message stringlengths 2 23.4k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 129 108k | cluster float64 6 6 | __index_level_0__ int64 258 216k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
Eudokimus, a system administrator is in trouble again. As a result of an error in some script, a list of names of very important files has been damaged. Since they were files in the BerFS file system, it is known that each file name has a form "name.ext", where:
* name is a string consisting of lowercase Latin letters, its length is from 1 to 8 characters;
* ext is a string consisting of lowercase Latin letters, its length is from 1 to 3 characters.
For example, "read.me", "example.txt" and "b.cpp" are valid file names and "version.info", "ntldr" and "contestdata.zip" are not.
Damage to the list meant that all the file names were recorded one after another, without any separators. So now Eudokimus has a single string.
Eudokimus needs to set everything right as soon as possible. He should divide the resulting string into parts so that each part would be a valid file name in BerFS. Since Eudokimus has already proved that he is not good at programming, help him. The resulting file list can contain the same file names.
Input
The input data consists of a single string s, its length is from 1 to 4Β·105 characters. The string can contain only lowercase Latin letters ('a' - 'z') and periods ('.').
Output
In the first line print "YES" (without the quotes), if it is possible to divide s into parts as required. In this case, the following lines should contain the parts of the required partition, one per line in the order in which they appear in s. The required partition can contain the same file names. If there are multiple solutions, print any of them.
If the solution does not exist, then print in a single line "NO" (without the quotes).
Examples
Input
read.meexample.txtb.cpp
Output
YES
read.m
eexample.t
xtb.cpp
Input
version.infontldrcontestdata.zip
Output
NO | instruction | 0 | 96,378 | 6 | 192,756 |
Tags: dp, greedy, implementation
Correct Solution:
```
#############<------------ Xorcestor_X ---------------->############
from math import *
def is_even(p):
n=len(p)
count=0
for i in range(n):
index=p.index(i,i,n)
if i==index:
pass
else:
count+=1
temp=p[i]
p[i]=p[index]
p[index]=temp
# print(p)
if count%2==0:
return True
else:
return False
prime=[]
def SieveOfEratosthenes():
global prime
prime=[1]*2000010
prime[1]=0
p=2
while p*p<=2000001:
if prime[p]:
for i in range(p*p,2000002,p):
prime[i]=0
lpf=[]
def precompute():
global lpf
lpf=[0]*1000001
for i in range(2,1000001):
if not lpf[i]:
for j in range(i,1000001,i):
if not lpf[j]:
lpf[j]=i
def binpow(a,b):
res=1
while b>0:
if b&1:
res*=a
a*=a
b>>=1
return res
def modpow(a,b,x):
res=1
while b>0:
if b&1:
res*=a
res%=x
a*=a
a%=x
b>>=1
return res
cont=[]
def f(x):
global cont
total=0
for i in cont:
total+=abs(i-x)
return total
def bs(low,high,target):
while low+3<high:
mid=(low+high)/2
if arr[mid]<target:
low=mid
else:
high=mid-1
for i in range(high,low-1,-1):
if arr[o]<target:
return i
return -1
def ternary_search(l,r):
while r-l>10:
m1=l+(r-l)/3
m2=r-(r-l)/3
f1=f(m1)
f2=f(m2)
if f1>f2:
l=m1
else:
r=m2
mino=f(l)
for i in range(l,r+1):
mino=min(mino,f(i))
return mino
s=input()
l=s.split('.')
n=len(l)
if n==0 or n==1:
print('NO')
quit()
glob=[]
b=True
if len(l[0])>8 or len(l[0])==0:
b=False
if len(l[-1])>3 or len(l[-1])==0:
b=False
if n==1:
if b:
print("YES")
print(s)
quit()
else:
print("NO")
quit()
glob.append(l[0]+'.')
for i in range(1,n-1):
if 2<=len(l[i])<=11:
if len(l[i])<=9:
glob[i-1]+=l[i][0:1]
glob.append(l[i][1:]+'.')
else:
glob[i-1]+=l[i][0:-8]
glob.append(l[i][-8:]+'.')
else:
b=False
break
glob[-1]+=l[-1]
if b:
print('YES')
for a in glob:
print(a)
else:
print('NO')
``` | output | 1 | 96,378 | 6 | 192,757 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Eudokimus, a system administrator is in trouble again. As a result of an error in some script, a list of names of very important files has been damaged. Since they were files in the BerFS file system, it is known that each file name has a form "name.ext", where:
* name is a string consisting of lowercase Latin letters, its length is from 1 to 8 characters;
* ext is a string consisting of lowercase Latin letters, its length is from 1 to 3 characters.
For example, "read.me", "example.txt" and "b.cpp" are valid file names and "version.info", "ntldr" and "contestdata.zip" are not.
Damage to the list meant that all the file names were recorded one after another, without any separators. So now Eudokimus has a single string.
Eudokimus needs to set everything right as soon as possible. He should divide the resulting string into parts so that each part would be a valid file name in BerFS. Since Eudokimus has already proved that he is not good at programming, help him. The resulting file list can contain the same file names.
Input
The input data consists of a single string s, its length is from 1 to 4Β·105 characters. The string can contain only lowercase Latin letters ('a' - 'z') and periods ('.').
Output
In the first line print "YES" (without the quotes), if it is possible to divide s into parts as required. In this case, the following lines should contain the parts of the required partition, one per line in the order in which they appear in s. The required partition can contain the same file names. If there are multiple solutions, print any of them.
If the solution does not exist, then print in a single line "NO" (without the quotes).
Examples
Input
read.meexample.txtb.cpp
Output
YES
read.m
eexample.t
xtb.cpp
Input
version.infontldrcontestdata.zip
Output
NO | instruction | 0 | 96,379 | 6 | 192,758 |
Tags: dp, greedy, implementation
Correct Solution:
```
# ========= /\ /| |====/|
# | / \ | | / |
# | /____\ | | / |
# | / \ | | / |
# ========= / \ ===== |/====|
# code
def main():
s = input()
a = list(s.split('.'))
# print(a)
if len(a) == 1:
print('NO')
return
if '' in a:
print('NO')
return
if len(a[0]) > 8:
print('NO')
return
if len(a[-1]) > 3:
print('NO')
return
for i in range(1 , len(a)-1):
if len(a[i]) > 11 or len(a[i]) <= 1:
print('NO')
return
print('YES')
print(a[0],end='.')
for i in range(1,len(a)-1):
if len(a[i]) > 3:
print(a[i][:3])
print(a[i][3:] , end='.')
else:
print(a[i][0])
print(a[i][1:] , end = '.')
print(a[-1])
return
if __name__ == "__main__":
main()
``` | output | 1 | 96,379 | 6 | 192,759 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Input
The input contains a single integer a (1 β€ a β€ 40).
Output
Output a single string.
Examples
Input
2
Output
Adams
Input
8
Output
Van Buren
Input
29
Output
Harding | instruction | 0 | 96,440 | 6 | 192,880 |
Tags: *special, implementation
Correct Solution:
```
pres = ["Washington",
"Adams",
"Jefferson",
"Madison",
"Monroe",
"Adams",
"Jackson",
"Van Buren",
"Harrison",
"Tyler",
"Polk",
"Taylor",
"Fillmore",
"Pierce",
"Buchanan",
"Lincoln",
"Johnson",
"Grant",
"Hayes",
"Garfield",
"Arthur",
"Cleveland",
"Harrison",
"Cleveland",
"McKinley",
"Roosevelt",
"Taft",
"Wilson",
"Harding",
"Coolidge",
"Hoover",
"Roosevelt",
"Truman",
"Eisenhower",
"Kennedy",
"Johnson",
"Nixon",
"Ford",
"Carter",
"Reagan",
"Bush",
"Clinton",
"Bush",
"Obama",
"Trump",
"Biden"]
print(pres[int(input())-1])
``` | output | 1 | 96,440 | 6 | 192,881 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Input
The input contains a single integer a (1 β€ a β€ 40).
Output
Output a single string.
Examples
Input
2
Output
Adams
Input
8
Output
Van Buren
Input
29
Output
Harding | instruction | 0 | 96,441 | 6 | 192,882 |
Tags: *special, implementation
Correct Solution:
```
n=int(input())
if (n == 1) :
print ("Washington")
elif (n == 2):
print ("Adams")
elif (n == 3):
print ("Jefferson")
elif (n == 4):
print ("Madison")
elif (n == 5):
print ("Monroe")
elif (n == 6):
print ("Adams")
elif (n == 7):
print ("Jackson")
elif (n == 8):
print ("Van Buren")
elif (n == 9):
print("Harrison")
elif (n == 10):
print("Tyler")
elif (n == 11):
print("Polk")
elif (n == 12):
print("Taylor")
elif (n == 13):
print("Fillmore")
elif (n == 14):
print("Pierce")
elif (n == 15):
print("Buchanan")
elif (n == 16):
print ("Lincoln")
elif (n == 17):
print ("Johnson")
elif (n == 18):
print ("Grant")
elif (n == 19):
print ("Hayes")
elif (n == 20):
print ("Garfield")
elif (n == 21):
print ("Arthur")
elif (n == 22):
print ("Cleveland")
elif (n == 23):
print ("Harrison")
elif (n == 24):
print ("Cleveland")
elif (n == 25):
print ("McKinley")
elif (n == 26):
print ("Roosevelt")
elif (n == 27):
print ("Taft")
elif (n == 28):
print ("Wilson")
elif (n == 29):
print ('Harding')
elif (n == 30):
print ("Coolidge")
elif (n == 31):
print ("Hoover")
elif (n == 32):
print ("Roosevelt")
elif (n == 33):
print ("Truman")
elif (n == 34):
print ("Eisenhower")
elif (n == 35):
print ("Kennedy")
elif (n == 36):
print ("Johnson")
elif (n == 37):
print ("Nixon")
elif n == 38:
print ("Ford")
elif n == 39:
print ("Carter")
elif n == 40:
print ("Reagan")
``` | output | 1 | 96,441 | 6 | 192,883 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Input
The input contains a single integer a (1 β€ a β€ 40).
Output
Output a single string.
Examples
Input
2
Output
Adams
Input
8
Output
Van Buren
Input
29
Output
Harding | instruction | 0 | 96,442 | 6 | 192,884 |
Tags: *special, implementation
Correct Solution:
```
a = ['Washington', 'Adams', 'Jefferson', 'Madison', 'Monroe', 'Adams', 'Jackson', 'Van Buren', 'Harrison', 'Tyler', 'Polk', 'Taylor', 'Fillmore', 'Pierce', 'Buchanan', 'Lincoln', 'Johnson', 'Grant', 'Hayes', 'Garfield', 'Arthur', 'Cleveland', 'Harrison', 'Cleveland', 'McKinley', 'Roosevelt', 'Taft', 'Wilson', 'Harding', 'Coolidge', 'Hoover', 'Roosevelt', 'Truman', 'Eisenhower', 'Kennedy', 'Johnson', 'Nixon', 'Ford', 'Carter', 'Reagan', 'Bush', '']
print(a[int(input()) - 1])
``` | output | 1 | 96,442 | 6 | 192,885 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Special Agent Smart Beaver works in a secret research department of ABBYY. He's been working there for a long time and is satisfied with his job, as it allows him to eat out in the best restaurants and order the most expensive and exotic wood types there.
The content special agent has got an important task: to get the latest research by British scientists on the English Language. These developments are encoded and stored in a large safe. The Beaver's teeth are strong enough, so the authorities assured that upon arriving at the place the beaver won't have any problems with opening the safe.
And he finishes his aspen sprig and leaves for this important task. Of course, the Beaver arrived at the location without any problems, but alas. He can't open the safe with his strong and big teeth. At this point, the Smart Beaver get a call from the headquarters and learns that opening the safe with the teeth is not necessary, as a reliable source has sent the following information: the safe code consists of digits and has no leading zeroes. There also is a special hint, which can be used to open the safe. The hint is string s with the following structure:
* if si = "?", then the digit that goes i-th in the safe code can be anything (between 0 to 9, inclusively);
* if si is a digit (between 0 to 9, inclusively), then it means that there is digit si on position i in code;
* if the string contains letters from "A" to "J", then all positions with the same letters must contain the same digits and the positions with distinct letters must contain distinct digits.
* The length of the safe code coincides with the length of the hint.
For example, hint "?JGJ9" has such matching safe code variants: "51919", "55959", "12329", "93539" and so on, and has wrong variants such as: "56669", "00111", "03539" and "13666".
After receiving such information, the authorities change the plan and ask the special agents to work quietly and gently and not to try to open the safe by mechanical means, and try to find the password using the given hint.
At a special agent school the Smart Beaver was the fastest in his platoon finding codes for such safes, but now he is not in that shape: the years take their toll ... Help him to determine the number of possible variants of the code to the safe, matching the given hint. After receiving this information, and knowing his own speed of entering codes, the Smart Beaver will be able to determine whether he will have time for tonight's show "Beavers are on the trail" on his favorite TV channel, or he should work for a sleepless night...
Input
The first line contains string s β the hint to the safe code. String s consists of the following characters: ?, 0-9, A-J. It is guaranteed that the first character of string s doesn't equal to character 0.
The input limits for scoring 30 points are (subproblem A1):
* 1 β€ |s| β€ 5.
The input limits for scoring 100 points are (subproblems A1+A2):
* 1 β€ |s| β€ 105.
Here |s| means the length of string s.
Output
Print the number of codes that match the given hint.
Examples
Input
AJ
Output
81
Input
1?AA
Output
100 | instruction | 0 | 96,454 | 6 | 192,908 |
Tags: greedy
Correct Solution:
```
s = input()
z = set()
us = 0
ans = 1
if s[0] == '?' or (s[0] >= 'A' and s[0] <= 'J'):
ans = 9
z.add(s[0])
if s[0] >= 'A' and s[0] <= 'J':
us += 1
i = -1
for x in s:
i += 1
if i == 0:
continue
if x == '?':
ans *= 10
if x >= 'A' and x <= 'J':
if x not in z:
ans *= (10 - us)
z.add(x)
us += 1
print(ans)
``` | output | 1 | 96,454 | 6 | 192,909 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Special Agent Smart Beaver works in a secret research department of ABBYY. He's been working there for a long time and is satisfied with his job, as it allows him to eat out in the best restaurants and order the most expensive and exotic wood types there.
The content special agent has got an important task: to get the latest research by British scientists on the English Language. These developments are encoded and stored in a large safe. The Beaver's teeth are strong enough, so the authorities assured that upon arriving at the place the beaver won't have any problems with opening the safe.
And he finishes his aspen sprig and leaves for this important task. Of course, the Beaver arrived at the location without any problems, but alas. He can't open the safe with his strong and big teeth. At this point, the Smart Beaver get a call from the headquarters and learns that opening the safe with the teeth is not necessary, as a reliable source has sent the following information: the safe code consists of digits and has no leading zeroes. There also is a special hint, which can be used to open the safe. The hint is string s with the following structure:
* if si = "?", then the digit that goes i-th in the safe code can be anything (between 0 to 9, inclusively);
* if si is a digit (between 0 to 9, inclusively), then it means that there is digit si on position i in code;
* if the string contains letters from "A" to "J", then all positions with the same letters must contain the same digits and the positions with distinct letters must contain distinct digits.
* The length of the safe code coincides with the length of the hint.
For example, hint "?JGJ9" has such matching safe code variants: "51919", "55959", "12329", "93539" and so on, and has wrong variants such as: "56669", "00111", "03539" and "13666".
After receiving such information, the authorities change the plan and ask the special agents to work quietly and gently and not to try to open the safe by mechanical means, and try to find the password using the given hint.
At a special agent school the Smart Beaver was the fastest in his platoon finding codes for such safes, but now he is not in that shape: the years take their toll ... Help him to determine the number of possible variants of the code to the safe, matching the given hint. After receiving this information, and knowing his own speed of entering codes, the Smart Beaver will be able to determine whether he will have time for tonight's show "Beavers are on the trail" on his favorite TV channel, or he should work for a sleepless night...
Input
The first line contains string s β the hint to the safe code. String s consists of the following characters: ?, 0-9, A-J. It is guaranteed that the first character of string s doesn't equal to character 0.
The input limits for scoring 30 points are (subproblem A1):
* 1 β€ |s| β€ 5.
The input limits for scoring 100 points are (subproblems A1+A2):
* 1 β€ |s| β€ 105.
