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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Roy and Biv have a set of n points on the infinite number line. Each point has one of 3 colors: red, green, or blue. Roy and Biv would like to connect all the points with some edges. Edges can be drawn between any of the two of the given points. The cost of an edge is equal to the distance between the two points it connects. They want to do this in such a way that they will both see that all the points are connected (either directly or indirectly). However, there is a catch: Roy cannot see the color red and Biv cannot see the color blue. Therefore, they have to choose the edges in such a way that if all the red points are removed, the remaining blue and green points are connected (and similarly, if all the blue points are removed, the remaining red and green points are connected). Help them compute the minimum cost way to choose edges to satisfy the above constraints. Input The first line will contain an integer n (1 ≤ n ≤ 300 000), the number of points. The next n lines will contain two tokens pi and ci (pi is an integer, 1 ≤ pi ≤ 109, ci is a uppercase English letter 'R', 'G' or 'B'), denoting the position of the i-th point and the color of the i-th point. 'R' means red, 'G' denotes green, and 'B' means blue. The positions will be in strictly increasing order. Output Print a single integer, the minimum cost way to solve the problem. Examples Input 4 1 G 5 R 10 B 15 G Output 23 Input 4 1 G 2 R 3 B 10 G Output 12 Note In the first sample, it is optimal to draw edges between the points (1,2), (1,4), (3,4). These have costs 4, 14, 5, respectively. Submitted Solution: ``` # Collaborated with Rudransh Singh n = int(input()) r = 0 g = 0 b = 0 maxR = 0 maxB = 0 maxG = 0 minCost = 0 for i in range(n): p, c = input().split(" ") p = int(p) if c == "R" or c == "G": if r: minCost += p - r maxR = max(maxR, p - r) r = p if c == "B" or c == "G": if b: minCost += p - b maxB = max(maxB, p - b) b = p if c == "G": if g: minCost += min(0, p - g - maxR - maxB) g = p maxR = 0 maxB = 0 print(minCost) ```
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Roy and Biv have a set of n points on the infinite number line. Each point has one of 3 colors: red, green, or blue. Roy and Biv would like to connect all the points with some edges. Edges can be drawn between any of the two of the given points. The cost of an edge is equal to the distance between the two points it connects. They want to do this in such a way that they will both see that all the points are connected (either directly or indirectly). However, there is a catch: Roy cannot see the color red and Biv cannot see the color blue. Therefore, they have to choose the edges in such a way that if all the red points are removed, the remaining blue and green points are connected (and similarly, if all the blue points are removed, the remaining red and green points are connected). Help them compute the minimum cost way to choose edges to satisfy the above constraints. Input The first line will contain an integer n (1 ≤ n ≤ 300 000), the number of points. The next n lines will contain two tokens pi and ci (pi is an integer, 1 ≤ pi ≤ 109, ci is a uppercase English letter 'R', 'G' or 'B'), denoting the position of the i-th point and the color of the i-th point. 'R' means red, 'G' denotes green, and 'B' means blue. The positions will be in strictly increasing order. Output Print a single integer, the minimum cost way to solve the problem. Examples Input 4 1 G 5 R 10 B 15 G Output 23 Input 4 1 G 2 R 3 B 10 G Output 12 Note In the first sample, it is optimal to draw edges between the points (1,2), (1,4), (3,4). These have costs 4, 14, 5, respectively. Submitted Solution: ``` k=int(input()) t,a,b,m,n,o,d,e,s,x,y,z,l=13*[0] for i in range(k): c=input().split(" ") f=int(c[0]) if c[1]=="G": if o<1: z=f if t: if m>0: d=max(d,f-m) if n>0: e=max(e,f-n) s+=min(2*(f-o),3*(f-o)-d-e) d,e,a,b=4*[0] m=f n=f o=f t=1 l+=1 if c[1]=="R": a+=1 if m<1: x=f if m>0 and t: d=max(d,f-m) m=f if c[1]=="B": b+=1 if n<1: y=f if n>0 and t: e=max(e,f-n) n=f if l>0: if a>0: s+=m-o if b>0: s+=n-o if x>0: s+=z-x if y>0: s+=z-y else: s=m-x+n-y print(s) ```
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Roy and Biv have a set of n points on the infinite number line. Each point has one of 3 colors: red, green, or blue. Roy and Biv would like to connect all the points with some edges. Edges can be drawn between any of the two of the given points. The cost of an edge is equal to the distance between the two points it connects. They want to do this in such a way that they will both see that all the points are connected (either directly or indirectly). However, there is a catch: Roy cannot see the color red and Biv cannot see the color blue. Therefore, they have to choose the edges in such a way that if all the red points are removed, the remaining blue and green points are connected (and similarly, if all the blue points are removed, the remaining red and green points are connected). Help them compute the minimum cost way to choose edges to satisfy the above constraints. Input The first line will contain an integer n (1 ≤ n ≤ 300 000), the number of points. The next n lines will contain two tokens pi and ci (pi is an integer, 1 ≤ pi ≤ 109, ci is a uppercase English letter 'R', 'G' or 'B'), denoting the position of the i-th point and the color of the i-th point. 'R' means red, 'G' denotes green, and 'B' means blue. The positions will be in strictly increasing order. Output Print a single integer, the minimum cost way to solve the problem. Examples Input 4 1 G 5 R 10 B 15 G Output 23 Input 4 1 G 2 R 3 B 10 G Output 12 Note In the first sample, it is optimal to draw edges between the points (1,2), (1,4), (3,4). These have costs 4, 14, 5, respectively. Submitted Solution: ``` #Problem Set F: Collaborated with no one n = int(input()) result = 0 temp = 0 b_red = 0 b_blue = 0 final_red = -1 final_blue = -1 final_green = -(1<<60) for i in range(n): cost_colorList = input().split() cost = int(cost_colorList[0]) color = cost_colorList[1] if color == 'R' or color == 'G': if final_red != -1: b_red = max(b_red, cost - final_red) temp += cost - final_red final_red = cost if color == 'B' or color == 'G': if final_blue != -1: b_blue = max(b_blue, cost - final_blue) temp += cost - final_blue final_blue = cost if color == 'G': result += temp + min(0, - b_red - b_blue + cost - final_green) final_red = final_blue = final_green = cost b_red = b_blue = temp = 0 result += temp print(result) ```
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Roy and Biv have a set of n points on the infinite number line. Each point has one of 3 colors: red, green, or blue. Roy and Biv would like to connect all the points with some edges. Edges can be drawn between any of the two of the given points. The cost of an edge is equal to the distance between the two points it connects. They want to do this in such a way that they will both see that all the points are connected (either directly or indirectly). However, there is a catch: Roy cannot see the color red and Biv cannot see the color blue. Therefore, they have to choose the edges in such a way that if all the red points are removed, the remaining blue and green points are connected (and similarly, if all the blue points are removed, the remaining red and green points are connected). Help them compute the minimum cost way to choose edges to satisfy the above constraints. Input The first line will contain an integer n (1 ≤ n ≤ 300 000), the number of points. The next n lines will contain two tokens pi and ci (pi is an integer, 1 ≤ pi ≤ 109, ci is a uppercase English letter 'R', 'G' or 'B'), denoting the position of the i-th point and the color of the i-th point. 'R' means red, 'G' denotes green, and 'B' means blue. The positions will be in strictly increasing order. Output Print a single integer, the minimum cost way to solve the problem. Examples Input 4 1 G 5 R 10 B 15 G Output 23 Input 4 1 G 2 R 3 B 10 G Output 12 Note In the first sample, it is optimal to draw edges between the points (1,2), (1,4), (3,4). These have costs 4, 14, 5, respectively. Submitted Solution: ``` n = int( input() ) G = [] R = [] B = [] a = [] L1, L2 = [], [] for i in range( n ): p, c = input().split() p = int(p) a.append( (p,c) ) if c == 'G': G.append(p) L1.append(i) L2.append(i) elif c == 'R': R.append(p) L1.append(i) else: B.append(p) L2.append(i) ans = 0 edges = [] for i in range( 1, len(G) ): edges.append( abs( G[i] - G[i-1] ) ) #ans += min( abs( G[i]-G[i+1] ), abs( G[i]-G[i-1] ) ) #connect (1st, last) or (1st,2nd) + (last,last-1) g=len(G)-1 #ans += min( abs( G[0] - G[-1] ), abs( G[0]-G[1] ) + abs( G[g]-G[g-1] ) ) #ans = sum(edges) #if len(edges) > 1: # ans -= max(edges) #print(ans) def left_right_points( what, G ): global ans #left from first G idx = 0 has_found_what = False points = [] while idx < len(a): if a[idx][1] == 'G': if has_found_what == False: return else: points.append( a[idx][0] ) #calculate for i in range(1, len(points) ): ans += abs( points[i] - points[i-1] ) break elif a[idx][1] == what: points.append( a[idx][0] ) has_found_what = True idx += 1 idx = len(a)-1 has_found_what = False points = [] while idx >= 0: if a[idx][1] == 'G': if has_found_what == False: return else: points.append( a[idx][0] ) #calculate for i in range(1, len(points) ): ans += abs( points[i] - points[i-1] ) break elif a[idx][1] == what: points.append( a[idx][0] ) has_found_what = True idx -= 1 left_right_points( 'R', G ) left_right_points( 'B', G ) def intermediate_points( L1, what, left_green, right_green ): global ans edges = [] ok = False for j in range( left_green, right_green+1 ): if a[ L1[j] ][1] == what: ok = True break if ok == False: return for j in range( left_green+1, right_green+1 ): #print( a[ L1[j-1] ][1], a[ L1[j] ][1] ) prev_point = a[ L1[j-1] ][0] cur_point = a[ L1[j] ][0] dist = abs( prev_point - cur_point ) edges.append( dist ) prev_point = a[ L1[left_green] ][0] cur_point = a[ L1[right_green] ][0] edges.append( abs( prev_point - cur_point ) ) ans += sum( edges ) if len(edges) > 1: ans -= max(edges) def intermediate_green_segments( L1, what ): global ans left_green, right_green = -1, -1 for i in range( len(L1) ): if a[ L1[i] ][1] == 'G': if left_green == -1: left_green = i elif right_green == -1: right_green = i else: left_green, right_green = right_green, i #rint( left_green, right_green ) intermediate_points( L1, what, left_green, right_green ) intermediate_points( L1, what, left_green, right_green ) intermediate_green_segments( L1, 'R' ) intermediate_green_segments( L2, 'B' ) #print( dist1, dist2 ) print( ans ) ```
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Roy and Biv have a set of n points on the infinite number line. Each point has one of 3 colors: red, green, or blue. Roy and Biv would like to connect all the points with some edges. Edges can be drawn between any of the two of the given points. The cost of an edge is equal to the distance between the two points it connects. They want to do this in such a way that they will both see that all the points are connected (either directly or indirectly). However, there is a catch: Roy cannot see the color red and Biv cannot see the color blue. Therefore, they have to choose the edges in such a way that if all the red points are removed, the remaining blue and green points are connected (and similarly, if all the blue points are removed, the remaining red and green points are connected). Help them compute the minimum cost way to choose edges to satisfy the above constraints. Input The first line will contain an integer n (1 ≤ n ≤ 300 000), the number of points. The next n lines will contain two tokens pi and ci (pi is an integer, 1 ≤ pi ≤ 109, ci is a uppercase English letter 'R', 'G' or 'B'), denoting the position of the i-th point and the color of the i-th point. 'R' means red, 'G' denotes green, and 'B' means blue. The positions will be in strictly increasing order. Output Print a single integer, the minimum cost way to solve the problem. Examples Input 4 1 G 5 R 10 B 15 G Output 23 Input 4 1 G 2 R 3 B 10 G Output 12 Note In the first sample, it is optimal to draw edges between the points (1,2), (1,4), (3,4). These have costs 4, 14, 5, respectively. Submitted Solution: ``` n = int( input() ) min_red, max_red = -1, -1 min_blue, max_blue = -1, -1 left_green, right_green = -1, -1 a = [] ans = 0 last_r, last_b, last_g = -1, -1, -1 r_edges = [] b_edges = [] g_edges = [] for i in range( n ): p, c = input().split() p = int(p) if c == 'R' or c == 'G': if last_r != -1: r_edges.append( p - last_r ) last_r = p if c == 'B' or c == 'G': if last_b != -1: b_edges.append( p - last_b ) last_b = p if c == 'G': ans += sum(r_edges) + sum(b_edges) if len(r_edges) > 0 and len(b_edges) > 0: #print( r_edges ) #print( b_edges ) max_red = max(r_edges) max_blue = max(b_edges) if max_red+max_blue > p-last_g: ans -= (max_red+max_blue) r_edges = [ ] b_edges = [ ] if last_g != -1: ans += p-last_g last_g = p ans += sum(r_edges) + sum(b_edges) print( ans ) ```
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Roy and Biv have a set of n points on the infinite number line. Each point has one of 3 colors: red, green, or blue. Roy and Biv would like to connect all the points with some edges. Edges can be drawn between any of the two of the given points. The cost of an edge is equal to the distance between the two points it connects. They want to do this in such a way that they will both see that all the points are connected (either directly or indirectly). However, there is a catch: Roy cannot see the color red and Biv cannot see the color blue. Therefore, they have to choose the edges in such a way that if all the red points are removed, the remaining blue and green points are connected (and similarly, if all the blue points are removed, the remaining red and green points are connected). Help them compute the minimum cost way to choose edges to satisfy the above constraints. Input The first line will contain an integer n (1 ≤ n ≤ 300 000), the number of points. The next n lines will contain two tokens pi and ci (pi is an integer, 1 ≤ pi ≤ 109, ci is a uppercase English letter 'R', 'G' or 'B'), denoting the position of the i-th point and the color of the i-th point. 'R' means red, 'G' denotes green, and 'B' means blue. The positions will be in strictly increasing order. Output Print a single integer, the minimum cost way to solve the problem. Examples Input 4 1 G 5 R 10 B 15 G Output 23 Input 4 1 G 2 R 3 B 10 G Output 12 Note In the first sample, it is optimal to draw edges between the points (1,2), (1,4), (3,4). These have costs 4, 14, 5, respectively. Submitted Solution: ``` n = int( input() ) G = [] R = [] B = [] a = [] L1, L2 = [], [] for i in range( n ): p, c = input().split() p = int(p) a.append( (p,c) ) if c == 'G': G.append(p) L1.append(i) L2.append(i) elif c == 'R': R.append(p) L1.append(i) else: B.append(p) L2.append(i) ans = 0 edges = [] for i in range( 1, len(G) ): edges.append( abs( G[i] - G[i-1] ) ) #ans += min( abs( G[i]-G[i+1] ), abs( G[i]-G[i-1] ) ) #connect (1st, last) or (1st,2nd) + (last,last-1) g=len(G)-1 #ans += min( abs( G[0] - G[-1] ), abs( G[0]-G[1] ) + abs( G[g]-G[g-1] ) ) ans = sum(edges) if len(edges) > 1: ans -= max(edges) #print(ans) def left_right_points( what, G ): global ans #left from first G idx = 0 has_found_what = False points = [] while idx < len(a): if a[idx][1] == 'G': if has_found_what == False: return else: points.append( a[idx][0] ) #calculate for i in range(1, len(points) ): ans += abs( points[i] - points[i-1] ) elif a[idx][1] == what: points.append( a[idx][0] ) has_found_what = True idx += 1 idx = len(a)-1 has_found_what = False points = [] while idx >= 0: if a[idx][1] == 'G': if has_found_what == False: return else: points.append( a[idx][0] ) #calculate for i in range(1, len(points) ): ans += abs( points[i] - points[i-1] ) elif a[idx][1] == what: points.append( a[idx][0] ) has_found_what = True idx -= 1 left_right_points( 'R', G ) left_right_points( 'B', G ) def intermediate_points( L1, what, left_green, right_green ): global ans edges = [] ok = False for j in range( left_green, right_green+1 ): if a[ L1[j] ][1] == what: ok = True break if ok == False: return for j in range( left_green+1, right_green+1 ): #print( a[ L1[j-1] ][1], a[ L1[j] ][1] ) prev_point = a[ L1[j-1] ][0] cur_point = a[ L1[j] ][0] dist = abs( prev_point - cur_point ) edges.append( dist ) ans += sum( edges ) if len(edges) > 1: ans -= max(edges) def intermediate_green_segments( L1, what ): global ans left_green, right_green = -1, -1 for i in range( len(L1) ): if a[ L1[i] ][1] == 'G': if left_green == -1: left_green = i elif right_green == -1: right_green = i else: left_green, right_green = right_green, i #rint( left_green, right_green ) intermediate_points( L1, what, left_green, right_green ) intermediate_points( L1, what, left_green, right_green ) intermediate_green_segments( L1, 'R' ) intermediate_green_segments( L2, 'B' ) #print( dist1, dist2 ) print( ans ) ```
