message stringlengths 2 44.5k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 42 109k | cluster float64 5 5 | __index_level_0__ int64 84 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which prints $n$-th fibonacci number for a given integer $n$. The $n$-th fibonacci number is defined by the following recursive formula:
\begin{equation*} fib(n)= \left \\{ \begin{array}{ll} 1 & (n = 0) \\\ 1 & (n = 1) \\\ fib(n - 1) + fib(n - 2) & \\\ \end{array} \right. \end{equation*}
Constraints
* $0 \leq n \leq 44$
Input
An integer $n$ is given.
Example
Input
3
Output
3
Submitted Solution:
```
#coding:UTF-8
def FN(n):
if n==0 or n==1:
return 1
else:
ans=FN(n-1)+FN(n-2)
return ans
if __name__=="__main__":
n=int(input())
ans=FN(n)
print(ans)
``` | instruction | 0 | 53,908 | 5 | 107,816 |
No | output | 1 | 53,908 | 5 | 107,817 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which prints $n$-th fibonacci number for a given integer $n$. The $n$-th fibonacci number is defined by the following recursive formula:
\begin{equation*} fib(n)= \left \\{ \begin{array}{ll} 1 & (n = 0) \\\ 1 & (n = 1) \\\ fib(n - 1) + fib(n - 2) & \\\ \end{array} \right. \end{equation*}
Constraints
* $0 \leq n \leq 44$
Input
An integer $n$ is given.
Example
Input
3
Output
3
Submitted Solution:
```
def fib(n):
if n == 0 or n == 1:
return 1
else :
return fib(n - 1) + fib(n - 2)
print( fib( int( input() ) ) )
``` | instruction | 0 | 53,909 | 5 | 107,818 |
No | output | 1 | 53,909 | 5 | 107,819 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which prints $n$-th fibonacci number for a given integer $n$. The $n$-th fibonacci number is defined by the following recursive formula:
\begin{equation*} fib(n)= \left \\{ \begin{array}{ll} 1 & (n = 0) \\\ 1 & (n = 1) \\\ fib(n - 1) + fib(n - 2) & \\\ \end{array} \right. \end{equation*}
Constraints
* $0 \leq n \leq 44$
Input
An integer $n$ is given.
Example
Input
3
Output
3
Submitted Solution:
```
F = {}
def fib(n):
global F
if n < 0:
print("error")
exit()
if n < 2:
F[n] = 1
return F[n]
F[n] = fib(n-1) + fib(n-2)
# F[n] = F[n-1] + F[n-2]
return F[n]
n = int(input())
print(fib(n))
#n = int(input())
#print(fib(n))
#fib(44)
#for i in range(44+1):
# print(fib(i))
# print(F[i])
``` | instruction | 0 | 53,910 | 5 | 107,820 |
No | output | 1 | 53,910 | 5 | 107,821 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which prints $n$-th fibonacci number for a given integer $n$. The $n$-th fibonacci number is defined by the following recursive formula:
\begin{equation*} fib(n)= \left \\{ \begin{array}{ll} 1 & (n = 0) \\\ 1 & (n = 1) \\\ fib(n - 1) + fib(n - 2) & \\\ \end{array} \right. \end{equation*}
Constraints
* $0 \leq n \leq 44$
Input
An integer $n$ is given.
Example
Input
3
Output
3
Submitted Solution:
```
F_list = [1,1] + [None]*43
def fibo(n):
F=F_list[n]
if n==0 or n==1: return F
F = fibo(n-1)+fibo(n-2)
F_list[n]=F
return F
n = int(input())
print(fibo(n))
``` | instruction | 0 | 53,911 | 5 | 107,822 |
No | output | 1 | 53,911 | 5 | 107,823 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which calculates the distance between two points P1(x1, y1) and P2(x2, y2).
Input
Four real numbers x1, y1, x2 and y2 are given in a line.
Output
Print the distance in real number. The output should not contain an absolute error greater than 10-4.
Example
Input
0 0 1 1
Output
1.41421356 | instruction | 0 | 53,912 | 5 | 107,824 |
"Correct Solution:
```
import math
i=list(map(float,input().split()))
x=(i[2]-i[0])**2
y=(i[3]-i[1])**2
print(math.sqrt(x+y))
``` | output | 1 | 53,912 | 5 | 107,825 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which calculates the distance between two points P1(x1, y1) and P2(x2, y2).
Input
Four real numbers x1, y1, x2 and y2 are given in a line.
Output
Print the distance in real number. The output should not contain an absolute error greater than 10-4.
Example
Input
0 0 1 1
Output
1.41421356 | instruction | 0 | 53,913 | 5 | 107,826 |
"Correct Solution:
```
x1, y1, x2, y2 = map(float, input().split())
print(f"{((x1-x2)**2+(y1-y2)**2)**0.5:.6f}")
``` | output | 1 | 53,913 | 5 | 107,827 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which calculates the distance between two points P1(x1, y1) and P2(x2, y2).
Input
Four real numbers x1, y1, x2 and y2 are given in a line.
Output
Print the distance in real number. The output should not contain an absolute error greater than 10-4.
Example
Input
0 0 1 1
Output
1.41421356 | instruction | 0 | 53,914 | 5 | 107,828 |
"Correct Solution:
```
a=list(map(float,input().split()))
print((abs(a[0]-a[2])**2+abs(a[1]-a[3])**2)**(1/2))
``` | output | 1 | 53,914 | 5 | 107,829 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which calculates the distance between two points P1(x1, y1) and P2(x2, y2).
Input
Four real numbers x1, y1, x2 and y2 are given in a line.
Output
Print the distance in real number. The output should not contain an absolute error greater than 10-4.
Example
Input
0 0 1 1
Output
1.41421356 | instruction | 0 | 53,915 | 5 | 107,830 |
"Correct Solution:
```
x1,y1,x2,y2=map(float,input().split())
p=((x1-x2)**2+(y1-y2)**2)**0.5
print(f'{p:.8f}')
``` | output | 1 | 53,915 | 5 | 107,831 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which calculates the distance between two points P1(x1, y1) and P2(x2, y2).
Input
Four real numbers x1, y1, x2 and y2 are given in a line.
Output
Print the distance in real number. The output should not contain an absolute error greater than 10-4.
Example
Input
0 0 1 1
Output
1.41421356 | instruction | 0 | 53,916 | 5 | 107,832 |
"Correct Solution:
```
x1,y1,x2,y2 = map(float,input().split())
print(format( ((x2-x1) ** 2 + (y2-y1) ** 2) ** 0.5,".5f"))
``` | output | 1 | 53,916 | 5 | 107,833 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which calculates the distance between two points P1(x1, y1) and P2(x2, y2).
Input
Four real numbers x1, y1, x2 and y2 are given in a line.
Output
Print the distance in real number. The output should not contain an absolute error greater than 10-4.
Example
Input
0 0 1 1
Output
1.41421356 | instruction | 0 | 53,917 | 5 | 107,834 |
"Correct Solution:
```
import math
X1,Y1,X2,Y2=map(float,input().split())
print(math.sqrt((X2-X1)*(X2-X1)+(Y2-Y1)*(Y2-Y1)))
``` | output | 1 | 53,917 | 5 | 107,835 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which calculates the distance between two points P1(x1, y1) and P2(x2, y2).
Input
Four real numbers x1, y1, x2 and y2 are given in a line.
Output
Print the distance in real number. The output should not contain an absolute error greater than 10-4.
Example
Input
0 0 1 1
Output
1.41421356 | instruction | 0 | 53,918 | 5 | 107,836 |
"Correct Solution:
```
a,b,c,d=map(float,input().split())
e=(c-a)**2
f=(d-b)**2
print(f"{(e+f)**(1/2):.8f}")
``` | output | 1 | 53,918 | 5 | 107,837 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which calculates the distance between two points P1(x1, y1) and P2(x2, y2).
Input
Four real numbers x1, y1, x2 and y2 are given in a line.
Output
Print the distance in real number. The output should not contain an absolute error greater than 10-4.
Example
Input
0 0 1 1
Output
1.41421356 | instruction | 0 | 53,919 | 5 | 107,838 |
"Correct Solution:
```
import math
x1,y1,x2,y2=map(float,input().split())
n=(x1-x2)**2+(y1-y2)**2
n1=math.sqrt(n)
print(n1)
``` | output | 1 | 53,919 | 5 | 107,839 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which calculates the distance between two points P1(x1, y1) and P2(x2, y2).