Here |s| means the length of string s.
Output
Print the number of codes that match the given hint.
Examples
Input
AJ
Output
81
Input
1?AA
Output
100 | instruction | 0 | 96,455 | 6 | 192,910 |
Tags: greedy
Correct Solution:
```
s = input()
ans = 1
l = list('ABCDEFGHIJ')
if s[0] == "?":
ans *= 9
elif s[0] in l:
ans *= 9
l.remove(s[0])
for i in s[1:]:
if i == "?":
ans *= 10
elif i in l:
ans *= len(l)
l.remove(i)
print(ans)
``` | output | 1 | 96,455 | 6 | 192,911 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Special Agent Smart Beaver works in a secret research department of ABBYY. He's been working there for a long time and is satisfied with his job, as it allows him to eat out in the best restaurants and order the most expensive and exotic wood types there.
The content special agent has got an important task: to get the latest research by British scientists on the English Language. These developments are encoded and stored in a large safe. The Beaver's teeth are strong enough, so the authorities assured that upon arriving at the place the beaver won't have any problems with opening the safe.
And he finishes his aspen sprig and leaves for this important task. Of course, the Beaver arrived at the location without any problems, but alas. He can't open the safe with his strong and big teeth. At this point, the Smart Beaver get a call from the headquarters and learns that opening the safe with the teeth is not necessary, as a reliable source has sent the following information: the safe code consists of digits and has no leading zeroes. There also is a special hint, which can be used to open the safe. The hint is string s with the following structure:
* if si = "?", then the digit that goes i-th in the safe code can be anything (between 0 to 9, inclusively);
* if si is a digit (between 0 to 9, inclusively), then it means that there is digit si on position i in code;
* if the string contains letters from "A" to "J", then all positions with the same letters must contain the same digits and the positions with distinct letters must contain distinct digits.
* The length of the safe code coincides with the length of the hint.
For example, hint "?JGJ9" has such matching safe code variants: "51919", "55959", "12329", "93539" and so on, and has wrong variants such as: "56669", "00111", "03539" and "13666".
After receiving such information, the authorities change the plan and ask the special agents to work quietly and gently and not to try to open the safe by mechanical means, and try to find the password using the given hint.
At a special agent school the Smart Beaver was the fastest in his platoon finding codes for such safes, but now he is not in that shape: the years take their toll ... Help him to determine the number of possible variants of the code to the safe, matching the given hint. After receiving this information, and knowing his own speed of entering codes, the Smart Beaver will be able to determine whether he will have time for tonight's show "Beavers are on the trail" on his favorite TV channel, or he should work for a sleepless night...
Input
The first line contains string s β the hint to the safe code. String s consists of the following characters: ?, 0-9, A-J. It is guaranteed that the first character of string s doesn't equal to character 0.
The input limits for scoring 30 points are (subproblem A1):
* 1 β€ |s| β€ 5.
The input limits for scoring 100 points are (subproblems A1+A2):
* 1 β€ |s| β€ 105.
Here |s| means the length of string s.
Output
Print the number of codes that match the given hint.
Examples
Input
AJ
Output
81
Input
1?AA
Output
100 | instruction | 0 | 96,456 | 6 | 192,912 |
Tags: greedy
Correct Solution:
```
s = str(input())
result = 1
n = len(s)
rozne = set()
pytajniki = 0
mnoznik_z_pierwszego = 1
for i in range(0,n):
if ord(s[i]) >= ord('0') and ord(s[i]) <= ord('9'):
continue;
elif ord(s[i]) >= ord('A') and ord(s[i]) <= ord('Z'):
rozne.add(ord(s[i]))
continue
else:
if i == 0:
mnoznik_z_pierwszego = 9
else:
pytajniki = pytajniki + 1
for i in range(0, len(rozne)):
result = result * (10 - i)
result = result * mnoznik_z_pierwszego
if ord(s[0]) >= ord('A') and ord(s[0]) <= ord('Z'):
result = result / 10 * 9
print(int(result), end="")
for i in range(pytajniki):
print("0", end="")
print()
``` | output | 1 | 96,456 | 6 | 192,913 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Special Agent Smart Beaver works in a secret research department of ABBYY. He's been working there for a long time and is satisfied with his job, as it allows him to eat out in the best restaurants and order the most expensive and exotic wood types there.
The content special agent has got an important task: to get the latest research by British scientists on the English Language. These developments are encoded and stored in a large safe. The Beaver's teeth are strong enough, so the authorities assured that upon arriving at the place the beaver won't have any problems with opening the safe.
And he finishes his aspen sprig and leaves for this important task. Of course, the Beaver arrived at the location without any problems, but alas. He can't open the safe with his strong and big teeth. At this point, the Smart Beaver get a call from the headquarters and learns that opening the safe with the teeth is not necessary, as a reliable source has sent the following information: the safe code consists of digits and has no leading zeroes. There also is a special hint, which can be used to open the safe. The hint is string s with the following structure:
* if si = "?", then the digit that goes i-th in the safe code can be anything (between 0 to 9, inclusively);
* if si is a digit (between 0 to 9, inclusively), then it means that there is digit si on position i in code;
* if the string contains letters from "A" to "J", then all positions with the same letters must contain the same digits and the positions with distinct letters must contain distinct digits.
* The length of the safe code coincides with the length of the hint.
For example, hint "?JGJ9" has such matching safe code variants: "51919", "55959", "12329", "93539" and so on, and has wrong variants such as: "56669", "00111", "03539" and "13666".
After receiving such information, the authorities change the plan and ask the special agents to work quietly and gently and not to try to open the safe by mechanical means, and try to find the password using the given hint.
At a special agent school the Smart Beaver was the fastest in his platoon finding codes for such safes, but now he is not in that shape: the years take their toll ... Help him to determine the number of possible variants of the code to the safe, matching the given hint. After receiving this information, and knowing his own speed of entering codes, the Smart Beaver will be able to determine whether he will have time for tonight's show "Beavers are on the trail" on his favorite TV channel, or he should work for a sleepless night...
Input
The first line contains string s β the hint to the safe code. String s consists of the following characters: ?, 0-9, A-J. It is guaranteed that the first character of string s doesn't equal to character 0.
The input limits for scoring 30 points are (subproblem A1):
* 1 β€ |s| β€ 5.
The input limits for scoring 100 points are (subproblems A1+A2):
* 1 β€ |s| β€ 105.
Here |s| means the length of string s.
Output
Print the number of codes that match the given hint.
Examples
Input
AJ
Output
81
Input
1?AA
Output
100 | instruction | 0 | 96,457 | 6 | 192,914 |
Tags: greedy
Correct Solution:
```
import math
'''
r,c,n,k = map(int,input().split())
matrix = [['*' for row in range(c)] for column in range(r)]
for i in range(n):
x,y = map(int,input().split())
matrix[x-1][y-1] = '#'
ans = 0
for row1 in range(r):
for row2 in range(r):
if matrix[row1:row2+1].count('#') >= k:
ans+=1
for column1 in range(c):
for column2 in range(column1,c):
count = 0
for row in range(r):
count+=matrix[r][column1:column2+1].count('#')
if count >=k:
ans+=1
print(ans)
'''
s = input()
ques = s[1:].count('?')
d = {'A':0,'B':0,'C':0,'D':0,'E':0,'F':0,'G':0,'H':0,'I':0,'J':0}
digit = set([str(i) for i in range(0,10)])
digit.add('?')
ans = 1
ans*=pow(10,ques)
count =0
for i in range(1,len(s)):
if s[i] not in digit and d[s[i]] == 0:
count+=1
d[s[i]] = 1
start = 10
if s[0] in d and d[s[0]] == 1:
count-=1
ans*=9
start = 9
if s[0] in d and d[s[0]] == 0:
ans*=9
start = 9
while count!=0:
ans*=start
start-=1
count-=1
if s[0] == '?':
ans*=9
print(ans)
``` | output | 1 | 96,457 | 6 | 192,915 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Special Agent Smart Beaver works in a secret research department of ABBYY. He's been working there for a long time and is satisfied with his job, as it allows him to eat out in the best restaurants and order the most expensive and exotic wood types there.
The content special agent has got an important task: to get the latest research by British scientists on the English Language. These developments are encoded and stored in a large safe. The Beaver's teeth are strong enough, so the authorities assured that upon arriving at the place the beaver won't have any problems with opening the safe.
And he finishes his aspen sprig and leaves for this important task. Of course, the Beaver arrived at the location without any problems, but alas. He can't open the safe with his strong and big teeth. At this point, the Smart Beaver get a call from the headquarters and learns that opening the safe with the teeth is not necessary, as a reliable source has sent the following information: the safe code consists of digits and has no leading zeroes. There also is a special hint, which can be used to open the safe. The hint is string s with the following structure:
* if si = "?", then the digit that goes i-th in the safe code can be anything (between 0 to 9, inclusively);
* if si is a digit (between 0 to 9, inclusively), then it means that there is digit si on position i in code;
* if the string contains letters from "A" to "J", then all positions with the same letters must contain the same digits and the positions with distinct letters must contain distinct digits.
* The length of the safe code coincides with the length of the hint.
For example, hint "?JGJ9" has such matching safe code variants: "51919", "55959", "12329", "93539" and so on, and has wrong variants such as: "56669", "00111", "03539" and "13666".
After receiving such information, the authorities change the plan and ask the special agents to work quietly and gently and not to try to open the safe by mechanical means, and try to find the password using the given hint.
At a special agent school the Smart Beaver was the fastest in his platoon finding codes for such safes, but now he is not in that shape: the years take their toll ... Help him to determine the number of possible variants of the code to the safe, matching the given hint. After receiving this information, and knowing his own speed of entering codes, the Smart Beaver will be able to determine whether he will have time for tonight's show "Beavers are on the trail" on his favorite TV channel, or he should work for a sleepless night...
Input
The first line contains string s β the hint to the safe code. String s consists of the following characters: ?, 0-9, A-J. It is guaranteed that the first character of string s doesn't equal to character 0.
The input limits for scoring 30 points are (subproblem A1):
* 1 β€ |s| β€ 5.
The input limits for scoring 100 points are (subproblems A1+A2):
* 1 β€ |s| β€ 105.
Here |s| means the length of string s.
Output
Print the number of codes that match the given hint.
Examples
Input
AJ
Output
81
Input
1?AA
Output
100 | instruction | 0 | 96,458 | 6 | 192,916 |
Tags: greedy
Correct Solution:
```
from sys import *
from math import *
s = stdin.readline().strip()
ans = 1
now = 10
was = {}
was['A'] = False
was['B'] = False
was['C'] = False
was['D'] = False
was['E'] = False
was['F'] = False
was['G'] = False
was['H'] = False
was['I'] = False
was['J'] = False
if s[0] == '?':
ans *= 9
if (ord(s[0]) >= ord('A')) and (ord(s[0]) <= ord('J')):
ans *= 9
was[s[0]] = True
now = 9
cnt = 0
for i in range(1, len(s)):
if s[i] == '?':
cnt += 1
if (ord(s[i]) >= ord('A')) and (ord(s[i]) <= ord('J')):
if was[s[i]] == False:
ans *= now
now -= 1
was[s[i]] = True
print(ans, end = "")
for i in range(cnt):
print('0', end = "")
print()
``` | output | 1 | 96,458 | 6 | 192,917 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Special Agent Smart Beaver works in a secret research department of ABBYY. He's been working there for a long time and is satisfied with his job, as it allows him to eat out in the best restaurants and order the most expensive and exotic wood types there.
The content special agent has got an important task: to get the latest research by British scientists on the English Language. These developments are encoded and stored in a large safe. The Beaver's teeth are strong enough, so the authorities assured that upon arriving at the place the beaver won't have any problems with opening the safe.
And he finishes his aspen sprig and leaves for this important task. Of course, the Beaver arrived at the location without any problems, but alas. He can't open the safe with his strong and big teeth. At this point, the Smart Beaver get a call from the headquarters and learns that opening the safe with the teeth is not necessary, as a reliable source has sent the following information: the safe code consists of digits and has no leading zeroes. There also is a special hint, which can be used to open the safe. The hint is string s with the following structure:
* if si = "?", then the digit that goes i-th in the safe code can be anything (between 0 to 9, inclusively);
* if si is a digit (between 0 to 9, inclusively), then it means that there is digit si on position i in code;
* if the string contains letters from "A" to "J", then all positions with the same letters must contain the same digits and the positions with distinct letters must contain distinct digits.
* The length of the safe code coincides with the length of the hint.
For example, hint "?JGJ9" has such matching safe code variants: "51919", "55959", "12329", "93539" and so on, and has wrong variants such as: "56669", "00111", "03539" and "13666".
After receiving such information, the authorities change the plan and ask the special agents to work quietly and gently and not to try to open the safe by mechanical means, and try to find the password using the given hint.
At a special agent school the Smart Beaver was the fastest in his platoon finding codes for such safes, but now he is not in that shape: the years take their toll ... Help him to determine the number of possible variants of the code to the safe, matching the given hint. After receiving this information, and knowing his own speed of entering codes, the Smart Beaver will be able to determine whether he will have time for tonight's show "Beavers are on the trail" on his favorite TV channel, or he should work for a sleepless night...
Input
The first line contains string s β the hint to the safe code. String s consists of the following characters: ?, 0-9, A-J. It is guaranteed that the first character of string s doesn't equal to character 0.
The input limits for scoring 30 points are (subproblem A1):
* 1 β€ |s| β€ 5.
The input limits for scoring 100 points are (subproblems A1+A2):
* 1 β€ |s| β€ 105.
Here |s| means the length of string s.
Output
Print the number of codes that match the given hint.
Examples
Input
AJ
Output
81
Input
1?AA
Output
100 | instruction | 0 | 96,459 | 6 | 192,918 |
Tags: greedy
Correct Solution:
```
import math
import string
s = input()
p = 0
for x in string.ascii_uppercase[:10]:
if x in s:
p += 1
ans = 0
r = s.count('?')
if s[0] == '?':
ans = 9 * pow(10, r - 1) * math.factorial(10) // math.factorial(10 - p)
elif s[0] in string.ascii_uppercase:
ans = 9 * pow(10, r) * math.factorial(9) // math.factorial(9 - p + 1)
else:
ans = pow(10, r) * math.factorial(10) // math.factorial(10 - p)
print(ans)
``` | output | 1 | 96,459 | 6 | 192,919 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Special Agent Smart Beaver works in a secret research department of ABBYY. He's been working there for a long time and is satisfied with his job, as it allows him to eat out in the best restaurants and order the most expensive and exotic wood types there.
The content special agent has got an important task: to get the latest research by British scientists on the English Language. These developments are encoded and stored in a large safe. The Beaver's teeth are strong enough, so the authorities assured that upon arriving at the place the beaver won't have any problems with opening the safe.
And he finishes his aspen sprig and leaves for this important task. Of course, the Beaver arrived at the location without any problems, but alas. He can't open the safe with his strong and big teeth. At this point, the Smart Beaver get a call from the headquarters and learns that opening the safe with the teeth is not necessary, as a reliable source has sent the following information: the safe code consists of digits and has no leading zeroes. There also is a special hint, which can be used to open the safe. The hint is string s with the following structure:
* if si = "?", then the digit that goes i-th in the safe code can be anything (between 0 to 9, inclusively);
* if si is a digit (between 0 to 9, inclusively), then it means that there is digit si on position i in code;
* if the string contains letters from "A" to "J", then all positions with the same letters must contain the same digits and the positions with distinct letters must contain distinct digits.
* The length of the safe code coincides with the length of the hint.
For example, hint "?JGJ9" has such matching safe code variants: "51919", "55959", "12329", "93539" and so on, and has wrong variants such as: "56669", "00111", "03539" and "13666".
After receiving such information, the authorities change the plan and ask the special agents to work quietly and gently and not to try to open the safe by mechanical means, and try to find the password using the given hint.
At a special agent school the Smart Beaver was the fastest in his platoon finding codes for such safes, but now he is not in that shape: the years take their toll ... Help him to determine the number of possible variants of the code to the safe, matching the given hint. After receiving this information, and knowing his own speed of entering codes, the Smart Beaver will be able to determine whether he will have time for tonight's show "Beavers are on the trail" on his favorite TV channel, or he should work for a sleepless night...
Input
The first line contains string s β the hint to the safe code. String s consists of the following characters: ?, 0-9, A-J. It is guaranteed that the first character of string s doesn't equal to character 0.
