai - 1). Also you have a positive integer k. You have to find minimum possible i such that Ai contains a number which is larger or equal than k.
Input
The first line contains two integers n and k (2 β€ n β€ 200000, 1 β€ k β€ 1018). n is the size of array A0.
The second line contains n integers A00, A01... A0n - 1 β the elements of A0 (0 β€ A0i β€ 109). At least two elements of A0 are positive.
Output
Print the minimum i such that Ai contains a number which is larger or equal than k.
Examples
Input
2 2
1 1
Output
1
Input
3 6
1 1 1
Output
2
Input
3 1
1 0 1
Output
0
Submitted Solution:
```
mod = 10**9 + 7
n, k = map(int,input().split())
a = list(map(int, input().split()))
a.reverse()
def sol() :
l = 0; r = 10**18; mid = 0; p = 1; sum = 0
while r - l > 1 :
mid = (l + r) // 2
p = 1; sum = 0
for i in range(n) :
if a[i] * p >= k : r = mid; break
sum += a[i] * p
if sum >= k : r = mid; break
if i + 1 < n : p = p * (mid + i) // (i + 1)
if p >= k : r = mid; break
if r != mid : l = mid + 1
p = 1; sum = 0
for i in range(n) :
if a[i] * p >= k : return l
sum += a[i] * p
if sum >= k : return l
if i + 1 < n : p = p * (l + i) // (i + 1)
if p >= k : return l
return r
for i in range(n - 1, -1, -1) :
if a[i] != 0 : break
else : n -= 1
if max(a) >= k : print(0)
else : print(sol())
``` | instruction | 0 | 99,990 | 5 | 199,980 |
Yes | output | 1 | 99,990 | 5 | 199,981 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Consider the function p(x), where x is an array of m integers, which returns an array y consisting of m + 1 integers such that yi is equal to the sum of first i elements of array x (0 β€ i β€ m).
You have an infinite sequence of arrays A0, A1, A2..., where A0 is given in the input, and for each i β₯ 1 Ai = p(Ai - 1). Also you have a positive integer k. You have to find minimum possible i such that Ai contains a number which is larger or equal than k.
Input
The first line contains two integers n and k (2 β€ n β€ 200000, 1 β€ k β€ 1018). n is the size of array A0.
The second line contains n integers A00, A01... A0n - 1 β the elements of A0 (0 β€ A0i β€ 109). At least two elements of A0 are positive.
Output
Print the minimum i such that Ai contains a number which is larger or equal than k.
Examples
Input
2 2
1 1
Output
1
Input
3 6
1 1 1
Output
2
Input
3 1
1 0 1
Output
0
Submitted Solution:
```
s = input().split()
n = int(s[0]); k = int(s[1])
s = input().split()
a = [1]
for i in range(1, n + 1):
a.append(int(s[i - 1]))
for i in range(1, n + 1):
if (a[i] >= k):
print(0); exit(0)
def C(nn, kk):
global k
prod = 1
kk = min(kk, nn - kk)
# print(nn, nn - kk + 1)
for i in range(1, kk + 1):
# print("///" + str(i))
prod *= nn - i + 1
prod = prod // i
if (prod >= k):
return -1
if (prod >= k):
return -1
return prod
def holyshit(pwr):
global n, k, a
sum = 0
for i in range(n, 0, -1):
if (a[i] == 0):
continue
prod = C(pwr - 1 + n - i, pwr - 1)
if (prod == -1):
return True
sum += prod * a[i]
if (sum >= k):
return True
# print("wait, the sum is..." + str(sum))
return False
left = 1; right = int(1e19); ans = int(1e19)
while left <= right:
mid = (left + right) >> 1
# print("/" + str(left) + " " + str(mid) + " " + str(right))
if (holyshit(mid)):
# print("////okay")
ans = mid
right = mid - 1
else:
# print("////notokay")
left = mid + 1
print(ans)
# print(int(1e19))
# k = int(1e18)
# # print(C(6, 3))
# # print(C(10, 1))
# # print(C(7, 5))
# # print(C(8, 2))
``` | instruction | 0 | 99,991 | 5 | 199,982 |
Yes | output | 1 | 99,991 | 5 | 199,983 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Consider the function p(x), where x is an array of m integers, which returns an array y consisting of m + 1 integers such that yi is equal to the sum of first i elements of array x (0 β€ i β€ m).
You have an infinite sequence of arrays A0, A1, A2..., where A0 is given in the input, and for each i β₯ 1 Ai = p(Ai - 1). Also you have a positive integer k. You have to find minimum possible i such that Ai contains a number which is larger or equal than k.
Input
The first line contains two integers n and k (2 β€ n β€ 200000, 1 β€ k β€ 1018). n is the size of array A0.
The second line contains n integers A00, A01... A0n - 1 β the elements of A0 (0 β€ A0i β€ 109). At least two elements of A0 are positive.
Output
Print the minimum i such that Ai contains a number which is larger or equal than k.
Examples
Input
2 2
1 1
Output
1
Input
3 6
1 1 1
Output
2
Input
3 1
1 0 1
Output
0
Submitted Solution:
```
n, k = map(int, input().split())
A = []
for x in map(int, input().split()):
if x > 0 or len(A) > 0:
A.append(x)
if max(A) >= k:
print(0)
elif len(A) == 2:
if (k-A[1]) % A[0] == 0:
print((k-A[1])//A[0])
else :
print ((k-A[1])//A[0] + 1)
elif len(A) == 3:
left = 0
right = 10**18
while left < right:
mid = (left + right) // 2
if A[2] + A[1] * mid + A[0] * mid * (mid + 1) // 2 >= k:
right = mid
else : left = mid + 1
print (left)
else :
ans = 0
while A[-1] < k:
ans += 1
for i in range(1, len(A)):
A[i] += A[i-1]
print (ans)
``` | instruction | 0 | 99,992 | 5 | 199,984 |
Yes | output | 1 | 99,992 | 5 | 199,985 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Consider the function p(x), where x is an array of m integers, which returns an array y consisting of m + 1 integers such that yi is equal to the sum of first i elements of array x (0 β€ i β€ m).
You have an infinite sequence of arrays A0, A1, A2..., where A0 is given in the input, and for each i β₯ 1 Ai = p(Ai - 1). Also you have a positive integer k. You have to find minimum possible i such that Ai contains a number which is larger or equal than k.
