message stringlengths 2 44.5k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 42 109k | cluster float64 5 5 | __index_level_0__ int64 84 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let s(x) be sum of digits in decimal representation of positive integer x. Given two integers n and m, find some positive integers a and b such that
* s(a) ≥ n,
* s(b) ≥ n,
* s(a + b) ≤ m.
Input
The only line of input contain two integers n and m (1 ≤ n, m ≤ 1129).
Output
Print two lines, one for decimal representation of a and one for decimal representation of b. Both numbers must not contain leading zeros and must have length no more than 2230.
Examples
Input
6 5
Output
6
7
Input
8 16
Output
35
53
Note
In the first sample, we have n = 6 and m = 5. One valid solution is a = 6, b = 7. Indeed, we have s(a) = 6 ≥ n and s(b) = 7 ≥ n, and also s(a + b) = s(13) = 4 ≤ m.
Submitted Solution:
```
n,m=map(int,input().split())
s=int((min(n,m)//9)*'9'+(abs(n-m)+1)*'5')
print(s)
print(s)
``` | instruction | 0 | 16,843 | 5 | 33,686 |
No | output | 1 | 16,843 | 5 | 33,687 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An arithmetic progression is such a non-empty sequence of numbers where the difference between any two successive numbers is constant. This constant number is called common difference. For example, the sequence 3, 7, 11, 15 is an arithmetic progression. The definition implies that any sequences whose length equals 1 or 2 are arithmetic and all sequences whose length equals 0 are non-arithmetic.
You are given a sequence of different integers a1, a2, ..., an. You should either split it into two arithmetic progressions or find out that the operation is impossible to perform. Splitting assigns each member of the given sequence to one of two progressions, but the relative order of numbers does not change. Splitting is an inverse operation to merging.
Input
The first line contains a positive integer n (2 ≤ n ≤ 30000), n is the length of the given sequence. The second line contains elements of the given sequence a1, a2, ..., an ( - 108 ≤ ai ≤ 108). The elements of the progression are different integers.
Output
Print the required arithmetic progressions, one per line. The progressions can be positioned in any order. Each progression should contain at least one number. If there's no solution, then print "No solution" (without the quotes)in the only line of the input file. If there are several solutions, print any of them.
Examples
Input
6
4 1 2 7 3 10
Output
1 2 3
4 7 10
Input
5
1 2 3 -2 -7
Output
1 2 3
-2 -7
Note
In the second sample another solution is also possible (number three can be assigned to the second progression): 1, 2 and 3, -2, -7.
Submitted Solution:
```
n=int(input())
ar=list(map(int,input().split()))
if(n<2):
print("No solution")
quit()
if(n==2):
print(ar[0])
print(ar[1])
quit()
L,R=[],[]
def check(fir,dif):
global L,ar,R
cur=fir
lef=[]
rig=[]
for e in ar:
if(e==cur):
cur+=dif
rig.append(e)
else:
lef.append(e)
if(len(lef)==0):
return 0
dif=set()
for i in range(1,len(lef)):
dif.add(lef[i]-lef[i-1])
if(len(dif)<=1):
L=lef
R=rig
return 1
return 0
if(check(ar[0],ar[1]-ar[0])):
print(*L)
print(*R)
elif(check(ar[0],ar[2]-ar[0])):
print(*L)
print(*R)
elif(check(ar[1],ar[2]-ar[1])):
print(*L)
print(*R)
else:
print("No solution")
``` | instruction | 0 | 16,943 | 5 | 33,886 |
No | output | 1 | 16,943 | 5 | 33,887 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an integer x. Can you make x by summing up some number of 11, 111, 1111, 11111, …? (You can use any number among them any number of times).
For instance,
* 33=11+11+11
* 144=111+11+11+11
Input
The first line of input contains a single integer t (1 ≤ t ≤ 10000) — the number of testcases.
The first and only line of each testcase contains a single integer x (1 ≤ x ≤ 10^9) — the number you have to make.
Output
For each testcase, you should output a single string. If you can make x, output "YES" (without quotes). Otherwise, output "NO".
You can print each letter of "YES" and "NO" in any case (upper or lower).
Example
Input
3
33
144
69
Output
YES
YES
NO
Note
Ways to make 33 and 144 were presented in the statement. It can be proved that we can't present 69 this way.
Submitted Solution:
```
t = int(input())
for _ in range(t):
n = int(input())
if (n >= 111*(n%11)):
print("YES")
else:
print("NO")
``` | instruction | 0 | 17,038 | 5 | 34,076 |
Yes | output | 1 | 17,038 | 5 | 34,077 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an integer x. Can you make x by summing up some number of 11, 111, 1111, 11111, …? (You can use any number among them any number of times).
For instance,
* 33=11+11+11
* 144=111+11+11+11
Input
The first line of input contains a single integer t (1 ≤ t ≤ 10000) — the number of testcases.
The first and only line of each testcase contains a single integer x (1 ≤ x ≤ 10^9) — the number you have to make.
Output
For each testcase, you should output a single string. If you can make x, output "YES" (without quotes). Otherwise, output "NO".
You can print each letter of "YES" and "NO" in any case (upper or lower).
Example
Input
3
33
144
69
Output
YES
YES
NO
Note
Ways to make 33 and 144 were presented in the statement. It can be proved that we can't present 69 this way.
Submitted Solution:
```
tc=int(input())
for _ in range(tc):
n=int(input())
can=False
for i in range(20):
if (n%11==0): can=True
n-=111
if (n<0):
break
if (can): print("yes")
else: print("no")
``` | instruction | 0 | 17,039 | 5 | 34,078 |
Yes | output | 1 | 17,039 | 5 | 34,079 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an integer x. Can you make x by summing up some number of 11, 111, 1111, 11111, …? (You can use any number among them any number of times).
For instance,
* 33=11+11+11
* 144=111+11+11+11
Input
The first line of input contains a single integer t (1 ≤ t ≤ 10000) — the number of testcases.
The first and only line of each testcase contains a single integer x (1 ≤ x ≤ 10^9) — the number you have to make.
Output
For each testcase, you should output a single string. If you can make x, output "YES" (without quotes). Otherwise, output "NO".
You can print each letter of "YES" and "NO" in any case (upper or lower).
Example
Input
3
33
144
69
Output
YES
YES
NO
Note
Ways to make 33 and 144 were presented in the statement. It can be proved that we can't present 69 this way.
Submitted Solution:
```
for each in range(int(input())):
a = int(input())
if ((a % 11)*111) <= a:
print("YES")
else:
print("NO")
``` | instruction | 0 | 17,041 | 5 | 34,082 |
Yes | output | 1 | 17,041 | 5 | 34,083 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an integer x. Can you make x by summing up some number of 11, 111, 1111, 11111, …? (You can use any number among them any number of times).
For instance,
* 33=11+11+11
* 144=111+11+11+11
Input
The first line of input contains a single integer t (1 ≤ t ≤ 10000) — the number of testcases.
The first and only line of each testcase contains a single integer x (1 ≤ x ≤ 10^9) — the number you have to make.
Output
For each testcase, you should output a single string. If you can make x, output "YES" (without quotes). Otherwise, output "NO".
You can print each letter of "YES" and "NO" in any case (upper or lower).
Example
Input
3
33
144
69
Output
YES
YES
NO
Note
Ways to make 33 and 144 were presented in the statement. It can be proved that we can't present 69 this way.
Submitted Solution:
```
def B(x):
if x==0:
return 'NO'
arr=[11,111,1111,11111,111111,1111111,11111111,111111111,1111111111]
j=len(arr)-1
while j>=0 and x!=0:
if arr[j]/x>1:
j-=1
else:
x=x%arr[j]
if x==0:
return ('YES')
else:
return ('NO')
T=int(input())
while T>0:
x=int(input())
print(B(x))
T=T-1
``` | instruction | 0 | 17,043 | 5 | 34,086 |
No | output | 1 | 17,043 | 5 | 34,087 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an integer x. Can you make x by summing up some number of 11, 111, 1111, 11111, …? (You can use any number among them any number of times).
For instance,
* 33=11+11+11
* 144=111+11+11+11
Input
The first line of input contains a single integer t (1 ≤ t ≤ 10000) — the number of testcases.
The first and only line of each testcase contains a single integer x (1 ≤ x ≤ 10^9) — the number you have to make.
Output
For each testcase, you should output a single string. If you can make x, output "YES" (without quotes). Otherwise, output "NO".
You can print each letter of "YES" and "NO" in any case (upper or lower).
Example
Input
3
33
144
69
Output
YES
YES
NO
Note
Ways to make 33 and 144 were presented in the statement. It can be proved that we can't present 69 this way.
Submitted Solution:
```
for _ in range(int(input())):
n = int(input())
x = [11111111, 1111111, 111111, 11111, 1111, 111, 11]
ans = 'NO'
for i in x:
if n % i == 0:
ans = 'YES'
print(ans)
``` | instruction | 0 | 17,045 | 5 | 34,090 |
No | output | 1 | 17,045 | 5 | 34,091 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Greg has an array a = a1, a2, ..., an and m operations. Each operation looks as: li, ri, di, (1 ≤ li ≤ ri ≤ n). To apply operation i to the array means to increase all array elements with numbers li, li + 1, ..., ri by value di.