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Roy and Biv have a set of n points on the infinite number line. Each point has one of 3 colors: red, green, or blue. Roy and Biv would like to connect all the points with some edges. Edges can be drawn between any of the two of the given points. The cost of an edge is equal to the distance between the two points it connects. They want to do this in such a way that they will both see that all the points are connected (either directly or indirectly). However, there is a catch: Roy cannot see the color red and Biv cannot see the color blue. Therefore, they have to choose the edges in such a way that if all the red points are removed, the remaining blue and green points are connected (and similarly, if all the blue points are removed, the remaining red and green points are connected). Help them compute the minimum cost way to choose edges to satisfy the above constraints. Input The first line will contain an integer n (1 ≤ n ≤ 300 000), the number of points. The next n lines will contain two tokens pi and ci (pi is an integer, 1 ≤ pi ≤ 109, ci is a uppercase English letter 'R', 'G' or 'B'), denoting the position of the i-th point and the color of the i-th point. 'R' means red, 'G' denotes green, and 'B' means blue. The positions will be in strictly increasing order. Output Print a single integer, the minimum cost way to solve the problem. Examples Input 4 1 G 5 R 10 B 15 G Output 23 Input 4 1 G 2 R 3 B 10 G Output 12 Note In the first sample, it is optimal to draw edges between the points (1,2), (1,4), (3,4). These have costs 4, 14, 5, respectively. Submitted Solution: ``` n = int(input()); A = []; B = []; for q in range(n): a, b = input().split(); B.append(int(a)); A.append(b); g1 = -100000000000; g2 = -100000000000; blues = []; reds = []; res = 0; for q in range(n): if A[q] == "B": blues.append(B[q]); if A[q] == "R": reds.append(B[q]); if A[q] == "G": g1 = g2; g2 = B[q]; for w in range(1, len(blues)): res = res + blues[w] - blues[w - 1]; for e in range(1, len(reds)): res = res + reds[e] - reds[e - 1]; if len(blues) > 0: resb = min(blues[0] - g1, g2 - blues[len(blues) - 1]); bl = max(blues[0] - g1, g2 - blues[len(blues) - 1]); else: resb = 0; bl = 10000000000; if len(reds) > 0: resr = min(reds[0] - g1, g2 - reds[len(reds) - 1]); rl = max(reds[0] - g1, g2 - reds[len(reds) - 1]); else: resr = 0; rl = 100000000000; res = res + resb + resr; if g1 != -100000000000: #print(res); res = res + min(g2 - g1, bl + rl); #if g1 != -100000000000: # mi = g2 - g1; # if bl blues = []; reds = []; if g2 != -100000000000: if len(blues) > 0: res = res + blues[0] - g2; if len(reds) > 0: res = res + reds[0] - g2; for q in range(1, len(blues)): res = res + blues[q] - blues[q - 1]; for q in range(1, len(reds)): res = res + reds[q] - reds[q - 1]; print(res); ```
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Provide tags and a correct Python 3 solution for this coding contest problem. President of Berland has a very vast office-room, where, apart from him, work his subordinates. Each subordinate, as well as President himself, has his own desk of a unique colour. Each desk is rectangular, and its sides are parallel to the office walls. One day President decided to establish an assembly, of which all his deputies will be members. Unfortunately, he does not remember the exact amount of his deputies, but he remembers that the desk of each his deputy is adjacent to his own desk, that is to say, the two desks (President's and each deputy's) have a common side of a positive length. The office-room plan can be viewed as a matrix with n rows and m columns. Each cell of this matrix is either empty, or contains a part of a desk. An uppercase Latin letter stands for each desk colour. The «period» character («.») stands for an empty cell. Input The first line contains two separated by a space integer numbers n, m (1 ≤ n, m ≤ 100) — the length and the width of the office-room, and c character — the President's desk colour. The following n lines contain m characters each — the office-room description. It is guaranteed that the colour of each desk is unique, and each desk represents a continuous subrectangle of the given matrix. All colours are marked by uppercase Latin letters. Output Print the only number — the amount of President's deputies. Examples Input 3 4 R G.B. .RR. TTT. Output 2 Input 3 3 Z ... .H. ..Z Output 0
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Tags: implementation Correct Solution: ``` n , m , p = input().strip().split(' ') n , m = int(n), int(m) M = [[None for _ in range(m)] for _ in range(n)] for i in range(n): s = input().strip() for j in range(m): M[i][j] = s[j] T = [[False for _ in range(m)] for _ in range(n)] for i in range(n): for j in range(m): if M[i][j] == p: a , b , c , d , e , f , g , h = i , j - 1 , i , j + 1 , i - 1 , j , i + 1 , j if 0 <= a < n and 0 <= b < m: T[a][b] = True if 0 <= c < n and 0 <= d < m: T[c][d] = True if 0 <= e < n and 0 <= f < m: T[e][f] = True if 0 <= g < n and 0 <= h < m: T[g][h] = True ans = 0 x = [False for _ in range(26)] for i in range(n): for j in range(m): c = M[i][j] if c != '.' and c != p: if T[i][j] == True and x[ord(c)- ord('A')] == False: x[ord(c)-ord('A')] = True ans += 1 print(ans) ```
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Provide tags and a correct Python 3 solution for this coding contest problem. President of Berland has a very vast office-room, where, apart from him, work his subordinates. Each subordinate, as well as President himself, has his own desk of a unique colour. Each desk is rectangular, and its sides are parallel to the office walls. One day President decided to establish an assembly, of which all his deputies will be members. Unfortunately, he does not remember the exact amount of his deputies, but he remembers that the desk of each his deputy is adjacent to his own desk, that is to say, the two desks (President's and each deputy's) have a common side of a positive length. The office-room plan can be viewed as a matrix with n rows and m columns. Each cell of this matrix is either empty, or contains a part of a desk. An uppercase Latin letter stands for each desk colour. The «period» character («.») stands for an empty cell. Input The first line contains two separated by a space integer numbers n, m (1 ≤ n, m ≤ 100) — the length and the width of the office-room, and c character — the President's desk colour. The following n lines contain m characters each — the office-room description. It is guaranteed that the colour of each desk is unique, and each desk represents a continuous subrectangle of the given matrix. All colours are marked by uppercase Latin letters. Output Print the only number — the amount of President's deputies. Examples Input 3 4 R G.B. .RR. TTT. Output 2 Input 3 3 Z ... .H. ..Z Output 0
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7
2,636
Tags: implementation Correct Solution: ``` t=list(map(str,input().split())) a=[] for _ in range(int(t[0])): a.append(input()) r=[] #print(a) n=int(t[0]) m=int(t[1]) for i in range(n-1): for j in range(m-1): if a[i][j]!='.' and a[i][j+1]==t[2] and a[i][j]!=t[2]: r.append(a[i][j]) if a[i][j]==t[2] and a[i+1][j]!='.' and a[i+1][j]!=t[2]: r.append(a[i+1][j]) if a[i][j]==t[2] and a[i][j+1]!=t[2] and a[i][j+1]!='.': r.append(a[i][j+1]) if a[i][j]!='.' and a[i+1][j]==t[2] and a[i][j]!=t[2]: r.append(a[i][j]) for i in range(n-1): if a[i][m-1]==t[2] and a[i+1][m-1]!='.' and a[i+1][m-1]!=t[2]: r.append(a[i+1][m-1]) if a[i][m-1]!='.' and a[i+1][m-1]==t[2] and a[i][m-1]!=t[2]: r.append(a[i][m-1]) for i in range(m-1): if a[n-1][i]==t[2] and a[n-1][i+1]!='.' and a[n-1][i+1]!=t[2]: r.append(a[n-1][i+1]) if a[n-1][i]!='.' and a[n-1][i+1]==t[2] and a[n-1][i]!=t[2]: r.append(a[n-1][i]) #print(r) r=set(r) print(len(r)) ```
output
1
1,318
7
2,637
Provide tags and a correct Python 3 solution for this coding contest problem. President of Berland has a very vast office-room, where, apart from him, work his subordinates. Each subordinate, as well as President himself, has his own desk of a unique colour. Each desk is rectangular, and its sides are parallel to the office walls. One day President decided to establish an assembly, of which all his deputies will be members. Unfortunately, he does not remember the exact amount of his deputies, but he remembers that the desk of each his deputy is adjacent to his own desk, that is to say, the two desks (President's and each deputy's) have a common side of a positive length. The office-room plan can be viewed as a matrix with n rows and m columns. Each cell of this matrix is either empty, or contains a part of a desk. An uppercase Latin letter stands for each desk colour. The «period» character («.») stands for an empty cell. Input The first line contains two separated by a space integer numbers n, m (1 ≤ n, m ≤ 100) — the length and the width of the office-room, and c character — the President's desk colour. The following n lines contain m characters each — the office-room description. It is guaranteed that the colour of each desk is unique, and each desk represents a continuous subrectangle of the given matrix. All colours are marked by uppercase Latin letters. Output Print the only number — the amount of President's deputies. Examples Input 3 4 R G.B. .RR. TTT. Output 2 Input 3 3 Z ... .H. ..Z Output 0
instruction
0
1,319
7
2,638
Tags: implementation Correct Solution: ``` a = input().split() n = int(a[0]) m = int(a[1]) c = a[2] k = [] d = [] b = [] for i in range(n): st = input() k.append(st) for i in range(n): for j in range(m): if k[i][j] == c: d.append([i, j]) b.append(c) for i in range(len(d)): if d[i][0] != 0: if k[d[i][0] - 1][d[i][1]] != "." and k[d[i][0] - 1][d[i][1]] not in b: b.append(k[d[i][0] - 1][d[i][1]]) if d[i][1] != 0: if k[d[i][0]][d[i][1] - 1] != "." and k[d[i][0]][d[i][1] - 1] not in b: b.append(k[d[i][0]][d[i][1] - 1]) if d[i][0] != n - 1: if k[d[i][0] + 1][d[i][1]] != "." and k[d[i][0] + 1][d[i][1]] not in b: b.append(k[d[i][0] + 1][d[i][1]]) if d[i][1] != m - 1: if k[d[i][0]][d[i][1] + 1] != "." and k[d[i][0]][d[i][1] + 1] not in b: b.append(k[d[i][0]][d[i][1] + 1]) print(len(b) - 1) ```
output
1
1,319
7
2,639
Provide tags and a correct Python 3 solution for this coding contest problem. President of Berland has a very vast office-room, where, apart from him, work his subordinates. Each subordinate, as well as President himself, has his own desk of a unique colour. Each desk is rectangular, and its sides are parallel to the office walls. One day President decided to establish an assembly, of which all his deputies will be members. Unfortunately, he does not remember the exact amount of his deputies, but he remembers that the desk of each his deputy is adjacent to his own desk, that is to say, the two desks (President's and each deputy's) have a common side of a positive length. The office-room plan can be viewed as a matrix with n rows and m columns. Each cell of this matrix is either empty, or contains a part of a desk. An uppercase Latin letter stands for each desk colour. The «period» character («.») stands for an empty cell. Input The first line contains two separated by a space integer numbers n, m (1 ≤ n, m ≤ 100) — the length and the width of the office-room, and c character — the President's desk colour. The following n lines contain m characters each — the office-room description. It is guaranteed that the colour of each desk is unique, and each desk represents a continuous subrectangle of the given matrix. All colours are marked by uppercase Latin letters. Output Print the only number — the amount of President's deputies. Examples Input 3 4 R G.B. .RR. TTT. Output 2 Input 3 3 Z ... .H. ..Z Output 0
instruction
0
1,320
7
2,640
Tags: implementation Correct Solution: ``` n, m, c = input().split() n, m = map(int, (n, m)) a = [input() for i in range(n)] s = set() d = (0, 1), (1, 0), (0, -1), (-1, 0) cor = lambda x, y: 0 <= x < n and 0 <= y < m for i in range(n): for j in range(m): if a[i][j] == c: for dx, dy in d: ni, nj = i + dx, j + dy if cor(ni, nj): s.add(a[ni][nj]) s.discard('.') s.discard(c) ans = len(s) print(ans) ```
output
1
1,320
7
2,641
Provide tags and a correct Python 3 solution for this coding contest problem. President of Berland has a very vast office-room, where, apart from him, work his subordinates. Each subordinate, as well as President himself, has his own desk of a unique colour. Each desk is rectangular, and its sides are parallel to the office walls. One day President decided to establish an assembly, of which all his deputies will be members. Unfortunately, he does not remember the exact amount of his deputies, but he remembers that the desk of each his deputy is adjacent to his own desk, that is to say, the two desks (President's and each deputy's) have a common side of a positive length. The office-room plan can be viewed as a matrix with n rows and m columns. Each cell of this matrix is either empty, or contains a part of a desk. An uppercase Latin letter stands for each desk colour. The «period» character («.») stands for an empty cell. Input The first line contains two separated by a space integer numbers n, m (1 ≤ n, m ≤ 100) — the length and the width of the office-room, and c character — the President's desk colour. The following n lines contain m characters each — the office-room description. It is guaranteed that the colour of each desk is unique, and each desk represents a continuous subrectangle of the given matrix. All colours are marked by uppercase Latin letters. Output Print the only number — the amount of President's deputies. Examples Input 3 4 R G.B. .RR. TTT. Output 2 Input 3 3 Z ... .H. ..Z Output 0