The input limits for scoring 30 points are (subproblem A1):
* 1 β€ |s| β€ 5.
The input limits for scoring 100 points are (subproblems A1+A2):
* 1 β€ |s| β€ 105.
Here |s| means the length of string s.
Output
Print the number of codes that match the given hint.
Examples
Input
AJ
Output
81
Input
1?AA
Output
100 | instruction | 0 | 96,460 | 6 | 192,920 |
Tags: greedy
Correct Solution:
```
s = input()
abc = [0] * 26
cnt1 = 0
cnt2 = 0
ans = 1
for i in range(len(s)):
if s[i] == '?':
if i == 0:
ans *= 9
else:
cnt2 += 1
elif (s[i] >= 'A') and (s[i] <= 'Z'):
if abc[(ord(s[i]) - ord('A'))] == 0:
if i == 0:
abc[(ord(s[i]) - ord('A'))] = 1
ans *= 9
cnt1 += 1
else:
abc[(ord(s[i]) - ord('A'))] = 1
ans *= (10 - cnt1)
cnt1 += 1
print(str(ans) + '0' * cnt2)
``` | output | 1 | 96,460 | 6 | 192,921 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Special Agent Smart Beaver works in a secret research department of ABBYY. He's been working there for a long time and is satisfied with his job, as it allows him to eat out in the best restaurants and order the most expensive and exotic wood types there.
The content special agent has got an important task: to get the latest research by British scientists on the English Language. These developments are encoded and stored in a large safe. The Beaver's teeth are strong enough, so the authorities assured that upon arriving at the place the beaver won't have any problems with opening the safe.
And he finishes his aspen sprig and leaves for this important task. Of course, the Beaver arrived at the location without any problems, but alas. He can't open the safe with his strong and big teeth. At this point, the Smart Beaver get a call from the headquarters and learns that opening the safe with the teeth is not necessary, as a reliable source has sent the following information: the safe code consists of digits and has no leading zeroes. There also is a special hint, which can be used to open the safe. The hint is string s with the following structure:
* if si = "?", then the digit that goes i-th in the safe code can be anything (between 0 to 9, inclusively);
* if si is a digit (between 0 to 9, inclusively), then it means that there is digit si on position i in code;
* if the string contains letters from "A" to "J", then all positions with the same letters must contain the same digits and the positions with distinct letters must contain distinct digits.
* The length of the safe code coincides with the length of the hint.
For example, hint "?JGJ9" has such matching safe code variants: "51919", "55959", "12329", "93539" and so on, and has wrong variants such as: "56669", "00111", "03539" and "13666".
After receiving such information, the authorities change the plan and ask the special agents to work quietly and gently and not to try to open the safe by mechanical means, and try to find the password using the given hint.
At a special agent school the Smart Beaver was the fastest in his platoon finding codes for such safes, but now he is not in that shape: the years take their toll ... Help him to determine the number of possible variants of the code to the safe, matching the given hint. After receiving this information, and knowing his own speed of entering codes, the Smart Beaver will be able to determine whether he will have time for tonight's show "Beavers are on the trail" on his favorite TV channel, or he should work for a sleepless night...
Input
The first line contains string s β the hint to the safe code. String s consists of the following characters: ?, 0-9, A-J. It is guaranteed that the first character of string s doesn't equal to character 0.
The input limits for scoring 30 points are (subproblem A1):
* 1 β€ |s| β€ 5.
The input limits for scoring 100 points are (subproblems A1+A2):
* 1 β€ |s| β€ 105.
Here |s| means the length of string s.
Output
Print the number of codes that match the given hint.
Examples
Input
AJ
Output
81
Input
1?AA
Output
100 | instruction | 0 | 96,461 | 6 | 192,922 |
Tags: greedy
Correct Solution:
```
I=input()
s=set()
r=I.count('?')
for x in I:
if ord(x)>64:s.add(x)
i=10
t=1
for _ in s:t*=i;i-=1
if r:t*=10;r-=1
if ord(I[0])>57:t=t//10*9
print(str(t)+'0'*r)
``` | output | 1 | 96,461 | 6 | 192,923 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has recently finished writing a book. Now he faces the problem of giving it the title. Vasya wants the title to be vague and mysterious for his book to be noticeable among others. That's why the title should be represented by a single word containing at least once each of the first k Latin letters and not containing any other ones. Also, the title should be a palindrome, that is it should be read similarly from the left to the right and from the right to the left.
Vasya has already composed the approximate variant of the title. You are given the title template s consisting of lowercase Latin letters and question marks. Your task is to replace all the question marks by lowercase Latin letters so that the resulting word satisfies the requirements, described above. Each question mark should be replaced by exactly one letter, it is not allowed to delete characters or add new ones to the template. If there are several suitable titles, choose the first in the alphabetical order, for Vasya's book to appear as early as possible in all the catalogues.
Input
The first line contains an integer k (1 β€ k β€ 26) which is the number of allowed alphabet letters. The second line contains s which is the given template. In s only the first k lowercase letters of Latin alphabet and question marks can be present, the length of s is from 1 to 100 characters inclusively.
Output
If there is no solution, print IMPOSSIBLE. Otherwise, a single line should contain the required title, satisfying the given template. The title should be a palindrome and it can only contain the first k letters of the Latin alphabet. At that, each of those k letters must be present at least once. If there are several suitable titles, print the lexicographically minimal one.
The lexicographical comparison is performed by the standard < operator in modern programming languages. The line a is lexicographically smaller than the line b, if exists such an i (1 β€ i β€ |s|), that ai < bi, and for any j (1 β€ j < i) aj = bj. |s| stands for the length of the given template.
Examples
Input
3
a?c
Output
IMPOSSIBLE
Input
2
a??a
Output
abba
Input
2
?b?a
Output
abba | instruction | 0 | 96,567 | 6 | 193,134 |
Tags: expression parsing
Correct Solution:
```
from sys import stdin
def main():
n = int(stdin.readline())
line = stdin.readline().strip()
i,j = 0,len(line)-1
ans = ["" for i in range(len(line))]
visited = [False for i in range(27)]
ok = True
for i in range(len(line)):
if(96< ord(line[i]) <123):
cont = ord(line[i])-97
visited[cont] = True
if cont > n:
ok = False
N = len(line)
if(N%2 != 0):
mid = N//2
i = mid-1
j = mid+1
if(line[mid] == "?"):
v = 0
while v < n:
if(not visited[n-v-1]):
ans[mid] = chr(n-v-1+97)
visited[n-v-1] = True
break
v+=1
if(ans[mid] == ""):
ans[mid] = "a"
else:
ans[mid]=line[mid]
else:
mid = N//2
i = mid-1
j = mid
while(j < len(line)):
#print(ans)
if(line[j] == "?" and line[i] != "?"):
ans[i] = line[i]
ans[j] = line[i]
visited[ord(line[i])-97] = True
elif(line[j] != "?" and line[i] == "?"):
ans[i] = line[j]
ans[j] = line[j]
visited[ord(line[j])-97] = True
elif(line[j] == "?" and line[i] == "?"):
v = 0
while v < n:
if(not visited[n-v-1]):
ans[i] = chr(n-v-1+97)
ans[j] = chr(n-v-1+97)
visited[n-v-1] = True
break
v+=1
if(ans[i] == ""):
ans[i] = "a"
ans[j] = "a"
elif(line[j] == line[i]):
ans[i]=line[j]
ans[j]=line[j]
visited[ord(line[j])-97] = True
else:
ok = False
j+=1
i-=1
w = 0
while w < n :
if(not visited[w]):
ok = False
w+=1
while w < len(visited) :
if(visited[w]):
ok = False
w+=1
#print(ans)
if(ok):
aux = ""
for k in range(len(ans)):
aux += ans[k]
print(aux)
else:
print("IMPOSSIBLE")
main()
``` | output | 1 | 96,567 | 6 | 193,135 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has recently finished writing a book. Now he faces the problem of giving it the title. Vasya wants the title to be vague and mysterious for his book to be noticeable among others. That's why the title should be represented by a single word containing at least once each of the first k Latin letters and not containing any other ones. Also, the title should be a palindrome, that is it should be read similarly from the left to the right and from the right to the left.
Vasya has already composed the approximate variant of the title. You are given the title template s consisting of lowercase Latin letters and question marks. Your task is to replace all the question marks by lowercase Latin letters so that the resulting word satisfies the requirements, described above. Each question mark should be replaced by exactly one letter, it is not allowed to delete characters or add new ones to the template. If there are several suitable titles, choose the first in the alphabetical order, for Vasya's book to appear as early as possible in all the catalogues.
Input
The first line contains an integer k (1 β€ k β€ 26) which is the number of allowed alphabet letters. The second line contains s which is the given template. In s only the first k lowercase letters of Latin alphabet and question marks can be present, the length of s is from 1 to 100 characters inclusively.
Output
If there is no solution, print IMPOSSIBLE. Otherwise, a single line should contain the required title, satisfying the given template. The title should be a palindrome and it can only contain the first k letters of the Latin alphabet. At that, each of those k letters must be present at least once. If there are several suitable titles, print the lexicographically minimal one.
The lexicographical comparison is performed by the standard < operator in modern programming languages. The line a is lexicographically smaller than the line b, if exists such an i (1 β€ i β€ |s|), that ai < bi, and for any j (1 β€ j < i) aj = bj. |s| stands for the length of the given template.
Examples
Input
3
a?c
Output
IMPOSSIBLE
Input
2
a??a
Output
abba
Input
2
?b?a
Output
abba | instruction | 0 | 96,568 | 6 | 193,136 |
Tags: expression parsing
Correct Solution:
```
import sys
from array import array # noqa: F401
def input():
return sys.stdin.buffer.readline().decode('utf-8')
k = int(input())
a = list(input().rstrip())
n = len(a)
unused = [1] * k
def ng():
print('IMPOSSIBLE')
exit()
try:
for i in range(n):
if a[i] == '?' and a[n - i - 1] != '?':
a[i] = a[n - i - 1]
if a[i] != '?':
unused[ord(a[i]) - 97] = 0
except IndexError:
ng()
for i in range(n):
if a[i] != a[n - i - 1]:
ng()
for i in range(n // 2, n):
if a[i] == '?':
for cc in range(k - 1, -1, -1):
if unused[cc]:
a[i] = a[n - i - 1] = chr(cc + 97)
unused[cc] = 0
break
else:
a[i] = a[n - i - 1] = 'a'
if any(unused):
ng()
print(*a, sep='')
``` | output | 1 | 96,568 | 6 | 193,137 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has recently finished writing a book. Now he faces the problem of giving it the title. Vasya wants the title to be vague and mysterious for his book to be noticeable among others. That's why the title should be represented by a single word containing at least once each of the first k Latin letters and not containing any other ones. Also, the title should be a palindrome, that is it should be read similarly from the left to the right and from the right to the left.
Vasya has already composed the approximate variant of the title. You are given the title template s consisting of lowercase Latin letters and question marks. Your task is to replace all the question marks by lowercase Latin letters so that the resulting word satisfies the requirements, described above. Each question mark should be replaced by exactly one letter, it is not allowed to delete characters or add new ones to the template. If there are several suitable titles, choose the first in the alphabetical order, for Vasya's book to appear as early as possible in all the catalogues.
Input
The first line contains an integer k (1 β€ k β€ 26) which is the number of allowed alphabet letters. The second line contains s which is the given template. In s only the first k lowercase letters of Latin alphabet and question marks can be present, the length of s is from 1 to 100 characters inclusively.
Output
If there is no solution, print IMPOSSIBLE. Otherwise, a single line should contain the required title, satisfying the given template. The title should be a palindrome and it can only contain the first k letters of the Latin alphabet. At that, each of those k letters must be present at least once. If there are several suitable titles, print the lexicographically minimal one.
The lexicographical comparison is performed by the standard < operator in modern programming languages. The line a is lexicographically smaller than the line b, if exists such an i (1 β€ i β€ |s|), that ai < bi, and for any j (1 β€ j < i) aj = bj. |s| stands for the length of the given template.
Examples
Input
3
a?c
Output
IMPOSSIBLE
Input
2
a??a
Output
abba
Input
2
?b?a
Output
abba | instruction | 0 | 96,569 | 6 | 193,138 |
Tags: expression parsing
Correct Solution:
```
a = [0]*26
k = int(input())
s = input()
sl = [i for i in s]
for i in s:
if(i!='?'):
a[ord(i)-97] = 1
for i in range(len(s)//2,len(s)):
if(s[i]=='?'):
if(s[len(s)-i-1] == '?'):
f = 0
for j in range(k-1,-1,-1):
if(a[j]!=1):
f = 1
sl.pop(i)
sl.insert(i,chr(j+97))
sl.pop(len(s)-i-1)
sl.insert(len(s)-i-1,chr(j+97))
a[j] = 1
break
if(not f):
sl.pop(i)
sl.insert(i,'a')
sl.pop(len(s)-i-1)
sl.insert(len(s)-i-1,'a')
else:
sl.pop(i)
sl.insert(i,s[len(s)-i-1])
else:
if(s[len(s)-i-1] == '?'):
sl.pop(len(s)-i-1)
sl.insert(len(s)-i-1,s[i])
#print(a)
for i in range(k):
if(a[i]==0):
print("IMPOSSIBLE")
exit(0)
for i in range(len(s)):
if(sl[i]=='?'):
sl.pop(i)
sl.insert(i,'a')
#print(sl)
if(sl == sl[::-1]):
ans = ''
for i in sl:
ans+=i
print(ans)
else:
print("IMPOSSIBLE")
``` | output | 1 | 96,569 | 6 | 193,139 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has recently finished writing a book. Now he faces the problem of giving it the title. Vasya wants the title to be vague and mysterious for his book to be noticeable among others. That's why the title should be represented by a single word containing at least once each of the first k Latin letters and not containing any other ones. Also, the title should be a palindrome, that is it should be read similarly from the left to the right and from the right to the left.
Vasya has already composed the approximate variant of the title. You are given the title template s consisting of lowercase Latin letters and question marks. Your task is to replace all the question marks by lowercase Latin letters so that the resulting word satisfies the requirements, described above. Each question mark should be replaced by exactly one letter, it is not allowed to delete characters or add new ones to the template. If there are several suitable titles, choose the first in the alphabetical order, for Vasya's book to appear as early as possible in all the catalogues.
Input
The first line contains an integer k (1 β€ k β€ 26) which is the number of allowed alphabet letters. The second line contains s which is the given template. In s only the first k lowercase letters of Latin alphabet and question marks can be present, the length of s is from 1 to 100 characters inclusively.
Output
If there is no solution, print IMPOSSIBLE. Otherwise, a single line should contain the required title, satisfying the given template. The title should be a palindrome and it can only contain the first k letters of the Latin alphabet. At that, each of those k letters must be present at least once. If there are several suitable titles, print the lexicographically minimal one.
The lexicographical comparison is performed by the standard < operator in modern programming languages. The line a is lexicographically smaller than the line b, if exists such an i (1 β€ i β€ |s|), that ai < bi, and for any j (1 β€ j < i) aj = bj. |s| stands for the length of the given template.
Examples
Input
3
a?c
Output
IMPOSSIBLE
Input
2
a??a
Output
abba
Input
2
?b?a
Output
abba | instruction | 0 | 96,570 | 6 | 193,140 |
Tags: expression parsing
Correct Solution:
```
import sys
k = int(input())
s = list(input())
used = [False] * k
for i in range(len(s)):
if '?' not in (s[i], s[-i - 1]) and \
s[i] != s[-i - 1]:
print('IMPOSSIBLE')
sys.exit(0)
if s[i] != '?':
if s[-i - 1] == '?':
s[-i - 1] = s[i]
used[ord(s[i]) - ord('a')] = True
if len(s) % 2 and s[len(s) // 2] == '?':
doUnused = True
for j in range(k - 1, -1, -1):
if not used[j]:
s[len(s) // 2] = chr(ord('a') + j)
used[j] = True
doUnused = False
break
if doUnused:
s[len(s) // 2] = 'a'
for i in range((len(s) - 2) // 2, -1, -1):
if s[i] == '?':
doUnused = True
for j in range(k - 1, -1, -1):
if not used[j]:
s[i] = chr(ord('a') + j)
s[-i - 1] = s[i]
used[j] = True
doUnused = False
break
if doUnused:
s[i] = 'a'
s[-i - 1] = 'a'
if not all(used):
print('IMPOSSIBLE')
else:
print(''.join(s))
``` | output | 1 | 96,570 | 6 | 193,141 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has recently finished writing a book. Now he faces the problem of giving it the title. Vasya wants the title to be vague and mysterious for his book to be noticeable among others. That's why the title should be represented by a single word containing at least once each of the first k Latin letters and not containing any other ones. Also, the title should be a palindrome, that is it should be read similarly from the left to the right and from the right to the left.
