message stringlengths 2 22.7k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 145 109k | cluster float64 9 9 | __index_level_0__ int64 290 217k |
|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
We have A apples and P pieces of apple.
We can cut an apple into three pieces of apple, and make one apple pie by simmering two pieces of apple in a pan.
Find the maximum number of apple pies we can make with what we have now.
Constraints
* All values in input are integers.
* 0 \leq A, P \leq 100
Input
Input is given from Standard Input in the following format:
A P
Output
Print the maximum number of apple pies we can make with what we have.
Examples
Input
1 3
Output
3
Input
0 1
Output
0
Input
32 21
Output
58 | instruction | 0 | 35,793 | 9 | 71,586 |
"Correct Solution:
```
a,p=map(int,input().split())
b=(3*a+p)//2
print(b)
``` | output | 1 | 35,793 | 9 | 71,587 |
Provide a correct Python 3 solution for this coding contest problem.
We have A apples and P pieces of apple.
We can cut an apple into three pieces of apple, and make one apple pie by simmering two pieces of apple in a pan.
Find the maximum number of apple pies we can make with what we have now.
Constraints
* All values in input are integers.
* 0 \leq A, P \leq 100
Input
Input is given from Standard Input in the following format:
A P
Output
Print the maximum number of apple pies we can make with what we have.
Examples
Input
1 3
Output
3
Input
0 1
Output
0
Input
32 21
Output
58 | instruction | 0 | 35,794 | 9 | 71,588 |
"Correct Solution:
```
x,p =map(int,input().split())
print(int((x*3+p)/2))
``` | output | 1 | 35,794 | 9 | 71,589 |
Provide a correct Python 3 solution for this coding contest problem.
We have A apples and P pieces of apple.
We can cut an apple into three pieces of apple, and make one apple pie by simmering two pieces of apple in a pan.
Find the maximum number of apple pies we can make with what we have now.
Constraints
* All values in input are integers.
* 0 \leq A, P \leq 100
Input
Input is given from Standard Input in the following format:
A P
Output
Print the maximum number of apple pies we can make with what we have.
Examples
Input
1 3
Output
3
Input
0 1
Output
0
Input
32 21
Output
58 | instruction | 0 | 35,795 | 9 | 71,590 |
"Correct Solution:
```
a,p=map(int,input().split())
print(((3*a)+p)//2)
``` | output | 1 | 35,795 | 9 | 71,591 |
Provide a correct Python 3 solution for this coding contest problem.
We have A apples and P pieces of apple.
We can cut an apple into three pieces of apple, and make one apple pie by simmering two pieces of apple in a pan.
Find the maximum number of apple pies we can make with what we have now.
Constraints
* All values in input are integers.
* 0 \leq A, P \leq 100
Input
Input is given from Standard Input in the following format:
A P
Output
Print the maximum number of apple pies we can make with what we have.
Examples
Input
1 3
Output
3
Input
0 1
Output
0
Input
32 21
Output
58 | instruction | 0 | 35,796 | 9 | 71,592 |
"Correct Solution:
```
A,P= map(int, input().split())
B=(3*A+P) // 2
print(B)
``` | output | 1 | 35,796 | 9 | 71,593 |
Provide a correct Python 3 solution for this coding contest problem.
We have A apples and P pieces of apple.
We can cut an apple into three pieces of apple, and make one apple pie by simmering two pieces of apple in a pan.
Find the maximum number of apple pies we can make with what we have now.
Constraints
* All values in input are integers.
* 0 \leq A, P \leq 100
Input
Input is given from Standard Input in the following format:
A P
Output
Print the maximum number of apple pies we can make with what we have.
Examples
Input
1 3
Output
3
Input
0 1
Output
0
Input
32 21
Output
58 | instruction | 0 | 35,797 | 9 | 71,594 |
"Correct Solution:
```
A, P = map(int,input().split())
s = 3*A + P
print(s//2)
``` | output | 1 | 35,797 | 9 | 71,595 |
Provide a correct Python 3 solution for this coding contest problem.
We have A apples and P pieces of apple.
We can cut an apple into three pieces of apple, and make one apple pie by simmering two pieces of apple in a pan.
Find the maximum number of apple pies we can make with what we have now.
Constraints
* All values in input are integers.
* 0 \leq A, P \leq 100
Input
Input is given from Standard Input in the following format:
A P
Output
Print the maximum number of apple pies we can make with what we have.
Examples
Input
1 3
Output
3
Input
0 1
Output
0
Input
32 21
Output
58 | instruction | 0 | 35,798 | 9 | 71,596 |
"Correct Solution:
```
n,k = map(int,input().split(' '))
A = n*3+k
print(A//2)
``` | output | 1 | 35,798 | 9 | 71,597 |
Provide a correct Python 3 solution for this coding contest problem.
We have A apples and P pieces of apple.
We can cut an apple into three pieces of apple, and make one apple pie by simmering two pieces of apple in a pan.
Find the maximum number of apple pies we can make with what we have now.
Constraints
* All values in input are integers.
* 0 \leq A, P \leq 100
Input
Input is given from Standard Input in the following format:
A P
Output
Print the maximum number of apple pies we can make with what we have.
Examples
Input
1 3
Output
3
Input
0 1
Output
0
Input
32 21
Output
58 | instruction | 0 | 35,799 | 9 | 71,598 |
"Correct Solution:
```
a, p = map(int, input().split())
print(int((a*3+p)//2))
``` | output | 1 | 35,799 | 9 | 71,599 |
Provide a correct Python 3 solution for this coding contest problem.
We have A apples and P pieces of apple.
We can cut an apple into three pieces of apple, and make one apple pie by simmering two pieces of apple in a pan.
Find the maximum number of apple pies we can make with what we have now.
Constraints
* All values in input are integers.
* 0 \leq A, P \leq 100
Input
Input is given from Standard Input in the following format:
A P
Output
Print the maximum number of apple pies we can make with what we have.
Examples
Input
1 3
Output
3
Input
0 1
Output
0
Input
32 21
Output
58 | instruction | 0 | 35,800 | 9 | 71,600 |
"Correct Solution:
```
a,p=map(int,input().split( ))
p=p+a*3
print(p//2)
``` | output | 1 | 35,800 | 9 | 71,601 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have A apples and P pieces of apple.
We can cut an apple into three pieces of apple, and make one apple pie by simmering two pieces of apple in a pan.
Find the maximum number of apple pies we can make with what we have now.
Constraints
* All values in input are integers.
* 0 \leq A, P \leq 100
Input
Input is given from Standard Input in the following format:
A P
Output
Print the maximum number of apple pies we can make with what we have.
Examples
Input
1 3
Output
3
Input
0 1
Output
0
Input
32 21
Output
58
Submitted Solution:
```
a, p = map(int, input().split())
k = a*3+p
print(k//2)
``` | instruction | 0 | 35,801 | 9 | 71,602 |
Yes | output | 1 | 35,801 | 9 | 71,603 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have A apples and P pieces of apple.
We can cut an apple into three pieces of apple, and make one apple pie by simmering two pieces of apple in a pan.
Find the maximum number of apple pies we can make with what we have now.
Constraints
* All values in input are integers.
* 0 \leq A, P \leq 100
Input
Input is given from Standard Input in the following format:
A P
Output
Print the maximum number of apple pies we can make with what we have.
Examples
Input
1 3
Output
3
Input
0 1
Output
0
Input
32 21
Output
58
Submitted Solution:
```
A,P = map(int, input().split())
print(int((A*3+P)//2))
``` | instruction | 0 | 35,802 | 9 | 71,604 |
Yes | output | 1 | 35,802 | 9 | 71,605 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have A apples and P pieces of apple.
We can cut an apple into three pieces of apple, and make one apple pie by simmering two pieces of apple in a pan.
Find the maximum number of apple pies we can make with what we have now.
Constraints
* All values in input are integers.
* 0 \leq A, P \leq 100
Input
Input is given from Standard Input in the following format:
A P
Output
Print the maximum number of apple pies we can make with what we have.
Examples
Input
1 3
Output
3
Input
0 1
Output
0
Input
32 21
Output
58
Submitted Solution:
```
A,P=map(int,input().split())
c=(A*3+P)//2
print(c)
``` | instruction | 0 | 35,803 | 9 | 71,606 |
Yes | output | 1 | 35,803 | 9 | 71,607 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have A apples and P pieces of apple.
We can cut an apple into three pieces of apple, and make one apple pie by simmering two pieces of apple in a pan.
