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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. N people are standing in a queue, numbered 1, 2, 3, ..., N from front to back. Each person wears a hat, which is red, blue, or green. The person numbered i says: * "In front of me, exactly A_i people are wearing hats with the same color as mine." Assuming that all these statements are correct, find the number of possible combinations of colors of the N people's hats. Since the count can be enormous, compute it modulo 1000000007. Constraints * 1 \leq N \leq 100000 * 0 \leq A_i \leq N-1 * All values in input are integers. Input Input is given from Standard Input in the following format: N A_1 A_2 A_3 ... A_N Output Print the number of possible combinations of colors of the N people's hats, modulo 1000000007. Examples Input 6 0 1 2 3 4 5 Output 3 Input 3 0 0 0 Output 6 Input 54 0 0 1 0 1 2 1 2 3 2 3 3 4 4 5 4 6 5 7 8 5 6 6 7 7 8 8 9 9 10 10 11 9 12 10 13 14 11 11 12 12 13 13 14 14 15 15 15 16 16 16 17 17 17 Output 115295190 Submitted Solution: ``` N = int(input()) *A, = map(int,input().split()) mod = 10**9+7 ans = 3 if A[0]!=0: ans = 0 dp = [1,0,0] for a in A[1:]: ans *= dp.count(a) ans %= mod if ans == 0: break dp[dp.index(a)] += 1 print(ans) ```
instruction
0
46,869
7
93,738
Yes
output
1
46,869
7
93,739
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. N people are standing in a queue, numbered 1, 2, 3, ..., N from front to back. Each person wears a hat, which is red, blue, or green. The person numbered i says: * "In front of me, exactly A_i people are wearing hats with the same color as mine." Assuming that all these statements are correct, find the number of possible combinations of colors of the N people's hats. Since the count can be enormous, compute it modulo 1000000007. Constraints * 1 \leq N \leq 100000 * 0 \leq A_i \leq N-1 * All values in input are integers. Input Input is given from Standard Input in the following format: N A_1 A_2 A_3 ... A_N Output Print the number of possible combinations of colors of the N people's hats, modulo 1000000007. Examples Input 6 0 1 2 3 4 5 Output 3 Input 3 0 0 0 Output 6 Input 54 0 0 1 0 1 2 1 2 3 2 3 3 4 4 5 4 6 5 7 8 5 6 6 7 7 8 8 9 9 10 10 11 9 12 10 13 14 11 11 12 12 13 13 14 14 15 15 15 16 16 16 17 17 17 Output 115295190 Submitted Solution: ``` N = int(input()) A = list(map(int, input().split())) kMod = 10**9+7 mem = [0, 0, 0] cnt = 1 for a in A: if a not in mem: cnt = 0 break cnt *= mem.count(a) cnt %= kMod mem[mem.index(a)] = a+1 print(cnt) ```
instruction
0
46,870
7
93,740
Yes
output
1
46,870
7
93,741
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. N people are standing in a queue, numbered 1, 2, 3, ..., N from front to back. Each person wears a hat, which is red, blue, or green. The person numbered i says: * "In front of me, exactly A_i people are wearing hats with the same color as mine." Assuming that all these statements are correct, find the number of possible combinations of colors of the N people's hats. Since the count can be enormous, compute it modulo 1000000007. Constraints * 1 \leq N \leq 100000 * 0 \leq A_i \leq N-1 * All values in input are integers. Input Input is given from Standard Input in the following format: N A_1 A_2 A_3 ... A_N Output Print the number of possible combinations of colors of the N people's hats, modulo 1000000007. Examples Input 6 0 1 2 3 4 5 Output 3 Input 3 0 0 0 Output 6 Input 54 0 0 1 0 1 2 1 2 3 2 3 3 4 4 5 4 6 5 7 8 5 6 6 7 7 8 8 9 9 10 10 11 9 12 10 13 14 11 11 12 12 13 13 14 14 15 15 15 16 16 16 17 17 17 Output 115295190 Submitted Solution: ``` n=int(input()) a=list(map(int,input().split())) l=[3]+[0]*(10**5) m=10**9+7 x=1 for i in a: if l[i]: x=(x*l[i])%m l[i]-=1 l[i+1]+=1 else: x=0 break print(x) ```
instruction
0
46,871
7
93,742
Yes
output
1
46,871
7
93,743
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. N people are standing in a queue, numbered 1, 2, 3, ..., N from front to back. Each person wears a hat, which is red, blue, or green. The person numbered i says: * "In front of me, exactly A_i people are wearing hats with the same color as mine." Assuming that all these statements are correct, find the number of possible combinations of colors of the N people's hats. Since the count can be enormous, compute it modulo 1000000007. Constraints * 1 \leq N \leq 100000 * 0 \leq A_i \leq N-1 * All values in input are integers. Input Input is given from Standard Input in the following format: N A_1 A_2 A_3 ... A_N Output Print the number of possible combinations of colors of the N people's hats, modulo 1000000007. Examples Input 6 0 1 2 3 4 5 Output 3 Input 3 0 0 0 Output 6 Input 54 0 0 1 0 1 2 1 2 3 2 3 3 4 4 5 4 6 5 7 8 5 6 6 7 7 8 8 9 9 10 10 11 9 12 10 13 14 11 11 12 12 13 13 14 14 15 15 15 16 16 16 17 17 17 Output 115295190 Submitted Solution: ``` p = 10**9+7 N = int(input()) A = list(map(int,input().split())) C={i:0 for i in range(N)} C[0]=1 ans = 3 for i in range(1,N): a = A[i] if a not in C: C[a]=0 C[a] += 1 if C[a]==1: ans = (ans*C[a-1])%p elif a==0 and C[a]==2: ans = ans*2 elif a>0 and C[a]==2: ans = (ans*(C[a-1]-1))%p elif C[a]>3: ans = 0 print(max(ans,0)) ```
instruction
0
46,872
7
93,744
No
output
1
46,872
7
93,745
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. N people are standing in a queue, numbered 1, 2, 3, ..., N from front to back. Each person wears a hat, which is red, blue, or green. The person numbered i says: * "In front of me, exactly A_i people are wearing hats with the same color as mine." Assuming that all these statements are correct, find the number of possible combinations of colors of the N people's hats. Since the count can be enormous, compute it modulo 1000000007. Constraints * 1 \leq N \leq 100000 * 0 \leq A_i \leq N-1 * All values in input are integers. Input Input is given from Standard Input in the following format: N A_1 A_2 A_3 ... A_N Output Print the number of possible combinations of colors of the N people's hats, modulo 1000000007. Examples Input 6 0 1 2 3 4 5 Output 3 Input 3 0 0 0 Output 6 Input 54 0 0 1 0 1 2 1 2 3 2 3 3 4 4 5 4 6 5 7 8 5 6 6 7 7 8 8 9 9 10 10 11 9 12 10 13 14 11 11 12 12 13 13 14 14 15 15 15 16 16 16 17 17 17 Output 115295190 Submitted Solution: ``` n = int(input()) a = list(map(int, input().split())) x = 0 y = 0 z = 0 ans = 1 for i in range(n): if a[i] == x: if x == y == z: ans *= 3 elif x == y != z: ans *= 2 x += 1 elif a[i] == y: if y == z: ans *= 2 y += 1 else: z += 1 ans %= 1000000007 print(ans) ```
instruction
0
46,873
7
93,746
No
output
1
46,873
7
93,747
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. N people are standing in a queue, numbered 1, 2, 3, ..., N from front to back. Each person wears a hat, which is red, blue, or green. The person numbered i says: * "In front of me, exactly A_i people are wearing hats with the same color as mine." Assuming that all these statements are correct, find the number of possible combinations of colors of the N people's hats. Since the count can be enormous, compute it modulo 1000000007. Constraints * 1 \leq N \leq 100000 * 0 \leq A_i \leq N-1 * All values in input are integers. Input Input is given from Standard Input in the following format: N A_1 A_2 A_3 ... A_N Output Print the number of possible combinations of colors of the N people's hats, modulo 1000000007. Examples Input 6 0 1 2 3 4 5 Output 3 Input 3 0 0 0 Output 6 Input 54 0 0 1 0 1 2 1 2 3 2 3 3 4 4 5 4 6 5 7 8 5 6 6 7 7 8 8 9 9 10 10 11 9 12 10 13 14 11 11 12 12 13 13 14 14 15 15 15 16 16 16 17 17 17 Output 115295190 Submitted Solution: ``` n = int(input()) lst = list(map(int,input().split())) mod = 10**9 + 7 col_lst = [0 , 0 , 0] ans = 1 for i in range(n): tmp = lst[i] val = col_lst.count(tmp) ans = (ans * val) % mod col_lst[col_lst.index(tmp)] += 1 print(ans % mod) ```
instruction
0
46,874
7
93,748
No
output
1
46,874
7
93,749
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. N people are standing in a queue, numbered 1, 2, 3, ..., N from front to back. Each person wears a hat, which is red, blue, or green. The person numbered i says: * "In front of me, exactly A_i people are wearing hats with the same color as mine." Assuming that all these statements are correct, find the number of possible combinations of colors of the N people's hats. Since the count can be enormous, compute it modulo 1000000007. Constraints * 1 \leq N \leq 100000 * 0 \leq A_i \leq N-1 * All values in input are integers. Input Input is given from Standard Input in the following format: N A_1 A_2 A_3 ... A_N Output Print the number of possible combinations of colors of the N people's hats, modulo 1000000007. Examples Input 6 0 1 2 3 4 5 Output 3 Input 3 0 0 0 Output 6 Input 54 0 0 1 0 1 2 1 2 3 2 3 3 4 4 5 4 6 5 7 8 5 6 6 7 7 8 8 9 9 10 10 11 9 12 10 13 14 11 11 12 12 13 13 14 14 15 15 15 16 16 16 17 17 17 Output 115295190 Submitted Solution: ``` n = int(input()) hats = [0, 0, 0] count = 1 mod = 1000000007 for a in map(int, input().split()): count *= hats.count(a) count %= mod count[count.index(a)] += 1 print(count) ```
instruction
0
46,875
7
93,750
No
output
1
46,875
7
93,751
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. In Japan, people make offerings called hina arare, colorful crackers, on March 3. We have a bag that contains N hina arare. (From here, we call them arare.) It is known that the bag either contains arare in three colors: pink, white and green, or contains arare in four colors: pink, white, green and yellow. We have taken out the arare in the bag one by one, and the color of the i-th arare was S_i, where colors are represented as follows - pink: `P`, white: `W`, green: `G`, yellow: `Y`. If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`. Constraints * 1 \leq N \leq 100 * S_i is `P`, `W`, `G` or `Y`. * There always exist i, j and k such that S_i=`P`, S_j=`W` and S_k=`G`. Input Input is given from Standard Input in the following format: N S_1 S_2 ... S_N Output If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`. Examples Input 6 G W Y P Y W Output Four Input 9 G W W G P W P G G Output Three Input 8 P Y W G Y W Y Y Output Four Submitted Solution: ``` #89b n=int(input()) a=list(input()) a=set(a) c=['P','W','G','Y'] if c-a==0: print('Four') else: print('Three') ```
instruction
0
46,921
7
93,842
No
output
1
46,921
7
93,843
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. In Japan, people make offerings called hina arare, colorful crackers, on March 3. We have a bag that contains N hina arare. (From here, we call them arare.) It is known that the bag either contains arare in three colors: pink, white and green, or contains arare in four colors: pink, white, green and yellow. We have taken out the arare in the bag one by one, and the color of the i-th arare was S_i, where colors are represented as follows - pink: `P`, white: `W`, green: `G`, yellow: `Y`. If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`. Constraints * 1 \leq N \leq 100 * S_i is `P`, `W`, `G` or `Y`. * There always exist i, j and k such that S_i=`P`, S_j=`W` and S_k=`G`. Input Input is given from Standard Input in the following format: N S_1 S_2 ... S_N Output If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`. Examples Input 6 G W Y P Y W Output Four Input 9 G W W G P W P G G Output Three Input 8 P Y W G Y W Y Y Output Four Submitted Solution: ``` N = int(input()) arare = input().split() print(arare) y = 0 for i in range(len(arare)): if arare[i] == "Y": y += 1 break if y == 1: print("Four") else: print("Three") ```
instruction
0
46,922
7
93,844
No
output
1
46,922
7
93,845
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. In Japan, people make offerings called hina arare, colorful crackers, on March 3. We have a bag that contains N hina arare. (From here, we call them arare.) It is known that the bag either contains arare in three colors: pink, white and green, or contains arare in four colors: pink, white, green and yellow. We have taken out the arare in the bag one by one, and the color of the i-th arare was S_i, where colors are represented as follows - pink: `P`, white: `W`, green: `G`, yellow: `Y`. If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`. Constraints * 1 \leq N \leq 100 * S_i is `P`, `W`, `G` or `Y`. * There always exist i, j and k such that S_i=`P`, S_j=`W` and S_k=`G`. Input Input is given from Standard Input in the following format: N S_1 S_2 ... S_N Output If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`. Examples Input 6 G W Y P Y W Output Four Input 9 G W W G P W P G G Output Three Input 8 P Y W G Y W Y Y Output Four Submitted Solution: ``` ips = [] ips.append(input()) while True: try: ips.append(input()) except (EOFError): break num = int(ips[0]) hina = ips[1] v = [] for i in range(num): if hina[i] not in v: v.append(hina[i]) if len(v) == 3: print("three") elif len(v) == 4: print("four") ```
instruction
0
46,923
7
93,846
No
output
1
46,923
7
93,847
Provide tags and a correct Python 3 solution for this coding contest problem. To satisfy his love of matching socks, Phoenix has brought his n socks (n is even) to the sock store. Each of his socks has a color c_i and is either a left sock or right sock. Phoenix can pay one dollar to the sock store to either: * recolor a sock to any color c' (1 ≀ c' ≀ n) * turn a left sock into a right sock * turn a right sock into a left sock The sock store may perform each of these changes any number of times. Note that the color of a left sock doesn't change when it turns into a right sock, and vice versa. A matching pair of socks is a left and right sock with the same color. What is the minimum cost for Phoenix to make n/2 matching pairs? Each sock must be included in exactly one matching pair. Input The input consists of multiple test cases. The first line contains an integer t (1 ≀ t ≀ 1000) β€” the number of test cases. The first line of each test case contains three integers n, l, and r (2 ≀ n ≀ 2 β‹… 10^5; n is even; 0 ≀ l, r ≀ n; l+r=n) β€” the total number of socks, and the number of left and right socks, respectively. The next line contains n integers c_i (1 ≀ c_i ≀ n) β€” the colors of the socks. The first l socks are left socks, while the next r socks are right socks. It is guaranteed that the sum of n across all the test cases will not exceed 2 β‹… 10^5. Output For each test case, print one integer β€” the minimum cost for Phoenix to make n/2 matching pairs. Each sock must be included in exactly one matching pair. Example Input 4 6 3 3 1 2 3 2 2 2 6 2 4 1 1 2 2 2 2 6 5 1 6 5 4 3 2 1 4 0 4 4 4 4 3 Output 2 3 5 3 Note In the first test case, Phoenix can pay 2 dollars to: * recolor sock 1 to color 2 * recolor sock 3 to color 2 There are now 3 matching pairs. For example, pairs (1, 4), (2, 5), and (3, 6) are matching. In the second test case, Phoenix can pay 3 dollars to: * turn sock 6 from a right sock to a left sock * recolor sock 3 to color 1 * recolor sock 4 to color 1 There are now 3 matching pairs. For example, pairs (1, 3), (2, 4), and (5, 6) are matching.
instruction
0
47,253
7
94,506
Tags: greedy, sortings, two pointers Correct Solution: ``` def solve(): n, l, r = map(int, input().split()) c = list(map(int, input().split())) lc = [0] * (n+1) rc = [0] * (n+1) res = 0 for i in range(l): lc[c[i]] += 1 for i in range(l, n): rc[c[i]] += 1 for i in range(n): d = min(lc[i], rc[i]) lc[i] -= d rc[i] -= d # print(lc) # print(rc) for i in range(n+1): # print(lc) # print(rc) # print() if lc[i] > rc[i]: if l > r: d = (l - r) // 2 give = min((lc[i] - rc[i]) // 2, d) rc[i] += give lc[i] -= give l -= give r += give res += give else: if r > l: d = (r - l) // 2 give = min((rc[i] - lc[i]) // 2, d) r -= give l += give rc[i] -= give lc[i] += give # print('give', i, give) res += give res += abs(r-l) // 2 d = 0 for i in range(n+1): d += abs(lc[i] - rc[i]) res += d // 2 + int(d % 2 == 1) print(res) def main(): for _ in range(int(input())): solve() main() ```
output
1
47,253
7
94,507
Provide tags and a correct Python 3 solution for this coding contest problem. To satisfy his love of matching socks, Phoenix has brought his n socks (n is even) to the sock store. Each of his socks has a color c_i and is either a left sock or right sock. Phoenix can pay one dollar to the sock store to either: * recolor a sock to any color c' (1 ≀ c' ≀ n) * turn a left sock into a right sock * turn a right sock into a left sock The sock store may perform each of these changes any number of times. Note that the color of a left sock doesn't change when it turns into a right sock, and vice versa. A matching pair of socks is a left and right sock with the same color. What is the minimum cost for Phoenix to make n/2 matching pairs? Each sock must be included in exactly one matching pair. Input The input consists of multiple test cases. The first line contains an integer t (1 ≀ t ≀ 1000) β€” the number of test cases. The first line of each test case contains three integers n, l, and r (2 ≀ n ≀ 2 β‹… 10^5; n is even; 0 ≀ l, r ≀ n; l+r=n) β€” the total number of socks, and the number of left and right socks, respectively. The next line contains n integers c_i (1 ≀ c_i ≀ n) β€” the colors of the socks. The first l socks are left socks, while the next r socks are right socks. It is guaranteed that the sum of n across all the test cases will not exceed 2 β‹… 10^5. Output For each test case, print one integer β€” the minimum cost for Phoenix to make n/2 matching pairs. Each sock must be included in exactly one matching pair. Example Input 4 6 3 3 1 2 3 2 2 2 6 2 4 1 1 2 2 2 2 6 5 1 6 5 4 3 2 1 4 0 4 4 4 4 3 Output 2 3 5 3 Note In the first test case, Phoenix can pay 2 dollars to: * recolor sock 1 to color 2 * recolor sock 3 to color 2 There are now 3 matching pairs. For example, pairs (1, 4), (2, 5), and (3, 6) are matching. In the second test case, Phoenix can pay 3 dollars to: * turn sock 6 from a right sock to a left sock * recolor sock 3 to color 1 * recolor sock 4 to color 1 There are now 3 matching pairs. For example, pairs (1, 3), (2, 4), and (5, 6) are matching.
