message stringlengths 2 44.5k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 42 109k | cluster float64 5 5 | __index_level_0__ int64 84 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N positive integers arranged in a circle.
Now, the i-th number is A_i. Takahashi wants the i-th number to be B_i. For this objective, he will repeatedly perform the following operation:
* Choose an integer i such that 1 \leq i \leq N.
* Let a, b, c be the (i-1)-th, i-th, and (i+1)-th numbers, respectively. Replace the i-th number with a+b+c.
Here the 0-th number is the N-th number, and the (N+1)-th number is the 1-st number.
Determine if Takahashi can achieve his objective. If the answer is yes, find the minimum number of operations required.
Constraints
* 3 \leq N \leq 2 \times 10^5
* 1 \leq A_i, B_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
B_1 B_2 ... B_N
Output
Print the minimum number of operations required, or `-1` if the objective cannot be achieved.
Examples
Input
3
1 1 1
13 5 7
Output
4
Input
4
1 2 3 4
2 3 4 5
Output
-1
Input
5
5 6 5 2 1
9817 1108 6890 4343 8704
Output
25
Submitted Solution:
```
import heapq
import sys
def main():
input=sys.stdin.readline
N=int(input())
A=list(map(int,input().split()))
B=list(map(int,input().split()))
H=[]
for i,x in enumerate(B):
heapq.heappush(H,(-x,i))
ans=0
flg=0
while flg==0:
x,i=heapq.heappop(H)
v=x+B[(i-1)%N]+B[(i+1)%N]
if -v<A[i]:
for i,j in zip(A,B):
if i!=j:
print(-1)
exit()
break
B[i]=-v
heapq.heappush(H,(v,i))
ans+=1
print(ans)
if __name__ == '__main__':
main()
``` | instruction | 0 | 4,009 | 5 | 8,018 |
No | output | 1 | 4,009 | 5 | 8,019 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N positive integers arranged in a circle.
Now, the i-th number is A_i. Takahashi wants the i-th number to be B_i. For this objective, he will repeatedly perform the following operation:
* Choose an integer i such that 1 \leq i \leq N.
* Let a, b, c be the (i-1)-th, i-th, and (i+1)-th numbers, respectively. Replace the i-th number with a+b+c.
Here the 0-th number is the N-th number, and the (N+1)-th number is the 1-st number.
Determine if Takahashi can achieve his objective. If the answer is yes, find the minimum number of operations required.
Constraints
* 3 \leq N \leq 2 \times 10^5
* 1 \leq A_i, B_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
B_1 B_2 ... B_N
Output
Print the minimum number of operations required, or `-1` if the objective cannot be achieved.
Examples
Input
3
1 1 1
13 5 7
Output
4
Input
4
1 2 3 4
2 3 4 5
Output
-1
Input
5
5 6 5 2 1
9817 1108 6890 4343 8704
Output
25
Submitted Solution:
```
n=int(input())
A=[int(i) for i in input().split()]
B=[int(i) for i in input().split()]
from heapq import heappop, heappush
push = lambda x,i: heappush(BB,(-x,i))
BB=[]
for i in range(n):
push(B[i],i)
ans=0
while BB:
b,ind=heappop(BB)
b,ai=-b,A[ind]
if b<ai:
ans=-1
break
d=B[(ind-1)%n]+B[(ind+1)%n]
dd=(b-ai)//d
if dd==0:
if b==ai:
continue
ans=-1
break
ans+=dd
B[ind]-=d*dd
push(B[ind],ind)
print(ans)
``` | instruction | 0 | 4,010 | 5 | 8,020 |
No | output | 1 | 4,010 | 5 | 8,021 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N positive integers arranged in a circle.
Now, the i-th number is A_i. Takahashi wants the i-th number to be B_i. For this objective, he will repeatedly perform the following operation:
* Choose an integer i such that 1 \leq i \leq N.
* Let a, b, c be the (i-1)-th, i-th, and (i+1)-th numbers, respectively. Replace the i-th number with a+b+c.
Here the 0-th number is the N-th number, and the (N+1)-th number is the 1-st number.
Determine if Takahashi can achieve his objective. If the answer is yes, find the minimum number of operations required.
Constraints
* 3 \leq N \leq 2 \times 10^5
* 1 \leq A_i, B_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
B_1 B_2 ... B_N
Output
Print the minimum number of operations required, or `-1` if the objective cannot be achieved.
Examples
Input
3
1 1 1
13 5 7
Output
4
Input
4
1 2 3 4
2 3 4 5
Output
-1
Input
5
5 6 5 2 1
9817 1108 6890 4343 8704
Output
25
Submitted Solution:
```
N = int(input())
A = list(map(int, input().split()))
B = list(map(int, input().split()))
maxA = max(A)
cnt = 0
while 1:
maxB = 0
maxB_ind = -1
for i, b in enumerate(B):
if maxB < b:
maxB_ind = i
maxB = b
if maxB <= maxA:
if A==B: print(cnt)
else: print(-1)
exit()
if maxB_ind==0:
cnt += B[maxB_ind]//(B[1]+B[-1])
if cnt==0:
print(-1)
exit()
B[maxB_ind] %= (B[1]+B[-1])
elif maxB_ind==N-1:
cnt += B[maxB_ind]//(B[0]+B[maxB_ind-1])
if cnt==0:
print(-1)
exit()
B[maxB_ind] %= (B[0]+B[maxB_ind-1])
else:
cnt += B[maxB_ind]//(B[maxB_ind-1]+B[maxB_ind+1])
if cnt==0:
print(-1)
exit()
B[maxB_ind] %= (B[maxB_ind-1]+B[maxB_ind+1])
``` | instruction | 0 | 4,011 | 5 | 8,022 |
No | output | 1 | 4,011 | 5 | 8,023 |
Provide a correct Python 3 solution for this coding contest problem.
Matrix of given integers
a1,1 a1,2 ... a1, n
a2,1 a2,2 ... a2, n
::
an, 1 an, 2 ... an, n
Then, create a program that outputs the maximum value of the sum of one or more consecutive terms (submatrix) in the vertical and horizontal directions and ends.
Input
The input data is given in the following format.
n
a1,1 a1,2 ... a1, n
a2,1 a2,2 ... a2, n
::
an, 1 an, 2 ... an, n
n is 1 or more and 100 or less, and ai, j is -10000 or more and 10000 or less.
Output
Print the maximum value on one line.
Examples
Input
3
1 -2 3
-4 5 6
7 8 -9
Output
16
Input
4
1 3 -9 2
2 7 -1 5
-8 3 2 -1
5 0 -3 1
Output
15 | instruction | 0 | 4,092 | 5 | 8,184 |
"Correct Solution:
```
n = int(input())
s = [[0 for i in range(n + 1)] for j in range(n + 1)]
for r in range(n):
inp = list(map(int, input().split()))
for c in range(n):
s[r + 1][c + 1] = inp[c] + s[r][c + 1]
ans = -10001
for r_end in range(1, n + 1):
for r_start in range(r_end):
dp = [-10001]
for c in range(1, n + 1):
s_tmp = s[r_end][c] - s[r_start][c]
dp.append(max(dp[c - 1] + s_tmp, s_tmp))
ans = max(ans, max(dp))
print(ans)
``` | output | 1 | 4,092 | 5 | 8,185 |
Provide a correct Python 3 solution for this coding contest problem.
Matrix of given integers
a1,1 a1,2 ... a1, n
a2,1 a2,2 ... a2, n
::
an, 1 an, 2 ... an, n
Then, create a program that outputs the maximum value of the sum of one or more consecutive terms (submatrix) in the vertical and horizontal directions and ends.
Input
The input data is given in the following format.
n
a1,1 a1,2 ... a1, n
a2,1 a2,2 ... a2, n
::
an, 1 an, 2 ... an, n
n is 1 or more and 100 or less, and ai, j is -10000 or more and 10000 or less.
Output
Print the maximum value on one line.
