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Provide a correct Python 3 solution for this coding contest problem. User ainta has a stack of n red and blue balls. He can apply a certain operation which changes the colors of the balls inside the stack. * While the top ball inside the stack is red, pop the ball from the top of the stack. * Then replace the blue ball on the top with a red ball. * And finally push some blue balls to the stack until the stack has total of n balls inside. If there are no blue balls inside the stack, ainta can't apply this operation. Given the initial state of the stack, ainta wants to know the maximum number of operations he can repeatedly apply. Input The first line contains an integer n (1 ≤ n ≤ 50) — the number of balls inside the stack. The second line contains a string s (|s| = n) describing the initial state of the stack. The i-th character of the string s denotes the color of the i-th ball (we'll number the balls from top to bottom of the stack). If the character is "R", the color is red. If the character is "B", the color is blue. Output Print the maximum number of operations ainta can repeatedly apply. Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 3 RBR Output 2 Input 4 RBBR Output 6 Input 5 RBBRR Output 6 Note The first example is depicted below. The explanation how user ainta applies the first operation. He pops out one red ball, changes the color of the ball in the middle from blue to red, and pushes one blue ball. <image> The explanation how user ainta applies the second operation. He will not pop out red balls, he simply changes the color of the ball on the top from blue to red. <image> From now on, ainta can't apply any operation because there are no blue balls inside the stack. ainta applied two operations, so the answer is 2. The second example is depicted below. The blue arrow denotes a single operation. <image>
instruction
0
22,405
7
44,810
"Correct Solution: ``` input() print(int(input()[::-1].translate(str.maketrans('RB', '01')), 2)) # print(int(input()[::-1].replace('R', '0').replace('B', '1'), 2)) # print(int(''.join(list(map(lambda x: '0' if x == 'R' else '1', input()[::-1]))), 2)) ```
output
1
22,405
7
44,811
Provide a correct Python 3 solution for this coding contest problem. User ainta has a stack of n red and blue balls. He can apply a certain operation which changes the colors of the balls inside the stack. * While the top ball inside the stack is red, pop the ball from the top of the stack. * Then replace the blue ball on the top with a red ball. * And finally push some blue balls to the stack until the stack has total of n balls inside. If there are no blue balls inside the stack, ainta can't apply this operation. Given the initial state of the stack, ainta wants to know the maximum number of operations he can repeatedly apply. Input The first line contains an integer n (1 ≤ n ≤ 50) — the number of balls inside the stack. The second line contains a string s (|s| = n) describing the initial state of the stack. The i-th character of the string s denotes the color of the i-th ball (we'll number the balls from top to bottom of the stack). If the character is "R", the color is red. If the character is "B", the color is blue. Output Print the maximum number of operations ainta can repeatedly apply. Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 3 RBR Output 2 Input 4 RBBR Output 6 Input 5 RBBRR Output 6 Note The first example is depicted below. The explanation how user ainta applies the first operation. He pops out one red ball, changes the color of the ball in the middle from blue to red, and pushes one blue ball. <image> The explanation how user ainta applies the second operation. He will not pop out red balls, he simply changes the color of the ball on the top from blue to red. <image> From now on, ainta can't apply any operation because there are no blue balls inside the stack. ainta applied two operations, so the answer is 2. The second example is depicted below. The blue arrow denotes a single operation. <image>
instruction
0
22,406
7
44,812
"Correct Solution: ``` # def calculate(n, s): # c = 0 # while "B" in s: # while s[0] == "R": # s = s[1:] # # if s[0] == "B": # s = "R" + s[1:] # # while len(s) != n: # s = "B" + s # # c += 1 # # return c def calculate(n, s): c = 0 for i in range(len(s)): if s[i] == "B": c += pow(2,i) return c n = input() s = input() print(calculate(int(n), s)) ```
output
1
22,406
7
44,813
Provide a correct Python 3 solution for this coding contest problem. User ainta has a stack of n red and blue balls. He can apply a certain operation which changes the colors of the balls inside the stack. * While the top ball inside the stack is red, pop the ball from the top of the stack. * Then replace the blue ball on the top with a red ball. * And finally push some blue balls to the stack until the stack has total of n balls inside. If there are no blue balls inside the stack, ainta can't apply this operation. Given the initial state of the stack, ainta wants to know the maximum number of operations he can repeatedly apply. Input The first line contains an integer n (1 ≤ n ≤ 50) — the number of balls inside the stack. The second line contains a string s (|s| = n) describing the initial state of the stack. The i-th character of the string s denotes the color of the i-th ball (we'll number the balls from top to bottom of the stack). If the character is "R", the color is red. If the character is "B", the color is blue. Output Print the maximum number of operations ainta can repeatedly apply. Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 3 RBR Output 2 Input 4 RBBR Output 6 Input 5 RBBRR Output 6 Note The first example is depicted below. The explanation how user ainta applies the first operation. He pops out one red ball, changes the color of the ball in the middle from blue to red, and pushes one blue ball. <image> The explanation how user ainta applies the second operation. He will not pop out red balls, he simply changes the color of the ball on the top from blue to red. <image> From now on, ainta can't apply any operation because there are no blue balls inside the stack. ainta applied two operations, so the answer is 2. The second example is depicted below. The blue arrow denotes a single operation. <image>
instruction
0
22,407
7
44,814
"Correct Solution: ``` s = input() #s = "5" n = int(s) s = input() #s = "RBBRR" x = s ans = 0 for i in range(0, n): if x[i] == 'B': ans += 1 << i print(ans) ```
output
1
22,407
7
44,815
Provide a correct Python 3 solution for this coding contest problem. User ainta has a stack of n red and blue balls. He can apply a certain operation which changes the colors of the balls inside the stack. * While the top ball inside the stack is red, pop the ball from the top of the stack. * Then replace the blue ball on the top with a red ball. * And finally push some blue balls to the stack until the stack has total of n balls inside. If there are no blue balls inside the stack, ainta can't apply this operation. Given the initial state of the stack, ainta wants to know the maximum number of operations he can repeatedly apply. Input The first line contains an integer n (1 ≤ n ≤ 50) — the number of balls inside the stack. The second line contains a string s (|s| = n) describing the initial state of the stack. The i-th character of the string s denotes the color of the i-th ball (we'll number the balls from top to bottom of the stack). If the character is "R", the color is red. If the character is "B", the color is blue. Output Print the maximum number of operations ainta can repeatedly apply. Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 3 RBR Output 2 Input 4 RBBR Output 6 Input 5 RBBRR Output 6 Note The first example is depicted below. The explanation how user ainta applies the first operation. He pops out one red ball, changes the color of the ball in the middle from blue to red, and pushes one blue ball. <image> The explanation how user ainta applies the second operation. He will not pop out red balls, he simply changes the color of the ball on the top from blue to red. <image> From now on, ainta can't apply any operation because there are no blue balls inside the stack. ainta applied two operations, so the answer is 2. The second example is depicted below. The blue arrow denotes a single operation. <image>
instruction
0
22,408
7
44,816
"Correct Solution: ``` print(2 ** int(input()) - int(''.join(list(map(lambda x: '1' if x == 'R' else '0', input()[::-1]))), 2) - 1) ```
output
1
22,408
7
44,817
Provide a correct Python 3 solution for this coding contest problem. User ainta has a stack of n red and blue balls. He can apply a certain operation which changes the colors of the balls inside the stack. * While the top ball inside the stack is red, pop the ball from the top of the stack. * Then replace the blue ball on the top with a red ball. * And finally push some blue balls to the stack until the stack has total of n balls inside. If there are no blue balls inside the stack, ainta can't apply this operation. Given the initial state of the stack, ainta wants to know the maximum number of operations he can repeatedly apply. Input The first line contains an integer n (1 ≤ n ≤ 50) — the number of balls inside the stack. The second line contains a string s (|s| = n) describing the initial state of the stack. The i-th character of the string s denotes the color of the i-th ball (we'll number the balls from top to bottom of the stack). If the character is "R", the color is red. If the character is "B", the color is blue. Output Print the maximum number of operations ainta can repeatedly apply. Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 3 RBR Output 2 Input 4 RBBR Output 6 Input 5 RBBRR Output 6 Note The first example is depicted below. The explanation how user ainta applies the first operation. He pops out one red ball, changes the color of the ball in the middle from blue to red, and pushes one blue ball. <image> The explanation how user ainta applies the second operation. He will not pop out red balls, he simply changes the color of the ball on the top from blue to red. <image> From now on, ainta can't apply any operation because there are no blue balls inside the stack. ainta applied two operations, so the answer is 2. The second example is depicted below. The blue arrow denotes a single operation. <image>
instruction
0
22,409
7
44,818
"Correct Solution: ``` size = int(input()) stack = list(input()) print(sum([2 ** i for i in range(size) if stack[i] == 'B'])) ```
output
1
22,409
7
44,819
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. User ainta has a stack of n red and blue balls. He can apply a certain operation which changes the colors of the balls inside the stack. * While the top ball inside the stack is red, pop the ball from the top of the stack. * Then replace the blue ball on the top with a red ball. * And finally push some blue balls to the stack until the stack has total of n balls inside. If there are no blue balls inside the stack, ainta can't apply this operation. Given the initial state of the stack, ainta wants to know the maximum number of operations he can repeatedly apply. Input The first line contains an integer n (1 ≤ n ≤ 50) — the number of balls inside the stack. The second line contains a string s (|s| = n) describing the initial state of the stack. The i-th character of the string s denotes the color of the i-th ball (we'll number the balls from top to bottom of the stack). If the character is "R", the color is red. If the character is "B", the color is blue. Output Print the maximum number of operations ainta can repeatedly apply. Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 3 RBR Output 2 Input 4 RBBR Output 6 Input 5 RBBRR Output 6 Note The first example is depicted below. The explanation how user ainta applies the first operation. He pops out one red ball, changes the color of the ball in the middle from blue to red, and pushes one blue ball. <image> The explanation how user ainta applies the second operation. He will not pop out red balls, he simply changes the color of the ball on the top from blue to red. <image> From now on, ainta can't apply any operation because there are no blue balls inside the stack. ainta applied two operations, so the answer is 2. The second example is depicted below. The blue arrow denotes a single operation. <image> Submitted Solution: ``` n = int(input()) s = input().strip() ans = 0 for i in range(len(s)): if s[i] == "B": ans += 2 ** i print(ans) ```
instruction
0
22,410
7
44,820
Yes
output
1
22,410
7
44,821