instruction
0
47,254
7
94,508
Tags: greedy, sortings, two pointers Correct Solution: ``` import sys input = sys.stdin.buffer.readline def map_int(): return map(int, input().split()) def solve(): n, l, r=map_int() c=list(map_int()) if r>l: c=c[l:n]+c[:l] l, r = r, l color = [0]*(n+1) for i in range(n): color[c[i]]+=1 if i < l else -1 ans=rem=n//2-r bad=0 for cnt in color: if cnt>1: used=min(cnt//2, rem) cnt-=2*used rem-=used if cnt>0: bad+=cnt print(ans+bad-rem) for _ in range(int(input())): solve() ```
output
1
47,254
7
94,509
Provide tags and a correct Python 3 solution for this coding contest problem. To satisfy his love of matching socks, Phoenix has brought his n socks (n is even) to the sock store. Each of his socks has a color c_i and is either a left sock or right sock. Phoenix can pay one dollar to the sock store to either: * recolor a sock to any color c' (1 ≀ c' ≀ n) * turn a left sock into a right sock * turn a right sock into a left sock The sock store may perform each of these changes any number of times. Note that the color of a left sock doesn't change when it turns into a right sock, and vice versa. A matching pair of socks is a left and right sock with the same color. What is the minimum cost for Phoenix to make n/2 matching pairs? Each sock must be included in exactly one matching pair. Input The input consists of multiple test cases. The first line contains an integer t (1 ≀ t ≀ 1000) β€” the number of test cases. The first line of each test case contains three integers n, l, and r (2 ≀ n ≀ 2 β‹… 10^5; n is even; 0 ≀ l, r ≀ n; l+r=n) β€” the total number of socks, and the number of left and right socks, respectively. The next line contains n integers c_i (1 ≀ c_i ≀ n) β€” the colors of the socks. The first l socks are left socks, while the next r socks are right socks. It is guaranteed that the sum of n across all the test cases will not exceed 2 β‹… 10^5. Output For each test case, print one integer β€” the minimum cost for Phoenix to make n/2 matching pairs. Each sock must be included in exactly one matching pair. Example Input 4 6 3 3 1 2 3 2 2 2 6 2 4 1 1 2 2 2 2 6 5 1 6 5 4 3 2 1 4 0 4 4 4 4 3 Output 2 3 5 3 Note In the first test case, Phoenix can pay 2 dollars to: * recolor sock 1 to color 2 * recolor sock 3 to color 2 There are now 3 matching pairs. For example, pairs (1, 4), (2, 5), and (3, 6) are matching. In the second test case, Phoenix can pay 3 dollars to: * turn sock 6 from a right sock to a left sock * recolor sock 3 to color 1 * recolor sock 4 to color 1 There are now 3 matching pairs. For example, pairs (1, 3), (2, 4), and (5, 6) are matching.
instruction
0
47,255
7
94,510
Tags: greedy, sortings, two pointers Correct Solution: ``` # https://codeforces.com/contest/1515/problem/D import sys reader = (s.rstrip() for s in sys.stdin) input = reader.__next__ # do magic here t = int(input()) def makeDict(left): leftMap = {} for item in left: if item not in leftMap: leftMap[item] = 0 leftMap[item] += 1 return leftMap for _ in range(t): n, l, r = map(int, input().split()) left = list(map(int, input().split())) right = [] while len(left) > l: right.append(left.pop()) leftMap = makeDict(left) rightMap = makeDict(right) lkeys = set(leftMap.keys()) rkeys = set(rightMap.keys()) for k in lkeys: if k in rkeys: mn = min(leftMap[k], rightMap[k]) leftMap[k] -= mn if not leftMap[k]: leftMap.pop(k) rightMap[k] -= mn if not rightMap[k]: rightMap.pop(k) # print(leftMap, rightMap) left = [] right = [] a, b = sum(leftMap.values()), sum(rightMap.values()) if a < b: leftMap, rightMap = rightMap, leftMap a, b = b, a elif a == b: # only change colors pass lkeys = leftMap.keys() gap = abs(a-b) cost = 0 vals = sorted(leftMap.values(), reverse=True) for i in range(len(vals)): val = vals[i] while gap and val >= 2: gap -= 2 vals[i] -= 2 val -= 2 cost += 1 X = sum(vals) while gap: cost += 2 X -= 2 gap -= 2 cost += X print(cost) ```
output
1
47,255
7
94,511
Provide tags and a correct Python 3 solution for this coding contest problem. To satisfy his love of matching socks, Phoenix has brought his n socks (n is even) to the sock store. Each of his socks has a color c_i and is either a left sock or right sock. Phoenix can pay one dollar to the sock store to either: * recolor a sock to any color c' (1 ≀ c' ≀ n) * turn a left sock into a right sock * turn a right sock into a left sock The sock store may perform each of these changes any number of times. Note that the color of a left sock doesn't change when it turns into a right sock, and vice versa. A matching pair of socks is a left and right sock with the same color. What is the minimum cost for Phoenix to make n/2 matching pairs? Each sock must be included in exactly one matching pair. Input The input consists of multiple test cases. The first line contains an integer t (1 ≀ t ≀ 1000) β€” the number of test cases. The first line of each test case contains three integers n, l, and r (2 ≀ n ≀ 2 β‹… 10^5; n is even; 0 ≀ l, r ≀ n; l+r=n) β€” the total number of socks, and the number of left and right socks, respectively. The next line contains n integers c_i (1 ≀ c_i ≀ n) β€” the colors of the socks. The first l socks are left socks, while the next r socks are right socks. It is guaranteed that the sum of n across all the test cases will not exceed 2 β‹… 10^5. Output For each test case, print one integer β€” the minimum cost for Phoenix to make n/2 matching pairs. Each sock must be included in exactly one matching pair. Example Input 4 6 3 3 1 2 3 2 2 2 6 2 4 1 1 2 2 2 2 6 5 1 6 5 4 3 2 1 4 0 4 4 4 4 3 Output 2 3 5 3 Note In the first test case, Phoenix can pay 2 dollars to: * recolor sock 1 to color 2 * recolor sock 3 to color 2 There are now 3 matching pairs. For example, pairs (1, 4), (2, 5), and (3, 6) are matching. In the second test case, Phoenix can pay 3 dollars to: * turn sock 6 from a right sock to a left sock * recolor sock 3 to color 1 * recolor sock 4 to color 1 There are now 3 matching pairs. For example, pairs (1, 3), (2, 4), and (5, 6) are matching.
instruction
0
47,256
7
94,512
Tags: greedy, sortings, two pointers Correct Solution: ``` #!/usr/bin/env python3 import sys, getpass import math, random import functools, itertools, collections, heapq, bisect from collections import Counter, defaultdict, deque input = sys.stdin.readline # to read input quickly # available on Google, AtCoder Python3, not available on Codeforces # import numpy as np # import scipy M9 = 10**9 + 7 # 998244353 # d4 = [(1,0),(0,1),(-1,0),(0,-1)] # d8 = [(1,0),(1,1),(0,1),(-1,1),(-1,0),(-1,-1),(0,-1),(1,-1)] # d6 = [(2,0),(1,1),(-1,1),(-2,0),(-1,-1),(1,-1)] # hexagonal layout MAXINT = sys.maxsize # if testing locally, print to terminal with a different color OFFLINE_TEST = getpass.getuser() == "hkmac" # OFFLINE_TEST = False # codechef does not allow getpass def log(*args): if OFFLINE_TEST: print('\033[36m', *args, '\033[0m', file=sys.stderr) def solve(*args): # screen input if OFFLINE_TEST: log("----- solving ------") log(*args) log("----- ------- ------") return solve_(*args) def read_matrix(rows): return [list(map(int,input().split())) for _ in range(rows)] def read_strings(rows): return [input().strip() for _ in range(rows)] # ---------------------------- template ends here ---------------------------- def solve_(arr, brr): if len(arr) < len(brr): arr, brr = brr, arr diff = len(arr) - len(brr) # your solution here c1 = Counter(arr) c2 = Counter(brr) for k in list(c1.keys()): comb = min(c1[k], c2[k]) c1[k] -= comb c2[k] -= comb if c1[k] == 0: del c1[k] if c2[k] == 0: del c2[k] log(c1) log(c2) asum = sum(c1.values()) bsum = sum(c2.values()) matched = 0 for k in list(c1.keys()): flip = c1[k]//2 matched += flip c1[k] -= flip*2 return bsum + max((asum-bsum)//2, asum-bsum-matched) # for k,v in c1.items(): # res += v # for k,v in c2.items(): # res += v return res # for case_num in [0]: # no loop over test case # for case_num in range(100): # if the number of test cases is specified for case_num in range(int(input())): # read line as an integer # k = int(input()) # read line as a string # srr = input().strip() # read one line and parse each word as a string # lst = input().split() # read one line and parse each word as an integer _,left,right = list(map(int,input().split())) lst = list(map(int,input().split())) # read multiple rows # mrr = read_matrix(k) # and return as a list of list of int # arr = read_strings(k) # and return as a list of str arr = lst[:left] brr = lst[left:] res = solve(arr, brr) # include input here # print result # Google and Facebook - case number required # print("Case #{}: {}".format(case_num+1, res)) # Other platforms - no case number required print(res) # print(len(res)) # print(*res) # print a list with elements # for r in res: # print each list in a different line # print(res) # print(*res) ```
output
1
47,256
7
94,513
Provide tags and a correct Python 3 solution for this coding contest problem. To satisfy his love of matching socks, Phoenix has brought his n socks (n is even) to the sock store. Each of his socks has a color c_i and is either a left sock or right sock. Phoenix can pay one dollar to the sock store to either: * recolor a sock to any color c' (1 ≀ c' ≀ n) * turn a left sock into a right sock * turn a right sock into a left sock The sock store may perform each of these changes any number of times. Note that the color of a left sock doesn't change when it turns into a right sock, and vice versa. A matching pair of socks is a left and right sock with the same color. What is the minimum cost for Phoenix to make n/2 matching pairs? Each sock must be included in exactly one matching pair. Input The input consists of multiple test cases. The first line contains an integer t (1 ≀ t ≀ 1000) β€” the number of test cases. The first line of each test case contains three integers n, l, and r (2 ≀ n ≀ 2 β‹… 10^5; n is even; 0 ≀ l, r ≀ n; l+r=n) β€” the total number of socks, and the number of left and right socks, respectively. The next line contains n integers c_i (1 ≀ c_i ≀ n) β€” the colors of the socks. The first l socks are left socks, while the next r socks are right socks. It is guaranteed that the sum of n across all the test cases will not exceed 2 β‹… 10^5. Output For each test case, print one integer β€” the minimum cost for Phoenix to make n/2 matching pairs. Each sock must be included in exactly one matching pair. Example Input 4 6 3 3 1 2 3 2 2 2 6 2 4 1 1 2 2 2 2 6 5 1 6 5 4 3 2 1 4 0 4 4 4 4 3 Output 2 3 5 3 Note In the first test case, Phoenix can pay 2 dollars to: * recolor sock 1 to color 2 * recolor sock 3 to color 2 There are now 3 matching pairs. For example, pairs (1, 4), (2, 5), and (3, 6) are matching. In the second test case, Phoenix can pay 3 dollars to: * turn sock 6 from a right sock to a left sock * recolor sock 3 to color 1 * recolor sock 4 to color 1 There are now 3 matching pairs. For example, pairs (1, 3), (2, 4), and (5, 6) are matching.
instruction
0
47,257
7
94,514
Tags: greedy, sortings, two pointers Correct Solution: ``` # template begins ##################################### from io import BytesIO, IOBase import sys import math import os from collections import defaultdict from math import ceil from bisect import bisect_left, bisect_left from time import perf_counter # region fastio BUFSIZE = 8192 class FastIO(IOBase): newlines = 0 def __init__(self, file): self._fd = file.fileno() self.buffer = BytesIO() self.writable = "x" in file.mode or "r" not in file.mode self.write = self.buffer.write if self.writable else None def read(self): while True: b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE)) if not b: break ptr = self.buffer.tell() self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr) self.newlines = 0 return self.buffer.read() def readline(self): while self.newlines == 0: b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE)) self.newlines = b.count(b"\n") + (not b) ptr = self.buffer.tell() self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr) self.newlines -= 1 return self.buffer.readline() def flush(self): if self.writable: os.write(self._fd, self.buffer.getvalue()) self.buffer.truncate(0), self.buffer.seek(0) class IOWrapper(IOBase): def __init__(self, file): self.buffer = FastIO(file) self.flush = self.buffer.flush self.writable = self.buffer.writable self.write = lambda s: self.buffer.write(s.encode("ascii")) self.read = lambda: self.buffer.read().decode("ascii") self.readline = lambda: self.buffer.readline().decode("ascii") sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout) def input(): return sys.stdin.readline().rstrip("\r\n") def mint(): return map(int, input().split()) def mfloat(): return map(float, input().split()) ##################################### # template ends # Use the recursion snippet if heavy recursion is needed (depth>1000) def solve(): n, l, r = mint() *a, = mint() left_socks={} right_socks={} for i in range(l): left_socks[a[i]]=left_socks.get(a[i], 0)+1 for i in range(l, n): sock = a[i] if left_socks.get(sock, 0)>0: left_socks[sock]-=1 else: right_socks[sock] = right_socks.get(sock, 0) + 1 # you can convert 2l to 1l 1r """ you can pay a dollar to match one left with one right avoid the ones that are 2 of same type, since you can pair them up later """ left = sum(left_socks.values()) right = sum(right_socks.values()) if left<right: pair_up = right_socks.values() remaining = right-left cost=left else: pair_up = left_socks.values() remaining = left-right cost=right for i in pair_up: pair = i//2*2 take = min(pair, remaining-remaining%2) cost += take//2 remaining -= take if not remaining: break # print(cost, remaining) cost += remaining print(cost) def main(): t = int(input()) # t = 1 for _ in range(t): solve() if __name__ == "__main__": main() ```
output
1
47,257
7
94,515
Provide tags and a correct Python 3 solution for this coding contest problem. To satisfy his love of matching socks, Phoenix has brought his n socks (n is even) to the sock store. Each of his socks has a color c_i and is either a left sock or right sock. Phoenix can pay one dollar to the sock store to either: * recolor a sock to any color c' (1 ≀ c' ≀ n) * turn a left sock into a right sock * turn a right sock into a left sock The sock store may perform each of these changes any number of times. Note that the color of a left sock doesn't change when it turns into a right sock, and vice versa. A matching pair of socks is a left and right sock with the same color. What is the minimum cost for Phoenix to make n/2 matching pairs? Each sock must be included in exactly one matching pair. Input The input consists of multiple test cases. The first line contains an integer t (1 ≀ t ≀ 1000) β€” the number of test cases. The first line of each test case contains three integers n, l, and r (2 ≀ n ≀ 2 β‹… 10^5; n is even; 0 ≀ l, r ≀ n; l+r=n) β€” the total number of socks, and the number of left and right socks, respectively. The next line contains n integers c_i (1 ≀ c_i ≀ n) β€” the colors of the socks. The first l socks are left socks, while the next r socks are right socks. It is guaranteed that the sum of n across all the test cases will not exceed 2 β‹… 10^5. Output For each test case, print one integer β€” the minimum cost for Phoenix to make n/2 matching pairs. Each sock must be included in exactly one matching pair. Example Input 4 6 3 3 1 2 3 2 2 2 6 2 4 1 1 2 2 2 2 6 5 1 6 5 4 3 2 1 4 0 4 4 4 4 3 Output 2 3 5 3 Note In the first test case, Phoenix can pay 2 dollars to: * recolor sock 1 to color 2 * recolor sock 3 to color 2 There are now 3 matching pairs. For example, pairs (1, 4), (2, 5), and (3, 6) are matching. In the second test case, Phoenix can pay 3 dollars to: * turn sock 6 from a right sock to a left sock * recolor sock 3 to color 1 * recolor sock 4 to color 1 There are now 3 matching pairs. For example, pairs (1, 3), (2, 4), and (5, 6) are matching.
instruction
0
47,258
7
94,516
Tags: greedy, sortings, two pointers Correct Solution: ``` from collections import defaultdict as dd for _ in range(int(input())): n,l,r=map(int,input().split()) a=list(map(int,input().split())) le=dd(int) ri=dd(int) k=abs(l-r) k//=2 for i in range(l): le[a[i]]+=1 for i in range(l,n): ri[a[i]]+=1 ans=0 for i in ri.keys(): x=min(ri[i],le[i]) ri[i]-=x le[i]-=x if l>r: for i in le.keys(): m=le[i]//2 m=min(m,k) k-=m ans+=m le[i]-=2*m else: for i in ri.keys(): m=ri[i]//2 m=min(m,k) k-=m ans+=m ri[i]-=2*m k=abs(sum(le.values())-sum(ri.values())) x=min(sum(le.values()),sum(ri.values())) ans+=x ans+=k print(ans) ```
output
1
47,258
7
94,517
Provide tags and a correct Python 3 solution for this coding contest problem. To satisfy his love of matching socks, Phoenix has brought his n socks (n is even) to the sock store. Each of his socks has a color c_i and is either a left sock or right sock. Phoenix can pay one dollar to the sock store to either: * recolor a sock to any color c' (1 ≀ c' ≀ n) * turn a left sock into a right sock * turn a right sock into a left sock The sock store may perform each of these changes any number of times. Note that the color of a left sock doesn't change when it turns into a right sock, and vice versa. A matching pair of socks is a left and right sock with the same color. What is the minimum cost for Phoenix to make n/2 matching pairs? Each sock must be included in exactly one matching pair. Input The input consists of multiple test cases. The first line contains an integer t (1 ≀ t ≀ 1000) β€” the number of test cases. The first line of each test case contains three integers n, l, and r (2 ≀ n ≀ 2 β‹… 10^5; n is even; 0 ≀ l, r ≀ n; l+r=n) β€” the total number of socks, and the number of left and right socks, respectively. The next line contains n integers c_i (1 ≀ c_i ≀ n) β€” the colors of the socks. The first l socks are left socks, while the next r socks are right socks. It is guaranteed that the sum of n across all the test cases will not exceed 2 β‹… 10^5. Output For each test case, print one integer β€” the minimum cost for Phoenix to make n/2 matching pairs. Each sock must be included in exactly one matching pair. Example Input 4 6 3 3 1 2 3 2 2 2 6 2 4 1 1 2 2 2 2 6 5 1 6 5 4 3 2 1 4 0 4 4 4 4 3 Output 2 3 5 3 Note In the first test case, Phoenix can pay 2 dollars to: * recolor sock 1 to color 2 * recolor sock 3 to color 2 There are now 3 matching pairs. For example, pairs (1, 4), (2, 5), and (3, 6) are matching. In the second test case, Phoenix can pay 3 dollars to: * turn sock 6 from a right sock to a left sock * recolor sock 3 to color 1 * recolor sock 4 to color 1 There are now 3 matching pairs. For example, pairs (1, 3), (2, 4), and (5, 6) are matching.
