message stringlengths 2 22.7k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 145 109k | cluster float64 9 9 | __index_level_0__ int64 290 217k |
|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
You are going to eat X red apples and Y green apples.
You have A red apples of deliciousness p_1,p_2, \dots, p_A, B green apples of deliciousness q_1,q_2, \dots, q_B, and C colorless apples of deliciousness r_1,r_2, \dots, r_C.
Before eating a colorless apple, you can paint it red or green, and it will count as a red or green apple, respectively.
From the apples above, you will choose the apples to eat while making the sum of the deliciousness of the eaten apples as large as possible.
Find the maximum possible sum of the deliciousness of the eaten apples that can be achieved when optimally coloring zero or more colorless apples.
Constraints
* 1 \leq X \leq A \leq 10^5
* 1 \leq Y \leq B \leq 10^5
* 1 \leq C \leq 10^5
* 1 \leq p_i \leq 10^9
* 1 \leq q_i \leq 10^9
* 1 \leq r_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y A B C
p_1 p_2 ... p_A
q_1 q_2 ... q_B
r_1 r_2 ... r_C
Output
Print the maximum possible sum of the deliciousness of the eaten apples.
Examples
Input
1 2 2 2 1
2 4
5 1
3
Output
12
Input
2 2 2 2 2
8 6
9 1
2 1
Output
25
Input
2 2 4 4 4
11 12 13 14
21 22 23 24
1 2 3 4
Output
74 | instruction | 0 | 32,259 | 9 | 64,518 |
"Correct Solution:
```
X,Y,A,B,C=map(int,input().split())
p=list(map(int,input().split()))
q=list(map(int,input().split()))
r=list(map(int,input().split()))
p.sort(reverse=True)
q.sort(reverse=True)
r.sort(reverse=True)
eat=p[:X]+q[:Y]+r
eat.sort(reverse=True)
eat=eat[:(X+Y)]
print(sum(eat))
``` | output | 1 | 32,259 | 9 | 64,519 |
Provide a correct Python 3 solution for this coding contest problem.
You are going to eat X red apples and Y green apples.
You have A red apples of deliciousness p_1,p_2, \dots, p_A, B green apples of deliciousness q_1,q_2, \dots, q_B, and C colorless apples of deliciousness r_1,r_2, \dots, r_C.
Before eating a colorless apple, you can paint it red or green, and it will count as a red or green apple, respectively.
From the apples above, you will choose the apples to eat while making the sum of the deliciousness of the eaten apples as large as possible.
Find the maximum possible sum of the deliciousness of the eaten apples that can be achieved when optimally coloring zero or more colorless apples.
Constraints
* 1 \leq X \leq A \leq 10^5
* 1 \leq Y \leq B \leq 10^5
* 1 \leq C \leq 10^5
* 1 \leq p_i \leq 10^9
* 1 \leq q_i \leq 10^9
* 1 \leq r_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y A B C
p_1 p_2 ... p_A
q_1 q_2 ... q_B
r_1 r_2 ... r_C
Output
Print the maximum possible sum of the deliciousness of the eaten apples.
Examples
Input
1 2 2 2 1
2 4
5 1
3
Output
12
Input
2 2 2 2 2
8 6
9 1
2 1
Output
25
Input
2 2 4 4 4
11 12 13 14
21 22 23 24
1 2 3 4
Output
74 | instruction | 0 | 32,260 | 9 | 64,520 |
"Correct Solution:
```
x,y,a,b,c=map(int,input().split())
*p,=sorted(map(int, input().split()))
*q,=sorted(map(int, input().split()))
*r,=map(int, input().split())
p=p[-x:]
q=q[-y:]
r=sorted(p+q+r)
print(sum(r[-x-y:]))
``` | output | 1 | 32,260 | 9 | 64,521 |
Provide a correct Python 3 solution for this coding contest problem.
You are going to eat X red apples and Y green apples.
You have A red apples of deliciousness p_1,p_2, \dots, p_A, B green apples of deliciousness q_1,q_2, \dots, q_B, and C colorless apples of deliciousness r_1,r_2, \dots, r_C.
Before eating a colorless apple, you can paint it red or green, and it will count as a red or green apple, respectively.
From the apples above, you will choose the apples to eat while making the sum of the deliciousness of the eaten apples as large as possible.
Find the maximum possible sum of the deliciousness of the eaten apples that can be achieved when optimally coloring zero or more colorless apples.
Constraints
* 1 \leq X \leq A \leq 10^5
* 1 \leq Y \leq B \leq 10^5
* 1 \leq C \leq 10^5
* 1 \leq p_i \leq 10^9
* 1 \leq q_i \leq 10^9
* 1 \leq r_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y A B C
p_1 p_2 ... p_A
q_1 q_2 ... q_B
r_1 r_2 ... r_C
Output
Print the maximum possible sum of the deliciousness of the eaten apples.
Examples
Input
1 2 2 2 1
2 4
5 1
3
Output
12
Input
2 2 2 2 2
8 6
9 1
2 1
Output
25
Input
2 2 4 4 4
11 12 13 14
21 22 23 24
1 2 3 4
Output
74 | instruction | 0 | 32,261 | 9 | 64,522 |
"Correct Solution:
```
x, y, a, b, c = map(int, input().split())
p = list(map(int, input().split()))
q = list(map(int, input().split()))
r = list(map(int, input().split()))
p.sort(reverse=True)
q.sort(reverse=True)
ls = p[:x]+q[:y]+r
ls.sort(reverse=True)
print(sum(ls[:x+y]))
``` | output | 1 | 32,261 | 9 | 64,523 |
Provide a correct Python 3 solution for this coding contest problem.
You are going to eat X red apples and Y green apples.
You have A red apples of deliciousness p_1,p_2, \dots, p_A, B green apples of deliciousness q_1,q_2, \dots, q_B, and C colorless apples of deliciousness r_1,r_2, \dots, r_C.
Before eating a colorless apple, you can paint it red or green, and it will count as a red or green apple, respectively.
From the apples above, you will choose the apples to eat while making the sum of the deliciousness of the eaten apples as large as possible.
Find the maximum possible sum of the deliciousness of the eaten apples that can be achieved when optimally coloring zero or more colorless apples.
Constraints
* 1 \leq X \leq A \leq 10^5
* 1 \leq Y \leq B \leq 10^5
* 1 \leq C \leq 10^5
* 1 \leq p_i \leq 10^9
* 1 \leq q_i \leq 10^9
* 1 \leq r_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y A B C
p_1 p_2 ... p_A
q_1 q_2 ... q_B
r_1 r_2 ... r_C
Output
Print the maximum possible sum of the deliciousness of the eaten apples.
Examples
Input
1 2 2 2 1
2 4
5 1
3
Output
12
Input
2 2 2 2 2
8 6
9 1
2 1
Output
25
Input
2 2 4 4 4
11 12 13 14
21 22 23 24
1 2 3 4
Output
74 | instruction | 0 | 32,262 | 9 | 64,524 |
"Correct Solution:
```
x, y, a, b, c = map(int, input().split())
p = sorted(list(map(int, input().split())), reverse=True)[:x]
q = sorted(list(map(int, input().split())), reverse=True)[:y]
r = list(map(int, input().split()))
print(sum(sorted(p + q + r, reverse=True)[:x+y]))
``` | output | 1 | 32,262 | 9 | 64,525 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are going to eat X red apples and Y green apples.
You have A red apples of deliciousness p_1,p_2, \dots, p_A, B green apples of deliciousness q_1,q_2, \dots, q_B, and C colorless apples of deliciousness r_1,r_2, \dots, r_C.
Before eating a colorless apple, you can paint it red or green, and it will count as a red or green apple, respectively.
From the apples above, you will choose the apples to eat while making the sum of the deliciousness of the eaten apples as large as possible.
Find the maximum possible sum of the deliciousness of the eaten apples that can be achieved when optimally coloring zero or more colorless apples.
Constraints
* 1 \leq X \leq A \leq 10^5
* 1 \leq Y \leq B \leq 10^5
* 1 \leq C \leq 10^5
* 1 \leq p_i \leq 10^9
* 1 \leq q_i \leq 10^9
* 1 \leq r_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y A B C
p_1 p_2 ... p_A
q_1 q_2 ... q_B
r_1 r_2 ... r_C
Output
Print the maximum possible sum of the deliciousness of the eaten apples.
