message stringlengths 2 48.6k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 318 108k | cluster float64 8 8 | __index_level_0__ int64 636 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
Ivan has n songs on his phone. The size of the i-th song is a_i bytes. Ivan also has a flash drive which can hold at most m bytes in total. Initially, his flash drive is empty.
Ivan wants to copy all n songs to the flash drive. He can compress the songs. If he compresses the i-th song, the size of the i-th song reduces from a_i to b_i bytes (b_i < a_i).
Ivan can compress any subset of the songs (possibly empty) and copy all the songs to his flash drive if the sum of their sizes is at most m. He can compress any subset of the songs (not necessarily contiguous).
Ivan wants to find the minimum number of songs he needs to compress in such a way that all his songs fit on the drive (i.e. the sum of their sizes is less than or equal to m).
If it is impossible to copy all the songs (even if Ivan compresses all the songs), print "-1". Otherwise print the minimum number of songs Ivan needs to compress.
Input
The first line of the input contains two integers n and m (1 ≤ n ≤ 10^5, 1 ≤ m ≤ 10^9) — the number of the songs on Ivan's phone and the capacity of Ivan's flash drive.
The next n lines contain two integers each: the i-th line contains two integers a_i and b_i (1 ≤ a_i, b_i ≤ 10^9, a_i > b_i) — the initial size of the i-th song and the size of the i-th song after compression.
Output
If it is impossible to compress a subset of the songs in such a way that all songs fit on the flash drive, print "-1". Otherwise print the minimum number of the songs to compress.
Examples
Input
4 21
10 8
7 4
3 1
5 4
Output
2
Input
4 16
10 8
7 4
3 1
5 4
Output
-1
Note
In the first example Ivan can compress the first and the third songs so after these moves the sum of sizes will be equal to 8 + 7 + 1 + 5 = 21 ≤ 21. Also Ivan can compress the first and the second songs, then the sum of sizes will be equal 8 + 4 + 3 + 5 = 20 ≤ 21. Note that compressing any single song is not sufficient to copy all the songs on the flash drive (for example, after compressing the second song the sum of sizes will be equal to 10 + 4 + 3 + 5 = 22 > 21).
In the second example even if Ivan compresses all the songs the sum of sizes will be equal 8 + 4 + 1 + 4 = 17 > 16. | instruction | 0 | 28,254 | 8 | 56,508 |
Tags: sortings
Correct Solution:
```
input_str = input()
n, m = map(lambda x: int(x), input_str.split())
a = []
b = []
diff = []
for i in range(n):
input_str = input()
a.append(int(input_str.split()[0]))
b.append(int(input_str.split()[1]))
diff.append(a[-1]-b[-1])
vals = list(zip(zip(a, b), diff))
song_sum_comp = sum(b)
if song_sum_comp>m:
print (-1)
vals.sort(key=lambda tup:tup[1])
#print (vals)
min_rem = 0
song_sum = sum(a)
if song_sum <= m:
print (0)
else:
for el in reversed(vals):
song_sum -= el[1]
min_rem += 1
if song_sum <= m:
print (min_rem)
break
``` | output | 1 | 28,254 | 8 | 56,509 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ivan has n songs on his phone. The size of the i-th song is a_i bytes. Ivan also has a flash drive which can hold at most m bytes in total. Initially, his flash drive is empty.
Ivan wants to copy all n songs to the flash drive. He can compress the songs. If he compresses the i-th song, the size of the i-th song reduces from a_i to b_i bytes (b_i < a_i).
Ivan can compress any subset of the songs (possibly empty) and copy all the songs to his flash drive if the sum of their sizes is at most m. He can compress any subset of the songs (not necessarily contiguous).
Ivan wants to find the minimum number of songs he needs to compress in such a way that all his songs fit on the drive (i.e. the sum of their sizes is less than or equal to m).
If it is impossible to copy all the songs (even if Ivan compresses all the songs), print "-1". Otherwise print the minimum number of songs Ivan needs to compress.
Input
The first line of the input contains two integers n and m (1 ≤ n ≤ 10^5, 1 ≤ m ≤ 10^9) — the number of the songs on Ivan's phone and the capacity of Ivan's flash drive.
The next n lines contain two integers each: the i-th line contains two integers a_i and b_i (1 ≤ a_i, b_i ≤ 10^9, a_i > b_i) — the initial size of the i-th song and the size of the i-th song after compression.
Output
If it is impossible to compress a subset of the songs in such a way that all songs fit on the flash drive, print "-1". Otherwise print the minimum number of the songs to compress.
Examples
Input
4 21
10 8
7 4
3 1
5 4
Output
2
Input
4 16
10 8
7 4
3 1
5 4
Output
-1
Note
In the first example Ivan can compress the first and the third songs so after these moves the sum of sizes will be equal to 8 + 7 + 1 + 5 = 21 ≤ 21. Also Ivan can compress the first and the second songs, then the sum of sizes will be equal 8 + 4 + 3 + 5 = 20 ≤ 21. Note that compressing any single song is not sufficient to copy all the songs on the flash drive (for example, after compressing the second song the sum of sizes will be equal to 10 + 4 + 3 + 5 = 22 > 21).
In the second example even if Ivan compresses all the songs the sum of sizes will be equal 8 + 4 + 1 + 4 = 17 > 16. | instruction | 0 | 28,255 | 8 | 56,510 |
Tags: sortings
Correct Solution:
```
n, m = map(int, input().split())
diff = []
s = 0
for i in range(n):
a, b = map(int, input().split())
s += a
diff.append(a-b)
diff = sorted(diff, reverse = True)
count = 0
for i in range(n):
if s <= m:
print(count)
break
else:
s -= diff[i]
count += 1
else:
if s <= m:
print(count)
else:
print(-1)
``` | output | 1 | 28,255 | 8 | 56,511 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ivan has n songs on his phone. The size of the i-th song is a_i bytes. Ivan also has a flash drive which can hold at most m bytes in total. Initially, his flash drive is empty.
Ivan wants to copy all n songs to the flash drive. He can compress the songs. If he compresses the i-th song, the size of the i-th song reduces from a_i to b_i bytes (b_i < a_i).
Ivan can compress any subset of the songs (possibly empty) and copy all the songs to his flash drive if the sum of their sizes is at most m. He can compress any subset of the songs (not necessarily contiguous).
Ivan wants to find the minimum number of songs he needs to compress in such a way that all his songs fit on the drive (i.e. the sum of their sizes is less than or equal to m).
If it is impossible to copy all the songs (even if Ivan compresses all the songs), print "-1". Otherwise print the minimum number of songs Ivan needs to compress.
Input
The first line of the input contains two integers n and m (1 ≤ n ≤ 10^5, 1 ≤ m ≤ 10^9) — the number of the songs on Ivan's phone and the capacity of Ivan's flash drive.
The next n lines contain two integers each: the i-th line contains two integers a_i and b_i (1 ≤ a_i, b_i ≤ 10^9, a_i > b_i) — the initial size of the i-th song and the size of the i-th song after compression.
Output
If it is impossible to compress a subset of the songs in such a way that all songs fit on the flash drive, print "-1". Otherwise print the minimum number of the songs to compress.
Examples
Input
4 21
10 8
7 4
3 1
5 4
Output
2
Input
4 16
10 8
7 4
3 1
5 4
Output
-1
Note
In the first example Ivan can compress the first and the third songs so after these moves the sum of sizes will be equal to 8 + 7 + 1 + 5 = 21 ≤ 21. Also Ivan can compress the first and the second songs, then the sum of sizes will be equal 8 + 4 + 3 + 5 = 20 ≤ 21. Note that compressing any single song is not sufficient to copy all the songs on the flash drive (for example, after compressing the second song the sum of sizes will be equal to 10 + 4 + 3 + 5 = 22 > 21).
In the second example even if Ivan compresses all the songs the sum of sizes will be equal 8 + 4 + 1 + 4 = 17 > 16. | instruction | 0 | 28,256 | 8 | 56,512 |
Tags: sortings
Correct Solution:
```
def ind(k, i):
if i == 0:
return 0
else:
l = 0
r = i - 1
while True:
if l == r:
if D[l] > k:
return l - 1
else:
return l
m = (r + l) // 2
if k == D[m]:
return m
if k > D[m]:
r = m - 1
else:
l = m + 1
n, m = map(int, input().split())
D = [0] * n
s = 0
z = 0
ans = 0
for i in range(n):
a, b = map(int, input().split())
k = a - b
D[i] = k
s += a
z += b
D.sort(reverse = True)
if z > m:
print(-1)
else:
for i in range(n):
if s <= m:
break
s -= D[i]
ans += 1
print(ans)
``` | output | 1 | 28,256 | 8 | 56,513 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ivan has n songs on his phone. The size of the i-th song is a_i bytes. Ivan also has a flash drive which can hold at most m bytes in total. Initially, his flash drive is empty.
Ivan wants to copy all n songs to the flash drive. He can compress the songs. If he compresses the i-th song, the size of the i-th song reduces from a_i to b_i bytes (b_i < a_i).
Ivan can compress any subset of the songs (possibly empty) and copy all the songs to his flash drive if the sum of their sizes is at most m. He can compress any subset of the songs (not necessarily contiguous).
Ivan wants to find the minimum number of songs he needs to compress in such a way that all his songs fit on the drive (i.e. the sum of their sizes is less than or equal to m).
If it is impossible to copy all the songs (even if Ivan compresses all the songs), print "-1". Otherwise print the minimum number of songs Ivan needs to compress.
Input
The first line of the input contains two integers n and m (1 ≤ n ≤ 10^5, 1 ≤ m ≤ 10^9) — the number of the songs on Ivan's phone and the capacity of Ivan's flash drive.
The next n lines contain two integers each: the i-th line contains two integers a_i and b_i (1 ≤ a_i, b_i ≤ 10^9, a_i > b_i) — the initial size of the i-th song and the size of the i-th song after compression.
Output
If it is impossible to compress a subset of the songs in such a way that all songs fit on the flash drive, print "-1". Otherwise print the minimum number of the songs to compress.
Examples
Input
4 21
10 8
7 4
3 1
5 4
Output
2
Input
4 16
10 8
7 4
3 1
5 4
Output
-1
Note
In the first example Ivan can compress the first and the third songs so after these moves the sum of sizes will be equal to 8 + 7 + 1 + 5 = 21 ≤ 21. Also Ivan can compress the first and the second songs, then the sum of sizes will be equal 8 + 4 + 3 + 5 = 20 ≤ 21. Note that compressing any single song is not sufficient to copy all the songs on the flash drive (for example, after compressing the second song the sum of sizes will be equal to 10 + 4 + 3 + 5 = 22 > 21).
In the second example even if Ivan compresses all the songs the sum of sizes will be equal 8 + 4 + 1 + 4 = 17 > 16. | instruction | 0 | 28,257 | 8 | 56,514 |
Tags: sortings
Correct Solution:
```
n,size=map(int,input().split())
pot=list()
tot=0
for i in range(n):
a,b=map(int,input().split())
pot.append(a-b)
tot+=a
pot.sort()
pot=pot[::-1]
cpt=0
while(tot>size and cpt<len(pot)):
tot-=pot[cpt]
cpt+=1
if(tot>size):print(-1)
else:print(cpt)
``` | output | 1 | 28,257 | 8 | 56,515 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ivan has n songs on his phone. The size of the i-th song is a_i bytes. Ivan also has a flash drive which can hold at most m bytes in total. Initially, his flash drive is empty.
Ivan wants to copy all n songs to the flash drive. He can compress the songs. If he compresses the i-th song, the size of the i-th song reduces from a_i to b_i bytes (b_i < a_i).
Ivan can compress any subset of the songs (possibly empty) and copy all the songs to his flash drive if the sum of their sizes is at most m. He can compress any subset of the songs (not necessarily contiguous).
Ivan wants to find the minimum number of songs he needs to compress in such a way that all his songs fit on the drive (i.e. the sum of their sizes is less than or equal to m).
If it is impossible to copy all the songs (even if Ivan compresses all the songs), print "-1". Otherwise print the minimum number of songs Ivan needs to compress.
Input
The first line of the input contains two integers n and m (1 ≤ n ≤ 10^5, 1 ≤ m ≤ 10^9) — the number of the songs on Ivan's phone and the capacity of Ivan's flash drive.
The next n lines contain two integers each: the i-th line contains two integers a_i and b_i (1 ≤ a_i, b_i ≤ 10^9, a_i > b_i) — the initial size of the i-th song and the size of the i-th song after compression.
Output
If it is impossible to compress a subset of the songs in such a way that all songs fit on the flash drive, print "-1". Otherwise print the minimum number of the songs to compress.
Examples
Input
4 21
10 8
7 4
3 1
5 4
Output
2
Input
4 16
10 8
7 4
3 1
5 4
Output
-1
Note
In the first example Ivan can compress the first and the third songs so after these moves the sum of sizes will be equal to 8 + 7 + 1 + 5 = 21 ≤ 21. Also Ivan can compress the first and the second songs, then the sum of sizes will be equal 8 + 4 + 3 + 5 = 20 ≤ 21. Note that compressing any single song is not sufficient to copy all the songs on the flash drive (for example, after compressing the second song the sum of sizes will be equal to 10 + 4 + 3 + 5 = 22 > 21).
In the second example even if Ivan compresses all the songs the sum of sizes will be equal 8 + 4 + 1 + 4 = 17 > 16. | instruction | 0 | 28,258 | 8 | 56,516 |
Tags: sortings
Correct Solution:
```
t,m = map(int, input().rstrip().split(" "))
a = [0]*t
b = [0]*t
d = [0]*t
i = 0
while i <t:
ai,bi = map(int, input().rstrip().split(" "))
a[i]=ai
b[i]=bi
d[i]=ai-bi
i=i+1
d.sort(reverse=True)
if sum(b)> m:
print(-1)
elif sum(b)==m:
print(t)
else:
z=sum(a)
j = 0
while z>m:
z=z-d[j]
j+=1
print(j)
``` | output | 1 | 28,258 | 8 | 56,517 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ivan has n songs on his phone. The size of the i-th song is a_i bytes. Ivan also has a flash drive which can hold at most m bytes in total. Initially, his flash drive is empty.
Ivan wants to copy all n songs to the flash drive. He can compress the songs. If he compresses the i-th song, the size of the i-th song reduces from a_i to b_i bytes (b_i < a_i).
Ivan can compress any subset of the songs (possibly empty) and copy all the songs to his flash drive if the sum of their sizes is at most m. He can compress any subset of the songs (not necessarily contiguous).
Ivan wants to find the minimum number of songs he needs to compress in such a way that all his songs fit on the drive (i.e. the sum of their sizes is less than or equal to m).
If it is impossible to copy all the songs (even if Ivan compresses all the songs), print "-1". Otherwise print the minimum number of songs Ivan needs to compress.
Input
The first line of the input contains two integers n and m (1 ≤ n ≤ 10^5, 1 ≤ m ≤ 10^9) — the number of the songs on Ivan's phone and the capacity of Ivan's flash drive.
The next n lines contain two integers each: the i-th line contains two integers a_i and b_i (1 ≤ a_i, b_i ≤ 10^9, a_i > b_i) — the initial size of the i-th song and the size of the i-th song after compression.
Output
If it is impossible to compress a subset of the songs in such a way that all songs fit on the flash drive, print "-1". Otherwise print the minimum number of the songs to compress.
Examples
Input
4 21
10 8
7 4
3 1
5 4
Output
2
Input
4 16
10 8
7 4
3 1
5 4
Output
-1
Note
In the first example Ivan can compress the first and the third songs so after these moves the sum of sizes will be equal to 8 + 7 + 1 + 5 = 21 ≤ 21. Also Ivan can compress the first and the second songs, then the sum of sizes will be equal 8 + 4 + 3 + 5 = 20 ≤ 21. Note that compressing any single song is not sufficient to copy all the songs on the flash drive (for example, after compressing the second song the sum of sizes will be equal to 10 + 4 + 3 + 5 = 22 > 21).