Input
The first line contains two integers n and k (2 β€ n β€ 200000, 1 β€ k β€ 1018). n is the size of array A0.
The second line contains n integers A00, A01... A0n - 1 β the elements of A0 (0 β€ A0i β€ 109). At least two elements of A0 are positive.
Output
Print the minimum i such that Ai contains a number which is larger or equal than k.
Examples
Input
2 2
1 1
Output
1
Input
3 6
1 1 1
Output
2
Input
3 1
1 0 1
Output
0
Submitted Solution:
```
def list_input():
return list(map(int,input().split()))
def map_input():
return map(int,input().split())
def map_string():
return input().split()
def power(a,b,m):
if b == 0: return 1
if b == 1: return a
x = min(power(a,b//2,m),m)
if b%2 == 1: return min(m,x*x*a)
else: return min(m,x*x)
def solve(a,n,k,i):
res = 0
cur = n
if i == 0:
return max(a) >= k
for j in range(n):
res += a[j]*power(cur,i-1,k)
if res >= k:
return True
cur -= 1
return False
n,k = map(int,input().split())
a = list_input()
b = []
for i in a:
if i != 0:
b.append(i)
a = b[::]
n = len(a)
low = 0
high = k
ans = -1
while low <= high:
mid = (low+high)//2
if solve(a,n,k,mid):
high = mid-1
ans = mid
else:
low = mid+1
print(ans)
``` | instruction | 0 | 99,993 | 5 | 199,986 |
No | output | 1 | 99,993 | 5 | 199,987 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Consider the function p(x), where x is an array of m integers, which returns an array y consisting of m + 1 integers such that yi is equal to the sum of first i elements of array x (0 β€ i β€ m).
You have an infinite sequence of arrays A0, A1, A2..., where A0 is given in the input, and for each i β₯ 1 Ai = p(Ai - 1). Also you have a positive integer k. You have to find minimum possible i such that Ai contains a number which is larger or equal than k.
Input
The first line contains two integers n and k (2 β€ n β€ 200000, 1 β€ k β€ 1018). n is the size of array A0.
The second line contains n integers A00, A01... A0n - 1 β the elements of A0 (0 β€ A0i β€ 109). At least two elements of A0 are positive.
Output
Print the minimum i such that Ai contains a number which is larger or equal than k.
Examples
Input
2 2
1 1
Output
1
Input
3 6
1 1 1
Output
2
Input
3 1
1 0 1
Output
0
Submitted Solution:
```
n, k = map(int,input().split())
a = list(map(int,input().split()))
def check(x):
if x==0:
return max(a) >= k
binomial = 1
sum = 0
for i in range(n):
if binomial >= k:
return True
sum += binomial * a[n-i-1]
binomial *= (x+i)
binomial //= (i+1)
if sum >= k:
return True
return False
lo,hi = 0, k
while lo < hi:
md = (lo+hi) // 2
if check(md):
hi = md;
else:
lo = md + 1
print(lo)
``` | instruction | 0 | 99,994 | 5 | 199,988 |
No | output | 1 | 99,994 | 5 | 199,989 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Consider the function p(x), where x is an array of m integers, which returns an array y consisting of m + 1 integers such that yi is equal to the sum of first i elements of array x (0 β€ i β€ m).
You have an infinite sequence of arrays A0, A1, A2..., where A0 is given in the input, and for each i β₯ 1 Ai = p(Ai - 1). Also you have a positive integer k. You have to find minimum possible i such that Ai contains a number which is larger or equal than k.
Input
The first line contains two integers n and k (2 β€ n β€ 200000, 1 β€ k β€ 1018). n is the size of array A0.
The second line contains n integers A00, A01... A0n - 1 β the elements of A0 (0 β€ A0i β€ 109). At least two elements of A0 are positive.
Output
Print the minimum i such that Ai contains a number which is larger or equal than k.
Examples
Input
2 2
1 1
Output
1
Input
3 6
1 1 1
Output
2
Input
3 1
1 0 1
Output
0
Submitted Solution:
```
import math
n, k = map(int, input().split())
A = []
for x in map(int, input().split()):
if x > 0 or len(A) > 0:
A.append(x)
if max(A) >= k:
print(0)
elif len(A) == 2:
print (math.ceil((k-A[1])/A[0]))
elif len(A) == 3:
left = 0
right = 10**18
while left < right:
mid = (left + right) // 2
if A[0] + A[1] * mid + A[2] * mid * (mid + 1) // 2 >= k:
right = mid
else : left = mid + 1
print (left)
else :
ans = 0
while A[-1] < k:
ans += 1
for i in range(1, len(A)):
A[i] += A[i-1]
print (ans)
``` | instruction | 0 | 99,995 | 5 | 199,990 |
No | output | 1 | 99,995 | 5 | 199,991 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Consider the function p(x), where x is an array of m integers, which returns an array y consisting of m + 1 integers such that yi is equal to the sum of first i elements of array x (0 β€ i β€ m).
You have an infinite sequence of arrays A0, A1, A2..., where A0 is given in the input, and for each i β₯ 1 Ai = p(Ai - 1). Also you have a positive integer k. You have to find minimum possible i such that Ai contains a number which is larger or equal than k.
Input
The first line contains two integers n and k (2 β€ n β€ 200000, 1 β€ k β€ 1018). n is the size of array A0.
The second line contains n integers A00, A01... A0n - 1 β the elements of A0 (0 β€ A0i β€ 109). At least two elements of A0 are positive.
Output
Print the minimum i such that Ai contains a number which is larger or equal than k.
Examples
Input
2 2
1 1
Output
1
Input
3 6
1 1 1
Output
2
Input
3 1
1 0 1
Output
0
Submitted Solution:
```
from math import factorial
def ncr(n, r):
ans = 1
for i in range(r):
ans*=n-i
for i in range(r):
ans/=i+1
return ans
n,k = map(int, input().split())
inp = list(map(int,input().split()))
nz = 0
seq = []
for i in range(n):
if(inp[i]!=0):
nz = 1
if(nz!=0):
seq.append(inp[i])
if(max(seq) >= k):
print("0")
exit(0)
if(len(seq) <= 8):
seq.reverse()
mn = 1
mx = pow(10,18)
while(mn < mx):
mid = (mn + mx)//2
curr = 0
for i in range(len(seq)):
curr+=seq[i]*ncr(mid+i-1, i)
if(curr>=k):
mx = mid
else:
mn = mid + 1
print(mn)
exit(0)
for i in range(1000):
for j in range(1,len(seq)):
seq[j]+=seq[j-1]
if(max(seq) >= k):
print(i)
exit(0)
``` | instruction | 0 | 99,996 | 5 | 199,992 |
No | output | 1 | 99,996 | 5 | 199,993 |
Provide a correct Python 3 solution for this coding contest problem.