Find the maximum number of apple pies we can make with what we have now.
Constraints
* All values in input are integers.
* 0 \leq A, P \leq 100
Input
Input is given from Standard Input in the following format:
A P
Output
Print the maximum number of apple pies we can make with what we have.
Examples
Input
1 3
Output
3
Input
0 1
Output
0
Input
32 21
Output
58
Submitted Solution:
```
A,P = map(int,input().split())
P = P + A*3
print(P//2)
``` | instruction | 0 | 35,804 | 9 | 71,608 |
Yes | output | 1 | 35,804 | 9 | 71,609 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have A apples and P pieces of apple.
We can cut an apple into three pieces of apple, and make one apple pie by simmering two pieces of apple in a pan.
Find the maximum number of apple pies we can make with what we have now.
Constraints
* All values in input are integers.
* 0 \leq A, P \leq 100
Input
Input is given from Standard Input in the following format:
A P
Output
Print the maximum number of apple pies we can make with what we have.
Examples
Input
1 3
Output
3
Input
0 1
Output
0
Input
32 21
Output
58
Submitted Solution:
```
A = 42
B = 26
pies = (A*3 + B) // 2
print(pies)
``` | instruction | 0 | 35,805 | 9 | 71,610 |
No | output | 1 | 35,805 | 9 | 71,611 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have A apples and P pieces of apple.
We can cut an apple into three pieces of apple, and make one apple pie by simmering two pieces of apple in a pan.
Find the maximum number of apple pies we can make with what we have now.
Constraints
* All values in input are integers.
* 0 \leq A, P \leq 100
Input
Input is given from Standard Input in the following format:
A P
Output
Print the maximum number of apple pies we can make with what we have.
Examples
Input
1 3
Output
3
Input
0 1
Output
0
Input
32 21
Output
58
Submitted Solution:
```
A, P = map(int, input().input())
print((A * 3 + P)//2)
``` | instruction | 0 | 35,806 | 9 | 71,612 |
No | output | 1 | 35,806 | 9 | 71,613 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have A apples and P pieces of apple.
We can cut an apple into three pieces of apple, and make one apple pie by simmering two pieces of apple in a pan.
Find the maximum number of apple pies we can make with what we have now.
Constraints
* All values in input are integers.
* 0 \leq A, P \leq 100
Input
Input is given from Standard Input in the following format:
A P
Output
Print the maximum number of apple pies we can make with what we have.
Examples
Input
1 3
Output
3
Input
0 1
Output
0
Input
32 21
Output
58
Submitted Solution:
```
x,p =map(int,input().split())
print(int((x*3+p)))
``` | instruction | 0 | 35,807 | 9 | 71,614 |
No | output | 1 | 35,807 | 9 | 71,615 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have A apples and P pieces of apple.
We can cut an apple into three pieces of apple, and make one apple pie by simmering two pieces of apple in a pan.
Find the maximum number of apple pies we can make with what we have now.
Constraints
* All values in input are integers.
* 0 \leq A, P \leq 100
Input
Input is given from Standard Input in the following format:
A P
Output
Print the maximum number of apple pies we can make with what we have.
Examples
Input
1 3
Output
3
Input
0 1
Output
0
Input
32 21
Output
58
Submitted Solution:
```
import numpy as np
``` | instruction | 0 | 35,808 | 9 | 71,616 |
No | output | 1 | 35,808 | 9 | 71,617 |
Provide a correct Python 3 solution for this coding contest problem.
There is always an integer in Takahashi's mind.
Initially, the integer in Takahashi's mind is 0. Takahashi is now going to eat four symbols, each of which is `+` or `-`. When he eats `+`, the integer in his mind increases by 1; when he eats `-`, the integer in his mind decreases by 1.
The symbols Takahashi is going to eat are given to you as a string S. The i-th character in S is the i-th symbol for him to eat.
Find the integer in Takahashi's mind after he eats all the symbols.
Constraints
* The length of S is 4.
* Each character in S is `+` or `-`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the integer in Takahashi's mind after he eats all the symbols.
Examples
Input
+-++
Output
2
Input
-+--
Output
-2
Input
----
Output
-4 | instruction | 0 | 35,825 | 9 | 71,650 |
"Correct Solution:
```
S = input()
print(4-2*S.count("-"))
``` | output | 1 | 35,825 | 9 | 71,651 |
Provide a correct Python 3 solution for this coding contest problem.
There is always an integer in Takahashi's mind.
Initially, the integer in Takahashi's mind is 0. Takahashi is now going to eat four symbols, each of which is `+` or `-`. When he eats `+`, the integer in his mind increases by 1; when he eats `-`, the integer in his mind decreases by 1.
The symbols Takahashi is going to eat are given to you as a string S. The i-th character in S is the i-th symbol for him to eat.
Find the integer in Takahashi's mind after he eats all the symbols.
Constraints
* The length of S is 4.
* Each character in S is `+` or `-`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the integer in Takahashi's mind after he eats all the symbols.
Examples
Input
+-++
Output
2
Input
-+--
Output
-2
Input
----
Output
-4 | instruction | 0 | 35,826 | 9 | 71,652 |
"Correct Solution:
```
s = input()
print(4 - s.count('-')*2)
``` | output | 1 | 35,826 | 9 | 71,653 |
Provide a correct Python 3 solution for this coding contest problem.
There is always an integer in Takahashi's mind.
Initially, the integer in Takahashi's mind is 0. Takahashi is now going to eat four symbols, each of which is `+` or `-`. When he eats `+`, the integer in his mind increases by 1; when he eats `-`, the integer in his mind decreases by 1.
The symbols Takahashi is going to eat are given to you as a string S. The i-th character in S is the i-th symbol for him to eat.
Find the integer in Takahashi's mind after he eats all the symbols.
Constraints
* The length of S is 4.
* Each character in S is `+` or `-`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the integer in Takahashi's mind after he eats all the symbols.
Examples
Input
+-++
Output
2
Input
-+--
Output
-2
Input
----
Output
-4 | instruction | 0 | 35,827 | 9 | 71,654 |
"Correct Solution:
```
s = input()
p = s.count("+")
m = 4-p
print(p-m)
``` | output | 1 | 35,827 | 9 | 71,655 |
Provide a correct Python 3 solution for this coding contest problem.
There is always an integer in Takahashi's mind.
Initially, the integer in Takahashi's mind is 0. Takahashi is now going to eat four symbols, each of which is `+` or `-`. When he eats `+`, the integer in his mind increases by 1; when he eats `-`, the integer in his mind decreases by 1.
The symbols Takahashi is going to eat are given to you as a string S. The i-th character in S is the i-th symbol for him to eat.
Find the integer in Takahashi's mind after he eats all the symbols.
Constraints
* The length of S is 4.
* Each character in S is `+` or `-`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the integer in Takahashi's mind after he eats all the symbols.
Examples
Input
+-++
Output
2
Input
-+--
Output
-2
Input
----
Output
-4 | instruction | 0 | 35,828 | 9 | 71,656 |
"Correct Solution:
```
s=str(input())
m=s.count('-')
print(4-2*m)
``` | output | 1 | 35,828 | 9 | 71,657 |
Provide a correct Python 3 solution for this coding contest problem.
There is always an integer in Takahashi's mind.
Initially, the integer in Takahashi's mind is 0. Takahashi is now going to eat four symbols, each of which is `+` or `-`. When he eats `+`, the integer in his mind increases by 1; when he eats `-`, the integer in his mind decreases by 1.
The symbols Takahashi is going to eat are given to you as a string S. The i-th character in S is the i-th symbol for him to eat.
Find the integer in Takahashi's mind after he eats all the symbols.
Constraints
* The length of S is 4.
* Each character in S is `+` or `-`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the integer in Takahashi's mind after he eats all the symbols.
Examples
Input
+-++
Output
2
Input
-+--
Output
-2
Input
----
Output
-4 | instruction | 0 | 35,829 | 9 | 71,658 |
"Correct Solution:
```
n = input().count('+')
print(2*n-4)
``` | output | 1 | 35,829 | 9 | 71,659 |
Provide a correct Python 3 solution for this coding contest problem.
There is always an integer in Takahashi's mind.
Initially, the integer in Takahashi's mind is 0. Takahashi is now going to eat four symbols, each of which is `+` or `-`. When he eats `+`, the integer in his mind increases by 1; when he eats `-`, the integer in his mind decreases by 1.
The symbols Takahashi is going to eat are given to you as a string S. The i-th character in S is the i-th symbol for him to eat.