Input
Four real numbers x1, y1, x2 and y2 are given in a line.
Output
Print the distance in real number. The output should not contain an absolute error greater than 10-4.
Example
Input
0 0 1 1
Output
1.41421356
Submitted Solution:
```
A,B,C,D=map(float,input().split())
E=(C-A)**2
F=(D-B)**2
print((float)(E+F)**(1/2))
``` | instruction | 0 | 53,922 | 5 | 107,844 |
Yes | output | 1 | 53,922 | 5 | 107,845 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which calculates the distance between two points P1(x1, y1) and P2(x2, y2).
Input
Four real numbers x1, y1, x2 and y2 are given in a line.
Output
Print the distance in real number. The output should not contain an absolute error greater than 10-4.
Example
Input
0 0 1 1
Output
1.41421356
Submitted Solution:
```
x1,y1,x2,y2=map(int,input().split())
print(float((abs(x1-x2)**2)+abs(y1-y2)**2)**(1/2))
``` | instruction | 0 | 53,925 | 5 | 107,850 |
No | output | 1 | 53,925 | 5 | 107,851 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which calculates the distance between two points P1(x1, y1) and P2(x2, y2).
Input
Four real numbers x1, y1, x2 and y2 are given in a line.
Output
Print the distance in real number. The output should not contain an absolute error greater than 10-4.
Example
Input
0 0 1 1
Output
1.41421356
Submitted Solution:
```
#coding: UTF-8
import math
p = list(map(float, input().split()))
dis = math.sqrt((p[2] - p[0]) + (p[3] - p[1]))
print(dis)
``` | instruction | 0 | 53,926 | 5 | 107,852 |
No | output | 1 | 53,926 | 5 | 107,853 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which calculates the distance between two points P1(x1, y1) and P2(x2, y2).
Input
Four real numbers x1, y1, x2 and y2 are given in a line.
Output
Print the distance in real number. The output should not contain an absolute error greater than 10-4.
Example
Input
0 0 1 1
Output
1.41421356
Submitted Solution:
```
import math
x1, y1, x2, y2 = map(int, input().split())
print(((y2-y1)**2 + (x2-x1)**2)**(1/2))
``` | instruction | 0 | 53,927 | 5 | 107,854 |
No | output | 1 | 53,927 | 5 | 107,855 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have two integers l and r. Find an integer x which satisfies the conditions below:
* l ≤ x ≤ r.
* All digits of x are different.
If there are multiple answers, print any of them.
Input
The first line contains two integers l and r (1 ≤ l ≤ r ≤ 10^{5}).
Output
If an answer exists, print any of them. Otherwise, print -1.
Examples
Input
121 130
Output
123
Input
98766 100000
Output
-1
Note
In the first example, 123 is one of the possible answers. However, 121 can't be the answer, because there are multiple 1s on different digits.
In the second example, there is no valid answer.
Submitted Solution:
```
l,r= map(int,input().split())
f=0
for i in range(l,r+1):
if len(set(str(i)))==len(str(i)):
f=1
print(i)
break
if f==0:
print("-1")
``` | instruction | 0 | 54,042 | 5 | 108,084 |
Yes | output | 1 | 54,042 | 5 | 108,085 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have two integers l and r. Find an integer x which satisfies the conditions below:
* l ≤ x ≤ r.
* All digits of x are different.
If there are multiple answers, print any of them.
Input
The first line contains two integers l and r (1 ≤ l ≤ r ≤ 10^{5}).
Output
If an answer exists, print any of them. Otherwise, print -1.
Examples
Input
121 130
Output
123
Input
98766 100000
Output
-1
Note
In the first example, 123 is one of the possible answers. However, 121 can't be the answer, because there are multiple 1s on different digits.
In the second example, there is no valid answer.
Submitted Solution:
```
l, r = map(int, input().split())
for i in range(l, r+1):
if len(str(i)) == len(set(str(i))):print(i);exit()
print(-1)
``` | instruction | 0 | 54,043 | 5 | 108,086 |
Yes | output | 1 | 54,043 | 5 | 108,087 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have two integers l and r. Find an integer x which satisfies the conditions below:
* l ≤ x ≤ r.
* All digits of x are different.
If there are multiple answers, print any of them.
Input
The first line contains two integers l and r (1 ≤ l ≤ r ≤ 10^{5}).
Output
If an answer exists, print any of them. Otherwise, print -1.
Examples
Input
121 130
Output
123
Input
98766 100000
Output
-1
Note
In the first example, 123 is one of the possible answers. However, 121 can't be the answer, because there are multiple 1s on different digits.
In the second example, there is no valid answer.
Submitted Solution:
```
def check(n):
ch = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
while n > 0:
ch[n%10] += 1
n //= 10
for i in ch:
if i > 1:
return False
return True
a, b = map(int, input().split())
while check(a) == False and a <= b:
a += 1
if check(a) == True and a <= b:
print(a)
else:
print('-1')
``` | instruction | 0 | 54,044 | 5 | 108,088 |
Yes | output | 1 | 54,044 | 5 | 108,089 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have two integers l and r. Find an integer x which satisfies the conditions below:
* l ≤ x ≤ r.
* All digits of x are different.
If there are multiple answers, print any of them.
Input
The first line contains two integers l and r (1 ≤ l ≤ r ≤ 10^{5}).
Output
If an answer exists, print any of them. Otherwise, print -1.
Examples
Input
121 130
Output
123
Input
98766 100000
Output
-1
Note
In the first example, 123 is one of the possible answers. However, 121 can't be the answer, because there are multiple 1s on different digits.
In the second example, there is no valid answer.
Submitted Solution:
```
"""
Author : co_devil Chirag Garg
Institute : JIIT
"""
from math import *
from sys import stdin, stdout
import itertools, os, sys, threading
from collections import deque, Counter, OrderedDict, defaultdict
from heapq import *
#from math import ceil, floor, log, sqrt, factorial, pow, pi, gcd
# from bisect import bisect_left,bisect_right
# from decimal import *,threading
from fractions import Fraction
def ii(): return int(input())
def si(): return str(input())
def mi(): return map(int, input().split())
def li(): return list(mi())
def fii(): return int(stdin.readline())
def fsi(): return str(stdin.readline())
def fmi(): return map(int, stdin.readline().split())
def fli(): return list(fmi())
abd = {'a': 0, 'b': 1, 'c': 2, 'd': 3, 'e': 4, 'f': 5, 'g': 6, 'h': 7, 'i': 8, 'j': 9, 'k': 10, 'l': 11, 'm': 12,
'n': 13, 'o': 14, 'p': 15, 'q': 16, 'r': 17, 's': 18, 't': 19, 'u': 20, 'v': 21, 'w': 22, 'x': 23, 'y': 24,
'z': 25}
mod = 1000000007
def getKey(item): return item[0]
def sort2(l): return sorted(l, key=getKey)
def d2(n, m, num): return [[num for x in range(m)] for y in range(n)]
def isPowerOfTwo(x): return (x and (not (x & (x - 1))))
def decimalToBinary(n): return bin(n).replace("0b", "")
def ntl(n): return [int(i) for i in str(n)]
def powerMod(x, y, p):
res = 1
x %= p
while y > 0:
if y & 1:
res = (res * x) % p
y = y >> 1
x = (x * x) % p
return res
graph = defaultdict(list)
visited = [0] * 1000000
col = [-1] * 1000000
def bfs(d, v):
q = []
q.append(v)
visited[v] = 1
while len(q) != 0:
x = q[0]
q.pop(0)
for i in d[x]:
if visited[i] != 1:
visited[i] = 1
q.append(i)
print(x)
def make_graph(e):
d = {}
for i in range(e):
x, y, z = mi()
if x not in d:
d[x]=[[z,y]]
else:
d[x].append([z,y])
if y not in d:
d[y]=[[z,x]]
else:
d[y].append([z,x])
return d
def gr2(n):
d = defaultdict(list)
for i in range(n):
x, y = mi()
d[x].append(y)
return d
def connected_components(graph):
seen = set()
def dfs(v):
vs = set([v])
component = []
while vs:
v = vs.pop()
seen.add(v)
vs |= set(graph[v]) - seen
component.append(v)
return component
ans = []
for v in graph:
if v not in seen:
d = dfs(v)
ans.append(d)
return ans
def primeFactors(n):
s = set()
while n % 2 == 0:
s.add(2)
n = n // 2
for i in range(3, int(sqrt(n)) + 1, 2):
while n % i == 0:
s.add(i)
n = n // i
if n > 2:
s.add(n)
return s
def find_all(a_str, sub):
start = 0
while True:
start = a_str.find(sub, start)
if start == -1: return
yield start
start += len(sub)
def SieveOfEratosthenes(n, isPrime):
isPrime[0] = isPrime[1] = False
for i in range(2, n):
isPrime[i] = True
p = 2
while (p * p <= n):
if (isPrime[p] == True):
i = p * p
while (i <= n):
isPrime[i] = False
i += p
p += 1
return isPrime
def dijkstra(edges, f, t):
g = defaultdict(list)
for l,r,c in edges:
g[l].append((c,r))
q, seen, mins = [(0,f,())], set(), {f: 0}
while q:
(cost,v1,path) = heappop(q)
if v1 not in seen:
seen.add(v1)
path = (v1, path)
if v1 == t: return (cost, path)
for c, v2 in g.get(v1, ()):
if v2 in seen: continue
prev = mins.get(v2, None)
next = cost + c
if prev is None or next < prev:
mins[v2] = next
heappush(q, (next, v2, path))
return float("inf")
n,m=mi()
for i in range(n,m+1):
i=str(i)
if len(set(i))==len(list(i)):
print(i)
exit()
print(-1)
``` | instruction | 0 | 54,045 | 5 | 108,090 |
Yes | output | 1 | 54,045 | 5 | 108,091 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have two integers l and r. Find an integer x which satisfies the conditions below:
* l ≤ x ≤ r.