Vasya has already composed the approximate variant of the title. You are given the title template s consisting of lowercase Latin letters and question marks. Your task is to replace all the question marks by lowercase Latin letters so that the resulting word satisfies the requirements, described above. Each question mark should be replaced by exactly one letter, it is not allowed to delete characters or add new ones to the template. If there are several suitable titles, choose the first in the alphabetical order, for Vasya's book to appear as early as possible in all the catalogues.
Input
The first line contains an integer k (1 β€ k β€ 26) which is the number of allowed alphabet letters. The second line contains s which is the given template. In s only the first k lowercase letters of Latin alphabet and question marks can be present, the length of s is from 1 to 100 characters inclusively.
Output
If there is no solution, print IMPOSSIBLE. Otherwise, a single line should contain the required title, satisfying the given template. The title should be a palindrome and it can only contain the first k letters of the Latin alphabet. At that, each of those k letters must be present at least once. If there are several suitable titles, print the lexicographically minimal one.
The lexicographical comparison is performed by the standard < operator in modern programming languages. The line a is lexicographically smaller than the line b, if exists such an i (1 β€ i β€ |s|), that ai < bi, and for any j (1 β€ j < i) aj = bj. |s| stands for the length of the given template.
Examples
Input
3
a?c
Output
IMPOSSIBLE
Input
2
a??a
Output
abba
Input
2
?b?a
Output
abba | instruction | 0 | 96,571 | 6 | 193,142 |
Tags: expression parsing
Correct Solution:
```
k = int(input())
s = input()
ans = ['' for _ in range(len(s))]
r = set([chr(ord('a')+x) for x in range(k)]) - set(s)
r = list(r)
r.sort(reverse=True)
c = 0
for i in range(len(s)//2):
if s[i] == '?' and s[-i - 1] == '?':
c += 1
if len(s) % 2 == 1 and s[len(s)//2] == '?':
c += 1
c -= len(r)
for i in range(len(s)//2):
if s[i] == '?' and s[-i-1] == '?':
if c > 0:
ans[i] = 'a'
c -= 1
else:
ans[i] = r.pop()
ans[-i-1] = ans[i]
elif s[i] == '?':
ans[i] = ans[-i-1] = s[-i-1]
elif s[-i-1] == '?':
ans[-i-1] = ans[i] = s[i]
else:
if s[i] == s[-i-1]:
ans[i] = ans[-i-1] = s[i]
else:
print('IMPOSSIBLE')
break
else:
if len(s) % 2 == 1:
if s[len(s)//2] == '?':
if r:
ans[len(s)//2] = r.pop()
else:
ans[len(s)//2] = 'a'
else:
ans[len(s)//2] = s[len(s)//2]
if r:
print('IMPOSSIBLE')
else:
print(*ans, sep='')
``` | output | 1 | 96,571 | 6 | 193,143 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has recently finished writing a book. Now he faces the problem of giving it the title. Vasya wants the title to be vague and mysterious for his book to be noticeable among others. That's why the title should be represented by a single word containing at least once each of the first k Latin letters and not containing any other ones. Also, the title should be a palindrome, that is it should be read similarly from the left to the right and from the right to the left.
Vasya has already composed the approximate variant of the title. You are given the title template s consisting of lowercase Latin letters and question marks. Your task is to replace all the question marks by lowercase Latin letters so that the resulting word satisfies the requirements, described above. Each question mark should be replaced by exactly one letter, it is not allowed to delete characters or add new ones to the template. If there are several suitable titles, choose the first in the alphabetical order, for Vasya's book to appear as early as possible in all the catalogues.
Input
The first line contains an integer k (1 β€ k β€ 26) which is the number of allowed alphabet letters. The second line contains s which is the given template. In s only the first k lowercase letters of Latin alphabet and question marks can be present, the length of s is from 1 to 100 characters inclusively.
Output
If there is no solution, print IMPOSSIBLE. Otherwise, a single line should contain the required title, satisfying the given template. The title should be a palindrome and it can only contain the first k letters of the Latin alphabet. At that, each of those k letters must be present at least once. If there are several suitable titles, print the lexicographically minimal one.
The lexicographical comparison is performed by the standard < operator in modern programming languages. The line a is lexicographically smaller than the line b, if exists such an i (1 β€ i β€ |s|), that ai < bi, and for any j (1 β€ j < i) aj = bj. |s| stands for the length of the given template.
Examples
Input
3
a?c
Output
IMPOSSIBLE
Input
2
a??a
Output
abba
Input
2
?b?a
Output
abba | instruction | 0 | 96,572 | 6 | 193,144 |
Tags: expression parsing
Correct Solution:
```
import sys, string
k = int(input())
pal = list(input().strip())
n = len(pal)
center = (n-1)//2
for i in range(center+1):
j = n-1-i
if pal[i] == pal[j]:
continue
if pal[i] == '?':
pal[i] = pal[j]
elif pal[j] == '?':
pal[j] = pal[i]
else:
print('IMPOSSIBLE')
sys.exit()
need = []
for ch in string.ascii_letters[:k]:
if ch not in pal:
need.append(ch)
nix = len(need)-1
for i in range(center, -1, -1):
if pal[i] != '?':
continue
j = n-i-1
if nix == -1:
pal[i] = pal[j] = 'a'
else:
pal[i] = pal[j] = need[nix]
nix -= 1
if nix != -1:
print('IMPOSSIBLE')
else:
print(''.join(pal))
# Made By Mostafa_Khaled
``` | output | 1 | 96,572 | 6 | 193,145 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has recently finished writing a book. Now he faces the problem of giving it the title. Vasya wants the title to be vague and mysterious for his book to be noticeable among others. That's why the title should be represented by a single word containing at least once each of the first k Latin letters and not containing any other ones. Also, the title should be a palindrome, that is it should be read similarly from the left to the right and from the right to the left.
Vasya has already composed the approximate variant of the title. You are given the title template s consisting of lowercase Latin letters and question marks. Your task is to replace all the question marks by lowercase Latin letters so that the resulting word satisfies the requirements, described above. Each question mark should be replaced by exactly one letter, it is not allowed to delete characters or add new ones to the template. If there are several suitable titles, choose the first in the alphabetical order, for Vasya's book to appear as early as possible in all the catalogues.
Input
The first line contains an integer k (1 β€ k β€ 26) which is the number of allowed alphabet letters. The second line contains s which is the given template. In s only the first k lowercase letters of Latin alphabet and question marks can be present, the length of s is from 1 to 100 characters inclusively.
Output
If there is no solution, print IMPOSSIBLE. Otherwise, a single line should contain the required title, satisfying the given template. The title should be a palindrome and it can only contain the first k letters of the Latin alphabet. At that, each of those k letters must be present at least once. If there are several suitable titles, print the lexicographically minimal one.
The lexicographical comparison is performed by the standard < operator in modern programming languages. The line a is lexicographically smaller than the line b, if exists such an i (1 β€ i β€ |s|), that ai < bi, and for any j (1 β€ j < i) aj = bj. |s| stands for the length of the given template.
Examples
Input
3
a?c
Output
IMPOSSIBLE
Input
2
a??a
Output
abba
Input
2
?b?a
Output
abba | instruction | 0 | 96,573 | 6 | 193,146 |
Tags: expression parsing
Correct Solution:
```
def f():
k, t = int(input()), input()
j, n = 0, (len(t) + 1) // 2
p = [0] * n
q = 'abcdefghijklmnopqrstuvwxyz'[: k]
r = {x: 0 for x in q}
r['?'] = 0
for i in range(n):
x, y = t[i], t[- 1 - i]
if x == '?': x = y
elif y != '?' and x != y: return 'IMPOSSIBLE'
if not x in r: return 'IMPOSSIBLE'
r[x] += 1
p[i] = x
y = ''.join(x for x in q if not r[x])
if len(y) > r['?']: return 'IMPOSSIBLE'
y = 'a' * (r['?'] - len(y)) + y
for i in range(n):
if p[i] == '?':
p[i] = y[j]
j += 1
p += reversed(p[: len(t) // 2])
return ''.join(p)
print(f())
``` | output | 1 | 96,573 | 6 | 193,147 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has recently finished writing a book. Now he faces the problem of giving it the title. Vasya wants the title to be vague and mysterious for his book to be noticeable among others. That's why the title should be represented by a single word containing at least once each of the first k Latin letters and not containing any other ones. Also, the title should be a palindrome, that is it should be read similarly from the left to the right and from the right to the left.
Vasya has already composed the approximate variant of the title. You are given the title template s consisting of lowercase Latin letters and question marks. Your task is to replace all the question marks by lowercase Latin letters so that the resulting word satisfies the requirements, described above. Each question mark should be replaced by exactly one letter, it is not allowed to delete characters or add new ones to the template. If there are several suitable titles, choose the first in the alphabetical order, for Vasya's book to appear as early as possible in all the catalogues.
Input
The first line contains an integer k (1 β€ k β€ 26) which is the number of allowed alphabet letters. The second line contains s which is the given template. In s only the first k lowercase letters of Latin alphabet and question marks can be present, the length of s is from 1 to 100 characters inclusively.
Output
If there is no solution, print IMPOSSIBLE. Otherwise, a single line should contain the required title, satisfying the given template. The title should be a palindrome and it can only contain the first k letters of the Latin alphabet. At that, each of those k letters must be present at least once. If there are several suitable titles, print the lexicographically minimal one.
The lexicographical comparison is performed by the standard < operator in modern programming languages. The line a is lexicographically smaller than the line b, if exists such an i (1 β€ i β€ |s|), that ai < bi, and for any j (1 β€ j < i) aj = bj. |s| stands for the length of the given template.
Examples
Input
3
a?c
Output
IMPOSSIBLE
Input
2
a??a
Output
abba
Input
2
?b?a
Output
abba | instruction | 0 | 96,574 | 6 | 193,148 |
Tags: expression parsing
Correct Solution:
```
Z='IMPOSSIBLE'
R=range
P=print
I=input
k=int(I())
s=list(I())
n=len(s)
for i in R(n):
if s[i]==s[n-i-1]:pass
elif s[i]=='?':s[i]=s[n-i-1]
elif s[n-i-1]=='?':s[n-i-1]=s[i]
else:P(Z);exit()
d=set(chr(i)for i in R(97,97+k)if chr(i) not in s)
for i in R(n//2,-1,-1):
if len(d) and s[i]=='?':s[i]=s[n-i-1]=max(d);d.remove(max(d))
s=''.join(s).replace('?','a')
P([Z,s][set(s)==set(chr(i)for i in R(97,97+k))])
``` | output | 1 | 96,574 | 6 | 193,149 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has recently finished writing a book. Now he faces the problem of giving it the title. Vasya wants the title to be vague and mysterious for his book to be noticeable among others. That's why the title should be represented by a single word containing at least once each of the first k Latin letters and not containing any other ones. Also, the title should be a palindrome, that is it should be read similarly from the left to the right and from the right to the left.
Vasya has already composed the approximate variant of the title. You are given the title template s consisting of lowercase Latin letters and question marks. Your task is to replace all the question marks by lowercase Latin letters so that the resulting word satisfies the requirements, described above. Each question mark should be replaced by exactly one letter, it is not allowed to delete characters or add new ones to the template. If there are several suitable titles, choose the first in the alphabetical order, for Vasya's book to appear as early as possible in all the catalogues.
Input
The first line contains an integer k (1 β€ k β€ 26) which is the number of allowed alphabet letters. The second line contains s which is the given template. In s only the first k lowercase letters of Latin alphabet and question marks can be present, the length of s is from 1 to 100 characters inclusively.
Output
If there is no solution, print IMPOSSIBLE. Otherwise, a single line should contain the required title, satisfying the given template. The title should be a palindrome and it can only contain the first k letters of the Latin alphabet. At that, each of those k letters must be present at least once. If there are several suitable titles, print the lexicographically minimal one.
The lexicographical comparison is performed by the standard < operator in modern programming languages. The line a is lexicographically smaller than the line b, if exists such an i (1 β€ i β€ |s|), that ai < bi, and for any j (1 β€ j < i) aj = bj. |s| stands for the length of the given template.
Examples
Input
3
a?c
Output
IMPOSSIBLE
Input
2
a??a
Output
abba
Input
2
?b?a
Output
abba
Submitted Solution:
```
'''''''''''
Author : code_marshal
'''''''''''
alp = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
k, s = int(input()), list(input())
ch = alp[:k]
i=j=0
if len(s)%2: i=len(s)//2; j=i+1
else: j=len(s)//2; i=j-1
while i>=0 or j<len(s):
if s[i]=='?':
if s[~i]!='?': s[i]=s[~i]
else:
lol = list(set(ch)-set(s)); lol.sort(reverse=True)
k = 0
for l in lol:k=l; break
if k==0: s[i]=s[~i]=ch[0]
else: s[i]=s[~i]=k
if '?' not in s: break
try:
if s[j]=='?':
if s[~j]!='?': s[j]=s[~j]
else:
lol = list(set(ch)-set(s)); lol.sort(reverse=True)
k = 0
for l in lol:k=l; break
if k==0: s[j]=s[~j]=ch[0]
else: s[j]=s[~j]=k
if '?' not in s: break
except: pass
i-=1;j+=1
if s[::-1]==s and not set(ch)-set(s): print(''.join(s))
else: print("IMPOSSIBLE")
``` | instruction | 0 | 96,575 | 6 | 193,150 |
Yes | output | 1 | 96,575 | 6 | 193,151 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has recently finished writing a book. Now he faces the problem of giving it the title. Vasya wants the title to be vague and mysterious for his book to be noticeable among others. That's why the title should be represented by a single word containing at least once each of the first k Latin letters and not containing any other ones. Also, the title should be a palindrome, that is it should be read similarly from the left to the right and from the right to the left.
Vasya has already composed the approximate variant of the title. You are given the title template s consisting of lowercase Latin letters and question marks. Your task is to replace all the question marks by lowercase Latin letters so that the resulting word satisfies the requirements, described above. Each question mark should be replaced by exactly one letter, it is not allowed to delete characters or add new ones to the template. If there are several suitable titles, choose the first in the alphabetical order, for Vasya's book to appear as early as possible in all the catalogues.
Input
The first line contains an integer k (1 β€ k β€ 26) which is the number of allowed alphabet letters. The second line contains s which is the given template. In s only the first k lowercase letters of Latin alphabet and question marks can be present, the length of s is from 1 to 100 characters inclusively.
Output
If there is no solution, print IMPOSSIBLE. Otherwise, a single line should contain the required title, satisfying the given template. The title should be a palindrome and it can only contain the first k letters of the Latin alphabet. At that, each of those k letters must be present at least once. If there are several suitable titles, print the lexicographically minimal one.
The lexicographical comparison is performed by the standard < operator in modern programming languages. The line a is lexicographically smaller than the line b, if exists such an i (1 β€ i β€ |s|), that ai < bi, and for any j (1 β€ j < i) aj = bj. |s| stands for the length of the given template.
Examples
Input
3
a?c
Output
IMPOSSIBLE
Input
2
a??a
Output
abba
Input
2
?b?a
Output
abba
Submitted Solution:
```
n = int(input())
add = [False for i in range(n)]
# l = [int(i) for i in range(n)]
s = input()
v = []
for i in range(len(s)):
v.append(s[i])
if s[i] != '?':
add[ord(s[i])-97] = True
if len(s)%2 == 1:
i = len(s)//2
j = len(s)//2
else:
i = (len(s)//2)-1
j = len(s)//2
# print(i, j)
while i >= 0:
if v[i] == '?':
if v[j] == '?':
id = -1
for k in range(n-1, -1, -1):
if add[k] == False:
id = k
break
else:
id = 0
# print(i, j, id)
v[i] = chr(id+97)
v[j] = chr(id+97)
add[id] = True
else:
v[i] = v[j]
else:
if v[j] == '?':
v[j] = v[i]
else:
if v[i] != v[j]:
print("IMPOSSIBLE")
exit()
i-=1
j+=1
# print(add)
for i in range(n):
if add[i] == False:
# print("oi")
print("IMPOSSIBLE")
exit()
for i in range(len(v)):
print(v[i], end='')
print()
``` | instruction | 0 | 96,576 | 6 | 193,152 |
Yes | output | 1 | 96,576 | 6 | 193,153 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has recently finished writing a book. Now he faces the problem of giving it the title. Vasya wants the title to be vague and mysterious for his book to be noticeable among others. That's why the title should be represented by a single word containing at least once each of the first k Latin letters and not containing any other ones. Also, the title should be a palindrome, that is it should be read similarly from the left to the right and from the right to the left.