Find the integer in Takahashi's mind after he eats all the symbols.
Constraints
* The length of S is 4.
* Each character in S is `+` or `-`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the integer in Takahashi's mind after he eats all the symbols.
Examples
Input
+-++
Output
2
Input
-+--
Output
-2
Input
----
Output
-4 | instruction | 0 | 35,830 | 9 | 71,660 |
"Correct Solution:
```
n=sum(map(lambda a:a=='+',input()));print(2*n-4)
``` | output | 1 | 35,830 | 9 | 71,661 |
Provide a correct Python 3 solution for this coding contest problem.
There is always an integer in Takahashi's mind.
Initially, the integer in Takahashi's mind is 0. Takahashi is now going to eat four symbols, each of which is `+` or `-`. When he eats `+`, the integer in his mind increases by 1; when he eats `-`, the integer in his mind decreases by 1.
The symbols Takahashi is going to eat are given to you as a string S. The i-th character in S is the i-th symbol for him to eat.
Find the integer in Takahashi's mind after he eats all the symbols.
Constraints
* The length of S is 4.
* Each character in S is `+` or `-`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the integer in Takahashi's mind after he eats all the symbols.
Examples
Input
+-++
Output
2
Input
-+--
Output
-2
Input
----
Output
-4 | instruction | 0 | 35,831 | 9 | 71,662 |
"Correct Solution:
```
cnt = sum(s=='+' for s in input())
print(cnt*2-4)
``` | output | 1 | 35,831 | 9 | 71,663 |
Provide a correct Python 3 solution for this coding contest problem.
There is always an integer in Takahashi's mind.
Initially, the integer in Takahashi's mind is 0. Takahashi is now going to eat four symbols, each of which is `+` or `-`. When he eats `+`, the integer in his mind increases by 1; when he eats `-`, the integer in his mind decreases by 1.
The symbols Takahashi is going to eat are given to you as a string S. The i-th character in S is the i-th symbol for him to eat.
Find the integer in Takahashi's mind after he eats all the symbols.
Constraints
* The length of S is 4.
* Each character in S is `+` or `-`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the integer in Takahashi's mind after he eats all the symbols.
Examples
Input
+-++
Output
2
Input
-+--
Output
-2
Input
----
Output
-4 | instruction | 0 | 35,832 | 9 | 71,664 |
"Correct Solution:
```
s=input()
a=s.count("+")
ans=-4+a*2
print(ans)
``` | output | 1 | 35,832 | 9 | 71,665 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is always an integer in Takahashi's mind.
Initially, the integer in Takahashi's mind is 0. Takahashi is now going to eat four symbols, each of which is `+` or `-`. When he eats `+`, the integer in his mind increases by 1; when he eats `-`, the integer in his mind decreases by 1.
The symbols Takahashi is going to eat are given to you as a string S. The i-th character in S is the i-th symbol for him to eat.
Find the integer in Takahashi's mind after he eats all the symbols.
Constraints
* The length of S is 4.
* Each character in S is `+` or `-`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the integer in Takahashi's mind after he eats all the symbols.
Examples
Input
+-++
Output
2
Input
-+--
Output
-2
Input
----
Output
-4
Submitted Solution:
```
s = input().count('-')
print(4-2*s)
``` | instruction | 0 | 35,833 | 9 | 71,666 |
Yes | output | 1 | 35,833 | 9 | 71,667 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is always an integer in Takahashi's mind.
Initially, the integer in Takahashi's mind is 0. Takahashi is now going to eat four symbols, each of which is `+` or `-`. When he eats `+`, the integer in his mind increases by 1; when he eats `-`, the integer in his mind decreases by 1.
The symbols Takahashi is going to eat are given to you as a string S. The i-th character in S is the i-th symbol for him to eat.
Find the integer in Takahashi's mind after he eats all the symbols.
Constraints
* The length of S is 4.
* Each character in S is `+` or `-`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the integer in Takahashi's mind after he eats all the symbols.
Examples
Input
+-++
Output
2
Input
-+--
Output
-2
Input
----
Output
-4
Submitted Solution:
```
hoge=input()
print(hoge.count("+")-hoge.count("-"))
``` | instruction | 0 | 35,834 | 9 | 71,668 |
Yes | output | 1 | 35,834 | 9 | 71,669 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is always an integer in Takahashi's mind.
Initially, the integer in Takahashi's mind is 0. Takahashi is now going to eat four symbols, each of which is `+` or `-`. When he eats `+`, the integer in his mind increases by 1; when he eats `-`, the integer in his mind decreases by 1.
The symbols Takahashi is going to eat are given to you as a string S. The i-th character in S is the i-th symbol for him to eat.
Find the integer in Takahashi's mind after he eats all the symbols.
Constraints
* The length of S is 4.
* Each character in S is `+` or `-`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the integer in Takahashi's mind after he eats all the symbols.
Examples
Input
+-++
Output
2
Input
-+--
Output
-2
Input
----
Output
-4
Submitted Solution:
```
a=input()
b=(a.count('+'))
n=-4+b*2
print (n)
``` | instruction | 0 | 35,835 | 9 | 71,670 |
Yes | output | 1 | 35,835 | 9 | 71,671 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is always an integer in Takahashi's mind.
Initially, the integer in Takahashi's mind is 0. Takahashi is now going to eat four symbols, each of which is `+` or `-`. When he eats `+`, the integer in his mind increases by 1; when he eats `-`, the integer in his mind decreases by 1.
The symbols Takahashi is going to eat are given to you as a string S. The i-th character in S is the i-th symbol for him to eat.
Find the integer in Takahashi's mind after he eats all the symbols.
Constraints
* The length of S is 4.
* Each character in S is `+` or `-`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the integer in Takahashi's mind after he eats all the symbols.
Examples
Input
+-++
Output
2
Input
-+--
Output
-2
Input
----
Output
-4
Submitted Solution:
```
s=input()
n=len(s)
a=s.count("+")
print(2*a - n)
``` | instruction | 0 | 35,836 | 9 | 71,672 |
Yes | output | 1 | 35,836 | 9 | 71,673 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is always an integer in Takahashi's mind.
Initially, the integer in Takahashi's mind is 0. Takahashi is now going to eat four symbols, each of which is `+` or `-`. When he eats `+`, the integer in his mind increases by 1; when he eats `-`, the integer in his mind decreases by 1.
The symbols Takahashi is going to eat are given to you as a string S. The i-th character in S is the i-th symbol for him to eat.
Find the integer in Takahashi's mind after he eats all the symbols.
Constraints
* The length of S is 4.
* Each character in S is `+` or `-`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the integer in Takahashi's mind after he eats all the symbols.
Examples
Input
+-++
Output
2
Input
-+--
Output
-2
Input
----
Output
-4
Submitted Solution:
```
a=list(input())
sum=0
for i in range(len(a)):
sum+=1 if a[i]=="+" else sum-1
print(sum)
``` | instruction | 0 | 35,837 | 9 | 71,674 |
No | output | 1 | 35,837 | 9 | 71,675 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is always an integer in Takahashi's mind.
Initially, the integer in Takahashi's mind is 0. Takahashi is now going to eat four symbols, each of which is `+` or `-`. When he eats `+`, the integer in his mind increases by 1; when he eats `-`, the integer in his mind decreases by 1.
The symbols Takahashi is going to eat are given to you as a string S. The i-th character in S is the i-th symbol for him to eat.
Find the integer in Takahashi's mind after he eats all the symbols.
Constraints
* The length of S is 4.
* Each character in S is `+` or `-`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the integer in Takahashi's mind after he eats all the symbols.
Examples
Input
+-++
Output
2
Input
-+--
Output
-2
Input
----
Output
-4
Submitted Solution:
```
# -*- coding: utf-8 -*-
A,B,C,D=map(str,input().split())
+ = "1"
- = "-1"
L = [+,-]
S = map(int,L.split())
print("{}".format(A+B+C+D))
``` | instruction | 0 | 35,838 | 9 | 71,676 |
No | output | 1 | 35,838 | 9 | 71,677 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is always an integer in Takahashi's mind.
Initially, the integer in Takahashi's mind is 0. Takahashi is now going to eat four symbols, each of which is `+` or `-`. When he eats `+`, the integer in his mind increases by 1; when he eats `-`, the integer in his mind decreases by 1.
The symbols Takahashi is going to eat are given to you as a string S. The i-th character in S is the i-th symbol for him to eat.
Find the integer in Takahashi's mind after he eats all the symbols.