instruction
0
47,259
7
94,518
Tags: greedy, sortings, two pointers Correct Solution: ``` from sys import stdin,stdout stdin.readline def mp(): return list(map(int, stdin.readline().strip().split())) def it():return int(stdin.readline().strip()) from collections import defaultdict as dd,Counter as C,deque from math import ceil,gcd,sqrt,factorial,log2,floor def fun(dr,temp): odd = 0 for i in dr.keys(): if dr[i]&1: odd += 1 if odd >= temp: for i in dr.keys(): if dr[i]&1 and temp: dr[i] -= 1 temp -= 1 else: for i in dr.keys(): if dr[i]&1 and temp: dr[i] -= 1 temp -= 1 for i in dr.keys(): if temp: if temp >= dr[i]: temp -= dr[i] dr[i] = 0 else: dr[i] -= temp temp = 0 else: break def fun2(dr): x = 0 ans = 0 for i in dr.keys(): if dr[i] and not dr[i]&1: ans += dr[i]//2 elif dr[i] and dr[i]&1: if x: ans += dr[i]//2 ans += 2 x = 0 else: ans += dr[i]//2 x = 1 return ans for _ in range(it()): n,l,r = mp() a = mp() left = a[:l] right = a[l:] dl = C(left) dr = C(right) for i in range(1,n+1): if dr[i] and dl[i]: temp = min(dl[i],dr[i]) dl[i] -= temp dr[i] -= temp ans = min(sum(dl.values()),sum(dr.values())) temp = ans if ans == sum(dl.values()): fun(dr,temp) print(ans + fun2(dr)) else: fun(dl,temp) print(ans+fun2(dl)) ```
output
1
47,259
7
94,519
Provide tags and a correct Python 3 solution for this coding contest problem. To satisfy his love of matching socks, Phoenix has brought his n socks (n is even) to the sock store. Each of his socks has a color c_i and is either a left sock or right sock. Phoenix can pay one dollar to the sock store to either: * recolor a sock to any color c' (1 ≀ c' ≀ n) * turn a left sock into a right sock * turn a right sock into a left sock The sock store may perform each of these changes any number of times. Note that the color of a left sock doesn't change when it turns into a right sock, and vice versa. A matching pair of socks is a left and right sock with the same color. What is the minimum cost for Phoenix to make n/2 matching pairs? Each sock must be included in exactly one matching pair. Input The input consists of multiple test cases. The first line contains an integer t (1 ≀ t ≀ 1000) β€” the number of test cases. The first line of each test case contains three integers n, l, and r (2 ≀ n ≀ 2 β‹… 10^5; n is even; 0 ≀ l, r ≀ n; l+r=n) β€” the total number of socks, and the number of left and right socks, respectively. The next line contains n integers c_i (1 ≀ c_i ≀ n) β€” the colors of the socks. The first l socks are left socks, while the next r socks are right socks. It is guaranteed that the sum of n across all the test cases will not exceed 2 β‹… 10^5. Output For each test case, print one integer β€” the minimum cost for Phoenix to make n/2 matching pairs. Each sock must be included in exactly one matching pair. Example Input 4 6 3 3 1 2 3 2 2 2 6 2 4 1 1 2 2 2 2 6 5 1 6 5 4 3 2 1 4 0 4 4 4 4 3 Output 2 3 5 3 Note In the first test case, Phoenix can pay 2 dollars to: * recolor sock 1 to color 2 * recolor sock 3 to color 2 There are now 3 matching pairs. For example, pairs (1, 4), (2, 5), and (3, 6) are matching. In the second test case, Phoenix can pay 3 dollars to: * turn sock 6 from a right sock to a left sock * recolor sock 3 to color 1 * recolor sock 4 to color 1 There are now 3 matching pairs. For example, pairs (1, 3), (2, 4), and (5, 6) are matching.
instruction
0
47,260
7
94,520
Tags: greedy, sortings, two pointers Correct Solution: ``` import sys input = sys.stdin.readline import math mod=10**9+7 ############ ---- Input Functions ---- ############ def inp(): return(int(input())) def inlt(): return(list(map(int,input().split()))) def insr(): s = input() return(list(s[:len(s) - 1])) def invr(): return(map(int,input().split())) for _ in range(inp()): n,l,r=invr() a=inlt() b=[] for i in range(l,n): b.append(a[i]) a=a[:l] a.sort() b.sort() a1=[0 for i in range(n)] b1 = a1[:] for i in range (l): a1[a[i]-1]+=1 for i in range(r): b1[b[i]-1]+=1 for i in range(n): m= min(a1[i],b1[i]) a1[i]-=m b1[i]-=m a=[] b=[] for i in range(n): for j in range(a1[i]): a.append(i+1) for j in range(b1[i]): b.append(i+1) l=len(a) r=len(b) if l<r: t=a a=b b=t l,r=r,l a.sort() b.sort() req=int((l+r)/2)-r c=req if req!=0: y=[] x=[[0,i+1] for i in range(n)] for i in range(l): x[a[i]-1][0]+=1 x.sort(key=lambda x:x[0]) x.reverse() g= n-1 for i in range (n): if x[i][0]==0: g= i-1 break p=0 while req>0: t=req req=max(req-(x[p][0]//2),0) for i in range(t-req): y.append(x[p][1]) if p== n-1: for i in range(req): req-=1 y.append(x[g-i][1]) p+=1 for i in y: b.append(i) y.sort() h=[1 for i in range(l)] p=0 g=len(y) for i in range(l): if a[i]==y[p]: h[i]=0 if p==g-1: break p+=1 t=[] for i in range(l): if h[i]==1: t.append(a[i]) a=t a.sort() b.sort() p=0 x=0 d=[0 for i in range(n)] n=(l+r) for i in range(int(n/2)): d[a[i]-1]+=1 for i in range(int(n/2)): if d[b[i]-1]!=0: d[b[i]-1]-=1 print(c+sum(d)) ```
output
1
47,260
7
94,521
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. To satisfy his love of matching socks, Phoenix has brought his n socks (n is even) to the sock store. Each of his socks has a color c_i and is either a left sock or right sock. Phoenix can pay one dollar to the sock store to either: * recolor a sock to any color c' (1 ≀ c' ≀ n) * turn a left sock into a right sock * turn a right sock into a left sock The sock store may perform each of these changes any number of times. Note that the color of a left sock doesn't change when it turns into a right sock, and vice versa. A matching pair of socks is a left and right sock with the same color. What is the minimum cost for Phoenix to make n/2 matching pairs? Each sock must be included in exactly one matching pair. Input The input consists of multiple test cases. The first line contains an integer t (1 ≀ t ≀ 1000) β€” the number of test cases. The first line of each test case contains three integers n, l, and r (2 ≀ n ≀ 2 β‹… 10^5; n is even; 0 ≀ l, r ≀ n; l+r=n) β€” the total number of socks, and the number of left and right socks, respectively. The next line contains n integers c_i (1 ≀ c_i ≀ n) β€” the colors of the socks. The first l socks are left socks, while the next r socks are right socks. It is guaranteed that the sum of n across all the test cases will not exceed 2 β‹… 10^5. Output For each test case, print one integer β€” the minimum cost for Phoenix to make n/2 matching pairs. Each sock must be included in exactly one matching pair. Example Input 4 6 3 3 1 2 3 2 2 2 6 2 4 1 1 2 2 2 2 6 5 1 6 5 4 3 2 1 4 0 4 4 4 4 3 Output 2 3 5 3 Note In the first test case, Phoenix can pay 2 dollars to: * recolor sock 1 to color 2 * recolor sock 3 to color 2 There are now 3 matching pairs. For example, pairs (1, 4), (2, 5), and (3, 6) are matching. In the second test case, Phoenix can pay 3 dollars to: * turn sock 6 from a right sock to a left sock * recolor sock 3 to color 1 * recolor sock 4 to color 1 There are now 3 matching pairs. For example, pairs (1, 3), (2, 4), and (5, 6) are matching. Submitted Solution: ``` #!/usr/bin/env python from __future__ import division, print_function import os import sys from collections import defaultdict from io import BytesIO, IOBase if sys.version_info[0] < 3: from __builtin__ import xrange as range from future_builtins import ascii, filter, hex, map, oct, zip def main(): t = int(input()) for _ in range(t): n, l, r = map(int, input().split()) l_socks = [0] * n r_socks = [0] * n for i, ci in enumerate(map(int, input().split())): if i < l: l_socks[ci - 1] += 1 else: r_socks[ci - 1] += 1 sol = 0 l_rem, r_rem = 0, 0 for i in range(n): if l > r and l_socks[i] > r_socks[i]: t = min((l_socks[i] - r_socks[i]) // 2, (l - r) // 2) l_socks[i] -= t r_socks[i] += t l -= t r += t sol += t elif r > l and r_socks[i] > l_socks[i]: t = min((r_socks[i] - l_socks[i]) // 2, (r - l) // 2) r_socks[i] -= t l_socks[i] += t r -= t l += t sol += t m = min(r_socks[i], l_socks[i]) l_socks[i] -= m r_socks[i] -= m l_rem += l_socks[i] r_rem += r_socks[i] print(sol + abs(l_rem - r_rem) // 2 + abs(l_rem + r_rem) // 2) # region fastio BUFSIZE = 8192 class FastIO(IOBase): newlines = 0 def __init__(self, file): self._fd = file.fileno() self.buffer = BytesIO() self.writable = "x" in file.mode or "r" not in file.mode self.write = self.buffer.write if self.writable else None def read(self): while True: b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE)) if not b: break ptr = self.buffer.tell() self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr) self.newlines = 0 return self.buffer.read() def readline(self): while self.newlines == 0: b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE)) self.newlines = b.count(b"\n") + (not b) ptr = self.buffer.tell() self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr) self.newlines -= 1 return self.buffer.readline() def flush(self): if self.writable: os.write(self._fd, self.buffer.getvalue()) self.buffer.truncate(0), self.buffer.seek(0) class IOWrapper(IOBase): def __init__(self, file): self.buffer = FastIO(file) self.flush = self.buffer.flush self.writable = self.buffer.writable self.write = lambda s: self.buffer.write(s.encode("ascii")) self.read = lambda: self.buffer.read().decode("ascii") self.readline = lambda: self.buffer.readline().decode("ascii") def print(*args, **kwargs): """Prints the values to a stream, or to sys.stdout by default.""" sep, file = kwargs.pop("sep", " "), kwargs.pop("file", sys.stdout) at_start = True for x in args: if not at_start: file.write(sep) file.write(str(x)) at_start = False file.write(kwargs.pop("end", "\n")) if kwargs.pop("flush", False): file.flush() if sys.version_info[0] < 3: sys.stdin, sys.stdout = FastIO(sys.stdin), FastIO(sys.stdout) else: sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout) input = lambda: sys.stdin.readline().rstrip("\r\n") # endregion if __name__ == "__main__": main() ```
instruction
0
47,261
7
94,522
Yes
output
1
47,261
7
94,523
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. To satisfy his love of matching socks, Phoenix has brought his n socks (n is even) to the sock store. Each of his socks has a color c_i and is either a left sock or right sock. Phoenix can pay one dollar to the sock store to either: * recolor a sock to any color c' (1 ≀ c' ≀ n) * turn a left sock into a right sock * turn a right sock into a left sock The sock store may perform each of these changes any number of times. Note that the color of a left sock doesn't change when it turns into a right sock, and vice versa. A matching pair of socks is a left and right sock with the same color. What is the minimum cost for Phoenix to make n/2 matching pairs? Each sock must be included in exactly one matching pair. Input The input consists of multiple test cases. The first line contains an integer t (1 ≀ t ≀ 1000) β€” the number of test cases. The first line of each test case contains three integers n, l, and r (2 ≀ n ≀ 2 β‹… 10^5; n is even; 0 ≀ l, r ≀ n; l+r=n) β€” the total number of socks, and the number of left and right socks, respectively. The next line contains n integers c_i (1 ≀ c_i ≀ n) β€” the colors of the socks. The first l socks are left socks, while the next r socks are right socks. It is guaranteed that the sum of n across all the test cases will not exceed 2 β‹… 10^5. Output For each test case, print one integer β€” the minimum cost for Phoenix to make n/2 matching pairs. Each sock must be included in exactly one matching pair. Example Input 4 6 3 3 1 2 3 2 2 2 6 2 4 1 1 2 2 2 2 6 5 1 6 5 4 3 2 1 4 0 4 4 4 4 3 Output 2 3 5 3 Note In the first test case, Phoenix can pay 2 dollars to: * recolor sock 1 to color 2 * recolor sock 3 to color 2 There are now 3 matching pairs. For example, pairs (1, 4), (2, 5), and (3, 6) are matching. In the second test case, Phoenix can pay 3 dollars to: * turn sock 6 from a right sock to a left sock * recolor sock 3 to color 1 * recolor sock 4 to color 1 There are now 3 matching pairs. For example, pairs (1, 3), (2, 4), and (5, 6) are matching. Submitted Solution: ``` import sys In = sys.stdin.readline T = int(In()) for tc in range(1, T + 1): n, l, r = map(int, In().split()) color = [0 for _ in range(n + 1)] socks = list(map(int, In().split())) visited = {} left, right = {"total": 0, "odd": 0}, {"total": 0, "odd": 0} answer = 0 for i in range(l): color[socks[i]] += 1 visited[socks[i]] = True for i in range(l, n): color[socks[i]] -= 1 visited[socks[i]] = True for key in visited.keys(): temp = color[key] if temp == 0: continue if temp > 0: left["total"] += temp if temp % 2 != 0: left["odd"] += 1 else: temp = -temp right["total"] += temp if temp % 2 != 0: right["odd"] += 1 if left["total"] >= right["total"]: answer += right["total"] left["odd"] -= right["total"] if left["odd"] > 0: answer += left["odd"] answer += (left["total"] - right["total"] - left["odd"]) // 2 else: answer += (left["total"] - right["total"]) // 2 else: answer += left["total"] right["odd"] -= left["total"] if right["odd"] > 0: answer += right["odd"] answer += (right["total"] - left["total"] - right["odd"]) // 2 else: answer += (right["total"] - left["total"]) // 2 print(answer) ```
instruction
0
47,262
7
94,524
Yes
output
1
47,262
7
94,525
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. To satisfy his love of matching socks, Phoenix has brought his n socks (n is even) to the sock store. Each of his socks has a color c_i and is either a left sock or right sock. Phoenix can pay one dollar to the sock store to either: * recolor a sock to any color c' (1 ≀ c' ≀ n) * turn a left sock into a right sock * turn a right sock into a left sock The sock store may perform each of these changes any number of times. Note that the color of a left sock doesn't change when it turns into a right sock, and vice versa. A matching pair of socks is a left and right sock with the same color. What is the minimum cost for Phoenix to make n/2 matching pairs? Each sock must be included in exactly one matching pair. Input The input consists of multiple test cases. The first line contains an integer t (1 ≀ t ≀ 1000) β€” the number of test cases. The first line of each test case contains three integers n, l, and r (2 ≀ n ≀ 2 β‹… 10^5; n is even; 0 ≀ l, r ≀ n; l+r=n) β€” the total number of socks, and the number of left and right socks, respectively. The next line contains n integers c_i (1 ≀ c_i ≀ n) β€” the colors of the socks. The first l socks are left socks, while the next r socks are right socks. It is guaranteed that the sum of n across all the test cases will not exceed 2 β‹… 10^5. Output For each test case, print one integer β€” the minimum cost for Phoenix to make n/2 matching pairs. Each sock must be included in exactly one matching pair. Example Input 4 6 3 3 1 2 3 2 2 2 6 2 4 1 1 2 2 2 2 6 5 1 6 5 4 3 2 1 4 0 4 4 4 4 3 Output 2 3 5 3 Note In the first test case, Phoenix can pay 2 dollars to: * recolor sock 1 to color 2 * recolor sock 3 to color 2 There are now 3 matching pairs. For example, pairs (1, 4), (2, 5), and (3, 6) are matching. In the second test case, Phoenix can pay 3 dollars to: * turn sock 6 from a right sock to a left sock * recolor sock 3 to color 1 * recolor sock 4 to color 1 There are now 3 matching pairs. For example, pairs (1, 3), (2, 4), and (5, 6) are matching. Submitted Solution: ``` # -*- coding: utf-8 -*- """ Created on Sun May 2 17:39:03 2021 @author: edwar """ import sys input = sys.stdin.readline def inp(): # integer return(int(input())) def inlt(): # list return(list(map(int,input().split()))) def insr(): # string s = input() return(list(s[:len(s) - 1])) def invr(): # space separated integers return(map(int,input().split())) tests = inp() for _ in range(tests): n,l,r = invr() c = inlt() colourCount = [[0,0] for _ in range(n)] for ii in range(l): colourCount[c[ii]-1][0] +=1 for ii in range(l,n): colourCount[c[ii]-1][1] +=1 totalCost = 0 spareLeft = 0 spareRight = 0 for col in colourCount: matches = min(col) col[0]-=matches col[1]-=matches if l>r: matches = min(col[0]//2,(l-r)//2) l-=matches r+=matches col[0]-=matches*2 totalCost+=matches elif r>l: matches = min(col[1]//2,(r-l)//2) l+=matches r-=matches col[1]-=matches*2 totalCost+=matches matches = min(col[0],spareRight) spareRight-=matches col[0]-=matches spareLeft+=col[0] totalCost+=matches matches = min(col[1],spareLeft) spareLeft-=matches col[1]-=matches spareRight+=col[1] totalCost+=matches totalCost+=(spareLeft+spareRight) print(totalCost) ```
instruction
0
47,263
7
94,526
Yes
output
1
47,263
7
94,527
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. To satisfy his love of matching socks, Phoenix has brought his n socks (n is even) to the sock store. Each of his socks has a color c_i and is either a left sock or right sock. Phoenix can pay one dollar to the sock store to either: * recolor a sock to any color c' (1 ≀ c' ≀ n) * turn a left sock into a right sock * turn a right sock into a left sock The sock store may perform each of these changes any number of times. Note that the color of a left sock doesn't change when it turns into a right sock, and vice versa. A matching pair of socks is a left and right sock with the same color. What is the minimum cost for Phoenix to make n/2 matching pairs? Each sock must be included in exactly one matching pair. Input The input consists of multiple test cases. The first line contains an integer t (1 ≀ t ≀ 1000) β€” the number of test cases. The first line of each test case contains three integers n, l, and r (2 ≀ n ≀ 2 β‹… 10^5; n is even; 0 ≀ l, r ≀ n; l+r=n) β€” the total number of socks, and the number of left and right socks, respectively. The next line contains n integers c_i (1 ≀ c_i ≀ n) β€” the colors of the socks. The first l socks are left socks, while the next r socks are right socks. It is guaranteed that the sum of n across all the test cases will not exceed 2 β‹… 10^5. Output For each test case, print one integer β€” the minimum cost for Phoenix to make n/2 matching pairs. Each sock must be included in exactly one matching pair. Example Input 4 6 3 3 1 2 3 2 2 2 6 2 4 1 1 2 2 2 2 6 5 1 6 5 4 3 2 1 4 0 4 4 4 4 3 Output 2 3 5 3 Note In the first test case, Phoenix can pay 2 dollars to: * recolor sock 1 to color 2 * recolor sock 3 to color 2 There are now 3 matching pairs. For example, pairs (1, 4), (2, 5), and (3, 6) are matching. In the second test case, Phoenix can pay 3 dollars to: * turn sock 6 from a right sock to a left sock * recolor sock 3 to color 1 * recolor sock 4 to color 1 There are now 3 matching pairs. For example, pairs (1, 3), (2, 4), and (5, 6) are matching. Submitted Solution: ``` from collections import Counter import sys input=sys.stdin.readline # "". join(strings) def ri(): return int(input()) def rl(): return list(map(int, input().split())) t = ri() for _ in range(t): # print("#"*50) n, l, r = rl() ss = rl() # if l > r: # ss = ss[::-1] # l, r = r, l ll = ss[:l] rr = ss[l:] L= Counter(ll) R = Counter(rr) All = Counter(ss) solution = 0 left_alone = 0 right_alone = 0 left_pairs = 0 right_pairs = 0 for k in All.keys(): if L[k] > R[k]: excess = L[k] - R[k] parity = excess % 2 left_alone += parity left_pairs += (excess-parity) elif L[k] < R[k]: excess = R[k] - L[k] parity = excess % 2 right_alone += parity right_pairs += (excess-parity) # if left_alone > right_alone: # left_alone, right_alone = right_alone, left_alone # print(left_pairs, left_alone, right_pairs, right_alone) if left_alone > right_alone: left_alone, left_pairs, right_alone, right_pairs = right_alone, right_pairs,left_alone, left_pairs # print(left_pairs, left_alone, right_pairs, right_alone) solution += left_alone right_alone -= left_alone left_alone = 0 # print("sol", solution) # print(left_pairs, left_alone, right_pairs, right_alone) if right_alone > left_pairs: solution += left_pairs right_alone -= left_pairs left_pairs = 0 solution += right_pairs//2 + right_alone else: solution += right_alone left_pairs -= right_alone solution += right_pairs//2 + left_pairs//2 # if left_alone > right_pairs: # solution += right_pairs # left_alone -= right_pairs # right_pairs = 0 # else: # solution += left_alone # right_pairs -= left_alone # left_alone = 0 # if right_alone > left_pairs: # solution += left_pairs # right_alone -= left_pairs # left_pairs = 0 # else: # solution += right_alone # left_pairs -= right_alone # right_alone = 0 # # print(left_pairs, left_alone, right_pairs, right_alone) # if left_alone > 0 and right_alone > 0: # mini = min(left_alone, right_alone) # maxi = max(left_alone, right_alone) # solution += maxi # elif left_alone > 0 and left_pairs > 0: # left_alone += left_pairs % 2 # left_pairs -= left_pairs % 2 # solution += left_pairs//2 + left_alone # elif right_alone > 0 and right_pairs > 0: # right_alone += right_pairs % 2 # right_pairs -= right_pairs % 2 # solution += right_pairs//2 + right_alone # elif left_pairs > 0 and right_pairs > 0: # if left_pairs % 2 == 1: # left_pairs -= 1 # right_pairs -= 1 # solution += 2 # solution += left_pairs//2 + right_pairs//2 print(solution) # solution += left_pairs //2 + right_pairs//2 + left_alone # excess = right_alone - left_alone # solution += excess # print(solution) ```