Examples
Input
1 2 2 2 1
2 4
5 1
3
Output
12
Input
2 2 2 2 2
8 6
9 1
2 1
Output
25
Input
2 2 4 4 4
11 12 13 14
21 22 23 24
1 2 3 4
Output
74
Submitted Solution:
```
X, Y, A, B, C = map(int, input().split())
p = list(map(int, input().split()))
q = list(map(int, input().split()))
r = list(map(int, input().split()))
p.sort()
q.sort()
r.sort()
p = p[-X:]
q = q[-Y:]
r.extend(p)
r.extend(q)
r.sort()
print(sum(r[-(X + Y):]))
``` | instruction | 0 | 32,263 | 9 | 64,526 |
Yes | output | 1 | 32,263 | 9 | 64,527 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are going to eat X red apples and Y green apples.
You have A red apples of deliciousness p_1,p_2, \dots, p_A, B green apples of deliciousness q_1,q_2, \dots, q_B, and C colorless apples of deliciousness r_1,r_2, \dots, r_C.
Before eating a colorless apple, you can paint it red or green, and it will count as a red or green apple, respectively.
From the apples above, you will choose the apples to eat while making the sum of the deliciousness of the eaten apples as large as possible.
Find the maximum possible sum of the deliciousness of the eaten apples that can be achieved when optimally coloring zero or more colorless apples.
Constraints
* 1 \leq X \leq A \leq 10^5
* 1 \leq Y \leq B \leq 10^5
* 1 \leq C \leq 10^5
* 1 \leq p_i \leq 10^9
* 1 \leq q_i \leq 10^9
* 1 \leq r_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y A B C
p_1 p_2 ... p_A
q_1 q_2 ... q_B
r_1 r_2 ... r_C
Output
Print the maximum possible sum of the deliciousness of the eaten apples.
Examples
Input
1 2 2 2 1
2 4
5 1
3
Output
12
Input
2 2 2 2 2
8 6
9 1
2 1
Output
25
Input
2 2 4 4 4
11 12 13 14
21 22 23 24
1 2 3 4
Output
74
Submitted Solution:
```
x, y, a, b, c = map(int, input().split())
P = list(map(int, input().split()))
Q = list(map(int, input().split()))
R = list(map(int, input().split()))
P.sort(reverse=True); Q.sort(reverse=True)
print(sum(sorted(P[:x]+Q[:y]+R, reverse=True)[:x+y]))
``` | instruction | 0 | 32,264 | 9 | 64,528 |
Yes | output | 1 | 32,264 | 9 | 64,529 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are going to eat X red apples and Y green apples.
You have A red apples of deliciousness p_1,p_2, \dots, p_A, B green apples of deliciousness q_1,q_2, \dots, q_B, and C colorless apples of deliciousness r_1,r_2, \dots, r_C.
Before eating a colorless apple, you can paint it red or green, and it will count as a red or green apple, respectively.
From the apples above, you will choose the apples to eat while making the sum of the deliciousness of the eaten apples as large as possible.
Find the maximum possible sum of the deliciousness of the eaten apples that can be achieved when optimally coloring zero or more colorless apples.
Constraints
* 1 \leq X \leq A \leq 10^5
* 1 \leq Y \leq B \leq 10^5
* 1 \leq C \leq 10^5
* 1 \leq p_i \leq 10^9
* 1 \leq q_i \leq 10^9
* 1 \leq r_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y A B C
p_1 p_2 ... p_A
q_1 q_2 ... q_B
r_1 r_2 ... r_C
Output
Print the maximum possible sum of the deliciousness of the eaten apples.
Examples
Input
1 2 2 2 1
2 4
5 1
3
Output
12
Input
2 2 2 2 2
8 6
9 1
2 1
Output
25
Input
2 2 4 4 4
11 12 13 14
21 22 23 24
1 2 3 4
Output
74
Submitted Solution:
```
x,y,a,b,c=map(int,input().split())
p=sorted(list(map(int,input().split())),reverse=True)
q=sorted(list(map(int,input().split())),reverse=True)
r=sorted(list(map(int,input().split())),reverse=True)
all=sorted(p[:x]+q[:y]+r,reverse=True)
print(sum(all[:x+y]))
``` | instruction | 0 | 32,265 | 9 | 64,530 |
Yes | output | 1 | 32,265 | 9 | 64,531 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are going to eat X red apples and Y green apples.
You have A red apples of deliciousness p_1,p_2, \dots, p_A, B green apples of deliciousness q_1,q_2, \dots, q_B, and C colorless apples of deliciousness r_1,r_2, \dots, r_C.
Before eating a colorless apple, you can paint it red or green, and it will count as a red or green apple, respectively.
From the apples above, you will choose the apples to eat while making the sum of the deliciousness of the eaten apples as large as possible.
Find the maximum possible sum of the deliciousness of the eaten apples that can be achieved when optimally coloring zero or more colorless apples.
Constraints
* 1 \leq X \leq A \leq 10^5
* 1 \leq Y \leq B \leq 10^5
* 1 \leq C \leq 10^5
* 1 \leq p_i \leq 10^9
* 1 \leq q_i \leq 10^9
* 1 \leq r_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y A B C
p_1 p_2 ... p_A
q_1 q_2 ... q_B
r_1 r_2 ... r_C
Output
Print the maximum possible sum of the deliciousness of the eaten apples.
Examples
Input
1 2 2 2 1
2 4
5 1
3
Output
12
Input
2 2 2 2 2
8 6
9 1
2 1
Output
25
Input
2 2 4 4 4
11 12 13 14
21 22 23 24
1 2 3 4
Output
74
Submitted Solution:
```
import sys
input = sys.stdin.readline
X,Y,A,B,C=map(int,input().split())
P=sorted(map(int,input().split()),reverse=True)
Q=sorted(map(int,input().split()),reverse=True)
R=list(map(int,input().split()))
C=P[:X]+Q[:Y]+R
C.sort(reverse=True)
print(sum(C[:X+Y]))
``` | instruction | 0 | 32,266 | 9 | 64,532 |
Yes | output | 1 | 32,266 | 9 | 64,533 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are going to eat X red apples and Y green apples.
You have A red apples of deliciousness p_1,p_2, \dots, p_A, B green apples of deliciousness q_1,q_2, \dots, q_B, and C colorless apples of deliciousness r_1,r_2, \dots, r_C.
Before eating a colorless apple, you can paint it red or green, and it will count as a red or green apple, respectively.
From the apples above, you will choose the apples to eat while making the sum of the deliciousness of the eaten apples as large as possible.
Find the maximum possible sum of the deliciousness of the eaten apples that can be achieved when optimally coloring zero or more colorless apples.
Constraints
* 1 \leq X \leq A \leq 10^5
* 1 \leq Y \leq B \leq 10^5
* 1 \leq C \leq 10^5
* 1 \leq p_i \leq 10^9
* 1 \leq q_i \leq 10^9
* 1 \leq r_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y A B C
p_1 p_2 ... p_A
q_1 q_2 ... q_B
r_1 r_2 ... r_C
Output
Print the maximum possible sum of the deliciousness of the eaten apples.
Examples
Input
1 2 2 2 1
2 4
5 1
3
Output
12
Input
2 2 2 2 2
8 6
9 1
2 1
Output
25
Input
2 2 4 4 4
11 12 13 14
21 22 23 24
1 2 3 4
Output
74
Submitted Solution:
```
#!/usr/bin/env python3
from pprint import pprint
import sys
sys.setrecursionlimit(10 ** 6)
X, Y, A, B, C = map(int, input().split())
apples_A = sorted(list(map(int, input().split())))
apples_B = sorted(list(map(int, input().split())))
apples_C = sorted(list(map(int, input().split())))
# 赤のリンゴからおいしさが大きい順に X 個選ぶ
# 緑のリンゴからおいしさが大きい順に Y 個選ぶ
# 無色のリンゴからおいしさが最も大きいリングを選び、そのリンゴ以上の美味しさでかつ美味しさが最も小さい赤 or 緑リンゴと交換する
# 上記の交換をできるだけ多く行う
res_A = apples_A[A - X:]
res_B = apples_B[B - Y:]
while apples_C:
candidate = apples_C.pop()
min_apple = min(res_A[0], res_B[0])
if candidate <= min_apple:
break
if res_A[0] <= res_B[0]:
# there is apple which has minimum value in A
res_A[0] = candidate
else:
res_B[0] = candidate
ans = sum(res_A) + sum(res_B)
print(ans)
``` | instruction | 0 | 32,267 | 9 | 64,534 |
No | output | 1 | 32,267 | 9 | 64,535 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are going to eat X red apples and Y green apples.