You are given an array a_0, a_1, ..., a_{N-1} of length N. Process Q queries of the following types.
* `0 p x`: a_p \gets a_p + x
* `1 l r`: Print \sum_{i = l}^{r - 1}{a_i}.
Constraints
* 1 \leq N, Q \leq 500,000
* 0 \leq a_i, x \leq 10^9
* 0 \leq p < N
* 0 \leq l_i < r_i \leq N
* All values in Input are integer.
Input
Input is given from Standard Input in the following format:
N Q
a_0 a_1 ... a_{N - 1}
\textrm{Query}_0
\textrm{Query}_1
:
\textrm{Query}_{Q - 1}
Output
For each query of the latter type, print the answer.
Example
Input
5 5
1 2 3 4 5
1 0 5
1 2 4
0 3 10
1 0 5
1 0 3
Output
15
7
25
6 | instruction | 0 | 100,077 | 5 | 200,154 |
"Correct Solution:
```
class BIT():
__slots__ = ["n", "data"]
def __init__(self, length_or_list):
if isinstance(length_or_list, int):
self.n = length_or_list + 1
self.data = [0] * self.n
else:
self.n = len(length_or_list) + 1
self.data = [0] + length_or_list
for i in range(1, self.n):
if i + (i & -i) < self.n:
self.data[i + (i & -i)] += self.data[i]
def point_append(self, index, delta):
index += 1
while index < self.n:
self.data[index] += delta
index += index & -index
def prefix_folded(self, end):
res = 0
while end > 0:
res += self.data[end]
end -= end & -end
return res
def folded(self, begin, end):
ret = 0
while begin < end:
ret += self.data[end]
end -= end & -end
while end < begin:
ret -= self.data[begin]
begin -= begin & -begin
return ret
def main():
import sys
input = sys.stdin.buffer.readline
read = sys.stdin.buffer.read
N, Q = map(int, input().split())
seg = BIT(list(map(int, input().split())))
for _ in range(Q):
a, b, c = map(int, input().split())
if a:
print(seg.folded(b, c))
else:
seg.point_append(b, c)
if __name__ == "__main__":
main()
``` | output | 1 | 100,077 | 5 | 200,155 |
Provide a correct Python 3 solution for this coding contest problem.
You are given an array a_0, a_1, ..., a_{N-1} of length N. Process Q queries of the following types.
* `0 p x`: a_p \gets a_p + x
* `1 l r`: Print \sum_{i = l}^{r - 1}{a_i}.
Constraints
* 1 \leq N, Q \leq 500,000
* 0 \leq a_i, x \leq 10^9
* 0 \leq p < N
* 0 \leq l_i < r_i \leq N
* All values in Input are integer.
Input
Input is given from Standard Input in the following format:
N Q
a_0 a_1 ... a_{N - 1}
\textrm{Query}_0
\textrm{Query}_1
:
\textrm{Query}_{Q - 1}
Output
For each query of the latter type, print the answer.
Example
Input
5 5
1 2 3 4 5
1 0 5
1 2 4
0 3 10
1 0 5
1 0 3
Output
15
7
25
6 | instruction | 0 | 100,078 | 5 | 200,156 |
"Correct Solution:
```
class BIT:
def __init__(self, n):
self.n = n
self.bit = [0]*(self.n+1) # 1-indexed
def init(self, init_val):
for i, v in enumerate(init_val):
self.add(i, v)
def add(self, i, x):
# i: 0-indexed
i += 1 # to 1-indexed
while i <= self.n:
self.bit[i] += x
i += (i & -i)
def sum(self, i, j):
# return sum of [i, j)
# i, j: 0-indexed
return self._sum(j) - self._sum(i)
def _sum(self, i):
# return sum of [0, i)
# i: 0-indexed
res = 0
while i > 0:
res += self.bit[i]
i -= i & (-i)
return res
def lower_bound(self, x):
s = 0
pos = 0
depth = self.n.bit_length()
v = 1 << depth
for i in range(depth, -1, -1):
k = pos + v
if k <= self.n and s + self.bit[k] < x:
s += self.bit[k]
pos += v
v >>= 1
return pos
n, q = map(int, input().split())
A = list(map(int, input().split()))
bit = BIT(n)
bit.init(A)
for _ in range(q):
i, j, k = map(int, input().split())
if i == 0:
bit.add(j, k)
else:
print(bit.sum(j, k))
``` | output | 1 | 100,078 | 5 | 200,157 |
Provide a correct Python 3 solution for this coding contest problem.
You are given an array a_0, a_1, ..., a_{N-1} of length N. Process Q queries of the following types.
* `0 p x`: a_p \gets a_p + x
* `1 l r`: Print \sum_{i = l}^{r - 1}{a_i}.
Constraints
* 1 \leq N, Q \leq 500,000
* 0 \leq a_i, x \leq 10^9
* 0 \leq p < N
* 0 \leq l_i < r_i \leq N
* All values in Input are integer.
Input
Input is given from Standard Input in the following format:
N Q
a_0 a_1 ... a_{N - 1}
\textrm{Query}_0
\textrm{Query}_1
:
\textrm{Query}_{Q - 1}
Output
For each query of the latter type, print the answer.