Vasya has already composed the approximate variant of the title. You are given the title template s consisting of lowercase Latin letters and question marks. Your task is to replace all the question marks by lowercase Latin letters so that the resulting word satisfies the requirements, described above. Each question mark should be replaced by exactly one letter, it is not allowed to delete characters or add new ones to the template. If there are several suitable titles, choose the first in the alphabetical order, for Vasya's book to appear as early as possible in all the catalogues.
Input
The first line contains an integer k (1 β€ k β€ 26) which is the number of allowed alphabet letters. The second line contains s which is the given template. In s only the first k lowercase letters of Latin alphabet and question marks can be present, the length of s is from 1 to 100 characters inclusively.
Output
If there is no solution, print IMPOSSIBLE. Otherwise, a single line should contain the required title, satisfying the given template. The title should be a palindrome and it can only contain the first k letters of the Latin alphabet. At that, each of those k letters must be present at least once. If there are several suitable titles, print the lexicographically minimal one.
The lexicographical comparison is performed by the standard < operator in modern programming languages. The line a is lexicographically smaller than the line b, if exists such an i (1 β€ i β€ |s|), that ai < bi, and for any j (1 β€ j < i) aj = bj. |s| stands for the length of the given template.
Examples
Input
3
a?c
Output
IMPOSSIBLE
Input
2
a??a
Output
abba
Input
2
?b?a
Output
abba
Submitted Solution:
```
import sys, string
k = int(input())
pal = list(input().strip())
n = len(pal)
center = (n-1)//2
for i in range(center+1):
j = n-1-i
if pal[i] == pal[j]:
continue
if pal[i] == '?':
pal[i] = pal[j]
elif pal[j] == '?':
pal[j] = pal[i]
else:
print('IMPOSSIBLE')
sys.exit()
need = []
for ch in string.ascii_letters[:k]:
if ch not in pal:
need.append(ch)
nix = len(need)-1
for i in range(center, -1, -1):
if pal[i] != '?':
continue
j = n-i-1
if nix == -1:
pal[i] = pal[j] = 'a'
else:
pal[i] = pal[j] = need[nix]
nix -= 1
if nix != -1:
print('IMPOSSIBLE')
else:
print(''.join(pal))
``` | instruction | 0 | 96,577 | 6 | 193,154 |
Yes | output | 1 | 96,577 | 6 | 193,155 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has recently finished writing a book. Now he faces the problem of giving it the title. Vasya wants the title to be vague and mysterious for his book to be noticeable among others. That's why the title should be represented by a single word containing at least once each of the first k Latin letters and not containing any other ones. Also, the title should be a palindrome, that is it should be read similarly from the left to the right and from the right to the left.
Vasya has already composed the approximate variant of the title. You are given the title template s consisting of lowercase Latin letters and question marks. Your task is to replace all the question marks by lowercase Latin letters so that the resulting word satisfies the requirements, described above. Each question mark should be replaced by exactly one letter, it is not allowed to delete characters or add new ones to the template. If there are several suitable titles, choose the first in the alphabetical order, for Vasya's book to appear as early as possible in all the catalogues.
Input
The first line contains an integer k (1 β€ k β€ 26) which is the number of allowed alphabet letters. The second line contains s which is the given template. In s only the first k lowercase letters of Latin alphabet and question marks can be present, the length of s is from 1 to 100 characters inclusively.
Output
If there is no solution, print IMPOSSIBLE. Otherwise, a single line should contain the required title, satisfying the given template. The title should be a palindrome and it can only contain the first k letters of the Latin alphabet. At that, each of those k letters must be present at least once. If there are several suitable titles, print the lexicographically minimal one.
The lexicographical comparison is performed by the standard < operator in modern programming languages. The line a is lexicographically smaller than the line b, if exists such an i (1 β€ i β€ |s|), that ai < bi, and for any j (1 β€ j < i) aj = bj. |s| stands for the length of the given template.
Examples
Input
3
a?c
Output
IMPOSSIBLE
Input
2
a??a
Output
abba
Input
2
?b?a
Output
abba
Submitted Solution:
```
k=int(input())
s=list(input())
n=len(s)
ali=0;
for i in range(n):
if s[i]==s[n-i-1]: ali+=1;
elif s[i]=='?': s[i]=s[n-i-1]
elif s[n-i-1]=='?': s[n-i-1]=s[i]
else:
print('IMPOSSIBLE')
exit()
d=set(chr(i+97) for i in range(k) if chr(i+97) not in s)
#print(d)
for i in range(n//2,-1,-1):
if s[i]==s[n-i-1]=='?':
if len(d):
s[i]=s[n-i-1]=max(d)
d.remove(max(d))
else:
s[i]=s[n-i-1]='a'
if d:
print('IMPOSSIBLE')
else:
print(*s,sep='')
``` | instruction | 0 | 96,578 | 6 | 193,156 |
Yes | output | 1 | 96,578 | 6 | 193,157 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has recently finished writing a book. Now he faces the problem of giving it the title. Vasya wants the title to be vague and mysterious for his book to be noticeable among others. That's why the title should be represented by a single word containing at least once each of the first k Latin letters and not containing any other ones. Also, the title should be a palindrome, that is it should be read similarly from the left to the right and from the right to the left.
Vasya has already composed the approximate variant of the title. You are given the title template s consisting of lowercase Latin letters and question marks. Your task is to replace all the question marks by lowercase Latin letters so that the resulting word satisfies the requirements, described above. Each question mark should be replaced by exactly one letter, it is not allowed to delete characters or add new ones to the template. If there are several suitable titles, choose the first in the alphabetical order, for Vasya's book to appear as early as possible in all the catalogues.
Input
The first line contains an integer k (1 β€ k β€ 26) which is the number of allowed alphabet letters. The second line contains s which is the given template. In s only the first k lowercase letters of Latin alphabet and question marks can be present, the length of s is from 1 to 100 characters inclusively.
Output
If there is no solution, print IMPOSSIBLE. Otherwise, a single line should contain the required title, satisfying the given template. The title should be a palindrome and it can only contain the first k letters of the Latin alphabet. At that, each of those k letters must be present at least once. If there are several suitable titles, print the lexicographically minimal one.
The lexicographical comparison is performed by the standard < operator in modern programming languages. The line a is lexicographically smaller than the line b, if exists such an i (1 β€ i β€ |s|), that ai < bi, and for any j (1 β€ j < i) aj = bj. |s| stands for the length of the given template.
Examples
Input
3
a?c
Output
IMPOSSIBLE
Input
2
a??a
Output
abba
Input
2
?b?a
Output
abba
Submitted Solution:
```
def ii():return int(input())
def si():return input()
def mi():return map(int,input().split())
def li():return list(mi())
abc="abcdefghijklmnopqrstuvwxyz"
n=ii()
s=si()
k=len(s)
c=0
b=[]
f=0
for i in range(k):
if(s[i]==s[k-i-1] or s[k-i-1]=='?'):
b.append(s[i])
elif(s[i]==s[k-i-1] or s[i]=='?'):
b.append(s[k-i-1])
else:
f=1
print("IMPOSSIBLE")
break
c+=1
if(c==n):
break
if(f==0):
if((2*n)>k):
print("IMPOSSIBLE")
f=1
d=[]
for i in range(n,k-n):
if(s[i]=='?' and s[k-i-1]=='?'):
d.append('c')
if(s[i]==s[k-i-1] or s[k-i-1]=='?'):
d.append(s[i])
elif(s[i]==s[k-i-1] or s[i]=='?'):
d.append(s[k-i-1])
else:
if(f==0):
print("IMPOSSIBLE")
f=1
break
if(f==0):
for i in range(n):
if(b[i]=='?'):
for j in range(26):
if(abc[j] not in b):
b[i]=abc[j]
break
for i in range(n):
print(b[i],end="")
b.reverse()
for i in d:
print(i,end="")
for i in range(k-n,k):
print(b[i-k+n],end="")
print()
``` | instruction | 0 | 96,579 | 6 | 193,158 |
No | output | 1 | 96,579 | 6 | 193,159 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has recently finished writing a book. Now he faces the problem of giving it the title. Vasya wants the title to be vague and mysterious for his book to be noticeable among others. That's why the title should be represented by a single word containing at least once each of the first k Latin letters and not containing any other ones. Also, the title should be a palindrome, that is it should be read similarly from the left to the right and from the right to the left.
Vasya has already composed the approximate variant of the title. You are given the title template s consisting of lowercase Latin letters and question marks. Your task is to replace all the question marks by lowercase Latin letters so that the resulting word satisfies the requirements, described above. Each question mark should be replaced by exactly one letter, it is not allowed to delete characters or add new ones to the template. If there are several suitable titles, choose the first in the alphabetical order, for Vasya's book to appear as early as possible in all the catalogues.
Input
The first line contains an integer k (1 β€ k β€ 26) which is the number of allowed alphabet letters. The second line contains s which is the given template. In s only the first k lowercase letters of Latin alphabet and question marks can be present, the length of s is from 1 to 100 characters inclusively.
Output
If there is no solution, print IMPOSSIBLE. Otherwise, a single line should contain the required title, satisfying the given template. The title should be a palindrome and it can only contain the first k letters of the Latin alphabet. At that, each of those k letters must be present at least once. If there are several suitable titles, print the lexicographically minimal one.
The lexicographical comparison is performed by the standard < operator in modern programming languages. The line a is lexicographically smaller than the line b, if exists such an i (1 β€ i β€ |s|), that ai < bi, and for any j (1 β€ j < i) aj = bj. |s| stands for the length of the given template.
Examples
Input
3
a?c
Output
IMPOSSIBLE
Input
2
a??a
Output
abba
Input
2
?b?a
Output
abba
Submitted Solution:
```
def palind(ch):
ch1=""
for i in ch:
ch1=i+ch1
return ch1
l='abcdefghijklmnopqrstuvwxyz'
k=int(input())
ch=input()
l=l[:k]
l1=""
x=0
D=[]
for i in ch:
D.append(i)
if i=="?":
x+=1
for i in l:
if i not in ch and i!="?":
l1+=i
if (len(l1)>x//2 and x%2==0 )or (len(l1)>x//2+1 and x%2==1 ):
print("IMPOSSIBLE")
elif k==1:
ch1=""
for j in range(len(ch)):
ch1+="a"
print(ch1)
else:
B=True
for i in range(len(ch)//2+2):
if D[i]=="?" and D[len(ch)-i-1]=="?" and l1!="":
D[i]=l1[0]
D[len(ch)-i-1]=l1[0]
l1=l1[1:]
if l1=="":
B=False
elif D[i]=="?" and D[len(ch)-i-1]=="?" and l1=="":
l1=l
B=False
D[i]=l1[0]
D[len(ch)-i-1]=l1[0]
elif D[i]=="?" and D[len(ch)-i-1]!="?":
D[i]=D[len(D)-i-1]
elif D[i]!="?" and D[len(ch)-i-1]=="?":
D[len(D)-i-1]=D[i]
if len(l1)==0:
B=False
if B==True:
print("IMPOSSIBLE")
else:
fin=""
for j in D:
fin+=j
if palind(fin)==fin:
print(fin)
else:
print("IMPOSSIBLE")
``` | instruction | 0 | 96,580 | 6 | 193,160 |
No | output | 1 | 96,580 | 6 | 193,161 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has recently finished writing a book. Now he faces the problem of giving it the title. Vasya wants the title to be vague and mysterious for his book to be noticeable among others. That's why the title should be represented by a single word containing at least once each of the first k Latin letters and not containing any other ones. Also, the title should be a palindrome, that is it should be read similarly from the left to the right and from the right to the left.
Vasya has already composed the approximate variant of the title. You are given the title template s consisting of lowercase Latin letters and question marks. Your task is to replace all the question marks by lowercase Latin letters so that the resulting word satisfies the requirements, described above. Each question mark should be replaced by exactly one letter, it is not allowed to delete characters or add new ones to the template. If there are several suitable titles, choose the first in the alphabetical order, for Vasya's book to appear as early as possible in all the catalogues.
Input
The first line contains an integer k (1 β€ k β€ 26) which is the number of allowed alphabet letters. The second line contains s which is the given template. In s only the first k lowercase letters of Latin alphabet and question marks can be present, the length of s is from 1 to 100 characters inclusively.
Output
If there is no solution, print IMPOSSIBLE. Otherwise, a single line should contain the required title, satisfying the given template. The title should be a palindrome and it can only contain the first k letters of the Latin alphabet. At that, each of those k letters must be present at least once. If there are several suitable titles, print the lexicographically minimal one.
The lexicographical comparison is performed by the standard < operator in modern programming languages. The line a is lexicographically smaller than the line b, if exists such an i (1 β€ i β€ |s|), that ai < bi, and for any j (1 β€ j < i) aj = bj. |s| stands for the length of the given template.
Examples
Input
3
a?c
Output
IMPOSSIBLE
Input
2
a??a
Output
abba
Input
2
?b?a
Output
abba
Submitted Solution:
```
k = int(input())
s = input()
c = set('abcdefghijklmnopqrstuvwxyz'[:k])
for a in s:
if a != '?' and a in c:
c.remove(a)
for i in range(len(s)):
if s[i] == '?':
if s[-(i+1)] != '?':
s = s[:i] + s[-(i+1)] + s[i+1:]
if s[i] in c:
c.remove(s[i])
for i in range(len(s)):
if s[i] == '?':
if len(c) > 0:
r = c.pop()
else:
r = 'a'
s = s[:i] + r + s[i+1:len(s)-i-1] + r + s[len(s) - i:]
if len(c) > 0 or s != s[::-1]:
print("IMPOSSIBLE")
else:
print(s)
``` | instruction | 0 | 96,581 | 6 | 193,162 |
No | output | 1 | 96,581 | 6 | 193,163 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has recently finished writing a book. Now he faces the problem of giving it the title. Vasya wants the title to be vague and mysterious for his book to be noticeable among others. That's why the title should be represented by a single word containing at least once each of the first k Latin letters and not containing any other ones. Also, the title should be a palindrome, that is it should be read similarly from the left to the right and from the right to the left.
Vasya has already composed the approximate variant of the title. You are given the title template s consisting of lowercase Latin letters and question marks. Your task is to replace all the question marks by lowercase Latin letters so that the resulting word satisfies the requirements, described above. Each question mark should be replaced by exactly one letter, it is not allowed to delete characters or add new ones to the template. If there are several suitable titles, choose the first in the alphabetical order, for Vasya's book to appear as early as possible in all the catalogues.
Input
The first line contains an integer k (1 β€ k β€ 26) which is the number of allowed alphabet letters. The second line contains s which is the given template. In s only the first k lowercase letters of Latin alphabet and question marks can be present, the length of s is from 1 to 100 characters inclusively.
Output
If there is no solution, print IMPOSSIBLE. Otherwise, a single line should contain the required title, satisfying the given template. The title should be a palindrome and it can only contain the first k letters of the Latin alphabet. At that, each of those k letters must be present at least once. If there are several suitable titles, print the lexicographically minimal one.
The lexicographical comparison is performed by the standard < operator in modern programming languages. The line a is lexicographically smaller than the line b, if exists such an i (1 β€ i β€ |s|), that ai < bi, and for any j (1 β€ j < i) aj = bj. |s| stands for the length of the given template.