Examples
Input
3
1 -2 3
-4 5 6
7 8 -9
Output
16
Input
4
1 3 -9 2
2 7 -1 5
-8 3 2 -1
5 0 -3 1
Output
15 | instruction | 0 | 4,093 | 5 | 8,186 |
"Correct Solution:
```
import sys
readline = sys.stdin.readline
write = sys.stdout.write
def solve():
N = int(readline())
A = [list(map(int, readline().split())) for i in range(N)]
B = [[0]*(N+1) for i in range(N+1)]
for i in range(N):
c = 0
Ai = A[i]
Bi = B[i]
Bj = B[i+1]
for j in range(N):
Bj[j+1] = Bi[j+1] + Ai[j]
def gen():
for i0 in range(N):
Ba = B[i0]
for i1 in range(i0+1, N+1):
Bb = B[i1]
mi = su = 0
for j in range(N):
su += Bb[j+1] - Ba[j+1]
yield su - mi
mi = min(mi, su)
write("%d\n" % max(gen()))
solve()
``` | output | 1 | 4,093 | 5 | 8,187 |
Provide a correct Python 3 solution for this coding contest problem.
Matrix of given integers
a1,1 a1,2 ... a1, n
a2,1 a2,2 ... a2, n
::
an, 1 an, 2 ... an, n
Then, create a program that outputs the maximum value of the sum of one or more consecutive terms (submatrix) in the vertical and horizontal directions and ends.
Input
The input data is given in the following format.
n
a1,1 a1,2 ... a1, n
a2,1 a2,2 ... a2, n
::
an, 1 an, 2 ... an, n
n is 1 or more and 100 or less, and ai, j is -10000 or more and 10000 or less.
Output
Print the maximum value on one line.
Examples
Input
3
1 -2 3
-4 5 6
7 8 -9
Output
16
Input
4
1 3 -9 2
2 7 -1 5
-8 3 2 -1
5 0 -3 1
Output
15 | instruction | 0 | 4,094 | 5 | 8,188 |
"Correct Solution:
```
n = int(input())
a = [list(map(int, input().split())) for i in range(n)]
# ?????????
sum_v = [[0 for i in range(n)] for i in range(n + 1)]
for i in range(n):
c = 0
for j in range(n):
c += a[j][i]
sum_v[j+1][i] = c
ans = -10**9
for sr in range(n):
er = 0
for er in range(sr, n):
c = 0
for col in range(n):
c += sum_v[er+1][col] - sum_v[sr][col]
ans = max(ans, c)
if c < 0:
c = 0 # c????????¢ (a(?????°) + b < b????????????
print(ans)
``` | output | 1 | 4,094 | 5 | 8,189 |
Provide a correct Python 3 solution for this coding contest problem.
Matrix of given integers
a1,1 a1,2 ... a1, n
a2,1 a2,2 ... a2, n
::
an, 1 an, 2 ... an, n
Then, create a program that outputs the maximum value of the sum of one or more consecutive terms (submatrix) in the vertical and horizontal directions and ends.
Input
The input data is given in the following format.
n
a1,1 a1,2 ... a1, n
a2,1 a2,2 ... a2, n
::
an, 1 an, 2 ... an, n
n is 1 or more and 100 or less, and ai, j is -10000 or more and 10000 or less.
Output
Print the maximum value on one line.
Examples
Input
3
1 -2 3
-4 5 6
7 8 -9
Output
16
Input
4
1 3 -9 2
2 7 -1 5
-8 3 2 -1
5 0 -3 1
Output
15 | instruction | 0 | 4,095 | 5 | 8,190 |
"Correct Solution:
```
from itertools import accumulate
n = int(input())
mp = [list(map(int, input().split())) for _ in range(n)]
acc_arr = [list(accumulate([0] + line)) for line in mp]
ans = max([max(line) for line in mp])
for i in range(n + 1):
for j in range(i + 1, n + 1):
acc = 0
for k in range(n):
add = acc_arr[k][j] - acc_arr[k][i]
if acc + add > 0:
acc = acc + add
ans = max(acc, ans)
else:
acc = 0
print(ans)
``` | output | 1 | 4,095 | 5 | 8,191 |
Provide a correct Python 3 solution for this coding contest problem.
Matrix of given integers
a1,1 a1,2 ... a1, n
a2,1 a2,2 ... a2, n
::
an, 1 an, 2 ... an, n
Then, create a program that outputs the maximum value of the sum of one or more consecutive terms (submatrix) in the vertical and horizontal directions and ends.
Input
The input data is given in the following format.
n
a1,1 a1,2 ... a1, n
a2,1 a2,2 ... a2, n
::
an, 1 an, 2 ... an, n
n is 1 or more and 100 or less, and ai, j is -10000 or more and 10000 or less.
Output
Print the maximum value on one line.
Examples
Input
3
1 -2 3
-4 5 6
7 8 -9
Output
16
Input
4
1 3 -9 2
2 7 -1 5
-8 3 2 -1
5 0 -3 1
Output
15 | instruction | 0 | 4,096 | 5 | 8,192 |
"Correct Solution:
```
# AOJ 0098 Maximum Sum Sequence II
# Python3 2018.6.17 bal4u
#include <stdio.h>
a = [[0 for c in range(102)] for r in range(102)]
s = [[0 for c in range(102)] for r in range(102)]
n = int(input())
for r in range(n):
a[r] = list(map(int, input().split()))
for r in range(n):
for c in range(n): s[r][c+1] += s[r][c]+a[r][c]
ans = s[0][1];
for c in range(n):
for k in range(c+1, n+1):
t = 0
for r in range(n):
if t < 0: t = s[r][k]-s[r][c]
else: t += s[r][k]-s[r][c]
if t > ans: ans = t
print(ans)
``` | output | 1 | 4,096 | 5 | 8,193 |
Provide a correct Python 3 solution for this coding contest problem.
Matrix of given integers
a1,1 a1,2 ... a1, n
a2,1 a2,2 ... a2, n
::
an, 1 an, 2 ... an, n
Then, create a program that outputs the maximum value of the sum of one or more consecutive terms (submatrix) in the vertical and horizontal directions and ends.
Input
The input data is given in the following format.
n
a1,1 a1,2 ... a1, n
a2,1 a2,2 ... a2, n
::
an, 1 an, 2 ... an, n
n is 1 or more and 100 or less, and ai, j is -10000 or more and 10000 or less.
Output
Print the maximum value on one line.
Examples
Input
3
1 -2 3
-4 5 6
7 8 -9
Output
16
Input
4
1 3 -9 2
2 7 -1 5
-8 3 2 -1
5 0 -3 1
Output
15 | instruction | 0 | 4,097 | 5 | 8,194 |
"Correct Solution:
```
n=int(input())
dp=[[0]*(n) for _ in range(n)]
ans=-10**9
a=[list(map(int,input().split())) for i in range(n)]
for i in range(n):
s=[0]*101
for j in range(n):s[j+1]=s[j]+a[i][j]
for j in range(n):
for k in range(j,n):
dp[j][k]=max(dp[j][k],0)+s[k+1]-s[j]
ans=max(ans,dp[j][k])
print(ans)
``` | output | 1 | 4,097 | 5 | 8,195 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Matrix of given integers
a1,1 a1,2 ... a1, n
a2,1 a2,2 ... a2, n
::
an, 1 an, 2 ... an, n
Then, create a program that outputs the maximum value of the sum of one or more consecutive terms (submatrix) in the vertical and horizontal directions and ends.
Input
The input data is given in the following format.
n
a1,1 a1,2 ... a1, n
a2,1 a2,2 ... a2, n
::
an, 1 an, 2 ... an, n
n is 1 or more and 100 or less, and ai, j is -10000 or more and 10000 or less.
Output
Print the maximum value on one line.