You have A red apples of deliciousness p_1,p_2, \dots, p_A, B green apples of deliciousness q_1,q_2, \dots, q_B, and C colorless apples of deliciousness r_1,r_2, \dots, r_C.
Before eating a colorless apple, you can paint it red or green, and it will count as a red or green apple, respectively.
From the apples above, you will choose the apples to eat while making the sum of the deliciousness of the eaten apples as large as possible.
Find the maximum possible sum of the deliciousness of the eaten apples that can be achieved when optimally coloring zero or more colorless apples.
Constraints
* 1 \leq X \leq A \leq 10^5
* 1 \leq Y \leq B \leq 10^5
* 1 \leq C \leq 10^5
* 1 \leq p_i \leq 10^9
* 1 \leq q_i \leq 10^9
* 1 \leq r_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y A B C
p_1 p_2 ... p_A
q_1 q_2 ... q_B
r_1 r_2 ... r_C
Output
Print the maximum possible sum of the deliciousness of the eaten apples.
Examples
Input
1 2 2 2 1
2 4
5 1
3
Output
12
Input
2 2 2 2 2
8 6
9 1
2 1
Output
25
Input
2 2 4 4 4
11 12 13 14
21 22 23 24
1 2 3 4
Output
74
Submitted Solution:
```
import sys
input = sys.stdin.readline
X, Y, A, B, C = map(int, input().split())
p = [int(x) for x in input().split()]
q = [int(x) for x in input().split()]
r = [int(x) for x in input().split()]
p.sort(reverse = True)
q.sort(reverse = True)
r.sort(reverse = True)
red = p[:X]
green = q[:Y]
ri = 1
gi = 1
while True :
if not r :
break
red_min = min(red[-ri], red[-1])
green_min = min(green[-gi], green[-1])
if red_min > green_min :
if green_min < r[0] :
green.remove(green_min)
green.append(r[0])
gi += 1
r.pop(0)
else :
break
else :
if red_min < r[0] :
red.remove(red_min)
red.append(r[0])
ri += 1
r.pop(0)
else :
break
print(sum(red)+sum(green))
``` | instruction | 0 | 32,268 | 9 | 64,536 |
No | output | 1 | 32,268 | 9 | 64,537 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are going to eat X red apples and Y green apples.
You have A red apples of deliciousness p_1,p_2, \dots, p_A, B green apples of deliciousness q_1,q_2, \dots, q_B, and C colorless apples of deliciousness r_1,r_2, \dots, r_C.
Before eating a colorless apple, you can paint it red or green, and it will count as a red or green apple, respectively.
From the apples above, you will choose the apples to eat while making the sum of the deliciousness of the eaten apples as large as possible.
Find the maximum possible sum of the deliciousness of the eaten apples that can be achieved when optimally coloring zero or more colorless apples.
Constraints
* 1 \leq X \leq A \leq 10^5
* 1 \leq Y \leq B \leq 10^5
* 1 \leq C \leq 10^5
* 1 \leq p_i \leq 10^9
* 1 \leq q_i \leq 10^9
* 1 \leq r_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y A B C
p_1 p_2 ... p_A
q_1 q_2 ... q_B
r_1 r_2 ... r_C
Output
Print the maximum possible sum of the deliciousness of the eaten apples.
Examples
Input
1 2 2 2 1
2 4
5 1
3
Output
12
Input
2 2 2 2 2
8 6
9 1
2 1
Output
25
Input
2 2 4 4 4
11 12 13 14
21 22 23 24
1 2 3 4
Output
74
Submitted Solution:
```
# -*- coding: utf-8 -*-
from collections import deque
X,Y,A,B,C = map(int, input().split())
P = list(map(int, input().split()))
Q = list(map(int, input().split()))
R = list(map(int, input().split()))
def sort(L):
if len(L)==1:
return L
left = sort(L[:len(L)//2])
right = sort(L[len(L)//2:])
result = []
left.append(-1)
right.append(-1)
left_index = 0
right_index = 0
while len(result)<len(L):
if left[left_index]>=right[right_index]:
result.append(left[left_index])
left_index += 1
else:
result.append(right[right_index])
right_index += 1
return result
P = sort(P)[:X]
Q = sort(Q)[:Y]
R = sort(P+Q+R)[:X+Y]
print(sum(R))
``` | instruction | 0 | 32,269 | 9 | 64,538 |
No | output | 1 | 32,269 | 9 | 64,539 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are going to eat X red apples and Y green apples.
You have A red apples of deliciousness p_1,p_2, \dots, p_A, B green apples of deliciousness q_1,q_2, \dots, q_B, and C colorless apples of deliciousness r_1,r_2, \dots, r_C.
Before eating a colorless apple, you can paint it red or green, and it will count as a red or green apple, respectively.
From the apples above, you will choose the apples to eat while making the sum of the deliciousness of the eaten apples as large as possible.
Find the maximum possible sum of the deliciousness of the eaten apples that can be achieved when optimally coloring zero or more colorless apples.
Constraints
* 1 \leq X \leq A \leq 10^5
* 1 \leq Y \leq B \leq 10^5
* 1 \leq C \leq 10^5
* 1 \leq p_i \leq 10^9
* 1 \leq q_i \leq 10^9
* 1 \leq r_i \leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y A B C
p_1 p_2 ... p_A
q_1 q_2 ... q_B
r_1 r_2 ... r_C
Output
Print the maximum possible sum of the deliciousness of the eaten apples.
Examples
Input
1 2 2 2 1
2 4
5 1
3
Output
12
Input
2 2 2 2 2
8 6
9 1
2 1
Output
25
Input
2 2 4 4 4
11 12 13 14
21 22 23 24
1 2 3 4
Output
74
Submitted Solution:
```
from collections import deque
x,y,a,b,c=map(int,input().split())
p=sorted(list(map(int,input().split())),reverse=True)
q=sorted(list(map(int,input().split())),reverse=True)
r=deque(sorted(list(map(int,input().split())),reverse=True))
p=deque(p[:x])
q=deque(q[:y])
ans=sum(p)+sum(q)
while p[-1]<r[0] or q[-1]<r[0]:
if p[-1]<q[-1]:
ans+=r[0]-p[-1]
r.popleft()
p.pop()
else:
ans+=r[0]-q[-1]
r.popleft()
q.pop()
if p==deque([]) or q==deque([]) or r==deque([]):
break
print(ans)
``` | instruction | 0 | 32,270 | 9 | 64,540 |
No | output | 1 | 32,270 | 9 | 64,541 |
Provide a correct Python 3 solution for this coding contest problem.
You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The flavor of Apple i is L+i-1, which can be negative.
You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.
You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.
You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.
Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.
We can prove that this value is uniquely determined.
Constraints
* 2 \leq N \leq 200
* -100 \leq L \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N L
Output
Find the flavor of the apple pie made of the remaining N-1 apples when you optimally choose the apple to eat.
Examples
Input
5 2
Output
18
Input
3 -1
Output
0
Input
30 -50
Output
-1044 | instruction | 0 | 32,287 | 9 | 64,574 |
"Correct Solution:
```
N,L=map(int,input().split())
l=[L+i for i in range(N)]
l_abs=[abs(i) for i in l]
print(sum(l)-l[l_abs.index(min(l_abs))])
``` | output | 1 | 32,287 | 9 | 64,575 |
Provide a correct Python 3 solution for this coding contest problem.
You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The flavor of Apple i is L+i-1, which can be negative.
You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.
You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.
You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.
Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.
We can prove that this value is uniquely determined.
Constraints
* 2 \leq N \leq 200
* -100 \leq L \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N L
Output
Find the flavor of the apple pie made of the remaining N-1 apples when you optimally choose the apple to eat.
Examples
Input
5 2
Output
18
Input
3 -1
Output
0
Input
30 -50
Output
-1044 | instruction | 0 | 32,288 | 9 | 64,576 |
"Correct Solution:
```
N, L = map(int, input().split())
aji = [L + i for i in range(N)]
print(sum(aji) - min(aji, key=abs))
``` | output | 1 | 32,288 | 9 | 64,577 |
Provide a correct Python 3 solution for this coding contest problem.
You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The flavor of Apple i is L+i-1, which can be negative.
You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.
You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.
You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.
Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.
We can prove that this value is uniquely determined.
Constraints
* 2 \leq N \leq 200
* -100 \leq L \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N L
Output
Find the flavor of the apple pie made of the remaining N-1 apples when you optimally choose the apple to eat.