Greg wrote down k queries on a piece of paper. Each query has the following form: xi, yi, (1 ≤ xi ≤ yi ≤ m). That means that one should apply operations with numbers xi, xi + 1, ..., yi to the array.
Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.
Input
The first line contains integers n, m, k (1 ≤ n, m, k ≤ 105). The second line contains n integers: a1, a2, ..., an (0 ≤ ai ≤ 105) — the initial array.
Next m lines contain operations, the operation number i is written as three integers: li, ri, di, (1 ≤ li ≤ ri ≤ n), (0 ≤ di ≤ 105).
Next k lines contain the queries, the query number i is written as two integers: xi, yi, (1 ≤ xi ≤ yi ≤ m).
The numbers in the lines are separated by single spaces.
Output
On a single line print n integers a1, a2, ..., an — the array after executing all the queries. Separate the printed numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.
Examples
Input
3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3
Output
9 18 17
Input
1 1 1
1
1 1 1
1 1
Output
2
Input
4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3
Output
5 18 31 20
Submitted Solution:
```
def arr_inp(n):
if n == 1:
return [int(x) for x in stdin.readline().split()]
elif n == 2:
return [float(x) for x in stdin.readline().split()]
else:
return [str(x) for x in stdin.readline().split()]
def cum_m():
for l, r in k_a:
m_cum[l] += 1
m_cum[r + 1] -= 1
for i in range(2, m + 1):
m_cum[i] += m_cum[i - 1]
def cum_a():
i = 1
for l, r, d in m_a:
a_cum[l] += (d * m_cum[i])
a_cum[r + 1] -= (d * m_cum[i])
i += 1
for i in range(2, n + 1):
a_cum[i] += a_cum[i - 1]
def solve():
cum_m()
cum_a()
ans = [0] * n
for i in range(n):
ans[i] += a[i] + a_cum[i + 1]
return ans
from sys import stdin
from collections import *
n, m, k = arr_inp(1)
a, m_cum, a_cum = arr_inp(1), defaultdict(int), defaultdict(int)
m_a, k_a = [arr_inp(1) for i in range(m)], [arr_inp(1) for j in range(k)]
print(*solve())
``` | instruction | 0 | 17,103 | 5 | 34,206 |
Yes | output | 1 | 17,103 | 5 | 34,207 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Greg has an array a = a1, a2, ..., an and m operations. Each operation looks as: li, ri, di, (1 ≤ li ≤ ri ≤ n). To apply operation i to the array means to increase all array elements with numbers li, li + 1, ..., ri by value di.
Greg wrote down k queries on a piece of paper. Each query has the following form: xi, yi, (1 ≤ xi ≤ yi ≤ m). That means that one should apply operations with numbers xi, xi + 1, ..., yi to the array.
Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.
Input
The first line contains integers n, m, k (1 ≤ n, m, k ≤ 105). The second line contains n integers: a1, a2, ..., an (0 ≤ ai ≤ 105) — the initial array.
Next m lines contain operations, the operation number i is written as three integers: li, ri, di, (1 ≤ li ≤ ri ≤ n), (0 ≤ di ≤ 105).
Next k lines contain the queries, the query number i is written as two integers: xi, yi, (1 ≤ xi ≤ yi ≤ m).
The numbers in the lines are separated by single spaces.
Output
On a single line print n integers a1, a2, ..., an — the array after executing all the queries. Separate the printed numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.
Examples
Input
3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3
Output
9 18 17
Input
1 1 1
1
1 1 1
1 1
Output
2
Input
4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3
Output
5 18 31 20
Submitted Solution:
```
"""
Code of Ayush Tiwari
Codeforces: servermonk
Codechef: ayush572000
"""
import sys
input = sys.stdin.buffer.readline
def solution():
n,m,k=map(int,input().split())
a=list(map(int,input().split()))
op=[]
op_counter=[0]*(1000004)
dp=[0]*(1000004)
for _ in range(m):
l,r,d=map(int,input().split())
op.append([l,r,d])
for i in range(k):
x,y=map(int,input().split())
op_counter[x-1]+=1
op_counter[y]-=1
for i in range(1,len(op_counter)):
op_counter[i]+=op_counter[i-1]
for i in range(len(op)):
l=op[i][0]
r=op[i][1]
d=op[i][2]
dp[l-1]+=(op_counter[i]*d)
dp[r]-=(op_counter[i]*d)
for i in range(1,len(dp)):
dp[i]+=dp[i-1]
for i in range(n):
a[i]+=dp[i]
print(*a)
solution()
``` | instruction | 0 | 17,104 | 5 | 34,208 |
Yes | output | 1 | 17,104 | 5 | 34,209 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Greg has an array a = a1, a2, ..., an and m operations. Each operation looks as: li, ri, di, (1 ≤ li ≤ ri ≤ n). To apply operation i to the array means to increase all array elements with numbers li, li + 1, ..., ri by value di.
Greg wrote down k queries on a piece of paper. Each query has the following form: xi, yi, (1 ≤ xi ≤ yi ≤ m). That means that one should apply operations with numbers xi, xi + 1, ..., yi to the array.
Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.
Input
The first line contains integers n, m, k (1 ≤ n, m, k ≤ 105). The second line contains n integers: a1, a2, ..., an (0 ≤ ai ≤ 105) — the initial array.
Next m lines contain operations, the operation number i is written as three integers: li, ri, di, (1 ≤ li ≤ ri ≤ n), (0 ≤ di ≤ 105).
Next k lines contain the queries, the query number i is written as two integers: xi, yi, (1 ≤ xi ≤ yi ≤ m).
The numbers in the lines are separated by single spaces.
Output
On a single line print n integers a1, a2, ..., an — the array after executing all the queries. Separate the printed numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.
Examples
Input
3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3
Output
9 18 17
Input
1 1 1
1
1 1 1
1 1
Output
2
Input
4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3
Output
5 18 31 20
Submitted Solution:
```
#!/usr/bin/env python
from io import BytesIO, IOBase
import os
import sys
from collections import *
def solve():
n, m, q = li()
arr = li()
x = [0]*(m+1)
y = [0]*(n+1)
bd = [li() for _ in range(m)]
for _ in range(q):
a, b = li()
x[a-1] += 1
x[b] -= 1
s = 0
for i in range(m):
l, r, d = bd[i]
s += x[i]
y[l-1] += s*d
y[r] -= s*d
s = 0
for i in range(n):
s += y[i]
arr[i] += s
for i in arr:
prl(i)
def main():
# T = inp()
T = 1
for _ in range(T):
solve()
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
def input(): return sys.stdin.readline().rstrip("\r\n")
def li(): return list(map(int, sys.stdin.readline().split()))
def mp(): return map(int, sys.stdin.readline().split())
def inp(): return int(sys.stdin.readline())
def pr(n): return sys.stdout.write(str(n)+"\n")
def prl(n): return sys.stdout.write(str(n)+" ")
if __name__ == "__main__":
main()
``` | instruction | 0 | 17,105 | 5 | 34,210 |
Yes | output | 1 | 17,105 | 5 | 34,211 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Greg has an array a = a1, a2, ..., an and m operations. Each operation looks as: li, ri, di, (1 ≤ li ≤ ri ≤ n). To apply operation i to the array means to increase all array elements with numbers li, li + 1, ..., ri by value di.
Greg wrote down k queries on a piece of paper. Each query has the following form: xi, yi, (1 ≤ xi ≤ yi ≤ m). That means that one should apply operations with numbers xi, xi + 1, ..., yi to the array.
Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.
Input
The first line contains integers n, m, k (1 ≤ n, m, k ≤ 105). The second line contains n integers: a1, a2, ..., an (0 ≤ ai ≤ 105) — the initial array.
Next m lines contain operations, the operation number i is written as three integers: li, ri, di, (1 ≤ li ≤ ri ≤ n), (0 ≤ di ≤ 105).
Next k lines contain the queries, the query number i is written as two integers: xi, yi, (1 ≤ xi ≤ yi ≤ m).
The numbers in the lines are separated by single spaces.
Output
On a single line print n integers a1, a2, ..., an — the array after executing all the queries. Separate the printed numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.
Examples
Input
3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3
Output
9 18 17
Input
1 1 1
1
1 1 1
1 1
Output
2
Input
4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3
Output
5 18 31 20
Submitted Solution:
```
import sys
input=sys.stdin.readline
n,m,k=list(map(int,input().split()))
a=list(map(int,input().split()))
tmp=[[0]]
for i in range(m):
x=list(map(int,input().split()))
tmp.append(x)
#print(tmp)
cnt=[0]*(m+2)
for i in range(k):
x,y=map(int,input().split())
cnt[x]+=1
cnt[y+1]-=1
for i in range(1,m+2):
cnt[i]+=cnt[i-1]
#print(cnt)
ans=[0]*(n+2)
for i in range(1,m+1):
l,r,d=tmp[i][0],tmp[i][1],tmp[i][2]
x=d*cnt[i]
ans[l]+=x
ans[r+1]-=x
#print(1,ans)
for i in range(1,n+1):
ans[i]+=ans[i-1]
#print(2,ans)
for i in range(1,n+1):
ans[i]+=a[i-1]
print(*ans[1:n+1])
``` | instruction | 0 | 17,106 | 5 | 34,212 |
Yes | output | 1 | 17,106 | 5 | 34,213 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Greg has an array a = a1, a2, ..., an and m operations. Each operation looks as: li, ri, di, (1 ≤ li ≤ ri ≤ n). To apply operation i to the array means to increase all array elements with numbers li, li + 1, ..., ri by value di.