In the second example even if Ivan compresses all the songs the sum of sizes will be equal 8 + 4 + 1 + 4 = 17 > 16. | instruction | 0 | 28,259 | 8 | 56,518 |
Tags: sortings
Correct Solution:
```
import sys
input=sys.stdin.readline
n,m=map(int,input().split())
a=[]
p=0
for j in range(n):
x,y=map(int,input().split())
a.append(x-y)
p+=x
a.sort()
j=n-1
q=0
while(j>=0):
if p<=m:
break
else:
p+=-a[j]
q+=1
j+=-1
if p<=m:
print(q)
else:
print(-1)
``` | output | 1 | 28,259 | 8 | 56,519 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ivan has n songs on his phone. The size of the i-th song is a_i bytes. Ivan also has a flash drive which can hold at most m bytes in total. Initially, his flash drive is empty.
Ivan wants to copy all n songs to the flash drive. He can compress the songs. If he compresses the i-th song, the size of the i-th song reduces from a_i to b_i bytes (b_i < a_i).
Ivan can compress any subset of the songs (possibly empty) and copy all the songs to his flash drive if the sum of their sizes is at most m. He can compress any subset of the songs (not necessarily contiguous).
Ivan wants to find the minimum number of songs he needs to compress in such a way that all his songs fit on the drive (i.e. the sum of their sizes is less than or equal to m).
If it is impossible to copy all the songs (even if Ivan compresses all the songs), print "-1". Otherwise print the minimum number of songs Ivan needs to compress.
Input
The first line of the input contains two integers n and m (1 ≤ n ≤ 10^5, 1 ≤ m ≤ 10^9) — the number of the songs on Ivan's phone and the capacity of Ivan's flash drive.
The next n lines contain two integers each: the i-th line contains two integers a_i and b_i (1 ≤ a_i, b_i ≤ 10^9, a_i > b_i) — the initial size of the i-th song and the size of the i-th song after compression.
Output
If it is impossible to compress a subset of the songs in such a way that all songs fit on the flash drive, print "-1". Otherwise print the minimum number of the songs to compress.
Examples
Input
4 21
10 8
7 4
3 1
5 4
Output
2
Input
4 16
10 8
7 4
3 1
5 4
Output
-1
Note
In the first example Ivan can compress the first and the third songs so after these moves the sum of sizes will be equal to 8 + 7 + 1 + 5 = 21 ≤ 21. Also Ivan can compress the first and the second songs, then the sum of sizes will be equal 8 + 4 + 3 + 5 = 20 ≤ 21. Note that compressing any single song is not sufficient to copy all the songs on the flash drive (for example, after compressing the second song the sum of sizes will be equal to 10 + 4 + 3 + 5 = 22 > 21).
In the second example even if Ivan compresses all the songs the sum of sizes will be equal 8 + 4 + 1 + 4 = 17 > 16.
Submitted Solution:
```
n,m=map(int,input().split())
l=[]
for i in range(n):
a,b=map(int,input().split())
l.append([a,b])
x=[]
sum1=0
for i in range(n):
sum1+=l[i][0]
x.append(l[i][0]-l[i][1])
x.sort()
x.reverse()
c=0
while(c < n and sum1 > m):
sum1=sum1-x[c]
c=c+1
if (sum1>m):
print("-1")
else:
print(c)
``` | instruction | 0 | 28,260 | 8 | 56,520 |
Yes | output | 1 | 28,260 | 8 | 56,521 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ivan has n songs on his phone. The size of the i-th song is a_i bytes. Ivan also has a flash drive which can hold at most m bytes in total. Initially, his flash drive is empty.
Ivan wants to copy all n songs to the flash drive. He can compress the songs. If he compresses the i-th song, the size of the i-th song reduces from a_i to b_i bytes (b_i < a_i).
Ivan can compress any subset of the songs (possibly empty) and copy all the songs to his flash drive if the sum of their sizes is at most m. He can compress any subset of the songs (not necessarily contiguous).
Ivan wants to find the minimum number of songs he needs to compress in such a way that all his songs fit on the drive (i.e. the sum of their sizes is less than or equal to m).
If it is impossible to copy all the songs (even if Ivan compresses all the songs), print "-1". Otherwise print the minimum number of songs Ivan needs to compress.
Input
The first line of the input contains two integers n and m (1 ≤ n ≤ 10^5, 1 ≤ m ≤ 10^9) — the number of the songs on Ivan's phone and the capacity of Ivan's flash drive.
The next n lines contain two integers each: the i-th line contains two integers a_i and b_i (1 ≤ a_i, b_i ≤ 10^9, a_i > b_i) — the initial size of the i-th song and the size of the i-th song after compression.
Output
If it is impossible to compress a subset of the songs in such a way that all songs fit on the flash drive, print "-1". Otherwise print the minimum number of the songs to compress.
Examples
Input
4 21
10 8
7 4
3 1
5 4
Output
2
Input
4 16
10 8
7 4
3 1
5 4
Output
-1
Note
In the first example Ivan can compress the first and the third songs so after these moves the sum of sizes will be equal to 8 + 7 + 1 + 5 = 21 ≤ 21. Also Ivan can compress the first and the second songs, then the sum of sizes will be equal 8 + 4 + 3 + 5 = 20 ≤ 21. Note that compressing any single song is not sufficient to copy all the songs on the flash drive (for example, after compressing the second song the sum of sizes will be equal to 10 + 4 + 3 + 5 = 22 > 21).
In the second example even if Ivan compresses all the songs the sum of sizes will be equal 8 + 4 + 1 + 4 = 17 > 16.
Submitted Solution:
```
n,m=map(int,input().split())
a=[]
b=[]
c=[]
for i in range(n):
r,l=map(int,input().split())
a.append(r)
b.append(l)
c.append(r-l)
if sum(b)>m:
print(-1)
elif sum(a)<m:
print(0)
else:
t=sum(a)-m
c.sort()
c.reverse()
i=0
while t>0:
t-=c[i]
i+=1
print(i)
``` | instruction | 0 | 28,261 | 8 | 56,522 |
Yes | output | 1 | 28,261 | 8 | 56,523 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ivan has n songs on his phone. The size of the i-th song is a_i bytes. Ivan also has a flash drive which can hold at most m bytes in total. Initially, his flash drive is empty.
Ivan wants to copy all n songs to the flash drive. He can compress the songs. If he compresses the i-th song, the size of the i-th song reduces from a_i to b_i bytes (b_i < a_i).
Ivan can compress any subset of the songs (possibly empty) and copy all the songs to his flash drive if the sum of their sizes is at most m. He can compress any subset of the songs (not necessarily contiguous).
Ivan wants to find the minimum number of songs he needs to compress in such a way that all his songs fit on the drive (i.e. the sum of their sizes is less than or equal to m).
If it is impossible to copy all the songs (even if Ivan compresses all the songs), print "-1". Otherwise print the minimum number of songs Ivan needs to compress.
Input
The first line of the input contains two integers n and m (1 ≤ n ≤ 10^5, 1 ≤ m ≤ 10^9) — the number of the songs on Ivan's phone and the capacity of Ivan's flash drive.
The next n lines contain two integers each: the i-th line contains two integers a_i and b_i (1 ≤ a_i, b_i ≤ 10^9, a_i > b_i) — the initial size of the i-th song and the size of the i-th song after compression.
Output
If it is impossible to compress a subset of the songs in such a way that all songs fit on the flash drive, print "-1". Otherwise print the minimum number of the songs to compress.
Examples
Input
4 21
10 8
7 4
3 1
5 4
Output
2
Input
4 16
10 8
7 4
3 1
5 4
Output
-1
Note
In the first example Ivan can compress the first and the third songs so after these moves the sum of sizes will be equal to 8 + 7 + 1 + 5 = 21 ≤ 21. Also Ivan can compress the first and the second songs, then the sum of sizes will be equal 8 + 4 + 3 + 5 = 20 ≤ 21. Note that compressing any single song is not sufficient to copy all the songs on the flash drive (for example, after compressing the second song the sum of sizes will be equal to 10 + 4 + 3 + 5 = 22 > 21).
In the second example even if Ivan compresses all the songs the sum of sizes will be equal 8 + 4 + 1 + 4 = 17 > 16.
Submitted Solution:
```
# -*- coding: utf-8 -*-
"""
Created on Tue Jul 31 21:30:45 2018
@author: chirayu jain
"""
N, M = [int(x) for x in input().split()]
arr1 = []
arr2 = []
sub = []
count = 0
for i in range(0,N):
A, B = [int(x) for x in input().split()]
arr1.append(A)
arr2.append(B)
else:
sum1 = sum(arr1)
diff = sum1 - M
for i in range(0,len(arr1)):
sub.append(arr1[i]-arr2[i])
sub.sort()
sub.reverse()
for i in range(0,len(sub)):
if diff>0:
diff = diff - sub[i]
count = count + 1
if sum(arr2) > M:
print("-1")
else:
print(count)
``` | instruction | 0 | 28,262 | 8 | 56,524 |
Yes | output | 1 | 28,262 | 8 | 56,525 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ivan has n songs on his phone. The size of the i-th song is a_i bytes. Ivan also has a flash drive which can hold at most m bytes in total. Initially, his flash drive is empty.
Ivan wants to copy all n songs to the flash drive. He can compress the songs. If he compresses the i-th song, the size of the i-th song reduces from a_i to b_i bytes (b_i < a_i).
Ivan can compress any subset of the songs (possibly empty) and copy all the songs to his flash drive if the sum of their sizes is at most m. He can compress any subset of the songs (not necessarily contiguous).
Ivan wants to find the minimum number of songs he needs to compress in such a way that all his songs fit on the drive (i.e. the sum of their sizes is less than or equal to m).
If it is impossible to copy all the songs (even if Ivan compresses all the songs), print "-1". Otherwise print the minimum number of songs Ivan needs to compress.
Input
The first line of the input contains two integers n and m (1 ≤ n ≤ 10^5, 1 ≤ m ≤ 10^9) — the number of the songs on Ivan's phone and the capacity of Ivan's flash drive.
The next n lines contain two integers each: the i-th line contains two integers a_i and b_i (1 ≤ a_i, b_i ≤ 10^9, a_i > b_i) — the initial size of the i-th song and the size of the i-th song after compression.
Output
If it is impossible to compress a subset of the songs in such a way that all songs fit on the flash drive, print "-1". Otherwise print the minimum number of the songs to compress.
Examples
Input
4 21
10 8
7 4
3 1
5 4
Output
2
Input
4 16
10 8
7 4
3 1
5 4
Output
-1
Note
In the first example Ivan can compress the first and the third songs so after these moves the sum of sizes will be equal to 8 + 7 + 1 + 5 = 21 ≤ 21. Also Ivan can compress the first and the second songs, then the sum of sizes will be equal 8 + 4 + 3 + 5 = 20 ≤ 21. Note that compressing any single song is not sufficient to copy all the songs on the flash drive (for example, after compressing the second song the sum of sizes will be equal to 10 + 4 + 3 + 5 = 22 > 21).
In the second example even if Ivan compresses all the songs the sum of sizes will be equal 8 + 4 + 1 + 4 = 17 > 16.
Submitted Solution:
```
import sys
input = sys.stdin.readline
############ ---- Input Functions ---- ############
def inp():
return (int(input()))
def inlt():
return (list(map(int, input().split())))
def insr():
s = input()
return (list(s[:len(s) - 1]))
def invr():
return (map(int, input().split()))
def get_v(l, p):
if p < 0:
return 0
if p >= len(l):
return 0
return l[p]
def main():
n, k = inlt()
data = []
for i in range(n):
a, b = inlt()
data.append((a, b))
total = sum([d[0] for d in data])
data.sort(key = lambda b:b[0]-b[1], reverse=True)
c = 0
while total>k and c<len(data):
total-=(data[c][0]-data[c][1])
c+=1
print(c if total <=k else -1)
if __name__ == "__main__":
# sys.setrecursionlimit(10 ** 6)
# threading.stack_size(10 ** 8)
# t = threading.Thread(target=main)
# t.start()
# t.join()
main()
``` | instruction | 0 | 28,263 | 8 | 56,526 |
Yes | output | 1 | 28,263 | 8 | 56,527 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ivan has n songs on his phone. The size of the i-th song is a_i bytes. Ivan also has a flash drive which can hold at most m bytes in total. Initially, his flash drive is empty.
Ivan wants to copy all n songs to the flash drive. He can compress the songs. If he compresses the i-th song, the size of the i-th song reduces from a_i to b_i bytes (b_i < a_i).
Ivan can compress any subset of the songs (possibly empty) and copy all the songs to his flash drive if the sum of their sizes is at most m. He can compress any subset of the songs (not necessarily contiguous).
Ivan wants to find the minimum number of songs he needs to compress in such a way that all his songs fit on the drive (i.e. the sum of their sizes is less than or equal to m).
If it is impossible to copy all the songs (even if Ivan compresses all the songs), print "-1". Otherwise print the minimum number of songs Ivan needs to compress.
Input
The first line of the input contains two integers n and m (1 ≤ n ≤ 10^5, 1 ≤ m ≤ 10^9) — the number of the songs on Ivan's phone and the capacity of Ivan's flash drive.
The next n lines contain two integers each: the i-th line contains two integers a_i and b_i (1 ≤ a_i, b_i ≤ 10^9, a_i > b_i) — the initial size of the i-th song and the size of the i-th song after compression.
Output
If it is impossible to compress a subset of the songs in such a way that all songs fit on the flash drive, print "-1". Otherwise print the minimum number of the songs to compress.
Examples
Input
4 21
10 8
7 4
3 1
5 4
Output
2
Input
4 16
10 8
7 4
3 1
5 4
Output
-1
Note
In the first example Ivan can compress the first and the third songs so after these moves the sum of sizes will be equal to 8 + 7 + 1 + 5 = 21 ≤ 21. Also Ivan can compress the first and the second songs, then the sum of sizes will be equal 8 + 4 + 3 + 5 = 20 ≤ 21. Note that compressing any single song is not sufficient to copy all the songs on the flash drive (for example, after compressing the second song the sum of sizes will be equal to 10 + 4 + 3 + 5 = 22 > 21).
In the second example even if Ivan compresses all the songs the sum of sizes will be equal 8 + 4 + 1 + 4 = 17 > 16.
Submitted Solution:
```
# -*- coding: utf-8 -*-
"""
Created on Tue Jul 31 21:30:45 2018
@author: chirayu jain
"""
N, M = [int(x) for x in input().split()]
arr1 = []
arr2 = []
sub = []
count = 0
for i in range(0,N):
A, B = [int(x) for x in input().split()]
arr1.append(A)
arr2.append(B)
else:
sum1 = sum(arr1)
diff = sum1 - M
arr1.sort()
arr2.sort()
for i in range(0,len(arr1)):
sub.append(arr1[i]-arr2[i])
sub.reverse()
for i in range(0,len(sub)):
if diff>0 and sub[i]<=diff:
diff = diff - sub[i]
count = count + 1
if sub[i]>=diff:
break
if sum(arr2) > M:
print("-1")
else:
print(count)
``` | instruction | 0 | 28,264 | 8 | 56,528 |
No | output | 1 | 28,264 | 8 | 56,529 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ivan has n songs on his phone. The size of the i-th song is a_i bytes. Ivan also has a flash drive which can hold at most m bytes in total. Initially, his flash drive is empty.
Ivan wants to copy all n songs to the flash drive. He can compress the songs. If he compresses the i-th song, the size of the i-th song reduces from a_i to b_i bytes (b_i < a_i).
Ivan can compress any subset of the songs (possibly empty) and copy all the songs to his flash drive if the sum of their sizes is at most m. He can compress any subset of the songs (not necessarily contiguous).
Ivan wants to find the minimum number of songs he needs to compress in such a way that all his songs fit on the drive (i.e. the sum of their sizes is less than or equal to m).
If it is impossible to copy all the songs (even if Ivan compresses all the songs), print "-1". Otherwise print the minimum number of songs Ivan needs to compress.