Examples
Input
3
a?c
Output
IMPOSSIBLE
Input
2
a??a
Output
abba
Input
2
?b?a
Output
abba
Submitted Solution:
```
from sys import stdin
def main():
n = int(stdin.readline())
line = stdin.readline().strip()
i,j = 0,len(line)-1
ans = ["" for i in range(len(line))]
visited = [False for i in range(27)]
ok = True
while(i<=j):
if(line[i] == "?" and line[j] != "?"):
ans[i] = line[j]
ans[j] = line[j]
visited[ord(line[j])-97] = True
elif(line[i] != "?" and line[j] == "?"):
ans[i] = line[i]
ans[j] = line[i]
visited[ord(line[i])-97] = True
elif(line[i] != "?" and line[j] != "?"and line[i] == line[j]):
ans[i]= line[i]
ans[j]= line[i]
elif(line[i] == "?" and line[j] == "?"):
for k in range(n):
if(not visited[k]):
visited[k] = True
ans[i] = chr(k+97)
ans[j] = chr(k+97)
if(ans[i] == "?" and ans[j] == "?"):
ans[i] = "a"
ans[j] = "a"
else:
ok = False
i,j=i+1,j-1
if(ok):
aux = ""
for u in range(len(ans)):
aux+=ans[u]
print(aux)
else:
print("IMPOSSIBLE")
main()
``` | instruction | 0 | 96,582 | 6 | 193,164 |
No | output | 1 | 96,582 | 6 | 193,165 |
Provide tags and a correct Python 3 solution for this coding contest problem.
ZS the Coder is coding on a crazy computer. If you don't type in a word for a c consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second a and then the next word at second b, then if b - a β€ c, just the new word is appended to other words on the screen. If b - a > c, then everything on the screen disappears and after that the word you have typed appears on the screen.
For example, if c = 5 and you typed words at seconds 1, 3, 8, 14, 19, 20 then at the second 8 there will be 3 words on the screen. After that, everything disappears at the second 13 because nothing was typed. At the seconds 14 and 19 another two words are typed, and finally, at the second 20, one more word is typed, and a total of 3 words remain on the screen.
You're given the times when ZS the Coder typed the words. Determine how many words remain on the screen after he finished typing everything.
Input
The first line contains two integers n and c (1 β€ n β€ 100 000, 1 β€ c β€ 109) β the number of words ZS the Coder typed and the crazy computer delay respectively.
The next line contains n integers t1, t2, ..., tn (1 β€ t1 < t2 < ... < tn β€ 109), where ti denotes the second when ZS the Coder typed the i-th word.
Output
Print a single positive integer, the number of words that remain on the screen after all n words was typed, in other words, at the second tn.
Examples
Input
6 5
1 3 8 14 19 20
Output
3
Input
6 1
1 3 5 7 9 10
Output
2
Note
The first sample is already explained in the problem statement.
For the second sample, after typing the first word at the second 1, it disappears because the next word is typed at the second 3 and 3 - 1 > 1. Similarly, only 1 word will remain at the second 9. Then, a word is typed at the second 10, so there will be two words on the screen, as the old word won't disappear because 10 - 9 β€ 1. | instruction | 0 | 96,631 | 6 | 193,262 |
Tags: implementation
Correct Solution:
```
n,c=map(int, input().split())
t=[int(t) for t in input().split()]
r=1
for i in range(n-1):
if t[i+1]-t[i]<=c:
r+=1
else:
r=1
print(r)
``` | output | 1 | 96,631 | 6 | 193,263 |
Provide tags and a correct Python 3 solution for this coding contest problem.
ZS the Coder is coding on a crazy computer. If you don't type in a word for a c consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second a and then the next word at second b, then if b - a β€ c, just the new word is appended to other words on the screen. If b - a > c, then everything on the screen disappears and after that the word you have typed appears on the screen.
For example, if c = 5 and you typed words at seconds 1, 3, 8, 14, 19, 20 then at the second 8 there will be 3 words on the screen. After that, everything disappears at the second 13 because nothing was typed. At the seconds 14 and 19 another two words are typed, and finally, at the second 20, one more word is typed, and a total of 3 words remain on the screen.
You're given the times when ZS the Coder typed the words. Determine how many words remain on the screen after he finished typing everything.
Input
The first line contains two integers n and c (1 β€ n β€ 100 000, 1 β€ c β€ 109) β the number of words ZS the Coder typed and the crazy computer delay respectively.
The next line contains n integers t1, t2, ..., tn (1 β€ t1 < t2 < ... < tn β€ 109), where ti denotes the second when ZS the Coder typed the i-th word.
Output
Print a single positive integer, the number of words that remain on the screen after all n words was typed, in other words, at the second tn.
Examples
Input
6 5
1 3 8 14 19 20
Output
3
Input
6 1
1 3 5 7 9 10
Output
2
Note
The first sample is already explained in the problem statement.
For the second sample, after typing the first word at the second 1, it disappears because the next word is typed at the second 3 and 3 - 1 > 1. Similarly, only 1 word will remain at the second 9. Then, a word is typed at the second 10, so there will be two words on the screen, as the old word won't disappear because 10 - 9 β€ 1. | instruction | 0 | 96,632 | 6 | 193,264 |
Tags: implementation
Correct Solution:
```
import sys
from collections import defaultdict, Counter
import string
def main():
n, c = [int(i) for i in input().split()]
t = [int(i) for i in input().split()]
words = 1
for i, j in zip(t[:-1], t[1:]):
if j - i > c:
words = 1
else:
words += 1
print(words)
if __name__ == '__main__':
main()
``` | output | 1 | 96,632 | 6 | 193,265 |
Provide tags and a correct Python 3 solution for this coding contest problem.
ZS the Coder is coding on a crazy computer. If you don't type in a word for a c consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second a and then the next word at second b, then if b - a β€ c, just the new word is appended to other words on the screen. If b - a > c, then everything on the screen disappears and after that the word you have typed appears on the screen.
For example, if c = 5 and you typed words at seconds 1, 3, 8, 14, 19, 20 then at the second 8 there will be 3 words on the screen. After that, everything disappears at the second 13 because nothing was typed. At the seconds 14 and 19 another two words are typed, and finally, at the second 20, one more word is typed, and a total of 3 words remain on the screen.
You're given the times when ZS the Coder typed the words. Determine how many words remain on the screen after he finished typing everything.
Input
The first line contains two integers n and c (1 β€ n β€ 100 000, 1 β€ c β€ 109) β the number of words ZS the Coder typed and the crazy computer delay respectively.
The next line contains n integers t1, t2, ..., tn (1 β€ t1 < t2 < ... < tn β€ 109), where ti denotes the second when ZS the Coder typed the i-th word.
Output
Print a single positive integer, the number of words that remain on the screen after all n words was typed, in other words, at the second tn.
Examples
Input
6 5
1 3 8 14 19 20
Output
3
Input
6 1
1 3 5 7 9 10
Output
2
Note
The first sample is already explained in the problem statement.
For the second sample, after typing the first word at the second 1, it disappears because the next word is typed at the second 3 and 3 - 1 > 1. Similarly, only 1 word will remain at the second 9. Then, a word is typed at the second 10, so there will be two words on the screen, as the old word won't disappear because 10 - 9 β€ 1. | instruction | 0 | 96,633 | 6 | 193,266 |
Tags: implementation
Correct Solution:
```
#Codeforce 716A
n,c = (int(v) for v in input().split())
list1=[int(u) for u in input().split()]
list1=list1[::-1]
ans=1
for i in range(1,n):
if list1[i-1] - list1[i] <= c:
ans += 1
else:
break
print(ans)
``` | output | 1 | 96,633 | 6 | 193,267 |
Provide tags and a correct Python 3 solution for this coding contest problem.
ZS the Coder is coding on a crazy computer. If you don't type in a word for a c consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second a and then the next word at second b, then if b - a β€ c, just the new word is appended to other words on the screen. If b - a > c, then everything on the screen disappears and after that the word you have typed appears on the screen.
For example, if c = 5 and you typed words at seconds 1, 3, 8, 14, 19, 20 then at the second 8 there will be 3 words on the screen. After that, everything disappears at the second 13 because nothing was typed. At the seconds 14 and 19 another two words are typed, and finally, at the second 20, one more word is typed, and a total of 3 words remain on the screen.
You're given the times when ZS the Coder typed the words. Determine how many words remain on the screen after he finished typing everything.
Input
The first line contains two integers n and c (1 β€ n β€ 100 000, 1 β€ c β€ 109) β the number of words ZS the Coder typed and the crazy computer delay respectively.
The next line contains n integers t1, t2, ..., tn (1 β€ t1 < t2 < ... < tn β€ 109), where ti denotes the second when ZS the Coder typed the i-th word.
Output
Print a single positive integer, the number of words that remain on the screen after all n words was typed, in other words, at the second tn.
Examples
Input
6 5
1 3 8 14 19 20
Output
3
Input
6 1
1 3 5 7 9 10
Output
2
Note
The first sample is already explained in the problem statement.
For the second sample, after typing the first word at the second 1, it disappears because the next word is typed at the second 3 and 3 - 1 > 1. Similarly, only 1 word will remain at the second 9. Then, a word is typed at the second 10, so there will be two words on the screen, as the old word won't disappear because 10 - 9 β€ 1. | instruction | 0 | 96,634 | 6 | 193,268 |
Tags: implementation
Correct Solution:
```
n,c=map(int,input().split())
s=list(map(int,input().split()))
ans=1
for i in range(1,n):
if s[i]-s[i-1]>c:
ans=1
else:
ans+=1
print(ans)
``` | output | 1 | 96,634 | 6 | 193,269 |
Provide tags and a correct Python 3 solution for this coding contest problem.
ZS the Coder is coding on a crazy computer. If you don't type in a word for a c consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second a and then the next word at second b, then if b - a β€ c, just the new word is appended to other words on the screen. If b - a > c, then everything on the screen disappears and after that the word you have typed appears on the screen.
For example, if c = 5 and you typed words at seconds 1, 3, 8, 14, 19, 20 then at the second 8 there will be 3 words on the screen. After that, everything disappears at the second 13 because nothing was typed. At the seconds 14 and 19 another two words are typed, and finally, at the second 20, one more word is typed, and a total of 3 words remain on the screen.
You're given the times when ZS the Coder typed the words. Determine how many words remain on the screen after he finished typing everything.
Input
The first line contains two integers n and c (1 β€ n β€ 100 000, 1 β€ c β€ 109) β the number of words ZS the Coder typed and the crazy computer delay respectively.
The next line contains n integers t1, t2, ..., tn (1 β€ t1 < t2 < ... < tn β€ 109), where ti denotes the second when ZS the Coder typed the i-th word.
Output
Print a single positive integer, the number of words that remain on the screen after all n words was typed, in other words, at the second tn.
Examples
Input
6 5
1 3 8 14 19 20
Output
3
Input
6 1
1 3 5 7 9 10
Output
2
Note
The first sample is already explained in the problem statement.
For the second sample, after typing the first word at the second 1, it disappears because the next word is typed at the second 3 and 3 - 1 > 1. Similarly, only 1 word will remain at the second 9. Then, a word is typed at the second 10, so there will be two words on the screen, as the old word won't disappear because 10 - 9 β€ 1. | instruction | 0 | 96,635 | 6 | 193,270 |
Tags: implementation
Correct Solution:
```
n,c = [int(x) for x in input().split()]
t = list(map(int,input().split()))
l = [t[0]]
for i in range(1,n):
if t[i]-t[i-1]<=c:
l.append(t[i])
else:
l.clear()
l.append(t[i])
print(len(l))
``` | output | 1 | 96,635 | 6 | 193,271 |
Provide tags and a correct Python 3 solution for this coding contest problem.
ZS the Coder is coding on a crazy computer. If you don't type in a word for a c consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second a and then the next word at second b, then if b - a β€ c, just the new word is appended to other words on the screen. If b - a > c, then everything on the screen disappears and after that the word you have typed appears on the screen.
For example, if c = 5 and you typed words at seconds 1, 3, 8, 14, 19, 20 then at the second 8 there will be 3 words on the screen. After that, everything disappears at the second 13 because nothing was typed. At the seconds 14 and 19 another two words are typed, and finally, at the second 20, one more word is typed, and a total of 3 words remain on the screen.
You're given the times when ZS the Coder typed the words. Determine how many words remain on the screen after he finished typing everything.
Input
The first line contains two integers n and c (1 β€ n β€ 100 000, 1 β€ c β€ 109) β the number of words ZS the Coder typed and the crazy computer delay respectively.
The next line contains n integers t1, t2, ..., tn (1 β€ t1 < t2 < ... < tn β€ 109), where ti denotes the second when ZS the Coder typed the i-th word.
Output
Print a single positive integer, the number of words that remain on the screen after all n words was typed, in other words, at the second tn.
Examples
Input
6 5
1 3 8 14 19 20
Output
3
Input
6 1
1 3 5 7 9 10
Output
2
Note
The first sample is already explained in the problem statement.
For the second sample, after typing the first word at the second 1, it disappears because the next word is typed at the second 3 and 3 - 1 > 1. Similarly, only 1 word will remain at the second 9. Then, a word is typed at the second 10, so there will be two words on the screen, as the old word won't disappear because 10 - 9 β€ 1. | instruction | 0 | 96,636 | 6 | 193,272 |
Tags: implementation
Correct Solution:
```
n, c = map(int, input().split(" "))
t = list(map(int, input().split(" ")))
words = 1
for i in range(1, n):
if t[i] - t[i - 1] <= c:
words += 1
else:
words = 1
print(words)
``` | output | 1 | 96,636 | 6 | 193,273 |
Provide tags and a correct Python 3 solution for this coding contest problem.
ZS the Coder is coding on a crazy computer. If you don't type in a word for a c consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second a and then the next word at second b, then if b - a β€ c, just the new word is appended to other words on the screen. If b - a > c, then everything on the screen disappears and after that the word you have typed appears on the screen.
For example, if c = 5 and you typed words at seconds 1, 3, 8, 14, 19, 20 then at the second 8 there will be 3 words on the screen. After that, everything disappears at the second 13 because nothing was typed. At the seconds 14 and 19 another two words are typed, and finally, at the second 20, one more word is typed, and a total of 3 words remain on the screen.
You're given the times when ZS the Coder typed the words. Determine how many words remain on the screen after he finished typing everything.
Input
The first line contains two integers n and c (1 β€ n β€ 100 000, 1 β€ c β€ 109) β the number of words ZS the Coder typed and the crazy computer delay respectively.
The next line contains n integers t1, t2, ..., tn (1 β€ t1 < t2 < ... < tn β€ 109), where ti denotes the second when ZS the Coder typed the i-th word.
Output
Print a single positive integer, the number of words that remain on the screen after all n words was typed, in other words, at the second tn.
Examples
Input
6 5
1 3 8 14 19 20
Output
3
Input
6 1
1 3 5 7 9 10
Output
2
Note
The first sample is already explained in the problem statement.
For the second sample, after typing the first word at the second 1, it disappears because the next word is typed at the second 3 and 3 - 1 > 1. Similarly, only 1 word will remain at the second 9. Then, a word is typed at the second 10, so there will be two words on the screen, as the old word won't disappear because 10 - 9 β€ 1. | instruction | 0 | 96,637 | 6 | 193,274 |
Tags: implementation
Correct Solution:
```
n , c = map(int , input().split())
x = [int(x) for x in input().split()]
cnt = 0
for i in range(len(x) - 1):
if x[i + 1] - x[i] <= c:
cnt += 1
else:
cnt = 0
print(cnt + 1)
``` | output | 1 | 96,637 | 6 | 193,275 |
Provide tags and a correct Python 3 solution for this coding contest problem.
ZS the Coder is coding on a crazy computer. If you don't type in a word for a c consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second a and then the next word at second b, then if b - a β€ c, just the new word is appended to other words on the screen. If b - a > c, then everything on the screen disappears and after that the word you have typed appears on the screen.
For example, if c = 5 and you typed words at seconds 1, 3, 8, 14, 19, 20 then at the second 8 there will be 3 words on the screen. After that, everything disappears at the second 13 because nothing was typed. At the seconds 14 and 19 another two words are typed, and finally, at the second 20, one more word is typed, and a total of 3 words remain on the screen.
You're given the times when ZS the Coder typed the words. Determine how many words remain on the screen after he finished typing everything.
Input
The first line contains two integers n and c (1 β€ n β€ 100 000, 1 β€ c β€ 109) β the number of words ZS the Coder typed and the crazy computer delay respectively.
The next line contains n integers t1, t2, ..., tn (1 β€ t1 < t2 < ... < tn β€ 109), where ti denotes the second when ZS the Coder typed the i-th word.
Output
Print a single positive integer, the number of words that remain on the screen after all n words was typed, in other words, at the second tn.