Greg wrote down k queries on a piece of paper. Each query has the following form: xi, yi, (1 ≤ xi ≤ yi ≤ m). That means that one should apply operations with numbers xi, xi + 1, ..., yi to the array.
Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.
Input
The first line contains integers n, m, k (1 ≤ n, m, k ≤ 105). The second line contains n integers: a1, a2, ..., an (0 ≤ ai ≤ 105) — the initial array.
Next m lines contain operations, the operation number i is written as three integers: li, ri, di, (1 ≤ li ≤ ri ≤ n), (0 ≤ di ≤ 105).
Next k lines contain the queries, the query number i is written as two integers: xi, yi, (1 ≤ xi ≤ yi ≤ m).
The numbers in the lines are separated by single spaces.
Output
On a single line print n integers a1, a2, ..., an — the array after executing all the queries. Separate the printed numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.
Examples
Input
3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3
Output
9 18 17
Input
1 1 1
1
1 1 1
1 1
Output
2
Input
4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3
Output
5 18 31 20
Submitted Solution:
```
start = input().split()
arr_len = int(start[0])
num_ops = int(start[1])
num_queries = int(start[2])
print("1")
source = input().split()
array = list(source)
array[0] = int(source[0])
for i in range(1, arr_len):
array[i] = int(source[i]) - int(source[i - 1])
#print(array)
print("1")
operations = []
for i in range(num_ops):
cur_op = input().split()
cur_op[0] = int(cur_op[0])
cur_op[1] = int(cur_op[1])
cur_op[2] = int(cur_op[2])
operations.append(cur_op)
queries = [0] * num_ops
print("1")
for i in range(num_queries):
cur_query = input().split()
# cur_query[0] = int(cur_query[0]) - 1
# cur_query[1] = int(cur_query[1])
queries[int(cur_query[0]) - 1] = queries[int(cur_query[0]) - 1] + 1
second_index = int(cur_query[1])
if second_index < num_ops:
queries[int(cur_query[1])] = queries[int(cur_query[1])] - 1
print("1")
for i in range(num_ops):
multiplier = queries[i]
cur_op = operations[i]
first_index = cur_op[0] - 1
second_index = cur_op[1]
d = cur_op[2]
array[first_index] = array[first_index] + d * multiplier
if second_index < arr_len:
array[second_index] = array[second_index] - d * multiplier
# for i in range(cur_query[0] - 1, cur_query[1]):
# cur_op = operations[i]
# first_index = cur_op[0] - 1
# second_index = cur_op[1]
# d = cur_op[2]
# array[first_index] = array[first_index] + d
# if second_index < arr_len:
# array[second_index] = array[second_index] - d
print("1")
for i in range(1, arr_len):
array[i] = array[i] + array[i - 1]
for i in range(arr_len):
print(array[i], end =" ")
``` | instruction | 0 | 17,107 | 5 | 34,214 |
No | output | 1 | 17,107 | 5 | 34,215 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Greg has an array a = a1, a2, ..., an and m operations. Each operation looks as: li, ri, di, (1 ≤ li ≤ ri ≤ n). To apply operation i to the array means to increase all array elements with numbers li, li + 1, ..., ri by value di.
Greg wrote down k queries on a piece of paper. Each query has the following form: xi, yi, (1 ≤ xi ≤ yi ≤ m). That means that one should apply operations with numbers xi, xi + 1, ..., yi to the array.
Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.
Input
The first line contains integers n, m, k (1 ≤ n, m, k ≤ 105). The second line contains n integers: a1, a2, ..., an (0 ≤ ai ≤ 105) — the initial array.
Next m lines contain operations, the operation number i is written as three integers: li, ri, di, (1 ≤ li ≤ ri ≤ n), (0 ≤ di ≤ 105).
Next k lines contain the queries, the query number i is written as two integers: xi, yi, (1 ≤ xi ≤ yi ≤ m).
The numbers in the lines are separated by single spaces.
Output
On a single line print n integers a1, a2, ..., an — the array after executing all the queries. Separate the printed numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.
Examples
Input
3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3
Output
9 18 17
Input
1 1 1
1
1 1 1
1 1
Output
2
Input
4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3
Output
5 18 31 20
Submitted Solution:
```
(n, m, k) = map(int, input().split(' '))
a = [0] + list(map(int, input().split(' ')))
l = []
r = []
d = []
flag = False
for i in range(m):
(li, ri, di) = map(int, input().split(' '))
l.append(li)
r.append(ri)
d.append(di)
try:
times = [0 for i in range(k)]
for i in range(k):
(x, y) = map(int, input().split(' '))
for j in range(x - 1, y):
times[j] += 1
for i in range(0, m):
for j in range(l[i], r[i] + 1):
a[j] += (times[i]*d[i])
except Exception as e:
print("oops")
flag = True
if not flag:
print(' '.join(map(str,a[1::])))
``` | instruction | 0 | 17,108 | 5 | 34,216 |
No | output | 1 | 17,108 | 5 | 34,217 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Greg has an array a = a1, a2, ..., an and m operations. Each operation looks as: li, ri, di, (1 ≤ li ≤ ri ≤ n). To apply operation i to the array means to increase all array elements with numbers li, li + 1, ..., ri by value di.
Greg wrote down k queries on a piece of paper. Each query has the following form: xi, yi, (1 ≤ xi ≤ yi ≤ m). That means that one should apply operations with numbers xi, xi + 1, ..., yi to the array.
Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.
Input
The first line contains integers n, m, k (1 ≤ n, m, k ≤ 105). The second line contains n integers: a1, a2, ..., an (0 ≤ ai ≤ 105) — the initial array.
Next m lines contain operations, the operation number i is written as three integers: li, ri, di, (1 ≤ li ≤ ri ≤ n), (0 ≤ di ≤ 105).
Next k lines contain the queries, the query number i is written as two integers: xi, yi, (1 ≤ xi ≤ yi ≤ m).
The numbers in the lines are separated by single spaces.
Output
On a single line print n integers a1, a2, ..., an — the array after executing all the queries. Separate the printed numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.
Examples
Input
3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3
Output
9 18 17
Input
1 1 1
1
1 1 1
1 1
Output
2
Input
4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3
Output
5 18 31 20
Submitted Solution:
```
n, m, k = input().split(" ")
A = input().split(" ")
arr = A[:int(n)]
operation = []
queries = []
for i in range(0, int(m)):
x_y_z = input().split(" ")
operation.append(tuple(x_y_z))
for i in range(0, int(k)):
x_y = input().split(" ")
queries.append(tuple(x_y))
v = 0
for i in range(0, int(k)):
if v >= int(m):
v = 0
left, right, value = operation[v]
v += 1
x, y = queries[i]
times = (int(y)-int(x))+1
for j in range(1, times+1):
l = int(left)
r = int(right)
while l <= r:
arr[l-1] = int(arr[l-1]) + int(value)
l += 1
print(*arr)
``` | instruction | 0 | 17,109 | 5 | 34,218 |
No | output | 1 | 17,109 | 5 | 34,219 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Greg has an array a = a1, a2, ..., an and m operations. Each operation looks as: li, ri, di, (1 ≤ li ≤ ri ≤ n). To apply operation i to the array means to increase all array elements with numbers li, li + 1, ..., ri by value di.
Greg wrote down k queries on a piece of paper. Each query has the following form: xi, yi, (1 ≤ xi ≤ yi ≤ m). That means that one should apply operations with numbers xi, xi + 1, ..., yi to the array.
Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.
Input
The first line contains integers n, m, k (1 ≤ n, m, k ≤ 105). The second line contains n integers: a1, a2, ..., an (0 ≤ ai ≤ 105) — the initial array.
Next m lines contain operations, the operation number i is written as three integers: li, ri, di, (1 ≤ li ≤ ri ≤ n), (0 ≤ di ≤ 105).
Next k lines contain the queries, the query number i is written as two integers: xi, yi, (1 ≤ xi ≤ yi ≤ m).
The numbers in the lines are separated by single spaces.
Output
On a single line print n integers a1, a2, ..., an — the array after executing all the queries. Separate the printed numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.
Examples
Input
3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3
Output
9 18 17
Input
1 1 1
1
1 1 1
1 1
Output
2
Input
4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3
Output
5 18 31 20
Submitted Solution:
```
from array import array
n,m,k = [int(x) for x in input().split(" ")]
b = []
c = []
a=array('i',[int(x) for x in input().split(" ")])
for i in range(m):
b.append([int(x) for x in input().split(" ")])
for i in range(k):
c.append([int(x) for x in input().split(" ")])
d=array('i',[0 for x in range(m)])
e=array('i',[0 for x in range(n)])
z=0
for i in c:
for j in range(i[0],i[1]+1):
d[j-1]=d[j-1]+1
for i in b:
for j in range(i[0],i[1]+1):
e[j-1]=e[j-1]+i[2]*d[z]
z=z+1
z=0
p=[]
for i in a:
print(i+a[z], end=" ")
z=z+1
``` | instruction | 0 | 17,110 | 5 | 34,220 |
No | output | 1 | 17,110 | 5 | 34,221 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Dima misbehaved during a math lesson a lot and the nasty teacher Mr. Pickles gave him the following problem as a punishment.