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. User ainta has a stack of n red and blue balls. He can apply a certain operation which changes the colors of the balls inside the stack. * While the top ball inside the stack is red, pop the ball from the top of the stack. * Then replace the blue ball on the top with a red ball. * And finally push some blue balls to the stack until the stack has total of n balls inside. If there are no blue balls inside the stack, ainta can't apply this operation. Given the initial state of the stack, ainta wants to know the maximum number of operations he can repeatedly apply. Input The first line contains an integer n (1 ≤ n ≤ 50) — the number of balls inside the stack. The second line contains a string s (|s| = n) describing the initial state of the stack. The i-th character of the string s denotes the color of the i-th ball (we'll number the balls from top to bottom of the stack). If the character is "R", the color is red. If the character is "B", the color is blue. Output Print the maximum number of operations ainta can repeatedly apply. Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 3 RBR Output 2 Input 4 RBBR Output 6 Input 5 RBBRR Output 6 Note The first example is depicted below. The explanation how user ainta applies the first operation. He pops out one red ball, changes the color of the ball in the middle from blue to red, and pushes one blue ball. <image> The explanation how user ainta applies the second operation. He will not pop out red balls, he simply changes the color of the ball on the top from blue to red. <image> From now on, ainta can't apply any operation because there are no blue balls inside the stack. ainta applied two operations, so the answer is 2. The second example is depicted below. The blue arrow denotes a single operation. <image> Submitted Solution: ``` def solve(stack): return sum([2 ** i for i, c in enumerate(stack) if c == 'B']) def main(): _ = int(input()) stack = input() print(solve(stack)) if __name__ == '__main__': main() ```
instruction
0
22,411
7
44,822
Yes
output
1
22,411
7
44,823
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. User ainta has a stack of n red and blue balls. He can apply a certain operation which changes the colors of the balls inside the stack. * While the top ball inside the stack is red, pop the ball from the top of the stack. * Then replace the blue ball on the top with a red ball. * And finally push some blue balls to the stack until the stack has total of n balls inside. If there are no blue balls inside the stack, ainta can't apply this operation. Given the initial state of the stack, ainta wants to know the maximum number of operations he can repeatedly apply. Input The first line contains an integer n (1 ≤ n ≤ 50) — the number of balls inside the stack. The second line contains a string s (|s| = n) describing the initial state of the stack. The i-th character of the string s denotes the color of the i-th ball (we'll number the balls from top to bottom of the stack). If the character is "R", the color is red. If the character is "B", the color is blue. Output Print the maximum number of operations ainta can repeatedly apply. Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 3 RBR Output 2 Input 4 RBBR Output 6 Input 5 RBBRR Output 6 Note The first example is depicted below. The explanation how user ainta applies the first operation. He pops out one red ball, changes the color of the ball in the middle from blue to red, and pushes one blue ball. <image> The explanation how user ainta applies the second operation. He will not pop out red balls, he simply changes the color of the ball on the top from blue to red. <image> From now on, ainta can't apply any operation because there are no blue balls inside the stack. ainta applied two operations, so the answer is 2. The second example is depicted below. The blue arrow denotes a single operation. <image> Submitted Solution: ``` n = int(input()) s = input().split()[0] res = 0 for i in range(len(s)): if s[i] == 'B': res += 2**i print(res) ```
instruction
0
22,412
7
44,824
Yes
output
1
22,412
7
44,825
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. User ainta has a stack of n red and blue balls. He can apply a certain operation which changes the colors of the balls inside the stack. * While the top ball inside the stack is red, pop the ball from the top of the stack. * Then replace the blue ball on the top with a red ball. * And finally push some blue balls to the stack until the stack has total of n balls inside. If there are no blue balls inside the stack, ainta can't apply this operation. Given the initial state of the stack, ainta wants to know the maximum number of operations he can repeatedly apply. Input The first line contains an integer n (1 ≤ n ≤ 50) — the number of balls inside the stack. The second line contains a string s (|s| = n) describing the initial state of the stack. The i-th character of the string s denotes the color of the i-th ball (we'll number the balls from top to bottom of the stack). If the character is "R", the color is red. If the character is "B", the color is blue. Output Print the maximum number of operations ainta can repeatedly apply. Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 3 RBR Output 2 Input 4 RBBR Output 6 Input 5 RBBRR Output 6 Note The first example is depicted below. The explanation how user ainta applies the first operation. He pops out one red ball, changes the color of the ball in the middle from blue to red, and pushes one blue ball. <image> The explanation how user ainta applies the second operation. He will not pop out red balls, he simply changes the color of the ball on the top from blue to red. <image> From now on, ainta can't apply any operation because there are no blue balls inside the stack. ainta applied two operations, so the answer is 2. The second example is depicted below. The blue arrow denotes a single operation. <image> Submitted Solution: ``` length, string = int(input()), input() print(sum([2 ** i if string[i] == "B" else 0 for i in range(len(string))])) ```
instruction
0
22,413
7
44,826
Yes
output
1
22,413
7
44,827
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. User ainta has a stack of n red and blue balls. He can apply a certain operation which changes the colors of the balls inside the stack. * While the top ball inside the stack is red, pop the ball from the top of the stack. * Then replace the blue ball on the top with a red ball. * And finally push some blue balls to the stack until the stack has total of n balls inside. If there are no blue balls inside the stack, ainta can't apply this operation. Given the initial state of the stack, ainta wants to know the maximum number of operations he can repeatedly apply. Input The first line contains an integer n (1 ≤ n ≤ 50) — the number of balls inside the stack. The second line contains a string s (|s| = n) describing the initial state of the stack. The i-th character of the string s denotes the color of the i-th ball (we'll number the balls from top to bottom of the stack). If the character is "R", the color is red. If the character is "B", the color is blue. Output Print the maximum number of operations ainta can repeatedly apply. Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 3 RBR Output 2 Input 4 RBBR Output 6 Input 5 RBBRR Output 6 Note The first example is depicted below. The explanation how user ainta applies the first operation. He pops out one red ball, changes the color of the ball in the middle from blue to red, and pushes one blue ball. <image> The explanation how user ainta applies the second operation. He will not pop out red balls, he simply changes the color of the ball on the top from blue to red. <image> From now on, ainta can't apply any operation because there are no blue balls inside the stack. ainta applied two operations, so the answer is 2. The second example is depicted below. The blue arrow denotes a single operation. <image> Submitted Solution: ``` n = int(input()) str = input() if(n==5): print('6') else: stack = [] for i in range(n): stack.append(str[i]) sum = 0 while(stack.count('B')>0): sum+=1 i = n-1 while(stack[i]=='R'): del stack[i] i-=1 stack[i]='R' while(len(stack)!=n): stack.append('B') print(sum) ```
instruction
0
22,414
7
44,828
No
output
1
22,414
7
44,829
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. User ainta has a stack of n red and blue balls. He can apply a certain operation which changes the colors of the balls inside the stack. * While the top ball inside the stack is red, pop the ball from the top of the stack. * Then replace the blue ball on the top with a red ball. * And finally push some blue balls to the stack until the stack has total of n balls inside. If there are no blue balls inside the stack, ainta can't apply this operation. Given the initial state of the stack, ainta wants to know the maximum number of operations he can repeatedly apply. Input The first line contains an integer n (1 ≤ n ≤ 50) — the number of balls inside the stack. The second line contains a string s (|s| = n) describing the initial state of the stack. The i-th character of the string s denotes the color of the i-th ball (we'll number the balls from top to bottom of the stack). If the character is "R", the color is red. If the character is "B", the color is blue. Output Print the maximum number of operations ainta can repeatedly apply. Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 3 RBR Output 2 Input 4 RBBR Output 6 Input 5 RBBRR Output 6 Note The first example is depicted below. The explanation how user ainta applies the first operation. He pops out one red ball, changes the color of the ball in the middle from blue to red, and pushes one blue ball. <image> The explanation how user ainta applies the second operation. He will not pop out red balls, he simply changes the color of the ball on the top from blue to red. <image> From now on, ainta can't apply any operation because there are no blue balls inside the stack. ainta applied two operations, so the answer is 2. The second example is depicted below. The blue arrow denotes a single operation. <image> Submitted Solution: ``` n = int(input()) s = input() res = 0 l1 = [1] l2 = [1] res = 0 for i in range(1,n): l1.append(l2[i-1]+1) l2.append(l2[i-1]+l1[i]) if(s[i-1] == 'B'): res += l1[i-1] #print(l1) print(res) ```
instruction
0
22,415
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No
output
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22,415
7
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. User ainta has a stack of n red and blue balls. He can apply a certain operation which changes the colors of the balls inside the stack. * While the top ball inside the stack is red, pop the ball from the top of the stack. * Then replace the blue ball on the top with a red ball. * And finally push some blue balls to the stack until the stack has total of n balls inside. If there are no blue balls inside the stack, ainta can't apply this operation. Given the initial state of the stack, ainta wants to know the maximum number of operations he can repeatedly apply. Input The first line contains an integer n (1 ≤ n ≤ 50) — the number of balls inside the stack. The second line contains a string s (|s| = n) describing the initial state of the stack. The i-th character of the string s denotes the color of the i-th ball (we'll number the balls from top to bottom of the stack). If the character is "R", the color is red. If the character is "B", the color is blue. Output Print the maximum number of operations ainta can repeatedly apply. Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 3 RBR Output 2 Input 4 RBBR Output 6 Input 5 RBBRR Output 6 Note The first example is depicted below. The explanation how user ainta applies the first operation. He pops out one red ball, changes the color of the ball in the middle from blue to red, and pushes one blue ball. <image> The explanation how user ainta applies the second operation. He will not pop out red balls, he simply changes the color of the ball on the top from blue to red. <image> From now on, ainta can't apply any operation because there are no blue balls inside the stack. ainta applied two operations, so the answer is 2. The second example is depicted below. The blue arrow denotes a single operation. <image> Submitted Solution: ``` n = int(input()) str = input() stack = [] for i in range(n): stack.append(str[i]) sum = 0 while(stack.count('B')>0): sum+=1 i = n-1 while(stack[i]=='R'): del stack[i] i-=1 stack[i]='R' while(len(stack)!=n): stack.append('B') print(sum) ```
instruction
0
22,416
7
44,832
No
output
1
22,416
7
44,833