instruction
0
1,321
7
2,642
Tags: implementation Correct Solution: ``` # Fast IO import sys input = sys.stdin.readline def print(x, end='\n'): sys.stdout.write(str(x) + end) # IO helpers def get_int(): return int(input()) def get_list_ints(): return list(map(int, input().split())) def get_char_list(): s = input() return list(s[:len(s) - 1]) def get_tuple_ints(): return tuple(map(int, input().split())) def print_iterable(p): print(" ".join(map(str, p))) #Code def main(): n, m, c = input().split() n=int(n) m=int(m) a=[] a=[get_char_list() for _ in range(n)] d=[] for i in range(n): for j in range(m): if a[i][j]==c: if i!=0: if a[i-1][j]!=c and a[i-1][j]!='.' and a[i-1][j] not in d: d+=[a[i-1][j]] if j!=0: if a[i][j-1]!=c and a[i][j-1]!='.' and a[i][j-1] not in d: d+=[a[i][j-1]] if i!=n-1: if a[i+1][j]!=c and a[i+1][j]!='.' and a[i+1][j] not in d: d+=[a[i+1][j]] if j!=m-1: if a[i][j+1]!=c and a[i][j+1]!='.' and a[i][j+1] not in d: d+=[a[i][j+1]] print(len(d)) if __name__=='__main__': main() ```
output
1
1,321
7
2,643
Provide tags and a correct Python 3 solution for this coding contest problem. President of Berland has a very vast office-room, where, apart from him, work his subordinates. Each subordinate, as well as President himself, has his own desk of a unique colour. Each desk is rectangular, and its sides are parallel to the office walls. One day President decided to establish an assembly, of which all his deputies will be members. Unfortunately, he does not remember the exact amount of his deputies, but he remembers that the desk of each his deputy is adjacent to his own desk, that is to say, the two desks (President's and each deputy's) have a common side of a positive length. The office-room plan can be viewed as a matrix with n rows and m columns. Each cell of this matrix is either empty, or contains a part of a desk. An uppercase Latin letter stands for each desk colour. The «period» character («.») stands for an empty cell. Input The first line contains two separated by a space integer numbers n, m (1 ≤ n, m ≤ 100) — the length and the width of the office-room, and c character — the President's desk colour. The following n lines contain m characters each — the office-room description. It is guaranteed that the colour of each desk is unique, and each desk represents a continuous subrectangle of the given matrix. All colours are marked by uppercase Latin letters. Output Print the only number — the amount of President's deputies. Examples Input 3 4 R G.B. .RR. TTT. Output 2 Input 3 3 Z ... .H. ..Z Output 0
instruction
0
1,322
7
2,644
Tags: implementation Correct Solution: ``` m, n, c = input().split() m = int(m) n = int(n) a = [[j for j in input()]for i in range(m)] inxs = list() con = list() fin = list() for i in range(m): for j in range(n): if a[i][j] == c: inxs.append(i) inxs.append(j) # if i == 0: # if j == 0: # if (a[0][1] != '.') & (a[0][1] != c): # con += 1 # if (a[1][0] != '.') & (a[1][0] != c): # con += 1 # if j == n-1: # if (a[0][n-2] != '.') & (a[0][n-2] != c): # con += 1 # if (a[1][n-1] != '.') & (a[1][n-1] != c): # con += 1 # if i == m-1: # if j == 0: # if (a[m-1][1] != '.') & (a[m-1][1] != c): # con += 1 # if (a[m-2][0] != '.') & (a[m-2][0] != c): # con += 1 # if j == n-1: # if (a[m-1][n-2] != '.') & (a[m-1][n-2] != c): # con += 1 # if (a[m-2][n-1] != '.') & (a[m-2][n-1] != c): # con += 1 for i in range(0, len(inxs), 2): if inxs[i+1] > 0: if (a[inxs[i]][inxs[i+1]-1] != c) & (a[inxs[i]][inxs[i+1]-1] != '.'): con.append(a[inxs[i]][inxs[i+1]-1]) if inxs[i+1] < n-1: if (a[inxs[i]][inxs[i+1]+1] != c) & (a[inxs[i]][inxs[i+1]+1] != '.'): con.append(a[inxs[i]][inxs[i+1]+1]) if inxs[i] > 0: if (a[inxs[i]-1][inxs[i+1]] != c) & (a[inxs[i]-1][inxs[i+1]] != '.'): con.append(a[inxs[i]-1][inxs[i+1]]) if inxs[i] < m-1: if (a[inxs[i]+1][inxs[i+1]] != c) & (a[inxs[i]+1][inxs[i+1]] != '.'): con.append(a[inxs[i]+1][inxs[i+1]]) for i in con: if i not in fin: fin.append(i) print(len(fin)) # def index_2d(a, c): # for i, e in enumerate(a): # try: # return i, e.index(c) # except ValueError: # pass # raise ValueError("{} is not in list".format(repr(c))) # print(index_2d(a, c)) ```
output
1
1,322
7
2,645
Provide tags and a correct Python 3 solution for this coding contest problem. President of Berland has a very vast office-room, where, apart from him, work his subordinates. Each subordinate, as well as President himself, has his own desk of a unique colour. Each desk is rectangular, and its sides are parallel to the office walls. One day President decided to establish an assembly, of which all his deputies will be members. Unfortunately, he does not remember the exact amount of his deputies, but he remembers that the desk of each his deputy is adjacent to his own desk, that is to say, the two desks (President's and each deputy's) have a common side of a positive length. The office-room plan can be viewed as a matrix with n rows and m columns. Each cell of this matrix is either empty, or contains a part of a desk. An uppercase Latin letter stands for each desk colour. The «period» character («.») stands for an empty cell. Input The first line contains two separated by a space integer numbers n, m (1 ≤ n, m ≤ 100) — the length and the width of the office-room, and c character — the President's desk colour. The following n lines contain m characters each — the office-room description. It is guaranteed that the colour of each desk is unique, and each desk represents a continuous subrectangle of the given matrix. All colours are marked by uppercase Latin letters. Output Print the only number — the amount of President's deputies. Examples Input 3 4 R G.B. .RR. TTT. Output 2 Input 3 3 Z ... .H. ..Z Output 0
instruction
0
1,323
7
2,646
Tags: implementation Correct Solution: ``` n,m,c = input().split(" ") n = int(n) m = int(m) M = [] temp = [] for i in range(m+2): temp.append('.') M.append(temp) for i in range(0,n): k = list(input()) k.insert(0,'.') k.insert(len(k),'.') M.append(k) M.append(temp) #print(M) d={} for i in range(1,n+1): for j in range(1,m+1): #print(M[i][j]) if M[i][j]==c : if M[i][j+1]!=c and M[i][j+1]!='.': d[M[i][j+1]] =1 if M[i+1][j]!=c and M[i+1][j]!='.': d[M[i+1][j]] =1 if M[i][j-1]!=c and M[i][j-1]!='.': d[M[i][j-1]] =1 if M[i-1][j]!=c and M[i-1][j]!='.': d[M[i-1][j]] =1 print(len(d)) ```
output
1
1,323
7
2,647
Provide tags and a correct Python 3 solution for this coding contest problem. President of Berland has a very vast office-room, where, apart from him, work his subordinates. Each subordinate, as well as President himself, has his own desk of a unique colour. Each desk is rectangular, and its sides are parallel to the office walls. One day President decided to establish an assembly, of which all his deputies will be members. Unfortunately, he does not remember the exact amount of his deputies, but he remembers that the desk of each his deputy is adjacent to his own desk, that is to say, the two desks (President's and each deputy's) have a common side of a positive length. The office-room plan can be viewed as a matrix with n rows and m columns. Each cell of this matrix is either empty, or contains a part of a desk. An uppercase Latin letter stands for each desk colour. The «period» character («.») stands for an empty cell. Input The first line contains two separated by a space integer numbers n, m (1 ≤ n, m ≤ 100) — the length and the width of the office-room, and c character — the President's desk colour. The following n lines contain m characters each — the office-room description. It is guaranteed that the colour of each desk is unique, and each desk represents a continuous subrectangle of the given matrix. All colours are marked by uppercase Latin letters. Output Print the only number — the amount of President's deputies. Examples Input 3 4 R G.B. .RR. TTT. Output 2 Input 3 3 Z ... .H. ..Z Output 0
instruction
0
1,324
7
2,648
Tags: implementation Correct Solution: ``` rows, columns, color = input().split() rows = int(rows) columns = int(columns) mat = [] desk = {color} for i in range(rows): mat.append(list(input())) for i in range(len(mat)): for j in range(columns): if mat[i][j] != '.': if j+1 < columns: if mat[i][j+1] == color: desk.add(mat[i][j]) if j-1 >=0: if mat[i][j-1] == color: desk.add(mat[i][j]) if i+1 < rows: if mat[i+1][j] == color: desk.add(mat[i][j]) if i-1 >=0: if mat[i-1][j] == color: desk.add(mat[i][j]) print(len(desk)-1) ```
output
1
1,324
7
2,649
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. President of Berland has a very vast office-room, where, apart from him, work his subordinates. Each subordinate, as well as President himself, has his own desk of a unique colour. Each desk is rectangular, and its sides are parallel to the office walls. One day President decided to establish an assembly, of which all his deputies will be members. Unfortunately, he does not remember the exact amount of his deputies, but he remembers that the desk of each his deputy is adjacent to his own desk, that is to say, the two desks (President's and each deputy's) have a common side of a positive length. The office-room plan can be viewed as a matrix with n rows and m columns. Each cell of this matrix is either empty, or contains a part of a desk. An uppercase Latin letter stands for each desk colour. The «period» character («.») stands for an empty cell. Input The first line contains two separated by a space integer numbers n, m (1 ≤ n, m ≤ 100) — the length and the width of the office-room, and c character — the President's desk colour. The following n lines contain m characters each — the office-room description. It is guaranteed that the colour of each desk is unique, and each desk represents a continuous subrectangle of the given matrix. All colours are marked by uppercase Latin letters. Output Print the only number — the amount of President's deputies. Examples Input 3 4 R G.B. .RR. TTT. Output 2 Input 3 3 Z ... .H. ..Z Output 0 Submitted Solution: ``` n,m,pres=input().split() n,m=int(n),int(m) l=[] for i in range(n): l1=list(input()) l.append(l1) ans=[] for i in range(n): for j in range(m): if l[i][j]==pres: if i-1>=0: ans.append(l[i-1][j]) if i+1<n: ans.append(l[i+1][j]) if j-1>=0: ans.append(l[i][j-1]) if j+1<m: ans.append(l[i][j+1]) ans=set(ans) ans.discard('.') ans.discard(pres) print(len(set(ans))) ```
instruction
0
1,325
7
2,650
Yes
output
1
1,325
7
2,651
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. President of Berland has a very vast office-room, where, apart from him, work his subordinates. Each subordinate, as well as President himself, has his own desk of a unique colour. Each desk is rectangular, and its sides are parallel to the office walls. One day President decided to establish an assembly, of which all his deputies will be members. Unfortunately, he does not remember the exact amount of his deputies, but he remembers that the desk of each his deputy is adjacent to his own desk, that is to say, the two desks (President's and each deputy's) have a common side of a positive length. The office-room plan can be viewed as a matrix with n rows and m columns. Each cell of this matrix is either empty, or contains a part of a desk. An uppercase Latin letter stands for each desk colour. The «period» character («.») stands for an empty cell. Input The first line contains two separated by a space integer numbers n, m (1 ≤ n, m ≤ 100) — the length and the width of the office-room, and c character — the President's desk colour. The following n lines contain m characters each — the office-room description. It is guaranteed that the colour of each desk is unique, and each desk represents a continuous subrectangle of the given matrix. All colours are marked by uppercase Latin letters. Output Print the only number — the amount of President's deputies. Examples Input 3 4 R G.B. .RR. TTT. Output 2 Input 3 3 Z ... .H. ..Z Output 0 Submitted Solution: ``` n,m,c = input().split() n = int(n) m = int(m) office = '' for i in range(n): office += input() x,y=office.index(c),office.rindex(c) colours={} for i in range(len(office)): if office[i]!='.' and office[i]!=c and ((x%m-1==i%m or i%m==y%m+1) and x//m<=i//m<=y//m or (int(x/m)-1==int(i/m) or int(i/m)==int(y/m)+1) and x%m<=i%m<=y%m): colours[office[i]]=1 print(len(colours)) ```
instruction
0
1,326
7
2,652
Yes
output
1
1,326
7
2,653
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. President of Berland has a very vast office-room, where, apart from him, work his subordinates. Each subordinate, as well as President himself, has his own desk of a unique colour. Each desk is rectangular, and its sides are parallel to the office walls. One day President decided to establish an assembly, of which all his deputies will be members. Unfortunately, he does not remember the exact amount of his deputies, but he remembers that the desk of each his deputy is adjacent to his own desk, that is to say, the two desks (President's and each deputy's) have a common side of a positive length. The office-room plan can be viewed as a matrix with n rows and m columns. Each cell of this matrix is either empty, or contains a part of a desk. An uppercase Latin letter stands for each desk colour. The «period» character («.») stands for an empty cell. Input The first line contains two separated by a space integer numbers n, m (1 ≤ n, m ≤ 100) — the length and the width of the office-room, and c character — the President's desk colour. The following n lines contain m characters each — the office-room description. It is guaranteed that the colour of each desk is unique, and each desk represents a continuous subrectangle of the given matrix. All colours are marked by uppercase Latin letters. Output Print the only number — the amount of President's deputies. Examples Input 3 4 R G.B. .RR. TTT. Output 2 Input 3 3 Z ... .H. ..Z Output 0 Submitted Solution: ``` n , m , c = input().split() n = int(n) m = int(m) matrix = [] for i in range(n): matrix.append(input()) count = 0 d = {} for i in range(n): val = matrix[i] for j in range(m): if(val[j]==c): if(i-1>=0 and matrix[i-1][j]!=c and matrix[i-1][j]!='.' and matrix[i-1][j] not in d): count+=1 v = matrix[i-1][j] d[v] = 1 if(j-1>=0 and matrix[i][j-1]!=c and matrix[i][j-1]!='.' and matrix[i][j-1] not in d): count+=1 v = matrix[i][j-1] d[v]=1 if(j+1<m and matrix[i][j+1]!=c and matrix[i][j+1]!='.' and matrix[i][j+1] not in d): count+=1 v = matrix[i][j+1] d[v] = 1 if(i+1<n and matrix[i+1][j]!=c and matrix[i+1][j]!='.' and matrix[i+1][j] not in d): count+=1 v = matrix[i+1][j] d[v] = 1 print(count) ```
instruction
0
1,327
7
2,654
Yes
output
1
1,327
7
2,655