Examples
Input
6 5
1 3 8 14 19 20
Output
3
Input
6 1
1 3 5 7 9 10
Output
2
Note
The first sample is already explained in the problem statement.
For the second sample, after typing the first word at the second 1, it disappears because the next word is typed at the second 3 and 3 - 1 > 1. Similarly, only 1 word will remain at the second 9. Then, a word is typed at the second 10, so there will be two words on the screen, as the old word won't disappear because 10 - 9 β€ 1. | instruction | 0 | 96,638 | 6 | 193,276 |
Tags: implementation
Correct Solution:
```
n, c = map(int, input().split())
l = list(map(int, input().split()))
ans = 1
for i in range(1, n):
if l[i] - l[i - 1] <= c:
ans += 1
else:
ans = 1
print(ans)
``` | output | 1 | 96,638 | 6 | 193,277 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
ZS the Coder is coding on a crazy computer. If you don't type in a word for a c consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second a and then the next word at second b, then if b - a β€ c, just the new word is appended to other words on the screen. If b - a > c, then everything on the screen disappears and after that the word you have typed appears on the screen.
For example, if c = 5 and you typed words at seconds 1, 3, 8, 14, 19, 20 then at the second 8 there will be 3 words on the screen. After that, everything disappears at the second 13 because nothing was typed. At the seconds 14 and 19 another two words are typed, and finally, at the second 20, one more word is typed, and a total of 3 words remain on the screen.
You're given the times when ZS the Coder typed the words. Determine how many words remain on the screen after he finished typing everything.
Input
The first line contains two integers n and c (1 β€ n β€ 100 000, 1 β€ c β€ 109) β the number of words ZS the Coder typed and the crazy computer delay respectively.
The next line contains n integers t1, t2, ..., tn (1 β€ t1 < t2 < ... < tn β€ 109), where ti denotes the second when ZS the Coder typed the i-th word.
Output
Print a single positive integer, the number of words that remain on the screen after all n words was typed, in other words, at the second tn.
Examples
Input
6 5
1 3 8 14 19 20
Output
3
Input
6 1
1 3 5 7 9 10
Output
2
Note
The first sample is already explained in the problem statement.
For the second sample, after typing the first word at the second 1, it disappears because the next word is typed at the second 3 and 3 - 1 > 1. Similarly, only 1 word will remain at the second 9. Then, a word is typed at the second 10, so there will be two words on the screen, as the old word won't disappear because 10 - 9 β€ 1.
Submitted Solution:
```
n,c=map(int,input().split())
sum=1
words=list(map(int,input().split()))
for k in range(1,n):
if words[k]-words[k-1]<=c:
sum+=1
else:
sum=1
print(sum)
``` | instruction | 0 | 96,639 | 6 | 193,278 |
Yes | output | 1 | 96,639 | 6 | 193,279 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
ZS the Coder is coding on a crazy computer. If you don't type in a word for a c consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second a and then the next word at second b, then if b - a β€ c, just the new word is appended to other words on the screen. If b - a > c, then everything on the screen disappears and after that the word you have typed appears on the screen.
For example, if c = 5 and you typed words at seconds 1, 3, 8, 14, 19, 20 then at the second 8 there will be 3 words on the screen. After that, everything disappears at the second 13 because nothing was typed. At the seconds 14 and 19 another two words are typed, and finally, at the second 20, one more word is typed, and a total of 3 words remain on the screen.
You're given the times when ZS the Coder typed the words. Determine how many words remain on the screen after he finished typing everything.
Input
The first line contains two integers n and c (1 β€ n β€ 100 000, 1 β€ c β€ 109) β the number of words ZS the Coder typed and the crazy computer delay respectively.
The next line contains n integers t1, t2, ..., tn (1 β€ t1 < t2 < ... < tn β€ 109), where ti denotes the second when ZS the Coder typed the i-th word.
Output
Print a single positive integer, the number of words that remain on the screen after all n words was typed, in other words, at the second tn.
Examples
Input
6 5
1 3 8 14 19 20
Output
3
Input
6 1
1 3 5 7 9 10
Output
2
Note
The first sample is already explained in the problem statement.
For the second sample, after typing the first word at the second 1, it disappears because the next word is typed at the second 3 and 3 - 1 > 1. Similarly, only 1 word will remain at the second 9. Then, a word is typed at the second 10, so there will be two words on the screen, as the old word won't disappear because 10 - 9 β€ 1.
Submitted Solution:
```
import sys
n,c = map(int,input().split())
arr = list(map(int,input().split()))
cnt = 1
for i in range(n-1,-1,-1):
if i > 0 and arr[i] - arr[i-1] > c:
break
elif i > 0 and arr[i] - arr[i-1] <= c:
cnt += 1
print(cnt)
``` | instruction | 0 | 96,640 | 6 | 193,280 |
Yes | output | 1 | 96,640 | 6 | 193,281 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
ZS the Coder is coding on a crazy computer. If you don't type in a word for a c consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second a and then the next word at second b, then if b - a β€ c, just the new word is appended to other words on the screen. If b - a > c, then everything on the screen disappears and after that the word you have typed appears on the screen.
For example, if c = 5 and you typed words at seconds 1, 3, 8, 14, 19, 20 then at the second 8 there will be 3 words on the screen. After that, everything disappears at the second 13 because nothing was typed. At the seconds 14 and 19 another two words are typed, and finally, at the second 20, one more word is typed, and a total of 3 words remain on the screen.
You're given the times when ZS the Coder typed the words. Determine how many words remain on the screen after he finished typing everything.
Input
The first line contains two integers n and c (1 β€ n β€ 100 000, 1 β€ c β€ 109) β the number of words ZS the Coder typed and the crazy computer delay respectively.
The next line contains n integers t1, t2, ..., tn (1 β€ t1 < t2 < ... < tn β€ 109), where ti denotes the second when ZS the Coder typed the i-th word.
Output
Print a single positive integer, the number of words that remain on the screen after all n words was typed, in other words, at the second tn.
Examples
Input
6 5
1 3 8 14 19 20
Output
3
Input
6 1
1 3 5 7 9 10
Output
2
Note
The first sample is already explained in the problem statement.
For the second sample, after typing the first word at the second 1, it disappears because the next word is typed at the second 3 and 3 - 1 > 1. Similarly, only 1 word will remain at the second 9. Then, a word is typed at the second 10, so there will be two words on the screen, as the old word won't disappear because 10 - 9 β€ 1.
Submitted Solution:
```
# βͺ H4WK3yEδΉ‘
# Mayank Chaudhary
# I can :)
# ABES EC , Ghaziabad
# ///==========Libraries, Constants and Functions=============///
import sys
from bisect import bisect_left,bisect_right,insort
from collections import deque,Counter
from math import gcd,sqrt,factorial,ceil,log10
from itertools import permutations
from heapq import heappush,heappop,heapify
inf = float("inf")
mod = 1000000007
mini=1000000007
def max_subarray(array): # <------- Extended Kadane's algo which gives maximum sum sub-array but also the starting and ending indexes
max_so_far = max_ending_here = array[0]
start_index = 0
end_index = 0
for i in range(1, len(array) -1):
temp_start_index = temp_end_index = None
if array[i] > (max_ending_here + array[i]):
temp_start_index = temp_end_index = i
max_ending_here = array[i]
else:
temp_end_index = i
max_ending_here = max_ending_here + array[i]
if max_so_far < max_ending_here:
max_so_far = max_ending_here
if temp_start_index != None:
start_index = temp_start_index
end_index = i
print(max_so_far, start_index, end_index)
def ncr(n,r): # < ------ To calculate nCr mod p value using Fermat Little under modulo m
d=10**9+7
num=fact(n)
den=(fact(r)*fact(n-r))%d
den=pow(den,d-2,d)
return (num*den)%d
def sieve(n): # <----- sieve of eratosthenes for prime no.
prime=[True for i in range(n+1)]
lst=[]
p=2
while p*p<=n:
if prime[p]:
for i in range(p*p,n+1,p):
prime[i]=False
p=p+1
for i in range(2,n+1):
if prime[i]:
lst.append(i)
return lst
def binary(number): # <----- calculate the no. of 1's in binary representation of number
result=0
while number:
result=result+1
number=number&(number-1)
return result
def calculate_factors(n): #<---- most efficient method to calculate no. of factors of number
hh = [1] * (n + 1);
p = 2;
while((p * p) < n):
if (hh[p] == 1):
for i in range((p * 2), n, p):
hh[i] = 0;
p += 1;
total = 1;
for p in range(2, n + 1):
if (hh[p] == 1):
count = 0;
if (n % p == 0):
while (n % p == 0):
n = int(n / p);
count += 1;
total *= (count + 1);
return total;
def prime_factors(n): #<------------ to find prime factors of a no.
i = 2
factors = set()
while i * i <= n:
if n % i:
i += 1
else:
factors.add(n//i)
n=n//i
factors.add(i)
if n > 1:
factors.add(n)
return (factors)
def isPrime(n): #<-----------check whether a no. is prime or not
if n==2 or n==3: return True
if n%2==0 or n<2: return False
for i in range(3,int(n**0.5)+1,2): # only odd numbers
if n%i==0:
return False
return True
def solve(n):
if n==1:
return (1)
p=2;result=[]
while (p*p)<=n:
if n%p==0:
result.append(p);result.append(n//p)
p=p+1
return result
def atMostSum(arr, n, k):
_sum = 0
cnt = 0
maxcnt = 0
for i in range(n):
# If adding current element doesn't
# Cross limit add it to current window
if ((_sum + arr[i]) <= k):
_sum += arr[i]
cnt += 1
# Else, remove first element of current
# window and add the current element
elif(sum != 0):
_sum = _sum - arr[i - cnt] + arr[i]
# keep track of max length.
maxcnt = max(cnt, maxcnt)
return maxcnt
def get_array(): return list(map(int, sys.stdin.readline().strip().split()))
def get_ints(): return map(int, sys.stdin.readline().strip().split())
def input(): return sys.stdin.readline().strip()
# ///==========MAIN=============///
n,c=get_ints()
count=1
Arr=get_array()
for i in range(1,n):
if Arr[i]-Arr[i-1]<=c:
count+=1
else:
count=1
print(count)
``` | instruction | 0 | 96,641 | 6 | 193,282 |
Yes | output | 1 | 96,641 | 6 | 193,283 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
ZS the Coder is coding on a crazy computer. If you don't type in a word for a c consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second a and then the next word at second b, then if b - a β€ c, just the new word is appended to other words on the screen. If b - a > c, then everything on the screen disappears and after that the word you have typed appears on the screen.
For example, if c = 5 and you typed words at seconds 1, 3, 8, 14, 19, 20 then at the second 8 there will be 3 words on the screen. After that, everything disappears at the second 13 because nothing was typed. At the seconds 14 and 19 another two words are typed, and finally, at the second 20, one more word is typed, and a total of 3 words remain on the screen.
You're given the times when ZS the Coder typed the words. Determine how many words remain on the screen after he finished typing everything.
Input
The first line contains two integers n and c (1 β€ n β€ 100 000, 1 β€ c β€ 109) β the number of words ZS the Coder typed and the crazy computer delay respectively.
The next line contains n integers t1, t2, ..., tn (1 β€ t1 < t2 < ... < tn β€ 109), where ti denotes the second when ZS the Coder typed the i-th word.
Output
Print a single positive integer, the number of words that remain on the screen after all n words was typed, in other words, at the second tn.
Examples
Input
6 5
1 3 8 14 19 20
Output
3
Input
6 1
1 3 5 7 9 10
Output
2
Note
The first sample is already explained in the problem statement.
For the second sample, after typing the first word at the second 1, it disappears because the next word is typed at the second 3 and 3 - 1 > 1. Similarly, only 1 word will remain at the second 9. Then, a word is typed at the second 10, so there will be two words on the screen, as the old word won't disappear because 10 - 9 β€ 1.
Submitted Solution:
```
n, c = map(int, input().split())
t = list(map(int, input().split()))
time = 0
number_of_words = 0
for action in t:
if action - time > c:
number_of_words = 1
else:
number_of_words += 1
time = action
print(number_of_words)
``` | instruction | 0 | 96,642 | 6 | 193,284 |
Yes | output | 1 | 96,642 | 6 | 193,285 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
ZS the Coder is coding on a crazy computer. If you don't type in a word for a c consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second a and then the next word at second b, then if b - a β€ c, just the new word is appended to other words on the screen. If b - a > c, then everything on the screen disappears and after that the word you have typed appears on the screen.
For example, if c = 5 and you typed words at seconds 1, 3, 8, 14, 19, 20 then at the second 8 there will be 3 words on the screen. After that, everything disappears at the second 13 because nothing was typed. At the seconds 14 and 19 another two words are typed, and finally, at the second 20, one more word is typed, and a total of 3 words remain on the screen.
You're given the times when ZS the Coder typed the words. Determine how many words remain on the screen after he finished typing everything.
Input
The first line contains two integers n and c (1 β€ n β€ 100 000, 1 β€ c β€ 109) β the number of words ZS the Coder typed and the crazy computer delay respectively.
The next line contains n integers t1, t2, ..., tn (1 β€ t1 < t2 < ... < tn β€ 109), where ti denotes the second when ZS the Coder typed the i-th word.
Output
Print a single positive integer, the number of words that remain on the screen after all n words was typed, in other words, at the second tn.
Examples
Input
6 5
1 3 8 14 19 20
Output
3
Input
6 1
1 3 5 7 9 10
Output
2
Note
The first sample is already explained in the problem statement.
For the second sample, after typing the first word at the second 1, it disappears because the next word is typed at the second 3 and 3 - 1 > 1. Similarly, only 1 word will remain at the second 9. Then, a word is typed at the second 10, so there will be two words on the screen, as the old word won't disappear because 10 - 9 β€ 1.
Submitted Solution:
```
n , c = map(int, input().split())
a = list(map(int,input().split()))
ans , it1, tmp = 1, 0, 1
for it2 in range(1, n):
if a[it2]-a[it1] > c :
ans = max(ans, tmp)
tmp = 1
it1 , tmp = it1+1, tmp+1
print(ans)
``` | instruction | 0 | 96,643 | 6 | 193,286 |
No | output | 1 | 96,643 | 6 | 193,287 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
ZS the Coder is coding on a crazy computer. If you don't type in a word for a c consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second a and then the next word at second b, then if b - a β€ c, just the new word is appended to other words on the screen. If b - a > c, then everything on the screen disappears and after that the word you have typed appears on the screen.
For example, if c = 5 and you typed words at seconds 1, 3, 8, 14, 19, 20 then at the second 8 there will be 3 words on the screen. After that, everything disappears at the second 13 because nothing was typed. At the seconds 14 and 19 another two words are typed, and finally, at the second 20, one more word is typed, and a total of 3 words remain on the screen.
You're given the times when ZS the Coder typed the words. Determine how many words remain on the screen after he finished typing everything.
Input
The first line contains two integers n and c (1 β€ n β€ 100 000, 1 β€ c β€ 109) β the number of words ZS the Coder typed and the crazy computer delay respectively.
The next line contains n integers t1, t2, ..., tn (1 β€ t1 < t2 < ... < tn β€ 109), where ti denotes the second when ZS the Coder typed the i-th word.
Output
Print a single positive integer, the number of words that remain on the screen after all n words was typed, in other words, at the second tn.
Examples
Input
6 5
1 3 8 14 19 20
Output
3
Input
6 1
1 3 5 7 9 10
Output
2
Note
The first sample is already explained in the problem statement.
For the second sample, after typing the first word at the second 1, it disappears because the next word is typed at the second 3 and 3 - 1 > 1. Similarly, only 1 word will remain at the second 9. Then, a word is typed at the second 10, so there will be two words on the screen, as the old word won't disappear because 10 - 9 β€ 1.
Submitted Solution:
```
n, c =[int(i) for i in input().split()]
t = [int(i) for i in input().split()]
ans = 0
for i in range(c):
if t[i] - t[i-1] <= c:
ans += 2
else:
ans = 1
print(ans)
``` | instruction | 0 | 96,644 | 6 | 193,288 |
No | output | 1 | 96,644 | 6 | 193,289 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
ZS the Coder is coding on a crazy computer. If you don't type in a word for a c consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second a and then the next word at second b, then if b - a β€ c, just the new word is appended to other words on the screen. If b - a > c, then everything on the screen disappears and after that the word you have typed appears on the screen.