Examples
Input
3
1 -2 3
-4 5 6
7 8 -9
Output
16
Input
4
1 3 -9 2
2 7 -1 5
-8 3 2 -1
5 0 -3 1
Output
15
Submitted Solution:
```
# -*- coding: utf-8 -*-
"""
http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0098
TLE n=85だと通らない
"""
import sys
from sys import stdin
from functools import lru_cache
input = stdin.readline
def calc_points(n, array):
# 右下から(x, y)までの長方形に含まれる値の和
global dp
for y in range(n - 1, -1, -1):
for x in range(n - 1, -1, -1):
dp[y][x] = dp[y+1][x] + dp[y][x+1] - dp[y+1][x+1] + array[y][x]
@lru_cache(maxsize=None)
def get_dp(y, x):
return dp[y][x]
def solve(n, array):
ans = 0
calc_points(n, array)
for sy in range(n + 1):
for sx in range(n + 1):
for ey in range(sy+1, n + 1):
for ex in range(sx+1, n + 1):
s1 = get_dp(sy, sx)
s2 = get_dp(sy, ex)
s3 = get_dp(ey, sx)
s4 = get_dp(ey, ex)
s = s1 - s2 - s3 + s4
if s > ans:
ans = s
return ans
dp = [[0] * (100 + 1) for _ in range(100 + 1)]
def main(args):
array = []
# n = 3
# array.append([1, -2, 3])
# array.append([-4, 5, 6])
# array.append([7, 8, -9])
n = int(input())
for _ in range(n):
array.append([int(x) for x in input().split()])
ans = solve(n, array)
print(ans)
if __name__ == '__main__':
main(sys.argv[1:])
``` | instruction | 0 | 4,098 | 5 | 8,196 |
No | output | 1 | 4,098 | 5 | 8,197 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Matrix of given integers
a1,1 a1,2 ... a1, n
a2,1 a2,2 ... a2, n
::
an, 1 an, 2 ... an, n
Then, create a program that outputs the maximum value of the sum of one or more consecutive terms (submatrix) in the vertical and horizontal directions and ends.
Input
The input data is given in the following format.
n
a1,1 a1,2 ... a1, n
a2,1 a2,2 ... a2, n
::
an, 1 an, 2 ... an, n
n is 1 or more and 100 or less, and ai, j is -10000 or more and 10000 or less.
Output
Print the maximum value on one line.
Examples
Input
3
1 -2 3
-4 5 6
7 8 -9
Output
16
Input
4
1 3 -9 2
2 7 -1 5
-8 3 2 -1
5 0 -3 1
Output
15
Submitted Solution:
```
n = int(input())
l = [[int(i) for i in input().split()] for j in range(n)]
m = -1000000000
for x1 in range(n):
for x2 in range(x1,n):
for y1 in range(n):
for y2 in range(y1,n):
s = 0
for x in range(x1,x2+1):
for y in range(y1,y2+1):
s += l[y][x]
if s > m:
m = s
print(m)
``` | instruction | 0 | 4,099 | 5 | 8,198 |
No | output | 1 | 4,099 | 5 | 8,199 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Matrix of given integers
a1,1 a1,2 ... a1, n
a2,1 a2,2 ... a2, n
::
an, 1 an, 2 ... an, n
Then, create a program that outputs the maximum value of the sum of one or more consecutive terms (submatrix) in the vertical and horizontal directions and ends.
Input
The input data is given in the following format.
n
a1,1 a1,2 ... a1, n
a2,1 a2,2 ... a2, n
::
an, 1 an, 2 ... an, n
n is 1 or more and 100 or less, and ai, j is -10000 or more and 10000 or less.
Output
Print the maximum value on one line.
Examples
Input
3
1 -2 3
-4 5 6
7 8 -9
Output
16
Input
4
1 3 -9 2
2 7 -1 5
-8 3 2 -1
5 0 -3 1
Output
15
Submitted Solution:
```
# -*- coding: utf-8 -*-
"""
http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0098
"""
import sys
from sys import stdin
input = stdin.readline
def calc_points(n, array):
# 右下から(x, y)までの長方形に含まれる値の和
dp = [[0] * (n + 1) for _ in range(n + 1)]
for y in range(n - 1, -1, -1):
for x in range(n - 1, -1, -1):
dp[y][x] = dp[y+1][x] + dp[y][x+1] - dp[y+1][x+1] + array[y][x]
return dp
def solve(n, array):
ans = []
dp = calc_points(n, array)
for sy in range(n + 1):
for sx in range(n + 1):
for ey in range(sy, n + 1):
for ex in range(sx, n + 1):
s1 = dp[sy][sx] # 右下から始点まで
s2 = dp[sy][ex] # 重なり部分
s3 = dp[ey][sx] # 重なり部分
s4 = dp[ey][ex] # 重なりの重なり部分
s = s1 - s2 -s3 + s4 # (sx, sy) - (ex, ey) 長方形の美味しさポイント
# area = abs(sy - ey) * abs(sx - ex) # 長方形の面積
ans.append(s)
return max(ans)
def main(args):
array = []
# n = 3
# array.append([1, -2, 3])
# array.append([-4, 5, 6])
# array.append([7, 8, -9])
n = int(input())
for _ in range(n):
array.append([int(x) for x in input().split()])
ans = solve(n, array)
print(ans)
if __name__ == '__main__':
main(sys.argv[1:])
``` | instruction | 0 | 4,100 | 5 | 8,200 |
No | output | 1 | 4,100 | 5 | 8,201 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Matrix of given integers
a1,1 a1,2 ... a1, n
a2,1 a2,2 ... a2, n
::
an, 1 an, 2 ... an, n
Then, create a program that outputs the maximum value of the sum of one or more consecutive terms (submatrix) in the vertical and horizontal directions and ends.
Input
The input data is given in the following format.
n
a1,1 a1,2 ... a1, n
a2,1 a2,2 ... a2, n
::
an, 1 an, 2 ... an, n
n is 1 or more and 100 or less, and ai, j is -10000 or more and 10000 or less.
Output
Print the maximum value on one line.
Examples
Input
3
1 -2 3
-4 5 6
7 8 -9
Output
16
Input
4
1 3 -9 2
2 7 -1 5
-8 3 2 -1
5 0 -3 1
Output
15
Submitted Solution:
```
# -*- coding: utf-8 -*-
"""
http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0098
"""
import sys
from sys import stdin
input = stdin.readline
def calc_points(n, array):
# 右下から(x, y)までの長方形に含まれる値の和
dp = [[0] * (n + 1) for _ in range(n + 1)]
for y in range(n - 1, -1, -1):
for x in range(n - 1, -1, -1):
dp[y][x] = dp[y+1][x] + dp[y][x+1] - dp[y+1][x+1] + array[y][x]
return dp
def solve(n, array):
ans = []
dp = calc_points(n, array)
for sy in range(n + 1):
for sx in range(n + 1):
for ey in range(sy+1, n + 1):
for ex in range(sx+1, n + 1):
s1 = dp[sy][sx] # 右下から始点まで
s2 = dp[sy][ex] # 重なり部分
s3 = dp[ey][sx] # 重なり部分
s4 = dp[ey][ex] # 重なりの重なり部分
s = s1 - s2 -s3 + s4 # (sx, sy) - (ex, ey) 長方形の美味しさポイント
# area = abs(sy - ey) * abs(sx - ex) # 長方形の面積
ans.append(s)
return max(ans)
def main(args):
array = []
# n = 3
# array.append([1, -2, 3])
# array.append([-4, 5, 6])
# array.append([7, 8, -9])
n = int(input())
for _ in range(n):
array.append([int(x) for x in input().split()])
ans = solve(n, array)
print(ans)
if __name__ == '__main__':
main(sys.argv[1:])
``` | instruction | 0 | 4,101 | 5 | 8,202 |
No | output | 1 | 4,101 | 5 | 8,203 |
Provide tags and a correct Python 3 solution for this coding contest problem.
<image>
Input
The input contains a single integer a (0 ≤ a ≤ 15).
Output
Output a single integer.
Example
Input
3
Output
13 | instruction | 0 | 4,210 | 5 | 8,420 |
Tags: bitmasks, brute force
Correct Solution:
```
n = int(input())
d = []
for i in range(4):
d.append(n % 2)
n //= 2
x = 1
for i in range(3,-1,-1):
d[i] ^= x
x &= d[i]
r = 0
for v in d[::-1]:
r = 2*r + v
print(r)
``` | output | 1 | 4,210 | 5 | 8,421 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
Input
The input contains a single integer a (0 ≤ a ≤ 15).