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. President of Berland has a very vast office-room, where, apart from him, work his subordinates. Each subordinate, as well as President himself, has his own desk of a unique colour. Each desk is rectangular, and its sides are parallel to the office walls. One day President decided to establish an assembly, of which all his deputies will be members. Unfortunately, he does not remember the exact amount of his deputies, but he remembers that the desk of each his deputy is adjacent to his own desk, that is to say, the two desks (President's and each deputy's) have a common side of a positive length. The office-room plan can be viewed as a matrix with n rows and m columns. Each cell of this matrix is either empty, or contains a part of a desk. An uppercase Latin letter stands for each desk colour. The «period» character («.») stands for an empty cell. Input The first line contains two separated by a space integer numbers n, m (1 ≤ n, m ≤ 100) — the length and the width of the office-room, and c character — the President's desk colour. The following n lines contain m characters each — the office-room description. It is guaranteed that the colour of each desk is unique, and each desk represents a continuous subrectangle of the given matrix. All colours are marked by uppercase Latin letters. Output Print the only number — the amount of President's deputies. Examples Input 3 4 R G.B. .RR. TTT. Output 2 Input 3 3 Z ... .H. ..Z Output 0 Submitted Solution: ``` def solution(n,m,c,lists): deputies = {} x = [] ans = 0 for _x,l in enumerate(lists): for _y,d in enumerate(l): if d == c: x.append((_x,_y)) else: if d!='.' and d not in deputies: deputies[d] = False for _x,l in enumerate(lists): for _y,d in enumerate(l): if d in deputies: if not deputies[d] and ((_x+1,_y) in x or (_x-1,_y) in x or (_x,_y+1) in x or (_x,_y-1) in x): ans+=1 deputies[d] = True return ans n,m,c = input().split(' ') n = int(n) m = int(m) lists = [] for x in range(n): lists.append(list(input())) print(solution(n,m,c,lists)) ```
instruction
0
1,328
7
2,656
Yes
output
1
1,328
7
2,657
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. President of Berland has a very vast office-room, where, apart from him, work his subordinates. Each subordinate, as well as President himself, has his own desk of a unique colour. Each desk is rectangular, and its sides are parallel to the office walls. One day President decided to establish an assembly, of which all his deputies will be members. Unfortunately, he does not remember the exact amount of his deputies, but he remembers that the desk of each his deputy is adjacent to his own desk, that is to say, the two desks (President's and each deputy's) have a common side of a positive length. The office-room plan can be viewed as a matrix with n rows and m columns. Each cell of this matrix is either empty, or contains a part of a desk. An uppercase Latin letter stands for each desk colour. The «period» character («.») stands for an empty cell. Input The first line contains two separated by a space integer numbers n, m (1 ≤ n, m ≤ 100) — the length and the width of the office-room, and c character — the President's desk colour. The following n lines contain m characters each — the office-room description. It is guaranteed that the colour of each desk is unique, and each desk represents a continuous subrectangle of the given matrix. All colours are marked by uppercase Latin letters. Output Print the only number — the amount of President's deputies. Examples Input 3 4 R G.B. .RR. TTT. Output 2 Input 3 3 Z ... .H. ..Z Output 0 Submitted Solution: ``` def find_color(room, color): for i, line in enumerate(room): j = line.find(color) if j != -1: return (i, j) inp = input().split() height, width = [int(i) for i in inp[:2]] color = inp[2] room = [] for i in range(height): room.append(input()) y, x = find_color(room, color) adyacents = set() i = x j = y # print(i, j) if y > 0: while i < width and room[y][i] == color: # print(f"checking {(y - 1, i)}: {room[y - 1][i]}") adyacents.add(room[y - 1][i]) i += 1 if x > 0: while j < height and room[j][x]: # print(f"checking {(j, x - 1)}: {room[j][x - 1]}") adyacents.add(room[j][x - 1]) j += 1 # print(i, j) if i < width - 1: i -= 1 while y < height and room[y][i] == color: # print(f"checking {(y, i + 1)}: {room[y - 1][i]}") adyacents.add(room[y][i + 1]) y += 1 if j < height - 1: j -= 1 while x < width and room[j][x] == color: # print(f"checking {(j + 1, x)}: {room[j + 1][x]}") adyacents.add(room[j + 1][x]) x += 1 # print(adyacents) result = len(adyacents) if '.' in adyacents: result -= 1 if color in adyacents: result -= 1 print(result) ```
instruction
0
1,329
7
2,658
No
output
1
1,329
7
2,659
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. President of Berland has a very vast office-room, where, apart from him, work his subordinates. Each subordinate, as well as President himself, has his own desk of a unique colour. Each desk is rectangular, and its sides are parallel to the office walls. One day President decided to establish an assembly, of which all his deputies will be members. Unfortunately, he does not remember the exact amount of his deputies, but he remembers that the desk of each his deputy is adjacent to his own desk, that is to say, the two desks (President's and each deputy's) have a common side of a positive length. The office-room plan can be viewed as a matrix with n rows and m columns. Each cell of this matrix is either empty, or contains a part of a desk. An uppercase Latin letter stands for each desk colour. The «period» character («.») stands for an empty cell. Input The first line contains two separated by a space integer numbers n, m (1 ≤ n, m ≤ 100) — the length and the width of the office-room, and c character — the President's desk colour. The following n lines contain m characters each — the office-room description. It is guaranteed that the colour of each desk is unique, and each desk represents a continuous subrectangle of the given matrix. All colours are marked by uppercase Latin letters. Output Print the only number — the amount of President's deputies. Examples Input 3 4 R G.B. .RR. TTT. Output 2 Input 3 3 Z ... .H. ..Z Output 0 Submitted Solution: ``` if __name__ == '__main__': n, m, color = input().split() n = int(n) m = int(m) mat = [] indi = [] indj = [] dep = [] for i in range(n): ar = input() for j in range(m): if ar[j] == color: indi.append(i) indj.append(j) mat.append(ar) l = len(indi) for k in range(l): i = indi[k] j = indj[k] if i+1 < n and j < m: if mat[i+1][j] != 'R' and mat[i+1][j] != '.': dep.append(mat[i+1][j]) if i < n and j+1 < m: if mat[i][j+1] != 'R' and mat[i][j+1] != '.': dep.append(mat[i][j+1]) if i-1 >=0 and j < m: if mat[i-1][j] != 'R' and mat[i-1][j] != '.': dep.append(mat[i-1][j]) if i < n and j-1>= 0: if mat[i][j-1] != 'R' and mat[i][j-1] != '.': dep.append(mat[i][j-1]) d = set(dep) ans = len(d) print(ans) ```
instruction
0
1,330
7
2,660
No
output
1
1,330
7
2,661
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. President of Berland has a very vast office-room, where, apart from him, work his subordinates. Each subordinate, as well as President himself, has his own desk of a unique colour. Each desk is rectangular, and its sides are parallel to the office walls. One day President decided to establish an assembly, of which all his deputies will be members. Unfortunately, he does not remember the exact amount of his deputies, but he remembers that the desk of each his deputy is adjacent to his own desk, that is to say, the two desks (President's and each deputy's) have a common side of a positive length. The office-room plan can be viewed as a matrix with n rows and m columns. Each cell of this matrix is either empty, or contains a part of a desk. An uppercase Latin letter stands for each desk colour. The «period» character («.») stands for an empty cell. Input The first line contains two separated by a space integer numbers n, m (1 ≤ n, m ≤ 100) — the length and the width of the office-room, and c character — the President's desk colour. The following n lines contain m characters each — the office-room description. It is guaranteed that the colour of each desk is unique, and each desk represents a continuous subrectangle of the given matrix. All colours are marked by uppercase Latin letters. Output Print the only number — the amount of President's deputies. Examples Input 3 4 R G.B. .RR. TTT. Output 2 Input 3 3 Z ... .H. ..Z Output 0 Submitted Solution: ``` n,m,z=map(str,input().split()) r=[] for _ in range(int(n)): d=input() r.append(d) ans=[] for i in range(int(n)): for j in range(int(m)): if r[i][j]==z: #print(i,j,r[i][j]) try: if r[i-1][j]!=z and r[i-1][j]!='.' and i>=0: ans.append(r[i-1][j]) #print(ans,i,j) if r[i][j-1]!=z and r[i][j-1]!='.'and j>=0: ans.append(r[i][j-1]) #print(ans,i,j) if r[i+1][j]!=z and r[i+1][j]!='.': ans.append(r[i+1][j]) #print(ans,i,j) if r[i][j+1]!=z and r[i][j+1]!='.': ans.append(r[i][j+1]) #print(ans,i,j) except: pass print(len(set(ans))) #print(ans) ```
instruction
0
1,331
7
2,662
No
output
1
1,331
7
2,663
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. President of Berland has a very vast office-room, where, apart from him, work his subordinates. Each subordinate, as well as President himself, has his own desk of a unique colour. Each desk is rectangular, and its sides are parallel to the office walls. One day President decided to establish an assembly, of which all his deputies will be members. Unfortunately, he does not remember the exact amount of his deputies, but he remembers that the desk of each his deputy is adjacent to his own desk, that is to say, the two desks (President's and each deputy's) have a common side of a positive length. The office-room plan can be viewed as a matrix with n rows and m columns. Each cell of this matrix is either empty, or contains a part of a desk. An uppercase Latin letter stands for each desk colour. The «period» character («.») stands for an empty cell. Input The first line contains two separated by a space integer numbers n, m (1 ≤ n, m ≤ 100) — the length and the width of the office-room, and c character — the President's desk colour. The following n lines contain m characters each — the office-room description. It is guaranteed that the colour of each desk is unique, and each desk represents a continuous subrectangle of the given matrix. All colours are marked by uppercase Latin letters. Output Print the only number — the amount of President's deputies. Examples Input 3 4 R G.B. .RR. TTT. Output 2 Input 3 3 Z ... .H. ..Z Output 0 Submitted Solution: ``` list = [] list2 = [] deputies = 0 x,y,c = input().split() for i in range(int(x)): lst = input() list.append(lst) for i in range(int(x)): for j in range(int(y)): if list[i][j] == c: list2.append(i) list2.append(j) for i in range(len(list2)//2): list3 = [] rows = list2[2*i] columns = list2[2*i+1] if int(rows) > 0: if list[rows-1][columns] != '.' and list[rows-1][columns] != c: list3.append(list[rows-1][columns]) if int(columns) > 0: if list[rows][columns-1] != '.' and list[rows][columns-1] != c: list3.append(list[rows][columns-1]) if int(rows) < int(x)-1: if list[rows+1][columns] != '.' and list[rows+1][columns] != c: list3.append(list[rows+1][columns]) if int(columns) < int(y)-1: if list[rows][columns+1] != '.' and list[rows][columns+1] != c: list3.append(list[rows][columns+1]) if len(set(list3)) > deputies: deputies = len(set(list3)) print(deputies) ```
instruction
0
1,332
7
2,664
No
output
1
1,332
7
2,665
Provide tags and a correct Python 3 solution for this coding contest problem. The flag of Berland is such rectangular field n × m that satisfies following conditions: * Flag consists of three colors which correspond to letters 'R', 'G' and 'B'. * Flag consists of three equal in width and height stripes, parralel to each other and to sides of the flag. Each stripe has exactly one color. * Each color should be used in exactly one stripe. You are given a field n × m, consisting of characters 'R', 'G' and 'B'. Output "YES" (without quotes) if this field corresponds to correct flag of Berland. Otherwise, print "NO" (without quotes). Input The first line contains two integer numbers n and m (1 ≤ n, m ≤ 100) — the sizes of the field. Each of the following n lines consisting of m characters 'R', 'G' and 'B' — the description of the field. Output Print "YES" (without quotes) if the given field corresponds to correct flag of Berland . Otherwise, print "NO" (without quotes). Examples Input 6 5 RRRRR RRRRR BBBBB BBBBB GGGGG GGGGG Output YES Input 4 3 BRG BRG BRG BRG Output YES Input 6 7 RRRGGGG RRRGGGG RRRGGGG RRRBBBB RRRBBBB RRRBBBB Output NO Input 4 4 RRRR RRRR BBBB GGGG Output NO Note The field in the third example doesn't have three parralel stripes. Rows of the field in the fourth example are parralel to each other and to borders. But they have different heights — 2, 1 and 1.
instruction
0
1,389
7
2,778
Tags: brute force, implementation Correct Solution: ``` N, M = map(int, input().split()) flag = [input() for n in range(N)] def get_rect_of_color(color): rect_points = [] for i, row in enumerate(flag): first = True seq_is_broken = False tmp = [None] * 4 for j, char in enumerate(row): if char == color: if first: first = False tmp[0], tmp[1] = i, j if seq_is_broken: raise Exception() tmp[2], tmp[3] = i, j elif not first: seq_is_broken = True if tmp[0] is not None: rect_points += [tmp] return rect_points def get_bounding_rect(rect): last_pos = rect[0] first = True for row in rect: if first: first = False continue ly1, lx1, ly2, lx2 = last_pos y1, x1, y2, x2 = row # print(y1, x1, y2, x2) # print(ly1, lx1, ly2, lx2) if y1 - ly1 != 1 or y2 - ly2 != 1 or\ x1 - lx1 != 0 or x2 - lx2 != 0: raise Exception() last_pos = row return ( (rect[0][0], rect[0][1]), (rect[-1][2], rect[-1][3]), ) try: R = get_bounding_rect(get_rect_of_color('R')) G = get_bounding_rect(get_rect_of_color('G')) B = get_bounding_rect(get_rect_of_color('B')) Rh = abs(R[1][0] - R[0][0]) Bh = abs(B[1][0] - B[0][0]) Gh = abs(G[1][0] - G[0][0]) Rw = abs(R[1][1] - R[0][1]) Bw = abs(B[1][1] - B[0][1]) Gw = abs(G[1][1] - G[0][1]) # print(Rh, Bh, Gh) # print(Rw, Bw, Gw) if len(set([Rw, Bw, Gw])) != 1 or len(set([Rh, Bh, Gh])) != 1: print('NO') else: print('YES') except Exception: print('NO') ```
output
1
1,389
7
2,779
Provide tags and a correct Python 3 solution for this coding contest problem. The flag of Berland is such rectangular field n × m that satisfies following conditions: * Flag consists of three colors which correspond to letters 'R', 'G' and 'B'. * Flag consists of three equal in width and height stripes, parralel to each other and to sides of the flag. Each stripe has exactly one color. * Each color should be used in exactly one stripe. You are given a field n × m, consisting of characters 'R', 'G' and 'B'. Output "YES" (without quotes) if this field corresponds to correct flag of Berland. Otherwise, print "NO" (without quotes). Input The first line contains two integer numbers n and m (1 ≤ n, m ≤ 100) — the sizes of the field. Each of the following n lines consisting of m characters 'R', 'G' and 'B' — the description of the field. Output Print "YES" (without quotes) if the given field corresponds to correct flag of Berland . Otherwise, print "NO" (without quotes). Examples Input 6 5 RRRRR RRRRR BBBBB BBBBB GGGGG GGGGG Output YES Input 4 3 BRG BRG BRG BRG Output YES Input 6 7 RRRGGGG RRRGGGG RRRGGGG RRRBBBB RRRBBBB RRRBBBB Output NO Input 4 4 RRRR RRRR BBBB GGGG Output NO Note The field in the third example doesn't have three parralel stripes. Rows of the field in the fourth example are parralel to each other and to borders. But they have different heights — 2, 1 and 1.