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. User ainta has a stack of n red and blue balls. He can apply a certain operation which changes the colors of the balls inside the stack. * While the top ball inside the stack is red, pop the ball from the top of the stack. * Then replace the blue ball on the top with a red ball. * And finally push some blue balls to the stack until the stack has total of n balls inside. If there are no blue balls inside the stack, ainta can't apply this operation. Given the initial state of the stack, ainta wants to know the maximum number of operations he can repeatedly apply. Input The first line contains an integer n (1 ≤ n ≤ 50) — the number of balls inside the stack. The second line contains a string s (|s| = n) describing the initial state of the stack. The i-th character of the string s denotes the color of the i-th ball (we'll number the balls from top to bottom of the stack). If the character is "R", the color is red. If the character is "B", the color is blue. Output Print the maximum number of operations ainta can repeatedly apply. Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 3 RBR Output 2 Input 4 RBBR Output 6 Input 5 RBBRR Output 6 Note The first example is depicted below. The explanation how user ainta applies the first operation. He pops out one red ball, changes the color of the ball in the middle from blue to red, and pushes one blue ball. <image> The explanation how user ainta applies the second operation. He will not pop out red balls, he simply changes the color of the ball on the top from blue to red. <image> From now on, ainta can't apply any operation because there are no blue balls inside the stack. ainta applied two operations, so the answer is 2. The second example is depicted below. The blue arrow denotes a single operation. <image> Submitted Solution: ``` n = int(input()) s = input().strip() op_cnt = 0 while s.find('B') >= 0: while s[0] == 'R': s = s[1:] #print(s) if s[0] == 'B': s = 'R' + s[1:] #print(s) if len(s) < n: s = 'B'*(n-len(s)) + s #print(s) op_cnt += 1 if op_cnt > 8: break print(op_cnt) ```
instruction
0
22,417
7
44,834
No
output
1
22,417
7
44,835
Provide a correct Python 3 solution for this coding contest problem. We have a chocolate bar partitioned into H horizontal rows and W vertical columns of squares. The square (i, j) at the i-th row from the top and the j-th column from the left is dark if S_{i,j} is `0`, and white if S_{i,j} is `1`. We will cut the bar some number of times to divide it into some number of blocks. In each cut, we cut the whole bar by a line running along some boundaries of squares from end to end of the bar. How many times do we need to cut the bar so that every block after the cuts has K or less white squares? Constraints * 1 \leq H \leq 10 * 1 \leq W \leq 1000 * 1 \leq K \leq H \times W * S_{i,j} is `0` or `1`. Input Input is given from Standard Input in the following format: H W K S_{1,1}S_{1,2}...S_{1,W} : S_{H,1}S_{H,2}...S_{H,W} Output Print the number of minimum times the bar needs to be cut so that every block after the cuts has K or less white squares. Examples Input 3 5 4 11100 10001 00111 Output 2 Input 3 5 8 11100 10001 00111 Output 0 Input 4 10 4 1110010010 1000101110 0011101001 1101000111 Output 3
instruction
0
22,618
7
45,236
"Correct Solution: ``` h, w, k = map(int, input().split()) S = [[int(s) for s in list(input())] for i in range(h)] ans = 10**4 for b in range(2**(h-1)): cnt = bin(b).count('1') B = format(b, 'b').zfill(h-1)+'1' T = [[0]*w for i in range(cnt+1)] for j in range(w): t, c = 0, 0 for i in range(h): t += S[i][j] if B[i] == '1': T[c][j] += t t = 0 c += 1 if max([max(T[i]) for i in range(cnt+1)]) > k: continue A = [T[i][0] for i in range(cnt+1)] tmp = cnt for j in range(1, w): A = [A[i]+T[i][j] for i in range(cnt+1)] if any([a > k for a in A]): A = [T[i][j] for i in range(cnt+1)] tmp += 1 ans = min(ans, tmp) print(ans) ```
output
1
22,618
7
45,237
Provide a correct Python 3 solution for this coding contest problem. We have a chocolate bar partitioned into H horizontal rows and W vertical columns of squares. The square (i, j) at the i-th row from the top and the j-th column from the left is dark if S_{i,j} is `0`, and white if S_{i,j} is `1`. We will cut the bar some number of times to divide it into some number of blocks. In each cut, we cut the whole bar by a line running along some boundaries of squares from end to end of the bar. How many times do we need to cut the bar so that every block after the cuts has K or less white squares? Constraints * 1 \leq H \leq 10 * 1 \leq W \leq 1000 * 1 \leq K \leq H \times W * S_{i,j} is `0` or `1`. Input Input is given from Standard Input in the following format: H W K S_{1,1}S_{1,2}...S_{1,W} : S_{H,1}S_{H,2}...S_{H,W} Output Print the number of minimum times the bar needs to be cut so that every block after the cuts has K or less white squares. Examples Input 3 5 4 11100 10001 00111 Output 2 Input 3 5 8 11100 10001 00111 Output 0 Input 4 10 4 1110010010 1000101110 0011101001 1101000111 Output 3
instruction
0
22,619
7
45,238
"Correct Solution: ``` import itertools h, w, k = map(int, input().split()) a = [] for i in range(h): s = input() a.append(s) s = [[0 for i in range(w)] for i in range(h)] ans = h+w for grid in itertools.product([0,1], repeat=h-1): ary = [[0]] for i in range(h-1): if grid[i] == 1: ary.append([i+1]) else: ary[-1].append(i+1) # print (grid, ary) wk = 0 for i in grid: if i == 1: wk += 1 # print (wk) cnt = [0] * len(ary) for j in range(w): for ii, g in enumerate(ary): for b in g: if a[b][j] == '1': cnt[ii] += 1 if any(W > k for W in cnt): wk += 1 cnt = [0] * len(ary) for ii, g in enumerate(ary): for jj in g: if a[jj][j] == '1': cnt[ii] += 1 if any(W > k for W in cnt): wk = h+w break ans = min(ans, wk) print (ans) ```
output
1
22,619
7
45,239
Provide a correct Python 3 solution for this coding contest problem. We have a chocolate bar partitioned into H horizontal rows and W vertical columns of squares. The square (i, j) at the i-th row from the top and the j-th column from the left is dark if S_{i,j} is `0`, and white if S_{i,j} is `1`. We will cut the bar some number of times to divide it into some number of blocks. In each cut, we cut the whole bar by a line running along some boundaries of squares from end to end of the bar. How many times do we need to cut the bar so that every block after the cuts has K or less white squares? Constraints * 1 \leq H \leq 10 * 1 \leq W \leq 1000 * 1 \leq K \leq H \times W * S_{i,j} is `0` or `1`. Input Input is given from Standard Input in the following format: H W K S_{1,1}S_{1,2}...S_{1,W} : S_{H,1}S_{H,2}...S_{H,W} Output Print the number of minimum times the bar needs to be cut so that every block after the cuts has K or less white squares. Examples Input 3 5 4 11100 10001 00111 Output 2 Input 3 5 8 11100 10001 00111 Output 0 Input 4 10 4 1110010010 1000101110 0011101001 1101000111 Output 3
instruction
0
22,620
7
45,240
"Correct Solution: ``` from collections import defaultdict from itertools import product H, W, K = map(int, input().split()) S = [input() for _ in range(H)] i = 0 while i < len(S): if '1' in S[i]: i += 1 else: del S[i] H = len(S) C = [[int(s[i]) for s in S] for i in range(W)] total = sum(sum(c) for c in C) if total <= K: answer = 0 else: answer = H * W for X in product([False, True], repeat=H-1): ans = sum(X) if ans > answer: continue M = [[0]] for i, x in enumerate(X): if x: M.append([]) M[-1].append(i+1) D = [0] * len(M) for c in C: for k, m in enumerate(M): D[k] += sum(c[i] for i in m) if any(d > K for d in D): ans += 1 if ans > answer: break D = [sum(c[i] for i in m) for m in M] if any(d > K for d in D): ans = answer + 1 break answer = min(answer, ans) print(answer) ```
output
1
22,620
7
45,241
Provide a correct Python 3 solution for this coding contest problem. We have a chocolate bar partitioned into H horizontal rows and W vertical columns of squares. The square (i, j) at the i-th row from the top and the j-th column from the left is dark if S_{i,j} is `0`, and white if S_{i,j} is `1`. We will cut the bar some number of times to divide it into some number of blocks. In each cut, we cut the whole bar by a line running along some boundaries of squares from end to end of the bar. How many times do we need to cut the bar so that every block after the cuts has K or less white squares? Constraints * 1 \leq H \leq 10 * 1 \leq W \leq 1000 * 1 \leq K \leq H \times W * S_{i,j} is `0` or `1`. Input Input is given from Standard Input in the following format: H W K S_{1,1}S_{1,2}...S_{1,W} : S_{H,1}S_{H,2}...S_{H,W} Output Print the number of minimum times the bar needs to be cut so that every block after the cuts has K or less white squares. Examples Input 3 5 4 11100 10001 00111 Output 2 Input 3 5 8 11100 10001 00111 Output 0 Input 4 10 4 1110010010 1000101110 0011101001 1101000111 Output 3
instruction
0
22,621
7
45,242
"Correct Solution: ``` h, w, k = map(int, input().split()) S = [list(map(int, list(input()))) for _ in range(h)] ans = float("inf") for i in range(2**(h-1)): L = [0] cnt = 0 for j in range(h-1): if i>>j & 1: L.append(j+1) cnt += 1 L.append(h) C = [0]*(len(L)-1) for j in range(w): D = [0]*(len(L)-1) for l in range(len(L)-1): a, b = L[l], L[l+1] for s in range(a, b): D[l] += S[s][j] if max(D) > k: break for l, d in enumerate(D): if C[l]+d > k: break else: for l, d in enumerate(D): C[l] += d continue cnt += 1 for l, d in enumerate(D): C[l] = d else: ans = min(ans, cnt) print(ans) ```
output
1
22,621
7
45,243
Provide a correct Python 3 solution for this coding contest problem. We have a chocolate bar partitioned into H horizontal rows and W vertical columns of squares. The square (i, j) at the i-th row from the top and the j-th column from the left is dark if S_{i,j} is `0`, and white if S_{i,j} is `1`. We will cut the bar some number of times to divide it into some number of blocks. In each cut, we cut the whole bar by a line running along some boundaries of squares from end to end of the bar. How many times do we need to cut the bar so that every block after the cuts has K or less white squares? Constraints * 1 \leq H \leq 10 * 1 \leq W \leq 1000 * 1 \leq K \leq H \times W * S_{i,j} is `0` or `1`. Input Input is given from Standard Input in the following format: H W K S_{1,1}S_{1,2}...S_{1,W} : S_{H,1}S_{H,2}...S_{H,W} Output Print the number of minimum times the bar needs to be cut so that every block after the cuts has K or less white squares. Examples Input 3 5 4 11100 10001 00111 Output 2 Input 3 5 8 11100 10001 00111 Output 0 Input 4 10 4 1110010010 1000101110 0011101001 1101000111 Output 3
instruction
0
22,622
7
45,244
"Correct Solution: ``` H,W,K = map(int,input().split()) S = [list(map(int,input())) for _ in [0]*H] ans = H*W S2 = [[0]*(W+1) for _ in [0]*(H+1)] for i in range(H): for j in range(W): S2[i+1][j+1] = S2[i][j+1] + S[i][j] for i in range(1,H+1): for j in range(W): S2[i][j+1] += S2[i][j] for i in range(1<<(H-1)): check = [0]+[j+1 for j in range(H-1) if i>>j&1]+[H] cnt = len(check)-2 l = 0 r = 1 while r<=W: for j,k in zip(check[:-1],check[1:]): if S2[j][l] + S2[k][r] - S2[j][r] - S2[k][l] > K: if r==l+1: cnt += H*W r = W+1 break cnt += 1 l = r-1 r = r break else: r += 1 ans = min(ans,cnt) print(ans) ```
output
1
22,622
7
45,245
Provide a correct Python 3 solution for this coding contest problem. We have a chocolate bar partitioned into H horizontal rows and W vertical columns of squares. The square (i, j) at the i-th row from the top and the j-th column from the left is dark if S_{i,j} is `0`, and white if S_{i,j} is `1`. We will cut the bar some number of times to divide it into some number of blocks. In each cut, we cut the whole bar by a line running along some boundaries of squares from end to end of the bar. How many times do we need to cut the bar so that every block after the cuts has K or less white squares? Constraints * 1 \leq H \leq 10 * 1 \leq W \leq 1000 * 1 \leq K \leq H \times W * S_{i,j} is `0` or `1`. Input Input is given from Standard Input in the following format: H W K S_{1,1}S_{1,2}...S_{1,W} : S_{H,1}S_{H,2}...S_{H,W} Output Print the number of minimum times the bar needs to be cut so that every block after the cuts has K or less white squares. Examples Input 3 5 4 11100 10001 00111 Output 2 Input 3 5 8 11100 10001 00111 Output 0 Input 4 10 4 1110010010 1000101110 0011101001 1101000111 Output 3
instruction
0
22,623
7
45,246
"Correct Solution: ``` H,W,K=map(int,input().split()) S=[list(map(int,list(input()))) for i in range(H)] ans=H+W-2 for bit in range(2**(H-1)): divH=[0] for j in range(H-1): if(bit>>j&1): divH.append(j+1) divH.append(H) glen=len(divH)-1 group=[0]*(glen) res=glen-1 go=True w=0 while w<W: ok=True c=[0]*(glen) for g in range(glen): cum=0 for h in range(divH[g],divH[g+1]): cum+=S[h][w] c[g]+=cum if cum>K: go=False break if c[g]+group[g]>K: ok=False if not go: break if not ok: res+=1 group=[0]*glen else: for i in range(glen): group[i]+=c[i] w+=1 if not go: continue ans=min(ans,res) print(ans) ```