Input
The first line of the input contains two integers n and m (1 ≤ n ≤ 10^5, 1 ≤ m ≤ 10^9) — the number of the songs on Ivan's phone and the capacity of Ivan's flash drive.
The next n lines contain two integers each: the i-th line contains two integers a_i and b_i (1 ≤ a_i, b_i ≤ 10^9, a_i > b_i) — the initial size of the i-th song and the size of the i-th song after compression.
Output
If it is impossible to compress a subset of the songs in such a way that all songs fit on the flash drive, print "-1". Otherwise print the minimum number of the songs to compress.
Examples
Input
4 21
10 8
7 4
3 1
5 4
Output
2
Input
4 16
10 8
7 4
3 1
5 4
Output
-1
Note
In the first example Ivan can compress the first and the third songs so after these moves the sum of sizes will be equal to 8 + 7 + 1 + 5 = 21 ≤ 21. Also Ivan can compress the first and the second songs, then the sum of sizes will be equal 8 + 4 + 3 + 5 = 20 ≤ 21. Note that compressing any single song is not sufficient to copy all the songs on the flash drive (for example, after compressing the second song the sum of sizes will be equal to 10 + 4 + 3 + 5 = 22 > 21).
In the second example even if Ivan compresses all the songs the sum of sizes will be equal 8 + 4 + 1 + 4 = 17 > 16.
Submitted Solution:
```
n,m=map(int,input().split())
arr=[]
summ=0
for i in range(n):
arr1=list(map(int,input().split()))
arr.append(arr1[0]-arr1[1])
summ+=arr1[0]-arr1[1]
arr.sort(reverse=True)
flag=0
for i in range(n):
if summ<=m:
flag=1
print(i)
break
summ-=arr[i]
if flag==0 and summ<=m:
print(n)
elif summ>m:
print(-1)
``` | instruction | 0 | 28,265 | 8 | 56,530 |
No | output | 1 | 28,265 | 8 | 56,531 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ivan has n songs on his phone. The size of the i-th song is a_i bytes. Ivan also has a flash drive which can hold at most m bytes in total. Initially, his flash drive is empty.
Ivan wants to copy all n songs to the flash drive. He can compress the songs. If he compresses the i-th song, the size of the i-th song reduces from a_i to b_i bytes (b_i < a_i).
Ivan can compress any subset of the songs (possibly empty) and copy all the songs to his flash drive if the sum of their sizes is at most m. He can compress any subset of the songs (not necessarily contiguous).
Ivan wants to find the minimum number of songs he needs to compress in such a way that all his songs fit on the drive (i.e. the sum of their sizes is less than or equal to m).
If it is impossible to copy all the songs (even if Ivan compresses all the songs), print "-1". Otherwise print the minimum number of songs Ivan needs to compress.
Input
The first line of the input contains two integers n and m (1 ≤ n ≤ 10^5, 1 ≤ m ≤ 10^9) — the number of the songs on Ivan's phone and the capacity of Ivan's flash drive.
The next n lines contain two integers each: the i-th line contains two integers a_i and b_i (1 ≤ a_i, b_i ≤ 10^9, a_i > b_i) — the initial size of the i-th song and the size of the i-th song after compression.
Output
If it is impossible to compress a subset of the songs in such a way that all songs fit on the flash drive, print "-1". Otherwise print the minimum number of the songs to compress.
Examples
Input
4 21
10 8
7 4
3 1
5 4
Output
2
Input
4 16
10 8
7 4
3 1
5 4
Output
-1
Note
In the first example Ivan can compress the first and the third songs so after these moves the sum of sizes will be equal to 8 + 7 + 1 + 5 = 21 ≤ 21. Also Ivan can compress the first and the second songs, then the sum of sizes will be equal 8 + 4 + 3 + 5 = 20 ≤ 21. Note that compressing any single song is not sufficient to copy all the songs on the flash drive (for example, after compressing the second song the sum of sizes will be equal to 10 + 4 + 3 + 5 = 22 > 21).
In the second example even if Ivan compresses all the songs the sum of sizes will be equal 8 + 4 + 1 + 4 = 17 > 16.
Submitted Solution:
```
n, m = map(int, input().split())
a = []
b = []
for _ in range(n):
x, y = map(int, input().split())
a.append(x)
b.append(y)
offset = list(map(lambda x, y: x - y, a, b))
if sum(b) > m:
print(-1)
else:
offset = sorted(offset, reverse=True)
t = sum(a) - m
cnt = 0
s = 0
for x in offset:
if s >= t:
print(cnt)
break
else:
cnt += 1
s += x
if s >= t:
print(cnt)
``` | instruction | 0 | 28,266 | 8 | 56,532 |
No | output | 1 | 28,266 | 8 | 56,533 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ivan has n songs on his phone. The size of the i-th song is a_i bytes. Ivan also has a flash drive which can hold at most m bytes in total. Initially, his flash drive is empty.
Ivan wants to copy all n songs to the flash drive. He can compress the songs. If he compresses the i-th song, the size of the i-th song reduces from a_i to b_i bytes (b_i < a_i).
Ivan can compress any subset of the songs (possibly empty) and copy all the songs to his flash drive if the sum of their sizes is at most m. He can compress any subset of the songs (not necessarily contiguous).
Ivan wants to find the minimum number of songs he needs to compress in such a way that all his songs fit on the drive (i.e. the sum of their sizes is less than or equal to m).
If it is impossible to copy all the songs (even if Ivan compresses all the songs), print "-1". Otherwise print the minimum number of songs Ivan needs to compress.
Input
The first line of the input contains two integers n and m (1 ≤ n ≤ 10^5, 1 ≤ m ≤ 10^9) — the number of the songs on Ivan's phone and the capacity of Ivan's flash drive.
The next n lines contain two integers each: the i-th line contains two integers a_i and b_i (1 ≤ a_i, b_i ≤ 10^9, a_i > b_i) — the initial size of the i-th song and the size of the i-th song after compression.
Output
If it is impossible to compress a subset of the songs in such a way that all songs fit on the flash drive, print "-1". Otherwise print the minimum number of the songs to compress.
Examples
Input
4 21
10 8
7 4
3 1
5 4
Output
2
Input
4 16
10 8
7 4
3 1
5 4
Output
-1
Note
In the first example Ivan can compress the first and the third songs so after these moves the sum of sizes will be equal to 8 + 7 + 1 + 5 = 21 ≤ 21. Also Ivan can compress the first and the second songs, then the sum of sizes will be equal 8 + 4 + 3 + 5 = 20 ≤ 21. Note that compressing any single song is not sufficient to copy all the songs on the flash drive (for example, after compressing the second song the sum of sizes will be equal to 10 + 4 + 3 + 5 = 22 > 21).
In the second example even if Ivan compresses all the songs the sum of sizes will be equal 8 + 4 + 1 + 4 = 17 > 16.
Submitted Solution:
```
def check():
global n,m,a,b,ratio
if sum(b) > m:
print(-1)
return
compressed = set()
out = 0
#print(ratio)
size = sum(a)
dik = []
for i in range(n):
dik.append((i,ratio[i]))
dik = sorted(dik,key=lambda x : x[1],reverse=1)
start = 0
while size > m:
size = size - a[dik[start][0]] + b[dik[start][0]]
out += 1
start += 1
print(out)
return
[n,m] = [int(i) for i in input().split()]
a = []
b = []
ratio = []
for i in range(n):
foo = [int(i) for i in input().split()]
a.append(foo[0])
b.append(foo[1])
ratio.append(foo[0]/foo[1])
check()
``` | instruction | 0 | 28,267 | 8 | 56,534 |
No | output | 1 | 28,267 | 8 | 56,535 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is an easier version of the problem. In this version n ≤ 1000
The outskirts of the capital are being actively built up in Berland. The company "Kernel Panic" manages the construction of a residential complex of skyscrapers in New Berlskva. All skyscrapers are built along the highway. It is known that the company has already bought n plots along the highway and is preparing to build n skyscrapers, one skyscraper per plot.
Architects must consider several requirements when planning a skyscraper. Firstly, since the land on each plot has different properties, each skyscraper has a limit on the largest number of floors it can have. Secondly, according to the design code of the city, it is unacceptable for a skyscraper to simultaneously have higher skyscrapers both to the left and to the right of it.
Formally, let's number the plots from 1 to n. Then if the skyscraper on the i-th plot has a_i floors, it must hold that a_i is at most m_i (1 ≤ a_i ≤ m_i). Also there mustn't be integers j and k such that j < i < k and a_j > a_i < a_k. Plots j and k are not required to be adjacent to i.
The company wants the total number of floors in the built skyscrapers to be as large as possible. Help it to choose the number of floors for each skyscraper in an optimal way, i.e. in such a way that all requirements are fulfilled, and among all such construction plans choose any plan with the maximum possible total number of floors.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of plots.
The second line contains the integers m_1, m_2, …, m_n (1 ≤ m_i ≤ 10^9) — the limit on the number of floors for every possible number of floors for a skyscraper on each plot.
Output
Print n integers a_i — the number of floors in the plan for each skyscraper, such that all requirements are met, and the total number of floors in all skyscrapers is the maximum possible.
If there are multiple answers possible, print any of them.
Examples
Input
5
1 2 3 2 1
Output
1 2 3 2 1
Input
3
10 6 8
Output
10 6 6
Note
In the first example, you can build all skyscrapers with the highest possible height.
In the second test example, you cannot give the maximum height to all skyscrapers as this violates the design code restriction. The answer [10, 6, 6] is optimal. Note that the answer of [6, 6, 8] also satisfies all restrictions, but is not optimal. | instruction | 0 | 28,401 | 8 | 56,802 |
Tags: brute force, data structures, dp, greedy
Correct Solution:
```
n=int(input())
m=tuple(map(int,input().split()))
ma=list(m)
best=0
curlimit=m[0]
for i in range(n):
if(m[i]>curlimit):
ma[i]=curlimit
if(curlimit>m[i]):
curlimit=m[i]
best+=curlimit
besti=0
bestseq=ma
for i in range(n):
ma=list(m)
curlimit=m[i]
curbest=curlimit
for j in range(i+1,n):
if(m[j]>curlimit):
ma[j]=curlimit
if(curlimit>m[j]):
curlimit=m[j]
curbest+=curlimit
curlimit=m[i]
for j in range(i-1,-1,-1):
if(m[j]>curlimit):
ma[j]=curlimit
if(curlimit>m[j]):
curlimit=m[j]
curbest+=curlimit
if(curbest>best):
best=curbest
besti=i
bestseq=ma
print(*bestseq)
``` | output | 1 | 28,401 | 8 | 56,803 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is an easier version of the problem. In this version n ≤ 1000
The outskirts of the capital are being actively built up in Berland. The company "Kernel Panic" manages the construction of a residential complex of skyscrapers in New Berlskva. All skyscrapers are built along the highway. It is known that the company has already bought n plots along the highway and is preparing to build n skyscrapers, one skyscraper per plot.
Architects must consider several requirements when planning a skyscraper. Firstly, since the land on each plot has different properties, each skyscraper has a limit on the largest number of floors it can have. Secondly, according to the design code of the city, it is unacceptable for a skyscraper to simultaneously have higher skyscrapers both to the left and to the right of it.
Formally, let's number the plots from 1 to n. Then if the skyscraper on the i-th plot has a_i floors, it must hold that a_i is at most m_i (1 ≤ a_i ≤ m_i). Also there mustn't be integers j and k such that j < i < k and a_j > a_i < a_k. Plots j and k are not required to be adjacent to i.
The company wants the total number of floors in the built skyscrapers to be as large as possible. Help it to choose the number of floors for each skyscraper in an optimal way, i.e. in such a way that all requirements are fulfilled, and among all such construction plans choose any plan with the maximum possible total number of floors.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of plots.
The second line contains the integers m_1, m_2, …, m_n (1 ≤ m_i ≤ 10^9) — the limit on the number of floors for every possible number of floors for a skyscraper on each plot.
Output
Print n integers a_i — the number of floors in the plan for each skyscraper, such that all requirements are met, and the total number of floors in all skyscrapers is the maximum possible.
If there are multiple answers possible, print any of them.
Examples
Input
5
1 2 3 2 1
Output
1 2 3 2 1
Input
3
10 6 8
Output
10 6 6
Note
In the first example, you can build all skyscrapers with the highest possible height.
In the second test example, you cannot give the maximum height to all skyscrapers as this violates the design code restriction. The answer [10, 6, 6] is optimal. Note that the answer of [6, 6, 8] also satisfies all restrictions, but is not optimal. | instruction | 0 | 28,402 | 8 | 56,804 |
Tags: brute force, data structures, dp, greedy
Correct Solution:
```
from bisect import bisect_left as bl
from bisect import bisect_right as br
import heapq
import math
from collections import *
from functools import reduce,cmp_to_key
import sys
input = sys.stdin.readline
M = mod = 10**9 + 7
def factors(n):return sorted(set(reduce(list.__add__, ([i, n//i] for i in range(1, int(n**0.5) + 1) if n % i == 0))))
def inv_mod(n):return pow(n, mod - 2, mod)
def li():return [int(i) for i in input().rstrip('\n').split()]
def st():return input().rstrip('\n')
def val():return int(input().rstrip('\n'))
def li2():return [i for i in input().rstrip('\n').split(' ')]
def li3():return [int(i) for i in input().rstrip('\n')]
def leftincreasing(l):
l.append(0)
d = deque()
d.append(-1)
# d.append(0)
dp = []
# print(l)
for i in range(len(l)-1):
while l[d[-1]] >= l[i]:d.pop()
if i and l[i] >= l[i-1]:
dp.append(dp[-1] + l[i])
elif d[-1] == -1:
dp.append(l[i]*(i + 1))
else:
dp.append(dp[d[-1]] + l[i]*(i - d[-1]))
d.append(i)
return dp
def giveans(i,l):
l1 = []
l2 = []
temp = i
i -= 1
while i>=0:
if not l1:
l1.append(min(l[i],l[temp]))
else:
l1.append(min(l[i],l1[-1]))
i -= 1
i = temp + 1
while i < len(l):
if not l2:
l2.append(min(l[i],l[temp]))
else:
l2.append(min(l[i],l2[-1]))
i += 1
return l1[::-1] + [l[temp]] + l2
n = val()
l = li()
ldec = leftincreasing(l[:])
linc = leftincreasing(l[:][::-1])[::-1]
# print(l)
# print(ldec,linc,sep = '\n')
ans = 0
currans = -float('inf')
for i in range(n):
if ldec[i] + linc[i] - l[i] > currans:
currans = ldec[i] + linc[i] - l[i]
ans = i
elif currans == ldec[i] + linc[i] - l[i] and l[ans] < l[i]:
ans = i
print(*giveans(ans,l))
``` | output | 1 | 28,402 | 8 | 56,805 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is an easier version of the problem. In this version n ≤ 1000
The outskirts of the capital are being actively built up in Berland. The company "Kernel Panic" manages the construction of a residential complex of skyscrapers in New Berlskva. All skyscrapers are built along the highway. It is known that the company has already bought n plots along the highway and is preparing to build n skyscrapers, one skyscraper per plot.
Architects must consider several requirements when planning a skyscraper. Firstly, since the land on each plot has different properties, each skyscraper has a limit on the largest number of floors it can have. Secondly, according to the design code of the city, it is unacceptable for a skyscraper to simultaneously have higher skyscrapers both to the left and to the right of it.
Formally, let's number the plots from 1 to n. Then if the skyscraper on the i-th plot has a_i floors, it must hold that a_i is at most m_i (1 ≤ a_i ≤ m_i). Also there mustn't be integers j and k such that j < i < k and a_j > a_i < a_k. Plots j and k are not required to be adjacent to i.
The company wants the total number of floors in the built skyscrapers to be as large as possible. Help it to choose the number of floors for each skyscraper in an optimal way, i.e. in such a way that all requirements are fulfilled, and among all such construction plans choose any plan with the maximum possible total number of floors.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of plots.