Examples
Input
5 2
Output
18
Input
3 -1
Output
0
Input
30 -50
Output
-1044 | instruction | 0 | 32,289 | 9 | 64,578 |
"Correct Solution:
```
n,l=map(int,input().split())
if n+l-1<0:
b=n+l-1
elif l>0:
b=l
else:
b=0
print(int(n*(2*l+n-1)/2-b))
``` | output | 1 | 32,289 | 9 | 64,579 |
Provide a correct Python 3 solution for this coding contest problem.
You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The flavor of Apple i is L+i-1, which can be negative.
You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.
You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.
You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.
Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.
We can prove that this value is uniquely determined.
Constraints
* 2 \leq N \leq 200
* -100 \leq L \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N L
Output
Find the flavor of the apple pie made of the remaining N-1 apples when you optimally choose the apple to eat.
Examples
Input
5 2
Output
18
Input
3 -1
Output
0
Input
30 -50
Output
-1044 | instruction | 0 | 32,290 | 9 | 64,580 |
"Correct Solution:
```
n,l = map(int,input().split())
if 0 <= l:
t = 1
else:
t = min(n,-l+1)
print(int((1/2*n*(2*l+n-1)-(t+l-1))))
``` | output | 1 | 32,290 | 9 | 64,581 |
Provide a correct Python 3 solution for this coding contest problem.
You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The flavor of Apple i is L+i-1, which can be negative.
You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.
You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.
You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.
Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.
We can prove that this value is uniquely determined.
Constraints
* 2 \leq N \leq 200
* -100 \leq L \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N L
Output
Find the flavor of the apple pie made of the remaining N-1 apples when you optimally choose the apple to eat.
Examples
Input
5 2
Output
18
Input
3 -1
Output
0
Input
30 -50
Output
-1044 | instruction | 0 | 32,291 | 9 | 64,582 |
"Correct Solution:
```
n,l = map(int,input().split())
al = [l+i for i in range(n)]
a = min(al,key=abs)
al.remove(a)
print(sum(al))
``` | output | 1 | 32,291 | 9 | 64,583 |
Provide a correct Python 3 solution for this coding contest problem.
You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The flavor of Apple i is L+i-1, which can be negative.
You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.
You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.
You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.
Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.
We can prove that this value is uniquely determined.
Constraints
* 2 \leq N \leq 200
* -100 \leq L \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N L
Output
Find the flavor of the apple pie made of the remaining N-1 apples when you optimally choose the apple to eat.
Examples
Input
5 2
Output
18
Input
3 -1
Output
0
Input
30 -50
Output
-1044 | instruction | 0 | 32,292 | 9 | 64,584 |
"Correct Solution:
```
N,L = map(int,input().split())
A = [L+i for i in range(N)]
A.sort(key = lambda x: abs(x))
answer = sum(A[1:])
print(answer)
``` | output | 1 | 32,292 | 9 | 64,585 |
Provide a correct Python 3 solution for this coding contest problem.
You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The flavor of Apple i is L+i-1, which can be negative.
You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.
You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.
You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.
Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.
We can prove that this value is uniquely determined.
Constraints
* 2 \leq N \leq 200
* -100 \leq L \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N L
Output
Find the flavor of the apple pie made of the remaining N-1 apples when you optimally choose the apple to eat.
Examples
Input
5 2
Output
18
Input
3 -1
Output
0
Input
30 -50
Output
-1044 | instruction | 0 | 32,293 | 9 | 64,586 |
"Correct Solution:
```
n,l=map(int,input().split())
a=(l-1)*n+((n+1)*(n))//2
print(a if l<=0<=l+n-1 else (a-l if 0<l else a-l-n+1))
``` | output | 1 | 32,293 | 9 | 64,587 |
Provide a correct Python 3 solution for this coding contest problem.
You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The flavor of Apple i is L+i-1, which can be negative.
You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.
You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.
You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.
Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.
We can prove that this value is uniquely determined.
Constraints
* 2 \leq N \leq 200
* -100 \leq L \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N L
Output
Find the flavor of the apple pie made of the remaining N-1 apples when you optimally choose the apple to eat.
Examples
Input
5 2
Output
18
Input
3 -1
Output
0
Input
30 -50
Output
-1044 | instruction | 0 | 32,294 | 9 | 64,588 |
"Correct Solution:
```
N,L=map(int,input().split())
L=[L+i-1 for i in range(1,N+1)]
c=sum(L)
R=[abs(i) for i in L]
print(c-L[R.index(min(R))])
``` | output | 1 | 32,294 | 9 | 64,589 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The flavor of Apple i is L+i-1, which can be negative.
You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.
You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.
You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.
Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.
We can prove that this value is uniquely determined.
Constraints
* 2 \leq N \leq 200
* -100 \leq L \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N L
Output
Find the flavor of the apple pie made of the remaining N-1 apples when you optimally choose the apple to eat.
Examples
Input
5 2
Output
18
Input
3 -1
Output
0
Input
30 -50
Output
-1044
Submitted Solution:
```
N, L = map(int, input().split())
tastes = [L + i for i in range(N)]
print(sum(tastes) - min(tastes, key=abs))
``` | instruction | 0 | 32,295 | 9 | 64,590 |
Yes | output | 1 | 32,295 | 9 | 64,591 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The flavor of Apple i is L+i-1, which can be negative.
You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.
You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.
You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.
Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.
We can prove that this value is uniquely determined.
Constraints
* 2 \leq N \leq 200
* -100 \leq L \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N L
Output
Find the flavor of the apple pie made of the remaining N-1 apples when you optimally choose the apple to eat.
Examples
Input
5 2
Output
18
Input
3 -1
Output
0
Input
30 -50
Output
-1044
Submitted Solution:
```
a,b=map(int,input().split())
ans=0
list=[i+b-1 for i in range(1,a+1)]
list.sort(key=lambda i:abs(i))
ans=sum(list[1:])
print(ans)
``` | instruction | 0 | 32,296 | 9 | 64,592 |
Yes | output | 1 | 32,296 | 9 | 64,593 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The flavor of Apple i is L+i-1, which can be negative.
You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.
You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.
You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.
Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.
We can prove that this value is uniquely determined.
Constraints
* 2 \leq N \leq 200
* -100 \leq L \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N L
Output
Find the flavor of the apple pie made of the remaining N-1 apples when you optimally choose the apple to eat.
Examples
Input
5 2
Output
18
Input
3 -1
Output
0
Input
30 -50
Output
-1044
Submitted Solution:
```
N, L = map(int, input().split())
a = []
for i in range(N):
a.append(L + i)
print(sum(a) - min(a, key=abs))
``` | instruction | 0 | 32,297 | 9 | 64,594 |
Yes | output | 1 | 32,297 | 9 | 64,595 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The flavor of Apple i is L+i-1, which can be negative.
You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.
You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.
You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.
Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.
We can prove that this value is uniquely determined.
Constraints
* 2 \leq N \leq 200
* -100 \leq L \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N L
Output
Find the flavor of the apple pie made of the remaining N-1 apples when you optimally choose the apple to eat.
Examples
Input
5 2
Output
18
Input
3 -1
Output
0
Input
30 -50
Output
-1044
Submitted Solution:
```
n, l = map(int, input().split())
x = [l+i for i in range(n)]
x = sorted(x, key=lambda x: abs(x))
print(sum(x[1:]))
``` | instruction | 0 | 32,298 | 9 | 64,596 |
Yes | output | 1 | 32,298 | 9 | 64,597 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The flavor of Apple i is L+i-1, which can be negative.
You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.
You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.
You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.
Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.
We can prove that this value is uniquely determined.
Constraints
* 2 \leq N \leq 200
* -100 \leq L \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N L
Output
Find the flavor of the apple pie made of the remaining N-1 apples when you optimally choose the apple to eat.
Examples
Input
5 2
Output
18
Input
3 -1
Output
0
Input
30 -50
Output
-1044
Submitted Solution:
```
n, l = map(int, input().split())
if l < 0 and n+l < 0:
kei = sum(list(x for x in range(l,l+n-1)))
if l < 0 and n+l >= 0:
kei = sum(list(x for x in range(l,l+n)))
if l >= 0:
kei = sum(list(x for x in range(l+1,l+n)))
print(kei)
``` | instruction | 0 | 32,299 | 9 | 64,598 |
No | output | 1 | 32,299 | 9 | 64,599 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The flavor of Apple i is L+i-1, which can be negative.