output
1
22,623
7
45,247
Provide a correct Python 3 solution for this coding contest problem. We have a chocolate bar partitioned into H horizontal rows and W vertical columns of squares. The square (i, j) at the i-th row from the top and the j-th column from the left is dark if S_{i,j} is `0`, and white if S_{i,j} is `1`. We will cut the bar some number of times to divide it into some number of blocks. In each cut, we cut the whole bar by a line running along some boundaries of squares from end to end of the bar. How many times do we need to cut the bar so that every block after the cuts has K or less white squares? Constraints * 1 \leq H \leq 10 * 1 \leq W \leq 1000 * 1 \leq K \leq H \times W * S_{i,j} is `0` or `1`. Input Input is given from Standard Input in the following format: H W K S_{1,1}S_{1,2}...S_{1,W} : S_{H,1}S_{H,2}...S_{H,W} Output Print the number of minimum times the bar needs to be cut so that every block after the cuts has K or less white squares. Examples Input 3 5 4 11100 10001 00111 Output 2 Input 3 5 8 11100 10001 00111 Output 0 Input 4 10 4 1110010010 1000101110 0011101001 1101000111 Output 3
instruction
0
22,624
7
45,248
"Correct Solution: ``` from itertools import combinations H, W, K = map(int, input().split()) S = [input() for _ in range(H)] C = [[0] * (W + 1) for _ in range(H + 1)] for h in range(H): wc = 0 for w in range(W): wc += (S[h][w] == '1') C[h + 1][w + 1] = C[h][w + 1] + wc ans = 2000 for cuth in range(H): for comb in combinations([h for h in range(1, H)], cuth): comb = [0] + list(comb) + [H] wi, cutw = 0, 0 for w in range(W): if max([C[comb[i]][w + 1] - C[comb[i]][wi] - C[comb[i - 1]][w + 1] + C[comb[i - 1]][wi] for i in range(1, len(comb))]) > K: if wi == w: cutw = 2000 wi, cutw = w, cutw + 1 ans = min(ans, cuth + cutw) print(ans) ```
output
1
22,624
7
45,249
Provide tags and a correct Python 3 solution for this coding contest problem. Once Bob took a paper stripe of n squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece, and each piece contains positive integer amount of squares. Would you help Bob solve this problem? Input The first input line contains integer n (1 ≤ n ≤ 105) — amount of squares in the stripe. The second line contains n space-separated numbers — they are the numbers written in the squares of the stripe. These numbers are integer and do not exceed 10000 in absolute value. Output Output the amount of ways to cut the stripe into two non-empty pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece. Don't forget that it's allowed to cut the stripe along the squares' borders only. Examples Input 9 1 5 -6 7 9 -16 0 -2 2 Output 3 Input 3 1 1 1 Output 0 Input 2 0 0 Output 1
instruction
0
23,114
7
46,228
Tags: data structures, implementation Correct Solution: ``` n = int(input()) squares = [ int(x) for x in input().split() ] result = 0 soma = sum(squares) if soma % 2 == 0: parcial = 0 soma //= 2 for i in squares: parcial += i if parcial == soma: result += 1 if parcial == soma: result -= 1 print(result) ```
output
1
23,114
7
46,229
Provide tags and a correct Python 3 solution for this coding contest problem. Once Bob took a paper stripe of n squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece, and each piece contains positive integer amount of squares. Would you help Bob solve this problem? Input The first input line contains integer n (1 ≤ n ≤ 105) — amount of squares in the stripe. The second line contains n space-separated numbers — they are the numbers written in the squares of the stripe. These numbers are integer and do not exceed 10000 in absolute value. Output Output the amount of ways to cut the stripe into two non-empty pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece. Don't forget that it's allowed to cut the stripe along the squares' borders only. Examples Input 9 1 5 -6 7 9 -16 0 -2 2 Output 3 Input 3 1 1 1 Output 0 Input 2 0 0 Output 1
instruction
0
23,115
7
46,230
Tags: data structures, implementation Correct Solution: ``` n = int(input()) stripes = list(map(int, input().split(" "))) total = sum(stripes) leftSum = 0 ways = 0 for i in range(n-1): leftSum = leftSum + stripes[i] if(2*leftSum == total): ways = ways + 1 print(ways) ```
output
1
23,115
7
46,231
Provide tags and a correct Python 3 solution for this coding contest problem. Once Bob took a paper stripe of n squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece, and each piece contains positive integer amount of squares. Would you help Bob solve this problem? Input The first input line contains integer n (1 ≤ n ≤ 105) — amount of squares in the stripe. The second line contains n space-separated numbers — they are the numbers written in the squares of the stripe. These numbers are integer and do not exceed 10000 in absolute value. Output Output the amount of ways to cut the stripe into two non-empty pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece. Don't forget that it's allowed to cut the stripe along the squares' borders only. Examples Input 9 1 5 -6 7 9 -16 0 -2 2 Output 3 Input 3 1 1 1 Output 0 Input 2 0 0 Output 1
instruction
0
23,116
7
46,232
Tags: data structures, implementation Correct Solution: ``` n=int(input()) a = list(map(int, input().strip().split(' '))) s=sum(a) k=0 c=0 for i in range(n-1): k+=a[i] s-=a[i] if k==s: c+=1 print(c) ```
output
1
23,116
7
46,233
Provide tags and a correct Python 3 solution for this coding contest problem. Once Bob took a paper stripe of n squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece, and each piece contains positive integer amount of squares. Would you help Bob solve this problem? Input The first input line contains integer n (1 ≤ n ≤ 105) — amount of squares in the stripe. The second line contains n space-separated numbers — they are the numbers written in the squares of the stripe. These numbers are integer and do not exceed 10000 in absolute value. Output Output the amount of ways to cut the stripe into two non-empty pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece. Don't forget that it's allowed to cut the stripe along the squares' borders only. Examples Input 9 1 5 -6 7 9 -16 0 -2 2 Output 3 Input 3 1 1 1 Output 0 Input 2 0 0 Output 1
instruction
0
23,117
7
46,234
Tags: data structures, implementation Correct Solution: ``` n = int(input()) stripe = list(map(int, input().split())) count = 0 left = 0 right = sum(stripe) for s in stripe[:-1]: left += s right -= s if left == right: count += 1 print(count) ```
output
1
23,117
7
46,235
Provide tags and a correct Python 3 solution for this coding contest problem. Once Bob took a paper stripe of n squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece, and each piece contains positive integer amount of squares. Would you help Bob solve this problem? Input The first input line contains integer n (1 ≤ n ≤ 105) — amount of squares in the stripe. The second line contains n space-separated numbers — they are the numbers written in the squares of the stripe. These numbers are integer and do not exceed 10000 in absolute value. Output Output the amount of ways to cut the stripe into two non-empty pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece. Don't forget that it's allowed to cut the stripe along the squares' borders only. Examples Input 9 1 5 -6 7 9 -16 0 -2 2 Output 3 Input 3 1 1 1 Output 0 Input 2 0 0 Output 1
instruction
0
23,118
7
46,236
Tags: data structures, implementation Correct Solution: ``` n = int(input()) v = list(map(int, input().split())) s1 = 0 s2 = sum(v) c = 0 for i in range(n-1): s1 += v[i] s2 -= v[i] if(s1 == s2): c += 1 print(c) ```
output
1
23,118
7
46,237
Provide tags and a correct Python 3 solution for this coding contest problem. Once Bob took a paper stripe of n squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece, and each piece contains positive integer amount of squares. Would you help Bob solve this problem? Input The first input line contains integer n (1 ≤ n ≤ 105) — amount of squares in the stripe. The second line contains n space-separated numbers — they are the numbers written in the squares of the stripe. These numbers are integer and do not exceed 10000 in absolute value. Output Output the amount of ways to cut the stripe into two non-empty pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece. Don't forget that it's allowed to cut the stripe along the squares' borders only. Examples Input 9 1 5 -6 7 9 -16 0 -2 2 Output 3 Input 3 1 1 1 Output 0 Input 2 0 0 Output 1
instruction
0
23,119
7
46,238
Tags: data structures, implementation Correct Solution: ``` n=eval(input()) temp=input() a=temp.split() total=0 temptotal=0 count=0 for i in range(len(a)): total+=int(a[i]) for i in range(len(a)-1): temptotal+=int(a[i]) if temptotal*2==total: count+=1 print(count) ```
output
1
23,119
7
46,239
Provide tags and a correct Python 3 solution for this coding contest problem. Once Bob took a paper stripe of n squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece, and each piece contains positive integer amount of squares. Would you help Bob solve this problem? Input The first input line contains integer n (1 ≤ n ≤ 105) — amount of squares in the stripe. The second line contains n space-separated numbers — they are the numbers written in the squares of the stripe. These numbers are integer and do not exceed 10000 in absolute value. Output Output the amount of ways to cut the stripe into two non-empty pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece. Don't forget that it's allowed to cut the stripe along the squares' borders only. Examples Input 9 1 5 -6 7 9 -16 0 -2 2 Output 3 Input 3 1 1 1 Output 0 Input 2 0 0 Output 1
instruction
0
23,120
7
46,240
Tags: data structures, implementation Correct Solution: ``` from itertools import accumulate, islice n = int(input()) a = list(map(int, input().split())) S = sum(a) print(sum(S == 2*x for x in islice(accumulate(a), n-1))) ```
output
1
23,120
7
46,241
Provide tags and a correct Python 3 solution for this coding contest problem. Once Bob took a paper stripe of n squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece, and each piece contains positive integer amount of squares. Would you help Bob solve this problem? Input The first input line contains integer n (1 ≤ n ≤ 105) — amount of squares in the stripe. The second line contains n space-separated numbers — they are the numbers written in the squares of the stripe. These numbers are integer and do not exceed 10000 in absolute value. Output Output the amount of ways to cut the stripe into two non-empty pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece. Don't forget that it's allowed to cut the stripe along the squares' borders only. Examples Input 9 1 5 -6 7 9 -16 0 -2 2 Output 3 Input 3 1 1 1 Output 0 Input 2 0 0 Output 1
instruction
0
23,121
7
46,242
Tags: data structures, implementation Correct Solution: ``` n = int(input()) sq = [int(i) for i in input().split(" ")] ways = 0 soma1anterior = 0 soma2anterior = sum(sq[1:n]) + sq[0] count = 0 for i in range(0, n - 1): s1 = soma1anterior + sq[i] s2 = soma2anterior - sq[i] if s1 == s2: ways += 1 soma1anterior = s1 soma2anterior = s2 print(ways) ```
output
1
23,121
7
46,243
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Once Bob took a paper stripe of n squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece, and each piece contains positive integer amount of squares. Would you help Bob solve this problem? Input The first input line contains integer n (1 ≤ n ≤ 105) — amount of squares in the stripe. The second line contains n space-separated numbers — they are the numbers written in the squares of the stripe. These numbers are integer and do not exceed 10000 in absolute value. Output Output the amount of ways to cut the stripe into two non-empty pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece. Don't forget that it's allowed to cut the stripe along the squares' borders only. Examples Input 9 1 5 -6 7 9 -16 0 -2 2 Output 3 Input 3 1 1 1 Output 0 Input 2 0 0 Output 1 Submitted Solution: ``` class Stripe: @staticmethod def read_input(): num_squares = input('') numbers = list(map(int, input('').split())) return numbers @staticmethod def run(): left, right = set(), set() numbers = Stripe.read_input() sum_left = 0 sum_right = sum(numbers) num_equals = 0 for i in range(0, len(numbers)-1): sum_left += numbers[i] sum_right -= numbers[i] if sum_left == sum_right: num_equals += 1 print(num_equals) if __name__ == "__main__": Stripe.run() ```
instruction
0
23,122
7
46,244
Yes
output
1
23,122
7
46,245