The second line contains the integers m_1, m_2, …, m_n (1 ≤ m_i ≤ 10^9) — the limit on the number of floors for every possible number of floors for a skyscraper on each plot.
Output
Print n integers a_i — the number of floors in the plan for each skyscraper, such that all requirements are met, and the total number of floors in all skyscrapers is the maximum possible.
If there are multiple answers possible, print any of them.
Examples
Input
5
1 2 3 2 1
Output
1 2 3 2 1
Input
3
10 6 8
Output
10 6 6
Note
In the first example, you can build all skyscrapers with the highest possible height.
In the second test example, you cannot give the maximum height to all skyscrapers as this violates the design code restriction. The answer [10, 6, 6] is optimal. Note that the answer of [6, 6, 8] also satisfies all restrictions, but is not optimal. | instruction | 0 | 28,403 | 8 | 56,806 |
Tags: brute force, data structures, dp, greedy
Correct Solution:
```
n=int(input())
x=list(map(int,input().split()))
dp,dp2,s,s2,d,d2=[0]*n,[0]*n,[],[],{},{}
for i in range(n):
if i==0:
dp[0]=x[0]
elif x[i]>=x[i-1]:
dp[i]=dp[i-1]+x[i]
s.append(x[i-1])
else:
while len(s)>0 and x[i]<s[len(s)-1]:
s.pop()
if len(s)==0:
dp[i]=x[i]*(i+1)
else:
dp[i]=dp[d[s[len(s)-1]]]+x[i]*(i-d[s[len(s)-1]])
d[x[i]]=i
for i in range(n-1,-1,-1):
if i==n-1:
dp2[i]=x[i]
elif x[i]>=x[i+1]:
dp2[i]=dp2[i+1]+x[i]
s2.append(x[i+1])
else:
while len(s2)>0 and x[i]<s2[len(s2)-1]:
s2.pop()
if len(s2)==0:
dp2[i]=x[i]*(n-i)
else:
dp2[i]=dp2[d2[s2[len(s2)-1]]]+x[i]*(d2[s2[len(s2)-1]]-i)
d2[x[i]]=i
ans,ma=0,0
for i in range(n):
if dp[i]+dp2[i]-x[i]>ma:
ma=dp[i]+dp2[i]-x[i]
ans=i
lim,y=x[ans],[0]*n
y[ans]=x[ans]
for i in range(ans+1,n):
y[i]=min(x[i],lim)
lim=y[i]
lim=x[ans]
for i in range(ans-1,-1,-1):
y[i]=min(lim,x[i])
lim=y[i]
for i in range(n):
print(y[i],end=" ")
``` | output | 1 | 28,403 | 8 | 56,807 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is an easier version of the problem. In this version n ≤ 1000
The outskirts of the capital are being actively built up in Berland. The company "Kernel Panic" manages the construction of a residential complex of skyscrapers in New Berlskva. All skyscrapers are built along the highway. It is known that the company has already bought n plots along the highway and is preparing to build n skyscrapers, one skyscraper per plot.
Architects must consider several requirements when planning a skyscraper. Firstly, since the land on each plot has different properties, each skyscraper has a limit on the largest number of floors it can have. Secondly, according to the design code of the city, it is unacceptable for a skyscraper to simultaneously have higher skyscrapers both to the left and to the right of it.
Formally, let's number the plots from 1 to n. Then if the skyscraper on the i-th plot has a_i floors, it must hold that a_i is at most m_i (1 ≤ a_i ≤ m_i). Also there mustn't be integers j and k such that j < i < k and a_j > a_i < a_k. Plots j and k are not required to be adjacent to i.
The company wants the total number of floors in the built skyscrapers to be as large as possible. Help it to choose the number of floors for each skyscraper in an optimal way, i.e. in such a way that all requirements are fulfilled, and among all such construction plans choose any plan with the maximum possible total number of floors.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of plots.
The second line contains the integers m_1, m_2, …, m_n (1 ≤ m_i ≤ 10^9) — the limit on the number of floors for every possible number of floors for a skyscraper on each plot.
Output
Print n integers a_i — the number of floors in the plan for each skyscraper, such that all requirements are met, and the total number of floors in all skyscrapers is the maximum possible.
If there are multiple answers possible, print any of them.
Examples
Input
5
1 2 3 2 1
Output
1 2 3 2 1
Input
3
10 6 8
Output
10 6 6
Note
In the first example, you can build all skyscrapers with the highest possible height.
In the second test example, you cannot give the maximum height to all skyscrapers as this violates the design code restriction. The answer [10, 6, 6] is optimal. Note that the answer of [6, 6, 8] also satisfies all restrictions, but is not optimal. | instruction | 0 | 28,404 | 8 | 56,808 |
Tags: brute force, data structures, dp, greedy
Correct Solution:
```
from sys import stdin,stdout
from math import gcd,sqrt
from collections import deque
input=stdin.readline
R=lambda:map(int,input().split())
I=lambda:int(input())
S=lambda:input().rstrip('\n')
L=lambda:list(R())
P=lambda x:stdout.write(x)
lcm=lambda x,y:(x*y)//gcd(x,y)
hg=lambda x,y:((y+x-1)//x)*x
pw=lambda x:0 if x==1 else 1+pw(x//2)
chk=lambda x:chk(x//2) if not x%2 else True if x==1 else False
sm=lambda x:(x**2+x)//2
N=10**9+7
def floor(ind,val):
mn=val
arr=deque([val])
for i in range(ind-1,-1,-1):
if a[i]>mn:arr.appendleft(mn)
else:mn=a[i];arr.appendleft(mn)
mn=val
for i in range(ind+1,n):
if a[i]>mn:arr.append(mn)
else:mn=a[i];arr.append(mn)
return arr
n=I()
a=L()
ans=floor(0,a[0])
sm=sum(ans)
for i in range(1,n):
ans1=floor(i,a[i])
if sum(ans1)>sm:
sm=sum(ans1)
ans=ans1.copy()
print(*ans)
``` | output | 1 | 28,404 | 8 | 56,809 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is an easier version of the problem. In this version n ≤ 1000
The outskirts of the capital are being actively built up in Berland. The company "Kernel Panic" manages the construction of a residential complex of skyscrapers in New Berlskva. All skyscrapers are built along the highway. It is known that the company has already bought n plots along the highway and is preparing to build n skyscrapers, one skyscraper per plot.
Architects must consider several requirements when planning a skyscraper. Firstly, since the land on each plot has different properties, each skyscraper has a limit on the largest number of floors it can have. Secondly, according to the design code of the city, it is unacceptable for a skyscraper to simultaneously have higher skyscrapers both to the left and to the right of it.
Formally, let's number the plots from 1 to n. Then if the skyscraper on the i-th plot has a_i floors, it must hold that a_i is at most m_i (1 ≤ a_i ≤ m_i). Also there mustn't be integers j and k such that j < i < k and a_j > a_i < a_k. Plots j and k are not required to be adjacent to i.
The company wants the total number of floors in the built skyscrapers to be as large as possible. Help it to choose the number of floors for each skyscraper in an optimal way, i.e. in such a way that all requirements are fulfilled, and among all such construction plans choose any plan with the maximum possible total number of floors.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of plots.
The second line contains the integers m_1, m_2, …, m_n (1 ≤ m_i ≤ 10^9) — the limit on the number of floors for every possible number of floors for a skyscraper on each plot.
Output
Print n integers a_i — the number of floors in the plan for each skyscraper, such that all requirements are met, and the total number of floors in all skyscrapers is the maximum possible.
If there are multiple answers possible, print any of them.
Examples
Input
5
1 2 3 2 1
Output
1 2 3 2 1
Input
3
10 6 8
Output
10 6 6
Note
In the first example, you can build all skyscrapers with the highest possible height.
In the second test example, you cannot give the maximum height to all skyscrapers as this violates the design code restriction. The answer [10, 6, 6] is optimal. Note that the answer of [6, 6, 8] also satisfies all restrictions, but is not optimal. | instruction | 0 | 28,405 | 8 | 56,810 |
Tags: brute force, data structures, dp, greedy
Correct Solution:
```
from collections import defaultdict, Counter
from bisect import bisect, bisect_left
from math import sqrt, gcd, ceil, factorial
from heapq import heapify, heappush, heappop
MOD = 10**9 + 7
inf = float("inf")
ans_ = []
def nin():return int(input())
def ninf():return int(file.readline())
def st():return (input().strip())
def stf():return (file.readline().strip())
def read(): return list(map(int, input().strip().split()))
def readf():return list(map(int, file.readline().strip().split()))
ans_ = []
def mini(arr):
n = len(arr)
stk = [0]
a = [-1]*n
for i in range(n):
while stk and arr[stk[-1]] >= arr[i]:
stk.pop()
if stk:a[i] = stk[-1]
stk.append(i)
return(a)
# file = open("input.txt", "r")
def solve():
n = nin(); arr = read()
lmin = mini(arr)
rmin = [n-i-1 for i in mini(arr[::-1])[::-1]]
pre = [0]*n; suf = [0]*n
for i in range(n):
x, y = i, n-i-1
if lmin[x] == -1:
pre[x] = (x + 1) * arr[x]
else:
pre[x] = pre[lmin[x]] + (x - lmin[i]) * arr[x]
if rmin[y] == n:
suf[y] = (n - y) * arr[y]
else:
suf[y] = suf[rmin[y]] + (rmin[y] - y) * arr[y]
mx, ind = 0, -1
for i in range(n):
if i == 0:
tem = suf[i]
elif i == n-1:
tem = pre[i]
else:
tem = pre[i]+suf[i]-arr[i]
if tem > mx:
mx = tem
ind = i
ans, i = [0]*n, ind
while i != -1:
for x in range(i, lmin[i],-1):
ans[x] = arr[i]
i = lmin[i]
i = ind
while i != n:
for x in range(i, rmin[i]):
ans[x] = arr[i]
i = rmin[i]
# print(arr)
# print(lmin, rmin)
# print(pre, suf)
# print(mx, ind)
ans_.append(ans)
# file.close()
solve()
for i in ans_:print(*i)
``` | output | 1 | 28,405 | 8 | 56,811 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is an easier version of the problem. In this version n ≤ 1000
The outskirts of the capital are being actively built up in Berland. The company "Kernel Panic" manages the construction of a residential complex of skyscrapers in New Berlskva. All skyscrapers are built along the highway. It is known that the company has already bought n plots along the highway and is preparing to build n skyscrapers, one skyscraper per plot.
Architects must consider several requirements when planning a skyscraper. Firstly, since the land on each plot has different properties, each skyscraper has a limit on the largest number of floors it can have. Secondly, according to the design code of the city, it is unacceptable for a skyscraper to simultaneously have higher skyscrapers both to the left and to the right of it.
Formally, let's number the plots from 1 to n. Then if the skyscraper on the i-th plot has a_i floors, it must hold that a_i is at most m_i (1 ≤ a_i ≤ m_i). Also there mustn't be integers j and k such that j < i < k and a_j > a_i < a_k. Plots j and k are not required to be adjacent to i.
The company wants the total number of floors in the built skyscrapers to be as large as possible. Help it to choose the number of floors for each skyscraper in an optimal way, i.e. in such a way that all requirements are fulfilled, and among all such construction plans choose any plan with the maximum possible total number of floors.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of plots.
The second line contains the integers m_1, m_2, …, m_n (1 ≤ m_i ≤ 10^9) — the limit on the number of floors for every possible number of floors for a skyscraper on each plot.
Output
Print n integers a_i — the number of floors in the plan for each skyscraper, such that all requirements are met, and the total number of floors in all skyscrapers is the maximum possible.
If there are multiple answers possible, print any of them.
Examples
Input
5
1 2 3 2 1
Output
1 2 3 2 1
Input
3
10 6 8
Output
10 6 6
Note
In the first example, you can build all skyscrapers with the highest possible height.
In the second test example, you cannot give the maximum height to all skyscrapers as this violates the design code restriction. The answer [10, 6, 6] is optimal. Note that the answer of [6, 6, 8] also satisfies all restrictions, but is not optimal. | instruction | 0 | 28,406 | 8 | 56,812 |
Tags: brute force, data structures, dp, greedy
Correct Solution:
```
import math
if __name__ == "__main__":
n = int(input())
mi = input().split()
mi = [int(m) for m in mi]
l = [0 for i in range(n)]
r = [0 for i in range(n)]
right_to_left = [-1 for i in range(n)]
left_to_right = [-1 for i in range(n)]
stack = [0]
for i in range(1, n, 1):
while len(stack) != 0 and mi[stack[-1]] > mi[i]:
left_to_right[stack.pop()] = i
stack.append(i)
stack = [n-1]
for i in range(n-2, -1, -1):
while len(stack) != 0 and mi[stack[-1]] > mi[i]:
right_to_left[stack.pop()] = i
stack.append(i)
l[0] = mi[0]
for i in range(1, n, 1):
if mi[i - 1] <= mi[i]:
l[i] = l[i - 1] + mi[i]
else:
li = right_to_left[i]
if li == -1:
l[i] = mi[i] * (i + 1)
else:
l[i] = l[li] + mi[i] * (i - li)
r[n-1] = mi[n-1]
for i in range(n - 2, -1, -1):
if mi[i + 1] <= mi[i]:
r[i] = r[i + 1] + mi[i]
else:
ri = left_to_right[i]
if ri == -1:
r[i] = mi[i] * (n - i)
else:
r[i] = r[ri] + mi[i] * (ri - i)
# print(f"l: {l}")
# print(f"r: {r}")
peak = 0
for i in range(n):
if l[peak] + r[peak] - mi[peak] < l[i] + r[i] - mi[i]:
peak = i
# print(f"peak: {peak}")
for i in range(peak, 0, -1):
if mi[i-1] > mi[i]:
mi[i-1] = mi[i]
for i in range(peak, n-1, 1):
if mi[i+1] > mi[i]:
mi[i+1] = mi[i]
for i in range(n):
print(mi[i],end=" ")
print()
``` | output | 1 | 28,406 | 8 | 56,813 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is an easier version of the problem. In this version n ≤ 1000
The outskirts of the capital are being actively built up in Berland. The company "Kernel Panic" manages the construction of a residential complex of skyscrapers in New Berlskva. All skyscrapers are built along the highway. It is known that the company has already bought n plots along the highway and is preparing to build n skyscrapers, one skyscraper per plot.
Architects must consider several requirements when planning a skyscraper. Firstly, since the land on each plot has different properties, each skyscraper has a limit on the largest number of floors it can have. Secondly, according to the design code of the city, it is unacceptable for a skyscraper to simultaneously have higher skyscrapers both to the left and to the right of it.
Formally, let's number the plots from 1 to n. Then if the skyscraper on the i-th plot has a_i floors, it must hold that a_i is at most m_i (1 ≤ a_i ≤ m_i). Also there mustn't be integers j and k such that j < i < k and a_j > a_i < a_k. Plots j and k are not required to be adjacent to i.
The company wants the total number of floors in the built skyscrapers to be as large as possible. Help it to choose the number of floors for each skyscraper in an optimal way, i.e. in such a way that all requirements are fulfilled, and among all such construction plans choose any plan with the maximum possible total number of floors.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of plots.
The second line contains the integers m_1, m_2, …, m_n (1 ≤ m_i ≤ 10^9) — the limit on the number of floors for every possible number of floors for a skyscraper on each plot.
Output
Print n integers a_i — the number of floors in the plan for each skyscraper, such that all requirements are met, and the total number of floors in all skyscrapers is the maximum possible.
If there are multiple answers possible, print any of them.
Examples
Input
5
1 2 3 2 1
Output
1 2 3 2 1
Input
3
10 6 8
Output
10 6 6
Note
In the first example, you can build all skyscrapers with the highest possible height.