* All digits of x are different.
If there are multiple answers, print any of them.
Input
The first line contains two integers l and r (1 ≤ l ≤ r ≤ 10^{5}).
Output
If an answer exists, print any of them. Otherwise, print -1.
Examples
Input
121 130
Output
123
Input
98766 100000
Output
-1
Note
In the first example, 123 is one of the possible answers. However, 121 can't be the answer, because there are multiple 1s on different digits.
In the second example, there is no valid answer.
Submitted Solution:
```
n = list(map(int,input().split()))
l = n[0]
r = n[1]
x = list(map(int,str(l)))
y = list(map(int,str(r)))
d = r-l
if len(set(x)) == len(x):
print(l)
elif len(set(x)) != len(x):
for i in range(1,d+1):
k = l+i
z = list(map(int,str(k)))
if len(set(z)) == len(z):
print(k)
break
elif k == l+d:
print(-1)
else:
continue
``` | instruction | 0 | 54,046 | 5 | 108,092 |
No | output | 1 | 54,046 | 5 | 108,093 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have two integers l and r. Find an integer x which satisfies the conditions below:
* l ≤ x ≤ r.
* All digits of x are different.
If there are multiple answers, print any of them.
Input
The first line contains two integers l and r (1 ≤ l ≤ r ≤ 10^{5}).
Output
If an answer exists, print any of them. Otherwise, print -1.
Examples
Input
121 130
Output
123
Input
98766 100000
Output
-1
Note
In the first example, 123 is one of the possible answers. However, 121 can't be the answer, because there are multiple 1s on different digits.
In the second example, there is no valid answer.
Submitted Solution:
```
a, b=map(int, input().split())
m = int()
while b-1 > a :
i=0
x = str(b-1)
for i in range (0, len(x)):
m=0
for n in range (0,9):
z = str(n)
s = x.count(z)
if s == 1 :
m = m+1
b -=1
if m == len(x):
print(b+1)
exit()
print(-1)
``` | instruction | 0 | 54,047 | 5 | 108,094 |
No | output | 1 | 54,047 | 5 | 108,095 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have two integers l and r. Find an integer x which satisfies the conditions below:
* l ≤ x ≤ r.
* All digits of x are different.
If there are multiple answers, print any of them.
Input
The first line contains two integers l and r (1 ≤ l ≤ r ≤ 10^{5}).
Output
If an answer exists, print any of them. Otherwise, print -1.
Examples
Input
121 130
Output
123
Input
98766 100000
Output
-1
Note
In the first example, 123 is one of the possible answers. However, 121 can't be the answer, because there are multiple 1s on different digits.
In the second example, there is no valid answer.
Submitted Solution:
```
R=lambda:map(int,input().split());n,m=R();flag=0;
while(flag!=1 or n<=m):
new=str(n)
old=set(new)
if(len(old)==len(new)):
flag=1
break
else:
n+=1
if n>=m:
break
if flag==1:
print(n)
else:
print(-1)
``` | instruction | 0 | 54,048 | 5 | 108,096 |
No | output | 1 | 54,048 | 5 | 108,097 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have two integers l and r. Find an integer x which satisfies the conditions below:
* l ≤ x ≤ r.
* All digits of x are different.
If there are multiple answers, print any of them.
Input
The first line contains two integers l and r (1 ≤ l ≤ r ≤ 10^{5}).
Output
If an answer exists, print any of them. Otherwise, print -1.
Examples
Input
121 130
Output
123
Input
98766 100000
Output
-1
Note
In the first example, 123 is one of the possible answers. However, 121 can't be the answer, because there are multiple 1s on different digits.
In the second example, there is no valid answer.
Submitted Solution:
```
l,r=map(int,input().split())
for i in range(l,r+1):
if l==r:
print(-1)
break
n=i
visited = [0,0,0,0,0,0,0,0,0,0]
while (i):
if visited[i% 10]==1:
break;
visited[i% 10]=1
i=i//10
if i == 0:
print(n)
break
if i!=0 and n==r-1:
print(-1)
break
``` | instruction | 0 | 54,049 | 5 | 108,098 |
No | output | 1 | 54,049 | 5 | 108,099 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Now you get Baby Ehab's first words: "Given an integer n, find the longest subsequence of [1,2, …, n-1] whose product is 1 modulo n." Please solve the problem.
A sequence b is a subsequence of an array a if b can be obtained from a by deleting some (possibly all) elements. The product of an empty subsequence is equal to 1.
Input
The only line contains the integer n (2 ≤ n ≤ 10^5).
Output
The first line should contain a single integer, the length of the longest subsequence.
The second line should contain the elements of the subsequence, in increasing order.
If there are multiple solutions, you can print any.
Examples
Input
5
Output
3
1 2 3
Input
8
Output
4
1 3 5 7
Note
In the first example, the product of the elements is 6 which is congruent to 1 modulo 5. The only longer subsequence is [1,2,3,4]. Its product is 24 which is congruent to 4 modulo 5. Hence, the answer is [1,2,3].
Submitted Solution:
```
from sys import stdin, stdout
input, print = stdin.readline, stdout.write
from math import *
def main():
n = int(input())
mul = 1
good = [1]
for i in range(2, n):
if gcd(n, i) == 1:
mul *= i
mul %= n
good.append(i)
if mul == 1:
print(str(len(good)) + '\n')
else:
print(str(len(good) - 1) + '\n')
for elem in good:
if elem != mul or mul == 1:
print(str(elem) + ' ')
main()
``` | instruction | 0 | 54,194 | 5 | 108,388 |
Yes | output | 1 | 54,194 | 5 | 108,389 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Now you get Baby Ehab's first words: "Given an integer n, find the longest subsequence of [1,2, …, n-1] whose product is 1 modulo n." Please solve the problem.
A sequence b is a subsequence of an array a if b can be obtained from a by deleting some (possibly all) elements. The product of an empty subsequence is equal to 1.
Input
The only line contains the integer n (2 ≤ n ≤ 10^5).
Output
The first line should contain a single integer, the length of the longest subsequence.
The second line should contain the elements of the subsequence, in increasing order.
If there are multiple solutions, you can print any.
Examples
Input
5
Output
3
1 2 3
Input
8
Output
4
1 3 5 7
Note
In the first example, the product of the elements is 6 which is congruent to 1 modulo 5. The only longer subsequence is [1,2,3,4]. Its product is 24 which is congruent to 4 modulo 5. Hence, the answer is [1,2,3].
Submitted Solution:
```
n = int(input())
if n % 2 == 0:
print(int(n/2))
for i in range(1, n, 2):
print(i, end=' ')
else:
print(n-2)
for i in range(1, n-1):
print(i, end=' ')
``` | instruction | 0 | 54,198 | 5 | 108,396 |
No | output | 1 | 54,198 | 5 | 108,397 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an integer a that consists of n digits. You are also given a sequence of digits s of length m. The digit in position j (1 ≤ j ≤ m) of sequence s means that you can choose an arbitrary position i (1 ≤ i ≤ n) in a and replace the digit in the chosen position i with sj. Each element in the sequence s can participate in no more than one replacing operation.