instruction
0
1,390
7
2,780
Tags: brute force, implementation Correct Solution: ``` n, m = list(map(int, input().split())) res = max(n, m) >= 3 is_horo = True is_vert = True if res: flag = [] for i in range(n): r = input() if len(r) != m: res = False break flag.append(list(r)) px = flag[0][0] for i in range(1, m): if flag[0][i] != px: is_horo = False break for i in range(1, n): if flag[i][0] != px: is_vert = False break res = is_horo ^ is_vert compressed = [] if res: if is_horo: for r in flag: px = r[0] for c in r[1:]: if c != px: res = False break compressed.append(px) elif is_vert: for i in range(m): px = flag[0][i] for j in range(1, n): if flag[j][i] != px: res = False break compressed.append(px) if res and compressed: stripe_width = None c_stripe = None c_width = 0 widths = [] seen = set() for stripe in compressed: if c_stripe is None: c_stripe = stripe c_width = 1 elif c_stripe != stripe: seen.add(c_stripe) widths.append(c_width) c_width = 1 c_stripe = stripe else: c_width += 1 widths.append(c_width) seen.add(c_stripe) if len(widths) != 3 or len(seen) != 3: res = False else: first = widths[0] for i in range(1, len(widths)): if widths[i] != first: res = False break print('YES' if res else 'NO') ```
output
1
1,390
7
2,781
Provide tags and a correct Python 3 solution for this coding contest problem. The flag of Berland is such rectangular field n × m that satisfies following conditions: * Flag consists of three colors which correspond to letters 'R', 'G' and 'B'. * Flag consists of three equal in width and height stripes, parralel to each other and to sides of the flag. Each stripe has exactly one color. * Each color should be used in exactly one stripe. You are given a field n × m, consisting of characters 'R', 'G' and 'B'. Output "YES" (without quotes) if this field corresponds to correct flag of Berland. Otherwise, print "NO" (without quotes). Input The first line contains two integer numbers n and m (1 ≤ n, m ≤ 100) — the sizes of the field. Each of the following n lines consisting of m characters 'R', 'G' and 'B' — the description of the field. Output Print "YES" (without quotes) if the given field corresponds to correct flag of Berland . Otherwise, print "NO" (without quotes). Examples Input 6 5 RRRRR RRRRR BBBBB BBBBB GGGGG GGGGG Output YES Input 4 3 BRG BRG BRG BRG Output YES Input 6 7 RRRGGGG RRRGGGG RRRGGGG RRRBBBB RRRBBBB RRRBBBB Output NO Input 4 4 RRRR RRRR BBBB GGGG Output NO Note The field in the third example doesn't have three parralel stripes. Rows of the field in the fourth example are parralel to each other and to borders. But they have different heights — 2, 1 and 1.
instruction
0
1,391
7
2,782
Tags: brute force, implementation Correct Solution: ``` #python 3.5.2 b, k = map(int, input().split()) arr = [] for i in range(b): s = input() arr.append(s) x = arr[0][0] nb = 1 nk = 1 pola = str(x) while (nk < k and arr[0][nk] == x): nk += 1 pola += x if (nk == k or nk == k/3): if (nk == k/3): # print("xx") arr = list(map(lambda x: ''.join(x), (map(list, zip(*arr))))) # print(arr) b, k = k, b nb = 1 nk = 1 pola = str(x) while (nk < k and arr[0][nk] == x): nk += 1 pola += x while (nb < b and arr[nb][:nk] == pola): nb += 1 if (nb == b/3): y = arr[nb][0] polay = "" for i in range(nk): polay += y nby = 0 brs = nb while (nby+nb < b and arr[nby+nb] == polay): nby+=1 if (nby == nb): z = arr[nby+nb][0] if (z != x): polaz = "" for i in range(nk): polaz += z nbz = 0 brs = nby+nb while (nbz+nby+nb < b and arr[nbz+nby+nb] == polaz): nbz+=1 if (nbz == nb): print("YES") else: print("NO") else: print("NO") else: print("NO") else: print("NO") else: print("NO") ```
output
1
1,391
7
2,783
Provide tags and a correct Python 3 solution for this coding contest problem. The flag of Berland is such rectangular field n × m that satisfies following conditions: * Flag consists of three colors which correspond to letters 'R', 'G' and 'B'. * Flag consists of three equal in width and height stripes, parralel to each other and to sides of the flag. Each stripe has exactly one color. * Each color should be used in exactly one stripe. You are given a field n × m, consisting of characters 'R', 'G' and 'B'. Output "YES" (without quotes) if this field corresponds to correct flag of Berland. Otherwise, print "NO" (without quotes). Input The first line contains two integer numbers n and m (1 ≤ n, m ≤ 100) — the sizes of the field. Each of the following n lines consisting of m characters 'R', 'G' and 'B' — the description of the field. Output Print "YES" (without quotes) if the given field corresponds to correct flag of Berland . Otherwise, print "NO" (without quotes). Examples Input 6 5 RRRRR RRRRR BBBBB BBBBB GGGGG GGGGG Output YES Input 4 3 BRG BRG BRG BRG Output YES Input 6 7 RRRGGGG RRRGGGG RRRGGGG RRRBBBB RRRBBBB RRRBBBB Output NO Input 4 4 RRRR RRRR BBBB GGGG Output NO Note The field in the third example doesn't have three parralel stripes. Rows of the field in the fourth example are parralel to each other and to borders. But they have different heights — 2, 1 and 1.
instruction
0
1,392
7
2,784
Tags: brute force, implementation Correct Solution: ``` n, m = map(int, input().split()) s = [input() for _ in range(n)] if n % 3 != 0 and m % 3 != 0: print('NO') exit() flag = 0 if n % 3 == 0: if not(s[0][0]!=s[n//3][0] and s[2*n//3][0]!=s[n//3][0] and s[2*n//3][0]!=s[0][0]): flag=1 r, g, b = 0, 0, 0 if s[0][0] == 'R': r = 1 elif s[0][0] == 'G': g = 1 else: b = 1 for i in range(n//3): for j in range(m): if s[i][j] == 'G' and g != 1: flag = 1 elif s[i][j] == 'R' and r != 1: flag = 1 elif s[i][j] == 'B' and b != 1: flag = 1 if s[n//3][0] == 'R': if r == 1: flag = 1 r = 1 g, b = 0, 0 elif s[n//3][0] == 'G': if g == 1: flag = 1 g = 1 r, b = 0, 0 else: if b == 1: flag = 1 b = 1 r, g = 0, 0 for i in range(n//3, 2*n//3): for j in range(m): if s[i][j] == 'G' and g != 1: flag = 1 elif s[i][j] == 'R' and r != 1: flag = 1 elif s[i][j] == 'B' and b != 1: flag = 1 if s[2*n//3][0] == 'R': if r == 1: flag = 1 r = 1 g, b = 0, 0 elif s[2*n//3][0] == 'G': if g == 1: flag = 1 g=1 r, b = 0, 0 else: if b == 1: flag = 1 b = 1 r, g = 0, 0 for i in range(2*n//3, n): for j in range(m): if s[i][j] == 'G' and g != 1: flag = 1 elif s[i][j] == 'R' and r != 1: flag = 1 elif s[i][j] == 'B' and b != 1: flag = 1 if flag == 0: print('YES') exit() flag = 0 if (m % 3 == 0): if not (s[0][0]!=s[0][m//3] and s[0][2*m//3]!=s[0][m//3] and s[0][0]!=s[0][2*m//3]): flag=1 r, g, b = 0, 0, 0 if s[0][0] == 'R': r += 1 elif s[0][0] == 'G': g += 1 else: b += 1 for j in range(m//3): for i in range(n): if s[i][j] == 'G' and g != 1: flag = 1 elif s[i][j] == 'R' and r != 1: flag = 1 elif s[i][j] == 'B' and b != 1: flag = 1 if s[0][m//3] == 'R': if r == 1: flag = 1 r = 1 g, b = 0, 0 elif s[0][m//3] == 'G': if g == 1: flag = 1 g = 1 r, b = 0, 0 else: if b == 1: flag = 1 b = 1 r, g = 0, 0 for j in range(m//3, 2*m//3): for i in range(n): if s[i][j] == 'G' and g != 1: flag = 1 elif s[i][j] == 'R' and r != 1: flag = 1 elif s[i][j] == 'B' and b != 1: flag = 1 if s[0][2*m//3] == 'R': if r == 1: flag = 1 r = 1 g, b = 0, 0 elif s[0][2*m//3] == 'G': if g == 1: flag = 1 g=1 r, b = 0, 0 else: if b == 1: flag = 1 b = 1 r, g = 0, 0 for j in range(2*m//3, m): for i in range(n): if s[i][j] == 'G' and g != 1: flag = 1 elif s[i][j] == 'R' and r != 1: flag = 1 elif s[i][j] == 'B' and b != 1: flag = 1 if flag == 0: print('YES') exit() print('NO') ```
output
1
1,392
7
2,785
Provide tags and a correct Python 3 solution for this coding contest problem. The flag of Berland is such rectangular field n × m that satisfies following conditions: * Flag consists of three colors which correspond to letters 'R', 'G' and 'B'. * Flag consists of three equal in width and height stripes, parralel to each other and to sides of the flag. Each stripe has exactly one color. * Each color should be used in exactly one stripe. You are given a field n × m, consisting of characters 'R', 'G' and 'B'. Output "YES" (without quotes) if this field corresponds to correct flag of Berland. Otherwise, print "NO" (without quotes). Input The first line contains two integer numbers n and m (1 ≤ n, m ≤ 100) — the sizes of the field. Each of the following n lines consisting of m characters 'R', 'G' and 'B' — the description of the field. Output Print "YES" (without quotes) if the given field corresponds to correct flag of Berland . Otherwise, print "NO" (without quotes). Examples Input 6 5 RRRRR RRRRR BBBBB BBBBB GGGGG GGGGG Output YES Input 4 3 BRG BRG BRG BRG Output YES Input 6 7 RRRGGGG RRRGGGG RRRGGGG RRRBBBB RRRBBBB RRRBBBB Output NO Input 4 4 RRRR RRRR BBBB GGGG Output NO Note The field in the third example doesn't have three parralel stripes. Rows of the field in the fourth example are parralel to each other and to borders. But they have different heights — 2, 1 and 1.
instruction
0
1,393
7
2,786
Tags: brute force, implementation Correct Solution: ``` import sys #import random from bisect import bisect_left as lb from collections import deque #sys.setrecursionlimit(10**8) from queue import PriorityQueue as pq from math import * input_ = lambda: sys.stdin.readline().strip("\r\n") ii = lambda : int(input_()) il = lambda : list(map(int, input_().split())) ilf = lambda : list(map(float, input_().split())) ip = lambda : input_() fi = lambda : float(input_()) ap = lambda ab,bc,cd : ab[bc].append(cd) li = lambda : list(input_()) pr = lambda x : print(x) prinT = lambda x : print(x) f = lambda : sys.stdout.flush() inv =lambda x:pow(x,mod-2,mod) mod = 10**9 + 7 n,m = il() a = [] for i in range (n) : a.append(list(ip())) if (n%3 != 0 and m%3 != 0) : print("NO") exit(0) fl = 1 if (n%3 == 0) : x = n//3 d = {} for k in range (3) : i = 0 + x*k ch = a[i][0] if (d.get(ch)) : fl = 0 break for i1 in range (x) : for j in range (m) : if (ch != a[i1+i][j]) : fl = 0 break if (fl == 0) : break d[ch] = 1 if fl : print("YES") exit(0) if (m%3 == 0) : x = m//3 d = {} fl = 1 for k in range (3) : i = 0 + x*k ch = a[0][i] if (d.get(ch)) : fl = 0 break for i1 in range (x) : for j in range (n) : if (ch != a[j][i1+i]) : fl = 0 break if (fl == 0) : break d[ch] = 1 if (fl) : print("YES") exit(0) print("NO") ```
output
1
1,393
7
2,787
Provide tags and a correct Python 3 solution for this coding contest problem. The flag of Berland is such rectangular field n × m that satisfies following conditions: * Flag consists of three colors which correspond to letters 'R', 'G' and 'B'. * Flag consists of three equal in width and height stripes, parralel to each other and to sides of the flag. Each stripe has exactly one color. * Each color should be used in exactly one stripe. You are given a field n × m, consisting of characters 'R', 'G' and 'B'. Output "YES" (without quotes) if this field corresponds to correct flag of Berland. Otherwise, print "NO" (without quotes). Input The first line contains two integer numbers n and m (1 ≤ n, m ≤ 100) — the sizes of the field. Each of the following n lines consisting of m characters 'R', 'G' and 'B' — the description of the field. Output Print "YES" (without quotes) if the given field corresponds to correct flag of Berland . Otherwise, print "NO" (without quotes). Examples Input 6 5 RRRRR RRRRR BBBBB BBBBB GGGGG GGGGG Output YES Input 4 3 BRG BRG BRG BRG Output YES Input 6 7 RRRGGGG RRRGGGG RRRGGGG RRRBBBB RRRBBBB RRRBBBB Output NO Input 4 4 RRRR RRRR BBBB GGGG Output NO Note The field in the third example doesn't have three parralel stripes. Rows of the field in the fourth example are parralel to each other and to borders. But they have different heights — 2, 1 and 1.
instruction
0
1,394
7
2,788
Tags: brute force, implementation Correct Solution: ``` def c(f, n, m): if n % 3 != 0:return 0 s=n//3;s=f[0],f[s],f[2*s] if set(s)!=set(map(lambda x:x*m,'RGB')):return 0 for i in range(n): if f[i] != s[i*3 // n]:return 0 return 1 n,m=map(int, input().split()) f=[input() for _ in range(n)] print('Yes'if c(f,n,m) or c([''.join(f[j][i] for j in range(n)) for i in range(m)],m,n)else'No') ```
output
1
1,394
7
2,789
Provide tags and a correct Python 3 solution for this coding contest problem. The flag of Berland is such rectangular field n × m that satisfies following conditions: * Flag consists of three colors which correspond to letters 'R', 'G' and 'B'. * Flag consists of three equal in width and height stripes, parralel to each other and to sides of the flag. Each stripe has exactly one color. * Each color should be used in exactly one stripe. You are given a field n × m, consisting of characters 'R', 'G' and 'B'. Output "YES" (without quotes) if this field corresponds to correct flag of Berland. Otherwise, print "NO" (without quotes). Input The first line contains two integer numbers n and m (1 ≤ n, m ≤ 100) — the sizes of the field. Each of the following n lines consisting of m characters 'R', 'G' and 'B' — the description of the field. Output Print "YES" (without quotes) if the given field corresponds to correct flag of Berland . Otherwise, print "NO" (without quotes). Examples Input 6 5 RRRRR RRRRR BBBBB BBBBB GGGGG GGGGG Output YES Input 4 3 BRG BRG BRG BRG Output YES Input 6 7 RRRGGGG RRRGGGG RRRGGGG RRRBBBB RRRBBBB RRRBBBB Output NO Input 4 4 RRRR RRRR BBBB GGGG Output NO Note The field in the third example doesn't have three parralel stripes. Rows of the field in the fourth example are parralel to each other and to borders. But they have different heights — 2, 1 and 1.