Output
Output a single integer.
Example
Input
3
Output
13
Submitted Solution:
```
n = int(input())
b = list(bin(n).split('b')[1])
l1 = list(['0']*(4-len(b))+b)
x = int(''.join(reversed(l1)),2)-1
if x < 0:
x = 15
y = list(bin(x).split('b')[1])
l2 = list(['0']*(4-len(y))+y)
print(int(''.join(reversed(l2)), 2))
``` | instruction | 0 | 4,215 | 5 | 8,430 |
Yes | output | 1 | 4,215 | 5 | 8,431 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
Input
The input contains a single integer a (0 ≤ a ≤ 15).
Output
Output a single integer.
Example
Input
3
Output
13
Submitted Solution:
```
import io, sys, atexit, os
import math as ma
from sys import exit
from decimal import Decimal as dec
from itertools import permutations
from itertools import combinations
def li ():
return list (map (int, input ().split ()))
def num ():
return map (int, input ().split ())
def nu ():
return int (input ())
def find_gcd ( x, y ):
while (y):
x, y = y, x % y
return x
def prod(n):
s=1
while(n!=0):
s=s*(n%10)
n=n//10
return s
def check(xp):
op=sorted(xp)
if(op==xp):
return True
mm = 1000000007
def solve ():
t = 1
for it in range (t):
n=nu()
xp=[ 15, 14, 12, 13, 8, 9, 10, 11, 0, 1, 2, 3, 4, 5, 6, 7, 16, 17]
print (xp [ n ])
continue
if(n<=7):
print(xp[n])
else:
if(n==8):
print(30)
if __name__ == "__main__":
solve ()
``` | instruction | 0 | 4,216 | 5 | 8,432 |
Yes | output | 1 | 4,216 | 5 | 8,433 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
Input
The input contains a single integer a (0 ≤ a ≤ 15).
Output
Output a single integer.
Example
Input
3
Output
13
Submitted Solution:
```
a=int(input());
if (a==0): print(15)
elif (a==1):print(14)
elif (a==4): print(8)
elif (a==5): print(9)
elif (a==7): print(11)
elif (a==6): print(10)
elif (a==8):print(0)
elif (a==9):print(1)
elif (a==10):print(2)
elif (a==11):print(3)
elif (a==12): print(4)
elif (a==13): print(5)
elif (a==14): print(6)
elif (a==15): print(7)
else: print('1'+str(a))
``` | instruction | 0 | 4,217 | 5 | 8,434 |
Yes | output | 1 | 4,217 | 5 | 8,435 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
Input
The input contains a single integer a (0 ≤ a ≤ 15).
Output
Output a single integer.
Example
Input
3
Output
13
Submitted Solution:
```
N = int(input())
if N:
S = bin(N)[2:]
S = '0' * (4-len(S)) + S
Z = 0
for I in range(4):
if S[I] == '1':
Z += 2**I
S = bin(Z-1)[2:]
S = '0' * (4 - len(S)) + S
Z = 0
for I in range(4):
if S[I] == '1':
Z += 2**I
print(Z)
else:
print(15)
``` | instruction | 0 | 4,218 | 5 | 8,436 |
Yes | output | 1 | 4,218 | 5 | 8,437 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
Input
The input contains a single integer a (0 ≤ a ≤ 15).
Output
Output a single integer.
Example
Input
3
Output
13
Submitted Solution:
```
k=int(input())
y=0
for i in range(k):
y+=k
print(y+k+1)
``` | instruction | 0 | 4,219 | 5 | 8,438 |
No | output | 1 | 4,219 | 5 | 8,439 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
Input
The input contains a single integer a (0 ≤ a ≤ 15).
Output
Output a single integer.
Example
Input
3
Output
13
Submitted Solution:
```
N = int(input())
if N == 3:
print(13)
elif N == 0:
print(15)
elif N == 1:
print(14)
elif N == 2:
print(12)
elif N == 4:
print(9)
``` | instruction | 0 | 4,220 | 5 | 8,440 |
No | output | 1 | 4,220 | 5 | 8,441 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
Input
The input contains a single integer a (0 ≤ a ≤ 15).
Output
Output a single integer.
Example
Input
3
Output
13
Submitted Solution:
```
N = int(input())
def calc(n):
if n == 3: return 13
if n == 0: return 15
if n == 1: return 14
if n == 2: return 12
if n == 4: return 8
if n == 5: return 7
return 1/0
print(calc(N))
``` | instruction | 0 | 4,221 | 5 | 8,442 |
No | output | 1 | 4,221 | 5 | 8,443 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
Input
The input contains a single integer a (0 ≤ a ≤ 15).
Output
Output a single integer.
Example
Input
3
Output
13
Submitted Solution:
```
mas = [2] * 16
mas[4] = 8
mas[2] = 12
mas[3] = 13
mas[1] = 14
mas[0] = 15
print(mas[int(input())])
``` | instruction | 0 | 4,222 | 5 | 8,444 |
No | output | 1 | 4,222 | 5 | 8,445 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence of positive integers a1, a2, ..., an. Find all such indices i, that the i-th element equals the arithmetic mean of all other elements (that is all elements except for this one).
Input
The first line contains the integer n (2 ≤ n ≤ 2·105). The second line contains elements of the sequence a1, a2, ..., an (1 ≤ ai ≤ 1000). All the elements are positive integers.
Output
Print on the first line the number of the sought indices. Print on the second line the sought indices in the increasing order. All indices are integers from 1 to n.
If the sought elements do not exist, then the first output line should contain number 0. In this case you may either not print the second line or print an empty line.
Examples
Input
5
1 2 3 4 5
Output
1
3
Input
4
50 50 50 50
Output
4
1 2 3 4
Submitted Solution:
```
#!/usr/bin/env python
def main( ):
n = int( input( ) )
a = list( map( int, input( ).split( ) ) )
s = sum( a )
res = list( )
for i in range( len( a ) ):
if ( s - a[ i ] ) / ( n - 1 ) == a[ i ]:
res.append( i + 1 )
print( len( res ) )
if len( res ) > 0:
print( " ".join( map( str, res ) ) )
if __name__ == '__main__':
main( )
``` | instruction | 0 | 4,344 | 5 | 8,688 |
Yes | output | 1 | 4,344 | 5 | 8,689 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence of positive integers a1, a2, ..., an. Find all such indices i, that the i-th element equals the arithmetic mean of all other elements (that is all elements except for this one).
Input
The first line contains the integer n (2 ≤ n ≤ 2·105). The second line contains elements of the sequence a1, a2, ..., an (1 ≤ ai ≤ 1000). All the elements are positive integers.
Output
Print on the first line the number of the sought indices. Print on the second line the sought indices in the increasing order. All indices are integers from 1 to n.
If the sought elements do not exist, then the first output line should contain number 0. In this case you may either not print the second line or print an empty line.
Examples
Input
5
1 2 3 4 5
Output
1
3
Input
4
50 50 50 50
Output
4
1 2 3 4
Submitted Solution:
```
n = int(input())
num = list(map(int, input().split()))
count = []
sm = sum(num)
#print(sm)
for i in range(n):
if (sm-num[i])/(n-1) == num[i]: count.append(i+1)
print(len(count))
for i in range(len(count)):
print(count[i], end=" ")
``` | instruction | 0 | 4,345 | 5 | 8,690 |
Yes | output | 1 | 4,345 | 5 | 8,691 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence of positive integers a1, a2, ..., an. Find all such indices i, that the i-th element equals the arithmetic mean of all other elements (that is all elements except for this one).
Input
The first line contains the integer n (2 ≤ n ≤ 2·105). The second line contains elements of the sequence a1, a2, ..., an (1 ≤ ai ≤ 1000). All the elements are positive integers.
Output
Print on the first line the number of the sought indices. Print on the second line the sought indices in the increasing order. All indices are integers from 1 to n.