Your task is to perform such sequence of replacements, that the given number a gets maximum value. You are allowed to use not all elements from s.
Input
The first line contains positive integer a. Its length n is positive and doesn't exceed 105. The second line contains sequence of digits s. Its length m is positive and doesn't exceed 105. The digits in the sequence s are written consecutively without any separators.
The given number a doesn't contain leading zeroes.
Output
Print the maximum value that can be obtained from a after a series of replacements. You are allowed to use not all elements from s. The printed number shouldn't contain any leading zeroes.
Examples
Input
1024
010
Output
1124
Input
987
1234567
Output
987
Submitted Solution:
```
a=list(input())
b=sorted(list(input()))[::-1]
for i in range(min(len(a),len(b))):
if b[i]>a[i]:
a[i]=(b[i],a[i])
for i in a:
print(i[0],end='')
``` | instruction | 0 | 54,229 | 5 | 108,458 |
No | output | 1 | 54,229 | 5 | 108,459 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Maxim loves to fill in a matrix in a special manner. Here is a pseudocode of filling in a matrix of size (m + 1) × (m + 1):
<image>
Maxim asks you to count, how many numbers m (1 ≤ m ≤ n) are there, such that the sum of values in the cells in the row number m + 1 of the resulting matrix equals t.
Expression (x xor y) means applying the operation of bitwise excluding "OR" to numbers x and y. The given operation exists in all modern programming languages. For example, in languages C++ and Java it is represented by character "^", in Pascal — by "xor".
Input
A single line contains two integers n and t (1 ≤ n, t ≤ 1012, t ≤ n + 1).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output
In a single line print a single integer — the answer to the problem.
Examples
Input
1 1
Output
1
Input
3 2
Output
1
Input
3 3
Output
0
Input
1000000000000 1048576
Output
118606527258 | instruction | 0 | 54,241 | 5 | 108,482 |
Tags: constructive algorithms, dp, math
Correct Solution:
```
n, t = map(int, input().split())
s = bin(n + 2)[2:]
l = len(s)
if t & (t - 1):
ans = 0
else:
t = t.bit_length()
f = [[0] * (l + 1) for i in range(l + 1)]
for i in range(l + 1):
f[i][0] = f[i][i] = 1
for j in range(1, i):
f[i][j] = f[i - 1][j - 1] + f[i - 1][j]
ans = c = 0
for i in range(l):
if s[i] == '1':
if t - c <= l - i - 1:
ans += f[l - i - 1][t - c]
c += 1
if t == 1: ans -= 1
print(ans)
``` | output | 1 | 54,241 | 5 | 108,483 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Maxim loves to fill in a matrix in a special manner. Here is a pseudocode of filling in a matrix of size (m + 1) × (m + 1):
<image>
Maxim asks you to count, how many numbers m (1 ≤ m ≤ n) are there, such that the sum of values in the cells in the row number m + 1 of the resulting matrix equals t.
Expression (x xor y) means applying the operation of bitwise excluding "OR" to numbers x and y. The given operation exists in all modern programming languages. For example, in languages C++ and Java it is represented by character "^", in Pascal — by "xor".
Input
A single line contains two integers n and t (1 ≤ n, t ≤ 1012, t ≤ n + 1).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output
In a single line print a single integer — the answer to the problem.
Examples
Input
1 1
Output
1
Input
3 2
Output
1
Input
3 3
Output
0
Input
1000000000000 1048576
Output
118606527258 | instruction | 0 | 54,242 | 5 | 108,484 |
Tags: constructive algorithms, dp, math
Correct Solution:
```
from math import factorial as fac
n, t = map(int, input().split())
if t & (t - 1):
ans = 0
else:
ans = c = 0
s = bin(n + 2)[2:]
l = len(s)
for i in range(l):
if s[i] == '1':
m, k = l - i - 1, t.bit_length() - c
if 0 <= k <= m:
ans += fac(m) // fac(k) // fac(m - k)
c += 1
if t == 1: ans -= 1
print(ans)
``` | output | 1 | 54,242 | 5 | 108,485 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Maxim loves to fill in a matrix in a special manner. Here is a pseudocode of filling in a matrix of size (m + 1) × (m + 1):
<image>
Maxim asks you to count, how many numbers m (1 ≤ m ≤ n) are there, such that the sum of values in the cells in the row number m + 1 of the resulting matrix equals t.
Expression (x xor y) means applying the operation of bitwise excluding "OR" to numbers x and y. The given operation exists in all modern programming languages. For example, in languages C++ and Java it is represented by character "^", in Pascal — by "xor".
Input
A single line contains two integers n and t (1 ≤ n, t ≤ 1012, t ≤ n + 1).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output
In a single line print a single integer — the answer to the problem.
Examples
Input
1 1
Output
1
Input
3 2
Output
1
Input
3 3
Output
0
Input
1000000000000 1048576
Output
118606527258 | instruction | 0 | 54,243 | 5 | 108,486 |
Tags: constructive algorithms, dp, math
Correct Solution:
```
def comb(n, r):
if r > n or r < 0:
return 0
r = min(r, n-r)
result = 1
for i in range(1, r+1):
result = result*(n+1-i)//i
return result
def F(n, t):
if t == 0:
return 1
elif n == 0:
return 0
elif n == 1:
return int(t == 1)
m = len(bin(n)) - 3
return F(n-(1 << m), t-1) + comb(m, t)
n, t = map(int, input().strip().split())
T = len(bin(t)) - 3
if (1 << T) != t:
print(0)
else:
print(F(n+1, T+1) - int(t == 1))
``` | output | 1 | 54,243 | 5 | 108,487 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Maxim loves to fill in a matrix in a special manner. Here is a pseudocode of filling in a matrix of size (m + 1) × (m + 1):
<image>
Maxim asks you to count, how many numbers m (1 ≤ m ≤ n) are there, such that the sum of values in the cells in the row number m + 1 of the resulting matrix equals t.
Expression (x xor y) means applying the operation of bitwise excluding "OR" to numbers x and y. The given operation exists in all modern programming languages. For example, in languages C++ and Java it is represented by character "^", in Pascal — by "xor".
Input
A single line contains two integers n and t (1 ≤ n, t ≤ 1012, t ≤ n + 1).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output
In a single line print a single integer — the answer to the problem.
Examples
Input
1 1
Output
1
Input
3 2
Output
1
Input
3 3
Output
0
Input
1000000000000 1048576
Output
118606527258
Submitted Solution:
```
n, t = map(int, input().split())
s = bin(n + 1)[2:]
l = len(s)
if t & (t - 1):
ans = 0
else:
t = t.bit_length()
f = [[0] * (l + 1) for i in range(l + 1)]
for i in range(l + 1):
f[i][0] = f[i][i] = 1
for j in range(1, i):
f[i][j] = f[i - 1][j - 1] + f[i - 1][j]
ans = c = 0
for i in range(l):
if s[i] == '1':
if t - c <= l - i - 1:
ans += f[l - i - 1][t - c]
c += 1
print(ans)
``` | instruction | 0 | 54,244 | 5 | 108,488 |
No | output | 1 | 54,244 | 5 | 108,489 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Maxim loves to fill in a matrix in a special manner. Here is a pseudocode of filling in a matrix of size (m + 1) × (m + 1):
<image>
Maxim asks you to count, how many numbers m (1 ≤ m ≤ n) are there, such that the sum of values in the cells in the row number m + 1 of the resulting matrix equals t.
Expression (x xor y) means applying the operation of bitwise excluding "OR" to numbers x and y. The given operation exists in all modern programming languages. For example, in languages C++ and Java it is represented by character "^", in Pascal — by "xor".
Input
A single line contains two integers n and t (1 ≤ n, t ≤ 1012, t ≤ n + 1).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output
In a single line print a single integer — the answer to the problem.
Examples
Input
1 1
Output
1
Input
3 2
Output
1
Input
3 3
Output
0
Input
1000000000000 1048576
Output
118606527258
Submitted Solution:
```
def comb(n, r):
if r > n or r < 0:
return 0
r = min(r, n-r)
result = 1
for i in range(1, r+1):
result = result*(n+1-i)//i
return result
def F(n, t):
if n == 0:
return 0
elif t == 0:
return 1
elif n == 1:
return int(t == 1)
m = len(bin(n)) - 3
return F(n-(1 << m), t-1) + comb(m, t)
n, t = map(int, input().strip().split())
T = len(bin(t)) - 3
if (1 << T) != t:
print(0)
else:
print(F(n, T+1))
``` | instruction | 0 | 54,245 | 5 | 108,490 |
No | output | 1 | 54,245 | 5 | 108,491 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Maxim loves to fill in a matrix in a special manner. Here is a pseudocode of filling in a matrix of size (m + 1) × (m + 1):
<image>
Maxim asks you to count, how many numbers m (1 ≤ m ≤ n) are there, such that the sum of values in the cells in the row number m + 1 of the resulting matrix equals t.