Example
Input
5 5
1 2 3 4 5
1 0 5
1 2 4
0 3 10
1 0 5
1 0 3
Output
15
7
25
6 | instruction | 0 | 100,079 | 5 | 200,158 |
"Correct Solution:
```
import sys
class Bit:
def __init__(self, n, arr):
self.size = n
self.tree = [0] + arr
for i in range(1, n+1):
x = i + (i & -i)
if x < n + 1:
self.tree[x] += self.tree[i]
def sum(self, i):
s = 0
while i > 0:
s += self.tree[i]
i -= i & -i
return s
def add(self, i, x):
while i <= self.size:
self.tree[i] += x
i += i & -i
def range_sum(self, l, r):
return self.sum(r) - self.sum(l)
def main():
n, q = map(int, sys.stdin.buffer.readline().split())
bit = Bit(n, list(map(int, sys.stdin.buffer.readline().split())))
for x in sys.stdin.buffer.readlines():
q, p, x = map(int, x.split())
if q:
print(bit.range_sum(p, x))
else:
bit.add(p+1, x)
if __name__ == "__main__":
main()
``` | output | 1 | 100,079 | 5 | 200,159 |
Provide a correct Python 3 solution for this coding contest problem.
You are given an array a_0, a_1, ..., a_{N-1} of length N. Process Q queries of the following types.
* `0 p x`: a_p \gets a_p + x
* `1 l r`: Print \sum_{i = l}^{r - 1}{a_i}.
Constraints
* 1 \leq N, Q \leq 500,000
* 0 \leq a_i, x \leq 10^9
* 0 \leq p < N
* 0 \leq l_i < r_i \leq N
* All values in Input are integer.
Input
Input is given from Standard Input in the following format:
N Q
a_0 a_1 ... a_{N - 1}
\textrm{Query}_0
\textrm{Query}_1
:
\textrm{Query}_{Q - 1}
Output
For each query of the latter type, print the answer.
Example
Input
5 5
1 2 3 4 5
1 0 5
1 2 4
0 3 10
1 0 5
1 0 3
Output
15
7
25
6 | instruction | 0 | 100,080 | 5 | 200,160 |
"Correct Solution:
```
import sys
input = lambda: sys.stdin.readline()
class BIT:
def __init__(self, n):
self.n = n
self.data = [0] * (n + 1)
def sum(self, i):
s = 0
while i > 0:
s += self.data[i]
i -= i & -i
return s
def add(self, i, x):
while i <= self.n:
self.data[i] += x
i += i & -i
n, m = map(int, input().split())
c = list(map(int, input().split()))
b = BIT(n)
for i in range(n):
b.add(i + 1, c[i])
res = []
for i in range(m):
t, x, y = map(int, input().split())
if t == 1:
res.append(b.sum(y) - b.sum(x))
else:
b.add(x + 1, y)
print("\n".join(map(str, res)))
``` | output | 1 | 100,080 | 5 | 200,161 |
Provide a correct Python 3 solution for this coding contest problem.
You are given an array a_0, a_1, ..., a_{N-1} of length N. Process Q queries of the following types.
* `0 p x`: a_p \gets a_p + x
* `1 l r`: Print \sum_{i = l}^{r - 1}{a_i}.
Constraints
* 1 \leq N, Q \leq 500,000
* 0 \leq a_i, x \leq 10^9
* 0 \leq p < N
* 0 \leq l_i < r_i \leq N
* All values in Input are integer.
Input
Input is given from Standard Input in the following format:
N Q
a_0 a_1 ... a_{N - 1}
\textrm{Query}_0
\textrm{Query}_1
:
\textrm{Query}_{Q - 1}
Output
For each query of the latter type, print the answer.
Example
Input
5 5
1 2 3 4 5
1 0 5
1 2 4
0 3 10
1 0 5
1 0 3
Output
15
7
25
6 | instruction | 0 | 100,081 | 5 | 200,162 |
"Correct Solution:
```
import sys
sys.setrecursionlimit(10 ** 8)
input = sys.stdin.readline
def main():
def segfunc(x, y):
return x + y
def init(init_val):
for i in range(n):
seg[i + num - 1] = init_val[i]
for i in range(num - 2, -1, -1):
seg[i] = segfunc(seg[2 * i + 1], seg[2 * i + 2])
def update(k, x):
k += num - 1
seg[k] = x
while k:
k = (k - 1) // 2
seg[k] = segfunc(seg[k * 2 + 1], seg[k * 2 + 2])
def query(p, q):
if q <= p:
return ide_ele
p += num - 1
q += num - 2
res = ide_ele
while q - p > 1:
if p & 1 == 0:
res = segfunc(res, seg[p])
if q & 1 == 1:
res = segfunc(res, seg[q])
q -= 1
p = p // 2
q = (q - 1) // 2
if p == q:
res = segfunc(res, seg[p])
else:
res = segfunc(segfunc(res, seg[p]), seg[q])
return res
N, Q = [int(x) for x in input().split()]
A = [int(x) for x in input().split()]
# seg treeεζε€ (εδ½ε
)
n = N
ide_ele = 0
num = 2 ** (n - 1).bit_length()
seg = [ide_ele] * 2 * num
init(A)
for _ in range(Q):
q, p, x = [int(x) for x in input().split()]
if q == 0:
A[p] += x
update(p, A[p])
else:
print(query(p, x))
if __name__ == '__main__':
main()
``` | output | 1 | 100,081 | 5 | 200,163 |
Provide a correct Python 3 solution for this coding contest problem.
You are given an array a_0, a_1, ..., a_{N-1} of length N. Process Q queries of the following types.
* `0 p x`: a_p \gets a_p + x
* `1 l r`: Print \sum_{i = l}^{r - 1}{a_i}.
Constraints
* 1 \leq N, Q \leq 500,000
* 0 \leq a_i, x \leq 10^9
* 0 \leq p < N
* 0 \leq l_i < r_i \leq N
* All values in Input are integer.
Input
Input is given from Standard Input in the following format:
N Q
a_0 a_1 ... a_{N - 1}
\textrm{Query}_0
\textrm{Query}_1
:
\textrm{Query}_{Q - 1}
Output
For each query of the latter type, print the answer.
Example
Input
5 5
1 2 3 4 5
1 0 5
1 2 4
0 3 10
1 0 5
1 0 3
Output
15
7
25
6 | instruction | 0 | 100,082 | 5 | 200,164 |
"Correct Solution:
```
def main():
def f(i,x):
while i<=n:
b[i]+=x
i+=i&-i
def g(i):
s=0
while i:
s+=b[i]
i-=i&-i
return s
(n,q,*w),a,*t=[map(int,t.split())for t in open(0)]
b=[0]*-~n
*map(f,range(1,n+1),a),
for q,l,r in t:
if q:w+=g(r)-g(l),
else:f(l+1,r)
print(' '.join(map(str,w)))
main()
``` | output | 1 | 100,082 | 5 | 200,165 |
Provide a correct Python 3 solution for this coding contest problem.