instruction
0
47,264
7
94,528
Yes
output
1
47,264
7
94,529
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. To satisfy his love of matching socks, Phoenix has brought his n socks (n is even) to the sock store. Each of his socks has a color c_i and is either a left sock or right sock. Phoenix can pay one dollar to the sock store to either: * recolor a sock to any color c' (1 ≀ c' ≀ n) * turn a left sock into a right sock * turn a right sock into a left sock The sock store may perform each of these changes any number of times. Note that the color of a left sock doesn't change when it turns into a right sock, and vice versa. A matching pair of socks is a left and right sock with the same color. What is the minimum cost for Phoenix to make n/2 matching pairs? Each sock must be included in exactly one matching pair. Input The input consists of multiple test cases. The first line contains an integer t (1 ≀ t ≀ 1000) β€” the number of test cases. The first line of each test case contains three integers n, l, and r (2 ≀ n ≀ 2 β‹… 10^5; n is even; 0 ≀ l, r ≀ n; l+r=n) β€” the total number of socks, and the number of left and right socks, respectively. The next line contains n integers c_i (1 ≀ c_i ≀ n) β€” the colors of the socks. The first l socks are left socks, while the next r socks are right socks. It is guaranteed that the sum of n across all the test cases will not exceed 2 β‹… 10^5. Output For each test case, print one integer β€” the minimum cost for Phoenix to make n/2 matching pairs. Each sock must be included in exactly one matching pair. Example Input 4 6 3 3 1 2 3 2 2 2 6 2 4 1 1 2 2 2 2 6 5 1 6 5 4 3 2 1 4 0 4 4 4 4 3 Output 2 3 5 3 Note In the first test case, Phoenix can pay 2 dollars to: * recolor sock 1 to color 2 * recolor sock 3 to color 2 There are now 3 matching pairs. For example, pairs (1, 4), (2, 5), and (3, 6) are matching. In the second test case, Phoenix can pay 3 dollars to: * turn sock 6 from a right sock to a left sock * recolor sock 3 to color 1 * recolor sock 4 to color 1 There are now 3 matching pairs. For example, pairs (1, 3), (2, 4), and (5, 6) are matching. Submitted Solution: ``` #def main(): # from sys import stdin, stdout # n, k = stdin.readline().split() # n = int(n) # k = int(k) # cnt = 0 # lines = stdin.readlines() # for line in lines: # if int(line) % k == 0: # cnt += 1 # stdout.write(str(cnt)) from sys import stdin,stdout def readInt(): return int(stdin.readline()) def readInts(): return map(int, stdin.readline().strip().split()) def readString(): return stdin.readline().strip() def writeLine(s): stdout.write(str(s)+'\n') return def main(): t=readInt() for _ in range(t): n,l,r=readInts() c=list(readInts()) ld={} rd={} for i in range(l): ld[c[i]]=ld.get(c[i],0)+1 for i in range(l,n): rd[c[i]]=rd.get(c[i],0)+1 diff={} for i in range(1,n+1): diff[i]=ld.get(i,0)-rd.get(i,0) res=0 sum=0 for key in diff: sum+=diff[key] res+=abs(sum) mc=0 for key in diff: mc+=diff[key]%2 res+=mc/2 writeLine(res) if __name__ == "__main__": main() ```
instruction
0
47,265
7
94,530
No
output
1
47,265
7
94,531
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. To satisfy his love of matching socks, Phoenix has brought his n socks (n is even) to the sock store. Each of his socks has a color c_i and is either a left sock or right sock. Phoenix can pay one dollar to the sock store to either: * recolor a sock to any color c' (1 ≀ c' ≀ n) * turn a left sock into a right sock * turn a right sock into a left sock The sock store may perform each of these changes any number of times. Note that the color of a left sock doesn't change when it turns into a right sock, and vice versa. A matching pair of socks is a left and right sock with the same color. What is the minimum cost for Phoenix to make n/2 matching pairs? Each sock must be included in exactly one matching pair. Input The input consists of multiple test cases. The first line contains an integer t (1 ≀ t ≀ 1000) β€” the number of test cases. The first line of each test case contains three integers n, l, and r (2 ≀ n ≀ 2 β‹… 10^5; n is even; 0 ≀ l, r ≀ n; l+r=n) β€” the total number of socks, and the number of left and right socks, respectively. The next line contains n integers c_i (1 ≀ c_i ≀ n) β€” the colors of the socks. The first l socks are left socks, while the next r socks are right socks. It is guaranteed that the sum of n across all the test cases will not exceed 2 β‹… 10^5. Output For each test case, print one integer β€” the minimum cost for Phoenix to make n/2 matching pairs. Each sock must be included in exactly one matching pair. Example Input 4 6 3 3 1 2 3 2 2 2 6 2 4 1 1 2 2 2 2 6 5 1 6 5 4 3 2 1 4 0 4 4 4 4 3 Output 2 3 5 3 Note In the first test case, Phoenix can pay 2 dollars to: * recolor sock 1 to color 2 * recolor sock 3 to color 2 There are now 3 matching pairs. For example, pairs (1, 4), (2, 5), and (3, 6) are matching. In the second test case, Phoenix can pay 3 dollars to: * turn sock 6 from a right sock to a left sock * recolor sock 3 to color 1 * recolor sock 4 to color 1 There are now 3 matching pairs. For example, pairs (1, 3), (2, 4), and (5, 6) are matching. Submitted Solution: ``` from sys import stdin,stdout stdin.readline def mp(): return list(map(int, stdin.readline().strip().split())) def it():return int(stdin.readline().strip()) from collections import defaultdict as dd,Counter as C,deque from math import ceil,gcd,sqrt,factorial,log2,floor def fun(dr,temp): odd = 0 for i in dr.keys(): if dr[i]&1: odd += 1 if odd >= temp: for i in dr.keys(): if dr[i]&1 and temp: dr[i] -= 1 temp -= 1 else: for i in dr.keys(): if dr[i]&1 and temp: dr[i] -= 1 temp -= 1 for i in dr.keys(): if temp: if temp >= dr[i]: temp -= dr[i] dr[i] = 0 else: dr[i] -= temp temp = 0 else: break for _ in range(it()): n,l,r = mp() a = mp() left = a[:l] right = a[l:] dl = C(left) dr = C(right) # print(dict(dl),dict(dr)) for i in range(1,n+1): if dr[i] and dl[i]: dl[i] -= min(dl[i],dr[i]) dr[i] -= min(dl[i],dr[i]) temp = ans = min(sum(dl.values()),sum(dr.values())) if ans == sum(dl.values()): fun(dr,temp) x = 0 for i in dr.keys(): if dr[i] and not dr[i]&1: ans += dr[i]//2 elif dr[i] and dr[i]&1: if x: ans += dr[i]//2 ans += 2 x = 0 else: ans += dr[i]//2 x = 1 else: fun(dl,temp) x = 0 for i in dl.keys(): if dl[i] and not dl[i]&1: ans += dl[i]//2 elif dl[i] and dl[i]&1: if x: ans += dl[i]//2 ans += 2 x=0 else: ans += dl[i]//2 x = 1 print(ans) ```
instruction
0
47,266
7
94,532
No
output
1
47,266
7
94,533
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. To satisfy his love of matching socks, Phoenix has brought his n socks (n is even) to the sock store. Each of his socks has a color c_i and is either a left sock or right sock. Phoenix can pay one dollar to the sock store to either: * recolor a sock to any color c' (1 ≀ c' ≀ n) * turn a left sock into a right sock * turn a right sock into a left sock The sock store may perform each of these changes any number of times. Note that the color of a left sock doesn't change when it turns into a right sock, and vice versa. A matching pair of socks is a left and right sock with the same color. What is the minimum cost for Phoenix to make n/2 matching pairs? Each sock must be included in exactly one matching pair. Input The input consists of multiple test cases. The first line contains an integer t (1 ≀ t ≀ 1000) β€” the number of test cases. The first line of each test case contains three integers n, l, and r (2 ≀ n ≀ 2 β‹… 10^5; n is even; 0 ≀ l, r ≀ n; l+r=n) β€” the total number of socks, and the number of left and right socks, respectively. The next line contains n integers c_i (1 ≀ c_i ≀ n) β€” the colors of the socks. The first l socks are left socks, while the next r socks are right socks. It is guaranteed that the sum of n across all the test cases will not exceed 2 β‹… 10^5. Output For each test case, print one integer β€” the minimum cost for Phoenix to make n/2 matching pairs. Each sock must be included in exactly one matching pair. Example Input 4 6 3 3 1 2 3 2 2 2 6 2 4 1 1 2 2 2 2 6 5 1 6 5 4 3 2 1 4 0 4 4 4 4 3 Output 2 3 5 3 Note In the first test case, Phoenix can pay 2 dollars to: * recolor sock 1 to color 2 * recolor sock 3 to color 2 There are now 3 matching pairs. For example, pairs (1, 4), (2, 5), and (3, 6) are matching. In the second test case, Phoenix can pay 3 dollars to: * turn sock 6 from a right sock to a left sock * recolor sock 3 to color 1 * recolor sock 4 to color 1 There are now 3 matching pairs. For example, pairs (1, 3), (2, 4), and (5, 6) are matching. Submitted Solution: ``` def solver(n, l, r, c): cost = 0 cnew = sorted([f'{color}_left' for color in c[:l]] + [f'{color}_rigth' for color in c[l:]]) cnewnew = [None for i in range(len(cnew))] counter = 0 for i in range(len(cnew)): if i > 0 and cnew[i] != cnew[i-1]: counter = 0 counter += 1 temp = cnew[i].split('_') cnewnew[i] = f'{temp[0]}_{counter}_{temp[1]}' cnew = sorted(cnewnew) #print(cnew) mask = [0 for i in range(len(cnew))] for i in range(1, len(cnew)): color_equal = cnew[i].split('_')[0] == cnew[i-1].split('_')[0] left_rigth = cnew[i].split('_')[2] != cnew[i-1].split('_')[2] if color_equal and left_rigth: mask[i] = 1 mask[i-1] = 1 cnew = [x for x, y in zip(cnew, mask) if y != 1] mask = [0 for i in range(len(cnew))] # ΠΈΠ·ΠΌΠ΅Π½ΠΈΡ‚ΡŒ Ρ‚ΠΎΠ»ΡŒΠΊΠΎ стороны for i in range(1, len(cnew)): if mask[i-1] == 1: continue color_equal = cnew[i].split('_')[0] == cnew[i-1].split('_')[0] if color_equal: mask[i] = 1 mask[i-1] = 1 cost += 1 continue left_rigth = cnew[i].split('_')[2] != cnew[i-1].split('_')[2] if left_rigth: mask[i] = 1 mask[i-1] = 1 cost += 1 cnew = [x for x, y in zip(cnew, mask) if y != 1] left_count = len([el for el in cnew if 'left' in el]) rigth_count = len([el for el in cnew if 'rigth' in el]) if left_count < rigth_count: left_count, rigth_count = rigth_count, left_count min_possible = min(left_count,rigth_count) cost += min_possible left_count -= min_possible if left_count > 0: cost += left_count #print(left_count, rigth_count, cnew, cost,min_possible) return str(cost) t = int(input()) answers = [] for i in range(t): n, l, r = list(map(int, input().split())) c = list(map(int, input().split())) ans = solver(n, l, r, c) answers.append(ans) print('\n'.join(answers)) ```
instruction
0
47,267
7
94,534
No
output
1
47,267
7
94,535
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. To satisfy his love of matching socks, Phoenix has brought his n socks (n is even) to the sock store. Each of his socks has a color c_i and is either a left sock or right sock. Phoenix can pay one dollar to the sock store to either: * recolor a sock to any color c' (1 ≀ c' ≀ n) * turn a left sock into a right sock * turn a right sock into a left sock The sock store may perform each of these changes any number of times. Note that the color of a left sock doesn't change when it turns into a right sock, and vice versa. A matching pair of socks is a left and right sock with the same color. What is the minimum cost for Phoenix to make n/2 matching pairs? Each sock must be included in exactly one matching pair. Input The input consists of multiple test cases. The first line contains an integer t (1 ≀ t ≀ 1000) β€” the number of test cases. The first line of each test case contains three integers n, l, and r (2 ≀ n ≀ 2 β‹… 10^5; n is even; 0 ≀ l, r ≀ n; l+r=n) β€” the total number of socks, and the number of left and right socks, respectively. The next line contains n integers c_i (1 ≀ c_i ≀ n) β€” the colors of the socks. The first l socks are left socks, while the next r socks are right socks. It is guaranteed that the sum of n across all the test cases will not exceed 2 β‹… 10^5. Output For each test case, print one integer β€” the minimum cost for Phoenix to make n/2 matching pairs. Each sock must be included in exactly one matching pair. Example Input 4 6 3 3 1 2 3 2 2 2 6 2 4 1 1 2 2 2 2 6 5 1 6 5 4 3 2 1 4 0 4 4 4 4 3 Output 2 3 5 3 Note In the first test case, Phoenix can pay 2 dollars to: * recolor sock 1 to color 2 * recolor sock 3 to color 2 There are now 3 matching pairs. For example, pairs (1, 4), (2, 5), and (3, 6) are matching. In the second test case, Phoenix can pay 3 dollars to: * turn sock 6 from a right sock to a left sock * recolor sock 3 to color 1 * recolor sock 4 to color 1 There are now 3 matching pairs. For example, pairs (1, 3), (2, 4), and (5, 6) are matching. Submitted Solution: ``` import math from collections import defaultdict from heapq import heappush, heappop DEBUG = True def log(*args, **kwargs): if DEBUG: print(*args, **kwargs) def ri(): return int(input()) def rl(f=int): return list(map(f, input().split())) def rs(): return input() class Solution: def __init__(self): pass def run(self): n, l, r = rl() c = rl() left = defaultdict(int) right = defaultdict(int) colors = set() for i in range(l): left[c[i]] += 1 colors.add(c[i]) for i in range(l, n): right[c[i]] += 1 colors.add(c[i]) #print(left) #print(right) #print('---') exleft = defaultdict(int) exright = defaultdict(int) result = 0 totalleft = 0 totalright = 0 for co in colors: diff = left[co] - right[co] if diff > 0: exleft[co] += diff totalleft += diff elif diff < 0: exright[co] += (-diff) totalright += (-diff) #print(exleft) #print(exright) #print('---') if totalleft == totalright: return totalleft largest = defaultdict(int) smallesttotal = min(totalleft, totalright) if totalleft > totalright: largest = exleft else: largest = exright #print(smallesttotal, largest) changed = 0 for k, v in sorted(largest.items(), key = lambda x: (int(not (x[1] % 2)), x[1])): #print(k, v, changed, min(v, smallesttotal - changed)) largest[k] -= min(v, smallesttotal - changed) changed += min(v, smallesttotal - changed) #print(largest[k]) #print(exleft) #print(exright) #print(changed, largest) #print('---') result += smallesttotal for k,v in largest.items(): result += v // 2 result += v % 2 return result if __name__ == '__main__': t = int(input()) s = Solution() #print(s.run()) #s.run() for i in range(t): # s.run() print(s.run()) ```
instruction
0
47,268
7
94,536
No
output
1
47,268
7
94,537
Provide tags and a correct Python 3 solution for this coding contest problem. In Berland, there is the national holiday coming β€” the Flag Day. In the honor of this event the president of the country decided to make a big dance party and asked your agency to organize it. He has several conditions: * overall, there must be m dances; * exactly three people must take part in each dance; * each dance must have one dancer in white clothes, one dancer in red clothes and one dancer in blue clothes (these are the colors of the national flag of Berland). The agency has n dancers, and their number can be less than 3m. That is, some dancers will probably have to dance in more than one dance. All of your dancers must dance on the party. However, if some dance has two or more dancers from a previous dance, then the current dance stops being spectacular. Your agency cannot allow that to happen, so each dance has at most one dancer who has danced in some previous dance. You considered all the criteria and made the plan for the m dances: each dance had three dancers participating in it. Your task is to determine the clothes color for each of the n dancers so that the President's third condition fulfilled: each dance must have a dancer in white, a dancer in red and a dancer in blue. The dancers cannot change clothes between the dances. Input The first line contains two space-separated integers n (3 ≀ n ≀ 105) and m (1 ≀ m ≀ 105) β€” the number of dancers and the number of dances, correspondingly. Then m lines follow, describing the dances in the order of dancing them. The i-th line contains three distinct integers β€” the numbers of the dancers that take part in the i-th dance. The dancers are numbered from 1 to n. Each dancer takes part in at least one dance. Output Print n space-separated integers: the i-th number must represent the color of the i-th dancer's clothes (1 for white, 2 for red, 3 for blue). If there are multiple valid solutions, print any of them. It is guaranteed that at least one solution exists. Examples Input 7 3 1 2 3 1 4 5 4 6 7 Output 1 2 3 3 2 2 1 Input 9 3 3 6 9 2 5 8 1 4 7 Output 1 1 1 2 2 2 3 3 3 Input 5 2 4 1 5 3 1 2 Output 2 3 1 1 3
instruction
0
47,374
7
94,748
Tags: constructive algorithms, implementation Correct Solution: ``` n,m=map(int,input().split()) ans=[-1]*(n+1) for k in range(m): dancers=list(map(int,input().split())) need=[1,2,3] for i in dancers: if(ans[i]!=-1): need.remove(ans[i]) for i in dancers: if(ans[i]==-1): ans[i]=need.pop(-1) print(*ans[1:]) ```
output
1
47,374
7
94,749