Expression (x xor y) means applying the operation of bitwise excluding "OR" to numbers x and y. The given operation exists in all modern programming languages. For example, in languages C++ and Java it is represented by character "^", in Pascal — by "xor".
Input
A single line contains two integers n and t (1 ≤ n, t ≤ 1012, t ≤ n + 1).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output
In a single line print a single integer — the answer to the problem.
Examples
Input
1 1
Output
1
Input
3 2
Output
1
Input
3 3
Output
0
Input
1000000000000 1048576
Output
118606527258
Submitted Solution:
```
def comb(n, r):
if r > n or r < 0:
return 0
r = min(r, n-r)
result = 1
for i in range(1, r+1):
result = result*(n+1-i)//i
return result
def F(n, t):
if n == 0:
return 0
elif n==1 and t==1:
return 1
m = len(bin(n)) - 3
return F(n-(1 << m), t-1) + comb(m, t)
n, t = map(int, input().strip().split())
T = len(bin(t)) - 3
if (1 << T) != t:
print(0)
else:
print(F(n, T+1))
``` | instruction | 0 | 54,246 | 5 | 108,492 |
No | output | 1 | 54,246 | 5 | 108,493 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Maxim loves to fill in a matrix in a special manner. Here is a pseudocode of filling in a matrix of size (m + 1) × (m + 1):
<image>
Maxim asks you to count, how many numbers m (1 ≤ m ≤ n) are there, such that the sum of values in the cells in the row number m + 1 of the resulting matrix equals t.
Expression (x xor y) means applying the operation of bitwise excluding "OR" to numbers x and y. The given operation exists in all modern programming languages. For example, in languages C++ and Java it is represented by character "^", in Pascal — by "xor".
Input
A single line contains two integers n and t (1 ≤ n, t ≤ 1012, t ≤ n + 1).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output
In a single line print a single integer — the answer to the problem.
Examples
Input
1 1
Output
1
Input
3 2
Output
1
Input
3 3
Output
0
Input
1000000000000 1048576
Output
118606527258
Submitted Solution:
```
n, t = map(int, input().split())
s = bin(n + 2)[2:]
l = len(s)
if t & (t - 1):
ans = 0
else:
t = t.bit_length()
f = [[0] * (l + 1) for i in range(l + 1)]
for i in range(l + 1):
f[i][0] = f[i][i] = 1
for j in range(1, i):
f[i][j] = f[i - 1][j - 1] + f[i - 1][j]
ans = c = 0
for i in range(l):
if s[i] == '1':
if t - c <= l - i - 1:
ans += f[l - i - 1][t - c]
c += 1
print(ans)
``` | instruction | 0 | 54,247 | 5 | 108,494 |
No | output | 1 | 54,247 | 5 | 108,495 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two positive integers a and b have a sum of s and a bitwise XOR of x. How many possible values are there for the ordered pair (a, b)?
Input
The first line of the input contains two integers s and x (2 ≤ s ≤ 1012, 0 ≤ x ≤ 1012), the sum and bitwise xor of the pair of positive integers, respectively.
Output
Print a single integer, the number of solutions to the given conditions. If no solutions exist, print 0.
Examples
Input
9 5
Output
4
Input
3 3
Output
2
Input
5 2
Output
0
Note
In the first sample, we have the following solutions: (2, 7), (3, 6), (6, 3), (7, 2).
In the second sample, the only solutions are (1, 2) and (2, 1).
Submitted Solution:
```
s, x = input().split()
s, x = int(s), int(x)
ones_in_x = 0
for let in reversed("{0:b}".format(x)):
if let == "1":
ones_in_x += 1
zbytkove = s - x
if zbytkove % 2 == 1 or x > s:
print(0)
elif s == x:
print(2**ones_in_x - 2)
else:
for zb, let in zip(reversed("{0:b}".format(zbytkove//2)), reversed("{0:b}".format(x))):
if zb == "1" and zb == let:
print(0)
break
else:
print(2**ones_in_x)
``` | instruction | 0 | 54,416 | 5 | 108,832 |
Yes | output | 1 | 54,416 | 5 | 108,833 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two positive integers a and b have a sum of s and a bitwise XOR of x. How many possible values are there for the ordered pair (a, b)?
Input
The first line of the input contains two integers s and x (2 ≤ s ≤ 1012, 0 ≤ x ≤ 1012), the sum and bitwise xor of the pair of positive integers, respectively.
Output
Print a single integer, the number of solutions to the given conditions. If no solutions exist, print 0.
Examples
Input
9 5
Output
4
Input
3 3
Output
2
Input
5 2
Output
0
Note
In the first sample, we have the following solutions: (2, 7), (3, 6), (6, 3), (7, 2).
In the second sample, the only solutions are (1, 2) and (2, 1).
Submitted Solution:
```
import io
import sys
import time
import random
#~ start = time.clock()
#~ test = '''3 3''' # 2 solutions, (1,2) and (2,1)
#~ test = '''9 5''' # 4 solutions
#~ test = '''5 2''' # 0 solutions
#~ test = '''6 0''' # 1 solution
#~ sys.stdin = io.StringIO(test)
s,x = list(map(int, input().split()))
#~ print(s,x)
bitlen = s.bit_length()
def bits_of(x,bitlen):
return [int((1<<i)&x!=0) for i in range(bitlen)]
sbits = bits_of(s,bitlen)
xbits = bits_of(x,bitlen)
overflows = bits_of(s^x,bitlen+1)
#~ print("s",sbits)
#~ print("x",xbits)
#~ print("overflows",overflows)
count = 1
if overflows[0]!=0 or s<x:
count = 0
else:
zero_is_solution = True
for i in range(bitlen):
sumof_a_and_b = 2*overflows[i+1]+sbits[i]-overflows[i]
#~ print(i,":",xbits[i],overflows[i+1],sbits[i],sumof_a_and_b)
if (sumof_a_and_b==0 and xbits[i]==1) or \
(sumof_a_and_b==1 and xbits[i]==0) or \
(sumof_a_and_b==2 and xbits[i]==1) or \
sumof_a_and_b>2 or sumof_a_and_b<0:
count = 0
break
if sumof_a_and_b==1 and xbits[i]==1:
count *= 2
#~ if sumof_a_and_b==0 and xbits[i]==0:
#~ print("s",(0,0))
#~ if sumof_a_and_b==1 and xbits[i]==1:
#~ print("s",(0,1),(1,0))
if sumof_a_and_b==2 and xbits[i]==0:
#~ print("s",(1,1))
zero_is_solution = False
if count>0 and zero_is_solution:
#~ print("R")
count -= 2
print(count)
#~ dur = time.clock()-start
#~ print("Time:",dur)
``` | instruction | 0 | 54,417 | 5 | 108,834 |
Yes | output | 1 | 54,417 | 5 | 108,835 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two positive integers a and b have a sum of s and a bitwise XOR of x. How many possible values are there for the ordered pair (a, b)?
Input
The first line of the input contains two integers s and x (2 ≤ s ≤ 1012, 0 ≤ x ≤ 1012), the sum and bitwise xor of the pair of positive integers, respectively.
Output
Print a single integer, the number of solutions to the given conditions. If no solutions exist, print 0.
Examples
Input
9 5
Output
4
Input
3 3
Output
2
Input
5 2
Output
0
Note
In the first sample, we have the following solutions: (2, 7), (3, 6), (6, 3), (7, 2).
In the second sample, the only solutions are (1, 2) and (2, 1).
Submitted Solution:
```
def solve(s, x):
d = (s - x)
if x << 1 & d or d%2 or d<0: return 0
return 2 ** (bin(x).count('1')) - (0 if d else 2)
s, x = map(int, input().split())
print(solve(s, x))
``` | instruction | 0 | 54,418 | 5 | 108,836 |
Yes | output | 1 | 54,418 | 5 | 108,837 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two positive integers a and b have a sum of s and a bitwise XOR of x. How many possible values are there for the ordered pair (a, b)?