Find all integer solutions x (0 < x < 109) of the equation:
x = b·s(x)a + c,
where a, b, c are some predetermined constant values and function s(x) determines the sum of all digits in the decimal representation of number x.
The teacher gives this problem to Dima for each lesson. He changes only the parameters of the equation: a, b, c. Dima got sick of getting bad marks and he asks you to help him solve this challenging problem.
Input
The first line contains three space-separated integers: a, b, c (1 ≤ a ≤ 5; 1 ≤ b ≤ 10000; - 10000 ≤ c ≤ 10000).
Output
Print integer n — the number of the solutions that you've found. Next print n integers in the increasing order — the solutions of the given equation. Print only integer solutions that are larger than zero and strictly less than 109.
Examples
Input
3 2 8
Output
3
10 2008 13726
Input
1 2 -18
Output
0
Input
2 2 -1
Output
4
1 31 337 967
Submitted Solution:
```
#python3
import sys, threading, os.path
import collections, heapq, math,bisect
import string
from platform import python_version
import itertools
sys.setrecursionlimit(10**6)
threading.stack_size(2**27)
def scompute(x):
str1 = str(x)
sum = 0
for c in str1:
sum+=int(c)
return sum
def main():
if os.path.exists('input.txt'):
input = open('input.txt', 'r')
else:
input = sys.stdin
#--------------------------------INPUT---------------------------------
a, b, c = list(map(int, input.readline().split()))
lis = []
for i in range(1,100000):
lis.append((i,(b*pow(i,a))+c))
sol = []
for x,y in lis:
if y>0 and y < 1000000000 and scompute(y)==x:
sol.append(y)
#print(lis)
if len(lis)==0:
output = 0
else:
output = str(len(sol))
output += '\n'
output += ' '.join(map(str, sol))
#-------------------------------OUTPUT----------------------------------
if os.path.exists('output.txt'):
open('output.txt', 'w').writelines(str(output))
else:
sys.stdout.write(str(output))
if __name__ == '__main__':
main()
#threading.Thread(target=main).start()
``` | instruction | 0 | 17,181 | 5 | 34,362 |
Yes | output | 1 | 17,181 | 5 | 34,363 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Dima misbehaved during a math lesson a lot and the nasty teacher Mr. Pickles gave him the following problem as a punishment.
Find all integer solutions x (0 < x < 109) of the equation:
x = b·s(x)a + c,
where a, b, c are some predetermined constant values and function s(x) determines the sum of all digits in the decimal representation of number x.
The teacher gives this problem to Dima for each lesson. He changes only the parameters of the equation: a, b, c. Dima got sick of getting bad marks and he asks you to help him solve this challenging problem.
Input
The first line contains three space-separated integers: a, b, c (1 ≤ a ≤ 5; 1 ≤ b ≤ 10000; - 10000 ≤ c ≤ 10000).
Output
Print integer n — the number of the solutions that you've found. Next print n integers in the increasing order — the solutions of the given equation. Print only integer solutions that are larger than zero and strictly less than 109.
Examples
Input
3 2 8
Output
3
10 2008 13726
Input
1 2 -18
Output
0
Input
2 2 -1
Output
4
1 31 337 967
Submitted Solution:
```
a, b, c = [ int(x) for x in input().split() ]
roots = []
for i in range(1, 81 + 1) :
x = b * i**a + c
if x > 0 :
if x < 1000000000 :
t = x // 10; s = x % 10
while t > 0 :
s += t % 10; t //= 10
if s == i : roots.append(x)
else : break
print(len(roots))
for x in roots : print(x, end=' ')
print()
``` | instruction | 0 | 17,182 | 5 | 34,364 |
Yes | output | 1 | 17,182 | 5 | 34,365 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Dima misbehaved during a math lesson a lot and the nasty teacher Mr. Pickles gave him the following problem as a punishment.
Find all integer solutions x (0 < x < 109) of the equation:
x = b·s(x)a + c,
where a, b, c are some predetermined constant values and function s(x) determines the sum of all digits in the decimal representation of number x.
The teacher gives this problem to Dima for each lesson. He changes only the parameters of the equation: a, b, c. Dima got sick of getting bad marks and he asks you to help him solve this challenging problem.
Input
The first line contains three space-separated integers: a, b, c (1 ≤ a ≤ 5; 1 ≤ b ≤ 10000; - 10000 ≤ c ≤ 10000).
Output
Print integer n — the number of the solutions that you've found. Next print n integers in the increasing order — the solutions of the given equation. Print only integer solutions that are larger than zero and strictly less than 109.
Examples
Input
3 2 8
Output
3
10 2008 13726
Input
1 2 -18
Output
0
Input
2 2 -1
Output
4
1 31 337 967
Submitted Solution:
```
a,b,c=map(int,input().split())
L=[]
for i in range(1,82):
val=b*(i**a)+c
check=0
if val>0 and val<10**9:
s=str(val)
for j in s:
check+=int(j)
if check==i:
L.append(val)
if len(L)==0:
print(0)
else:
print(len(L))
print(*L)
``` | instruction | 0 | 17,183 | 5 | 34,366 |
Yes | output | 1 | 17,183 | 5 | 34,367 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Dima misbehaved during a math lesson a lot and the nasty teacher Mr. Pickles gave him the following problem as a punishment.
Find all integer solutions x (0 < x < 109) of the equation:
x = b·s(x)a + c,
where a, b, c are some predetermined constant values and function s(x) determines the sum of all digits in the decimal representation of number x.
The teacher gives this problem to Dima for each lesson. He changes only the parameters of the equation: a, b, c. Dima got sick of getting bad marks and he asks you to help him solve this challenging problem.
Input
The first line contains three space-separated integers: a, b, c (1 ≤ a ≤ 5; 1 ≤ b ≤ 10000; - 10000 ≤ c ≤ 10000).
Output
Print integer n — the number of the solutions that you've found. Next print n integers in the increasing order — the solutions of the given equation. Print only integer solutions that are larger than zero and strictly less than 109.
Examples
Input
3 2 8
Output
3
10 2008 13726
Input
1 2 -18
Output
0
Input
2 2 -1
Output
4
1 31 337 967
Submitted Solution:
```
def s(x):
res = 0
while x > 0:
res += x % 10
x //= 10
return res
a, b, c = map(int, input().split())
ans = []
for i in range(100):
x = b * (i**a) + c
if x < 0:
continue
if s(x) == i and 0 < x < 10**9:
ans.append(x);
ans.sort()
print(len(ans))
if len(ans) != 0:
print(*ans)
``` | instruction | 0 | 17,184 | 5 | 34,368 |
Yes | output | 1 | 17,184 | 5 | 34,369 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Dima misbehaved during a math lesson a lot and the nasty teacher Mr. Pickles gave him the following problem as a punishment.
Find all integer solutions x (0 < x < 109) of the equation:
x = b·s(x)a + c,
where a, b, c are some predetermined constant values and function s(x) determines the sum of all digits in the decimal representation of number x.
The teacher gives this problem to Dima for each lesson. He changes only the parameters of the equation: a, b, c. Dima got sick of getting bad marks and he asks you to help him solve this challenging problem.
Input
The first line contains three space-separated integers: a, b, c (1 ≤ a ≤ 5; 1 ≤ b ≤ 10000; - 10000 ≤ c ≤ 10000).
Output
Print integer n — the number of the solutions that you've found. Next print n integers in the increasing order — the solutions of the given equation. Print only integer solutions that are larger than zero and strictly less than 109.
Examples
Input
3 2 8
Output
3
10 2008 13726
Input
1 2 -18
Output
0
Input
2 2 -1
Output
4
1 31 337 967
Submitted Solution:
```
def sumDigit(n):
n=str(n)
answer=0
for i in n:
answer+=int(i)
return answer
s=input().strip().split()
a,b,c = int(s[0]),int(s[1]),int(s[2])
answer=list()
x = 0 if c<0 else c+1
flag=False
count=0
while x<10**9:
count+=1
if count>=10**5:
break
s = sumDigit(x)
s = s**a
if x == b*s+c:
answer.append(x)
flag=True
if flag:
x+=b
else:
x+=1
print(len(answer))
for i in answer:
print(i,end=' ')
``` | instruction | 0 | 17,185 | 5 | 34,370 |
No | output | 1 | 17,185 | 5 | 34,371 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Dima misbehaved during a math lesson a lot and the nasty teacher Mr. Pickles gave him the following problem as a punishment.
Find all integer solutions x (0 < x < 109) of the equation:
x = b·s(x)a + c,
where a, b, c are some predetermined constant values and function s(x) determines the sum of all digits in the decimal representation of number x.
The teacher gives this problem to Dima for each lesson. He changes only the parameters of the equation: a, b, c. Dima got sick of getting bad marks and he asks you to help him solve this challenging problem.
Input
The first line contains three space-separated integers: a, b, c (1 ≤ a ≤ 5; 1 ≤ b ≤ 10000; - 10000 ≤ c ≤ 10000).
Output
Print integer n — the number of the solutions that you've found. Next print n integers in the increasing order — the solutions of the given equation. Print only integer solutions that are larger than zero and strictly less than 109.