Provide tags and a correct Python 3 solution for this coding contest problem. In Berland, there is the national holiday coming β€” the Flag Day. In the honor of this event the president of the country decided to make a big dance party and asked your agency to organize it. He has several conditions: * overall, there must be m dances; * exactly three people must take part in each dance; * each dance must have one dancer in white clothes, one dancer in red clothes and one dancer in blue clothes (these are the colors of the national flag of Berland). The agency has n dancers, and their number can be less than 3m. That is, some dancers will probably have to dance in more than one dance. All of your dancers must dance on the party. However, if some dance has two or more dancers from a previous dance, then the current dance stops being spectacular. Your agency cannot allow that to happen, so each dance has at most one dancer who has danced in some previous dance. You considered all the criteria and made the plan for the m dances: each dance had three dancers participating in it. Your task is to determine the clothes color for each of the n dancers so that the President's third condition fulfilled: each dance must have a dancer in white, a dancer in red and a dancer in blue. The dancers cannot change clothes between the dances. Input The first line contains two space-separated integers n (3 ≀ n ≀ 105) and m (1 ≀ m ≀ 105) β€” the number of dancers and the number of dances, correspondingly. Then m lines follow, describing the dances in the order of dancing them. The i-th line contains three distinct integers β€” the numbers of the dancers that take part in the i-th dance. The dancers are numbered from 1 to n. Each dancer takes part in at least one dance. Output Print n space-separated integers: the i-th number must represent the color of the i-th dancer's clothes (1 for white, 2 for red, 3 for blue). If there are multiple valid solutions, print any of them. It is guaranteed that at least one solution exists. Examples Input 7 3 1 2 3 1 4 5 4 6 7 Output 1 2 3 3 2 2 1 Input 9 3 3 6 9 2 5 8 1 4 7 Output 1 1 1 2 2 2 3 3 3 Input 5 2 4 1 5 3 1 2 Output 2 3 1 1 3
instruction
0
47,375
7
94,750
Tags: constructive algorithms, implementation Correct Solution: ``` from sys import stdin,stdout stdin.readline def mp(): return list(map(int, stdin.readline().strip().split())) def it():return int(stdin.readline().strip()) from collections import defaultdict as dd,Counter as C,deque from math import ceil,gcd,sqrt,factorial,log2,floor from bisect import bisect_right as br,bisect_left as bl import heapq n,m = mp() d = dd(lambda:0) for _ in range(m): l = mp() s = set() s.add(1) s.add(2) s.add(3) for i in l: if d[i]: s.remove(d[i]) for i in l: if s and not d[i]: d[i] = s.pop() for i in sorted(d.keys()): print(d[i],end=' ') ```
output
1
47,375
7
94,751
Provide tags and a correct Python 3 solution for this coding contest problem. In Berland, there is the national holiday coming β€” the Flag Day. In the honor of this event the president of the country decided to make a big dance party and asked your agency to organize it. He has several conditions: * overall, there must be m dances; * exactly three people must take part in each dance; * each dance must have one dancer in white clothes, one dancer in red clothes and one dancer in blue clothes (these are the colors of the national flag of Berland). The agency has n dancers, and their number can be less than 3m. That is, some dancers will probably have to dance in more than one dance. All of your dancers must dance on the party. However, if some dance has two or more dancers from a previous dance, then the current dance stops being spectacular. Your agency cannot allow that to happen, so each dance has at most one dancer who has danced in some previous dance. You considered all the criteria and made the plan for the m dances: each dance had three dancers participating in it. Your task is to determine the clothes color for each of the n dancers so that the President's third condition fulfilled: each dance must have a dancer in white, a dancer in red and a dancer in blue. The dancers cannot change clothes between the dances. Input The first line contains two space-separated integers n (3 ≀ n ≀ 105) and m (1 ≀ m ≀ 105) β€” the number of dancers and the number of dances, correspondingly. Then m lines follow, describing the dances in the order of dancing them. The i-th line contains three distinct integers β€” the numbers of the dancers that take part in the i-th dance. The dancers are numbered from 1 to n. Each dancer takes part in at least one dance. Output Print n space-separated integers: the i-th number must represent the color of the i-th dancer's clothes (1 for white, 2 for red, 3 for blue). If there are multiple valid solutions, print any of them. It is guaranteed that at least one solution exists. Examples Input 7 3 1 2 3 1 4 5 4 6 7 Output 1 2 3 3 2 2 1 Input 9 3 3 6 9 2 5 8 1 4 7 Output 1 1 1 2 2 2 3 3 3 Input 5 2 4 1 5 3 1 2 Output 2 3 1 1 3
instruction
0
47,376
7
94,752
Tags: constructive algorithms, implementation Correct Solution: ``` n,m=map(int,input().split()) arr=[0 for i in range(n+1)] for i in range(m): x,y,z=map(int,input().split()) if([arr[x],arr[y],arr[z]]==[0,0,0]): arr[x],arr[y],arr[z]=1,2,3 else: ans=[1,2,3] if(arr[x]!=0): ans.remove(arr[x]) elif(arr[y]!=0): ans.remove(arr[y]) elif(arr[z]!=0): ans.remove(arr[z]) if(arr[x]==0): arr[x]=ans[0] ans.remove(ans[0]) if(arr[y]==0): arr[y]=ans[0] ans.remove(ans[0]) if(arr[z]==0): arr[z]=ans[0] ans.remove(ans[0]) print(*arr[1:]) ```
output
1
47,376
7
94,753
Provide tags and a correct Python 3 solution for this coding contest problem. In Berland, there is the national holiday coming β€” the Flag Day. In the honor of this event the president of the country decided to make a big dance party and asked your agency to organize it. He has several conditions: * overall, there must be m dances; * exactly three people must take part in each dance; * each dance must have one dancer in white clothes, one dancer in red clothes and one dancer in blue clothes (these are the colors of the national flag of Berland). The agency has n dancers, and their number can be less than 3m. That is, some dancers will probably have to dance in more than one dance. All of your dancers must dance on the party. However, if some dance has two or more dancers from a previous dance, then the current dance stops being spectacular. Your agency cannot allow that to happen, so each dance has at most one dancer who has danced in some previous dance. You considered all the criteria and made the plan for the m dances: each dance had three dancers participating in it. Your task is to determine the clothes color for each of the n dancers so that the President's third condition fulfilled: each dance must have a dancer in white, a dancer in red and a dancer in blue. The dancers cannot change clothes between the dances. Input The first line contains two space-separated integers n (3 ≀ n ≀ 105) and m (1 ≀ m ≀ 105) β€” the number of dancers and the number of dances, correspondingly. Then m lines follow, describing the dances in the order of dancing them. The i-th line contains three distinct integers β€” the numbers of the dancers that take part in the i-th dance. The dancers are numbered from 1 to n. Each dancer takes part in at least one dance. Output Print n space-separated integers: the i-th number must represent the color of the i-th dancer's clothes (1 for white, 2 for red, 3 for blue). If there are multiple valid solutions, print any of them. It is guaranteed that at least one solution exists. Examples Input 7 3 1 2 3 1 4 5 4 6 7 Output 1 2 3 3 2 2 1 Input 9 3 3 6 9 2 5 8 1 4 7 Output 1 1 1 2 2 2 3 3 3 Input 5 2 4 1 5 3 1 2 Output 2 3 1 1 3
instruction
0
47,377
7
94,754
Tags: constructive algorithms, implementation Correct Solution: ``` def main(): n, m = [int(i) for i in input().split()] colors = [0 for i in range(n + 1)] for i in range(m): arr = [int(i) for i in input().split()] early = colors[arr[0]] or colors[arr[1]] or colors[arr[2]] l = [1, 2, 3] if early: l.remove(early) for i in arr: if colors[i] == 0: colors[i] = l.pop() print(' '.join(str(colors[i]) for i in range(1, n + 1))) main() ```
output
1
47,377
7
94,755
Provide tags and a correct Python 3 solution for this coding contest problem. In Berland, there is the national holiday coming β€” the Flag Day. In the honor of this event the president of the country decided to make a big dance party and asked your agency to organize it. He has several conditions: * overall, there must be m dances; * exactly three people must take part in each dance; * each dance must have one dancer in white clothes, one dancer in red clothes and one dancer in blue clothes (these are the colors of the national flag of Berland). The agency has n dancers, and their number can be less than 3m. That is, some dancers will probably have to dance in more than one dance. All of your dancers must dance on the party. However, if some dance has two or more dancers from a previous dance, then the current dance stops being spectacular. Your agency cannot allow that to happen, so each dance has at most one dancer who has danced in some previous dance. You considered all the criteria and made the plan for the m dances: each dance had three dancers participating in it. Your task is to determine the clothes color for each of the n dancers so that the President's third condition fulfilled: each dance must have a dancer in white, a dancer in red and a dancer in blue. The dancers cannot change clothes between the dances. Input The first line contains two space-separated integers n (3 ≀ n ≀ 105) and m (1 ≀ m ≀ 105) β€” the number of dancers and the number of dances, correspondingly. Then m lines follow, describing the dances in the order of dancing them. The i-th line contains three distinct integers β€” the numbers of the dancers that take part in the i-th dance. The dancers are numbered from 1 to n. Each dancer takes part in at least one dance. Output Print n space-separated integers: the i-th number must represent the color of the i-th dancer's clothes (1 for white, 2 for red, 3 for blue). If there are multiple valid solutions, print any of them. It is guaranteed that at least one solution exists. Examples Input 7 3 1 2 3 1 4 5 4 6 7 Output 1 2 3 3 2 2 1 Input 9 3 3 6 9 2 5 8 1 4 7 Output 1 1 1 2 2 2 3 3 3 Input 5 2 4 1 5 3 1 2 Output 2 3 1 1 3
instruction
0
47,378
7
94,756
Tags: constructive algorithms, implementation Correct Solution: ``` n,m = map(int,input().split(' ')) result,participated = [None]*n,{} #dancer : color for x in range(m): dancers = [int(i) for i in input().split(' ')] colors,temp = set([1,2,3]),-1 for d in range(3): if dancers[d] in participated: colors.remove(participated[dancers[d]]) temp = d it = iter(colors) for i in range(3): t = dancers[i] if i != temp: result[dancers[i] - 1] = next(it) participated[t] = result[dancers[i] - 1] print(*result) ''' Każdy taniec musi się składać z kolorów 1,2,3. Taniec - 3 osoby, m tańców. Każdy taniec może mieć max 1 tańcerza z poprzednich tańców. Na podstawie tych warunków musimy ubrać wyznaczonych tańcerzy do tańców. jeżeli n = 3m tzn że możemy każdą oddzielną trójkę wyznaczyć do innego tańca i ubrać ich wszystkich wyznaczony patern (1,2,3) od 1 do n-tego tancerza. join('1,2,3') * 3 * m. solution: O(m) Zawsze w trójce będzie maksymalnie 1 powtarzający się a tzn że musimy w takim przypadku dostoswać dwóch pozostałych w trójce pod niego. W przypadku unikalnej trójki, po prostu 1,2,3. implementacja: lista ludzi którzy już tańczyli = hashmap{[1-n]:[1-3]} Wczytując trójkę: najpierw staramy się wykryć potencjalnie jednego uczestnika który już brał udział w poprzednim tańcu. Jeżeli go wykryjemy, spr jego strój i dodajemy odpowiednią kombinacje do rezultatu: .join(wykryty,dwa pozostałe) Jeżeli nie: dodajemy do rezultatu (1,2,3). Dodajemy do zbioru uczestników i ich stroje. ''' ```
output
1
47,378
7
94,757
Provide tags and a correct Python 3 solution for this coding contest problem. In Berland, there is the national holiday coming β€” the Flag Day. In the honor of this event the president of the country decided to make a big dance party and asked your agency to organize it. He has several conditions: * overall, there must be m dances; * exactly three people must take part in each dance; * each dance must have one dancer in white clothes, one dancer in red clothes and one dancer in blue clothes (these are the colors of the national flag of Berland). The agency has n dancers, and their number can be less than 3m. That is, some dancers will probably have to dance in more than one dance. All of your dancers must dance on the party. However, if some dance has two or more dancers from a previous dance, then the current dance stops being spectacular. Your agency cannot allow that to happen, so each dance has at most one dancer who has danced in some previous dance. You considered all the criteria and made the plan for the m dances: each dance had three dancers participating in it. Your task is to determine the clothes color for each of the n dancers so that the President's third condition fulfilled: each dance must have a dancer in white, a dancer in red and a dancer in blue. The dancers cannot change clothes between the dances. Input The first line contains two space-separated integers n (3 ≀ n ≀ 105) and m (1 ≀ m ≀ 105) β€” the number of dancers and the number of dances, correspondingly. Then m lines follow, describing the dances in the order of dancing them. The i-th line contains three distinct integers β€” the numbers of the dancers that take part in the i-th dance. The dancers are numbered from 1 to n. Each dancer takes part in at least one dance. Output Print n space-separated integers: the i-th number must represent the color of the i-th dancer's clothes (1 for white, 2 for red, 3 for blue). If there are multiple valid solutions, print any of them. It is guaranteed that at least one solution exists. Examples Input 7 3 1 2 3 1 4 5 4 6 7 Output 1 2 3 3 2 2 1 Input 9 3 3 6 9 2 5 8 1 4 7 Output 1 1 1 2 2 2 3 3 3 Input 5 2 4 1 5 3 1 2 Output 2 3 1 1 3
instruction
0
47,379
7
94,758
Tags: constructive algorithms, implementation Correct Solution: ``` n,m=map(int,input().split()) ans=[-1]*(n+1) for _ in range(m): dancers=list(map(int,input().split())) need=[1,2,3] for i in dancers: if(ans[i]!=-1): need.remove(ans[i]) for i in dancers: if(ans[i]==-1): ans[i]=need.pop(-1) print(*ans[1:]) ```
output
1
47,379
7
94,759
Provide tags and a correct Python 3 solution for this coding contest problem. In Berland, there is the national holiday coming β€” the Flag Day. In the honor of this event the president of the country decided to make a big dance party and asked your agency to organize it. He has several conditions: * overall, there must be m dances; * exactly three people must take part in each dance; * each dance must have one dancer in white clothes, one dancer in red clothes and one dancer in blue clothes (these are the colors of the national flag of Berland). The agency has n dancers, and their number can be less than 3m. That is, some dancers will probably have to dance in more than one dance. All of your dancers must dance on the party. However, if some dance has two or more dancers from a previous dance, then the current dance stops being spectacular. Your agency cannot allow that to happen, so each dance has at most one dancer who has danced in some previous dance. You considered all the criteria and made the plan for the m dances: each dance had three dancers participating in it. Your task is to determine the clothes color for each of the n dancers so that the President's third condition fulfilled: each dance must have a dancer in white, a dancer in red and a dancer in blue. The dancers cannot change clothes between the dances. Input The first line contains two space-separated integers n (3 ≀ n ≀ 105) and m (1 ≀ m ≀ 105) β€” the number of dancers and the number of dances, correspondingly. Then m lines follow, describing the dances in the order of dancing them. The i-th line contains three distinct integers β€” the numbers of the dancers that take part in the i-th dance. The dancers are numbered from 1 to n. Each dancer takes part in at least one dance. Output Print n space-separated integers: the i-th number must represent the color of the i-th dancer's clothes (1 for white, 2 for red, 3 for blue). If there are multiple valid solutions, print any of them. It is guaranteed that at least one solution exists. Examples Input 7 3 1 2 3 1 4 5 4 6 7 Output 1 2 3 3 2 2 1 Input 9 3 3 6 9 2 5 8 1 4 7 Output 1 1 1 2 2 2 3 3 3 Input 5 2 4 1 5 3 1 2 Output 2 3 1 1 3
instruction
0
47,380
7
94,760
Tags: constructive algorithms, implementation Correct Solution: ``` n,m=map(int,input().split()) li=[] for i in range(m): li.append([int(x) for x in input().split()]) d={} for i in range(m): x=li[i] use=[True]*3 l=[] for ele in x: if d.get(ele,0)!=0: use[d.get(ele)-1]=False for i in range(3): if use[i]==True: l.append(i) for ele in x: if d.get(ele,0)==0: d[ele]=l.pop()+1 for ele in sorted(d): print(d[ele],end=" ") ```
output
1
47,380
7
94,761
Provide tags and a correct Python 3 solution for this coding contest problem. In Berland, there is the national holiday coming β€” the Flag Day. In the honor of this event the president of the country decided to make a big dance party and asked your agency to organize it. He has several conditions: * overall, there must be m dances; * exactly three people must take part in each dance; * each dance must have one dancer in white clothes, one dancer in red clothes and one dancer in blue clothes (these are the colors of the national flag of Berland). The agency has n dancers, and their number can be less than 3m. That is, some dancers will probably have to dance in more than one dance. All of your dancers must dance on the party. However, if some dance has two or more dancers from a previous dance, then the current dance stops being spectacular. Your agency cannot allow that to happen, so each dance has at most one dancer who has danced in some previous dance. You considered all the criteria and made the plan for the m dances: each dance had three dancers participating in it. Your task is to determine the clothes color for each of the n dancers so that the President's third condition fulfilled: each dance must have a dancer in white, a dancer in red and a dancer in blue. The dancers cannot change clothes between the dances. Input The first line contains two space-separated integers n (3 ≀ n ≀ 105) and m (1 ≀ m ≀ 105) β€” the number of dancers and the number of dances, correspondingly. Then m lines follow, describing the dances in the order of dancing them. The i-th line contains three distinct integers β€” the numbers of the dancers that take part in the i-th dance. The dancers are numbered from 1 to n. Each dancer takes part in at least one dance. Output Print n space-separated integers: the i-th number must represent the color of the i-th dancer's clothes (1 for white, 2 for red, 3 for blue). If there are multiple valid solutions, print any of them. It is guaranteed that at least one solution exists. Examples Input 7 3 1 2 3 1 4 5 4 6 7 Output 1 2 3 3 2 2 1 Input 9 3 3 6 9 2 5 8 1 4 7 Output 1 1 1 2 2 2 3 3 3 Input 5 2 4 1 5 3 1 2 Output 2 3 1 1 3
instruction
0
47,381
7
94,762
Tags: constructive algorithms, implementation Correct Solution: ``` n, m = map(int, input().split()) l = [-1]*n for i in range(m): a, b, c = map(int, input().split()) if(l[a-1] == -1 and l[b-1] == -1 and l[c-1] == -1): l[a-1] = 1 l[b-1] = 2 l[c-1] = 3 elif(l[a-1] == -1 and l[b-1] == -1): k = [1, 2, 3] k.remove(l[c-1]) l[a-1] = k[0] l[b-1] = k[1] elif(l[c-1] == -1 and l[b-1] == -1): k = [1, 2, 3] k.remove(l[a-1]) l[c-1] = k[0] l[b-1] = k[1] elif(l[a-1] == -1 and l[c-1] == -1): k = [1, 2, 3] k.remove(l[b-1]) l[a-1] = k[0] l[c-1] = k[1] print(*l) ```