You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.
You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.
You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.
Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.
We can prove that this value is uniquely determined.
Constraints
* 2 \leq N \leq 200
* -100 \leq L \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N L
Output
Find the flavor of the apple pie made of the remaining N-1 apples when you optimally choose the apple to eat.
Examples
Input
5 2
Output
18
Input
3 -1
Output
0
Input
30 -50
Output
-1044
Submitted Solution:
```
n, l = map(int, input().split())
if l < 0:
if l+n >= 1:
print(sum(list(range(l,l+n))))
else:
print(sum(list(range(l,l+n-1))))
if l >= 0:
print(sum(list(range(l,n+2)))-l)
``` | instruction | 0 | 32,300 | 9 | 64,600 |
No | output | 1 | 32,300 | 9 | 64,601 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The flavor of Apple i is L+i-1, which can be negative.
You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.
You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.
You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.
Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.
We can prove that this value is uniquely determined.
Constraints
* 2 \leq N \leq 200
* -100 \leq L \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N L
Output
Find the flavor of the apple pie made of the remaining N-1 apples when you optimally choose the apple to eat.
Examples
Input
5 2
Output
18
Input
3 -1
Output
0
Input
30 -50
Output
-1044
Submitted Solution:
```
N,L = map(int,input().split())
sum = 0
for i in range(N):
sum += (L + i)
if L > 1:
sum = sum - L
elif (N + L -1) < 0:
sum = sum - (L + N -1)
else:
sum = sum
print(sum)
``` | instruction | 0 | 32,301 | 9 | 64,602 |
No | output | 1 | 32,301 | 9 | 64,603 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The flavor of Apple i is L+i-1, which can be negative.
You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.
You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.
You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.
Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.
We can prove that this value is uniquely determined.
Constraints
* 2 \leq N \leq 200
* -100 \leq L \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N L
Output
Find the flavor of the apple pie made of the remaining N-1 apples when you optimally choose the apple to eat.
Examples
Input
5 2
Output
18
Input
3 -1
Output
0
Input
30 -50
Output
-1044
Submitted Solution:
```
a = list(map(int,input().split()))
N = a[0]
L = a[1]
taste = 0
def if_test(N,L):
if L > 0:
for i in range(N):
taste = taste + L + i
taste = taste - L
print(taste)
elif L+N-1 < 0:
for i in range(N):
taste = taste + L + i
taste = taste - (L + N - 1)
print(taste)
else:
for i in range(N):
taste = taste + L + i
print(taste)
if_test(L,N)
``` | instruction | 0 | 32,302 | 9 | 64,604 |
No | output | 1 | 32,302 | 9 | 64,605 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This winter is so cold in Nvodsk! A group of n friends decided to buy k bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has l milliliters of the drink. Also they bought c limes and cut each of them into d slices. After that they found p grams of salt.
To make a toast, each friend needs nl milliliters of the drink, a slice of lime and np grams of salt. The friends want to make as many toasts as they can, provided they all drink the same amount. How many toasts can each friend make?
Input
The first and only line contains positive integers n, k, l, c, d, p, nl, np, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space.
Output
Print a single integer — the number of toasts each friend can make.
Examples
Input
3 4 5 10 8 100 3 1
Output
2
Input
5 100 10 1 19 90 4 3
Output
3
Input
10 1000 1000 25 23 1 50 1
Output
0
Note
A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is min(6, 80, 100) / 3 = 2. | instruction | 0 | 32,755 | 9 | 65,510 |
Tags: implementation, math
Correct Solution:
```
n, k, l, c, d, p, nl, np = list(map(int, input().split(' ')))
totml = k*l
totslice = c*d
x = totml//nl
y = p//np
z = min(x,y,totslice)
print(z//n)
``` | output | 1 | 32,755 | 9 | 65,511 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This winter is so cold in Nvodsk! A group of n friends decided to buy k bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has l milliliters of the drink. Also they bought c limes and cut each of them into d slices. After that they found p grams of salt.
To make a toast, each friend needs nl milliliters of the drink, a slice of lime and np grams of salt. The friends want to make as many toasts as they can, provided they all drink the same amount. How many toasts can each friend make?
Input
The first and only line contains positive integers n, k, l, c, d, p, nl, np, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space.
Output
Print a single integer — the number of toasts each friend can make.
Examples
Input
3 4 5 10 8 100 3 1
Output
2
Input
5 100 10 1 19 90 4 3
Output
3
Input
10 1000 1000 25 23 1 50 1
Output
0
Note
A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is min(6, 80, 100) / 3 = 2. | instruction | 0 | 32,756 | 9 | 65,512 |
Tags: implementation, math
Correct Solution:
```
n, k, l, c, d, p, nl, np = map(int,input().split())
a = (k*l)//(nl*n)
b = (c*d)//(n)
c = (p) // (np*n)
print(min(a,b,c))
``` | output | 1 | 32,756 | 9 | 65,513 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This winter is so cold in Nvodsk! A group of n friends decided to buy k bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has l milliliters of the drink. Also they bought c limes and cut each of them into d slices. After that they found p grams of salt.
To make a toast, each friend needs nl milliliters of the drink, a slice of lime and np grams of salt. The friends want to make as many toasts as they can, provided they all drink the same amount. How many toasts can each friend make?
Input
The first and only line contains positive integers n, k, l, c, d, p, nl, np, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space.
Output
Print a single integer — the number of toasts each friend can make.
Examples
Input
3 4 5 10 8 100 3 1
Output
2
Input
5 100 10 1 19 90 4 3
Output
3
Input
10 1000 1000 25 23 1 50 1
Output
0
Note
A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is min(6, 80, 100) / 3 = 2. | instruction | 0 | 32,757 | 9 | 65,514 |
Tags: implementation, math
Correct Solution:
```
arr=list(map(int, input().split()))
n=arr[0]
k=arr[1]
l=arr[2]
c=arr[3]
d=arr[4]
p=arr[5]
nl=arr[6]
np=arr[7]
drink=(k*l)//nl
slices=c*d
salt=p//np
print(min(drink, slices, salt)//n)
``` | output | 1 | 32,757 | 9 | 65,515 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This winter is so cold in Nvodsk! A group of n friends decided to buy k bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has l milliliters of the drink. Also they bought c limes and cut each of them into d slices. After that they found p grams of salt.
To make a toast, each friend needs nl milliliters of the drink, a slice of lime and np grams of salt. The friends want to make as many toasts as they can, provided they all drink the same amount. How many toasts can each friend make?
Input
The first and only line contains positive integers n, k, l, c, d, p, nl, np, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space.
Output
Print a single integer — the number of toasts each friend can make.
Examples
Input
3 4 5 10 8 100 3 1
Output
2
Input
5 100 10 1 19 90 4 3
Output
3
Input
10 1000 1000 25 23 1 50 1
Output
0
Note
A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is min(6, 80, 100) / 3 = 2. | instruction | 0 | 32,758 | 9 | 65,516 |
Tags: implementation, math
Correct Solution:
```
n,k,l,c,d,p,nl,np=map(int,input().split())
a,b,q=k*l//nl,c*d,p//np
print(min(a,b,q)//n)
``` | output | 1 | 32,758 | 9 | 65,517 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This winter is so cold in Nvodsk! A group of n friends decided to buy k bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has l milliliters of the drink. Also they bought c limes and cut each of them into d slices. After that they found p grams of salt.
To make a toast, each friend needs nl milliliters of the drink, a slice of lime and np grams of salt. The friends want to make as many toasts as they can, provided they all drink the same amount. How many toasts can each friend make?
Input
The first and only line contains positive integers n, k, l, c, d, p, nl, np, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space.
Output
Print a single integer — the number of toasts each friend can make.
Examples
Input
3 4 5 10 8 100 3 1
Output
2
Input
5 100 10 1 19 90 4 3
Output
3
Input
10 1000 1000 25 23 1 50 1
Output
0
Note
A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is min(6, 80, 100) / 3 = 2. | instruction | 0 | 32,759 | 9 | 65,518 |
Tags: implementation, math
Correct Solution:
```
#!/usr/bin/python3
def readln(): return tuple(map(int, input().split()))
n, k, l, c, d, p, nl, np = readln()
cnt_l = k * l // nl
cnt_d = c * d
cnt_p = p // np
print(min([cnt_l // n, cnt_d // n, cnt_p // n]))
``` | output | 1 | 32,759 | 9 | 65,519 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This winter is so cold in Nvodsk! A group of n friends decided to buy k bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has l milliliters of the drink. Also they bought c limes and cut each of them into d slices. After that they found p grams of salt.