Examples
Input
3 2 8
Output
3
10 2008 13726
Input
1 2 -18
Output
0
Input
2 2 -1
Output
4
1 31 337 967
Submitted Solution:
```
a,b,c=map(int,input().split())
ans=[]
c0=0
if(b+c<0):
print(0)
else:
for i in range(1,74):
val=(b*(pow(i,a)))+c
st=str(val)
c1=0
for j in st:
c1+=int(j)
if(c1==i):
ans.append(val)
c0+=1
print(c0)
print(*ans)
``` | instruction | 0 | 17,186 | 5 | 34,372 |
No | output | 1 | 17,186 | 5 | 34,373 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Dima misbehaved during a math lesson a lot and the nasty teacher Mr. Pickles gave him the following problem as a punishment.
Find all integer solutions x (0 < x < 109) of the equation:
x = b·s(x)a + c,
where a, b, c are some predetermined constant values and function s(x) determines the sum of all digits in the decimal representation of number x.
The teacher gives this problem to Dima for each lesson. He changes only the parameters of the equation: a, b, c. Dima got sick of getting bad marks and he asks you to help him solve this challenging problem.
Input
The first line contains three space-separated integers: a, b, c (1 ≤ a ≤ 5; 1 ≤ b ≤ 10000; - 10000 ≤ c ≤ 10000).
Output
Print integer n — the number of the solutions that you've found. Next print n integers in the increasing order — the solutions of the given equation. Print only integer solutions that are larger than zero and strictly less than 109.
Examples
Input
3 2 8
Output
3
10 2008 13726
Input
1 2 -18
Output
0
Input
2 2 -1
Output
4
1 31 337 967
Submitted Solution:
```
import math
def lhs(x):
if x<=0:
return 0
string = str(x)
add = 0
for i in range(len(string)):
add+=int(string[i])
return add
def main():
a , b, c = map(int,input().split())
ans = []
for i in range(1,82):
x = b*(math.pow(i,a))+c
# print(x)
x1 = lhs(int(x))
if x1==i and x1>0 and x1<1000000000:
ans.append(int(x))
print(len(ans))
for x in ans:
print(x,end=' ')
main()
``` | instruction | 0 | 17,187 | 5 | 34,374 |
No | output | 1 | 17,187 | 5 | 34,375 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Dima misbehaved during a math lesson a lot and the nasty teacher Mr. Pickles gave him the following problem as a punishment.
Find all integer solutions x (0 < x < 109) of the equation:
x = b·s(x)a + c,
where a, b, c are some predetermined constant values and function s(x) determines the sum of all digits in the decimal representation of number x.
The teacher gives this problem to Dima for each lesson. He changes only the parameters of the equation: a, b, c. Dima got sick of getting bad marks and he asks you to help him solve this challenging problem.
Input
The first line contains three space-separated integers: a, b, c (1 ≤ a ≤ 5; 1 ≤ b ≤ 10000; - 10000 ≤ c ≤ 10000).
Output
Print integer n — the number of the solutions that you've found. Next print n integers in the increasing order — the solutions of the given equation. Print only integer solutions that are larger than zero and strictly less than 109.
Examples
Input
3 2 8
Output
3
10 2008 13726
Input
1 2 -18
Output
0
Input
2 2 -1
Output
4
1 31 337 967
Submitted Solution:
```
def sumDigit(n):
ans = 0
if n <= 0:
return ans
while n:
ans += n % 10
n //= 10
return ans
a, b, c = map(int, input().split())
ans = []
can = 82;
for i in range(1, 82):
temp = b * int(pow(i, a)) + c
if sumDigit(temp) == i:
ans.append(temp)
print(len(ans))
for it in ans:
print(it, end=' ')
``` | instruction | 0 | 17,188 | 5 | 34,376 |
No | output | 1 | 17,188 | 5 | 34,377 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's denote as <image> the number of bits set ('1' bits) in the binary representation of the non-negative integer x.
You are given multiple queries consisting of pairs of integers l and r. For each query, find the x, such that l ≤ x ≤ r, and <image> is maximum possible. If there are multiple such numbers find the smallest of them.
Input
The first line contains integer n — the number of queries (1 ≤ n ≤ 10000).
Each of the following n lines contain two integers li, ri — the arguments for the corresponding query (0 ≤ li ≤ ri ≤ 1018).
Output
For each query print the answer in a separate line.
Examples
Input
3
1 2
2 4
1 10
Output
1
3
7
Note
The binary representations of numbers from 1 to 10 are listed below:
110 = 12
210 = 102
310 = 112
410 = 1002
510 = 1012
610 = 1102
710 = 1112
810 = 10002
910 = 10012
1010 = 10102
Submitted Solution:
```
#!/usr/bin/env python
import os
import sys
from io import BytesIO, IOBase
#from bisect import bisect_left as bl #c++ lowerbound bl(array,element)
#from bisect import bisect_right as br #c++ upperbound br(array,element)
def main():
# sys.stdin = open('input.txt', 'r')
# sys.stdout = open('output.txt', 'w')
for _ in range(int(input())):
l,r=map(int,input().split(" "))
rlist=[int(x) for x in bin(r)[2:]]
llist=[int(x) for x in bin(l)[2:]]
# ans=l
# for x in range(60):
# if 2**x-1>=l and 2**x-1<=r:
# ans=2**x-1
llist.reverse()
cnt=sum(llist)
for x in range(len(rlist)):
if x>=len(llist):
if l+2**x<=r:
l+=2**x
cnt+=1
elif llist[x]==0:
if l+2**x<=r:
l+=2**x
cnt+=1
print(l)
#-----------------------------BOSS-------------------------------------!
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
# endregion
if __name__ == "__main__":
main()
``` | instruction | 0 | 17,197 | 5 | 34,394 |
Yes | output | 1 | 17,197 | 5 | 34,395 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's denote as <image> the number of bits set ('1' bits) in the binary representation of the non-negative integer x.
You are given multiple queries consisting of pairs of integers l and r. For each query, find the x, such that l ≤ x ≤ r, and <image> is maximum possible. If there are multiple such numbers find the smallest of them.
Input
The first line contains integer n — the number of queries (1 ≤ n ≤ 10000).
Each of the following n lines contain two integers li, ri — the arguments for the corresponding query (0 ≤ li ≤ ri ≤ 1018).
Output
For each query print the answer in a separate line.
Examples
Input
3
1 2
2 4
1 10
Output
1
3
7
Note
The binary representations of numbers from 1 to 10 are listed below:
110 = 12
210 = 102
310 = 112
410 = 1002
510 = 1012
610 = 1102
710 = 1112
810 = 10002
910 = 10012
1010 = 10102
Submitted Solution:
```
import bisect
import collections
import copy
import functools
import heapq
import itertools
import math
import random
import re
import sys
import time
import string
from typing import List, Mapping
sys.setrecursionlimit(999999)
p=[0,1]
for _ in range(int(input())):
l,r = map(int,input().split())
while p[-1]<r:
p.append(p[-1]*2+1)
ans = 0
while l<r:
j = bisect.bisect_left(p,r+1)
j-=1
if l<=p[j]<=r:
ans+=p[j]
r=l-1
else:
ans+=p[j]+1
l=l-p[j]-1
r=r-p[j]-1
if l==r:
ans+= l
print(ans)
``` | instruction | 0 | 17,198 | 5 | 34,396 |
Yes | output | 1 | 17,198 | 5 | 34,397 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's denote as <image> the number of bits set ('1' bits) in the binary representation of the non-negative integer x.
You are given multiple queries consisting of pairs of integers l and r. For each query, find the x, such that l ≤ x ≤ r, and <image> is maximum possible. If there are multiple such numbers find the smallest of them.
Input
The first line contains integer n — the number of queries (1 ≤ n ≤ 10000).
Each of the following n lines contain two integers li, ri — the arguments for the corresponding query (0 ≤ li ≤ ri ≤ 1018).
Output
For each query print the answer in a separate line.
Examples
Input
3
1 2
2 4
1 10
Output
1
3
7
Note
The binary representations of numbers from 1 to 10 are listed below:
110 = 12
210 = 102
310 = 112
410 = 1002
510 = 1012
610 = 1102
710 = 1112
810 = 10002
910 = 10012
1010 = 10102
Submitted Solution:
```
def pops(k):
ans = 0
while k > 0:
if k & 1:
ans += 1
k >>= 1
return ans
for _ in range(int(input())):
l, r = list(map(int, input().split()))
i = 0
while l | (1 << i) <= r:
# print(l)
l |= (1 << i)
i += 1
print(l)
``` | instruction | 0 | 17,199 | 5 | 34,398 |
Yes | output | 1 | 17,199 | 5 | 34,399 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's denote as <image> the number of bits set ('1' bits) in the binary representation of the non-negative integer x.
You are given multiple queries consisting of pairs of integers l and r. For each query, find the x, such that l ≤ x ≤ r, and <image> is maximum possible. If there are multiple such numbers find the smallest of them.
Input
The first line contains integer n — the number of queries (1 ≤ n ≤ 10000).
Each of the following n lines contain two integers li, ri — the arguments for the corresponding query (0 ≤ li ≤ ri ≤ 1018).
Output
For each query print the answer in a separate line.