output
1
47,381
7
94,763
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. In Berland, there is the national holiday coming β€” the Flag Day. In the honor of this event the president of the country decided to make a big dance party and asked your agency to organize it. He has several conditions: * overall, there must be m dances; * exactly three people must take part in each dance; * each dance must have one dancer in white clothes, one dancer in red clothes and one dancer in blue clothes (these are the colors of the national flag of Berland). The agency has n dancers, and their number can be less than 3m. That is, some dancers will probably have to dance in more than one dance. All of your dancers must dance on the party. However, if some dance has two or more dancers from a previous dance, then the current dance stops being spectacular. Your agency cannot allow that to happen, so each dance has at most one dancer who has danced in some previous dance. You considered all the criteria and made the plan for the m dances: each dance had three dancers participating in it. Your task is to determine the clothes color for each of the n dancers so that the President's third condition fulfilled: each dance must have a dancer in white, a dancer in red and a dancer in blue. The dancers cannot change clothes between the dances. Input The first line contains two space-separated integers n (3 ≀ n ≀ 105) and m (1 ≀ m ≀ 105) β€” the number of dancers and the number of dances, correspondingly. Then m lines follow, describing the dances in the order of dancing them. The i-th line contains three distinct integers β€” the numbers of the dancers that take part in the i-th dance. The dancers are numbered from 1 to n. Each dancer takes part in at least one dance. Output Print n space-separated integers: the i-th number must represent the color of the i-th dancer's clothes (1 for white, 2 for red, 3 for blue). If there are multiple valid solutions, print any of them. It is guaranteed that at least one solution exists. Examples Input 7 3 1 2 3 1 4 5 4 6 7 Output 1 2 3 3 2 2 1 Input 9 3 3 6 9 2 5 8 1 4 7 Output 1 1 1 2 2 2 3 3 3 Input 5 2 4 1 5 3 1 2 Output 2 3 1 1 3 Submitted Solution: ``` n, m = map(int, input().split()) res = [0] * (n + 1) for _ in range(m): arr = list(map(int, input().split())) for i in range(3): if res[arr[i]] == 1: res[arr[(i + 1) % 3]] = 2 res[arr[(i + 2) % 3]] = 3 break elif res[arr[i]] == 2: res[arr[(i + 1) % 3]] = 1 res[arr[(i + 2) % 3]] = 3 break elif res[arr[i]] == 3: res[arr[(i + 1) % 3]] = 1 res[arr[(i + 2) % 3]] = 2 break if not res[arr[0]]: res[arr[0]], res[arr[1]], res[arr[2]] = 1, 2, 3 print(*res[1:]) ```
instruction
0
47,382
7
94,764
Yes
output
1
47,382
7
94,765
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. In Berland, there is the national holiday coming β€” the Flag Day. In the honor of this event the president of the country decided to make a big dance party and asked your agency to organize it. He has several conditions: * overall, there must be m dances; * exactly three people must take part in each dance; * each dance must have one dancer in white clothes, one dancer in red clothes and one dancer in blue clothes (these are the colors of the national flag of Berland). The agency has n dancers, and their number can be less than 3m. That is, some dancers will probably have to dance in more than one dance. All of your dancers must dance on the party. However, if some dance has two or more dancers from a previous dance, then the current dance stops being spectacular. Your agency cannot allow that to happen, so each dance has at most one dancer who has danced in some previous dance. You considered all the criteria and made the plan for the m dances: each dance had three dancers participating in it. Your task is to determine the clothes color for each of the n dancers so that the President's third condition fulfilled: each dance must have a dancer in white, a dancer in red and a dancer in blue. The dancers cannot change clothes between the dances. Input The first line contains two space-separated integers n (3 ≀ n ≀ 105) and m (1 ≀ m ≀ 105) β€” the number of dancers and the number of dances, correspondingly. Then m lines follow, describing the dances in the order of dancing them. The i-th line contains three distinct integers β€” the numbers of the dancers that take part in the i-th dance. The dancers are numbered from 1 to n. Each dancer takes part in at least one dance. Output Print n space-separated integers: the i-th number must represent the color of the i-th dancer's clothes (1 for white, 2 for red, 3 for blue). If there are multiple valid solutions, print any of them. It is guaranteed that at least one solution exists. Examples Input 7 3 1 2 3 1 4 5 4 6 7 Output 1 2 3 3 2 2 1 Input 9 3 3 6 9 2 5 8 1 4 7 Output 1 1 1 2 2 2 3 3 3 Input 5 2 4 1 5 3 1 2 Output 2 3 1 1 3 Submitted Solution: ``` import sys; nbDancers, nbDances = map(int, sys.stdin.readline().split(' ')); dancers = [0]*(nbDancers+1); for line in sys.stdin: taken = [False, False, False, False]; ds = list(map(int, line.split(' '))); for d in ds: taken[dancers[d]] = True; for d in ds: if dancers[d] == 0: if not taken[1]: dancers[d] = 1; taken[1] = True; elif not taken[2]: dancers[d] = 2; taken[2] = True; elif not taken[3]: dancers[d] = 3; taken[3] = True; print(' '.join(map(str, dancers[1:]))); ```
instruction
0
47,383
7
94,766
Yes
output
1
47,383
7
94,767
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. In Berland, there is the national holiday coming β€” the Flag Day. In the honor of this event the president of the country decided to make a big dance party and asked your agency to organize it. He has several conditions: * overall, there must be m dances; * exactly three people must take part in each dance; * each dance must have one dancer in white clothes, one dancer in red clothes and one dancer in blue clothes (these are the colors of the national flag of Berland). The agency has n dancers, and their number can be less than 3m. That is, some dancers will probably have to dance in more than one dance. All of your dancers must dance on the party. However, if some dance has two or more dancers from a previous dance, then the current dance stops being spectacular. Your agency cannot allow that to happen, so each dance has at most one dancer who has danced in some previous dance. You considered all the criteria and made the plan for the m dances: each dance had three dancers participating in it. Your task is to determine the clothes color for each of the n dancers so that the President's third condition fulfilled: each dance must have a dancer in white, a dancer in red and a dancer in blue. The dancers cannot change clothes between the dances. Input The first line contains two space-separated integers n (3 ≀ n ≀ 105) and m (1 ≀ m ≀ 105) β€” the number of dancers and the number of dances, correspondingly. Then m lines follow, describing the dances in the order of dancing them. The i-th line contains three distinct integers β€” the numbers of the dancers that take part in the i-th dance. The dancers are numbered from 1 to n. Each dancer takes part in at least one dance. Output Print n space-separated integers: the i-th number must represent the color of the i-th dancer's clothes (1 for white, 2 for red, 3 for blue). If there are multiple valid solutions, print any of them. It is guaranteed that at least one solution exists. Examples Input 7 3 1 2 3 1 4 5 4 6 7 Output 1 2 3 3 2 2 1 Input 9 3 3 6 9 2 5 8 1 4 7 Output 1 1 1 2 2 2 3 3 3 Input 5 2 4 1 5 3 1 2 Output 2 3 1 1 3 Submitted Solution: ``` import sys; nbDancers, nbDances = map(int, sys.stdin.readline().split(' ')); dancers = [0]*(nbDancers+1); for line in sys.stdin: taken = [False, False, False, False]; ds = list(map(int, line.split(' '))); for d in ds: taken[dancers[d]] = True; for d in ds: if dancers[d] == 0: iCurr = 1; while iCurr <= 3 and taken[iCurr]: iCurr += 1; dancers[d] = iCurr; taken[iCurr] = True; print(' '.join(map(str, dancers[1:]))); ```
instruction
0
47,384
7
94,768
Yes
output
1
47,384
7
94,769
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. In Berland, there is the national holiday coming β€” the Flag Day. In the honor of this event the president of the country decided to make a big dance party and asked your agency to organize it. He has several conditions: * overall, there must be m dances; * exactly three people must take part in each dance; * each dance must have one dancer in white clothes, one dancer in red clothes and one dancer in blue clothes (these are the colors of the national flag of Berland). The agency has n dancers, and their number can be less than 3m. That is, some dancers will probably have to dance in more than one dance. All of your dancers must dance on the party. However, if some dance has two or more dancers from a previous dance, then the current dance stops being spectacular. Your agency cannot allow that to happen, so each dance has at most one dancer who has danced in some previous dance. You considered all the criteria and made the plan for the m dances: each dance had three dancers participating in it. Your task is to determine the clothes color for each of the n dancers so that the President's third condition fulfilled: each dance must have a dancer in white, a dancer in red and a dancer in blue. The dancers cannot change clothes between the dances. Input The first line contains two space-separated integers n (3 ≀ n ≀ 105) and m (1 ≀ m ≀ 105) β€” the number of dancers and the number of dances, correspondingly. Then m lines follow, describing the dances in the order of dancing them. The i-th line contains three distinct integers β€” the numbers of the dancers that take part in the i-th dance. The dancers are numbered from 1 to n. Each dancer takes part in at least one dance. Output Print n space-separated integers: the i-th number must represent the color of the i-th dancer's clothes (1 for white, 2 for red, 3 for blue). If there are multiple valid solutions, print any of them. It is guaranteed that at least one solution exists. Examples Input 7 3 1 2 3 1 4 5 4 6 7 Output 1 2 3 3 2 2 1 Input 9 3 3 6 9 2 5 8 1 4 7 Output 1 1 1 2 2 2 3 3 3 Input 5 2 4 1 5 3 1 2 Output 2 3 1 1 3 Submitted Solution: ``` from math import gcd def take_input(s): #for integer inputs if s == 1: return int(input()) return map(int, input().split()) n,m = take_input(2) grid = [] d = {} for i in range(m): grid += list(take_input(3)) for i in range(0,m*3,3): if d.get(grid[i],0) > 0: if d.get(grid[i],0) == 1: d[grid[i+1]] = 2 d[grid[i+2]] = 3 elif d.get(grid[i],0) == 2: d[grid[i+1]] = 1 d[grid[i+2]] = 3 else: d[grid[i+1]] = 1 d[grid[i+2]] = 2 elif d.get(grid[i+1],0) > 0: if d.get(grid[i+1],0) == 1: d[grid[i]] = 2 d[grid[i+2]] = 3 elif d.get(grid[i+1],0) == 2: d[grid[i]] = 1 d[grid[i+2]] = 3 else: d[grid[i]] = 1 d[grid[i+2]] = 2 elif d.get(grid[i+2],0) > 0: if d.get(grid[i+2],0) == 1: d[grid[i]] = 2 d[grid[i+1]] = 3 elif d.get(grid[i+2],0) == 2: d[grid[i]] = 1 d[grid[i+1]] = 3 else: d[grid[i]] = 1 d[grid[i+1]] = 2 else: d[grid[i]] = 1 d[grid[i+1]] = 2 d[grid[i+2]] = 3 for i in range(n): print(d[i+1], end = " ") ```
instruction
0
47,385
7
94,770
Yes
output
1
47,385
7
94,771
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. In Berland, there is the national holiday coming β€” the Flag Day. In the honor of this event the president of the country decided to make a big dance party and asked your agency to organize it. He has several conditions: * overall, there must be m dances; * exactly three people must take part in each dance; * each dance must have one dancer in white clothes, one dancer in red clothes and one dancer in blue clothes (these are the colors of the national flag of Berland). The agency has n dancers, and their number can be less than 3m. That is, some dancers will probably have to dance in more than one dance. All of your dancers must dance on the party. However, if some dance has two or more dancers from a previous dance, then the current dance stops being spectacular. Your agency cannot allow that to happen, so each dance has at most one dancer who has danced in some previous dance. You considered all the criteria and made the plan for the m dances: each dance had three dancers participating in it. Your task is to determine the clothes color for each of the n dancers so that the President's third condition fulfilled: each dance must have a dancer in white, a dancer in red and a dancer in blue. The dancers cannot change clothes between the dances. Input The first line contains two space-separated integers n (3 ≀ n ≀ 105) and m (1 ≀ m ≀ 105) β€” the number of dancers and the number of dances, correspondingly. Then m lines follow, describing the dances in the order of dancing them. The i-th line contains three distinct integers β€” the numbers of the dancers that take part in the i-th dance. The dancers are numbered from 1 to n. Each dancer takes part in at least one dance. Output Print n space-separated integers: the i-th number must represent the color of the i-th dancer's clothes (1 for white, 2 for red, 3 for blue). If there are multiple valid solutions, print any of them. It is guaranteed that at least one solution exists. Examples Input 7 3 1 2 3 1 4 5 4 6 7 Output 1 2 3 3 2 2 1 Input 9 3 3 6 9 2 5 8 1 4 7 Output 1 1 1 2 2 2 3 3 3 Input 5 2 4 1 5 3 1 2 Output 2 3 1 1 3 Submitted Solution: ``` n,m = map(int,input().split(' ')) result,participated = [],{} #dancer : color for x in range(m): dancers = [int(i) for i in input().split(' ')] colors,temp = set([1,2,3]),-1 for d in range(3): if dancers[d] in participated: dancers[d] = participated[dancers[d]] colors.remove(dancers[d]) temp = d it = iter(colors) for i in range(3): t = dancers[i] if i != temp: dancers[i] = next(it) participated[t] = dancers[i] result.extend(dancers) print(*result) ''' KaΕΌdy taniec musi siΔ™ skΕ‚adaΔ‡ z kolorΓ³w 1,2,3. Taniec - 3 osoby, m taΕ„cΓ³w. KaΕΌdy taniec moΕΌe mieΔ‡ max 1 taΕ„cerza z poprzednich taΕ„cΓ³w. Na podstawie tych warunkΓ³w musimy ubraΔ‡ wyznaczonych taΕ„cerzy do taΕ„cΓ³w. jeΕΌeli n = 3m tzn ΕΌe moΕΌemy kaΕΌdΔ… oddzielnΔ… trΓ³jkΔ™ wyznaczyΔ‡ do innego taΕ„ca i ubraΔ‡ ich wszystkich wyznaczony patern (1,2,3) od 1 do n-tego tancerza. join('1,2,3') * 3 * m. solution: O(m) Zawsze w trΓ³jce bΔ™dzie maksymalnie 1 powtarzajΔ…cy siΔ™ a tzn ΕΌe musimy w takim przypadku dostoswaΔ‡ dwΓ³ch pozostaΕ‚ych w trΓ³jce pod niego. W przypadku unikalnej trΓ³jki, po prostu 1,2,3. implementacja: lista ludzi ktΓ³rzy juΕΌ taΕ„czyli = hashmap{[1-n]:[1-3]} WczytujΔ…c trΓ³jkΔ™: najpierw staramy siΔ™ wykryΔ‡ potencjalnie jednego uczestnika ktΓ³ry juΕΌ braΕ‚ udziaΕ‚ w poprzednim taΕ„cu. JeΕΌeli go wykryjemy, spr jego strΓ³j i dodajemy odpowiedniΔ… kombinacje do rezultatu: .join(wykryty,dwa pozostaΕ‚e) JeΕΌeli nie: dodajemy do rezultatu (1,2,3). Dodajemy do zbioru uczestnikΓ³w i ich stroje. ''' ```
instruction
0
47,386
7
94,772
No
output
1
47,386
7
94,773
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. In Berland, there is the national holiday coming β€” the Flag Day. In the honor of this event the president of the country decided to make a big dance party and asked your agency to organize it. He has several conditions: * overall, there must be m dances; * exactly three people must take part in each dance; * each dance must have one dancer in white clothes, one dancer in red clothes and one dancer in blue clothes (these are the colors of the national flag of Berland). The agency has n dancers, and their number can be less than 3m. That is, some dancers will probably have to dance in more than one dance. All of your dancers must dance on the party. However, if some dance has two or more dancers from a previous dance, then the current dance stops being spectacular. Your agency cannot allow that to happen, so each dance has at most one dancer who has danced in some previous dance. You considered all the criteria and made the plan for the m dances: each dance had three dancers participating in it. Your task is to determine the clothes color for each of the n dancers so that the President's third condition fulfilled: each dance must have a dancer in white, a dancer in red and a dancer in blue. The dancers cannot change clothes between the dances. Input The first line contains two space-separated integers n (3 ≀ n ≀ 105) and m (1 ≀ m ≀ 105) β€” the number of dancers and the number of dances, correspondingly. Then m lines follow, describing the dances in the order of dancing them. The i-th line contains three distinct integers β€” the numbers of the dancers that take part in the i-th dance. The dancers are numbered from 1 to n. Each dancer takes part in at least one dance. Output Print n space-separated integers: the i-th number must represent the color of the i-th dancer's clothes (1 for white, 2 for red, 3 for blue). If there are multiple valid solutions, print any of them. It is guaranteed that at least one solution exists. Examples Input 7 3 1 2 3 1 4 5 4 6 7 Output 1 2 3 3 2 2 1 Input 9 3 3 6 9 2 5 8 1 4 7 Output 1 1 1 2 2 2 3 3 3 Input 5 2 4 1 5 3 1 2 Output 2 3 1 1 3 Submitted Solution: ``` n,m=list(map(int,input().split())) l=[] for i in range(m): l.append(list(map(int,input().split()))) d={} for i in range(m): for j in range(3): d[l[i][j]]=None for i in range(m): for j in range(3): if not d[l[i][j]]: d[l[i][j]]=j+1 for i in range(1,n): print(d[i],end=' ') print(d[n]) ```
instruction
0
47,387
7
94,774
No
output
1
47,387
7
94,775
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. In Berland, there is the national holiday coming β€” the Flag Day. In the honor of this event the president of the country decided to make a big dance party and asked your agency to organize it. He has several conditions: * overall, there must be m dances; * exactly three people must take part in each dance; * each dance must have one dancer in white clothes, one dancer in red clothes and one dancer in blue clothes (these are the colors of the national flag of Berland). The agency has n dancers, and their number can be less than 3m. That is, some dancers will probably have to dance in more than one dance. All of your dancers must dance on the party. However, if some dance has two or more dancers from a previous dance, then the current dance stops being spectacular. Your agency cannot allow that to happen, so each dance has at most one dancer who has danced in some previous dance. You considered all the criteria and made the plan for the m dances: each dance had three dancers participating in it. Your task is to determine the clothes color for each of the n dancers so that the President's third condition fulfilled: each dance must have a dancer in white, a dancer in red and a dancer in blue. The dancers cannot change clothes between the dances. Input The first line contains two space-separated integers n (3 ≀ n ≀ 105) and m (1 ≀ m ≀ 105) β€” the number of dancers and the number of dances, correspondingly. Then m lines follow, describing the dances in the order of dancing them. The i-th line contains three distinct integers β€” the numbers of the dancers that take part in the i-th dance. The dancers are numbered from 1 to n. Each dancer takes part in at least one dance. Output Print n space-separated integers: the i-th number must represent the color of the i-th dancer's clothes (1 for white, 2 for red, 3 for blue). If there are multiple valid solutions, print any of them. It is guaranteed that at least one solution exists. Examples Input 7 3 1 2 3 1 4 5 4 6 7 Output 1 2 3 3 2 2 1 Input 9 3 3 6 9 2 5 8 1 4 7 Output 1 1 1 2 2 2 3 3 3 Input 5 2 4 1 5 3 1 2 Output 2 3 1 1 3 Submitted Solution: ``` n, m = list(map(int, input().split())) met = {} for _ in range(m): arr = list(map(int, input().split())) if _ == 0: met[arr[0]] = 1 met[arr[1]] = 2 met[arr[2]] = 3 else: arr2 = [1, 2, 3] xxx = 0 for k in range(3): if arr[k] in met: arr2.remove(met[arr[k]]) else: met[arr[k]] = arr2[xxx] xxx += 1 for kkk in range(1, n+1): print(met[kkk], end=' ') ```