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Once Bob took a paper stripe of n squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece, and each piece contains positive integer amount of squares. Would you help Bob solve this problem? Input The first input line contains integer n (1 ≤ n ≤ 105) — amount of squares in the stripe. The second line contains n space-separated numbers — they are the numbers written in the squares of the stripe. These numbers are integer and do not exceed 10000 in absolute value. Output Output the amount of ways to cut the stripe into two non-empty pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece. Don't forget that it's allowed to cut the stripe along the squares' borders only. Examples Input 9 1 5 -6 7 9 -16 0 -2 2 Output 3 Input 3 1 1 1 Output 0 Input 2 0 0 Output 1 Submitted Solution: ``` n=int(input()) c=0 l=[int(i) for i in input().split()] pre=[0]*(n+1) for i in range(1,n+1): pre[i]=pre[i-1]+l[i-1] for i in range(1,n): if pre[i]==(pre[n]-pre[i]): c+=1 print(c) ```
instruction
0
23,123
7
46,246
Yes
output
1
23,123
7
46,247
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Once Bob took a paper stripe of n squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece, and each piece contains positive integer amount of squares. Would you help Bob solve this problem? Input The first input line contains integer n (1 ≤ n ≤ 105) — amount of squares in the stripe. The second line contains n space-separated numbers — they are the numbers written in the squares of the stripe. These numbers are integer and do not exceed 10000 in absolute value. Output Output the amount of ways to cut the stripe into two non-empty pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece. Don't forget that it's allowed to cut the stripe along the squares' borders only. Examples Input 9 1 5 -6 7 9 -16 0 -2 2 Output 3 Input 3 1 1 1 Output 0 Input 2 0 0 Output 1 Submitted Solution: ``` import sys,math as mt I=lambda:list(map(int,input().split())) n,=I() l=[0]+I() ans=0 for i in range(1,n+1): l[i]+=l[i-1] tot=l[-1] for i in range(1,n): if l[i]==tot-l[i]: ans+=1 print(ans) ```
instruction
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Yes
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Once Bob took a paper stripe of n squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece, and each piece contains positive integer amount of squares. Would you help Bob solve this problem? Input The first input line contains integer n (1 ≤ n ≤ 105) — amount of squares in the stripe. The second line contains n space-separated numbers — they are the numbers written in the squares of the stripe. These numbers are integer and do not exceed 10000 in absolute value. Output Output the amount of ways to cut the stripe into two non-empty pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece. Don't forget that it's allowed to cut the stripe along the squares' borders only. Examples Input 9 1 5 -6 7 9 -16 0 -2 2 Output 3 Input 3 1 1 1 Output 0 Input 2 0 0 Output 1 Submitted Solution: ``` import os import sys from io import BytesIO, IOBase def main(): pass # region fastio BUFSIZE = 8192 class FastIO(IOBase): newlines = 0 def __init__(self, file): self._fd = file.fileno() self.buffer = BytesIO() self.writable = "x" in file.mode or "r" not in file.mode self.write = self.buffer.write if self.writable else None def read(self): while True: b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE)) if not b: break ptr = self.buffer.tell() self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr) self.newlines = 0 return self.buffer.read() def readline(self): while self.newlines == 0: b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE)) self.newlines = b.count(b"\n") + (not b) ptr = self.buffer.tell() self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr) self.newlines -= 1 return self.buffer.readline() def flush(self): if self.writable: os.write(self._fd, self.buffer.getvalue()) self.buffer.truncate(0), self.buffer.seek(0) class IOWrapper(IOBase): def __init__(self, file): self.buffer = FastIO(file) self.flush = self.buffer.flush self.writable = self.buffer.writable self.write = lambda s: self.buffer.write(s.encode("ascii")) self.read = lambda: self.buffer.read().decode("ascii") self.readline = lambda: self.buffer.readline().decode("ascii") sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout) input = lambda: sys.stdin.readline().rstrip("\r\n") def count1(s): c=0 for i in s: if(i=='1'): c+=1 return(c) def binary(n): return(bin(n).replace("0b","")) def decimal(s): return(int(s,2)) def pow2(n): p=0 while(n>1): n//=2 p+=1 return(p) def isPrime(n): if(n==1): return(False) else: root=int(n**0.5) root+=1 for i in range(2,root): if(n%i==0): return(False) return(True) n=int(input()) l=list(map(int,input().split())) s=sum(l) ls=0 a=0 for i in range(0,n-1): ls+=l[i] if(ls==s-ls): a+=1 print(a) ```
instruction
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Yes
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Once Bob took a paper stripe of n squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece, and each piece contains positive integer amount of squares. Would you help Bob solve this problem? Input The first input line contains integer n (1 ≤ n ≤ 105) — amount of squares in the stripe. The second line contains n space-separated numbers — they are the numbers written in the squares of the stripe. These numbers are integer and do not exceed 10000 in absolute value. Output Output the amount of ways to cut the stripe into two non-empty pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece. Don't forget that it's allowed to cut the stripe along the squares' borders only. Examples Input 9 1 5 -6 7 9 -16 0 -2 2 Output 3 Input 3 1 1 1 Output 0 Input 2 0 0 Output 1 Submitted Solution: ``` x = int(input("square")) y = input("number").split(" ") z = [] for i in y: z.append(int(i)) count = 0 for i in range(1,len(z)): if sum(z[:i])==sum(z[-(len(z)-i):]): count+=1 print(count) ```
instruction
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No
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Once Bob took a paper stripe of n squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece, and each piece contains positive integer amount of squares. Would you help Bob solve this problem? Input The first input line contains integer n (1 ≤ n ≤ 105) — amount of squares in the stripe. The second line contains n space-separated numbers — they are the numbers written in the squares of the stripe. These numbers are integer and do not exceed 10000 in absolute value. Output Output the amount of ways to cut the stripe into two non-empty pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece. Don't forget that it's allowed to cut the stripe along the squares' borders only. Examples Input 9 1 5 -6 7 9 -16 0 -2 2 Output 3 Input 3 1 1 1 Output 0 Input 2 0 0 Output 1 Submitted Solution: ``` n = int(input()) numbers = [] [numbers.append(int(i)) for i in input().split()] count, soma = 0, 0 totalSum = sum(numbers) for i in range(n - 1): soma = soma + numbers[i] print(soma) if soma * 2 == totalSum: count = count + 1 print(count) ```
instruction
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46,254
No
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7
46,255
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Once Bob took a paper stripe of n squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece, and each piece contains positive integer amount of squares. Would you help Bob solve this problem? Input The first input line contains integer n (1 ≤ n ≤ 105) — amount of squares in the stripe. The second line contains n space-separated numbers — they are the numbers written in the squares of the stripe. These numbers are integer and do not exceed 10000 in absolute value. Output Output the amount of ways to cut the stripe into two non-empty pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece. Don't forget that it's allowed to cut the stripe along the squares' borders only. Examples Input 9 1 5 -6 7 9 -16 0 -2 2 Output 3 Input 3 1 1 1 Output 0 Input 2 0 0 Output 1 Submitted Solution: ``` k = int(input()) sum_array= [] b= 0 for i in input().split(): sum_array.append(b+int(i)) b+= int(i) max= sum_array[-1] print(max) if max % 3 != 0: print(0) quit() i=0 for b in range(1, k): if sum_array[b-1]* 3== max: for b1 in range(b+1, k): if sum_array[b1-1]== 2* sum_array[b-1]: i+= 1 b1+= 1 print(i) ```
instruction
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46,256
No
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1
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46,257
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Once Bob took a paper stripe of n squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece, and each piece contains positive integer amount of squares. Would you help Bob solve this problem? Input The first input line contains integer n (1 ≤ n ≤ 105) — amount of squares in the stripe. The second line contains n space-separated numbers — they are the numbers written in the squares of the stripe. These numbers are integer and do not exceed 10000 in absolute value. Output Output the amount of ways to cut the stripe into two non-empty pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece. Don't forget that it's allowed to cut the stripe along the squares' borders only. Examples Input 9 1 5 -6 7 9 -16 0 -2 2 Output 3 Input 3 1 1 1 Output 0 Input 2 0 0 Output 1 Submitted Solution: ``` k = int(input()) X = [] sum_array= [] b=0 for i in input().strip().split(): X.append(int(i)) b+= int(i) sum_array.append(b) max= sum_array[-1] if max % 3 != 0: print(0) quit() i=0 b=1 while b< (k-1): b1= b+ 1 if sum_array[b-1]== 0: #sum_left b+= 1 break if max / sum_array[b-1]== 3: while b1< k: if sum_array[b-1]== (sum_array[b1-1]- sum_array[b-1]): i+= 1 b1+= 1 b+= 1 print(i) ```
instruction
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No
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1
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7
46,259
Provide a correct Python 3 solution for this coding contest problem. Taro, who aims to become a web designer, is currently training. My senior at the office tells me that the background color of this page is # ffe085, which is a color number peculiar to web design, but I can't think of what kind of color it is. This color number represents the intensity of each of the three primary colors of light, red, green, and blue. Specifically, it is a combination of three 2-digit hexadecimal numbers, and when the color number is “#RGB”, R is the intensity of red, G is the intensity of green, and is the intensity of blue. .. Each value is from 00 to ff. For Taro who is not familiar with color numbers, please create a program that inputs the color number and outputs the name of the closest color from the color table. The table of colors used is as follows. | Color name | Red intensity | Green intensity | Blue intensity --- | --- | --- | --- | --- | black | 00 | 00 | 00 | blue | 00 | 00 | ff | lime | 00 | ff | 00 aqua | 00 | ff | ff | red | ff | 00 | 00 | fuchsia | ff | 00 | ff | yellow | ff | ff | 00 | white | ff | ff | ff The "closest color" is defined as follows. When the intensities of red, green, and blue at a given color number are R, G, and B, respectively, and the intensities of red, green, and blue of the kth color in the table are Rk, Gk, and Bk, respectively. The color with the smallest dk value calculated by the following formula is the closest color. <image> If there are multiple colors with the same dk value, the color at the top of the table will be the closest color. Input A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. For each dataset, a string representing the color number is given on one line in #RGB format. The number of datasets does not exceed 1000. Output Outputs the name of the closest color for each dataset on one line. Examples Input #ffe085 #787878 #decade #ff55ff 0 Output white black white fuchsia Input ffe085 787878 decade ff55ff 0 Output white black white fuchsia
instruction
0
23,724
7
47,448
"Correct Solution: ``` import math sample1 = [ [0, 0, 0], [0, 0, 255], [0, 255, 0], [0, 255, 255], [255, 0, 0], [255, 0, 255], [255, 255, 0], [255, 255, 255] ] sample2 = ['black', 'blue', 'lime', 'aqua', 'red', 'fuchsia', 'yellow', 'white'] while True: color = input() if color=='0': break Color = list(color) Color.pop(0) for i in range(6): if Color[i]=='a': Color.pop(i) Color.insert(i,10) if Color[i]=='b': Color.pop(i) Color.insert(i,11) if Color[i]=='c': Color.pop(i) Color.insert(i,12) if Color[i]=='d': Color.pop(i) Color.insert(i,13) if Color[i]=='e': Color.pop(i) Color.insert(i,14) if Color[i]=='f': Color.pop(i) Color.insert(i,15) R = int(Color[0])*16 + int(Color[1]) G = int(Color[2])*16 + int(Color[3]) B = int(Color[4])*16 + int(Color[5]) D = [] for i in range(8): d = math.sqrt( (R-sample1[i][0])**2 + (G-sample1[i][1])**2 + (B-sample1[i][2])**2 ) D.append(d) dmin = min(D) index = D.index(dmin) print(sample2[index]) ```