Constraints
* The length of S is 4.
* Each character in S is `+` or `-`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the integer in Takahashi's mind after he eats all the symbols.
Examples
Input
+-++
Output
2
Input
-+--
Output
-2
Input
----
Output
-4
Submitted Solution:
```
import math
n, k = map(int, input().split())
data = list(map(int, input().split()))
print(math.ceil((n-1)/(k-1)))
``` | instruction | 0 | 35,839 | 9 | 71,678 |
No | output | 1 | 35,839 | 9 | 71,679 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is always an integer in Takahashi's mind.
Initially, the integer in Takahashi's mind is 0. Takahashi is now going to eat four symbols, each of which is `+` or `-`. When he eats `+`, the integer in his mind increases by 1; when he eats `-`, the integer in his mind decreases by 1.
The symbols Takahashi is going to eat are given to you as a string S. The i-th character in S is the i-th symbol for him to eat.
Find the integer in Takahashi's mind after he eats all the symbols.
Constraints
* The length of S is 4.
* Each character in S is `+` or `-`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the integer in Takahashi's mind after he eats all the symbols.
Examples
Input
+-++
Output
2
Input
-+--
Output
-2
Input
----
Output
-4
Submitted Solution:
```
from sys import stdin
n_s, k_s = stdin.readline().rstrip().split() # ει‘ζγ«εΊγ¦γγAοΌBοΌCγη©Ίη½εΊεγγ§1θ‘γ§ε
₯εγγγε ΄εγ―γ’γ³γγγ―代ε
₯γδΎΏε©
a_s_l = stdin.readline().rstrip().split() # ει‘ζγ«εΊγ¦γγAοΌBοΌCγη©Ίη½εΊεγγ§1θ‘γ§ε
₯εγγγε ΄εγ―γ’γ³γγγ―代ε
₯γδΎΏε©
N = int(n_s)
K = int(k_s)
#A = []
"""
for i in a_s_l:
A.append(int(i))
"""
A = list(map(int, a_s_l))
#AA = A
count = 0
j = K - 1
for i, a in enumerate(A):
if N == K :
count = count + 1
break
elif i > N - K:
#buf = A[N - K : N]
count = count + 1
elif j== i :
#buf = A[i : i + K]
count = count + 1
j = i + K - 1
print(count)
``` | instruction | 0 | 35,840 | 9 | 71,680 |
No | output | 1 | 35,840 | 9 | 71,681 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Natasha is planning an expedition to Mars for n people. One of the important tasks is to provide food for each participant.
The warehouse has m daily food packages. Each package has some food type a_i.
Each participant must eat exactly one food package each day. Due to extreme loads, each participant must eat the same food type throughout the expedition. Different participants may eat different (or the same) types of food.
Formally, for each participant j Natasha should select his food type b_j and each day j-th participant will eat one food package of type b_j. The values b_j for different participants may be different.
What is the maximum possible number of days the expedition can last, following the requirements above?
Input
The first line contains two integers n and m (1 β€ n β€ 100, 1 β€ m β€ 100) β the number of the expedition participants and the number of the daily food packages available.
The second line contains sequence of integers a_1, a_2, ..., a_m (1 β€ a_i β€ 100), where a_i is the type of i-th food package.
Output
Print the single integer β the number of days the expedition can last. If it is not possible to plan the expedition for even one day, print 0.
Examples
Input
4 10
1 5 2 1 1 1 2 5 7 2
Output
2
Input
100 1
1
Output
0
Input
2 5
5 4 3 2 1
Output
1
Input
3 9
42 42 42 42 42 42 42 42 42
Output
3
Note
In the first example, Natasha can assign type 1 food to the first participant, the same type 1 to the second, type 5 to the third and type 2 to the fourth. In this case, the expedition can last for 2 days, since each participant can get two food packages of his food type (there will be used 4 packages of type 1, two packages of type 2 and two packages of type 5).
In the second example, there are 100 participants and only 1 food package. In this case, the expedition can't last even 1 day. | instruction | 0 | 35,982 | 9 | 71,964 |
Tags: binary search, brute force, implementation
Correct Solution:
```
from collections import Counter
def _cal(arr, x):
ans = 0
for i in arr:
ans += int(i/x)
return ans
def main():
n, m = [int(x) for x in input().split()]
a = [int(x) for x in input().split()]
if (n > m):
print(0)
return
n_of_each_type = list(Counter(a).values())
max_val = max(n_of_each_type)
x = None
for i in range(1, max_val + 1, 1):
val = _cal(n_of_each_type, i)
if (val >= n):
x = i
if (x): print(x)
else: print(0)
main()
``` | output | 1 | 35,982 | 9 | 71,965 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Natasha is planning an expedition to Mars for n people. One of the important tasks is to provide food for each participant.
The warehouse has m daily food packages. Each package has some food type a_i.
Each participant must eat exactly one food package each day. Due to extreme loads, each participant must eat the same food type throughout the expedition. Different participants may eat different (or the same) types of food.
Formally, for each participant j Natasha should select his food type b_j and each day j-th participant will eat one food package of type b_j. The values b_j for different participants may be different.
What is the maximum possible number of days the expedition can last, following the requirements above?
Input
The first line contains two integers n and m (1 β€ n β€ 100, 1 β€ m β€ 100) β the number of the expedition participants and the number of the daily food packages available.
The second line contains sequence of integers a_1, a_2, ..., a_m (1 β€ a_i β€ 100), where a_i is the type of i-th food package.
Output
Print the single integer β the number of days the expedition can last. If it is not possible to plan the expedition for even one day, print 0.
Examples
Input
4 10
1 5 2 1 1 1 2 5 7 2
Output
2
Input
100 1
1
Output
0
Input
2 5
5 4 3 2 1
Output
1
Input
3 9
42 42 42 42 42 42 42 42 42
Output
3
Note
In the first example, Natasha can assign type 1 food to the first participant, the same type 1 to the second, type 5 to the third and type 2 to the fourth. In this case, the expedition can last for 2 days, since each participant can get two food packages of his food type (there will be used 4 packages of type 1, two packages of type 2 and two packages of type 5).
In the second example, there are 100 participants and only 1 food package. In this case, the expedition can't last even 1 day. | instruction | 0 | 35,983 | 9 | 71,966 |
Tags: binary search, brute force, implementation
Correct Solution:
```
n, m = map(int, input().split())
a = list(map(int, input().split()))
vis = [0 for i in range(105)]
for i in range(m):
vis[a[i]] += 1
ans = 0
for i in range(1, m + 1):
cnt = 0
for j in range(1, 101):
cnt += vis[j] // i
if cnt >= n:
ans = max(ans, i)
print(ans)
``` | output | 1 | 35,983 | 9 | 71,967 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Natasha is planning an expedition to Mars for n people. One of the important tasks is to provide food for each participant.
The warehouse has m daily food packages. Each package has some food type a_i.
Each participant must eat exactly one food package each day. Due to extreme loads, each participant must eat the same food type throughout the expedition. Different participants may eat different (or the same) types of food.
Formally, for each participant j Natasha should select his food type b_j and each day j-th participant will eat one food package of type b_j. The values b_j for different participants may be different.
What is the maximum possible number of days the expedition can last, following the requirements above?
Input
The first line contains two integers n and m (1 β€ n β€ 100, 1 β€ m β€ 100) β the number of the expedition participants and the number of the daily food packages available.
The second line contains sequence of integers a_1, a_2, ..., a_m (1 β€ a_i β€ 100), where a_i is the type of i-th food package.
Output
Print the single integer β the number of days the expedition can last. If it is not possible to plan the expedition for even one day, print 0.
Examples
Input
4 10
1 5 2 1 1 1 2 5 7 2
Output
2
Input
100 1
1
Output
0
Input
2 5
5 4 3 2 1
Output
1
Input
3 9
42 42 42 42 42 42 42 42 42
Output
3
Note
In the first example, Natasha can assign type 1 food to the first participant, the same type 1 to the second, type 5 to the third and type 2 to the fourth. In this case, the expedition can last for 2 days, since each participant can get two food packages of his food type (there will be used 4 packages of type 1, two packages of type 2 and two packages of type 5).