instruction
0
1,395
7
2,790
Tags: brute force, implementation Correct Solution: ``` import sys #sys.stdin = open("input2","r") n,m = map(int,input().split()) s = [] for i in range(n): string = input() s.append(string) no = 0 # row mix check r_mix = 0 for i in range(n): cnt_r = s[i].count('R') cnt_b = s[i].count('B') cnt_g = s[i].count('G') if ((cnt_r and cnt_b) or (cnt_b and cnt_g) or (cnt_g and cnt_r) ): r_mix = 1 # col mix check c_mix = 0 for j in range(m): cnt_r = cnt_b = cnt_g = 0 for i in range(n): if (s[i][j] == 'R'): cnt_r += 1 elif (s[i][j] == 'B'): cnt_b += 1 elif(s[i][j] == 'G'): cnt_g += 1 if ((cnt_r and cnt_b) or (cnt_b and cnt_g) or (cnt_g and cnt_r) ): c_mix = 1 if (r_mix == 1 and c_mix == 1) or ( r_mix == 0 and c_mix == 0): no = 1 if(r_mix == 1): cnt_b = cnt_g = cnt_r = 0 if s[0][0] == 'R': cnt_r += 1 elif s[0][0] == 'G': cnt_g += 1 elif s[0][0] == 'B': cnt_b += 1 f,c = -1,1 for j in range(0,m-1): if s[0][j] == s[0][j+1]: c += 1 else: if s[0][j+1] == 'R': cnt_r += 1 elif s[0][j + 1] == 'G': cnt_g += 1 elif s[0][j + 1] == 'B': cnt_b += 1 if f == -1: f = c if f != c: no = 1 break c = 1 if ((f != c) or (cnt_r != 1 or cnt_b != 1 or cnt_g != 1)): no = 1 if (c_mix): f = -1 c = 1 cnt_b = 0 cnt_g = 0 cnt_r = 0 if s[0][0] == 'R': cnt_r += 1 elif s[0][0] == 'G': cnt_g += 1 elif s[0][0] == 'B': cnt_b += 1 for i in range(0, n-1): if s[i][0] == s[i+1][0]: c += 1 #print('c',c) else: if s[i + 1][0] == 'R': cnt_r += 1 elif s[i + 1][0] == 'G': cnt_g += 1 elif s[i + 1][0] == 'B': cnt_b += 1 if f == -1: f = c #print('f',f) if f != c: #print(f,c) no = 1 break c = 1 #print(cnt_r,cnt_b,cnt_g) if ((f != c) or (cnt_r != 1 or cnt_b != 1 or cnt_g != 1)): no = 1 if no == 1: print('NO') else: print('YES') ```
output
1
1,395
7
2,791
Provide tags and a correct Python 3 solution for this coding contest problem. The flag of Berland is such rectangular field n × m that satisfies following conditions: * Flag consists of three colors which correspond to letters 'R', 'G' and 'B'. * Flag consists of three equal in width and height stripes, parralel to each other and to sides of the flag. Each stripe has exactly one color. * Each color should be used in exactly one stripe. You are given a field n × m, consisting of characters 'R', 'G' and 'B'. Output "YES" (without quotes) if this field corresponds to correct flag of Berland. Otherwise, print "NO" (without quotes). Input The first line contains two integer numbers n and m (1 ≤ n, m ≤ 100) — the sizes of the field. Each of the following n lines consisting of m characters 'R', 'G' and 'B' — the description of the field. Output Print "YES" (without quotes) if the given field corresponds to correct flag of Berland . Otherwise, print "NO" (without quotes). Examples Input 6 5 RRRRR RRRRR BBBBB BBBBB GGGGG GGGGG Output YES Input 4 3 BRG BRG BRG BRG Output YES Input 6 7 RRRGGGG RRRGGGG RRRGGGG RRRBBBB RRRBBBB RRRBBBB Output NO Input 4 4 RRRR RRRR BBBB GGGG Output NO Note The field in the third example doesn't have three parralel stripes. Rows of the field in the fourth example are parralel to each other and to borders. But they have different heights — 2, 1 and 1.
instruction
0
1,396
7
2,792
Tags: brute force, implementation Correct Solution: ``` [n,m] = [int(i) for i in input().split()] flag = [] flip_flag = [] for i in range(m): flip_flag.append([]) tmp = n while tmp: tmp -= 1 flag.append(list(input())) for i in range(m): flip_flag[i].append(flag[-1][i]) if len(set(flag[0])) != 1: flag = flip_flag strip_count = {} valid = True strip_count[flag[0][0]]=1 if len(set(flag[0])) != 1: valid = False for i in range(1, len(flag)): if len(set(flag[i])) != 1 or valid == False: valid = False break if flag[i][0] not in strip_count.keys(): strip_count[flag[i][0]] = 1 elif flag[i][0] != flag[i-1][0]: valid = False break else: strip_count[flag[i][0]] += 1 if len(set(strip_count.values())) != 1: valid = False if not(all(i in strip_count.keys() for i in ['R','G','B']) and len(set(strip_count.keys())) == 3): valid = False print('YES' if valid else 'NO') ```
output
1
1,396
7
2,793
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The flag of Berland is such rectangular field n × m that satisfies following conditions: * Flag consists of three colors which correspond to letters 'R', 'G' and 'B'. * Flag consists of three equal in width and height stripes, parralel to each other and to sides of the flag. Each stripe has exactly one color. * Each color should be used in exactly one stripe. You are given a field n × m, consisting of characters 'R', 'G' and 'B'. Output "YES" (without quotes) if this field corresponds to correct flag of Berland. Otherwise, print "NO" (without quotes). Input The first line contains two integer numbers n and m (1 ≤ n, m ≤ 100) — the sizes of the field. Each of the following n lines consisting of m characters 'R', 'G' and 'B' — the description of the field. Output Print "YES" (without quotes) if the given field corresponds to correct flag of Berland . Otherwise, print "NO" (without quotes). Examples Input 6 5 RRRRR RRRRR BBBBB BBBBB GGGGG GGGGG Output YES Input 4 3 BRG BRG BRG BRG Output YES Input 6 7 RRRGGGG RRRGGGG RRRGGGG RRRBBBB RRRBBBB RRRBBBB Output NO Input 4 4 RRRR RRRR BBBB GGGG Output NO Note The field in the third example doesn't have three parralel stripes. Rows of the field in the fourth example are parralel to each other and to borders. But they have different heights — 2, 1 and 1. Submitted Solution: ``` n,m=map(int,input().split()) ls=[] for i in range(n): s=input() ls.append(s) #check for horizontal strips horizontal=[] f1=True for i in range(n): if(ls[i]==ls[i][0]*len(ls[i])): if(i==0): horizontal.append([ls[i],1]) elif(ls[i]==horizontal[-1][0]): horizontal[-1][1]+=1 else: horizontal.append([ls[i],1]) else: f1=False break if(len(horizontal)==3 and horizontal[0][1]==horizontal[1][1]==horizontal[2][1]): if(horizontal[0][0]!=horizontal[1][0] and horizontal[0][0]!=horizontal[2][0] and horizontal[1][0]!=horizontal[2][0]): s="" else: f1=False else: f1=False new_ls=["" for i in range(m)] for i in range(n): for j in range(m): new_ls[j]+=ls[i][j] ls=new_ls #check for horizontal strips horizontal=[] f2=True for i in range(m): if(ls[i]==ls[i][0]*len(ls[i])): if(i==0): horizontal.append([ls[i],1]) elif(ls[i]==horizontal[-1][0]): horizontal[-1][1]+=1 else: horizontal.append([ls[i],1]) else: f2=False break if(len(horizontal)==3 and horizontal[0][1]==horizontal[1][1]==horizontal[2][1]): if(horizontal[0][0]!=horizontal[1][0] and horizontal[0][0]!=horizontal[2][0] and horizontal[1][0]!=horizontal[2][0]): s="" else: f2=False else: f2=False if(f1 or f2):print("YES") else:print("NO") ```
instruction
0
1,397
7
2,794
Yes
output
1
1,397
7
2,795
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The flag of Berland is such rectangular field n × m that satisfies following conditions: * Flag consists of three colors which correspond to letters 'R', 'G' and 'B'. * Flag consists of three equal in width and height stripes, parralel to each other and to sides of the flag. Each stripe has exactly one color. * Each color should be used in exactly one stripe. You are given a field n × m, consisting of characters 'R', 'G' and 'B'. Output "YES" (without quotes) if this field corresponds to correct flag of Berland. Otherwise, print "NO" (without quotes). Input The first line contains two integer numbers n and m (1 ≤ n, m ≤ 100) — the sizes of the field. Each of the following n lines consisting of m characters 'R', 'G' and 'B' — the description of the field. Output Print "YES" (without quotes) if the given field corresponds to correct flag of Berland . Otherwise, print "NO" (without quotes). Examples Input 6 5 RRRRR RRRRR BBBBB BBBBB GGGGG GGGGG Output YES Input 4 3 BRG BRG BRG BRG Output YES Input 6 7 RRRGGGG RRRGGGG RRRGGGG RRRBBBB RRRBBBB RRRBBBB Output NO Input 4 4 RRRR RRRR BBBB GGGG Output NO Note The field in the third example doesn't have three parralel stripes. Rows of the field in the fourth example are parralel to each other and to borders. But they have different heights — 2, 1 and 1. Submitted Solution: ``` height, width = map(int, input().split()) a = [input() for i in range(height)] c = {'r': 0, 'g': 0, 'b': 0} p = {'r': 0, 'g': 0, 'b': 0} color = {'r': False, 'g': False, 'b': False} horizontal, vertical = True, False for i in range(height): for j in range(width): color[a[i][j].lower()] = True for i in range(height): for j in range(1, width): if a[i][j] != a[i][j - 1]: horizontal = False break c[a[i][j].lower()] += 1 if not horizontal: vertical = True for key in c.keys(): c[key] = 0 for i in range(width): for j in range(1, height): if a[j][i] != a[j - 1][i]: vertical = False break c[a[j][i].lower()] += 1 prev = None if horizontal: for i in range(height): if prev is None: prev = a[i][0].lower() c[a[i][0].lower()] += 1 p[a[i][0].lower()] += 1 else: if prev != a[i][0].lower(): p[a[i][0].lower()] += 1 if p[a[i][0].lower()] >= 2: print('NO') exit() prev = a[i][0].lower() c[a[i][0].lower()] += 1 elif vertical: for i in range(width): if prev is None: prev = a[0][i].lower() c[a[0][i].lower()] += 1 else: if prev != a[0][i].lower(): p[a[0][i].lower()] += 1 if p[a[0][i].lower()] >= 2: print('NO') exit() prev = a[0][i].lower() c[a[0][i].lower()] += 1 else: print('NO') exit() if c['r'] == c['g'] == c['b'] and color['r'] and color['g'] and color['b']: print('YES') else: print('NO') ```
instruction
0
1,398
7
2,796
Yes
output
1
1,398
7
2,797
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The flag of Berland is such rectangular field n × m that satisfies following conditions: * Flag consists of three colors which correspond to letters 'R', 'G' and 'B'. * Flag consists of three equal in width and height stripes, parralel to each other and to sides of the flag. Each stripe has exactly one color. * Each color should be used in exactly one stripe. You are given a field n × m, consisting of characters 'R', 'G' and 'B'. Output "YES" (without quotes) if this field corresponds to correct flag of Berland. Otherwise, print "NO" (without quotes). Input The first line contains two integer numbers n and m (1 ≤ n, m ≤ 100) — the sizes of the field. Each of the following n lines consisting of m characters 'R', 'G' and 'B' — the description of the field. Output Print "YES" (without quotes) if the given field corresponds to correct flag of Berland . Otherwise, print "NO" (without quotes). Examples Input 6 5 RRRRR RRRRR BBBBB BBBBB GGGGG GGGGG Output YES Input 4 3 BRG BRG BRG BRG Output YES Input 6 7 RRRGGGG RRRGGGG RRRGGGG RRRBBBB RRRBBBB RRRBBBB Output NO Input 4 4 RRRR RRRR BBBB GGGG Output NO Note The field in the third example doesn't have three parralel stripes. Rows of the field in the fourth example are parralel to each other and to borders. But they have different heights — 2, 1 and 1. Submitted Solution: ``` #python 3.5.2 #Ввод n m и самих цветов vv = input() n = int(vv[0:vv.find(' ')]) m = int(vv[vv.find(' '):]) x = '' for mm in range(n): x += input() col = 0 row = 0 res = True types = 0 if x[0] == x[n*m - m]: if m % 3 == 0: col = m//3 row = n types = 1 else: res = False else: if x[0] == x[m - 1]: if n%3 == 0: col = m row = n//3 types = 2 else: res = False else: res = False c1 = '' c2 = '' c3 = '' if res: if types == 1: for i in range(row): for j in range(col): c1 += x[j + m*i] for i in range(row): for j in range(col, col*2): c2 += x[j + m*i] for i in range(row): for j in range(col*2, col*3): c3 += x[j + m*i] if types == 2: for i in range(m*n//3): c1 += x[i] for i in range(m*n//3, m*n//3*2): c2 += x[i] for i in range(m*n//3*2, m*n): c3 += x[i] if res: let1 = c1[0] for i in c1: if i != let1: res = False break if res: let2 = c2[0] if let1 == let2: res =False else: for i in c2: if i != let2: res = False break if res: let3 = c3[0] if let1 == let3 or let2 == let3: res = False else: for i in c3: if i != let3: res = False break if res: print('YES') else: print('NO') ```
instruction
0
1,399
7
2,798
Yes
output
1
1,399
7
2,799
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The flag of Berland is such rectangular field n × m that satisfies following conditions: * Flag consists of three colors which correspond to letters 'R', 'G' and 'B'. * Flag consists of three equal in width and height stripes, parralel to each other and to sides of the flag. Each stripe has exactly one color. * Each color should be used in exactly one stripe. You are given a field n × m, consisting of characters 'R', 'G' and 'B'. Output "YES" (without quotes) if this field corresponds to correct flag of Berland. Otherwise, print "NO" (without quotes). Input The first line contains two integer numbers n and m (1 ≤ n, m ≤ 100) — the sizes of the field. Each of the following n lines consisting of m characters 'R', 'G' and 'B' — the description of the field. Output Print "YES" (without quotes) if the given field corresponds to correct flag of Berland . Otherwise, print "NO" (without quotes). Examples Input 6 5 RRRRR RRRRR BBBBB BBBBB GGGGG GGGGG Output YES Input 4 3 BRG BRG BRG BRG Output YES Input 6 7 RRRGGGG RRRGGGG RRRGGGG RRRBBBB RRRBBBB RRRBBBB Output NO Input 4 4 RRRR RRRR BBBB GGGG Output NO Note The field in the third example doesn't have three parralel stripes. Rows of the field in the fourth example are parralel to each other and to borders. But they have different heights — 2, 1 and 1. Submitted Solution: ``` import sys, math n, m = map(int, input().split()) a = ["" for i in range(n)] for i in range(n): a[i] = input() if (a[0][0] == a[0][m-1]) and (n % 3 == 0): for i in range(n // 3): for j in range(m): if (not a[i][j] == a[0][0]): print("NO") sys.exit() for i in range(n // 3, 2 * n // 3): for j in range(m): if (not a[i][j] == a[n // 3][0]): print("NO") sys.exit() for i in range(2 * n // 3, n): for j in range(m): if (not a[i][j] == a[2 * n // 3][0]): print("NO") sys.exit() if (a[0][0] == a[n // 3][0]) or (a[0][0] == a[2 * n // 3][0]) or (a[2 * n // 3][0] == a[n // 3][0]): print("NO") sys.exit() else: print("YES") sys.exit() elif (a[0][0] == a[n - 1][0]) and (m % 3 == 0): for i in range(n): for j in range(m // 3): if not ((a[i][j] == a[0][0]) and (a[i][j + m // 3] == a[0][m // 3]) and ( a[i][j + 2 * m // 3] == a[0][2 * m // 3])): print("NO") sys.exit() if (a[0][0] == a[0][m // 3]) or (a[0][0] == a[0][2 * m // 3]) or (a[0][2 * m // 3] == a[0][m // 3]): print("NO") sys.exit() else: print("YES") else: print("NO") ```