Input
The first line of the input contains two integers s and x (2 ≤ s ≤ 1012, 0 ≤ x ≤ 1012), the sum and bitwise xor of the pair of positive integers, respectively.
Output
Print a single integer, the number of solutions to the given conditions. If no solutions exist, print 0.
Examples
Input
9 5
Output
4
Input
3 3
Output
2
Input
5 2
Output
0
Note
In the first sample, we have the following solutions: (2, 7), (3, 6), (6, 3), (7, 2).
In the second sample, the only solutions are (1, 2) and (2, 1).
Submitted Solution:
```
import io
import sys
import time
import random
#~ start = time.clock()
#~ test = '''3 3''' # 2 solutions, (1,2) and (2,1)
#~ test = '''9 5''' # 4 solutions
#~ test = '''5 2''' # 0 solutions
#~ test = '''6 0''' # 1 solution
#~ sys.stdin = io.StringIO(test)
s,x = list(map(int, input().split()))
def bit_of(x,i):
return int((1<<i)&x!=0)
def solve(s,x):
if s<x or (s^x)%2!=0:
return 0
d = (s-x)//2
zero_is_solution = True
count = 1
for i in range(s.bit_length()):
db = bit_of(d,i)
xb = bit_of(x,i)
if db==1:
if xb==1:
return 0
else:
zero_is_solution = False
if db==0 and xb==1:
count *= 2
if zero_is_solution:
count -= 2
return count
print(solve(s,x))
``` | instruction | 0 | 54,419 | 5 | 108,838 |
Yes | output | 1 | 54,419 | 5 | 108,839 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two positive integers a and b have a sum of s and a bitwise XOR of x. How many possible values are there for the ordered pair (a, b)?
Input
The first line of the input contains two integers s and x (2 ≤ s ≤ 1012, 0 ≤ x ≤ 1012), the sum and bitwise xor of the pair of positive integers, respectively.
Output
Print a single integer, the number of solutions to the given conditions. If no solutions exist, print 0.
Examples
Input
9 5
Output
4
Input
3 3
Output
2
Input
5 2
Output
0
Note
In the first sample, we have the following solutions: (2, 7), (3, 6), (6, 3), (7, 2).
In the second sample, the only solutions are (1, 2) and (2, 1).
Submitted Solution:
```
#!/usr/bin/env python3
from math import log
s, x = [int(x) for x in input().split()]
# sum == 0, xor == 0, one == 0 - both are 0 or 1 (2 variants)
# sum == 0, xor == 0, one == 1 - impossible
# sum == 0, xor == 1, one == 0 - impossible
# sum == 0, xor == 1, one == 1 - one 1 and another 1 is 0 (2 variants)
# sum == 1, xor == 0, one == 0 - impossible
# sum == 1, xor == 0, one == 1 - both are 0 or 1 (2 variants)
# sum == 1, xor == 1, one == 0 - one 1 and another 1 is 0 (2 variants)
# sum == 1, xor == 1, one == 1 - impossible
def get_count(size, one_bit, s, x):
if size == 0 or \
not one_bit and s == 0 and x == 0:
return 1
sum_bit = s & 1 != 0
xor_bit = x & 1 != 0
print('size = {2:0>2}, sum_bit = {0}, xor_bit = {1}, one_bit = {3}'.format(sum_bit, xor_bit, size, one_bit))
if not sum_bit and not xor_bit and one_bit or \
not sum_bit and xor_bit and not one_bit or \
sum_bit and not xor_bit and not one_bit or \
sum_bit and xor_bit and one_bit:
return 0
s >>= 1
x >>= 1
size -= 1
if not sum_bit and not xor_bit and not one_bit or \
sum_bit and not xor_bit and one_bit:
return get_count(size, False, s, x) + get_count(size, True, s, x)
elif not sum_bit and xor_bit and one_bit:
return 2 * get_count(size, True, s, x)
else:
return 2 * get_count(size, False, s, x)
size = int(log(1000000000000)/log(2))
count = get_count(size, False, s, x)
if s == x:
assert count >= 2
count -= 2 # numbers have to be > 0, so pairs with 0 aren't suitable
print(count)
``` | instruction | 0 | 54,420 | 5 | 108,840 |
No | output | 1 | 54,420 | 5 | 108,841 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two positive integers a and b have a sum of s and a bitwise XOR of x. How many possible values are there for the ordered pair (a, b)?
Input
The first line of the input contains two integers s and x (2 ≤ s ≤ 1012, 0 ≤ x ≤ 1012), the sum and bitwise xor of the pair of positive integers, respectively.
Output
Print a single integer, the number of solutions to the given conditions. If no solutions exist, print 0.
Examples
Input
9 5
Output
4
Input
3 3
Output
2
Input
5 2
Output
0
Note
In the first sample, we have the following solutions: (2, 7), (3, 6), (6, 3), (7, 2).
In the second sample, the only solutions are (1, 2) and (2, 1).
Submitted Solution:
```
s_, x_ = map(int, input().split())
s = bin(s_)[2:]
x = bin(x_)[2:]
x = '0' * (len(s) - len(x)) + x
#print(s)
#print(x)
zero = 1
one = 0
for a, b in zip(x[::-1], s[::-1]):
#print('a, b = ', a, b)
a = int(a)
b = int(b)
new_one = 0
new_zero = 0
if (a == 0 and b == 0):
new_one += zero
new_zero += zero
if (a == 0 and b == 1):
new_zero += one
new_one += one
if (a == 1 and b == 0):
new_one = 2 * one
new_zero = 0
if (a == 1 and b == 1):
new_one = 0
new_zero = 2 * zero
zero = new_zero
one = new_one
#print(zero, one)
if (s_ ^ 0 == x_):
zero -= 2
print(zero)
``` | instruction | 0 | 54,421 | 5 | 108,842 |
No | output | 1 | 54,421 | 5 | 108,843 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two positive integers a and b have a sum of s and a bitwise XOR of x. How many possible values are there for the ordered pair (a, b)?
Input
The first line of the input contains two integers s and x (2 ≤ s ≤ 1012, 0 ≤ x ≤ 1012), the sum and bitwise xor of the pair of positive integers, respectively.
Output
Print a single integer, the number of solutions to the given conditions. If no solutions exist, print 0.
Examples
Input
9 5
Output
4
Input
3 3
Output
2
Input
5 2
Output
0
Note
In the first sample, we have the following solutions: (2, 7), (3, 6), (6, 3), (7, 2).
In the second sample, the only solutions are (1, 2) and (2, 1).
Submitted Solution:
```
import io
import sys
import time
import random
start = time.clock()
#~ test = '''3 3'''
#~ test = '''9 5'''
#~ test = '''5 2'''
#~ test = '''6 0''' # expected: 0
#~ sys.stdin = io.StringIO(test)
s,x = list(map(int, input().split()))
#~ print(s,x)
bitlen = s.bit_length()
overflows = [0 for i in range(bitlen+1)]
sbits = [1 if ((1<<i)&s)>0 else 0 for i in range(bitlen)]
xbits = [1 if ((1<<i)&x)>0 else 0 for i in range(bitlen)]
for i in range(bitlen):
overflows[i] = sbits[i]^xbits[i]
# actually overflows[i] is the
# overflow bit used to compute sbits[i+1]
count = 1
for i in range(bitlen):
sumof_a_and_b = 2*overflows[i+1]+sbits[i]-overflows[i]
#~ print(i,sumof_a_and_b,xbits[i])
if (sumof_a_and_b==0 and xbits[i]==1) or \
(sumof_a_and_b==1 and xbits[i]==0) or \
(sumof_a_and_b==2 and xbits[i]==1):
count = 0
break
if sumof_a_and_b==1 and xbits[i]==1:
count *= 2
#~ if sumof_a_and_b==0 and xbits[0]==0:
#~ print("s",(0,0))
#~ if sumof_a_and_b==1 and xbits[0]==1:
#~ print("s",(0,1),(1,0))
#~ if sumof_a_and_b==2 and xbits[0]==0:
#~ print("s",(1,1))
print(count)
#~ dur = time.clock()-start
#~ print("Time:",dur)
``` | instruction | 0 | 54,422 | 5 | 108,844 |
No | output | 1 | 54,422 | 5 | 108,845 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two positive integers a and b have a sum of s and a bitwise XOR of x. How many possible values are there for the ordered pair (a, b)?
Input
The first line of the input contains two integers s and x (2 ≤ s ≤ 1012, 0 ≤ x ≤ 1012), the sum and bitwise xor of the pair of positive integers, respectively.