In the second example, there are 100 participants and only 1 food package. In this case, the expedition can't last even 1 day. | instruction | 0 | 35,984 | 9 | 71,968 |
Tags: binary search, brute force, implementation
Correct Solution:
```
def f(n, order, i):
num = 0
for c in order:
num += int(c / i)
if num >= n:
return True
return False
if __name__ == "__main__":
n, m = map(int, input().split(" "))
inputs = list(map(int, input().split(" ")))
l = [0] * 100
for i in inputs:
l[i - 1] += 1
order = []
for i in range(100):
if l[i] != 0:
order.append(l[i])
# print(order)
best = 0
minn = 1
maxx = sum(order)+1
while minn != maxx:
middle = int((minn + maxx) / 2)
if f(n, order, middle):
best = middle
minn = middle + 1
else:
maxx = middle
print(int(best))
``` | output | 1 | 35,984 | 9 | 71,969 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Natasha is planning an expedition to Mars for n people. One of the important tasks is to provide food for each participant.
The warehouse has m daily food packages. Each package has some food type a_i.
Each participant must eat exactly one food package each day. Due to extreme loads, each participant must eat the same food type throughout the expedition. Different participants may eat different (or the same) types of food.
Formally, for each participant j Natasha should select his food type b_j and each day j-th participant will eat one food package of type b_j. The values b_j for different participants may be different.
What is the maximum possible number of days the expedition can last, following the requirements above?
Input
The first line contains two integers n and m (1 β€ n β€ 100, 1 β€ m β€ 100) β the number of the expedition participants and the number of the daily food packages available.
The second line contains sequence of integers a_1, a_2, ..., a_m (1 β€ a_i β€ 100), where a_i is the type of i-th food package.
Output
Print the single integer β the number of days the expedition can last. If it is not possible to plan the expedition for even one day, print 0.
Examples
Input
4 10
1 5 2 1 1 1 2 5 7 2
Output
2
Input
100 1
1
Output
0
Input
2 5
5 4 3 2 1
Output
1
Input
3 9
42 42 42 42 42 42 42 42 42
Output
3
Note
In the first example, Natasha can assign type 1 food to the first participant, the same type 1 to the second, type 5 to the third and type 2 to the fourth. In this case, the expedition can last for 2 days, since each participant can get two food packages of his food type (there will be used 4 packages of type 1, two packages of type 2 and two packages of type 5).
In the second example, there are 100 participants and only 1 food package. In this case, the expedition can't last even 1 day. | instruction | 0 | 35,985 | 9 | 71,970 |
Tags: binary search, brute force, implementation
Correct Solution:
```
import sys
n,m=map(int,input().split())
l=list(map(int,input().split()))
d={}
d=d.fromkeys(l,0)
for i in l:
d[i]=d.get(i)+1
x=list(d.values())
x.sort()
k=1
u=0
while(k):
if sum(x)<n:
print(0)
u=0
break
newList = [ int(t / k) for t in x ]
if sum(newList)<n:
u=1
break
else:
k=k+1
if u:
print(k-1)
``` | output | 1 | 35,985 | 9 | 71,971 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Natasha is planning an expedition to Mars for n people. One of the important tasks is to provide food for each participant.
The warehouse has m daily food packages. Each package has some food type a_i.
Each participant must eat exactly one food package each day. Due to extreme loads, each participant must eat the same food type throughout the expedition. Different participants may eat different (or the same) types of food.
Formally, for each participant j Natasha should select his food type b_j and each day j-th participant will eat one food package of type b_j. The values b_j for different participants may be different.
What is the maximum possible number of days the expedition can last, following the requirements above?
Input
The first line contains two integers n and m (1 β€ n β€ 100, 1 β€ m β€ 100) β the number of the expedition participants and the number of the daily food packages available.
The second line contains sequence of integers a_1, a_2, ..., a_m (1 β€ a_i β€ 100), where a_i is the type of i-th food package.
Output
Print the single integer β the number of days the expedition can last. If it is not possible to plan the expedition for even one day, print 0.
Examples
Input
4 10
1 5 2 1 1 1 2 5 7 2
Output
2
Input
100 1
1
Output
0
Input
2 5
5 4 3 2 1
Output
1
Input
3 9
42 42 42 42 42 42 42 42 42
Output
3
Note
In the first example, Natasha can assign type 1 food to the first participant, the same type 1 to the second, type 5 to the third and type 2 to the fourth. In this case, the expedition can last for 2 days, since each participant can get two food packages of his food type (there will be used 4 packages of type 1, two packages of type 2 and two packages of type 5).
In the second example, there are 100 participants and only 1 food package. In this case, the expedition can't last even 1 day. | instruction | 0 | 35,986 | 9 | 71,972 |
Tags: binary search, brute force, implementation
Correct Solution:
```
from collections import Counter
n, m = map(int, input().split())
c = Counter(input().split()).values()
d = 1
while sum(ci//d for ci in c) >= n:
d += 1
print(d - 1)
``` | output | 1 | 35,986 | 9 | 71,973 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Natasha is planning an expedition to Mars for n people. One of the important tasks is to provide food for each participant.
The warehouse has m daily food packages. Each package has some food type a_i.
Each participant must eat exactly one food package each day. Due to extreme loads, each participant must eat the same food type throughout the expedition. Different participants may eat different (or the same) types of food.
Formally, for each participant j Natasha should select his food type b_j and each day j-th participant will eat one food package of type b_j. The values b_j for different participants may be different.
What is the maximum possible number of days the expedition can last, following the requirements above?
Input
The first line contains two integers n and m (1 β€ n β€ 100, 1 β€ m β€ 100) β the number of the expedition participants and the number of the daily food packages available.
The second line contains sequence of integers a_1, a_2, ..., a_m (1 β€ a_i β€ 100), where a_i is the type of i-th food package.
Output
Print the single integer β the number of days the expedition can last. If it is not possible to plan the expedition for even one day, print 0.
Examples
Input
4 10
1 5 2 1 1 1 2 5 7 2
Output
2
Input
100 1
1
Output
0
Input
2 5
5 4 3 2 1
Output
1
Input
3 9
42 42 42 42 42 42 42 42 42
Output
3
Note
In the first example, Natasha can assign type 1 food to the first participant, the same type 1 to the second, type 5 to the third and type 2 to the fourth. In this case, the expedition can last for 2 days, since each participant can get two food packages of his food type (there will be used 4 packages of type 1, two packages of type 2 and two packages of type 5).
In the second example, there are 100 participants and only 1 food package. In this case, the expedition can't last even 1 day. | instruction | 0 | 35,987 | 9 | 71,974 |
Tags: binary search, brute force, implementation
Correct Solution:
```
n,m=map(int,input().split())
a = list(map(int,input().split()))
arr = dict()
for i in range(m):
if(a[i] not in arr):
arr[a[i]] = 1
else:
arr[a[i]] +=1
b = 1
while sum(arr[i]//b for i in arr) >= n:
b +=1
print(b-1)
``` | output | 1 | 35,987 | 9 | 71,975 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Natasha is planning an expedition to Mars for n people. One of the important tasks is to provide food for each participant.
The warehouse has m daily food packages. Each package has some food type a_i.
Each participant must eat exactly one food package each day. Due to extreme loads, each participant must eat the same food type throughout the expedition. Different participants may eat different (or the same) types of food.
Formally, for each participant j Natasha should select his food type b_j and each day j-th participant will eat one food package of type b_j. The values b_j for different participants may be different.
What is the maximum possible number of days the expedition can last, following the requirements above?
Input
The first line contains two integers n and m (1 β€ n β€ 100, 1 β€ m β€ 100) β the number of the expedition participants and the number of the daily food packages available.
The second line contains sequence of integers a_1, a_2, ..., a_m (1 β€ a_i β€ 100), where a_i is the type of i-th food package.
Output
Print the single integer β the number of days the expedition can last. If it is not possible to plan the expedition for even one day, print 0.
Examples
Input
4 10
1 5 2 1 1 1 2 5 7 2
Output
2
Input
100 1
1
Output
0
Input
2 5
5 4 3 2 1
Output
1
Input
3 9
42 42 42 42 42 42 42 42 42
Output
3
Note
In the first example, Natasha can assign type 1 food to the first participant, the same type 1 to the second, type 5 to the third and type 2 to the fourth. In this case, the expedition can last for 2 days, since each participant can get two food packages of his food type (there will be used 4 packages of type 1, two packages of type 2 and two packages of type 5).
In the second example, there are 100 participants and only 1 food package. In this case, the expedition can't last even 1 day. | instruction | 0 | 35,988 | 9 | 71,976 |
Tags: binary search, brute force, implementation
Correct Solution:
```
n,m=map(int,input().split())
from collections import *
a=[*Counter(input().split()).values()]
d=m//n
while d>0:
if sum(c//d for c in a)>=n:break
d-=1
print(d)
``` | output | 1 | 35,988 | 9 | 71,977 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Natasha is planning an expedition to Mars for n people. One of the important tasks is to provide food for each participant.