To make a toast, each friend needs nl milliliters of the drink, a slice of lime and np grams of salt. The friends want to make as many toasts as they can, provided they all drink the same amount. How many toasts can each friend make?
Input
The first and only line contains positive integers n, k, l, c, d, p, nl, np, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space.
Output
Print a single integer — the number of toasts each friend can make.
Examples
Input
3 4 5 10 8 100 3 1
Output
2
Input
5 100 10 1 19 90 4 3
Output
3
Input
10 1000 1000 25 23 1 50 1
Output
0
Note
A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is min(6, 80, 100) / 3 = 2. | instruction | 0 | 32,760 | 9 | 65,520 |
Tags: implementation, math
Correct Solution:
```
n,k,l,c,d,p,nl,np=map(int,input().split())
v=(k*l)//nl
b=(c*d)
m=p//np
print(min(v,b,m)//n)
``` | output | 1 | 32,760 | 9 | 65,521 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This winter is so cold in Nvodsk! A group of n friends decided to buy k bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has l milliliters of the drink. Also they bought c limes and cut each of them into d slices. After that they found p grams of salt.
To make a toast, each friend needs nl milliliters of the drink, a slice of lime and np grams of salt. The friends want to make as many toasts as they can, provided they all drink the same amount. How many toasts can each friend make?
Input
The first and only line contains positive integers n, k, l, c, d, p, nl, np, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space.
Output
Print a single integer — the number of toasts each friend can make.
Examples
Input
3 4 5 10 8 100 3 1
Output
2
Input
5 100 10 1 19 90 4 3
Output
3
Input
10 1000 1000 25 23 1 50 1
Output
0
Note
A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is min(6, 80, 100) / 3 = 2. | instruction | 0 | 32,761 | 9 | 65,522 |
Tags: implementation, math
Correct Solution:
```
n, k, l, c, d, p, nl, np = list(map(int, input().split()))
print(min(k * l // nl, c * d, p // np) // n)
``` | output | 1 | 32,761 | 9 | 65,523 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This winter is so cold in Nvodsk! A group of n friends decided to buy k bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has l milliliters of the drink. Also they bought c limes and cut each of them into d slices. After that they found p grams of salt.
To make a toast, each friend needs nl milliliters of the drink, a slice of lime and np grams of salt. The friends want to make as many toasts as they can, provided they all drink the same amount. How many toasts can each friend make?
Input
The first and only line contains positive integers n, k, l, c, d, p, nl, np, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space.
Output
Print a single integer — the number of toasts each friend can make.
Examples
Input
3 4 5 10 8 100 3 1
Output
2
Input
5 100 10 1 19 90 4 3
Output
3
Input
10 1000 1000 25 23 1 50 1
Output
0
Note
A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is min(6, 80, 100) / 3 = 2. | instruction | 0 | 32,762 | 9 | 65,524 |
Tags: implementation, math
Correct Solution:
```
def answer():
a = input().split()
a = [int(x) for x in a]
n,k,l,c,d,p,nl,np=a[0],a[1],a[2],a[3],a[4],a[5],a[6],a[7]
volume =k*l
slices=c*d
salt=p
vols=int(volume/(nl*n))
slik=int(slices/n)
slt=int(salt/(np*n))
return min(vols,slik,slt)
print(answer())
``` | output | 1 | 32,762 | 9 | 65,525 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This winter is so cold in Nvodsk! A group of n friends decided to buy k bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has l milliliters of the drink. Also they bought c limes and cut each of them into d slices. After that they found p grams of salt.
To make a toast, each friend needs nl milliliters of the drink, a slice of lime and np grams of salt. The friends want to make as many toasts as they can, provided they all drink the same amount. How many toasts can each friend make?
Input
The first and only line contains positive integers n, k, l, c, d, p, nl, np, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space.
Output
Print a single integer — the number of toasts each friend can make.
Examples
Input
3 4 5 10 8 100 3 1
Output
2
Input
5 100 10 1 19 90 4 3
Output
3
Input
10 1000 1000 25 23 1 50 1
Output
0
Note
A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is min(6, 80, 100) / 3 = 2.
Submitted Solution:
```
a = input().split(" ")
a[0] = int(a[0])
a[1] = int(a[1])
a[2] = int(a[2])
a[3] = int(a[3])
a[4] = int(a[4])
a[5] = int(a[5])
a[6] = int(a[6])
a[7] = int(a[7])
b = a[1] * a[2] // a[6]
c = a[3] * a[4]
d = a[5] // a[7]
l = min(b , c , d)
print(l // a[0])
``` | instruction | 0 | 32,763 | 9 | 65,526 |
Yes | output | 1 | 32,763 | 9 | 65,527 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This winter is so cold in Nvodsk! A group of n friends decided to buy k bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has l milliliters of the drink. Also they bought c limes and cut each of them into d slices. After that they found p grams of salt.
To make a toast, each friend needs nl milliliters of the drink, a slice of lime and np grams of salt. The friends want to make as many toasts as they can, provided they all drink the same amount. How many toasts can each friend make?
Input
The first and only line contains positive integers n, k, l, c, d, p, nl, np, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space.
Output
Print a single integer — the number of toasts each friend can make.
Examples
Input
3 4 5 10 8 100 3 1
Output
2
Input
5 100 10 1 19 90 4 3
Output
3
Input
10 1000 1000 25 23 1 50 1
Output
0
Note
A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is min(6, 80, 100) / 3 = 2.
Submitted Solution:
```
q=input()
n,k,l,c,d,p,nl,np=map(int,q.split())
l=(k*l)
c=(c*d)
print((min(l//nl,c,p//np))//n)
``` | instruction | 0 | 32,764 | 9 | 65,528 |
Yes | output | 1 | 32,764 | 9 | 65,529 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This winter is so cold in Nvodsk! A group of n friends decided to buy k bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has l milliliters of the drink. Also they bought c limes and cut each of them into d slices. After that they found p grams of salt.
To make a toast, each friend needs nl milliliters of the drink, a slice of lime and np grams of salt. The friends want to make as many toasts as they can, provided they all drink the same amount. How many toasts can each friend make?
Input
The first and only line contains positive integers n, k, l, c, d, p, nl, np, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space.
Output
Print a single integer — the number of toasts each friend can make.
Examples
Input
3 4 5 10 8 100 3 1
Output
2
Input
5 100 10 1 19 90 4 3
Output
3
Input
10 1000 1000 25 23 1 50 1
Output
0
Note
A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is min(6, 80, 100) / 3 = 2.
Submitted Solution:
```
if __name__=='__main__':
n,k,l,c,d,p,nl,np=map(int, input().split())
drink=k*l
x=min(drink/nl,d*c,p/np)
print(int(x//n))
``` | instruction | 0 | 32,765 | 9 | 65,530 |
Yes | output | 1 | 32,765 | 9 | 65,531 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This winter is so cold in Nvodsk! A group of n friends decided to buy k bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has l milliliters of the drink. Also they bought c limes and cut each of them into d slices. After that they found p grams of salt.
To make a toast, each friend needs nl milliliters of the drink, a slice of lime and np grams of salt. The friends want to make as many toasts as they can, provided they all drink the same amount. How many toasts can each friend make?
Input
The first and only line contains positive integers n, k, l, c, d, p, nl, np, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space.
Output
Print a single integer — the number of toasts each friend can make.
Examples
Input
3 4 5 10 8 100 3 1
Output
2
Input
5 100 10 1 19 90 4 3
Output
3
Input
10 1000 1000 25 23 1 50 1
Output
0
Note
A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is min(6, 80, 100) / 3 = 2.
Submitted Solution:
```
n,k,l,c,d,p,nl,np=[int(i) for i in input().split()]
a=0
mili=(k*l)//(n*nl)
limon=(c*d)//n
namak=p//np//n
print(min(mili,namak,limon))
``` | instruction | 0 | 32,766 | 9 | 65,532 |
Yes | output | 1 | 32,766 | 9 | 65,533 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This winter is so cold in Nvodsk! A group of n friends decided to buy k bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has l milliliters of the drink. Also they bought c limes and cut each of them into d slices. After that they found p grams of salt.
To make a toast, each friend needs nl milliliters of the drink, a slice of lime and np grams of salt. The friends want to make as many toasts as they can, provided they all drink the same amount. How many toasts can each friend make?