Output
Print a single integer, the number of solutions to the given conditions. If no solutions exist, print 0.
Examples
Input
9 5
Output
4
Input
3 3
Output
2
Input
5 2
Output
0
Note
In the first sample, we have the following solutions: (2, 7), (3, 6), (6, 3), (7, 2).
In the second sample, the only solutions are (1, 2) and (2, 1).
Submitted Solution:
```
'''
(a+b)=(a^b)+2*(a&b)
'''
def check(a,b):
# a and vala
for i in range(20):
if a&(1<<i):
if b&(1<<i):
return False
return True
# print(check(1,5))
def f(s,x):
if (s-x)%2!=0:
return 0
nd=(s-x)//2
bd=0
if nd==0:
bd=2
if check(nd,x):
btcnt=(bin(x).count("1"))
return (2**(btcnt))-bd
return 0
a,b=map(int,input().strip().split())
print(f(a,b))
``` | instruction | 0 | 54,423 | 5 | 108,846 |
No | output | 1 | 54,423 | 5 | 108,847 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a rebus of form ? + ? - ? + ? = n, consisting of only question marks, separated by arithmetic operation '+' and '-', equality and positive integer n. The goal is to replace each question mark with some positive integer from 1 to n, such that equality holds.
Input
The only line of the input contains a rebus. It's guaranteed that it contains no more than 100 question marks, integer n is positive and doesn't exceed 1 000 000, all letters and integers are separated by spaces, arithmetic operations are located only between question marks.
Output
The first line of the output should contain "Possible" (without quotes) if rebus has a solution and "Impossible" (without quotes) otherwise.
If the answer exists, the second line should contain any valid rebus with question marks replaced by integers from 1 to n. Follow the format given in the samples.
Examples
Input
? + ? - ? + ? + ? = 42
Output
Possible
9 + 13 - 39 + 28 + 31 = 42
Input
? - ? = 1
Output
Impossible
Input
? = 1000000
Output
Possible
1000000 = 1000000
Submitted Solution:
```
from math import ceil
def main():
p = 1
m = 0
n = 0
exp = str(input()).split(' ')
for i in range(len(exp)):
if exp[i] == '+':
p += 1
elif exp[i] == '-':
m += 1
elif exp[i] == '=':
n = int(exp[i+1])
if p > n + m * n:
print("Impossible")
return
result = n + m
if p <= result:
required = ceil(result / n)
if p >= required:
print("Possible")
else:
print("Impossible")
return
pVal = result // p
pRem = result % p
isMinus = False
s_out = ""
for i in range(len(exp)):
if exp[i] == '?':
if not isMinus:
val = pVal
if pRem > 0:
val += 1
pRem -= 1
s_out += str(val) + " "
else:
s_out += "1 "
else:
if exp[i] == '-':
isMinus = True
elif exp[i] == '+':
isMinus = False
else:
s_out += exp[i] + " " + exp[i+1]
break
s_out += exp[i] + " "
print(s_out)
else:
print("Possible")
comp = p - n
mVal = comp // m
mRem = comp % m
isMinus = False
s_out = ""
for i in range(len(exp)):
if exp[i] == '?':
if isMinus:
val = mVal
if mRem > 0:
val += 1
mRem -= 1
s_out += str(val) + " "
else:
s_out += "1 "
else:
if exp[i] == '-':
isMinus = True
elif exp[i] == '+':
isMinus = False
else:
s_out += exp[i] + " " + exp[i+1]
break
s_out += exp[i] + " "
print(s_out)
main()
``` | instruction | 0 | 54,432 | 5 | 108,864 |
Yes | output | 1 | 54,432 | 5 | 108,865 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a rebus of form ? + ? - ? + ? = n, consisting of only question marks, separated by arithmetic operation '+' and '-', equality and positive integer n. The goal is to replace each question mark with some positive integer from 1 to n, such that equality holds.
Input
The only line of the input contains a rebus. It's guaranteed that it contains no more than 100 question marks, integer n is positive and doesn't exceed 1 000 000, all letters and integers are separated by spaces, arithmetic operations are located only between question marks.
Output
The first line of the output should contain "Possible" (without quotes) if rebus has a solution and "Impossible" (without quotes) otherwise.
If the answer exists, the second line should contain any valid rebus with question marks replaced by integers from 1 to n. Follow the format given in the samples.
Examples
Input
? + ? - ? + ? + ? = 42
Output
Possible
9 + 13 - 39 + 28 + 31 = 42
Input
? - ? = 1
Output
Impossible
Input
? = 1000000
Output
Possible
1000000 = 1000000
Submitted Solution:
```
def mp(): return map(int,input().split())
def lt(): return list(map(int,input().split()))
def pt(x): print(x)
def ip(): return input()
def it(): return int(input())
def sl(x): return [t for t in x]
def spl(x): return x.split()
def aj(liste, item): liste.append(item)
def bin(x): return "{0:b}".format(x)
def listring(l): return ' '.join([str(x) for x in l])
def printlist(l): print(' '.join([str(x) for x in l]))
a = input().split()
n = int(a[-1])
if n*(a.count("+")+1) - a.count("-") < n:
print("Impossible")
else:
b = [x for x in a if x == "+" or x == "-"]
b.insert(0,"+")
c = [n if b[i] == "+" else 1 for i in range(len(b))]
x = n*(a.count("+")+1) - a.count("-") - n
j = 0
while x > 0 and j < len(c):
if x >= n-1:
if c[j] == n:
c[j] -= (n-1)
else:
c[j] += (n-1)
x -= (n-1)
else:
if c[j] == n:
c[j] -= x
else:
c[j] += x
x = 0
j += 1
if x != 0:
print("Impossible")
exit()
print("Possible")
result = ""
b.pop(0)
for i in range(len(b)):
result += str(c[i])
result += " "
result += b[i]
result += " "
result += ("%d " % c[-1])
result += ("= %d " % n)
print(result)
``` | instruction | 0 | 54,433 | 5 | 108,866 |
Yes | output | 1 | 54,433 | 5 | 108,867 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a rebus of form ? + ? - ? + ? = n, consisting of only question marks, separated by arithmetic operation '+' and '-', equality and positive integer n. The goal is to replace each question mark with some positive integer from 1 to n, such that equality holds.
Input
The only line of the input contains a rebus. It's guaranteed that it contains no more than 100 question marks, integer n is positive and doesn't exceed 1 000 000, all letters and integers are separated by spaces, arithmetic operations are located only between question marks.
Output
The first line of the output should contain "Possible" (without quotes) if rebus has a solution and "Impossible" (without quotes) otherwise.
If the answer exists, the second line should contain any valid rebus with question marks replaced by integers from 1 to n. Follow the format given in the samples.
Examples
Input
? + ? - ? + ? + ? = 42
Output
Possible
9 + 13 - 39 + 28 + 31 = 42
Input
? - ? = 1
Output
Impossible
Input
? = 1000000
Output
Possible
1000000 = 1000000
Submitted Solution:
```
s = input().split()
n = 0
arr = []
op = []
for i in s:
if (i=='='):
break
if (i=='+'):
op.append(1)
elif (i=='-'):
op.append(-1)
else :
arr.append(1)
n = int(s[-1])
val = arr[0]
for i in range(len(op)):
val += op[i]*arr[i+1]
if (val<n):
rem = n - val
for i in range(len(arr)):
if ( i!=0 and op[i-1]==-1):
continue
up = min(rem, n-arr[i])
arr[i] += up
rem -= up
if (rem == 0):
break
if (rem!=0):
print("Impossible")
exit(0)
elif (val>n):
rem = val - n
for i in range(len(arr)):
if ( i==0 or op[i-1]==1):
continue
up = min(rem, n-arr[i])
arr[i] += up
rem -= up
if (rem == 0):
break
if (rem!=0):
print("Impossible")
exit(0)
print("Possible")
tos = str(arr[0]) + " "
for i in range(len(op)):
if (op[i]==-1):
tos += "- "
else:
tos += "+ "
tos += str(arr[i+1]) + " "
tos += "= "+str(n)
print(tos)
``` | instruction | 0 | 54,435 | 5 | 108,870 |
Yes | output | 1 | 54,435 | 5 | 108,871 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a rebus of form ? + ? - ? + ? = n, consisting of only question marks, separated by arithmetic operation '+' and '-', equality and positive integer n. The goal is to replace each question mark with some positive integer from 1 to n, such that equality holds.