If the sought elements do not exist, then the first output line should contain number 0. In this case you may either not print the second line or print an empty line.
Examples
Input
5
1 2 3 4 5
Output
1
3
Input
4
50 50 50 50
Output
4
1 2 3 4
Submitted Solution:
```
n=int(input())
a=list(map(int,input().split()))
v=sum(a)
ans=0
b=[]
for i in range(n):
if(v-a[i])/(n-1)==a[i]:
ans+=1
b.append(i+1)
print(ans)
print(*b)
``` | instruction | 0 | 4,346 | 5 | 8,692 |
Yes | output | 1 | 4,346 | 5 | 8,693 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence of positive integers a1, a2, ..., an. Find all such indices i, that the i-th element equals the arithmetic mean of all other elements (that is all elements except for this one).
Input
The first line contains the integer n (2 ≤ n ≤ 2·105). The second line contains elements of the sequence a1, a2, ..., an (1 ≤ ai ≤ 1000). All the elements are positive integers.
Output
Print on the first line the number of the sought indices. Print on the second line the sought indices in the increasing order. All indices are integers from 1 to n.
If the sought elements do not exist, then the first output line should contain number 0. In this case you may either not print the second line or print an empty line.
Examples
Input
5
1 2 3 4 5
Output
1
3
Input
4
50 50 50 50
Output
4
1 2 3 4
Submitted Solution:
```
n=int(input())
a=list(map(int,input().split()))
s,ans=sum(a),[]
for i in range(n):
if (s-a[i])/(n-1)==a[i]:
ans.append(i+1)
print(*ans)
``` | instruction | 0 | 4,347 | 5 | 8,694 |
No | output | 1 | 4,347 | 5 | 8,695 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence of positive integers a1, a2, ..., an. Find all such indices i, that the i-th element equals the arithmetic mean of all other elements (that is all elements except for this one).
Input
The first line contains the integer n (2 ≤ n ≤ 2·105). The second line contains elements of the sequence a1, a2, ..., an (1 ≤ ai ≤ 1000). All the elements are positive integers.
Output
Print on the first line the number of the sought indices. Print on the second line the sought indices in the increasing order. All indices are integers from 1 to n.
If the sought elements do not exist, then the first output line should contain number 0. In this case you may either not print the second line or print an empty line.
Examples
Input
5
1 2 3 4 5
Output
1
3
Input
4
50 50 50 50
Output
4
1 2 3 4
Submitted Solution:
```
import sys
n = int(input())
s = [*map(int,sys.stdin.readline().split())]
su = sum(s)
ch = 0
a = []
for i in range(n):
if (su-s[i])//(n-1)==s[i]:
ch +=1
a.append(i+1)
print(ch)
print(*a)
``` | instruction | 0 | 4,348 | 5 | 8,696 |
No | output | 1 | 4,348 | 5 | 8,697 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence of positive integers a1, a2, ..., an. Find all such indices i, that the i-th element equals the arithmetic mean of all other elements (that is all elements except for this one).
Input
The first line contains the integer n (2 ≤ n ≤ 2·105). The second line contains elements of the sequence a1, a2, ..., an (1 ≤ ai ≤ 1000). All the elements are positive integers.
Output
Print on the first line the number of the sought indices. Print on the second line the sought indices in the increasing order. All indices are integers from 1 to n.
If the sought elements do not exist, then the first output line should contain number 0. In this case you may either not print the second line or print an empty line.
Examples
Input
5
1 2 3 4 5
Output
1
3
Input
4
50 50 50 50
Output
4
1 2 3 4
Submitted Solution:
```
n=int(input())
l=list(map(int,input().split()))
a=[]
c=0
s=sum(l)
for i in range(0,n):
if(l[i]==((s-l[i])//(n-1))):
c+=1
a.append(i+1)
print(c)
for i in a:
print(i,end=" ")
``` | instruction | 0 | 4,349 | 5 | 8,698 |
No | output | 1 | 4,349 | 5 | 8,699 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence of positive integers a1, a2, ..., an. Find all such indices i, that the i-th element equals the arithmetic mean of all other elements (that is all elements except for this one).
Input
The first line contains the integer n (2 ≤ n ≤ 2·105). The second line contains elements of the sequence a1, a2, ..., an (1 ≤ ai ≤ 1000). All the elements are positive integers.
Output
Print on the first line the number of the sought indices. Print on the second line the sought indices in the increasing order. All indices are integers from 1 to n.
If the sought elements do not exist, then the first output line should contain number 0. In this case you may either not print the second line or print an empty line.
Examples
Input
5
1 2 3 4 5
Output
1
3
Input
4
50 50 50 50
Output
4
1 2 3 4
Submitted Solution:
```
n=int(input())
a=list(map(int,input().split()))
p=[]
s=sum(a)
for i in range(n):
if (s-a[i])//(n-1)==a[i]:
p.append(i+1)
print(len(p))
print(*p)
``` | instruction | 0 | 4,350 | 5 | 8,700 |
No | output | 1 | 4,350 | 5 | 8,701 |
Provide a correct Python 3 solution for this coding contest problem.
There is a blackboard on which all integers from -10^{18} through 10^{18} are written, each of them appearing once. Takahashi will repeat the following sequence of operations any number of times he likes, possibly zero:
* Choose an integer between 1 and N (inclusive) that is written on the blackboard. Let x be the chosen integer, and erase x.
* If x-2 is not written on the blackboard, write x-2 on the blackboard.
* If x+K is not written on the blackboard, write x+K on the blackboard.
Find the number of possible sets of integers written on the blackboard after some number of operations, modulo M. We consider two sets different when there exists an integer contained in only one of the sets.
Constraints
* 1 \leq K\leq N \leq 150
* 10^8\leq M\leq 10^9
* N, K, and M are integers.
Input
Input is given from Standard Input in the following format:
N K M
Output
Print the number of possible sets of integers written on the blackboard after some number of operations, modulo M.
Examples
Input
3 1 998244353
Output
7
Input
6 3 998244353
Output
61
Input
9 4 702443618
Output
312
Input
17 7 208992811
Output
128832
Input
123 45 678901234
Output
256109226 | instruction | 0 | 4,857 | 5 | 9,714 |
"Correct Solution:
```
N, K, M = map(int, input().split())
# limitの最大値（limitなし）
L = (N+1)//2+1
def even(n, k) :
# dp[iまでみた][前のj個が連続]
dp = [[0] * (k+1) for _ in range(n+1)]
dp[0][0] = 1
for i in range(n) :
for j in range(k + 1) :
dp[i+1][0] = (dp[i+1][0] + dp[i][j]) % M
# 直前にK個連続しているときは追加できない
if j != k :
dp[i+1][j+1] = (dp[i+1][j+1] + dp[i][j]) % M
return sum(dp[n]) % M
def loop(x, y) :
return (2*x >= K+1 and 2*y >= K+3)
if K % 2 == 0 :
print(even(N//2, K//2) * even((N+1)//2, K//2) % M)
else :
# dp[x][y][z]
# iとパリティが異なる列がx個連続、iとパリティが同じ列がy個連続でかつxとyのどちらかをzまで伸ばせる組み合わせ
dp0 = [[[0]*(L+1) for _ in range(L+1)] for _ in range(L+1)]
dp0[0][0][L] = 1
for i in range(N) :
dp1 = [[[0]*(L+1) for _ in range(L+1)] for _ in range(L+1)]
for x in range(L+1) :
for y in range(L+1) :
if loop(x, y) : continue
for z in range(max(x, y)+1, L+1) :
if dp0[x][y][z] == 0 :
continue
dp1[y][x+1][z] += dp0[x][y][z]
dp1[y][x+1][z] %= M
# zの更新
# (1) y > x のときはzを引き継ぎ y <= x のときはLにリセット
# (2) ↖ みたいな矢印が引ける時 つまり 2*y >= K+3 and x > 0の時
# y - x + K//2 + 1 と (1)との最小値に更新
if y > x :
zz = z
else :
zz = L
if 2*y >= K+3 and x > 0 :
zz = min(zz, 1+y-x+K//2)
dp1[y][0][zz] += dp0[x][y][z]
dp1[y][0][zz] %= M
dp0 = dp1
ret = 0
for x in range(L+1) :
for y in range(L+1) :
if loop(x, y) : continue
for z in range(max(x, y)+1, L+1) :
ret += dp0[x][y][z]
ret %= M
print(ret)
``` | output | 1 | 4,857 | 5 | 9,715 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a blackboard on which all integers from -10^{18} through 10^{18} are written, each of them appearing once. Takahashi will repeat the following sequence of operations any number of times he likes, possibly zero:
* Choose an integer between 1 and N (inclusive) that is written on the blackboard. Let x be the chosen integer, and erase x.