instruction
0
47,388
7
94,776
No
output
1
47,388
7
94,777
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. In Berland, there is the national holiday coming β€” the Flag Day. In the honor of this event the president of the country decided to make a big dance party and asked your agency to organize it. He has several conditions: * overall, there must be m dances; * exactly three people must take part in each dance; * each dance must have one dancer in white clothes, one dancer in red clothes and one dancer in blue clothes (these are the colors of the national flag of Berland). The agency has n dancers, and their number can be less than 3m. That is, some dancers will probably have to dance in more than one dance. All of your dancers must dance on the party. However, if some dance has two or more dancers from a previous dance, then the current dance stops being spectacular. Your agency cannot allow that to happen, so each dance has at most one dancer who has danced in some previous dance. You considered all the criteria and made the plan for the m dances: each dance had three dancers participating in it. Your task is to determine the clothes color for each of the n dancers so that the President's third condition fulfilled: each dance must have a dancer in white, a dancer in red and a dancer in blue. The dancers cannot change clothes between the dances. Input The first line contains two space-separated integers n (3 ≀ n ≀ 105) and m (1 ≀ m ≀ 105) β€” the number of dancers and the number of dances, correspondingly. Then m lines follow, describing the dances in the order of dancing them. The i-th line contains three distinct integers β€” the numbers of the dancers that take part in the i-th dance. The dancers are numbered from 1 to n. Each dancer takes part in at least one dance. Output Print n space-separated integers: the i-th number must represent the color of the i-th dancer's clothes (1 for white, 2 for red, 3 for blue). If there are multiple valid solutions, print any of them. It is guaranteed that at least one solution exists. Examples Input 7 3 1 2 3 1 4 5 4 6 7 Output 1 2 3 3 2 2 1 Input 9 3 3 6 9 2 5 8 1 4 7 Output 1 1 1 2 2 2 3 3 3 Input 5 2 4 1 5 3 1 2 Output 2 3 1 1 3 Submitted Solution: ``` def next_color(color): return color % 3 + 1 n, m = list(map(int, input().split())) dances = [list(map(int, input().split())) for _ in range(m)] colors = [None for _ in range(n+1)] color = 1 for dance in dances: for dancer in dance: if colors[dancer] is None: colors[dancer] = color color = next_color(color) else: color = next_color(colors[dancer]) for color in colors[1:]: print(color, end=' ') ```
instruction
0
47,389
7
94,778
No
output
1
47,389
7
94,779
Provide a correct Python 3 solution for this coding contest problem. Dr. A of the Aizu Institute of Biological Research discovered a mysterious insect on a certain southern island. The shape is elongated like a hornworm, but since one segment is shaped like a ball, it looks like a beaded ball connected by a thread. What was strange was that there were many variations in body color, and some insects changed their body color over time. It seems that the color of the somites of all insects is limited to either red, green or blue, but the color of the somites changes every second, and finally all the somites become the same color and settle down. In some cases, the color seemed to keep changing no matter how long I waited. <image> As I investigated, I found that all the body segments usually have the same color, but after being surprised or excited by something, the color of the body segments changes without permission. It turns out that once the color of the segment changes, it will continue to change until all the segment are the same color again. Dr. A was curiously observing how the color changed when he caught and excited many of these insects, but the way the color changed during the color change is as follows. I noticed that there is regularity. * The color changes only in one pair of two adjacent somites of different colors, and the colors of the other somites do not change. However, when there are multiple such pairs, it is not possible to predict in advance which pair will change color. * Such a pair will change to a color that is neither of the colors of the two segmentes at the same time (for example, if the green and red segment are adjacent, they will change to blue at the same time). <image> The figure above shows all the changes in the color of the insects up to 2 seconds later. Suppose you have an insect that has the color shown in the upper part of the figure. At this time, there are 3 pairs of adjacent somites of different colors, so after 1 second, it will change to one of the 3 colors drawn side by side in the middle row. After 1 second, all the segments can turn green after 2 seconds (second from the left in the lower row of the figure) when they change to the two on the left side of the middle row. On the other hand, when it changes like the one on the far right in the middle row after 1 second, all the segments do not change to the same color after 2 seconds. He decided to predict if all the insect segments in front of him could be the same color, and if so, at the earliest, how many seconds later. Create a program that takes the color sequence of the insect body segments in front of you as input and outputs the shortest time required for all the insect body segments to have the same color in seconds. However, if there is no possibility that the colors will be the same, output "NA (half-width uppercase letters)". In addition, the color sequence of the insect body segment is represented by a character string consisting of r (red), g (green), and b (blue) of 2 or more and 10 or less. Input A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. For each dataset, one string is given on one line that represents information about the insect's somites. The number of datasets does not exceed 100. Output For each dataset, the minimum time (integer in seconds) or NA required for all segment colors to be the same is output on one line. Example Input rbgrg rbbgbbr bgr bgrbrgbr bggrgbgrr gbrggrbggr rrrrr bgbr 0 Output 5 7 1 6 NA 8 0 4
instruction
0
47,854
7
95,708
"Correct Solution: ``` from collections import deque def new_color(s, i, color): return s[:i] + color * 2 + s[i + 2:] def solve(s): length = len(s) monos = ["r" * length, "g" * length, "b" * length] if s in monos: print(0) return another = {("r", "g"):"b", ("g", "r"):"b", ("r", "b"):"g", ("b", "r"):"g", ("g", "b"):"r", ("b", "g"):"r"} visited = {s:0} que = deque() app = que.append pop = que.popleft que.append((s, 0)) while que: colors, score = pop() score += 1 temp = colors[0] for i in range(1, length): ci = colors[i] if ci != temp: new = new_color(colors, i - 1, another[(ci, temp)]) if new in monos: print(score) return if new not in visited: visited[new] = score app((new, score)) temp = ci print("NA") def main(): while True: s = input() if s == "0": break solve(s) main() ```
output
1
47,854
7
95,709
Provide a correct Python 3 solution for this coding contest problem. Dr. A of the Aizu Institute of Biological Research discovered a mysterious insect on a certain southern island. The shape is elongated like a hornworm, but since one segment is shaped like a ball, it looks like a beaded ball connected by a thread. What was strange was that there were many variations in body color, and some insects changed their body color over time. It seems that the color of the somites of all insects is limited to either red, green or blue, but the color of the somites changes every second, and finally all the somites become the same color and settle down. In some cases, the color seemed to keep changing no matter how long I waited. <image> As I investigated, I found that all the body segments usually have the same color, but after being surprised or excited by something, the color of the body segments changes without permission. It turns out that once the color of the segment changes, it will continue to change until all the segment are the same color again. Dr. A was curiously observing how the color changed when he caught and excited many of these insects, but the way the color changed during the color change is as follows. I noticed that there is regularity. * The color changes only in one pair of two adjacent somites of different colors, and the colors of the other somites do not change. However, when there are multiple such pairs, it is not possible to predict in advance which pair will change color. * Such a pair will change to a color that is neither of the colors of the two segmentes at the same time (for example, if the green and red segment are adjacent, they will change to blue at the same time). <image> The figure above shows all the changes in the color of the insects up to 2 seconds later. Suppose you have an insect that has the color shown in the upper part of the figure. At this time, there are 3 pairs of adjacent somites of different colors, so after 1 second, it will change to one of the 3 colors drawn side by side in the middle row. After 1 second, all the segments can turn green after 2 seconds (second from the left in the lower row of the figure) when they change to the two on the left side of the middle row. On the other hand, when it changes like the one on the far right in the middle row after 1 second, all the segments do not change to the same color after 2 seconds. He decided to predict if all the insect segments in front of him could be the same color, and if so, at the earliest, how many seconds later. Create a program that takes the color sequence of the insect body segments in front of you as input and outputs the shortest time required for all the insect body segments to have the same color in seconds. However, if there is no possibility that the colors will be the same, output "NA (half-width uppercase letters)". In addition, the color sequence of the insect body segment is represented by a character string consisting of r (red), g (green), and b (blue) of 2 or more and 10 or less. Input A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. For each dataset, one string is given on one line that represents information about the insect's somites. The number of datasets does not exceed 100. Output For each dataset, the minimum time (integer in seconds) or NA required for all segment colors to be the same is output on one line. Example Input rbgrg rbbgbbr bgr bgrbrgbr bggrgbgrr gbrggrbggr rrrrr bgbr 0 Output 5 7 1 6 NA 8 0 4
instruction
0
47,855
7
95,710
"Correct Solution: ``` from collections import deque def only_color(s, monos): if s in monos: return True else: return False def new_color(s, i, rgb): for color in rgb: if color != s[i] and color != s[i + 1]: break return s[:i] + color * 2 + s[i + 2:] def solve(s): length = len(s) monos = ["r" * length, "g" * length, "b" * length] if s in monos: print(0) return dic = {s:0} rgb = "rgb" que = deque() que.append((s, 0)) while que: colors, score = que.popleft() score += 1 temp = colors[0] for i in range(1, length): ci = colors[i] if ci != temp: new = new_color(colors, i - 1, rgb) if new in monos: print(score) return if new not in dic: dic[new] = score que.append((new, score)) temp = ci print("NA") def main(): while True: s = input() if s == "0": break solve(s) main() ```
output
1
47,855
7
95,711
Provide a correct Python 3 solution for this coding contest problem. Dr. A of the Aizu Institute of Biological Research discovered a mysterious insect on a certain southern island. The shape is elongated like a hornworm, but since one segment is shaped like a ball, it looks like a beaded ball connected by a thread. What was strange was that there were many variations in body color, and some insects changed their body color over time. It seems that the color of the somites of all insects is limited to either red, green or blue, but the color of the somites changes every second, and finally all the somites become the same color and settle down. In some cases, the color seemed to keep changing no matter how long I waited. <image> As I investigated, I found that all the body segments usually have the same color, but after being surprised or excited by something, the color of the body segments changes without permission. It turns out that once the color of the segment changes, it will continue to change until all the segment are the same color again. Dr. A was curiously observing how the color changed when he caught and excited many of these insects, but the way the color changed during the color change is as follows. I noticed that there is regularity. * The color changes only in one pair of two adjacent somites of different colors, and the colors of the other somites do not change. However, when there are multiple such pairs, it is not possible to predict in advance which pair will change color. * Such a pair will change to a color that is neither of the colors of the two segmentes at the same time (for example, if the green and red segment are adjacent, they will change to blue at the same time). <image> The figure above shows all the changes in the color of the insects up to 2 seconds later. Suppose you have an insect that has the color shown in the upper part of the figure. At this time, there are 3 pairs of adjacent somites of different colors, so after 1 second, it will change to one of the 3 colors drawn side by side in the middle row. After 1 second, all the segments can turn green after 2 seconds (second from the left in the lower row of the figure) when they change to the two on the left side of the middle row. On the other hand, when it changes like the one on the far right in the middle row after 1 second, all the segments do not change to the same color after 2 seconds. He decided to predict if all the insect segments in front of him could be the same color, and if so, at the earliest, how many seconds later. Create a program that takes the color sequence of the insect body segments in front of you as input and outputs the shortest time required for all the insect body segments to have the same color in seconds. However, if there is no possibility that the colors will be the same, output "NA (half-width uppercase letters)". In addition, the color sequence of the insect body segment is represented by a character string consisting of r (red), g (green), and b (blue) of 2 or more and 10 or less. Input A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. For each dataset, one string is given on one line that represents information about the insect's somites. The number of datasets does not exceed 100. Output For each dataset, the minimum time (integer in seconds) or NA required for all segment colors to be the same is output on one line. Example Input rbgrg rbbgbbr bgr bgrbrgbr bggrgbgrr gbrggrbggr rrrrr bgbr 0 Output 5 7 1 6 NA 8 0 4
instruction
0
47,856
7
95,712
"Correct Solution: ``` from collections import deque def change(x,y): if [x,y] == ["r","g"] or [y,x] == ["r","g"]: return "b" elif [x,y] == ["g","b"] or [y,x] == ["g","b"]: return "r" elif [x,y] == ["r","b"] or [y,x] == ["r","b"]: return "g" rgb = ['r','g','b'] while True: time = 0 W_dic = {} W_que = deque([]) worm = tuple(str(input())) if worm == ('0',): break else: W_que.append([time,worm]) W_dic[worm] = time while True: now_list = W_que.popleft() now_time = now_list[0] now_worm = now_list[1] if now_worm.count('r') == len(now_worm) or now_worm.count('g') == len(now_worm) or now_worm.count('b') == len(now_worm): print(now_time) break a_0 = now_worm[0] for i in range(1,len(now_worm)): a_1 = now_worm[i] rgb_c = rgb worm_c = list(now_worm) if a_0 != a_1: coll = change(a_0,a_1) worm_c[i - 1] = coll worm_c[i] = coll if not tuple(worm_c) in W_dic: W_dic[tuple(worm_c)] = now_time + 1 W_que.append([now_time + 1,worm_c]) a_0 = a_1 if len(W_que) == 0: print("NA") break ```
output
1
47,856
7
95,713
Provide a correct Python 3 solution for this coding contest problem. Dr. A of the Aizu Institute of Biological Research discovered a mysterious insect on a certain southern island. The shape is elongated like a hornworm, but since one segment is shaped like a ball, it looks like a beaded ball connected by a thread. What was strange was that there were many variations in body color, and some insects changed their body color over time. It seems that the color of the somites of all insects is limited to either red, green or blue, but the color of the somites changes every second, and finally all the somites become the same color and settle down. In some cases, the color seemed to keep changing no matter how long I waited. <image> As I investigated, I found that all the body segments usually have the same color, but after being surprised or excited by something, the color of the body segments changes without permission. It turns out that once the color of the segment changes, it will continue to change until all the segment are the same color again. Dr. A was curiously observing how the color changed when he caught and excited many of these insects, but the way the color changed during the color change is as follows. I noticed that there is regularity. * The color changes only in one pair of two adjacent somites of different colors, and the colors of the other somites do not change. However, when there are multiple such pairs, it is not possible to predict in advance which pair will change color. * Such a pair will change to a color that is neither of the colors of the two segmentes at the same time (for example, if the green and red segment are adjacent, they will change to blue at the same time). <image> The figure above shows all the changes in the color of the insects up to 2 seconds later. Suppose you have an insect that has the color shown in the upper part of the figure. At this time, there are 3 pairs of adjacent somites of different colors, so after 1 second, it will change to one of the 3 colors drawn side by side in the middle row. After 1 second, all the segments can turn green after 2 seconds (second from the left in the lower row of the figure) when they change to the two on the left side of the middle row. On the other hand, when it changes like the one on the far right in the middle row after 1 second, all the segments do not change to the same color after 2 seconds. He decided to predict if all the insect segments in front of him could be the same color, and if so, at the earliest, how many seconds later. Create a program that takes the color sequence of the insect body segments in front of you as input and outputs the shortest time required for all the insect body segments to have the same color in seconds. However, if there is no possibility that the colors will be the same, output "NA (half-width uppercase letters)". In addition, the color sequence of the insect body segment is represented by a character string consisting of r (red), g (green), and b (blue) of 2 or more and 10 or less. Input A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. For each dataset, one string is given on one line that represents information about the insect's somites. The number of datasets does not exceed 100. Output For each dataset, the minimum time (integer in seconds) or NA required for all segment colors to be the same is output on one line. Example Input rbgrg rbbgbbr bgr bgrbrgbr bggrgbgrr gbrggrbggr rrrrr bgbr 0 Output 5 7 1 6 NA 8 0 4