Input
The first and only line contains positive integers n, k, l, c, d, p, nl, np, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space.
Output
Print a single integer — the number of toasts each friend can make.
Examples
Input
3 4 5 10 8 100 3 1
Output
2
Input
5 100 10 1 19 90 4 3
Output
3
Input
10 1000 1000 25 23 1 50 1
Output
0
Note
A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is min(6, 80, 100) / 3 = 2.
Submitted Solution:
```
n,k,l,c,d,p,nl,np=[int(x) for x in input().split()]
jt=(k*l)//nl
lt=c*d
st=p//np
if (jt>=n) and (lt>=n) and (st>=n):
print(min(jt,lt,st))
else:
print(0)
``` | instruction | 0 | 32,767 | 9 | 65,534 |
No | output | 1 | 32,767 | 9 | 65,535 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This winter is so cold in Nvodsk! A group of n friends decided to buy k bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has l milliliters of the drink. Also they bought c limes and cut each of them into d slices. After that they found p grams of salt.
To make a toast, each friend needs nl milliliters of the drink, a slice of lime and np grams of salt. The friends want to make as many toasts as they can, provided they all drink the same amount. How many toasts can each friend make?
Input
The first and only line contains positive integers n, k, l, c, d, p, nl, np, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space.
Output
Print a single integer — the number of toasts each friend can make.
Examples
Input
3 4 5 10 8 100 3 1
Output
2
Input
5 100 10 1 19 90 4 3
Output
3
Input
10 1000 1000 25 23 1 50 1
Output
0
Note
A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is min(6, 80, 100) / 3 = 2.
Submitted Solution:
```
a=list(map(int,input().split()))
print(min(((a[2]*a[1])//a[-2]),(a[3]*a[4]),(a[-3]//a[-1])//a[0]))
``` | instruction | 0 | 32,768 | 9 | 65,536 |
No | output | 1 | 32,768 | 9 | 65,537 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This winter is so cold in Nvodsk! A group of n friends decided to buy k bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has l milliliters of the drink. Also they bought c limes and cut each of them into d slices. After that they found p grams of salt.
To make a toast, each friend needs nl milliliters of the drink, a slice of lime and np grams of salt. The friends want to make as many toasts as they can, provided they all drink the same amount. How many toasts can each friend make?
Input
The first and only line contains positive integers n, k, l, c, d, p, nl, np, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space.
Output
Print a single integer — the number of toasts each friend can make.
Examples
Input
3 4 5 10 8 100 3 1
Output
2
Input
5 100 10 1 19 90 4 3
Output
3
Input
10 1000 1000 25 23 1 50 1
Output
0
Note
A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is min(6, 80, 100) / 3 = 2.
Submitted Solution:
```
S = input().split()
N = int(S[0])
K = int(S[1])
L = int(S[2])
C = int(S[3])
D = int(S[4])
P = int(S[5])
Nl = int(S[6])
Np = int(S[7])
M = (N*K*L)//Nl
A = (N*C*D)
I = []
I.append(M)
I.append(A)
I.append(P//Np)
print(min(I)//10)
``` | instruction | 0 | 32,769 | 9 | 65,538 |
No | output | 1 | 32,769 | 9 | 65,539 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This winter is so cold in Nvodsk! A group of n friends decided to buy k bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has l milliliters of the drink. Also they bought c limes and cut each of them into d slices. After that they found p grams of salt.
To make a toast, each friend needs nl milliliters of the drink, a slice of lime and np grams of salt. The friends want to make as many toasts as they can, provided they all drink the same amount. How many toasts can each friend make?
Input
The first and only line contains positive integers n, k, l, c, d, p, nl, np, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space.
Output
Print a single integer — the number of toasts each friend can make.
Examples
Input
3 4 5 10 8 100 3 1
Output
2
Input
5 100 10 1 19 90 4 3
Output
3
Input
10 1000 1000 25 23 1 50 1
Output
0
Note
A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is min(6, 80, 100) / 3 = 2.
Submitted Solution:
```
n, k, l, c, d, p, nl, np = map(int, input().split())
total_toast = min( (k*l)/nl, (c*d), np/p )
print(int(total_toast/n))
``` | instruction | 0 | 32,770 | 9 | 65,540 |
No | output | 1 | 32,770 | 9 | 65,541 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Karafs is some kind of vegetable in shape of an 1 × h rectangle. Tavaspolis people love Karafs and they use Karafs in almost any kind of food. Tavas, himself, is crazy about Karafs.
<image>
Each Karafs has a positive integer height. Tavas has an infinite 1-based sequence of Karafses. The height of the i-th Karafs is si = A + (i - 1) × B.
For a given m, let's define an m-bite operation as decreasing the height of at most m distinct not eaten Karafses by 1. Karafs is considered as eaten when its height becomes zero.
Now SaDDas asks you n queries. In each query he gives you numbers l, t and m and you should find the largest number r such that l ≤ r and sequence sl, sl + 1, ..., sr can be eaten by performing m-bite no more than t times or print -1 if there is no such number r.
Input
The first line of input contains three integers A, B and n (1 ≤ A, B ≤ 106, 1 ≤ n ≤ 105).
Next n lines contain information about queries. i-th line contains integers l, t, m (1 ≤ l, t, m ≤ 106) for i-th query.
Output
For each query, print its answer in a single line.
Examples
Input
2 1 4
1 5 3
3 3 10
7 10 2
6 4 8
Output
4
-1
8
-1
Input
1 5 2
1 5 10
2 7 4
Output
1
2 | instruction | 0 | 33,786 | 9 | 67,572 |
Tags: binary search, greedy, math
Correct Solution:
```
import math
a, b, n = [int(x) for x in input().split()]
for i in range(n):
l, t, m = [int(x) for x in input().split()]
x = a + (l - 1) * b
if x > t:
print("-1")
continue
r = (t - a) // b + 1
D = (2 * x - b) ** 2 + 8 * m * t * b
d = int(math.floor((-2 * x + b + math.sqrt(D)) / (2 * b)))
r = min(r, l + d - 1)
# total = t * m
# last = a + (r - 1) * b
# total_need = (x + last) * (r - l + 1) // 2
# while total_need > total:
# total_need -= last
# last -= b
# r -= 1
print(r)
``` | output | 1 | 33,786 | 9 | 67,573 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Karafs is some kind of vegetable in shape of an 1 × h rectangle. Tavaspolis people love Karafs and they use Karafs in almost any kind of food. Tavas, himself, is crazy about Karafs.
<image>
Each Karafs has a positive integer height. Tavas has an infinite 1-based sequence of Karafses. The height of the i-th Karafs is si = A + (i - 1) × B.
For a given m, let's define an m-bite operation as decreasing the height of at most m distinct not eaten Karafses by 1. Karafs is considered as eaten when its height becomes zero.
Now SaDDas asks you n queries. In each query he gives you numbers l, t and m and you should find the largest number r such that l ≤ r and sequence sl, sl + 1, ..., sr can be eaten by performing m-bite no more than t times or print -1 if there is no such number r.
Input
The first line of input contains three integers A, B and n (1 ≤ A, B ≤ 106, 1 ≤ n ≤ 105).
Next n lines contain information about queries. i-th line contains integers l, t, m (1 ≤ l, t, m ≤ 106) for i-th query.
Output
For each query, print its answer in a single line.
Examples
Input
2 1 4
1 5 3
3 3 10
7 10 2
6 4 8
Output
4
-1
8
-1
Input
1 5 2
1 5 10
2 7 4
Output
1
2 | instruction | 0 | 33,787 | 9 | 67,574 |
Tags: binary search, greedy, math
Correct Solution:
```
from collections import defaultdict,deque,Counter
import sys
import bisect
import math
input=sys.stdin.readline
mod=1000000007
a,b,n=map(int,input().split())
for ii in range(n):
l,t,m=map(int,input().split())
lo=l
hi=100000000
while lo<hi:
mid=(lo+hi)//2
count=(mid-l)+1
first=a+(l-1)*b
last=a+(mid-1)*b
#print('aaaaa',first,last,(count*(first+last))/2)
if last<=t and (count*(first+last))//2<=m*t:
lo=mid+1
else:
hi=mid
if mid!=lo:
print(mid)
else:
count=(mid-1-l)+1
first=a+(l-1)*b
last=a+(mid-1-1)*b
if last<=t and (count*(first+last))//2<=m*t and mid-1>=l:
print(mid-1)
else:
print(-1)
``` | output | 1 | 33,787 | 9 | 67,575 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Karafs is some kind of vegetable in shape of an 1 × h rectangle. Tavaspolis people love Karafs and they use Karafs in almost any kind of food. Tavas, himself, is crazy about Karafs.