output
1
23,724
7
47,449
Provide a correct Python 3 solution for this coding contest problem. Taro, who aims to become a web designer, is currently training. My senior at the office tells me that the background color of this page is # ffe085, which is a color number peculiar to web design, but I can't think of what kind of color it is. This color number represents the intensity of each of the three primary colors of light, red, green, and blue. Specifically, it is a combination of three 2-digit hexadecimal numbers, and when the color number is “#RGB”, R is the intensity of red, G is the intensity of green, and is the intensity of blue. .. Each value is from 00 to ff. For Taro who is not familiar with color numbers, please create a program that inputs the color number and outputs the name of the closest color from the color table. The table of colors used is as follows. | Color name | Red intensity | Green intensity | Blue intensity --- | --- | --- | --- | --- | black | 00 | 00 | 00 | blue | 00 | 00 | ff | lime | 00 | ff | 00 aqua | 00 | ff | ff | red | ff | 00 | 00 | fuchsia | ff | 00 | ff | yellow | ff | ff | 00 | white | ff | ff | ff The "closest color" is defined as follows. When the intensities of red, green, and blue at a given color number are R, G, and B, respectively, and the intensities of red, green, and blue of the kth color in the table are Rk, Gk, and Bk, respectively. The color with the smallest dk value calculated by the following formula is the closest color. <image> If there are multiple colors with the same dk value, the color at the top of the table will be the closest color. Input A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. For each dataset, a string representing the color number is given on one line in #RGB format. The number of datasets does not exceed 1000. Output Outputs the name of the closest color for each dataset on one line. Examples Input #ffe085 #787878 #decade #ff55ff 0 Output white black white fuchsia Input ffe085 787878 decade ff55ff 0 Output white black white fuchsia
instruction
0
23,725
7
47,450
"Correct Solution: ``` # -*- coding: utf-8 -*- """ http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0176 """ import sys from sys import stdin from collections import namedtuple from math import sqrt input = stdin.readline color = namedtuple('color', ['name', 'r', 'g', 'b']) def main(args): references = [color('black', 0x00, 0x00, 0x00), color('blue', 0x00, 0x00, 0xff), color('lime', 0x00, 0xff, 0x00), color('aqua', 0x00, 0xff, 0xff), color('red', 0xff, 0x00, 0x00), color('fuchsia', 0xff, 0x00, 0xff), color('yellow', 0xff, 0xff, 0x00), color('white', 0xff, 0xff, 0xff)] while True: data = input().strip() if data[0] == '0': break my_r = int(data[1:3], 16) my_g = int(data[3:5], 16) my_b = int(data[5:7], 16) distances = [] for c in references: d = sqrt((c.r - my_r)**2 + (c.g - my_g)**2 + (c.b - my_b)**2) distances.append(d) closest_distance = min(distances) closest_color = distances.index(closest_distance) print(references[closest_color].name) if __name__ == '__main__': main(sys.argv[1:]) ```
output
1
23,725
7
47,451
Provide a correct Python 3 solution for this coding contest problem. Taro, who aims to become a web designer, is currently training. My senior at the office tells me that the background color of this page is # ffe085, which is a color number peculiar to web design, but I can't think of what kind of color it is. This color number represents the intensity of each of the three primary colors of light, red, green, and blue. Specifically, it is a combination of three 2-digit hexadecimal numbers, and when the color number is “#RGB”, R is the intensity of red, G is the intensity of green, and is the intensity of blue. .. Each value is from 00 to ff. For Taro who is not familiar with color numbers, please create a program that inputs the color number and outputs the name of the closest color from the color table. The table of colors used is as follows. | Color name | Red intensity | Green intensity | Blue intensity --- | --- | --- | --- | --- | black | 00 | 00 | 00 | blue | 00 | 00 | ff | lime | 00 | ff | 00 aqua | 00 | ff | ff | red | ff | 00 | 00 | fuchsia | ff | 00 | ff | yellow | ff | ff | 00 | white | ff | ff | ff The "closest color" is defined as follows. When the intensities of red, green, and blue at a given color number are R, G, and B, respectively, and the intensities of red, green, and blue of the kth color in the table are Rk, Gk, and Bk, respectively. The color with the smallest dk value calculated by the following formula is the closest color. <image> If there are multiple colors with the same dk value, the color at the top of the table will be the closest color. Input A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. For each dataset, a string representing the color number is given on one line in #RGB format. The number of datasets does not exceed 1000. Output Outputs the name of the closest color for each dataset on one line. Examples Input #ffe085 #787878 #decade #ff55ff 0 Output white black white fuchsia Input ffe085 787878 decade ff55ff 0 Output white black white fuchsia
instruction
0
23,726
7
47,452
"Correct Solution: ``` # Aizu Problem 0176: What Color? # import sys, math, os, bisect # read input: PYDEV = os.environ.get('PYDEV') if PYDEV=="True": sys.stdin = open("sample-input.txt", "rt") colors = {"black": "#000000", "blue": "#0000ff", "lime": "#00ff00", "aqua": "#00ffff", "red": "#ff0000", "fuchsia": "#ff00ff", "yellow": "#ffff00", "white": "#ffffff"} def distance(cc1, cc2): r1 = int(cc1[1:3], 16) r2 = int(cc2[1:3], 16) g1 = int(cc1[3:5], 16) g2 = int(cc2[3:5], 16) b1 = int(cc1[5:], 16) b2 = int(cc2[5:], 16) return math.sqrt((r1 - r2)**2 + (g1 - g2)**2 + (b1 - b2)**2) def get_color(cc): min_dist = float('Inf') for color in colors: dist = distance(cc, colors[color]) if dist < min_dist: min_dist = dist best = color return best while True: cc = input().strip() if cc[0] == '0': break print(get_color(cc)) ```
output
1
23,726
7
47,453
Provide a correct Python 3 solution for this coding contest problem. Taro, who aims to become a web designer, is currently training. My senior at the office tells me that the background color of this page is # ffe085, which is a color number peculiar to web design, but I can't think of what kind of color it is. This color number represents the intensity of each of the three primary colors of light, red, green, and blue. Specifically, it is a combination of three 2-digit hexadecimal numbers, and when the color number is “#RGB”, R is the intensity of red, G is the intensity of green, and is the intensity of blue. .. Each value is from 00 to ff. For Taro who is not familiar with color numbers, please create a program that inputs the color number and outputs the name of the closest color from the color table. The table of colors used is as follows. | Color name | Red intensity | Green intensity | Blue intensity --- | --- | --- | --- | --- | black | 00 | 00 | 00 | blue | 00 | 00 | ff | lime | 00 | ff | 00 aqua | 00 | ff | ff | red | ff | 00 | 00 | fuchsia | ff | 00 | ff | yellow | ff | ff | 00 | white | ff | ff | ff The "closest color" is defined as follows. When the intensities of red, green, and blue at a given color number are R, G, and B, respectively, and the intensities of red, green, and blue of the kth color in the table are Rk, Gk, and Bk, respectively. The color with the smallest dk value calculated by the following formula is the closest color. <image> If there are multiple colors with the same dk value, the color at the top of the table will be the closest color. Input A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. For each dataset, a string representing the color number is given on one line in #RGB format. The number of datasets does not exceed 1000. Output Outputs the name of the closest color for each dataset on one line. Examples Input #ffe085 #787878 #decade #ff55ff 0 Output white black white fuchsia Input ffe085 787878 decade ff55ff 0 Output white black white fuchsia
instruction
0
23,727
7
47,454
"Correct Solution: ``` # AOJ 0176: What Color? # Python3 2018.6.19 bal4u color = [ \ [ "black", 0, 0, 0 ], \ [ "blue", 0, 0, 0xff ], \ [ "lime", 0, 0xff, 0 ], \ [ "aqua", 0, 0xff, 0xff ], \ [ "red", 0xff, 0, 0 ], \ [ "fuchsia", 0xff, 0, 0xff ], \ [ "yellow", 0xff, 0xff, 0 ], \ [ "white", 0xff, 0xff, 0xff ]] while True: a = list(input()) if a[0] == '0': break r, g, b = int(a[1]+a[2], 16), int(a[3]+a[4], 16), int(a[5]+a[6], 16) vmin = 3* 0xff**2 for i in color: d = (r-i[1])**2 + (g-i[2])**2 + (b-i[3])**2 if d < vmin: j, vmin = i, d print(j[0]) ```
output
1
23,727
7
47,455
Provide a correct Python 3 solution for this coding contest problem. Taro, who aims to become a web designer, is currently training. My senior at the office tells me that the background color of this page is # ffe085, which is a color number peculiar to web design, but I can't think of what kind of color it is. This color number represents the intensity of each of the three primary colors of light, red, green, and blue. Specifically, it is a combination of three 2-digit hexadecimal numbers, and when the color number is “#RGB”, R is the intensity of red, G is the intensity of green, and is the intensity of blue. .. Each value is from 00 to ff. For Taro who is not familiar with color numbers, please create a program that inputs the color number and outputs the name of the closest color from the color table. The table of colors used is as follows. | Color name | Red intensity | Green intensity | Blue intensity --- | --- | --- | --- | --- | black | 00 | 00 | 00 | blue | 00 | 00 | ff | lime | 00 | ff | 00 aqua | 00 | ff | ff | red | ff | 00 | 00 | fuchsia | ff | 00 | ff | yellow | ff | ff | 00 | white | ff | ff | ff The "closest color" is defined as follows. When the intensities of red, green, and blue at a given color number are R, G, and B, respectively, and the intensities of red, green, and blue of the kth color in the table are Rk, Gk, and Bk, respectively. The color with the smallest dk value calculated by the following formula is the closest color. <image> If there are multiple colors with the same dk value, the color at the top of the table will be the closest color. Input A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. For each dataset, a string representing the color number is given on one line in #RGB format. The number of datasets does not exceed 1000. Output Outputs the name of the closest color for each dataset on one line. Examples Input #ffe085 #787878 #decade #ff55ff 0 Output white black white fuchsia Input ffe085 787878 decade ff55ff 0 Output white black white fuchsia
instruction
0
23,728
7
47,456
"Correct Solution: ``` INF = 10 ** 10 dic = {} for i in range(10): dic[str(i)] = i for i in range(ord("a"), ord("f") + 1): dic[chr(i)] = i - ord("a") + 10 def hex_to_dec(s): return dic[s[0]] * 16 + dic[s[1]] colors = [("black", list(map(hex_to_dec, ["00", "00", "00"]))), ("blue", list(map(hex_to_dec, ["00", "00", "ff"]))), ("lime", list(map(hex_to_dec, ["00", "ff", "00"]))), ("aqua", list(map(hex_to_dec, ["00", "ff", "ff"]))), ("red", list(map(hex_to_dec, ["ff", "00", "00"]))), ("fuchsia", list(map(hex_to_dec, ["ff", "00", "ff"]))), ("yellow", list(map(hex_to_dec, ["ff", "ff", "00"]))), ("white", list(map(hex_to_dec, ["ff", "ff", "ff"])))] while True: s = input() if s == "0": break r, g, b = map(hex_to_dec, [s[1:3], s[3:5], s[5:7]]) lowest_name = "KUWA" lowest_score = INF for name, rgb in colors: rc, gc, bc = rgb score = (r - rc) ** 2 + (g - gc) ** 2 + (b - bc) ** 2 if score < lowest_score: lowest_name, lowest_score = name, score print(lowest_name) ```
output
1
23,728
7
47,457
Provide a correct Python 3 solution for this coding contest problem. Taro, who aims to become a web designer, is currently training. My senior at the office tells me that the background color of this page is # ffe085, which is a color number peculiar to web design, but I can't think of what kind of color it is. This color number represents the intensity of each of the three primary colors of light, red, green, and blue. Specifically, it is a combination of three 2-digit hexadecimal numbers, and when the color number is “#RGB”, R is the intensity of red, G is the intensity of green, and is the intensity of blue. .. Each value is from 00 to ff. For Taro who is not familiar with color numbers, please create a program that inputs the color number and outputs the name of the closest color from the color table. The table of colors used is as follows. | Color name | Red intensity | Green intensity | Blue intensity --- | --- | --- | --- | --- | black | 00 | 00 | 00 | blue | 00 | 00 | ff | lime | 00 | ff | 00 aqua | 00 | ff | ff | red | ff | 00 | 00 | fuchsia | ff | 00 | ff | yellow | ff | ff | 00 | white | ff | ff | ff The "closest color" is defined as follows. When the intensities of red, green, and blue at a given color number are R, G, and B, respectively, and the intensities of red, green, and blue of the kth color in the table are Rk, Gk, and Bk, respectively. The color with the smallest dk value calculated by the following formula is the closest color. <image> If there are multiple colors with the same dk value, the color at the top of the table will be the closest color. Input A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. For each dataset, a string representing the color number is given on one line in #RGB format. The number of datasets does not exceed 1000. Output Outputs the name of the closest color for each dataset on one line. Examples Input #ffe085 #787878 #decade #ff55ff 0 Output white black white fuchsia Input ffe085 787878 decade ff55ff 0 Output white black white fuchsia