For example, if c = 5 and you typed words at seconds 1, 3, 8, 14, 19, 20 then at the second 8 there will be 3 words on the screen. After that, everything disappears at the second 13 because nothing was typed. At the seconds 14 and 19 another two words are typed, and finally, at the second 20, one more word is typed, and a total of 3 words remain on the screen.
You're given the times when ZS the Coder typed the words. Determine how many words remain on the screen after he finished typing everything.
Input
The first line contains two integers n and c (1 β€ n β€ 100 000, 1 β€ c β€ 109) β the number of words ZS the Coder typed and the crazy computer delay respectively.
The next line contains n integers t1, t2, ..., tn (1 β€ t1 < t2 < ... < tn β€ 109), where ti denotes the second when ZS the Coder typed the i-th word.
Output
Print a single positive integer, the number of words that remain on the screen after all n words was typed, in other words, at the second tn.
Examples
Input
6 5
1 3 8 14 19 20
Output
3
Input
6 1
1 3 5 7 9 10
Output
2
Note
The first sample is already explained in the problem statement.
For the second sample, after typing the first word at the second 1, it disappears because the next word is typed at the second 3 and 3 - 1 > 1. Similarly, only 1 word will remain at the second 9. Then, a word is typed at the second 10, so there will be two words on the screen, as the old word won't disappear because 10 - 9 β€ 1.
Submitted Solution:
```
a,b=map(int,input().split())
x=list(map(int,input().split()))
count=1;
for i in range (a):
if (x[i]-x[i-1])<= b:
count=count+1
else:
count=1
print(count)
``` | instruction | 0 | 96,645 | 6 | 193,290 |
No | output | 1 | 96,645 | 6 | 193,291 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
ZS the Coder is coding on a crazy computer. If you don't type in a word for a c consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second a and then the next word at second b, then if b - a β€ c, just the new word is appended to other words on the screen. If b - a > c, then everything on the screen disappears and after that the word you have typed appears on the screen.
For example, if c = 5 and you typed words at seconds 1, 3, 8, 14, 19, 20 then at the second 8 there will be 3 words on the screen. After that, everything disappears at the second 13 because nothing was typed. At the seconds 14 and 19 another two words are typed, and finally, at the second 20, one more word is typed, and a total of 3 words remain on the screen.
You're given the times when ZS the Coder typed the words. Determine how many words remain on the screen after he finished typing everything.
Input
The first line contains two integers n and c (1 β€ n β€ 100 000, 1 β€ c β€ 109) β the number of words ZS the Coder typed and the crazy computer delay respectively.
The next line contains n integers t1, t2, ..., tn (1 β€ t1 < t2 < ... < tn β€ 109), where ti denotes the second when ZS the Coder typed the i-th word.
Output
Print a single positive integer, the number of words that remain on the screen after all n words was typed, in other words, at the second tn.
Examples
Input
6 5
1 3 8 14 19 20
Output
3
Input
6 1
1 3 5 7 9 10
Output
2
Note
The first sample is already explained in the problem statement.
For the second sample, after typing the first word at the second 1, it disappears because the next word is typed at the second 3 and 3 - 1 > 1. Similarly, only 1 word will remain at the second 9. Then, a word is typed at the second 10, so there will be two words on the screen, as the old word won't disappear because 10 - 9 β€ 1.
Submitted Solution:
```
n,m = map(int,input().split())
a = [int(s) for s in input().split()]
count = 0
for i in range(n - 1):
if abs(a[i] - a[i + 1]) > m :
count = 1
else:
count += 1
print(count)
``` | instruction | 0 | 96,646 | 6 | 193,292 |
No | output | 1 | 96,646 | 6 | 193,293 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya has a string of length n consisting of small and large English letters and digits.
He performs m operations. Each operation is described with two integers l and r and a character c: Petya removes from the string all characters c on positions between l and r, inclusive. It's obvious that the length of the string remains the same or decreases after each operation.
Find how the string will look like after Petya performs all m operations.
Input
The first string contains two integers n and m (1 β€ n, m β€ 2Β·105) β the length of the string and the number of operations.
The second line contains the string of length n, consisting of small and large English letters and digits. Positions in the string are enumerated from 1.
Each of the next m lines contains two integers l and r (1 β€ l β€ r), followed by a character c, which is a small or large English letter or a digit. This line describes one operation. It is guaranteed that r doesn't exceed the length of the string s before current operation.
Output
Print the string Petya will obtain after performing all m operations. If the strings becomes empty after all operations, print an empty line.
Examples
Input
4 2
abac
1 3 a
2 2 c
Output
b
Input
3 2
A0z
1 3 0
1 1 z
Output
Az
Input
10 4
agtFrgF4aF
2 5 g
4 9 F
1 5 4
1 7 a
Output
tFrg4
Input
9 5
aAAaBBccD
1 4 a
5 6 c
2 3 B
4 4 D
2 3 A
Output
AB
Note
In the first example during the first operation both letters 'a' are removed, so the string becomes "bc". During the second operation the letter 'c' (on the second position) is removed, and the string becomes "b".
In the second example during the first operation Petya removes '0' from the second position. After that the string becomes "Az". During the second operations the string doesn't change. | instruction | 0 | 96,690 | 6 | 193,380 |
Tags: data structures, strings
Correct Solution:
```
#!/usr/bin/env python
import os
import sys
from io import BytesIO, IOBase
class FenwickTree:
def __init__(self, x):
"""transform list into BIT"""
self.bit = x
for i in range(len(x)):
j = i | (i + 1)
if j < len(x):
x[j] += x[i]
def update(self, idx, x):
"""updates bit[idx] += x"""
while idx < len(self.bit):
self.bit[idx] += x
idx |= idx + 1
def query(self, end):
"""calc sum(bit[:end])"""
x = 0
while end:
x += self.bit[end - 1]
end &= end - 1
return x
def findkth(self, k):
"""Find largest idx such that sum(bit[:idx]) <= k"""
idx = -1
for d in reversed(range(len(self.bit).bit_length())):
right_idx = idx + (1 << d)
if right_idx < len(self.bit) and k >= self.bit[right_idx]:
idx = right_idx
k -= self.bit[idx]
return idx + 1
def lb(a,x):
l,r=-1,len(a)
while(r-l>1):
m=(l+r)//2
if(a[m]<x):
l=m
else:
r=m
return r
def main():
n,m=map(int,input().split())
# print (n,m)
s=input()
a = [ [] for _ in range(256)]
b = FenwickTree([1]*len(s))
for i,x in enumerate(s):
a[ord(x)].append(i+1)
# print(s)
# print(a)
for _ in range(m):
l,r,c=input().split()
l,r=map(int,[l,r])
# print("k",l,b.findkth(l-1))
l,r=b.findkth(l),b.findkth(r)
# print(l,r,c)
c=ord(c)
l=lb(a[c],l)
r=lb(a[c],r+1)
for j in range(l,r):
# print("rm",a[c][j])
b.update(a[c][j],-1)
n-=1
a[c] = a[c][:l]+a[c][r:]
b = [ x for x in map(b.findkth,range(1,n+1))]
# print(b)
print("".join(s[x-1] for x in b))
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
# endregion
if __name__ == "__main__":
main()
``` | output | 1 | 96,690 | 6 | 193,381 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya has a string of length n consisting of small and large English letters and digits.
He performs m operations. Each operation is described with two integers l and r and a character c: Petya removes from the string all characters c on positions between l and r, inclusive. It's obvious that the length of the string remains the same or decreases after each operation.
Find how the string will look like after Petya performs all m operations.
Input
The first string contains two integers n and m (1 β€ n, m β€ 2Β·105) β the length of the string and the number of operations.
The second line contains the string of length n, consisting of small and large English letters and digits. Positions in the string are enumerated from 1.
Each of the next m lines contains two integers l and r (1 β€ l β€ r), followed by a character c, which is a small or large English letter or a digit. This line describes one operation. It is guaranteed that r doesn't exceed the length of the string s before current operation.
Output
Print the string Petya will obtain after performing all m operations. If the strings becomes empty after all operations, print an empty line.
Examples
Input
4 2
abac
1 3 a
2 2 c
Output
b
Input
3 2
A0z
1 3 0
1 1 z
Output
Az
Input
10 4
agtFrgF4aF
2 5 g
4 9 F
1 5 4
1 7 a
Output
tFrg4
Input
9 5
aAAaBBccD
1 4 a
5 6 c
2 3 B
4 4 D
2 3 A
Output
AB
Note
In the first example during the first operation both letters 'a' are removed, so the string becomes "bc". During the second operation the letter 'c' (on the second position) is removed, and the string becomes "b".
In the second example during the first operation Petya removes '0' from the second position. After that the string becomes "Az". During the second operations the string doesn't change.
Submitted Solution:
```
nm=input().split()
lnm=list(map(int,nm))
n=lnm[0]
m=lnm[1]
strin = list(input())
for i in range(m):
fn = input().split()
l=int(fn[0])-1
r=int(fn[1])
c=fn[2]
copy=strin[l:r]
while c in copy:
copy.remove(c)
if r < len(strin) and l >0:
strin=strin[:l]+copy+strin[l+len(copy)+1:]
elif r==len(strin) and l>0:
strin=strin[:l]+copy
elif r<len(strin) and l == 0:
strin = copy +strin[l+len(copy)+1:]
else:
strin=copy
print(''.join(strin))
``` | instruction | 0 | 96,691 | 6 | 193,382 |
No | output | 1 | 96,691 | 6 | 193,383 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya has a string of length n consisting of small and large English letters and digits.
He performs m operations. Each operation is described with two integers l and r and a character c: Petya removes from the string all characters c on positions between l and r, inclusive. It's obvious that the length of the string remains the same or decreases after each operation.
Find how the string will look like after Petya performs all m operations.
Input
The first string contains two integers n and m (1 β€ n, m β€ 2Β·105) β the length of the string and the number of operations.
The second line contains the string of length n, consisting of small and large English letters and digits. Positions in the string are enumerated from 1.
Each of the next m lines contains two integers l and r (1 β€ l β€ r), followed by a character c, which is a small or large English letter or a digit. This line describes one operation. It is guaranteed that r doesn't exceed the length of the string s before current operation.
Output
Print the string Petya will obtain after performing all m operations. If the strings becomes empty after all operations, print an empty line.
Examples
Input
4 2
abac
1 3 a
2 2 c
Output
b
Input
3 2
A0z
1 3 0
1 1 z
Output
Az
Input
10 4
agtFrgF4aF
2 5 g
4 9 F
1 5 4
1 7 a
Output
tFrg4
Input
9 5
aAAaBBccD
1 4 a
5 6 c
2 3 B
4 4 D
2 3 A
Output
AB
Note
In the first example during the first operation both letters 'a' are removed, so the string becomes "bc". During the second operation the letter 'c' (on the second position) is removed, and the string becomes "b".
In the second example during the first operation Petya removes '0' from the second position. After that the string becomes "Az". During the second operations the string doesn't change.
Submitted Solution:
```
def pro(s, oper):
k = oper.split()
x = int(k[0])
y = int(k[1])
ss = k[2]
s2 = list(s)
if x == 1:
if y == n:
while (ss in s2)==True:
s2.remove(ss)
return ''.join(s2)
else:
s21 = s2[:y]
s22 = s2[y:]
while (ss in s21)==True:
s21.remove(ss)
return ''.join(s21+s22)
else:
if y == n:
s21 = s2[x-1:]
s22 = s2[:x-1]
while (ss in s21)==True:
s21.remove(ss)
return ''.join(s21+s22)
else:
s21 = s2[x-1:y]
s22 = s2[:x-1]
s23 = s2[y:]
while (ss in s21)==True:
s21.remove(ss)
return ''.join(s22+s21+s23)
s = input()
k = list(map(int, s.split()))
n = k[0]
m = k[1]
origin = input()
list1 = []
for i in range(0, m):
list1.append(input())
for i in list1:
origin = pro(origin, i)
if len(origin) == 0:
print()
else:
print(origin)
``` | instruction | 0 | 96,692 | 6 | 193,384 |
No | output | 1 | 96,692 | 6 | 193,385 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya has a string of length n consisting of small and large English letters and digits.
He performs m operations. Each operation is described with two integers l and r and a character c: Petya removes from the string all characters c on positions between l and r, inclusive. It's obvious that the length of the string remains the same or decreases after each operation.
Find how the string will look like after Petya performs all m operations.
Input
The first string contains two integers n and m (1 β€ n, m β€ 2Β·105) β the length of the string and the number of operations.
The second line contains the string of length n, consisting of small and large English letters and digits. Positions in the string are enumerated from 1.
Each of the next m lines contains two integers l and r (1 β€ l β€ r), followed by a character c, which is a small or large English letter or a digit. This line describes one operation. It is guaranteed that r doesn't exceed the length of the string s before current operation.
Output
Print the string Petya will obtain after performing all m operations. If the strings becomes empty after all operations, print an empty line.
Examples
Input
4 2
abac
1 3 a
2 2 c
Output
b
Input
3 2
A0z
1 3 0
1 1 z
Output
Az
Input
10 4
agtFrgF4aF
2 5 g
4 9 F
1 5 4
1 7 a
Output
tFrg4
Input
9 5
aAAaBBccD
1 4 a
5 6 c
2 3 B
4 4 D
2 3 A
Output
AB
Note
In the first example during the first operation both letters 'a' are removed, so the string becomes "bc". During the second operation the letter 'c' (on the second position) is removed, and the string becomes "b".
In the second example during the first operation Petya removes '0' from the second position. After that the string becomes "Az". During the second operations the string doesn't change.
Submitted Solution:
```
nm=input().split()
lnm=list(map(int,nm))
n=lnm[0]
m=lnm[1]
strin = list(input())
for i in range(m):
fn = input().split()
l=int(fn[0])-1
r=int(fn[1])
c=fn[2]
while c in strin[l:r]:
strin.remove(c)
print(''.join(strin))
``` | instruction | 0 | 96,693 | 6 | 193,386 |
No | output | 1 | 96,693 | 6 | 193,387 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya has a string of length n consisting of small and large English letters and digits.
He performs m operations. Each operation is described with two integers l and r and a character c: Petya removes from the string all characters c on positions between l and r, inclusive. It's obvious that the length of the string remains the same or decreases after each operation.
Find how the string will look like after Petya performs all m operations.
Input
The first string contains two integers n and m (1 β€ n, m β€ 2Β·105) β the length of the string and the number of operations.
The second line contains the string of length n, consisting of small and large English letters and digits. Positions in the string are enumerated from 1.
Each of the next m lines contains two integers l and r (1 β€ l β€ r), followed by a character c, which is a small or large English letter or a digit. This line describes one operation. It is guaranteed that r doesn't exceed the length of the string s before current operation.
Output
Print the string Petya will obtain after performing all m operations. If the strings becomes empty after all operations, print an empty line.
Examples
Input
4 2
abac
1 3 a
2 2 c
Output
b
Input
3 2
A0z
1 3 0
1 1 z
Output
Az
Input
10 4
agtFrgF4aF
2 5 g
4 9 F
1 5 4
1 7 a
Output
tFrg4
Input
9 5
aAAaBBccD
1 4 a
5 6 c
2 3 B
4 4 D
2 3 A
Output
AB
Note
In the first example during the first operation both letters 'a' are removed, so the string becomes "bc". During the second operation the letter 'c' (on the second position) is removed, and the string becomes "b".
In the second example during the first operation Petya removes '0' from the second position. After that the string becomes "Az". During the second operations the string doesn't change.
Submitted Solution:
```
stline = input()
stline = stline.split()
stline = list(map(int, stline))
seclinestring = input()
newstring = ""
lstofm = []
n = stline[0] # length of the string
m = stline[1] # number of the operations
for i in range(0, m):
lstofm.append(input())
for row in range(0, m):
l = int(lstofm[row][0])-1
r = int(lstofm[row][2])
a = lstofm[row][4]
newstring = seclinestring[:l]
substring = seclinestring[l:r]
for index in range(0,len(substring)):
if substring[index] != a:
newstring = newstring + substring[index]
newstring = newstring + seclinestring[r:]
seclinestring = newstring
print(newstring)
``` | instruction | 0 | 96,694 | 6 | 193,388 |
No | output | 1 | 96,694 | 6 | 193,389 |
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