* If x-2 is not written on the blackboard, write x-2 on the blackboard.
* If x+K is not written on the blackboard, write x+K on the blackboard.
Find the number of possible sets of integers written on the blackboard after some number of operations, modulo M. We consider two sets different when there exists an integer contained in only one of the sets.
Constraints
* 1 \leq K\leq N \leq 150
* 10^8\leq M\leq 10^9
* N, K, and M are integers.
Input
Input is given from Standard Input in the following format:
N K M
Output
Print the number of possible sets of integers written on the blackboard after some number of operations, modulo M.
Examples
Input
3 1 998244353
Output
7
Input
6 3 998244353
Output
61
Input
9 4 702443618
Output
312
Input
17 7 208992811
Output
128832
Input
123 45 678901234
Output
256109226
Submitted Solution:
```
import itertools
N, K, M = map(int, input().split(" "))
all_set = set()
seq = [i for i in range(1, N+1)]
all_set.add(tuple(seq))
for i in range(1, N+1):
l_ls = list(itertools.permutations(seq,i))
for l_tp in l_ls:
t = set([i for i in range(-1, N+K+1)])
for l in l_tp:
t.remove(l)
t.add(l-2)
t.add(l+K)
all_set.add(tuple(sorted(list(t))))
print(len(all_set) % M)
``` | instruction | 0 | 4,858 | 5 | 9,716 |
No | output | 1 | 4,858 | 5 | 9,717 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi had a pair of two positive integers not exceeding N, (a,b), which he has forgotten. He remembers that the remainder of a divided by b was greater than or equal to K. Find the number of possible pairs that he may have had.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq K \leq N-1
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N K
Output
Print the number of possible pairs that he may have had.
Examples
Input
5 2
Output
7
Input
10 0
Output
100
Input
31415 9265
Output
287927211 | instruction | 0 | 4,875 | 5 | 9,750 |
"Correct Solution:
```
n,k=map(int,input().split())
ans=0
if k==0:
print(n*n)
exit()
for i in range(k+1,n+1):
ans+=(i-k)*(n//i)
if n-i*(n//i)-k+1>0:
ans+=n-i*(n//i)-k+1
# print(ans,i)
print(ans)
``` | output | 1 | 4,875 | 5 | 9,751 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi had a pair of two positive integers not exceeding N, (a,b), which he has forgotten. He remembers that the remainder of a divided by b was greater than or equal to K. Find the number of possible pairs that he may have had.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq K \leq N-1
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N K
Output
Print the number of possible pairs that he may have had.
Examples
Input
5 2
Output
7
Input
10 0
Output
100
Input
31415 9265
Output
287927211 | instruction | 0 | 4,876 | 5 | 9,752 |
"Correct Solution:
```
n,k=map(int,input().split())
ans=0
for b in range(1,n+1):
p=n//b
r=n-p*b
ans+=p*max(b-k,0)+max(0,r-k+1)
if k==0:
ans-=n
print(ans)
``` | output | 1 | 4,876 | 5 | 9,753 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi had a pair of two positive integers not exceeding N, (a,b), which he has forgotten. He remembers that the remainder of a divided by b was greater than or equal to K. Find the number of possible pairs that he may have had.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq K \leq N-1
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N K
Output
Print the number of possible pairs that he may have had.
Examples
Input
5 2
Output
7
Input
10 0
Output
100
Input
31415 9265
Output
287927211 | instruction | 0 | 4,877 | 5 | 9,754 |
"Correct Solution:
```
N,K=map(int,input().split())
if K==0:
print(N**2)
exit(0)
ans=0
for i in range(K+1,N+1):
base=i-(K-1)-1
ans+=(N//i)*base
rest=N%i
ans+=max(rest-(K-1),0)
print(ans)
``` | output | 1 | 4,877 | 5 | 9,755 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi had a pair of two positive integers not exceeding N, (a,b), which he has forgotten. He remembers that the remainder of a divided by b was greater than or equal to K. Find the number of possible pairs that he may have had.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq K \leq N-1
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N K
Output
Print the number of possible pairs that he may have had.
Examples
Input
5 2
Output
7
Input
10 0
Output
100
Input
31415 9265
Output
287927211 | instruction | 0 | 4,878 | 5 | 9,756 |
"Correct Solution:
```
n, k = map(int,input().split())
num = 0
for b in range(k+1,n+1):
c = n%b
num += (n//b)*(b-k) + max(0,c-k+1)
if k == 0:
num -= 1
print(num)
``` | output | 1 | 4,878 | 5 | 9,757 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi had a pair of two positive integers not exceeding N, (a,b), which he has forgotten. He remembers that the remainder of a divided by b was greater than or equal to K. Find the number of possible pairs that he may have had.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq K \leq N-1
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N K
Output
Print the number of possible pairs that he may have had.
Examples
Input
5 2
Output
7
Input
10 0
Output
100
Input
31415 9265
Output
287927211 | instruction | 0 | 4,879 | 5 | 9,758 |
"Correct Solution:
```
def main():
n,k = map(int,input().split())
ans = 0
for b in range(k+1,n+1):
ans += ((n//b)*max(0,b-k)+max(0,(n%b)-k+1))
if k == 0:
ans -= n
print(ans)
main()
``` | output | 1 | 4,879 | 5 | 9,759 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi had a pair of two positive integers not exceeding N, (a,b), which he has forgotten. He remembers that the remainder of a divided by b was greater than or equal to K. Find the number of possible pairs that he may have had.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq K \leq N-1
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N K
Output
Print the number of possible pairs that he may have had.
Examples
Input
5 2
Output
7
Input
10 0
Output
100
Input
31415 9265
Output
287927211 | instruction | 0 | 4,880 | 5 | 9,760 |
"Correct Solution:
```
N,K=map(int,input().split())
def f(b):
d=max(b-K,0)*(N//b)+max(N%b-K+1,0)
return d
ans=0
if K==0:
print(N**2)
exit()
for i in range(1,N+1):
ans+=(f(i))
print(ans)
``` | output | 1 | 4,880 | 5 | 9,761 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi had a pair of two positive integers not exceeding N, (a,b), which he has forgotten. He remembers that the remainder of a divided by b was greater than or equal to K. Find the number of possible pairs that he may have had.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq K \leq N-1
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N K
Output
Print the number of possible pairs that he may have had.
Examples
Input
5 2
Output
7
Input
10 0
Output
100
Input
31415 9265
Output
287927211 | instruction | 0 | 4,881 | 5 | 9,762 |
"Correct Solution:
```
N,K=map(int, input().split())
ans=0
for b in range(K+1,N+1):
ans += (b-K)*(N//b)
ans += max(0, N%b + (1 - K if K!=0 else 0))
print(ans)
``` | output | 1 | 4,881 | 5 | 9,763 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi had a pair of two positive integers not exceeding N, (a,b), which he has forgotten. He remembers that the remainder of a divided by b was greater than or equal to K. Find the number of possible pairs that he may have had.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq K \leq N-1
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N K
Output
Print the number of possible pairs that he may have had.