Examples
Input
3
1 2
2 4
1 10
Output
1
3
7
Note
The binary representations of numbers from 1 to 10 are listed below:
110 = 12
210 = 102
310 = 112
410 = 1002
510 = 1012
610 = 1102
710 = 1112
810 = 10002
910 = 10012
1010 = 10102
Submitted Solution:
```
for _ in range(int(input())):
m,n=map(int,input().split())
while(m|(m+1)<=n):
m|=(m+1)
print(m)
``` | instruction | 0 | 17,200 | 5 | 34,400 |
Yes | output | 1 | 17,200 | 5 | 34,401 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's denote as <image> the number of bits set ('1' bits) in the binary representation of the non-negative integer x.
You are given multiple queries consisting of pairs of integers l and r. For each query, find the x, such that l ≤ x ≤ r, and <image> is maximum possible. If there are multiple such numbers find the smallest of them.
Input
The first line contains integer n — the number of queries (1 ≤ n ≤ 10000).
Each of the following n lines contain two integers li, ri — the arguments for the corresponding query (0 ≤ li ≤ ri ≤ 1018).
Output
For each query print the answer in a separate line.
Examples
Input
3
1 2
2 4
1 10
Output
1
3
7
Note
The binary representations of numbers from 1 to 10 are listed below:
110 = 12
210 = 102
310 = 112
410 = 1002
510 = 1012
610 = 1102
710 = 1112
810 = 10002
910 = 10012
1010 = 10102
Submitted Solution:
```
from sys import stdin
from collections import defaultdict
import math
#stdin = open('input.txt', 'r')
def countSetBits(n):
count = 0
while (n):
n &= (n-1)
count+=1
return count
def brute(l,r):
num = 0
tim = 0
for i in range(l,r+1):
if(countSetBits(i)>tim):
tim = countSetBits(i)
num = i
return num
mod = 10**9+7
I = stdin.readline
t = int(I())
for _ in range(t):
l,r = map(int,I().split())
b1 = bin(l)[2:]
b2 = bin(r)[2:]
y = math.log(r+1,2)
#che = brute(l,r)
if(len(b2)>len(b1)):
if(y == int(y)):
ans = r
#print(r)
else:
x = len(b2)
ans = (2**(x-1)-1)
#print(2**(x-1)-1)
#brute(l,r)
else:
n = len(b1)
ans = []
flag = 0
if(y == int(y)):
#print(r)
ans = r
else:
for i in range(n):
if(flag == 0):
if(b1[i] == b2[i]):
ans.append(b1[i])
else:
if(b1[i] == "0" and b2[i] == "1"):
if(i != n-1):
ans.append("0")
flag = 1
else:
ans.append("1")
else:
ans.append("1")
s=("".join(ans))
ans = int(s,2)
if(countSetBits(r)>countSetBits(ans)): ans = r
print(ans)
#print(ans)
#print(int(s,2))
#print(int(s,2))
#brute(l,r)
``` | instruction | 0 | 17,201 | 5 | 34,402 |
No | output | 1 | 17,201 | 5 | 34,403 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's denote as <image> the number of bits set ('1' bits) in the binary representation of the non-negative integer x.
You are given multiple queries consisting of pairs of integers l and r. For each query, find the x, such that l ≤ x ≤ r, and <image> is maximum possible. If there are multiple such numbers find the smallest of them.
Input
The first line contains integer n — the number of queries (1 ≤ n ≤ 10000).
Each of the following n lines contain two integers li, ri — the arguments for the corresponding query (0 ≤ li ≤ ri ≤ 1018).
Output
For each query print the answer in a separate line.
Examples
Input
3
1 2
2 4
1 10
Output
1
3
7
Note
The binary representations of numbers from 1 to 10 are listed below:
110 = 12
210 = 102
310 = 112
410 = 1002
510 = 1012
610 = 1102
710 = 1112
810 = 10002
910 = 10012
1010 = 10102
Submitted Solution:
```
import sys
f = sys.stdin.readline
n = int(f().strip())
for i in range(n):
l, r = map(int, (f().strip().split()))
cur = 1
j = 1
# print('---',i+1,'---', l, r)
while cur<=r:
cur += (1<<j)
j += 1
if cur>>1 >= l:
print(cur>>1)
else:
if bin(l)[2:].count('1') == bin(r)[2:].count('1'):
print(l)
else:
print(l+1)
``` | instruction | 0 | 17,202 | 5 | 34,404 |
No | output | 1 | 17,202 | 5 | 34,405 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's denote as <image> the number of bits set ('1' bits) in the binary representation of the non-negative integer x.
You are given multiple queries consisting of pairs of integers l and r. For each query, find the x, such that l ≤ x ≤ r, and <image> is maximum possible. If there are multiple such numbers find the smallest of them.
Input
The first line contains integer n — the number of queries (1 ≤ n ≤ 10000).
Each of the following n lines contain two integers li, ri — the arguments for the corresponding query (0 ≤ li ≤ ri ≤ 1018).
Output
For each query print the answer in a separate line.
Examples
Input
3
1 2
2 4
1 10
Output
1
3
7
Note
The binary representations of numbers from 1 to 10 are listed below:
110 = 12
210 = 102
310 = 112
410 = 1002
510 = 1012
610 = 1102
710 = 1112
810 = 10002
910 = 10012
1010 = 10102
Submitted Solution:
```
for _ in range(int(input())):
l,r=map(int,input().split())
while(l|(l+1)<=r):
l|=(l+1)
print(1)
``` | instruction | 0 | 17,203 | 5 | 34,406 |
No | output | 1 | 17,203 | 5 | 34,407 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's denote as <image> the number of bits set ('1' bits) in the binary representation of the non-negative integer x.
You are given multiple queries consisting of pairs of integers l and r. For each query, find the x, such that l ≤ x ≤ r, and <image> is maximum possible. If there are multiple such numbers find the smallest of them.
Input
The first line contains integer n — the number of queries (1 ≤ n ≤ 10000).
Each of the following n lines contain two integers li, ri — the arguments for the corresponding query (0 ≤ li ≤ ri ≤ 1018).
Output
For each query print the answer in a separate line.
Examples
Input
3
1 2
2 4
1 10
Output
1
3
7
Note
The binary representations of numbers from 1 to 10 are listed below:
110 = 12
210 = 102
310 = 112
410 = 1002
510 = 1012
610 = 1102
710 = 1112
810 = 10002
910 = 10012
1010 = 10102
Submitted Solution:
```
# -*- coding: utf-8 -*-
"""
Created on Fri Sep 25 08:39:04 2020
@author: Dark Soul
"""
def BinToDec(s):
n=len(s)
ans=0
for i in range(n-1,-1,-1):
ans+=int(s[i])*(2**(n-i-1))
return ans
t=int(input(''))
cnt=0
for _ in range(t):
[l,r]=list(map(int,input().split()))
sl=bin(l)
sr=bin(r)
if l==r:
print(l)
elif len(sl)!=len(sr):
n=len(sr)-2
if r==(2**n-1):
print(r)
else:
print(-1+2**(n-1))
else:
sr=list(sr[2:])
n=len(sr)
k=n-1
for i in range(1,n):
if sr[i]=='1':
k=i
break
if k==n-1:
print(r)
cnt+=1
continue
ase=0
for j in range(k+1,n):
if sr[j]=='0':
ase=1
break
if ase==0:
print(r)
cnt+=1
else:
sr[k]='0'
for j in range(k+1,n):
if sr[j]=='0':
sr[j]='1'
x=BinToDec(sr)
if x<l:
x=l
print(x)
``` | instruction | 0 | 17,204 | 5 | 34,408 |
No | output | 1 | 17,204 | 5 | 34,409 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two positive integers a and b have a sum of s and a bitwise XOR of x. How many possible values are there for the ordered pair (a, b)?
Input
The first line of the input contains two integers s and x (2 ≤ s ≤ 1012, 0 ≤ x ≤ 1012), the sum and bitwise xor of the pair of positive integers, respectively.
Output
Print a single integer, the number of solutions to the given conditions. If no solutions exist, print 0.
Examples
Input
9 5
Output
4
Input
3 3
Output
2
Input
5 2
Output
0
Note
In the first sample, we have the following solutions: (2, 7), (3, 6), (6, 3), (7, 2).
In the second sample, the only solutions are (1, 2) and (2, 1).
Submitted Solution:
```
s, x = map(int, input().split())
print(((s-x)&(x+x+1)==0 and x <= s) * (2 ** bin(x).count('1') - 2 * (s == x)))
``` | instruction | 0 | 17,250 | 5 | 34,500 |
Yes | output | 1 | 17,250 | 5 | 34,501 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two positive integers a and b have a sum of s and a bitwise XOR of x. How many possible values are there for the ordered pair (a, b)?
Input
The first line of the input contains two integers s and x (2 ≤ s ≤ 1012, 0 ≤ x ≤ 1012), the sum and bitwise xor of the pair of positive integers, respectively.
Output
Print a single integer, the number of solutions to the given conditions. If no solutions exist, print 0.
Examples
Input
9 5
Output
4
Input
3 3
Output
2
Input
5 2
Output
0
Note
In the first sample, we have the following solutions: (2, 7), (3, 6), (6, 3), (7, 2).
In the second sample, the only solutions are (1, 2) and (2, 1).