The warehouse has m daily food packages. Each package has some food type a_i.
Each participant must eat exactly one food package each day. Due to extreme loads, each participant must eat the same food type throughout the expedition. Different participants may eat different (or the same) types of food.
Formally, for each participant j Natasha should select his food type b_j and each day j-th participant will eat one food package of type b_j. The values b_j for different participants may be different.
What is the maximum possible number of days the expedition can last, following the requirements above?
Input
The first line contains two integers n and m (1 β€ n β€ 100, 1 β€ m β€ 100) β the number of the expedition participants and the number of the daily food packages available.
The second line contains sequence of integers a_1, a_2, ..., a_m (1 β€ a_i β€ 100), where a_i is the type of i-th food package.
Output
Print the single integer β the number of days the expedition can last. If it is not possible to plan the expedition for even one day, print 0.
Examples
Input
4 10
1 5 2 1 1 1 2 5 7 2
Output
2
Input
100 1
1
Output
0
Input
2 5
5 4 3 2 1
Output
1
Input
3 9
42 42 42 42 42 42 42 42 42
Output
3
Note
In the first example, Natasha can assign type 1 food to the first participant, the same type 1 to the second, type 5 to the third and type 2 to the fourth. In this case, the expedition can last for 2 days, since each participant can get two food packages of his food type (there will be used 4 packages of type 1, two packages of type 2 and two packages of type 5).
In the second example, there are 100 participants and only 1 food package. In this case, the expedition can't last even 1 day. | instruction | 0 | 35,989 | 9 | 71,978 |
Tags: binary search, brute force, implementation
Correct Solution:
```
import sys
n, m = map(int, input().split())
L = [int(el) for el in input().split()]
L.sort()
L1 = []
L1.append(L.count(L[0]))
for i in range(1, len(L)):
if L[i] != L[i - 1]:
L1.append(L.count(L[i]))
zn = 0
for i in range(1, 1000):
p = n
for el in L1:
if el >= i:
p -= el // i
if p <= 0:
zn = i
if p > 0:
print(zn)
sys.exit()
``` | output | 1 | 35,989 | 9 | 71,979 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Natasha is planning an expedition to Mars for n people. One of the important tasks is to provide food for each participant.
The warehouse has m daily food packages. Each package has some food type a_i.
Each participant must eat exactly one food package each day. Due to extreme loads, each participant must eat the same food type throughout the expedition. Different participants may eat different (or the same) types of food.
Formally, for each participant j Natasha should select his food type b_j and each day j-th participant will eat one food package of type b_j. The values b_j for different participants may be different.
What is the maximum possible number of days the expedition can last, following the requirements above?
Input
The first line contains two integers n and m (1 β€ n β€ 100, 1 β€ m β€ 100) β the number of the expedition participants and the number of the daily food packages available.
The second line contains sequence of integers a_1, a_2, ..., a_m (1 β€ a_i β€ 100), where a_i is the type of i-th food package.
Output
Print the single integer β the number of days the expedition can last. If it is not possible to plan the expedition for even one day, print 0.
Examples
Input
4 10
1 5 2 1 1 1 2 5 7 2
Output
2
Input
100 1
1
Output
0
Input
2 5
5 4 3 2 1
Output
1
Input
3 9
42 42 42 42 42 42 42 42 42
Output
3
Note
In the first example, Natasha can assign type 1 food to the first participant, the same type 1 to the second, type 5 to the third and type 2 to the fourth. In this case, the expedition can last for 2 days, since each participant can get two food packages of his food type (there will be used 4 packages of type 1, two packages of type 2 and two packages of type 5).
In the second example, there are 100 participants and only 1 food package. In this case, the expedition can't last even 1 day.
Submitted Solution:
```
from collections import Counter
n, m = map(int, input().split())
a = list(map(int, input().split()))
C = Counter(a)
def check(p):
return sum(el // p for el in C.values()) >= n
def binSearch(a, b):
left, right = a - 1, b + 1
while right - left > 1:
mid = (left + right) // 2
if check(mid):
left = mid
else:
right = mid
return left
print(binSearch(1, 100))
``` | instruction | 0 | 35,990 | 9 | 71,980 |
Yes | output | 1 | 35,990 | 9 | 71,981 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Natasha is planning an expedition to Mars for n people. One of the important tasks is to provide food for each participant.
The warehouse has m daily food packages. Each package has some food type a_i.
Each participant must eat exactly one food package each day. Due to extreme loads, each participant must eat the same food type throughout the expedition. Different participants may eat different (or the same) types of food.
Formally, for each participant j Natasha should select his food type b_j and each day j-th participant will eat one food package of type b_j. The values b_j for different participants may be different.
What is the maximum possible number of days the expedition can last, following the requirements above?
Input
The first line contains two integers n and m (1 β€ n β€ 100, 1 β€ m β€ 100) β the number of the expedition participants and the number of the daily food packages available.
The second line contains sequence of integers a_1, a_2, ..., a_m (1 β€ a_i β€ 100), where a_i is the type of i-th food package.
Output
Print the single integer β the number of days the expedition can last. If it is not possible to plan the expedition for even one day, print 0.
Examples
Input
4 10
1 5 2 1 1 1 2 5 7 2
Output
2
Input
100 1
1
Output
0
Input
2 5
5 4 3 2 1
Output
1
Input
3 9
42 42 42 42 42 42 42 42 42
Output
3
Note
In the first example, Natasha can assign type 1 food to the first participant, the same type 1 to the second, type 5 to the third and type 2 to the fourth. In this case, the expedition can last for 2 days, since each participant can get two food packages of his food type (there will be used 4 packages of type 1, two packages of type 2 and two packages of type 5).
In the second example, there are 100 participants and only 1 food package. In this case, the expedition can't last even 1 day.
Submitted Solution:
```
def main():
n, m = map(int, input().split())
storage = [0]*101
for i in map(int, input().split()):
storage[i] += 1
storage = [i for i in storage if i != 0]
num_of_days = 1
while True:
if max_people(storage, num_of_days) < n:
print(num_of_days - 1)
return 0
num_of_days += 1
def max_people(storage, num_of_days):
result = 0
for i in storage:
result += int(i/num_of_days)
return int(result)
if __name__ == "__main__":
main()
``` | instruction | 0 | 35,991 | 9 | 71,982 |
Yes | output | 1 | 35,991 | 9 | 71,983 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Natasha is planning an expedition to Mars for n people. One of the important tasks is to provide food for each participant.
The warehouse has m daily food packages. Each package has some food type a_i.
Each participant must eat exactly one food package each day. Due to extreme loads, each participant must eat the same food type throughout the expedition. Different participants may eat different (or the same) types of food.
Formally, for each participant j Natasha should select his food type b_j and each day j-th participant will eat one food package of type b_j. The values b_j for different participants may be different.
What is the maximum possible number of days the expedition can last, following the requirements above?
Input
The first line contains two integers n and m (1 β€ n β€ 100, 1 β€ m β€ 100) β the number of the expedition participants and the number of the daily food packages available.
The second line contains sequence of integers a_1, a_2, ..., a_m (1 β€ a_i β€ 100), where a_i is the type of i-th food package.
Output
Print the single integer β the number of days the expedition can last. If it is not possible to plan the expedition for even one day, print 0.
Examples
Input
4 10
1 5 2 1 1 1 2 5 7 2
Output
2
Input
100 1
1
Output
0
Input
2 5
5 4 3 2 1
Output
1
Input
3 9
42 42 42 42 42 42 42 42 42
Output
3
Note
In the first example, Natasha can assign type 1 food to the first participant, the same type 1 to the second, type 5 to the third and type 2 to the fourth. In this case, the expedition can last for 2 days, since each participant can get two food packages of his food type (there will be used 4 packages of type 1, two packages of type 2 and two packages of type 5).
In the second example, there are 100 participants and only 1 food package. In this case, the expedition can't last even 1 day.