In the second test example, you cannot give the maximum height to all skyscrapers as this violates the design code restriction. The answer [10, 6, 6] is optimal. Note that the answer of [6, 6, 8] also satisfies all restrictions, but is not optimal. | instruction | 0 | 28,407 | 8 | 56,814 |
Tags: brute force, data structures, dp, greedy
Correct Solution:
```
import sys
n = int(sys.stdin.readline().strip())
m = list(map(int, sys.stdin.readline().strip().split()))
left = []
right = []
a = []
highest = 0
floors = 0
for i in range(n):
if(highest > m[i]):
for j in range(i-1, -1, -1):
if(a[j] <= m[i]):
break
floors -= a[j]-m[i]
a[j] = m[i]
left.append(floors)
floors += m[i]
a.append(m[i])
highest = m[i]
a = []
highest = 0
floors = 0
for i in range(n-1, -1, -1):
if(highest > m[i]):
for j in range(i+1, n):
if(a[n-1-j] <= m[i]):
break
floors -= a[n-1-j]-m[i]
a[n-1-j] = m[i]
right.append(floors)
floors += m[i]
a.append(m[i])
highest = m[i]
right.reverse()
maximum = -1
highest = -1
for i in range(n):
floors = left[i] + right[i] + m[i]
if(maximum < floors):
maximum = floors
highest = i
floors = []
high = m[highest]
for i in range(highest, -1, -1):
high = min(high, m[i])
floors.append(str(high))
floors.reverse()
high = m[highest]
for i in range(highest+1, n):
high = min(high, m[i])
floors.append(str(high))
sys.stdout.write(" ".join(floors))
``` | output | 1 | 28,407 | 8 | 56,815 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is an easier version of the problem. In this version n ≤ 1000
The outskirts of the capital are being actively built up in Berland. The company "Kernel Panic" manages the construction of a residential complex of skyscrapers in New Berlskva. All skyscrapers are built along the highway. It is known that the company has already bought n plots along the highway and is preparing to build n skyscrapers, one skyscraper per plot.
Architects must consider several requirements when planning a skyscraper. Firstly, since the land on each plot has different properties, each skyscraper has a limit on the largest number of floors it can have. Secondly, according to the design code of the city, it is unacceptable for a skyscraper to simultaneously have higher skyscrapers both to the left and to the right of it.
Formally, let's number the plots from 1 to n. Then if the skyscraper on the i-th plot has a_i floors, it must hold that a_i is at most m_i (1 ≤ a_i ≤ m_i). Also there mustn't be integers j and k such that j < i < k and a_j > a_i < a_k. Plots j and k are not required to be adjacent to i.
The company wants the total number of floors in the built skyscrapers to be as large as possible. Help it to choose the number of floors for each skyscraper in an optimal way, i.e. in such a way that all requirements are fulfilled, and among all such construction plans choose any plan with the maximum possible total number of floors.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of plots.
The second line contains the integers m_1, m_2, …, m_n (1 ≤ m_i ≤ 10^9) — the limit on the number of floors for every possible number of floors for a skyscraper on each plot.
Output
Print n integers a_i — the number of floors in the plan for each skyscraper, such that all requirements are met, and the total number of floors in all skyscrapers is the maximum possible.
If there are multiple answers possible, print any of them.
Examples
Input
5
1 2 3 2 1
Output
1 2 3 2 1
Input
3
10 6 8
Output
10 6 6
Note
In the first example, you can build all skyscrapers with the highest possible height.
In the second test example, you cannot give the maximum height to all skyscrapers as this violates the design code restriction. The answer [10, 6, 6] is optimal. Note that the answer of [6, 6, 8] also satisfies all restrictions, but is not optimal. | instruction | 0 | 28,408 | 8 | 56,816 |
Tags: brute force, data structures, dp, greedy
Correct Solution:
```
n = int(input())
m = list(map(int, input().split()))
sums = 0
ans = []
for i in range(n):
t = m[::]
for j in range(i - 1, -1, -1):
t[j] = min(t[j], t[j + 1])
for j in range(i + 1, n):
t[j] = min(t[j], t[j - 1])
# print(t, ans)
s = sum(t)
if s > sums:
sums=s
ans = t
print(*ans)
``` | output | 1 | 28,408 | 8 | 56,817 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an easier version of the problem. In this version n ≤ 1000
The outskirts of the capital are being actively built up in Berland. The company "Kernel Panic" manages the construction of a residential complex of skyscrapers in New Berlskva. All skyscrapers are built along the highway. It is known that the company has already bought n plots along the highway and is preparing to build n skyscrapers, one skyscraper per plot.
Architects must consider several requirements when planning a skyscraper. Firstly, since the land on each plot has different properties, each skyscraper has a limit on the largest number of floors it can have. Secondly, according to the design code of the city, it is unacceptable for a skyscraper to simultaneously have higher skyscrapers both to the left and to the right of it.
Formally, let's number the plots from 1 to n. Then if the skyscraper on the i-th plot has a_i floors, it must hold that a_i is at most m_i (1 ≤ a_i ≤ m_i). Also there mustn't be integers j and k such that j < i < k and a_j > a_i < a_k. Plots j and k are not required to be adjacent to i.
The company wants the total number of floors in the built skyscrapers to be as large as possible. Help it to choose the number of floors for each skyscraper in an optimal way, i.e. in such a way that all requirements are fulfilled, and among all such construction plans choose any plan with the maximum possible total number of floors.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of plots.
The second line contains the integers m_1, m_2, …, m_n (1 ≤ m_i ≤ 10^9) — the limit on the number of floors for every possible number of floors for a skyscraper on each plot.
Output
Print n integers a_i — the number of floors in the plan for each skyscraper, such that all requirements are met, and the total number of floors in all skyscrapers is the maximum possible.
If there are multiple answers possible, print any of them.
Examples
Input
5
1 2 3 2 1
Output
1 2 3 2 1
Input
3
10 6 8
Output
10 6 6
Note
In the first example, you can build all skyscrapers with the highest possible height.
In the second test example, you cannot give the maximum height to all skyscrapers as this violates the design code restriction. The answer [10, 6, 6] is optimal. Note that the answer of [6, 6, 8] also satisfies all restrictions, but is not optimal.
Submitted Solution:
```
import sys
import math
import heapq
import collections
def inputnum():
return(int(input()))
def inputnums():
return(map(int,input().split()))
def inputlist():
return(list(map(int,input().split())))
def inputstring():
return([x for x in input()])
def inputstringnum():
return([ord(x)-ord('a') for x in input()])
def inputmatrixchar(rows):
arr2d = [[j for j in input().strip()] for i in range(rows)]
return arr2d
def inputmatrixint(rows):
arr2d = []
for _ in range(rows):
arr2d.append([int(i) for i in input().split()])
return arr2d
n = inputnum()
m = inputlist()
ans = [0]*n
anssum = 0
for i in range(n):
cur = [0]*n
cur[i] = m[i]
cursum = m[i]
temp = m[i]
for j in reversed(range(i)):
cur[j] = min(m[j], temp)
cursum += min(m[j], temp)
temp = min(m[j], temp)
temp = m[i]
for j in range(i+1, n):
cur[j] = min(m[j], temp)
cursum += min(m[j], temp)
temp = min(m[j], temp)
if cursum > anssum:
anssum = cursum
ans = cur
print(*ans)
``` | instruction | 0 | 28,409 | 8 | 56,818 |
Yes | output | 1 | 28,409 | 8 | 56,819 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an easier version of the problem. In this version n ≤ 1000
The outskirts of the capital are being actively built up in Berland. The company "Kernel Panic" manages the construction of a residential complex of skyscrapers in New Berlskva. All skyscrapers are built along the highway. It is known that the company has already bought n plots along the highway and is preparing to build n skyscrapers, one skyscraper per plot.
Architects must consider several requirements when planning a skyscraper. Firstly, since the land on each plot has different properties, each skyscraper has a limit on the largest number of floors it can have. Secondly, according to the design code of the city, it is unacceptable for a skyscraper to simultaneously have higher skyscrapers both to the left and to the right of it.
Formally, let's number the plots from 1 to n. Then if the skyscraper on the i-th plot has a_i floors, it must hold that a_i is at most m_i (1 ≤ a_i ≤ m_i). Also there mustn't be integers j and k such that j < i < k and a_j > a_i < a_k. Plots j and k are not required to be adjacent to i.
The company wants the total number of floors in the built skyscrapers to be as large as possible. Help it to choose the number of floors for each skyscraper in an optimal way, i.e. in such a way that all requirements are fulfilled, and among all such construction plans choose any plan with the maximum possible total number of floors.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of plots.
The second line contains the integers m_1, m_2, …, m_n (1 ≤ m_i ≤ 10^9) — the limit on the number of floors for every possible number of floors for a skyscraper on each plot.
Output
Print n integers a_i — the number of floors in the plan for each skyscraper, such that all requirements are met, and the total number of floors in all skyscrapers is the maximum possible.
If there are multiple answers possible, print any of them.
Examples
Input
5
1 2 3 2 1
Output
1 2 3 2 1
Input
3
10 6 8
Output
10 6 6
Note
In the first example, you can build all skyscrapers with the highest possible height.
In the second test example, you cannot give the maximum height to all skyscrapers as this violates the design code restriction. The answer [10, 6, 6] is optimal. Note that the answer of [6, 6, 8] also satisfies all restrictions, but is not optimal.
Submitted Solution:
```
def r(x, d):
stack = [-1]
s = [0] * x
for i in range(x - 1, -1, -1):
while d[i] < d[stack[-1]] and stack[-1] != -1:
stack.pop()
s[i] = (x - i) * d[i] if stack[-1] == -1 else s[stack[-1]] + d[i] *(stack[-1] - i)
stack += [i]
return s
def total():
inf = float('inf')
n = int(input())
a = [*map(int, input().split())]
le = r(n, a)
a = a[::-1]
ri = r(n, a)[::-1]
a = a[::-1]
ma = 0
x = 0
for i in range(n):
if le[i] + ri[i] - a[i] > ma:
ma = le[i] + ri[i] - a[i]
x = i
for i in range(x + 1, n):
a[i] = min(a[i], a[i - 1])
for i in range(x - 1, -1, -1):
a[i] = min(a[i], a[i + 1])
print(*a)
total()
``` | instruction | 0 | 28,410 | 8 | 56,820 |
Yes | output | 1 | 28,410 | 8 | 56,821 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an easier version of the problem. In this version n ≤ 1000
The outskirts of the capital are being actively built up in Berland. The company "Kernel Panic" manages the construction of a residential complex of skyscrapers in New Berlskva. All skyscrapers are built along the highway. It is known that the company has already bought n plots along the highway and is preparing to build n skyscrapers, one skyscraper per plot.
Architects must consider several requirements when planning a skyscraper. Firstly, since the land on each plot has different properties, each skyscraper has a limit on the largest number of floors it can have. Secondly, according to the design code of the city, it is unacceptable for a skyscraper to simultaneously have higher skyscrapers both to the left and to the right of it.
Formally, let's number the plots from 1 to n. Then if the skyscraper on the i-th plot has a_i floors, it must hold that a_i is at most m_i (1 ≤ a_i ≤ m_i). Also there mustn't be integers j and k such that j < i < k and a_j > a_i < a_k. Plots j and k are not required to be adjacent to i.
The company wants the total number of floors in the built skyscrapers to be as large as possible. Help it to choose the number of floors for each skyscraper in an optimal way, i.e. in such a way that all requirements are fulfilled, and among all such construction plans choose any plan with the maximum possible total number of floors.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of plots.
The second line contains the integers m_1, m_2, …, m_n (1 ≤ m_i ≤ 10^9) — the limit on the number of floors for every possible number of floors for a skyscraper on each plot.
Output
Print n integers a_i — the number of floors in the plan for each skyscraper, such that all requirements are met, and the total number of floors in all skyscrapers is the maximum possible.
If there are multiple answers possible, print any of them.
Examples
Input
5
1 2 3 2 1
Output
1 2 3 2 1
Input
3
10 6 8
Output
10 6 6
Note
In the first example, you can build all skyscrapers with the highest possible height.
In the second test example, you cannot give the maximum height to all skyscrapers as this violates the design code restriction. The answer [10, 6, 6] is optimal. Note that the answer of [6, 6, 8] also satisfies all restrictions, but is not optimal.
Submitted Solution:
```
n=int(input())
M = list(map(int,input().split()))
maxsum = 0
for i in range(n):
a = M.copy()
Sum = a[i]
for j in range(i+1,n):
a[j] = min(a[j],a[j-1])
Sum+=a[j]
for j in range(i-1,-1,-1):
a[j] = min(a[j],a[j+1])
Sum+= a[j]
if Sum > maxsum :
maxsum = Sum
array = a.copy()
for i in array :
print(i,end=" ")
``` | instruction | 0 | 28,411 | 8 | 56,822 |
Yes | output | 1 | 28,411 | 8 | 56,823 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an easier version of the problem. In this version n ≤ 1000
The outskirts of the capital are being actively built up in Berland. The company "Kernel Panic" manages the construction of a residential complex of skyscrapers in New Berlskva. All skyscrapers are built along the highway. It is known that the company has already bought n plots along the highway and is preparing to build n skyscrapers, one skyscraper per plot.
Architects must consider several requirements when planning a skyscraper. Firstly, since the land on each plot has different properties, each skyscraper has a limit on the largest number of floors it can have. Secondly, according to the design code of the city, it is unacceptable for a skyscraper to simultaneously have higher skyscrapers both to the left and to the right of it.
Formally, let's number the plots from 1 to n. Then if the skyscraper on the i-th plot has a_i floors, it must hold that a_i is at most m_i (1 ≤ a_i ≤ m_i). Also there mustn't be integers j and k such that j < i < k and a_j > a_i < a_k. Plots j and k are not required to be adjacent to i.
The company wants the total number of floors in the built skyscrapers to be as large as possible. Help it to choose the number of floors for each skyscraper in an optimal way, i.e. in such a way that all requirements are fulfilled, and among all such construction plans choose any plan with the maximum possible total number of floors.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of plots.
The second line contains the integers m_1, m_2, …, m_n (1 ≤ m_i ≤ 10^9) — the limit on the number of floors for every possible number of floors for a skyscraper on each plot.
Output
Print n integers a_i — the number of floors in the plan for each skyscraper, such that all requirements are met, and the total number of floors in all skyscrapers is the maximum possible.
If there are multiple answers possible, print any of them.
Examples
Input
5
1 2 3 2 1
Output
1 2 3 2 1
Input
3
10 6 8
Output
10 6 6
Note
In the first example, you can build all skyscrapers with the highest possible height.
In the second test example, you cannot give the maximum height to all skyscrapers as this violates the design code restriction. The answer [10, 6, 6] is optimal. Note that the answer of [6, 6, 8] also satisfies all restrictions, but is not optimal.
Submitted Solution:
```
n = int(input())
m = list(map(int, input().split()))
ans, idx = 0, -1
for i in range(n):
a = [0] * n
a[i] = m[i]
for j in range(i - 1, -1, -1):
a[j] = min(m[j], a[j + 1])
for j in range(i + 1, n):
a[j] = min(m[j], a[j - 1])
tot = sum(a)
if tot > ans:
ans = tot
idx = i
a = [0] * n
a[idx] = m[idx]
for j in range(idx - 1, -1, -1):
a[j] = min(m[j], a[j + 1])
for j in range(idx + 1, n):
a[j] = min(m[j], a[j - 1])
print(*a)
``` | instruction | 0 | 28,412 | 8 | 56,824 |
Yes | output | 1 | 28,412 | 8 | 56,825 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an easier version of the problem. In this version n ≤ 1000
The outskirts of the capital are being actively built up in Berland. The company "Kernel Panic" manages the construction of a residential complex of skyscrapers in New Berlskva. All skyscrapers are built along the highway. It is known that the company has already bought n plots along the highway and is preparing to build n skyscrapers, one skyscraper per plot.
Architects must consider several requirements when planning a skyscraper. Firstly, since the land on each plot has different properties, each skyscraper has a limit on the largest number of floors it can have. Secondly, according to the design code of the city, it is unacceptable for a skyscraper to simultaneously have higher skyscrapers both to the left and to the right of it.