You are given an array a_0, a_1, ..., a_{N-1} of length N. Process Q queries of the following types.
* `0 p x`: a_p \gets a_p + x
* `1 l r`: Print \sum_{i = l}^{r - 1}{a_i}.
Constraints
* 1 \leq N, Q \leq 500,000
* 0 \leq a_i, x \leq 10^9
* 0 \leq p < N
* 0 \leq l_i < r_i \leq N
* All values in Input are integer.
Input
Input is given from Standard Input in the following format:
N Q
a_0 a_1 ... a_{N - 1}
\textrm{Query}_0
\textrm{Query}_1
:
\textrm{Query}_{Q - 1}
Output
For each query of the latter type, print the answer.
Example
Input
5 5
1 2 3 4 5
1 0 5
1 2 4
0 3 10
1 0 5
1 0 3
Output
15
7
25
6 | instruction | 0 | 100,083 | 5 | 200,166 |
"Correct Solution:
```
class fenwick_tree():
def __init__(self, n:int):
self.__n = n
self.__data = [0] * self.__n
def add(self, p:int, x:int):
assert (0 <= p) & (p < self.__n)
p+=1
while( p<= self.__n):
self.__data[p-1] += x
p += p & -p
def sum(self, l:int, r:int):
assert (0 <= l) & (l <= r) & (r <= self.__n)
return self.__sum_mod0(r) - self.__sum_mod0(l)
def __sum_mod0(self, r:int):
s = 0
while(r > 0):
s += self.__data[r-1]
r -= r & -r
return s
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
n,q = map(int,readline().split())
a = list(map(int,readline().split()))
query = list(map(int,read().split()))
ft = fenwick_tree(n)
ans = []
for i,ai in enumerate(a):
ft.add(i,ai)
i = 0
for _ in range(q):
if(query[i]==0):
p,x = query[i+1:i+3]
ft.add(p,x)
else:
l,r = query[i+1:i+3]
ans.append(ft.sum(l,r))
i += 3
print('\n'.join(map(str,ans)))
``` | output | 1 | 100,083 | 5 | 200,167 |
Provide a correct Python 3 solution for this coding contest problem.
You are given an array a_0, a_1, ..., a_{N-1} of length N. Process Q queries of the following types.
* `0 p x`: a_p \gets a_p + x
* `1 l r`: Print \sum_{i = l}^{r - 1}{a_i}.
Constraints
* 1 \leq N, Q \leq 500,000
* 0 \leq a_i, x \leq 10^9
* 0 \leq p < N
* 0 \leq l_i < r_i \leq N
* All values in Input are integer.
Input
Input is given from Standard Input in the following format:
N Q
a_0 a_1 ... a_{N - 1}
\textrm{Query}_0
\textrm{Query}_1
:
\textrm{Query}_{Q - 1}
Output
For each query of the latter type, print the answer.
Example
Input
5 5
1 2 3 4 5
1 0 5
1 2 4
0 3 10
1 0 5
1 0 3
Output
15
7
25
6 | instruction | 0 | 100,084 | 5 | 200,168 |
"Correct Solution:
```
n, q = map(int, input().split())
BIT = [0] * (n + 1)
def add(i, x):
while i <= n:
BIT[i] += x
i += i & -i
def query(i):
s = 0
while i > 0:
s += BIT[i]
i -= i & -i
return s
a = list(map(int, input().split()))
for i in range(n):
add(i + 1, a[i])
for i in range(q):
x, y, z = map(int, input().split())
if x == 0:
add(y + 1, z)
else:
print(query(z) - query(y))
``` | output | 1 | 100,084 | 5 | 200,169 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array a_0, a_1, ..., a_{N-1} of length N. Process Q queries of the following types.
* `0 p x`: a_p \gets a_p + x
* `1 l r`: Print \sum_{i = l}^{r - 1}{a_i}.
Constraints
* 1 \leq N, Q \leq 500,000
* 0 \leq a_i, x \leq 10^9
* 0 \leq p < N
* 0 \leq l_i < r_i \leq N
* All values in Input are integer.
Input
Input is given from Standard Input in the following format:
N Q
a_0 a_1 ... a_{N - 1}
\textrm{Query}_0
\textrm{Query}_1
:
\textrm{Query}_{Q - 1}
Output
For each query of the latter type, print the answer.
Example
Input
5 5
1 2 3 4 5
1 0 5
1 2 4
0 3 10
1 0 5
1 0 3
Output
15
7
25
6
Submitted Solution:
```
class BinaryIndexedTree:
# a[i] = [0] * n
def __init__(self, n):
self.size = n
self.data = [0] * (n+1)
# return sum(a[0:i])
def cumulative_sum(self, i):
ans = 0
while i > 0:
ans += self.data[i]
i -= i & -i
return ans
# a[i] += x
def add(self, i, x):
i += 1
while i <= self.size:
self.data[i] += x
i += i & -i
def main():
from sys import stdin
input = stdin.buffer.readline
n, q = map(int, input().split())
a = list(map(int, input().split()))
bit = BinaryIndexedTree(n)
for i, ai in enumerate(a):
bit.add(i, ai)
ans = []
for _ in range(q):
typ, i, j = map(int, input().split())
if typ == 0:
bit.add(i, j)
else:
ans.append(bit.cumulative_sum(j) - bit.cumulative_sum(i))
for i in ans:
print(i)
main()
``` | instruction | 0 | 100,088 | 5 | 200,176 |
Yes | output | 1 | 100,088 | 5 | 200,177 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array a_0, a_1, ..., a_{N-1} of length N. Process Q queries of the following types.
* `0 p x`: a_p \gets a_p + x
* `1 l r`: Print \sum_{i = l}^{r - 1}{a_i}.
Constraints
* 1 \leq N, Q \leq 500,000
* 0 \leq a_i, x \leq 10^9
* 0 \leq p < N
* 0 \leq l_i < r_i \leq N
* All values in Input are integer.
Input
Input is given from Standard Input in the following format:
N Q
a_0 a_1 ... a_{N - 1}
\textrm{Query}_0
\textrm{Query}_1
:
\textrm{Query}_{Q - 1}
Output
For each query of the latter type, print the answer.