instruction
0
1,400
7
2,800
Yes
output
1
1,400
7
2,801
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The flag of Berland is such rectangular field n × m that satisfies following conditions: * Flag consists of three colors which correspond to letters 'R', 'G' and 'B'. * Flag consists of three equal in width and height stripes, parralel to each other and to sides of the flag. Each stripe has exactly one color. * Each color should be used in exactly one stripe. You are given a field n × m, consisting of characters 'R', 'G' and 'B'. Output "YES" (without quotes) if this field corresponds to correct flag of Berland. Otherwise, print "NO" (without quotes). Input The first line contains two integer numbers n and m (1 ≤ n, m ≤ 100) — the sizes of the field. Each of the following n lines consisting of m characters 'R', 'G' and 'B' — the description of the field. Output Print "YES" (without quotes) if the given field corresponds to correct flag of Berland . Otherwise, print "NO" (without quotes). Examples Input 6 5 RRRRR RRRRR BBBBB BBBBB GGGGG GGGGG Output YES Input 4 3 BRG BRG BRG BRG Output YES Input 6 7 RRRGGGG RRRGGGG RRRGGGG RRRBBBB RRRBBBB RRRBBBB Output NO Input 4 4 RRRR RRRR BBBB GGGG Output NO Note The field in the third example doesn't have three parralel stripes. Rows of the field in the fourth example are parralel to each other and to borders. But they have different heights — 2, 1 and 1. Submitted Solution: ``` height, width = map(int, input().split()) a = [input() for i in range(height)] c = {'r': 0, 'g': 0, 'b': 0} color = {'r': False, 'g': False, 'b': False} all_lines = True for i in range(height): for j in range(width): color[a[i][j].lower()] = True for i in range(height): for j in range(1, width): if a[i][j] != a[i][j - 1]: all_lines = False break c[a[i][j].lower()] += 1 if not all_lines: all_lines = True for key in c.keys(): c[key] = 0 for i in range(width): for j in range(1, height): if a[j][i] != a[j - 1][i]: all_lines = False break c[a[j][i].lower()] += 1 if all_lines and c['r'] == c['b'] == c['g'] and color['r'] and color['b'] and color['g']: print('YES') else: print('NO') ```
instruction
0
1,401
7
2,802
No
output
1
1,401
7
2,803
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The flag of Berland is such rectangular field n × m that satisfies following conditions: * Flag consists of three colors which correspond to letters 'R', 'G' and 'B'. * Flag consists of three equal in width and height stripes, parralel to each other and to sides of the flag. Each stripe has exactly one color. * Each color should be used in exactly one stripe. You are given a field n × m, consisting of characters 'R', 'G' and 'B'. Output "YES" (without quotes) if this field corresponds to correct flag of Berland. Otherwise, print "NO" (without quotes). Input The first line contains two integer numbers n and m (1 ≤ n, m ≤ 100) — the sizes of the field. Each of the following n lines consisting of m characters 'R', 'G' and 'B' — the description of the field. Output Print "YES" (without quotes) if the given field corresponds to correct flag of Berland . Otherwise, print "NO" (without quotes). Examples Input 6 5 RRRRR RRRRR BBBBB BBBBB GGGGG GGGGG Output YES Input 4 3 BRG BRG BRG BRG Output YES Input 6 7 RRRGGGG RRRGGGG RRRGGGG RRRBBBB RRRBBBB RRRBBBB Output NO Input 4 4 RRRR RRRR BBBB GGGG Output NO Note The field in the third example doesn't have three parralel stripes. Rows of the field in the fourth example are parralel to each other and to borders. But they have different heights — 2, 1 and 1. Submitted Solution: ``` #python 3.5.2 #Ввод n m и самих цветов vv = input() n = int(vv[0:vv.find(' ')]) m = int(vv[vv.find(' '):]) x = '' for mm in range(n): x += input() col = 0 row = 0 res = True types = 0 if x[0] == x[n*m - m]: if m % 3 == 0: col = m//3 row = n types = 1 else: res = False else: if x[0] == x[m - 1]: if n%3 == 0: col = m row = n//3 types = 2 else: res = False else: res = False c1 = '' c2 = '' c3 = '' if res: if types == 1: for i in range(row): for j in range(col): c1 += x[j + m*i] for i in range(row): for j in range(col, col*2): c2 += x[j + m*i] for i in range(row): for j in range(col*2, col*3): c3 += x[j + m*i] if types == 2: for i in range(m*n//3): c1 += x[i] for i in range(m*n//3, m*n//3*2): c2 += x[i] for i in range(m*n//3*2, m*n): c3 += x[i] if res: let = c1[0] for i in c1: if i != let: res = False break if res: let = c2[0] for i in c2: if i != let: res = False break if res: let = c3[0] for i in c3: if i != let: res = False break if res: print('YES') else: print('NO') ```
instruction
0
1,402
7
2,804
No
output
1
1,402
7
2,805
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The flag of Berland is such rectangular field n × m that satisfies following conditions: * Flag consists of three colors which correspond to letters 'R', 'G' and 'B'. * Flag consists of three equal in width and height stripes, parralel to each other and to sides of the flag. Each stripe has exactly one color. * Each color should be used in exactly one stripe. You are given a field n × m, consisting of characters 'R', 'G' and 'B'. Output "YES" (without quotes) if this field corresponds to correct flag of Berland. Otherwise, print "NO" (without quotes). Input The first line contains two integer numbers n and m (1 ≤ n, m ≤ 100) — the sizes of the field. Each of the following n lines consisting of m characters 'R', 'G' and 'B' — the description of the field. Output Print "YES" (without quotes) if the given field corresponds to correct flag of Berland . Otherwise, print "NO" (without quotes). Examples Input 6 5 RRRRR RRRRR BBBBB BBBBB GGGGG GGGGG Output YES Input 4 3 BRG BRG BRG BRG Output YES Input 6 7 RRRGGGG RRRGGGG RRRGGGG RRRBBBB RRRBBBB RRRBBBB Output NO Input 4 4 RRRR RRRR BBBB GGGG Output NO Note The field in the third example doesn't have three parralel stripes. Rows of the field in the fourth example are parralel to each other and to borders. But they have different heights — 2, 1 and 1. Submitted Solution: ``` lines = [] m,n = input().split() for i in range(int(m)): lines.append(input()) noError = 'YES' lineInx = 0 direction = 'vert' for l in lines: if l[0] != lines[0][0]: direction = 'gorz' if direction == 'gorz': while noError == 'YES' and lineInx < int(m): if direction == 'gorz': if lines[lineInx][0] == 'R': if 'G' in lines[lineInx] or 'B' in lines[lineInx]: noError = 'NO' elif lines[lineInx][0] == 'G': if 'R' in lines[lineInx] or 'B' in lines[lineInx]: noError = 'NO' elif lines[lineInx][0] == 'B': if 'G' in lines[lineInx] or 'R' in lines[lineInx]: noError = 'NO' else: noError = 'NO' lineInx += 1 else: for i in range(int(n)): for j in range(int(m)-1): if lines[j][i] != lines[j+1][i]: noError = 'NO' print(noError) ```
instruction
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1,403
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2,806
No
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1,403
7
2,807
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The flag of Berland is such rectangular field n × m that satisfies following conditions: * Flag consists of three colors which correspond to letters 'R', 'G' and 'B'. * Flag consists of three equal in width and height stripes, parralel to each other and to sides of the flag. Each stripe has exactly one color. * Each color should be used in exactly one stripe. You are given a field n × m, consisting of characters 'R', 'G' and 'B'. Output "YES" (without quotes) if this field corresponds to correct flag of Berland. Otherwise, print "NO" (without quotes). Input The first line contains two integer numbers n and m (1 ≤ n, m ≤ 100) — the sizes of the field. Each of the following n lines consisting of m characters 'R', 'G' and 'B' — the description of the field. Output Print "YES" (without quotes) if the given field corresponds to correct flag of Berland . Otherwise, print "NO" (without quotes). Examples Input 6 5 RRRRR RRRRR BBBBB BBBBB GGGGG GGGGG Output YES Input 4 3 BRG BRG BRG BRG Output YES Input 6 7 RRRGGGG RRRGGGG RRRGGGG RRRBBBB RRRBBBB RRRBBBB Output NO Input 4 4 RRRR RRRR BBBB GGGG Output NO Note The field in the third example doesn't have three parralel stripes. Rows of the field in the fourth example are parralel to each other and to borders. But they have different heights — 2, 1 and 1. Submitted Solution: ``` n, m = map(int, input().split()) a = [] for i in range(n): a.append(input()) f1 = 0 f2 = 0 if n % 3 == 0: f1 = 1 o1 = a[0][0] o2 = a[n // 3][0] o3 = a[2 * n // 3][0] for i in range(n): if i < n // 3: if a[i] != o1 * m: f1 = 0 break elif i < 2 * n // 3: if a[i] != o2 * m: f1 = 0 break else: if a[i] != o3 * m: f1 = 0 break if m % 3 == 0: f2 = 1 o1 = a[0][0] o2 = a[0][m // 3] o3 = a[0][2 * m // 3] for i in range(n): for j in range(m): if j < m // 3: if a[i][j] != o1: f2 = 0 break elif i < 2 * m // 3: if a[i][j] != o2: f2 = 0 break else: if a[i][j] != o3: f2 = 0 break if not f2: break if f1 or f2: print("YES") else: print("NO") ```
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1,404
7
2,808
No
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1,404
7
2,809
Provide tags and a correct Python 3 solution for this coding contest problem. You are given n integers. You need to choose a subset and put the chosen numbers in a beautiful rectangle (rectangular matrix). Each chosen number should occupy one of its rectangle cells, each cell must be filled with exactly one chosen number. Some of the n numbers may not be chosen. A rectangle (rectangular matrix) is called beautiful if in each row and in each column all values are different. What is the largest (by the total number of cells) beautiful rectangle you can construct? Print the rectangle itself. Input The first line contains n (1 ≤ n ≤ 4⋅10^5). The second line contains n integers (1 ≤ a_i ≤ 10^9). Output In the first line print x (1 ≤ x ≤ n) — the total number of cells of the required maximum beautiful rectangle. In the second line print p and q (p ⋅ q=x): its sizes. In the next p lines print the required rectangle itself. If there are several answers, print any. Examples Input 12 3 1 4 1 5 9 2 6 5 3 5 8 Output 12 3 4 1 2 3 5 3 1 5 4 5 6 8 9 Input 5 1 1 1 1 1 Output 1 1 1 1
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0
2,595
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5,190
Tags: brute force, combinatorics, constructive algorithms, data structures, greedy, math Correct Solution: ``` def play(arr): n = len(arr) number2Count = {} for p in arr: number2Count[p] = number2Count.get(p, 0) + 1 count2Numbers = {} maxCnt = 0 for num in number2Count: cnt = number2Count[num] if not cnt in count2Numbers: count2Numbers[cnt] = [] count2Numbers[cnt].append(num) maxCnt = max(maxCnt, cnt) numRepeats = [0] * (n + 1) numRepeats[n] = len(count2Numbers.get(n, [])) for i in range(n - 1, 0, -1): numRepeats[i] = numRepeats[i + 1] + len(count2Numbers.get(i, [])) a_ideal = 0 b_ideal = 0 square = 0 square_ideal = 0 for a in range(1, n + 1): square += numRepeats[a] b = int(square / a) if a <= b: if square_ideal < a * b: square_ideal = a * b a_ideal = a b_ideal = b print(a_ideal * b_ideal) print(str(a_ideal) + ' ' + str(b_ideal)) matrix = [[0] * b_ideal for p in range(0, a_ideal)] x = 0 y = 0 for cnt in range(maxCnt, 0, -1): for num in count2Numbers.get(cnt, []): for i in range(0, min(cnt, a_ideal)): if matrix[x][y] > 0: x = (x + 1) % a_ideal if matrix[x][y] == 0: matrix[x][y] = num x = (x + 1) % a_ideal y = (y + 1) % b_ideal for i in range(0, a_ideal): print(*matrix[i]) def main(): input() arr = list(map(int, input().split())) play(arr) main() #print(play([3, 1, 4, 1, 5, 9, 2, 6, 5, 3, 5, 8])) #print(play([4, 9, 5, 9, 6, 8, 9, 8, 7])) # play(['010', '101', '0']) # play(['00000', '00001']) # play(['01', '001', '0001', '00001']) ```
output
1
2,595
7
5,191
Provide a correct Python 3 solution for this coding contest problem. You are given a grid of squares with H horizontal rows and W vertical columns, where each square is painted white or black. HW characters from A_{11} to A_{HW} represent the colors of the squares. A_{ij} is `#` if the square at the i-th row from the top and the j-th column from the left is black, and A_{ij} is `.` if that square is white. We will repeatedly perform the following operation until all the squares are black: * Every white square that shares a side with a black square, becomes black. Find the number of operations that will be performed. The initial grid has at least one black square. Constraints * 1 \leq H,W \leq 1000 * A_{ij} is `#` or `.`. * The given grid has at least one black square. Input Input is given from Standard Input in the following format: H W A_{11}A_{12}...A_{1W} : A_{H1}A_{H2}...A_{HW} Output Print the number of operations that will be performed. Examples Input 3 3 ... .#. ... Output 2 Input 6 6 ..#..# ...... ..#.. ...... .#.... ....#. Output 3
instruction
0
3,134
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6,268
"Correct Solution: ``` INF=float("inf") def main(): H,W=map(int, input().split()) A=[input()for _ in range(H)] D=[[0 if A[h][w]=="#" else INF for w in range(W)] for h in range(H)] for h in range(H): for w in range(1,W): D[h][w]=min(D[h][w],D[h][w-1]+1) for w in range(W-2, -1, -1): D[h][w]=min(D[h][w],D[h][w+1]+1) for w in range(W): for h in range(1,H): D[h][w]=min(D[h][w],D[h-1][w]+1) for h in range(H-2, -1, -1): D[h][w]=min(D[h][w],D[h+1][w]+1) print(max(d for dd in D for d in dd)) if __name__ == "__main__": main() ```
output
1
3,134
7
6,269