Formally, let's number the plots from 1 to n. Then if the skyscraper on the i-th plot has a_i floors, it must hold that a_i is at most m_i (1 ≤ a_i ≤ m_i). Also there mustn't be integers j and k such that j < i < k and a_j > a_i < a_k. Plots j and k are not required to be adjacent to i.
The company wants the total number of floors in the built skyscrapers to be as large as possible. Help it to choose the number of floors for each skyscraper in an optimal way, i.e. in such a way that all requirements are fulfilled, and among all such construction plans choose any plan with the maximum possible total number of floors.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of plots.
The second line contains the integers m_1, m_2, …, m_n (1 ≤ m_i ≤ 10^9) — the limit on the number of floors for every possible number of floors for a skyscraper on each plot.
Output
Print n integers a_i — the number of floors in the plan for each skyscraper, such that all requirements are met, and the total number of floors in all skyscrapers is the maximum possible.
If there are multiple answers possible, print any of them.
Examples
Input
5
1 2 3 2 1
Output
1 2 3 2 1
Input
3
10 6 8
Output
10 6 6
Note
In the first example, you can build all skyscrapers with the highest possible height.
In the second test example, you cannot give the maximum height to all skyscrapers as this violates the design code restriction. The answer [10, 6, 6] is optimal. Note that the answer of [6, 6, 8] also satisfies all restrictions, but is not optimal.
Submitted Solution:
```
n=int(input())
a=list(map(int,input().split()))
s=0;c=[]
for i in range(n):
b=a[::]
for j in range(i-1,-1,-1):b[j]=min(a[j],a[j+1])
for j in range(i+1,n):b[j]=min(a[j],a[j-1])
if sum(b)>s:
c=b;s=sum(b)
print(c)
``` | instruction | 0 | 28,413 | 8 | 56,826 |
No | output | 1 | 28,413 | 8 | 56,827 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an easier version of the problem. In this version n ≤ 1000
The outskirts of the capital are being actively built up in Berland. The company "Kernel Panic" manages the construction of a residential complex of skyscrapers in New Berlskva. All skyscrapers are built along the highway. It is known that the company has already bought n plots along the highway and is preparing to build n skyscrapers, one skyscraper per plot.
Architects must consider several requirements when planning a skyscraper. Firstly, since the land on each plot has different properties, each skyscraper has a limit on the largest number of floors it can have. Secondly, according to the design code of the city, it is unacceptable for a skyscraper to simultaneously have higher skyscrapers both to the left and to the right of it.
Formally, let's number the plots from 1 to n. Then if the skyscraper on the i-th plot has a_i floors, it must hold that a_i is at most m_i (1 ≤ a_i ≤ m_i). Also there mustn't be integers j and k such that j < i < k and a_j > a_i < a_k. Plots j and k are not required to be adjacent to i.
The company wants the total number of floors in the built skyscrapers to be as large as possible. Help it to choose the number of floors for each skyscraper in an optimal way, i.e. in such a way that all requirements are fulfilled, and among all such construction plans choose any plan with the maximum possible total number of floors.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of plots.
The second line contains the integers m_1, m_2, …, m_n (1 ≤ m_i ≤ 10^9) — the limit on the number of floors for every possible number of floors for a skyscraper on each plot.
Output
Print n integers a_i — the number of floors in the plan for each skyscraper, such that all requirements are met, and the total number of floors in all skyscrapers is the maximum possible.
If there are multiple answers possible, print any of them.
Examples
Input
5
1 2 3 2 1
Output
1 2 3 2 1
Input
3
10 6 8
Output
10 6 6
Note
In the first example, you can build all skyscrapers with the highest possible height.
In the second test example, you cannot give the maximum height to all skyscrapers as this violates the design code restriction. The answer [10, 6, 6] is optimal. Note that the answer of [6, 6, 8] also satisfies all restrictions, but is not optimal.
Submitted Solution:
```
n=int(input())
a=list(map(int,input().split()))
z=0
b=[0]*n
for i in range(n):
if a[i]>a[z]:
z=i
i,j=z-1,z+1
c=a[z]
b[z]=a[z]
while i!=-1 or j!=n:
if j!=n and (i==-1 or a[j]>a[i]):
b[j]=min(a[j],c)
c=b[j]
j+=1
else:
b[i]=min(a[i],c)
c=b[i]
i-=1
print(*b)
``` | instruction | 0 | 28,414 | 8 | 56,828 |
No | output | 1 | 28,414 | 8 | 56,829 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an easier version of the problem. In this version n ≤ 1000
The outskirts of the capital are being actively built up in Berland. The company "Kernel Panic" manages the construction of a residential complex of skyscrapers in New Berlskva. All skyscrapers are built along the highway. It is known that the company has already bought n plots along the highway and is preparing to build n skyscrapers, one skyscraper per plot.
Architects must consider several requirements when planning a skyscraper. Firstly, since the land on each plot has different properties, each skyscraper has a limit on the largest number of floors it can have. Secondly, according to the design code of the city, it is unacceptable for a skyscraper to simultaneously have higher skyscrapers both to the left and to the right of it.
Formally, let's number the plots from 1 to n. Then if the skyscraper on the i-th plot has a_i floors, it must hold that a_i is at most m_i (1 ≤ a_i ≤ m_i). Also there mustn't be integers j and k such that j < i < k and a_j > a_i < a_k. Plots j and k are not required to be adjacent to i.
The company wants the total number of floors in the built skyscrapers to be as large as possible. Help it to choose the number of floors for each skyscraper in an optimal way, i.e. in such a way that all requirements are fulfilled, and among all such construction plans choose any plan with the maximum possible total number of floors.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of plots.
The second line contains the integers m_1, m_2, …, m_n (1 ≤ m_i ≤ 10^9) — the limit on the number of floors for every possible number of floors for a skyscraper on each plot.
Output
Print n integers a_i — the number of floors in the plan for each skyscraper, such that all requirements are met, and the total number of floors in all skyscrapers is the maximum possible.
If there are multiple answers possible, print any of them.
Examples
Input
5
1 2 3 2 1
Output
1 2 3 2 1
Input
3
10 6 8
Output
10 6 6
Note
In the first example, you can build all skyscrapers with the highest possible height.
In the second test example, you cannot give the maximum height to all skyscrapers as this violates the design code restriction. The answer [10, 6, 6] is optimal. Note that the answer of [6, 6, 8] also satisfies all restrictions, but is not optimal.
Submitted Solution:
```
n=int(input())
a=list(map(int,input().split()))
t=0
s=a[:]
for j in range(1,n):
if a[j]>=a[j-1]:
if t==0:
continue
else:
a[j]=a[j-1]
else:
t=1
t=0
for j in range(n-1,0,-1):
if s[j]<=s[j-1]:
if t==0:
continue
else:
s[j-1]=s[j]
else:
t=1
if sum(s)>=sum(a):
print(*s,sep=" ")
else:
print(*a,sep=" ")
``` | instruction | 0 | 28,415 | 8 | 56,830 |
No | output | 1 | 28,415 | 8 | 56,831 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an easier version of the problem. In this version n ≤ 1000
The outskirts of the capital are being actively built up in Berland. The company "Kernel Panic" manages the construction of a residential complex of skyscrapers in New Berlskva. All skyscrapers are built along the highway. It is known that the company has already bought n plots along the highway and is preparing to build n skyscrapers, one skyscraper per plot.
Architects must consider several requirements when planning a skyscraper. Firstly, since the land on each plot has different properties, each skyscraper has a limit on the largest number of floors it can have. Secondly, according to the design code of the city, it is unacceptable for a skyscraper to simultaneously have higher skyscrapers both to the left and to the right of it.
Formally, let's number the plots from 1 to n. Then if the skyscraper on the i-th plot has a_i floors, it must hold that a_i is at most m_i (1 ≤ a_i ≤ m_i). Also there mustn't be integers j and k such that j < i < k and a_j > a_i < a_k. Plots j and k are not required to be adjacent to i.
The company wants the total number of floors in the built skyscrapers to be as large as possible. Help it to choose the number of floors for each skyscraper in an optimal way, i.e. in such a way that all requirements are fulfilled, and among all such construction plans choose any plan with the maximum possible total number of floors.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of plots.
The second line contains the integers m_1, m_2, …, m_n (1 ≤ m_i ≤ 10^9) — the limit on the number of floors for every possible number of floors for a skyscraper on each plot.
Output
Print n integers a_i — the number of floors in the plan for each skyscraper, such that all requirements are met, and the total number of floors in all skyscrapers is the maximum possible.
If there are multiple answers possible, print any of them.
Examples
Input
5
1 2 3 2 1
Output
1 2 3 2 1
Input
3
10 6 8
Output
10 6 6
Note
In the first example, you can build all skyscrapers with the highest possible height.
In the second test example, you cannot give the maximum height to all skyscrapers as this violates the design code restriction. The answer [10, 6, 6] is optimal. Note that the answer of [6, 6, 8] also satisfies all restrictions, but is not optimal.
Submitted Solution:
```
n = int(input())
numplots = list(map(int,input().split()))
mins = []
copy = []
for i in range(n):
copy.append(numplots[i])
for i in range(n):
xindex = i
sum1 = 0
for j in range(0,xindex):
if numplots[j]>numplots[xindex]:
sum1+= numplots[j]-numplots[xindex]
sum2 = 0
for j in range(xindex+1,n):
if numplots[j]>numplots[xindex]:
sum2+= numplots[j]-numplots[xindex]
# print(sum1,sum2)
if sum1<sum2 and (sum1 != 0 or sum2 != 0):
for j in range(0,xindex):
if numplots[j]>numplots[xindex]:
numplots[j] = numplots[xindex]
if sum1>=sum2 and (sum1 != 0 or sum2 != 0):
for j in range(xindex+1,n):
if numplots[j]>numplots[xindex]:
numplots[j] = numplots[xindex]
print(*numplots)
``` | instruction | 0 | 28,416 | 8 | 56,832 |
No | output | 1 | 28,416 | 8 | 56,833 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mike is a bartender at Rico's bar. At Rico's, they put beer glasses in a special shelf. There are n kinds of beer at Rico's numbered from 1 to n. i-th kind of beer has ai milliliters of foam on it.
<image>
Maxim is Mike's boss. Today he told Mike to perform q queries. Initially the shelf is empty. In each request, Maxim gives him a number x. If beer number x is already in the shelf, then Mike should remove it from the shelf, otherwise he should put it in the shelf.
After each query, Mike should tell him the score of the shelf. Bears are geeks. So they think that the score of a shelf is the number of pairs (i, j) of glasses in the shelf such that i < j and <image> where <image> is the greatest common divisor of numbers a and b.
Mike is tired. So he asked you to help him in performing these requests.
Input
The first line of input contains numbers n and q (1 ≤ n, q ≤ 2 × 105), the number of different kinds of beer and number of queries.
The next line contains n space separated integers, a1, a2, ... , an (1 ≤ ai ≤ 5 × 105), the height of foam in top of each kind of beer.
The next q lines contain the queries. Each query consists of a single integer integer x (1 ≤ x ≤ n), the index of a beer that should be added or removed from the shelf.
Output
For each query, print the answer for that query in one line.
Examples
Input
5 6
1 2 3 4 6
1
2
3
4
5
1
Output
0
1
3
5
6
2
Submitted Solution:
```
print(2)
``` | instruction | 0 | 28,652 | 8 | 57,304 |
No | output | 1 | 28,652 | 8 | 57,305 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mike is a bartender at Rico's bar. At Rico's, they put beer glasses in a special shelf. There are n kinds of beer at Rico's numbered from 1 to n. i-th kind of beer has ai milliliters of foam on it.
<image>
Maxim is Mike's boss. Today he told Mike to perform q queries. Initially the shelf is empty. In each request, Maxim gives him a number x. If beer number x is already in the shelf, then Mike should remove it from the shelf, otherwise he should put it in the shelf.
After each query, Mike should tell him the score of the shelf. Bears are geeks. So they think that the score of a shelf is the number of pairs (i, j) of glasses in the shelf such that i < j and <image> where <image> is the greatest common divisor of numbers a and b.
Mike is tired. So he asked you to help him in performing these requests.
Input
The first line of input contains numbers n and q (1 ≤ n, q ≤ 2 × 105), the number of different kinds of beer and number of queries.
The next line contains n space separated integers, a1, a2, ... , an (1 ≤ ai ≤ 5 × 105), the height of foam in top of each kind of beer.
The next q lines contain the queries. Each query consists of a single integer integer x (1 ≤ x ≤ n), the index of a beer that should be added or removed from the shelf.
Output
For each query, print the answer for that query in one line.
Examples
Input
5 6
1 2 3 4 6
1
2
3
4
5
1
Output
0
1
3
5
6
2
Submitted Solution:
```
import sys
l1 = next(sys.stdin).rstrip().split(" ")
n = int(l1[0])
q = int(l1[1])
l2 = [int(i) for i in next(sys.stdin).rstrip().split(" ")]
from fractions import gcd
shelf = []
shelfset = set()
shelffoam = []
score = [0]
def query(qu):
qu = int(qu.rstrip()) - 1
h = l2[qu]
if qu not in shelfset:
shelfset.add(qu)
for i, a in enumerate(shelffoam):
if gcd(a,h) == 1:
score[0] += 1
shelf.append(qu)
shelffoam.append(h)
print("%d" % score[0])
else:
ix = shelf.index(qu)
for i, a in enumerate(shelf):
if i != ix and gcd(a, h) == 1:
score[0] -= 1
shelfset.remove(qu)
del shelffoam[ix]
del shelf[ix]
print("%d" % score[0])
for l in sys.stdin:
query(l)
``` | instruction | 0 | 28,653 | 8 | 57,306 |
No | output | 1 | 28,653 | 8 | 57,307 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mike is a bartender at Rico's bar. At Rico's, they put beer glasses in a special shelf. There are n kinds of beer at Rico's numbered from 1 to n. i-th kind of beer has ai milliliters of foam on it.
<image>
Maxim is Mike's boss. Today he told Mike to perform q queries. Initially the shelf is empty. In each request, Maxim gives him a number x. If beer number x is already in the shelf, then Mike should remove it from the shelf, otherwise he should put it in the shelf.
After each query, Mike should tell him the score of the shelf. Bears are geeks. So they think that the score of a shelf is the number of pairs (i, j) of glasses in the shelf such that i < j and <image> where <image> is the greatest common divisor of numbers a and b.
Mike is tired. So he asked you to help him in performing these requests.
Input
The first line of input contains numbers n and q (1 ≤ n, q ≤ 2 × 105), the number of different kinds of beer and number of queries.
The next line contains n space separated integers, a1, a2, ... , an (1 ≤ ai ≤ 5 × 105), the height of foam in top of each kind of beer.
The next q lines contain the queries. Each query consists of a single integer integer x (1 ≤ x ≤ n), the index of a beer that should be added or removed from the shelf.
Output
For each query, print the answer for that query in one line.
Examples
Input
5 6
1 2 3 4 6
1
2
3
4
5
1
Output
0
1
3
5
6
2
Submitted Solution:
```
from collections import defaultdict
from operator import mul
from functools import reduce
from itertools import combinations
import sys
input = sys.stdin.readline
n, q = map(int, input().split())
divs = [set() for _ in range(n)]
facts = [set() for _ in range(n)]
for i, a in enumerate(map(int, input().split())):
for div in range(1, int(a**.5)+1):
if a % div == 0:
divs[i] |= {div, a//div}
for p in range(2, int(-(-a**.5//1))+1):
if a % p == 0:
facts[i].add(p)
while a % p == 0:
a //= p
if a != 1:
facts[i].add(a)
score = 0
divcnt = defaultdict(int)
shelf = [0]*n
shelf_len = 0
for _ in range(q):
x = int(input())-1
div = divs[x]
fact = facts[x]
if not shelf[x]:
score_add = shelf_len
shelf_len += 1
for k in range(1, len(fact)+1):
for subset in combinations(fact, k):
z = reduce(mul, subset)
if k % 2:
score_add -= divcnt[z]
else:
score_add += divcnt[z]
score += score_add
print(score)
shelf[x] = 1
for d in div:
divcnt[d] += 1
else:
shelf_len -= 1
score_sub = shelf_len
for k in range(1, len(fact)+1):
for subset in combinations(fact, k):
z = reduce(mul, subset)
if k % 2:
score_sub -= divcnt[z]
else:
score_sub += divcnt[z]
score -= score_sub
print(score)
shelf[x] = 0
for d in div:
divcnt[d] -= 1
``` | instruction | 0 | 28,654 | 8 | 57,308 |
No | output | 1 | 28,654 | 8 | 57,309 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nikita has a stack. A stack in this problem is a data structure that supports two operations. Operation push(x) puts an integer x on the top of the stack, and operation pop() deletes the top integer from the stack, i. e. the last added. If the stack is empty, then the operation pop() does nothing.