Input
The only line of the input contains a rebus. It's guaranteed that it contains no more than 100 question marks, integer n is positive and doesn't exceed 1 000 000, all letters and integers are separated by spaces, arithmetic operations are located only between question marks.
Output
The first line of the output should contain "Possible" (without quotes) if rebus has a solution and "Impossible" (without quotes) otherwise.
If the answer exists, the second line should contain any valid rebus with question marks replaced by integers from 1 to n. Follow the format given in the samples.
Examples
Input
? + ? - ? + ? + ? = 42
Output
Possible
9 + 13 - 39 + 28 + 31 = 42
Input
? - ? = 1
Output
Impossible
Input
? = 1000000
Output
Possible
1000000 = 1000000
Submitted Solution:
```
raw = input()
s = raw.replace('?','')
n = int(s.split(' ')[-1])
m = s.count('-')
p = s.count('+')
c = p - m
def main():
if n-c < 1 or n-c > n:
print('Impossible')
return
print('Possible')
print(str(n-c) + " " + raw[2:].replace('?', '1'))
main()
``` | instruction | 0 | 54,436 | 5 | 108,872 |
No | output | 1 | 54,436 | 5 | 108,873 |
Provide a correct Python 3 solution for this coding contest problem.
Using the given four integers from 1 to 9, we create an expression that gives an answer of 10. When you enter four integers a, b, c, d, write a program that outputs an expression that gives an answer of 10 according to the following conditions. Also, if there are multiple answers, only the first answer found will be output. If there is no answer, output 0.
* Use only addition (+), subtraction (-), and multiplication (*) as operators. Do not use division (/). You can use three operators.
* You must use all four numbers.
* You can freely change the order of the four numbers.
* You can use parentheses. You can use up to 3 sets (6) of parentheses.
Input
Given multiple datasets. The format of each dataset is as follows:
a b c d
Input ends with four 0s. The number of datasets does not exceed 40.
Output
For each dataset, combine the given four integers with the above arithmetic symbols and parentheses to output an expression or 0 with a value of 10 on one line. The expression string must not exceed 1024 characters.
Example
Input
8 7 9 9
4 4 4 4
5 5 7 5
0 0 0 0
Output
((9 * (9 - 7)) - 8)
0
((7 * 5) - (5 * 5)) | instruction | 0 | 54,686 | 5 | 109,372 |
"Correct Solution:
```
from itertools import *
g=lambda a,x,b:a+b if x=='+'else a-b if x=='-'else a*b
def f(s):
for a,b,c,d in permutations(s):
for x,y,z in product('+-*',repeat=3):
if g(g(a,x,b),y,g(c,z,d))==10:return f"(({a} {x} {b}) {y} ({c} {z} {d}))"
if g(g(a,x,g(b,y,c)),z,d)==10:return f"(({a} {x} ({b} {y} {c})) {z} {d})"
return 0
for e in iter(input,'0 0 0 0'):print(f(list(map(int,e.split()))))
``` | output | 1 | 54,686 | 5 | 109,373 |
Provide a correct Python 3 solution for this coding contest problem.
Using the given four integers from 1 to 9, we create an expression that gives an answer of 10. When you enter four integers a, b, c, d, write a program that outputs an expression that gives an answer of 10 according to the following conditions. Also, if there are multiple answers, only the first answer found will be output. If there is no answer, output 0.
* Use only addition (+), subtraction (-), and multiplication (*) as operators. Do not use division (/). You can use three operators.
* You must use all four numbers.
* You can freely change the order of the four numbers.
* You can use parentheses. You can use up to 3 sets (6) of parentheses.
Input
Given multiple datasets. The format of each dataset is as follows:
a b c d
Input ends with four 0s. The number of datasets does not exceed 40.
Output
For each dataset, combine the given four integers with the above arithmetic symbols and parentheses to output an expression or 0 with a value of 10 on one line. The expression string must not exceed 1024 characters.
Example
Input
8 7 9 9
4 4 4 4
5 5 7 5
0 0 0 0
Output
((9 * (9 - 7)) - 8)
0
((7 * 5) - (5 * 5)) | instruction | 0 | 54,687 | 5 | 109,374 |
"Correct Solution:
```
from itertools import *
g=lambda a,x,b:a+b if x=='+'else a-b if x=='-'else a*b
def f(s):
for a,b,c,d in permutations(s):
for x,y,z in product('+-*',repeat=3):
if g(g(a,x,b),y,g(c,z,d))==10:return f"(({a} {x} {b}) {y} ({c} {z} {d}))"
if g(g(a,x,g(b,y,c)),z,d)==10:return f"(({a} {x} ({b} {y} {c})) {z} {d})"
else:return 0
for e in iter(input,'0 0 0 0'):print(f(list(map(int,e.split()))))
``` | output | 1 | 54,687 | 5 | 109,375 |
Provide a correct Python 3 solution for this coding contest problem.
Using the given four integers from 1 to 9, we create an expression that gives an answer of 10. When you enter four integers a, b, c, d, write a program that outputs an expression that gives an answer of 10 according to the following conditions. Also, if there are multiple answers, only the first answer found will be output. If there is no answer, output 0.
* Use only addition (+), subtraction (-), and multiplication (*) as operators. Do not use division (/). You can use three operators.
* You must use all four numbers.
* You can freely change the order of the four numbers.
* You can use parentheses. You can use up to 3 sets (6) of parentheses.
Input
Given multiple datasets. The format of each dataset is as follows:
a b c d
Input ends with four 0s. The number of datasets does not exceed 40.
Output
For each dataset, combine the given four integers with the above arithmetic symbols and parentheses to output an expression or 0 with a value of 10 on one line. The expression string must not exceed 1024 characters.
Example
Input
8 7 9 9
4 4 4 4
5 5 7 5
0 0 0 0
Output
((9 * (9 - 7)) - 8)
0
((7 * 5) - (5 * 5)) | instruction | 0 | 54,688 | 5 | 109,376 |
"Correct Solution:
```
import sys,itertools
if sys.version_info[0]>=3: raw_input=input
def dfs(a):
if len(a)<2: yield (a[0],str(a[0]))
for i in range(len(a)-1):
for l in dfs(a[:i+1]):
for r in dfs(a[i+1:]):
yield (l[0]+r[0],'(%s + %s)'%(l[1],r[1]))
yield (l[0]-r[0],'(%s - %s)'%(l[1],r[1]))
yield (l[0]*r[0],'(%s * %s)'%(l[1],r[1]))
def solve(a):
for e in itertools.permutations(a):
for n,s in dfs(e):
if n==10:
print(s)
return True
try:
while True:
a=[int(e) for e in raw_input().split()]
if a==[0,0,0,0]: break
if not solve(a): print(0)
except EOFError:
pass
``` | output | 1 | 54,688 | 5 | 109,377 |
Provide a correct Python 3 solution for this coding contest problem.
Using the given four integers from 1 to 9, we create an expression that gives an answer of 10. When you enter four integers a, b, c, d, write a program that outputs an expression that gives an answer of 10 according to the following conditions. Also, if there are multiple answers, only the first answer found will be output. If there is no answer, output 0.
* Use only addition (+), subtraction (-), and multiplication (*) as operators. Do not use division (/). You can use three operators.
* You must use all four numbers.
* You can freely change the order of the four numbers.
* You can use parentheses. You can use up to 3 sets (6) of parentheses.
Input
Given multiple datasets. The format of each dataset is as follows:
a b c d
Input ends with four 0s. The number of datasets does not exceed 40.
Output
For each dataset, combine the given four integers with the above arithmetic symbols and parentheses to output an expression or 0 with a value of 10 on one line. The expression string must not exceed 1024 characters.
Example
Input
8 7 9 9
4 4 4 4
5 5 7 5
0 0 0 0
Output
((9 * (9 - 7)) - 8)
0
((7 * 5) - (5 * 5)) | instruction | 0 | 54,689 | 5 | 109,378 |
"Correct Solution:
```
import itertools,sys
def f(a):
if len(a)<2:yield[a[0]]*2
for i in range(1,len(a)):
for p,s in f(a[:i]):
for q,t in f(a[i:]):
yield(p+q,f'({s} + {t})')
yield(p-q,f'({s} - {t})')
yield(p*q,f'({s} * {t})')
def s(a):
for p in itertools.permutations(a):
for n,s in f(p):
if n==10:print(s);return 1
for e in sys.stdin:
a=list(map(int,e.split()))
if sum(a)and not s(a):print(0)
``` | output | 1 | 54,689 | 5 | 109,379 |
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