Examples
Input
5 2
Output
7
Input
10 0
Output
100
Input
31415 9265
Output
287927211 | instruction | 0 | 4,882 | 5 | 9,764 |
"Correct Solution:
```
n,k = map(int,input().split())
if(k==0):
print(n*n)
exit()
ans = 0
for i in range(k+1,n+1):
ans += (n//i) * (i-k)
ans += max(0, n%i-k+1)
print(ans)
``` | output | 1 | 4,882 | 5 | 9,765 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi had a pair of two positive integers not exceeding N, (a,b), which he has forgotten. He remembers that the remainder of a divided by b was greater than or equal to K. Find the number of possible pairs that he may have had.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq K \leq N-1
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N K
Output
Print the number of possible pairs that he may have had.
Examples
Input
5 2
Output
7
Input
10 0
Output
100
Input
31415 9265
Output
287927211
Submitted Solution:
```
import sys
N, K = map(int, input().split())
if K == 0:
print(N**2)
sys.exit()
ans = 0
for b in range(K+1,N+1):
peri, res = divmod(N,b)
ans += (b-K)*peri + max(0,res-K+1)
print(ans)
``` | instruction | 0 | 4,883 | 5 | 9,766 |
Yes | output | 1 | 4,883 | 5 | 9,767 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi had a pair of two positive integers not exceeding N, (a,b), which he has forgotten. He remembers that the remainder of a divided by b was greater than or equal to K. Find the number of possible pairs that he may have had.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq K \leq N-1
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N K
Output
Print the number of possible pairs that he may have had.
Examples
Input
5 2
Output
7
Input
10 0
Output
100
Input
31415 9265
Output
287927211
Submitted Solution:
```
N,K = map(int,input().split())
if K==0:
print(N*N)
exit()
ans = 0
for b in range(K+1,N+1):
d,m = divmod(N+1,b)
ans += (b-K)*d
ans += max(0, (m-1)-K+1)
print(ans)
``` | instruction | 0 | 4,884 | 5 | 9,768 |
Yes | output | 1 | 4,884 | 5 | 9,769 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi had a pair of two positive integers not exceeding N, (a,b), which he has forgotten. He remembers that the remainder of a divided by b was greater than or equal to K. Find the number of possible pairs that he may have had.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq K \leq N-1
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N K
Output
Print the number of possible pairs that he may have had.
Examples
Input
5 2
Output
7
Input
10 0
Output
100
Input
31415 9265
Output
287927211
Submitted Solution:
```
N, K = map(int, input().split())
if K == 0:
print(N**2)
exit()
ans = 0
for b in range(1, N+1):
if b <= K:
continue
ans += (N // b) * (b - K)
ans += max(0, N % b - K + 1)
print(ans)
``` | instruction | 0 | 4,885 | 5 | 9,770 |
Yes | output | 1 | 4,885 | 5 | 9,771 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi had a pair of two positive integers not exceeding N, (a,b), which he has forgotten. He remembers that the remainder of a divided by b was greater than or equal to K. Find the number of possible pairs that he may have had.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq K \leq N-1
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N K
Output
Print the number of possible pairs that he may have had.
Examples
Input
5 2
Output
7
Input
10 0
Output
100
Input
31415 9265
Output
287927211
Submitted Solution:
```
n,k=map(int,input().split())
ans=0
for i in range(n):
ans+=(n//(i+1))*max(0,i+1-k)+max(0,n%(i+1)-k+1)
if k>0:
print(ans)
else:
print(ans-n)
``` | instruction | 0 | 4,886 | 5 | 9,772 |
Yes | output | 1 | 4,886 | 5 | 9,773 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi had a pair of two positive integers not exceeding N, (a,b), which he has forgotten. He remembers that the remainder of a divided by b was greater than or equal to K. Find the number of possible pairs that he may have had.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq K \leq N-1
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N K
Output
Print the number of possible pairs that he may have had.
Examples
Input
5 2
Output
7
Input
10 0
Output
100
Input
31415 9265
Output
287927211
Submitted Solution:
```
n,k = map(int,input().split())
ans = 0
for i in range(k+1,n+1):
for j in range(1,n+1):
if j % i >= k:
ans +=1
print(ans)
``` | instruction | 0 | 4,887 | 5 | 9,774 |
No | output | 1 | 4,887 | 5 | 9,775 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi had a pair of two positive integers not exceeding N, (a,b), which he has forgotten. He remembers that the remainder of a divided by b was greater than or equal to K. Find the number of possible pairs that he may have had.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq K \leq N-1
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N K
Output
Print the number of possible pairs that he may have had.
Examples
Input
5 2
Output
7
Input
10 0
Output
100
Input
31415 9265
Output
287927211
Submitted Solution:
```
N, K = map(int, input().split())
ans = 0
for b in range(1, N+1):
block_K = max(0, b-K)
#print("b", b, "block_num", N//b, "block_K", block_K, "remain", (N+1)%b)
ans += block_K * ((N+1)//b) + max(0, (N+1)%b - K)
print(ans)
``` | instruction | 0 | 4,888 | 5 | 9,776 |
No | output | 1 | 4,888 | 5 | 9,777 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi had a pair of two positive integers not exceeding N, (a,b), which he has forgotten. He remembers that the remainder of a divided by b was greater than or equal to K. Find the number of possible pairs that he may have had.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq K \leq N-1
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N K
Output
Print the number of possible pairs that he may have had.
Examples
Input
5 2
Output
7
Input
10 0
Output
100
Input
31415 9265
Output
287927211
Submitted Solution:
```
n, k = map(int, input().split())
ans = 0
for i in range(1,n+1):
ans += max(0, (i-k) * (n // i)) + max(0, (n-(n//i)*i-1)-k+1)
print(ans)
``` | instruction | 0 | 4,889 | 5 | 9,778 |
No | output | 1 | 4,889 | 5 | 9,779 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi had a pair of two positive integers not exceeding N, (a,b), which he has forgotten. He remembers that the remainder of a divided by b was greater than or equal to K. Find the number of possible pairs that he may have had.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq K \leq N-1
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N K
Output
Print the number of possible pairs that he may have had.
Examples
Input
5 2
Output
7
Input
10 0
Output
100
Input
31415 9265
Output
287927211
Submitted Solution:
```
N,K = map(int,input().split())
ans = 0
if K == 0:
print(N**2)
exit()
for b in range(K+1,N+1): #bを一個ずつチェックK+1からNまで
amari = b-K
loop = N//b
nokori = max(N%b+1-K,0)
temp = loop*amari + nokori
print(b,amari,loop,nokori,temp)
ans += temp
print(ans)
``` | instruction | 0 | 4,890 | 5 | 9,780 |
No | output | 1 | 4,890 | 5 | 9,781 |
Provide a correct Python 3 solution for this coding contest problem.
B: AddMulSubDiv
Problem Statement
You have an array A of N integers. A_i denotes the i-th element of A.
You have to process one of the following queries Q times:
* Query 1: The query consists of non-negative integer x, and two positive integers s, t. For all the elements greater than or equal to x in A, you have to add s to the elements, and then multiply them by t. That is, an element with v (v \geq x) becomes t(v + s) after this query.
* Query 2: The query consists of non-negative integer x, and two positive integers s, t. For all the elements less than or equal to x in A, you have to subtract s from the elements, and then divide them by t. If the result is not an integer, you truncate it towards zero. That is, an element with v (v \leq x) becomes $\mathrm{trunc}$ ( \frac{v - s}{t} ) after this query, where $\mathrm{trunc}$ ( y ) is the integer obtained by truncating y towards zero.
* "Truncating towards zero" means converting a decimal number to an integer so that if x = 0.0 then 0 , otherwise an integer whose absolute value is the maximum integer no more than |x| and whose sign is same as x. For example, truncating 3.5 towards zero is 3, and truncating -2.8 towards zero is -2.
After applying Q queries one by one, how many elements in A are no less than L and no more than R?
Input
N Q L R
A_1 A_2 ... A_N
q_1 x_1 s_1 t_1
:
q_Q x_Q s_Q t_Q
* The first line contains four integers N, Q, L, and R. N is the number of elements in an integer array A, Q is the number of queries, and L and R specify the range of integers you want to count within after the queries.
* The second line consists of N integers, the i-th of which is the i-th element of A.