Nikita made m operations with the stack but forgot them. Now Nikita wants to remember them. He remembers them one by one, on the i-th step he remembers an operation he made pi-th. In other words, he remembers the operations in order of some permutation p1, p2, ..., pm. After each step Nikita wants to know what is the integer on the top of the stack after performing the operations he have already remembered, in the corresponding order. Help him!
Input
The first line contains the integer m (1 ≤ m ≤ 105) — the number of operations Nikita made.
The next m lines contain the operations Nikita remembers. The i-th line starts with two integers pi and ti (1 ≤ pi ≤ m, ti = 0 or ti = 1) — the index of operation he remembers on the step i, and the type of the operation. ti equals 0, if the operation is pop(), and 1, is the operation is push(x). If the operation is push(x), the line also contains the integer xi (1 ≤ xi ≤ 106) — the integer added to the stack.
It is guaranteed that each integer from 1 to m is present exactly once among integers pi.
Output
Print m integers. The integer i should equal the number on the top of the stack after performing all the operations Nikita remembered on the steps from 1 to i. If the stack is empty after performing all these operations, print -1.
Examples
Input
2
2 1 2
1 0
Output
2
2
Input
3
1 1 2
2 1 3
3 0
Output
2
3
2
Input
5
5 0
4 0
3 1 1
2 1 1
1 1 2
Output
-1
-1
-1
-1
2
Note
In the first example, after Nikita remembers the operation on the first step, the operation push(2) is the only operation, so the answer is 2. After he remembers the operation pop() which was done before push(2), answer stays the same.
In the second example, the operations are push(2), push(3) and pop(). Nikita remembers them in the order they were performed.
In the third example Nikita remembers the operations in the reversed order.
Submitted Solution:
```
import sys
def cur_top(a):
a.sort()
print(a)
stack = [-1]
for com in a:
if com[1] == 1:
stack.append(com[2])
else:
top = stack.pop()
if top == -1:
stack.append(-1)
return stack.pop()
def main():
n = int(sys.stdin.readline())
reader = (list(map(int, line.split())) for line in sys.stdin)
oppers = list(reader)
answer = []
for i in range(n):
current = cur_top(oppers[:i + 1])
answer.append(current)
for top in answer:
print(top)
if __name__ == "__main__":
main()
``` | instruction | 0 | 28,745 | 8 | 57,490 |
No | output | 1 | 28,745 | 8 | 57,491 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nikita has a stack. A stack in this problem is a data structure that supports two operations. Operation push(x) puts an integer x on the top of the stack, and operation pop() deletes the top integer from the stack, i. e. the last added. If the stack is empty, then the operation pop() does nothing.
Nikita made m operations with the stack but forgot them. Now Nikita wants to remember them. He remembers them one by one, on the i-th step he remembers an operation he made pi-th. In other words, he remembers the operations in order of some permutation p1, p2, ..., pm. After each step Nikita wants to know what is the integer on the top of the stack after performing the operations he have already remembered, in the corresponding order. Help him!
Input
The first line contains the integer m (1 ≤ m ≤ 105) — the number of operations Nikita made.
The next m lines contain the operations Nikita remembers. The i-th line starts with two integers pi and ti (1 ≤ pi ≤ m, ti = 0 or ti = 1) — the index of operation he remembers on the step i, and the type of the operation. ti equals 0, if the operation is pop(), and 1, is the operation is push(x). If the operation is push(x), the line also contains the integer xi (1 ≤ xi ≤ 106) — the integer added to the stack.
It is guaranteed that each integer from 1 to m is present exactly once among integers pi.
Output
Print m integers. The integer i should equal the number on the top of the stack after performing all the operations Nikita remembered on the steps from 1 to i. If the stack is empty after performing all these operations, print -1.
Examples
Input
2
2 1 2
1 0
Output
2
2
Input
3
1 1 2
2 1 3
3 0
Output
2
3
2
Input
5
5 0
4 0
3 1 1
2 1 1
1 1 2
Output
-1
-1
-1
-1
2
Note
In the first example, after Nikita remembers the operation on the first step, the operation push(2) is the only operation, so the answer is 2. After he remembers the operation pop() which was done before push(2), answer stays the same.
In the second example, the operations are push(2), push(3) and pop(). Nikita remembers them in the order they were performed.
In the third example Nikita remembers the operations in the reversed order.
Submitted Solution:
```
from collections import deque
from bisect import bisect_left
m = int(input())
ops = []
stops = []
pops = 0
pushs = 0
for i in range(m):
st = input()
k = bisect_left(stops, st)
stops.insert(k, st)
s = tuple(map(int, st.split()))
ops.insert(k, s[1:])
stack = deque()
for op in ops:
if op[0] == 0:
try:
stack.pop()
except:
pass
elif op[0] == 1:
stack.append(op[1])
try:
print(stack.pop())
except:
print(-1)
``` | instruction | 0 | 28,746 | 8 | 57,492 |
No | output | 1 | 28,746 | 8 | 57,493 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nikita has a stack. A stack in this problem is a data structure that supports two operations. Operation push(x) puts an integer x on the top of the stack, and operation pop() deletes the top integer from the stack, i. e. the last added. If the stack is empty, then the operation pop() does nothing.
Nikita made m operations with the stack but forgot them. Now Nikita wants to remember them. He remembers them one by one, on the i-th step he remembers an operation he made pi-th. In other words, he remembers the operations in order of some permutation p1, p2, ..., pm. After each step Nikita wants to know what is the integer on the top of the stack after performing the operations he have already remembered, in the corresponding order. Help him!
Input
The first line contains the integer m (1 ≤ m ≤ 105) — the number of operations Nikita made.
The next m lines contain the operations Nikita remembers. The i-th line starts with two integers pi and ti (1 ≤ pi ≤ m, ti = 0 or ti = 1) — the index of operation he remembers on the step i, and the type of the operation. ti equals 0, if the operation is pop(), and 1, is the operation is push(x). If the operation is push(x), the line also contains the integer xi (1 ≤ xi ≤ 106) — the integer added to the stack.
It is guaranteed that each integer from 1 to m is present exactly once among integers pi.
Output
Print m integers. The integer i should equal the number on the top of the stack after performing all the operations Nikita remembered on the steps from 1 to i. If the stack is empty after performing all these operations, print -1.
Examples
Input
2
2 1 2
1 0
Output
2
2
Input
3
1 1 2
2 1 3
3 0
Output
2
3
2
Input
5
5 0
4 0
3 1 1
2 1 1
1 1 2
Output
-1
-1
-1
-1
2
Note
In the first example, after Nikita remembers the operation on the first step, the operation push(2) is the only operation, so the answer is 2. After he remembers the operation pop() which was done before push(2), answer stays the same.
In the second example, the operations are push(2), push(3) and pop(). Nikita remembers them in the order they were performed.
In the third example Nikita remembers the operations in the reversed order.
Submitted Solution:
```
from bisect import bisect
n = int(input())
push_i = []
push_v = []
pop_i = set()
for t in range(n):
r = list(map(int, input().split()))
i = r[0]
if r[1]:
ii = bisect(push_i, i)
push_i.insert(ii, i)
push_v.insert(ii, r[2])
elif not len(push_i) or i > push_i[-1]:
pop_i.add(i)
for z,(i,v) in enumerate(zip(reversed(push_i), reversed(push_v))):
if len(pop_i.intersection(range(i,n+1))) <= z:
print(v)
break
else:
print(-1)
``` | instruction | 0 | 28,747 | 8 | 57,494 |
No | output | 1 | 28,747 | 8 | 57,495 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nikita has a stack. A stack in this problem is a data structure that supports two operations. Operation push(x) puts an integer x on the top of the stack, and operation pop() deletes the top integer from the stack, i. e. the last added. If the stack is empty, then the operation pop() does nothing.
Nikita made m operations with the stack but forgot them. Now Nikita wants to remember them. He remembers them one by one, on the i-th step he remembers an operation he made pi-th. In other words, he remembers the operations in order of some permutation p1, p2, ..., pm. After each step Nikita wants to know what is the integer on the top of the stack after performing the operations he have already remembered, in the corresponding order. Help him!
Input
The first line contains the integer m (1 ≤ m ≤ 105) — the number of operations Nikita made.
The next m lines contain the operations Nikita remembers. The i-th line starts with two integers pi and ti (1 ≤ pi ≤ m, ti = 0 or ti = 1) — the index of operation he remembers on the step i, and the type of the operation. ti equals 0, if the operation is pop(), and 1, is the operation is push(x). If the operation is push(x), the line also contains the integer xi (1 ≤ xi ≤ 106) — the integer added to the stack.
It is guaranteed that each integer from 1 to m is present exactly once among integers pi.
Output
Print m integers. The integer i should equal the number on the top of the stack after performing all the operations Nikita remembered on the steps from 1 to i. If the stack is empty after performing all these operations, print -1.
Examples
Input
2
2 1 2
1 0
Output
2
2
Input
3
1 1 2
2 1 3
3 0
Output
2
3
2
Input
5
5 0
4 0
3 1 1
2 1 1
1 1 2
Output
-1
-1
-1
-1
2
Note
In the first example, after Nikita remembers the operation on the first step, the operation push(2) is the only operation, so the answer is 2. After he remembers the operation pop() which was done before push(2), answer stays the same.
In the second example, the operations are push(2), push(3) and pop(). Nikita remembers them in the order they were performed.
In the third example Nikita remembers the operations in the reversed order.
Submitted Solution:
```
m = int(input())
ops = [0] * m
pops = 0
pushs = 0
for i in range(m):
s = tuple(map(int, input().split()))
ops[s[0]-1] = s[1:]
stack = []
for op in ops:
if op[0] == 0:
try:
stack.pop()
except:
pass
try:
print(stack[-1])
except:
print(-1)
else:
stack.append(op[1])
print(op[1])
``` | instruction | 0 | 28,748 | 8 | 57,496 |
No | output | 1 | 28,748 | 8 | 57,497 |
Provide a correct Python 3 solution for this coding contest problem.
We have two desks: A and B. Desk A has a vertical stack of N books on it, and Desk B similarly has M books on it.
It takes us A_i minutes to read the i-th book from the top on Desk A (1 \leq i \leq N), and B_i minutes to read the i-th book from the top on Desk B (1 \leq i \leq M).
Consider the following action:
* Choose a desk with a book remaining, read the topmost book on that desk, and remove it from the desk.
How many books can we read at most by repeating this action so that it takes us at most K minutes in total? We ignore the time it takes to do anything other than reading.
Constraints
* 1 \leq N, M \leq 200000
* 1 \leq K \leq 10^9
* 1 \leq A_i, B_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N M K
A_1 A_2 \ldots A_N
B_1 B_2 \ldots B_M
Output
Print an integer representing the maximum number of books that can be read.
Examples
Input
3 4 240
60 90 120
80 150 80 150
Output
3
Input
3 4 730
60 90 120
80 150 80 150
Output
7
Input
5 4 1
1000000000 1000000000 1000000000 1000000000 1000000000
1000000000 1000000000 1000000000 1000000000
Output
0 | instruction | 0 | 28,844 | 8 | 57,688 |
"Correct Solution:
```
n,m,k=map(int,input().split())
A=list(map(int,input().split()))
B=list(map(int,input().split()))
a=[0];b=[0];ans=0;j=m
for i in range(n):
a.append(a[i]+A[i])
for i in range(m):
b.append(b[i]+B[i])
for i in range(n+1):
if a[i]>k:
break
while b[j]>k-a[i]:
j-=1
ans=max(ans,i+j)
print(ans)
``` | output | 1 | 28,844 | 8 | 57,689 |
Provide a correct Python 3 solution for this coding contest problem.
We have two desks: A and B. Desk A has a vertical stack of N books on it, and Desk B similarly has M books on it.
It takes us A_i minutes to read the i-th book from the top on Desk A (1 \leq i \leq N), and B_i minutes to read the i-th book from the top on Desk B (1 \leq i \leq M).
Consider the following action:
* Choose a desk with a book remaining, read the topmost book on that desk, and remove it from the desk.
How many books can we read at most by repeating this action so that it takes us at most K minutes in total? We ignore the time it takes to do anything other than reading.
Constraints
* 1 \leq N, M \leq 200000
* 1 \leq K \leq 10^9
* 1 \leq A_i, B_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N M K
A_1 A_2 \ldots A_N
B_1 B_2 \ldots B_M
Output
Print an integer representing the maximum number of books that can be read.
Examples
Input
3 4 240
60 90 120
80 150 80 150
Output
3
Input
3 4 730
60 90 120
80 150 80 150
Output
7
Input
5 4 1
1000000000 1000000000 1000000000 1000000000 1000000000
1000000000 1000000000 1000000000 1000000000
Output
0 | instruction | 0 | 28,845 | 8 | 57,690 |
"Correct Solution:
```
from bisect import*
from itertools import*
n,_,k,*x=map(int,open(0).read().split());c=accumulate;*b,=c(x[n:]);print(max(i+bisect(b,k-v)for i,v in enumerate(c([0]+x[:n]))if v<=k))
``` | output | 1 | 28,845 | 8 | 57,691 |
Provide a correct Python 3 solution for this coding contest problem.
We have two desks: A and B. Desk A has a vertical stack of N books on it, and Desk B similarly has M books on it.
It takes us A_i minutes to read the i-th book from the top on Desk A (1 \leq i \leq N), and B_i minutes to read the i-th book from the top on Desk B (1 \leq i \leq M).
Consider the following action:
* Choose a desk with a book remaining, read the topmost book on that desk, and remove it from the desk.
How many books can we read at most by repeating this action so that it takes us at most K minutes in total? We ignore the time it takes to do anything other than reading.
Constraints
* 1 \leq N, M \leq 200000
* 1 \leq K \leq 10^9
* 1 \leq A_i, B_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N M K
A_1 A_2 \ldots A_N
B_1 B_2 \ldots B_M
Output
Print an integer representing the maximum number of books that can be read.
Examples
Input
3 4 240
60 90 120
80 150 80 150
Output
3
Input
3 4 730
60 90 120
80 150 80 150
Output
7
Input
5 4 1
1000000000 1000000000 1000000000 1000000000 1000000000
1000000000 1000000000 1000000000 1000000000
Output
0 | instruction | 0 | 28,846 | 8 | 57,692 |
"Correct Solution:
```
N,M,K=map(int,input().split())
A=list(map(int,input().split()))
B=list(map(int,input().split()))
a,b = [0],[0]
for i in range(N):
a.append(a[i]+A[i])
for j in range(M):
b.append(b[j]+B[j])
ans = 0
j = M
for i in range(N+1):
if a[i] > K:
break
while b[j] > K - a[i]:
j -= 1
ans = max(ans,i+j)
print(ans)
``` | output | 1 | 28,846 | 8 | 57,693 |
Provide a correct Python 3 solution for this coding contest problem.
We have two desks: A and B. Desk A has a vertical stack of N books on it, and Desk B similarly has M books on it.
It takes us A_i minutes to read the i-th book from the top on Desk A (1 \leq i \leq N), and B_i minutes to read the i-th book from the top on Desk B (1 \leq i \leq M).
Consider the following action:
* Choose a desk with a book remaining, read the topmost book on that desk, and remove it from the desk.