instruction
0
23,729
7
47,458
"Correct Solution: ``` from collections import OrderedDict colors = OrderedDict() colors['black'] = [0, 0, 0] colors['blue'] = [0, 0, 255] colors['lime'] = [0, 255, 0] colors['aqua'] = [0, 255, 255] colors['red'] = [255, 0, 0] colors['fuchsia'] = [255, 0, 255] colors['yellow'] = [255, 255, 0] colors['white'] = [255, 255, 255] while True: color = input() if color == '0': break r, g, b = (int(color[1:3], 16), int(color[3:5], 16), int(color[5:7], 16)) near_color = ['', float('inf')] for k, v in colors.items(): dk = ((v[0] - r) ** 2 + (v[1] - g) ** 2 + (v[2] - b) ** 2) ** .5 if dk < near_color[1]: near_color = [k, dk] print(near_color[0]) ```
output
1
23,729
7
47,459
Provide a correct Python 3 solution for this coding contest problem. Taro, who aims to become a web designer, is currently training. My senior at the office tells me that the background color of this page is # ffe085, which is a color number peculiar to web design, but I can't think of what kind of color it is. This color number represents the intensity of each of the three primary colors of light, red, green, and blue. Specifically, it is a combination of three 2-digit hexadecimal numbers, and when the color number is “#RGB”, R is the intensity of red, G is the intensity of green, and is the intensity of blue. .. Each value is from 00 to ff. For Taro who is not familiar with color numbers, please create a program that inputs the color number and outputs the name of the closest color from the color table. The table of colors used is as follows. | Color name | Red intensity | Green intensity | Blue intensity --- | --- | --- | --- | --- | black | 00 | 00 | 00 | blue | 00 | 00 | ff | lime | 00 | ff | 00 aqua | 00 | ff | ff | red | ff | 00 | 00 | fuchsia | ff | 00 | ff | yellow | ff | ff | 00 | white | ff | ff | ff The "closest color" is defined as follows. When the intensities of red, green, and blue at a given color number are R, G, and B, respectively, and the intensities of red, green, and blue of the kth color in the table are Rk, Gk, and Bk, respectively. The color with the smallest dk value calculated by the following formula is the closest color. <image> If there are multiple colors with the same dk value, the color at the top of the table will be the closest color. Input A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. For each dataset, a string representing the color number is given on one line in #RGB format. The number of datasets does not exceed 1000. Output Outputs the name of the closest color for each dataset on one line. Examples Input #ffe085 #787878 #decade #ff55ff 0 Output white black white fuchsia Input ffe085 787878 decade ff55ff 0 Output white black white fuchsia
instruction
0
23,730
7
47,460
"Correct Solution: ``` L = [ [ 0, "black", 0, 0, 0 ], [ 1, "blue", 0, 0, 255 ], [ 2, "lime", 0, 255, 0 ], [ 3, "aqua", 0, 255, 255 ], [ 4, "red", 255, 0, 0 ], [ 5, "fuchsia", 255, 0, 255 ], [ 6, "yellow", 255, 255, 0 ], [ 7, "white", 255, 255, 255 ] ] while True: T = [] s = input() if s == "0": break code = [] for i in range(3): code.append( int(s[1+2*i:3+2*i], 16) ) for i in range(len(L)): m = 0 for j in range(3): m += (L[i][2+j] - code[j])**2 T.append( [ L[i][0], m] ) T.sort(key=lambda x: (x[1], x[0])) print(L[T[0][0]][1]) ```
output
1
23,730
7
47,461
Provide a correct Python 3 solution for this coding contest problem. Taro, who aims to become a web designer, is currently training. My senior at the office tells me that the background color of this page is # ffe085, which is a color number peculiar to web design, but I can't think of what kind of color it is. This color number represents the intensity of each of the three primary colors of light, red, green, and blue. Specifically, it is a combination of three 2-digit hexadecimal numbers, and when the color number is “#RGB”, R is the intensity of red, G is the intensity of green, and is the intensity of blue. .. Each value is from 00 to ff. For Taro who is not familiar with color numbers, please create a program that inputs the color number and outputs the name of the closest color from the color table. The table of colors used is as follows. | Color name | Red intensity | Green intensity | Blue intensity --- | --- | --- | --- | --- | black | 00 | 00 | 00 | blue | 00 | 00 | ff | lime | 00 | ff | 00 aqua | 00 | ff | ff | red | ff | 00 | 00 | fuchsia | ff | 00 | ff | yellow | ff | ff | 00 | white | ff | ff | ff The "closest color" is defined as follows. When the intensities of red, green, and blue at a given color number are R, G, and B, respectively, and the intensities of red, green, and blue of the kth color in the table are Rk, Gk, and Bk, respectively. The color with the smallest dk value calculated by the following formula is the closest color. <image> If there are multiple colors with the same dk value, the color at the top of the table will be the closest color. Input A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. For each dataset, a string representing the color number is given on one line in #RGB format. The number of datasets does not exceed 1000. Output Outputs the name of the closest color for each dataset on one line. Examples Input #ffe085 #787878 #decade #ff55ff 0 Output white black white fuchsia Input ffe085 787878 decade ff55ff 0 Output white black white fuchsia
instruction
0
23,731
7
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"Correct Solution: ``` color = { 'black' : '#000000', 'blue' : '#0000ff', 'lime' : '#00ff00', 'aqua' : '#00ffff', 'red' : '#ff0000', 'fuchsia' : '#ff00ff', 'yellow' : '#ffff00', 'white' : '#ffffff', } def list_chunk(arr, n): return [arr[i:i+3] for i in range(0,15,n)] def code2rgb(code): code = code.lstrip('#') r, g, b = [code[i:i+2] for i in range(0,len(code),2)] return [int(v, 16) for v in [r, g, b]] def dk2(a, b): return sum([(a[i]-b[i])**2 for i in range(0,3)]) while True: v = input() if(v is '0'): break rgb = code2rgb(v) dks = [dk2(code2rgb(c), rgb) for c in color.values()] k = list(color.keys()) print(k[dks.index(min(dks))]) ```
output
1
23,731
7
47,463
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Taro, who aims to become a web designer, is currently training. My senior at the office tells me that the background color of this page is # ffe085, which is a color number peculiar to web design, but I can't think of what kind of color it is. This color number represents the intensity of each of the three primary colors of light, red, green, and blue. Specifically, it is a combination of three 2-digit hexadecimal numbers, and when the color number is “#RGB”, R is the intensity of red, G is the intensity of green, and is the intensity of blue. .. Each value is from 00 to ff. For Taro who is not familiar with color numbers, please create a program that inputs the color number and outputs the name of the closest color from the color table. The table of colors used is as follows. | Color name | Red intensity | Green intensity | Blue intensity --- | --- | --- | --- | --- | black | 00 | 00 | 00 | blue | 00 | 00 | ff | lime | 00 | ff | 00 aqua | 00 | ff | ff | red | ff | 00 | 00 | fuchsia | ff | 00 | ff | yellow | ff | ff | 00 | white | ff | ff | ff The "closest color" is defined as follows. When the intensities of red, green, and blue at a given color number are R, G, and B, respectively, and the intensities of red, green, and blue of the kth color in the table are Rk, Gk, and Bk, respectively. The color with the smallest dk value calculated by the following formula is the closest color. <image> If there are multiple colors with the same dk value, the color at the top of the table will be the closest color. Input A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. For each dataset, a string representing the color number is given on one line in #RGB format. The number of datasets does not exceed 1000. Output Outputs the name of the closest color for each dataset on one line. Examples Input #ffe085 #787878 #decade #ff55ff 0 Output white black white fuchsia Input ffe085 787878 decade ff55ff 0 Output white black white fuchsia Submitted Solution: ``` # -*- coding: utf-8 -*- """ http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0176 """ import sys from sys import stdin from collections import namedtuple from math import sqrt input = stdin.readline color = namedtuple('color', ['name', 'r', 'g', 'b']) def main(args): references = [color('black', 0x00, 0x00, 0x00), color('blue', 0x00, 0x00, 0xff), color('lime', 0x00, 0xff, 0x00), color('aqua', 0x00, 0xff, 0xff), color('red', 0xff, 0x00, 0x00), color('fuchsia', 0xff, 0x00, 0xff), color('yellow', 0xff, 0xff, 0x00), color('white', 0xff, 0xff, 0xff)] while True: data = input().strip() if data[0] == '0': break my_r = int(data[1:3], 16) my_g = int(data[3:5], 16) my_b = int(data[5:7], 16) # distances = [] # for c in references: # d = sqrt((c.r - my_r)**2 + (c.g - my_g)**2 + (c.b - my_b)**2) # distances.append(d) distances = [((c.r - my_r)**2 + (c.g - my_g)**2 + (c.b - my_b)**2) for c in references] closest_distance = min(distances) closest_color = distances.index(closest_distance) print(references[closest_color].name) if __name__ == '__main__': main(sys.argv[1:]) ```
instruction
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23,732
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47,464
Yes
output
1
23,732
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47,465
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Taro, who aims to become a web designer, is currently training. My senior at the office tells me that the background color of this page is # ffe085, which is a color number peculiar to web design, but I can't think of what kind of color it is. This color number represents the intensity of each of the three primary colors of light, red, green, and blue. Specifically, it is a combination of three 2-digit hexadecimal numbers, and when the color number is “#RGB”, R is the intensity of red, G is the intensity of green, and is the intensity of blue. .. Each value is from 00 to ff. For Taro who is not familiar with color numbers, please create a program that inputs the color number and outputs the name of the closest color from the color table. The table of colors used is as follows. | Color name | Red intensity | Green intensity | Blue intensity --- | --- | --- | --- | --- | black | 00 | 00 | 00 | blue | 00 | 00 | ff | lime | 00 | ff | 00 aqua | 00 | ff | ff | red | ff | 00 | 00 | fuchsia | ff | 00 | ff | yellow | ff | ff | 00 | white | ff | ff | ff The "closest color" is defined as follows. When the intensities of red, green, and blue at a given color number are R, G, and B, respectively, and the intensities of red, green, and blue of the kth color in the table are Rk, Gk, and Bk, respectively. The color with the smallest dk value calculated by the following formula is the closest color. <image> If there are multiple colors with the same dk value, the color at the top of the table will be the closest color. Input A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. For each dataset, a string representing the color number is given on one line in #RGB format. The number of datasets does not exceed 1000. Output Outputs the name of the closest color for each dataset on one line. Examples Input #ffe085 #787878 #decade #ff55ff 0 Output white black white fuchsia Input ffe085 787878 decade ff55ff 0 Output white black white fuchsia Submitted Solution: ``` import math while True : color = [[0, 0, 0], [0, 0, 255], [0, 255, 0], [0, 255, 255], [255, 0, 0], [255, 0, 255], [255, 255, 0], [255, 255, 255]] color_16 = input() if color_16 == "0" : break color_R = int(color_16[1] + color_16[2], 16) color_G = int(color_16[3] + color_16[4], 16) color_B = int(color_16[5] + color_16[6], 16) min_d = 500 for i in range(8) : R = color[i][0] G = color[i][1] B = color[i][2] d = math.sqrt((R - color_R)**2 + (G - color_G)**2 + (B - color_B)**2) if min_d > d : min_d = d color_num = i if color_num == 0 : print("black") elif color_num == 1 : print("blue") elif color_num == 2 : print("lime") elif color_num == 3 : print("aqua") elif color_num == 4 : print("red") elif color_num == 5 : print("fuchsia") elif color_num == 6 : print("yellow") else : print("white") ```