<image>
Each Karafs has a positive integer height. Tavas has an infinite 1-based sequence of Karafses. The height of the i-th Karafs is si = A + (i - 1) × B.
For a given m, let's define an m-bite operation as decreasing the height of at most m distinct not eaten Karafses by 1. Karafs is considered as eaten when its height becomes zero.
Now SaDDas asks you n queries. In each query he gives you numbers l, t and m and you should find the largest number r such that l ≤ r and sequence sl, sl + 1, ..., sr can be eaten by performing m-bite no more than t times or print -1 if there is no such number r.
Input
The first line of input contains three integers A, B and n (1 ≤ A, B ≤ 106, 1 ≤ n ≤ 105).
Next n lines contain information about queries. i-th line contains integers l, t, m (1 ≤ l, t, m ≤ 106) for i-th query.
Output
For each query, print its answer in a single line.
Examples
Input
2 1 4
1 5 3
3 3 10
7 10 2
6 4 8
Output
4
-1
8
-1
Input
1 5 2
1 5 10
2 7 4
Output
1
2 | instruction | 0 | 33,788 | 9 | 67,576 |
Tags: binary search, greedy, math
Correct Solution:
```
A, B, n = map(int, input().split())
def s(i):
return A + i * B
def f(r):
return r * A + r * (r - 1) // 2 * B
for i in range(n):
l, t, m = map(int, input().split())
ans = -1
if s(l - 1) <= t:
L, R = l, 10 ** 6 + 1
while L + 1 < R:
M = (L + R) // 2
if f(M) - f(l - 1) <= t * m and s(M - 1) <= t:
L = M
else:
R = M
ans = L
print(ans)
``` | output | 1 | 33,788 | 9 | 67,577 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Karafs is some kind of vegetable in shape of an 1 × h rectangle. Tavaspolis people love Karafs and they use Karafs in almost any kind of food. Tavas, himself, is crazy about Karafs.
<image>
Each Karafs has a positive integer height. Tavas has an infinite 1-based sequence of Karafses. The height of the i-th Karafs is si = A + (i - 1) × B.
For a given m, let's define an m-bite operation as decreasing the height of at most m distinct not eaten Karafses by 1. Karafs is considered as eaten when its height becomes zero.
Now SaDDas asks you n queries. In each query he gives you numbers l, t and m and you should find the largest number r such that l ≤ r and sequence sl, sl + 1, ..., sr can be eaten by performing m-bite no more than t times or print -1 if there is no such number r.
Input
The first line of input contains three integers A, B and n (1 ≤ A, B ≤ 106, 1 ≤ n ≤ 105).
Next n lines contain information about queries. i-th line contains integers l, t, m (1 ≤ l, t, m ≤ 106) for i-th query.
Output
For each query, print its answer in a single line.
Examples
Input
2 1 4
1 5 3
3 3 10
7 10 2
6 4 8
Output
4
-1
8
-1
Input
1 5 2
1 5 10
2 7 4
Output
1
2 | instruction | 0 | 33,789 | 9 | 67,578 |
Tags: binary search, greedy, math
Correct Solution:
```
#------------------------template--------------------------#
import os
import sys
from math import *
from collections import *
# from fractions import *
# from heapq import*
from bisect import *
from io import BytesIO, IOBase
def vsInput():
sys.stdin = open('input.txt', 'r')
sys.stdout = open('output.txt', 'w')
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
ALPHA='abcdefghijklmnopqrstuvwxyz/'
M=998244353
EPS=1e-6
def Ceil(a,b): return a//b+int(a%b>0)
def value():return tuple(map(int,input().split()))
def array():return [int(i) for i in input().split()]
def Int():return int(input())
def Str():return input()
def arrayS():return [i for i in input().split()]
#-------------------------code---------------------------#
# vsInput()
def possible(r):
n=r-l+1
s=n*a+ n*(n-1)*B//2
# print(m,s,n,a)
return s<=m*t and a+B*(n-1)<=t
A,B,n=value()
for _ in range(n):
l,t,m=value()
a=A+(l-1)*B
low=l
high=10**10
ans=-1
while(low<=high):
mid=low+(high-low)//2
# print(low,mid,high)
if(possible(mid)):
ans=mid
low=mid+1
else:
high=mid-1
print(ans)
``` | output | 1 | 33,789 | 9 | 67,579 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Karafs is some kind of vegetable in shape of an 1 × h rectangle. Tavaspolis people love Karafs and they use Karafs in almost any kind of food. Tavas, himself, is crazy about Karafs.
<image>
Each Karafs has a positive integer height. Tavas has an infinite 1-based sequence of Karafses. The height of the i-th Karafs is si = A + (i - 1) × B.
For a given m, let's define an m-bite operation as decreasing the height of at most m distinct not eaten Karafses by 1. Karafs is considered as eaten when its height becomes zero.
Now SaDDas asks you n queries. In each query he gives you numbers l, t and m and you should find the largest number r such that l ≤ r and sequence sl, sl + 1, ..., sr can be eaten by performing m-bite no more than t times or print -1 if there is no such number r.
Input
The first line of input contains three integers A, B and n (1 ≤ A, B ≤ 106, 1 ≤ n ≤ 105).
Next n lines contain information about queries. i-th line contains integers l, t, m (1 ≤ l, t, m ≤ 106) for i-th query.
Output
For each query, print its answer in a single line.
Examples
Input
2 1 4
1 5 3
3 3 10
7 10 2
6 4 8
Output
4
-1
8
-1
Input
1 5 2
1 5 10
2 7 4
Output
1
2 | instruction | 0 | 33,790 | 9 | 67,580 |
Tags: binary search, greedy, math
Correct Solution:
```
from sys import stdin
A,B,n = [int(x) for x in stdin.readline().split()]
for q in range(n):
l,t,m = [int(x) for x in stdin.readline().split()]
l -= 1
if B*l+A > t:
print(-1)
else:
const = A*(l)+(B*(l-1)*(l))//2
#print(l,const)
high = (t-A)//B+1
low = l+1
while high >= low:
mid = (low+high)//2
total = A*mid+(B*mid*(mid-1))//2-const
if total <= t*m:
#print(mid, total,'valid')
low = mid+1
else:
#print(mid,total,'invalid')
high = mid-1
print(high)
``` | output | 1 | 33,790 | 9 | 67,581 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Karafs is some kind of vegetable in shape of an 1 × h rectangle. Tavaspolis people love Karafs and they use Karafs in almost any kind of food. Tavas, himself, is crazy about Karafs.
<image>
Each Karafs has a positive integer height. Tavas has an infinite 1-based sequence of Karafses. The height of the i-th Karafs is si = A + (i - 1) × B.
For a given m, let's define an m-bite operation as decreasing the height of at most m distinct not eaten Karafses by 1. Karafs is considered as eaten when its height becomes zero.
Now SaDDas asks you n queries. In each query he gives you numbers l, t and m and you should find the largest number r such that l ≤ r and sequence sl, sl + 1, ..., sr can be eaten by performing m-bite no more than t times or print -1 if there is no such number r.
Input
The first line of input contains three integers A, B and n (1 ≤ A, B ≤ 106, 1 ≤ n ≤ 105).
Next n lines contain information about queries. i-th line contains integers l, t, m (1 ≤ l, t, m ≤ 106) for i-th query.
Output
For each query, print its answer in a single line.
Examples
Input
2 1 4
1 5 3
3 3 10
7 10 2
6 4 8
Output
4
-1
8
-1
Input
1 5 2
1 5 10
2 7 4
Output
1
2 | instruction | 0 | 33,791 | 9 | 67,582 |
Tags: binary search, greedy, math
Correct Solution:
```
import math
A, B, n = map(int, input().split())
ans = []
for _ in range(n):
l, t, m = map(int, input().split())
if A + B * (l - 1) > t:
ans.append(-1)
continue
r1 = (t - A) / B + 1
D = (B-2*A)*(B-2*A)-4*B*(-2*l*A+2*A-B*(l-2)*(l-1)-2*m*t)
r2 = int(((B-2*A) + math.sqrt(D)) / 2 / B)
if r1 > r2:
r1 = r2
ans.append(int(r1))
print("\n".join(map(str, ans)))
``` | output | 1 | 33,791 | 9 | 67,583 |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.