How many books can we read at most by repeating this action so that it takes us at most K minutes in total? We ignore the time it takes to do anything other than reading.
Constraints
* 1 \leq N, M \leq 200000
* 1 \leq K \leq 10^9
* 1 \leq A_i, B_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N M K
A_1 A_2 \ldots A_N
B_1 B_2 \ldots B_M
Output
Print an integer representing the maximum number of books that can be read.
Examples
Input
3 4 240
60 90 120
80 150 80 150
Output
3
Input
3 4 730
60 90 120
80 150 80 150
Output
7
Input
5 4 1
1000000000 1000000000 1000000000 1000000000 1000000000
1000000000 1000000000 1000000000 1000000000
Output
0 | instruction | 0 | 28,847 | 8 | 57,694 |
"Correct Solution:
```
from bisect import bisect
n, m, k = map(int, input().split())
A = list(map(int, input().split()))
B = list(map(int, input().split()))
a = [0]
for i in range(n):
a.append(a[-1] + A[i])
b = [0]
for i in range(m):
b.append(b[-1] + B[i])
ans = 0
for i in range(n+1):
if a[i] > k:
break
ans = max(ans, i + bisect(b, k-a[i]) - 1)
print(ans)
``` | output | 1 | 28,847 | 8 | 57,695 |
Provide a correct Python 3 solution for this coding contest problem.
We have two desks: A and B. Desk A has a vertical stack of N books on it, and Desk B similarly has M books on it.
It takes us A_i minutes to read the i-th book from the top on Desk A (1 \leq i \leq N), and B_i minutes to read the i-th book from the top on Desk B (1 \leq i \leq M).
Consider the following action:
* Choose a desk with a book remaining, read the topmost book on that desk, and remove it from the desk.
How many books can we read at most by repeating this action so that it takes us at most K minutes in total? We ignore the time it takes to do anything other than reading.
Constraints
* 1 \leq N, M \leq 200000
* 1 \leq K \leq 10^9
* 1 \leq A_i, B_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N M K
A_1 A_2 \ldots A_N
B_1 B_2 \ldots B_M
Output
Print an integer representing the maximum number of books that can be read.
Examples
Input
3 4 240
60 90 120
80 150 80 150
Output
3
Input
3 4 730
60 90 120
80 150 80 150
Output
7
Input
5 4 1
1000000000 1000000000 1000000000 1000000000 1000000000
1000000000 1000000000 1000000000 1000000000
Output
0 | instruction | 0 | 28,848 | 8 | 57,696 |
"Correct Solution:
```
from bisect import*
from itertools import*
n,m,k,*x=map(int,open(0).read().split());c=accumulate;b=[*c(x[n:])];print(max(i+bisect(b,k-v)for i,v in enumerate(c([0]+x[:n]))if v<=k))
``` | output | 1 | 28,848 | 8 | 57,697 |
Provide a correct Python 3 solution for this coding contest problem.
We have two desks: A and B. Desk A has a vertical stack of N books on it, and Desk B similarly has M books on it.
It takes us A_i minutes to read the i-th book from the top on Desk A (1 \leq i \leq N), and B_i minutes to read the i-th book from the top on Desk B (1 \leq i \leq M).
Consider the following action:
* Choose a desk with a book remaining, read the topmost book on that desk, and remove it from the desk.
How many books can we read at most by repeating this action so that it takes us at most K minutes in total? We ignore the time it takes to do anything other than reading.
Constraints
* 1 \leq N, M \leq 200000
* 1 \leq K \leq 10^9
* 1 \leq A_i, B_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N M K
A_1 A_2 \ldots A_N
B_1 B_2 \ldots B_M
Output
Print an integer representing the maximum number of books that can be read.
Examples
Input
3 4 240
60 90 120
80 150 80 150
Output
3
Input
3 4 730
60 90 120
80 150 80 150
Output
7
Input
5 4 1
1000000000 1000000000 1000000000 1000000000 1000000000
1000000000 1000000000 1000000000 1000000000
Output
0 | instruction | 0 | 28,849 | 8 | 57,698 |
"Correct Solution:
```
from itertools import *
f=lambda:map(int,input().split())
g=lambda:[0]+[*accumulate(f())]
n,m,k=f()
A,B=g(),g()
a,j=0,m
for i in range(n+1):
while j and B[j]>k-A[i]: j-=1
if A[i]+B[j]<=k: a=max(a,i+j)
print(a)
``` | output | 1 | 28,849 | 8 | 57,699 |
Provide a correct Python 3 solution for this coding contest problem.
We have two desks: A and B. Desk A has a vertical stack of N books on it, and Desk B similarly has M books on it.
It takes us A_i minutes to read the i-th book from the top on Desk A (1 \leq i \leq N), and B_i minutes to read the i-th book from the top on Desk B (1 \leq i \leq M).
Consider the following action:
* Choose a desk with a book remaining, read the topmost book on that desk, and remove it from the desk.
How many books can we read at most by repeating this action so that it takes us at most K minutes in total? We ignore the time it takes to do anything other than reading.
Constraints
* 1 \leq N, M \leq 200000
* 1 \leq K \leq 10^9
* 1 \leq A_i, B_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N M K
A_1 A_2 \ldots A_N
B_1 B_2 \ldots B_M
Output
Print an integer representing the maximum number of books that can be read.
Examples
Input
3 4 240
60 90 120
80 150 80 150
Output
3
Input
3 4 730
60 90 120
80 150 80 150
Output
7
Input
5 4 1
1000000000 1000000000 1000000000 1000000000 1000000000
1000000000 1000000000 1000000000 1000000000
Output
0 | instruction | 0 | 28,850 | 8 | 57,700 |
"Correct Solution:
```
n,m,k=map(int, input().split())
A=list(map(int,input().split()))
B=list(map(int,input().split()))
import bisect
AR=[0]
BR=[0]
for i in range(n):
AR.append(A[i]+AR[i])
for i in range(m):
BR.append(B[i]+BR[i])
ans=0
for i in range(n+1):
if AR[i]>k:
break
s=k-AR[i]
t=bisect.bisect(BR,s)-1
ans=max(ans,i+t)
print(ans)
``` | output | 1 | 28,850 | 8 | 57,701 |
Provide a correct Python 3 solution for this coding contest problem.
We have two desks: A and B. Desk A has a vertical stack of N books on it, and Desk B similarly has M books on it.
It takes us A_i minutes to read the i-th book from the top on Desk A (1 \leq i \leq N), and B_i minutes to read the i-th book from the top on Desk B (1 \leq i \leq M).
Consider the following action:
* Choose a desk with a book remaining, read the topmost book on that desk, and remove it from the desk.
How many books can we read at most by repeating this action so that it takes us at most K minutes in total? We ignore the time it takes to do anything other than reading.
Constraints
* 1 \leq N, M \leq 200000
* 1 \leq K \leq 10^9
* 1 \leq A_i, B_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N M K
A_1 A_2 \ldots A_N
B_1 B_2 \ldots B_M
Output
Print an integer representing the maximum number of books that can be read.
Examples
Input
3 4 240
60 90 120
80 150 80 150
Output
3
Input
3 4 730
60 90 120
80 150 80 150
Output
7
Input
5 4 1
1000000000 1000000000 1000000000 1000000000 1000000000
1000000000 1000000000 1000000000 1000000000
Output
0 | instruction | 0 | 28,851 | 8 | 57,702 |
"Correct Solution:
```
N,M,K=map(int,input().split())
A=list(map(int,input().split()))
B=list(map(int,input().split()))
C=[0]
for x in range(N):
C.append(C[-1]+A[x])
D=[0]
for x in range(M):
D.append(D[-1]+B[x])
count=0
y=M
for x in range(N+1):
if C[x]>K:
break
while D[y]>K-C[x] and y>0:
y-=1
count=max(count,x+y)
print(count)
``` | output | 1 | 28,851 | 8 | 57,703 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have two desks: A and B. Desk A has a vertical stack of N books on it, and Desk B similarly has M books on it.
It takes us A_i minutes to read the i-th book from the top on Desk A (1 \leq i \leq N), and B_i minutes to read the i-th book from the top on Desk B (1 \leq i \leq M).
Consider the following action:
* Choose a desk with a book remaining, read the topmost book on that desk, and remove it from the desk.
How many books can we read at most by repeating this action so that it takes us at most K minutes in total? We ignore the time it takes to do anything other than reading.
Constraints
* 1 \leq N, M \leq 200000
* 1 \leq K \leq 10^9
* 1 \leq A_i, B_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N M K
A_1 A_2 \ldots A_N
B_1 B_2 \ldots B_M
Output
Print an integer representing the maximum number of books that can be read.
Examples
Input
3 4 240
60 90 120
80 150 80 150
Output
3
Input
3 4 730
60 90 120
80 150 80 150
Output
7
Input
5 4 1
1000000000 1000000000 1000000000 1000000000 1000000000
1000000000 1000000000 1000000000 1000000000
Output
0
Submitted Solution:
```
n,m,k=map(int,input().split())
A=list(map(int,input().split()))
B=list(map(int,input().split()))
a=[0]
b=[0]
for i in range(n):
a.append(a[i]+A[i])
for i in range(m):
b.append(b[i]+B[i])
ans=0
j=m
for i in range(n+1):
if a[i]>k:
break
while a[i]+b[j]>k:
j-=1
ans=max(ans,i+j)
print(ans)
``` | instruction | 0 | 28,852 | 8 | 57,704 |
Yes | output | 1 | 28,852 | 8 | 57,705 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have two desks: A and B. Desk A has a vertical stack of N books on it, and Desk B similarly has M books on it.
It takes us A_i minutes to read the i-th book from the top on Desk A (1 \leq i \leq N), and B_i minutes to read the i-th book from the top on Desk B (1 \leq i \leq M).
Consider the following action:
* Choose a desk with a book remaining, read the topmost book on that desk, and remove it from the desk.
How many books can we read at most by repeating this action so that it takes us at most K minutes in total? We ignore the time it takes to do anything other than reading.
Constraints
* 1 \leq N, M \leq 200000
* 1 \leq K \leq 10^9
* 1 \leq A_i, B_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N M K
A_1 A_2 \ldots A_N
B_1 B_2 \ldots B_M
Output
Print an integer representing the maximum number of books that can be read.
Examples
Input
3 4 240
60 90 120
80 150 80 150
Output
3
Input
3 4 730
60 90 120
80 150 80 150
Output
7
Input
5 4 1
1000000000 1000000000 1000000000 1000000000 1000000000
1000000000 1000000000 1000000000 1000000000
Output
0
Submitted Solution:
```
from itertools import accumulate
import bisect
n,m,k=map(int,input().split())
a=list(map(int,input().split()))
aa=[0]+list(accumulate(a))
b=[0]+list(map(int,input().split()))
bb=list(accumulate(b))
ans=0
for i in range(n+1):
if aa[i]>k:
break
tmp=k-aa[i]
t=bisect.bisect(bb,tmp)
if i-1+t>ans:
ans=i+t-1
print(ans)
``` | instruction | 0 | 28,853 | 8 | 57,706 |
Yes | output | 1 | 28,853 | 8 | 57,707 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have two desks: A and B. Desk A has a vertical stack of N books on it, and Desk B similarly has M books on it.
It takes us A_i minutes to read the i-th book from the top on Desk A (1 \leq i \leq N), and B_i minutes to read the i-th book from the top on Desk B (1 \leq i \leq M).
Consider the following action:
* Choose a desk with a book remaining, read the topmost book on that desk, and remove it from the desk.
How many books can we read at most by repeating this action so that it takes us at most K minutes in total? We ignore the time it takes to do anything other than reading.
Constraints
* 1 \leq N, M \leq 200000
* 1 \leq K \leq 10^9
* 1 \leq A_i, B_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N M K
A_1 A_2 \ldots A_N
B_1 B_2 \ldots B_M
Output
Print an integer representing the maximum number of books that can be read.
Examples
Input
3 4 240
60 90 120
80 150 80 150
Output
3
Input
3 4 730
60 90 120
80 150 80 150
Output
7
Input
5 4 1
1000000000 1000000000 1000000000 1000000000 1000000000
1000000000 1000000000 1000000000 1000000000
Output
0
Submitted Solution:
```
n,m,p=map(int,input().split())
A=list(map(int,input().split()))
B=list(map(int,input().split()))
a=[0]*(n+1) ; b=[0]*(m+1)
for i in range(n):
a[i+1]+=a[i]+A[i]
for j in range(m):
b[j+1]=b[j]+B[j]
now=-1
import bisect as bi
for i in range(n+1):
if a[i]>p : break
G=p-a[i]
now=max(bi.bisect(b, G)+i-1, now)
print(now)
``` | instruction | 0 | 28,854 | 8 | 57,708 |
Yes | output | 1 | 28,854 | 8 | 57,709 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have two desks: A and B. Desk A has a vertical stack of N books on it, and Desk B similarly has M books on it.
It takes us A_i minutes to read the i-th book from the top on Desk A (1 \leq i \leq N), and B_i minutes to read the i-th book from the top on Desk B (1 \leq i \leq M).
Consider the following action:
* Choose a desk with a book remaining, read the topmost book on that desk, and remove it from the desk.
How many books can we read at most by repeating this action so that it takes us at most K minutes in total? We ignore the time it takes to do anything other than reading.
Constraints
* 1 \leq N, M \leq 200000
* 1 \leq K \leq 10^9
* 1 \leq A_i, B_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N M K
A_1 A_2 \ldots A_N
B_1 B_2 \ldots B_M
Output
Print an integer representing the maximum number of books that can be read.
Examples
Input
3 4 240
60 90 120
80 150 80 150
Output
3
Input
3 4 730
60 90 120
80 150 80 150
Output
7
Input
5 4 1
1000000000 1000000000 1000000000 1000000000 1000000000
1000000000 1000000000 1000000000 1000000000
Output
0
Submitted Solution:
```
n, m, k = map(int,input().split(' '))
a = [0] + list(map(int, input().split(' ')))
b = [0] + list(map(int, input().split(' ')))
j = m
ta, tb =0, sum(b)
r = 0
for i in range(n + 1):
ta += a[i]
if ta > k:
break
while tb > k - ta:
tb -= b[j]
j -= 1
r = max(r, i + j)
print(r)
``` | instruction | 0 | 28,855 | 8 | 57,710 |
Yes | output | 1 | 28,855 | 8 | 57,711 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have two desks: A and B. Desk A has a vertical stack of N books on it, and Desk B similarly has M books on it.
It takes us A_i minutes to read the i-th book from the top on Desk A (1 \leq i \leq N), and B_i minutes to read the i-th book from the top on Desk B (1 \leq i \leq M).
Consider the following action:
* Choose a desk with a book remaining, read the topmost book on that desk, and remove it from the desk.
How many books can we read at most by repeating this action so that it takes us at most K minutes in total? We ignore the time it takes to do anything other than reading.
Constraints
* 1 \leq N, M \leq 200000
* 1 \leq K \leq 10^9
* 1 \leq A_i, B_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N M K
A_1 A_2 \ldots A_N
B_1 B_2 \ldots B_M
Output
Print an integer representing the maximum number of books that can be read.
Examples
Input
3 4 240
60 90 120
80 150 80 150
Output
3
Input
3 4 730
60 90 120
80 150 80 150
Output
7
Input
5 4 1
1000000000 1000000000 1000000000 1000000000 1000000000
1000000000 1000000000 1000000000 1000000000
Output
0
Submitted Solution:
```
n,m,k = map(int,input().split())
a = tuple(map(int,input().split()))
b = tuple(map(int,input().split()))
t = 0
i = 0
j = 0
while (t <= k):
#print(i,j,t)
if i < n:
ai = a[i]
else:
ai = 10**10
if j < m:
bi = b[j]
else:
bi = 10**10
if ai < bi:
i += 1
t += ai
else:
j += 1
t += bi
if t <= k:
print(n+m)
else:
print(i+j-1)
#print(t,i,j)
``` | instruction | 0 | 28,856 | 8 | 57,712 |
No | output | 1 | 28,856 | 8 | 57,713 |
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