Submitted Solution:
```
s, x = map(int, input().split())
print(0 if s < x or (s - x) & (2 * x + 1) else 2 ** bin(x).count('1') - 2 * (s == x))
``` | instruction | 0 | 17,251 | 5 | 34,502 |
Yes | output | 1 | 17,251 | 5 | 34,503 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two positive integers a and b have a sum of s and a bitwise XOR of x. How many possible values are there for the ordered pair (a, b)?
Input
The first line of the input contains two integers s and x (2 ≤ s ≤ 1012, 0 ≤ x ≤ 1012), the sum and bitwise xor of the pair of positive integers, respectively.
Output
Print a single integer, the number of solutions to the given conditions. If no solutions exist, print 0.
Examples
Input
9 5
Output
4
Input
3 3
Output
2
Input
5 2
Output
0
Note
In the first sample, we have the following solutions: (2, 7), (3, 6), (6, 3), (7, 2).
In the second sample, the only solutions are (1, 2) and (2, 1).
Submitted Solution:
```
s,x = map(int,input().split())
minus = 0
if(s == x):
minus = -2
if((s-x)%2==1 or s<x):
print(0)
else:
a = (s - x)>>1
p = 0
bsdk = False
while(a or x):
if(x&1 and (not a&1)):
p += 1
elif(x&1 and a&1):
bsdk = True
a>>=1
x>>=1
if(bsdk):
print(0)
else:
print(pow(2, p) + minus)
``` | instruction | 0 | 17,252 | 5 | 34,504 |
Yes | output | 1 | 17,252 | 5 | 34,505 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two positive integers a and b have a sum of s and a bitwise XOR of x. How many possible values are there for the ordered pair (a, b)?
Input
The first line of the input contains two integers s and x (2 ≤ s ≤ 1012, 0 ≤ x ≤ 1012), the sum and bitwise xor of the pair of positive integers, respectively.
Output
Print a single integer, the number of solutions to the given conditions. If no solutions exist, print 0.
Examples
Input
9 5
Output
4
Input
3 3
Output
2
Input
5 2
Output
0
Note
In the first sample, we have the following solutions: (2, 7), (3, 6), (6, 3), (7, 2).
In the second sample, the only solutions are (1, 2) and (2, 1).
Submitted Solution:
```
def func(S,X):
if S - X < 0 :
return 0
elif (S - X) % 2:
return 0
nd = (S - X) // 2
c = 0
while X:
if X & 1:
if nd & 1:
return 0
c += 1
X >>= 1
nd >>= 1
return 2 ** c
S,X = map(int,input().split())
print(func(S,X) - 2*(S == X))
``` | instruction | 0 | 17,253 | 5 | 34,506 |
Yes | output | 1 | 17,253 | 5 | 34,507 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two positive integers a and b have a sum of s and a bitwise XOR of x. How many possible values are there for the ordered pair (a, b)?
Input
The first line of the input contains two integers s and x (2 ≤ s ≤ 1012, 0 ≤ x ≤ 1012), the sum and bitwise xor of the pair of positive integers, respectively.
Output
Print a single integer, the number of solutions to the given conditions. If no solutions exist, print 0.
Examples
Input
9 5
Output
4
Input
3 3
Output
2
Input
5 2
Output
0
Note
In the first sample, we have the following solutions: (2, 7), (3, 6), (6, 3), (7, 2).
In the second sample, the only solutions are (1, 2) and (2, 1).
Submitted Solution:
```
import sys,os,io
from sys import stdin
from math import log, gcd, ceil
from collections import defaultdict, deque, Counter
from heapq import heappush, heappop
from bisect import bisect_left , bisect_right
import math
alphabets = list('abcdefghijklmnopqrstuvwxyz')
def isPrime(x):
for i in range(2,x):
if i*i>x:
break
if (x%i==0):
return False
return True
def ncr(n, r, p):
num = den = 1
for i in range(r):
num = (num * (n - i)) % p
den = (den * (i + 1)) % p
return (num * pow(den,
p - 2, p)) % p
def primeFactors(n):
l = []
while n % 2 == 0:
l.append(2)
n = n / 2
for i in range(3,int(math.sqrt(n))+1,2):
while n % i== 0:
l.append(int(i))
n = n / i
if n > 2:
l.append(n)
return list(set(l))
def power(x, y, p) :
res = 1
x = x % p
if (x == 0) :
return 0
while (y > 0) :
if ((y & 1) == 1) :
res = (res * x) % p
y = y >> 1 # y = y/2
x = (x * x) % p
return res
def SieveOfEratosthenes(n):
prime = [True for i in range(n+1)]
p = 2
while (p * p <= n):
if (prime[p] == True):
for i in range(p * p, n+1, p):
prime[i] = False
p += 1
return prime
def countdig(n):
c = 0
while (n > 0):
n //= 10
c += 1
return c
def si():
return input()
def prefix_sum(arr):
r = [0] * (len(arr)+1)
for i, el in enumerate(arr):
r[i+1] = r[i] + el
return r
def divideCeil(n,x):
if (n%x==0):
return n//x
return n//x+1
def ii():
return int(input())
def li():
return list(map(int,input().split()))
def ws(s): sys.stdout.write(s + '\n')
def wi(n): sys.stdout.write(str(n) + '\n')
def wia(a): sys.stdout.write(' '.join([str(x) for x in a]) + '\n')
def power_set(L):
cardinality=len(L)
n=2 ** cardinality
powerset = []
for i in range(n):
a=bin(i)[2:]
subset=[]
for j in range(len(a)):
if a[-j-1]=='1':
subset.append(L[j])
powerset.append(subset)
powerset_orderred=[]
for k in range(cardinality+1):
for w in powerset:
if len(w)==k:
powerset_orderred.append(w)
return powerset_orderred
def fastPlrintNextLines(a):
# 12
# 3
# 1
#like this
#a is list of strings
print('\n'.join(map(str,a)))
def sortByFirstAndSecond(A):
A = sorted(A,key = lambda x:x[0])
A = sorted(A,key = lambda x:x[1])
return list(A)
#__________________________TEMPLATE__________________OVER_______________________________________________________
if(os.path.exists('input.txt')):
sys.stdin = open("input.txt","r") ; sys.stdout = open("output.txt","w")
else:
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
def solve():
s,x = li()
andval = (s-x) /2
if andval!=int(andval):
print(0)
else:
w = andval
andval=int(andval)
andval = list(bin(andval)[2:]);x = list(bin(x)[2:])
s=andval[:]
if len(x)>len(s):
s = ['0']*(len(x)-len(s))+s
else:
x = ['0']*(len(s)-len(x))+x
andval=s[:]
ans=0
for i in range(len(s)-1,-1,-1):
if x[i]=='1':
ans+=1
# print(andval,x)
ans=2**ans
if w==0:
ans-=2
print(ans)
# s = list(bin(s)[1:]);x = list(bin(x)[1:])
# if len(x)>len(s):
# s = [0]*(len(x)-len(s))+s
# else:
# x = [0]*(len(s)-len(x))+x
# dp = [[0,0]]*(len(s))
# for i in range(len(s)-1,-1,-1):
# if s[i]=='0' and x[i]=='0':
# if i<len(s)-1:
# dp[i][0]=dp[i+1][0]+dp[i+1][1]
# else:
# dp[i][0]=1
# continue
# if s[i]=='1' and x[i]=='1':
t = 1
# t = int(input())
for _ in range(t):
solve()
``` | instruction | 0 | 17,254 | 5 | 34,508 |
No | output | 1 | 17,254 | 5 | 34,509 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two positive integers a and b have a sum of s and a bitwise XOR of x. How many possible values are there for the ordered pair (a, b)?
Input
The first line of the input contains two integers s and x (2 ≤ s ≤ 1012, 0 ≤ x ≤ 1012), the sum and bitwise xor of the pair of positive integers, respectively.
Output
Print a single integer, the number of solutions to the given conditions. If no solutions exist, print 0.
Examples
Input
9 5
Output
4
Input
3 3
Output
2
Input
5 2
Output
0
Note
In the first sample, we have the following solutions: (2, 7), (3, 6), (6, 3), (7, 2).
In the second sample, the only solutions are (1, 2) and (2, 1).
Submitted Solution:
```
s, x = map(int, input().split())
if (s - x) % 2 == 1:
print(0)
exit(0)
else:
c = bin(x)[2:]
k = 0
for i in range(len(c)):
if c[i] == "1":
k += 1
h = 0
if s == x:
h = 1
print(2 * (k - h))
``` | instruction | 0 | 17,255 | 5 | 34,510 |
No | output | 1 | 17,255 | 5 | 34,511 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two positive integers a and b have a sum of s and a bitwise XOR of x. How many possible values are there for the ordered pair (a, b)?
Input
The first line of the input contains two integers s and x (2 ≤ s ≤ 1012, 0 ≤ x ≤ 1012), the sum and bitwise xor of the pair of positive integers, respectively.
Output
Print a single integer, the number of solutions to the given conditions. If no solutions exist, print 0.
Examples
Input
9 5
Output
4
Input
3 3
Output
2
Input
5 2
Output
0
Note
In the first sample, we have the following solutions: (2, 7), (3, 6), (6, 3), (7, 2).
In the second sample, the only solutions are (1, 2) and (2, 1).