* The following Q lines represent information of queries. The j-th line of them corresponds to the j-th query and consists of four integers q_j, x_j, s_j, and t_j. Here, q_j = 1 stands for the j-th query is Query 1, and q_j = 2 stands for the j-th query is Query 2. x_j, s_j, and t_j are parameters used for the j-th query.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 1 \leq Q \leq 2 \times 10^5
* -2^{63} < L \leq R < 2^{63}
* 0 \leq |A_i| \leq 10^9
* q_j \in \\{ 1, 2 \\}
* 0 \leq x_j < 2^{63}
* 1 \leq s_j, t_j \leq 10^9
* Inputs consist only of integers.
* The absolute value of any element in the array dosen't exceed 2^{63} at any point during query processing.
Output
Output the number of elements in A that are no less than L and no more than R after processing all given queries in one line.
Sample Input 1
3 3 3 10
1 -2 3
1 2 2 3
2 20 1 3
2 1 20 5
Output for Sample Input 1
1
Example
Input
3 3 3 10
1 -2 3
1 2 2 3
2 20 1 3
2 1 20 5
Output
1 | instruction | 0 | 4,992 | 5 | 9,984 |
"Correct Solution:
```
import bisect
n,Q,L,R = map(int,input().split())
a = list(map(int,input().split()))
a.sort()
p = []
for i in range(Q):
p.append(tuple(map(int,input().split())))
def f(z):
for q,x,s,t in p:
if q == 1:
if z >= x:
z = t*(z+s)
else:
if z <= x:
if z-s < 0:
z = -(abs(z-s)//t)
else:
z = (z-s)//t
return z
ng = pow(2,63)
ok = -ng
for i in range(100):
mid = (ok+ng)//2
if f(mid) <= R:
ok = mid
else:
ng = mid
right = ok
ok = pow(2,63)
ng = -ok
for i in range(100):
mid = (ok+ng)//2
if f(mid) >= L:
ok = mid
else:
ng = mid
left = ok
k1 = bisect.bisect_left(a,left)
k2 = bisect.bisect_right(a,right)
print(k2-k1)
``` | output | 1 | 4,992 | 5 | 9,985 |
Provide a correct Python 3 solution for this coding contest problem.
B: AddMulSubDiv
Problem Statement
You have an array A of N integers. A_i denotes the i-th element of A.
You have to process one of the following queries Q times:
* Query 1: The query consists of non-negative integer x, and two positive integers s, t. For all the elements greater than or equal to x in A, you have to add s to the elements, and then multiply them by t. That is, an element with v (v \geq x) becomes t(v + s) after this query.
* Query 2: The query consists of non-negative integer x, and two positive integers s, t. For all the elements less than or equal to x in A, you have to subtract s from the elements, and then divide them by t. If the result is not an integer, you truncate it towards zero. That is, an element with v (v \leq x) becomes $\mathrm{trunc}$ ( \frac{v - s}{t} ) after this query, where $\mathrm{trunc}$ ( y ) is the integer obtained by truncating y towards zero.
* "Truncating towards zero" means converting a decimal number to an integer so that if x = 0.0 then 0 , otherwise an integer whose absolute value is the maximum integer no more than |x| and whose sign is same as x. For example, truncating 3.5 towards zero is 3, and truncating -2.8 towards zero is -2.
After applying Q queries one by one, how many elements in A are no less than L and no more than R?
Input
N Q L R
A_1 A_2 ... A_N
q_1 x_1 s_1 t_1
:
q_Q x_Q s_Q t_Q
* The first line contains four integers N, Q, L, and R. N is the number of elements in an integer array A, Q is the number of queries, and L and R specify the range of integers you want to count within after the queries.
* The second line consists of N integers, the i-th of which is the i-th element of A.
* The following Q lines represent information of queries. The j-th line of them corresponds to the j-th query and consists of four integers q_j, x_j, s_j, and t_j. Here, q_j = 1 stands for the j-th query is Query 1, and q_j = 2 stands for the j-th query is Query 2. x_j, s_j, and t_j are parameters used for the j-th query.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 1 \leq Q \leq 2 \times 10^5
* -2^{63} < L \leq R < 2^{63}
* 0 \leq |A_i| \leq 10^9
* q_j \in \\{ 1, 2 \\}
* 0 \leq x_j < 2^{63}
* 1 \leq s_j, t_j \leq 10^9
* Inputs consist only of integers.
* The absolute value of any element in the array dosen't exceed 2^{63} at any point during query processing.
Output
Output the number of elements in A that are no less than L and no more than R after processing all given queries in one line.
Sample Input 1
3 3 3 10
1 -2 3
1 2 2 3
2 20 1 3
2 1 20 5
Output for Sample Input 1
1
Example
Input
3 3 3 10
1 -2 3
1 2 2 3
2 20 1 3
2 1 20 5
Output
1 | instruction | 0 | 4,993 | 5 | 9,986 |
"Correct Solution:
```
#!usr/bin/env python3
from collections import defaultdict,deque
from heapq import heappush, heappop
import sys
import math
import bisect
import random
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def I(): return int(sys.stdin.readline())
def LS():return [list(x) for x in sys.stdin.readline().split()]
def S():
res = list(sys.stdin.readline())
if res[-1] == "\n":
return res[:-1]
return res
def IR(n):
return [I() for i in range(n)]
def LIR(n):
return [LI() for i in range(n)]
def SR(n):
return [S() for i in range(n)]
def LSR(n):
return [LS() for i in range(n)]
sys.setrecursionlimit(1000000)
mod = 1000000007
#A
def A():
n = I()
a = LI()
s = sum([i%2 for i in a])
if s in (0,n):
print(0)
else:
print(n-2+(s%2))
return
#B
def B():
n,Q,L,R = LI()
a = LI()
a.sort()
query = LIR(Q)
l = -1
r = n
while r-l > 1:
m = (l+r)>>1
am = a[m]
for q,x,s,t in query:
if q == 1:
if am < x:
continue
am += s
am *= t
else:
if am > x:
continue
am -= s
if am < 0:
am = -((-am)//t)
else:
am //= t
if am < L:
l = m
else:
r = m
left = r
l = 0
r = n
while r-l > 1:
m = (l+r)>>1
am = a[m]
for q,x,s,t in query:
if q == 1:
if am < x:
continue
am += s
am *= t
else:
if am > x:
continue
am -= s
if am < 0:
am = -((-am)//t)
else:
am //= t
if am <= R:
l = m
else:
r = m
print(r-left)
return
#C
def C():
n = I()
return
#D
def D():
n = I()
return
#E
def E():
n = I()
return
#F
def F():
n = I()
return
#G
def G():
n = I()
return
#H
def H():
n = I()
return
#I
def I_():
n = I()
return
#J
def J():
n = I()
return
#Solve
if __name__ == "__main__":
B()
``` | output | 1 | 4,993 | 5 | 9,987 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given one integer number n. Find three distinct integers a, b, c such that 2 ≤ a, b, c and a ⋅ b ⋅ c = n or say that it is impossible to do it.
If there are several answers, you can print any.
You have to answer t independent test cases.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
The next n lines describe test cases. The i-th test case is given on a new line as one integer n (2 ≤ n ≤ 10^9).
Output
For each test case, print the answer on it. Print "NO" if it is impossible to represent n as a ⋅ b ⋅ c for some distinct integers a, b, c such that 2 ≤ a, b, c.
Otherwise, print "YES" and any possible such representation.
Example
Input
5
64
32
97
2
12345
Output
YES
2 4 8
NO
NO
NO
YES
3 5 823
Submitted Solution:
```
import math
for p in range(int(input())):
num=int(input())
b=[]
a=num
for i in range(2,int(math.sqrt(num))+1):
if(len(b)<2):
if(a%i==0):
b.append(int(i))
a/=i
else:
break
if((a not in b) and (len(b)==2)):
print('YES')
print(str(b[0])+' '+str(b[1])+' '+str(int(a)))
else:
print('NO')
``` | instruction | 0 | 5,169 | 5 | 10,338 |
Yes | output | 1 | 5,169 | 5 | 10,339 |
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