Example
Input
5 5
1 2 3 4 5
1 0 5
1 2 4
0 3 10
1 0 5
1 0 3
Output
15
7
25
6
Submitted Solution:
```
n, q = list(map(lambda x: int(x), input().split()))
list_a = list(map(lambda x: int(x), input().split()))
# element of ith index is the sum of subarray: list_a[:i+1]
current_sum = 0
sum_list_a = []
for ele in list_a:
# print(ele, current_sum)
current_sum += ele
sum_list_a.append(current_sum)
for _ in range(q):
i, x, y = list(map(lambda x: int(x), input().split()))
if i == 0:
for i in range(x, len(x)):
sum_list_a[i] += y
continue
if (x == 0):
print(sum_list_a[y-1])
continue
print(sum_list_a[y-1] - sum_list_a[x-1])
``` | instruction | 0 | 100,089 | 5 | 200,178 |
No | output | 1 | 100,089 | 5 | 200,179 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array a_0, a_1, ..., a_{N-1} of length N. Process Q queries of the following types.
* `0 p x`: a_p \gets a_p + x
* `1 l r`: Print \sum_{i = l}^{r - 1}{a_i}.
Constraints
* 1 \leq N, Q \leq 500,000
* 0 \leq a_i, x \leq 10^9
* 0 \leq p < N
* 0 \leq l_i < r_i \leq N
* All values in Input are integer.
Input
Input is given from Standard Input in the following format:
N Q
a_0 a_1 ... a_{N - 1}
\textrm{Query}_0
\textrm{Query}_1
:
\textrm{Query}_{Q - 1}
Output
For each query of the latter type, print the answer.
Example
Input
5 5
1 2 3 4 5
1 0 5
1 2 4
0 3 10
1 0 5
1 0 3
Output
15
7
25
6
Submitted Solution:
```
import sys
class Bit:
def __init__(self, n):
self.size = n
self.tree = [0] * (n + 1)
def sum(self, i):
s = 0
while i > 0:
s += self.tree[i]
i -= i & -i
return s
def add(self, i, x):
while i <= self.size:
self.tree[i] += x
i += i & -i
def main():
n, q = map(int, sys.stdin.buffer.readline().split())
bit = Bit(n+1)
a = list(map(int, sys.stdin.buffer.readline().split()))
for i in range(n):
bit.add(i+1, a[i])
for x in sys.stdin.buffer.readlines():
q, p, x = map(int, x.split())
if q:
print(bit.sum(x) - bit.sum(p))
else:
bit.add(p, x)
if __name__ == "__main__":
main()
``` | instruction | 0 | 100,090 | 5 | 200,180 |
No | output | 1 | 100,090 | 5 | 200,181 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array a_0, a_1, ..., a_{N-1} of length N. Process Q queries of the following types.
* `0 p x`: a_p \gets a_p + x
* `1 l r`: Print \sum_{i = l}^{r - 1}{a_i}.
Constraints
* 1 \leq N, Q \leq 500,000
* 0 \leq a_i, x \leq 10^9
* 0 \leq p < N
* 0 \leq l_i < r_i \leq N
* All values in Input are integer.
Input
Input is given from Standard Input in the following format:
N Q
a_0 a_1 ... a_{N - 1}
\textrm{Query}_0
\textrm{Query}_1
:
\textrm{Query}_{Q - 1}
Output
For each query of the latter type, print the answer.
Example
Input
5 5
1 2 3 4 5
1 0 5
1 2 4
0 3 10
1 0 5
1 0 3
Output
15
7
25
6
Submitted Solution:
```
class binaryindexedtree():
def __init__(self,n):
self.n=n
self.tree=[0]*n
def add(self,a,w):
x=a
while x<=self.n:
self.tree[x-1]+=w
x+=x&(-x)
def sums(self,a):
x=a
S=0
while x!=0:
S+=self.tree[x-1]
x-=x&(-x)
return S
n,q=map(int,input().split())
a=list(map(int,input().split()))
bit=binaryindexedtree(n)
for i,x in enumerate(a,1):
bit.add(i,x)
ans=[]
for _ in range(q):
x,y,z=map(int,input().split())
if x:ans+=[bit.sums(z)-bit.sums(y)]
else:bit.add(y,z)
print(*ans,sep='\n')
``` | instruction | 0 | 100,091 | 5 | 200,182 |
No | output | 1 | 100,091 | 5 | 200,183 |
Provide a correct Python 3 solution for this coding contest problem.
Give a pair of integers (A, B) such that A^5-B^5 = X. It is guaranteed that there exists such a pair for the given integer X.
Constraints
* 1 \leq X \leq 10^9
* X is an integer.
* There exists a pair of integers (A, B) satisfying the condition in Problem Statement.
Input
Input is given from Standard Input in the following format:
X
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Examples
Input
33
Output
2 -1
Input
1
Output
0 -1 | instruction | 0 | 100,093 | 5 | 200,186 |
"Correct Solution:
```
x=int(input())
for i in range(120):
for j in range(-62,i):
if i**5-j**5==x:print(i,j);exit()
``` | output | 1 | 100,093 | 5 | 200,187 |
Provide a correct Python 3 solution for this coding contest problem.
Give a pair of integers (A, B) such that A^5-B^5 = X. It is guaranteed that there exists such a pair for the given integer X.
Constraints
* 1 \leq X \leq 10^9
* X is an integer.
* There exists a pair of integers (A, B) satisfying the condition in Problem Statement.
Input
Input is given from Standard Input in the following format:
X
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Examples
Input
33
Output
2 -1
Input
1
Output
0 -1 | instruction | 0 | 100,094 | 5 | 200,188 |
"Correct Solution:
```
x=int(input())
for a in range(201):
for b in range(-200,201):
if a**5-b**5==x:
print(a,b)
exit()
``` | output | 1 | 100,094 | 5 | 200,189 |
Provide a correct Python 3 solution for this coding contest problem.
Give a pair of integers (A, B) such that A^5-B^5 = X. It is guaranteed that there exists such a pair for the given integer X.
Constraints
* 1 \leq X \leq 10^9
* X is an integer.
* There exists a pair of integers (A, B) satisfying the condition in Problem Statement.