Submitted Solution:
```
from queue import PriorityQueue
import copy
import math
nmlist = input()
nm = [int(i) for i in nmlist.split()]
qnt_pessoas = nm[0]
qnt_comida = nm[1]
coef = int(qnt_comida/qnt_pessoas)
comida = {}
mlist = input()
for i in mlist.split():
i = int(i)
if i not in comida:
comida[i] = 0
comida[i] += 1
q = PriorityQueue()
for i in comida:
q.put((-comida[i], i))
def last_n_days(days, q):
qcopy = PriorityQueue()
qcopy.queue = copy.deepcopy(q.queue)
last = 0
n = qnt_pessoas
while not qcopy.empty() and n > 0:
entry = qcopy.get()
last += (-entry[0])//days
#print(days, entry, last)
n -= 1
'''
for i in range(qnt_pessoas):
entry = qcopy.get()
eat = entry[0] + days
if eat == 0:
last += 1
elif eat < 0:
last += 1
qcopy.put((eat, entry[1]))
else:
break
'''
return last - qnt_pessoas
def busca_binaria(left, right):
repeat = 0
while True:
mid = int((left + right)/2)
res = last_n_days(mid, q)
#print(left, right, mid, res)
if abs(left - right) == 1:
repeat += 1
if left - right == 0 or repeat > 10:
return mid
if res >= 0:
left = mid
else:
right = mid
if qnt_pessoas > qnt_comida:
print(0)
elif last_n_days(coef, q) == 0:
print(coef)
else:
print(busca_binaria(1, coef))
``` | instruction | 0 | 35,992 | 9 | 71,984 |
Yes | output | 1 | 35,992 | 9 | 71,985 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Natasha is planning an expedition to Mars for n people. One of the important tasks is to provide food for each participant.
The warehouse has m daily food packages. Each package has some food type a_i.
Each participant must eat exactly one food package each day. Due to extreme loads, each participant must eat the same food type throughout the expedition. Different participants may eat different (or the same) types of food.
Formally, for each participant j Natasha should select his food type b_j and each day j-th participant will eat one food package of type b_j. The values b_j for different participants may be different.
What is the maximum possible number of days the expedition can last, following the requirements above?
Input
The first line contains two integers n and m (1 β€ n β€ 100, 1 β€ m β€ 100) β the number of the expedition participants and the number of the daily food packages available.
The second line contains sequence of integers a_1, a_2, ..., a_m (1 β€ a_i β€ 100), where a_i is the type of i-th food package.
Output
Print the single integer β the number of days the expedition can last. If it is not possible to plan the expedition for even one day, print 0.
Examples
Input
4 10
1 5 2 1 1 1 2 5 7 2
Output
2
Input
100 1
1
Output
0
Input
2 5
5 4 3 2 1
Output
1
Input
3 9
42 42 42 42 42 42 42 42 42
Output
3
Note
In the first example, Natasha can assign type 1 food to the first participant, the same type 1 to the second, type 5 to the third and type 2 to the fourth. In this case, the expedition can last for 2 days, since each participant can get two food packages of his food type (there will be used 4 packages of type 1, two packages of type 2 and two packages of type 5).
In the second example, there are 100 participants and only 1 food package. In this case, the expedition can't last even 1 day.
Submitted Solution:
```
def proverka(k, n):
kol = 0
i = 0
while i < len(count) and kol < n:
kol += count[i] // k
i += 1
return kol >= n
n, m = map(int, input().split())
myList = list(map(int, input().split()))
count = [0] * 101
for elem in myList:
count[elem] += 1
s = sum(count)
if s < n:
print(0)
else:
k = 1
new_k = 2
count.sort(reverse=True)
while True:
if proverka(new_k, n):
k = new_k
new_k = k + 1
else:
break
print(k)
``` | instruction | 0 | 35,993 | 9 | 71,986 |
Yes | output | 1 | 35,993 | 9 | 71,987 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Natasha is planning an expedition to Mars for n people. One of the important tasks is to provide food for each participant.
The warehouse has m daily food packages. Each package has some food type a_i.
Each participant must eat exactly one food package each day. Due to extreme loads, each participant must eat the same food type throughout the expedition. Different participants may eat different (or the same) types of food.
Formally, for each participant j Natasha should select his food type b_j and each day j-th participant will eat one food package of type b_j. The values b_j for different participants may be different.
What is the maximum possible number of days the expedition can last, following the requirements above?
Input
The first line contains two integers n and m (1 β€ n β€ 100, 1 β€ m β€ 100) β the number of the expedition participants and the number of the daily food packages available.
The second line contains sequence of integers a_1, a_2, ..., a_m (1 β€ a_i β€ 100), where a_i is the type of i-th food package.
Output
Print the single integer β the number of days the expedition can last. If it is not possible to plan the expedition for even one day, print 0.
Examples
Input
4 10
1 5 2 1 1 1 2 5 7 2
Output
2
Input
100 1
1
Output
0
Input
2 5
5 4 3 2 1
Output
1
Input
3 9
42 42 42 42 42 42 42 42 42
Output
3
Note
In the first example, Natasha can assign type 1 food to the first participant, the same type 1 to the second, type 5 to the third and type 2 to the fourth. In this case, the expedition can last for 2 days, since each participant can get two food packages of his food type (there will be used 4 packages of type 1, two packages of type 2 and two packages of type 5).
In the second example, there are 100 participants and only 1 food package. In this case, the expedition can't last even 1 day.
Submitted Solution:
```
#!/usr/bin/python3
from sys import stdin, stdout
import sys
# N, M = int(x) for x in stdin.readline().split()
N, M = [int(x) for x in input().split(' ')]
sk = [0]*101
for x in stdin.readline().split():
sk[int(x)] += 1
for i in range(M//(N+1), 0, -1):
count = 0
for j in range(101):
count += sk[j]//i
if count >= N:
print(i)
exit(0)
print(0)
``` | instruction | 0 | 35,994 | 9 | 71,988 |
No | output | 1 | 35,994 | 9 | 71,989 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Natasha is planning an expedition to Mars for n people. One of the important tasks is to provide food for each participant.
The warehouse has m daily food packages. Each package has some food type a_i.
Each participant must eat exactly one food package each day. Due to extreme loads, each participant must eat the same food type throughout the expedition. Different participants may eat different (or the same) types of food.
Formally, for each participant j Natasha should select his food type b_j and each day j-th participant will eat one food package of type b_j. The values b_j for different participants may be different.
What is the maximum possible number of days the expedition can last, following the requirements above?
Input
The first line contains two integers n and m (1 β€ n β€ 100, 1 β€ m β€ 100) β the number of the expedition participants and the number of the daily food packages available.
The second line contains sequence of integers a_1, a_2, ..., a_m (1 β€ a_i β€ 100), where a_i is the type of i-th food package.
Output
Print the single integer β the number of days the expedition can last. If it is not possible to plan the expedition for even one day, print 0.
Examples
Input
4 10
1 5 2 1 1 1 2 5 7 2
Output
2
Input
100 1
1
Output
0
Input
2 5
5 4 3 2 1
Output
1
Input
3 9
42 42 42 42 42 42 42 42 42
Output
3
Note
In the first example, Natasha can assign type 1 food to the first participant, the same type 1 to the second, type 5 to the third and type 2 to the fourth. In this case, the expedition can last for 2 days, since each participant can get two food packages of his food type (there will be used 4 packages of type 1, two packages of type 2 and two packages of type 5).
In the second example, there are 100 participants and only 1 food package. In this case, the expedition can't last even 1 day.
Submitted Solution:
```
def f(s):
k = 0
for el in b.values():
k += el // s
if k >= n:
return True
else:
return False
n, m = map(int, input().split())
a = [int(i) for i in input().split()]
b = {}
for i in a:
b[i] = b.get(i, 0) + 1
l = 0
r = 100
while r - l > 1:
m = (l + r) // 2
if f(m):
l = m
else:
r = m
if not f(1):
print(0)
else:
print(l)
``` | instruction | 0 | 35,995 | 9 | 71,990 |
No | output | 1 | 35,995 | 9 | 71,991 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Natasha is planning an expedition to Mars for n people. One of the important tasks is to provide food for each participant.
The warehouse has m daily food packages. Each package has some food type a_i.
Each participant must eat exactly one food package each day. Due to extreme loads, each participant must eat the same food type throughout the expedition. Different participants may eat different (or the same) types of food.
Formally, for each participant j Natasha should select his food type b_j and each day j-th participant will eat one food package of type b_j. The values b_j for different participants may be different.
What is the maximum possible number of days the expedition can last, following the requirements above?
Input
The first line contains two integers n and m (1 β€ n β€ 100, 1 β€ m β€ 100) β the number of the expedition participants and the number of the daily food packages available.
The second line contains sequence of integers a_1, a_2, ..., a_m (1 β€ a_i β€ 100), where a_i is the type of i-th food package.