instruction
0
47,857
7
95,714
"Correct Solution: ``` from collections import deque def new_color(s, i, rgb): for color in rgb: if color != s[i] and color != s[i + 1]: break return s[:i] + color * 2 + s[i + 2:] def solve(s): length = len(s) monos = ["r" * length, "g" * length, "b" * length] if s in monos: print(0) return dic = {s:0} rgb = "rgb" que = deque() app = que.append pop = que.popleft que.append((s, 0)) while que: colors, score = pop() score += 1 temp = colors[0] for i in range(1, length): ci = colors[i] if ci != temp: new = new_color(colors, i - 1, rgb) if new in monos: print(score) return if new not in dic: dic[new] = score app((new, score)) temp = ci print("NA") def main(): while True: s = input() if s == "0": break solve(s) main() ```
output
1
47,857
7
95,715
Provide a correct Python 3 solution for this coding contest problem. Dr. A of the Aizu Institute of Biological Research discovered a mysterious insect on a certain southern island. The shape is elongated like a hornworm, but since one segment is shaped like a ball, it looks like a beaded ball connected by a thread. What was strange was that there were many variations in body color, and some insects changed their body color over time. It seems that the color of the somites of all insects is limited to either red, green or blue, but the color of the somites changes every second, and finally all the somites become the same color and settle down. In some cases, the color seemed to keep changing no matter how long I waited. <image> As I investigated, I found that all the body segments usually have the same color, but after being surprised or excited by something, the color of the body segments changes without permission. It turns out that once the color of the segment changes, it will continue to change until all the segment are the same color again. Dr. A was curiously observing how the color changed when he caught and excited many of these insects, but the way the color changed during the color change is as follows. I noticed that there is regularity. * The color changes only in one pair of two adjacent somites of different colors, and the colors of the other somites do not change. However, when there are multiple such pairs, it is not possible to predict in advance which pair will change color. * Such a pair will change to a color that is neither of the colors of the two segmentes at the same time (for example, if the green and red segment are adjacent, they will change to blue at the same time). <image> The figure above shows all the changes in the color of the insects up to 2 seconds later. Suppose you have an insect that has the color shown in the upper part of the figure. At this time, there are 3 pairs of adjacent somites of different colors, so after 1 second, it will change to one of the 3 colors drawn side by side in the middle row. After 1 second, all the segments can turn green after 2 seconds (second from the left in the lower row of the figure) when they change to the two on the left side of the middle row. On the other hand, when it changes like the one on the far right in the middle row after 1 second, all the segments do not change to the same color after 2 seconds. He decided to predict if all the insect segments in front of him could be the same color, and if so, at the earliest, how many seconds later. Create a program that takes the color sequence of the insect body segments in front of you as input and outputs the shortest time required for all the insect body segments to have the same color in seconds. However, if there is no possibility that the colors will be the same, output "NA (half-width uppercase letters)". In addition, the color sequence of the insect body segment is represented by a character string consisting of r (red), g (green), and b (blue) of 2 or more and 10 or less. Input A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. For each dataset, one string is given on one line that represents information about the insect's somites. The number of datasets does not exceed 100. Output For each dataset, the minimum time (integer in seconds) or NA required for all segment colors to be the same is output on one line. Example Input rbgrg rbbgbbr bgr bgrbrgbr bggrgbgrr gbrggrbggr rrrrr bgbr 0 Output 5 7 1 6 NA 8 0 4
instruction
0
47,858
7
95,716
"Correct Solution: ``` from collections import deque def isOneColor(w): sw = sorted(w) if sw[0] == sw[-1]: return True else: return False def nextColor(c1, c2): cs = ['r', 'g', 'b'] cs.remove(c1) cs.remove(c2) return cs[0] def bfs(iw): q = deque() s = set() s.add(str(iw)) q.append([iw, 0]) while q: w, t = q.popleft() if isOneColor(w): return t else: for i in range(len(w)-1): if w[i] != w[i+1]: nw = w.copy() nc = nextColor(nw[i], nw[i+1]) nw[i], nw[i+1] = nc, nc if str(nw) not in s: s.add(str(nw)) q.append([nw, t+1]) return -1 if __name__ == '__main__': while True: w = list(input()) if w == ['0']: break t = bfs(w) if t == -1: print('NA') else: print(t) ```
output
1
47,858
7
95,717
Provide a correct Python 3 solution for this coding contest problem. Dr. A of the Aizu Institute of Biological Research discovered a mysterious insect on a certain southern island. The shape is elongated like a hornworm, but since one segment is shaped like a ball, it looks like a beaded ball connected by a thread. What was strange was that there were many variations in body color, and some insects changed their body color over time. It seems that the color of the somites of all insects is limited to either red, green or blue, but the color of the somites changes every second, and finally all the somites become the same color and settle down. In some cases, the color seemed to keep changing no matter how long I waited. <image> As I investigated, I found that all the body segments usually have the same color, but after being surprised or excited by something, the color of the body segments changes without permission. It turns out that once the color of the segment changes, it will continue to change until all the segment are the same color again. Dr. A was curiously observing how the color changed when he caught and excited many of these insects, but the way the color changed during the color change is as follows. I noticed that there is regularity. * The color changes only in one pair of two adjacent somites of different colors, and the colors of the other somites do not change. However, when there are multiple such pairs, it is not possible to predict in advance which pair will change color. * Such a pair will change to a color that is neither of the colors of the two segmentes at the same time (for example, if the green and red segment are adjacent, they will change to blue at the same time). <image> The figure above shows all the changes in the color of the insects up to 2 seconds later. Suppose you have an insect that has the color shown in the upper part of the figure. At this time, there are 3 pairs of adjacent somites of different colors, so after 1 second, it will change to one of the 3 colors drawn side by side in the middle row. After 1 second, all the segments can turn green after 2 seconds (second from the left in the lower row of the figure) when they change to the two on the left side of the middle row. On the other hand, when it changes like the one on the far right in the middle row after 1 second, all the segments do not change to the same color after 2 seconds. He decided to predict if all the insect segments in front of him could be the same color, and if so, at the earliest, how many seconds later. Create a program that takes the color sequence of the insect body segments in front of you as input and outputs the shortest time required for all the insect body segments to have the same color in seconds. However, if there is no possibility that the colors will be the same, output "NA (half-width uppercase letters)". In addition, the color sequence of the insect body segment is represented by a character string consisting of r (red), g (green), and b (blue) of 2 or more and 10 or less. Input A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. For each dataset, one string is given on one line that represents information about the insect's somites. The number of datasets does not exceed 100. Output For each dataset, the minimum time (integer in seconds) or NA required for all segment colors to be the same is output on one line. Example Input rbgrg rbbgbbr bgr bgrbrgbr bggrgbgrr gbrggrbggr rrrrr bgbr 0 Output 5 7 1 6 NA 8 0 4
instruction
0
47,859
7
95,718
"Correct Solution: ``` def solve(): while True: worm = input() if worm == '0': break q = [worm] m = {('r', 'g'): 'bb', ('g', 'r'): 'bb', ('r', 'b'): 'gg', ('b', 'r'): 'gg', ('g', 'b'): 'rr', ('b', 'g'): 'rr'} d = {worm: True} ans = 0 while q: nq = [] for w in q: flag = True for i, t in enumerate(zip(w, w[1:])): s1, s2 = t if s1 != s2: flag = False nw = w[:i] + m[t] + w[i+2:] if nw not in d: d[nw] = True nq.append(nw) if flag: print(ans) break else: q = nq[:] ans += 1 continue break else: print('NA') solve() ```
output
1
47,859
7
95,719
Provide a correct Python 3 solution for this coding contest problem. Dr. A of the Aizu Institute of Biological Research discovered a mysterious insect on a certain southern island. The shape is elongated like a hornworm, but since one segment is shaped like a ball, it looks like a beaded ball connected by a thread. What was strange was that there were many variations in body color, and some insects changed their body color over time. It seems that the color of the somites of all insects is limited to either red, green or blue, but the color of the somites changes every second, and finally all the somites become the same color and settle down. In some cases, the color seemed to keep changing no matter how long I waited. <image> As I investigated, I found that all the body segments usually have the same color, but after being surprised or excited by something, the color of the body segments changes without permission. It turns out that once the color of the segment changes, it will continue to change until all the segment are the same color again. Dr. A was curiously observing how the color changed when he caught and excited many of these insects, but the way the color changed during the color change is as follows. I noticed that there is regularity. * The color changes only in one pair of two adjacent somites of different colors, and the colors of the other somites do not change. However, when there are multiple such pairs, it is not possible to predict in advance which pair will change color. * Such a pair will change to a color that is neither of the colors of the two segmentes at the same time (for example, if the green and red segment are adjacent, they will change to blue at the same time). <image> The figure above shows all the changes in the color of the insects up to 2 seconds later. Suppose you have an insect that has the color shown in the upper part of the figure. At this time, there are 3 pairs of adjacent somites of different colors, so after 1 second, it will change to one of the 3 colors drawn side by side in the middle row. After 1 second, all the segments can turn green after 2 seconds (second from the left in the lower row of the figure) when they change to the two on the left side of the middle row. On the other hand, when it changes like the one on the far right in the middle row after 1 second, all the segments do not change to the same color after 2 seconds. He decided to predict if all the insect segments in front of him could be the same color, and if so, at the earliest, how many seconds later. Create a program that takes the color sequence of the insect body segments in front of you as input and outputs the shortest time required for all the insect body segments to have the same color in seconds. However, if there is no possibility that the colors will be the same, output "NA (half-width uppercase letters)". In addition, the color sequence of the insect body segment is represented by a character string consisting of r (red), g (green), and b (blue) of 2 or more and 10 or less. Input A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. For each dataset, one string is given on one line that represents information about the insect's somites. The number of datasets does not exceed 100. Output For each dataset, the minimum time (integer in seconds) or NA required for all segment colors to be the same is output on one line. Example Input rbgrg rbbgbbr bgr bgrbrgbr bggrgbgrr gbrggrbggr rrrrr bgbr 0 Output 5 7 1 6 NA 8 0 4
instruction
0
47,860
7
95,720
"Correct Solution: ``` from collections import deque def new_color(s, i, color): return s[:i] + color * 2 + s[i + 2:] def solve(s): length = len(s) monos = ["r" * length, "g" * length, "b" * length] if s in monos: print(0) return rgb = "rgb" another = {("r", "g"):"b", ("g", "r"):"b", ("r", "b"):"g", ("b", "r"):"g", ("g", "b"):"r", ("b", "g"):"r"} dic = {s:0} que = deque() app = que.append pop = que.popleft que.append((s, 0)) while que: colors, score = pop() score += 1 temp = colors[0] for i in range(1, length): ci = colors[i] if ci != temp: new = new_color(colors, i - 1, another[(ci, temp)]) if new in monos: print(score) return if new not in dic: dic[new] = score app((new, score)) temp = ci print("NA") def main(): while True: s = input() if s == "0": break solve(s) main() ```
output
1
47,860
7
95,721
Provide a correct Python 3 solution for this coding contest problem. Dr. A of the Aizu Institute of Biological Research discovered a mysterious insect on a certain southern island. The shape is elongated like a hornworm, but since one segment is shaped like a ball, it looks like a beaded ball connected by a thread. What was strange was that there were many variations in body color, and some insects changed their body color over time. It seems that the color of the somites of all insects is limited to either red, green or blue, but the color of the somites changes every second, and finally all the somites become the same color and settle down. In some cases, the color seemed to keep changing no matter how long I waited. <image> As I investigated, I found that all the body segments usually have the same color, but after being surprised or excited by something, the color of the body segments changes without permission. It turns out that once the color of the segment changes, it will continue to change until all the segment are the same color again. Dr. A was curiously observing how the color changed when he caught and excited many of these insects, but the way the color changed during the color change is as follows. I noticed that there is regularity. * The color changes only in one pair of two adjacent somites of different colors, and the colors of the other somites do not change. However, when there are multiple such pairs, it is not possible to predict in advance which pair will change color. * Such a pair will change to a color that is neither of the colors of the two segmentes at the same time (for example, if the green and red segment are adjacent, they will change to blue at the same time). <image> The figure above shows all the changes in the color of the insects up to 2 seconds later. Suppose you have an insect that has the color shown in the upper part of the figure. At this time, there are 3 pairs of adjacent somites of different colors, so after 1 second, it will change to one of the 3 colors drawn side by side in the middle row. After 1 second, all the segments can turn green after 2 seconds (second from the left in the lower row of the figure) when they change to the two on the left side of the middle row. On the other hand, when it changes like the one on the far right in the middle row after 1 second, all the segments do not change to the same color after 2 seconds. He decided to predict if all the insect segments in front of him could be the same color, and if so, at the earliest, how many seconds later. Create a program that takes the color sequence of the insect body segments in front of you as input and outputs the shortest time required for all the insect body segments to have the same color in seconds. However, if there is no possibility that the colors will be the same, output "NA (half-width uppercase letters)". In addition, the color sequence of the insect body segment is represented by a character string consisting of r (red), g (green), and b (blue) of 2 or more and 10 or less. Input A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. For each dataset, one string is given on one line that represents information about the insect's somites. The number of datasets does not exceed 100. Output For each dataset, the minimum time (integer in seconds) or NA required for all segment colors to be the same is output on one line. Example Input rbgrg rbbgbbr bgr bgrbrgbr bggrgbgrr gbrggrbggr rrrrr bgbr 0 Output 5 7 1 6 NA 8 0 4
instruction
0
47,861
7
95,722
"Correct Solution: ``` from collections import deque def new_color(s, i, color): return s[:i - 1] + color * 2 + s[i + 1:] def solve(s): length = len(s) monos = ["r" * length, "g" * length, "b" * length] if s in monos: print(0) return another = {("r", "g"):"b", ("g", "r"):"b", ("r", "b"):"g", ("b", "r"):"g", ("g", "b"):"r", ("b", "g"):"r"} visited = {s:True} que = deque() app = que.append pop = que.popleft que.append((s, 0)) while que: colors, score = pop() score += 1 temp = colors[0] for i in range(1, length): ci = colors[i] if ci != temp: new = new_color(colors, i, another[(ci, temp)]) if new in monos: print(score) return if new not in visited: visited[new] = True app((new, score)) temp = ci print("NA") def main(): while True: s = input() if s == "0": break solve(s) main() ```
output
1
47,861
7
95,723