Submitted Solution:
```
def solutionB(s,x):
if s==x<=2:
return 0
# Convert x into binary
x_binary = bin(x)[2:]
s_binary = bin(s)[2:]
length_x = len(x_binary)
length_s = len(s_binary)
# Get n and m
n = x_binary.count('1')
m = length_x-n
# Find a solution
num1 = list(x_binary)
for i in range(length_s-len(num1)):
num1.insert(0,'0')
num2 = ['0' for c in range(len(num1))]
found = False
for i in range(length_s):
if not int(num1[i]):
num1[i] = '1'
num2[i] = '1'
sum_num = int(''.join(num1), 2) + int(''.join(num2), 2)
if sum_num > s:
num1[i] = '0'
num2[i] = '0'
elif sum_num == s:
found = True
break
# Return
if found:
if m != 0 and x!=274869346299:
return 2**n
else:
return 2**n-2
else:
return 0
if __name__ == '__main__':
#s,x = (274869346299, 274869346299)
s,x = input().split()
#print('SolutionA: ', solutionA(int(s),int(x)))
print(solutionB(int(s),int(x)))
``` | instruction | 0 | 17,256 | 5 | 34,512 |
No | output | 1 | 17,256 | 5 | 34,513 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two positive integers a and b have a sum of s and a bitwise XOR of x. How many possible values are there for the ordered pair (a, b)?
Input
The first line of the input contains two integers s and x (2 ≤ s ≤ 1012, 0 ≤ x ≤ 1012), the sum and bitwise xor of the pair of positive integers, respectively.
Output
Print a single integer, the number of solutions to the given conditions. If no solutions exist, print 0.
Examples
Input
9 5
Output
4
Input
3 3
Output
2
Input
5 2
Output
0
Note
In the first sample, we have the following solutions: (2, 7), (3, 6), (6, 3), (7, 2).
In the second sample, the only solutions are (1, 2) and (2, 1).
Submitted Solution:
```
def solutionA(s, x):
a = 0
b = s
counter = 0
while a <= s:
xor = a^b
if a==0 or b==0:
xor = 0
#print('a:%s b:%s xor:%s x:%s'%(a,b,xor,x))
if xor == x:
counter += 1
a += 1
b -= 1
return counter
if __name__ == '__main__':
print('\n',solutionA(5,2))
``` | instruction | 0 | 17,257 | 5 | 34,514 |
No | output | 1 | 17,257 | 5 | 34,515 |
Provide a correct Python 3 solution for this coding contest problem.
Given is an integer x that is greater than or equal to 0, and less than or equal to 1. Output 1 if x is equal to 0, or 0 if x is equal to 1.
Constraints
* 0 \leq x \leq 1
* x is an integer
Input
Input is given from Standard Input in the following format:
x
Output
Print 1 if x is equal to 0, or 0 if x is equal to 1.
Examples
Input
1
Output
0
Input
0
Output
1 | instruction | 0 | 17,440 | 5 | 34,880 |
"Correct Solution:
```
ans = [1, 0]
print(ans[int(input())])
``` | output | 1 | 17,440 | 5 | 34,881 |
Provide a correct Python 3 solution for this coding contest problem.
Given is an integer x that is greater than or equal to 0, and less than or equal to 1. Output 1 if x is equal to 0, or 0 if x is equal to 1.
Constraints
* 0 \leq x \leq 1
* x is an integer
Input
Input is given from Standard Input in the following format:
x
Output
Print 1 if x is equal to 0, or 0 if x is equal to 1.
Examples
Input
1
Output
0
Input
0
Output
1 | instruction | 0 | 17,441 | 5 | 34,882 |
"Correct Solution:
```
x=int(input())
print(['1','0'][x==1])
``` | output | 1 | 17,441 | 5 | 34,883 |
Provide a correct Python 3 solution for this coding contest problem.
Given is an integer x that is greater than or equal to 0, and less than or equal to 1. Output 1 if x is equal to 0, or 0 if x is equal to 1.
Constraints
* 0 \leq x \leq 1
* x is an integer
Input
Input is given from Standard Input in the following format:
x
Output
Print 1 if x is equal to 0, or 0 if x is equal to 1.
Examples
Input
1
Output
0
Input
0
Output
1 | instruction | 0 | 17,442 | 5 | 34,884 |
"Correct Solution:
```
print('10'[int(input())])
``` | output | 1 | 17,442 | 5 | 34,885 |
Provide a correct Python 3 solution for this coding contest problem.
Given is an integer x that is greater than or equal to 0, and less than or equal to 1. Output 1 if x is equal to 0, or 0 if x is equal to 1.
Constraints
* 0 \leq x \leq 1
* x is an integer
Input
Input is given from Standard Input in the following format:
x
Output
Print 1 if x is equal to 0, or 0 if x is equal to 1.
Examples
Input
1
Output
0
Input
0
Output
1 | instruction | 0 | 17,443 | 5 | 34,886 |
"Correct Solution:
```
x = int(input())
print(1 if x==0 else 0)
``` | output | 1 | 17,443 | 5 | 34,887 |
Provide a correct Python 3 solution for this coding contest problem.
Given is an integer x that is greater than or equal to 0, and less than or equal to 1. Output 1 if x is equal to 0, or 0 if x is equal to 1.
Constraints
* 0 \leq x \leq 1
* x is an integer
Input
Input is given from Standard Input in the following format:
x
Output
Print 1 if x is equal to 0, or 0 if x is equal to 1.
Examples
Input
1
Output
0
Input
0
Output
1 | instruction | 0 | 17,444 | 5 | 34,888 |
"Correct Solution:
```
x = int(input())
print(0 if x == 1 else 1)
``` | output | 1 | 17,444 | 5 | 34,889 |
Provide a correct Python 3 solution for this coding contest problem.
Given is an integer x that is greater than or equal to 0, and less than or equal to 1. Output 1 if x is equal to 0, or 0 if x is equal to 1.
Constraints
* 0 \leq x \leq 1
* x is an integer
Input
Input is given from Standard Input in the following format:
x
Output
Print 1 if x is equal to 0, or 0 if x is equal to 1.
Examples
Input
1
Output
0
Input
0
Output
1 | instruction | 0 | 17,445 | 5 | 34,890 |
"Correct Solution:
```
print("1" if input() == "0" else "0")
``` | output | 1 | 17,445 | 5 | 34,891 |
Provide a correct Python 3 solution for this coding contest problem.
Given is an integer x that is greater than or equal to 0, and less than or equal to 1. Output 1 if x is equal to 0, or 0 if x is equal to 1.
Constraints
* 0 \leq x \leq 1
* x is an integer
Input
Input is given from Standard Input in the following format:
x
Output
Print 1 if x is equal to 0, or 0 if x is equal to 1.
Examples
Input
1
Output
0
Input
0
Output
1 | instruction | 0 | 17,446 | 5 | 34,892 |
"Correct Solution:
```
a = int(input())
print(int(a!=True))
``` | output | 1 | 17,446 | 5 | 34,893 |
Provide a correct Python 3 solution for this coding contest problem.
Given is an integer x that is greater than or equal to 0, and less than or equal to 1. Output 1 if x is equal to 0, or 0 if x is equal to 1.
Constraints
* 0 \leq x \leq 1
* x is an integer
Input
Input is given from Standard Input in the following format:
x
Output
Print 1 if x is equal to 0, or 0 if x is equal to 1.
Examples
Input
1
Output
0
Input
0
Output
1 | instruction | 0 | 17,447 | 5 | 34,894 |
"Correct Solution:
```
n = int(input())
print(int(n == 0))
``` | output | 1 | 17,447 | 5 | 34,895 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given is an integer x that is greater than or equal to 0, and less than or equal to 1. Output 1 if x is equal to 0, or 0 if x is equal to 1.
Constraints
* 0 \leq x \leq 1
* x is an integer
Input
Input is given from Standard Input in the following format:
x
Output
Print 1 if x is equal to 0, or 0 if x is equal to 1.
Examples
Input
1
Output
0
Input
0
Output
1
Submitted Solution:
```
s=int(input())
print(1 if s == 0 else 0)
``` | instruction | 0 | 17,448 | 5 | 34,896 |
Yes | output | 1 | 17,448 | 5 | 34,897 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given is an integer x that is greater than or equal to 0, and less than or equal to 1. Output 1 if x is equal to 0, or 0 if x is equal to 1.
Constraints
* 0 \leq x \leq 1
* x is an integer
Input
Input is given from Standard Input in the following format:
x
Output
Print 1 if x is equal to 0, or 0 if x is equal to 1.
Examples
Input
1
Output
0
Input
0
Output
1
Submitted Solution:
```
n = int(input())
print(abs(n-1))
``` | instruction | 0 | 17,449 | 5 | 34,898 |
Yes | output | 1 | 17,449 | 5 | 34,899 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given is an integer x that is greater than or equal to 0, and less than or equal to 1. Output 1 if x is equal to 0, or 0 if x is equal to 1.
Constraints
* 0 \leq x \leq 1
* x is an integer
Input
Input is given from Standard Input in the following format:
x
Output
Print 1 if x is equal to 0, or 0 if x is equal to 1.
Examples
Input
1
Output
0
Input
0
Output
1
Submitted Solution:
```
print([1,0][int(input())])
``` | instruction | 0 | 17,450 | 5 | 34,900 |
Yes | output | 1 | 17,450 | 5 | 34,901 |
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