Output
Print the single integer β the number of days the expedition can last. If it is not possible to plan the expedition for even one day, print 0.
Examples
Input
4 10
1 5 2 1 1 1 2 5 7 2
Output
2
Input
100 1
1
Output
0
Input
2 5
5 4 3 2 1
Output
1
Input
3 9
42 42 42 42 42 42 42 42 42
Output
3
Note
In the first example, Natasha can assign type 1 food to the first participant, the same type 1 to the second, type 5 to the third and type 2 to the fourth. In this case, the expedition can last for 2 days, since each participant can get two food packages of his food type (there will be used 4 packages of type 1, two packages of type 2 and two packages of type 5).
In the second example, there are 100 participants and only 1 food package. In this case, the expedition can't last even 1 day.
Submitted Solution:
```
import sys
import math
import bisect
from sys import stdin, stdout
from math import gcd, floor, sqrt, log2, ceil
from collections import defaultdict as dd
from bisect import bisect_left as bl, bisect_right as br
from bisect import insort
from collections import Counter
from collections import deque
from heapq import heappush,heappop,heapify
from itertools import permutations,combinations
from itertools import accumulate as ac
mod = int(1e9)+7
#mod = 998244353
ip = lambda : int(stdin.readline())
inp = lambda: map(int,stdin.readline().split())
ips = lambda: stdin.readline().rstrip()
out = lambda x : stdout.write(str(x)+"\n")
t = 1
for _ in range(t):
n,m = inp()
arr = list(inp())
dic = Counter(arr)
val = list(dic.values())
val.sort()
ans = 0
for i in range(1,100):
count = 0
for j in val:
if j%i == 0:
count += j//i
else:
count += j//i
if count>= n:
ans = i
print(ans)
``` | instruction | 0 | 35,996 | 9 | 71,992 |
No | output | 1 | 35,996 | 9 | 71,993 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Natasha is planning an expedition to Mars for n people. One of the important tasks is to provide food for each participant.
The warehouse has m daily food packages. Each package has some food type a_i.
Each participant must eat exactly one food package each day. Due to extreme loads, each participant must eat the same food type throughout the expedition. Different participants may eat different (or the same) types of food.
Formally, for each participant j Natasha should select his food type b_j and each day j-th participant will eat one food package of type b_j. The values b_j for different participants may be different.
What is the maximum possible number of days the expedition can last, following the requirements above?
Input
The first line contains two integers n and m (1 β€ n β€ 100, 1 β€ m β€ 100) β the number of the expedition participants and the number of the daily food packages available.
The second line contains sequence of integers a_1, a_2, ..., a_m (1 β€ a_i β€ 100), where a_i is the type of i-th food package.
Output
Print the single integer β the number of days the expedition can last. If it is not possible to plan the expedition for even one day, print 0.
Examples
Input
4 10
1 5 2 1 1 1 2 5 7 2
Output
2
Input
100 1
1
Output
0
Input
2 5
5 4 3 2 1
Output
1
Input
3 9
42 42 42 42 42 42 42 42 42
Output
3
Note
In the first example, Natasha can assign type 1 food to the first participant, the same type 1 to the second, type 5 to the third and type 2 to the fourth. In this case, the expedition can last for 2 days, since each participant can get two food packages of his food type (there will be used 4 packages of type 1, two packages of type 2 and two packages of type 5).
In the second example, there are 100 participants and only 1 food package. In this case, the expedition can't last even 1 day.
Submitted Solution:
```
def check(k,z,n):
if k==0:
return 0
counter=0
for i in z:
counter+=int(z[i]/k)
if counter>=n:
return(k)
else:
k=k-1
check(k,z,n)
n,m = map(int, input().split())
from collections import Counter
qlist=map(int,input().split())
z=Counter(qlist)
k=int(m/n)
check(k,z,n)
``` | instruction | 0 | 35,997 | 9 | 71,994 |
No | output | 1 | 35,997 | 9 | 71,995 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mike decided to teach programming to children in an elementary school. He knows that it is not an easy task to interest children in that age to code. That is why he decided to give each child two sweets.
Mike has n sweets with sizes a_1, a_2, β¦, a_n. All his sweets have different sizes. That is, there is no such pair (i, j) (1 β€ i, j β€ n) such that i β j and a_i = a_j.
Since Mike has taught for many years, he knows that if he gives two sweets with sizes a_i and a_j to one child and a_k and a_p to another, where (a_i + a_j) β (a_k + a_p), then a child who has a smaller sum of sizes will be upset. That is, if there are two children who have different sums of sweets, then one of them will be upset. Apparently, Mike does not want somebody to be upset.
Mike wants to invite children giving each of them two sweets. Obviously, he can't give one sweet to two or more children. His goal is to invite as many children as he can.
Since Mike is busy preparing to his first lecture in the elementary school, he is asking you to find the maximum number of children he can invite giving each of them two sweets in such way that nobody will be upset.
Input
The first line contains one integer n (2 β€ n β€ 1 000) β the number of sweets Mike has.
The second line contains n integers a_1, a_2, β¦, a_n (1 β€ a_i β€ 10^5) β the sizes of the sweets. It is guaranteed that all integers are distinct.
Output
Print one integer β the maximum number of children Mike can invite giving each of them two sweets in such way that nobody will be upset.
Examples
Input
8
1 8 3 11 4 9 2 7
Output
3
Input
7
3 1 7 11 9 2 12
Output
2
Note
In the first example, Mike can give 9+2=11 to one child, 8+3=11 to another one, and 7+4=11 to the third child. Therefore, Mike can invite three children. Note that it is not the only solution.
In the second example, Mike can give 3+9=12 to one child and 1+11 to another one. Therefore, Mike can invite two children. Note that it is not the only solution. | instruction | 0 | 36,061 | 9 | 72,122 |
Tags: brute force, implementation
Correct Solution:
```
from collections import *
import sys
sys.setrecursionlimit(100000)
input = sys.stdin.readline
n = int(input())
s = [int(i) for i in input().split(' ')]
s.sort()
tot = 0
if len(s) < 4:
print(1)
else:
c=Counter()
for i in range(n-1):
for j in range(i+1,n):
c[s[i]+s[j]]+=1
print(max(c.values()))
``` | output | 1 | 36,061 | 9 | 72,123 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mike decided to teach programming to children in an elementary school. He knows that it is not an easy task to interest children in that age to code. That is why he decided to give each child two sweets.
Mike has n sweets with sizes a_1, a_2, β¦, a_n. All his sweets have different sizes. That is, there is no such pair (i, j) (1 β€ i, j β€ n) such that i β j and a_i = a_j.
Since Mike has taught for many years, he knows that if he gives two sweets with sizes a_i and a_j to one child and a_k and a_p to another, where (a_i + a_j) β (a_k + a_p), then a child who has a smaller sum of sizes will be upset. That is, if there are two children who have different sums of sweets, then one of them will be upset. Apparently, Mike does not want somebody to be upset.
Mike wants to invite children giving each of them two sweets. Obviously, he can't give one sweet to two or more children. His goal is to invite as many children as he can.
Since Mike is busy preparing to his first lecture in the elementary school, he is asking you to find the maximum number of children he can invite giving each of them two sweets in such way that nobody will be upset.
Input
The first line contains one integer n (2 β€ n β€ 1 000) β the number of sweets Mike has.
The second line contains n integers a_1, a_2, β¦, a_n (1 β€ a_i β€ 10^5) β the sizes of the sweets. It is guaranteed that all integers are distinct.
Output
Print one integer β the maximum number of children Mike can invite giving each of them two sweets in such way that nobody will be upset.
Examples
Input
8
1 8 3 11 4 9 2 7
Output
3
Input
7
3 1 7 11 9 2 12
Output
2
Note
In the first example, Mike can give 9+2=11 to one child, 8+3=11 to another one, and 7+4=11 to the third child. Therefore, Mike can invite three children. Note that it is not the only solution.
In the second example, Mike can give 3+9=12 to one child and 1+11 to another one. Therefore, Mike can invite two children. Note that it is not the only solution. | instruction | 0 | 36,062 | 9 | 72,124 |
Tags: brute force, implementation
Correct Solution:
```
n=int(input())
it=list(map(int,input().split()))
s={}
for i in range(len(it)):
for j in range(i+1,len(it)):
try:
s[it[i]+it[j]]+=1
except:
s[it[i]+it[j]]=1
x=max(list(s.values()))
print(x)
``` | output | 1 | 36,062 | 9 | 72,125 |
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