Provide a correct Python 3 solution for this coding contest problem. You are given a grid of squares with H horizontal rows and W vertical columns, where each square is painted white or black. HW characters from A_{11} to A_{HW} represent the colors of the squares. A_{ij} is `#` if the square at the i-th row from the top and the j-th column from the left is black, and A_{ij} is `.` if that square is white. We will repeatedly perform the following operation until all the squares are black: * Every white square that shares a side with a black square, becomes black. Find the number of operations that will be performed. The initial grid has at least one black square. Constraints * 1 \leq H,W \leq 1000 * A_{ij} is `#` or `.`. * The given grid has at least one black square. Input Input is given from Standard Input in the following format: H W A_{11}A_{12}...A_{1W} : A_{H1}A_{H2}...A_{HW} Output Print the number of operations that will be performed. Examples Input 3 3 ... .#. ... Output 2 Input 6 6 ..#..# ...... ..#.. ...... .#.... ....#. Output 3
instruction
0
3,135
7
6,270
"Correct Solution: ``` from collections import deque h,w = map(int,input().split()) l = [list(input()) for i in range(h)] dis = [[10000]*w for i in range(h)] q = deque([]) for i in range(h): for j in range(w): if l[i][j] == "#": q.append([i,j,0]) dis[i][j] = 0 dx = [0,0,1,-1] dy = [1,-1,0,0] while q: x,y,d = q.popleft() for i in range(4): nx = x + dx[i] ny = y + dy[i] if 0 <= nx < h and 0 <= ny < w and dis[nx][ny] > d+1: dis[nx][ny] = d + 1 q.append([nx,ny,d+1]) ans = 0 for i in dis: ans = max(ans,max(i)) print(ans) ```
output
1
3,135
7
6,271
Provide a correct Python 3 solution for this coding contest problem. You are given a grid of squares with H horizontal rows and W vertical columns, where each square is painted white or black. HW characters from A_{11} to A_{HW} represent the colors of the squares. A_{ij} is `#` if the square at the i-th row from the top and the j-th column from the left is black, and A_{ij} is `.` if that square is white. We will repeatedly perform the following operation until all the squares are black: * Every white square that shares a side with a black square, becomes black. Find the number of operations that will be performed. The initial grid has at least one black square. Constraints * 1 \leq H,W \leq 1000 * A_{ij} is `#` or `.`. * The given grid has at least one black square. Input Input is given from Standard Input in the following format: H W A_{11}A_{12}...A_{1W} : A_{H1}A_{H2}...A_{HW} Output Print the number of operations that will be performed. Examples Input 3 3 ... .#. ... Output 2 Input 6 6 ..#..# ...... ..#.. ...... .#.... ....#. Output 3
instruction
0
3,136
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6,272
"Correct Solution: ``` h,w = map(int,input().split()) a = list(list(input())for i in range(h)) stack = [] for i in range(h): for j in range(w): if a[i][j] == "#": stack.append((i,j)) vec = ((1,0),(0,1),(-1,0),(0,-1)) move = 0 while stack: next = [] move +=1 for y,x in stack: for ny,nx in vec: ty,tx = y+ny,x+nx if ty>h-1 or tx>w-1 or ty<0 or tx <0:continue if a[ty][tx] == ".": a[ty][tx] = move next.append((ty,tx)) stack = next print(move-1) ```
output
1
3,136
7
6,273
Provide a correct Python 3 solution for this coding contest problem. You are given a grid of squares with H horizontal rows and W vertical columns, where each square is painted white or black. HW characters from A_{11} to A_{HW} represent the colors of the squares. A_{ij} is `#` if the square at the i-th row from the top and the j-th column from the left is black, and A_{ij} is `.` if that square is white. We will repeatedly perform the following operation until all the squares are black: * Every white square that shares a side with a black square, becomes black. Find the number of operations that will be performed. The initial grid has at least one black square. Constraints * 1 \leq H,W \leq 1000 * A_{ij} is `#` or `.`. * The given grid has at least one black square. Input Input is given from Standard Input in the following format: H W A_{11}A_{12}...A_{1W} : A_{H1}A_{H2}...A_{HW} Output Print the number of operations that will be performed. Examples Input 3 3 ... .#. ... Output 2 Input 6 6 ..#..# ...... ..#.. ...... .#.... ....#. Output 3
instruction
0
3,137
7
6,274
"Correct Solution: ``` from collections import deque h, w = map(int, input().split()) d = deque() op = [[-1] * w for i in range(h)] for i in range(h): s = input().rstrip() for j in range(len(s)): if s[j] == '#': d.append((i, j, 0)) op[i][j] = 0 while d: i, j, step = d.popleft() for i2, j2 in [(i-1, j), (i+1, j), (i, j-1), (i, j+1)]: if 0 <= i2 < h and 0 <= j2 < w: if op[i2][j2] == -1: d.append((i2, j2, step+1)) op[i2][j2] = step + 1 print(max([max(op[i]) for i in range(h)])) ```
output
1
3,137
7
6,275
Provide a correct Python 3 solution for this coding contest problem. You are given a grid of squares with H horizontal rows and W vertical columns, where each square is painted white or black. HW characters from A_{11} to A_{HW} represent the colors of the squares. A_{ij} is `#` if the square at the i-th row from the top and the j-th column from the left is black, and A_{ij} is `.` if that square is white. We will repeatedly perform the following operation until all the squares are black: * Every white square that shares a side with a black square, becomes black. Find the number of operations that will be performed. The initial grid has at least one black square. Constraints * 1 \leq H,W \leq 1000 * A_{ij} is `#` or `.`. * The given grid has at least one black square. Input Input is given from Standard Input in the following format: H W A_{11}A_{12}...A_{1W} : A_{H1}A_{H2}...A_{HW} Output Print the number of operations that will be performed. Examples Input 3 3 ... .#. ... Output 2 Input 6 6 ..#..# ...... ..#.. ...... .#.... ....#. Output 3
instruction
0
3,138
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6,276
"Correct Solution: ``` from collections import deque h, w = map(int, input().split()) a = [list(input()) for _ in range(h)] q = deque([]) for i in range(h): for j in range(w): if a[i][j] == '#': q.append([i, j]) q.append(0) while q: y, x = q.popleft() ans = q.popleft() + 1 for dy, dx in [[1, 0], [0, 1], [-1, 0], [0, -1]]: ny, nx = dy + y, dx + x if ny < 0 or nx < 0 or ny >= h or nx >= w: continue if a[ny][nx] == '.': a[ny][nx] = '#' q.append([ny, nx]) q.append(ans) print(ans-1) ```
output
1
3,138
7
6,277
Provide a correct Python 3 solution for this coding contest problem. You are given a grid of squares with H horizontal rows and W vertical columns, where each square is painted white or black. HW characters from A_{11} to A_{HW} represent the colors of the squares. A_{ij} is `#` if the square at the i-th row from the top and the j-th column from the left is black, and A_{ij} is `.` if that square is white. We will repeatedly perform the following operation until all the squares are black: * Every white square that shares a side with a black square, becomes black. Find the number of operations that will be performed. The initial grid has at least one black square. Constraints * 1 \leq H,W \leq 1000 * A_{ij} is `#` or `.`. * The given grid has at least one black square. Input Input is given from Standard Input in the following format: H W A_{11}A_{12}...A_{1W} : A_{H1}A_{H2}...A_{HW} Output Print the number of operations that will be performed. Examples Input 3 3 ... .#. ... Output 2 Input 6 6 ..#..# ...... ..#.. ...... .#.... ....#. Output 3
instruction
0
3,139
7
6,278
"Correct Solution: ``` from collections import deque h, w = map(int, input().split()) A = [input() for _ in range(h)] dist = [[-1]*w for _ in range(h)] di = [1, 0, -1, 0] dj = [0, 1, 0, -1] que = deque() for i in range(h): for j in range(w): if A[i][j] == "#": que.append((i, j)) dist[i][j] = 0 while que: y, x = que.popleft() for dy, dx in zip(di, dj): ny, nx = y+dy, x+dx if ny < 0 or ny >= h or nx < 0 or nx >= w: continue if dist[ny][nx] != -1: continue dist[ny][nx] = dist[y][x] + 1 que.append((ny, nx)) ans = 0 for i in dist: ans = max(ans, max(i)) print(ans) ```
output
1
3,139
7
6,279
Provide a correct Python 3 solution for this coding contest problem. You are given a grid of squares with H horizontal rows and W vertical columns, where each square is painted white or black. HW characters from A_{11} to A_{HW} represent the colors of the squares. A_{ij} is `#` if the square at the i-th row from the top and the j-th column from the left is black, and A_{ij} is `.` if that square is white. We will repeatedly perform the following operation until all the squares are black: * Every white square that shares a side with a black square, becomes black. Find the number of operations that will be performed. The initial grid has at least one black square. Constraints * 1 \leq H,W \leq 1000 * A_{ij} is `#` or `.`. * The given grid has at least one black square. Input Input is given from Standard Input in the following format: H W A_{11}A_{12}...A_{1W} : A_{H1}A_{H2}...A_{HW} Output Print the number of operations that will be performed. Examples Input 3 3 ... .#. ... Output 2 Input 6 6 ..#..# ...... ..#.. ...... .#.... ....#. Output 3
instruction
0
3,140
7
6,280
"Correct Solution: ``` h,w=map(int,input().split()) G=[input() for _ in range(h)] from collections import deque move=[(0,1),(0,-1),(1,0),(-1,0)] que=deque([]) for i in range(h): for j in range(w): if G[i][j]=='#': que.append((i,j,0)) c=0 visit=[[0]*w for _ in range(h)] while len(que)>0: ni,nj,c=que.popleft() for di,dj in move: mi,mj=ni+di,nj+dj if 0<=mi<h and 0<=mj<w and G[mi][mj]=='.' and visit[mi][mj]==0: visit[mi][mj]=1 que.append((mi,mj,c+1)) print(c) ```
output
1
3,140
7
6,281
Provide a correct Python 3 solution for this coding contest problem. You are given a grid of squares with H horizontal rows and W vertical columns, where each square is painted white or black. HW characters from A_{11} to A_{HW} represent the colors of the squares. A_{ij} is `#` if the square at the i-th row from the top and the j-th column from the left is black, and A_{ij} is `.` if that square is white. We will repeatedly perform the following operation until all the squares are black: * Every white square that shares a side with a black square, becomes black. Find the number of operations that will be performed. The initial grid has at least one black square. Constraints * 1 \leq H,W \leq 1000 * A_{ij} is `#` or `.`. * The given grid has at least one black square. Input Input is given from Standard Input in the following format: H W A_{11}A_{12}...A_{1W} : A_{H1}A_{H2}...A_{HW} Output Print the number of operations that will be performed. Examples Input 3 3 ... .#. ... Output 2 Input 6 6 ..#..# ...... ..#.. ...... .#.... ....#. Output 3
instruction
0
3,141
7
6,282
"Correct Solution: ``` from collections import deque H,W = map(int, input().split()) A = 0 dp = [None] * H mat = deque() for h in range(H): s = list(input()) for w, x in zip(range(W), s): if x == "#": mat.append((h, w, 0)) dp[h] = s while len(mat): h, w, cnt = mat.popleft() for t, h, w, cnt in [(h > 0, h - 1, w, cnt),(h < H-1, h + 1, w, cnt),(w > 0, h , w - 1, cnt),(w < W-1, h , w + 1, cnt)]: if t and dp[h][w] == ".": mat.append((h, w, cnt+1)) dp[h][w] = "#" print(cnt) ```
output
1
3,141
7
6,283
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a grid of squares with H horizontal rows and W vertical columns, where each square is painted white or black. HW characters from A_{11} to A_{HW} represent the colors of the squares. A_{ij} is `#` if the square at the i-th row from the top and the j-th column from the left is black, and A_{ij} is `.` if that square is white. We will repeatedly perform the following operation until all the squares are black: * Every white square that shares a side with a black square, becomes black. Find the number of operations that will be performed. The initial grid has at least one black square. Constraints * 1 \leq H,W \leq 1000 * A_{ij} is `#` or `.`. * The given grid has at least one black square. Input Input is given from Standard Input in the following format: H W A_{11}A_{12}...A_{1W} : A_{H1}A_{H2}...A_{HW} Output Print the number of operations that will be performed. Examples Input 3 3 ... .#. ... Output 2 Input 6 6 ..#..# ...... ..#.. ...... .#.... ....#. Output 3 Submitted Solution: ``` H, W = map(int, input().split()) l = [list(input()) for _ in range(H)] from collections import deque q = deque() for i, r in enumerate(l): for j, c in enumerate(r): if c == '#': l[i][j] = 0 q.append((i, j)) d = [(0, 1), (0, -1), (1, 0), (-1, 0)] while q: y, x = q.popleft() for dy, dx in d: if (0 <= y+dy < H) and (0 <= x+dx < W) and l[y+dy][x+dx] == '.': l[y+dy][x+dx] = l[y][x] + 1 q.append((y+dy, x+dx)) m = 0 for r in l: for c in r: if m < c: m = c print(m) ```
instruction
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3,142
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6,284
Yes
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3,142
7
6,285
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a grid of squares with H horizontal rows and W vertical columns, where each square is painted white or black. HW characters from A_{11} to A_{HW} represent the colors of the squares. A_{ij} is `#` if the square at the i-th row from the top and the j-th column from the left is black, and A_{ij} is `.` if that square is white. We will repeatedly perform the following operation until all the squares are black: * Every white square that shares a side with a black square, becomes black. Find the number of operations that will be performed. The initial grid has at least one black square. Constraints * 1 \leq H,W \leq 1000 * A_{ij} is `#` or `.`. * The given grid has at least one black square. Input Input is given from Standard Input in the following format: H W A_{11}A_{12}...A_{1W} : A_{H1}A_{H2}...A_{HW} Output Print the number of operations that will be performed. Examples Input 3 3 ... .#. ... Output 2 Input 6 6 ..#..# ...... ..#.. ...... .#.... ....#. Output 3 Submitted Solution: ``` import collections h,w = map(int, input().split()) cells = [] for i in range(h): row = input() cells.append([c == '#' for c in row]) blacks = collections.deque() for i in range(h): for j in range(w): if cells[i][j]: blacks.append((i,j,0)) res = 0 while blacks: y,x,c = blacks.popleft() for dy,dx in ((-1, 0), (1, 0), (0, -1), (0,1)): if 0<=y+dy<h and 0<=x+dx<w and not cells[y+dy][x+dx]: cells[y+dy][x+dx] = True blacks.append((y+dy, x+dx, c+1)) res = c+1 print(c) ```
instruction
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3,143
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6,286
Yes
output
1
3,143
7
6,287