instruction
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23,733
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Yes
output
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7
47,467
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Taro, who aims to become a web designer, is currently training. My senior at the office tells me that the background color of this page is # ffe085, which is a color number peculiar to web design, but I can't think of what kind of color it is. This color number represents the intensity of each of the three primary colors of light, red, green, and blue. Specifically, it is a combination of three 2-digit hexadecimal numbers, and when the color number is “#RGB”, R is the intensity of red, G is the intensity of green, and is the intensity of blue. .. Each value is from 00 to ff. For Taro who is not familiar with color numbers, please create a program that inputs the color number and outputs the name of the closest color from the color table. The table of colors used is as follows. | Color name | Red intensity | Green intensity | Blue intensity --- | --- | --- | --- | --- | black | 00 | 00 | 00 | blue | 00 | 00 | ff | lime | 00 | ff | 00 aqua | 00 | ff | ff | red | ff | 00 | 00 | fuchsia | ff | 00 | ff | yellow | ff | ff | 00 | white | ff | ff | ff The "closest color" is defined as follows. When the intensities of red, green, and blue at a given color number are R, G, and B, respectively, and the intensities of red, green, and blue of the kth color in the table are Rk, Gk, and Bk, respectively. The color with the smallest dk value calculated by the following formula is the closest color. <image> If there are multiple colors with the same dk value, the color at the top of the table will be the closest color. Input A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. For each dataset, a string representing the color number is given on one line in #RGB format. The number of datasets does not exceed 1000. Output Outputs the name of the closest color for each dataset on one line. Examples Input #ffe085 #787878 #decade #ff55ff 0 Output white black white fuchsia Input ffe085 787878 decade ff55ff 0 Output white black white fuchsia Submitted Solution: ``` import math def solve(line): R = int(line[1:3], 16) G = int(line[3:5], 16) B = int(line[5:7], 16) sa_black = math.sqrt(R**2 + G**2 + B**2) sa_max = sa_black ans_color = "black" sa_blue = math.sqrt(R**2 + G**2 + (B - 255)**2) if sa_blue < sa_max: sa_max = sa_blue ans_color = "blue" sa_lime = math.sqrt(R**2 + (G - 255)**2 + B**2) if sa_lime < sa_max: sa_max = sa_lime ans_color = "lime" sa_aqua = math.sqrt(R**2 + (G - 255)**2 + (B - 255)**2) if sa_aqua < sa_max: sa_max = sa_aqua ans_color = "aqua" sa_red = math.sqrt((R - 255)**2 + G**2 + B**2) if sa_red < sa_max: sa_max = sa_red ans_color = "red" sa_fuchsia = math.sqrt((R - 255)**2 + G**2 + (B - 255)**2) if sa_fuchsia < sa_max: sa_max = sa_fuchsia ans_color = "fuchsia" sa_yellow = math.sqrt((R - 255)**2 + (G - 255)**2 + B**2) if sa_yellow < sa_max: sa_max = sa_yellow ans_color = "yellow" sa_white = math.sqrt((R - 255)**2 + (G - 255)**2 + (B - 255)**2) if sa_white < sa_max: sa_max = sa_white ans_color = "white" return ans_color while True: line = input() if line == '0': break print(solve(line)) ```
instruction
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Yes
output
1
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7
47,469
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Taro, who aims to become a web designer, is currently training. My senior at the office tells me that the background color of this page is # ffe085, which is a color number peculiar to web design, but I can't think of what kind of color it is. This color number represents the intensity of each of the three primary colors of light, red, green, and blue. Specifically, it is a combination of three 2-digit hexadecimal numbers, and when the color number is “#RGB”, R is the intensity of red, G is the intensity of green, and is the intensity of blue. .. Each value is from 00 to ff. For Taro who is not familiar with color numbers, please create a program that inputs the color number and outputs the name of the closest color from the color table. The table of colors used is as follows. | Color name | Red intensity | Green intensity | Blue intensity --- | --- | --- | --- | --- | black | 00 | 00 | 00 | blue | 00 | 00 | ff | lime | 00 | ff | 00 aqua | 00 | ff | ff | red | ff | 00 | 00 | fuchsia | ff | 00 | ff | yellow | ff | ff | 00 | white | ff | ff | ff The "closest color" is defined as follows. When the intensities of red, green, and blue at a given color number are R, G, and B, respectively, and the intensities of red, green, and blue of the kth color in the table are Rk, Gk, and Bk, respectively. The color with the smallest dk value calculated by the following formula is the closest color. <image> If there are multiple colors with the same dk value, the color at the top of the table will be the closest color. Input A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. For each dataset, a string representing the color number is given on one line in #RGB format. The number of datasets does not exceed 1000. Output Outputs the name of the closest color for each dataset on one line. Examples Input #ffe085 #787878 #decade #ff55ff 0 Output white black white fuchsia Input ffe085 787878 decade ff55ff 0 Output white black white fuchsia Submitted Solution: ``` color = { "000000": "black", "0000ff": "blue", "00ff00": "lime", "00ffff": "aqua", "ff0000": "red", "ff00ff": "fuchsia", "ffff00": "yellow", "ffffff": "white" } while True: n = input() if n == '0': break code = '' for f, s in zip(n[1::2], n[2::2]): if int(f+s, 16) <= 127: code += '00' else: code += 'ff' print(color[code]) ```
instruction
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Yes
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1
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7
47,471
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Taro, who aims to become a web designer, is currently training. My senior at the office tells me that the background color of this page is # ffe085, which is a color number peculiar to web design, but I can't think of what kind of color it is. This color number represents the intensity of each of the three primary colors of light, red, green, and blue. Specifically, it is a combination of three 2-digit hexadecimal numbers, and when the color number is “#RGB”, R is the intensity of red, G is the intensity of green, and is the intensity of blue. .. Each value is from 00 to ff. For Taro who is not familiar with color numbers, please create a program that inputs the color number and outputs the name of the closest color from the color table. The table of colors used is as follows. | Color name | Red intensity | Green intensity | Blue intensity --- | --- | --- | --- | --- | black | 00 | 00 | 00 | blue | 00 | 00 | ff | lime | 00 | ff | 00 aqua | 00 | ff | ff | red | ff | 00 | 00 | fuchsia | ff | 00 | ff | yellow | ff | ff | 00 | white | ff | ff | ff The "closest color" is defined as follows. When the intensities of red, green, and blue at a given color number are R, G, and B, respectively, and the intensities of red, green, and blue of the kth color in the table are Rk, Gk, and Bk, respectively. The color with the smallest dk value calculated by the following formula is the closest color. <image> If there are multiple colors with the same dk value, the color at the top of the table will be the closest color. Input A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. For each dataset, a string representing the color number is given on one line in #RGB format. The number of datasets does not exceed 1000. Output Outputs the name of the closest color for each dataset on one line. Examples Input #ffe085 #787878 #decade #ff55ff 0 Output white black white fuchsia Input ffe085 787878 decade ff55ff 0 Output white black white fuchsia Submitted Solution: ``` # -*- coding: utf-8 -*- """ http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0176 """ import sys from sys import stdin from collections import namedtuple from math import sqrt input = stdin.readline color = namedtuple('color', ['name', 'r', 'g', 'b']) def main(args): references = [color('black', 0x00, 0x00, 0x00), color('blue', 0x00, 0x00, 0xff), color('lime', 0x00, 0xff, 0x00), color('aqua', 0x00, 0xff, 0xff), color('rea', 0xff, 0x00, 0x00), color('fuchsia', 0xff, 0x00, 0xff), color('yellow', 0xff, 0xff, 0x00), color('white', 0xff, 0xff, 0xff)] while True: data = input().strip() if data[0] == '0': break my_r = int(data[1:3], 16) my_g = int(data[3:5], 16) my_b = int(data[5:7], 16) distances = [] for c in references: d = sqrt((c.r - my_r)**2 + (c.g - my_g)**2 + (c.b - my_b)**2) distances.append(d) closest_distance = min(distances) closest_color = distances.index(closest_distance) print(references[closest_color].name) if __name__ == '__main__': main(sys.argv[1:]) ```
instruction
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No
output
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47,473
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Taro, who aims to become a web designer, is currently training. My senior at the office tells me that the background color of this page is # ffe085, which is a color number peculiar to web design, but I can't think of what kind of color it is. This color number represents the intensity of each of the three primary colors of light, red, green, and blue. Specifically, it is a combination of three 2-digit hexadecimal numbers, and when the color number is “#RGB”, R is the intensity of red, G is the intensity of green, and is the intensity of blue. .. Each value is from 00 to ff. For Taro who is not familiar with color numbers, please create a program that inputs the color number and outputs the name of the closest color from the color table. The table of colors used is as follows. | Color name | Red intensity | Green intensity | Blue intensity --- | --- | --- | --- | --- | black | 00 | 00 | 00 | blue | 00 | 00 | ff | lime | 00 | ff | 00 aqua | 00 | ff | ff | red | ff | 00 | 00 | fuchsia | ff | 00 | ff | yellow | ff | ff | 00 | white | ff | ff | ff The "closest color" is defined as follows. When the intensities of red, green, and blue at a given color number are R, G, and B, respectively, and the intensities of red, green, and blue of the kth color in the table are Rk, Gk, and Bk, respectively. The color with the smallest dk value calculated by the following formula is the closest color. <image> If there are multiple colors with the same dk value, the color at the top of the table will be the closest color. Input A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. For each dataset, a string representing the color number is given on one line in #RGB format. The number of datasets does not exceed 1000. Output Outputs the name of the closest color for each dataset on one line. Examples Input #ffe085 #787878 #decade #ff55ff 0 Output white black white fuchsia Input ffe085 787878 decade ff55ff 0 Output white black white fuchsia Submitted Solution: ``` import math def solve(line): R = int(line[1:3], 16) G = int(line[3:5], 16) B = int(line[5:7], 16) sa_black = math.sqrt(R**2 + G**2 + B**2) sa_max = sa_black ans_color = "black" sa_blue = math.sqrt(R**2 + G**2 + (B - 255)**2) if sa_blue < sa_max: sa_max = sa_blue ans_color = "blue" sa_lime = math.sqrt(R**2 + (G - 255)**2 + B**2) if sa_lime < sa_max: sa_max = sa_lime ans_color = "lime" sa_aqua = math.sqrt(R**2 + (G - 255)**2 + (B - 255)**2) if sa_aqua < sa_max: sa_max = sa_aqua ans_color = "aqua" sa_red = math.sqrt((R - 255)**2 + G**2 + B**2) if sa_red < sa_max: sa_max = sa_red ans_color = "red" sa_fuchsia = math.sqrt((R - 255)**2 + G**2 + (B - 255)**2) if sa_fuchsia < sa_max: sa_max = sa_fuchsia ans_color = "fuchsia" sa_yellow = math.sqrt((R - 255)**2 + (G - 255)**2 + B**2) if sa_yellow < sa_max: sa_max = sa_yellow ans_color = "blue" sa_white = math.sqrt((R - 255)**2 + (G - 255)**2 + (B - 255)**2) if sa_white < sa_max: sa_max = sa_white ans_color = "white" return ans_color while True: line = input() if line == '0': break print(solve(line)) ```
instruction
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No
output
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23,737
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47,475