Input
Input is given from Standard Input in the following format:
X
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Examples
Input
33
Output
2 -1
Input
1
Output
0 -1 | instruction | 0 | 100,095 | 5 | 200,190 |
"Correct Solution:
```
A= int(input())
for i in range(-119,119):
for j in range(-119,119):
if i**5-j**5 == A:
print(i,j)
exit()
``` | output | 1 | 100,095 | 5 | 200,191 |
Provide a correct Python 3 solution for this coding contest problem.
Give a pair of integers (A, B) such that A^5-B^5 = X. It is guaranteed that there exists such a pair for the given integer X.
Constraints
* 1 \leq X \leq 10^9
* X is an integer.
* There exists a pair of integers (A, B) satisfying the condition in Problem Statement.
Input
Input is given from Standard Input in the following format:
X
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Examples
Input
33
Output
2 -1
Input
1
Output
0 -1 | instruction | 0 | 100,096 | 5 | 200,192 |
"Correct Solution:
```
x=int(input())
for a in range(120):
for b in range(-120,a):
if a**5 - b**5 == x:
print(a,b)
exit()
``` | output | 1 | 100,096 | 5 | 200,193 |
Provide a correct Python 3 solution for this coding contest problem.
Give a pair of integers (A, B) such that A^5-B^5 = X. It is guaranteed that there exists such a pair for the given integer X.
Constraints
* 1 \leq X \leq 10^9
* X is an integer.
* There exists a pair of integers (A, B) satisfying the condition in Problem Statement.
Input
Input is given from Standard Input in the following format:
X
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Examples
Input
33
Output
2 -1
Input
1
Output
0 -1 | instruction | 0 | 100,097 | 5 | 200,194 |
"Correct Solution:
```
x=int(input())
for i in range(-400,400):
for j in range(-400,400):
if i**5-j**5==x:
print(i,j)
exit()
``` | output | 1 | 100,097 | 5 | 200,195 |
Provide a correct Python 3 solution for this coding contest problem.
Give a pair of integers (A, B) such that A^5-B^5 = X. It is guaranteed that there exists such a pair for the given integer X.
Constraints
* 1 \leq X \leq 10^9
* X is an integer.
* There exists a pair of integers (A, B) satisfying the condition in Problem Statement.
Input
Input is given from Standard Input in the following format:
X
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Examples
Input
33
Output
2 -1
Input
1
Output
0 -1 | instruction | 0 | 100,098 | 5 | 200,196 |
"Correct Solution:
```
x=int(input())
for i in range(120):
for j in range(-54,i):
if i**5-j**5==x:print(i,j);exit()
``` | output | 1 | 100,098 | 5 | 200,197 |
Provide a correct Python 3 solution for this coding contest problem.
Give a pair of integers (A, B) such that A^5-B^5 = X. It is guaranteed that there exists such a pair for the given integer X.
Constraints
* 1 \leq X \leq 10^9
* X is an integer.
* There exists a pair of integers (A, B) satisfying the condition in Problem Statement.
Input
Input is given from Standard Input in the following format:
X
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Examples
Input
33
Output
2 -1
Input
1
Output
0 -1 | instruction | 0 | 100,099 | 5 | 200,198 |
"Correct Solution:
```
x = int(input())
for i in range(238):
a = i-118
for j in range(238):
b = j-119
if a**5-b**5==x:
print(a, b)
exit()
``` | output | 1 | 100,099 | 5 | 200,199 |
Provide a correct Python 3 solution for this coding contest problem.
Give a pair of integers (A, B) such that A^5-B^5 = X. It is guaranteed that there exists such a pair for the given integer X.
Constraints
* 1 \leq X \leq 10^9
* X is an integer.
* There exists a pair of integers (A, B) satisfying the condition in Problem Statement.
Input
Input is given from Standard Input in the following format:
X
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Examples
Input
33
Output
2 -1
Input
1
Output
0 -1 | instruction | 0 | 100,100 | 5 | 200,200 |
"Correct Solution:
```
x = int(input())
for i in range(-119, 120):
for j in range(-119, 120):
if i**5 - j**5 == x:
print(i,j)
exit()
``` | output | 1 | 100,100 | 5 | 200,201 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Give a pair of integers (A, B) such that A^5-B^5 = X. It is guaranteed that there exists such a pair for the given integer X.
Constraints
* 1 \leq X \leq 10^9
* X is an integer.
* There exists a pair of integers (A, B) satisfying the condition in Problem Statement.
Input
Input is given from Standard Input in the following format:
X
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Examples
Input
33
Output
2 -1
Input
1
Output
0 -1
Submitted Solution:
```
X = int(input())
for A in range(-200,200):
for B in range(-200,200):
if A**5-B**5 == X:
print(A,B)
exit()
``` | instruction | 0 | 100,101 | 5 | 200,202 |
Yes | output | 1 | 100,101 | 5 | 200,203 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Give a pair of integers (A, B) such that A^5-B^5 = X. It is guaranteed that there exists such a pair for the given integer X.
Constraints
* 1 \leq X \leq 10^9
* X is an integer.
* There exists a pair of integers (A, B) satisfying the condition in Problem Statement.
Input
Input is given from Standard Input in the following format:
X
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Examples
Input
33
Output
2 -1
Input
1
Output
0 -1
Submitted Solution:
```
X = int(input())
for a in range(-201,201):
for b in range(-201,201):
if a**5 - b**5 == X:
print(a,b)
quit()
``` | instruction | 0 | 100,102 | 5 | 200,204 |
Yes | output | 1 | 100,102 | 5 | 200,205 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Give a pair of integers (A, B) such that A^5-B^5 = X. It is guaranteed that there exists such a pair for the given integer X.
Constraints
* 1 \leq X \leq 10^9
* X is an integer.
* There exists a pair of integers (A, B) satisfying the condition in Problem Statement.
Input
Input is given from Standard Input in the following format:
X
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Examples
Input
33
Output
2 -1
Input
1
Output
0 -1
Submitted Solution:
```
x=int(input())
[print(i,j)+exit()for i in range(200)for j in range(-i,i)if i**5-j**5==x]
``` | instruction | 0 | 100,103 | 5 | 200,206 |
Yes | output | 1 | 100,103 | 5 | 200,207 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Give a pair of integers (A, B) such that A^5-B^5 = X. It is guaranteed that there exists such a pair for the given integer X.
Constraints
* 1 \leq X \leq 10^9
* X is an integer.
* There exists a pair of integers (A, B) satisfying the condition in Problem Statement.
Input
Input is given from Standard Input in the following format:
X
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Examples
Input
33
Output
2 -1
Input
1
Output
0 -1
Submitted Solution:
```
X=int(input())
for a in range(-118,120):
for b in range(-119,119):
if X==a**5-b**5:
print(a,b)
exit()
``` | instruction | 0 | 100,104 | 5 | 200,208 |
Yes | output | 1 | 100,104 | 5 | 200,209 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Give a pair of integers (A, B) such that A^5-B^5 = X. It is guaranteed that there exists such a pair for the given integer X.
Constraints
* 1 \leq X \leq 10^9
* X is an integer.
* There exists a pair of integers (A, B) satisfying the condition in Problem Statement.
Input
Input is given from Standard Input in the following format:
X
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Examples
Input
33
Output
2 -1
Input
1
Output
0 -1
Submitted Solution:
```
x=int(input())
for a in range(-100,100):
for b in range(-100,100):
if (a**5-b**5)==x:
a_ans=a
b_ans=b
break
print(a_ans,b_ans)
``` | instruction | 0 | 100,105 | 5 | 200,210 |
No | output | 1 | 100,105 | 5 | 200,211 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Give a pair of integers (A, B) such that A^5-B^5 = X. It is guaranteed that there exists such a pair for the given integer X.
Constraints
* 1 \leq X \leq 10^9
* X is an integer.
* There exists a pair of integers (A, B) satisfying the condition in Problem Statement.
Input
Input is given from Standard Input in the following format:
X
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Examples
Input
33
Output
2 -1
Input
1
Output
0 -1
Submitted Solution:
```
x = int(input())
for i in range(10**5):
if i**5 >= x:
up = i
down = i-1
break
# print(up, down)
for i in range(10**5):
if down**5 + i**5 == x:
print(down, -i)
exit()
if down**5 + i**5 > x:
break
for i in range(10**5):
if up**5 - i**5 == x:
print(up, i)
exit()
if up**5 - i**5 < x:
break
``` | instruction | 0 | 100,107 | 5 | 200,214 |
No | output | 1 | 100,107 | 5 | 200,215 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Give a pair of integers (A, B) such that A^5-B^5 = X. It is guaranteed that there exists such a pair for the given integer X.
Constraints
* 1 \leq X \leq 10^9
* X is an integer.
* There exists a pair of integers (A, B) satisfying the condition in Problem Statement.
Input
Input is given from Standard Input in the following format:
X
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Output
Print A and B, with space in between. If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.
A B
Examples
Input
33
Output
2 -1
Input
1
Output
0 -1
Submitted Solution:
```
import numpy
x = int(input())
max = 10**9+1
flag = False
for i in range(1,max):
if x%i == 0:
for j in range(0,i+1):
if (numpy.power(i-j,5,dtype=numpy.int64) - numpy.power(j,5,dtype=numpy.int64)) == x:
print(str(i-j)+" "+str(j))
flag = True
break
if (numpy.power(i+j,5,dtype=numpy.int64) - numpy.power(-j,5,dtype=numpy.int64)) == x:
print(str(i-j)+" "+str(j))
flag = True
break
if flag:
break
``` | instruction | 0 | 100,108 | 5 | 200,216 |
No | output | 1 | 100,108 | 5 | 200,217 |
Provide a correct Python 3 solution for this coding contest problem.
Find the minimum prime number greater than or equal to X.
Constraints
* 2 \le X \le 10^5
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X
Output
Print the minimum prime number greater than or equal to X.
Examples
Input
20
Output
23
Input
2
Output
2
Input
99992
Output
100003 | instruction | 0 | 100,109 | 5 | 200,218 |
"Correct Solution:
```
x = int(input())
while True:
n = 2
while x % n != 0 and n <= x/2:
n += 1
if n < x/2:
x += 1
else:
print(x)
break
``` | output | 1 | 100,109 | 5 | 200,219 |
Provide a correct Python 3 solution for this coding contest problem.
Find the minimum prime number greater than or equal to X.
Constraints
* 2 \le X \le 10^5
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X
Output
Print the minimum prime number greater than or equal to X.
Examples
Input
20
Output
23
Input
2
Output
2
Input
99992
Output
100003 | instruction | 0 | 100,110 | 5 | 200,220 |
"Correct Solution:
```
import math
X=int(input())
while True:
for i in range(2,int(math.sqrt(X))+1):
if X%i==0:
X+=1
break
else:
print(X)
break
``` | output | 1 | 100,110 | 5 | 200,221 |
Provide a correct Python 3 solution for this coding contest problem.
Find the minimum prime number greater than or equal to X.
Constraints
* 2 \le X \le 10^5
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X
Output
Print the minimum prime number greater than or equal to X.
Examples
Input
20
Output
23
Input
2
Output
2
Input
99992
Output
100003 | instruction | 0 | 100,111 | 5 | 200,222 |
"Correct Solution:
```
X=int(input())
ans=True
while ans:
for i in range(2,X):
if X%i==0:
X+=1
break
else:
print(X)
ans=False
``` | output | 1 | 100,111 | 5 | 200,223 |
Provide a correct Python 3 solution for this coding contest problem.
Find the minimum prime number greater than or equal to X.
Constraints
* 2 \le X \le 10^5
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X
Output
Print the minimum prime number greater than or equal to X.
Examples
Input
20
Output
23
Input
2
Output
2
Input
99992
Output
100003 | instruction | 0 | 100,112 | 5 | 200,224 |
"Correct Solution:
```
x=int(input())
while any(x%i<1 for i in range(2,x)):
x+=1
print(x)
``` | output | 1 | 100,112 | 5 | 200,225 |
Provide a correct Python 3 solution for this coding contest problem.
Find the minimum prime number greater than or equal to X.
Constraints
* 2 \le X \le 10^5
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X
Output
Print the minimum prime number greater than or equal to X.
Examples
Input
20
Output
23
Input
2
Output
2
Input
99992
Output
100003 | instruction | 0 | 100,113 | 5 | 200,226 |
"Correct Solution:
```
x=int(input())
if x <4:
print(x);exit()
while 1:
for i in range(2,int(x**.5)+1):
if x%i:continue
break
else:print(x);exit()
x+=1
``` | output | 1 | 100,113 | 5 | 200,227 |
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